Problem: Kostya is a genial sculptor, he has an idea: to carve a marble sculpture in the shape of a sphere. Kostya has a friend Zahar who works at a career. Zahar knows about Kostya's idea and wants to present him a rectangular parallelepiped of marble from which he can carve the sphere. 

Zahar has n stones which are rectangular parallelepipeds. The edges sizes of the i-th of them are ai, bi and ci. He can take no more than two stones and present them to Kostya. 

If Zahar takes two stones, he should glue them together on one of the faces in order to get a new piece of rectangular parallelepiped of marble. Thus, it is possible to glue a pair of stones together if and only if two faces on which they are glued together match as rectangles. In such gluing it is allowed to rotate and flip the stones in any way. 

Help Zahar choose such a present so that Kostya can carve a sphere of the maximum possible volume and present it to Zahar.

Input

The first line contains the integer n (1 ≤ n ≤ 105).

n lines follow, in the i-th of which there are three integers ai, bi and ci (1 ≤ ai, bi, ci ≤ 109) — the lengths of edges of the i-th stone. Note, that two stones may have exactly the same sizes, but they still will be considered two different stones.

Output

In the first line print k (1 ≤ k ≤ 2) the number of stones which Zahar has chosen. In the second line print k distinct integers from 1 to n — the numbers of stones which Zahar needs to choose. Consider that stones are numbered from 1 to n in the order as they are given in the input data.

You can print the stones in arbitrary order. If there are several answers print any of them. 

Examples

Input

6
5 5 5
3 2 4
1 4 1
2 1 3
3 2 4
3 3 4


Output

1
1


Input

7
10 7 8
5 10 3
4 2 6
5 5 5
10 2 8
4 2 1
7 7 7


Output

2
1 5

Note

In the first example we can connect the pairs of stones:

  * 2 and 4, the size of the parallelepiped: 3 × 2 × 5, the radius of the inscribed sphere 1
  * 2 and 5, the size of the parallelepiped: 3 × 2 × 8 or 6 × 2 × 4 or 3 × 4 × 4, the radius of the inscribed sphere 1, or 1, or 1.5 respectively. 
  * 2 and 6, the size of the parallelepiped: 3 × 5 × 4, the radius of the inscribed sphere 1.5
  * 4 and 5, the size of the parallelepiped: 3 × 2 × 5, the radius of the inscribed sphere 1
  * 5 and 6, the size of the parallelepiped: 3 × 4 × 5, the radius of the inscribed sphere 1.5



Or take only one stone:

  * 1 the size of the parallelepiped: 5 × 5 × 5, the radius of the inscribed sphere 2.5
  * 2 the size of the parallelepiped: 3 × 2 × 4, the radius of the inscribed sphere 1
  * 3 the size of the parallelepiped: 1 × 4 × 1, the radius of the inscribed sphere 0.5
  * 4 the size of the parallelepiped: 2 × 1 × 3, the radius of the inscribed sphere 0.5
  * 5 the size of the parallelepiped: 3 × 2 × 4, the radius of the inscribed sphere 1
  * 6 the size of the parallelepiped: 3 × 3 × 4, the radius of the inscribed sphere 1.5



It is most profitable to take only the first stone. 

Solution (in PYTHON3):

Solution:
#!/usr/bin/env python
 
class HashMap(object):

    def __init__(self, size=256):
        # self._values = [None for item in range(size)]
        self._keys = []
        self.data = [[0] for i in range(size)]
        self.numItems = 0
        self.size = size
    
    # def __getitem__(self,key):
        # if self._values[self.hashfunc(key)] is not None:
        #     return self._values[self.hashfunc(key)] 
        # else:
        #     return None

    def __setitem__(self,key,value):
        
        pos = self.set_find(key) #find empty space or old value
        if pos != -1:
            if len(self.data[pos]) > 1:
                if self.data[pos][0] == key:
                    try:
                        self.data[pos] = [key, value]
                    except:
                        print("Update failed!")
                        return False
                    return True
            
            self.data[pos] = [key, value]
            self.numItems += 1
   
            self._keys.append(key)            
            return True
        else:
            return False
        # if value is None:
        #     raise ValueError('None is not permitted as a value.')

        # if self._values[self.hashfunc(key)] is None:
        #     self._keys.append(key)
        #     self._values[self.hashfunc(key)] = value
        #     # print(float(len(self._keys))/len(self._values))
        #     if (self.size - len(self._keys)) == 2:
        #     # if float(len(self._keys))/len(self._values) > 0.1:
        #         self.__resize__()
        
        # else:
        #     if key in self._keys: 
        #         self._values[self.hashfunc(key)] = value
        #     else:
        #         self._keys.append(key)
        #         self._values[self.hashfunc(key)] = value
        #         # self.__resize__() # resize values
        #         # self.__setitem__(key,value) 

    def __missing__(self,not_key):
        raise KeyError('{0} is not a valid key'.format(not_key))

    def __getitem__(self, key):
        pos = self.get_find(key)
        if pos == -1:
            return None
        else:
            return self.data[pos][1]

    def __repr__(self):
        # list_repr = ['{0}:{1}'.format(key, self._values[self.hashfunc(key)]) for key in self._keys]
        return str(self.data)
        return 'HashMap({0})'.format(list_repr)

    def __contains__(self,key):
        if key in self._keys:
            return True
        else:
            return False

    def __len__(self):
        return len(self._keys)

    def __iter__(self):
        return (key for key in self._keys)

    def hashfunc(self,key): # with collision
        print(hash(key))
        return hash(key) % len(self._values)

    def set_find(self, key):
        
        collisionNum = 0
        currentPos = hash(key) % self.size #hash key
        
        while self.data[currentPos][0] != 0 and self.data[currentPos][0]!=key:
            """quadratic resolution"""
            collisionNum += 1
            currentPos = (currentPos + collisionNum**2) % self.size
            """alternate way of calculating
            currentPos += 2*collisionNum - 1
            if currentPos >= self.capacity:
                currentPos -= self.capacity
            """
            if collisionNum > self.size:
                return -1 
                """this doesn't mean there aren't empty slots, but at this
                point you're better off rehashing"""
            
        return currentPos

    
    def get_find(self, key):
        collisionNum = 0
        currentPos = hash(key) % self.size #hash key
        while True:
            while self.data[currentPos][0] != 0 and self.data[currentPos][0]!=key:
                collisionNum += 1
                currentPos = (currentPos + collisionNum**2) % self.size
                if collisionNum > self.size:
                    return -1 
            if self.data[currentPos][0] == 0:
                if len(self.data[currentPos]) == 1:
                    return -1
                else:
                    collisionNum += 1
                    currentPos = (currentPos + collisionNum**2) % self.size
            else: #found key
                return currentPos 

    # def __resize__(self,**kwargs):
    #     old_values = kwargs.get('values',[self._values[self.hashfunc(key)] for key in self._keys])
    #     self._values = [None for item in range(2*len(self._values))]
    #     for key, value in zip(self._keys,old_values):
    #         if self._values[self.hashfunc(key)] is None: 
    #             self._values[self.hashfunc(key)] = value
    #         else:
    #             self.__resize__(values = old_values)


if __name__ == '__main__':
    answer = 0
    min_val = 0
    diam = 0
    # with open("input.txt") as f_in:
    n = int(input())
    shapes = {} #HashMap(400)
    for i in range(n):
        face = list(sorted(map(int, input().split())))
        key = (face[1], face[2])
        if key in shapes:

        # if shapes.get_find(key) != -1:
            # old, k = shapes[key]
            old, k = shapes[key]
            res = [old + face[0], face[1], face[2]]
            m = min(res)
            if m > min_val:
                min_val = m
                diam = m
                mn = [k, i]
            if old < face[0]: # update min
                # shapes.set(key, (face[0], i))
                shapes[key] = (face[0], i)
        else:      
            # shapes.set(key, (face[0], i))
            shapes[key] = (face[0], i)

            # shapes.insert(new_key)
        m = face[0]    
        if m > min_val:
            diam = min(face)
            min_val = m
            mn = [i]

    # with open('output.txt','w') as f_out:
    #     f_out.write(str(len(mn)) + "\n"\
    #     + " ".join(map(lambda x: str(x+1), mn)) + "\n" \
    #      + str(min_val))

    print(len(mn))
    print(" ".join(map(lambda x: str(x+1), mn)))   
    # print("diameter", min_val)