Problem: A positive (strictly greater than zero) integer is called round if it is of the form d00...0. In other words, a positive integer is round if all its digits except the leftmost (most significant) are equal to zero. In particular, all numbers from 1 to 9 (inclusive) are round.

For example, the following numbers are round: 4000, 1, 9, 800, 90. The following numbers are not round: 110, 707, 222, 1001.

You are given a positive integer n (1 ≤ n ≤ 10^4). Represent the number n as a sum of round numbers using the minimum number of summands (addends). In other words, you need to represent the given number n as a sum of the least number of terms, each of which is a round number.

Input

The first line contains an integer t (1 ≤ t ≤ 10^4) — the number of test cases in the input. Then t test cases follow.

Each test case is a line containing an integer n (1 ≤ n ≤ 10^4).

Output

Print t answers to the test cases. Each answer must begin with an integer k — the minimum number of summands. Next, k terms must follow, each of which is a round number, and their sum is n. The terms can be printed in any order. If there are several answers, print any of them.

Example

Input


5
5009
7
9876
10000
10


Output


2
5000 9
1
7 
4
800 70 6 9000 
1
10000 
1
10 

Solution (in PYTHON3):

Solution:
# -*- coding: utf-8 -*-
"""
Created on Sat May  9 21:12:24 2020

@author: reach
"""

t=input()
t=int(t)
for s in range(t):
	num=input()
	num=int(num)
	out=[]
	c=0
	if(num>10000):
		out.append(num-num%10000)
		num=num%10000
		c+=1
	if(num>1000):
		out.append(num-num%1000)
		c+=1
		num=num%1000
	if(num>100):
		out.append(num-num%100)
		num=num%100
		c+=1
	
	if(num>10):
		out.append(num-num%10)
		num=num%10
		c+=1
	if(num>0):
	    out.append(num)
	    c+=1
	print(c)
	print(' '.join(map(str, out)))