Problem: For strings s and t, we will say that s and t are prefix-free when neither is a prefix of the other.

Let L be a positive integer. A set of strings S is a good string set when the following conditions hold true:

* Each string in S has a length between 1 and L (inclusive) and consists of the characters `0` and `1`.
* Any two distinct strings in S are prefix-free.



We have a good string set S = \\{ s_1, s_2, ..., s_N \\}. Alice and Bob will play a game against each other. They will alternately perform the following operation, starting from Alice:

* Add a new string to S. After addition, S must still be a good string set.



The first player who becomes unable to perform the operation loses the game. Determine the winner of the game when both players play optimally.

Constraints

* 1 \leq N \leq 10^5
* 1 \leq L \leq 10^{18}
* s_1, s_2, ..., s_N are all distinct.
* { s_1, s_2, ..., s_N } is a good string set.
* |s_1| + |s_2| + ... + |s_N| \leq 10^5

Input

Input is given from Standard Input in the following format:


N L
s_1
s_2
:
s_N


Output

If Alice will win, print `Alice`; if Bob will win, print `Bob`.

Examples

Input

2 2
00
01


Output

Alice


Input

2 2
00
11


Output

Bob


Input

3 3
0
10
110


Output

Alice


Input

2 1
0
1


Output

Bob


Input

1 2
11


Output

Alice


Input

2 3
101
11


Output

Bob

Solution (in CPP):

Solution:
#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
const int N=100005;
int now,n,son[N][2],sc,dep[N];
char s[N];
ll L,ans;
void ins(char *s)
{
	now=0;int len=strlen(s);
	for (int i=0;i<len;i++)
	{
		int c=s[i]-'0';
		if (!son[now][c]) son[now][c]=++sc,dep[sc]=dep[now]+1;
		now=son[now][c];
	}
}
ll sg(ll x){return x&(-x);}

void dfs(int now)
{
	int cnt=0;
	if (son[now][0]){
		dfs(son[now][0]);
		cnt++;
	}
	if (son[now][1]){
		dfs(son[now][1]);
		cnt++;
	}
	if (cnt==1){//切下一半的子树
		ans^=sg(L-dep[now]); 
	} 
}

int main()
{
	scanf("%d%lld",&n,&L);
	for (int i=1;i<=n;i++){
		scanf("%s",s);
		ins(s);
	}
	dfs(0);
	puts(ans==0?"Bob":"Alice"); 
	return 0;
}