Problem: Vasya came up with a password to register for EatForces — a string s. The password in EatForces should be a string, consisting of lowercase and uppercase Latin letters and digits.

But since EatForces takes care of the security of its users, user passwords must contain at least one digit, at least one uppercase Latin letter and at least one lowercase Latin letter. For example, the passwords "abaCABA12", "Z7q" and "3R24m" are valid, and the passwords "qwerty", "qwerty12345" and "Password" are not. 

A substring of string s is a string x = s_l s_{l + 1} ... s_{l + len - 1} (1 ≤ l ≤ |s|, 0 ≤ len ≤ |s| - l + 1). len is the length of the substring. Note that the empty string is also considered a substring of s, it has the length 0.

Vasya's password, however, may come too weak for the security settings of EatForces. He likes his password, so he wants to replace some its substring with another string of the same length in order to satisfy the above conditions. This operation should be performed exactly once, and the chosen string should have the minimal possible length.

Note that the length of s should not change after the replacement of the substring, and the string itself should contain only lowercase and uppercase Latin letters and digits.

Input

The first line contains a single integer T (1 ≤ T ≤ 100) — the number of testcases.

Each of the next T lines contains the initial password s~(3 ≤ |s| ≤ 100), consisting of lowercase and uppercase Latin letters and digits.

Only T = 1 is allowed for hacks.

Output

For each testcase print a renewed password, which corresponds to given conditions. 

The length of the replaced substring is calculated as following: write down all the changed positions. If there are none, then the length is 0. Otherwise the length is the difference between the first and the last changed position plus one. For example, the length of the changed substring between the passwords "abcdef" → "a7cdEf" is 4, because the changed positions are 2 and 5, thus (5 - 2) + 1 = 4.

It is guaranteed that such a password always exists.

If there are several suitable passwords — output any of them.

Example

Input

2
abcDCE
htQw27


Output

abcD4E
htQw27

Note

In the first example Vasya's password lacks a digit, he replaces substring "C" with "4" and gets password "abcD4E". That means, he changed the substring of length 1.

In the second example Vasya's password is ok from the beginning, and nothing has to be changed. That is the same as replacing the empty substring with another empty substring (length 0).

Solution (in PYTHON3):

Solution:
#------------------------------what is this I don't know....just makes my mess faster--------------------------------------
import os
import sys
from io import BytesIO, IOBase
 
BUFSIZE = 8192
 
class FastIO(IOBase):
    newlines = 0
 
    def __init__(self, file):
        self._fd = file.fileno()
        self.buffer = BytesIO()
        self.writable = "x" in file.mode or "r" not in file.mode
        self.write = self.buffer.write if self.writable else None
 
    def read(self):
        while True:
            b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
            if not b:
                break
            ptr = self.buffer.tell()
            self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
        self.newlines = 0
        return self.buffer.read()
 
    def readline(self):
        while self.newlines == 0:
            b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
            self.newlines = b.count(b"\n") + (not b)
            ptr = self.buffer.tell()
            self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
        self.newlines -= 1
        return self.buffer.readline()
 
    def flush(self):
        if self.writable:
            os.write(self._fd, self.buffer.getvalue())
            self.buffer.truncate(0), self.buffer.seek(0)
 
 
class IOWrapper(IOBase):
    def __init__(self, file):
        self.buffer = FastIO(file)
        self.flush = self.buffer.flush
        self.writable = self.buffer.writable
        self.write = lambda s: self.buffer.write(s.encode("ascii"))
        self.read = lambda: self.buffer.read().decode("ascii")
        self.readline = lambda: self.buffer.readline().decode("ascii")
 
 
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
 
#----------------------------------Real game starts here--------------------------------------
'''
 
 
___________________THIS IS AESTROIX CODE________________________
                       KARMANYA GUPTA
 
'''
#_______________________________________________________________#
import math
def fact(x):
	if x == 0:
		return 1
	else:
		return x * fact(x-1)
def lower_bound(li, num): #return 0 if all are greater or equal to
	answer = -1 
	start = 0
	end = len(li)-1

	while(start <= end):
		middle = (end+start)//2
		if li[middle] >= num:
			answer = middle
			end = middle - 1
		else:
			start = middle + 1
	return answer #index where x is not less than num
def upper_bound(li, num): #return n-1 if all are small or equal
	answer = -1
	start = 0
	end = len(li)-1

	while(start <= end):
		middle = (end+start)//2

		if li[middle] <= num:
			answer = middle
			start = middle + 1
		
		else:
			end = middle - 1
	return answer #index where x is not greater than num

def abs(x):
	return x if x >=0 else -x
def binary_search(li, val, lb, ub):
	ans = 0
	while(lb <= ub):
		mid = (lb+ub)//2
		#print(mid, li[mid])
		if li[mid] > val:
			ub = mid-1
		elif val > li[mid]:
			lb = mid + 1
		else:
			ans = 1
			break
	return ans
#_______________________________________________________________#



for _ in range(int(input())):
	string = input()
	n=len(string)
	check = [0,0,0] #lower, upper, digit
	exchange = ['a','A','1']
	flag = 'dont'
	for i in string:
		if i.isdigit():
			check[2] += 1
		elif i.islower():
			check[0] += 1
		else:
			check[1] += 1
	if 0 not in check:
		print(string)
	else:
		by = check.index(0)
		for i in range(n):
			ans = string[:i]+exchange[by]+string[i+1:]
			checker = [0,0,0] #lower, upper, digit
			for i in ans:
				if i.isdigit():
					checker[2] += 1
				elif i.islower():
					checker[0] += 1
				else:
					checker[1] += 1
			if 0 not in checker:
				print(ans)
				flag = 'stop'
				break
	if flag == 'dont':
		if string.isalpha():
			if string.islower():
				print('A4', end='')
				print(string[2:])
			elif string.isupper():
				print("a1",end='')
				print(string[2:])
		elif string.isdigit():
			print("aA",end='')
			print(string[2:])