Problem: You are given a positive integer n. In one move, you can increase n by one (i.e. make n := n + 1). Your task is to find the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains two integers n and s (1 ≤ n ≤ 10^{18}; 1 ≤ s ≤ 162).

Output

For each test case, print the answer: the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

Example

Input


5
2 1
1 1
500 4
217871987498122 10
100000000000000001 1


Output


8
0
500
2128012501878
899999999999999999

Solution (in JAVA):

Solution:
import java.util.*;
public class Divisibility
{
    public static void main(String[] args){
    
    Scanner sc = new Scanner(System.in);
    int t,a,b,mul,ans;
    t = sc.nextInt();
    for(int i =0;i<t;i++){
    a = sc.nextInt();
    b = sc.nextInt();
    if(a%b!=0){
    mul = a/b;
    ans = b * (mul+1);
    System.out.println(ans-a);
    }else{
    System.out.println(0);
    }
    }

}
    
}