Problem: Silver Fox is fighting with N monsters.

The monsters are standing in a row, and we can assume them to be standing on a number line. The i-th monster, standing at the coordinate X_i, has the health of H_i.

Silver Fox can use bombs to attack the monsters. Using a bomb at the coordinate x decreases the healths of all monsters between the coordinates x-D and x+D (inclusive) by A. There is no way other than bombs to decrease the monster's health.

Silver Fox wins when all the monsters' healths become 0 or below.

Find the minimum number of bombs needed to win.

Constraints

* 1 \leq N \leq 2 \times 10^5
* 0 \leq D \leq 10^9
* 1 \leq A \leq 10^9
* 0 \leq X_i \leq 10^9
* 1 \leq H_i \leq 10^9
* X_i are distinct.
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N D A
X_1 H_1
:
X_N H_N


Output

Print the minimum number of bombs needed to win.

Examples

Input

3 3 2
1 2
5 4
9 2


Output

2


Input

9 4 1
1 5
2 4
3 3
4 2
5 1
6 2
7 3
8 4
9 5


Output

5


Input

3 0 1
300000000 1000000000
100000000 1000000000
200000000 1000000000


Output

3000000000

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
using ll = long long;

const int MAX_N = 2e5+10;
int N, D, A;
pair<ll,ll> v[MAX_N];
ll damage[MAX_N];

void solve()
{
	sort(v,v+N);
	ll ans = 0;
	for(int i=0;i<N;++i){
		if(i>0) damage[i]+=damage[i-1];
		if(damage[i]>=v[i].second) continue;
		const ll b = 1LL*(v[i].second-damage[i]+A-1)/A;
		ans += b;
		int j = upper_bound(v, v+N, make_pair(v[i].first+2LL*D,1LL<<60))-v;
		damage[i]+=b*A, damage[j]-=b*A;
	}
	cout<<ans;
}

int main()
{
	cin >> N >> D >> A;
	for(int i=0;i<N;++i) cin >> v[i].first >> v[i].second;
	solve();
	return 0;
}