Problem: You are given two positive integers n and k. Print the k-th positive integer that is not divisible by n.

For example, if n=3, and k=7, then all numbers that are not divisible by 3 are: 1, 2, 4, 5, 7, 8, 10, 11, 13 .... The 7-th number among them is 10.

Input

The first line contains an integer t (1 ≤ t ≤ 1000) — the number of test cases in the input. Next, t test cases are given, one per line.

Each test case is two positive integers n (2 ≤ n ≤ 10^9) and k (1 ≤ k ≤ 10^9).

Output

For each test case print the k-th positive integer that is not divisible by n.

Example

Input


6
3 7
4 12
2 1000000000
7 97
1000000000 1000000000
2 1


Output


10
15
1999999999
113
1000000001
1

Solution (in PYTHON3):

Solution:
#!/usr/bin/python3

# Codeforces - Round 640
# Problem C - K-th Not Divisible by n


def read_int():
	n = int(input())
	return n


def read_ints():
	ints = [int(x) for x in input().split(" ")]
	return ints
	

#---

def solve(n,k):
	cntr = k // (n-1)
	sol = cntr + k
	
	if sol % n == 0:
		sol -= 1
	
	return sol

# Main
t = read_int()
for case in range(t):
	n, k = read_ints()
	sol = solve(n,k)
	
	print (sol)