Problem: There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice. Each of these choices is represented by a string s_i. If s_i is `AB`, you must add 1 to A or B then subtract 1 from the other; if s_i is `AC`, you must add 1 to A or C then subtract 1 from the other; if s_i is `BC`, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

* 1 \leq N \leq 10^5
* 0 \leq A,B,C \leq 10^9
* N, A, B, C are integers.
* s_i is `AB`, `AC`, or `BC`.

Input

Input is given from Standard Input in the following format:


N A B C
s_1
s_2
:
s_N


Output

If it is possible to make N choices under the condition, print `Yes`; otherwise, print `No`.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (`A`, `B`, or `C`) to which you add 1 in the i-th choice.

Examples

Input

2 1 3 0
AB
AC


Output

Yes
A
C


Input

3 1 0 0
AB
BC
AB


Output

No


Input

1 0 9 0
AC


Output

No


Input

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB


Output

Yes
C
B
B
C
C
B
A
A

Solution (in PYTHON3):

Solution:

n,a,b,c = map(int,input().split())

s = []

for i in range(n):
    tmp_s = input()
    s.append(tmp_s)

ans = []

for i,val in enumerate(s):
    if val == 'AB':
        if a == b == 0:
            print('No')
            exit(0)
        elif a < b or (a == b and i != n-1 and 'A' in s[i+1]):
            ans.append('A')
            a += 1
            b -= 1
        else:
            ans.append('B')
            a -= 1
            b += 1

    elif val == 'BC':
        if b == c == 0:
            print('No')
            exit(0)
        elif b < c or (b == c and i != n-1 and 'B' in s[i+1]):
            ans.append('B')
            b += 1
            c -= 1
        else:
            ans.append('C')
            b -= 1
            c += 1
    else:
        if c == a == 0:
            print('No')
            exit(0)
        elif c < a or (c == a and i != n-1 and 'C' in s[i+1]):
            ans.append('C')
            c += 1
            a -= 1
        else:
            ans.append('A')
            c -= 1
            a += 1
        
        

print('Yes')
print(*ans,sep='\n')