Problem: There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice. Each of these choices is represented by a string s_i. If s_i is `AB`, you must add 1 to A or B then subtract 1 from the other; if s_i is `AC`, you must add 1 to A or C then subtract 1 from the other; if s_i is `BC`, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

* 1 \leq N \leq 10^5
* 0 \leq A,B,C \leq 10^9
* N, A, B, C are integers.
* s_i is `AB`, `AC`, or `BC`.

Input

Input is given from Standard Input in the following format:


N A B C
s_1
s_2
:
s_N


Output

If it is possible to make N choices under the condition, print `Yes`; otherwise, print `No`.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (`A`, `B`, or `C`) to which you add 1 in the i-th choice.

Examples

Input

2 1 3 0
AB
AC


Output

Yes
A
C


Input

3 1 0 0
AB
BC
AB


Output

No


Input

1 0 9 0
AC


Output

No


Input

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB


Output

Yes
C
B
B
C
C
B
A
A

Solution (in PYTHON3):

Solution:
n,a,b,c=map(int,input().split())
# from collections import Counter
s=[input() for _ in range(n)]
AB,BC,AC="AB","BC","AC"

A="A";B="B";C="C"
ans=[]
for i in range(n):
    now=s[i]
    if i==n-1:
        nxt=" "
    else:
        nxt=s[i+1]
    
    if now==AB:
        if a==0:
            a+=1;b-=1
            ans.append(A)
        elif b==0:
            b+=1;a-=1
            ans.append(B)
        else:
            if nxt==BC:
                b+=1;a-=1
                ans.append(B)
            else:
                a+=1;b-=1
                ans.append(A)
    
    elif now==BC:
        if b==0:
            b+=1;c-=1
            ans.append(B)
        elif c==0:
            c+=1;b-=1
            ans.append(C)
        else:
            if nxt==AC:
                c+=1;b-=1
                ans.append(C)
            else:
                b+=1;c-=1
                ans.append(B)
                
    elif now==AC:
        if a==0:
            a+=1;c-=1
            ans.append(A)
        elif c==0:
            c+=1;a-=1
            ans.append(C)
        else:
            if nxt==BC:
                c+=1;a-=1
                ans.append(C)
            else:
                a+=1;c-=1
                ans.append(A)
                
    
    if min(a,b,c)==-1:
        print("No")
        exit()
print("Yes")
for i in ans:
    print(i)