Problem: Today, Osama gave Fadi an integer X, and Fadi was wondering about the minimum possible value of max(a, b) such that LCM(a, b) equals X. Both a and b should be positive integers.

LCM(a, b) is the smallest positive integer that is divisible by both a and b. For example, LCM(6, 8) = 24, LCM(4, 12) = 12, LCM(2, 3) = 6.

Of course, Fadi immediately knew the answer. Can you be just like Fadi and find any such pair?

Input

The first and only line contains an integer X (1 ≤ X ≤ 10^{12}).

Output

Print two positive integers, a and b, such that the value of max(a, b) is minimum possible and LCM(a, b) equals X. If there are several possible such pairs, you can print any.

Examples

Input


2


Output


1 2


Input


6


Output


2 3


Input


4


Output


1 4


Input


1


Output


1 1

Solution (in PYTHON3):

Solution:
# -*- coding: utf-8 -*-
"""
Created on Wed Jan 15 22:53:45 2020

@author: Mridul Garg
"""

#x = [1, 2, 3]
#x.append(x)
#x[3][3][3][3][0] = 5
#print(x)
import math


def gcd(a, b):
    if b == 0:
        return a
    else:
        return gcd(b, a%b)

n = int(input())

ma = n

le = int(math.sqrt(n)) 
#print(le)

for i in range(1, 1+ le):
    if n%i == 0:
        a = i
        b = n//i
        temp = gcd(a, b)
        if temp == 1:
            if max(a, b) < ma:
                ma = max(a, b)
                
print(ma, n//ma)