Please read the following table in HTML format from a webpage and then answer the question in detail according to the table. Each table cell is defined by a <td> and a </td> tag. Each table row starts with a <tr> and ends with a </tr> tag. 'rowspan=m' and 'colspan=n' represents a cell spaning over 'm' rows and 'n' columns.

Webpage title:
Kelvin
Table title:
Practical uses
Table:
<table id='hittask' contenteditable='False'>
<tr> <th colspan=1 rowspan=1 >  </th><th colspan=1 rowspan=1 > from kelvins </th><th colspan=1 rowspan=1 > to kelvins </th></tr>
<tr> <th colspan=1 rowspan=1 > Celsius </th><td class="highlighted"  colspan=1 rowspan=1 > [°C] = [K] − 273.15 </td><td colspan=1 rowspan=1 > [K] = [°C] + 273.15 </td></tr>
<tr> <th colspan=1 rowspan=1 > Fahrenheit </th><td class="highlighted"  colspan=1 rowspan=1 > [°F] = [K] × ​9⁄5 − 459.67 </td><td colspan=1 rowspan=1 > [K] = ([°F] + 459.67) × ​5⁄9 </td></tr>
<tr> <th colspan=1 rowspan=1 > Rankine </th><td colspan=1 rowspan=1 > [°R] = [K] × ​9⁄5 </td><td colspan=1 rowspan=1 > [K] = [°R] × ​5⁄9 </td></tr>
<tr> <td colspan=3 rowspan=1 > For temperature intervals rather than specific temperatures, 1 K = 1 °C = ​9⁄5 °F = ​9⁄5 °R Comparisons among various temperature scales </td></tr>
</table>
Question:
What is the Celsius equivalent of absolute zero and how is it calculated?
Answer:
The [°C] = [K] − 273.15 ([°F] = [K] × ​9⁄5 − 459.67) definition implies that absolute zero (0 K) is equivalent to −273.15 °C (−459.67 °F).