Problem: Write a program which manipulates a disjoint set S = {S1, S2, . . . , Sk}.

First of all, the program should read an integer n, then make a disjoint set where each element consists of 0, 1, ... n−1 respectively.

Next, the program should read an integer q and manipulate the set for q queries. There are two kinds of queries for different operations:

* unite(x, y): unites sets that contain x and y, say Sx and Sy, into a new set.
* same(x, y): determine whether x and y are in the same set.

Constraints

* 1 ≤ n ≤ 10000
* 1 ≤ q ≤ 100000
* x ≠ y

Input


n q
com1 x1 y1
com2 x2 y2
...
comq xq yq


In the first line, n and q are given. Then, q queries are given where com represents the type of queries. '0' denotes unite and '1' denotes same operation.

Output

For each same operation, print 1 if x and y are in the same set, otherwise 0, in a line.

Example

Input

5 12
0 1 4
0 2 3
1 1 2
1 3 4
1 1 4
1 3 2
0 1 3
1 2 4
1 3 0
0 0 4
1 0 2
1 3 0


Output

0
0
1
1
1
0
1
1

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int uni[100000],n,m,r[100000];
int find(int a){
	if(a!=uni[a])a=find(uni[a]);
	return a;
}
bool same(int a,int b){
	return find(a)==find(b);
}
void unit(int a,int b){
	int c=find(a),d=find(b);
	if(r[c]>r[d])uni[c]=d;
	else{uni[d]=c;
		if(r[c]==r[d])r[d]++;
	}
}
int main() {
	cin>>n>>m;
	for(int i=0;i<n;i++){uni[i]=i;r[i]=0;}
	for(int i=0;i<m;i++){
		int a,b,c;
		cin>>c>>a>>b;
		if(c)cout<<(same(a,b)?1:0)<<endl;
		else unit(a,b);
	}
}