Problem: For given a sequence $A = \\{a_0, a_1, ..., a_{n-1}\\}$, print the previous permutation and the next permutation in lexicographic order.

Constraints

* $1 \leq n \leq 9$
* $a_i$ consist of $1, 2, ..., n$

Input

A sequence is given in the following format.


$n$
$a_0 \; a_1 \; ... \; a_{n-1}$


Output

Print the previous permutation, the given sequence and the next permutation in the 1st, 2nd and 3rd lines respectively. Separate adjacency elements by a space character. Note that if there is no permutation, print nothing in the corresponding line.

Examples

Input

3
2 1 3


Output

1 3 2
2 1 3
2 3 1


Input

3
3 2 1


Output

3 1 2
3 2 1

Solution (in PYTHON3):

Solution:
import itertools
n=int(input())
a=[int(i) for i in input().split(" ")]

perms=list(itertools.permutations([i+1 for i in range(n)]))
for i,p in enumerate(perms):
    if list(p)==a:
        break

if i>0:
    print(" ".join([str(j) for j in perms[i-1]]))
print(" ".join([str(j) for j in perms[i]]))
try:
    print(" ".join([str(j) for j in perms[i+1]]))
except IndexError:
    pass