Problem: Try guessing the statement from this picture: 

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You are given a non-negative integer d. You have to find two non-negative real numbers a and b such that a + b = d and a ⋅ b = d.

Input

The first line contains t (1 ≤ t ≤ 10^3) — the number of test cases.

Each test case contains one integer d (0 ≤ d ≤ 10^3).

Output

For each test print one line.

If there is an answer for the i-th test, print "Y", and then the numbers a and b.

If there is no answer for the i-th test, print "N".

Your answer will be considered correct if |(a + b) - a ⋅ b| ≤ 10^{-6} and |(a + b) - d| ≤ 10^{-6}.

Example

Input


7
69
0
1
4
5
999
1000


Output


Y 67.985071301 1.014928699
Y 0.000000000 0.000000000
N
Y 2.000000000 2.000000000
Y 3.618033989 1.381966011
Y 997.998996990 1.001003010
Y 998.998997995 1.001002005

Solution (in JAVA):

Solution:
import java.io.File;
import java.io.IOException;
import java.util.Scanner;

public class C1076 {

	public static void main(String[] args) throws IOException{
		Scanner scanner = new Scanner(System.in);
		int length = scanner.nextInt();
		
		for(long i = 0; i < length; i++) {
			int num = scanner.nextInt();
			if(num == 0) {
				System.out.printf("Y %.9f %.9f%n", 0.0d, 0.0d);
				continue;
			} else if(num < 4) {
				System.out.printf("N%n");
				continue;
			}
			
			double temp = Math.sqrt(num * (num - 4));
			double a = (num + temp)/2;
			double b = (num - temp)/2;
			System.out.printf("Y %.9f %.9f%n", a, b);
		}
	}
}