Problem: The Human-Cow Confederation (HC2), led by Heidi, has built a base where people and cows can hide, guarded from zombie attacks. The entrance to the base is protected by an automated gate which performs a kind of a Turing test: it shows the entering creature a photograph and asks them whether the top and bottom halves of this photograph have been swapped or not. A person (or even a cow) will have no problem answering such questions; on the other hand, a zombie would just randomly smash one of the two buttons.

The creature is asked a series of such questions. If at least 75% of them are answered correctly, the gate is unlocked; otherwise, a side door opens, beneath which a huge fan is spinning...

Heidi is now building a robot army to fight the zombies, and she wants the robots to also be able to enter the base. You are tasked with programming them to distinguish the images.

<image>

The first two images from the test set. The first picture has been rearranged, but not the second.

Input

The first line of the input contains the number q of questions (1 ≤ q ≤ 220). After that, q questions follow, each of which in the format described below.

The first line of every question contains two space-separated integers h and w (1 ≤ h, w ≤ 600) – the height (number of rows) and width (number of columns) of the photograph. (Most photographs are roughly 200 × 300.) After this, h lines follow, each describing a single row of the picture. The picture is monochrome (in shades of grey). Its i-th row is described by w space-separated integers aij (j = 1, ..., w), where aij is the brightness of the corresponding pixel (0 ≤ aij < 256, where 0 is black and 255 is white).

Each picture will be either a real-life photograph, or a real-life photograph which has been broken up into two pieces and rearranged. More precisely, in the latter case, the topmost <image> rows have been moved to the bottom of the picture. It is guaranteed that h is even.

There is only a single input file to be processed, called all.in, and it is downloadable from the online judge. You are also a given another input file, called sample.in, which contains the first 20 pictures from all.in; you are provided the correct answers for sample.in in sample.out. You are also given a directory easy_bmp, which contains the first 50 input photographs in the form of .bmp image files, as well as a directory easy_sample_original_bmp, which contains the first 20 images before rearrangement. Check the notes for the download links.

Output

Your program should print q lines. The i-th line should contain your answer for the i-th question: YES if the photograph has been rearranged and NO otherwise. Your answers will be accepted if they all conform to this format and if at least 75% of them are correct.

Because the input is rather huge, feel free to process it locally and submit just your precomputed answers (i.e., a program which just prints your output for the input file all.in).

Note

The link to download all necessary files is http://assets.codeforces.com/files/690/easy_contestant_package.zip

Solution (in JAVA):

Solution:
import java.util.Scanner;
import java.util.function.Supplier;

/**
 * Created by Администратор on 14.07.2016.
 */
public class ComparePictures {
    public static void main(String args[]){
        Scanner in=new Scanner(System.in);
        int q=in.nextInt();

        for(int i=0;i<q;i++){

            int h=in.nextInt();
            int w=in.nextInt();
            int difs[][]=new int[4][w];
            //count first; h/2 ;h/2+1; last
            for(int iH=1;iH<=h;iH++){
                if(iH==1){
                    for(int iW=0;iW<w;iW++){
                        difs[0][iW]=in.nextInt();
                    }
                }else if(iH==h/2){
                    for(int iW=0;iW<w;iW++){
                        difs[1][iW]=in.nextInt();
                    }
                }else if(iH==h/2+1){
                    for(int iW=0;iW<w;iW++){
                        difs[2][iW]=in.nextInt();
                    }
                }else if(iH==h){
                    for(int iW=0;iW<w;iW++){
                        difs[3][iW]=in.nextInt();
                    }
                }else{
                    for(int iW=0;iW<w;iW++){
                        in.nextInt();
                    }
                }
            }

            float difEdjes=countAverageDistanse(difs[0],difs[3]);
            float difMiddle=countAverageDistanse(difs[1],difs[2]);
            if(difMiddle>difEdjes){
                System.out.println("YES");
            }else{
                System.out.println("NO");
            }
        }
    }

    private static float countAverageDistanse(int[] dif, int[] dif1) {
        float res=0;
        for(int i=0;i<dif.length;i++){
            res+=(dif[i]-dif1[i]);
        }
        return Math.abs(res/(float)dif.length);
    }
}