Problem: A mad scientist Dr.Jubal has made a competitive programming task. Try to solve it!

You are given integers n,k. Construct a grid A with size n × n consisting of integers 0 and 1. The very important condition should be satisfied: the sum of all elements in the grid is exactly k. In other words, the number of 1 in the grid is equal to k.

Let's define:

  * A_{i,j} as the integer in the i-th row and the j-th column. 
  * R_i = A_{i,1}+A_{i,2}+...+A_{i,n} (for all 1 ≤ i ≤ n). 
  * C_j = A_{1,j}+A_{2,j}+...+A_{n,j} (for all 1 ≤ j ≤ n). 
  * In other words, R_i are row sums and C_j are column sums of the grid A. 
  * For the grid A let's define the value f(A) = (max(R)-min(R))^2 + (max(C)-min(C))^2 (here for an integer sequence X we define max(X) as the maximum value in X and min(X) as the minimum value in X). 



Find any grid A, which satisfies the following condition. Among such grids find any, for which the value f(A) is the minimum possible. Among such tables, you can find any.

Input

The input consists of multiple test cases. The first line contains a single integer t (1 ≤ t ≤ 100) — the number of test cases. Next t lines contain descriptions of test cases.

For each test case the only line contains two integers n, k (1 ≤ n ≤ 300, 0 ≤ k ≤ n^2).

It is guaranteed that the sum of n^2 for all test cases does not exceed 10^5.

Output

For each test case, firstly print the minimum possible value of f(A) among all tables, for which the condition is satisfied.

After that, print n lines contain n characters each. The j-th character in the i-th line should be equal to A_{i,j}.

If there are multiple answers you can print any.

Example

Input


4
2 2
3 8
1 0
4 16


Output


0
10
01
2
111
111
101
0
0
0
1111
1111
1111
1111

Note

In the first test case, the sum of all elements in the grid is equal to 2, so the condition is satisfied. R_1 = 1, R_2 = 1 and C_1 = 1, C_2 = 1. Then, f(A) = (1-1)^2 + (1-1)^2 = 0, which is the minimum possible value of f(A).

In the second test case, the sum of all elements in the grid is equal to 8, so the condition is satisfied. R_1 = 3, R_2 = 3, R_3 = 2 and C_1 = 3, C_2 = 2, C_3 = 3. Then, f(A) = (3-2)^2 + (3-2)^2 = 2. It can be proven, that it is the minimum possible value of f(A).

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.*;

/**
 * Problem CF1372D
 */
@SuppressWarnings("unchecked")
public class CF1371D {

    static class Task extends IOHandler {
        public void run() {
            int t = in.nextInt();
            while(t-->0){
                Grid g = new Grid(in.nextInt(),in.nextInt());
                int s = g.solve();
                out.println(s);
                g.print(out);
            }
            // for(int i = 0; i <= 9; ++i){
            //     Grid g = new Grid(3,i);
            //     int s = g.solve();
            //     g.print(out);
            //     out.println("k="+i+" ,s="+s);
            //     out.println("==========================");
            // }
        }
    }

    static class Grid {
        private int n;
        private int k;
        private int[][] g;
        public Grid(int n, int k) {
            this.n = n;
            this.k = k;
            this.g = new int[n][n];
        }
        public int solve() {
            int i = 0;
            int j = 0;
            for (int a = 0; a < k; ++a){
                g[i][j]=1;
                i++;
                j=(j+1)%n;
                if(i==n){
                    i=0;
                    j=(j+1)%n;
                }

            }
            return k%n==0?0:2;
        }
        public void print(OutputWriter out) {
            for(int i = 0; i < n; ++i){
                for(int j = 0; j < n; ++j){
                    out.print(g[i][j]);
                }
                out.println();
            }
        }
    }

    /***********************************************************
     *                        COMMONS                          *
     ***********************************************************/
    static class Pair<A, B> implements Comparable<Pair<A, B>> {
        public A a;
        public B b;
        public Pair(Pair<A, B> p) {
            this(p.a, p.b);
        }

        public Pair(A a, B b) {
            this.a = a;
            this.b = b;
        }

        public String toString() {
            return a+" "+b;
        }

        public int hashCode() {
            return Objects.hash(a, b);
        }

        public boolean equals(Object o) {
            if(o instanceof Pair) {
                Pair<A,B> p = (Pair<A,B>) o;
                return a.equals(p.a)&&b.equals(p.b);
            }
            return false;
        }

        @Override
        public int compareTo(Pair<A, B> p) {
            int cmp = ((Comparable<A>) a).compareTo(p.a);
            if(cmp==0) {
                return ((Comparable<B>) b).compareTo(p.b);
            }
            return cmp;
        }
    }

    /***********************************************************
     *                      BOILERPLATE                        *
     ***********************************************************/
    public static void main(String[] args) {
        Task task = new Task();
        task.run();
        task.cleanup();
    }

    static class IOHandler {
        public InputReader in = new InputReader(System.in);
        public OutputWriter out = new OutputWriter(System.out);

        public void cleanup() {
            out.close();
        }
    }

    static class InputReader {
        public BufferedReader reader;
        public StringTokenizer tokenizer;

        public InputReader(InputStream stream) {
            reader = new BufferedReader(new InputStreamReader(stream), 32768);
            tokenizer = null;
        }

        public String next() {
            while (tokenizer == null || !tokenizer.hasMoreTokens()) {
                try {
                    tokenizer = new StringTokenizer(reader.readLine());
                } catch (IOException e) {
                    throw new RuntimeException(e);
                }
            }
            return tokenizer.nextToken();
        }

        public int nextInt() {
            return Integer.parseInt(next());
        }

        public int[] nextInts(int n) {
            int a[] = new int[n];
            for(int i = 0; i < n; ++i)
                a[i] = nextInt();
            return a;
        }

        public long nextLong() {
            return Long.parseLong(next());
        }

        public long[] nextLongs(int n) {
            long a[] = new long[n];
            for(int i = 0; i < n; ++i)
                a[i] = nextLong();
            return a;
        }
    }

    static class OutputWriter extends PrintWriter {
        public OutputWriter(OutputStream out) {
            super(out);
        }

        public void println(String format, Object... args) {
            this.println(String.format(format, args));
        }

        public void print(String format, Object... args) {
            this.print(String.format(format, args));
        }
    }

}