Problem: There is a given string S consisting of N symbols. Your task is to find the number of ordered pairs of integers i and j such that

1. 1 ≤ i, j ≤ N

2. S[i] = S[j], that is the i-th symbol of string S is equal to the j-th.

Input

The single input line contains S, consisting of lowercase Latin letters and digits. It is guaranteed that string S in not empty and its length does not exceed 105.

Output

Print a single number which represents the number of pairs i and j with the needed property. Pairs (x, y) and (y, x) should be considered different, i.e. the ordered pairs count.

Examples

Input

great10


Output

7


Input

aaaaaaaaaa


Output

100

Solution (in JAVA):

Solution:
print(function(s) {
	var cnt = new Int32Array(256);
	for (var i = 0; i < 256; i++)
		cnt[i] = 1;
	var ans = 0;
	for (var i = 0; i < s.length; i++) {
		ans += cnt[s.charCodeAt(i)];
		cnt[s.charCodeAt(i)] += 2;
	}
	return ans;
}(readline()));