Problem: Levko loves permutations very much. A permutation of length n is a sequence of distinct positive integers, each is at most n.

Let’s assume that value gcd(a, b) shows the greatest common divisor of numbers a and b. Levko assumes that element pi of permutation p1, p2, ... , pn is good if gcd(i, pi) > 1. Levko considers a permutation beautiful, if it has exactly k good elements. Unfortunately, he doesn’t know any beautiful permutation. Your task is to help him to find at least one of them.

Input

The single line contains two integers n and k (1 ≤ n ≤ 105, 0 ≤ k ≤ n).

Output

In a single line print either any beautiful permutation or -1, if such permutation doesn’t exist.

If there are multiple suitable permutations, you are allowed to print any of them.

Examples

Input

4 2


Output

2 4 3 1

Input

1 1


Output

-1

Note

In the first sample elements 4 and 3 are good because gcd(2, 4) = 2 > 1 and gcd(3, 3) = 3 > 1. Elements 2 and 1 are not good because gcd(1, 2) = 1 and gcd(4, 1) = 1. As there are exactly 2 good elements, the permutation is beautiful.

The second sample has no beautiful permutations.

Solution (in PYTHON):

Solution:
'''
def gcd(a,b):
    if (b == 0):
         return a
    return gcd(b, a%b)
'''

n, k = map(int, raw_input().split())
# p = range(1, n+1)
out = ''

if n == k:
	print '-1'
elif n-1 == k:
	for i in xrange(1, n):
		out += str(i) + ' '
	print out + str(n)
else:
	out += str(k+2) + ' '
	for i in xrange(2, n):
		if i <= k+1:
			out += str(i) + ' '
		else: 
			out += str(i+1) + ' '
	print out + '1'