Problem: Write a program which manipulates a disjoint set S = {S1, S2, . . . , Sk}.

First of all, the program should read an integer n, then make a disjoint set where each element consists of 0, 1, ... n−1 respectively.

Next, the program should read an integer q and manipulate the set for q queries. There are two kinds of queries for different operations:

* unite(x, y): unites sets that contain x and y, say Sx and Sy, into a new set.
* same(x, y): determine whether x and y are in the same set.

Constraints

* 1 ≤ n ≤ 10000
* 1 ≤ q ≤ 100000
* x ≠ y

Input


n q
com1 x1 y1
com2 x2 y2
...
comq xq yq


In the first line, n and q are given. Then, q queries are given where com represents the type of queries. '0' denotes unite and '1' denotes same operation.

Output

For each same operation, print 1 if x and y are in the same set, otherwise 0, in a line.

Example

Input

5 12
0 1 4
0 2 3
1 1 2
1 3 4
1 1 4
1 3 2
0 1 3
1 2 4
1 3 0
0 0 4
1 0 2
1 3 0


Output

0
0
1
1
1
0
1
1

Solution (in CPP):

Solution:
#include<iostream>
using namespace std;

int n,q;
int tree[10000];
void init(){
  for(int i=0;i<n;i++){
    tree[i]=i;
  }
}
int root(int x){
  if(tree[x]==x) return x;
  return tree[x]=root(tree[x]);
}
void unite(int x,int y){
  x=root(x);
  y=root(y);
  if(x==y)return;
  tree[x]=y;
}
int same(int x,int y){
  return root(x)==root(y);
}
int main(){
  cin>>n>>q;
  init();
  int com,x,y;
  for(int i=0;i<q;i++){
    cin>>com>>x>>y;
    if(com==0) unite(x,y);
    else cout<<same(x,y)<<"\n";
  }
}