Problem: Write a program which manipulates a disjoint set S = {S1, S2, . . . , Sk}.

First of all, the program should read an integer n, then make a disjoint set where each element consists of 0, 1, ... n−1 respectively.

Next, the program should read an integer q and manipulate the set for q queries. There are two kinds of queries for different operations:

* unite(x, y): unites sets that contain x and y, say Sx and Sy, into a new set.
* same(x, y): determine whether x and y are in the same set.

Constraints

* 1 ≤ n ≤ 10000
* 1 ≤ q ≤ 100000
* x ≠ y

Input


n q
com1 x1 y1
com2 x2 y2
...
comq xq yq


In the first line, n and q are given. Then, q queries are given where com represents the type of queries. '0' denotes unite and '1' denotes same operation.

Output

For each same operation, print 1 if x and y are in the same set, otherwise 0, in a line.

Example

Input

5 12
0 1 4
0 2 3
1 1 2
1 3 4
1 1 4
1 3 2
0 1 3
1 2 4
1 3 0
0 0 4
1 0 2
1 3 0


Output

0
0
1
1
1
0
1
1

Solution (in PYTHON3):

Solution:
maxn = 100000

n , q = map(int, input().split())

par = [0] * n
rank = [0] * n

#初期化
for i in range(n):
    par[i] = i
    rank[i] = 0

#判定(一番上野根を求める)
def find(x):
    if par[x] == x:
        return x
    else:
        par[x] = find(par[x])
        return par[x]
    
#結合
def unite(x , y):
    rx = find(x)
    ry = find(y)
    
    if rx == ry:
        return
    
    if rank[rx] < rank[ry]:
        par[rx] = ry
    elif rank[rx] > rank[ry]:
        par[ry] = rx
    else:
        par[ry] = x
        rank[rx] += 1      

def same(x,y):
    return find(x) == find(y)

for i in range(q):
    p,a,b = map(int, input().split())
    if p == 0:
        unite(a,b)
    if p == 1:
        print(1 if same(a,b) else 0)