Problem: Today, Osama gave Fadi an integer X, and Fadi was wondering about the minimum possible value of max(a, b) such that LCM(a, b) equals X. Both a and b should be positive integers.

LCM(a, b) is the smallest positive integer that is divisible by both a and b. For example, LCM(6, 8) = 24, LCM(4, 12) = 12, LCM(2, 3) = 6.

Of course, Fadi immediately knew the answer. Can you be just like Fadi and find any such pair?

Input

The first and only line contains an integer X (1 ≤ X ≤ 10^{12}).

Output

Print two positive integers, a and b, such that the value of max(a, b) is minimum possible and LCM(a, b) equals X. If there are several possible such pairs, you can print any.

Examples

Input


2


Output


1 2


Input


6


Output


2 3


Input


4


Output


1 4


Input


1


Output


1 1

Solution (in PYTHON3):

Solution:
from math import gcd as __gcd, sqrt, ceil 
  
def lcm(a, b): 
    return (a // __gcd(a, b) * b) 
  

def findNums(x): 

    if x == 1:
        print(1,1)
        return
    ans = 0
  
    for i in range(ceil(sqrt(x)), -1, -1): 
  
        if (x % i == 0 and lcm(i, x // i) == x): 
            ans = i
            print(ans, (x//ans))
            return
  
    print(ans, (x//ans)) 
  

if __name__ == "__main__":
    findNums(int(input()))