Problem: Constraints

* 1 ≤ |V| ≤ 1000
* 0 ≤ |E| ≤ 2000
* -10000 ≤ di ≤ 10000
* There are no parallel edges
* There are no self-loops

Input

An edge-weighted graph G (V, E) and the source r.


|V| |E| r
s0 t0 d0
s1 t1 d1
:
s|E|-1 t|E|-1 d|E|-1


|V| is the number of vertices and |E| is the number of edges in G. The graph vertices are named with the numbers 0, 1,..., |V|-1 respectively. r is the source of the graph.

si and ti represent source and target vertices of i-th edge (directed) and di represents the cost of the i-th edge.

Output

If the graph contains a negative cycle (a cycle whose sum of edge costs is a negative value) which is reachable from the source r, print


NEGATIVE CYCLE


in a line.

Otherwise, print


c0
c1
:
c|V|-1


The output consists of |V| lines. Print the cost of the shortest path from the source r to each vertex 0, 1, ... |V|-1 in order. If there is no path from the source to a vertex, print "INF".

Examples

Input

4 5 0
0 1 2
0 2 3
1 2 -5
1 3 1
2 3 2


Output

0
2
-3
-1


Input

4 6 0
0 1 2
0 2 3
1 2 -5
1 3 1
2 3 2
3 1 0


Output

NEGATIVE CYCLE


Input

4 5 1
0 1 2
0 2 3
1 2 -5
1 3 1
2 3 2


Output

INF
0
-5
-3

Solution (in PYTHON):

Solution:
def bellmanford(s,v,es):
    n=len(es)
    negative=False
    d=[inf for _ in xrange(v)]
    d[s]=0
    for i in xrange(n):
        update=False
        for fr,to,cost in es:
            if fr!=float('inf') and d[to]>d[fr]+cost:
                d[to]=d[fr]+cost
                update=True
                if i==n-1:
                    negative=True
        if not update:
            break
    return d,negative

inf=float('inf')
V,E,r=map(int,raw_input().split())
es=[map(int,raw_input().split()) for _ in xrange(E)]
d,negative=bellmanford(r,V,es)
if negative:
    print("NEGATIVE CYCLE")
else:
    for i in d:
        print(i if i<inf else "INF")