Problem: There is a tree with N vertices, numbered 1, 2, \ldots, N. For each i (1 \leq i \leq N - 1), the i-th edge connects Vertex x_i and y_i.

Taro has decided to paint each vertex in white or black, so that any black vertex can be reached from any other black vertex by passing through only black vertices.

You are given a positive integer M. For each v (1 \leq v \leq N), answer the following question:

* Assuming that Vertex v has to be black, find the number of ways in which the vertices can be painted, modulo M.

Constraints

* All values in input are integers.
* 1 \leq N \leq 10^5
* 2 \leq M \leq 10^9
* 1 \leq x_i, y_i \leq N
* The given graph is a tree.

Input

Input is given from Standard Input in the following format:


N M
x_1 y_1
x_2 y_2
:
x_{N - 1} y_{N - 1}


Output

Print N lines. The v-th (1 \leq v \leq N) line should contain the answer to the following question:

* Assuming that Vertex v has to be black, find the number of ways in which the vertices can be painted, modulo M.

Examples

Input

3 100
1 2
2 3


Output

3
4
3


Input

4 100
1 2
1 3
1 4


Output

8
5
5
5


Input

1 100


Output

1


Input

10 2
8 5
10 8
6 5
1 5
4 8
2 10
3 6
9 2
1 7


Output

0
0
1
1
1
0
1
0
1
1

Solution (in PYTHON3):

Solution:
# -*- coding: utf-8 -*-

# Based on the following blog.
# https://null-mn.hatenablog.com/entry/2020/04/14/124151

from collections import defaultdict

class ReRooting:
    def __init__(self, f, g, merge, ie):
        self.tree = defaultdict(list)
        self.f = f
        self.g = g
        self.merge = merge
        self.ie = ie
        self.dp = defaultdict(dict)

    def add_edge(self, u, v):
        self.tree[u].append(v)
        self.tree[v].append(u)

    def __dfs1(self, u, p):
        o = []
        s = [(u, -1)]
        while s:
            u, p = s.pop()
            o.append((u, p))
            for v in self.tree[u]:
                if v == p:
                    continue
                s.append((v, u))

        for u, p in reversed(o):
            r = self.ie
            for v in self.tree[u]:
                if v == p:
                    continue
                r = self.merge(r, self.f(self.dp[u][v], v))

            self.dp[p][u] = self.g(r, u)

    def __dfs2(self, u, p, a):
        s = [(u, p, a)]

        while s:
            u, p, a = s.pop()
            self.dp[u][p] = a

            pl = [0] * (len(self.tree[u]) + 1)
            pl[0] = self.ie
            for i, v in enumerate(self.tree[u]):
                pl[i+1] = self.merge(pl[i], self.f(self.dp[u][v], v))

            pr = [0] * (len(self.tree[u]) + 1)
            pr[-1] = self.ie
            for i, v in reversed(list(enumerate(self.tree[u]))):
                pr[i] = self.merge(pr[i+1], self.f(self.dp[u][v], v))

            for i, v in enumerate(self.tree[u]):
                if v == p:
                    continue
                r = self.merge(pl[i], pr[i+1])
                s.append((v, u, self.g(r, u)))

    # def __dfs1(self, u, p):
    #     r = self.ie
    #     for v in self.tree[u]:
    #         if v == p:
    #             continue
    #         self.dp[u][v] = self.__dfs1(v, u)
    #         r = self.merge(r, self.f(self.dp[u][v], v))

    #     return self.g(r, u)

    # def __dfs2(self, u, p, a):
    #     for v in self.tree[u]:
    #         if v == p:
    #             self.dp[u][v] = a
    #             break
    #     pl = [0] * (len(self.tree[u]) + 1)
    #     pl[0] = self.ie
    #     for i, v in enumerate(self.tree[u]):
    #         pl[i+1] = self.merge(pl[i], self.f(self.dp[u][v], v))

    #     pr = [0] * (len(self.tree[u]) + 1)
    #     pr[-1] = self.ie
    #     for i, v in reversed(list(enumerate(self.tree[u]))):
    #         pr[i] = self.merge(pr[i+1], self.f(self.dp[u][v], v))

    #     for i, v in enumerate(self.tree[u]):
    #         if v == p:
    #             continue
    #         r = self.merge(pl[i], pr[i+1])
    #         self.__dfs2(v, u, self.g(r, v))

    def build(self, root=1):
        self.__dfs1(root, -1)
        self.__dfs2(root, -1, self.ie)

    def slv(self, u):
        r = self.ie
        for v in self.tree[u]:
            r = self.merge(r, self.f(self.dp[u][v], v))

        return self.g(r, u)


def atcoder_dp_dp_v():
    # https://atcoder.jp/contests/dp/tasks/dp_v
    N, M = map(int, input().split())
    XY = [list(map(int, input().split())) for _ in range(N-1)]

    f = lambda x, y: x
    g = lambda x, y: x + 1
    merge = lambda x, y: (x * y) % M
    rr = ReRooting(f, g, merge, 1)
    for x, y in XY:
        rr.add_edge(x, y)

    rr.build()
    for u in range(1, N+1):
        print(rr.slv(u)-1)


def atcoder_abc60_f():
    # https://atcoder.jp/contests/abc160/tasks/abc160_f
    # https://atcoder.jp/contests/abc160/submissions/16667517
    N = int(input())
    AB = [list(map(int, input().split())) for _ in range(N-1)]

    M = 10**9+7

    from functools import reduce

    fact = [1]
    for i in range(1, 10**6):
        fact.append(fact[-1]*i % M)

    def f(x, _):
        c = x[0]
        s = x[1]
        c *= pow(fact[s], M-2, M)
        c %= M
        return (c, s)

    def g(x, _):
        c = x[0]
        s = x[1]
        c *= fact[s]
        c %= M
        return (c, s+1)

    def merge(x, y):
        return (x[0]*y[0]%M, x[1]+y[1])

    rr = ReRooting(f, g, merge, (1, 0))
    for a, b in AB:
        rr.add_edge(a, b)

    rr.build()
    for u in range(1, N+1):
        print(rr.slv(u)[0])


def codeforces_1324_f():
    N = int(input())
    A = list(map(int, input().split()))
    UV = [list(map(int, input().split())) for _ in range(N-1)]

    f = lambda x, v: max(x, 0)

    def g(x, v):
        return x + (1 if A[v-1] == 1 else -1)

    def merge(x, y):
        return x + y

    rr = ReRooting(f, g, merge, 0)
    for u, v in UV:
        rr.add_edge(u, v)



    rr.build()
    # rr.slv(2)
    ans = []
    for u in range(1, N+1):
        ans.append(rr.slv(u))

    print(*ans)


if __name__ == '__main__':
    atcoder_dp_dp_v()
    # atcoder_abc60_f()
    # codeforces_1324_f()