Problem: There is data on sales of your company. Your task is to write a program which identifies good workers.

The program should read a list of data where each item includes the employee ID i, the amount of sales q and the corresponding unit price p. Then, the program should print IDs of employees whose total sales proceeds (i.e. sum of p × q) is greater than or equal to 1,000,000 in the order of inputting. If there is no such employees, the program should print "NA". You can suppose that n < 4000, and each employee has an unique ID. The unit price p is less than or equal to 1,000,000 and the amount of sales q is less than or equal to 100,000.



Input

The input consists of several datasets. The input ends with a line including a single 0. Each dataset consists of:


n (the number of data in the list)
i p q
i p q
:
:
i p q


Output

For each dataset, print a list of employee IDs or a text "NA"

Example

Input

4
1001 2000 520
1002 1800 450
1003 1600 625
1001 200 1220
2
1001 100 3
1005 1000 100
2
2013 5000 100
2013 5000 100
0


Output

1001
1003
NA
2013

Solution (in CPP):

Solution:
#include <iostream>
#include <math.h>
using namespace std;
int main() {
	while (1) {
		/*for (int i = 0; i < n; i++) {
			e[i] = 0;
		}
		for (int i = 0; i < 4000; i++) {
			m[i] = 0;
			pr[i] = 0;
		}
		na = 1;*/
		int n = 0, p, q, na = 1, e[4000] = {}, pr[4000] = {};
		unsigned long long int m[4000] = {};

		cin >> n;
		if (n == 0)
			break;

		for (int i = 0; i < n; i++) {
			cin >> e[i] >> p >> q;
			m[e[i] - 1] += p * q;
			if (m[e[i] - 1] >= 1000000 && pr[e[i] - 1] == 0) {
				cout << e[i] << endl;
				pr[e[i] - 1] = 1;
				na = 0;
			}
		}
		
		if (na)
			cout << "NA\n";

	}
	return 0;
}