Problem: There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice. Each of these choices is represented by a string s_i. If s_i is `AB`, you must add 1 to A or B then subtract 1 from the other; if s_i is `AC`, you must add 1 to A or C then subtract 1 from the other; if s_i is `BC`, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

* 1 \leq N \leq 10^5
* 0 \leq A,B,C \leq 10^9
* N, A, B, C are integers.
* s_i is `AB`, `AC`, or `BC`.

Input

Input is given from Standard Input in the following format:


N A B C
s_1
s_2
:
s_N


Output

If it is possible to make N choices under the condition, print `Yes`; otherwise, print `No`.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (`A`, `B`, or `C`) to which you add 1 in the i-th choice.

Examples

Input

2 1 3 0
AB
AC


Output

Yes
A
C


Input

3 1 0 0
AB
BC
AB


Output

No


Input

1 0 9 0
AC


Output

No


Input

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB


Output

Yes
C
B
B
C
C
B
A
A

Solution (in JAVA):

Solution:
import java.util.Scanner;
public class Main {
	public static void main(String[] args)throws Exception{
		Scanner stdIn=new Scanner(System.in);
		int N=stdIn.nextInt();
		int A=stdIn.nextInt();
		int B=stdIn.nextInt();
		int C=stdIn.nextInt();
		String s[]=new String[N];
		char ans[]=new char[N];
		for(int i=0;i<N;i++){
			s[i]=stdIn.next();
		}
		for(int i=0;i<N;i++){
			if(s[i].equals("AB")){
				if(A>B){
					A--;B++;ans[i]='B';
				}
				else
				if(B>A){
					B--;A++;ans[i]='A';
				}
				else
				if(A==B){
					if(A==1&&C==0&&i!=N-1&&s[i+1].equals("BC")){
						A--;B++;ans[i]='B';
					}
					else{
						B--;A++;ans[i]='A';
					}
				}
			}
			if(s[i].equals("AC")){
				if(A>C){
					A--;C++;ans[i]='C';
				}
				else
				if(C>A){
					C--;A++;ans[i]='A';
				}
				else
				if(A==C){
					if(A==1&&B==0&&i!=N-1&&s[i+1].equals("BC")){
						A--;C++;ans[i]='C';
					}
					else{
						C--;A++;ans[i]='A';
					}
				}
			}
			if(s[i].equals("BC")){
				if(C>B){
					C--;B++;ans[i]='B';
				}
				else
				if(B>C){
					B--;C++;ans[i]='C';
				}
				else
				if(C==B){
					if(C==1&&A==0&&i!=N-1&&s[i+1].equals("AB")){
						C--;B++;ans[i]='B';
					}
					else{
						B--;C++;ans[i]='C';
					}
				}
			}
			if(A<0||B<0||C<0){
				System.out.println("No");
				System.exit(0);
			}
		}
		System.out.println("Yes");
		for(int i=0;i<N;i++){
			System.out.println(ans[i]);
		}
	}
}