Problem: Filya just learned new geometry object — rectangle. He is given a field consisting of n × n unit cells. Rows are numbered from bottom to top with integer from 1 to n. Columns are numbered from left to right with integers from 1 to n. Cell, located at the intersection of the row r and column c is denoted as (r, c). Filya has painted two rectangles, such that their sides are parallel to coordinate axes and each cell lies fully inside or fully outside each of them. Moreover, no cell lies in both rectangles.

Later, hedgehog Filya became interested in the location of his rectangles but was unable to find the sheet of paper they were painted on. They were taken by Sonya and now she wants to play a little game with Filya. He tells her a query rectangle and she replies with the number of initial rectangles that lie fully inside the given query rectangle. The query rectangle should match the same conditions as initial rectangles. Rectangle lies fully inside the query if each o its cells lies inside the query.

Filya knows Sonya really well, so is sure that if he asks more than 200 questions she will stop to reply.

Input

The first line of the input contains an integer n (2 ≤ n ≤ 216) — size of the field.

For each query an integer between 0 and 2 is returned — the number of initial rectangles that lie fully inside the query rectangle.

Output

To make a query you have to print "? x1 y1 x2 y2" (without quotes) (1 ≤ x1 ≤ x2 ≤ n, 1 ≤ y1 ≤ y2 ≤ n), where (x1, y1) stands for the position of the bottom left cell of the query and (x2, y2) stands for the up right cell of the query. You are allowed to ask no more than 200 queries. After each query you should perform "flush" operation and read the answer.

In case you suppose you've already determined the location of two rectangles (or run out of queries) you should print "! x11 y11 x12 y12 x21 y21 x22 y22" (without quotes), where first four integers describe the bottom left and up right cells of the first rectangle, and following four describe the corresponding cells of the second rectangle. You can print the rectangles in an arbitrary order. After you have printed the answer, print the end of the line and perform "flush". Your program should terminate immediately after it print the answer.

Interaction

To flush you can use (just after printing an integer and end-of-line): 

  * fflush(stdout) in C++; 
  * System.out.flush() in Java; 
  * stdout.flush() in Python; 
  * flush(output) in Pascal; 
  * See the documentation for other languages. 



You will get the Wrong Answer verdict if you ask more than 200 queries, or if you print an incorrect coordinates.

You will get the Idleness Limit Exceeded verdict if you don't print anything (but you should) or if you forget about flushing the output (more info below).

Hacking.

The first line should contain an integer n (2 ≤ n ≤ 216).

The second line should contain four integers x1, y1, x2, y2 (1 ≤ x1 ≤ x2 ≤ n, 1 ≤ y1 ≤ y2 ≤ n) — the description of the first rectangle.

The third line contains the description of the second rectangle in the similar way.

Example

Input

5
2
1
0
1
1
1
0
1


Output

? 1 1 5 5
? 1 1 3 3
? 1 1 3 1
? 2 2 2 2
? 3 3 5 5
? 3 3 3 5
? 3 3 3 4
? 3 4 3 5
! 2 2 2 2 3 4 3 5

Solution (in JAVA):

Solution:
//make sure to make new file!
import java.io.*;
import java.util.*;

public class B713{
   
   public static BufferedReader f;
   public static PrintWriter out; 
   
   public static void main(String[] args)throws IOException{
      f = new BufferedReader(new InputStreamReader(System.in));
      out = new PrintWriter(System.out);
      
      int n = Integer.parseInt(f.readLine());
      
      
      int l;
      int r;
      int mid;
      int ans;
      
      
      l = 1;
      r = n;
      ans = -1;
      //see if you can draw vertical line between them
      
      while(l <= r){
         mid = l + (r-l)/2;
         if(mid == n) break;
         
         int il = query(1,1,n,mid);
         int ir = query(1,mid+1,n,n);
         
         if(il == 1 && ir == 1){
            ans = mid;
            break;
         }
         
         if(il > ir){
            r = mid-1;
         } else {
            l = mid+1;
         }
      }
      
      int x11 = -1;
      int y11 = -1;
      int x12 = -1;
      int y12 = -1;
      int x21 = -1;
      int y21 = -1;
      int x22 = -1;
      int y22 = -1;
      if(ans == -1){
         //find horizontal line
         l = 1;
         r = n;
         ans = -1;
      
         while(l <= r){
            mid = l + (r-l)/2;
         
         
            int il = query(1,1,mid,n);
            int ir = query(mid+1,1,n,n);
         
            if(il == 1 && ir == 1){
               ans = mid;
               break;
            }
         
            if(il > ir){
               r = mid-1;
            } else {
               l = mid+1;
            }
         }
      
         int bar = ans;
         
                  //find top line of top block
         l = 1;
         r = bar;
         ans = -1;
         while(l <= r){
            mid = l + (r-l)/2;
            
            int i = query(mid,1,bar,n);
            if(i == 1){
               ans = mid;
               l = mid+1;
            } else {
               r = mid-1;
            }
         }
         
         x11 = ans;
         
         //find bottom line of top block
         l = 1;
         r = bar;
         ans = -1;
         while(l <= r){
            mid = l + (r-l)/2;
            
            int i = query(1,1,mid,n);
            if(i == 1){
               ans = mid;
               r = mid-1;
            } else {
               l = mid+1;
            }
         }
         
         x12 = ans;
         
         //find left of top block
         
         l = 1;
         r = n;
         ans = -1;
         while(l <= r){
            mid = l + (r-l)/2;
            
            int i = query(1,mid,bar,n);
            
            if(i == 1){
               ans = mid;
               l = mid+1;
            } else {
               r = mid-1;
            }
         }
         
         y11 = ans;
         
         //find right of top block
         l = 1;
         r = n;
         ans = -1;
         while(l <= r){
            mid = l + (r-l)/2;
            
            int i = query(1,1,bar,mid);
            
            if(i == 1){
               ans = mid;
               r = mid-1;
            } else {
               l = mid+1;
            }
         }
         
         y12 = ans;
         
         
         
         
         
         //find top line of bottom block
         l = bar+1;
         r = n;
         ans = -1;
         while(l <= r){
            mid = l + (r-l)/2;
            
            int i = query(mid,1,n,n);
            if(i == 1){
               ans = mid;
               l = mid+1;
            } else {
               r = mid-1;
            }
         }
         
         x21 = ans;
         
         //find bottom line of bottom block
         l = bar+1;
         r = n;
         ans = -1;
         while(l <= r){
            mid = l + (r-l)/2;
            
            int i = query(bar+1,1,mid,n);
            if(i == 1){
               ans = mid;
               r = mid-1;
            } else {
               l = mid+1;
            }
         }
         
         x22 = ans;
         
         //find left of bottom block
         
         l = 1;
         r = n;
         ans = -1;
         while(l <= r){
            mid = l + (r-l)/2;
            
            int i = query(bar+1,mid,n,n);
            
            if(i == 1){
               ans = mid;
               l = mid+1;
            } else {
               r = mid-1;
            }
         }
         
         y21 = ans;
         
         //find right of bottom block
         l = 1;
         r = n;
         ans = -1;
         while(l <= r){
            mid = l + (r-l)/2;
            
            int i = query(bar+1,1,n,mid);
            
            if(i == 1){
               ans = mid;
               r = mid-1;
            } else {
               l = mid+1;
            }
         }
         
         y22 = ans;
         
         
         
         
         
       
      } else {
         //ans is the vertical line between
         int bar = ans;
         //find left line of left block
         l = 1;
         r = bar;
         ans = -1;
         while(l <= r){
            mid = l + (r-l)/2;
            
            int i = query(1,mid,n,bar);
            if(i == 1){
               ans = mid;
               l = mid+1;
            } else {
               r = mid-1;
            }
         }
         
         y11 = ans;
         
         //find right line of left block
         l = 1;
         r = bar;
         ans = -1;
         while(l <= r){
            mid = l + (r-l)/2;
            
            int i = query(1,1,n,mid);
            if(i == 1){
               ans = mid;
               r = mid-1;
            } else {
               l = mid+1;
            }
         }
         
         y12 = ans;
         
         //find top of left block
         
         l = 1;
         r = n;
         ans = -1;
         while(l <= r){
            mid = l + (r-l)/2;
            
            int i = query(mid,1,n,bar);
            
            if(i == 1){
               ans = mid;
               l = mid+1;
            } else {
               r = mid-1;
            }
         }
         
         x11 = ans;
         
         //find bottom of left block
         l = 1;
         r = n;
         ans = -1;
         while(l <= r){
            mid = l + (r-l)/2;
            
            int i = query(1,1,mid,bar);
            
            if(i == 1){
               ans = mid;
               r = mid-1;
            } else {
               l = mid+1;
            }
         }
         
         x12 = ans;
         
         
         
         
         
         //find left line of right block
         l = bar+1;
         r = n;
         ans = -1;
         while(l <= r){
            mid = l + (r-l)/2;
            
            int i = query(1,mid,n,n);
            if(i == 1){
               ans = mid;
               l = mid+1;
            } else {
               r = mid-1;
            }
         }
         
         y21 = ans;
         
         //find right line of right block
         l = bar+1;
         r = n;
         ans = -1;
         while(l <= r){
            mid = l + (r-l)/2;
            
            int i = query(1,bar+1,n,mid);
            if(i == 1){
               ans = mid;
               r = mid-1;
            } else {
               l = mid+1;
            }
         }
         
         y22 = ans;
         
         //find top of right block
         
         l = 1;
         r = n;
         ans = -1;
         while(l <= r){
            mid = l + (r-l)/2;
            
            int i = query(mid,bar+1,n,n);
            
            if(i == 1){
               ans = mid;
               l = mid+1;
            } else {
               r = mid-1;
            }
         }
         
         x21 = ans;
         
         //find bottom of right block
         l = 1;
         r = n;
         ans = -1;
         while(l <= r){
            mid = l + (r-l)/2;
            
            int i = query(1,bar+1,mid,n);
            
            if(i == 1){
               ans = mid;
               r = mid-1;
            } else {
               l = mid+1;
            }
         }
         
         x22 = ans;
         
      
      }
      
      out.println("! " + x11 + " " + y11 + " " + x12 + " " + y12 + " " + x21 + " " + y21 + " " + x22 + " " + y22);
      
      
      
      
      out.close();
   }
   
   public static int query(int a,int b, int c, int d)throws IOException{
      out.println("? " + a + " " + b + " " + c + " " + d);
      out.flush();
      
      return Integer.parseInt(f.readLine());
   }
   
      
}