Problem: We have a tree with N vertices numbered 1 to N. The i-th edge in the tree connects Vertex u_i and Vertex v_i, and its length is w_i. Your objective is to paint each vertex in the tree white or black (it is fine to paint all vertices the same color) so that the following condition is satisfied:

* For any two vertices painted in the same color, the distance between them is an even number.



Find a coloring of the vertices that satisfies the condition and print it. It can be proved that at least one such coloring exists under the constraints of this problem.

Constraints

* All values in input are integers.
* 1 \leq N \leq 10^5
* 1 \leq u_i < v_i \leq N
* 1 \leq w_i \leq 10^9

Input

Input is given from Standard Input in the following format:


N
u_1 v_1 w_1
u_2 v_2 w_2
.
.
.
u_{N - 1} v_{N - 1} w_{N - 1}


Output

Print a coloring of the vertices that satisfies the condition, in N lines. The i-th line should contain `0` if Vertex i is painted white and `1` if it is painted black.

If there are multiple colorings that satisfy the condition, any of them will be accepted.

Examples

Input

3
1 2 2
2 3 1


Output

0
0
1


Input

5
2 5 2
2 3 10
1 3 8
3 4 2


Output

1
0
1
0
1

Solution (in PYTHON3):

Solution:
import sys
sys.setrecursionlimit(pow(10, 7))

def dfs(v, c):
	color[v] = c
	for x in glaph[v]:
		u, w = x[0], x[1]
		if color[u] != -1:
			continue
		if w%2 == 0:
			dfs(u, c)
		else:
			dfs(u, 1-c)
			
n = int(input())
color = [-1]*n
glaph = [[]*n for _ in range(n)]
for _ in range(n-1):
	u,v,w = map(int, input().split())
	glaph[u-1].append((v-1, w))
	glaph[v-1].append((u-1, w))	

dfs(v=0, c=0)
for i in color:
	print(i)