Problem: You have a sequence A composed of N positive integers: A_{1}, A_{2}, \cdots, A_{N}.

You will now successively do the following Q operations:

* In the i-th operation, you replace every element whose value is B_{i} with C_{i}.



For each i (1 \leq i \leq Q), find S_{i}: the sum of all elements in A just after the i-th operation.

Constraints

* All values in input are integers.
* 1 \leq N, Q, A_{i}, B_{i}, C_{i} \leq 10^{5}
* B_{i} \neq C_{i}

Input

Input is given from Standard Input in the following format:


N
A_{1} A_{2} \cdots A_{N}
Q
B_{1} C_{1}
B_{2} C_{2}
\vdots
B_{Q} C_{Q}


Output

Print Q integers S_{i} to Standard Output in the following format:


S_{1}
S_{2}
\vdots
S_{Q}


Note that S_{i} may not fit into a 32-bit integer.

Examples

Input

4
1 2 3 4
3
1 2
3 4
2 4


Output

11
12
16


Input

4
1 1 1 1
3
1 2
2 1
3 5


Output

8
4
4


Input

2
1 2
3
1 100
2 100
100 1000


Output

102
200
2000

Solution (in JAVA):

Solution:
import java.io.PrintWriter;
import java.util.HashMap;
import java.util.Map;
import java.util.Scanner;

public class Main {
    Map<Integer, Integer> count = new HashMap<>();
    long sum;
    void solve(Scanner sc, PrintWriter pw) {
        int N = sc.nextInt();
        for (int i = 0; i < N; i++) {
            int data = sc.nextInt();
            count.put(data, count.getOrDefault(data, 0) + 1);
            sum += data;
        }
        int Q = sc.nextInt();
        long result = sum;
        for (int i = 0; i < Q; i++) {
            int b = sc.nextInt();
            int c = sc.nextInt();
            result += (c - b) * count.getOrDefault(b, 0);
            count.put(c, count.getOrDefault(b, 0) + count.getOrDefault(c, 0));
            count.remove(b);
            pw.println(result);
        }
    }
    public static void main(String[] args){
        Scanner sc = new Scanner(System.in);
        PrintWriter pw = new PrintWriter(System.out);
        new Main().solve(sc, pw);
        pw.flush();
        pw.close();
        sc.close();
    }
}