Problem: You are given a positive integer n. In one move, you can increase n by one (i.e. make n := n + 1). Your task is to find the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains two integers n and s (1 ≤ n ≤ 10^{18}; 1 ≤ s ≤ 162).

Output

For each test case, print the answer: the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

Example

Input


5
2 1
1 1
500 4
217871987498122 10
100000000000000001 1


Output


8
0
500
2128012501878
899999999999999999

Solution (in PYTHON3):

Solution:
import sys
import math

def ii():
    return sys.stdin.readline().strip()

def idata():
    return [int(x) for x in ii().split()]

def binary_search(array, x):
    left, right = -1, len(array)
    while left + 1 != right:
        middle = (left + right) // 2
        if array[middle] >= x:
            right = middle
        elif array[middle] < x:
            left = middle
    return right

def solve_of_problem():
    a, b = idata()
    k = a // b
    z = a % b
    if z == 0:
        print(0)
        return
    if k == 0:
        print(b - a)
        return
    print(b - z)
    return

for ______ in range(int(ii())):
    solve_of_problem()