Problem: Today, Osama gave Fadi an integer X, and Fadi was wondering about the minimum possible value of max(a, b) such that LCM(a, b) equals X. Both a and b should be positive integers.

LCM(a, b) is the smallest positive integer that is divisible by both a and b. For example, LCM(6, 8) = 24, LCM(4, 12) = 12, LCM(2, 3) = 6.

Of course, Fadi immediately knew the answer. Can you be just like Fadi and find any such pair?

Input

The first and only line contains an integer X (1 ≤ X ≤ 10^{12}).

Output

Print two positive integers, a and b, such that the value of max(a, b) is minimum possible and LCM(a, b) equals X. If there are several possible such pairs, you can print any.

Examples

Input


2


Output


1 2


Input


6


Output


2 3


Input


4


Output


1 4


Input


1


Output


1 1

Solution (in PYTHON3):

Solution:
"""GCD(GCF) get greatest common divisor/factor (Euclid's algorithm)"""
def gcd(x, y):
    while y != 0:
        (x, y) = (y, x % y)
    return x

"""LCM get lowest common multiple. need gcd function"""
def lcm(x ,y):
    return x*y//gcd(x,y)

x=int(input())

for i in range(int(x**0.5+1),0,-1):
    if x%i==0 and lcm(i,x//i)==x:
        a=i
        b=x//i
        break
print('{} {}'.format(a,b))