Problem: Today, Osama gave Fadi an integer X, and Fadi was wondering about the minimum possible value of max(a, b) such that LCM(a, b) equals X. Both a and b should be positive integers.

LCM(a, b) is the smallest positive integer that is divisible by both a and b. For example, LCM(6, 8) = 24, LCM(4, 12) = 12, LCM(2, 3) = 6.

Of course, Fadi immediately knew the answer. Can you be just like Fadi and find any such pair?

Input

The first and only line contains an integer X (1 ≤ X ≤ 10^{12}).

Output

Print two positive integers, a and b, such that the value of max(a, b) is minimum possible and LCM(a, b) equals X. If there are several possible such pairs, you can print any.

Examples

Input


2


Output


1 2


Input


6


Output


2 3


Input


4


Output


1 4


Input


1


Output


1 1

Solution (in PYTHON3):

Solution:
import math

def lcm(a,b):
    m = a*b
    while a != 0 and b != 0:
        if a > b:
            a %= b
        else:
            b %= a
    return m // (a+b)

n = int(input())
sm = 10**12 + 1

a,b = 1, n

for i in range(1, int(math.sqrt(n)) + 100):
    if n % i == 0 and (n//i) % i != 0:
        if max(n//i, i) < sm and lcm(n//i, i) == n:
            sm = max(n//i, i)
            a,b = n//i, i

print(a, b)