Problem: George is a cat, so he really likes to play. Most of all he likes to play with his array of positive integers b. During the game, George modifies the array by using special changes. Let's mark George's current array as b1, b2, ..., b|b| (record |b| denotes the current length of the array). Then one change is a sequence of actions: 

  * Choose two distinct indexes i and j (1 ≤ i, j ≤ |b|; i ≠ j), such that bi ≥ bj. 
  * Get number v = concat(bi, bj), where concat(x, y) is a number obtained by adding number y to the end of the decimal record of number x. For example, concat(500, 10) = 50010, concat(2, 2) = 22. 
  * Add number v to the end of the array. The length of the array will increase by one. 
  * Remove from the array numbers with indexes i and j. The length of the array will decrease by two, and elements of the array will become re-numbered from 1 to current length of the array. 



George played for a long time with his array b and received from array b an array consisting of exactly one number p. Now George wants to know: what is the maximum number of elements array b could contain originally? Help him find this number. Note that originally the array could contain only positive integers.

Input

The first line of the input contains a single integer p (1 ≤ p < 10100000). It is guaranteed that number p doesn't contain any leading zeroes.

Output

Print an integer — the maximum number of elements array b could contain originally.

Examples

Input

9555


Output

4

Input

10000000005


Output

2

Input

800101


Output

3

Input

45


Output

1

Input

1000000000000001223300003342220044555


Output

17

Input

19992000


Output

1

Input

310200


Output

2

Note

Let's consider the test examples: 

  * Originally array b can be equal to {5, 9, 5, 5}. The sequence of George's changes could have been: {5, 9, 5, 5} → {5, 5, 95} → {95, 55} → {9555}. 
  * Originally array b could be equal to {1000000000, 5}. Please note that the array b cannot contain zeros. 
  * Originally array b could be equal to {800, 10, 1}. 
  * Originally array b could be equal to {45}. It cannot be equal to {4, 5}, because George can get only array {54} from this array in one operation. 



Note that the numbers can be very large.

Solution (in JAVA):

Solution:
import java.util.*;
import java.io.*;
import java.math.BigInteger;
 
public class tr0 {
	static PrintWriter out;
	static StringBuilder sb;
	static final double EPS = 1e-9;
	static long mod = (int) 1e9 + 7;
	static int inf = (int) 1e9 + 2;
	static long[] fac;
	static int[] si;
	static ArrayList<Integer> primes;
	static ArrayList<Integer>[] ad;
	static ArrayList<pair>[] d;
	static edge[] ed;
	static boolean []vis;
	static int[] l, ch;
	static int[] occ;
	static Queue<Integer>[] can;
	static String s;
	public static void main(String[] args) throws Exception {
		Scanner sc = new Scanner(System.in);
		out = new PrintWriter(System.out);
		String h=sc.next();
		int n=0;
		for(int i=0;i<h.length();i++) {
			if(h.charAt(i)!='0')
				n++;
		}
		int id=0;
		StringBuilder []a=new StringBuilder [n];
		for(int i=0;i<h.length();i++) {
			a[id]=new StringBuilder();
			a[id].append(h.charAt(i));
			i++;
			while(i<h.length() && h.charAt(i)=='0') {
				a[id].append(h.charAt(i));
				i++;
			}
		//	if(a[id].length()>1) {
				i--;
			//}
			id++;
		}
		sb=new StringBuilder();
		int tt=1;
		sb.append(a[0]);
		for(int i=1;i<n;i++) {
			 boolean t=false;
			 if(a[i].length()>sb.length()) {
				 t=true;
				 
			 }
			 else  if(a[i].length()==sb.length()){
				 for(int j=0;j<a[i].length();j++) {
					 if(a[i].charAt(j)>sb.charAt(j)) {
						 t=true;
						 break;
					 }
					 else if(a[i].charAt(j)<sb.charAt(j)) {
						 t=false;
						 break;
					 }
				 }
			 }
	            if(t) {
	            	tt=i+1;
	            }
	            sb.append(a[i]);
		}
		out.print(n-tt+1);
		out.close();
	}
	static int se;

	static long inver(long x,long kk) {
		int a = (int) x;
		long e = (kk - 2);
		long res = 1;
		while (e > 0) {
			if ((e & 1) == 1) {
				// System.out.println(res*a);
				res = (int) ((1l * res * a) % kk);
			}
			a = (int) ((1l * a * a) % kk);
			e >>= 1;
		}
		// out.println(res+" "+x);
		return res % kk;
	}
 
	static TreeSet<Integer> trr;
    static void dfs(int v) {
    	se++;
    	vis[v]=true;
    	for(int d:ad[v])
    		if(!vis[d])
    			dfs(d);
    }
	static class qu  implements Comparable<qu>{
		int i,j;
		qu(int a, int s) {
			i=a;
			j=s;
		}
       public String toString() {
    	   return i+" "+j;
       }
       public int compareTo(qu o) {
    	   if(i==o.i)
    		   return j-o.j;
    	   return i-o.i;
       }
	}
    
	static class pair {
		int to;
		int number;
 
		pair(int t, int n) {
			number = n;
			to = t;
		}
 
		public String toString() {
			return to + " " + number;
		}
	}
 
	static double modPow(double a, int e)
 
	{
		double res = 1;
		while (e > 0) {
			if ((e & 1) == 1)
				res = (res * a);
			a = (a * a);
			e >>= 1;
		}
		return res;
	}
 
	static boolean[] in;
 
	/*
	 * static void mst() { Arrays.sort(ed); UnionFind uf=new UnionFind(n); for(int
	 * i=0;i<m;i++) { edge w=ed[i]; if(!uf.union(w.from, w.to)) continue;
	 * in[i]=true; } }
	 */
	static class edge implements Comparable<edge> {
		int from;
		int to;
		int number;
 
		edge(int f, int t, int n) {
			from = f;
			to = t;
			number = n;
		}
 
		public String toString() {
			return from + " " + to + " " + number;
		}
 
		public int compareTo(edge f) {
			return number - f.number;
		}
	}
 
	static class seg implements Comparable<seg> {
		int a;
		int b;
 
		seg(int s, int e) {
			a = s;
			b = e;
		}
 
		public String toString() {
			return a + " " + b;
		}
 
		public int compareTo(seg o) {
			// if(a==o.a)
			return o.b - b;
			// return
		}
	}
 
	static long power(int i) {
		// if(i==0)
		// return 1;
		long a = 1;
		for (int k = 0; k < i; k++)
			a *= i;
		return a;
	}
 
	static void seive() {
		si = new int[1000001];
		primes = new ArrayList<>();
		int N = 1000001;
		si[1] = 1;
		for (int i = 2; i < N; i++) {
			if (si[i] == 0) {
				si[i] = i;
				primes.add(i);
			}
			for (int j = 0; j < primes.size() && primes.get(j) <= si[i] && (i * primes.get(j)) < N; j++)
				si[primes.get(j) * i] = primes.get(j);
 
		}
	}
	static long fac(int n) {
		if (n == 0)
			return fac[n] = 1;
		if (n == 1)
			return fac[n] = 1;
		long ans = 1;
		for (int i = 1; i <= n; i++)
			fac[i] = ans = (i % mod * ans % mod) % mod;
		return ans % mod;
	}
 
	static long gcd(long a, long b) {
 
		if (b == 0)
			return a;
		return gcd(b, a % b);
	}
 
	static class unionfind {
		int[] p;
		int[] size;
 
		unionfind(int n) {
			p = new int[n];
			size = new int[n];
 
			for (int i = 0; i < n; i++) {
				p[i] = i;
			}
			Arrays.fill(size, 1);
		}
 
		int findSet(int v) {
			if (v == p[v])
				return v;
			return p[v] = findSet(p[v]);
		}
 
		boolean sameSet(int a, int b) {
			a = findSet(a);
			b = findSet(b);
			if (a == b)
				return true;
			return false;
		}
 
		int max() {
			int max = 0;
			for (int i = 0; i < size.length; i++)
				if (size[i] > max)
					max = size[i];
			return max;
		}
 
		boolean combine(int a, int b) {
			a = findSet(a);
			b = findSet(b);
			if (a == b)
				return true;
			if (size[a] > size[b]) {
				p[b] = a;
				size[a] += size[b];
 
			} else {
				p[a] = b;
				size[b] += size[a];
			}
			return false;
		}
	}
 
	static class Scanner {
		StringTokenizer st;
		BufferedReader br;
 
		public Scanner(InputStream system) {
			br = new BufferedReader(new InputStreamReader(system));
		}
 
		public Scanner(String file) throws Exception {
			br = new BufferedReader(new FileReader(file));
		}
 
		public String next() throws IOException {
			while (st == null || !st.hasMoreTokens())
				st = new StringTokenizer(br.readLine());
			return st.nextToken();
		}
 
		public String nextLine() throws IOException {
			return br.readLine();
		}
 
		public int nextInt() throws IOException {
			return Integer.parseInt(next());
		}
 
		public double nextDouble() throws IOException {
			return Double.parseDouble(next());
		}
 
		public char nextChar() throws IOException {
			return next().charAt(0);
		}
 
		public Long nextLong() throws IOException {
			return Long.parseLong(next());
		}
 
		public boolean ready() throws IOException {
			return br.ready();
		}
 
		public void waitForInput() throws InterruptedException {
			Thread.sleep(3000);
		}
	}
}