Problem: Create a program that rotates the pattern of 8 characters x 8 lines clockwise by 90 degrees, 180 degrees, and 270 degrees and outputs it.



Input

A pattern consisting of 8 characters x 8 lines is given. Characters consist of alphanumeric characters, half-width pound'#', and asterisk'*'.

Output

Output the rotated pattern in the following format.


90 (fixed half-width numbers)
Pattern rotated 90 degrees
180 (fixed half-width numbers)
180 degree rotated pattern
270 (fixed half-width numbers)
Pattern rotated 270 degrees


Examples

Input

#*******
#*******
#*******
#*******
#*******
#*******
#*******
########


Output

90
########
#*******
#*******
#*******
#*******
#*******
#*******
#*******
180
########
*******#
*******#
*******#
*******#
*******#
*******#
*******#
270
*******#
*******#
*******#
*******#
*******#
*******#
*******#
########


Input

*******
*******
*******
*******
*******
*******
*******


Output

90

*******
*******
*******
*******
*******
*******
*******
180

*******#
*******#
*******#
*******#
*******#
*******#
*******#
270
*******#
*******#
*******#
*******#
*******#
*******#
*******#

Solution (in CPP):

Solution:
#include<iostream>
#include<cstdio>
#include<algorithm>
#include<climits>
#include<string>
#include<vector>
#include<list>
#include<map>
#include<set>
#include<cmath>
#include<queue>
#include<cstring>
#include<stack>
#include<functional>
using namespace std;

void rotate90(char fld[8][8]){
	char fld_c[8][8]; memcpy(fld_c,fld,sizeof(fld_c));
	for(int i=0;i<8;i++){
		for(int j=0;j<8;j++){
			fld[j][7-i] = fld_c[i][j];
		}
	}
}

int main(){
	char fld[8][8];
	for(int i=0;i<8;i++){
		for(int j=0;j<8;j++){
			scanf(" %c",&fld[i][j]);
		}
	}
	for(int i=90;i<=270;i+=90){
		rotate90(fld);
		printf("%d\n",i);
		for(int j=0;j<8;j++){
			for(int k=0;k<8;k++){
				printf("%c",fld[j][k]);
			}puts("");
		}
	}
	return 0;
}