Problem: Ilya the Lion wants to help all his friends with passing exams. They need to solve the following problem to pass the IT exam.

You've got string s = s1s2... sn (n is the length of the string), consisting only of characters "." and "#" and m queries. Each query is described by a pair of integers li, ri (1 ≤ li < ri ≤ n). The answer to the query li, ri is the number of such integers i (li ≤ i < ri), that si = si + 1.

Ilya the Lion wants to help his friends but is there anyone to help him? Help Ilya, solve the problem.

Input

The first line contains string s of length n (2 ≤ n ≤ 105). It is guaranteed that the given string only consists of characters "." and "#".

The next line contains integer m (1 ≤ m ≤ 105) — the number of queries. Each of the next m lines contains the description of the corresponding query. The i-th line contains integers li, ri (1 ≤ li < ri ≤ n).

Output

Print m integers — the answers to the queries in the order in which they are given in the input.

Examples

Input

......
4
3 4
2 3
1 6
2 6


Output

1
1
5
4


Input

#..###
5
1 3
5 6
1 5
3 6
3 4


Output

1
1
2
2
0

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
template <class T>
T max(T a, T b, T c) {
  return ((a > b) ? ((a > c) ? a : c) : ((b > c) ? b : c));
}
template <class T>
T min(T a, T b, T c) {
  return ((a < b) ? ((a < c) ? a : c) : ((b < c) ? b : c));
}
const int MOD = 1000000000 + 7;
const int MAXN = 100000 + 9;
int main() {
  int t = 1;
  while (t--) {
    string str;
    cin >> str;
    int n = str.length();
    int m;
    cin >> m;
    vector<int> dp(n);
    for (int i = 1; i < n; i++) {
      dp[i] = dp[i - 1] + (str[i] == str[i - 1] ? 1 : 0);
    }
    while (m--) {
      int l, r;
      cin >> l >> r;
      l--;
      r--;
      cout << dp[r] - dp[l] << "\n";
    }
  }
  return 0;
}