Problem: Create a program that rotates the pattern of 8 characters x 8 lines clockwise by 90 degrees, 180 degrees, and 270 degrees and outputs it.



Input

A pattern consisting of 8 characters x 8 lines is given. Characters consist of alphanumeric characters, half-width pound'#', and asterisk'*'.

Output

Output the rotated pattern in the following format.


90 (fixed half-width numbers)
Pattern rotated 90 degrees
180 (fixed half-width numbers)
180 degree rotated pattern
270 (fixed half-width numbers)
Pattern rotated 270 degrees


Examples

Input

#*******
#*******
#*******
#*******
#*******
#*******
#*******
########


Output

90
########
#*******
#*******
#*******
#*******
#*******
#*******
#*******
180
########
*******#
*******#
*******#
*******#
*******#
*******#
*******#
270
*******#
*******#
*******#
*******#
*******#
*******#
*******#
########


Input

*******
*******
*******
*******
*******
*******
*******


Output

90

*******
*******
*******
*******
*******
*******
*******
180

*******#
*******#
*******#
*******#
*******#
*******#
*******#
270
*******#
*******#
*******#
*******#
*******#
*******#
*******#

Solution (in CPP):

Solution:
#include<iostream>
using namespace std;

int main(){
  char p[8][9];
  char p90[8][9],p180[8][9],p270[8][9];
  int i,j;

  for(i=0;i<8;i++)scanf("%s",p[i]);

  for(i=0;i<8;i++){
    for(j=0;j<8;j++){
      p90[i][j] = p[7-j][i];
      p180[i][j] = p[7-i][7-j];
      p270[i][j] = p[j][7-i];
    }
  }
  for(i=0;i<8;i++){
    p90[i][8] = '\0';
    p180[i][8] = '\0';
    p270[i][8] = '\0';
  }
  cout << "90" << endl;
  for(i=0;i<8;i++)printf("%s\n",p90[i]);
  cout << "180" << endl;
  for(i=0;i<8;i++)printf("%s\n",p180[i]);
  cout << "270" << endl;
  for(i=0;i<8;i++)printf("%s\n",p270[i]);

  return 0;
}