Problem: It's a very unfortunate day for Volodya today. He got bad mark in algebra and was therefore forced to do some work in the kitchen, namely to cook borscht (traditional Russian soup). This should also improve his algebra skills.

According to the borscht recipe it consists of n ingredients that have to be mixed in proportion <image> litres (thus, there should be a1 ·x, ..., an ·x litres of corresponding ingredients mixed for some non-negative x). In the kitchen Volodya found out that he has b1, ..., bn litres of these ingredients at his disposal correspondingly. In order to correct his algebra mistakes he ought to cook as much soup as possible in a V litres volume pan (which means the amount of soup cooked can be between 0 and V litres). What is the volume of borscht Volodya will cook ultimately?

Input

The first line of the input contains two space-separated integers n and V (1 ≤ n ≤ 20, 1 ≤ V ≤ 10000). The next line contains n space-separated integers ai (1 ≤ ai ≤ 100). Finally, the last line contains n space-separated integers bi (0 ≤ bi ≤ 100).

Output

Your program should output just one real number — the volume of soup that Volodya will cook. Your answer must have a relative or absolute error less than 10 - 4.

Examples

Input

1 100
1
40


Output

40.0


Input

2 100
1 1
25 30


Output

50.0


Input

2 100
1 1
60 60


Output

100.0

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.*;
import java.math.*;

public class A implements Runnable {
	public static void main(String[] args) {
		new A().run();
	}

	class FastScanner {
		BufferedReader br;
		StringTokenizer st;
		boolean eof;
		String buf;

		public FastScanner(String fileName) throws FileNotFoundException {
			br = new BufferedReader(new FileReader(fileName));
			nextToken();
		}

		public FastScanner(InputStream stream) {
			br = new BufferedReader(new InputStreamReader(stream));
			nextToken();
		}

		String nextToken() {
			while (st == null || !st.hasMoreTokens()) {
				try {
					st = new StringTokenizer(br.readLine());
				} catch (Exception e) {
					eof = true;
					break;
				}
			}
			String ret = buf;
			buf = eof ? "-1" : st.nextToken();
			return ret;
		}

		int nextInt() {
			return Integer.parseInt(nextToken());
		}

		long nextLong() {
			return Long.parseLong(nextToken());
		}

		double nextDouble() {
			return Double.parseDouble(nextToken());
		}

		BigInteger nextBigInteger() {
			return new BigInteger(nextToken());
		}

		void close() {
			try {
				br.close();
			} catch (Exception e) {

			}
		}

		boolean isEOF() {
			return eof;
		}
	}

	FastScanner sc;
	PrintWriter out;

	public void run() {
		Locale.setDefault(Locale.US);
		try {
			sc = new FastScanner(System.in);
			out = new PrintWriter(System.out);
			solve();
			sc.close();
			out.close();
		} catch (Throwable e) {
			e.printStackTrace();
			System.exit(1);
		}
	}

	int nextInt() {
		return sc.nextInt();
	}

	String nextToken() {
		return sc.nextToken();
	}

	long nextLong() {
		return sc.nextLong();
	}

	double nextDouble() {
		return sc.nextDouble();
	}

	BigInteger nextBigInteger() {
		return sc.nextBigInteger();
	}

	void solve() {
		int n = nextInt();
		int v = nextInt();
		int[] a = new int[n];
		for (int i = 0; i < a.length; i++) {
			a[i] = nextInt();
		}
		int[] b = new int[n];
		for (int i = 0; i < b.length; i++) {
			b[i] = nextInt();
		}
		double can = Double.POSITIVE_INFINITY;
		for (int i = 0; i < n; i++) {
			can = Math.min(can, 1. * b[i] / a[i]);
		}
		int sum = 0;
		for (int i = 0; i < n; i++) {
			sum += a[i];
		}
		out.println(Math.min(v, sum * can));
	}
}