Problem: You are a coach at your local university. There are n students under your supervision, the programming skill of the i-th student is a_i.

You have to create a team for a new programming competition. As you know, the more students some team has the more probable its victory is! So you have to create a team with the maximum number of students. But you also know that a team should be balanced. It means that the programming skill of each pair of students in a created team should differ by no more than 5.

Your task is to report the maximum possible number of students in a balanced team.

Input

The first line of the input contains one integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the number of students.

The second line of the input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9), where a_i is a programming skill of the i-th student.

Output

Print one integer — the maximum possible number of students in a balanced team.

Examples

Input


6
1 10 17 12 15 2


Output


3


Input


10
1337 1337 1337 1337 1337 1337 1337 1337 1337 1337


Output


10


Input


6
1 1000 10000 10 100 1000000000


Output


1

Note

In the first example you can create a team with skills [12, 17, 15].

In the second example you can take all students in a team because their programming skills are equal.

In the third example you can create a team consisting of a single student (and you cannot create a team consisting of at least two students).

Solution (in JAVA):

Solution:
import java.util.Arrays;
import java.util.Scanner;

public class ProblemaL {
	
	public static void main(String[] args) {
	
		Scanner sc = new Scanner(System.in);
		
		int n = sc.nextInt();
		
		sc.nextLine();
		
		String line = sc.nextLine();
		
		String[] lineSplit = line.split(" ");
		
		Integer[] array = new Integer[n];
		
		fillArray(line, array);
		
		Arrays.sort(array);
		int max = 0;
		
		int j = 0;
		
		for(int i = 0; i < n; i++) {
			
			int rightLimit = array[i] + 5;
			
			while(j < n && array[j] <= rightLimit) {
				
				j++;
				
			}
			int cont = j - i;
			if (cont > max) {
				max = cont;
			}
			
		}
		
		System.out.println(max);
		
		
	
	}
	
	private static void fillArray(String linha, Integer[] array) {
		
		String[] aux = linha.split(" ");
		
		for(int i = 0; i < array.length; i++) {
			
			array[i] = Integer.parseInt(aux[i]);
		}
		
	}


}