Problem: You are given an array a of length n consisting of zeros. You perform n actions with this array: during the i-th action, the following sequence of operations appears:

  1. Choose the maximum by length subarray (continuous subsegment) consisting only of zeros, among all such segments choose the leftmost one; 
  2. Let this segment be [l; r]. If r-l+1 is odd (not divisible by 2) then assign (set) a[(l+r)/(2)] := i (where i is the number of the current action), otherwise (if r-l+1 is even) assign (set) a[(l+r-1)/(2)] := i. 



Consider the array a of length 5 (initially a=[0, 0, 0, 0, 0]). Then it changes as follows:

  1. Firstly, we choose the segment [1; 5] and assign a[3] := 1, so a becomes [0, 0, 1, 0, 0]; 
  2. then we choose the segment [1; 2] and assign a[1] := 2, so a becomes [2, 0, 1, 0, 0]; 
  3. then we choose the segment [4; 5] and assign a[4] := 3, so a becomes [2, 0, 1, 3, 0]; 
  4. then we choose the segment [2; 2] and assign a[2] := 4, so a becomes [2, 4, 1, 3, 0]; 
  5. and at last we choose the segment [5; 5] and assign a[5] := 5, so a becomes [2, 4, 1, 3, 5]. 



Your task is to find the array a of length n after performing all n actions. Note that the answer exists and unique.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains one integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the length of a.

It is guaranteed that the sum of n over all test cases does not exceed 2 ⋅ 10^5 (∑ n ≤ 2 ⋅ 10^5).

Output

For each test case, print the answer — the array a of length n after performing n actions described in the problem statement. Note that the answer exists and unique.

Example

Input


6
1
2
3
4
5
6


Output


1 
1 2 
2 1 3 
3 1 2 4 
2 4 1 3 5 
3 4 1 5 2 6 

Solution (in JAVA):

Solution:
/*
    JAI MATA DI
 */

import java.util.*;

import java.io.*;
import java.math.BigInteger;
import java.sql.Array;


public class Main {
	  static class FR{
			BufferedReader br;
			StringTokenizer st;
			public FR() {
				br = new BufferedReader(new InputStreamReader(System.in));
			}
			String next() 
		    { 
		        while (st == null || !st.hasMoreElements()) 
		        { 
		            try
		            { 
		                st = new StringTokenizer(br.readLine()); 
		            } 
		            catch (IOException  e) 
		            { 
		                e.printStackTrace(); 
		            } 
		        } 
		        return st.nextToken(); 
		    } 

		    int nextInt() 
		    { 
		        return Integer.parseInt(next()); 
		    } 

		    long nextLong() 
		    { 
		        return Long.parseLong(next()); 
		    } 

		    double nextDouble() 
		    { 
		        return Double.parseDouble(next()); 
		    } 

		    String nextLine() 
		    { 
		        String str = ""; 
		        try
		        { 
		            str = br.readLine(); 
		        } 
		        catch (IOException e) 
		        { 
		            e.printStackTrace(); 
		        } 
		        return str; 
		    } 
		}
	 static long mod  = 1000000007;
	 static long gcd(long a, long b)
	  {      
	     if (b == 0)
	        return a;
	     return gcd(b, a % b); 
	  }
	static void sort(long[] arr ) {
		 ArrayList<Long> al = new ArrayList<>();
		 for(long e:arr) al.add(e);
		 Collections.sort(al);
		 for(int i = 0 ; i<al.size(); i++) arr[i] = al.get(i);
	 }
	static void sort(int[] arr ) {
		 ArrayList<Integer> al = new ArrayList<>();
		 for(int e:arr) al.add(e);
		 Collections.sort(al);
		 for(int i = 0 ; i<al.size(); i++) arr[i] = al.get(i);
	 }
	static int UB(long[] arr , long find , int l , int r) {
		while(l<=r) {
			int m = (l+r)/2;
			if(arr[m]<find) l = m+1;
			else r = m-1;
		}
		return l;
	}
	static int LB(long[] arr , long find,int l ,int r ) {
		while(l<=r) {
			int m = (l+r)/2;
			if(arr[m] > find) r = m-1;
			else l = m+1;
		}
		return r;
	}
	static int UB(int[] arr , long find , int l , int r) {
		while(l<=r) {
			int m = (l+r)/2;
			if(arr[m]<find) l = m+1;
			else r = m-1;
		}
		return l;
	}
	static int LB(int[] arr , long find,int l ,int r ) {
		while(l<=r) {
			int m = (l+r)/2;
			if(arr[m] > find) r = m-1;
			else l = m+1;
		}
		return r;
	}
	 static boolean[] prime(int num) {
			boolean[] bool = new boolean[num];
		     
		      for (int i = 0; i< bool.length; i++) {
		         bool[i] = true;
		      }
		      for (int i = 2; i< Math.sqrt(num); i++) {
		         if(bool[i] == true) {
		            for(int j = (i*i); j<num; j = j+i) {
		               bool[j] = false;
		            }
		         }
		      }
		      if(num >= 0) {
		    	  bool[0] = false;
		    	  bool[1] = false;
		      }
		      
		      return bool;
		}

	 static int ncr(int n, int k)
	    {
	        long C[][] = new long[n + 1][k + 1];
	        int i, j;
	 
	        // Calculate  value of Binomial
	        // Coefficient in bottom up manner
	        for (i = 0; i <= n; i++) {
	            for (j = 0; j <= Math.min(i, k); j++) {
	                // Base Cases
	                if (j == 0 || j == i)
	                    C[i][j] = 1;
	 
	                // Calculate value using
	                // previously stored values
	                else
	                    C[i][j] = (C[i - 1][j - 1] + C[i - 1][j])%mod;
	            }
	        }
	 
	        return (int)C[n][k];
	    }

/* ***************************************************************************************************************************************************/	 
	 static FR sc = new FR();
	 static StringBuilder sb = new StringBuilder();
	 public static void main(String args[]) {
		 int tc = 1;
		  tc = sc.nextInt();
		 
		 
		 while(tc-->0) {
				
			 TEST_CASE();
		 }
	    System.out.println(sb);
	 }
	 static void TEST_CASE() {
		 int n = sc.nextInt();
		 PriorityQueue<Pair> pq = new PriorityQueue<Main.Pair>();
		 pq.add(new Pair(0 , n-1));
		 int[] arr = new int[n];
		 int v = 1;
		 while(!pq.isEmpty()) {
			 Pair pp = pq.poll();
			 int pl = pp.l , pr = pp.r;
			 if(pl > pr) continue;
			 arr[(pl+pr)/2] = v++;
			 if(pl == pr) {
				 continue;
			 }
			 int m = (pl + pr)/2;
			 pq.add(new Pair(pl , m-1));
			 pq.add(new Pair(m+1 , pr));
		 }
		 for(int e:arr) sb.append(e+" ");
		 sb.append("\n");
	 }
	 static class Pair implements Comparable<Pair>{
		 int l;
		 int r;
		 Pair(int l , int r){
			 this.l = l;
			 this.r = r;
		 }
		@Override
		public int compareTo(Pair o) {
			int v1 = this.r - this.l;
			int v2 = o.r - o.l;
			if(v1 > v2) return -1;
			else if(v2 > v1) return 1;
			else return this.l - o.l;
		}
		 
	 }
}