Problem: You are given two integers n and k. Find k-th smallest divisor of n, or report that it doesn't exist.

Divisor of n is any such natural number, that n can be divided by it without remainder.

Input

The first line contains two integers n and k (1 ≤ n ≤ 1015, 1 ≤ k ≤ 109).

Output

If n has less than k divisors, output -1.

Otherwise, output the k-th smallest divisor of n.

Examples

Input

4 2


Output

2


Input

5 3


Output

-1


Input

12 5


Output

6

Note

In the first example, number 4 has three divisors: 1, 2 and 4. The second one is 2.

In the second example, number 5 has only two divisors: 1 and 5. The third divisor doesn't exist, so the answer is -1.

Solution (in PYTHON3):

Solution:
#problem 762A

#10.01.2018

def f2(n,i,Ans):

    if n==1 or i==1:

        return n,Ans



    while n%i==0:

        Ans[i] = Ans.get(i,0)+1

        n//=i

    return n, Ans

def f(n):

    Ans={}

    b=[2,3,5]

    for b_i in b:

        if n%b_i==0:

            n,Ans=f2(n,b_i,Ans)



    if n==1:

        return Ans











    n_squr=int(n**0.5)



    k=[1, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 169, 173, 179, 181, 191, 193, 197, 199, 211, 221, 223, 227, 229, 233, 239, 241, 247, 251, 257, 263, 269, 271, 277, 281, 283, 289, 293, 299, 307, 311, 313, 317, 323, 331, 337, 347, 349, 353, 359, 361, 367, 373, 377, 379, 383, 389, 391, 397, 401, 403, 409, 419, 421, 431, 433, 437, 439, 443, 449, 457, 461, 463, 467, 479, 481, 487, 491, 493, 499, 503, 509, 521, 523, 527, 529, 533, 541, 547, 551, 557, 559, 563, 569, 571, 577, 587, 589, 593, 599, 601, 607, 611, 613, 617, 619, 629, 631, 641, 643, 647, 653, 659, 661, 667, 673, 677, 683, 689, 691, 697, 701, 703, 709, 713, 719, 727, 731, 733, 739, 743, 751, 757, 761, 767, 769, 773, 779, 787, 793, 797, 799, 809, 811, 817, 821, 823, 827, 829, 839, 841, 851, 853, 857, 859, 863, 871, 877, 881, 883, 887, 893, 899, 901, 907, 911, 919, 923, 929, 937, 941, 943, 947, 949, 953, 961, 967, 971, 977, 983, 989, 991, 997, 1003, 1007, 1009, 1013, 1019, 1021, 1027, 1031, 1033, 1037, 1039, 1049, 1051, 1061, 1063, 1069, 1073, 1079, 1081, 1087, 1091, 1093, 1097, 1103, 1109, 1117, 1121, 1123, 1129, 1139, 1147, 1151, 1153, 1157, 1159, 1163, 1171, 1181, 1187, 1189, 1193, 1201, 1207, 1213, 1217, 1219, 1223, 1229, 1231, 1237, 1241, 1247, 1249, 1259, 1261, 1271, 1273, 1277, 1279, 1283, 1289, 1291, 1297, 1301, 1303, 1307, 1313, 1319, 1321, 1327, 1333, 1339, 1343, 1349, 1357, 1361, 1363, 1367, 1369, 1373, 1381, 1387, 1391, 1399, 1403, 1409, 1411, 1417, 1423, 1427, 1429, 1433, 1439, 1447, 1451, 1453, 1457, 1459, 1469, 1471, 1481, 1483, 1487, 1489, 1493, 1499, 1501, 1511, 1513, 1517, 1523, 1531, 1537, 1541, 1543, 1549, 1553, 1559, 1567, 1571, 1577, 1579, 1583, 1591, 1597, 1601, 1607, 1609, 1613, 1619, 1621, 1627, 1633, 1637, 1643, 1649, 1651, 1657, 1663, 1667, 1669, 1679, 1681, 1691, 1693, 1697, 1699, 1703, 1709, 1711, 1717, 1721, 1723, 1733, 1739, 1741, 1747, 1751, 1753, 1759, 1763, 1769, 1777, 1781, 1783, 1787, 1789, 1801, 1807, 1811, 1817, 1819, 1823, 1829, 1831, 1843, 1847, 1849, 1853, 1861, 1867, 1871, 1873, 1877, 1879, 1889, 1891, 1901, 1907, 1909, 1913, 1919, 1921, 1927, 1931, 1933, 1937, 1943, 1949, 1951, 1957, 1961, 1963, 1973, 1979, 1987, 1993, 1997, 1999, 2003, 2011, 2017, 2021, 2027, 2029, 2033, 2039, 2041, 2047, 2053, 2059, 2063, 2069, 2071, 2077, 2081, 2083, 2087, 2089, 2099, 2111, 2113, 2117, 2119, 2129, 2131, 2137, 2141, 2143, 2147, 2153, 2159, 2161, 2171, 2173, 2179, 2183, 2197, 2201, 2203, 2207, 2209, 2213, 2221, 2227, 2231, 2237, 2239, 2243, 2249, 2251, 2257, 2263, 2267, 2269, 2273, 2279, 2281, 2287, 2291, 2293, 2297, 2309]



    for i in range(0,(n_squr+1),2310):

        for j in k:

            if n%(i+j)==0:

                n,Ans=f2(n,i+j,Ans)







    if n>1:

        Ans[n] = Ans.get(n,0)+1

    return Ans

def main():

    n, k = list(map(int,input().split()))

    a = f(n)

    

    ex = 1,

    for i in a:

        new = list()

        for j in ex:

            for v in range(0,a[i]+1):

                new.append(j*i**v)

        ex = new

    if(len(ex)<k):

        print(-1)

    else:

        print(sorted(ex)[k-1])

main()





# Made By Mostafa_Khaled