Problem: Arpa is taking a geometry exam. Here is the last problem of the exam.

You are given three points a, b, c.

Find a point and an angle such that if we rotate the page around the point by the angle, the new position of a is the same as the old position of b, and the new position of b is the same as the old position of c.

Arpa is doubting if the problem has a solution or not (i.e. if there exists a point and an angle satisfying the condition). Help Arpa determine if the question has a solution or not.

Input

The only line contains six integers ax, ay, bx, by, cx, cy (|ax|, |ay|, |bx|, |by|, |cx|, |cy| ≤ 109). It's guaranteed that the points are distinct.

Output

Print "Yes" if the problem has a solution, "No" otherwise.

You can print each letter in any case (upper or lower).

Examples

Input

0 1 1 1 1 0


Output

Yes


Input

1 1 0 0 1000 1000


Output

No

Note

In the first sample test, rotate the page around (0.5, 0.5) by <image>.

In the second sample test, you can't find any solution.

Solution (in PYTHON3):

Solution:
"""Ý tưởng, Nằm trên đường tròn tâm là điểm thứ 2 và 2 điểm """
ax, ay, bx, by, cx, cy = input().split()
ax, ay, bx, by, cx, cy = int(ax), int(ay), int(bx), int(by), int(cx), int(cy)

distant_1 = (ax - bx) ** 2 + (ay - by) ** 2
distant_2 = (bx - cx) ** 2 + (by - cy) ** 2

"""Vector AB và BC kiểm tra thẳng hàng"""
abx = bx - ax
aby = by - ay
bcx = cx - bx
bcy = cy - by

"""Không chia được thì nhân, vì số 0 thì không chia được"""
if distant_1 != distant_2:
    print('No')
if distant_1 == distant_2:
    if abx * bcy == aby * bcx:
        print('No')
    else:
        print('Yes')