Problem: On a history lesson the teacher asked Vasya to name the dates when n famous events took place. He doesn't remembers the exact dates but he remembers a segment of days [li, ri] (inclusive) on which the event could have taken place. However Vasya also remembers that there was at most one event in one day. Help him choose such n dates of famous events that will fulfill both conditions. It is guaranteed that it is possible.

Input

The first line contains one integer n (1 ≤ n ≤ 100) — the number of known events. Then follow n lines containing two integers li and ri each (1 ≤ li ≤ ri ≤ 107) — the earliest acceptable date and the latest acceptable date of the i-th event.

Output

Print n numbers — the dates on which the events took place. If there are several solutions, print any of them. It is guaranteed that a solution exists.

Examples

Input

3
1 2
2 3
3 4


Output

1 2 3 


Input

2
1 3
1 3


Output

1 2 

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
class graph {
 public:
  map<long long, list<long long>> adj;
  long long v;
  list<long long> order;
  void init(vector<long long> &b) {
    v = b.size() - 1;
    for (long long i = 1; i <= v; i++) {
      if (b[i] == -1) continue;
      adj[i].push_back(b[i]);
    }
  }
  void call() {
    unordered_map<long long, bool> visited;
    for (long long i = 1; i <= v; i++)
      if (visited[i] == false) {
        dfs(i, visited);
      }
    reverse(order.begin(), order.end());
  }
  void dfs(long long node, unordered_map<long long, bool> &visited) {
    visited[node] = true;
    for (auto child : adj[node]) {
      if (visited[child] == true) continue;
      dfs(child, visited);
    }
    order.push_back(node);
  }
};
bool comp(pair<long long, pair<long long, long long>> a,
          pair<long long, pair<long long, long long>> b) {
  if (a.second.second <= b.second.second && a.second.first >= b.second.first)
    return true;
  if (b.second.second <= a.second.second && b.second.first >= a.second.first)
    return false;
  if (a.second.second >= b.second.first && a.second.first <= b.second.first)
    return false;
  if (b.second.second >= a.second.first && b.second.first <= a.second.first)
    return true;
  else
    return a.second.second > b.second.second;
}
int32_t main() {
  vector<pair<long long, pair<long long, long long>>> seg;
  long long n;
  cin >> n;
  for (long long i = 0; i < n; ++i) {
    long long s, e;
    cin >> s >> e;
    seg.push_back({i, {s, e}});
  }
  sort(seg.begin(), seg.end(), comp);
  vector<long long> answer(n);
  map<long long, bool> visited;
  for (long long i = 0; i < n; ++i) {
    long long e = seg[i].second.second;
    while (visited[e] == true) e--;
    answer[seg[i].first] = e;
    visited[e] = true;
  }
  for (auto node : answer) cout << node << " ";
  cout << endl;
}