Problem: Kostya is a genial sculptor, he has an idea: to carve a marble sculpture in the shape of a sphere. Kostya has a friend Zahar who works at a career. Zahar knows about Kostya's idea and wants to present him a rectangular parallelepiped of marble from which he can carve the sphere. 

Zahar has n stones which are rectangular parallelepipeds. The edges sizes of the i-th of them are ai, bi and ci. He can take no more than two stones and present them to Kostya. 

If Zahar takes two stones, he should glue them together on one of the faces in order to get a new piece of rectangular parallelepiped of marble. Thus, it is possible to glue a pair of stones together if and only if two faces on which they are glued together match as rectangles. In such gluing it is allowed to rotate and flip the stones in any way. 

Help Zahar choose such a present so that Kostya can carve a sphere of the maximum possible volume and present it to Zahar.

Input

The first line contains the integer n (1 ≤ n ≤ 105).

n lines follow, in the i-th of which there are three integers ai, bi and ci (1 ≤ ai, bi, ci ≤ 109) — the lengths of edges of the i-th stone. Note, that two stones may have exactly the same sizes, but they still will be considered two different stones.

Output

In the first line print k (1 ≤ k ≤ 2) the number of stones which Zahar has chosen. In the second line print k distinct integers from 1 to n — the numbers of stones which Zahar needs to choose. Consider that stones are numbered from 1 to n in the order as they are given in the input data.

You can print the stones in arbitrary order. If there are several answers print any of them. 

Examples

Input

6
5 5 5
3 2 4
1 4 1
2 1 3
3 2 4
3 3 4


Output

1
1


Input

7
10 7 8
5 10 3
4 2 6
5 5 5
10 2 8
4 2 1
7 7 7


Output

2
1 5

Note

In the first example we can connect the pairs of stones:

  * 2 and 4, the size of the parallelepiped: 3 × 2 × 5, the radius of the inscribed sphere 1
  * 2 and 5, the size of the parallelepiped: 3 × 2 × 8 or 6 × 2 × 4 or 3 × 4 × 4, the radius of the inscribed sphere 1, or 1, or 1.5 respectively. 
  * 2 and 6, the size of the parallelepiped: 3 × 5 × 4, the radius of the inscribed sphere 1.5
  * 4 and 5, the size of the parallelepiped: 3 × 2 × 5, the radius of the inscribed sphere 1
  * 5 and 6, the size of the parallelepiped: 3 × 4 × 5, the radius of the inscribed sphere 1.5



Or take only one stone:

  * 1 the size of the parallelepiped: 5 × 5 × 5, the radius of the inscribed sphere 2.5
  * 2 the size of the parallelepiped: 3 × 2 × 4, the radius of the inscribed sphere 1
  * 3 the size of the parallelepiped: 1 × 4 × 1, the radius of the inscribed sphere 0.5
  * 4 the size of the parallelepiped: 2 × 1 × 3, the radius of the inscribed sphere 0.5
  * 5 the size of the parallelepiped: 3 × 2 × 4, the radius of the inscribed sphere 1
  * 6 the size of the parallelepiped: 3 × 3 × 4, the radius of the inscribed sphere 1.5



It is most profitable to take only the first stone. 

Solution (in JAVA):

Solution:
import java.util.*; 
    import java.math.*;
    import java.io.*;
    import java.text.DecimalFormat;
    import java.math.BigInteger;
    public class Main{
        //static int d=20;
        static long mod=1000000007 ;
        static long mod3=1000000009 ;
        static long mod2=mod-1;
        //static HashMap<String,Integer> hm=new HashMap<>(); 
        static ArrayList<ArrayList<Integer>> arr;
        static int size;
        static long[][] fac;
        static long[][] dp;
        static int num,max;
        static int ans=0;
        static HashMap<Integer,Integer> hm;
        public static void main(String[] args)  throws IOException {
            boolean online =false;
            String fileName = "C-large";
            PrintWriter out;
            if (online) {
                s.init(new FileInputStream(new File(fileName + ".in")));
                 out= new PrintWriter(new FileWriter(fileName + "out.txt"));
            }
             else {
                s.init(System.in);   
            
                out = new PrintWriter(new BufferedWriter(new OutputStreamWriter(System.out)));
            }
            int n=s.ni();
            long[][] a=new long[n][3];
            HashMap<String,ArrayList<Integer>> hm=new HashMap<>();
            HashMap<String,ArrayList<Long>> hm2=new HashMap<>();
            ArrayList<Integer> arr=new ArrayList<>();
            long max=0;
            for(int i=0;i<n;i++){
                a[i][0]=s.nl();
                a[i][1]=s.nl();
                a[i][2]=s.nl();
                Arrays.sort(a[i]);
                String[] xx=new String[]{a[i][0]+" "+a[i][1],a[i][1]+" "+a[i][2],a[i][0]+" "+a[i][2]};;
                for(int j=0;j<xx.length;j++){
                    long a1,a2,a3;
                        if(j==0){
                            a1=a[i][0];
                            a2=a[i][1];
                            a3=a[i][2];
                        }
                        else if(j==1){
                            a1=a[i][1];
                            a2=a[i][2];
                            a3=a[i][0];
                        }
                        else{
                            a1=a[i][0];
                            a2=a[i][2];
                            a3=a[i][1];
                        }
                    if(a1<=a3 || a2<=a3)
                        continue;
                    String x=xx[j];
                    if(hm.containsKey(x)){
                        if(hm.get(x).size()==1 && hm.get(x).get(0)!=i){
                            hm.get(x).add(i);
                            hm2.get(x).add(a3);
                            

                        }
                        else{
                            if(a3>hm2.get(x).get(0) && hm.get(x).get(0)!=i && hm2.get(x).get(0)<hm2.get(x).get(1)){
                                hm2.get(x).remove(0);
                                hm2.get(x).add(a3);
                                hm.get(x).remove(0);
                                hm.get(x).add(i);
                                

                            }
                            else if(a3>hm2.get(x).get(1) && hm.get(x).get(1)!=i){
                                hm2.get(x).remove(1);
                                hm2.get(x).add(a3);
                                hm.get(x).remove(1);
                                hm.get(x).add(i);
                                

                            }


                        }
                    }
                    else{
                        ArrayList<Integer>  ar=new ArrayList<>();
                        ArrayList<Long>  ar2=new ArrayList<>();
                        ar2.add(a3);
                        ar.add(i);
                        hm.put(x,ar);
                        hm2.put(x,ar2);
    
                    }
                }
                long curr=Math.min(a[i][0],Math.min(a[i][1],a[i][2]));
                
                if(curr>max){
                    arr.clear();
                    arr.add(i+1);
                    max=curr;
                }

            } 
            for(int i=0;i<n;i++){
               
            
                String[] xx=new String[]{a[i][0]+" "+a[i][1],a[i][1]+" "+a[i][2],a[i][0]+" "+a[i][2]};;
                for(int j=0;j<xx.length;j++){
                    String x=xx[j];
                    if(!hm.containsKey(x) || !hm.get(x).contains(i))
                        continue;
                    hm.get(x).remove(hm.get(x).indexOf(i));
                    //out.println(x); 

                    for(Integer z:hm.get(x)){
                        
                        long a1,a2,a3;
                        if(j==0){
                            a1=a[i][0];
                            a2=a[i][1];
                            a3=a[i][2];
                        }
                        else if(j==1){
                            a1=a[i][1];
                            a2=a[i][2];
                            a3=a[i][0];
                        }
                        else{
                            a1=a[i][0];
                            a2=a[i][2];
                            a3=a[i][1];
                        }
                        if(a[z][0]==a1 && a[z][1]==a2 )
                            a3+=a[z][2];
                        else if(a[z][1]==a1 && a[z][2]==a2 )
                            a3+=a[z][0];
                        else
                            a3+=a[z][1];
                        //out.println(a1+" "+a2+" "+a3);
                        long curr=Math.min(a1,Math.min(a2,a3));
                
                        if(curr>max){
                            arr.clear();
                            arr.add(i+1);
                            arr.add(z+1);
                            max=curr;
                        }



                    }
                }
               
            }
            Collections.sort(arr);
            out.println(arr.size());
            for(int w:arr)
                out.print(w+" ");

            out.close();
            
        }
       
     
        static class bulb implements Comparable<bulb>{
            long cost,ecost;
            int id;
            boolean on;
            int count;
            public bulb(long x,long y,int idd,int c){
                cost=x;
                ecost=y;
                id=idd;
                count=c;
                on=true;
            }
            public int compareTo(bulb o){
                return (int)Math.signum(ecost-o.ecost);
            }
        }
        public static long pow(long a,long b,long mod){
            long ans=1;
            while(b>0){
                if(b%2==1)
                    ans=(a*ans)%mod;
                a=(a*a)%mod;
                b/=2;
            }
            return  ans;
        }
     
        public static long pow2(long a,long b){
            long ans=1;
            while(b>0){
                if(b%2==1)
                    ans=(a*ans);
                a=(a*a);
                b/=2;
            }
            return  ans;
        }
        
        public static class s {
            static BufferedReader reader;
            static StringTokenizer tokenizer;
        
            /** call this method to initialize reader for InputStream */
            static void init(InputStream input) {
                reader = new BufferedReader(
                            new InputStreamReader(input) );
                tokenizer = new StringTokenizer("");
            }   
        
            /** get next word */
            static String ns() throws IOException {
                while ( ! tokenizer.hasMoreTokens() ) {
                    //TODO add check for eof if necessary
                    tokenizer = new StringTokenizer(
                        reader.readLine() );
                }
                return tokenizer.nextToken();
            }
        
            static int ni() throws IOException {
                return Integer.parseInt( ns() );
            }
        
            static double nd() throws IOException {
                return Double.parseDouble( ns() );
            }
            static long nl() throws IOException {
                return Long.parseLong( ns() );
            }
            
        }
    }