Problem: There is data on sales of your company. Your task is to write a program which identifies good workers.

The program should read a list of data where each item includes the employee ID i, the amount of sales q and the corresponding unit price p. Then, the program should print IDs of employees whose total sales proceeds (i.e. sum of p × q) is greater than or equal to 1,000,000 in the order of inputting. If there is no such employees, the program should print "NA". You can suppose that n < 4000, and each employee has an unique ID. The unit price p is less than or equal to 1,000,000 and the amount of sales q is less than or equal to 100,000.



Input

The input consists of several datasets. The input ends with a line including a single 0. Each dataset consists of:


n (the number of data in the list)
i p q
i p q
:
:
i p q


Output

For each dataset, print a list of employee IDs or a text "NA"

Example

Input

4
1001 2000 520
1002 1800 450
1003 1600 625
1001 200 1220
2
1001 100 3
1005 1000 100
2
2013 5000 100
2013 5000 100
0


Output

1001
1003
NA
2013

Solution (in CPP):

Solution:
#include <iostream>
#include <utility>
#include <vector>
using namespace std;

int main()
{
	while ( true )
	{
		int n; cin>>n;
		if ( n == 0 )
			break;
		vector<pair<int,long long> > E;

		for ( int i=0; i<n; i++ )
		{
			int a, b, c;
			cin>>a>>b>>c;
			int j;
			for ( j=0; j<(int)E.size(); j++ )
				if ( E[j].first==a )
					break;
			if ( j==(int)E.size() )
				E.push_back( make_pair(a,0ll) );
			E[j].second += (long long)b*c;
		}
		bool f = false;
		for ( int i=0; i<(int)E.size(); i++ )
			if ( E[i].second >= 1000000 )
				cout << E[i].first << endl,
				f = true;
		if ( ! f )
			cout << "NA" << endl;
	}
}