Problem: There is data on sales of your company. Your task is to write a program which identifies good workers.

The program should read a list of data where each item includes the employee ID i, the amount of sales q and the corresponding unit price p. Then, the program should print IDs of employees whose total sales proceeds (i.e. sum of p × q) is greater than or equal to 1,000,000 in the order of inputting. If there is no such employees, the program should print "NA". You can suppose that n < 4000, and each employee has an unique ID. The unit price p is less than or equal to 1,000,000 and the amount of sales q is less than or equal to 100,000.



Input

The input consists of several datasets. The input ends with a line including a single 0. Each dataset consists of:


n (the number of data in the list)
i p q
i p q
:
:
i p q


Output

For each dataset, print a list of employee IDs or a text "NA"

Example

Input

4
1001 2000 520
1002 1800 450
1003 1600 625
1001 200 1220
2
1001 100 3
1005 1000 100
2
2013 5000 100
2013 5000 100
0


Output

1001
1003
NA
2013

Solution (in CPP):

Solution:
#include<iostream>
#include<vector>
#include<algorithm>
using namespace std;
typedef long long ll;
ll sums[4000];
bool used[4000];
int main()
{
	int n;
	while(cin>>n,n) 
	{
		vector<int> order;
		bool f=false;
		int num;
		int a,b;
		fill(sums,sums+4000,0);
		fill(used,used+4000,0);
		for(int i = 0; i < n; ++i)
		{
			cin>>num>>a>>b;
			sums[num-1]+=(ll)a*b;
			order.push_back(num-1);
		}
		for(int i = 0; i < order.size(); ++i)
		{
			if(!used[order[i]]&&sums[order[i]]>=1000000)
			{
				cout<<order[i]+1<<endl;
				f=true;
				used[order[i]]=true;
			}
		}
		if(!f) cout<<"NA"<<endl;
	}
  return 0;
}