Problem: There is a given string S consisting of N symbols. Your task is to find the number of ordered pairs of integers i and j such that

1. 1 ≤ i, j ≤ N

2. S[i] = S[j], that is the i-th symbol of string S is equal to the j-th.

Input

The single input line contains S, consisting of lowercase Latin letters and digits. It is guaranteed that string S in not empty and its length does not exceed 105.

Output

Print a single number which represents the number of pairs i and j with the needed property. Pairs (x, y) and (y, x) should be considered different, i.e. the ordered pairs count.

Examples

Input

great10


Output

7


Input

aaaaaaaaaa


Output

100

Solution (in PYTHON3):

Solution:
import sys
import os.path
import math
import heapq
from sys import stdin,stdout
from collections import*
from math import gcd,ceil,floor
mod = int(1e9+7)
##input=sys.stdin.readline
if os.path.exists('Updated prg/Input3d.txt'):
    sys.stdout=open("Updated prg/Output3d.txt","w")
    sys.stdin=open("Updated prg/Input3d.txt","r")
def sinp():return input()
def ninp():return int(sinp())
def mapinp():return map(int,sinp().split())
def linp():return list(mapinp())
def sl():return list(sinp())
def prnt(a):print(a)
s1=sinp()
l1=Counter(s1)
c=0
for i in l1:
    c=c+(l1[i]*l1[i])
prnt(c)