Problem: Write a program which manipulates a disjoint set S = {S1, S2, . . . , Sk}.

First of all, the program should read an integer n, then make a disjoint set where each element consists of 0, 1, ... n−1 respectively.

Next, the program should read an integer q and manipulate the set for q queries. There are two kinds of queries for different operations:

* unite(x, y): unites sets that contain x and y, say Sx and Sy, into a new set.
* same(x, y): determine whether x and y are in the same set.

Constraints

* 1 ≤ n ≤ 10000
* 1 ≤ q ≤ 100000
* x ≠ y

Input


n q
com1 x1 y1
com2 x2 y2
...
comq xq yq


In the first line, n and q are given. Then, q queries are given where com represents the type of queries. '0' denotes unite and '1' denotes same operation.

Output

For each same operation, print 1 if x and y are in the same set, otherwise 0, in a line.

Example

Input

5 12
0 1 4
0 2 3
1 1 2
1 3 4
1 1 4
1 3 2
0 1 3
1 2 4
1 3 0
0 0 4
1 0 2
1 3 0


Output

0
0
1
1
1
0
1
1

Solution (in PYTHON3):

Solution:
class UnionFind():
    def __init__(self,n):
        self.n=n
        self.parents=[-1]*n

    def find(self,x):
        if self.parents[x]<0:
            return x
        else:
            self.parents[x]=self.find(self.parents[x])
            return self.parents[x]

    def unite(self,x,y):
        x=self.find(x)
        y=self.find(y)

        if x!=y:
            if self.parents[x]>self.parents[y]:
                x,y=y,x

            self.parents[x]+=self.parents[y]
            self.parents[y]=x

    def same(self,x,y):
        return self.find(x)==self.find(y)

n,q=map(int,input().split())
UF=UnionFind(n)
for i in range(q):
    com,x,y=map(int,input().split())
    if com==0:
        UF.unite(x,y)
    elif com==1:
        if UF.same(x,y):
            print(1)
        else:
            print(0)