Problem: You are given four integers: H, W, h and w (1 ≤ h ≤ H, 1 ≤ w ≤ W). Determine whether there exists a matrix such that all of the following conditions are held, and construct one such matrix if the answer is positive:

* The matrix has H rows and W columns.
* Each element of the matrix is an integer between -10^9 and 10^9 (inclusive).
* The sum of all the elements of the matrix is positive.
* The sum of all the elements within every subrectangle with h rows and w columns in the matrix is negative.

Constraints

* 1 ≤ h ≤ H ≤ 500
* 1 ≤ w ≤ W ≤ 500

Input

Input is given from Standard Input in the following format:


H W h w


Output

If there does not exist a matrix that satisfies all of the conditions, print `No`.

Otherwise, print `Yes` in the first line, and print a matrix in the subsequent lines in the following format:


a_{11} ... a_{1W}
:
a_{H1} ... a_{HW}


Here, a_{ij} represents the (i,\ j) element of the matrix.

Examples

Input

3 3 2 2


Output

Yes
1 1 1
1 -4 1
1 1 1


Input

2 4 1 2


Output

No


Input

3 4 2 3


Output

Yes
2 -5 8 7
3 -5 -4 -5
2 1 -1 7

Solution (in CPP):

Solution:
#include<cstdio>
#include<algorithm>
using namespace std;
int W,H,w,h,sum,ans[510][510],v;
int main(){
    scanf("%d%d%d%d",&H,&W,&h,&w);
    if(H%h==0&&W%w==0){puts("No");return 0;}
    v=500*500/(w*h-1);
    for(int i=1;i<=H;i++)
        for(int j=1;j<=W;j++){
            if(i%h==0&&j%w==0)ans[i][j]=-(w*h-1)*v-1;
            else ans[i][j]=v;
            sum+=ans[i][j];
        }
    if(sum>0){
        puts("Yes");
        for(int i=1;i<=H;i++,puts(""))
            for(int j=1;j<=W;j++)
                printf("%d ",ans[i][j]);
    }
    else puts("No");
}