Problem: Today, Osama gave Fadi an integer X, and Fadi was wondering about the minimum possible value of max(a, b) such that LCM(a, b) equals X. Both a and b should be positive integers.

LCM(a, b) is the smallest positive integer that is divisible by both a and b. For example, LCM(6, 8) = 24, LCM(4, 12) = 12, LCM(2, 3) = 6.

Of course, Fadi immediately knew the answer. Can you be just like Fadi and find any such pair?

Input

The first and only line contains an integer X (1 ≤ X ≤ 10^{12}).

Output

Print two positive integers, a and b, such that the value of max(a, b) is minimum possible and LCM(a, b) equals X. If there are several possible such pairs, you can print any.

Examples

Input


2


Output


1 2


Input


6


Output


2 3


Input


4


Output


1 4


Input


1


Output


1 1

Solution (in PYTHON3):

Solution:
from math import gcd
from sys import stdin


def main():
    input = lambda: stdin.readline()[:-1]
    X = int(input())

    lcm = lambda x, y: x * y // gcd(x, y)
    n = int(X ** 0.5)
    for a in range(n, 0, -1):
        b, mod = divmod(X, a)
        if not mod and lcm(a, b) == X:
            print(*sorted([a, b]))
            break


main()