Problem: The only difference between easy and hard versions is constraints.

You are given n segments on the coordinate axis OX. Segments can intersect, lie inside each other and even coincide. The i-th segment is [l_i; r_i] (l_i ≤ r_i) and it covers all integer points j such that l_i ≤ j ≤ r_i.

The integer point is called bad if it is covered by strictly more than k segments.

Your task is to remove the minimum number of segments so that there are no bad points at all.

Input

The first line of the input contains two integers n and k (1 ≤ k ≤ n ≤ 200) — the number of segments and the maximum number of segments by which each integer point can be covered.

The next n lines contain segments. The i-th line contains two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 200) — the endpoints of the i-th segment.

Output

In the first line print one integer m (0 ≤ m ≤ n) — the minimum number of segments you need to remove so that there are no bad points.

In the second line print m distinct integers p_1, p_2, ..., p_m (1 ≤ p_i ≤ n) — indices of segments you remove in any order. If there are multiple answers, you can print any of them.

Examples

Input


7 2
11 11
9 11
7 8
8 9
7 8
9 11
7 9


Output


3
1 4 7 


Input


5 1
29 30
30 30
29 29
28 30
30 30


Output


3
1 2 4 


Input


6 1
2 3
3 3
2 3
2 2
2 3
2 3


Output


4
1 3 5 6 

Solution (in JAVA):

Solution:
import java.util.ArrayList;
import java.util.Scanner;

public class Too_Many_Segments_easy_version {
	public static void main(String []  args) {
		Scanner sc=new Scanner(System.in);
		int n=sc.nextInt();
		int k=sc.nextInt();
		int seg[][]=new int [n][2];
		boolean rem[]=new boolean [n];
		int [] arr=new int [205];
		ArrayList<Integer> remove=new ArrayList<Integer>();
		for(int i=0;i<n;i++) {
			int l=sc.nextInt();
			int r=sc.nextInt();
			seg[i][0]=l;
			seg[i][1]=r;
			if(l==r) {
				arr[l]++;
			}
			else {
			for(int j=l;j<=r;j++) {
				arr[j]++;
			}
			}
		}
		
		for(int i=0;i<205;i++) {
			while(arr[i]>k) {
				int maxrange=0;
				int r=0;
				for(int j=0;j<n;j++) {
					if(seg[j][0]<=i&& seg[j][1]>=i &&rem[j]==false) {
						int range=seg[j][1]-i+1;
						if(range>maxrange) {
							maxrange=range;
							r=j;
						}
					}
					
				}
				rem[r]=true;
				remove.add(r);
				if(seg[r][0]==seg[r][1]) {
					arr[seg[r][0]]--;
				}
				else {
				for(int j=seg[r][0];j<=seg[r][1];j++) {
					arr[j]--;
			   }
				
				}

				
			}
		}
		int l=remove.size();
		System.out.println(l);
		for(int i=0;i<l;i++) {
			System.out.print((remove.get(i)+1)+" ");
		}
		
	}

}