Problem: I have a sequence defined as follows:

* All even-numbered terms are equal to the previous term multiplied by 2.
* All odd-numbered terms are equal to the previous term divided by 3.



Create a program that reads the first term a of this sequence and outputs the sum s (10) from the first term to the tenth term.



Input

The input consists of multiple test cases. For each test case, a real number a (1.0 ≤ a ≤ 10.0) representing the first term of the sequence is given in one row.

The number of test cases does not exceed 50.

Output

Print s (10) on one line for each test case.

The output may contain an error of 0.000001 or less.

Example

Input

1.0
2.0
3.0


Output

7.81481481
15.62962963
23.44444444

Solution (in CPP):

Solution:
#include<iostream>
using namespace std;
int main(){
	double array[15];
	double sum=0;
	while(cin>>array[0]){
		for(int i=1;i<=9;i++){
			if(i%2==1){
				array[i]=array[i-1]*2;
			}else{
				array[i]=array[i-1]/3;
			}
		}
		for(int i=0;i<=9;i++){
			sum+=array[i];
		}
		cout.precision(10);
		cout<<sum<<endl;
		sum=0;
	}
}