Problem: I have a sequence defined as follows:

* All even-numbered terms are equal to the previous term multiplied by 2.
* All odd-numbered terms are equal to the previous term divided by 3.



Create a program that reads the first term a of this sequence and outputs the sum s (10) from the first term to the tenth term.



Input

The input consists of multiple test cases. For each test case, a real number a (1.0 ≤ a ≤ 10.0) representing the first term of the sequence is given in one row.

The number of test cases does not exceed 50.

Output

Print s (10) on one line for each test case.

The output may contain an error of 0.000001 or less.

Example

Input

1.0
2.0
3.0


Output

7.81481481
15.62962963
23.44444444

Solution (in JAVA):

Solution:
import java.util.*;
public class Main {
	static Scanner sc = new Scanner(System.in);
	static double[] sequence;	
	static  int i;
	static double Sum = 0.0;
	public static void main(String[] args) {
		
		while(read()){
			slove();
		}
	}
	static boolean read(){
		if(!sc.hasNextDouble())return false;
		
		sequence = new double[11];
		sequence[0] = 0.0;
		sequence[1] = 0.0;
		sequence[1] = sc.nextDouble();
		return true;
	}
	static void slove(){
		
		for(i = 2; i <= 10; i++){
			if(i%2 == 0){
				sequence[i] = 2*sequence[i-1];
			}else{
				sequence[i] = sequence[i-1]/3;
			}
			//System.out.println(sequence[i]);
		}
		for(i = 1; i <= 10; i++){
			Sum = Sum + sequence[i];
		}
		for(i = 1; i <= 10; i++){
			sequence[i] = 0.0;
		}
		System.out.println(Sum);
		Sum = 0.0;
	}
}