Problem: Daniel has a string s, consisting of lowercase English letters and period signs (characters '.'). Let's define the operation of replacement as the following sequence of steps: find a substring ".." (two consecutive periods) in string s, of all occurrences of the substring let's choose the first one, and replace this substring with string ".". In other words, during the replacement operation, the first two consecutive periods are replaced by one. If string s contains no two consecutive periods, then nothing happens.

Let's define f(s) as the minimum number of operations of replacement to perform, so that the string does not have any two consecutive periods left.

You need to process m queries, the i-th results in that the character at position xi (1 ≤ xi ≤ n) of string s is assigned value ci. After each operation you have to calculate and output the value of f(s).

Help Daniel to process all queries.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 300 000) the length of the string and the number of queries.

The second line contains string s, consisting of n lowercase English letters and period signs.

The following m lines contain the descriptions of queries. The i-th line contains integer xi and ci (1 ≤ xi ≤ n, ci — a lowercas English letter or a period sign), describing the query of assigning symbol ci to position xi.

Output

Print m numbers, one per line, the i-th of these numbers must be equal to the value of f(s) after performing the i-th assignment.

Examples

Input

10 3
.b..bz....
1 h
3 c
9 f


Output

4
3
1


Input

4 4
.cc.
2 .
3 .
2 a
1 a


Output

1
3
1
1

Note

Note to the first sample test (replaced periods are enclosed in square brackets).

The original string is ".b..bz....".

  * after the first query f(hb..bz....) = 4 ("hb[..]bz...."  →  "hb.bz[..].."  →  "hb.bz[..]."  →  "hb.bz[..]"  →  "hb.bz.")
  * after the second query f(hbс.bz....) = 3 ("hbс.bz[..].."  →  "hbс.bz[..]."  →  "hbс.bz[..]"  →  "hbс.bz.")
  * after the third query f(hbс.bz..f.) = 1 ("hbс.bz[..]f."  →  "hbс.bz.f.")



Note to the second sample test.

The original string is ".cc.".

  * after the first query: f(..c.) = 1 ("[..]c."  →  ".c.")
  * after the second query: f(....) = 3 ("[..].."  →  "[..]."  →  "[..]"  →  ".")
  * after the third query: f(.a..) = 1 (".a[..]"  →  ".a.")
  * after the fourth query: f(aa..) = 1 ("aa[..]"  →  "aa.")

Solution (in JAVA):

Solution:


import java.awt.List;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.OutputStreamWriter;
import java.io.PrintWriter;
import java.math.BigInteger;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Collections;
import java.util.Comparator;
import java.util.HashMap;
import java.util.HashSet;
import java.util.Iterator;
import java.util.LinkedList;
import java.util.Queue;
import java.util.Scanner;
import java.util.Set;
import java.util.Stack;
import java.util.*;


 
 
public class ck {

	private static InputStream stream;
	private static PrintWriter pw;
	
	
	
//	static int a;
//	static int b;
//	static int f = 0;
//	static int n;
//	static int m;
//	static char[][] arr;
	

	
//	static int[][] dir = {{-1,0},{0,1},{1,0},{0,-1}};

//	static int visited[][];
	
	
//	static ArrayList<Integer> ans;

//	static int arr[][];
//	static int arr[];
//	static char[][] arr;
//	static int[][] visited;
//  static int c;
//	static int d[];
//	static int arr[][];
//	static ArrayList<Integer> arr[];
	static ArrayList<Integer> comp[];
	
	//static int c;
	static int parent[];
	static int nodes;
	static long ans = 0;
	static long a;
	static long d;
	static int n;
	
	public static void main(String[] args) throws NumberFormatException, IOException{
		//InputReader(System.in);
		//pw = new PrintWriter(System.out);
		
		Scanner in = new Scanner(System.in);
		
		PrintWriter out=new PrintWriter(new OutputStreamWriter(System.out));
	
		int n=in.nextInt();
		int m=in.nextInt();
		String ss=in.next();
		int ans=0;
		int k=0;
		char arr[] = ss.toCharArray();
		
		for(int i=0;i<n;i++)
		{
			if(arr[i]!='.')
			{
				if(k>0) 
					ans += k-1;
					k=0;
			}
			else 
				k++;
		}
		
		if(k>0) 
			ans += k-1;
		
		
		for(int i=0;i<m;i++)
		{
			int x = in.nextInt()-1; 
			char c = in.next().charAt(0);
			
			if( x>0 && arr[x-1] == '.')
			{
				if(arr[x]== '.' && c != '.')
					ans--;
				else if(arr[x] != '.' && c == '.')
					ans++;
			}
			if( x < n-1 && arr[x+1] == '.')
			{
				if(arr[x] == '.' && c != '.')
					ans--;
				else if(arr[x] != '.' && c=='.')
					ans++;
			}
			arr[x]=c;
			out.println(ans);
		}
		out.flush();
		
		}
	
	
	public static long dfs(int i){
		
		if(i == 1){
			return a;
		}
		
		if(i == 2){
			return a + (long)Math.min(a, d);
		}
		
		if(i%2 == 0){
			
			if((i/2)*a < d){
				return dfs(i/2) + (long)(i/2)*a;
			}else{
				return dfs(i/2) + d;
			}
		}else{
			return (long)Math.min(dfs(i-1),dfs(i+1)) + a;
		}
		
		
	}
public static void ddfs(int n,int m,int i,int j,char arr[][],int visited[][],int dir[][],int store[][],int ans){
		
		if(visited[i][j] == 1){
			return;
		}
		
		
		//System.out.println(i + " " + j + " " + arr[i][j]);
		if(arr[i][j] == '*'){
			ans++;
			return;
		}
		
		visited[i][j] = 1;
		store[i][j] = ans;
		int x = i;
		int y = j;
		
		for(int p = 0;p<4;p++){
			
			i = x + dir[p][0];
			j = y + dir[p][1];
			
			if(i < 0 || i >= n|| j < 0 || j >=m){
				
			}else{
				dfs(n,m,i,j,arr,visited,dir);
			}
			
		}
		
		
	}
	
	
	public static void dfs(int n,int m,int i,int j,char arr[][],int visited[][],int dir[][]){
		
		if(visited[i][j] == 1){
			return;
		}
		
		
		//System.out.println(i + " " + j + " " + arr[i][j]);
		if(arr[i][j] == '*'){
			ans++;
			return;
		}
		
		visited[i][j] = 1;
		int x = i;
		int y = j;
		
		for(int p = 0;p<4;p++){
			
			i = x + dir[p][0];
			j = y + dir[p][1];
			
			if(i < 0 || i >= n|| j < 0 || j >=m){
				
			}else{
				dfs(n,m,i,j,arr,visited,dir);
			}
			
		}
		
		
	}
	
	

//	
//	public static void bfs(int i){
//		
//		Queue<Integer> q=new LinkedList<Integer>();
//    	q.add(i);
//    	
//    	visited[i] = 1;
//    	c++;
//    	nodes++;
//    	while(!q.isEmpty()){
//    		int top=q.poll();
//    		
//    		Iterator<Integer> it= arr[top].listIterator();
//    		while(it.hasNext()){
//    			int next =it.next();
//    			
//    			if(visited[next] == 0){
//    				nodes++;
//    				visited[next] = 1;
//    				q.add(next);
//    			}
//    		
//    		}
//    	}
//		
//	}
	
	
	public static void union(int a,int b){
		a = find(a);
		b = find(b);
		
		parent[a] = b;
		return;
	}
	
	public static int find(int i){
		if(i == parent[i]){
			return i;
		}
		
		parent[i] = find(parent[i]);
		return parent[i];
	}
	
//	public static void dfs(int i){
//		
//		
//		if(visited[i] == 1){
//			return;
//		}
//		
//		visited[i] = 1;
//		con[c].add(i);
//		//System.out.print(i + " ");
//		for(int j = 0;j<arr[i].size();j++){
//			dfs(arr[i].get(j));
//		}
//		
//	}
//	
//	
//	public static void dfss(int i){
//		if(visited[i] == 1){
//			return;
//		}
//		
//		visited[i] = 1;
//		
//		for(int j = 0;j<arr[i].size();j++){
//			dfss(arr[i].get(j));
//		}
//	//	System.out.println(i);
//		stack.push(i);
//	}
//	
//	public static void reverse(){
//		ArrayList[] temp = new ArrayList[n];
//		
//		for(int i = 0;i<n;i++){
//			temp[i] = new ArrayList();
//		}
//		
//		for(int i = 0;i<n;i++){
//			for(int j = 0;j<arr[i].size();j++){
//				temp[arr[i].get(j)].add(i);
//			}
//		}
//		
//		arr = temp;
//		
//	}
//	
//	
	
	
	
	
	
	
	public static boolean isPrime(int n) {
		// Corner cases
		if (n <= 1)
			return false;
		if (n <= 3)
			return true;
 
		// This is checked so that we can skip 
		// middle five numbers in below loop
		if (n % 2 == 0 || n % 3 == 0)
			return false;
 
		for (int i = 5; i * i <= n; i = i + 6)
			if (n % i == 0 || n % (i + 2) == 0)
				return false;
 
		return true;
	}
	
	
	
	public static void Range(int[] numbers, int target) {
	    if (numbers == null)
	        return;

	    int low = 0, high = numbers.length - 1;
	    // get the start index of target number
	    int startIndex = -1;
	    while (low <= high) {
	        int mid = (high - low) / 2 + low;
	        if (numbers[mid] > target) {
	            high = mid - 1;
	        } else if (numbers[mid] == target) {
	            startIndex = mid;
	            high = mid - 1;
	        } else
	            low = mid + 1;
	    }

	    // get the end index of target number
	    int endIndex = -1;
	    low = 0;
	    high = numbers.length - 1;
	    while (low <= high) {
	        int mid = (high - low) / 2 + low;
	        if (numbers[mid] > target) {
	            high = mid - 1;
	        } else if (numbers[mid] == target) {
	            endIndex = mid;
	            low = mid + 1;
	        } else
	            low = mid + 1;
	    }

	    if (startIndex != -1 && endIndex != -1){
	        for(int i=0; i+startIndex<=endIndex;i++){
	            if(i>0)
	                System.out.print(',');
	            System.out.print(i+startIndex);
	        }
	    }
	}
	
	 // union code starts	
	
	 private static void initialize( int Arr[ ],int size[], int N)
	    {
	        for(int i = 0;i<N;i++)
	        {
	        	Arr[ i ] = i ;
	        	size[ i ] = 1;
	        }
	    }
	 
	 private static int root(int Arr[ ],int i)
	    {
	        while(Arr[ i ] != i)           //chase parent of current element until it reaches root
	        {
	            Arr[ i ] = Arr[ Arr[ i ] ] ; 
	            i = Arr[ i ];
	        }
	        return i;
	    }
	 
	 private static void union(int Arr[ ],int size[ ],int A,int B)
	    {
	        int root_A = root(Arr,A);
	        int root_B = root(Arr,B);
	     
	        if(root_A != root_B){
	        	 if(size[root_A] < size[root_B ])
	 	        {
	        		 Arr[ root_A ] = Arr[root_B];
	        		 size[root_B] += size[root_A];	 	
	 	        }
	 	        else
	 	        {   	
	 	        	Arr[ root_B ] = Arr[root_A];
	 	        	size[root_A] += size[root_B];	 	   
	 	        }	
	        }
	    }
	 
	 private static boolean find(int Arr[],int A,int B)
	    {
	        if( root(Arr,A)==root(Arr,B) )       //if A and B have the same root, it means that they are connected.
	        return true;
	        else
	        return false;
	    }
	 
	 
	 // union code ends
	
	
	 
//	 // Segment tree code begins
//	 
//	 
//	 static void build(int node,int start,int end)
//	 {
//	 if(start==end)
//	 tree[node]=a[start];
//	 else
//	 {
//	 int mid=(start+end)/2;
//	 build(2*node,start,mid);
//	 build(2*node+1,mid+1,end);
//	 if(tree[2*node]<tree[2*node+1])
//	 tree[node]=tree[2*node];
//	 else
//	 tree[node]=tree[2*node+1];
//	 }
//	 }
//	 
//	 
//	 static void update(int node,int start,int end,int idx,int val)
//	 {
//	 if(start==end)
//	 {
//	 a[idx]=val;
//	 tree[node]=val;
//	 }
//	 else
//	 {
//	 int mid=(start+end)/2;
//	 if(idx>=start&&idx<=mid)
//	 update(2*node,start,mid,idx,val);
//	 else
//	 update(2*node+1,mid+1,end,idx,val);
//	 if(tree[2*node]<tree[2*node+1])
//	 tree[node]=tree[2*node];
//	 else
//	 tree[node]=tree[2*node+1];
//	 }
//	 }
//	 
//	 static int query(int node,int start,int end,int l,int r)
//	 {
//	 if(l>end||start>r)
//	 return 100005;
//	 if(l<=start&&r>=end)
//	 return tree[node];
//	 int p1,p2;
//	 int mid=(start+end)/2;
//	 p1=query(2*node,start,mid,l,r);
//	 p2=query(2*node+1,mid+1,end,l,r);
//	 if(p1<p2)
//	 return p1;
//	 else
//	 return p2;
//	 }
//	 
//	 
//	 
//}

}

class Node{
	int a;
	int b;
}


class MyComp2 implements Comparator<Node>{
    
	@Override
	public int compare(Node o1, Node o2) {
		if(o1.a>o2.a){
			return 1;
		}else if(o1.a<o2.a){
			return -1;
		}else{
			if(o1.b>o2.b){
				return 1;
				
			}else{
				return -1;
			}
			
			
		}
		
		
	}
}


class Card implements Comparable<Card>
{
	int a,b;
	public Card(int w,int h)
	{
		this.a=w;
		this.b=h;
		
	}
	public int compareTo(Card that)
	{
		return this.a-that.a;
	}
}