Problem: You are given a positive integer n. In one move, you can increase n by one (i.e. make n := n + 1). Your task is to find the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains two integers n and s (1 ≤ n ≤ 10^{18}; 1 ≤ s ≤ 162).

Output

For each test case, print the answer: the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

Example

Input


5
2 1
1 1
500 4
217871987498122 10
100000000000000001 1


Output


8
0
500
2128012501878
899999999999999999

Solution (in PYTHON3):

Solution:
import sys
import time
import math


def calc(a, b):
    temp = math.ceil(a/b)
    temp *= b
    return temp-a


def main():
    for _ in range(int(sys.stdin.readline())):
        a, b = list(map(int, sys.stdin.readline().split()))
        sys.stdout.write('%d\n' % calc(a, b))


if __name__ == '__main__':
    HELLO_WORLD = False
    if HELLO_WORLD is True:
        sys.stdin = open('input.in.txt', 'r')
        start_time = time.time()
        main()
        print("--- %.5s seconds ---" % (time.time() - start_time))
    else:
        main()