Problem: There is data on sales of your company. Your task is to write a program which identifies good workers.

The program should read a list of data where each item includes the employee ID i, the amount of sales q and the corresponding unit price p. Then, the program should print IDs of employees whose total sales proceeds (i.e. sum of p × q) is greater than or equal to 1,000,000 in the order of inputting. If there is no such employees, the program should print "NA". You can suppose that n < 4000, and each employee has an unique ID. The unit price p is less than or equal to 1,000,000 and the amount of sales q is less than or equal to 100,000.



Input

The input consists of several datasets. The input ends with a line including a single 0. Each dataset consists of:


n (the number of data in the list)
i p q
i p q
:
:
i p q


Output

For each dataset, print a list of employee IDs or a text "NA"

Example

Input

4
1001 2000 520
1002 1800 450
1003 1600 625
1001 200 1220
2
1001 100 3
1005 1000 100
2
2013 5000 100
2013 5000 100
0


Output

1001
1003
NA
2013

Solution (in CPP):

Solution:
#include <iostream>
#include <map>
#include <vector>
using namespace std;

int main(){
	int n,number;
	long long a,b;
	bool flag;
	map<int,long long> info;
	vector<int> seq;
	
	while(cin >> n && n){
		info.clear();
		seq.clear();
		while(n--){
			cin >> number >> a >> b;
			if(!info[number])seq.push_back(number); // 既出だったら表示順記録配列に入れない。単価0円ケースを考慮してません。
			info[number] += a*b;
		}
		flag = true;
		for(int i=0;i<seq.size();i++){
			if(info[seq[i]]>=1000000){
				flag = false;
				cout << seq[i] << endl;
			}
		}
		if(flag)cout << "NA" << endl;
	}
}