Problem: Constraints

* 1 ≤ |V| ≤ 1000
* 0 ≤ |E| ≤ 2000
* -10000 ≤ di ≤ 10000
* There are no parallel edges
* There are no self-loops

Input

An edge-weighted graph G (V, E) and the source r.


|V| |E| r
s0 t0 d0
s1 t1 d1
:
s|E|-1 t|E|-1 d|E|-1


|V| is the number of vertices and |E| is the number of edges in G. The graph vertices are named with the numbers 0, 1,..., |V|-1 respectively. r is the source of the graph.

si and ti represent source and target vertices of i-th edge (directed) and di represents the cost of the i-th edge.

Output

If the graph contains a negative cycle (a cycle whose sum of edge costs is a negative value) which is reachable from the source r, print


NEGATIVE CYCLE


in a line.

Otherwise, print


c0
c1
:
c|V|-1


The output consists of |V| lines. Print the cost of the shortest path from the source r to each vertex 0, 1, ... |V|-1 in order. If there is no path from the source to a vertex, print "INF".

Examples

Input

4 5 0
0 1 2
0 2 3
1 2 -5
1 3 1
2 3 2


Output

0
2
-3
-1


Input

4 6 0
0 1 2
0 2 3
1 2 -5
1 3 1
2 3 2
3 1 0


Output

NEGATIVE CYCLE


Input

4 5 1
0 1 2
0 2 3
1 2 -5
1 3 1
2 3 2


Output

INF
0
-5
-3

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;

struct edge { int from, to, cost; };

typedef pair<long long, int> plli;
int main() {
  int n, m, r;
  cin>>n>>m>>r;
  vector<edge> graph(m);
  for (int i=0; i<m; i++) {
    int s, t, d;
    cin>>s>>t>>d;
    graph[i] = {s, t, d};
  }
  long long inf = 1e5 * 1e4 + 1;

  long long d[n];
  for (int i=0; i<n; i++) {
    d[i] = inf;
  }

  d[r] = 0;
  for (int i=0; i<2*n; i++) {
    for (edge e: graph) {
      if (d[e.from] != inf && d[e.to] > d[e.from] + e.cost) {
        d[e.to] = d[e.from] + e.cost;
        if (i >= n) {
          cout<<"NEGATIVE CYCLE"<<endl;
          return 0;
        }
      }
    }
  }
  for (auto di: d) {
    if (di == inf) {
      cout<<"INF"<<endl;
    } else {
      cout<<di<<endl;
    }

  }
}