Problem: The array a with n integers is given. Let's call the sequence of one or more consecutive elements in a segment. Also let's call the segment k-good if it contains no more than k different values.

Find any longest k-good segment.

As the input/output can reach huge size it is recommended to use fast input/output methods: for example, prefer to use scanf/printf instead of cin/cout in C++, prefer to use BufferedReader/PrintWriter instead of Scanner/System.out in Java.

Input

The first line contains two integers n, k (1 ≤ k ≤ n ≤ 5·105) — the number of elements in a and the parameter k.

The second line contains n integers ai (0 ≤ ai ≤ 106) — the elements of the array a.

Output

Print two integers l, r (1 ≤ l ≤ r ≤ n) — the index of the left and the index of the right ends of some k-good longest segment. If there are several longest segments you can print any of them. The elements in a are numbered from 1 to n from left to right.

Examples

Input

5 5
1 2 3 4 5


Output

1 5


Input

9 3
6 5 1 2 3 2 1 4 5


Output

3 7


Input

3 1
1 2 3


Output

1 1

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.ArrayList;
import java.util.HashSet;

public class P620C
{
	public static void main(String[] args) throws IOException
	{
		BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
		int n = Integer.parseInt(br.readLine());
		String[] strArr = br.readLine().split("\\s");
		HashSet<Integer> types = new HashSet<Integer>();
		ArrayList<Integer> segmentStartEnd = new ArrayList<Integer>();
		int segments = 0;
		boolean newSegment = true;
		
		for (int i = 1; i <= n; i++)
		{
			if (newSegment)
			{
				types = new HashSet<Integer>();
				newSegment = false;
				segmentStartEnd.add(i);
			}
			int type = Integer.parseInt(strArr[i-1]);
			if (types.contains(type))
			{
				newSegment = true;
				segmentStartEnd.add(i);
				segments++;
			}
			else if (i == n && segmentStartEnd.size() >= 2)
				segmentStartEnd.set(segmentStartEnd.size()-2, i);
			else
				types.add(type);
		}
		if (segments == 0)
			System.out.println(-1);
		else
		{
			System.out.println(segments);
			for (int i = 0; i < segments; i++)
				System.out.println(segmentStartEnd.get(2*i) + " " + segmentStartEnd.get(2*i+1));
		}
	}
}