Problem: Vasya has an array a_1, a_2, ..., a_n.

You don't know this array, but he told you m facts about this array. The i-th fact is a triple of numbers t_i, l_i and r_i (0 ≤ t_i ≤ 1, 1 ≤ l_i < r_i ≤ n) and it means:

  * if t_i=1 then subbarray a_{l_i}, a_{l_i + 1}, ..., a_{r_i} is sorted in non-decreasing order; 
  * if t_i=0 then subbarray a_{l_i}, a_{l_i + 1}, ..., a_{r_i} is not sorted in non-decreasing order. A subarray is not sorted if there is at least one pair of consecutive elements in this subarray such that the former is greater than the latter. 



For example if a = [2, 1, 1, 3, 2] then he could give you three facts: t_1=1, l_1=2, r_1=4 (the subarray [a_2, a_3, a_4] = [1, 1, 3] is sorted), t_2=0, l_2=4, r_2=5 (the subarray [a_4, a_5] = [3, 2] is not sorted), and t_3=0, l_3=3, r_3=5 (the subarray [a_3, a_5] = [1, 3, 2] is not sorted).

You don't know the array a. Find any array which satisfies all the given facts.

Input

The first line contains two integers n and m (2 ≤ n ≤ 1000, 1 ≤ m ≤ 1000).

Each of the next m lines contains three integers t_i, l_i and r_i (0 ≤ t_i ≤ 1, 1 ≤ l_i < r_i ≤ n).

If t_i = 1 then subbarray a_{l_i}, a_{l_i + 1}, ... , a_{r_i} is sorted. Otherwise (if t_i = 0) subbarray a_{l_i}, a_{l_i + 1}, ... , a_{r_i} is not sorted.

Output

If there is no array that satisfies these facts in only line print NO (in any letter case).

If there is a solution, print YES (in any letter case). In second line print n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9) — the array a, satisfying all the given facts. If there are multiple satisfying arrays you can print any of them.

Examples

Input


7 4
1 1 3
1 2 5
0 5 6
1 6 7


Output


YES
1 2 2 3 5 4 4


Input


4 2
1 1 4
0 2 3


Output


NO

Solution (in PYTHON3):

Solution:
import sys,math

def read_int():
    return int(sys.stdin.readline().strip())

def read_int_list():
    return list(map(int,sys.stdin.readline().strip().split()))

def read_string():
    return sys.stdin.readline().strip()

def read_string_list(delim=" "):
    return sys.stdin.readline().strip().split(delim)

def print_list(l, delim=" "):
    print(delim.join(map(str, l)))


###### Author : Samir Vyas #######
###### Write Code Below    #######

n,q = read_int_list()
diffs = [1 for _ in range(n)]

tlrs = []
for _ in range(q):
	tlrs.append(read_int_list())


for t,l,r in tlrs:
	if t == 1:
		for i in range(l,r):
			diffs[i] = 0

for t,l,r in tlrs:
	if t == 0:
		all_0 = True
		for i in range(l,r):
			if diffs[i] != 0:
				all_0 = False
				break
		if all_0:
			print("NO")
			sys.exit()
		for i in range(l,r):
			if diffs[i] == 1:
				diffs[i] = -1

		


# print(diffs)
print("YES")
last = n
print(last, end=" ")
for i in range(1,n):
	last += diffs[i]
	print(last, end=" ")

print()