Problem: Today, Osama gave Fadi an integer X, and Fadi was wondering about the minimum possible value of max(a, b) such that LCM(a, b) equals X. Both a and b should be positive integers.

LCM(a, b) is the smallest positive integer that is divisible by both a and b. For example, LCM(6, 8) = 24, LCM(4, 12) = 12, LCM(2, 3) = 6.

Of course, Fadi immediately knew the answer. Can you be just like Fadi and find any such pair?

Input

The first and only line contains an integer X (1 ≤ X ≤ 10^{12}).

Output

Print two positive integers, a and b, such that the value of max(a, b) is minimum possible and LCM(a, b) equals X. If there are several possible such pairs, you can print any.

Examples

Input


2


Output


1 2


Input


6


Output


2 3


Input


4


Output


1 4


Input


1


Output


1 1

Solution (in PYTHON3):

Solution:
# maa chudaaye duniya
from sys import stdin, stdout
from math import gcd, sqrt
def lcm(a, b):
    return a // gcd(a, b) * b

x = int(stdin.readline().strip())
cntr = 1
ans = 0
while cntr <= sqrt(x) + 1:
    if x%cntr == 0 and lcm(cntr, x//cntr) == x:
        ans = cntr
    cntr += 1
stdout.write('{} {}\n'.format(ans, x//ans))