Problem: A permutation is a sequence of integers p1, p2, ..., pn, consisting of n distinct positive integers, each of them doesn't exceed n. Let's denote the i-th element of permutation p as pi. We'll call number n the size of permutation p1, p2, ..., pn.

Nickolas adores permutations. He likes some permutations more than the others. He calls such permutations perfect. A perfect permutation is such permutation p that for any i (1 ≤ i ≤ n) (n is the permutation size) the following equations hold ppi = i and pi ≠ i. Nickolas asks you to print any perfect permutation of size n for the given n.

Input

A single line contains a single integer n (1 ≤ n ≤ 100) — the permutation size.

Output

If a perfect permutation of size n doesn't exist, print a single integer -1. Otherwise print n distinct integers from 1 to n, p1, p2, ..., pn — permutation p, that is perfect. Separate printed numbers by whitespaces.

Examples

Input

1


Output

-1


Input

2


Output

2 1 


Input

4


Output

2 1 4 3 

Solution (in JAVA):

Solution:

import java.util.*;

public class Perfect_Permutation {

    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        int n = in.nextInt();
        if (n % 2 == 1) {
            System.out.println("-1");
            return;
        }
        StringBuilder out = new StringBuilder();
        int[] ans = new int[n];
        ans[0] = 2;
        out.append(ans[0] + " ");
        for (int i = 1; i < n; i++) {
            if (i % 2 == 1) {
                ans[i] = ans[i - 1] - 1;
            } else {
                ans[i] = ans[i - 2] + 2;
            }
            out.append(ans[i] + " ");
        }
        out.deleteCharAt(out.length()-1);
        System.out.println(out);
    }
}