Problem: You are given a positive number x. Find the smallest positive integer number that has the sum of digits equal to x and all digits are distinct (unique).

Input

The first line contains a single positive integer t (1 ≤ t ≤ 50) — the number of test cases in the test. Then t test cases follow.

Each test case consists of a single integer number x (1 ≤ x ≤ 50).

Output

Output t answers to the test cases:

  * if a positive integer number with the sum of digits equal to x and all digits are different exists, print the smallest such number; 
  * otherwise print -1. 

Example

Input


4
1
5
15
50


Output


1
5
69
-1

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
#define rep(i,a,b) for(int i = (a); i <= (b); i++)
#define rng(a) a.begin(), a.end()
#define ina(n,a) cin >> n; for(int i = 1; i <= n; i++) cin >> a[i]
#define sz(x) (int)(x).size()
#define se second
#define fi first
#define prev            coyhhhhhhyoc    
#define next          sdNNNmNNNNNNNmds  
#define y0           hNNNNy_yNNNNNN_sNh
#define y1          mNNNNNdtdNNNNNNtsNNm
#define yn          mNNNNNNNNy___smNNNms
#define tm            oooooosyysooooot 
#define read               tyhyt        
#define rank              ytmNmo         
#define index              yyy
#define pb push_back
#define pcnt __builtin_popcountll
#define rrep(i,a,b) for(int i = (b); i >= (a); i--)
#define rall(x,a) for(auto x : a)
#define MOD 1000000007
#define endl "\n"
typedef long long ll;
using namespace std;

int solve() {
    int x;
    string ans;
    cin >> x;
    rrep(d, 1, 9) {
        if(d <= x) {
            x -= d;
            ans += d + '0';
        }
    }
    if(x) {
        cout << -1 << endl;
        return 0;
    }
    reverse(rng(ans));
    cout << ans << endl;
    return 0;
}
 
signed main() {
    ios_base::sync_with_stdio(false);
    cin.tie(0);
    int t;
    cin >> t;
    while(t--) {
        solve();
    }
    return 0;
}