Problem: problem

There are $ V $ islands, numbered $ 0, 1, ..., V-1 $, respectively. There are $ E $ bridges, numbered $ 0, 1, ..., E-1 $, respectively. The $ i $ th bridge spans island $ s_i $ and island $ t_i $ and is $ c_i $ wide.

The AOR Ika-chan Corps (commonly known as the Squid Corps), which has a base on the island $ 0 $, is small in scale, so it is always being killed by the Sosu-Usa Corps (commonly known as the Sosuusa Corps) on the island $ V-1 $. .. One day, the squid group got the information that "the Sosusa group will attack tomorrow." A large number of Sosusa's subordinates move across the island from the Sosusa's base, and if even one of their subordinates reaches the Squid's base, the Squid will perish ...

Therefore, the squid group tried to avoid the crisis by putting a road closure tape on the bridge to prevent it from passing through. The length of the tape used is the sum of the widths of the closed bridges. Also, if all the subordinates of the Sosusa group always pass through a bridge with a width of $ 1 $, the squid group can ambush there to prevent them from passing through the Sosusa group.

The length of the tape it holds is $ 10 ^ 4 $. Considering the future, I would like to consume as little tape as possible. Find the minimum length of tape used to keep Sosusa's subordinates from reaching the squid's base. However, if the tape is not long enough and you are attacked by all means, output $ -1 $.



output

Output the minimum length of tape used to prevent Sosusa's subordinates from reaching the Squid's base. However, if the tape is not long enough and you are attacked by all means, output $ -1 $. Also, output a line break at the end.

Example

Input

4 4
0 1 3
0 2 4
1 3 1
2 3 5


Output

4

Solution (in CPP):

Solution:
#include "bits/stdc++.h"
#include<unordered_map>
#include<unordered_set>
#pragma warning(disable:4996)
using namespace std;
using ld = double;
const ld eps = 1e-9;
//
//using Graph = vector<vector<int>>;
//
//int dfs(const Graph&g, const int now, vector<int>&ch_cnts) {
//  ch_cnts[now]++;
//  for (auto&& e : g[now]) {
//      ch_cnts[now] += dfs(g, e, ch_cnts);
//  }
//  return ch_cnts[now];
//}
//
//struct HL_Edge {
//  int from;
//  int to;
//  bool heavy;
//};
//
//void dfs2(const Graph&g, vector<vector<HL_Edge>>&hl_tree, const int now, const vector<int>&ch_cnts) {
//
//  int max_ch_id = 1;
//  {
//      int max_ch_num = -1;
//      for (auto&&e : g[now]) {
//          if (max_ch_num < ch_cnts[e]) {
//              max_ch_num = ch_cnts[e];
//              max_ch_id = e;
//          }
//      }
//  }
//  for (auto e : g[now]) {
//      bool heavy = (e == max_ch_id);
//
//      hl_tree[now].push_back(HL_Edge{ now,e,heavy });
//  }
//  return;
//}
//
//void HL(const vector<vector<int>>&ro_tree) {
//  vector<int>ch_cnts(ro_tree.size());
//
//  dfs(ro_tree, 0, ch_cnts);
//
//  vector<vector<HL_Edge>>hl_tree(ro_tree.size());
//
//  dfs2(ro_tree, hl_tree, 0, ch_cnts);
//}
//
//namespace FastFourierTransform
//{
//  using C = complex< double >;
//
//  void DiscreteFourierTransform(vector< C > &F, bool rev)
//  {
//      const int N = (int)F.size();
//      const double PI = (rev ? -1 : 1) * acos(-1);
//      for (int i = 0, j = 1; j + 1 < N; j++) {
//          for (int k = N >> 1; k > (i ^= k); k >>= 1);
//          if (i > j) swap(F[i], F[j]);
//      }
//      C w, s, t;
//      for (int i = 1; i < N; i <<= 1) {
//          for (int k = 0; k < i; k++) {
//              w = polar(1.0, PI / i * k);
//              for (int j = 0; j < N; j += i * 2) {
//                  s = F[j + k];
//                  t = C(F[j + k + i].real() * w.real() - F[j + k + i].imag() * w.imag(),
//                      F[j + k + i].real() * w.imag() + F[j + k + i].imag() * w.real());
//                  F[j + k] = s + t, F[j + k + i] = s - t;
//              }
//          }
//      }
//      if (rev) for (int i = 0; i < N; i++) F[i] /= N;
//  }
//
//  vector< int> Multiply(const vector<int > &A, const vector<int > &B)
//  {
//      int sz = 1;
//      while (sz <= A.size() + B.size()) sz <<= 1;
//      vector< C > F(sz), G(sz);
//      for (int i = 0; i < A.size(); i++) F[i] = A[i];
//      for (int i = 0; i < B.size(); i++) G[i] = B[i];
//      DiscreteFourierTransform(F, false);
//      DiscreteFourierTransform(G, false);
//      for (int i = 0; i < sz; i++) F[i] *= G[i];
//      DiscreteFourierTransform(F, true);
//      vector< int > X(A.size() + B.size() - 1);
//      for (int i = 0; i < A.size() + B.size() - 1; i++) X[i] = F[i].real() + 0.5;
//      return (X);
//  }
//};



#define _GLIBCXX_DEBUG

using namespace std;

#define REP(i,n) for(int i=0;i<(int)n;++i)
#define FOR(i,c) for(auto i=(c).begin();i!=(c).end();++i)
#define ALL(c) (c).begin(), (c).end()


//const int INF = 2147483647;
//const long long int L_INF = 9223372036854775807;

typedef long long int Weight;

const Weight INF = 1e18;
const Weight ZERO = 0;
struct Edge {
	int src, dst;
	Weight weight;
	Edge(int src, int dst, Weight weight) :
		src(src), dst(dst), weight(weight) { }
	Edge() :src(0), dst(0), weight(0) {

	}
};
bool operator < (const Edge &e, const Edge &f) {
	return e.weight != f.weight ? e.weight > f.weight : // !!INVERSE!!
	e.src != f.src ? e.src < f.src : e.dst < f.dst;
}
typedef vector<Edge> Edges;
typedef vector<Edges> Graph;

typedef vector<Weight> Array;
typedef vector<Array> Matrix;
#define RESIDUE(s,t) (capacity[s*1e4+t]-flow[s*1e4+t])

//流量0の逆辺も張らないと正しく求まらないので注意
Weight maximumFlow(const Graph &ag, int s, int t) {

	Graph g(ag);

	int n = g.size();
	//Matrix flow(n, Array(n,ZERO)), capacity(n, Array(n,ZERO));

	map<int,Weight>flow,capacity;
	REP(u, n) FOR(e, g[u]) capacity[e->src*1e4+e->dst] =capacity[1e4*e->src+e->dst]+ e->weight;


	Weight total = ZERO;
	while (1) {
		queue<int> Q; Q.push(s);
		vector<int> prev(n, -1); prev[s] = s;
		while (!Q.empty() && prev[t] < 0) {
			int u = Q.front(); Q.pop();
			FOR(e, g[u]) if (prev[e->dst] < 0 && RESIDUE(u, e->dst) > ZERO) {
				prev[e->dst] = u;
				Q.push(e->dst);
			}
		}
		if (prev[t] < 0)break; // prev[x] == -1 <=> t-side
		Weight inc = INF;
		for (int j = t; prev[j] != j; j = prev[j]){
			auto v(RESIDUE(prev[j], j));
			if (inc > v) {
				inc = v;
			}
		}
		for (int j = t; prev[j] != j; j = prev[j])
			flow[prev[j]*1e4+j] =flow[j+1e4 * prev[j]]+inc, flow[j*1e4 + prev[j]] =flow[j*1e4+prev[j]]- inc;;
		total += inc;
	}

	return total;
}


int main() {
	int V,E;cin>>V>>E;
	Graph g(V);
	for (int i = 0; i < E; ++i) {
		int f,t,c;cin>>f>>t>>c;
		long long int num=c*static_cast<long long int>(1e9);
		if(num==1e9)num--;
		g[f].push_back(Edge(f,t,num));
		g[t].push_back(Edge(t,f,num));

	}

	auto ans=maximumFlow(g,0,V-1);

	long long int nn=ans/(1e9);
	if(nn>1e4)nn=-1;
	cout<<nn<<endl;
	return 0;
}