Problem: You are given a positive integer n. In one move, you can increase n by one (i.e. make n := n + 1). Your task is to find the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains two integers n and s (1 ≤ n ≤ 10^{18}; 1 ≤ s ≤ 162).

Output

For each test case, print the answer: the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

Example

Input


5
2 1
1 1
500 4
217871987498122 10
100000000000000001 1


Output


8
0
500
2128012501878
899999999999999999

Solution (in PYTHON3):

Solution:
if __name__=='__main__':
    test=int(input())
    ar=[]
    br=[]
    for i in range(test):
        a,b=list(map(int,input().strip().split()))
        ar.append(a)
        br.append(b)
    for i in range(test):
        if(ar[i]%br[i]==0):
            print(0)
        else:
            print((br[i]*((ar[i]//br[i])+1))-ar[i])