Problem: You are given the array a consisting of n elements and the integer k ≤ n.

You want to obtain at least k equal elements in the array a. In one move, you can make one of the following two operations:

  * Take one of the minimum elements of the array and increase its value by one (more formally, if the minimum value of a is mn then you choose such index i that a_i = mn and set a_i := a_i + 1); 
  * take one of the maximum elements of the array and decrease its value by one (more formally, if the maximum value of a is mx then you choose such index i that a_i = mx and set a_i := a_i - 1). 



Your task is to calculate the minimum number of moves required to obtain at least k equal elements in the array.

Input

The first line of the input contains two integers n and k (1 ≤ k ≤ n ≤ 2 ⋅ 10^5) — the number of elements in a and the required number of equal elements.

The second line of the input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9), where a_i is the i-th element of a.

Output

Print one integer — the minimum number of moves required to obtain at least k equal elements in the array.

Examples

Input


6 5
1 2 2 4 2 3


Output


3


Input


7 5
3 3 2 1 1 1 3


Output


4

Solution (in JAVA):

Solution:

import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.util.ArrayList;
import java.util.Collections;
import java.util.Scanner;

public class badDay {

	public static void main(String[] args) {
		// TODO Auto-generated method stub
		Scanner s = new Scanner(new BufferedReader(new InputStreamReader(System.in)));
		int n = s.nextInt();
		int k = s.nextInt();
		int[] arr = new int[n];
		int max = Integer.MIN_VALUE;
		for (int i = 0; i < n; i++) {
			arr[i] = s.nextInt();
			if (arr[i] > max) {
				max = arr[i];
			}
		}
		int ans = Integer.MAX_VALUE;
		ArrayList<Integer>[] listarr = new ArrayList[200006];
		for(int i = 0; i < 200006; i++) {
			listarr[i]= new ArrayList<>();
		}
		for(int i = 0; i < n; i++) {
			int x = arr[i];
			int div = 0;
			while(x>0) {
				listarr[x].add(div);
				div++;
				x>>=1;
			}
		}
		for(int i = 0; i < 200006; i++) {
			if(listarr[i].size()<k) {
				continue;
			}
			ArrayList<Integer> curr = listarr[i];
			Collections.sort(curr);
			int temp = 0;
			for(int j = 0; j < k; j++) {
				temp+=curr.get(j);
			}
			ans = Math.min(ans, temp);
		}
		System.out.println(ans);
	}
}