Problem: It is November 18 now in Japan. By the way, 11 and 18 are adjacent Lucas numbers.

You are given an integer N. Find the N-th Lucas number.

Here, the i-th Lucas number L_i is defined as follows:

* L_0=2
* L_1=1
* L_i=L_{i-1}+L_{i-2} (i≥2)

Constraints

* 1≤N≤86
* It is guaranteed that the answer is less than 10^{18}.
* N is an integer.

Input

Input is given from Standard Input in the following format:


N


Output

Print the N-th Lucas number.

Examples

Input

5


Output

11


Input

86


Output

939587134549734843

Solution (in CPP):

Solution:
#include <stdio.h>
int main(){
	long long n;
	scanf("%lld",&n);
	long long luc[n],i;
	luc[0]=2;
	luc[1]=1;
	for(i=2;i<=n;i++){
		luc[i]=luc[i-1]+luc[i-2];
		}
	printf("%lld",luc[n]);
	return 0;
}