Problem: The array a with n integers is given. Let's call the sequence of one or more consecutive elements in a segment. Also let's call the segment k-good if it contains no more than k different values.

Find any longest k-good segment.

As the input/output can reach huge size it is recommended to use fast input/output methods: for example, prefer to use scanf/printf instead of cin/cout in C++, prefer to use BufferedReader/PrintWriter instead of Scanner/System.out in Java.

Input

The first line contains two integers n, k (1 ≤ k ≤ n ≤ 5·105) — the number of elements in a and the parameter k.

The second line contains n integers ai (0 ≤ ai ≤ 106) — the elements of the array a.

Output

Print two integers l, r (1 ≤ l ≤ r ≤ n) — the index of the left and the index of the right ends of some k-good longest segment. If there are several longest segments you can print any of them. The elements in a are numbered from 1 to n from left to right.

Examples

Input

5 5
1 2 3 4 5


Output

1 5


Input

9 3
6 5 1 2 3 2 1 4 5


Output

3 7


Input

3 1
1 2 3


Output

1 1

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.Closeable;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.math.BigInteger;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.HashMap;
import java.util.HashSet;
import java.util.LinkedList;
import java.util.Map;
import java.util.Map.Entry;
import java.util.Set;
import java.util.StringTokenizer;
import java.util.TreeSet;

public class D {

	public static void main(String[] args) {
		
		try (final Scanner sc = new Scanner(System.in)) {
			final int n = sc.nextInt();
			final int k = sc.nextInt();
			
			final int MAX = 1000000;
			int[] map = new int[MAX + 1];
			
			int[] array = new int[n];
			for(int i = 0; i < n; i++){
				array[i] = sc.nextInt();
			}
			
			int fst = 0, lst = 0, count = 0;
			int max_start = -1, max_last = -2;
			while(fst < n){
				//System.out.println("(" + fst + ", " + lst + "]");
				
				final int max_len = max_last - max_start + 1;
				if(max_len < (lst - fst)){
					max_start = (fst + 1);
					max_last  = (lst - 1) + 1;
				}
				
				if(lst < n && ((count < k) || (count == k && map[array[lst]] > 0))){
					if(map[array[lst]] == 0){
						count++;
					}
					map[array[lst]]++;
					
					lst++;
					continue;
				}
				
				{
					map[array[fst]]--;
					if(map[array[fst]] <= 0){
						count--;
					}
					
					fst++;
				}
			}
			
			System.out.println(max_start + " " + max_last);
			
		}
	}

	public static class Scanner implements Closeable {
		private BufferedReader br;
		private StringTokenizer tok;

		public Scanner(InputStream is) {
			br = new BufferedReader(new InputStreamReader(is));
		}

		private void getLine() {
			try {
				while (!hasNext()) {
					tok = new StringTokenizer(br.readLine());
				}
			} catch (IOException e) { /* ignore */
			}
		}

		private boolean hasNext() {
			return tok != null && tok.hasMoreTokens();
		}

		public String next() {
			getLine();
			return tok.nextToken();
		}

		public int nextInt() {
			return Integer.parseInt(next());
		}

		public long nextLong() {
			return Long.parseLong(next());
		}

		public void close() {
			try {
				br.close();
			} catch (IOException e) { /* ignore */
			}
		}
	}
}