Problem: The array a with n integers is given. Let's call the sequence of one or more consecutive elements in a segment. Also let's call the segment k-good if it contains no more than k different values.

Find any longest k-good segment.

As the input/output can reach huge size it is recommended to use fast input/output methods: for example, prefer to use scanf/printf instead of cin/cout in C++, prefer to use BufferedReader/PrintWriter instead of Scanner/System.out in Java.

Input

The first line contains two integers n, k (1 ≤ k ≤ n ≤ 5·105) — the number of elements in a and the parameter k.

The second line contains n integers ai (0 ≤ ai ≤ 106) — the elements of the array a.

Output

Print two integers l, r (1 ≤ l ≤ r ≤ n) — the index of the left and the index of the right ends of some k-good longest segment. If there are several longest segments you can print any of them. The elements in a are numbered from 1 to n from left to right.

Examples

Input

5 5
1 2 3 4 5


Output

1 5


Input

9 3
6 5 1 2 3 2 1 4 5


Output

3 7


Input

3 1
1 2 3


Output

1 1

Solution (in JAVA):

Solution:

import java.awt.AWTException;
import java.awt.Robot;
import java.awt.event.InputEvent;
import java.awt.event.KeyEvent;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.OutputStream;
import java.io.PrintWriter;
import java.math.BigInteger;
import java.util.ArrayDeque;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Collections;
import java.util.Comparator;
import java.util.HashMap;
import java.util.HashSet;
import java.util.Iterator;
import java.util.LinkedList;
import java.util.List;
import java.util.Map;
import java.util.PriorityQueue;
import java.util.Queue;
import java.util.Set;
import java.util.StringTokenizer;
import java.util.TreeMap;
import java.util.TreeSet;
import java.util.Vector;
import java.util.logging.Level;
import java.util.logging.Logger;
import javax.swing.text.html.parser.Entity;

public class Main {

    
    public static void main(String[] args) throws InterruptedException, AWTException {
        InputStream inputStream = System.in;
        OutputStream outputStream = System.out;
        PrintWriter out = new PrintWriter(outputStream);
        InputReader in = new InputReader(inputStream);
        
        int n = in.nextInt(), k = in.nextInt();
        int[] a = new int[n];
        int[] c = new int[1000001];
        for(int i = 0; i < n; i++) {
            a[i] = in.nextInt();
        }
        int cnt = 0;
        int ansl = -1, ansr = -1, res = -1;
        for(int r = 0, l = 0; r < n; r++) {
            while(cnt > k) {
                c[a[l]]--;
                if(c[a[l]] == 0) cnt--;
                l++;
            }
            c[a[r]]++;
            if(c[a[r]] == 1) cnt++;
            if(r - l > res && cnt <= k) {
                res = r - l;
                ansl = l; ansr = r;
            }
        }
        ansl++; ansr++;
        out.println(ansl + " " + ansr);
        out.close();
    }

    static class InputReader {

        BufferedReader reader;
        StringTokenizer tokenizer;

        public InputReader(InputStream inputStream) {
            reader = new BufferedReader(new InputStreamReader(inputStream), 32624);
            tokenizer = null;
        }

        public String next() {
            while (tokenizer == null || !tokenizer.hasMoreTokens()) {
                try {
                    tokenizer = new StringTokenizer(reader.readLine());
                } catch (IOException ex) {
                    Logger.getLogger(Main.class.getName()).log(Level.SEVERE, null, ex);
                }
            }
            return tokenizer.nextToken();
        }

        public int nextInt() {
            return Integer.parseInt(next());
        }

        private long nextLong() {
            return Long.parseLong(next());
        }

        private BigInteger nextBigInteger() {
            return new BigInteger(next());
        }
    }

}