Problem: Let a be a matrix of size r × c containing positive integers, not necessarily distinct. Rows of the matrix are numbered from 1 to r, columns are numbered from 1 to c. We can construct an array b consisting of r + c integers as follows: for each i ∈ [1, r], let b_i be the greatest common divisor of integers in the i-th row, and for each j ∈ [1, c] let b_{r+j} be the greatest common divisor of integers in the j-th column. 

We call the matrix diverse if all r + c numbers b_k (k ∈ [1, r + c]) are pairwise distinct. 

The magnitude of a matrix equals to the maximum of b_k.

For example, suppose we have the following matrix:

\begin{pmatrix} 2 & 9 & 7\\\ 4 & 144 & 84 \end{pmatrix} 

We construct the array b:

  1. b_1 is the greatest common divisor of 2, 9, and 7, that is 1; 
  2. b_2 is the greatest common divisor of 4, 144, and 84, that is 4; 
  3. b_3 is the greatest common divisor of 2 and 4, that is 2; 
  4. b_4 is the greatest common divisor of 9 and 144, that is 9; 
  5. b_5 is the greatest common divisor of 7 and 84, that is 7. 



So b = [1, 4, 2, 9, 7]. All values in this array are distinct, so the matrix is diverse. The magnitude is equal to 9.

For a given r and c, find a diverse matrix that minimises the magnitude. If there are multiple solutions, you may output any of them. If there are no solutions, output a single integer 0. 

Input

The only line in the input contains two space separated integers r and c (1 ≤ r,c ≤ 500) — the number of rows and the number of columns of the matrix to be found.

Output

If there is no solution, output a single integer 0.

Otherwise, output r rows. The i-th of them should contain c space-separated integers, the j-th of which is a_{i,j} — the positive integer in the i-th row and j-th column of a diverse matrix minimizing the magnitude.

Furthermore, it must hold that 1 ≤ a_{i,j} ≤ 10^9. It can be shown that if a solution exists, there is also a solution with this additional constraint (still having minimum possible magnitude).

Examples

Input


2 2


Output


4 12
2 9

Input


1 1


Output


0

Note

In the first example, the GCDs of rows are b_1 = 4 and b_2 = 1, and the GCDs of columns are b_3 = 2 and b_4 = 3. All GCDs are pairwise distinct and the maximum of them is 4. Since the GCDs have to be distinct and at least 1, it is clear that there are no diverse matrices of size 2 × 2 with magnitude smaller than 4.

In the second example, no matter what a_{1,1} is, b_1 = b_2 will always hold, so there are no diverse matrices.

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.HashMap;
import java.util.InputMismatchException;
import java.util.TreeSet;
public class Main implements Runnable{
	               	                    static final long MAX = 464897L;
	                    static class InputReader
	                    {
	                        private InputStream stream;
	                        private byte[] buf = new byte[1024];
	                        private int curChar;
	                        private int numChars;
	                        private SpaceCharFilter filter;
	                        private BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
	                 
	                        public InputReader(InputStream stream)
	                        {
	                            this.stream = stream;
	                        }
	                        
	                        public int read()
	                        {
	                            if (numChars==-1) 
	                                throw new InputMismatchException();
	                            
	                            if (curChar >= numChars)
	                            {
	                                curChar = 0;
	                                try 
	                                {
	                                    numChars = stream.read(buf);
	                                }
	                                catch (IOException e)
	                                {
	                                    throw new InputMismatchException();
	                                }
	                                
	                                if(numChars <= 0)                
	                                    return -1;
	                            }
	                            return buf[curChar++];
	                        }
	                     
	                        public String nextLine()
	                        {
	                            String str = "";
            try
            {
                str = br.readLine();
            }
            catch (IOException e)
            {
                e.printStackTrace();
            }
            return str;
        }
        public int nextInt()
        {
            int c = read();
            
            while(isSpaceChar(c)) 
                c = read();
            
            int sgn = 1;
            
            if (c == '-') 
            {
                sgn = -1;
                c = read();
            }
            
            int res = 0;
            do 
            {
                if(c<'0'||c>'9') 
                    throw new InputMismatchException();
                res *= 10;
                res += c - '0';
                c = read();
            }
            while (!isSpaceChar(c)); 
            
            return res * sgn;
        }
        
        public long nextLong() 
        {
            int c = read();
            while (isSpaceChar(c))
                c = read();
            int sgn = 1;
            if (c == '-') 
            {
                sgn = -1;
                c = read();
            }
            long res = 0;
            
            do 
            {
                if (c < '0' || c > '9')
                    throw new InputMismatchException();
                res *= 10;
                res += c - '0';
                c = read();
            }
            while (!isSpaceChar(c));
                return res * sgn;
        }
        
        public double nextDouble() 
        {
            int c = read();
            while (isSpaceChar(c))
                c = read();
            int sgn = 1;
            if (c == '-') 
            {
                sgn = -1;
                c = read();
            }
            double res = 0;
            while (!isSpaceChar(c) && c != '.') 
            {
                if (c == 'e' || c == 'E')
                    return res * Math.pow(10, nextInt());
                if (c < '0' || c > '9')
                    throw new InputMismatchException();
                res *= 10;
                res += c - '0';
                c = read();
            }
            if (c == '.') 
            {
                c = read();
                double m = 1;
                while (!isSpaceChar(c)) 
                {
                    if (c == 'e' || c == 'E')
                        return res * Math.pow(10, nextInt());
                    if (c < '0' || c > '9')
                        throw new InputMismatchException();
                    m /= 10;
                    res += (c - '0') * m;
                    c = read();
                }
            }
            return res * sgn;
        }
        
        public String readString() 
        {
            int c = read();
            while (isSpaceChar(c))
                c = read();
            StringBuilder res = new StringBuilder();
            do 
            {
                res.appendCodePoint(c);
                c = read();
            } 
            while (!isSpaceChar(c));
            
            return res.toString();
        }
     
        public boolean isSpaceChar(int c) 
        {
            if (filter != null)
                return filter.isSpaceChar(c);
            return c == ' ' || c == '\n' || c == '\r' || c == '\t' || c == -1;
        }
     
        public String next() 
        {
            return readString();
        }
        
        public interface SpaceCharFilter 
        {
            public boolean isSpaceChar(int ch);
        }
    }
     
    public static void main(String args[]) throws Exception
    {
        new Thread(null, new Main(),"Main",1<<26).start();
    }   
    static long gcd(long a, long b) 
    { 
      if (b == 0) 
        return a; 
      return gcd(b, a % b);  
    } 
    static long lcm(long a,long b) {
        return (a*b)/gcd(a,b);
    }
    int maxn = 1000005;
    long MOD = 1000000007;
    long prime = 29;
    ArrayList<Integer> adj[];
    HashMap<Integer,Integer> tmap = new HashMap();
    static class Node implements Comparable<Node>{
		int destination;
		long weight;
		Node(int destination,long weight){
			this.destination = destination;
			this.weight = weight;
		}
		Node(){
			
		}
		@Override
		public int compareTo(Node n) {
			return Long.signum(weight - n.weight);
		}
	}
    int[] val;
    boolean[] visited;
	public void run() 
    {
        InputReader sc = new InputReader(System.in);
        PrintWriter w = new PrintWriter(System.out);
        int r = sc.nextInt();
        int c = sc.nextInt();
        if(r == 1 && c == 1) {
        	w.println("0");
        }else if(r == 1) {
        	for(int i = 1;i <= c;i++) {
        		w.print((i+1) + " ");
        	}
        }else {
        	int temp = r + c - r;
        	for(int i = 1;i <= r;i++) {
        		long curr = temp + i;
        		for(int j = 1;j <= c;j++) {
        			w.print((curr * j) + " ");
        		}
        		w.println();
        	}
        }
        w.close();
    } 
	long f_hash(String s) {
		char[] ch = s.toCharArray();
		long ans = 0;
		long p = 31;
		long pow = 1;
		long mod = (long) (1e9 + 9);
		for(int  i = 0;i < s.length();i++) {
			ans = (ans + (ch[i] - 'a' + 1) * pow) % mod;
			pow = (pow * p) % mod;
		}
		return ans;
	}
	long b_hash(String s) {
		char[] ch = s.toCharArray();
		long ans = 0;
		long p = 31;
		long pow = 1;
		long mod = (long) (1e9 + 9);
		for(int i = s.length()-1;i >= 0;i--) {
			ans = (ans + (ch[i] - 'a' + 1) * pow) % mod;
			pow = (pow * p) % mod;
		}
		return ans;
	}
	ArrayList KMPSearch(String pat, String txt) 
    { 
		ArrayList<Integer> ar = new ArrayList();
        int M = pat.length(); 
        int N = txt.length(); 
  
        // create lps[] that will hold the longest 
        // prefix suffix values for pattern 
        int lps[] = new int[M]; 
        int j = 0; // index for pat[] 
  
        
        computeLPSArray(pat, M, lps); 
  
        int i = 0; // index for txt[] 
        while (i < N) { 
            if (pat.charAt(j) == txt.charAt(i)) { 
                j++; 
                i++; 
            } 
            if (j == M) { 
                ar.add((i-j));
                j = lps[j - 1]; 
            } 
  
            // mismatch after j matches 
            else if (i < N && pat.charAt(j) != txt.charAt(i)) { 
                // Do not match lps[0..lps[j-1]] characters, 
                // they will match anyway 
                if (j != 0) 
                    j = lps[j - 1]; 
                else
                    i = i + 1; 
            } 
        } 
        return ar;
    } 
  
    void computeLPSArray(String pat, int M, int lps[]) 
    { 
        // length of the previous longest prefix suffix 
        int len = 0; 
        int i = 1; 
        lps[0] = 0; // lps[0] is always 0 
  
        // the loop calculates lps[i] for i = 1 to M-1 
        while (i < M) { 
            if (pat.charAt(i) == pat.charAt(len)) { 
                len++; 
                lps[i] = len; 
                i++; 
            } 
            else // (pat[i] != pat[len]) 
            { 
                // This is tricky. Consider the example. 
                // AAACAAAA and i = 7. The idea is similar 
                // to search step. 
                if (len != 0) { 
                    len = lps[len - 1]; 
  
                    // Also, note that we do not increment 
                    // i here 
                } 
                else // if (len == 0) 
                { 
                    lps[i] = len; 
                    i++; 
                } 
            } 
        } 
    } 
	static long power(long a,long b,long MOD) {
        long ans = 1;
        a = a % MOD;
        while(b != 0) {
            if(b % 2 == 1) {
                ans = (ans * a) % MOD;
            }
            a = (a * a) % MOD;
            b = b/2;
        }
        return ans;
    }
    class Equal implements Comparable<Equal>{
    	Character a;
    	int b;
    	public Equal(char a,int b){
    		this.a = a;
    		this.b = b;
    	}
		@Override
		public int compareTo(Equal an) {
			// TODO Auto-generated method stub
			return this.a.compareTo(an.a);
		}
    }
    class Pair implements Comparable<Pair>{
        long a;
        long b;
        long c;
        Pair(long a,long b,long c){
            this.b = b;
            this.a = a;
            this.c = c;
        }
        public boolean equals(Object o) {
            Pair p = (Pair)o;
            return this.a == p.a && this.b == p.b && this.c == p.c;
        }
        public int hashCode(){
            return Long.hashCode(a)*27 + Long.hashCode(b)*31;
        }
        public int compareTo(Pair p) {
       	     return Long.compare(this.a,p.a);
        }
    }
    
    class Pair3 implements Comparable<Pair3>{
        int a;
        int b;
        int c;
        Pair3(int a,int b,int c){
            this.b = b;
            this.a = a;
            this.c = c;
        }
        public boolean equals(Object o) {
            Pair3 p = (Pair3)o;
            return this.a == p.a && this.b == p.b && this.c == p.c;
        }
        public int hashCode(){
            return Long.hashCode(a)*27 + Long.hashCode(b)*31;
        }
        public int compareTo(Pair3 p) {
            return Long.compare(this.b,p.b);
        }
    }
    class Pair2 implements Comparable<Pair2>{
        int a;
        int b;
        int c;
        Pair2(int a,int b,int c){
            this.b = b;
            this.a = a;
            this.c = c;
        }
        public boolean equals(Object o) {
            Pair2 p = (Pair2)o;
            return this.a == p.a && this.b == p.b && this.c == p.c;
        }
        public int hashCode(){
            return Long.hashCode(a)*27 + Long.hashCode(b)*31 + Long.hashCode(c)*3;
        }
        public int compareTo(Pair2 p) {
            return Long.compare(p.a,this.a);
        }
    }
}