Problem: Ron is a happy owner of a permutation a of length n.

A permutation of length n is an array consisting of n distinct integers from 1 to n in arbitrary order. For example, [2,3,1,5,4] is a permutation, but [1,2,2] is not a permutation (2 appears twice in the array) and [1,3,4] is also not a permutation (n=3 but there is 4 in the array).

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Ron's permutation is subjected to m experiments of the following type: (r_i, p_i). This means that elements in range [1, r_i] (in other words, the prefix of length r_i) have to be sorted in ascending order with the probability of p_i. All experiments are performed in the same order in which they are specified in the input data.

As an example, let's take a look at a permutation [4, 2, 1, 5, 3] and an experiment (3, 0.6). After such an experiment with the probability of 60\% the permutation will assume the form [1, 2, 4, 5, 3] and with a 40\% probability it will remain unchanged.

You have to determine the probability of the permutation becoming completely sorted in ascending order after m experiments.

Input

Each test contains one or more test cases. The first line contains the number of test cases t (1 ≤ t ≤ 100).

The first line of each test case contains two integers n and m (1 ≤ n, m ≤ 10^5) — the length of the permutation and the number of experiments, respectively.

The second line of each test case contains n integers a_1, a_2, …, a_n (1 ≤ a_i ≤ n) — contents of the permutation.

The following m lines of each test case each contain an integer r_i and a real number p_i (1 ≤ r_i ≤ n, 0 ≤ p_i ≤ 1) — the length of the prefix and the probability of it being sorted. All probabilities are given with at most 6 decimal places.

It is guaranteed that the sum of n and the sum of m does not exceed 10^5 (∑ n, ∑ m ≤ 10^5).

Output

For each test case, print a single number — the probability that after all experiments the permutation becomes sorted in ascending order. Your answer will be considered correct if its absolute or relative error does not exceed 10^{-6}.

Formally, let your answer be a, and the jury's answer be b. Your answer is accepted if and only if \frac{|a - b|}{max{(1, |b|)}} ≤ 10^{-6}.

Example

Input


4
4 3
4 3 2 1
1 0.3
3 1
4 0.6
5 3
4 2 1 3 5
3 0.8
4 0.6
5 0.3
6 5
1 3 2 4 5 6
4 0.9
5 0.3
2 0.4
6 0.7
3 0.5
4 2
1 2 3 4
2 0.5
4 0.1


Output


0.600000
0.720000
0.989500
1.000000

Note

Explanation of the first test case: It can be demonstrated that whether the final permutation is sorted or not depends solely on sorting being performed in the (4, 0.6) experiment.

Solution (in JAVA):

Solution:
import java.awt.*;
import java.io.*;
import java.util.*;
import java.util.List;
import java.util.concurrent.LinkedBlockingQueue;

public class Coding {

    private static BufferedReader bi = new BufferedReader(new InputStreamReader(System.in));
    private static BufferedWriter writer = new BufferedWriter(new OutputStreamWriter(System.out));

    public static void main(String[] args) {
        try {
            run();
        } catch (Exception e) {
            e.printStackTrace();
        }
    }

    public static void run() throws Exception {
        InputModule inp = new InputModule();
        OutputModule out = new OutputModule();
        int t = inp.cinInt();
        while (t > 0) {
            int[] input = inp.cinIntArray(2);
            int n = input[0];
            int m = input[1];
            int[] ar = inp.cinIntArray(n);
            int val = 0;
            for(int i=n;i>=1;--i) {
                if (ar[i-1]!=i) {
                    val = i;
                    break;
                }
            }
            double ans = 1.0;
            for(int i=1;i<=m;++i) {
                String[] inpp = inp.cinString().split(" ");
                int idx = Integer.parseInt(inpp[0].trim());
                double prob = Double.parseDouble(inpp[1].trim());
                if (idx>=val) {
                    ans = ans*(1-prob);
                }
            }
            if (val==0) out.printDouble(1.000000);
            else {
                ans = 1.0 - ans;
                out.printDouble(ans);
            }
            t--;
        }
    }

    private static class InputModule {
        private int cinInt() throws Exception {
            return Integer.parseInt(bi.readLine().split(" ")[0].trim());
        }

        private long cinLong() throws Exception {
            return Long.parseLong(bi.readLine().split(" ")[0].trim());
        }

        private Double cinDouble() throws Exception {
            return Double.parseDouble(bi.readLine().split(" ")[0].trim());
        }

        private String cinString() throws Exception {
            return bi.readLine();
        }

        private int[] cinIntArray(int n) throws Exception {
            String input = bi.readLine();
            String[] values = input.split(" ");
            int[] ar = new int[n];
            for (int i = 0; i < n; ++i) {
                ar[i] = Integer.parseInt(values[i]);
            }
            return ar;
        }

        private int[] cinIntArray() throws Exception {
            String input = bi.readLine();
            String[] values = input.split(" ");
            int[] ar = new int[values.length];
            for (int i = 0; i < values.length; ++i) {
                ar[i] = Integer.parseInt(values[i]);
            }
            return ar;
        }

        private long[] cinLongArray(int n) throws Exception {
            String input = bi.readLine();
            String[] values = input.split(" ");
            long[] ar = new long[n];
            for (int i = 0; i < n; ++i) {
                ar[i] = Long.parseLong(values[i]);
            }
            return ar;
        }

        private String[] cinStringArray(int n) throws Exception {
            return bi.readLine().split(" ");
        }
    }

    private static class OutputModule {
        private void printInt(int ans) throws Exception {
            writer.append(ans + "\n");
            writer.flush();
        }

        private void printLong(long ans) throws Exception {
            writer.append(ans + "\n");
            writer.flush();
        }

        private void printDouble(Double ans) throws Exception {
            writer.append(String.format("%.10f", ans));
            writer.append("\n");
            writer.flush();
        }

        private void printString(String ans) throws Exception {
            writer.append(ans + "\n");
            writer.flush();
        }

        private void printIntArray(int[] ans) throws Exception {
            for (int i = 0; i < ans.length; ++i) {
                writer.append(ans[i] + " ");
            }
            writer.append("\n");
            writer.flush();
        }

        private void printLongArray(long[] ans) throws Exception {
            for (int i = 0; i < ans.length; ++i) {
                writer.append(ans[i] + " ");
            }
            writer.append("\n");
            writer.flush();
        }

        private void printIntMatrix(int[][] mat, int n, int m) throws Exception {
            for (int i = 0; i < n; ++i) {
                for (int j = 0; j < m; ++j) {
                    writer.append(mat[i][j] + " ");
                }
                writer.append("\n");
            }
            writer.flush();
        }

        private void printLongMatrix(long[][] mat, int n, int m) throws Exception {
            for (int i = 0; i < n; ++i) {
                for (int j = 0; j < m; ++j) {
                    writer.append(mat[i][j] + " ");
                }
                writer.append("\n");
            }
            writer.flush();
        }

        private void printPoint(Point p) throws Exception {
            writer.append(p.x + " " + p.y + "\n");
            writer.flush();
        }

        private void printPoints(List<Point> p) throws Exception {
            for (Point pp : p) {
                writer.append(pp.x + " " + pp.y + "\n");
            }
            writer.flush();
        }
    }
}