Problem: Let's define the cost of a string s as the number of index pairs i and j (1 ≤ i < j < |s|) such that s_i = s_j and s_{i+1} = s_{j+1}.

You are given two positive integers n and k. Among all strings with length n that contain only the first k characters of the Latin alphabet, find a string with minimum possible cost. If there are multiple such strings with minimum cost — find any of them.

Input

The only line contains two integers n and k (1 ≤ n ≤ 2 ⋅ 10^5; 1 ≤ k ≤ 26).

Output

Print the string s such that it consists of n characters, each its character is one of the k first Latin letters, and it has the minimum possible cost among all these strings. If there are multiple such strings — print any of them.

Examples

Input


9 4


Output


aabacadbb


Input


5 1


Output


aaaaa

Input


10 26


Output


codeforces

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
#define boost ios_base::sync_with_stdio(false); cin.tie(NULL);cout.tie(NULL);
#define ll long long int

void input() {return;}
template<typename T1, typename... T2>
    void input(T1 & x, T2&... args){((cin >> x), input(args...));}
void wrt() { cout << endl; return;}
template<typename T1, typename... T2>
    void wrt(T1 x, T2... args){((cout << x << ' '), wrt(args...));}
template<typename T> void inputlst(T & lst, int x, int y)
    { for(int i = x ; i < y; i++ ) cin >> lst[i]; }
template<typename T> void printlst(T & lst, int x, int y)
    { for(int i = x ; i < y; i++ ) cout << lst[i] << " "; cout << endl; }
#define sortlst(lst) sort(lst.begin(), lst.end())
#define setbits(n) __builtin_popcount(n)
#define sortarr(x, n) sort(x, x + n)
#define fora(i, x, y) for (ll i = x; i < y; ++i)
#define ford(i, x, y) for (ll i = x; i >= y; --i)
#define readArr(v) for(auto i : v)cin>>i;
typedef pair<ll, ll> pll;
typedef vector<ll> vl;
typedef vector<int> vi;
typedef vector<vl> vovl;
typedef vector<vi> vovi;
typedef vector<string> vs;
typedef set<ll> sl;
typedef unordered_map<ll, ll> uml;
typedef map<ll, ll> ml;
typedef map<int, int> mi;

//------------------------------------------------------------------------------
int ceil(int a, int b) { int c=a/b; if(a%b != 0)c++; return c; }
//-------------------------------------------------------------------------------
// whole debugging process
#ifndef ONLINE_JUDGE
#define debug(x) cerr << #x<<" "; _print(x); cerr << endl;
#else
#define debug(x);
#endif
 

void _print(int t) {cerr << t;}
void _print(string t) {cerr << t;}
void _print(char t) {cerr << t;}
void _print(double t) {cerr << t;}
void _print(long long int t) { cerr << t;}
 
template <class T, class V> void _print(pair <T, V> p);
template <class T> void _print(vector <T> v);
template <class T> void _print(set <T> v);
template <class T, class V> void _print(map <T, V> v);
template <class T> void _print(multiset <T> v);
template <class T, class V> void _print(pair <T, V> p) {cerr << "{"; _print(p.first); cerr << ","; _print(p.second); cerr << "}";}
template <class T> void _print(vector <T> v) {cerr << "[ "; for (T i : v) {_print(i); cerr << " ";} cerr << "]";}
template <class T> void _print(set <T> v) {cerr << "[ "; for (T i : v) {_print(i); cerr << " ";} cerr << "]";}
template <class T> void _print(multiset <T> v) {cerr << "[ "; for (T i : v) {_print(i); cerr << " ";} cerr << "]";}
template <class T, class V> void _print(map <T, V> v) {cerr << "[ "; for (auto i : v) {_print(i); cerr << " ";} cerr << "]";}
 
 

// ############################# CODE IS HERE ##############################

int n, k;
int cur[26];
vector<ll> path;

void dfs(int v) {
  while (cur[v] < k) {
    int u = cur[v]++;
    // cout<<"U: "<<u<<endl;
    // cout<<"cur: ";for(auto i : cur)cout<<i<<" ";
    // cout<<"\n";
    dfs(u);
    path.push_back(u);
    
  }
}


int main()
{
  #ifndef ONLINE_JUDGE
  freopen("input.txt", "r", stdin);
  freopen("output.txt", "w", stdout);
  freopen("error.txt", "w", stderr);
  #endif
  boost;
  ll test=1; 
  // cin >> test; 
  while(test--)
  {
    input(n,k);
    dfs(0);
    // cout<<" ";for(auto i : path)cout<<(char)(i + 'a');
    // cout<<"\n";
    cout<<'a';
    for (int i = 0; i < n - 1; ++i)
        cout<<((char)(path[i % path.size()] + 'a'));
  }
  return 0;
}