Problem: It is November 18 now in Japan. By the way, 11 and 18 are adjacent Lucas numbers.

You are given an integer N. Find the N-th Lucas number.

Here, the i-th Lucas number L_i is defined as follows:

* L_0=2
* L_1=1
* L_i=L_{i-1}+L_{i-2} (i≥2)

Constraints

* 1≤N≤86
* It is guaranteed that the answer is less than 10^{18}.
* N is an integer.

Input

Input is given from Standard Input in the following format:


N


Output

Print the N-th Lucas number.

Examples

Input

5


Output

11


Input

86


Output

939587134549734843

Solution (in JAVA):

Solution:
import java.util.Scanner;

public class Main {

	private static final long x = (long) Math.pow(10, 18);

	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		int n = sc.nextInt();
		long x[] = new long[n + 1];

		x[0] = 2;
		x[1] = 1;
		long ans = 0;
		for (int i = 2; i <= n; i++) {
			ans =  x[i - 1] + x[i - 2];
			x[i] = ans;
		}

		if (n == 1) {
			System.out.println(1);
		} else {
			System.out.println(ans);
		}

		sc.close();
	}

}