Problem: There is data on sales of your company. Your task is to write a program which identifies good workers.

The program should read a list of data where each item includes the employee ID i, the amount of sales q and the corresponding unit price p. Then, the program should print IDs of employees whose total sales proceeds (i.e. sum of p × q) is greater than or equal to 1,000,000 in the order of inputting. If there is no such employees, the program should print "NA". You can suppose that n < 4000, and each employee has an unique ID. The unit price p is less than or equal to 1,000,000 and the amount of sales q is less than or equal to 100,000.



Input

The input consists of several datasets. The input ends with a line including a single 0. Each dataset consists of:


n (the number of data in the list)
i p q
i p q
:
:
i p q


Output

For each dataset, print a list of employee IDs or a text "NA"

Example

Input

4
1001 2000 520
1002 1800 450
1003 1600 625
1001 200 1220
2
1001 100 3
1005 1000 100
2
2013 5000 100
2013 5000 100
0


Output

1001
1003
NA
2013

Solution (in CPP):

Solution:
#include<iostream>
#include<queue>

using namespace std;

int main()
{
	
	while(1)
	{
		int sum = 0;
		int n;
		cin >> n;
		if(n == 0) break;
		
		queue<int> q;
		bool checked[4000];
		long long list[4000];
		for(int i = 0;i < 4000;i++)
		{
			checked[i] = false;
			list[i] = 0;
		}
		for(int i = 0;i < n;i++)
		{
			long long no, x, y;
			cin >> no >> x >> y;
			list[no - 1] += x * y;
			if(!checked[no - 1])
			{
				q.push(no);
				checked[no - 1] = true;
			}
		}
		
		while(!q.empty())
		{
			int no = q.front();
			q.pop();
			if(list[no - 1] >= 1000000)
			{
				cout << no << endl;
				sum++;
			}
		}
		if(sum == 0) cout << "NA" << endl;
	}
	return 0;
}