Problem: It is the hard version of the problem. The only difference is that in this version 3 ≤ k ≤ n.

You are given a positive integer n. Find k positive integers a_1, a_2, …, a_k, such that:

  * a_1 + a_2 + … + a_k = n 
  * LCM(a_1, a_2, …, a_k) ≤ n/2 



Here LCM is the [least common multiple](https://en.wikipedia.org/wiki/Least_common_multiple) of numbers a_1, a_2, …, a_k.

We can show that for given constraints the answer always exists.

Input

The first line contains a single integer t (1 ≤ t ≤ 10^4) — the number of test cases.

The only line of each test case contains two integers n, k (3 ≤ n ≤ 10^9, 3 ≤ k ≤ n).

It is guaranteed that the sum of k over all test cases does not exceed 10^5.

Output

For each test case print k positive integers a_1, a_2, …, a_k, for which all conditions are satisfied.

Example

Input


2
6 4
9 5


Output


1 2 2 1 
1 3 3 1 1 

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.OutputStream;
import java.io.PrintWriter;
import java.util.ArrayDeque;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Collections;
import java.util.Deque;
import java.util.HashMap;
import java.util.HashSet;
import java.util.List;
import java.util.Map;
import java.util.Set;
import java.util.Stack;
import java.util.StringTokenizer;

public class Main {
    public static void main(String[] args) {
        InputStream inputStream = System.in;
        OutputStream outputStream = System.out;
        InputReader in = new InputReader(inputStream);
        PrintWriter out = new PrintWriter(outputStream);
        solve(in, out);
        out.close();
    }

    static String reverse(String s) {
        return (new StringBuilder(s)).reverse().toString();
    }

    static void sieveOfEratosthenes(int n, int factors[]) 
    { 
        factors[1]=1;
        for(int p = 2; p*p <=n; p++) 
        { 
            if(factors[p] == 0) 
            { 
                factors[p]=p;
                for(int i = p*p; i <= n; i += p) 
                    factors[i] = p; 
            } 
        } 
    }

    static void sort(int ar[]) {
        int n = ar.length;
        ArrayList<Integer> a = new ArrayList<>();
        for (int i = 0; i < n; i++)
            a.add(ar[i]);
        Collections.sort(a);
        for (int i = 0; i < n; i++)
            ar[i] = a.get(i);
    }

    static void sort1(long ar[]) {
        int n = ar.length;
        ArrayList<Long> a = new ArrayList<>();
        for (int i = 0; i < n; i++)
            a.add(ar[i]);
        Collections.sort(a);
        for (int i = 0; i < n; i++)
            ar[i] = a.get(i);
    }

    static long ncr(long n, long r, long mod) {
        if (r == 0)
            return 1;
        long val = ncr(n - 1, r - 1, mod);
        val = (n * val) % mod;
        val = (val * modInverse(r, mod)) % mod;
        return val;
    }
    public static int convert(String a, String b)
    {
    	int T=0;
    	if(b.charAt(0)=='P')
    	{
    		if(a.charAt(0)=='1'&&a.charAt(1)=='2') T=12;
    		else
    			T=(a.charAt(0)-'0')*10+(a.charAt(1)-'0')+12;
    	}
    	else if(b.charAt(0)=='A')
    	{
    		if(a.charAt(0)=='1'&&a.charAt(1)=='2') T=0;
    		else
    			T=(a.charAt(0)-'0')*10+(a.charAt(1)-'0');
    	}
    		
    	T=T*100+(a.charAt(3)-'0')*10+(a.charAt(4)-'0');
    	return T;
    	
    }
    static boolean areBracketsBalanced(String expr) 
    { 
        // Using ArrayDeque is faster than using Stack class 
        Deque<Character> stack 
            = new ArrayDeque<Character>(); 
  
        // Traversing the Expression 
        for (int i = 0; i < expr.length(); i++)  
        { 
            char x = expr.charAt(i); 
  
            if (x == '(' || x == '[' || x == '{')  
            { 
                // Push the element in the stack 
                stack.push(x); 
                continue; 
            } 
  
            // IF current current character is not opening 
            // bracket, then it must be closing. So stack 
            // cannot be empty at this point. 
            if (stack.isEmpty()) 
                return false; 
            char check; 
            switch (x) { 
            case ')': 
                check = stack.pop(); 
                if (check == '{' || check == '[') 
                    return false; 
                break; 
  
            case '}': 
                check = stack.pop(); 
                if (check == '(' || check == '[') 
                    return false; 
                break; 
  
            case ']': 
                check = stack.pop(); 
                if (check == '(' || check == '{') 
                    return false; 
                break; 
            } 
        } 
  
        // Check Empty Stack 
        return (stack.isEmpty()); 
    } 
    public static int hr(String s)
    {
    	int hh=0;
    	hh=(s.charAt(0)-'0')*10+(s.charAt(1)-'0');
    	return hh;
    }
    public static int mn(String s)
    {
    	int mm=0;
    	mm=(s.charAt(3)-'0')*10+(s.charAt(4)-'0');
    	return mm;
    }
  
    
  
    public static void solve(InputReader sc, PrintWriter pw) {

  	  int t=sc.nextInt();
  
  	  while(t-->0) 
  			  {
  		int n=sc.nextInt();
  		int k=sc.nextInt();
  		n=n-(k-3);
  		while(k>3) {pw.print("1"+" "); k--;}
  		
 	     if(n%3==0)
	     {
	    	 pw.print(n/3+" "+n/3+" "+n/3);
	     }
 	  
 	 
 	     else if((n&1)==1)
 	     {
 	    	  pw.print("1"+" "+n/2+" "+n/2);
 	     }
 	     
 	     else
 	     {
 	    
 	    		
 	    		if(n%4==0)
	    		 pw.print(n/2+" "+(n/2)/2+" "+((n/2)/2));
	    		else
                   pw.print("2"+" "+(n-1)/2+" "+(n-1)/2);  	    	 
 	     }
 		 
 		 pw.println();
 		

  			  
		
		  	
  		
  		

  			  }
    }
    static class Pair1 {
        long a;
        long b;
        
        Pair1(long a, long b) {
            this.a = a;
            this.b = b;
        }
    }

    static class Pair implements Comparable<Pair> {
        int a;
        int b;
        
        Pair(int a, int b) {
            this.a = a;
            this.b = b;
        }
 
        public int compareTo(Pair p) {
            if(a!=p.a)
                return p.a-a;
            return b-p.b;
        }
    }

    static boolean isPrime(long n) {
        if (n <= 1)
            return false;
        if (n <= 3)
            return true;
        if (n % 2 == 0 || n % 3 == 0)
            return false;
        for (int i = 5; i * i <= n; i = i + 6)
            if (n % i == 0 || n % (i + 2) == 0)
                return false;
        return true;
    }

    static long gcd(long a, long b) {
        if (b == 0)
            return a;
        return gcd(b, a % b);
    }

    static long fast_pow(long base, long n, long M) {
        if (n == 0)
            return 1;
        if (n == 1)
            return base % M;
        long halfn = fast_pow(base, n / 2, M);
        if (n % 2 == 0)
            return (halfn * halfn) % M;
        else
            return (((halfn * halfn) % M) * base) % M;
    }

    static long modInverse(long n, long M) {
        return fast_pow(n, M - 2, M);
    }

    static class InputReader {
        public BufferedReader reader;
        public StringTokenizer tokenizer;

        public InputReader(InputStream stream) {
            reader = new BufferedReader(new InputStreamReader(stream), 32768);
            tokenizer = null;
        }

        public String next() {
            while (tokenizer == null || !tokenizer.hasMoreTokens()) {
                try {
                    tokenizer = new StringTokenizer(reader.readLine());
                } catch (IOException e) {
                    throw new RuntimeException(e);
                }
            }
            return tokenizer.nextToken();
        }

        public int nextInt() {
            return Integer.parseInt(next());
        }

        public long nextLong() {
            return Long.parseLong(next());
        }
    }
}