Problem: You are given a positive integer n, it is guaranteed that n is even (i.e. divisible by 2).

You want to construct the array a of length n such that: 

  * The first n/2 elements of a are even (divisible by 2); 
  * the second n/2 elements of a are odd (not divisible by 2); 
  * all elements of a are distinct and positive; 
  * the sum of the first half equals to the sum of the second half (∑_{i=1}^{n/2} a_i = ∑_{i=n/2 + 1}^{n} a_i). 



If there are multiple answers, you can print any. It is not guaranteed that the answer exists.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains one integer n (2 ≤ n ≤ 2 ⋅ 10^5) — the length of the array. It is guaranteed that that n is even (i.e. divisible by 2).

It is guaranteed that the sum of n over all test cases does not exceed 2 ⋅ 10^5 (∑ n ≤ 2 ⋅ 10^5).

Output

For each test case, print the answer — "NO" (without quotes), if there is no suitable answer for the given test case or "YES" in the first line and any suitable array a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9) satisfying conditions from the problem statement on the second line.

Example

Input


5
2
4
6
8
10


Output


NO
YES
2 4 1 5
NO
YES
2 4 6 8 1 3 5 11
NO

Solution (in PYTHON3):

Solution:
def solve(n):
    global arr
    if n % 4:
        return False
    arr = [-1] * n
    for i in range(n >> 1):
        arr[i] = (i << 1) + 2
    k = 1
    M = set()
    for i in range(0, n >> 1, 2):
        su = arr[i] + arr[i + 1]
        while k in M or (su - k) in M:
            k += 2
        arr[i + (n >> 1)] = k
        arr[i + (n >> 1) + 1] = su - k
        M.add(k)
        M.add(su - k)
    return True


arr = list()
for _ in range(int(input())):
    n = int(input())
    ans = solve(n)
    print('YES') if ans else print('NO')
    if ans:
        print(*arr)