Problem: Stack is a container of elements that are inserted and deleted according to LIFO (Last In First Out).

For $n$ stack $S_i$ ($i = 0, 1, ..., n-1$), perform a sequence of the following operations.

* push($t$, $x$): Insert an integer $x$ to $S_t$.
* top($t$): Report the value which should be deleted next from $S_t$. If $S_t$ is empty, do nothing.
* pop($t$): Delete an element from $S_t$. If $S_t$ is empty, do nothing.



In the initial state, all stacks are empty.

Constraints

* $1 \leq n \leq 1,000$
* $1 \leq q \leq 200,000$
* $-1,000,000,000 \leq x \leq 1,000,000,000$

Input

The input is given in the following format.


$n \; q$
$query_1$
$query_2$
:
$query_q$


Each query $query_i$ is given by


0 $t$ $x$


or


1 $t$


or


2 $t$


where the first digits 0, 1 and 2 represent push, top and pop operations respectively.

Output

For each top operation, print an integer in a line.

Example

Input

3 9
0 0 1
0 0 2
0 0 3
0 2 4
0 2 5
1 0
1 2
2 0
1 0


Output

3
5
2

Solution (in PYTHON3):

Solution:
#!/usr/bin/env python
# -*- coding: utf-8 -*-
#
# FileName: 	stack
# CreatedDate:  2020-05-22 23:23:23 +0900
# LastModified: 2020-05-22 23:46:42 +0900
#


import os
import sys
#import numpy as np
#import pandas as pd


def main():
    n,q = map(int,input().split())
    stack = [[] for _ in range(n)]
    for _ in range(q):
        order = list(map(int,input().split()))

        if order[0]==0:
            stack[order[1]].append(order[2])
        elif order[0]==1:
            if len(stack[order[1]])!=0:
                print(stack[order[1]][-1])
        else:
            if len(stack[order[1]])!=0:
                stack[order[1]].pop(-1)


if __name__ == "__main__":
    main()