Problem: You are given a directed graph G which can contain loops (edges from a vertex to itself). Multi-edges are absent in G which means that for all ordered pairs (u, v) exists at most one edge from u to v. Vertices are numbered from 1 to n.

A path from u to v is a sequence of edges such that:

  * vertex u is the start of the first edge in the path; 
  * vertex v is the end of the last edge in the path; 
  * for all pairs of adjacent edges next edge starts at the vertex that the previous edge ends on. 



We will assume that the empty sequence of edges is a path from u to u.

For each vertex v output one of four values:

  * 0, if there are no paths from 1 to v; 
  * 1, if there is only one path from 1 to v; 
  * 2, if there is more than one path from 1 to v and the number of paths is finite; 
  * -1, if the number of paths from 1 to v is infinite. 



Let's look at the example shown in the figure.

<image>

Then:

  * the answer for vertex 1 is 1: there is only one path from 1 to 1 (path with length 0); 
  * the answer for vertex 2 is 0: there are no paths from 1 to 2; 
  * the answer for vertex 3 is 1: there is only one path from 1 to 3 (it is the edge (1, 3)); 
  * the answer for vertex 4 is 2: there are more than one paths from 1 to 4 and the number of paths are finite (two paths: [(1, 3), (3, 4)] and [(1, 4)]); 
  * the answer for vertex 5 is -1: the number of paths from 1 to 5 is infinite (the loop can be used in a path many times); 
  * the answer for vertex 6 is -1: the number of paths from 1 to 6 is infinite (the loop can be used in a path many times). 

Input

The first contains an integer t (1 ≤ t ≤ 10^4) — the number of test cases in the input. Then t test cases follow. Before each test case, there is an empty line.

The first line of the test case contains two integers n and m (1 ≤ n ≤ 4 ⋅ 10^5, 0 ≤ m ≤ 4 ⋅ 10^5) — numbers of vertices and edges in graph respectively. The next m lines contain edges descriptions. Each line contains two integers a_i, b_i (1 ≤ a_i, b_i ≤ n) — the start and the end of the i-th edge. The vertices of the graph are numbered from 1 to n. The given graph can contain loops (it is possible that a_i = b_i), but cannot contain multi-edges (it is not possible that a_i = a_j and b_i = b_j for i ≠ j).

The sum of n over all test cases does not exceed 4 ⋅ 10^5. Similarly, the sum of m over all test cases does not exceed 4 ⋅ 10^5.

Output

Output t lines. The i-th line should contain an answer for the i-th test case: a sequence of n integers from -1 to 2.

Example

Input


5

6 7
1 4
1 3
3 4
4 5
2 1
5 5
5 6

1 0

3 3
1 2
2 3
3 1

5 0

4 4
1 2
2 3
1 4
4 3


Output


1 0 1 2 -1 -1 
1 
-1 -1 -1 
1 0 0 0 0 
1 1 2 1 

Solution (in JAVA):

Solution:


import java.io.*;
import java.util.*;

public class CodeForces {
    /*****************************************WRITING CODE STARTS HERE******************************************/


    private static void findCycleNodes(int curr,Deque<Integer> currStack, boolean[] visited,boolean[] isInCurrStack){
        if(isInCurrStack[curr]){
            cycleNodes.add(curr);
            return;
        }
        currStack.push(curr);
        isInCurrStack[curr] = true;
        for(int neig : adj[curr]){
            if(!visited[neig])
                findCycleNodes(neig,currStack,visited,isInCurrStack);
        }
        visited[curr] = true;
        isInCurrStack[curr] = false;
        currStack.pop();

    }
    private static void dfs(int curr){
        visited[curr] = true;
        res[curr] = -1;
        for(int neig : adj[curr])
            if(!visited[neig])
                dfs(neig);
    }
    private static void dfs2(int curr){
        res[curr]++;
        if(res[curr]>2){
            res[curr] = 2;
            return;
        }
        for(int neig : adj[curr])
            if(!visited[neig])
                dfs2(neig);
    }
    static ArrayList<Integer>[] adj;
    static List<Integer> cycleNodes;
    static int[] res;
    static boolean[] visited;
    public static void solve(int test)throws IOException {
       int n = sc.nextInt();
       int m = sc.nextInt();
       adj = new ArrayList[n+1];
        cycleNodes = new ArrayList<>();
        res = new int[n+1];
        visited = new boolean[n+1];
       for(int i=0;i<=n;i++){
           adj[i] = new ArrayList<>();
       }
       for(int i=0;i<m;i++){
           int x = sc.nextInt();
           int y = sc.nextInt();
           adj[x].add(y);
       }
       findCycleNodes(1,new ArrayDeque<>(),new boolean[n+1],new boolean[n+1]);
       for(int ele : cycleNodes)
           if(!visited[ele])
               dfs(ele);
       if(res[1] !=-1){
           dfs2(1);
       }
       for(int i=1;i<=n;i++)out.print(res[i]+" ");
       out.println();



    }
    /*****************************************WRITING CODE ENDS HERE******************************************/

    public static void main(String[] args) throws IOException{
        int testCase = 1;
        testCase = sc.nextInt();
        long start = System.currentTimeMillis();
        for (int i = 1; i <= testCase; i++) solve(i);
//        out.println(((System.currentTimeMillis()) - start )/1000d);
        closeIO();
    }
    static FastestReader sc = new FastestReader();              // FASTEST INPUT
    static PrintWriter out = new PrintWriter(System.out);                // FAST OUTPUT


    /**************************************HELPER FUNCTION STARTS HERE ************************************/

    public static int mod = (int) 1e9 + 7;
    public static final int inf_int = (int) 1e9;
    public static final long inf_long = (long) 1e12;

    public static final String YES = "YES";
    public static final String NO = "NO";

    public static void sort(int[] a, boolean isAscending) {
        ArrayList<Integer> temp = new ArrayList<>();
        for (int j : a) temp.add(j);
        sort(temp, isAscending);
        for (int i = 0; i < a.length; i++) a[i] = temp.get(i);
    }

    public static void sort(long[] a, boolean isAscending) {
        ArrayList<Long> temp = new ArrayList<>();
        for (long ele : a) temp.add(ele);
        sort(temp, isAscending);
        for (int i = 0; i < a.length; i++) a[i] = temp.get(i);
    }
    @SuppressWarnings({"rawtypes","unchecked"})
    public static void sort(List list, boolean isAscending) {
        if (isAscending)
            Collections.sort(list);
        else list.sort(Collections.reverseOrder());
    }

    // count the length of a number, time O(1)
    public static int countDigitBase10(long n) {
        if (n == 0) return 0;
        return (int) (1 + Math.log10(n));
    }

    // euclidean algorithm
    public static long gcd(long a, long b) {
        // time O(max (loga ,logb))
        long x = Math.min(a, b);
        long y = Math.max(a, b);
        if (y % x == 0) return x;
        return gcd(y % x, x);
    }

    public static long lcm(long a, long b) {
        // lcm(a,b) * gcd(a,b) = a * b
        return (a / gcd(a, b)) * b;
    }

    public static long power(long x, long n) {
        // time O(logn)
        long ans = 1;
        while (n > 0) {
            if ((n & 1) == 1) {
                ans *= x;
                ans %= mod;
                n--;
            } else {
                x *= x;
                x %= mod;
                n >>= 1;
            }
        }
        return ans;
    }

    public static long firstDivisor(long n) {
        if (n == 1 || n == 0) return n;
        for (long i = 2; i * i <= n; i++)
            if (n % i == 0) return i;
        return -1;
    }

    public static long max3(long a, long b, long c) {
        return max2(max2(a, b), c);
    }

    public static long max2(long a, long b) {
        return Math.max(a, b);
    }

    public static long min3(long a, long b, long c) {
        return min2(min2(a, b), c);
    }

    public static long min2(long a, long b) {
        return Math.min(a, b);
    }

    public static int max3(int a, int b, int c) {
        return max2(max2(a, b), c);
    }

    public static int max2(int a, int b) {
        return Math.max(a, b);
    }

    public static int min3(int a, int b, int c) {
        return min2(min2(a, b), c);
    }

    public static int min2(int a, int b) {
        return Math.min(a, b);
    }

    /**************************************HELPER FUNCTION ENDS HERE ************************************/

    /*****************************************FAST INPUT STARTS HERE *************************************/


    public static void closeIO() throws IOException{
            out.flush();
            out.close();
            sc.close();
    }
    private static class FastestReader {
        private static final int BUFFER_SIZE = 1 << 16;
        private final DataInputStream din;
        private final byte[] buffer;
        private int bufferPointer, bytesRead;

        FastestReader() {
            din = new DataInputStream(System.in);
            buffer = new byte[BUFFER_SIZE];
            bufferPointer = bytesRead = 0;
        }

        FastestReader(String file_name) throws IOException {
            din = new DataInputStream(new FileInputStream(file_name));
            buffer = new byte[BUFFER_SIZE];
            bufferPointer = bytesRead = 0;
        }

        public String nextLine() throws IOException {
            final byte[] buf = new byte[(1<<18)]; // 262144 at max line length
            int cnt = 0, c;
            while ((c = read()) != -1) {
                if (c == '\n') {
                    break;
                }
                buf[cnt++] = (byte) c;
            }
            return new String(buf, 0, cnt);
        }

        private static boolean isSpaceChar(int c) { return !(c >= 33 && c <= 126); }

        private int skip() throws IOException {
            int b;
            //noinspection StatementWithEmptyBody
            while ((b = read()) != -1 && isSpaceChar(b)) {}
            return b;
        }

        public String next() throws IOException {
            int b = skip();
            final StringBuilder sb = new StringBuilder();
            while (!isSpaceChar(b)) { // when nextLine, (isSpaceChar(b) && b != ' ')
                sb.appendCodePoint(b);
                b = read();
            }
            return sb.toString();
        }

        public int nextInt() throws IOException {
            int ret = 0;
            byte c = read();
            while (c <= ' ') {
                c = read();
            }
            final boolean neg = c == '-';
            if (neg) { c = read(); }
            do {
                ret = ret * 10 + c - '0';
            } while ((c = read()) >= '0' && c <= '9');

            if (neg) { return -ret; }
            return ret;
        }

        public long nextLong() throws IOException {
            long ret = 0;
            byte c = read();
            while (c <= ' ') { c = read(); }
            final boolean neg = c == '-';
            if (neg) { c = read(); }
            do {
                ret = ret * 10 + c - '0';
            } while ((c = read()) >= '0' && c <= '9');
            if (neg) { return -ret; }
            return ret;
        }

        public double nextDouble() throws IOException {
            double ret = 0, div = 1;
            byte c = read();
            while (c <= ' ') { c = read(); }
            final boolean neg = c == '-';
            if (neg) { c = read(); }

            do {
                ret = ret * 10 + c - '0';
            } while ((c = read()) >= '0' && c <= '9');

            if (c == '.') {
                while ((c = read()) >= '0' && c <= '9') {
                    ret += (c - '0') / (div *= 10);
                }
            }

            if (neg) { return -ret; }
            return ret;
        }

        private void fillBuffer() throws IOException {
            bytesRead = din.read(buffer, bufferPointer = 0, BUFFER_SIZE);
            if (bytesRead == -1) { buffer[0] = -1; }
        }

        private byte read() throws IOException {
            if (bufferPointer == bytesRead) { fillBuffer(); }
            return buffer[bufferPointer++];
        }

        public void close() throws IOException {
            din.close();
        }

    }
    /*****************************************FAST INPUT ENDS HERE *************************************/
}