Problem: Hearing that energy drinks increase rating in those sites, Takahashi decides to buy up M cans of energy drinks.

There are N stores that sell energy drinks. In the i-th store, he can buy at most B_i cans of energy drinks for A_i yen (the currency of Japan) each.

What is the minimum amount of money with which he can buy M cans of energy drinks?

It is guaranteed that, in the given inputs, a sufficient amount of money can always buy M cans of energy drinks.

Constraints

* All values in input are integers.
* 1 \leq N, M \leq 10^5
* 1 \leq A_i \leq 10^9
* 1 \leq B_i \leq 10^5
* B_1 + ... + B_N \geq M

Input

Input is given from Standard Input in the following format:


N M
A_1 B_1
A_2 B_2
\vdots
A_N B_N


Output

Print the minimum amount of money with which Takahashi can buy M cans of energy drinks.

Examples

Input

2 5
4 9
2 4


Output

12


Input

4 30
6 18
2 5
3 10
7 9


Output

130


Input

1 100000
1000000000 100000


Output

100000000000000

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
 typedef long long ll;


int main(){
ll N,M;
cin>>N>>M;
vector<pair<ll, ll>> a(N);
for(int i = 0;i<N;i++){
ll A, B;
cin >> A >> B;
a[i].first=A;
a[i].second=B;
}
sort(a.begin(),a.end());
ll ans = 0;
for(int i = 0;i<N&&M>0;i++){
ans+=a[i].first*min(M,a[i].second);
M-=a[i].second;
}
cout<<ans<<endl;

}