Problem: There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice. Each of these choices is represented by a string s_i. If s_i is `AB`, you must add 1 to A or B then subtract 1 from the other; if s_i is `AC`, you must add 1 to A or C then subtract 1 from the other; if s_i is `BC`, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

* 1 \leq N \leq 10^5
* 0 \leq A,B,C \leq 10^9
* N, A, B, C are integers.
* s_i is `AB`, `AC`, or `BC`.

Input

Input is given from Standard Input in the following format:


N A B C
s_1
s_2
:
s_N


Output

If it is possible to make N choices under the condition, print `Yes`; otherwise, print `No`.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (`A`, `B`, or `C`) to which you add 1 in the i-th choice.

Examples

Input

2 1 3 0
AB
AC


Output

Yes
A
C


Input

3 1 0 0
AB
BC
AB


Output

No


Input

1 0 9 0
AC


Output

No


Input

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB


Output

Yes
C
B
B
C
C
B
A
A

Solution (in PYTHON3):

Solution:
def abc(d, down_text, up_text):
    d[down_text] -= 1
    d[up_text] += 1


def main():
    n, a, b, c = map(int, input().split())
    ans_list = []
    dct = {"A": a, "B": b, "C": c}

    abc_list = [input() for _ in range(n)]
    abc_list.append('AB')

    for i in range(n):
        # a_txt = input()
        l_txt = abc_list[i][0]
        r_txt = abc_list[i][1]

        if dct[l_txt] < dct[r_txt]:
            abc(dct, r_txt, l_txt)
            ans_list.append(l_txt)

        elif dct[l_txt] > dct[r_txt]:
            abc(dct, l_txt, r_txt)
            ans_list.append(r_txt)

        else:
            if dct[l_txt] == dct[r_txt] == 0:
                print('No')
                break
            else:
                if l_txt in abc_list[i + 1]:
                    abc(dct, r_txt, l_txt)
                    ans_list.append(l_txt)
                elif r_txt in abc_list[i + 1]:
                    abc(dct, l_txt, r_txt)
                    ans_list.append(r_txt)
    else:
        print('Yes')
        print(*ans_list, sep='\n')


if __name__ == "__main__":
    main()