Problem: Ilya the Lion wants to help all his friends with passing exams. They need to solve the following problem to pass the IT exam.

You've got string s = s1s2... sn (n is the length of the string), consisting only of characters "." and "#" and m queries. Each query is described by a pair of integers li, ri (1 ≤ li < ri ≤ n). The answer to the query li, ri is the number of such integers i (li ≤ i < ri), that si = si + 1.

Ilya the Lion wants to help his friends but is there anyone to help him? Help Ilya, solve the problem.

Input

The first line contains string s of length n (2 ≤ n ≤ 105). It is guaranteed that the given string only consists of characters "." and "#".

The next line contains integer m (1 ≤ m ≤ 105) — the number of queries. Each of the next m lines contains the description of the corresponding query. The i-th line contains integers li, ri (1 ≤ li < ri ≤ n).

Output

Print m integers — the answers to the queries in the order in which they are given in the input.

Examples

Input

......
4
3 4
2 3
1 6
2 6


Output

1
1
5
4


Input

#..###
5
1 3
5 6
1 5
3 6
3 4


Output

1
1
2
2
0

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int getint() {
  int ans(0);
  char w = getchar();
  while (w < '0' || '9' < w) w = getchar();
  while ('0' <= w && w <= '9') {
    ans = ans * 10 + w - '0';
    w = getchar();
  }
  return ans;
}
int main() {
  int m, l, r;
  string s;
  cin >> s >> m;
  int n = s.length();
  int* dp = new int[n];
  dp[0] = 0;
  for (int i = 0; i < n - 1; i++) {
    dp[i + 1] = dp[i] + ((s[i] == s[i + 1]) ? 1 : 0);
  }
  for (int i = 0; i < m; i++) {
    l = getint();
    r = getint();
    printf("%d\n", dp[r - 1] - dp[l - 1]);
  }
  delete dp;
  return 0;
}