Problem: Today, Osama gave Fadi an integer X, and Fadi was wondering about the minimum possible value of max(a, b) such that LCM(a, b) equals X. Both a and b should be positive integers.

LCM(a, b) is the smallest positive integer that is divisible by both a and b. For example, LCM(6, 8) = 24, LCM(4, 12) = 12, LCM(2, 3) = 6.

Of course, Fadi immediately knew the answer. Can you be just like Fadi and find any such pair?

Input

The first and only line contains an integer X (1 ≤ X ≤ 10^{12}).

Output

Print two positive integers, a and b, such that the value of max(a, b) is minimum possible and LCM(a, b) equals X. If there are several possible such pairs, you can print any.

Examples

Input


2


Output


1 2


Input


6


Output


2 3


Input


4


Output


1 4


Input


1


Output


1 1

Solution (in PYTHON3):

Solution:
from collections import defaultdict,Counter
from math import ceil,floor,log2,gcd
from itertools import permutations,combinations
from functools import reduce
#n,k = map(int,input().split())
#a = sorted(list(map(int,input().split())))
#a = list(map(int,input().split())) 
n = int(input())
def lcm(a, b):
    return abs(a*b) // gcd(a, b)
best = n+1
for x in range(1,int(n**0.5)+1):
    if n%x:
        continue
    elif lcm(x,n//x) == n:
        best = min(best,max(x,n//x))
print (best,n//best)