Problem: You are given a positive integer n. In one move, you can increase n by one (i.e. make n := n + 1). Your task is to find the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains two integers n and s (1 ≤ n ≤ 10^{18}; 1 ≤ s ≤ 162).

Output

For each test case, print the answer: the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

Example

Input


5
2 1
1 1
500 4
217871987498122 10
100000000000000001 1


Output


8
0
500
2128012501878
899999999999999999

Solution (in PYTHON3):

Solution:
def sumDigits(n):
    res = 0
    while(n):
        res += n % 10
        n //= 10
    return res
    
cases = int(input())
for _ in range(cases):
    n, s = map(int, input().split())
    adds = 0
    multipler = 1
    while sumDigits(n) > s:
        toZero = 10 - n % 10
        if toZero == 10:
            toZero = 0
        adds += multipler * toZero
        n = (n + toZero) // 10
        multipler *= 10
    print(adds)