Problem: Hearing that energy drinks increase rating in those sites, Takahashi decides to buy up M cans of energy drinks.

There are N stores that sell energy drinks. In the i-th store, he can buy at most B_i cans of energy drinks for A_i yen (the currency of Japan) each.

What is the minimum amount of money with which he can buy M cans of energy drinks?

It is guaranteed that, in the given inputs, a sufficient amount of money can always buy M cans of energy drinks.

Constraints

* All values in input are integers.
* 1 \leq N, M \leq 10^5
* 1 \leq A_i \leq 10^9
* 1 \leq B_i \leq 10^5
* B_1 + ... + B_N \geq M

Input

Input is given from Standard Input in the following format:


N M
A_1 B_1
A_2 B_2
\vdots
A_N B_N


Output

Print the minimum amount of money with which Takahashi can buy M cans of energy drinks.

Examples

Input

2 5
4 9
2 4


Output

12


Input

4 30
6 18
2 5
3 10
7 9


Output

130


Input

1 100000
1000000000 100000


Output

100000000000000

Solution (in JAVA):

Solution:
import java.util.Map;
import java.util.Scanner;
import java.util.TreeMap;

public class Main {

    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        long N = scanner.nextLong(), M = scanner.nextLong();
        Map<Long, Long> drinks = new TreeMap<>();
        for(int i = 0; i < N; i++){
            Long key = scanner.nextLong();
            Long value = scanner.nextLong();
            drinks.computeIfPresent(key,(k, v) -> v + value);
            drinks.computeIfAbsent(key,(k) -> value);
        }
        drinks.entrySet().stream().sorted((m1, m2) -> {
            return m1.getKey().compareTo(m2.getKey());
        });
        long ans = 0;
        for(Long k : drinks.keySet()){
            long buy = Long.min(drinks.get(k), M);
            ans += (buy * k);
            M -= buy;
            if(M == 0)
                break;
        }
        System.out.println(ans);
    }
}