Problem: You are given a positive number x. Find the smallest positive integer number that has the sum of digits equal to x and all digits are distinct (unique).

Input

The first line contains a single positive integer t (1 ≤ t ≤ 50) — the number of test cases in the test. Then t test cases follow.

Each test case consists of a single integer number x (1 ≤ x ≤ 50).

Output

Output t answers to the test cases:

  * if a positive integer number with the sum of digits equal to x and all digits are different exists, print the smallest such number; 
  * otherwise print -1. 

Example

Input


4
1
5
15
50


Output


1
5
69
-1

Solution (in PYTHON3):

Solution:
for i in range(int(input())):
        n=int(input())
        u=[1,2,3,4,5,6,7,8,9]
        uyt=[19,29,39,49,59,69,79,89,189,289,389,489,589,689,789,1789,2789,3789,4789,5789,6789,16789,26789,36789,46789,56789,156789,256789,356789,456789,1456789,2456789,3456789,13456789,23456789,123456789]
        ui=[10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,34,35,36,37,38,39,40,41,42,43,44,45]
        if n in u:
                print(n)
        elif n in ui:
                print(uyt[ui.index(n)])
        else:
                print(-1)