Problem: Ringo Kingdom Congress is voting on a bill.

N members are present, and the i-th member (1 ≤ i ≤ N) has w_i white ballots and b_i blue ballots. Each member i will put all the w_i white ballots into the box if he/she is in favor of the bill, and put all the b_i blue ballots into the box if he/she is not in favor of the bill. No other action is allowed. For example, a member must not forfeit voting, or put only a part of his/her white ballots or a part of his/her blue ballots into the box.

After all the members vote, if at least P percent of the ballots in the box is white, the bill is passed; if less than P percent of the ballots is white, the bill is rejected.

In order for the bill to pass, at least how many members must be in favor of it?

Constraints

* 1 ≤ N ≤ 10^5
* 1 ≤ P ≤ 100
* 1 ≤ w_i ≤ 10^9
* 1 ≤ b_i ≤ 10^9
* All input values are integers.

Input

Input is given from Standard Input in the following format:


N P
w_1 b_1
w_2 b_2
:
w_N b_N


Output

Print the minimum number of members in favor of the bill required for passage.

Examples

Input

4 75
1 1
1 1
1 1
1 1


Output

3


Input

4 75
1 1
1 1
1 1
100 1


Output

1


Input

5 60
6 3
5 9
3 4
7 8
4 7


Output

3

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
struct fast_ios { fast_ios(){ cin.tie(0); ios::sync_with_stdio(false); cout << fixed << setprecision(20); }; } fast_ios_;
#define FOR(i, begin, end) for(int i=(begin);i<(end);i++)
#define REP(i, n) FOR(i,0,n)
#define IFOR(i, begin, end) for(int i=(end)-1;i>=(begin);i--)
#define IREP(i, n) IFOR(i,0,n)
#define Sort(v) sort(v.begin(), v.end())
#define Reverse(v) reverse(v.begin(), v.end())
#define all(v) v.begin(),v.end()
#define SZ(v) ((int)v.size())
#define Lower_bound(v, x) distance(v.begin(), lower_bound(v.begin(), v.end(), x))
#define Upper_bound(v, x) distance(v.begin(), upper_bound(v.begin(), v.end(), x))
#define Max(a, b) a = max(a, b)
#define Min(a, b) a = min(a, b)
#define bit(n) (1LL<<(n))
#define Ans(f, y, n) if(f) cout << y << endl; else cout << n << endl;
#define debug(x) cout << #x << "=" << x << endl;
#define vdebug(v) cout << #v << "=" << endl; REP(i, v.size()){ cout << v[i] << ","; } cout << endl;
#define mdebug(m) cout << #m << "=" << endl; REP(i, m.size()){ REP(j, m[i].size()){ cout << m[i][j] << ","; } cout << endl;}
#define pb push_back
#define f first
#define s second
#define int long long
#define INF 1000000000000000000

using vec = vector<int>;
using mat = vector<vec>;
using Pii = pair<int, int>;
using PiP = pair<int, Pii>;
using PPi = pair<Pii, int>;
using bools = vector<bool>;
using pairs = vector<Pii>;

template<typename T> void readv(vector<T> &a){ REP(i, a.size()) cin >> a[i]; }
void readv_m1(vector<int> &a){ REP(i, a.size()){cin >> a[i]; a[i]--;} }

//int dx[4] = {1,0,-1,0};
//int dy[4] = {0,1,0,-1};

int mod = 1000000007;
//int mod = 998244353;
#define Add(x, y) x = (x + (y)) % mod
#define Mult(x, y) x = (x * (y)) % mod
#define AddMult(x, y, z) x = (x + (y) * (z)) % mod



signed main(){

    int N, P; cin >> N >> P;
    vec w(N), b(N), v(N);
    int B = 0;
    REP(i, N){
        cin >> w[i] >> b[i];
        B += b[i];
        v[i] = (100 - P) * w[i] + P * b[i];
    }
    Sort(v);
    Reverse(v);
    int ss = 0, ans;
    REP(i, N){
        ss += v[i];
        if(ss >= P * B){
            ans = i + 1;
            break;
        }
    }
    cout << ans << endl;

    return 0;
}