Problem: You are given a positive integer n. In one move, you can increase n by one (i.e. make n := n + 1). Your task is to find the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains two integers n and s (1 ≤ n ≤ 10^{18}; 1 ≤ s ≤ 162).

Output

For each test case, print the answer: the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

Example

Input


5
2 1
1 1
500 4
217871987498122 10
100000000000000001 1


Output


8
0
500
2128012501878
899999999999999999

Solution (in PYTHON3):

Solution:
"""def power(x, y): 
    res = 1
    x=x
    while (y > 0): 
        if ((y & 1) == 1) : 
            res = (res * x) 
        y = y >> 1
        x = (x * x)
    return res""" 
"""def fact(n):
    if(n==0):
        return 1
    if(n==1):
        return 1
    return fact(n-1)+fact(n-2)"""

import math
#import combinations
t=int(input())
for _ in range(t):
    #n=int(input())
    #arr=list(map(int,input().split()))
    n,k=map(int,input().split())
    #count=0
    #arr=list(map(int,input().split()))
    if(n%k==0):
        print("0")
    else:
        print(k-n%k)