Problem: You are given a positive integer n. In one move, you can increase n by one (i.e. make n := n + 1). Your task is to find the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains two integers n and s (1 ≤ n ≤ 10^{18}; 1 ≤ s ≤ 162).

Output

For each test case, print the answer: the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

Example

Input


5
2 1
1 1
500 4
217871987498122 10
100000000000000001 1


Output


8
0
500
2128012501878
899999999999999999

Solution (in PYTHON3):

Solution:
for _ in range(int(input())):
    s,k=map(str,input().split())
    k=int(k)
    su=0
    for i in range(len(s)):
        su+=int(s[i])
        if su>=k:
            ans=int(s[i:])    
            ans=int("1"+(len(s)-i)*"0")-ans
            # print(ans)
            break
    su=0    
    for i in range(len(s)):
        su+=int(s[i])
    if su<=k:
        print(0)
    else:
        print(ans)