Problem: There are n piles of stones, where the i-th pile has a_i stones. Two people play a game, where they take alternating turns removing stones.

In a move, a player may remove a positive number of stones from the first non-empty pile (the pile with the minimal index, that has at least one stone). The first player who cannot make a move (because all piles are empty) loses the game. If both players play optimally, determine the winner of the game.

Input

The first line contains a single integer t (1≤ t≤ 1000) — the number of test cases. Next 2t lines contain descriptions of test cases.

The first line of each test case contains a single integer n (1≤ n≤ 10^5) — the number of piles.

The second line of each test case contains n integers a_1,…,a_n (1≤ a_i≤ 10^9) — a_i is equal to the number of stones in the i-th pile.

It is guaranteed that the sum of n for all test cases does not exceed 10^5.

Output

For each test case, if the player who makes the first move will win, output "First". Otherwise, output "Second".

Example

Input


7
3
2 5 4
8
1 1 1 1 1 1 1 1
6
1 2 3 4 5 6
6
1 1 2 1 2 2
1
1000000000
5
1 2 2 1 1
3
1 1 1


Output


First
Second
Second
First
First
Second
First

Note

In the first test case, the first player will win the game. His winning strategy is: 

  1. The first player should take the stones from the first pile. He will take 1 stone. The numbers of stones in piles will be [1, 5, 4]. 
  2. The second player should take the stones from the first pile. He will take 1 stone because he can't take any other number of stones. The numbers of stones in piles will be [0, 5, 4]. 
  3. The first player should take the stones from the second pile because the first pile is empty. He will take 4 stones. The numbers of stones in piles will be [0, 1, 4]. 
  4. The second player should take the stones from the second pile because the first pile is empty. He will take 1 stone because he can't take any other number of stones. The numbers of stones in piles will be [0, 0, 4]. 
  5. The first player should take the stones from the third pile because the first and second piles are empty. He will take 4 stones. The numbers of stones in piles will be [0, 0, 0]. 
  6. The second player will lose the game because all piles will be empty. 

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.FileNotFoundException;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.util.StringTokenizer;

public class b658 {
    static PrintWriter out;
    static BufferedReader in;
    static StringTokenizer st;

    public static void main(String[] args) throws FileNotFoundException {
        out = new PrintWriter(System.out);
        in = new BufferedReader(new InputStreamReader(System.in));
        new b658().Run();
        out.close();
    }

    String ns() {
        try {
            if (st == null || !st.hasMoreTokens()) {
                st = new StringTokenizer(in.readLine());
            }
            return st.nextToken();
        } catch (Exception e) {
            return null;
        }
    }

    int nextint() {
        return Integer.valueOf(ns());
    }

    int N;
    private static int inf = Integer.MAX_VALUE;
    public void Run() {
        N = nextint();
        while(N-- > 0){
            int n = nextint();
            boolean t = false;
            int cnt = 0;
            int min = inf;
            for(int i = 0; i < n; i++){
                int a = nextint();
                if (a != 1 && min == inf) {
                    min = i;
                    t = min % 2 == 0? t : !t;
                }
                if (a == 1) cnt++;
            }
            if(cnt == n && n % 2 == 0) t = !t;
            else if (cnt!=n && cnt - min > 0) {
                t = n - min % 2 == 1 ? !t : t;
            }

            out.println(!t ? "First" : "Second");
        }
    }
}