Problem: <image>


At the request of a friend who started learning abacus, you decided to create a program to display the abacus beads. Create a program that takes a certain number as input and outputs a row of abacus beads. However, the number of digits of the abacus to be displayed is 5 digits, and the arrangement of beads from 0 to 9 is as follows using'*' (half-width asterisk),''(half-width blank), and'=' (half-width equal). It shall be expressed as.

<image>



Input

Multiple test cases are given. Up to 5 digits (integer) are given on one line for each test case.

The number of test cases does not exceed 1024.

Output

Output the abacus bead arrangement for each test case. Insert a blank line between the test cases.

Example

Input

2006
1111


Output

****
    *
=====
 *  *
****
* ***
*****
*****

*****

=====
 ****
*
*****
*****
*****

Solution (in CPP):

Solution:
#include <vector>
#include <list>
#include <map>
#include <set>
#include <unordered_set>
#include <unordered_map>
#include <deque>
#include <stack>
#include <bitset>
#include <algorithm>
#include <functional>
#include <numeric>
#include <utility>
#include <sstream>
#include <queue>
#include <iostream>
#include <iomanip>
#include <cstdio>
#include <cmath>
#include <cstdlib>
#include <cctype>
#include <string>
#include <cstring>
#include <ctime>
#include <fstream>
#include <cstdio>
#include <climits>
#include <complex>
#include <cstdint>
#include <tuple>

#define M_PI       3.14159265358979323846

using namespace std;

//conversion
//------------------------------------------
inline int toInt(string s) { int v; istringstream sin(s); sin >> v; return v; }
template<class T> inline string toString(T x) { ostringstream sout; sout << x; return sout.str(); }
inline int readInt() { int x; scanf("%d", &x); return x; }

//typedef
//------------------------------------------
typedef vector<int> VI;
typedef vector<VI> VVI;
typedef vector<string> VS;
typedef pair<int, int> PII;
typedef pair<int, PII> TIII;
typedef long long LL;
typedef unsigned long long ULL;
typedef vector<LL> VLL;
typedef vector<VLL> VVLL;

//container util

//------------------------------------------
#define ALL(a)  (a).begin(),(a).end()
#define RALL(a) (a).rbegin(), (a).rend()
#define PB push_back
#define MP make_pair
#define SZ(a) int((a).size())
#define SQ(a) ((a)*(a))
#define EACH(i,c) for(typeof((c).begin()) i=(c).begin(); i!=(c).end(); ++i)
#define EXIST(s,e) ((s).find(e)!=(s).end())
#define SORT(c) sort((c).begin(),(c).end())

//repetition
//------------------------------------------
#define FOR(i,s,n) for(int i=s;i<(int)n;++i)
#define REP(i,n) FOR(i,0,n)
#define MOD 1000000007

#define rep(i, a, b) for(int i = a; i < (b); ++i)
#define trav(a, x) for(auto& a : x)
#define all(x) x.begin(), x.end()
#define sz(x) (int)(x).size()
struct Edge {
    int to, cost;
    Edge(int to, int cost): to(to), cost(cost) {}
};

typedef long long ll;
typedef pair<int, int> pii;
typedef vector<int> vi;
typedef vector<vector<Edge>> AdjList;
AdjList graph;

const int INF = 100000000;

int main() {
    //cout << fixed << setprecision(15);

    vector<string> v;
    v.push_back("* = ****");
    v.push_back("* =* ***");
    v.push_back("* =** **");
    v.push_back("* =*** *");
    v.push_back("* =**** ");
    v.push_back(" *= ****");
    v.push_back(" *=* ***");
    v.push_back(" *=** **");
    v.push_back(" *=*** *");
    v.push_back(" *=**** ");
    
    string n;
    int cnt=0;
    while(cin >> n){
        if(cnt) cout << endl;
        cnt++;
        while(n.size()!=5){
            n = '0' + n;
        }
        if(n.size()==5){
            for(int i=0; i<8; ++i){
                string t = "";
                for(int j=0; j<n.size(); ++j){
                    int num = n[j]-'0';
                    t += v[num][i];
                    
                }
                cout << t << endl;
            }
        }
    }
    return 0;
}