Problem: We have N points numbered 1 to N arranged in a line in this order.

Takahashi decides to make an undirected graph, using these points as the vertices. In the beginning, the graph has no edge. Takahashi will do M operations to add edges in this graph. The i-th operation is as follows:

* The operation uses integers L_i and R_i between 1 and N (inclusive), and a positive integer C_i. For every pair of integers (s, t) such that L_i \leq s < t \leq R_i, add an edge of length C_i between Vertex s and Vertex t.



The integers L_1, ..., L_M, R_1, ..., R_M, C_1, ..., C_M are all given as input.

Takahashi wants to solve the shortest path problem in the final graph obtained. Find the length of the shortest path from Vertex 1 to Vertex N in the final graph.

Constraints

* 2 \leq N \leq 10^5
* 1 \leq M \leq 10^5
* 1 \leq L_i < R_i \leq N
* 1 \leq C_i \leq 10^9

Input

Input is given from Standard Input in the following format:


N M
L_1 R_1 C_1
:
L_M R_M C_M


Output

Print the length of the shortest path from Vertex 1 to Vertex N in the final graph. If there is no shortest path, print `-1` instead.

Examples

Input

4 3
1 3 2
2 4 3
1 4 6


Output

5


Input

4 2
1 2 1
3 4 2


Output

-1


Input

10 7
1 5 18
3 4 8
1 3 5
4 7 10
5 9 8
6 10 5
8 10 3


Output

28

Solution (in PYTHON3):

Solution:
n,m = map(int,input().split())
abd = [list(map(int,input().split())) for i in range(m)]
graph = [[] for i in range(n+1)]
for a,b,d in abd:
  graph[a].append((b,d))
for i in range(1,n):
  graph[i+1].append((i,0))
import heapq as hq
dist = [10**18]*(n+1)
dist[1] = 0
q = [(0,1)]
hq.heapify(q)
while q:
  d,x = hq.heappop(q)
  for y,dd in graph[x]:
    if dist[y] > dist[x]+dd:
      dist[y] = dist[x]+dd
      hq.heappush(q,(dist[y],y))
if dist[n] == 10**18:
  print(-1)
else:
  print(dist[n])