Problem: Write a program which manipulates a disjoint set S = {S1, S2, . . . , Sk}.

First of all, the program should read an integer n, then make a disjoint set where each element consists of 0, 1, ... n−1 respectively.

Next, the program should read an integer q and manipulate the set for q queries. There are two kinds of queries for different operations:

* unite(x, y): unites sets that contain x and y, say Sx and Sy, into a new set.
* same(x, y): determine whether x and y are in the same set.

Constraints

* 1 ≤ n ≤ 10000
* 1 ≤ q ≤ 100000
* x ≠ y

Input


n q
com1 x1 y1
com2 x2 y2
...
comq xq yq


In the first line, n and q are given. Then, q queries are given where com represents the type of queries. '0' denotes unite and '1' denotes same operation.

Output

For each same operation, print 1 if x and y are in the same set, otherwise 0, in a line.

Example

Input

5 12
0 1 4
0 2 3
1 1 2
1 3 4
1 1 4
1 3 2
0 1 3
1 2 4
1 3 0
0 0 4
1 0 2
1 3 0


Output

0
0
1
1
1
0
1
1

Solution (in PYTHON3):

Solution:
# Disjoint Set: Union Find Tree
p = []
rank = []

def makeSet(x):
    global p, rank
    p.append(x)
    rank.append(0)

def findSet(x):
    global p
    if x != p[x]:
        p[x] = findSet(p[x])
    return p[x]

def link(x, y):
    global p, rank
    if rank[x] > rank[y]:
        p[y] = x
    else:
        p[x] = y
        if rank[x] == rank[y]:
            rank[y] += 1

def union(x, y):
    link(findSet(x), findSet(y))    

def same(x, y):
    if findSet(x) == findSet(y):
        return 1
    else:
        return 0   

[n, q] = list(map(int, input().split()))
for i in range(n):
    makeSet(i)

for i in range(q):
    [com, x, y] = list(map(int, input().split()))
    if com == 0:
        union(x, y)
    else:
        print(same(x, y))