Problem: You are given a positive integer n, it is guaranteed that n is even (i.e. divisible by 2).

You want to construct the array a of length n such that: 

  * The first n/2 elements of a are even (divisible by 2); 
  * the second n/2 elements of a are odd (not divisible by 2); 
  * all elements of a are distinct and positive; 
  * the sum of the first half equals to the sum of the second half (∑_{i=1}^{n/2} a_i = ∑_{i=n/2 + 1}^{n} a_i). 



If there are multiple answers, you can print any. It is not guaranteed that the answer exists.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains one integer n (2 ≤ n ≤ 2 ⋅ 10^5) — the length of the array. It is guaranteed that that n is even (i.e. divisible by 2).

It is guaranteed that the sum of n over all test cases does not exceed 2 ⋅ 10^5 (∑ n ≤ 2 ⋅ 10^5).

Output

For each test case, print the answer — "NO" (without quotes), if there is no suitable answer for the given test case or "YES" in the first line and any suitable array a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9) satisfying conditions from the problem statement on the second line.

Example

Input


5
2
4
6
8
10


Output


NO
YES
2 4 1 5
NO
YES
2 4 6 8 1 3 5 11
NO

Solution (in PYTHON3):

Solution:
t = int(input())
ans = []
seqs = []
for _ in range(0, t):
  n = int(input())
  if (n // 2) % 2 == 0:
    ans.append("YES")
    seq = []
    i = 2
    s1 = 0
    while i <= n:
      seq.append(i)
      s1 += i
      i += 2
    i = 1
    s2 = 0
    while i <= n - 3:
      seq.append(i)
      s2 += i
      i += 2
    seq.append(s1 - s2)
    seqs.append(seq)
  else:
    ans.append("NO")

j = 0
for i in range(0, len(ans)):
  print(ans[i])
  if ans[i] == "YES":
    for _ in range(0, len(seqs[j])):
      print(seqs[j][_], end=" ")
    print()
    j += 1