Problem: You have array of n numbers a_{1}, a_{2}, …, a_{n}. 

Rearrange these numbers to satisfy |a_{1} - a_{2}| ≤ |a_{2} - a_{3}| ≤ … ≤ |a_{n-1} - a_{n}|, where |x| denotes absolute value of x. It's always possible to find such rearrangement.

Note that all numbers in a are not necessarily different. In other words, some numbers of a may be same.

You have to answer independent t test cases.

Input

The first line contains a single integer t (1 ≤ t ≤ 10^{4}) — the number of test cases.

The first line of each test case contains single integer n (3 ≤ n ≤ 10^{5}) — the length of array a. It is guaranteed that the sum of values of n over all test cases in the input does not exceed 10^{5}.

The second line of each test case contains n integers a_{1}, a_{2}, …, a_{n} (-10^{9} ≤ a_{i} ≤ 10^{9}).

Output

For each test case, print the rearranged version of array a which satisfies given condition. If there are multiple valid rearrangements, print any of them.

Example

Input


2
6
5 -2 4 8 6 5
4
8 1 4 2


Output


5 5 4 6 8 -2
1 2 4 8

Note

In the first test case, after given rearrangement, |a_{1} - a_{2}| = 0 ≤ |a_{2} - a_{3}| = 1 ≤ |a_{3} - a_{4}| = 2 ≤ |a_{4} - a_{5}| = 2 ≤ |a_{5} - a_{6}| = 10. There are other possible answers like "5 4 5 6 -2 8".

In the second test case, after given rearrangement, |a_{1} - a_{2}| = 1 ≤ |a_{2} - a_{3}| = 2 ≤ |a_{3} - a_{4}| = 4. There are other possible answers like "2 4 8 1".

Solution (in PYTHON3):

Solution:
import sys

# sys.stdin = open(r'input/nsort.txt')

t = int(input())
inp = [line.strip().split() for line in reversed(sys.stdin.readlines())]
ans = []
while t:
    n = int(inp.pop()[0])
    a = sorted([int(i) for i in inp.pop()])
    lena = len(a)
    tans = []
    if lena % 2 == 1:
        mid = lena // 2
        tans.append(str(a[mid]))
        for i in range(1, lena//2 + 1):
            tans.append(str(a[mid+i]))
            tans.append(str(a[mid-i]))
        ans.append(' '.join(tans))
    else:
        mid = lena // 2
        curup = mid
        curd = mid - 1
        tans.append(a[curd])
        tans.append(a[curup])
        for i in range(lena//2 - 1):
            curd -= 1
            curup += 1
            tans.append(a[curd])
            tans.append(a[curup])
        ans.append(' '.join(map(str, tans)))
    t -= 1
print(*ans, sep='\n')