Problem: You are given a positive integer n, it is guaranteed that n is even (i.e. divisible by 2).

You want to construct the array a of length n such that: 

  * The first n/2 elements of a are even (divisible by 2); 
  * the second n/2 elements of a are odd (not divisible by 2); 
  * all elements of a are distinct and positive; 
  * the sum of the first half equals to the sum of the second half (∑_{i=1}^{n/2} a_i = ∑_{i=n/2 + 1}^{n} a_i). 



If there are multiple answers, you can print any. It is not guaranteed that the answer exists.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains one integer n (2 ≤ n ≤ 2 ⋅ 10^5) — the length of the array. It is guaranteed that that n is even (i.e. divisible by 2).

It is guaranteed that the sum of n over all test cases does not exceed 2 ⋅ 10^5 (∑ n ≤ 2 ⋅ 10^5).

Output

For each test case, print the answer — "NO" (without quotes), if there is no suitable answer for the given test case or "YES" in the first line and any suitable array a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9) satisfying conditions from the problem statement on the second line.

Example

Input


5
2
4
6
8
10


Output


NO
YES
2 4 1 5
NO
YES
2 4 6 8 1 3 5 11
NO

Solution (in JAVA):

Solution:
import java.util.Scanner;

			public class BM  {
				
				public static void main(String[] args) {
				
					Scanner sc = new Scanner(System.in);
					int t = sc.nextInt();
					while(t-- > 0)
					{
					int n = sc.nextInt();
					if(((n/2)&1)==1)
						System.out.println("NO");
					else
					{
						System.out.println("YES");
						int val = n/2;
						int temp = val;
						for(int i=2;temp-- > 0;i=i+2)
							System.out.print(i +" ");
						temp = val;
						int last = val * 2 + val -1;
						for(int i=1;temp-->1;i=i+2)
							System.out.print(i+" ");
						System.out.println(last);
						
					}
					}
				}
			}