Problem: Hearing that energy drinks increase rating in those sites, Takahashi decides to buy up M cans of energy drinks.

There are N stores that sell energy drinks. In the i-th store, he can buy at most B_i cans of energy drinks for A_i yen (the currency of Japan) each.

What is the minimum amount of money with which he can buy M cans of energy drinks?

It is guaranteed that, in the given inputs, a sufficient amount of money can always buy M cans of energy drinks.

Constraints

* All values in input are integers.
* 1 \leq N, M \leq 10^5
* 1 \leq A_i \leq 10^9
* 1 \leq B_i \leq 10^5
* B_1 + ... + B_N \geq M

Input

Input is given from Standard Input in the following format:


N M
A_1 B_1
A_2 B_2
\vdots
A_N B_N


Output

Print the minimum amount of money with which Takahashi can buy M cans of energy drinks.

Examples

Input

2 5
4 9
2 4


Output

12


Input

4 30
6 18
2 5
3 10
7 9


Output

130


Input

1 100000
1000000000 100000


Output

100000000000000

Solution (in JAVA):

Solution:
import java.util.Scanner;
import java.util.TreeMap;

public class Main {
    public static void main(String[] args) {
        Scanner scan = new Scanner(System.in);
        int n = scan.nextInt();
        int m = scan.nextInt();

        TreeMap<Long, Long> map = new TreeMap<>();
        for(int i = 0; i < n; i++) {
        	long a = scan.nextLong();
        	long b = scan.nextLong();
        	if(map.containsKey(a)) {
        		map.put(a, map.get(a) + b);
        	}else {
        		map.put(a, b);
        	}
        }

        long ans = 0;
        for(long i: map.keySet()) {
        	if(m >= map.get(i)) {
        		ans += i * map.get(i);
        		m -= map.get(i);
        	}else {
        		ans += i * m;
        		m -= m;
        	}

        	if(m ==0)
        		break;
        }
        System.out.println(ans);
    }
}