Problem: You are given an equation: 

Ax2 + Bx + C = 0. 

Your task is to find the number of distinct roots of the equation and print all of them in ascending order.

Input

The first line contains three integer numbers A, B and C ( - 105 ≤ A, B, C ≤ 105). Any coefficient may be equal to 0.

Output

In case of infinite root count print the only integer -1. In case of no roots print the only integer 0. In other cases print the number of root on the first line and the roots on the following lines in the ascending order. Print roots with at least 5 digits after the decimal point.

Examples

Input

1 -5 6


Output

2
2.0000000000
3.0000000000

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.math.BigInteger;
import java.text.DecimalFormat;
import java.text.NumberFormat;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Collections;
import java.util.List;
import java.util.StringTokenizer;

public class Solution20B {
  public static void main(String[] args) {
    InputReader in = new InputReader(System.in);
    PrintWriter out = new PrintWriter(System.out);
    Solver20B solver = new Solver20B();
    solver.solve(0, in, out);
    out.close();
  }

  static class Solver20B {
    NumberFormat formatter = new DecimalFormat("#0.00000000");
    public void solve(int testNumber, InputReader in, PrintWriter out) {
      int a = in.nextInt(), b = in.nextInt(), c = in.nextInt();

      if (a == 0) {
        if (b == 0) {
          if (c == 0) {
            out.println(-1);
          } else {
            out.println(0);
          }
        } else {
          out.println(1);
          out.println(formatter.format(-(double) c * 1.0 / (double) b));
        }
      } else {
        long tmp = (long) b * (long) b - 4L * (long) a * (long) c;
        if (tmp >= 0) {
          double sqrt = Math.sqrt((double) tmp / (4.0 * (double) a * (double) a));
          double d = (double) b / 2.0 / (double) a;
          if (tmp > 0) {
            out.println(2);
            out.println(formatter.format(-sqrt - d));
            out.println(formatter.format(sqrt - d));
          } else {
            out.println(1);
            out.println(formatter.format(-d));
          }
        } else {
          out.println(0);
        }
      }
    }
  }

  static class InputReader {
    public BufferedReader reader;
    public StringTokenizer tokenizer;

    public InputReader(InputStream stream) {
      reader = new BufferedReader(new InputStreamReader(stream), 32768);
      tokenizer = null;
    }

    public String next() {
      while (tokenizer == null || !tokenizer.hasMoreTokens()) {
        try {
          tokenizer = new StringTokenizer(reader.readLine());
        } catch (IOException e) {
          throw new RuntimeException(e);
        }
      }
      return tokenizer.nextToken();
    }

    public int nextInt() {
      return Integer.parseInt(next());
    }
  }
}