Problem: You are given a positive integer n. In one move, you can increase n by one (i.e. make n := n + 1). Your task is to find the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains two integers n and s (1 ≤ n ≤ 10^{18}; 1 ≤ s ≤ 162).

Output

For each test case, print the answer: the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

Example

Input


5
2 1
1 1
500 4
217871987498122 10
100000000000000001 1


Output


8
0
500
2128012501878
899999999999999999

Solution (in PYTHON3):

Solution:
def solve(n, s):
    dns = [ord(x)-ord('0') for x in str(n)]
    if sum(dns) <= s:
        return 0
    m = len(dns)
    for i, d in enumerate(dns):
        if d >= s:
            return 10**(m-i) - (n % (10**(m-i)))
        s -= d
    return 42


for _ in range(int(input())):
    n, s = [int(x) for x in input().split()]
    print(solve(n, s))