Problem: A positive (strictly greater than zero) integer is called round if it is of the form d00...0. In other words, a positive integer is round if all its digits except the leftmost (most significant) are equal to zero. In particular, all numbers from 1 to 9 (inclusive) are round.

For example, the following numbers are round: 4000, 1, 9, 800, 90. The following numbers are not round: 110, 707, 222, 1001.

You are given a positive integer n (1 ≤ n ≤ 10^4). Represent the number n as a sum of round numbers using the minimum number of summands (addends). In other words, you need to represent the given number n as a sum of the least number of terms, each of which is a round number.

Input

The first line contains an integer t (1 ≤ t ≤ 10^4) — the number of test cases in the input. Then t test cases follow.

Each test case is a line containing an integer n (1 ≤ n ≤ 10^4).

Output

Print t answers to the test cases. Each answer must begin with an integer k — the minimum number of summands. Next, k terms must follow, each of which is a round number, and their sum is n. The terms can be printed in any order. If there are several answers, print any of them.

Example

Input


5
5009
7
9876
10000
10


Output


2
5000 9
1
7 
4
800 70 6 9000 
1
10000 
1
10 

Solution (in PYTHON3):

Solution:
from sys import stdin
import math

a=int(stdin.readline())

for b in range(0,a):
    c=int(stdin.readline())
    C=str(c)
    count=0

    for e in C:
        if e!='0':
            count+=1
    print(count)

    while c>0:
        d=int(math.floor(math.log10(c)))
        if c-(10**d)*(int(math.floor(c/(10**d))))==0:
           print((10**d)*(int(math.floor(c/(10**d)))))
        else:
            print((10 ** d) * (int(math.floor(c / (10 ** d)))),end=' ')
        c-=(10**d)*(int(math.floor(c/(10**d))))