Problem: You are given four integers: H, W, h and w (1 ≤ h ≤ H, 1 ≤ w ≤ W). Determine whether there exists a matrix such that all of the following conditions are held, and construct one such matrix if the answer is positive:

* The matrix has H rows and W columns.
* Each element of the matrix is an integer between -10^9 and 10^9 (inclusive).
* The sum of all the elements of the matrix is positive.
* The sum of all the elements within every subrectangle with h rows and w columns in the matrix is negative.

Constraints

* 1 ≤ h ≤ H ≤ 500
* 1 ≤ w ≤ W ≤ 500

Input

Input is given from Standard Input in the following format:


H W h w


Output

If there does not exist a matrix that satisfies all of the conditions, print `No`.

Otherwise, print `Yes` in the first line, and print a matrix in the subsequent lines in the following format:


a_{11} ... a_{1W}
:
a_{H1} ... a_{HW}


Here, a_{ij} represents the (i,\ j) element of the matrix.

Examples

Input

3 3 2 2


Output

Yes
1 1 1
1 -4 1
1 1 1


Input

2 4 1 2


Output

No


Input

3 4 2 3


Output

Yes
2 -5 8 7
3 -5 -4 -5
2 1 -1 7

Solution (in CPP):

Solution:
#include<cstdio>
#include<cstring>
#include<algorithm>
using namespace std;
int const lim=100000000;
typedef long long ll;
ll s;
int a[601][601],i,j,k,n,m,x,y;
int main(){
	scanf("%d%d%d%d",&n,&m,&x,&y);
	if (x==1&&y==1){
		puts("No");return 0;
	}
	for (i=1,s=0;i<=n;i++)
	 for (j=1;j<=m;j++){
	 	if (i%x==0&&j%y==0) a[i][j]=-lim;else{
	 		a[i][j]=(lim-1)/(x*y-1);
	 		if (i%x==1&&j%y==1) a[i][j]+=(lim-1)%(x*y-1);
		 }
		s+=a[i][j];
	 }
	if (s>0){
		puts("Yes");
		for (i=1;i<=n;i++)
		 for (j=1;j<=m;j++) printf("%d%c",a[i][j],(j==m)?'\n':' ');
	}else puts("No");
	return 0;
}