Problem: The city administration of IT City decided to fix up a symbol of scientific and technical progress in the city's main square, namely an indicator board that shows the effect of Moore's law in real time.

Moore's law is the observation that the number of transistors in a dense integrated circuit doubles approximately every 24 months. The implication of Moore's law is that computer performance as function of time increases exponentially as well.

You are to prepare information that will change every second to display on the indicator board. Let's assume that every second the number of transistors increases exactly 1.000000011 times.

Input

The only line of the input contains a pair of integers n (1000 ≤ n ≤ 10 000) and t (0 ≤ t ≤ 2 000 000 000) — the number of transistors in the initial time and the number of seconds passed since the initial time.

Output

Output one number — the estimate of the number of transistors in a dence integrated circuit in t seconds since the initial time. The relative error of your answer should not be greater than 10 - 6.

Examples

Input

1000 1000000


Output

1011.060722383550382782399454922040

Solution (in JAVA):

Solution:
// Working program with FastReader 
import java.io.BufferedReader; 
import java.io.IOException; 
import java.io.InputStreamReader; 
import java.util.*;
public class g
{ 
    static class FastReader 
    { 
        BufferedReader br; 
        StringTokenizer st; 

        public FastReader() 
        { 
            br = new BufferedReader(new
                InputStreamReader(System.in)); 
        } 

        String next() 
        { 
            while (st == null || !st.hasMoreElements()) 
            { 
                try
                { 
                    st = new StringTokenizer(br.readLine()); 
                } 
                catch (IOException  e) 
                { 
                    e.printStackTrace(); 
                } 
            } 
            return st.nextToken(); 
        } 

        int nextInt() 
        { 
            return Integer.parseInt(next()); 
        } 

        long nextLong() 
        { 
            return Long.parseLong(next()); 
        } 

        double nextDouble() 
        { 
            return Double.parseDouble(next()); 
        } 

        String nextLine() 
        { 
            String str = ""; 
            try
            { 
                str = br.readLine(); 
            } 
            catch (IOException e) 
            { 
                e.printStackTrace(); 
            } 
            return str; 
        } 
    } 
    public static int findIndex(long arr[], long t) 
    { 

        // if array is Null 
        if (arr == null) { 
            return -1; 
        } 

        // find length of array 
        int len = arr.length; 
        int i = 0; 

        // traverse in the array 
        while (i < len) { 

            // if the i-th element is t 
            // then return the index 
            if (arr[i] == t) { 
                return i; 
            } 
            else { 
                i = i + 1; 
            } 
        } 
        return -1; 
    }

    static int gcd(int a, int b)
    {
        if (a == 0)
            return b; 
        return gcd(b % a, a); 
    }    

    static int [] rev(int i,int p,int a[])
    {

        for(int j=i;j<=p;j++)
        {
            int temp=a[j];
            a[j]=a[p];
            a[p]=temp;
            p--;
        }
        return a;
    }

    static void sort(int[] a) {
        ArrayList<Integer> l = new ArrayList<>();
        for (int i : a)
            l.add(i);
        Collections.sort(l);
        for (int i = 0; i < a.length; i++)
            a[i] = l.get(i);
    }

    public static void main(String[] args) 
    {
        FastReader d=new FastReader();
        int t,i,j,c,z,k,l,n;
        int mod = (int) 1e9 + 7;
        int Inf=Integer.MAX_VALUE;
        int negInf=Integer.MIN_VALUE;
        //t=d.nextInt();
        t=1;
        //String s;
        //char ch,ch1,ch2,ch3;
        while(t-->0)
        {
            z=c=0;
            n=d.nextInt();
            long tt=d.nextLong();
            double p=1.000000011;
            double q=1d;
            long ii;
            while(tt>1)
            {
                for(ii=1;2*ii<=tt;ii*=2)
                {
                    p*=p;
                    c++;
                }
                tt-=ii;
                q*=p;
                p=1.000000011;;
            }
            if(t==1)
            q*=1.000000011;
            q*=n;
            System.out.println(q);
            //System.out.println(c);
            //int a[]=new int[n];
            //for(i=0;i<n;i++)
            //a[i]=d.nextInt();
            //s=d.nextLine();//dont need extra d.nextLine()
        }
    } 
}