Problem: I have a sequence defined as follows:

* All even-numbered terms are equal to the previous term multiplied by 2.
* All odd-numbered terms are equal to the previous term divided by 3.



Create a program that reads the first term a of this sequence and outputs the sum s (10) from the first term to the tenth term.



Input

The input consists of multiple test cases. For each test case, a real number a (1.0 ≤ a ≤ 10.0) representing the first term of the sequence is given in one row.

The number of test cases does not exceed 50.

Output

Print s (10) on one line for each test case.

The output may contain an error of 0.000001 or less.

Example

Input

1.0
2.0
3.0


Output

7.81481481
15.62962963
23.44444444

Solution (in CPP):

Solution:
#include <cstdio>
using namespace std;

int main(){
	double sum, a[10], n;

	while( scanf("%lf" , &n ) != EOF ){
		sum = n;
		a[0] = n;
		for(int i=1 ; i<10 ; ++i){
			a[i] = ( i%2 )? a[i-1]*2.0 : a[i-1]/3.0 ;
			sum += a[i];
		}
		printf("%.8f\n", sum);
	}
}