Problem: Today, Osama gave Fadi an integer X, and Fadi was wondering about the minimum possible value of max(a, b) such that LCM(a, b) equals X. Both a and b should be positive integers.

LCM(a, b) is the smallest positive integer that is divisible by both a and b. For example, LCM(6, 8) = 24, LCM(4, 12) = 12, LCM(2, 3) = 6.

Of course, Fadi immediately knew the answer. Can you be just like Fadi and find any such pair?

Input

The first and only line contains an integer X (1 ≤ X ≤ 10^{12}).

Output

Print two positive integers, a and b, such that the value of max(a, b) is minimum possible and LCM(a, b) equals X. If there are several possible such pairs, you can print any.

Examples

Input


2


Output


1 2


Input


6


Output


2 3


Input


4


Output


1 4


Input


1


Output


1 1

Solution (in PYTHON3):

Solution:
X = int(input())
Xo = X

factor = []

test = 2
while test * test <= X:
    curr = 0
    while X % test == 0:
        X //= test
        curr += 1

    if curr > 0:
        factor.append(pow(test,curr))
    test += 1
    
if X > 1:
    factor.append(X)

X = Xo

poss = [1]
for fact in factor:
    for v in poss[:]:
        if fact * v * fact * v <= X:
            poss.append(fact * v)

best = max(poss)
print(best, X//best)