Problem: The name of one small but proud corporation consists of n lowercase English letters. The Corporation has decided to try rebranding — an active marketing strategy, that includes a set of measures to change either the brand (both for the company and the goods it produces) or its components: the name, the logo, the slogan. They decided to start with the name.

For this purpose the corporation has consecutively hired m designers. Once a company hires the i-th designer, he immediately contributes to the creation of a new corporation name as follows: he takes the newest version of the name and replaces all the letters xi by yi, and all the letters yi by xi. This results in the new version. It is possible that some of these letters do no occur in the string. It may also happen that xi coincides with yi. The version of the name received after the work of the last designer becomes the new name of the corporation.

Manager Arkady has recently got a job in this company, but is already soaked in the spirit of teamwork and is very worried about the success of the rebranding. Naturally, he can't wait to find out what is the new name the Corporation will receive.

Satisfy Arkady's curiosity and tell him the final version of the name.

Input

The first line of the input contains two integers n and m (1 ≤ n, m ≤ 200 000) — the length of the initial name and the number of designers hired, respectively.

The second line consists of n lowercase English letters and represents the original name of the corporation.

Next m lines contain the descriptions of the designers' actions: the i-th of them contains two space-separated lowercase English letters xi and yi.

Output

Print the new name of the corporation.

Examples

Input

6 1
police
p m


Output

molice


Input

11 6
abacabadaba
a b
b c
a d
e g
f a
b b


Output

cdcbcdcfcdc

Note

In the second sample the name of the corporation consecutively changes as follows:

<image>

<image>

<image>

<image>

<image>

<image>

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.util.StringTokenizer;

/**
 * Created by god on 25.10.15.
 */

public class TaskRebranding {

    public static void main(String[] args) {
        In in = new In(System.in);
        PrintWriter writer = new PrintWriter(System.out);
        // --
        int n = in.nextInt();
        int m = in.nextInt();
        String src = in.next();

        NameProcessor np = new NameProcessor();
        for (int i = 0; i < m; i++) {
            char from = in.next().charAt(0);
            char to = in.next().charAt(0);
            np.addRule(from, to);
        }

        writer.println(np.process(src));
        // --
        writer.flush();
    }

    public static class NameProcessor {
        private char[] map;
        public NameProcessor() {
            map = new char[26];
            for (int i = 0; i < 26; i++) {
                map[i] = (char)(i + 'a');
            }
        }

        public void addRule(char from, char to) {
            for (int i = 0; i < 26; i++) {
                if (map[i] == from) map[i] = to;
                else if (map[i] == to) map[i] = from;
            }
        }

        public String process(String s) {
            char[] name = new char[s.length()];
            for (int i = 0; i < s.length(); i++) {
                name[i] = process(s.charAt(i));
            }
            return new String(name);
        }

        private char process(char c) {
            return map[c - 'a'];
        }
    }

    public static class In {
        public BufferedReader reader;
        public StringTokenizer tokenizer;

        public In(InputStream in) {
            reader = new BufferedReader(new InputStreamReader(in));
        }

        private void restore() {
            while (tokenizer == null || !tokenizer.hasMoreTokens())
                try {
                    tokenizer = new StringTokenizer(reader.readLine());
                } catch (Exception e) {
                }
        }

        public String next() {
            restore();
            return tokenizer.nextToken();
        }

        public int nextInt() {
            return Integer.parseInt(next());
        }
    }
}