Problem: Constraints

* 1 ≤ |V| ≤ 1000
* 0 ≤ |E| ≤ 2000
* -10000 ≤ di ≤ 10000
* There are no parallel edges
* There are no self-loops

Input

An edge-weighted graph G (V, E) and the source r.


|V| |E| r
s0 t0 d0
s1 t1 d1
:
s|E|-1 t|E|-1 d|E|-1


|V| is the number of vertices and |E| is the number of edges in G. The graph vertices are named with the numbers 0, 1,..., |V|-1 respectively. r is the source of the graph.

si and ti represent source and target vertices of i-th edge (directed) and di represents the cost of the i-th edge.

Output

If the graph contains a negative cycle (a cycle whose sum of edge costs is a negative value) which is reachable from the source r, print


NEGATIVE CYCLE


in a line.

Otherwise, print


c0
c1
:
c|V|-1


The output consists of |V| lines. Print the cost of the shortest path from the source r to each vertex 0, 1, ... |V|-1 in order. If there is no path from the source to a vertex, print "INF".

Examples

Input

4 5 0
0 1 2
0 2 3
1 2 -5
1 3 1
2 3 2


Output

0
2
-3
-1


Input

4 6 0
0 1 2
0 2 3
1 2 -5
1 3 1
2 3 2
3 1 0


Output

NEGATIVE CYCLE


Input

4 5 1
0 1 2
0 2 3
1 2 -5
1 3 1
2 3 2


Output

INF
0
-5
-3

Solution (in PYTHON3):

Solution:
N, M, S = map(int, input().split())
G = [[] for _ in range(N)]
for _ in range(M):
    a, b, l = map(int, input().split())
    G[a].append([b, l])
INF = 10**10


def bellman_ford(G, N, S):

    res = [INF for _ in range(N)]
    res[S] = 0
    for _ in range(N-1):
        for i in range(N):
            if res[i] == INF:
                continue
            for sa, sb in G[i]:
                res[sa] = min(res[sa], res[i]+sb)
    for i in range(N):
        if res[i] == INF:
            continue
        for sa, sb in G[i]:
            if res[sa] > res[i]+sb:
                return False
    return res


res = bellman_ford(G, N, S)
if res == False:
    print("NEGATIVE CYCLE")
else:
    for i in range(N):
        if res[i] == INF:
            print("INF")
        else:
            print(res[i])