Problem: There is a given string S consisting of N symbols. Your task is to find the number of ordered pairs of integers i and j such that

1. 1 ≤ i, j ≤ N

2. S[i] = S[j], that is the i-th symbol of string S is equal to the j-th.

Input

The single input line contains S, consisting of lowercase Latin letters and digits. It is guaranteed that string S in not empty and its length does not exceed 105.

Output

Print a single number which represents the number of pairs i and j with the needed property. Pairs (x, y) and (y, x) should be considered different, i.e. the ordered pairs count.

Examples

Input

great10


Output

7


Input

aaaaaaaaaa


Output

100

Solution (in PYTHON3):

Solution:
from sys import stdin,stdout
from collections import Counter
from collections import defaultdict
from math import ceil
from bisect import bisect_left 
from bisect import bisect_right
import math

ai = lambda: list(map(int, stdin.readline().split()))
ei = lambda: map(int, stdin.readline().split())
ip = lambda: int(stdin.readline().strip())

s = input()
s = [i for i in s]
d = list(Counter(s).values())
ans = 0
for i in d:
	if i > 1:
		ans += i*(i+1)-i
	else:
		ans += 1
print(ans)