Problem: Let s(x) be sum of digits in decimal representation of positive integer x. Given two integers n and m, find some positive integers a and b such that 

  * s(a) ≥ n, 
  * s(b) ≥ n, 
  * s(a + b) ≤ m. 

Input

The only line of input contain two integers n and m (1 ≤ n, m ≤ 1129).

Output

Print two lines, one for decimal representation of a and one for decimal representation of b. Both numbers must not contain leading zeros and must have length no more than 2230.

Examples

Input

6 5


Output

6 
7


Input

8 16


Output

35 
53

Note

In the first sample, we have n = 6 and m = 5. One valid solution is a = 6, b = 7. Indeed, we have s(a) = 6 ≥ n and s(b) = 7 ≥ n, and also s(a + b) = s(13) = 4 ≤ m.

Solution (in JAVA):

Solution:
import java.util.Scanner;

public class unnatural_conditions_1028{
	public static void main(String[] args){
		Scanner in = new Scanner(System.in);

		int n = in.nextInt();
		int m = in.nextInt();

		int iters = (int)Math.ceil((n-5)/9.0);

		String a = "";
		String b = "";

		for(int i=0; i<iters; i++){
			a += "54";
			b += "45";
		}

		a += "5";
		b += "5";

		System.out.println(a);
		System.out.println(b);
	}
}