Problem: There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice. Each of these choices is represented by a string s_i. If s_i is `AB`, you must add 1 to A or B then subtract 1 from the other; if s_i is `AC`, you must add 1 to A or C then subtract 1 from the other; if s_i is `BC`, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

* 1 \leq N \leq 10^5
* 0 \leq A,B,C \leq 10^9
* N, A, B, C are integers.
* s_i is `AB`, `AC`, or `BC`.

Input

Input is given from Standard Input in the following format:


N A B C
s_1
s_2
:
s_N


Output

If it is possible to make N choices under the condition, print `Yes`; otherwise, print `No`.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (`A`, `B`, or `C`) to which you add 1 in the i-th choice.

Examples

Input

2 1 3 0
AB
AC


Output

Yes
A
C


Input

3 1 0 0
AB
BC
AB


Output

No


Input

1 0 9 0
AC


Output

No


Input

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB


Output

Yes
C
B
B
C
C
B
A
A

Solution (in PYTHON3):

Solution:
n, a, b, c = map(int, input().split())
stage = []

for _ in range(n):
    s = input()
    stage.append(s)


var = [a, b, c]

if var.count(0) == 3:
    print('No')
    exit()


d = {"A": 0, "B": 1, "C": 2}
dd = {0: "A", 1: "B", 2: "C"}

ans = []

for i in range(n):
    p = d[stage[i][0]]
    q = d[stage[i][1]]
    r = 3 - p - q
    if var[p] == 0 and var[q] == 0:
        print('No')
        exit()
    elif var[p] == 1 and var[q] == 1 and var[r] == 0:
        if i != n-1:
            pp = d[stage[i+1][0]]
            qq = d[stage[i+1][1]]
            if p not in [pp, qq]:
                var[q] += 1
                var[p] -= 1
                ans.append(dd[q])
            else:
                var[p] += 1
                var[q] -= 1
                ans.append(dd[p])
        else:
            ans.append(dd[p])
    else:
        if var[p] < var[q]:
            var[p] += 1
            var[q] -= 1
            ans.append(dd[p])
        else:
            var[q] += 1
            var[p] -= 1
            ans.append(dd[q])

print('Yes')
for x in ans:
    print(x)