Problem: You are given a positive integer n, it is guaranteed that n is even (i.e. divisible by 2).

You want to construct the array a of length n such that: 

  * The first n/2 elements of a are even (divisible by 2); 
  * the second n/2 elements of a are odd (not divisible by 2); 
  * all elements of a are distinct and positive; 
  * the sum of the first half equals to the sum of the second half (∑_{i=1}^{n/2} a_i = ∑_{i=n/2 + 1}^{n} a_i). 



If there are multiple answers, you can print any. It is not guaranteed that the answer exists.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains one integer n (2 ≤ n ≤ 2 ⋅ 10^5) — the length of the array. It is guaranteed that that n is even (i.e. divisible by 2).

It is guaranteed that the sum of n over all test cases does not exceed 2 ⋅ 10^5 (∑ n ≤ 2 ⋅ 10^5).

Output

For each test case, print the answer — "NO" (without quotes), if there is no suitable answer for the given test case or "YES" in the first line and any suitable array a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9) satisfying conditions from the problem statement on the second line.

Example

Input


5
2
4
6
8
10


Output


NO
YES
2 4 1 5
NO
YES
2 4 6 8 1 3 5 11
NO

Solution (in PYTHON3):

Solution:
n = int(input())
count = 0

dat = []
while count < n:
    s = int(input())
    dat.append(s)
    count += 1


for x in dat :
    if ((x//2)%2 != 0):
        print ("NO")

    else:
        even=[]
        odd = []
        count = 1
        print ("YES")
        for y in range(1,(x//2)):
            odd.append(count)
            count += 1
            even.append(count)
            count += 1

        count += 1
        even.append(count)
        sum_even = sum(even)
        sum_odd = sum(odd)
        last_odd = sum_even - sum_odd
        odd.append(last_odd)
        total = ""
        for x in even:
            total+= str(x)
            total += " "
        for z in odd:
            total+= str(z)
            total+=" "
        print (total)