Problem: You're given an array a of length n. You can perform the following operations on it:

  * choose an index i (1 ≤ i ≤ n), an integer x (0 ≤ x ≤ 10^6), and replace a_j with a_j+x for all (1 ≤ j ≤ i), which means add x to all the elements in the prefix ending at i. 
  * choose an index i (1 ≤ i ≤ n), an integer x (1 ≤ x ≤ 10^6), and replace a_j with a_j \% x for all (1 ≤ j ≤ i), which means replace every element in the prefix ending at i with the remainder after dividing it by x. 



Can you make the array strictly increasing in no more than n+1 operations?

Input

The first line contains an integer n (1 ≤ n ≤ 2000), the number of elements in the array a.

The second line contains n space-separated integers a_1, a_2, ..., a_n (0 ≤ a_i ≤ 10^5), the elements of the array a.

Output

On the first line, print the number of operations you wish to perform. On the next lines, you should print the operations.

To print an adding operation, use the format "1 i x"; to print a modding operation, use the format "2 i x". If i or x don't satisfy the limitations above, or you use more than n+1 operations, you'll get wrong answer verdict.

Examples

Input

3
1 2 3


Output

0

Input

3
7 6 3


Output

2
1 1 1
2 2 4

Note

In the first sample, the array is already increasing so we don't need any operations.

In the second sample:

In the first step: the array becomes [8,6,3].

In the second step: the array becomes [0,2,3].

Solution (in JAVA):

Solution:
import java.util.*;
import java.io.*;
import java.math.*;
 
public class Main {

	private static FastReader fr = new FastReader();
	private static Helper helper = new Helper();
	private static StringBuilder result = new StringBuilder();
 
	public static void main(String[] args) {
		Task solver = new Task();
		solver.solve();
	}
 
	static class Task {
	    
		public void solve() {
		    int n = fr.ni();
			long[] arr = new long[n];
			for(int i=0; i<n; i++) arr[i] = fr.nl();
			result.append(n+1).append("\n");
			long sum = 0;
			for(int i=n-1; i>=0; i--){
				long add = i + (n-(arr[i]+sum)%n);
				arr[i] += add;
				result.append("1 ").append(i+1).append(" ").append(add).append("\n");
				sum += add;
			}
			for(int i=0; i<n; i++) arr[i] %= n;
			result.append("2 ").append(n).append(" ").append(n).append("\n");
			System.out.println(result);
		}
	}
    
    static class Helper{
		public long[] tiArr(int n, int si){
			long[] arr = new long[n];
			for(int i=si; i<n; i++) arr[i] = fr.nl();
			return arr;
		}
	}
 
	static class FastReader {
		public BufferedReader reader;
		public StringTokenizer tokenizer;
		private static PrintWriter pw;
 
		public FastReader() {
			reader = new BufferedReader(new InputStreamReader(System.in));
			pw = new PrintWriter(System.out);
			tokenizer = null;
		}
 
		public String next() {
			while (tokenizer == null || !tokenizer.hasMoreTokens()) {
				try {
					tokenizer = new StringTokenizer(reader.readLine());
				} catch (IOException e) {
					throw new RuntimeException(e);
				}
			}
			return tokenizer.nextToken();
		}
 
		public int ni() {
			return Integer.parseInt(next());
		}
 
		public long nl() {
			return Long.parseLong(next());
		}
 
		public String rl() {
			try {
				return reader.readLine();
			} catch (IOException e) {
				e.printStackTrace();
			}
			return null;
		}
 
		public void print(String str) {
			pw.print(str);
			pw.flush();
		}
	}
}