Problem: For given two circles $c1$ and $c2$, print the coordinates of the cross points of them.

Constraints

* The given circle have at least one cross point and have different center coordinates.
* $-10,000 \leq c1x, c1y, c2x, c2y \leq 10,000$
* $1 \leq c1r, c2r \leq 10,000$

Input

The input is given in the following format.

$c1x\; c1y\; c1r$
$c2x\; c2y\; c2r$


$c1x$, $c1y$ and $c1r$ represent the coordinate and radius of the first circle. $c2x$, $c2y$ and $c2r$ represent the coordinate and radius of the second circle. All input values are given in integers.

Output

Print the coordinates ($x1$, $y1$) and ($x2$, $y2$) of the cross points $p1$ and $p2$ respectively in the following rules.

* If there is one cross point, print two coordinates with the same values.
* Print the coordinate with smaller $x$ first. In case of a tie, print the coordinate with smaller $y$ first.



The output values should be in a decimal fraction with an error less than 0.000001.

Examples

Input

0 0 2
2 0 2


Output

1.00000000 -1.73205080 1.00000000 1.73205080


Input

0 0 2
0 3 1


Output

0.00000000 2.00000000 0.00000000 2.00000000

Solution (in CPP):

Solution:
#include<iostream>
#include<cmath>
#include<vector>
#include<cstdio>
#include<algorithm>
using namespace std;
#define EPS (1e-10)
#define equals(a, b) (fabs((a) - (b)) < EPS )
class Point{
public:
  double x, y;
  Point ( double x = 0, double y = 0): x(x), y(y){}
  Point operator + ( Point p ){ return Point(x + p.x, y + p.y); }
  Point operator - ( Point p ){ return Point(x - p.x, y - p.y); }
  Point operator * ( double a ){ return Point(x*a, y*a); }
  Point operator / ( double a ){ return Point(x/a, y/a); }
  double abs() { return sqrt(norm());}
  double norm() { return x*x + y*y; }
  bool operator < ( const Point &p ) const {
    return x != p.x ? x < p.x : y < p.y;
  }
  bool operator == ( const Point &p ) const {
    return fabs(x-p.x) < EPS && fabs(y-p.y) < EPS;
  }
};
class Segment{
public:
  Point p1, p2;
  Segment ( Point p1 = Point(0.0,0.0), Point p2 = Point(0.0,0.0)): p1(p1), p2(p2){}
  double abs() { return sqrt(norm());}
  double norm() { return (p2.x - p1.x)*(p2.x - p1.x) + (p2.y - p1.y)*(p2.y - p1.y); }
};
typedef Point Vector;
typedef Segment Line;
double norm( Vector a ){ return a.x*a.x + a.y*a.y; }
double abs( Vector a ){ return sqrt(norm(a)); }
double dot( Vector a, Vector b ){ return a.x*b.x + a.y*b.y; }
double cross( Vector a, Vector b ){ return a.x*b.y - a.y*b.x; }
double getDistanceLP(Line s,Point p){
  return abs(cross(s.p2-s.p1,p-s.p1)/abs(s.p2-s.p1));
}
double getDistanceSP(Segment s,Point p){
  if(dot(s.p2-s.p1,p-s.p1)<0.0)return abs(p-s.p1);
  if(dot(s.p1-s.p2,p-s.p2)<0.0)return abs(p-s.p2);
  return getDistanceLP(s,p);
}

Point project(Segment s,Point p){
  Vector base = s.p2-s.p1;
  double t = dot(p-s.p1,base)/norm(base);
  return s.p1+base*t;
}

Point p1,p2;
double r1,r2;
Segment s;

Point rotate( Point a, double si,double co){
  return Point(a.x*co-a.y*si,a.x*si+a.y*co);
}

Point getCrossPointCC(Point p1,double r1,Point p2,double r2){
  double a=r2,b=r1,c=abs(p1-p2);
  double cos_A = (b*b+c*c-a*a) / (2.0*b*c);
  double sin_A = sqrt(1.0-cos_A*cos_A);
  Vector v=p2-p1;
  v = v * r1 / c;
  return p1+rotate(v,sin_A,cos_A);
}

int main(){
  cin>>p1.x>>p1.y>>r1;
  cin>>p2.x>>p2.y>>r2;

  Point A=getCrossPointCC(p1,r1,p2,r2);
  Point B=getCrossPointCC(p2,r2,p1,r1);
  Point a=min(A,B),b=max(A,B);
  printf("%.9f %.9f %.9f %.9f\n",a.x,a.y,b.x,b.y);
  return 0;
}