Problem: Silver Fox is fighting with N monsters.

The monsters are standing in a row, and we can assume them to be standing on a number line. The i-th monster, standing at the coordinate X_i, has the health of H_i.

Silver Fox can use bombs to attack the monsters. Using a bomb at the coordinate x decreases the healths of all monsters between the coordinates x-D and x+D (inclusive) by A. There is no way other than bombs to decrease the monster's health.

Silver Fox wins when all the monsters' healths become 0 or below.

Find the minimum number of bombs needed to win.

Constraints

* 1 \leq N \leq 2 \times 10^5
* 0 \leq D \leq 10^9
* 1 \leq A \leq 10^9
* 0 \leq X_i \leq 10^9
* 1 \leq H_i \leq 10^9
* X_i are distinct.
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N D A
X_1 H_1
:
X_N H_N


Output

Print the minimum number of bombs needed to win.

Examples

Input

3 3 2
1 2
5 4
9 2


Output

2


Input

9 4 1
1 5
2 4
3 3
4 2
5 1
6 2
7 3
8 4
9 5


Output

5


Input

3 0 1
300000000 1000000000
100000000 1000000000
200000000 1000000000


Output

3000000000

Solution (in PYTHON3):

Solution:
import bisect
import sys
input = sys.stdin.readline

n,d,a= map(int, input().split())
x= [list(map(int, input().split())) for i in range(n)]

x.sort()
y=[]
for i in range(n):
    y.append(x[i][0])
    x[i][1]=-(-x[i][1]//a)

# どのモンスターまで倒したか管理しながら進める。
ans=0
# いつ効力が切れるか記録
z=[0]*(n+1)
# 今の攻撃力
atk=0
for i in range(n):
    atk+=z[i]
    if x[i][1]-atk>0:
        ans+=x[i][1]-atk
        q=bisect.bisect_right(y,x[i][0]+2*d,i,n)
        z[q]-=x[i][1]-atk
        atk+=x[i][1]-atk
print(ans)