Problem: Queue is a container of elements that are inserted and deleted according to FIFO (First In First Out).

For $n$ queues $Q_i$ ($i = 0, 1, ..., n-1$), perform a sequence of the following operations.

* enqueue($t$, $x$): Insert an integer $x$ to $Q_t$.
* front($t$): Report the value which should be deleted next from $Q_t$. If $Q_t$ is empty, do nothing.
* dequeue($t$): Delete an element from $Q_t$. If $Q_t$ is empty, do nothing.



In the initial state, all queues are empty.

Constraints

* $1 \leq n \leq 1,000$
* $1 \leq q \leq 200,000$
* $-1,000,000,000 \leq x \leq 1,000,000,000$

Input

The input is given in the following format.


$n \; q$
$query_1$
$query_2$
:
$query_q$


Each query $query_i$ is given by


0 $t$ $x$


or


1 $t$


or


2 $t$


where the first digits 0, 1 and 2 represent enqueue, front and dequeue operations respectively.

Output

For each front operation, print an integer in a line.

Example

Input

3 9
0 0 1
0 0 2
0 0 3
0 2 4
0 2 5
1 0
1 2
2 0
1 0


Output

1
4
2

Solution (in CPP):

Solution:
#include<iostream>
#include<queue>

using namespace std;


int main() {
	
	int n;
	cin >> n;
	queue<int> qe[n];
	
	int n2;
	cin >> n2;
	
	int choice;
	int temp, temp2;
	
	for(int i=0;i<n2;i++) {
		
		cin >> choice;
		
		switch(choice) {
			
			case 0:
				cin >> temp >> temp2;
				qe[temp].push(temp2);
				break;
				
			case 1:
				cin >> temp;
				
				if(qe[temp].size() == 0)
					break;
					
				else
					cout << qe[temp].front() << "\n";
					
				break;
				
			case 2:
				cin >> temp;
				
				if(qe[temp].size() == 0)
					break;
				
				else
					qe[temp].pop();
		}
		
	}
	
	return 0;
}