Problem: You are given a positive integer n. In one move, you can increase n by one (i.e. make n := n + 1). Your task is to find the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains two integers n and s (1 ≤ n ≤ 10^{18}; 1 ≤ s ≤ 162).

Output

For each test case, print the answer: the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

Example

Input


5
2 1
1 1
500 4
217871987498122 10
100000000000000001 1


Output


8
0
500
2128012501878
899999999999999999

Solution (in PYTHON3):

Solution:
mod = 10**9 + 7
import math 
from bisect import bisect_left as bl
from collections import Counter
from itertools import combinations
 
def ain():
    return map(int, input().split())
def fain():
    return map(float, input().split())
 
def mc2(s):
    return (s*(s-1))//2 
    
for _ in range(int(input())):
    a,b = ain()
    a = a%b
    if(a == 0) :
        print(0)
    else:
        print(b - a%b)
    
# python3 pan.py