Problem: Stack is a container of elements that are inserted and deleted according to LIFO (Last In First Out).

For $n$ stack $S_i$ ($i = 0, 1, ..., n-1$), perform a sequence of the following operations.

* push($t$, $x$): Insert an integer $x$ to $S_t$.
* top($t$): Report the value which should be deleted next from $S_t$. If $S_t$ is empty, do nothing.
* pop($t$): Delete an element from $S_t$. If $S_t$ is empty, do nothing.



In the initial state, all stacks are empty.

Constraints

* $1 \leq n \leq 1,000$
* $1 \leq q \leq 200,000$
* $-1,000,000,000 \leq x \leq 1,000,000,000$

Input

The input is given in the following format.


$n \; q$
$query_1$
$query_2$
:
$query_q$


Each query $query_i$ is given by


0 $t$ $x$


or


1 $t$


or


2 $t$


where the first digits 0, 1 and 2 represent push, top and pop operations respectively.

Output

For each top operation, print an integer in a line.

Example

Input

3 9
0 0 1
0 0 2
0 0 3
0 2 4
0 2 5
1 0
1 2
2 0
1 0


Output

3
5
2

Solution (in PYTHON3):

Solution:
from sys import stdin,stdout
from collections import defaultdict,deque

n, q = map(int,stdin.readline().split())
queries = stdin.readlines()
A = defaultdict(deque)
ans = []

#count = 0
for query in queries:
    #print(count)
    #count += 1
    query = query.split()
    if query[0] == '0':
        A[int(query[1])].append(query[2])
    elif query[0] == '1':
        index = int(query[1])
        if A[index]:
            ans.append(A[index][-1])
    else:
        index = int(query[1])
        if A[index]:
            A[index].pop()

print('\n'.join(ans))