Problem: Write a program which manipulates a disjoint set S = {S1, S2, . . . , Sk}.

First of all, the program should read an integer n, then make a disjoint set where each element consists of 0, 1, ... n−1 respectively.

Next, the program should read an integer q and manipulate the set for q queries. There are two kinds of queries for different operations:

* unite(x, y): unites sets that contain x and y, say Sx and Sy, into a new set.
* same(x, y): determine whether x and y are in the same set.

Constraints

* 1 ≤ n ≤ 10000
* 1 ≤ q ≤ 100000
* x ≠ y

Input


n q
com1 x1 y1
com2 x2 y2
...
comq xq yq


In the first line, n and q are given. Then, q queries are given where com represents the type of queries. '0' denotes unite and '1' denotes same operation.

Output

For each same operation, print 1 if x and y are in the same set, otherwise 0, in a line.

Example

Input

5 12
0 1 4
0 2 3
1 1 2
1 3 4
1 1 4
1 3 2
0 1 3
1 2 4
1 3 0
0 0 4
1 0 2
1 3 0


Output

0
0
1
1
1
0
1
1

Solution (in CPP):

Solution:
#include <iostream>
#include <algorithm>
using namespace std;
int root(int a,int P[]);

int root(int a,int P[])
{
    if(P[a] == a)
        return a;
    else    return (P[a] = root(P[a],P));
}
int is_same_set(int a,int b,int P[])
{
    return root(a,P) == root(b,P);
}

int main()
{
    int n,q,i,com,x,y,flag;
    cin >> n >> q;
    int P[n];
    for(i=0;i<n;i++)
        P[i] = i;
    for(i=0;i<q;i++)
    {
        cin >> com >> x >> y;
        if(com == 0)
            P[root(x,P)] = root(y,P);
        else    if(com == 1)
                {
                    flag = is_same_set(x,y,P);
                    cout << flag << endl;
                }
    }
    return 0;
}