Problem: Ilya the Lion wants to help all his friends with passing exams. They need to solve the following problem to pass the IT exam.

You've got string s = s1s2... sn (n is the length of the string), consisting only of characters "." and "#" and m queries. Each query is described by a pair of integers li, ri (1 ≤ li < ri ≤ n). The answer to the query li, ri is the number of such integers i (li ≤ i < ri), that si = si + 1.

Ilya the Lion wants to help his friends but is there anyone to help him? Help Ilya, solve the problem.

Input

The first line contains string s of length n (2 ≤ n ≤ 105). It is guaranteed that the given string only consists of characters "." and "#".

The next line contains integer m (1 ≤ m ≤ 105) — the number of queries. Each of the next m lines contains the description of the corresponding query. The i-th line contains integers li, ri (1 ≤ li < ri ≤ n).

Output

Print m integers — the answers to the queries in the order in which they are given in the input.

Examples

Input

......
4
3 4
2 3
1 6
2 6


Output

1
1
5
4


Input

#..###
5
1 3
5 6
1 5
3 6
3 4


Output

1
1
2
2
0

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
char str[111111];
int iseq[111111];
int main(void) {
  int m = 0;
  scanf("%s %d", str, &m);
  int n = strlen(str);
  for (int i = 0; i < n - 1; i++) {
    iseq[i] = str[i] == str[i + 1];
  }
  for (int i = 1; i < n; i++) {
    iseq[i] += iseq[i - 1];
  }
  for (int i = 0; i < m; i++) {
    int l = 0;
    int r = 0;
    scanf("%d %d", &l, &r);
    l--;
    r--;
    int ans = iseq[r - 1];
    if (l - 1 >= 0) ans -= iseq[l - 1];
    printf("%d\n", ans);
  }
  while (getchar() != EOF)
    ;
  return 0;
}