Problem: There is a given string S consisting of N symbols. Your task is to find the number of ordered pairs of integers i and j such that

1. 1 ≤ i, j ≤ N

2. S[i] = S[j], that is the i-th symbol of string S is equal to the j-th.

Input

The single input line contains S, consisting of lowercase Latin letters and digits. It is guaranteed that string S in not empty and its length does not exceed 105.

Output

Print a single number which represents the number of pairs i and j with the needed property. Pairs (x, y) and (y, x) should be considered different, i.e. the ordered pairs count.

Examples

Input

great10


Output

7


Input

aaaaaaaaaa


Output

100

Solution (in PYTHON):

Solution:
# -*- coding: utf-8 -*- 
import itertools, math, random, re, string, sys
from bisect import *
from collections import *
from decimal import *
from fractions import *
from itertools import combinations, permutations, product
from math import ceil, exp, log, sqrt
from Queue import *
getcontext().prec = 100
sys.setrecursionlimit(100000)
MOD = 10 ** 9 + 7
INF = float('+inf')

s = raw_input()
ans = 0
c = Counter(s)
for x in c:
    ans += c[x] ** 2
print ans