Problem: You are given a positive integer n. In one move, you can increase n by one (i.e. make n := n + 1). Your task is to find the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains two integers n and s (1 ≤ n ≤ 10^{18}; 1 ≤ s ≤ 162).

Output

For each test case, print the answer: the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

Example

Input


5
2 1
1 1
500 4
217871987498122 10
100000000000000001 1


Output


8
0
500
2128012501878
899999999999999999

Solution (in PYTHON3):

Solution:
t = int(input())
for _ in range(t):
	n,s = map(int,input().split())
	total = n
	x = list(map(int,str(n)))
	sum1 = sum(x)
	if s >= sum1:
		print(0)
		continue
	i = 10
	while  sum1 > s:
		if n%i!=0:
			n = n+(i-(n%i))
		i*=10
		sum1 = list(map(int,str(n)))
		sum1 = sum(sum1)
	print(n - total)