Problem: A permutation is a sequence of integers p1, p2, ..., pn, consisting of n distinct positive integers, each of them doesn't exceed n. Let's denote the i-th element of permutation p as pi. We'll call number n the size of permutation p1, p2, ..., pn.

Nickolas adores permutations. He likes some permutations more than the others. He calls such permutations perfect. A perfect permutation is such permutation p that for any i (1 ≤ i ≤ n) (n is the permutation size) the following equations hold ppi = i and pi ≠ i. Nickolas asks you to print any perfect permutation of size n for the given n.

Input

A single line contains a single integer n (1 ≤ n ≤ 100) — the permutation size.

Output

If a perfect permutation of size n doesn't exist, print a single integer -1. Otherwise print n distinct integers from 1 to n, p1, p2, ..., pn — permutation p, that is perfect. Separate printed numbers by whitespaces.

Examples

Input

1


Output

-1


Input

2


Output

2 1 


Input

4


Output

2 1 4 3 

Solution (in JAVA):

Solution:
import java.util.*;
public class p13 {

	public static void main(String[] args) {
		
		Scanner in=new Scanner(System.in);
		int n=in.nextInt();
		int a[]=new int[n];
		for(int i=0;i<n;i++)
		{
			if(i%2==0)
			{
				a[i]=i+2;
			}
			else
			{
				a[i]=i;
			}
		}
		int k=0;
		for(int i=0;i<n;i++)
		{
			if(a[i]>n)
			{
			System.out.println("-1");
			k=1;
			break;
			
			}
			
		}
		if(k!=1)
		{
			for(int i=0;i<n;i++)
			{
				
				System.out.print(a[i]+" ");
				
				
				}
				
			}
		}
		

	}