Problem: Try guessing the statement from this picture: 

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You are given a non-negative integer d. You have to find two non-negative real numbers a and b such that a + b = d and a ⋅ b = d.

Input

The first line contains t (1 ≤ t ≤ 10^3) — the number of test cases.

Each test case contains one integer d (0 ≤ d ≤ 10^3).

Output

For each test print one line.

If there is an answer for the i-th test, print "Y", and then the numbers a and b.

If there is no answer for the i-th test, print "N".

Your answer will be considered correct if |(a + b) - a ⋅ b| ≤ 10^{-6} and |(a + b) - d| ≤ 10^{-6}.

Example

Input


7
69
0
1
4
5
999
1000


Output


Y 67.985071301 1.014928699
Y 0.000000000 0.000000000
N
Y 2.000000000 2.000000000
Y 3.618033989 1.381966011
Y 997.998996990 1.001003010
Y 998.998997995 1.001002005

Solution (in PYTHON3):

Solution:
#!/usr/bin/env python3
import sys

def rint():
    return map(int, sys.stdin.readline().split())
#lines = stdin.readlines()

t = int(input())

for i in range(t):
    d = int(input())
    r = d**2 - 4*d
    if r < 0:
        print("N")
        continue

    a = (d + r**0.5)/2.0
    b = d - a
    if a <= d and  b >= 0:
        print("Y", a, b)
        continue
    a = (d - r**0.5)/2.0
    b = d - a
    if a <= d and  b >= 0:
        print("Y", a, b)
        continue
    print("N")