Problem: Hearing that energy drinks increase rating in those sites, Takahashi decides to buy up M cans of energy drinks.

There are N stores that sell energy drinks. In the i-th store, he can buy at most B_i cans of energy drinks for A_i yen (the currency of Japan) each.

What is the minimum amount of money with which he can buy M cans of energy drinks?

It is guaranteed that, in the given inputs, a sufficient amount of money can always buy M cans of energy drinks.

Constraints

* All values in input are integers.
* 1 \leq N, M \leq 10^5
* 1 \leq A_i \leq 10^9
* 1 \leq B_i \leq 10^5
* B_1 + ... + B_N \geq M

Input

Input is given from Standard Input in the following format:


N M
A_1 B_1
A_2 B_2
\vdots
A_N B_N


Output

Print the minimum amount of money with which Takahashi can buy M cans of energy drinks.

Examples

Input

2 5
4 9
2 4


Output

12


Input

4 30
6 18
2 5
3 10
7 9


Output

130


Input

1 100000
1000000000 100000


Output

100000000000000

Solution (in CPP):

Solution:
#include<bits/stdc++.h>
using namespace std;
using ll = long long;
const int MOD = 1e9+7;

int main(){
	
	int n,m; cin>>n>>m;
	priority_queue<pair<ll,ll>> q;
	for(int i=0; i<n; i++){
		ll a,b;cin>>a>>b;
		q.push({-a,b});
	}
	ll sum{},now{};
	while(1){
		auto p = q.top();
		q.pop();
		if(p.second>=m-now){
			sum += -p.first*(m-now);
			break;
		}
		else{
			now += p.second;
			sum += -p.first*p.second;
		}
	}
	
	cout << sum<<endl;
	
}