Problem: You are given a positive integer n. In one move, you can increase n by one (i.e. make n := n + 1). Your task is to find the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains two integers n and s (1 ≤ n ≤ 10^{18}; 1 ≤ s ≤ 162).

Output

For each test case, print the answer: the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

Example

Input


5
2 1
1 1
500 4
217871987498122 10
100000000000000001 1


Output


8
0
500
2128012501878
899999999999999999

Solution (in PYTHON3):

Solution:
'''
Author: AsilenceBTF
Blog: asilencebtf.top
Date: 2020-05-28 13:02:12
LastEditTime: 2020-09-04 23:11:19
'''

def f(n):
    res = 0
    while n > 0 : 
        res = res + 1
        n = n // 10
    return res
def check(n):
    res = 0
    while n > 0:
        res = res + (n%10)
        n = n // 10
    return res
for _ in range(int(input())):
    n, s = map(int, input().split())
    len = f(n)
    ans = pow(10, 20)
    if check(n) <= s:
        ans = 0 
    for i in range(0, len):
        p = n // pow(10, i + 1)
        p = p * pow(10, i + 1)
        p = p + pow(10, i + 1)
        if check(p) <= s:
            if ans > (p - n):
                ans = p - n 
    print(ans)