Problem: You are given a positive integer n. In one move, you can increase n by one (i.e. make n := n + 1). Your task is to find the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains two integers n and s (1 ≤ n ≤ 10^{18}; 1 ≤ s ≤ 162).

Output

For each test case, print the answer: the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

Example

Input


5
2 1
1 1
500 4
217871987498122 10
100000000000000001 1


Output


8
0
500
2128012501878
899999999999999999

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.StringTokenizer;

public class D {
    private FastScanner in;
    private PrintWriter out;

    public D(FastScanner in, PrintWriter out) {
        this.in = in;
        this.out = out;
    }

    public static void main(String[] args) {
        try (
                FastScanner in = new FastScanner(System.in);
                PrintWriter out = new PrintWriter(System.out);
        ) {
            D solution = new D(in, out);
            solution.solve();
        } catch (IOException e) {
            e.printStackTrace();
        }
    }

    public void solve() throws IOException {
        int t = in.nextInt();
        while (t-- > 0) {
            long n = in.nextLong();
            long s = in.nextLong();
            long multiplyer = 1;
            long res = 0;
            while (n > 1) {
                if (digitSum(n) <= s) {
                    break;
                }
                res += (10 - n % 10) * multiplyer;
                multiplyer *= 10;
                n /= 10;
                n++;
            }
            out.println(res);
        }
    }

    private long digitSum(long n) {
        long res = 0;
        while (n > 0) {
            res += n % 10;
            n /= 10;
        }
        return res;
    }


    public static class FastScanner implements Closeable {
        BufferedReader bufferedReader;
        StringTokenizer stringTokenizer;

        public FastScanner(InputStream inputStream) {
            this.bufferedReader = new BufferedReader(new InputStreamReader(inputStream));
        }

        public FastScanner(File file) throws FileNotFoundException {
            this(new FileInputStream(file));
        }

        public String next() throws IOException {
            while (stringTokenizer == null || !stringTokenizer.hasMoreTokens()) {
                String line = bufferedReader.readLine();
                if (line == null) {
                    throw new EOFException("End of input stream is reached.");
                }
                stringTokenizer = new StringTokenizer(line);
            }
            return stringTokenizer.nextToken();
        }

        public String nextLine() throws IOException {
            stringTokenizer = null;
            return bufferedReader.readLine();
        }

        public int nextInt() throws IOException {
            return Integer.parseInt(next());
        }

        public long nextLong() throws IOException {
            return Long.parseLong(next());
        }

        public double nextDouble() throws IOException {
            return Double.parseDouble(next());
        }

        @Override
        public void close() throws IOException {
            bufferedReader.close();
        }
    }
}