Problem: A positive (strictly greater than zero) integer is called round if it is of the form d00...0. In other words, a positive integer is round if all its digits except the leftmost (most significant) are equal to zero. In particular, all numbers from 1 to 9 (inclusive) are round.

For example, the following numbers are round: 4000, 1, 9, 800, 90. The following numbers are not round: 110, 707, 222, 1001.

You are given a positive integer n (1 ≤ n ≤ 10^4). Represent the number n as a sum of round numbers using the minimum number of summands (addends). In other words, you need to represent the given number n as a sum of the least number of terms, each of which is a round number.

Input

The first line contains an integer t (1 ≤ t ≤ 10^4) — the number of test cases in the input. Then t test cases follow.

Each test case is a line containing an integer n (1 ≤ n ≤ 10^4).

Output

Print t answers to the test cases. Each answer must begin with an integer k — the minimum number of summands. Next, k terms must follow, each of which is a round number, and their sum is n. The terms can be printed in any order. If there are several answers, print any of them.

Example

Input


5
5009
7
9876
10000
10


Output


2
5000 9
1
7 
4
800 70 6 9000 
1
10000 
1
10 

Solution (in PYTHON3):

Solution:
import math
t=int(input())
i=1 
while(i<=t):
    n=int(input())
    l=len(str(n))
    s=str(n)
    lst=[]
    c=s.count('0')
    if(l==1 and n!=0):
        print(1)
        print(n)
    elif(s[0]!=0 and c==(l-1)):
        print(1)
        print(n)
    else:
        for j in range(0,l):
            m=n%10
            if(m!=0):
                a1=int(m*math.pow(10,j))
                lst+=[a1]
            n=n//10
        print(len(lst))
        print(*lst)
    i+=1