Problem: Today, Osama gave Fadi an integer X, and Fadi was wondering about the minimum possible value of max(a, b) such that LCM(a, b) equals X. Both a and b should be positive integers.

LCM(a, b) is the smallest positive integer that is divisible by both a and b. For example, LCM(6, 8) = 24, LCM(4, 12) = 12, LCM(2, 3) = 6.

Of course, Fadi immediately knew the answer. Can you be just like Fadi and find any such pair?

Input

The first and only line contains an integer X (1 ≤ X ≤ 10^{12}).

Output

Print two positive integers, a and b, such that the value of max(a, b) is minimum possible and LCM(a, b) equals X. If there are several possible such pairs, you can print any.

Examples

Input


2


Output


1 2


Input


6


Output


2 3


Input


4


Output


1 4


Input


1


Output


1 1

Solution (in PYTHON3):

Solution:
import math
def gcd(a,b):
    if b==0:
        return a 
    return gcd(b,a%b)

def lcm(a,b):
    return (a*b)//gcd(a,b)

def div(k):
    m=100000000000000
    for i in range(1,math.floor(math.sqrt(k))+1):
        if k%i==0 and lcm(i,k//i)==k:
            m=min(max(k//i,i),m)
    return m
            

n=int(input())
a=div(n)
print(a,n//a)