Problem: There is a given string S consisting of N symbols. Your task is to find the number of ordered pairs of integers i and j such that

1. 1 ≤ i, j ≤ N

2. S[i] = S[j], that is the i-th symbol of string S is equal to the j-th.

Input

The single input line contains S, consisting of lowercase Latin letters and digits. It is guaranteed that string S in not empty and its length does not exceed 105.

Output

Print a single number which represents the number of pairs i and j with the needed property. Pairs (x, y) and (y, x) should be considered different, i.e. the ordered pairs count.

Examples

Input

great10


Output

7


Input

aaaaaaaaaa


Output

100

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

public class B {
	
	public static void main(String[] args) throws IOException {
		BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
		String str = in.readLine();
		long []repeated = new long[200];//containing letter and digits repeatetion number
		for (int i = 0; i < str.length(); i++) {
			repeated[str.charAt(i)]++;
		}
		long sum = 0;
		for (int i = 0; i < repeated.length; i++) {
			if(repeated[i] > 0){
				sum += repeated[i]*repeated[i];// combinations of pairs + their number itself -> ex. AAAB ->3*3+1*1 = 10
			}
		}
		System.out.println(sum);
	}
		
	
}