Problem: You are a coach at your local university. There are n students under your supervision, the programming skill of the i-th student is a_i.

You have to create a team for a new programming competition. As you know, the more students some team has the more probable its victory is! So you have to create a team with the maximum number of students. But you also know that a team should be balanced. It means that the programming skill of each pair of students in a created team should differ by no more than 5.

Your task is to report the maximum possible number of students in a balanced team.

Input

The first line of the input contains one integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the number of students.

The second line of the input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9), where a_i is a programming skill of the i-th student.

Output

Print one integer — the maximum possible number of students in a balanced team.

Examples

Input


6
1 10 17 12 15 2


Output


3


Input


10
1337 1337 1337 1337 1337 1337 1337 1337 1337 1337


Output


10


Input


6
1 1000 10000 10 100 1000000000


Output


1

Note

In the first example you can create a team with skills [12, 17, 15].

In the second example you can take all students in a team because their programming skills are equal.

In the third example you can create a team consisting of a single student (and you cannot create a team consisting of at least two students).

Solution (in PYTHON3):

Solution:
n, K = map(int, input().split())
arr = sorted(map(int, input().split()))
freq = {}
for x in arr:
    freq[x] = freq.get(x, 0)+1
arr = sorted(freq.keys())
freq = [freq[x] for x in arr]
n = len(arr)

dp = [[0 for _ in range(n+1)] for _ in range(2)]
for k in range(1, K+1):
    for i in range(n-1, -1, -1):
        j = i
        curr = 0
        curr_ans = dp[k&1][i+1]
        while j < n and abs(arr[i]-arr[j]) <= 5:
            curr += freq[j]
            curr_ans = max(curr_ans, curr+dp[1-(k&1)][j+1])
            j += 1
        dp[k&1][i] = curr_ans
print(dp[K&1][0])