Problem: Today, Osama gave Fadi an integer X, and Fadi was wondering about the minimum possible value of max(a, b) such that LCM(a, b) equals X. Both a and b should be positive integers.

LCM(a, b) is the smallest positive integer that is divisible by both a and b. For example, LCM(6, 8) = 24, LCM(4, 12) = 12, LCM(2, 3) = 6.

Of course, Fadi immediately knew the answer. Can you be just like Fadi and find any such pair?

Input

The first and only line contains an integer X (1 ≤ X ≤ 10^{12}).

Output

Print two positive integers, a and b, such that the value of max(a, b) is minimum possible and LCM(a, b) equals X. If there are several possible such pairs, you can print any.

Examples

Input


2


Output


1 2


Input


6


Output


2 3


Input


4


Output


1 4


Input


1


Output


1 1

Solution (in PYTHON3):

Solution:
n=int(input())
i=1
d=[]
while i*i<=n:
    if n%i==0:d.append(i)
    i+=1
d.reverse()
def gcd(a,b):
    if a>b:a,b=b,a,
    while b:
        a,b=b,a%b
    return a
def lcm(a,b):
    return a*b//gcd(a,b)
for u in d:
    if lcm(u,n//u)==n:
        print(u,n//u)
        exit(0)