Problem: I have a sequence defined as follows:

* All even-numbered terms are equal to the previous term multiplied by 2.
* All odd-numbered terms are equal to the previous term divided by 3.



Create a program that reads the first term a of this sequence and outputs the sum s (10) from the first term to the tenth term.



Input

The input consists of multiple test cases. For each test case, a real number a (1.0 ≤ a ≤ 10.0) representing the first term of the sequence is given in one row.

The number of test cases does not exceed 50.

Output

Print s (10) on one line for each test case.

The output may contain an error of 0.000001 or less.

Example

Input

1.0
2.0
3.0


Output

7.81481481
15.62962963
23.44444444

Solution (in CPP):

Solution:
#include <iostream>
#include <stdio.h>
using namespace std;

int main()
{
	double a, n[10] = {};

	while (cin >> a)
	{
		n[0] = a;
		double sum = n[0];
		for (int i = 1; i < 10; i++)
		{
			if (i % 2 == 1) n[i] = n[i - 1] * 2;
			else  n[i] = n[i - 1] / 3.0; 
			sum += n[i];
	//		cout << n[i] << " ";
		}
		//cout << endl;
		printf("%.6f\n", sum);
	}
	return 0;
}