Problem: We have a grid with H rows and W columns of squares. Snuke is painting these squares in colors 1, 2, ..., N. Here, the following conditions should be satisfied:

* For each i (1 ≤ i ≤ N), there are exactly a_i squares painted in Color i. Here, a_1 + a_2 + ... + a_N = H W.
* For each i (1 ≤ i ≤ N), the squares painted in Color i are 4-connected. That is, every square painted in Color i can be reached from every square painted in Color i by repeatedly traveling to a horizontally or vertically adjacent square painted in Color i.



Find a way to paint the squares so that the conditions are satisfied. It can be shown that a solution always exists.

Constraints

* 1 ≤ H, W ≤ 100
* 1 ≤ N ≤ H W
* a_i ≥ 1
* a_1 + a_2 + ... + a_N = H W

Input

Input is given from Standard Input in the following format:


H W
N
a_1 a_2 ... a_N


Output

Print one way to paint the squares that satisfies the conditions. Output in the following format:


c_{1 1} ... c_{1 W}
:
c_{H 1} ... c_{H W}


Here, c_{i j} is the color of the square at the i-th row from the top and j-th column from the left.

Examples

Input

2 2
3
2 1 1


Output

1 1
2 3


Input

3 5
5
1 2 3 4 5


Output

1 4 4 4 3
2 5 4 5 3
2 5 5 5 3


Input

1 1
1
1


Output

1

Solution (in CPP):

Solution:
#include<iostream>
using namespace std;
#define rep(i,n) for(int i=0;i<(n);i++)
int h, w, n, a, b[10010];
int main() {
	cin >> h >> w >> n;
	int sum = 1;
	rep(i, n) {
		b[sum]++;
		cin >> a;
		sum += a;
	}
	for (int i = 1; i <= h * w; i++) {
		b[i] += b[i - 1];
	}
	for (int i = 0; i < h; i++) {
		for (int j = 0; j < w - 1; j++) {
			if (i % 2)cout << b[i * w + w - j] << " ";
			else cout << b[i * w + j + 1] << " ";
		}
		if(i % 2)cout << b[i * w + 1] << endl;
		else cout << b[(i + 1) * w] << endl;
	}
	return 0;
}