Problem: There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice. Each of these choices is represented by a string s_i. If s_i is `AB`, you must add 1 to A or B then subtract 1 from the other; if s_i is `AC`, you must add 1 to A or C then subtract 1 from the other; if s_i is `BC`, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

* 1 \leq N \leq 10^5
* 0 \leq A,B,C \leq 10^9
* N, A, B, C are integers.
* s_i is `AB`, `AC`, or `BC`.

Input

Input is given from Standard Input in the following format:


N A B C
s_1
s_2
:
s_N


Output

If it is possible to make N choices under the condition, print `Yes`; otherwise, print `No`.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (`A`, `B`, or `C`) to which you add 1 in the i-th choice.

Examples

Input

2 1 3 0
AB
AC


Output

Yes
A
C


Input

3 1 0 0
AB
BC
AB


Output

No


Input

1 0 9 0
AC


Output

No


Input

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB


Output

Yes
C
B
B
C
C
B
A
A

Solution (in PYTHON3):

Solution:
N, A, B, C = map(int, input().split())
S = [list(input()) for i in range(N)]

v = [A, B, C]
id_d = {'A':0, 'B':1, 'C':2}
ans = [0] * N
for i, s in enumerate(S):
  s1, s2 = s
  id1, id2 = id_d[s1], id_d[s2]
  v1, v2 = v[id1], v[id2]
  if v1 == v2 == 0:
    if i == 0:
      print('No')
      quit()
    else:
      pre_s1, pre_s2 = S[i-1]
      pre_id1, pre_id2 = id_d[pre_s1], id_d[pre_s2]
      if pre_s1 in [s1, s2]:
        v[pre_id1] += 2
        v[pre_id2] -= 2
        ans[i-1] = pre_s1
        if v[pre_id2] < 0:
          print('No')
          quit()
      else: # pre_s2 in [s1, s2]
        v[pre_id2] += 2
        v[pre_id1] -= 2
        ans[i-1] = pre_s2
        if v[pre_id1] < 0:
          print('No')
          quit()
  v1, v2 = v[id1], v[id2]
  if v1 >= v2:
    ans[i] = s2
    v[id1] -= 1
    v[id2] += 1
  else:
    ans[i] = s1
    v[id1] += 1
    v[id2] -= 1

print('Yes')
print(*ans, sep='\n')