Problem: There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice. Each of these choices is represented by a string s_i. If s_i is `AB`, you must add 1 to A or B then subtract 1 from the other; if s_i is `AC`, you must add 1 to A or C then subtract 1 from the other; if s_i is `BC`, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

* 1 \leq N \leq 10^5
* 0 \leq A,B,C \leq 10^9
* N, A, B, C are integers.
* s_i is `AB`, `AC`, or `BC`.

Input

Input is given from Standard Input in the following format:


N A B C
s_1
s_2
:
s_N


Output

If it is possible to make N choices under the condition, print `Yes`; otherwise, print `No`.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (`A`, `B`, or `C`) to which you add 1 in the i-th choice.

Examples

Input

2 1 3 0
AB
AC


Output

Yes
A
C


Input

3 1 0 0
AB
BC
AB


Output

No


Input

1 0 9 0
AC


Output

No


Input

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB


Output

Yes
C
B
B
C
C
B
A
A

Solution (in PYTHON3):

Solution:
n,a,b,c = map(int, input().split())
op = [input() for i in range(n)]

val=[a,b,c]
flag=True
ansls=list()

for i in range(n):
    s1=ord(op[i][0])-ord('A')
    s2=ord(op[i][1])-ord('A')
    if val[s1]>val[s2]:
        ansls.append(s2)
        val[s2]+=1
        val[s1]-=1
    elif val[s1]<val[s2] or i+1==n:
        ansls.append(s1)
        val[s1]+=1
        val[s2]-=1
    else:
        s1n = ord(op[i+1][0])-ord('A')
        s2n = ord(op[i+1][1])-ord('A')
        nxt = set([s1,s2]) & set([s1n,s2n])
        nxt = list(nxt)[0]
        ansls.append(nxt)
        val[nxt]+=1
        if nxt==s1:
            val[s2]-=1
        else:
            val[s1]-=1
    if min(val)<0:
        flag=False
        break

if flag:
    print('Yes')
    for i in range(n):
        print(chr(ansls[i]+ord('A')))
else:
    print('No')