Problem: You are a coach at your local university. There are n students under your supervision, the programming skill of the i-th student is a_i.

You have to create a team for a new programming competition. As you know, the more students some team has the more probable its victory is! So you have to create a team with the maximum number of students. But you also know that a team should be balanced. It means that the programming skill of each pair of students in a created team should differ by no more than 5.

Your task is to report the maximum possible number of students in a balanced team.

Input

The first line of the input contains one integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the number of students.

The second line of the input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9), where a_i is a programming skill of the i-th student.

Output

Print one integer — the maximum possible number of students in a balanced team.

Examples

Input


6
1 10 17 12 15 2


Output


3


Input


10
1337 1337 1337 1337 1337 1337 1337 1337 1337 1337


Output


10


Input


6
1 1000 10000 10 100 1000000000


Output


1

Note

In the first example you can create a team with skills [12, 17, 15].

In the second example you can take all students in a team because their programming skills are equal.

In the third example you can create a team consisting of a single student (and you cannot create a team consisting of at least two students).

Solution (in JAVA):

Solution:

import java.math.*;
import java.util.*;


public class Solving {
   public static void merge(int arr[], int l, int m, int r){ 
        int n1 = m - l + 1; 
        int n2 = r - m; 
  
        int L[] = new int [n1]; 
        int R[] = new int [n2]; 
  
        for (int i=0; i<n1; ++i) 
            L[i] = arr[l + i]; 
        for (int j=0; j<n2; ++j) 
            R[j] = arr[m + 1+ j]; 
  
  
        int i = 0, j = 0; 
  
        int k = l; 
        while (i < n1 && j < n2) 
        { 
            if (L[i] <= R[j]) 
            { 
                arr[k] = L[i]; 
                i++; 
            } 
            else
            { 
                arr[k] = R[j]; 
                j++; 
            } 
            k++; 
        } 
  
        while (i < n1) 
        { 
            arr[k] = L[i]; 
            i++; 
            k++; 
        } 
  
        while (j < n2) 
        { 
            arr[k] = R[j]; 
            j++; 
            k++; 
        } 
    } 
   public static void sort(int arr[], int l, int r){ 
        if (l < r) 
        { 
            int m = (l+r)/2; 
  
            sort(arr, l, m); 
            sort(arr , m+1, r); 
  
            merge(arr, l, m, r); 
        } 
    } 
   public static void main(String[] args){
      Scanner in =new Scanner(System.in);
      int n=in.nextInt();
      int[]z=new int[n];
      for(int i=0;i<n;i++)
          z[i]=in.nextInt();
      sort(z,0,z.length-1);
      int p1=0,p2=0;
      long max=0;
      while(p2<n){
          if(z[p2]-z[p1]<=5)
              p2++;
          else
              p1++;
          max=Math.max(max,p2-p1);
      }
       System.out.println(max);
   }
}