Problem: Ilya the Lion wants to help all his friends with passing exams. They need to solve the following problem to pass the IT exam.

You've got string s = s1s2... sn (n is the length of the string), consisting only of characters "." and "#" and m queries. Each query is described by a pair of integers li, ri (1 ≤ li < ri ≤ n). The answer to the query li, ri is the number of such integers i (li ≤ i < ri), that si = si + 1.

Ilya the Lion wants to help his friends but is there anyone to help him? Help Ilya, solve the problem.

Input

The first line contains string s of length n (2 ≤ n ≤ 105). It is guaranteed that the given string only consists of characters "." and "#".

The next line contains integer m (1 ≤ m ≤ 105) — the number of queries. Each of the next m lines contains the description of the corresponding query. The i-th line contains integers li, ri (1 ≤ li < ri ≤ n).

Output

Print m integers — the answers to the queries in the order in which they are given in the input.

Examples

Input

......
4
3 4
2 3
1 6
2 6


Output

1
1
5
4


Input

#..###
5
1 3
5 6
1 5
3 6
3 4


Output

1
1
2
2
0

Solution (in PYTHON3):

Solution:
# # 2 39 4 2 1 2 4 52 2 10
# # 2 41 45 47 48 50 54 106 108 118
# # sum from 1-5? 48
# # sum from 2-9? 108-2
# # sum from 1-8? 106
#
# # 0 0 1 1 2 3
# # ^before anything at all
# # #..###
# # ^^
# # 5
# # 1 3 (is 1 = 2? is 2 = 3?) -> 1
# # 5 6
# # 1 5
# # 3 6
# # 3 4
# s=input()
# m=int(input())
# # do processing first
#
# counts=[0]
# count=0
# for j in range(len(s)-1):
#     if s[j]==s[j+1]:
#         count+=1
#     counts.append(count)
#
#
# for i in range(m):
#     count=0
#     l,r=map(int,input().split(" "))
#     # for i in range(l-1,r-1):
#     #     if s[i]==s[i+1]:
#     #         count+=1
#
#     # retrieve answer
#     print(counts[r-1]-counts[l-1])

from sys import stdin, stdout


# 2 39 4 2 1 2 4 52 2 10
# 2 41 45 47 48 50 54 106 108 118
# sum from 1-5? 48
# sum from 2-9? 108-2
# sum from 1-8? 106

# 0 0 1 1 2 3
# ^before anything at all
# #..###
# ^^
# 5
# 1 3 (is 1 = 2? is 2 = 3?) -> 1
# 5 6
# 1 5
# 3 6
# 3 4
s=stdin.readline()
m=int(stdin.readline())
# do processing first

counts=[0]
count=0
for j in range(len(s)-1):
    if s[j]==s[j+1]:
        count+=1
    counts.append(count)


for i in range(m):
    count=0
    l,r=map(int,stdin.readline().split(" "))
    # for i in range(l-1,r-1):
    #     if s[i]==s[i+1]:
    #         count+=1

    # retrieve answer
    stdout.write(str(counts[r-1]-counts[l-1]) + '\n')