Problem: You are a coach at your local university. There are n students under your supervision, the programming skill of the i-th student is a_i.

You have to create a team for a new programming competition. As you know, the more students some team has the more probable its victory is! So you have to create a team with the maximum number of students. But you also know that a team should be balanced. It means that the programming skill of each pair of students in a created team should differ by no more than 5.

Your task is to report the maximum possible number of students in a balanced team.

Input

The first line of the input contains one integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the number of students.

The second line of the input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9), where a_i is a programming skill of the i-th student.

Output

Print one integer — the maximum possible number of students in a balanced team.

Examples

Input


6
1 10 17 12 15 2


Output


3


Input


10
1337 1337 1337 1337 1337 1337 1337 1337 1337 1337


Output


10


Input


6
1 1000 10000 10 100 1000000000


Output


1

Note

In the first example you can create a team with skills [12, 17, 15].

In the second example you can take all students in a team because their programming skills are equal.

In the third example you can create a team consisting of a single student (and you cannot create a team consisting of at least two students).

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
const long long MAX = 1000;
const long long MAXN = 1000;
const double PI = acos(-1.0);
long long gcd(long long a, long long b) { return b ? gcd(b, a % b) : a; }
long long a[300000];
int main() {
  int n;
  cin >> n;
  for (int i = 0; i < n; i++) {
    cin >> a[i];
  }
  sort(a, a + n);
  int s = 0, t = 0;
  while (t + 1 < n && a[t + 1] - a[s] <= 5) t++;
  int ans = t - s + 1;
  while (t != n) {
    while (s + 1 < n && a[s + 1] == a[s]) s++;
    s++;
    while (t + 1 < n && a[t + 1] - a[s] <= 5) t++;
    if (t - s + 1 > ans) ans = t - s + 1;
    if (t == n - 1) break;
  }
  cout << ans << endl;
  return 0;
}