Problem: You are given a positive integer n. In one move, you can increase n by one (i.e. make n := n + 1). Your task is to find the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains two integers n and s (1 ≤ n ≤ 10^{18}; 1 ≤ s ≤ 162).

Output

For each test case, print the answer: the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

Example

Input


5
2 1
1 1
500 4
217871987498122 10
100000000000000001 1


Output


8
0
500
2128012501878
899999999999999999

Solution (in PYTHON3):

Solution:
# cook your dish here
from sys import stdin,stdout
from collections import Counter
from itertools import permutations
import bisect
import math
I=lambda: map(int,stdin.readline().split())
I1=lambda: stdin.readline()

def fun(n):
    s=0
    while n:
        s+=n%10
        n//=10
    return s 
    
for _ in range(int(I1())):
    n,s=I()
    c=0 
    r=10 
    while fun(n)>s:
        x=n%r 
        c+=r-x 
        n+=r-x 
        r*=10
    print(c)