Problem: You are given a string, consisting of lowercase Latin letters.

A pair of neighbouring letters in a string is considered ugly if these letters are also neighbouring in a alphabet. For example, string "abaca" contains ugly pairs at positions (1, 2) — "ab" and (2, 3) — "ba". Letters 'a' and 'z' aren't considered neighbouring in a alphabet.

Can you rearrange the letters of a given string so that there are no ugly pairs? You can choose any order of the letters of the given string but you can't add any new letters or remove the existing ones. You can also leave the order the same.

If there are multiple answers, print any of them.

You also have to answer T separate queries.

Input

The first line contains a single integer T (1 ≤ T ≤ 100) — the number of queries.

Each of the next T lines contains string s (1 ≤ |s| ≤ 100) — the string for the next query. It is guaranteed that it contains only lowercase Latin letters.

Note that in hacks you have to set T = 1.

Output

Print T lines. The i-th line should contain the answer to the i-th query.

If the answer for the i-th query exists, then print such a rearrangment of letters of the given string that it contains no ugly pairs. You can choose any order of the letters of the given string but you can't add any new letters or remove the existing ones. You can also leave the order the same.

If there are multiple answers, print any of them.

Otherwise print "No answer" for that query.

Example

Input


4
abcd
gg
codeforces
abaca


Output


cadb
gg
codfoerces
No answer

Note

In the first example answer "bdac" is also correct.

The second example showcases the fact that only neighbouring in alphabet letters are not allowed. The same letter is ok.

There are lots of valid answers for the third example.

Solution (in JAVA):

Solution:
// Java implementation of the approach taken from GFG
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.*;

public class B
{

    // Function that returns true if the
    // current arrangement is valid
    private static  StringBuilder sb;
    static boolean check(String s)
    {
        for (int i = 0; i + 1 < s.length(); ++i)
        {
            if (Math.abs(s.charAt(i) -
                    s.charAt(i + 1)) == 1)
            {
                return false;
            }
        }
        return true;
    }

    // Function to rearrange the characters of
    // the string such that no two neighbours
    // in the English alphabets appear together
    static void Rearrange(String str)
    {

        // To store the odd and the
        // even positioned characters
        String odd = "", even = "";

        // Traverse through the array
        for (int i = 0; i < str.length(); ++i)
        {
            if (str.charAt(i) % 2 == 0)
            {
                even += str.charAt(i);
            }
            else
            {
                odd += str.charAt(i);
            }
        }

        // Sort both the strings
        odd = sort(odd);
        even = sort(even);

        // Check possibilities
        if (check(odd + even))
        {
            sb.append(odd + even);
        }
        else if (check(even + odd))
        {
            sb.append(even + odd);
        }
        else
        {
            sb.append("No answer");
        }
        sb.append("\n");
    }

    // Method to sort a string alphabetically
    public static String sort(String inputString)
    {
        // convert input string to char array
        char tempArray[] = inputString.toCharArray();

        // sort tempArray
        Arrays.sort(tempArray);

        // return new sorted string
        return new String(tempArray);
    }

    // Driver code
    public static void main(String[] args) throws IOException
    {
        BufferedReader br=new BufferedReader(new InputStreamReader(System.in));

        int T=Integer.parseInt(br.readLine().trim());
        sb=new StringBuilder();

        while(T-->0) Rearrange(br.readLine().trim());
        System.out.println(sb);
    }
}

// This code is contributed by 29AjayKumar