Problem: You have a full binary tree having infinite levels.

Each node has an initial value. If a node has value x, then its left child has value 2·x and its right child has value 2·x + 1. 

The value of the root is 1. 

You need to answer Q queries. 

There are 3 types of queries: 

  1. Cyclically shift the values of all nodes on the same level as node with value X by K units. (The values/nodes of any other level are not affected).
  2. Cyclically shift the nodes on the same level as node with value X by K units. (The subtrees of these nodes will move along with them).
  3. Print the value of every node encountered on the simple path from the node with value X to the root.



Positive K implies right cyclic shift and negative K implies left cyclic shift. 

It is guaranteed that atleast one type 3 query is present.

Input

The first line contains a single integer Q (1 ≤ Q ≤ 105).

Then Q queries follow, one per line: 

  * Queries of type 1 and 2 have the following format: T X K (1 ≤ T ≤ 2; 1 ≤ X ≤ 1018; 0 ≤ |K| ≤ 1018), where T is type of the query.
  * Queries of type 3 have the following format: 3 X (1 ≤ X ≤ 1018).

Output

For each query of type 3, print the values of all nodes encountered in descending order.

Examples

Input

5
3 12
1 2 1
3 12
2 4 -1
3 8


Output

12 6 3 1 
12 6 2 1 
8 4 2 1 


Input

5
3 14
1 5 -3
3 14
1 3 1
3 14


Output

14 7 3 1 
14 6 3 1 
14 6 2 1 

Note

Following are the images of the first 4 levels of the tree in the first test case:

Original: 

<image>

After query 1 2 1: 

<image>

After query 2 4 -1: 

<image>

Solution (in JAVA):

Solution:
import java.util.*;

public class D {

	public Object solve() {
		int Q = sc.nextInt();

		long [] S = new long [100], P = new long [100];

		for (@SuppressWarnings("unused") int q : rep(Q)) {
			int t = sc.nextInt();
			switch(t) {
			case 1:
				long X = sc.nextLong(), K = sc.nextLong();
				int L = Long.numberOfTrailingZeros(Long.highestOneBit(X));
				S[L] = mod(S[L] + K, bit(L));
				P[L+1] = mod(P[L+1] + K, bit(L));
				break;

			case 2:
				X = sc.nextLong(); K = sc.nextLong();
				L = Long.numberOfTrailingZeros(Long.highestOneBit(X));
				S[L] = mod(S[L] + K, bit(L));
				break;

			case 3:
				X = sc.nextLong();
				L = Long.numberOfTrailingZeros(Long.highestOneBit(X));
				long [] res = new long [L+1]; int R = 0; long B = bit(L);
				while (L > 0) {
					res[R++] = X;
					X -= B;
					X = (X + S[L]) % B;
					X /= 2; B /= 2;
					X = (X + B - P[L]) % B;
					X += B;
					--L;
				}
				res[R] = X;
				print(res);
				break;
			}
		}

		return null;
	}

	private static final boolean ONE_TEST_CASE = true;

	private static void init() {
	}

	private static long bit (int i) { return (1L << i); }
	private static long mod (long x, long mod) { return ((x % mod) + mod) % mod; }
	private static Iterable<Integer> rep (int N) { return rep(0, N); }
	private static Iterable<Integer> rep (final int S, final int T) { return new Iterable<Integer>() { public Iterator<Integer> iterator() { return S < T ? java.util.stream.IntStream.range(S,  T).iterator() : Collections.emptyIterator(); } }; }
	////////////////////////////////////////////////////////////////////////////////////
	private static IOUtils.MyScanner sc = new IOUtils.MyScanner();
	private static Object print (Object o, Object ... A) { IOUtils.print(o, A); return null; }
	private static class IOUtils {
		public static class MyScanner {
			public String next() { newLine(); return line[index++]; }
			public int nextInt() { return Integer.parseInt(next()); }
			public long nextLong() { return Long.parseLong(next()); }
			//////////////////////////////////////////////
			private boolean eol() { return index == line.length; }
			private String readLine() {
				try {
					return r.readLine();
				} catch (Exception e) {
					throw new Error (e);
				}
			}
			private final java.io.BufferedReader r;
			private MyScanner () { this(new java.io.BufferedReader(new java.io.InputStreamReader(System.in))); }
			private MyScanner (java.io.BufferedReader r) {
				try {
					this.r = r;
					while (!r.ready())
						Thread.sleep(1);
					start();
				} catch (Exception e) {
					throw new Error(e);
				}
			}
			private String [] line;
			private int index;
			private void newLine() {
				if (line == null || eol()) {
					line = split(readLine());
					index = 0;
				}
			}
			private String [] split(String s) { return s.length() > 0 ? s.split(" ") : new String [0]; }
		}
		private static String build(Object o, Object ... A) { return buildDelim(" ", o, A); }
		private static String buildDelim(String delim, Object o, Object ... A) {
			StringBuilder b = new StringBuilder();
			append(b, o, delim);
			for (Object p : A)
				append(b, p, delim);
			return b.substring(delim.length());
		}
		//////////////////////////////////////////////////////////////////////////////////
		private static void start() { if (t == 0) t = millis(); }
		private static void append(java.util.function.Consumer<Object> f, java.util.function.Consumer<Object> g, final Object o) {
			if (o.getClass().isArray()) {
				int len = java.lang.reflect.Array.getLength(o);
				for (int i = 0; i < len; ++i)
					f.accept(java.lang.reflect.Array.get(o, i));
			}
			else if (o instanceof Iterable<?>)
				((Iterable<?>)o).forEach(f::accept);
			else
				g.accept(o instanceof Double ? new java.text.DecimalFormat("#.#########").format(o) : o);
		}
		private static void append(final StringBuilder b, Object o, final String delim) {
			append(x -> { append(b, x, delim); }, x -> b.append(delim).append(x), o);
		}
		private static java.io.PrintWriter pw = new java.io.PrintWriter(System.out);
		private static Object print(Object o, Object ... A) { pw.println(build(o, A)); return null; }
		private static void err(Object o, Object ... A) { System.err.println(build(o, A)); }
		private static boolean PRINT;
		private static void write(Object o) {
			err(o, '(', time(), ')');
			if (PRINT)
				pw.println(o);
		}
		private static void exit() {
			IOUtils.pw.close();
			System.out.flush();
			err("------------------");
			err(time());
			System.exit(0);
		}
		private static long t;
		private static long millis() { return System.currentTimeMillis(); }
		private static String time() { return "Time: " + (millis() - t) / 1000.0; }
		private static void run(int N) {
			try { PRINT = System.getProperties().containsKey("PRINT"); }
			catch (Throwable t) {}

			for (int n = 1; n <= N; ++n) {
				Object res = new D().solve();
				if (res != null)
					write("Case #" + n + ": " + build(res));
			}
			exit();
		}
	}
	public static void main(String[] args) {
		init();
		int N = ONE_TEST_CASE ? 1 : sc.nextInt();
		IOUtils.run(N);
	}
}