Problem: You are given a positive integer n. In one move, you can increase n by one (i.e. make n := n + 1). Your task is to find the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains two integers n and s (1 ≤ n ≤ 10^{18}; 1 ≤ s ≤ 162).

Output

For each test case, print the answer: the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

Example

Input


5
2 1
1 1
500 4
217871987498122 10
100000000000000001 1


Output


8
0
500
2128012501878
899999999999999999

Solution (in PYTHON3):

Solution:
def sod(num):
    sums = 0
    while num>0:
        sums+=num%10
        num = num//10
    return sums
if __name__ == '__main__':
    t = int(input())
    for _ in range(t):
        n,s = map(int,input().split())
        if sod(n)<=s:
            print(0)
        else:
            temp = n
            i=1
            while sod(temp)>s:
                temp = temp//(10**i)
                temp +=1
                temp = temp*(10**i)
                i+=1
            print(temp-n)