Problem: For given three points p1, p2, p, find the reflection point x of p onto p1p2.

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Constraints

* 1 ≤ q ≤ 1000
* -10000 ≤ xi, yi ≤ 10000
* p1 and p2 are not identical.

Input


xp1 yp1 xp2 yp2
q
xp0 yp0
xp1 yp1
...
xpq−1 ypq−1


In the first line, integer coordinates of p1 and p2 are given. Then, q queries are given for integer coordinates of p.

Output

For each query, print the coordinate of the reflection point x. The output values should be in a decimal fraction with an error less than 0.00000001.

Examples

Input

0 0 2 0
3
-1 1
0 1
1 1


Output

-1.0000000000 -1.0000000000
0.0000000000 -1.0000000000
1.0000000000 -1.0000000000


Input

0 0 3 4
3
2 5
1 4
0 3


Output

4.2400000000 3.3200000000
3.5600000000 2.0800000000
2.8800000000 0.8400000000

Solution (in PYTHON3):

Solution:
# Vector class
class Vector:
    def __init__(self, x, y):
        self.x = x
        self.y = y
    def is_orthogonal(self, v):
        if self.x * v.x + self.y * v.y == 0:
            return True
        else:
            return False
    def is_parallel(self, v):
        if self.x * v.y - self.y * v.x == 0:
            return True
        else:
            return False
    def dot_product(self, v):
        return self.x * v.x + self.y * v.y
    def quadrance(self):
        return self.x ** 2 + self. y ** 2
    def mul(self, k):
        return Vector(self.x * k, self.y *k)
    def __add__(self, v):
        return Vector(self.x + v.x, self.y + v.y)
    def __sub__(self, v):
        return Vector(self.x - v.x, self.y - v.y)
    def __str__(self):
        return "{0:.8f} {1:.8f}".format(self.x, self. y)
    def projection_on(self, v):
        return v.mul(self.dot_product(v) / v.quadrance())
    def rejection_from(self, v):
        return self - self.projection_on(v)

# Acceptance of input and Print the reflection point
import sys

file_input = sys.stdin

x_p1, y_p1, x_p2, y_p2 = map(int, file_input.readline().split())
p1_p2 = Vector(x_p2 - x_p1, y_p2 - y_p1)

q = int(file_input.readline())

for line in file_input:
    x_p, y_p = map(int, line.split())
    p1_p = Vector(x_p - x_p1, y_p - y_p1)
    r_v = p1_p.rejection_from(p1_p2)
    o_p = Vector(x_p, y_p)
    print(o_p - r_v.mul(2))