Problem: It's tough to be a superhero. And it's twice as tough to resist the supervillain who is cool at math. Suppose that you're an ordinary Batman in an ordinary city of Gotham. Your enemy Joker mined the building of the city administration and you only have several minutes to neutralize the charge. To do that you should enter the cancel code on the bomb control panel.

However, that mad man decided to give you a hint. This morning the mayor found a playing card under his pillow. There was a line written on the card:

<image>

The bomb has a note saying "J(x) = A", where A is some positive integer. You suspect that the cancel code is some integer x that meets the equation J(x) = A. Now in order to decide whether you should neutralize the bomb or run for your life, you've got to count how many distinct positive integers x meet this equation.

Input

The single line of the input contains a single integer A (1 ≤ A ≤ 1012).

Output

Print the number of solutions of the equation J(x) = A.

Examples

Input

3


Output

1


Input

24


Output

3

Note

Record x|n means that number n divides number x.

<image> is defined as the largest positive integer that divides both a and b.

In the first sample test the only suitable value of x is 2. Then J(2) = 1 + 2.

In the second sample test the following values of x match:

  * x = 14, J(14) = 1 + 2 + 7 + 14 = 24
  * x = 15, J(15) = 1 + 3 + 5 + 15 = 24
  * x = 23, J(23) = 1 + 23 = 24

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
template <class T>
void chmax(T& l, const T r) {
  l = max(l, r);
}
template <class T>
void chmin(T& l, const T r) {
  l = min(l, r);
}
void reader(int& x) {
  int k, m = 0;
  x = 0;
  for (;;) {
    (k) = getchar_unlocked();
    if (k == '-') {
      m = 1;
      break;
    }
    if ('0' <= k && k <= '9') {
      x = k - '0';
      break;
    }
  }
  for (;;) {
    (k) = getchar_unlocked();
    if (k < '0' || k > '9') break;
    x = x * 10 + k - '0';
  }
  if (m) x = -x;
}
void reader(long long& x) {
  int k, m = 0;
  x = 0;
  for (;;) {
    (k) = getchar_unlocked();
    if (k == '-') {
      m = 1;
      break;
    }
    if ('0' <= k && k <= '9') {
      x = k - '0';
      break;
    }
  }
  for (;;) {
    (k) = getchar_unlocked();
    if (k < '0' || k > '9') break;
    x = x * 10 + k - '0';
  }
  if (m) x = -x;
}
int reader(char c[]) {
  int i, s = 0;
  for (;;) {
    (i) = getchar_unlocked();
    if (i != ' ' && i != '\n' && i != '\r' && i != '\t' && i != EOF) break;
  }
  c[s++] = i;
  for (;;) {
    (i) = getchar_unlocked();
    if (i == ' ' || i == '\n' || i == '\r' || i == '\t' || i == EOF) break;
    c[s++] = i;
  }
  c[s] = '\0';
  return s;
}
template <class T, class S>
void reader(T& x, S& y) {
  reader(x);
  reader(y);
}
template <class T, class S, class U>
void reader(T& x, S& y, U& z) {
  reader(x);
  reader(y);
  reader(z);
}
template <class T, class S, class U, class V>
void reader(T& x, S& y, U& z, V& w) {
  reader(x);
  reader(y);
  reader(z);
  reader(w);
}
void writer(int x, char c) {
  int s = 0, m = 0;
  char f[10];
  if (x < 0) m = 1, x = -x;
  while (x) f[s++] = x % 10, x /= 10;
  if (!s) f[s++] = 0;
  if (m) putchar_unlocked('-');
  while (s--) putchar_unlocked(f[s] + '0');
  putchar_unlocked(c);
}
void writer(long long x, char c) {
  int s = 0, m = 0;
  char f[20];
  if (x < 0) m = 1, x = -x;
  while (x) f[s++] = x % 10, x /= 10;
  if (!s) f[s++] = 0;
  if (m) putchar_unlocked('-');
  while (s--) putchar_unlocked(f[s] + '0');
  putchar_unlocked(c);
}
void writer(const char c[]) {
  int i;
  for (i = 0; c[i] != '\0'; i++) putchar_unlocked(c[i]);
}
void writer(const char x[], char c) {
  int i;
  for (i = 0; x[i] != '\0'; i++) putchar_unlocked(x[i]);
  putchar_unlocked(c);
}
template <class T>
void writerLn(T x) {
  writer(x, '\n');
}
template <class T, class S>
void writerLn(T x, S y) {
  writer(x, ' ');
  writer(y, '\n');
}
template <class T, class S, class U>
void writerLn(T x, S y, U z) {
  writer(x, ' ');
  writer(y, ' ');
  writer(z, '\n');
}
template <class T>
void writerArr(T x[], int n) {
  if (!n) {
    putchar_unlocked('\n');
    return;
  }
  for (int i = 0; i < (n - 1); i++) writer(x[i], ' ');
  writer(x[n - 1], '\n');
}
bool prime[1000001];
vector<int> prs;
void init_prime() {
  memset(prime, 1, sizeof(prime));
  prime[0] = prime[1] = false;
  for (int i = 2; i < sizeof(prime); i++)
    if (prime[i])
      for (int j = i * 2; j < sizeof(prime); j += i) prime[j] = false;
  for (int i = 2; i < sizeof(prime); i++)
    if (prime[i]) prs.push_back(i);
}
bool is_prime(long long n) {
  for (long long p : prs) {
    if (p * p > n) return true;
    if (n % p == 0) return false;
  }
  return true;
}
template <class T>
T gcd(T a, T b) {
  return b ? gcd(b, a % b) : a;
}
int greedy(int n) {
  int ans = 0;
  for (int i = 1; i <= n; i++) {
    int cur = 0;
    for (int k = 1; k <= i; k++)
      if (i % k == 0 && gcd(k, i / k) == 1) cur += k;
    if (cur == n) ans++;
  }
  return ans;
}
bool can_div[((int)1e6)];
int f(long long a) {
  if (a == 1) return 1;
  if (a == 2) return 0;
  for (int i = 1; i < ((int)1e6); i++) {
    if (i > a) break;
    if (a % i == 0) {
      can_div[i] = true;
    }
  }
  map<long long, int> mp;
  mp[a] = 1;
  for (long long p : prs) {
    map<long long, int> add;
    for (long long np = p; np < a; np *= p) {
      const long long b = np + 1;
      if (b < ((int)1e6)) {
        if (!can_div[b]) continue;
      } else {
        if (a % b != 0) continue;
      }
      for (auto it = mp.rbegin(); it != mp.rend(); ++it) {
        auto& kv = *it;
        if (kv.first < b) break;
        if (kv.first % b == 0) {
          add[kv.first / b] += kv.second;
        }
      }
    }
    for (auto kv : add) {
      mp[kv.first] += kv.second;
    }
  }
  long long ans = 0;
  ans += mp[1];
  for (auto kv : mp) {
    if (kv.first <= ((int)1e6)) continue;
    long long x = kv.first - 1;
    if (is_prime(x)) ans += kv.second;
  }
  return ans;
}
int main() {
  init_prime();
  long long a;
  cin >> a;
  int ans = f(a);
  cout << ans << endl;
}