Problem: There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice. Each of these choices is represented by a string s_i. If s_i is `AB`, you must add 1 to A or B then subtract 1 from the other; if s_i is `AC`, you must add 1 to A or C then subtract 1 from the other; if s_i is `BC`, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

* 1 \leq N \leq 10^5
* 0 \leq A,B,C \leq 10^9
* N, A, B, C are integers.
* s_i is `AB`, `AC`, or `BC`.

Input

Input is given from Standard Input in the following format:


N A B C
s_1
s_2
:
s_N


Output

If it is possible to make N choices under the condition, print `Yes`; otherwise, print `No`.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (`A`, `B`, or `C`) to which you add 1 in the i-th choice.

Examples

Input

2 1 3 0
AB
AC


Output

Yes
A
C


Input

3 1 0 0
AB
BC
AB


Output

No


Input

1 0 9 0
AC


Output

No


Input

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB


Output

Yes
C
B
B
C
C
B
A
A

Solution (in PYTHON3):

Solution:
N,A,B,C=map(int,input().split())
li=[A,B,C]
ans=""
Q=[]
for i in range(N):
  Q.append(input())
Q.append(Q[-1])
for i in range(N):
  S=Q[i]
  target=[0,1,2]
  ta1 = target[ord(S[0])-ord("A")]
  ta2 = target[ord(S[1])-ord("A")]
  
  if li[ta1] > li[ta2]:
    ans+=chr(ord("A")+ta2)
    li[ta1]-=1
    li[ta2]+=1
  elif li[ta1] < li[ta2]:
    ans+=chr(ord("A")+ta1)
    li[ta1]+=1
    li[ta2]-=1
  else:
    if li[ta1]+li[ta2]>=4:
      ans+=chr(ord("A")+ta2)
      li[ta1]-=1
      li[ta2]+=1
    elif li[ta1] == 0 and li[ta2] == 0:
      print("No")
      exit()
    else:
      if S[0] in Q[i+1] and S[1] in Q[i+1]:
        ans+=chr(ord("A")+ta2)
        li[ta1]-=1
        li[ta2]+=1
      else:
        if S[0] in Q[i+1]:
          ans+=chr(ord("A")+ta1)
          li[ta1]+=1
          li[ta2]-=1
        else:
          ans+=chr(ord("A")+ta2)
          li[ta1]-=1
          li[ta2]+=1
          
    

print("Yes")
for s in ans:
  print(s)