Problem: The hobbits Frodo and Sam are carrying the One Ring to Mordor. In order not to be spotted by orcs, they decided to go through the mountains.

The mountain relief can be represented as a polyline with n points (x_i, y_i), numbered from 1 to n (x_i < x_{i + 1} for 1 ≤ i ≤ n - 1). Hobbits start their journey at the point (x_1, y_1) and should reach the point (x_n, y_n) to complete their mission.

The problem is that there is a tower with the Eye of Sauron, which watches them. The tower is located at the point (x_n, y_n) and has the height H, so the Eye is located at the point (x_n, y_n + H). In order to complete the mission successfully, the hobbits have to wear cloaks all the time when the Sauron Eye can see them, i. e. when there is a direct line from the Eye to the hobbits which is not intersected by the relief.

The hobbits are low, so their height can be considered negligibly small, but still positive, so when a direct line from the Sauron Eye to the hobbits only touches the relief, the Eye can see them.

<image> The Sauron Eye can't see hobbits when they are in the left position, but can see them when they are in the right position.

The hobbits do not like to wear cloaks, so they wear them only when they can be spotted by the Eye. Your task is to calculate the total distance the hobbits have to walk while wearing cloaks.

Input

The first line of the input contains two integers n and H (2 ≤ n ≤ 2 ⋅ 10^5; 1 ≤ H ≤ 10^4) — the number of vertices in polyline and the tower height.

The next n lines contain two integers x_i, y_i each (0 ≤ x_i ≤ 4 ⋅ 10^5; 0 ≤ y_i ≤ 10^4) — the coordinates of the polyline vertices. It is guaranteed that x_i < x_{i + 1} for 1 ≤ i ≤ n - 1.

Output

Print one real number — the total distance the hobbits have to walk while wearing cloaks. Your answer will be considered correct if its absolute or relative error does not exceed 10^{-6} — formally, if your answer is a, and the jury's answer is b, your answer will be accepted if (|a - b|)/(max(1, b)) ≤ 10^{-6}.

Examples

Input


6 10
10 40
20 10
25 30
30 15
50 15
65 30


Output


70.4034587602


Input


9 5
0 0
5 10
15 10
20 0
25 11
30 0
35 10
50 10
60 5


Output


27.2787986124


Input


2 10000
0 10000
400000 0


Output


400124.9804748512

Solution (in CPP):

Solution:
#include<bits/stdc++.h>
#define ll long long
using namespace std;
 
const double EPS = 1e-9;
  
inline int sign(double a) { return a < -EPS ? -1 : a > EPS; }
  
inline int cmp(double a, double b){ return sign(a-b); }
  
struct P {
	double x, y;
	P() {}
	P(double _x, double _y) : x(_x), y(_y) {}
	P operator+(P p) { return {x + p.x, y + p.y}; }
	P operator-(P p) { return {x - p.x, y - p.y}; }
	P operator*(double d) { return {x * d, y * d}; }
	P operator/(double d) { return {x / d, y / d}; }
 
	bool operator<(P p) const { 
		int c = cmp(x, p.x);
		if (c) return c == -1;
		return cmp(y, p.y) == -1;
	}
 
	bool operator==(P o) const{
		return cmp(x,o.x) == 0 && cmp(y,o.y) == 0;
	}
 
	double dot(P p) { return x * p.x + y * p.y; }
	double det(P p) { return x * p.y - y * p.x; }
	 
	double distTo(P p) { return (*this-p).abs(); }
	double alpha() { return atan2(y, x); }
	void read() { cin>>x>>y; }
	void write() {cout<<"("<<x<<","<<y<<")"<<endl;}
	double abs() { return sqrt(abs2());}
	double abs2() { return x * x + y * y; }
	P rot90() { return P(-y,x);}
	P unit() { return *this/abs(); }
	int quad() const { return sign(y) == 1 || (sign(y) == 0 && sign(x) >= 0); }
	P rot(double an){ return {x*cos(an)-y*sin(an),x*sin(an) + y*cos(an)}; }
};
  
struct L{ //ps[0] -> ps[1]
	P ps[2];
	P& operator[](int i) { return ps[i]; }
	P dir() { return ps[1] - ps[0]; }
	L (P a,P b) {
		ps[0]=a;
		ps[1]=b;
	}
	bool include(P p) { return sign((ps[1] - ps[0]).det(p - ps[0])) > 0; }
	L push(){ // push eps outward
		const double eps = 1e-8;
		P delta = (ps[1] - ps[0]).rot90().unit() * eps;
		return {ps[0] + delta, ps[1] + delta};
	}
};
 
#define cross(p1,p2,p3) ((p2.x-p1.x)*(p3.y-p1.y)-(p3.x-p1.x)*(p2.y-p1.y))
#define crossOp(p1,p2,p3) sign(cross(p1,p2,p3))
  
bool chkLL(P p1, P p2, P q1, P q2) {
	double a1 = cross(q1, q2, p1), a2 = -cross(q1, q2, p2);
	return sign(a1+a2) != 0;
}
 
P isLL(P p1, P p2, P q1, P q2) {
	double a1 = cross(q1, q2, p1), a2 = -cross(q1, q2, p2);
	return (p1 * a2 + p2 * a1) / (a1 + a2);
}
  
P isLL(L l1,L l2){ return isLL(l1[0],l1[1],l2[0],l2[1]); }
  
bool intersect(double l1,double r1,double l2,double r2){
	if(l1>r1) swap(l1,r1); if(l2>r2) swap(l2,r2); 
	return !( cmp(r1,l2) == -1 || cmp(r2,l1) == -1 );
}
  
bool isSS(P p1, P p2, P q1, P q2){
	return intersect(p1.x,p2.x,q1.x,q2.x) && intersect(p1.y,p2.y,q1.y,q2.y) && 
	crossOp(p1,p2,q1) * crossOp(p1,p2,q2) <= 0 && crossOp(q1,q2,p1)
			* crossOp(q1,q2,p2) <= 0;
}
  
bool isSS_strict(P p1, P p2, P q1, P q2){
	return crossOp(p1,p2,q1) * crossOp(p1,p2,q2) < 0 && crossOp(q1,q2,p1)
			* crossOp(q1,q2,p2) < 0;
}
  
bool isMiddle(double a, double m, double b) {
	return sign(a - m) == 0 || sign(b - m) == 0 || (a < m != b < m);
}
  
bool isMiddle(P a, P m, P b) {
	return isMiddle(a.x, m.x, b.x) && isMiddle(a.y, m.y, b.y);
}
  
bool onSeg(P p1, P p2, P q){
	return crossOp(p1,p2,q) == 0 && isMiddle(p1, q, p2);
}
 
bool onSeg_strict(P p1, P p2, P q){
	return crossOp(p1,p2,q) == 0 && sign((q-p1).dot(p1-p2)) * sign((q-p2).dot(p1-p2)) < 0;
}
  
P proj(P p1, P p2, P q) {
	P dir = p2 - p1;
	return p1 + dir * (dir.dot(q - p1) / dir.abs2());
}
  
P reflect(P p1, P p2, P q){
	return proj(p1,p2,q) * 2 - q;
}
  
double nearest(P p1,P p2,P q){
	P h = proj(p1,p2,q);
	if(isMiddle(p1,h,p2))
		return q.distTo(h);
	return min(p1.distTo(q),p2.distTo(q));
}
  
double disSS(P p1, P p2, P q1, P q2){
	if(isSS(p1,p2,q1,q2)) return 0;
	return min(min(nearest(p1,p2,q1),nearest(p1,p2,q2)), min(nearest(q1,q2,p1),nearest(q1,q2,p2)));
}
  
double rad(P p1,P p2){
	return atan2l(p1.det(p2),p1.dot(p2));
}
  
double incircle(P p1, P p2, P p3){
	double A = p1.distTo(p2);
	double B = p2.distTo(p3);
	double C = p3.distTo(p1);
	return sqrtl(A*B*C/(A+B+C));
}
  
//polygon
  
double area(vector<P> ps){
	double ret = 0; 
  for(int i=0; i< ps.size(); i++) ret += ps[i].det(ps[(i+1)%ps.size()]); 
	return ret/2;
}
  
int contain(vector<P> ps, P p){ //2:inside,1:on_seg,0:outside
	int n = ps.size(), ret = 0; 
	for(int i = 0; i < n; i++) {
		P u=ps[i],v=ps[(i+1)%n];
		if(onSeg(u,v,p)) return 1;
		if(cmp(u.y,v.y)<=0) swap(u,v);
		if(cmp(p.y,u.y) >0 || cmp(p.y,v.y) <= 0) continue;
		ret ^= crossOp(p,u,v) > 0;
	}
	return ret*2;
}
  
vector<P> convexHull(vector<P> ps) {
	int n = ps.size(); if(n <= 1) return ps;
	sort(ps.begin(), ps.end());
	vector<P> qs(n * 2); int k = 0;
	for (int i = 0; i < n; qs[k++] = ps[i++]) 
		while (k > 1 && crossOp(qs[k - 2], qs[k - 1], ps[i]) <= 0) --k;
	for (int i = n - 2, t = k; i >= 0; qs[k++] = ps[i--])
		while (k > t && crossOp(qs[k - 2], qs[k - 1], ps[i]) <= 0) --k;
	qs.resize(k - 1);
	return qs;
}
  
vector<P> convexHullNonStrict(vector<P> ps) {
	//caution: need to unique the Ps first
	int n = ps.size(); if(n <= 1) return ps;
	sort(ps.begin(), ps.end());
	vector<P> qs(n * 2); int k = 0;
	for (int i = 0; i < n; qs[k++] = ps[i++]) 
		while (k > 1 && crossOp(qs[k - 2], qs[k - 1], ps[i]) < 0) --k;
	for (int i = n - 2, t = k; i >= 0; qs[k++] = ps[i--])
		while (k > t && crossOp(qs[k - 2], qs[k - 1], ps[i]) < 0) --k;
	qs.resize(k - 1);
	return qs;
}
  
double convexDiameter(vector<P> ps){
	int n = ps.size(); if(n <= 1) return 0;
	int is = 0, js = 0; for(int k = 1; k < n; k++) is = ps[k]<ps[is]?k:is, js = ps[js] < ps[k]?k:js;
	int i = is, j = js;
	double ret = ps[i].distTo(ps[j]);
	do{
		if((ps[(i+1)%n]-ps[i]).det(ps[(j+1)%n]-ps[j]) >= 0)
			(++j)%=n;
		else
			(++i)%=n;
		ret = max(ret,ps[i].distTo(ps[j]));
	}while(i!=is || j!=js);
	return ret;
}
  
vector<P> convexCut(const vector<P>&ps, P q1, P q2) {
	vector<P> qs;
	int n = ps.size();
	for(int i = 0; i<n; i++) {
		P p1 = ps[i], p2 = ps[(i+1)%n];
		int d1 = crossOp(q1,q2,p1), d2 = crossOp(q1,q2,p2);
		if(d1 >= 0) qs.push_back(p1);
		if(d1 * d2 < 0) qs.push_back(isLL(p1,p2,q1,q2));
	}
	return qs;
}
  
//min_dist
  
double min_dist(vector<P>&ps,int l,int r){
	if(r-l<=5){
		double ret = 1e100;
		for(int i = l; i<r; i++) for(int j=l;j<i;j++) ret = min(ret,ps[i].distTo(ps[j]));
		return ret;
	}
	int m = (l+r)>>1;
	double ret = min(min_dist(ps,l,m),min_dist(ps,m,r));
	vector<P> qs; for(int i = l; i< r;i++) if(abs(ps[i].x-ps[m].x)<= ret) qs.push_back(ps[i]);
	sort(qs.begin(), qs.end(),[](P a,P b) -> bool {return a.y<b.y; });
	for(int i = 1; i < qs.size(); i++) for(int j=i-1;j>=0&&qs[j].y>=qs[i].y-ret;--j)
		ret = min(ret,qs[i].distTo(qs[j]));
	return ret;
}
  
int type(P o1,double r1,P o2,double r2){
	double d = o1.distTo(o2);
	if(cmp(d,r1+r2) == 1) return 4;
	if(cmp(d,r1+r2) == 0) return 3;
	if(cmp(d,abs(r1-r2)) == 1) return 2;
	if(cmp(d,abs(r1-r2)) == 0) return 1;
	return 0;
}
  
vector<P> isCL(P o,double r,P p1,P p2){
	if (cmp(abs((o-p1).det(p2-p1)/p1.distTo(p2)),r)>0) return {};
	double x = (p1-o).dot(p2-p1), y = (p2-p1).abs2(), d = x * x - y * ((p1-o).abs2() - r*r);
	d = max(d,0.0); P m = p1 - (p2-p1)*(x/y), dr = (p2-p1)*(sqrt(d)/y);
	return {m-dr,m+dr}; //along dir: p1->p2
}
  
vector<P> isCC(P o1, double r1, P o2, double r2) { //need to check whether two circles are the same
	double d = o1.distTo(o2); 
	if (cmp(d, r1 + r2) == 1) return {};
	if (cmp(d,abs(r1-r2))==-1) return {};
	d = min(d, r1 + r2);
	double y = (r1 * r1 + d * d - r2 * r2) / (2 * d), x = sqrt(r1 * r1 - y * y);
	P dr = (o2 - o1).unit();
	P q1 = o1 + dr * y, q2 = dr.rot90() * x;
	return {q1-q2,q1+q2};//along circle 1
}
  
vector<P> tanCP(P o, double r, P p) {
	double x = (p - o).abs2(), d = x - r * r;
	if (sign(d) <= 0) return {}; // on circle => no tangent
	P q1 = o + (p - o) * (r * r / x);
	P q2 = (p - o).rot90() * (r * sqrt(d) / x);
	return {q1-q2,q1+q2}; //counter clock-wise
}
  
  
vector<L> extanCC(P o1, double r1, P o2, double r2) {
	vector<L> ret;
	if (cmp(r1, r2) == 0) {
		P dr = (o2 - o1).unit().rot90() * r1;
		ret.push_back(L(o1 + dr, o2 + dr)), ret.push_back(L(o1 - dr, o2 - dr));
	} else {
		P p = (o2 * r1 - o1 * r2) / (r1 - r2);
		vector<P> ps = tanCP(o1, r1, p), qs = tanCP(o2, r2, p);
		for(int i = 0; i < min(ps.size(),qs.size());i++) ret.push_back(L(ps[i], qs[i])); //c1 counter-clock wise
	}
	return ret;
}
  
vector<L> intanCC(P o1, double r1, P o2, double r2) {
	vector<L> ret;
	P p = (o1 * r2 + o2 * r1) / (r1 + r2);
	vector<P> ps = tanCP(o1,r1,p), qs = tanCP(o2,r2,p);
	for(int i = 0; i < min(ps.size(),qs.size()); i++) ret.push_back(L(ps[i], qs[i])); //c1 counter-clock wise
	return ret;
}
  
double areaCT(double r, P p1, P p2){
	vector<P> is = isCL(P(0,0),r,p1,p2);
	if(is.empty()) return r*r*rad(p1,p2)/2;
	bool b1 = cmp(p1.abs2(),r*r) == 1, b2 = cmp(p2.abs2(), r*r) == 1;
	if(b1 && b2){
		if(sign((p1-is[0]).dot(p2-is[0])) <= 0 &&
			sign((p1-is[0]).dot(p2-is[0])) <= 0)
		return r*r*(rad(p1,is[0]) + rad(is[1],p2))/2 + is[0].det(is[1])/2;
		else return r*r*rad(p1,p2)/2;
	}
	if(b1) return (r*r*rad(p1,is[0]) + is[0].det(p2))/2;
	if(b2) return (p1.det(is[1]) + r*r*rad(is[1],p2))/2;
	return p1.det(p2)/2;
}
  
bool parallel(L l0, L l1) { return sign( l0.dir().det( l1.dir() ) ) == 0; }
  
bool sameDir(L l0, L l1) { return parallel(l0, l1) && sign(l0.dir().dot(l1.dir()) ) == 1; }
  
bool cmp (P a,  P b) {
	if (a.quad() != b.quad()) {
		return a.quad() < b.quad();
	} else {
		return sign( a.det(b) ) > 0;
	}
}
  
bool operator < (L l0, L l1) {
	if (sameDir(l0, l1)) {
		return l1.include(l0[0]);
	} else {
		return cmp( l0.dir(), l1.dir() );
	}
}
  
bool check(L u, L v, L w) { 
	return w.include(isLL(u,v)); 
}
  
vector<P> halfPlaneIS(vector<L> &l) {
	sort(l.begin(), l.end());
	deque<L> q;
	for (int i = 0; i < (int)l.size(); ++i) {
		if (i && sameDir(l[i], l[i - 1])) continue;
		while (q.size() > 1 && !check(q[q.size() - 2], q[q.size() - 1], l[i])) q.pop_back();
		while (q.size() > 1 && !check(q[1], q[0], l[i])) q.pop_front();
		q.push_back(l[i]);
	}
	while (q.size() > 2 && !check(q[q.size() - 2], q[q.size() - 1], q[0])) q.pop_back();
	while (q.size() > 2 && !check(q[1], q[0], q[q.size() - 1])) q.pop_front();
	vector<P> ret;
	for (int i = 0; i < (int)q.size(); ++i) ret.push_back(isLL(q[i], q[(i + 1) % q.size()]));
	return ret;
}
 
P inCenter(P A, P B, P C) {
	double a = (B - C).abs(), b = (C - A).abs(), c = (A - B).abs();
	return (A * a + B * b + C * c) / (a + b + c);
}
 
P circumCenter(P a, P b, P c) { 
	P bb = b - a, cc = c - a;
	double db = bb.abs2(), dc = cc.abs2(), d = 2 * bb.det(cc);
	return a - P(bb.y * dc - cc.y * db, cc.x * db - bb.x * dc) / d;
}
 
P othroCenter(P a, P b, P c) { 
	P ba = b - a, ca = c - a, bc = b - c;
	double Y = ba.y * ca.y * bc.y,
	A = ca.x * ba.y - ba.x * ca.y,
	x0 = (Y + ca.x * ba.y * b.x - ba.x * ca.y * c.x) / A,
	y0 = -ba.x * (x0 - c.x) / ba.y + ca.y;
	return {x0, y0};
}
const int N = 2e5+1;
int x[N]; int y[N];
P p[N];

int main() {
int n, H; cin >> n >> H;
for(int i = 0; i<n; i++) {
  cin >> x[i] >> y[i];
  p[i]=P(x[i],y[i]);
}
P eye(x[n-1], y[n-1]+H);
P mount(x[n-1], y[n-1]);
double res=0;
for(int i = n-2; i >= 0; i--) {
  bool seeR = crossOp(eye,mount,p[i+1]) <= 0;
  bool seeL = crossOp(eye,mount,p[i]) <= 0;
  if(seeL) {
    if(seeR) res += p[i].distTo(p[i+1]);
    else {
      P inter=isLL(eye,mount,p[i],p[i+1]);
      res+=p[i].distTo(inter);
    }
  }
  if(seeL) mount=p[i];
}
printf("%.10f\n",res);
}