Problem: Write a program which manipulates a disjoint set S = {S1, S2, . . . , Sk}.

First of all, the program should read an integer n, then make a disjoint set where each element consists of 0, 1, ... n−1 respectively.

Next, the program should read an integer q and manipulate the set for q queries. There are two kinds of queries for different operations:

* unite(x, y): unites sets that contain x and y, say Sx and Sy, into a new set.
* same(x, y): determine whether x and y are in the same set.

Constraints

* 1 ≤ n ≤ 10000
* 1 ≤ q ≤ 100000
* x ≠ y

Input


n q
com1 x1 y1
com2 x2 y2
...
comq xq yq


In the first line, n and q are given. Then, q queries are given where com represents the type of queries. '0' denotes unite and '1' denotes same operation.

Output

For each same operation, print 1 if x and y are in the same set, otherwise 0, in a line.

Example

Input

5 12
0 1 4
0 2 3
1 1 2
1 3 4
1 1 4
1 3 2
0 1 3
1 2 4
1 3 0
0 0 4
1 0 2
1 3 0


Output

0
0
1
1
1
0
1
1

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;

int par[111111];
int rnk[111111];
int n,m;

int root(int a){
	return par[a]!=a?root(par[a]):a;
}

void unite(int a,int b){
	if(rnk[a]<rnk[b]) swap(a,b);
	par[root(a)] =  root(b);
	rnk[root(b)] += rnk[root(a)];
}

int main(){
	for(int i=0;i<111111;i++)par[i]=i;
	cin>>n>>m;
	while(m--){
		int a,b,c;
		cin>>a>>b>>c;
		if(a) cout<<(root(b)==root(c))<<'\n';
		else if(root(b)!=root(c)) unite(b,c);
	}
}