Problem: Today, Osama gave Fadi an integer X, and Fadi was wondering about the minimum possible value of max(a, b) such that LCM(a, b) equals X. Both a and b should be positive integers.

LCM(a, b) is the smallest positive integer that is divisible by both a and b. For example, LCM(6, 8) = 24, LCM(4, 12) = 12, LCM(2, 3) = 6.

Of course, Fadi immediately knew the answer. Can you be just like Fadi and find any such pair?

Input

The first and only line contains an integer X (1 ≤ X ≤ 10^{12}).

Output

Print two positive integers, a and b, such that the value of max(a, b) is minimum possible and LCM(a, b) equals X. If there are several possible such pairs, you can print any.

Examples

Input


2


Output


1 2


Input


6


Output


2 3


Input


4


Output


1 4


Input


1


Output


1 1

Solution (in PYTHON3):

Solution:
import math

def lcm(a,b):
    g = math.gcd(max(a,b),min(a,b))
    return a*b//g

def main():
    x = int(input())
    facts = []
    for i in range(1,int(x**0.5)+1):
        if x%i == 0:
            facts.append([i,x//i])

    min_val = float('inf')
    a = -1
    b = -1
    for i in facts:
        if max(i) < min_val and lcm(i[0],i[1]) == x:
            min_val = max(i)
            a = i[0]
            b = i[1]

    print(a,b)

main()