Problem: You are given a positive integer n. In one move, you can increase n by one (i.e. make n := n + 1). Your task is to find the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains two integers n and s (1 ≤ n ≤ 10^{18}; 1 ≤ s ≤ 162).

Output

For each test case, print the answer: the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

Example

Input


5
2 1
1 1
500 4
217871987498122 10
100000000000000001 1


Output


8
0
500
2128012501878
899999999999999999

Solution (in PYTHON3):

Solution:
def nod(a,b):
      while a != b:
            a, b = max(a,b), min(a,b)
            if a % b == 0:
                  a -= (a // b - 1) * b
            else:
                  a -= (a // b) * b
      return a
for i in range(int(input())):
      a, b = [int(x) for x in input().split()]
      if a % b == 0:
            print(0)
      else:
            print((a // b + 1) * b  - a)