Problem: There is a grid of squares with H+1 horizontal rows and W vertical columns.

You will start at one of the squares in the top row and repeat moving one square right or down. However, for each integer i from 1 through H, you cannot move down from the A_i-th, (A_i + 1)-th, \ldots, B_i-th squares from the left in the i-th row from the top.

For each integer k from 1 through H, find the minimum number of moves needed to reach one of the squares in the (k+1)-th row from the top. (The starting square can be chosen individually for each case.) If, starting from any square in the top row, none of the squares in the (k+1)-th row can be reached, print `-1` instead.

Constraints

* 1 \leq H,W \leq 2\times 10^5
* 1 \leq A_i \leq B_i \leq W

Input

Input is given from Standard Input in the following format:


H W
A_1 B_1
A_2 B_2
:
A_H B_H


Output

Print H lines. The i-th line should contain the answer for the case k=i.

Example

Input

4 4
2 4
1 1
2 3
2 4


Output

1
3
6
-1

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;

int main() {
  int W;
  cin >> W >> W;
  map<int, int> X;
  multiset<int> Y;
  for (int i = 0; i < W; i++) X[i] = i, Y.insert(0);
  for (int h = 1, A, B, C, D; cin >> A >> B;  ) {
    C = -1;
    for(auto j = X.lower_bound(--A);j != X.end() && j -> first <= B; X.erase(j++)){
      D = j -> first;
      C = max(C, X[D]);
      Y.erase(Y.find(D - X[D]));
    }
    if (C + 1 && B < W) X[B] = C, Y.insert(B - C);
    cout << ((Y.size()) ? *Y.begin() + h++ : -1) << "\n";
  }
}