Problem: There are n piles of stones, where the i-th pile has a_i stones. Two people play a game, where they take alternating turns removing stones.

In a move, a player may remove a positive number of stones from the first non-empty pile (the pile with the minimal index, that has at least one stone). The first player who cannot make a move (because all piles are empty) loses the game. If both players play optimally, determine the winner of the game.

Input

The first line contains a single integer t (1≤ t≤ 1000) — the number of test cases. Next 2t lines contain descriptions of test cases.

The first line of each test case contains a single integer n (1≤ n≤ 10^5) — the number of piles.

The second line of each test case contains n integers a_1,…,a_n (1≤ a_i≤ 10^9) — a_i is equal to the number of stones in the i-th pile.

It is guaranteed that the sum of n for all test cases does not exceed 10^5.

Output

For each test case, if the player who makes the first move will win, output "First". Otherwise, output "Second".

Example

Input


7
3
2 5 4
8
1 1 1 1 1 1 1 1
6
1 2 3 4 5 6
6
1 1 2 1 2 2
1
1000000000
5
1 2 2 1 1
3
1 1 1


Output


First
Second
Second
First
First
Second
First

Note

In the first test case, the first player will win the game. His winning strategy is: 

  1. The first player should take the stones from the first pile. He will take 1 stone. The numbers of stones in piles will be [1, 5, 4]. 
  2. The second player should take the stones from the first pile. He will take 1 stone because he can't take any other number of stones. The numbers of stones in piles will be [0, 5, 4]. 
  3. The first player should take the stones from the second pile because the first pile is empty. He will take 4 stones. The numbers of stones in piles will be [0, 1, 4]. 
  4. The second player should take the stones from the second pile because the first pile is empty. He will take 1 stone because he can't take any other number of stones. The numbers of stones in piles will be [0, 0, 4]. 
  5. The first player should take the stones from the third pile because the first and second piles are empty. He will take 4 stones. The numbers of stones in piles will be [0, 0, 0]. 
  6. The second player will lose the game because all piles will be empty. 

Solution (in JAVA):

Solution:

import java.util.Collections;



import java.util.*;
import java.lang.*;
import java.io.*;
import java.util.Arrays;

public class CodeChef {
	
	
    public static void main(String args[] ) throws Exception {
 

        
        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
        StringBuilder sb=new StringBuilder();
            int t=Integer.parseInt(br.readLine());
            		while(t-->0)
            		{
            		
       int n=Integer.parseInt(br.readLine());
       
       
       
       int[] arr=new int[n];
       int[] dp=new int[n+1];
       
       String[] sr=br.readLine().split(" ");
       for(int i=0;i<n;i++)
       {arr[i]=Integer.parseInt(sr[i]);
    	   
       }
   dp[0]=2;
   dp[1]=1;
   for(int i=2;i<=n;i++)
   {
	   if(arr[i-2]==1)
		   dp[i]=dp[i-2];
	   else
		   dp[i]=dp[i-1];
   }
   if(dp[n]==2)
	   System.out.println("Second");
   else
	   System.out.println("First");
       
       
            	



	
}


    } 
}