Problem: One way to create a task is to learn from math. You can generate some random math statement or modify some theorems to get something new and build a new task from that.

For example, there is a statement called the "Goldbach's conjecture". It says: "each even number no less than four can be expressed as the sum of two primes". Let's modify it. How about a statement like that: "each integer no less than 12 can be expressed as the sum of two composite numbers." Not like the Goldbach's conjecture, I can prove this theorem.

You are given an integer n no less than 12, express it as a sum of two composite numbers.

Input

The only line contains an integer n (12 ≤ n ≤ 106).

Output

Output two composite integers x and y (1 < x, y < n) such that x + y = n. If there are multiple solutions, you can output any of them.

Examples

Input

12


Output

4 8


Input

15


Output

6 9


Input

23


Output

8 15


Input

1000000


Output

500000 500000

Note

In the first example, 12 = 4 + 8 and both 4, 8 are composite numbers. You can output "6 6" or "8 4" as well.

In the second example, 15 = 6 + 9. Note that you can't output "1 14" because 1 is not a composite number.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int main() {
  int n, n1, n2;
  cin >> n;
  if (n % 2 == 0) {
    n1 = n2 = n / 2;
  } else {
    n1 = n / 2;
    n2 = n / 2 + 1;
  }
  bool check1 = false;
  bool check2 = false;
  while (true) {
    for (int i = 2; i < n1; i++) {
      if (n1 % i == 0) {
        check1 = true;
      }
    }
    for (int i = 2; i < n2; i++) {
      if (n2 % i == 0) {
        check2 = true;
      }
    }
    if (check1 == false || check2 == false) {
      n1--;
      n2++;
      check1 = false;
      check2 = false;
    } else {
      break;
    }
  }
  cout << n1 << " " << n2;
}