Problem: Try guessing the statement from this picture: 

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You are given a non-negative integer d. You have to find two non-negative real numbers a and b such that a + b = d and a ⋅ b = d.

Input

The first line contains t (1 ≤ t ≤ 10^3) — the number of test cases.

Each test case contains one integer d (0 ≤ d ≤ 10^3).

Output

For each test print one line.

If there is an answer for the i-th test, print "Y", and then the numbers a and b.

If there is no answer for the i-th test, print "N".

Your answer will be considered correct if |(a + b) - a ⋅ b| ≤ 10^{-6} and |(a + b) - d| ≤ 10^{-6}.

Example

Input


7
69
0
1
4
5
999
1000


Output


Y 67.985071301 1.014928699
Y 0.000000000 0.000000000
N
Y 2.000000000 2.000000000
Y 3.618033989 1.381966011
Y 997.998996990 1.001003010
Y 998.998997995 1.001002005

Solution (in JAVA):

Solution:
import java.util.Scanner;
public class Ab {
    public static void main(String[] args){
        Scanner in = new Scanner(System.in);
        int t = in.nextInt();
        int[] arr = new int[t];

        for (int i = 0; i < t; i++) {
            arr[i] = in.nextInt();
        }
        double a, b;
        for (int i = 0 ; i < arr.length; i++){
            int e = arr[i];
            a = (e + Math.sqrt(e*e - 4 * e)) / 2;
            
            b = e-a;
            
            if (Math.abs((a+b)- a*b) <= 0.00000001 && Math.abs((a+b)- e) <= 0.00000001){
                
                System.out.printf("Y %.10f %.10f%n",a,b);
            }
            
            else System.out.println("N");
        }
        
       
    }
}