Problem: Amr has got a large array of size n. Amr doesn't like large arrays so he intends to make it smaller.

Amr doesn't care about anything in the array except the beauty of it. The beauty of the array is defined to be the maximum number of times that some number occurs in this array. He wants to choose the smallest subsegment of this array such that the beauty of it will be the same as the original array.

Help Amr by choosing the smallest subsegment possible.

Input

The first line contains one number n (1 ≤ n ≤ 105), the size of the array.

The second line contains n integers ai (1 ≤ ai ≤ 106), representing elements of the array.

Output

Output two integers l, r (1 ≤ l ≤ r ≤ n), the beginning and the end of the subsegment chosen respectively.

If there are several possible answers you may output any of them. 

Examples

Input

5
1 1 2 2 1


Output

1 5

Input

5
1 2 2 3 1


Output

2 3

Input

6
1 2 2 1 1 2


Output

1 5

Note

A subsegment B of an array A from l to r is an array of size r - l + 1 where Bi = Al + i - 1 for all 1 ≤ i ≤ r - l + 1

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.FileReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.OutputStream;
import java.io.PrintWriter;
import java.util.StringTokenizer;

public class Main {

	public static void main(String[] args) {
		InputStream inputStream = System.in;
		OutputStream outputStream = System.out;
		InputReader in = new InputReader(inputStream);
		PrintWriter out = new PrintWriter(outputStream);
		Task solver = new Task();
		solver.solve(in, out);
		out.close();
	}
	
}

class Task {
	public void solve(InputReader in, PrintWriter out) {
		int n = in.nextInt();
		int[] nums = new int[n];
		for (int i = 0; i < n; i++)
			nums[i] = in.nextInt();
		int[] occurs = new int[1000005];
		int[] starts = new int[1000005];
		int[] ends = new int[1000005];
		for (int i = 0; i < 1000005; i++)
			starts[i] = -1;
		for (int i = 0; i < n; i++) {
			occurs[nums[i]]++;
			if (starts[nums[i]] == -1)
				starts[nums[i]] = i;
			ends[nums[i]] = i;
		}
		int mx = 0;
		for (int i = 1; i <= 1000000; i++) {
			if (occurs[i] > occurs[mx])
				mx = i;
			else if (occurs[i] == occurs[mx])
				if (ends[i] - starts[i] < ends[mx] - starts[mx])
					mx = i;
		}
		out.println((starts[mx]+1) + " " + (ends[mx]+1));
	}
}

class InputReader {
	private BufferedReader input;
	private StringTokenizer line = new StringTokenizer("");
	public InputReader() {
		this(System.in);
	}
	public InputReader(InputStream in) {
		input = new BufferedReader(new InputStreamReader(in));
	}
	public InputReader(String s) {
		try {
			input = new BufferedReader(new FileReader(s));
		} catch(IOException io) { io.printStackTrace(); System.exit(0);}
	}
	public void fill() {
		try {
			if(!line.hasMoreTokens()) line = new StringTokenizer(input.readLine());
		} catch(IOException io) { io.printStackTrace(); System.exit(0);}
	}

	public int nextInt() {
		fill();
		return Integer.parseInt(line.nextToken());
	}
	
	public double nextDouble() {
		fill();
		return Double.parseDouble(line.nextToken());
	}
	
	public String nextString() {
		fill();
		return line.nextToken();
	}
}