Problem: There is data on sales of your company. Your task is to write a program which identifies good workers.

The program should read a list of data where each item includes the employee ID i, the amount of sales q and the corresponding unit price p. Then, the program should print IDs of employees whose total sales proceeds (i.e. sum of p × q) is greater than or equal to 1,000,000 in the order of inputting. If there is no such employees, the program should print "NA". You can suppose that n < 4000, and each employee has an unique ID. The unit price p is less than or equal to 1,000,000 and the amount of sales q is less than or equal to 100,000.



Input

The input consists of several datasets. The input ends with a line including a single 0. Each dataset consists of:


n (the number of data in the list)
i p q
i p q
:
:
i p q


Output

For each dataset, print a list of employee IDs or a text "NA"

Example

Input

4
1001 2000 520
1002 1800 450
1003 1600 625
1001 200 1220
2
1001 100 3
1005 1000 100
2
2013 5000 100
2013 5000 100
0


Output

1001
1003
NA
2013

Solution (in CPP):

Solution:
#include<iostream>
#include<map>
#include<vector>
using namespace std;

typedef long long ll;

#define BORDER 1000000LL

int main() {
	map<int, ll> dat;
	vector<int> ord;
	int n, id, c; ll e, s;
	while(1) {
		cin >> n;
		if(!n) break;
		dat.clear(); ord.clear();
		for(int i=0; i<n; ++i) {
			cin >> id >> e >> s;
			if(!dat.count(id)) {
				ord.push_back(id);
				dat[id] = e*s;
			}else dat[id] += e*s;
		}
		c = 0;
		for(int i=0; i<(signed)ord.size(); ++i) {
			id = ord[i];
			if(dat[id]>=BORDER) {
				cout << ord[i] << endl;
				++c;
			}
		}
		if(!c) cout << "NA" << endl;
	}
	return 0;
}