Problem: You are given the array a consisting of n elements and the integer k ≤ n.

You want to obtain at least k equal elements in the array a. In one move, you can make one of the following two operations:

  * Take one of the minimum elements of the array and increase its value by one (more formally, if the minimum value of a is mn then you choose such index i that a_i = mn and set a_i := a_i + 1); 
  * take one of the maximum elements of the array and decrease its value by one (more formally, if the maximum value of a is mx then you choose such index i that a_i = mx and set a_i := a_i - 1). 



Your task is to calculate the minimum number of moves required to obtain at least k equal elements in the array.

Input

The first line of the input contains two integers n and k (1 ≤ k ≤ n ≤ 2 ⋅ 10^5) — the number of elements in a and the required number of equal elements.

The second line of the input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9), where a_i is the i-th element of a.

Output

Print one integer — the minimum number of moves required to obtain at least k equal elements in the array.

Examples

Input


6 5
1 2 2 4 2 3


Output


3


Input


7 5
3 3 2 1 1 1 3


Output


4

Solution (in PYTHON3):

Solution:
from sys import stdin

input = stdin.readline
inf = 1000 * 1000 * 1000

n, k = map(int, input().split())
a = [int(i) for i in input().split()]

a.sort()
res = inf
for i in range(0, 200001, 1):
    b = []
    for j in a:
        tmp2 = 0
        while j > i:
            tmp2 += 1
            j //= 2
        if j == i:
            b.append(tmp2)
        else:
            b.append(inf)
    b.sort()
    tmp = 0
    for i in range(k):
        tmp += b[i]
    res = min(res, tmp)

print(res)