Problem: A positive (strictly greater than zero) integer is called round if it is of the form d00...0. In other words, a positive integer is round if all its digits except the leftmost (most significant) are equal to zero. In particular, all numbers from 1 to 9 (inclusive) are round.

For example, the following numbers are round: 4000, 1, 9, 800, 90. The following numbers are not round: 110, 707, 222, 1001.

You are given a positive integer n (1 ≤ n ≤ 10^4). Represent the number n as a sum of round numbers using the minimum number of summands (addends). In other words, you need to represent the given number n as a sum of the least number of terms, each of which is a round number.

Input

The first line contains an integer t (1 ≤ t ≤ 10^4) — the number of test cases in the input. Then t test cases follow.

Each test case is a line containing an integer n (1 ≤ n ≤ 10^4).

Output

Print t answers to the test cases. Each answer must begin with an integer k — the minimum number of summands. Next, k terms must follow, each of which is a round number, and their sum is n. The terms can be printed in any order. If there are several answers, print any of them.

Example

Input


5
5009
7
9876
10000
10


Output


2
5000 9
1
7 
4
800 70 6 9000 
1
10000 
1
10 

Solution (in PYTHON3):

Solution:
# cook your dish here
# cook your dish here
import math,sys
import heapq
from fractions import Fraction
from collections import Counter,defaultdict
def li(): return list(map(int,sys.stdin.readline().split()))
def ls(): return list(map(int,list(input())))
def la(): return list(input())
def ii():  return int(input())
def dic(x): return defaultdict(lambda: x) 
def isPrime(n):
    i= 2
    if n == 1:
        return False
    while i <= int(math.sqrt(n)):
        if n%i == 0:
            return False
        i = i + 1
    return True
def gcd(a,b):
    if b == 0:
        return a
    return gcd(b,a%b)
def LCM(a,b): 
    return (a*b) / gcd(a,b) 
t = int(input())
for _ in range(t):
    n = int(input())
    a = []
    i= 0 
    for i in range(1,5):
        if n%(10**i) != 0:
            a.append(n%(10**i))
            n -= n%(10**i)
            if n== 0 :
                break
    if n != 0 :
        a.append(n)
    print(len(a))
    print(*a)