Problem: On a chessboard with a width of n and a height of n, rows are numbered from bottom to top from 1 to n, columns are numbered from left to right from 1 to n. Therefore, for each cell of the chessboard, you can assign the coordinates (r,c), where r is the number of the row, and c is the number of the column.

The white king has been sitting in a cell with (1,1) coordinates for a thousand years, while the black king has been sitting in a cell with (n,n) coordinates. They would have sat like that further, but suddenly a beautiful coin fell on the cell with coordinates (x,y)...

Each of the monarchs wanted to get it, so they decided to arrange a race according to slightly changed chess rules:

As in chess, the white king makes the first move, the black king makes the second one, the white king makes the third one, and so on. However, in this problem, kings can stand in adjacent cells or even in the same cell at the same time.

The player who reaches the coin first will win, that is to say, the player who reaches the cell with the coordinates (x,y) first will win.

Let's recall that the king is such a chess piece that can move one cell in all directions, that is, if the king is in the (a,b) cell, then in one move he can move from (a,b) to the cells (a + 1,b), (a - 1,b), (a,b + 1), (a,b - 1), (a + 1,b - 1), (a + 1,b + 1), (a - 1,b - 1), or (a - 1,b + 1). Going outside of the field is prohibited.

Determine the color of the king, who will reach the cell with the coordinates (x,y) first, if the white king moves first.

Input

The first line contains a single integer n (2 ≤ n ≤ 10^{18}) — the length of the side of the chess field.

The second line contains two integers x and y (1 ≤ x,y ≤ n) — coordinates of the cell, where the coin fell.

Output

In a single line print the answer "White" (without quotes), if the white king will win, or "Black" (without quotes), if the black king will win.

You can print each letter in any case (upper or lower).

Examples

Input

4
2 3


Output

White

Input

5
3 5


Output

Black

Input

2
2 2


Output

Black

Note

An example of the race from the first sample where both the white king and the black king move optimally:

  1. The white king moves from the cell (1,1) into the cell (2,2).
  2. The black king moves form the cell (4,4) into the cell (3,3).
  3. The white king moves from the cell (2,2) into the cell (2,3). This is cell containing the coin, so the white king wins.

<image>

An example of the race from the second sample where both the white king and the black king move optimally:

  1. The white king moves from the cell (1,1) into the cell (2,2).
  2. The black king moves form the cell (5,5) into the cell (4,4).
  3. The white king moves from the cell (2,2) into the cell (3,3).
  4. The black king moves from the cell (4,4) into the cell (3,5). This is the cell, where the coin fell, so the black king wins.

<image>

In the third example, the coin fell in the starting cell of the black king, so the black king immediately wins.

<image>

Solution (in JAVA):

Solution:

import java.io.*;
import java.util.*;
import javax.print.attribute.standard.Finishings;

import java.math.*;

public class Exam {
	static final Random random = new Random();
	static PrintWriter out = new PrintWriter((System.out));
	static Reader sc = new Reader();

	public static void main(String args[]) throws IOException {
//		int t = sc.nextInt();
//		while (t-- > 0) {

//        	CODE START FROM HERE
		long n = sc.nextLong();
		long x = sc.nextLong();
//				sc.nextLong();
		long y = sc.nextLong();
		long x1 = 1;
		long y1 = 1;
		long x2 = n;
		long y2 = n;

		long white = Integer.MAX_VALUE;
		long black = Integer.MAX_VALUE;

		white = ((Math.abs((x1 - x) + (y1 - y))));

//		System.out.println(white);
		black = ((Math.abs((x2 - x) + (y2 - y))));

//		System.out.println(black);
		if (white <= black)
			System.out.println("White");
		else
			System.out.println("Black");
	}

	public static long square(long l) {
		return l * l;
	}

	// Fast Input Output
	static class Reader {
		BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
		StringTokenizer st = new StringTokenizer("");

		public String next() {
			while (!st.hasMoreTokens()) {
				try {
					st = new StringTokenizer(br.readLine());
				} catch (Exception e) {
					e.printStackTrace();
				}
			}
			return st.nextToken();
		}

		public int nextInt() {
			return Integer.parseInt(next());
		}

		public long nextLong() {
			return Long.parseLong(next());
		}

		public double nextDouble() {
			return Double.parseDouble(next());
		}

		public String nextLine() {
			try {
				return br.readLine();
			} catch (Exception e) {
				e.printStackTrace();
			}
			return null;
		}

		public boolean hasNext() {
			String next = null;
			try {
				next = br.readLine();
			} catch (Exception e) {
			}
			if (next == null) {
				return false;
			}
			st = new StringTokenizer(next);
			return true;
		}
	}

	// EFFICIENT SORTING Ascending
	static void ruffleSortAsc(Integer[] a) {
		int n = a.length; // shuffle, then sort
		for (int i = 0; i < n; i++) {
			int oi = random.nextInt(n), temp = a[oi];
			a[oi] = a[i];
			a[i] = temp;
		}
		Arrays.sort(a);
	}

	// EFFICIENT SORTING Descending
	static void ruffleSortDesc(Integer[] a) {
		int n = a.length; // shuffle, then sort
		for (int i = 0; i < n; i++) {
			int oi = random.nextInt(n), temp = a[oi];
			a[oi] = a[i];
			a[i] = temp;
		}
		Arrays.sort(a, Collections.reverseOrder());
	}

	// Array Sum
	static long sum(Integer[] arr) {
		long sum = 0;
		for (int i : arr)
			sum += i;
		return sum;
	}

	// swap array elements
	static void swap(int arr1[], int arr2[], int i, int j) {
		int temp = arr1[i];
		arr1[i] = arr2[j];
		arr2[j] = temp;
	}

	// reading array value;
	static void read(String[] places) {
		for (int i = 0; i < places.length; i++)
			places[i] = sc.next();
		return;
	}

//    reading arraylistValue

	// check for even odd
	static boolean isEven(int n) {
		return ((n & 1) != 1);
	}

	// max in a array
	static int max(Integer[] arr) {
		int max = Integer.MIN_VALUE;
		for (int i = 0; i < arr.length; i++)
			if (max < arr[i])
				max = arr[i];
		return max;
	}

	// print array
	static void printarr(Integer arr[]) {
		for (int i : arr)
			System.out.println(i);
	}

	// ceil of two elements
	static long ceil(int a, int b) {
		return (long) Math.ceil(((double) a / (double) b));
	}

	// floor of two elements
	static long floor(int a, int b) {
		return (long) Math.floor(((double) a / (double) b));
	}

}