Problem: Stack is a container of elements that are inserted and deleted according to LIFO (Last In First Out).

For $n$ stack $S_i$ ($i = 0, 1, ..., n-1$), perform a sequence of the following operations.

* push($t$, $x$): Insert an integer $x$ to $S_t$.
* top($t$): Report the value which should be deleted next from $S_t$. If $S_t$ is empty, do nothing.
* pop($t$): Delete an element from $S_t$. If $S_t$ is empty, do nothing.



In the initial state, all stacks are empty.

Constraints

* $1 \leq n \leq 1,000$
* $1 \leq q \leq 200,000$
* $-1,000,000,000 \leq x \leq 1,000,000,000$

Input

The input is given in the following format.


$n \; q$
$query_1$
$query_2$
:
$query_q$


Each query $query_i$ is given by


0 $t$ $x$


or


1 $t$


or


2 $t$


where the first digits 0, 1 and 2 represent push, top and pop operations respectively.

Output

For each top operation, print an integer in a line.

Example

Input

3 9
0 0 1
0 0 2
0 0 3
0 2 4
0 2 5
1 0
1 2
2 0
1 0


Output

3
5
2

Solution (in CPP):

Solution:
#include<iostream>
#include<vector>
#include<algorithm>
#include<string>
#include<stack>
using namespace std;



int main() {

	int n, q;
	cin >> n >> q;

	vector< stack <int> > s(n);

	for (int i = 0; i < q; i++) {

		int a, t, x;
		cin >> a;
		if (a == 0) {
			cin >> t >> x;

			s[t].push(x);

		}

		if (a == 1) {
			cin >> t;
			if (!s[t].empty()) {
				cout << s[t].top() << endl;
			}
		}

		if (a == 2) {
			cin >> t;
			if (!s[t].empty()) {
				s[t].pop();

			}


		}

	}



	return 0;
}