Problem: Given a string s, determine if it contains any palindrome of length exactly 100 as a subsequence. If it has any, print any one of them. If it doesn't have any, print a palindrome that is a subsequence of s and is as long as possible.

Input

The only line of the input contains one string s of length n (1 ≤ n ≤ 5·104) containing only lowercase English letters.

Output

If s contains a palindrome of length exactly 100 as a subsequence, print any palindrome of length 100 which is a subsequence of s. If s doesn't contain any palindromes of length exactly 100, print a palindrome that is a subsequence of s and is as long as possible.

If there exists multiple answers, you are allowed to print any of them.

Examples

Input

bbbabcbbb


Output

bbbcbbb


Input

rquwmzexectvnbanemsmdufrg


Output

rumenanemur

Note

A subsequence of a string is a string that can be derived from it by deleting some characters without changing the order of the remaining characters. A palindrome is a string that reads the same forward or backward.

Solution (in PYTHON3):

Solution:
def p2(a):
  n = len(a)
  last = [[0] * 26 for _ in range(n)]
  last[0][ord(a[0])-97] = 0
  for i in range(1, n):
    for j in range(26):
      last[i][j] = last[i-1][j]
    last[i][ord(a[i])-97] = i
  dp = [''] * n
  for i in range(n-1, -1, -1):
    for j in range(n-1, i, -1):
        k = last[j][ord(a[i])-97]
        if k > i:
            if (k - i) == 1 and len(dp[j]) < 2:
                dp[j] = a[i] + a[i]
            elif len(dp[j]) < (len(dp[k-1]) + 2):
                dp[j] = a[i] + dp[k - 1] + a[i]
                if len(dp[j]) >= 100:
                    if len(dp[j]) == 101:
                      return dp[j][:50] + dp[j][51:]
                    else:
                      return dp[j]
    dp[i] = a[i]
  return dp[n-1]

print(p2(input()))