Problem: There is a given string S consisting of N symbols. Your task is to find the number of ordered pairs of integers i and j such that

1. 1 ≤ i, j ≤ N

2. S[i] = S[j], that is the i-th symbol of string S is equal to the j-th.

Input

The single input line contains S, consisting of lowercase Latin letters and digits. It is guaranteed that string S in not empty and its length does not exceed 105.

Output

Print a single number which represents the number of pairs i and j with the needed property. Pairs (x, y) and (y, x) should be considered different, i.e. the ordered pairs count.

Examples

Input

great10


Output

7


Input

aaaaaaaaaa


Output

100

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
char str[1000000];
int main() {
  while (scanf("%s", str) != -1) {
    map<char, long long> m;
    for (int i = 0; str[i]; ++i) m[str[i]]++;
    long long ans = 0;
    for (map<char, long long>::iterator it = m.begin(); it != m.end(); ++it) {
      ans += it->second * it->second;
    }
    printf("%I64d\n", ans);
  }
  return 0;
}