Problem: One way to create a task is to learn from math. You can generate some random math statement or modify some theorems to get something new and build a new task from that.

For example, there is a statement called the "Goldbach's conjecture". It says: "each even number no less than four can be expressed as the sum of two primes". Let's modify it. How about a statement like that: "each integer no less than 12 can be expressed as the sum of two composite numbers." Not like the Goldbach's conjecture, I can prove this theorem.

You are given an integer n no less than 12, express it as a sum of two composite numbers.

Input

The only line contains an integer n (12 ≤ n ≤ 106).

Output

Output two composite integers x and y (1 < x, y < n) such that x + y = n. If there are multiple solutions, you can output any of them.

Examples

Input

12


Output

4 8


Input

15


Output

6 9


Input

23


Output

8 15


Input

1000000


Output

500000 500000

Note

In the first example, 12 = 4 + 8 and both 4, 8 are composite numbers. You can output "6 6" or "8 4" as well.

In the second example, 15 = 6 + 9. Note that you can't output "1 14" because 1 is not a composite number.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
typedef unsigned long long ULL;
typedef unsigned long long uint64;
typedef long long LL;
typedef long long int64;
template <class T>
inline void checkmax(T &a, T b) {
  if (b > a) a = b;
}
template <class T>
inline void checkmin(T &a, T b) {
  if (b < a) a = b;
}
template <class T>
inline T MAX(T a, T b) {
  return (a > b) ? a : b;
}
template <class T>
inline T MIN(T a, T b) {
  return (a < b) ? a : b;
}
template <class T>
inline T sqr(T x) {
  return x * x;
}
template <class T>
inline T fABS(T a) {
  return a < 0 ? a * (-1) : a;
}
template <class T>
inline void SWAP(T &a, T &b) {
  T t = a;
  a = b;
  b = t;
}
inline LL POW(LL base, LL power) {
  LL I, res = base;
  if (power == 0) return 1;
  for (I = 0; I < power - 1; I++) res *= base;
  return res;
}
bool isUpperCase(char c) { return c >= 'A' && c <= 'Z'; }
bool isLowerCase(char c) { return c >= 'a' && c <= 'z'; }
bool isVowel(char c) {
  return (c == 'a' || c == 'e' || c == 'i' || c == 'o' || c == 'u' ||
          c == 'A' || c == 'E' || c == 'I' || c == 'O' || c == 'U');
}
bool isLetter(char c) { return c >= 'A' && c <= 'Z' || c >= 'a' && c <= 'z'; }
bool isDigit(char c) { return c >= '0' && c <= '9'; }
char toLowerCase(char c) { return (isUpperCase(c)) ? (c + 32) : c; }
char toUpperCase(char c) { return (isLowerCase(c)) ? (c - 32) : c; }
int toInt(string s) {
  int r = 0;
  istringstream sin(s);
  sin >> r;
  return r;
}
double toDouble(string s) {
  double r = 0;
  istringstream sin(s);
  sin >> r;
  return r;
}
string toString(int n) {
  string s;
  stringstream convert;
  convert << n;
  s = convert.str();
  return s;
}
const double PI = 2 * acos(0.0);
const double EPS = 1e-11;
const int SIZE = 1e6 + 2;
int status[SIZE], prime[SIZE];
void sieve() {
  int I, K, sqrtN = int(sqrt((double)SIZE));
  status[0] = 1;
  status[1] = 1;
  for (I = 2; I <= sqrtN; I++) {
    if (!status[I]) {
      for (K = I * I; K <= SIZE; K += I) {
        if (!status[K]) status[K] = 1;
      }
    }
  }
}
int main() {
  std::ios_base::sync_with_stdio(0);
  int tcases, caseno = 1, I, J, K, N, n, m, cnt = 0, len, M, S;
  sieve();
  cin >> n;
  K = n - 2;
  for (I = 2; I <= n / 2; I++) {
    if (status[I] && status[K]) {
      if (I + K == n) {
        cout << I << " " << K << '\n';
        break;
      }
      K--;
    } else
      K--;
  }
  return 0;
}