Problem: You are given an array a of n integers.

You want to make all elements of a equal to zero by doing the following operation exactly three times:

  * Select a segment, for each number in this segment we can add a multiple of len to it, where len is the length of this segment (added integers can be different). 



It can be proven that it is always possible to make all elements of a equal to zero.

Input

The first line contains one integer n (1 ≤ n ≤ 100 000): the number of elements of the array.

The second line contains n elements of an array a separated by spaces: a_1, a_2, ..., a_n (-10^9 ≤ a_i ≤ 10^9).

Output

The output should contain six lines representing three operations.

For each operation, print two lines:

  * The first line contains two integers l, r (1 ≤ l ≤ r ≤ n): the bounds of the selected segment.

  * The second line contains r-l+1 integers b_l, b_{l+1}, ..., b_r (-10^{18} ≤ b_i ≤ 10^{18}): the numbers to add to a_l, a_{l+1}, …, a_r, respectively; b_i should be divisible by r - l + 1.

Example

Input


4
1 3 2 4


Output


1 1 
-1
3 4
4 2
2 4
-3 -6 -6

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.*;
public class C
{
	static Reader sc=new Reader();
    static PrintWriter out=new PrintWriter((System.out));
    public static void main(String args[])throws IOException
    {
        int t=sc.nextInt();
        long arr[] = new long[t];
        for(int i = 0; i < t; i++) {
        	arr[i] = sc.nextLong();
        }
        if(t <= 3) {
        	if(t == 1) {
        		out.println("1 1");
        		out.println("-1");
        		arr[0]--;
        		out.println("1 1");
        		out.println("-1");
        		arr[0]--;
        		long temp = -1 * arr[0];
        		out.println("1 1");
        		out.println(temp);
        	}else if(t == 2) {
        		out.println("1 1");
        		out.println(-1*arr[0]);
        		arr[0] = 0;
        		out.println("2 2");
        		out.println("-1");
        		arr[1]--;
        		long temp = -1 * arr[1];
        		out.println("2 2");
        		out.println(temp);
        	}else {
        		out.println("1 1");
        		out.println(-1*arr[0]);
        		out.println("2 2");
        		out.println(-1*arr[1]);
        		out.println("3 3");
        		out.println(-1*arr[2]);
        	}
        }else {
        	out.println("1 " + (t-1));
        	for(int i = 0; i < t-1; i++) {
        		long temp = arr[i] % t;
        		temp = (temp)*(t-1);
        		//boolean found = false;
        		/*
        		while(!found) {
        			if((arr[i] + temp) % (t) == 0) {
        				found = true;
        				continue;
        			}
        			temp += t-1;
        		}
        		*/
        		out.print(temp + " ");
        		arr[i] += temp;
        	}
        	out.println();
        	out.println(t + " " + t);
        	//boolean found = false;
        	long temp = 1;
        	long terp = (arr[t-1] + temp)%t;
        	temp += (t-terp);
        	out.println(temp);
        	arr[t-1] += temp;
        	out.println(1 + " " + t);
        	for(int i = 0; i < t; i++) {
        		out.print((-1*arr[i]) + " ");
        	}
        }
	out.close();
    }

    public static void solve()
    {
    	
    }
    
    static class Reader 
    { 
        BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
        StringTokenizer st=new StringTokenizer("");
        public String next()
        {
            while(!st.hasMoreTokens())
            {
                try
                {
                    st=new StringTokenizer(br.readLine());
                }
                catch(Exception e)
                {
                    e.printStackTrace();
                }
            }
            return st.nextToken();
        }
        public int nextInt()
        {
            return Integer.parseInt(next());
        }
        public long nextLong()
        {
            return Long.parseLong(next());
        }
        public double nextDouble()
        {
            return Double.parseDouble(next());
        }
        public String nextLine()
        {
            try
            {
                return br.readLine();
            }
            catch(Exception e)
            {
                e.printStackTrace();
            }
            return null;
        }
        public boolean hasNext()
        {
            String next=null;
            try
            {
                next=br.readLine();
            }
            catch(Exception e)
            {
            }
            if(next==null)
            {
                return false;
            }
            st=new StringTokenizer(next);
            return true;
        }
    } 
}