Problem: A permutation is a sequence of integers p1, p2, ..., pn, consisting of n distinct positive integers, each of them doesn't exceed n. Let's denote the i-th element of permutation p as pi. We'll call number n the size of permutation p1, p2, ..., pn.

Nickolas adores permutations. He likes some permutations more than the others. He calls such permutations perfect. A perfect permutation is such permutation p that for any i (1 ≤ i ≤ n) (n is the permutation size) the following equations hold ppi = i and pi ≠ i. Nickolas asks you to print any perfect permutation of size n for the given n.

Input

A single line contains a single integer n (1 ≤ n ≤ 100) — the permutation size.

Output

If a perfect permutation of size n doesn't exist, print a single integer -1. Otherwise print n distinct integers from 1 to n, p1, p2, ..., pn — permutation p, that is perfect. Separate printed numbers by whitespaces.

Examples

Input

1


Output

-1


Input

2


Output

2 1 


Input

4


Output

2 1 4 3 

Solution (in JAVA):

Solution:
import java.util.Scanner;

public class PerfectPermutation {
    public static void main(String[] args) {
        Scanner scan = new Scanner(System.in);

        int n = scan.nextInt();
        StringBuilder sb = new StringBuilder();
        if((n & 1) != 1) {
            for (int i = 1; i + 1 <= n; i += 2) {
                sb.append((i + 1) + " " + i + " ");
            }
        }

        if(sb.length() == 0) {
            System.out.print(-1);
        }else {
            System.out.print(sb);
        }
    }
}