Problem: A positive (strictly greater than zero) integer is called round if it is of the form d00...0. In other words, a positive integer is round if all its digits except the leftmost (most significant) are equal to zero. In particular, all numbers from 1 to 9 (inclusive) are round.

For example, the following numbers are round: 4000, 1, 9, 800, 90. The following numbers are not round: 110, 707, 222, 1001.

You are given a positive integer n (1 ≤ n ≤ 10^4). Represent the number n as a sum of round numbers using the minimum number of summands (addends). In other words, you need to represent the given number n as a sum of the least number of terms, each of which is a round number.

Input

The first line contains an integer t (1 ≤ t ≤ 10^4) — the number of test cases in the input. Then t test cases follow.

Each test case is a line containing an integer n (1 ≤ n ≤ 10^4).

Output

Print t answers to the test cases. Each answer must begin with an integer k — the minimum number of summands. Next, k terms must follow, each of which is a round number, and their sum is n. The terms can be printed in any order. If there are several answers, print any of them.

Example

Input


5
5009
7
9876
10000
10


Output


2
5000 9
1
7 
4
800 70 6 9000 
1
10000 
1
10 

Solution (in PYTHON3):

Solution:
#import sys
#sys.stdin = open("input10.txt")
T = int(input())
for t in range (T):
    a = input()
    k = 0
    esp = 0
    b = int(a[0])
    b = b*(10**(len(a)-1))
    output = list()
    output.append(b)
    for i in range (1,len(a)):
        b = int(a[i])
        if b != 0:
            esp = len(a)-(i+1)
            b = b*(10**esp)
            output.append(b)
    k = len(output)
    print(k)
    for o in range (k):
        if k-o != 1:
            print(output[o], end =" ")
        else:
            print(output[o])