Problem: The array a with n integers is given. Let's call the sequence of one or more consecutive elements in a segment. Also let's call the segment k-good if it contains no more than k different values.

Find any longest k-good segment.

As the input/output can reach huge size it is recommended to use fast input/output methods: for example, prefer to use scanf/printf instead of cin/cout in C++, prefer to use BufferedReader/PrintWriter instead of Scanner/System.out in Java.

Input

The first line contains two integers n, k (1 ≤ k ≤ n ≤ 5·105) — the number of elements in a and the parameter k.

The second line contains n integers ai (0 ≤ ai ≤ 106) — the elements of the array a.

Output

Print two integers l, r (1 ≤ l ≤ r ≤ n) — the index of the left and the index of the right ends of some k-good longest segment. If there are several longest segments you can print any of them. The elements in a are numbered from 1 to n from left to right.

Examples

Input

5 5
1 2 3 4 5


Output

1 5


Input

9 3
6 5 1 2 3 2 1 4 5


Output

3 7


Input

3 1
1 2 3


Output

1 1

Solution (in JAVA):

Solution:
import java.util.ArrayList;
import java.util.HashSet;
import java.util.Scanner;

/**
 *
 * @author 753617
 */
public class Learn1 {
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        
      long n = in.nextInt();
        ArrayList<Integer> al = new ArrayList();
        
        for(int i =0; i<n;i++)
        {
            al.add(in.nextInt());
            
        }
        HashSet<Integer> hs = new HashSet<Integer>();
        
        ArrayList<String> st= new ArrayList<String>();
        
        int start=0;
       int prev=0;
        for(int i =0; i<n; i++)
        {
            if(!hs.contains(al.get(i)))
            {
                hs.add(al.get(i));
            }
        
            else{
               
                st.add((start+1)+" "+ (i+1));
             
                prev= start;
                start=i+1;
             
                hs.clear();
            }
        }
    
    if(st.size()==0)
    {
        System.out.println("-1");
        return;
    }
    if(!hs.isEmpty())
    {
        st.remove(st.remove(st.size()-1));
        
        st.add((prev+1)+" "+ n);
        
    }
    
        System.out.println(st.size());
    for(int i =0; i<st.size(); i++)
    {
        System.out.println(st.get(i));
    }
    }
}