Problem: Polycarp has guessed three positive integers a, b and c. He keeps these numbers in secret, but he writes down four numbers on a board in arbitrary order — their pairwise sums (three numbers) and sum of all three numbers (one number). So, there are four numbers on a board in random order: a+b, a+c, b+c and a+b+c.

You have to guess three numbers a, b and c using given numbers. Print three guessed integers in any order.

Pay attention that some given numbers a, b and c can be equal (it is also possible that a=b=c).

Input

The only line of the input contains four positive integers x_1, x_2, x_3, x_4 (2 ≤ x_i ≤ 10^9) — numbers written on a board in random order. It is guaranteed that the answer exists for the given number x_1, x_2, x_3, x_4.

Output

Print such positive integers a, b and c that four numbers written on a board are values a+b, a+c, b+c and a+b+c written in some order. Print a, b and c in any order. If there are several answers, you can print any. It is guaranteed that the answer exists.

Examples

Input


3 6 5 4


Output


2 1 3


Input


40 40 40 60


Output


20 20 20


Input


201 101 101 200


Output


1 100 100

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
int main() {
  int array[4], swap, c, d, n = 4, x, y, z;
  n = 4;
  for (c = 0; c < n; c++) scanf("%d", &array[c]);
  for (c = 0; c < n - 1; c++) {
    for (d = 0; d < n - c - 1; d++) {
      if (array[d] > array[d + 1]) {
        swap = array[d];
        array[d] = array[d + 1];
        array[d + 1] = swap;
      }
    }
  }
  x = array[3] - array[2];
  y = array[0] - x;
  z = array[2] - y;
  printf("%d %d %d\n", x, y, z);
}