Problem: Write a program which manipulates a disjoint set S = {S1, S2, . . . , Sk}.

First of all, the program should read an integer n, then make a disjoint set where each element consists of 0, 1, ... n−1 respectively.

Next, the program should read an integer q and manipulate the set for q queries. There are two kinds of queries for different operations:

* unite(x, y): unites sets that contain x and y, say Sx and Sy, into a new set.
* same(x, y): determine whether x and y are in the same set.

Constraints

* 1 ≤ n ≤ 10000
* 1 ≤ q ≤ 100000
* x ≠ y

Input


n q
com1 x1 y1
com2 x2 y2
...
comq xq yq


In the first line, n and q are given. Then, q queries are given where com represents the type of queries. '0' denotes unite and '1' denotes same operation.

Output

For each same operation, print 1 if x and y are in the same set, otherwise 0, in a line.

Example

Input

5 12
0 1 4
0 2 3
1 1 2
1 3 4
1 1 4
1 3 2
0 1 3
1 2 4
1 3 0
0 0 4
1 0 2
1 3 0


Output

0
0
1
1
1
0
1
1

Solution (in PYTHON3):

Solution:
n, q = map(int,input().split())
queries = []
for _ in range(q):
    com, x, y = map(int,input().split())
    queries.append((com, x, y))

joining = [[x] for x in range(n)]

def unite(x, y):
    if joining[x] == joining[y]:
        return
    joining[x] += joining[y]
    for member in joining[y]:
        joining[member] = joining[x]

def is_same(x, y):
    return joining[x] == joining[y]

answers = []
for query in queries:
    if query[0] == 0:
        unite(query[1], query[2])
    else:
        answers.append(is_same(query[1], query[2]))

for answer in answers:
    if answer:
        print(1)
    else:
        print(0)