Problem: The city administration of IT City decided to fix up a symbol of scientific and technical progress in the city's main square, namely an indicator board that shows the effect of Moore's law in real time.

Moore's law is the observation that the number of transistors in a dense integrated circuit doubles approximately every 24 months. The implication of Moore's law is that computer performance as function of time increases exponentially as well.

You are to prepare information that will change every second to display on the indicator board. Let's assume that every second the number of transistors increases exactly 1.000000011 times.

Input

The only line of the input contains a pair of integers n (1000 ≤ n ≤ 10 000) and t (0 ≤ t ≤ 2 000 000 000) — the number of transistors in the initial time and the number of seconds passed since the initial time.

Output

Output one number — the estimate of the number of transistors in a dence integrated circuit in t seconds since the initial time. The relative error of your answer should not be greater than 10 - 6.

Examples

Input

1000 1000000


Output

1011.060722383550382782399454922040

Solution (in JAVA):

Solution:

import java.io.*;
import java.math.BigDecimal;
import java.math.RoundingMode;

import java.util.*;

public class Main {

    public static void main(String[] args) throws Exception {
        Scan in = new Scan();
        double n, t;
        n = in.nextDouble();
        t = in.nextDouble();
        final double num = 1.000000011;
        double ans = n * Math.pow(num, t);
        System.out.println(new BigDecimal(ans).setScale(30, BigDecimal.ROUND_HALF_DOWN));

    }

    static class Scan {

        BufferedReader br;
        StringTokenizer st;

        Scan() { // To read from the standard input
            br = new BufferedReader(new InputStreamReader(System.in));
        }

        Scan(String fn) throws IOException { // To read from a file
            br = new BufferedReader(new FileReader(fn));
        }

        boolean hasNext() throws IOException {
            String s = br.readLine();
            if (s == null) {
                return false;
            }
            st = new StringTokenizer(s);
            return true;
        }

        String next() throws IOException {
            while (st == null || !st.hasMoreTokens()) {
                st = new StringTokenizer(br.readLine());
            }
            return st.nextToken();
        }

        int nextInt() throws IOException {
            return Integer.parseInt(next());
        }

        long nextLong() throws IOException {
            return Long.parseLong(next());
        }

        double nextDouble() throws IOException {
            return Double.parseDouble(next());
        }

        String nextLine() throws IOException {
            return br.readLine();
        }
    }

}