Problem: You are given a positive integer n. In one move, you can increase n by one (i.e. make n := n + 1). Your task is to find the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains two integers n and s (1 ≤ n ≤ 10^{18}; 1 ≤ s ≤ 162).

Output

For each test case, print the answer: the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

Example

Input


5
2 1
1 1
500 4
217871987498122 10
100000000000000001 1


Output


8
0
500
2128012501878
899999999999999999

Solution (in PYTHON3):

Solution:
import sys
# import math
input = sys.stdin.readline


def int_array():
    return list(map(int, input().strip().split()))


def str_array():
    return input().strip().split()


def lower_letters():
    lowercase = [chr(i) for i in range(97, 97+26)]
    return lowercase


def upper_letters():
    uppercase = [chr(i) for i in range(65, 65+26)]
    return uppercase

######################### TEMPLATE ENDS HERE ##################################


for _ in range(int(input())):
    a, b = int_array()
    if a % b != 0:
        print(b*((a//b)+1)-a)
    else:
        print(0)