Problem: Stack is a container of elements that are inserted and deleted according to LIFO (Last In First Out).

For $n$ stack $S_i$ ($i = 0, 1, ..., n-1$), perform a sequence of the following operations.

* push($t$, $x$): Insert an integer $x$ to $S_t$.
* top($t$): Report the value which should be deleted next from $S_t$. If $S_t$ is empty, do nothing.
* pop($t$): Delete an element from $S_t$. If $S_t$ is empty, do nothing.



In the initial state, all stacks are empty.

Constraints

* $1 \leq n \leq 1,000$
* $1 \leq q \leq 200,000$
* $-1,000,000,000 \leq x \leq 1,000,000,000$

Input

The input is given in the following format.


$n \; q$
$query_1$
$query_2$
:
$query_q$


Each query $query_i$ is given by


0 $t$ $x$


or


1 $t$


or


2 $t$


where the first digits 0, 1 and 2 represent push, top and pop operations respectively.

Output

For each top operation, print an integer in a line.

Example

Input

3 9
0 0 1
0 0 2
0 0 3
0 2 4
0 2 5
1 0
1 2
2 0
1 0


Output

3
5
2

Solution (in CPP):

Solution:
#include <iostream>
#include <stack>
#include <string>
#include <sstream>

using namespace std;

int main()
{
  int n, q;
  int op[3];
  string line;
  stack<int> s[1000];
  
  cin >> n >> q;
  cin.ignore();
  
  for (int i = 0; i < q; i++) {
    getline(cin, line);
    stringstream ss;
    ss << line;
    int a;
    int j = 0;
    while (ss >> a) {
      op[j] = a;
      j++;
    }
    if (op[0] == 0) {
      s[op[1]].push(op[2]);
    } else if (op[0] == 1) {
      if (!s[op[1]].empty()) {
	cout << s[op[1]].top() << endl;
      }
    } else if (op[0] == 2) {
      if (!s[op[1]].empty()) {
	s[op[1]].pop();
      }
    }
  }
}