Problem: Arpa is taking a geometry exam. Here is the last problem of the exam.

You are given three points a, b, c.

Find a point and an angle such that if we rotate the page around the point by the angle, the new position of a is the same as the old position of b, and the new position of b is the same as the old position of c.

Arpa is doubting if the problem has a solution or not (i.e. if there exists a point and an angle satisfying the condition). Help Arpa determine if the question has a solution or not.

Input

The only line contains six integers ax, ay, bx, by, cx, cy (|ax|, |ay|, |bx|, |by|, |cx|, |cy| ≤ 109). It's guaranteed that the points are distinct.

Output

Print "Yes" if the problem has a solution, "No" otherwise.

You can print each letter in any case (upper or lower).

Examples

Input

0 1 1 1 1 0


Output

Yes


Input

1 1 0 0 1000 1000


Output

No

Note

In the first sample test, rotate the page around (0.5, 0.5) by <image>.

In the second sample test, you can't find any solution.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
string mirror = "AHIMOTUVWXY";
string letter = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
int main() {
  long long n, m, i, j, k, x, y, z, t;
  long long ax, bx, cx, ay, by, cy;
  cin >> ax >> ay >> bx >> by >> cx >> cy;
  long long ab = (ax - bx) * (ax - bx) + (ay - by) * (ay - by);
  long long bc = (bx - cx) * (bx - cx) + (by - cy) * (by - cy);
  if (ab == bc) {
    if ((by - ay) * (cx - ax) == ((bx - ax) * (cy - ay)))
      printf("NO\n");
    else
      printf("YES\n");
  } else {
    printf("NO\n");
  }
}