Problem: Ilya the Lion wants to help all his friends with passing exams. They need to solve the following problem to pass the IT exam.

You've got string s = s1s2... sn (n is the length of the string), consisting only of characters "." and "#" and m queries. Each query is described by a pair of integers li, ri (1 ≤ li < ri ≤ n). The answer to the query li, ri is the number of such integers i (li ≤ i < ri), that si = si + 1.

Ilya the Lion wants to help his friends but is there anyone to help him? Help Ilya, solve the problem.

Input

The first line contains string s of length n (2 ≤ n ≤ 105). It is guaranteed that the given string only consists of characters "." and "#".

The next line contains integer m (1 ≤ m ≤ 105) — the number of queries. Each of the next m lines contains the description of the corresponding query. The i-th line contains integers li, ri (1 ≤ li < ri ≤ n).

Output

Print m integers — the answers to the queries in the order in which they are given in the input.

Examples

Input

......
4
3 4
2 3
1 6
2 6


Output

1
1
5
4


Input

#..###
5
1 3
5 6
1 5
3 6
3 4


Output

1
1
2
2
0

Solution (in PYTHON):

Solution:
from itertools import izip
import time

import sys

times = []

if __name__ == '__main__':
    s = list(raw_input())
    m = int(raw_input())

    start = time.time()
    # precompute difference list
    A = [0] + [int(ss == sss) for ss, sss in zip(s, s[1:])]
    # A = [0]*len(s)
    # for i in range(len(s)-1):
    #     A[i+1] = s[i] == s[i+1]
    times.append(time.time() - start)

    start = time.time()
    SA, accum = [0]*len(A), 0
    for i, a in enumerate(A):
        accum += a
        SA[i] = accum
    times.append(time.time() - start)

    start = time.time()
    # ranges = [[int(num)-1 for num in raw_input().split()] for _ in range(m)]
    lines = sys.stdin.readlines()
    ranges = [[int(num)-1 for num in line.split()] for line in lines]
    times.append(time.time() - start)

    start = time.time()
    outputs = [0]*m
    for i, (l, r) in enumerate(ranges):
        outputs[i] = str(SA[r] - SA[l])
    times.append(time.time() - start)

    start = time.time()
    print '\n'.join(outputs)
    times.append(time.time() - start)

    # print times