Problem: Let's denote d(n) as the number of divisors of a positive integer n. You are given three integers a, b and c. Your task is to calculate the following sum:

<image>

Find the sum modulo 1073741824 (230).

Input

The first line contains three space-separated integers a, b and c (1 ≤ a, b, c ≤ 2000).

Output

Print a single integer — the required sum modulo 1073741824 (230).

Examples

Input

2 2 2


Output

20


Input

4 4 4


Output

328


Input

10 10 10


Output

11536

Note

For the first example.

  * d(1·1·1) = d(1) = 1; 
  * d(1·1·2) = d(2) = 2; 
  * d(1·2·1) = d(2) = 2; 
  * d(1·2·2) = d(4) = 3; 
  * d(2·1·1) = d(2) = 2; 
  * d(2·1·2) = d(4) = 3; 
  * d(2·2·1) = d(4) = 3; 
  * d(2·2·2) = d(8) = 4. 



So the result is 1 + 2 + 2 + 3 + 2 + 3 + 3 + 4 = 20.

Solution (in PYTHON3):

Solution:
primes=[2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,53,59,61,67,71,73,79,83,89,97]
def fun(x):
    cnt=0
    ans=1
    for i in primes:
        if x<i:
            break
        cnt=1
        while x%i==0 and x>=i:
            x=x//i
            cnt+=1
        ans*=cnt
    return ans
a,b,c=map(int,input().split())
res=0
dic=dict()
for i in range(1,a+1):
    for j in range(1,b+1):
        for k in range(1,c+1):
            if i*j*k not in dic.keys():
                dic[i*j*k]=fun(i*j*k)
            res+=dic[i*j*k]
print(res%1073741824)