Problem: You are given a positive integer n, it is guaranteed that n is even (i.e. divisible by 2).

You want to construct the array a of length n such that: 

  * The first n/2 elements of a are even (divisible by 2); 
  * the second n/2 elements of a are odd (not divisible by 2); 
  * all elements of a are distinct and positive; 
  * the sum of the first half equals to the sum of the second half (∑_{i=1}^{n/2} a_i = ∑_{i=n/2 + 1}^{n} a_i). 



If there are multiple answers, you can print any. It is not guaranteed that the answer exists.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains one integer n (2 ≤ n ≤ 2 ⋅ 10^5) — the length of the array. It is guaranteed that that n is even (i.e. divisible by 2).

It is guaranteed that the sum of n over all test cases does not exceed 2 ⋅ 10^5 (∑ n ≤ 2 ⋅ 10^5).

Output

For each test case, print the answer — "NO" (without quotes), if there is no suitable answer for the given test case or "YES" in the first line and any suitable array a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9) satisfying conditions from the problem statement on the second line.

Example

Input


5
2
4
6
8
10


Output


NO
YES
2 4 1 5
NO
YES
2 4 6 8 1 3 5 11
NO

Solution (in PYTHON3):

Solution:
t = int(input())
for a0 in range(t):
    e1 = []
    o1 = []
    
    def out(n):
        if n%2==0:
            if (n//2)%2==0:
                odd = 0
                even = 0
                for i in range(1,n+1):
                    if i%2==0:
                        e1.append(i)
                        even+=i
                    else:
                        o1.append(i)
                        odd+=i
                if odd != even:
                    if odd > even:
                        e1[len(e1)-1] += abs(odd-even)
                    else:
                        o1[len(o1)-1] += abs(odd-even)
                return "YES"
            else:
                return "NO"
        else:
            return "NO"
                
    n = int(input())
    res = out(n)
    if res == "YES":
        print(res)
        print()
        for c in e1:
            print(c,end=' ')
        for c in o1:
            print(c,end=' ')
    else:
        print(res)
    print()