Problem: Dima loves representing an odd number as the sum of multiple primes, and Lisa loves it when there are at most three primes. Help them to represent the given number as the sum of at most than three primes.

More formally, you are given an odd numer n. Find a set of numbers pi (1 ≤ i ≤ k), such that

  1. 1 ≤ k ≤ 3
  2. pi is a prime
  3. <image>



The numbers pi do not necessarily have to be distinct. It is guaranteed that at least one possible solution exists.

Input

The single line contains an odd number n (3 ≤ n < 109).

Output

In the first line print k (1 ≤ k ≤ 3), showing how many numbers are in the representation you found.

In the second line print numbers pi in any order. If there are multiple possible solutions, you can print any of them.

Examples

Input

27


Output

3
5 11 11

Note

A prime is an integer strictly larger than one that is divisible only by one and by itself.

Solution (in PYTHON3):

Solution:
import sys
from math import gcd,sqrt,ceil
from collections import defaultdict,Counter,deque
from bisect import bisect_left,bisect_right
import math
from itertools import permutations

# input=sys.stdin.readline
# def print(x):
#     sys.stdout.write(str(x)+"\n")

# sys.stdin = open('input.txt', 'r')
# sys.stdout = open('output.txt', 'w')
import os
import sys
from io import BytesIO, IOBase

BUFSIZE = 8192


class FastIO(IOBase):
    newlines = 0

    def __init__(self, file):
        self._fd = file.fileno()
        self.buffer = BytesIO()
        self.writable = "x" in file.mode or "r" not in file.mode
        self.write = self.buffer.write if self.writable else None

    def read(self):
        while True:
            b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
            if not b:
                break
            ptr = self.buffer.tell()
            self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
        self.newlines = 0
        return self.buffer.read()

    def readline(self):
        while self.newlines == 0:
            b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
            self.newlines = b.count(b"\n") + (not b)
            ptr = self.buffer.tell()
            self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
        self.newlines -= 1
        return self.buffer.readline()

    def flush(self):
        if self.writable:
            os.write(self._fd, self.buffer.getvalue())
            self.buffer.truncate(0), self.buffer.seek(0)


class IOWrapper(IOBase):
    def __init__(self, file):
        self.buffer = FastIO(file)
        self.flush = self.buffer.flush
        self.writable = self.buffer.writable
        self.write = lambda s: self.buffer.write(s.encode("ascii"))
        self.read = lambda: self.buffer.read().decode("ascii")
        self.readline = lambda: self.buffer.readline().decode("ascii")


sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")

# import sys
# import io, os
# input = io.BytesIO(os.read(0,os.fstat(0).st_size)).readline
def get_sum(bit,i):
    s = 0

    i+=1
    while i>0:
        s+=bit[i]
        i-=i&(-i)

    return s

def update(bit,n,i,v):
    i+=1

    while i<=n:
        bit[i]+=v
        i+=i&(-i)


def modInverse(b,m):
    g = math.gcd(b, m)
    if (g != 1):
        return -1
    else:
        return pow(b, m - 2, m)

def primeFactors(n):

    sa = set()
    sa.add(n)
    while n % 2 == 0:
        sa.add(2)
        n = n // 2


    for i in range(3,int(math.sqrt(n))+1,2):


        while n % i== 0:
            sa.add(i)
            n = n // i

    # sa.add(n)
    return sa


def seive(n):

    pri = [True]*(n+1)
    p = 2
    while p*p<=n:

        if pri[p] == True:

            for i in range(p*p,n+1,p):
                pri[i] = False

        p+=1

    return pri

def check_prim(n):

    if n<0:
        return False
    for i in range(2,int(sqrt(n))+1):
        if n%i == 0:
            return False

    return True

z = seive(10**4+1)
pri = []
for i in range(2,10**4+1):
    if z[i]:
        pri.append(i)
# print(len(pri))

n = int(input())
if n in pri:
    print(1)
    print(n)
    exit()


x,y,z = -1,-1,-1
for i in range(len(pri)):
    flag = 0
    for j in range(len(pri)):
        z = pri[i] + pri[j]
        if check_prim(n-z) :
            x = pri[i]
            y = pri[j]
            z = n-z

            flag = 1
            break

    if flag:
        break

# print(check_prim(0))
if x!=0 and y!=0 and z!=0:
 print(3)
 print(x,y,z)
else:
    print(2)
    print(x,y)