Problem: Akira, the student council president of A High School, decided to investigate which club activities the A High School students belong to. A High School has N students numbered 1 to N and M types of club activities numbered 1 to M. There is no limit to the number of people in each club activity, and there can be 0 club activities. However, according to the school rules of A High School, students can only belong to one club activity. All students follow this school rule.

Akira asked student members to investigate and obtained records for line K, such as each line being one of the following:

* Student a and student b belong to the same club activities.
* Student c belongs to club activity x.



However, there may be a contradiction in this record that would cause someone to violate school rules. Akira decided to look at the first line in order and look for the first line that could be judged to be inconsistent.

Create a program that finds the number of the first line that can be determined to be inconsistent given a record of K lines.



Input

The input is given in the following format.


NMK
record1
record2
::
recordK


The first line gives the number of students N (1 ≤ N ≤ 100000), the number of club activity types M (1 ≤ M ≤ 100000), and the number of recorded lines K (1 ≤ K ≤ 200000). Each line of record, recordi, is given in the following K lines in one of the following formats:


1 a b


Or


2 c x


When the first digit is "1", it indicates that student a (1 ≤ a ≤ N) and student b (1 ≤ b ≤ N) belong to the same club activity. However, a ≠ b.

When the first digit is "2", it indicates that student c (1 ≤ c ≤ N) belongs to club activity x (1 ≤ x ≤ M).

Output

Output the number of the first line that can be determined to be inconsistent on one line. If not found, output 0 on one line.

Examples

Input

3 2 5
1 1 2
1 2 3
2 1 1
2 3 2
2 2 1


Output

4


Input

3 2 4
1 1 2
2 1 1
2 3 2
2 2 1


Output

0


Input

3 2 2
1 1 2
2 1 1


Output

0

Solution (in CPP):

Solution:
#include <iostream>
#include <cstdio>
#include <vector>
#define _USE_MATH_DEFINES
#include <math.h>
#include <cstring>
#include <numeric>
#include <algorithm>
#include <stdlib.h>
#include <functional>
#include <string>
#include <array>
#include <map>
#include <queue>
#include <limits.h>
#include <set>
#include <stack>
#include <random>
#include <complex>
#include <unordered_map>
#include <nmmintrin.h>
#include <chrono>
#define rep(i,s,n) for(int i = (s); (n) > i; i++)
#define REP(i,n) rep(i,0,n)
#define RANGE(x,a,b) ((a) <= (x) && (x) <= (b))
#define DUPLE(a,b,c,d) (RANGE(a,c,d) || RANGE(b,c,d) || RANGE(c,a,b) || RANGE(d,a,b))
#define INCLU(a,b,c,d) (RANGE(a,c,d) && (b,c,d))
#define PW(x) ((x)*(x))
#define ALL(x) (x).begin(), (x).end()
#define MODU 1000000007
#define bitcheck(a,b)   ((a >> b) & 1)
#define bitset(a,b)      ( a |= (1 << b))
#define bitunset(a,b)    (a &= ~(1 << b))
#define MP(a,b) make_pair((a),(b))
#define Manh(a,b) (abs((a).first-(b).first) + abs((a).second - ((b).second))
#define pritnf printf
#define scnaf scanf
#define itn int
#ifdef _MSC_VER
#define __builtin_popcount _mm_popcnt_u32
#define __builtin_popcountll _mm_popcnt_u64
#endif
using namespace std;
typedef long long ll;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
ll gcd(ll a, ll b) {
	if (b == 0) return a;
	return gcd(b, a%b);
}
template<typename A, size_t N, typename T>
void Fill(A(&array)[N], const T &val) {
	std::fill((T*)array, (T*)(array + N), val);
}


struct UnionFind{
	vector<int> data;
	int n, m;

	UnionFind(int ns, int ms) : n(ns), m(ms), data(ns + ms, INT_MIN){
		REP(i, m){
			data[i + n] = -i-1;
		}
	}

	bool unite(int a, int b){//矛盾の判定
		a = root(a), b = root(b);

		if (a == b)
			return true;

		if (data[a] != INT_MIN && data[b] != INT_MIN){
			if (data[a] != data[b]){
				return false;
			}
			else {
				if (rand() % 2)
					data[b] = a;
				else
					data[a] = b;
			}
		}
		else if (data[a] != INT_MIN)
			data[b] = a;
		else if (data[b] != INT_MIN)
			data[a] = b;
		else{
			if (rand() % 2)
				data[b] = a;
			else
				data[a] = b;
		}
		return true;
	}


	bool unitebu(int a, int b){//矛盾の判定 aをbの部活
		a = root(a);
		b += n;

		if (data[a] == data[b])
			return true;
		if (data[a] != INT_MIN)
			return false;

		data[a] = b;
		return true;
	}

	bool findset(int a, int b){
		return root(a) == root(b);
	}

	int root(int x){
		return data[x] < 0 ? x : data[x] = root(data[x]);
	}
};

signed main() {
	int n, m, k;
	cin >> n >> m >> k;
	UnionFind uf(n,m);
	REP(i, k){
		int t, a, b;
		scanf("%d %d %d", &t, &a, &b);
		bool ret = 1;
		a--, b--;
		if (t == 1){
			ret = uf.unite(a, b);
		}
		else if (t == 2){
			ret = uf.unitebu(a, b);
		}

		if (!ret){
			printf("%d\n", i + 1);
			return 0;
		}
	}

	printf("0\n");

	return 0;
}