Problem: You are a coach at your local university. There are n students under your supervision, the programming skill of the i-th student is a_i.

You have to create a team for a new programming competition. As you know, the more students some team has the more probable its victory is! So you have to create a team with the maximum number of students. But you also know that a team should be balanced. It means that the programming skill of each pair of students in a created team should differ by no more than 5.

Your task is to report the maximum possible number of students in a balanced team.

Input

The first line of the input contains one integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the number of students.

The second line of the input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9), where a_i is a programming skill of the i-th student.

Output

Print one integer — the maximum possible number of students in a balanced team.

Examples

Input


6
1 10 17 12 15 2


Output


3


Input


10
1337 1337 1337 1337 1337 1337 1337 1337 1337 1337


Output


10


Input


6
1 1000 10000 10 100 1000000000


Output


1

Note

In the first example you can create a team with skills [12, 17, 15].

In the second example you can take all students in a team because their programming skills are equal.

In the third example you can create a team consisting of a single student (and you cannot create a team consisting of at least two students).

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
long long n, bb, res = 0;
vector<long long> v;
long long busquedaBinaria(const long long &p) {
  long long maxP = (-1), ini = p, fin = n, m;
  while ((ini + 1) < fin) {
    m = ((ini + fin) / 2);
    if (abs(v[p] - v[m]) <= 5)
      ini = m, maxP = max(maxP, m);
    else
      fin = m;
  }
  if (abs(v[p] - v[ini]) <= 5) maxP = max(maxP, ini);
  if (abs(v[p] - v[fin]) <= 5) maxP = max(maxP, fin);
  return maxP;
}
int main() {
  ios::sync_with_stdio(false);
  cin.tie(NULL);
  cin >> n;
  v = vector<long long>(n);
  for (long long i = 0; i < n; i++) cin >> v[i];
  sort(v.begin(), v.end());
  for (long long i = 0; i < n; i++) {
    bb = busquedaBinaria(i);
    res = max(res, (bb - i + 1));
  }
  cout << res << "\n";
  return 0;
}