Problem: Levko loves permutations very much. A permutation of length n is a sequence of distinct positive integers, each is at most n.

Let’s assume that value gcd(a, b) shows the greatest common divisor of numbers a and b. Levko assumes that element pi of permutation p1, p2, ... , pn is good if gcd(i, pi) > 1. Levko considers a permutation beautiful, if it has exactly k good elements. Unfortunately, he doesn’t know any beautiful permutation. Your task is to help him to find at least one of them.

Input

The single line contains two integers n and k (1 ≤ n ≤ 105, 0 ≤ k ≤ n).

Output

In a single line print either any beautiful permutation or -1, if such permutation doesn’t exist.

If there are multiple suitable permutations, you are allowed to print any of them.

Examples

Input

4 2


Output

2 4 3 1

Input

1 1


Output

-1

Note

In the first sample elements 4 and 3 are good because gcd(2, 4) = 2 > 1 and gcd(3, 3) = 3 > 1. Elements 2 and 1 are not good because gcd(1, 2) = 1 and gcd(4, 1) = 1. As there are exactly 2 good elements, the permutation is beautiful.

The second sample has no beautiful permutations.

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.*;

/**
 * Created by vikas.k on 13/03/17.
 */
public class CF210B {
    public static PrintWriter out;
    public static FastScanner in;

    private void solve(){
        int n = in.nextInt();
        int k = in.nextInt();

        if (n==k){
            out.println(-1);
            return;
        }
        k = n-k;

        int st = 1;
        if(k%2 != 0){
            out.print(1+" ");
            st++;
        }

        for(int i=st;i<k;i+=2){
            out.print((i+1)+" "+i+ " ");
        }
        for(int i=k+1;i<=n;i++){
            out.print(i+" ");
        }
    }
    private void runIO(){
        in = new FastScanner();
        out = new PrintWriter(new BufferedOutputStream(System.out));
        solve();
        out.close();
    }
    private static class FastScanner {
        BufferedReader bufferedReader;
        StringTokenizer stringTokenizer;

        private FastScanner(){
            bufferedReader = new BufferedReader(new InputStreamReader(System.in));
        }

        private String next(){
            if(stringTokenizer == null || !stringTokenizer.hasMoreElements()){
                try {
                    stringTokenizer = new StringTokenizer(bufferedReader.readLine());
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
            return stringTokenizer.nextToken();
        }

        private int nextInt(){
            return Integer.parseInt(next());
        }
        private long nextLong(){
            return Long.parseLong(next());
        }
        private String nextLine(){
            String ret= "";
            try {
                ret= bufferedReader.readLine();
            } catch (IOException e) {
                e.printStackTrace();
            }
            return ret;
        }
    }

    public static void main(String[] args) {
        new CF210B().runIO();
    }
}