Problem: Phoenix loves beautiful arrays. An array is beautiful if all its subarrays of length k have the same sum. A subarray of an array is any sequence of consecutive elements.

Phoenix currently has an array a of length n. He wants to insert some number of integers, possibly zero, into his array such that it becomes beautiful. The inserted integers must be between 1 and n inclusive. Integers may be inserted anywhere (even before the first or after the last element), and he is not trying to minimize the number of inserted integers.

Input

The input consists of multiple test cases. The first line contains an integer t (1 ≤ t ≤ 50) — the number of test cases.

The first line of each test case contains two integers n and k (1 ≤ k ≤ n ≤ 100).

The second line of each test case contains n space-separated integers (1 ≤ a_i ≤ n) — the array that Phoenix currently has. This array may or may not be already beautiful.

Output

For each test case, if it is impossible to create a beautiful array, print -1. Otherwise, print two lines.

The first line should contain the length of the beautiful array m (n ≤ m ≤ 10^4). You don't need to minimize m.

The second line should contain m space-separated integers (1 ≤ b_i ≤ n) — a beautiful array that Phoenix can obtain after inserting some, possibly zero, integers into his array a. You may print integers that weren't originally in array a.

If there are multiple solutions, print any. It's guaranteed that if we can make array a beautiful, we can always make it with resulting length no more than 10^4.

Example

Input


4
4 2
1 2 2 1
4 3
1 2 2 1
3 2
1 2 3
4 4
4 3 4 2


Output


5
1 2 1 2 1
4
1 2 2 1
-1
7
4 3 2 1 4 3 2

Note

In the first test case, we can make array a beautiful by inserting the integer 1 at index 3 (in between the two existing 2s). Now, all subarrays of length k=2 have the same sum 3. There exists many other possible solutions, for example: 

  * 2, 1, 2, 1, 2, 1 
  * 1, 2, 1, 2, 1, 2 



In the second test case, the array is already beautiful: all subarrays of length k=3 have the same sum 5.

In the third test case, it can be shown that we cannot insert numbers to make array a beautiful.

In the fourth test case, the array b shown is beautiful and all subarrays of length k=4 have the same sum 10. There exist other solutions also.

Solution (in PYTHON3):

Solution:

MOD = 10 ** 9 + 7

def main():
    for _ in inputt():
        n, k = inputi()
        A = inputl()
        l = len(set(A))
        if l > k:
            print(-1)
            continue
        l = list(set(A)) + [A[0]] * (k - l)
        l *= len(A)
        print(len(l))
        print(*l)

# region M


# region import
# 所有import部分

from math import *
from heapq import *
from itertools import *
from functools import reduce, lru_cache, partial
from collections import Counter, defaultdict
import re, copy, operator, cmath
import sys, io, os, builtins
sys.setrecursionlimit(1000)

# endregion

# region fastio

BUFSIZE = 8192
class FastIO(io.IOBase):
    newlines = 0
    def __init__(self, file):
        self._fd = file.fileno()
        self.buffer = io.BytesIO()
        self.writable = "x" in file.mode or "r" not in file.mode
        self.write = self.buffer.write if self.writable else None
    def read(self):
        while True:
            b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
            if not b:
                break
            ptr = self.buffer.tell()
            self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
        self.newlines = 0
        return self.buffer.read()
    def readline(self):
        while self.newlines == 0:
            b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
            self.newlines = b.count(b"\n") + (not b)
            ptr = self.buffer.tell()
            self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
        self.newlines -= 1
        return self.buffer.readline()
    def flush(self):
        if self.writable:
            os.write(self._fd, self.buffer.getvalue())
            self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(io.IOBase):
    def __init__(self, file):
        self.buffer = FastIO(file)
        self.flush = self.buffer.flush
        self.writable = self.buffer.writable
        self.write = lambda s: self.buffer.write(s.encode("ascii"))
        self.read = lambda: self.buffer.read().decode("ascii")
        self.readline = lambda: self.buffer.readline().decode("ascii")
def print(*args, **kwargs):
    if args:
        sys.stdout.write(str(args[0]))
        split = kwargs.pop("split", " ")
        for arg in args[1:]:
            sys.stdout.write(split)
            sys.stdout.write(str(arg))
    sys.stdout.write(kwargs.pop("end", "\n"))
def debug(*args, **kwargs):
    print("debug", *args, **kwargs)
    sys.stdout.flush()
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip()
inputt = lambda t = 0: range(t) if t else range(int(input()))
inputs = lambda: input().split()
inputi = lambda k = int: map(k, inputs())
inputl = lambda t = 0, k = lambda: list(inputi()): [k() for _ in range(t)] if t else list(k())

# endregion

# region bisect

def len(a):
    if isinstance(a, range):
        return -((a.start - a.stop) // a.step)
    return builtins.len(a)
def bisect_left(a, x, key = None, lo = 0, hi = None):
    if lo < 0: lo = 0
    if hi == None: hi = len(a)
    if key == None: key = do_nothing
    while lo < hi:
        mid = (lo + hi) // 2
        if key(a[mid]) < x: lo = mid + 1
        else: hi = mid
    return lo
def bisect_right(a, x, key = None, lo = 0, hi = None):
    if lo < 0: lo = 0
    if hi == None: hi = len(a)
    if key == None: key = do_nothing
    while lo < hi:
        mid = (lo + hi) // 2
        if x < key(a[mid]): hi = mid
        else: lo = mid + 1
    return lo
def insort_left(a, x, key = None, lo = 0, hi = None):
    lo = bisect_left(a, x, key, lo, hi)
    a.insert(lo, x)
def insort_right(a, x, key = None, lo = 0, hi = None):
    lo = bisect_right(a, x, key, lo, hi)
    a.insert(lo, x)
do_nothing = lambda x: x
bisect = bisect_right
insort = insort_right
def index(a, x, default = None, key = None, lo = 0, hi = None):
    if lo < 0: lo = 0
    if hi == None: hi = len(a)
    if key == None: key = do_nothing
    i = bisect_left(a, x, key, lo, hi)
    if lo <= i < hi and key(a[i]) == x: return a[i]
    if default != None: return default
    raise ValueError
def find_lt(a, x, default = None, key = None, lo = 0, hi = None):
    if lo < 0: lo = 0
    if hi == None: hi = len(a)
    i = bisect_left(a, x, key, lo, hi)
    if lo < i <= hi: return a[i - 1]
    if default != None: return default
    raise ValueError
def find_le(a, x, default = None, key = None, lo = 0, hi = None):
    if lo < 0: lo = 0
    if hi == None: hi = len(a)
    i = bisect_right(a, x, key, lo, hi)
    if lo < i <= hi: return a[i - 1]
    if default != None: return default
    raise ValueError
def find_gt(a, x, default = None, key = None, lo = 0, hi = None):
    if lo < 0: lo = 0
    if hi == None: hi = len(a)
    i = bisect_right(a, x, key, lo, hi)
    if lo <= i < hi: return a[i]
    if default != None: return default
    raise ValueError
def find_ge(a, x, default = None, key = None, lo = 0, hi = None):
    if lo < 0: lo = 0
    if hi == None: hi = len(a)
    i = bisect_left(a, x, key, lo, hi)
    if lo <= i < hi: return a[i]
    if default != None: return default
    raise ValueError

# endregion

# region csgraph
# TODO

class Tree:
    def __init__(n):
        self._n = n
        self._conn = [[] for _ in range(n)]
        self._list = [0] * n
    def connect(a, b):
        pass

# endregion

# region ntheory

class Sieve:
    def __init__(self):
        self._n = 6
        self._list = [2, 3, 5, 7, 11, 13]
    def extend(self, n):
        if n <= self._list[-1]: return
        maxbase = int(n ** 0.5) + 1
        self.extend(maxbase)
        begin = self._list[-1] + 1
        newsieve = [i for i in range(begin, n + 1)]
        for p in self.primerange(2, maxbase):
            for i in range(-begin % p, len(newsieve), p):
                newsieve[i] = 0
        self._list.extend([x for x in newsieve if x])
    def extend_to_no(self, i):
        while len(self._list) < i: 
            self.extend(int(self._list[-1] * 1.5))
    def primerange(self, a, b):
        a = max(2, a)
        if a >= b: return
        self.extend(b)
        i = self.search(a)[1]
        maxi = len(self._list) + 1
        while i < maxi:
            p = self._list[i - 1]
            if p < b:
                yield p
                i += 1
            else: return
    def search(self, n):
        if n < 2: raise ValueError
        if n > self._list[-1]: self.extend(n)
        b = bisect(self._list, n)
        if self._list[b - 1] == n: return b, b
        else: return b, b + 1
    def __contains__(self, n):
        if n < 2: raise ValueError
        if not n % 2: return n == 2
        a, b = self.search(n)
        return a == b
    def __getitem__(self, n):
        if isinstance(n, slice):
            self.extend_to_no(n.stop + 1)
            return self._list[n.start: n.stop: n.step]
        else:
            self.extend_to_no(n + 1)
            return self._list[n]

sieve = Sieve()
def isprime(n):
    if n <= sieve._list[-1]:
        return n in sieve
    for i in sieve:
        if not n % i: return False
        if n < i * i: return True
prime = sieve.__getitem__
primerange = lambda a, b = 0: sieve.primerange(a, b) if b else sieve.primerange(2, a)
def factorint(n):
    factors = []
    for i in sieve:
        if n < i * i: break
        while not n % i:
            factors.append(i)
            n //= i
    if n != 1: factors.append(n)
    return factors
factordict = lambda n: Counter(factorint(n))

# endregion

# region main

if __name__ == "__main__":
    main()

# endregion


# endregion