Problem: Write a program which manipulates a disjoint set S = {S1, S2, . . . , Sk}.

First of all, the program should read an integer n, then make a disjoint set where each element consists of 0, 1, ... n−1 respectively.

Next, the program should read an integer q and manipulate the set for q queries. There are two kinds of queries for different operations:

* unite(x, y): unites sets that contain x and y, say Sx and Sy, into a new set.
* same(x, y): determine whether x and y are in the same set.

Constraints

* 1 ≤ n ≤ 10000
* 1 ≤ q ≤ 100000
* x ≠ y

Input


n q
com1 x1 y1
com2 x2 y2
...
comq xq yq


In the first line, n and q are given. Then, q queries are given where com represents the type of queries. '0' denotes unite and '1' denotes same operation.

Output

For each same operation, print 1 if x and y are in the same set, otherwise 0, in a line.

Example

Input

5 12
0 1 4
0 2 3
1 1 2
1 3 4
1 1 4
1 3 2
0 1 3
1 2 4
1 3 0
0 0 4
1 0 2
1 3 0


Output

0
0
1
1
1
0
1
1

Solution (in PYTHON):

Solution:
class node:
    def __init__(self,parent):
        self.parent=parent

def findset(x):
    global nodes
    if nodes[x].parent==x:
        return x
    else:
        nodes[x].parent=findset(nodes[x].parent)
        return nodes[x].parent

def unite(x,y):
    global rank,nodes
    findset(x)
    findset(y)
    if rank[nodes[x].parent]<rank[nodes[y].parent]:
        nodes[nodes[x].parent].parent=nodes[nodes[y].parent].parent
    elif rank[nodes[x].parent]==rank[nodes[y].parent]:
        nodes[nodes[x].parent].parent=nodes[nodes[y].parent].parent
        rank[y]+=1
    else:
        nodes[nodes[y].parent].parent=nodes[nodes[x].parent].parent

def same(x,y):
    global nodes
    findset(x)
    findset(y)
    if nodes[x].parent==nodes[y].parent:
        print(1)
    else:
        print(0)

n,q=map(int,raw_input().split())
rank=[0]*n
nodes=[]
for i in xrange(n):
    fac=node(i)
    nodes.append(fac)
for i in xrange(q):
    com,x,y=map(int,raw_input().split())
    if com==0:
        unite(x,y) 
    else:
        same(x,y)