Problem: Polycarp has guessed three positive integers a, b and c. He keeps these numbers in secret, but he writes down four numbers on a board in arbitrary order — their pairwise sums (three numbers) and sum of all three numbers (one number). So, there are four numbers on a board in random order: a+b, a+c, b+c and a+b+c.

You have to guess three numbers a, b and c using given numbers. Print three guessed integers in any order.

Pay attention that some given numbers a, b and c can be equal (it is also possible that a=b=c).

Input

The only line of the input contains four positive integers x_1, x_2, x_3, x_4 (2 ≤ x_i ≤ 10^9) — numbers written on a board in random order. It is guaranteed that the answer exists for the given number x_1, x_2, x_3, x_4.

Output

Print such positive integers a, b and c that four numbers written on a board are values a+b, a+c, b+c and a+b+c written in some order. Print a, b and c in any order. If there are several answers, you can print any. It is guaranteed that the answer exists.

Examples

Input


3 6 5 4


Output


2 1 3


Input


40 40 40 60


Output


20 20 20


Input


201 101 101 200


Output


1 100 100

Solution (in JAVA):

Solution:
import java.util.*;
import java.lang.String;
import java.lang.Math;
import java.util.Arrays;

public class Capitalization2
{

public static void main(String[] args)
{
    Scanner sc=new Scanner(System.in);
long a,b,c,d;
a=sc.nextLong();
b=sc.nextLong();
c=sc.nextLong();
d=sc.nextLong();
long sum=(a+b+c+d)/3;
long res1=sum-a;
long res2=sum-b;
long res3=sum-c;
long res4=sum-d;
if(res1==0&&res2==0&&res3==0&&res4==0)
System.out.print(res1+" "+res2+" "+res3);
else
{
if(res1!=0)
System.out.print(res1+" ");
if(res2!=0)
System.out.print(res2+" ");
if(res3!=0)
System.out.print(res3+" ");
if(res4!=0)

System.out.print(res4+" ");

}


}

}