Problem: You are given two positive integers n and k. Print the k-th positive integer that is not divisible by n.

For example, if n=3, and k=7, then all numbers that are not divisible by 3 are: 1, 2, 4, 5, 7, 8, 10, 11, 13 .... The 7-th number among them is 10.

Input

The first line contains an integer t (1 ≤ t ≤ 1000) — the number of test cases in the input. Next, t test cases are given, one per line.

Each test case is two positive integers n (2 ≤ n ≤ 10^9) and k (1 ≤ k ≤ 10^9).

Output

For each test case print the k-th positive integer that is not divisible by n.

Example

Input


6
3 7
4 12
2 1000000000
7 97
1000000000 1000000000
2 1


Output


10
15
1999999999
113
1000000001
1

Solution (in PYTHON3):

Solution:
def kth_not_div_n(n, k):
        num_blocks = (k // (n - 1))
        residue = k % (n-1)
        print(num_blocks * n + residue  - int(residue == 0))

        #print('k', k, 'n', n, 'num_blocks', num_blocks, 'residue', residue)

if __name__ == "__main__":
    t = int(input())
    for _ in range(t): 
        n, k = [int(i) for i in input().split()]
        kth_not_div_n(n, k)