Problem: Write a program which manipulates a disjoint set S = {S1, S2, . . . , Sk}.

First of all, the program should read an integer n, then make a disjoint set where each element consists of 0, 1, ... n−1 respectively.

Next, the program should read an integer q and manipulate the set for q queries. There are two kinds of queries for different operations:

* unite(x, y): unites sets that contain x and y, say Sx and Sy, into a new set.
* same(x, y): determine whether x and y are in the same set.

Constraints

* 1 ≤ n ≤ 10000
* 1 ≤ q ≤ 100000
* x ≠ y

Input


n q
com1 x1 y1
com2 x2 y2
...
comq xq yq


In the first line, n and q are given. Then, q queries are given where com represents the type of queries. '0' denotes unite and '1' denotes same operation.

Output

For each same operation, print 1 if x and y are in the same set, otherwise 0, in a line.

Example

Input

5 12
0 1 4
0 2 3
1 1 2
1 3 4
1 1 4
1 3 2
0 1 3
1 2 4
1 3 0
0 0 4
1 0 2
1 3 0


Output

0
0
1
1
1
0
1
1

Solution (in PYTHON3):

Solution:
class UnionFind:
    def __init__(self, n):
        self.root = list(range(n + 1))
        self.size = [1] * (n + 1)

    def __getitem__(self, x):
        root = self.root
        while root[x] != x:
            root[x] = root[root[x]]
            x = root[x]
        return x

    def merge(self, x, y):
        x = self[x]
        y = self[y]
        if x == y:
            return
        sx, sy = self.size[x], self.size[y]
        if sx < sy:
            x, y = y, x
            sx, sy = sy, sx
        self.root[y] = x
        self.size[x] += sy


n, q = map(int, input().split())
uni = UnionFind(n)

for i in range(q):
    com, x, y = map(int, input().split())
    if com == 0:
        uni.merge(x, y)
    else:
        print(int(uni[x] == uni[y]))