Problem: Queue is a container of elements that are inserted and deleted according to FIFO (First In First Out).

For $n$ queues $Q_i$ ($i = 0, 1, ..., n-1$), perform a sequence of the following operations.

* enqueue($t$, $x$): Insert an integer $x$ to $Q_t$.
* front($t$): Report the value which should be deleted next from $Q_t$. If $Q_t$ is empty, do nothing.
* dequeue($t$): Delete an element from $Q_t$. If $Q_t$ is empty, do nothing.



In the initial state, all queues are empty.

Constraints

* $1 \leq n \leq 1,000$
* $1 \leq q \leq 200,000$
* $-1,000,000,000 \leq x \leq 1,000,000,000$

Input

The input is given in the following format.


$n \; q$
$query_1$
$query_2$
:
$query_q$


Each query $query_i$ is given by


0 $t$ $x$


or


1 $t$


or


2 $t$


where the first digits 0, 1 and 2 represent enqueue, front and dequeue operations respectively.

Output

For each front operation, print an integer in a line.

Example

Input

3 9
0 0 1
0 0 2
0 0 3
0 2 4
0 2 5
1 0
1 2
2 0
1 0


Output

1
4
2

Solution (in CPP):

Solution:
#include <iostream>
#include <vector>
#include <deque>
using namespace std;

int main(){

	int n, q;
	cin >> n >> q;
	vector< deque<int> > a(n);
	int querynum = 0;
	while (querynum < q) {
		int var1;
		cin >> var1;
		if (var1 == 0) {
			int var2, var3;
			cin >> var2 >> var3;
			a[var2].push_back(var3);
		}
		else if (var1 == 1) {
			int var2;
			cin >> var2;
			if (!a[var2].empty())  cout << a[var2].front() << endl;
		}
		else {
			int var2;
			cin >> var2;
			if (!a[var2].empty()) a[var2].pop_front();
		}
		querynum++;
	}
	
	return 0;
}