Problem: Takahashi is at an all-you-can-eat restaurant.

The restaurant offers N kinds of dishes. It takes A_i minutes to eat the i-th dish, whose deliciousness is B_i.

The restaurant has the following rules:

* You can only order one dish at a time. The dish ordered will be immediately served and ready to eat.
* You cannot order the same kind of dish more than once.
* Until you finish eating the dish already served, you cannot order a new dish.
* After T-0.5 minutes from the first order, you can no longer place a new order, but you can continue eating the dish already served.



Let Takahashi's happiness be the sum of the deliciousness of the dishes he eats in this restaurant.

What is the maximum possible happiness achieved by making optimal choices?

Constraints

* 2 \leq N \leq 3000
* 1 \leq T \leq 3000
* 1 \leq A_i \leq 3000
* 1 \leq B_i \leq 3000
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N T
A_1 B_1
:
A_N B_N


Output

Print the maximum possible happiness Takahashi can achieve.

Examples

Input

2 60
10 10
100 100


Output

110


Input

3 60
10 10
10 20
10 30


Output

60


Input

3 60
30 10
30 20
30 30


Output

50


Input

10 100
15 23
20 18
13 17
24 12
18 29
19 27
23 21
18 20
27 15
22 25


Output

145

Solution (in JAVA):

Solution:

import java.io.IOException;
import java.io.InputStream;
import java.util.NoSuchElementException;

class FastScanner {
    private final InputStream in = System.in;
    private final byte[] buffer = new byte[1024];
    private int ptr = 0;
    private int buflen = 0;
    private boolean hasNextByte(){
        if(ptr < buflen){
            return true;
        }else{
            ptr = 0;
            try{
                buflen = in.read(buffer);
            }catch(IOException e){
                e.printStackTrace();
            }
            if(buflen <=0){
                return false;
            }
        }
        return true;
    }

    private int readByte(){
        if(hasNextByte())return buffer[ptr++];
        else return -1;
    }

    private static boolean isPrintableChar(int c){
        return 33<=c && c<=126;
    }
    public boolean hasNext(){
        while(hasNextByte() && !isPrintableChar(buffer[ptr]))ptr++;
        return hasNextByte();
    }

    public String next(){
        if(!hasNext()) throw new NoSuchElementException();
        StringBuilder sb = new StringBuilder();
        int b = readByte();
        while(isPrintableChar(b)){
            sb.appendCodePoint(b);
            b = readByte();
        }
        return sb.toString();
    }

    public long nextLong(){
        if(!hasNext()) throw new NoSuchElementException();
        long n = 0;
        boolean minus = false;
        int b = readByte();
        if(b == '-'){
            minus = true;
            b = readByte();
        }
        if(b < '0' || '9' < b){
            throw new NumberFormatException();
        }
        while(true){
            if('0' <= b && b<='9'){
                n*=10;
                n+=b-'0';
            }else if(b==-1 || !isPrintableChar(b)){
                return minus ? -n : n;
            }else{
                throw new NumberFormatException();
            }
            b = readByte();
        }
    }
    public int nextInt(){
        long nl = nextLong();
        if(nl < Integer.MIN_VALUE || nl > Integer.MAX_VALUE)throw new NumberFormatException();
        return (int) nl;
    }
    public double nextDoutble(){return Double.parseDouble(next());}
}
public class Main {
    public static void main(String[] args) {
        FastScanner fs = new FastScanner();
        int n = fs.nextInt();
        int t = fs.nextInt();
        int[][] ab = new int[n][2];
        for(int i=0;i<n;i++){
            ab[i][0] = fs.nextInt();
            ab[i][1] = fs.nextInt();
        }

        int[][] dp = new int[n+1][t];
        for(int i=0;i<n;i++){
            for(int j=0;j<t;j++){
                if(j-ab[i][0]>=0){
                   dp[i+1][j] = Math.max(dp[i][j],dp[i][j-ab[i][0]]+ab[i][1]);
                }else{
                    dp[i+1][j] = dp[i][j];
                }
            }
        }

        int[][] dp2 = new int[n+1][t];
        for(int i=n-1;i>=0;i--){
            for(int j=0;j<t;j++){
                if(j-ab[i][0]>=0){
                    dp2[i][j] = Math.max(dp2[i+1][j],dp2[i+1][j-ab[i][0]]+ab[i][1]); 
                }else{
                    dp2[i][j] = dp2[i+1][j];
                }
            }
        }

        int max = 0;
        for(int i=0;i<n;i++){
            for(int j=0;j<t;j++){
                max = Math.max(max,ab[i][1]+dp[i][j]+dp2[i+1][t-1-j]);
            }
        }

        System.out.println(max);
        
    }
}