Problem: Bizon the Champion isn't just friendly, he also is a rigorous coder.

Let's define function f(a), where a is a sequence of integers. Function f(a) returns the following sequence: first all divisors of a1 go in the increasing order, then all divisors of a2 go in the increasing order, and so on till the last element of sequence a. For example, f([2, 9, 1]) = [1, 2, 1, 3, 9, 1].

Let's determine the sequence Xi, for integer i (i ≥ 0): X0 = [X] ([X] is a sequence consisting of a single number X), Xi = f(Xi - 1) (i > 0). For example, at X = 6 we get X0 = [6], X1 = [1, 2, 3, 6], X2 = [1, 1, 2, 1, 3, 1, 2, 3, 6].

Given the numbers X and k, find the sequence Xk. As the answer can be rather large, find only the first 105 elements of this sequence.

Input

A single line contains two space-separated integers — X (1 ≤ X ≤ 1012) and k (0 ≤ k ≤ 1018).

Output

Print the elements of the sequence Xk in a single line, separated by a space. If the number of elements exceeds 105, then print only the first 105 elements.

Examples

Input

6 1


Output

1 2 3 6 


Input

4 2


Output

1 1 2 1 2 4 


Input

10 3


Output

1 1 1 2 1 1 5 1 1 2 1 5 1 2 5 10 

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
const double pi = acos(-1.0);
const long long mod = 1e9 + 7;
long long dy[4] = {1, 0, -1, 0};
long long dx[4] = {0, 1, 0, -1};
template <class T>
inline bool chmax(T& a, T b) {
  if (a < b) {
    a = b;
    return true;
  }
  return false;
}
template <class T>
inline bool chmin(T& a, T b) {
  if (a > b) {
    a = b;
    return true;
  }
  return false;
}
template <class A, class B>
ostream& operator<<(ostream& ost, const pair<A, B>& p) {
  ost << "{" << p.first << ", " << p.second << "} ";
  return ost;
}
template <class T>
ostream& operator<<(ostream& ost, const vector<T>& v) {
  ost << "{";
  for (int i = 0; i < v.size(); i++) {
    if (i) ost << ", ";
    ost << v[i];
  }
  ost << "} ";
  return ost;
}
template <class A, class B>
ostream& operator<<(ostream& ost, const map<A, B>& v) {
  ost << "{";
  for (auto p : v) {
    ost << "{" << p.first << ", " << p.second << "} ";
  }
  ost << "} ";
  return ost;
}
bool out_check(long long a, long long b) { return (0 <= a && a < b); }
void addmod(long long& a, long long& b) { a = (a + b) % mod; }
double pitagoras(long long a, long long b, long long c, long long d) {
  double dx = a - b, dy = c - d;
  return pow(dx * dx + dy * dy, 0.5);
}
long long powmod(long long a, long long b) {
  long long c = 1;
  while (b > 0) {
    if (b & 1) {
      c = a * c % mod;
    }
    a = a * a % mod;
    b >>= 1;
  }
  return c;
}
void Yes(bool x) { cout << ((x) ? "Yes\n" : "No\n"); }
void YES(bool x) { cout << ((x) ? "YES\n" : "NO\n"); }
void yes(bool x) { cout << ((x) ? "yes\n" : "no\n"); }
void Yay(bool x) { cout << ((x) ? "Yay!\n" : ":(\n"); }
vector<string> DAY = {"SUN", "MON", "TUE", "WED", "THU", "FRI", "SAT"};
long long n, m, d, e, r, l, k, h, Q, ans, ret = LLONG_MAX;
bool flag = false, flag2 = false, flag3 = false;
string s, t, u;
vector<long long> divisor(long long n) {
  vector<long long> w;
  for (long long i = 1; i * i <= n; ++i) {
    if (n % i == 0) {
      w.push_back(i);
      if (i * i != n) {
        w.push_back(n / i);
      }
    }
  }
  sort(w.begin(), w.end());
  return w;
}
vector<long long> rec;
map<long long, long long> ma;
vector<vector<long long> > num;
void calc(long long v, long long k) {
  if (k == 0) {
    if (rec.size() < 1e5) rec.emplace_back(v);
    return;
  }
  long long x = ma[v];
  for (auto N : num[x]) {
    if (rec.size() >= 1e5) return;
    if (N == 1)
      rec.emplace_back(1);
    else
      calc(N, k - 1);
  }
}
int main() {
  long long x;
  cin >> x >> k;
  if (x == 1) {
    puts("1");
    return 0;
  }
  if (k >= 1e5) {
    for (int i = 0; i < 1e5; ++i) cout << "1 ";
    puts("");
    return 0;
  }
  auto v = divisor(x);
  num.resize(v.size());
  for (int i = 0; i < v.size(); ++i) {
    ma[v[i]] = i;
    num[i] = divisor(v[i]);
  }
  calc(x, k);
  for (int i = 0; i < min((size_t)1e5, rec.size()); ++i) cout << rec[i] << " ";
  puts("");
}