Problem: You are given two positive integers n and k. Print the k-th positive integer that is not divisible by n.

For example, if n=3, and k=7, then all numbers that are not divisible by 3 are: 1, 2, 4, 5, 7, 8, 10, 11, 13 .... The 7-th number among them is 10.

Input

The first line contains an integer t (1 ≤ t ≤ 1000) — the number of test cases in the input. Next, t test cases are given, one per line.

Each test case is two positive integers n (2 ≤ n ≤ 10^9) and k (1 ≤ k ≤ 10^9).

Output

For each test case print the k-th positive integer that is not divisible by n.

Example

Input


6
3 7
4 12
2 1000000000
7 97
1000000000 1000000000
2 1


Output


10
15
1999999999
113
1000000001
1

Solution (in PYTHON3):

Solution:
import math
T=int(input())
for _ in range(0,T):
    N,K=list(map(int,input().split(" ")))
    mid = N - 1
    term = int(math.ceil(K / mid)) - 1

    #now num
    idx = 0

    # K th num
    result = 0
    idx += N * term
    result += mid * term
    #print(idx, result)
    aterm = K - result
    print(idx + aterm)
    """
    while 1:
        if (result + mid >= K):
            break
        idx += N
        result += mid
    """



    #print(idx)