Problem: A positive (strictly greater than zero) integer is called round if it is of the form d00...0. In other words, a positive integer is round if all its digits except the leftmost (most significant) are equal to zero. In particular, all numbers from 1 to 9 (inclusive) are round.

For example, the following numbers are round: 4000, 1, 9, 800, 90. The following numbers are not round: 110, 707, 222, 1001.

You are given a positive integer n (1 ≤ n ≤ 10^4). Represent the number n as a sum of round numbers using the minimum number of summands (addends). In other words, you need to represent the given number n as a sum of the least number of terms, each of which is a round number.

Input

The first line contains an integer t (1 ≤ t ≤ 10^4) — the number of test cases in the input. Then t test cases follow.

Each test case is a line containing an integer n (1 ≤ n ≤ 10^4).

Output

Print t answers to the test cases. Each answer must begin with an integer k — the minimum number of summands. Next, k terms must follow, each of which is a round number, and their sum is n. The terms can be printed in any order. If there are several answers, print any of them.

Example

Input


5
5009
7
9876
10000
10


Output


2
5000 9
1
7 
4
800 70 6 9000 
1
10000 
1
10 

Solution (in JAVA):

Solution:
import java.util.*;

public class Solution{
	static Scanner sc = new Scanner(System.in);
    public static void main(String[] args){
        int t = sc.nextInt();
        while(t-->0){
            solve();
        }
    }
    
    public static void solve(){
        int n = sc.nextInt();
        String sx = Integer.toString(n);
        int k = 0;
        for(int x = 0;x < sx.length();x++)
        	if(sx.charAt(x) != '0')k++;
        
        System.out.println(k);
        int i = 0;
        while(n > 0){
            int temp = n%10;
            if(temp != 0)System.out.print(temp * (int)Math.pow(10, i) + " ");
            n = n/10;
            i++;
        }
        
        System.out.println();
    }
}