Problem: Today, Osama gave Fadi an integer X, and Fadi was wondering about the minimum possible value of max(a, b) such that LCM(a, b) equals X. Both a and b should be positive integers.

LCM(a, b) is the smallest positive integer that is divisible by both a and b. For example, LCM(6, 8) = 24, LCM(4, 12) = 12, LCM(2, 3) = 6.

Of course, Fadi immediately knew the answer. Can you be just like Fadi and find any such pair?

Input

The first and only line contains an integer X (1 ≤ X ≤ 10^{12}).

Output

Print two positive integers, a and b, such that the value of max(a, b) is minimum possible and LCM(a, b) equals X. If there are several possible such pairs, you can print any.

Examples

Input


2


Output


1 2


Input


6


Output


2 3


Input


4


Output


1 4


Input


1


Output


1 1

Solution (in PYTHON3):

Solution:
# -*- coding: utf-8 -*-
"""
Created on Thu Jun  4 13:03:38 2020

@author: Anmol Singla
"""
def gcd(x,y):
    while(y!=0):
        x,y=y,x%y
    return x    
    
from math import sqrt
x=int(input())
n=sqrt(x)
a=1
b=x
for i in range(1,int(n+1)):
    if(x%i==0):
        c=x//i
        if(gcd(c,i)==1):
            if(c%i):
                a=i
                b=c
print(int(a),int(b))