Problem: Roy's friends has been spying on his text messages, so Roy thought of an algorithm to encrypt text messages.  

Encryption Algorithm is as follows:
We say message to be encrypted as Plain Text and encrypted form of message as Cipher.
Plain Text consists of lower case alphabets only.
Consider the Cipher Disk as shown in figure.  

Initially, we start with 0 (zero). For each character in Plain Text, we move either clockwise or anti-clockwise on the disk depending on which way is closest from where we are currently standing.
If both clockwise and anti-clockwise distances are equal, we give priority to clockwise movement.
Clockwise movements are represented using positive numbers while Anti-clockwise movements are represented as negative numbers.

Roy needs your help in implementing this algorithm. Given a Plain Text message, your task is to encrypt it using above algorithm and print the Cipher Text.

Input:
First line contains integer T - number of test cases.
Each of next T lines contains a string representing Plain Text message.  

Output:
For each test case, print the encrypted form of given string in new line.
Each line should consist of space separated integers in the range [-12,13].
See the sample test case for more clarification.  

Constraints:
1 ≤ T ≤ 100
1 ≤ Length of Plain Text string ≤ 100  

Sample Test Case Explanation:
Explanation for 3rd sample test case "correct"SAMPLE INPUT
3
aeiou
hackerearth
correct

SAMPLE OUTPUT
0 4 4 6 6
7 -7 2 8 -6 13 13 -4 -9 2 -12
2 12 3 0 13 -2 -9

Explanation

We begin from 0 (zero)
1. 'a'->'c' - two steps clockwise, we reach 'c'
2. 'c'->'o' - twelve steps clockwise, we reach 'o'
3. 'o'->'r' - three steps clockwise, we reach 'r'
4. 'r'->'r' - we are already at 'r', so zero steps
5. 'r'->'e' - thirteen steps clockwise, we reach 'e'
6. 'e'->'c' - here moving anti-clockwise is optimal, so two steps anticlockwise, and for anticlockwise we add negative sign.
7. 'c'->'t' - again anti-clockwise, nine steps.

Solution (in PYTHON):

Solution:
t = input()
T = t if 1<=t<=100 else exit(1)
for i in range(T):
	string = list(raw_input())
	alpha = ['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z']
	num = [0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25]
	dick = dict(zip(alpha,num))
	if 1<=len(string)<=100:
		j=0
		output = []
		initial  = 0
		while(j<len(string)):
			current = dick.get(string[j])
			dis1 = (current - initial)%26
			dis2 = (initial - current)%26
			if dis1 <= dis2:
				distance = dis1
			else:
				distance = -dis2
			initial = current
			output.append(distance)
			j += 1
		print ' '.join(map(str,output))