Problem: There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice. Each of these choices is represented by a string s_i. If s_i is `AB`, you must add 1 to A or B then subtract 1 from the other; if s_i is `AC`, you must add 1 to A or C then subtract 1 from the other; if s_i is `BC`, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

* 1 \leq N \leq 10^5
* 0 \leq A,B,C \leq 10^9
* N, A, B, C are integers.
* s_i is `AB`, `AC`, or `BC`.

Input

Input is given from Standard Input in the following format:


N A B C
s_1
s_2
:
s_N


Output

If it is possible to make N choices under the condition, print `Yes`; otherwise, print `No`.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (`A`, `B`, or `C`) to which you add 1 in the i-th choice.

Examples

Input

2 1 3 0
AB
AC


Output

Yes
A
C


Input

3 1 0 0
AB
BC
AB


Output

No


Input

1 0 9 0
AC


Output

No


Input

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB


Output

Yes
C
B
B
C
C
B
A
A

Solution (in PYTHON3):

Solution:

n,a,b,c = list(map(int, input().split()))
s = [[0]*2 for _ in range(n)]
S = []
for i in range(n):
  X = input()
  S += X
  cnt = 0
  for x in X:
    if x == 'A':
      s[i][cnt] = 0
    elif x == 'B':
      s[i][cnt] = 1
    else:
      s[i][cnt] = 2
    cnt += 1

if (a + b + c) == 0:exit(print('No'))
abc = [a,b,c]
ABC = ['A','B','C']


ans = [0] * n

def zero(xy):
  x = xy[0]
  y = xy[1]
  if abc[x] == 0 and abc[y] == 0:
    return -1,-1
  elif abc[x] == 0:
    return x,y
  elif abc[y] == 0:
    return y,x
  else:
    return 3,3

def main():
  global ans
  global abc
  
  for i in range(n):
    x,y = zero(s[i])
    if x == -1:exit(print('No'))
    if x == 3:
      if i < n-1:
        if s[i][1] in s[i+1]:
          x = s[i][1]
          y = s[i][0]
        else:
          x = s[i][0]
          y = s[i][1]
      else:
        x = s[i][0]
        y = s[i][1]
    ans[i] = x
    abc[x] += 1
    abc[y] -= 1

main()
print('Yes')
for i in range(n):
  print(ABC[ans[i]])