Problem: We have a tree with N vertices numbered 1 to N. The i-th edge in the tree connects Vertex u_i and Vertex v_i, and its length is w_i. Your objective is to paint each vertex in the tree white or black (it is fine to paint all vertices the same color) so that the following condition is satisfied:

* For any two vertices painted in the same color, the distance between them is an even number.



Find a coloring of the vertices that satisfies the condition and print it. It can be proved that at least one such coloring exists under the constraints of this problem.

Constraints

* All values in input are integers.
* 1 \leq N \leq 10^5
* 1 \leq u_i < v_i \leq N
* 1 \leq w_i \leq 10^9

Input

Input is given from Standard Input in the following format:


N
u_1 v_1 w_1
u_2 v_2 w_2
.
.
.
u_{N - 1} v_{N - 1} w_{N - 1}


Output

Print a coloring of the vertices that satisfies the condition, in N lines. The i-th line should contain `0` if Vertex i is painted white and `1` if it is painted black.

If there are multiple colorings that satisfy the condition, any of them will be accepted.

Examples

Input

3
1 2 2
2 3 1


Output

0
0
1


Input

5
2 5 2
2 3 10
1 3 8
3 4 2


Output

1
0
1
0
1

Solution (in CPP):

Solution:
#include<bits/stdc++.h>

using namespace std;
using ll = long long;

int n;
vector<vector<pair<int,int>>> hen;
vector<int> col;

void dfs(int v, int prev, ll dist){

    col[v] = dist & 1;

    for(auto i : hen[v]) {
        if(i.first == prev)continue;
        dfs(i.first, v, dist + i.second);

    }

}

int main()
{
    cin >> n;
    hen.resize(n);
    col.resize(n);

    for(int i = 0; i < n - 1; i++){
        int a, b, c; cin >> a >> b >> c; a--, b--;
        hen[a].push_back({b,c});
        hen[b].push_back({a,c});
    }

    dfs(0,0,0);

    for(auto i : col){
        cout << i << endl;
    }

}