Problem: For given three points p1, p2, p, find the reflection point x of p onto p1p2.

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Constraints

* 1 ≤ q ≤ 1000
* -10000 ≤ xi, yi ≤ 10000
* p1 and p2 are not identical.

Input


xp1 yp1 xp2 yp2
q
xp0 yp0
xp1 yp1
...
xpq−1 ypq−1


In the first line, integer coordinates of p1 and p2 are given. Then, q queries are given for integer coordinates of p.

Output

For each query, print the coordinate of the reflection point x. The output values should be in a decimal fraction with an error less than 0.00000001.

Examples

Input

0 0 2 0
3
-1 1
0 1
1 1


Output

-1.0000000000 -1.0000000000
0.0000000000 -1.0000000000
1.0000000000 -1.0000000000


Input

0 0 3 4
3
2 5
1 4
0 3


Output

4.2400000000 3.3200000000
3.5600000000 2.0800000000
2.8800000000 0.8400000000

Solution (in CPP):

Solution:
#include<bits/stdc++.h>
using namespace std;
using FLOAT = double;
struct Point{
    FLOAT x, y;
    FLOAT operator * (const Point& point)const{return x * point.x + y * point.y;}
    FLOAT norm2()const{return x * x + y * y;}
    Point operator - (const Point& point)const{return {x - point.x, y - point.y};}
    Point operator + (const Point& point)const{return {x + point.x, y + point.y};}
    Point operator * (const FLOAT& k)const{return {k * x, k * y};}
};
Point operator * (const FLOAT& k, const Point& point){return point * k;}
struct Line{
    Point A, B;
    Point AB()const{return B - A;}
};
Point projection(const Point& point, const Line& line){
    return line.A + (point - line.A) * line.AB() / line.AB().norm2() * line.AB();
}
Point reflection(const Point& point, const Line& line){
    return 2 * projection(point, line) - point;
}
int main(){
    ios::sync_with_stdio(false);
    cin.tie(nullptr);
    cout.tie(nullptr);
    cout << fixed << setprecision(20);
    Line line;
    cin >> line.A.x >> line.A.y >> line.B.x >> line.B.y;
    int q;
    cin >> q;
    for(int i = 0; i < q; i += 1){
        Point point;
        cin >> point.x >> point.y;
        auto result = reflection(point, line);
        cout << result.x << " " << result.y << "\n";
    }
    return 0;
}