Problem: You are given two positive integers n and k. Print the k-th positive integer that is not divisible by n.

For example, if n=3, and k=7, then all numbers that are not divisible by 3 are: 1, 2, 4, 5, 7, 8, 10, 11, 13 .... The 7-th number among them is 10.

Input

The first line contains an integer t (1 ≤ t ≤ 1000) — the number of test cases in the input. Next, t test cases are given, one per line.

Each test case is two positive integers n (2 ≤ n ≤ 10^9) and k (1 ≤ k ≤ 10^9).

Output

For each test case print the k-th positive integer that is not divisible by n.

Example

Input


6
3 7
4 12
2 1000000000
7 97
1000000000 1000000000
2 1


Output


10
15
1999999999
113
1000000001
1

Solution (in PYTHON3):

Solution:
import sys 
try:
	sys.stdin = open('input.txt', 'r') 
	sys.stdout = open('output.txt', 'w')
except:
	pass
input = sys.stdin.readline
for tt in range(int(input())):
	n,k = map(int,input().split())
	if k<n:
		print(k)
	else:
		temp = (k)//(n-1)
		pos = (n*temp)
		k -= (n-1)*temp
		if k==0:
			pos -= 1
		else:
			pos += k
		# while k:
		# 	pos += 1
		# 	if pos%n != 0:
		# 		k-=1

		print(pos)