Problem: There is data on sales of your company. Your task is to write a program which identifies good workers.

The program should read a list of data where each item includes the employee ID i, the amount of sales q and the corresponding unit price p. Then, the program should print IDs of employees whose total sales proceeds (i.e. sum of p × q) is greater than or equal to 1,000,000 in the order of inputting. If there is no such employees, the program should print "NA". You can suppose that n < 4000, and each employee has an unique ID. The unit price p is less than or equal to 1,000,000 and the amount of sales q is less than or equal to 100,000.



Input

The input consists of several datasets. The input ends with a line including a single 0. Each dataset consists of:


n (the number of data in the list)
i p q
i p q
:
:
i p q


Output

For each dataset, print a list of employee IDs or a text "NA"

Example

Input

4
1001 2000 520
1002 1800 450
1003 1600 625
1001 200 1220
2
1001 100 3
1005 1000 100
2
2013 5000 100
2013 5000 100
0


Output

1001
1003
NA
2013

Solution (in CPP):

Solution:
#include <iostream>
#include <vector>
#include <string>
#include <algorithm>
#include <map>
using namespace std;

#define loop(i,a,b) for(int i=(a); i<(int)(b); i++)
#define rep(i,b) loop(i,0,b)
#define all(c) (c).begin(), (c).end()
 
typedef vector<int> vi;
typedef vector<vi> vvi;
typedef pair<int,int> pii;

int main() {
  int n;
  while(cin >> n, n) {
    unsigned long long a[4100] = {};
    vi in(n);
    rep(i, n) {
      int p, q, r; cin >> p >> q >> r;
      a[p] += q*r;
      in[i] = p;
    }

    bool b = false;
    rep(i, n) {
      if(a[in[i]] >= 1000000) {
        cout << in[i] << endl;
        a[in[i]] = 0;
        b = true;
      }
    }
    if(!b) cout << "NA" << endl;
  }
}