Problem: There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice. Each of these choices is represented by a string s_i. If s_i is `AB`, you must add 1 to A or B then subtract 1 from the other; if s_i is `AC`, you must add 1 to A or C then subtract 1 from the other; if s_i is `BC`, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

* 1 \leq N \leq 10^5
* 0 \leq A,B,C \leq 10^9
* N, A, B, C are integers.
* s_i is `AB`, `AC`, or `BC`.

Input

Input is given from Standard Input in the following format:


N A B C
s_1
s_2
:
s_N


Output

If it is possible to make N choices under the condition, print `Yes`; otherwise, print `No`.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (`A`, `B`, or `C`) to which you add 1 in the i-th choice.

Examples

Input

2 1 3 0
AB
AC


Output

Yes
A
C


Input

3 1 0 0
AB
BC
AB


Output

No


Input

1 0 9 0
AC


Output

No


Input

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB


Output

Yes
C
B
B
C
C
B
A
A

Solution (in PYTHON3):

Solution:
n, a, b, c = map(int, input().split())
s = [input() for _ in range(n)]

can = 'Yes'
ans = []
val = {'A': a, 'B': b, 'C': c}
if a+b+c == 0:
    can = 'No'
elif a+b+c == 1:
    for ss in s:
        v1, v2 = ss[0], ss[1]
        if val[v1] == val[v2] == 0:
            can = 'No'
            break
        val[v1], val[v2] = val[v2], val[v1]
        ans.append(v1) if val[v1] else ans.append(v2)
else:
    for i in range(n):
        v1, v2 = s[i][0], s[i][1]
        if val[v1] == val[v2] == 0:
            can = 'No'
            break
        if a+b+c == 2 and val[v1] == val[v2] == 1 and i != n-1 and s[i] != s[i+1]:
            if v1 in s[i+1]:
                val[v1] += 1
                val[v2] -= 1
                ans.append(v1)
            else:
                val[v2] += 1
                val[v1] -= 1
                ans.append(v2)
        else:
            if val[v1] < val[v2]:
                val[v1] += 1
                val[v2] -= 1
                ans.append(v1)
            else:
                val[v2] += 1
                val[v1] -= 1
                ans.append(v2)

print(can)
if can == 'Yes':
    print('\n'.join(ans))