Problem: There is a given string S consisting of N symbols. Your task is to find the number of ordered pairs of integers i and j such that

1. 1 ≤ i, j ≤ N

2. S[i] = S[j], that is the i-th symbol of string S is equal to the j-th.

Input

The single input line contains S, consisting of lowercase Latin letters and digits. It is guaranteed that string S in not empty and its length does not exceed 105.

Output

Print a single number which represents the number of pairs i and j with the needed property. Pairs (x, y) and (y, x) should be considered different, i.e. the ordered pairs count.

Examples

Input

great10


Output

7


Input

aaaaaaaaaa


Output

100

Solution (in JAVA):

Solution:
import java.util.*;
import java.io.*;
import java.text.*;
import java.math.*;

public class Main {
    public static FastIO file = new FastIO();

    private static void solve() {
        long[] arr = new long[256];
        String s = nextLine();
        for (int i = 0; i < s.length(); i++) {
            arr[s.charAt(i)]++;
        }
        long count = 0, local;
        for (int i = 0; i < 256; i++) {
            local = arr[i] * arr[i];
            count += local;
        }
        System.out.println(count);
    }


    private static int[] nextArray(int n) {
        int[] a = new int[n];
        for (int i = 0; i < n; i++) a[i] = nextInt();
        return a;
    }

    public static int[][] nextArray2D(int n, int m) {
        int[][] result = new int[n][];
        for (int i = 0; i < n; i++) {
            result[i] = nextArray(m);
        }
        return result;
    }

    public static long pow(long n, long p) {
        long ret = 1L;
        while (p > 0) {
            if (p % 2 != 0L)
                ret *= n;
            n *= n;
            p >>= 1L;
        }
        return ret;
    }

    public static String next() {
        return file.next();
    }

    public static int nextInt() {
        return file.nextInt();
    }

    public static long nextLong() {
        return file.nextLong();
    }

    public static double nextDouble() {
        return file.nextDouble();
    }

    public static String nextLine() {
        return file.nextLine();
    }

    public static class FastIO {
        BufferedReader br;
        StringTokenizer st;
        PrintWriter out;

        public FastIO() {
            br = new BufferedReader(new InputStreamReader(System.in));
            out = new PrintWriter(System.out);
        }

        String next() {
            while (st == null || !st.hasMoreElements()) {
                try {
                    st = new StringTokenizer(br.readLine());
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
            return st.nextToken();
        }

        int nextInt() {
            return Integer.parseInt(next());
        }

        long nextLong() {
            return Long.parseLong(next());
        }

        double nextDouble() {
            return Double.parseDouble(next());
        }

        String nextLine() {
            String str = "";
            try {
                str = br.readLine();
            } catch (IOException e) {
                e.printStackTrace();
            }
            return str;
        }
    }

    public static void main(String[] args) throws IOException {
        solve();
    }


}