Problem: It is November 18 now in Japan. By the way, 11 and 18 are adjacent Lucas numbers.

You are given an integer N. Find the N-th Lucas number.

Here, the i-th Lucas number L_i is defined as follows:

* L_0=2
* L_1=1
* L_i=L_{i-1}+L_{i-2} (i≥2)

Constraints

* 1≤N≤86
* It is guaranteed that the answer is less than 10^{18}.
* N is an integer.

Input

Input is given from Standard Input in the following format:


N


Output

Print the N-th Lucas number.

Examples

Input

5


Output

11


Input

86


Output

939587134549734843

Solution (in JAVA):

Solution:
import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int N = sc.nextInt();

        long[] Lucas = new long[N + 1];

        for (int i = 0; i < Lucas.length; i++) {
            if (i == 0) {
                Lucas[i] = 2;
            }else if (i == 1) {
                Lucas[i] = 1;
            }else{
                Lucas[i] = Lucas[i-2] + Lucas[i - 1];
            }
        }
        System.out.println(Lucas[N]);
    }
}