Problem: Write a program which manipulates a disjoint set S = {S1, S2, . . . , Sk}.

First of all, the program should read an integer n, then make a disjoint set where each element consists of 0, 1, ... n−1 respectively.

Next, the program should read an integer q and manipulate the set for q queries. There are two kinds of queries for different operations:

* unite(x, y): unites sets that contain x and y, say Sx and Sy, into a new set.
* same(x, y): determine whether x and y are in the same set.

Constraints

* 1 ≤ n ≤ 10000
* 1 ≤ q ≤ 100000
* x ≠ y

Input


n q
com1 x1 y1
com2 x2 y2
...
comq xq yq


In the first line, n and q are given. Then, q queries are given where com represents the type of queries. '0' denotes unite and '1' denotes same operation.

Output

For each same operation, print 1 if x and y are in the same set, otherwise 0, in a line.

Example

Input

5 12
0 1 4
0 2 3
1 1 2
1 3 4
1 1 4
1 3 2
0 1 3
1 2 4
1 3 0
0 0 4
1 0 2
1 3 0


Output

0
0
1
1
1
0
1
1

Solution (in JAVA):

Solution:
import java.util.Scanner;

public class Main {

    public static void main(String[] args) {
        
        Scanner sc = new Scanner(System.in);
        
        int n = Integer.parseInt(sc.next());
        int q = Integer.parseInt(sc.next());
        
        UnionFind uf = new UnionFind(n);
        StringBuilder sb = new StringBuilder();
        for(int i = 0; i < q; i++){
            if(Integer.parseInt(sc.next()) == 0){
                uf.unite(Integer.parseInt(sc.next()), Integer.parseInt(sc.next()));
            }else{
                if(uf.same(Integer.parseInt(sc.next()), Integer.parseInt(sc.next()))){
                    sb.append(1).append(System.lineSeparator());
                }else{
                    sb.append(0).append(System.lineSeparator());
                }
            }
        }
        
        System.out.print(sb);
    }
    
    static class UnionFind {
        int[] parent;
        int[] rank;
        
        public UnionFind(int n) {
            parent = new int[n];
            rank = new int[n];
            for(int i = 0; i < n; i++){
                parent[i] = i;
            }
        }
        int root(int x){
            if(parent[x] == x){
                return x;
            }else{
                return parent[x] = root(parent[x]);
            }
        }
        void unite(int x, int y){
            x = root(x);
            y = root(y);
            if(x == y) return;

            if(rank[x] < rank[y]){
                parent[x] = y;
            }else{
                parent[y] = x;
                if(rank[x] == rank[y]){
                    rank[x]++;
                }
            }
        }
        boolean same(int x, int y){
            return root(x) == root(y);
        }
    }
}