Problem: This is an interactive problem.

Now Serval is a senior high school student in Japari Middle School. However, on the way to the school, he must go across a pond, in which there is a dangerous snake. The pond can be represented as a n × n grid. The snake has a head and a tail in different cells, and its body is a series of adjacent cells connecting the head and the tail without self-intersecting. If Serval hits its head or tail, the snake will bite him and he will die.

Luckily, he has a special device which can answer the following question: you can pick a rectangle, it will tell you the number of times one needs to cross the border of the rectangle walking cell by cell along the snake from the head to the tail. The pictures below show a possible snake and a possible query to it, which will get an answer of 4.

<image> <image>

Today Serval got up too late and only have time to make 2019 queries. As his best friend, can you help him find the positions of the head and the tail?

Note that two cells are adjacent if and only if they have a common edge in the grid, and a snake can have a body of length 0, that means it only has adjacent head and tail.

Also note that the snake is sleeping, so it won't move while Serval using his device. And what's obvious is that the snake position does not depend on your queries.

Input

The first line contains a single integer n (2≤ n ≤ 1000) — the size of the grid.

Output

When you are ready to answer, you should print ! x1 y1 x2 y2, where (x_1, y_1) represents the position of the head and (x_2,y_2) represents the position of the tail. You can print head and tail in any order.

Interaction

To make a query, you should print ? x1 y1 x2 y2 (1 ≤ x_1 ≤ x_2 ≤ n, 1≤ y_1 ≤ y_2 ≤ n), representing a rectangle consisting of all cells (x,y) such that x_1 ≤ x ≤ x_2 and y_1 ≤ y ≤ y_2. You will get a single integer as the answer.

After printing a query, do not forget to output the end of line and flush the output, otherwise you will get Idleness limit exceeded. To do this, use:

  * fflush(stdout) or cout.flush() in C++; 
  * System.out.flush() in Java; 
  * flush(output) in Pascal; 
  * stdout.flush() in Python; 
  * see documentation for other languages. 



Answer -1 instead of a valid answer means that you made an invalid query or exceeded the maximum number of queries. Exit immediately after receiving -1 and you will see Wrong answer verdict. Otherwise you can get an arbitrary verdict because your solution will continue to read from a closed stream.

If your program cannot find out the head and tail of the snake correctly, you will also get a Wrong Answer verdict.

Hacks

To make a hack, print a single integer n (2 ≤ n ≤ 1000) in the first line, indicating the size of the grid.

Then print an integer k (2 ≤ k ≤ n^2) in the second line, indicating the length of the snake.

In the next k lines, print k pairs of integers x_i, y_i (1 ≤ x_i, y_i ≤ n), each pair in a single line, indicating the i-th cell of snake, such that the adjacent pairs are adjacent, and all k pairs are distinct.

Examples

Input


2

1

0

0


Output



? 1 1 1 1

? 1 2 1 2

? 2 2 2 2

! 1 1 2 1

Input


3

2

0


Output



? 2 2 2 2

? 2 1 2 3

! 2 1 2 3

Note

<image> <image> <image> <image>

The pictures above show our queries and the answers in the first example. We first made a query for (1,1) and got an answer 1, then found that it must be connected to exactly one other cell. Then we made a query for (1,2) and got an answer of 0, then knew that the snake never entered it. So the cell connected to (1,1) must be (2,1). Then we made a query for (2,2) and got an answer 0, then knew that it never entered (2,2) as well. So the snake cannot leave (2,1), which implies that the answer is (1,1) and (2,1).

<image> <image> <image>

The pictures above show our queries and the answers in the second example. By making query to (2,2) and receiving 2, we found that the snake occupies (2,2). And by making query to rectangle from (2,1) to (2,3) and receiving answer 0, we knew that it never goes out of the rectangle from (2,1) to (2,3). Since the first answer is 2, both (2,1) and (2,3) must be occupied but none of others, so the answer is (2,1) and (2,3).

Solution (in JAVA):

Solution:


import java.io.FileInputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.OutputStream;
import java.nio.charset.Charset;
import java.util.*;

public class CFContest551 {
    public static void main(String[] args) throws Exception {
        boolean local = false;//System.getProperty("ONLINE_JUDGE") == null;
        boolean async = false;

        Charset charset = Charset.forName("ascii");

        FastIO io = local ? new FastIO(new FileInputStream("D:\\DATABASE\\TESTCASE\\Code.in"), System.out, charset) : new FastIO(System.in, System.out, charset);
        Task task = new Task(io, new Debug(local));

        if (async) {
            Thread t = new Thread(null, task, "dalt", 1 << 27);
            t.setPriority(Thread.MAX_PRIORITY);
            t.start();
            t.join();
        } else {
            task.run();
        }

        if (local) {
            io.cache.append("\n\n--memory -- \n" + ((Runtime.getRuntime().totalMemory() - Runtime.getRuntime().freeMemory()) >> 20) + "M");
        }

        io.flush();
    }

    public static class Task implements Runnable {
        final FastIO io;
        final Debug debug;
        int inf = (int) 1e8;

        public Task(FastIO io, Debug debug) {
            this.io = io;
            this.debug = debug;
        }

        @Override
        public void run() {
            solve();
        }

        public void solve() {
            int n = io.readInt();
            //find each row
            int r1 = -1;
            int r2 = -1;
            int c1 = -1;
            int c2 = -1;
            int[] rowQ = new int[n + 1];
            int[] colQ = new int[n + 1];
            for (int i = 1; i <= n; i++) {
                query(i, 1, i, n);
                rowQ[i] = io.readInt();
                query(1, i, n, i);
                colQ[i] = io.readInt();

                if (rowQ[i] % 2 == 1) {
                    if (r1 == -1) {
                        r1 = i;
                    } else {
                        r2 = i;
                    }
                }
                if (colQ[i] % 2 == 1) {
                    if (c1 == -1) {
                        c1 = i;
                    } else {
                        c2 = i;
                    }
                }
            }


            if (r1 == -1) {
                //same row
                int l = 1;
                int r = n;
                while (l < r) {
                    int m = (l + r) >> 1;
                    query(1, c1, m, c1);
                    int ans = io.readInt();
                    if (ans % 2 == 1) {
                        r = m;
                    } else {
                        l = m + 1;
                    }
                }
                r1 = r2 = l;
            }

            if (c1 == -1) {
                //same col
                int l = 1;
                int r = n;
                while (l < r) {
                    int m = (l + r) >> 1;
                    query(r1, 1, r1, m);
                    int ans = io.readInt();
                    if (ans % 2 == 1) {
                        r = m;
                    } else {
                        l = m + 1;
                    }
                }
                c1 = c2 = l;
            }

            query(r1, c1, r1, c1);
            if (io.readInt() == 1) {
                answer(r1, c1, r2, c2);
            } else {
                answer(r1, c2, r2, c1);
            }
            return;
        }

        public void query(int x1, int y1, int x2, int y2) {
            io.cache.append("? ").append(x1).append(' ').append(y1).append(' ').append(x2).append(' ').append(y2).append('\n');
            io.flush();
        }

        public void answer(int x1, int y1, int x2, int y2) {
            io.cache.append("! ").append(x1).append(' ').append(y1).append(' ').append(x2).append(' ').append(y2).append('\n');
            io.flush();
        }
    }


    public static class FastIO {
        public final StringBuilder cache = new StringBuilder();
        private final InputStream is;
        private final OutputStream os;
        private final Charset charset;
        private StringBuilder defaultStringBuf = new StringBuilder(1 << 8);
        private byte[] buf = new byte[1 << 13];
        private int bufLen;
        private int bufOffset;
        private int next;

        public FastIO(InputStream is, OutputStream os, Charset charset) {
            this.is = is;
            this.os = os;
            this.charset = charset;
        }

        public FastIO(InputStream is, OutputStream os) {
            this(is, os, Charset.forName("ascii"));
        }

        private int read() {
            while (bufLen == bufOffset) {
                bufOffset = 0;
                try {
                    bufLen = is.read(buf);
                } catch (IOException e) {
                    throw new RuntimeException(e);
                }
                if (bufLen == -1) {
                    return -1;
                }
            }
            return buf[bufOffset++];
        }

        public void skipBlank() {
            while (next >= 0 && next <= 32) {
                next = read();
            }
        }

        public int readInt() {
            int sign = 1;

            skipBlank();
            if (next == '+' || next == '-') {
                sign = next == '+' ? 1 : -1;
                next = read();
            }

            int val = 0;
            if (sign == 1) {
                while (next >= '0' && next <= '9') {
                    val = val * 10 + next - '0';
                    next = read();
                }
            } else {
                while (next >= '0' && next <= '9') {
                    val = val * 10 - next + '0';
                    next = read();
                }
            }

            return val;
        }

        public long readLong() {
            int sign = 1;

            skipBlank();
            if (next == '+' || next == '-') {
                sign = next == '+' ? 1 : -1;
                next = read();
            }

            long val = 0;
            if (sign == 1) {
                while (next >= '0' && next <= '9') {
                    val = val * 10 + next - '0';
                    next = read();
                }
            } else {
                while (next >= '0' && next <= '9') {
                    val = val * 10 - next + '0';
                    next = read();
                }
            }

            return val;
        }

        public double readDouble() {
            boolean sign = true;
            skipBlank();
            if (next == '+' || next == '-') {
                sign = next == '+';
                next = read();
            }

            long val = 0;
            while (next >= '0' && next <= '9') {
                val = val * 10 + next - '0';
                next = read();
            }
            if (next != '.') {
                return sign ? val : -val;
            }
            next = read();
            long radix = 1;
            long point = 0;
            while (next >= '0' && next <= '9') {
                point = point * 10 + next - '0';
                radix = radix * 10;
                next = read();
            }
            double result = val + (double) point / radix;
            return sign ? result : -result;
        }

        public String readString(StringBuilder builder) {
            skipBlank();

            while (next > 32) {
                builder.append((char) next);
                next = read();
            }

            return builder.toString();
        }

        public String readString() {
            defaultStringBuf.setLength(0);
            return readString(defaultStringBuf);
        }

        public int readLine(char[] data, int offset) {
            int originalOffset = offset;
            while (next != -1 && next != '\n') {
                data[offset++] = (char) next;
                next = read();
            }
            return offset - originalOffset;
        }

        public int readString(char[] data, int offset) {
            skipBlank();

            int originalOffset = offset;
            while (next > 32) {
                data[offset++] = (char) next;
                next = read();
            }

            return offset - originalOffset;
        }

        public int readString(byte[] data, int offset) {
            skipBlank();

            int originalOffset = offset;
            while (next > 32) {
                data[offset++] = (byte) next;
                next = read();
            }

            return offset - originalOffset;
        }

        public char readChar() {
            skipBlank();
            char c = (char) next;
            next = read();
            return c;
        }

        public void flush() {
            try {
                os.write(cache.toString().getBytes(charset));
                os.flush();
                cache.setLength(0);
            } catch (IOException e) {
                throw new RuntimeException(e);
            }
        }

        public boolean hasMore() {
            skipBlank();
            return next != -1;
        }
    }

    public static class Debug {
        private boolean allowDebug;

        public Debug(boolean allowDebug) {
            this.allowDebug = allowDebug;
        }

        public void assertTrue(boolean flag) {
            if (!allowDebug) {
                return;
            }
            if (!flag) {
                fail();
            }
        }

        public void fail() {
            throw new RuntimeException();
        }

        public void assertFalse(boolean flag) {
            if (!allowDebug) {
                return;
            }
            if (flag) {
                fail();
            }
        }

        private void outputName(String name) {
            System.out.print(name + " = ");
        }

        public void debug(String name, int x) {
            if (!allowDebug) {
                return;
            }

            outputName(name);
            System.out.println("" + x);
        }

        public void debug(String name, long x) {
            if (!allowDebug) {
                return;
            }
            outputName(name);
            System.out.println("" + x);
        }

        public void debug(String name, double x) {
            if (!allowDebug) {
                return;
            }
            outputName(name);
            System.out.println("" + x);
        }

        public void debug(String name, int[] x) {
            if (!allowDebug) {
                return;
            }
            outputName(name);
            System.out.println(Arrays.toString(x));
        }

        public void debug(String name, long[] x) {
            if (!allowDebug) {
                return;
            }
            outputName(name);
            System.out.println(Arrays.toString(x));
        }

        public void debug(String name, double[] x) {
            if (!allowDebug) {
                return;
            }
            outputName(name);
            System.out.println(Arrays.toString(x));
        }

        public void debug(String name, Object x) {
            if (!allowDebug) {
                return;
            }
            outputName(name);
            System.out.println("" + x);
        }

        public void debug(String name, Object... x) {
            if (!allowDebug) {
                return;
            }
            outputName(name);
            System.out.println(Arrays.deepToString(x));
        }
    }
}