Problem: You are given integers n, k. Let's consider the alphabet consisting of k different elements.

Let beauty f(s) of the string s be the number of indexes i, 1≤ i<|s|, for which prefix of s of length i equals to suffix of s of length i. For example, beauty of the string abacaba equals 2, as for i = 1, 3 prefix and suffix of length i are equal.

Consider all words of length n in the given alphabet. Find the expected value of f(s)^2 of a uniformly chosen at random word. We can show that it can be expressed as P/Q, where P and Q are coprime and Q isn't divided by 10^9 + 7. Output P⋅ Q^{-1} mod 10^9 + 7.

Input

The first and the only line contains two integers n, k (1≤ n ≤ 10^5, 1≤ k≤ 10^9) — the length of a string and the size of alphabet respectively.

Output

Output a single integer — P× Q^{-1} mod 10^9 + 7.

Examples

Input


2 3


Output


333333336


Input


1 5


Output


0


Input


100 1


Output


9801


Input


10 10


Output


412377396

Note

In the first example, there are 9 words of length 2 in alphabet of size 3 — aa, ab, ac, ba, bb, bc, ca, cb, cc. 3 of them have beauty 1 and 6 of them have beauty 0, so the average value is 1/3.

In the third example, there is only one such word, and it has beauty 99, so the average value is 99^2.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
template <class T>
void splitstr(const string &s, vector<T> &out) {
  istringstream in(s);
  out.clear();
  copy(istream_iterator<T>(in), istream_iterator<T>(), back_inserter(out));
}
static void redirect(int argc, const char **argv) {
  ios::sync_with_stdio(false);
  cin.tie(NULL);
  if (argc > 1) {
    static filebuf f;
    f.open(argv[1], ios::in);
    cin.rdbuf(&f);
    if (!cin) {
      cerr << "Failed to open '" << argv[1] << "'" << endl;
      exit(1);
    }
  }
  if (argc > 2) {
    static filebuf f;
    f.open(argv[2], ios::out | ios::trunc);
    cout.rdbuf(&f);
    if (!cout) {
      cerr << "Failed to open '" << argv[2] << "'" << endl;
    }
  }
  cin.exceptions(ios::failbit);
}
template <typename T>
static constexpr T gcd(T a, T b) {
  return b ? gcd(b, a % b) : a;
}
template <typename T>
static constexpr T wrap_pos(T a, T m) {
  return a < 0 ? a + m : a;
}
template <typename T>
static constexpr T sqr(T a) {
  return a * a;
}
template <typename T>
static constexpr T mod(T a, T m) {
  return wrap_pos(a % m, m);
}
template <typename T>
static constexpr T inverse2(T a, T m) {
  return a <= 1 ? a : mod((1 - inverse2(m % a, a) * m) / a, m);
}
template <typename T>
static constexpr T inverse(T a, T m) {
  return inverse2(mod(a, m), m);
}
template <typename T, typename P>
static constexpr T power(T a, P b) {
  return b == 0 ? T(1) : (b % 2) ? power(a, b - 1) * a : sqr(power(a, b / 2));
}
template <typename T, typename C, T Modulus>
class MR {
 private:
  struct tag_plus {};
  struct tag_minus {};
  struct tag_good {};
  T value;
  static_assert(std::numeric_limits<C>::max() / Modulus / Modulus > 0,
                "compute type is too small");
  static_assert(Modulus < std::numeric_limits<T>::max() / 2,
                "storage type is too small");
  static constexpr T reduce(T value, tag_plus) {
    return value >= Modulus ? value - Modulus : value;
  }
  static constexpr T reduce(T value, tag_minus) {
    return value < 0 ? value + Modulus : value;
  }
  static constexpr T reduce(T value, tag_good) { return value; }

 public:
  static constexpr T modulus = Modulus;
  constexpr MR() : value(0) {}
  constexpr MR(C value) : value(reduce(value % Modulus, tag_minus())) {}
  template <typename tag_t>
  constexpr MR(T value, tag_t tag) : value(reduce(value, tag)) {}
  MR &operator=(C value) {
    this->value = reduce(value % Modulus, tag_minus());
    return *this;
  }
  constexpr MR operator+(MR b) const { return MR(value + b.value, tag_plus()); }
  constexpr MR operator-(MR b) const {
    return MR(value - b.value, tag_minus());
  }
  constexpr MR operator*(MR b) const {
    return MR(C(value) * C(b.value) % Modulus, tag_good());
  }
  constexpr MR operator-() const { return MR(-value, tag_minus()); }
  MR &operator+=(MR b) {
    value = reduce(value + b.value, tag_plus());
    return *this;
  }
  MR &operator-=(MR b) {
    value = reduce(value - b.value, tag_minus());
    return *this;
  }
  MR &operator*=(MR b) {
    value = C(value) * C(b.value) % Modulus;
    return *this;
  }
  constexpr bool operator==(MR b) const { return value == b.value; }
  constexpr bool operator!=(MR b) const { return value != b.value; }
  constexpr T get() const { return value; }
  constexpr MR inverse() const {
    return MR(::inverse(C(value), C(Modulus)), tag_good());
  }
  constexpr MR operator/(MR b) const { return *this * b.inverse(); }
  MR &operator/=(MR b) { return *this *= b.inverse(); }
};
template <typename T, typename C, T Modulus>
static inline std::ostream &operator<<(std::ostream &o, MR<T, C, Modulus> mr) {
  return o << mr.get();
}
int main(int argc, const char **argv) {
  redirect(argc, argv);
  int N, K_;
  cin >> N >> K_;
  MR<int, long long, 1000000007> K{K_};
  MR<int, long long, 1000000007> ans = 0;
  vector<MR<int, long long, 1000000007> > powers(3 * N + 1);
  powers[0] = 1;
  for (int i = 1; i <= 3 * N; i++) powers[i] = powers[i - 1] * K;
  MR<int, long long, 1000000007> invKN = powers[N].inverse();
  vector<MR<int, long long, 1000000007> > dp(N + 1);
  for (int g = 1; g < N; g++) {
    for (int h = (N - 1) / g * g; h >= g; h -= g) {
      MR<int, long long, 1000000007> s;
      long long T = (N - 1) / h;
      long long L = (N + g + h - 1) / h;
      long long up = (2 * T - L + 2) * (2 * T - L + 1) / 2;
      if (K_ == 1)
        s = up;
      else {
        s = (powers[(T + 1) * h] - powers[h]) / (powers[h] - 1);
        s *= powers[(T + 1) * h];
        s -= powers[L * h] * T;
        s /= powers[h] - 1;
        s *= invKN;
      }
      s += powers[g] * (T * T - up);
      for (int i = 2 * h; i < N; i += h) s -= dp[i];
      dp[h] = s;
    }
    ans += dp[g];
  }
  ans /= powers[N];
  cout << ans << '\n';
  return 0;
}