Problem: There is a given string S consisting of N symbols. Your task is to find the number of ordered pairs of integers i and j such that

1. 1 ≤ i, j ≤ N

2. S[i] = S[j], that is the i-th symbol of string S is equal to the j-th.

Input

The single input line contains S, consisting of lowercase Latin letters and digits. It is guaranteed that string S in not empty and its length does not exceed 105.

Output

Print a single number which represents the number of pairs i and j with the needed property. Pairs (x, y) and (y, x) should be considered different, i.e. the ordered pairs count.

Examples

Input

great10


Output

7


Input

aaaaaaaaaa


Output

100

Solution (in JAVA):

Solution:
import java.util.Scanner;

public class JavaApplication1 {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        String s = scanner.next();
        long count = 0L;
        long a[] = new long [36]; 
        for (int i = 0; i < s.length(); i++) {
            if (s.charAt(i) >= 'a' && s.charAt(i) <= 'z')
                a[s.charAt(i) - 'a']++;
            else
                a[s.charAt(i) - '0' + 'z' - 'a' + 1]++;
        }
        for (int i = 0; i < a.length; i++) {
            count+= a[i] * a[i];
        }
        
        
        System.out.println(count);
        }

    }