Problem: You are given two positive integers n and k. Print the k-th positive integer that is not divisible by n.

For example, if n=3, and k=7, then all numbers that are not divisible by 3 are: 1, 2, 4, 5, 7, 8, 10, 11, 13 .... The 7-th number among them is 10.

Input

The first line contains an integer t (1 ≤ t ≤ 1000) — the number of test cases in the input. Next, t test cases are given, one per line.

Each test case is two positive integers n (2 ≤ n ≤ 10^9) and k (1 ≤ k ≤ 10^9).

Output

For each test case print the k-th positive integer that is not divisible by n.

Example

Input


6
3 7
4 12
2 1000000000
7 97
1000000000 1000000000
2 1


Output


10
15
1999999999
113
1000000001
1

Solution (in PYTHON3):

Solution:
from sys import stdin,stdout
t = int(stdin.readline())
while t>0:
    n,k = map(int,stdin.readline().split())
    if n>k:
        stdout.write("{}\n".format(k))
    elif n==k:
        stdout.write("{}\n".format(k+1))
    else:
        ans = 0
        r = k%(n-1)
        q = k//(n-1)
        if r==0:
            ans = n*q - 1
        else:
            ans = n*q + r
        stdout.write("{}\n".format(ans))
    t-=1