Problem: Ilya the Lion wants to help all his friends with passing exams. They need to solve the following problem to pass the IT exam.

You've got string s = s1s2... sn (n is the length of the string), consisting only of characters "." and "#" and m queries. Each query is described by a pair of integers li, ri (1 ≤ li < ri ≤ n). The answer to the query li, ri is the number of such integers i (li ≤ i < ri), that si = si + 1.

Ilya the Lion wants to help his friends but is there anyone to help him? Help Ilya, solve the problem.

Input

The first line contains string s of length n (2 ≤ n ≤ 105). It is guaranteed that the given string only consists of characters "." and "#".

The next line contains integer m (1 ≤ m ≤ 105) — the number of queries. Each of the next m lines contains the description of the corresponding query. The i-th line contains integers li, ri (1 ≤ li < ri ≤ n).

Output

Print m integers — the answers to the queries in the order in which they are given in the input.

Examples

Input

......
4
3 4
2 3
1 6
2 6


Output

1
1
5
4


Input

#..###
5
1 3
5 6
1 5
3 6
3 4


Output

1
1
2
2
0

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
const long long maxn = 100005;
const double pi = acos(-1);
using namespace std;
int dp[maxn] = {0};
int main() {
  string s;
  cin >> s;
  int n = s.length();
  int t;
  cin >> t;
  if (s[0] == s[1]) {
    dp[0] = 1;
  }
  for (int i = 1; i < n - 1; i++) {
    if (s[i] == s[i + 1]) {
      dp[i] = dp[i - 1] + 1;
    } else {
      dp[i] = dp[i - 1];
    }
  }
  dp[n - 1] = dp[n - 2];
  for (int i = 0; i < n; i++) {
  }
  cout << endl;
  while (t--) {
    int l, r;
    cin >> l >> r;
    l--;
    r--;
    cout << dp[l] - dp[l - 1] + dp[--r] - dp[l] << endl;
  }
  return 0;
}