Problem: You are given a positive integer n, it is guaranteed that n is even (i.e. divisible by 2).

You want to construct the array a of length n such that: 

  * The first n/2 elements of a are even (divisible by 2); 
  * the second n/2 elements of a are odd (not divisible by 2); 
  * all elements of a are distinct and positive; 
  * the sum of the first half equals to the sum of the second half (∑_{i=1}^{n/2} a_i = ∑_{i=n/2 + 1}^{n} a_i). 



If there are multiple answers, you can print any. It is not guaranteed that the answer exists.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains one integer n (2 ≤ n ≤ 2 ⋅ 10^5) — the length of the array. It is guaranteed that that n is even (i.e. divisible by 2).

It is guaranteed that the sum of n over all test cases does not exceed 2 ⋅ 10^5 (∑ n ≤ 2 ⋅ 10^5).

Output

For each test case, print the answer — "NO" (without quotes), if there is no suitable answer for the given test case or "YES" in the first line and any suitable array a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9) satisfying conditions from the problem statement on the second line.

Example

Input


5
2
4
6
8
10


Output


NO
YES
2 4 1 5
NO
YES
2 4 6 8 1 3 5 11
NO

Solution (in PYTHON3):

Solution:
from sys import stdin, stdout
from collections import deque
rl = lambda: stdin.readline()
rll = lambda: stdin.readline().split()

def main():
	T = int(rl())
	for _ in range(T):
		n = int(rl())
		if n//2 % 2 == 1:
			stdout.write("NO");stdout.write("\n")
			continue
		m = n//2
		ans = deque([2, 1])
		for i in range(1, m):
			if i % 2 == 1:
				ans.appendleft(ans[0]+2)
				ans.append(ans[-1]+4)
			else:
				ans.appendleft(ans[0] + 4)
				ans.append(ans[-1]+2)
		stdout.write("YES");stdout.write("\n")
		stdout.write(" ".join(str(x) for x in ans));stdout.write("\n")
	stdout.close()

if __name__ == "__main__":
	main()