Problem: There is a given string S consisting of N symbols. Your task is to find the number of ordered pairs of integers i and j such that

1. 1 ≤ i, j ≤ N

2. S[i] = S[j], that is the i-th symbol of string S is equal to the j-th.

Input

The single input line contains S, consisting of lowercase Latin letters and digits. It is guaranteed that string S in not empty and its length does not exceed 105.

Output

Print a single number which represents the number of pairs i and j with the needed property. Pairs (x, y) and (y, x) should be considered different, i.e. the ordered pairs count.

Examples

Input

great10


Output

7


Input

aaaaaaaaaa


Output

100

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int main() {
  string S;
  cin >> S;
  int length = S.length();
  vector<long long int> was(36, 0);
  for (int i = 0; i < length; ++i) {
    if (S[i] <= 57) {
      ++was[S[i] - 48];
    } else {
      ++was[S[i] - 87];
    }
  }
  long long int res = 0;
  for (int i = 0; i < 36; ++i) {
    res += was[i] * was[i];
  }
  cout << res;
  return 0;
}