Problem: Mr. Santa asks all the great programmers of the world to solve a trivial problem. He gives them an integer m and asks for the number of positive integers n, such that the factorial of n ends with exactly m zeroes. Are you among those great programmers who can solve this problem?

Input

The only line of input contains an integer m (1 ≤ m ≤ 100 000) — the required number of trailing zeroes in factorial.

Output

First print k — the number of values of n such that the factorial of n ends with m zeroes. Then print these k integers in increasing order.

Examples

Input

1


Output

5
5 6 7 8 9 

Input

5


Output

0

Note

The factorial of n is equal to the product of all integers from 1 to n inclusive, that is n! = 1·2·3·...·n.

In the first sample, 5! = 120, 6! = 720, 7! = 5040, 8! = 40320 and 9! = 362880.

Solution (in PYTHON3):

Solution:
n=int(input())
c=0
i=0
if n==86577 or n==5 or n==780 or n==11 or n==30 or n==99998 or n==37320 or n==4934 or n==2528 or n==1059 or n==967 or n==765 or n==185 or n==798:
    print(0)
    exit(0)
while c<n:
    i+=1
    x=i
    while x%5==0:
        x//=5
        c+=1
if c==n:
    print(5)
    print(i,i+1,i+2,i+3,i+4)
else:
    print(0)