Problem: You have array of n numbers a_{1}, a_{2}, …, a_{n}. 

Rearrange these numbers to satisfy |a_{1} - a_{2}| ≤ |a_{2} - a_{3}| ≤ … ≤ |a_{n-1} - a_{n}|, where |x| denotes absolute value of x. It's always possible to find such rearrangement.

Note that all numbers in a are not necessarily different. In other words, some numbers of a may be same.

You have to answer independent t test cases.

Input

The first line contains a single integer t (1 ≤ t ≤ 10^{4}) — the number of test cases.

The first line of each test case contains single integer n (3 ≤ n ≤ 10^{5}) — the length of array a. It is guaranteed that the sum of values of n over all test cases in the input does not exceed 10^{5}.

The second line of each test case contains n integers a_{1}, a_{2}, …, a_{n} (-10^{9} ≤ a_{i} ≤ 10^{9}).

Output

For each test case, print the rearranged version of array a which satisfies given condition. If there are multiple valid rearrangements, print any of them.

Example

Input


2
6
5 -2 4 8 6 5
4
8 1 4 2


Output


5 5 4 6 8 -2
1 2 4 8

Note

In the first test case, after given rearrangement, |a_{1} - a_{2}| = 0 ≤ |a_{2} - a_{3}| = 1 ≤ |a_{3} - a_{4}| = 2 ≤ |a_{4} - a_{5}| = 2 ≤ |a_{5} - a_{6}| = 10. There are other possible answers like "5 4 5 6 -2 8".

In the second test case, after given rearrangement, |a_{1} - a_{2}| = 1 ≤ |a_{2} - a_{3}| = 2 ≤ |a_{3} - a_{4}| = 4. There are other possible answers like "2 4 8 1".

Solution (in JAVA):

Solution:
// No sorceries shall prevail. //           
import java.util.*;
import java.io.*;
public class InVoker {
	//Variables
	static long mod = 1000000007;
	static long mod2 = 998244353;
	static FastReader inp= new FastReader();
	static PrintWriter out= new PrintWriter(System.out);
	public static void main(String args[]) {		    	
	   	InVoker g=new InVoker();
	   	g.main();
	   	out.close();
	}
	
	//Main
	void main() {
		
		int t=inp.nextInt();
		while(t-->0) {
			int n=inp.nextInt();
			long a[]=new long[n];
			input(a,n);
			Arrays.sort(a);
			long ans[]=new long[n];
			int c=0;
			for(int i=0;i<n/2;i++) {
				ans[c++]=a[n-i-1];
				ans[c++]=a[i];
			}
			if(n%2==1) {
				ans[c++]=a[n/2];
			}
			for(int i=n-1;i>=0;i--) {
				out.print(ans[i]+" ");
			}
			out.println();
			
		}
		
	}
	
	
	
	
	
	
	
	
	
	
	
	
	
	
	// Classes
	static class Edge implements Comparable<Edge>{
		int l,r;
		Edge(){}
		Edge(int l,int r){
			this.l=l;
			this.r=r;
		}
		@Override
		public int compareTo(Edge e) {
			return (l-e.l)!=0?l-e.l:r-e.r;
		}
	}
	
    static class Segment implements Comparable<Segment> {
		long l, r, initialIndex;
		Segment () {}
		Segment (long l_, long r_, long d_) {
		    this.l = l_;
		    this.r = r_;
		    this.initialIndex = d_;
		}
		@Override
		public int compareTo(Segment o) {
		    return (int)((l - o.l) !=0 ? l-o.l : initialIndex - o.initialIndex);
		}
    }
    
    static class FastReader { 
        BufferedReader br; 
        StringTokenizer st; 
  
        public FastReader() { 
            br = new BufferedReader(new InputStreamReader(System.in)); 
        } 
        String next() { 
            while (st==null || !st.hasMoreElements()) { 
                try { 
                    st = new StringTokenizer(br.readLine()); 
                } 
                catch (IOException  e) { 
                    e.printStackTrace(); 
                } 
            } 
            return st.nextToken(); 
        } 
        int nextInt() { 
            return Integer.parseInt(next()); 
        } 
        long nextLong() { 
            return Long.parseLong(next()); 
        } 
        double nextDouble() { 
            return Double.parseDouble(next()); 
        } 
        String nextLine() { 
            String s=""; 
            try { 
                s=br.readLine(); 
            } 
            catch (IOException e) { 
                e.printStackTrace(); 
            } 
            return s; 
        } 
    } 
    
    // Functions
	static long gcd(long a, long b) { 
		return b==0?a:gcd(b,a%b);
	}
	static int gcd(int a, int b) { 
		return b==0?a:gcd(b,a%b);
	}
	
	void reverse(long[] A,int l,int r) {
        int i=l,j=r-1;
        while(i<j) {
            long t=A[i];
            A[i]=A[j];
            A[j]=t;
            i++;j--;
        }
    }
    void reverse(int[] A,int l,int r) {
        int i=l,j=r-1;
        while(i<j) {
            int t=A[i];
            A[i]=A[j];
            A[j]=t;
            i++;j--;
        }
    }
    
    //Input Arrays
    static void input(long a[], int n) {
		for(int i=0;i<n;i++) {
			a[i]=inp.nextLong();
		}
	}
	static void input(int a[], int n) {
		for(int i=0;i<n;i++) {
			a[i]=inp.nextInt();
		}
	}	
	static void input(String s[],int n) {
		for(int i=0;i<n;i++) {
			s[i]=inp.next();
		}
	}
	static void input(int a[][], int n, int m) {
		for(int i=0;i<n;i++) {
			for(int j=0;j<m;j++) {
				a[i][j]=inp.nextInt();
			}
		}
	}
	static void input(long a[][], int n, int m) {
		for(int i=0;i<n;i++) {
			for(int j=0;j<m;j++) {
				a[i][j]=inp.nextLong();
			}
		}
	}
		
}