Problem: There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice. Each of these choices is represented by a string s_i. If s_i is `AB`, you must add 1 to A or B then subtract 1 from the other; if s_i is `AC`, you must add 1 to A or C then subtract 1 from the other; if s_i is `BC`, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

* 1 \leq N \leq 10^5
* 0 \leq A,B,C \leq 10^9
* N, A, B, C are integers.
* s_i is `AB`, `AC`, or `BC`.

Input

Input is given from Standard Input in the following format:


N A B C
s_1
s_2
:
s_N


Output

If it is possible to make N choices under the condition, print `Yes`; otherwise, print `No`.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (`A`, `B`, or `C`) to which you add 1 in the i-th choice.

Examples

Input

2 1 3 0
AB
AC


Output

Yes
A
C


Input

3 1 0 0
AB
BC
AB


Output

No


Input

1 0 9 0
AC


Output

No


Input

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB


Output

Yes
C
B
B
C
C
B
A
A

Solution (in PYTHON3):

Solution:
import sys
sys.setrecursionlimit(10 ** 5 + 10)

N, A, B, C = [int(i) for i in input().split()]

ans = list()
l = list()

for n in range(N):
    l.append(input())

def dfs(i, a, b, c):
    if i == N:
        return True

    ss = l[i]
    if ss == 'AB':
        if a == 0 and b == 0:
            return False
        if b > 0 and dfs(i + 1, a + 1, b - 1, c):
            ans.append('A')
            return True
        if a > 0 and dfs(i + 1, a - 1, b + 1, c):
            ans.append('B')
            return True
    if ss == 'AC':
        if a == 0 and c == 0:
            return False
        if c > 0 and dfs(i + 1, a + 1, b, c - 1):
            ans.append('A')
            return True
        if a > 0 and dfs(i + 1, a - 1, b, c + 1):
            ans.append('C')
            return True
    if ss == 'BC':
        if b == 0 and c == 0:
            return False
        if c > 0 and dfs(i + 1, a, b + 1, c - 1):
            ans.append('B')
            return True
        if b > 0 and dfs(i + 1, a, b - 1, c + 1):
            ans.append('C')
            return True
    return False

dfs(0, A, B, C)

if len(ans) > 0:
    print('Yes')
    for x in reversed(ans):
        print(x)
else:
    print('No')