Problem: Valera is a coder. Recently he wrote a funny program. The pseudo code for this program is given below:
    
    
      
    //input: integers x, k, p  
    a = x;  
    for(step = 1; step <= k; step = step + 1){  
        rnd = [random integer from 1 to 100];  
        if(rnd <= p)  
            a = a * 2;  
        else  
            a = a + 1;  
    }  
      
    s = 0;  
      
    while(remainder after dividing a by 2 equals 0){  
        a = a / 2;  
        s = s + 1;  
    }  
      
    

Now Valera wonders: given the values x, k and p, what is the expected value of the resulting number s?

Input

The first line of the input contains three integers x, k, p (1 ≤ x ≤ 109; 1 ≤ k ≤ 200; 0 ≤ p ≤ 100).

Output

Print the required expected value. Your answer will be considered correct if the absolute or relative error doesn't exceed 10 - 6.

Examples

Input

1 1 50


Output

1.0000000000000


Input

5 3 0


Output

3.0000000000000


Input

5 3 25


Output

1.9218750000000

Note

If the concept of expected value is new to you, you can read about it by the link: 

http://en.wikipedia.org/wiki/Expected_value

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
int x, k;
double f[2][210], p;
int main() {
  scanf("%d%d%lf", &x, &k, &p);
  p /= 100.0;
  for (int i = 0; i <= k; i++) {
    register int t = x + i;
    while (!(t & 1)) f[0][i]++, t >>= 1;
  }
  for (int i = 1; i <= k; i++) {
    memset(f[i & 1], 0, sizeof(f[0]));
    for (int j = 0; j <= k; j++) {
      if (j) f[i & 1][j - 1] += f[!(i & 1)][j] * (1.0 - p);
      if ((j << 1) <= k) f[i & 1][j << 1] += (f[!(i & 1)][j] + 1) * p;
    }
  }
  printf("%.10f\n", f[k & 1][0]);
  return 0;
}