Problem: One way to create a task is to learn from math. You can generate some random math statement or modify some theorems to get something new and build a new task from that.

For example, there is a statement called the "Goldbach's conjecture". It says: "each even number no less than four can be expressed as the sum of two primes". Let's modify it. How about a statement like that: "each integer no less than 12 can be expressed as the sum of two composite numbers." Not like the Goldbach's conjecture, I can prove this theorem.

You are given an integer n no less than 12, express it as a sum of two composite numbers.

Input

The only line contains an integer n (12 ≤ n ≤ 106).

Output

Output two composite integers x and y (1 < x, y < n) such that x + y = n. If there are multiple solutions, you can output any of them.

Examples

Input

12


Output

4 8


Input

15


Output

6 9


Input

23


Output

8 15


Input

1000000


Output

500000 500000

Note

In the first example, 12 = 4 + 8 and both 4, 8 are composite numbers. You can output "6 6" or "8 4" as well.

In the second example, 15 = 6 + 9. Note that you can't output "1 14" because 1 is not a composite number.

Solution (in JAVA):

Solution:
import java.util.Scanner;

public class trial_1 {
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        int n = in.nextInt();

        int i = n/2, j = n-i;

        if (i%2 == 0 && j%2 == 0) System.out.println(i + " " + j);
        else {
            while(isPrime(i) || isPrime(j)) {
                i--;
                j++;
            }
            System.out.println(i + " " + j);
        }
    }

    static boolean isPrime (int n) {

        // Check if number is less than
        // equal to 1
        if (n <= 1) return false;

            // Check if number is 2
        else if (n == 2) return true;

            // Check if n is a multiple of 2
        else if (n % 2 == 0) return false;

        // If not, then just check the odds
        for (int i = 3; i <= Math.sqrt(n); i += 2) {
            if (n % i == 0) return false;
        }
        return true;
    }
}