Problem: Let's denote d(n) as the number of divisors of a positive integer n. You are given three integers a, b and c. Your task is to calculate the following sum:

<image>

Find the sum modulo 1073741824 (230).

Input

The first line contains three space-separated integers a, b and c (1 ≤ a, b, c ≤ 2000).

Output

Print a single integer — the required sum modulo 1073741824 (230).

Examples

Input

2 2 2


Output

20


Input

4 4 4


Output

328


Input

10 10 10


Output

11536

Note

For the first example.

  * d(1·1·1) = d(1) = 1; 
  * d(1·1·2) = d(2) = 2; 
  * d(1·2·1) = d(2) = 2; 
  * d(1·2·2) = d(4) = 3; 
  * d(2·1·1) = d(2) = 2; 
  * d(2·1·2) = d(4) = 3; 
  * d(2·2·1) = d(4) = 3; 
  * d(2·2·2) = d(8) = 4. 



So the result is 1 + 2 + 2 + 3 + 2 + 3 + 3 + 4 = 20.

Solution (in PYTHON3):

Solution:
#236B

import math

arr = list(map(int, input().split(" ")))
a = arr[0]
b = arr[1]
c = arr[2]

d = dict()

def numdiv(n):
	if n in d:
		return d[n]
	else:
		count = 0
		for i in range(1, int(math.sqrt(n) + 1)):
			if n % i == 0:
				count += 2
		if int(math.sqrt(n)) * int(math.sqrt(n)) == n:
			count -= 1
		d[n] = count
		return count

answer = 0
for i in range(1, a + 1):
	for j in range(1, b + 1):
		for k in range(1, c + 1):
			answer += numdiv(i * j * k)

print(answer)