Problem: Hearing that energy drinks increase rating in those sites, Takahashi decides to buy up M cans of energy drinks.

There are N stores that sell energy drinks. In the i-th store, he can buy at most B_i cans of energy drinks for A_i yen (the currency of Japan) each.

What is the minimum amount of money with which he can buy M cans of energy drinks?

It is guaranteed that, in the given inputs, a sufficient amount of money can always buy M cans of energy drinks.

Constraints

* All values in input are integers.
* 1 \leq N, M \leq 10^5
* 1 \leq A_i \leq 10^9
* 1 \leq B_i \leq 10^5
* B_1 + ... + B_N \geq M

Input

Input is given from Standard Input in the following format:


N M
A_1 B_1
A_2 B_2
\vdots
A_N B_N


Output

Print the minimum amount of money with which Takahashi can buy M cans of energy drinks.

Examples

Input

2 5
4 9
2 4


Output

12


Input

4 30
6 18
2 5
3 10
7 9


Output

130


Input

1 100000
1000000000 100000


Output

100000000000000

Solution (in JAVA):

Solution:
import java.util.*;

class Main {
	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		int N = sc.nextInt();
		long M = sc.nextLong();
		long[][] x = new long[N][2];
		for (int i=0;i<N;i++) {
			for (int j=0;j<2;j++) {
				x[i][j]=sc.nextLong();
			}
		}
		Arrays.sort(x,Comparator.comparingLong(o -> o[0]));
		int num=0;
		Long cost=(long)0;
		while (M>0) {
			if (M>=x[num][1]) {
				M=M-x[num][1];
				cost=cost+x[num][0]*x[num][1];
				num++;
			}else {
				break;
			}
		}
		if (M>0) {
			cost=cost+x[num][0]*M;
		}
		System.out.println(cost);
	}
}