Problem: 

Input

The first line contains a single integer n (1 ≤ n ≤ 1000) — the number of points on a plane.

Each of the next n lines contains two real coordinates xi and yi of the <image> point, specified with exactly 2 fractional digits. All coordinates are between  - 1000 and 1000, inclusive.

Output

Output a single real number θ — the answer to the problem statement. The absolute or relative error of your answer should be at most 10 - 2.

Examples

Input

8
-2.14 2.06
-1.14 2.04
-2.16 1.46
-2.14 0.70
-1.42 0.40
-0.94 -0.48
-1.42 -1.28
-2.16 -1.62


Output

5.410


Input

5
2.26 1.44
2.28 0.64
2.30 -0.30
1.58 0.66
3.24 0.66


Output

5.620


Input

8
6.98 2.06
6.40 1.12
5.98 0.24
5.54 -0.60
7.16 0.30
7.82 1.24
8.34 0.24
8.74 -0.76


Output

5.480


Input

5
10.44 2.06
10.90 0.80
11.48 -0.48
12.06 0.76
12.54 2.06


Output

6.040


Input

8
16.94 2.42
15.72 2.38
14.82 1.58
14.88 0.50
15.76 -0.16
16.86 -0.20
17.00 0.88
16.40 0.92


Output

6.040


Input

7
20.62 3.00
21.06 2.28
21.56 1.36
21.66 0.56
21.64 -0.52
22.14 2.32
22.62 3.04


Output

6.720

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int n;
double a, b, Sig1, Sig2;
inline int gcd(int x, int y) {
  if (!y) return x;
  return gcd(y, x % y);
}
inline int read(int &x) {
  char ch;
  int N = 1;
  while ((ch = getchar()) && (!((ch >= '0') && (ch <= '9'))) && (!(ch == '-')))
    ;
  if ((ch == '-')) {
    N = -1;
    while ((ch = getchar()) && (!((ch >= '0') && (ch <= '9'))))
      ;
  }
  x = ch - 48;
  while ((ch = getchar()) && (((ch >= '0') && (ch <= '9'))))
    x = x * 10 + ch - 48;
  x *= N;
}
int main() {
  scanf("%d", &n);
  for (int i = 1; i <= n; i++) {
    scanf("%lf %lf", &a, &b);
    Sig1 += a;
    Sig2 += b;
  }
  Sig1 += 0.1;
  printf("%lf\n", Sig2 / n + Sig2 / Sig1 / 10000 + 5);
}