Problem: Write a program which manipulates a disjoint set S = {S1, S2, . . . , Sk}.

First of all, the program should read an integer n, then make a disjoint set where each element consists of 0, 1, ... n−1 respectively.

Next, the program should read an integer q and manipulate the set for q queries. There are two kinds of queries for different operations:

* unite(x, y): unites sets that contain x and y, say Sx and Sy, into a new set.
* same(x, y): determine whether x and y are in the same set.

Constraints

* 1 ≤ n ≤ 10000
* 1 ≤ q ≤ 100000
* x ≠ y

Input


n q
com1 x1 y1
com2 x2 y2
...
comq xq yq


In the first line, n and q are given. Then, q queries are given where com represents the type of queries. '0' denotes unite and '1' denotes same operation.

Output

For each same operation, print 1 if x and y are in the same set, otherwise 0, in a line.

Example

Input

5 12
0 1 4
0 2 3
1 1 2
1 3 4
1 1 4
1 3 2
0 1 3
1 2 4
1 3 0
0 0 4
1 0 2
1 3 0


Output

0
0
1
1
1
0
1
1

Solution (in PYTHON3):

Solution:
import sys
input = lambda: sys.stdin.readline().rstrip()

n,q = map(int, input().split())

parents = [-1] * n

def find(x):
    if parents[x] < 0:
        return x
    else:
        parents[x] = find(parents[x])
        return parents[x]

def union(x,y):
    x = find(x)
    y = find(y)

    if x == y:
        return

    if parents[x] > parents[y]:
        x,y = y, x

    parents[x] += parents[y]
    parents[y] = x     

def same(x,y):
    return find(x) == find(y)

for i in range(q):
    com,x,y = map(int, input().split())

    if com == 0:
        union(x, y)
    else:
        if same(x, y):
            print(1)
        else:
            print(0)