Problem: Ilya the Lion wants to help all his friends with passing exams. They need to solve the following problem to pass the IT exam.

You've got string s = s1s2... sn (n is the length of the string), consisting only of characters "." and "#" and m queries. Each query is described by a pair of integers li, ri (1 ≤ li < ri ≤ n). The answer to the query li, ri is the number of such integers i (li ≤ i < ri), that si = si + 1.

Ilya the Lion wants to help his friends but is there anyone to help him? Help Ilya, solve the problem.

Input

The first line contains string s of length n (2 ≤ n ≤ 105). It is guaranteed that the given string only consists of characters "." and "#".

The next line contains integer m (1 ≤ m ≤ 105) — the number of queries. Each of the next m lines contains the description of the corresponding query. The i-th line contains integers li, ri (1 ≤ li < ri ≤ n).

Output

Print m integers — the answers to the queries in the order in which they are given in the input.

Examples

Input

......
4
3 4
2 3
1 6
2 6


Output

1
1
5
4


Input

#..###
5
1 3
5 6
1 5
3 6
3 4


Output

1
1
2
2
0

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
const long long int N = 200010;
const long long mod = 1000000007;
const long long inf = 1000000000000000000;
const long double pi = 3.14159265358979323846264338;
signed main() {
  ios_base::sync_with_stdio(false);
  cin.tie(NULL);
  string str;
  cin >> str;
  long long int n = str.size(), suffix_sum[n + 1];
  suffix_sum[n] = 0, suffix_sum[0] = 0;
  for (long long int i = n - 2; i >= 0; i--) {
    if (str[i] == str[i + 1])
      suffix_sum[i + 1] = suffix_sum[i + 2] + 1;
    else
      suffix_sum[i + 1] = suffix_sum[i + 2];
  }
  long long int t;
  cin >> t;
  while (t--) {
    long long int l, r;
    cin >> l >> r;
    cout << (suffix_sum[l] - suffix_sum[r]) << "\n";
  }
  return 0;
}