Problem: Shrimpy Duc is a fat and greedy boy who is always hungry. After a while of searching for food to satisfy his never-ending hunger, Shrimpy Duc finds M&M candies lying unguarded on a L × L grid. There are n M&M candies on the grid, the i-th M&M is currently located at (x_i + 0.5, y_i + 0.5), and has color c_i out of a total of k colors (the size of M&Ms are insignificant).

Shrimpy Duc wants to steal a rectangle of M&Ms, specifically, he wants to select a rectangle with integer coordinates within the grid and steal all candies within the rectangle. Shrimpy Duc doesn't need to steal every single candy, however, he would like to steal at least one candy for each color.

In other words, he wants to select a rectangle whose sides are parallel to the coordinate axes and whose left-bottom vertex (X_1, Y_1) and right-top vertex (X_2, Y_2) are points with integer coordinates satisfying 0 ≤ X_1 < X_2 ≤ L and 0 ≤ Y_1 < Y_2 ≤ L, so that for every color 1 ≤ c ≤ k there is at least one M&M with color c that lies within that rectangle.

How many such rectangles are there? This number may be large, so you only need to find it modulo 10^9 + 7.

Input

The first line contains three positive integers n, k, L (1 ≤ k ≤ n ≤ 2 ⋅ 10^3, 1 ≤ L ≤ 10^9 ) — the number of M&Ms, the number of colors and the length of the grid respectively.

The following n points describe the M&Ms. Each line contains three integers x_i, y_i, c_i (0 ≤ x_i, y_i < L, 1 ≤ c_i ≤ k) — the coordinates and color of the i-th M&M respectively. 

Different M&Ms have different coordinates (x_i ≠ x_j or y_i ≠ y_j for every i ≠ j), and for every 1 ≤ c ≤ k there is at least one M&M with color c.

Output

Output a single integer — the number of rectangles satisfying Shrimpy Duc's conditions, modulo 10^9 + 7.

Examples

Input


4 2 4
3 2 2
3 1 1
1 1 1
1 2 1


Output


20


Input


5 3 10
6 5 3
5 3 1
7 9 1
2 3 2
5 0 2


Output


300


Input


10 4 10
5 4 4
0 0 3
6 0 1
3 9 2
8 7 1
8 1 3
2 1 3
6 3 2
3 5 3
4 3 4


Output


226

Note

Grid for the first sample:

<image>

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
using ld = long double;
using db = double;
using str = string;
using pi = pair<int, int>;
using pl = pair<ll, ll>;
using pd = pair<db, db>;
using vi = vector<int>;
using vb = vector<bool>;
using vl = vector<ll>;
using vd = vector<db>;
using vs = vector<str>;
using vpi = vector<pi>;
using vpl = vector<pl>;
using vpd = vector<pd>;
template <class T>
using V = vector<T>;
template <class T, size_t SZ>
using AR = array<T, SZ>;
const int MOD = 1e9 + 7;
const int MX = 2e5 + 5;
const ll INF = 1e18;
const ld PI = acos((ld)-1);
const int xd[4] = {1, 0, -1, 0}, yd[4] = {0, 1, 0, -1};
mt19937 rng((uint32_t)chrono::steady_clock::now().time_since_epoch().count());
constexpr int pct(int x) { return __builtin_popcount(x); }
constexpr int bits(int x) { return 31 - __builtin_clz(x); }
ll cdiv(ll a, ll b) { return a / b + ((a ^ b) > 0 && a % b); }
ll fdiv(ll a, ll b) { return a / b - ((a ^ b) < 0 && a % b); }
ll half(ll x) { return fdiv(x, 2); }
template <class T>
bool ckmin(T& a, const T& b) {
  return b < a ? a = b, 1 : 0;
}
template <class T>
bool ckmax(T& a, const T& b) {
  return a < b ? a = b, 1 : 0;
}
template <class T, class U>
T fstTrue(T lo, T hi, U first) {
  hi++;
  assert(lo <= hi);
  while (lo < hi) {
    T mid = half(lo + hi);
    first(mid) ? hi = mid : lo = mid + 1;
  }
  return lo;
}
template <class T, class U>
T lstTrue(T lo, T hi, U first) {
  lo--;
  assert(lo <= hi);
  while (lo < hi) {
    T mid = half(lo + hi + 1);
    first(mid) ? lo = mid : hi = mid - 1;
  }
  return lo;
}
template <class T>
void remDup(vector<T>& v) {
  sort(begin(v), end(v));
  v.erase(unique(begin(v), end(v)), end(v));
}
template <class T, class U>
void erase(T& t, const U& u) {
  auto it = t.find(u);
  assert(it != end(t));
  t.erase(u);
}
template <class T>
void re(complex<T>& c);
template <class T, class U>
void re(pair<T, U>& p);
template <class T>
void re(vector<T>& v);
template <class T, size_t SZ>
void re(AR<T, SZ>& a);
template <class T>
void re(T& x) {
  cin >> x;
}
void re(db& d) {
  str t;
  re(t);
  d = stod(t);
}
void re(ld& d) {
  str t;
  re(t);
  d = stold(t);
}
template <class T, class... U>
void re(T& t, U&... u) {
  re(t);
  re(u...);
}
template <class T>
void re(complex<T>& c) {
  T a, b;
  re(a, b);
  c = {a, b};
}
template <class T, class U>
void re(pair<T, U>& p) {
  re(p.first, p.second);
}
template <class T>
void re(vector<T>& x) {
  for (auto& a : x) re(a);
}
template <class T, size_t SZ>
void re(array<T, SZ>& x) {
  for (auto& a : x) re(a);
}
str to_string(char c) { return str(1, c); }
str to_string(const char* second) { return (str)second; }
str to_string(str second) { return second; }
str to_string(bool b) { return to_string((int)b); }
template <class T>
str to_string(complex<T> c) {
  stringstream ss;
  ss << c;
  return ss.str();
}
str to_string(vector<bool> v) {
  str res = "{";
  for (int i = (0); i < ((int)(v).size()); ++i) res += char('0' + v[i]);
  res += "}";
  return res;
}
template <size_t SZ>
str to_string(bitset<SZ> b) {
  str res = "";
  for (int i = (0); i < (SZ); ++i) res += char('0' + b[i]);
  return res;
}
template <class T, class U>
str to_string(pair<T, U> p);
template <class T>
str to_string(T v) {
  bool fst = 1;
  str res = "";
  for (const auto& x : v) {
    if (!fst) res += " ";
    fst = 0;
    res += to_string(x);
  }
  return res;
}
template <class T, class U>
str to_string(pair<T, U> p) {
  return to_string(p.first) + " " + to_string(p.second);
}
template <class T>
void pr(T x) {
  cout << to_string(x);
}
template <class T, class... U>
void pr(const T& t, const U&... u) {
  pr(t);
  pr(u...);
}
void ps() { pr("\n"); }
template <class T, class... U>
void ps(const T& t, const U&... u) {
  pr(t);
  if (sizeof...(u)) pr(" ");
  ps(u...);
}
void DBG() { cerr << "]" << endl; }
template <class T, class... U>
void DBG(const T& t, const U&... u) {
  cerr << to_string(t);
  if (sizeof...(u)) cerr << ", ";
  DBG(u...);
}
void setIn(str second) { freopen(second.c_str(), "r", stdin); }
void setOut(str second) { freopen(second.c_str(), "w", stdout); }
void unsyncIO() { cin.tie(0)->sync_with_stdio(0); }
void setIO(str second = "") {
  unsyncIO();
  if ((int)(second).size()) {
    setIn(second + ".in"), setOut(second + ".out");
  }
}
template <int MOD, int RT>
struct mint {
  static const int mod = MOD;
  static constexpr mint rt() { return RT; }
  int v;
  explicit operator int() const { return v; }
  mint() { v = 0; }
  mint(ll _v) {
    v = (-MOD < _v && _v < MOD) ? _v : _v % MOD;
    if (v < 0) v += MOD;
  }
  friend bool operator==(const mint& a, const mint& b) { return a.v == b.v; }
  friend bool operator!=(const mint& a, const mint& b) { return !(a == b); }
  friend bool operator<(const mint& a, const mint& b) { return a.v < b.v; }
  friend void re(mint& a) {
    ll x;
    re(x);
    a = mint(x);
  }
  friend str to_string(mint a) { return to_string(a.v); }
  mint& operator+=(const mint& m) {
    if ((v += m.v) >= MOD) v -= MOD;
    return *this;
  }
  mint& operator-=(const mint& m) {
    if ((v -= m.v) < 0) v += MOD;
    return *this;
  }
  mint& operator*=(const mint& m) {
    v = (ll)v * m.v % MOD;
    return *this;
  }
  mint& operator/=(const mint& m) { return (*this) *= inv(m); }
  friend mint pow(mint a, ll p) {
    mint ans = 1;
    assert(p >= 0);
    for (; p; p /= 2, a *= a)
      if (p & 1) ans *= a;
    return ans;
  }
  friend mint inv(const mint& a) {
    assert(a.v != 0);
    return pow(a, MOD - 2);
  }
  mint operator-() const { return mint(-v); }
  mint& operator++() { return *this += 1; }
  mint& operator--() { return *this -= 1; }
  friend mint operator+(mint a, const mint& b) { return a += b; }
  friend mint operator-(mint a, const mint& b) { return a -= b; }
  friend mint operator*(mint a, const mint& b) { return a *= b; }
  friend mint operator/(mint a, const mint& b) { return a /= b; }
};
typedef mint<MOD, 5> mi;
vector<vector<mi> > scmb;
void genComb(int SZ) {
  scmb.assign(SZ, vector<mi>(SZ));
  scmb[0][0] = 1;
  for (int i = (1); i < (SZ); ++i)
    for (int j = (0); j < (i + 1); ++j)
      scmb[i][j] = scmb[i - 1][j] + (j ? scmb[i - 1][j - 1] : 0);
}
using T = AR<int, 3>;
int n, k, L;
V<T> mm;
vpi todo[2001];
vpi del[MX];
mi go() {
  for (int i = (1); i < (k + 1); ++i) todo[i] = {{L, -1}};
  V<T> cur = mm;
  sort(begin(cur), end(cur));
  0;
  map<int, int> dat;
  mi csum = 0;
  auto oops = [&](map<int, int>::iterator it) -> mi {
    if (it == end(dat) || it == begin(dat)) return 0;
    return mi(it->first - prev(it)->first) * (L - it->second);
  };
  auto upd = [&](int x, int y) {
    auto it = dat.lower_bound(x);
    if (it != end(dat) && it->second >= y) return;
    if (it != end(dat)) {
      if (it->first == x) {
        csum -= oops(it);
        csum -= oops(next(it));
      } else {
        csum -= oops(it);
      }
    }
    dat[x] = y;
    it = dat.find(x);
    csum += oops(next(it));
    while (it != begin(dat) && prev(it)->second <= y) {
      csum -= oops(prev(it));
      dat.erase(prev(it));
    }
    csum += oops(it);
  };
  for (int i = ((int)(cur).size()) - 1; i >= (0); --i) {
    int col = cur[i][2];
    vpi& v = todo[col];
    del[i] = {{v.back().first - 1, L}};
    while ((int)(v).size() && v.back().second >= cur[i][1]) {
      pi a = v.back();
      v.pop_back();
      pi b = v.back();
      del[i].push_back({b.first - 1, a.second});
    }
    v.push_back({cur[i][0], cur[i][1]});
  }
  for (int i = (1); i < (k + 1); ++i) {
    int lst = L;
    reverse(begin(todo[i]), end(todo[i]));
    for (auto& t : todo[i]) upd(t.first - 1, lst), lst = t.second;
    0;
  }
  int lst = -1;
  mi ans = 0;
  for (int i = (0); i < ((int)(cur).size()); ++i) {
    ans += (cur[i][0] - lst) * csum;
    lst = cur[i][0];
    for (auto& t : del[i]) upd(t.first, t.second);
  }
  0;
  0;
  return ans;
}
int main() {
  setIO();
  re(n, k, L);
  mm.resize(n);
  re(mm);
  sort(begin(mm), end(mm), [](T a, T b) { return a[1] < b[1]; });
  int lst = -1;
  mi ans = 0;
  while ((int)(mm).size()) {
    int y = mm[0][1];
    ans += (y - lst) * go();
    0;
    lst = y;
    mm.erase(begin(mm));
  }
  ps(ans);
}