Problem: Ilya the Lion wants to help all his friends with passing exams. They need to solve the following problem to pass the IT exam.

You've got string s = s1s2... sn (n is the length of the string), consisting only of characters "." and "#" and m queries. Each query is described by a pair of integers li, ri (1 ≤ li < ri ≤ n). The answer to the query li, ri is the number of such integers i (li ≤ i < ri), that si = si + 1.

Ilya the Lion wants to help his friends but is there anyone to help him? Help Ilya, solve the problem.

Input

The first line contains string s of length n (2 ≤ n ≤ 105). It is guaranteed that the given string only consists of characters "." and "#".

The next line contains integer m (1 ≤ m ≤ 105) — the number of queries. Each of the next m lines contains the description of the corresponding query. The i-th line contains integers li, ri (1 ≤ li < ri ≤ n).

Output

Print m integers — the answers to the queries in the order in which they are given in the input.

Examples

Input

......
4
3 4
2 3
1 6
2 6


Output

1
1
5
4


Input

#..###
5
1 3
5 6
1 5
3 6
3 4


Output

1
1
2
2
0

Solution (in PYTHON3):

Solution:
from sys import stdin
input = stdin.readline

OUT = []

def write(item):
    if type(item) is int:
        OUT.append(str(item))
    elif type(item) is list:
        if type(item[0]) is int:
            OUT.append(" ".join(map(str, item)))
        else:
            OUT.append(" ".join(item))
    else:
        OUT.append(item)

GI = lambda: int(input())
GS = lambda: input()[:-1]

gi = lambda: list(map(int, input().split()))
gs = lambda: input().split()

psa = [0]
s = p = 0
for i in input():
    if i == p:
        s += 1
    else:
        p = i
    psa.append(s)

for i in range(int(input())):
    l, r = map(int, input().split())
    write(psa[r] - psa[l])

print("\n".join(OUT))