Problem: There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice. Each of these choices is represented by a string s_i. If s_i is `AB`, you must add 1 to A or B then subtract 1 from the other; if s_i is `AC`, you must add 1 to A or C then subtract 1 from the other; if s_i is `BC`, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

* 1 \leq N \leq 10^5
* 0 \leq A,B,C \leq 10^9
* N, A, B, C are integers.
* s_i is `AB`, `AC`, or `BC`.

Input

Input is given from Standard Input in the following format:


N A B C
s_1
s_2
:
s_N


Output

If it is possible to make N choices under the condition, print `Yes`; otherwise, print `No`.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (`A`, `B`, or `C`) to which you add 1 in the i-th choice.

Examples

Input

2 1 3 0
AB
AC


Output

Yes
A
C


Input

3 1 0 0
AB
BC
AB


Output

No


Input

1 0 9 0
AC


Output

No


Input

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB


Output

Yes
C
B
B
C
C
B
A
A

Solution (in PYTHON3):

Solution:
N, A, B, C = map(int, input().split())

S = ['']*N
for i in range(N):
  S[i] = input()
  
play = [''] * N
flag = True
for i, s in enumerate(S):
  next = ''
  if i < len(S)-1:
    next = S[i+1]
  if s == 'AB':
    if A == 0 and B == 0:
      flag = False
      break
    elif A == B and 'B' in next:
      A -= 1
      B += 1
      play[i] = 'B'
    elif A > B:
      A -= 1
      B += 1
      play[i] = 'B'
    else:
      A += 1
      B -= 1
      play[i] = 'A'
  elif s == 'AC':
    if A == 0 and C == 0:
      flag = False
      break
    elif A == C and 'C' in next:
      A -= 1
      C += 1
      play[i] = 'C'
    elif A > C:
      A -= 1
      C += 1
      play[i] = 'C'
    else:
      A += 1
      C -= 1
      play[i] = 'A'
  else:
    if B == 0 and C == 0:
      flag = False
      break
    elif B == C and 'C' in next:
      B -= 1
      C += 1
      play[i] = 'C'
    elif B > C:
      B -= 1
      C += 1
      play[i] = 'C'
    else:
      B += 1
      C -= 1
      play[i] = 'B'

if flag:
  print('Yes')
  for i in play:
    print(i)
else:
  print('No')