Problem: You are given three sequences: a_1, a_2, …, a_n; b_1, b_2, …, b_n; c_1, c_2, …, c_n.

For each i, a_i ≠ b_i, a_i ≠ c_i, b_i ≠ c_i.

Find a sequence p_1, p_2, …, p_n, that satisfy the following conditions:

  * p_i ∈ \\{a_i, b_i, c_i\}
  * p_i ≠ p_{(i mod n) + 1}.



In other words, for each element, you need to choose one of the three possible values, such that no two adjacent elements (where we consider elements i,i+1 adjacent for i<n and also elements 1 and n) will have equal value.

It can be proved that in the given constraints solution always exists. You don't need to minimize/maximize anything, you need to find any proper sequence.

Input

The first line of input contains one integer t (1 ≤ t ≤ 100): the number of test cases.

The first line of each test case contains one integer n (3 ≤ n ≤ 100): the number of elements in the given sequences.

The second line contains n integers a_1, a_2, …, a_n (1 ≤ a_i ≤ 100).

The third line contains n integers b_1, b_2, …, b_n (1 ≤ b_i ≤ 100).

The fourth line contains n integers c_1, c_2, …, c_n (1 ≤ c_i ≤ 100).

It is guaranteed that a_i ≠ b_i, a_i ≠ c_i, b_i ≠ c_i for all i.

Output

For each test case, print n integers: p_1, p_2, …, p_n (p_i ∈ \\{a_i, b_i, c_i\}, p_i ≠ p_{i mod n + 1}).

If there are several solutions, you can print any.

Example

Input


5
3
1 1 1
2 2 2
3 3 3
4
1 2 1 2
2 1 2 1
3 4 3 4
7
1 3 3 1 1 1 1
2 4 4 3 2 2 4
4 2 2 2 4 4 2
3
1 2 1
2 3 3
3 1 2
10
1 1 1 2 2 2 3 3 3 1
2 2 2 3 3 3 1 1 1 2
3 3 3 1 1 1 2 2 2 3


Output


1 2 3
1 2 1 2
1 3 4 3 2 4 2
1 3 2
1 2 3 1 2 3 1 2 3 2

Note

In the first test case p = [1, 2, 3].

It is a correct answer, because:

  * p_1 = 1 = a_1, p_2 = 2 = b_2, p_3 = 3 = c_3 
  * p_1 ≠ p_2 , p_2 ≠ p_3 , p_3 ≠ p_1 



All possible correct answers to this test case are: [1, 2, 3], [1, 3, 2], [2, 1, 3], [2, 3, 1], [3, 1, 2], [3, 2, 1].

In the second test case p = [1, 2, 1, 2].

In this sequence p_1 = a_1, p_2 = a_2, p_3 = a_3, p_4 = a_4. Also we can see, that no two adjacent elements of the sequence are equal.

In the third test case p = [1, 3, 4, 3, 2, 4, 2].

In this sequence p_1 = a_1, p_2 = a_2, p_3 = b_3, p_4 = b_4, p_5 = b_5, p_6 = c_6, p_7 = c_7. Also we can see, that no two adjacent elements of the sequence are equal.

Solution (in JAVA):

Solution:
import java.util.*;
import java.lang.*;
import java.io.*;

public class Code{
    public static void main(String[] args) throws java.lang.Exception{
        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
        int t = Integer.parseInt(br.readLine());
        for(int q=0;q<t;q++){
            int n = Integer.parseInt(br.readLine());
            int[] a = new int[n];
            int[] b = new int[n];
            int[] c = new int[n];
            String aA = br.readLine();
            String bA = br.readLine();
            String cA = br.readLine();
            String[] aArr = aA.split(" ");
            String[] bArr = bA.split(" ");
            String[] cArr = cA.split(" ");
            for(int i=0;i<n;i++){
                a[i] = Integer.parseInt(aArr[i]);
                b[i] = Integer.parseInt(bArr[i]);
                c[i] = Integer.parseInt(cArr[i]);
            }
            int curr = a[0];
            int[] p = new int[n];
            for(int i=0;i<n-1;i++){
                p[i] = curr;
                if(curr == a[i+1]){
                    if(curr == b[i+1]){
                        curr = c[i+1];
                    } else {
                        curr = b[i+1];
                    }
                } else {
                    curr = a[i+1];
                }
            }
            if(a[n-1]==p[0]){
                if(p[n-2] ==  b[n-1]){
                    p[n-1] = c[n-1];
                } else {
                    if(b[n-1] == p[0]){
                        p[n-1] = c[n-1];
                    } else {
                        p[n-1] = b[n-1];
                    }
                    
                }
            } else {
                if(p[n-2] == a[n-1]){
                    if(p[n-2] == b[n-1]){
                        p[n-1] = c[n-1];
                    } else {
                        if(b[n-1]==p[0]){
                            p[n-1]=c[n-1];
                        } else {
                            p[n-1] = b[n-1];
                        }
                    }
                } else{
                    p[n-1] = a[n-1];
                }
            }
            
            for(int i=0;i<n;i++){
                System.out.print(p[i]+" ");
            }
            System.out.println();
        }
    }
}