Problem: Valera is a coder. Recently he wrote a funny program. The pseudo code for this program is given below:
    
    
      
    //input: integers x, k, p  
    a = x;  
    for(step = 1; step <= k; step = step + 1){  
        rnd = [random integer from 1 to 100];  
        if(rnd <= p)  
            a = a * 2;  
        else  
            a = a + 1;  
    }  
      
    s = 0;  
      
    while(remainder after dividing a by 2 equals 0){  
        a = a / 2;  
        s = s + 1;  
    }  
      
    

Now Valera wonders: given the values x, k and p, what is the expected value of the resulting number s?

Input

The first line of the input contains three integers x, k, p (1 ≤ x ≤ 109; 1 ≤ k ≤ 200; 0 ≤ p ≤ 100).

Output

Print the required expected value. Your answer will be considered correct if the absolute or relative error doesn't exceed 10 - 6.

Examples

Input

1 1 50


Output

1.0000000000000


Input

5 3 0


Output

3.0000000000000


Input

5 3 25


Output

1.9218750000000

Note

If the concept of expected value is new to you, you can read about it by the link: 

http://en.wikipedia.org/wiki/Expected_value

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int x, k, p;
double dp[210][2100];
void init() {
  memset(dp, 0, sizeof(dp));
  for (int i = 0; i <= k; i++) {
    int T = x + i;
    while (T) {
      if (T & 1) break;
      dp[0][i]++;
      T /= 2;
    }
  }
}
int main() {
  while (~scanf("%d%d%d", &x, &k, &p)) {
    double winp = p * 1.0 / 100;
    double sp = 1 - winp;
    init();
    for (int i = 0; i <= k; i++) {
      for (int j = 2000; j >= 0; j--) {
        dp[i + 1][j] += dp[i][j + 1] * sp;
        if (2 * j <= k) dp[i + 1][j * 2] += (dp[i][j] + 1) * winp;
      }
    }
    printf("%.7lf\n", dp[k][0]);
  }
}