Problem: The array a with n integers is given. Let's call the sequence of one or more consecutive elements in a segment. Also let's call the segment k-good if it contains no more than k different values.

Find any longest k-good segment.

As the input/output can reach huge size it is recommended to use fast input/output methods: for example, prefer to use scanf/printf instead of cin/cout in C++, prefer to use BufferedReader/PrintWriter instead of Scanner/System.out in Java.

Input

The first line contains two integers n, k (1 ≤ k ≤ n ≤ 5·105) — the number of elements in a and the parameter k.

The second line contains n integers ai (0 ≤ ai ≤ 106) — the elements of the array a.

Output

Print two integers l, r (1 ≤ l ≤ r ≤ n) — the index of the left and the index of the right ends of some k-good longest segment. If there are several longest segments you can print any of them. The elements in a are numbered from 1 to n from left to right.

Examples

Input

5 5
1 2 3 4 5


Output

1 5


Input

9 3
6 5 1 2 3 2 1 4 5


Output

3 7


Input

3 1
1 2 3


Output

1 1

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.*;

public class C
{
	String line;
	StringTokenizer inputParser;
	BufferedReader is;
	FileInputStream fstream;
	DataInputStream in;
	String FInput="";
	
	
	void openInput(String file)
	{

		if(file==null)is = new BufferedReader(new InputStreamReader(System.in));//stdin
		else
		{
			try{
		
				
			fstream = new FileInputStream(file);
			in = new DataInputStream(fstream);
			is = new BufferedReader(new InputStreamReader(in));
			}catch(Exception e)
			{
				System.err.println(e);
			}
		}

	}
	
	void readNextLine()
	{
		try {
			line = is.readLine();
			inputParser = new StringTokenizer(line, " ");
			//System.err.println("Input: " + line);
		} catch (IOException e) {
			System.err.println("Unexpected IO ERROR: " + e);
		}	
		
	}
	
	int NextInt()
	{
		String n = inputParser.nextToken();
		int val = Integer.parseInt(n);
		
		//System.out.println("I read this number: " + val);
		return val;
	}
	
	private double NextDouble() {
        String n = inputParser.nextToken();
        double val = Double.parseDouble(n);
        return val;
	}
	
	String NextString()
	{
		String n = inputParser.nextToken();
		return n;
	}
	
	void closeInput()
	{
		try {
			is.close();
		} catch (IOException e) {
			System.err.println("Unexpected IO ERROR: " + e);
		}
			
	}
	
	public void readFInput()
	{
		for(;;)
		{
			try
			{
				readNextLine();
				FInput+=line+" ";
			}
			catch(Exception e)
			{
				break;
			}
		}
		inputParser = new StringTokenizer(FInput, " ");
	}
	
	long NextLong()
    {
            String n = inputParser.nextToken();
            
            long val = Long.parseLong(n);
            
            return val;
    }
	
	public static void main(String [] argv)
	{
		//String filePath="input.txt";
        String filePath=null;
        if(argv.length>0)filePath=argv[0];
		new C(filePath);
	}
	
	public C(String inputFile)
	{
		openInput(inputFile);
		//readNextLine();
		int T=1;//NextInt();
		StringBuilder sb = new StringBuilder();
		for(int t=1; t<=T; t++)
		{
			readNextLine();
			int N=NextInt();
			readNextLine();
			HashSet<Integer> hs = new HashSet<Integer>();
			int start=1;
			int cnt=0;
			boolean ok=false;
			for(int i=0; i<N; i++)
			{
				int x=NextInt();
				if(hs.contains(x))
				{
					sb.append(start+" "+(i+1)+"\n");
					start=i+2;
					cnt++;
					hs.clear();
					if(i==N-1)ok=true;
				}
				else hs.add(x);
			}
			if(cnt==0)sb.append(-1);
			else
			{
				if(!ok){
					while(sb.charAt(sb.length()-1)!=' ')sb.deleteCharAt(sb.length()-1);
					sb.append(N);
				}
				sb.insert(0, cnt+"\n");
			}
			
		}
		System.out.print(sb);
		
		closeInput();		
	}

}