Problem: You are given two positive integers n and k. Print the k-th positive integer that is not divisible by n.

For example, if n=3, and k=7, then all numbers that are not divisible by 3 are: 1, 2, 4, 5, 7, 8, 10, 11, 13 .... The 7-th number among them is 10.

Input

The first line contains an integer t (1 ≤ t ≤ 1000) — the number of test cases in the input. Next, t test cases are given, one per line.

Each test case is two positive integers n (2 ≤ n ≤ 10^9) and k (1 ≤ k ≤ 10^9).

Output

For each test case print the k-th positive integer that is not divisible by n.

Example

Input


6
3 7
4 12
2 1000000000
7 97
1000000000 1000000000
2 1


Output


10
15
1999999999
113
1000000001
1

Solution (in JAVA):

Solution:
/**
 * @author egaeus
 * @mail sebegaeusprogram@gmail.com
 * @veredict
 * @url
 * @category
 * @date
 **/

import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.util.StringTokenizer;

import static java.lang.Integer.parseInt;

public class CFC {
    public static void main(String args[]) throws Throwable {
        BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
        int T = parseInt(in.readLine());
        for (int t = 0; t < T; t++) {
            StringTokenizer st = new StringTokenizer(in.readLine());
            long N = parseInt(st.nextToken()), K = parseInt(st.nextToken());
            long q = K / (N - 1);
            System.out.println(q * N + K % (N - 1) - (K % (N -1) == 0 ? 1 : 0));
        }
    }
}