Problem: You are a coach at your local university. There are n students under your supervision, the programming skill of the i-th student is a_i.

You have to create a team for a new programming competition. As you know, the more students some team has the more probable its victory is! So you have to create a team with the maximum number of students. But you also know that a team should be balanced. It means that the programming skill of each pair of students in a created team should differ by no more than 5.

Your task is to report the maximum possible number of students in a balanced team.

Input

The first line of the input contains one integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the number of students.

The second line of the input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9), where a_i is a programming skill of the i-th student.

Output

Print one integer — the maximum possible number of students in a balanced team.

Examples

Input


6
1 10 17 12 15 2


Output


3


Input


10
1337 1337 1337 1337 1337 1337 1337 1337 1337 1337


Output


10


Input


6
1 1000 10000 10 100 1000000000


Output


1

Note

In the first example you can create a team with skills [12, 17, 15].

In the second example you can take all students in a team because their programming skills are equal.

In the third example you can create a team consisting of a single student (and you cannot create a team consisting of at least two students).

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int main() {
  long long int n;
  cin >> n;
  vector<long long int> a(n);
  for (int i = 0; i < n; i++) cin >> a[i];
  sort(a.begin(), a.end());
  long long int lo = 0, hi = 0, max_dist = -1;
  for (; hi < n && lo < n; hi++) {
    long long int dif = a[hi] - a[lo];
    long long int dist = hi - lo + 1;
    if (dif <= 5 && dist > max_dist) {
      max_dist = dist;
    }
    if (dif > 5) {
      while (dif > 5) {
        lo++;
        dif = a[hi] - a[lo];
      }
      dist = hi - lo + 1;
      if (dif <= 5 && dist > max_dist) {
        max_dist = dist;
        cout << a[lo] << " " << a[hi] << "\n";
      }
    }
  }
  cout << max_dist << "\n";
}