Problem: For given two segments s1 and s2, print the coordinate of the cross point of them.

s1 is formed by end points p0 and p1, and s2 is formed by end points p2 and p3.

Constraints

* 1 ≤ q ≤ 1000
* -10000 ≤ xpi, ypi ≤ 10000
* p0 ≠ p1 and p2 ≠ p3.
* The given segments have a cross point and are not in parallel.

Input

The entire input looks like:


q (the number of queries)
1st query
2nd query
...
qth query


Each query consists of integer coordinates of end points of s1 and s2 in the following format:


xp0 yp0 xp1 yp1 xp2 yp2 xp3 yp3


Output

For each query, print the coordinate of the cross point. The output values should be in a decimal fraction with an error less than 0.00000001.

Example

Input

3
0 0 2 0 1 1 1 -1
0 0 1 1 0 1 1 0
0 0 1 1 1 0 0 1


Output

1.0000000000 0.0000000000
0.5000000000 0.5000000000
0.5000000000 0.5000000000

Solution (in PYTHON3):

Solution:
from functools import singledispatch
import math

EPS = 1e-10

COUNTER_CLOCKWISE = 1
CLOCKWISE = -1
ONLINE_BACK = 2
ONLINE_FRONT = -2
ON_SEGMENT = 0

class Segment():
    def __init__(self, p1, p2):
        self.p1 = p1
        self.p2 = p2

class Point():
    def __init__(self, x, y):
        self.x = x
        self.y = y

    def __add__(self, point):
        # + 演算子での挙動を指定
        return Point(self.x+point.x, self.y+point.y)

    def __sub__(self, point):
        # - 演算子での挙動を指定
        return Point(self.x-point.x, self.y-point.y)

    def __mul__(self, a):
        # * 演算子での挙動を指定
        return Point(a*self.x, a*self.y)

    def __truediv__(self, a):
        # / 演算子での挙動を指定
        return Point(self.x/a, self.y/a)

    def __abs__(self):
        # abs関数での挙動を指定
        return math.sqrt(self.norm())

    def norm(self):
        return self.x**2+self.y**2

    def __eq__(self, point):
        # == 演算子での挙動を指定
        return abs(self.x-point.x) < EPS and abs(self.y-point.y) <EPS

def dot(a, b):
    return a.x*b.x+a.y*b.y

def cross(a, b):
    return a.x*b.y - a.y*b.x

def isOrthogonal(a, b):
    return dot(a, b) == 0

def isParallel(a, b):
    return cross(a, b) == 0

def project(s, p):
    #s: Segment(), p: Point()
    base = s.p2 - s.p1
    r = dot(p-s.p1, base)/base.norm()
    return s.p1+base*r

def reflect(s, p):
    return p+(project(s, p)-p)*2

@singledispatch
def get_distance(a, b):
    return abs(a-b)

def get_distance_lp(l, p):
    return abs(cross(l.p2-l.p1, p-l.p1)/abs(l.p2-l.p1))

def get_distance_sp(s, p):
    if dot(s.p2-s.p1, p-s.p1) < 0:
        return abs(p-s.p1)
    if dot(s.p1-s.p2, p-s.p2) < 0:
        return abs(p-s.p2)
    return get_distance_lp(s, p)
    
@get_distance.register(Segment)
def _(s1, s2):
    if intersect(s1, s2):
        return 0
    return min([get_distance_sp(s1, s2.p1), get_distance_sp(s1, s2.p2),
                get_distance_sp(s2, s1.p1), get_distance_sp(s2, s1.p2)])

def ccw(p0, p1, p2):
    a = p1 - p0
    b = p2 - p0
    if cross(a, b) > EPS:
        return COUNTER_CLOCKWISE
    if cross(a, b) < -EPS:
        return CLOCKWISE
    if dot(a, b) < -EPS:
        return ONLINE_BACK
    if a.norm() < b.norm():
        return ONLINE_FRONT
    return ON_SEGMENT

@singledispatch
def intersect(p1, p2, p3, p4):
    return (ccw(p1, p2, p3)*ccw(p1, p2, p4) <= 0
            and ccw(p3, p4, p1)*ccw(p3, p4, p2) <= 0)

@intersect.register(Segment)
def _(s1, s2):
    return intersect(s1.p1, s1.p2, s2.p1, s2.p2)

def get_cross_point(s1, s2):
    base = s2.p2 - s2.p1
    d1 = abs(cross(base, s1.p1-s2.p1))
    d2 = abs(cross(base, s1.p2-s2.p1))
    t = d1/(d1+d2)
    return s1.p1 + (s1.p2-s1.p1)*t

if __name__ == '__main__':
    from sys import stdin
    input = stdin.readline

    q = int(input())
    for _ in range(q):
        x0, y0, x1, y1, x2, y2, x3, y3 = map(int, input().split())
        p0 = Point(x0, y0)
        p1 = Point(x1, y1)
        p2 = Point(x2, y2)
        p3 = Point(x3, y3)
        s1 = Segment(p0, p1)
        s2 = Segment(p2, p3)
        p = get_cross_point(s1, s2)
        print(p.x, p.y)