Problem: You have array of n numbers a_{1}, a_{2}, …, a_{n}. 

Rearrange these numbers to satisfy |a_{1} - a_{2}| ≤ |a_{2} - a_{3}| ≤ … ≤ |a_{n-1} - a_{n}|, where |x| denotes absolute value of x. It's always possible to find such rearrangement.

Note that all numbers in a are not necessarily different. In other words, some numbers of a may be same.

You have to answer independent t test cases.

Input

The first line contains a single integer t (1 ≤ t ≤ 10^{4}) — the number of test cases.

The first line of each test case contains single integer n (3 ≤ n ≤ 10^{5}) — the length of array a. It is guaranteed that the sum of values of n over all test cases in the input does not exceed 10^{5}.

The second line of each test case contains n integers a_{1}, a_{2}, …, a_{n} (-10^{9} ≤ a_{i} ≤ 10^{9}).

Output

For each test case, print the rearranged version of array a which satisfies given condition. If there are multiple valid rearrangements, print any of them.

Example

Input


2
6
5 -2 4 8 6 5
4
8 1 4 2


Output


5 5 4 6 8 -2
1 2 4 8

Note

In the first test case, after given rearrangement, |a_{1} - a_{2}| = 0 ≤ |a_{2} - a_{3}| = 1 ≤ |a_{3} - a_{4}| = 2 ≤ |a_{4} - a_{5}| = 2 ≤ |a_{5} - a_{6}| = 10. There are other possible answers like "5 4 5 6 -2 8".

In the second test case, after given rearrangement, |a_{1} - a_{2}| = 1 ≤ |a_{2} - a_{3}| = 2 ≤ |a_{3} - a_{4}| = 4. There are other possible answers like "2 4 8 1".

Solution (in PYTHON3):

Solution:
n=int(input())
i=0
ans=[]
for i in range(0,n):
    d=int(input())
    data=[]
    dd = input()
    ddd=dd.split()
    for k in range(0,d):
        data.append(int(ddd[k]))
    data.sort()
    data2=[]
    s=""
    if d % 2 == 0:
        mid=(len(data))//2
        data2.append(data[mid])
        for k in range(1,(len(data))//2):
            data2.append(data[mid-k])
            data2.append(data[mid+k])
        data2.append(data[0])
    else:
        mid = (len(data)-1) // 2
        data2.append(data[mid])
        for k in range(1, (len(data)) // 2):
            data2.append(data[mid + k])
            data2.append(data[mid - k])
        data2.append(data[-1])
        data2.append(data[0])
    for s1 in data2:
        s+=str(s1)+" "
    ans.append(s)
for i in range(0,n):
    print(ans[i])