Problem: Write a program which manipulates a disjoint set S = {S1, S2, . . . , Sk}.

First of all, the program should read an integer n, then make a disjoint set where each element consists of 0, 1, ... n−1 respectively.

Next, the program should read an integer q and manipulate the set for q queries. There are two kinds of queries for different operations:

* unite(x, y): unites sets that contain x and y, say Sx and Sy, into a new set.
* same(x, y): determine whether x and y are in the same set.

Constraints

* 1 ≤ n ≤ 10000
* 1 ≤ q ≤ 100000
* x ≠ y

Input


n q
com1 x1 y1
com2 x2 y2
...
comq xq yq


In the first line, n and q are given. Then, q queries are given where com represents the type of queries. '0' denotes unite and '1' denotes same operation.

Output

For each same operation, print 1 if x and y are in the same set, otherwise 0, in a line.

Example

Input

5 12
0 1 4
0 2 3
1 1 2
1 3 4
1 1 4
1 3 2
0 1 3
1 2 4
1 3 0
0 0 4
1 0 2
1 3 0


Output

0
0
1
1
1
0
1
1

Solution (in CPP):

Solution:
#include <stdio.h>
#include <vector>
#include <algorithm>
#include <stack>

using namespace std;

int main(){
	int n,q,label,com,x,y,to_change1,to_change2;

	scanf("%d %d",&n,&q);
	int table[n];

	for(int i = 0; i < n; i++)table[i] = i;
	label = n;

	for(int i = 0; i < q; i++){
		scanf("%d %d %d",&com,&x,&y);

		if(com == 1){
			if(table[x] == table[y])printf("1\n");
			else{
				printf("0\n");
			}
		}else{
			if(table[x] == table[y])continue;

			to_change1 = table[x];
			to_change2 = table[y];

			for(int i = 0; i < n; i++){
				if(table[i] == to_change1 || table[i] == to_change2){
					table[i] = label;
				}
			}
			label++;
		}
	}

    return 0;
}