Problem: You have a sequence A composed of N positive integers: A_{1}, A_{2}, \cdots, A_{N}.

You will now successively do the following Q operations:

* In the i-th operation, you replace every element whose value is B_{i} with C_{i}.



For each i (1 \leq i \leq Q), find S_{i}: the sum of all elements in A just after the i-th operation.

Constraints

* All values in input are integers.
* 1 \leq N, Q, A_{i}, B_{i}, C_{i} \leq 10^{5}
* B_{i} \neq C_{i}

Input

Input is given from Standard Input in the following format:


N
A_{1} A_{2} \cdots A_{N}
Q
B_{1} C_{1}
B_{2} C_{2}
\vdots
B_{Q} C_{Q}


Output

Print Q integers S_{i} to Standard Output in the following format:


S_{1}
S_{2}
\vdots
S_{Q}


Note that S_{i} may not fit into a 32-bit integer.

Examples

Input

4
1 2 3 4
3
1 2
3 4
2 4


Output

11
12
16


Input

4
1 1 1 1
3
1 2
2 1
3 5


Output

8
4
4


Input

2
1 2
3
1 100
2 100
100 1000


Output

102
200
2000

Solution (in PYTHON):

Solution:
from sys import *

input = stdin.readline
maxn = 10 ** 5 + 5

Sum = [0] * maxn
Cnt = [0] * maxn

n = int(input())
arr = list(map(int, input().split()))
ans = 0
for x in arr:
	ans += x
	Sum[x] += x
	Cnt[x] += 1 
q = int(input())
result = []
for i in range(q):
	x, y = map(int, input().split())
	ans -= Sum[x]
	ans += y * Cnt[x]
	Sum[y] += y * Cnt[x]
	Cnt[y] += Cnt[x]
	Sum[x] = 0
	Cnt[x] = 0
	result.append(ans)
print('\n'.join(map(str, result)))