Problem: Kostya is a genial sculptor, he has an idea: to carve a marble sculpture in the shape of a sphere. Kostya has a friend Zahar who works at a career. Zahar knows about Kostya's idea and wants to present him a rectangular parallelepiped of marble from which he can carve the sphere. 

Zahar has n stones which are rectangular parallelepipeds. The edges sizes of the i-th of them are ai, bi and ci. He can take no more than two stones and present them to Kostya. 

If Zahar takes two stones, he should glue them together on one of the faces in order to get a new piece of rectangular parallelepiped of marble. Thus, it is possible to glue a pair of stones together if and only if two faces on which they are glued together match as rectangles. In such gluing it is allowed to rotate and flip the stones in any way. 

Help Zahar choose such a present so that Kostya can carve a sphere of the maximum possible volume and present it to Zahar.

Input

The first line contains the integer n (1 ≤ n ≤ 105).

n lines follow, in the i-th of which there are three integers ai, bi and ci (1 ≤ ai, bi, ci ≤ 109) — the lengths of edges of the i-th stone. Note, that two stones may have exactly the same sizes, but they still will be considered two different stones.

Output

In the first line print k (1 ≤ k ≤ 2) the number of stones which Zahar has chosen. In the second line print k distinct integers from 1 to n — the numbers of stones which Zahar needs to choose. Consider that stones are numbered from 1 to n in the order as they are given in the input data.

You can print the stones in arbitrary order. If there are several answers print any of them. 

Examples

Input

6
5 5 5
3 2 4
1 4 1
2 1 3
3 2 4
3 3 4


Output

1
1


Input

7
10 7 8
5 10 3
4 2 6
5 5 5
10 2 8
4 2 1
7 7 7


Output

2
1 5

Note

In the first example we can connect the pairs of stones:

  * 2 and 4, the size of the parallelepiped: 3 × 2 × 5, the radius of the inscribed sphere 1
  * 2 and 5, the size of the parallelepiped: 3 × 2 × 8 or 6 × 2 × 4 or 3 × 4 × 4, the radius of the inscribed sphere 1, or 1, or 1.5 respectively. 
  * 2 and 6, the size of the parallelepiped: 3 × 5 × 4, the radius of the inscribed sphere 1.5
  * 4 and 5, the size of the parallelepiped: 3 × 2 × 5, the radius of the inscribed sphere 1
  * 5 and 6, the size of the parallelepiped: 3 × 4 × 5, the radius of the inscribed sphere 1.5



Or take only one stone:

  * 1 the size of the parallelepiped: 5 × 5 × 5, the radius of the inscribed sphere 2.5
  * 2 the size of the parallelepiped: 3 × 2 × 4, the radius of the inscribed sphere 1
  * 3 the size of the parallelepiped: 1 × 4 × 1, the radius of the inscribed sphere 0.5
  * 4 the size of the parallelepiped: 2 × 1 × 3, the radius of the inscribed sphere 0.5
  * 5 the size of the parallelepiped: 3 × 2 × 4, the radius of the inscribed sphere 1
  * 6 the size of the parallelepiped: 3 × 3 × 4, the radius of the inscribed sphere 1.5



It is most profitable to take only the first stone. 

Solution (in JAVA):

Solution:
import javafx.util.Pair;

import java.io.*;
import java.util.Arrays;
import java.util.HashMap;

public class Main {

    private static myScanner sc;
    private static PrintWriter pw;

    private static final int numberOfTests = 1;

    private static final String nameOfInAndOutFile = "";
    private static final String fullNameInputFile = nameOfInAndOutFile + ".in";
    private static final String fullNameOutputFile = nameOfInAndOutFile + ".out";

    public static void main(String[] args) throws IOException {
        if (nameOfInAndOutFile.length() == 0) {
            setDefaultInAndOutPut();
        } else {
            setInAndOutPutFromFile();
        }
        for (int test = 1; test <= numberOfTests; test++) {
            solve();
            pw.flush();
        }

        pw.close();
    }

    private static void setDefaultInAndOutPut() {
        sc = new myScanner(new BufferedReader(new InputStreamReader(System.in)));
        pw = new PrintWriter(System.out);
    }

    private static void setInAndOutPutFromFile() throws IOException {
        sc = new myScanner(new BufferedReader(new FileReader(new File(fullNameInputFile))));
        pw = new PrintWriter(new File(fullNameOutputFile));
    }

    private static final int intINF = Integer.MAX_VALUE;
    private static final int MOD = 1000000007;
    private static final long longINF = Long.MAX_VALUE;

    private static void solve() {
        long m = 1000000000;
        int n = sc.nextInt();
        HashMap<Long, Pair<Integer,Long>> hashMap = new HashMap<>();

        long best = 0;
        int k = 0;
        int ans1 = 0;
        int ans2 = 0;

        int[] l = new int[3];

        for (int i = 0; i < n; i++) {
            for (int j = 0; j < 3; j++) l[j] = sc.nextInt();
            Arrays.sort(l);
            if (l[0] > best) {
                best = l[0];
                k = 1;
                ans1 = i + 1;
            }

            Pair<Integer,Long> z1 = hashMap.getOrDefault(l[1] * m + l[2],new Pair<>(-1,-1L));
            if (z1.getKey()>=0) {
                long p = l[0]+z1.getValue();
                long less = Math.min(p,Math.min(l[1],l[2]));
                if (less>best){
                    best=less;
                    k=2;
                    ans1=i+1;
                    ans2=z1.getKey()+1;
                }
            }
            if (l[0]>z1.getValue()){
                hashMap.put(l[1] * m + l[2],new Pair<>(i,(long)l[0]));
            }

            z1 = hashMap.getOrDefault(l[0] * m + l[2],new Pair<>(-1,-1L));
            if (z1.getKey()>=0) {
                long p = l[1]+z1.getValue();
                long less = Math.min(p,Math.min(l[0],l[2]));
                if (less>best){
                    best=less;
                    k=2;
                    ans1=i+1;
                    ans2=z1.getKey()+1;
                }
            }
            if (l[1]>z1.getValue()){
                hashMap.put(l[0] * m + l[2],new Pair<>(i,(long)l[1]));
            }

            z1 = hashMap.getOrDefault(l[0] * m + l[1],new Pair<>(-1,-1L));
            if (l[2]>z1.getValue()){
                hashMap.put(l[0] * m + l[1],new Pair<>(i,(long)l[2]));
            }
        }
        pw.println(k);
        pw.println(ans1 + (k == 2 ? " " + ans2 : ""));
    }
}

class myScanner {
    private char[] buffer = new char[1 << 8];
    private int pos = 1;

    private BufferedReader reader;

    public myScanner(BufferedReader reader) {
        this.reader = reader;
    }

    public boolean hasNext() {
        return pos > 0;
    }

    private void loadBuffer() {
        pos = 0;
        try {
            for (int i; (i = reader.read()) != -1; ) {
                char c = (char) i;
                if (c != ' ' && c != '\n' && c != '\t' && c != '\r' && c != '\f') {
                    if (pos == buffer.length) buffer = Arrays.copyOf(buffer, 2 * pos);
                    buffer[pos++] = c;
                } else if (pos != 0) break;
            }
        } catch (IOException e) {
            throw new UncheckedIOException(e);
        }
    }

    public String current() {
        return String.copyValueOf(buffer, 0, pos);
    }


    public String next() {
        loadBuffer();
        return current();
    }


    public String nextLine() {
        try {
            return reader.readLine();
        } catch (IOException e) {
            throw new UncheckedIOException(e);
        }
    }


    public int nextInt() {
        return nextInt(10);
    }

    public long nextLong() {
        return nextLong(10);
    }

    public int nextInt(int radix) {
        loadBuffer();
        int result = 0;
        int i = buffer[0] == '-' || buffer[0] == '+' ? 1 : 0;
        for (checkValidNumber(pos > i); i < pos; i++) {
            int digit = buffer[i] - '0';
            checkValidNumber(0 <= digit && digit <= radix - 1);
            result = result * radix + digit;
        }
        return buffer[0] == '-' ? -result : result;
    }

    public long nextLong(int radix) {
        loadBuffer();
        long result = 0;
        int i = buffer[0] == '-' || buffer[0] == '+' ? 1 : 0;
        for (checkValidNumber(pos > i); i < pos; i++) {
            int digit = buffer[i] - '0';
            checkValidNumber(0 <= digit && digit <= radix - 1);
            result = result * radix + digit;
        }
        return buffer[0] == '-' ? -result : result;
    }

    public int[] nextArrayInts(int size) {
        int[] input = new int[size];
        for (int i = 0; i < size; i++) input[i] = nextInt();
        return input;
    }

    public long[] nextArrayLongs(int size) {
        long[] input = new long[size];
        for (int i = 0; i < size; i++) input[i] = nextLong();
        return input;
    }

    public double nextDouble() {
        loadBuffer();
        long result = 0;
        int i = buffer[0] == '-' || buffer[0] == '+' ? 1 : 0;
        long round = 1;
        final int radix = 10;
        boolean hasPoint = false;
        for (checkValidNumber(pos > i); i < pos; i++) {
            int digit = buffer[i] - '0';
            checkValidNumber((0 <= digit && digit <= radix - 1) || (!hasPoint && digit == -2));
            if (digit == -2) hasPoint = true;
            else {
                if (hasPoint) round *= radix;
                result = result * radix + digit;
            }

        }
        return buffer[0] == '-' ? -result / (1.0 * round) : result / (1.0 * round);
    }

    private void checkValidNumber(boolean condition) {
        if (!condition) throw new NumberFormatException(current());
    }
}