Problem: Ilya the Lion wants to help all his friends with passing exams. They need to solve the following problem to pass the IT exam.

You've got string s = s1s2... sn (n is the length of the string), consisting only of characters "." and "#" and m queries. Each query is described by a pair of integers li, ri (1 ≤ li < ri ≤ n). The answer to the query li, ri is the number of such integers i (li ≤ i < ri), that si = si + 1.

Ilya the Lion wants to help his friends but is there anyone to help him? Help Ilya, solve the problem.

Input

The first line contains string s of length n (2 ≤ n ≤ 105). It is guaranteed that the given string only consists of characters "." and "#".

The next line contains integer m (1 ≤ m ≤ 105) — the number of queries. Each of the next m lines contains the description of the corresponding query. The i-th line contains integers li, ri (1 ≤ li < ri ≤ n).

Output

Print m integers — the answers to the queries in the order in which they are given in the input.

Examples

Input

......
4
3 4
2 3
1 6
2 6


Output

1
1
5
4


Input

#..###
5
1 3
5 6
1 5
3 6
3 4


Output

1
1
2
2
0

Solution (in JAVA):

Solution:
import java.io.PrintWriter;
import java.util.*;

public class Solution {
    public static void main(String[] args) { new Solution().run(); }

    private void run() {
        Scanner in = new Scanner(System.in);
        PrintWriter out = new PrintWriter(System.out);

        String s = in.next();

        byte[] a = new byte[s.length()];
        int[] sum = new int[s.length()];

        for (int i = 0; i < s.length() - 1; i++) {
            if (s.charAt(i) == s.charAt(i + 1))
                a[i] = 1;
            else
                a[i] = 0;

            if (i == 0)
                sum[i] = a[i];
            else
                sum[i] = sum[i - 1] + a[i];
        }

        int m = in.nextInt();
        int l, r;
        for (int i = 0; i < m; i++) {
            l = in.nextInt() - 1;
            r = in.nextInt() - 1;
            
            if (l == 0)
                out.println(sum[r - 1]);
            else
                out.println(sum[r - 1] - sum[l - 1]);
        }

        in.close();
        out.close();
    }
}