Problem: A permutation is a sequence of integers p1, p2, ..., pn, consisting of n distinct positive integers, each of them doesn't exceed n. Let's denote the i-th element of permutation p as pi. We'll call number n the size of permutation p1, p2, ..., pn.

Nickolas adores permutations. He likes some permutations more than the others. He calls such permutations perfect. A perfect permutation is such permutation p that for any i (1 ≤ i ≤ n) (n is the permutation size) the following equations hold ppi = i and pi ≠ i. Nickolas asks you to print any perfect permutation of size n for the given n.

Input

A single line contains a single integer n (1 ≤ n ≤ 100) — the permutation size.

Output

If a perfect permutation of size n doesn't exist, print a single integer -1. Otherwise print n distinct integers from 1 to n, p1, p2, ..., pn — permutation p, that is perfect. Separate printed numbers by whitespaces.

Examples

Input

1


Output

-1


Input

2


Output

2 1 


Input

4


Output

2 1 4 3 

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
int main() {
  int n;
  scanf("%d", &n);
  if (n % 2 == 1) {
    printf("-1\n");
    return 0;
  }
  int output[102] = {0}, i, j;
  for (i = 1, j = 1; i <= n;) {
    if (i == j) {
      output[++j] = i;
      output[j - 1] = ++i;
      j++;
    } else
      output[j] = i++;
  }
  for (i = 1; i <= n; i++)
    if (output[i] != 0) printf("%d ", output[i]);
}