Problem: We have a tree with N vertices numbered 1 to N. The i-th edge in the tree connects Vertex u_i and Vertex v_i, and its length is w_i. Your objective is to paint each vertex in the tree white or black (it is fine to paint all vertices the same color) so that the following condition is satisfied:

* For any two vertices painted in the same color, the distance between them is an even number.



Find a coloring of the vertices that satisfies the condition and print it. It can be proved that at least one such coloring exists under the constraints of this problem.

Constraints

* All values in input are integers.
* 1 \leq N \leq 10^5
* 1 \leq u_i < v_i \leq N
* 1 \leq w_i \leq 10^9

Input

Input is given from Standard Input in the following format:


N
u_1 v_1 w_1
u_2 v_2 w_2
.
.
.
u_{N - 1} v_{N - 1} w_{N - 1}


Output

Print a coloring of the vertices that satisfies the condition, in N lines. The i-th line should contain `0` if Vertex i is painted white and `1` if it is painted black.

If there are multiple colorings that satisfy the condition, any of them will be accepted.

Examples

Input

3
1 2 2
2 3 1


Output

0
0
1


Input

5
2 5 2
2 3 10
1 3 8
3 4 2


Output

1
0
1
0
1

Solution (in JAVA):

Solution:
import java.util.*;
import java.lang.*;

public class Main {
	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		int n = sc.nextInt();
		HashMap<Integer, ArrayList<Edge>> map = new HashMap<>();
		for (int i = 0; i < n; i++) {
			map.put(i, new ArrayList<>());
		}
		for (int i = 0; i < n - 1; i++) {
			int from = sc.nextInt() - 1;
			int to = sc.nextInt() - 1;
			int dis = sc.nextInt();
			Edge e = new Edge(from, to, dis);
			map.get(from).add(e);
			map.get(to).add(e);
		}
		TreeMap<Integer, Integer> color = new TreeMap<>();
		dfs(map, color, 0, 0);
		for (int i = 0; i < n; i++) {
			System.out.println(color.get(i));
		}
	}
	static void dfs(HashMap<Integer, ArrayList<Edge>> map, TreeMap<Integer, Integer> color, int index, int col) {
		for (int i = 0; i < map.get(index).size(); i++) {
			Edge e = map.get(index).get(i);
			if (!color.containsKey(e.from)) {
				color.put(e.from, (col + e.distance) % 2);
				dfs(map, color, e.from, (col + e.distance) % 2);
			} else if (!color.containsKey(e.to)) {
				color.put(e.to, (col + e.distance) % 2);
				dfs(map, color, e.to, (col + e.distance) % 2);
			}
		}
	}
}

class Edge {
	int from;
	int to;
	int distance;
	Edge(int from, int to, int distance) {
		this.from = from;
		this.to = to;
		this.distance = distance;
	}
}