Problem: Dreamoon likes to play with sets, integers and <image>. <image> is defined as the largest positive integer that divides both a and b.

Let S be a set of exactly four distinct integers greater than 0. Define S to be of rank k if and only if for all pairs of distinct elements si, sj from S, <image>.

Given k and n, Dreamoon wants to make up n sets of rank k using integers from 1 to m such that no integer is used in two different sets (of course you can leave some integers without use). Calculate the minimum m that makes it possible and print one possible solution.

Input

The single line of the input contains two space separated integers n, k (1 ≤ n ≤ 10 000, 1 ≤ k ≤ 100).

Output

On the first line print a single integer — the minimal possible m. 

On each of the next n lines print four space separated integers representing the i-th set.

Neither the order of the sets nor the order of integers within a set is important. If there are multiple possible solutions with minimal m, print any one of them.

Examples

Input

1 1


Output

5
1 2 3 5


Input

2 2


Output

22
2 4 6 22
14 18 10 16

Note

For the first example it's easy to see that set {1, 2, 3, 4} isn't a valid set of rank 1 since <image>.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
void err(istream_iterator<string> it) { cout << "NEXT\n"; }
template <typename T, typename... Args>
void err(istream_iterator<string> it, T a, Args... args) {
  cerr << *it << " = " << a << ", ";
  err(++it, args...);
}
template <typename... T>
void rd(T&... args) {
  ((cin >> args), ...);
}
template <typename... T>
void ps(T... args) {
  ((cout << args << ' '), ...);
  cout << '\n';
}
const long long MOD = 1e9 + 7, MOD1 = 998244353LL, MAX = 2e5 + 5;
const char nl = '\n';
const int INF = 1e9 + 5;
int n, k;
void solve() {
  cin >> n >> k;
  cout << (n * 6 - 1) * k << '\n';
  for (int i = 0; i < n; i++) {
    cout << (i * 6 + 1) * k << ' ' << (i * 6 + 3) * k << ' ' << (i * 6 + 4) * k
         << ' ' << (i * 6 + 5) * k << '\n';
  }
}
int main() {
  ios::sync_with_stdio(false);
  cin.tie(nullptr);
  int __ = 1;
  while (__--) {
    solve();
  }
  return 0;
}