Problem: You are given a positive integer n. In one move, you can increase n by one (i.e. make n := n + 1). Your task is to find the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains two integers n and s (1 ≤ n ≤ 10^{18}; 1 ≤ s ≤ 162).

Output

For each test case, print the answer: the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

Example

Input


5
2 1
1 1
500 4
217871987498122 10
100000000000000001 1


Output


8
0
500
2128012501878
899999999999999999

Solution (in PYTHON3):

Solution:
import math
import sys;
Z=sys.stdin.readline
def check(n):
    s1=str(n)
    sm=0
    for i in s1:
        sm+=int(i)
    return sm
for _ in range(int(Z())):
    n,s=map(int,input().split())
    n1=n
    i=0
    while check(n)>s:
        i+=1
        k=int(math.pow(10,i))-(n%int(math.pow(10,i)))
        n+=k
    print(n-n1)