Problem: It is November 18 now in Japan. By the way, 11 and 18 are adjacent Lucas numbers.

You are given an integer N. Find the N-th Lucas number.

Here, the i-th Lucas number L_i is defined as follows:

* L_0=2
* L_1=1
* L_i=L_{i-1}+L_{i-2} (i≥2)

Constraints

* 1≤N≤86
* It is guaranteed that the answer is less than 10^{18}.
* N is an integer.

Input

Input is given from Standard Input in the following format:


N


Output

Print the N-th Lucas number.

Examples

Input

5


Output

11


Input

86


Output

939587134549734843

Solution (in JAVA):

Solution:
import java.util.Scanner;

public class Main {
	static int n;
	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		n = sc.nextInt();
		if(n == 0) {
			System.out.println(2);
			return;
		}
		if(n == 1) {
			System.out.println(1);
			return;
		}
		solve(2,1,2);
	}
	static void solve(long l1, long l2, int w) {
		if(w == n) {
			System.out.println(l2 + l1);
			return;
		}
		long li = l2 + l1;
		solve(l2, li, w+1);
	}
}