Problem: You are given a positive integer D. Let's build the following graph from it: 

  * each vertex is a divisor of D (not necessarily prime, 1 and D itself are also included); 
  * two vertices x and y (x > y) have an undirected edge between them if x is divisible by y and \frac x y is a prime; 
  * the weight of an edge is the number of divisors of x that are not divisors of y. 



For example, here is the graph for D=12: 

<image>

Edge (4,12) has weight 3 because 12 has divisors [1,2,3,4,6,12] and 4 has divisors [1,2,4]. Thus, there are 3 divisors of 12 that are not divisors of 4 — [3,6,12].

There is no edge between 3 and 2 because 3 is not divisible by 2. There is no edge between 12 and 3 because 12/3=4 is not a prime.

Let the length of the path between some vertices v and u in the graph be the total weight of edges on it. For example, path [(1, 2), (2, 6), (6, 12), (12, 4), (4, 2), (2, 6)] has length 1+2+2+3+1+2=11. The empty path has length 0.

So the shortest path between two vertices v and u is the path that has the minimal possible length.

Two paths a and b are different if there is either a different number of edges in them or there is a position i such that a_i and b_i are different edges.

You are given q queries of the following form: 

  * v u — calculate the number of the shortest paths between vertices v and u. 



The answer for each query might be large so print it modulo 998244353.

Input

The first line contains a single integer D (1 ≤ D ≤ 10^{15}) — the number the graph is built from.

The second line contains a single integer q (1 ≤ q ≤ 3 ⋅ 10^5) — the number of queries.

Each of the next q lines contains two integers v and u (1 ≤ v, u ≤ D). It is guaranteed that D is divisible by both v and u (both v and u are divisors of D).

Output

Print q integers — for each query output the number of the shortest paths between the two given vertices modulo 998244353.

Examples

Input


12
3
4 4
12 1
3 4


Output


1
3
1


Input


1
1
1 1


Output


1


Input


288807105787200
4
46 482955026400
12556830686400 897
414 12556830686400
4443186242880 325


Output


547558588
277147129
457421435
702277623

Note

In the first example: 

  * The first query is only the empty path — length 0; 
  * The second query are paths [(12, 4), (4, 2), (2, 1)] (length 3+1+1=5), [(12, 6), (6, 2), (2, 1)] (length 2+2+1=5) and [(12, 6), (6, 3), (3, 1)] (length 2+2+1=5). 
  * The third query is only the path [(3, 1), (1, 2), (2, 4)] (length 1+1+1=3). 

Solution (in PYTHON3):

Solution:
mod = 998244353
eps = 10**-9


def main():
    import sys
    input = sys.stdin.buffer.readline

    # comb init
    # mod = 1000000007
    nmax = 100  # change here
    fac = [0] * nmax
    finv = [0] * nmax
    inv = [0] * nmax
    fac[0] = 1
    fac[1] = 1
    finv[0] = 1
    finv[1] = 1
    inv[1] = 1
    for i in range(2, nmax):
        fac[i] = fac[i - 1] * i % mod
        inv[i] = mod - inv[mod % i] * (mod // i) % mod
        finv[i] = finv[i - 1] * inv[i] % mod

    def comb(n, r):
        if n < r:
            return 0
        else:
            return (fac[n] * ((finv[r] * finv[n - r]) % mod)) % mod

    def PrimeDecomposition(N):
        ret = {}
        n = int(N ** 0.5)
        for d in range(2, n + 1):
            while N % d == 0:
                if d not in ret:
                    ret[d] = 1
                else:
                    ret[d] += 1
                N //= d
            if N == 1:
                break
        if N != 1:
            ret[N] = 1
        return ret

    D = int(input())
    PD = PrimeDecomposition(D)
    P = list(PD.keys())
    np = len(P)

    ans_all = []
    for _ in range(int(input())):
        u, v = map(int, input().split())
        pos = []
        neg = []
        for p in P:
            up = 0
            while u % p == 0:
                up += 1
                u //= p
            vp = 0
            while v % p == 0:
                vp += 1
                v //= p

            if up > vp:
                pos.append(up - vp)
            elif up < vp:
                neg.append(vp - up)
        ans = 1
        if pos:
            ans = (ans * fac[sum(pos)])%mod
            for x in pos:
                ans = (ans * finv[x])%mod
        if neg:
            ans = (ans * fac[sum(neg)]) % mod
            for x in neg:
                ans = (ans * finv[x]) % mod
        ans_all.append(ans)
    print(*ans_all, sep="\n")


if __name__ == '__main__':
    main()