Problem: There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice. Each of these choices is represented by a string s_i. If s_i is `AB`, you must add 1 to A or B then subtract 1 from the other; if s_i is `AC`, you must add 1 to A or C then subtract 1 from the other; if s_i is `BC`, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

* 1 \leq N \leq 10^5
* 0 \leq A,B,C \leq 10^9
* N, A, B, C are integers.
* s_i is `AB`, `AC`, or `BC`.

Input

Input is given from Standard Input in the following format:


N A B C
s_1
s_2
:
s_N


Output

If it is possible to make N choices under the condition, print `Yes`; otherwise, print `No`.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (`A`, `B`, or `C`) to which you add 1 in the i-th choice.

Examples

Input

2 1 3 0
AB
AC


Output

Yes
A
C


Input

3 1 0 0
AB
BC
AB


Output

No


Input

1 0 9 0
AC


Output

No


Input

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB


Output

Yes
C
B
B
C
C
B
A
A

Solution (in PYTHON3):

Solution:
N, A, B, C = map(int, input().split())
S = [input() for _ in range(N)]

A, B, C = min(A, 2), min(B, 2), min(C, 2)
X = [0, A, B, C]  # 1-indexecの方が楽そう
F = {1: 'A', 2: 'B', 3: 'C'}

ans = []
for k, s in enumerate(S):
    if s == 'AB':
        i, j = 1, 2
    elif s == 'BC':
        i, j = 2, 3
    elif s == 'AC':
        i, j = 1, 3

    if X[i] > X[j]:
        X[i] -= 1
        X[j] += 1
        ans.append(j)

    elif X[i] < X[j]:
        X[i] += 1
        X[j] -= 1
        ans.append(i)

    else:
        if (X[i] == X[j] == 1) and (k < N - 1):
            if ((S[k + 1][0] == F[i]) and (S[k + 1][1] == F[i ^ j])) or ((S[k + 1][0] == F[i ^ j]) and (S[k + 1][1] == F[i])):
                X[i] += 1
                X[j] -= 1
                ans.append(i)
            else:
                X[j] += 1
                X[i] -= 1
                ans.append(j)
        else:
            X[i] -= 1
            X[j] += 1
            ans.append(j)

    if any([x < 0 for x in X]):
        print('No')
        exit()

print('Yes')
for a in ans:
    print(F[a])