Problem: Today, Osama gave Fadi an integer X, and Fadi was wondering about the minimum possible value of max(a, b) such that LCM(a, b) equals X. Both a and b should be positive integers.

LCM(a, b) is the smallest positive integer that is divisible by both a and b. For example, LCM(6, 8) = 24, LCM(4, 12) = 12, LCM(2, 3) = 6.

Of course, Fadi immediately knew the answer. Can you be just like Fadi and find any such pair?

Input

The first and only line contains an integer X (1 ≤ X ≤ 10^{12}).

Output

Print two positive integers, a and b, such that the value of max(a, b) is minimum possible and LCM(a, b) equals X. If there are several possible such pairs, you can print any.

Examples

Input


2


Output


1 2


Input


6


Output


2 3


Input


4


Output


1 4


Input


1


Output


1 1

Solution (in PYTHON3):

Solution:
def gcd(a, b):
    if b == 0:
        return a
    else:
        return gcd(b, a % b)


def isValid(a, b, x):
    temp = (a * b) / gcd(a, b)
    if temp == x:
        return True
    else:
        return False


def solve(x):
    if x == 1:
        print(1, 1)
        return
    maxi = x
    ansa = 1
    ansb = x
    limit = int(x ** 0.5) + 1
    for i in range(1, limit):
        if x % i == 0 and isValid(i, x / i, x) and max(i, x/i) < maxi:
            maxi = max(i, x/i)
            ansa = i
            ansb = x // i
    print(ansa, ansb)



def main():
    x = int(input())
    solve(x)

main()