Problem: Polycarp has guessed three positive integers a, b and c. He keeps these numbers in secret, but he writes down four numbers on a board in arbitrary order — their pairwise sums (three numbers) and sum of all three numbers (one number). So, there are four numbers on a board in random order: a+b, a+c, b+c and a+b+c.

You have to guess three numbers a, b and c using given numbers. Print three guessed integers in any order.

Pay attention that some given numbers a, b and c can be equal (it is also possible that a=b=c).

Input

The only line of the input contains four positive integers x_1, x_2, x_3, x_4 (2 ≤ x_i ≤ 10^9) — numbers written on a board in random order. It is guaranteed that the answer exists for the given number x_1, x_2, x_3, x_4.

Output

Print such positive integers a, b and c that four numbers written on a board are values a+b, a+c, b+c and a+b+c written in some order. Print a, b and c in any order. If there are several answers, you can print any. It is guaranteed that the answer exists.

Examples

Input


3 6 5 4


Output


2 1 3


Input


40 40 40 60


Output


20 20 20


Input


201 101 101 200


Output


1 100 100

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
int main() {
  int x1, x2, x3, x4, a, b, c;
  scanf("%d %d %d %d", &x1, &x2, &x3, &x4);
  if (x1 > x2 && x1 > x3 && x1 > x4) {
    a = x1 - x3;
    b = x1 - x4;
    c = x1 - x2;
    printf("%d %d %d", a, b, c);
  } else if (x2 > x1 && x2 > x3 && x2 > x4) {
    a = x2 - x3;
    b = x2 - x4;
    c = x2 - x1;
    printf("%d %d %d", a, b, c);
  } else if (x3 > x1 && x3 > x2 && x3 > x4) {
    a = x3 - x2;
    b = x3 - x4;
    c = x3 - x1;
    printf("%d %d %d", a, b, c);
  } else {
    a = x4 - x2;
    b = x4 - x3;
    c = x4 - x1;
    printf("%d %d %d", a, b, c);
  }
  return 0;
}