Problem: An open-top box having a square bottom is placed on the floor. You see a number of needles vertically planted on its bottom.

You want to place a largest possible spheric balloon touching the box bottom, interfering with none of the side walls nor the needles.

Java Specific: Submitted Java programs may not use "java.awt.geom.Area". You may use it for your debugging purposes.

Figure H.1 shows an example of a box with needles and the corresponding largest spheric balloon. It corresponds to the first dataset of the sample input below.

<image>
Figure H.1. The upper shows an example layout and the lower shows the largest spheric balloon that can be placed.



Input

The input is a sequence of datasets. Each dataset is formatted as follows.


n w
x1 y1 h1
:
xn yn hn


The first line of a dataset contains two positive integers, n and w, separated by a space. n represents the number of needles, and w represents the height of the side walls.

The bottom of the box is a 100 × 100 square. The corners of the bottom face are placed at positions (0, 0, 0), (0, 100, 0), (100, 100, 0), and (100, 0, 0).

Each of the n lines following the first line contains three integers, xi, yi, and hi. (xi, yi, 0) and hi represent the base position and the height of the i-th needle. No two needles stand at the same position.

You can assume that 1 ≤ n ≤ 10, 10 ≤ w ≤ 200, 0 < xi < 100, 0 < yi < 100 and 1 ≤ hi ≤ 200. You can ignore the thicknesses of the needles and the walls.

The end of the input is indicated by a line of two zeros. The number of datasets does not exceed 1000.

Output

For each dataset, output a single line containing the maximum radius of a balloon that can touch the bottom of the box without interfering with the side walls or the needles. The output should not contain an error greater than 0.0001.

Example

Input

5 16
70 66 40
38 52 20
40 35 10
70 30 10
20 60 10
1 100
54 75 200
1 10
90 10 1
1 11
54 75 200
3 10
53 60 1
61 38 1
45 48 1
4 10
20 20 10
20 80 10
80 20 10
80 80 10
0 0


Output

26.00000
39.00000
130.00000
49.49777
85.00000
95.00000

Solution (in CPP):

Solution:
#include <cmath>
#include <iostream>
#include <vector>
using namespace std;

constexpr double EPS = 1e-9;

struct point {
	double x, y;
	point(double x = 0.0, double y = 0.0):x(x), y(y) {}
	point(const point& p):x(p.x), y(p.y) {}

	point operator+ (const point& p) const {
		return point(x + p.x, y + p.y);
	}

	point operator- (const point& p) const {
		return point(x - p.x, y - p.y);
	}

	point operator* (const double s) const {
		return point(x * s, y * s);
	}

	point operator* (const point& p) const {
		return point(x * p.x - y * p.y, x * p.y + y * p.x);
	}

	point operator/ (const double s) const {
		return point(x / s, y / s);
	}

	bool operator< (const point& p) const {
		return x + EPS < p.x || abs(x - p.x) < EPS && y + EPS < p.y;
	}

	bool operator== (const point& p) const {
		return abs(x - p.x) < EPS && abs(y - p.y) < EPS;
	}
};

inline double angle(const point& p) {
	return atan2(p.y, p.x);
}

inline double abs(const point& p) {
	return sqrt(p.x * p.x + p.y * p.y);
}

inline double norm(const point& p) {
	return p.x * p.x + p.y * p.y;
}

inline double dot(const point& l, const point& r) {
	return l.x * r.x + l.y * r.y;
}

inline double cross(const point& l, const point& r) {
	return l.x * r.y - l.y * r.x;
}

struct line {
	point a, b;
	line(const point& a, const point& b):a(a), b(b){}
};

struct segment {
	point a, b;
	segment(const point& a, const point& b):a(a), b(b){}
};

struct circle {
	point c;
	double r;
	circle(point c, double r):c(c), r(r){}
};

typedef vector<point> polygon;

inline int ccw(const point& a, point b, point c) {
	b = b - a;
	c = c - a;
	const double tmp = cross(b, c);
	if(tmp > EPS) return 1; // ccw
	if(tmp < -EPS) return -1; // cw
	if(dot(b, c) < 0) return 2; // c, a, b 順に一直線上
	if(norm(b) < norm(c)) return -2; // a, b, c 順に一直線上
	return 0; //a, c, b 順で一直線上
}

inline point projection(const line& l, const point& p) {
	const point dif = l.b - l.a;
	const double tmp = dot(p - l.a, dif) / norm(dif);
	return l.a + dif * tmp;
}

inline bool intersect(const line& l, const line& m) {
	return abs(cross(l.b - l.a, m.b - m.a)) > EPS || abs(cross(l.b - l.a, m.b - l.a)) < EPS;
}

inline bool intersect(const line& l, const segment& s) {
	return cross(l.b - l.a, s.a - l.a) * cross(l.b - l.a, s.b - l.a) < EPS;
}

inline bool intersect(const line& l, const point& p) {
	return abs(ccw(l.a, l.b, p)) != -1;
}

inline bool intersect(const segment& s, const segment& t) {
	return ccw(s.a, s.b, t.a) * ccw(s.a, s.b, t.b) <= 0 &&
		ccw(t.a, t.b, s.a) * ccw(t.a, t.b, s.b) <= 0;
}

inline bool intersect(const segment& s, const point& p) {
	return ccw(s.a, s.b, p) == 0;
}

inline bool intersect(const circle& c, const point& p) {
	return abs(c.c - p) <= c.r + EPS;
}

inline bool intersect(const circle& c, const circle& d) {
	return abs(c.c - d.c) <= c.r + d.r && abs(c.c - d.c) >= abs(c.r - d.r);
}

inline double dist(const line& l, const point& p) {
	return abs(cross((l.b - l.a), (p - l.a))) / abs(l.b - l.a);
}

inline double dist(const line& l, const line& m) {
	return intersect(l, m) ? 0 : dist(l, m.a);
}

inline double dist(const line& l, const segment& s) {
	return intersect(l, s) ? 0 : min(dist(l, s.a), dist(l, s.b));
}

inline double dist(const segment& s, const point& p) {
	if(dot((s.b - s.a), (p - s.a)) < 0) return abs(p - s.a);
	if(dot((s.a - s.b), (p - s.b)) < 0) return abs(p - s.b);
	return dist(line(s.a, s.b), p);
}

inline double dist(const segment& s, const segment& t) {
	if(intersect(s, t))
		return 0;
	return min(min(dist(s, t.a), dist(s, t.b)), min(dist(t, s.a), dist(t, s.b)));
}

inline double dist(const point& a, const point& b) {
	return abs(a - b);
}

inline bool intersect(const circle& c, const segment& s) {
	return dist(s, c.c) < c.r + EPS;
}

//先に，intersectを用いて交差判定を行うこと
inline vector<point> crosspoint(const circle &c, const circle& d) {
	vector<point> res;
	if(abs(c.c - d.c) < EPS) // 中心の座標が同じ
		return res;

	const double tmp = abs(c.c - d.c);
	const double rc = (tmp * tmp + c.r * c.r - d.r * d.r) / (tmp + tmp);
	const double rs = sqrt(c.r * c.r - rc * rc);
	const point diff = (d.c - c.c) / tmp;
	res.push_back(point(c.c + diff * point(rc, rs)));
	res.push_back(point(c.c + diff * point(rc, -rs)));
	return res;
}

inline vector<point> crosspoint(const circle& c, const line& l) {
	vector<point> res;
	const point h = projection(l, c.c);
	const double d = abs(h - c.c);
	if(d > c.r - EPS) {
		res.push_back(h);
	}
	else if(d <= c.r - EPS) {
		point v = l.b - l.a;
		v = v * sqrt(c.r * c.r - d * d) / abs(v);
		res.push_back(h + v);
		res.push_back(h - v);
	}

	return res;
}

inline vector<point> crosspoint(const circle& c, const segment& s) {
	vector<point> res;
	vector<point> tmp = crosspoint(c, line(s.a, s.b));
	for(int i = 0; i < tmp.size(); ++i)
		if(intersect(s, tmp[i]))
			res.push_back(tmp[i]);

	return res;
}

// 多角形と点の包含関係．境界を含む．
bool contain(const polygon& P, const point& p) {
	const int n = P.size();
	bool res = false;
	for(int i = 0; i < n; ++i) {
		point v1 = P[i] - p, v2 = P[(i + 1) % n] - p;
		if(v1.y > v2.y)
			swap(v1, v2);

		if(v1.y < EPS && EPS < v2.y && cross(v1, v2) > EPS)
			res = !res;

		if(abs(cross(v1, v2)) < EPS && dot(v1, v2) < EPS)
			return true; // 境界を含まないなら，falseにする．
	}

	return res;
}

constexpr int SIZE = 100;
constexpr int MAX_N = 10;

int n, w;
int x[MAX_N], y[MAX_N], h[MAX_N];

double calc_width(double r, double h) {
	return r < h + EPS ? r : sqrt(r * r - (r - h) * (r - h));
}

polygon calc_polygon(double width) {
	polygon res;
	res.emplace_back(width, width);
	res.emplace_back(width, SIZE - width);
	res.emplace_back(SIZE - width, SIZE - width);
	res.emplace_back(SIZE - width, width);
	return res;
}

vector<circle> calc_circles(double r) {
	vector<circle> circles;
	for(int i = 0; i < n; ++i) {
		circles.emplace_back(point(x[i], y[i]), calc_width(r, h[i]));
	}
	return circles;
}

bool ok(double r) {
	const double width = calc_width(r, w);
	if(width >= 50.0) return false;

	polygon rectangle = calc_polygon(width);
	vector<circle> circles = calc_circles(r);

	vector<point> points(rectangle);
	for(int i = 0; i < n; ++i) {
		for(int j = 0; j < 4; ++j) {
			const segment seg(rectangle[j], rectangle[(j + 1) % 4]);
			const vector<point> cp = crosspoint(circles[i], seg);
			points.insert(points.end(), cp.begin(), cp.end());
		}

		for(int j = i + 1; j < n; ++j) {
			if(intersect(circles[i], circles[j])) {
				const vector<point> cp = crosspoint(circles[i], circles[j]);
				points.insert(points.end(), cp.begin(), cp.end());
			}
		}
	}

	for(const auto &p : points) {
		if(!contain(rectangle, p)) continue;

		for(const auto &c : circles) {
			if(dist(c.c, p) + EPS < c.r) goto next;
		}

		return true;
	next:;
	}
	return false;
}

int main() {
	cin.tie(nullptr);
	ios::sync_with_stdio(false);
	cout.flags(ios::fixed);
	cout.precision(5);

	while(cin >> n >> w && n) {
		for(int i = 0; i < n; ++i) {
			cin >> x[i] >> y[i] >> h[i];
		}

		double low = 0.0, high = 10000.0;
		for(int i = 0; i < 100; ++i) {
			const double mid = (low + high) / 2.0;
			if(ok(mid))
				low = mid;
			else
				high = mid;
		}
		cout << low << endl;
	}
	return EXIT_SUCCESS;
}