Problem: Snuke, a water strider, lives in a rectangular pond that can be seen as a grid with H east-west rows and W north-south columns. Let (i,j) be the square at the i-th row from the north and j-th column from the west.

Some of the squares have a lotus leaf on it and cannot be entered. The square (i,j) has a lotus leaf on it if c_{ij} is `@`, and it does not if c_{ij} is `.`.

In one stroke, Snuke can move between 1 and K squares (inclusive) toward one of the four directions: north, east, south, and west. The move may not pass through a square with a lotus leaf. Moving to such a square or out of the pond is also forbidden.

Find the minimum number of strokes Snuke takes to travel from the square (x_1,y_1) to (x_2,y_2). If the travel from (x_1,y_1) to (x_2,y_2) is impossible, point out that fact.

Constraints

* 1 \leq H,W,K \leq 10^6
* H \times W \leq 10^6
* 1 \leq x_1,x_2 \leq H
* 1 \leq y_1,y_2 \leq W
* x_1 \neq x_2 or y_1 \neq y_2.
* c_{i,j} is `.` or `@`.
* c_{x_1,y_1} = `.`
* c_{x_2,y_2} = `.`
* All numbers in input are integers.

Input

Input is given from Standard Input in the following format:


H W K
x_1 y_1 x_2 y_2
c_{1,1}c_{1,2} .. c_{1,W}
c_{2,1}c_{2,2} .. c_{2,W}
:
c_{H,1}c_{H,2} .. c_{H,W}


Output

Print the minimum number of strokes Snuke takes to travel from the square (x_1,y_1) to (x_2,y_2), or print `-1` if the travel is impossible.

Examples

Input

3 5 2
3 2 3 4
.....
.@..@
..@..


Output

5


Input

1 6 4
1 1 1 6
......


Output

2


Input

3 3 1
2 1 2 3
.@.
.@.
.@.


Output

-1

Solution (in PYTHON3):

Solution:
# coding: utf-8
# Your code here!

from collections import deque
# from pprint import pprint
moves=[(0,1),(1,0),(0,-1),(-1,0)]
# pp=pprint
INF=float("inf")

h,w,k=map(int,input().split())
x1,y1,x2,y2=map(lambda x:int(x)-1,input().split())
maze=[list(input()) for _ in range(h)]
cost=[[INF]*w for _ in range(h)]

todo=deque()
todo.append((x1,y1))
cost[x1][y1]=0

while todo:
    x,y=todo.popleft()
    for vx,vy in moves:
        for kk in range(1,k+1):
            nx=x+vx*kk
            ny=y+vy*kk
            if not(0<=nx<h) or not(0<=ny<w):
                break
                # 更に伸ばす必要はない
            if maze[nx][ny]=="@":
                break
                # 蓮の向こうにはいけないので
            if cost[nx][ny]<=cost[x][y]:
                break
                # 更新を1回以上受けていて、更に良くならない場合はbreak
            if cost[nx][ny]==INF:
                cost[nx][ny]=cost[x][y]+1
                todo.append((nx,ny))
                # 更新されてなければ、[x][y]から1マス先を更新、キューに突っ込む


# pp(cost)
ans=cost[x2][y2]
if ans==INF:ans=-1
print(ans)