Problem: Spongebob is already tired trying to reason his weird actions and calculations, so he simply asked you to find all pairs of n and m, such that there are exactly x distinct squares in the table consisting of n rows and m columns. For example, in a 3 × 5 table there are 15 squares with side one, 8 squares with side two and 3 squares with side three. The total number of distinct squares in a 3 × 5 table is 15 + 8 + 3 = 26.

Input

The first line of the input contains a single integer x (1 ≤ x ≤ 1018) — the number of squares inside the tables Spongebob is interested in.

Output

First print a single integer k — the number of tables with exactly x distinct squares inside.

Then print k pairs of integers describing the tables. Print the pairs in the order of increasing n, and in case of equality — in the order of increasing m.

Examples

Input

26


Output

6
1 26
2 9
3 5
5 3
9 2
26 1


Input

2


Output

2
1 2
2 1


Input

8


Output

4
1 8
2 3
3 2
8 1

Note

In a 1 × 2 table there are 2 1 × 1 squares. So, 2 distinct squares in total.

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In a 2 × 3 table there are 6 1 × 1 squares and 2 2 × 2 squares. That is equal to 8 squares in total.

<image>

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
set<pair<unsigned long long, unsigned long long> > S;
int main() {
  long long x;
  cin >> x;
  S.insert(make_pair(1, x));
  S.insert(make_pair(x, 1));
  for (unsigned long long i = 2; i <= 10000000; i++) {
    if ((6 * x + i * (i - 1) * (i + 1)) % (3 * i * (i + 1)) == 0) {
      if (i > (6 * x + i * (i - 1) * (i + 1)) / (3 * i * (i + 1))) continue;
      S.insert(
          make_pair(i, (6 * x + i * (i - 1) * (i + 1)) / (3 * i * (i + 1))));
      S.insert(
          make_pair((6 * x + i * (i - 1) * (i + 1)) / (3 * i * (i + 1)), i));
    }
  }
  cout << S.size() << '\n';
  for (set<pair<unsigned long long, unsigned long long> >::iterator it =
           S.begin();
       it != S.end(); it++)
    cout << it->first << ' ' << it->second << '\n';
  return 0;
}