Problem: Polycarp has guessed three positive integers a, b and c. He keeps these numbers in secret, but he writes down four numbers on a board in arbitrary order — their pairwise sums (three numbers) and sum of all three numbers (one number). So, there are four numbers on a board in random order: a+b, a+c, b+c and a+b+c.

You have to guess three numbers a, b and c using given numbers. Print three guessed integers in any order.

Pay attention that some given numbers a, b and c can be equal (it is also possible that a=b=c).

Input

The only line of the input contains four positive integers x_1, x_2, x_3, x_4 (2 ≤ x_i ≤ 10^9) — numbers written on a board in random order. It is guaranteed that the answer exists for the given number x_1, x_2, x_3, x_4.

Output

Print such positive integers a, b and c that four numbers written on a board are values a+b, a+c, b+c and a+b+c written in some order. Print a, b and c in any order. If there are several answers, you can print any. It is guaranteed that the answer exists.

Examples

Input


3 6 5 4


Output


2 1 3


Input


40 40 40 60


Output


20 20 20


Input


201 101 101 200


Output


1 100 100

Solution (in PYTHON3):

Solution:
xs = list(map(int, input().strip().split(" ")))


def ok(a, b, c):
    print("%d %d %d"%(a,b,c))
    exit(0)


def check(a, b, c):
    a=sorted([a+b,a+c,b+c,a+b+c])
    return a==sorted(xs)
    # return a+b in xs and a+c in xs and b+c in xs and a+b+c in xs


for i in range(4):
    for j in range(i, 4):
        for k in range(j, 4):
            a = xs[i]-xs[k]+xs[j]
            if a % 2 != 0:
                continue
            a = a//2
            b = xs[i]-a
            c = xs[j]-a
            if check(a,b,c):
                ok(a,b,c)