Problem: We have N points in a two-dimensional plane.
The coordinates of the i-th point (1 \leq i \leq N) are (x_i,y_i).
Let us consider a rectangle whose sides are parallel to the coordinate axes that contains K or more of the N points in its interior.
Here, points on the sides of the rectangle are considered to be in the interior.
Find the minimum possible area of such a rectangle.

Constraints

* 2 \leq K \leq N \leq 50
* -10^9 \leq x_i,y_i \leq 10^9 (1 \leq i \leq N)
* x_i≠x_j (1 \leq i<j \leq N)
* y_i≠y_j (1 \leq i<j \leq N)
* All input values are integers. (Added at 21:50 JST)

Input

Input is given from Standard Input in the following format:


N K
x_1 y_1
:
x_{N} y_{N}


Output

Print the minimum possible area of a rectangle that satisfies the condition.

Examples

Input

4 4
1 4
3 3
6 2
8 1


Output

21


Input

4 2
0 0
1 1
2 2
3 3


Output

1


Input

4 3
-1000000000 -1000000000
1000000000 1000000000
-999999999 999999999
999999999 -999999999


Output

3999999996000000001

Solution (in PYTHON3):

Solution:
import itertools
N,K=map(int,input().split())
XY=[list(map(int,input().split())) for i in range(N)]
ans=float("inf")

for xv in itertools.combinations( [xy[0] for xy in XY] ,2):
  for yv in itertools.combinations( [xy[1] for xy in XY] ,2):
    xmax=max(xv[0],xv[1])
    xmin=min(xv[0],xv[1])
    ymax=max(yv[0],yv[1])
    ymin=min(yv[0],yv[1])

    k=0
    for xy in XY:
      x,y=xy[0],xy[1]
      if xmin<=x and x<=xmax:
        if ymin<=y and y<=ymax:
          k+=1    
    if k>=K:
      ans=min(ans,(xmax-xmin)*(ymax-ymin))
print(ans)