Problem: Arpa is taking a geometry exam. Here is the last problem of the exam.

You are given three points a, b, c.

Find a point and an angle such that if we rotate the page around the point by the angle, the new position of a is the same as the old position of b, and the new position of b is the same as the old position of c.

Arpa is doubting if the problem has a solution or not (i.e. if there exists a point and an angle satisfying the condition). Help Arpa determine if the question has a solution or not.

Input

The only line contains six integers ax, ay, bx, by, cx, cy (|ax|, |ay|, |bx|, |by|, |cx|, |cy| ≤ 109). It's guaranteed that the points are distinct.

Output

Print "Yes" if the problem has a solution, "No" otherwise.

You can print each letter in any case (upper or lower).

Examples

Input

0 1 1 1 1 0


Output

Yes


Input

1 1 0 0 1000 1000


Output

No

Note

In the first sample test, rotate the page around (0.5, 0.5) by <image>.

In the second sample test, you can't find any solution.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int orientation(long long ax, long long ay, long long bx, long long by,
                long long cx, long long cy) {
  long long val = (by - ay) * (cx - bx) - (bx - ax) * (cy - by);
  if (val == 0) return 0;
  return (val > 0) ? 1 : 2;
}
int main() {
  long long ax, ay, bx, by, cx, cy;
  cin >> ax >> ay >> bx >> by >> cx >> cy;
  if (orientation(ax, ay, bx, by, cx, cy) == 0) {
    printf("No\n");
    return 0;
  }
  unsigned long long dab = (unsigned long long)((ax - bx) * (ax - bx)) +
                           (unsigned long long)((ay - by) * (ay - by));
  unsigned long long dac = (unsigned long long)((ax - cx) * (ax - cx)) +
                           (unsigned long long)((ay - cy) * (ay - cy));
  unsigned long long dbc = (unsigned long long)((cx - bx) * (cx - bx)) +
                           (unsigned long long)((cy - by) * (cy - by));
  if (dab == dbc) {
    printf("Yes\n");
  } else {
    printf("No\n");
  }
  return 0;
}