Problem: There is a given string S consisting of N symbols. Your task is to find the number of ordered pairs of integers i and j such that

1. 1 ≤ i, j ≤ N

2. S[i] = S[j], that is the i-th symbol of string S is equal to the j-th.

Input

The single input line contains S, consisting of lowercase Latin letters and digits. It is guaranteed that string S in not empty and its length does not exceed 105.

Output

Print a single number which represents the number of pairs i and j with the needed property. Pairs (x, y) and (y, x) should be considered different, i.e. the ordered pairs count.

Examples

Input

great10


Output

7


Input

aaaaaaaaaa


Output

100

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
long long tmp[300];
char line[100010];
int main() {
  scanf("%s", line);
  long long sz = strlen(line);
  long long total = 0;
  memset(tmp, 0, sizeof tmp);
  for (int i = 0; i < sz; i++) tmp[line[i]]++;
  for (int i = 0; i < 300; i++) total += tmp[i] * (tmp[i] - 1);
  printf("%I64d\n", total + sz);
  return 0;
}