Problem: A positive (strictly greater than zero) integer is called round if it is of the form d00...0. In other words, a positive integer is round if all its digits except the leftmost (most significant) are equal to zero. In particular, all numbers from 1 to 9 (inclusive) are round.

For example, the following numbers are round: 4000, 1, 9, 800, 90. The following numbers are not round: 110, 707, 222, 1001.

You are given a positive integer n (1 ≤ n ≤ 10^4). Represent the number n as a sum of round numbers using the minimum number of summands (addends). In other words, you need to represent the given number n as a sum of the least number of terms, each of which is a round number.

Input

The first line contains an integer t (1 ≤ t ≤ 10^4) — the number of test cases in the input. Then t test cases follow.

Each test case is a line containing an integer n (1 ≤ n ≤ 10^4).

Output

Print t answers to the test cases. Each answer must begin with an integer k — the minimum number of summands. Next, k terms must follow, each of which is a round number, and their sum is n. The terms can be printed in any order. If there are several answers, print any of them.

Example

Input


5
5009
7
9876
10000
10


Output


2
5000 9
1
7 
4
800 70 6 9000 
1
10000 
1
10 

Solution (in PYTHON3):

Solution:
inp=input
li=list
iinp=lambda : int(inp())
ent=lambda : map(int,inp().split())
lient=lambda : [int(i) for i in inp().split()]
li0= lambda x: [0 for i in range(x)]
livalor=lambda valor,x: [valor for i in range(x)]
stent=lambda : [i for i in inp()]
filldp=lambda valor,x,y: [[valor for i in range(y)] for i in range(x)]
l=len

t=iinp()
for _ in range(t):
    n=inp()
    divisor=10**(l(n)-1)
    cont=l(n)-1
    n=int(n)
    respuesta=[]
    
    while n!=0:
        tmp=n//divisor*divisor
        if tmp!=0: respuesta.append(tmp)
        n%=divisor
        divisor=10**(cont)
        cont-=1    
    print(l(respuesta))
    print(*respuesta)