Problem: Problem

Given a convex polygon consisting of $ N $ vertices and the center coordinates of $ M $ circles. The radius of all circles is $ r $.

I want to find the minimum real number $ r $ that satisfies the following conditions.

Condition: Every point inside a convex polygon is contained in at least one circle.

Constraints

The input satisfies the following conditions.

* $ 3 \ le N \ le 100 $
* $ 1 \ le M \ le 100 $
* $ -10 ^ 5 \ le px_i, py_i \ le 10 ^ 5 $
* $ -10 ^ 5 \ le cx_i, cy_i \ le 10 ^ 5 $
* No matter which of the three vertices of the convex polygon is selected, they do not exist on the same straight line.

Input

All inputs are given as integers in the following format:


$ N $
$ px_1 $ $ py_1 $
$ px_2 $ $ py_2 $
::
$ px_N $ $ py_N $
$ M $
$ Cx_1 $ $ cy_1 $
$ cx_2 $ $ cy_2 $
::
$ Cx_M $ $ cy_M $


The $ 1 $ line is given an integer $ N $ that represents the number of vertices of the convex polygon.
Information on each vertex of the convex polygon is given in the counterclockwise order from the $ 2 $ line to the $ 2 + N-1 $ line. The $ 1 + i $ line is given $ px_i $ $ py_i $, which represents the coordinates of the $ i $ th vertex, separated by blanks.
The $ 2 + N $ line is given the integer $ M $, which represents the number of circles.
Information on the center coordinates of the circle is given from the $ 2 + N + 1 $ line to the $ 2 + N + M $ line. On the $ 2 + N + i $ line, $ cx_i $ $ cy_i $ representing the center coordinates of the $ i $ th circle is given, separated by blanks.

Output

Outputs the radius $ r $ of the smallest circle that satisfies the condition.
However, absolute or relative errors up to $ 10 ^ {-5} $ are acceptable.

Examples

Input

4
2 3
1 2
2 1
3 2
4
1 3
1 1
3 3
3 1


Output

1.414213562373


Input

7
-96469 25422
-55204 -45592
-29140 -72981
98837 -86795
92303 63297
19059 96012
-67980 70342
17
-4265 -14331
33561 72343
52055 98952
-71189 60872
10459 -7512
-11981 57756
-78228 -28044
37397 -69980
-27527 -51966
22661 -16694
13759 -59976
86539 -47703
17098 31709
-62497 -70998
-57608 59799
-1904 -35574
-73860 121


Output

75307.220122044484

Solution (in CPP):

Solution:
#include<iostream>
#include<complex>
#include<vector>
#include<string>
#include<algorithm>	
#include<map>
#include<set>
#include<utility>
#include<cmath>
#include<cstring>
#include<queue>
#include<stack>
#include<cstdio>
#include<sstream>
#include<iomanip>
#include<assert.h>
#define loop(i,a,b) for(int i=a;i<b;i++) 
#define rep(i,a) loop(i,0,a)
#define pb push_back
#define all(in) in.begin(),in.end()
#define shosu(x) fixed<<setprecision(x)
using namespace std;
//kaewasuretyuui
typedef long long ll;
typedef int Def;
typedef pair<Def,Def> pii;
typedef vector<Def> vi;
typedef vector<vi> vvi;
typedef vector<pii> vp;
typedef vector<vp> vvp;
typedef vector<string> vs;
typedef vector<double> vd;
typedef vector<vd> vvd;
typedef pair<Def,pii> pip;
typedef vector<pip>vip;
//#define mt make_tuple
//typedef tuple<double,int,double> tp;
//typedef vector<tp> vt;
template<typename A,typename B>bool cmin(A &a,const B &b){return a>b?(a=b,true):false;}
template<typename A,typename B>bool cmax(A &a,const B &b){return a<b?(a=b,true):false;}
const double PI=acos(-1);
const double EPS=1e-10;
Def inf = sizeof(Def) == sizeof(long long) ? 2e18 : 1e9;
int dx[]={0,1,0,-1};
int dy[]={1,0,-1,0};
typedef complex<double> P;
typedef vector<P> G;
typedef vector<double> vd;
typedef vector<vd> vvd;

struct L : public vector<P> {
  L(const P &a, const P &b) {
    push_back(a); push_back(b);
  }
  L(){;}
};
struct C{
	P c;double r;
	C(const P &c,double r):c(c),r(r){}
};
#define curr(P, i) P[i]
#define next(P, i) P[(i+1)%P.size()]
#define diff(P, i) (next(P, i) - curr(P, i))
namespace std {
	bool operator < (const P& a, const P& b) {
		return real(a) != real(b) ? real(a) < real(b) : imag(a) < imag(b);
		//return imag(a) != imag(b) ? imag(a) < imag(b) : real(a) < real(b);  
	}
	bool operator == (const P& a, const P& b) {
		return a.real()==b.real()&&a.imag()==b.imag();
	}
}
P pin(){
	double x,y;
	char d;
	cin>>x>>y;
	P p(x,y);
	return p;
}
void PIN(P* a,int n){
	rep(i,n)a[i]=pin();
}
double dot(P a,P b){
	return real(conj(a)*b);
}
double cross(P a,P b){
	return imag(conj(a)*b);
}
int ccw(P a, P b, P c) {
  b -= a; c -= a;
  if (cross(b, c) > 0)   return +1;       // counter clockwise
  if (cross(b, c) < 0)   return -1;       // clockwise
  if (dot(b, c) < 0)     return +2;       // c--a--b on line
  if (norm(b) < norm(c)) return -2;       // a--b--c on line
  return 0;                               // a--c--b on line
}
P projection(L a,P p){
	double t=dot(p-a[0],a[0]-a[1])/norm(a[0]-a[1]);
	return a[0]+t*(a[0]-a[1]);
}
P reflection(L a,P p){
	return p+2.0*(projection(a,p)-p);
}
bool intersectLL(const L &l, const L &m) {
  return abs(cross(l[1]-l[0], m[1]-m[0])) > EPS || // non-parallel
         abs(cross(l[1]-l[0], m[0]-l[0])) < EPS;   // same line
}
bool intersectLS(const L &l, const L &s) {
  return cross(l[1]-l[0], s[0]-l[0])*       // s[0] is left of l
         cross(l[1]-l[0], s[1]-l[0]) < EPS; // s[1] is right of l
}
bool intersectLP(const L &l, const P &p) {
  return abs(cross(l[1]-p, l[0]-p)) < EPS;
}
bool intersectSS(const L &s, const L &t) {
  return ccw(s[0],s[1],t[0])*ccw(s[0],s[1],t[1]) <= 0 &&
         ccw(t[0],t[1],s[0])*ccw(t[0],t[1],s[1]) <= 0;
}
bool intersectSP(const L &s, const P &p) {
  return abs(s[0]-p)+abs(s[1]-p)-abs(s[1]-s[0]) < EPS; // triangle inequality
}
double distanceLP(const L &l, const P &p) {
	return abs(p - projection(l, p));
}
double distanceLL(const L &l, const L &m) {
  return intersectLL(l, m) ? 0 : distanceLP(l, m[0]);
}
double distanceLS(const L &l, const L &s) {
  if (intersectLS(l, s)) return 0;
  return min(distanceLP(l, s[0]), distanceLP(l, s[1]));
}
double distanceSP(const L &s, const P &p) {
  const P r = projection(s, p);
  if (intersectSP(s, r)) return abs(r - p);
  return min(abs(s[0] - p), abs(s[1] - p));
}
double distanceSS(const L &s, const L &t) {
  if (intersectSS(s, t)) return 0;
  return min(min(distanceSP(s, t[0]), distanceSP(s, t[1])),
             min(distanceSP(t, s[0]), distanceSP(t, s[1])));
}
/*bool intersectCS(C c,const L &l){
    return (distanceLP(l,c.c) < c.r+EPS &&
            (c.r < abs(c.c-l[0]) + EPS || c.r < abs(c.c-l[1]) + EPS));
}*/
int intersectCS(C c,L l){
	if(norm(projection(l,c.c)-c.c)-c.r*c.r>EPS)return 0;
	const double d1=abs(c.c-l[0]),d2=abs(c.c-l[1]);
	if(d1<c.r+EPS&&d2<c.r+EPS)return 0;
	if(d1<c.r-EPS&&d2>c.r+EPS||d1>c.r+EPS&&d2<c.r-EPS)return 1;
	const P h=projection(l,c.c);
	if(dot(l[0]-h,l[1]-h)<0)return 2;
	return 0;
}
P crosspointSS(L a,L b){
	double t1=abs(cross(a[1]-a[0],b[0]-a[0]));
	double t2=abs(cross(a[1]-a[0],b[1]-a[0]));
	return b[0]+(b[1]-b[0])*t1/(t1+t2);
}
L crosspointCL(C c,L l){
	P pr=projection(l,c.c);
	P e=(l[1]-l[0])/abs(l[1]-l[0]);
	double tmp=c.r*c.r-norm(pr-c.c);
	if(abs(tmp)<EPS)tmp=0;
	double t=sqrt(tmp);
	P a=pr+t*e;
	P b=pr-t*e;
	if(b<a)swap(a,b);
	return L(a,b);
}
L crosspointCS(C c,L l){
	if(intersectCS(c,l)==2)return crosspointCL(c,l);
	L ret=crosspointCL(c,l);
	if(dot(l[0]-ret[0],l[1]-ret[0])<0)ret[1]=ret[0];
	else ret[0]=ret[1];
	return ret;
}
L crosspointCC(C a,C b){
	P tmp=b.c-a.c;
	double d=abs(tmp);
	double q=acos((a.r*a.r+d*d-b.r*b.r)/(2*a.r*d));
	double t=arg(tmp);//atan(tmp.imag()/tmp.real());
	P p1=a.c+polar(a.r,t+q);
	P p2=a.c+polar(a.r,t-q);
	if(p2<p1)swap(p1,p2);
	return L(p1,p2);
}
P crosspointLL(const L &l, const L &m) {
  double A = cross(l[1] - l[0], m[1] - m[0]);
  double B = cross(l[1] - l[0], l[1] - m[0]);
  if (abs(A) < EPS && abs(B) < EPS) return m[0]; // same line
  return m[0] + B / A * (m[1] - m[0]);
}
double area(const G &g){
    double S =0;
    for(int i =0;i <g.size();i++){
        S +=(cross(g[i],g[(i+1)%g.size()]));
    }
    return abs(S/2.0);
}
bool isconvex(const G &g){
	int n=g.size();
	rep(i,n)if(ccw(g[(i+n-1)%n],g[i%n],g[(i+1)%n])==-1)return false;
	return true;
}
int inconvex(const G& g, const P& p) {
	bool in = false;
	int n=g.size();
	rep(i,n){
		P a=g[i%n]-p;
		P b=g[(i+1)%n]-p;
		if(imag(a)>imag(b))swap(a, b);
		if(imag(a)<EPS&&0<imag(b))if(cross(a,b)<0)in=!in;
		if(abs(cross(a,b))<EPS&&dot(a,b)<EPS)return 1;//ON
	}
	return in?2:0;//IN : OUT;
}
G convex_hull(G &ps) {
    int n=ps.size(),k=0;
	sort(ps.begin(), ps.end());
	G ch(2*n);
	for(int i=0;i<n;ch[k++]=ps[i++])//lower-hull
		while(k>=2&&ccw(ch[k-2],ch[k-1],ps[i])==-1)--k;//<=0  ->  ==-1
	for(int i=n-2,t=k+1;i>=0;ch[k++]=ps[i--])//upper-hull
		while(k>=t&&ccw(ch[k-2],ch[k-1],ps[i])==-1)--k;//
	ch.resize(k-1);
	return ch;
}
double convex_diameter(const G &pt) {
  const int n = pt.size();
  int is = 0, js = 0;
  for (int i = 1; i < n; ++i) {
    if (imag(pt[i]) > imag(pt[is])) is = i;
    if (imag(pt[i]) < imag(pt[js])) js = i;
  }
  double maxd = norm(pt[is]-pt[js]);

  int i, maxi, j, maxj;
  i = maxi = is;
  j = maxj = js;
  do {
    if (cross(diff(pt,i), diff(pt,j)) >= 0) j = (j+1) % n;
    else i = (i+1) % n;
    if (norm(pt[i]-pt[j]) > maxd) {
      maxd = norm(pt[i]-pt[j]);
      maxi = i; maxj = j;
    }
  } while (i != is || j != js);
  return sqrt(maxd); /* farthest pair is (maxi, maxj). */
}//convex_diameter(g)
G convex_cut(const G& g, const L& l) {
  G Q;
  for (int i = 0; i < g.size(); ++i) {
    P a= curr(g, i), b= next(g, i);
    if (ccw(l[0], l[1], a) != -1) Q.push_back(a);
    if (ccw(l[0], l[1], a)*ccw(l[0], l[1], b) < 0)
      Q.push_back(crosspointLL(L(a,b), l));
  }
  return Q;
}
P turn(P p,double t){
	return p*exp(P(.0,t*PI/180.0));
}
P turn2(P p,double t){
	return p*exp(P(.0,t));
}
vector<L> tangentCC(C a,C b){
	if(a.r<b.r)swap(a,b);
	double d=abs(a.c-b.c);
	vector<L>l;
	if(d<EPS)return l;
	if(a.r+b.r<d-EPS){//hanareteiru
		double t=acos((a.r+b.r)/d);
		t=t*180/PI;
		l.pb(L(a.c+turn(a.r/d*(b.c-a.c),t),b.c+turn(b.r/d*(a.c-b.c),t)));
		l.pb(L(a.c+turn(a.r/d*(b.c-a.c),-t),b.c+turn(b.r/d*(a.c-b.c),-t)));
	}else if(a.r+b.r<d+EPS){//kuttuiteiru soto
		P p=a.c+a.r/d*(b.c-a.c);
		l.pb(L(p,p+turn(b.c-a.c,90)));
	}
	if(abs(a.r-b.r)<d-EPS){//majiwatteiru
		double t1=acos((a.r-b.r)/d);
		t1=t1*180/PI;
		double t2=180-t1;
		l.pb(L(a.c+turn(a.r/d*(b.c-a.c),t1),b.c+turn(b.r/d*(a.c-b.c),-t2)));
		l.pb(L(a.c+turn(a.r/d*(b.c-a.c),-t1),b.c+turn(b.r/d*(a.c-b.c),t2)));
	}else if(abs(a.r-b.r)<d+EPS){//kuttuiteiru uti
		P p=a.c+a.r/d*(b.c-a.c);
		l.pb(L(p,p+turn(b.c-a.c,90)));
	}
	return l;
}
void printL(const L &out){
	printf("%0.9f %0.9f %0.9f %0.9f\n",out[0].real(),out[0].imag(),out[1].real(),out[1].imag());
}
C CIN(){
	P p=pin();
	double r;
	cin>>r;
	return C(p,r);
}
bool para(L a,L b){
	return (abs(cross(a[1]-a[0],b[1]-b[0]))<EPS);
}
double min(double a,double b){return a<b?a:b;}
double max(double a,double b){return a>b?a:b;}


//XY座標
#define X real()
#define Y imag()
	
// 三角形クラス
class Triangle{

private:
	//三角形の３点の座標
	P a, b, c;
	//三角形の３辺の長さ
	double edgeA,edgeB,edgeC;
	//三角形の３角の大きさ(ラジアン)
	double angleA,angleB,angleC;
	//余弦定理から３つの角度を求める関数
	double LawOfCosines(double a,double b, double c){
		return acos( (b*b+c*c-a*a) / (2.0*b*c) );
	}
	//２つのdouble型の数値が等しいかどうか
	bool equal(double a, double b){
		return (abs( a-b ) < EPS)? true : false ;
	}

public:
	//コンストラクタ(３つの点と辺と角度を初期化)
	Triangle(P p1, P p2, P p3){
		a = p1;
		b = p2;
		c = p3;
		edgeB = abs(c-a);
		edgeA = abs(b-c);
		edgeC = abs(a-b);
		angleA = LawOfCosines(edgeA,edgeB,edgeC);
		angleB = LawOfCosines(edgeB,edgeC,edgeA);
		angleC = LawOfCosines(edgeC,edgeA,edgeB);
	}
	
	double circumscribedCircleRadius(){//外接円の半径を返す
		return ( edgeA / sin(angleA) / 2.0 );
	}
	double circumscribedCircleX(){//外心(外接円の中心)のX座標を返す
		double A = sin(2.0*angleA);
		double B = sin(2.0*angleB);
		double C = sin(2.0*angleC);
		return ( (a.X * A + b.X * B + c.X * C) / (A+B+C) );
	}
	double circumscribedCircleY(){//外心(外接円の中心)のY座標を返す
		double A = sin(2.0*angleA);
		double B = sin(2.0*angleB);
		double C = sin(2.0*angleC);
		return ( (a.Y * A + b.Y * B + c.Y * C) / (A+B+C) );
	}
};

int main(){
//		Triangle Tr(a,b,c);
//		r  = Tr.circumscribedCircleRadius();
//		xp = Tr.circumscribedCircleX();
//		yp = Tr.circumscribedCircleY();

	int n;
	cin>>n;
	G g(n);
	rep(i,n){
		double a,b;
		cin>>a>>b;
		g[i]=P(a,b);
	}
	int m;
	cin>>m;
	G in(m);
	rep(i,m){
		double a,b;
		cin>>a>>b;
		in[i]=P(a,b);
	}	
	double out=0;
	rep(i,n){
		double mi=inf;
		rep(j,m)mi=min(mi,abs(g[i]-in[j]));
		out=max(out,mi);
	}//couner
//	cout<<shosu(10)<<out<<endl;
	
	rep(i,m)loop(j,i+1,m)loop(k,j+1,m){
		Triangle Tr(in[i],in[j],in[k]);
		P p(Tr.circumscribedCircleX(),Tr.circumscribedCircleY());
		if(!inconvex(g,p))continue;
		double mi=inf;
		rep(q,m)mi=min(mi,abs(p-in[q]));
		out=max(out,mi);
	}// gaisin
//	cout<<shosu(10)<<out<<endl;

	rep(i,m)loop(j,i+1,m){
		P p=in[i]+(in[j]-in[i])/2.;
		L l(p,p+P(0,1)*(in[j]-in[i]));
		rep(k,n){
			if(!intersectLS(l,L(g[k],g[(k+1)%n])))continue;
			P cr=crosspointLL(l,L(g[k],g[(k+1)%n]));
			double mi=inf;
			rep(q,m)mi=min(mi,abs(cr-in[q]));
			out=max(out,mi);
		}
	}
	
	cout<<shosu(10)<<out<<endl;
	
}