Problem: Ilya the Lion wants to help all his friends with passing exams. They need to solve the following problem to pass the IT exam.

You've got string s = s1s2... sn (n is the length of the string), consisting only of characters "." and "#" and m queries. Each query is described by a pair of integers li, ri (1 ≤ li < ri ≤ n). The answer to the query li, ri is the number of such integers i (li ≤ i < ri), that si = si + 1.

Ilya the Lion wants to help his friends but is there anyone to help him? Help Ilya, solve the problem.

Input

The first line contains string s of length n (2 ≤ n ≤ 105). It is guaranteed that the given string only consists of characters "." and "#".

The next line contains integer m (1 ≤ m ≤ 105) — the number of queries. Each of the next m lines contains the description of the corresponding query. The i-th line contains integers li, ri (1 ≤ li < ri ≤ n).

Output

Print m integers — the answers to the queries in the order in which they are given in the input.

Examples

Input

......
4
3 4
2 3
1 6
2 6


Output

1
1
5
4


Input

#..###
5
1 3
5 6
1 5
3 6
3 4


Output

1
1
2
2
0

Solution (in JAVA):

Solution:

import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.BufferedReader;
import java.io.OutputStream;
import java.io.PrintWriter;
import java.io.IOException;
import java.util.Arrays;
import java.util.StringTokenizer;

public class B313 {

    public static BufferedReader in;
    public static PrintWriter out;
    public static StringTokenizer tokenizer;

    public static void main(String[] args) {
        InputStream inputStream = System.in;
        OutputStream outputStream = System.out;
        in = new BufferedReader(new InputStreamReader(inputStream), 32768);
        out = new PrintWriter(outputStream);
        solve();
        out.close();
    }

    public static void solve() {
        String s = next();
        int[] d = new int[s.length() + 1];
        d[0] = 0;
        for (int i = 1; i < s.length(); i++) {
            d[i] = d[i - 1];
            if (s.charAt(i) == s.charAt(i - 1)) {
                d[i]++;
            }
        }
        int n = nextInt();
        for (int i = 0; i < n; i++) {
            int l = nextInt() - 1;
            int r = nextInt() - 1;
            out.println(d[r] - d[l]);
        }
    }

    public static String next() {
        while (tokenizer == null || !tokenizer.hasMoreTokens()) {
            try {
                tokenizer = new StringTokenizer(in.readLine());
            } catch (IOException e) {
                throw new RuntimeException(e);
            }
        }
        return tokenizer.nextToken();
    }

    public static int nextInt() {
        return Integer.parseInt(next());
    }

    public static long nextLong() {
        return Long.parseLong(next());
    }

    public static double nextDouble() {
        return Double.parseDouble(next());
    }
}