Problem: You are given a positive integer n. In one move, you can increase n by one (i.e. make n := n + 1). Your task is to find the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains two integers n and s (1 ≤ n ≤ 10^{18}; 1 ≤ s ≤ 162).

Output

For each test case, print the answer: the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

Example

Input


5
2 1
1 1
500 4
217871987498122 10
100000000000000001 1


Output


8
0
500
2128012501878
899999999999999999

Solution (in PYTHON3):

Solution:
def f(n):
  r = 0
  while n:
    r += n%10
    n //= 10
  return r

def solve():
  n, s = (int(x) for x in input().split())
  orig = n
  mod = 10
  while f(n) > s:
    while n % mod == 0:
      mod *= 10
    n += mod - (n % mod)
  print(n - orig)

t = int(input())
for _ in range(t):
  solve()