Problem: You are a coach at your local university. There are n students under your supervision, the programming skill of the i-th student is a_i.

You have to create a team for a new programming competition. As you know, the more students some team has the more probable its victory is! So you have to create a team with the maximum number of students. But you also know that a team should be balanced. It means that the programming skill of each pair of students in a created team should differ by no more than 5.

Your task is to report the maximum possible number of students in a balanced team.

Input

The first line of the input contains one integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the number of students.

The second line of the input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9), where a_i is a programming skill of the i-th student.

Output

Print one integer — the maximum possible number of students in a balanced team.

Examples

Input


6
1 10 17 12 15 2


Output


3


Input


10
1337 1337 1337 1337 1337 1337 1337 1337 1337 1337


Output


10


Input


6
1 1000 10000 10 100 1000000000


Output


1

Note

In the first example you can create a team with skills [12, 17, 15].

In the second example you can take all students in a team because their programming skills are equal.

In the third example you can create a team consisting of a single student (and you cannot create a team consisting of at least two students).

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int main() {
  int n;
  scanf("%d", &n);
  vector<long long> arr(n);
  for (int i = 0; i < n; i++) scanf("%lld", &arr[i]);
  sort(arr.begin(), arr.end());
  int max_val = 0;
  for (int i = 0; i < n; i++) {
    long long curr_val = arr[i];
    for (int j = 0; j < 5; j++) {
      int low = static_cast<int>(
          upper_bound(arr.begin(), arr.end(), curr_val + (5 - j)) -
          arr.begin());
      int up = static_cast<int>(
          lower_bound(arr.begin(), arr.end(), curr_val - j) - arr.begin());
      max_val = max(max_val, (low - up));
    }
  }
  printf("%d", max_val);
  return 0;
}