Problem: A positive (strictly greater than zero) integer is called round if it is of the form d00...0. In other words, a positive integer is round if all its digits except the leftmost (most significant) are equal to zero. In particular, all numbers from 1 to 9 (inclusive) are round.

For example, the following numbers are round: 4000, 1, 9, 800, 90. The following numbers are not round: 110, 707, 222, 1001.

You are given a positive integer n (1 ≤ n ≤ 10^4). Represent the number n as a sum of round numbers using the minimum number of summands (addends). In other words, you need to represent the given number n as a sum of the least number of terms, each of which is a round number.

Input

The first line contains an integer t (1 ≤ t ≤ 10^4) — the number of test cases in the input. Then t test cases follow.

Each test case is a line containing an integer n (1 ≤ n ≤ 10^4).

Output

Print t answers to the test cases. Each answer must begin with an integer k — the minimum number of summands. Next, k terms must follow, each of which is a round number, and their sum is n. The terms can be printed in any order. If there are several answers, print any of them.

Example

Input


5
5009
7
9876
10000
10


Output


2
5000 9
1
7 
4
800 70 6 9000 
1
10000 
1
10 

Solution (in JAVA):

Solution:
import java.util.ArrayList;
import java.util.Scanner;

	public class Training {		
		public static void main(String[] args) {
			Scanner in = new Scanner(System.in);
			int t = in.nextInt();
			int count = 0;
			while(t-- > 0) {
				int n = in.nextInt();
				String s = Integer.toString(n);
				for(int i = 0; i < s.length(); i++) {
					if(s.charAt(i) != '0') {
						count++;
					}
				}
				System.out.println(count);
				int a = s.length() - 1;
				for(int i = 0; i < s.length(); i++) {
					if(s.charAt(i) != '0')
					System.out.print(Character.getNumericValue(s.charAt(i)) * (int) Math.pow(10, a) + " ");
					a--;
				}
				System.out.println();
				count = 0;
			}
		}
	}