Problem: There is data on sales of your company. Your task is to write a program which identifies good workers.

The program should read a list of data where each item includes the employee ID i, the amount of sales q and the corresponding unit price p. Then, the program should print IDs of employees whose total sales proceeds (i.e. sum of p × q) is greater than or equal to 1,000,000 in the order of inputting. If there is no such employees, the program should print "NA". You can suppose that n < 4000, and each employee has an unique ID. The unit price p is less than or equal to 1,000,000 and the amount of sales q is less than or equal to 100,000.



Input

The input consists of several datasets. The input ends with a line including a single 0. Each dataset consists of:


n (the number of data in the list)
i p q
i p q
:
:
i p q


Output

For each dataset, print a list of employee IDs or a text "NA"

Example

Input

4
1001 2000 520
1002 1800 450
1003 1600 625
1001 200 1220
2
1001 100 3
1005 1000 100
2
2013 5000 100
2013 5000 100
0


Output

1001
1003
NA
2013

Solution (in CPP):

Solution:
#include <iostream>
#include <vector>
#include <map>
#include <algorithm>
using namespace std;

int main( void )
{
	int n;
	while ( cin >> n && n != 0 )
	{
		vector <int> visited;
		map <int, long long> profit;
		bool exist = false;
		for ( int i = 0; i < min(n, 4000); i++ )
		{
			int no, p, q;
			cin >> no >> p >> q;

			profit[no] += (long long)p * q;

			if ( find( visited.begin(), visited.end(), no ) == visited.end() && profit[no] >= 1000000L )
			{
				exist = true;
				visited.push_back( no );
			}
		}

		if ( exist )
		{
			for ( vector <int>::iterator it = visited.begin(); it != visited.end(); it++ )
			{
				cout << *it << endl;
			}
		}
		else
			cout << "NA" << endl;
	}

	return 0;
}