Problem: One way to create a task is to learn from math. You can generate some random math statement or modify some theorems to get something new and build a new task from that.

For example, there is a statement called the "Goldbach's conjecture". It says: "each even number no less than four can be expressed as the sum of two primes". Let's modify it. How about a statement like that: "each integer no less than 12 can be expressed as the sum of two composite numbers." Not like the Goldbach's conjecture, I can prove this theorem.

You are given an integer n no less than 12, express it as a sum of two composite numbers.

Input

The only line contains an integer n (12 ≤ n ≤ 106).

Output

Output two composite integers x and y (1 < x, y < n) such that x + y = n. If there are multiple solutions, you can output any of them.

Examples

Input

12


Output

4 8


Input

15


Output

6 9


Input

23


Output

8 15


Input

1000000


Output

500000 500000

Note

In the first example, 12 = 4 + 8 and both 4, 8 are composite numbers. You can output "6 6" or "8 4" as well.

In the second example, 15 = 6 + 9. Note that you can't output "1 14" because 1 is not a composite number.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
bool ne_prost[1000000];
long long f(long long n) {
  int k = 0;
  ne_prost[0] = true;
  ne_prost[1] = true;
  for (int i = 2; i <= 1000000; i++)
    if (ne_prost[i] == false) {
      for (int j = i * 2; j <= 1000000; j += i) ne_prost[j] = true;
    }
  if (ne_prost[n] == false)
    return 1;
  else
    return 0;
}
int main() {
  long long x;
  cin >> x;
  vector<int> v;
  for (int i = 4; i <= x; i++) {
    if (f(i) == 0 && f(x - i) == 0) {
      cout << i << " " << x - i << endl;
      break;
    }
  }
  return 0;
}