Problem: You are given two positive integers n and k. Print the k-th positive integer that is not divisible by n.

For example, if n=3, and k=7, then all numbers that are not divisible by 3 are: 1, 2, 4, 5, 7, 8, 10, 11, 13 .... The 7-th number among them is 10.

Input

The first line contains an integer t (1 ≤ t ≤ 1000) — the number of test cases in the input. Next, t test cases are given, one per line.

Each test case is two positive integers n (2 ≤ n ≤ 10^9) and k (1 ≤ k ≤ 10^9).

Output

For each test case print the k-th positive integer that is not divisible by n.

Example

Input


6
3 7
4 12
2 1000000000
7 97
1000000000 1000000000
2 1


Output


10
15
1999999999
113
1000000001
1

Solution (in JAVA):

Solution:
import java.util.*;
public class S{
    public static void main(String args[]){
	    Scanner sc = new Scanner(System.in);
	    int t = sc.nextInt();
	    for(int i = 0;i<t;i++){
	        int n = sc.nextInt();
	        int k = sc.nextInt();
	        int mod = k%(n-1);
	        if(mod==0)  mod = n-1;
	        System.out.println(n*(int)Math.ceil((double)k/(n-1))-n+mod);
	    }
    }
}