Problem: The new camp by widely-known over the country Spring Programming Camp is going to start soon. Hence, all the team of friendly curators and teachers started composing the camp's schedule. After some continuous discussion, they came up with a schedule s, which can be represented as a binary string, in which the i-th symbol is '1' if students will write the contest in the i-th day and '0' if they will have a day off.

At the last moment Gleb said that the camp will be the most productive if it runs with the schedule t (which can be described in the same format as schedule s). Since the number of days in the current may be different from number of days in schedule t, Gleb required that the camp's schedule must be altered so that the number of occurrences of t in it as a substring is maximum possible. At the same time, the number of contest days and days off shouldn't change, only their order may change.

Could you rearrange the schedule in the best possible way?

Input

The first line contains string s (1 ⩽ |s| ⩽ 500 000), denoting the current project of the camp's schedule.

The second line contains string t (1 ⩽ |t| ⩽ 500 000), denoting the optimal schedule according to Gleb.

Strings s and t contain characters '0' and '1' only.

Output

In the only line print the schedule having the largest number of substrings equal to t. Printed schedule should consist of characters '0' and '1' only and the number of zeros should be equal to the number of zeros in s and the number of ones should be equal to the number of ones in s.

In case there multiple optimal schedules, print any of them.

Examples

Input


101101
110


Output


110110

Input


10010110
100011


Output


01100011


Input


10
11100


Output


01

Note

In the first example there are two occurrences, one starting from first position and one starting from fourth position.

In the second example there is only one occurrence, which starts from third position. Note, that the answer is not unique. For example, if we move the first day (which is a day off) to the last position, the number of occurrences of t wouldn't change.

In the third example it's impossible to make even a single occurrence.

Solution (in JAVA):

Solution:
import javafx.util.Pair;

import java.io.FileInputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.PrintWriter;
import java.util.*;
import java.util.function.BiFunction;
import java.util.function.BinaryOperator;
import java.util.function.Function;
import java.util.function.UnaryOperator;
import java.util.regex.Matcher;
import java.util.regex.Pattern;

import static java.lang.Math.abs;

public class problem1 {

    boolean ONLINE_JUDGE = (System.getProperty("ONLINE_JUDGE") != null);

    public problem1() throws IOException {
        InputReader in;
        if (ONLINE_JUDGE) {
            in = new InputReader(System.in);
        } else {
            in = new InputReader(new FileInputStream("input.txt"));
        }
        PrintWriter out = new PrintWriter(System.out);

        int T = 1;
        for (int caseNo = 1; caseNo <= T; caseNo++) {
            solve(caseNo, in, out);
        }

        out.close();
    }

    int lower_bound(int arr[], int key, int low, int high)
    {
        if (low > high)
            //return -1;
            return low;

        int mid = low + ((high - low) >> 1);
        //if (arr[mid] == key) return mid;

        //Attention here, we go left for lower_bound when meeting equal values
        if (arr[mid] >= key)
            return lower_bound(arr, key, low, mid - 1);
        else
            return lower_bound(arr, key, mid + 1, high);
    }

    final int mod = (1 << 28) - 3;



    private void solve(int caseNo, InputReader in, PrintWriter out) throws IOException {

        String s1 = in.nextString(), s2 = in.nextString();

        int h1l = 0, h1r = 0, h2l = 0, h2r = 0;
        int pow1 = 1, pow2 = 1;
        int bestSufLen = 0;
        for (int i = 0; i < s2.length() - 1; i++) {
            int l = s2.charAt(i) - '0', r = s2.charAt(s2.length() - i - 1) - '0';

            h1l = (h1l * 3 + l) % mod; h2l = (h2l * 5 + l) % mod;
            h1r = (h1r + pow1 * r) % mod; h2r = (h2r + pow2 * r) % mod;
            pow1 = (pow1 * 3) % mod; pow2 = (pow2 * 5) % mod;


            if (h1l == h1r && h2l == h2r) {
                bestSufLen = i + 1;
            }
        }

        int cnt[] = new int [2];
        for (char c : s1.toCharArray()) {
            cnt[c - '0']++;
        }

        StringBuffer ans = new StringBuffer(s1.length());

        int pos = 0;
        while (true) {
            char c = s2.charAt(pos);
            if (cnt[c - '0'] == 0) break;

            cnt[c - '0']--;
            pos++;
            ans.append(c);

            if (pos == s2.length()) pos = bestSufLen;
        }
        while (cnt[0] > 0) {
            ans.append('0');
            cnt[0]--;
        }
        while (cnt[1] > 0) {
            ans.append('1');
            cnt[1]--;
        }


        out.println(ans);
    }

    static class InputReader {

        private InputStream stream;
        private byte[] buf = new byte[1024];
        private int curChar;
        private int numChars;
        private SpaceCharFilter filter;

        public InputReader(InputStream stream) {
            this.stream = stream;
        }

        public static boolean isWhitespace(int c) {
            return c == ' ' || c == '\n' || c == '\r' || c == '\t' || c == -1;
        }

        public int read() {
            if (numChars == -1) {
                throw new InputMismatchException();
            }
            if (curChar >= numChars) {
                curChar = 0;
                try {
                    numChars = stream.read(buf);
                } catch (IOException e) {
                    throw new InputMismatchException();
                }
                if (numChars <= 0) {
                    return -1;
                }
            }
            return buf[curChar++];
        }

        public boolean isSpaceChar(int c) {
            if (filter != null) {
                return filter.isSpaceChar(c);
            }
            return isWhitespace(c);
        }

        public interface SpaceCharFilter {

            public boolean isSpaceChar(int ch);
        }

        public String next() {
            return nextString();
        }

        public String nextString() {
            int c = read();
            while (isSpaceChar(c)) {
                c = read();
            }
            StringBuilder res = new StringBuilder();
            do {
                res.appendCodePoint(c);
                c = read();
            } while (!isSpaceChar(c));
            return res.toString();
        }

        public int nextInt() {
            int c = read();
            while (isSpaceChar(c)) {
                c = read();
            }
            int sgn = 1;
            if (c == '-') {
                sgn = -1;
                c = read();
            }
            int res = 0;
            do {
                if (c < '0' || c > '9') {
                    throw new InputMismatchException();
                }
                res *= 10;
                res += c - '0';
                c = read();
            } while (!isSpaceChar(c));
            return res * sgn;
        }

        public Long nextLong() {
            return Long.parseLong(nextString());
        }

        public Double nextDouble() {
            return Double.parseDouble(nextString());
        }

        public char nextCharacter() {
            return nextString().charAt(0);
        }

        public int[] nextIntArray(int N) {
            int A[] = new int[N];
            for (int i = 0; i < N; i++) {
                A[i] = nextInt();
            }
            return A;
        }

        public long[] nextLongArray(int N) {
            long A[] = new long[N];
            for (int i = 0; i < N; i++) {
                A[i] = nextLong();
            }
            return A;
        }

        public double[] nextDoubleArray(int N) {
            double A[] = new double[N];
            for (int i = 0; i < N; i++) {
                A[i] = nextDouble();
            }
            return A;
        }
    }

    int min(int... a) {
        int min = Integer.MAX_VALUE;
        for (int v : a) {
            min = Math.min(min, v);
        }
        return min;
    }

    long min(long... a) {
        long min = Long.MAX_VALUE;
        for (long v : a) {
            min = Math.min(min, v);
        }
        return min;
    }

    double min(double... a) {
        double min = Double.MAX_VALUE;
        for (double v : a) {
            min = Math.min(min, v);
        }
        return min;
    }

    int max(int... a) {
        int max = Integer.MIN_VALUE;
        for (int v : a) {
            max = Math.max(max, v);
        }
        return max;
    }

    long max(long... a) {
        long max = Long.MIN_VALUE;
        for (long v : a) {
            max = Math.max(max, v);
        }
        return max;
    }

    double max(double... a) {
        double max = Double.MIN_VALUE;
        for (double v : a) {
            max = Math.max(max, v);
        }
        return max;
    }

    private void debug(Object... o) {
        if (ONLINE_JUDGE) {
            return;
        }
        System.out.println(Arrays.deepToString(o));
    }

    public static void main(String args[]) throws IOException {
        new problem1();
    }
}