Problem: The array a with n integers is given. Let's call the sequence of one or more consecutive elements in a segment. Also let's call the segment k-good if it contains no more than k different values.

Find any longest k-good segment.

As the input/output can reach huge size it is recommended to use fast input/output methods: for example, prefer to use scanf/printf instead of cin/cout in C++, prefer to use BufferedReader/PrintWriter instead of Scanner/System.out in Java.

Input

The first line contains two integers n, k (1 ≤ k ≤ n ≤ 5·105) — the number of elements in a and the parameter k.

The second line contains n integers ai (0 ≤ ai ≤ 106) — the elements of the array a.

Output

Print two integers l, r (1 ≤ l ≤ r ≤ n) — the index of the left and the index of the right ends of some k-good longest segment. If there are several longest segments you can print any of them. The elements in a are numbered from 1 to n from left to right.

Examples

Input

5 5
1 2 3 4 5


Output

1 5


Input

9 3
6 5 1 2 3 2 1 4 5


Output

3 7


Input

3 1
1 2 3


Output

1 1

Solution (in JAVA):

Solution:
import java.io.BufferedOutputStream;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.util.HashMap;
import java.util.LinkedList;
import java.util.Queue;
import java.util.StringTokenizer;

public class main {
    private static PrintWriter out;
    private static class FastScanner {
        BufferedReader br;
        StringTokenizer st;
        public FastScanner() {
            br = new BufferedReader(new InputStreamReader(System.in));
        }
        String next() {
            while (st == null || !st.hasMoreElements()) {
                try {
                    st = new StringTokenizer(br.readLine());
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
            return st.nextToken();
        }
        int nextInt() {
            return Integer.parseInt(next());
        }
        long nextLong() {
            return Long.parseLong(next());
        }
        double nextDouble() {
            return Double.parseDouble(next());
        }
        String nextLine() {
            String str = "";
            try {
                str = br.readLine();
            } catch (IOException e) {
                e.printStackTrace();
            }
            return str;
        }

    }
    public static void main(String[] args) {
        FastScanner sc = new FastScanner();
        StringBuilder sb = new StringBuilder();
        HashMap<Integer, Integer> map = new HashMap<Integer, Integer>();
        out = new PrintWriter(new BufferedOutputStream(System.out));
        int n = sc.nextInt(), leftpointer = 0, counter = 0;
        LinkedList<Integer> leftidx = new LinkedList<Integer>();
        LinkedList<Integer> rightidx = new LinkedList<Integer>();

        //300000
        
        for(int i = 0; i < n; i ++)
        {
        	int input = sc.nextInt();
        	if(!map.containsKey(input))
        	{
        		map.put(input, 0);
        	}
        	else
        	{
        		map.clear();
        		counter ++;
        		leftidx.add((leftpointer+1));
        		rightidx.add((i+1));
        		leftpointer = i+1;
        	}
        }
        if(counter == 0) out.println("-1");
        else out.println(counter);
        if(counter!=0)
	        if(rightidx.peek()!=n) 
	        {
	        	rightidx.pollLast();
	        	rightidx.add(n);
	        }
        while(!leftidx.isEmpty())
        {
        	out.println(leftidx.poll() + " " + rightidx.poll());
        }
        out.close();
    }

}