Problem: There is a given string S consisting of N symbols. Your task is to find the number of ordered pairs of integers i and j such that

1. 1 ≤ i, j ≤ N

2. S[i] = S[j], that is the i-th symbol of string S is equal to the j-th.

Input

The single input line contains S, consisting of lowercase Latin letters and digits. It is guaranteed that string S in not empty and its length does not exceed 105.

Output

Print a single number which represents the number of pairs i and j with the needed property. Pairs (x, y) and (y, x) should be considered different, i.e. the ordered pairs count.

Examples

Input

great10


Output

7


Input

aaaaaaaaaa


Output

100

Solution (in JAVA):

Solution:
import java.util.*;
import java.io.*;
import java.math.*;

public class Str {

	public static void main(String[] args) 
		throws FileNotFoundException{
		Scanner in = new Scanner(System.in);
		String s = in.nextLine();
		long [] c = new long[256];
		for (int i = 0; i < s.length(); i++) {
			c[s.charAt(i)]++;
		}
		long rez = 0;
		for (int i = 'a'; i <= 'z'; i++) {
			rez += (c[i]-1)*c[i]+c[i];
		}
		for (int i = '0'; i <= '9'; i++) {
			rez +=  (c[i]-1)*c[i]+c[i];
		}
		System.out.print(rez);
	}
}