Problem: There is data on sales of your company. Your task is to write a program which identifies good workers.

The program should read a list of data where each item includes the employee ID i, the amount of sales q and the corresponding unit price p. Then, the program should print IDs of employees whose total sales proceeds (i.e. sum of p × q) is greater than or equal to 1,000,000 in the order of inputting. If there is no such employees, the program should print "NA". You can suppose that n < 4000, and each employee has an unique ID. The unit price p is less than or equal to 1,000,000 and the amount of sales q is less than or equal to 100,000.



Input

The input consists of several datasets. The input ends with a line including a single 0. Each dataset consists of:


n (the number of data in the list)
i p q
i p q
:
:
i p q


Output

For each dataset, print a list of employee IDs or a text "NA"

Example

Input

4
1001 2000 520
1002 1800 450
1003 1600 625
1001 200 1220
2
1001 100 3
1005 1000 100
2
2013 5000 100
2013 5000 100
0


Output

1001
1003
NA
2013

Solution (in CPP):

Solution:
#include <cstdio>
#include <vector>
#include <algorithm>
#include <map>
using namespace std;
int main() {
	int n;
	while (scanf("%d",&n)&&n!=0) {
		map<int, long long> sales;
		vector<int> log;
		long long prc, mnt;
		int num;
		for (int i=0; i<n; i++) {
			scanf("%d%lld%lld",&num,&prc,&mnt);
			if (!sales[num]) {
				log.push_back(num);
			}
			sales[num] += prc * mnt;
		}
		bool flag = true;
		for (int i=0; i<log.size(); i++) {
			if (sales[log[i]]>=1000000) {
				flag = false;
				printf("%d\n", log[i]);
			}
		}
		if (flag) printf("NA\n");
	}
}