Problem: Polycarp has guessed three positive integers a, b and c. He keeps these numbers in secret, but he writes down four numbers on a board in arbitrary order — their pairwise sums (three numbers) and sum of all three numbers (one number). So, there are four numbers on a board in random order: a+b, a+c, b+c and a+b+c.

You have to guess three numbers a, b and c using given numbers. Print three guessed integers in any order.

Pay attention that some given numbers a, b and c can be equal (it is also possible that a=b=c).

Input

The only line of the input contains four positive integers x_1, x_2, x_3, x_4 (2 ≤ x_i ≤ 10^9) — numbers written on a board in random order. It is guaranteed that the answer exists for the given number x_1, x_2, x_3, x_4.

Output

Print such positive integers a, b and c that four numbers written on a board are values a+b, a+c, b+c and a+b+c written in some order. Print a, b and c in any order. If there are several answers, you can print any. It is guaranteed that the answer exists.

Examples

Input


3 6 5 4


Output


2 1 3


Input


40 40 40 60


Output


20 20 20


Input


201 101 101 200


Output


1 100 100

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int main() {
  int x1, x2, x3, x4, mx, a, b, c;
  cin >> x1 >> x2 >> x3 >> x4;
  mx = max(max(x1, x2), max(x3, x4));
  if (mx == 0) {
    a = 0;
    b = 0;
    c = 0;
    cout << a << " " << b << " " << c;
  } else {
    if (mx == x1) {
      a = mx - x4;
      b = mx - x3;
      c = mx - x2;
      cout << a << " " << b << " " << c;
    } else if (mx == x2) {
      a = mx - x4;
      b = mx - x3;
      c = mx - x1;
      cout << a << " " << b << " " << c;
    } else if (mx == x3) {
      a = mx - x4;
      b = mx - x2;
      c = mx - x1;
      cout << a << " " << b << " " << c;
    } else if (mx == x4) {
      a = mx - x3;
      b = mx - x2;
      c = mx - x1;
      cout << a << " " << b << " " << c;
    }
  }
}