Problem: There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice. Each of these choices is represented by a string s_i. If s_i is `AB`, you must add 1 to A or B then subtract 1 from the other; if s_i is `AC`, you must add 1 to A or C then subtract 1 from the other; if s_i is `BC`, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

* 1 \leq N \leq 10^5
* 0 \leq A,B,C \leq 10^9
* N, A, B, C are integers.
* s_i is `AB`, `AC`, or `BC`.

Input

Input is given from Standard Input in the following format:


N A B C
s_1
s_2
:
s_N


Output

If it is possible to make N choices under the condition, print `Yes`; otherwise, print `No`.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (`A`, `B`, or `C`) to which you add 1 in the i-th choice.

Examples

Input

2 1 3 0
AB
AC


Output

Yes
A
C


Input

3 1 0 0
AB
BC
AB


Output

No


Input

1 0 9 0
AC


Output

No


Input

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB


Output

Yes
C
B
B
C
C
B
A
A

Solution (in PYTHON3):

Solution:
ABC = [0] * 3
N, ABC[0], ABC[1], ABC[2] = map(int, input().split())
s = [''] * N
for i in range(N):
	s[i] = input()
a = ''
b = True
for i in range(N):
	if not ABC[ord(s[i][0]) - ord('A')]:
		if not ABC[ord(s[i][1]) - ord('A')]:
			b = False
			break
		ABC[ord(s[i][0]) - ord('A')] += 1
		ABC[ord(s[i][1]) - ord('A')] -= 1
		a += s[i][0]
	elif not ABC[ord(s[i][1]) - ord('A')]:
		ABC[ord(s[i][0]) - ord('A')] -= 1
		ABC[ord(s[i][1]) - ord('A')] += 1
		a += s[i][1]
	else:
		if i == N - 1:
			ABC[ord(s[i][0]) - ord('A')] += 1
			ABC[ord(s[i][1]) - ord('A')] -= 1
			a += s[i][0]
		else:
			if s[i][0] == s[i + 1][0] or s[i][0] == s[i + 1][1]:
				ABC[ord(s[i][0]) - ord('A')] += 1
				ABC[ord(s[i][1]) - ord('A')] -= 1
				a += s[i][0]
			else:
				ABC[ord(s[i][0]) - ord('A')] -= 1
				ABC[ord(s[i][1]) - ord('A')] += 1
				a += s[i][1]
if b:
	print('Yes')
	for i in a:
		print(i)
else:
	print('No')