Problem: There is a rectangular room, covered with square tiles. Each tile is colored either red or black. A man is standing on a black tile. From a tile, he can move to one of four adjacent tiles. But he can't move on red tiles, he can move only on black tiles.

Write a program to count the number of black tiles which he can reach by repeating the moves described above.



Input

The input consists of multiple data sets. A data set starts with a line containing two positive integers W and H; W and H are the numbers of tiles in the x- and y- directions, respectively. W and H are not more than 20.

There are H more lines in the data set, each of which includes W characters. Each character represents the color of a tile as follows.

* '.' - a black tile
* '#' - a red tile
* '@' - a man on a black tile(appears exactly once in a data set)


The end of the input is indicated by a line consisting of two zeros.

Output

For each data set, your program should output a line which contains the number of tiles he can reach from the initial tile (including itself).

Examples

Input

6 9
....#.
.....#
......
......
......
......
......
#@...#
.#..#.
11 9
.#.........
.#.#######.
.#.#.....#.
.#.#.###.#.
.#.#..@#.#.
.#.#####.#.
.#.......#.
.#########.
...........
11 6
..#..#..#..
..#..#..#..
..#..#..###
..#..#..#@.
..#..#..#..
..#..#..#..
7 7
..#.#..
..#.#..
###.###
...@...
###.###
..#.#..
..#.#..
0 0


Output

45
59
6
13


Input

6 9
....#.
.....#
......
......
......
......
......
@...#
.#..#.
11 9
.#.........
.#.#######.
.#.#.....#.
.#.#.###.#.
.#.#..@#.#.
.#.#####.#.
.#.......#.
.#########.
...........
11 6
..#..#..#..
..#..#..#..
..#..#..###
..#..#..#@.
..#..#..#..
..#..#..#..
7 7
..#.#..
..#.#..
.###
...@...
.###
..#.#..
..#.#..
0 0


Output

45
59
6
13

Solution (in JAVA):

Solution:
import java.util.Scanner;

public class Main {

	static int[] v1 = { 0, 1, 0, -1 };
	static int[] v2 = { 1, 0, -1, 0 };
	static int[][] field;
	static int count = 0;

	public static void main(String[] args) {
		Scanner cin = new Scanner(System.in);
		while (true) {
			int w = cin.nextInt();
			int h = cin.nextInt();
			if(w+h==0){break;}
			
			int startx = 0, starty = 0;
			count=0;
			field = new int[h + 2][w + 2];
			for (int i = 1; i <= h; i++) {
				String str = cin.next();
				for (int j = 1; j <= w; j++) {
					if (str.charAt(j-1) == '.') {
						field[i][j] = 1;
					} else if (str.charAt(j-1) == '#') {
						field[i][j] = 2;
					} else if (str.charAt(j-1) == '@') {
						field[i][j] = 1;
						startx = i;
						starty = j;
					}
				}
			}
			bfs(startx, starty);
			System.out.println(count);
		}
	}

	static void bfs(int x, int y) {
		field[x][y] = 2;
		count++;
		for (int i = 0; i < 4; i++) {
			int xx = x + v1[i];
			int yy = y + v2[i];
			if (field[xx][yy] == 1) {
				

				bfs(xx, yy);
			}
		}
	}
}