Problem: Today, Osama gave Fadi an integer X, and Fadi was wondering about the minimum possible value of max(a, b) such that LCM(a, b) equals X. Both a and b should be positive integers.

LCM(a, b) is the smallest positive integer that is divisible by both a and b. For example, LCM(6, 8) = 24, LCM(4, 12) = 12, LCM(2, 3) = 6.

Of course, Fadi immediately knew the answer. Can you be just like Fadi and find any such pair?

Input

The first and only line contains an integer X (1 ≤ X ≤ 10^{12}).

Output

Print two positive integers, a and b, such that the value of max(a, b) is minimum possible and LCM(a, b) equals X. If there are several possible such pairs, you can print any.

Examples

Input


2


Output


1 2


Input


6


Output


2 3


Input


4


Output


1 4


Input


1


Output


1 1

Solution (in PYTHON3):

Solution:
import sys
from math import sqrt, gcd
from bisect import bisect
inp = sys.stdin.readline
read = lambda: list(map(int, inp().strip().split()))

# sys.setrecursionlimit(10**6)



def solve():
	n = int(inp())
	for i in range(int(sqrt(n)+1), 0, -1):
		if n%i == 0 and gcd(i, n//i) == 1:
			print(i, n//i)
			break

if __name__ == "__main__":
	solve()