Problem: You are given two integers n and k. You are asked to choose maximum number of distinct integers from 1 to n so that there is no subset of chosen numbers with sum equal to k.

A subset of a set is a set that can be obtained from initial one by removing some (possibly all or none) elements of it.

Input

The first line contains the number of test cases T (1 ≤ T ≤ 100).

Each of the next T lines contains two integers n and k (1 ≤ k ≤ n ≤ 1000) — the description of test cases.

Output

For each test case output two lines. In the first line output a single integer m — the number of chosen integers.

In the second line output m distinct integers from 1 to n — the chosen numbers.

If there are multiple answers, print any. You can print the numbers in any order.

Example

Input


3
3 2
5 3
1 1


Output


2
3 1 
3
4 5 2 
0

Solution (in CPP):

Solution:
//
// Created by Abhishek Bansal on 3/6/2021
//
//#pragma GCC optimize ("O3")
//#pragma GCC optimize("Ofast,no-stack-protector")
//#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,mmx,tune=native")
#include <bits/stdc++.h>
#define ll long long
#define ld long double
using namespace std;
clock_t startTime;
double getCurrentTime() {
    return (double)(clock() - startTime) / CLOCKS_PER_SEC;
}
/*------------------------------------------------IO_OPERATORS---------------------------------------------*/
template<typename T, typename U> inline ostream &operator << (ostream &_out, const pair<T, U> &_p) { _out << _p.first << " " << _p.second; return _out; }
template<typename T, typename U> inline istream &operator >> (istream &_in, pair<T, U> &_p) { _in >> _p.first >> _p.second; return _in; }
template<typename T> inline ostream &operator << (ostream &_out, const vector<T> &_v) { if (_v.empty()) return _out; _out << _v.front(); for (auto _it = ++_v.begin(); _it != _v.end(); ++_it) _out << ' ' << *_it; return _out; }
template<typename T> inline istream &operator >> (istream &_in, vector<T> &_v) { for (auto &_i : _v) _in >> _i; return _in; }
template<typename T> inline ostream &operator << (ostream &_out, const set<T> &_s) { if (_s.empty()) return _out; _out << *_s.begin(); for (auto _it = ++_s.begin(); _it != _s.end(); ++_it) _out << ' ' << *_it; return _out; }
template<typename T> inline ostream &operator << (ostream &_out, const multiset<T> &_s) { if (_s.empty()) return _out; _out << *_s.begin(); for (auto _it = ++_s.begin(); _it != _s.end(); ++_it) _out << ' ' << *_it; return _out; }
template<typename T> inline ostream &operator << (ostream &_out, const unordered_set<T> &_s) { if (_s.empty()) return _out; _out << *_s.begin(); for (auto _it = ++_s.begin(); _it != _s.end(); ++_it) _out << ' ' << *_it; return _out; }
template<typename T> inline ostream &operator << (ostream &_out, const unordered_multiset<T> &_s) { if (_s.empty()) return _out; _out << *_s.begin(); for (auto _it = ++_s.begin(); _it != _s.end(); ++_it) _out << ' ' << *_it; return _out; }
template<typename T, typename U> inline ostream &operator << (ostream &_out, const map<T, U> &_m) { if (_m.empty()) return _out; _out << "{\"" << _m.begin()->first << "\", \"" << _m.begin()->second << "\"}"; for (auto _it = ++_m.begin(); _it != _m.end(); ++_it) _out << ", { \"" << _it->first << "\", \"" << _it->second << "\"}"; return _out; }
template<typename T, typename U> inline ostream &operator << (ostream &_out, const unordered_map<T, U> &_m) { if (_m.empty()) return _out; _out << '(' << _m.begin()->first << ": " << _m.begin()->second << ')'; for (auto _it = ++_m.begin(); _it != _m.end(); ++_it) _out << ", (" << _it->first << ": " << _it->second << ')'; return _out; }
//For 1 based indexing
template<typename T>
void out(const vector<T> &a, int n) {
    for (int i = 1; i <= n; ++i) {cout << a[i] << ' ';} cout << "\n";
}
template<typename T>
void out(const vector<vector<T>> &a, int n, int m) {
    for (int i = 1; i <= n; ++i) {for (int j = 1; j <= m; ++j) {cout << a[i][j] << ' ';}cout << '\n';}
}

void solve() {
    int n, k;cin >> n >> k;
    vector<int> ans;
    for (int i = (k + 1) / 2; i < k; ++i) {
        ans.push_back(i);
    }
    for (int j = k + 1; j <= n; ++j) {
        ans.push_back(j);
    }
    cout << ans.size() << "\n";
    cout << ans << "\n";
}

int main() {
    ios_base::sync_with_stdio(false);cin.tie(nullptr);

    startTime = clock();
//	freopen("input.txt", "r", stdin);
//	freopen("output.txt", "w", stdout);
//    cout << fixed << setprecision(20);
    int T = 1;
    cin >> T;
    while (T--) {
        solve();
    }
    return 0;
}