Problem: You are a coach at your local university. There are n students under your supervision, the programming skill of the i-th student is a_i.

You have to create a team for a new programming competition. As you know, the more students some team has the more probable its victory is! So you have to create a team with the maximum number of students. But you also know that a team should be balanced. It means that the programming skill of each pair of students in a created team should differ by no more than 5.

Your task is to report the maximum possible number of students in a balanced team.

Input

The first line of the input contains one integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the number of students.

The second line of the input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9), where a_i is a programming skill of the i-th student.

Output

Print one integer — the maximum possible number of students in a balanced team.

Examples

Input


6
1 10 17 12 15 2


Output


3


Input


10
1337 1337 1337 1337 1337 1337 1337 1337 1337 1337


Output


10


Input


6
1 1000 10000 10 100 1000000000


Output


1

Note

In the first example you can create a team with skills [12, 17, 15].

In the second example you can take all students in a team because their programming skills are equal.

In the third example you can create a team consisting of a single student (and you cannot create a team consisting of at least two students).

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int dp[5005][5005];
int main() {
  long long n, m;
  cin >> n >> m;
  vector<long long> a(n + 1);
  for (int i = 1; i <= n; ++i) cin >> a[i];
  sort(a.begin() + 1, a.end());
  for (int i = 1, j = 1; i <= n; ++i) {
    for (int k = 0; k <= m; ++k) dp[i][k] = dp[i - 1][k];
    for (; a[j] + 5 < a[i]; ++j)
      ;
    for (int k = 0; k < m; ++k)
      dp[i][k + 1] = max(dp[i][k + 1], dp[j - 1][k] + i - j + 1);
  }
  cout << dp[n][m];
  return 0;
}