Problem: You are given a positive integer n. In one move, you can increase n by one (i.e. make n := n + 1). Your task is to find the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains two integers n and s (1 ≤ n ≤ 10^{18}; 1 ≤ s ≤ 162).

Output

For each test case, print the answer: the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

Example

Input


5
2 1
1 1
500 4
217871987498122 10
100000000000000001 1


Output


8
0
500
2128012501878
899999999999999999

Solution (in PYTHON3):

Solution:
for _ in range(int(input())):
	a,b=map(int,input().split())
	t=a
	x=list(map(int,list(str(a))))
	s=sum(x)
	if(s<=b):
		print(0)
	else:
		i=10
		while s>b:
			if(a%i==0):
				pass
			else:

				a=a+(i-(a%i))
			i*=10
			x=list(map(int,list(str(a))))
			s=sum(x)
		print(a-t)