Problem: You are given a set of n segments on the axis Ox, each segment has integer endpoints between 1 and m inclusive. Segments may intersect, overlap or even coincide with each other. Each segment is characterized by two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ m) — coordinates of the left and of the right endpoints. 

Consider all integer points between 1 and m inclusive. Your task is to print all such points that don't belong to any segment. The point x belongs to the segment [l; r] if and only if l ≤ x ≤ r.

Input

The first line of the input contains two integers n and m (1 ≤ n, m ≤ 100) — the number of segments and the upper bound for coordinates.

The next n lines contain two integers each l_i and r_i (1 ≤ l_i ≤ r_i ≤ m) — the endpoints of the i-th segment. Segments may intersect, overlap or even coincide with each other. Note, it is possible that l_i=r_i, i.e. a segment can degenerate to a point.

Output

In the first line print one integer k — the number of points that don't belong to any segment.

In the second line print exactly k integers in any order — the points that don't belong to any segment. All points you print should be distinct.

If there are no such points at all, print a single integer 0 in the first line and either leave the second line empty or do not print it at all.

Examples

Input

3 5
2 2
1 2
5 5


Output

2
3 4 


Input

1 7
1 7


Output

0

Note

In the first example the point 1 belongs to the second segment, the point 2 belongs to the first and the second segments and the point 5 belongs to the third segment. The points 3 and 4 do not belong to any segment.

In the second example all the points from 1 to 7 belong to the first segment.

Solution (in JAVA):

Solution:
import java.util.Scanner;
import java.util.ArrayList;
public class Main
{
	public static void main(String args[])
	{
		Scanner sc = new Scanner(System.in);
		String t[] = sc.nextLine().split(" ");
		int n = Integer.parseInt(t[0]);
		int m = Integer.parseInt(t[1]);
		int v[][] = new int[n][2];
		ArrayList<Integer> l = new ArrayList<Integer>();
		for(int i = 1;i<=m;i++)
			l.add(i);
		for(int i = 0;i<n;i++)
		{
			String temp[] = sc.nextLine().split(" ");
			v[i][0]	= Integer.parseInt(temp[0]);
			v[i][1]	= Integer.parseInt(temp[1]);
			for(int j = v[i][0];j<=v[i][1];j++)
			{
				
				if(l.indexOf(j) >=0)
				{
					
					l.remove(l.indexOf(j));	
				}
			}
		}
		System.out.println(l.size());
		System.out.println(l.toString().replaceAll("[\\[\\],]"," ").trim());
				

	}

	
}