Problem: Kostya is a genial sculptor, he has an idea: to carve a marble sculpture in the shape of a sphere. Kostya has a friend Zahar who works at a career. Zahar knows about Kostya's idea and wants to present him a rectangular parallelepiped of marble from which he can carve the sphere. 

Zahar has n stones which are rectangular parallelepipeds. The edges sizes of the i-th of them are ai, bi and ci. He can take no more than two stones and present them to Kostya. 

If Zahar takes two stones, he should glue them together on one of the faces in order to get a new piece of rectangular parallelepiped of marble. Thus, it is possible to glue a pair of stones together if and only if two faces on which they are glued together match as rectangles. In such gluing it is allowed to rotate and flip the stones in any way. 

Help Zahar choose such a present so that Kostya can carve a sphere of the maximum possible volume and present it to Zahar.

Input

The first line contains the integer n (1 ≤ n ≤ 105).

n lines follow, in the i-th of which there are three integers ai, bi and ci (1 ≤ ai, bi, ci ≤ 109) — the lengths of edges of the i-th stone. Note, that two stones may have exactly the same sizes, but they still will be considered two different stones.

Output

In the first line print k (1 ≤ k ≤ 2) the number of stones which Zahar has chosen. In the second line print k distinct integers from 1 to n — the numbers of stones which Zahar needs to choose. Consider that stones are numbered from 1 to n in the order as they are given in the input data.

You can print the stones in arbitrary order. If there are several answers print any of them. 

Examples

Input

6
5 5 5
3 2 4
1 4 1
2 1 3
3 2 4
3 3 4


Output

1
1


Input

7
10 7 8
5 10 3
4 2 6
5 5 5
10 2 8
4 2 1
7 7 7


Output

2
1 5

Note

In the first example we can connect the pairs of stones:

  * 2 and 4, the size of the parallelepiped: 3 × 2 × 5, the radius of the inscribed sphere 1
  * 2 and 5, the size of the parallelepiped: 3 × 2 × 8 or 6 × 2 × 4 or 3 × 4 × 4, the radius of the inscribed sphere 1, or 1, or 1.5 respectively. 
  * 2 and 6, the size of the parallelepiped: 3 × 5 × 4, the radius of the inscribed sphere 1.5
  * 4 and 5, the size of the parallelepiped: 3 × 2 × 5, the radius of the inscribed sphere 1
  * 5 and 6, the size of the parallelepiped: 3 × 4 × 5, the radius of the inscribed sphere 1.5



Or take only one stone:

  * 1 the size of the parallelepiped: 5 × 5 × 5, the radius of the inscribed sphere 2.5
  * 2 the size of the parallelepiped: 3 × 2 × 4, the radius of the inscribed sphere 1
  * 3 the size of the parallelepiped: 1 × 4 × 1, the radius of the inscribed sphere 0.5
  * 4 the size of the parallelepiped: 2 × 1 × 3, the radius of the inscribed sphere 0.5
  * 5 the size of the parallelepiped: 3 × 2 × 4, the radius of the inscribed sphere 1
  * 6 the size of the parallelepiped: 3 × 3 × 4, the radius of the inscribed sphere 1.5



It is most profitable to take only the first stone. 

Solution (in JAVA):

Solution:

import java.io.*;
import java.util.*;
/**
 *
 * @author Sourav Kumar Paul (spaul100)
 * NIT Silchar    
 */

public class SolveD {

    public static Reader in;
    public static PrintWriter out;
    public static long mod = 1000000007;
    public static long inf = 100000000000000000l;
    public static long fac[],inv[];
    public static int union[];

    public static void solve(){
        int n = in.nextInt();
        int max = 0, a= -1, b= -1;
        HashMap<String, Pair> map = new HashMap<>();
        int arr[] = new int[3];
        for(int i=0; i<n; i++)
        {
            int temp = Integer.MAX_VALUE;
            for(int j=0; j<3; j++)
            {
                arr[j] = in.nextInt();
                temp = Math.min(arr[j], temp);
            }
            if(temp > max)
            {
                max = temp;
                a = i;
                b= -1;
            }
            Arrays.sort(arr);
            int val = arr[2], pos = i;
            if(map.containsKey(arr[0]+" "+arr[1]))
            {
                Pair pp = map.get(arr[0] +" "+arr[1]);
                temp = Math.min(pp.x + arr[2], Math.min(arr[0], arr[1]));
                if(pos != pp.y && temp > max)
                {
                    max = temp;
                    a = i;
                    b = pp.y;
                }
                
                if(pp.x > val)
                {
                    val = pp.x;
                    pos = pp.y;
                }
            }
            map.put(arr[0]+" "+arr[1], new Pair(val,pos));
            
            val = arr[0]; pos = i;
            if(map.containsKey(arr[1]+" "+arr[2]))
            {
                Pair pp = map.get(arr[1] +" "+arr[2]);
                temp = Math.min(pp.x + arr[0], Math.min(arr[1], arr[2]));
                if(pos != pp.y && temp > max)
                {
                    max = temp;
                    a = i;
                    b = pp.y;
                }
                
                if(pp.x > val)
                {
                    val = pp.x;
                    pos = pp.y;
                }
            }
            map.put(arr[1]+" "+arr[2], new Pair(val,pos));
            
            val = arr[1]; pos = i;
            if(map.containsKey(arr[0]+" "+arr[2]))
            {
                Pair pp = map.get(arr[0] +" "+arr[2]);
                temp = Math.min(pp.x + arr[1], Math.min(arr[0], arr[2]));
                if(pos != pp.y && temp > max)
                {
                    max = temp;
                    a = i;
                    b = pp.y;
                }
                
                if(pp.x > val)
                {
                    val = pp.x;
                    pos = pp.y;
                }
            }
            map.put(arr[0]+" "+arr[2], new Pair(val,pos));
            
        }
        
        if(b==-1)
        {
            out.println(1);
            out.println(a+1);
        }
        else
        {
            out.println(2);
            out.println((a+1)+" "+(b+1));
          //  out.println(b+1);
        }
    }

/**
 *  ############################### Template ################################
 */
    

    public static class Pair implements Comparable{
        int x,y;
       
        Pair(int x, int y)
        {
            this.x = x;
            this.y = y;
        }
        @Override
        public int compareTo(Object o)
        {
            Pair pp = (Pair)o;
            if(pp.x == x)
                return 0;
            else if (x>pp.x)
                return 1;
            else 
                return -1;
        }
    }

   
    public static void init()
    {
        for(int i=0; i<union.length; i++)
            union[i] = i;
    }
    public static int find(int n)
    {
        return (union[n]==n)?n:(union[n]=find(union[n]));
    }
    public static void unionSet(int i ,int j)
    {
        union[find(i)]=find(j);
    }
    public static boolean connected(int i,int j)
    {   
        return union[i]==union[j];
    }

    public static long gcd(long a, long b) {
        long x = Math.min(a,b);
        long y = Math.max(a,b);
        while(x!=0)
        {
            long temp = x;
            x = y%x;
            y = temp;
        }
        return y;       
    }

    public static long modPow(long base, long exp, long mod) {
        base = base % mod;
        long result =1;
        while(exp > 0)
        {
            if(exp % 2== 1)
            {
                result = (result * base) % mod;
                exp --;
            }
            else
            {
                base = (base * base) % mod;
                exp = exp >> 1;
            }
            
        }
        return result;
    }
    
    public static void cal()
    {
        fac = new long[1000005];
        inv = new long[1000005];
        fac[0]=1;
        inv[0]=1;
        for(int i=1; i<=1000000; i++)
        {
            fac[i]=(fac[i-1]*i)%mod;
            inv[i]=(inv[i-1]*modPow(i,mod-2,mod))%mod;
        }
    }
    public static long ncr(int n, int r)
    {
        return (((fac[n]*inv[r])%mod)*inv[n-r])%mod;
    }


    SolveD() throws IOException {
	in = new Reader(new InputStreamReader(System.in));
        out = new PrintWriter(new OutputStreamWriter(System.out));
	solve();
        out.flush();
	out.close();
    }
 
    public static void main(String args[]) {
	new Thread(null, new Runnable() {
            public void run() {
                try {
                    new SolveD();
		} catch (Exception e) {
                    e.printStackTrace();
		}
            }
	}, "1", 1 << 26).start();
    }
    
    public static class Reader {
        public BufferedReader reader;
        public StringTokenizer st;

        public Reader(InputStreamReader stream) {
            reader = new BufferedReader(stream);
            st = null;
        }

        public String next() {
            while (st == null || !st.hasMoreTokens()) {
                try {
                    st = new StringTokenizer(reader.readLine());
                } catch (IOException e) {
                    throw new RuntimeException(e);
                }
            }
            return st.nextToken();
        }

        public int nextInt() {
            return Integer.parseInt(next());
        }
        public String nextLine() throws IOException{
            return reader.readLine();
        }
        public long nextLong(){
            return Long.parseLong(next());
        }
        public double nextDouble(){
            return Double.parseDouble(next());
        }

    }
}