Problem: There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice. Each of these choices is represented by a string s_i. If s_i is `AB`, you must add 1 to A or B then subtract 1 from the other; if s_i is `AC`, you must add 1 to A or C then subtract 1 from the other; if s_i is `BC`, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

* 1 \leq N \leq 10^5
* 0 \leq A,B,C \leq 10^9
* N, A, B, C are integers.
* s_i is `AB`, `AC`, or `BC`.

Input

Input is given from Standard Input in the following format:


N A B C
s_1
s_2
:
s_N


Output

If it is possible to make N choices under the condition, print `Yes`; otherwise, print `No`.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (`A`, `B`, or `C`) to which you add 1 in the i-th choice.

Examples

Input

2 1 3 0
AB
AC


Output

Yes
A
C


Input

3 1 0 0
AB
BC
AB


Output

No


Input

1 0 9 0
AC


Output

No


Input

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB


Output

Yes
C
B
B
C
C
B
A
A

Solution (in PYTHON3):

Solution:
N, A, B, C = map(int, input().split())
n = [A, B, C]
c = ["A", "B", "C"]
S = [input() for i in range(N)]
op = []

for i in range(N):
	if S[i] == "AB":
		op.append((0, 1))
	elif S[i] == "BC":
		op.append((1, 2))
	else:
		op.append((2, 0))

dec = []
for i in range(N):
	j1 = op[i][0]
	j2 = op[i][1]
	if n[j1] < n[j2]:
		dec.append(c[j1])
		n[j1] += 1
		n[j2] -= 1
	elif n[j2] < n[j1]:
		dec.append(c[j2])
		n[j2] += 1
		n[j1] -= 1
	elif i < N - 1:
		if j1 in op[i + 1]:
			if j1 == op[i + 1][0]:
				j3 = op[i + 1][1]
			else:
				j3 = op[i + 1][0]
			if n[j3] < n[j1]:
				dec.append(c[j1])
				n[j1] += 1
				n[j2] -= 1
			else:
				dec.append(c[j2])
				n[j2] += 1
				n[j1] -= 1
		else:
			if j2 == op[i + 1][0]:
				j3 = op[i + 1][1]
			else:
				j3 = op[i + 1][0]
			if n[j3] < n[j2]:
				dec.append(c[j2])
				n[j2] += 1
				n[j1] -= 1
			else:
				dec.append(c[j1])
				n[j1] += 1
				n[j2] -= 1
	else:
		dec.append(c[j1])
		n[j1] += 1
		n[j2] -= 1
	if n[0] < 0 or n[1] < 0 or n[2] < 0:
		print("No")
		exit()
print("Yes")
print("\n".join(dec))