Problem: You are given a positive integer n. In one move, you can increase n by one (i.e. make n := n + 1). Your task is to find the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains two integers n and s (1 ≤ n ≤ 10^{18}; 1 ≤ s ≤ 162).

Output

For each test case, print the answer: the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

Example

Input


5
2 1
1 1
500 4
217871987498122 10
100000000000000001 1


Output


8
0
500
2128012501878
899999999999999999

Solution (in PYTHON3):

Solution:
#                               #
    # author : samars_diary #
    # 02-09-2020 │ 15:59:04 #
#                               #

import sys, os.path

if(os.path.exists('input.txt')):
    sys.stdin = open('input.txt',"r")
    # sys.stdout = open('output.txt',"w")

sys.setrecursionlimit(10 ** 5)

def II(): return int(sys.stdin.readline())
def MI(): return map(int, sys.stdin.readline().split())
def LI(): return list(map(int, sys.stdin.readline().split()))

def solve():
    a,b=MI()
    if a%b!=0:
        print((a//b+1)*b-a)
    else:
        print(0)

for _ in range(II()):
    solve()