Problem: There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice. Each of these choices is represented by a string s_i. If s_i is `AB`, you must add 1 to A or B then subtract 1 from the other; if s_i is `AC`, you must add 1 to A or C then subtract 1 from the other; if s_i is `BC`, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

* 1 \leq N \leq 10^5
* 0 \leq A,B,C \leq 10^9
* N, A, B, C are integers.
* s_i is `AB`, `AC`, or `BC`.

Input

Input is given from Standard Input in the following format:


N A B C
s_1
s_2
:
s_N


Output

If it is possible to make N choices under the condition, print `Yes`; otherwise, print `No`.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (`A`, `B`, or `C`) to which you add 1 in the i-th choice.

Examples

Input

2 1 3 0
AB
AC


Output

Yes
A
C


Input

3 1 0 0
AB
BC
AB


Output

No


Input

1 0 9 0
AC


Output

No


Input

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB


Output

Yes
C
B
B
C
C
B
A
A

Solution (in PYTHON3):

Solution:
n,a,b,c = map(int,input().split())

si = [input() for i in range(n)]

if a == 0 and b == 0 and c== 0:
    print("No")
    exit()

s1 = 0
s2 = 0

abc = [a,b,c]
moji = ['A','B','C']

def checkmoji(s):
    if s == "AB":
        s1 = 0
        s2 = 1
    elif s == 'AC':
        s1 = 0
        s2 = 2
    elif s == 'BC':
        s1 = 1
        s2 = 2
    return s1,s2

ans = []

for i in range(n):
    s1,s2 = checkmoji(si[i])
    if abc[s1] == 0 and abc[s2] == 0:
        print('No')
        exit()
    if abc[s2] == 0:
        abc[s1] -= 1
        abc[s2] += 1
        ans.append(moji[s2])
    elif abc[s1] == 0:
        abc[s1] += 1
        abc[s2] -= 1
        ans.append(moji[s1])
    else:
        
        if i == n-1:
            ans.append(moji[s1])
            break
        
        s1_a,s2_a = checkmoji(si[i+1])
        if s1 == s1_a or s1 == s2_a:
            abc[s1] += 1
            abc[s2] -= 1
            ans.append(moji[s1])
        else:
            abc[s1] -= 1
            abc[s2] += 1
            ans.append(moji[s2])
print('Yes')
for i in range(len(ans)):
    print(ans[i])