Problem: This problem is actually a subproblem of problem G from the same contest.

There are n candies in a candy box. The type of the i-th candy is a_i (1 ≤ a_i ≤ n).

You have to prepare a gift using some of these candies with the following restriction: the numbers of candies of each type presented in a gift should be all distinct (i. e. for example, a gift having two candies of type 1 and two candies of type 2 is bad). 

It is possible that multiple types of candies are completely absent from the gift. It is also possible that not all candies of some types will be taken to a gift.

Your task is to find out the maximum possible size of the single gift you can prepare using the candies you have.

You have to answer q independent queries.

If you are Python programmer, consider using PyPy instead of Python when you submit your code.

Input

The first line of the input contains one integer q (1 ≤ q ≤ 2 ⋅ 10^5) — the number of queries. Each query is represented by two lines.

The first line of each query contains one integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the number of candies.

The second line of each query contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ n), where a_i is the type of the i-th candy in the box.

It is guaranteed that the sum of n over all queries does not exceed 2 ⋅ 10^5.

Output

For each query print one integer — the maximum possible size of the single gift you can compose using candies you got in this query with the restriction described in the problem statement.

Example

Input


3
8
1 4 8 4 5 6 3 8
16
2 1 3 3 4 3 4 4 1 3 2 2 2 4 1 1
9
2 2 4 4 4 7 7 7 7


Output


3
10
9

Note

In the first query, you can prepare a gift with two candies of type 8 and one candy of type 5, totalling to 3 candies.

Note that this is not the only possible solution — taking two candies of type 4 and one candy of type 6 is also valid.

Solution (in JAVA):

Solution:
//package src;

import java.util.Scanner;
import java.util.HashMap;
import java.util.HashSet;
import java.util.Iterator;
import java.util.PriorityQueue;
import java.util.Queue;
import java.util.Stack;
import java.util.StringTokenizer;
import java.util.TreeMap;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Collections;
import java.util.Comparator;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.lang.StringBuilder;
import java.math.BigInteger;

public class idk {
	static Scanner scn = new Scanner(System.in);
	static int mod = 1000000007;

	public static void main(String args[]) {
		int t = scn.nextInt();
		while (t-- > 0) {
			int n = scn.nextInt();
			int arr[] = new int[n+1], max = 0,ans=0;
			HashMap<Integer, Integer> map = new HashMap<Integer, Integer>();
			for (int i = 0; i < n; i++) {
				int x=scn.nextInt();
				arr[x]++;
			}
			Arrays.parallelSort(arr);
			max=arr[n];
			//System.out.println(max);
			for(int i=n-1;i>0;i--)
			{
				if(arr[i]>=max)
				{
					max--;
					ans+=max;
				}
				else
				{
					max=arr[i];
					ans+=arr[i];
				}
				if(max<=0)
					break;
			}
			max=arr[n];
			System.out.println(ans+max);
		}

	}

	public static int decode(String str, int i, int[] memo) {
		if (i == 0) {
			return 1;
		}
		int ind = str.length() - i;
		if (str.charAt(ind) == '0')
			return 0;
		if (memo[i] != -1)
			return memo[i];
		int res = decode(str, i - 1, memo);
		if (i >= 2 && Integer.parseInt(str.substring(ind, ind + 2)) <= 26) {
			res += decode(str, i - 2, memo);
		}
		memo[i] = res;
		return res;
	}

	public static long gcd(long a, long b) {
		if (a == 0)
			return b;
		return gcd(b % a, a);
	}

	public static String factorial(int n) {
		BigInteger fac = new BigInteger("1");
		for (int i = 1; i <= n; i++) {
			fac = fac.multiply(BigInteger.valueOf(i));
		}
		return fac.toString();
	}

}

class pair {
	int a;
	int b;

	pair(int x, int y) {
		this.a = x;
		this.b = y;
	}
}

class sorting implements Comparator<pair> {

	@Override
	public int compare(pair o1, pair o2) {
		// TODO Auto-generated method stub
		int x=o1.a-o2.a,y=o1.b-o2.b;
		if(y==0)
		{
			if(x>=0)
				return -1;
				else
					return 1;
		}
		else if(y>0)
			return -1;
		else
			return 1;
	}

}