Problem: Today, Osama gave Fadi an integer X, and Fadi was wondering about the minimum possible value of max(a, b) such that LCM(a, b) equals X. Both a and b should be positive integers.

LCM(a, b) is the smallest positive integer that is divisible by both a and b. For example, LCM(6, 8) = 24, LCM(4, 12) = 12, LCM(2, 3) = 6.

Of course, Fadi immediately knew the answer. Can you be just like Fadi and find any such pair?

Input

The first and only line contains an integer X (1 ≤ X ≤ 10^{12}).

Output

Print two positive integers, a and b, such that the value of max(a, b) is minimum possible and LCM(a, b) equals X. If there are several possible such pairs, you can print any.

Examples

Input


2


Output


1 2


Input


6


Output


2 3


Input


4


Output


1 4


Input


1


Output


1 1

Solution (in PYTHON3):

Solution:
N = int(input())
M = N
A = []
flag = True
while flag == True:
    flag = False
    for i in range(2,int(N**0.5)+1):
        if N%i == 0:
            hoge = i
            while N%hoge == 0:
                hoge *= i
            A.append(hoge//i)
            N //= (hoge//i)
            flag = True
            break
A.append(N)
ans = M
for i in range(2**len(A)):
    hoge = 1
    for j in range(len(A)):
        if i & 1 == 1:
            hoge *= A[j]
        i >>= 1
    ans = min(ans,max(M//hoge,hoge))
print(ans,M//ans)