Problem: You are a coach at your local university. There are n students under your supervision, the programming skill of the i-th student is a_i.

You have to create a team for a new programming competition. As you know, the more students some team has the more probable its victory is! So you have to create a team with the maximum number of students. But you also know that a team should be balanced. It means that the programming skill of each pair of students in a created team should differ by no more than 5.

Your task is to report the maximum possible number of students in a balanced team.

Input

The first line of the input contains one integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the number of students.

The second line of the input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9), where a_i is a programming skill of the i-th student.

Output

Print one integer — the maximum possible number of students in a balanced team.

Examples

Input


6
1 10 17 12 15 2


Output


3


Input


10
1337 1337 1337 1337 1337 1337 1337 1337 1337 1337


Output


10


Input


6
1 1000 10000 10 100 1000000000


Output


1

Note

In the first example you can create a team with skills [12, 17, 15].

In the second example you can take all students in a team because their programming skills are equal.

In the third example you can create a team consisting of a single student (and you cannot create a team consisting of at least two students).

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int main() {
  int n, temp;
  vector<int> v;
  priority_queue<int, vector<int>, greater<int> > pq;
  cin >> n;
  for (int i = 0; i < n; i++) {
    cin >> temp;
    v.push_back(temp);
  }
  sort(v.begin(), v.end());
  int min = v[0];
  int count = 0;
  int maxcount = 0;
  for (int i = 0; i < n; i++) {
    if (i == 0) {
      pq.push(v[i]);
      count++;
    } else {
      if ((v[i] - pq.top()) <= 5) {
        pq.push(v[i]);
        count++;
      } else if (v[i] - pq.top() > 5) {
        while (count != 0) {
          pq.pop();
          count--;
          if (v[i] - pq.top() <= 5) break;
        }
        pq.push(v[i]);
        count++;
      }
    }
    if (count > maxcount) maxcount = count;
  }
  cout << maxcount << endl;
}