Problem: Berland Government decided to improve relations with neighboring countries. First of all, it was decided to build new roads so that from each city of Berland and neighboring countries it became possible to reach all the others. There are n cities in Berland and neighboring countries in total and exactly n - 1 two-way roads. Because of the recent financial crisis, the Berland Government is strongly pressed for money, so to build a new road it has to close some of the existing ones. Every day it is possible to close one existing road and immediately build a new one. Your task is to determine how many days would be needed to rebuild roads so that from each city it became possible to reach all the others, and to draw a plan of closure of old roads and building of new ones.

Input

The first line contains integer n (2 ≤ n ≤ 1000) — amount of cities in Berland and neighboring countries. Next n - 1 lines contain the description of roads. Each road is described by two space-separated integers ai, bi (1 ≤ ai, bi ≤ n, ai ≠ bi) — pair of cities, which the road connects. It can't be more than one road between a pair of cities. No road connects the city with itself.

Output

Output the answer, number t — what is the least amount of days needed to rebuild roads so that from each city it became possible to reach all the others. Then output t lines — the plan of closure of old roads and building of new ones. Each line should describe one day in the format i j u v — it means that road between cities i and j became closed and a new road between cities u and v is built. Cities are numbered from 1. If the answer is not unique, output any.

Examples

Input

2
1 2


Output

0


Input

7
1 2
2 3
3 1
4 5
5 6
6 7


Output

1
3 1 3 7

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.util.ArrayList;
import java.util.StringTokenizer;


public class RoadsNotOnlyinBerland {
	static JP in = new JP(System.in);
	static int N,E,u,v;
	static ArrayList<ii> rem = new ArrayList();
	static ArrayList<ii> ans = new ArrayList();
	static PrintWriter out = new PrintWriter(System.out);
	public static void main(String[]args) throws Throwable{
		N =  in.j();
		DSU1 dsu = new DSU1(N);
		E = N-1;
		for(int i=0;i<E;i++){
			u = in.j(); v = in.j();
			u--;
			v--;
			if(!dsu.isSameSet(u,v)) dsu.union(u, v);
			else rem.add(new ii(u,v));

		}
		int days = rem.size();
		for(int i=0;i<N;i++){
			for(int j=0;j<N;j++){
				if(!dsu.isSameSet(i,j)){
					dsu.union(i,j);
					ans.add(new ii(i,j));
				}
			}
		}
		out.printf("%d\n",days);
		//System.err.println(days+" "+ans.size());
		for(int i=0;i<days;i++){
			int f1 = (rem.get(i).fst+1);
			int t1 = (rem.get(i).snd+1);
			int f2 = (ans.get(i).fst+1);
			int t2 = (ans.get(i).snd+1);

			out.printf("%d %d %d %d\n",f1,t1,f2,t2); 
		}
		out.flush();

	}
}

class ii{
	int fst;
	int snd;
	public ii(int fst,int snd){
		this.fst = fst;
		this.snd=snd;
	}
}


class JP {
	public BufferedReader reader;
	public StringTokenizer tokenizer;

	public JP(InputStream stream) {
		reader = new BufferedReader(new InputStreamReader(stream), 32768);
		tokenizer = null;
	}

	public String next() {
		while (tokenizer == null || !tokenizer.hasMoreTokens()) {
			try {
				tokenizer = new StringTokenizer(reader.readLine());
			} catch (IOException e) {
				throw new RuntimeException(e);
			}
		}
		return tokenizer.nextToken();
	}

	public int j() {
		return Integer.parseInt(next());
	}


}
class DSU1 {
	int rank[];
	int parent[];
	int N;
	int sets;
	int setsize[];

	public DSU1(int N){
		this.N = N;
		sets = N;
		parent = new int[N];
		rank = new int[N];
		setsize = new int[N];
		for(int i=0;i<N;i++){ parent[i] = i; setsize[i] = 1; }

	}

	public void union(int x,int y){
		if(isSameSet(x,y)) return;
		sets--;
		int xp = getParent(x);
		int yp = getParent(y);
		if(rank[xp]>rank[yp]){ parent[yp] = xp; setsize[xp]+=setsize[yp];}
		else{
			if(rank[xp]==rank[yp]){
				rank[yp]++;
				parent[xp] = yp;
				setsize[yp]+=setsize[xp];
			}
			else
			{ parent[xp] =yp; setsize[yp] += setsize[xp]; }
		}

	}

	public int getParent(int x){
		if(x==parent[x]) return x;
		return parent[x] = getParent(parent[x]);
	}

	public boolean isSameSet(int x,int y){
		return getParent(x)==getParent(y);
	}

	public int numDisjointSets(){
		return sets;
	}
	public int getSetSize(int x){
		return setsize[getParent(x)];
	}



}