Problem: You are given a positive integer n. In one move, you can increase n by one (i.e. make n := n + 1). Your task is to find the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains two integers n and s (1 ≤ n ≤ 10^{18}; 1 ≤ s ≤ 162).

Output

For each test case, print the answer: the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

Example

Input


5
2 1
1 1
500 4
217871987498122 10
100000000000000001 1


Output


8
0
500
2128012501878
899999999999999999

Solution (in PYTHON3):

Solution:
def sum(n):
  d =  0
  for i in list(str(n)):
    d += int(i)
  return d


for i in range(int(input())):
    n, s = map(int, input().split())
    ans = []
    while sum(n) > s:
        ans.insert(0, str((10 - n%10)%10))
        n=n//10 + (1 if n%10 else 0)
    if len(ans) == 0:
        print(0)
        continue;
    print(''.join(ans))