Problem: You are given a positive integer n. In one move, you can increase n by one (i.e. make n := n + 1). Your task is to find the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains two integers n and s (1 ≤ n ≤ 10^{18}; 1 ≤ s ≤ 162).

Output

For each test case, print the answer: the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

Example

Input


5
2 1
1 1
500 4
217871987498122 10
100000000000000001 1


Output


8
0
500
2128012501878
899999999999999999

Solution (in PYTHON3):

Solution:
for t in range(int(input())):
    n, s = map(int, input().split())
    m = n
    ans = n
    d = 0
    while True:
        a = m
        c = 0
        while a > 0:
            c += a % 10
            a //= 10
        if c <= s:
            ans = m*(10**d)-n
            break
        if m % 10 == 0:
            m //= 10
            d += 1
        else:
            m += 10-m % 10
    print(ans)