Problem: There is data on sales of your company. Your task is to write a program which identifies good workers.

The program should read a list of data where each item includes the employee ID i, the amount of sales q and the corresponding unit price p. Then, the program should print IDs of employees whose total sales proceeds (i.e. sum of p × q) is greater than or equal to 1,000,000 in the order of inputting. If there is no such employees, the program should print "NA". You can suppose that n < 4000, and each employee has an unique ID. The unit price p is less than or equal to 1,000,000 and the amount of sales q is less than or equal to 100,000.



Input

The input consists of several datasets. The input ends with a line including a single 0. Each dataset consists of:


n (the number of data in the list)
i p q
i p q
:
:
i p q


Output

For each dataset, print a list of employee IDs or a text "NA"

Example

Input

4
1001 2000 520
1002 1800 450
1003 1600 625
1001 200 1220
2
1001 100 3
1005 1000 100
2
2013 5000 100
2013 5000 100
0


Output

1001
1003
NA
2013

Solution (in CPP):

Solution:
#include <bits/stdc++.h>

using namespace std;

typedef long long ll;

int n;
ll need = (int)1e6;

int main() {
	while (1) {
		cin >> n; if (n == 0) break;
		
		map<ll, ll> sum;
		vector<ll> ids;
		for (int i = 0; i < n; i++) {
			ll id, p, q; cin >> id >> p >> q;
			bool add = true;
			for (int j = 0; j < (int)ids.size(); j++) {
				if (ids[j] == id) add = false;
			}
			if (add) ids.push_back(id);
			sum[id] += (p * q);
		}
		
		bool na = true;
		for (int i = 0; i < (int)ids.size(); i++) {
			if (sum[ids[i]] >= need) {
				cout << ids[i] << endl;
				na = false;
			}
		}
		
		if (na) cout << "NA" << endl;
	}
	
	return 0;
}