Problem: Maria participates in a bicycle race.

The speedway takes place on the shores of Lake Lucerne, just repeating its contour. As you know, the lake shore consists only of straight sections, directed to the north, south, east or west.

Let's introduce a system of coordinates, directing the Ox axis from west to east, and the Oy axis from south to north. As a starting position of the race the southernmost point of the track is selected (and if there are several such points, the most western among them). The participants start the race, moving to the north. At all straight sections of the track, the participants travel in one of the four directions (north, south, east or west) and change the direction of movement only in bends between the straight sections. The participants, of course, never turn back, that is, they do not change the direction of movement from north to south or from east to west (or vice versa).

Maria is still young, so she does not feel confident at some turns. Namely, Maria feels insecure if at a failed or untimely turn, she gets into the water. In other words, Maria considers the turn dangerous if she immediately gets into the water if it is ignored.

Help Maria get ready for the competition — determine the number of dangerous turns on the track.

Input

The first line of the input contains an integer n (4 ≤ n ≤ 1000) — the number of straight sections of the track.

The following (n + 1)-th line contains pairs of integers (xi, yi) ( - 10 000 ≤ xi, yi ≤ 10 000). The first of these points is the starting position. The i-th straight section of the track begins at the point (xi, yi) and ends at the point (xi + 1, yi + 1).

It is guaranteed that:

  * the first straight section is directed to the north; 
  * the southernmost (and if there are several, then the most western of among them) point of the track is the first point; 
  * the last point coincides with the first one (i.e., the start position); 
  * any pair of straight sections of the track has no shared points (except for the neighboring ones, they share exactly one point); 
  * no pair of points (except for the first and last one) is the same; 
  * no two adjacent straight sections are directed in the same direction or in opposite directions. 

Output

Print a single integer — the number of dangerous turns on the track.

Examples

Input

6
0 0
0 1
1 1
1 2
2 2
2 0
0 0


Output

1


Input

16
1 1
1 5
3 5
3 7
2 7
2 9
6 9
6 7
5 7
5 3
4 3
4 4
3 4
3 2
5 2
5 1
1 1


Output

6

Note

The first sample corresponds to the picture:

<image>

The picture shows that you can get in the water under unfortunate circumstances only at turn at the point (1, 1). Thus, the answer is 1.

Solution (in JAVA):

Solution:
import java.io.BufferedOutputStream;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.util.ArrayList;
import java.util.HashMap;
import java.util.HashSet;
import java.util.List;
import java.util.Map;
import java.util.Set;
import java.util.StringTokenizer;

public class Code {
    public static void main(String[] args) {
        // Use the Scanner class
        MyScanner sc = new MyScanner();
        out = new PrintWriter(new BufferedOutputStream(System.out));

        int n = sc.nextInt();
        Point[] P = new Point[n+1];
        Edge[] E = new Edge[n+1];
        for (int i = 0; i < n+1; ++i) {
            int a_x = sc.nextInt();
            int a_y = sc.nextInt();

            Point p = new Point(a_x, a_y);
            P[i] = p;
        }

        for (int i = 0; i < n; ++i) {
            E[i] = new Edge();
            E[i].dir = get_dir(P[i], P[i+1]);
            //System.out.println(E[i].dir);
        }

        E[n] = E[0];
        Dir water_dir = Dir.R;

        for (int i = 0; i < n; ++i) {
            E[i].waterSide = water_dir;
            //get_water_side(E[i], E[i+1]);
        }


        int cnt = 0;
        for (int i = 0; i < n; ++i) {
            if (is_accidential(E[i], E[i+1])) {
                cnt++;
            }
        }

        System.out.println(cnt);

    }

    static boolean is_accidential(Edge e1, Edge e2) {
        if (e1.dir == Dir.R && e2.dir == Dir.U) {
            return true;
        }

        if (e1.dir == Dir.D && e2.dir == Dir.R) {
            return true;
        }

        if (e1.dir == Dir.U && e2.dir == Dir.L) {
            return true;
        }

        if (e1.dir == Dir.L && e2.dir == Dir.D) {
            return true;
        }
//        if (e1.dir == Dir.R || e1.dir == Dir.L) {
//            return e2.waterSide == e1.dir;
//        }
//
//        if (e1.dir == Dir.U || e1.dir == Dir.D) {
//            return are_opposite(e1.dir, e2.waterSide);
//        }
//
        return false;
    }

    static boolean are_opposite(Dir d1, Dir d2) {
        if (d1== Dir.R && d2 == Dir.U) {
            return true;
        }

        if (d1 == Dir.L && d2 == Dir.D) {
            return true;
        }

        if (d1 == Dir.U && d2 == Dir.L) {
            return true;
        }

        if (d1 == Dir.D && d2 == Dir.R) {
            return true;
        }

        return false;
    }
    static void get_water_side(Edge e1, Edge e2) {
        if (e1.dir == Dir.U ) {
            e1.waterSide = e2.dir;
        }

        if (e1.dir == Dir.D ) {
            e1.waterSide = e2.dir == Dir.R ? Dir.L : Dir.R ;
        }

        if (e1.dir == Dir.L ) {
            if (e2.dir == Dir.U) {
                e1.waterSide = Dir.R;
            } else {
                e1.waterSide = Dir.L;
            }
        }

        if (e1.dir == Dir.R ) {
            e1.waterSide = Dir.R;
        }

        //return Dir.D;
    }

    static Dir get_dir(Point p1, Point p2) {
        if (p2.x > p1.x) {
            return Dir.R;
        }

        if (p2.x < p1.x) {
            return Dir.L;
        }

        if (p2.y > p1.y) {
            return Dir.U;
        }

        if (p1.y > p2.y) {
            return Dir.D;
        }

        return Dir.L;
    }

    static class Point {
        int x;
        int y;

        public Point(int x, int y) {
            this.x = x;
            this.y = y;
        }
    }

    static class Edge {
        Dir dir;
        Dir waterSide;
    }
    static enum Dir {
        L, R, U, D;
    }

    static int get_node_val(int init_val, int gp_flipped) {
        return gp_flipped % 2 == 1? (init_val == 0 ? 1 : 0) : init_val;
    }

    static boolean are_last_4_equal(String s, int i, char val) {
        return (s.charAt(i-1) == val && s.charAt(i-2) == val && s.charAt(i-3) == val && s.charAt(i-4) == val);
    }

    public static PrintWriter out;

    //-----------MyScanner class for faster input----------
    public static class MyScanner {
       BufferedReader br;
       StringTokenizer st;

       public MyScanner() {
          br = new BufferedReader(new InputStreamReader(System.in));
       }

       String next() {
           while (st == null || !st.hasMoreElements()) {
               try {
                   st = new StringTokenizer(br.readLine());
               } catch (IOException e) {
                   e.printStackTrace();
               }
           }
           return st.nextToken();
       }

       int nextInt() {
           return Integer.parseInt(next());
       }

       long nextLong() {
           return Long.parseLong(next());
       }

       double nextDouble() {
           return Double.parseDouble(next());
       }

       String nextLine(){
           String str = "";
       try {
          str = br.readLine();
       } catch (IOException e) {
          e.printStackTrace();
       }
       return str;
       }

    }

}