Problem: Let's call some positive integer classy if its decimal representation contains no more than 3 non-zero digits. For example, numbers 4, 200000, 10203 are classy and numbers 4231, 102306, 7277420000 are not.

You are given a segment [L; R]. Count the number of classy integers x such that L ≤ x ≤ R.

Each testcase contains several segments, for each of them you are required to solve the problem separately.

Input

The first line contains a single integer T (1 ≤ T ≤ 10^4) — the number of segments in a testcase.

Each of the next T lines contains two integers L_i and R_i (1 ≤ L_i ≤ R_i ≤ 10^{18}).

Output

Print T lines — the i-th line should contain the number of classy integers on a segment [L_i; R_i].

Example

Input

4
1 1000
1024 1024
65536 65536
999999 1000001


Output

1000
1
0
2

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
long long dp[21][4][2][2];
string a, b;
long long solve(int n, int z, bool minus, bool maxis) {
  if (dp[n][z][minus][maxis] != -1) return dp[n][z][minus][maxis];
  if (n == 19) {
    if ((minus) && (maxis) && (z <= 3))
      return 1;
    else
      return 0;
  }
  if (z > 3) return dp[n][z][minus][maxis] = 0;
  dp[n][z][minus][maxis] = 0;
  for (int i = 0; i <= 9; i++) {
    if (!minus && (i + '0') < a[n]) continue;
    if (!maxis && (i + '0') > b[n]) continue;
    dp[n][z][minus][maxis] +=
        solve(n + 1, z + (i != 0), minus | ((i + '0') > a[n]),
              maxis | ((i + '0') < b[n]));
  }
  return dp[n][z][minus][maxis];
}
int main() {
  int t;
  scanf("%d", &t);
  while (t--) {
    memset(dp, -1, sizeof dp);
    cin >> a >> b;
    long long resp = 0;
    int z = 0;
    for (int i = 0; i < a.size(); i++)
      if (a[i] != '0') z++;
    if (z <= 3) resp++;
    z = 0;
    for (int i = 0; i < b.size(); i++)
      if (b[i] != '0') z++;
    if (z <= 3) resp++;
    if (a == b) resp /= 2;
    while (a.size() < 19) a = '0' + a;
    while (b.size() < 19) b = '0' + b;
    printf("%lld\n", solve(0, 0, false, false) + resp);
  }
  return 0;
}