Problem: A positive (strictly greater than zero) integer is called round if it is of the form d00...0. In other words, a positive integer is round if all its digits except the leftmost (most significant) are equal to zero. In particular, all numbers from 1 to 9 (inclusive) are round.

For example, the following numbers are round: 4000, 1, 9, 800, 90. The following numbers are not round: 110, 707, 222, 1001.

You are given a positive integer n (1 ≤ n ≤ 10^4). Represent the number n as a sum of round numbers using the minimum number of summands (addends). In other words, you need to represent the given number n as a sum of the least number of terms, each of which is a round number.

Input

The first line contains an integer t (1 ≤ t ≤ 10^4) — the number of test cases in the input. Then t test cases follow.

Each test case is a line containing an integer n (1 ≤ n ≤ 10^4).

Output

Print t answers to the test cases. Each answer must begin with an integer k — the minimum number of summands. Next, k terms must follow, each of which is a round number, and their sum is n. The terms can be printed in any order. If there are several answers, print any of them.

Example

Input


5
5009
7
9876
10000
10


Output


2
5000 9
1
7 
4
800 70 6 9000 
1
10000 
1
10 

Solution (in PYTHON3):

Solution:
#space seperated input in a list-------
#a = list(map(int, input().split()))
t=int(input())
for d in range(t):
  n=int(input())
  x=str(n)
  arr=[]
  if len(x)==1 or n%(10**(len(x)-1))==0:
      print(1)
      print(n)
  elif len(x)>1:
      for i in range (len(x)):
          g=int(x[i])*(10**(len(x)-i-1))
          if g!=0:
              arr.append(g)
          elif g==0:
              continue
      print(len(arr))
      for i in range(len(arr)):
        print(arr[i], end=' ')