Problem: You are given a positive integer n. In one move, you can increase n by one (i.e. make n := n + 1). Your task is to find the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains two integers n and s (1 ≤ n ≤ 10^{18}; 1 ≤ s ≤ 162).

Output

For each test case, print the answer: the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

Example

Input


5
2 1
1 1
500 4
217871987498122 10
100000000000000001 1


Output


8
0
500
2128012501878
899999999999999999

Solution (in PYTHON3):

Solution:
import math
st=''


def func(a,b):
    k=a%b
    if (a+k)%b==0:
        return k
    return (b-k)





for _ in range(int(input())):
    a,b=map(int,input().split())
    #n = int(input())
    #l1=[]
    #inp=input().split()
    #s=input()
    #l1=list(map(int,input().split()))
    #l2 = list(map(int, input().split()))
    #l1=input().split()
    #l2=input().split()
    st+=str(func(a,b))+'\n'
print(st)