Problem: Valera loves segments. He has recently come up with one interesting problem.

The Ox axis of coordinates has n segments, the i-th segment starts in position li and ends in position ri (we will mark it as [li, ri]). Your task is to process m queries, each consists of number cnti and a set of cnti coordinates of points located on the Ox axis. The answer to the query is the number of segments, such that each of them contains at least one point from the query. Segment [l, r] contains point q, if l ≤ q ≤ r.

Valera found the solution of this problem too difficult. So he asked you to help him. Help Valera. 

Input

The first line contains two integers n, m (1 ≤ n, m ≤ 3·105) — the number of segments on the axis of coordinates and the number of queries. 

Next n lines contain the descriptions of the segments. The i-th line contains two positive integers li, ri (1 ≤ li ≤ ri ≤ 106) — the borders of the i-th segment.

Next m lines contain the description of the queries, one per line. Each line starts from integer cnti (1 ≤ cnti ≤ 3·105) — the number of points in the i-th query. Then the line contains cnti distinct positive integers p1, p2, ..., pcnti (1 ≤ p1 < p2 < ... < pcnti ≤ 106) — the coordinates of points in the i-th query.

It is guaranteed that the total number of points in all queries doesn't exceed 3·105. 

Output

Print m non-negative integers, where the i-th number is the response to the i-th query.

Examples

Input

3 3
1 3
4 5
6 7
3 1 4 7
2 4 5
1 8


Output

3
1
0

Solution (in JAVA):

Solution:
//package codeforces;

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.util.*;

public class E {
    BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
    PrintWriter writer = new PrintWriter(System.out);
    StringTokenizer stringTokenizer;

    String next() throws IOException {
        while (stringTokenizer == null || !stringTokenizer.hasMoreTokens()) {
            stringTokenizer = new StringTokenizer(reader.readLine());
        }
        return stringTokenizer.nextToken();
    }

    int nextInt() throws IOException {
        return Integer.parseInt(next());
    }

    long nextLong() throws IOException {
        return Long.parseLong(next());
    }

    void solve() throws IOException {
        final int n = nextInt();
        final int m = nextInt();
        List<Event> events = new ArrayList<>(2 * n);
        for(int i = 0; i < n; i++) {
            events.add(new Event(nextInt(), nextInt()));
        }
        int[] ans = new int[m];
        for(int k = 0; k < m; k++) {
            int prev = 0;
            for(int i = nextInt(); i > 0; i--) {
                int cur = nextInt();
                events.add(new Query(prev, cur, ans, k));
                prev = cur;
            }
            events.add(new Query(prev, 1000 * 1000 + 1, ans, k));
        }
        Collections.sort(events);
        SegmentTree segmentTree = new SegmentTree();
        for(Event event: events) {
            event.eventAction(segmentTree);
        }
        for(int x: ans) {
            writer.println(n - x);
        }
        writer.flush();
        writer.close();

    }

    class SegmentTree {
        int q = 1 << 20;
        int[] a = new int[2 * q];

        void add(int i, int x) {
            for(i += q; i > 0; i >>= 1) {
                a[i] += x;
            }
        }

        int sum(int l, int r) {
            int ret = 0;
            for(l += q, r += q; l < r; l >>= 1, r >>= 1) {
                if(l % 2 == 1) {
                    ret += a[l++];
                }
                if(r % 2 == 1) {
                    ret += a[--r];
                }
            }
            return ret;
        }
    }

    class Event implements Comparable<Event> {
        int l, r;
        int tier;

        Event(int l, int r) {
            this.l = l;
            this.r = r;
        }

        @Override
        public int compareTo(Event o) {
            if(r == o.r) {
                return tier - o.tier;
            }
            return r - o.r;
        }

        public void eventAction(SegmentTree segmentTree) {
            segmentTree.add(l, 1);
        }
    }

    class Query extends Event {
        int[] queryAnswers;
        int queryNumber;

        Query(int l, int r, int[] queryAnswers, int queryNumber) {
            super(l, r);
            this.queryAnswers = queryAnswers;
            this.queryNumber = queryNumber;
            tier = -1;
        }

        @Override
        public void eventAction(SegmentTree segmentTree) {
            queryAnswers[queryNumber] += segmentTree.sum(l + 1, r);
        }
    }

    public static void main(String[] args) throws IOException {
        new E().solve();
    }
}