Problem: You are given two positive integers n and k. Print the k-th positive integer that is not divisible by n.

For example, if n=3, and k=7, then all numbers that are not divisible by 3 are: 1, 2, 4, 5, 7, 8, 10, 11, 13 .... The 7-th number among them is 10.

Input

The first line contains an integer t (1 ≤ t ≤ 1000) — the number of test cases in the input. Next, t test cases are given, one per line.

Each test case is two positive integers n (2 ≤ n ≤ 10^9) and k (1 ≤ k ≤ 10^9).

Output

For each test case print the k-th positive integer that is not divisible by n.

Example

Input


6
3 7
4 12
2 1000000000
7 97
1000000000 1000000000
2 1


Output


10
15
1999999999
113
1000000001
1

Solution (in PYTHON3):

Solution:
import math
t=int(input())
for i in range(t):
    l1= input()
    l=l1.split()
     
    n = int(l[0])
    #m = int(l[1])
    k = int(l[1])
    
    print()
    
    if k<n:
        print(k)
    else:
        p=k/(n-1)
        #print(p)
       # r=int(p)
        q=n*p
        if k%(n-1)!=0:
                
                if int(q)-int(p)==k:
                    print(math.floor(q))
                else:
                    print(math.ceil(q))
        else:
            print(int(p*n-1))