Problem: A positive (strictly greater than zero) integer is called round if it is of the form d00...0. In other words, a positive integer is round if all its digits except the leftmost (most significant) are equal to zero. In particular, all numbers from 1 to 9 (inclusive) are round.

For example, the following numbers are round: 4000, 1, 9, 800, 90. The following numbers are not round: 110, 707, 222, 1001.

You are given a positive integer n (1 ≤ n ≤ 10^4). Represent the number n as a sum of round numbers using the minimum number of summands (addends). In other words, you need to represent the given number n as a sum of the least number of terms, each of which is a round number.

Input

The first line contains an integer t (1 ≤ t ≤ 10^4) — the number of test cases in the input. Then t test cases follow.

Each test case is a line containing an integer n (1 ≤ n ≤ 10^4).

Output

Print t answers to the test cases. Each answer must begin with an integer k — the minimum number of summands. Next, k terms must follow, each of which is a round number, and their sum is n. The terms can be printed in any order. If there are several answers, print any of them.

Example

Input


5
5009
7
9876
10000
10


Output


2
5000 9
1
7 
4
800 70 6 9000 
1
10000 
1
10 

Solution (in PYTHON3):

Solution:
t = int(input())

ans = list()

for i in range(0,t,1):
    num = int(input())
    k=0

    if (num >= 1 and num <= 9):
        print(1)
        print(num)
    else:
        while True:
            r = num%10
            j = pow(10,k)*int(r)
            #print("**",j,"**")
            if j != 0:
                ans.append(int(j))
            num /= 10
            k+=1
            if (num >= 1 and num < 10):
                j = pow(10,k)*int(num)
                #print("##",j,"##")
                ans.append(int(j))
                break
            
    if len(ans) == 0:
        continue
    else:
        print(len(ans))
        for item in ans:
            print(item,end=' ')

    ans.clear()
    print(end='\n')