Problem: Today, Osama gave Fadi an integer X, and Fadi was wondering about the minimum possible value of max(a, b) such that LCM(a, b) equals X. Both a and b should be positive integers.

LCM(a, b) is the smallest positive integer that is divisible by both a and b. For example, LCM(6, 8) = 24, LCM(4, 12) = 12, LCM(2, 3) = 6.

Of course, Fadi immediately knew the answer. Can you be just like Fadi and find any such pair?

Input

The first and only line contains an integer X (1 ≤ X ≤ 10^{12}).

Output

Print two positive integers, a and b, such that the value of max(a, b) is minimum possible and LCM(a, b) equals X. If there are several possible such pairs, you can print any.

Examples

Input


2


Output


1 2


Input


6


Output


2 3


Input


4


Output


1 4


Input


1


Output


1 1

Solution (in PYTHON3):

Solution:
from math import gcd

def divisor(n):
    ret = []
    for i in range(1, int(n**0.5)+1):
        if n % i == 0:
            ret.append(i)
            if i*i != n:
                ret.append(n//i)
    return ret

x = int(input())
ans = float("inf")
for ai in divisor(x):
    b = x//ai
    if gcd(ai, b) == 1:
        tmp = max(ai, b)
        ans = min(ans, tmp)
print(x//ans, ans)