Problem: Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.

You are given a string s consisting of lowercase letters. Determine if there exists a (contiguous) substring of s that is unbalanced. If the answer is positive, show a position where such a substring occurs in s.

Constraints

* 2 ≦ |s| ≦ 10^5
* s consists of lowercase letters.

Input

The input is given from Standard Input in the following format:


s


Output

If there exists no unbalanced substring of s, print `-1 -1`.

If there exists an unbalanced substring of s, let one such substring be s_a s_{a+1} ... s_{b} (1 ≦ a < b ≦ |s|), and print `a b`. If there exists more than one such substring, any of them will be accepted.

Examples

Input

needed


Output

2 5


Input

atcoder


Output

-1 -1

Solution (in PYTHON3):

Solution:


"""
アンバランス
・長さが2以上
→そのまま
・過半数の文字が同じ
→abcaa　とか aabacda　aa とか 

ある2文字や3文字の区間を見た時に
・2文字：両方一致
・3文字：3つ中二つが一致
ならアンバランス
"""

S = input()
N = len(S)

for i in range(N-1):
  if len(set(S[i:i+2])) == 1:
    print(i+1, i+2)
    exit()

for i in range(N-2):
  if len(set(S[i:i+3])) <= 2:
    print(i+1, i+3)
    exit()

print(-1, -1)