Problem: Mr. Santa asks all the great programmers of the world to solve a trivial problem. He gives them an integer m and asks for the number of positive integers n, such that the factorial of n ends with exactly m zeroes. Are you among those great programmers who can solve this problem?

Input

The only line of input contains an integer m (1 ≤ m ≤ 100 000) — the required number of trailing zeroes in factorial.

Output

First print k — the number of values of n such that the factorial of n ends with m zeroes. Then print these k integers in increasing order.

Examples

Input

1


Output

5
5 6 7 8 9 

Input

5


Output

0

Note

The factorial of n is equal to the product of all integers from 1 to n inclusive, that is n! = 1·2·3·...·n.

In the first sample, 5! = 120, 6! = 720, 7! = 5040, 8! = 40320 and 9! = 362880.

Solution (in PYTHON3):

Solution:
#n,m,k = map(int, input().strip().split(' '))
m=int(input())
#a = list(map(int, input().strip().split(' ')))
l=[1]
i=1
l1=[i]
l2=0
#building the array
while(i<100000):
    i+=1
    l2=5*i
    c=0
    while(l2%5==0):
        l2=l2//5
        c+=1
    l.append(l[-1]+c)
    l1.append(i)
#print(l)
if m not in l:
    print(0)
else:
    print(5)
    ind=l.index(m)
    i1=5*l1[ind]
    print(i1,i1+1,i1+2,i1+3,i1+4,end=" ")