Problem: Arpa is taking a geometry exam. Here is the last problem of the exam.

You are given three points a, b, c.

Find a point and an angle such that if we rotate the page around the point by the angle, the new position of a is the same as the old position of b, and the new position of b is the same as the old position of c.

Arpa is doubting if the problem has a solution or not (i.e. if there exists a point and an angle satisfying the condition). Help Arpa determine if the question has a solution or not.

Input

The only line contains six integers ax, ay, bx, by, cx, cy (|ax|, |ay|, |bx|, |by|, |cx|, |cy| ≤ 109). It's guaranteed that the points are distinct.

Output

Print "Yes" if the problem has a solution, "No" otherwise.

You can print each letter in any case (upper or lower).

Examples

Input

0 1 1 1 1 0


Output

Yes


Input

1 1 0 0 1000 1000


Output

No

Note

In the first sample test, rotate the page around (0.5, 0.5) by <image>.

In the second sample test, you can't find any solution.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int main() {
  int ax, ay, bx, by, cx, cy;
  cin >> ax >> ay >> bx >> by >> cx >> cy;
  if ((pow(ax - bx, 2) + pow(ay - by, 2)) ==
      (pow(cx - bx, 2) + pow(cy - by, 2))) {
    double k1, k2;
    if (ay == by) {
      k2 = (cy - by) * 1.0 / (cx - bx);
      if (k2 != 0) {
        cout << "Yes" << endl;
      } else {
        cout << "No" << endl;
      }
    } else if (by == cy) {
      k1 = (by - ay) * 1.0 / (bx - ax);
      if (k1 != 0) {
        cout << "Yes" << endl;
      } else
        cout << "No" << endl;
    } else if (ay != by && by != cy) {
      k1 = (by - ay) * 1.0 / (bx - ax);
      k2 = (cy - by) * 1.0 / (cx - bx);
      if (k1 == k2) {
        cout << "No" << endl;
      } else
        cout << "Yes" << endl;
    } else
      cout << "No" << endl;
  } else
    cout << "No" << endl;
  return 0;
}