Problem: The only difference between easy and hard versions is constraints.

You are given n segments on the coordinate axis OX. Segments can intersect, lie inside each other and even coincide. The i-th segment is [l_i; r_i] (l_i ≤ r_i) and it covers all integer points j such that l_i ≤ j ≤ r_i.

The integer point is called bad if it is covered by strictly more than k segments.

Your task is to remove the minimum number of segments so that there are no bad points at all.

Input

The first line of the input contains two integers n and k (1 ≤ k ≤ n ≤ 200) — the number of segments and the maximum number of segments by which each integer point can be covered.

The next n lines contain segments. The i-th line contains two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 200) — the endpoints of the i-th segment.

Output

In the first line print one integer m (0 ≤ m ≤ n) — the minimum number of segments you need to remove so that there are no bad points.

In the second line print m distinct integers p_1, p_2, ..., p_m (1 ≤ p_i ≤ n) — indices of segments you remove in any order. If there are multiple answers, you can print any of them.

Examples

Input


7 2
11 11
9 11
7 8
8 9
7 8
9 11
7 9


Output


3
1 4 7 


Input


5 1
29 30
30 30
29 29
28 30
30 30


Output


3
1 2 4 


Input


6 1
2 3
3 3
2 3
2 2
2 3
2 3


Output


4
1 3 5 6 

Solution (in JAVA):

Solution:

import java.io.*;
import java.util.*;
public class Main {
	static BufferedReader br;
	static PrintWriter pr;
	static int cin() throws Exception
	{
		return Integer.valueOf(br.readLine());
	}
	static int[] split() throws Exception
	{
		String[] cmd=br.readLine().split(" ");
		int[] ans=new int[cmd.length];
		for(int i=0;i<cmd.length;i++)
		{
			ans[i]=Integer.valueOf(cmd[i]);
		}
		return ans;
	}
	static long[] splitL() throws IOException
	{
		String[] cmd=br.readLine().split(" ");
		long[] ans=new long[cmd.length];
		for(int i=0;i<cmd.length;i++)
		{
			ans[i]=Long.valueOf(cmd[i]);
		}
		return ans;
	}
	static int sum(long n)
	{
		int ans=0;
		while(n!=0)
		{
			ans=ans+(int)(n%10);
			n=n/10;
		}
		return ans;
	}
	static int gcd(int x,int y)
	{
		if(x==0)
			return y;
		if(y==0)
			return x;
		if(x>y)
			return gcd(x%y,y);
		else
			return gcd(x,y%x);
	}
	public static void main(String[] args) throws Exception{
		// TODO Auto-generated method stub
		br=new BufferedReader(new InputStreamReader(System.in));
		pr=new PrintWriter(new OutputStreamWriter(System.out));
		int cases=1;
		while(cases!=0)
		{
			cases--;
			int[]ar=split();
			int n=ar[0];
			int k=ar[1];
			int[]p=new int[201];
			int[][]seg=new int[n][2];
			for(int i=0;i<n;i++)
			{
				seg[i]=split();
				for(int j=seg[i][0];j<=seg[i][1];j++)
				{
					p[j]++;
				}
			}
			ArrayList<Integer> ans=new ArrayList<>();
			int[] mark=new int[n];
			for(int i=0;i<=200;i++)
			{
				if(p[i]<=k)
					continue;
				int r=0;
				int sg=0;
				for(int j=0;j<n;j++)
				{
					if(seg[j][0]<=i && seg[j][1]>=i && mark[j]==0 && seg[j][1]>r)
					{
						r=seg[j][1];
						sg=j;
					}
				}
				mark[sg]=1;
				ans.add(sg);
				for(int j=seg[sg][0];j<=seg[sg][1];j++)
				{
					p[j]--;
				}
				i--;
			}
			System.out.println(ans.size());
			for(int i=0;i<ans.size();i++)
			{
				System.out.print(ans.get(i)+1+" ");
			}
			System.out.println();
		}
	}
}