Problem: There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice. Each of these choices is represented by a string s_i. If s_i is `AB`, you must add 1 to A or B then subtract 1 from the other; if s_i is `AC`, you must add 1 to A or C then subtract 1 from the other; if s_i is `BC`, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

* 1 \leq N \leq 10^5
* 0 \leq A,B,C \leq 10^9
* N, A, B, C are integers.
* s_i is `AB`, `AC`, or `BC`.

Input

Input is given from Standard Input in the following format:


N A B C
s_1
s_2
:
s_N


Output

If it is possible to make N choices under the condition, print `Yes`; otherwise, print `No`.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (`A`, `B`, or `C`) to which you add 1 in the i-th choice.

Examples

Input

2 1 3 0
AB
AC


Output

Yes
A
C


Input

3 1 0 0
AB
BC
AB


Output

No


Input

1 0 9 0
AC


Output

No


Input

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB


Output

Yes
C
B
B
C
C
B
A
A

Solution (in PYTHON3):

Solution:
n, a, b, c = map(int, input().split())
abc = list((a, b, c))
ans = [0] * n
dic = {'A': 0, 'B': 1, 'C': 2}
flag = True
s = [input() for i in range(n)]
for i in range(n):
    if abc[dic[s[i][0]]] == 0 and abc[dic[s[i][1]]] == 0:
        flag = False
        break
    elif sum(abc) == 2 and abc[dic[s[i][0]]] == 1 and abc[dic[s[i][1]]] == 1 and i != n - 1:
        ps = (set(s[i]) & set(s[i + 1])).pop()
        ms = (set(s[i]) - set(ps)).pop()
        abc[dic[ps]] += 1
        abc[dic[ms]] -= 1
        ans[i] = ps
    elif abc[dic[s[i][0]]] <= abc[dic[s[i][1]]]:
        abc[dic[s[i][0]]] += 1
        abc[dic[s[i][1]]] -= 1
        ans[i] = s[i][0]
    else:
        abc[dic[s[i][0]]] -= 1
        abc[dic[s[i][1]]] += 1
        ans[i] = s[i][1]
if flag:
    print('Yes')
    print(*ans, sep='\n')
else:
    print('No')