Problem: There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice. Each of these choices is represented by a string s_i. If s_i is `AB`, you must add 1 to A or B then subtract 1 from the other; if s_i is `AC`, you must add 1 to A or C then subtract 1 from the other; if s_i is `BC`, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

* 1 \leq N \leq 10^5
* 0 \leq A,B,C \leq 10^9
* N, A, B, C are integers.
* s_i is `AB`, `AC`, or `BC`.

Input

Input is given from Standard Input in the following format:


N A B C
s_1
s_2
:
s_N


Output

If it is possible to make N choices under the condition, print `Yes`; otherwise, print `No`.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (`A`, `B`, or `C`) to which you add 1 in the i-th choice.

Examples

Input

2 1 3 0
AB
AC


Output

Yes
A
C


Input

3 1 0 0
AB
BC
AB


Output

No


Input

1 0 9 0
AC


Output

No


Input

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB


Output

Yes
C
B
B
C
C
B
A
A

Solution (in JAVA):

Solution:

import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;
import java.util.Scanner;

public class Main {

	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		// 整数の入力
		int n = sc.nextInt();
		int a = sc.nextInt();
		int b = sc.nextInt();
		int c = sc.nextInt();

		int[] init = new int[] { a, b, c };

		String[] s = new String[n];
		for (int i = 0; i < n; i++) {
			s[i] = sc.next();
		}

		List<String> result = new ArrayList<>();
		dfs(result, s, 0, n, init);

		if (result.size() == n) {
			System.out.println("Yes");
			for (int i = result.size() - 1; i >= 0; i--) {
				System.out.println(result.get(i));
			}
		} else {
			System.out.println("No");

		}

	}

	private static boolean dfs(List<String> result, String[] s, int i, int n, int[] init) {
		if (i == n)
			return true;

		int l = s[i].charAt(0) - 'A';
		int r = s[i].charAt(1) - 'A';

		if (init[l] == 0 && init[r] == 0) {
			return false;
		}

		if (init[r] > 0) {
			int[] next = Arrays.copyOf(init, init.length);
			next[r]--;
			next[l]++;
			if( dfs(result, s, i + 1, n, next) ) {
				result.add(s[i].substring(0, 1));
				return true;
			}
		}

		if (init[l] > 0) {
			int[] next = Arrays.copyOf(init, init.length);
			next[l]--;
			next[r]++;
			if( dfs(result, s, i + 1, n, next) ) {
				result.add(s[i].substring(1, 2));
				return true;
			}
		}


		return false;
	}

}