Problem: You are given two positive integers n and k. Print the k-th positive integer that is not divisible by n.

For example, if n=3, and k=7, then all numbers that are not divisible by 3 are: 1, 2, 4, 5, 7, 8, 10, 11, 13 .... The 7-th number among them is 10.

Input

The first line contains an integer t (1 ≤ t ≤ 1000) — the number of test cases in the input. Next, t test cases are given, one per line.

Each test case is two positive integers n (2 ≤ n ≤ 10^9) and k (1 ≤ k ≤ 10^9).

Output

For each test case print the k-th positive integer that is not divisible by n.

Example

Input


6
3 7
4 12
2 1000000000
7 97
1000000000 1000000000
2 1


Output


10
15
1999999999
113
1000000001
1

Solution (in JAVA):

Solution:
import java.util.Scanner;

/**
 * Description:
 *
 * @author L
 * @Date Create on 2020/5/9
 */
public class contest_1352_C {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int t = sc.nextInt();
        for (int i = 0; i < t; i++) {
            int n = sc.nextInt();
            int k = sc.nextInt();
            if(n > k) {
                System.out.println(k);
            }else if(n == k) {
                System.out.println(k + 1);
            }else {
                int res = k;
                res += k/n;
                while (res/n - k/n > 0) {
                    int temp = res;
                    res += res/n - k/n;
                    k = temp;
                }
                System.out.println(res);
            }
        }
    }
}