Problem: In Walrusland public transport tickets are characterized by two integers: by the number of the series and by the number of the ticket in the series. Let the series number be represented by a and the ticket number — by b, then a ticket is described by the ordered pair of numbers (a, b). 

The walruses believe that a ticket is lucky if a * b = rev(a) * rev(b). The function rev(x) reverses a number written in the decimal system, at that the leading zeroes disappear. For example, rev(12343) = 34321, rev(1200) = 21.

The Public Transport Management Committee wants to release x series, each containing y tickets, so that at least w lucky tickets were released and the total number of released tickets (x * y) were minimum. The series are numbered from 1 to x inclusive. The tickets in each series are numbered from 1 to y inclusive. The Transport Committee cannot release more than maxx series and more than maxy tickets in one series.

Input

The first line contains three integers maxx, maxy, w (1 ≤ maxx, maxy ≤ 105, 1 ≤ w ≤ 107).

Output

Print on a single line two space-separated numbers, the x and the y. If there are several possible variants, print any of them. If such x and y do not exist, print a single number  - 1.

Examples

Input

2 2 1


Output

1 1

Input

132 10 35


Output

7 5

Input

5 18 1000


Output

-1


Input

48 132 235


Output

22 111

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int maxx, maxy, w, x, y, c, ansx, ansy;
map<double, int> p, q;
double t;
int rev(int x) {
  int ans = 0;
  while (x > 0) {
    ans = ans * 10 + (x % 10);
    x /= 10;
  }
  return ans;
}
int main() {
  cin >> maxx >> maxy >> w;
  for (int i = 1; i <= maxx; i++) {
    t = i * 1.0 / rev(i);
    p[t]++;
  }
  x = maxx;
  while (y <= maxy && x >= 1) {
    if (c >= w) {
      if (ansx * ansy > x * y || !ansx) {
        ansx = x;
        ansy = y;
      }
      t = (x * 1.0) / rev(x);
      c -= q[t];
      p[t]--;
      x--;
      continue;
    }
    if (y >= maxy) {
      y = maxy + 1;
      continue;
    }
    if (c < w && y < maxy) {
      y++;
      t = (rev(y) * 1.0) / y;
      c += p[t];
      q[t]++;
    }
  }
  if (!ansx)
    cout << -1 << endl;
  else
    cout << ansx << " " << ansy << endl;
}