Problem: A positive (strictly greater than zero) integer is called round if it is of the form d00...0. In other words, a positive integer is round if all its digits except the leftmost (most significant) are equal to zero. In particular, all numbers from 1 to 9 (inclusive) are round.

For example, the following numbers are round: 4000, 1, 9, 800, 90. The following numbers are not round: 110, 707, 222, 1001.

You are given a positive integer n (1 ≤ n ≤ 10^4). Represent the number n as a sum of round numbers using the minimum number of summands (addends). In other words, you need to represent the given number n as a sum of the least number of terms, each of which is a round number.

Input

The first line contains an integer t (1 ≤ t ≤ 10^4) — the number of test cases in the input. Then t test cases follow.

Each test case is a line containing an integer n (1 ≤ n ≤ 10^4).

Output

Print t answers to the test cases. Each answer must begin with an integer k — the minimum number of summands. Next, k terms must follow, each of which is a round number, and their sum is n. The terms can be printed in any order. If there are several answers, print any of them.

Example

Input


5
5009
7
9876
10000
10


Output


2
5000 9
1
7 
4
800 70 6 9000 
1
10000 
1
10 

Solution (in JAVA):

Solution:
import java.util.*;
public class Sum {
    
    public static void main (String[] args) {
        
        Scanner scan = new Scanner (System.in);
        int cases = scan.nextInt();
        for (int loop = 0; loop < cases; loop++) {
            
            int n = scan.nextInt();
            String x = Integer.toString(n);
            int count = 0;
            for (int i = 0; i < x.length(); i++) {
                
                if (x.charAt(i) != '0') {
                    
                    count++;
                }
            }
            System.out.println(count);
            for (int i = 0; i < x.length(); i++) {
                
                if (x.charAt(i) != '0') {
                    
                    System.out.println(Character.getNumericValue(x.charAt(i)) * (int)Math.pow(10, (x.length() - i - 1)));
                }
            }
            count = 0;
        }
    }
}