Problem: It is November 18 now in Japan. By the way, 11 and 18 are adjacent Lucas numbers.

You are given an integer N. Find the N-th Lucas number.

Here, the i-th Lucas number L_i is defined as follows:

* L_0=2
* L_1=1
* L_i=L_{i-1}+L_{i-2} (i≥2)

Constraints

* 1≤N≤86
* It is guaranteed that the answer is less than 10^{18}.
* N is an integer.

Input

Input is given from Standard Input in the following format:


N


Output

Print the N-th Lucas number.

Examples

Input

5


Output

11


Input

86


Output

939587134549734843

Solution (in JAVA):

Solution:

import java.util.Scanner;

public class Main {
	public static void main(String[] args) {
		
		try(Scanner sc = new Scanner(System.in)){
			int n = sc.nextInt();
			System.out.println(Ryuka(n));
		}
	}
	static long Ryuka(int n) {
		long[] ans = new long[87];
		ans[0] = 2;
		ans[1] = 1;
		for(int i = 2;i <= n;i++) {
			ans[i] = ans[i-1] + ans[i-2];
		}
		return ans[n];
	}
}