Problem: You are given an array a of n integers.

You want to make all elements of a equal to zero by doing the following operation exactly three times:

  * Select a segment, for each number in this segment we can add a multiple of len to it, where len is the length of this segment (added integers can be different). 



It can be proven that it is always possible to make all elements of a equal to zero.

Input

The first line contains one integer n (1 ≤ n ≤ 100 000): the number of elements of the array.

The second line contains n elements of an array a separated by spaces: a_1, a_2, ..., a_n (-10^9 ≤ a_i ≤ 10^9).

Output

The output should contain six lines representing three operations.

For each operation, print two lines:

  * The first line contains two integers l, r (1 ≤ l ≤ r ≤ n): the bounds of the selected segment.

  * The second line contains r-l+1 integers b_l, b_{l+1}, ..., b_r (-10^{18} ≤ b_i ≤ 10^{18}): the numbers to add to a_l, a_{l+1}, …, a_r, respectively; b_i should be divisible by r - l + 1.

Example

Input


4
1 3 2 4


Output


1 1 
-1
3 4
4 2
2 4
-3 -6 -6

Solution (in PYTHON3):

Solution:
import sys
import heapq, functools, collections
import math, random
from collections import Counter, defaultdict

# available on Google, not available on Codeforces
# import numpy as np
# import scipy

@functools.lru_cache(maxsize=None)
def invmod(a,b):
    return 0 if a==0 else 1 if b%a==0 else b - invmod(b%a,a)*b//a

def solve(lst):  # fix inputs here
    console("----- solving ------")
    if len(lst) == 1:
        print("1 1")
        print(0)
        print("1 1")
        print(0)
        print("1 1")
        print(-lst[0])
        return

    length = len(lst)

    inv = invmod(length, length-1)
    console(inv)

    arr = [x*(length-1) for x in lst[1:]]
    console(arr)

    print("{} {}".format(2, length))    
    print(" ".join(str(x) for x in arr))
    
    lst[1:] = [a+b for a,b in zip(arr, lst[1:])]

    diff = lst[0]%len(lst)

    if diff == 0:
        print("1 1")
        print(0)
    
    else:
        print("{} {}".format(1, diff))
        print("{} ".format(-diff) + " ".join(["0" for i in range(diff-1)]))

    lst[0] = lst[0] - diff

    assert all(x%length == 0 for x in lst)

    print("{} {}".format(1, length))
    print(" ".join([str(-x) for x in lst])) 

    return


def console(*args):  # the judge will not read these print statement
    print('\033[36m', *args, '\033[0m', file=sys.stderr)
    return

# fast read all
# sys.stdin.readlines()

for _ in [1]:
    # read line as a string
    # strr = input()

    # read line as an integer
    _ = int(input())
    
    # read one line and parse each word as a string
    # lst = input().split()

    # read one line and parse each word as an integer
    lst = list(map(int,input().split()))

    # read matrix and parse as integers (after reading read nrows)
    # lst = list(map(int,input().split()))
    # nrows = lst[0]  # index containing information, please change
    # grid = []
    # for _ in range(nrows):
    #     grid.append(list(map(int,input().split())))

    solve(lst)  # please change
    
    # Google - case number required
    # print("Case #{}: {}".format(case_num+1, res))

    # Codeforces - no case number required
    # print(res)