Problem: Well, here is another math class task. In mathematics, GCD is the greatest common divisor, and it's an easy task to calculate the GCD between two positive integers.

A common divisor for two positive numbers is a number which both numbers are divisible by.

But your teacher wants to give you a harder task, in this task you have to find the greatest common divisor d between two integers a and b that is in a given range from low to high (inclusive), i.e. low ≤ d ≤ high. It is possible that there is no common divisor in the given range.

You will be given the two integers a and b, then n queries. Each query is a range from low to high and you have to answer each query.

Input

The first line contains two integers a and b, the two integers as described above (1 ≤ a, b ≤ 109). The second line contains one integer n, the number of queries (1 ≤ n ≤ 104). Then n lines follow, each line contains one query consisting of two integers, low and high (1 ≤ low ≤ high ≤ 109).

Output

Print n lines. The i-th of them should contain the result of the i-th query in the input. If there is no common divisor in the given range for any query, you should print -1 as a result for this query.

Examples

Input

9 27
3
1 5
10 11
9 11


Output

3
-1
9

Solution (in PYTHON3):

Solution:
import math
import bisect

a, b = map(int, input().split())
gcd = math.gcd(a, b)

a, b = (a, b) if a < b else (b, a)
divisors = []
for i in range(1, int(math.sqrt(a)) + 1):
    n, f = divmod(a, i)
    if f == 0:
        divisors.append(i)
        divisors.append(n)
divisors.sort()

for _ in range(int(input())):
    low, high = map(int, input().split())
    cd = -1
    if low > gcd:
        pass
    elif low <= gcd <= high:
        cd = gcd
    else:
        ib = bisect.bisect_left(divisors, low)
        ie = bisect.bisect_right(divisors, high)
        for i in range(ib, ie):
            d = divisors[i]
            if b % d == 0:
                cd = d
    print(cd)