Problem: You are given a positive integer n. In one move, you can increase n by one (i.e. make n := n + 1). Your task is to find the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains two integers n and s (1 ≤ n ≤ 10^{18}; 1 ≤ s ≤ 162).

Output

For each test case, print the answer: the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

Example

Input


5
2 1
1 1
500 4
217871987498122 10
100000000000000001 1


Output


8
0
500
2128012501878
899999999999999999

Solution (in JAVA):

Solution:
import java.util.*;
import java.io.*;
public class Divisibility
{
public static void main(String[] args)
{
Scanner s=new Scanner(System.in);
int t=s.nextInt();
for(int i=0;i<t;i++)
{
int a=s.nextInt();
int b=s.nextInt();
int c=a-(a%b);
if(a%b==0)
{
System.out.println(0);
}
else
{
System.out.println((c+b)-a);
}
}
}
}