Problem: Let us define a magic grid to be a square matrix of integers of size n × n, satisfying the following conditions. 

  * All integers from 0 to (n^2 - 1) inclusive appear in the matrix exactly once. 
  * [Bitwise XOR](https://en.wikipedia.org/wiki/Bitwise_operation#XOR) of all elements in a row or a column must be the same for each row and column. 



You are given an integer n which is a multiple of 4. Construct a magic grid of size n × n.

Input

The only line of input contains an integer n (4 ≤ n ≤ 1000). It is guaranteed that n is a multiple of 4.

Output

Print a magic grid, i.e. n lines, the i-th of which contains n space-separated integers, representing the i-th row of the grid.

If there are multiple answers, print any. We can show that an answer always exists.

Examples

Input


4


Output


8 9 1 13
3 12 7 5
0 2 4 11
6 10 15 14

Input


8


Output


19 55 11 39 32 36 4 52
51 7 35 31 12 48 28 20
43 23 59 15 0 8 16 44
3 47 27 63 24 40 60 56
34 38 6 54 17 53 9 37
14 50 30 22 49 5 33 29
2 10 18 46 41 21 57 13
26 42 62 58 1 45 25 61

Note

In the first example, XOR of each row and each column is 13.

In the second example, XOR of each row and each column is 60.

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.util.StringTokenizer;
import java.util.HashMap;

public class Main
{
	public static void main(String[] args)
	{
		FastReader fr =new FastReader();	PrintWriter op =new PrintWriter(System.out);

		int dp[][] ={{8,9,1,13},{3,12,7,5},{0,2,4,11},{6,10,15,14}} ;

		int n =fr.nextInt() ,i ,i_ ,j ,j_ ,k ,arr[][] =new int[n][n];

		if (n > 4) {
			for (i =0 ; i<4 ; ++i) {
				for (j =0 ; j<4 ; ++j) {
					arr[i][j] =dp[i][j] ;
				}
			}
			k =16 ;	j_ =4 ;
			while(j_ < n) {
				for (i =0 ; i<4 ; ++i) {
					for (j =0 ; j<4 ; ++j) {
						arr[i][j+j_] =arr[i][j] + k ;
					}
				}
				k =k+16 ;	j_ += 4 ;
			}
			i_ =i ;	
			while (i_ < n) {
				j_ =0 ;			
				while (j_ < n) {
					for (i =0 ; i<4 ; ++i) {
						for (j =0 ; j<4 ; ++j) {
							arr[i+i_][j+j_] =arr[i][j] + k ;
						}
					}
					j_ += 4 ;	k =k+16 ;
				}
				i_ += 4 ;
			}
		}
		else {
			for (i =0 ; i<4 ; ++i) {
				for (j =0 ; j<4 ; ++j) {
					arr[i][j] =dp[i][j] ;
				}
			}
		}
		for (i =0 ; i<n ; ++i) {
			for (j =0 ; j<n ; ++j) {
				op.print(arr[i][j] + " ") ;
			}
			op.println() ;
		}
		op.flush();	op.close();
	}
	static class FastReader {
		BufferedReader br;
		StringTokenizer st;

		public FastReader() {
			br =new BufferedReader(new InputStreamReader(System.in));
		}

		String next() {
			while (st==null || (!st.hasMoreElements())) 
			{
				try
				{
					st =new StringTokenizer(br.readLine());
				}
				catch(IOException e)
				{
					e.printStackTrace();
				}
				
			}
			return st.nextToken();
		}

		String nextLine() {
			String str ="";

			try
			{
				str =br.readLine();
			}
			catch(IOException e)
			{
				e.printStackTrace();
			}

			return str;
		}

		int nextInt() {
			return Integer.parseInt(next());
		}

		long nextLong() {
			return Long.parseLong(next()) ;
		}
	}
}