Problem: There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice. Each of these choices is represented by a string s_i. If s_i is `AB`, you must add 1 to A or B then subtract 1 from the other; if s_i is `AC`, you must add 1 to A or C then subtract 1 from the other; if s_i is `BC`, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

* 1 \leq N \leq 10^5
* 0 \leq A,B,C \leq 10^9
* N, A, B, C are integers.
* s_i is `AB`, `AC`, or `BC`.

Input

Input is given from Standard Input in the following format:


N A B C
s_1
s_2
:
s_N


Output

If it is possible to make N choices under the condition, print `Yes`; otherwise, print `No`.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (`A`, `B`, or `C`) to which you add 1 in the i-th choice.

Examples

Input

2 1 3 0
AB
AC


Output

Yes
A
C


Input

3 1 0 0
AB
BC
AB


Output

No


Input

1 0 9 0
AC


Output

No


Input

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB


Output

Yes
C
B
B
C
C
B
A
A

Solution (in PYTHON3):

Solution:
N, A, B, C = map(int, input().split())
X = [input() for _ in range(N)]


def solve(x):
    d = {"A": 0, "B": 1, "C": 2}
    ans = []
    for i in range(N):
        u, v = X[i]
        if x[d[u]] == x[d[v]] == 0:
            return

        if x[d[u]] < x[d[v]]:
            x[d[u]] += 1
            x[d[v]] -= 1
            ans.append(u)
        elif x[d[u]] > x[d[v]]:
            x[d[u]] -= 1
            x[d[v]] += 1
            ans.append(v)
        elif i < N - 1 and X[i] != X[i + 1]:
            # x[d[u]] == x[d[v]] >= 1
            if u in X[i + 1]:
                x[d[u]] += 1
                x[d[v]] -= 1
                ans.append(u)
            else:
                x[d[u]] -= 1
                x[d[v]] += 1
                ans.append(v)
        else:
            x[d[u]] += 1
            x[d[v]] -= 1
            ans.append(u)

        if x[d[u]] < 0 or x[d[v]] < 0:
            return

    return ans

ans = solve([A, B, C])
if ans:
    print("Yes")
    print(*ans, sep="\n")
else:
    print("No")