Problem: Let n be an integer. Consider all permutations on integers 1 to n in lexicographic order, and concatenate them into one big sequence P. For example, if n = 3, then P = [1, 2, 3, 1, 3, 2, 2, 1, 3, 2, 3, 1, 3, 1, 2, 3, 2, 1]. The length of this sequence is n ⋅ n!.

Let 1 ≤ i ≤ j ≤ n ⋅ n! be a pair of indices. We call the sequence (P_i, P_{i+1}, ..., P_{j-1}, P_j) a subarray of P. 

You are given n. Find the number of distinct subarrays of P. Since this number may be large, output it modulo 998244353 (a prime number). 

Input

The only line contains one integer n (1 ≤ n ≤ 10^6), as described in the problem statement.

Output

Output a single integer — the number of distinct subarrays, modulo 998244353.

Examples

Input


2


Output


8


Input


10


Output


19210869

Note

In the first example, the sequence P = [1, 2, 2, 1]. It has eight distinct subarrays: [1], [2], [1, 2], [2, 1], [2, 2], [1, 2, 2], [2, 2, 1] and [1, 2, 2, 1]. 

Solution (in JAVA):

Solution:
import java.util.*;
import java.io.*;
//import javafx.util.Pair;
public class Main implements Runnable 
{  
    
    static class Pair implements Comparable <Pair>
    {
        int x,y;
        Pair(int x,int y)
        {
            this.x=x;
            this.y=y;
        }
        public int compareTo(Pair p)
        {
            if(x==p.x)
                return Integer.compare(y,p.y);
            return Integer.compare(x,p.x);
        }
    }
    
    public static void main(String[] args)
    {
        new Thread(null, new Main(), "rev", 1 << 29).start();
    }

    public void run()
    {
        InputStream inputStream = System.in;
        OutputStream outputStream = System.out;
        InputReader in = new InputReader(inputStream);
        PrintWriter out = new PrintWriter(outputStream);
        Task solver = new Task();
        solver.solve(1,in,out);
        out.close();
    }
    
    static class Task
    { 
        //int max=(int)1e6+1;
        int m=998244353;
        void solve(int testNumber, InputReader in, PrintWriter out)
        {
            int n=in.nextInt();
            long []dp1=new long[n+1];
            long []dp2=new long[n+1];
            dp1[1]=1;
            for(int i=2;i<=n;i++)
                dp1[i]=i*dp1[i-1]%m;
            dp2[1]=1;
            for(int i=2;i<=n;i++)
                dp2[i]=i*(((dp2[i-1]+dp1[i-1])%m-1+m)%m)%m;
            out.println(dp2[n]);
        }
    }
    /*static class OutputWriter
    {
        private final PrintWriter writer;

        public OutputWriter(OutputStream outputStream)
        {
            writer = new PrintWriter(new BufferedWriter(new OutputStreamWriter(outputStream)));
        }

        public OutputWriter(Writer writer)
        {
            this.writer = new PrintWriter(writer);
        }

        public void print(Object... objects)
        {
            for(int i=0;i<objects.length;i++)
            {
                if (i!=0)
                {
                    writer.print(' ');
                }
                writer.print(objects[i]);
            }
        }

        public void println(Object... objects)
        {
            print(objects);
            writer.println();
        }

        public void close()
        {
            writer.close();
        }
    }*/

static class InputReader 
{
    private InputStream stream;
    private byte[] buf = new byte[8192];
    private int curChar, snumChars;
    private SpaceCharFilter filter;
 
    public InputReader(InputStream stream) 
    {
        this.stream = stream;
    }
 
    public int snext() 
    {
        if(snumChars==-1)
            throw new InputMismatchException();
        if(curChar>=snumChars)
        {
            curChar=0;
            try 
            {
                snumChars = stream.read(buf);                
            } 
            catch(IOException e) 
            {
                throw new InputMismatchException();
            }
            if(snumChars<=0)
                return -1;
        }
        return buf[curChar++];
    }
 
    public int nextInt()
    {
        int c = snext();
        while(isSpaceChar(c))
            c=snext();
        int sgn=1;
        if(c=='-')
        {
            sgn = -1;
            c = snext();
        }
        int res=0;
        do
        {
            if(c<'0' || c>'9')
                throw new InputMismatchException();
            res*=10;
            res+=c-'0';
            c=snext();
            }while(!isSpaceChar(c));
        return res * sgn;
    }
 
    public long nextLong()
    {
        int c = snext();
        while(isSpaceChar(c))
            c=snext();
        int sgn=1;
        if(c=='-')
        {
            sgn=-1;
            c=snext();
        }
        long res=0;
        do{
            if (c<'0' || c>'9')
                throw new InputMismatchException();
            res*=10;
            res+=c-'0';
            c=snext();
        }while (!isSpaceChar(c));
        return res * sgn;
    }
 
    public int[] nextIntArray(int n)
    {
        int a[]=new int[n];
        for(int i=1; i<n; i++)
            a[i]=nextInt();
        return a;
    }

    public long[] nextLongArray(int n)
    {
        long a[]=new long[n];
        for(int i=1; i<n; i++)
            a[i]=nextLong();
        return a;
    }
    public String nextString()
    {
        int c=snext();
        while(isSpaceChar(c))
            c=snext();
        StringBuilder res=new StringBuilder();
        do{
            res.appendCodePoint(c);
            c = snext();
        }while (!isSpaceChar(c));
        return res.toString();
    }
 
    public boolean isSpaceChar(int c)
    {
        if(filter != null)
            return filter.isSpaceChar(c);
        return c==' ' || c=='\n' || c=='\r' || c=='\t' || c==-1;
    }
 
    public interface SpaceCharFilter
    {
        public boolean isSpaceChar(int ch);
    }
}
}