Problem: There is data on sales of your company. Your task is to write a program which identifies good workers.

The program should read a list of data where each item includes the employee ID i, the amount of sales q and the corresponding unit price p. Then, the program should print IDs of employees whose total sales proceeds (i.e. sum of p × q) is greater than or equal to 1,000,000 in the order of inputting. If there is no such employees, the program should print "NA". You can suppose that n < 4000, and each employee has an unique ID. The unit price p is less than or equal to 1,000,000 and the amount of sales q is less than or equal to 100,000.



Input

The input consists of several datasets. The input ends with a line including a single 0. Each dataset consists of:


n (the number of data in the list)
i p q
i p q
:
:
i p q


Output

For each dataset, print a list of employee IDs or a text "NA"

Example

Input

4
1001 2000 520
1002 1800 450
1003 1600 625
1001 200 1220
2
1001 100 3
1005 1000 100
2
2013 5000 100
2013 5000 100
0


Output

1001
1003
NA
2013

Solution (in CPP):

Solution:
#include <cstdio>
using namespace std;

typedef long long Int;

int main(){
	const int AIM = 1000000;
	int n;
	int num, per, sum;
	bool exist;
	bool comp[4001];
	Int pro[4001];
	
	while(true){
		scanf("%d", &n);
		if(n == 0) break;
		for(int i = 1; i <= 4000; i++){
			comp[i] = false;
			pro[i] = 0;
		}
		exist = false;
		for(int i = 0; i < n; i++){
			scanf("%d%d%d", &num, &per, &sum);
			if(comp[num]) continue;
			if(pro[num] + (Int)per * sum >= AIM){
				exist = true;
				comp[num] = true;
				printf("%d\n", num);
			}
			else{
				pro[num] += (Int)per * sum;
			}
		}
		if(!exist) printf("NA\n");
	}
	
	return 0;
}