Problem: You have array of n numbers a_{1}, a_{2}, …, a_{n}. 

Rearrange these numbers to satisfy |a_{1} - a_{2}| ≤ |a_{2} - a_{3}| ≤ … ≤ |a_{n-1} - a_{n}|, where |x| denotes absolute value of x. It's always possible to find such rearrangement.

Note that all numbers in a are not necessarily different. In other words, some numbers of a may be same.

You have to answer independent t test cases.

Input

The first line contains a single integer t (1 ≤ t ≤ 10^{4}) — the number of test cases.

The first line of each test case contains single integer n (3 ≤ n ≤ 10^{5}) — the length of array a. It is guaranteed that the sum of values of n over all test cases in the input does not exceed 10^{5}.

The second line of each test case contains n integers a_{1}, a_{2}, …, a_{n} (-10^{9} ≤ a_{i} ≤ 10^{9}).

Output

For each test case, print the rearranged version of array a which satisfies given condition. If there are multiple valid rearrangements, print any of them.

Example

Input


2
6
5 -2 4 8 6 5
4
8 1 4 2


Output


5 5 4 6 8 -2
1 2 4 8

Note

In the first test case, after given rearrangement, |a_{1} - a_{2}| = 0 ≤ |a_{2} - a_{3}| = 1 ≤ |a_{3} - a_{4}| = 2 ≤ |a_{4} - a_{5}| = 2 ≤ |a_{5} - a_{6}| = 10. There are other possible answers like "5 4 5 6 -2 8".

In the second test case, after given rearrangement, |a_{1} - a_{2}| = 1 ≤ |a_{2} - a_{3}| = 2 ≤ |a_{3} - a_{4}| = 4. There are other possible answers like "2 4 8 1".

Solution (in PYTHON3):

Solution:
import collections, math, bisect

local = False
if local:
    file = open("input.txt", "r")
    import time

def inp():
    if local:
        return file.readline().rstrip()
    else:
        return input().rstrip()

def ints():
    return [int(_) for _ in inp().split()]


if local:
    start=time.time()


t = int(inp())

for _ in range(1,t+1):
    n = int(inp())
    arr = [int(_) for _ in inp().split()]

    arr.sort(key=lambda x: x)

    l, r = 0, n-1

    res = [0]*n
    pos = n-1

    while l<r:
        res[pos] = arr[r]
        res[pos-1] = arr[l]

        pos-=2
        r-=1
        l+=1

    if l==r:
        res[0] = arr[l]

    print(" ".join([str(_) for _ in res]))


if local:
    fin = (time.time()-start)*1000
    print("{:.2f}".format(fin) + "ms")