Problem: You have a sequence A composed of N positive integers: A_{1}, A_{2}, \cdots, A_{N}.

You will now successively do the following Q operations:

* In the i-th operation, you replace every element whose value is B_{i} with C_{i}.



For each i (1 \leq i \leq Q), find S_{i}: the sum of all elements in A just after the i-th operation.

Constraints

* All values in input are integers.
* 1 \leq N, Q, A_{i}, B_{i}, C_{i} \leq 10^{5}
* B_{i} \neq C_{i}

Input

Input is given from Standard Input in the following format:


N
A_{1} A_{2} \cdots A_{N}
Q
B_{1} C_{1}
B_{2} C_{2}
\vdots
B_{Q} C_{Q}


Output

Print Q integers S_{i} to Standard Output in the following format:


S_{1}
S_{2}
\vdots
S_{Q}


Note that S_{i} may not fit into a 32-bit integer.

Examples

Input

4
1 2 3 4
3
1 2
3 4
2 4


Output

11
12
16


Input

4
1 1 1 1
3
1 2
2 1
3 5


Output

8
4
4


Input

2
1 2
3
1 100
2 100
100 1000


Output

102
200
2000

Solution (in JAVA):

Solution:
import java.util.HashMap;
import java.util.Map;
import java.util.Scanner;

public class Main {
  public static void main(String[] args) {
    Scanner sc = new Scanner(System.in);
    int n = sc.nextInt();
    Map<Integer, Integer> map = new HashMap<>();

    for (int i = 0; i < n; i++) {
      int key = sc.nextInt();
      Integer mapVal = map.get(key);
      map.put(key, mapVal == null ? 1 : ++mapVal);
    }

    long sum = map.entrySet().stream().mapToLong(v -> v.getKey() * v.getValue()).sum();

    int q = sc.nextInt();
    for (int j = 0; j < q; j++) {
      int b = sc.nextInt();
      int c = sc.nextInt();

      Integer bVal = map.get(b);
      Integer cVal = map.get(c);

      map.remove(b);

      if (bVal != null) {
        map.put(c, cVal == null ? bVal : cVal + bVal);
        sum += (long) (c-b) * bVal;
      }

      System.out.println(sum);
    }
  }
}