Problem: There is data on sales of your company. Your task is to write a program which identifies good workers.

The program should read a list of data where each item includes the employee ID i, the amount of sales q and the corresponding unit price p. Then, the program should print IDs of employees whose total sales proceeds (i.e. sum of p × q) is greater than or equal to 1,000,000 in the order of inputting. If there is no such employees, the program should print "NA". You can suppose that n < 4000, and each employee has an unique ID. The unit price p is less than or equal to 1,000,000 and the amount of sales q is less than or equal to 100,000.



Input

The input consists of several datasets. The input ends with a line including a single 0. Each dataset consists of:


n (the number of data in the list)
i p q
i p q
:
:
i p q


Output

For each dataset, print a list of employee IDs or a text "NA"

Example

Input

4
1001 2000 520
1002 1800 450
1003 1600 625
1001 200 1220
2
1001 100 3
1005 1000 100
2
2013 5000 100
2013 5000 100
0


Output

1001
1003
NA
2013

Solution (in CPP):

Solution:
#include<iostream>
#include<vector>
#include<map>
#include<algorithm>
using namespace std;

int main(){
	vector<pair<int,long long> > v;
	int n,a;
	long long b,c;
	while(cin>>n&&n){
		v.clear();
		while(n--){
			cin>>a>>b>>c;
			int index = -1;
			for(int i=0;i<v.size();i++){
				if(a==v[i].first){
					index = i;
					break;
				}
			}
			if(index==-1)v.push_back(make_pair(a,b*c));
			else v[index].second += b*c;
		}
		bool flag = false;
		for(int i=0;i<v.size();i++){
			if(v[i].second >= 1000000){
				flag = true;
				cout<<v[i].first<<endl;
			}
		}
		if(!flag)cout<<"NA\n";
	}
	return 0;
}