Problem: We have N points numbered 1 to N arranged in a line in this order.

Takahashi decides to make an undirected graph, using these points as the vertices. In the beginning, the graph has no edge. Takahashi will do M operations to add edges in this graph. The i-th operation is as follows:

* The operation uses integers L_i and R_i between 1 and N (inclusive), and a positive integer C_i. For every pair of integers (s, t) such that L_i \leq s < t \leq R_i, add an edge of length C_i between Vertex s and Vertex t.



The integers L_1, ..., L_M, R_1, ..., R_M, C_1, ..., C_M are all given as input.

Takahashi wants to solve the shortest path problem in the final graph obtained. Find the length of the shortest path from Vertex 1 to Vertex N in the final graph.

Constraints

* 2 \leq N \leq 10^5
* 1 \leq M \leq 10^5
* 1 \leq L_i < R_i \leq N
* 1 \leq C_i \leq 10^9

Input

Input is given from Standard Input in the following format:


N M
L_1 R_1 C_1
:
L_M R_M C_M


Output

Print the length of the shortest path from Vertex 1 to Vertex N in the final graph. If there is no shortest path, print `-1` instead.

Examples

Input

4 3
1 3 2
2 4 3
1 4 6


Output

5


Input

4 2
1 2 1
3 4 2


Output

-1


Input

10 7
1 5 18
3 4 8
1 3 5
4 7 10
5 9 8
6 10 5
8 10 3


Output

28

Solution (in PYTHON3):

Solution:
import heapq

N, M = map(int,input().split())

V = N
G = [[] for _ in range(V)]    #[[to, cost], [], ...]
s = 0

INF = float('inf')

for i in range(V-1):
    G[i+1].append([i, 0])

for _ in range(M):
    l, r, c = map(int,input().split())
    G[l-1].append([r-1, c])

def dijkstra(s):			#始点sからの最短距離のリストを返す
    d = [INF for _ in range(V)]
    d[s] = 0
    que = []
    heapq.heappush(que, (0, s))
    
    while len(que) != 0:
        p = heapq.heappop(que)
        v = p[1]
        if d[v] < p[0]:
            continue
        for i in range(len(G[v])):
            e = G[v][i]
            if d[e[0]] > d[v] + e[1]:
                d[e[0]] = d[v] + e[1]
                heapq.heappush(que, (d[e[0]], e[0]))

    return d

L = dijkstra(s)

ans = -1 if L[N-1] == INF else L[N-1]

print(ans)