Problem: You are given three strings s, t and p consisting of lowercase Latin letters. You may perform any number (possibly, zero) operations on these strings.

During each operation you choose any character from p, erase it from p and insert it into string s (you may insert this character anywhere you want: in the beginning of s, in the end or between any two consecutive characters). 

For example, if p is aba, and s is de, then the following outcomes are possible (the character we erase from p and insert into s is highlighted):

  * aba → ba, de → ade; 
  * aba → ba, de → dae; 
  * aba → ba, de → dea; 
  * aba → aa, de → bde; 
  * aba → aa, de → dbe; 
  * aba → aa, de → deb; 
  * aba → ab, de → ade; 
  * aba → ab, de → dae; 
  * aba → ab, de → dea; 



Your goal is to perform several (maybe zero) operations so that s becomes equal to t. Please determine whether it is possible.

Note that you have to answer q independent queries.

Input

The first line contains one integer q (1 ≤ q ≤ 100) — the number of queries. Each query is represented by three consecutive lines.

The first line of each query contains the string s (1 ≤ |s| ≤ 100) consisting of lowercase Latin letters.

The second line of each query contains the string t (1 ≤ |t| ≤ 100) consisting of lowercase Latin letters.

The third line of each query contains the string p (1 ≤ |p| ≤ 100) consisting of lowercase Latin letters.

Output

For each query print YES if it is possible to make s equal to t, and NO otherwise.

You may print every letter in any case you want (so, for example, the strings yEs, yes, Yes and YES will all be recognized as positive answer).

Example

Input


4
ab
acxb
cax
a
aaaa
aaabbcc
a
aaaa
aabbcc
ab
baaa
aaaaa


Output


YES
YES
NO
NO

Note

In the first test case there is the following sequence of operation: 

  1. s =  ab, t =  acxb, p =  cax; 
  2. s =  acb, t =  acxb, p =  ax; 
  3. s =  acxb, t =  acxb, p =  a. 



In the second test case there is the following sequence of operation: 

  1. s =  a, t =  aaaa, p =  aaabbcc; 
  2. s =  aa, t =  aaaa, p =  aabbcc; 
  3. s =  aaa, t =  aaaa, p =  abbcc; 
  4. s =  aaaa, t =  aaaa, p =  bbcc. 

Solution (in JAVA):

Solution:
/*
 
    /$$$$$  /$$$$$$  /$$    /$$  /$$$$$$                                                                  
   |__  $$ /$$__  $$ |$$    |$$ /$$__  $$                                                                 
          | $$| $$  \ $$|    $$|$$| $$  \ $$                                                                 
          | $$| $$$$$$$$|  $$ / $$/| $$$$$$$$                                                                 
/ $$  | $$| $$__  $$ \  $$ $$/ | $$__  $$                                                                 
| $$  | $$| $$  | $$  \  $$$/  | $$  | $$                                                                 
|  $$$$$$/| $$  | $$   \  $/   | $$  | $$                                                                 
 \______/ |__/  |__/    \_/    |__/  |__/    
 
/$$$$$$$  /$$$$$$$   /$$$$$$   /$$$$$$  /$$$$$$$   /$$$$$$  /$$      /$$ /$$      /$$ /$$$$$$$$ /$$$$$$$ 
| $$__  $$| $$__  $$ /$$__  $$ /$$__  $$| $$__  $$ /$$__  $$| $$$    /$$$| $$$    /$$$| $$_____/| $$__  $$
| $$  \ $$| $$  \ $$| $$  \ $$| $$  \__/| $$  \ $$| $$  \ $$| $$$$  /$$$$| $$$$  /$$$$| $$      | $$  \ $$
| $$$$$$$/| $$$$$$$/| $$  | $$| $$ /$$$$| $$$$$$$/| $$$$$$$$| $$ $$/$$ $$| $$ $$/$$ $$| $$$$$   | $$$$$$$/
| $$____/ | $$__  $$| $$  | $$| $$|_  $$| $$__  $$| $$__  $$| $$  $$$| $$| $$  $$$| $$| $$__/   | $$__  $$
| $$      | $$  \ $$| $$  | $$| $$  \ $$| $$  \ $$| $$  | $$| $$\  $ | $$| $$\  $ | $$| $$      | $$  \ $$
| $$      | $$  | $$|  $$$$$$/|  $$$$$$/| $$  | $$| $$  | $$| $$ \/  | $$| $$ \/  | $$| $$$$$$$$| $$  | $$
|__/      |__/  |__/ \______/  \______/ |__/  |__/|__/  |__/|__/     |__/|__/     |__/|________/|__/  |__/
                                                                                                           
                                                                                                                                                                                                                 
                                                                                                                                                                                                                
 
*/
import java.util.*;
import java.lang.*;
import java.io.*;

/* Name of the class has to be "Main" only if the class is public. */
 public class codeforces
{
    static void shuffle( int arr[])
    {
        int n = arr.length;
        Random r = new Random();
         
       for (int i = n-1; i > 0; i--) {
           int j = r.nextInt(i+1);
             
            int temp = arr[i];
            arr[i] = arr[j];
            arr[j] = temp;
        }
    }
    static void shuffle( int arr[][])
    {
        int n = arr.length;
        Random r = new Random();
         
       for (int i = n-1; i > 0; i--) {
           int j = r.nextInt(i+1);
             
            int[] temp = arr[i];
            arr[i] = arr[j];
            arr[j] = temp;
        }
    }
    
    static class FastReader 
    { 
        BufferedReader br; 
        StringTokenizer st; 
  
        public FastReader() 
        { 
            br = new BufferedReader(new
                     InputStreamReader(System.in)); 
        } 
  
        String next() 
        { 
            while (st == null || !st.hasMoreElements()) 
            { 
                try
                { 
                    st = new StringTokenizer(br.readLine()); 
                } 
                catch (IOException  e) 
                { 
                    e.printStackTrace(); 
                } 
            } 
            return st.nextToken(); 
        }
        int[][] tdiarr(int m , int n){
            int[][] a = new int[m][n];
            for(int i=0;i<m;i++){
                for(int j=0;j<n;j++){
                    a[i][j]=Integer.parseInt(next());
                }
            }
            return a;
        } 
        int[] niarr(int n)
        {
            int[] a = new int[n];
            for(int i=0;i<n;i++)a[i]=Integer.parseInt(next());
            return a;
        }
        long[] nlarr(int n)
        {
            long[] a = new long[n];
            for(int i=0;i<n;i++)a[i]=Long.parseLong(next());
            return a;
        }
        char[] ncarr(){
            return next().trim().toCharArray();
            
            
        }
        
  
        int ni() 
        { 
            return Integer.parseInt(next()); 
        } 
  
        long nl() 
        { 
            return Long.parseLong(next()); 
        } 
  
        double nd() 
        { 
            return Double.parseDouble(next()); 
        } 
  
        String nstr() 
        { 
            String str = ""; 
            try
            { 
                str = br.readLine(); 
            } 
            catch (IOException e) 
            { 
                e.printStackTrace(); 
            } 
            return str; 
        } 
    }
    
    static void SegmentTree(int arr[], int n)
    {
        // Allocate memory for segment tree
        //Height of segment tree
        int x = (int) (Math.ceil(Math.log(n) / Math.log(2)));
 
        //Maximum size of segment tree
        int max_size = 2 * (int) Math.pow(2, x) - 1;
 
         int[] st = new int[max_size]; // Memory allocation
 
        constructSTUtil(arr, 0, n - 1, 0);
    }
    static int constructSTUtil(int arr[], int ss, int se, int si)
    {
        // If there is one element in array, store it in current node of
        // segment tree and return
        if (ss == se) {
            st[si] = arr[ss];
            return arr[ss];
        }
 
        // If there are more than one elements, then recur for left and
        // right subtrees and store the sum of values in this node
        int mid = getMid(ss, se);
        st[si] = Math.min(constructSTUtil(arr, ss, mid, si * 2 + 1) ,
                 constructSTUtil(arr, mid + 1, se, si * 2 + 2));
        return st[si];
    }
    static int getMid(int s, int e) {
        return s + (e - s) / 2;
    }
    static int getSum(int n, int qs, int qe)
    {
        // Check for erroneous input values
        if (qs < 0 || qe > n - 1 || qs > qe) {
           // System.out.println("Invalid Input");
            return -1;
        }
        return getSumUtil(0, n - 1, qs, qe, 0);
    }
    static int getSumUtil(int ss, int se, int qs, int qe, int si)
    {
        // If segment of this node is a part of given range, then return
        // the sum of the segment
        if (qs <= ss && qe >= se)
            return st[si];
 
        // If segment of this node is outside the given range
        if (se < qs || ss > qe)
            return Integer.MAX_VALUE;
 
        // If a part of this segment overlaps with the given range
        int mid = getMid(ss, se);
        return Math.min(getSumUtil(ss, mid, qs, qe, 2 * si + 1) ,
                getSumUtil(mid + 1, se, qs, qe, 2 * si + 2));
    }
    static void updateValue(int arr[], int n, int i, int new_val)
    {
        // Check for erroneous input index
        if (i < 0 || i > n - 1) {
//            System.out.println("Invalid Input");
            return;
        }
 
        // Get the difference between new value and old value
        int diff = new_val - arr[i];
 
        // Update the value in array
        arr[i] = new_val;
 
        // Update the values of nodes in segment tree
        updateValueUtil(0, n - 1, i, diff, 0);
    }
    static void updateValueUtil(int ss, int se, int i, int diff, int si)
    {
        // Base Case: If the input index lies outside the range of
        // this segment
        if (i < ss || i > se)
            return;
 
        // If the input index is in range of this node, then update the
        // value of the node and its children
        st[si] = st[si] + diff;
        if (se != ss) {
            int mid = getMid(ss, se);
            updateValueUtil(ss, mid, i, diff, 2 * si + 1);
            updateValueUtil(mid + 1, se, i, diff, 2 * si + 2);
        }
    }
    static boolean checkbound(int x , int y , int m , int n){
        if(x<0 || x>=m || y<0 || y>=n)return false;
        return true;
    }
    static void printarr(int[][] a){
        int m = a.length , n = a[0].length;
        for(int i=0;i<m;i++){
            for(int j=0;j<n;j++){
                System.out.print(a[i][j]+" ");
            }
            System.out.println();
        }
    }
    static void printarr(int[] a){
        int n = a.length;
            for(int j=0;j<n;j++){
                System.out.print(a[j]+" ");
            }
            System.out.println();

        
    }

    static void revarr(int[] a ){
        int i=0,j=a.length-1;
        while(i<j){
            int tem = a[i];
            a[i]=a[j];
            a[j]=tem;
            i++;j--;
        }
        //return a;
    }
    
    
    static int[] st;
    static FastReader br=new FastReader();//(new InputStreamReader(System.in));
/*

*/
///////////////////////////////////////////////////////////


 
 

    public static void main (String[] args) throws java.lang.Exception
    {
        // your code goes here
        int t=1;
        br=new FastReader();
                 t=br.ni();//Integer.parseInt(br.readLine().trim());
        StringBuilder sb=new StringBuilder();
          
    in1 :   while(t-->0)
        {
              //
           // printarr(g);
                //
            //
            sb.append(solve()+"\n");
        
            //    solve();
        }
          
            //          System.out.println("OUTPUT:::");
    
        System.out.println(sb);
    }
    static String solve(){
        char[] s = br.ncarr();
        char[] t = br.ncarr();
        char[] p = br.ncarr();
        int[] fre = new int[26];
        for(char c : p)fre[c-'a']++;
//            int i = 0 , j = 0;
            int i=0;
        for(int j=0;j<t.length ;j++){
            if(i<s.length && s[i] == t[j]){
                i++;
                continue;

            }
            else {
                int y = t[j]-'a';
                if(fre[y]==0){
                    return  "NO";
                }
                fre[y]--;

            }

        }
        if(i!=s.length)return "NO";
        return "YES";


 
    }




    }    
    /*
    1 1 1 3 5 5 10
   10 5 5 3 1 1 1
    1 1 1 1 1  
      */