Problem: You are a coach at your local university. There are n students under your supervision, the programming skill of the i-th student is a_i.

You have to create a team for a new programming competition. As you know, the more students some team has the more probable its victory is! So you have to create a team with the maximum number of students. But you also know that a team should be balanced. It means that the programming skill of each pair of students in a created team should differ by no more than 5.

Your task is to report the maximum possible number of students in a balanced team.

Input

The first line of the input contains one integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the number of students.

The second line of the input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9), where a_i is a programming skill of the i-th student.

Output

Print one integer — the maximum possible number of students in a balanced team.

Examples

Input


6
1 10 17 12 15 2


Output


3


Input


10
1337 1337 1337 1337 1337 1337 1337 1337 1337 1337


Output


10


Input


6
1 1000 10000 10 100 1000000000


Output


1

Note

In the first example you can create a team with skills [12, 17, 15].

In the second example you can take all students in a team because their programming skills are equal.

In the third example you can create a team consisting of a single student (and you cannot create a team consisting of at least two students).

Solution (in JAVA):

Solution:
import java.util.*;
import java.io.*;
public class Solution1133C
{
  public static void main(String[] args)throws IOException
  {
    Scanner sc=new Scanner(System.in);
    BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
    int n=Integer.parseInt(br.readLine());
    ArrayList<Integer> a=new ArrayList<Integer>();
    String s[]=br.readLine().split(" ");
    for(int i=0;i<n;i++)
    {
      a.add(Integer.parseInt(s[i]));
    }
    int max=0;
    Collections.sort(a);
    int j = 0;
 for (int i = 0; i < n; ++i) {
  while (j < n && a.get(j)-a.get(i) <= 5) {
   ++j;
   max = Math.max(max, j - i);
  }
 }
    System.out.println(max);
  }
}