Problem: We have a tree with N vertices numbered 1 to N. The i-th edge in the tree connects Vertex u_i and Vertex v_i, and its length is w_i. Your objective is to paint each vertex in the tree white or black (it is fine to paint all vertices the same color) so that the following condition is satisfied:

* For any two vertices painted in the same color, the distance between them is an even number.



Find a coloring of the vertices that satisfies the condition and print it. It can be proved that at least one such coloring exists under the constraints of this problem.

Constraints

* All values in input are integers.
* 1 \leq N \leq 10^5
* 1 \leq u_i < v_i \leq N
* 1 \leq w_i \leq 10^9

Input

Input is given from Standard Input in the following format:


N
u_1 v_1 w_1
u_2 v_2 w_2
.
.
.
u_{N - 1} v_{N - 1} w_{N - 1}


Output

Print a coloring of the vertices that satisfies the condition, in N lines. The i-th line should contain `0` if Vertex i is painted white and `1` if it is painted black.

If there are multiple colorings that satisfy the condition, any of them will be accepted.

Examples

Input

3
1 2 2
2 3 1


Output

0
0
1


Input

5
2 5 2
2 3 10
1 3 8
3 4 2


Output

1
0
1
0
1

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
#define pi pair<int,int>
#define ff first
#define ss second
#define boost ios::sync_with_stdio(false);cin.tie(nullptr)
#define int long long
#include "string"

int32_t main() {
	boost;
	int n;
	cin>>n;
	vector<pi>g[n+1];
	for(int i=1,u,v,w;i<n;i++){
		cin>>u>>v>>w;
		g[u].push_back({v,w});
		g[v].push_back({u,w});
	}
	int ans[n+1];
	function< void(int,int,int) > dfs = [&](int u,int p,int s){
		ans[u] = s % 2;
		for(auto v:g[u]){
			if(v.ff == p)
				continue;
			dfs(v.ff,u,s+v.ss);
		}
	};

	dfs(1,0,0);
	for(int i=1;i<=n;i++)
		cout<<ans[i]<<endl;
}