Problem: There is a given string S consisting of N symbols. Your task is to find the number of ordered pairs of integers i and j such that

1. 1 ≤ i, j ≤ N

2. S[i] = S[j], that is the i-th symbol of string S is equal to the j-th.

Input

The single input line contains S, consisting of lowercase Latin letters and digits. It is guaranteed that string S in not empty and its length does not exceed 105.

Output

Print a single number which represents the number of pairs i and j with the needed property. Pairs (x, y) and (y, x) should be considered different, i.e. the ordered pairs count.

Examples

Input

great10


Output

7


Input

aaaaaaaaaa


Output

100

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int main() {
  string a;
  long long c, sum = 0;
  getline(cin, a);
  for (long long i = 0; i < a.length(); i++) {
    if (a[i] != '?') {
      c = 1;
      for (long long j = i + 1; j < a.length(); j++)
        if (a[i] == a[j]) {
          c++;
          a[j] = '?';
        }
      sum += c * c;
    }
  }
  cout << sum << endl;
}