Problem: Suppose you have a string S which has length N and is indexed from 0 to N−1. String R is the reverse of the string S. The string S is funny if the condition |Si−Si−1|=|Ri−Ri−1| is true for every i from 1 to N−1.

(Note: Given a string str, stri denotes the ascii value of the ith character (0-indexed) of str. |x| denotes the absolute value of an integer x)

SAMPLE INPUT
2
acxz
bcxz

SAMPLE OUTPUT
Funny
Not Funny

Explanation

Consider the 1st testcase acxz :

c-a
=
x-z
= 2

z-x
=
a-c
= 2

Consider the 2st testcase bcxz

|c-b| != |x-z|

Solution (in PYTHON):

Solution:
def funnyornot(string):
	rev = string[::-1]
	for i in range(len(string)/2):
		if abs(ord(string[i+1]) - ord(string[i])) != abs(ord(rev[i+1]) - ord(rev[i])):
			return "Not Funny"
	return "Funny"
#	return rev
inp = int(raw_input())
for i in range(inp):
	print funnyornot(raw_input())