Problem: In the Land of Fire there are n villages and n-1 bidirectional road, and there is a path between any pair of villages by roads. There are only two types of roads: stone ones and sand ones. Since the Land of Fire is constantly renovating, every morning workers choose a single road and flip its type (so it becomes a stone road if it was a sand road and vice versa). Also everyone here loves ramen, that's why every morning a ramen pavilion is set in the middle of every stone road, and at the end of each day all the pavilions are removed.

For each of the following m days, after another road is flipped, Naruto and Jiraiya choose a simple path — that is, a route which starts in a village and ends in a (possibly, the same) village, and doesn't contain any road twice. Since Naruto and Jiraiya also love ramen very much, they buy a single cup of ramen on each stone road and one of them eats it. Since they don't want to offend each other, they only choose routes where they can eat equal number of ramen cups. Since they both like traveling, they choose any longest possible path. After every renovation find the maximal possible length of a path (that is, the number of roads in it) they can follow.

Input

The first line contains the only positive integer n (2 ≤ n ≤ 500 000) standing for the number of villages in the Land of Fire.

Each of the following (n-1) lines contains a description of another road, represented as three positive integers u, v and t (1 ≤ u, v ≤ n, t ∈ \{0,1\}). The first two numbers denote the villages connected by the road, and the third denotes the initial type of the road: 0 for the sand one and 1 for the stone one. Roads are numbered from 1 to (n-1) in the order from the input.

The following line contains a positive integer m (1 ≤ m ≤ 500 000) standing for the number of days Naruto and Jiraiya travel for.

Each of the following m lines contains the single integer id (1 ≤ id ≤ n-1) standing for the index of the road whose type is flipped on the morning of corresponding day.

It is guaranteed that there is a road path between any pair of villages.

Output

Output m lines. In the i-th of them print the only integer denoting the maximal possible length of any valid path on the i-th day.

Example

Input


5
1 2 0
1 3 0
3 5 0
3 4 0
5
3
4
1
3
4


Output


3
2
3
3
2

Note

After the renovation of the 3-rd road the longest path consists of the roads 1, 2 and 4.

After the renovation of the 4-th road one of the longest paths consists of the roads 1 and 2.

After the renovation of the 1-st road one of the longest paths consists of the roads 1, 2 and 3.

After the renovation of the 3-rd road the longest path consists of the roads 1, 2 and 4.

After the renovation of the 4-rd road one of the longest paths consists of the roads 2 and 4.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
template <typename T>
ostream &operator<<(ostream &os, const vector<T> &v) {
  os << '{';
  string sep;
  for (const auto &x : v) os << sep << x, sep = ", ";
  return os << '}';
}
template <typename T, size_t size>
ostream &operator<<(ostream &os, const array<T, size> &arr) {
  os << '{';
  string sep;
  for (const auto &x : arr) os << sep << x, sep = ", ";
  return os << '}';
}
template <typename A, typename B>
ostream &operator<<(ostream &os, const pair<A, B> &p) {
  return os << '(' << p.first << ", " << p.second << ')';
}
void dbg_out() { cerr << endl; }
template <typename Head, typename... Tail>
void dbg_out(Head H, Tail... T) {
  cerr << ' ' << H;
  dbg_out(T...);
}
template <typename T, bool maximum_mode = false>
struct RMQ {
  int n = 0;
  vector<T> values;
  vector<vector<int>> range_low;
  RMQ(const vector<T> &_values = {}) {
    if (!_values.empty()) build(_values);
  }
  static int largest_bit(int x) { return x == 0 ? -1 : 31 - __builtin_clz(x); }
  int better_index(int a, int b) const {
    return (maximum_mode ? values[b] < values[a] : values[a] < values[b]) ? a
                                                                          : b;
  }
  void build(const vector<T> &_values) {
    values = _values;
    n = int(values.size());
    int levels = largest_bit(n) + 1;
    range_low.resize(levels);
    for (int k = 0; k < levels; k++) range_low[k].resize(n - (1 << k) + 1);
    for (int i = 0; i < n; i++) range_low[0][i] = i;
    for (int k = 1; k < levels; k++)
      for (int i = 0; i <= n - (1 << k); i++)
        range_low[k][i] = better_index(range_low[k - 1][i],
                                       range_low[k - 1][i + (1 << (k - 1))]);
  }
  int query_index(int a, int b) const {
    assert(0 <= a && a < b && b <= n);
    int level = largest_bit(b - a);
    return better_index(range_low[level][a],
                        range_low[level][b - (1 << level)]);
  }
  T query_value(int a, int b) const { return values[query_index(a, b)]; }
};
struct LCA {
  int n = 0;
  vector<vector<int>> adj;
  vector<int> parent, depth, subtree_size;
  vector<int> euler, first_occurrence;
  vector<int> tour_start, tour_end, postorder;
  vector<int> tour_list, rev_tour_list;
  vector<int> heavy_root;
  RMQ<int> rmq;
  bool built;
  LCA(int _n = 0) { init(_n); }
  LCA(const vector<vector<int>> &_adj) { init(_adj); }
  void init(int _n) {
    n = _n;
    adj.assign(n, {});
    parent.resize(n);
    depth.resize(n);
    subtree_size.resize(n);
    first_occurrence.resize(n);
    tour_start.resize(n);
    tour_end.resize(n);
    postorder.resize(n);
    tour_list.resize(n);
    heavy_root.resize(n);
    built = false;
  }
  void init(const vector<vector<int>> &_adj) {
    init(int(_adj.size()));
    adj = _adj;
  }
  void add_edge(int a, int b) {
    adj[a].push_back(b);
    adj[b].push_back(a);
  }
  int degree(int v) const {
    return int(adj[v].size()) + (built && parent[v] >= 0);
  }
  void dfs(int node, int par) {
    parent[node] = par;
    depth[node] = par < 0 ? 0 : depth[par] + 1;
    subtree_size[node] = 1;
    adj[node].erase(remove(adj[node].begin(), adj[node].end(), par),
                    adj[node].end());
    for (int child : adj[node]) {
      dfs(child, node);
      subtree_size[node] += subtree_size[child];
    }
    sort(adj[node].begin(), adj[node].end(),
         [&](int a, int b) { return subtree_size[a] > subtree_size[b]; });
  }
  int tour, post_tour;
  void tour_dfs(int node, bool heavy) {
    heavy_root[node] = heavy ? heavy_root[parent[node]] : node;
    first_occurrence[node] = int(euler.size());
    euler.push_back(node);
    tour_list[tour] = node;
    tour_start[node] = tour++;
    bool heavy_child = true;
    for (int child : adj[node]) {
      tour_dfs(child, heavy_child);
      euler.push_back(node);
      heavy_child = false;
    }
    tour_end[node] = tour;
    postorder[node] = post_tour++;
  }
  void build(int root = -1) {
    parent.assign(n, -1);
    if (0 <= root && root < n) dfs(root, -1);
    for (int i = 0; i < n; i++)
      if (i != root && parent[i] < 0) dfs(i, -1);
    tour = post_tour = 0;
    euler.clear();
    euler.reserve(2 * n);
    for (int i = 0; i < n; i++)
      if (parent[i] < 0) {
        tour_dfs(i, false);
        euler.push_back(-1);
      }
    rev_tour_list = tour_list;
    reverse(rev_tour_list.begin(), rev_tour_list.end());
    assert(int(euler.size()) == 2 * n);
    vector<int> euler_depths;
    euler_depths.reserve(euler.size());
    for (int node : euler)
      euler_depths.push_back(node < 0 ? node : depth[node]);
    rmq.build(euler_depths);
    built = true;
  }
  pair<int, int> find_farthest(int node, int par, int path) const {
    pair<int, int> current = {path, node};
    for (int neighbor : adj[node])
      if (neighbor != par)
        current = max(current, find_farthest(neighbor, node, path + 1));
    return current;
  }
  pair<int, array<int, 2>> get_diameter() const {
    int u = find_farthest(0, -1, 0).second;
    pair<int, int> farthest = find_farthest(u, -1, 0);
    int v = farthest.second;
    return {farthest.first, {u, v}};
  }
  int get_lca(int a, int b) const {
    a = first_occurrence[a];
    b = first_occurrence[b];
    if (a > b) swap(a, b);
    return euler[rmq.query_index(a, b + 1)];
  }
  bool is_ancestor(int a, int b) const {
    return tour_start[a] <= tour_start[b] && tour_start[b] < tour_end[a];
  }
  bool on_path(int x, int a, int b) const {
    return (is_ancestor(x, a) || is_ancestor(x, b)) &&
           is_ancestor(get_lca(a, b), x);
  }
  int get_dist(int a, int b) const {
    return depth[a] + depth[b] - 2 * depth[get_lca(a, b)];
  }
  int child_ancestor(int a, int b) const {
    assert(a != b);
    assert(is_ancestor(a, b));
    int child =
        euler[rmq.query_index(first_occurrence[a], first_occurrence[b] + 1) +
              1];
    assert(parent[child] == a);
    assert(is_ancestor(child, b));
    return child;
  }
  int get_kth_ancestor(int a, int k) const {
    while (a >= 0) {
      int root = heavy_root[a];
      if (depth[root] <= depth[a] - k) return tour_list[tour_start[a] - k];
      k -= depth[a] - depth[root] + 1;
      a = parent[root];
    }
    return a;
  }
  int get_kth_node_on_path(int a, int b, int k) const {
    int anc = get_lca(a, b);
    int first_half = depth[a] - depth[anc];
    int second_half = depth[b] - depth[anc];
    assert(0 <= k && k <= first_half + second_half);
    if (k < first_half)
      return get_kth_ancestor(a, k);
    else
      return get_kth_ancestor(b, first_half + second_half - k);
  }
  int get_common_node(int a, int b, int c) const {
    int x = get_lca(a, b);
    int y = get_lca(b, c);
    int z = get_lca(c, a);
    if (depth[y] > depth[x]) x = y;
    if (depth[z] > depth[x]) x = z;
    return x;
  }
  vector<pair<int, int>> compress_tree(vector<int> nodes) const {
    if (nodes.empty()) return {};
    auto &&compare_tour = [&](int a, int b) {
      return tour_start[a] < tour_start[b];
    };
    sort(nodes.begin(), nodes.end(), compare_tour);
    int k = int(nodes.size());
    for (int i = 0; i < k - 1; i++)
      nodes.push_back(get_lca(nodes[i], nodes[i + 1]));
    sort(nodes.begin() + k, nodes.end(), compare_tour);
    inplace_merge(nodes.begin(), nodes.begin() + k, nodes.end(), compare_tour);
    nodes.erase(unique(nodes.begin(), nodes.end()), nodes.end());
    vector<pair<int, int>> result = {{nodes[0], -1}};
    for (int i = 1; i < int(nodes.size()); i++)
      result.emplace_back(nodes[i], get_lca(nodes[i], nodes[i - 1]));
    return result;
  }
};
const int INF = 1e9 + 5;
struct segment_change {
  bool flip;
  segment_change(bool _flip = false) : flip(_flip) {}
  void reset() { flip = false; }
  bool has_change() const { return flip; }
  segment_change combine(const segment_change &other) const {
    return segment_change(flip ^ other.flip);
  }
};
struct segment {
  int deepest[2] = {-INF, -INF};
  void apply(int, const segment_change &change) {
    if (change.flip) swap(deepest[0], deepest[1]);
  }
  void join(const segment &other) {
    for (int r = 0; r < 2; r++) deepest[r] = max(deepest[r], other.deepest[r]);
  }
  void join(const segment &a, const segment &b) {
    *this = a;
    join(b);
  }
};
pair<int, int> right_half[32];
struct seg_tree {
  int tree_n = 0;
  vector<segment> tree;
  vector<segment_change> changes;
  seg_tree(int n = -1) {
    if (n >= 0) init(n);
  }
  void init(int n) {
    tree_n = 1;
    while (tree_n < n) tree_n *= 2;
    tree.assign(2 * tree_n, segment());
    changes.assign(tree_n, segment_change());
  }
  void build(const vector<segment> &initial) {
    int n = int(initial.size());
    init(n);
    assert(n <= tree_n);
    for (int i = 0; i < n; i++) tree[tree_n + i] = initial[i];
    for (int position = tree_n - 1; position > 0; position--)
      tree[position].join(tree[2 * position], tree[2 * position + 1]);
  }
  void apply_and_combine(int position, int length,
                         const segment_change &change) {
    tree[position].apply(length, change);
    if (position < tree_n)
      changes[position] = changes[position].combine(change);
  }
  void push_down(int position, int length) {
    if (changes[position].has_change()) {
      apply_and_combine(2 * position, length / 2, changes[position]);
      apply_and_combine(2 * position + 1, length / 2, changes[position]);
      changes[position].reset();
    }
  }
  void push_all(int a, int b) {
    assert(0 <= a && a < b && b <= tree_n);
    a += tree_n;
    b += tree_n - 1;
    for (int up = 31 - __builtin_clz(tree_n); up > 0; up--) {
      int x = a >> up, y = b >> up;
      push_down(x, 1 << up);
      if (x != y) push_down(y, 1 << up);
    }
  }
  void join_and_apply(int position, int length) {
    tree[position].join(tree[2 * position], tree[2 * position + 1]);
    tree[position].apply(length, changes[position]);
  }
  void join_all(int a, int b) {
    assert(0 <= a && a < b && b <= tree_n);
    a += tree_n;
    b += tree_n - 1;
    int length = 1;
    while (a > 1) {
      a /= 2;
      b /= 2;
      length *= 2;
      join_and_apply(a, length);
      if (a != b) join_and_apply(b, length);
    }
  }
  template <typename T_range_op>
  void process_range(int a, int b, bool needs_join, T_range_op &&range_op) {
    if (a == b) return;
    push_all(a, b);
    int original_a = a, original_b = b;
    int length = 1, r_size = 0;
    for (a += tree_n, b += tree_n; a < b; a /= 2, b /= 2, length *= 2) {
      if (a & 1) range_op(a++, length);
      if (b & 1) right_half[r_size++] = {--b, length};
    }
    for (int i = r_size - 1; i >= 0; i--)
      range_op(right_half[i].first, right_half[i].second);
    if (needs_join) join_all(original_a, original_b);
  }
  segment query(int a, int b) {
    assert(0 <= a && a <= b && b <= tree_n);
    segment answer;
    process_range(a, b, false,
                  [&](int position, int) { answer.join(tree[position]); });
    return answer;
  }
  void update(int a, int b, const segment_change &change) {
    assert(0 <= a && a <= b && b <= tree_n);
    process_range(a, b, true, [&](int position, int length) {
      apply_and_combine(position, length, change);
    });
  }
  vector<segment> to_array() {
    for (int i = 1; i < tree_n; i++)
      push_down(i, tree_n >> (31 - __builtin_clz(i)));
    vector<segment> segs(tree_n);
    for (int i = 0; i < tree_n; i++) segs[i] = tree[tree_n + i];
    return segs;
  }
  void update_single(int index, const segment &seg);
  template <typename T_bool>
  int find_last_prefix(int n, T_bool &&should_join);
  template <typename T_bool>
  int find_last_subarray(int n, int start, T_bool &&should_join);
};
int main() {
  ios::sync_with_stdio(false);
  cin.tie(nullptr);
  int N;
  cin >> N;
  LCA lca[2] = {LCA(N), LCA(N)};
  vector<array<int, 2>> edges(N - 1);
  vector<bool> status(N - 1);
  for (int e = 0; e < N - 1; e++) {
    int u, v, s;
    cin >> u >> v >> s;
    u--;
    v--;
    edges[e] = {u, v};
    status[e] = s;
    for (int t = 0; t < 2; t++) lca[t].add_edge(u, v);
  }
  array<int, 2> diameter = lca[0].get_diameter().second;
  for (int t = 0; t < 2; t++) lca[t].build(diameter[t]);
  seg_tree tree[2] = {seg_tree(N), seg_tree(N)};
  for (int t = 0; t < 2; t++) {
    vector<segment> initial(N);
    for (int node = 0; node < N; node++)
      initial[lca[t].tour_start[node]].deepest[0] = lca[t].depth[node];
    tree[t].build(initial);
  }
  auto query = [&] {
    return max(tree[0].tree[1].deepest[0], tree[1].tree[1].deepest[0]);
  };
  auto flip_edge = [&](int a, int b) {
    for (int t = 0; t < 2; t++) {
      int v = lca[t].depth[a] > lca[t].depth[b] ? a : b;
      tree[t].update(lca[t].tour_start[v], lca[t].tour_end[v],
                     segment_change(true));
    }
  };
  for (int e = 0; e < N - 1; e++)
    if (status[e]) flip_edge(edges[e][0], edges[e][1]);
  int M;
  cin >> M;
  for (int q = 0; q < M; q++) {
    int id;
    cin >> id;
    id--;
    flip_edge(edges[id][0], edges[id][1]);
    cout << query() << '\n';
  }
}