Problem: A permutation is a sequence of integers p1, p2, ..., pn, consisting of n distinct positive integers, each of them doesn't exceed n. Let's denote the i-th element of permutation p as pi. We'll call number n the size of permutation p1, p2, ..., pn.

Nickolas adores permutations. He likes some permutations more than the others. He calls such permutations perfect. A perfect permutation is such permutation p that for any i (1 ≤ i ≤ n) (n is the permutation size) the following equations hold ppi = i and pi ≠ i. Nickolas asks you to print any perfect permutation of size n for the given n.

Input

A single line contains a single integer n (1 ≤ n ≤ 100) — the permutation size.

Output

If a perfect permutation of size n doesn't exist, print a single integer -1. Otherwise print n distinct integers from 1 to n, p1, p2, ..., pn — permutation p, that is perfect. Separate printed numbers by whitespaces.

Examples

Input

1


Output

-1


Input

2


Output

2 1 


Input

4


Output

2 1 4 3 

Solution (in JAVA):

Solution:


import java.util.Scanner;

public class Main {

    public static void main(String[] args) {

        Scanner sc = new Scanner(System.in);
    
        int n = sc.nextInt();
        if(n==1){System.out.println(-1);
            return ;
            
        }
        int cur=0;
        String res ="";
        int c = 0;
        for(int i = 1 ; i<=n;++i)
        {
            if(i%2==0)
            {
                res +=(" "+i+" "+cur);
            c +=2;  
            }
            else
                cur =i;
            
        }
    
        res = new StringBuilder(res).deleteCharAt(0).toString();    
        
        if(c==n)
        {
            System.out.print(res);
        }
        else
            System.out.println(-1);
        
    }

}