Problem: You are given a positive integer n, it is guaranteed that n is even (i.e. divisible by 2).

You want to construct the array a of length n such that: 

  * The first n/2 elements of a are even (divisible by 2); 
  * the second n/2 elements of a are odd (not divisible by 2); 
  * all elements of a are distinct and positive; 
  * the sum of the first half equals to the sum of the second half (∑_{i=1}^{n/2} a_i = ∑_{i=n/2 + 1}^{n} a_i). 



If there are multiple answers, you can print any. It is not guaranteed that the answer exists.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains one integer n (2 ≤ n ≤ 2 ⋅ 10^5) — the length of the array. It is guaranteed that that n is even (i.e. divisible by 2).

It is guaranteed that the sum of n over all test cases does not exceed 2 ⋅ 10^5 (∑ n ≤ 2 ⋅ 10^5).

Output

For each test case, print the answer — "NO" (without quotes), if there is no suitable answer for the given test case or "YES" in the first line and any suitable array a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9) satisfying conditions from the problem statement on the second line.

Example

Input


5
2
4
6
8
10


Output


NO
YES
2 4 1 5
NO
YES
2 4 6 8 1 3 5 11
NO

Solution (in PYTHON3):

Solution:
class Bit:
    def __init__(self, n):
        self.size = n
        self.tree = [0] * (n + 1)
        self.depth = n.bit_length()

    def sum(self, i):
        s = 0
        while i > 0:
            s += self.tree[i]
            i -= i & -i
        return s

    def add(self, i, x):
        while i <= self.size:
            self.tree[i] += x
            i += i & -i

    def lower_bound(self, x):
        sum_ = 0
        pos = 0
        for i in range(self.depth, -1, -1):
            k = pos + (1 << i)
            if k <= self.size and sum_ + self.tree[k] < x:
                sum_ += self.tree[k]
                pos += 1 << i
        return pos + 1, sum_


t = int(input())
buf = []
for _ in range(t):
    n, k = map(int, input().split())
    aaa = list(map(int, input().split()))
    bit = Bit(2 * k + 1)
    for a0, a1 in zip(aaa[:n // 2], reversed(aaa[n // 2:])):
        mn = min(a0, a1)
        mx = max(a0, a1)
        sm = a0 + a1
        bit.add(mn + 1, 1)
        bit.add(sm, 1)
        bit.add(sm + 1, -1)
        bit.add(mx + k + 1, -1)
    ans = max(bit.sum(s) for s in range(2, 2 * k + 1))
    buf.append(n - ans)

print('\n'.join(map(str, buf)))