Problem: All Berland residents are waiting for an unprecedented tour of wizard in his Blue Helicopter over the cities of Berland!

It is well-known that there are n cities in Berland, some pairs of which are connected by bidirectional roads. Each pair of cities is connected by no more than one road. It is not guaranteed that the road network is connected, i.e. it is possible that you can't reach some city from some other.

The tour will contain several episodes. In each of the episodes:

  * the wizard will disembark at some city x from the Helicopter; 
  * he will give a performance and show a movie for free at the city x; 
  * he will drive to some neighboring city y using a road; 
  * he will give a performance and show a movie for free at the city y; 
  * he will drive to some neighboring to y city z; 
  * he will give a performance and show a movie for free at the city z; 
  * he will embark the Helicopter and fly away from the city z. 



It is known that the wizard doesn't like to use roads, so he agrees to use each road at most once (regardless of direction). In other words, for road between a and b he only can drive once from a to b, or drive once from b to a, or do not use this road at all.

The wizards wants to plan as many episodes as possible without violation the above rules. Help the wizard!

Please note that the wizard can visit the same city multiple times, the restriction is on roads only.

Input

The first line contains two integers n, m (1 ≤ n ≤ 2·105, 0 ≤ m ≤ 2·105) — the number of cities and the number of roads in Berland, respectively.

The roads description follow, one in each line. Each description is a pair of two integers ai, bi (1 ≤ ai, bi ≤ n, ai ≠ bi), where ai and bi are the ids of the cities connected by the i-th road. It is guaranteed that there are no two roads connecting the same pair of cities. Every road is bidirectional. The cities are numbered from 1 to n.

It is possible that the road network in Berland is not connected.

Output

In the first line print w — the maximum possible number of episodes. The next w lines should contain the episodes in format x, y, z — the three integers denoting the ids of the cities in the order of the wizard's visits.

Examples

Input

4 5
1 2
3 2
2 4
3 4
4 1


Output

2
1 4 2
4 3 2


Input

5 8
5 3
1 2
4 5
5 1
2 5
4 3
1 4
3 2


Output

4
1 4 5
2 3 4
1 5 3
5 2 1

Solution (in JAVA):

Solution:
import java.io.OutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.OutputStream;
import java.io.IOException;
import java.util.ArrayList;
import java.io.UncheckedIOException;
import java.util.List;
import java.io.Closeable;
import java.io.Writer;
import java.io.OutputStreamWriter;
import java.io.InputStream;

/**
 * Built using CHelper plug-in
 * Actual solution is at the top
 */
public class Main {
    public static void main(String[] args) throws Exception {
        Thread thread = new Thread(null, new TaskAdapter(), "", 1 << 27);
        thread.start();
        thread.join();
    }

    static class TaskAdapter implements Runnable {
        @Override
        public void run() {
            InputStream inputStream = System.in;
            OutputStream outputStream = System.out;
            FastInput in = new FastInput(inputStream);
            FastOutput out = new FastOutput(outputStream);
            DWizardsTour solver = new DWizardsTour();
            solver.solve(1, in, out);
            out.close();
        }
    }

    static class DWizardsTour {
        public void solve(int testNumber, FastInput in, FastOutput out) {
            int n = in.readInt();
            int m = in.readInt();
            Node[] nodes = new Node[n];
            Edge[] edges = new Edge[m];
            for (int i = 0; i < n; i++) {
                nodes[i] = new Node();
                nodes[i].id = i;
            }

            for (int i = 0; i < m; i++) {
                Node a = nodes[in.readInt() - 1];
                Node b = nodes[in.readInt() - 1];
                edges[i] = new Edge();
                edges[i].a = a;
                edges[i].b = b;
                a.next.add(edges[i]);
                b.next.add(edges[i]);

                a.odd ^= 1;
                edges[i].dir = a;
            }

            for (int i = 0; i < n; i++) {
                dfs(nodes[i], null);
            }

            for (int i = 0; i < m; i++) {
                edges[i].dir.to.add(edges[i]);
            }

            List<int[]> ans = new ArrayList<>(m);
            for (int i = 0; i < n; i++) {
                for (int j = 1; j < nodes[i].to.size(); j += 2) {
                    Edge e1 = nodes[i].to.get(j - 1);
                    Edge e2 = nodes[i].to.get(j);
                    ans.add(new int[]{e1.other(nodes[i]).id, i, e2.other(nodes[i]).id});
                }
            }

            out.println(ans.size());
            for (int[] way : ans) {
                for (int x : way) {
                    out.append(x + 1).append(' ');
                }
                out.println();
            }
        }

        public void dfs(Node root, Edge from) {
            if (root.visited) {
                return;
            }
            root.visited = true;
            for (Edge e : root.next) {
                Node node = e.other(root);
                dfs(node, e);
            }

            if (root.odd == 1 && from != null) {
                from.reverse();
            }
        }

    }

    static class FastOutput implements AutoCloseable, Closeable, Appendable {
        private StringBuilder cache = new StringBuilder(10 << 20);
        private final Writer os;

        public FastOutput append(CharSequence csq) {
            cache.append(csq);
            return this;
        }

        public FastOutput append(CharSequence csq, int start, int end) {
            cache.append(csq, start, end);
            return this;
        }

        public FastOutput(Writer os) {
            this.os = os;
        }

        public FastOutput(OutputStream os) {
            this(new OutputStreamWriter(os));
        }

        public FastOutput append(char c) {
            cache.append(c);
            return this;
        }

        public FastOutput append(int c) {
            cache.append(c);
            return this;
        }

        public FastOutput println(int c) {
            return append(c).println();
        }

        public FastOutput println() {
            cache.append(System.lineSeparator());
            return this;
        }

        public FastOutput flush() {
            try {
                os.append(cache);
                os.flush();
                cache.setLength(0);
            } catch (IOException e) {
                throw new UncheckedIOException(e);
            }
            return this;
        }

        public void close() {
            flush();
            try {
                os.close();
            } catch (IOException e) {
                throw new UncheckedIOException(e);
            }
        }

        public String toString() {
            return cache.toString();
        }

    }

    static class Node {
        List<Edge> next = new ArrayList<>();
        int odd;
        int id;
        boolean visited;
        List<Edge> to = new ArrayList<>();

        public String toString() {
            return "" + id;
        }

    }

    static class Edge {
        Node a;
        Node b;
        Node dir;

        public void reverse() {
            dir = other(dir);
            a.odd ^= 1;
            b.odd ^= 1;
        }

        Node other(Node x) {
            return a == x ? b : a;
        }

    }

    static class FastInput {
        private final InputStream is;
        private byte[] buf = new byte[1 << 13];
        private int bufLen;
        private int bufOffset;
        private int next;

        public FastInput(InputStream is) {
            this.is = is;
        }

        private int read() {
            while (bufLen == bufOffset) {
                bufOffset = 0;
                try {
                    bufLen = is.read(buf);
                } catch (IOException e) {
                    bufLen = -1;
                }
                if (bufLen == -1) {
                    return -1;
                }
            }
            return buf[bufOffset++];
        }

        public void skipBlank() {
            while (next >= 0 && next <= 32) {
                next = read();
            }
        }

        public int readInt() {
            int sign = 1;

            skipBlank();
            if (next == '+' || next == '-') {
                sign = next == '+' ? 1 : -1;
                next = read();
            }

            int val = 0;
            if (sign == 1) {
                while (next >= '0' && next <= '9') {
                    val = val * 10 + next - '0';
                    next = read();
                }
            } else {
                while (next >= '0' && next <= '9') {
                    val = val * 10 - next + '0';
                    next = read();
                }
            }

            return val;
        }

    }
}