Problem: You are given four integers: H, W, h and w (1 ≤ h ≤ H, 1 ≤ w ≤ W). Determine whether there exists a matrix such that all of the following conditions are held, and construct one such matrix if the answer is positive:

* The matrix has H rows and W columns.
* Each element of the matrix is an integer between -10^9 and 10^9 (inclusive).
* The sum of all the elements of the matrix is positive.
* The sum of all the elements within every subrectangle with h rows and w columns in the matrix is negative.

Constraints

* 1 ≤ h ≤ H ≤ 500
* 1 ≤ w ≤ W ≤ 500

Input

Input is given from Standard Input in the following format:


H W h w


Output

If there does not exist a matrix that satisfies all of the conditions, print `No`.

Otherwise, print `Yes` in the first line, and print a matrix in the subsequent lines in the following format:


a_{11} ... a_{1W}
:
a_{H1} ... a_{HW}


Here, a_{ij} represents the (i,\ j) element of the matrix.

Examples

Input

3 3 2 2


Output

Yes
1 1 1
1 -4 1
1 1 1


Input

2 4 1 2


Output

No


Input

3 4 2 3


Output

Yes
2 -5 8 7
3 -5 -4 -5
2 1 -1 7

Solution (in JAVA):

Solution:
import java.io.PrintWriter;
import java.util.*;

public class Main {
	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		PrintWriter pw = new PrintWriter(System.out);
		
		int H = sc.nextInt();
		int W = sc.nextInt();
		int h = sc.nextInt();
		int w = sc.nextInt();
		
		if(H%h==0) {
			if(W%w==0) {
				pw.println("No");
			} else {
				pw.println("Yes");
				int[] v = getArray(w);
				for(int i=0; i<H; i++) {
					for(int j=0; j<W; j++) {
						pw.print(v[j%w]);
						pw.print(j<W-1 ? " " : "\n");
					}
				}
			}
		} else {
			pw.println("Yes");
			int[] v = getArray(h);
			for(int i=0; i<H; i++) {
				for(int j=0; j<W; j++) {
					pw.print(v[i%h]);
					pw.print(j<W-1 ? " " : "\n");
				}
			}
		}
		
		sc.close();
		pw.close();
	}
	
	static int[] getArray(int N) {
		int BASE = 1000;
		
		int[] ans = new int[N];
		Arrays.fill(ans, BASE);
		ans[N-1] = -(BASE*(N-1)+1);
		
		return ans;
	}
}