Problem: Create a program that rotates the pattern of 8 characters x 8 lines clockwise by 90 degrees, 180 degrees, and 270 degrees and outputs it.



Input

A pattern consisting of 8 characters x 8 lines is given. Characters consist of alphanumeric characters, half-width pound'#', and asterisk'*'.

Output

Output the rotated pattern in the following format.


90 (fixed half-width numbers)
Pattern rotated 90 degrees
180 (fixed half-width numbers)
180 degree rotated pattern
270 (fixed half-width numbers)
Pattern rotated 270 degrees


Examples

Input

#*******
#*******
#*******
#*******
#*******
#*******
#*******
########


Output

90
########
#*******
#*******
#*******
#*******
#*******
#*******
#*******
180
########
*******#
*******#
*******#
*******#
*******#
*******#
*******#
270
*******#
*******#
*******#
*******#
*******#
*******#
*******#
########


Input

*******
*******
*******
*******
*******
*******
*******


Output

90

*******
*******
*******
*******
*******
*******
*******
180

*******#
*******#
*******#
*******#
*******#
*******#
*******#
270
*******#
*******#
*******#
*******#
*******#
*******#
*******#

Solution (in CPP):

Solution:
#include<vector>
#include<list>
#include<algorithm>
#include<iostream>
#include<string>
#include<cstdio>
#include<cstdlib>
#include<cstring>
#include<cmath>
using namespace std;
int main(){
  int h,i,j;
  char b[8][9],c[8][9],s[9];
  memset(b,0,sizeof(b));
  memset(c,0,sizeof(c));
  for(i=0;i<8;i++){
    cin>>s;
    for(j=0;j<8;j++)
      b[j][i]=s[j];
  }
  for(h=1;h<4;h++){  
    for(i=0;i<8;i++)
      for(j=0;j<8;j++)
	c[j][i]=b[i][7-j];    
    memcpy(b,c,sizeof(c));
    cout<<h*90<<endl;
    for(i=0;i<8;i++){
      for(j=0;j<8;j++)
	cout<<b[j][i];
      cout<<endl;
    }
  }
  return 0;
}