Problem: You are given a positive integer n. In one move, you can increase n by one (i.e. make n := n + 1). Your task is to find the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains two integers n and s (1 ≤ n ≤ 10^{18}; 1 ≤ s ≤ 162).

Output

For each test case, print the answer: the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

Example

Input


5
2 1
1 1
500 4
217871987498122 10
100000000000000001 1


Output


8
0
500
2128012501878
899999999999999999

Solution (in PYTHON3):

Solution:
n=int(input())
l=[]

for i in range(n):
    a,b=map(int,input().split())
    l.append(a)
    l.append(b)
i=0
while i<(2*n)-1:
    ct=0
    if l[i]%l[i+1]!=0:
        q=int(l[i]/l[i+1])
        ct=(l[i+1]*(q+1))-l[i]
    
    i+=2
    print(ct)