Problem: There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice. Each of these choices is represented by a string s_i. If s_i is `AB`, you must add 1 to A or B then subtract 1 from the other; if s_i is `AC`, you must add 1 to A or C then subtract 1 from the other; if s_i is `BC`, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

* 1 \leq N \leq 10^5
* 0 \leq A,B,C \leq 10^9
* N, A, B, C are integers.
* s_i is `AB`, `AC`, or `BC`.

Input

Input is given from Standard Input in the following format:


N A B C
s_1
s_2
:
s_N


Output

If it is possible to make N choices under the condition, print `Yes`; otherwise, print `No`.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (`A`, `B`, or `C`) to which you add 1 in the i-th choice.

Examples

Input

2 1 3 0
AB
AC


Output

Yes
A
C


Input

3 1 0 0
AB
BC
AB


Output

No


Input

1 0 9 0
AC


Output

No


Input

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB


Output

Yes
C
B
B
C
C
B
A
A

Solution (in PYTHON3):

Solution:
import sys

s=[]
ans=[]
 
def dfs(a,b,c,i,root):
    if i==n:
        global ans
        ans=root.copy()
        return True
    l=False
    r=False
    if s[i]=='AB':
        if a>0:
            root.append('B')
            l=dfs(a-1,b+1,c,i+1,root)
            root.pop()
        if not l and b>0:
            root.append('A')
            r=dfs(a+1,b-1,c,i+1,root)
            root.pop()
    elif s[i]=='AC':
        if a>0:
            root.append('C')
            l=dfs(a-1,b,c+1,i+1,root)
            root.pop()
        if not l and c>0:
            root.append('A')
            r=dfs(a+1,b,c-1,i+1,root)
            root.pop()
    else:
        if b>0:
            root.append('C')
            l=dfs(a,b-1,c+1,i+1,root)
            root.pop()
        if not l and c>0:
            root.append('B')
            r=dfs(a,b+1,c-1,i+1,root)
            root.pop()
    return l or r
 
sys.setrecursionlimit(10**6)
n,a,b,c=map(int,input().split())
s=['']*n
for i in range(n):
    s[i]=input()
flag=dfs(a,b,c,0,[])
 
if flag:
    print("Yes")
    for t in ans:
        print(t)
else:
    print("No")