Problem: There are two persons, numbered 0 and 1, and a variable x whose initial value is 0. The two persons now play a game. The game is played in N rounds. The following should be done in the i-th round (1 \leq i \leq N):

* Person S_i does one of the following:
* Replace x with x \oplus A_i, where \oplus represents bitwise XOR.
* Do nothing.



Person 0 aims to have x=0 at the end of the game, while Person 1 aims to have x \neq 0 at the end of the game.

Determine whether x becomes 0 at the end of the game when the two persons play optimally.

Solve T test cases for each input file.

Constraints

* 1 \leq T \leq 100
* 1 \leq N \leq 200
* 1 \leq A_i \leq 10^{18}
* S is a string of length N consisting of `0` and `1`.
* All numbers in input are integers.

Input

Input is given from Standard Input in the following format. The first line is as follows:


T


Then, T test cases follow. Each test case is given in the following format:


N
A_1 A_2 \cdots A_N
S


Output

For each test case, print a line containing `0` if x becomes 0 at the end of the game, and `1` otherwise.

Example

Input

3
2
1 2
10
2
1 1
10
6
2 3 4 5 6 7
111000


Output

1
0
0

Solution (in CPP):

Solution:
#include<iostream>
#include<cstdio>
#include<cmath>
#include<cstring>
#include<algorithm>
using namespace std;
typedef long long ll;
int T,n;
ll a[203],num[64];
int s[203];
bool ins(ll x)
{
	for(int i=62;i>=0;i--)
		if((x>>i)&1)
		{
			if(num[i]==0)
			{
				num[i]=x;
				return true;
			}
			x^=num[i];
		}
	return false;
}
int main()
{
	scanf("%d",&T);
	while(T--)
	{
		scanf("%d",&n);
		for(int i=1;i<=n;i++)
			scanf("%lld",&a[i]);
		for(int i=1;i<=n;i++)
			scanf("%1d",&s[i]);
		memset(num,0,sizeof(num));
		int ans=0;
		for(int i=n;i;i--)
		{
			if(s[i]==0) ins(a[i]);
			else if(ins(a[i]))
			{
				ans=1;
				break;
			}
		}
		printf("%d\n",ans);
	}
	return 0;
}