Problem: You are given a sequence a1, a2, ..., an consisting of different integers. It is required to split this sequence into the maximum number of subsequences such that after sorting integers in each of them in increasing order, the total sequence also will be sorted in increasing order.

Sorting integers in a subsequence is a process such that the numbers included in a subsequence are ordered in increasing order, and the numbers which are not included in a subsequence don't change their places.

Every element of the sequence must appear in exactly one subsequence.

Input

The first line of input data contains integer n (1 ≤ n ≤ 105) — the length of the sequence.

The second line of input data contains n different integers a1, a2, ..., an ( - 109 ≤ ai ≤ 109) — the elements of the sequence. It is guaranteed that all elements of the sequence are distinct.

Output

In the first line print the maximum number of subsequences k, which the original sequence can be split into while fulfilling the requirements.

In the next k lines print the description of subsequences in the following format: the number of elements in subsequence ci (0 < ci ≤ n), then ci integers l1, l2, ..., lci (1 ≤ lj ≤ n) — indices of these elements in the original sequence. 

Indices could be printed in any order. Every index from 1 to n must appear in output exactly once.

If there are several possible answers, print any of them.

Examples

Input

6
3 2 1 6 5 4


Output

4
2 1 3
1 2
2 4 6
1 5


Input

6
83 -75 -49 11 37 62


Output

1
6 1 2 3 4 5 6

Note

In the first sample output:

After sorting the first subsequence we will get sequence 1 2 3 6 5 4.

Sorting the second subsequence changes nothing.

After sorting the third subsequence we will get sequence 1 2 3 4 5 6.

Sorting the last subsequence changes nothing.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
long long int min(long long int a, long long int b) { return a < b ? a : b; }
long long int min(long long int a, long long int b, long long int c) {
  a = min(a, b);
  a = min(a, c);
  return a;
}
long long int max(long long int a, long long int b) { return a > b ? a : b; }
long long int max(long long int a, long long int b, long long int c) {
  a = max(a, b);
  a = max(a, c);
  return a;
}
long long int dsum(long long int n) {
  long long int ans = 0;
  while (n) {
    ans += (n % 10);
    n /= 10;
  }
  return ans;
}
long long int power(long long int a, long long int b) {
  long long int res = 1;
  while (b) {
    if (b & 1) res = res * a;
    a = a * a;
    b >>= 1;
  }
  return res;
}
long long int Ceil(long long int a, long long int b) {
  long long int res = a / b;
  if (a % b != 0) res++;
  return res;
}
template <typename T>
istream &operator>>(istream &is, vector<T> &v) {
  for (T &t : v) is >> t;
  return is;
}
template <typename T>
ostream &operator<<(ostream &os, const vector<T> &v) {
  for (const T &t : v) {
    os << t << " ";
  }
  os << '\n';
  return os;
}
long long int dxx[] = {1, 1, 0, -1, -1, -1, 0, 1};
long long int dyy[] = {0, 1, 1, 1, 0, -1, -1, -1};
long long int dx[] = {1, 0, -1, 0};
long long int dy[] = {0, 1, 0, -1};
struct pll {
  long long int x, y;
};
bool comp(pll a, pll b) {
  if (a.x == b.x)
    return a.y < b.y;
  else
    return a.x < b.x;
}
bool vis[200005];
vector<vector<long long int> > adj(200005);
vector<long long int> vv;
void dfs(long long int x) {
  if (vis[x]) return;
  vis[x] = true;
  vv.push_back(x);
  for (auto j : adj[x]) {
    if (!vis[j]) {
      dfs(j);
    }
  }
}
long long int par[200005];
long long int sz[200005];
void init() {
  for (long long int i = 0; i < 200005; i++) {
    par[i] = i;
    sz[i] = 1;
  }
}
long long int parent(long long int x) {
  if (par[x] == x) return x;
  par[x] = parent(par[x]);
  return par[x];
}
void unionxy(long long int x, long long int y) {
  long long int px = parent(x);
  long long int py = parent(y);
  if (px == py) return;
  par[py] = px;
  sz[px] += sz[py];
}
void solve(long long int the) {
  char ch;
  double aa, bb, cc, dd, xx;
  string s1, s2, s3, str;
  long long int i, j, k, a, b, c, d, n, m, l, r, x, y, z, low, high, mid,
      sum = 0, ans = 0, temp, t;
  cin >> n;
  vector<long long int> v(n);
  cin >> v;
  map<long long int, long long int> in;
  for (i = 0; i < n; i++) {
    in[v[i]] = i + 1;
  }
  sort(v.begin(), v.end());
  map<long long int, long long int> fi;
  for (i = 0; i < n; i++) {
    fi[v[i]] = i + 1;
  }
  init();
  for (i = 0; i < n; i++) {
    a = in[v[i]];
    b = fi[v[i]];
    adj[a].push_back(b);
    adj[b].push_back(a);
    unionxy(a, b);
  }
  for (i = 1; i <= n; i++) {
    if (parent(i) == i) ans++;
  }
  cout << ans << endl;
  memset(vis, false, sizeof(vis));
  for (i = 1; i <= n; i++) {
    if (!vis[i]) {
      vv.clear();
      dfs(i);
      cout << vv.size() << " " << vv;
    }
  }
}
int main() {
  long long int t = 1, c = 1;
  while (t--) {
    solve(c);
    c++;
  }
  return 0;
}