Problem: The statement of this problem is the same as the statement of problem C1. The only difference is that, in problem C1, n is always even, and in C2, n is always odd.

You are given a regular polygon with 2 ⋅ n vertices (it's convex and has equal sides and equal angles) and all its sides have length 1. Let's name it as 2n-gon.

Your task is to find the square of the minimum size such that you can embed 2n-gon in the square. Embedding 2n-gon in the square means that you need to place 2n-gon in the square in such way that each point which lies inside or on a border of 2n-gon should also lie inside or on a border of the square.

You can rotate 2n-gon and/or the square.

Input

The first line contains a single integer T (1 ≤ T ≤ 200) — the number of test cases.

Next T lines contain descriptions of test cases — one per line. Each line contains single odd integer n (3 ≤ n ≤ 199). Don't forget you need to embed 2n-gon, not an n-gon.

Output

Print T real numbers — one per test case. For each test case, print the minimum length of a side of the square 2n-gon can be embedded in. Your answer will be considered correct if its absolute or relative error doesn't exceed 10^{-6}.

Example

Input


3
3
5
199


Output


1.931851653
3.196226611
126.687663595

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.*;

public class solution {
    static class sort implements Comparator<ArrayList<Integer>> {

        @Override
        public int compare(ArrayList<Integer> o1, ArrayList<Integer> o2) {
            int c = o2.get(1).compareTo(o1.get(1));
            if (c == 0) {

                c = o2.get(0).compareTo(o1.get(0));
            }
            return c;
        }
    }

    public static void merge(long arr[], int l, int m, int r) {
        int n1 = m - l + 1;
        int n2 = r - m;
        long L[] = new long[n1];
        long R[] = new long[n2];
        for (int i = 0; i < n1; ++i)
            L[i] = arr[l + i];
        for (int j = 0; j < n2; ++j)
            R[j] = arr[m + 1 + j];
        int i = 0, j = 0;
        int k = l;
        while (i < n1 && j < n2) {
            if (L[i] <= R[j]) {
                arr[k] = L[i];
                i++;
            } else {
                arr[k] = R[j];
                j++;
            }
            k++;
        }
        while (i < n1) {
            arr[k] = L[i];
            i++;
            k++;
        }
        while (j < n2) {
            arr[k] = R[j];
            j++;
            k++;
        }
    }

    public static void sort(long arr[], int l, int r) {
        if (l < r) {
            int m = (l + r) / 2;
            sort(arr, l, m);
            sort(arr, m + 1, r);
            merge(arr, l, m, r);
        }
    }

    public static long gcd(long a, long b) {
        if (b == 0) {
            return a;
        } else return gcd(b, a % b);
    }

    public static long lcm(long a, long b) {
        long gcd = gcd(a, b);
        long pord = a * b;
        return pord / gcd;
    }

    static class graphs {
        private int V;
        private ArrayList<Integer> adj[];

        graphs(int v) {
            V = v;
            adj = new ArrayList[v];
            for (int i = 0; i < v; i++) {
                adj[i] = new ArrayList<>();
            }
        }

        void addedge(int u, int v) {
            adj[u].add(v);
        }

        void BFS(int v) {
            boolean visited[] = new boolean[V];
            Queue<Integer> Q = new LinkedList<>();
            visited[v] = true;
            Q.add(v);
            while (!Q.isEmpty()) {
                int temp = Q.peek();
                System.out.print(temp + " ");
                Q.remove();
                Iterator<Integer> it = adj[temp].listIterator();
                while (it.hasNext()) {
                    int n = it.next();
                    if (!visited[n]) {
                        visited[n] = true;
                        Q.add(n);
                    }
                }
            }
        }

        void DFSUtil(int v, boolean visited[]) {
            visited[v] = true;
            System.out.print(v + " ");
            Iterator<Integer> it = adj[v].listIterator();
            while (it.hasNext()) {
                int n = it.next();
                if (!visited[n]) {
                    DFSUtil(n, visited);
                }
            }
        }

        void DFS(int v) {
            boolean visited[] = new boolean[V];
            DFSUtil(v, visited);
        }
    }

    public static int Binaraysearch(long a[], int low, int high, long key) {
        while (low <= high) {
            int mid = low + (high - low) / 2;
            if (a[mid] == key) {
                return mid;
            } else if (a[mid] < key) {
                low = mid;
            } else {
                high = mid;
            }
        }
        return -1;
    }

    public static void seive(boolean prime[]) {
        Arrays.fill(prime, true);
        int n = prime.length - 1;
        for (int p = 2; p * p <= n; p++) {
            if (prime[p] == true) {
                for (int i = p * p; i <= n; i += p)
                    prime[i] = false;
            }
        }
    }

    public static boolean random(long a, long b) {
        return a < b;
    }

    public static int subArraySum(int arr[], int n, int sum) {
        int curr_sum = arr[0], start = 0, i;
        for (i = 1; i <= n; i++) {
            // If curr_sum exceeds the sum, then remove the starting elements
            while (curr_sum > sum && start < i - 1) {
                curr_sum = curr_sum - arr[start];
                start++;
            }

            // If curr_sum becomes equal to sum, then return true
            if (curr_sum == sum) {
                int p = i - 1;
                if (p != start)
                    return 1;
            }

            // Add this element to curr_sum
            if (i < n)
                curr_sum = curr_sum + arr[i];

        }
        return 0;
    }

    public static void main(String args[]) throws IOException {
        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
        int t = Integer.parseInt(br.readLine());
        for (int ii = 0; ii < t; ii++) {
           double n = Double.parseDouble(br.readLine());
           n*=2;
           double m = ((double) 180/n);
           double angle = Math.toRadians((double) m/2);
           double ans =((double)1/Math.sin(angle));
           ans/=2;
            System.out.println(ans);
        }
    }
}