Problem: You are given two positive integers n and k. Print the k-th positive integer that is not divisible by n.

For example, if n=3, and k=7, then all numbers that are not divisible by 3 are: 1, 2, 4, 5, 7, 8, 10, 11, 13 .... The 7-th number among them is 10.

Input

The first line contains an integer t (1 ≤ t ≤ 1000) — the number of test cases in the input. Next, t test cases are given, one per line.

Each test case is two positive integers n (2 ≤ n ≤ 10^9) and k (1 ≤ k ≤ 10^9).

Output

For each test case print the k-th positive integer that is not divisible by n.

Example

Input


6
3 7
4 12
2 1000000000
7 97
1000000000 1000000000
2 1


Output


10
15
1999999999
113
1000000001
1

Solution (in JAVA):

Solution:
import java.lang.*;
import java.util.*;
import java.io.*;
public class MyClass{
   static int kthNonDivisible(int N, int K){
    return (int) (K + Math.floor((K - 1) / (N - 1)));
}
 
public static void main(String[] args){
    Scanner scan=new Scanner(System.in);
    int t =scan.nextInt();
    while(t-->0){
        int N = scan.nextInt();
        int K = scan.nextInt();
        System.out.println(kthNonDivisible(N, K));
    }
}
}