Problem: Silver Fox is fighting with N monsters.

The monsters are standing in a row, and we can assume them to be standing on a number line. The i-th monster, standing at the coordinate X_i, has the health of H_i.

Silver Fox can use bombs to attack the monsters. Using a bomb at the coordinate x decreases the healths of all monsters between the coordinates x-D and x+D (inclusive) by A. There is no way other than bombs to decrease the monster's health.

Silver Fox wins when all the monsters' healths become 0 or below.

Find the minimum number of bombs needed to win.

Constraints

* 1 \leq N \leq 2 \times 10^5
* 0 \leq D \leq 10^9
* 1 \leq A \leq 10^9
* 0 \leq X_i \leq 10^9
* 1 \leq H_i \leq 10^9
* X_i are distinct.
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N D A
X_1 H_1
:
X_N H_N


Output

Print the minimum number of bombs needed to win.

Examples

Input

3 3 2
1 2
5 4
9 2


Output

2


Input

9 4 1
1 5
2 4
3 3
4 2
5 1
6 2
7 3
8 4
9 5


Output

5


Input

3 0 1
300000000 1000000000
100000000 1000000000
200000000 1000000000


Output

3000000000

Solution (in PYTHON3):

Solution:
from itertools import accumulate
import math
import bisect

n,d,a = map(int,input().split())
xh = [tuple(map(int,input().split())) for _ in range(n)]
xh.sort()
x = [xh[i][0] for i in range(n)]
h = [xh[i][1] for i in range(n)]
damage = [0]*(n+1)
point = 0

for i in range(n):
    if i != 0:
        damage[i] += damage[i-1]
    bi = bisect.bisect(x,2*d+x[i])
    count = max(math.ceil((h[i]-damage[i])/a),0)
    damage[i] += a*count
    damage[bi] -= a*count
    point += count
    
print(point)