Problem: You are given a positive integer n. In one move, you can increase n by one (i.e. make n := n + 1). Your task is to find the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains two integers n and s (1 ≤ n ≤ 10^{18}; 1 ≤ s ≤ 162).

Output

For each test case, print the answer: the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

Example

Input


5
2 1
1 1
500 4
217871987498122 10
100000000000000001 1


Output


8
0
500
2128012501878
899999999999999999

Solution (in JAVA):

Solution:
import java.util.Scanner;
import java.util.StringTokenizer;

public class Divisibility {
    public static void main(String[] args) {
        Scanner s = new Scanner(System.in);
        int cases = Integer.parseInt(s.nextLine());

        for (int i = 0; i < cases; i++) {
            StringTokenizer st = new StringTokenizer(s.nextLine());
            double b = Integer.parseInt(st.nextToken());
            double a = Integer.parseInt(st.nextToken());
            int n = (int) Math.ceil(b / a);
            System.out.println((int) (a * n - b));
        }
    }
}