Problem: You are given a positive integer n. In one move, you can increase n by one (i.e. make n := n + 1). Your task is to find the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains two integers n and s (1 ≤ n ≤ 10^{18}; 1 ≤ s ≤ 162).

Output

For each test case, print the answer: the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

Example

Input


5
2 1
1 1
500 4
217871987498122 10
100000000000000001 1


Output


8
0
500
2128012501878
899999999999999999

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
void calc(long long int a, long long int b) {
  if (a % b == 0)
    cout << "0" << endl;
  else {
    long long int t, c;
    long long int m;
    t = a / b;
    m = t + 1;
    c = (m * b) - a;
    cout << c << endl;
  }
}
int main() {
  long long int T;
  cin >> T;
  while (T--) {
    long long int a, b;
    cin >> a >> b;
    calc(a, b);
  }
  return 0;
}