Problem: Queue is a container of elements that are inserted and deleted according to FIFO (First In First Out).

For $n$ queues $Q_i$ ($i = 0, 1, ..., n-1$), perform a sequence of the following operations.

* enqueue($t$, $x$): Insert an integer $x$ to $Q_t$.
* front($t$): Report the value which should be deleted next from $Q_t$. If $Q_t$ is empty, do nothing.
* dequeue($t$): Delete an element from $Q_t$. If $Q_t$ is empty, do nothing.



In the initial state, all queues are empty.

Constraints

* $1 \leq n \leq 1,000$
* $1 \leq q \leq 200,000$
* $-1,000,000,000 \leq x \leq 1,000,000,000$

Input

The input is given in the following format.


$n \; q$
$query_1$
$query_2$
:
$query_q$


Each query $query_i$ is given by


0 $t$ $x$


or


1 $t$


or


2 $t$


where the first digits 0, 1 and 2 represent enqueue, front and dequeue operations respectively.

Output

For each front operation, print an integer in a line.

Example

Input

3 9
0 0 1
0 0 2
0 0 3
0 2 4
0 2 5
1 0
1 2
2 0
1 0


Output

1
4
2

Solution (in CPP):

Solution:
#include<bits/stdc++.h>

using namespace std;

vector<queue<int> > que;

void f0()
{
    int p1,p2;
    cin>>p1>>p2;

    que[p1].push(p2);
}

void f1()
{
    int p;
    cin>>p;

    if(!que[p].empty())
        cout<<que[p].front()<<endl;
}

void f2()
{
    int p;
    cin>>p;

    if(!que[p].empty()) que[p].pop();
}

int main()
{
    ios::sync_with_stdio(false);
    cin.tie(0);
    int n,q;

    cin>>n>>q;

    que.resize(n);

    while(q--)
    {
        int op;
        cin>>op;

        switch(op)
        {
            case 0:f0();break;
            case 1:f1();break;
            case 2:f2();break;
        }
    }


    return 0;
}