Problem: Boboniu likes playing chess with his employees. As we know, no employee can beat the boss in the chess game, so Boboniu has never lost in any round.

You are a new applicant for his company. Boboniu will test you with the following chess question:

Consider a n× m grid (rows are numbered from 1 to n, and columns are numbered from 1 to m). You have a chess piece, and it stands at some cell (S_x,S_y) which is not on the border (i.e. 2 ≤ S_x ≤ n-1 and 2 ≤ S_y ≤ m-1).

From the cell (x,y), you can move your chess piece to (x,y') (1≤ y'≤ m, y' ≠ y) or (x',y) (1≤ x'≤ n, x'≠ x). In other words, the chess piece moves as a rook. From the cell, you can move to any cell on the same row or column.

Your goal is to visit each cell exactly once. Can you find a solution?

Note that cells on the path between two adjacent cells in your route are not counted as visited, and it is not required to return to the starting point.

Input

The only line of the input contains four integers n, m, S_x and S_y (3≤ n,m≤ 100, 2 ≤ S_x ≤ n-1, 2 ≤ S_y ≤ m-1) — the number of rows, the number of columns, and the initial position of your chess piece, respectively.

Output

You should print n⋅ m lines.

The i-th line should contain two integers x_i and y_i (1 ≤ x_i ≤ n, 1 ≤ y_i ≤ m), denoting the i-th cell that you visited. You should print exactly nm pairs (x_i, y_i), they should cover all possible pairs (x_i, y_i), such that 1 ≤ x_i ≤ n, 1 ≤ y_i ≤ m.

We can show that under these constraints there always exists a solution. If there are multiple answers, print any.

Examples

Input


3 3 2 2


Output


2 2
1 2
1 3
2 3
3 3
3 2
3 1
2 1
1 1


Input


3 4 2 2


Output


2 2
2 1
2 3
2 4
1 4
3 4
3 3
3 2
3 1
1 1
1 2
1 3

Note

Possible routes for two examples:

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Solution (in JAVA):

Solution:
import java.io.*;
import java.util.StringTokenizer;
import java.util.function.Function;

public class Main {

    public static void main(String[] args) throws Exception {
        MyScanner sc = new MyScanner();
        out = new PrintWriter(new BufferedOutputStream(System.out));

        // Start writing your solution here. -------------------------------------
        int n = sc.nextInt();
        int m = sc.nextInt();
        int sx = sc.nextInt();
        int sy = sc.nextInt();
        int[][] visited = new int[n + 1][m + 1];
        out.print(sx);
        out.print(" ");
        out.println(sy);
        visited[sx][sy] = 1;
        for (int i = 1; i <= m; i++) {
            if (visited[sx][i] == 0) {
                sy = i;
                out.print(sx);
                out.print(" ");
                out.println(sy);
                visited[sx][sy] = 1;
            }
        }
        for (int i = 1; i <= n; i++) {
            if (visited[i][sy] == 0) {
                sx = i;
                out.print(sx);
                out.print(" ");
                out.println(sy);
                visited[sx][sy] = 1;
                for (int j = 1; j <= m; j++) {
                    if (visited[sx][j] == 0) {
                        sy = j;
                        out.print(sx);
                        out.print(" ");
                        out.println(sy);
                        visited[sx][sy] = 1;
                    }
                }
            }
        }
        // Stop writing your solution here. -------------------------------------
        out.close();
    }

    static int countMatches(String s, char c) {
        return s.length() - s.replaceAll(String.valueOf(c), "").length();
    }

    public static class Pair<L,R> {
        private L l;
        private R r;
        public Pair(L l, R r){
            this.l = l;
            this.r = r;
        }
        public L getL(){ return l; }
        public R getR(){ return r; }
        public void setL(L l){ this.l = l; }
        public void setR(R r){ this.r = r; }
    }

    public static class SegmentTree {

        private final Function<Long, SegmentTreeNode> buildFunction;
        private final Function3<SegmentTreeNode, SegmentTreeNode, SegmentTreeNode> mergeFunction;

        public static class SegmentTreeNode {
            long value;
            long l, r;

            SegmentTreeNode(long value, long l, long r) {
                this.value = value;
                this.l = l;
                this.r = r;
            }
        }

        SegmentTreeNode[] segmentTreeNodes;
        long size;

        SegmentTree(long n, Function<Long, SegmentTreeNode> buildFunction,
                    Function3<SegmentTreeNode, SegmentTreeNode, SegmentTreeNode> mergeFunction) {
            size = 4 * n + 1;
            segmentTreeNodes = new SegmentTreeNode[(int) size];
            this.buildFunction = buildFunction;
            this.mergeFunction = mergeFunction;
        }

        void build(int id, long l, long r) throws Exception {
            if (l == r) {
                segmentTreeNodes[id] = buildFunction.apply(l);
            } else {
                long mid = (l + r) / 2;
                build(2 * id, l, mid);
                build(2 * id + 1, mid + 1, r);
                segmentTreeNodes[id] = mergeFunction.apply(segmentTreeNodes[2 * id], segmentTreeNodes[2 * id + 1]);
            }
        }

        SegmentTreeNode query(int id, long l, long r, long u, long v) {
            if (v < l || u > r) {
                return new SegmentTreeNode(0, 0, 0);
            }

            if (u <= l && v >= r) {
                return segmentTreeNodes[id];
            }

            long mid = (l + r) / 2;
            return mergeFunction.apply(query(2 * id, l, mid, u, v), query(2 * id + 1, mid + 1, r, u, v));
        }
    }

    interface Function1<One> {
        One apply();
    }

    interface Function3<One, Two, Three> {
        Three apply(One one, Two two);
    }

    //-----------PrintWriter for faster output---------------------------------
    public static PrintWriter out;

    //-----------MyScanner class for faster input----------
    public static class MyScanner {

        BufferedReader br;
        StringTokenizer st;

        public MyScanner() {
            br = new BufferedReader(new InputStreamReader(System.in));
        }

        String next() {
            while (st == null || !st.hasMoreElements()) {
                try {
                    st = new StringTokenizer(br.readLine());
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
            return st.nextToken();
        }

        int nextInt() {
            return Integer.parseInt(next());
        }

        long nextLong() {
            return Long.parseLong(next());
        }

        double nextDouble() {
            return Double.parseDouble(next());
        }

        String nextLine() {
            String str = "";
            try {
                str = br.readLine();
            } catch (IOException e) {
                e.printStackTrace();
            }
            return str;
        }

    }
    //--------------------------------------------------------
}