Problem: Today, Osama gave Fadi an integer X, and Fadi was wondering about the minimum possible value of max(a, b) such that LCM(a, b) equals X. Both a and b should be positive integers.

LCM(a, b) is the smallest positive integer that is divisible by both a and b. For example, LCM(6, 8) = 24, LCM(4, 12) = 12, LCM(2, 3) = 6.

Of course, Fadi immediately knew the answer. Can you be just like Fadi and find any such pair?

Input

The first and only line contains an integer X (1 ≤ X ≤ 10^{12}).

Output

Print two positive integers, a and b, such that the value of max(a, b) is minimum possible and LCM(a, b) equals X. If there are several possible such pairs, you can print any.

Examples

Input


2


Output


1 2


Input


6


Output


2 3


Input


4


Output


1 4


Input


1


Output


1 1

Solution (in PYTHON3):

Solution:
import math


def fadi_and_lcm(x):
    minn = [1, x]
    for i in range(2, math.ceil(math.sqrt(x))):
        if x % i == 0:
            if lcm(i, x//i) == x:
                if max(i, x//i) < max(minn[0], minn[1]):
                    minn = [i, x//i]

    return str(minn[0]) + " " + str(minn[1])


def gcd(num1, num2):
    if num1 == 0:
        return num2
    return gcd(num2 % num1, num1)


def lcm(a, b):
    return (a*b)//gcd(a, b)


def main():
    num = input()
    print(fadi_and_lcm(int(num)))


main()