Problem: Hearing that energy drinks increase rating in those sites, Takahashi decides to buy up M cans of energy drinks.

There are N stores that sell energy drinks. In the i-th store, he can buy at most B_i cans of energy drinks for A_i yen (the currency of Japan) each.

What is the minimum amount of money with which he can buy M cans of energy drinks?

It is guaranteed that, in the given inputs, a sufficient amount of money can always buy M cans of energy drinks.

Constraints

* All values in input are integers.
* 1 \leq N, M \leq 10^5
* 1 \leq A_i \leq 10^9
* 1 \leq B_i \leq 10^5
* B_1 + ... + B_N \geq M

Input

Input is given from Standard Input in the following format:


N M
A_1 B_1
A_2 B_2
\vdots
A_N B_N


Output

Print the minimum amount of money with which Takahashi can buy M cans of energy drinks.

Examples

Input

2 5
4 9
2 4


Output

12


Input

4 30
6 18
2 5
3 10
7 9


Output

130


Input

1 100000
1000000000 100000


Output

100000000000000

Solution (in JAVA):

Solution:
import java.util.Map;
import java.util.Scanner;
import java.util.TreeMap;


public class Main {

	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);

		Map<Long, Long> shop =new TreeMap<Long, Long>();

		int N = sc.nextInt();
		int M = sc.nextInt();
		long min = 0;
		for (int i = 0; i < N; i++) {
			long key = sc.nextLong();
			long val = sc.nextLong();

			if (shop.containsKey(key)) {
				shop.put(key, shop.get(key) + val);
			} else {
				shop.put(key, val);
			}
		}

		for (Long item : shop.keySet()) {
			long lot = shop.get(item);
			if (lot >= M) {
				min += item*M;
				break;
			} else {
				M -= lot;
				min += item*lot;
			}
		}

		System.out.println(min);

	}
}