Problem: Petya once wrote a sad love song and shared it to Vasya. The song is a string consisting of lowercase English letters. Vasya made up q questions about this song. Each question is about a subsegment of the song starting from the l-th letter to the r-th letter. Vasya considers a substring made up from characters on this segment and repeats each letter in the subsegment k times, where k is the index of the corresponding letter in the alphabet. For example, if the question is about the substring "abbcb", then Vasya repeats letter 'a' once, each of the letters 'b' twice, letter 'c" three times, so that the resulting string is "abbbbcccbb", its length is 10. Vasya is interested about the length of the resulting string.

Help Petya find the length of each string obtained by Vasya.

Input

The first line contains two integers n and q (1≤ n≤ 100 000, 1≤ q ≤ 100 000) — the length of the song and the number of questions. 

The second line contains one string s — the song, consisting of n lowercase letters of English letters.

Vasya's questions are contained in the next q lines. Each line contains two integers l and r (1 ≤ l ≤ r ≤ n) — the bounds of the question.

Output

Print q lines: for each question print the length of the string obtained by Vasya.

Examples

Input


7 3
abacaba
1 3
2 5
1 7


Output


4
7
11


Input


7 4
abbabaa
1 3
5 7
6 6
2 4


Output


5
4
1
5


Input


13 7
sonoshikumiwo
1 5
2 10
7 7
1 13
4 8
2 5
3 9


Output


82
125
9
191
62
63
97

Note

In the first example Vasya is interested in three questions. In the first question Vasya considers the substring "aba", that transforms to "abba", so the answer is equal to 4. In the second question Vasya considers "baca", that transforms to "bbaccca", so the answer is 7. In the third question Vasya considers the string "abacaba",that transforms to "abbacccabba" of length 11.

Solution (in CPP):

Solution:
#include<bits/stdc++.h>
// #include <ext/pb_ds/assoc_container.hpp>
// #include <ext/pb_ds/tree_policy.hpp>

using namespace std;
// using namespace __gnu_pbds;

#pragma GCC target ("avx2")
#pragma GCC optimization ("O3")
#pragma GCC optimization ("unroll-loops")

#define fi first
#define se second
#define be_ begin()
#define en_ end()
#define pb push_back
#define mp(a,b) make_pair(a,b)
#define _f0(i,n) for(i = 0; i < ( n ); i ++)
#define _f1(i,n) for(i = 1; i <= ( n ); i ++)
#define _f(i,m,n) for(auto i = ( m ); i <= ( n ); i ++)
#define _in(v) for(auto& _var:v)    cin>>_var;
#define _out(v) for(auto _var:v)    cout<<_var<<" ";
#define _rout(x) for(auto _it=x.rbegin(); _it!=x.rend(); _it++) cout<<(*_it)<<" ";
#define _all(x) x.begin(), x.end()
#define _rall(x) x.rbegin(), x.rend()
#define _loop(x) for(auto& _var:x)
#define _ms(x,n) memset(x,n,sizeof(x))
#define run ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);
#define nl cout<<"\n";
#define loopt int _tc; cin>>_tc; while(_tc--)
#define ordered_set tree<int, null_type,less<int>, rb_tree_tag,tree_order_statistics_node_update>

using ll = long long int;
using ull = unsigned long long int;
using vi = vector<int>;
using vl = vector<ll>;
using ii = pair<int,int>;
using lili = pair<long long int,long long int>;
using vii = vector<ii >;
using vll = vector<lili>;
using viv = vector<vi >;

const ll INF = 1000000005;
const ll mod = ((int)1e9+7);
const ll mod1 = 998244353;

//******************************************************\\

ll _fac(ll n, ll MOD = LLONG_MAX)   {return (n==1||n==0)?1:(n*((_fac(n-1))%MOD))%MOD;}

ll _pow(ll a, ll b, ll MOD = LLONG_MAX)
{
    if(b==0||a==1)  return 1;
    if(a==0)    return 0;
    if(b&1) {ll temp = _pow(a,b/2,MOD)%MOD; return (((temp*temp)%MOD)*a)%MOD;}
    else    {ll temp = _pow(a,b/2,MOD)%MOD; return (temp*temp)%MOD;}
}

ll _powm(ll a, ll b, ll MOD)
{
    ll res = 1; a = a%MOD;
    if(a==0)    return 0;
    while(b>0)
    {
        if(b&1) res = (res*a)%MOD;
        b = b>>1;
        a = (a*a)%MOD;
    }
    return res;
}

ll _gcd(ll a, ll b) {if(b==0)    return a;   return _gcd(b,a%b);}

ll _lcm(ll a, ll b) {return (a*b)/_gcd(a,b);}

ll _nPr(ll n, ll r) {return _fac(n)/_fac(r);}

ll _nCr(ll n, ll r)
{
    if(r>n-r)   r = n-r;
    if(r==0)    return 1;
    ll n1 = 1;
    ll n2 = 1;
    _f(i,1,r)    n1*=i;
    _f(i,n-r+1,n)  n2*=i;
    return n2/n1;
}

ll _invMod(ll a, ll m)  {return _pow(a, m-2, m);}

ll _cat(int n)  {return _nCr(2*n,n)/(n+1);}

ll _msb(ll n)
{
    n |= n>>1;
    n |= n>>2;
    n |= n>>4;
    n |= n>>8;
    n |= n>>16;
    n |= n>>32;
    n++;
    return (n>>1);
}

int _nod(ll n)  {int c = 0;  while(n>0)  {c++; n/=10;}   return c;}

int _nob(ll n)  {int c = 0;  while(n>0)  {c++; n&=(n-1);}   return c;}

bool _isPrime(ll n, int k = 5)
{
    if(n<=1||n==4)  return false;
    if(n<=3)    return true;
    while(k>0)
    {
        ll a = 2 + rand()%(n-4);
        if(_gcd(n,a)!=1)    return false;
        if(_pow(a,n-1,n)!=1)    return false;
        k--;
    }
    return true;
}

ll _lsb(ll n) {
    return (n&(-n));
}

//******************************************************\\

class _rand_ {public: _rand_() {func();}   void func() {srand((unsigned)time(0));}};  _rand_ _rno_;

class fenwickTree {                         // Be careful for the mod
    private:    vl ft;
    public:
        fenwickTree(int n) {
            ft.assign(n+1, 0);
        }
        ll rsq(int b) {
            ll sum = 0;
            for(; b; b-=_lsb(b))    sum+=ft[b];
            return sum;
        }
        ll rsq(int a, int b) {
            return rsq(b) - ((a==1)?0:rsq(a-1));
        }
        void adjust(int i, ll prev, ll nxt) {               // MOD IS USED. BE CAREFUL.
            for(; i<(int)ft.size(); i+=_lsb(i)) {
            ft[i]-=prev;
            ft[i]+=nxt;
            }
        }
        void print() {
            _out(ft); nl;
        }
};

class _udf
{
    private: vi _p, _rank;
    public: _udf(int n)
    {
        _rank.assign(n+1,0);
        _p.assign(n+1,0);
        _f(i,1,n) _p[i] = i;
    }
    int findSet(int i)  {return (_p[i]==i)?i:(_p[i] = findSet(_p[i]));}
    bool isSameSet(int i, int j)   {return findSet(i)==findSet(j);}
    void unionSet(int i, int j)
    {
        if(!isSameSet(i,j))
        {
            int x = findSet(i), y = findSet(j);
            if(_rank[x]>_rank[y]) _p[y] = x;
            else    {_p[x] = y; if(_rank[x]==_rank[y]) _rank[y]++;}
        }
    }
};

clock_t _tstart, _tend;

class ___
{
    public:
        ___(){b();}
        ~___(){e();}
    void b()
    {
        _tstart = clock();
        #ifndef ONLINE_JUDGE
        freopen("input.txt", "r", stdin);
        freopen("output.txt", "w", stdout);
        #endif
    }
    void e()
    {
        _tend = clock();
        #ifndef ONLINE_JUDGE
            nl;nl; cout<<"Time Take: "<<(double)(_tend-_tstart)/(double)(CLOCKS_PER_SEC)<<"s"; nl; nl; nl;
        #endif
    }
}; 
___ __;
//******************************************************\\

/*
a^b=a+b-2*(a&b)
gcd(a,b)=gcd(a,b-a)
gcd(a,b,c)=gcd(a,gcd(b,c))=gcd(gcd(a,b),c)=gcd(a,b-a,c)=gcd(a,c,b-a)=gcd(a,c-a,b-a)
We can use (x & y) == x to check if x is a subset of y. 
    The subset means every state in x could be 1 only if the corresponding state in y is 1.
We can use (x & (y >> 1)) == 0 to check if there are no adjancent valid states in x and y.
    Run ((x >> 1) & y) to also to ensure no adjacency on either sides.
*/

int main() {
	ll n, q;
	cin>>n>>q;
	string s;	cin>>s;
	vl v(n, 0);
	v[0] = (int)(s[0]-96);
	_f(i,1,n-1) {
		v[i] = v[i-1]+(int)(s[i]-96);
	}
	ll ans = 0;
	_f(i,0,q-1) {
		int a, b;	cin>>a>>b;
		a--, b--;
		ans = v[b];
		if(a>0)	ans-=v[a-1];
		cout<<ans;
		nl;
	}
	return 0;
}