Problem: There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice. Each of these choices is represented by a string s_i. If s_i is `AB`, you must add 1 to A or B then subtract 1 from the other; if s_i is `AC`, you must add 1 to A or C then subtract 1 from the other; if s_i is `BC`, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

* 1 \leq N \leq 10^5
* 0 \leq A,B,C \leq 10^9
* N, A, B, C are integers.
* s_i is `AB`, `AC`, or `BC`.

Input

Input is given from Standard Input in the following format:


N A B C
s_1
s_2
:
s_N


Output

If it is possible to make N choices under the condition, print `Yes`; otherwise, print `No`.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (`A`, `B`, or `C`) to which you add 1 in the i-th choice.

Examples

Input

2 1 3 0
AB
AC


Output

Yes
A
C


Input

3 1 0 0
AB
BC
AB


Output

No


Input

1 0 9 0
AC


Output

No


Input

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB


Output

Yes
C
B
B
C
C
B
A
A

Solution (in PYTHON3):

Solution:
def add_i1():
	abc[i1]+=1
	abc[i2]-=1
	res[i]=i1
	return

def add_i2():
	abc[i1]-=1
	abc[i2]+=1
	res[i]=i2

n,*abc=map(int,input().split())
ip=[0]*n

for i in range(n):
	ip[i]=list(map(lambda x:ord(x)-ord("A"),list(input())))

ans="Yes"
res=[0]*n
s=sum(abc)
if s==0:
	ans="No"
elif s==1:
	for i in range(n):
		i1=ip[i][0]
		i2=ip[i][1]
		ABC=[abc[i1],abc[i2]]
		if ABC==[0,0]:
			ans="No"
		elif ABC==[0,1]:
			add_i1()
		else:
			add_i2()
else:
	i1=ip[0][0]
	i2=ip[0][1]
	if [abc[i1],abc[i2]]==[0,0]:
		ans="No"
	else:
		for i in range(n):
			i1=ip[i][0]
			i2=ip[i][1]
			if abc[i1]==0:
				add_i1()
			elif abc[i2]==0:
				add_i2()
			elif i+1<n and ip[i+1]!=ip[i]:
				c=list(set(ip[i])&set(ip[i+1]))[0]
				if i1==c:
					add_i1()
				else:
					add_i2()
			else:
				add_i1()

dic={0:"A",1:"B",2:"C"}
print(ans)
if ans=="Yes":
	for i in range(n):
		print(dic[res[i]])