Problem: There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice. Each of these choices is represented by a string s_i. If s_i is `AB`, you must add 1 to A or B then subtract 1 from the other; if s_i is `AC`, you must add 1 to A or C then subtract 1 from the other; if s_i is `BC`, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

* 1 \leq N \leq 10^5
* 0 \leq A,B,C \leq 10^9
* N, A, B, C are integers.
* s_i is `AB`, `AC`, or `BC`.

Input

Input is given from Standard Input in the following format:


N A B C
s_1
s_2
:
s_N


Output

If it is possible to make N choices under the condition, print `Yes`; otherwise, print `No`.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (`A`, `B`, or `C`) to which you add 1 in the i-th choice.

Examples

Input

2 1 3 0
AB
AC


Output

Yes
A
C


Input

3 1 0 0
AB
BC
AB


Output

No


Input

1 0 9 0
AC


Output

No


Input

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB


Output

Yes
C
B
B
C
C
B
A
A

Solution (in PYTHON3):

Solution:
N,A,B,C = map(int,input().split())
C = {"A":A,"B":B,"C":C}
S = [input().strip() for _ in range(N)]
D = []
flag = 0
for i in range(N):
    a,b = S[i][0],S[i][1]
    if C[a]>C[b]:
        C[a] -= 1
        C[b] += 1
        D.append(b)
    elif C[b]>C[a]:
        C[b] -= 1
        C[a] += 1
        D.append(a)
    else:
        if C[a]>1:
            C[a] -= 1
            C[b] += 1
            D.append(b)
        elif C[a]==1:
            if i==N-1:
                D.append(b)
            elif S[i]==S[i+1]:
                C[a] -= 1
                C[b] += 1
                D.append(b)
            else:
                if a in S[i+1]:
                    C[a] += 1
                    C[b] -= 1
                    D.append(a)
                else:
                    C[a] -= 1
                    C[b] += 1
                    D.append(b)
        else:
            flag = 1
            break
    if C["A"]<0 or C["B"]<0 or C["C"]<0:
        flag = 1
        break
if flag==1:
    print("No")
else:
    print("Yes")
    for i in range(N):
        print(D[i])