Problem: Today, Osama gave Fadi an integer X, and Fadi was wondering about the minimum possible value of max(a, b) such that LCM(a, b) equals X. Both a and b should be positive integers.

LCM(a, b) is the smallest positive integer that is divisible by both a and b. For example, LCM(6, 8) = 24, LCM(4, 12) = 12, LCM(2, 3) = 6.

Of course, Fadi immediately knew the answer. Can you be just like Fadi and find any such pair?

Input

The first and only line contains an integer X (1 ≤ X ≤ 10^{12}).

Output

Print two positive integers, a and b, such that the value of max(a, b) is minimum possible and LCM(a, b) equals X. If there are several possible such pairs, you can print any.

Examples

Input


2


Output


1 2


Input


6


Output


2 3


Input


4


Output


1 4


Input


1


Output


1 1

Solution (in PYTHON3):

Solution:
def gcd(a, b):
    while b:
        a, b = b, a%b
    return a

def lcm(a, b):
    return a*b//gcd(a, b)

X = int(input())
M = X
ans_a = 1
ans_b = X

for i in range(1, int(X**0.5)+1):
    if X%i==0:
        a = i
        b = X//i
        
        if lcm(a, b)!=X:
            continue
        
        if M>max(a, b):
            M = max(a, b)
            ans_a = a
            ans_b = b

print(ans_a, ans_b)