Problem: There is data on sales of your company. Your task is to write a program which identifies good workers.

The program should read a list of data where each item includes the employee ID i, the amount of sales q and the corresponding unit price p. Then, the program should print IDs of employees whose total sales proceeds (i.e. sum of p × q) is greater than or equal to 1,000,000 in the order of inputting. If there is no such employees, the program should print "NA". You can suppose that n < 4000, and each employee has an unique ID. The unit price p is less than or equal to 1,000,000 and the amount of sales q is less than or equal to 100,000.



Input

The input consists of several datasets. The input ends with a line including a single 0. Each dataset consists of:


n (the number of data in the list)
i p q
i p q
:
:
i p q


Output

For each dataset, print a list of employee IDs or a text "NA"

Example

Input

4
1001 2000 520
1002 1800 450
1003 1600 625
1001 200 1220
2
1001 100 3
1005 1000 100
2
2013 5000 100
2013 5000 100
0


Output

1001
1003
NA
2013

Solution (in CPP):

Solution:
#include <algorithm>
#include <iostream>
#include <list>
#include <map>
#include <math.h>
#include <stack>
#include <stdio.h>
#include <string>
#include <queue>
#include <vector>
using namespace std;

int main()
{
	queue<int> E;
	map<int, int> R;
	int n, e, p, q;
	while (cin >> n) {
		if (n == 0) break;
		R.clear();
		for (int i = 0; i < n; i++) {
			cin >> e >> p >> q;

			if (R[e] > 0) {
				R[e] += p * q;
			}
			else {
				R[e] = p * q;
				E.push(e);
			}
		}

		bool f = true;
		while (E.size() != 0) {
			int ep = E.front(); E.pop();
			if (R[ep] >= 1000000) {
				cout << ep << endl;
				f = false;
			}
		}

		if (f) cout << "NA" << endl;
	}
}