Problem: Hearing that energy drinks increase rating in those sites, Takahashi decides to buy up M cans of energy drinks.

There are N stores that sell energy drinks. In the i-th store, he can buy at most B_i cans of energy drinks for A_i yen (the currency of Japan) each.

What is the minimum amount of money with which he can buy M cans of energy drinks?

It is guaranteed that, in the given inputs, a sufficient amount of money can always buy M cans of energy drinks.

Constraints

* All values in input are integers.
* 1 \leq N, M \leq 10^5
* 1 \leq A_i \leq 10^9
* 1 \leq B_i \leq 10^5
* B_1 + ... + B_N \geq M

Input

Input is given from Standard Input in the following format:


N M
A_1 B_1
A_2 B_2
\vdots
A_N B_N


Output

Print the minimum amount of money with which Takahashi can buy M cans of energy drinks.

Examples

Input

2 5
4 9
2 4


Output

12


Input

4 30
6 18
2 5
3 10
7 9


Output

130


Input

1 100000
1000000000 100000


Output

100000000000000

Solution (in JAVA):

Solution:
import java.util.*;

public class Main {
    public static void main(String[] args) throws Exception {
        
        Scanner sc = new Scanner(System.in);
        
        int N = sc.nextInt();
        int M = sc.nextInt();
        
        // 値段、個数
        Map<Integer, Integer> map = new TreeMap<>();
        
        for(int i = 0; i < N; i ++){
            int A = sc.nextInt();
            int B = sc.nextInt();
            
            Integer BB = map.get(A);
            if ( BB == null ){
                map.put(A, B);
            } else {
                map.put(A, BB + B);
            }
        }
        
        long ans = 0;
        for(int nedan : map.keySet()){
            int kosuu = map.get(nedan);
            if( kosuu < M ){
                ans += (long)nedan * kosuu;
                M -= kosuu;
            } else {
                ans += (long)nedan * M;
                break;
            }
        }
        
        System.out.println(ans);

    }
}