Problem: There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice. Each of these choices is represented by a string s_i. If s_i is `AB`, you must add 1 to A or B then subtract 1 from the other; if s_i is `AC`, you must add 1 to A or C then subtract 1 from the other; if s_i is `BC`, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

* 1 \leq N \leq 10^5
* 0 \leq A,B,C \leq 10^9
* N, A, B, C are integers.
* s_i is `AB`, `AC`, or `BC`.

Input

Input is given from Standard Input in the following format:


N A B C
s_1
s_2
:
s_N


Output

If it is possible to make N choices under the condition, print `Yes`; otherwise, print `No`.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (`A`, `B`, or `C`) to which you add 1 in the i-th choice.

Examples

Input

2 1 3 0
AB
AC


Output

Yes
A
C


Input

3 1 0 0
AB
BC
AB


Output

No


Input

1 0 9 0
AC


Output

No


Input

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB


Output

Yes
C
B
B
C
C
B
A
A

Solution (in CPP):

Solution:
#include<bits/stdc++.h>
using namespace std;
string s[100010];
char ans[100010];
int main()
{
	int n,a,b,c;
	cin>>n>>a>>b>>c;
	for(int i=1;i<=n;i++)
	cin>>s[i];
	for(int i=1;i<=n;i++)
	{
		if(s[i]=="AB"){
			if(a==0&&b==0){
				printf("No\n");
				return 0;
			}
			if(a>b)a--,b++,ans[i]='B';
			else if(a<b)a++,b--,ans[i]='A';
			else{
				if(s[i+1]=="BC")a--,b++,ans[i]='B';
				else a++,b--,ans[i]='A';
			}
		}
		if(s[i]=="BC"){
			if(c==0&&b==0){
				printf("No\n");
				return 0;
			}
			if(c>b)c--,b++,ans[i]='B';
			else if(c<b)c++,b--,ans[i]='C';
			else{
				if(s[i+1]=="AB")c--,b++,ans[i]='B';
				else c++,b--,ans[i]='C';
			}
		}
		if(s[i]=="AC"){
			if(a==0&&c==0){
				printf("No\n");
				return 0;
			}
			if(a>c)a--,c++,ans[i]='C';
			else if(a<c)a++,c--,ans[i]='A';
			else{
				if(s[i+1]=="BC")a--,c++,ans[i]='C';
				else a++,c--,ans[i]='A';
			}
		}
	}
	printf("Yes\n");
	for(int i=1;i<=n;i++)
	printf("%c\n",ans[i]);
}