Problem: On a chessboard with a width of n and a height of n, rows are numbered from bottom to top from 1 to n, columns are numbered from left to right from 1 to n. Therefore, for each cell of the chessboard, you can assign the coordinates (r,c), where r is the number of the row, and c is the number of the column.

The white king has been sitting in a cell with (1,1) coordinates for a thousand years, while the black king has been sitting in a cell with (n,n) coordinates. They would have sat like that further, but suddenly a beautiful coin fell on the cell with coordinates (x,y)...

Each of the monarchs wanted to get it, so they decided to arrange a race according to slightly changed chess rules:

As in chess, the white king makes the first move, the black king makes the second one, the white king makes the third one, and so on. However, in this problem, kings can stand in adjacent cells or even in the same cell at the same time.

The player who reaches the coin first will win, that is to say, the player who reaches the cell with the coordinates (x,y) first will win.

Let's recall that the king is such a chess piece that can move one cell in all directions, that is, if the king is in the (a,b) cell, then in one move he can move from (a,b) to the cells (a + 1,b), (a - 1,b), (a,b + 1), (a,b - 1), (a + 1,b - 1), (a + 1,b + 1), (a - 1,b - 1), or (a - 1,b + 1). Going outside of the field is prohibited.

Determine the color of the king, who will reach the cell with the coordinates (x,y) first, if the white king moves first.

Input

The first line contains a single integer n (2 ≤ n ≤ 10^{18}) — the length of the side of the chess field.

The second line contains two integers x and y (1 ≤ x,y ≤ n) — coordinates of the cell, where the coin fell.

Output

In a single line print the answer "White" (without quotes), if the white king will win, or "Black" (without quotes), if the black king will win.

You can print each letter in any case (upper or lower).

Examples

Input

4
2 3


Output

White

Input

5
3 5


Output

Black

Input

2
2 2


Output

Black

Note

An example of the race from the first sample where both the white king and the black king move optimally:

  1. The white king moves from the cell (1,1) into the cell (2,2).
  2. The black king moves form the cell (4,4) into the cell (3,3).
  3. The white king moves from the cell (2,2) into the cell (2,3). This is cell containing the coin, so the white king wins.

<image>

An example of the race from the second sample where both the white king and the black king move optimally:

  1. The white king moves from the cell (1,1) into the cell (2,2).
  2. The black king moves form the cell (5,5) into the cell (4,4).
  3. The white king moves from the cell (2,2) into the cell (3,3).
  4. The black king moves from the cell (4,4) into the cell (3,5). This is the cell, where the coin fell, so the black king wins.

<image>

In the third example, the coin fell in the starting cell of the black king, so the black king immediately wins.

<image>

Solution (in JAVA):

Solution:
//Author: Mo Abjal, MJP Rohilkhand University Bareilly, UP, India 2018.
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/////////////////////////////////////////*     S0LUT10N     *//////////////////////////////////////////////
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import java.util.*;
import java.io.*;
import java.text.*;
import java.math.*;
public class Main{
	public static StringTokenizer token = new StringTokenizer("");
	public static BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
	public static PrintWriter output = new PrintWriter(System.out);
	public static void main(String[] afzal) throws Exception {		
		long N = nl();
		long X = nl();
		long Y = nl();
		long a = X-1 + Y-1;
		long b = N-X + N-Y;
		if(a<=b) output.println("White"); else output.println("Black"); output.close();
	}
	public static long gcd(long a,long b){
		if(b==0) return a;
		else return gcd(b,a%b);
	}
	public static String pc(char c){
		return Character.toString(c);
	} 
	public static Integer pci(char c){
		return pi(Character.toString(c));
	}
	public static Integer pi(String str){
		return Integer.parseInt(str);
	}
	public static Long pl(String str){
		return Long.parseLong(str);
	}
	public static String ps(Integer N){
		return Integer.toString(N);
	}
	public static char[] pcc(String str){
		return str.toCharArray();
	}
	public static Integer ni() throws IOException{
		if(!token.hasMoreElements()){
			token = new StringTokenizer(br.readLine());
		}
		return Integer.parseInt(token.nextToken());
	}
	public static Long nl() throws IOException{
		if(!token.hasMoreElements()){
			token = new StringTokenizer(br.readLine());
		}
		return Long.parseLong(token.nextToken());
	}
	public static Double nd() throws IOException{
		if(!token.hasMoreElements()){
			token = new StringTokenizer(br.readLine());
		}
		return Double.parseDouble(token.nextToken());
	}
	public static String ns() throws IOException{
		if(!token.hasMoreElements()){
			token = new StringTokenizer(br.readLine());
		}
		return token.nextToken();
	}
	public static Integer[] ai(int N) throws IOException{
		Integer A[] = new Integer[N];
		token = new StringTokenizer(br.readLine());
		for(int i=0;i<A.length;i++){
			A[i] = pi(token.nextToken());
		}
		return A;
	}
	public static long[] al(int N) throws IOException{
		long A[] = new long[N];
		token = new StringTokenizer(br.readLine());
		for(int i=0;i<N;i++){
			A[i] = Long.parseLong(token.nextToken());
		}
		return A;
	}
	public static char[][] acc(int N,int M) throws IOException{
		char C[][] = new char[N][M];
		for(int i=0;i<N;i++){
			token = new StringTokenizer(br.readLine());
			String s = token.nextToken();
			for(int j=0;j<M;j++){
				C[i][j] = s.charAt(j);
			}
		}
		return C;
	}
	public static String[] as(int N) throws IOException{
		String S[] = new String[N];
		token = new StringTokenizer(br.readLine());
		for(int i=0;i<S.length;i++){
			S[i] = token.nextToken();
		}
		return S;
	}
	public static double ncr(int n, int r){
		if(n==r) return 1;
		else
		return (fact(n)/(fact(r)*fact(n-r)));
	}
	public static long fact(long N){
		long fact = 1;
		for(int i=1;i<=N;i++){
			fact = fact * i;
		}
		return fact;
	}
	public static BigInteger factB(int N){
		BigInteger b = new BigInteger("1");
		for(int i=1;i<=N;i++){
			b = b.multiply(BigInteger.valueOf(i));
		}
		return b;
	}
	public static long sod(long N){
		long sum = 0;
		while(N>0){
			long x = N%10;
			sum = sum + x;
			N = N/10;
		}
		return sum;
	}
	public static Integer cd(long N){
		int count=0;
		while(N>0){
			N = N/10; count++;
		}
		return count=0;
	}
}
class Pair implements Comparable{
	int a,b;
	public Pair(int a,int b){
		this.a = a;
		this.b = b;
	}
	public int compareTo(Object p){
		Pair pa = (Pair)p;
		//if(this.a==pa.a) return this.b - pa.b;
		return this.a - pa.a;
	} 
}class Pair3 implements Comparable{
	int a,b,c;
	public Pair3(int a,int b,int c){
		this.a = a;
		this.b = b;
		this.c = c;
	}
	public int compareTo(Object p){
		Pair pa = (Pair)p;
		//if(this.a==pa.a) return this.b - pa.b;
		return this.a - pa.a;
	} 
}
//Copyright Reserved - Mo Abjal.