Problem: Ilya the Lion wants to help all his friends with passing exams. They need to solve the following problem to pass the IT exam.

You've got string s = s1s2... sn (n is the length of the string), consisting only of characters "." and "#" and m queries. Each query is described by a pair of integers li, ri (1 ≤ li < ri ≤ n). The answer to the query li, ri is the number of such integers i (li ≤ i < ri), that si = si + 1.

Ilya the Lion wants to help his friends but is there anyone to help him? Help Ilya, solve the problem.

Input

The first line contains string s of length n (2 ≤ n ≤ 105). It is guaranteed that the given string only consists of characters "." and "#".

The next line contains integer m (1 ≤ m ≤ 105) — the number of queries. Each of the next m lines contains the description of the corresponding query. The i-th line contains integers li, ri (1 ≤ li < ri ≤ n).

Output

Print m integers — the answers to the queries in the order in which they are given in the input.

Examples

Input

......
4
3 4
2 3
1 6
2 6


Output

1
1
5
4


Input

#..###
5
1 3
5 6
1 5
3 6
3 4


Output

1
1
2
2
0

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
int main() {
  long int n, m, l, r;
  char s[100001] = {'\0'};
  long int ans[100001] = {0};
  scanf("%s", s);
  n = strlen(s);
  scanf("%ld", &m);
  long int so_far = 0;
  for (long int i = 0; i < n - 1; ++i) {
    if (s[i] == s[i + 1]) {
      ++so_far;
    }
    ans[i] = so_far;
  }
  for (long int i = 0; i < m; ++i) {
    scanf("%ld %ld", &l, &r);
    --l;
    --r;
    long int between = ans[r - 1] - (l ? ans[l - 1] : 0);
    printf("%ld\n", between);
  }
  return 0;
}