Problem: Queue is a container of elements that are inserted and deleted according to FIFO (First In First Out).

For $n$ queues $Q_i$ ($i = 0, 1, ..., n-1$), perform a sequence of the following operations.

* enqueue($t$, $x$): Insert an integer $x$ to $Q_t$.
* front($t$): Report the value which should be deleted next from $Q_t$. If $Q_t$ is empty, do nothing.
* dequeue($t$): Delete an element from $Q_t$. If $Q_t$ is empty, do nothing.



In the initial state, all queues are empty.

Constraints

* $1 \leq n \leq 1,000$
* $1 \leq q \leq 200,000$
* $-1,000,000,000 \leq x \leq 1,000,000,000$

Input

The input is given in the following format.


$n \; q$
$query_1$
$query_2$
:
$query_q$


Each query $query_i$ is given by


0 $t$ $x$


or


1 $t$


or


2 $t$


where the first digits 0, 1 and 2 represent enqueue, front and dequeue operations respectively.

Output

For each front operation, print an integer in a line.

Example

Input

3 9
0 0 1
0 0 2
0 0 3
0 2 4
0 2 5
1 0
1 2
2 0
1 0


Output

1
4
2

Solution (in PYTHON3):

Solution:
class Node:
  def __init__(self,key):
    self.key = key
    self.prev = None
    self.next = None

class Queue:
  def __init__(self):
    self.head = Node(0)
    self.tail = self.head

  def enqueue(self,key):
    node = Node(key)
    self.tail.next = node
    node.prev = self.tail
    self.tail = node

  def front(self):
    if self.head != self.tail:
      return self.head.next.key

  def dequeue(self):
    if self.head != self.tail:
      if self.head.next == self.tail:
        self.tail = self.head
      self.head.next = self.head.next.next


n,q = map(int,input().split())

Q = [Queue() for i in range(n)]

for i in range(q):
  com, index, *n = map(int,input().split())
  if com == 0:
    Q[index].enqueue(*n)
  elif com == 1:
    key = Q[index].front()
    if key != None:
      print(key)
  elif com == 2:
    Q[index].dequeue()