Problem: Today, Osama gave Fadi an integer X, and Fadi was wondering about the minimum possible value of max(a, b) such that LCM(a, b) equals X. Both a and b should be positive integers.

LCM(a, b) is the smallest positive integer that is divisible by both a and b. For example, LCM(6, 8) = 24, LCM(4, 12) = 12, LCM(2, 3) = 6.

Of course, Fadi immediately knew the answer. Can you be just like Fadi and find any such pair?

Input

The first and only line contains an integer X (1 ≤ X ≤ 10^{12}).

Output

Print two positive integers, a and b, such that the value of max(a, b) is minimum possible and LCM(a, b) equals X. If there are several possible such pairs, you can print any.

Examples

Input


2


Output


1 2


Input


6


Output


2 3


Input


4


Output


1 4


Input


1


Output


1 1

Solution (in JAVA):

Solution:
import java.util.Scanner;

public class Main {

    static long gcd(long a,long b){
        return b == 0 ? a : gcd(b,a % b);
    }

    static long lcm(long a,long b){
        return a / gcd(a,b) * b;
    }

    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        long n = scanner.nextLong();
        for (int i = (int) Math.round(Math.sqrt(n)); i >= 1; i--) {
            if ((n % i == 0) && lcm(i, n/i) == n) {
                System.out.println(i+" "+n/i);
                break;
            }
        }
    }
}