Problem: You are given a positive integer n. In one move, you can increase n by one (i.e. make n := n + 1). Your task is to find the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains two integers n and s (1 ≤ n ≤ 10^{18}; 1 ≤ s ≤ 162).

Output

For each test case, print the answer: the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

Example

Input


5
2 1
1 1
500 4
217871987498122 10
100000000000000001 1


Output


8
0
500
2128012501878
899999999999999999

Solution (in PYTHON3):

Solution:
# -*- coding: utf-8 -*-
"""
@author: Saurav Sihag
"""

rr = lambda: input().strip()
rri = lambda: int(rr())
# rri = lambda: int(stdin.readline())
rrm = lambda: [int(x) for x in rr().split()]
# stdout.write(str()+'\n')

from sys import stdin, stdout, setrecursionlimit
from math import ceil


def sol():
    x, n=rrm()
    s=str(x)[::-1]
    sm=0
    z=ord('0')
    for c in s:
        sm+=ord(c)-z
    if sm<=n:
        print(0)
        return
    n=sm-n
    res=0
    zz=z+10
    m=1
    prev=0
    for c in s:
        res+=m*(zz-ord(c)-prev)
        n-=ord(c)-z
        prev=1
        if n+prev<=0:
            print(res)
            return
        m*=10
    return

    
def main():
    T = rri()
    for t in range(1, T + 1):
        ans=sol()
        # print("Case #{}: {}".format(t, ans))

main()