Problem: A positive (strictly greater than zero) integer is called round if it is of the form d00...0. In other words, a positive integer is round if all its digits except the leftmost (most significant) are equal to zero. In particular, all numbers from 1 to 9 (inclusive) are round.

For example, the following numbers are round: 4000, 1, 9, 800, 90. The following numbers are not round: 110, 707, 222, 1001.

You are given a positive integer n (1 ≤ n ≤ 10^4). Represent the number n as a sum of round numbers using the minimum number of summands (addends). In other words, you need to represent the given number n as a sum of the least number of terms, each of which is a round number.

Input

The first line contains an integer t (1 ≤ t ≤ 10^4) — the number of test cases in the input. Then t test cases follow.

Each test case is a line containing an integer n (1 ≤ n ≤ 10^4).

Output

Print t answers to the test cases. Each answer must begin with an integer k — the minimum number of summands. Next, k terms must follow, each of which is a round number, and their sum is n. The terms can be printed in any order. If there are several answers, print any of them.

Example

Input


5
5009
7
9876
10000
10


Output


2
5000 9
1
7 
4
800 70 6 9000 
1
10000 
1
10 

Solution (in PYTHON):

Solution:
from sys import stdin,stdout
from collections import defaultdict as dd
from math import log
read,write = stdin.readline,stdout.write
iread = lambda: int(read())
sread = lambda: read().strip()
spread = lambda func=int: map(func,read().split())

t = iread()
for _ in xrange(t):
    n = iread()
    
    numbers = []
    while n:
        if n < 10:
            numbers.append(n)
            break
        exp = int(log(n,10))
        num = 10**exp * int(n/(10**exp))
        n -= num
        numbers.append(num)
    
    print len(numbers)
    print ' '.join(map(str,numbers))