Problem: Today, Osama gave Fadi an integer X, and Fadi was wondering about the minimum possible value of max(a, b) such that LCM(a, b) equals X. Both a and b should be positive integers.

LCM(a, b) is the smallest positive integer that is divisible by both a and b. For example, LCM(6, 8) = 24, LCM(4, 12) = 12, LCM(2, 3) = 6.

Of course, Fadi immediately knew the answer. Can you be just like Fadi and find any such pair?

Input

The first and only line contains an integer X (1 ≤ X ≤ 10^{12}).

Output

Print two positive integers, a and b, such that the value of max(a, b) is minimum possible and LCM(a, b) equals X. If there are several possible such pairs, you can print any.

Examples

Input


2


Output


1 2


Input


6


Output


2 3


Input


4


Output


1 4


Input


1


Output


1 1

Solution (in PYTHON3):

Solution:
from math import ceil, gcd
def fact(x):
    A = []
#    A.append(1)
    A.append(x)
    for i in range(2, ceil(x ** 0.5)):
        if x % i == 0:
#            A.append(i)
            A.append(x // i)
    A.sort()
    return A
def lcm(a, b):
    return a * b / gcd(a, b)
x = int(input())
A = fact(x)
for i in range(len(A)):
    a = A[i]
    b = x // a
    if lcm(a, b) == x:
        print(b, a)
        break