Problem: Levko loves permutations very much. A permutation of length n is a sequence of distinct positive integers, each is at most n.

Let’s assume that value gcd(a, b) shows the greatest common divisor of numbers a and b. Levko assumes that element pi of permutation p1, p2, ... , pn is good if gcd(i, pi) > 1. Levko considers a permutation beautiful, if it has exactly k good elements. Unfortunately, he doesn’t know any beautiful permutation. Your task is to help him to find at least one of them.

Input

The single line contains two integers n and k (1 ≤ n ≤ 105, 0 ≤ k ≤ n).

Output

In a single line print either any beautiful permutation or -1, if such permutation doesn’t exist.

If there are multiple suitable permutations, you are allowed to print any of them.

Examples

Input

4 2


Output

2 4 3 1

Input

1 1


Output

-1

Note

In the first sample elements 4 and 3 are good because gcd(2, 4) = 2 > 1 and gcd(3, 3) = 3 > 1. Elements 2 and 1 are not good because gcd(1, 2) = 1 and gcd(4, 1) = 1. As there are exactly 2 good elements, the permutation is beautiful.

The second sample has no beautiful permutations.

Solution (in JAVA):

Solution:

import java.util.Scanner;

public class LevkoAndPermutation
{
    static int gcd(int a, int b)
    {
        return b == 0 ? a : gcd(b, a % b);
    }

    public static void main(String[] args)
    {
        Scanner in = new Scanner(System.in);
        int n = in.nextInt(), k = in.nextInt();
        if (k == n)
            System.out.println(-1);
        else
        {
            int[] a = new int[n];
            for (int i = 0; i < n; i++)
                a[i] = i + 1;
            int dif = n - 1 - k;
            int start = 1;
            if (dif % 2 != 0)
            {
                a[0] = 2;
                a[1] = 1;
                dif--;
                start = 2;
            }
            for (int i = start; dif > 0 && i + 1 < n; i += 2, dif -= 2)
            {
                int t = a[i];
                a[i] = a[i + 1];
                a[i + 1] = t;
            }

            for (int i = 0; i < n; i++)
                System.out.print(a[i] + " ");
        }
        in.close();
    }
}