Problem: There is a given string S consisting of N symbols. Your task is to find the number of ordered pairs of integers i and j such that

1. 1 ≤ i, j ≤ N

2. S[i] = S[j], that is the i-th symbol of string S is equal to the j-th.

Input

The single input line contains S, consisting of lowercase Latin letters and digits. It is guaranteed that string S in not empty and its length does not exceed 105.

Output

Print a single number which represents the number of pairs i and j with the needed property. Pairs (x, y) and (y, x) should be considered different, i.e. the ordered pairs count.

Examples

Input

great10


Output

7


Input

aaaaaaaaaa


Output

100

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int main() {
  long long int count = 0, c;
  int j;
  string s;
  cin >> s;
  sort(s.begin(), s.end());
  unsigned int l = s.length();
  for (unsigned int i = 0; i < l; ++i) {
    c = 0;
    char p = s[i];
    for (j = i; j < l; j++) {
      if (s[j] != p) break;
      if (s[j] == p) c++;
    }
    count += c * c;
    i = j - 1;
  }
  cout << count;
}