Problem: There are n boys and m girls studying in the class. They should stand in a line so that boys and girls alternated there as much as possible. Let's assume that positions in the line are indexed from left to right by numbers from 1 to n + m. Then the number of integers i (1 ≤ i < n + m) such that positions with indexes i and i + 1 contain children of different genders (position i has a girl and position i + 1 has a boy or vice versa) must be as large as possible. 

Help the children and tell them how to form the line.

Input

The single line of the input contains two integers n and m (1 ≤ n, m ≤ 100), separated by a space.

Output

Print a line of n + m characters. Print on the i-th position of the line character "B", if the i-th position of your arrangement should have a boy and "G", if it should have a girl. 

Of course, the number of characters "B" should equal n and the number of characters "G" should equal m. If there are multiple optimal solutions, print any of them.

Examples

Input

3 3


Output

GBGBGB


Input

4 2


Output

BGBGBB

Note

In the first sample another possible answer is BGBGBG. 

In the second sample answer BBGBGB is also optimal.

Solution (in JAVA):

Solution:
//package codeforce;

import java.io.BufferedReader;
import java.io.BufferedWriter;
import java.io.File;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.FileWriter;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.OutputStream;
import java.io.OutputStreamWriter;
import java.io.StreamTokenizer;
import java.util.Scanner;

public class CodeForce {

    private static MyScanner sc;
    private static MyPrinter out;

    private static void solve() throws IOException {
        int n = sc.nextInt();
        int m = sc.nextInt();
        int p = 1;
        if (m < n) {
            p = 0;
        }
        while (n > 0 || m > 0) {
            if (p % 2 == 0) {
                if (n > 0) {
                    out.print("B");
                    n--;
                } else {
                    out.print("G");
                    m--;
                }
            } else {
                if (m > 0) {
                    out.print("G");
                    m--;
                } else {
                    out.print("B");
                    n--;
                }
            }
            p++;
        }
    }

    public static void main(String[] args) throws IOException {
        sc = new MyScanner("input.txt");
        out = new MyPrinter("output.txt");
        solve();
        out.close();
    }
}

class MyScanner {

    private StreamTokenizer st;
    private Scanner sc;

    public MyScanner(InputStream is) {
        st = new StreamTokenizer(new BufferedReader(new InputStreamReader(is)));
        sc = new Scanner(is);
    }

    public MyScanner(String s) throws FileNotFoundException {
        st = new StreamTokenizer(new BufferedReader(new FileReader(new File(s))));
        sc = new Scanner(new File(s));
    }

    public int nextInt() throws IOException {
        st.nextToken();
        return ((int) st.nval);
    }

    public double nextDouble() throws IOException {
        st.nextToken();
        return (st.nval);
    }

    public long nextLong() {
        return (sc.nextLong());
    }

    public String next() {
        return (sc.next());
    }

    public String nextLine() {
        return (sc.nextLine());
    }

    public boolean hasNext() {
        return (sc.hasNext());
    }
}

class MyPrinter {

    public BufferedWriter out;

    public MyPrinter(OutputStream os) {
        out = new BufferedWriter(new OutputStreamWriter(os));
    }

    public MyPrinter(String s) throws IOException {
        out = new BufferedWriter(new FileWriter(new File(s)));
    }

    public void print(Object o) throws IOException {
        out.write(o.toString());
    }

    public void println(Object o) throws IOException {
        out.write(o.toString());
        out.newLine();
    }

    public void close() throws IOException {
        out.flush();
        out.close();
    }
}