Problem: Today, Osama gave Fadi an integer X, and Fadi was wondering about the minimum possible value of max(a, b) such that LCM(a, b) equals X. Both a and b should be positive integers.

LCM(a, b) is the smallest positive integer that is divisible by both a and b. For example, LCM(6, 8) = 24, LCM(4, 12) = 12, LCM(2, 3) = 6.

Of course, Fadi immediately knew the answer. Can you be just like Fadi and find any such pair?

Input

The first and only line contains an integer X (1 ≤ X ≤ 10^{12}).

Output

Print two positive integers, a and b, such that the value of max(a, b) is minimum possible and LCM(a, b) equals X. If there are several possible such pairs, you can print any.

Examples

Input


2


Output


1 2


Input


6


Output


2 3


Input


4


Output


1 4


Input


1


Output


1 1

Solution (in PYTHON3):

Solution:
import math

def gcd(a,b):
    if a == 0:
        return b
    else:
        return gcd(b%a,a)

def lcm(a,b):
    ans = (a*b)//gcd(a,b)
    return ans

n = int(input())
ans = n
a1 = 1
a2 = n
for i in range(1,int(math.ceil(math.sqrt(n)))+1):
    if n%i == 0:
        if lcm(i,n//i) == n:
            maxi = max(i,n//i)
            if ans > maxi:
                a1=i
                a2=n//i
                ans = maxi
print(a1,a2)