Problem: There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice. Each of these choices is represented by a string s_i. If s_i is `AB`, you must add 1 to A or B then subtract 1 from the other; if s_i is `AC`, you must add 1 to A or C then subtract 1 from the other; if s_i is `BC`, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

* 1 \leq N \leq 10^5
* 0 \leq A,B,C \leq 10^9
* N, A, B, C are integers.
* s_i is `AB`, `AC`, or `BC`.

Input

Input is given from Standard Input in the following format:


N A B C
s_1
s_2
:
s_N


Output

If it is possible to make N choices under the condition, print `Yes`; otherwise, print `No`.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (`A`, `B`, or `C`) to which you add 1 in the i-th choice.

Examples

Input

2 1 3 0
AB
AC


Output

Yes
A
C


Input

3 1 0 0
AB
BC
AB


Output

No


Input

1 0 9 0
AC


Output

No


Input

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB


Output

Yes
C
B
B
C
C
B
A
A

Solution (in PYTHON3):

Solution:
n,a,b,c=map(int,input().split())
a=min(3,a)
b=min(3,b)
S=[input() for i in range(n)]
X=a+b+c
idx=0
log=[0]*n#0,1のいずれか,
plog=[(a,b)]*(n+1)

flag=False

while idx!=n:

    #3回以上戻ってたらもうダメ 0回目の時点でアウトでもダメ
    if idx<n-2 and log[idx+2]==2 and log[idx]==2:
        flag=True
        break
    if idx==0 and log[0]==2:
        flag=True
        break

    a,b=plog[idx]
    dx,dy=0,0
    if S[idx]=='AB':
        dx,dy=1,-1
    elif S[idx]=='BC':
        dx,dy=0,1
    else:#AC
        dx,dy=1,0

    if log[idx]==0:
        a+=dx
        b+=dy
    elif log[idx]==1:
        a-=dx
        b-=dy
    else:
        log[idx]=0
        idx-=1
        log[idx]+=1
        continue
    
    if a<0 or b<0 or X-(a+b)<0:
        log[idx]+=1
        continue
    else:
        idx+=1
        plog[idx]=(a,b)

if flag:
    print('No')
else:
    print('Yes')
    for i,s in zip(log,S):
        print(s[i])