Problem: There is data on sales of your company. Your task is to write a program which identifies good workers.

The program should read a list of data where each item includes the employee ID i, the amount of sales q and the corresponding unit price p. Then, the program should print IDs of employees whose total sales proceeds (i.e. sum of p × q) is greater than or equal to 1,000,000 in the order of inputting. If there is no such employees, the program should print "NA". You can suppose that n < 4000, and each employee has an unique ID. The unit price p is less than or equal to 1,000,000 and the amount of sales q is less than or equal to 100,000.



Input

The input consists of several datasets. The input ends with a line including a single 0. Each dataset consists of:


n (the number of data in the list)
i p q
i p q
:
:
i p q


Output

For each dataset, print a list of employee IDs or a text "NA"

Example

Input

4
1001 2000 520
1002 1800 450
1003 1600 625
1001 200 1220
2
1001 100 3
1005 1000 100
2
2013 5000 100
2013 5000 100
0


Output

1001
1003
NA
2013

Solution (in CPP):

Solution:
#include <stdio.h>
#include <vector>
#include <map>
using namespace std;
#define rep(i, n) for (int i = 0; i < (int)(n); i++)
typedef long long Int;

int main() {
    for (;;) {
        int n;
        scanf("%d", &n);
        if (n == 0) return 0;
        map<int, Int> of;
        vector<int> ids;
        int c = 0;
        rep (_, n) {
            int id, p, q;
            scanf("%d%d%d", &id, &p, &q);
            ids.push_back(id);
            of[id] += (Int)p*q;
        }
        rep (i, n) if (of[ids[i]] >= 1000000) {
            printf("%d\n", ids[i]);
            of[ids[i]] = 0;
            c++;
        }
        if (c == 0) puts("NA");
    }
    return 0;
}