Problem: Example

Input

2 1
WE


Output

1 2

Solution (in CPP):

Solution:
#include<iostream>
#include<vector>
#include<string>
#include<algorithm>	
#include<map>
#include<set>
#include<utility>
#include<cmath>
#include<cstring>
#include<queue>
#include<stack>
#include<cstdio>
#include<sstream>
#include<iomanip>
#include<assert.h>
#define loop(i,a,b) for(int i=a;i<b;i++) 
#define rep(i,a) loop(i,0,a)
#define pb push_back
#define all(in) in.begin(),in.end()
#define shosu(x) fixed<<setprecision(x)
using namespace std;
//kaewasuretyuui
typedef long long ll;
typedef int Def;
typedef pair<Def,Def> pii;
typedef vector<Def> vi;
typedef vector<vi> vvi;
typedef vector<pii> vp;
typedef vector<vp> vvp;
typedef vector<string> vs;
typedef vector<double> vd;
typedef vector<vd> vvd;
typedef pair<Def,pii> pip;
typedef vector<pip>vip;
//#define mt make_tuple
//typedef tuple<double,int,double> tp;
//typedef vector<tp> vt;
template<typename A,typename B>bool cmin(A &a,const B &b){return a>b?(a=b,true):false;}
template<typename A,typename B>bool cmax(A &a,const B &b){return a<b?(a=b,true):false;}
const double PI=acos(-1);
const double EPS=1e-7;
Def inf=sizeof(Def)==sizeof(long long)?2e18:1e9;
int dx[]={0,1,0,-1};
int dy[]={1,0,-1,0};
int main(){
	int n,m;
	cin>>m>>n;
	vs in(n);
	rep(i,n)cin>>in[i];
	int out=0;
	int cow=0,coe=0;
	rep(i,n)rep(j,m)if(in[i][j]=='W')cow++;
	int ma=cow;
	rep(i,m){
		int co=0;
		rep(j,n)if(in[j][i]=='W')co++;
		cow-=co;
		coe+=n-co;
		if(ma>cow+coe){
			ma=cow+coe;
			out=i+1;
		}
	}
	cout<<out<<" "<<out+1<<endl;
}