Problem: You are given a positive integer n. In one move, you can increase n by one (i.e. make n := n + 1). Your task is to find the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains two integers n and s (1 ≤ n ≤ 10^{18}; 1 ≤ s ≤ 162).

Output

For each test case, print the answer: the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

Example

Input


5
2 1
1 1
500 4
217871987498122 10
100000000000000001 1


Output


8
0
500
2128012501878
899999999999999999

Solution (in PYTHON3):

Solution:
def sums(n):
    res=0
    while(n>0):
        res+=n%10
        n=n//10
    return res
        
t=int(input())
while(t):
    t-=1
    n,s=map(int,input().split())
    if sums(n)<=s:
        print(0)
        continue
    
    pw=1
    ans=0
    for i in range(1,19):
        dig=(n//pw)%10
        add=((10-dig)%10)*pw
        ans+=add
        n+=add
        if sums(n)<=s:
            break
        pw*=10
    print(ans)