Problem: You are given a positive integer n.

Let S(x) be sum of digits in base 10 representation of x, for example, S(123) = 1 + 2 + 3 = 6, S(0) = 0.

Your task is to find two integers a, b, such that 0 ≤ a, b ≤ n, a + b = n and S(a) + S(b) is the largest possible among all such pairs.

Input

The only line of input contains an integer n (1 ≤ n ≤ 10^{12}).

Output

Print largest S(a) + S(b) among all pairs of integers a, b, such that 0 ≤ a, b ≤ n and a + b = n.

Examples

Input

35


Output

17


Input

10000000000


Output

91

Note

In the first example, you can choose, for example, a = 17 and b = 18, so that S(17) + S(18) = 1 + 7 + 1 + 8 = 17. It can be shown that it is impossible to get a larger answer.

In the second test example, you can choose, for example, a = 5000000001 and b = 4999999999, with S(5000000001) + S(4999999999) = 91. It can be shown that it is impossible to get a larger answer.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int main() {
  long long int n, x;
  cin >> n;
  int i = 0;
  while (true) {
    long long int z = pow(10, i);
    if (n < z) break;
    i++;
  }
  i--;
  long long int z = pow(10, i);
  x = (n / z) * (z)-1;
  long long int y = n - x;
  int sum = 0;
  while (x > 0) {
    int rem;
    rem = x % 10;
    x = x / 10;
    sum = sum + rem;
  }
  while (y > 0) {
    int rem;
    rem = y % 10;
    y = y / 10;
    sum = sum + rem;
  }
  cout << sum;
}