Problem: Let's call some square matrix with integer values in its cells palindromic if it doesn't change after the order of rows is reversed and it doesn't change after the order of columns is reversed.

For example, the following matrices are palindromic:

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The following matrices are not palindromic because they change after the order of rows is reversed:

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The following matrices are not palindromic because they change after the order of columns is reversed:

<image>

You are given n^2 integers. Put them into a matrix of n rows and n columns so that each number is used exactly once, each cell contains exactly one number and the resulting matrix is palindromic. If there are multiple answers, print any. If there is no solution, print "NO".

Input

The first line contains one integer n (1 ≤ n ≤ 20).

The second line contains n^2 integers a_1, a_2, ..., a_{n^2} (1 ≤ a_i ≤ 1000) — the numbers to put into a matrix of n rows and n columns.

Output

If it is possible to put all of the n^2 numbers into a matrix of n rows and n columns so that each number is used exactly once, each cell contains exactly one number and the resulting matrix is palindromic, then print "YES". Then print n lines with n space-separated numbers — the resulting matrix.

If it's impossible to construct any matrix, then print "NO".

You can print each letter in any case (upper or lower). For example, "YeS", "no" and "yES" are all acceptable.

Examples

Input


4
1 8 8 1 2 2 2 2 2 2 2 2 1 8 8 1


Output


YES
1 2 2 1
8 2 2 8
8 2 2 8
1 2 2 1


Input


3
1 1 1 1 1 3 3 3 3


Output


YES
1 3 1
3 1 3
1 3 1


Input


4
1 2 1 9 8 4 3 8 8 3 4 8 9 2 1 1


Output


NO


Input


1
10


Output


YES
10 

Note

Note that there exist multiple answers for the first two examples.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
long long int ll_max(long long int a, long long int b, long long int c) {
  return max(a, max(b, c));
}
int int_max(int a, int b, int c) { return max(a, max(b, c)); }
long long int ll_min(long long int a, long long int b, long long int c) {
  return min(a, min(b, c));
}
int int_min(int a, int b, int c) { return min(a, min(b, c)); }
long long int max(int a, long long int b) { return max((long long int)a, b); }
long long int min(int a, long long int b) { return min((long long int)a, b); }
long long int min(long long int a, int b) { return min(a, (long long int)b); }
long long int max(long long int a, int b) { return max(a, (long long int)b); }
long long int maximum(long long int a[], long long int n) {
  long long int max1 = LLONG_MIN;
  for (long long int i = 0; i < n; i++) {
    max1 = max(max1, a[i]);
  }
  return max1;
}
long long int minimum(long long int a[], long long int n) {
  long long int min1 = LLONG_MAX;
  for (long long int i = 0; i < n; i++) {
    min1 = min(min1, a[i]);
  }
  return min1;
}
long long int dx[] = {0, 0, 1, -1};
long long int dy[] = {1, -1, 0, 0};
long long int power(long long int x, long long int y, long long int m) {
  if (y == 0) return 1;
  long long int a = power(x, y / 2, m);
  if (y % 2) {
    return (a * ((a * x) % m)) % m;
  } else {
    return (a * a) % m;
  }
}
long long int mod_inverse(long long int x, long long int m) {
  return power(x, m - 2, m);
}
long long int fact(long long int n, long long int m) {
  if (n <= 1) return 1;
  return (fact(n - 1, m) * n) % m;
}
long long int ncr(long long int n, long long int r, long long int m) {
  if (r > n) return 0;
  long long int n1 = 1, d1 = 1, d2 = 1;
  n1 = fact(n, m);
  d1 = fact(r, m);
  d2 = fact(n - r, m);
  long long int ans = mod_inverse((d1 * d2) % m, m);
  ans = (ans * n1) % m;
  return ans;
}
int gcd(int a, int b) {
  if (a == 0 || b == 0) return max(a, b);
  if (a < b) return gcd(b, a);
  if (a % b == 0) return b;
  return gcd(b, a % b);
}
int ispal(string s) {
  int len = s.size();
  int flag = 1;
  for (int i = 0; i < len; ++i) {
    if (s[i] != s[len - i - 1]) {
      flag = 0;
      break;
    }
  }
  return flag;
}
long long int sroot(long long int n, long long int low = 1,
                    long long int high = 1e9 + 1) {
  if (low == high) return low;
  if (low == high - 1) {
    if (high * high <= n)
      return high;
    else
      return low;
  }
  long long int mid = (low + high) / 2;
  long long int a = mid * mid;
  if (a > n)
    return sroot(n, low, mid - 1);
  else
    return sroot(n, mid, high);
}
long long int croot(long long int n, long long int low = 1,
                    long long int high = 1e6 + 1) {
  if (low == high) return low;
  if (low == high - 1) {
    if (high * high * high <= n)
      return high;
    else
      return low;
  }
  long long int mid = (low + high) / 2;
  long long int a = mid * mid * mid;
  if (a > n)
    return croot(n, low, mid - 1);
  else
    return croot(n, mid, high);
}
bool sortbysec(const pair<long long int, long long int> &a,
               const pair<long long int, long long int> &b) {
  return (a.second < b.second);
}
class solver {
 public:
  long long int a[505];
  void even(long long int n) {
    long long int N = n * n;
    long long int cnt[1005]{};
    for (long long int i = 0; i < N; i++) cnt[a[i]]++;
    long long int f = 0, c = 0;
    for (long long int i = 1; i <= 1000; i++) {
      long long int x = cnt[i];
      if (x % 4 != 0) {
        f = 1;
        break;
      }
      c += x / 4;
    }
    if (f == 0 && c == ((n / 2) * (n / 2))) {
      cout << "YES\n";
      long long int n1 = n / 2;
      long long int m[n1 + 1][n1 + 1];
      long long int i = 1, j = 1;
      for (long long int k = 1; k <= 1000; k++) {
        long long int x = cnt[k];
        while (x != 0) {
          m[i][j] = k;
          i++;
          if (i == n1 + 1) {
            i = 1;
            j++;
          }
          x -= 4;
        }
      }
      for (long long int i = 1; i <= n1; i++) {
        for (long long int j = 1; j <= n1; j++) cout << m[i][j] << " ";
        for (long long int j = n1; j >= 1; j--) cout << m[i][j] << " ";
        cout << "\n";
      }
      for (long long int i = n1; i >= 1; i--) {
        for (long long int j = 1; j <= n1; j++) cout << m[i][j] << " ";
        for (long long int j = n1; j >= 1; j--) cout << m[i][j] << " ";
        cout << "\n";
      }
    } else
      cout << "NO";
  }
  void odd(long long int n) {
    long long int N = n * n;
    long long int cnt[1005]{};
    for (long long int i = 0; i < N; i++) cnt[a[i]]++;
    long long int f = 0, c = 0;
    long long int dp[10]{};
    long long int g = (n / 2) * (n / 2);
    vector<long long int> v4;
    vector<long long int> v2, v1;
    for (long long int k = 1; k <= 1000; k++) {
      long long int x = cnt[k];
      if (x % 2 == 1) {
        dp[1]++;
        v1.push_back(k);
        x--;
      }
      while (x != 0) {
        if (x >= 4) {
          if (dp[4] < g) {
            dp[4]++;
            x -= 4;
            v4.push_back(k);
          } else {
            dp[2]++;
            v2.push_back(k);
            x -= 2;
          }
        } else if (x >= 2) {
          dp[2]++, x -= 2;
          v2.push_back(k);
        }
      }
    }
    if (dp[4] == g && dp[1] == 1 && dp[2] == ((n / 2) * 2)) {
      cout << "YES\n";
      long long int n1 = n / 2;
      long long int m[n1 + 1][n1 + 1];
      long long int c = 0;
      long long int i = 1, j = 1;
      for (long long int k = 1; k <= g; k++) {
        m[i][j] = v4[c++];
        i++;
        if (i == (1 + n1)) {
          i = 1;
          j++;
        }
      }
      c = 0;
      vector<long long int> vy;
      for (long long int i = 1; i <= n1; i++) {
        for (long long int j = 1; j <= n1; j++) cout << m[i][j] << " ";
        vy.push_back(v2[c]);
        cout << v2[c++] << " ";
        for (long long int j = n1; j >= 1; j--) cout << m[i][j] << " ";
        cout << "\n";
      }
      vector<long long int> vx;
      for (long long int i = 1; i <= 1; i++) {
        while (c != v2.size()) vx.push_back(v2[c]), cout << v2[c++] << " ";
        if (c == v2.size()) {
          cout << v1[0] << " ";
          for (long long int j = vx.size() - 1; j >= 0; j--)
            cout << vx[j] << " ";
        }
      }
      cout << "\n";
      c = vy.size() - 1;
      for (long long int i = n1; i >= 1; i--) {
        for (long long int j = 1; j <= n1; j++) cout << m[i][j] << " ";
        cout << vy[c--] << " ";
        for (long long int j = n1; j >= 1; j--) cout << m[i][j] << " ";
        cout << "\n";
      }
    } else
      cout << "NO";
  }
  void solve() {
    long long int n;
    cin >> n;
    long long int N = n * n;
    for (long long int i = 0; i < N; i++) cin >> a[i];
    if (n == 1) {
      cout << "YES\n" << a[0];
    } else {
      if (n % 2 == 0)
        even(n);
      else
        odd(n);
    }
  }
};
int main() {
  std::ios::sync_with_stdio(false);
  std::cin.tie(NULL);
  std::cout.tie(NULL);
  int test = 1, c = 1;
  while (test--) {
    solver o;
    o.solve();
  }
}