Problem: We have a set S of N points in a two-dimensional plane. The coordinates of the i-th point are (x_i, y_i). The N points have distinct x-coordinates and distinct y-coordinates.

For a non-empty subset T of S, let f(T) be the number of points contained in the smallest rectangle, whose sides are parallel to the coordinate axes, that contains all the points in T. More formally, we define f(T) as follows:

* f(T) :=  (the number of integers i (1 \leq i \leq N) such that a \leq x_i \leq b and c \leq y_i \leq d, where a, b, c, and d are the minimum x-coordinate, the maximum x-coordinate, the minimum y-coordinate, and the maximum y-coordinate of the points in T)



Find the sum of f(T) over all non-empty subset T of S. Since it can be enormous, print the sum modulo 998244353.

Constraints

* 1 \leq N \leq 2 \times 10^5
* -10^9 \leq x_i, y_i \leq 10^9
* x_i \neq x_j (i \neq j)
* y_i \neq y_j (i \neq j)
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N
x_1 y_1
:
x_N y_N


Output

Print the sum of f(T) over all non-empty subset T of S, modulo 998244353.

Examples

Input

3
-1 3
2 1
3 -2


Output

13


Input

4
1 4
2 1
3 3
4 2


Output

34


Input

10
19 -11
-3 -12
5 3
3 -15
8 -14
-9 -20
10 -9
0 2
-7 17
6 -6


Output

7222

Solution (in PYTHON3):

Solution:
import itertools
import os
import sys
from collections import defaultdict

if os.getenv("LOCAL"):
    sys.stdin = open("_in.txt", "r")

sys.setrecursionlimit(2147483647)
INF = float("inf")
IINF = 10 ** 18
MOD = 998244353


class BinaryIndexedTree:
    # http://hos.ac/slides/20140319_bit.pdf
    def __init__(self, size):
        """
        :param int size:
        """
        self._bit = [0] * (size + 1)
        self._size = size

    def add(self, i, w):
        """
        i 番目に w を加える
        :param int i:
        :param int w:
        :return:
        """
        x = i
        while x <= self._size:
            self._bit[x] += w
            x += x & -x

    def sum(self, i):
        """
        0 番目から i 番目までの合計
        :param int i:
        :return:
        """
        ret = 0
        x = i
        while x > 0:
            ret += self._bit[x]
            x -= x & -x
        return ret

    def __len__(self):
        return self._size


def compress(li):
    """
    大小関係を保ったまま 1 以上の数値に圧縮する。
    scipy.stats.rankdata に近い感じ
    :param list li:
    :rtype: list of int
    """
    ret = [0] * len(li)
    rank = 0
    prev = None
    for a, i in sorted([(a, i) for i, a in enumerate(li)]):
        if a != prev:
            rank += 1
        ret[i] = rank
    return ret


# 解説AC
N = int(sys.stdin.readline())
XY = [list(map(int, sys.stdin.readline().split())) for _ in range(N)]


def test():
    ret = 0
    counts = defaultdict(int)
    for selection in itertools.product([0, 1], repeat=N):
        if not any(selection):
            continue
        xs = set([XY[i][0] for i, s in enumerate(selection) if s])
        ys = set([XY[i][1] for i, s in enumerate(selection) if s])
        xl = min(xs)
        xr = max(xs)
        yl = min(ys)
        yr = max(ys)
        r = 0
        for x, y in XY:
            r += xl <= x <= xr and yl <= y <= yr
        ret += r
        counts[r] += 1
    return ret


XY.sort()
Y = [y for _, y in XY]
Y = compress(Y)

# LL[i]: x が X[i] より小さくて、y が Y[i] より小さい数
# LG[i]: x が X[i] より小さくて、y が Y[i] より大きい数
LL = []
LG = []
GL = []
GG = []

bit = BinaryIndexedTree(size=N)
for i, y in enumerate(Y):
    ll = bit.sum(y)
    lg = i - ll
    gl = y - ll - 1
    gg = N - y - lg
    LL.append(ll)
    LG.append(lg)
    GL.append(gl)
    GG.append(gg)
    bit.add(y, 1)

pow2 = [1] * N
p = 1
for i in range(N - 1):
    p = p * 2 % MOD
    pow2[i + 1] = p

# 点 p = (X[i], Y[i]) が何回カウントされるか
ans = 0
for ll, lg, gl, gg in zip(LL, LG, GL, GG):
    # -- p を選ぶ --
    ans += pow2[N - 1]
    # -- p を選ばない --
    # ll, gg をそれぞれ1つ以上選ぶ
    a = (pow2[ll] - 1) * (pow2[gg] - 1) % MOD * pow2[N - ll - gg - 1]
    # lg, gl をそれぞれ1つ以上選ぶ
    b = (pow2[lg] - 1) * (pow2[gl] - 1) % MOD * pow2[N - lg - gl - 1]
    # ll, gg, gl, lg をそれぞれ1つ以上選ぶ
    c = (pow2[ll] - 1) * (pow2[gg] - 1) % MOD * (pow2[lg] - 1) * (pow2[gl] - 1) % MOD
    ans += a + b - c
    ans %= MOD
print(ans)