Problem: This problem is actually a subproblem of problem G from the same contest.

There are n candies in a candy box. The type of the i-th candy is a_i (1 ≤ a_i ≤ n).

You have to prepare a gift using some of these candies with the following restriction: the numbers of candies of each type presented in a gift should be all distinct (i. e. for example, a gift having two candies of type 1 and two candies of type 2 is bad). 

It is possible that multiple types of candies are completely absent from the gift. It is also possible that not all candies of some types will be taken to a gift.

Your task is to find out the maximum possible size of the single gift you can prepare using the candies you have.

You have to answer q independent queries.

If you are Python programmer, consider using PyPy instead of Python when you submit your code.

Input

The first line of the input contains one integer q (1 ≤ q ≤ 2 ⋅ 10^5) — the number of queries. Each query is represented by two lines.

The first line of each query contains one integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the number of candies.

The second line of each query contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ n), where a_i is the type of the i-th candy in the box.

It is guaranteed that the sum of n over all queries does not exceed 2 ⋅ 10^5.

Output

For each query print one integer — the maximum possible size of the single gift you can compose using candies you got in this query with the restriction described in the problem statement.

Example

Input


3
8
1 4 8 4 5 6 3 8
16
2 1 3 3 4 3 4 4 1 3 2 2 2 4 1 1
9
2 2 4 4 4 7 7 7 7


Output


3
10
9

Note

In the first query, you can prepare a gift with two candies of type 8 and one candy of type 5, totalling to 3 candies.

Note that this is not the only possible solution — taking two candies of type 4 and one candy of type 6 is also valid.

Solution (in JAVA):

Solution:

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.*;

public class Main
{
    static void sort(int a[])
    {
        Random ran = new Random();
        for (int i = 0; i < a.length; i++) {
            int r = ran.nextInt(a.length);
            int temp = a[r];
            a[r] = a[i];
            a[i] = temp;
        }
        
        Arrays.sort(a);
    }
    public static void main(String args[])
    {
        FastScanner input = new FastScanner();
           StringBuilder result = new StringBuilder();
        int tc = input.nextInt();
        while (tc-- > 0) {
         int n = input.nextInt();
        HashMap<Integer,Integer> map  = new HashMap<>();
        int count[] = new int[n+1];
        TreeSet<Integer> set = new TreeSet<>();
            
        for (int i = 0; i < n; i++) {
            int value = input.nextInt();
            count[value]++;
            map.put(value, map.getOrDefault(value, 0)+1);
        }
        sort(count);
        long ans  = 0;
   
//         
          int last = Integer.MAX_VALUE;
          int temp = n;
         while(temp>0&&last>=1)
         {
             int v = count[temp];
             if(v<last)
             {
                 ans+=v;
                 last = v-1;
                 
             }
             else if(v>=last)
             {
                 ans+=(last);
                 last--;
             }
                 temp--;
         }
         result.append(ans+"\n");
        
           
           
        }
        System.out.println(result);
    }

    static class FastScanner
    {

        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
        StringTokenizer st = new StringTokenizer("");

        String next()
        {
            while (!st.hasMoreTokens()) {
                try {
                    st = new StringTokenizer(br.readLine());
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
            return st.nextToken();
        }

        int nextInt()
        {
            return Integer.parseInt(next());
        }

        long nextLong()
        {

            return Long.parseLong(next());
        }

        double nextDouble()
        {
            return Double.parseDouble(next());
        }

        String nextLine() throws IOException
        {
            return br.readLine();
        }
    }

}