Problem: A positive (strictly greater than zero) integer is called round if it is of the form d00...0. In other words, a positive integer is round if all its digits except the leftmost (most significant) are equal to zero. In particular, all numbers from 1 to 9 (inclusive) are round.

For example, the following numbers are round: 4000, 1, 9, 800, 90. The following numbers are not round: 110, 707, 222, 1001.

You are given a positive integer n (1 ≤ n ≤ 10^4). Represent the number n as a sum of round numbers using the minimum number of summands (addends). In other words, you need to represent the given number n as a sum of the least number of terms, each of which is a round number.

Input

The first line contains an integer t (1 ≤ t ≤ 10^4) — the number of test cases in the input. Then t test cases follow.

Each test case is a line containing an integer n (1 ≤ n ≤ 10^4).

Output

Print t answers to the test cases. Each answer must begin with an integer k — the minimum number of summands. Next, k terms must follow, each of which is a round number, and their sum is n. The terms can be printed in any order. If there are several answers, print any of them.

Example

Input


5
5009
7
9876
10000
10


Output


2
5000 9
1
7 
4
800 70 6 9000 
1
10000 
1
10 

Solution (in PYTHON3):

Solution:
a=list(map(int,input().split()))
t=a[0]
while(t>0):
    l=[]
    b=list(map(int,input().split()))
    n=b[0]
    while(n>0):
        l.append(n%10)
        n=n//10
    for i in range (len(l)):
        for j in range (i+1,len(l)):
            l[j]*=10
    count=0
    for i in range (len(l)):
        if (l[i]>0):
            count+=1
    print(count)
    for m in range (len(l)-1,-1,-1):
        if(l[m]>0):
            if(m>0):
                print(l[m],end=' ')
            else:
                print(l[m])
        elif (m==0):
            print()
    t-=1