Problem: Valera is a coder. Recently he wrote a funny program. The pseudo code for this program is given below:
    
    
      
    //input: integers x, k, p  
    a = x;  
    for(step = 1; step <= k; step = step + 1){  
        rnd = [random integer from 1 to 100];  
        if(rnd <= p)  
            a = a * 2;  
        else  
            a = a + 1;  
    }  
      
    s = 0;  
      
    while(remainder after dividing a by 2 equals 0){  
        a = a / 2;  
        s = s + 1;  
    }  
      
    

Now Valera wonders: given the values x, k and p, what is the expected value of the resulting number s?

Input

The first line of the input contains three integers x, k, p (1 ≤ x ≤ 109; 1 ≤ k ≤ 200; 0 ≤ p ≤ 100).

Output

Print the required expected value. Your answer will be considered correct if the absolute or relative error doesn't exceed 10 - 6.

Examples

Input

1 1 50


Output

1.0000000000000


Input

5 3 0


Output

3.0000000000000


Input

5 3 25


Output

1.9218750000000

Note

If the concept of expected value is new to you, you can read about it by the link: 

http://en.wikipedia.org/wiki/Expected_value

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
double dp[202][202];
int main() {
  int x, n, pp;
  scanf("%d%d%d", &x, &n, &pp);
  double p = 1.0 * pp / 100;
  dp[0][0] = 1.0;
  double ans = 0.0;
  for (int i = 0; i < n; ++i) {
    for (int j = 0; j <= n; ++j) {
      dp[i + 1][j + 1] += dp[i][j] * (1 - p);
      if (j % 2 == 0) {
        dp[i + 1][j / 2] += dp[i][j] * p;
        ans += dp[i][j] * p;
      }
    }
  }
  for (int j = 0; j <= n; ++j) {
    int xx = x + j;
    while (xx % 2 == 0) {
      xx /= 2;
      ans += dp[n][j];
    }
  }
  printf("%.10lf\n", ans);
  return 0;
}