Problem: A positive (strictly greater than zero) integer is called round if it is of the form d00...0. In other words, a positive integer is round if all its digits except the leftmost (most significant) are equal to zero. In particular, all numbers from 1 to 9 (inclusive) are round.

For example, the following numbers are round: 4000, 1, 9, 800, 90. The following numbers are not round: 110, 707, 222, 1001.

You are given a positive integer n (1 ≤ n ≤ 10^4). Represent the number n as a sum of round numbers using the minimum number of summands (addends). In other words, you need to represent the given number n as a sum of the least number of terms, each of which is a round number.

Input

The first line contains an integer t (1 ≤ t ≤ 10^4) — the number of test cases in the input. Then t test cases follow.

Each test case is a line containing an integer n (1 ≤ n ≤ 10^4).

Output

Print t answers to the test cases. Each answer must begin with an integer k — the minimum number of summands. Next, k terms must follow, each of which is a round number, and their sum is n. The terms can be printed in any order. If there are several answers, print any of them.

Example

Input


5
5009
7
9876
10000
10


Output


2
5000 9
1
7 
4
800 70 6 9000 
1
10000 
1
10 

Solution (in PYTHON3):

Solution:
def main():

    import sys, math
    #from bisect import bisect_left as bl, bisect_right as br, insort
    from heapq import heapify, heappush, heappop
    from collections import defaultdict as dd, deque
    def data(): return sys.stdin.readline().strip()
    def mdata(): return list(map(int, data().split()))
    def out(*var, end="\n"): sys.stdout.write(' '.join(map(str, var))+end)
    # sys.setrecursionlimit(100000)
    INF = int(1e9)
    mod = int(1e9)+7

    for t in range(int(data())):
        n=int(data())
        t=1
        ans=[]
        while n:
            if n%10:
                ans.append((n%10)*t)
            n//=10
            t*=10
        print(len(ans))
        print(*ans)

if __name__ == '__main__':
    main()