Problem: Write a program which manipulates a disjoint set S = {S1, S2, . . . , Sk}.

First of all, the program should read an integer n, then make a disjoint set where each element consists of 0, 1, ... n−1 respectively.

Next, the program should read an integer q and manipulate the set for q queries. There are two kinds of queries for different operations:

* unite(x, y): unites sets that contain x and y, say Sx and Sy, into a new set.
* same(x, y): determine whether x and y are in the same set.

Constraints

* 1 ≤ n ≤ 10000
* 1 ≤ q ≤ 100000
* x ≠ y

Input


n q
com1 x1 y1
com2 x2 y2
...
comq xq yq


In the first line, n and q are given. Then, q queries are given where com represents the type of queries. '0' denotes unite and '1' denotes same operation.

Output

For each same operation, print 1 if x and y are in the same set, otherwise 0, in a line.

Example

Input

5 12
0 1 4
0 2 3
1 1 2
1 3 4
1 1 4
1 3 2
0 1 3
1 2 4
1 3 0
0 0 4
1 0 2
1 3 0


Output

0
0
1
1
1
0
1
1

Solution (in PYTHON3):

Solution:
n,q = map(int,input().split())
L = []
for i in range(q):
    L.append(list(map(int,input().split())))
par = []
for i in range(n):
    par.append(i)
rank = [0]*n
def find(x,par):
    if x == par[x]:
        return x
    else:
        return find(par[x],par)
def unite(x,y,par,rank):
    x = find(x,par)
    y = find(y,par)
    if x != y:
        if rank[x] < rank[y]:
            par[x] = y
        else:
            par[y] = x
    else:
        par[y] = x
        if rank[x] == rank[y]:
            rank[x] += 1
for i in range(q):
    if L[i][0] == 0:
        unite(L[i][1],L[i][2],par,rank)
    else:
        if find(L[i][1],par) == find(L[i][2],par):
            print(1)
        else:
            print(0)