Problem: A positive (strictly greater than zero) integer is called round if it is of the form d00...0. In other words, a positive integer is round if all its digits except the leftmost (most significant) are equal to zero. In particular, all numbers from 1 to 9 (inclusive) are round.

For example, the following numbers are round: 4000, 1, 9, 800, 90. The following numbers are not round: 110, 707, 222, 1001.

You are given a positive integer n (1 ≤ n ≤ 10^4). Represent the number n as a sum of round numbers using the minimum number of summands (addends). In other words, you need to represent the given number n as a sum of the least number of terms, each of which is a round number.

Input

The first line contains an integer t (1 ≤ t ≤ 10^4) — the number of test cases in the input. Then t test cases follow.

Each test case is a line containing an integer n (1 ≤ n ≤ 10^4).

Output

Print t answers to the test cases. Each answer must begin with an integer k — the minimum number of summands. Next, k terms must follow, each of which is a round number, and their sum is n. The terms can be printed in any order. If there are several answers, print any of them.

Example

Input


5
5009
7
9876
10000
10


Output


2
5000 9
1
7 
4
800 70 6 9000 
1
10000 
1
10 

Solution (in JAVA):

Solution:
//package com.company;


import java.util.ArrayList;
import java.util.LinkedList;
import java.util.Scanner;

public class Main {

    public static void main(String[] args) {
//        ArrayList<Integer> list = new ArrayList<>();
//        LinkedList<Integer> linkedList = new LinkedList<>();
//        StringBuilder stringBuilder = new StringBuilder();
        Scanner scanner = new Scanner(System.in);
        int t = scanner.nextInt();
        for(int i = 0 ; i<t;i++) {
            int x = scanner.nextInt();
            int ans = 0;
            int k = x % 10;
            if (k > 0) {
                ans++;
            }
            int l = (x / 10) % 10;
            if (l > 0) {
                ans++;
            }
            int m = (x / 100) % 10;
            if (m > 0) {
                ans++;
            }
            int o = (x / 1000);
            if (o > 0) {
                ans++;
            }
            System.out.println(ans);
            if (o != 0 ) {
                System.out.print(o * 1000 +" ");
            }
            if(m!=0){
                System.out.print(m * 100 + " ");
            }
            if(l!=0){
                System.out.print(l * 10 + " ");
            }
            if(k!=0){
                System.out.print(k + " ");
            }
            System.out.println();
        }
    }
}