Problem: A positive (strictly greater than zero) integer is called round if it is of the form d00...0. In other words, a positive integer is round if all its digits except the leftmost (most significant) are equal to zero. In particular, all numbers from 1 to 9 (inclusive) are round.

For example, the following numbers are round: 4000, 1, 9, 800, 90. The following numbers are not round: 110, 707, 222, 1001.

You are given a positive integer n (1 ≤ n ≤ 10^4). Represent the number n as a sum of round numbers using the minimum number of summands (addends). In other words, you need to represent the given number n as a sum of the least number of terms, each of which is a round number.

Input

The first line contains an integer t (1 ≤ t ≤ 10^4) — the number of test cases in the input. Then t test cases follow.

Each test case is a line containing an integer n (1 ≤ n ≤ 10^4).

Output

Print t answers to the test cases. Each answer must begin with an integer k — the minimum number of summands. Next, k terms must follow, each of which is a round number, and their sum is n. The terms can be printed in any order. If there are several answers, print any of them.

Example

Input


5
5009
7
9876
10000
10


Output


2
5000 9
1
7 
4
800 70 6 9000 
1
10000 
1
10 

Solution (in PYTHON3):

Solution:
t = int(input())
for i in range(t):
    a = []
    n = int(input())
    k2 = str(n)
    n1 = n
    m = 0
    n2 = 1
    count = 0
    while n2 > 0:
        n2 = n1//(10)**m
        m = m+1
    m = m - 1
    m1 = m
    if m == 1:
        a.append(int(n))
        count = 1
    else:
        mop = [int(i) for i in str(k2)]
        for j in mop:
            if j == 0:
                m = m-1
            else:
                ans = j*(10**m)
                m = m-1
                a.append(int(ans/10))
                count = count + 1
    print(count)
    print(*a)