Problem: Queue is a container of elements that are inserted and deleted according to FIFO (First In First Out).

For $n$ queues $Q_i$ ($i = 0, 1, ..., n-1$), perform a sequence of the following operations.

* enqueue($t$, $x$): Insert an integer $x$ to $Q_t$.
* front($t$): Report the value which should be deleted next from $Q_t$. If $Q_t$ is empty, do nothing.
* dequeue($t$): Delete an element from $Q_t$. If $Q_t$ is empty, do nothing.



In the initial state, all queues are empty.

Constraints

* $1 \leq n \leq 1,000$
* $1 \leq q \leq 200,000$
* $-1,000,000,000 \leq x \leq 1,000,000,000$

Input

The input is given in the following format.


$n \; q$
$query_1$
$query_2$
:
$query_q$


Each query $query_i$ is given by


0 $t$ $x$


or


1 $t$


or


2 $t$


where the first digits 0, 1 and 2 represent enqueue, front and dequeue operations respectively.

Output

For each front operation, print an integer in a line.

Example

Input

3 9
0 0 1
0 0 2
0 0 3
0 2 4
0 2 5
1 0
1 2
2 0
1 0


Output

1
4
2

Solution (in CPP):

Solution:
#include<iostream>
#include<string>
#include<vector>
#include<algorithm>
#include<cmath>
#include<stdio.h>
#include<queue>
#include <climits>
#include <map>
#include <set>
const int mod = 1e9 + 7;
const int INF = 1 << 20;
using namespace std;
typedef long long ll;
typedef pair<int,int> P;
 
int main()
{
    int n,q; cin >> n >> q;
    vector<vector<int> > v(n);
    for(int i = 0; i < q; i++){
        int a; cin >> a;
        if(a == 0){
            int b,c; cin >> b >> c;
            v[b].push_back(c);
        }else if(a==1){
            int b; cin >> b;
            if(!v[b].empty()){
                cout << v[b].front() << endl;
            }
        }else{
            int b; cin >> b;
            if(!v[b].empty()){
                v[b].erase(v[b].begin());
            }
        }
    }
}