Problem: Today, Osama gave Fadi an integer X, and Fadi was wondering about the minimum possible value of max(a, b) such that LCM(a, b) equals X. Both a and b should be positive integers.

LCM(a, b) is the smallest positive integer that is divisible by both a and b. For example, LCM(6, 8) = 24, LCM(4, 12) = 12, LCM(2, 3) = 6.

Of course, Fadi immediately knew the answer. Can you be just like Fadi and find any such pair?

Input

The first and only line contains an integer X (1 ≤ X ≤ 10^{12}).

Output

Print two positive integers, a and b, such that the value of max(a, b) is minimum possible and LCM(a, b) equals X. If there are several possible such pairs, you can print any.

Examples

Input


2


Output


1 2


Input


6


Output


2 3


Input


4


Output


1 4


Input


1


Output


1 1

Solution (in PYTHON3):

Solution:
import math

def gcd(a,b):
    if a == 0 :
        return b
    return gcd(b%a,a)

def lcm(a,b):
    return (a*b)/gcd(a,b)

x = int(input())
ans = 9999999999999
ansa = 0
ansb = 0
a = False
if x == 1:
    print("1 1")
    a = True

if a == False:
    for i in range(1,int(math.sqrt(x))+1):
        if(x%i == 0):
            if(i == x/i):
                continue
            else :
                a = i
                b = x/i
                if(lcm(a,b) == x):
                    if(max(a,b) < ans):
                        ans = max(a,b)
                        ansa = a
                        ansb = b



    print(int(ansa),int(ansb))