Problem: A TV show called "Guess a number!" is gathering popularity. The whole Berland, the old and the young, are watching the show.

The rules are simple. The host thinks of an integer y and the participants guess it by asking questions to the host. There are four types of acceptable questions:

  * Is it true that y is strictly larger than number x? 
  * Is it true that y is strictly smaller than number x? 
  * Is it true that y is larger than or equal to number x? 
  * Is it true that y is smaller than or equal to number x? 



On each question the host answers truthfully, "yes" or "no".

Given the sequence of questions and answers, find any integer value of y that meets the criteria of all answers. If there isn't such value, print "Impossible".

Input

The first line of the input contains a single integer n (1 ≤ n ≤ 10000) — the number of questions (and answers). Next n lines each contain one question and one answer to it. The format of each line is like that: "sign x answer", where the sign is:

  * ">" (for the first type queries), 
  * "<" (for the second type queries), 
  * ">=" (for the third type queries), 
  * "<=" (for the fourth type queries). 



All values of x are integer and meet the inequation  - 109 ≤ x ≤ 109. The answer is an English letter "Y" (for "yes") or "N" (for "no").

Consequtive elements in lines are separated by a single space.

Output

Print any of such integers y, that the answers to all the queries are correct. The printed number y must meet the inequation  - 2·109 ≤ y ≤ 2·109. If there are many answers, print any of them. If such value doesn't exist, print word "Impossible" (without the quotes).

Examples

Input

4
&gt;= 1 Y
&lt; 3 N
&lt;= -3 N
&gt; 55 N


Output

17


Input

2
&gt; 100 Y
&lt; -100 Y


Output

Impossible

Solution (in PYTHON3):

Solution:
import math,sys
#from itertools import permutations, combinations;import heapq,random;
from collections import defaultdict,deque
import bisect as bi
def yes():print('YES')
def no():print('NO')
def I():return (int(sys.stdin.readline()))
def In():return(map(int,sys.stdin.readline().split()))
def Sn():return sys.stdin.readline().strip()
#sys.setrecursionlimit(1500)
def dict(a):
    d={} 
    for x in a:
        if d.get(x,-1)!=-1:
            d[x]+=1
        else:
            d[x]=1
    return d
def find_gt(a, x):
    'Find leftmost value greater than x'
    i = bi.bisect_left(a, x)
    if i != len(a):
        return i
    else:            
        return -1
        
def main():
    try:
        n=I()
        low,high=-P,P
        for i in range(n):
            Q=Sn().split()
            if Q[-1]=='Y':
                if Q[0]=='>':
                    low=max(low,int(Q[1])+1)
                elif Q[0]=='>=':
                    low=max(low,int(Q[1]))
                if Q[0]=='<':
                    high=min(high,int(Q[1])-1)
                elif Q[0]=='<=':
                    high=min(high,int(Q[1]))
            if Q[-1]=='N':
                if Q[0]=='<':
                    low=max(low,int(Q[1]))
                elif Q[0]=='<=':
                    low=max(low,int(Q[1])+1)
                if Q[0]=='>':
                    high=min(high,int(Q[1]))
                elif Q[0]=='>=':
                    high=min(high,int(Q[1])-1)
        if high<low:
            print('Impossible')
        else:
            print(low)
    except:
        pass
        
M = 998244353
P = 1000000007
 
if __name__ == '__main__':
    # for _ in range(I()):main()
    for _ in range(1):main()
#        *******************    All The Best    *******************   #