Problem: You are given two integers n and k. Find k-th smallest divisor of n, or report that it doesn't exist.

Divisor of n is any such natural number, that n can be divided by it without remainder.

Input

The first line contains two integers n and k (1 ≤ n ≤ 1015, 1 ≤ k ≤ 109).

Output

If n has less than k divisors, output -1.

Otherwise, output the k-th smallest divisor of n.

Examples

Input

4 2


Output

2


Input

5 3


Output

-1


Input

12 5


Output

6

Note

In the first example, number 4 has three divisors: 1, 2 and 4. The second one is 2.

In the second example, number 5 has only two divisors: 1 and 5. The third divisor doesn't exist, so the answer is -1.

Solution (in PYTHON3):

Solution:
def div(x):
    d = []
    for i in range(1, 1 + int(x ** .5)):
        if x % i == 0:
            d.append(i)
            y = x // i
            if y != i:
                d.append(y)
    d.sort()
    return d


n, k = map(int, input().split())
dd = div(n)
if k <= len(dd):
    print(dd[k - 1])
else:
    print(-1)