Problem: One way to create a task is to learn from math. You can generate some random math statement or modify some theorems to get something new and build a new task from that.

For example, there is a statement called the "Goldbach's conjecture". It says: "each even number no less than four can be expressed as the sum of two primes". Let's modify it. How about a statement like that: "each integer no less than 12 can be expressed as the sum of two composite numbers." Not like the Goldbach's conjecture, I can prove this theorem.

You are given an integer n no less than 12, express it as a sum of two composite numbers.

Input

The only line contains an integer n (12 ≤ n ≤ 106).

Output

Output two composite integers x and y (1 < x, y < n) such that x + y = n. If there are multiple solutions, you can output any of them.

Examples

Input

12


Output

4 8


Input

15


Output

6 9


Input

23


Output

8 15


Input

1000000


Output

500000 500000

Note

In the first example, 12 = 4 + 8 and both 4, 8 are composite numbers. You can output "6 6" or "8 4" as well.

In the second example, 15 = 6 + 9. Note that you can't output "1 14" because 1 is not a composite number.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
const int N = 1e5 + 5;
const long long mod = pow(10, 9) + 7;
void google(int tc) { cout << "Case #" << tc << ": "; }
bool palindrome(const string &s) {
  int n = s.length();
  for (int i = 0; i < n; i++) {
    if (s[i] != s[n - i - 1]) return false;
  }
  return true;
}
int main() {
  ios::sync_with_stdio(0);
  cin.tie(0);
  int n;
  cin >> n;
  if (n & 1) {
    if (n == 13)
      cout << "4 9";
    else if (n == 15)
      cout << "6 9";
    else if (n == 17)
      cout << "9 8";
    else
      cout << "15 " << n - 15;
  } else {
    cout << 4 << " " << n - 4 << "\n";
  }
}