Problem: Being stuck at home, Ray became extremely bored. To pass time, he asks Lord Omkar to use his time bending power: Infinity Clock! However, Lord Omkar will only listen to mortals who can solve the following problem:

You are given an array a of n integers. You are also given an integer k. Lord Omkar wants you to do k operations with this array.

Define one operation as the following: 

  1. Set d to be the maximum value of your array. 
  2. For every i from 1 to n, replace a_{i} with d-a_{i}. 



The goal is to predict the contents in the array after k operations. Please help Ray determine what the final sequence will look like!

Input

Each test contains multiple test cases. The first line contains the number of cases t (1 ≤ t ≤ 100). Description of the test cases follows.

The first line of each test case contains two integers n and k (1 ≤ n ≤ 2 ⋅ 10^5, 1 ≤ k ≤ 10^{18}) – the length of your array and the number of operations to perform.

The second line of each test case contains n integers a_{1},a_{2},...,a_{n} (-10^9 ≤ a_{i} ≤ 10^9) – the initial contents of your array.

It is guaranteed that the sum of n over all test cases does not exceed 2 ⋅ 10^5.

Output

For each case, print the final version of array a after k operations described above.

Example

Input


3
2 1
-199 192
5 19
5 -1 4 2 0
1 2
69


Output


391 0
0 6 1 3 5
0

Note

In the first test case the array changes as follows:

  * Initially, the array is [-199, 192]. d = 192.

  * After the operation, the array becomes [d-(-199), d-192] = [391, 0].

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.BitSet;
import java.util.StringTokenizer;

public class ProbB {
    private static void solve() throws Exception {
        int n = fs.nextInt();
        long k = fs.nextLong();
        int[] a = fs.readArray(n);
        int[] odd = op(a);
        int[] even = op(odd);
        if (k%2 == 1) {
            for (int x : odd) {
                out.print(x);
                out.print(' ');
            }
        } else {
            for (int x : even) {
                out.print(x);
                out.print(' ');
            }
        }
        out.println();
    }

    private static int[] op(int[] r) {
        int maxx = Integer.MIN_VALUE;
        for (int x: r) { maxx = Math.max(maxx,x ); }
        int[] a = new int[r.length];
        for (int i = 0 ; i < r.length; i ++ ) {
            a[i] = maxx - r[i];
        }
        return a;
    }

    private static FastScanner fs = new FastScanner();
    private static PrintWriter out = new PrintWriter(System.out);

    public static void main(String[] args) throws Exception {
        int T = fs.nextInt();
        for (int t = 0; t < T; t++) {
            solve();
        }
        out.close();
    }

    static void debug(Object... O) {
        System.err.print("DEBUG ");
        System.err.println(Arrays.deepToString(O));
    }

    static class FastScanner {
        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
        StringTokenizer st = new StringTokenizer("");

        String next() {
            while (!st.hasMoreTokens())
                try {
                    st = new StringTokenizer(br.readLine());
                } catch (IOException e) {
                    e.printStackTrace();
                }
            return st.nextToken();
        }

        int nextInt() {
            return Integer.parseInt(next());
        }

        int[] readArray(int n) {
            int[] a = new int[n];
            for (int i = 0; i < n; i++) a[i] = nextInt();
            return a;
        }

        long nextLong() {
            return Long.parseLong(next());
        }

        double nextDouble() {
            return Double.parseDouble(next());
        }

        String nextString() {
            return next();
        }
    }
}