Problem: There is data on sales of your company. Your task is to write a program which identifies good workers.

The program should read a list of data where each item includes the employee ID i, the amount of sales q and the corresponding unit price p. Then, the program should print IDs of employees whose total sales proceeds (i.e. sum of p × q) is greater than or equal to 1,000,000 in the order of inputting. If there is no such employees, the program should print "NA". You can suppose that n < 4000, and each employee has an unique ID. The unit price p is less than or equal to 1,000,000 and the amount of sales q is less than or equal to 100,000.



Input

The input consists of several datasets. The input ends with a line including a single 0. Each dataset consists of:


n (the number of data in the list)
i p q
i p q
:
:
i p q


Output

For each dataset, print a list of employee IDs or a text "NA"

Example

Input

4
1001 2000 520
1002 1800 450
1003 1600 625
1001 200 1220
2
1001 100 3
1005 1000 100
2
2013 5000 100
2013 5000 100
0


Output

1001
1003
NA
2013

Solution (in JAVA):

Solution:
import java.util.*;
import java.math.*;

public class Main{
	public static void main(String[] args){
		Scanner sc = new Scanner(System.in);
		BigInteger million = new BigInteger("1000000");

		while(true){
			int n = sc.nextInt();
			if(n == 0) break;

			String[] no = new String[n];
			BigInteger[] sum = new BigInteger[n];
			int size = 0;

			for(int i=0;i<n;i++){
				String s = sc.next();
				BigInteger mul = sc.nextBigInteger().multiply(sc.nextBigInteger());
				int j;

				for(j=0;j<size;j++){
					if(no[j].equals(s)){
						sum[j] = sum[j].add(mul);
						break;
					}
				}

				if(j == size){
					no[size] = s;
					sum[size] = mul;
					size++;
				}
			}

			boolean naflg = true;
			for(int i=0;i<size;i++){
				if(sum[i].compareTo(million) >= 0){
					System.out.println(no[i]);
					naflg = false;
				}
			}

			if(naflg) System.out.println("NA");
		}
	}
}