Problem: Try guessing the statement from this picture: 

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You are given a non-negative integer d. You have to find two non-negative real numbers a and b such that a + b = d and a ⋅ b = d.

Input

The first line contains t (1 ≤ t ≤ 10^3) — the number of test cases.

Each test case contains one integer d (0 ≤ d ≤ 10^3).

Output

For each test print one line.

If there is an answer for the i-th test, print "Y", and then the numbers a and b.

If there is no answer for the i-th test, print "N".

Your answer will be considered correct if |(a + b) - a ⋅ b| ≤ 10^{-6} and |(a + b) - d| ≤ 10^{-6}.

Example

Input


7
69
0
1
4
5
999
1000


Output


Y 67.985071301 1.014928699
Y 0.000000000 0.000000000
N
Y 2.000000000 2.000000000
Y 3.618033989 1.381966011
Y 997.998996990 1.001003010
Y 998.998997995 1.001002005

Solution (in JAVA):

Solution:
import java.util.*;
public class susbus{
   public static void main(String[] args){
      Scanner sc = new Scanner(System.in);
      int t = sc.nextInt();
      int [] bayus = new int[t];
      for (int i=0;i<t;i++){
         bayus[i] = sc.nextInt();
      }
      for (int i=0;i<t;i++){
      if(bayus[i]>=4 || bayus[i]<=0){
         int n = bayus[i];
         double asdf = Math.sqrt(n*n-4*n);
         double sol1 = (n+asdf)/2;
         double sol2 = (n-asdf)/2;
         System.out.println("Y"+" "+sol1+" "+ sol2);
      }
      else {
         System.out.println("N");
      }
      //(n+sqrt(n^2-4n))/2
      //(n-sqrt(n^2-4n))/2
   }
   }
   
}