Problem: There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice. Each of these choices is represented by a string s_i. If s_i is `AB`, you must add 1 to A or B then subtract 1 from the other; if s_i is `AC`, you must add 1 to A or C then subtract 1 from the other; if s_i is `BC`, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

* 1 \leq N \leq 10^5
* 0 \leq A,B,C \leq 10^9
* N, A, B, C are integers.
* s_i is `AB`, `AC`, or `BC`.

Input

Input is given from Standard Input in the following format:


N A B C
s_1
s_2
:
s_N


Output

If it is possible to make N choices under the condition, print `Yes`; otherwise, print `No`.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (`A`, `B`, or `C`) to which you add 1 in the i-th choice.

Examples

Input

2 1 3 0
AB
AC


Output

Yes
A
C


Input

3 1 0 0
AB
BC
AB


Output

No


Input

1 0 9 0
AC


Output

No


Input

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB


Output

Yes
C
B
B
C
C
B
A
A

Solution (in PYTHON3):

Solution:
# -*- coding: utf-8 -*-

N,A,B,C=input().split()
D=dict()
D["A"]=int(A)
D["B"]=int(B)
D["C"]=int(C)

S=[]
for i in range(int(N)):
    S.append(input())

ans="Yes"
F=[]
for i,s in enumerate(S):
    if D[s[0]]==0 and D[s[1]]==0:
        ans="No"
        break
    if D[s[0]]==1 and D[s[1]]==1:
        if D["A"]+D["B"]+D["C"]==2:
            if i!=int(N)-1:
                if S[i+1] != s:
                    s0=S[i+1][0]
                    s1=S[i+1][1]
                    if s[0]==s0 or s[0]==s1:
                        F.append(s[0])
                    if s[1]==s0 or s[1]==s1:
                        F.append(s[1])
    if len(F)!=i+1:
        if D[s[0]]<D[s[1]]:
            F.append(s[0])
        if D[s[0]]>D[s[1]]:
            F.append(s[1])
        if D[s[0]]==D[s[1]]:
            F.append(s[0])

    D[F[-1]]+=1
    if s[0]==F[-1]: D[s[1]]-=1
    if s[1]==F[-1]: D[s[0]]-=1
    #print(D)
    #print(F)

print(ans)
if ans=="Yes":
    for f in F:
        print(f)