Problem: One day, Hongcow goes to the store and sees a brand new deck of n special cards. Each individual card is either red or blue. He decides he wants to buy them immediately. To do this, he needs to play a game with the owner of the store.

This game takes some number of turns to complete. On a turn, Hongcow may do one of two things: 

  * Collect tokens. Hongcow collects 1 red token and 1 blue token by choosing this option (thus, 2 tokens in total per one operation). 
  * Buy a card. Hongcow chooses some card and spends tokens to purchase it as specified below. 



The i-th card requires ri red resources and bi blue resources. Suppose Hongcow currently has A red cards and B blue cards. Then, the i-th card will require Hongcow to spend max(ri - A, 0) red tokens, and max(bi - B, 0) blue tokens. Note, only tokens disappear, but the cards stay with Hongcow forever. Each card can be bought only once.

Given a description of the cards and their costs determine the minimum number of turns Hongcow needs to purchase all cards.

Input

The first line of input will contain a single integer n (1 ≤ n ≤ 16).

The next n lines of input will contain three tokens ci, ri and bi. ci will be 'R' or 'B', denoting the color of the card as red or blue. ri will be an integer denoting the amount of red resources required to obtain the card, and bi will be an integer denoting the amount of blue resources required to obtain the card (0 ≤ ri, bi ≤ 107).

Output

Output a single integer, denoting the minimum number of turns needed to acquire all the cards.

Examples

Input

3
R 0 1
B 1 0
R 1 1


Output

4


Input

3
R 3 0
R 2 0
R 1 0


Output

6

Note

For the first sample, Hongcow's four moves are as follows: 

  1. Collect tokens 
  2. Buy card 1
  3. Buy card 2
  4. Buy card 3

Note, at the fourth step, Hongcow is able to buy card 3 because Hongcow already has one red and one blue card, so we don't need to collect tokens.

For the second sample, one optimal strategy is as follows: 

  1. Collect tokens 
  2. Collect tokens 
  3. Buy card 2
  4. Collect tokens 
  5. Buy card 3
  6. Buy card 1

At the fifth step, even though Hongcow has a red token, Hongcow doesn't actually need to spend it, since Hongcow has a red card already.

Solution (in JAVA):

Solution:
import java.io.OutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.OutputStream;
import java.util.Arrays;
import java.io.IOException;
import java.io.UncheckedIOException;
import java.io.Closeable;
import java.io.Writer;
import java.io.OutputStreamWriter;
import java.io.InputStream;

/**
 * Built using CHelper plug-in
 * Actual solution is at the top
 */
public class Main {
    public static void main(String[] args) throws Exception {
        Thread thread = new Thread(null, new TaskAdapter(), "", 1 << 29);
        thread.start();
        thread.join();
    }

    static class TaskAdapter implements Runnable {
        @Override
        public void run() {
            InputStream inputStream = System.in;
            OutputStream outputStream = System.out;
            FastInput in = new FastInput(inputStream);
            FastOutput out = new FastOutput(outputStream);
            CHongcowBuysADeckOfCards solver = new CHongcowBuysADeckOfCards();
            solver.solve(1, in, out);
            out.close();
        }
    }

    static class CHongcowBuysADeckOfCards {
        public void solve(int testNumber, FastInput in, FastOutput out) {
            int n = in.readInt();
            Card[] cards = new Card[n];
            for (int i = 0; i < n; i++) {
                cards[i] = new Card();
                cards[i].type = in.readChar() == 'R' ? 0 : 1;
                cards[i].r = in.readInt();
                cards[i].b = in.readInt();
            }

            int[][] save = new int[150][1 << n];
            SequenceUtils.deepFill(save, -(int) 1e9);
            save[0][0] = 0;
            for (int i = 0; i < 1 << n; i++) {
                int rCnt = 0;
                int bCnt = 0;
                for (int j = 0; j < n; j++) {
                    if (Bits.get(i, j) == 0) {
                        continue;
                    }
                    if (cards[j].type == 0) {
                        rCnt++;
                    } else {
                        bCnt++;
                    }
                }
                for (int j = 0; j < n; j++) {
                    if (Bits.get(i, j) == 1) {
                        continue;
                    }
                    int next = Bits.set(i, j);
                    int rSave = Math.min(cards[j].r, rCnt);
                    int bSave = Math.min(cards[j].b, bCnt);
                    for (int k = 0; k < 150; k++) {
                        if (k + rSave < 150) {
                            save[k + rSave][next] = Math.max(save[k + rSave][next], save[k][i] + bSave);
                        }
                    }
                }
            }

            int rSum = 0;
            int bSum = 0;
            for (int i = 0; i < n; i++) {
                rSum += cards[i].r;
                bSum += cards[i].b;
            }

            int ans = (int) 1e9;
            int mask = (1 << n) - 1;
            for (int i = 0; i < 150; i++) {
                int time = Math.max(Math.abs(rSum - i), Math.abs(bSum - save[i][mask]));
                ans = Math.min(ans, time);
            }
            ans += n;

            out.println(ans);
        }

    }

    static class SequenceUtils {
        public static void deepFill(Object array, int val) {
            if (!array.getClass().isArray()) {
                throw new IllegalArgumentException();
            }
            if (array instanceof int[]) {
                int[] intArray = (int[]) array;
                Arrays.fill(intArray, val);
            } else {
                Object[] objArray = (Object[]) array;
                for (Object obj : objArray) {
                    deepFill(obj, val);
                }
            }
        }

    }

    static class FastInput {
        private final InputStream is;
        private byte[] buf = new byte[1 << 13];
        private int bufLen;
        private int bufOffset;
        private int next;

        public FastInput(InputStream is) {
            this.is = is;
        }

        private int read() {
            while (bufLen == bufOffset) {
                bufOffset = 0;
                try {
                    bufLen = is.read(buf);
                } catch (IOException e) {
                    bufLen = -1;
                }
                if (bufLen == -1) {
                    return -1;
                }
            }
            return buf[bufOffset++];
        }

        public void skipBlank() {
            while (next >= 0 && next <= 32) {
                next = read();
            }
        }

        public int readInt() {
            int sign = 1;

            skipBlank();
            if (next == '+' || next == '-') {
                sign = next == '+' ? 1 : -1;
                next = read();
            }

            int val = 0;
            if (sign == 1) {
                while (next >= '0' && next <= '9') {
                    val = val * 10 + next - '0';
                    next = read();
                }
            } else {
                while (next >= '0' && next <= '9') {
                    val = val * 10 - next + '0';
                    next = read();
                }
            }

            return val;
        }

        public char readChar() {
            skipBlank();
            char c = (char) next;
            next = read();
            return c;
        }

    }

    static class Card {
        int type;
        int r;
        int b;

    }

    static class Bits {
        private Bits() {
        }

        public static int get(int x, int i) {
            return (x >>> i) & 1;
        }

        public static int set(int x, int i) {
            return x | (1 << i);
        }

    }

    static class FastOutput implements AutoCloseable, Closeable, Appendable {
        private StringBuilder cache = new StringBuilder(10 << 20);
        private final Writer os;

        public FastOutput append(CharSequence csq) {
            cache.append(csq);
            return this;
        }

        public FastOutput append(CharSequence csq, int start, int end) {
            cache.append(csq, start, end);
            return this;
        }

        public FastOutput(Writer os) {
            this.os = os;
        }

        public FastOutput(OutputStream os) {
            this(new OutputStreamWriter(os));
        }

        public FastOutput append(char c) {
            cache.append(c);
            return this;
        }

        public FastOutput append(int c) {
            cache.append(c);
            return this;
        }

        public FastOutput println(int c) {
            return append(c).println();
        }

        public FastOutput println() {
            cache.append(System.lineSeparator());
            return this;
        }

        public FastOutput flush() {
            try {
                os.append(cache);
                os.flush();
                cache.setLength(0);
            } catch (IOException e) {
                throw new UncheckedIOException(e);
            }
            return this;
        }

        public void close() {
            flush();
            try {
                os.close();
            } catch (IOException e) {
                throw new UncheckedIOException(e);
            }
        }

        public String toString() {
            return cache.toString();
        }

    }
}