Problem: In this problem you will write a simple generator of Brainfuck (<https://en.wikipedia.org/wiki/Brainfuck>) calculators.

You are given an arithmetic expression consisting of integers from 0 to 255 and addition/subtraction signs between them. Output a Brainfuck program which, when executed, will print the result of evaluating this expression.

We use a fairly standard Brainfuck interpreter for checking the programs:

  * 30000 memory cells.
  * memory cells store integers from 0 to 255 with unsigned 8-bit wraparound.
  * console input (, command) is not supported, but it's not needed for this problem.

Input

The only line of input data contains the arithmetic expression. The expression will contain between 2 and 10 operands, separated with arithmetic signs plus and/or minus. Each operand will be an integer between 0 and 255, inclusive. The calculations result is guaranteed to be an integer between 0 and 255, inclusive (results of intermediary calculations might be outside of these boundaries).

Output

Output a Brainfuck program which, when executed, will print the result of evaluating this expression. The program must be at most 5000000 characters long (including the non-command characters), and its execution must be complete in at most 50000000 steps.

Examples

Input

2+3


Output

++&gt;
+++&gt;
&lt;[&lt;+&gt;-]&lt;
++++++++++++++++++++++++++++++++++++++++++++++++.


Input

9-7


Output

+++++++++&gt;
+++++++&gt;
&lt;[&lt;-&gt;-]&lt;
++++++++++++++++++++++++++++++++++++++++++++++++.

Note

You can download the source code of the Brainfuck interpreter by the link [http://assets.codeforces.com/rounds/784/bf.cpp](//assets.codeforces.com/rounds/784/bf.cpp). We use this code to interpret outputs.

Solution (in PYTHON3):

Solution:
'''
/*
Date: 2017/01/16 00:47:25 Monday
*/
#include<bits/stdc++.h>
using namespace std;
#define X first
#define Y second
#define mp make_pair
#define pb push_back
#define rep(i,a,n) for(int i=(a);i<=(n);++i)
#define dep(i,a,n) for(int i=(a);i>=(n);--i)
#define eps 1e-8
#define pi 3.1415926535897
#define sqr(x) ((x)*(x))
#define MAX(a,b) a=max(a,b)
#define MIN(a,b) a=min(a,b)
#define SZ(x) ((int)(x).size())
#define CPY(a,b) memcpy(a,b,sizeof(a))
#define CLR(a) memset(a,0,sizeof(a))
#define POSIN(x,y) (1<=(x)&&(x)<=n&&1<=(y)&&(y)<=m)
#define all(x) (x).begin(),(x).end()
#define COUT(S,x) cout<<fixed<<setprecision(x)<<S<<endl
#define buli(x) (__builtin_popcountll(x))
#define bur0(x) (__builtin_ctzll(x))
#define bul2(x) (63-__builtin_clzll(x))
#define pw(x) ((ll(1))<<(x))
#define upmo(a,b) (((a)=((a)+(b))%mo)<0?(a)+=mo:(a))
#define mmo(a,b) (((a)=1ll*(a)*(b)%mo)<0?(a)+=mo:(a))
#define y0 y0z
#define y1 y1z
#define yn ynz
#define j0 j0z
#define j1 j1z
#define jn jnz
#define tm tmz
#ifdef LOCAL
#define debug(...) fprintf(stderr, __VA_ARGS__)
#else
#define debug(...) 
#endif
typedef long long ll;
typedef double lf;
typedef pair<int,int> pii;
typedef pair<ll,ll> pll;
typedef pair<lf,lf> pff;
typedef complex<double> CD;
const int inf=0x3f3f3f3f;
const int mo=1000000007;
inline void gn(long long&x){
	int sg=1;char c;while(((c=getchar())<'0'||c>'9')&&c!='-');c=='-'?(sg=-1,x=0):(x=c-'0');
	while((c=getchar())>='0'&&c<='9')x=x*10+c-'0';x*=sg;
}
inline void gn(int&x){long long t;gn(t);x=t;}
inline void gn(unsigned long long&x){long long t;gn(t);x=t;}
inline void gn(double&x){double t;scanf("%lf",&t);x=t;}
inline void gn(long double&x){double t;scanf("%lf",&t);x=t;}
template<class T1,class T2>inline void gn(T1&r,T2&s){gn(r),gn(s);}
template<class T1,class T2,class T3>inline void gn(T1&r,T2&s,T3&t){gn(r),gn(s),gn(t);}
template<class T1,class T2,class T3,class T4>inline void gn(T1&r,T2&s,T3&t,T4&u){gn(r),gn(s),gn(t),gn(u);}
inline void gs(char *s){scanf("%s",s);}
inline void gc(char &c){while((c=getchar())>126 || c<33);}
inline void pc(char c){putchar(c);}
const int DX[]={1,0,-1,0},DY[]={0,1,0,-1};
ll powmod(ll a,ll b) {ll res=1;a%=mo;for(;b;b>>=1){if(b&1)res=res*a%mo;a=a*a%mo;}return res;}
ll powmod(ll a,ll b,ll mo) {ll res=1;a%=mo;for(;b;b>>=1){if(b&1)res=res*a%mo;a=a*a%mo;}return res;}
ll gcd(ll a,ll b) { return b?gcd(b,a%b):a;}
//*******************************************

const int N=111111,M=1111111;
int l,m,n,t,C,ans;
//0123456789ABCDEF
int A[]={1,0,0,0,1,0,1,0,2,1,1,2,0,1,0,0};
int main(){
#ifdef LOCAL
	freopen("D.in","r",stdin);//freopen("D.out","w",stdout);
#endif
    while(scanf("%d",&n)!=EOF){
        if(n==0){puts("1");return 0;}
    for(;n;n/=16)ans+=A[n%16];
    printf("%d\n",ans);
    }
	return 0;
}
'''
def pr(x):
    for i in range(x+48):
        print('+',end='')
    print('.',end='')
    for i in range(x+48):
        print('-',end='')
def work(x):
    if x==0:return
    work(x//10)
    pr(x%10)
s=input()
p=eval(s)
if p==0:
    pr(0)
else:
    work(p)