Problem: Let's call two strings s and t anagrams of each other if it is possible to rearrange symbols in the string s to get a string, equal to t.

Let's consider two strings s and t which are anagrams of each other. We say that t is a reducible anagram of s if there exists an integer k ≥ 2 and 2k non-empty strings s_1, t_1, s_2, t_2, ..., s_k, t_k that satisfy the following conditions:

  1. If we write the strings s_1, s_2, ..., s_k in order, the resulting string will be equal to s; 
  2. If we write the strings t_1, t_2, ..., t_k in order, the resulting string will be equal to t; 
  3. For all integers i between 1 and k inclusive, s_i and t_i are anagrams of each other. 



If such strings don't exist, then t is said to be an irreducible anagram of s. Note that these notions are only defined when s and t are anagrams of each other.

For example, consider the string s =  "gamegame". Then the string t =  "megamage" is a reducible anagram of s, we may choose for example s_1 =  "game", s_2 =  "gam", s_3 =  "e" and t_1 =  "mega", t_2 =  "mag", t_3 =  "e":

<image>

On the other hand, we can prove that t =  "memegaga" is an irreducible anagram of s.

You will be given a string s and q queries, represented by two integers 1 ≤ l ≤ r ≤ |s| (where |s| is equal to the length of the string s). For each query, you should find if the substring of s formed by characters from the l-th to the r-th has at least one irreducible anagram.

Input

The first line contains a string s, consisting of lowercase English characters (1 ≤ |s| ≤ 2 ⋅ 10^5).

The second line contains a single integer q (1 ≤ q ≤ 10^5) — the number of queries.

Each of the following q lines contain two integers l and r (1 ≤ l ≤ r ≤ |s|), representing a query for the substring of s formed by characters from the l-th to the r-th.

Output

For each query, print a single line containing "Yes" (without quotes) if the corresponding substring has at least one irreducible anagram, and a single line containing "No" (without quotes) otherwise.

Examples

Input


aaaaa
3
1 1
2 4
5 5


Output


Yes
No
Yes


Input


aabbbbbbc
6
1 2
2 4
2 2
1 9
5 7
3 5


Output


No
Yes
Yes
Yes
No
No

Note

In the first sample, in the first and third queries, the substring is "a", which has itself as an irreducible anagram since two or more non-empty strings cannot be put together to obtain "a". On the other hand, in the second query, the substring is "aaa", which has no irreducible anagrams: its only anagram is itself, and we may choose s_1 =  "a", s_2 =  "aa", t_1 =  "a", t_2 =  "aa" to show that it is a reducible anagram.

In the second query of the second sample, the substring is "abb", which has, for example, "bba" as an irreducible anagram.

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.*;
import java.util.function.BinaryOperator;


public class Main {
    private final static long mod = 1000000007;

    private final static int MAXN = 1000001;

    private static long power(long x, long y, long m) {
        long temp;
        if (y == 0)
            return 1;
        temp = power(x, y / 2, m);
        temp = (temp * temp) % m;
        if (y % 2 == 0)
            return temp;
        else
            return ((x % m) * temp) % m;
    }

    private static long power(long x, long y) {
        return power(x, y, mod);
    }

    private static long gcd(long a, long b) {
        if (b == 0) return a;
        return gcd(b, a % b);
    }

    static int nextPowerOf2(int a) {
        return 1 << nextLog2(a);
    }

    static int nextLog2(int a) {
        return (a == 0 ? 0 : 32 - Integer.numberOfLeadingZeros(a - 1));
    }

    private static long modInverse(long a, long m) {
        long m0 = m;
        long y = 0, x = 1;
        if (m == 1)
            return 0;
        while (a > 1) {
            long q = a / m;
            long t = m;
            m = a % m;
            a = t;
            t = y;
            y = x - q * y;
            x = t;
        }
        if (x < 0)
            x += m0;
        return x;
    }

    private static int[] getLogArr(int n) {
        int arr[] = new int[n + 1];
        for (int i = 1; i < n + 1; i++) {
            arr[i] = (int) (Math.log(i) / Math.log(2) + 1e-10);
        }
        return arr;
    }

    private static int log[] = getLogArr(MAXN);

    private static int getLRSpt(int st[][], int L, int R, BinaryOperator<Integer> binaryOperator) {
        int j = log[R - L + 1];
        return binaryOperator.apply(st[L][j], st[R - (1 << j) + 1][j]);
    }

    private static int[][] getSparseTable(int array[], BinaryOperator<Integer> binaryOperator) {
        int k = log[array.length+1] + 1;
        int st[][] = new int[array.length+1][k + 1];

        for (int i = 0; i < array.length; i++)
            st[i][0] = array[i];

        for (int j = 1; j <= k; j++) {
            for (int i = 0; i + (1 << j) <= array.length; i++) {
                st[i][j] = binaryOperator.apply(st[i][j - 1], st[i + (1 << (j - 1))][j - 1]);
            }
        }
        return st;
    }

    static class Subset {
        int parent;
        int rank;

        @Override
        public String toString() {
            return "" + parent;
        }
    }

    static int find(Subset[] Subsets, int i) {
        if (Subsets[i].parent != i)
            Subsets[i].parent = find(Subsets, Subsets[i].parent);
        return Subsets[i].parent;
    }

    static void union(Subset[] Subsets, int x, int y) {
        int xroot = find(Subsets, x);
        int yroot = find(Subsets, y);

        if (Subsets[xroot].rank < Subsets[yroot].rank)
            Subsets[xroot].parent = yroot;
        else if (Subsets[yroot].rank < Subsets[xroot].rank)
            Subsets[yroot].parent = xroot;
        else {
            Subsets[xroot].parent = yroot;
            Subsets[yroot].rank++;
        }
    }


    private static int maxx(Integer... a) {
        return Collections.max(Arrays.asList(a));
    }

    private static int minn(Integer... a) {
        return Collections.min(Arrays.asList(a));
    }



    private static long maxx(Long... a) {
        return Collections.max(Arrays.asList(a));
    }

    private static long minn(Long... a) {
        return Collections.min(Arrays.asList(a));
    }

    private static class Pair<T, U> {
        T a;
        U b;

        public Pair(T a, U b) {
            this.a = a;
            this.b = b;
        }

        @Override
        public boolean equals(Object o) {
            if (this == o) return true;
            if (o == null || getClass() != o.getClass()) return false;
            Pair pair = (Pair) o;
            return a.equals(pair.a) &&
                    b.equals(pair.b);
        }

        @Override
        public int hashCode() {
            return Objects.hash(a, b);
        }

        @Override
        public String toString() {
            return "(" + a +
                    "," + b +
                    ')';
        }
    }


    private static boolean isPrimeAKS(long n) {
        if(n%mod==0||n<2) return false;
        if(n>2&&n%2==0)return false;
        return (power((mod-1),n, n)==(power(mod,n,n)-1+n)%n);
    }

    public static int upperBound(List<Integer> list, int value) {
        int low = 0;
        int high = list.size();
        while (low < high) {
            final int mid = (low + high) / 2;
            if (value >= list.get(mid)) {
                low = mid + 1;
            } else {
                high = mid;
            }
        }
        return low;
    }


    private static int[] getLPSArray(String pattern) {
        int i,j,n=pattern.length();
        int[] lps = new int[pattern.length()];
        lps[0]=0;
        for(i=1,j=0;i<n;){
            if(pattern.charAt(i)==pattern.charAt(j)) {
                lps[i++]=++j;
            }
            else if(j>0){
                j=lps[j-1];
            }
            else {
                lps[i++]=0;
            }
        }
        return lps;
    }

    private static List<Integer> findPattern(String text, String pattern) {
        List<Integer> matchedIndexes = new ArrayList<>();
        if(pattern.length()==0) {
            return matchedIndexes;
        }
        int[] lps = getLPSArray(pattern);
        int i=0,j=0,n=text.length(),m=pattern.length();
        while(i<n) {
            if(text.charAt(i)==pattern.charAt(j)) {
                i++;
                j++;
            }
            if (j == m) {
                matchedIndexes.add(i - j);
                j = lps[j - 1];
            }
            if(i<n&&text.charAt(i)!=pattern.charAt(j)) {
                if (j > 0) {
                    j = lps[j - 1];
                } else {
                    i++;
                }
            }
        }
        return matchedIndexes;
    }

    private static Set<Long> getDivisors(long n) {
        Set<Long> divisors = new HashSet<>();
        divisors.add(1L);
        divisors.add(n);
        for (long i = 2; i <= Math.sqrt(n); i++) {
            if (n % i == 0) {
                divisors.add(i);
                divisors.add(n / i);
            }
        }
        return divisors;
    }

    private static long getLCM(long a, long b) {
        return (Math.max(a,b)/gcd(a,b))*Math.min(a,b);
    }

    private static int getState(int grid[][], int i) {
        if(i==0||i>=grid[0].length)return 0;
        int x= grid[0][i-1]+
            2*(grid[1][i-1]+2*(grid[0][i]+
                            2*(grid[1][i])));

        return x;


    }

    private static int solve(int dp[][], int a[], int l, int r,int k, int m) {
        if(m==1) {
            return Math.max(a[l],a[r]);
        }
        if(dp[l][r]!=0){
            return dp[l][r];
        }
        if(k>0){
            return dp[l][r]=Math.max(solve(dp, a, l+1,r,k-1, m-1),solve(dp, a, l,r-1,k-1, m-1));
        }
        else {
            return dp[l][r]=Math.min(solve(dp, a, l+1,r,k-1, m-1),solve(dp, a, l,r-1,k-1, m-1));
        }
    }


    public static void main(String[] args) throws Exception {

        long START_TIME = System.currentTimeMillis();
        try (FastReader in = new FastReader();
             FastWriter out = new FastWriter()) {

            int t, i, j, n, k, l, r, c,m, ti, tidx,gm,mx,mx1,mn,p,q;

            //for (t = in.nextInt(), tidx = 1; tidx <= t; tidx++)
            {
                long x=0, y=0, z=0,sum=0,bhc=0,ans=0;
                //out.print(String.format("Case #%d: ", tidx));

                String s=in.next();
                n=s.length();
                int csum[][]=new int[n+1][26];
                for(i=0;i<n;i++){
                    for(j=0;j<26;j++){
                        csum[i+1][j]=csum[i][j];
                    }
                    csum[i+1][s.charAt(i)-'a']++;
                }
                q=in.nextInt();
                while (q-->0){
                    l=in.nextInt();
                    r=in.nextInt();
                    if(l==r) {
                        out.println("Yes");
                    }
                    else {
                        Integer cnt[] = new Integer[26];
                        for (j = 0; j < 26; j++) {
                            cnt[j] = csum[r][j] - csum[l - 1][j];
                        }
                        Arrays.sort(cnt, Comparator.reverseOrder());
                        if(cnt[2]>0){
                            out.println("Yes");
                        } else if(cnt[1]==0){
                            out.println("No");
                        }
                        else {
                            if(s.charAt(l-1)==s.charAt(r-1)){
                                out.println("No");
                            }
                            else{
                                out.println("Yes");
                            }
                        }
                    }

                }

            }
            if(args.length>0 && "ex_time".equals(args[0])) {
                out.print("\nTime taken: ");
                out.println(System.currentTimeMillis()-START_TIME);
            }
            out.commit();
        } catch (Exception e){
            e.printStackTrace();
        }
    }


    public static class FastReader implements Closeable {
        private BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
        private StringTokenizer st;

        String next() {
            while (st == null || !st.hasMoreElements()) {
                try {
                    st = new StringTokenizer(br.readLine());
                } catch (Exception e) {
                    e.printStackTrace();
                }
            }
            return st.nextToken();
        }

        int nextInt() {
            return Integer.parseInt(next());
        }

        long nextLong() {
            return Long.parseLong(next());
        }

        double nextDouble() {
            return Double.parseDouble(next());
        }

        String nextLine() {
            String str = "";
            try {
                str = br.readLine();
            } catch (IOException e) {
                e.printStackTrace();
            }
            return str;
        }

        int[] nextIntArr(int n) {
            int[] arr = new int[n];
            for (int i = 0; i < n; i++) {
                arr[i] = nextInt();
            }
            return arr;
        }

        double[] nextDoubleArr(int n) {
            double[] arr = new double[n];
            for (int i = 0; i < n; i++) {
                arr[i] = nextDouble();
            }
            return arr;
        }

        long[] nextLongArr(int n) {
            long[] arr = new long[n];
            for (int i = 0; i < n; i++) {
                arr[i] = nextLong();
            }
            return arr;
        }

        String[] nextStrArr(int n) {
            String[] arr = new String[n];
            for (int i = 0; i < n; i++) {
                arr[i] = next();
            }
            return arr;
        }


        long[][] nextLongArr2(int n, int m) {
            long[][] arr = new long[n][m];
            for (int i = 0; i < n; i++) {
                arr[i] = nextLongArr(m);
            }
            return arr;
        }

        @Override
        public void close() throws IOException {
            br.close();
        }
    }


    public static class FastWriter implements Closeable {
        BufferedWriter bw;
        StringBuilder sb = new StringBuilder();
        List<String> list = new ArrayList<>();
        Set<String> set = new HashSet<>();

        public FastWriter() {
            bw = new BufferedWriter(new OutputStreamWriter(System.out));
        }

        <T> void commit() throws IOException {
            bw.write(sb.toString());
            bw.flush();
            sb = new StringBuilder();
        }

        public <T> void print(T obj) throws IOException {
            sb.append(obj.toString());
            //commit();
        }

        public void println() throws IOException {
            print("\n");
        }

        public <T> void println(T obj) throws IOException {
            print(obj.toString() + "\n");
        }

        <T> void printArrLn(T[] arr) throws IOException {
            for (int i = 0; i < arr.length - 1; i++) {
                print(arr[i] + " ");
            }
            println(arr[arr.length - 1]);
        }

        <T> void printArr2(T[][] arr) throws IOException {
            for (int j = 0; j < arr.length; j++) {
                for (int i = 0; i < arr[j].length - 1; i++) {
                    print(arr[j][i] + " ");
                }
                println(arr[j][arr.length - 1]);
            }
        }

        <T> void printColl(Collection<T> coll) throws IOException {
            for (T e : coll) {
                print(e + " ");
            }
            println();
        }

        void printCharN(char c, int n) throws IOException {
            for (int i = 0; i < n; i++) {
                print(c);
            }
        }

        void printIntArr2(int[][] arr) throws IOException {
            for (int j = 0; j < arr.length; j++) {
                for (int i = 0; i < arr[j].length - 1; i++) {
                    print(arr[j][i] + " ");
                }
                println(arr[j][arr.length - 1]);
            }
        }

        @Override
        public void close() throws IOException {
            bw.close();
        }
    }

}