Problem: 

Input

The input contains a single integer a (1 ≤ a ≤ 40).

Output

Output a single string.

Examples

Input

2


Output

Adams


Input

8


Output

Van Buren


Input

29


Output

Harding

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.StringTokenizer;


public class T290A {

	public void solve(int a) {
		String[] ans = {
				"",
				"Washington",
				"Adams",
				"Jefferson",
				"Madison",
				"Monroe",
				"Adams",
				"Jackson",
				"Van Buren",
				"Harrison",
				"Tyler",
				"Polk",
				"Taylor",
				"Fillmore",
				"Pierce",
				"Buchanan",
				"Lincoln",
				"Johnson",
				"Grant",
				"Hayes",
				"Garfield",
				"Arthur",
				"Cleveland",
				"Harrison",
				"Cleveland",
				"McKinley",
				"Roosevelt",
				"Taft",
				"Wilson",
				"Harding",
				"Coolidge",
				"Hoover",
				"Roosevelt",
				"Truman",
				"Eisenhower",
				"Kennedy",
				"Johnson",
				"Nixon",
				"Ford",
				"Carter",
				"Reagan"
		};
		System.out.println(ans[a]);
	}
	
	public static void main(String[] args) {
		FastScanner in = new FastScanner();
		new T290A().solve(in.nextInt());

	}
	static class FastScanner {

		BufferedReader br;
		StringTokenizer st;

		public FastScanner(String s) {
			try {
				br = new BufferedReader(new FileReader(s));
			} catch (FileNotFoundException e) {
				e.printStackTrace();
			}
		}

		public FastScanner() {
			br = new BufferedReader(new InputStreamReader(System.in));
		}

		String nextToken() {
			while (st == null || !st.hasMoreElements()) {
				try {
					st = new StringTokenizer(br.readLine());
				} catch (IOException e) {
					e.printStackTrace();
				}
			}
			return st.nextToken();
		}

		int nextInt() {
			return Integer.parseInt(nextToken());
		}

		long nextLong() {
			return Long.parseLong(nextToken());
		}

		double nextDouble() {
			return Double.parseDouble(nextToken());
		}

	}
}