Problem: The array a with n integers is given. Let's call the sequence of one or more consecutive elements in a segment. Also let's call the segment k-good if it contains no more than k different values.

Find any longest k-good segment.

As the input/output can reach huge size it is recommended to use fast input/output methods: for example, prefer to use scanf/printf instead of cin/cout in C++, prefer to use BufferedReader/PrintWriter instead of Scanner/System.out in Java.

Input

The first line contains two integers n, k (1 ≤ k ≤ n ≤ 5·105) — the number of elements in a and the parameter k.

The second line contains n integers ai (0 ≤ ai ≤ 106) — the elements of the array a.

Output

Print two integers l, r (1 ≤ l ≤ r ≤ n) — the index of the left and the index of the right ends of some k-good longest segment. If there are several longest segments you can print any of them. The elements in a are numbered from 1 to n from left to right.

Examples

Input

5 5
1 2 3 4 5


Output

1 5


Input

9 3
6 5 1 2 3 2 1 4 5


Output

3 7


Input

3 1
1 2 3


Output

1 1

Solution (in PYTHON3):

Solution:


n= int(input())


t = list(map(int,input().split()))


f={}


l=[]

st = 1
for j in range(n):
    if t[j] not in f:
        f[t[j]]=1
    else:
        l.append([st,j+1])
        f={}
        st=j+2



if st!= n+1:
    if len(l)>0:
        a=l.pop()[0]
        l.append([a,n])

        print(len(l))
        for j in l:
            print(*j)
    else:
        print(-1)
else:

    print(len(l))

    for j in l:
        print(*j)