Problem: Write a program which manipulates a sequence $A$ = {$a_0, a_1, ..., a_{n-1}$} with the following operations:

* $add(s, t, x)$ : add $x$ to $a_s, a_{s+1}, ..., a_t$.
* $find(s, t)$ : report the minimum value in $a_s, a_{s+1}, ..., a_t$.



Note that the initial values of $a_i ( i = 0, 1, ..., n-1 )$ are 0.

Constraints

* $1 ≤ n ≤ 100000$
* $1 ≤ q ≤ 100000$
* $0 ≤ s ≤ t < n$
* $-1000 ≤ x ≤ 1000$

Input


$n$ $q$
$query_1$
$query_2$
:
$query_q$


In the first line, $n$ (the number of elements in $A$) and $q$ (the number of queries) are given. Then, $i$th query $query_i$ is given in the following format:


0 $s$ $t$ $x$


or


1 $s$ $t$


The first digit represents the type of the query. '0' denotes $add(s, t, x)$ and '1' denotes $find(s, t)$.

Output

For each $find$ query, print the minimum value.

Example

Input

6 7
0 1 3 1
0 2 4 -2
1 0 5
1 0 1
0 3 5 3
1 3 4
1 0 5


Output

-2
0
1
-1

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const ll INF=LLONG_MAX;
struct segtree
{
    vector<ll> node;
    vector<ll> lazy;
    vector<bool> lflg;
    int n;
    segtree(int sz)
    {
        n=1;while(n<sz) n*=2;
        node.resize(2*n,0);
        lazy.resize(2*n,0);
        lflg.resize(2*n,false);
    }
    void lazyupdate(int k, int l, int r)
    {
        if(lflg[k])
        {
            node[k]+=lazy[k];
            push(lazy[k],k,l,r);
            lazy[k]=0;
            lflg[k]=false;
        }
    }
    void push(int v,int k,int l,int r)
    {
        if(r-l>0)
        {
            lazy[2*k]+=v;
            lazy[2*k+1]+=v;
            lflg[2*k]=lflg[2*k+1]=true;
        }
    }
    void update(int qa, int qb, int v, int k=1, int l=1,int r=-1)
    {
        if(r<0) r=n;
        lazyupdate(k, l, r);
        if(qb<l||r<qa) return;
        if(qa<=l&&r<=qb)
        {
            node[k]+=v;
            push(v,k,l,r);
        }
        else
        {
            int m=(l+r)/2;
            update(qa,qb,v,2*k,l,m);
            update(qa,qb,v,2*k+1,m+1,r);
            node[k]=min(node[2*k],node[2*k+1]);
        }
    }
    ll get(int qa, int qb, int k=1, int l=1, int r=-1)
    {
        if(r<0) r=n;
        lazyupdate(k ,l, r);
        if(qb<l||r<qa) return INF;
        if(qa<=l&&r<=qb) return node[k];
        else
        {
            int m=(l+r)/2;
            ll lv=get(qa, qb, 2*k, l, m);
            ll rv=get(qa, qb, 2*k+1, m+1, r);
            return min(lv,rv);
        }
    }
};

int main()
{
    int n,q;
    scanf("%d %d",&n,&q);
    segtree tree(n);
    for(int i=0;i<q;i++){
        int c;
        scanf("%d",&c);
        if(c){
            int x,y;
            scanf("%d %d",&x,&y);
            cout<<tree.get(x+1,y+1)<<endl;
        }else{
            int s,t,v;
            scanf("%d %d %d",&s,&t,&v);
            tree.update(s+1,t+1,v);
        }
    }
}