Problem: Ilya the Lion wants to help all his friends with passing exams. They need to solve the following problem to pass the IT exam.

You've got string s = s1s2... sn (n is the length of the string), consisting only of characters "." and "#" and m queries. Each query is described by a pair of integers li, ri (1 ≤ li < ri ≤ n). The answer to the query li, ri is the number of such integers i (li ≤ i < ri), that si = si + 1.

Ilya the Lion wants to help his friends but is there anyone to help him? Help Ilya, solve the problem.

Input

The first line contains string s of length n (2 ≤ n ≤ 105). It is guaranteed that the given string only consists of characters "." and "#".

The next line contains integer m (1 ≤ m ≤ 105) — the number of queries. Each of the next m lines contains the description of the corresponding query. The i-th line contains integers li, ri (1 ≤ li < ri ≤ n).

Output

Print m integers — the answers to the queries in the order in which they are given in the input.

Examples

Input

......
4
3 4
2 3
1 6
2 6


Output

1
1
5
4


Input

#..###
5
1 3
5 6
1 5
3 6
3 4


Output

1
1
2
2
0

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
string s;
long long int n, m, i, j, x, y, a[200000];
pair<long long int, long long int> p[200000];
int main() {
  cin >> s >> m;
  n = s.size();
  a[0] = 0;
  j = 1;
  for (i = 0; i < n; i++) {
    if (s[i] == s[i + 1]) {
      a[j] = a[j - 1] + 1;
    } else {
      a[j] = a[j - 1];
    }
    j++;
  }
  for (i = 0; i < m; i++) {
    cin >> x >> y;
    p[i].first = x;
    p[i].second = y;
  }
  x = y = 0;
  for (i = 0; i < m; i++) {
    x = p[i].first;
    y = p[i].second;
    cout << abs(a[x - 1] - a[y - 1]) << endl;
  }
  return 0;
}