Problem: Example

Input

0 3 1 7 5 9 8 6 4 2
7 0 9 2 1 5 4 8 6 3
4 2 0 6 8 7 1 3 5 9
1 7 5 0 9 8 3 4 2 6
6 1 2 3 0 4 5 9 7 8
3 6 7 4 2 0 9 5 8 1
5 8 6 9 7 2 0 1 3 4
8 9 4 5 3 6 2 0 1 7
9 4 3 8 6 1 7 2 0 5
2 5 8 1 4 3 6 7 9 0


Output

0

Solution (in CPP):

Solution:
#include<bits/stdc++.h>
#define rep(i,n)for(int i=0;i<n;i++)
using namespace std;

int x[10][10];
int main() {
	rep(i, 10)rep(j, 10)scanf("%d", &x[i][j]);
	int cnt = 0;
	rep(a, 10)rep(b, 10)rep(c, 10)rep(d, 10) {
		int e = x[x[x[x[0][a]][b]][c]][d];
		int k[]{ a,b,c,d,e };
		rep(i, 5) {
			int o = k[i];
			rep(j, 10) {
				if (o == j)continue;
				k[i] = j;
				if (x[x[x[x[x[0][k[0]]][k[1]]][k[2]]][k[3]]][k[4]] == 0) {
					cnt++; goto g;
				}
			}
			k[i] = o;
		}
		rep(i, 4) {
			if (k[i] == k[i + 1])continue;
			swap(k[i], k[i + 1]);
			if (x[x[x[x[x[0][k[0]]][k[1]]][k[2]]][k[3]]][k[4]] == 0) {
				cnt++; goto g;
			}
			swap(k[i], k[i + 1]);
		}
	g:;
	}
	printf("%d\n", cnt);
}