Problem: You are a coach at your local university. There are n students under your supervision, the programming skill of the i-th student is a_i.

You have to create a team for a new programming competition. As you know, the more students some team has the more probable its victory is! So you have to create a team with the maximum number of students. But you also know that a team should be balanced. It means that the programming skill of each pair of students in a created team should differ by no more than 5.

Your task is to report the maximum possible number of students in a balanced team.

Input

The first line of the input contains one integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the number of students.

The second line of the input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9), where a_i is a programming skill of the i-th student.

Output

Print one integer — the maximum possible number of students in a balanced team.

Examples

Input


6
1 10 17 12 15 2


Output


3


Input


10
1337 1337 1337 1337 1337 1337 1337 1337 1337 1337


Output


10


Input


6
1 1000 10000 10 100 1000000000


Output


1

Note

In the first example you can create a team with skills [12, 17, 15].

In the second example you can take all students in a team because their programming skills are equal.

In the third example you can create a team consisting of a single student (and you cannot create a team consisting of at least two students).

Solution (in JAVA):

Solution:


import java.io.*;
import java.util.Arrays;
import java.util.StringTokenizer;

public class C {
    String filename = null;
    final int INF = 1_000_000_000;

    void solve() {
        int n = readInt();
        int[] a = new int[n];
        for(int i = 0;i<n;i++) a[i] = readInt();
        Integer[] aObj = new Integer[n];
        for (int i = 0; i < n; ++i) aObj[i] = a[i];
        Arrays.sort(aObj);
        for (int i = 0; i < n; ++i) a[i] = aObj[i];
        int ans = 0;
        for (int left = 0, right = 0; left < n; left++) {
            while (right < n - 1 && a[right + 1] - a[left] <= 5) {
                right++;
            }
            ans = Math.max(ans, right - left + 1);
        }
        out.print(ans);
    }

    public static void main(String[] args) {
        new C().run();
    }
    private void run() {
        try {
            init();
            solve();
            out.close();
        } catch (Exception e) {
            e.printStackTrace();
            System.exit(-1);
        }
    }

    private BufferedReader in;
    private StringTokenizer tok = new StringTokenizer("");

    private PrintWriter out;

    private void init() {
        if (filename == null) {
            in = new BufferedReader(new InputStreamReader(System.in));
            out = new PrintWriter(System.out);
            return;
        }

        try {
            in = new BufferedReader(new FileReader(new File(filename)));
            out = new PrintWriter(new File(filename));
        } catch (FileNotFoundException e) {
            e.printStackTrace();
        }

    }
    private String readLine() {
        try {
            return in.readLine();
        } catch (IOException e) {
            throw new RuntimeException(e);
        }
    }

    private String readString() {
        while (!tok.hasMoreTokens()) {
            String nextLine = readLine();
            if (nextLine == null) return null;
            tok = new StringTokenizer(nextLine);
        }

        return tok.nextToken();
    }

    private int readInt() {
        return Integer.parseInt(readString());
    }

    private long readLong() {
        return Long.parseLong(readString());
    }
}