Problem: You are a coach at your local university. There are n students under your supervision, the programming skill of the i-th student is a_i.

You have to create a team for a new programming competition. As you know, the more students some team has the more probable its victory is! So you have to create a team with the maximum number of students. But you also know that a team should be balanced. It means that the programming skill of each pair of students in a created team should differ by no more than 5.

Your task is to report the maximum possible number of students in a balanced team.

Input

The first line of the input contains one integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the number of students.

The second line of the input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9), where a_i is a programming skill of the i-th student.

Output

Print one integer — the maximum possible number of students in a balanced team.

Examples

Input


6
1 10 17 12 15 2


Output


3


Input


10
1337 1337 1337 1337 1337 1337 1337 1337 1337 1337


Output


10


Input


6
1 1000 10000 10 100 1000000000


Output


1

Note

In the first example you can create a team with skills [12, 17, 15].

In the second example you can take all students in a team because their programming skills are equal.

In the third example you can create a team consisting of a single student (and you cannot create a team consisting of at least two students).

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
void print(vector<int> a, int i) {
  for (int j = 0; i < i; j++) cout << a[j] << "  ";
  cout << " | ";
}
int main() {
  int n;
  cin >> n;
  vector<int> a;
  for (int i = 0; i < n; i++) {
    int x;
    cin >> x;
    a.push_back(x);
  }
  sort(a.begin(), a.end());
  int pivot = a[0];
  int ans[2] = {1, 0};
  int j = 0;
  for (int i = 1; i < n; i++) {
    if (a[i] == pivot) {
      ans[0]++;
      j++;
    } else if ((a[i] - pivot) <= 5) {
      ans[0]++;
    } else {
      ans[1] = ans[0] > ans[1] ? ans[0] : ans[1];
      ans[0] = 1;
      pivot = a[j + 1];
      i = j + 1;
      j = j + 1;
    }
  }
  ans[1] = ans[0] > ans[1] ? ans[0] : ans[1];
  cout << ans[1];
}