Problem: A positive (strictly greater than zero) integer is called round if it is of the form d00...0. In other words, a positive integer is round if all its digits except the leftmost (most significant) are equal to zero. In particular, all numbers from 1 to 9 (inclusive) are round.

For example, the following numbers are round: 4000, 1, 9, 800, 90. The following numbers are not round: 110, 707, 222, 1001.

You are given a positive integer n (1 ≤ n ≤ 10^4). Represent the number n as a sum of round numbers using the minimum number of summands (addends). In other words, you need to represent the given number n as a sum of the least number of terms, each of which is a round number.

Input

The first line contains an integer t (1 ≤ t ≤ 10^4) — the number of test cases in the input. Then t test cases follow.

Each test case is a line containing an integer n (1 ≤ n ≤ 10^4).

Output

Print t answers to the test cases. Each answer must begin with an integer k — the minimum number of summands. Next, k terms must follow, each of which is a round number, and their sum is n. The terms can be printed in any order. If there are several answers, print any of them.

Example

Input


5
5009
7
9876
10000
10


Output


2
5000 9
1
7 
4
800 70 6 9000 
1
10000 
1
10 

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.*;
import java.math.*;

public class A {

	public void realMain() throws Exception {

		BufferedReader fin = new BufferedReader(new InputStreamReader(System.in), 1000000);

		String in = fin.readLine();

		String[] ar = in.split(" ");

		int T = Integer.parseInt(ar[0]);
	for(int t = 0; t < T; t++) {
		
			int ret = 0;
			boolean dig = false;
			for (int ch = 0; (ch = fin.read()) != -1; ) {
        			if (ch >= '0' && ch <= '9') {
            				dig = true;
           				ret = ret * 10 + ch - '0';
        			} else if (dig) break;
    			}

			int n = ret;

			int numzeroes = 0;

			int numsum = 0;

			ArrayList<Integer> ans = new ArrayList<Integer>();

			while(n > 0) {
				if(n % 10 != 0) {
					int print = n % 10;
					print *= Math.pow(10, numzeroes);
					ans.add(print);
					numsum++;
				}
				numzeroes++;
				n /= 10;
			}

			System.out.println(numsum);
			for(int i = 0; i < numsum; i++) {
				System.out.print(ans.get(i) + " ");
			}
			System.out.println();
	}
			
		



	}


	public static void main(String[] args) throws Exception {
		A a = new A();
		a.realMain();
	}
}