Problem: You're given a list of n strings a1, a2, ..., an. You'd like to concatenate them together in some order such that the resulting string would be lexicographically smallest.

Given the list of strings, output the lexicographically smallest concatenation.

Input

The first line contains integer n — the number of strings (1 ≤ n ≤ 5·104).

Each of the next n lines contains one string ai (1 ≤ |ai| ≤ 50) consisting of only lowercase English letters. The sum of string lengths will not exceed 5·104.

Output

Print the only string a — the lexicographically smallest string concatenation.

Examples

Input

4
abba
abacaba
bcd
er


Output

abacabaabbabcder


Input

5
x
xx
xxa
xxaa
xxaaa


Output

xxaaaxxaaxxaxxx


Input

3
c
cb
cba


Output

cbacbc

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.util.*;

public class Main {
    static BufferedReader in;
    static PrintWriter out;
    static StringTokenizer buffer;

    public static void solve() {
        int n = ni();
        String[] s = new String[n];
        for (int i=0;i<n;i++) s[i] = ns();
        Arrays.sort(s, new Comparator<String>(){
            @Override
            public int compare(String o1, String o2) {
                return (o1+o2).compareTo(o2+o1);
            }
        });
        for (int i=0;i<n;i++) {
            out.print(s[i]);
        }
        out.println();
    }

    public static void main(String[] args) throws IOException {
        in = new BufferedReader(new InputStreamReader(System.in));
        out = new PrintWriter(System.out);
        solve();
        out.close();
    }

    static String next() {
        while (buffer == null || !buffer.hasMoreElements()) {
            try {
                buffer = new StringTokenizer(in.readLine());
            } catch (IOException e) {
            }
        }
        return buffer.nextToken();
    }

    static int ni() {
        return Integer.parseInt(next());
    }

    static long nl() {
        return Long.parseLong(next());
    }

    static double nd() {
        return Double.parseDouble(next());
    }

    static String ns() {
        return next();
    }

    static int[] ni(int n) {
        int[] res = new int[n];
        for (int i = 0; i < n; i++)
            res[i] = Integer.parseInt(next());
        return res;
    }

    static long[] nl(int n) {
        long[] res = new long[n];
        for (int i = 0; i < n; i++)
            res[i] = Long.parseLong(next());
        return res;
    }

    static double[] nd(int n) {
        double[] res = new double[n];
        for (int i = 0; i < n; i++)
            res[i] = Double.parseDouble(next());
        return res;
    }

    static String[] ns(int n) {
        String[] res = new String[n];
        for (int i = 0; i < n; i++)
            res[i] = next();
        return res;
    }

}