Problem: We have N points numbered 1 to N arranged in a line in this order.

Takahashi decides to make an undirected graph, using these points as the vertices. In the beginning, the graph has no edge. Takahashi will do M operations to add edges in this graph. The i-th operation is as follows:

* The operation uses integers L_i and R_i between 1 and N (inclusive), and a positive integer C_i. For every pair of integers (s, t) such that L_i \leq s < t \leq R_i, add an edge of length C_i between Vertex s and Vertex t.



The integers L_1, ..., L_M, R_1, ..., R_M, C_1, ..., C_M are all given as input.

Takahashi wants to solve the shortest path problem in the final graph obtained. Find the length of the shortest path from Vertex 1 to Vertex N in the final graph.

Constraints

* 2 \leq N \leq 10^5
* 1 \leq M \leq 10^5
* 1 \leq L_i < R_i \leq N
* 1 \leq C_i \leq 10^9

Input

Input is given from Standard Input in the following format:


N M
L_1 R_1 C_1
:
L_M R_M C_M


Output

Print the length of the shortest path from Vertex 1 to Vertex N in the final graph. If there is no shortest path, print `-1` instead.

Examples

Input

4 3
1 3 2
2 4 3
1 4 6


Output

5


Input

4 2
1 2 1
3 4 2


Output

-1


Input

10 7
1 5 18
3 4 8
1 3 5
4 7 10
5 9 8
6 10 5
8 10 3


Output

28

Solution (in PYTHON3):

Solution:
import bisect
import copy
import heapq
import sys
import itertools
import math
import queue
from functools import lru_cache
input = sys.stdin.readline
sys.setrecursionlimit(1000000)
mod = 10 ** 9 + 7 

def read_values(): return map(int, input().split())
def read_index(): return map(lambda x: int(x) - 1, input().split())
def read_list(): return list(read_values())
def read_lists(N): return [read_list() for n in range(N)]


def main():
    N, M = read_values()
    T = read_lists(M)
    T.sort()

    S = []
    C = [10 ** 20] * N
    C[0] = 0
    t = 0
    for i in range(N):
        if i != 0 and len(S) == 0:
            print(-1)
            return

        c, r = (0, 0) if len(S) == 0 else S[0]
        while t < M:
            ll, rr, cc = T[t]
            ll -= 1
            rr -= 1
            if ll > i:
                break
                
            C[rr] = min(C[rr], c + cc)
            heapq.heappush(S, (C[rr], rr))
            t += 1

        while S:
            if S[0][1] > i:
                break
            heapq.heappop(S)

    print(C[-1])


if __name__ == "__main__":
    main()