Please read the following table in Markdown format and then answer the question according to the table. Table cells in one row are seperated by '|', and different rows are seperated by '
'.

Table:
| Class | Wheel arrangement | Fleet number(s) | Manufacturer | Year made | Quantity made | Quantity preserved |
| --- | --- | --- | --- | --- | --- | --- |
| 2-8-0 — oOOOO — Consolidation | 2-8-0 — oOOOO — Consolidation | 2-8-0 — oOOOO — Consolidation | 2-8-0 — oOOOO — Consolidation | 2-8-0 — oOOOO — Consolidation | 2-8-0 — oOOOO — Consolidation | 2-8-0 — oOOOO — Consolidation |
| F | 2-8-0 | 95–103 | Baldwin | 1883 | 9 | 0 |
| F-1 | 2-8-0 | 50–81 | Baldwin | 1888–1891 | 32 | 0 |
| F-2 | 2-8-0 | 82–83 | Baldwin | 1888 | 2 | 0 |
| F-3 | 2-8-0 | 84–91 | Rome | 1889–1890 | 8 | 0 |
| F-4 | 2-8-0 | 92–94 | Grant | 1887 | 3 | 0 |
| F-5 | 2-8-0 | 45–46 | Schenectady | 1900 | 2 | 0 |
| F-6 | 2-8-0 | 47 | Richmond | 1895 | 1 | 0 |
| F-7 | 2-8-0 | 48–49 | Rhode Island | 1888 | 2 | 0 |
| F-8 | 2-8-0 | 4–6 | PRR Altoona | 1891 | 3 | 0 |
| Y | 2-8-0 | 30–43 | Schenectady | 1898 | 14 | 0 |
| Y-1 | 2-8-0 | 17–29 | Schenectady | 1899–1900 | 13 | 1 |
| Y-2 | 2-8-0 | 1250–1279 | Schenectady Alco ( Richmond ) | 1901–1902 | 30 | 0 |
| Y-3 | 2-8-0 | 1200–1213 | Schenectady | 1901 | 14 | 0 |
| Y-4 | 2-8-0 | 1280–1293 | Alco ( Schen. ) | 1903 | 14 | 0 |
| Y-5 | 2-8-0 | 1214–1223 | Alco ( Schen. ) | 1903 | 10 | 0 |
Question:
What is the quantity when the wheel arrangement is 2-8-0, and class is f-4?
Answer:
3.0