Problem: One way to create a task is to learn from math. You can generate some random math statement or modify some theorems to get something new and build a new task from that.

For example, there is a statement called the "Goldbach's conjecture". It says: "each even number no less than four can be expressed as the sum of two primes". Let's modify it. How about a statement like that: "each integer no less than 12 can be expressed as the sum of two composite numbers." Not like the Goldbach's conjecture, I can prove this theorem.

You are given an integer n no less than 12, express it as a sum of two composite numbers.

Input

The only line contains an integer n (12 ≤ n ≤ 106).

Output

Output two composite integers x and y (1 < x, y < n) such that x + y = n. If there are multiple solutions, you can output any of them.

Examples

Input

12


Output

4 8


Input

15


Output

6 9


Input

23


Output

8 15


Input

1000000


Output

500000 500000

Note

In the first example, 12 = 4 + 8 and both 4, 8 are composite numbers. You can output "6 6" or "8 4" as well.

In the second example, 15 = 6 + 9. Note that you can't output "1 14" because 1 is not a composite number.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int main() {
  long int n, ni, nd;
  int i;
  cin >> n;
  if (n % 2 == 0) {
    ni = (n) / 2;
    nd = (n) / 2;
    if ((ni % 2 == 0 || ni % 3 == 0) && (nd % 2 == 0 || nd % 3 == 0)) {
      cout << ni << " " << nd << endl;
    } else {
      while ((ni + nd) == n && nd > 1) {
        if ((ni % 2 == 0 || ni % 3 == 0) && (nd % 2 == 0 || nd % 3 == 0)) {
          cout << ni << " " << nd << endl;
          return 0;
        }
        ni++;
        nd--;
      }
    }
  } else {
    ni = (n + 1) / 2;
    nd = (n - 1) / 2;
    while ((ni + nd) == n && nd > 1) {
      if ((ni % 2 == 0 || ni % 3 == 0) && (nd % 2 == 0 || nd % 3 == 0)) {
        cout << ni << " " << nd << endl;
        return 0;
      }
      ni++;
      nd--;
    }
  }
  return 0;
}