Problem: There is a given string S consisting of N symbols. Your task is to find the number of ordered pairs of integers i and j such that

1. 1 ≤ i, j ≤ N

2. S[i] = S[j], that is the i-th symbol of string S is equal to the j-th.

Input

The single input line contains S, consisting of lowercase Latin letters and digits. It is guaranteed that string S in not empty and its length does not exceed 105.

Output

Print a single number which represents the number of pairs i and j with the needed property. Pairs (x, y) and (y, x) should be considered different, i.e. the ordered pairs count.

Examples

Input

great10


Output

7


Input

aaaaaaaaaa


Output

100

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int kei[0x100];
int de(char a) {
  if (a <= 'z' && a >= 'a')
    return (a - 'a');
  else
    return (a - '0') + 26;
}
int main() {
  int i;
  string s;
  long long out = 0;
  memset(kei, 0, sizeof(kei));
  cin >> s;
  for (i = 0; i < s.size(); i++) kei[s[i]]++;
  for (i = 0; i < 0x100; i++) out += (long long)kei[i] * kei[i];
  cout << out << endl;
  return 0;
}