Problem: Today, Osama gave Fadi an integer X, and Fadi was wondering about the minimum possible value of max(a, b) such that LCM(a, b) equals X. Both a and b should be positive integers.

LCM(a, b) is the smallest positive integer that is divisible by both a and b. For example, LCM(6, 8) = 24, LCM(4, 12) = 12, LCM(2, 3) = 6.

Of course, Fadi immediately knew the answer. Can you be just like Fadi and find any such pair?

Input

The first and only line contains an integer X (1 ≤ X ≤ 10^{12}).

Output

Print two positive integers, a and b, such that the value of max(a, b) is minimum possible and LCM(a, b) equals X. If there are several possible such pairs, you can print any.

Examples

Input


2


Output


1 2


Input


6


Output


2 3


Input


4


Output


1 4


Input


1


Output


1 1

Solution (in PYTHON3):

Solution:
import math
n=int(input())
x=int(math.sqrt(n))
fact=[]
if n==1:
    print("1 1")
else:
    for i in range(x,0,-1):
        if n%i==0:
            
            if n//i==i:
                continue
            #print((i*(n//i))//math.gcd(i,n//i))
            if ((i*(n//i))//math.gcd(i,n//i)) !=n:
                continue
            print(n//i,i)
            break