Problem: There is data on sales of your company. Your task is to write a program which identifies good workers.

The program should read a list of data where each item includes the employee ID i, the amount of sales q and the corresponding unit price p. Then, the program should print IDs of employees whose total sales proceeds (i.e. sum of p × q) is greater than or equal to 1,000,000 in the order of inputting. If there is no such employees, the program should print "NA". You can suppose that n < 4000, and each employee has an unique ID. The unit price p is less than or equal to 1,000,000 and the amount of sales q is less than or equal to 100,000.



Input

The input consists of several datasets. The input ends with a line including a single 0. Each dataset consists of:


n (the number of data in the list)
i p q
i p q
:
:
i p q


Output

For each dataset, print a list of employee IDs or a text "NA"

Example

Input

4
1001 2000 520
1002 1800 450
1003 1600 625
1001 200 1220
2
1001 100 3
1005 1000 100
2
2013 5000 100
2013 5000 100
0


Output

1001
1003
NA
2013

Solution (in CPP):

Solution:
#include<stdio.h>
#include<string.h>
int main(void)
{
	long long int n,m,flg,i,j,a[1001],b[1001],c[1001];
	long long int e[1001],p[1001],q[1001];
	while(1){
		scanf("%lld",&n);
		if(n==0) break;
		for(i=0;i<n;i++){
			a[i]=0; b[i]=0; c[i]=0;
		}	
		for(i=0;i<n;i++){
			scanf("%lld %lld %lld",&e[i],&p[i],&q[i]);
			if(p[i]*q[i]>=1000000) a[i]=1;
			if(a[i]==0) b[i]=p[i]*q[i];
		}	
		for(i=0;i<n-1;i++){
			for(j=i+1;j<n;j++){
				if(e[i]==e[j]){
					if(a[i]==0){
						b[i]+=b[j];
						b[j]=0;
					}
					if(b[i]>=1000000&&a[i]==0) a[i]=1;
				}
			}
		}
		flg=0;
		for(i=0;i<n;i++){
			if(a[i]!=0){
				printf("%lld\n",e[i]);
				flg=1;
			}
		}	
		if(flg==0) printf("NA\n");
	}
	return 0;
}