Problem: Hearing that energy drinks increase rating in those sites, Takahashi decides to buy up M cans of energy drinks.

There are N stores that sell energy drinks. In the i-th store, he can buy at most B_i cans of energy drinks for A_i yen (the currency of Japan) each.

What is the minimum amount of money with which he can buy M cans of energy drinks?

It is guaranteed that, in the given inputs, a sufficient amount of money can always buy M cans of energy drinks.

Constraints

* All values in input are integers.
* 1 \leq N, M \leq 10^5
* 1 \leq A_i \leq 10^9
* 1 \leq B_i \leq 10^5
* B_1 + ... + B_N \geq M

Input

Input is given from Standard Input in the following format:


N M
A_1 B_1
A_2 B_2
\vdots
A_N B_N


Output

Print the minimum amount of money with which Takahashi can buy M cans of energy drinks.

Examples

Input

2 5
4 9
2 4


Output

12


Input

4 30
6 18
2 5
3 10
7 9


Output

130


Input

1 100000
1000000000 100000


Output

100000000000000

Solution (in JAVA):

Solution:
import java.util.*;

public class Main {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);

        int n = sc.nextInt();
        int m = sc.nextInt();
        long[][] a = new long[n][2];
        int number = 0;
        long ans = 0;
        for(int i =0; i < n; i++){
            a[i][0] = sc.nextLong();
            a[i][1] = sc.nextLong();
        }
        //ここまで値を格納するフェーズ
        //値段の安い順を考慮して並べ替えるが、値段が重複してる部分を消さないようにする
        Arrays.sort(a,(x,y)->Long.compare(x[0], y[0]));
        //安い店から買っていく処理        
        for(int i = 0; i < n; i++){
            if(number + a[i][1] < m){
                ans += a[i][0] * a[i][1];
			    number += a[i][1];
            }else{
                ans += a[i][0] * (m - number);
				break;
            }
        }
        System.out.println(ans);
    }
}