Problem: There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice. Each of these choices is represented by a string s_i. If s_i is `AB`, you must add 1 to A or B then subtract 1 from the other; if s_i is `AC`, you must add 1 to A or C then subtract 1 from the other; if s_i is `BC`, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

* 1 \leq N \leq 10^5
* 0 \leq A,B,C \leq 10^9
* N, A, B, C are integers.
* s_i is `AB`, `AC`, or `BC`.

Input

Input is given from Standard Input in the following format:


N A B C
s_1
s_2
:
s_N


Output

If it is possible to make N choices under the condition, print `Yes`; otherwise, print `No`.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (`A`, `B`, or `C`) to which you add 1 in the i-th choice.

Examples

Input

2 1 3 0
AB
AC


Output

Yes
A
C


Input

3 1 0 0
AB
BC
AB


Output

No


Input

1 0 9 0
AC


Output

No


Input

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB


Output

Yes
C
B
B
C
C
B
A
A

Solution (in PYTHON3):

Solution:
import sys
input = sys.stdin.readline

def select_a(a, b):
    nums[a] += 1
    nums[b] -= 1
    choices.append(a)

n, a, b, c = map(int, input().split())
nums = [a, b, c]
queries = []
for i in range(n):
    s = input()
    if 'AB' in s:
        queries.append((0, 1))
    elif 'AC' in s:
        queries.append((0, 2))
    else:
        queries.append((1, 2))

choices = []
for i in range(n):
    p, q = queries[i]
    if nums[p] > nums[q]:
        select_a(q, p)
        if min(nums) < 0:
            break
    elif nums[p] < nums[q]:
        select_a(p, q)
        if min(nums) < 0:
            break
    else:
        if i == n-1:
            select_a(p, q)
            if min(nums) < 0:
                break
        else:
            v, w = queries[i+1]
            if p in {v, w}:
                select_a(p, q)
                if min(nums) < 0:
                    break
            else:
                select_a(q, p)
                if min(nums) < 0:
                    break

if min(nums) < 0:
    print('No')
else:
    print('Yes')
    for choice in choices:
        print('ABC'[choice])