Problem: A positive (strictly greater than zero) integer is called round if it is of the form d00...0. In other words, a positive integer is round if all its digits except the leftmost (most significant) are equal to zero. In particular, all numbers from 1 to 9 (inclusive) are round.

For example, the following numbers are round: 4000, 1, 9, 800, 90. The following numbers are not round: 110, 707, 222, 1001.

You are given a positive integer n (1 ≤ n ≤ 10^4). Represent the number n as a sum of round numbers using the minimum number of summands (addends). In other words, you need to represent the given number n as a sum of the least number of terms, each of which is a round number.

Input

The first line contains an integer t (1 ≤ t ≤ 10^4) — the number of test cases in the input. Then t test cases follow.

Each test case is a line containing an integer n (1 ≤ n ≤ 10^4).

Output

Print t answers to the test cases. Each answer must begin with an integer k — the minimum number of summands. Next, k terms must follow, each of which is a round number, and their sum is n. The terms can be printed in any order. If there are several answers, print any of them.

Example

Input


5
5009
7
9876
10000
10


Output


2
5000 9
1
7 
4
800 70 6 9000 
1
10000 
1
10 

Solution (in PYTHON3):

Solution:
def is_round(n):
    s = str(n)
    for i in range(1, len(s)):
        if s[i]!="0":
            return False
    return True

def get_results(n):
    result = []
    s = str(n)
    while True:
        max_round = int(s[0]) * 10**(len(s)-1)
        result.append(max_round)
        n = n - max_round
        if n == 0:
            break
        if n<10:
            result.append(n)
            break
        s = str(n)
    return result



cas = int(input())
for t in range(cas):
    n = int(input())
    if n>=1 and n<=9:
        print(1)
        print(n)
    elif is_round(n):
        print(1)
        print(n)
    else:
        result = get_results(n)
        print(len(result))
        print(" ".join([str(c) for c in result]))