Problem: Today, Osama gave Fadi an integer X, and Fadi was wondering about the minimum possible value of max(a, b) such that LCM(a, b) equals X. Both a and b should be positive integers.

LCM(a, b) is the smallest positive integer that is divisible by both a and b. For example, LCM(6, 8) = 24, LCM(4, 12) = 12, LCM(2, 3) = 6.

Of course, Fadi immediately knew the answer. Can you be just like Fadi and find any such pair?

Input

The first and only line contains an integer X (1 ≤ X ≤ 10^{12}).

Output

Print two positive integers, a and b, such that the value of max(a, b) is minimum possible and LCM(a, b) equals X. If there are several possible such pairs, you can print any.

Examples

Input


2


Output


1 2


Input


6


Output


2 3


Input


4


Output


1 4


Input


1


Output


1 1

Solution (in PYTHON3):

Solution:
import sys
import math
from collections import defaultdict,deque

input = sys.stdin.readline
def inar():
    return [int(el) for el in input().split()]
def main():
    x=int(input())
    ans=10**12
    pair=[0,0]
    for i in range(1,int(x**0.5)+1):
        if x % i==0:
            l=i*(x//i)/math.gcd(i,x//i)
            if l==x:
                if ans>max(i,x//i):
                    ans=max(i,x//i)
                    pair[0]=i
                    pair[1]=x//i
    print(*pair)


if __name__ == '__main__':
    main()