Problem: This is the easy version of the problem. The difference between versions is the constraints on n and a_i. You can make hacks only if all versions of the problem are solved.

First, Aoi came up with the following idea for the competitive programming problem:

Yuzu is a girl who collecting candies. Originally, she has x candies. There are also n enemies numbered with integers from 1 to n. Enemy i has a_i candies.

Yuzu is going to determine a permutation P. A permutation is an array consisting of n distinct integers from 1 to n in arbitrary order. For example, \{2,3,1,5,4\} is a permutation, but \{1,2,2\} is not a permutation (2 appears twice in the array) and \{1,3,4\} is also not a permutation (because n=3 but there is the number 4 in the array).

After that, she will do n duels with the enemies with the following rules:

  * If Yuzu has equal or more number of candies than enemy P_i, she wins the duel and gets 1 candy. Otherwise, she loses the duel and gets nothing. 
  * The candy which Yuzu gets will be used in the next duels. 



Yuzu wants to win all duels. How many valid permutations P exist?

This problem was easy and wasn't interesting for Akari, who is a friend of Aoi. And Akari made the following problem from the above idea:

Let's define f(x) as the number of valid permutations for the integer x.

You are given n, a and a prime number p ≤ n. Let's call a positive integer x good, if the value f(x) is not divisible by p. Find all good integers x.

Your task is to solve this problem made by Akari.

Input

The first line contains two integers n, p (2 ≤ p ≤ n ≤ 2000). It is guaranteed, that the number p is prime (it has exactly two divisors 1 and p).

The second line contains n integers a_1, a_2, …, a_n (1 ≤ a_i ≤ 2000).

Output

In the first line, print the number of good integers x.

In the second line, output all good integers x in the ascending order.

It is guaranteed that the number of good integers x does not exceed 10^5.

Examples

Input


3 2
3 4 5


Output


1
3


Input


4 3
2 3 5 6


Output


2
3 4


Input


4 3
9 1 1 1


Output


0

Note

In the first test, p=2.

  * If x ≤ 2, there are no valid permutations for Yuzu. So f(x)=0 for all x ≤ 2. The number 0 is divisible by 2, so all integers x ≤ 2 are not good. 
  * If x = 3, \{1,2,3\} is the only valid permutation for Yuzu. So f(3)=1, so the number 3 is good. 
  * If x = 4, \{1,2,3\} , \{1,3,2\} , \{2,1,3\} , \{2,3,1\} are all valid permutations for Yuzu. So f(4)=4, so the number 4 is not good. 
  * If x ≥ 5, all 6 permutations are valid for Yuzu. So f(x)=6 for all x ≥ 5, so all integers x ≥ 5 are not good. 



So, the only good number is 3.

In the third test, for all positive integers x the value f(x) is divisible by p = 3.

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.util.ArrayList;
import java.util.Arrays;

public class cf_654 {

	static Reader r = new Reader();
	static PrintWriter out = new PrintWriter(System.out);

	private static void solve1() throws IOException {

		int t = r.nextInt();
		StringBuilder res = new StringBuilder();

		while (t-- > 0) {

			int n = r.nextInt();

			int ans = (int) Math.ceil((double) n / 2);

			res.append(ans).append("\n");

		}

		out.print(res);
		out.close();

	}

	private static void solve2() throws IOException {

		int t = r.nextInt();
		StringBuilder res = new StringBuilder();

		while (t-- > 0) {

			int n = r.nextInt();
			int rt = r.nextInt();

			int min = Math.min(n, rt);

			long ans = 0;

			if (min == n) {
				min--;
				ans = 1;
			}
			ans += ((long) min * (min + 1)) / 2;

			res.append(ans).append("\n");

		}

		out.print(res);
		out.close();

	}

	private static void solve3() throws IOException {

		int t = r.nextInt();
		StringBuilder res = new StringBuilder();

		while (t-- > 0) {

			long a = r.nextLong();
			long b = r.nextLong();
			long n = r.nextLong();
			long m = r.nextLong();

			boolean flag = false;

			if (a + b >= n + m && Math.min(a, b) >= m) {
				flag = true;
			}

			res.append(flag ? "Yes" : "No").append("\n");

		}

		out.print(res);
		out.close();

	}

	private static void solve4() throws IOException {

		int t = r.nextInt();
		StringBuilder res = new StringBuilder();

		while (t-- > 0) {

			int n = r.nextInt();
			int k = r.nextInt();

			int ans[][] = new int[n][n];

			if (k % n == 0) {
				res.append(0).append("\n");
			} else {
				res.append(2).append("\n");
			}

			for (int i = 0; i < n && k > 0; i++) {
				int l = 0, m = i;
				for (int j = 0; j < n && k > 0; j++, k--) {
					ans[l][m] = 1;
					l = (l + 1) % n;
					m = (m + 1) % n;
				}
			}

			for (int i = 0; i < n; i++) {
				for (int j = 0; j < n; j++) {
					res.append(ans[i][j]);
				}
				res.append("\n");
			}

		}

		out.print(res);
		out.close();

	}

	static int arr[], n;

	private static int binarySearch(int val) {
		int lt = 0, rt = arr.length - 1, idx = -1;
		while (lt <= rt) {
			int mid = (lt + rt) / 2;
			if (arr[mid] > val) {
				rt = mid - 1;
			} else {
				lt = mid + 1;
				idx = mid;
			}
		}
		return idx + 1;
	}

	private static void solve5() throws IOException {

		StringBuilder res = new StringBuilder();

		n = r.nextInt();
		int p = r.nextInt();

		arr = r.nextIntArray(n);
		Arrays.sort(arr);

		ArrayList<Integer> good_x = new ArrayList<Integer>();

		for (int x = 1; x <= 2000; x++) {
			boolean flag = true;
			for (int i = 0; i < n; i++) {
				int no_s = binarySearch(x + i);
//				System.out.println(no_s);
				int f_x = no_s - i;
				if (f_x % p == 0) {
					flag = false;
					break;
				}
			}
			if (flag) {
				good_x.add(x);
			}
		}

		res.append(good_x.size()).append("\n");
		for (int x_s : good_x) {
			res.append(x_s).append(" ");
		}

		out.print(res);
		out.close();

	}

	private static void solve6() throws IOException {

		int t = r.nextInt();
		StringBuilder res = new StringBuilder();

		while (t-- > 0) {

			int n = r.nextInt();

			res.append(false).append("\n");

		}

		out.print(res);
		out.close();

	}

	public static void main(String[] args) throws IOException {

//		solve1();

//		solve2();

//		solve3();

//		solve4();

		solve5();

//		solve6();

	}

	static class Reader {

		final private int BUFFER_SIZE = 1 << 12;
		boolean consume = false;
		private byte[] buffer;
		private int bufferPointer, bytesRead;
		private boolean reachedEnd = false;

		public Reader() {
			buffer = new byte[BUFFER_SIZE];
			bufferPointer = 0;
			bytesRead = 0;
		}

		public boolean hasNext() {
			return !reachedEnd;
		}

		private void fillBuffer() throws IOException {
			bytesRead = System.in.read(buffer, bufferPointer = 0, BUFFER_SIZE);
			if (bytesRead == -1) {
				buffer[0] = -1;
				reachedEnd = true;
			}
		}

		private void consumeSpaces() throws IOException {
			while (read() <= ' ' && reachedEnd == false)
				;
			bufferPointer--;
		}

		private byte read() throws IOException {
			if (bufferPointer == bytesRead) {
				fillBuffer();
			}
			return buffer[bufferPointer++];
		}

		public String next() throws IOException {
			StringBuilder sb = new StringBuilder();
			consumeSpaces();
			byte c = read();
			do {
				sb.append((char) c);
			} while ((c = read()) > ' ');
			if (consume) {
				consumeSpaces();
			}
			;
			if (sb.length() == 0) {
				return null;
			}
			return sb.toString();
		}

		public String nextLine() throws IOException {
			BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
			String str = br.readLine();
			return str;
		}

		public int nextInt() throws IOException {
			consumeSpaces();
			int ret = 0;
			byte c = read();
			boolean neg = (c == '-');
			if (neg) {
				c = read();
			}
			do {
				ret = ret * 10 + c - '0';
			} while ((c = read()) >= '0' && c <= '9');
			if (consume) {
				consumeSpaces();
			}
			if (neg) {
				return -ret;
			}
			return ret;
		}

		public long nextLong() throws IOException {
			consumeSpaces();
			long ret = 0;
			byte c = read();
			boolean neg = (c == '-');
			if (neg) {
				c = read();
			}
			do {
				ret = ret * 10L + c - '0';
			} while ((c = read()) >= '0' && c <= '9');
			if (consume) {
				consumeSpaces();
			}
			if (neg) {
				return -ret;
			}
			return ret;
		}

		public double nextDouble() throws IOException {
			consumeSpaces();
			double ret = 0;
			double div = 1;
			byte c = read();
			boolean neg = (c == '-');
			if (neg) {
				c = read();
			}
			do {
				ret = ret * 10 + c - '0';
			} while ((c = read()) >= '0' && c <= '9');
			if (c == '.') {
				while ((c = read()) >= '0' && c <= '9') {
					ret += (c - '0') / (div *= 10);
				}
			}
			if (consume) {
				consumeSpaces();
			}
			if (neg) {
				return -ret;
			}
			return ret;
		}

		public int[] nextIntArray(int n) throws IOException {
			int[] a = new int[n];
			for (int i = 0; i < n; i++) {
				a[i] = nextInt();
			}
			return a;
		}

		public long[] nextLongArray(int n) throws IOException {
			long[] a = new long[n];
			for (int i = 0; i < n; i++) {
				a[i] = nextLong();
			}
			return a;
		}

		public int[][] nextIntMatrix(int n, int m) throws IOException {
			int[][] grid = new int[n][m];
			for (int i = 0; i < n; i++) {
				grid[i] = nextIntArray(m);
			}
			return grid;
		}

		public char[][] nextCharacterMatrix(int n) throws IOException {
			char[][] a = new char[n][];
			for (int i = 0; i < n; i++) {
				a[i] = next().toCharArray();
			}
			return a;
		}

		public void close() throws IOException {
			if (System.in == null) {
				return;
			} else {
				System.in.close();
			}
		}
	}

}