Problem: You are given a positive integer n. In one move, you can increase n by one (i.e. make n := n + 1). Your task is to find the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains two integers n and s (1 ≤ n ≤ 10^{18}; 1 ≤ s ≤ 162).

Output

For each test case, print the answer: the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

Example

Input


5
2 1
1 1
500 4
217871987498122 10
100000000000000001 1


Output


8
0
500
2128012501878
899999999999999999

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
long long int power(long long int x, long long int b) {
  long long int p = 1;
  while (b > 0) {
    if (b & 1) {
      p = p * x;
      p %= 1000000007;
    }
    b >>= 1;
    x *= x;
    x %= 1000000007;
  }
  return p % 1000000007;
}
using namespace std;
int main() {
  ios_base::sync_with_stdio(false);
  cin.tie(NULL);
  ;
  long long int tc;
  cin >> tc;
  for (long long int number = 1; number <= tc; number++) {
    long long int a, b;
    cin >> a >> b;
    if (a % b == 0)
      cout << 0 << "\n";
    else
      cout << (b - a % b) << "\n";
  }
  return 0;
}