Problem: There are n boys and m girls studying in the class. They should stand in a line so that boys and girls alternated there as much as possible. Let's assume that positions in the line are indexed from left to right by numbers from 1 to n + m. Then the number of integers i (1 ≤ i < n + m) such that positions with indexes i and i + 1 contain children of different genders (position i has a girl and position i + 1 has a boy or vice versa) must be as large as possible. 

Help the children and tell them how to form the line.

Input

The single line of the input contains two integers n and m (1 ≤ n, m ≤ 100), separated by a space.

Output

Print a line of n + m characters. Print on the i-th position of the line character "B", if the i-th position of your arrangement should have a boy and "G", if it should have a girl. 

Of course, the number of characters "B" should equal n and the number of characters "G" should equal m. If there are multiple optimal solutions, print any of them.

Examples

Input

3 3


Output

GBGBGB


Input

4 2


Output

BGBGBB

Note

In the first sample another possible answer is BGBGBG. 

In the second sample answer BBGBGB is also optimal.

Solution (in JAVA):

Solution:
import static java.lang.Math.*;
import static java.util.Arrays.*;
import java.util.*;
import java.io.*;

public class Main {
	public static void main(String[] args) throws Exception {
		Class<?> here = new Object(){}.getClass().getEnclosingClass();
//		try {
//			String packageName = here.getPackage().getName();
//			packageName = packageName.replaceAll("\\.", "/");
//			System.setIn(new FileInputStream("src/" + packageName + "/input.txt"));
//			System.setOut(new PrintStream(new FileOutputStream("src/" + packageName + "/result.txt")));
//		} catch (FileNotFoundException e) {
//		}

			String className = here.getName();
			Object object = Class.forName(className).newInstance();
			object.getClass().getMethod("run").invoke(object);
	}

	void tr(Object... os) {
		System.err.println(deepToString(os));
	}


	MyScanner sc = null;
	PrintWriter out = null;
	public void run() throws Exception {
		sc = new MyScanner(new FileInputStream("input.txt"));
		out = new PrintWriter("output.txt");
		for (;sc.hasNext();) {
			solve();
			out.flush();
		}
		out.close();
	}
	public void solve() {
		int n = sc.nextInt();
		int m = sc.nextInt();

		int t = n + m;
		char[] ch = new char[t];
		if (n >= m) {
			for (int i = 0; i < t; i++) {
				if (i % 2 == 0 || m == 0) {
					ch[i] = 'B';
					n--;
				} else {
					ch[i] = 'G';
					m--;
				}
			}
		} else {
			for (int i = 0; i < t; i++) {
				if (i % 2 == 0 || n == 0) {
					ch[i] = 'G';
					m--;
				} else {
					ch[i] = 'B';
					n--;
				}
			}
		}
		out.println(new String(ch));

	}


	class MyScanner {
		String line;
		BufferedReader reader;
		StringTokenizer tokenizer;

		public MyScanner(InputStream stream) {
			reader = new BufferedReader(new InputStreamReader(stream));
			tokenizer = null;
		}

		public void eat() {
			while (tokenizer == null || !tokenizer.hasMoreTokens()) {
				try {
					line = reader.readLine();
					if (line == null) {
						tokenizer = null;
						return;
					}
					tokenizer = new StringTokenizer(line);
				} catch (IOException e) {
					throw new RuntimeException(e);
				}
			}
		}

		public String next() {
			eat();
			return tokenizer.nextToken();
		}

		public String nextLine() {
			try {
				return reader.readLine();
			} catch (IOException e) {
				throw new RuntimeException(e);
			}
		}

		public boolean hasNext() {
			eat();
			return (tokenizer != null && tokenizer.hasMoreElements());
		}

		public int nextInt() {
			return Integer.parseInt(next());
		}

		public long nextLong() {
			return Long.parseLong(next());
		}

		public double nextDouble() {
			return Double.parseDouble(next());
		}
	}
}