Problem: You are given a positive integer n. In one move, you can increase n by one (i.e. make n := n + 1). Your task is to find the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains two integers n and s (1 ≤ n ≤ 10^{18}; 1 ≤ s ≤ 162).

Output

For each test case, print the answer: the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

Example

Input


5
2 1
1 1
500 4
217871987498122 10
100000000000000001 1


Output


8
0
500
2128012501878
899999999999999999

Solution (in PYTHON3):

Solution:
"https://codeforces.com/contest/1328/problem/A"
import collections, heapq, itertools, math
groupby = itertools.groupby
ri = lambda: int(input())
rm = lambda: map(int, input().split())

def solve(a,b):
    return math.ceil(a/b)*b-a
        
for t in range(1, 1 + ri()):
    a, b = rm()
    ans = solve(a,b)
    print ("{}".format(ans))