Problem: You are given two positive integers n and k. Print the k-th positive integer that is not divisible by n.

For example, if n=3, and k=7, then all numbers that are not divisible by 3 are: 1, 2, 4, 5, 7, 8, 10, 11, 13 .... The 7-th number among them is 10.

Input

The first line contains an integer t (1 ≤ t ≤ 1000) — the number of test cases in the input. Next, t test cases are given, one per line.

Each test case is two positive integers n (2 ≤ n ≤ 10^9) and k (1 ≤ k ≤ 10^9).

Output

For each test case print the k-th positive integer that is not divisible by n.

Example

Input


6
3 7
4 12
2 1000000000
7 97
1000000000 1000000000
2 1


Output


10
15
1999999999
113
1000000001
1

Solution (in JAVA):

Solution:
import java.util.*;
import java.lang.*;
import java.io.*;

public class Solution{
  public static void main(String[] args) throws IOException{
    StringBuilder print = new StringBuilder();
    BufferedReader input = new BufferedReader(new InputStreamReader(System.in));
    int t = Integer.parseInt(input.readLine());
    while(t-- > 0){
      StringTokenizer st = new StringTokenizer(input.readLine());
      int n = Integer.parseInt(st.nextToken());
      int k = Integer.parseInt(st.nextToken());
      int finalNum = (k/(n-1) * n) + (k%(n-1));
      if( k%(n-1) == 0 ){
        finalNum--;
      }
      print.append(finalNum + "\n");
    }
    System.out.println(print.toString());
  }
}