Problem: You are given a string s consisting of |s| small english letters.

In one move you can replace any character of this string to the next character in alphabetical order (a will be replaced with b, s will be replaced with t, etc.). You cannot replace letter z with any other letter.

Your target is to make some number of moves (not necessary minimal) to get string abcdefghijklmnopqrstuvwxyz (english alphabet) as a subsequence. Subsequence of the string is the string that is obtained by deleting characters at some positions. You need to print the string that will be obtained from the given string and will be contain english alphabet as a subsequence or say that it is impossible.

Input

The only one line of the input consisting of the string s consisting of |s| (1 ≤ |s| ≤ 105) small english letters.

Output

If you can get a string that can be obtained from the given string and will contain english alphabet as a subsequence, print it. Otherwise print «-1» (without quotes).

Examples

Input

aacceeggiikkmmooqqssuuwwyy


Output

abcdefghijklmnopqrstuvwxyz


Input

thereisnoanswer


Output

-1

Solution (in JAVA):

Solution:
import java.io.*;
import java.math.BigInteger;
import java.util.*;

import javax.rmi.ssl.SslRMIClientSocketFactory;

public class tr1 {
	static PrintWriter out;
	static StringBuilder sb;
	static int n, k;
	static long mod = 1000000007;
	static int[][] memo;
	static String s;
	static HashSet<Integer> nodes;
	static ArrayList<Integer>[] ad, tree;
	static boolean[] vis, taken;
	static int[] a;
	static TreeSet<Long> al;
	static long[] val;
	static ArrayList<String> aa;
	static char[] b;

	public static void main(String[] args) throws Exception {
		Scanner sc = new Scanner(System.in);
		out = new PrintWriter(System.out);
		char[] a = sc.nextLine().toCharArray();
		char n = 'a';
		for (int i = 0; i < a.length; i++) {
			if(n>'z')
				continue;
			if (a[i] == n) {
				n++;
				continue;
			}
			if (a[i] < n) {
				a[i] = n;
				n++;
			}
		}
		if(n<='z')
		{
			System.out.println(-1);
			return;
		}
		for(int i=0;i<a.length;i++)
			out.print(a[i]);
		out.flush();
	}

	static class pair implements Comparable<pair> {
		int to;
		long number;

		pair(int t, long n) {
			number = n;
			to = t;
		}

		public String toString() {
			return to + " " + number;
		}

		@Override
		public int compareTo(pair o) {
			return Long.compare(number, o.number);
		}

	}

	static class Scanner {
		StringTokenizer st;
		BufferedReader br;

		public Scanner(InputStream system) {
			br = new BufferedReader(new InputStreamReader(system));
		}

		public Scanner(String file) throws Exception {
			br = new BufferedReader(new FileReader(file));
		}

		public String next() throws IOException {
			while (st == null || !st.hasMoreTokens())
				st = new StringTokenizer(br.readLine());
			return st.nextToken();
		}

		public String nextLine() throws IOException {
			return br.readLine();
		}

		public int nextInt() throws IOException {
			return Integer.parseInt(next());
		}

		public double nextDouble() throws IOException {
			return Double.parseDouble(next());
		}

		public char nextChar() throws IOException {
			return next().charAt(0);
		}

		public Long nextLong() throws IOException {
			return Long.parseLong(next());
		}

		public int[] nextArrInt(int n) throws IOException {
			int[] a = new int[n];
			for (int i = 0; i < n; i++)
				a[i] = nextInt();
			return a;
		}

		public long[] nextArrLong(int n) throws IOException {
			long[] a = new long[n];
			for (int i = 0; i < n; i++)
				a[i] = nextLong();
			return a;
		}

		public boolean ready() throws IOException {
			return br.ready();
		}

		public void waitForInput() throws InterruptedException {
			Thread.sleep(3000);
		}
	}
}