Problem: You are given a positive integer n, it is guaranteed that n is even (i.e. divisible by 2).

You want to construct the array a of length n such that: 

  * The first n/2 elements of a are even (divisible by 2); 
  * the second n/2 elements of a are odd (not divisible by 2); 
  * all elements of a are distinct and positive; 
  * the sum of the first half equals to the sum of the second half (∑_{i=1}^{n/2} a_i = ∑_{i=n/2 + 1}^{n} a_i). 



If there are multiple answers, you can print any. It is not guaranteed that the answer exists.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains one integer n (2 ≤ n ≤ 2 ⋅ 10^5) — the length of the array. It is guaranteed that that n is even (i.e. divisible by 2).

It is guaranteed that the sum of n over all test cases does not exceed 2 ⋅ 10^5 (∑ n ≤ 2 ⋅ 10^5).

Output

For each test case, print the answer — "NO" (without quotes), if there is no suitable answer for the given test case or "YES" in the first line and any suitable array a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9) satisfying conditions from the problem statement on the second line.

Example

Input


5
2
4
6
8
10


Output


NO
YES
2 4 1 5
NO
YES
2 4 6 8 1 3 5 11
NO

Solution (in PYTHON3):

Solution:
import sys
from math import log2,floor,ceil,sqrt
# import bisect
# from collections import deque

# from types import GeneratorType
# def bootstrap(func, stack=[]):
#     def wrapped_function(*args, **kwargs):
#         if stack:
#             return func(*args, **kwargs)
#         else:
#             call = func(*args, **kwargs)
#             while True:
#                 if type(call) is GeneratorType:
#                     stack.append(call)
#                     call = next(call)
#                 else:
#                     stack.pop()
#                     if not stack:
#                         break
#                     call = stack[-1].send(call)
#             return call
#     return wrapped_function

Ri = lambda : [int(x) for x in sys.stdin.readline().split()]
ri = lambda : sys.stdin.readline().strip()
 
def input(): return sys.stdin.readline().strip()
def list2d(a, b, c): return [[c] * b for i in range(a)]
def list3d(a, b, c, d): return [[[d] * c for j in range(b)] for i in range(a)]
def list4d(a, b, c, d, e): return [[[[e] * d for j in range(c)] for j in range(b)] for i in range(a)]
def ceil(x, y=1): return int(-(-x // y))
def INT(): return int(input())
def MAP(): return map(int, input().split())
def LIST(N=None): return list(MAP()) if N is None else [INT() for i in range(N)]
def Yes(): print('Yes')
def No(): print('No')
def YES(): print('YES')
def NO(): print('NO')
INF = 10 ** 18
MOD = 10**9+7

for _ in range(int(ri())):
    # n = int(ri())
    n,k =Ri()
    a = Ri()

    dp = [0]*(2*k+2)
    dic = {}
    for i in range(n//2):
        if a[i]+a[n-i-1] in dic:
            dic[a[i] + a[n-i-1]]+=1
        else:
            dic[a[i] + a[n-1-i]] = 1
    
    for i in range(n//2):
        dp[k+max(a[i],a[n-1-i])+1]-=1
        dp[1+min(a[i],a[n-1-i])]+=1
    
    for i in range(1,2*k+2):
        dp[i]= dp[i-1]+dp[i]
    
    minn = INF
    for i in range(2,2*k+1):
        no = 0
        if i in dic:
            no = dic[i]
        cost = dp[i] - no
        # print(cost)
        cost += 2*(n//2 - dp[i])
        # print(cost,dp[i])
        # if n%2 == 1:
        #     if 
        if n%2 == 1:
            if a[n//2] != i:
                cost+=1
        minn = min(minn,cost)
    print(minn)