Problem: Arpa is taking a geometry exam. Here is the last problem of the exam.

You are given three points a, b, c.

Find a point and an angle such that if we rotate the page around the point by the angle, the new position of a is the same as the old position of b, and the new position of b is the same as the old position of c.

Arpa is doubting if the problem has a solution or not (i.e. if there exists a point and an angle satisfying the condition). Help Arpa determine if the question has a solution or not.

Input

The only line contains six integers ax, ay, bx, by, cx, cy (|ax|, |ay|, |bx|, |by|, |cx|, |cy| ≤ 109). It's guaranteed that the points are distinct.

Output

Print "Yes" if the problem has a solution, "No" otherwise.

You can print each letter in any case (upper or lower).

Examples

Input

0 1 1 1 1 0


Output

Yes


Input

1 1 0 0 1000 1000


Output

No

Note

In the first sample test, rotate the page around (0.5, 0.5) by <image>.

In the second sample test, you can't find any solution.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
inline int read(register int ans = 0, register int sgn = ' ',
                register int ch = getchar()) {
  for (; ch < '0' || ch > '9'; sgn = ch, ch = getchar())
    ;
  for (; ch >= '0' && ch <= '9'; (ans *= 10) += ch - '0', ch = getchar())
    ;
  return sgn - '-' ? ans : -ans;
}
int ax, ay, bx, by, cx, cy;
int main() {
  ax = read(), ay = read(), bx = read(), by = read(), cx = read(), cy = read();
  if (1ll * (ax - bx) * (ax - bx) + 1ll * (ay - by) * (ay - by) !=
      1ll * (bx - cx) * (bx - cx) + 1ll * (by - cy) * (by - cy))
    puts("No");
  else if (ax - bx == bx - cx && ay - by == by - cy)
    puts("No");
  else
    puts("Yes");
  return 0;
}