Problem: We have a tree with N vertices numbered 1 to N. The i-th edge in the tree connects Vertex u_i and Vertex v_i, and its length is w_i. Your objective is to paint each vertex in the tree white or black (it is fine to paint all vertices the same color) so that the following condition is satisfied:

* For any two vertices painted in the same color, the distance between them is an even number.



Find a coloring of the vertices that satisfies the condition and print it. It can be proved that at least one such coloring exists under the constraints of this problem.

Constraints

* All values in input are integers.
* 1 \leq N \leq 10^5
* 1 \leq u_i < v_i \leq N
* 1 \leq w_i \leq 10^9

Input

Input is given from Standard Input in the following format:


N
u_1 v_1 w_1
u_2 v_2 w_2
.
.
.
u_{N - 1} v_{N - 1} w_{N - 1}


Output

Print a coloring of the vertices that satisfies the condition, in N lines. The i-th line should contain `0` if Vertex i is painted white and `1` if it is painted black.

If there are multiple colorings that satisfy the condition, any of them will be accepted.

Examples

Input

3
1 2 2
2 3 1


Output

0
0
1


Input

5
2 5 2
2 3 10
1 3 8
3 4 2


Output

1
0
1
0
1

Solution (in JAVA):

Solution:
import java.util.Deque;
import java.util.LinkedList;
import java.util.List;
import java.util.Scanner;

public class Main {
    public static void debug(String str) {
        boolean debug = false;
        if (debug == false) {
            return;
        }
        System.out.println(str);
    }

    public static class Edge {
        int u;
        int v;
        int w;
        int id;

        public Edge(int u, int v, int w, int id) {
            this.u = u;
            this.v = v;
            this.w = w;
            this.id = id;
        }
    }

    public static class Node {
        List<Edge> edge = new LinkedList<>();
    }

    public static void main(String[] args) {

        int N;
        Node[] node;
        int[] vst;
        try (Scanner sc = new Scanner(System.in)) {
            N = sc.nextInt();
            node = new Node[N];
            vst = new int[N - 1];
            for (int i = 0; i < N; i++) {
                node[i] = new Node();
            }
            for (int i = 0; i < N - 1; i++) {
                int u = sc.nextInt();
                int v = sc.nextInt();
                int w = sc.nextInt();
                Edge e = new Edge(u, v, w, i);
                node[u - 1].edge.add(e);
                node[v - 1].edge.add(e);
            }
        }
        int[] distans = new int[N];
        Deque<Integer> queue = new LinkedList<>();
        queue.push(1);
        distans[0] = 0;
        Integer target;
        while ((target = queue.pollFirst()) != null) {
            List<Edge> list = node[target - 1].edge;
            for (Edge e : list) {
                if (vst[e.id] != 0) {
                    continue;
                } else {
                    int d = (distans[target - 1] + e.w) % 2;
                    int i;
                    if (e.u != target) {
                        i = e.u;
                    } else {
                        i = e.v;
                    }
                    queue.addLast(i);
                    distans[i - 1] = d;
                    vst[e.id] = 1;
                }
            }
        }
        for (int i : distans) {
            System.out.println(i % 2);
        }
    }

}