Problem: Vitya loves programming and problem solving, but sometimes, to distract himself a little, he plays computer games. Once he found a new interesting game about tanks, and he liked it so much that he went through almost all levels in one day. Remained only the last level, which was too tricky. Then Vitya remembered that he is a programmer, and wrote a program that helped him to pass this difficult level. Try do the same.

The game is organized as follows. There is a long road, two cells wide and n cells long. Some cells have obstacles. You control a tank that occupies one cell. Initially, the tank is located before the start of the road, in a cell with coordinates (0, 1). Your task is to move the tank to the end of the road, to the cell (n + 1, 1) or (n + 1, 2).

<image>

Every second the tank moves one cell to the right: the coordinate x is increased by one. When you press the up or down arrow keys, the tank instantly changes the lane, that is, the y coordinate. When you press the spacebar, the tank shoots, and the nearest obstacle along the lane in which the tank rides is instantly destroyed. In order to load a gun, the tank needs t seconds. Initially, the gun is not loaded, that means, the first shot can be made only after t seconds after the tank starts to move.

If at some point the tank is in the same cell with an obstacle not yet destroyed, it burns out. If you press the arrow exactly at the moment when the tank moves forward, the tank will first move forward, and then change the lane, so it will not be possible to move diagonally.

Your task is to find out whether it is possible to pass the level, and if possible, to find the order of actions the player need to make.

Input

The first line contains four integers n, m1, m2 and t, the length of the field, the number of obstacles in the first lane, the number of obstacles in the second lane and the number of tank steps before reloading, respectively (1 ≤ n ≤ 109; 0 ≤ m1, m2 ≤ n; 0 ≤ m1 + m2 ≤ 106; 1 ≤ t ≤ n).

The next two lines contain a description of the obstacles. The first of these lines contains m1 numbers xi — the obstacle coordinates in the first lane (1 ≤ xi ≤ n; xi < xi + 1). The y coordinate for all these obstacles will be 1.

The second line contains m2 numbers describing the obstacles of the second lane in the same format. The y coordinate of all these obstacles will be 2.

Output

In the first line print «Yes», if it is possible to pass the level, or «No», otherwise.

If it is possible, then in the second line print the number of times the tank moves from one lane to another, and in the next line print the coordinates of the transitions, one number per transition: the coordinate x (0 ≤ x ≤ n + 1). All transition coordinates coordinates must be distinct and should be output in strictly increasing order.The number of transitions should not exceed 2·106. If the tank can pass the level, then it can do it using no more than 2·106 transitions.

In the fourth line print the number of shots that the tank makes during the movement, in the following lines print two numbers, x and y coordinates of the point (1 ≤ x ≤ n, 1 ≤ y ≤ 2), from which the tank fired a shot, the number of shots must not exceed m1 + m2. Shots must be output in the order in which they are fired.

If there are several solutions, output any one.

Examples

Input

6 2 3 2
2 6
3 5 6


Output

Yes
2
0 3 
2
2 2
4 1


Input

1 1 1 1
1
1


Output

No


Input

9 5 2 5
1 2 7 8 9
4 6


Output

Yes
4
0 3 5 10 
1
5 2

Note

Picture for the first sample test. 

<image>

Solution (in CPP):

Solution:
#pragma comment(linker, "/stack:200000000")
#pragma GCC optimize("Ofast")
#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native")
#pragma GCC optimize("unroll-loops")

#define _CRT_SECURE_NO_WARNINGS
# include <iostream>
# include <cmath>
# include <algorithm>
# include <stdio.h>
# include <cstdint>
# include <cstring>
# include <string>
# include <cstdlib>
# include <vector>
# include <bitset>
# include <map>
# include <queue>
# include <ctime>
# include <stack>
# include <set>
# include <list>
# include <random>
# include <deque>
# include <functional>
# include <iomanip>
# include <sstream>
# include <fstream>
# include <complex>
# include <numeric>
# include <immintrin.h>
# include <cassert>
# include <array>
# include <tuple>

#ifdef LOCAL
# include <opencv2/core/core.hpp>
# include <opencv2/highgui/highgui.hpp>
# include <opencv2/imgproc/imgproc.hpp>
#endif

using namespace std;

// Let's define unordered map
# ifdef __GNUC__
# if __cplusplus > 199711L
# include <unordered_set>
# include <unordered_map>
# else
# include <tr1/unordered_map>
# include <tr1/unordered_set>
using namespace tr1;
# endif
# else
# include <unordered_map>
# include <unordered_set>
# endif

#define VA_NUM_ARGS(...) VA_NUM_ARGS_IMPL_((0,__VA_ARGS__, 6,5,4,3,2,1))
#define VA_NUM_ARGS_IMPL_(tuple) VA_NUM_ARGS_IMPL tuple
#define VA_NUM_ARGS_IMPL(_0,_1,_2,_3,_4,_5,_6,N,...) N
#define macro_dispatcher(macro, ...) macro_dispatcher_(macro, VA_NUM_ARGS(__VA_ARGS__))
#define macro_dispatcher_(macro, nargs) macro_dispatcher__(macro, nargs)
#define macro_dispatcher__(macro, nargs) macro_dispatcher___(macro, nargs)
#define macro_dispatcher___(macro, nargs) macro ## nargs
#define DBN1(a)           cerr<<#a<<"="<<(a)<<"\n"
#define DBN2(a,b)         cerr<<#a<<"="<<(a)<<", "<<#b<<"="<<(b)<<"\n"
#define DBN3(a,b,c)       cerr<<#a<<"="<<(a)<<", "<<#b<<"="<<(b)<<", "<<#c<<"="<<(c)<<"\n"
#define DBN4(a,b,c,d)     cerr<<#a<<"="<<(a)<<", "<<#b<<"="<<(b)<<", "<<#c<<"="<<(c)<<", "<<#d<<"="<<(d)<<"\n"
#define DBN5(a,b,c,d,e)   cerr<<#a<<"="<<(a)<<", "<<#b<<"="<<(b)<<", "<<#c<<"="<<(c)<<", "<<#d<<"="<<(d)<<", "<<#e<<"="<<(e)<<"\n"
#define DBN6(a,b,c,d,e,f) cerr<<#a<<"="<<(a)<<", "<<#b<<"="<<(b)<<", "<<#c<<"="<<(c)<<", "<<#d<<"="<<(d)<<", "<<#e<<"="<<(e)<<", "<<#f<<"="<<(f)<<"\n"
#define DBN(...) macro_dispatcher(DBN, __VA_ARGS__)(__VA_ARGS__)
#define DA(a,n) cerr<<#a<<"=["; printarray(a,n); cerr<<"]\n"
#define DAR(a,n,s) cerr<<#a<<"["<<s<<"-"<<n-1<<"]=["; printarray(a,n,s); cerr<<"]\n"

#ifdef _MSC_VER
#define PREFETCH(ptr, rw, level) ((void)0)
#else
#define PREFETCH(ptr, rw, level) __builtin_prefetch(ptr, rw, level)
#endif

#ifdef LOCAL
#define CURTIME() cerr << clock() * 1.0 / CLOCKS_PER_SEC << endl
#else
#define CURTIME()
#endif

#define mp make_pair
typedef long long ll;
typedef unsigned int uint;
typedef unsigned long long ull;
typedef pair<int, int> pii;
typedef pair<long long, long long> pll;
typedef vector<int> vi;
typedef vector<long long> vll;
typedef int itn;

template<class T1, class T2, class T3>
struct triple{ T1 a; T2 b; T3 c; triple() : a(T1()), b(T2()), c(T3()) {}; triple(T1 _a, T2 _b, T3 _c) :a(_a), b(_b), c(_c){} };
template<class T1, class T2, class T3>
bool operator<(const triple<T1,T2,T3>&t1,const triple<T1,T2,T3>&t2){if(t1.a!=t2.a)return t1.a<t2.a;else if(t1.b!=t2.b)return t1.b<t2.b;else return t1.c<t2.c;}
template<class T1, class T2, class T3>
bool operator>(const triple<T1,T2,T3>&t1,const triple<T1,T2,T3>&t2){if(t1.a!=t2.a)return t1.a>t2.a;else if(t1.b!=t2.b)return t1.b>t2.b;else return t1.c>t2.c;}
#define tri triple<int,int,int>
#define trll triple<ll,ll,ll>

#define FI(n) for(int i=0;i<(n);++i)
#define FJ(n) for(int j=0;j<(n);++j)
#define FK(n) for(int k=0;k<(n);++k)
#define FL(n) for(int l=0;l<(n);++l)
#define FQ(n) for(int q=0;q<(n);++q)
#define FOR(i,a,b) for(int i = (a), __e = (int) (b); i < __e; ++i)
#define all(a) std::begin(a), std::end(a)
#define reunique(v) v.resize(std::unique(v.begin(), v.end()) - v.begin())

#define sqr(x) ((x) * (x))
#define sqrt(x) sqrt(1.0 * (x))
#define pow(x, n) pow(1.0 * (x), n)

#define COMPARE(obj) [&](const std::decay_t<decltype(obj)>& a, const std::decay_t<decltype(obj)>& b)
#define COMPARE_BY(obj, field) [&](const std::decay_t<decltype(obj)>& a, const std::decay_t<decltype(obj)>& b) { return a.field < b.field; }

#define checkbit(n, b) (((n) >> (b)) & 1)
#define setbit(n, b) ((n) | (static_cast<std::decay<decltype(n)>::type>(1) << (b)))
#define removebit(n, b) ((n) & ~(static_cast<std::decay<decltype(n)>::type>(1) << (b)))
#define flipbit(n, b) ((n) ^ (static_cast<std::decay<decltype(n)>::type>(1) << (b)))
inline int countBits(uint v){v=v-((v>>1)&0x55555555);v=(v&0x33333333)+((v>>2)&0x33333333);return((v+(v>>4)&0xF0F0F0F)*0x1010101)>>24;}
inline int countBits(ull v){uint t=v>>32;uint p=(v & ((1ULL << 32) - 1)); return countBits(t) + countBits(p); }
inline int countBits(ll v){return countBits((ull)v); }
inline int countBits(int v){return countBits((uint)v); }
unsigned int reverseBits(uint x){ x = (((x & 0xaaaaaaaa) >> 1) | ((x & 0x55555555) << 1)); x = (((x & 0xcccccccc) >> 2) | ((x & 0x33333333) << 2)); x = (((x & 0xf0f0f0f0) >> 4) | ((x & 0x0f0f0f0f) << 4)); x = (((x & 0xff00ff00) >> 8) | ((x & 0x00ff00ff) << 8)); return((x >> 16) | (x << 16)); }
template<class T> inline int sign(T x){ return x > 0 ? 1 : x < 0 ? -1 : 0; }
inline bool isPowerOfTwo(int x){ return (x != 0 && (x&(x - 1)) == 0); }
constexpr ll power(ll x, int p) { return p == 0 ? 1 : (x * power(x, p - 1)); }
//template<class T1, class T2, class T3> T1 inline clamp(T1 x, const T2& a, const T3& b) { if (x < a) return a; else if (x > b) return b; else return x; }
unsigned long long rdtsc() { unsigned long long ret = 0;
#ifdef __clang__
    return __builtin_readcyclecounter();
#endif
#ifndef _MSC_VER
    asm volatile("rdtsc" : "=A" (ret) : :);
#endif
    return ret; }
// Fast IO ********************************************************************************************************
const int __BS = 4096;
static char __bur[__BS + 16], *__er = __bur + __BS, *__ir = __er;
template<class T = int> T readInt() {
    auto c = [&]() { if (__ir == __er) std::fill(__bur, __bur + __BS, 0), cin.read(__bur, __BS), __ir = __bur; };
    c(); while (*__ir && (*__ir < '0' || *__ir > '9') && *__ir != '-') ++__ir; c();
    bool m = false; if (*__ir == '-') ++__ir, c(), m = true;
    T r = 0; while (*__ir >= '0' && *__ir <= '9') r = r * 10 + *__ir - '0', ++__ir, c();
    ++__ir; return m ? -r : r;
}
static char __buw[__BS + 20], *__iw = __buw, *__ew = __buw + __BS;
template<class T>
void writeInt(T x, char endc = '\n') {
    if (x < 0) *__iw++ = '-', x = -x; if (x == 0) *__iw++ = '0';
    char* s = __iw;
    while (x) { T t = x / 10; char c = x - 10 * t + '0'; *__iw++ = c; x = t; }
    char* f = __iw - 1; while (s < f) swap(*s, *f), ++s, --f;
    if (__iw > __ew) cout.write(__buw, __iw - __buw), __iw = __buw;
    *__iw++ = endc;
}
template<class T>
void writeStr(const T& str) {
    int i = 0; while (str[i]) { *__iw++ = str[i++]; if (__iw > __ew) cout.write(__buw, __iw - __buw), __iw = __buw; }
}
struct __FL__ { ~__FL__() { if (__iw != __buw) cout.write(__buw, __iw - __buw); } };
static __FL__ __flushVar__;

//STL output *****************************************************************************************************
#define TT1 template<class T>
#define TT1T2 template<class T1, class T2>
#define TT1T2T3 template<class T1, class T2, class T3>
TT1T2 ostream& operator << (ostream& os, const pair<T1, T2>& p);
TT1 ostream& operator << (ostream& os, const vector<T>& v);
TT1T2 ostream& operator << (ostream& os, const set<T1, T2>&v);
TT1T2 ostream& operator << (ostream& os, const multiset<T1, T2>&v);
TT1T2 ostream& operator << (ostream& os, priority_queue<T1, T2> v);
TT1T2T3 ostream& operator << (ostream& os, const map<T1, T2, T3>& v);
TT1T2T3 ostream& operator << (ostream& os, const multimap<T1, T2, T3>& v);
TT1T2T3 ostream& operator << (ostream& os, const triple<T1, T2, T3>& t);
template<class T, size_t N> ostream& operator << (ostream& os, const array<T, N>& v);
TT1T2 ostream& operator << (ostream& os, const pair<T1, T2>& p){ return os <<"("<<p.first<<", "<< p.second<<")"; }
TT1 ostream& operator << (ostream& os, const vector<T>& v){       bool f=1;os<<"[";for(auto& i : v) { if (!f)os << ", ";os<<i;f=0;}return os << "]"; }
template<class T, size_t N> ostream& operator << (ostream& os, const array<T, N>& v) {     bool f=1;os<<"[";for(auto& i : v) { if (!f)os << ", ";os<<i;f=0;}return os << "]"; }
TT1T2 ostream& operator << (ostream& os, const set<T1, T2>&v){    bool f=1;os<<"[";for(auto& i : v) { if (!f)os << ", ";os<<i;f=0;}return os << "]"; }
TT1T2 ostream& operator << (ostream& os, const multiset<T1,T2>&v){bool f=1;os<<"[";for(auto& i : v) { if (!f)os << ", ";os<<i;f=0;}return os << "]"; }
TT1T2T3 ostream& operator << (ostream& os, const map<T1,T2,T3>& v){ bool f = 1; os << "["; for (auto& ii : v) { if (!f)os << ", "; os << "(" << ii.first << " -> " << ii.second << ") "; f = 0; }return os << "]"; }
TT1T2 ostream& operator << (ostream& os, const multimap<T1, T2>& v){ bool f = 1; os << "["; for (auto& ii : v) { if (!f)os << ", "; os << "(" << ii.first << " -> " << ii.second << ") "; f = 0; }return os << "]"; }
TT1T2 ostream& operator << (ostream& os, priority_queue<T1, T2> v) { bool f = 1; os << "["; while (!v.empty()) { auto x = v.top(); v.pop(); if (!f) os << ", "; f = 0; os << x; } return os << "]"; }
TT1T2T3 ostream& operator << (ostream& os, const triple<T1, T2, T3>& t){ return os << "(" << t.a << ", " << t.b << ", " << t.c << ")"; }
TT1T2 void printarray(const T1& a, T2 sz, T2 beg = 0){ for (T2 i = beg; i<sz; i++) cout << a[i] << " "; cout << endl; }

//STL input *****************************************************************************************************
TT1T2T3 inline istream& operator >> (istream& os, triple<T1, T2, T3>& t);
TT1T2 inline istream& operator >> (istream& os, pair<T1, T2>& p) { return os >> p.first >> p.second; }
TT1 inline istream& operator >> (istream& os, vector<T>& v) {
    if (v.size()) for (T& t : v) os >> t; else {
        string s; T obj; while (s.empty()) {getline(os, s); if (!os) return os;}
        stringstream ss(s); while (ss >> obj) v.push_back(obj);
    }
    return os;
}
TT1T2T3 inline istream& operator >> (istream& os, triple<T1, T2, T3>& t) { return os >> t.a >> t.b >> t.c; }

//Pair magic *****************************************************************************************************
#define PT1T2 pair<T1, T2>
TT1T2 inline PT1T2 operator+(const PT1T2 &p1 , const PT1T2 &p2) { return PT1T2(p1.first + p2.first, p1.second + p2.second); }
TT1T2 inline PT1T2& operator+=(PT1T2 &p1 , const PT1T2 &p2) { p1.first += p2.first, p1.second += p2.second; return p1; }
TT1T2 inline PT1T2 operator-(const PT1T2 &p1 , const PT1T2 &p2) { return PT1T2(p1.first - p2.first, p1.second - p2.second); }
TT1T2 inline PT1T2& operator-=(PT1T2 &p1 , const PT1T2 &p2) { p1.first -= p2.first, p1.second -= p2.second; return p1; }

#undef TT1
#undef TT1T2
#undef TT1T2T3

#define FREIN(FILE) freopen(FILE, "rt", stdin)
#define FREOUT(FILE) freopen(FILE, "wt", stdout)
#ifdef LOCAL
#define BEGIN_PROFILE(idx, name) int profileIdx = idx; profileName[profileIdx] = name; totalTime[profileIdx] -= rdtsc() / 1e3;
#define END_PROFILE totalTime[profileIdx] += rdtsc() / 1e3; totalCount[profileIdx]++;
#else
#define BEGIN_PROFILE(idx, name)
#define END_PROFILE
#endif

template<class T> inline void normmod(T &x, T m) { x %= m; if (x < 0) x += m; }
template<class T1, class T2> inline T2 summodfast(T1 x, T1 y, T2 m) { T2 res = x + y; if (res >= m) res -= m; return res; }
template<class T1, class T2, class T3> inline void addmodfast(T1 &x, T2 y, T3 m) { x += y; if (x >= m) x -= m; }
template<class T1, class T2, class T3> inline void submodfast(T1 &x, T2 y, T3 m) { x -= y; if (x < 0) x += m; }
#if INTPTR_MAX == INT32_MAX or !defined(__SIZEOF_INT128__)
inline ll mulmod(ll x, ll n, ll m){ ll r = 0; normmod(x, m); normmod(n, m); while (n) { if (n & 1) r += x; x += x; if (r >= m) r -= m; if (x >= m) x -= m; n /= 2; } return r; }
#else
using int128 = __int128;
inline ll mulmod(ll x, ll n, ll m){ return __int128(x) * n % m; }
#endif
inline ll powmod(ll x, ll n, ll m){ ll r = 1; normmod(x, m); while (n){ if (n & 1) r *= x; x *= x; r %= m; x %= m; n /= 2; }return r; }
inline ll powmulmod(ll x, ll n, ll m) { ll res = 1; normmod(x, m); while (n){ if (n & 1)res = mulmod(res, x, m); x = mulmod(x, x, m); n /= 2; } return res; }
template<class T> inline T gcd(T a, T b) { while (b) { T t = a % b; a = b; b = t; } return a; }
template<class T>
T fast_gcd(T u, T v) {
    int shl = 0; while ( u && v && u != v) { T eu = u & 1; u >>= eu ^ 1; T ev = v & 1; v >>= ev ^ 1;
        shl += (~(eu | ev) & 1); T d = u & v & 1 ? (u + v) >> 1 : 0; T dif = (u - v) >> (sizeof(T) * 8 - 1); u -= d & ~dif; v -= d & dif;
    } return std::max(u, v) << shl;
}

inline ll lcm(ll a, ll b){ return a / gcd(a, b) * b; }
template<class T> inline T gcd(T a, T b, T c){ return gcd(gcd(a, b), c); }
ll gcdex(ll a, ll b, ll& x, ll& y) {
    if (!a) { x = 0; y = 1; return b; }
    ll y1; ll d = gcdex(b % a, a, y, y1); x = y1 - (b / a) * y;
    return d;
}
template<class T> bool isPrime(T x) { if (x <= 4 || x % 2 == 0 || x % 3 == 0) return x == 2 || x == 3;
    for (T i = 5; i * i <= x; i += 6) if (x % i == 0 || x % (i + 2) == 0) return 0; return 1; }
bool millerRabin(long long n) {
    if (n <= 1000) return isPrime(n);
    long long s = n - 1; int t = 0; while (s % 2 == 0) s /= 2, ++t;
    for (int a : {2, 325, 9375, 28178, 450775, 9780504, 1795265022}) { if (!(a %= n)) return true;
        long long f = powmulmod(a, s, n); if (f == 1 || f == n - 1) continue;
        for (int i = 1; i < t; ++i) if ((f = mulmod(f, f, n)) == n - 1) goto nextp;
        return false; nextp:;
    } return true;
}

// Useful constants

//int some_primes[7] = {24443, 100271, 1000003, 1000333, 5000321, 98765431, 1000000123};
#define T9          1000000000
#define T18         1000000000000000000LL
#define INF         1011111111
#define LLINF       1000111000111000111LL
#define mod         1000000007
#define fftmod      998244353
#define EPS         (double)1e-10
#define PI          3.14159265358979323846264
#define link        asaxlajrewqwe
#define rank        wahayawehasdakw
//*************************************************************************************


int32_t solve();
int32_t main(int argc, char** argv) {
    ios_base::sync_with_stdio(0);cin.tie(0);
#ifdef LOCAL
//            FREIN("input.txt");
    //        FREOUT("out.txt");
#endif
    return solve();
}

vector<int> v[2];
int dp[2][4020202];
bool e[2][4030303];
int32_t solve() {
    int n;
    cin >> n;
    int m[2], t;
    cin >> m[0] >> m[1] >> t;
    vector<int> allV;
    FI(2) FJ(m[i]) {
        int x;
        cin >> x;
        allV.push_back(x);
        allV.push_back(x + 1);
        v[i].push_back(x);
    }
    v[0].push_back(INF);
    v[1].push_back(INF);
    allV.push_back(0);
    allV.push_back(n + 1);
    sort(all(allV));
    reunique(allV);
    FI(2) sort(all(v[i]));
    FI(2) {
        dp[i][0] = 0;
    }
    for (int i = 1; i < allV.size(); ++i) {
        int x = allV[i];
        int prevX = allV[i - 1];
        bool e[2];
        FJ(2) {
            e[j] = *lower_bound(v[j].begin(), v[j].end(), x) == x;
            ::e[j][i] = e[j];
        }
        FJ(2) {
            dp[j][i] = -INF;
            if (!e[j]) {
                if (dp[j][i - 1] >= 0) {
                    dp[j][i] = dp[j][i - 1] + x - prevX;
                }
            } else if (dp[j][i - 1] + x - prevX - 1 >= t) {
                dp[j][i] = dp[j][i - 1] - t + x - prevX;
            }
        }
        FJ(2) {
            if (!e[j]) {
                if (dp[1 - j][i] >= 0) {
                    dp[j][i] = max(dp[j][i], min(dp[1 - j][i], t));
                }
            }
        }
//        DBN(i, x, dp[0][i], dp[1][i]);
    }
    vector<pii> vs;
    vector<int> vc;
    FJ(2) {
        if (dp[j][allV.size() - 1] >= 0) {
            cout << "Yes" << endl;
            int cur = j;
            int shots = 0;
            for (int i = (int)allV.size() - 1; i > 0; --i) {
                int x = allV[i];
                int prevX = allV[i - 1];
                if (e[cur][i]) {
                    ++shots;
                }
                if (!e[cur][i] && dp[cur][i] == dp[cur][i - 1] + x - prevX) {
                    continue;
                } else if (e[cur][i] && dp[cur][i] == dp[cur][i - 1] + x - prevX - t) {
                    continue;
                } else {
                    int bal = dp[cur][i];
                    int pos = x;
                    while (shots > 0) {
                        shots--;
                        if (bal < t) {
                            pos += t - bal;
                            bal += t - bal;
                        }
                        bal = 0;
                        vs.push_back({pos, cur + 1});
                    }
                    cur = 1 - cur;
                    if (e[cur][i]) {
                        ++shots;
                    }
                    vc.push_back(x);
                }
            }
            {
                int bal = dp[cur][0];
                int pos = 0;
                while (shots > 0) {
                    shots--;
                    if (bal < t) {
                        pos += t - bal;
                        bal += t - bal;
                    }
                    bal = 0;
                    vs.push_back({pos, cur + 1});
                }
            }
            sort(all(vs));
            if (cur == 1) {
                vc.push_back(0);
            }
            sort(all(vc));
            cout << vc.size() << endl;
            for (int x : vc) {
                cout << x << ' ';
            }
            cout << endl;
            cout << vs.size() << endl;
            for (auto p : vs) {
                cout << p.first << ' ' << p.second << '\n';
            }
            return 0;
        }
    }
    cout << "No" << endl;
    return 0;
}