Problem: There is a given string S consisting of N symbols. Your task is to find the number of ordered pairs of integers i and j such that

1. 1 ≤ i, j ≤ N

2. S[i] = S[j], that is the i-th symbol of string S is equal to the j-th.

Input

The single input line contains S, consisting of lowercase Latin letters and digits. It is guaranteed that string S in not empty and its length does not exceed 105.

Output

Print a single number which represents the number of pairs i and j with the needed property. Pairs (x, y) and (y, x) should be considered different, i.e. the ordered pairs count.

Examples

Input

great10


Output

7


Input

aaaaaaaaaa


Output

100

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int N, M;
long long contadores[255];
char entrada[100003];
int i;
long long cantidad;
int main() {
  gets(entrada);
  i = 0;
  memset(contadores, 0, sizeof(contadores));
  while (entrada[i] != '\0') {
    ++contadores[entrada[i]];
    ++i;
  }
  cantidad = 0;
  for (i = 0; i < 255; ++i) {
    cantidad += contadores[i] * contadores[i];
  }
  cout << cantidad << endl;
}