Problem: A positive (strictly greater than zero) integer is called round if it is of the form d00...0. In other words, a positive integer is round if all its digits except the leftmost (most significant) are equal to zero. In particular, all numbers from 1 to 9 (inclusive) are round.

For example, the following numbers are round: 4000, 1, 9, 800, 90. The following numbers are not round: 110, 707, 222, 1001.

You are given a positive integer n (1 ≤ n ≤ 10^4). Represent the number n as a sum of round numbers using the minimum number of summands (addends). In other words, you need to represent the given number n as a sum of the least number of terms, each of which is a round number.

Input

The first line contains an integer t (1 ≤ t ≤ 10^4) — the number of test cases in the input. Then t test cases follow.

Each test case is a line containing an integer n (1 ≤ n ≤ 10^4).

Output

Print t answers to the test cases. Each answer must begin with an integer k — the minimum number of summands. Next, k terms must follow, each of which is a round number, and their sum is n. The terms can be printed in any order. If there are several answers, print any of them.

Example

Input


5
5009
7
9876
10000
10


Output


2
5000 9
1
7 
4
800 70 6 9000 
1
10000 
1
10 

Solution (in PYTHON3):

Solution:
for _ in range(int(input())):
    n = int(input())
    count = 0
    count_zero = 0
    lst = []
    if 0 < n <= 9:
        count += 1
        lst.append(n)
    else:
        m = str(n)
        lst_n = [int(elem) for elem in m]
        if sum(lst_n) == 1 and list(set(lst_n[1:]))[0]==0:
            count = 1
            lst.append(n)
        else:
            while n:
                rem = n % 10
                n = n//10
                count += 1
                if rem !=0:
                    
                    lst.append(rem * pow(10, count-1))
                else:
                    count_zero += 1
            count = count - count_zero
    print(count)
    ans = " ".join([str(elem) for elem in lst])
    print(ans)