Problem: Today, Osama gave Fadi an integer X, and Fadi was wondering about the minimum possible value of max(a, b) such that LCM(a, b) equals X. Both a and b should be positive integers.

LCM(a, b) is the smallest positive integer that is divisible by both a and b. For example, LCM(6, 8) = 24, LCM(4, 12) = 12, LCM(2, 3) = 6.

Of course, Fadi immediately knew the answer. Can you be just like Fadi and find any such pair?

Input

The first and only line contains an integer X (1 ≤ X ≤ 10^{12}).

Output

Print two positive integers, a and b, such that the value of max(a, b) is minimum possible and LCM(a, b) equals X. If there are several possible such pairs, you can print any.

Examples

Input


2


Output


1 2


Input


6


Output


2 3


Input


4


Output


1 4


Input


1


Output


1 1

Solution (in PYTHON3):

Solution:
import math
def compute_gcd(x, y):
   while(y):
       x, y = y, x % y
   return x

def compute_lcm(x, y):
   lcm = (x*y)//compute_gcd(x,y)
   return lcm

el = int(input())
square_root = math.ceil(math.sqrt(el))
a = 1
b = el
for i in range(1, square_root + 1):
    if el%i == 0:
        if compute_lcm(i, int(el/i)) == el:
            a = i
            b = int(el/i)
print(a, b)