Problem: There are two persons, numbered 0 and 1, and a variable x whose initial value is 0. The two persons now play a game. The game is played in N rounds. The following should be done in the i-th round (1 \leq i \leq N):

* Person S_i does one of the following:
* Replace x with x \oplus A_i, where \oplus represents bitwise XOR.
* Do nothing.



Person 0 aims to have x=0 at the end of the game, while Person 1 aims to have x \neq 0 at the end of the game.

Determine whether x becomes 0 at the end of the game when the two persons play optimally.

Solve T test cases for each input file.

Constraints

* 1 \leq T \leq 100
* 1 \leq N \leq 200
* 1 \leq A_i \leq 10^{18}
* S is a string of length N consisting of `0` and `1`.
* All numbers in input are integers.

Input

Input is given from Standard Input in the following format. The first line is as follows:


T


Then, T test cases follow. Each test case is given in the following format:


N
A_1 A_2 \cdots A_N
S


Output

For each test case, print a line containing `0` if x becomes 0 at the end of the game, and `1` otherwise.

Example

Input

3
2
1 2
10
2
1 1
10
6
2 3 4 5 6 7
111000


Output

1
0
0

Solution (in PYTHON3):

Solution:
def xor_gauss_jordan(A):
    """掃き出し法でジョルダン標準形を求める"""
    cnt_row = len(A)
    cnt_col = len(bin(max(A))[2::])
 
    rank = 0
    for col in range(cnt_col):
        # ピボットを探す
        pivot = -1
        for row in range(rank, cnt_row):
            if A[row] & 2**(cnt_col - col - 1):
                pivot = row
                break
 
        #  ピボットがない場合は次の列に
        if pivot == -1:
            continue
 
        # 行をスワップする
        A[pivot], A[rank] = A[rank], A[pivot]
 
        # ピボットのある列の値がすべて0になるように掃き出す
        A_rank = A[rank]
        for row in range(cnt_row):
            if row != rank and A[row] & 2**(cnt_col - col - 1):
                A[row] ^= A[rank]
        rank += 1
 
    return A


t = int(input())
for _ in range(t):
    n = int(input())
    a = list(map(int, input().split()))
    s = input()

    hand = [0]
    flag = False

    for i in range(n)[::-1]:
        val = a[i]
        if s[i] == "1":
            # 手持ちでvalを作れるか確認する
            hand.sort(reverse=True)
            for num in hand:
                if val.bit_length() == num.bit_length():
                    val ^= num
            if val != 0:
                flag = True
        else:
            # valを手持ちに加える
            hand.append(val)
            # 手持ちは基底で管理するので掃き出し法を行う
            hand = xor_gauss_jordan(hand)


    if flag:
        print(1)
    else:
        print(0)