Problem: Nastya is a competitive programmer, but she is only studying now. Recently, Denis told her about the way to check if the string is correct bracket sequence. After that, unexpectedly, Nastya came up with a much more complex problem that Denis couldn't solve. Can you solve it? 

A string s is given. It consists of k kinds of pairs of brackets. Each bracket has the form t — it is an integer, such that 1 ≤ |t| ≤ k. If the bracket has a form t, then: 

  * If t > 0, then it's an opening bracket of the type t. 
  * If t < 0, then it's a closing bracket of the type -t. 



Thus, there are k types of pairs of brackets in total. 

The queries need to be answered: 

  1. Replace the bracket at position i with the bracket of the form t. 
  2. Check if the substring from the l-th to r-th position (including) is the correct bracket sequence. 

Recall the definition of the correct bracket sequence: 
  * An empty sequence is correct. 
  * If A and B are two correct bracket sequences, then their concatenation "A B" is also correct bracket sequence. 
  * If A is the correct bracket sequence, c (1 ≤ c ≤ k) is a type of brackets, then the sequence "c A -c" is also correct bracket sequence. 

Input

The first line contains an integer n (1 ≤ n ≤ 10^5) — length of string and k (1 ≤ k ≤ n) — the number of kinds of pairs of brackets.

The second line contains string s of length n — n integers s_1, s_2, …, s_n (1 ≤ |s_i| ≤ k)

The third line contains single integer q (1 ≤ q ≤ 10^5) — the number of queries.

Each of the following q lines describes the queries: 

  * 1 i t - query of the 1 type (1 ≤ i ≤ n, 1 ≤ |t| ≤ k). 
  * 2 l r - query of the 2 type (1 ≤ l ≤ r ≤ n). 

Output

For each query of 2 type, output "Yes" if the substring from the query is the correct bracket sequence and "No", otherwise.

All letters can be displayed in any case.

Examples

Input


2 1
1 -1
1
2 1 2


Output


Yes


Input


2 2
1 -2
1
2 1 2


Output


No


Input


6 2
1 2 -2 -1 1 -1
3
2 1 6
2 1 4
2 2 5


Output


Yes
Yes
No


Input


2 2
-1 1
4
2 1 2
1 1 1
1 2 -1
2 1 2


Output


No
Yes

Note

In the fourth test, initially, the string is not a correct bracket sequence, so the answer to the first query is "No". After two changes it will be equal to "1 -1", so it is a correct bracket sequence and the answer to the fourth query is "Yes".

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
#pragma GCC optimize("O3")
#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx")
using namespace std;
static unsigned rnd() {
  static unsigned second = 124612741;
  second ^= second << 13;
  second ^= second >> 17;
  return second ^= second << 5;
}
inline int fpow(int a, int st, int mod) {
  int ans = 1;
  while (st) {
    if (st % 2) ans = (long long)ans * a % mod;
    a = (long long)a * a % mod;
    st /= 2;
  }
  return ans;
}
int invmod(int first, int second) {
  int a = 1, b = 0, k;
  for (; second; swap(first, second), swap(a, b)) {
    k = first / second;
    first -= second * k;
    a -= b * k;
  }
  return a + max(b, 0);
}
inline int calcBits(int a) { return __builtin_popcount(a); }
struct Hash {
  Hash() : x1(0), x2(0) {}
  Hash(const int& x1, const int& x2) : x1(x1), x2(x2) {}
  int x1, x2;
  static int mod1, mod2;
  static int p1, p2;
  static int invp1, invp2;
  static bool initCalled;
  static const Hash ONE, ZERO, INVALID;
  static Hash UNIT, INV_UNIT;
  static bool prime(int a) {
    if (a == 1) return 0;
    for (int i = 2; i * i <= a; ++i) {
      if (a % i == 0) return false;
    }
    return true;
  }
  static int pickModHelper(int start, int bad) {
    int mn = 1000000000, best = -1;
    for (int _n(start + 5000), i(start); i <= _n; i++) {
      if (i == bad || !prime(i)) continue;
      int cur = calcBits(i);
      if (cur < mn) {
        mn = cur;
        best = i;
      }
    }
    return best;
  }
  static void init() {
    if (initCalled) return;
    initCalled = true;
    mod1 = pickModHelper(1000000000 + rnd() % 10000000, -1);
    mod2 = pickModHelper(1000000000 + rnd() % 10000000, mod1);
    invp1 = invmod(p1, mod1);
    invp2 = invmod(p2, mod2);
    INV_UNIT = Hash(invp1, invp2);
  }
  inline Hash& operator+=(const Hash& other) {
    x1 += other.x1;
    if (x1 >= Hash::mod1) x1 -= Hash::mod1;
    x2 += other.x2;
    if (x2 >= Hash::mod2) x2 -= Hash::mod2;
    return *this;
  }
  inline Hash& operator-=(const Hash& other) {
    x1 -= other.x1;
    if (x1 < 0) x1 += Hash::mod1;
    x2 -= other.x2;
    if (x2 < 0) x2 += Hash::mod2;
    return *this;
  }
  inline Hash& operator*=(const Hash& other) {
    x1 = (long long)x1 * other.x1 % Hash::mod1;
    x2 = (long long)x2 * other.x2 % Hash::mod2;
    return *this;
  }
  inline Hash& operator*=(const int& other) {
    x1 = (long long)x1 * other % Hash::mod1;
    x2 = (long long)x2 * other % Hash::mod2;
    return *this;
  }
  inline Hash& operator^=(const int& power) {
    int st = power;
    Hash ans(1, 1);
    while (st) {
      if (st % 2) ans *= *this;
      x1 = (long long)x1 * x1 % Hash::mod1;
      x2 = (long long)x2 * x2 % Hash::mod2;
      st /= 2;
    }
    return *this;
  }
  inline bool operator==(const Hash& other) const {
    return x1 == other.x1 && x2 == other.x2;
  }
  inline bool operator<(const Hash& other) const {
    return x1 < other.x1 || (x1 == other.x1 && x2 < other.x2);
  }
  inline unsigned long long getULL() const {
    return ((unsigned long long)x1 << 31) + x2;
  }
};
bool Hash::initCalled = false;
int Hash::mod1 = 0;
int Hash::mod2 = 0;
int Hash::p1 = 23561;
int Hash::p2 = 10000019;
int Hash::invp1 = -1;
int Hash::invp2 = -1;
const Hash Hash::ONE(1, 1);
const Hash Hash::ZERO(0, 0);
const Hash Hash::INVALID(-1, -1);
Hash Hash::UNIT(Hash::p1, Hash::p2);
Hash Hash::INV_UNIT(-1, -1);
inline Hash operator+(const Hash& a, const Hash& b) {
  Hash ans(a.x1 + b.x1, a.x2 + b.x2);
  if (ans.x1 >= Hash::mod1) ans.x1 -= Hash::mod1;
  if (ans.x2 >= Hash::mod2) ans.x2 -= Hash::mod2;
  return ans;
}
inline Hash operator-(const Hash& a, const Hash& b) {
  Hash ans(a.x1 - b.x1, a.x2 - b.x2);
  if (ans.x1 < 0) ans.x1 += Hash::mod1;
  if (ans.x2 < 0) ans.x2 += Hash::mod2;
  return ans;
}
inline Hash operator*(const Hash& a, const Hash& b) {
  return Hash((long long)a.x1 * b.x1 % Hash::mod1,
              (long long)a.x2 * b.x2 % Hash::mod2);
}
inline Hash operator*(const Hash& a, const int& b) {
  return Hash((long long)a.x1 * b % Hash::mod1,
              (long long)a.x2 * b % Hash::mod2);
}
inline Hash operator^(const Hash& a, const int& power) {
  int st = power;
  Hash ans(1, 1), cur(a);
  while (st) {
    if (st % 2) ans *= cur;
    cur *= cur;
    st /= 2;
  }
  return ans;
}
inline Hash fpow(const Hash& a, const int& power) { return a ^ power; }
inline Hash invmod(const Hash& a) {
  return Hash(invmod(a.x1, Hash::mod1), invmod(a.x2, Hash::mod2));
}
vector<Hash> pmem;
inline Hash cpow(int pw) {
  if (pw < (int)((pmem).size())) return pmem[pw];
  if (pmem.empty()) {
    pmem.push_back(Hash::ONE);
  }
  pmem.resize(pw + 1);
  for (int _n((pw)), i(1); i <= _n; i++) {
    pmem[i] = pmem[i - 1] * Hash::UNIT;
  }
  return pmem[pw];
}
struct node;
void* GP;
class pnode;
inline void decref(pnode& p);
inline void incref(pnode& p);
class pnode {
 public:
  pnode(node* p) : step(p ? (int)((size_t)p - (size_t)GP) : -1) {
    incref(*this);
  }
  inline pnode& operator=(node* p) {
    decref(*this);
    step = p ? (int)((size_t)p - (size_t)GP) : -1;
    incref(*this);
    return *this;
  }
  pnode(const pnode& other) : step(other.step) { incref(*this); }
  inline pnode& operator=(const pnode& other) {
    decref(*this);
    step = other.step;
    incref(*this);
    return *this;
  }
  pnode() : step(-1) {}
  pnode(pnode&& other) {
    step = other.step;
    other.step = -1;
  }
  inline pnode& operator=(pnode&& other) {
    decref(*this);
    step = other.step;
    other.step = -1;
    return *this;
  }
  ~pnode() { decref(*this); }
  inline node* operator->() { return (node*)((size_t)GP + step); }
  inline node& operator*() { return *((node*)((size_t)GP + step)); }
  inline operator bool() { return step != -1; }

 private:
  int step;
};
struct node {
  Hash hs;
  int cnt;
  int hval;
  pnode l, r;
  int ref;
};
void decref(pnode& p) {
  if (!p) return;
  --p->ref;
}
void incref(pnode& p) {
  if (!p) return;
  ++p->ref;
}
inline int cnt(pnode a) {
  if (!a) return 0;
  return a->cnt;
}
const int N = 1000000;
node tr[N];
int tc;
inline void cl(pnode t) {
  t->cnt = 0;
  t->hs = Hash::ZERO;
  t->hval = 0;
  t->l = NULL;
  t->r = NULL;
}
inline pnode cp(pnode a) {
  if (tc >= N) {
    tc = 0;
  }
  while (tc < N && tr[tc].ref > 0) ++tc;
  if (tc >= N) {
    tc = 0;
  }
  while (tc < N && tr[tc].ref > 0) ++tc;
  if (tc >= N) {
    throw std::runtime_error("Oops");
  }
  pnode t = &tr[tc++];
  cl(t);
  if (!a) return t;
  t->cnt = a->cnt;
  t->hval = a->hval;
  t->hs = a->hs;
  t->l = a->l;
  t->r = a->r;
  return t;
}
inline void upd(pnode root) {
  if (root == NULL) return;
  root->cnt = 1;
  if (root->l) root->cnt += root->l->cnt;
  if (root->r) root->cnt += root->r->cnt;
  root->hs = Hash::ZERO;
  if (root->l) {
    root->hs = root->l->hs;
  }
  root->hs *= Hash::UNIT;
  root->hs += Hash(root->hval, root->hval);
  if (root->r) {
    root->hs *= cpow(root->r->cnt);
    root->hs += root->r->hs;
  }
}
pnode merge(pnode a, pnode b) {
  if (a == NULL && b == NULL) return NULL;
  if (a == NULL) return b;
  if (b == NULL) return a;
  if (rnd() % (a->cnt + b->cnt) < a->cnt) {
    pnode root = cp(a);
    root->r = merge(a->r, b);
    upd(root);
    return root;
  } else {
    pnode root = cp(b);
    root->l = merge(a, b->l);
    upd(root);
    return root;
  }
}
void split(pnode root, pnode& a, pnode& b, int cnt) {
  if (root == NULL) {
    a = b = NULL;
    return;
  }
  if ((root->l ? root->l->cnt : 0) >= cnt) {
    b = cp(root);
    split(root->l, a, b->l, cnt);
    upd(b);
  } else {
    a = cp(root);
    split(root->r, a->r, b, cnt - (root->l ? root->l->cnt : 0) - 1);
    upd(a);
  }
}
int a, b, c, d, n, m, k;
int mas[100002];
struct Node {
  pnode fr;
  pnode bk;
  bool bad;
};
Node TR[262144 + 2];
inline void un(Node& lf, Node& rt, Node& s) {
  s.fr = 0;
  s.bk = 0;
  s.bad = 0;
  if (lf.bad || rt.bad) {
    s.bad = 1;
    return;
  }
  if (cnt(lf.bk) < cnt(rt.fr)) {
    pnode t = cp(rt.fr);
    pnode t1 = 0, t2 = 0;
    split(t, t1, t2, cnt(rt.fr) - cnt(lf.bk));
    if (t2 != 0 && (lf.bk == 0 || !(t2->hs == lf.bk->hs))) {
      s.bad = 1;
      return;
    }
    s.fr = t1;
    s.fr = merge(s.fr, lf.fr);
    s.bk = rt.bk;
  } else if (cnt(lf.bk) > cnt(rt.fr)) {
    pnode t = cp(lf.bk);
    pnode t1 = 0, t2 = 0;
    split(t, t1, t2, cnt(lf.bk) - cnt(rt.fr));
    if (t2 != 0 && (rt.fr == 0 || !(t2->hs == rt.fr->hs))) {
      s.bad = 1;
      return;
    }
    s.bk = t1;
    s.bk = merge(s.bk, rt.bk);
    s.fr = lf.fr;
  } else {
    if (cnt(lf.bk) > 0) {
      if (!(lf.bk->hs == rt.fr->hs)) {
        s.bad = 1;
        return;
      }
    }
    s.fr = lf.fr;
    s.bk = rt.bk;
  }
}
void build(int l, int r, int v) {
  if (l == r - 1) {
    TR[v].fr = 0;
    TR[v].bk = 0;
    TR[v].bad = 0;
    if (mas[l] < 0) {
      pnode nfr = cp(0);
      nfr->cnt = 1;
      nfr->l = nfr->r = 0;
      nfr->hval = -mas[l];
      nfr->hs = Hash(-mas[l], -mas[l]);
      TR[v].fr = nfr;
    } else {
      pnode nfr = cp(0);
      nfr->cnt = 1;
      nfr->l = nfr->r = 0;
      nfr->hval = mas[l];
      nfr->hs = Hash(mas[l], mas[l]);
      TR[v].bk = nfr;
    }
    return;
  }
  int xx = (r + l) / 2;
  build(l, xx, v * 2);
  build(xx, r, v * 2 + 1);
  un(TR[v * 2], TR[v * 2 + 1], TR[v]);
}
inline void upd(int l, int r, int pos, int val, int v) {
  if (l == r - 1) {
    TR[v].fr = 0;
    TR[v].bk = 0;
    TR[v].bad = 0;
    if (mas[l] < 0) {
      pnode nfr = cp(0);
      nfr->cnt = 1;
      nfr->l = nfr->r = 0;
      nfr->hval = -mas[l];
      nfr->hs = Hash(-mas[l], -mas[l]);
      TR[v].fr = nfr;
    } else {
      pnode nfr = cp(0);
      nfr->cnt = 1;
      nfr->l = nfr->r = 0;
      nfr->hval = mas[l];
      nfr->hs = Hash(mas[l], mas[l]);
      TR[v].bk = nfr;
    }
    return;
  }
  int xx = (r + l) / 2;
  if (pos < xx)
    upd(l, xx, pos, val, v * 2);
  else
    upd(xx, r, pos, val, v * 2 + 1);
  un(TR[v * 2], TR[v * 2 + 1], TR[v]);
}
Node fnd(int l, int r, int a, int b, int v) {
  if (l == a && b == r - 1) {
    return TR[v];
  }
  int xx = (r + l) / 2;
  if (b < xx)
    return fnd(l, xx, a, b, v * 2);
  else if (a >= xx)
    return fnd(xx, r, a, b, v * 2 + 1);
  auto a1 = fnd(l, xx, a, xx - 1, v * 2);
  if (a1.bad) return a1;
  auto a2 = fnd(xx, r, xx, b, v * 2 + 1);
  if (a2.bad) return a2;
  Node res;
  un(a1, a2, res);
  return res;
}
inline bool check(int l, int r) {
  auto t = fnd(0, n, l, r, 1);
  if (t.bad) return false;
  if (cnt(t.fr) || cnt(t.bk)) return 0;
  return true;
}
int main() {
  Hash::init();
  scanf("%d%d", &n, &k);
  for (int _n((n)-1), i(0); i <= _n; i++) {
    scanf("%d", &mas[i]);
  }
  pmem.clear();
  tc = 0;
  GP = tr;
  cpow(n + 1);
  build(0, n, 1);
  int ov = 0;
  scanf("%d", &m);
  for (int _n((m)-1), iter(0); iter <= _n; iter++) {
    scanf("%d", &a);
    if (a == 1) {
      scanf("%d%d", &a, &b);
      --a;
      mas[a] = b;
      upd(0, n, a, b, 1);
    } else {
      scanf("%d%d", &a, &b);
      --a;
      --b;
      bool ans = check(a, b);
      if (ans)
        puts("Yes");
      else
        puts("No");
    }
  }
}