Problem: Find places where a R × C pattern is found within a H × W region. Print top-left coordinates (i, j) of sub-regions where the pattern found. The top-left and bottom-right coordinates of the region is (0, 0) and (H-1, W-1) respectively.

Constraints

* 1 ≤ H, W ≤ 1000
* 1 ≤ R, C ≤ 1000
* The input consists of alphabetical characters and digits

Input

In the first line, two integers H and W are given. In the following H lines, i-th lines of the region are given.

In the next line, two integers R and C are given. In the following R lines, i-th lines of the pattern are given.

Example

Input

4 5
00010
00101
00010
00100
3 2
10
01
10


Output

0 3
1 2

Solution (in CPP):

Solution:
#include<iostream>
#include<vector>
#include<algorithm>
#include<string>
#include<cctype>
#include<cstdio>
#include<cassert>
    
    
using namespace std;
    
struct AhoCorasick {
    
  static const int ALPHABET_SIZE = 62, root=0;
    
  inline int index(char ch){
    if(isupper(ch))return ch-'A';
    if(islower(ch))return 26+ch-'a';
    if(isdigit(ch))return 52+ch-'0';
    assert(false);
    return -1;
  }
      
  int N; // num of node
    
  struct Node {
    int parent, link;
    int child[ALPHABET_SIZE], next[ALPHABET_SIZE];
    char ch;
    bool leaf;
    
    Node():parent(0),link(0),ch('\0'),leaf(false){
      link=-1;
      fill(child,child+ALPHABET_SIZE,-1);
      fill(next,next+ALPHABET_SIZE,-1);
    }
  };
    
  vector<Node> nodes;
    
  AhoCorasick(int maxNodes):N(1),nodes(maxNodes){
    nodes[root].link = root;
    nodes[root].parent = -1;
  }
    
  void add(string s) {
    int cur = 0, sl=s.size();
    for(int i=0;i<sl;i++){
      char ch = s[i];
      int c = index(ch);
      if(!~nodes[cur].child[c]){
    nodes[N].parent = cur;
    nodes[N].ch = ch;
    nodes[cur].child[c] = N++;
      }
      cur = nodes[cur].child[c];
    }
    nodes[cur].leaf = true;
  }
    
  int failure(int id) {
    Node& node = nodes[id];
    if(node.link == -1){
      if(!node.parent)node.link=root;
      else node.link=go(failure(node.parent),node.ch);
    }
    return node.link;
  }
    
  int go(int id, char ch) {
    int c = index(ch);
    Node& node = nodes[id];
    if(node.next[c] == -1){
      if(node.child[c] != -1)node.next[c]=node.child[c];
      else if(!id)node.next[c]=root;
      else node.next[c]=go(failure(id),ch);
    }
    return node.next[c];
  }
};

typedef pair<int,int> pii;
    
vector<pii> bakerBird(const vector<string>&T, const vector<string>&pattern){
  int pl=pattern.size(),tl=T.size(),pil=pattern[0].size();
  AhoCorasick aho(500000);
    
  for(int i=0;i<pl;i++)aho.add(pattern[i]);
      
  vector<int>acc;
  for(int i=0;i<pl;i++){
    int node = 0;
    for(int j=0;j<pil;j++){
      node = aho.go(node, pattern[i][j]);
      if(aho.nodes[node].leaf)acc.push_back(node);
    }
  }
    
  const int til = T[0].size();
      
  int td[til][tl];
  for(int i=0;i<tl;i++){
    int node = 0;
    for(int j=0;j<til;j++){
      node = aho.go(node, T[i][j]);
      td[til-j-1][i]=node;
    }
  }
    
  vector<pii>res;
  int tl2=acc.size(),sl=acc.size()+tl+1;
  vector<int>a(acc.size()+tl+2,-1);
  for(int i=0;i<til;i++){
    vector<int>s=acc;
    s.push_back(-1);
    for(int j=0;j<til;j++)s.push_back(td[i][j]);
    for(int k=0,j=-1;k<sl;a[++k]=++j)while(j>=0 && s[k]!=s[j])j=a[j];
    for(int k=tl2+1;k<=sl;k++){
      if(a[k]==tl2)res.push_back(pii(k-tl2*2-1,til-i-pil));
    }
  }
  return res;
}
    
int main(void){
  int h,w,r,c;
      
  cin >> h >> w;
  vector<string>s(h);
  for(int i=0;i<h;i++){
    s[i].resize(w);
    for(int j=0;j<w;j++){
      scanf(" %c",&s[i][j]);
    }
  }
  cin >> r >> c;
  vector<string>t(r);
  for(int i=0;i<r;i++){
    t[i].resize(c);
    for(int j=0;j<c;j++){
      scanf(" %c",&t[i][j]);
    }
  }
  vector<pii>res=bakerBird(s,t);
  sort(res.begin(),res.end());
    
  for(int i=0;i<res.size();i++)
    cout << res[i].first << " " << res[i].second << "\n";
    
  return 0;
}