Problem: Let n be an integer. Consider all permutations on integers 1 to n in lexicographic order, and concatenate them into one big sequence P. For example, if n = 3, then P = [1, 2, 3, 1, 3, 2, 2, 1, 3, 2, 3, 1, 3, 1, 2, 3, 2, 1]. The length of this sequence is n ⋅ n!.

Let 1 ≤ i ≤ j ≤ n ⋅ n! be a pair of indices. We call the sequence (P_i, P_{i+1}, ..., P_{j-1}, P_j) a subarray of P. 

You are given n. Find the number of distinct subarrays of P. Since this number may be large, output it modulo 998244353 (a prime number). 

Input

The only line contains one integer n (1 ≤ n ≤ 10^6), as described in the problem statement.

Output

Output a single integer — the number of distinct subarrays, modulo 998244353.

Examples

Input


2


Output


8


Input


10


Output


19210869

Note

In the first example, the sequence P = [1, 2, 2, 1]. It has eight distinct subarrays: [1], [2], [1, 2], [2, 1], [2, 2], [1, 2, 2], [2, 2, 1] and [1, 2, 2, 1]. 

Solution (in JAVA):

Solution:
/**
 * @author derrick20
 */
import java.io.*;
import java.util.*;

public class PermutationConcatenation {
    static long mod = 998244353;

    public static void main(String args[]) throws Exception {
        FastScanner sc = new FastScanner();
        PrintWriter out = new PrintWriter(System.out);

        int N = sc.nextInt();
        fact = new long[N + 1];
        invFact = new long[N + 1];
        fact[0] = 1;
        invFact[0] = 1;
        for (int i = 1; i <= N; i++) {
            fact[i] = (fact[i - 1] * (long) i % mod);
            invFact[i] = modInverse(fact[i]);
        }
        long ans = fact[N];
        // Non-spanning first, now we do spanning perms
        for (int left = N - 1; left >= 1; left--) {
            long delta = (choose(N, left) * (fact[left] - 1)) % mod;
            delta = (delta * fact[N - left]) % mod; // arrange the rest of the left side,
            // not the part being spanned
            ans = (ans + delta) % mod;
        }
        out.println(ans);
        out.close();
    }

    static long[] fact, invFact;

    static long choose(int N, int K) {
        long ans = (fact[N] * invFact[K]) % mod;
        return (ans * invFact[N - K]) % mod;
    }

    static long modInverse(long x) {
        return fastExpo(x, mod - 2);
    }

    static long fastExpo(long x, long k) {
        if (k == 0) {
            return 1;
        }
        else if (k == 1) {
            return x;
        }
        else {
            long root = fastExpo(x, k / 2);
            long ans = (root * root) % mod;
            if (k % 2 == 1) {
                return (ans * x) % mod;
            }
            else {
                return ans;
            }
        }
    }

    static class Pair implements Comparable<Pair> {
        int x, y;
        public Pair(int xx, int yy) {
            x = xx; y = yy;
        }

        public int compareTo(Pair p2) {
            return x - p2.x == 0 ? y - p2.y : x - p2.x;
        }
    }

    static class FastScanner {
        public int BS = 1<<16;
        public char NC = (char)0;
        byte[] buf = new byte[BS];
        int bId = 0, size = 0;
        char c = NC;
        double cnt = 1;
        BufferedInputStream in;

        public FastScanner() {
            in = new BufferedInputStream(System.in, BS);
        }

        public FastScanner(String s) {
            try {
                in = new BufferedInputStream(new FileInputStream(new File(s)), BS);
            }
            catch (Exception e) {
                in = new BufferedInputStream(System.in, BS);
            }
        }

        private char getChar(){
            while(bId==size) {
                try {
                    size = in.read(buf);
                }catch(Exception e) {
                    return NC;
                }
                if(size==-1)return NC;
                bId=0;
            }
            return (char)buf[bId++];
        }

        public int nextInt() {
            return (int)nextLong();
        }

        public long nextLong() {
            cnt=1;
            boolean neg = false;
            if(c==NC)c=getChar();
            for(;(c<'0' || c>'9'); c = getChar()) {
                if(c=='-')neg=true;
            }
            long res = 0;
            for(; c>='0' && c <='9'; c=getChar()) {
                res = (res<<3)+(res<<1)+c-'0';
                cnt*=10;
            }
            return neg?-res:res;
        }

        public double nextDouble() {
            double cur = nextLong();
            return c!='.' ? cur:cur+nextLong()/cnt;
        }

        public String next() {
            StringBuilder res = new StringBuilder();
            while(c<=32)c=getChar();
            while(c>32) {
                res.append(c);
                c=getChar();
            }
            return res.toString();
        }

        public String nextLine() {
            StringBuilder res = new StringBuilder();
            while(c<=32)c=getChar();
            while(c!='\n') {
                res.append(c);
                c=getChar();
            }
            return res.toString();
        }

        public boolean hasNext() {
            if(c>32)return true;
            while(true) {
                c=getChar();
                if(c==NC)return false;
                else if(c>32)return true;
            }
        }
    }
}