Problem: There is data on sales of your company. Your task is to write a program which identifies good workers.

The program should read a list of data where each item includes the employee ID i, the amount of sales q and the corresponding unit price p. Then, the program should print IDs of employees whose total sales proceeds (i.e. sum of p × q) is greater than or equal to 1,000,000 in the order of inputting. If there is no such employees, the program should print "NA". You can suppose that n < 4000, and each employee has an unique ID. The unit price p is less than or equal to 1,000,000 and the amount of sales q is less than or equal to 100,000.



Input

The input consists of several datasets. The input ends with a line including a single 0. Each dataset consists of:


n (the number of data in the list)
i p q
i p q
:
:
i p q


Output

For each dataset, print a list of employee IDs or a text "NA"

Example

Input

4
1001 2000 520
1002 1800 450
1003 1600 625
1001 200 1220
2
1001 100 3
1005 1000 100
2
2013 5000 100
2013 5000 100
0


Output

1001
1003
NA
2013

Solution (in JAVA):

Solution:
import java.util.LinkedHashMap;
import java.util.Map;
import java.util.Scanner;

public class Main
{
  public static void main(String[] args)
  {
    Scanner sc = new Scanner(System.in);

    while (sc.hasNextLine())
    {
      String[] input = sc.nextLine().split(" ");

      if (input.length == 1)
      {
        if (Integer.valueOf(input[0]) == 0)
        {
          break;
        }
      }

      final int dataset = Integer.valueOf(input[0]);

      Map<Long, Long> dataMap = new LinkedHashMap<>();
      for (int i = 0; i < dataset; i++)
      {
        String[] inputDataset = sc.nextLine().split(" ");
        final long empNum = Long.valueOf(inputDataset[0]);
        final long price = Long.valueOf(inputDataset[1]);
        final long count = Long.valueOf(inputDataset[2]);

        if (!dataMap.containsKey(empNum))
        {
          dataMap.put(empNum, price * count);
        }
        else
        {
          dataMap.put(empNum, dataMap.get(empNum) + (long) (price * count));
        }

      }
      Object[] keySet = dataMap.keySet().toArray();
      Object[] valueSet = dataMap.values().toArray();

      boolean zeroData = true;
      for (int j = 0; j < keySet.length; j++)
      {
        if ((long) valueSet[j] >= 1000000)
        {
          zeroData = false;
          System.out.println(keySet[j]);
        }
      }

      if (zeroData)
      {
        System.out.println("NA");
      }

    }

    sc.close();
  }
}