Problem: Try guessing the statement from this picture: 

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You are given a non-negative integer d. You have to find two non-negative real numbers a and b such that a + b = d and a ⋅ b = d.

Input

The first line contains t (1 ≤ t ≤ 10^3) — the number of test cases.

Each test case contains one integer d (0 ≤ d ≤ 10^3).

Output

For each test print one line.

If there is an answer for the i-th test, print "Y", and then the numbers a and b.

If there is no answer for the i-th test, print "N".

Your answer will be considered correct if |(a + b) - a ⋅ b| ≤ 10^{-6} and |(a + b) - d| ≤ 10^{-6}.

Example

Input


7
69
0
1
4
5
999
1000


Output


Y 67.985071301 1.014928699
Y 0.000000000 0.000000000
N
Y 2.000000000 2.000000000
Y 3.618033989 1.381966011
Y 997.998996990 1.001003010
Y 998.998997995 1.001002005

Solution (in JAVA):

Solution:
import java.util.*;

public final class Solution {
  public static void main(String[] args) {
    Scanner input = new Scanner(System.in);
    int t = input.nextInt();
    while (t-- > 0) {
      int d = input.nextInt();
      double tmp1 = (double)d*d - (double)4*d;
      if (tmp1 < 0) {
        System.out.println("N");
        continue;
      }
      tmp1 = Math.sqrt(tmp1);
      double tmp2 = ((double)d + tmp1)/2.0;
      double tmp3 = ((double)d - tmp1)/2.0;
      System.out.print("Y ");
      System.out.println(tmp2 + " " + tmp3);
    }
  }
}