Problem: A positive (strictly greater than zero) integer is called round if it is of the form d00...0. In other words, a positive integer is round if all its digits except the leftmost (most significant) are equal to zero. In particular, all numbers from 1 to 9 (inclusive) are round.

For example, the following numbers are round: 4000, 1, 9, 800, 90. The following numbers are not round: 110, 707, 222, 1001.

You are given a positive integer n (1 ≤ n ≤ 10^4). Represent the number n as a sum of round numbers using the minimum number of summands (addends). In other words, you need to represent the given number n as a sum of the least number of terms, each of which is a round number.

Input

The first line contains an integer t (1 ≤ t ≤ 10^4) — the number of test cases in the input. Then t test cases follow.

Each test case is a line containing an integer n (1 ≤ n ≤ 10^4).

Output

Print t answers to the test cases. Each answer must begin with an integer k — the minimum number of summands. Next, k terms must follow, each of which is a round number, and their sum is n. The terms can be printed in any order. If there are several answers, print any of them.

Example

Input


5
5009
7
9876
10000
10


Output


2
5000 9
1
7 
4
800 70 6 9000 
1
10000 
1
10 

Solution (in PYTHON3):

Solution:
def count1(n):
    n = str(n)
    ans = 0
    for i in range(len(n)):
        if n[i] != '0':
            ans+=1
    return ans
t = int(input())
for _ in range(t):
    n = int(input())
    ans1 = []
    if 1 <= n<= 10:
        print(1)
        print(n)
    else:
        for i in range(len(str(n))):
            if str(n)[i] == '0':
                continue
            else:
                pos = len(str(n))-i
                if i == 0:
                    count = pos - i - 1
                else:
                    count = pos - 1
                ans1.append(str(n)[i]+'0'*count)
        print(count1(str(n)))
        print(*ans1)