Problem: Write a program which manipulates a disjoint set S = {S1, S2, . . . , Sk}.

First of all, the program should read an integer n, then make a disjoint set where each element consists of 0, 1, ... n−1 respectively.

Next, the program should read an integer q and manipulate the set for q queries. There are two kinds of queries for different operations:

* unite(x, y): unites sets that contain x and y, say Sx and Sy, into a new set.
* same(x, y): determine whether x and y are in the same set.

Constraints

* 1 ≤ n ≤ 10000
* 1 ≤ q ≤ 100000
* x ≠ y

Input


n q
com1 x1 y1
com2 x2 y2
...
comq xq yq


In the first line, n and q are given. Then, q queries are given where com represents the type of queries. '0' denotes unite and '1' denotes same operation.

Output

For each same operation, print 1 if x and y are in the same set, otherwise 0, in a line.

Example

Input

5 12
0 1 4
0 2 3
1 1 2
1 3 4
1 1 4
1 3 2
0 1 3
1 2 4
1 3 0
0 0 4
1 0 2
1 3 0


Output

0
0
1
1
1
0
1
1

Solution (in CPP):

Solution:
#include<iostream>
using namespace std;

int P[10010];

void init(int N)
{
	for (int i=0; i<N; ++i) 
	    P[i] = i;
} 

int root(int a)
{
	if(P[a]==a)   
	   return a;
	else  return(P[a]=root(P[a]));
}
 
bool is_same_set(int a,int b)
{
	return(root(a)==root(b));
}

void unite(int a,int b)
{
	P[root(a)]=root(b);
}

int main()
{
	int n,q;
	cin >> n >> q;
	init(n);
	for(int i=0;i<q;i++)
	{
		int com,m,n;
		cin >> com >> m >> n;
		if(!com)
		   unite(m,n);
		else
			cout << is_same_set(m,n) << endl;	
	}
}