Problem: Write a program which manipulates a disjoint set S = {S1, S2, . . . , Sk}.

First of all, the program should read an integer n, then make a disjoint set where each element consists of 0, 1, ... n−1 respectively.

Next, the program should read an integer q and manipulate the set for q queries. There are two kinds of queries for different operations:

* unite(x, y): unites sets that contain x and y, say Sx and Sy, into a new set.
* same(x, y): determine whether x and y are in the same set.

Constraints

* 1 ≤ n ≤ 10000
* 1 ≤ q ≤ 100000
* x ≠ y

Input


n q
com1 x1 y1
com2 x2 y2
...
comq xq yq


In the first line, n and q are given. Then, q queries are given where com represents the type of queries. '0' denotes unite and '1' denotes same operation.

Output

For each same operation, print 1 if x and y are in the same set, otherwise 0, in a line.

Example

Input

5 12
0 1 4
0 2 3
1 1 2
1 3 4
1 1 4
1 3 2
0 1 3
1 2 4
1 3 0
0 0 4
1 0 2
1 3 0


Output

0
0
1
1
1
0
1
1

Solution (in PYTHON3):

Solution:
class UnionFindWithRank(object):
    par = []
    rank = []
    cache = True
    log = []

    def __init__(self, n):
        for i in range(n):
            self.par.append(i)
            self.rank.append(0)

    def root(self, x):
        if self.par[x] == x:
            return x
        else:
            p = self.root(self.par[x])
            self.par[x] = p
            return p

    def same(self, x, y):
        return self.root(x) == self.root(y)

    def unite(self, x, y):
        ox, oy = x, y
        x = self.root(x)
        y = self.root(y)

        if x == y:
            return

        if self.rank[x] < self.rank[y]:
            x, y = y, x
            self.par[y] = x

        else:
            self.par[y] = x
            if self.rank[x] == self.rank[y]:
                self.rank[x] += 1

n, q = map(int, input().split())
u = UnionFindWithRank(n)
for _ in range(q):
    c, a, b= map(int, input().split())
    a, b = a, b
    if c == 0:
        u.unite(a, b)
    else:
        print(1 if u.same(a, b) else 0)