Problem: One way to create a task is to learn from math. You can generate some random math statement or modify some theorems to get something new and build a new task from that.

For example, there is a statement called the "Goldbach's conjecture". It says: "each even number no less than four can be expressed as the sum of two primes". Let's modify it. How about a statement like that: "each integer no less than 12 can be expressed as the sum of two composite numbers." Not like the Goldbach's conjecture, I can prove this theorem.

You are given an integer n no less than 12, express it as a sum of two composite numbers.

Input

The only line contains an integer n (12 ≤ n ≤ 106).

Output

Output two composite integers x and y (1 < x, y < n) such that x + y = n. If there are multiple solutions, you can output any of them.

Examples

Input

12


Output

4 8


Input

15


Output

6 9


Input

23


Output

8 15


Input

1000000


Output

500000 500000

Note

In the first example, 12 = 4 + 8 and both 4, 8 are composite numbers. You can output "6 6" or "8 4" as well.

In the second example, 15 = 6 + 9. Note that you can't output "1 14" because 1 is not a composite number.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
const long double PI =
    3.14159265358979323846264338327950288419716939937510582097494459230;
const long long MOD = 1000000007LL;
const long long INF = 1e9;
const long long LINF = 1e18;
const long double EPS = 1e-9;
const long double GOLD = ((1 + sqrt(5)) / 2);
template <class T>
int getbit(T s, int i) {
  return (s >> 1) & 1;
}
template <class T>
T onbit(T s, int i) {
  return s | (T(1) << i);
}
template <class T>
T offbit(T s, int i) {
  return s & (~(T(1) << i));
}
template <class T>
int cntbit(T s) {
  return __builtin_popcount(s);
}
long long n;
bool isComp(long long z) {
  for (long long i = 2; i <= sqrt(z); i++) {
    if (z % i == 0) return true;
  }
  return false;
}
void VarInput() { cin >> n; }
void ProSolve() {
  for (long long i = 4; i <= n / 2; i++) {
    if (isComp(i) && isComp(n - i)) {
      cout << i << " " << n - i;
      return;
    }
  }
}
int main() {
  ios_base::sync_with_stdio(0);
  cin.tie(NULL);
  VarInput();
  ProSolve();
  return 0;
}