Problem: We have a tree with N vertices numbered 1 to N. The i-th edge in the tree connects Vertex u_i and Vertex v_i, and its length is w_i. Your objective is to paint each vertex in the tree white or black (it is fine to paint all vertices the same color) so that the following condition is satisfied:

* For any two vertices painted in the same color, the distance between them is an even number.



Find a coloring of the vertices that satisfies the condition and print it. It can be proved that at least one such coloring exists under the constraints of this problem.

Constraints

* All values in input are integers.
* 1 \leq N \leq 10^5
* 1 \leq u_i < v_i \leq N
* 1 \leq w_i \leq 10^9

Input

Input is given from Standard Input in the following format:


N
u_1 v_1 w_1
u_2 v_2 w_2
.
.
.
u_{N - 1} v_{N - 1} w_{N - 1}


Output

Print a coloring of the vertices that satisfies the condition, in N lines. The i-th line should contain `0` if Vertex i is painted white and `1` if it is painted black.

If there are multiple colorings that satisfy the condition, any of them will be accepted.

Examples

Input

3
1 2 2
2 3 1


Output

0
0
1


Input

5
2 5 2
2 3 10
1 3 8
3 4 2


Output

1
0
1
0
1

Solution (in JAVA):

Solution:
import java.util.*;
import java.util.Map.*;

public class Main {
    private static int[] colors;
    private static Map<Integer, Integer>[] friendship;
    
    public static void main(String[] args) throws Exception {
        // Your code here!
        Scanner sc = new Scanner(System.in);
        int n = sc.nextInt();
        int m = n - 1;
        
        colors = new int[n];
        Arrays.fill(colors, -1);
        
        friendship = new HashMap[n];
        Arrays.setAll(friendship, i -> new HashMap<Integer, Integer>());
        
        while (m-- > 0) {
            int me = sc.nextInt() - 1;
            int you = sc.nextInt() - 1;
            int length = sc.nextInt();
            friendship[me].put(you, length);
            friendship[you].put(me, length);
        }
        
        dfs(0, 0);
        
        for (int c : colors) {
            System.out.println(c);
        }
    }
    
    public static void dfs(int p, int length) {
        boolean alreadyKnown = colors[p] != -1;
        if (alreadyKnown) return;
        
        if (length % 2 == 0) {
            colors[p] = 0;
        } else {
            colors[p] = 1;
        }
        
        for (Entry<Integer, Integer> entry : friendship[p].entrySet()) {
            int friend = entry.getKey();
            int length2 = entry.getValue();
            dfs(friend, length + length2);
        }
    }
}