Problem: Create a program that rotates the pattern of 8 characters x 8 lines clockwise by 90 degrees, 180 degrees, and 270 degrees and outputs it.



Input

A pattern consisting of 8 characters x 8 lines is given. Characters consist of alphanumeric characters, half-width pound'#', and asterisk'*'.

Output

Output the rotated pattern in the following format.


90 (fixed half-width numbers)
Pattern rotated 90 degrees
180 (fixed half-width numbers)
180 degree rotated pattern
270 (fixed half-width numbers)
Pattern rotated 270 degrees


Examples

Input

#*******
#*******
#*******
#*******
#*******
#*******
#*******
########


Output

90
########
#*******
#*******
#*******
#*******
#*******
#*******
#*******
180
########
*******#
*******#
*******#
*******#
*******#
*******#
*******#
270
*******#
*******#
*******#
*******#
*******#
*******#
*******#
########


Input

*******
*******
*******
*******
*******
*******
*******


Output

90

*******
*******
*******
*******
*******
*******
*******
180

*******#
*******#
*******#
*******#
*******#
*******#
*******#
270
*******#
*******#
*******#
*******#
*******#
*******#
*******#

Solution (in CPP):

Solution:
#include <stdio.h>
#include <string.h>

int rote(int map[][8])
{
	int tmp[8][8];
	
	
	for (int i = 0; i < 8 ; i++){
		for (int j = 0; j < 8; j++){
			tmp[j][i] = map[j][i];
		}
	}
	
	for (int i = 0; i < 8 ; i++){
		for (int j = 0; j < 8; j++){
			map[j][i] = tmp[i][8 - j - 1];
		}
	}
	
	return (0);
}


int main(void)
{
	int map[8][8];
	char in[9];
	
	for (int y = 0; y < 8; y++){
		scanf("%s", in);
		for (int x = 0; x < 8; x++){
			map[x][y] = in[x];
		}
	}
	
	for (int i = 0; i < 3; i++){
		rote(map);
		printf("%d\n", 90 * (i + 1));
		for (int y = 0; y < 8; y++){
			for (int x = 0; x < 8; x++){
				printf("%c", map[x][y]);
			}
			puts("");
		}
	}
	
	return (0);
}