Problem: There is a given string S consisting of N symbols. Your task is to find the number of ordered pairs of integers i and j such that

1. 1 ≤ i, j ≤ N

2. S[i] = S[j], that is the i-th symbol of string S is equal to the j-th.

Input

The single input line contains S, consisting of lowercase Latin letters and digits. It is guaranteed that string S in not empty and its length does not exceed 105.

Output

Print a single number which represents the number of pairs i and j with the needed property. Pairs (x, y) and (y, x) should be considered different, i.e. the ordered pairs count.

Examples

Input

great10


Output

7


Input

aaaaaaaaaa


Output

100

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.FileReader;
import java.io.FileWriter;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.OutputStreamWriter;
import java.io.PrintWriter;
import java.math.BigInteger;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Collections;
import java.util.HashMap;
import java.util.HashSet;
import java.util.LinkedList;
import java.util.PriorityQueue;
import java.util.Queue;
import java.util.Scanner;
import java.util.StringTokenizer;
import java.util.concurrent.LinkedBlockingDeque;

import javax.swing.border.Border;

public class a {

	public static long mod = (long) Math.pow(10, 9) + 7;

	private static class node {
		int x;
		int y;

		node(int x, int c) {
			this.x = x;
			this.y = c;

		}

	}

	public static void main(String[] args) throws IOException {
		BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
		StringBuilder qq = new StringBuilder();
		PrintWriter out = new PrintWriter(new OutputStreamWriter(System.out));

		String y = in.readLine();
		char e[] = y.toCharArray();
		Arrays.sort(e);
		long ans = y.length();
		long c = 1;
		for (int i = 1; i < e.length; i++) {
			if (e[i] == e[i - 1])
				c++;
			else {

				ans += (long) c * ((long) c - 1);
				c = 1;

			}
		}

		ans += (long) c * ((long) c - 1);
		System.out.println(ans);

		out.close();

	}
}