Problem: Today, Osama gave Fadi an integer X, and Fadi was wondering about the minimum possible value of max(a, b) such that LCM(a, b) equals X. Both a and b should be positive integers.

LCM(a, b) is the smallest positive integer that is divisible by both a and b. For example, LCM(6, 8) = 24, LCM(4, 12) = 12, LCM(2, 3) = 6.

Of course, Fadi immediately knew the answer. Can you be just like Fadi and find any such pair?

Input

The first and only line contains an integer X (1 ≤ X ≤ 10^{12}).

Output

Print two positive integers, a and b, such that the value of max(a, b) is minimum possible and LCM(a, b) equals X. If there are several possible such pairs, you can print any.

Examples

Input


2


Output


1 2


Input


6


Output


2 3


Input


4


Output


1 4


Input


1


Output


1 1

Solution (in PYTHON3):

Solution:
def hcf(a,b):
    if a>b:
        c=a%b
    else:
        c=b%a
    if c==0:
        return min(a,b)
    else:
        return hcf(min(a,b),c)
n=int(input())
j=int(n**0.5)
mx=1
if j**2!=n:
    for i in range(1,j+1):
        if n%i==0 and hcf(i,int(n/i))==1:
            mx=i
else:
    for i in range(1,j):
        if n%i==0 and hcf(i,int(n/i))==1:
            mx=i
print(str(mx)+" "+str(int(n/mx)))