Problem: We have N points numbered 1 to N arranged in a line in this order.

Takahashi decides to make an undirected graph, using these points as the vertices. In the beginning, the graph has no edge. Takahashi will do M operations to add edges in this graph. The i-th operation is as follows:

* The operation uses integers L_i and R_i between 1 and N (inclusive), and a positive integer C_i. For every pair of integers (s, t) such that L_i \leq s < t \leq R_i, add an edge of length C_i between Vertex s and Vertex t.



The integers L_1, ..., L_M, R_1, ..., R_M, C_1, ..., C_M are all given as input.

Takahashi wants to solve the shortest path problem in the final graph obtained. Find the length of the shortest path from Vertex 1 to Vertex N in the final graph.

Constraints

* 2 \leq N \leq 10^5
* 1 \leq M \leq 10^5
* 1 \leq L_i < R_i \leq N
* 1 \leq C_i \leq 10^9

Input

Input is given from Standard Input in the following format:


N M
L_1 R_1 C_1
:
L_M R_M C_M


Output

Print the length of the shortest path from Vertex 1 to Vertex N in the final graph. If there is no shortest path, print `-1` instead.

Examples

Input

4 3
1 3 2
2 4 3
1 4 6


Output

5


Input

4 2
1 2 1
3 4 2


Output

-1


Input

10 7
1 5 18
3 4 8
1 3 5
4 7 10
5 9 8
6 10 5
8 10 3


Output

28

Solution (in PYTHON3):

Solution:
import sys
from collections import defaultdict
from heapq import *

sys.setrecursionlimit(10 ** 6)
input = sys.stdin.readline
int1 = lambda x: int(x) - 1
p2D = lambda x: print(*x, sep="\n")

def main():
    to = defaultdict(list)
    n, m = map(int, input().split())
    for _ in range(m):
        l, r, c = map(int, input().split())
        l, r = l - 1, r - 1
        to[l].append([r, c])
    costs = [-1] * n
    hp = []
    heappush(hp, [0, 0])
    while hp:
        # print(hp)
        c, u = heappop(hp)
        if u == n - 1:
            print(c)
            # print(costs)
            exit()
        if costs[u] != -1: continue
        costs[u] = c
        for v, dc in to[u]:
            if costs[v] != -1: continue
            heappush(hp, [c + dc, v])
        for v in range(u - 1, 0, -1):
            if costs[v] != -1: break
            heappush(hp, [c, v])
    print(-1)

main()