Problem: There is data on sales of your company. Your task is to write a program which identifies good workers.

The program should read a list of data where each item includes the employee ID i, the amount of sales q and the corresponding unit price p. Then, the program should print IDs of employees whose total sales proceeds (i.e. sum of p × q) is greater than or equal to 1,000,000 in the order of inputting. If there is no such employees, the program should print "NA". You can suppose that n < 4000, and each employee has an unique ID. The unit price p is less than or equal to 1,000,000 and the amount of sales q is less than or equal to 100,000.



Input

The input consists of several datasets. The input ends with a line including a single 0. Each dataset consists of:


n (the number of data in the list)
i p q
i p q
:
:
i p q


Output

For each dataset, print a list of employee IDs or a text "NA"

Example

Input

4
1001 2000 520
1002 1800 450
1003 1600 625
1001 200 1220
2
1001 100 3
1005 1000 100
2
2013 5000 100
2013 5000 100
0


Output

1001
1003
NA
2013

Solution (in CPP):

Solution:
#include <stdio.h>
 
 

 
int main(void){
	int i,j,k;
	int n,num[4000];
	long long int tanka,sale_num,sale_sum[4000],sale_all[4001];
	bool judge[4001];
	
	while(scanf("%d",&n),n){
		
		//初期化

		k=0;
		for(j=0;j<=4001;j++){
			judge[j]=0;
			sale_all[j]=0;
		}
		
		for(i=0;i<n;i++){
			scanf("%d %lld %lld",&num[i],&tanka,&sale_num);
			sale_sum[i]=tanka*sale_num;
		}
		
		
		//idに対応したsaleに+
		for(i=0;i<n;i++){
			sale_all[num[i]] = sale_all[num[i]] + sale_sum[i];
		}
		
		for(i=0;i<n;i++){
			if((sale_all[num[i]] >= 1000000)&&(judge[num[i]]==0)){
				printf("%d\n",num[i]);
				judge[num[i]]=1;
				k=1;
			}
		}
		
		if(k!=1)printf("NA\n");
	}
	
	return 0;
}