Problem: You are a coach at your local university. There are n students under your supervision, the programming skill of the i-th student is a_i.

You have to create a team for a new programming competition. As you know, the more students some team has the more probable its victory is! So you have to create a team with the maximum number of students. But you also know that a team should be balanced. It means that the programming skill of each pair of students in a created team should differ by no more than 5.

Your task is to report the maximum possible number of students in a balanced team.

Input

The first line of the input contains one integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the number of students.

The second line of the input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9), where a_i is a programming skill of the i-th student.

Output

Print one integer — the maximum possible number of students in a balanced team.

Examples

Input


6
1 10 17 12 15 2


Output


3


Input


10
1337 1337 1337 1337 1337 1337 1337 1337 1337 1337


Output


10


Input


6
1 1000 10000 10 100 1000000000


Output


1

Note

In the first example you can create a team with skills [12, 17, 15].

In the second example you can take all students in a team because their programming skills are equal.

In the third example you can create a team consisting of a single student (and you cannot create a team consisting of at least two students).

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
const int INF = 2e5 + 10;
long long number[INF];
int n;
int gg(long long x) {
  int st = 0, len = n;
  while (len - st != 1) {
    int mid = (st + len) / 2;
    if (number[mid] > x)
      len = mid;
    else
      st = mid;
  }
  return st;
}
int main() {
  ios::sync_with_stdio(0);
  cin >> n;
  for (int a = 0; a < n; a++) cin >> number[a];
  sort(number, number + n);
  int maxx = 0;
  for (int a = 0; a < n; a++) {
    int x = number[a] + 5;
    maxx = max(maxx, gg(x) - a + 1);
  }
  cout << maxx << endl;
  return 0;
}