Problem: I have a sequence defined as follows:

* All even-numbered terms are equal to the previous term multiplied by 2.
* All odd-numbered terms are equal to the previous term divided by 3.



Create a program that reads the first term a of this sequence and outputs the sum s (10) from the first term to the tenth term.



Input

The input consists of multiple test cases. For each test case, a real number a (1.0 ≤ a ≤ 10.0) representing the first term of the sequence is given in one row.

The number of test cases does not exceed 50.

Output

Print s (10) on one line for each test case.

The output may contain an error of 0.000001 or less.

Example

Input

1.0
2.0
3.0


Output

7.81481481
15.62962963
23.44444444

Solution (in CPP):

Solution:
#include <iostream>
#include <cstdio>
using namespace std;

int main() {
	double n;
	while (cin >> n) {
		double sum = 0, a[10] = { 0 };
		sum = a[0] = n;
		for (int i = 1; i < 10; i++) {
			if ((i + 1) % 2 == 0) {
				a[i] = a[i - 1] * 2.0;
				sum += a[i];
			} else {
				a[i] = a[i - 1] / 3.0;
				sum += a[i];
			}
		}
		printf("%.8f\n", sum);
	}
	return 0;
}