Problem: There is data on sales of your company. Your task is to write a program which identifies good workers.

The program should read a list of data where each item includes the employee ID i, the amount of sales q and the corresponding unit price p. Then, the program should print IDs of employees whose total sales proceeds (i.e. sum of p × q) is greater than or equal to 1,000,000 in the order of inputting. If there is no such employees, the program should print "NA". You can suppose that n < 4000, and each employee has an unique ID. The unit price p is less than or equal to 1,000,000 and the amount of sales q is less than or equal to 100,000.



Input

The input consists of several datasets. The input ends with a line including a single 0. Each dataset consists of:


n (the number of data in the list)
i p q
i p q
:
:
i p q


Output

For each dataset, print a list of employee IDs or a text "NA"

Example

Input

4
1001 2000 520
1002 1800 450
1003 1600 625
1001 200 1220
2
1001 100 3
1005 1000 100
2
2013 5000 100
2013 5000 100
0


Output

1001
1003
NA
2013

Solution (in CPP):

Solution:
#include<iostream>
#include<algorithm>
#include<vector>
#include<map>
using namespace std;

int main()
{
	int n, i;
	bool f;
	long long int a, b, c;
	map<int, long long int> member;
	vector<int> order;
	vector<int>::iterator it;
	while (cin>>n, n) {
		member.clear();
		order.clear();
		for (i = 0; i < n; i++) {
			cin>>a>>b>>c;
			member[a] += b*c;
			if ( order.end() == find( order.begin(), order.end(), a ) ) {
				order.push_back(a);
			}
		}
		f = true;
		for (it = order.begin(); it != order.end(); it++) {
			if (member[*it] >= 1000000) {
				cout<<*it<<endl;
				f = false;
			}
		}
		if (f) cout<<"NA"<<endl;
	}

	return 0;
}