Problem: Sereja placed n points on a plane. Now Sereja wants to place on the plane two straight lines, intersecting at a right angle, so that one of the straight lines intersect the Ox axis at an angle of 45 degrees and the maximum distance from the points to the straight lines were minimum. 

In this problem we consider the distance between points (x1, y1) and (x2, y2) equal |x1 - x2| + |y1 - y2|. The distance between the point and the straight lines is the minimum distance from the point to some point belonging to one of the lines.

Help Sereja, find the maximum distance from the points to the optimally located straight lines.

Input

The first line contains integer n (1 ≤ n ≤ 105). Next n lines contain the coordinates of the lines. The i-th line contains two integers xi, yi (|xi|, |yi| ≤ 109).

Output

In a single line print a real number — the answer to the problem. Your answer will be considered correct iff its absolute or relative error doesn't exceed 10 - 6.

Examples

Input

4
0 0
2 0
0 2
2 2


Output

0.000000000000000


Input

4
1 0
0 1
2 1
1 2


Output

1.000000000000000

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
template <typename T1, typename T2>
inline void chkmin(T1 &x, T2 y) {
  if (x > y) x = y;
}
template <typename T1, typename T2>
inline void chkmax(T1 &x, T2 y) {
  if (x < y) x = y;
}
inline int readChar();
template <class T = int>
inline T readInt();
template <class T>
inline void writeInt(T x, char end = 0);
inline void writeChar(int x);
inline void writeWord(const char *s);
static const int buf_size = 4096;
inline int getChar() {
  static char buf[buf_size];
  static int len = 0, pos = 0;
  if (pos == len) pos = 0, len = fread(buf, 1, buf_size, stdin);
  if (pos == len) return -1;
  return buf[pos++];
}
inline int readChar() {
  int c = getChar();
  while (c <= 32) c = getChar();
  return c;
}
template <class T>
inline T readInt() {
  int s = 1, c = readChar();
  T x = 0;
  if (c == '-') s = -1, c = getChar();
  while ('0' <= c && c <= '9') x = x * 10 + c - '0', c = getChar();
  return s == 1 ? x : -x;
}
static int write_pos = 0;
static char write_buf[buf_size];
inline void writeChar(int x) {
  if (write_pos == buf_size)
    fwrite(write_buf, 1, buf_size, stdout), write_pos = 0;
  write_buf[write_pos++] = x;
}
template <class T>
inline void writeInt(T x, char end) {
  if (x < 0) writeChar('-'), x = -x;
  char s[24];
  int n = 0;
  while (x || !n) s[n++] = '0' + x % 10, x /= 10;
  while (n--) writeChar(s[n]);
  if (end) writeChar(end);
}
inline void writeWord(const char *s) {
  while (*s) writeChar(*s++);
}
struct flusher {
  ~flusher() {
    if (write_pos) fwrite(write_buf, 1, write_pos, stdout), write_pos = 0;
  }
} flusher;
const int MAXN = 100228;
const long long inf = 10000000000LL;
struct point {
  long long x, y;
};
int pos[MAXN];
long long minPref[MAXN], maxPref[MAXN], minSuff[MAXN], maxSuff[MAXN];
pair<long long, int> lx[MAXN], rx[MAXN];
long long x[2 * MAXN];
point p[MAXN];
int main() {
  int n = readInt();
  for (int i = 0; i < n; i++) {
    long long x = readInt(), y = readInt();
    x *= 2LL;
    y *= 2LL;
    p[i].x = x + y;
    p[i].y = x - y;
  }
  for (int i = 0; i < n; i++) {
    lx[i] = make_pair(p[i].x, i);
    rx[i] = make_pair(p[i].x, i);
    x[(i << 1)] = p[i].x;
    x[(i << 1) + 1] = p[i].x;
  }
  sort(lx, lx + n);
  sort(rx, rx + n);
  sort(x, x + 2 * n);
  int k = unique(x, x + 2 * n) - x;
  long long ans = inf, l = 0, r = inf;
  while (l <= r) {
    long long mid = (l + r) >> 1;
    bool can = false;
    for (int i = 0; i < n; i++) {
      minPref[i] = min((i > 0 ? minPref[i - 1] : inf), p[lx[i].second].y + mid);
      maxPref[i] =
          max((i > 0 ? maxPref[i - 1] : -inf), p[lx[i].second].y - mid);
    }
    for (int i = n - 1; i >= 0; i--) {
      minSuff[i] =
          min((i + 1 < n ? minSuff[i + 1] : inf), p[rx[i].second].y + mid);
      maxSuff[i] =
          max((i + 1 < n ? maxSuff[i + 1] : -inf), p[rx[i].second].y - mid);
    }
    int i = 0, j = 0, ukl = -1, ukr = 0;
    while (i < k && j < k) {
      if (x[i] - mid < x[j] + mid) {
        long long cx = x[i++] - mid;
        while (ukl + 1 < n && lx[ukl + 1].first + mid < cx) {
          ukl++;
        }
        while (ukr < n && rx[ukr].first - mid <= cx) {
          ukr++;
        }
        long long _left = -inf, _right = inf;
        if (ukl >= 0) {
          _left = max(_left, maxPref[ukl]);
          _right = min(_right, minPref[ukl]);
        }
        if (ukr < n) {
          _left = max(_left, maxSuff[ukr]);
          _right = min(_right, minSuff[ukr]);
        }
        if (_left <= _right) {
          can = true;
          break;
        }
      } else {
        long long cx = x[j++] + mid;
        while (ukl + 1 < n && lx[ukl + 1].first + mid < cx) {
          ukl++;
        }
        while (ukr < n && rx[ukr].first - mid <= cx) {
          ukr++;
        }
        long long _left = -inf, _right = inf;
        if (ukl >= 0) {
          _left = max(_left, maxPref[ukl]);
          _right = min(_right, minPref[ukl]);
        }
        if (ukr < n) {
          _left = max(_left, maxSuff[ukr]);
          _right = min(_right, minSuff[ukr]);
        }
        if (_left <= _right) {
          can = true;
          break;
        }
      }
    }
    while (i < k && !can) {
      long long cx = x[i++] - mid;
      while (ukl + 1 < n && lx[ukl + 1].first + mid < cx) {
        ukl++;
      }
      while (ukr < n && rx[ukr].first - mid <= cx) {
        ukr++;
      }
      long long _left = -inf, _right = inf;
      if (ukl >= 0) {
        _left = max(_left, maxPref[ukl]);
        _right = min(_right, minPref[ukl]);
      }
      if (ukr < n) {
        _left = max(_left, maxSuff[ukr]);
        _right = min(_right, minSuff[ukr]);
      }
      if (_left <= _right) {
        can = true;
        break;
      }
    }
    while (j < k && !can) {
      long long cx = x[j++] - mid;
      while (ukl + 1 < n && lx[ukl + 1].first + mid < cx) {
        ukl++;
      }
      while (ukr < n && rx[ukr].first - mid <= cx) {
        ukr++;
      }
      long long _left = -inf, _right = inf;
      if (ukl >= 0) {
        _left = max(_left, maxPref[ukl]);
        _right = min(_right, minPref[ukl]);
      }
      if (ukr < n) {
        _left = max(_left, maxSuff[ukr]);
        _right = min(_right, minSuff[ukr]);
      }
      if (_left <= _right) {
        can = true;
        break;
      }
    }
    if (can) {
      ans = mid;
      r = mid - 1;
    } else {
      l = mid + 1;
    }
  }
  printf("%lld.%d\n", ans / 2, (ans % 2 ? 5 : 0));
  return 0;
}