Problem: Hearing that energy drinks increase rating in those sites, Takahashi decides to buy up M cans of energy drinks.

There are N stores that sell energy drinks. In the i-th store, he can buy at most B_i cans of energy drinks for A_i yen (the currency of Japan) each.

What is the minimum amount of money with which he can buy M cans of energy drinks?

It is guaranteed that, in the given inputs, a sufficient amount of money can always buy M cans of energy drinks.

Constraints

* All values in input are integers.
* 1 \leq N, M \leq 10^5
* 1 \leq A_i \leq 10^9
* 1 \leq B_i \leq 10^5
* B_1 + ... + B_N \geq M

Input

Input is given from Standard Input in the following format:


N M
A_1 B_1
A_2 B_2
\vdots
A_N B_N


Output

Print the minimum amount of money with which Takahashi can buy M cans of energy drinks.

Examples

Input

2 5
4 9
2 4


Output

12


Input

4 30
6 18
2 5
3 10
7 9


Output

130


Input

1 100000
1000000000 100000


Output

100000000000000

Solution (in JAVA):

Solution:
import java.lang.reflect.Array;
import java.util.Arrays;
import java.util.Map;
import java.util.Scanner;
import java.util.TreeMap;

public class Main {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        
        int N = sc.nextInt();
        int M = sc.nextInt();

        int array[][] = new int[N][2];

        for (int i = 0; i < N; i++) {
            array[i][0] = sc.nextInt();
            array[i][1] = sc.nextInt();
        }

        Arrays.sort(array, (a, b) -> Integer.compare(a[0], b[0]));

        long res = 0;

        for(int[] pair: array) {
            int a = pair[0];
            int b = pair[1];

            if ( b > M ) {
                res += (long)a * (long)M;
                break;
            } else {
                res += (long)a * (long)b;
                M -= b;
            }
        }

        System.out.println(res);

    }
}