Problem: Ilya the Lion wants to help all his friends with passing exams. They need to solve the following problem to pass the IT exam.

You've got string s = s1s2... sn (n is the length of the string), consisting only of characters "." and "#" and m queries. Each query is described by a pair of integers li, ri (1 ≤ li < ri ≤ n). The answer to the query li, ri is the number of such integers i (li ≤ i < ri), that si = si + 1.

Ilya the Lion wants to help his friends but is there anyone to help him? Help Ilya, solve the problem.

Input

The first line contains string s of length n (2 ≤ n ≤ 105). It is guaranteed that the given string only consists of characters "." and "#".

The next line contains integer m (1 ≤ m ≤ 105) — the number of queries. Each of the next m lines contains the description of the corresponding query. The i-th line contains integers li, ri (1 ≤ li < ri ≤ n).

Output

Print m integers — the answers to the queries in the order in which they are given in the input.

Examples

Input

......
4
3 4
2 3
1 6
2 6


Output

1
1
5
4


Input

#..###
5
1 3
5 6
1 5
3 6
3 4


Output

1
1
2
2
0

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int arr[200000];
int main() {
  string str;
  cin >> str;
  int cont = 0;
  for (int i = 0; i < str.size() - 1; i++) {
    if (str[i] == str[i + 1]) {
      cont++;
      arr[i + 1] = cont;
    } else {
      arr[i + 1] = cont;
    }
  }
  arr[str.size()] = arr[str.size() - 1];
  int n;
  scanf("%d", &n);
  for (int k = 0; k < n; k++) {
    int l, r;
    scanf("%d%d", &l, &r);
    int total = (arr[l] - arr[l - 1]) + (arr[r - 1] - arr[l]);
    printf("%d\n", total);
  }
  return 0;
}