Problem: Don't you tell me what you think that I can be

If you say that Arkady is a bit old-fashioned playing checkers, you won't be right. There is also a modern computer game Arkady and his friends are keen on. We won't discuss its rules, the only feature important to this problem is that each player has to pick a distinct hero in the beginning of the game.

There are 2 teams each having n players and 2n heroes to distribute between the teams. The teams take turns picking heroes: at first, the first team chooses a hero in its team, after that the second team chooses a hero and so on. Note that after a hero is chosen it becomes unavailable to both teams.

The friends estimate the power of the i-th of the heroes as p_i. Each team wants to maximize the total power of its heroes. However, there is one exception: there are m pairs of heroes that are especially strong against each other, so when any team chooses a hero from such a pair, the other team must choose the other one on its turn. Each hero is in at most one such pair.

This is an interactive problem. You are to write a program that will optimally choose the heroes for one team, while the jury's program will play for the other team. Note that the jury's program may behave inefficiently, in this case you have to take the opportunity and still maximize the total power of your team. Formally, if you ever have chance to reach the total power of q or greater regardless of jury's program choices, you must get q or greater to pass a test.

Input

The first line contains two integers n and m (1 ≤ n ≤ 10^3, 0 ≤ m ≤ n) — the number of players in one team and the number of special pairs of heroes.

The second line contains 2n integers p_1, p_2, …, p_{2n} (1 ≤ p_i ≤ 10^3) — the powers of the heroes.

Each of the next m lines contains two integer a and b (1 ≤ a, b ≤ 2n, a ≠ b) — a pair of heroes that are especially strong against each other. It is guaranteed that each hero appears at most once in this list.

The next line contains a single integer t (1 ≤ t ≤ 2) — the team you are to play for. If t = 1, the first turn is yours, otherwise you have the second turn.

Hacks

In order to hack, use the format described above with one additional line. In this line output 2n distinct integers from 1 to 2n — the priority order for the jury's team. The jury's team will on each turn select the first possible hero from this list. Here possible means that it is not yet taken and does not contradict the rules about special pair of heroes.

Interaction

When it is your turn, print a single integer x (1 ≤ x ≤ 2n) — the index of the hero chosen by you. Note that you can't choose a hero previously chosen by either you of the other player, and you must follow the rules about special pairs of heroes.

When it is the other team's turn, read a line containing a single integer x (1 ≤ x ≤ 2n) — the index of the hero chosen by the other team. It is guaranteed that this index is not chosen before and that the other team also follows the rules about special pairs of heroes.

After the last turn you should terminate without printing anything.

After printing your choice do not forget to output end of line and flush the output. Otherwise you will get Idleness limit exceeded. To do this, use:

  * fflush(stdout) or cout.flush() in C++;
  * System.out.flush() in Java;
  * flush(output) in Pascal;
  * stdout.flush() in Python;
  * see documentation for other languages.



Jury's answer -1 instead of a valid choice means that you made an invalid turn. Exit immediately after receiving -1 and you will see Wrong answer verdict. Otherwise you can get an arbitrary verdict because your solution will continue to read from a closed stream.

Examples

Input


3 1
1 2 3 4 5 6
2 6
1

2

4

1


Output






6

5

3


Input


3 1
1 2 3 4 5 6
1 5
2
6

1

3


Output







5

4

2

Note

In the first example the first turn is yours. In example, you choose 6, the other team is forced to reply with 2. You choose 5, the other team chooses 4. Finally, you choose 3 and the other team choose 1.

In the second example you have the second turn. The other team chooses 6, you choose 5, forcing the other team to choose 1. Now you choose 4, the other team chooses 3 and you choose 2.

Solution (in JAVA):

Solution:


import java.io.*;
import java.lang.reflect.Array;
import java.math.BigInteger;
import java.util.*;

public class B {

    String fileName = "";
    //////////////////////    SOLUTION   SOLUTION  SOLUTION    //////////////////////////////
    long INF = Long.MAX_VALUE / 1000;
    int MODULO = 1000*1000*1000 + 7;
    long MAX_VALUE = 1000l*1000*1000*100;
    int[][] steps = {{0, 1}, {1, 0}, {-1, 0}, {0, -1}};
    private final static Random rnd = new Random();
    double eps = 1e-1;
    class Edge{
        int to, num, dist;

        public Edge(int to, int num, int dist) {
            this.to = to;
            this.num = num;
            this.dist = dist;
        }
    }
    class Vertex implements Comparable<Vertex>{
        int from, count;

        public Vertex(int from, int count) {
            this.from = from;
            this.count = count;
        }

        @Override
        public int compareTo(Vertex o) {
            return Long.compare(this.count, o.count);
        }
    }
    class Hero implements Comparable<Hero>{
        int p, ind;

        public Hero(int p, int ind) {
            this.p = p;
            this.ind = ind;
        }

        @Override
        public int compareTo(Hero o) {
            return -Integer.compare(this.p, o.p);
        }
    }
    class Pair implements Comparable<Pair>{
        Hero min, max;

        public Pair(Hero min, Hero max) {
            this.min = min;
            this.max = max;
        }

        @Override
        public int compareTo(Pair o) {
            return -Integer.compare(this.max.p, o.max.p);
        }
    }
    void solve() throws IOException {
        int n = readInt();
        int m = readInt();
        boolean[] used = new boolean[n<<1];
        Hero[] heroes = new Hero[n<<1];
        PriorityQueue<Pair> pairs = new PriorityQueue<>();
        PriorityQueue<Hero> lonelyHeroes = new PriorityQueue<>();
        for (int i=0; i < n<<1; ++i){
            heroes[i] = new Hero(readInt(), i);
        }
        Hero[] pairHero = new Hero[n<<1];
        for (int i=0; i<m; ++i){
            Hero hero1 = heroes[readInt() - 1];
            Hero hero2 = heroes[readInt() - 1];
            if (hero1.p > hero2.p){
                Hero temp = hero1;
                hero1 = hero2;
                hero2 = temp;
            }
            pairHero[hero1.ind] = hero2;
            pairHero[hero2.ind] = hero1;
            pairs.add(new Pair(hero1, hero2));
        }
        PriorityQueue<Hero> heroesQueue  = new PriorityQueue<>();
        for (int i=0; i< n<<1; ++i) heroesQueue.add(heroes[i]);

        int pointer = 0;

        int ch = readInt() % 2;

        for (int i = 1; i<= n<<1; ++i){
            if (i%2==ch){
                Hero nextHero = new Hero(-1, -1);
                if (lonelyHeroes.size() > 0){
                    nextHero = lonelyHeroes.poll();
                }else if (pairs.size() > 0){
                    Pair curP = pairs.poll();
                    if (used[curP.max.ind]) {
                        i--;
                        continue;
                    }
                    nextHero = curP.max;
                    lonelyHeroes.add(curP.min);
                }else{
                    boolean flag = false;
                    while (heroesQueue.size() > 0 && !flag){
                        Hero curH = heroesQueue.poll();
                        if (!used[curH.ind]){
                            nextHero = curH;
                            flag = true;
                        }
                    }
                }
                if (nextHero.ind != -1)used[nextHero.ind] = true;
                out.println(nextHero.ind + 1);
                out.flush();
            }else{
                int cur = readInt();
                if (lonelyHeroes.size() > 0) lonelyHeroes.clear();
                else if (pairHero[cur - 1] != null){
                    lonelyHeroes.add(pairHero[cur-1]);
                }
                used[cur - 1] = true;
            }

        }
    }


    class SegmentTree{
        long[] t;
        int n;
        SegmentTree(long[] arr, int n){
            t = new long[n*4];
            build(arr, 1, 1, n);
        }
        void build(long[] arr, int v, int tl , int tr){
            if (tl == tr) {
                t[v] = arr[tl];
                return;
            }
            int tm = (tl + tr) / 2;
            build(arr, 2 * v, tl, tm);
            build(arr, 2 * v + 1, tm + 1, tr);
            t[v] = Math.max(t[2*v], t[2*v + 1]);
        }

        long get(int v, int tl , int tr, int l , int r){
            if (l > r) return -1;
            if (tl == l && tr == r) return t[v];
            int tm = (tl + tr) / 2;
            long val1 = get(2 * v, tl, tm, l, Math.min(tm, r));
            long val2 = get(2 * v + 1, tm + 1, tr, Math.max(tm + 1, l), r);
            return Math.max(val1, val2);
        }

    }
    void brute(){
        int n = 10;
        int[] arr = new int[n];
        int[] b = new int[n];
        for (int it=0; it < 100; ++it){
            for (int i=0; i< n; ++i) {
                arr[i] = rnd.nextInt(100);
                b[i] = arr[i];
            }
            Arrays.sort(b);
            for (int k=0; k<n; ++k){
                int ans = orderStatistic(arr, k, 0, n-1);
                if (ans != b[k]) {
                    out.println("HACK!!!");
                    out.println(n +" " + (k+1));
                    for (int i: arr) out.print(i +" ");
                    out.println();
                    out.println(b[k] + " " + ans);
                }
            }
        }
    }
    int orderStatistic(int[] arr, int k, int l , int r){
        int part = partition(arr, l , r);
        if (part == k) return arr[part];
        if (part > k) return orderStatistic(arr, k, l, part);
        return orderStatistic(arr, k, part, r);
    }

    int partition(int[] arr, int l, int r){
        int i = l;
        int j = r;
        if (i == j) return i;
        int pivot = arr[l + rnd.nextInt(r - l)];
        while (true){
            while (arr[i] < pivot) i++;
            while (arr[j] > pivot) j--;
            if (j <= i) return j;
            int temp = arr[j];
            arr[j] = arr[i];
            arr[i] = temp;
            j--; i++;
        }
    }
    long binPow(long a, long b, long m) {
        if (b == 0) {
            return 1;
        }
        if (b % 2 == 1) {
            return ((a % m) * (binPow(a, b - 1, m) % m)) % m;
        } else {
            long c = binPow(a, b / 2, m);
            return (c * c) % m;
        }

    }

    class Fenwik {
        int[] t;
        int n;
        Fenwik(int n){
            t = new int[n];
            this.n = n;
        }

        void inc(int r, int delta){
            for (; r < n; r = r | (r + 1)) t[r] += delta;
        }
        int getSum(int r){
            int res = 0;
            for (; r >=0; r = (r & (r + 1) ) - 1) res += t[r];
            return res;
        }
    }
    boolean isPrime(int n){
        for (int i=2; i*i<=n; ++i){
            if (n%i==0) return false;
        }
        return true;
    }



    class Number implements Comparable<Number>{
        int x, cost;
        Number(int x, int cost){
            this.x = x;
            this.cost = cost;
        }

        @Override
        public int compareTo(Number o) {
            return Integer.compare(this.cost, o.cost);
        }
    }



    ///////////////////////////////////////////////////////////////////////////////////////////


    class SparseTable{
        int[][] rmq;
        int[] logTable;
        int n;
        SparseTable(int[] a){
            n = a.length;
            logTable = new int[n+1];
            for(int i = 2; i <= n; ++i){
                logTable[i] = logTable[i >> 1] + 1;
            }
            rmq = new int[logTable[n] + 1][n];
            for(int i=0; i<n; ++i){
                rmq[0][i] = a[i];
            }

            for(int k=1; (1 << k) < n; ++k){
                for(int i=0; i + (1 << k) <= n; ++i){
                    int max1 = rmq[k - 1][i];
                    int max2 = rmq[k-1][i + (1 << (k-1))];
                    rmq[k][i] = Math.max(max1, max2);
                }
            }
        }

        int max(int l, int r){
            int k = logTable[r - l];
            int max1 = rmq[k][l];
            int max2 = rmq[k][r - (1 << k) + 1];
            return Math.max(max1, max2);
        }
    }
    long checkBit(long mask, int bit){
        return (mask >> bit) & 1;
    }

    static int checkBit(int mask, int bit) {
        return (mask >> bit) & 1;
    }
    boolean isLower(char c){
        return c >= 'a' && c <= 'z';
    }

    ////////////////////////////////////////////////////////////



    int gcd(int a, int b){
        return b == 0 ? a : gcd(b, a%b);
    }
    long gcd(long a, long b){
        return b == 0 ? a : gcd(b, a%b);
    }
    double binPow(double a, int pow){
        if (pow == 0) return 1;
        if (pow % 2 == 1) {
            return a * binPow(a, pow - 1);
        } else {
            double c = binPow(a, pow / 2);
            return c * c;
        }
    }

    int minInt(int... values) {
        int min = Integer.MAX_VALUE;
        for (int value : values) min = Math.min(min, value);
        return min;
    }

    int maxInt(int... values) {
        int max = Integer.MIN_VALUE;
        for (int value : values) max = Math.max(max, value);
        return max;
    }
    public static void main(String[] args) throws NumberFormatException, IOException {
        // TODO Auto-generated method stub
        new B().run();
    }

    void run() throws NumberFormatException, IOException {
        solve();
        out.close();
    };

    BufferedReader in;
    PrintWriter out;

    StringTokenizer tok;
    String delim = " ";

    B() throws FileNotFoundException {
        try {
            in = new BufferedReader(new FileReader("input.txt"));
            out = new PrintWriter("output.txt");
        } catch (Exception e) {
            if (fileName.isEmpty()) {
                in = new BufferedReader(new InputStreamReader(System.in));
                out = new PrintWriter(System.out);
            } else {
                in = new BufferedReader(new FileReader(fileName + ".in"));
                out = new PrintWriter(fileName + ".out");
            }

        }
        tok = new StringTokenizer("");
    }

    String readLine() throws IOException {
        return in.readLine();
    }

    String readString() throws IOException {
        while (!tok.hasMoreTokens()) {
            String nextLine = readLine();
            if (null == nextLine) {
                return null;
            }

            tok = new StringTokenizer(nextLine);
        }
        return tok.nextToken();
    }

    int readInt() throws NumberFormatException, IOException {
        return Integer.parseInt(readString());
    }
    byte readByte() throws NumberFormatException, IOException {
        return Byte.parseByte(readString());
    }
    int[] readIntArray (int n) throws NumberFormatException, IOException {
        int[] a = new int[n];
        for(int i=0; i<n; ++i){
            a[i] = readInt();
        }
        return a;
    }
    int[] readIntArrayWithDecrease (int n) throws NumberFormatException, IOException {
        int[] a = new int[n];
        for(int i=0; i<n; ++i){
            a[i] = readInt() - 1;
        }
        return a;
    }
    Integer[] readIntegerArray (int n) throws NumberFormatException, IOException {
        Integer[] a = new Integer[n];
        for(int i=0; i<n; ++i){
            a[i] = readInt();
        }
        return a;
    }

    long readLong() throws NumberFormatException, IOException {
        return Long.parseLong(readString());
    }

    double readDouble() throws NumberFormatException, IOException {
        return Double.parseDouble(readString());
    }
}