Problem: Ilya the Lion wants to help all his friends with passing exams. They need to solve the following problem to pass the IT exam.

You've got string s = s1s2... sn (n is the length of the string), consisting only of characters "." and "#" and m queries. Each query is described by a pair of integers li, ri (1 ≤ li < ri ≤ n). The answer to the query li, ri is the number of such integers i (li ≤ i < ri), that si = si + 1.

Ilya the Lion wants to help his friends but is there anyone to help him? Help Ilya, solve the problem.

Input

The first line contains string s of length n (2 ≤ n ≤ 105). It is guaranteed that the given string only consists of characters "." and "#".

The next line contains integer m (1 ≤ m ≤ 105) — the number of queries. Each of the next m lines contains the description of the corresponding query. The i-th line contains integers li, ri (1 ≤ li < ri ≤ n).

Output

Print m integers — the answers to the queries in the order in which they are given in the input.

Examples

Input

......
4
3 4
2 3
1 6
2 6


Output

1
1
5
4


Input

#..###
5
1 3
5 6
1 5
3 6
3 4


Output

1
1
2
2
0

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
vector<int> solve(string a) {
  vector<int> ans(a.size());
  ans[0] = 1;
  for (int i = 1; i < a.size(); i++) {
    if (a[i] == a[i - 1]) {
      ans[i] = ans[i - 1] + 1;
    } else {
      ans[i] = ans[i - 1];
    }
  }
  return ans;
}
int main() {
  string h;
  while (cin >> h) {
    int n;
    cin >> n;
    auto ans = solve(h);
    vector<int> a;
    for (int i = 1; i <= n; i++) {
      int c, b;
      cin >> c >> b;
      a.push_back(ans[b - 1] - ans[c - 1]);
    }
    for_each(a.begin(), a.end(), [](int a) { cout << a << endl; });
  }
  return 0;
}