Problem: I have a sequence defined as follows:

* All even-numbered terms are equal to the previous term multiplied by 2.
* All odd-numbered terms are equal to the previous term divided by 3.



Create a program that reads the first term a of this sequence and outputs the sum s (10) from the first term to the tenth term.



Input

The input consists of multiple test cases. For each test case, a real number a (1.0 ≤ a ≤ 10.0) representing the first term of the sequence is given in one row.

The number of test cases does not exceed 50.

Output

Print s (10) on one line for each test case.

The output may contain an error of 0.000001 or less.

Example

Input

1.0
2.0
3.0


Output

7.81481481
15.62962963
23.44444444

Solution (in CPP):

Solution:
#include<stdio.h>

int main(void){
	double a[11],d,sum=0;
	int i;
	
	while(scanf("%lf",&d)!=EOF){
	a[1]=d;
	for(i=2;i<11;i++){
		if(i%2==0)a[i]=a[i-1]*2;
		else a[i]=a[i-1]/3;
	}
	for(i=1;i<11;i++)sum=sum+a[i];
	printf("%0.8f\n",sum);
	sum=0;
	}
return 0;
}