Problem: You are given four integers: H, W, h and w (1 ≤ h ≤ H, 1 ≤ w ≤ W). Determine whether there exists a matrix such that all of the following conditions are held, and construct one such matrix if the answer is positive:

* The matrix has H rows and W columns.
* Each element of the matrix is an integer between -10^9 and 10^9 (inclusive).
* The sum of all the elements of the matrix is positive.
* The sum of all the elements within every subrectangle with h rows and w columns in the matrix is negative.

Constraints

* 1 ≤ h ≤ H ≤ 500
* 1 ≤ w ≤ W ≤ 500

Input

Input is given from Standard Input in the following format:


H W h w


Output

If there does not exist a matrix that satisfies all of the conditions, print `No`.

Otherwise, print `Yes` in the first line, and print a matrix in the subsequent lines in the following format:


a_{11} ... a_{1W}
:
a_{H1} ... a_{HW}


Here, a_{ij} represents the (i,\ j) element of the matrix.

Examples

Input

3 3 2 2


Output

Yes
1 1 1
1 -4 1
1 1 1


Input

2 4 1 2


Output

No


Input

3 4 2 3


Output

Yes
2 -5 8 7
3 -5 -4 -5
2 1 -1 7

Solution (in JAVA):

Solution:

import java.io.FileNotFoundException;
import java.util.Arrays;
import java.util.Scanner;

public class Main {
	public static void main(String[] args) throws FileNotFoundException {
		new Main().run();
	}

	void run() {
		Scanner sc = new Scanner(System.in);
		int H = sc.nextInt();
		int W = sc.nextInt();
		int h = sc.nextInt();
		int w = sc.nextInt();
		if (H % h == 0 && W % w == 0) {
			System.out.println("No");
			return;
		} else {
			System.out.println("Yes");
		}
		int[][] a = new int[H][W];
		for (int i = 0; i < H; i += h) {
			for (int j = 0; j < W; j += w) {
				a[i][j] = 1_000_000_000 - 1;
				if (i + h - 1 < H && j + w - 1 < W) {
					a[i + h - 1][j + w - 1] = -1_000_000_000;
				}
			}
		}
		for (int i = 0; i < H; ++i) {
			for (int j = 0; j < W; ++j) {
				System.out.print(a[i][j] + (j < W - 1 ? " " : "\n"));
			}
		}

	}

	void tr(Object... objects) {
		System.out.println(Arrays.deepToString(objects));
	}
}