Problem: There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice. Each of these choices is represented by a string s_i. If s_i is `AB`, you must add 1 to A or B then subtract 1 from the other; if s_i is `AC`, you must add 1 to A or C then subtract 1 from the other; if s_i is `BC`, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

* 1 \leq N \leq 10^5
* 0 \leq A,B,C \leq 10^9
* N, A, B, C are integers.
* s_i is `AB`, `AC`, or `BC`.

Input

Input is given from Standard Input in the following format:


N A B C
s_1
s_2
:
s_N


Output

If it is possible to make N choices under the condition, print `Yes`; otherwise, print `No`.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (`A`, `B`, or `C`) to which you add 1 in the i-th choice.

Examples

Input

2 1 3 0
AB
AC


Output

Yes
A
C


Input

3 1 0 0
AB
BC
AB


Output

No


Input

1 0 9 0
AC


Output

No


Input

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB


Output

Yes
C
B
B
C
C
B
A
A

Solution (in JAVA):

Solution:
import java.util.*;
public class Main {

	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		int N = sc.nextInt();
		int A = sc.nextInt();
		int B = sc.nextInt();
		int C = sc.nextInt();
		String[] s = new String[N+1];
		for(int i = 0; i < N; i++)
			s[i] = sc.next();
		s[N] = "";
		StringBuilder ans = new StringBuilder();
		for(int i = 0; i < N; i++) {
			if(s[i].equals("AB")) {
				if(A <= 0 && B <= 0) {
					System.out.println("No");
					return;
				}
				if(A < B) {
					ans.append("A\n");
					A++;
					B--;
				}
				else if(B < A) {
					ans.append("B\n");
					B++;
					A--;
				}
				else {
					if(s[i+1].equals("BC")) {
						ans.append("B\n");
						B++;
						A--;
					}
					else {
						ans.append("A\n");
						A++;
						B--;
					}
				}
			}
			else if(s[i].equals("AC")) {
				if(A <= 0 && C <= 0) {
					System.out.println("No");
					return;
				}
				if(A < C) {
					ans.append("A\n");
					A++;
					C--;
				}
				else if(C < A) {
					ans.append("C\n");
					C++;
					A--;
				}
				else {
					if(s[i+1].equals("AB")) {
						ans.append("A\n");
						A++;
						C--;
					}
					else {
						ans.append("C\n");
						C++;
						A--;
					}
				}
			}
			else {
				if(B <= 0 && C <= 0) {
					System.out.println("No");
					return;
				}
				if(B < C) {
					ans.append("B\n");
					B++;
					C--;
				}
				else if(C < B) {
					ans.append("C\n");
					C++;
					B--;
				}
				else {
					if(s[i+1].equals("AC")) {
						ans.append("C\n");
						C++;
						B--;
					}
					else {
						ans.append("B\n");
						B++;
						C--;
					}
				}
			}
		}
		System.out.print("Yes\n"+ans);
	}

}