Problem: You are a coach at your local university. There are n students under your supervision, the programming skill of the i-th student is a_i.

You have to create a team for a new programming competition. As you know, the more students some team has the more probable its victory is! So you have to create a team with the maximum number of students. But you also know that a team should be balanced. It means that the programming skill of each pair of students in a created team should differ by no more than 5.

Your task is to report the maximum possible number of students in a balanced team.

Input

The first line of the input contains one integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the number of students.

The second line of the input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9), where a_i is a programming skill of the i-th student.

Output

Print one integer — the maximum possible number of students in a balanced team.

Examples

Input


6
1 10 17 12 15 2


Output


3


Input


10
1337 1337 1337 1337 1337 1337 1337 1337 1337 1337


Output


10


Input


6
1 1000 10000 10 100 1000000000


Output


1

Note

In the first example you can create a team with skills [12, 17, 15].

In the second example you can take all students in a team because their programming skills are equal.

In the third example you can create a team consisting of a single student (and you cannot create a team consisting of at least two students).

Solution (in PYTHON3):

Solution:
"""""""""""""""""""""""""""""""""""""""""""""
|    author: mr.math - Hakimov Rahimjon     |
|    e-mail: mr.math0777@gmail.com          |
"""""""""""""""""""""""""""""""""""""""""""""
#inp = open("lepus.in", "r"); input = inp.readline; out = open("lepus.out", "w"); print = out.write
TN = 1


# ===========================================
  
  
def solution():
    n = int(input())
    a = list(map(int, input().split()))
    dct = {}
    ans = []
    keys = []
    for i in range(n):
        try: x = dct[a[i]]
        except:
            dct[a[i]] = 1
            keys.append(a[i])
        else: dct[a[i]] += 1
    for i in keys:
        x = dct[i]
        for j in range(1, 6):
            try: y = dct[i-j]
            except: y = 0
            else: x += dct[i-j]
        ans.append(x)
    print(max(ans))


# ===========================================
while TN != 0:
    solution()
    TN -= 1
# ===========================================
#inp.close()
#out.close()