Problem: Write a program which manipulates a disjoint set S = {S1, S2, . . . , Sk}.

First of all, the program should read an integer n, then make a disjoint set where each element consists of 0, 1, ... n−1 respectively.

Next, the program should read an integer q and manipulate the set for q queries. There are two kinds of queries for different operations:

* unite(x, y): unites sets that contain x and y, say Sx and Sy, into a new set.
* same(x, y): determine whether x and y are in the same set.

Constraints

* 1 ≤ n ≤ 10000
* 1 ≤ q ≤ 100000
* x ≠ y

Input


n q
com1 x1 y1
com2 x2 y2
...
comq xq yq


In the first line, n and q are given. Then, q queries are given where com represents the type of queries. '0' denotes unite and '1' denotes same operation.

Output

For each same operation, print 1 if x and y are in the same set, otherwise 0, in a line.

Example

Input

5 12
0 1 4
0 2 3
1 1 2
1 3 4
1 1 4
1 3 2
0 1 3
1 2 4
1 3 0
0 0 4
1 0 2
1 3 0


Output

0
0
1
1
1
0
1
1

Solution (in CPP):

Solution:
#include<iostream>
#include<vector>
using namespace std;
class UnionFind{
  vector<int> node;
 public:
  UnionFind(int n):node(n){
    for(int i = 0;i < n;i++){
      node[i] = i;
    }
  }
  int root(int x){
    if(node[x] == x)return x;
    return node[x] = root(node[x]);
  }
  void unite(int x,int y){
    node[root(x)] = root(y);
  }
  bool same(int x,int y){
    return root(x) == root(y);
  }
};
int main(){
  int n,q;
  cin >> n >> q;
  UnionFind u(n);
  for(int i = 0;i < q;i++){
    int com,x,y;
    cin >> com >> x >> y;
    if(com == 0){
      u.unite(x,y);
    }else{
      cout << (int)u.same(x,y) << endl;
    }
  }
}