Problem: Polycarp has guessed three positive integers a, b and c. He keeps these numbers in secret, but he writes down four numbers on a board in arbitrary order — their pairwise sums (three numbers) and sum of all three numbers (one number). So, there are four numbers on a board in random order: a+b, a+c, b+c and a+b+c.

You have to guess three numbers a, b and c using given numbers. Print three guessed integers in any order.

Pay attention that some given numbers a, b and c can be equal (it is also possible that a=b=c).

Input

The only line of the input contains four positive integers x_1, x_2, x_3, x_4 (2 ≤ x_i ≤ 10^9) — numbers written on a board in random order. It is guaranteed that the answer exists for the given number x_1, x_2, x_3, x_4.

Output

Print such positive integers a, b and c that four numbers written on a board are values a+b, a+c, b+c and a+b+c written in some order. Print a, b and c in any order. If there are several answers, you can print any. It is guaranteed that the answer exists.

Examples

Input


3 6 5 4


Output


2 1 3


Input


40 40 40 60


Output


20 20 20


Input


201 101 101 200


Output


1 100 100

Solution (in JAVA):

Solution:
import java.util.*;
public class Main
{
    public static final void main(String[] args)
    {
        
        Scanner s=new Scanner(System.in);
        int x1=s.nextInt();
        int x2=s.nextInt();
        int x3=s.nextInt();
        int x4=s.nextInt();
        int m1=Math.max(x1,x2);
        int m2=Math.max(x3,x4);
        int m=Math.max(m1,m2);
        int a=m-x1;
        int b=m-x2;
        int c=m-x3;
        int d=m-x4;
        if(m==x1)
           System.out.println(b+" "+c+" "+d);
        else if(m==x2)
           System.out.println(a+" "+c+" "+d);
        else if(m==x3)
           System.out.println(a+" "+b+" "+d);
        else if(m==x4)
           System.out.println(a+" "+b+" "+c);
    }
}