Problem: Create a program that rotates the pattern of 8 characters x 8 lines clockwise by 90 degrees, 180 degrees, and 270 degrees and outputs it.



Input

A pattern consisting of 8 characters x 8 lines is given. Characters consist of alphanumeric characters, half-width pound'#', and asterisk'*'.

Output

Output the rotated pattern in the following format.


90 (fixed half-width numbers)
Pattern rotated 90 degrees
180 (fixed half-width numbers)
180 degree rotated pattern
270 (fixed half-width numbers)
Pattern rotated 270 degrees


Examples

Input

#*******
#*******
#*******
#*******
#*******
#*******
#*******
########


Output

90
########
#*******
#*******
#*******
#*******
#*******
#*******
#*******
180
########
*******#
*******#
*******#
*******#
*******#
*******#
*******#
270
*******#
*******#
*******#
*******#
*******#
*******#
*******#
########


Input

*******
*******
*******
*******
*******
*******
*******


Output

90

*******
*******
*******
*******
*******
*******
*******
180

*******#
*******#
*******#
*******#
*******#
*******#
*******#
270
*******#
*******#
*******#
*******#
*******#
*******#
*******#

Solution (in CPP):

Solution:
#include <stdio.h>

#define N 8

int main(void){
    char buf[N+1];
    char ptn[N][N];
    
    for (int y=0; y<N; y++){
        scanf("%s", buf);
        for (int x=0; x<N; x++){
            ptn[x][y]=buf[x];
        }
    }
    
    puts("90");
    for (int y=0; y<N; y++){
        for (int x=0; x<N; x++){
            printf("%c",ptn[y][N-1-x]);
        }
        printf("\n");
    }
    puts("180");
    for (int y=0; y<N; y++){
        for (int x=0; x<N; x++){
            printf("%c",ptn[N-1-x][N-1-y]);
        }
        printf("\n");
    }
    puts("270");
    for (int y=0; y<N; y++){
        for (int x=0; x<N; x++){
            printf("%c",ptn[N-1-y][x]);
        }
        printf("\n");
    }
    
    
    return 0;
}