Problem: Ilya the Lion wants to help all his friends with passing exams. They need to solve the following problem to pass the IT exam.

You've got string s = s1s2... sn (n is the length of the string), consisting only of characters "." and "#" and m queries. Each query is described by a pair of integers li, ri (1 ≤ li < ri ≤ n). The answer to the query li, ri is the number of such integers i (li ≤ i < ri), that si = si + 1.

Ilya the Lion wants to help his friends but is there anyone to help him? Help Ilya, solve the problem.

Input

The first line contains string s of length n (2 ≤ n ≤ 105). It is guaranteed that the given string only consists of characters "." and "#".

The next line contains integer m (1 ≤ m ≤ 105) — the number of queries. Each of the next m lines contains the description of the corresponding query. The i-th line contains integers li, ri (1 ≤ li < ri ≤ n).

Output

Print m integers — the answers to the queries in the order in which they are given in the input.

Examples

Input

......
4
3 4
2 3
1 6
2 6


Output

1
1
5
4


Input

#..###
5
1 3
5 6
1 5
3 6
3 4


Output

1
1
2
2
0

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int countArray[100005];
void preProcess(char s[], int n) {
  countArray[0] = (s[0] == s[1]) ? 1 : 0;
  for (int i = 1; i < n; i++) {
    if (s[i] == s[i + 1])
      countArray[i] += (countArray[i - 1] + 1);
    else
      countArray[i] = countArray[i - 1];
  }
}
int query(char s[], int i, int j) {
  int ans = countArray[j - 2] - countArray[i - 1];
  if (s[i - 1] == s[i]) ans++;
  return ans;
}
char s[100005];
int main() {
  scanf("%s", s);
  int n = strlen(s);
  preProcess(s, n);
  int m, i, j;
  scanf("%d", &m);
  while (m--) {
    scanf("%d", &i);
    scanf("%d", &j);
    printf("%d\n", query(s, i, j));
  }
  return 0;
}