Problem: A positive (strictly greater than zero) integer is called round if it is of the form d00...0. In other words, a positive integer is round if all its digits except the leftmost (most significant) are equal to zero. In particular, all numbers from 1 to 9 (inclusive) are round.

For example, the following numbers are round: 4000, 1, 9, 800, 90. The following numbers are not round: 110, 707, 222, 1001.

You are given a positive integer n (1 ≤ n ≤ 10^4). Represent the number n as a sum of round numbers using the minimum number of summands (addends). In other words, you need to represent the given number n as a sum of the least number of terms, each of which is a round number.

Input

The first line contains an integer t (1 ≤ t ≤ 10^4) — the number of test cases in the input. Then t test cases follow.

Each test case is a line containing an integer n (1 ≤ n ≤ 10^4).

Output

Print t answers to the test cases. Each answer must begin with an integer k — the minimum number of summands. Next, k terms must follow, each of which is a round number, and their sum is n. The terms can be printed in any order. If there are several answers, print any of them.

Example

Input


5
5009
7
9876
10000
10


Output


2
5000 9
1
7 
4
800 70 6 9000 
1
10000 
1
10 

Solution (in PYTHON3):

Solution:
def isround(n):
    k=1
    if n[0] != '0':
        for i in range(1,len(n)):
            if n[i] != '0':
                k=0
                break
    else:
        k=0
    return k

def ifnotround(a):
    global count
    string=''
    l=len(a)-1
    for i in a:
        if i!='0':
            string +=str(int(i)*(pow(10,l)))
            string += ' '
            count+=1
        l-=1
    print(count)
    print(string)

def main():
    global count
    a=input()
    if isround(a) ==1:
        print('1',a,sep='\n')
    else:
        ifnotround(a)

count=0
n=int(input())
for i in range(n):
    count=0
    main()