Problem: There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice. Each of these choices is represented by a string s_i. If s_i is `AB`, you must add 1 to A or B then subtract 1 from the other; if s_i is `AC`, you must add 1 to A or C then subtract 1 from the other; if s_i is `BC`, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

* 1 \leq N \leq 10^5
* 0 \leq A,B,C \leq 10^9
* N, A, B, C are integers.
* s_i is `AB`, `AC`, or `BC`.

Input

Input is given from Standard Input in the following format:


N A B C
s_1
s_2
:
s_N


Output

If it is possible to make N choices under the condition, print `Yes`; otherwise, print `No`.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (`A`, `B`, or `C`) to which you add 1 in the i-th choice.

Examples

Input

2 1 3 0
AB
AC


Output

Yes
A
C


Input

3 1 0 0
AB
BC
AB


Output

No


Input

1 0 9 0
AC


Output

No


Input

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB


Output

Yes
C
B
B
C
C
B
A
A

Solution (in PYTHON3):

Solution:
n,a,b,c = list(map(int,input().split()))
ls = [""]*n
moji = [""]*n
for i in range(n):
    moji[i] = input()
for i in range(n):
    s = moji[i]
    if s == "AB":
        if a > b:
            a -= 1;b+=1
            ls[i] = 'B'
        elif a < b or i == n-1:
            a += 1;b-=1
            ls[i] = 'A'
        else:
            if moji[i+1] == "AC":
                b -= 1;a += 1
                ls[i] = "A"
            else:
                a -= 1;b+=1
                ls[i] = "B"
    if s == "BC":
        if c > b:
            c -= 1;b+=1
            ls[i] = 'B'
        elif c < b or i == n-1:
            c += 1;b-=1
            ls[i] = 'C'
        else:
            if moji[i+1] == "AC":
                b -= 1;c += 1
                ls[i] = "C"
            else:
                c -= 1;b+=1
                ls[i] = "B"

    if s == "AC":
        if a > c:
            a -= 1;c+=1
            ls[i] = 'C'
        elif a < c or n-1 == i:
            a += 1;c-=1
            ls[i] = 'A'
        else:
            if moji[i+1] == "AB":
                c -= 1;a += 1
                ls[i] = "A"
            else:
                a -= 1;c+=1
                ls[i] = "C"
    if a < 0 or b < 0 or c < 0:break

if a < 0 or b < 0 or c < 0:
    print("No")
else:
    print("Yes")
    for i in range(n):
        print(ls[i])