Problem: Today, Osama gave Fadi an integer X, and Fadi was wondering about the minimum possible value of max(a, b) such that LCM(a, b) equals X. Both a and b should be positive integers.

LCM(a, b) is the smallest positive integer that is divisible by both a and b. For example, LCM(6, 8) = 24, LCM(4, 12) = 12, LCM(2, 3) = 6.

Of course, Fadi immediately knew the answer. Can you be just like Fadi and find any such pair?

Input

The first and only line contains an integer X (1 ≤ X ≤ 10^{12}).

Output

Print two positive integers, a and b, such that the value of max(a, b) is minimum possible and LCM(a, b) equals X. If there are several possible such pairs, you can print any.

Examples

Input


2


Output


1 2


Input


6


Output


2 3


Input


4


Output


1 4


Input


1


Output


1 1

Solution (in PYTHON3):

Solution:
import math as m
def gcd(a,b):
	if a%b==0:
		return b
	return gcd(b,a%b)
def lcm(a,b):
	return a*b//gcd(a,b)
def isprime(x):
	for i in range(2,m.ceil(m.sqrt(x))+1):
		if x%i==0:
			return False
	return True
x=int(input())
if isprime(x):
	print(1,x)
else:	
	for i in range(m.floor(m.sqrt(x)),0,-1):
		if x%i==0 and lcm(i,x//i)==x :
			print(i,x//i)
			break