Problem: Ringo found a string s of length n in his [yellow submarine](https://www.youtube.com/watch?v=m2uTFF_3MaA). The string contains only lowercase letters from the English alphabet. As Ringo and his friends love palindromes, he would like to turn the string s into a palindrome by applying two types of operations to the string. 

The first operation allows him to choose i (2 ≤ i ≤ n-1) and to append the substring s_2s_3 … s_i (i - 1 characters) reversed to the front of s.

The second operation allows him to choose i (2 ≤ i ≤ n-1) and to append the substring s_i s_{i + 1}… s_{n - 1} (n - i characters) reversed to the end of s.

Note that characters in the string in this problem are indexed from 1.

For example suppose s=abcdef. If he performs the first operation with i=3 then he appends cb to the front of s and the result will be cbabcdef. Performing the second operation on the resulted string with i=5 will yield cbabcdefedc.

Your task is to help Ringo make the entire string a palindrome by applying any of the two operations (in total) at most 30 times. The length of the resulting palindrome must not exceed 10^6

It is guaranteed that under these constraints there always is a solution. Also note you do not have to minimize neither the number of operations applied, nor the length of the resulting string, but they have to fit into the constraints.

Input

The only line contains the string S (3 ≤ |s| ≤ 10^5) of lowercase letters from the English alphabet.

Output

The first line should contain k (0≤ k ≤ 30) — the number of operations performed.

Each of the following k lines should describe an operation in form L i or R i. L represents the first operation, R represents the second operation, i represents the index chosen.

The length of the resulting palindrome must not exceed 10^6.

Examples

Input


abac


Output


2
R 2
R 5


Input


acccc


Output


2
L 4
L 2


Input


hannah


Output


0

Note

For the first example the following operations are performed:

abac → abacab → abacaba

The second sample performs the following operations: acccc → cccacccc → ccccacccc

The third example is already a palindrome so no operations are required.

Solution (in JAVA):

Solution:


import javax.swing.tree.TreeNode;
import java.io.IOException;
import java.io.InputStream;
import java.util.*;

public class TestClass {


    static final class InputReader {
        private final InputStream stream;
        private final byte[] buf = new byte[1024];
        private int curChar;
        private int numChars;

        public InputReader(InputStream stream) {
            this.stream = stream;
        }

        private int read() throws IOException {
            if (curChar >= numChars) {
                curChar = 0;
                numChars = stream.read(buf);
                if (numChars <= 0) {
                    return -1;
                }
            }
            return buf[curChar++];
        }

        public final int readInt() throws IOException {
            return (int) readLong();
        }

        public final long readLong() throws IOException {
            int c = read();
            while (isSpaceChar(c)) {
                c = read();
                if (c == -1) throw new IOException();
            }
            boolean negative = false;
            if (c == '-') {
                negative = true;
                c = read();
            }
            long res = 0;
            do {
                res *= 10;
                res += c - '0';
                c = read();
            } while (!isSpaceChar(c));
            return negative ? -res : res;
        }

        public final int[] readIntArray(int size) throws IOException {
            int[] array = new int[size];
            for (int i = 0; i < size; i++) {
                array[i] = readInt();
            }
            return array;
        }

        public final long[] readLongArray(int size) throws IOException {
            long[] array = new long[size];
            for (int i = 0; i < size; i++) {
                array[i] = readLong();
            }
            return array;
        }

        public final String readString() throws IOException {
            int c = read();
            while (isSpaceChar(c)) {
                c = read();
            }
            StringBuilder res = new StringBuilder();
            do {
                res.append((char) c);
                c = read();
            } while (!isSpaceChar(c));
            return res.toString();
        }

        private boolean isSpaceChar(int c) {
            return c == ' ' || c == '\n' || c == '\r' || c == '\t' || c == -1;
        }
    }

    static long mulmod(long a, long b,
                       long mod) {
        long res = 0; // Initialize result
        a = a % mod;
        while (b > 0) {
            // If b is odd, add 'a' to result
            if (b % 2 == 1) {
                res = (res + a) % mod;
            }

            // Multiply 'a' with 2
            a = (a * 2) % mod;

            // Divide b by 2
            b /= 2;
        }

        // Return result
        return res % mod;
    }

    static long pow(long a, long b, long MOD) {
        long x = 1, y = a;
        while (b > 0) {
            if (b % 2 == 1) {
                x = (x * y);
                if (x > MOD) x %= MOD;
            }
            y = (y * y);
            if (y > MOD) y %= MOD;
            b /= 2;
        }
        return x;
    }

    static long[] f = new long[100001];

    static long InverseEuler(long n, long MOD) {
        return pow(n, MOD - 2, MOD);
    }

    static long C(int n, int r, long MOD) {

        return (f[n] * ((InverseEuler(f[r], MOD) * InverseEuler(f[n - r], MOD)) % MOD)) % MOD;
    }


    static int[] h = {0, 0, -1, 1};
    static int[] v = {1, -1, 0, 0};


    public static class Pair {
        public int a;

        public int b;

        @Override
        public boolean equals(Object o) {
            if (this == o) return true;
            if (o == null || getClass() != o.getClass()) return false;
            Pair pair = (Pair) o;
            return a == pair.a &&
                    b == pair.b;
        }

        @Override
        public int hashCode() {
            return Objects.hash(a, b);
        }

        public Pair(int a, int b) {
            this.a = a;
            this.b = b;
        }
    }

    static class Pair2 {
        public long cost;
        int node;

        public Pair2(long cos, int node) {
            this.cost = cos;
            this.node = node;
        }
    }

    static long compute_hash(String s) {
        int p = 31;
        int m = 1000000007;
        long hash_value = 0;
        long p_pow = 1;
        for (int i = 0; i < s.length(); ++i) {
            char c = s.charAt(i);
            hash_value = (hash_value + (c - 'a' + 1) * p_pow) % m;
            p_pow = (p_pow * p) % m;
        }
        return hash_value;
    }

    public static class SegmentTree {
        long[][] tree;
        int n;

        public SegmentTree(int[] nodes) {
            tree = new long[nodes.length * 4][2];
            n = nodes.length;
            build(0, n - 1, 0, nodes);

        }

        private void build(int l, int r, int pos, int[] nodes) {
            if (l == r) {
                tree[pos][0] = nodes[l];
                tree[pos][1] = l;
                return;
            }
            int mid = (l + r) / 2;
            build(l, mid, 2 * pos + 1, nodes);
            build(mid + 1, r, 2 * pos + 2, nodes);
            if (tree[2 * pos + 1][0] > tree[2 * pos + 2][0]) {
                tree[pos][1] = tree[2 * pos + 1][1];
            } else {
                tree[pos][1] = tree[2 * pos + 2][1];
            }
            tree[pos][0] = Math.max(tree[2 * pos + 1][0], tree[2 * pos + 2][0]);
        }

//        public void update(int pos, int val) {
//            updateUtil(0, n - 1, 0, pos, val);
//        }

        public long[] get(int l, int r) {
            return getUtil(0, n - 1, 0, l, r);
        }

        private long[] getUtil(int l, int r, int pos, int ql, int qr) {
            if (ql > r || qr < l) {
                return new long[]{-1, -1};
            }
            if (l >= ql && r <= qr) {
                return tree[pos];
            }

            int mid = (l + r) / 2;
            long[] left = getUtil(l, mid, 2 * pos + 1, ql, qr);
            long[] right = getUtil(mid + 1, r, 2 * pos + 2, ql, qr);
            long choice = right[1];
            if (left[0] > right[0]) choice = left[1];
            return new long[]{Math.max(left[0], right[0]), choice};

        }

//        private void updateUtil(int l, int r, int pos, int i, int val) {
//            if (i < l || i > r) {
//                return;
//            }
//            if (l == r) {
//                tree[pos] = val;
//                return;
//            }
//            int mid = (l + r) / 2;
//            updateUtil(l, mid, 2 * pos + 1, i, val);
//            updateUtil(mid + 1, r, 2 * pos + 2, i, val);
//            tree[pos] = tree[2 * pos + 1] + tree[2 * pos + 2];
//        }
    }

    static int counter = 0;
    static int[] rIn;
    static int[] rOut;
    static int[] lIn;
    static int[] lOut;
    private static int[] flatten;
    private static int[] lFlatten;
    static long answer = 0;

    static int VISITED = 1;
    static int VISITING = 2;

    static int[] DIRX = new int[]{0, 0, 1, -1};
    static int[] DIRY = new int[]{1, -1, 0, 0};

    public static void main(String[] args) throws Exception {
        //https://i...content-available-to-author-only...e.com/ebRGa6
        InputReader in = new InputReader(System.in);


        int t = 1;
        while (t-- > 0) {

            String s = in.readString();

            System.out.println(4);
            int len = s.length();
            len += s.length() - 2;
            len += 1;
            len += len - 2;
            System.out.println("R 2");
            System.out.println("L 2");
            System.out.println("R 2");
            System.out.println("R " + (len - 1));


        }

    }

    private static int dfs(HashMap<Pair, TreeSet<Pair>> grid, int x, int y, int ti, HashSet<Pair> vis, int r, int startX, int startY) {
//        System.out.println(x + "  " + y);
        int taken = ti - Math.abs(startX - x) - Math.abs(startY - y);
        if (taken < 0) return 0;
        if (x < 0 || y < 0 || x > r || y > r) return 0;
        if (vis.contains(new Pair(x, y))) return 0;
        int max = 0;

        if (grid.containsKey(new Pair(x, y))) {
            TreeSet<Pair> times = grid.get(new Pair(x, y));
            for (Pair t : times) {
                if (t.a <= taken) {
                    max = Math.max(t.b, max);
                } else break;
            }
        }
        vis.add(new Pair(x, y));
        max = Math.max(dfs(grid, x + 1, y, ti, vis, r, startX, startY), max);
        max = Math.max(dfs(grid, x, y + 1, ti, vis, r, startX, startY), max);
        max = Math.max(dfs(grid, x - 1, y, ti, vis, r, startX, startY), max);
        max = Math.max(dfs(grid, x, y - 1, ti, vis, r, startX, startY), max);
        return max;
    }

    private static int solver(int[] nums, int pos, int[] dp) {
        if (pos >= nums.length) return 0;
        if (dp[pos] != Integer.MAX_VALUE) return dp[pos];
        int min = solver(nums, pos + 2, dp) + nums[pos];
        min = Math.min(solver(nums, pos + 3, dp) + nums[pos], min);
        if (pos + 1 < nums.length) min = Math.min(min, nums[pos] + nums[pos + 1] + solver(nums, pos + 3, dp));
        if (pos + 1 < nums.length) min = Math.min(min, nums[pos] + nums[pos + 1] + solver(nums, pos + 4, dp));

//        System.out.println(pos + " " + min);
        return dp[pos] = min;
    }


    static int countFreq(String pattern, String text) {
        int m = pattern.length();
        int n = text.length();
        int res = 0;

        for (int i = 0; i <= n - m; i++) {
            int j;
            for (j = 0; j < m; j++) {
                if (text.charAt(i + j) != pattern.charAt(j)) {
                    break;
                }
            }
            if (j == m) {
                res++;
                j = 0;
            }
        }
        return res;
    }

    private static int solve(int n, int[] dp, int cn) {
        if (cn > n) return 0;
        if (cn == n) return 1;
        if (dp[cn] != -1) return dp[cn];
        int ans = 0;
        for (int i = 2; i <= 9; ++i) {
            ans += solve(n, dp, cn * i);
        }
        return dp[cn] = ans;
    }


    private static void dfsR(List<List<Integer>> g, int node, int[] v) {
        rIn[node] = counter;
        flatten[counter++] = v[node];

        for (int i = 0; i < g.get(node).size(); ++i) {
            dfsR(g, g.get(node).get(i), v);
        }

        rOut[node] = counter;
        flatten[counter++] = v[node] * -1;
    }

    private static void dfsL(List<List<Integer>> g, int node, int[] v) {
        lIn[node] = counter;
        lFlatten[counter++] = v[node];

        for (int i = 0; i < g.get(node).size(); ++i) {
            dfsL(g, g.get(node).get(i), v);
        }

        lOut[node] = counter;
        lFlatten[counter++] = v[node] * -1;

        TreeMap<String, Integer> map = new TreeMap<>();
    }


    private static void preprocess(int pos, int[][] pre, List<List<Integer>> tree, int[] traverse, int depth, int last, int[] tin, int[] tout) {
        tin[pos] = counter++;
        traverse[depth] = pos;

        for (int i = 0; depth - (1 << i) >= 0; ++i) {
            pre[pos][i] = traverse[depth - (1 << i)];
        }

        for (int i = 0; i < tree.get(pos).size(); ++i) {
            if (tree.get(pos).get(i) != last)
                preprocess(tree.get(pos).get(i), pre, tree, traverse, depth + 1, pos, tin, tout);
        }
        tout[pos] = counter++;
    }

    static int gcd(int a, int b) {

        while (b != 0) {
            int t = a;
            a = b;
            b = t % b;
        }
        return a;
    }


    static boolean submit = true;

    static void debug(String s) {
        if (!submit)
            System.out.println(s);
    }

    static void debug(int s) {

        Stack<Integer> st = new Stack<>();
        if (!submit)
            System.out.println(s);


        /*

        4 2 3 _ 2 4 3 _
         */
    }



}