Problem: On a history lesson the teacher asked Vasya to name the dates when n famous events took place. He doesn't remembers the exact dates but he remembers a segment of days [li, ri] (inclusive) on which the event could have taken place. However Vasya also remembers that there was at most one event in one day. Help him choose such n dates of famous events that will fulfill both conditions. It is guaranteed that it is possible.

Input

The first line contains one integer n (1 ≤ n ≤ 100) — the number of known events. Then follow n lines containing two integers li and ri each (1 ≤ li ≤ ri ≤ 107) — the earliest acceptable date and the latest acceptable date of the i-th event.

Output

Print n numbers — the dates on which the events took place. If there are several solutions, print any of them. It is guaranteed that a solution exists.

Examples

Input

3
1 2
2 3
3 4


Output

1 2 3 


Input

2
1 3
1 3


Output

1 2 

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
struct seg {
  int s, e;
  int ind;
  int res;
  bool operator<(const seg& b) const { return s < b.s; }
};
int n;
seg r[111];
bool read() {
  if (scanf("%d", &n) == EOF) return false;
  for (int i = 0; i < n; i++) scanf("%d%d", &r[i].s, &r[i].e), r[i].ind = i;
  return true;
}
struct comp {
  bool operator()(const seg& a, const seg& b) const { return a.e > b.e; }
};
int qres[111];
vector<int> pos;
void process() {
  sort(r, r + n);
  pos.clear();
  for (int i = 0; i < n; i++) {
    for (int j = min(0, r[i].s - 111); j < r[i].s + 111; j++) {
      if (pos.size() == 0)
        pos.push_back(j);
      else if (j > pos[pos.size() - 1])
        pos.push_back(j);
    }
  }
  priority_queue<seg, vector<seg>, comp> heap;
  int cur = 0;
  for (int i = 0; i < pos.size(); i++) {
    while (cur < n && r[cur].s == pos[i]) {
      heap.push(r[cur]);
      cur++;
    }
    if (heap.empty() == false) {
      seg x = heap.top();
      heap.pop();
      qres[x.ind] = pos[i];
    }
  }
  for (int i = 0; i < n; i++) {
    if (i) printf(" ");
    printf("%d", qres[i]);
  }
  puts("");
}
int main() {
  int t = -1;
  while (t-- && read()) process();
  return 0;
}