Problem: A mad scientist Dr.Jubal has made a competitive programming task. Try to solve it!

You are given integers n,k. Construct a grid A with size n × n consisting of integers 0 and 1. The very important condition should be satisfied: the sum of all elements in the grid is exactly k. In other words, the number of 1 in the grid is equal to k.

Let's define:

  * A_{i,j} as the integer in the i-th row and the j-th column. 
  * R_i = A_{i,1}+A_{i,2}+...+A_{i,n} (for all 1 ≤ i ≤ n). 
  * C_j = A_{1,j}+A_{2,j}+...+A_{n,j} (for all 1 ≤ j ≤ n). 
  * In other words, R_i are row sums and C_j are column sums of the grid A. 
  * For the grid A let's define the value f(A) = (max(R)-min(R))^2 + (max(C)-min(C))^2 (here for an integer sequence X we define max(X) as the maximum value in X and min(X) as the minimum value in X). 



Find any grid A, which satisfies the following condition. Among such grids find any, for which the value f(A) is the minimum possible. Among such tables, you can find any.

Input

The input consists of multiple test cases. The first line contains a single integer t (1 ≤ t ≤ 100) — the number of test cases. Next t lines contain descriptions of test cases.

For each test case the only line contains two integers n, k (1 ≤ n ≤ 300, 0 ≤ k ≤ n^2).

It is guaranteed that the sum of n^2 for all test cases does not exceed 10^5.

Output

For each test case, firstly print the minimum possible value of f(A) among all tables, for which the condition is satisfied.

After that, print n lines contain n characters each. The j-th character in the i-th line should be equal to A_{i,j}.

If there are multiple answers you can print any.

Example

Input


4
2 2
3 8
1 0
4 16


Output


0
10
01
2
111
111
101
0
0
0
1111
1111
1111
1111

Note

In the first test case, the sum of all elements in the grid is equal to 2, so the condition is satisfied. R_1 = 1, R_2 = 1 and C_1 = 1, C_2 = 1. Then, f(A) = (1-1)^2 + (1-1)^2 = 0, which is the minimum possible value of f(A).

In the second test case, the sum of all elements in the grid is equal to 8, so the condition is satisfied. R_1 = 3, R_2 = 3, R_3 = 2 and C_1 = 3, C_2 = 2, C_3 = 3. Then, f(A) = (3-2)^2 + (3-2)^2 = 2. It can be proven, that it is the minimum possible value of f(A).

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.*;

public class Q3 {
	private void solve(Scan scan, Print print) throws Exception {
		int T = scan.nextInt();
		while (T-- > 0) {
			int N=scan.nextInt();
			int K=scan.nextInt();
			int arr[][]=new int[N][N];
			int i=0;
			int j=0;
			while(K>0)
			{
				arr[i][j]=1;
				K--;
				i++;
				j++;
				j%=N;
				if(i==N)
				{
					i=0;
					j++;
					j%=N;
				}
			}
			int maxr=0,minr=Integer.MAX_VALUE;
			int maxc=0,minc=minr;
			for(i=0;i<N;i++)
			{
				int sumr=0,sumc=0;
				for(j=0;j<N;j++)
				{
					sumr+=arr[i][j];
					sumc+=arr[j][i];
				}
				maxr=Math.max(maxr,sumr);
				maxc=Math.max(maxc,sumc);
				minc=Math.min(minc,sumc);
				minr=Math.min(minr,sumr);
			}
			print.println((maxr-minr)*(maxr-minr) + (maxc-minc)*(maxc-minc));
			for(i=0;i<N;i++)
			{
				for(j=0;j<N;j++)
				{
					print.print(arr[i][j]);
				}
				print.print("\n");
			}
		}
	}

	public static void main(String args[]) throws Exception {
		Scan scan = new Scan();
		Print print = new Print();
		Q3 o = new Q3();
		o.solve(scan, print);
		print.close();
	}

	public static class Print {
		private final BufferedWriter bw;

		public Print() {
			this.bw = new BufferedWriter(new OutputStreamWriter(System.out));
		}

		public void print(Object object) throws IOException {
			bw.append("" + object);
		}

		public void println(Object object) throws IOException {
			print(object);
			bw.append("\n");
		}

		public void println(int object[]) throws IOException {
			print(Arrays.toString(object));
			bw.append("\n");
		}

		public void print(int object[]) throws IOException {
			print(Arrays.toString(object));
		}

		public void println(long object[]) throws IOException {
			print(Arrays.toString(object));
			bw.append("\n");
		}

		public void print(long object[]) throws IOException {
			print(Arrays.toString(object));
		}

		public void println(boolean object[]) throws IOException {
			print(Arrays.toString(object));
			bw.append("\n");
		}

		public void print(boolean object[]) throws IOException {
			print(Arrays.toString(object));
		}

		public void println(Object object[]) throws IOException {
			print(Arrays.deepToString(object));
			bw.append("\n");
		}

		public void print(Object object[]) throws IOException {
			print(Arrays.deepToString(object));
		}

		public void close() throws IOException {
			bw.close();
		}
	}

	static class Scan {
		private byte[] buf = new byte[1024 * 1024 * 4];
		private int index;
		private InputStream in;
		private int total;

		public Scan() {
			in = System.in;
		}

		public int scan() throws IOException {
			if (total < 0)
				throw new InputMismatchException();
			if (index >= total) {
				index = 0;
				total = in.read(buf);
				if (total <= 0)
					return -1;
			}
			return buf[index++];
		}

		public int nextInt() throws IOException {
			int integer = 0;
			int n = scan();
			while (isWhiteSpace(n))
				n = scan();
			int neg = 1;
			if (n == '-') {
				neg = -1;
				n = scan();
			}
			while (!isWhiteSpace(n)) {
				if (n >= '0' && n <= '9') {
					integer *= 10;
					integer += n - '0';
					n = scan();
				} else
					throw new InputMismatchException();
			}
			return neg * integer;
		}

		public double nextDouble() throws IOException {
			double doub = 0;
			int n = scan();
			while (isWhiteSpace(n))
				n = scan();
			int neg = 1;
			if (n == '-') {
				neg = -1;
				n = scan();
			}
			while (!isWhiteSpace(n) && n != '.') {
				if (n >= '0' && n <= '9') {
					doub *= 10;
					doub += n - '0';
					n = scan();
				} else
					throw new InputMismatchException();
			}
			if (n == '.') {
				n = scan();
				double temp = 1;
				while (!isWhiteSpace(n)) {
					if (n >= '0' && n <= '9') {
						temp /= 10;
						doub += (n - '0') * temp;
						n = scan();
					} else
						throw new InputMismatchException();
				}
			}
			return doub * neg;
		}

		public long nextLong() throws IOException {
			long ret = 0;
			long c = scan();
			while (c <= ' ') {
				c = scan();
			}

			boolean neg = (c == '-');
			if (neg) {
				c = scan();
			}

			do {
				ret = ret * 10 + c - '0';
			} while ((c = scan()) >= '0' && c <= '9');

			if (neg) {
				return -ret;
			}
			return ret;
		}

		public String next() throws IOException {
			StringBuilder sb = new StringBuilder();
			int n = scan();
			while (isWhiteSpace(n))
				n = scan();
			while (!isWhiteSpace(n) || n == ' ') {
				sb.append((char) n);
				n = scan();
			}
			return sb.toString();
		}

		public void next(int arr[]) throws IOException {
			for (int i = 0; i < arr.length; i++) {
				arr[i] = nextInt();
			}
		}

		public void next(long arr[]) throws IOException {
			for (int i = 0; i < arr.length; i++) {
				arr[i] = nextLong();
			}
		}

		public char[] next(char c) throws IOException {
			char arr[] = next().toCharArray();
			return arr;
		}

		private boolean isWhiteSpace(int n) {
			if (n == ' ' || n == '\n' || n == '\r' || n == '\t' || n == -1)
				return true;
			return false;
		}
	}
}