Problem: Sometimes one has to spell email addresses over the phone. Then one usually pronounces a dot as dot, an at sign as at. As a result, we get something like vasyaatgmaildotcom. Your task is to transform it into a proper email address (vasya@gmail.com). 

It is known that a proper email address contains only such symbols as . @ and lower-case Latin letters, doesn't start with and doesn't end with a dot. Also, a proper email address doesn't start with and doesn't end with an at sign. Moreover, an email address contains exactly one such symbol as @, yet may contain any number (possible, zero) of dots. 

You have to carry out a series of replacements so that the length of the result was as short as possible and it was a proper email address. If the lengths are equal, you should print the lexicographically minimal result. 

Overall, two variants of replacement are possible: dot can be replaced by a dot, at can be replaced by an at. 

Input

The first line contains the email address description. It is guaranteed that that is a proper email address with all the dots replaced by dot an the at signs replaced by at. The line is not empty and its length does not exceed 100 symbols.

Output

Print the shortest email address, from which the given line could be made by the described above replacements. If there are several solutions to that problem, print the lexicographically minimal one (the lexicographical comparison of the lines are implemented with an operator < in modern programming languages).

In the ASCII table the symbols go in this order: . @ ab...z

Examples

Input

vasyaatgmaildotcom


Output

vasya@gmail.com


Input

dotdotdotatdotdotat


Output

dot..@..at


Input

aatt


Output

a@t

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Random;
import java.util.StringTokenizer;


public class Main {

	static boolean visited[] ; 
	static boolean ends[] ;
	static long mod = 1000000007 ;
	static int lens[] ; 
	static int seeds[] ; 
	static char a[] ;
	static double total ; 
	public static ArrayList adj[] ; 
	public static long x,y ;
	public static ArrayList<Integer> xx ;	
	public static double dp[][][] ;
	public static void main(String[] args) throws IOException, InterruptedException {
		Scanner sc =  new Scanner(System.in) ;



		char arr[] = sc.next().toCharArray() ; 
		int n=arr.length ;
		char res[] = new char[arr.length];
		for (int i = 0; i < res.length; i++) res[i]=arr[i];

		for (int i = 1; i < res.length-2; i++)
			if(arr[i]=='a' && arr[i+1]=='t')
			{
				res[i]='@' ; res[i+1]='X' ;
				break ;			
			}

		for (int i = 1; i < arr.length-3; i++)
			if(arr[i]=='d' && arr[i+1]=='o' && arr[i+2]=='t')
			{
				res[i]='.' ; res[i+1]='X' ; res[i+2]='X';
				i+=2;				
			}


		for (int i = 0; i < res.length; i++)
			if(res[i]!='X')System.out.print(res[i]+"");
	}

	static void generate(int n)
	{
		if(n>=10000000)
			return ; 

		xx.add(n) ; 
		generate(Integer.parseInt("4"+n)) ;
		generate(Integer.parseInt("7"+n)) ;

	}


	static long pow(long base, int exp) {
		long res = 1;
		while(exp > 0) {
			if(exp % 2 == 1) {
				res = (res * base) % mod;
			}

			base = (base * base) % mod;
			exp /= 2;
		}

		return res;
	}
































	public static void dfss(int root , int len)
	{
		visited[root]=true ; 
		if(ends[root] && root!=0) lens[root] = len ; 

		for (int i = 0; i < adj[root].size(); i++)
		{
			int c= (int) adj[root].get(i) ; 
			if(visited[c]==false)
				dfss(c, len+1);
		}
	}

	public static void pr(int root ,  int seed){
		visited[root] = true ;
		int dv = adj[root].size()-1 ; 
		if(root==0) dv++ ;

		for (int i = 0; i < adj[root].size(); i++)
		{
			int c = (int)adj[root].get(i) ; 
			seeds[c]=dv*seed ;
		}

		for (int i = 0; i < adj[root].size() ; i++)
		{
			int c = (int)adj[root].get(i) ; 
			if(visited[c]==false)
				pr(c , seeds[c]);

		}

	}



	static class Scanner {
		StringTokenizer st;
		BufferedReader br;

		public Scanner(InputStream s) {
			br = new BufferedReader(new InputStreamReader(s));
		}

		public String next() throws IOException {
			while (st == null || !st.hasMoreTokens())
				st = new StringTokenizer(br.readLine());
			return st.nextToken();
		}

		public int nextInt() throws IOException {
			return Integer.parseInt(next());
		}

		public long nextLong() throws IOException {
			return Long.parseLong(next());
		}

		public String nextLine() throws IOException {
			return br.readLine();
		}

		public double nextDouble() throws IOException {
			return Double.parseDouble(next());
		}

		public boolean ready() throws IOException {
			return br.ready();
		}
	}


	public static long getGCD(long n1, long n2) {
		if (n2 == 0) {
			return n1;
		}
		return getGCD(n2, n1 % n2);
	}


	public static void shuffle(ArrayList<Integer> ss){
		if(ss.size()==1)
			return ; 
		for (int i = 0; i < ss.size(); i++)
		{
			Random rand = new Random();

			int  n = rand.nextInt(ss.size()-1) + 0;

			int tmp = ss.get(n);
			ss.remove(n);
			ss.add(tmp);
		}
	}
	//	public static int binary(ArrayList<pair> arr, int l, int r, long x)   /// begin by 0 and n-1
	//	{
	//		if (r>=l)
	//		{
	//			int mid = l + (r - l)/2;
	//			if (arr.get(mid).x== x)
	//				return mid;
	//			if (arr.get(mid).x> x)
	//				return binary(arr, l, mid-1, x);
	//			return binary(arr, mid+1, r, x);
	//		}
	//		return -1;
	//	}

	/// searching for the index of first elment greater than x
	public static int binary1(int[]arr , int x) {
		int low = 0, high = arr.length; // numElems is the size of the array i.e arr.size() 
		while (low != high) {
			int mid = (low + high) / 2; // Or a fancy way to avoid int overflow
			if (arr[mid] <= x) {
				/* This index, and everything below it, must not be the first element
				 * greater than what we're looking for because this element is no greater
				 * than the element.
				 */
				low = mid + 1;
			}
			else {
				/* This element is at least as large as the element, so anything after it can't
				 * be the first element that's at least as large.
				 */
				high = mid;
			}
		}
		return low ; // return high ; 
	}


	////// searching for last element less than X 
	//	public static int binary2(pair[]arr , int x) {
	//		int low = 0, high = arr.length; // numElems is the size of the array i.e arr.size() 
	//		while (low != high) {
	//			int mid = (low + high) / 2; // Or a fancy way to avoid int overflow
	//			if (arr[mid].x >= x) {
	//				/* This index, and everything below it, must not be the first element
	//				 * greater than what we're looking for because this element is no greater
	//				 * than the element.
	//				 */
	//				high=mid;
	//			}
	//			else {
	//				/* This element is at least as large as the element, so anything after it can't
	//				 * be the first element that's at least as large.
	//				 */
	//				low = mid+1 ; 
	//			}
	//		}
	//		return low ; // return high ; 
	//	}







	public static int binary(long []arr , long target , int low , long shift) {
		int high = arr.length; 
		while (low != high) {
			int mid = (low + high) / 2; 
			if (arr[mid]-shift <= target) {
				low = mid + 1;
			}
			else {
				high = mid;
			}
		}
		return low ; // return high ; 
	}
	public static boolean isLetter(char x){
		if(x+0 <=122 && x+0 >=97 )
			return true ;
		else if (x+0 <=90 && x+0 >=65 )
			return true ; 
		else return false; 
	}
	public static long getPrimes(long x ){
		if(x==2 || x==3 || x==1)
			return 2 ;
		if(isPrime(x))
			return 5 ;
		for (int i = 2; i*i<=x; i++)
		{
			if(x%i==0 && isPrime(i))
				return getPrimes(x/i) ;
		}
		return -1;
	}







	public static int lis( int[]a , int n){
		int lis[] = new int[n] ; 
		Arrays.fill(lis,1) ; 

		for(int i=1;i<n;i++)
			for(int j=0 ; j<i; j++)
				if (a[i]>a[j] &&  lis[i] < lis[j]+1)   
					lis[i] = lis[j] + 1;           

		int max = lis[0];

		for(int i=1; i<n ; i++)
			if (max < lis[i])
				max = lis[i] ;
		return (max);

		//			ArrayList<Integer> s = new ArrayList<Integer>() ;
		//			for (int i = n-1; i >=0; i--)
		//			{
		//				if(lis[i]==max)
		//				{
		//					s.add(a[i].z);
		//					max --; 
		//				}
		//			}
		//
		//			for (int i = s.size()-1 ; i>=0 ;  i--)
		//			{
		//				System.out.print(s.get(i)+" ");
		//			}
		//
	}
	public static int calcDepth(Vertix node){
		if(node.depth>0) return node.depth; 
		// meaning it has been updated before;
		if(node.parent != null)
			return 1+ calcDepth(node.parent);
		else
			return -1;
	}

	public static boolean isPrime (long num){
		if (num < 2) return false;
		if (num == 2) return true;
		if (num % 2 == 0) return false;
		for (int i = 3; i * i <= num; i += 2)
			if (num % i == 0) return false;
		return true;
	}


	public static ArrayList<Long> getDiv(Long n)
	{
		ArrayList<Long>  f = new ArrayList<Long>() ; 

		while (n%2==0)
		{
			if(!f.contains(2))f.add((long) 2) ;
			n /= 2;
		}

		// n must be odd at this point.  So we can
		// skip one element (Note i = i +2)
		for (long i = 3; i <= Math.sqrt(n); i+= 2)
		{
			// While i divides n, print i and divide n
			while (n%i == 0)
			{
				if(!f.contains(i))f.add(i);
				n /= i;
			}
		}

		// This condition is to handle the case whien
		// n is a prime number greater than 2
		if (n > 2)
			if(!f.contains(n))f.add(n);


		return f ;



	}

	//		public static boolean dfs(Vertix v , int target){
	//			try{
	//				visited[v.i]= true ;
	//			} catch (NullPointerException e)
	//			{
	//				System.out.println(v.i);
	//			}
	//			if(v.i == target)
	//
	//				return true ;
	//			for (int i =0 ; i< v.neighbours.size() ; i++)
	//			{ 
	//
	//				Vertix child = v.neighbours.get(i) ;
	//				if(child.i == target){
	//					found = true  ; 
	//				}
	//				if(visited[child.i]==false){
	//					found |= dfs(child, target) ;
	//				}
	//			}
	//			return found; 
	//		}









	public static class Vertix{
		long i ; 
		int depth ;
		ArrayList<Vertix> neighbours ; 
		Vertix parent ; 
		Vertix child ; 


		public Vertix(long i){
			this.i = i ;
			this.neighbours = new ArrayList<Vertix> () ;
			this.parent = null ;
			depth =-1;
			this.child = null ;
		}
	}

	public static class pair implements Comparable<pair> {
		long x ; 
		int y ; 




		public pair(long x, int y ){

			this.x=x ; 
			this.y =y ;


		}


		@Override
		public int compareTo(pair p) {
			if(this.x > p.x)
				return 1 ; 
			else if (this.x == p.x) 
				return 0 ; 
			else 
				return -1 ;
		}




	}

	public static class pair2 implements Comparable<pair2>{
		int i ; 
		int j ;
		int plus ;

		public pair2(int i , int j , int plus){
			this.i =i ;
			this.j = j ; 
			this.plus = plus ;
		}

		@Override
		public int compareTo(pair2 p) {
			if(this.j > p.j)
				return 1 ; 
			else if (this.j == p.j) return 0 ;
			else 
				return -1 ;
		}


	}
	public static class point implements  Comparable<point>
	{
		int x, y ; 
		public point(int x,int y){
			this.x=x ; this.y=y;
		}
		@Override
		public boolean equals(Object o) {

			// If the object is compared with itself then return true  
			if (o == this) {
				return true;
			}

			/* Check if o is an instance of Complex or not
	          "null instanceof [type]" also returns false */
			if (!(o instanceof point)) {
				return false;
			}

			// typecast o to Complex so that we can compare data members 
			point c = (point) o;

			// Compare the data members and return accordingly 
			return Integer.compare(x, c.x) == 0
					&& Integer.compare(y, c.y) == 0;
		}
		@Override
		public int compareTo(point p) {
			if(this.x == p.x && this.y ==p.y)
				return 0 ; 
			else
				return -1 ; 
		}

		@Override
		public int hashCode()
		{
			return 15+x+(y%2) ;
		}



	}


}