Problem: There is a given string S consisting of N symbols. Your task is to find the number of ordered pairs of integers i and j such that

1. 1 ≤ i, j ≤ N

2. S[i] = S[j], that is the i-th symbol of string S is equal to the j-th.

Input

The single input line contains S, consisting of lowercase Latin letters and digits. It is guaranteed that string S in not empty and its length does not exceed 105.

Output

Print a single number which represents the number of pairs i and j with the needed property. Pairs (x, y) and (y, x) should be considered different, i.e. the ordered pairs count.

Examples

Input

great10


Output

7


Input

aaaaaaaaaa


Output

100

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
long long cnt[50];
char s[1000000];
int main() {
  scanf("%s", s);
  long long n = strlen(s);
  for (long long i = 0; i < n; ++i)
    if ('0' <= s[i] && s[i] <= '9')
      cnt[26 + s[i] - '0']++;
    else
      cnt[s[i] - 'a']++;
  long long res = 0;
  for (long long i = 0; i <= 40; ++i) res += cnt[i] * cnt[i];
  cout << res << endl;
  return 0;
}