Problem: The only difference between easy and hard versions is constraints.

You are given n segments on the coordinate axis OX. Segments can intersect, lie inside each other and even coincide. The i-th segment is [l_i; r_i] (l_i ≤ r_i) and it covers all integer points j such that l_i ≤ j ≤ r_i.

The integer point is called bad if it is covered by strictly more than k segments.

Your task is to remove the minimum number of segments so that there are no bad points at all.

Input

The first line of the input contains two integers n and k (1 ≤ k ≤ n ≤ 200) — the number of segments and the maximum number of segments by which each integer point can be covered.

The next n lines contain segments. The i-th line contains two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 200) — the endpoints of the i-th segment.

Output

In the first line print one integer m (0 ≤ m ≤ n) — the minimum number of segments you need to remove so that there are no bad points.

In the second line print m distinct integers p_1, p_2, ..., p_m (1 ≤ p_i ≤ n) — indices of segments you remove in any order. If there are multiple answers, you can print any of them.

Examples

Input


7 2
11 11
9 11
7 8
8 9
7 8
9 11
7 9


Output


3
1 4 7 


Input


5 1
29 30
30 30
29 29
28 30
30 30


Output


3
1 2 4 


Input


6 1
2 3
3 3
2 3
2 2
2 3
2 3


Output


4
1 3 5 6 

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.BufferedWriter;
import java.io.FileWriter;
import java.io.InputStreamReader;
import java.io.OutputStreamWriter;
import java.util.*;

public class TooManySegments {

	static BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
	static BufferedWriter writer = new BufferedWriter(new OutputStreamWriter(System.out));

	static int n, k;
	static pair[] seg;
	
	static int N = 200002;
	
	static pair pair(int x, int y) {
		return new pair(x, y);
	}
	
	static class pair {
		int x;
		int y;
		public pair(int x, int y) {
			super();
			this.x = x;
			this.y = y;
		}
		
		public boolean equals(Object obj) {
    		if(obj == null || obj.getClass()!= this.getClass()) return false;
            pair p = (pair) obj;
            return (this.x==p.x && this.y==p.y);
        }
    	public int hashCode() {
            return Objects.hash(x,y);
        }
	}
	
	static void process() throws Exception {
		Map<Integer, List<Integer>> ev = new HashMap<>();
		int[] cnt = new int[N];
		for (int i = 0; i < n; i++) {
			cnt[seg[i].x]++;
			cnt[seg[i].y + 1]--;
			int idx = i;
			ev.compute(seg[i].x, (k, v) -> {
				if (v == null) {
					v = new ArrayList<>();
				}
				v.add(idx + 1);
				return v;
			});
			ev.compute(seg[i].y + 1, (k, v) -> {
				if (v == null) {
					v = new ArrayList<>();
				}
				v.add(-idx - 1);
				return v;
			});
		}
		
		for (int i = 1; i < N; i++) {
			cnt[i] = cnt[i] + cnt[i - 1];
		}
		
		int[] ans = new int[n], sub = new int[N];
		PriorityQueue<pair> curSegs = new PriorityQueue<>((p1, p2) -> p2.y - p1.y);
		int curSeg = 0;
		for (int i = 0; i < N; i++) {
			curSeg += sub[i];
			for (int it: ev.getOrDefault(i, Collections.emptyList())) {
				if (it > 0) {
					curSegs.add(pair(it - 1, seg[it - 1].y));
				} else {
					curSegs.remove(pair(-it - 1, seg[-it - 1].y));
				}
			}
			while (cnt[i] - curSeg > k) {
				pair p = curSegs.poll();
				++curSeg;
				--sub[p.y + 1];
				ans[p.x] = 1;
			}
		}
		
		int count = 0;
		StringBuilder builder = new StringBuilder();
		for (int i = 0; i < n; i++) {
			if (ans[i] == 1) {
				builder.append(String.format("%d ", i + 1));
				count++;
			}
		}
		writer.write(String.format("%d", count));
		writer.newLine();
		writer.write(builder.toString());
		writer.newLine();
	}

	public static void main(String[] args) throws Exception {
		//		writer = new BufferedWriter(new FileWriter("output.txt"));
		String data[], input;
		data = reader.readLine().split(" ");
		n = Integer.parseInt(data[0]); k = Integer.parseInt(data[1]);
		seg = new pair[n];
		for (int i = 0; i < n; i++) {
			data = reader.readLine().split(" ");
			seg[i] = pair(Integer.parseInt(data[0]) - 1, Integer.parseInt(data[1]) - 1);
		}
		process();
		writer.close();
	}

}