Problem: There are n boys and m girls studying in the class. They should stand in a line so that boys and girls alternated there as much as possible. Let's assume that positions in the line are indexed from left to right by numbers from 1 to n + m. Then the number of integers i (1 ≤ i < n + m) such that positions with indexes i and i + 1 contain children of different genders (position i has a girl and position i + 1 has a boy or vice versa) must be as large as possible. 

Help the children and tell them how to form the line.

Input

The single line of the input contains two integers n and m (1 ≤ n, m ≤ 100), separated by a space.

Output

Print a line of n + m characters. Print on the i-th position of the line character "B", if the i-th position of your arrangement should have a boy and "G", if it should have a girl. 

Of course, the number of characters "B" should equal n and the number of characters "G" should equal m. If there are multiple optimal solutions, print any of them.

Examples

Input

3 3


Output

GBGBGB


Input

4 2


Output

BGBGBB

Note

In the first sample another possible answer is BGBGBG. 

In the second sample answer BBGBGB is also optimal.

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.File;
import java.io.FileReader;
import java.io.PrintWriter;
import java.io.BufferedOutputStream;
import java.lang.Runnable;
import java.util.StringTokenizer;
import java.lang.Math;
import java.util.Arrays;

public class Solution implements Runnable {
    // Solution
    /* ______________________________________________________ */

    public void solve(InputReader in, PrintWriter out) {
        int nBoys = in.nextInt();
        int nGirls = in.nextInt();
        if (nBoys < nGirls) {
            for (int i = 0; i < nBoys; i++) {
                out.print("GB");
            }
            for (int i = nBoys; i < nGirls; i++) {
                out.print("G");
            }
        }
        else {
            for (int i = 0; i < nGirls; i++) {
                out.print("BG");
            }
            for (int i = nGirls; i < nBoys; i++) {
                out.print("B");
            }            
        }
    }


    /* ______________________________________________________ */
    // Template
    public static void main(String[] args) {
        new Solution().run();
    }

    public void run() {
        try {
            // BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
            BufferedReader reader = new BufferedReader(new FileReader("input.txt"));
            StringTokenizer tokenizer = null;
            InputReader in = new InputReader(reader, tokenizer);
            // PrintWriter out = new PrintWriter(new BufferedOutputStream(System.out));
            PrintWriter out = new PrintWriter(new File("output.txt"));
            solve(in, out);
            out.close();
        } catch (Exception e) {
            e.printStackTrace();
            System.exit(1);
        }
    }

    class InputReader {
        private BufferedReader reader;
        private StringTokenizer tokenizer;
        public int lineNumber = -1;

        public InputReader(BufferedReader reader, StringTokenizer tokenizer) {
            this.reader = reader;
            this.tokenizer = tokenizer;
        }

        public String next() {
            while ((tokenizer == null) || (!tokenizer.hasMoreTokens())) {
                try {
                    String line = reader.readLine();
                    if (line == null) return "EndOfStream";
                    lineNumber++;
                    tokenizer = new StringTokenizer(line);
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
            return tokenizer.nextToken();
        }

        public int nextInt() {
            return Integer.parseInt(next());
        }

        public long nextLong() {
            return Long.parseLong(next());
        }

        public char nextChar() {
            return next().charAt(0);
        }

        public int[] nextIntArray(int n) {
            int[] a = new int[n];
            for (int i = 0; i < n; i++) {
                a[i] = nextInt();
            }
            return a;
        }
    }
}