Problem: This is an easy version of the problem. In this version, all numbers in the given array are distinct and the constraints on n are less than in the hard version of the problem.

You are given an array a of n integers (there are no equals elements in the array). You can perform the following operations on array elements:

  1. choose any index i (1 ≤ i ≤ n) and move the element a[i] to the begin of the array; 
  2. choose any index i (1 ≤ i ≤ n) and move the element a[i] to the end of the array. 



For example, if n = 5, a = [4, 7, 2, 3, 9], then the following sequence of operations can be performed: 

  * after performing the operation of the first type to the second element, the array a will become [7, 4, 2, 3, 9]; 
  * after performing the operation of the second type to the second element, the array a will become [7, 2, 3, 9, 4]. 



You can perform operations of any type any number of times in any order.

Find the minimum total number of operations of the first and second type that will make the a array sorted in non-decreasing order. In other words, what is the minimum number of operations that must be performed so the array satisfies the inequalities a[1] ≤ a[2] ≤ … ≤ a[n].

Input

The first line contains a single integer t (1 ≤ t ≤ 100) — the number of test cases in the test. Then t test cases follow.

Each test case starts with a line containing an integer n (1 ≤ n ≤ 3000) — length of the array a.

Then follow n integers a_1, a_2, …, a_n (0 ≤ a_i ≤ 10^9) — an array that needs to be sorted by the given operations. All numbers in the given array are distinct.

The sum of n for all test cases in one test does not exceed 3000.

Output

For each test case output one integer — the minimum total number of operations of the first and second type, which will make the array sorted in non-decreasing order.

Example

Input


4
5
4 7 2 3 9
5
3 5 8 1 7
5
1 4 5 7 12
4
0 2 1 3


Output


2
2
0
2

Note

In the first test case, you first need to move 3, and then 2 to the beginning of the array. Therefore, the desired sequence of operations: [4, 7, 2, 3, 9] → [3, 4, 7, 2, 9] → [2, 3, 4, 7, 9].

In the second test case, you need to move the 1 to the beginning of the array, and the 8 — to the end. Therefore, the desired sequence of operations: [3, 5, 8, 1, 7] → [1, 3, 5, 8, 7] → [1, 3, 5, 7, 8].

In the third test case, the array is already sorted.

Solution (in JAVA):

Solution:

import java.io.*;
import java.util.*;
import static java.lang.Math.*;

public class Main implements Runnable {

    private boolean console=false;
    private long MOD = 1000_000_007L;
    private int MAX = 1000_001;

    private void solve1(){

        int n = in.ni();
        int[] arr = arrInt(n);
        int[] tmp = Arrays.copyOfRange(arr,0,n);
        HashMap<Integer,Integer> map = new HashMap<>();
        sort(tmp);
        for(int i=0;i<n;++i){
            map.put(tmp[i],i);
        }

        for(int i=0;i<n;++i){
            arr[i] = map.get(arr[i]);
        }

        int[] a = new int[n];
        for (int i=0 ; i<n; i++) {
            a[arr[i]] = i;
        }
        long ans=1;
        long cnt=1;
        for(int i=0;i<n;i++) {
            if(i!=n-1&&a[i]<a[i+1])cnt++;
            else {
                ans=Math.max(ans, cnt);
                cnt=1;
            }
        }
        ans=Math.max(ans, cnt);
        ans=n-ans;


        out.printLn(ans);
    }

    private void solve() {
        int testCases = 1;
        testCases = in.ni();
        while (testCases-->0){
            solve1();
        }
    }

    private void add(TreeMap<Integer, Integer> map, int key){
        map.put(key,map.getOrDefault(key,0)+1);
    }

    private void remove(TreeMap<Integer,Integer> map,int key){
        if(!map.containsKey(key))
            return;
        map.put(key,map.getOrDefault(key,0)-1);
        if(map.get(key)==0)
            map.remove(key);
    }

    @Override
    public void run() {
        long time = System.currentTimeMillis();
        try {
            init();
        } catch (FileNotFoundException e) {
            e.printStackTrace();
        }
        try {
            solve();
            out.flush();
            System.err.println(System.currentTimeMillis()-time);
            System.exit(0);
        }catch (Exception e){
            e.printStackTrace(); System.exit(1);
        }
    }

    /* -------------------- Templates and Input Classes -------------------------------*/

    private FastInput in;
    private FastOutput out;
    public static void main(String[] args) throws Exception {
        new Main().run();
//        new Thread(null, new Main(), "Main", 1 << 27).start();
    }
    private void init() throws FileNotFoundException {
        InputStream inputStream = System.in;
        OutputStream outputStream = System.out;
        try {
            if (!console && System.getProperty("user.name").equals("puneet")) {
                outputStream = new FileOutputStream("/home/puneet/Desktop/output.txt");
                inputStream = new FileInputStream("/home/puneet/Desktop/input.txt");
            }
        } catch (Exception ignored) {
        }
        out = new FastOutput(outputStream);
        in = new FastInput(inputStream);
    }
    private void maualAssert(int a,int b,int c){
        if(a<b || a>c) throw new RuntimeException();
    }
    private void maualAssert(long a,long b,long c){
        if(a<b || a>c) throw new RuntimeException();
    }
    private void sort(int[] arr) {
        List<Integer> list = new ArrayList<>();
        for (int object : arr) list.add(object);
        Collections.sort(list);
        for (int i = 0; i < list.size(); ++i) arr[i] = list.get(i);
    }
    private void sort(long[] arr) {
        List<Long> list = new ArrayList<>();
        for (long object : arr) list.add(object);
        Collections.sort(list);
        for (int i = 0; i < list.size(); ++i) arr[i] = list.get(i);
    }
    private long ModPow(long x, long y, long MOD) {
        long res = 1L;
        x = x % MOD;
        while (y >= 1L) {
            if ((y & 1L) > 0) res = (res * x) % MOD;
            x = (x * x) % MOD;
            y >>= 1L;
        }
        return res;
    }
    private int gcd(int a, int b) {
        if (a == 0) return b;
        return gcd(b % a, a);
    }
    private long gcd(long a, long b) {
        if (a == 0) return b;
        return gcd(b % a, a);
    }
    private int[] arrInt(int n){
        int[] arr=new int[n];for(int i=0;i<n;++i)arr[i]=in.ni();
        return arr;
    }
    private long[] arrLong(int n){
        long[] arr=new long[n];for(int i=0;i<n;++i)arr[i]=in.nl();
        return arr;
    }

    private int arrMax(int[] arr){
        int ans = arr[0];
        for(int i=1;i<arr.length;++i){
            ans = max(ans,arr[i]);
        }
        return ans;
    }

    private long arrMax(long[] arr){
        long ans = arr[0];
        for(int i=1;i<arr.length;++i){
            ans = max(ans,arr[i]);
        }
        return ans;
    }

    private int arrMin(int[] arr){
        int ans = arr[0];
        for(int i=1;i<arr.length;++i){
            ans = max(ans,arr[i]);
        }
        return ans;
    }

    private long arrMin(long[] arr){
        long ans = arr[0];
        for(int i=1;i<arr.length;++i){
            ans = max(ans,arr[i]);
        }
        return ans;
    }

    class FastInput { InputStream obj;
        public FastInput(InputStream obj) {
            this.obj = obj;
        }
        private byte inbuffer[] = new byte[1024];
        private int lenbuffer = 0, ptrbuffer = 0;
        private int readByte() { if (lenbuffer == -1) throw new InputMismatchException();
            if (ptrbuffer >= lenbuffer) { ptrbuffer = 0;
                try { lenbuffer = obj.read(inbuffer);
                } catch (IOException e) { throw new InputMismatchException(); } }
            if (lenbuffer <= 0) return -1;return inbuffer[ptrbuffer++]; }
        String ns() { int b = skip();StringBuilder sb = new StringBuilder();
            while (!(isSpaceChar(b))) // when nextLine, (isSpaceChar(b) && b!=' ')
            { sb.appendCodePoint(b);b = readByte(); }return sb.toString();}
        int ni() {
            int num = 0, b;boolean minus = false;
            while ((b = readByte()) != -1 && !((b >= '0' && b <= '9') || b == '-')) ;
            if (b == '-') { minus = true;b = readByte(); }
            while (true) { if (b >= '0' && b <= '9') { num = num * 10 + (b - '0'); } else {
                return minus ? -num : num; }b = readByte(); }}
        long nl() { long num = 0;int b;boolean minus = false;
            while ((b = readByte()) != -1 && !((b >= '0' && b <= '9') || b == '-')) ;
            if (b == '-') { minus = true;b = readByte(); }
            while (true) { if (b >= '0' && b <= '9') { num = num * 10L + (b - '0'); } else {
                return minus ? -num : num; }b = readByte(); } }
        private boolean isSpaceChar(int c) {
            return (!(c >= 33 && c <= 126));
        }
        int skip() { int b;while ((b = readByte()) != -1 && isSpaceChar(b)) ;return b; }
        float nf() {return Float.parseFloat(ns());}
        double nd() {return Double.parseDouble(ns());}
        char nc() {return (char) skip();}
    }

    class FastOutput{

        private final PrintWriter writer;

        public FastOutput(OutputStream outputStream) {
            writer = new PrintWriter(outputStream);
        }
        public PrintWriter getWriter(){
            return writer;
        }
        public void print(Object obj){
            writer.print(obj);
        }
        public void printLn(){
            writer.println();
        }
        public void printLn(Object obj){
            writer.print(obj);
            printLn();
        }
        public void printSp(Object obj){
            writer.print(obj+" ");
        }
        public void printArr(int[]  arr){
            for(int i:arr)
                printSp(i);
            printLn();
        }
        public void printArr(long[]  arr){
            for(long i:arr)
                printSp(i);
            printLn();
        }
        public void flush(){
            writer.flush();
        }
    }
}