Problem: Artsem has a friend Saunders from University of Chicago. Saunders presented him with the following problem.

Let [n] denote the set {1, ..., n}. We will also write f: [x] → [y] when a function f is defined in integer points 1, ..., x, and all its values are integers from 1 to y.

Now then, you are given a function f: [n] → [n]. Your task is to find a positive integer m, and two functions g: [n] → [m], h: [m] → [n], such that g(h(x)) = x for all <image>, and h(g(x)) = f(x) for all <image>, or determine that finding these is impossible.

Input

The first line contains an integer n (1 ≤ n ≤ 105).

The second line contains n space-separated integers — values f(1), ..., f(n) (1 ≤ f(i) ≤ n).

Output

If there is no answer, print one integer -1.

Otherwise, on the first line print the number m (1 ≤ m ≤ 106). On the second line print n numbers g(1), ..., g(n). On the third line print m numbers h(1), ..., h(m).

If there are several correct answers, you may output any of them. It is guaranteed that if a valid answer exists, then there is an answer satisfying the above restrictions.

Examples

Input

3
1 2 3


Output

3
1 2 3
1 2 3


Input

3
2 2 2


Output

1
1 1 1
2


Input

2
2 1


Output

-1

Solution (in PYTHON):

Solution:
import copy

size = int(raw_input())
f=[]
f = map(int,raw_input().split())
temp = copy.deepcopy(f)
temp.sort()
h = []
h.append(temp[0])
for num in temp:
    if(h[-1]==num):
        continue
    else:
        h.append(num)

dic = {}
for idx, num in enumerate(h):
    dic[num]=idx+1


g ={}
for idx,num in enumerate(f):
    g[idx+1]=dic[num]


for idx,num in enumerate(h):
    if(g[num]!=(idx+1)):
        print -1
        quit();

print len(h)
for num in g.values():
    print num,
print 
for num in h:
    print num,