Please read the following table in Markdown format and then answer the question according to the table. Table cells in one row are seperated by '|', and different rows are seperated by '
'.

Table:
| Formula | color | symmetry | space group | No | Pearson symbol | a (pm) | b (pm) | c (pm) | Z | density, g/cm3 |
| --- | --- | --- | --- | --- | --- | --- | --- | --- | --- | --- |
| Pa | silvery-gray | tetragonal | I4/mmm | 139 | tI2 | 392.5 | 392.5 | 323.8 | 2 | 15.37 |
| PaO |  | rocksalt | Fm3m | 225 | cF8 | 496.1 |  |  | 4 | 13.44 |
| PaO2 | black | fcc | Fm3m | 225 | cF12 | 550.5 |  |  | 4 | 10.47 |
| Pa2O5 | white |  | Fm3m | 225 | cF16 | 547.6 | 547.6 | 547.6 | 4 | 10.96 |
| Pa2O5 | white |  | orthorhombic |  |  | 692 | 402 | 418 |  |  |
| PaH3 | black | cubic | Pm3n | 223 | cP32 | 664.8 | 664.8 | 664.8 | 8 | 10.58 |
| PaF4 | brown-red | monoclinic | C2/c | 15 | mS60 |  |  |  | 2 |  |
| PaCl4 | green-yellow | tetragonal | I41/amd | 141 | tI20 | 837.7 | 837.7 | 748.1 | 4 | 4.72 |
| PaBr4 | brown | tetragonal | I41/amd | 141 | tI20 | 882.4 | 882.4 | 795.7 |  |  |
| PaCl5 | yellow | monoclinic | C2/c | 15 | mS24 | 797 | 1135 | 836 | 4 | 3.74 |
| PaBr5 | red | monoclinic | P21/c | 14 | mP24 | 838.5 | 1120.5 | 1214.6 | 4 | 4.98 |
| PaOBr3 |  | monoclinic | C2 |  |  | 1691.1 | 387.1 | 933.4 |  |  |
| Pa(PO3)4 |  | orthorhombic |  |  |  | 696.9 | 895.9 | 1500.9 |  |  |
| Pa2P2O7 |  | cubic | Pa3 |  |  | 865 | 865 | 865 |  |  |
| Pa(C8H8)2 | golden-yellow | monoclinic |  |  |  | 709 | 875 | 1062 |  |  |
Question:
what is the formula for the compound that has the same pearson symbol as pacl4?
Answer:
PaBr4