Problem: A positive (strictly greater than zero) integer is called round if it is of the form d00...0. In other words, a positive integer is round if all its digits except the leftmost (most significant) are equal to zero. In particular, all numbers from 1 to 9 (inclusive) are round.

For example, the following numbers are round: 4000, 1, 9, 800, 90. The following numbers are not round: 110, 707, 222, 1001.

You are given a positive integer n (1 ≤ n ≤ 10^4). Represent the number n as a sum of round numbers using the minimum number of summands (addends). In other words, you need to represent the given number n as a sum of the least number of terms, each of which is a round number.

Input

The first line contains an integer t (1 ≤ t ≤ 10^4) — the number of test cases in the input. Then t test cases follow.

Each test case is a line containing an integer n (1 ≤ n ≤ 10^4).

Output

Print t answers to the test cases. Each answer must begin with an integer k — the minimum number of summands. Next, k terms must follow, each of which is a round number, and their sum is n. The terms can be printed in any order. If there are several answers, print any of them.

Example

Input


5
5009
7
9876
10000
10


Output


2
5000 9
1
7 
4
800 70 6 9000 
1
10000 
1
10 

Solution (in JAVA):

Solution:
import java.util.*;
import java.io.*;
import java.lang.*;



public class Main
{




  public static void main(String[] args)
  {
  Scanner s=new Scanner(System.in);
  int t=s.nextInt();
  while(t-->0)
  {
    int n=s.nextInt();
    int rem=0,k=1;
    ArrayList<Integer> al= new ArrayList<>();
    while(n!=0)
    {
      rem=n%10;
      rem=rem*k;
      if(rem>0)
      {
        al.add(rem);
      }
      
      k=k*10;
      n=n/10;
    }
    System.out.println(al.size());
    for(int i:al)
    {
      System.out.print(i+" ");
    }
    System.out.println();
  }


  

  }
}