Problem: You have n sticks of the given lengths.

Your task is to choose exactly four of them in such a way that they can form a rectangle. No sticks can be cut to pieces, each side of the rectangle must be formed by a single stick. No stick can be chosen multiple times. It is guaranteed that it is always possible to choose such sticks.

Let S be the area of the rectangle and P be the perimeter of the rectangle. 

The chosen rectangle should have the value (P^2)/(S) minimal possible. The value is taken without any rounding.

If there are multiple answers, print any of them.

Each testcase contains several lists of sticks, for each of them you are required to solve the problem separately.

Input

The first line contains a single integer T (T ≥ 1) — the number of lists of sticks in the testcase.

Then 2T lines follow — lines (2i - 1) and 2i of them describe the i-th list. The first line of the pair contains a single integer n (4 ≤ n ≤ 10^6) — the number of sticks in the i-th list. The second line of the pair contains n integers a_1, a_2, ..., a_n (1 ≤ a_j ≤ 10^4) — lengths of the sticks in the i-th list.

It is guaranteed that for each list there exists a way to choose four sticks so that they form a rectangle.

The total number of sticks in all T lists doesn't exceed 10^6 in each testcase.

Output

Print T lines. The i-th line should contain the answer to the i-th list of the input. That is the lengths of the four sticks you choose from the i-th list, so that they form a rectangle and the value (P^2)/(S) of this rectangle is minimal possible. You can print these four lengths in arbitrary order.

If there are multiple answers, print any of them.

Example

Input

3
4
7 2 2 7
8
2 8 1 4 8 2 1 5
5
5 5 5 5 5


Output

2 7 7 2
2 2 1 1
5 5 5 5

Note

There is only one way to choose four sticks in the first list, they form a rectangle with sides 2 and 7, its area is 2 ⋅ 7 = 14, perimeter is 2(2 + 7) = 18. (18^2)/(14) ≈ 23.143.

The second list contains subsets of four sticks that can form rectangles with sides (1, 2), (2, 8) and (1, 8). Their values are (6^2)/(2) = 18, (20^2)/(16) = 25 and (18^2)/(8) = 40.5, respectively. The minimal one of them is the rectangle (1, 2).

You can choose any four of the 5 given sticks from the third list, they will form a square with side 5, which is still a rectangle with sides (5, 5).

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.util.Arrays;
import java.util.Collection;
import java.util.List;
import java.util.PriorityQueue;
import java.util.Random;
import java.util.StringTokenizer;
import java.util.stream.Stream;

public class Solution implements Runnable {

	static final double time = 1e9;
	static final int MOD = (int) 1e9 + 7;
	static final long mh = Long.MAX_VALUE;
	static final Reader in = new Reader();
	static final PrintWriter out = new PrintWriter(System.out);
	StringBuilder answer = new StringBuilder();

	public static void main(String[] args) {
		new Thread(null, new Solution(), "persefone", 1 << 28).start();
	}

	@Override
	public void run() {
		long start = System.nanoTime();
		solve();
		printf();
		long elapsed = System.nanoTime() - start;
		// out.println("stamp : " + elapsed / time);
		// out.println("stamp : " + TimeUnit.SECONDS.convert(elapsed,
		// TimeUnit.NANOSECONDS));
		close();
	}
	/*
	 x ^ 2 + (x + y) ^ 2 / x(x + y) = 2x(x+y) + y^2 / x(x + y)
	 y ^ 2 / x(x + y) min 
	 
	 */

	void solve() {
		int m = 10001;
		for (int t = in.nextInt(); t > 0; t--) {
			int n = in.nextInt();
			int[] f = in.nextIntArray(n);
			PriorityQueue<Integer> queue = new PriorityQueue<>();
			for (int i = 0; i < n; i++) queue.add(f[i]);
			for (int i = 0; i < n; i++) f[i] = queue.poll();
			
			int a = 0, b = 0;
			int r = 1, prev = -1;
			
			for (int i = 1; i < n; i++) {
				if (f[i] == f[i - 1]) {
					r++;
					if (r == 4) {
						a = b = f[i];
						break;
					} else if (r == 2) {
						if (a == 0) {
							a = f[i];
						} else if (b == 0) {
							b = f[i];
						} else {
							if (f[i] * a < b * prev) {
								a = prev;
								b = f[i];
							}
						}
						prev = f[i];
					}
				} else {
					r = 1;
				}
			}
			
			add(a + " " + b + " " + a + " " + b, '\n');
		}
	}
	
	public static int[] shuffle(int[] a, Random gen) {
		for (int i = 0, n = a.length; i < n; i++) {
			int ind = gen.nextInt(n - i) + i;
			int d = a[i];
			a[i] = a[ind];
			a[ind] = d;
		}
		return a;
	}

	public static int[] shrinkX(int[] a) {
		int n = a.length;
		long[] b = new long[n];
		for (int i = 0; i < n; i++)
			b[i] = (long) a[i] << 32 | i;
		Arrays.sort(b);
		int[] ret = new int[n];
		int p = 0;
		ret[0] = (int) (b[0] >> 32);
		for (int i = 0; i < n; i++) {
			if (i > 0 && (b[i] ^ b[i - 1]) >> 32 != 0) {
				p++;
				ret[p] = (int) (b[i] >> 32);
			}
			a[(int) b[i]] = p;
		}
		return Arrays.copyOf(ret, p + 1);
	}

	int pow(int a, int b, int p) {
		long ans = 1, base = a;
		while (b > 0) {
			if ((b & 1) > 0) {
				ans *= base %= p;
			}
			base *= base %= p;
			b >>= 1;
		}
		return (int) ans;
	}

	public static int[] enumLowestPrimeFactors(int n) {
		int tot = 0;
		int[] lpf = new int[n + 1];
		int u = n + 32;
		double lu = Math.log(u);
		int[] primes = new int[(int) (u / lu + u / lu / lu * 1.5)];
		for (int i = 2; i <= n; i++)
			lpf[i] = i;
		for (int p = 2; p <= n; p++) {
			if (lpf[p] == p)
				primes[tot++] = p;
			int tmp;
			for (int i = 0; i < tot && primes[i] <= lpf[p] && (tmp = primes[i] * p) <= n; i++) {
				lpf[tmp] = primes[i];
			}
		}
		return lpf;
	}

	public static int[] enumNumDivisorsFast(int n, int[] lpf) {
		int[] nd = new int[n + 1];
		nd[1] = 1;
		for (int i = 2; i <= n; i++) {
			int j = i, e = 0;
			while (j % lpf[i] == 0) {
				j /= lpf[i];
				e++;
			}
			nd[i] = nd[j] * (e + 1);
		}
		return nd;
	}

	boolean isPrime(long n) {

		for (int i = 2; 1l * i * i <= n; i++)
			if (n % i == 0)
				return false;
		return true;
	}

	void printf() {
		out.print(answer);
	}

	void close() {
		out.close();
	}

	void printf(Stream<?> str) {
		str.forEach(o -> add(o, " "));
		add("\n");
	}

	void printf(Object... obj) {
		printf(false, obj);
	}

	void printfWithDescription(Object... obj) {
		printf(true, obj);
	}

	private void printf(boolean b, Object... obj) {

		if (obj.length > 1) {
			for (int i = 0; i < obj.length; i++) {
				if (b)
					add(obj[i].getClass().getSimpleName(), " - ");
				if (obj[i] instanceof Collection<?>) {
					printf((Collection<?>) obj[i]);
				} else if (obj[i] instanceof int[][]) {
					printf((int[][]) obj[i]);
				} else if (obj[i] instanceof long[][]) {
					printf((long[][]) obj[i]);
				} else if (obj[i] instanceof double[][]) {
					printf((double[][]) obj[i]);
				} else
					printf(obj[i]);
			}
			return;
		}

		if (b)
			add(obj[0].getClass().getSimpleName(), " - ");
		printf(obj[0]);
	}

	void printf(Object o) {
		if (o instanceof int[])
			printf(Arrays.stream((int[]) o).boxed());
		else if (o instanceof char[])
			printf(new String((char[]) o));
		else if (o instanceof long[])
			printf(Arrays.stream((long[]) o).boxed());
		else if (o instanceof double[])
			printf(Arrays.stream((double[]) o).boxed());
		else if (o instanceof boolean[]) {
			for (boolean b : (boolean[]) o)
				add(b, " ");
			add("\n");
		} else
			add(o, "\n");
	}

	void printf(int[]... obj) {
		for (int i = 0; i < obj.length; i++)
			printf(obj[i]);
	}

	void printf(long[]... obj) {
		for (int i = 0; i < obj.length; i++)
			printf(obj[i]);
	}

	void printf(double[]... obj) {
		for (int i = 0; i < obj.length; i++)
			printf(obj[i]);
	}

	void printf(boolean[]... obj) {
		for (int i = 0; i < obj.length; i++)
			printf(obj[i]);
	}

	void printf(Collection<?> col) {
		printf(col.stream());
	}

	<T, K> void add(T t, K k) {
		if (t instanceof Collection<?>) {
			((Collection<?>) t).forEach(i -> add(i, " "));
		} else if (t instanceof Object[]) {
			Arrays.stream((Object[]) t).forEach(i -> add(i, " "));
		} else
			add(t);
		add(k);
	}

	<T> void add(T t) {
		answer.append(t);
	}

	@SuppressWarnings("unchecked")
	<T extends Comparable<? super T>> T min(T... t) {
		if (t.length == 0)
			return null;
		T m = t[0];
		for (int i = 1; i < t.length; i++)
			if (t[i].compareTo(m) < 0)
				m = t[i];
		return m;
	}

	@SuppressWarnings("unchecked")
	<T extends Comparable<? super T>> T max(T... t) {
		if (t.length == 0)
			return null;
		T m = t[0];
		for (int i = 1; i < t.length; i++)
			if (t[i].compareTo(m) > 0)
				m = t[i];
		return m;
	}

	int gcd(int a, int b) {
		return (b == 0) ? a : gcd(b, a % b);
	}

	long gcd(long a, long b) {
		return (b == 0) ? a : gcd(b, a % b);
	}

	long lcm(int a, int b) {
		return (1l * a * b / gcd(a, b));
	}

	long lcm(long a, long b) {
		if (a > Long.MAX_VALUE / b)
			throw new RuntimeException();
		return a * b / gcd(a, b);
	}

	// c = gcd(a, b) -> extends gcd method: ax + by = c <----> (b % a)p + q = c;
	int[] ext_gcd(int a, int b) {
		if (b == 0)
			return new int[] { a, 1, 0 };
		int[] vals = ext_gcd(b, a % b);
		int d = vals[0]; // gcd
		int p = vals[2]; //
		int q = vals[1] - (a / b) * vals[2];
		return new int[] { d, p, q };
	}

	// find any solution of the equation: ax + by = c using extends gcd
	boolean find_any_solution(int a, int b, int c, int[] root) {
		int[] vals = ext_gcd(Math.abs(a), Math.abs(b));
		if (c % vals[0] != 0)
			return false;
		printf(vals);
		root[0] = c * vals[1] / vals[0];
		root[1] = c * vals[2] / vals[0];
		if (a < 0)
			root[0] *= -1;
		if (b < 0)
			root[1] *= -1;
		return true;
	}

	int mod(int x) {
		return x % MOD;
	}

	int mod(int x, int y) {
		return mod(mod(x) + mod(y));
	}

	long mod(long x) {
		return x % MOD;
	}

	long mod(long x, long y) {
		return mod(mod(x) + mod(y));
	}

	int lw(long[] f, int l, int r, long k) {
		int R = r, m = 0;
		while (l <= r) {
			m = l + r >> 1;
			if (m == R)
				return m;
			if (f[m] >= k)
				r = m - 1;
			else
				l = m + 1;
		}
		return l;
	}

	int up(long[] f, int l, int r, long k) {
		int R = r, m = 0;
		while (l <= r) {
			m = l + r >> 1;
			if (m == R)
				return m;
			if (f[m] > k)
				r = m - 1;
			else
				l = m + 1;
		}
		return l;
	}

	int lw(int[] f, int l, int r, int k) {
		int R = r, m = 0;
		while (l <= r) {
			m = l + r >> 1;
			if (m == R)
				return m;
			if (f[m] >= k)
				r = m - 1;
			else
				l = m + 1;
		}
		return l;
	}

	int up(int[] f, int l, int r, int k) {
		int R = r, m = 0;
		while (l <= r) {
			m = l + r >> 1;
			if (m == R)
				return m;
			if (f[m] > k)
				r = m - 1;
			else
				l = m + 1;
		}
		return l;
	}

	<K extends Comparable<K>> int lw(List<K> li, int l, int r, K k) {
		int R = r, m = 0;
		while (l <= r) {
			m = l + r >> 1;
			if (m == R)
				return m;
			if (li.get(m).compareTo(k) >= 0)
				r = m - 1;
			else
				l = m + 1;
		}
		return l;
	}

	<K extends Comparable<K>> int up(List<K> li, int l, int r, K k) {
		int R = r, m = 0;
		while (l <= r) {
			m = l + r >> 1;
			if (m == R)
				return m;
			if (li.get(m).compareTo(k) > 0)
				r = m - 1;
			else
				l = m + 1;
		}
		return l;
	}

	<K extends Comparable<K>> int bs(List<K> li, int l, int r, K k) {
		while (l <= r) {
			int m = l + r >> 1;
			if (li.get(m) == k)
				return m;
			else if (li.get(m).compareTo(k) < 0)
				l = m + 1;
			else
				r = m - 1;
		}
		return -1;
	}

	long calc(int base, int exponent, int p) {
		if (exponent == 0)
			return 1;
		if (exponent == 1)
			return base % p;
		long m = calc(base, exponent >> 1, p);
		if (exponent % 2 == 0)
			return (m * m) % p;
		return 1l * base * m % p * m % p;
	}

	long calc(int base, long exponent, int p) {
		if (exponent == 0)
			return 1;
		if (exponent == 1)
			return base % p;
		long m = calc(base, exponent >> 1, p);
		if (exponent % 2 == 0)
			return (m * m) % p;
		return 1l * base * m % p * m % p;
	}

	long calc(long base, long exponent, int p) {
		if (exponent == 0)
			return 1;
		if (exponent == 1)
			return base % p;
		long m = calc(base, exponent >> 1, p);
		if (exponent % 2 == 0)
			return (m * m) % p;
		return base * m % p * m % p;
	}

	long power(int base, int exponent) {
		if (exponent == 0)
			return 1;
		long m = power(base, exponent / 2);
		if (exponent % 2 == 0)
			return m * m;
		return base * m * m;
	}

	void swap(int[] a, int i, int j) {
		a[i] ^= a[j];
		a[j] ^= a[i];
		a[i] ^= a[j];
	}

	void swap(long[] a, int i, int j) {
		long tmp = a[i];
		a[i] = a[j];
		a[j] = tmp;
	}

	static class Pair<K extends Comparable<? super K>, V extends Comparable<? super V>>
			implements Comparable<Pair<K, V>> {
		private K k;
		private V v;

		Pair() {
		}

		Pair(K k, V v) {
			this.k = k;
			this.v = v;
		}

		K getK() {
			return k;
		}

		V getV() {
			return v;
		}

		void setK(K k) {
			this.k = k;
		}

		void setV(V v) {
			this.v = v;
		}

		void setKV(K k, V v) {
			this.k = k;
			this.v = v;
		}

		@SuppressWarnings("unchecked")
		@Override
		public boolean equals(Object o) {
			if (this == o)
				return true;
			if (o == null || !(o instanceof Pair))
				return false;
			Pair<K, V> p = (Pair<K, V>) o;
			return k.compareTo(p.k) == 0 && v.compareTo(p.v) == 0;
		}

		@Override
		public int hashCode() {
			int hash = 31;
			hash = hash * 89 + k.hashCode();
			hash = hash * 89 + v.hashCode();
			return hash;
		}

		@Override
		public int compareTo(Pair<K, V> pair) {
			return k.compareTo(pair.k) == 0 ? v.compareTo(pair.v) : k.compareTo(pair.k);
		}

		@Override
		public Pair<K, V> clone() {
			return new Pair<K, V>(this.k, this.v);
		}

		@Override
		public String toString() {
			return String.valueOf(k).concat(" ").concat(String.valueOf(v)).concat("\n");
		}
	}

	static class Reader {
		private BufferedReader br;
		private StringTokenizer st;

		Reader() {
			br = new BufferedReader(new InputStreamReader(System.in));
		}

		String next() {
			try {
				while (st == null || !st.hasMoreTokens()) {
					st = new StringTokenizer(br.readLine());
				}
			} catch (IOException e) {
				e.printStackTrace();
			}
			return st.nextToken();
		}

		int nextInt() {
			return Integer.parseInt(next());
		}

		int[] nextIntArray(int n) {
			int[] arr = new int[n];
			for (int i = 0; i < n; i++)
				arr[i] = nextInt();
			return arr;
		}

		long nextLong() {
			return Long.parseLong(next());
		}

		String nextLine() {
			String s = "";
			try {
				s = br.readLine();
			} catch (IOException e) {
				e.printStackTrace();
			}
			return s;
		}
	}
}