Problem: Today, Osama gave Fadi an integer X, and Fadi was wondering about the minimum possible value of max(a, b) such that LCM(a, b) equals X. Both a and b should be positive integers.

LCM(a, b) is the smallest positive integer that is divisible by both a and b. For example, LCM(6, 8) = 24, LCM(4, 12) = 12, LCM(2, 3) = 6.

Of course, Fadi immediately knew the answer. Can you be just like Fadi and find any such pair?

Input

The first and only line contains an integer X (1 ≤ X ≤ 10^{12}).

Output

Print two positive integers, a and b, such that the value of max(a, b) is minimum possible and LCM(a, b) equals X. If there are several possible such pairs, you can print any.

Examples

Input


2


Output


1 2


Input


6


Output


2 3


Input


4


Output


1 4


Input


1


Output


1 1

Solution (in PYTHON3):

Solution:
def gcd(a,b):
    if(a%b==0):
        return b
    return gcd(b,a%b)
n=int(input())
i=1
maxa=10**18
ans=0
while(i*i<=n):
    if(n%i==0):
        num1=i
        num2=n//i
        if(gcd(num1,num2)==1):
            if(max(num1,num2)<maxa):
                ans=i
            maxa=min(maxa,max(num1,num2))
    i+=1
print(ans,n//ans)