Problem: You are a coach at your local university. There are n students under your supervision, the programming skill of the i-th student is a_i.

You have to create a team for a new programming competition. As you know, the more students some team has the more probable its victory is! So you have to create a team with the maximum number of students. But you also know that a team should be balanced. It means that the programming skill of each pair of students in a created team should differ by no more than 5.

Your task is to report the maximum possible number of students in a balanced team.

Input

The first line of the input contains one integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the number of students.

The second line of the input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9), where a_i is a programming skill of the i-th student.

Output

Print one integer — the maximum possible number of students in a balanced team.

Examples

Input


6
1 10 17 12 15 2


Output


3


Input


10
1337 1337 1337 1337 1337 1337 1337 1337 1337 1337


Output


10


Input


6
1 1000 10000 10 100 1000000000


Output


1

Note

In the first example you can create a team with skills [12, 17, 15].

In the second example you can take all students in a team because their programming skills are equal.

In the third example you can create a team consisting of a single student (and you cannot create a team consisting of at least two students).

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
string tostr(int n) {
  stringstream rr;
  rr << n;
  return rr.str();
}
int main() {
  ios_base::sync_with_stdio(false);
  cin.tie(NULL);
  long long n;
  cin >> n;
  vector<long long> a(n + 1);
  for (int(i) = (1); (i) < (n + 1); i += 1) {
    cin >> a[i];
  }
  sort(a.begin(), a.end());
  vector<int> dif(n + 1);
  dif[0] = 0;
  int res = 1;
  for (int(i) = (1); (i) < (n + 1); i += 1) {
    dif[i] = max(dif[i - 1] - 1, 1);
    int j = i + dif[i];
    while (a[j] - a[i] <= 5 && j < n + 1) {
      j += 1;
      dif[i] += 1;
    }
    if (dif[i] > res) {
      res = dif[i];
    }
  }
  cout << res << endl;
  return 0;
}