Problem: We have a tree with N vertices numbered 1 to N. The i-th edge in the tree connects Vertex u_i and Vertex v_i, and its length is w_i. Your objective is to paint each vertex in the tree white or black (it is fine to paint all vertices the same color) so that the following condition is satisfied:

* For any two vertices painted in the same color, the distance between them is an even number.



Find a coloring of the vertices that satisfies the condition and print it. It can be proved that at least one such coloring exists under the constraints of this problem.

Constraints

* All values in input are integers.
* 1 \leq N \leq 10^5
* 1 \leq u_i < v_i \leq N
* 1 \leq w_i \leq 10^9

Input

Input is given from Standard Input in the following format:


N
u_1 v_1 w_1
u_2 v_2 w_2
.
.
.
u_{N - 1} v_{N - 1} w_{N - 1}


Output

Print a coloring of the vertices that satisfies the condition, in N lines. The i-th line should contain `0` if Vertex i is painted white and `1` if it is painted black.

If there are multiple colorings that satisfy the condition, any of them will be accepted.

Examples

Input

3
1 2 2
2 3 1


Output

0
0
1


Input

5
2 5 2
2 3 10
1 3 8
3 4 2


Output

1
0
1
0
1

Solution (in CPP):

Solution:
#include <iostream>
#include <vector>

using namespace std;

vector< vector< pair<int,int> > > g(100005);
int ans[100005];

void dfs(int v, int c, int p = -1) {
    ans[v] = c;
    for(auto u: g[v]) {
        if(u.first == p)  continue;
        dfs(u.first, u.second^c, v);
    }
    return;
}

int main(void) {
    int N;
    cin >> N;
    for(int i=0; i<N-1; i++) {
        int u, v, w;
        cin >> u >> v >> w;
        --u; --v;
        g[u].emplace_back(v, w%2);
        g[v].emplace_back(u, w%2);
    }

    dfs(0, 0);

    for(int i=0; i<N; i++) {
        cout << ans[i] << endl;
    }
    return 0;
}