Problem: Another Codeforces Round has just finished! It has gathered n participants, and according to the results, the expected rating change of participant i is a_i. These rating changes are perfectly balanced — their sum is equal to 0.

Unfortunately, due to minor technical glitches, the round is declared semi-rated. It means that all rating changes must be divided by two.

There are two conditions though: 

  * For each participant i, their modified rating change b_i must be integer, and as close to (a_i)/(2) as possible. It means that either b_i = ⌊ (a_i)/(2) ⌋ or b_i = ⌈ (a_i)/(2) ⌉. In particular, if a_i is even, b_i = (a_i)/(2). Here ⌊ x ⌋ denotes rounding down to the largest integer not greater than x, and ⌈ x ⌉ denotes rounding up to the smallest integer not smaller than x. 
  * The modified rating changes must be perfectly balanced — their sum must be equal to 0. 



Can you help with that?

Input

The first line contains a single integer n (2 ≤ n ≤ 13 845), denoting the number of participants.

Each of the next n lines contains a single integer a_i (-336 ≤ a_i ≤ 1164), denoting the rating change of the i-th participant.

The sum of all a_i is equal to 0.

Output

Output n integers b_i, each denoting the modified rating change of the i-th participant in order of input.

For any i, it must be true that either b_i = ⌊ (a_i)/(2) ⌋ or b_i = ⌈ (a_i)/(2) ⌉. The sum of all b_i must be equal to 0.

If there are multiple solutions, print any. We can show that a solution exists for any valid input.

Examples

Input


3
10
-5
-5


Output


5
-2
-3


Input


7
-7
-29
0
3
24
-29
38


Output


-3
-15
0
2
12
-15
19

Note

In the first example, b_1 = 5, b_2 = -3 and b_3 = -2 is another correct solution.

In the second example there are 6 possible solutions, one of them is shown in the example output.

Solution (in PYTHON3):

Solution:
#https://codeforces.com/contest/1237/problem/A

import math
import sys
try: 
    sys.stdin = open('input.txt', 'r') 
    sys.stdout = open('output.txt', 'w')
 
except: 
    input = sys.stdin.readline
 
 
 
 
def takeInput():
    return [int(x) for x in input().strip().split()]
 
 
can_be_changed={}
n=int(input())
a=[]
 
for i in range(n):
    number=int(input())
    a.append(number)
 
for i in range(n):
    ele=a[i]
    if(ele%2!=0):
        can_be_changed[i]=ele
    a[i]=math.ceil(a[i]/2)
 
current_sum=sum(a)
for i in range(n):
    if(current_sum<=0):
        break
    if(i in can_be_changed):
        a[i]=math.floor(can_be_changed[i]/2)
        current_sum-=1
 
for ele in a:
    print(ele)