Problem: Write a program which manipulates a disjoint set S = {S1, S2, . . . , Sk}.

First of all, the program should read an integer n, then make a disjoint set where each element consists of 0, 1, ... n−1 respectively.

Next, the program should read an integer q and manipulate the set for q queries. There are two kinds of queries for different operations:

* unite(x, y): unites sets that contain x and y, say Sx and Sy, into a new set.
* same(x, y): determine whether x and y are in the same set.

Constraints

* 1 ≤ n ≤ 10000
* 1 ≤ q ≤ 100000
* x ≠ y

Input


n q
com1 x1 y1
com2 x2 y2
...
comq xq yq


In the first line, n and q are given. Then, q queries are given where com represents the type of queries. '0' denotes unite and '1' denotes same operation.

Output

For each same operation, print 1 if x and y are in the same set, otherwise 0, in a line.

Example

Input

5 12
0 1 4
0 2 3
1 1 2
1 3 4
1 1 4
1 3 2
0 1 3
1 2 4
1 3 0
0 0 4
1 0 2
1 3 0


Output

0
0
1
1
1
0
1
1

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
using lint = long long;
template<class T = int> using V  = vector<T>;
template<class T = int> using VV = V< V<T> >;
struct QU {
  V<> par;
  QU(int n) { par.resize(n); iota(par.begin(), par.end(), 0); }
  int find(int x) { return par[x] == x ? x : par[x] = find(par[x]); }
  bool same(int x, int y) { return find(x) == find(y); }
  void unite(int x, int y) { par[find(x)] = find(y); }
};
int main() {
  cin.tie(NULL); ios::sync_with_stdio(false);
  int n, q; cin >> n >> q;
  QU qu(n);
  for (int i = 0; i < q; i++) {
    int c, x, y; cin >> c >> x >> y;
    if (c) cout << qu.same(x, y) << '\n';
    else qu.unite(x, y);
  }
}