Problem: A positive (strictly greater than zero) integer is called round if it is of the form d00...0. In other words, a positive integer is round if all its digits except the leftmost (most significant) are equal to zero. In particular, all numbers from 1 to 9 (inclusive) are round.

For example, the following numbers are round: 4000, 1, 9, 800, 90. The following numbers are not round: 110, 707, 222, 1001.

You are given a positive integer n (1 ≤ n ≤ 10^4). Represent the number n as a sum of round numbers using the minimum number of summands (addends). In other words, you need to represent the given number n as a sum of the least number of terms, each of which is a round number.

Input

The first line contains an integer t (1 ≤ t ≤ 10^4) — the number of test cases in the input. Then t test cases follow.

Each test case is a line containing an integer n (1 ≤ n ≤ 10^4).

Output

Print t answers to the test cases. Each answer must begin with an integer k — the minimum number of summands. Next, k terms must follow, each of which is a round number, and their sum is n. The terms can be printed in any order. If there are several answers, print any of them.

Example

Input


5
5009
7
9876
10000
10


Output


2
5000 9
1
7 
4
800 70 6 9000 
1
10000 
1
10 

Solution (in PYTHON3):

Solution:
# for _ in range(int(input())):
#     n=int(input());
#     print(*[list(range(n-n%2,4,-2))+[2,4]+list(range(1,n+1,2)),[-1]][n<4])
#     # print(*[list(range(n-n%2,4,-2))])
 
for _ in range(int(input())):
    n=int(input())
    counter=0
    output=[] 
    if(n<=10):
        output.append(n)
    else:
        while(n>0): 
            if n%10!=0:  
                output.append(pow(10,counter)*int(n%10))
            counter=counter+1
            n=int(n/10)
    print(len(output))
    print(*output)