Problem: There are n boys and m girls studying in the class. They should stand in a line so that boys and girls alternated there as much as possible. Let's assume that positions in the line are indexed from left to right by numbers from 1 to n + m. Then the number of integers i (1 ≤ i < n + m) such that positions with indexes i and i + 1 contain children of different genders (position i has a girl and position i + 1 has a boy or vice versa) must be as large as possible. 

Help the children and tell them how to form the line.

Input

The single line of the input contains two integers n and m (1 ≤ n, m ≤ 100), separated by a space.

Output

Print a line of n + m characters. Print on the i-th position of the line character "B", if the i-th position of your arrangement should have a boy and "G", if it should have a girl. 

Of course, the number of characters "B" should equal n and the number of characters "G" should equal m. If there are multiple optimal solutions, print any of them.

Examples

Input

3 3


Output

GBGBGB


Input

4 2


Output

BGBGBB

Note

In the first sample another possible answer is BGBGBG. 

In the second sample answer BBGBGB is also optimal.

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.Scanner;
import java.util.StringTokenizer;

public class CodeForces {
    public static void main(String[] args) throws IOException {
        //reader input = new reader();
        //PrintWriter output=new PrintWriter(System.out);
        Scanner sc = new Scanner(new File("input.txt"));
        //FileReader myReader=new FileReader("input.txt");
        FileWriter myWriter = new FileWriter("output.txt");
        int n= sc.nextInt(),m=sc.nextInt();
        if(n>=m){
            while(n>0&&m>0){
                myWriter.write("BG");
                n--;
                m--;
            }
            while(n>0){
                myWriter.write("B");
                n--;
            }
        }else{
            while(n>0&&m>0){
                myWriter.write("GB");
                n--;
                m--;
            }
            while(m>0){
                myWriter.write("G");
                m--;
            }
        }
        myWriter.close();
        //output.close();
    }
    static boolean prime(long a){
        if(a==2||a==3)
            return true;
        if((a-1)%6==0)
            return true;
        if((a+1)%6==0)
            return true;
        return false;
    }
}

class reader {
    BufferedReader br;
    StringTokenizer st;
    public reader() {
        br = new BufferedReader(new
                InputStreamReader(System.in));
    }
    String next() {
        while (st == null || !st.hasMoreElements()) {
            try {
                st = new StringTokenizer(br.readLine());
            } catch (IOException e) {
                e.printStackTrace();
            }
        }
        return st.nextToken();
    }
    int nextInt() {
        return Integer.parseInt(next());
    }
    long nextLong() {
        return Long.parseLong(next());
    }
    double nextDouble() {
        return Double.parseDouble(next());
    }
    String nextLine() {
        String str = "";
        try {
            str = br.readLine();
        } catch (IOException e) {
            e.printStackTrace();
        }
        return str;
    }
    public int[] nextIntArray(int arraySize) {
        int array[] = new int[arraySize];
        for (int i = 0; i < arraySize; i++) {
            array[i] = nextInt();
        }
        return array;
    }
    public long[] nextLongArray(int arraySize) {
        long array[] = new long[arraySize];
        for (int i = 0; i < arraySize; i++) {
            array[i] = nextLong();
        }
        return array;
    }
}