Problem: In Walrusland public transport tickets are characterized by two integers: by the number of the series and by the number of the ticket in the series. Let the series number be represented by a and the ticket number — by b, then a ticket is described by the ordered pair of numbers (a, b). 

The walruses believe that a ticket is lucky if a * b = rev(a) * rev(b). The function rev(x) reverses a number written in the decimal system, at that the leading zeroes disappear. For example, rev(12343) = 34321, rev(1200) = 21.

The Public Transport Management Committee wants to release x series, each containing y tickets, so that at least w lucky tickets were released and the total number of released tickets (x * y) were minimum. The series are numbered from 1 to x inclusive. The tickets in each series are numbered from 1 to y inclusive. The Transport Committee cannot release more than maxx series and more than maxy tickets in one series.

Input

The first line contains three integers maxx, maxy, w (1 ≤ maxx, maxy ≤ 105, 1 ≤ w ≤ 107).

Output

Print on a single line two space-separated numbers, the x and the y. If there are several possible variants, print any of them. If such x and y do not exist, print a single number  - 1.

Examples

Input

2 2 1


Output

1 1

Input

132 10 35


Output

7 5

Input

5 18 1000


Output

-1


Input

48 132 235


Output

22 111

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int mx, mn, w, x, cc, y, ansx, ansy;
map<double, int> m1;
map<double, int> m2;
double q;
int dz(int x) {
  int ans = 0;
  while (x) ans = ans * 10 + (x % 10), x /= 10;
  return ans;
}
int main() {
  cin >> mx >> mn >> w;
  for (int i = 1; i <= mx; i++) q = i * 1.0 / dz(i), m1[q]++;
  x = mx;
  while (y <= mn && x >= 1) {
    if (cc < w && y < mn)
      y++, q = (dz(y) * 1.0) / y, cc += m1[q], m2[q]++;
    else if (cc >= w) {
      if (ansx * ansy > x * y || !ansx) ansx = x, ansy = y;
      q = (x * 1.0) / dz(x), cc -= m2[q], m1[q]--, x--;
    } else
      y = mn + 1;
  }
  if (ansx == 0)
    cout << -1;
  else
    cout << ansx << " " << ansy;
}