Problem: Ron is a happy owner of a permutation a of length n.

A permutation of length n is an array consisting of n distinct integers from 1 to n in arbitrary order. For example, [2,3,1,5,4] is a permutation, but [1,2,2] is not a permutation (2 appears twice in the array) and [1,3,4] is also not a permutation (n=3 but there is 4 in the array).

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Ron's permutation is subjected to m experiments of the following type: (r_i, p_i). This means that elements in range [1, r_i] (in other words, the prefix of length r_i) have to be sorted in ascending order with the probability of p_i. All experiments are performed in the same order in which they are specified in the input data.

As an example, let's take a look at a permutation [4, 2, 1, 5, 3] and an experiment (3, 0.6). After such an experiment with the probability of 60\% the permutation will assume the form [1, 2, 4, 5, 3] and with a 40\% probability it will remain unchanged.

You have to determine the probability of the permutation becoming completely sorted in ascending order after m experiments.

Input

Each test contains one or more test cases. The first line contains the number of test cases t (1 ≤ t ≤ 100).

The first line of each test case contains two integers n and m (1 ≤ n, m ≤ 10^5) — the length of the permutation and the number of experiments, respectively.

The second line of each test case contains n integers a_1, a_2, …, a_n (1 ≤ a_i ≤ n) — contents of the permutation.

The following m lines of each test case each contain an integer r_i and a real number p_i (1 ≤ r_i ≤ n, 0 ≤ p_i ≤ 1) — the length of the prefix and the probability of it being sorted. All probabilities are given with at most 6 decimal places.

It is guaranteed that the sum of n and the sum of m does not exceed 10^5 (∑ n, ∑ m ≤ 10^5).

Output

For each test case, print a single number — the probability that after all experiments the permutation becomes sorted in ascending order. Your answer will be considered correct if its absolute or relative error does not exceed 10^{-6}.

Formally, let your answer be a, and the jury's answer be b. Your answer is accepted if and only if \frac{|a - b|}{max{(1, |b|)}} ≤ 10^{-6}.

Example

Input


4
4 3
4 3 2 1
1 0.3
3 1
4 0.6
5 3
4 2 1 3 5
3 0.8
4 0.6
5 0.3
6 5
1 3 2 4 5 6
4 0.9
5 0.3
2 0.4
6 0.7
3 0.5
4 2
1 2 3 4
2 0.5
4 0.1


Output


0.600000
0.720000
0.989500
1.000000

Note

Explanation of the first test case: It can be demonstrated that whether the final permutation is sorted or not depends solely on sorting being performed in the (4, 0.6) experiment.

Solution (in JAVA):

Solution:
import java.util.*;
import java.io.*;
import static java.lang.Math.*;
public class C
{
    static InputReader in=new InputReader(System.in);
    static OutputWriter out=new OutputWriter(System.out);
    static StringBuilder sb=new StringBuilder();
    static long MOD = (long)(998244353);
    static Scanner ob  = new Scanner(System.in);

    // Main Class Starts Here
    public static void main(String args[])throws IOException
    {
        // Write your code.
        int t = ob.nextInt();
        while(t-->0) {
            int n = ob.nextInt();
            int m = ob.nextInt();
            int a[] = new int[n+1];
            for(int i = 1 ;i <= n; i++) a[i] = ob.nextInt();
            // check till where sorted.
            int bit[] = new int[n+2];
            int count = 0;
            for(int i = n; i >= 1 ;i--){
                if(a[i] == i){
                    bit[i] = 1;
                    count++;
                }
                else{
                    break;
                }
            }

            bit[n+1] = 1;

            double ans = 0.0D;
            double pref = 1.0D;

            for(int i = 0; i < m; i++){
                int r = ob.nextInt();
                double p = ob.nextDouble();
                if(bit[r+1] == 0)
                    p = 0.0D;
                ans += (pref * p);
                pref *= (1.0D - p);
            }

            if(count == n){
                app("1.000000\n");
                continue;
            }            

            app(String.format("%.6f", ans)+"\n");
        }
        out.printLine(sb);
        out.close();
    }

    public static int[] an(int n) {
        int ar[]=new int[n];
        for(int i=0;i<n;i++)
            ar[i]=in();
        return ar;
    }

    public static long[] lan(int n) {
        long ar[]=new long[n];
        for(int i=0;i<n;i++)
            ar[i]=lin();
        return ar;
    }

    public static String atos(Object ar[]) {
        return Arrays.toString(ar);
    }

    public static int in() {
        return in.readInt();
    }

    public static long lin() {
        return in.readLong();
    }

    public static String sn() {
        return in.readString();
    }

    public static void prln(Object o) {
        out.printLine(o);
    }

    public static void prn(Object o) {
        out.print(o);
    }

    public static void display(int a[]) {
        out.printLine(Arrays.toString(a));
    }

    public static HashMap<Integer,Integer> hm(int a[]){
        HashMap<Integer,Integer> map=new HashMap<>();
        for(int i=0; i < a.length;i++) {
            int keep = (int)map.getOrDefault(a[i],0);
            map.put(a[i],++keep);
        }
        return map;
    }

    public static void app(Object o) {
        sb.append(o);
    }

    public static long calcManhattanDist(int x1,int y1,int x2,int y2) {
        long xa = Math.abs(x1-x2);
        long ya = Math.abs(y1-y2);
        return (xa+ya);
    }


    static class InputReader {
        private InputStream stream;
        private byte[] buf = new byte[1024];
        private int curChar;
        private int numChars;
        private SpaceCharFilter filter;

        public InputReader(InputStream stream) {
            this.stream = stream;
        }

        public int read() {
            if (numChars == -1)
                throw new InputMismatchException();
            if (curChar >= numChars) {
                curChar = 0;
                try {
                    numChars = stream.read(buf);
                } catch (IOException e) {
                    throw new InputMismatchException();
                }
                if (numChars <= 0)
                    return -1;
            }
            return buf[curChar++];
        }

        public int readInt() {
            int c = read();
            while (isSpaceChar(c))
                c = read();
            int sgn = 1;
            if (c == '-') {
                sgn = -1;
                c = read();
            }
            int res = 0;
            do {
                if (c < '0' || c > '9')
                    throw new InputMismatchException();
                res *= 10;
                res += c - '0';
                c = read();
            } while (!isSpaceChar(c));
            return res * sgn;
        }

        public long readLong() {
            int c = read();
            while (isSpaceChar(c))
                c = read();
            int sgn = 1;
            if (c == '-') {
                sgn = -1;
                c = read();
            }
            long res = 0;
            do {
                if (c < '0' || c > '9')
                    throw new InputMismatchException();
                res *= 10;
                res += c - '0';
                c = read();
            } while (!isSpaceChar(c));
            return res * sgn;
        }

        public String readString() {
            int c = read();
            while (isSpaceChar(c))
                c = read();
            StringBuilder res = new StringBuilder();
            do {
                res.appendCodePoint(c);
                c = read();
            } while (!isSpaceChar(c));
            return res.toString();
        }

        public boolean isSpaceChar(int c) {
            if (filter != null)
                return filter.isSpaceChar(c);
            return c == ' ' || c == '\n' || c == '\r' || c == '\t' || c == -1;
        }

        public String next() {
            return readString();
        }

        public interface SpaceCharFilter {
            public boolean isSpaceChar(int ch);
        }
    }

    static class OutputWriter {
        private final PrintWriter writer;

        public OutputWriter(OutputStream outputStream) {
            writer = new PrintWriter(new BufferedWriter(new OutputStreamWriter(outputStream)));
        }

        public OutputWriter(Writer writer) {
            this.writer = new PrintWriter(writer);
        }

        public void print(Object...objects) {
            for (int i = 0; i < objects.length; i++) {
                if (i != 0)
                    writer.print(' ');
                writer.print(objects[i]);
            }
        }

        public void printLine(Object...objects) {
            print(objects);
            writer.println();
        }

        public void close() {
            writer.close();
        }
    }
}