Problem: You are given two positive integers n and k. Print the k-th positive integer that is not divisible by n.

For example, if n=3, and k=7, then all numbers that are not divisible by 3 are: 1, 2, 4, 5, 7, 8, 10, 11, 13 .... The 7-th number among them is 10.

Input

The first line contains an integer t (1 ≤ t ≤ 1000) — the number of test cases in the input. Next, t test cases are given, one per line.

Each test case is two positive integers n (2 ≤ n ≤ 10^9) and k (1 ≤ k ≤ 10^9).

Output

For each test case print the k-th positive integer that is not divisible by n.

Example

Input


6
3 7
4 12
2 1000000000
7 97
1000000000 1000000000
2 1


Output


10
15
1999999999
113
1000000001
1

Solution (in PYTHON3):

Solution:
def _print(array):
    for e in array:
        print(e)

def not_div(n,k):
    if k < n:
        return k
    q= 1
    n_div = 0
    while q != k:
        n_div = int(k/n) - int(q/n)
        q = k
        k += n_div
    return k

t =int(input())
res = []
for i in range(t):
    n,k = [int(a) for a in input().split(' ')]
    res += [not_div(n,k)]
_print(res)