Problem: You are given a positive integer n. In one move, you can increase n by one (i.e. make n := n + 1). Your task is to find the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains two integers n and s (1 ≤ n ≤ 10^{18}; 1 ≤ s ≤ 162).

Output

For each test case, print the answer: the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

Example

Input


5
2 1
1 1
500 4
217871987498122 10
100000000000000001 1


Output


8
0
500
2128012501878
899999999999999999

Solution (in PYTHON):

Solution:
from __future__ import division, print_function

import sys
from atexit import register

if sys.version_info[0] < 3:
    from io import BytesIO as stream
else:
    from io import StringIO as stream


sys.stdin = stream(sys.stdin.read())
input = lambda: sys.stdin.readline().rstrip('\r\n')

sys.stdout = stream()
register(lambda: sys.__stdout__.write(sys.stdout.getvalue()))


def read_int():
    return int(input())


def read_ints():
    return list(map(int, input().split(' ')))


def solve():
    n, s = read_ints()
    base = 1
    i = -1
    moves = 0
    while sum(map(int, str(n))) > s:
        if str(n)[i] != '0':
            t = (10-int(str(n)[i]))*base
            n += t
            moves += t
        base *= 10
        i -= 1
    return moves


if __name__ == '__main__':
    T = read_int()
    for _ in range(T):
        print(solve())