Problem: Today, Osama gave Fadi an integer X, and Fadi was wondering about the minimum possible value of max(a, b) such that LCM(a, b) equals X. Both a and b should be positive integers.

LCM(a, b) is the smallest positive integer that is divisible by both a and b. For example, LCM(6, 8) = 24, LCM(4, 12) = 12, LCM(2, 3) = 6.

Of course, Fadi immediately knew the answer. Can you be just like Fadi and find any such pair?

Input

The first and only line contains an integer X (1 ≤ X ≤ 10^{12}).

Output

Print two positive integers, a and b, such that the value of max(a, b) is minimum possible and LCM(a, b) equals X. If there are several possible such pairs, you can print any.

Examples

Input


2


Output


1 2


Input


6


Output


2 3


Input


4


Output


1 4


Input


1


Output


1 1

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
long long gcd(long long a, long long b) {
  if (a < b) swap(a, b);
  long long r = a % b;
  while (r) {
    a = b;
    b = r;
    r = a % b;
  }
  return b;
}
int main() {
  long long X;
  cin >> X;
  long long a = 1;
  long long b = X;
  for (long long i = 1; i * i <= X; i++) {
    long long j = X / i;
    if (i * j != X || gcd(i, j) != 1) continue;
    if (max(a, b) > max(i, j)) {
      a = i;
      b = j;
    }
  }
  cout << a << ' ' << b << endl;
}