Problem: Girl Lena likes it when everything is in order, and looks for order everywhere. Once she was getting ready for the University and noticed that the room was in a mess — all the objects from her handbag were thrown about the room. Of course, she wanted to put them back into her handbag. The problem is that the girl cannot carry more than two objects at a time, and cannot move the handbag. Also, if he has taken an object, she cannot put it anywhere except her handbag — her inherent sense of order does not let her do so.

You are given the coordinates of the handbag and the coordinates of the objects in some Сartesian coordinate system. It is known that the girl covers the distance between any two objects in the time equal to the squared length of the segment between the points of the objects. It is also known that initially the coordinates of the girl and the handbag are the same. You are asked to find such an order of actions, that the girl can put all the objects back into her handbag in a minimum time period.

Input

The first line of the input file contains the handbag's coordinates xs, ys. The second line contains number n (1 ≤ n ≤ 24) — the amount of objects the girl has. The following n lines contain the objects' coordinates. All the coordinates do not exceed 100 in absolute value. All the given positions are different. All the numbers are integer.

Output

In the first line output the only number — the minimum time the girl needs to put the objects into her handbag. 

In the second line output the possible optimum way for Lena. Each object in the input is described by its index number (from 1 to n), the handbag's point is described by number 0. The path should start and end in the handbag's point. If there are several optimal paths, print any of them. 

Examples

Input

0 0
2
1 1
-1 1


Output

8
0 1 2 0 


Input

1 1
3
4 3
3 4
0 0


Output

32
0 1 2 0 3 0 

Solution (in JAVA):

Solution:
import java.util.InputMismatchException;
import java.io.*;
import java.util.Vector;
import java.util.Collections;
import java.util.Arrays;

/**
 * Generated by Contest helper plug-in
 * Actual solution is at the bottom
 */
public class Main {
    public static void main(String[] args) {
        InputReader in = new StreamInputReader(System.in);
        PrintWriter out = new PrintWriter(System.out);
        run(in, out);
    }

    public static void run(InputReader in, PrintWriter out) {
        Solver solver = new Sellerman();
        solver.solve(1, in, out);
        Exit.exit(in, out);
    }
}

class StreamInputReader extends InputReader {
    private InputStream stream;
    private byte[] buf = new byte[1024];
    private int curChar, numChars;

    public StreamInputReader(InputStream stream) {
        this.stream = stream;
    }

    public int read() {
        if (numChars == -1)
            throw new InputMismatchException();
        if (curChar >= numChars) {
            curChar = 0;
            try {
                numChars = stream.read(buf);
            } catch (IOException e) {
                throw new InputMismatchException();
            }
            if (numChars <= 0)
                return -1;
        }
        return buf[curChar++];
    }

    @Override
    public void close() {
        try {
            stream.close();
        } catch (IOException ignored) {
        }
    }
}

abstract class InputReader {
    private boolean finished = false;

    public abstract int read();

    public int nextInt() {
        return Integer.parseInt(nextToken());
    }


    public String nextToken() {
        int c = read();
        while (isSpaceChar(c))
            c = read();
        StringBuffer res = new StringBuffer();
        do {
            res.appendCodePoint(c);
            c = read();
        } while (!isSpaceChar(c));
        return res.toString();
    }
    private boolean isSpaceChar(int c) {
        return c == ' ' || c == '\n' || c == '\r' || c == '\t' || c == -1;
    }

    public void setFinished(boolean finished) {
        this.finished = finished;
    }

    public abstract void close();
}

interface Solver {
    public void solve(int testNumber, InputReader in, PrintWriter out);
}

class Exit {
    private Exit() {
    }

    public static void exit(InputReader in, PrintWriter out) {
        in.setFinished(true);
        in.close();
        out.close();
    }
}

class Sellerman implements Solver {

    public void solve(int testNumber, InputReader in, PrintWriter out) {
        int x0 = in.nextInt();
        int y0 = in.nextInt();
        int n = in.nextInt() + 1;
        int[] x = new int[n];
        int[] y = new int[n];
        x[n - 1] = x0;
        y[n - 1] = y0;
        for (int i = 0; i < n - 1; ++i) {
            x[i] = in.nextInt();
            y[i] = in.nextInt();
        }
        int [][] g = new int[n][n];
        for(int i = 0; i < n; ++i)
            for (int j = 0; j < n; ++j) {
                g[i][j] = (x[i] - x[j]) * (x[i] - x[j]) + (y[i] - y[j]) * (y[i] - y[j]);
            }
        -- n;
        int[] dm = new int[1 << n];
        int[] prev = new int[1 << n];
        byte [] bit = new byte[1 << n];
        byte [] item0 = new byte[1 << n];
        byte [] item1 = new byte[1 << n];
        for (int i = 0; i < n; ++i) {
            bit[1 << i] = (byte) i;
        }
        Arrays.fill(dm, -1);
        dm[0] = 0;
        int tt[][] = new int[n][n];
        for (int i = 0; i < n; ++i)
            for (int j =0 ; j < n; ++j) {
                tt[i][j] = Math.min(g[n][i] + g[i][j] + g[j][n],
                                    g[n][j] + g[i][j] + g[i][n]);
            }
        for (int i = 0; i < (1 << n); ++i) {
            if (dm[i] == -1)continue;
            int t = (i ^ ((1 << n) - 1));
            int left = bit[t - (t & (t - 1))];
            for (int j = left; j < n; ++j) {
                if ((i & (1 << j)) > 0) continue;
                int nm = i | (1 << left) | (1 << j);
                if (dm[nm] == -1 || dm[nm] > dm[i] + tt[left][j]) {
                    dm[nm] = dm[i] + tt[left][j];
                    prev[nm] = i;
                    item0[nm] = (byte)left;
                    item1[nm] = (byte)j;
                }
            }
        }
        out.println(dm[(1 << n) - 1]);
        Vector<Vector<Integer>> path = new Vector<Vector<Integer>> () ;
        int cmask = (1 << n) - 1;
        while (cmask > 0) {
            int p = prev[cmask];
            Vector<Integer> tmp = new Vector<Integer> () ;
            tmp.add(0);
            tmp.add(item0[cmask] + 1);
            tmp.add(item1[cmask] + 1);
            cmask = prev[cmask];
            path.add(tmp);
        }
        Collections.reverse(path);
        int len = 0;
        for (Vector<Integer> vec : path)
            len += vec.size();
        int ans[] = new int[len];
        boolean[] valid = new boolean[len];
        Arrays.fill(valid, true);
        len = 0;
        for (Vector<Integer> vec : path) {
            for (int ttt : vec) {
                ans[len ++] = ttt;
            }
        }
        for (int i = 0; i < len - 1; ++i) {
            if (ans[i] == ans[i + 1])
                valid[i] = false;
        }
        for (int i = 0; i < len; ++i) {
            if (valid[i]) {
                out.print(ans[i] + " ");
            }
        }
        out.print("0");

    }
}