Problem: There is data on sales of your company. Your task is to write a program which identifies good workers.

The program should read a list of data where each item includes the employee ID i, the amount of sales q and the corresponding unit price p. Then, the program should print IDs of employees whose total sales proceeds (i.e. sum of p × q) is greater than or equal to 1,000,000 in the order of inputting. If there is no such employees, the program should print "NA". You can suppose that n < 4000, and each employee has an unique ID. The unit price p is less than or equal to 1,000,000 and the amount of sales q is less than or equal to 100,000.



Input

The input consists of several datasets. The input ends with a line including a single 0. Each dataset consists of:


n (the number of data in the list)
i p q
i p q
:
:
i p q


Output

For each dataset, print a list of employee IDs or a text "NA"

Example

Input

4
1001 2000 520
1002 1800 450
1003 1600 625
1001 200 1220
2
1001 100 3
1005 1000 100
2
2013 5000 100
2013 5000 100
0


Output

1001
1003
NA
2013

Solution (in CPP):

Solution:
#include<iostream>
using namespace std;

class meb{
public:
	int num;
	unsigned long long tanka;
	unsigned long long count;
	unsigned long long sum;
};

int main(){
	int n;
	while(1){
		int cc=0;
		cin>>n;
		meb st[n];
		if(n==0)break;
		for(int i=0;i<n;i++){
			cin>>st[i].num>>st[i].tanka>>st[i].count;
		}
		for(int k=0;k<n;k++){
			st[k].sum=st[k].tanka*st[k].count;
		}
		for(int j=0;j<n;j++){
			for(int l=j+1;l<n;l++){
				if(st[j].num==st[l].num){
					(st[j].sum)=(st[j].sum)+(st[l].sum);
					st[l].sum=0;
				}
			}
		}
		for(int a=0;a<n;a++){
			if(st[a].sum>=1000000)cout<<st[a].num<<endl;
			else cc++;
		}
		if(cc==n)cout<<"NA"<<endl;
	}
	return 0;
}