Problem: You are given four integers: H, W, h and w (1 ≤ h ≤ H, 1 ≤ w ≤ W). Determine whether there exists a matrix such that all of the following conditions are held, and construct one such matrix if the answer is positive:

* The matrix has H rows and W columns.
* Each element of the matrix is an integer between -10^9 and 10^9 (inclusive).
* The sum of all the elements of the matrix is positive.
* The sum of all the elements within every subrectangle with h rows and w columns in the matrix is negative.

Constraints

* 1 ≤ h ≤ H ≤ 500
* 1 ≤ w ≤ W ≤ 500

Input

Input is given from Standard Input in the following format:


H W h w


Output

If there does not exist a matrix that satisfies all of the conditions, print `No`.

Otherwise, print `Yes` in the first line, and print a matrix in the subsequent lines in the following format:


a_{11} ... a_{1W}
:
a_{H1} ... a_{HW}


Here, a_{ij} represents the (i,\ j) element of the matrix.

Examples

Input

3 3 2 2


Output

Yes
1 1 1
1 -4 1
1 1 1


Input

2 4 1 2


Output

No


Input

3 4 2 3


Output

Yes
2 -5 8 7
3 -5 -4 -5
2 1 -1 7

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
#define sz(c)      int(c.size())
#define rep(i,a,b) for (int i=a; i<(b); ++i)
#define per(i,a,b) for (int i=(b)-1; i>=(a); --i)
using namespace std;
using ll = long long;

int H,W,h,w;

int main() {
	cin.tie(0);
	ios_base::sync_with_stdio(0);
	cout<<fixed<<setprecision(10);
	
	cin>>H>>W>>h>>w;
	
	if (H%h==0 && W%w==0) {
		cout<<"No\n";
		return 0;
	}

	cout<<"Yes\n";
	rep(i,0,H) rep(j,0,W) {
		if ((i+1)%h==0 && (j+1)%w==0) cout<<-4000*(h*w-1)-1; else cout<<4000;
		cout<<" \n"[j+1==W];
	}
}