Problem: You are given a positive integer n. In one move, you can increase n by one (i.e. make n := n + 1). Your task is to find the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains two integers n and s (1 ≤ n ≤ 10^{18}; 1 ≤ s ≤ 162).

Output

For each test case, print the answer: the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

Example

Input


5
2 1
1 1
500 4
217871987498122 10
100000000000000001 1


Output


8
0
500
2128012501878
899999999999999999

Solution (in PYTHON3):

Solution:
from datetime import datetime
instanteInicial = datetime.now()
instanteFinal = datetime.now()
testcases = input()
testcases = int(testcases)
for i in range (testcases):
    entrada = input().split(" ")
    a = int(entrada[0])
    b = int(entrada[1])
    if a % b == 0:
        print(0)
        continue
    moves = 0
    first = True
    status = ((a // b) + 1) * b
    print(status - a)