Problem: Write a program which manipulates a disjoint set S = {S1, S2, . . . , Sk}.

First of all, the program should read an integer n, then make a disjoint set where each element consists of 0, 1, ... n−1 respectively.

Next, the program should read an integer q and manipulate the set for q queries. There are two kinds of queries for different operations:

* unite(x, y): unites sets that contain x and y, say Sx and Sy, into a new set.
* same(x, y): determine whether x and y are in the same set.

Constraints

* 1 ≤ n ≤ 10000
* 1 ≤ q ≤ 100000
* x ≠ y

Input


n q
com1 x1 y1
com2 x2 y2
...
comq xq yq


In the first line, n and q are given. Then, q queries are given where com represents the type of queries. '0' denotes unite and '1' denotes same operation.

Output

For each same operation, print 1 if x and y are in the same set, otherwise 0, in a line.

Example

Input

5 12
0 1 4
0 2 3
1 1 2
1 3 4
1 1 4
1 3 2
0 1 3
1 2 4
1 3 0
0 0 4
1 0 2
1 3 0


Output

0
0
1
1
1
0
1
1

Solution (in CPP):

Solution:
#include <iostream>
using namespace std;

int p[10000];

int root( int n ) {
	if ( p[n] != n )
		p[n] = root( p[n] );
	return p[n];
}

void unit( int x, int y ) {
	p[root( y )] = root( x );
}

void same( int x, int y ) {
	if ( root( x ) == root( y ) )
		cout << 1 << endl;
	else
		cout << 0 << endl;
}

int main() {
	int n, q, com, x, y;
	cin >> n >> q;
	for ( int i = 0; i < n; i++ )
		p[i] = i;
	for ( int i = 0; i < q; i++ ) {
		cin >> com >> x >> y;
		if ( com == 0 )
			unit( x, y );
		else
			same( x, y );
	}
}