Problem: <image>


At the request of a friend who started learning abacus, you decided to create a program to display the abacus beads. Create a program that takes a certain number as input and outputs a row of abacus beads. However, the number of digits of the abacus to be displayed is 5 digits, and the arrangement of beads from 0 to 9 is as follows using'*' (half-width asterisk),''(half-width blank), and'=' (half-width equal). It shall be expressed as.

<image>



Input

Multiple test cases are given. Up to 5 digits (integer) are given on one line for each test case.

The number of test cases does not exceed 1024.

Output

Output the abacus bead arrangement for each test case. Insert a blank line between the test cases.

Example

Input

2006
1111


Output

****
    *
=====
 *  *
****
* ***
*****
*****

*****

=====
 ****
*
*****
*****
*****

Solution (in CPP):

Solution:
#define _USE_MATH_DEFINES
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <cmath>
#include <climits>
#include <cfloat>
#include <ctime>
#include <cassert>
#include <map>
#include <utility>
#include <set>
#include <iostream>
#include <memory>
#include <string>
#include <vector>
#include <algorithm>
#include <functional>
#include <sstream>
#include <complex>
#include <stack>
#include <queue>
#include <numeric>
#include <list>
#include <iomanip>


#ifdef _DEBUG
#define typeof(X) std::identity<decltype(X)>::type //C++0x (for vs2010)
#else
#define typeof(X) __typeof__(X) // for gcc
#endif

#define sz(a)  int((a).size())
#define FOREACH(it, c) for (typeof((c).begin()) it=(c).begin(); it != (c).end(); ++it)
#define FOR(i,count) for (int i = 0; i < (int)(count); i++)

template <class T> void max_swap(T& a, const T& b) { a = max(a, b); }
template <class T> void min_swap(T& a, const T& b) { a = min(a, b); }

using namespace std;
static const double EPS = 1e-5;
typedef long long ll;
const int MODULO = 100000 ;
const int INF = 100000000; //1e8

typedef long long ll;
typedef pair<int,int> Pii;
typedef pair<ll,ll> Pll;
typedef complex<double> Cd;

using namespace std;


int main()
{
	int n;
	bool nw = false;
	while(cin>>n){
		if(nw) puts("");
		nw = true;
		int a[5];
		for(int i = 10000,j = 0; j < 5; i /= 10,j++) a[j] = (n / i) % 10;
		char c[6];
		FOR(j,5) c[j] = a[j]/5 ? ' ':'*';
		c[5] = '\0';
		puts(c);
		FOR(j,5) c[j] = a[j]/5 ? '*':' ';
		puts(c);
		puts("=====");
		FOR(i,5){
			FOR(j,5){
				putchar(a[j]%5 == i ? ' ':'*');
			}
			puts("");
		}
	}
	return 0;
}