Problem: Ilya the Lion wants to help all his friends with passing exams. They need to solve the following problem to pass the IT exam.

You've got string s = s1s2... sn (n is the length of the string), consisting only of characters "." and "#" and m queries. Each query is described by a pair of integers li, ri (1 ≤ li < ri ≤ n). The answer to the query li, ri is the number of such integers i (li ≤ i < ri), that si = si + 1.

Ilya the Lion wants to help his friends but is there anyone to help him? Help Ilya, solve the problem.

Input

The first line contains string s of length n (2 ≤ n ≤ 105). It is guaranteed that the given string only consists of characters "." and "#".

The next line contains integer m (1 ≤ m ≤ 105) — the number of queries. Each of the next m lines contains the description of the corresponding query. The i-th line contains integers li, ri (1 ≤ li < ri ≤ n).

Output

Print m integers — the answers to the queries in the order in which they are given in the input.

Examples

Input

......
4
3 4
2 3
1 6
2 6


Output

1
1
5
4


Input

#..###
5
1 3
5 6
1 5
3 6
3 4


Output

1
1
2
2
0

Solution (in JAVA):

Solution:
import javafx.util.Pair;

import java.io.InputStream;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;
import java.util.Scanner;

public class Main {

    public static void main(String[] args) {

        Scanner cin = new Scanner(System.in);

        String str = cin.nextLine();
        int n = str.length();
        int[] dp = new int[n+1];
        dp[1] = 0;
        for(int i = 2;i <= n; i++){
            if(str.charAt(i-2) == str.charAt(i-1)){
                dp[i] = dp[i-1] + 1;
            }else
                dp[i] =  dp[i-1];
        }
        int m = cin.nextInt();
        for(int i = 0;i < m; i++){
            int l = cin.nextInt();
            int r = cin.nextInt();
            System.out.println(dp[r] - dp[l]);
        }

    }

}