Problem: You are given a number n and an array b_1, b_2, …, b_{n+2}, obtained according to the following algorithm: 

  * some array a_1, a_2, …, a_n was guessed; 
  * array a was written to array b, i.e. b_i = a_i (1 ≤ i ≤ n); 
  * The (n+1)-th element of the array b is the sum of the numbers in the array a, i.e. b_{n+1} = a_1+a_2+…+a_n; 
  * The (n+2)-th element of the array b was written some number x (1 ≤ x ≤ 10^9), i.e. b_{n+2} = x; The 
  * array b was shuffled. 



For example, the array b=[2, 3, 7, 12 ,2] it could be obtained in the following ways: 

  * a=[2, 2, 3] and x=12; 
  * a=[3, 2, 7] and x=2. 



For the given array b, find any array a that could have been guessed initially.

Input

The first line contains a single integer t (1 ≤ t ≤ 10^4). Then t test cases follow.

The first line of each test case contains a single integer n (1 ≤ n ≤ 2 ⋅ 10^5).

The second row of each test case contains n+2 integers b_1, b_2, …, b_{n+2} (1 ≤ b_i ≤ 10^9).

It is guaranteed that the sum of n over all test cases does not exceed 2 ⋅ 10^5.

Output

For each test case, output: 

  * "-1", if the array b could not be obtained from any array a; 
  * n integers a_1, a_2, …, a_n, otherwise. 



If there are several arrays of a, you can output any.

Example

Input


4
3
2 3 7 12 2
4
9 1 7 1 6 5
5
18 2 2 3 2 9 2
3
2 6 9 2 1


Output


2 3 7 
-1
2 2 2 3 9 
1 2 6 

Solution (in CPP):

Solution:
#include<bits/stdc++.h>
using namespace std;
int main()
{
    long long int t;
    cin>>t;
    while(t--)
    {
        long long int n,i;
        cin>>n;
        long long int b[n+2];
        for(i=0;i<n+2;i++)
        cin>>b[i];
        sort(b,b+(n+2));
        long long int sum=0;
        for(i=0;i<n;i++)
        sum+=b[i];
        if(sum==b[n])
        {
            for(i=0;i<n;i++)
            cout<<b[i]<<" ";
            cout<<'\n';
        }
        else
        {
            int temp=0;
            sum=0;
            for(i=0;i<n+1;i++)
            sum+=b[i];
            for(i=0;i<n+1;i++)
            {
                if((sum-b[i])==b[n+1])
                {
                    b[i]=-1;
                    temp=1;
                    break;
                }
                
            }
            if(temp)
            {
            for(i=0;i<n+1;i++)
            {
                if(b[i]==-1)
                continue;
                else
                cout<<b[i]<<" ";
            }
            cout<<"\n";
            }
            else
            cout<<"-1"<<"\n";
            
        }
        
    }
    return 0;
}