Problem: Write a program which manipulates a disjoint set S = {S1, S2, . . . , Sk}.

First of all, the program should read an integer n, then make a disjoint set where each element consists of 0, 1, ... n−1 respectively.

Next, the program should read an integer q and manipulate the set for q queries. There are two kinds of queries for different operations:

* unite(x, y): unites sets that contain x and y, say Sx and Sy, into a new set.
* same(x, y): determine whether x and y are in the same set.

Constraints

* 1 ≤ n ≤ 10000
* 1 ≤ q ≤ 100000
* x ≠ y

Input


n q
com1 x1 y1
com2 x2 y2
...
comq xq yq


In the first line, n and q are given. Then, q queries are given where com represents the type of queries. '0' denotes unite and '1' denotes same operation.

Output

For each same operation, print 1 if x and y are in the same set, otherwise 0, in a line.

Example

Input

5 12
0 1 4
0 2 3
1 1 2
1 3 4
1 1 4
1 3 2
0 1 3
1 2 4
1 3 0
0 0 4
1 0 2
1 3 0


Output

0
0
1
1
1
0
1
1

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;

int par[10001], d[10001];
void init(int n){
	for(int i = 0;i < n;i++){
		par[i] = i;
		d[i] = 0;
	}
}

int find(int x){
	if(x == par[x])return x;
	return par[x] = find(par[x]);
}

void unite(int x, int y){
	x = find(x);
	y = find(y);
	if(x == y)return ;
	if(d[x] < d[y]){
		par[x] = y;
	}else{
		par[y] = x;
		if(d[x] == d[y])d[x]++;
	}
}

bool same(int x, int y){
	return find(x) == find(y);
}

int main(){
	int n, q, c, x, y;
	scanf("%d%d", &n, &q);
	init(n);
	
	for(int i = 0;i < q;i++){
		scanf("%d%d%d", &c, &x, &y);
		if(!c){
			unite(x, y);
		}else{
			printf("%d\n", same(x, y));
		}
	}
	return 0;
}