Problem: Queue is a container of elements that are inserted and deleted according to FIFO (First In First Out).

For $n$ queues $Q_i$ ($i = 0, 1, ..., n-1$), perform a sequence of the following operations.

* enqueue($t$, $x$): Insert an integer $x$ to $Q_t$.
* front($t$): Report the value which should be deleted next from $Q_t$. If $Q_t$ is empty, do nothing.
* dequeue($t$): Delete an element from $Q_t$. If $Q_t$ is empty, do nothing.



In the initial state, all queues are empty.

Constraints

* $1 \leq n \leq 1,000$
* $1 \leq q \leq 200,000$
* $-1,000,000,000 \leq x \leq 1,000,000,000$

Input

The input is given in the following format.


$n \; q$
$query_1$
$query_2$
:
$query_q$


Each query $query_i$ is given by


0 $t$ $x$


or


1 $t$


or


2 $t$


where the first digits 0, 1 and 2 represent enqueue, front and dequeue operations respectively.

Output

For each front operation, print an integer in a line.

Example

Input

3 9
0 0 1
0 0 2
0 0 3
0 2 4
0 2 5
1 0
1 2
2 0
1 0


Output

1
4
2

Solution (in CPP):

Solution:
#include <queue>
#include <vector>
#include <iostream>

using std::cin;
using std::cout;
using std::endl;
using std::queue;
using std::vector;

int main() {
	int n,q;
	cin >> n >> q;
	vector< queue<int> > qv(n);
	while (q--) {
		int op,t,x;
		cin >> op >> t;
		switch (op) {
			case 0:
				cin >> x;
				qv[t].push(x);
				break;
			case 1:
				if (!qv[t].empty()) {
					cout << qv[t].front() << endl;
				}
				break;
			default:
				if (!qv[t].empty()) {
					qv[t].pop();
				}
		}
	}
}