Problem: You are given an array a of n integers.

You want to make all elements of a equal to zero by doing the following operation exactly three times:

  * Select a segment, for each number in this segment we can add a multiple of len to it, where len is the length of this segment (added integers can be different). 



It can be proven that it is always possible to make all elements of a equal to zero.

Input

The first line contains one integer n (1 ≤ n ≤ 100 000): the number of elements of the array.

The second line contains n elements of an array a separated by spaces: a_1, a_2, ..., a_n (-10^9 ≤ a_i ≤ 10^9).

Output

The output should contain six lines representing three operations.

For each operation, print two lines:

  * The first line contains two integers l, r (1 ≤ l ≤ r ≤ n): the bounds of the selected segment.

  * The second line contains r-l+1 integers b_l, b_{l+1}, ..., b_r (-10^{18} ≤ b_i ≤ 10^{18}): the numbers to add to a_l, a_{l+1}, …, a_r, respectively; b_i should be divisible by r - l + 1.

Example

Input


4
1 3 2 4


Output


1 1 
-1
3 4
4 2
2 4
-3 -6 -6

Solution (in PYTHON3):

Solution:
# -*- coding: utf-8 -*-

import sys
# sys.setrecursionlimit(10**6)
# buff_readline = sys.stdin.buffer.readline
buff_readline = sys.stdin.readline
readline = sys.stdin.readline

INF = 2**62-1


def read_int():
    return int(buff_readline())


def read_int_n():
    return list(map(int, buff_readline().split()))


def read_float():
    return float(buff_readline())


def read_float_n():
    return list(map(float, buff_readline().split()))


def read_str():
    return readline().strip()


def read_str_n():
    return readline().strip().split()

def error_print(*args):
    print(*args, file=sys.stderr)


def mt(f):
    import time

    def wrap(*args, **kwargs):
        s = time.time()
        ret = f(*args, **kwargs)
        e = time.time()

        error_print(e - s, 'sec')
        return ret

    return wrap


def divisor(n):
    for i in range(1, int(n**0.5)+1):
        if n % i == 0:
            yield i
            if i != n // i:
                yield n // i


@mt
def slv(N, A):


    if N == 1:
        print(1, 1)
        print(-A[0])

        print(1, 1)
        print(0)

        print(1, 1)
        print(0)

        return

    a = A[:]
    na = a[:]
    error_print([-na[i] % N for i in range(N)])
    for i in range(N-1):
        if a[i] > 0:
            na[i] = a[i] + (a[i] % N) * (N-1)
        else:
            na[i] = a[i] - (N - (a[i] % N)) * (N-1)
    print(1, N-1)
    print(*[na[i] - a[i] for i in range(N-1)])


    a = na[:]
    for i in range(N-1, N):
        if a[i] > 0:
            na[i] = a[i] - (a[i] % N)
        else:
            na[i] = a[i] - (a[i] % N)
    print(N, N)
    print(*[na[i] - a[i] for i in range(N-1, N)])

    print(1, N)
    print(*[-na[i] for i in range(N)])

    error_print(na)
    error_print([-na[i]%N for i in range(N)])



def main():
    N = read_int()
    A = read_int_n()
    slv(N, A)


if __name__ == '__main__':
    main()