Problem: You are given a positive integer n, it is guaranteed that n is even (i.e. divisible by 2).

You want to construct the array a of length n such that: 

  * The first n/2 elements of a are even (divisible by 2); 
  * the second n/2 elements of a are odd (not divisible by 2); 
  * all elements of a are distinct and positive; 
  * the sum of the first half equals to the sum of the second half (∑_{i=1}^{n/2} a_i = ∑_{i=n/2 + 1}^{n} a_i). 



If there are multiple answers, you can print any. It is not guaranteed that the answer exists.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains one integer n (2 ≤ n ≤ 2 ⋅ 10^5) — the length of the array. It is guaranteed that that n is even (i.e. divisible by 2).

It is guaranteed that the sum of n over all test cases does not exceed 2 ⋅ 10^5 (∑ n ≤ 2 ⋅ 10^5).

Output

For each test case, print the answer — "NO" (without quotes), if there is no suitable answer for the given test case or "YES" in the first line and any suitable array a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9) satisfying conditions from the problem statement on the second line.

Example

Input


5
2
4
6
8
10


Output


NO
YES
2 4 1 5
NO
YES
2 4 6 8 1 3 5 11
NO

Solution (in PYTHON3):

Solution:
'''t = int(input())

for tests in range(t):
    ls = []
    n= int(input())
    for j in range(2,32):
        ls.append((int(n/(2**(j-1)-1))))
    print(ls[1])
                '''

t = int(input())
for i in range(t):
    lse = []
    lso = []
    n = int(input())
    if (n/2)%2==1:
        print('NO')
    else:
        print('YES')
        for j in range(1,n):
            if j %2==0:
                lse.append(j)
        a = int(lse[-1]+2+(n/2))
        lse.append(a)
        for k in range(2,n+2):
            if k %2==1:
                lso.append(k)
        lse.extend(lso)
    for m in range(len(lse)):
        print(lse[m],end=' ')