Problem: A line on the plane is described by an equation Ax + By + C = 0. You are to find any point on this line, whose coordinates are integer numbers from  - 5·1018 to 5·1018 inclusive, or to find out that such points do not exist.

Input

The first line contains three integers A, B and C ( - 2·109 ≤ A, B, C ≤ 2·109) — corresponding coefficients of the line equation. It is guaranteed that A2 + B2 > 0.

Output

If the required point exists, output its coordinates, otherwise output -1.

Examples

Input

2 5 3


Output

6 -3

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
long long help(long long a, long long b, long long &x, long long &y) {
  if (!b) {
    x = 1;
    y = 0;
    return a;
  } else {
    long long ans = help(b, a % b, x, y);
    long long t = x;
    x = y;
    y = t - (a / b) * y;
    return ans;
  }
}
int main() {
  ios::sync_with_stdio(false);
  cin.tie(0);
  cout.tie(0);
  long long a, b, c, x, y;
  cin >> a >> b >> c;
  long long d = help(a, b, x, y);
  if (c % d) {
    cout << -1;
  } else {
    cout << -x * (c / d) << ' ' << -y * (c / d);
  }
  cout << '\n';
  return 0;
}