Problem: Japate, while traveling through the forest of Mala, saw N bags of gold lying in a row. Each bag has some distinct weight of gold between 1 to N. Japate can carry only one bag of gold with him, so he uses the following strategy to choose a bag.

Initially, he starts with an empty bag (zero weight). He considers the bags in some order. If the current bag has a higher weight than the bag in his hand, he picks the current bag.

Japate put the bags in some order. Japate realizes that he will pick A bags, if he starts picking bags from the front, and will pick B bags, if he starts picking bags from the back. By picking we mean replacing the bag in his hand with the current one.

Now he wonders how many permutations of bags are possible, in which he picks A bags from the front and B bags from back using the above strategy.

Since the answer can be very large, output it modulo 998244353.

Input

The only line of input contains three space separated integers N (1 ≤ N ≤ 105), A and B (0 ≤ A, B ≤ N).

Output

Output a single integer — the number of valid permutations modulo 998244353.

Examples

Input

1 1 1


Output

1

Input

2 1 1


Output

0

Input

2 2 1


Output

1

Input

5 2 2


Output

22

Note

In sample case 1, the only possible permutation is [1]

In sample cases 2 and 3, only two permutations of size 2 are possible:{[1, 2], [2, 1]}. The values of a and b for first permutation is 2 and 1, and for the second permutation these values are 1 and 2. 

In sample case 4, out of 120 permutations of [1, 2, 3, 4, 5] possible, only 22 satisfy the given constraints of a and b.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
namespace NTT {
const int EXP = 23;
const unsigned long long EXP_MULT = 119, NTT_MOD = (EXP_MULT << EXP) + 1;
unsigned long long rt[EXP + 1], invrt[EXP + 1];
bool built;
unsigned long long modPow(unsigned long long a, unsigned long long p) {
  return p ? modPow((a) * (a) % NTT_MOD, p >> 1) * (p & 1 ? a : 1) % NTT_MOD
           : 1;
}
unsigned long long invMod(unsigned long long a) {
  return modPow(a, NTT_MOD - 2);
}
unsigned long long findCyclic() {
  vector<long long> multFactors;
  unsigned long long temp = EXP_MULT;
  for (long long i = 2; i * i <= temp; i += 2) {
    if (temp % i == 0) multFactors.push_back(i);
    while (temp % i == 0) temp /= i;
    if (i == 2) i--;
  }
  if (temp > 1) multFactors.push_back(temp);
  for (long long i = 2; i < NTT_MOD; i++) {
    bool works = 1;
    if (modPow(i, NTT_MOD >> 1) == 1) works = 0;
    for (const int factor : multFactors)
      if (modPow(i, NTT_MOD / factor) == 1) works = 0;
    if (works) return i;
  }
}
void buildRT() {
  if (built) return;
  built = 1;
  rt[EXP] = modPow(findCyclic(), EXP_MULT);
  for (int i = (EXP)-1; i >= 0; i--)
    rt[i] = (rt[i + 1]) * (rt[i + 1]) % NTT_MOD;
  for (int i = 0; i < (EXP + 1); i++) invrt[i] = invMod(rt[i]);
}
int rev(int idx, int sz) {
  int tmp = 1, res = 0;
  sz >>= 1;
  while (sz) {
    if (sz & idx) res |= tmp;
    sz >>= 1;
    tmp <<= 1;
  }
  return res;
}
vector<unsigned long long> bitReverseCopy(vector<unsigned long long> val) {
  vector<unsigned long long> res(val.size());
  for (int i = 0; i < (val.size()); i++) res[i] = val[rev(i, val.size())];
  return res;
}
vector<unsigned long long> ntt(vector<unsigned long long> val) {
  buildRT();
  vector<unsigned long long> res = bitReverseCopy(val);
  int n = res.size();
  for (int i = (1); i < (32 - __builtin_clz(n)); i++) {
    int m = 1 << i;
    unsigned long long wm = rt[i];
    for (int k = 0; k < n; k += m) {
      unsigned long long w = 1;
      for (int j = 0; j < (m >> 1); j++) {
        unsigned long long t = w * res[k + j + (m >> 1)] % NTT_MOD;
        unsigned long long u = res[k + j];
        res[k + j] = (u + t) % NTT_MOD;
        res[k + j + (m >> 1)] = (u + NTT_MOD - t) % NTT_MOD;
        w = (w * wm) % NTT_MOD;
      }
    }
  }
  return res;
}
vector<unsigned long long> invntt(vector<unsigned long long> val) {
  swap(rt, invrt);
  vector<unsigned long long> res = ntt(val);
  swap(rt, invrt);
  unsigned long long u = invMod(val.size());
  for (int i = 0; i < (res.size()); i++) res[i] = (res[i] * u) % NTT_MOD;
  return res;
}
vector<unsigned long long> conv(vector<unsigned long long> a,
                                vector<unsigned long long> b) {
  int finalSZ = a.size() + b.size() - 1;
  int neededSZ = 1 << (32 - __builtin_clz(finalSZ - 1));
  a.resize(neededSZ), b.resize(neededSZ);
  a = ntt(a), b = ntt(b);
  for (int i = 0; i < (neededSZ); i++) a[i] = a[i] * b[i] % NTT_MOD;
  a = invntt(a);
  a.resize(finalSZ);
  return a;
}
};  // namespace NTT
using namespace NTT;
struct Polynomial {
  int deg;
  unsigned long long* coefficients;
  Polynomial(int d = 0) {
    deg = d;
    coefficients = new unsigned long long[deg + 1];
    memset(coefficients, 0, (deg + 1) * sizeof(unsigned long long));
  }
  Polynomial operator()(Polynomial p) {
    Polynomial curr;
    curr[0] = 1;
    Polynomial res;
    for (int i = 0; i < (deg + 1); i++) {
      res += curr * coefficients[i];
      curr *= p;
    }
    return res;
  }
  Polynomial operator+(unsigned long long a) {
    Polynomial p(deg);
    for (int i = 0; i < (deg + 1); i++) p[i] = coefficients[i];
    p[0] += a;
    p[0] %= NTT_MOD;
    return p;
  }
  Polynomial operator-(unsigned long long a) {
    Polynomial p(deg);
    for (int i = 0; i < (deg + 1); i++) p[i] = coefficients[i];
    p[0] += NTT_MOD - a;
    p[0] %= NTT_MOD;
    return p;
  }
  Polynomial operator*(unsigned long long mult) {
    Polynomial p(deg);
    for (int i = 0; i < (deg + 1); i++) p[i] = coefficients[i] * mult % NTT_MOD;
    return p;
  }
  Polynomial operator/(unsigned long long div) { return *this * invMod(div); }
  Polynomial operator+(Polynomial b) {
    Polynomial res(max(deg, b.deg));
    for (int i = 0; i < (max(deg, b.deg) + 1); i++)
      res[i] = (((i > deg) ? 0 : coefficients[i]) + ((i > b.deg) ? 0 : b[i])) %
               NTT_MOD;
    return res;
  }
  Polynomial operator-(Polynomial p) { return *this + (p * (NTT_MOD - 1)); }
  Polynomial operator*(Polynomial b) {
    vector<unsigned long long> va, vb;
    for (int i = 0; i < (deg + 1); i++) va.push_back((*this)[i]);
    for (int i = 0; i < (b.deg + 1); i++) vb.push_back(b[i]);
    vector<unsigned long long> vc = NTT::conv(va, vb);
    Polynomial res(vc.size() - 1);
    for (int i = 0; i < (vc.size()); i++) res[i] = vc[i];
    return res;
  }
  void operator+=(unsigned long long a) {
    coefficients[0] += a, coefficients[0] %= NTT_MOD;
  }
  void operator-=(unsigned long long a) { *this += NTT_MOD - a; }
  void operator*=(unsigned long long mult) {
    for (int i = 0; i < (deg + 1); i++)
      coefficients[i] *= mult, coefficients[i] %= NTT_MOD;
  }
  void operator/=(unsigned long long div) { *this *= invMod(div); }
  void operator+=(Polynomial b) { *this = *this + b; }
  void operator-=(Polynomial p) { *this = *this - p; }
  void operator*=(Polynomial b) { *this = *this * b; }
  unsigned long long& operator[](int idx) { return coefficients[idx]; }
};
int N, A, B;
long long C(long long n, long long r) {
  long long res = 1;
  long long div = 1;
  for (int i = 0; i < (r); i++) res = res * (n - i) % NTT_MOD;
  for (int i = (1); i < (r + 1); i++) div = div * i % NTT_MOD;
  return res * invMod(div) % NTT_MOD;
}
int main() {
  ios::sync_with_stdio(0);
  cin.tie(0);
  cin >> N >> A >> B;
  if (A + B - 2 > N - 1 || A == 0 || B == 0) {
    cout << 0 << endl;
    return 0;
  }
  queue<Polynomial> q;
  Polynomial strt(0);
  strt[0] = 1;
  q.push(strt);
  for (int i = 0; i < (N - 1); i++) {
    Polynomial mult(1);
    mult[1] = 1;
    mult[0] = i;
    q.push(mult);
  }
  while (q.size() > 1) {
    Polynomial a = q.front();
    q.pop();
    Polynomial b = q.front();
    q.pop();
    q.push(a * b);
  }
  cout << q.front()[A + B - 2] * C(A + B - 2, A - 1) % NTT_MOD << endl;
  return 0;
}