Problem: Polycarp has guessed three positive integers a, b and c. He keeps these numbers in secret, but he writes down four numbers on a board in arbitrary order — their pairwise sums (three numbers) and sum of all three numbers (one number). So, there are four numbers on a board in random order: a+b, a+c, b+c and a+b+c.

You have to guess three numbers a, b and c using given numbers. Print three guessed integers in any order.

Pay attention that some given numbers a, b and c can be equal (it is also possible that a=b=c).

Input

The only line of the input contains four positive integers x_1, x_2, x_3, x_4 (2 ≤ x_i ≤ 10^9) — numbers written on a board in random order. It is guaranteed that the answer exists for the given number x_1, x_2, x_3, x_4.

Output

Print such positive integers a, b and c that four numbers written on a board are values a+b, a+c, b+c and a+b+c written in some order. Print a, b and c in any order. If there are several answers, you can print any. It is guaranteed that the answer exists.

Examples

Input


3 6 5 4


Output


2 1 3


Input


40 40 40 60


Output


20 20 20


Input


201 101 101 200


Output


1 100 100

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int mx(int a[]) {
  int m = 0, n;
  for (int i = 0; i < 4; i++) {
    if (m < a[i]) {
      m = a[i];
      n = i;
    }
  }
  return n;
}
int main() {
  int x[4], m, ar[3], j = 0;
  for (int i = 0; i < 4; i++) {
    cin >> x[i];
  }
  m = mx(x);
  for (int i = 0; i < 4; i++) {
    if (i == m) continue;
    ar[j++] = x[i];
  }
  cout << (ar[0] + ar[1] - ar[2]) / 2 << " ";
  cout << (ar[0] + ar[2] - ar[1]) / 2 << " ";
  cout << (ar[1] + ar[2] - ar[0]) / 2;
  return 0;
}