Problem: This is an interactive problem.

Omkar has just come across a duck! The duck is walking on a grid with n rows and n columns (2 ≤ n ≤ 25) so that the grid contains a total of n^2 cells. Let's denote by (x, y) the cell in the x-th row from the top and the y-th column from the left. Right now, the duck is at the cell (1, 1) (the cell in the top left corner) and would like to reach the cell (n, n) (the cell in the bottom right corner) by moving either down 1 cell or to the right 1 cell each second.

Since Omkar thinks ducks are fun, he wants to play a game with you based on the movement of the duck. First, for each cell (x, y) in the grid, you will tell Omkar a nonnegative integer a_{x,y} not exceeding 10^{16}, and Omkar will then put a_{x,y} uninteresting problems in the cell (x, y). After that, the duck will start their journey from (1, 1) to (n, n). For each cell (x, y) that the duck crosses during their journey (including the cells (1, 1) and (n, n)), the duck will eat the a_{x,y} uninteresting problems in that cell. Once the duck has completed their journey, Omkar will measure their mass to determine the total number k of uninteresting problems that the duck ate on their journey, and then tell you k.

Your challenge, given k, is to exactly reproduce the duck's path, i. e. to tell Omkar precisely which cells the duck crossed on their journey. To be sure of your mastery of this game, Omkar will have the duck complete q different journeys (1 ≤ q ≤ 10^3). Note that all journeys are independent: at the beginning of each journey, the cell (x, y) will still contain a_{x,y} uninteresting tasks.

Interaction

The interaction will begin with a line containing a single integer n (2 ≤ n ≤ 25), the amount of rows and columns in the grid. Read it.

Your program should then print n lines. The x-th line should contain n integers a_{x,1}, a_{x,2}, ..., a_{x,n} satisfying 0 ≤ a_{x,y} ≤ 10^{16}, where a_{x,y} is the amount of uninteresting problems Omkar should place in the cell (x, y).

After that, you will first receive a single integer q, the amount of journeys that the duck will take. q queries will follow; each query will consist of a single line containing an integer k, the amount of uninteresting problems that the duck ate on that journey. After each query, given that you have determined that the duck visited the cells (x_1, y_1), (x_2, y_2), ..., (x_{2n - 1}, y_{2n - 1}) in that order (it should always be true that (x_1, y_1) = (1, 1) and (x_{2n - 1}, y_{2n - 1}) = (n, n)), you should output 2n - 1 lines so that the j-th line contains the two integers x_j, y_j.

Bear in mind that if the sum on your path is k, but your path is different from the actual hidden path, then your solution is still wrong!

After printing each line do not forget to output end of line and flush the output. Otherwise, you will get Idleness limit exceeded. To do this, use:

  * fflush(stdout) or cout.flush() in C++;
  * System.out.flush() in Java;
  * flush(output) in Pascal;
  * stdout.flush() in Python;
  * see documentation for other languages.



Hack Format

To hack, first output a line containing n and another line containing q. It must be true that 2 ≤ n ≤ 25 and 1 ≤ q ≤ 1000. Then, output the q journeys taken by the duck in the same format as described above: for each journey, given that the duck visited the cells (x_1, y_1), (x_2, y_2), ..., (x_{2n - 1}, y_{2n - 1}) in that order, you should output 2n - 1 lines so that the j-th line contains the two integers x_j, y_j. It must be true that (x_1, y_1) = (1, 1) and (x_{2n - 1}, y_{2n - 1}) = (n, n). Additionally, for each j such that 2 ≤ j ≤ 2n - 1, it must be true that 1 ≤ x_j, y_j ≤ n and either (x_j, y_j) = (x_{j - 1} + 1, y_{j - 1}) or (x_j, y_j) = (x_{j - 1}, y_{j - 1} + 1).

Example

Input


4




3
23







26







27









Output


1 2 3 6
4 6 2 10
9 0 7 3
2 8 8 2


1 1
1 2
1 3
2 3
2 4
3 4
4 4

1 1
2 1
3 1
3 2
3 3
3 4
4 4

1 1
1 2
1 3
1 4
2 4
3 4
4 4

Note

The duck's three journeys are illustrated below.

1 + 2 + 3 + 2 + 10 + 3 + 2 = 23 

<image>

1 + 4 + 9 + 0 + 7 + 3 + 2 = 26 

<image>

1 + 2 + 3 + 6 + 10 + 3 + 2 = 27 

<image>

Solution (in JAVA):

Solution:
import java.io.DataInputStream; 
import java.io.FileInputStream; 
import java.io.IOException; 
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.util.Scanner; 
import java.util.StringTokenizer; 
import java.io.BufferedReader; 
import java.util.*;
import java.math.BigInteger; 


public class E{
	public static FastReader fs = new FastReader();
	
	static PrintWriter out = new PrintWriter(System.out);
	
	static void print(int x, int y) {
		x++;
		y++;
		out.println(y+" "+x);
		out.flush();
	}
	
	static void solve() {
		int n=fs.nextInt();
		long[][] grid=new long[n][n];
		for (int i=0; i<n; i++) {
			for (int j=0; j<n; j++) {
				long exp=(i+j-1);
				boolean have=(j%2!=0);
				if (have) grid[i][j]=1l<<exp;
			}
		}
		
		for (int y=0; y<n; y++) {
			for (int x=0; x<n; x++) System.out.print(grid[x][y]+" ");
			out.println();
		}
		out.flush();
		int q=fs.nextInt();
		for (int qq=0; qq<q; qq++) {
			long total=fs.nextLong();
			int x=0, y=0;
			while (x!=n && y!=n) {
				print(x, y);
				if ((total&(1l<<(x+y)))!=0) {
					//should be at odd height
					if (y%2==0) {
						y++;
					}
					else {
						x++;
					}
				}
				else {
					//even height
					if (y%2==0) {
						x++;
					}
					else {
						y++;
					}
				}
			}
			out.flush();
		}
	}
	
	public static void main(String[] args) {
		Thread t = new Thread(null,null,"",1 << 28) {
			public void run() {
				int test_case = 1;
				//test_case = fs.nextInt();
				for(int cs = 1; cs <= test_case; cs++) {
					solve();
				}
				out.close();
			}
		};
		t.start();
		try {
			t.join();
		} catch (InterruptedException e) {
			e.printStackTrace();
		}
	}
	static class FastReader 
    { 
        BufferedReader br; 
        StringTokenizer st; 
  
        public FastReader() 
        { 
            br = new BufferedReader(new
                     InputStreamReader(System.in)); 
        } 
  
        String next() 
        { 
            while (st == null || !st.hasMoreElements()) 
            { 
                try
                { 
                    st = new StringTokenizer(br.readLine()); 
                } 
                catch (IOException  e) 
                { 
                    e.printStackTrace(); 
                } 
            } 
            return st.nextToken(); 
        } 
  
        int nextInt() 
        { 
            return Integer.parseInt(next()); 
        } 
  
        long nextLong() 
        { 
            return Long.parseLong(next()); 
        } 
  
        double nextDouble() 
        { 
            return Double.parseDouble(next()); 
        } 
  
        String nextLine() 
        { 
            String str = ""; 
            try
            { 
                str = br.readLine(); 
            } 
            catch (IOException e) 
            { 
                e.printStackTrace(); 
            } 
            return str; 
        } 
        
        int [] readintarray(int n) {
        	int res [] = new int [n];
        	for(int i = 0; i<n; i++)res[i] = nextInt();
        	return res;
        }
        long [] readlongarray(int n) {
        	long res [] = new long [n];
        	for(int i = 0; i<n; i++)res[i] = nextLong();
        	return res;
        }
    } 
	
	static int ceil(int x,int y) {
		return (x % y == 0 ? x / y : (x / y +1));
	}
	
	static long ceil(long x,long y) {
		return (x % y == 0 ? x / y : (x / y +1));
	}
	
	static int max(int x,int y) {
		return Math.max(x, y);
	}
	
	static int min(int x,int y) {
		return Math.min(x, y);
	}
	
	static long max(long x,long y) {
		return Math.max(x, y);
	}
	
	static long min(long x,long y) {
		return Math.min(x, y);
	}
	
	static int min(int a []) {
		int x = 1_000_000_00_9;
		for(int i = 0; i<a.length; i++)x = min(x,a[i]);
		return x;
	}
	
	static int max(int a []) {
		int x = -1_000_000_00_9;
		for(int i = 0; i<a.length; i++)x = max(x,a[i]);
		return x;
	}
	
	static long min(long a []) {
		long x = (long)3e18;
		for(int i = 0; i<a.length; i++)x = min(x,a[i]);
		return x;
	}
	
	static long max(long a []) {
		long x = -(long)3e18;
		for(int i = 0; i<a.length; i++)x = max(x,a[i]);
		return x;
	}
	
	static int power(int x,int y) {
		int res = 1;
		while(y > 0) {
			if( y % 2 == 1)res = (res * x);
			y >>= 1;
            x = (x * x);
		}
		return res;
	}
	
	static long power(long x,long y) {
		long res = 1;
		while(y > 0) {
			if( y % 2 == 1)res = (res * x);
			y >>= 1;
            x = (x * x);
		}
		return res;
	}
	
	static long power(long x,long y,long mod) {
		long res = 1;
		x %= mod;
		while(y > 0) {
			if( y % 2 == 1)res = (res * x) % mod;
			y >>= 1;
            x = (x * x) % mod;
		}
		return res;
	}
	
	static void intsort(int [] a) {
		List<Integer> temp = new ArrayList<Integer>();
		for(int i = 0; i<a.length; i++)temp.add(a[i]);
		Collections.sort(temp);
		for(int i = 0; i<a.length; i++)a[i] = temp.get(i);
	}
	
	static void longsort(long [] a) {
		List<Long> temp = new ArrayList<Long>();
		for(int i = 0; i<a.length; i++)temp.add(a[i]);
		Collections.sort(temp);
		for(int i = 0; i<a.length; i++)a[i] = temp.get(i);
	}
	
	static void reverseintsort(int [] a) {
		List<Integer> temp = new ArrayList<Integer>();
		for(int i = 0; i<a.length; i++)temp.add(a[i]);
		Collections.sort(temp);
		Collections.reverse(temp);
		for(int i = 0; i<a.length; i++)a[i] = temp.get(i);
	}
	
	static void reverselongsort(long [] a) {
		List<Long> temp = new ArrayList<Long>();
		for(int i = 0; i<a.length; i++)temp.add(a[i]);
		Collections.sort(temp);
		Collections.reverse(temp);
		for(int i = 0; i<a.length; i++)a[i] = temp.get(i);
	}
	
	
	static void intervalsort(int a [],int start,int end) {
		ArrayList<Integer> temp = new ArrayList<>();
		for(int i = start; i<end; i++)
			temp.add(a[i]);
		Collections.sort(temp);
		for(int i = 0; i<temp.size(); i++)
			a[i+start] = temp.get(i);
	}
	
	static void intervalsort(long a [],int start,int end) {
		ArrayList<Long> temp = new ArrayList<>();
		for(int i = start; i<end; i++)
			temp.add(a[i]);
		Collections.sort(temp);
		for(int i = 0; i<temp.size(); i++)
			a[i+start] = temp.get(i);
	}
	
	static void reverseintervalsort(int a [],int start,int end) {
		ArrayList<Integer> temp = new ArrayList<>();
		for(int i = start; i<end; i++)
			temp.add(a[i]);
		Collections.sort(temp);
		Collections.reverse(temp);
		for(int i = 0; i<temp.size(); i++)
			a[i+start] = temp.get(i);
	}
	
	static void reverseintervalsort(long a [],int start,int end) {
		ArrayList<Long> temp = new ArrayList<>();
		for(int i = start; i<end; i++)
			temp.add(a[i]);
		Collections.sort(temp);
		Collections.reverse(temp);
		for(int i = 0; i<temp.size(); i++)
			a[i+start] = temp.get(i);
	}
	
	
	static class data{
		public long sum;
		
		data(long val){
		    this.sum = val;
		}
		
		data(){}
		
		data combine(data l, data r) {
		    data res = new data();
		    res.sum = l.sum + r.sum;
		    return res;
		}
	}
	
	static class Seg_Tree extends data{
		public int n;
		data [] seg;
		
		Seg_Tree(int sz){
			this.n = sz;
			seg = new data[4*n+4];
		}
		
		void build(long a[], int v, int tl, int tr) {
		    if (tl == tr) {
		        seg[v] = new data(a[tl]);
		    } else {
		        int tm = (tl + tr) / 2;
		        build(a, v*2, tl, tm);
		        build(a, v*2+1, tm+1, tr);
		        seg[v] = combine(seg[v*2],seg[v*2+1]);
		    }
		}

		void update(int v, int tl, int tr, int pos, long new_val) {
		    if (tl == tr) {
		        seg[v] = new data(new_val);
		    } else {
		        int tm = (tl + tr) / 2;
		        if (pos <= tm)
		            update(v*2, tl, tm, pos, new_val);
		        else
		            update(v*2+1, tm+1, tr, pos, new_val);
		        seg[v] = combine(seg[v*2],seg[v*2+1]);
		    }
		}
		
		data query(int v, int tl, int tr, int l, int r) {
		    if (l > r) 
		        return new data(0);
		    if (l == tl && r == tr) 
		        return seg[v];
		    int tm = (tl + tr) / 2;
		    return combine(query(v*2, tl, tm, l, min(r, tm)),query(v*2+1, tm+1, tr, max(l, tm+1), r));
		}
	}
	
	static class Bit_Tree{
		static int n;
		static int [] bit;
		
		Bit_Tree(int sz){
			Bit_Tree.n = sz;
			Bit_Tree.bit = new int[n+1];
		}
		
		static int child(int x) {
			return x + (x & (-x));
		}
		
		static int parent(int x) {
			return x - (x & (-x));
		}
		
		static void build(int [] a) {
			for(int i = 0; i<a.length; i++) {
				int start = i+1;
				while(start <= n) {
					bit[start] += a[i];
					start = child(start);
				}
			}
		}
		
		static void update(int idx,int new_val) {
			idx += 1;
			while(idx <= n) {
				bit[idx] += new_val;
				idx = child(idx);
			}
		}
		
		static int query(int right) {
			int res = 0;
			while(right > 0) {
				res += bit[right];
				right = parent(right);
			}
			return res;
		}
		
		static int query(int left,int right) {
			return query(right+1) - query(left);
		}
	}
	
	public static int gcd(int a, int b)  
    { 
        BigInteger b1 = BigInteger.valueOf(a); 
        BigInteger b2 = BigInteger.valueOf(b); 
        BigInteger gcd = b1.gcd(b2); 
            return gcd.intValue(); 
    } 
      
    public static long gcd(long a, long b)  
    { 
        BigInteger b1 = BigInteger.valueOf(a); 
        BigInteger b2 = BigInteger.valueOf(b); 
        BigInteger gcd = b1.gcd(b2); 
            return gcd.longValue(); 
    } 
}