Problem: When Serezha was three years old, he was given a set of cards with letters for his birthday. They were arranged into words in the way which formed the boy's mother favorite number in binary notation. Serezha started playing with them immediately and shuffled them because he wasn't yet able to read. His father decided to rearrange them. Help him restore the original number, on condition that it was the maximum possible one. 

Input

The first line contains a single integer n (1 ⩽ n ⩽ 10^5) — the length of the string. The second line contains a string consisting of English lowercase letters: 'z', 'e', 'r', 'o' and 'n'.

It is guaranteed that it is possible to rearrange the letters in such a way that they form a sequence of words, each being either "zero" which corresponds to the digit 0 or "one" which corresponds to the digit 1.

Output

Print the maximum possible number in binary notation. Print binary digits separated by a space. The leading zeroes are allowed.

Examples

Input


4
ezor


Output


0 


Input


10
nznooeeoer


Output


1 1 0 

Note

In the first example, the correct initial ordering is "zero".

In the second example, the correct initial ordering is "oneonezero".

Solution (in PYTHON):

Solution:
import decimal,math
from collections import *
from fractions import gcd
from bisect import bisect_right,bisect_left
import sys

def primeFactors(n): 
	arr=[]
	while n % 2 == 0: 
		arr.append(2) 
		n = n / 2
	for i in xrange(3,int(math.sqrt(n))+1,2): 
		while n % i== 0: 
			arr.append(i) 
			n = n / i 
	if n > 2: 
		arr.append(n)
		# print n
	return arr	 

def SieveOfEratosthenes(n): 
	prime = [True for i in xrange(n+1)] 
	p = 2
	while (p * p <= n): 
		if (prime[p] == True): 
			
			for i in xrange(p * p, n+1, p): 
				prime[i] = False
		p += 1
	arr=[]
	for p in xrange(2, n): 
		if prime[p]: 
			arr.append(p)
	return arr

def invmod(i,mod):
	return pow(i,mod-2,mod)	
def fact(mod):
	fac= [1,1]
	ifac = [1,1]
	for i in xrange(2,(3*10**5+ 2)):
		fac.append((fac[-1]*i)%mod)
		ifac.append((ifac[-1]*invmod(i,mod))%mod)
	return fac,ifac	
def divisors(n) : 
	list = []  
	for i in range(1, int(math.sqrt(n) + 1)) : 
		  
		if (n % i == 0) : 
			if (n / i == i) :
				list.append(i) 
			else : 
				list.append(i)
				list.append(int(n / i)) 
	list.sort()
	return list
				
def fi():
	return int(sys.stdin.readline())
 
def fi2():
	return map(int, sys.stdin.readline().split())
 
def fi3():
	return sys.stdin.readline()
 
def fo(*args):
	for s in args:
		sys.stdout.write(str(s)+" ")
	sys.stdout.write('\n')

decimal.getcontext().prec = 15

dic=defaultdict(list)

n = fi()
s = fi3()
s = list(s)
z = s.count('n')
o = s.count('z')
arr= ['1']*z + ['0']*o

fo(*arr)