Problem: We have N points numbered 1 to N arranged in a line in this order.

Takahashi decides to make an undirected graph, using these points as the vertices. In the beginning, the graph has no edge. Takahashi will do M operations to add edges in this graph. The i-th operation is as follows:

* The operation uses integers L_i and R_i between 1 and N (inclusive), and a positive integer C_i. For every pair of integers (s, t) such that L_i \leq s < t \leq R_i, add an edge of length C_i between Vertex s and Vertex t.



The integers L_1, ..., L_M, R_1, ..., R_M, C_1, ..., C_M are all given as input.

Takahashi wants to solve the shortest path problem in the final graph obtained. Find the length of the shortest path from Vertex 1 to Vertex N in the final graph.

Constraints

* 2 \leq N \leq 10^5
* 1 \leq M \leq 10^5
* 1 \leq L_i < R_i \leq N
* 1 \leq C_i \leq 10^9

Input

Input is given from Standard Input in the following format:


N M
L_1 R_1 C_1
:
L_M R_M C_M


Output

Print the length of the shortest path from Vertex 1 to Vertex N in the final graph. If there is no shortest path, print `-1` instead.

Examples

Input

4 3
1 3 2
2 4 3
1 4 6


Output

5


Input

4 2
1 2 1
3 4 2


Output

-1


Input

10 7
1 5 18
3 4 8
1 3 5
4 7 10
5 9 8
6 10 5
8 10 3


Output

28

Solution (in PYTHON3):

Solution:
import sys
input = sys.stdin.readline
import heapq as hp

N, M = map(int, input().split())
graph = [[] for _ in range(N)]
for _ in range(M):
    l, r, c = map(int, input().split())
    graph[l-1].append((c, r-1))

for i in range(N-1):
    graph[i+1].append((0, i))

INF = 10**16
D = [INF for _ in range(N)] # 頂点iへの最短距離がD[i]
D[0] = 0 
q = [] # しまっていく優先度付きキュー
hp.heappush(q, (0, 0))

while q:
    nd, np = hp.heappop(q) # 一番距離が近いものを取ってくる
    if D[np] < nd: # 追加した後の残骸は見ない
        continue
    for d, p in graph[np]:
        if D[p] > D[np] + d: # 隣接するやつの中で今よりも近くなれるなら更新
            D[p] = D[np] + d
            hp.heappush(q, (D[p], p))

d = D[-1]
if d == INF:
    print(-1)
else:
    print(d)