Problem: There is data on sales of your company. Your task is to write a program which identifies good workers.

The program should read a list of data where each item includes the employee ID i, the amount of sales q and the corresponding unit price p. Then, the program should print IDs of employees whose total sales proceeds (i.e. sum of p × q) is greater than or equal to 1,000,000 in the order of inputting. If there is no such employees, the program should print "NA". You can suppose that n < 4000, and each employee has an unique ID. The unit price p is less than or equal to 1,000,000 and the amount of sales q is less than or equal to 100,000.



Input

The input consists of several datasets. The input ends with a line including a single 0. Each dataset consists of:


n (the number of data in the list)
i p q
i p q
:
:
i p q


Output

For each dataset, print a list of employee IDs or a text "NA"

Example

Input

4
1001 2000 520
1002 1800 450
1003 1600 625
1001 200 1220
2
1001 100 3
1005 1000 100
2
2013 5000 100
2013 5000 100
0


Output

1001
1003
NA
2013

Solution (in CPP):

Solution:
#include<cstdio>
#include<map>
#include<vector>
std::vector<std::pair<int, long long>> pq;
int main() {
	int n, i, e;
	long long p, q;
	bool match;
	while (true) {
		scanf("%d", &n);
		if (n == 0)break;
		for (i = 0; i < n; i++) {
			scanf("%d%lld%lld", &e, &p, &q);
			match = false;
			for (auto itr = pq.begin(); itr != pq.end(); itr++) {
				if (itr->first == e) {
					itr->second += p*q;
					match = true;
					break;
				}
			}
			if (!match)pq.push_back(std::make_pair(e, p*q));
		}
		match = false;
		for (auto itr = pq.begin(); itr != pq.end(); itr++) {
			if (itr->second >= 1000000) {
				printf("%d\n", itr->first);
				match = true;
			}
		}
		if (!match)printf("NA\n");
		pq.clear();
	}
	return 0;
}