Problem: There is a given string S consisting of N symbols. Your task is to find the number of ordered pairs of integers i and j such that

1. 1 ≤ i, j ≤ N

2. S[i] = S[j], that is the i-th symbol of string S is equal to the j-th.

Input

The single input line contains S, consisting of lowercase Latin letters and digits. It is guaranteed that string S in not empty and its length does not exceed 105.

Output

Print a single number which represents the number of pairs i and j with the needed property. Pairs (x, y) and (y, x) should be considered different, i.e. the ordered pairs count.

Examples

Input

great10


Output

7


Input

aaaaaaaaaa


Output

100

Solution (in JAVA):

Solution:
import java.io.PrintWriter;
import java.util.Scanner;

public class P10 {
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        PrintWriter out = new PrintWriter(System.out);
        String s = in.next().trim();
        long freq [] = new long[128];
        for(int i=0; i < s.length(); ++i) {
            freq[s.charAt(i)]++;
        }
        long res = 0;
        for(int i=0; i < freq.length; ++i) {
            res += freq[i]*freq[i]; //(freq[i] * (freq[i]-1)) + freq[i];
        }
        out.println(res);
        out.flush();
        out.close();
    }
}