Problem: Dreamoon is standing at the position 0 on a number line. Drazil is sending a list of commands through Wi-Fi to Dreamoon's smartphone and Dreamoon follows them.

Each command is one of the following two types: 

  1. Go 1 unit towards the positive direction, denoted as '+'
  2. Go 1 unit towards the negative direction, denoted as '-'



But the Wi-Fi condition is so poor that Dreamoon's smartphone reports some of the commands can't be recognized and Dreamoon knows that some of them might even be wrong though successfully recognized. Dreamoon decides to follow every recognized command and toss a fair coin to decide those unrecognized ones (that means, he moves to the 1 unit to the negative or positive direction with the same probability 0.5). 

You are given an original list of commands sent by Drazil and list received by Dreamoon. What is the probability that Dreamoon ends in the position originally supposed to be final by Drazil's commands?

Input

The first line contains a string s1 — the commands Drazil sends to Dreamoon, this string consists of only the characters in the set {'+', '-'}. 

The second line contains a string s2 — the commands Dreamoon's smartphone recognizes, this string consists of only the characters in the set {'+', '-', '?'}. '?' denotes an unrecognized command.

Lengths of two strings are equal and do not exceed 10.

Output

Output a single real number corresponding to the probability. The answer will be considered correct if its relative or absolute error doesn't exceed 10 - 9.

Examples

Input

++-+-
+-+-+


Output

1.000000000000


Input

+-+-
+-??


Output

0.500000000000


Input

+++
??-


Output

0.000000000000

Note

For the first sample, both s1 and s2 will lead Dreamoon to finish at the same position  + 1. 

For the second sample, s1 will lead Dreamoon to finish at position 0, while there are four possibilites for s2: {"+-++", "+-+-", "+--+", "+---"} with ending position {+2, 0, 0, -2} respectively. So there are 2 correct cases out of 4, so the probability of finishing at the correct position is 0.5. 

For the third sample, s2 could only lead us to finish at positions {+1, -1, -3}, so the probability to finish at the correct position  + 3 is 0.

Solution (in JAVA):

Solution:
import java.io.BufferedInputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.OutputStream;
import java.io.PrintWriter;
import java.util.ArrayList;
import java.util.List;

public class Main {

    private final static InputReader inputReader = new InputReader(System.in);
    private final static OutputWriter outputWriter = new OutputWriter(System.out);

    public static void main(String[] args) throws IOException {
        int numberOfTestCases = 1;//inputReader.scanInt();
        for (int testCase = 1; testCase <= numberOfTestCases; ++testCase) {
            final ProblemParameters parameters = new ProblemParameters();
            parameters.orignalCommand = inputReader.scanString();
            parameters.receivedCommand = inputReader.scanString();

            final Solver solver = new Solver(parameters);
            solver.solve();
        }

        outputWriter.close();
    }

    static class Solver {

        private final ProblemParameters parameters;
        private double totalNumberOfMoves;
        private double desiredMoves;

        public Solver(final ProblemParameters parameters) {
            this.parameters = parameters;
            this.totalNumberOfMoves = 0;
            this.desiredMoves = 0;
        }

        public void solve() {
            explore(0, 0, 0);
            final double answer = desiredMoves/totalNumberOfMoves;
            outputWriter.println(answer);
        }

        private void explore(int currentCommand, int originalValue, int receivedValue) {
            if (currentCommand == parameters.orignalCommand.length()) {
                totalNumberOfMoves++;
                desiredMoves += (originalValue == receivedValue) ? 1 : 0;

                return;
            }

            originalValue += (parameters.orignalCommand.charAt(currentCommand) == '+' ? 1 : -1);
            if (parameters.receivedCommand.charAt(currentCommand) == '?') {
                explore(currentCommand + 1, originalValue, receivedValue + 1);
                explore(currentCommand + 1, originalValue, receivedValue - 1);
            } else {
                receivedValue += (parameters.receivedCommand.charAt(currentCommand) == '+' ? 1 : -1);
                explore(currentCommand + 1, originalValue, receivedValue);
            }
        }
    }

    static class ProblemParameters {

        String orignalCommand;
        String receivedCommand;
    }

    // We can use abstract method or loaner pattern to create different classes for different dataTypes and
    // keep repeated code in with generic class. But can't follow OOPS in CP :( because of TLE or MLE.
    // So try to use less object creation in CP.
    static class InputReader {

        private final BufferedInputStream bufferedInputStream;

        private final static char NEGATIVE_CHAR = '-';
        private final static char SPACE_CHAR = ' ';
        private final static char TAB_CHAR = '\t';
        private final static char NEW_LINE_WITH_N = '\n';
        private final static char NEW_LINE_WITH_R = '\r';
        private final static int END_OF_INPUT_STREAM = -1;

        public InputReader(final InputStream inputStream) {
            bufferedInputStream = new BufferedInputStream(inputStream);
        }

        public int scanInt() throws IOException {
            int currentByte = findFirstUsefulByte();
            boolean isNegative = false;
            if (currentByte == NEGATIVE_CHAR) {
                isNegative = true;
                currentByte = bufferedInputStream.read();
            }

            int number = 0;
            while (isUsefulByte(currentByte)) {
                number = (number * 10) + (currentByte - '0');
                currentByte = bufferedInputStream.read();
            }

            return isNegative ? -number : number;
        }

        public long scanLong() throws IOException {
            int currentByte = findFirstUsefulByte();
            boolean isNegative = false;
            if (currentByte == NEGATIVE_CHAR) {
                isNegative = true;
                currentByte = bufferedInputStream.read();
            }

            long number = 0;
            while (isUsefulByte(currentByte)) {
                number = (number * 10) + (currentByte - '0');
                currentByte = bufferedInputStream.read();
            }

            return isNegative ? -number : number;
        }

        public String scanString() throws IOException {
            int currentByte = findFirstUsefulByte();
            final StringBuilder stringBuilder = new StringBuilder();
            while (isUsefulByte(currentByte)) {
                stringBuilder.append((char) currentByte);
                currentByte = bufferedInputStream.read();
            }

            return stringBuilder.toString();
        }

        public double scanDouble() throws IOException { //Reason to use java's parser is because we had to write a lot of cases to handle floating point problems.
            return Double.parseDouble(scanString());
        }

        public List<Integer> scanListOfIntegers(int numbersCount) throws IOException {
            final List<Integer> numberList = new ArrayList<>();
            while (numbersCount-- > 0) {
                numberList.add(scanInt());
            }

            return numberList;
        }

        public List<Long> scanListOfLongs(int numbersCount) throws IOException {
            final List<Long> numberList = new ArrayList<>();
            while (numbersCount-- > 0) {
                numberList.add(scanLong());
            }

            return numberList;
        }

        public List<String> scanListOfStrings(int numbersCount) throws IOException {
            final List<String> stringList = new ArrayList<>();
            while (numbersCount-- > 0) {
                stringList.add(scanString());
            }

            return stringList;
        }

        public List<Double> scanListOfDoubles(int numbersCount) throws IOException {
            final List<Double> doubleList = new ArrayList<>();
            while (numbersCount-- > 0) {
                doubleList.add(scanDouble());
            }

            return doubleList;
        }

        private int findFirstUsefulByte() throws IOException {
            int currentByte = bufferedInputStream.read();
            while (!isUsefulByte(currentByte)) {
                currentByte = bufferedInputStream.read();
            }

            return currentByte;
        }

        private boolean isUsefulByte(final int currentByte) {
            if (currentByte == SPACE_CHAR || NEW_LINE_WITH_N == currentByte || NEW_LINE_WITH_R == currentByte
                || currentByte == TAB_CHAR || currentByte == END_OF_INPUT_STREAM) {
                return false;
            }
            else {
                return true;
            }
        }
    }

    // Try to use it in tr-resource block.
    // To avoid close call manually.
    static class OutputWriter implements AutoCloseable {

        private final static boolean IS_AUTO_FLUSH_FOR_NEW_LINE = true;
        private final PrintWriter printWriter;

        public OutputWriter(final OutputStream outputStream) {
            this.printWriter = new PrintWriter(outputStream, IS_AUTO_FLUSH_FOR_NEW_LINE);
        }

        public void print(Object... objects) {
            for (int objectIndex = 0; objectIndex < objects.length; ++objectIndex) {
                if (objectIndex != 0) {
                    printWriter.print(' ');
                }
                printWriter.print(objects[objectIndex]);
            }
        }

        public void println(Object... objects) {
            print(objects);
            printWriter.println();
        }

        public void flush() { //Force flush if require after printing each element on one line
            printWriter.flush();
        }

        public void close() {
            printWriter.close();
        }
    }
}