Problem: This is an interactive problem. You should use flush operation after each printed line. For example, in C++ you should use fflush(stdout), in Java you should use System.out.flush(), and in Pascal — flush(output).

In this problem you should guess an array a which is unknown for you. The only information you have initially is the length n of the array a.

The only allowed action is to ask the sum of two elements by their indices. Formally, you can print two indices i and j (the indices should be distinct). Then your program should read the response: the single integer equals to ai + aj.

It is easy to prove that it is always possible to guess the array using at most n requests.

Write a program that will guess the array a by making at most n requests.

Interaction

In each test your program should guess a single array.

The input starts with a line containing integer n (3 ≤ n ≤ 5000) — the length of the array. Your program should read it at first.

After that your program should print to the standard output the requests about the sum of two elements or inform that the array is guessed.

  * In case your program is making a request to ask the sum of two elements, it should print line in the format "? i j" (i and j are distinct integers between 1 and n), where i and j are indices in the array a.
  * In case your program informs that the array is guessed, it should print line in the format "! a1 a2 ... an" (it is guaranteed that all ai are positive integers not exceeding 105), where ai is the i-th element of the array a. 



The response on a request is a single integer equal to ai + aj, printed on a separate line.

Your program can do at most n requests. Note that the final line «! a1 a2 ... an» is not counted as a request.

Do not forget about flush operation after each printed line.

After you program prints the guessed array, it should terminate normally.

Example

Input

5
 
9
 
7
 
9
 
11
 
6
 

Output

 
? 1 5
 
? 2 3
 
? 4 1
 
? 5 2
 
? 3 4
 
! 4 6 1 5 5

Note

The format of a test to make a hack is:

  * The first line contains an integer number n (3 ≤ n ≤ 5000) — the length of the array.
  * The second line contains n numbers a1, a2, ..., an (1 ≤ ai ≤ 105) — the elements of the array to guess. 

Solution (in JAVA):

Solution:
import java.util.*;
import java.io.*;

public class C {
	public static void main(String args[]) {
		InputReader in = new InputReader(System.in);
		OutputStream outputStream = System.out;
		PrintWriter out = new PrintWriter(outputStream);
		/*------------------------------My Code starts here------------------------------*/
		int i=1,n=in.nextInt(),x,y,z;
		int[] a=new int[n+1];
		for(i=1;i+2<=n;i+=3)
		{
			out.println("? "+i+" "+(i+1));
			out.flush();
			x=in.nextInt();
			out.println("? "+i+" "+(i+2));
			out.flush();
			y=in.nextInt();
			out.println("? "+(i+1)+" "+(i+2));
			out.flush();
			z=in.nextInt();
			a[i]=(x+y-z)/2;
			a[i+1]=(x+z-y)/2;
			a[i+2]=(y+z-x)/2;
		}
		for(;i<=n;i++)
		{
			out.println("? "+(i-1)+" "+i);
			out.flush();
			x=in.nextInt();
			a[i]=x-a[i-1];
		}
		out.print("! ");
		for(i=1;i<=n;i++)
			out.print(a[i]+" ");
		out.close();
		/*------------------------------The End------------------------------------------*/
	}

	public static final long l = (int) (1e9 + 7);

	private static int[] nextIntArray(InputReader in, int n) {
		int[] a = new int[n];
		for (int i = 0; i < n; i++)
			a[i] = in.nextInt();
		return a;
	}

	private static long[] nextLongArray(InputReader in, int n) {
		long[] a = new long[n];
		for (int i = 0; i < n; i++)
			a[i] = in.nextLong();
		return a;
	}

	private static int[][] nextIntMatrix(InputReader in, int n, int m) {
		int[][] a = new int[n][m];
		for (int i = 0; i < n; i++) {
			for (int j = 0; j < m; j++)
				a[i][j] = in.nextInt();
		}
		return a;
	}

	private static void show(int[] a) {
		for (int i = 0; i < a.length; i++)
			System.out.print(a[i] + " ");
		System.out.println();
	}

	private static void show2DArray(char[][] a) {
		for (int i = 0; i < a.length; i++) {
			for (int j = 0; j < a[0].length; j++)
				System.out.print(a[i][j]);
			System.out.println();
		}
	}

	static class Pair {
		private int first;
		private int second;

		public Pair(int i, int j) {
			this.first = i;
			this.second = j;
		}

		public int getFirst() {
			return first;
		}

		public int getSecond() {
			return second;
		}

		public void setFirst(int k) {
			this.first = k;
		}

		public void setSecond(int k) {
			this.second = k;
		}
	}

	static int modPow(int a, int b, int p) {
		int result = 1;
		a %= p;
		while (b > 0) {
			if ((b & 1) != 0)
				result = (result * a) % p;
			b = b >> 1;
			a = (a * a) % p;
		}
		return result;
	}

	public static void SieveOfEratosthenes(int n) {
		boolean[] prime = new boolean[n + 1];
		Arrays.fill(prime, true);
		prime[1] = false;
		int i, j;
		for (i = 2; i * i <= n; i++) {
			if (prime[i]) {
				for (j = i; j <= n; j += i) {
					if (j != i)
						prime[j] = false;
				}
			}
		}
	}

	static class InputReader {
		public BufferedReader reader;
		public StringTokenizer tokenizer;

		public InputReader(InputStream inputstream) {
			reader = new BufferedReader(new InputStreamReader(inputstream));
			tokenizer = null;
		}

		public String nextLine() {
			String fullLine = null;
			while (tokenizer == null || !tokenizer.hasMoreTokens()) {
				try {
					fullLine = reader.readLine();
				} catch (IOException e) {
					throw new RuntimeException(e);
				}
				return fullLine;
			}
			return fullLine;
		}

		public String next() {
			while (tokenizer == null || !tokenizer.hasMoreTokens()) {
				try {
					tokenizer = new StringTokenizer(reader.readLine());
				} catch (IOException e) {
					throw new RuntimeException(e);
				}
			}
			return tokenizer.nextToken();
		}

		public long nextLong() {
			return Long.parseLong(next());
		}

		public int nextInt() {
			return Integer.parseInt(next());
		}
	}

}