Problem: There is data on sales of your company. Your task is to write a program which identifies good workers.

The program should read a list of data where each item includes the employee ID i, the amount of sales q and the corresponding unit price p. Then, the program should print IDs of employees whose total sales proceeds (i.e. sum of p × q) is greater than or equal to 1,000,000 in the order of inputting. If there is no such employees, the program should print "NA". You can suppose that n < 4000, and each employee has an unique ID. The unit price p is less than or equal to 1,000,000 and the amount of sales q is less than or equal to 100,000.



Input

The input consists of several datasets. The input ends with a line including a single 0. Each dataset consists of:


n (the number of data in the list)
i p q
i p q
:
:
i p q


Output

For each dataset, print a list of employee IDs or a text "NA"

Example

Input

4
1001 2000 520
1002 1800 450
1003 1600 625
1001 200 1220
2
1001 100 3
1005 1000 100
2
2013 5000 100
2013 5000 100
0


Output

1001
1003
NA
2013

Solution (in CPP):

Solution:
#include <iostream>
#include <map>
#include <vector>
#include <set>

using namespace std;

void solve()
{
	int n;
	while(cin >> n, n)
	{
		set<int> Set;
		vector<int> num;
		map<int, unsigned long long int> Map;
		while(n--)
		{
			unsigned long long int a, b, c;
			cin >> a >> b >> c;
			if(Set.find(a) == Set.end())
			{
				num.push_back(a);
			}
			Set.insert(a);
			Map[a] += b * c;
		}
		bool exist_flag = false;
		for(int i = 0; i < num.size(); ++i)
		{
			if(Map[num[i]] >= 1000000)
			{
				cout << num[i] << endl;
				exist_flag = true;
			}
		}
		if(!exist_flag)
		{
			cout << "NA" << endl;
		}
	}
}

int main()
{
	solve();
	return(0);
}