Problem: Write a program which manipulates a disjoint set S = {S1, S2, . . . , Sk}.

First of all, the program should read an integer n, then make a disjoint set where each element consists of 0, 1, ... n−1 respectively.

Next, the program should read an integer q and manipulate the set for q queries. There are two kinds of queries for different operations:

* unite(x, y): unites sets that contain x and y, say Sx and Sy, into a new set.
* same(x, y): determine whether x and y are in the same set.

Constraints

* 1 ≤ n ≤ 10000
* 1 ≤ q ≤ 100000
* x ≠ y

Input


n q
com1 x1 y1
com2 x2 y2
...
comq xq yq


In the first line, n and q are given. Then, q queries are given where com represents the type of queries. '0' denotes unite and '1' denotes same operation.

Output

For each same operation, print 1 if x and y are in the same set, otherwise 0, in a line.

Example

Input

5 12
0 1 4
0 2 3
1 1 2
1 3 4
1 1 4
1 3 2
0 1 3
1 2 4
1 3 0
0 0 4
1 0 2
1 3 0


Output

0
0
1
1
1
0
1
1

Solution (in CPP):

Solution:
#include<iostream>
using namespace std;
const int MAX = 100000;
int n,U[MAX];
void init()
{
	for (int i = 0; i < n; i++)
		U[i] = i;
}
int getAncestor(int v)
{
	if (U[v] == v)
		return v;
	else
	{
		U[v] = getAncestor(U[v]);
		return U[v];
	}
}
void unite(int s, int t)
{
	int a1 = getAncestor(s);
	int a2 = getAncestor(t);
	if (a1 != a2)
		U[a2] = a1;
}
int same(int s, int t)
{
	return getAncestor(s) == getAncestor(t);
}
int main()
{
	int q;
	cin >> n >> q;
	init();
	for (int i = 0; i < q; i++)
	{
		int com, s, t;
		cin >> com >> s >> t;
		if (com == 0)
			unite(s, t);
		else if (com == 1)
			cout << same(s, t) << endl;
	}
}