Problem: You are given a positive integer n, it is guaranteed that n is even (i.e. divisible by 2).

You want to construct the array a of length n such that: 

  * The first n/2 elements of a are even (divisible by 2); 
  * the second n/2 elements of a are odd (not divisible by 2); 
  * all elements of a are distinct and positive; 
  * the sum of the first half equals to the sum of the second half (∑_{i=1}^{n/2} a_i = ∑_{i=n/2 + 1}^{n} a_i). 



If there are multiple answers, you can print any. It is not guaranteed that the answer exists.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains one integer n (2 ≤ n ≤ 2 ⋅ 10^5) — the length of the array. It is guaranteed that that n is even (i.e. divisible by 2).

It is guaranteed that the sum of n over all test cases does not exceed 2 ⋅ 10^5 (∑ n ≤ 2 ⋅ 10^5).

Output

For each test case, print the answer — "NO" (without quotes), if there is no suitable answer for the given test case or "YES" in the first line and any suitable array a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9) satisfying conditions from the problem statement on the second line.

Example

Input


5
2
4
6
8
10


Output


NO
YES
2 4 1 5
NO
YES
2 4 6 8 1 3 5 11
NO

Solution (in PYTHON3):

Solution:
import math
t=int(input())
for i in range(t):
    n=int(input())
    a=[]
    d=int(n/2)
    i=1
    while(d>0):
        a.append(2*i)
        i=i+1
        d=d-1
    sum1=sum(a)
    k=0
    d=int(n/2)
    i=1
    while(d>0):
        if(k==n/2-1 and sum1%2!=0):
            if(sum1 not in a):
                a.append(sum1)
                sum1=0
                k=k+1
                break
            else:
                break
        elif(sum1>=i):
            sum1=sum1-i
            a.append(i)
            k=k+1
            i=i+2
            d=d-1
    if(sum1==0 and k==n/2):
        print("YES")
        print(*a)
    else:
        print("NO")