Problem: You are given a positive integer n. In one move, you can increase n by one (i.e. make n := n + 1). Your task is to find the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains two integers n and s (1 ≤ n ≤ 10^{18}; 1 ≤ s ≤ 162).

Output

For each test case, print the answer: the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

Example

Input


5
2 1
1 1
500 4
217871987498122 10
100000000000000001 1


Output


8
0
500
2128012501878
899999999999999999

Solution (in PYTHON):

Solution:
def func(n):
    x=str(n)
    f=0
    for i in x:
        f+=int(i)
    return f
for _ in range(input()):
    n,s=[int(i) for i in raw_input().split()]
    val=0;ct=0
    while func(n)>s:
        if n%10!=0:
            val+=(10**ct)*(10-n%10)
            n/=10
            n+=1
        else:
            n/=10
        ct+=1
    print val