Problem: Constraints

* 1 ≤ |V| ≤ 1000
* 0 ≤ |E| ≤ 2000
* -10000 ≤ di ≤ 10000
* There are no parallel edges
* There are no self-loops

Input

An edge-weighted graph G (V, E) and the source r.


|V| |E| r
s0 t0 d0
s1 t1 d1
:
s|E|-1 t|E|-1 d|E|-1


|V| is the number of vertices and |E| is the number of edges in G. The graph vertices are named with the numbers 0, 1,..., |V|-1 respectively. r is the source of the graph.

si and ti represent source and target vertices of i-th edge (directed) and di represents the cost of the i-th edge.

Output

If the graph contains a negative cycle (a cycle whose sum of edge costs is a negative value) which is reachable from the source r, print


NEGATIVE CYCLE


in a line.

Otherwise, print


c0
c1
:
c|V|-1


The output consists of |V| lines. Print the cost of the shortest path from the source r to each vertex 0, 1, ... |V|-1 in order. If there is no path from the source to a vertex, print "INF".

Examples

Input

4 5 0
0 1 2
0 2 3
1 2 -5
1 3 1
2 3 2


Output

0
2
-3
-1


Input

4 6 0
0 1 2
0 2 3
1 2 -5
1 3 1
2 3 2
3 1 0


Output

NEGATIVE CYCLE


Input

4 5 1
0 1 2
0 2 3
1 2 -5
1 3 1
2 3 2


Output

INF
0
-5
-3

Solution (in CPP):

Solution:
#include<bits/stdc++.h>
using namespace std;

struct edge{
  int to, cost;
};

int main(int argc, char *argv[]){
  int n, m, r;
  cin >> n >> m >> r;
  vector<vector<edge> > g(n);
  int from;
  for (int i = 0; i < m; i++) {
    edge e;
    cin >> from >> e.to >> e.cost;
    g[from].push_back(e);
  }
  int dp[n];
  for (int i = 0; i < n; i++) {
    dp[i] = 1e9;
  }
  dp[r] = 0;
  //???????????§?????????
  //????????????????????????????????????
  bool update = true;
  int cnt = 0;
  while(update){
    if(cnt > n)break;
    cnt++;
    update = false;
    for (int i = 0; i < n; i++) {
      for (int j = 0; j < g[i].size(); j++) {
        edge e = g[i][j];
        if(dp[e.to] > dp[i] + e.cost && dp[i] != 1e9){
          dp[e.to] = dp[i] + e.cost;
          update = true;
        }
      }
    }
  }
  if(cnt > n){
    std::cout << "NEGATIVE CYCLE" << std::endl;
  }else{
    for (int i = 0; i < n; i++) {
      if(dp[i] == 1e9)std::cout << "INF" << std::endl;
      else std::cout << dp[i] << std::endl;
    }
  }
  return 0;
}