Problem: The array a with n integers is given. Let's call the sequence of one or more consecutive elements in a segment. Also let's call the segment k-good if it contains no more than k different values.

Find any longest k-good segment.

As the input/output can reach huge size it is recommended to use fast input/output methods: for example, prefer to use scanf/printf instead of cin/cout in C++, prefer to use BufferedReader/PrintWriter instead of Scanner/System.out in Java.

Input

The first line contains two integers n, k (1 ≤ k ≤ n ≤ 5·105) — the number of elements in a and the parameter k.

The second line contains n integers ai (0 ≤ ai ≤ 106) — the elements of the array a.

Output

Print two integers l, r (1 ≤ l ≤ r ≤ n) — the index of the left and the index of the right ends of some k-good longest segment. If there are several longest segments you can print any of them. The elements in a are numbered from 1 to n from left to right.

Examples

Input

5 5
1 2 3 4 5


Output

1 5


Input

9 3
6 5 1 2 3 2 1 4 5


Output

3 7


Input

3 1
1 2 3


Output

1 1

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.util.ArrayList;
import java.util.HashSet;
import java.util.List;
import java.util.Set;

public class Main {
	static BufferedReader in;
	static PrintWriter out;

	public static void main(String[] args) throws IOException {
		in = new BufferedReader(new InputStreamReader(System.in));
		out = new PrintWriter(System.out);

		int N = ri();
		int[]a = rit();
		
		List<Integer> s = new ArrayList<Integer>();
		List<Integer> e = new ArrayList<Integer>();
		
		int start = -1;
		Set<Integer> used = new HashSet<Integer>(); 
		for (int i=0;i<N;i++) {
			if (start == -1) {
				start = i;
				used.clear();
				used.add(a[i]);
				continue;
			}
			if (used.contains(a[i])) {
				s.add(start);
				e.add(i);
				start = -1;
			} else {
				used.add(a[i]);
			}
		}
		
		if (s.size() == 0) {
			out.println(-1);
		} else {
			e.set(e.size()-1, N-1);
			out.println(s.size());
			for (int i=0;i<s.size();i++) {
				out.println((s.get(i)+1) + " " + (e.get(i)+1));
			}
		}

		in.close();
		out.close();
	}

	public static int ri() throws IOException {
		return Integer.parseInt(in.readLine());
	}

	public static long rl() throws IOException {
		return Long.parseLong(in.readLine());
	}

	public static String rs() throws IOException {
		return in.readLine();
	}

	public static String[] rst() throws IOException {
		return in.readLine().split(" ");
	}

	public static int[] rit() throws IOException {
		String[] tok = in.readLine().split(" ");
		int[] res = new int[tok.length];
		for (int i = 0; i < tok.length; i++) {
			res[i] = Integer.parseInt(tok[i]);
		}
		return res;
	}

	public static long[] rlt() throws IOException {
		String[] tok = in.readLine().split(" ");
		long[] res = new long[tok.length];
		for (int i = 0; i < tok.length; i++) {
			res[i] = Long.parseLong(tok[i]);
		}
		return res;
	}

}