Problem: You have n sticks of the given lengths.

Your task is to choose exactly four of them in such a way that they can form a rectangle. No sticks can be cut to pieces, each side of the rectangle must be formed by a single stick. No stick can be chosen multiple times. It is guaranteed that it is always possible to choose such sticks.

Let S be the area of the rectangle and P be the perimeter of the rectangle. 

The chosen rectangle should have the value (P^2)/(S) minimal possible. The value is taken without any rounding.

If there are multiple answers, print any of them.

Each testcase contains several lists of sticks, for each of them you are required to solve the problem separately.

Input

The first line contains a single integer T (T ≥ 1) — the number of lists of sticks in the testcase.

Then 2T lines follow — lines (2i - 1) and 2i of them describe the i-th list. The first line of the pair contains a single integer n (4 ≤ n ≤ 10^6) — the number of sticks in the i-th list. The second line of the pair contains n integers a_1, a_2, ..., a_n (1 ≤ a_j ≤ 10^4) — lengths of the sticks in the i-th list.

It is guaranteed that for each list there exists a way to choose four sticks so that they form a rectangle.

The total number of sticks in all T lists doesn't exceed 10^6 in each testcase.

Output

Print T lines. The i-th line should contain the answer to the i-th list of the input. That is the lengths of the four sticks you choose from the i-th list, so that they form a rectangle and the value (P^2)/(S) of this rectangle is minimal possible. You can print these four lengths in arbitrary order.

If there are multiple answers, print any of them.

Example

Input

3
4
7 2 2 7
8
2 8 1 4 8 2 1 5
5
5 5 5 5 5


Output

2 7 7 2
2 2 1 1
5 5 5 5

Note

There is only one way to choose four sticks in the first list, they form a rectangle with sides 2 and 7, its area is 2 ⋅ 7 = 14, perimeter is 2(2 + 7) = 18. (18^2)/(14) ≈ 23.143.

The second list contains subsets of four sticks that can form rectangles with sides (1, 2), (2, 8) and (1, 8). Their values are (6^2)/(2) = 18, (20^2)/(16) = 25 and (18^2)/(8) = 40.5, respectively. The minimal one of them is the rectangle (1, 2).

You can choose any four of the 5 given sticks from the third list, they will form a square with side 5, which is still a rectangle with sides (5, 5).

Solution (in JAVA):

Solution:
import java.util.*;
import java.io.*;
import static java.lang.Math.*;
public class Main
{  
    static Reader scan;
    static PrintWriter pw;
    public static void main(String[] args) {
        new Thread(null,null,"_",1<<25)
        {
           public void run()
           {
               try
               {
                   solve();
               }
               catch(Exception e)
               {  
                   e.printStackTrace();
                   System.exit(1);
               }
           }
        }.start();
    }
    static void solve() throws IOException
    {
        scan = new Reader();
        pw = new PrintWriter(System.out,true);
        StringBuilder sb = new StringBuilder();
        int t = ni();
        while(t-->0)
        {  
            int n = ni();
            ArrayList<Integer> ts = new ArrayList();
            int freq[] = new int[10001];
            for(int i=0;i<n;++i)
            {  
                int x = ni();
                ++freq[x];
                if(freq[x]==2)
                    ts.add(x);
            }
            Collections.sort(ts);
            long nr1 = 100000000,dr1 = 1;
            long atl = -1,atb = -1;
//            pl("set");
//            for(int e:ts)
//                p(e);
//            pl();
             int sz = ts.size();
            for(int i=0;i<sz;++i)
            {  
                //p(e);
                int e = ts.get(i);
                if(freq[e]>=4)
                {
                    atl = e;
                    atb = e;
                    break;
                }
                else
                {
                    Integer low = null;
                    if(i>0)
                        low = ts.get(i-1);
                    Integer high = null;
                    if(i+1<sz)
                        high = ts.get(i+1);
                    if(low!=null)
                    {  
                        long mc = e;
                        long bc = low;
                        long nr2 = (mc*mc)+(bc*bc);
                        long dr2 = mc*bc;
                        if(isless(nr2,dr2,nr1,dr1))
                        {
                            atl = e;
                            atb = low;
                            nr1 = nr2;
                            dr1 = dr2;
                        }
                    }
                    if(high!=null)
                    {
                        long mc = e;
                        long bc = high;
                        long nr2 = (mc*mc)+(bc*bc);
                        long dr2 = mc*bc;
                        if(isless(nr2,dr2,nr1,dr1))
                        {
                            atl = e;
                            atb = high;
                            nr1 = nr2;
                            dr1 = dr2;
                        }
                    }
                }
            }
            int mc = (int)atl;
            int bc = (int)atb;
            sb.append(mc+" "+mc+" "+bc+" "+bc);
            sb.append("\n");
        }
        psb(sb);
        pw.flush();
        pw.close();
    }
    static long gcd(long a,long b)
    {
        if(b==0)
            return a;
        return gcd(b,a%b);
    }
    static boolean isless(long nr1,long dr1,long nr2,long dr2)
    {
        long lcm = (dr1*dr2)/gcd(dr1,dr2);
        nr1*=(lcm/dr1);
        nr2*=(lcm/dr2);
        return nr1<nr2;
    }
    static int ni() throws IOException
    {
        return scan.nextInt();
    }
    static long nl() throws IOException
    {
        return scan.nextLong();
    }
    static double nd() throws IOException
    {
        return scan.nextDouble();
    }
    static void pl()
    {
        pw.println();
    }
    static void p(Object o)
    {
        pw.print(o+" ");
    }
    static void pl(Object o)
    {
        pw.println(o);
    }
    static void psb(StringBuilder sb)
    {
        pw.print(sb);
    }
    static class Reader {
    final private int BUFFER_SIZE = 1 << 16;
    private DataInputStream din;
    private byte[] buffer;
    private int bufferPointer, bytesRead;

    public Reader() {
        din = new DataInputStream(System.in);
        buffer = new byte[BUFFER_SIZE];
        bufferPointer = bytesRead = 0;
    }

    public Reader(String file_name) throws IOException {
        din = new DataInputStream(new FileInputStream(file_name));
        buffer = new byte[BUFFER_SIZE];
        bufferPointer = bytesRead = 0;
    }

    public String readLine() throws IOException {
        byte[] buf = new byte[64];
        int cnt = 0, c;
        while ((c = read()) != -1) {
            if (c == '\n') break;
            buf[cnt++] = (byte) c;
        }
        return new String(buf, 0, cnt);
    }

    public int nextInt() throws IOException {
        int ret = 0;
        byte c = read();
        while (c <= ' ') c = read();
        boolean neg = (c == '-');
        if (neg) c = read();
        do {
            ret = ret * 10 + c - '0';
        } while ((c = read()) >= '0' && c <= '9');
        if (neg) return -ret;
        return ret;
    }

    public long nextLong() throws IOException {
        long ret = 0;
        byte c = read();
        while (c <= ' ') c = read();
        boolean neg = (c == '-');
        if (neg) c = read();
        do {
            ret = ret * 10 + c - '0';
        } while ((c = read()) >= '0' && c <= '9');
        if (neg) return -ret;
        return ret;
    }

    public double nextDouble() throws IOException {
        double ret = 0, div = 1;
        byte c = read();
        while (c <= ' ') c = read();
        boolean neg = (c == '-');
        if (neg) c = read();
        do {
            ret = ret * 10 + c - '0';
        } while ((c = read()) >= '0' && c <= '9');
        if (c == '.') while ((c = read()) >= '0' && c <= '9') ret += (c - '0') / (div *= 10);
        if (neg) return -ret;
        return ret;
    }

    private void fillBuffer() throws IOException {
        bytesRead = din.read(buffer, bufferPointer = 0, BUFFER_SIZE);
        if (bytesRead == -1) buffer[0] = -1;
    }

    private byte read() throws IOException {
        if (bufferPointer == bytesRead) fillBuffer();
        return buffer[bufferPointer++];
    }

    public void close() throws IOException {
        if (din == null) return;
        din.close();
    }
}
}