Problem: You are given a positive integer n. In one move, you can increase n by one (i.e. make n := n + 1). Your task is to find the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains two integers n and s (1 ≤ n ≤ 10^{18}; 1 ≤ s ≤ 162).

Output

For each test case, print the answer: the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

Example

Input


5
2 1
1 1
500 4
217871987498122 10
100000000000000001 1


Output


8
0
500
2128012501878
899999999999999999

Solution (in PYTHON3):

Solution:
import math
def main():
    for x in range(int(input())):
        arr=list(map(int,input().split()))
        if(arr[0]%arr[1]==0):
            print(0)
        else:
            if(arr[0]<arr[1]):
                print(arr[1]-arr[0])
            else:
                print(round((math.ceil(float(arr[0]/arr[1]))-float(arr[0]/arr[1]))*arr[1]))
    
main()