Problem: There is a given string S consisting of N symbols. Your task is to find the number of ordered pairs of integers i and j such that

1. 1 ≤ i, j ≤ N

2. S[i] = S[j], that is the i-th symbol of string S is equal to the j-th.

Input

The single input line contains S, consisting of lowercase Latin letters and digits. It is guaranteed that string S in not empty and its length does not exceed 105.

Output

Print a single number which represents the number of pairs i and j with the needed property. Pairs (x, y) and (y, x) should be considered different, i.e. the ordered pairs count.

Examples

Input

great10


Output

7


Input

aaaaaaaaaa


Output

100

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int main() {
  char str[100001];
  long long solv[256];
  for (int i = 0; i < 256; i++) solv[i] = 0;
  gets(str);
  long long len = strlen(str);
  if (len <= 1) {
    printf("1");
    return 0;
  }
  for (int i = 0; i < len; i++) {
    solv[str[i]]++;
  }
  long long sum = 0;
  for (int i = 0; i < 256; i++)
    if (solv[i] > 1) sum += (solv[i] * (solv[i] - 1));
  cout << sum + len;
  return 0;
}