Problem: You're given a list of n strings a1, a2, ..., an. You'd like to concatenate them together in some order such that the resulting string would be lexicographically smallest.

Given the list of strings, output the lexicographically smallest concatenation.

Input

The first line contains integer n — the number of strings (1 ≤ n ≤ 5·104).

Each of the next n lines contains one string ai (1 ≤ |ai| ≤ 50) consisting of only lowercase English letters. The sum of string lengths will not exceed 5·104.

Output

Print the only string a — the lexicographically smallest string concatenation.

Examples

Input

4
abba
abacaba
bcd
er


Output

abacabaabbabcder


Input

5
x
xx
xxa
xxaa
xxaaa


Output

xxaaaxxaaxxaxxx


Input

3
c
cb
cba


Output

cbacbc

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.*;

public class Main{
    public static long mod = (long)1e9+7;
    public static ArrayList<Integer>[] graph;
    public static void main(String[] args) {
        InputStream inputStream = System.in;
		OutputStream outputStream = System.out;
		InputReader in = new InputReader(inputStream);
		PrintWriter out = new PrintWriter(outputStream);
        int t = 1;
        // t = in.nextInt();
        for(int i = 1;i<=t ;i++){
            solve(in,out);
        }
        out.close();
    }

    private static void solve(InputReader in, PrintWriter out) {
        int n = in.nextInt();
        String[] temp = new String[n];
        for (int i = 0; i < n; i++) {
            temp[i] = in.next();
        }   
        Arrays.sort(temp,new Comparator<String>(){
            @Override
            public int compare(String a,String b){
                String h = a+b;
                String g = b+a;
                return h.compareTo(g);
            }
            
        });
        for(String h:temp){
            out.print(h);
        }
        out.println();
    }
}
class InputReader {
    public BufferedReader reader;
    public StringTokenizer tokenizer;
 
    public InputReader(InputStream stream) {
        reader = new BufferedReader(new InputStreamReader(stream), 32768);
        tokenizer = null;
    }
 
    public String next() {
        while (tokenizer == null || !tokenizer.hasMoreTokens()) {
            try {
                tokenizer = new StringTokenizer(reader.readLine());
            } catch (IOException e) {
                throw new RuntimeException(e);
            }
        }
        return tokenizer.nextToken();
    }
 
    public int nextInt() {
        return Integer.parseInt(next());
    }
 
    public long nextLong() {
        return Long.parseLong(next());
    }
    public double nextDouble(){
        return Double.parseDouble(next());
    }
    public int[] readIntArray(int size){
        int[] list = new int[size];
        for(int i = 0;i<size;i++) list[i] = nextInt();
        return list;
    }
    public long[] readLongArray(int size){
        long[] list = new long[size];
        for(int i = 0;i<size;i++) list[i] = nextLong();
        return list;
    }
    public double[] readDoubleArray(int size){
        double[] list = new double[size];
        for(int i = 0;i<size;i++) list[i] = nextDouble();
        return list;
    }
    public String linereader() {
        String s = null;
        try{
            s = reader.readLine();
        }
        catch (IOException e) {
            throw new RuntimeException(e);
        }
        return s;
    }
 
}
class Pair<T extends Comparable<T>,K extends Comparable<K> > implements Comparable<Pair<T,K>>{
    T first;
    K second;
    public Pair(T first, K second){
        this.first  = first;
        this.second = second;
    }
    @Override
    public String toString(){
        return first+" "+second;
    }
    @Override
    public int compareTo(Pair<T,K> o) {
        // TODO Auto-generated method stub
        if((first).compareTo(o.first)!=0) return first.compareTo(o.first);
        else return second.compareTo(o.second);
    }

}