Problem: Queue is a container of elements that are inserted and deleted according to FIFO (First In First Out).

For $n$ queues $Q_i$ ($i = 0, 1, ..., n-1$), perform a sequence of the following operations.

* enqueue($t$, $x$): Insert an integer $x$ to $Q_t$.
* front($t$): Report the value which should be deleted next from $Q_t$. If $Q_t$ is empty, do nothing.
* dequeue($t$): Delete an element from $Q_t$. If $Q_t$ is empty, do nothing.



In the initial state, all queues are empty.

Constraints

* $1 \leq n \leq 1,000$
* $1 \leq q \leq 200,000$
* $-1,000,000,000 \leq x \leq 1,000,000,000$

Input

The input is given in the following format.


$n \; q$
$query_1$
$query_2$
:
$query_q$


Each query $query_i$ is given by


0 $t$ $x$


or


1 $t$


or


2 $t$


where the first digits 0, 1 and 2 represent enqueue, front and dequeue operations respectively.

Output

For each front operation, print an integer in a line.

Example

Input

3 9
0 0 1
0 0 2
0 0 3
0 2 4
0 2 5
1 0
1 2
2 0
1 0


Output

1
4
2

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;


void solve(){
  int n, q; cin >> n >> q;
  vector<queue<int> > qq(n);
  while(q--){
    int type; cin >> type;
    switch(type){
      case 0:
        int t0, x; cin >> t0 >> x;
        qq[t0].push(x);
        break;
      case 1:
        int t1; cin >> t1;
        if(!qq[t1].empty())
        cout << qq[t1].front() << endl;
        break;
      case 2:
        int t2; cin >> t2;
        if(!qq[t2].empty()){
          qq[t2].pop();
        }
        break;
      default: 
        cout << "Error" << endl;  
    }
  }
}

int main(){
  solve();
  return 0;
}