Problem: Ilya the Lion wants to help all his friends with passing exams. They need to solve the following problem to pass the IT exam.

You've got string s = s1s2... sn (n is the length of the string), consisting only of characters "." and "#" and m queries. Each query is described by a pair of integers li, ri (1 ≤ li < ri ≤ n). The answer to the query li, ri is the number of such integers i (li ≤ i < ri), that si = si + 1.

Ilya the Lion wants to help his friends but is there anyone to help him? Help Ilya, solve the problem.

Input

The first line contains string s of length n (2 ≤ n ≤ 105). It is guaranteed that the given string only consists of characters "." and "#".

The next line contains integer m (1 ≤ m ≤ 105) — the number of queries. Each of the next m lines contains the description of the corresponding query. The i-th line contains integers li, ri (1 ≤ li < ri ≤ n).

Output

Print m integers — the answers to the queries in the order in which they are given in the input.

Examples

Input

......
4
3 4
2 3
1 6
2 6


Output

1
1
5
4


Input

#..###
5
1 3
5 6
1 5
3 6
3 4


Output

1
1
2
2
0

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
inline vector<int> build_dict(const string &s) {
  vector<int> d(s.size(), 0);
  for (size_t i = 1; i < d.size(); ++i) {
    d[i] = d[i - 1];
    if (s[i - 1] == s[i]) d[i]++;
  }
  return d;
}
int main() {
  string s;
  cin >> s;
  vector<int> d = build_dict(s);
  int query_num;
  cin >> query_num;
  for (int i = 0; i < query_num; ++i) {
    int p, q;
    cin >> p >> q;
    cout << d[q - 1] - d[p - 1] << endl;
  }
  return 0;
}