Problem: There is data on sales of your company. Your task is to write a program which identifies good workers.

The program should read a list of data where each item includes the employee ID i, the amount of sales q and the corresponding unit price p. Then, the program should print IDs of employees whose total sales proceeds (i.e. sum of p × q) is greater than or equal to 1,000,000 in the order of inputting. If there is no such employees, the program should print "NA". You can suppose that n < 4000, and each employee has an unique ID. The unit price p is less than or equal to 1,000,000 and the amount of sales q is less than or equal to 100,000.



Input

The input consists of several datasets. The input ends with a line including a single 0. Each dataset consists of:


n (the number of data in the list)
i p q
i p q
:
:
i p q


Output

For each dataset, print a list of employee IDs or a text "NA"

Example

Input

4
1001 2000 520
1002 1800 450
1003 1600 625
1001 200 1220
2
1001 100 3
1005 1000 100
2
2013 5000 100
2013 5000 100
0


Output

1001
1003
NA
2013

Solution (in CPP):

Solution:
#include<math.h>
#include<cmath>
#include<bitset>
#include<stdio.h>
#include<string>
#include<map>
#include<algorithm>
#include<vector>
#include<iostream>
#include<utility>
using namespace std;
typedef long long ll;
int main(){
  while(1){
    ll i,b[4010],a[4010],n,e[4010],p,q,k=0;
    scanf("%lld\n",&n);
    if(n==0){
      return 0;
    }
    for(i=0;i<=4000;i++){
      a[i]=0,b[i]=0;
    }
    for(i=0;i<n;i++){
      scanf("%lld %lld %lld\n",&e[i],&p,&q);
      a[e[i]]+=p*q;
    }
    for(i=0;i<n;i++){
      if(b[e[i]]==0 && a[e[i]]>=1000000){
        b[e[i]]=1;
        printf("%lld\n",e[i]);
        k++;
      }
    }
    if(k==0){
      printf("NA\n");
    }
  }
  return 0;
}