Problem: Given a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both `voodoo` and `melee` are unbalanced, while neither `noon` nor `a` is.

You are given a string s consisting of lowercase letters. Determine if there exists a (contiguous) substring of s that is unbalanced. If the answer is positive, show a position where such a substring occurs in s.

Constraints

* 2 ≦ |s| ≦ 10^5
* s consists of lowercase letters.

Input

The input is given from Standard Input in the following format:


s


Output

If there exists no unbalanced substring of s, print `-1 -1`.

If there exists an unbalanced substring of s, let one such substring be s_a s_{a+1} ... s_{b} (1 ≦ a < b ≦ |s|), and print `a b`. If there exists more than one such substring, any of them will be accepted.

Examples

Input

needed


Output

2 5


Input

atcoder


Output

-1 -1

Solution (in CPP):

Solution:
#include<cstdio>
#include<cstring>
#include<iostream>
using namespace std;
char a[100000+5];
int alen;
int main()
{
	scanf("%s",a);
	alen=strlen(a);
	for(int i=0;i<alen-1;i++)
		if(a[i]==a[i+1])
		{
			printf("%d %d\n",i+1,i+2);
			return 0;
		}
	for(int i=0;i<alen-2;i++)
		if(a[i]==a[i+1]||a[i]==a[i+2]||a[i+1]==a[i+2])
		{
			printf("%d %d\n",i+1,i+3);
			return 0;
		}
	printf("-1 -1\n");
	return 0;
}