Problem: Sasha likes investigating different math objects, for example, magic squares. But Sasha understands that magic squares have already been studied by hundreds of people, so he sees no sense of studying them further. Instead, he invented his own type of square — a prime square. 

A square of size n × n is called prime if the following three conditions are held simultaneously: 

  * all numbers on the square are non-negative integers not exceeding 10^5; 
  * there are no prime numbers in the square; 
  * sums of integers in each row and each column are prime numbers. 



Sasha has an integer n. He asks you to find any prime square of size n × n. Sasha is absolutely sure such squares exist, so just help him!

Input

The first line contains a single integer t (1 ≤ t ≤ 10) — the number of test cases.

Each of the next t lines contains a single integer n (2 ≤ n ≤ 100) — the required size of a square.

Output

For each test case print n lines, each containing n integers — the prime square you built. If there are multiple answers, print any.

Example

Input


2
4
2


Output


4 6 8 1
4 9 9 9
4 10 10 65
1 4 4 4
1 1
1 1

Solution (in PYTHON3):

Solution:
from collections import Counter
import string
import math
import sys
from fractions import Fraction
def array_int():
    return [int(i) for i in sys.stdin.readline().split()]
def vary(arrber_of_variables):
    if arrber_of_variables==1:
        return int(sys.stdin.readline())
    if arrber_of_variables>=2:
        return map(int,sys.stdin.readline().split()) 
def makedict(var):
    return dict(Counter(var))
# i am noob wanted to be better and trying hard for that
def printDivisors(n): 
    divisors=[]  
    # Note that this loop runs till square root 
    i = 1
    while i <= math.sqrt(n): 
          
        if (n % i == 0) : 
              
            # If divisors are equal, print only one 
            if (n//i == i) : 
                divisors.append(i) 
            else : 
                # Otherwise print both 
                divisors.extend((i,n//i)) 
        i = i + 1
    return divisors
 
def countTotalBits(num):
     
     # convert number into it's binary and 
     # remove first two characters 0b.
     binary = bin(num)[2:]
     return(len(binary))
def isPrime(n) : 
  
    # Corner cases 
    if (n <= 1) : 
        return False
    if (n <= 3) : 
        return True
  
    # This is checked so that we can skip  
    # middle five numbers in below loop 
    if (n % 2 == 0 or n % 3 == 0) : 
        return False
  
    i = 5
    while(i * i <= n) : 
        if (n % i == 0 or n % (i + 2) == 0) : 
            return False
        i = i + 6
  
    return True
""" def dfs(node,val):
    global tree,visited
    visited[node]=1
    ans[node]=val
    val^=1
    for i in tree[node]:
        if visited[i]==-1:
            dfs(i,val) """
for _ in range(vary(1)):
    n=vary(1)
    # print(isPrime(9+8))
    if isPrime(n):
        for i in range(n):
            for j in range(n):
                print(1,end=" ")
            print()
    else:
        ft=n-1
        pt=4
        while 1:
            # print(pt)
            if isPrime(pt)==False:
                if isPrime(pt+ft)==True:
                    break
                else:
                    pt+=1
            else:
                pt+=1
        kt=0
        for i in range(n):
            kt+=1
            for j in range(n):
                if j==kt-1:
                    print(pt,end=" ")
                else:
                    print(1,end=" ")
            print()