Problem: Today, Osama gave Fadi an integer X, and Fadi was wondering about the minimum possible value of max(a, b) such that LCM(a, b) equals X. Both a and b should be positive integers.

LCM(a, b) is the smallest positive integer that is divisible by both a and b. For example, LCM(6, 8) = 24, LCM(4, 12) = 12, LCM(2, 3) = 6.

Of course, Fadi immediately knew the answer. Can you be just like Fadi and find any such pair?

Input

The first and only line contains an integer X (1 ≤ X ≤ 10^{12}).

Output

Print two positive integers, a and b, such that the value of max(a, b) is minimum possible and LCM(a, b) equals X. If there are several possible such pairs, you can print any.

Examples

Input


2


Output


1 2


Input


6


Output


2 3


Input


4


Output


1 4


Input


1


Output


1 1

Solution (in PYTHON3):

Solution:
import math
x = int(input())
mina = 10**13
a = -1
b = -1

def gcd(a,b):
    if(a == 0):
        return b
    else:
        return gcd(b%a,a)


for i in range(1,int(math.sqrt(x))+2):
    if(x%i == 0):
        if(gcd(i,x//i) == 1):
            if(max(i,x//i) < mina):
                mina = max(i,x//i)
                a = i
                b = x//i

print(a,end=' ')
print(b)