Problem: You are given the array a consisting of n elements and the integer k ≤ n.

You want to obtain at least k equal elements in the array a. In one move, you can make one of the following two operations:

  * Take one of the minimum elements of the array and increase its value by one (more formally, if the minimum value of a is mn then you choose such index i that a_i = mn and set a_i := a_i + 1); 
  * take one of the maximum elements of the array and decrease its value by one (more formally, if the maximum value of a is mx then you choose such index i that a_i = mx and set a_i := a_i - 1). 



Your task is to calculate the minimum number of moves required to obtain at least k equal elements in the array.

Input

The first line of the input contains two integers n and k (1 ≤ k ≤ n ≤ 2 ⋅ 10^5) — the number of elements in a and the required number of equal elements.

The second line of the input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9), where a_i is the i-th element of a.

Output

Print one integer — the minimum number of moves required to obtain at least k equal elements in the array.

Examples

Input


6 5
1 2 2 4 2 3


Output


3


Input


7 5
3 3 2 1 1 1 3


Output


4

Solution (in PYTHON3):

Solution:
MOD = 10**9 + 7
I = lambda:list(map(int,input().split()))
 
n, m = I()
l = I()
l.sort()
ans = MOD
o = [0]*300000
d = [0]*300000
for i in range(n):
	k = l[i]
	o[k] += 1
	if o[k] == m:
			ans = min(ans, d[k])
	i = 0
	while k > 0:
		i += 1
		k //= 2
		o[k] += 1
		d[k] += i
		if o[k] == m:
			ans = min(ans, d[k])
 
print(ans)
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