Problem: You are given four integers: H, W, h and w (1 ≤ h ≤ H, 1 ≤ w ≤ W). Determine whether there exists a matrix such that all of the following conditions are held, and construct one such matrix if the answer is positive:

* The matrix has H rows and W columns.
* Each element of the matrix is an integer between -10^9 and 10^9 (inclusive).
* The sum of all the elements of the matrix is positive.
* The sum of all the elements within every subrectangle with h rows and w columns in the matrix is negative.

Constraints

* 1 ≤ h ≤ H ≤ 500
* 1 ≤ w ≤ W ≤ 500

Input

Input is given from Standard Input in the following format:


H W h w


Output

If there does not exist a matrix that satisfies all of the conditions, print `No`.

Otherwise, print `Yes` in the first line, and print a matrix in the subsequent lines in the following format:


a_{11} ... a_{1W}
:
a_{H1} ... a_{HW}


Here, a_{ij} represents the (i,\ j) element of the matrix.

Examples

Input

3 3 2 2


Output

Yes
1 1 1
1 -4 1
1 1 1


Input

2 4 1 2


Output

No


Input

3 4 2 3


Output

Yes
2 -5 8 7
3 -5 -4 -5
2 1 -1 7

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
using ll = long long;

ll H, W, h, w;

int main() {
    scanf("%lld %lld %lld %lld", &H, &W, &h, &w);
    if (h == 1 && w == 1) {
        printf("No\n");
        return 0;
    }
    ll p = 999999999 / (h*w-1), k = -p*(h*w-1)-1;
    ll c = (H/h) * (W/w);
    if (c*k + (H*W-c)*p <= 0) printf("No\n");
    else {
        printf("Yes\n");
        for (ll r = 1; r <= H; r++) {
            for (ll c = 1; c <= W; c++) printf("%lld ", r % h == 0 && c % w == 0 ? k:p);
            printf("\n");
        }
    }
}