Problem: There is a given string S consisting of N symbols. Your task is to find the number of ordered pairs of integers i and j such that

1. 1 ≤ i, j ≤ N

2. S[i] = S[j], that is the i-th symbol of string S is equal to the j-th.

Input

The single input line contains S, consisting of lowercase Latin letters and digits. It is guaranteed that string S in not empty and its length does not exceed 105.

Output

Print a single number which represents the number of pairs i and j with the needed property. Pairs (x, y) and (y, x) should be considered different, i.e. the ordered pairs count.

Examples

Input

great10


Output

7


Input

aaaaaaaaaa


Output

100

Solution (in JAVA):

Solution:
import java.math.BigInteger;
import java.util.*;

public class pairs {
	public static void main(String[] args){
		String S;
		Scanner input = new Scanner(System.in);
		
		S = input.next();
		int A[] = new int[1000];
		
		for(int i=0;i<S.length();i++)
		{
			A[(int)S.charAt(i)]++;
		}
		
		long count = 0;
		for(int i=0;i<A.length;i++)
		{
			count = count + (long)A[i]*A[i];
		}
		
		System.out.println(count);
	}
}