Problem: Valera is a coder. Recently he wrote a funny program. The pseudo code for this program is given below:
    
    
      
    //input: integers x, k, p  
    a = x;  
    for(step = 1; step <= k; step = step + 1){  
        rnd = [random integer from 1 to 100];  
        if(rnd <= p)  
            a = a * 2;  
        else  
            a = a + 1;  
    }  
      
    s = 0;  
      
    while(remainder after dividing a by 2 equals 0){  
        a = a / 2;  
        s = s + 1;  
    }  
      
    

Now Valera wonders: given the values x, k and p, what is the expected value of the resulting number s?

Input

The first line of the input contains three integers x, k, p (1 ≤ x ≤ 109; 1 ≤ k ≤ 200; 0 ≤ p ≤ 100).

Output

Print the required expected value. Your answer will be considered correct if the absolute or relative error doesn't exceed 10 - 6.

Examples

Input

1 1 50


Output

1.0000000000000


Input

5 3 0


Output

3.0000000000000


Input

5 3 25


Output

1.9218750000000

Note

If the concept of expected value is new to you, you can read about it by the link: 

http://en.wikipedia.org/wiki/Expected_value

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
const int MAXN = 240;
double f[MAXN][MAXN];
int n, first;
double p;
int main() {
  cin >> first >> n >> p;
  p /= 100;
  for (int i = 0; i <= n; ++i)
    for (int j = 0; j <= n; ++j)
      if (!i)
        for (int a = first + j; !(a & 1); ++f[i][j], a >>= 1)
          ;
      else {
        f[i][j] += f[i - 1][j + 1] * (1.0 - p);
        if (!(j & 1)) f[i][j] += (f[i - 1][j / 2] + 1) * p;
      }
  printf("%.10lf\n", f[n][0]);
  fclose(stdin);
  fclose(stdout);
  return 0;
}