Problem: You are given four integers: H, W, h and w (1 ≤ h ≤ H, 1 ≤ w ≤ W). Determine whether there exists a matrix such that all of the following conditions are held, and construct one such matrix if the answer is positive:

* The matrix has H rows and W columns.
* Each element of the matrix is an integer between -10^9 and 10^9 (inclusive).
* The sum of all the elements of the matrix is positive.
* The sum of all the elements within every subrectangle with h rows and w columns in the matrix is negative.

Constraints

* 1 ≤ h ≤ H ≤ 500
* 1 ≤ w ≤ W ≤ 500

Input

Input is given from Standard Input in the following format:


H W h w


Output

If there does not exist a matrix that satisfies all of the conditions, print `No`.

Otherwise, print `Yes` in the first line, and print a matrix in the subsequent lines in the following format:


a_{11} ... a_{1W}
:
a_{H1} ... a_{HW}


Here, a_{ij} represents the (i,\ j) element of the matrix.

Examples

Input

3 3 2 2


Output

Yes
1 1 1
1 -4 1
1 1 1


Input

2 4 1 2


Output

No


Input

3 4 2 3


Output

Yes
2 -5 8 7
3 -5 -4 -5
2 1 -1 7

Solution (in CPP):

Solution:
#include<bits/stdc++.h>
using namespace std;
int main(){
 int H,W,h,w;
  cin>>H>>W>>h>>w;
  if(H%h==0 && W%w==0)
    cout<<"No"<<endl;
  else{
  cout<<"Yes"<<endl;
    vector<vector<int>>A(H,vector<int>(W));
    for(int i=0;i<H;i++)
      for(int j=0;j<W;j++)
        if(i%h==h-1 && j%w==w-1)
          A[i][j]=-4000*(h*w-1)-1;
    else
      A[i][j]=4000;
   for(int i=0;i<H;i++){
    for(int j=0;j<W-1;j++)
      cout<<A[i][j]<<" ";
    cout<<A[i][W-1]<<endl;
   }
  }
  return 0;
}