Problem: Levko loves permutations very much. A permutation of length n is a sequence of distinct positive integers, each is at most n.

Let’s assume that value gcd(a, b) shows the greatest common divisor of numbers a and b. Levko assumes that element pi of permutation p1, p2, ... , pn is good if gcd(i, pi) > 1. Levko considers a permutation beautiful, if it has exactly k good elements. Unfortunately, he doesn’t know any beautiful permutation. Your task is to help him to find at least one of them.

Input

The single line contains two integers n and k (1 ≤ n ≤ 105, 0 ≤ k ≤ n).

Output

In a single line print either any beautiful permutation or -1, if such permutation doesn’t exist.

If there are multiple suitable permutations, you are allowed to print any of them.

Examples

Input

4 2


Output

2 4 3 1

Input

1 1


Output

-1

Note

In the first sample elements 4 and 3 are good because gcd(2, 4) = 2 > 1 and gcd(3, 3) = 3 > 1. Elements 2 and 1 are not good because gcd(1, 2) = 1 and gcd(4, 1) = 1. As there are exactly 2 good elements, the permutation is beautiful.

The second sample has no beautiful permutations.

Solution (in JAVA):

Solution:
import java.io.*;
import java.math.BigInteger;
import java.util.*;

public class Main {
    InputReader in; PrintWriter out;
    void solve() {
        int n = in.nextInt();
        int k = in.nextInt();

        if (k >= n) {
            out.println("-1");
            return;
        }

        int[] ans = new int[n];
        int left = n - k;
        for (int i = 1; i < left; i++) {
            ans[i] = i;
        }
        ans[0] = left;
        for (int i = left; i < n; i++) {
            ans[i] = i + 1;
        }
        for (int i = 0; i < n; i++) {
            out.print(ans[i]);
            if (i < n - 1) {
                out.print(" ");
            }
        }
        out.println();
    }

    public long calcPower(long number, long base) {
        long ans = 0;
        while (number % base == 0 && number > 0) {
            ans++;
            number = number / base;
        }
        return ans;
    }

    Main(){
        boolean oj = System.getProperty("ONLINE_JUDGE") != null;
        try {
            if (oj) {
                in = new InputReader(System.in);
                out = new PrintWriter(System.out);
            }
            else {
                Writer w = new FileWriter("output.txt");
                in = new InputReader(new FileReader("input.txt"));
                out = new PrintWriter(w);
            }
        } catch(Exception e) {
            throw new RuntimeException(e);
        }
        solve();
        out.close();
    }
    public static void main(String[] args){
        new Main();
    }
}

class InputReader {
    private BufferedReader reader;
    private StringTokenizer tokenizer;

    public InputReader(InputStream stream) {
        reader = new BufferedReader(new InputStreamReader(stream));
        tokenizer = null;
    }

    public InputReader(FileReader fr) {
        reader = new BufferedReader(fr);
        tokenizer = null;
    }

    public String next() {
        while (tokenizer == null || !tokenizer.hasMoreTokens()) {
            try {
                tokenizer = new StringTokenizer(reader.readLine());
            } catch (IOException e) {
                throw new RuntimeException(e);
            }
        }
        return tokenizer.nextToken();
    }
    public int nextInt() {
        return Integer.parseInt(next());
    }
    public long nextLong() {
        return Long.parseLong(next());
    }
    public double nextDouble() {
        return Double.parseDouble(next());
    }

}