Problem: I have a sequence defined as follows:

* All even-numbered terms are equal to the previous term multiplied by 2.
* All odd-numbered terms are equal to the previous term divided by 3.



Create a program that reads the first term a of this sequence and outputs the sum s (10) from the first term to the tenth term.



Input

The input consists of multiple test cases. For each test case, a real number a (1.0 ≤ a ≤ 10.0) representing the first term of the sequence is given in one row.

The number of test cases does not exceed 50.

Output

Print s (10) on one line for each test case.

The output may contain an error of 0.000001 or less.

Example

Input

1.0
2.0
3.0


Output

7.81481481
15.62962963
23.44444444

Solution (in CPP):

Solution:
#include<iostream>
#include<iomanip>

using namespace std;

int main() {
	
	double n[10] = {};
	
	while(cin >> n[0]) {
	
	double sum = n[0];
	
	for(int i=1;i<10;i++) {
		
		if(i % 2)
			n[i] = n[i-1] * 2;
		
		else
			n[i] = n[i-1] / 3;
			
		sum += n[i];
		
	}
	
	cout << fixed << setprecision (8)<< sum << "\n";
	
}
	
	return 0;
}