Problem: There is a given string S consisting of N symbols. Your task is to find the number of ordered pairs of integers i and j such that

1. 1 ≤ i, j ≤ N

2. S[i] = S[j], that is the i-th symbol of string S is equal to the j-th.

Input

The single input line contains S, consisting of lowercase Latin letters and digits. It is guaranteed that string S in not empty and its length does not exceed 105.

Output

Print a single number which represents the number of pairs i and j with the needed property. Pairs (x, y) and (y, x) should be considered different, i.e. the ordered pairs count.

Examples

Input

great10


Output

7


Input

aaaaaaaaaa


Output

100

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
const int maxn = 100000 + 10;
char s[maxn];
long long a[maxn];
using namespace std;
int main() {
  while (scanf("%s", s) != EOF) {
    memset(a, 0, sizeof(a));
    long long sum = 0;
    long long len = strlen(s);
    for (int i = 0; i < len; i++) {
      if (s[i] >= 'a' && s[i] <= 'z')
        a[s[i] - 'a']++;
      else
        a[s[i] - '0' + 26]++;
    }
    for (int i = 0; i <= 35; i++) sum += a[i] * a[i];
    cout << sum << endl;
  }
  return 0;
}