Problem: Write a program which manipulates a disjoint set S = {S1, S2, . . . , Sk}.

First of all, the program should read an integer n, then make a disjoint set where each element consists of 0, 1, ... n−1 respectively.

Next, the program should read an integer q and manipulate the set for q queries. There are two kinds of queries for different operations:

* unite(x, y): unites sets that contain x and y, say Sx and Sy, into a new set.
* same(x, y): determine whether x and y are in the same set.

Constraints

* 1 ≤ n ≤ 10000
* 1 ≤ q ≤ 100000
* x ≠ y

Input


n q
com1 x1 y1
com2 x2 y2
...
comq xq yq


In the first line, n and q are given. Then, q queries are given where com represents the type of queries. '0' denotes unite and '1' denotes same operation.

Output

For each same operation, print 1 if x and y are in the same set, otherwise 0, in a line.

Example

Input

5 12
0 1 4
0 2 3
1 1 2
1 3 4
1 1 4
1 3 2
0 1 3
1 2 4
1 3 0
0 0 4
1 0 2
1 3 0


Output

0
0
1
1
1
0
1
1

Solution (in CPP):

Solution:
#include<iostream>
#include<vector>

using namespace std;

vector<int> UFtree;

int root(int i) {
  if(UFtree[i] == i) return i;
  return (UFtree[i] = root(UFtree[i]));
}

bool is_same_set(int i, int j) {
  return root(i) == root(j);
}

void unite(int i, int j) {
  UFtree[root(i)] = root(j);
}


int main() {
  int n, q, op, x, y;
  cin >> n >> q;
  for(int i = 0; i < n; i++) UFtree.push_back(i);
  for(int i = 0; i < q; i++) {
    cin >> op >> x >> y;
    if(op == 0) unite(x, y);
    else cout << is_same_set(x, y) << endl;
  }
  return 0;
}