Problem: Levko loves permutations very much. A permutation of length n is a sequence of distinct positive integers, each is at most n.

Let’s assume that value gcd(a, b) shows the greatest common divisor of numbers a and b. Levko assumes that element pi of permutation p1, p2, ... , pn is good if gcd(i, pi) > 1. Levko considers a permutation beautiful, if it has exactly k good elements. Unfortunately, he doesn’t know any beautiful permutation. Your task is to help him to find at least one of them.

Input

The single line contains two integers n and k (1 ≤ n ≤ 105, 0 ≤ k ≤ n).

Output

In a single line print either any beautiful permutation or -1, if such permutation doesn’t exist.

If there are multiple suitable permutations, you are allowed to print any of them.

Examples

Input

4 2


Output

2 4 3 1

Input

1 1


Output

-1

Note

In the first sample elements 4 and 3 are good because gcd(2, 4) = 2 > 1 and gcd(3, 3) = 3 > 1. Elements 2 and 1 are not good because gcd(1, 2) = 1 and gcd(4, 1) = 1. As there are exactly 2 good elements, the permutation is beautiful.

The second sample has no beautiful permutations.

Solution (in PYTHON):

Solution:
from Queue import * # Queue, LifoQueue, PriorityQueue
from bisect import * #bisect, insort
from datetime import * 
from collections import * #deque, Counter,OrderedDict,defaultdict
import calendar
import heapq
import math
import copy
import itertools

def gcd(a,b):
    r = a % b
    while r != 0:
        a = b
        b = r
        r = a % b

    return b


def solver():
    n,k = map(int,raw_input().split())

    k = n- k
    if k == 0:
        print -1
        return

    koukan = k / 2
    ans = [i+1 for i in range(n)]

    if k % 2 == 1:
        i = 1
        while koukan != 0:
            koukan -=1
            ans[i],ans[i+1] = ans[i+1],ans[i]
            i += 2
    else:
        i = 0
        while koukan != 0:
            koukan -= 1
            ans[i],ans[i+1] = ans[i+1],ans[i]
            i += 2

    for i in range(n-1):
        print ans[i],

    print ans[-1]


        


if __name__ == "__main__":
    solver()