Problem: There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice. Each of these choices is represented by a string s_i. If s_i is `AB`, you must add 1 to A or B then subtract 1 from the other; if s_i is `AC`, you must add 1 to A or C then subtract 1 from the other; if s_i is `BC`, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

* 1 \leq N \leq 10^5
* 0 \leq A,B,C \leq 10^9
* N, A, B, C are integers.
* s_i is `AB`, `AC`, or `BC`.

Input

Input is given from Standard Input in the following format:


N A B C
s_1
s_2
:
s_N


Output

If it is possible to make N choices under the condition, print `Yes`; otherwise, print `No`.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (`A`, `B`, or `C`) to which you add 1 in the i-th choice.

Examples

Input

2 1 3 0
AB
AC


Output

Yes
A
C


Input

3 1 0 0
AB
BC
AB


Output

No


Input

1 0 9 0
AC


Output

No


Input

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB


Output

Yes
C
B
B
C
C
B
A
A

Solution (in PYTHON3):

Solution:
N, A, B, C = map(int, input().split())

path = []
inputs = [input() for _ in range(N)]

for i in range(N):
	target = inputs[i]
	if target == 'AB':
		if A > B:
			A -= 1
			B += 1
			path.append('B')
		elif A == 1 and B == 1:
			if i != N - 1 and inputs[i + 1] == 'AC':
				A += 1
				B -= 1
				path.append('A')
			else:
				A -= 1
				B += 1
				path.append('B')
		else:
			A += 1
			B -= 1
			path.append('A')
	if target == 'AC':
		if A > C:
			A -= 1
			C += 1
			path.append('C')
		elif A == 1 and C == 1:
			if i != N - 1 and inputs[i + 1] == 'AB':
				A += 1
				C -= 1
				path.append('A')
			else:
				A -= 1
				C += 1
				path.append('C')
		else:
			A += 1
			C -= 1
			path.append('A')
	if target == 'BC':
		if B > C:
			B -= 1
			C += 1
			path.append('C')
		elif B == 1 and C == 1:
			if i != N - 1 and inputs[i + 1] == 'AB':
				B += 1
				C -= 1
				path.append('B')
			else:
				B -= 1
				C += 1
				path.append('C')
		else:
			B += 1
			C -= 1
			path.append('B')
	if A < 0 or B < 0 or C < 0:
		print('No')
		exit(0)

print('Yes')
for i in path:
	print(i)