Problem: We have N points numbered 1 to N arranged in a line in this order.

Takahashi decides to make an undirected graph, using these points as the vertices. In the beginning, the graph has no edge. Takahashi will do M operations to add edges in this graph. The i-th operation is as follows:

* The operation uses integers L_i and R_i between 1 and N (inclusive), and a positive integer C_i. For every pair of integers (s, t) such that L_i \leq s < t \leq R_i, add an edge of length C_i between Vertex s and Vertex t.



The integers L_1, ..., L_M, R_1, ..., R_M, C_1, ..., C_M are all given as input.

Takahashi wants to solve the shortest path problem in the final graph obtained. Find the length of the shortest path from Vertex 1 to Vertex N in the final graph.

Constraints

* 2 \leq N \leq 10^5
* 1 \leq M \leq 10^5
* 1 \leq L_i < R_i \leq N
* 1 \leq C_i \leq 10^9

Input

Input is given from Standard Input in the following format:


N M
L_1 R_1 C_1
:
L_M R_M C_M


Output

Print the length of the shortest path from Vertex 1 to Vertex N in the final graph. If there is no shortest path, print `-1` instead.

Examples

Input

4 3
1 3 2
2 4 3
1 4 6


Output

5


Input

4 2
1 2 1
3 4 2


Output

-1


Input

10 7
1 5 18
3 4 8
1 3 5
4 7 10
5 9 8
6 10 5
8 10 3


Output

28

Solution (in PYTHON3):

Solution:
import sys,heapq
input = sys.stdin.readline

n,m = map(int,input().split())

dg = 10**6


edge = [[] for _ in [0]*n]

for _ in [0]*m:
    l,r,c = map(int,input().split())
    edge[l-1].append(c*dg+r-1)

d = [10**20]*n
d[0] = 0

tank = []
for e in edge[0]:
    heapq.heappush(tank,e)
while len(tank) != 0:
    q = heapq.heappop(tank)
    go = q%dg
    if d[go] != 10**20:
        continue
    cost = q//dg

    for i in range(go,-1,-1):
        if d[i] != 10**20:
            break
        d[i] = cost
        for e in edge[i]:
            heapq.heappush(tank,e+cost*dg)
if d[-1] == 10**20:
    print(-1)
else:
    print(d[-1])