Problem: There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice. Each of these choices is represented by a string s_i. If s_i is `AB`, you must add 1 to A or B then subtract 1 from the other; if s_i is `AC`, you must add 1 to A or C then subtract 1 from the other; if s_i is `BC`, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

* 1 \leq N \leq 10^5
* 0 \leq A,B,C \leq 10^9
* N, A, B, C are integers.
* s_i is `AB`, `AC`, or `BC`.

Input

Input is given from Standard Input in the following format:


N A B C
s_1
s_2
:
s_N


Output

If it is possible to make N choices under the condition, print `Yes`; otherwise, print `No`.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (`A`, `B`, or `C`) to which you add 1 in the i-th choice.

Examples

Input

2 1 3 0
AB
AC


Output

Yes
A
C


Input

3 1 0 0
AB
BC
AB


Output

No


Input

1 0 9 0
AC


Output

No


Input

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB


Output

Yes
C
B
B
C
C
B
A
A

Solution (in PYTHON3):

Solution:
N, A, B, C = map(int, input().split())
v = [A, B, C]
s = [-1 for i in range(N)]
for i in range(N):
    t = input()
    if t == "AB":
        s[i] = 0
    if t == "BC":
        s[i] = 1
    if t == "AC":
        s[i] = 2
ans = [-1 for i in range(N)]
OK = True

for i in range(N):
    p = s[i]
    q = (s[i]+1)%3
    if v[p] < v[q]:
        ans[i] = p
        v[p] += 1
        v[q] -= 1
    elif v[p] > v[q]:
        ans[i] = q
        v[p] -= 1
        v[q] += 1
    elif v[p] > 0:
        if i == N-1:
            ans[i] = p
            v[p] += 1
            v[q] -= 1
        elif s[i+1] == q:
            ans[i] = q
            v[p] -= 1
            v[q] += 1
        else:
            ans[i] = p
            v[p] += 1
            v[q] -= 1
    else:
        OK = False
        break

ch = ["A", "B" ,"C"]
if OK:
    print("Yes")
    for i in range(N):
        print(ch[ans[i]])
else:
    print("No")