Problem: You are given two positive integers n and k. Print the k-th positive integer that is not divisible by n.

For example, if n=3, and k=7, then all numbers that are not divisible by 3 are: 1, 2, 4, 5, 7, 8, 10, 11, 13 .... The 7-th number among them is 10.

Input

The first line contains an integer t (1 ≤ t ≤ 1000) — the number of test cases in the input. Next, t test cases are given, one per line.

Each test case is two positive integers n (2 ≤ n ≤ 10^9) and k (1 ≤ k ≤ 10^9).

Output

For each test case print the k-th positive integer that is not divisible by n.

Example

Input


6
3 7
4 12
2 1000000000
7 97
1000000000 1000000000
2 1


Output


10
15
1999999999
113
1000000001
1

Solution (in PYTHON3):

Solution:
for _ in range(int(input())):
    n,k=map(int,input().split())
    if(k<n):
        print(k)
    elif(k==n):
        print(k+1)
    elif(n==2):
        print((n*k)-1)
    else:
        if(k%(n-1)==0):
            print((k//(n-1))*n+k%(n-1)-1)
        else:
            print((k//(n-1))*n+k%(n-1))
        
##        c=k//n
##        mod=k%n
##        ans=k+c+mod
##        c=c+mod
##        while(c>=n):
##            
##            c=(c+mod)//n
##            mod=c%n
####            ans+=c
##            
##        print()