Problem: Vivek has encountered a problem. He has a maze that can be represented as an n × m grid. Each of the grid cells may represent the following:

  * Empty — '.' 
  * Wall — '#' 
  * Good person — 'G' 
  * Bad person — 'B' 



The only escape from the maze is at cell (n, m).

A person can move to a cell only if it shares a side with their current cell and does not contain a wall. Vivek wants to block some of the empty cells by replacing them with walls in such a way, that all the good people are able to escape, while none of the bad people are able to. A cell that initially contains 'G' or 'B' cannot be blocked and can be travelled through.

Help him determine if there exists a way to replace some (zero or more) empty cells with walls to satisfy the above conditions.

It is guaranteed that the cell (n,m) is empty. Vivek can also block this cell.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. The description of the test cases follows.

The first line of each test case contains two integers n, m (1 ≤ n, m ≤ 50) — the number of rows and columns in the maze.

Each of the next n lines contain m characters. They describe the layout of the maze. If a character on a line equals '.', the corresponding cell is empty. If it equals '#', the cell has a wall. 'G' corresponds to a good person and 'B' corresponds to a bad person.

Output

For each test case, print "Yes" if there exists a way to replace some empty cells with walls to satisfy the given conditions. Otherwise print "No"

You may print every letter in any case (upper or lower).

Example

Input


6
1 1
.
1 2
G.
2 2
#B
G.
2 3
G.#
B#.
3 3
#B.
#..
GG.
2 2
#B
B.


Output


Yes
Yes
No
No
Yes
Yes

Note

For the first and second test cases, all conditions are already satisfied.

For the third test case, there is only one empty cell (2,2), and if it is replaced with a wall then the good person at (1,2) will not be able to escape.

For the fourth test case, the good person at (1,1) cannot escape.

For the fifth test case, Vivek can block the cells (2,3) and (2,2).

For the last test case, Vivek can block the destination cell (2, 2).

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.math.BigInteger;
import java.text.DecimalFormat;
import java.util.*;
import java.util.concurrent.ThreadLocalRandom;
import java.util.stream.Collectors;
import java.util.stream.IntStream;
import java.util.stream.LongStream;

public class Main2 {

    static long mod = 1000000007;
    static FastScanner scanner;

    public static void main(String[] args) {
        scanner = new FastScanner();
        int T = scanner.nextInt();

        StringBuilder b = new StringBuilder();
        for (int t = 0; t < T; t++) {
            solve();
        }
        System.out.print(b.toString());
    }

    public static void solve() {
        int n = scanner.nextInt();
        int m = scanner.nextInt();

        int good = 0;
        int bad = 0;
        int[][] a = new int[n][m];
        for (int i = 0; i < n; i++) {
            String s = scanner.nextLine();
            for (int j = 0; j < m; j++) {
                switch (s.charAt(j)) {
                    case '#':
                        a[i][j] = 1;
                        break;
                    case 'G':
                        a[i][j] = 2;
                        good++;
                        break;
                    case 'B':
                        a[i][j] = 3;
                        bad++;
                        break;
                    default:
                }
            }
        }
        if (good == 0) {
            System.out.println("Yes");
            return;
        }
        for (int i = 0; i < n; i++) {
            for (int j = 0; j < m; j++) {
                if (a[i][j] != 3) continue;
                if (i > 0) {
                    if (a[i - 1][j] == 0) a[i - 1][j] = 1;
                    if (a[i - 1][j] == 2) {
                        System.out.println("No");
                        return;
                    }
                }
                if (j > 0) {
                    if (a[i][j - 1] == 0) a[i][j - 1] = 1;
                    if (a[i][j - 1] == 2) {
                        System.out.println("No");
                        return;
                    }
                }
                if (j < m - 1) {
                    if (a[i][j+1] == 0) a[i][j+1]=1;
                    if (a[i][j+1] == 2) {
                        System.out.println("No");
                        return;
                    }
                }
                if (i < n - 1) {
                    if (a[i+1][j] == 0) a[i+1][j]=1;
                    if (a[i+1][j] == 2) {
                        System.out.println("No");
                        return;
                    }
                }
            }
        }

        int[][] steps = new int[n][m];
        LinkedList<Ptx> queue = new LinkedList<>();
        queue.add(new Ptx(n - 1, m - 1, 1));
        while (!queue.isEmpty()) {
            Ptx cur = queue.poll();
            if (cur.x < 0 || cur.x >= n || cur.y < 0 || cur.y >= m) continue;
            if (a[cur.x][cur.y] == 2) {
                good--;
            }
            if (a[cur.x][cur.y] == 1) continue;
            queue.add(new Ptx(cur.x - 1, cur.y, 0));
            queue.add(new Ptx(cur.x + 1, cur.y, 0));
            queue.add(new Ptx(cur.x , cur.y - 1, 0));
            queue.add(new Ptx(cur.x , cur.y + 1, 0));
            a[cur.x][cur.y] = 1;
        }
        System.out.println(good == 0 ? "Yes" : "No");
    }

    static class Ptx {
        int x, y, val;

        public Ptx(int x, int y, int val) {
            this.x = x;
            this.y = y;
            this.val = val;
        }
    }


    static class WithIdx implements Comparable<WithIdx> {
        int val, idx;

        public WithIdx(int val, int idx) {
            this.val = val;
            this.idx = idx;
        }

        @Override
        public int compareTo(WithIdx o) {
            return Integer.compare(val, o.val);
        }
    }

    public static class FastScanner {
        BufferedReader br;
        StringTokenizer st;

        public FastScanner() {
            br = new BufferedReader(new InputStreamReader(System.in));
        }

        String nextToken() {
            while (st == null || !st.hasMoreElements()) {
                try {
                    st = new StringTokenizer(br.readLine());
                } catch (IOException e) {
                    // TODO Auto-generated catch block
                    e.printStackTrace();
                }
            }
            return st.nextToken();
        }

        String nextLine() {
            try {
                return br.readLine();
            } catch (Exception e) {
                e.printStackTrace();
                throw new RuntimeException();
            }
        }

        int nextInt() {
            return Integer.parseInt(nextToken());
        }

        long nextLong() {
            return Long.parseLong(nextToken());
        }

        double nextDouble() {
            return Double.parseDouble(nextToken());
        }

        int[] nextIntArray(int n) {
            int[] res = new int[n];
            for (int i = 0; i < n; i++) res[i] = nextInt();
            return res;
        }

        long[] nextLongArray(int n) {
            long[] res = new long[n];
            for (int i = 0; i < n; i++) res[i] = nextLong();
            return res;
        }

        String[] nextStringArray(int n) {
            String[] res = new String[n];
            for (int i = 0; i < n; i++) res[i] = nextToken();
            return res;
        }
    }

    static class PrefixSums {
        long[] sums;

        public PrefixSums(long[] sums) {
            this.sums = sums;
        }

        public long sum(int fromInclusive, int toExclusive) {
            if (fromInclusive > toExclusive) throw new IllegalArgumentException("Wrong value");
            return sums[toExclusive] - sums[fromInclusive];
        }

        public static PrefixSums of(int[] ar) {
            long[] sums = new long[ar.length + 1];
            for (int i = 1; i <= ar.length; i++) {
                sums[i] = sums[i - 1] + ar[i - 1];
            }
            return new PrefixSums(sums);
        }

        public static PrefixSums of(long[] ar) {
            long[] sums = new long[ar.length + 1];
            for (int i = 1; i <= ar.length; i++) {
                sums[i] = sums[i - 1] + ar[i - 1];
            }
            return new PrefixSums(sums);
        }
    }

    static class ADUtils {
        static void sort(int[] ar) {
            Random rnd = ThreadLocalRandom.current();
            for (int i = ar.length - 1; i > 0; i--) {
                int index = rnd.nextInt(i + 1);
                // Simple swap
                int a = ar[index];
                ar[index] = ar[i];
                ar[i] = a;
            }
            Arrays.sort(ar);
        }

        static void reverse(int[] arr) {
            int last = arr.length / 2;
            for (int i = 0; i < last; i++) {
                int tmp = arr[i];
                arr[i] = arr[arr.length - 1 - i];
                arr[arr.length - 1 - i] = tmp;
            }
        }

        static void sort(long[] ar) {
            Random rnd = ThreadLocalRandom.current();
            for (int i = ar.length - 1; i > 0; i--) {
                int index = rnd.nextInt(i + 1);
                // Simple swap
                long a = ar[index];
                ar[index] = ar[i];
                ar[i] = a;
            }
            Arrays.sort(ar);
        }
    }

    static class MathUtils {
        static long[] FIRST_PRIMES = {
                2, 3, 5, 7, 11, 13, 17, 19, 23, 29,
                31, 37, 41, 43, 47, 53, 59, 61, 67, 71,
                73, 79, 83, 89, 97, 101, 103, 107, 109, 113,
                127, 131, 137, 139, 149, 151, 157, 163, 167, 173,
                179, 181, 191, 193, 197, 199, 211, 223, 227, 229,
                233, 239, 241, 251, 257, 263, 269, 271, 277, 281,
                283, 293, 307, 311, 313, 317, 331, 337, 347, 349,
                353, 359, 367, 373, 379, 383, 389, 397, 401, 409,
                419, 421, 431, 433, 439, 443, 449, 457, 461, 463,
                467, 479, 487, 491, 499, 503, 509, 521, 523, 541,
                547, 557, 563, 569, 571, 577, 587, 593, 599, 601,
                607, 613, 617, 619, 631, 641, 643, 647, 653, 659,
                661, 673, 677, 683, 691, 701, 709, 719, 727, 733,
                739, 743, 751, 757, 761, 769, 773, 787, 797, 809,
                811, 821, 823, 827, 829, 839, 853, 857, 859, 863,
                877, 881, 883, 887, 907, 911, 919, 929, 937, 941,
                947, 953, 967, 971, 977, 983, 991, 997, 1009, 1013,
                1019, 1021, 1031, 1033, 1039, 1049, 1051};

        static long[] primes(int to) {
            long[] all = new long[to + 1];
            long[] primes = new long[to + 1];
            all[1] = 1;
            int primesLength = 0;
            for (int i = 2; i <= to; i++) {
                if (all[i] == 0) {
                    primes[primesLength++] = i;
                    all[i] = i;
                }
                for (int j = 0; j < primesLength && i * primes[j] <= to && all[i] >= primes[j];
                        j++) {
                    all[(int) (i * primes[j])] = primes[j];
                }
            }
            return Arrays.copyOf(primes, primesLength);
        }

        static long modpow(long b, long e, long m) {
            long result = 1;

            while (e > 0) {
                if ((e & 1) == 1) {
                    /* multiply in this bit's contribution while using modulus to keep
                     * result small */
                    result = (result * b) % m;
                }
                b = (b * b) % m;
                e >>= 1;
            }

            return result;
        }

        static long submod(long x, long y, long m) {
            return (x - y + m) % m;
        }

        static public long gcdF(long a, long b) {
            while (b != 0) {
                long na = b;
                long nb = a % b;
                a = na;
                b = nb;
            }
            return a;
        }
    }
}
 
/*
5
3 2 3 8 8
2 8 5 10 1
 
 */