Problem: You are given a sequence a1, a2, ..., an consisting of different integers. It is required to split this sequence into the maximum number of subsequences such that after sorting integers in each of them in increasing order, the total sequence also will be sorted in increasing order.

Sorting integers in a subsequence is a process such that the numbers included in a subsequence are ordered in increasing order, and the numbers which are not included in a subsequence don't change their places.

Every element of the sequence must appear in exactly one subsequence.

Input

The first line of input data contains integer n (1 ≤ n ≤ 105) — the length of the sequence.

The second line of input data contains n different integers a1, a2, ..., an ( - 109 ≤ ai ≤ 109) — the elements of the sequence. It is guaranteed that all elements of the sequence are distinct.

Output

In the first line print the maximum number of subsequences k, which the original sequence can be split into while fulfilling the requirements.

In the next k lines print the description of subsequences in the following format: the number of elements in subsequence ci (0 < ci ≤ n), then ci integers l1, l2, ..., lci (1 ≤ lj ≤ n) — indices of these elements in the original sequence. 

Indices could be printed in any order. Every index from 1 to n must appear in output exactly once.

If there are several possible answers, print any of them.

Examples

Input

6
3 2 1 6 5 4


Output

4
2 1 3
1 2
2 4 6
1 5


Input

6
83 -75 -49 11 37 62


Output

1
6 1 2 3 4 5 6

Note

In the first sample output:

After sorting the first subsequence we will get sequence 1 2 3 6 5 4.

Sorting the second subsequence changes nothing.

After sorting the third subsequence we will get sequence 1 2 3 4 5 6.

Sorting the last subsequence changes nothing.

Solution (in JAVA):

Solution:
/**
 * All cobbled together from old pieces of code.  Took way too long.
 * If it's even correct.
 */
import java.io.*;
import java.util.*;
import java.util.stream.*;

public class Subsequences {
    public static void main(String [] av) {
        Scanner s = new Scanner();
        int n = s.nextInt();
        List<Integer> up = new ArrayList<>();
        for (int i = 0; i < n; i++)
            up.add(s.nextInt());

        Compressor<Integer> comp = new Compressor<Integer>(new ArrayList<>(up));
        //System.err.println("uncompressed: " + up);
        int [] p = new int[n];
        for (int i = 0; i < n; i++) {
            p[i] = comp.compress(up.get(i));
        }
        //System.err.println("compressed: " + Arrays.toString(p));

        List<List<Integer>> C = findCycles (p);
        StringBuffer out = new StringBuffer();
        //System.err.println("cycles: " + C);
        System.out.println(C.size());
        String sep = "";
        for (List<Integer> c : C) {
            out.append(sep);
            sep = "\n";
            out.append(c.size());
            out.append(" ");
            out.append(c.stream().map(i -> Integer.valueOf(i+1).toString()).collect(Collectors.joining(" ")));
        }
        System.out.println(out.toString());
    }

    static List<List<Integer>> findCycles (int [] p) {
        // System.out.println(Arrays.toString(p));
        List<List<Integer>> cycles = new ArrayList<>();

        boolean [] found = new boolean[p.length];
        for (int e = 0; e < p.length; e++) {
            if (found[e])
                continue;

            int start = e;
            found[start] = true;
            int j = start;
            ArrayList<Integer> cycle = new ArrayList<>();
            cycle.add(start);
            while (p[j] != start) {
                j = p[j];
                cycle.add(j);
                found[j] = true;
            }
            cycles.add(cycle);
        }
        return cycles;
    }

    /**
     * Illustration of on-the-fly compression, often used
     * to compress coordinates.   O(n log n).
     */
    static class Compressor<T extends Comparable<T>> {
        List<T> real;           // real (coordinate) values
        Compressor(List<T> real) {
            Collections.sort(this.real = real); }

        // compression, usually called once per realval
        int compress(T realval) { 
            return Collections.binarySearch(real, realval); }

        // access original value
        T uncompress(int compval) { return real.get(compval); }
    }

    //-----------Scanner class for faster input----------
    /* Provides similar API as java.util.Scanner but does not
     * use regular expression engine.  
     */
    public static class Scanner {
        BufferedReader br;
        StringTokenizer st;

        public Scanner(Reader in) {
            br = new BufferedReader(in);
        }

        public Scanner() { this(new InputStreamReader(System.in)); }

        String next() {
            while (st == null || !st.hasMoreElements()) {
                try {
                    st = new StringTokenizer(br.readLine());
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
            return st.nextToken();
        }

        int nextInt() { return Integer.parseInt(next()); }
        long nextLong() { return Long.parseLong(next()); }
        double nextDouble() { return Double.parseDouble(next()); }

        // Slightly different from java.util.Scanner.nextLine(),
        // which returns any remaining characters in current line,
        // if any.  
        String readNextLine() {
            String str = "";
            try {
                str = br.readLine();
            } catch (IOException e) {
                e.printStackTrace();
            }
            return str;
        }
    }
    //--------------------------------------------------------    
}