Problem: The main road in Bytecity is a straight line from south to north. Conveniently, there are coordinates measured in meters from the southernmost building in north direction.

At some points on the road there are n friends, and i-th of them is standing at the point xi meters and can move with any speed no greater than vi meters per second in any of the two directions along the road: south or north.

You are to compute the minimum time needed to gather all the n friends at some point on the road. Note that the point they meet at doesn't need to have integer coordinate. 

Input

The first line contains single integer n (2 ≤ n ≤ 60 000) — the number of friends.

The second line contains n integers x1, x2, ..., xn (1 ≤ xi ≤ 109) — the current coordinates of the friends, in meters.

The third line contains n integers v1, v2, ..., vn (1 ≤ vi ≤ 109) — the maximum speeds of the friends, in meters per second.

Output

Print the minimum time (in seconds) needed for all the n friends to meet at some point on the road. 

Your answer will be considered correct, if its absolute or relative error isn't greater than 10 - 6. Formally, let your answer be a, while jury's answer be b. Your answer will be considered correct if <image> holds.

Examples

Input

3
7 1 3
1 2 1


Output

2.000000000000


Input

4
5 10 3 2
2 3 2 4


Output

1.400000000000

Note

In the first sample, all friends can gather at the point 5 within 2 seconds. In order to achieve this, the first friend should go south all the time at his maximum speed, while the second and the third friends should go north at their maximum speeds.

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.*;

public class ProblemB {

    public static void main(String[] args) throws IOException {
        init();
        new ProblemB().run();
        out.flush();
        out.close();
    }

    static void init() throws IOException {
        in = new StreamTokenizer(new BufferedReader(new InputStreamReader(System.in)));
        out = new PrintWriter(new OutputStreamWriter(System.out));
        in.ordinaryChars(0, 65535);
        in.wordChars(0, 65535);
        in.whitespaceChars(' ', ' ');
        in.whitespaceChars('\n', '\n');
        in.whitespaceChars('\r', '\r');
    }

    // класс для пар
    class Pair<L, R> {
        private final L X;
        private final R Y;

        public Pair(L X, R Y) {
            this.X = X;
            this.Y = Y;
        }

        public L getX() {
            return X;
        }

        public R getY() {
            return Y;
        }

        @Override
        public int hashCode() {
            return X.hashCode() ^ Y.hashCode();
        }

        @Override
        public boolean equals(Object o) {
            if (!(o instanceof Pair)) return false;
            Pair pairo = (Pair) o;
            return X.equals(pairo.getX()) && Y.equals(pairo.getY());
        }
    }

    static final long INFL = 200000000000000000L;
    static final int INF = 2000000000;
    static final boolean DEBUG = true;

    static StreamTokenizer in;
    static PrintWriter out;

    static void print(String s) {
        print(s, 0);
    }

    static void print(String s, int debug) {
        if (debug == 0 || DEBUG) {
            out.print(s);
        }
    }

    static void println(String s) {
        println(s, 0);
    }

    static void println(String s, int debug) {
        if (debug == 0 || DEBUG) {
            out.println(s);
        }
    }

    static void printArray(int[] arr) {
        println(Arrays.toString(arr));
    }

    static void printArray(char[] arr) {
        println(Arrays.toString(arr));
    }

    static void printArray(String[] arr) {
        println(Arrays.toString(arr));
    }

    static void sort(int[] a) {
        Random rnd = new Random();
        for (int i = a.length - 1; i > 0; i--) {
            int index = rnd.nextInt(i);
            a[i] ^= a[index];
            a[index] ^= a[i];
            a[i] ^= a[index];
        }
        Arrays.sort(a);
    }

    static char[] inChars;
    static int inCharsInd;

    static String next() throws IOException {
        in.nextToken();
        return in.sval;
    }

    static char nextChar() throws IOException {
        while (inChars == null || inCharsInd >= inChars.length) {
            inChars = next().toCharArray();
            inCharsInd = 0;
        }
        return inChars[inCharsInd++];
    }

    static int nextInt() throws IOException {
        return Integer.valueOf(next());
    }

    static double nextDouble() throws IOException {
        return Double.valueOf(next());
    }

    static long nextLong() throws IOException {
        return Long.valueOf(next());
    }

    private void run() throws IOException {
        solve();
    }

    int K, L, M, N, P;


    class Friend {
        int distance;
        int velocity;
    }

    private void solve() throws IOException {
        N = nextInt();
        Friend[] friends = new Friend[N];

        for (int i = 0; i < N; i++) {
            friends[i] = new Friend();
            friends[i].distance = nextInt();
        }
        for (int i = 0; i < N; i++) {
            friends[i].velocity = nextInt();
        }

        Arrays.sort(friends, (o1, o2) -> (o1.distance - o2.distance));

        double left   = 0;
        double right  = INF;
        double middle;
        while (right - left > Math.pow(10, -7)){
            middle = (left + right)/2.;
            double maxL = -INFL;
            double minR = INFL;
            for (Friend friend : friends) {
                maxL = Math.max(maxL, friend.distance - friend.velocity * middle);
                minR = Math.min(minR, friend.distance + friend.velocity * middle);
            }
            if (maxL <= minR) {
                right = middle;
            } else {
                left = middle;
            }
        }

        out.println(left);
    }

}