Problem: Today, Osama gave Fadi an integer X, and Fadi was wondering about the minimum possible value of max(a, b) such that LCM(a, b) equals X. Both a and b should be positive integers.

LCM(a, b) is the smallest positive integer that is divisible by both a and b. For example, LCM(6, 8) = 24, LCM(4, 12) = 12, LCM(2, 3) = 6.

Of course, Fadi immediately knew the answer. Can you be just like Fadi and find any such pair?

Input

The first and only line contains an integer X (1 ≤ X ≤ 10^{12}).

Output

Print two positive integers, a and b, such that the value of max(a, b) is minimum possible and LCM(a, b) equals X. If there are several possible such pairs, you can print any.

Examples

Input


2


Output


1 2


Input


6


Output


2 3


Input


4


Output


1 4


Input


1


Output


1 1

Solution (in JAVA):

Solution:
import java.util.*;

public class Main {

    public static long GCD(long a, long b) {
        if (b % a == 0)
            return a;
        return GCD(b, a % b);
    }

    public static long LCM(long a, long b) {
        return (a * b) / GCD(a, b);
    }

    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);

        long x = scanner.nextLong();
        long pembagi = 0;

        for (long i = 1; i * i <= x; i++) {
            if (x % i == 0) {
                if (LCM(i, x / i) == x) {
                    pembagi = i;
                }
            }
        }

        System.out.println(pembagi + " " + x / pembagi);
    }
}