Problem: You are given two integers n and k. Find k-th smallest divisor of n, or report that it doesn't exist.

Divisor of n is any such natural number, that n can be divided by it without remainder.

Input

The first line contains two integers n and k (1 ≤ n ≤ 1015, 1 ≤ k ≤ 109).

Output

If n has less than k divisors, output -1.

Otherwise, output the k-th smallest divisor of n.

Examples

Input

4 2


Output

2


Input

5 3


Output

-1


Input

12 5


Output

6

Note

In the first example, number 4 has three divisors: 1, 2 and 4. The second one is 2.

In the second example, number 5 has only two divisors: 1 and 5. The third divisor doesn't exist, so the answer is -1.

Solution (in PYTHON3):

Solution:
import math

n,k=map(int,input().split())
arr=[i for i in range(1,int(math.sqrt(n))+1) if n%i==0]
l=len(arr)
if(k<=l):
	print(arr[k-1])
else:
	if(math.sqrt(n)%1==0):
			k+=1
	if(k>2*len(arr)):
		print(-1)
	else:
		k=(k)-int(l)
		k=int(l)-k
		print(int(n/arr[k]))