Problem: There is a given string S consisting of N symbols. Your task is to find the number of ordered pairs of integers i and j such that

1. 1 ≤ i, j ≤ N

2. S[i] = S[j], that is the i-th symbol of string S is equal to the j-th.

Input

The single input line contains S, consisting of lowercase Latin letters and digits. It is guaranteed that string S in not empty and its length does not exceed 105.

Output

Print a single number which represents the number of pairs i and j with the needed property. Pairs (x, y) and (y, x) should be considered different, i.e. the ordered pairs count.

Examples

Input

great10


Output

7


Input

aaaaaaaaaa


Output

100

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int main(int argc, char** argv) {
  map<char, long long> let;
  string str;
  char ch = 0;
  while (cin.get(ch)) {
    if (ch == '\n') break;
    let[ch]++;
  }
  unsigned long long sum = 0;
  for (map<char, long long>::iterator i = let.begin(); i != let.end(); ++i) {
    sum += (i->second * i->second);
  }
  cout << sum;
  return 0;
}