Problem: A permutation is a sequence of integers p1, p2, ..., pn, consisting of n distinct positive integers, each of them doesn't exceed n. Let's denote the i-th element of permutation p as pi. We'll call number n the size of permutation p1, p2, ..., pn.

Nickolas adores permutations. He likes some permutations more than the others. He calls such permutations perfect. A perfect permutation is such permutation p that for any i (1 ≤ i ≤ n) (n is the permutation size) the following equations hold ppi = i and pi ≠ i. Nickolas asks you to print any perfect permutation of size n for the given n.

Input

A single line contains a single integer n (1 ≤ n ≤ 100) — the permutation size.

Output

If a perfect permutation of size n doesn't exist, print a single integer -1. Otherwise print n distinct integers from 1 to n, p1, p2, ..., pn — permutation p, that is perfect. Separate printed numbers by whitespaces.

Examples

Input

1


Output

-1


Input

2


Output

2 1 


Input

4


Output

2 1 4 3 

Solution (in JAVA):

Solution:


import java.util.Scanner;

public class Main{

    public static void main(String[] args) {

        Scanner sc = new Scanner(System.in);
    
        int n = sc.nextInt();
        if(n==1){System.out.println(-1);
            return ;
            
        }
        int cur=0;
        String res ="";
        for(int i = 1 ; i<=n;++i)
        {
            if(i%2==0)res +=(" "+i+" "+cur);
            else
                cur =i;
            
        }
        res = new StringBuilder(res).deleteCharAt(0).toString();    
        String[] split = res.split(" ");
        if(split.length==n)
        {
            for(String j : split)System.out.print(j+" ");
        }
        else
            System.out.println(-1);
        
    }

}