Problem: Polycarp has guessed three positive integers a, b and c. He keeps these numbers in secret, but he writes down four numbers on a board in arbitrary order — their pairwise sums (three numbers) and sum of all three numbers (one number). So, there are four numbers on a board in random order: a+b, a+c, b+c and a+b+c.

You have to guess three numbers a, b and c using given numbers. Print three guessed integers in any order.

Pay attention that some given numbers a, b and c can be equal (it is also possible that a=b=c).

Input

The only line of the input contains four positive integers x_1, x_2, x_3, x_4 (2 ≤ x_i ≤ 10^9) — numbers written on a board in random order. It is guaranteed that the answer exists for the given number x_1, x_2, x_3, x_4.

Output

Print such positive integers a, b and c that four numbers written on a board are values a+b, a+c, b+c and a+b+c written in some order. Print a, b and c in any order. If there are several answers, you can print any. It is guaranteed that the answer exists.

Examples

Input


3 6 5 4


Output


2 1 3


Input


40 40 40 60


Output


20 20 20


Input


201 101 101 200


Output


1 100 100

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int main() {
  int a = 0;
  int b = 0;
  int c = 0;
  int x, y, z, w;
  cin >> x >> y >> z >> w;
  if (x >= y && x >= z && x >= w) {
    a = (x - w);
    b = (x - y);
    c = (x - z);
  } else if (w >= x && w >= z && w >= y) {
    a = (w - x);
    b = (w - y);
    c = (w - z);
  } else if (y >= x && y >= z && y >= w) {
    a = (y - x);
    b = (y - w);
    c = (y - z);
  } else if (z >= x && z >= w && z >= y) {
    a = (z - x);
    b = (z - y);
    c = (z - w);
  }
  cout << a << " " << b << " " << c;
  return 0;
}