Problem: There is data on sales of your company. Your task is to write a program which identifies good workers.

The program should read a list of data where each item includes the employee ID i, the amount of sales q and the corresponding unit price p. Then, the program should print IDs of employees whose total sales proceeds (i.e. sum of p × q) is greater than or equal to 1,000,000 in the order of inputting. If there is no such employees, the program should print "NA". You can suppose that n < 4000, and each employee has an unique ID. The unit price p is less than or equal to 1,000,000 and the amount of sales q is less than or equal to 100,000.



Input

The input consists of several datasets. The input ends with a line including a single 0. Each dataset consists of:


n (the number of data in the list)
i p q
i p q
:
:
i p q


Output

For each dataset, print a list of employee IDs or a text "NA"

Example

Input

4
1001 2000 520
1002 1800 450
1003 1600 625
1001 200 1220
2
1001 100 3
1005 1000 100
2
2013 5000 100
2013 5000 100
0


Output

1001
1003
NA
2013

Solution (in CPP):

Solution:
#include<iostream>
#include<cstdio>
#include<map>
#include<vector>
using namespace std;
typedef unsigned long long ll;
int main(){
  int n,val,num,inindex;
  vector<int> Index;
  map<int,ll> List;
  while(true){
    scanf("%d",&n);
    if(n == 0)break;
    List.clear();
    Index.clear();
    for(int i=0;i<n;i++){
      scanf("%d %d %d",&inindex,&val,&num);
      if(!List[inindex]){
	Index.push_back(inindex);
      }
      List[inindex]+=val*num;
    }
    bool NAf=true;
    for(int i=0;i<Index.size();i++){
      if(List[Index[i]] >= 1000000){
	printf("%d\n",Index[i]);
	NAf=false;
      }
    }
    if(NAf)printf("NA\n");
  }

  return 0;
}