Problem: You have array of n numbers a_{1}, a_{2}, …, a_{n}. 

Rearrange these numbers to satisfy |a_{1} - a_{2}| ≤ |a_{2} - a_{3}| ≤ … ≤ |a_{n-1} - a_{n}|, where |x| denotes absolute value of x. It's always possible to find such rearrangement.

Note that all numbers in a are not necessarily different. In other words, some numbers of a may be same.

You have to answer independent t test cases.

Input

The first line contains a single integer t (1 ≤ t ≤ 10^{4}) — the number of test cases.

The first line of each test case contains single integer n (3 ≤ n ≤ 10^{5}) — the length of array a. It is guaranteed that the sum of values of n over all test cases in the input does not exceed 10^{5}.

The second line of each test case contains n integers a_{1}, a_{2}, …, a_{n} (-10^{9} ≤ a_{i} ≤ 10^{9}).

Output

For each test case, print the rearranged version of array a which satisfies given condition. If there are multiple valid rearrangements, print any of them.

Example

Input


2
6
5 -2 4 8 6 5
4
8 1 4 2


Output


5 5 4 6 8 -2
1 2 4 8

Note

In the first test case, after given rearrangement, |a_{1} - a_{2}| = 0 ≤ |a_{2} - a_{3}| = 1 ≤ |a_{3} - a_{4}| = 2 ≤ |a_{4} - a_{5}| = 2 ≤ |a_{5} - a_{6}| = 10. There are other possible answers like "5 4 5 6 -2 8".

In the second test case, after given rearrangement, |a_{1} - a_{2}| = 1 ≤ |a_{2} - a_{3}| = 2 ≤ |a_{3} - a_{4}| = 4. There are other possible answers like "2 4 8 1".

Solution (in PYTHON3):

Solution:
import math,sys
from collections import Counter
def li(): return list(map(int,sys.stdin.readline().split()))
def ls(): return list(map(int,list(input())))
def la(): return list(input())
def i():  return int(input())
def isPrime(n):
    i= 2
    if n == 1:
        return False
    while i <= int(math.sqrt(n)):
        if n%i == 0:
            return False
        i = i + 1
    return True
def gcd(a,b):
    if b == 0:
        return a
    return gcd(b,a%b)
t = i()
for _ in range(t):
    n = int(input())
    a = li()
    a.sort()
    b = []
    i = 0
    while i>=0 and i< n//2:
        b.append(a[i])
        b.append(a[n-i-1])
        i = i+1
    if n%2 != 0:
        b.append(a[i])
    b.reverse()
    print(*b)