Problem: You're given a list of n strings a1, a2, ..., an. You'd like to concatenate them together in some order such that the resulting string would be lexicographically smallest.

Given the list of strings, output the lexicographically smallest concatenation.

Input

The first line contains integer n — the number of strings (1 ≤ n ≤ 5·104).

Each of the next n lines contains one string ai (1 ≤ |ai| ≤ 50) consisting of only lowercase English letters. The sum of string lengths will not exceed 5·104.

Output

Print the only string a — the lexicographically smallest string concatenation.

Examples

Input

4
abba
abacaba
bcd
er


Output

abacabaabbabcder


Input

5
x
xx
xxa
xxaa
xxaaa


Output

xxaaaxxaaxxaxxx


Input

3
c
cb
cba


Output

cbacbc

Solution (in JAVA):

Solution:

import java.io.*;
import java.lang.*;
import java.util.*;

public class C632 {
    public static void main(String[] args) throws IOException{
        StringBuffer ans = new StringBuffer();
        StringTokenizer st;
        BufferedReader f = new BufferedReader(new InputStreamReader(System.in));
        st = new StringTokenizer(f.readLine());
        int n = Integer.parseInt(st.nextToken());
        str[] arr = new str[n];
        for(int i = 0; i < n; i++){
            st = new StringTokenizer(f.readLine());
            arr[i] = new str(st.nextToken());
        }
        Arrays.sort(arr);
        //System.out.println(Arrays.toString(arr));
        for(str i : arr)
            ans.append(i);
        f.close();



        System.out.println(ans);
    }
    public static class str implements Comparable<str>{
        String x;
        public str(String x){
            this.x = x;
        }
        public String toString(){
            return(x);
        }
        public boolean equals(Object x){
            str y = ((str)(x));
            if (this.x.equals(y.x)){
                return true;
            }
            return false;
        }
        public int hashCode(){
            return Objects.hash(x);
        }
        public int compareTo(str other) {
            String r = x+other.x;
            String r1 = other.x+x;
            return r.compareTo(r1);
        }
    }
}