Problem: There is a given string S consisting of N symbols. Your task is to find the number of ordered pairs of integers i and j such that

1. 1 ≤ i, j ≤ N

2. S[i] = S[j], that is the i-th symbol of string S is equal to the j-th.

Input

The single input line contains S, consisting of lowercase Latin letters and digits. It is guaranteed that string S in not empty and its length does not exceed 105.

Output

Print a single number which represents the number of pairs i and j with the needed property. Pairs (x, y) and (y, x) should be considered different, i.e. the ordered pairs count.

Examples

Input

great10


Output

7


Input

aaaaaaaaaa


Output

100

Solution (in PYTHON3):

Solution:
from collections import Counter
import math



#print ("Digite a string")
my_string = str (input())

counter = Counter (my_string)
#print (counter)
sum = 0
for line in counter:
    #print (str(counter[str(line)]))
    sum = sum + math.pow(int (counter[line]),2)
    
print (int(sum))