Problem: Create a program that rotates the pattern of 8 characters x 8 lines clockwise by 90 degrees, 180 degrees, and 270 degrees and outputs it.



Input

A pattern consisting of 8 characters x 8 lines is given. Characters consist of alphanumeric characters, half-width pound'#', and asterisk'*'.

Output

Output the rotated pattern in the following format.


90 (fixed half-width numbers)
Pattern rotated 90 degrees
180 (fixed half-width numbers)
180 degree rotated pattern
270 (fixed half-width numbers)
Pattern rotated 270 degrees


Examples

Input

#*******
#*******
#*******
#*******
#*******
#*******
#*******
########


Output

90
########
#*******
#*******
#*******
#*******
#*******
#*******
#*******
180
########
*******#
*******#
*******#
*******#
*******#
*******#
*******#
270
*******#
*******#
*******#
*******#
*******#
*******#
*******#
########


Input

*******
*******
*******
*******
*******
*******
*******


Output

90

*******
*******
*******
*******
*******
*******
*******
180

*******#
*******#
*******#
*******#
*******#
*******#
*******#
270
*******#
*******#
*******#
*******#
*******#
*******#
*******#

Solution (in CPP):

Solution:
#include<stdio.h>

int main(){

char x[10];

char map[10][10];
char P[10][10];


for(int i=0;i<8;i++){
scanf("%s",x);
for(int j=0;j<8;j++)
map[i][j]=x[j];

}


for(int i=0;i<8;i++)
for(int j=0;j<8;j++)
if(i<4&&j<4)P[j][7-i]=map[i][j];
else if(i<4&&j>=4)P[j][7-i]=map[i][j];
else if(i>=4&&j>=4)P[j][7-i]=map[i][j];
else if(i>=4&&j<4)P[j][7-i]=map[i][j];

printf("90\n");
for(int i=0;i<8;i++){
for(int j=0;j<8;j++)
	printf("%c",P[i][j]);

printf("\n");
}
char PP[10][10];
char PPP[10][10];

for(int i=0;i<8;i++)
for(int j=0;j<8;j++)
if(i<4&&j<4)PP[j][7-i]=P[i][j];
else if(i<4&&j>=4)PP[j][7-i]=P[i][j];
else if(i>=4&&j>=4)PP[j][7-i]=P[i][j];
else if(i>=4&&j<4)PP[j][7-i]=P[i][j];

printf("180\n");
for(int i=0;i<8;i++){
for(int j=0;j<8;j++)
	printf("%c",PP[i][j]);

printf("\n");
}

for(int i=0;i<8;i++)
for(int j=0;j<8;j++)
if(i<4&&j<4)PPP[j][7-i]=PP[i][j];
else if(i<4&&j>=4)PPP[j][7-i]=PP[i][j];
else if(i>=4&&j>=4)PPP[j][7-i]=PP[i][j];
else if(i>=4&&j<4)PPP[j][7-i]=PP[i][j];

printf("270\n");
for(int i=0;i<8;i++){
for(int j=0;j<8;j++)
	printf("%c",PPP[i][j]);

printf("\n");
}




return 0;
}