Problem: Today, Osama gave Fadi an integer X, and Fadi was wondering about the minimum possible value of max(a, b) such that LCM(a, b) equals X. Both a and b should be positive integers.

LCM(a, b) is the smallest positive integer that is divisible by both a and b. For example, LCM(6, 8) = 24, LCM(4, 12) = 12, LCM(2, 3) = 6.

Of course, Fadi immediately knew the answer. Can you be just like Fadi and find any such pair?

Input

The first and only line contains an integer X (1 ≤ X ≤ 10^{12}).

Output

Print two positive integers, a and b, such that the value of max(a, b) is minimum possible and LCM(a, b) equals X. If there are several possible such pairs, you can print any.

Examples

Input


2


Output


1 2


Input


6


Output


2 3


Input


4


Output


1 4


Input


1


Output


1 1

Solution (in PYTHON3):

Solution:
'''Author- Akshit Monga'''
from sys import stdin, stdout
import math
def gcd(a, b):
    if a == 0:
        return b
    return gcd(b % a, a)
def lcm(a, b):
    return (a / gcd(a, b)) * b
input = stdin.readline
t=1
for _ in range(t):
    x=int(input())
    m=float('inf')
    a=1
    b=x
    for i in range(1,int(math.sqrt(x))+2):
        if x%i==0:
            if max(i,x//i)<m and lcm(i,x//i)==x:
                m=max(i,x//i)
                a=i
                b=x//i
    print(a,b)