Problem: You are given a tree consisting of n vertices. A tree is a connected undirected graph with n-1 edges. Each vertex v of this tree has a color assigned to it (a_v = 1 if the vertex v is white and 0 if the vertex v is black).

You have to solve the following problem for each vertex v: what is the maximum difference between the number of white and the number of black vertices you can obtain if you choose some subtree of the given tree that contains the vertex v? The subtree of the tree is the connected subgraph of the given tree. More formally, if you choose the subtree that contains cnt_w white vertices and cnt_b black vertices, you have to maximize cnt_w - cnt_b.

Input

The first line of the input contains one integer n (2 ≤ n ≤ 2 ⋅ 10^5) — the number of vertices in the tree.

The second line of the input contains n integers a_1, a_2, ..., a_n (0 ≤ a_i ≤ 1), where a_i is the color of the i-th vertex.

Each of the next n-1 lines describes an edge of the tree. Edge i is denoted by two integers u_i and v_i, the labels of vertices it connects (1 ≤ u_i, v_i ≤ n, u_i ≠ v_i).

It is guaranteed that the given edges form a tree.

Output

Print n integers res_1, res_2, ..., res_n, where res_i is the maximum possible difference between the number of white and black vertices in some subtree that contains the vertex i.

Examples

Input


9
0 1 1 1 0 0 0 0 1
1 2
1 3
3 4
3 5
2 6
4 7
6 8
5 9


Output


2 2 2 2 2 1 1 0 2 


Input


4
0 0 1 0
1 2
1 3
1 4


Output


0 -1 1 -1 

Note

The first example is shown below:

<image>

The black vertices have bold borders.

In the second example, the best subtree for vertices 2, 3 and 4 are vertices 2, 3 and 4 correspondingly. And the best subtree for the vertex 1 is the subtree consisting of vertices 1 and 3.

Solution (in JAVA):

Solution:
import java.io.BufferedInputStream;
import java.io.InputStream;
import java.io.PrintWriter;
import java.util.ArrayList;

@SuppressWarnings("unchecked")
public class F1092 {
	
	int n;
	long[] vals;
	long[] size;
	ArrayList<Integer>[] vs;
	
	long dfs(int node, int par) {
		long ans = vals[node];
		for(int v : vs[node]) if(v != par) {
			ans += dfs(v, node);
		}
		return size[node] = ans;
	}
	
	long go1(int node, int par, int dist) {
		long ans = dist * vals[node];
		for(int v : vs[node]) if(v != par) {
			ans += go1(v, node, dist + 1);
		}
		return ans;
	}
	
	long go(int node, int par, long curAns) {
		long ans = curAns;
		for(int v : vs[node]) if(v != par) {
			long nsize = size[v];
			long osize = size[0] - nsize;
			long nans = curAns + osize - nsize;
			ans = Math.max(ans, go(v, node, nans));
		}
		return ans;
	}
	
	public void solve(JoltyScanner in, PrintWriter out) {
		n = in.nextInt();
		vs = new ArrayList[n];
		vals = new long[n];
		size = new long[n];
		for(int i = 0; i < n; ++i) {
			vs[i] = new ArrayList<>();
			vals[i] = in.nextLong();
		}
		for(int i = 0; i < n - 1; ++i) {
			int u = in.nextInt() - 1, v = in.nextInt() - 1;
			vs[u].add(v);
			vs[v].add(u);
		}
		dfs(0, -1);
		long start = go1(0, -1, 0);
		long best = go(0, -1, start);
		out.println(best);
	}

	public static void main(String[] args) {
		JoltyScanner in = new JoltyScanner(System.in);
		PrintWriter out = new PrintWriter(System.out);
		new F1092().solve(in, out);
		out.close();
	}
	
	static class JoltyScanner 
	{
		public static final int BUFFER_SIZE = 1 << 16;
		public static final char NULL_CHAR = (char) -1;
		byte[] buffer = new byte[BUFFER_SIZE];
		boolean EOF_FLAG = false;
		int bufferIdx = 0, size = 0;
		char c = NULL_CHAR;
		BufferedInputStream in;
		public JoltyScanner(InputStream in) 
		{
			this.in = new BufferedInputStream(in, BUFFER_SIZE);
		}
		public int nextInt() 
		{
			long x = nextLong();
			if (x > Integer.MAX_VALUE || x < Integer.MIN_VALUE) 
			{
				throw new ArithmeticException("Scanned value overflows integer");
			}
			return (int) x;
		}
		public long nextLong() 
		{
			boolean negative = false;
			if (c == NULL_CHAR) 
			{
				c = nextChar();
			}
			for (; !EOF_FLAG && (c < '0' || c > '9'); c = nextChar()) 
			{
				if (c == '-') 
				{
					negative = true;
				}				
			}
			checkEOF();
			long res = 0;
			for (; c >= '0' && c <= '9'; c = nextChar()) 
			{
				res = (res << 3) + (res << 1) + c - '0';
			}
			return negative ? -res : res;
		}
		public char nextChar() 
		{
			if (EOF_FLAG) 
			{
				return NULL_CHAR;
			}
			while (bufferIdx == size) 
			{
				try 
				{
					size = in.read(buffer);
					if (size == -1) 
					{
						throw new Exception();
					}
				} 
				catch (Exception e) 
				{
					EOF_FLAG = true;
					return NULL_CHAR;
				}
				if (size == -1) 
				{
					size = BUFFER_SIZE;
				}
				bufferIdx = 0;
			}
			return (char) buffer[bufferIdx++];
		}
		public void checkEOF() 
		{
			if (EOF_FLAG) 
			{
				throw new EndOfFileException();
			}
		}
		public class EndOfFileException extends RuntimeException 
		{

			/**
			 * 
			 */
			private static final long serialVersionUID = 1L;
		}
	}
}