Problem: The array a with n integers is given. Let's call the sequence of one or more consecutive elements in a segment. Also let's call the segment k-good if it contains no more than k different values.

Find any longest k-good segment.

As the input/output can reach huge size it is recommended to use fast input/output methods: for example, prefer to use scanf/printf instead of cin/cout in C++, prefer to use BufferedReader/PrintWriter instead of Scanner/System.out in Java.

Input

The first line contains two integers n, k (1 ≤ k ≤ n ≤ 5·105) — the number of elements in a and the parameter k.

The second line contains n integers ai (0 ≤ ai ≤ 106) — the elements of the array a.

Output

Print two integers l, r (1 ≤ l ≤ r ≤ n) — the index of the left and the index of the right ends of some k-good longest segment. If there are several longest segments you can print any of them. The elements in a are numbered from 1 to n from left to right.

Examples

Input

5 5
1 2 3 4 5


Output

1 5


Input

9 3
6 5 1 2 3 2 1 4 5


Output

3 7


Input

3 1
1 2 3


Output

1 1

Solution (in JAVA):

Solution:
import java.io.BufferedInputStream;
        import java.math.BigInteger;
        import java.util.HashMap;
        import java.util.Scanner;

public class Main {


    public static void main(String[] args) {
        int n , k ;
        Scanner cin = new Scanner (new BufferedInputStream(System.in));
        HashMap<String, Integer> hashMap=new HashMap<>();
        int[] ar = new int[6000007];
        int[] a = new int[600007];
        n = cin.nextInt();  k = cin.nextInt();
        for(int i = 1; i <= n; ++ i)
        {
            a[i] = cin.nextInt();
        }
        int l = 1 , r =1 ;
        int num = 0;
        int ll =1;
        for(int i=1;i<=n;i++)
        {
            if(ar[a[i]]==0)
            {
                ar[a[i]]++;

                num++;
            }
            else
            {
                ar[a[i]]++;
            }
            while(num>k)
            {
                ar[a[ll]]--;
                if(ar[a[ll]]==0)
                    num--;
                ll++;
            }
            if((i-ll+1)>(r-l+1))
            {
                r=i;
                l=ll;
            }
        }
        System.out.println(l+ " "+r);
    }
}