Problem: You have a rooted tree consisting of n vertices. Each vertex of the tree has some color. We will assume that the tree vertices are numbered by integers from 1 to n. Then we represent the color of vertex v as cv. The tree root is a vertex with number 1.

In this problem you need to answer to m queries. Each query is described by two integers vj, kj. The answer to query vj, kj is the number of such colors of vertices x, that the subtree of vertex vj contains at least kj vertices of color x.

You can find the definition of a rooted tree by the following link: http://en.wikipedia.org/wiki/Tree_(graph_theory).

Input

The first line contains two integers n and m (2 ≤ n ≤ 105; 1 ≤ m ≤ 105). The next line contains a sequence of integers c1, c2, ..., cn (1 ≤ ci ≤ 105). The next n - 1 lines contain the edges of the tree. The i-th line contains the numbers ai, bi (1 ≤ ai, bi ≤ n; ai ≠ bi) — the vertices connected by an edge of the tree.

Next m lines contain the queries. The j-th line contains two integers vj, kj (1 ≤ vj ≤ n; 1 ≤ kj ≤ 105).

Output

Print m integers — the answers to the queries in the order the queries appear in the input.

Examples

Input

8 5
1 2 2 3 3 2 3 3
1 2
1 5
2 3
2 4
5 6
5 7
5 8
1 2
1 3
1 4
2 3
5 3


Output

2
2
1
0
1


Input

4 1
1 2 3 4
1 2
2 3
3 4
1 1


Output

4

Note

A subtree of vertex v in a rooted tree with root r is a set of vertices {u : dist(r, v) + dist(v, u) = dist(r, u)}. Where dist(x, y) is the length (in edges) of the shortest path between vertices x and y.

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.StringTokenizer;


public class A {

	static ArrayList<Integer>[] adjList;
	static int[] tin, tout;
	static int curTime;
	
	static void build(int u, int p)
	{
		
		eulerColor[curTime] = color[u];
		tin[u] = curTime++;
		for(int v: adjList[u])
			if(v != p)
				build(v, u);
					
		tout[u] = curTime - 1;
	}
	
	static int[] eulerColor, color, count;
	static FenwickTree ans;
	
	static void add(int val)
	{
		if(val == 0)
			return;
		ans.update_point(count[val], -1);
		ans.update_point(++count[val], 1);
	}
	
	static void remove(int val)
	{
		if(val == 0)
			return ;
	
		ans.update_point(count[val], -1);
		ans.update_point(--count[val], 1);
	}
	
	public static void main(String[] args) throws IOException 
	{
		Scanner sc = new Scanner(System.in);
		PrintWriter out = new PrintWriter(System.out);
		
		int n = sc.nextInt(), m = sc.nextInt();
		color = new int[n];
		for(int i = 0; i < n; ++i)
			color[i] = sc.nextInt();
		adjList = new ArrayList[n];
		for(int i = 0;i < n; ++i)
			adjList[i] = new ArrayList<Integer> ();
		for(int i = 0; i < n - 1; ++i)
		{
			int u = sc.nextInt() - 1, v = sc.nextInt() - 1;
			adjList[u].add(v);
			adjList[v].add(u);
		}

		eulerColor = new int[n * 2 - 1];
		
		tin = new int[n];
		tout = new int[n];
		build(0, -1);
		
		
		// 2. Preprocess queries
		Query[] queries = new Query[m];
		for(int i = 0; i < m; ++i)
		{
			int v = sc.nextInt()-1, k = sc.nextInt();
			queries[i] = new Query(tin[v], tout[v], i, k);
		}
		Query.s = (int)Math.sqrt(curTime);

		Arrays.sort(queries);
		
		// 3. Mo
		count = new int[(int)1e5 + 1];
		ans = new FenwickTree((int)1e5);
		int left = 0, right = 0;
		add(eulerColor[0]);
		
		int[] res = new int[m];
		for(Query q: queries)
		{
			//process query
			while(left < q.left) remove(eulerColor[left++]);
			while(left > q.left) add(eulerColor[--left]);
			while(right > q.right) remove(eulerColor[right--]);
			while(right < q.right) add(eulerColor[++right]);
			res[q.idx] = ans.rsq(q.k, 100000);
		}
		for(int x: res)
			out.println(x);
		out.flush();
		out.close();

	}
	
	static class Query implements Comparable<Query>
	{
		static int s;
		int left, right, idx, k;
		
		Query(int a, int b, int c, int d)
		{
			left = a;
			right = b;
			idx = c;
			k = d;
		}
		
		public int compareTo(Query q)
		{
			if(left / s != q.left / s)
				return left / s - q.left / s;
			return right - q.right;
		}
	}
	
	static class FenwickTree {

		int[] ft;
		
		int LSOne(int S) { return (S & (-S)); }
		
		FenwickTree(int n)
		{
			ft = new int[n+1];
		}
		
		int rsq(int b)
		{
			int sum = 0;
			while(b>0) { sum += ft[b]; b-=LSOne(b);}
			return sum;
		}
		
		int rsq(int a, int b)
		{
			return rsq(b) - rsq(a-1);
		}
		
		void update_point(int k, int val)
		{
			if(k <= 0)
				return;
			while(k < ft.length)
			{
				ft[k] += val;
				k += LSOne(k);
			}
		}
	}

	static class Scanner 
	{
		StringTokenizer st;
		BufferedReader br;

		public Scanner(InputStream s){	br = new BufferedReader(new InputStreamReader(s));}

		public String next() throws IOException 
		{
			while (st == null || !st.hasMoreTokens()) 
				st = new StringTokenizer(br.readLine());
			return st.nextToken();
		}

		public int nextInt() throws IOException {return Integer.parseInt(next());}

		public long nextLong() throws IOException {return Long.parseLong(next());}

		public String nextLine() throws IOException {return br.readLine();}

		public double nextDouble() throws IOException
		{
			String x = next();
			StringBuilder sb = new StringBuilder("0");
			double res = 0, f = 1;
			boolean dec = false, neg = false;
			int start = 0;
			if(x.charAt(0) == '-')
			{
				neg = true;
				start++;
			}
			for(int i = start; i < x.length(); i++)
				if(x.charAt(i) == '.')
				{
					res = Long.parseLong(sb.toString());
					sb = new StringBuilder("0");
					dec = true;
				}
				else
				{
					sb.append(x.charAt(i));
					if(dec)
						f *= 10;
				}
			res += Long.parseLong(sb.toString()) / f;
			return res * (neg?-1:1);
		}

		public boolean ready() throws IOException {return br.ready();}


	}
}