Problem: There is data on sales of your company. Your task is to write a program which identifies good workers.

The program should read a list of data where each item includes the employee ID i, the amount of sales q and the corresponding unit price p. Then, the program should print IDs of employees whose total sales proceeds (i.e. sum of p × q) is greater than or equal to 1,000,000 in the order of inputting. If there is no such employees, the program should print "NA". You can suppose that n < 4000, and each employee has an unique ID. The unit price p is less than or equal to 1,000,000 and the amount of sales q is less than or equal to 100,000.



Input

The input consists of several datasets. The input ends with a line including a single 0. Each dataset consists of:


n (the number of data in the list)
i p q
i p q
:
:
i p q


Output

For each dataset, print a list of employee IDs or a text "NA"

Example

Input

4
1001 2000 520
1002 1800 450
1003 1600 625
1001 200 1220
2
1001 100 3
1005 1000 100
2
2013 5000 100
2013 5000 100
0


Output

1001
1003
NA
2013

Solution (in PYTHON3):

Solution:
n = int(input())
while n != 0:
	earnings = []
	for i in range(0,n):
		a = str.split(input(),' ')
		if i > 0 :
			for j in range(0,len(earnings)):
				if a[0] == earnings[j][0]:
					earnings[j][1] = str(int(earnings[j][1])+(int(a[1])*int(a[2])))
					break
				if j == len(earnings) - 1:earnings.append([a[0],str(int(a[1])*int(a[2]))])
		else:earnings.append([a[0],str(int(a[1])*int(a[2]))])
	milionear = []
	for i in range(0,len(earnings)):
		if int(earnings[i][1]) >= 1e6:
			milionear.append(earnings[i][0])
	if len(milionear) == 0 : print('NA')
	else:
		for i in range(0,len(milionear)):
			print(milionear[i])
	n = int(input())