Problem: Polycarp has guessed three positive integers a, b and c. He keeps these numbers in secret, but he writes down four numbers on a board in arbitrary order — their pairwise sums (three numbers) and sum of all three numbers (one number). So, there are four numbers on a board in random order: a+b, a+c, b+c and a+b+c.

You have to guess three numbers a, b and c using given numbers. Print three guessed integers in any order.

Pay attention that some given numbers a, b and c can be equal (it is also possible that a=b=c).

Input

The only line of the input contains four positive integers x_1, x_2, x_3, x_4 (2 ≤ x_i ≤ 10^9) — numbers written on a board in random order. It is guaranteed that the answer exists for the given number x_1, x_2, x_3, x_4.

Output

Print such positive integers a, b and c that four numbers written on a board are values a+b, a+c, b+c and a+b+c written in some order. Print a, b and c in any order. If there are several answers, you can print any. It is guaranteed that the answer exists.

Examples

Input


3 6 5 4


Output


2 1 3


Input


40 40 40 60


Output


20 20 20


Input


201 101 101 200


Output


1 100 100

Solution (in JAVA):

Solution:
import java.util.Scanner ;
public class A_1154 
{
    public static void main(String [] args)
    {
        Scanner sc = new Scanner(System.in);
        int x1 = sc.nextInt();
        int x2 = sc.nextInt();
        int x3 = sc.nextInt();
        int x4 = sc.nextInt();
        if((x1 > x2) && (x1 > x3) && (x1 > x4))
            System.out.println((x1-x2) + " " + (x1-x3) + " " + (x1-x4));
        else if((x2 > x1) && (x2 > x3) && (x2 > x4))
            System.out.println((x2-x1) + " " + (x2-x3) + " " + (x2-x4));
        else if((x3 > x2) && (x3 > x1) && (x3 > x4))
            System.out.println((x3-x2) + " " + (x3-x1) + " " + (x3-x4));
        else
            System.out.println((x4-x2) + " " + (x4-x3) + " " + (x4-x1));
    }
}