Problem: We have a tree with N vertices numbered 1 to N. The i-th edge in the tree connects Vertex u_i and Vertex v_i, and its length is w_i. Your objective is to paint each vertex in the tree white or black (it is fine to paint all vertices the same color) so that the following condition is satisfied:

* For any two vertices painted in the same color, the distance between them is an even number.



Find a coloring of the vertices that satisfies the condition and print it. It can be proved that at least one such coloring exists under the constraints of this problem.

Constraints

* All values in input are integers.
* 1 \leq N \leq 10^5
* 1 \leq u_i < v_i \leq N
* 1 \leq w_i \leq 10^9

Input

Input is given from Standard Input in the following format:


N
u_1 v_1 w_1
u_2 v_2 w_2
.
.
.
u_{N - 1} v_{N - 1} w_{N - 1}


Output

Print a coloring of the vertices that satisfies the condition, in N lines. The i-th line should contain `0` if Vertex i is painted white and `1` if it is painted black.

If there are multiple colorings that satisfy the condition, any of them will be accepted.

Examples

Input

3
1 2 2
2 3 1


Output

0
0
1


Input

5
2 5 2
2 3 10
1 3 8
3 4 2


Output

1
0
1
0
1

Solution (in PYTHON3):

Solution:
import sys
sys.setrecursionlimit(1000000)

n = int(input())
tree = [[] for _ in range(n)]
color = [0]*n
for _ in range(n-1):
  a,b,c = map(int,input().split())
  a -= 1
  b -= 1
  tree[a].append((b,c))
  tree[b].append((a,c))
  
  
def dfs(i,before,cost):
  if cost == 1:
    color[i] = 1
  for j in tree[i]:
    if j[0] == before:
      continue
    dfs(j[0],i,(cost + j[1])%2 )
    
dfs(0,-1,0)

for i in range(n):
  print(color[i])