Problem: Polycarp has guessed three positive integers a, b and c. He keeps these numbers in secret, but he writes down four numbers on a board in arbitrary order — their pairwise sums (three numbers) and sum of all three numbers (one number). So, there are four numbers on a board in random order: a+b, a+c, b+c and a+b+c.

You have to guess three numbers a, b and c using given numbers. Print three guessed integers in any order.

Pay attention that some given numbers a, b and c can be equal (it is also possible that a=b=c).

Input

The only line of the input contains four positive integers x_1, x_2, x_3, x_4 (2 ≤ x_i ≤ 10^9) — numbers written on a board in random order. It is guaranteed that the answer exists for the given number x_1, x_2, x_3, x_4.

Output

Print such positive integers a, b and c that four numbers written on a board are values a+b, a+c, b+c and a+b+c written in some order. Print a, b and c in any order. If there are several answers, you can print any. It is guaranteed that the answer exists.

Examples

Input


3 6 5 4


Output


2 1 3


Input


40 40 40 60


Output


20 20 20


Input


201 101 101 200


Output


1 100 100

Solution (in JAVA):

Solution:
import java.util.*;

public class restoringThreeNumbers {
    public static void main(String[] args)
    {
        Scanner scanner = new Scanner(System.in);
        int w = scanner.nextInt();
        int x = scanner.nextInt();
        int y = scanner.nextInt();
        int z = scanner.nextInt();
        if(w > x && w > y && w > z)
            System.out.println((w-x) + " " + (w-y) + " " + (w-z));
        if(x > w && x > y && x > z)
            System.out.println((x-w) + " " + (x-y) + " " + (x-z));
        if(y > w && y > x && y > z)
            System.out.println((y-w) + " " + (y-x) + " " + (y-z));
        if(z > w && z > x && z > y)
            System.out.println((z-w) + " " + (z-x) + " " + (z-y));
    }
}