Problem: You are given a positive integer n. In one move, you can increase n by one (i.e. make n := n + 1). Your task is to find the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains two integers n and s (1 ≤ n ≤ 10^{18}; 1 ≤ s ≤ 162).

Output

For each test case, print the answer: the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

Example

Input


5
2 1
1 1
500 4
217871987498122 10
100000000000000001 1


Output


8
0
500
2128012501878
899999999999999999

Solution (in PYTHON3):

Solution:
for i in range(int(input())):
    n,s=map(int,input().split())
    l=list(map(int,list(str(n))))
    if sum(l)<=s:
        print(0)
        continue
    i=0
    q=l[0]
    while q<s:
        i+=1
        q+=l[i]
    # print('ind',i)
    req=len(l[i:])
    x=''.join(map(str,l[i:]))
    req_num=int(x)
    mov=10**req-req_num
    print(mov)