Problem: You are given a tree consisting of n vertices. A tree is a connected undirected graph with n-1 edges. Each vertex v of this tree has a color assigned to it (a_v = 1 if the vertex v is white and 0 if the vertex v is black).

You have to solve the following problem for each vertex v: what is the maximum difference between the number of white and the number of black vertices you can obtain if you choose some subtree of the given tree that contains the vertex v? The subtree of the tree is the connected subgraph of the given tree. More formally, if you choose the subtree that contains cnt_w white vertices and cnt_b black vertices, you have to maximize cnt_w - cnt_b.

Input

The first line of the input contains one integer n (2 ≤ n ≤ 2 ⋅ 10^5) — the number of vertices in the tree.

The second line of the input contains n integers a_1, a_2, ..., a_n (0 ≤ a_i ≤ 1), where a_i is the color of the i-th vertex.

Each of the next n-1 lines describes an edge of the tree. Edge i is denoted by two integers u_i and v_i, the labels of vertices it connects (1 ≤ u_i, v_i ≤ n, u_i ≠ v_i).

It is guaranteed that the given edges form a tree.

Output

Print n integers res_1, res_2, ..., res_n, where res_i is the maximum possible difference between the number of white and black vertices in some subtree that contains the vertex i.

Examples

Input


9
0 1 1 1 0 0 0 0 1
1 2
1 3
3 4
3 5
2 6
4 7
6 8
5 9


Output


2 2 2 2 2 1 1 0 2 


Input


4
0 0 1 0
1 2
1 3
1 4


Output


0 -1 1 -1 

Note

The first example is shown below:

<image>

The black vertices have bold borders.

In the second example, the best subtree for vertices 2, 3 and 4 are vertices 2, 3 and 4 correspondingly. And the best subtree for the vertex 1 is the subtree consisting of vertices 1 and 3.

Solution (in PYTHON3):

Solution:
import sys
import os
from io import BytesIO, IOBase
BUFSIZE = 8192

class Tree():
    def __init__(self, n, decrement=1):
        self.n = n
        self.edges = [[] for _ in range(n)]
        self.root = None
        self.size = [1]*n       # number of nodes in subtree
        self.decrement = decrement

    def add_edge(self, u, v):
        u, v = u-self.decrement, v-self.decrement
        self.edges[u].append(v)
        self.edges[v].append(u)

    def add_edges(self, edges):
        for u, v in edges:
            u, v = u-self.decrement, v-self.decrement
            self.edges[u].append(v)
            self.edges[v].append(u)

    def set_root(self, root):
        root -= self.decrement
        self.depth = [-1]*self.n
        self.root = root
        self.par = [-1]*self.n
        self.depth[root] = 0
        self.order = [root]     # the way back
        next_set = [root]
        while next_set:
            p = next_set.pop()
            for q in self.edges[p]:
                if self.depth[q] != -1: continue
                self.par[q] = p
                self.depth[q] = self.depth[p]+1
                self.order.append(q)
                next_set.append(q)
        for p in self.order[::-1]:
            for q in self.edges[p]:
                if self.par[p] == q: continue
                self.size[p] += self.size[q]

    def rerooting(self, op, merge, id):
        # assert self.root is not None
        dp1 = [id] * self.n
        dp2 = [id] * self.n
        for p in self.order[::-1]:
            t = id
            for q in self.edges[p]:
                if self.par[p] == q: continue
                dp2[q] = t
                t = merge(t, op(dp1[q], p, q))
            t = id
            for q in self.edges[p][::-1]:
                if self.par[p] == q: continue
                dp2[q] = merge(t, dp2[q])
                t = merge(t, op(dp1[q], p, q))
            dp1[p] = t
        for q in self.order[1:]:
            pq = self.par[q]
            dp2[q] = op(merge(dp2[q], dp2[pq]), q, pq)
            dp1[q] = merge(dp1[q], dp2[q])
        return dp1

class FastIO(IOBase):
    newlines = 0

    def __init__(self, file):
        self._fd = file.fileno()
        self.buffer = BytesIO()
        self.writable = "x" in file.mode or "r" not in file.mode
        self.write = self.buffer.write if self.writable else None

    def read(self):
        while True:
            b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
            if not b:
                break
            ptr = self.buffer.tell()
            self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
        self.newlines = 0
        return self.buffer.read()

    def readline(self):
        while self.newlines == 0:
            b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
            self.newlines = b.count(b"\n") + (not b)
            ptr = self.buffer.tell()
            self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
        self.newlines -= 1
        return self.buffer.readline()

    def flush(self):
        if self.writable:
            os.write(self._fd, self.buffer.getvalue())
            self.buffer.truncate(0), self.buffer.seek(0)


class IOWrapper(IOBase):
    def __init__(self, file):
        self.buffer = FastIO(file)
        self.flush = self.buffer.flush
        self.writable = self.buffer.writable
        self.write = lambda s: self.buffer.write(s.encode("ascii"))
        self.read = lambda: self.buffer.read().decode("ascii")
        self.readline = lambda: self.buffer.readline().decode("ascii")

#########################################################################################################
sys.stdin = IOWrapper(sys.stdin)
input = sys.stdin.readline

N = int(input())
T = Tree(N)
C = list(map(int, input().split()))
for _ in range(N-1):
    x, y = map(int, input().split())
    T.add_edge(x,y)
T.set_root(1)

##########################################################
def op(a, p, q):
    return max(a + 2*C[q]-1, 0)

def merge(a, b):
    return a+b

id = 0
##########################################################


dp = T.rerooting(op, merge, id)
res = [""]*N
for i in range(N):
    res[i] = str(dp[i]+ 2*C[i]-1)

print(" ".join(res))