Problem: A positive (strictly greater than zero) integer is called round if it is of the form d00...0. In other words, a positive integer is round if all its digits except the leftmost (most significant) are equal to zero. In particular, all numbers from 1 to 9 (inclusive) are round.

For example, the following numbers are round: 4000, 1, 9, 800, 90. The following numbers are not round: 110, 707, 222, 1001.

You are given a positive integer n (1 ≤ n ≤ 10^4). Represent the number n as a sum of round numbers using the minimum number of summands (addends). In other words, you need to represent the given number n as a sum of the least number of terms, each of which is a round number.

Input

The first line contains an integer t (1 ≤ t ≤ 10^4) — the number of test cases in the input. Then t test cases follow.

Each test case is a line containing an integer n (1 ≤ n ≤ 10^4).

Output

Print t answers to the test cases. Each answer must begin with an integer k — the minimum number of summands. Next, k terms must follow, each of which is a round number, and their sum is n. The terms can be printed in any order. If there are several answers, print any of them.

Example

Input


5
5009
7
9876
10000
10


Output


2
5000 9
1
7 
4
800 70 6 9000 
1
10000 
1
10 

Solution (in PYTHON3):

Solution:

# Get the input
# go over the digits of the number len(num) will be the range
    # for every digit that is not 0 store in an array and add zeros according to the position -1
# disect them according to the length of the number
nums = []
#number of inputs
inps =  int(input())
for i in range(inps):
    nums.append(str(input()))
sums = []
for num in nums:
    for ith_dig in range(len(num)):
        if not num[ith_dig] == "0":
            orig = num[ith_dig]
            zeros = len(num)- ith_dig - 1
            for i in range(zeros):
                orig+= "0"
            sums.append(int(orig))
    print(len(sums))
    for i in sums:
        print(i, end=" ")
    sums = []
    print()