Problem: For given n points in metric space, find the distance of the closest points.

Constraints

* 2 ≤ n ≤ 100,000
* -100 ≤ x, y ≤ 100

Input


n
x0 y0
x1 y1
:
xn-1 yn-1


The first integer n is the number of points.

In the following n lines, the coordinate of the i-th point is given by two real numbers xi and yi. Each value is a real number with at most 6 digits after the decimal point.

Output

Print the distance in a line. The output values should be in a decimal fraction with an error less than 0.000001.

Examples

Input

2
0.0 0.0
1.0 0.0


Output

1.000000


Input

3
0.0 0.0
2.0 0.0
1.0 1.0


Output

1.41421356237

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
#define ll long long
#define INF 1000000005
#define MOD 1000000007
#define EPS 1e-10
#define rep(i,n) for(int i=0;i<n;++i)

using namespace std;

typedef complex<double> C;

namespace std
{
    bool operator < (const C& a, const C& b) {
        return real(a) != real(b) ? real(a) < real(b) : imag(a) < imag(b);
    }
}

struct L : public vector<C>
{
    L(const C &a, const C &b) {
        push_back(a); push_back(b);
    }
};

//??????
double cross(const C& a, const C& b)
{
    return imag(conj(a)*b);
}
//??????
double dot(const C& a, const C& b)
{
    return real(conj(a)*b);
}


int ccw(C a, C b, C c)
{
    b -= a; c -= a;
    if (cross(b, c) > 0)   return +1;       // counter clockwise
    if (cross(b, c) < 0)   return -1;       // clockwise
    if (dot(b, c) < 0)     return +2;       // c--a--b on line
    if (norm(b) < norm(c)) return -2;       // a--b--c on line
    return 0;
}
//??´???????????????????????????(????????´??????True)
bool intersectLL(const L &l, const L &m)
{
    return abs(cross(l[1]-l[0], m[1]-m[0])) > EPS || abs(cross(l[1]-l[0], m[0]-l[0])) < EPS;
}
//??´?????¨?????????????????????(????????±??????????????¨??????)
bool intersectLS(const L &l, const L &s)
{
    return cross(l[1]-l[0], s[0]-l[0]) * cross(l[1]-l[0], s[1]-l[0]) < EPS;
}
//??´?????¨????????????(??±???)??????
bool intersectLP(const L &l, const C &p)
{
    return abs(cross(l[1]-p, l[0]-p)) < EPS;
}
//??????????????????????????????(????????±??????????????¨??????)
bool intersectSS(const L &s, const L &t)
{
    return ccw(s[0],s[1],t[0])*ccw(s[0],s[1],t[1]) <= 0 && ccw(t[0],t[1],s[0])*ccw(t[0],t[1],s[1]) <= 0;
}
//????????¨????????????(??±???)??????
bool intersectSP(const L &s, const C &p)
{
    return abs(s[0]-p)+abs(s[1]-p)-abs(s[1]-s[0]) < EPS;
}
//???p?????´???l???????°???±
C projection(const L &l, const C &p)
{
    double t = dot(p-l[0], l[0]-l[1]) / norm(l[0]-l[1]);
    return l[0] + t*(l[0]-l[1]);
}
//???p?????´???l????????¨??????????§°?§????
C reflection(const L &l, const C &p)
{
    return p + (projection(l, p) - p)*2.0;
}
//?????¨??´???????????¢
double distanceLP(const L &l, const C &p)
{
    return abs(p - projection(l, p));
}
//??´?????¨??´???????????¢
double distanceLL(const L &l, const L &m)
{
    return intersectLL(l, m) ? 0 : distanceLP(l, m[0]);
}
//??´?????¨??????????????¢
double distanceLS(const L &l, const L &s)
{
    if (intersectLS(l, s)) return 0;
    return min(distanceLP(l, s[0]), distanceLP(l, s[1]));
}
//????????¨???????????¢
double distanceSP(const L &s, const C &p)
{
    const C r = projection(s, p);
    if (intersectSP(s, r)) return abs(r - p);
    return min(abs(s[0] - p), abs(s[1] - p));
}
//????????¨??????????????¢
double distanceSS(const L &s, const L &t)
{
    if (intersectSS(s, t)) return 0;
    return min(min(distanceSP(s, t[0]), distanceSP(s, t[1])),min(distanceSP(t, s[0]), distanceSP(t, s[1])));
}
//??´???????????????????????????
C crosspoint(const L &l, const L &m)
{
    double A = cross(l[1] - l[0], m[1] - m[0]);
    double B = cross(l[1] - l[0], l[1] - m[0]);
    //????????´????????¨???
    if(abs(A) < EPS && abs(B) < EPS){
        return m[0];
    }
    return m[0] + B / A * (m[1] - m[0]);
}
//?????????????????????
L crosspointSS(C &p1,int r1,C &p2,int r2)
{
    double d = norm(p2-p1);
    double t = r2*r2 - r1*r1 - d;
    double aa = d,bb = t*(real(p2)-real(p1)),cc = t*t / 4.0 - (imag(p2) - imag(p1))*(imag(p2) - imag(p1))*r1*r1;
    double x1 = (-bb - sqrt(bb*bb - 4*aa*cc))/(2*aa),x2 = (-bb + sqrt(bb*bb - 4*aa*cc))/(2*aa);
    double y1,y2;
    if(imag(p1) == imag(p2)){
        y1 = -sqrt(r1*r1 - x1*x1);
        y2 = -y1;
    }else{
        y1 = (t+2*(real(p2)-real(p1))*x1)/(-2*(imag(p2)-imag(p1)));
        y2 = (t+2*(real(p2)-real(p1))*x2)/(-2*(imag(p2)-imag(p1)));
    }
    L ln = L(C(x1+real(p1),y1+imag(p1)),C(x2+real(p1),y2+imag(p1)));
    return ln;
}
//??????????±???????
vector<C> convex_hull(vector<C> ps)
{
    int n = ps.size(), k = 0;
    sort(ps.begin(), ps.end());
    vector<C> ch(2*n);
    for (int i = 0; i < n; ch[k++] = ps[i++]){
        while (k >= 2 && ccw(ch[k-2], ch[k-1], ps[i]) <= 0) k--;
    }
    for (int i = n-2, t = k+1; i >= 0; ch[k++] = ps[i--]){
        while (k >= t && ccw(ch[k-2], ch[k-1], ps[i]) <= 0) k--;
    }
    ch.resize(k-1);
    return ch;
}
//?????§??????
bool isconvex(const vector<C> &ps)
{
    rep(i,ps.size()){
        if (ccw(ps[(i+ps.size()-1) % ps.size()],ps[i],ps[(i+1) % ps.size()])) return false;
    }
    return true;
}
//????§???¢?????¢???
double area(const vector<C> &ps)
{
    double A = 0;
    rep(i,ps.size()){
        A += cross(ps[i],ps[(i+1) % ps.size()]);
    }
    return A / 2.0;
}
//???????§???¢?????´?????§???????????????????????´????????¢
vector<C> convex_cut(const vector<C> &ps, const L &l)
{
    vector<C> Q;
    rep(i,ps.size()){
        C A = ps[i], B = ps[(i+1)%ps.size()];
        if (ccw(l[0], l[1], A) != -1) Q.push_back(A);
        if (ccw(l[0], l[1], A)*ccw(l[0], l[1], B) < 0)
            Q.push_back(crosspoint(L(A, B), l));
    }
    return Q;
}
//??????????§???¢???????????????????????????(0??????????????????,1?????????,2???????????????)
int contains(const vector<C>& ps, const C& p)
{
    bool flag = false;
    rep(i,ps.size()) {
        C a = ps[i] - p, b = ps[(i+1)%ps.size()] - p;
        if (imag(a) > imag(b)) swap(a, b);
        if (imag(a) <= 0 && 0 < imag(b)){
            if (cross(a, b) < 0) flag = !flag;
        }
        if (cross(a, b) == 0 && dot(a, b) <= 0) return 1;
  }
  return flag ? 2 : 0;
}
//???????§???¢?????´???????±???????(?????£????????????)
//maxi,maxj?????????????????¨??????
double convex_diameter(const vector<C> &ps)
{
    const int n = ps.size();
    int is = 0, js = 0;
    for (int i = 1; i < n; ++i) {
        if (imag(ps[i]) > imag(ps[is])) is = i;
        if (imag(ps[i]) < imag(ps[js])) js = i;
    }
    double maxd = abs(ps[is]-ps[js]);
    int i, maxi, j, maxj;
    i = maxi = is;
    j = maxj = js;
    do{
        if (cross(ps[(i+1)%ps.size()]-ps[i],ps[(j+1)%ps.size()]-ps[j]) >= 0) j = (j+1) % n;
        else i = (i+1) % n;
        if (abs(ps[i]-ps[j]) > maxd) {
            maxd = abs(ps[i]-ps[j]);
            maxi = i; maxj = j;
        }
    } while (i != is || j != js);
    return maxd;
}

double closest_pair(C *a, int n){
    if(n<=1) return INF;
    int m=n/2;
    double x=a[m].real();
    double d=min(closest_pair(a,m),closest_pair(a+m,n-m));
    inplace_merge(a,a+m,a+n,[](C c1,C c2){return c1.imag() != c2.imag() ? c1.imag() < c2.imag() : c1.real() < c2.real();});
    vector<C> b;
    rep(i,n){
        if(abs(x-a[i].real())>=d) continue;
        rep(j,b.size()){
            C dp=a[i]-b[b.size()-1-j];
            if(dp.imag()>=d) break;
            d=min(d,abs(dp));
        }
        b.push_back(a[i]);
    }
    return d;
}
double compute_shortest(C *a,int n){
    sort(a,a+n);
    return closest_pair(a,n);
}

int main()
{
    int n;
    cin >> n;
    C p[100005];
    rep(i,n){
        double x,y;
        cin >> x >> y;
        p[i] = C(x,y);
    }
    printf("%.10f\n",compute_shortest(p,n));
}