Problem: There is data on sales of your company. Your task is to write a program which identifies good workers.

The program should read a list of data where each item includes the employee ID i, the amount of sales q and the corresponding unit price p. Then, the program should print IDs of employees whose total sales proceeds (i.e. sum of p × q) is greater than or equal to 1,000,000 in the order of inputting. If there is no such employees, the program should print "NA". You can suppose that n < 4000, and each employee has an unique ID. The unit price p is less than or equal to 1,000,000 and the amount of sales q is less than or equal to 100,000.



Input

The input consists of several datasets. The input ends with a line including a single 0. Each dataset consists of:


n (the number of data in the list)
i p q
i p q
:
:
i p q


Output

For each dataset, print a list of employee IDs or a text "NA"

Example

Input

4
1001 2000 520
1002 1800 450
1003 1600 625
1001 200 1220
2
1001 100 3
1005 1000 100
2
2013 5000 100
2013 5000 100
0


Output

1001
1003
NA
2013

Solution (in CPP):

Solution:
#include <iostream>
#include <cstdio>
#include <vector>
#include <map>
using namespace std;
typedef long long int ll;
int main(){
  ll n;
  while( cin >> n,n ){
    ll ma[4001] = {0};
    vector<ll>ve;
    ve.clear();
    for(ll k = 0 ; k < n ; k++ ){
      ll a,b,c;
      cin >> a >> b >> c;
      if(ma[a] == 0)ve.push_back(a);
      ma[a] += b*c;
    }
    int f = 1;
    for(vector<ll>::iterator it = ve.begin() ; it != ve.end() ; it++ ){
      if(ma[(*it)] >= 1000000 ){
	cout << (*it) << endl;
	f = 0;
      }
    }
    if(f)cout << "NA" << endl;
  }
  return 0;
}