Problem: Today, Osama gave Fadi an integer X, and Fadi was wondering about the minimum possible value of max(a, b) such that LCM(a, b) equals X. Both a and b should be positive integers.

LCM(a, b) is the smallest positive integer that is divisible by both a and b. For example, LCM(6, 8) = 24, LCM(4, 12) = 12, LCM(2, 3) = 6.

Of course, Fadi immediately knew the answer. Can you be just like Fadi and find any such pair?

Input

The first and only line contains an integer X (1 ≤ X ≤ 10^{12}).

Output

Print two positive integers, a and b, such that the value of max(a, b) is minimum possible and LCM(a, b) equals X. If there are several possible such pairs, you can print any.

Examples

Input


2


Output


1 2


Input


6


Output


2 3


Input


4


Output


1 4


Input


1


Output


1 1

Solution (in PYTHON3):

Solution:

def nod(a, b):
    while a > 0 and b > 0:
        if a > b:
            a %= b
        else:
            b %= a
    return max(a, b)


m = 10 ** 13
q1 = -1
i1 = -1
x = int(input())

sqrtx = int(x ** 0.5)
for i in range(1, sqrtx + 1):
    if x % i == 0:
        q = x // i
        if nod(q, i) * x == i * q and m > max(q, i):
            m = max(q, i)
            q1 = q
            i1 = i
print(q1, i1)