Problem: You are given a positive integer n. In one move, you can increase n by one (i.e. make n := n + 1). Your task is to find the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains two integers n and s (1 ≤ n ≤ 10^{18}; 1 ≤ s ≤ 162).

Output

For each test case, print the answer: the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

Example

Input


5
2 1
1 1
500 4
217871987498122 10
100000000000000001 1


Output


8
0
500
2128012501878
899999999999999999

Solution (in PYTHON3):

Solution:
T = int(input())
def f_sum(n):
    s=last=pw=ctr=0
    fg=False
    while n!=0:
        #print(n,s,last,pw,ctr)
        k=n%10
        n=n//10
        if not fg and k!=0:
            last=k
            fg=True
            pw=ctr
        ctr+=1
        s+=k
    return [s,last,pw]

arr=[]
for _ in range(T):
    n,s = list(map(int,input().split()))
    ans=0
    while True:
        su,last,pw = f_sum(n)
        if(su<=s):
            break
        number = 10-last
        number = number*10**pw
        ans = ans+number
        n = n+number
        #print(ans,n,number)
    arr.append(ans)
for i in arr:
    print(i)