Problem: This problem is actually a subproblem of problem G from the same contest.

There are n candies in a candy box. The type of the i-th candy is a_i (1 ≤ a_i ≤ n).

You have to prepare a gift using some of these candies with the following restriction: the numbers of candies of each type presented in a gift should be all distinct (i. e. for example, a gift having two candies of type 1 and two candies of type 2 is bad). 

It is possible that multiple types of candies are completely absent from the gift. It is also possible that not all candies of some types will be taken to a gift.

Your task is to find out the maximum possible size of the single gift you can prepare using the candies you have.

You have to answer q independent queries.

If you are Python programmer, consider using PyPy instead of Python when you submit your code.

Input

The first line of the input contains one integer q (1 ≤ q ≤ 2 ⋅ 10^5) — the number of queries. Each query is represented by two lines.

The first line of each query contains one integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the number of candies.

The second line of each query contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ n), where a_i is the type of the i-th candy in the box.

It is guaranteed that the sum of n over all queries does not exceed 2 ⋅ 10^5.

Output

For each query print one integer — the maximum possible size of the single gift you can compose using candies you got in this query with the restriction described in the problem statement.

Example

Input


3
8
1 4 8 4 5 6 3 8
16
2 1 3 3 4 3 4 4 1 3 2 2 2 4 1 1
9
2 2 4 4 4 7 7 7 7


Output


3
10
9

Note

In the first query, you can prepare a gift with two candies of type 8 and one candy of type 5, totalling to 3 candies.

Note that this is not the only possible solution — taking two candies of type 4 and one candy of type 6 is also valid.

Solution (in PYTHON3):

Solution:
q = int(input())

min1 = 0
max1 = 0

def cnt(candies):
  temp = candies[0]
  j = 1
  ans = []
  for i in range(1 , len(candies)):
    if(candies[i] == candies[i - 1]):
      j += 1
    else:
      ans.append(j)
      j = 1
  ans.append(j)
  return ans

for i in range(q):
  n = int(input())
  candies = input()
  candies = candies.split(' ')
  candies = [int(c) for c in candies]
  candies.sort()
  counted = cnt(candies)
  counted.sort(reverse =True)
  ans = 0
  temp = -1
  for item in counted:
    if(temp == 0):
      break
    if(temp > 0 and item >= temp):
      temp = temp - 1
      ans += temp
    else:
      ans += item
      temp = item
  print(ans)