Problem: Takahashi wants to grill N pieces of meat on a grilling net, which can be seen as a two-dimensional plane. The coordinates of the i-th piece of meat are \left(x_i, y_i\right), and its hardness is c_i.

Takahashi can use one heat source to grill the meat. If he puts the heat source at coordinates \left(X, Y\right), where X and Y are real numbers, the i-th piece of meat will be ready to eat in c_i \times \sqrt{\left(X - x_i\right)^2 + \left(Y-y_i\right)^2} seconds.

Takahashi wants to eat K pieces of meat. Find the time required to have K or more pieces of meat ready if he put the heat source to minimize this time.

Constraints

* All values in input are integers.
* 1 \leq N \leq 60
* 1 \leq K \leq N
* -1000 \leq x_i , y_i \leq 1000
* \left(x_i, y_i\right) \neq \left(x_j, y_j\right) \left(i \neq j \right)
* 1 \leq c_i \leq 100

Input

Input is given from Standard Input in the following format:


N K
x_1 y_1 c_1
\vdots
x_N y_N c_N


Output

Print the answer.

It will be considered correct if its absolute or relative error from our answer is at most 10^{-6}.

Examples

Input

4 3
-1 0 3
0 0 3
1 0 2
1 1 40


Output

2.4


Input

10 5
-879 981 26
890 -406 81
512 859 97
362 -955 25
128 553 17
-885 763 2
449 310 57
-656 -204 11
-270 76 40
184 170 16


Output

7411.2252

Solution (in PYTHON3):

Solution:
from math import sqrt
def crosscircle(c1, c2):
    (x1, y1, r1) = c1
    (x2, y2, r2) = c2
    if (x1-x2)**2 + (y1-y2)**2 > (r1+r2)**2:
        return ()
    elif x1 == x2 and y1 == y2:
        return ()
    elif (x1-x2)**2 + (y1-y2)**2 == (r1+r2)**2:
        x = (x1*r2+x2*r1)/(r1+r2)
        y = (y1*r2+y2*r1)/(r1+r2)
        return ((x, y),)
    elif y1 == y2:
        x = (r1**2-r2**2-x1**2+x2**2)/(2*(x2-x1))
        if y1**2-(y1**2-r1**2+(x-x1)**2) >= 0:
            yans1 = y1+sqrt(y1**2-(y1**2-r1**2+(x-x1)**2))
            yans2 = y1-sqrt(y1**2-(y1**2-r1**2+(x-x1)**2))
            return ((x, yans1), (x, yans2))
        else:
            return ()
    elif x1 == x2:
        y = (r1**2-r2**2-y1**2+y2**2)/(2*(y2-y1))
        if x1**2-(x1**2-r1**2+(y-y1)**2) >= 0:
            xans1 = x1+sqrt(x1**2-(x1**2-r1**2+(y-y1)**2))
            xans2 = x1-sqrt(x1**2-(x1**2-r1**2+(y-y1)**2))
            return ((xans1, y), (xans2, y))
        else:
            return ()
    else:
        A = ((x1-x2)/(y1-y2))**2 + 1
        B = (x1-x2)*(r1**2-r2**2-x1**2+x2**2+(y1-y2)**2)/(y1-y2)**2 - 2*x1
        C = ((r1**2-r2**2-x1**2+x2**2+(y1-y2)**2)/(2*(y1-y2)))**2 + x1**2 - r1**2
        if B**2 - 4*A*C >= 0:
            xans1 = (-B+sqrt(B**2-4*A*C))/(2*A)
            xans2 = (-B-sqrt(B**2-4*A*C))/(2*A)
            yans1 = -((r1**2-r2**2-x1**2+x2**2-y1**2+y2**2))/(2*(y1-y2))-xans1*(x1-x2)/(y1-y2)
            yans2 = -((r1**2-r2**2-x1**2+x2**2-y1**2+y2**2))/(2*(y1-y2))-xans2*(x1-x2)/(y1-y2)
            return ((xans1, yans1), (xans2, yans2))
        else:
            return ()

N, K = map(int, input().split())
li = [tuple(map(int, input().split())) for i in range(N)]
eps = 1e-6
U = 2e05
L = 0
while U - L > 1e-6:
    T = (U+L)/2
    points = []
    for i in range(N-1):
        for j in range(i+1, N):
            c1 = (li[i][0],li[i][1],T/li[i][2])
            c2 = (li[j][0],li[j][1],T/li[j][2])
            p = crosscircle(c1,c2)
            if p == ():
                continue
            for a in p:
                points.append(a)
    for i in range(N):
        points.append((li[i][0], li[i][1]))
    Max = 0
    for p in points:
        cnt = 0
        for i in range(N):
            x,y,r = li[i][0],li[i][1],T/li[i][2]
            if (p[0]-x)**2+(p[1]-y)**2<= (r+eps)**2:
                cnt += 1
        Max = max(Max, cnt)
    if Max < K:
        L = T
    else:
        U = T
print(T)