Problem: You are given a string s, consisting of brackets of two types: '(', ')', '[' and ']'.

A string is called a regular bracket sequence (RBS) if it's of one of the following types: 

  * empty string; 
  * '(' + RBS + ')'; 
  * '[' + RBS + ']'; 
  * RBS + RBS. 



where plus is a concatenation of two strings.

In one move you can choose a non-empty subsequence of the string s (not necessarily consecutive) that is an RBS, remove it from the string and concatenate the remaining parts without changing the order.

What is the maximum number of moves you can perform?

Input

The first line contains a single integer t (1 ≤ t ≤ 1000) — the number of testcases.

Each of the next t lines contains a non-empty string, consisting only of characters '(', ')', '[' and ']'. The total length of the strings over all testcases doesn't exceed 2 ⋅ 10^5.

Output

For each testcase print a single integer — the maximum number of moves you can perform on a given string s.

Example

Input


5
()
[]()
([)]
)]([
)[(]


Output


1
2
2
0
1

Note

In the first example you can just erase the whole string.

In the second example you can first erase the brackets on positions 1 and 2: "[]()", then "()" is left. After that you can erase it whole. You could erase the whole string from the beginning but you would get one move instead of two.

In the third example you can first erase the brackets on positions 1 and 3: "([)]". They form an RBS "()". Then "[]" is left, so you can erase it whole.

In the fourth example there is no subsequence that is an RBS, so you can't perform a move at all.

In the fifth example you can erase the brackets on positions 2 and 4: ")[(]" and get ")(" as a result. You can erase nothing from it.

Solution (in PYTHON3):

Solution:
import sys
import os
import math
import copy
from bisect import bisect
from io import BytesIO, IOBase
from math import sqrt,floor,factorial,gcd,log,ceil
from collections import deque,Counter,defaultdict
from itertools import permutations,combinations,accumulate

def Int():               return int(sys.stdin.readline())
def Mint():              return map(int,sys.stdin.readline().split())
def Lstr():              return list(sys.stdin.readline().strip())
def Str():               return sys.stdin.readline().strip()
def Mstr():              return map(str,sys.stdin.readline().strip().split())
def List():              return list(map(int,sys.stdin.readline().split()))
def Hash():              return dict()
def Mod():               return 1000000007
def Mat2x2(n):           return [List() for _ in range(n)]
def Lcm(x,y):            return (x*y)//gcd(x,y)
def dtob(n):             return bin(n).replace("0b","")
def btod(n):             return int(n,2) 
def watch(x):            return print(x)
def common(l1, l2):      return set(l1).intersection(l2)
def Most_frequent(list): return max(set(list), key = list.count)
   
def solution():
     for _ in range(Int()):
          s=Lstr()
          c=0
          a=[]
          b=[]
          for i in range(len(s)):
               if(s[i]=='('):
                    a.append('(')
               elif(s[i]==')' and len(a)>0):
                    a.pop()
                    c+=1
               if(s[i]=='['):
                    b.append('(')
               elif(s[i]==']' and len(b)>0):
                    b.pop()
                    c+=1
                    
          print(c)
               
          
          
if __name__ == "__main__":
     solution()