Problem: An exam for n students will take place in a long and narrow room, so the students will sit in a line in some order. The teacher suspects that students with adjacent numbers (i and i + 1) always studied side by side and became friends and if they take an exam sitting next to each other, they will help each other for sure.

Your task is to choose the maximum number of students and make such an arrangement of students in the room that no two students with adjacent numbers sit side by side.

Input

A single line contains integer n (1 ≤ n ≤ 5000) — the number of students at an exam.

Output

In the first line print integer k — the maximum number of students who can be seated so that no two students with adjacent numbers sit next to each other.

In the second line print k distinct integers a1, a2, ..., ak (1 ≤ ai ≤ n), where ai is the number of the student on the i-th position. The students on adjacent positions mustn't have adjacent numbers. Formally, the following should be true: |ai - ai + 1| ≠ 1 for all i from 1 to k - 1.

If there are several possible answers, output any of them.

Examples

Input

6

Output

6
1 5 3 6 2 4

Input

3


Output

2
1 3

Solution (in JAVA):

Solution:
import java.util.ArrayDeque;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.BufferedReader;
import java.io.OutputStream;
import java.io.PrintWriter;
import java.io.IOException;
import java.util.StringTokenizer;

/**
 * Built using CHelper plug-in
 * Actual solution is at the top
 * @author Artem Gilmudinov
 */
public class Main {
	public static void main(String[] args) {
		InputStream inputStream = System.in;
		OutputStream outputStream = System.out;
		Reader in = new Reader(inputStream);
		PrintWriter out = new PrintWriter(outputStream);
		TaskA solver = new TaskA();
		solver.solve(1, in, out);
		out.close();
	}
}

class TaskA {
    public void solve(int testNumber, Reader in, PrintWriter out) {
        int n = in.ni();
        if(n == 1) {
            out.println(1);
            out.println(1);
        } else if(n == 2) {
            out.println(1);
            out.println(1);
        } else if(n == 3) {
            out.println(2);
            out.println("1 3");
        } else {
            out.println(n);
            ArrayDeque<Integer> deque = new ArrayDeque<Integer>();
            deque.addFirst(3);
            deque.addFirst(1);
            deque.addFirst(4);
            deque.addFirst(2);
            for(int i = 5; i <= n; i++) {
                if(i % 2 == 0) {
                    deque.addFirst(i);
                } else {
                    deque.addLast(i);
                }
            }
            while(deque.size() != 0) {
                out.print(deque.pollFirst() + " ");
            }
        }
    }
}

class Reader {
    private BufferedReader in;
    private StringTokenizer st = new StringTokenizer("");
    private String delim = " ";

    public Reader(InputStream in) {
        this.in = new BufferedReader(new InputStreamReader(in));
    }

    public String next() {
        if (!st.hasMoreTokens()) {
            st = new StringTokenizer(rl());
        }
        return st.nextToken(delim);
    }

    public String rl() {
        try {
            return in.readLine();
        } catch(IOException e) {
            throw new RuntimeException(e);
        }
    }

    public int ni() {
        return Integer.parseInt(next());
    }

}