Problem: Polycarp loves ciphers. He has invented his own cipher called repeating.

Repeating cipher is used for strings. To encrypt the string s=s_{1}s_{2} ... s_{m} (1 ≤ m ≤ 10), Polycarp uses the following algorithm:

  * he writes down s_1 ones, 
  * he writes down s_2 twice, 
  * he writes down s_3 three times, 
  * ... 
  * he writes down s_m m times. 



For example, if s="bab" the process is: "b" → "baa" → "baabbb". So the encrypted s="bab" is "baabbb".

Given string t — the result of encryption of some string s. Your task is to decrypt it, i. e. find the string s.

Input

The first line contains integer n (1 ≤ n ≤ 55) — the length of the encrypted string. The second line of the input contains t — the result of encryption of some string s. It contains only lowercase Latin letters. The length of t is exactly n.

It is guaranteed that the answer to the test exists.

Output

Print such string s that after encryption it equals t.

Examples

Input


6
baabbb


Output


bab

Input


10
ooopppssss


Output


oops

Input


1
z


Output


z

Solution (in PYTHON3):

Solution:
t=input()
i=0
j=len(t)-1
l=[]
if len(t)==1:
    print(t)
else:    
    if len(t)%2==0:
        while(i<j):
            l.append(t[j])
            j=j-1
            l.append(t[i])
            i=i+1
    else:
        while(i<=j):
            if i==j:
                l.append(t[i])
                break
            else:
                l.append(t[i])
                i=i+1
                l.append(t[j])
                j=j-1
    l=l[::-1]
    s=""        
    for i in l:
        s=s+i
    print(s)