Problem: Read a set of coordinates of three different points P1 (x1, y1), P2 (x2, y2), Q (xq, yq) on the plane, and line symmetry with point Q with the straight line passing through point P1 point P2 as the axis of symmetry. Create a program that outputs the point R (x, y) at the position of. Note that the point Q is not on its axis of symmetry.

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input

The input consists of multiple datasets. Each dataset is given in the following format:


x1, y1, x2, y2, xq, yq


x1, y1, x2, y2, xq, yq (real numbers between -100 and 100) are given on one line separated by commas.

The number of datasets does not exceed 50.

output

Print x, y on a single line, separated by blanks, for each dataset. The output may contain an error of 0.0001 or less in real numbers.

Example

Input

1.0,0.0,-1.0,0.0,1.0,1.0
1.0,0.0,0.0,-1.0,3.0,0.0
0.0,1.0,0.0,-1.0,1.0,1.0


Output

1.000000 -1.000000
1.000000 2.000000
-1.000000 1.000000

Solution (in CPP):

Solution:
#include<iomanip>
#include<iostream>
#include<complex>
using namespace std;
typedef complex<double> xy_t;

double dot(xy_t a,xy_t b){
    return (conj(a)*b).real();
}

xy_t proj(xy_t a,xy_t b){ //b???a????°???±
    return b*dot(a,b)/norm(b);
}

int main(){
    double x1,y1,x2,y2,xq,yq;
    char no;
    while(cin>>x1>>no>>y1>>no>>x2>>no>>y2>>no>>xq>>no>>yq){
        xy_t normal=xy_t(y2-y1,x1-x2); //??????????????????
        //cerr<<normal.real()<<" "<<normal.imag()<<"\n";
        xy_t v=xy_t(x1-xq,y1-yq);
        //cerr<<v.real()<<" "<<v.imag()<<"\n";

        xy_t r=xy_t(xq,yq)+proj(v,normal)+proj(v,normal);
        //cerr<<proj(v,normal).real()<<" "<<proj(v,normal).imag()<<"\n";

        cout<<fixed<<setprecision(6)<<r.real()<<" "<<r.imag()<<"\n";
    }
}