Problem: Given is a directed graph G with N vertices and M edges.
The vertices are numbered 1 to N, and the i-th edge is directed from Vertex A_i to Vertex B_i.
It is guaranteed that the graph contains no self-loops or multiple edges.

Determine whether there exists an induced subgraph (see Notes) of G such that the in-degree and out-degree of every vertex are both 1. If the answer is yes, show one such subgraph.
Here the null graph is not considered as a subgraph.

Constraints

* 1 \leq N \leq 1000
* 0 \leq M \leq 2000
* 1 \leq A_i,B_i \leq N
* A_i \neq B_i
* All pairs (A_i, B_i) are distinct.
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N M
A_1 B_1
A_2 B_2
:
A_M B_M


Output

If there is no induced subgraph of G that satisfies the condition, print `-1`. Otherwise, print an induced subgraph of G that satisfies the condition, in the following format:


K
v_1
v_2
:
v_K


This represents the induced subgraph of G with K vertices whose vertex set is \\{v_1, v_2, \ldots, v_K\\}. (The order of v_1, v_2, \ldots, v_K does not matter.) If there are multiple subgraphs of G that satisfy the condition, printing any of them is accepted.

Examples

Input

4 5
1 2
2 3
2 4
4 1
4 3


Output

3
1
2
4


Input

4 5
1 2
2 3
2 4
1 4
4 3


Output

-1


Input

6 9
1 2
2 3
3 4
4 5
5 6
5 1
5 2
6 1
6 2


Output

4
2
3
4
5

Solution (in PYTHON3):

Solution:
import sys
sys.setrecursionlimit(10 ** 7)

def solve(G, p, ans, st, fst, arr, x):
    arr[p] = x
    cnt_1 = 0
    z = -1
    for nxt in G[p]:
        if nxt in st:
            cnt_1 += 1
            z = nxt
    cnt_2 = 0
    for v in st:
        if p in G[v]:
            cnt_2 += 1
    if cnt_1 > 1 or cnt_2 > 1:
        return False
    elif cnt_1 == 1 and cnt_2 == 1:
        if fst in G[p]:
            for v in st:
                ans.append(v)
            return True
        else:
            k = arr[z]
            for v in st:
                if arr[v] >= k:
                    ans.append(v)
            return True
    for nxt in G[p]:
        st.add(nxt)
        if solve(G, nxt, ans, st, fst, arr, x+1):
            return True
        st.remove(nxt)
    arr[p] = 0
    return False

def main():
    n, m = map(int, input().split())
    G = [[] for _ in range(n+1)]
    for _ in range(m):
        a, b = map(int, input().split())
        G[a].append(b)
    ans = []
    f = False
    st = set()
    arr = [0]*(n+1)
    for i in range(1, n+1):
        st.add(i)
        if solve(G, i, ans, st, i, arr, 1):
            f = True
            break
        st.remove(i)
    if f:
        print(len(ans))
        ans.sort()
        for v in ans:
            print(v)
    else:
        print(-1)

if __name__ == "__main__":
    main()