Problem: There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice. Each of these choices is represented by a string s_i. If s_i is `AB`, you must add 1 to A or B then subtract 1 from the other; if s_i is `AC`, you must add 1 to A or C then subtract 1 from the other; if s_i is `BC`, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

* 1 \leq N \leq 10^5
* 0 \leq A,B,C \leq 10^9
* N, A, B, C are integers.
* s_i is `AB`, `AC`, or `BC`.

Input

Input is given from Standard Input in the following format:


N A B C
s_1
s_2
:
s_N


Output

If it is possible to make N choices under the condition, print `Yes`; otherwise, print `No`.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (`A`, `B`, or `C`) to which you add 1 in the i-th choice.

Examples

Input

2 1 3 0
AB
AC


Output

Yes
A
C


Input

3 1 0 0
AB
BC
AB


Output

No


Input

1 0 9 0
AC


Output

No


Input

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB


Output

Yes
C
B
B
C
C
B
A
A

Solution (in PYTHON3):

Solution:
n,a,b,c = map(int,input().split())
l = [[*input()] for _ in range(n)]
l2 = l[1:]+["ABC"]
d = {"A":a, "B":b, "C":c}
a2 = a + 1
b2 = b + 1
c2 = c + 1
isNo = 0
if (a>0)+(b>0)+(c>0)>= 1:
  if d[l[0][0]] == 0 and d[l[0][1]] == 0:
    isNo = 1
  elif a+b+c == 1:
    for s,s2 in zip(l,l2):
      if d[s[0]]<d[s[1]]:
        d[s[1]]+=-1
        d[s[0]]+=1
        if s[0] not in s2:
          isNo = 1
          break
      else:
        d[s[1]]+=1
        d[s[0]]+=-1
        if s[1] not in s2:
          isNo = 1
          break
  else:isNo = 0
else:isNo = 1

d = {"A":a, "B":b, "C":c}
if isNo:print("No")
else:
  print("Yes")
  for s,s2 in zip(l,l2):
    if d[s[0]] > d[s[1]]:
      d[s[0]]+=-1
      d[s[1]]+=1
      print(s[1])
    elif d[s[0]] < d[s[1]]:
      d[s[1]]+=-1
      d[s[0]]+=1
      print(s[0])
    else:
      if s[0] in s2:
        d[s[1]]+=-1
        d[s[0]]+=1
        print(s[0])
      else:
        d[s[0]]+=-1
        d[s[1]]+=1
        print(s[1])