Problem: The only difference between easy and hard versions is constraints.

You are given n segments on the coordinate axis OX. Segments can intersect, lie inside each other and even coincide. The i-th segment is [l_i; r_i] (l_i ≤ r_i) and it covers all integer points j such that l_i ≤ j ≤ r_i.

The integer point is called bad if it is covered by strictly more than k segments.

Your task is to remove the minimum number of segments so that there are no bad points at all.

Input

The first line of the input contains two integers n and k (1 ≤ k ≤ n ≤ 200) — the number of segments and the maximum number of segments by which each integer point can be covered.

The next n lines contain segments. The i-th line contains two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 200) — the endpoints of the i-th segment.

Output

In the first line print one integer m (0 ≤ m ≤ n) — the minimum number of segments you need to remove so that there are no bad points.

In the second line print m distinct integers p_1, p_2, ..., p_m (1 ≤ p_i ≤ n) — indices of segments you remove in any order. If there are multiple answers, you can print any of them.

Examples

Input


7 2
11 11
9 11
7 8
8 9
7 8
9 11
7 9


Output


3
1 4 7 


Input


5 1
29 30
30 30
29 29
28 30
30 30


Output


3
1 2 4 


Input


6 1
2 3
3 3
2 3
2 2
2 3
2 3


Output


4
1 3 5 6 

Solution (in JAVA):

Solution:
import java.util.ArrayList;
import java.util.Collections;
import java.util.Comparator;
import java.util.HashMap;
import java.util.Scanner;

public class TaskD {
	public static void main(String[] args) {
		Scanner s = new Scanner(System.in); 
		int n = s.nextInt();
		int k = s.nextInt();
		
		Seg[] segms = new Seg[n];
		Comparator<Seg> comp = new Comparator<Seg>() {
			public int compare(Seg a, Seg b) {
					return Integer.compare(a.r, b.r);
			}
		};
		
		
		for(int i=0;i<n;i++) {
			segms[i] = new Seg(s.nextInt(),s.nextInt(),i+1);
		}
		
		ArrayList ans = new ArrayList();
		int count = 0;
		
		for(int x = 1; x <= 200; x++) {
			
			ArrayList<Seg> rel = new ArrayList<Seg>();
			
			for(int i=0;i<n;i++) {
				
				if(segms[i] == null) {
					continue;
				}
				
				if(cont(x,segms[i])) {
					rel.add(segms[i]);
				}
			}
			
			//System.out.println(x + " " + rel.size());
			
			if(rel.size() > k) {
				Collections.sort(rel,comp);
				for(int i=rel.size()-1;i>=k;i--) {
					count++;
					ans.add(rel.get(i).index);
					segms[rel.get(i).index-1] = null;
				}
			}
		}
		
		System.out.println(count);
		for(int i=0;i<ans.size();i++) {
			System.out.print(ans.get(i) + " ");
		}
	}
	
	public static boolean cont(int x , Seg seg) {
		return x >= seg.l && x <= seg.r;
	}
}

class Seg {
	public int l,r,length,index;
	
	public Seg(int l,int r, int index) {
		this.l = l;
		this.r = r;
		this.index = index;
		
		length = r-l+1;
	}
}