Problem: You are given two positive integers n and k. Print the k-th positive integer that is not divisible by n.

For example, if n=3, and k=7, then all numbers that are not divisible by 3 are: 1, 2, 4, 5, 7, 8, 10, 11, 13 .... The 7-th number among them is 10.

Input

The first line contains an integer t (1 ≤ t ≤ 1000) — the number of test cases in the input. Next, t test cases are given, one per line.

Each test case is two positive integers n (2 ≤ n ≤ 10^9) and k (1 ≤ k ≤ 10^9).

Output

For each test case print the k-th positive integer that is not divisible by n.

Example

Input


6
3 7
4 12
2 1000000000
7 97
1000000000 1000000000
2 1


Output


10
15
1999999999
113
1000000001
1

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
long long func(long long n, long long k) {
  long long high = n * k, low = 1, mid, ans;
  while (high >= low) {
    mid = low + (high - low) / 2;
    ans = mid - (mid / n);
    if (ans == k) {
      if (mid % n == 0) return mid - 1;
      return mid;
    }
    if (ans > k)
      high = mid - 1;
    else
      low = mid + 1;
  }
  return -1;
}
int main() {
  int t;
  scanf("%d", &t);
  long long n, k;
  while (t--) {
    cin >> n >> k;
    cout << func(n, k) << endl;
  }
  return 0;
}