Problem: We have a tree with N vertices numbered 1 to N. The i-th edge in the tree connects Vertex u_i and Vertex v_i, and its length is w_i. Your objective is to paint each vertex in the tree white or black (it is fine to paint all vertices the same color) so that the following condition is satisfied:

* For any two vertices painted in the same color, the distance between them is an even number.



Find a coloring of the vertices that satisfies the condition and print it. It can be proved that at least one such coloring exists under the constraints of this problem.

Constraints

* All values in input are integers.
* 1 \leq N \leq 10^5
* 1 \leq u_i < v_i \leq N
* 1 \leq w_i \leq 10^9

Input

Input is given from Standard Input in the following format:


N
u_1 v_1 w_1
u_2 v_2 w_2
.
.
.
u_{N - 1} v_{N - 1} w_{N - 1}


Output

Print a coloring of the vertices that satisfies the condition, in N lines. The i-th line should contain `0` if Vertex i is painted white and `1` if it is painted black.

If there are multiple colorings that satisfy the condition, any of them will be accepted.

Examples

Input

3
1 2 2
2 3 1


Output

0
0
1


Input

5
2 5 2
2 3 10
1 3 8
3 4 2


Output

1
0
1
0
1

Solution (in JAVA):

Solution:
import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;
import java.util.PriorityQueue;
import java.util.Queue;
import java.util.Scanner;
import java.util.stream.IntStream;

/**
 * 解説通りに作成したソースコード
 */
public class Main {

	public static void main(String[] args) {
		try (Scanner scanner = new Scanner(System.in)) {
			int n = scanner.nextInt();
			@SuppressWarnings("unchecked")
			List<Path>[] pathLists = new List[n];
			IntStream.range(0, n).forEach(i -> pathLists[i] = new ArrayList<>());
			IntStream.range(0, n - 1).forEach(i -> {
				int u = scanner.nextInt() - 1, v = scanner.nextInt() - 1;
				long w = scanner.nextLong();
				pathLists[u].add(new Path(u, v, w));
				pathLists[v].add(new Path(v, u, w));
			});
			long[] distances = dijkstra(pathLists, 0, n);
			Arrays.stream(distances).map(l -> l & 1L).forEach(System.out::println);
		}
	}

	/**
	 * @param pathLists ノード間の連結パス一覧の配列
	 * @param src       開始ノード
	 * @param n         ノードの数
	 * @return 開始ノードからの距離の配列
	 */
	private static long[] dijkstra(List<Path>[] pathLists, int src, int n) {
		long[] distances = new long[n];
		Arrays.fill(distances, Long.MAX_VALUE);
		// 最短距離が確定したかどうか
		boolean[] fixed = new boolean[n];
		Arrays.fill(fixed, false);
		// 出発地点までの距離を0とする
		distances[src] = 0;
		Queue<Path> queue = new PriorityQueue<>();
		queue.add(new Path(src, src, 0));
		while (!queue.isEmpty()) {
			int now = queue.poll().to;
			if (!fixed[now]) {
				fixed[now] = true;
				for (Path path : pathLists[now]) {
					if (!fixed[path.to] && distances[path.to] > distances[now] + path.cost) {
						distances[path.to] = distances[now] + path.cost;
						queue.add(new Path(path.to, path.to, distances[path.to]));
					}
				}
			}
		}
		return distances;
	}

	/**
	 * ノード間の一つのパスを表すクラス
	 */
	private static class Path implements Comparable<Path> {
		/** 開始ノード */
		@SuppressWarnings("unused")
		int from;
		/** 終了ノード */
		int to;
		/** 移動コスト */
		long cost;

		Path(int from, int to, long cost) {
			super();
			this.from = from;
			this.to = to;
			this.cost = cost;
		}

		@Override
		public int compareTo(Path path) {
			return Long.compare(cost, path.cost);
		}
	}
}