Problem: There are two persons, numbered 0 and 1, and a variable x whose initial value is 0. The two persons now play a game. The game is played in N rounds. The following should be done in the i-th round (1 \leq i \leq N):

* Person S_i does one of the following:
* Replace x with x \oplus A_i, where \oplus represents bitwise XOR.
* Do nothing.



Person 0 aims to have x=0 at the end of the game, while Person 1 aims to have x \neq 0 at the end of the game.

Determine whether x becomes 0 at the end of the game when the two persons play optimally.

Solve T test cases for each input file.

Constraints

* 1 \leq T \leq 100
* 1 \leq N \leq 200
* 1 \leq A_i \leq 10^{18}
* S is a string of length N consisting of `0` and `1`.
* All numbers in input are integers.

Input

Input is given from Standard Input in the following format. The first line is as follows:


T


Then, T test cases follow. Each test case is given in the following format:


N
A_1 A_2 \cdots A_N
S


Output

For each test case, print a line containing `0` if x becomes 0 at the end of the game, and `1` otherwise.

Example

Input

3
2
1 2
10
2
1 1
10
6
2 3 4 5 6 7
111000


Output

1
0
0

Solution (in PYTHON3):

Solution:
import sys
from copy import deepcopy

def canMake(k, Nums):#Numsにある数でkを作れるか
    L = len(Nums)
    index = 0
    bit = []
    for i in reversed(range(60)):
        flag = 0
        for j in range(index, L):
            if Nums[j] & (1 << i) == (1 << i):
                flag = 1
                Nums[index], Nums[j] = Nums[j], Nums[index]
                bit.append(i)
                break
        if flag == 1:
            for j in range(L):
                if Nums[j] & (1 << i) == (1 << i) and index != j: Nums[j] ^= Nums[index]
        if flag == 1: index += 1
    ans = 0
    for i in range(60):
        if k & (1 << i) == (1 << i):
            if i in bit: ans ^= Nums[bit.index(i)]
    if ans == k: return True
    else: return False


def solve():
    input = sys.stdin.readline
    T = int(input())
    Ans = [0] * T
    for t in range(T):
        N = int(input())
        A = [int(a) for a in input().split()]
        S = input().strip("\n")
        used = []
        for i in reversed(range(N)):
            if S[i] == "0":
                used.append(A[i])
            else:
                compare = deepcopy(used)
                if not canMake(A[i], compare):
                    Ans[t] = 1
                    break
    
    print(*Ans, sep="\n")

    return 0

if __name__ == "__main__":
    solve()