Problem: You are given three sequences: a_1, a_2, …, a_n; b_1, b_2, …, b_n; c_1, c_2, …, c_n.

For each i, a_i ≠ b_i, a_i ≠ c_i, b_i ≠ c_i.

Find a sequence p_1, p_2, …, p_n, that satisfy the following conditions:

  * p_i ∈ \\{a_i, b_i, c_i\}
  * p_i ≠ p_{(i mod n) + 1}.



In other words, for each element, you need to choose one of the three possible values, such that no two adjacent elements (where we consider elements i,i+1 adjacent for i<n and also elements 1 and n) will have equal value.

It can be proved that in the given constraints solution always exists. You don't need to minimize/maximize anything, you need to find any proper sequence.

Input

The first line of input contains one integer t (1 ≤ t ≤ 100): the number of test cases.

The first line of each test case contains one integer n (3 ≤ n ≤ 100): the number of elements in the given sequences.

The second line contains n integers a_1, a_2, …, a_n (1 ≤ a_i ≤ 100).

The third line contains n integers b_1, b_2, …, b_n (1 ≤ b_i ≤ 100).

The fourth line contains n integers c_1, c_2, …, c_n (1 ≤ c_i ≤ 100).

It is guaranteed that a_i ≠ b_i, a_i ≠ c_i, b_i ≠ c_i for all i.

Output

For each test case, print n integers: p_1, p_2, …, p_n (p_i ∈ \\{a_i, b_i, c_i\}, p_i ≠ p_{i mod n + 1}).

If there are several solutions, you can print any.

Example

Input


5
3
1 1 1
2 2 2
3 3 3
4
1 2 1 2
2 1 2 1
3 4 3 4
7
1 3 3 1 1 1 1
2 4 4 3 2 2 4
4 2 2 2 4 4 2
3
1 2 1
2 3 3
3 1 2
10
1 1 1 2 2 2 3 3 3 1
2 2 2 3 3 3 1 1 1 2
3 3 3 1 1 1 2 2 2 3


Output


1 2 3
1 2 1 2
1 3 4 3 2 4 2
1 3 2
1 2 3 1 2 3 1 2 3 2

Note

In the first test case p = [1, 2, 3].

It is a correct answer, because:

  * p_1 = 1 = a_1, p_2 = 2 = b_2, p_3 = 3 = c_3 
  * p_1 ≠ p_2 , p_2 ≠ p_3 , p_3 ≠ p_1 



All possible correct answers to this test case are: [1, 2, 3], [1, 3, 2], [2, 1, 3], [2, 3, 1], [3, 1, 2], [3, 2, 1].

In the second test case p = [1, 2, 1, 2].

In this sequence p_1 = a_1, p_2 = a_2, p_3 = a_3, p_4 = a_4. Also we can see, that no two adjacent elements of the sequence are equal.

In the third test case p = [1, 3, 4, 3, 2, 4, 2].

In this sequence p_1 = a_1, p_2 = a_2, p_3 = b_3, p_4 = b_4, p_5 = b_5, p_6 = c_6, p_7 = c_7. Also we can see, that no two adjacent elements of the sequence are equal.

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.*;
import java.util.stream.Collectors;


/**
 * ti*zi+yi
 */
public class Main {

    void solve() {
        int n = in.nextInt();
        int[] a = in.nextInts(n);
        int[] b = in.nextInts(n);
        int[] c = in.nextInts(n);
        int[] p = new int[n];
        p[0] = a[0];
        for (int i = 1; i < n-1; i++) {
            if (a[i] != p[i-1]){
                p[i] = a[i];
            }else{
                p[i] = b[i];
            }
        }
        if (a[n-1] != p[n-2] && a[n-1] != p[0]){
            p[n-1] = a[n-1];
        }else if(b[n-1] != p[n-2] && b[n-1] != p[0]){
            p[n-1] = b[n-1];
        }else{
            p[n-1] = c[n-1];
        }
        out.println(p);
    }

    static final boolean MULTI_TEST = true;

    // --------------------------------------------------------------------------------------------------------------
    // --------------------------------------------------HELPER------------------------------------------------------
    // --------------------------------------------------------------------------------------------------------------


    void run() {
        if (MULTI_TEST) {
            int t = in.nextInt();
            for (int i = 0; i < t; i++) {
                solve();
            }
        } else {
            solve();
        }
    }

    // --------------------ALGORITHM-------------------------

    static int MOD = 1000000007;

    public void sort(int[] arr) {
        List<Integer> tmp = Arrays.stream(arr).boxed().sorted().collect(Collectors.toList());
        for (int i = 0; i < arr.length; i++) {
            arr[i] = tmp.get(i);
        }
    }

    public void sortRev(int[] arr) {
        List<Integer> tmp = Arrays.stream(arr).boxed().sorted(Comparator.comparing((Integer x) -> x).reversed())
                .collect(Collectors.toList());
        for (int i = 0; i < arr.length; i++) {
            arr[i] = tmp.get(i);
        }
    }

    // --------------------SCANNER-------------------------
    public static class MyScanner {
        BufferedReader br;
        StringTokenizer st;

        public MyScanner(String fileName) {
            if (fileName != null) {
                try {
                    br = new BufferedReader(new FileReader(fileName));
                } catch (FileNotFoundException e) {
                    throw new RuntimeException(e);
                }
            } else {
                br = new BufferedReader(new InputStreamReader(System.in));
            }
        }

        String next() {
            while (st == null || !st.hasMoreElements()) {
                st = new StringTokenizer(nextLine());
            }
            return st.nextToken();
        }

        int nextInt() {
            return Integer.parseInt(next());
        }

        int[] nextInts(int n) {
            int[] arr = new int[n];
            for (int i = 0; i < n; i++) {
                arr[i] = nextInt();
            }
            return arr;
        }

        boolean[] nextLineBools() {
            String line = nextLine();
            int n = line.length();
            boolean[] booleans = new boolean[n];
            for (int i = 0; i < n; i++) {
                booleans[i] = line.charAt(i) == '1';
            }
            return booleans;
        }

        long nextLong() {
            return Long.parseLong(next());
        }

        public long[] nextLongs(int n) {
            long[] arr = new long[n];
            for (int i = 0; i < n; i++) {
                arr[i] = nextLong();
            }
            return arr;
        }

        double nextDouble() {
            return Double.parseDouble(next());
        }

        String nextLine() {
            try {
                String line = br.readLine();
                if (line == null) {
                    throw new RuntimeException("empty line");
                }
                return line;
            } catch (IOException e) {
                throw new RuntimeException(e);
            }
        }

    }

    // --------------------WRITER-------------------------
    public static class MyWriter extends PrintWriter {

        public static MyWriter of(String fileName) {
            if (fileName != null) {
                try {
                    return new MyWriter(new FileWriter(fileName));
                } catch (IOException e) {
                    throw new RuntimeException(e);
                }
            } else {
                return new MyWriter(new BufferedOutputStream(System.out));
            }
        }

        public MyWriter(FileWriter fileWriter) {
            super(fileWriter);
        }

        public MyWriter(OutputStream out) {
            super(out);
        }

        void println(int[] arr) {
            String line = Arrays.stream(arr).mapToObj(String::valueOf).collect(Collectors.joining(" "));
            println(line);
        }

    }

    // -----------------------BENCHMARK-------------------------
    public static class Benchmark {
        long time;

        public void reset() {
            time = System.currentTimeMillis();
        }

        public long calc() {
            long curTime = System.currentTimeMillis();
            long tmp = curTime - time;
            time = curTime;
            return tmp;
        }

    }


    // --------------------MAIN-------------------------

    public MyScanner in;
    public MyWriter out;
    public Benchmark bm;

    /**
     * run as `java Main`, `java Main input.txt' or `java Main input.txt output.txt'
     * add `-Xss256m` to increase stack size
     */
    public static void main(String[] args) {
        Main m = new Main();
        m.in = new MyScanner(args.length > 0 ? args[0] : null);
        m.out = MyWriter.of(args.length > 1 ? args[1] : null);
        m.bm = new Benchmark();
        m.run();
        m.out.close();
    }
}