Problem: There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice. Each of these choices is represented by a string s_i. If s_i is `AB`, you must add 1 to A or B then subtract 1 from the other; if s_i is `AC`, you must add 1 to A or C then subtract 1 from the other; if s_i is `BC`, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

* 1 \leq N \leq 10^5
* 0 \leq A,B,C \leq 10^9
* N, A, B, C are integers.
* s_i is `AB`, `AC`, or `BC`.

Input

Input is given from Standard Input in the following format:


N A B C
s_1
s_2
:
s_N


Output

If it is possible to make N choices under the condition, print `Yes`; otherwise, print `No`.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (`A`, `B`, or `C`) to which you add 1 in the i-th choice.

Examples

Input

2 1 3 0
AB
AC


Output

Yes
A
C


Input

3 1 0 0
AB
BC
AB


Output

No


Input

1 0 9 0
AC


Output

No


Input

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB


Output

Yes
C
B
B
C
C
B
A
A

Solution (in PYTHON3):

Solution:
N,A,B,C=map(int,input().split())
S=['']*(N+1)
for a in range(N):
    S[a]=input()

ans='Yes'
L_ans=['']*(N+1)
i=0
while i<N:
    if S[i]=='AB':
        if A>B:
            B+=1
            A-=1
            L_ans[i]='B'
        elif A<B:
            A+=1
            B-=1
            L_ans[i]='A'
        elif A==B and S[i+1]=='BC':
            B+=1
            A-=1
            L_ans[i]='B'
        else:
            A+=1
            B-=1
            L_ans[i]='A'
    elif S[i]=='AC':
        if A>C:
            C+=1
            A-=1
            L_ans[i]='C'
        elif A<C:
            A+=1
            C-=1
            L_ans[i]='A'
        elif A==C and S[i+1]=='BC':
            C+=1
            A-=1
            L_ans[i]='C'
        else:
            A+=1
            C-=1
            L_ans[i]='A'
    elif S[i]=='BC':
        if C>B:
            B+=1
            C-=1
            L_ans[i]='B'
        elif C<B:
            C+=1
            B-=1
            L_ans[i]='C'
        elif B==C and S[i+1]=='AB':
            B+=1
            C-=1
            L_ans[i]='B'
        else:
            C+=1
            B-=1
            L_ans[i]='C'
    i+=1
    if any([A<0,B<0,C<0]):
        ans='No'
        break

print(ans)
if ans=='Yes':
    j=0
    while j<N:
        print(L_ans[j])
        j+=1