Problem: Valera loves segments. He has recently come up with one interesting problem.

The Ox axis of coordinates has n segments, the i-th segment starts in position li and ends in position ri (we will mark it as [li, ri]). Your task is to process m queries, each consists of number cnti and a set of cnti coordinates of points located on the Ox axis. The answer to the query is the number of segments, such that each of them contains at least one point from the query. Segment [l, r] contains point q, if l ≤ q ≤ r.

Valera found the solution of this problem too difficult. So he asked you to help him. Help Valera. 

Input

The first line contains two integers n, m (1 ≤ n, m ≤ 3·105) — the number of segments on the axis of coordinates and the number of queries. 

Next n lines contain the descriptions of the segments. The i-th line contains two positive integers li, ri (1 ≤ li ≤ ri ≤ 106) — the borders of the i-th segment.

Next m lines contain the description of the queries, one per line. Each line starts from integer cnti (1 ≤ cnti ≤ 3·105) — the number of points in the i-th query. Then the line contains cnti distinct positive integers p1, p2, ..., pcnti (1 ≤ p1 < p2 < ... < pcnti ≤ 106) — the coordinates of points in the i-th query.

It is guaranteed that the total number of points in all queries doesn't exceed 3·105. 

Output

Print m non-negative integers, where the i-th number is the response to the i-th query.

Examples

Input

3 3
1 3
4 5
6 7
3 1 4 7
2 4 5
1 8


Output

3
1
0

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.*;

public class Main {

    public static void main(String[] args) throws Exception {
        Scanner sc = new Scanner(System.in);
        PrintWriter out = new PrintWriter(System.out);

        int n = sc.nextInt(), m = sc.nextInt();
        Event[] evs = new Event[(n << 1) + 300_000];
        for(int i = 0; i < n; ++i) {
            int l = sc.nextInt(), r = sc.nextInt();
            evs[i << 1] = new Event(l, i, 0);
            evs[i << 1 | 1] = new Event(r, i, 2);
        }

        int sz = n << 1;
        for(int i = 0; i < m; ++i) {
            int k = sc.nextInt();
            while(k-->0)
                evs[sz++] = new Event(sc.nextInt(), i, 1);
        }
        Arrays.sort(evs, 0, sz);

        FenwickTree ft = new FenwickTree(n);
        int[] ans = new int[m], id = new int[n], lst = new int[m];
        for(int i = 0, j = 0; i < sz; ++i) {
            Event ev = evs[i];
            if(ev.type == 0) {  // open interval
                ft.update(id[ev.i] = ++j, 1);
            }
            else if(ev.type == 1) { // query point
                ans[ev.i] += ft.query(lst[ev.i] + 1, j);
                lst[ev.i] = j;
            }
            else {  // close interval
                ft.update(id[ev.i], -1);
            }
        }
        for(int a: ans)
            out.println(a);
        out.close();
    }

    static class FenwickTree {

        int[] ft;

        FenwickTree(int n) { ft = new int[n + 1]; }

        int query(int l, int r) {
            if(l > r)
                return 0;
            return query(r) - query(l - 1);
        }

        int query(int idx) {
            int s = 0;
            while(idx > 0) {
                s += ft[idx];
                idx ^= idx & -idx;
            }
            return s;
        }

        void update(int idx, int val) {
            while(idx < ft.length) {
                ft[idx] += val;
                idx += idx & -idx;
            }
        }
    }

    static class Event implements Comparable<Event> {
        int t, i, type;

        Event(int a, int b, int c) { t = a; i = b; type = c; }

        @Override
        public int compareTo(Event o) {
            if(t != o.t)
                return t - o.t;
            return type - o.type;
        }
    }

    static class Scanner {
        StringTokenizer st;
        BufferedReader br;

        public Scanner(InputStream s) {
            br = new BufferedReader(new InputStreamReader(s));
        }

        public Scanner(FileReader s) {
            br = new BufferedReader(s);
        }

        public String next() throws IOException {
            while (st == null || !st.hasMoreTokens())
                st = new StringTokenizer(br.readLine());
            return st.nextToken();
        }

        public int nextInt() throws IOException {
            return Integer.parseInt(next());
        }

        public long nextLong() throws IOException {
            return Long.parseLong(next());
        }

        public String nextLine() throws IOException {
            return br.readLine();
        }
    }
}