Problem: One way to create a task is to learn from math. You can generate some random math statement or modify some theorems to get something new and build a new task from that.

For example, there is a statement called the "Goldbach's conjecture". It says: "each even number no less than four can be expressed as the sum of two primes". Let's modify it. How about a statement like that: "each integer no less than 12 can be expressed as the sum of two composite numbers." Not like the Goldbach's conjecture, I can prove this theorem.

You are given an integer n no less than 12, express it as a sum of two composite numbers.

Input

The only line contains an integer n (12 ≤ n ≤ 106).

Output

Output two composite integers x and y (1 < x, y < n) such that x + y = n. If there are multiple solutions, you can output any of them.

Examples

Input

12


Output

4 8


Input

15


Output

6 9


Input

23


Output

8 15


Input

1000000


Output

500000 500000

Note

In the first example, 12 = 4 + 8 and both 4, 8 are composite numbers. You can output "6 6" or "8 4" as well.

In the second example, 15 = 6 + 9. Note that you can't output "1 14" because 1 is not a composite number.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
long long POWER(long long a, long long p) {
  if (p == 0) return 1;
  if (p == 1) return a;
  long long x = POWER(a, p / 2);
  if (p % 2 == 0) return ((x)*x);
  return (((x)*x) * a);
}
bool brime(int x) {
  for (int i = 2; i < x; i++) {
    if (x % i == 0) {
      return false;
    }
  }
  return true;
}
int main() {
  int n, x = 0, y = 0;
  cin >> n;
  for (int i = 2; i < n; i++) {
    x = i;
    y = n - i;
    if (!brime(x) && !brime(y)) {
      cout << x << " " << y;
      return 0;
    }
  }
}