Problem:       
    HAI  
    I HAS A TUX  
    GIMMEH TUX  
    I HAS A FOO ITS 0  
    I HAS A BAR ITS 0  
    I HAS A BAZ ITS 0  
    I HAS A QUZ ITS 1  
    TUX IS NOW A NUMBR  
    IM IN YR LOOP NERFIN YR TUX TIL BOTH SAEM TUX AN 0  
    I HAS A PUR  
    GIMMEH PUR  
    PUR IS NOW A NUMBR  
    FOO R SUM OF FOO AN PUR  
    BAR R SUM OF BAR AN 1  
    BOTH SAEM BIGGR OF PRODUKT OF FOO AN QUZ AN PRODUKT OF BAR BAZ AN PRODUKT OF FOO AN QUZ  
    O RLY?  
    YA RLY  
    BAZ R FOO  
    QUZ R BAR  
    OIC  
    IM OUTTA YR LOOP  
    BAZ IS NOW A NUMBAR  
    VISIBLE SMOOSH QUOSHUNT OF BAZ QUZ  
    KTHXBYE  
    

Input

The input contains between 1 and 10 lines, i-th line contains an integer number xi (0 ≤ xi ≤ 9).

Output

Output a single real number. The answer is considered to be correct if its absolute or relative error does not exceed 10 - 4.

Examples

Input

3
0
1
1


Output

0.666667

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
int main() {
  int TUX;
  int n, a, i;
  double sum = 0, ans = 0;
  scanf("%d", &TUX);
  int FOO = 0, BAR = 0, BAZ = 0, QUZ = 1;
  for (i = 1; i <= TUX; i++) {
    int PUR;
    scanf("%d", &PUR);
    FOO = FOO + PUR;
    BAR = BAR + 1;
    if (((FOO * QUZ) > (BAR * BAZ) ? (FOO * QUZ) : (BAR * BAZ)) == FOO * QUZ) {
      BAZ = FOO;
      QUZ = BAR;
    }
  }
  printf("%lf\n", (1. * BAZ) / (1. * QUZ));
  return 0;
}