Problem: Let s(x) be sum of digits in decimal representation of positive integer x. Given two integers n and m, find some positive integers a and b such that 

  * s(a) ≥ n, 
  * s(b) ≥ n, 
  * s(a + b) ≤ m. 

Input

The only line of input contain two integers n and m (1 ≤ n, m ≤ 1129).

Output

Print two lines, one for decimal representation of a and one for decimal representation of b. Both numbers must not contain leading zeros and must have length no more than 2230.

Examples

Input

6 5


Output

6 
7


Input

8 16


Output

35 
53

Note

In the first sample, we have n = 6 and m = 5. One valid solution is a = 6, b = 7. Indeed, we have s(a) = 6 ≥ n and s(b) = 7 ≥ n, and also s(a + b) = s(13) = 4 ≤ m.

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.StringTokenizer;


public class aimA {
    FastScanner in;
    PrintWriter out;

    public static void main(String[] arg) {
        new aimA().run();
    }

    public void solve() throws IOException {
        int n = in.nextInt();
        int m = in.nextInt();
        int d = n - 5;
        int k = 1;
        while (d > 0) {
            out.print(4);
            d -= 4;
            k++;
        }
        out.print(5+" ");
        for (int i = 0; i < k; i++) {
            out.print(5);
        }
    }

    public void run() {
        try {
            in = new FastScanner(new BufferedReader(new InputStreamReader(System.in)));
            out = new PrintWriter(new BufferedWriter(new OutputStreamWriter(System.out)));

            solve();

            out.close();
        } catch (IOException e) {
            e.printStackTrace();
        }
    }

    class FastScanner {
        BufferedReader br;
        StringTokenizer st;

        FastScanner(BufferedReader bufferedReader) {
            br = new BufferedReader(new InputStreamReader(System.in));
        }

        String next() {
            while (st == null || !st.hasMoreTokens()) {
                try {
                    st = new StringTokenizer(br.readLine());
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
            return st.nextToken();
        }

        int nextInt() {
            return Integer.parseInt(next());
        }

        double nextDouble() {
            return Double.parseDouble(next());
        }

        long nextLong() {
            return Long.parseLong(next());
        }



    }
}