Problem: Stack is a container of elements that are inserted and deleted according to LIFO (Last In First Out).

For $n$ stack $S_i$ ($i = 0, 1, ..., n-1$), perform a sequence of the following operations.

* push($t$, $x$): Insert an integer $x$ to $S_t$.
* top($t$): Report the value which should be deleted next from $S_t$. If $S_t$ is empty, do nothing.
* pop($t$): Delete an element from $S_t$. If $S_t$ is empty, do nothing.



In the initial state, all stacks are empty.

Constraints

* $1 \leq n \leq 1,000$
* $1 \leq q \leq 200,000$
* $-1,000,000,000 \leq x \leq 1,000,000,000$

Input

The input is given in the following format.


$n \; q$
$query_1$
$query_2$
:
$query_q$


Each query $query_i$ is given by


0 $t$ $x$


or


1 $t$


or


2 $t$


where the first digits 0, 1 and 2 represent push, top and pop operations respectively.

Output

For each top operation, print an integer in a line.

Example

Input

3 9
0 0 1
0 0 2
0 0 3
0 2 4
0 2 5
1 0
1 2
2 0
1 0


Output

3
5
2

Solution (in CPP):

Solution:
#include<bits/stdc++.h>
using namespace std;
stack<int> s[1010];
int main()
{
	int n, m;
	scanf("%d%d",&n,&m);
	while(m--)
	{
		int x;
		scanf("%d",&x);
		if(x == 0)
		{
			int y, z;
			scanf("%d%d",&y,&z);
			s[y].push(z);
		}
		else if(x == 1)
		{
			int y;
			scanf("%d",&y);
			if(s[y].size())printf("%d\n",s[y].top());
			//else printf("\n");
		}
		else if(x == 2)
		{
			int y;
			scanf("%d",&y);
			if(s[y].size())s[y].pop();
		}
	}
	return 0;
}