Problem: Polycarp has guessed three positive integers a, b and c. He keeps these numbers in secret, but he writes down four numbers on a board in arbitrary order — their pairwise sums (three numbers) and sum of all three numbers (one number). So, there are four numbers on a board in random order: a+b, a+c, b+c and a+b+c.

You have to guess three numbers a, b and c using given numbers. Print three guessed integers in any order.

Pay attention that some given numbers a, b and c can be equal (it is also possible that a=b=c).

Input

The only line of the input contains four positive integers x_1, x_2, x_3, x_4 (2 ≤ x_i ≤ 10^9) — numbers written on a board in random order. It is guaranteed that the answer exists for the given number x_1, x_2, x_3, x_4.

Output

Print such positive integers a, b and c that four numbers written on a board are values a+b, a+c, b+c and a+b+c written in some order. Print a, b and c in any order. If there are several answers, you can print any. It is guaranteed that the answer exists.

Examples

Input


3 6 5 4


Output


2 1 3


Input


40 40 40 60


Output


20 20 20


Input


201 101 101 200


Output


1 100 100

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
int main() {
  long long int a, b, c, d, e = 0, f = 0, g = 0, h = 0, i = 0;
  scanf("%lld %lld %lld %lld", &a, &b, &c, &d);
  e = (a + b + c + d) / 3;
  f = e - a;
  g = e - b;
  h = e - c;
  i = e - d;
  if (f == 0)
    printf("%lld %lld %lld\n", g, h, i);
  else if (g == 0)
    printf("%lld %lld %lld\n", f, h, i);
  else if (h == 0)
    printf("%lld %lld %lld\n", f, g, i);
  else
    printf("%lld %lld %lld\n", f, g, h);
  return 0;
}