Problem: Amr has got a large array of size n. Amr doesn't like large arrays so he intends to make it smaller.

Amr doesn't care about anything in the array except the beauty of it. The beauty of the array is defined to be the maximum number of times that some number occurs in this array. He wants to choose the smallest subsegment of this array such that the beauty of it will be the same as the original array.

Help Amr by choosing the smallest subsegment possible.

Input

The first line contains one number n (1 ≤ n ≤ 105), the size of the array.

The second line contains n integers ai (1 ≤ ai ≤ 106), representing elements of the array.

Output

Output two integers l, r (1 ≤ l ≤ r ≤ n), the beginning and the end of the subsegment chosen respectively.

If there are several possible answers you may output any of them. 

Examples

Input

5
1 1 2 2 1


Output

1 5

Input

5
1 2 2 3 1


Output

2 3

Input

6
1 2 2 1 1 2


Output

1 5

Note

A subsegment B of an array A from l to r is an array of size r - l + 1 where Bi = Al + i - 1 for all 1 ≤ i ≤ r - l + 1

Solution (in PYTHON):

Solution:
'''
Created on 16-Jul-2015

@author: Venkatesh
'''

from collections import defaultdict


def read_int_list():
    return [int(x) for x in raw_input().split()]


def read_int():
    return int(raw_input())


def main():
    _ = read_int()
    num_lst = read_int_list()
    seg_dict = dict()
    cnt_dict = defaultdict(int)
    for idx, ele in enumerate(num_lst):
        cnt_dict[ele] += 1
        if ele in seg_dict:
            seg_dict[ele][1] = idx
        else:
            seg_dict[ele] = [idx, idx]
    max_len = max(cnt_dict.values())
    ans, seg_len = None, 1e6
    for key, val in seg_dict.iteritems():
        if cnt_dict[key] == max_len:
            cur_seg_len = val[1] - val[0] + 1
            if cur_seg_len < seg_len:
                seg_len = cur_seg_len
                ans = val
    print ans[0] + 1, ans[1] + 1


if __name__ == '__main__':
    main()