Problem: A permutation is a sequence of integers p1, p2, ..., pn, consisting of n distinct positive integers, each of them doesn't exceed n. Let's denote the i-th element of permutation p as pi. We'll call number n the size of permutation p1, p2, ..., pn.

Nickolas adores permutations. He likes some permutations more than the others. He calls such permutations perfect. A perfect permutation is such permutation p that for any i (1 ≤ i ≤ n) (n is the permutation size) the following equations hold ppi = i and pi ≠ i. Nickolas asks you to print any perfect permutation of size n for the given n.

Input

A single line contains a single integer n (1 ≤ n ≤ 100) — the permutation size.

Output

If a perfect permutation of size n doesn't exist, print a single integer -1. Otherwise print n distinct integers from 1 to n, p1, p2, ..., pn — permutation p, that is perfect. Separate printed numbers by whitespaces.

Examples

Input

1


Output

-1


Input

2


Output

2 1 


Input

4


Output

2 1 4 3 

Solution (in JAVA):

Solution:
//package com.company;
import java.math.BigInteger;
import java.util.Locale;
import java.util.Scanner;
import java.util.Arrays;
import java.util.ArrayList;
import java.util.Collections;

public class Main {
    public static void main(String[] args) {
        Scanner sc= new Scanner(System.in);
        int num = sc.nextInt();
        ArrayList<Integer> ans = new ArrayList<Integer>();
        if(num % 2 == 1){
            System.out.println(-1);
        }else {
            for(int i = 1; i <= num ; i++){
                if(i%2 == 1){
                    ans.add(i+1);
                }else {
                    ans.add(i-1);
                }
            }
        }
        for(int i : ans ){
            System.out.print(i +" ");
        }
    }
}