Problem: One way to create a task is to learn from math. You can generate some random math statement or modify some theorems to get something new and build a new task from that.

For example, there is a statement called the "Goldbach's conjecture". It says: "each even number no less than four can be expressed as the sum of two primes". Let's modify it. How about a statement like that: "each integer no less than 12 can be expressed as the sum of two composite numbers." Not like the Goldbach's conjecture, I can prove this theorem.

You are given an integer n no less than 12, express it as a sum of two composite numbers.

Input

The only line contains an integer n (12 ≤ n ≤ 106).

Output

Output two composite integers x and y (1 < x, y < n) such that x + y = n. If there are multiple solutions, you can output any of them.

Examples

Input

12


Output

4 8


Input

15


Output

6 9


Input

23


Output

8 15


Input

1000000


Output

500000 500000

Note

In the first example, 12 = 4 + 8 and both 4, 8 are composite numbers. You can output "6 6" or "8 4" as well.

In the second example, 15 = 6 + 9. Note that you can't output "1 14" because 1 is not a composite number.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int main() {
  int x, sum1 = 2, sum2, sum3, sum4, pepe;
  cin >> x;
  if (x & 1) {
    for (int i = 4; i < x; i += 2) {
      for (int j = i + 1; j < x; j += 2) {
        if ((j + i == x && i % 2 == 0 && j / 3 == 0) ||
            (j + i == x && j % 3 == 0 && i % 2 == 0)) {
          cout << j << " " << i;
          return 0;
        }
      }
    }
  } else {
    for (int i = 4; i < x; i += 2) {
      for (int j = i; j < x; j += 2) {
        if (j + i == x) {
          cout << j << " " << i;
          return 0;
        }
      }
    }
  }
  return 0;
}