Problem: You have array of n numbers a_{1}, a_{2}, …, a_{n}. 

Rearrange these numbers to satisfy |a_{1} - a_{2}| ≤ |a_{2} - a_{3}| ≤ … ≤ |a_{n-1} - a_{n}|, where |x| denotes absolute value of x. It's always possible to find such rearrangement.

Note that all numbers in a are not necessarily different. In other words, some numbers of a may be same.

You have to answer independent t test cases.

Input

The first line contains a single integer t (1 ≤ t ≤ 10^{4}) — the number of test cases.

The first line of each test case contains single integer n (3 ≤ n ≤ 10^{5}) — the length of array a. It is guaranteed that the sum of values of n over all test cases in the input does not exceed 10^{5}.

The second line of each test case contains n integers a_{1}, a_{2}, …, a_{n} (-10^{9} ≤ a_{i} ≤ 10^{9}).

Output

For each test case, print the rearranged version of array a which satisfies given condition. If there are multiple valid rearrangements, print any of them.

Example

Input


2
6
5 -2 4 8 6 5
4
8 1 4 2


Output


5 5 4 6 8 -2
1 2 4 8

Note

In the first test case, after given rearrangement, |a_{1} - a_{2}| = 0 ≤ |a_{2} - a_{3}| = 1 ≤ |a_{3} - a_{4}| = 2 ≤ |a_{4} - a_{5}| = 2 ≤ |a_{5} - a_{6}| = 10. There are other possible answers like "5 4 5 6 -2 8".

In the second test case, after given rearrangement, |a_{1} - a_{2}| = 1 ≤ |a_{2} - a_{3}| = 2 ≤ |a_{3} - a_{4}| = 4. There are other possible answers like "2 4 8 1".

Solution (in PYTHON3):

Solution:
for _ in range(int(input())):
    num = int(input())
    arr = [int(x) for x in input().split()]
    arr.sort()
    mid = num//2
    if num%2==0:
        ans =[]
        i = mid-1
        j = mid+1
        ans.append(arr[mid])
        while(1):
            ans.append(arr[i])
            ans.append(arr[j])
            i-=1
            j+=1
            if i==0 and j==num:
                ans.append(arr[i])
                break
        print(*ans)
    else:
        ans = []
        i = mid - 1
        j = mid + 1
        ans.append(arr[mid])
        while (1):
            ans.append(arr[i])
            ans.append(arr[j])
            i -= 1
            j += 1
            if i == 0 and j == num-1:
                ans.append(arr[i])
                ans.append(arr[j])
                break
            elif i<0 and j>num-1:
                break
        print(*ans)