Problem: Ilya the Lion wants to help all his friends with passing exams. They need to solve the following problem to pass the IT exam.

You've got string s = s1s2... sn (n is the length of the string), consisting only of characters "." and "#" and m queries. Each query is described by a pair of integers li, ri (1 ≤ li < ri ≤ n). The answer to the query li, ri is the number of such integers i (li ≤ i < ri), that si = si + 1.

Ilya the Lion wants to help his friends but is there anyone to help him? Help Ilya, solve the problem.

Input

The first line contains string s of length n (2 ≤ n ≤ 105). It is guaranteed that the given string only consists of characters "." and "#".

The next line contains integer m (1 ≤ m ≤ 105) — the number of queries. Each of the next m lines contains the description of the corresponding query. The i-th line contains integers li, ri (1 ≤ li < ri ≤ n).

Output

Print m integers — the answers to the queries in the order in which they are given in the input.

Examples

Input

......
4
3 4
2 3
1 6
2 6


Output

1
1
5
4


Input

#..###
5
1 3
5 6
1 5
3 6
3 4


Output

1
1
2
2
0

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
long long int fac[20];
int vis[3000000];
int dx[] = {0, 0, 1, -1};
int dy[] = {1, -1, 0, 0};
int arr[3000000];
int values[3000000];
int n, k;
int occ[3000000];
int main() {
  string s;
  cin >> s;
  for (int i = 0; i < s.size() - 1; i++) {
    if (s[i] == s[i + 1]) {
      occ[i + 1] = occ[i] + 1;
    } else
      occ[i + 1] = occ[i];
  }
  scanf("%d", &k);
  for (int i = 0; i < k; i++) {
    int r, l;
    scanf("%d %d", &r, &l);
    r--;
    l--;
    printf("%d\n", occ[l] - occ[r]);
  }
}