Problem: You are given three sequences: a_1, a_2, …, a_n; b_1, b_2, …, b_n; c_1, c_2, …, c_n.

For each i, a_i ≠ b_i, a_i ≠ c_i, b_i ≠ c_i.

Find a sequence p_1, p_2, …, p_n, that satisfy the following conditions:

  * p_i ∈ \\{a_i, b_i, c_i\}
  * p_i ≠ p_{(i mod n) + 1}.



In other words, for each element, you need to choose one of the three possible values, such that no two adjacent elements (where we consider elements i,i+1 adjacent for i<n and also elements 1 and n) will have equal value.

It can be proved that in the given constraints solution always exists. You don't need to minimize/maximize anything, you need to find any proper sequence.

Input

The first line of input contains one integer t (1 ≤ t ≤ 100): the number of test cases.

The first line of each test case contains one integer n (3 ≤ n ≤ 100): the number of elements in the given sequences.

The second line contains n integers a_1, a_2, …, a_n (1 ≤ a_i ≤ 100).

The third line contains n integers b_1, b_2, …, b_n (1 ≤ b_i ≤ 100).

The fourth line contains n integers c_1, c_2, …, c_n (1 ≤ c_i ≤ 100).

It is guaranteed that a_i ≠ b_i, a_i ≠ c_i, b_i ≠ c_i for all i.

Output

For each test case, print n integers: p_1, p_2, …, p_n (p_i ∈ \\{a_i, b_i, c_i\}, p_i ≠ p_{i mod n + 1}).

If there are several solutions, you can print any.

Example

Input


5
3
1 1 1
2 2 2
3 3 3
4
1 2 1 2
2 1 2 1
3 4 3 4
7
1 3 3 1 1 1 1
2 4 4 3 2 2 4
4 2 2 2 4 4 2
3
1 2 1
2 3 3
3 1 2
10
1 1 1 2 2 2 3 3 3 1
2 2 2 3 3 3 1 1 1 2
3 3 3 1 1 1 2 2 2 3


Output


1 2 3
1 2 1 2
1 3 4 3 2 4 2
1 3 2
1 2 3 1 2 3 1 2 3 2

Note

In the first test case p = [1, 2, 3].

It is a correct answer, because:

  * p_1 = 1 = a_1, p_2 = 2 = b_2, p_3 = 3 = c_3 
  * p_1 ≠ p_2 , p_2 ≠ p_3 , p_3 ≠ p_1 



All possible correct answers to this test case are: [1, 2, 3], [1, 3, 2], [2, 1, 3], [2, 3, 1], [3, 1, 2], [3, 2, 1].

In the second test case p = [1, 2, 1, 2].

In this sequence p_1 = a_1, p_2 = a_2, p_3 = a_3, p_4 = a_4. Also we can see, that no two adjacent elements of the sequence are equal.

In the third test case p = [1, 3, 4, 3, 2, 4, 2].

In this sequence p_1 = a_1, p_2 = a_2, p_3 = b_3, p_4 = b_4, p_5 = b_5, p_6 = c_6, p_7 = c_7. Also we can see, that no two adjacent elements of the sequence are equal.

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.ArrayList;
import java.util.StringTokenizer;

public class Main {
	public static void main(String[] args) throws Exception {
		Scanner sc = new Scanner();
		int t = sc.nextInt();
		while (t-- > 0) {
			int n = sc.nextInt();
			int a[] = new int[n];
			int b[] = new int[n];
			int c[] = new int[n];
			for (int i = 0; i < n; i++) {
				a[i] = sc.nextInt();
			}
			for (int i = 0; i < n; i++) {
				b[i] = sc.nextInt();
			}
			for (int i = 0; i < n; i++) {
				c[i] = sc.nextInt();
			}
			ArrayList<Integer> ar = new ArrayList<Integer>();
			ar.add(a[0]);
			for (int i = 1; i < n; i++) {
				int x = a[i];
				int y = b[i];
				int z = c[i];
				if (i == n - 1) {
					if (x != ar.get(ar.size() - 1) && x != ar.get(0)) {
						ar.add(x);
					} else if (y != ar.get(ar.size() - 1) && y != ar.get(0)) {
						ar.add(y);

					} else {
						ar.add(z);

					}

				} else {
					if (x != ar.get(ar.size() - 1)) {
						ar.add(x);
					} else if (y != ar.get(ar.size() - 1)) {
						ar.add(y);

					} else {
						ar.add(z);

					}

				}

			}
			StringBuilder sb = new StringBuilder();

			for (int i : ar) {
				sb.append(i + " ");
			}

			System.out.println(sb);

		}

	}

}

class Scanner {
	BufferedReader br;
	StringTokenizer st;

	Scanner() {
		br = new BufferedReader(new InputStreamReader(System.in));
	}

	String next() throws IOException {
		while (st == null || !st.hasMoreElements())
			st = new StringTokenizer(br.readLine());
		return st.nextToken();
	}

	int nextInt() throws NumberFormatException, IOException {
		return Integer.parseInt(next());
	}

	long nextLong() throws NumberFormatException, IOException {
		return Long.parseLong(next());
	}
}

//creating a hash table
//Hashtable<Integer, String> h = new Hashtable<Integer, String>();
//
//Hashtable<Integer, String> h1 = new Hashtable<Integer, String>();
//
//h.put(3, "Geeks");
//h.put(2, "forGeeks");
//h.put(1, "isBest");
//System.out.println(h.get(1));
//if (h.containsKey(1)) {
//	System.out.println(1111111);
//}
//if (h.containsValue("isBest")) {
//	System.out.println(1111111);
//}
//
//// create a clone or shallow copy of hash table h
//h1 = (Hashtable<Integer, String>) h.clone();
//
//// checking clone h1
////System.out.println("values in clone: " + h1);
//
//// clear hash table h
//h.clear();

//Creating object of the 
// class linked list 
//LinkedList<String> ll 
//    = new LinkedList<String>(); 
//
//// Adding elements to the linked list 
//ll.add("A"); 
//ll.add("B"); 
//ll.addLast("C"); 
//ll.addFirst("D"); 
//ll.add(2, "E"); 
//
//System.out.println(ll); 
//
//ll.remove("B"); 
//ll.remove(3); 
//ll.removeFirst(); 
//ll.removeLast(); 
//
//System.out.println(ll); 

//Set<Integer> set = new HashSet<Integer>();
//try {
//   for(int i = 0; i < 5; i++) {
//      set.add(count[i]);
//   }
//   System.out.println(set);
//
//   TreeSet sortedSet = new TreeSet<Integer>(set);
//   System.out.println("The sorted list is:");
//   System.out.println(sortedSet);
//
//   System.out.println("The First element of the set is: "+ (Integer)sortedSet.first());
//   System.out.println("The last element of the set is: "+ (Integer)sortedSet.last());
//}
//catch(Exception e) {}