Problem: A positive (strictly greater than zero) integer is called round if it is of the form d00...0. In other words, a positive integer is round if all its digits except the leftmost (most significant) are equal to zero. In particular, all numbers from 1 to 9 (inclusive) are round.

For example, the following numbers are round: 4000, 1, 9, 800, 90. The following numbers are not round: 110, 707, 222, 1001.

You are given a positive integer n (1 ≤ n ≤ 10^4). Represent the number n as a sum of round numbers using the minimum number of summands (addends). In other words, you need to represent the given number n as a sum of the least number of terms, each of which is a round number.

Input

The first line contains an integer t (1 ≤ t ≤ 10^4) — the number of test cases in the input. Then t test cases follow.

Each test case is a line containing an integer n (1 ≤ n ≤ 10^4).

Output

Print t answers to the test cases. Each answer must begin with an integer k — the minimum number of summands. Next, k terms must follow, each of which is a round number, and their sum is n. The terms can be printed in any order. If there are several answers, print any of them.

Example

Input


5
5009
7
9876
10000
10


Output


2
5000 9
1
7 
4
800 70 6 9000 
1
10000 
1
10 

Solution (in PYTHON3):

Solution:
import sys

def read_int():
    return int(sys.stdin.readline())

def read_ints():
    return list(map(int, sys.stdin.readline().split()))

t = read_int()
# t = 5

input1 = [5009, 7, 9876, 10000, 10]
for j in range(t):
    # value = input1[j]
    value = read_int()
    s = list(str(value))
    l = len(s)
    lst = []
    for ind, c in enumerate(s):
        if c is not '0':
            chislo = [c]
            chislo.extend(['0']*(l-ind-1))
            lst.append(int(''.join(chislo)))
    print(len(lst))
    for i in lst:
        print(i, end=" ")