Problem: Write a program which manipulates a disjoint set S = {S1, S2, . . . , Sk}.

First of all, the program should read an integer n, then make a disjoint set where each element consists of 0, 1, ... n−1 respectively.

Next, the program should read an integer q and manipulate the set for q queries. There are two kinds of queries for different operations:

* unite(x, y): unites sets that contain x and y, say Sx and Sy, into a new set.
* same(x, y): determine whether x and y are in the same set.

Constraints

* 1 ≤ n ≤ 10000
* 1 ≤ q ≤ 100000
* x ≠ y

Input


n q
com1 x1 y1
com2 x2 y2
...
comq xq yq


In the first line, n and q are given. Then, q queries are given where com represents the type of queries. '0' denotes unite and '1' denotes same operation.

Output

For each same operation, print 1 if x and y are in the same set, otherwise 0, in a line.

Example

Input

5 12
0 1 4
0 2 3
1 1 2
1 3 4
1 1 4
1 3 2
0 1 3
1 2 4
1 3 0
0 0 4
1 0 2
1 3 0


Output

0
0
1
1
1
0
1
1

Solution (in PYTHON3):

Solution:
def make_set(x, disjoint):
    disjoint[x] = x

def find_set(x, disjoint):
    if x not in disjoint.keys():
        make_set(x, disjoint)
    if x != disjoint[x]:
        disjoint[x] = find_set(disjoint[x], disjoint)
    return disjoint[x]

def link(x, y, disjoint):
    disjoint[y] = x

def unite(x, y, disjoint):
    link(find_set(x, disjoint), find_set(y, disjoint), disjoint)

def same(x, y, disjoint):
    if find_set(x, disjoint) == find_set(y, disjoint):
        return 1
    return 0

n, q = list(map(int, input().split()))
com_list = list()
x_list = list()
y_list = list()

for _ in range(q):
    com, x, y = list(map(int, input().split()))
    com_list.append(com)
    x_list.append(x)
    y_list.append(y)

disjoint = dict()

for i in range(q):
    com = com_list[i]
    x = x_list[i]
    y = y_list[i]

    if com == 0:
        unite(x, y, disjoint)
    else:
        print(same(x, y, disjoint))