Problem: Given is a directed graph G with N vertices and M edges.
The vertices are numbered 1 to N, and the i-th edge is directed from Vertex A_i to Vertex B_i.
It is guaranteed that the graph contains no self-loops or multiple edges.

Determine whether there exists an induced subgraph (see Notes) of G such that the in-degree and out-degree of every vertex are both 1. If the answer is yes, show one such subgraph.
Here the null graph is not considered as a subgraph.

Constraints

* 1 \leq N \leq 1000
* 0 \leq M \leq 2000
* 1 \leq A_i,B_i \leq N
* A_i \neq B_i
* All pairs (A_i, B_i) are distinct.
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N M
A_1 B_1
A_2 B_2
:
A_M B_M


Output

If there is no induced subgraph of G that satisfies the condition, print `-1`. Otherwise, print an induced subgraph of G that satisfies the condition, in the following format:


K
v_1
v_2
:
v_K


This represents the induced subgraph of G with K vertices whose vertex set is \\{v_1, v_2, \ldots, v_K\\}. (The order of v_1, v_2, \ldots, v_K does not matter.) If there are multiple subgraphs of G that satisfy the condition, printing any of them is accepted.

Examples

Input

4 5
1 2
2 3
2 4
4 1
4 3


Output

3
1
2
4


Input

4 5
1 2
2 3
2 4
1 4
4 3


Output

-1


Input

6 9
1 2
2 3
3 4
4 5
5 6
5 1
5 2
6 1
6 2


Output

4
2
3
4
5

Solution (in PYTHON3):

Solution:
#!python3

import sys
sys.setrecursionlimit(10 ** 6)

LI = lambda: list(map(int, input().split()))

# input
N, M = LI()
AB = [LI() for _ in range(M)]

# params
link = [[] for _ in range(N)]
for a, b in AB:
    link[a - 1].append(b - 1)
impossible = [False] * N


def joint(v, visit):
    if impossible[v]:
        return None
    visit = visit + [v]
    for u in link[v]:
        if u in visit:
            i = visit.index(u)
            return visit[i:]
        t = joint(u, visit)
        if t is not None:
            return t
    impossible[v] = True
    return None


def solve(l):
    n = len(l)
    d = {l[i]: i for i in range(n)}
    for i in range(n):
        x = l[i]
        for y in link[x]:
            if y in d:
                j = d[y]
                if (i + 1) % n == j:
                    continue
                if j < i:
                    l = l[j : i + 1]
                else:
                    l = l[: i + 1] + l[j:]
                return solve(l)
    return l
            

def main():
    t = None
    for i in range(N):
        t = joint(i, [])
        if t is not None:
            break
    if t is None:
        print(-1)
        return
    
    ans = solve(t)
    print(len(ans))
    for x in ans:
        print(x + 1)
        

if __name__ == "__main__":
    main()