Problem: Create a program that rotates the pattern of 8 characters x 8 lines clockwise by 90 degrees, 180 degrees, and 270 degrees and outputs it.



Input

A pattern consisting of 8 characters x 8 lines is given. Characters consist of alphanumeric characters, half-width pound'#', and asterisk'*'.

Output

Output the rotated pattern in the following format.


90 (fixed half-width numbers)
Pattern rotated 90 degrees
180 (fixed half-width numbers)
180 degree rotated pattern
270 (fixed half-width numbers)
Pattern rotated 270 degrees


Examples

Input

#*******
#*******
#*******
#*******
#*******
#*******
#*******
########


Output

90
########
#*******
#*******
#*******
#*******
#*******
#*******
#*******
180
########
*******#
*******#
*******#
*******#
*******#
*******#
*******#
270
*******#
*******#
*******#
*******#
*******#
*******#
*******#
########


Input

*******
*******
*******
*******
*******
*******
*******


Output

90

*******
*******
*******
*******
*******
*******
*******
180

*******#
*******#
*******#
*******#
*******#
*******#
*******#
270
*******#
*******#
*******#
*******#
*******#
*******#
*******#

Solution (in CPP):

Solution:
#include <iostream>
#include <string>
using namespace std;

int main(){
	int angle = 90;
	char a[8][8],b[8][8],c[8][8],d[8][8];
	for(int i = 0;i < 8;++i){
		for(int j = 0;j < 8;++j){
			cin >> a[i][j];
		}
	}
	for(int i = 0;i < 8;++i){
		for(int j = 0;j < 8;++j){
			b[i][j] = a[7 - j][i];
		}
	}
	cout << angle << endl;
	for(int i = 0;i < 8;++i){
		for(int j = 0;j < 8;++j){
			cout << b[i][j];
		}
		cout << endl;
	}
	for(int i = 0;i < 8;++i){
		for(int j = 0;j < 8;++j){
			c[i][j] = b[7 - j][i];
		}
	}
	cout << angle * 2 << endl;
	for(int i = 0;i < 8;++i){
		for(int j = 0;j < 8;++j){
			cout << c[i][j];
		}
		cout << endl;
	}
	for(int i = 0;i < 8;++i){
		for(int j = 0;j < 8;++j){
			d[i][j] = c[7 - j][i];
		}
	}
	cout << angle * 3 << endl;
	for(int i = 0;i < 8;++i){
		for(int j = 0;j < 8;++j){
			cout << d[i][j];
		}
		cout << endl;
	}
	return 0;
}