Problem: You are given a positive integer n, it is guaranteed that n is even (i.e. divisible by 2).

You want to construct the array a of length n such that: 

  * The first n/2 elements of a are even (divisible by 2); 
  * the second n/2 elements of a are odd (not divisible by 2); 
  * all elements of a are distinct and positive; 
  * the sum of the first half equals to the sum of the second half (∑_{i=1}^{n/2} a_i = ∑_{i=n/2 + 1}^{n} a_i). 



If there are multiple answers, you can print any. It is not guaranteed that the answer exists.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains one integer n (2 ≤ n ≤ 2 ⋅ 10^5) — the length of the array. It is guaranteed that that n is even (i.e. divisible by 2).

It is guaranteed that the sum of n over all test cases does not exceed 2 ⋅ 10^5 (∑ n ≤ 2 ⋅ 10^5).

Output

For each test case, print the answer — "NO" (without quotes), if there is no suitable answer for the given test case or "YES" in the first line and any suitable array a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9) satisfying conditions from the problem statement on the second line.

Example

Input


5
2
4
6
8
10


Output


NO
YES
2 4 1 5
NO
YES
2 4 6 8 1 3 5 11
NO

Solution (in PYTHON3):

Solution:



T = int(input())
results = []
results2 = []
for case in range(1, T + 1):
    n = int(input())
    if ((n // 2) % 2 == 1):
        results.append('NO')
    else:
        arr = []
        su = 0
        for i in range(n // 2):
            num = (i + 1) * 2
            su += num
            arr.append(num)
        su2 = 0
        for i in range(n // 2 - 1):
            num = i * 2 + 1
            su2 += num
            arr.append(num)
        arr.append(su - su2)
        results.append('YES')
        results2.append(arr)

for result in results:
    print (result)
    if (result == 'YES'):
        print (' '.join([str(i) for i in results2.pop(0)]))