Problem: Create a program that rotates the pattern of 8 characters x 8 lines clockwise by 90 degrees, 180 degrees, and 270 degrees and outputs it.



Input

A pattern consisting of 8 characters x 8 lines is given. Characters consist of alphanumeric characters, half-width pound'#', and asterisk'*'.

Output

Output the rotated pattern in the following format.


90 (fixed half-width numbers)
Pattern rotated 90 degrees
180 (fixed half-width numbers)
180 degree rotated pattern
270 (fixed half-width numbers)
Pattern rotated 270 degrees


Examples

Input

#*******
#*******
#*******
#*******
#*******
#*******
#*******
########


Output

90
########
#*******
#*******
#*******
#*******
#*******
#*******
#*******
180
########
*******#
*******#
*******#
*******#
*******#
*******#
*******#
270
*******#
*******#
*******#
*******#
*******#
*******#
*******#
########


Input

*******
*******
*******
*******
*******
*******
*******


Output

90

*******
*******
*******
*******
*******
*******
*******
180

*******#
*******#
*******#
*******#
*******#
*******#
*******#
270
*******#
*******#
*******#
*******#
*******#
*******#
*******#

Solution (in CPP):

Solution:
#include<iostream>
using namespace std;

//90度回転の方法が理解できたら、それを3回するだけ

char field[10][10];
char tmp[10][10];

void rotate(){
	for(int i=0; i < 8; i++){
		for(int j=0; j < 8; j++){
			tmp[i][j] = field[i][j];
		}
	}

	for(int i=0; i < 8; i++){
		for(int j=0; j < 8; j++){
			field[i][j] = tmp[7-j][i];
		}
	}
}

void output(){
	for(int i=0; i < 8; i++){
		for(int j=0; j < 8; j++){
			cout << field[i][j];
		}
		cout << endl;
	}
}

int main(){
	for(int i=0; i < 8; i++){
		for(int j=0; j < 8; j++){
			cin >> field[i][j];
		}
	}


	cout << 90 << endl;
	rotate();
	output();

	cout << 180 << endl;
	rotate();
	output();

	cout << 270 << endl;
	rotate();
	output();
}