Problem: You want to perform the combo on your opponent in one popular fighting game. The combo is the string s consisting of n lowercase Latin letters. To perform the combo, you have to press all buttons in the order they appear in s. I.e. if s="abca" then you have to press 'a', then 'b', 'c' and 'a' again.

You know that you will spend m wrong tries to perform the combo and during the i-th try you will make a mistake right after p_i-th button (1 ≤ p_i < n) (i.e. you will press first p_i buttons right and start performing the combo from the beginning). It is guaranteed that during the m+1-th try you press all buttons right and finally perform the combo.

I.e. if s="abca", m=2 and p = [1, 3] then the sequence of pressed buttons will be 'a' (here you're making a mistake and start performing the combo from the beginning), 'a', 'b', 'c', (here you're making a mistake and start performing the combo from the beginning), 'a' (note that at this point you will not perform the combo because of the mistake), 'b', 'c', 'a'.

Your task is to calculate for each button (letter) the number of times you'll press it.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases.

Then t test cases follow.

The first line of each test case contains two integers n and m (2 ≤ n ≤ 2 ⋅ 10^5, 1 ≤ m ≤ 2 ⋅ 10^5) — the length of s and the number of tries correspondingly.

The second line of each test case contains the string s consisting of n lowercase Latin letters.

The third line of each test case contains m integers p_1, p_2, ..., p_m (1 ≤ p_i < n) — the number of characters pressed right during the i-th try.

It is guaranteed that the sum of n and the sum of m both does not exceed 2 ⋅ 10^5 (∑ n ≤ 2 ⋅ 10^5, ∑ m ≤ 2 ⋅ 10^5).

It is guaranteed that the answer for each letter does not exceed 2 ⋅ 10^9.

Output

For each test case, print the answer — 26 integers: the number of times you press the button 'a', the number of times you press the button 'b', ..., the number of times you press the button 'z'.

Example

Input


3
4 2
abca
1 3
10 5
codeforces
2 8 3 2 9
26 10
qwertyuioplkjhgfdsazxcvbnm
20 10 1 2 3 5 10 5 9 4


Output


4 2 2 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 
0 0 9 4 5 3 0 0 0 0 0 0 0 0 9 0 0 3 1 0 0 0 0 0 0 0 
2 1 1 2 9 2 2 2 5 2 2 2 1 1 5 4 11 8 2 7 5 1 10 1 5 2 

Note

The first test case is described in the problem statement. Wrong tries are "a", "abc" and the final try is "abca". The number of times you press 'a' is 4, 'b' is 2 and 'c' is 2.

In the second test case, there are five wrong tries: "co", "codeforc", "cod", "co", "codeforce" and the final try is "codeforces". The number of times you press 'c' is 9, 'd' is 4, 'e' is 5, 'f' is 3, 'o' is 9, 'r' is 3 and 's' is 1.

Solution (in JAVA):

Solution:
import static java.lang.Integer.parseInt;
import static java.lang.Long.parseLong;
import static java.lang.Short.parseShort;
import static java.lang.Byte.parseByte;
import java.io.*;
import java.util.*;

public class Contest {

    static int nextInt() throws IOException {
        return parseInt(next());
    }

    static long nextLong() throws IOException {
        return parseLong(next());
    }

    static short nextShort() throws IOException {
        return parseShort(next());
    }

    static byte nextByte() throws IOException {
        return parseByte(next());
    }

    static String next() throws IOException {
        while (tok == null || !tok.hasMoreTokens())
            tok = new StringTokenizer(in.readLine());
        return tok.nextToken();
    }

    static String nextLine() throws IOException {
        return in.readLine();
    }

    private static BufferedReader in;
    private static StringTokenizer tok;
    private static PrintWriter out = new PrintWriter(System.out);
    private static Utilities doThis = new Utilities(out);
    private static MyMath doMath = new MyMath();

    public static void main(String[] args) throws Exception {
        in = new BufferedReader(new InputStreamReader(System.in));

        /*--------------------SolutionStarted-------------------*/
        solve();
        /*--------------------SolutionEnded--------------------*/

        in.close();
        out.close();
    }


    static int n, m, k,
            count = 0, length = 0, sum = 0,
            q, t,
            idx, temp;
    static char[] s, s1;
    static int max = Integer.MIN_VALUE, min = Integer.MAX_VALUE;
    static long lMax = Long.MAX_VALUE, lMin = Long.MIN_VALUE, lSum = 0, lCount;
    static int[] nums;
    static boolean flag;

    static void solve() throws IOException {
        t = nextInt();
        whl:
        while (t-- > 0) {
            n = nextInt();
            m = nextInt();
            s = next().toCharArray();
            nums = new int[m];
            for (int i = 0; i < m; i++) {
                nums[i] = nextInt();
            }
            int[] ch = new int[26];
          //  out.println(Arrays.toString(nums));
            Arrays.sort(nums);
            count=m;
            temp = 0;
            for (int i = 0; i <nums.length ; i++) {
                for (int j = temp; j <nums[i] ; j++) {
                    ch[s[j]-97]+=count;
                }
                count--;
                temp=nums[i];
            }
            for (int i = 0; i <s.length ; i++) {
                ch[s[i]-97]++;
            }
            for (int i = 0; i <ch.length ; i++) {
                out.print(ch[i]+" ");
            }
            out.println();
        }
    }
}
class Pair implements Comparable<Pair>{
    int k,v;
    boolean taken;
    Pair(int k,int v){
        this.k = k;
        this.v =v;
    }

    @Override
    public int compareTo(Pair o) {
        return v-o.v;
    }
}
class CharPair{
    char ch;
    int value;
    CharPair(char c, int v){
        ch =c; value=v;
    }
    char get(){
        return ch;
    }
}
class IntPair implements Comparable<IntPair> {
    int key, value;
    IntPair(int key, int value) {
        this.key = key;
        this.value = value;
    }

    @Override
    public int compareTo(IntPair o) {
        if (value == o.value)
            return key - o.key;
        return value - o.value;
    }

    public String toString() {
        return key + " " + value;
    }
}
class BooleanPair {
    boolean key, value;

    BooleanPair() {
    }

    BooleanPair(boolean key, boolean value) {
        this.key = key;
        this.value = value;
    }
}
class Utilities {
    PrintWriter out;
    Utilities(PrintWriter out){
        this.out = out;
    }
    //int arrays start
    int lowerBound(int[] arr, int low, int high, int element) {
        int middle;
        while (low < high) {
            middle = low + (high - low) / 2;
            if (element > arr[middle])
                low = middle + 1;
            else
                high = middle;
        }
        if (arr[low] < element)
            return -1;
        return low;
    }

    int upperBound(int[] arr, int low, int high, int element) {
        int middle;
        while (low < high) {
            middle = low + (high - low) / 2;
            if (arr[middle] > element)
                high = middle;
            else
                low = middle + 1;
        }
        if (arr[low] <= element)
            return -1;
        return low;
    }
    //int arrays end
    //long arrays start
    int lowerBound(long[] arr, int low, int high, long element) {
        int middle;
        while (low < high) {
            middle = low + (high - low) / 2;
            if (element > arr[middle])
                low = middle + 1;
            else
                high = middle;
        }
        if (arr[low] < element)
            return -1;
        return low;
    }

    int upperBound(long[] arr, int low, int high, long element) {
        int middle;
        while (low < high) {
            middle = low + (high - low) / 2;
            if (arr[middle] > element)
                high = middle;
            else
                low = middle + 1;
        }
        if (arr[low] <= element)
            return -1;
        return low;
    }
    //long arrays end
    //double arrays start
    int lowerBound(double[] arr, int low, int high, double element) {
        int middle;
        while (low < high) {
            middle = low + (high - low) / 2;
            if (element > arr[middle])
                low = middle + 1;
            else
                high = middle;
        }
        if (arr[low] < element)
            return -1;
        return low;
    }

    int upperBound(double[] arr, int low, int high, double element) {
        int middle;
        while (low < high) {
            middle = low + (high - low) / 2;
            if (arr[middle] > element)
                high = middle;
            else
                low = middle + 1;
        }
        if (arr[low] <= element)
            return -1;
        return low;
    }
    //double arrays end
    int arrUp(int [][]arr,int i, int j){
        if(i==0)
            return Integer.MIN_VALUE;
        return arr[i-1][j];
    }
    int arrDown(int [][]arr,int i, int j){
        if(i==arr.length-1)
            return Integer.MIN_VALUE;
        return arr[i+1][j];
    }
    int arrLeft(int [][]arr,int i, int j){
        if(j==0)
            return Integer.MIN_VALUE;
        return arr[i][j-1];
    }
    int arrRight(int [][]arr,int i, int j){
        if(j==arr[i].length-1)
            return Integer.MIN_VALUE;
        return arr[i][j+1];
    }
    int count(char[] s, char c){
        int count = 0;
        for (int i = 0; i < s.length; i++) {
            if (s[i]==c)
                count++;
        }
        return count;
    }
    void swap(char[] s, int a,int b){
        char temp =s[b];
        s[b]= s[a];
        s[a] = temp;
    }
    boolean odd(int a){
        return a%2==1;
    }
    boolean even(int a){
        return a%2==0;
    }
    void yes(){
        out.println("YES");
    }
    void no() {
        out.println("NO");
    }
    void bad(){
        out.println(-1);
    }
    void printBinary(int num){
        out.println(Integer.toBinaryString(num));
    }
}
class MyMath {
    boolean isCoPrime(int a, int b) {
        return gcd(a, b) == 1;
    }

    int gcd(int a, int b) {
        if (a == 0)
            return b;
        while (b != 0)
            if (a > b)
                a = a - b;
            else
                b = b - a;
        return a;
    }

    int log2(int x) {
        return (int) (Math.log(x) / Math.log(2));
    }
    boolean[] sieveOfEratosthenes(int n)
    {
        // Create a boolean array "primes[0..n]" and initialize
        // all entries it as true. A value in primes[i] will
        // finally be false if i is Not a primes, else true.
        boolean primes[] = new boolean[n+1];
        for(int i=0;i<n;i++)
            primes[i] = true;

        for(int p = 2; p*p <=n; p++)
        {
            // If primes[p] is not changed, then it is a primes
            if(primes[p])
            {
                // Update all multiples of p
                for(int i = p*p; i <= n; i += p)
                    primes[i] = false;
            }
        }
        return primes;
    }
}
class Bitmasks{
    static byte andBitmask(byte state, byte... masks){
        byte temp=0;
        for (int i = 0; i < masks.length; i++) {
            temp|=masks[i];
        }
        return (byte) (state&temp);
    }
    static byte toggleBitmask(byte state ,byte... masks){
        return state;
    }
    static byte removeBitmask(byte state, byte... masks){
        return state;
    }
    static byte addBitmask(byte state ,byte... masks){
        return state;
    }
}