Problem: I have a sequence defined as follows:

* All even-numbered terms are equal to the previous term multiplied by 2.
* All odd-numbered terms are equal to the previous term divided by 3.



Create a program that reads the first term a of this sequence and outputs the sum s (10) from the first term to the tenth term.



Input

The input consists of multiple test cases. For each test case, a real number a (1.0 ≤ a ≤ 10.0) representing the first term of the sequence is given in one row.

The number of test cases does not exceed 50.

Output

Print s (10) on one line for each test case.

The output may contain an error of 0.000001 or less.

Example

Input

1.0
2.0
3.0


Output

7.81481481
15.62962963
23.44444444

Solution (in CPP):

Solution:
#include <iostream>
#include <cstdio>
using namespace std ;

int main()
{
	double ary[10] ;

	while( cin >> ary[0] )
	{
		double sum = ary[0] ;
		for( int i = 1 ; i < 10 ; i ++ )
		{
			if( i %2 == 1 ){ ary[i] = ary[i-1]*2 ; }
			else if( i %2 == 0 ){ ary[i] = ary[i-1]/3 ; }
			sum += ary[i] ;
		}
		printf("%.8f\n",sum) ;
	}
	return 0 ;
}