Problem: You have a sequence A composed of N positive integers: A_{1}, A_{2}, \cdots, A_{N}.

You will now successively do the following Q operations:

* In the i-th operation, you replace every element whose value is B_{i} with C_{i}.



For each i (1 \leq i \leq Q), find S_{i}: the sum of all elements in A just after the i-th operation.

Constraints

* All values in input are integers.
* 1 \leq N, Q, A_{i}, B_{i}, C_{i} \leq 10^{5}
* B_{i} \neq C_{i}

Input

Input is given from Standard Input in the following format:


N
A_{1} A_{2} \cdots A_{N}
Q
B_{1} C_{1}
B_{2} C_{2}
\vdots
B_{Q} C_{Q}


Output

Print Q integers S_{i} to Standard Output in the following format:


S_{1}
S_{2}
\vdots
S_{Q}


Note that S_{i} may not fit into a 32-bit integer.

Examples

Input

4
1 2 3 4
3
1 2
3 4
2 4


Output

11
12
16


Input

4
1 1 1 1
3
1 2
2 1
3 5


Output

8
4
4


Input

2
1 2
3
1 100
2 100
100 1000


Output

102
200
2000

Solution (in JAVA):

Solution:
import java.util.*;
public class Main {
	public static void main(String[] args){
		Scanner sc = new Scanner(System.in);
        int N = sc.nextInt();
        int[] a=new int[N];
        int[] count=new int[(int)Math.pow(10,5)+1];
        long res = 0;

        for(int i=0; i<N; i++){
            a[i]=sc.nextInt();
            count[a[i]]++;
            res = res + (long)a[i];
        }

        int Q = sc.nextInt();
        
        for(int i=0; i<Q; i++){
            int b=sc.nextInt();
            int c=sc.nextInt();
            res = res + (c-b)*count[b];
            count[c] += count[b];
            count[b] = 0;
            System.out.println(res);
        }

        
        
        
        
        
        
        
        
        
        }
    }