Problem: Polycarp has interviewed Oleg and has written the interview down without punctuation marks and spaces to save time. Thus, the interview is now a string s consisting of n lowercase English letters.

There is a filler word ogo in Oleg's speech. All words that can be obtained from ogo by adding go several times to the end of it are also considered to be fillers. For example, the words ogo, ogogo, ogogogo are fillers, but the words go, og, ogog, ogogog and oggo are not fillers.

The fillers have maximal size, for example, for ogogoo speech we can't consider ogo a filler and goo as a normal phrase. We should consider ogogo as a filler here.

To print the interview, Polycarp has to replace each of the fillers with three asterisks. Note that a filler word is replaced with exactly three asterisks regardless of its length.

Polycarp has dealt with this problem in no time. Can you do the same? The clock is ticking!

Input

The first line contains a positive integer n (1 ≤ n ≤ 100) — the length of the interview.

The second line contains the string s of length n, consisting of lowercase English letters.

Output

Print the interview text after the replacement of each of the fillers with "***". It is allowed for the substring "***" to have several consecutive occurences.

Examples

Input

7
aogogob


Output

a***b


Input

13
ogogmgogogogo


Output

***gmg***


Input

9
ogoogoogo


Output

*********

Note

The first sample contains one filler word ogogo, so the interview for printing is "a***b".

The second sample contains two fillers ogo and ogogogo. Thus, the interview is transformed to "***gmg***".

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
using namespace chrono;
const long long SZ = 1e5 + 7;
const long long inf = 1e18;
const long long mod = 1e9 + 7;
const long long MOD = 998244353;
const long double PI = 3.1415926535897932384;
void __print(int x) { cerr << x; }
void __print(long long x) { cerr << x; }
void __print(unsigned long long x) { cerr << x; }
void __print(long double x) { cerr << x; }
void __print(char x) { cerr << x; }
void __print(const char *x) { cerr << x; }
void __print(const string &x) { cerr << x; }
void __print(bool x) { cerr << (x ? "true" : "false"); }
template <typename T, typename V>
void __print(const pair<T, V> &x) {
  cerr << '{';
  __print(x.first);
  cerr << ", ";
  __print(x.second);
  cerr << '}';
}
template <typename T>
void __print(const T &x) {
  int f = 0;
  cerr << '{';
  for (auto &i : x) {
    cerr << (f++ ? ", " : "");
    __print(i);
  }
  cerr << "}";
}
void _print() { cerr << "]\n"; }
template <typename T, typename... V>
void _print(T t, V... v) {
  __print(t);
  if (sizeof...(v)) {
    cerr << ", ";
  }
  _print(v...);
}
long long tc_cnt = 1;
auto clk = clock();
mt19937_64 rang(high_resolution_clock::now().time_since_epoch().count());
void run_time() {
  cerr << endl;
  cerr << "Time elapsed: " << (double)(clock() - clk) / CLOCKS_PER_SEC << endl;
  return;
}
long long int powermod(long long int a, long long int b) {
  long long int ans = 1;
  while (b) {
    if (b & 1) ans = (ans * a) % mod;
    b = b >> 1;
    a = (a * a) % mod;
  }
  return ans;
}
long long int modadd(long long int a, long long int b, long long int m = mod) {
  a = a % m;
  b = b % m;
  return (((a + b) % m) + m) % m;
}
long long int modsub(long long int a, long long int b, long long int m = mod) {
  a = a % m;
  b = b % m;
  return (((a - b) % m) + m) % m;
}
long long int modmul(long long int a, long long int b, long long int m = mod) {
  a = a % m;
  b = b % m;
  return (((a * b) % m) + m) % m;
}
long long int modinv(long long int a, long long int m = mod) {
  return powermod(a, m - 2);
}
long long int gcd(long long int a, long long int b) {
  if (b == 0) return a;
  return gcd(b, a % b);
}
long long int lcm(long long int a, long long int b) {
  return (a / gcd(a, b)) * b;
}
bool compare(const pair<long long int, long long int> &a,
             const pair<long long int, long long int> &b) {
  if (a.first == b.first) {
    return a.second < b.second;
  }
  return a.first < b.first;
}
void solve() {
  long long n;
  cin >> n;
  string s;
  cin >> s;
  string ans = "";
  for (long long i = 0; i < (n); i++) {
    if (s[i] == 'o' && s[i + 1] == 'g' && s[i + 2] == 'o') {
      ans.push_back('*');
      ans.push_back('*');
      ans.push_back('*');
      i += 3;
      while (s[i] == 'g' && s[i + 1] == 'o' && i + 1 < n) {
        i += 2;
      }
      i--;
    } else {
      ans.push_back(s[i]);
    }
  }
  for (long long i = 0; i < (ans.size()); i++) {
    cout << ans[i];
  }
  cout << "\n";
  return;
}
int main() {
  ios_base::sync_with_stdio(0);
  cin.tie(0);
  cout.tie(0);
  cerr << endl;
  { solve(); }
  run_time();
  return 0;
}