Problem: You are given two positive integers n and k. Print the k-th positive integer that is not divisible by n.

For example, if n=3, and k=7, then all numbers that are not divisible by 3 are: 1, 2, 4, 5, 7, 8, 10, 11, 13 .... The 7-th number among them is 10.

Input

The first line contains an integer t (1 ≤ t ≤ 1000) — the number of test cases in the input. Next, t test cases are given, one per line.

Each test case is two positive integers n (2 ≤ n ≤ 10^9) and k (1 ≤ k ≤ 10^9).

Output

For each test case print the k-th positive integer that is not divisible by n.

Example

Input


6
3 7
4 12
2 1000000000
7 97
1000000000 1000000000
2 1


Output


10
15
1999999999
113
1000000001
1

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
using Long = long long;
int main(void) {
  int t;
  cin >> t;
  while (t--) {
    Long n, k;
    cin >> n >> k;
    Long minVal = 1;
    Long maxVal = LONG_MAX;
    Long ans = 0;
    while (minVal <= maxVal) {
      Long currVal = minVal + (maxVal - minVal) / 2ll;
      Long notDivisible = currVal - currVal / n;
      if (notDivisible == k and currVal % n != 0) {
        ans = currVal;
        break;
      }
      if (notDivisible < k)
        minVal = currVal + 1;
      else
        maxVal = currVal - 1;
    }
    cout << ans << "\n";
  }
  return 0;
}