Problem: A line on the plane is described by an equation Ax + By + C = 0. You are to find any point on this line, whose coordinates are integer numbers from  - 5·1018 to 5·1018 inclusive, or to find out that such points do not exist.

Input

The first line contains three integers A, B and C ( - 2·109 ≤ A, B, C ≤ 2·109) — corresponding coefficients of the line equation. It is guaranteed that A2 + B2 > 0.

Output

If the required point exists, output its coordinates, otherwise output -1.

Examples

Input

2 5 3


Output

6 -3

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
const long double PI = acos(-1);
const long double EPS = 1e-11;
const long long INF = 1e18 + 5;
const long long mod = 1e9 + 7, MOD = 1073741824;
const int N = 1e5 + 5, M = 505;
using namespace std;
void move1step(long long& a, long long& b, long long q) {
  long long c = a - q * b;
  a = b;
  b = c;
}
long long egcd(long long r0, long long r1, long long& x0, long long& y0) {
  long long x1 = 0, y1 = 1;
  x0 = 1;
  y0 = 0;
  while (r1) {
    long long q = r0 / r1;
    move1step(r0, r1, q);
    move1step(x0, x1, q);
    move1step(y0, y1, q);
  }
  return r0;
}
int main() {
  ios_base::sync_with_stdio(0);
  cin.tie(0);
  cout.tie(0);
  int testcases = 1;
  while (testcases--) {
    long long a, b, c, x, y;
    cin >> a >> b >> c;
    long long g = egcd(-a, -b, x, y);
    if (c % g) {
      cout << -1 << "\n";
      continue;
    }
    long long num = c / g;
    x *= num;
    y *= num;
    cout << x << " " << y << "\n";
  }
  return 0;
}