Problem: A TV show called "Guess a number!" is gathering popularity. The whole Berland, the old and the young, are watching the show.

The rules are simple. The host thinks of an integer y and the participants guess it by asking questions to the host. There are four types of acceptable questions:

  * Is it true that y is strictly larger than number x? 
  * Is it true that y is strictly smaller than number x? 
  * Is it true that y is larger than or equal to number x? 
  * Is it true that y is smaller than or equal to number x? 



On each question the host answers truthfully, "yes" or "no".

Given the sequence of questions and answers, find any integer value of y that meets the criteria of all answers. If there isn't such value, print "Impossible".

Input

The first line of the input contains a single integer n (1 ≤ n ≤ 10000) — the number of questions (and answers). Next n lines each contain one question and one answer to it. The format of each line is like that: "sign x answer", where the sign is:

  * ">" (for the first type queries), 
  * "<" (for the second type queries), 
  * ">=" (for the third type queries), 
  * "<=" (for the fourth type queries). 



All values of x are integer and meet the inequation  - 109 ≤ x ≤ 109. The answer is an English letter "Y" (for "yes") or "N" (for "no").

Consequtive elements in lines are separated by a single space.

Output

Print any of such integers y, that the answers to all the queries are correct. The printed number y must meet the inequation  - 2·109 ≤ y ≤ 2·109. If there are many answers, print any of them. If such value doesn't exist, print word "Impossible" (without the quotes).

Examples

Input

4
&gt;= 1 Y
&lt; 3 N
&lt;= -3 N
&gt; 55 N


Output

17


Input

2
&gt; 100 Y
&lt; -100 Y


Output

Impossible

Solution (in JAVA):

Solution:

print(function(n){
	var high = 1e9+5;
	var low = -1e9-5;
	for(var i=0; i<n; i++){
		var l = readline().split(' ');

		if(l[0] === '>='){
			if(l[2] === 'Y'){
				low = Math.max(+l[1], low);
			}else{
				high = Math.min(+l[1]-1, high);
			}
		}else if(l[0] === '<='){
			if(l[2] === 'Y'){
				high = Math.min(+l[1], high);
			}else{
				low = Math.max(+l[1]+1, low);
			}
		}else if(l[0] === '>'){
			if(l[2] === 'Y'){
				low = Math.max(+l[1]+1, low);
			}else{
				high = Math.min(+l[1], high);
			}
		}else if(l[0] === '<'){
			if(l[2] === 'Y'){
				high = Math.min(+l[1]-1, high);
			}else{
				low = Math.max(+l[1], low);
			}
		}
	}
	if( high >= low ){
		return low;
	}
	return 'Impossible';

}(+readline()));