Problem: A permutation is a sequence of integers p1, p2, ..., pn, consisting of n distinct positive integers, each of them doesn't exceed n. Let's denote the i-th element of permutation p as pi. We'll call number n the size of permutation p1, p2, ..., pn.

Nickolas adores permutations. He likes some permutations more than the others. He calls such permutations perfect. A perfect permutation is such permutation p that for any i (1 ≤ i ≤ n) (n is the permutation size) the following equations hold ppi = i and pi ≠ i. Nickolas asks you to print any perfect permutation of size n for the given n.

Input

A single line contains a single integer n (1 ≤ n ≤ 100) — the permutation size.

Output

If a perfect permutation of size n doesn't exist, print a single integer -1. Otherwise print n distinct integers from 1 to n, p1, p2, ..., pn — permutation p, that is perfect. Separate printed numbers by whitespaces.

Examples

Input

1


Output

-1


Input

2


Output

2 1 


Input

4


Output

2 1 4 3 

Solution (in PYTHON3):

Solution:
#sys.setrecursionlimit(300000)
import sys
import math as m
def main():
    pass
def binary(n):
    #decimal to binary
    return (bin(n).replace("0b", ""))
def decimal(s):
    #binary to decimal
    return (int(s, 2))
def pow2(n):
    #power of a number base 2
    p = 0
    while n > 1:
        n //= 2
        p += 1
    return (p)
def isPrime(n):
    # if  number is prime in √n time
    if (n == 1):
        return (False)
    else:
        root = int(n ** 0.5)
        root += 1
        for i in range(2, root):
            if (n % i == 0):
                return (False)
        return (True)
def lts(l):
    #list to string ,no spaces
    s=''.join(map(str,l))
    return s
def stl(s):
    #for each character in string to list with no spaces -->
    l=list(s)
    #for space in string  -->
    #l=list(s.split(" "))
    return l
#Returns list of numbers with a particular sum
def sq(a,target,arr=[]):
    s=sum(arr)
    if(s==target):
        return arr
    if(s>=target):
        return
    for i in range(len(a)):
        n=a[i]
        remaining=a[i+1:]
        ans=sq(remaining,target,arr+[n])
        if(ans):
            return ans

#1000000007
mod=int(1e9)+7
def sinp(): return sys.stdin.readline().strip()
def iinp(): return int(input())
def ninp(): return map(int, sys.stdin.readline().strip().split())
def llinp(): return list(map(int, sys.stdin.readline().strip().split()))
def p(xyz): print(xyz)
def p2(a,b):print(a,b)
#for _ in range(iinp()):
n=iinp()
if(n%2!=0):
    print(-1)
else:
    s=1
    for i in range(n//2):
        print(s+1,s,end=" ")
        s=s+2
print()