Problem: Mr. Santa asks all the great programmers of the world to solve a trivial problem. He gives them an integer m and asks for the number of positive integers n, such that the factorial of n ends with exactly m zeroes. Are you among those great programmers who can solve this problem?

Input

The only line of input contains an integer m (1 ≤ m ≤ 100 000) — the required number of trailing zeroes in factorial.

Output

First print k — the number of values of n such that the factorial of n ends with m zeroes. Then print these k integers in increasing order.

Examples

Input

1


Output

5
5 6 7 8 9 

Input

5


Output

0

Note

The factorial of n is equal to the product of all integers from 1 to n inclusive, that is n! = 1·2·3·...·n.

In the first sample, 5! = 120, 6! = 720, 7! = 5040, 8! = 40320 and 9! = 362880.

Solution (in PYTHON3):

Solution:
from math import factorial 
a=int(input())
s=0
l=0
while 1:
    s+=5
    c=s*5
    d=-1
    while 1:
        l+=1
        d=d+1
        c=c//5
        if (c//5)%5!=0:
            break
    if l>=a :
        break
if l!=a:
    print('0')
else : 
    print('5')
    print(s,s+1,s+2,s+3,s+4)