Problem: A mad scientist Dr.Jubal has made a competitive programming task. Try to solve it!

You are given integers n,k. Construct a grid A with size n × n consisting of integers 0 and 1. The very important condition should be satisfied: the sum of all elements in the grid is exactly k. In other words, the number of 1 in the grid is equal to k.

Let's define:

  * A_{i,j} as the integer in the i-th row and the j-th column. 
  * R_i = A_{i,1}+A_{i,2}+...+A_{i,n} (for all 1 ≤ i ≤ n). 
  * C_j = A_{1,j}+A_{2,j}+...+A_{n,j} (for all 1 ≤ j ≤ n). 
  * In other words, R_i are row sums and C_j are column sums of the grid A. 
  * For the grid A let's define the value f(A) = (max(R)-min(R))^2 + (max(C)-min(C))^2 (here for an integer sequence X we define max(X) as the maximum value in X and min(X) as the minimum value in X). 



Find any grid A, which satisfies the following condition. Among such grids find any, for which the value f(A) is the minimum possible. Among such tables, you can find any.

Input

The input consists of multiple test cases. The first line contains a single integer t (1 ≤ t ≤ 100) — the number of test cases. Next t lines contain descriptions of test cases.

For each test case the only line contains two integers n, k (1 ≤ n ≤ 300, 0 ≤ k ≤ n^2).

It is guaranteed that the sum of n^2 for all test cases does not exceed 10^5.

Output

For each test case, firstly print the minimum possible value of f(A) among all tables, for which the condition is satisfied.

After that, print n lines contain n characters each. The j-th character in the i-th line should be equal to A_{i,j}.

If there are multiple answers you can print any.

Example

Input


4
2 2
3 8
1 0
4 16


Output


0
10
01
2
111
111
101
0
0
0
1111
1111
1111
1111

Note

In the first test case, the sum of all elements in the grid is equal to 2, so the condition is satisfied. R_1 = 1, R_2 = 1 and C_1 = 1, C_2 = 1. Then, f(A) = (1-1)^2 + (1-1)^2 = 0, which is the minimum possible value of f(A).

In the second test case, the sum of all elements in the grid is equal to 8, so the condition is satisfied. R_1 = 3, R_2 = 3, R_3 = 2 and C_1 = 3, C_2 = 2, C_3 = 3. Then, f(A) = (3-2)^2 + (3-2)^2 = 2. It can be proven, that it is the minimum possible value of f(A).

Solution (in JAVA):

Solution:

    import java.util.*;
    import java.lang.*;
    import java.io.*;   
    import java.math.*;
    public class Prac{     
        static class InputReader { 
            private final InputStream stream;
            private final byte[] buf = new byte[8192];
            private int curChar, snumChars;
            public InputReader(InputStream st) {
                this.stream = st;
            } 
            public int read() {
                if (snumChars == -1)
                    throw new InputMismatchException();
                if (curChar >= snumChars) {
                    curChar = 0;
                    try {
                        snumChars = stream.read(buf);
                    } 
                    catch (IOException e) {
                        throw new InputMismatchException();
                    }
                    if (snumChars <= 0)
                        return -1;
                }
                return buf[curChar++];
            }
            public int ni() {
                int c = read();
                while (isSpaceChar(c)) {
                    c = read();
                }
                int sgn = 1;
                if (c == '-') {
                    sgn = -1;
                    c = read();
                }
                int res = 0;
                do {
                    res *= 10;
                    res += c - '0';
                    c = read();
                } while (!isSpaceChar(c));
                return res * sgn;
            } 
            public long nl() {
                int c = read();
                while (isSpaceChar(c)) {
                c = read();
                }
                int sgn = 1;
                if (c == '-') {
                    sgn = -1;
                    c = read();
                }
                long res = 0;
                do {
                    res *= 10;
                    res += c - '0';
                    c = read();
                } while (!isSpaceChar(c));
                return res * sgn;
            } 
            public int[] nia(int n) {
                int a[] = new int[n];
                for (int i = 0; i < n; i++) {
                    a[i] = ni();
                }
                return a;
            } 
            public int[] nia1(int n) {
                int a[] = new int[n+1];
                for (int i = 1; i <=n; i++) {
                    a[i] = ni();
                }
                return a;
            } 
            public long[] nla(int n) {
                long a[] = new long[n];
                for (int i = 0; i < n; i++) {
                    a[i] = nl();
                }
                return a;
            } 
            public long[] nla1(int n) {
                long a[] = new long[n+1];
                for (int i = 1; i <= n; i++) {
                    a[i] = nl();
                }
                return a;
            } 
            public Long[] nLa(int n) {
                Long a[] = new Long[n];
                for (int i = 0; i < n; i++) {
                    a[i] = nl();
                }
                return a;
            } 
            public Long[] nLa1(int n) {
                Long a[] = new Long[n+1];
                for (int i = 1; i <= n; i++) {
                    a[i] = nl();
                }
                return a;
            } 
            public Integer[] nIa(int n) {
                Integer a[] = new Integer[n];
                for (int i = 0; i < n; i++) {
                    a[i] = ni();
                }
                return a;
            } 
            public Integer[] nIa1(int n) {
                Integer a[] = new Integer[n+1];
                for (int i = 1; i <= n; i++) {
                    a[i] = ni();
                }
                return a;
            } 
            public String rs() {
                int c = read();
                while (isSpaceChar(c)) {
                    c = read();
                }
                StringBuilder res = new StringBuilder();
                do {
                    res.appendCodePoint(c);
                        c = read();
                } while (!isSpaceChar(c));
                return res.toString();
            }
            public String nextLine() {
                int c = read();
                while (isSpaceChar(c))
                    c = read();
                StringBuilder res = new StringBuilder();
                do {
                    res.appendCodePoint(c);
                    c = read();
                } while (!isEndOfLine(c));
                return res.toString();
            } 
            public boolean isSpaceChar(int c) {
                return c == ' ' || c == '\n' || c == '\r' || c == '\t' || c == -1;
            }

            private boolean isEndOfLine(int c) {
                return c == '\n' || c == '\r' || c == -1;
            } 
        }
        public static class Key {
            private final int x, y;
            public Key(int x, int y) {
                this.x = x; this.y = y;
            }
            @Override
            public boolean equals(Object o) {
                if (this == o) return true;
                if (!(o instanceof Key)) return false;
                Key key = (Key) o;
                return x == key.x && y == key.y;
            }
            @Override
            public int hashCode() {
                int result = x;
                result = 31 * result + y;
                return result;
            }
        }
        static class Pair implements Comparable<Pair>{
                int x,y;
                Pair(int a,int b){
                        x=a;y=b;
                }
                @Override
                public int compareTo(Pair p) {
                        if(x==p.x) return y-p.y;
                        return x-p.x;
                }
        }
        static PrintWriter w = new PrintWriter(System.out);
        static long mod1=998244353L,mod=1000000007;
        //static int r[]={0,1,0,-1}, c[]={1,0,-1,0};
        
        public static void main(String [] args){
            InputReader sc=new InputReader(System.in); 
            int t=sc.ni();
            while(t-->0){
                int n=sc.ni();
                int k=sc.ni();
                int ans[][]=new int[n][n];
                for(int i=0;i<n&&k>0;i++){
                    for(int j=0;j<n&&k>0;j++){
                        int r=j;
                        int c=(j+i)%n;
                        ans[r][c]=1;
                        k--;
                    }
                }
                int minR=500,maxR=0,minC=500,maxC=0;
                for(int i=0;i<n;i++){
                    int c=0,r=0;
                    for(int j=0;j<n;j++){
                        r+=ans[i][j];
                        c+=ans[j][i];
                        
                    }
                    maxR=Math.max(r,maxR);
                    maxC=Math.max(c, maxC);
                    minR=Math.min(r,minR);
                    minC=Math.min(c,minC);
                }
                maxR-=minR;
                maxC-=minC;
                w.println(maxR*maxR+maxC*maxC);
                for(int i=0;i<n;i++){
                    for(int j=0;j<n;j++){
                        w.print(ans[i][j]);
                    }
                    w.println();
                }
            }
            
            w.close();
        }
    }