Problem: You are given a positive integer n. In one move, you can increase n by one (i.e. make n := n + 1). Your task is to find the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains two integers n and s (1 ≤ n ≤ 10^{18}; 1 ≤ s ≤ 162).

Output

For each test case, print the answer: the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

Example

Input


5
2 1
1 1
500 4
217871987498122 10
100000000000000001 1


Output


8
0
500
2128012501878
899999999999999999

Solution (in PYTHON3):

Solution:
##=====================================================
from sys import stdin, stdout
from collections import defaultdict, Counter
from functools import lru_cache
from math import gcd,floor,ceil

def ilist():
    return [int(x) for x in stdin.readline().strip().split(" ")]
def iint():
    return int(stdin.readline().strip())
def istr():
    return stdin.readline().strip()
##=====================================================
t=iint()
        
for _x in range(t):
    m,n=ilist()
    k=ceil(m/n)*n
    print(k-m)