Problem: Kostya is a genial sculptor, he has an idea: to carve a marble sculpture in the shape of a sphere. Kostya has a friend Zahar who works at a career. Zahar knows about Kostya's idea and wants to present him a rectangular parallelepiped of marble from which he can carve the sphere. 

Zahar has n stones which are rectangular parallelepipeds. The edges sizes of the i-th of them are ai, bi and ci. He can take no more than two stones and present them to Kostya. 

If Zahar takes two stones, he should glue them together on one of the faces in order to get a new piece of rectangular parallelepiped of marble. Thus, it is possible to glue a pair of stones together if and only if two faces on which they are glued together match as rectangles. In such gluing it is allowed to rotate and flip the stones in any way. 

Help Zahar choose such a present so that Kostya can carve a sphere of the maximum possible volume and present it to Zahar.

Input

The first line contains the integer n (1 ≤ n ≤ 105).

n lines follow, in the i-th of which there are three integers ai, bi and ci (1 ≤ ai, bi, ci ≤ 109) — the lengths of edges of the i-th stone. Note, that two stones may have exactly the same sizes, but they still will be considered two different stones.

Output

In the first line print k (1 ≤ k ≤ 2) the number of stones which Zahar has chosen. In the second line print k distinct integers from 1 to n — the numbers of stones which Zahar needs to choose. Consider that stones are numbered from 1 to n in the order as they are given in the input data.

You can print the stones in arbitrary order. If there are several answers print any of them. 

Examples

Input

6
5 5 5
3 2 4
1 4 1
2 1 3
3 2 4
3 3 4


Output

1
1


Input

7
10 7 8
5 10 3
4 2 6
5 5 5
10 2 8
4 2 1
7 7 7


Output

2
1 5

Note

In the first example we can connect the pairs of stones:

  * 2 and 4, the size of the parallelepiped: 3 × 2 × 5, the radius of the inscribed sphere 1
  * 2 and 5, the size of the parallelepiped: 3 × 2 × 8 or 6 × 2 × 4 or 3 × 4 × 4, the radius of the inscribed sphere 1, or 1, or 1.5 respectively. 
  * 2 and 6, the size of the parallelepiped: 3 × 5 × 4, the radius of the inscribed sphere 1.5
  * 4 and 5, the size of the parallelepiped: 3 × 2 × 5, the radius of the inscribed sphere 1
  * 5 and 6, the size of the parallelepiped: 3 × 4 × 5, the radius of the inscribed sphere 1.5



Or take only one stone:

  * 1 the size of the parallelepiped: 5 × 5 × 5, the radius of the inscribed sphere 2.5
  * 2 the size of the parallelepiped: 3 × 2 × 4, the radius of the inscribed sphere 1
  * 3 the size of the parallelepiped: 1 × 4 × 1, the radius of the inscribed sphere 0.5
  * 4 the size of the parallelepiped: 2 × 1 × 3, the radius of the inscribed sphere 0.5
  * 5 the size of the parallelepiped: 3 × 2 × 4, the radius of the inscribed sphere 1
  * 6 the size of the parallelepiped: 3 × 3 × 4, the radius of the inscribed sphere 1.5



It is most profitable to take only the first stone. 

Solution (in JAVA):

Solution:
//package cf.r378;

import java.io.BufferedInputStream;
import java.io.BufferedOutputStream;
import java.io.IOException;
import java.io.PrintWriter;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.HashMap;
import java.util.HashSet;
import java.util.List;
import java.util.Map;
import java.util.Scanner;
import java.util.Set;

public class D {

	public static void main(String[] args) throws IOException {
		Scanner sc = new Scanner(new BufferedInputStream(System.in));
		PrintWriter out = new PrintWriter(new BufferedOutputStream(System.out));

		List<Block> blocks = new ArrayList<>();
		
		Map<Side, Block> max = new HashMap<>();
		Map<Block, Integer> idx = new HashMap<>();
		
		
		int num = sc.nextInt();
		for (int i = 0; i < num; i++) {
			int[] sides = new int[3];
			for (int j = 0; j < sides.length; j++) {
				sides[j] = sc.nextInt();
			}
			Arrays.sort(sides);
			int k = 0;
			Block block = new Block(sides[k++], sides[k++], sides[k++]);
			
			blocks.add(block);
			
			idx.put(blocks.get(i), i);
			
			List<Side> sideObjs = block.getSides();
			for (Side side : sideObjs) {
				Block block1 = max.get(side);
				if (block1 == null || block.compareTo(block1) > 0) {
					max.put(side, block);
				}
			}			
		}

		int msi = -1;
		int ms = 0;
		int mti1 = -1;
		int mti2 = -1;
		int mt1 = 0;

		for (int i = 0; i < blocks.size(); i++) {
			Block block = blocks.get(i);
			if (block.getMin() > ms) {
				msi = i;
				ms = block.getMin();
			}

			for (Side side : block.getSides()) {
				Block block1 = max.get(side);
				if (block1 == block) continue;
				
				int ortho = side.getOrtho();
				int ortho1 = 0;
				Set<Side> sides1 = new HashSet<>(block1.getSides());
				for (Side side1 : sides1) {
					if (side1.equals(side)) {
						ortho1 = side1.getOrtho();
					}
				}

				int sum = ortho + ortho1;
				int mm = Math.min(Math.min(sum, side.a), side.b);
				if (mm > mt1) {
					mt1 = mm;
					mti1 = i;
					mti2 = idx.get(block1);
				}
			}
		}

		if (mt1 > ms) {
			out.println(2);
			out.println((mti1 + 1) + " " + (mti2 + 1));
		} else {
			out.println(1);
			out.println(msi + 1);
		}

		out.close();
	}

	private static class Block implements Comparable {
		private final int a;
		private final int b;
		private final int c;

		public Block(int a, int b, int c) {
			this.a = a;
			this.b = b;
			this.c = c;
		}

		public List<Side> getSides() {
			return Arrays.asList(new Side(a, b, c), new Side(b, c, a), new Side(a, c, b));
		}

		@Override
		public int compareTo(Object o) {
			Block other = (Block) o;
			if (a > other.a) {
				return 1;
			}
			if (b > other.b) {
				return 1;
			}
			if (c > other.c) {
				return 1;
			}

			if (a < other.a) {
				return -1;
			}
			if (b < other.b) {
				return -1;
			}
			if (c < other.c) {
				return -1;
			}

			return 0;
		}

		public int getMin() {
			return Math.min(Math.min(a, b), c);
		}
	}

	private static class Side {
		private final int a;
		private final int b;
		private int ortho;

		public Side(int a, int b, int ortho) {
			this.a = a;
			this.b = b;
			this.ortho = ortho;
		}

		public int getOrtho() {
			return ortho;
		}

		@Override
		public boolean equals(Object o) {
			if (this == o) return true;
			if (o == null || getClass() != o.getClass()) return false;

			Side side = (Side) o;

			if (a != side.a) return false;
			return b == side.b;

		}

		@Override
		public int hashCode() {
			int result = a;
			result = 31 * result + b;
			return result;
		}
	}

}