Problem: Pavel loves grid mazes. A grid maze is an n × m rectangle maze where each cell is either empty, or is a wall. You can go from one cell to another only if both cells are empty and have a common side.

Pavel drew a grid maze with all empty cells forming a connected area. That is, you can go from any empty cell to any other one. Pavel doesn't like it when his maze has too little walls. He wants to turn exactly k empty cells into walls so that all the remaining cells still formed a connected area. Help him.

Input

The first line contains three integers n, m, k (1 ≤ n, m ≤ 500, 0 ≤ k < s), where n and m are the maze's height and width, correspondingly, k is the number of walls Pavel wants to add and letter s represents the number of empty cells in the original maze.

Each of the next n lines contains m characters. They describe the original maze. If a character on a line equals ".", then the corresponding cell is empty and if the character equals "#", then the cell is a wall.

Output

Print n lines containing m characters each: the new maze that fits Pavel's requirements. Mark the empty cells that you transformed into walls as "X", the other cells must be left without changes (that is, "." and "#").

It is guaranteed that a solution exists. If there are multiple solutions you can output any of them.

Examples

Input

3 4 2
#..#
..#.
#...


Output

#.X#
X.#.
#...


Input

5 4 5
#...
#.#.
.#..
...#
.#.#


Output

#XXX
#X#.
X#..
...#
.#.#

Solution (in JAVA):

Solution:
import java.io.BufferedOutputStream;
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.util.HashMap;
import java.util.LinkedList;
import java.util.StringTokenizer;

public class Problem23 {

	public static class Point{
		int x;
		int y;
		public Point(int x,int y) {
			this.x=x;
			this.y=y;
		}
	}
	
	public static int k;
	public static int[][] matrix;
	public static LinkedList<Integer>[] adj;
	public static HashMap<Integer,Point> helper;
	
	public static void dfs(int current ,boolean[] visited) {
		visited[current]=true;
		for(Integer x:adj[current]) {
			if(!visited[x]) {
				dfs(x,visited);
			}
		}
		if(k>0) {
			Point current_point=helper.get(current);
			matrix[current_point.x][current_point.y]=-2;
			k--;
		}
	}
	
	public static void main(String[] args) {
		// TODO Auto-generated method stub
		out=new PrintWriter (new BufferedOutputStream(System.out));
		FastReader s=new FastReader();
		int n=s.nextInt();
		int m=s.nextInt();
		k=s.nextInt();
		matrix=new int[n][m];
		int count=1;
		helper=new HashMap<Integer,Point>();
		for(int i=0;i<n;i++) {
			String temp=s.next();
			for(int j=0;j<temp.length();j++) {
				if(temp.charAt(j)=='.') {
					helper.put(count, new Point(i,j));
					matrix[i][j]=count++;
				}else {
					matrix[i][j]=-1;
				}
			}
		}
		adj=new LinkedList[count+1];
		for(int i=0;i<count;i++) {
			adj[i]=new LinkedList<Integer>();
		}
		for(int i=0;i<n;i++) {
			for(int j=0;j<m;j++) {
				if(matrix[i][j]!=-1) {
					if(i+1<n && matrix[i+1][j]!=-1) {
						int u=matrix[i][j];
						int v=matrix[i+1][j];
						adj[u].add(v);
						adj[v].add(u);
					}
					if(j+1<m && matrix[i][j+1]!=-1) {
						int u=matrix[i][j];
						int v=matrix[i][j+1];
						adj[u].add(v);
						adj[v].add(u);
					}
				}
			}
		}
		dfs(1,new boolean[count+1]);
		for(int i=0;i<n;i++) {
			for(int j=0;j<m;j++) {
				if(matrix[i][j]==-1) {
					out.print('#');
				}else if(matrix[i][j]==-2) {
					out.print('X');
				}else {
					out.print('.');
				}
			}
			out.println();
		}
		out.close();
	}

	public static PrintWriter out;
	
	public static class FastReader {
		BufferedReader br;
		StringTokenizer st;
		//it reads the data about the specified point and divide the data about it ,it is quite fast
		//than using direct 

		public FastReader() {
			br = new BufferedReader(new InputStreamReader(System.in));
			//InputStream reads the data and decodes in character stream
			//It acts as bridge between byte stream and character stream
		}

		String next() {
			while (st == null || !st.hasMoreTokens()) {
				try {
					st = new StringTokenizer(br.readLine());
				} catch (Exception e) {
					e.printStackTrace();
				}
			}
			return st.nextToken();
		}

		int nextInt() {
			return Integer.parseInt(next());//converts string to integer
		}

		double nextDouble() {
			return Double.parseDouble(next());
		}

		long nextLong() {
			return Long.parseLong(next());
		}

		String nextLine() {
			String str = "";
			try {
				str = br.readLine();
			} catch (Exception e) {
				e.printStackTrace();
			}
			return str;
		}
	}
	
}