Problem: Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reorderings that achieve it.

Constraints

* 1\leq N \leq 2 \times 10^5
* 1\leq A_i,B_i \leq N
* A and B are each sorted in the ascending order.
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N
A_1 A_2 \cdots A_N
B_1 B_2 \cdots B_N


Output

If there exist no reorderings that satisfy the condition, print `No`.

If there exists a reordering that satisfies the condition, print `Yes` on the first line. After that, print a reordering of B on the second line, separating terms with a whitespace.

If there are multiple reorderings that satisfy the condition, you can print any of them.

Examples

Input

6
1 1 1 2 2 3
1 1 1 2 2 3


Output

Yes
2 2 3 1 1 1


Input

3
1 1 2
1 1 3


Output

No


Input

4
1 1 2 3
1 2 3 3


Output

Yes
3 3 1 2

Solution (in PYTHON3):

Solution:
n = int(input())
a = list(map(int,input().split()))
b = list(map(int,input().split()))
b.reverse()
p = 1
c = 0
d = 0
for i in range(n):
    if a[i] == b[i]:
        v = a[i]
        h = i
        p = 0
        break
if p == 1:
    print('Yes')
    for i in range(n):
        print(b[i],end = ' ')
else:
    for i in range(n):
        if a[i] != v and b[i] != v:
            c += 1
        if b[i] == a[i] :
            d += 1
    if c < d:
        print('No')
    else:
        print('Yes')
        o = 0
        for i in range(n):
            if a[i] != v and b[i] != v:
                b[i],b[h+o] = b[o+h],b[i]
                o += 1
                if o == d:
                    break
        for i in range(n):
            print(b[i],end = ' ')