Problem: There is data on sales of your company. Your task is to write a program which identifies good workers.

The program should read a list of data where each item includes the employee ID i, the amount of sales q and the corresponding unit price p. Then, the program should print IDs of employees whose total sales proceeds (i.e. sum of p × q) is greater than or equal to 1,000,000 in the order of inputting. If there is no such employees, the program should print "NA". You can suppose that n < 4000, and each employee has an unique ID. The unit price p is less than or equal to 1,000,000 and the amount of sales q is less than or equal to 100,000.



Input

The input consists of several datasets. The input ends with a line including a single 0. Each dataset consists of:


n (the number of data in the list)
i p q
i p q
:
:
i p q


Output

For each dataset, print a list of employee IDs or a text "NA"

Example

Input

4
1001 2000 520
1002 1800 450
1003 1600 625
1001 200 1220
2
1001 100 3
1005 1000 100
2
2013 5000 100
2013 5000 100
0


Output

1001
1003
NA
2013

Solution (in CPP):

Solution:
#include <iostream>
#include <map>
#include <vector>
using namespace std;

int main(){
	int n,number;
	long long a,b;
	bool flag;
	map<int,long long> info;
	vector<int> seq;
	
	while(cin >> n && n){
		info.clear();
		seq.clear();
		while(n--){
			cin >> number >> a >> b;
			if(!info[number])seq.push_back(number); // ツ甘ケツ出ツつセツづつスツづァツ表ツ篠ヲツ渉記ツ録ツ配ツ療アツづ可禿シツづェツづ按つ「ツ。ツ単ツ可ソ0ツ円ツケツーツスツづーツ考ツ猟カツつオツづづ慊つケツづアツ。
			info[number] += a*b;
		}
		flag = true;
		for(int i=0;i<seq.size();i++){
			if(info[seq[i]]>=1000000){
				flag = false;
				cout << seq[i] << endl;
			}
		}
		if(flag)cout << "NA" << endl;
	}
}