Problem: Long time ago Alex created an interesting problem about parallelogram. The input data for this problem contained four integer points on the Cartesian plane, that defined the set of vertices of some non-degenerate (positive area) parallelogram. Points not necessary were given in the order of clockwise or counterclockwise traversal.

Alex had very nice test for this problem, but is somehow happened that the last line of the input was lost and now he has only three out of four points of the original parallelogram. He remembers that test was so good that he asks you to restore it given only these three points.

Input

The input consists of three lines, each containing a pair of integer coordinates xi and yi ( - 1000 ≤ xi, yi ≤ 1000). It's guaranteed that these three points do not lie on the same line and no two of them coincide.

Output

First print integer k — the number of ways to add one new integer point such that the obtained set defines some parallelogram of positive area. There is no requirement for the points to be arranged in any special order (like traversal), they just define the set of vertices.

Then print k lines, each containing a pair of integer — possible coordinates of the fourth point.

Example

Input

0 0
1 0
0 1


Output

3
1 -1
-1 1
1 1

Note

If you need clarification of what parallelogram is, please check Wikipedia page:

https://en.wikipedia.org/wiki/Parallelogram

Solution (in JAVA):

Solution:
import java.util.Scanner;

/**
 * Created by Vadim on 19-Dec-16.
 */
public class prog_B {
    public static void main(String[] args)
    {
        Scanner in = new Scanner(System.in);
        int x1 = in.nextInt();
        int y1 = in.nextInt();
        int x2 = in.nextInt();
        int y2 = in.nextInt();
        int x3 = in.nextInt();
        int y3 = in.nextInt();
        Point p1 = new Point(x1,y1);
        Point p2 = new Point(x2,y2);
        Point p3 = new Point(x3,y3);
        Vector v1 = new Vector(p1,p2);
        Vector v2 = new Vector(p1,p3);

        System.out.println(3);
        Vector vv1 = VectSum(v1,v2);
        Vector vv2 = VectMinus(v1,v2);
        Vector vv3 = VectMinus(v2,v1);
        System.out.println((vv1.x+x1)+" "+(vv1.y+y1));
        System.out.println((vv2.x+x1)+" "+(vv2.y+y1));
        System.out.println((vv3.x+x1)+" "+(vv3.y+y1));
    }

    private static Vector VectSum(Vector v1, Vector v2)
    {
        Vector v3 = new Vector();
        v3.x = v1.x+ v2.x;
        v3.y = v1.y + v2.y;
        return v3;
    }

    private static Vector VectMinus(Vector v1, Vector v2)
    {
        Vector v3 = new Vector();
        v3.x = v1.x- v2.x;
        v3.y = v1.y - v2.y;
        return v3;
    }

    /**
     * Vectors multiply
     * @param p1
     * @param p2
     * @return
             */
    public static int VectorMult (Vector p1,Vector p2)
    {
        return p1.x*p2.x + p1.y*p2.y;
    }

    /**
     * point defenition
     */
    public static class Point
    {
        private int x,y;
        public Point(int x, int y)
        {
            this.x=x;
            this.y=y;
        }
    }

    /**
     * vector defenition
     */
    public static class Vector
    {
        private int x,y;
        public Vector()
        {
            x=0;
            y=0;
        }
        public Vector(Point start, Point end)
        {
            this.x = end.x - start.x;
            this.y = end.y - start.y;
        }
        /*public Vector VectSum(Vector v1, Vector v2)
        {
            Vector v3 = new Vector();
            v3.x = v1.x+ v2.x;
            v3.y = v1.y + v2.y;
            return v3;
        }*/
    }
}