Problem: You are given an array a of n integers.

You want to make all elements of a equal to zero by doing the following operation exactly three times:

  * Select a segment, for each number in this segment we can add a multiple of len to it, where len is the length of this segment (added integers can be different). 



It can be proven that it is always possible to make all elements of a equal to zero.

Input

The first line contains one integer n (1 ≤ n ≤ 100 000): the number of elements of the array.

The second line contains n elements of an array a separated by spaces: a_1, a_2, ..., a_n (-10^9 ≤ a_i ≤ 10^9).

Output

The output should contain six lines representing three operations.

For each operation, print two lines:

  * The first line contains two integers l, r (1 ≤ l ≤ r ≤ n): the bounds of the selected segment.

  * The second line contains r-l+1 integers b_l, b_{l+1}, ..., b_r (-10^{18} ≤ b_i ≤ 10^{18}): the numbers to add to a_l, a_{l+1}, …, a_r, respectively; b_i should be divisible by r - l + 1.

Example

Input


4
1 3 2 4


Output


1 1 
-1
3 4
4 2
2 4
-3 -6 -6

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
const long long int mod = 1000000007;
const long long int N = 200005;
const long long int inf = 1e18;
vector<long long int> vis(N);
vector<vector<long long int>> adj(N);
bool isPrime(long long n) {
  if (n < 2) return false;
  for (long long i = 2; i * i <= n; ++i) {
    if (n % i == 0) {
      return false;
    }
  }
  return true;
}
long long power(long long x, long long y) {
  long long res = 1;
  x = x;
  while (y > 0) {
    if (y & 1) res = (res * x) % mod;
    y = y >> 1;
    x = (x * x) % mod;
  }
  return res % mod;
}
long long gcd(long long a, long long b) {
  if (a == 0) return b;
  return gcd(b % a, a);
}
long long lcm(long long a, long long b) { return (a / gcd(a, b) * b); }
long long max(long long a, long long b) {
  long long ans = a > b ? a : b;
  return ans;
}
long long min(long long a, long long b) {
  long long ans = a < b ? a : b;
  return ans;
}
void segtree(long long int a[], long long int seg[], long long int l,
             long long int h, long long int pos) {
  if (l == h) {
    seg[pos] = a[l];
    return;
  }
  long long int mid = (l + h) / 2;
  segtree(a, seg, l, mid, 2 * pos + 1);
  segtree(a, seg, mid + 1, h, 2 * pos + 2);
  seg[pos] = max(seg[2 * pos + 1], seg[2 * pos + 2]);
}
long long int query(long long int seg[], long long int x, long long int l,
                    long long int h, long long int pos) {
  if (l == h) {
    if (seg[pos] >= x) return l;
  }
  long long int mid = (l + h) / 2;
  if (seg[2 * pos + 1] >= x) {
    return query(seg, x, l, mid, 2 * pos + 1);
  } else if (seg[2 * pos + 2] >= x) {
    return query(seg, x, mid + 1, h, 2 * pos + 2);
  } else {
    return -1;
  }
}
void updatequery(long long int seg[], long long int l, long long int h,
                 long long int x, long long int y, long long int pos) {
  if (l == h) {
    seg[pos] = y;
    return;
  }
  long long int mid = (l + h) / 2;
  if (x <= mid)
    updatequery(seg, l, mid, x, y, 2 * pos + 1);
  else
    updatequery(seg, mid + 1, h, x, y, 2 * pos + 2);
  seg[pos] = max(seg[2 * pos + 1], seg[2 * pos + 2]);
}
void fun() {}
signed main() {
  ios_base::sync_with_stdio(0);
  cin.tie(0);
  cout.tie(0);
  ;
  fun();
  long long int tt = 1;
  while (tt--) {
    long long int n;
    cin >> n;
    long long int a[n];
    for (long long int i = 0; i < n; i++) cin >> a[i];
    if (n == 1) {
      cout << "1 1"
           << "\n"
           << "0"
           << "\n"
           << "1 1"
           << "\n"
           << "0"
           << "\n"
           << "1 1"
           << "\n"
           << -a[0];
    } else {
      cout << "1 " << n << "\n";
      for (long long int i = 0; i < n; i++) {
        cout << -(n * a[i]) << " ";
        a[i] -= (n * a[i]);
      }
      cout << "\n";
      cout << "2 " << n << "\n";
      for (long long int i = 1; i < n; i++) {
        cout << -a[i] << " ";
        a[i] = 0;
      }
      cout << "\n";
      cout << "1 1"
           << "\n";
      cout << -a[0];
    }
  }
  return 0;
}