Problem: There are n piles of stones, where the i-th pile has a_i stones. Two people play a game, where they take alternating turns removing stones.

In a move, a player may remove a positive number of stones from the first non-empty pile (the pile with the minimal index, that has at least one stone). The first player who cannot make a move (because all piles are empty) loses the game. If both players play optimally, determine the winner of the game.

Input

The first line contains a single integer t (1≤ t≤ 1000) — the number of test cases. Next 2t lines contain descriptions of test cases.

The first line of each test case contains a single integer n (1≤ n≤ 10^5) — the number of piles.

The second line of each test case contains n integers a_1,…,a_n (1≤ a_i≤ 10^9) — a_i is equal to the number of stones in the i-th pile.

It is guaranteed that the sum of n for all test cases does not exceed 10^5.

Output

For each test case, if the player who makes the first move will win, output "First". Otherwise, output "Second".

Example

Input


7
3
2 5 4
8
1 1 1 1 1 1 1 1
6
1 2 3 4 5 6
6
1 1 2 1 2 2
1
1000000000
5
1 2 2 1 1
3
1 1 1


Output


First
Second
Second
First
First
Second
First

Note

In the first test case, the first player will win the game. His winning strategy is: 

  1. The first player should take the stones from the first pile. He will take 1 stone. The numbers of stones in piles will be [1, 5, 4]. 
  2. The second player should take the stones from the first pile. He will take 1 stone because he can't take any other number of stones. The numbers of stones in piles will be [0, 5, 4]. 
  3. The first player should take the stones from the second pile because the first pile is empty. He will take 4 stones. The numbers of stones in piles will be [0, 1, 4]. 
  4. The second player should take the stones from the second pile because the first pile is empty. He will take 1 stone because he can't take any other number of stones. The numbers of stones in piles will be [0, 0, 4]. 
  5. The first player should take the stones from the third pile because the first and second piles are empty. He will take 4 stones. The numbers of stones in piles will be [0, 0, 0]. 
  6. The second player will lose the game because all piles will be empty. 

Solution (in JAVA):

Solution:
import java.io.*;
import java.math.*;
import java.text.*;
import java.util.*;
import java.lang.*;


public class Contest1 {
	//static ArrayList<Integer> prime=new ArrayList();
	
	   public static TreeMap<Long,Integer> t1=new TreeMap();
	   public static void solve()
	    {
	      long m=1;
	      for(int j=2;j<=1000;j++)
	      {
	         
	          if(isprime(j))
	          {
	              m=m*j;
	              if(m>1000000)
	              {
	                  break;
	              }else{
	                  t1.put(m,1);
	              }
	          }
	      }
	    }
	
    public static int gcd(int n1, int n2)
    {
        if (n2 != 0)
            return gcd(n2, n1 % n2);
        else
            return n1;
    }
	
//////////////////	
	public static class trie {
        int x,y,z;
        trie (int x,int y,int z){
            this.x=x;
            this.y=y;
            this.z=z;
        }
	
	} 
        
	public static class pair {
        int x,y;
        pair (int x,int y){
            this.x=x;
            this.y=y;
        }
        public boolean equals(Object o) {
        	if(o instanceof pair) {
        		pair p = (pair)o;
        		return (x == p.x && y == p.y);
        	}
        	return false;
        }
        public int hashCode() {
        	return (Integer.hashCode(x) * 3 + Integer.hashCode(y) );
        }
    }
	
//////////////////	
	
	static class Cmp implements Comparator<pair>
	{
		public int compare(pair a,pair b)
		{
			if(a.x==b.x)
			{
				return(a.y-b.y);
			}
			return(a.x-b.x);
		}
	}
	
	
//////////////////
	
	
	
	
//////////////////
	
	
	
	
	
	   static class FastReader
	   {
		   BufferedReader br;
		   StringTokenizer st;
		   public FastReader()
		   {
			   br = new BufferedReader(new InputStreamReader(System.in));
		   }
		   
		   
		   String next() 
	        { 
	            while (st == null || !st.hasMoreElements()) 
	            { 
	                try
	                { 
	                    st = new StringTokenizer(br.readLine()); 
	                } 
	                catch (IOException  e) 
	                { 
	                    e.printStackTrace(); 
	                } 
	            } 
	            return st.nextToken(); 
	        } 
		   
		   
		   int nextInt()
		   {
			   return Integer.parseInt(next());
		   }
		   long nextLong()
		   {
			   return Long.parseLong(next());
		   }
		   double nextDouble() 
	        { 
	            return Double.parseDouble(next()); 
	        } 
		   
		   String nextLine() 
	        { 
	            String str = ""; 
	            try
	            { 
	                str = br.readLine(); 
	            } 
	            catch (IOException e) 
	            { 
	                e.printStackTrace(); 
	            } 
	            return str; 
	        } 
	   }
	   
////////////////////// 
	//public static ArrayList<Integer> a=new ArrayList();
	   
	  public static ArrayList<Integer> Divisors(int n) 
	  { 
	       // Note that this loop runs till square root 
		  ArrayList<Integer> a=new ArrayList();
		   long sum=0;
	       for (int i=1; i*i<=(n); i++) 
	       { 
	           if (n%i == 0) 
	           { 
	               // If divisors are equal, print only one 
	               if (n/i == i) 
	               {
	                  // printf("%d ", i); 
	            	   sum=sum+1;
	            	   a.add(i);
	               }
	     
	               else // Otherwise print both 
	               {
	                   //printf("%d %d ", i, n/i); 
	            	   sum=sum+2;
	            	   a.add(i);
	            	   a.add(n/i);
	               }
	           } 
	       } 
	       return(a);
	   } 
	   
/////////////////////	  
	  
	  public static long SmallestPrimeDivisor(long n) 
	  { 
	      // if divisible by 2 
	      if (n % 2 == 0) 
	          return 2; 
	    
	      // iterate from 3 to sqrt(n) 
	      for (long i = 3; i * i <= n; i += 2) { 
	          if (n % i == 0) 
	              return i; 
	      } 
	    
	      return n; 
	  } 
	    
////////////////////	  
	   
	   public static boolean isprime(long n)
	    {
	        int count=0;
	     
	        for(long i=2;i*i<=n;i++)
	        {
	            if(n%i==0)
	            {
	                return(false);
	            }
	        }
	        return(true);
	    }
	
	   
//////////////////////
	   
	     //   (x^n)%1000000007
	   public static long modularExponentiation(long x,long n,long M)
	   {
	       if(n==0)
	           return 1;
	       else if(n%2 == 0)        //n is even
	           return modularExponentiation((x*x)%M,n/2,M);
	       else                             //n is odd
	           return (x*modularExponentiation((x*x)%M,(n-1)/2,M))%M;

	   }
	   
	   public static long nCr(int n,int k)
	   {
		  if(k==0)
			  return 1;
		  return(n*nCr(n-1,k-1)/k);
	   }
	   public static long factorial(int n)
	   {
		   if(n==1)
			   return 1;
		   return((n)*factorial(n-1));
	   }
	   
	   public static void debug(Object...o) {
		    System.out.println( Arrays.deepToString(o) );
	   }
	   
	   public static boolean prime[]=new boolean[100005];
	   //prime[j]==false means it's a prime.
	   public static void seive()
	   {
		   prime[0]=false;
		   prime[1]=false;
		   for(int i=2;i*i<=100005;i++)
		   {
			   if(!prime[i])
			   {
				   for(int j=i*i;i<=100005;j+=i)
				   {
					   prime[j]=true;
				   }
			   }
		   }
	   }
	 
	 
	    public static boolean equals(StringBuilder sb1, StringBuilder sb2){
	    
	        if(sb1 == sb2)
	  
	        if(sb1 == null || sb2 == null)
	            return false;
	        
	        boolean isEqual = true;
	  
	        if(sb1.length() == sb2.length()){
	  
	            for(int i = 0 ; i < sb1.length(); i++){
	                
	                if(sb1.charAt(i) != sb2.charAt(i)){
	                    isEqual = false;
	                    break;
	                }
	            }
	            
	        }else{
	            isEqual = false;
	        }
	        
	        return isEqual;
	    }
	   
	    
	    public static boolean IsPalindrome(String s,int n)
	    {
	    	
	    	for(int i=0;i<n/2;i++)
	    	{
	    		if(s.charAt(i)!=s.charAt(n-i-1))
	    		{
	    			return false;
	    		}
	    	}
	    	return true;
	    }
	   
	   
	    
	    static long findSubarraySum(int arr[], int n, long sum)  
	    { 
	        HashMap <Long, Integer> prevSum = new HashMap<>(); 
	        HashMap <Long ,Integer> index=new HashMap();
	        
	        long res = 0;  
	        
	        // Sum of elements so far.  
	        long currsum = 0;  
	        
	        for (int i = 0; i < n; i++) {  
	        
	            // Add current element to sum so far.  
	            currsum += arr[i];  
	            if (currsum == sum)   
	                res++;          
	        
	           
	            if (prevSum.containsKey(currsum - sum))   
	                res += prevSum.get(currsum - sum);  
	                
	         
	            Integer count = prevSum.get(currsum); 
	            if (count == null) 
	            {
	                prevSum.put(currsum, 1); 
	                index.put(currsum,i);
	            }
	                
	            else
	            {
	                prevSum.put(currsum, count+1); 
	            }
	        }  
	        
	        return res;  
	    }  
	      
	  
	     
	    
	    
	  public static void main(String args[])
	  {
		  //Scanner sc=new Scanner(System.in);
		  FastReader in = new FastReader();
		  PrintWriter pw = new PrintWriter(System.out);
		
		 
		   int t = in.nextInt();
		   while(t-->0)
		   {
			 
			 int n = in.nextInt();
			 int y = -1;
			 for(int i=0;i<n;i++)
			 {
				 int x = in.nextInt();
				 if(x>1 && y==-1)
				 {
					 y=i;
				 }
				 
			 }
			 if(y==-1)
			 {
				 if(n%2==1)
				 {
					 pw.println("First");
				 }
				 else
				 {
					 pw.println("Second");
				 }
			 }
			 else
			 {
				 if(y%2==1)
				 {
					 pw.println("Second");
				 }
				 else
				 {
					 pw.println("First");
				 }
			 }
			   

		   }
		  
		      
		 
		  pw.flush();
		  pw.close();
	  }
	    
	    
	
}