Problem: The only difference between easy and hard versions is constraints.

You are given n segments on the coordinate axis OX. Segments can intersect, lie inside each other and even coincide. The i-th segment is [l_i; r_i] (l_i ≤ r_i) and it covers all integer points j such that l_i ≤ j ≤ r_i.

The integer point is called bad if it is covered by strictly more than k segments.

Your task is to remove the minimum number of segments so that there are no bad points at all.

Input

The first line of the input contains two integers n and k (1 ≤ k ≤ n ≤ 200) — the number of segments and the maximum number of segments by which each integer point can be covered.

The next n lines contain segments. The i-th line contains two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 200) — the endpoints of the i-th segment.

Output

In the first line print one integer m (0 ≤ m ≤ n) — the minimum number of segments you need to remove so that there are no bad points.

In the second line print m distinct integers p_1, p_2, ..., p_m (1 ≤ p_i ≤ n) — indices of segments you remove in any order. If there are multiple answers, you can print any of them.

Examples

Input


7 2
11 11
9 11
7 8
8 9
7 8
9 11
7 9


Output


3
1 4 7 


Input


5 1
29 30
30 30
29 29
28 30
30 30


Output


3
1 2 4 


Input


6 1
2 3
3 3
2 3
2 2
2 3
2 3


Output


4
1 3 5 6 

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
const int mod = 1e9 + 7;
template <class T, class U>
inline void add_self(T &a, U b) {
  a += b;
  if (a >= mod) a -= mod;
  if (a < 0) a += mod;
}
template <class T, class U>
inline void min_self(T &x, U y) {
  if (y < x) x = y;
}
template <class T, class U>
inline void max_self(T &x, U y) {
  if (y > x) x = y;
}
template <typename T>
void print(T v, bool show_index = false) {
  int w = 2;
  if (show_index) {
    for (int i = 0; i < v.size(); i++) cout << setw(w) << i << " ";
    cout << endl;
  }
  for (auto i = v.begin(); i != v.end(); i++) cout << setw(w) << *i << " ";
  cout << endl;
}
template <typename T>
void print_vv(T v) {
  if (v.size() == 0) {
    cout << "Empty" << endl;
    return;
  }
  int w = 3;
  cout << setw(w) << " ";
  for (int j = 0; j < v[0].size(); j++) cout << setw(w) << j << " ";
  cout << endl;
  for (auto i = 0; i < v.size(); i++) {
    cout << i << " {";
    for (auto j = 0; j != v[i].size(); j++) {
      cout << setw(w) << v[i][j] << ",";
    }
    cout << "}," << endl;
  }
  cout << endl;
}
template <class T, class U>
void print_m(map<T, U> m, int w = 3) {
  if (m.empty()) {
    cout << "Empty" << endl;
    return;
  }
  for (auto x : m) cout << "(" << x.first << ": " << x.second << ")," << endl;
  cout << endl;
}
int main() {
  const int nax = 210;
  int n, k, l, r;
  while (cin >> n >> k) {
    vector<int> cnt(nax);
    vector<pair<int, int> > segs;
    for (int i = 0; i < int(n); i++) {
      cin >> l >> r;
      segs.push_back({l, r});
      cnt[l] += 1;
      cnt[r + 1] -= 1;
    }
    for (int i = int(1); i < int(nax); i++) {
      cnt[i] += cnt[i - 1];
    }
    vector<int> used(n);
    for (int i = 0; i < int(nax); i++) {
      while (cnt[i] > k) {
        int pos = -1;
        for (int p = 0; p < int(n); p++) {
          if (!used[p] && (segs[p].first <= i && i <= segs[p].second) &&
              (pos == -1 || segs[p].second > segs[pos].second))
            pos = p;
        }
        assert(pos != -1);
        used[pos] = 1;
        for (int j = segs[pos].first; j <= segs[pos].second; ++j) --cnt[j];
      }
    }
    vector<int> out;
    for (int i = 0; i < int(n); i++)
      if (used[i]) out.push_back(i + 1);
    int sz = out.size();
    cout << sz << endl;
    for (int i = 0; i < int(sz); i++) cout << out[i] << " ";
    cout << endl;
  }
  return 0;
}