Problem: There is a square-shaped grid with N vertical rows and N horizontal columns. We will denote the square at the i-th row from the top and the j-th column from the left as (i,\ j).

Initially, each square is either white or black. The initial color of the grid is given to you as characters a_{ij}, arranged in a square shape. If the square (i,\ j) is white, a_{ij} is `.`. If it is black, a_{ij} is `#`.

You are developing a robot that repaints the grid. It can repeatedly perform the following operation:

* Select two integers i, j (1 ≤ i,\ j ≤ N). Memorize the colors of the squares (i,\ 1), (i,\ 2), ..., (i,\ N) as c_1, c_2, ..., c_N, respectively. Then, repaint the squares (1,\ j), (2,\ j), ..., (N,\ j) with the colors c_1, c_2, ..., c_N, respectively.



Your objective is to turn all the squares black. Determine whether it is possible, and find the minimum necessary number of operations to achieve it if the answer is positive.

Constraints

* 2 ≤ N ≤ 500
* a_{ij} is either `.` or `#`.

Input

The input is given from Standard Input in the following format:


N
a_{11}...a_{1N}
:
a_{N1}...a_{NN}


Output

If it is possible to turn all the squares black, print the minimum necessary number of operations to achieve the objective. If it is impossible, print `-1` instead.

Examples

Input

2
#.
.#


Output

3


Input

2
.
.#


Output

3


Input

2
..
..


Output

-1


Input

2


Output

0


Input

3
.#.

.#.


Output

2


Input

3
...
.#.
...


Output

5

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.*;

public class Main {
	FastScanner in;
	PrintWriter out;

	void solve() {
		int n = in.nextInt();
		char[][] a = new char[n][];
		for (int i = 0; i < n; i++) {
			a[i] = in.next().toCharArray();
		}
		boolean full = true;
		boolean empty = true;
		for (int i = 0; i < n; i++) {
			for (int j = 0; j < n; j++) {
				if (a[i][j] == '.') {
					full = false;
				} else {
					empty = false;
				}
			}
		}
		if (empty) {
			out.println(-1);
			return;
		}
		if (full) {
			out.println(0);
			return;
		}
		int res = Integer.MAX_VALUE;
		for (int r = 0; r < n; r++) {
			boolean ok = false;
			for (int i = 0; i < n; i++) {
				if (a[i][r] == '#') {
					ok = true;
				}
			}
			int cnt = ok ? 0 : 1;
			for (int i = 0; i < n; i++) {
				if (a[r][i] == '.') {
					cnt++;
				}
			}
			for (int c = 0; c < n; c++) {
				boolean ok2 = true;
				for (int i = 0; i < n; i++) {
					if (a[i][c] == '.') {
						ok2 = false;
					}
				}
				if (!ok2) {
					cnt++;
				}
			}
			res = Math.min(res, cnt);

		}
		out.println(res == Integer.MAX_VALUE ? -1 : res);
	}

	void run() {
		try {
			in = new FastScanner(new File("object.in"));
			out = new PrintWriter(new File("object.out"));

			solve();

			out.close();
		} catch (FileNotFoundException e) {
			e.printStackTrace();
		}
	}

	void runIO() {

		in = new FastScanner(System.in);
		out = new PrintWriter(System.out);

		solve();

		out.close();
	}

	class FastScanner {
		BufferedReader br;
		StringTokenizer st;

		public FastScanner(File f) {
			try {
				br = new BufferedReader(new FileReader(f));
			} catch (FileNotFoundException e) {
				e.printStackTrace();
			}
		}

		public FastScanner(InputStream f) {
			br = new BufferedReader(new InputStreamReader(f));
		}

		String next() {
			while (st == null || !st.hasMoreTokens()) {
				String s = null;
				try {
					s = br.readLine();
				} catch (IOException e) {
					e.printStackTrace();
				}
				if (s == null)
					return null;
				st = new StringTokenizer(s);
			}
			return st.nextToken();
		}

		boolean hasMoreTokens() {
			while (st == null || !st.hasMoreTokens()) {
				String s = null;
				try {
					s = br.readLine();
				} catch (IOException e) {
					e.printStackTrace();
				}
				if (s == null)
					return false;
				st = new StringTokenizer(s);
			}
			return true;
		}

		int nextInt() {
			return Integer.parseInt(next());
		}

		long nextLong() {
			return Long.parseLong(next());
		}

		double nextDouble() {
			return Double.parseDouble(next());
		}
	}

	public static void main(String[] args) {
		new Main().runIO();
	}
}