Problem: Given is an integer N.

Takahashi chooses an integer a from the positive integers not greater than N with equal probability.

Find the probability that a is odd.

Constraints

* 1 \leq N \leq 100

Input

Input is given from Standard Input in the following format:


N


Output

Print the probability that a is odd. Your output will be considered correct when its absolute or relative error from the judge's output is at most 10^{-6}.

Examples

Input

4


Output

0.5000000000


Input

5


Output

0.6000000000


Input

1


Output

1.0000000000

Solution (in CPP):

Solution:
#include <iostream>
 
using namespace std;
 
int main(){
	
	int n;
	cin>>n;
	double odd = (n%2)+n/2;
	cout<<odd/n<<endl;
		
	return 0;
}