Problem: There is a given string S consisting of N symbols. Your task is to find the number of ordered pairs of integers i and j such that

1. 1 ≤ i, j ≤ N

2. S[i] = S[j], that is the i-th symbol of string S is equal to the j-th.

Input

The single input line contains S, consisting of lowercase Latin letters and digits. It is guaranteed that string S in not empty and its length does not exceed 105.

Output

Print a single number which represents the number of pairs i and j with the needed property. Pairs (x, y) and (y, x) should be considered different, i.e. the ordered pairs count.

Examples

Input

great10


Output

7


Input

aaaaaaaaaa


Output

100

Solution (in JAVA):

Solution:

import java.util.*;
import java.lang.*;
import java.io.*;

public class Temp {
	static int imax = Integer.MAX_VALUE, imin = Integer.MIN_VALUE;
	static long lmax = Long.MAX_VALUE, lmin = Long.MIN_VALUE;
	static long mod = (long) 1e9 + 7;

	public static void main(String[] args) throws java.lang.Exception {
		InputReader in = new InputReader(System.in);
		PrintWriter out = new PrintWriter(System.out);
		// int test=in.ni();
		int test = 1;
		int i = 0, j = 0;
		while (test-- > 0) {
			// int n = in.ni();
			char str[] = in.ncs();
			long strfrq[] = new long[123];
			for (i = 0; i < str.length; i++) {
				strfrq[str[i]]++;
			}
			long ans = 0;
			for (i = '0'; i <= 'z'; i++) {
				if (strfrq[i] != 0){
					ans +=strfrq[i]* strfrq[i];
				}
			}
			out.println(ans);
		}
		out.close();
	}


	static class Pair {
		int x, y;

		Pair(int x, int y) {
			this.x = x;
			this.y = y;
		}

		public String toString() {
			return x + " " + y;
		}
	}

	static void print(int arr[], int len) {
		for (int i = 0; i < len; i++)
			System.out.print(arr[i] + " ");
		System.out.println();
	}

	static class InputReader {

		private InputStream stream;
		private byte[] buf = new byte[1024];
		private int curChar;
		private int numChars;

		public InputReader(InputStream stream) {
			this.stream = stream;
		}

		public int read() {
			if (numChars == -1)
				throw new InputMismatchException();
			if (curChar >= numChars) {
				curChar = 0;
				try {
					numChars = stream.read(buf);
				} catch (IOException e) {
					throw new InputMismatchException();
				}
				if (numChars <= 0)
					return -1;
			}
			return buf[curChar++];
		}

		public char[] ncs() {
			return ns().toCharArray();
		}

		public int ni() {
			int c = read();
			while (isSpaceChar(c))
				c = read();
			int sgn = 1;
			if (c == '-') {
				sgn = -1;
				c = read();
			}
			int res = 0;
			do {
				if (c < '0' || c > '9')
					throw new InputMismatchException();
				res *= 10;
				res += c & 15;
				c = read();
			} while (!isSpaceChar(c));
			return res * sgn;
		}

		public long nl() {
			int c = read();
			while (isSpaceChar(c))
				c = read();
			int sgn = 1;
			if (c == '-') {
				sgn = -1;
				c = read();
			}
			long res = 0;
			do {
				if (c < '0' || c > '9')
					throw new InputMismatchException();
				res *= 10;
				res += c & 15;
				c = read();
			} while (!isSpaceChar(c));
			return res * sgn;
		}

		public String ns() {
			int c = read();
			while (isSpaceChar(c))
				c = read();
			StringBuilder res = new StringBuilder();
			do {
				res.appendCodePoint(c);
				c = read();
			} while (!isSpaceChar(c));
			return res.toString();
		}

		public String nLine() {
			int c = read();
			// while (c != '\n' && c != '\r' && c != '\t' && c != -1)
			// c = read();
			StringBuilder res = new StringBuilder();
			do {
				res.appendCodePoint(c);
				c = read();
			} while (c != '\n' && c != '\r' && c != '\t' && c != -1);
			return res.toString();
		}

		public static boolean isSpaceChar(int c) {
			return c == ' ' || c == '\n' || c == '\r' || c == '\t' || c == -1;
		}

	}

}