Problem: There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice. Each of these choices is represented by a string s_i. If s_i is `AB`, you must add 1 to A or B then subtract 1 from the other; if s_i is `AC`, you must add 1 to A or C then subtract 1 from the other; if s_i is `BC`, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

* 1 \leq N \leq 10^5
* 0 \leq A,B,C \leq 10^9
* N, A, B, C are integers.
* s_i is `AB`, `AC`, or `BC`.

Input

Input is given from Standard Input in the following format:


N A B C
s_1
s_2
:
s_N


Output

If it is possible to make N choices under the condition, print `Yes`; otherwise, print `No`.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (`A`, `B`, or `C`) to which you add 1 in the i-th choice.

Examples

Input

2 1 3 0
AB
AC


Output

Yes
A
C


Input

3 1 0 0
AB
BC
AB


Output

No


Input

1 0 9 0
AC


Output

No


Input

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB


Output

Yes
C
B
B
C
C
B
A
A

Solution (in PYTHON3):

Solution:
N,A,B,C = map(int,input().split())
q = [input() for i in range(N)]
d = {'A':A,'B':B,'C':C}
ans = []
possible = True
for i in range(N):
    x = q[i][0]
    y = q[i][1]
    z = [s for s in 'ABC' if s!=x and s!=y][0]
    if d[x]>d[y]:
        ans.append(y)
        d[x] -= 1
        d[y] += 1
    elif d[x]<d[y]:
        ans.append(x)
        d[x] += 1
        d[y] -= 1
    else:
        if d[x]==1 and d[y]==1 and d[z]==0:
            if i==N-1 or q[i+1]==q[i]:
                ans.append(x)
                d[x] += 1
                d[y] -= 1
            elif x in q[i+1]:
                ans.append(x)
                d[x] += 1
                d[y] -= 1
            else:
                ans.append(y)
                d[y] += 1
                d[x] -= 1
        elif d[x]==0 and d[y]==0:
            possible = False
        else:
            ans.append(x)
            d[x] += 1
            d[y] -= 1

if possible:
    print('Yes')
    for i in range(N):
        print(ans[i])
else:
    print('No')