Problem: There are n distinct points on a coordinate line, the coordinate of i-th point equals to x_i. Choose a subset of the given set of points such that the distance between each pair of points in a subset is an integral power of two. It is necessary to consider each pair of points, not only adjacent. Note that any subset containing one element satisfies the condition above. Among all these subsets, choose a subset with maximum possible size.

In other words, you have to choose the maximum possible number of points x_{i_1}, x_{i_2}, ..., x_{i_m} such that for each pair x_{i_j}, x_{i_k} it is true that |x_{i_j} - x_{i_k}| = 2^d where d is some non-negative integer number (not necessarily the same for each pair of points).

Input

The first line contains one integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the number of points.

The second line contains n pairwise distinct integers x_1, x_2, ..., x_n (-10^9 ≤ x_i ≤ 10^9) — the coordinates of points.

Output

In the first line print m — the maximum possible number of points in a subset that satisfies the conditions described above.

In the second line print m integers — the coordinates of points in the subset you have chosen.

If there are multiple answers, print any of them.

Examples

Input

6
3 5 4 7 10 12


Output

3
7 3 5

Input

5
-1 2 5 8 11


Output

1
8

Note

In the first example the answer is [7, 3, 5]. Note, that |7-3|=4=2^2, |7-5|=2=2^1 and |3-5|=2=2^1. You can't find a subset having more points satisfying the required property.

Solution (in JAVA):

Solution:
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 */

import java.io.*;
import java.util.*;

public class Main {

    void solve() throws IOException {
        int n = readInt();
        long[] x = new long[n];
        for (int i = 0; i < n; i++) x[i] = readInt();
        HashSet<Long> set = new HashSet<>();
        for (long a : x) set.add(a);
        long[] pow2 = new long[31];
        pow2[0] = 1;
        for (int i = 1; i < 31; i++) pow2[i] = pow2[i - 1] << 1;
        long[] ans = new long[3];
        int answer = 0;
        long[] preans = new long[3];
        for (long f : set) {
            Arrays.fill(preans, -Integer.MAX_VALUE);
            int cur = 1;
            preans[0] = f;
            boolean f1, f2;
            for (long d : pow2) {
                int pre = 1;
                f1 = false;
                f2 = false;
                if (set.contains(f - d)) {
                    pre++;
                    f1 = true;
                }
                if (set.contains(f + d)) {
                    pre++;
                    f2 = true;
                }
                if (pre > cur) {
                    cur = pre;
                    if (f1) preans[1] = f - d;
                    if (f2) preans[2] = f + d;
                }
            }
            Arrays.sort(preans);
            if (answer < cur) {
                answer = cur;
                ans = preans.clone();
            }
        }
        out.println(answer);
        for (int i = 0; i < 3; i++)
            if (ans[i] != -Integer.MAX_VALUE)
                out.print(ans[i] + " ");

    }

    public static void main(String[] args) throws IOException {
        new Main().run();
    }

    BufferedReader in;
    PrintWriter out;
    StringTokenizer tok;

    Main() throws FileNotFoundException {
        try {
            in = new BufferedReader(new FileReader("input.txt"));
            out = new PrintWriter("output.txt");
        } catch (Exception e) {
            in = new BufferedReader(new InputStreamReader(System.in));
            out = new PrintWriter(System.out);
        }
        tok = new StringTokenizer("");
    }

    void run() throws IOException {
        solve();
        out.close();
    }

    String delimiter = " ";

    String readLine() throws IOException {
        return in.readLine();
    }

    String readString() throws IOException {
        while (!tok.hasMoreTokens()) {
            String nextLine = readLine();
            if (null == nextLine) return null;
            tok = new StringTokenizer(nextLine);
        }
        return tok.nextToken(delimiter);
    }

    int readInt() throws IOException {
        return Integer.parseInt(readString());
    }

    long readLong() throws IOException {
        return Long.parseLong(readString());
    }

    double readDouble() throws IOException {
        return Double.parseDouble(readString());
    }

    int[] readIntArray(int b) {
        int a[] = new int[b];
        for (int i = 0; i < b; i++)
            try {
                a[i] = readInt();
            } catch (IOException e) {
                e.printStackTrace();
            }
        return a;
    }

    int[] readSortedIntArray(int size) throws IOException {
        Integer[] array = new Integer[size];
        for (int index = 0; index < size; ++index) array[index] = readInt();
        Arrays.sort(array);
        int[] sortedArray = new int[size];
        for (int index = 0; index < size; ++index) sortedArray[index] = array[index];
        return sortedArray;
    }

    int[] sortedIntArray(int size, int[] array) throws IOException {
        for (int index = 0; index < size; ++index) array[index] = readInt();
        Arrays.sort(array);
        int[] sortedArray = new int[size];
        for (int index = 0; index < size; ++index) sortedArray[index] = array[index];
        return sortedArray;
    }

    int minInt(int... values) {
        int min = Integer.MAX_VALUE;
        for (int value : values) min = Math.min(min, value);
        return min;
    }

    int maxInt(int... values) {
        int max = Integer.MIN_VALUE;
        for (int value : values) max = Math.max(max, value);
        return max;
    }

    long minLong(long... values) {
        long min = Long.MAX_VALUE;
        for (long value : values) min = Math.min(min, value);
        return min;
    }

    long maxLong(long... values) {
        long max = Long.MIN_VALUE;
        for (long value : values) max = Math.max(max, value);
        return max;
    }

    boolean checkIndex(int index, int size) {
        return (0 <= index && index < size);
    }

    int abs(int a) {
        if (a < 0) return -a;
        return a;
    }
}