Problem: There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice. Each of these choices is represented by a string s_i. If s_i is `AB`, you must add 1 to A or B then subtract 1 from the other; if s_i is `AC`, you must add 1 to A or C then subtract 1 from the other; if s_i is `BC`, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

* 1 \leq N \leq 10^5
* 0 \leq A,B,C \leq 10^9
* N, A, B, C are integers.
* s_i is `AB`, `AC`, or `BC`.

Input

Input is given from Standard Input in the following format:


N A B C
s_1
s_2
:
s_N


Output

If it is possible to make N choices under the condition, print `Yes`; otherwise, print `No`.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (`A`, `B`, or `C`) to which you add 1 in the i-th choice.

Examples

Input

2 1 3 0
AB
AC


Output

Yes
A
C


Input

3 1 0 0
AB
BC
AB


Output

No


Input

1 0 9 0
AC


Output

No


Input

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB


Output

Yes
C
B
B
C
C
B
A
A

Solution (in PYTHON3):

Solution:
import sys
input = sys.stdin.readline
n,a,b,c=map(int,input().split())
def d(x):
	if x=="AB":
		return 0
	elif x=="BC":
		return 1
	else:
		return 2
L=[d(input().rsplit()[0]) for _ in range(n)]
ABC=[a,b,c]
ans=[]
w="ABC"
append=ans.append
sha={1:1,3:2,2:0}
for i,x in enumerate(L):
	y=(x+1)%3
	if ABC[x]==ABC[y]==0:
		print("No")
		exit()
	elif ABC[x]==ABC[y]:
		if i<n-1:
			xx=L[i+1]
			if x==xx:
				append(w[x])
				ABC[x]+=1
				ABC[y]-=1
			else:
				ss=sha[x^xx]
				if x==ss:
					append(w[x])
					ABC[x]+=1
					ABC[y]-=1
				else:
					append(w[y])
					ABC[x]-=1
					ABC[y]+=1
		else:
			append(w[x])
	else:
		if ABC[x]>ABC[y]:
			x,y=y,x
		append(w[x])
		ABC[x]+=1
		ABC[y]-=1
print("Yes")
print("\n".join(ans))