Problem: You are given a positive integer n. In one move, you can increase n by one (i.e. make n := n + 1). Your task is to find the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains two integers n and s (1 ≤ n ≤ 10^{18}; 1 ≤ s ≤ 162).

Output

For each test case, print the answer: the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

Example

Input


5
2 1
1 1
500 4
217871987498122 10
100000000000000001 1


Output


8
0
500
2128012501878
899999999999999999

Solution (in PYTHON3):

Solution:
def get_output(query):
	divisor=query[1]
	dividend=query[0]
	remainder=dividend%divisor
	add=dividend+remainder
	sub=dividend-remainder
	if add%divisor==0:
		return add-dividend
	elif sub%divisor==0:
		return (dividend+(divisor-remainder))-dividend
test_cases=int(input())
for i in range(test_cases):
	query=[int(i) for i in input().split()]
	print(get_output(query))