Problem: There is a given string S consisting of N symbols. Your task is to find the number of ordered pairs of integers i and j such that

1. 1 ≤ i, j ≤ N

2. S[i] = S[j], that is the i-th symbol of string S is equal to the j-th.

Input

The single input line contains S, consisting of lowercase Latin letters and digits. It is guaranteed that string S in not empty and its length does not exceed 105.

Output

Print a single number which represents the number of pairs i and j with the needed property. Pairs (x, y) and (y, x) should be considered different, i.e. the ordered pairs count.

Examples

Input

great10


Output

7


Input

aaaaaaaaaa


Output

100

Solution (in JAVA):

Solution:
import java.util.*;
import java.io.*;

/**
 * Created by HREN_VAM.
 */

public class B implements Runnable{

    BufferedReader in;
    PrintWriter out;
    StringTokenizer st;
    public static final String filename = "";

    public void solve() throws IOException{
        String s = nextToken();
        long[] a = new long[200];
        for(int i = 0;i < s.length();i ++){
            a[s.charAt(i)] ++;
        }
        long res = 0;
        for(int i = 0;i < 200;i ++){
            res += a[i] * a[i];
        }
        out.println(res);
    }

    public void run(){
        try{
            Locale.setDefault(Locale.US);
            in = new BufferedReader(new InputStreamReader(System.in));
            //in = new BufferedReader(new FileReader(filename + ".in"));
            out = new PrintWriter(System.out);
            //out = new PrintWriter(new FileWriter(filename + ".out"));
            st = new StringTokenizer("");
            solve();
            out.close();
        } catch(IOException e){
            throw new RuntimeException(e);
        }
    }

    public static void main(String[] args){
        new Thread(new B()).start();
    }

    public String nextToken() throws IOException{
        while(!st.hasMoreTokens()){
            st = new StringTokenizer(in.readLine());
        }
        return st.nextToken();
    }

    public int nextInt() throws IOException{
        return Integer.parseInt(nextToken());
    }

    public double nextDouble() throws IOException{
        return Double.parseDouble(nextToken());
    }
}