Problem: A permutation is a sequence of integers p1, p2, ..., pn, consisting of n distinct positive integers, each of them doesn't exceed n. Let's denote the i-th element of permutation p as pi. We'll call number n the size of permutation p1, p2, ..., pn.

Nickolas adores permutations. He likes some permutations more than the others. He calls such permutations perfect. A perfect permutation is such permutation p that for any i (1 ≤ i ≤ n) (n is the permutation size) the following equations hold ppi = i and pi ≠ i. Nickolas asks you to print any perfect permutation of size n for the given n.

Input

A single line contains a single integer n (1 ≤ n ≤ 100) — the permutation size.

Output

If a perfect permutation of size n doesn't exist, print a single integer -1. Otherwise print n distinct integers from 1 to n, p1, p2, ..., pn — permutation p, that is perfect. Separate printed numbers by whitespaces.

Examples

Input

1


Output

-1


Input

2


Output

2 1 


Input

4


Output

2 1 4 3 

Solution (in JAVA):

Solution:
import java.util.Scanner;

public class Main
{
public static void main(String[] args)
{
Scanner sc = new Scanner(System.in);
int N = sc.nextInt();
if (N % 2 == 1)
{
System.out.println("-1");
}
else{
int[] P = new int[N];
int[] PP = new int[100];

for (int i = 0; i < N/2; i++)
{
P[i]  = i+1;
P[N-1-i] = N-i;
}
for(int i = 0; i < N; i++)
	System.out.print(P[N - i -1]+" ");
}

}
}