Problem: One way to create a task is to learn from math. You can generate some random math statement or modify some theorems to get something new and build a new task from that.

For example, there is a statement called the "Goldbach's conjecture". It says: "each even number no less than four can be expressed as the sum of two primes". Let's modify it. How about a statement like that: "each integer no less than 12 can be expressed as the sum of two composite numbers." Not like the Goldbach's conjecture, I can prove this theorem.

You are given an integer n no less than 12, express it as a sum of two composite numbers.

Input

The only line contains an integer n (12 ≤ n ≤ 106).

Output

Output two composite integers x and y (1 < x, y < n) such that x + y = n. If there are multiple solutions, you can output any of them.

Examples

Input

12


Output

4 8


Input

15


Output

6 9


Input

23


Output

8 15


Input

1000000


Output

500000 500000

Note

In the first example, 12 = 4 + 8 and both 4, 8 are composite numbers. You can output "6 6" or "8 4" as well.

In the second example, 15 = 6 + 9. Note that you can't output "1 14" because 1 is not a composite number.

Solution (in PYTHON3):

Solution:
from math import sqrt

def isPrime(n):
    if n < 10:
        if n == 1:
            return False
        elif n == 2:
            return True
        elif n % 2 == 0:
            return False
        elif n % 3 == 0:
            return False
        return True
    else:
        if n % 2 == 0:
            return False
        for i in range(3, round(sqrt(n)), 2):
            if n % i == 0:
                return False
    return True


def Composite():
    n = int(input())
    if n % 2 == 0:
        if (n//2) % 2 == 0:
            print(f"{round(n/2)} {round(n/2)}")
        else:
            print(f"{round(n/2-1)} {round(n/2+1)}")
    else:
        even = n//2
        odd = n//2+1
        while isPrime(even) or isPrime(odd):
            even -= 1
            odd += 1
        print(f"{even} {odd}")


Composite()