Problem: You are given a positive integer n. In one move, you can increase n by one (i.e. make n := n + 1). Your task is to find the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains two integers n and s (1 ≤ n ≤ 10^{18}; 1 ≤ s ≤ 162).

Output

For each test case, print the answer: the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

Example

Input


5
2 1
1 1
500 4
217871987498122 10
100000000000000001 1


Output


8
0
500
2128012501878
899999999999999999

Solution (in PYTHON3):

Solution:
from collections import Counter
import math
import sys
from bisect import bisect,bisect_left,bisect_right
def input(): return sys.stdin.readline().strip()
def INT(): return int(input())
def MAP(): return map(int, input().split())
def LIST(N=None): return list(MAP()) if N is None else [INT() for i in range(N)]
def mod(): return 10**9+7

def find_sum(n):
    s = 0
    while n:
        s += n % 10
        n //= 10
    return s

for i in range(INT()): 
    #n = INT()
    #s = input()
    n,s = MAP()
    #arr = LIST()
    n2 = n
    diff = find_sum(n) - s
    mult = 10
    while diff > 0:
        n = n - (n % mult)
        n += mult 
        mult *= 10
        diff = find_sum(n) - s
        
                
    print(n-n2)