Problem: Today, Osama gave Fadi an integer X, and Fadi was wondering about the minimum possible value of max(a, b) such that LCM(a, b) equals X. Both a and b should be positive integers.

LCM(a, b) is the smallest positive integer that is divisible by both a and b. For example, LCM(6, 8) = 24, LCM(4, 12) = 12, LCM(2, 3) = 6.

Of course, Fadi immediately knew the answer. Can you be just like Fadi and find any such pair?

Input

The first and only line contains an integer X (1 ≤ X ≤ 10^{12}).

Output

Print two positive integers, a and b, such that the value of max(a, b) is minimum possible and LCM(a, b) equals X. If there are several possible such pairs, you can print any.

Examples

Input


2


Output


1 2


Input


6


Output


2 3


Input


4


Output


1 4


Input


1


Output


1 1

Solution (in PYTHON3):

Solution:
def HCF(a, b):
	a1 = max(a, b)
	b1 = min(a, b)
	while b1:
		a1, b1 = b1, a1%b1
	return a1

def pairs(n):
    for i in range(int(n**0.5) + 1, -1, -1):
            if n%i == 0 and HCF(n // i, i) == 1:
                    print(n // i, i)
                    break
	    
n = int(input())
pairs(n)