Problem: Today, Osama gave Fadi an integer X, and Fadi was wondering about the minimum possible value of max(a, b) such that LCM(a, b) equals X. Both a and b should be positive integers.

LCM(a, b) is the smallest positive integer that is divisible by both a and b. For example, LCM(6, 8) = 24, LCM(4, 12) = 12, LCM(2, 3) = 6.

Of course, Fadi immediately knew the answer. Can you be just like Fadi and find any such pair?

Input

The first and only line contains an integer X (1 ≤ X ≤ 10^{12}).

Output

Print two positive integers, a and b, such that the value of max(a, b) is minimum possible and LCM(a, b) equals X. If there are several possible such pairs, you can print any.

Examples

Input


2


Output


1 2


Input


6


Output


2 3


Input


4


Output


1 4


Input


1


Output


1 1

Solution (in PYTHON3):

Solution:
import math


def check(mx1, mx2):
    for i in range(2, int(math.sqrt(mx1)) + 1):
        if mx1 % i == 0 and (mx2 % i == 0 or mx2 % (mx1 // i) == 0):
            return False
    if mx2 % mx1 == 0:
        return False
    return True


def main():
    x = int(input())
    mx11, mx21 = 1, x
    for i in range(2, int(math.sqrt(x)) + 3):
        if x % i == 0:
            mx1, mx2 = i, x // i
            if check(mx1, mx2):
                mx11, mx21 = mx1, mx2
    print(mx11, mx21)


if __name__ == "__main__":
    t = 1
    for i in range(t):
        main()