Problem: Today, Osama gave Fadi an integer X, and Fadi was wondering about the minimum possible value of max(a, b) such that LCM(a, b) equals X. Both a and b should be positive integers.

LCM(a, b) is the smallest positive integer that is divisible by both a and b. For example, LCM(6, 8) = 24, LCM(4, 12) = 12, LCM(2, 3) = 6.

Of course, Fadi immediately knew the answer. Can you be just like Fadi and find any such pair?

Input

The first and only line contains an integer X (1 ≤ X ≤ 10^{12}).

Output

Print two positive integers, a and b, such that the value of max(a, b) is minimum possible and LCM(a, b) equals X. If there are several possible such pairs, you can print any.

Examples

Input


2


Output


1 2


Input


6


Output


2 3


Input


4


Output


1 4


Input


1


Output


1 1

Solution (in PYTHON3):

Solution:
from math import sqrt 
def gcd(a,b): 
    if a == 0: 
        return b 
    return gcd(b % a, a)
def lcm(a,b): 
    return (a*b) / gcd(a,b) 
def solve(n):
    l=[]
    for i in range(1,int(sqrt(n))+1):
        if n%i==0:
            l.append(i)
            l.append(n//i)
    return list(set(l))
x=int(input())
d=solve(x)
final=10**13
a,b=1,x
for i in d:
    if max(i,x//i)<final:
        if lcm(i,x//i)==x:
            a,b=i,x//i
            final=max(i,x//i)
print(a,b)