Problem: Queue is a container of elements that are inserted and deleted according to FIFO (First In First Out).

For $n$ queues $Q_i$ ($i = 0, 1, ..., n-1$), perform a sequence of the following operations.

* enqueue($t$, $x$): Insert an integer $x$ to $Q_t$.
* front($t$): Report the value which should be deleted next from $Q_t$. If $Q_t$ is empty, do nothing.
* dequeue($t$): Delete an element from $Q_t$. If $Q_t$ is empty, do nothing.



In the initial state, all queues are empty.

Constraints

* $1 \leq n \leq 1,000$
* $1 \leq q \leq 200,000$
* $-1,000,000,000 \leq x \leq 1,000,000,000$

Input

The input is given in the following format.


$n \; q$
$query_1$
$query_2$
:
$query_q$


Each query $query_i$ is given by


0 $t$ $x$


or


1 $t$


or


2 $t$


where the first digits 0, 1 and 2 represent enqueue, front and dequeue operations respectively.

Output

For each front operation, print an integer in a line.

Example

Input

3 9
0 0 1
0 0 2
0 0 3
0 2 4
0 2 5
1 0
1 2
2 0
1 0


Output

1
4
2

Solution (in JAVA):

Solution:
import java.util.ArrayList;
import java.util.List;
import java.util.Scanner;

public class Main {

	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);

		int n = sc.nextInt();
		ArrayList<List<Integer>> A = new ArrayList<>();
		for (int i = 0; i < n; i++) {
			ArrayList<Integer> B = new ArrayList<>();
			A.add(B);
		}
		int q = sc.nextInt();

		for (int i = 0; i < q; i++) {
			int x = sc.nextInt();
			if (x == 0) {
				int y = sc.nextInt();
				int z = sc.nextInt();
				A.get(y).add(z);

			} else if (x == 1) {
				int y = sc.nextInt();
				if (A.get(y).size() != 0) {
					System.out.println(A.get(y).get(0));
				}

			} else if (x == 2) {
				int y = sc.nextInt();
				if (A.get(y).size() != 0) {
					A.get(y).remove(0);
				}
			}
		}
		sc.close();
//A.get(y).size() - 1
	}

}