Problem: Constraints

* 1 ≤ |V| ≤ 1000
* 0 ≤ |E| ≤ 2000
* -10000 ≤ di ≤ 10000
* There are no parallel edges
* There are no self-loops

Input

An edge-weighted graph G (V, E) and the source r.


|V| |E| r
s0 t0 d0
s1 t1 d1
:
s|E|-1 t|E|-1 d|E|-1


|V| is the number of vertices and |E| is the number of edges in G. The graph vertices are named with the numbers 0, 1,..., |V|-1 respectively. r is the source of the graph.

si and ti represent source and target vertices of i-th edge (directed) and di represents the cost of the i-th edge.

Output

If the graph contains a negative cycle (a cycle whose sum of edge costs is a negative value) which is reachable from the source r, print


NEGATIVE CYCLE


in a line.

Otherwise, print


c0
c1
:
c|V|-1


The output consists of |V| lines. Print the cost of the shortest path from the source r to each vertex 0, 1, ... |V|-1 in order. If there is no path from the source to a vertex, print "INF".

Examples

Input

4 5 0
0 1 2
0 2 3
1 2 -5
1 3 1
2 3 2


Output

0
2
-3
-1


Input

4 6 0
0 1 2
0 2 3
1 2 -5
1 3 1
2 3 2
3 1 0


Output

NEGATIVE CYCLE


Input

4 5 1
0 1 2
0 2 3
1 2 -5
1 3 1
2 3 2


Output

INF
0
-5
-3

Solution (in CPP):

Solution:
#include <iostream>
#include <cstdlib>
using namespace std;
#define INF 1e9
#define MAX_E 500000
#define MAX_V 100000

struct edge {int u, v, cost;};
edge es[MAX_E];

int dis[MAX_V];
int V, E, r;

void bellman_ford(int s){
  for(int i = 0; i < V; i++) dis[i] = INF;
  dis[s] = 0;
  int count = 0;
  while(true){
    if(++count == V && count > 1){
      cout << "NEGATIVE CYCLE" << endl;
      exit(0);
    }
    bool update = false;
    for(int i = 0; i < E; i++){
      edge e = es[i];
      if(dis[e.u] != INF && dis[e.v] > dis[e.u] + e.cost){
        dis[e.v] = dis[e.u] + e.cost;
        update = true;
      }
    }
    if(!update) break;
  }
}

int main(void){
  int s, t, d;
  cin >> V >> E >> r;
  for(int i = 0; i < E; i++){
    cin >> s >> t >> d;
    edge e;
    e.u = s; e.v = t; e.cost = d;
    es[i] = e;
  }
  bellman_ford(r);
  for(int i = 0; i < V; i++){
    if(dis[i] == INF) cout << "INF" << endl;
    else cout << dis[i] << endl;
  }
  return 0;
}