Problem: Write a program which manipulates a disjoint set S = {S1, S2, . . . , Sk}.

First of all, the program should read an integer n, then make a disjoint set where each element consists of 0, 1, ... n−1 respectively.

Next, the program should read an integer q and manipulate the set for q queries. There are two kinds of queries for different operations:

* unite(x, y): unites sets that contain x and y, say Sx and Sy, into a new set.
* same(x, y): determine whether x and y are in the same set.

Constraints

* 1 ≤ n ≤ 10000
* 1 ≤ q ≤ 100000
* x ≠ y

Input


n q
com1 x1 y1
com2 x2 y2
...
comq xq yq


In the first line, n and q are given. Then, q queries are given where com represents the type of queries. '0' denotes unite and '1' denotes same operation.

Output

For each same operation, print 1 if x and y are in the same set, otherwise 0, in a line.

Example

Input

5 12
0 1 4
0 2 3
1 1 2
1 3 4
1 1 4
1 3 2
0 1 3
1 2 4
1 3 0
0 0 4
1 0 2
1 3 0


Output

0
0
1
1
1
0
1
1

Solution (in PYTHON3):

Solution:
#=============================================================================
# DSL1_A
#=============================================================================
n,q=map(int,input().split())
parents=[i for i in range(n)]
deepth=[0 for _ in range(n)]

def find(x):
    if parents[x]==x:
        return x
    return find(parents[x])

def unite(x,y):
    px=find(x)
    py=find(y)
    if deepth[px]>deepth[py]:
        parents[py]=px
        deepth[px]=max(deepth[px],deepth[py]+1)
    else:
        parents[px]=py
        deepth[py]=max(deepth[py],deepth[px]+1)

def same(x,y):
    if find(x)==find(y):
        return True
    else:
        return False

for _ in range(q):
    com,x,y=map(int,input().split())
    if com==0:
        unite(x,y)
    if com==1:
        if same(x,y):
            print(1)
        else:
            print(0)