Problem: As you know, the most intelligent beings on the Earth are, of course, cows. This conclusion was reached long ago by the Martian aliens, as well as a number of other intelligent civilizations from outer space. 

Sometimes cows gather into cowavans. This seems to be seasonal. But at this time the cows become passive and react poorly to external stimuli. A cowavan is a perfect target for the Martian scientific saucer, it's time for large-scale abductions, or, as the Martians say, raids. Simply put, a cowavan is a set of cows in a row. 

If we number all cows in the cowavan with positive integers from 1 to n, then we can formalize the popular model of abduction, known as the (a, b)-Cowavan Raid: first they steal a cow number a, then number a + b, then — number a + 2·b, and so on, until the number of an abducted cow exceeds n. During one raid the cows are not renumbered. 

The aliens would be happy to place all the cows on board of their hospitable ship, but unfortunately, the amount of cargo space is very, very limited. The researchers, knowing the mass of each cow in the cowavan, made p scenarios of the (a, b)-raid. Now they want to identify the following thing for each scenario individually: what total mass of pure beef will get on board of the ship. All the scenarios are independent, in the process of performing the calculations the cows are not being stolen. 

<image>

Input

The first line contains the only positive integer n (1 ≤ n ≤ 3·105) — the number of cows in the cowavan.

The second number contains n positive integer wi, separated by spaces, where the i-th number describes the mass of the i-th cow in the cowavan (1 ≤ wi ≤ 109).

The third line contains the only positive integer p — the number of scenarios of (a, b)-raids (1 ≤ p ≤ 3·105).

Each following line contains integer parameters a and b of the corresponding scenario (1 ≤ a, b ≤ n).

Output

Print for each scenario of the (a, b)-raid the total mass of cows, that can be stolen using only this scenario.

Please, do not use the %lld specificator to read or write 64-bit integers in С++. It is recommended to use the cin, cout streams of the %I64d specificator.

Examples

Input

3
1 2 3
2
1 1
1 2


Output

6
4


Input

4
2 3 5 7
3
1 3
2 3
2 2


Output

9
3
10

Solution (in JAVA):

Solution:
import java.io.*;
import java.math.BigInteger;
import java.util.*;

public class Main implements Runnable {

    // leave empty to read from stdin/stdout
    private static final String TASK_NAME_FOR_IO = "";

    // file names
    private static final String FILE_IN = TASK_NAME_FOR_IO + ".in";
    private static final String FILE_OUT = TASK_NAME_FOR_IO + ".out";

    BufferedReader in;
    PrintWriter out;
    StringTokenizer tokenizer = new StringTokenizer("");

    public static void main(String[] args) {
        new Thread(new Main()).start();
    }

    Random rnd;

    private void solve() throws IOException {
        int n = nextInt();
        int []a = new int[n + 1];
        for(int i = 1; i <= n; ++i) a[i] = nextInt();
        int T = nextInt();
        Q []q = new Q[T];
        for(int i = 0; i < T; ++i) {
            q[i] = new Q(nextInt(), nextInt(), i);
        }
        rnd = new Random();
        // sort(0, T - 1, q);
        Arrays.sort(q);
        // System.out.println(Arrays.toString(q));

        int border = (int)Math.sqrt(n + 1e-3);
        long []sum = new long[n + 1];
        long []ret = new long[T];
        int prev = -1;
        for(int i = 0; i < T; ++i) {
            if (prev == q[i].b) {
                ret[q[i].id] = sum[q[i].a];
                continue;
            }
            if (q[i].b >= border) {
                long s = 0;
                for(int j = q[i].a; j <= n; j+=q[i].b) {
                    s+=a[j];
                }
                ret[q[i].id] = s;
            }else {
                prev = q[i].b;
                for(int j = n;j > 0; --j) {
                    sum[j] = a[j];
                    if (j + q[i].b <= n) {
                        sum[j]+=sum[j + q[i].b];
                    }
                }
                ret[q[i].id] = sum[q[i].a];
            }
        }
        for(long i : ret) {
            out.println(i);
        }
    }

    private void sort(int l, int r, Q []q) {
        int m = rnd.nextInt(r - l  + 1);
        Q pivot = q[m].clone();
        int i = l, j = r;
        while(i <= j) {
            while(pivot.compareTo(q[i]) > 0) i++;
            while(pivot.compareTo(q[j]) < 0) j--;
            if (i <= j) {
                Q tmp = q[i];
                q[i] = q[j];
                q[j] = tmp;
                i++;j--;
            }
        }

        if (l < j) sort(l, j, q);
        if (i < r) sort(i, r, q);
    }

    class Q implements Comparable<Q>{
        int a, b, id;
        public Q(int a, int b, int id) {
            this.a = a;
            this.b = b;
            this.id = id;
        }

        public int compareTo(Q other) {
            return this.b - other.b;
        }

        public Q clone() {
            return new Q(a, b, id);
        }

        public String toString() {
            return ""+this.b;
        }
    }

    public void run() {
        long timeStart = System.currentTimeMillis();

        boolean fileIO = TASK_NAME_FOR_IO.length() > 0;
        try {

            if (fileIO) {
                in = new BufferedReader(new FileReader(FILE_IN));
                out = new PrintWriter(new FileWriter(FILE_OUT));
            } else {
                in = new BufferedReader(new InputStreamReader(System.in));
                out = new PrintWriter(new OutputStreamWriter(System.out));
            }

            solve();

            in.close();
            out.close();
        } catch (IOException e) {
            throw new IllegalStateException(e);
        }
        long timeEnd = System.currentTimeMillis();

        if (fileIO) {
            System.out.println("Time spent: " + (timeEnd - timeStart) + " ms");
        }
    }

    private String nextToken() throws IOException {
        while (!tokenizer.hasMoreTokens()) {
            String line = in.readLine();
            if (line == null) {
                return null;
            }
            tokenizer = new StringTokenizer(line);
        }
        return tokenizer.nextToken();
    }

    private int nextInt() throws IOException {
        return Integer.parseInt(nextToken());
    }

    private BigInteger nextBigInt() throws IOException {
        return new BigInteger(nextToken());
    }

    private long nextLong() throws IOException {
        return Long.parseLong(nextToken());
    }

    private double nextDouble() throws IOException {
        return Double.parseDouble(nextToken());
    }

}