Problem: For given two segments s1 and s2, print the coordinate of the cross point of them.

s1 is formed by end points p0 and p1, and s2 is formed by end points p2 and p3.

Constraints

* 1 ≤ q ≤ 1000
* -10000 ≤ xpi, ypi ≤ 10000
* p0 ≠ p1 and p2 ≠ p3.
* The given segments have a cross point and are not in parallel.

Input

The entire input looks like:


q (the number of queries)
1st query
2nd query
...
qth query


Each query consists of integer coordinates of end points of s1 and s2 in the following format:


xp0 yp0 xp1 yp1 xp2 yp2 xp3 yp3


Output

For each query, print the coordinate of the cross point. The output values should be in a decimal fraction with an error less than 0.00000001.

Example

Input

3
0 0 2 0 1 1 1 -1
0 0 1 1 0 1 1 0
0 0 1 1 1 0 0 1


Output

1.0000000000 0.0000000000
0.5000000000 0.5000000000
0.5000000000 0.5000000000

Solution (in PYTHON3):

Solution:
from collections import defaultdict,deque
import sys,heapq,bisect,math,itertools,string,queue
sys.setrecursionlimit(10**8)
INF = float('inf')
mod = 10**9+7
eps = 10**-7
def inp(): return int(input())
def inpl(): return list(map(int, input().split()))
def inpl_str(): return list(input().split())

###########################
#          幾何
###########################
def sgn(a):
    if a < -eps: return -1
    if a >  eps: return  1
    return 0

class Point:
    def __init__(self,x,y):
        self.x = x
        self.y = y
        pass

    def tolist(self):
        return [self.x,self.y]

    def __add__(self,p):
        return Point(self.x+p.x, self.y+p.y)
    def __iadd__(self,p):
        return self + p

    def __sub__(self,p):
        return Point(self.x - p.x, self.y - p.y)
    def __isub__(self,p):
        return self - p

    def __truediv__(self,n):
        return Point(self.x/n, self.y/n)
    def __itruediv__(self,n):
        return self / n

    def __mul__(self,n):
        return Point(self.x*n, self.y*n)
    def __imul__(self,n):
        return self * n

    def __lt__(self,other):
        tmp = sgn(self.x - other.x)
        if tmp != 0:
            return tmp < 0
        else:
            return sgn(self.y - other.y) < 0

    def __eq__(self,other):
        return sgn(self.x - other.x) == 0 and sgn(self.y - other.y) == 0

    def abs(self):
        return math.sqrt(self.x**2+self.y**2)

    def dot(self,p):
        return self.x * p.x + self.y*p.y

    def det(self,p):
        return self.x * p.y - self.y*p.x

    def arg(self,p):
        return math.atan2(y,x)

# 点の進行方向 a -> b -> c
def iSP(a,b,c):
    tmp = sgn((b-a).det(c-a))
    if tmp > 0:   return 1   # 左に曲がる場合
    elif tmp < 0: return -1  # 右に曲がる場合
    else: # まっすぐ
        if sgn((b-a).dot(c-a)) < 0: return -2 # c-a-b の順
        if sgn((a-b).dot(c-b)) < 0: return  2 # a-b-c の順
        return 0 # a-c-bの順

# ab,cd の直線交差
def isToleranceLine(a,b,c,d):
    if sgn((b-a).det(c-d)) != 0: return 1 # 交差する
    else:
        if sgn((b-a).det(c-a)) != 0: return 0 # 平行
        else: return -1 # 同一直線

# ab,cd の線分交差 重複，端点での交差もTrue
def isToleranceSegline(a,b,c,d):
    return sgn(iSP(a,b,c)*iSP(a,b,d))<=0 and sgn(iSP(c,d,a)*iSP(c,d,b)) <= 0

# 直線ab と 直線cd の交点 (存在する前提)
def Intersection(a,b,c,d):
    tmp1 = (b-a)*((c-a).det(d-c))
    tmp2 = (b-a).det(d-c)
    return a+(tmp1/tmp2)

# 直線ab と 点c の距離
def DistanceLineToPoint(a,b,c):
    return abs(((c-a).det(b-a))/((b-a).abs()))

# 線分ab と 点c の距離
def DistanceSeglineToPoint(a,b,c):
    if sgn((b-a).dot(c-a)) < 0: # <cab が鈍角
        return (c-a).abs()
    if sgn((a-b).dot(c-b)) < 0: # <cba が鈍角
        return (c-b).abs()
    return DistanceLineToPoint(a,b,c)

# 直線ab への 点c からの垂線の足
def Vfoot(a,b,c):
    d = c + Point((b-a).y,-(b-a).x)
    return Intersection(a,b,c,d)

# 多角形の面積
def PolygonArea(Plist):
    Plist = ConvexHull(Plist)
    L = len(Plist)
    S = 0
    for i in range(L):
        tmpS = (Plist[i-1].det(Plist[i]))/2
        S += tmpS
    return S

# 多角形の重心
def PolygonG(Plist):
    Plist = ConvexHull(Plist)
    L = len(Plist)
    S = 0
    G = Point(0,0)
    for i in range(L):
        tmpS = (Plist[i-1].det(Plist[i]))/2
        S += tmpS
        G += (Plist[i-1]+Plist[i])/3*tmpS
    return G/S

# 凸法
def ConvexHull(Plist):
    Plist.sort()
    L = len(Plist)
    qu = deque([])
    quL = 0
    for p in Plist:
        while quL >= 2 and iSP(qu[quL-2],qu[quL-1],p) == 1:
            qu.pop()
            quL -= 1
        qu.append(p)
        quL += 1

    qd = deque([])
    qdL = 0
    for p in Plist:
        while qdL >= 2 and iSP(qd[qdL-2],qd[qdL-1],p) == -1:
            qd.pop()
            qdL -= 1
        qd.append(p)
        qdL += 1

    qd.pop()
    qu.popleft()
    hidari = list(qd) + list(reversed(qu)) # 左端開始，左回りPlist
    return hidari

N = int(input())
for _ in range(N):
    x0,y0,x1,y1,x2,y2,x3,y3 = inpl()
    p0 = Point(x0,y0)
    p1 = Point(x1,y1)
    p2 = Point(x2,y2)
    p3 = Point(x3,y3)
    print(*Intersection(p0,p1,p2,p3).tolist())