Problem: Requirements

* All inputs are of non-negative integer value.
* T_{\text{max}} = 10000
* 200 \leq |V| \leq 400
* 1.5 |V| \leq |E| \leq 2 |V|
* 1 \leq u_{i}, v_{i} \leq |V| (1 \leq i \leq |E|)
* 1 \leq d_{u_i, v_i} \leq \lceil 4\sqrt{2|V|} \rceil (1 \leq i \leq |E|)
* The given graph has no self-loops / multiple edges and is guaranteed to be connected.
* 0 \leq N_{\text{new}} \leq 1
* 1 \leq \mathrm{new\\_id}_{i} \leq T_{\text{last}}+1 (1 \leq i \leq N_{\text{new}}). Note: If all orders are generated by the order generation rule as explained above, the total number of orders is at most T_{\text{last}}+1. Therefore, the possible range of \mathrm{new\\_id}_{i} should be from 1 to T_{\text{last}}+1.
* 2 \leq \mathrm{dst}_i \leq |V| (1 \leq i \leq N_{\text{new}})
* The order IDs \mathrm{new\\_{id}}_i are unique.

Input Format

Input is provided in the following form:


|V| |E|
u_{1} v_{1} d_{u_{1}, v_{1}}
u_{2} v_{2} d_{u_{2}, v_{2}}
:
u_{|E|} v_{|E|} d_{u_{|E|}, v_{|E|}}
T_{\text{max}}
\mathrm{info}_{0}
\mathrm{info}_{1}
:
\mathrm{info}_{T_{\text{max}}-1}


* In the first line |V| denotes the number of vertices, while |E| denotes the number of edges.
* The following |E| lines denote the edges of the graph. In particular, in the ith line u_{i} and v_{i} denote the edge connecting u_{i} and v_{i} and d_{u_{i}, v_{i}} the corresponding distance.
* The following line denotes the number of steps T_{\text{max}}.



In the following line, \mathrm{info}_t is information about the order from the customer that occurs at time t. \mathrm{info}_t is given in the form:


N_{\text{new}}
\mathrm{new\_id}_1 \mathrm{dst}_1
\mathrm{new\_id}_2 \mathrm{dst}_2
\vdots
\mathrm{new\_id}_{N_{\text{new}}} \mathrm{dst}_{N_{\text{new}}}


* N_{\text{new}} represents the number of new orders which appear at time t.
* The next N_{\text{new}} lines give the newly generated order information. The i-th order information indicates that the order ID \mathrm{new\\_{id}}_i of the new order, while \mathrm{dst}_i denotes the vertex to which the customer wishes the order to be delivered.
* Note: If N_{\text{new}}=0, there are no new lines.

Output Format

The Output expects T_{\text{max}} integers in the format specified below.


\mathrm{command}_{0}
\mathrm{command}_{1}
:
\mathrm{command}_{T_{\text{max}}-1}


In particular, \mathrm{command}_{i} shall specify the movement of the delivery car by using one of the following two options:

1) `stay`, if the car shall not move:


-1


2) `move w`, if the car shall be moved one step towards the neighboring vertex w


w


Note that in case of 2) w has to satisfy the following conditions:

* w \in V
* If the car is at vertex u: \left\\{ u, w \right\\} \in E .
* If the car is on the edge \left\\{ u, v \right\\}, w must either satisfy u = w or v = w.



* * *

Examples

Input




Output




Input

5 7
1 2 5
5 3 4
2 4 8
1 5 1
2 3 3
4 5 3
4 3 9
4
1
1 2
1
2 5
1
3 4
0


Output

2
-1
1
5

Solution (in CPP):

Solution:
#include "bits/stdc++.h"
#define in std::cin
#define out std::cout
#define rep(i,N) for(LL i=0;i<N;++i)
typedef long long int LL;

const LL inf = 11234567890;
std::vector<std::vector<LL>>dist;

void warshall_floyd(LL V)
{
	for (LL k = 1; k <= V; ++k) for (LL i = 1; i <= V; ++i) for (LL j = 1; j <= V; ++j) dist[i][j] = std::min(dist[i][j], dist[i][k] + dist[k][j]);
}

int main()
{
	LL V, E, T_max;
	in >> V >> E;
	std::vector<LL>u(E), v(E), d(E);
	rep(i, E) in >> u[i] >> v[i] >> d[i];
	in >> T_max;
	std::vector<std::vector<std::pair<LL, LL>>>info(T_max);
	rep(i, T_max)
	{
		LL N_new;
		in >> N_new;
		rep(j, N_new)
		{
			LL new_id, dst;
			in >> new_id >> dst;
			info[i].push_back(std::make_pair(new_id, dst));
		}
	}

	std::vector<std::vector<std::pair<LL, LL>>>G(V + 1);
	dist.resize(V + 1, std::vector<LL>(V + 1, inf));
	rep(i, E)
	{
		G[u[i]].push_back(std::make_pair(v[i], d[i]));
		G[v[i]].push_back(std::make_pair(u[i], d[i]));
		dist[u[i]][v[i]] = dist[v[i]][u[i]] = d[i];
	}
	warshall_floyd(V);

	bool moving = false, reached = false;
	LL now, dst, c;
	std::pair<LL, LL>edge;
	rep(t, T_max)
	{
		LL command = -2;
		if (!moving)
		{
			if (info[t].empty()) command = -1;
			else
			{
				now = 1;
				dst = info[t][0].second;
				c = 0;

				LL minD = inf;
				for (auto e : G[now])
				{
					LL d = dist[now][e.second] + dist[e.second][dst];
					if (d < minD)
					{
						minD = d;
						edge = e;
					}
				}
				moving = true;
				reached = false;
			}
		}
		else
		{
			if (c == edge.second)
			{
				now = edge.first;
				c = 0;
				if (now == 1 && reached)
				{
					moving = false;
					continue;
				}
				if (now == dst)
				{
					dst = 1;
					reached = true;
				}

				LL minD = inf;
				for (auto e : G[now])
				{
					LL d = dist[now][e.second] + dist[e.second][dst];
					if (d < minD)
					{
						minD = d;
						edge = e;
					}
				}
			}
			else
			{
				command = edge.first;
				++c;
			}
		}
		if (command != -2) out << command << std::endl;
		else --t;
	}
}