Problem: You are given a sequence a1, a2, ..., an consisting of different integers. It is required to split this sequence into the maximum number of subsequences such that after sorting integers in each of them in increasing order, the total sequence also will be sorted in increasing order.

Sorting integers in a subsequence is a process such that the numbers included in a subsequence are ordered in increasing order, and the numbers which are not included in a subsequence don't change their places.

Every element of the sequence must appear in exactly one subsequence.

Input

The first line of input data contains integer n (1 ≤ n ≤ 105) — the length of the sequence.

The second line of input data contains n different integers a1, a2, ..., an ( - 109 ≤ ai ≤ 109) — the elements of the sequence. It is guaranteed that all elements of the sequence are distinct.

Output

In the first line print the maximum number of subsequences k, which the original sequence can be split into while fulfilling the requirements.

In the next k lines print the description of subsequences in the following format: the number of elements in subsequence ci (0 < ci ≤ n), then ci integers l1, l2, ..., lci (1 ≤ lj ≤ n) — indices of these elements in the original sequence. 

Indices could be printed in any order. Every index from 1 to n must appear in output exactly once.

If there are several possible answers, print any of them.

Examples

Input

6
3 2 1 6 5 4


Output

4
2 1 3
1 2
2 4 6
1 5


Input

6
83 -75 -49 11 37 62


Output

1
6 1 2 3 4 5 6

Note

In the first sample output:

After sorting the first subsequence we will get sequence 1 2 3 6 5 4.

Sorting the second subsequence changes nothing.

After sorting the third subsequence we will get sequence 1 2 3 4 5 6.

Sorting the last subsequence changes nothing.

Solution (in JAVA):

Solution:
//package AIM_TECH_4; doubleCheck

import java.io.*;
import java.util.*;

public class C {
	public static void main(String[] args) throws Exception{ new C(new Reader()); }
	public C(Reader rr) throws IOException{
		int n=rr.ni();
		int[] a=new int[n];
		int[] b=new int[n];
		Map<Integer, Integer> indexOf=new HashMap<Integer, Integer>(n, 2);
		for(int i=0; i<n; i++){
			int next=rr.ni();
			a[i]=next; b[i]=next;
			indexOf.put(next, i);
		}
		Arrays.sort(b);
		ArrayList<ArrayList<Integer>> output=new ArrayList<ArrayList<Integer>>();
		boolean[] visited=new boolean[n];
		for(int i=0; i<n; i++){
			if(visited[i]) continue;
			ArrayList<Integer> sequence=new ArrayList<Integer>();
			int replace=a[i];
			int actual=b[i];
			int index=i;
			while(replace!=actual){
				sequence.add(indexOf.get(actual)+1);
				a[index]=actual;
				visited[index]=true;
				index=indexOf.get(actual);
				a[index]=replace;
				actual=b[index];
			}
			visited[index]=true;
			sequence.add(indexOf.get(actual)+1);
			sequence.add(0, sequence.size());
			output.add(sequence);
		}
		System.out.println(output.size());
		for(int i=0; i<output.size(); i++){
			for(int j=0; j<output.get(i).size(); j++)
				System.out.print(output.get(i).get(j)+" ");
			System.out.println();
		}
	}
	static class Reader{
		private DataInputStream din;
		private byte[] buffer=new byte[1024];
		private int bufP, bytR;
		public Reader() throws IOException{
			din=new DataInputStream(System.in);
			bufP=bytR=0;
		}
		public Reader(String file) throws IOException{
			din=new DataInputStream(new FileInputStream(file));
			bufP=bytR=0;
		}
		private String rl() throws IOException{
			byte[] buf=new byte[1024];
			int cnt=0, c;
			while((c=read())!=-1){
				if(c=='\n') break;
				buf[cnt++]=(byte)c;
			}
			return new String(buf, 0, cnt);
		}
		private int ni() throws IOException{
			int num=0;
			byte c=read();
			while(c<=' ') c=read();
			boolean neg=(c=='-');
			if(neg) c=read();
			do{
				num=num*10+c-'0';
			} while((c=read())>='0'&&c<='9');
			if(neg) return -num;
			return num;
		}
		private long nl() throws IOException{
			long num=0;
			byte c=read();
			while(c<=' ') c=read();
			boolean neg=(c=='-');
			if(neg) c=read();
			do{
				num=num*10+c-'0';
			} while((c=read())>='0'&&c<='9');
			if(neg) return -num;
			return num;
		}
		private double nd() throws IOException{ return Double.parseDouble(ns()); }
		private char nc() throws IOException{ return (char)next(); }
		private String ns() throws IOException{
			int c=next();
			StringBuilder sb=new StringBuilder();
			while(!(isChar(c))){
				sb.appendCodePoint(c);
				c=read();
			}
			return sb.toString();
		}
		private char[] ns(int n) throws IOException{
			char[] buf=new char[n];
			int c=next(), r=0;
			while(r<n&&!(isChar(c))){
				buf[r++]=(char)c;
				c=next();
			}
			return n==r?buf:Arrays.copyOf(buf, r);
		}
		private char[][] nm(int n, int m) throws IOException{
			char[][] map=new char[n][];
			for(int i=0; i<n; i++) map[i]=ns(m);
			return map;
		}
		private int[] na(int n) throws IOException{
			int[] a=new int[n];
			for(int i=0; i<n; i++) a[i]=ni();
			return a;
		}
		private boolean isChar(int c) throws IOException{ return !(c>=33&&c<=126); }
		private int next() throws IOException{ int c; while((c=read())!=-1&&isChar(c)); return c; }
		private byte read() throws IOException{
			if(bufP==bytR){
				bytR=din.read(buffer, bufP=0, 1024);
				if(bytR==-1) buffer[0]=-1;
			}
			return buffer[bufP++];
		}
		public void close() throws IOException{
			if(din==null) return;
			din.close();
		}
	}
}