Problem: Today, Osama gave Fadi an integer X, and Fadi was wondering about the minimum possible value of max(a, b) such that LCM(a, b) equals X. Both a and b should be positive integers.

LCM(a, b) is the smallest positive integer that is divisible by both a and b. For example, LCM(6, 8) = 24, LCM(4, 12) = 12, LCM(2, 3) = 6.

Of course, Fadi immediately knew the answer. Can you be just like Fadi and find any such pair?

Input

The first and only line contains an integer X (1 ≤ X ≤ 10^{12}).

Output

Print two positive integers, a and b, such that the value of max(a, b) is minimum possible and LCM(a, b) equals X. If there are several possible such pairs, you can print any.

Examples

Input


2


Output


1 2


Input


6


Output


2 3


Input


4


Output


1 4


Input


1


Output


1 1

Solution (in PYTHON3):

Solution:
import math


def gcd(a, b):
    if b == 0:
        return a
    return gcd(b, a % b)


def lcm(a, b):
    return (a*b)//gcd(a, b)


def factors(n):
    s = list()
    i = 1
    while i <= math.sqrt(n):
        if n % i == 0:
            s.append(i)
            s.append(n//i)
        i += 1
    return s


x = int(input())
arr = factors(x)
arr = list(arr)
arr = sorted(arr)
start, end = 0, len(arr)-1
while start <= end:
    if lcm(arr[start], arr[end]) == x:
        a, b = arr[start], arr[end]
    start += 1
    end -= 1
print(a, b)