Problem: Today, Osama gave Fadi an integer X, and Fadi was wondering about the minimum possible value of max(a, b) such that LCM(a, b) equals X. Both a and b should be positive integers.

LCM(a, b) is the smallest positive integer that is divisible by both a and b. For example, LCM(6, 8) = 24, LCM(4, 12) = 12, LCM(2, 3) = 6.

Of course, Fadi immediately knew the answer. Can you be just like Fadi and find any such pair?

Input

The first and only line contains an integer X (1 ≤ X ≤ 10^{12}).

Output

Print two positive integers, a and b, such that the value of max(a, b) is minimum possible and LCM(a, b) equals X. If there are several possible such pairs, you can print any.

Examples

Input


2


Output


1 2


Input


6


Output


2 3


Input


4


Output


1 4


Input


1


Output


1 1

Solution (in PYTHON3):

Solution:
def factorize(n):  # o(sqr(n))
    c, ans, mi, ma = 2, 0, 1, n
    while (c * c < n):
        if n % c == 0:
            if lcm(c, n // c) ==n:
                mi, ma = c, n // c
        c += 1

    # if c * c == n:
    #     ans += 1
    return mi, ma


def lcm(a, b):
    return a // gcd(a, b) * b


from math import gcd

n = int(input())
print(*factorize(n))