Problem: You are given two integers n and k. You are asked to choose maximum number of distinct integers from 1 to n so that there is no subset of chosen numbers with sum equal to k.

A subset of a set is a set that can be obtained from initial one by removing some (possibly all or none) elements of it.

Input

The first line contains the number of test cases T (1 ≤ T ≤ 100).

Each of the next T lines contains two integers n and k (1 ≤ k ≤ n ≤ 1000) — the description of test cases.

Output

For each test case output two lines. In the first line output a single integer m — the number of chosen integers.

In the second line output m distinct integers from 1 to n — the chosen numbers.

If there are multiple answers, print any. You can print the numbers in any order.

Example

Input


3
3 2
5 3
1 1


Output


2
3 1 
3
4 5 2 
0

Solution (in CPP):

Solution:
#include <iostream>
#include<vector>
#include <iomanip>
#include<algorithm>
#include<climits>
#include<cmath>
#include<map>
#include<unordered_set>
#include<set>
#include<queue>
#define ll long long
using namespace std;
 
int min(int a,int b){
    return a<b?a:b;
}
 
ll min(ll a,ll b){
    return a<b?a:b;
}
 
ll max(ll a,ll b){
    return a>b?a:b;
}
 
int maxi(int a,int b){
    return a>b?a:b;
}

bool cmp(pair<ll,vector<int> > a,pair<ll,vector<int> > b){
    return a.first<b.first;
}

void swap(int &a,int &b){
    int t = a;
    a = b;
    b = t;
}

void solve(){
    int n,k;
    cin>>n>>k;
    vector<int> ans;
    for(int i=k+1;i<=n;i++){
        ans.push_back(i);
    }
    for(int i=(k+1)/2;i<k;i++){
        ans.push_back(i);
    }
    cout<<ans.size()<<"\n";
    for(int i:ans){
        cout<<i<<" ";
    }
    cout<<"\n";
}    
 
int main(){
    int t;
    cin>>t;
    while(t--)
    solve();
    return 0;
}