Problem: You are a coach at your local university. There are n students under your supervision, the programming skill of the i-th student is a_i.

You have to create a team for a new programming competition. As you know, the more students some team has the more probable its victory is! So you have to create a team with the maximum number of students. But you also know that a team should be balanced. It means that the programming skill of each pair of students in a created team should differ by no more than 5.

Your task is to report the maximum possible number of students in a balanced team.

Input

The first line of the input contains one integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the number of students.

The second line of the input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9), where a_i is a programming skill of the i-th student.

Output

Print one integer — the maximum possible number of students in a balanced team.

Examples

Input


6
1 10 17 12 15 2


Output


3


Input


10
1337 1337 1337 1337 1337 1337 1337 1337 1337 1337


Output


10


Input


6
1 1000 10000 10 100 1000000000


Output


1

Note

In the first example you can create a team with skills [12, 17, 15].

In the second example you can take all students in a team because their programming skills are equal.

In the third example you can create a team consisting of a single student (and you cannot create a team consisting of at least two students).

Solution (in PYTHON3):

Solution:
dp=[]
for i in range(5005):
    dp.append([0]*5005)    

n,k=map(int,input().split())
a=list(map(int,input().split()))
a.sort()
p=[0]*(n+1)
for i in range(n):
    z=a[i]-5
    for j in range(i+1):
        if a[j]>=z:
            p[i]=j
            break
ans=-1            
for i in range(1,n+1):
    for j in range(k+1):
        dp[i][j]=max(dp[i-1][j],dp[p[i-1]][j-1]+(i-p[i-1]))
        if j!=k:
            ans=max(ans,dp[i][j])            
print(ans)