Problem: Simon loves neatness. So before he goes to bed, Simon wants to complete all chores in the house.

Simon's house looks like a rectangular table consisting of n rows and n columns from above. All rows of the table are numbered from 1 to n from top to bottom. All columns of the table are numbered from 1 to n from left to right. Each cell of the table is a room. Pair (x, y) denotes the room, located at the intersection of the x-th row and the y-th column. For each room we know if the light is on or not there.

Initially Simon is in room (x0, y0). He wants to turn off the lights in all the rooms in the house, and then return to room (x0, y0). Suppose that at the current moment Simon is in the room (x, y). To reach the desired result, he can perform the following steps:

  1. The format of the action is "1". The action is to turn on the light in room (x, y). Simon cannot do it if the room already has light on. 
  2. The format of the action is "2". The action is to turn off the light in room (x, y). Simon cannot do it if the room already has light off. 
  3. The format of the action is "dir" (dir is a character). The action is to move to a side-adjacent room in direction dir. The direction can be left, right, up or down (the corresponding dir is L, R, U or D). Additionally, Simon can move only if he see a light in the direction dir. More formally, if we represent the room, Simon wants to go, as (nx, ny), there shold be an integer k (k > 0), that room (x + (nx - x)k, y + (ny - y)k) has a light. Of course, Simon cannot move out of his house. 



Help Simon, find the sequence of actions that lets him achieve the desired result.

Input

The first line contains three positive integers n, x0, y0 (2 ≤ n ≤ 500, 1 ≤ x0, y0 ≤ n).

Next n lines contain the description of rooms in the house. The i-th line contains n space-separated integers ai1, ai2, ..., ain. If number aij equals zero, then room (i, j) has light off, and if number aij equals one, then room (i, j) has light on. It is guaranteed that at least one room has light on.

Output

If there is no desired sequence of actions, print "NO" (without the quotes). Otherwise, print "YES" (without the quotes) and the description of the required sequence of actions as a string. Note that you do not have to minimize the length of the sequence of actions but you shouldn't use more than 3·106 actions.

Examples

Input

3 1 1
1 0 0
0 1 0
1 0 0


Output

YES
D1R2L2D2UU2


Input

3 1 1
1 0 0
0 1 0
0 0 1


Output

NO

Solution (in JAVA):

Solution:
import java.io.BufferedInputStream;
import java.io.IOException;
import java.io.PrintWriter;
import java.text.DecimalFormat;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Collections;
import java.util.Comparator;
import java.util.HashMap;
import java.util.HashSet;
import java.util.InputMismatchException;
import java.util.Iterator;
import java.util.LinkedList;
import java.util.Map.Entry;
import java.util.PriorityQueue;
import java.util.Queue;
import java.util.Random;
import java.util.Set;
import java.util.SortedSet;
import java.util.Stack;
import java.util.TreeMap;
import java.util.TreeSet;

public class Main
{	
	/********************************************** a list of common variables **********************************************/
	private MyScanner scan = new MyScanner();
	private PrintWriter out = new PrintWriter(System.out);
	private final double PI = Math.PI;
	private final int INF = (int)(1e9);
	private final double EPS = 1e-6;
	private final int SIZEN = (int)(1e5);
	private final int MOD = (int)(1e9 + 7);
	private final long MODH = 10000000007L, BASE = 10007;
	private final int[] DX = {-1, 0, 1, 0}, DY = {0, 1, 0, -1};
	private ArrayList<Integer>[] edge;
	private final char[] dir = {'U', 'R', 'D', 'L'};
	private int n;
	private int[][] room;
	private boolean[][] vis;
	private StringBuilder ans = new StringBuilder();
	
	public void dfs(int x, int y)
	{
		vis[x][y] = true;
		if(0 == room[x][y])
		{
			ans.append('1');
			room[x][y] = 1;
		}
		for(int k = 0;k < 4;++k)
		{
			for(int i = 1;;++i)
			{
				int xNext = x + i * DX[k], yNext = y + i * DY[k];
				if(xNext < 0 || xNext >= n || yNext < 0 || yNext >= n) break;
				if(1 == room[xNext][yNext])
				{
					xNext = x + DX[k];
					yNext = y + DY[k];
					if(!vis[xNext][yNext])
					{
						ans.append(dir[k]);
						dfs(xNext, yNext);
						ans.append(dir[(k + 2) % 4]);
					}
					break;
				}
			}
		}
		ans.append('2');
		room[x][y] = 0;
	}
	
  	public void foo()
  	{
  		n = scan.nextInt();
  		int x0 = scan.nextInt();
  		int y0 = scan.nextInt();
  		room = new int[n][n];
  		for(int i = 0;i < n;++i)
  		{
  			for(int j = 0;j < n;++j)
  			{
  				room[i][j] = scan.nextInt();
  			}
  		}
  		vis = new boolean[n][n];
  		dfs(x0 - 1, y0 - 1);
  		for(int i = 0;i < n;++i)
  		{
  			for(int j = 0;j < n;++j)
  			{
  				if(1 == room[i][j])
  				{
  					out.println("NO");
  					return;
  				}
  			}
  		}
  		out.println("YES");
  		out.println(ans);
    } 

	public static void main(String[] args)
	{
		Main m = new Main();
		m.foo();
		m.out.close();
	}

	/********************************************** a list of common algorithms **********************************************/
	/**
	 * 1---Get greatest common divisor
	 * @param a :	first number
	 * @param b :	second number
	 * @return		greatest common divisor
	 */
	public long gcd(long a, long b)
	{
		return 0 == b ? a : gcd(b, a % b);
	}
	
	/**
	 * 2---Get the distance from a point to a line
	 * @param x1	the x coordinate of one endpoint of the line
	 * @param y1	the y coordinate of one endpoint of the line
	 * @param x2	the x coordinate of the other endpoint of the line
	 * @param y2	the y coordinate of the other endpoint of the line
	 * @param x		the x coordinate of the point 
	 * @param y		the x coordinate of the point
	 * @return		the distance from a point to a line
	 */
	public double getDist(long x1, long y1, long x2, long y2, long x, long y)
	{
		long a = y2 - y1;
		long b = x1 - x2;
		long c = y1 * (x2 - x1) - x1 * (y2 - y1);
		return Math.abs(a * x + b * y + c) / Math.sqrt(a * a + b * b);
	}
	
	/**
	 * 3---Get the distance from one point to a segment (not a line)
	 * @param x1	the x coordinate of one endpoint of the segment
	 * @param y1	the y coordinate of one endpoint of the segment
	 * @param x2	the x coordinate of the other endpoint of the segment
	 * @param y2	the y coordinate of the other endpoint of the segment
	 * @param x		the x coordinate of the point
	 * @param y		the y coordinate of the point
	 * @return		the distance from one point to a segment (not a line)
	 */
	public double ptToSeg(long x1, long y1, long x2, long y2, long x, long y)
	{
		double cross = (x2 - x1) * (x - x1) + (y2 - y1) * (y - y1);
		if(cross <= 0)
		{
			return (x - x1) * (x - x1) + (y - y1) * (y - y1);
		}
		double d = (x2 - x1) * (x2 - x1) + (y2 - y1) * (y2 - y1);
		if(cross >= d) 
		{
			return (x - x2) * (x - x2) + (y - y2) * (y - y2);
		}
		double r = cross / d;
		double px = x1 + (x2 - x1) * r;
		double py = y1 + (y2 - y1) * r;
		return (x - px) * (x - px) + (y - py) * (y - py);
	}
	
	/**
	 * 4---KMP match, i.e. kmpMatch("abcd", "bcd") = 1, kmpMatch("abcd", "bfcd") = -1.
	 * @param t:	String to match.
	 * @param p:	String to be matched.
	 * @return		if can match, first index; otherwise -1.
	 */
	public int kmpMatch(char[] t, char[] p)
	{
		int n = t.length;
		int m = p.length;
		int[] next = new int[m + 1];
		next[0] = -1;
		int j = -1;
		for(int i = 1;i < m;++i)
		{
			while(j >= 0 && p[i] != p[j + 1])
			{
				j = next[j];
			}
			if(p[i] == p[j + 1])
			{
				++j;
			}
			next[i] = j;
		}
		j = -1;
		for(int i = 0;i < n;++i)
		{
			while(j >= 0 && t[i] != p[j + 1])
			{
				j = next[j];
			}
			if(t[i] == p[j + 1])
			{
				++j;
			}
			if(j == m - 1)
			{
				return i - m + 1;
			}
		}
		return -1;
	}
	
	/**
	 * 5---Get the hash code of a String
	 * @param	s:	input string
	 * @return	hash code
	 */
	public long hash(String s)
	{
		long key = 0, t = 1;
		for(int i = 0;i < s.length();++i)
		{
			key = (key + s.charAt(i) * t) % MODH;
			t = t * BASE % MODH;
		}
		return key;
	}
	
	/**
	 * 6---Get x ^ n % MOD quickly.
	 * @param	x:	base
	 * @param 	n:	times
	 * @return	x ^ n % MOD
	 */
	public long quickMod(long x, long n)
	{
		long ans = 1;
		while(n > 0)
		{
			if(1 == n % 2)
			{
				ans = ans * x % MOD;
 			}
			x = x * x % MOD;
			n >>= 1;
		}
		return ans;
	}
	
	/**
	 * 7---judge if a point is located inside a polygon
	 * @param x0	the x coordinate of the point
	 * @param y0	the y coordinate of the point
	 * @return true if it is inside the polygon, otherwise false
	 */
	/*public boolean contains(double x0, double y0)
	{
		int cross = 0;
		for(int i = 0;i < n;++i)
		{
			double s = x[i + 1] == x[i] ? 100000000 : (double)(y[i + 1] - y[i]) / (x[i + 1] - x[i]);
			boolean b1 = x[i] <= x0 && x0 < x[i + 1];
			boolean b2 = x[i + 1] <= x0 && x0 < x[i];
			boolean b3 = y0 < s * (x0 - x[i]) + y[i];
			if((b1 || b2) && b3) ++cross;
		}
		return cross % 2 != 0;
	}*/
	
	/**
	 * 8---judge if a point is located on the segment
	 * @param	x1	the x coordinate of one point of the segment
	 * @param	y1	the y coordinate of one point of the segment
	 * @param 	x2	the x coordinate of another point of the segment
	 * @param 	y2	the y coordinate of another point of the segment
	 * @param	x	the x coordinate of the point
	 * @param 	y	the y coordinate of the point
	 * @return	true if it is located on the segment, otherwise false
	 */
	public boolean isOnSeg(long x1, long y1, long x2, long y2, long x, long y)
	{
		return (x - x1) * (y2 - y1) == (x2 - x1) * (y - y1) && 
				x >= Math.min(x1, x2) && x <= Math.max(x1, x2) && 
				y >= Math.min(y1, y2) && y <= Math.max(y1, y2);
	}
	
	/**
	 * 9---get the cross product
	 * @param 	p1	point A
	 * @param 	p2	point B
	 * @param 	p	point O
	 * @return	cross product of OA x OB
	 */
	/*public long cross(Point p1, Point p2, Point p)
	{
		return (long)(p1.x - p.x) * (p2.y - p.y) - (long)(p2.x - p.x) * (p1.y - p.y);
	}*/
	
	/**
	 * 10---implement topsort and tell if it is possible
	 * @return true if it is possible to implement topsort, otherwise false
	 */
	/*public boolean topsort()
	{
		Queue<Integer> q = new LinkedList<Integer>();
		StringBuilder ans = new StringBuilder();
		int[] in = new int[26];
		for(int i = 0;i < 26;++i)
		{
			if(0 == in[i]) 
			{
				ans.append((char)('a' + i));
				q.add(i);
			}
		}
		while(!q.isEmpty())
		{
			int u = q.poll();
			for(int i = 0;i < 26;++i)
			{
				if(map[u][i])
				{
					--in[i];
					if(0 == in[i])
					{
						ans.append((char)('a' + i));
						q.add(i);
					}
				}
			}
		}
		return 26 == ans.length();
	}*/
	
	class MyScanner
	{
	    private byte[] buf = new byte[1024];
	    private int curChar;
	    private int numChars;
	    BufferedInputStream bis = new BufferedInputStream(System.in);

	    public int read() 
	    {
	        if (-1 == numChars)
	        {
	        	throw new InputMismatchException();
	        }
	        if (curChar >= numChars)
	        {
	            curChar = 0;
	            try 
	            {
	                numChars = bis.read(buf);
	            }
	            catch (IOException e)
	            {
	                throw new InputMismatchException();
	            }
	            if (numChars <= 0)
	            {
	            	return -1;
	            }
	        }
	        return buf[curChar++];
	    }

	    public int nextInt() 
	    {
	        int c = read();
	        while (isSpaceChar(c))
	        {
	        	c = read();
	        }
	        int sgn = 1;
	        if (c == '-') 
	        {
	            sgn = -1;
	            c = read();
	        }
	        int res = 0;
	        do 
	        {
	            if (c < '0' || c > '9')
	            {
	            	throw new InputMismatchException();
	            }
	            res *= 10;
	            res += c - '0';
	            c = read();
	        } while (!isSpaceChar(c));
	        return res * sgn;
	    }
	    
	    public long nextLong() 
	    {
	    	int c = read();
	    	while (isSpaceChar(c))
	    	{
	    		c = read();
	    	}
	    	int sgn = 1;
	    	if (c == '-') 
	    	{
	    		sgn = -1;
	    		c = read();
	    	}
	    	long res = 0;
	    	do 
	    	{
	    		if (c < '0' || c > '9')
	    		{
	    			throw new InputMismatchException();
	    		}
	    		res *= 10;
	    		res += c - '0';
	    		c = read();
	    	} while (!isSpaceChar(c));
	    	return res * sgn;
	    }
	    
	    public double nextDouble() 
	    {
	        int c = read();
	        while (isSpaceChar(c))
	        {
	        	c = read();
	        }
	        int sgn = 1;
	        if (c == '-')
	        {
	            sgn = -1;
	            c = read();
	        }
	        double res = 0;
	        while (!isSpaceChar(c) && c != '.') 
	        {
	            if (c == 'e' || c == 'E')
	            {
	            	return res * Math.pow(10, nextInt());
	            }
	            if (c < '0' || c > '9')
	            {
	            	throw new InputMismatchException();
	            }
	            res *= 10;
	            res += c & 15;
	            c = read();
	        }
	        if (c == '.') 
	        {
	            c = read();
	            double m = 1;
	            while (!isSpaceChar(c)) 
	            {
	                if (c == 'e' || c == 'E')
	                {
	                	return res * Math.pow(10, nextInt());
	                }
	                if (c < '0' || c > '9')
	                {
	                	throw new InputMismatchException();
	                }
	                m /= 10;
	                res += (c & 15) * m;
	                c = read();
	            }
	        }
	        return res * sgn;
	    }
	    
	    public String next()
	    {
	        int c = read();
	        while (isSpaceChar(c))
	        {
	        	c = read();
	        }
	        StringBuilder res = new StringBuilder();
	        do 
	        {
	            res.appendCodePoint(c);
	            c = read();
	        } while (!isSpaceChar(c));
	        return res.toString();
	    }

	    private boolean isSpaceChar(int c) 
	    {
	        return ' ' == c || '\n' == c || '\r' == c || '\t' == c || -1 == c;
	    }
	}
}