Problem: Today, Osama gave Fadi an integer X, and Fadi was wondering about the minimum possible value of max(a, b) such that LCM(a, b) equals X. Both a and b should be positive integers.

LCM(a, b) is the smallest positive integer that is divisible by both a and b. For example, LCM(6, 8) = 24, LCM(4, 12) = 12, LCM(2, 3) = 6.

Of course, Fadi immediately knew the answer. Can you be just like Fadi and find any such pair?

Input

The first and only line contains an integer X (1 ≤ X ≤ 10^{12}).

Output

Print two positive integers, a and b, such that the value of max(a, b) is minimum possible and LCM(a, b) equals X. If there are several possible such pairs, you can print any.

Examples

Input


2


Output


1 2


Input


6


Output


2 3


Input


4


Output


1 4


Input


1


Output


1 1

Solution (in PYTHON3):

Solution:
def hcf(a, b) :
    if a % b == 0 :
        return b
    else :
        return hcf( b, a % b )
    
def function(x) :
    ans = [1, x ]
    for i in range( 2, int(x ** (1/2) ) + 1 ) :
        if ( x % i == 0 ) and ( hcf( i, x//i ) == 1 ) :
            if max(ans) > max([i, x//i ] ) :
                ans = [i, x//i ]
    return str(ans[0]) + " " + str(ans[1])

if __name__ == "__main__" :
    x = int(input())
    print(function(x))