Problem: Read a set of coordinates of three different points P1 (x1, y1), P2 (x2, y2), Q (xq, yq) on the plane, and line symmetry with point Q with the straight line passing through point P1 point P2 as the axis of symmetry. Create a program that outputs the point R (x, y) at the position of. Note that the point Q is not on its axis of symmetry.

<image>



input

The input consists of multiple datasets. Each dataset is given in the following format:


x1, y1, x2, y2, xq, yq


x1, y1, x2, y2, xq, yq (real numbers between -100 and 100) are given on one line separated by commas.

The number of datasets does not exceed 50.

output

Print x, y on a single line, separated by blanks, for each dataset. The output may contain an error of 0.0001 or less in real numbers.

Example

Input

1.0,0.0,-1.0,0.0,1.0,1.0
1.0,0.0,0.0,-1.0,3.0,0.0
0.0,1.0,0.0,-1.0,1.0,1.0


Output

1.000000 -1.000000
1.000000 2.000000
-1.000000 1.000000

Solution (in CPP):

Solution:
#include <bits/stdc++.h>

using namespace std;

namespace geometry
{	
	typedef double D;
	typedef complex<D> P;
	typedef pair<P, P> S;
	typedef S L;
	typedef pair<P, D> C;
	typedef vector<P> Poly;
	
	#define EPS 		(1e-10)
	#define EQ(a, b) 	(abs((a) - (b)) < EPS)
	#define EQV(a, b) 	(EQ((a).real(), (b).real()) && EQ((a).imag(), (b).imag()))
	
	D norm(P a) { return a.real() * a.real() + a.imag() * a.imag(); }
	
	D dot(P a, P b) { return a.real() * b.real() + a.imag() * b.imag(); }
	D cross(P a, P b) { return a.real() * b.imag() - a.imag() * b.real(); }
	
	bool isOrthogonal(P a1, P a2, P b1, P b2) { return EQ(dot(a1 - a2, b1 - b2), 0.0); }
	bool isOrthogonal(L a, L b) { return isOrthogonal(a.first, a.second, b.first, b.second); }
	bool isParallel(P a1, P a2, P b1, P b2) { return EQ(cross(a1 - a2, b1 - b2), 0.0); }
	bool isParallel(L a, L b) { return isParallel(a.first, a.second, b.first, b.second); }
	
	bool isPointOnLine(P a, P b, P c) { return EQ(cross(b - a, c - a), 0.0); }
	bool isPointOnLine(L a, P b) { return isPointOnLine(a.first, a.second, b); }
	bool isPointOnSegment(P a, P b, P c) {
		return EQ(cross(b - a, c - a), 0.0) &&
		       (dot(b - a, c - a) > -EPS) &&
			   (dot(a - b, c - b) > -EPS);
	}
	bool isPointOnSegment(S a, P b) { return isPointOnLine(a.first, a.second, b); }
	
	D distanceLP(P a, P b, P c) { return abs(cross(b - a, c - a)) / abs(b - a); }
	D distanceLP(L a, P b) { return distanceLP(a.first, a.second, b); }
	D distanceSP(P a, P b, P c) {
		if (dot(b - a, c - a) < EPS) return abs(c - a);
		if (dot(a - b, c - b) < EPS) return abs(c - b);
		return abs(cross(b - a, c - a)) / abs(b - a);
	}
	D distanceSP(S a, P b) { return distanceSP(a.first, a.second, b); }
	
	bool intersect(P a1, P a2, P b1, P b2) {
		return (cross(a2 - a1, b1 - a1) * cross(a2 - a1, b2 - a1) < EPS) &&
		       (cross(b2 - b1, a1 - b1) * cross(b1 - b1, a2 - b1) < EPS);
	}
	bool intersect(S a, S b){
		return intersect(a.first, a.second, b.first, b.second);
	}
	
	P project(S s, P p){
		P base = s.second - s.first;
		D r = dot(p - s.first, base) / (norm(base));
		return s.first + base * r;
	}
	P reflect(S s, P p){
		return p + (project(s, p) - p) * 2.0;
	}
}

using namespace geometry;

int main()
{
	D x1, y1, x2, y2, xq, yq;
	while (~scanf("%lf,%lf,%lf,%lf,%lf,%lf", &x1, &y1, &x2, &y2, &xq, &yq)){
		S s( P(x1, y1), P(x2, y2) );
		P p = reflect(s, P(xq, yq));
		printf("%f %f\n", p.real(), p.imag());
	}
}