Problem: You are given a positive integer n. In one move, you can increase n by one (i.e. make n := n + 1). Your task is to find the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains two integers n and s (1 ≤ n ≤ 10^{18}; 1 ≤ s ≤ 162).

Output

For each test case, print the answer: the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

Example

Input


5
2 1
1 1
500 4
217871987498122 10
100000000000000001 1


Output


8
0
500
2128012501878
899999999999999999

Solution (in PYTHON3):

Solution:
for _ in range(int(input())):
	n,s = map(int,input().split())
	a = [int(i) for i in str(n)]
	ans = 0
	i=0
	if sum(a)<=s:
		print(0)
		continue
	while(ans<s and i<len(a)):
		ans+=a[i]
		i+=1
	b = []
	for j in range(i-1,len(a)):
		b.append(a[j])
	# print(b)s
	c = ''.join(str(i) for i in b)
	d = 10**len(c)
	print(d-int(c))