Problem: The array a with n integers is given. Let's call the sequence of one or more consecutive elements in a segment. Also let's call the segment k-good if it contains no more than k different values.

Find any longest k-good segment.

As the input/output can reach huge size it is recommended to use fast input/output methods: for example, prefer to use scanf/printf instead of cin/cout in C++, prefer to use BufferedReader/PrintWriter instead of Scanner/System.out in Java.

Input

The first line contains two integers n, k (1 ≤ k ≤ n ≤ 5·105) — the number of elements in a and the parameter k.

The second line contains n integers ai (0 ≤ ai ≤ 106) — the elements of the array a.

Output

Print two integers l, r (1 ≤ l ≤ r ≤ n) — the index of the left and the index of the right ends of some k-good longest segment. If there are several longest segments you can print any of them. The elements in a are numbered from 1 to n from left to right.

Examples

Input

5 5
1 2 3 4 5


Output

1 5


Input

9 3
6 5 1 2 3 2 1 4 5


Output

3 7


Input

3 1
1 2 3


Output

1 1

Solution (in PYTHON3):

Solution:
n = int(input())
a = list(map(int, input().split()))

ans = []
s = set()

for i in range(len(a)):
    if a[i] in s:
        s = set()
        ans.append(i + 1)
    else:
        s.add(a[i])
if (len(ans) == 0):
    print(-1)
elif len(ans) == 1:
    print (len(ans))
    print(1, len(a))
else:
    print (len(ans))
    #print (ans)
    for i in range(len(ans)):
        if(i == 0):
            print(1, ans[0])
        elif i == len(ans) - 1:
            print(ans[i - 1] + 1, len(a))
        else:
            print(ans[i - 1] + 1, ans[i])