Problem: Polycarp has guessed three positive integers a, b and c. He keeps these numbers in secret, but he writes down four numbers on a board in arbitrary order — their pairwise sums (three numbers) and sum of all three numbers (one number). So, there are four numbers on a board in random order: a+b, a+c, b+c and a+b+c.

You have to guess three numbers a, b and c using given numbers. Print three guessed integers in any order.

Pay attention that some given numbers a, b and c can be equal (it is also possible that a=b=c).

Input

The only line of the input contains four positive integers x_1, x_2, x_3, x_4 (2 ≤ x_i ≤ 10^9) — numbers written on a board in random order. It is guaranteed that the answer exists for the given number x_1, x_2, x_3, x_4.

Output

Print such positive integers a, b and c that four numbers written on a board are values a+b, a+c, b+c and a+b+c written in some order. Print a, b and c in any order. If there are several answers, you can print any. It is guaranteed that the answer exists.

Examples

Input


3 6 5 4


Output


2 1 3


Input


40 40 40 60


Output


20 20 20


Input


201 101 101 200


Output


1 100 100

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int main() {
  int a, b, c, t;
  int n[4];
  for (int i = 0; i < 4; i++) {
    cin >> n[i];
  }
  for (int i = 0; i < 4; i++) {
    for (int j = 0; j < 3 - i; j++) {
      if (n[j] > n[j + 1]) {
        t = n[j];
        n[j] = n[j + 1];
        n[j + 1] = t;
      }
    }
  }
  a = n[0] - n[2];
  a = (n[1] + a) / 2;
  c = (n[1] - a);
  b = (n[0] - a);
  cout << a << ' ' << b << ' ' << c;
  return 0;
}