Problem: Let s(x) be sum of digits in decimal representation of positive integer x. Given two integers n and m, find some positive integers a and b such that 

  * s(a) ≥ n, 
  * s(b) ≥ n, 
  * s(a + b) ≤ m. 

Input

The only line of input contain two integers n and m (1 ≤ n, m ≤ 1129).

Output

Print two lines, one for decimal representation of a and one for decimal representation of b. Both numbers must not contain leading zeros and must have length no more than 2230.

Examples

Input

6 5


Output

6 
7


Input

8 16


Output

35 
53

Note

In the first sample, we have n = 6 and m = 5. One valid solution is a = 6, b = 7. Indeed, we have s(a) = 6 ≥ n and s(b) = 7 ≥ n, and also s(a + b) = s(13) = 4 ≤ m.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
long long in() {
  int a;
  scanf("%d", &a);
  return a;
}
long long inll() {
  long long a;
  scanf("%lld", &a);
  return a;
}
const int e3 = 1003;
const int e4 = 10004;
const int e5 = 100005;
const int e6 = 1000006;
const int e7 = 10000007;
const int e8 = 100000008;
const int e9 = 1000000009;
int main() {
  int n = in(), m = in();
  int l = n / 4 + 1;
  for (int i = 0; i < l; i++) cout << 5;
  cout << endl;
  for (int i = 0; i < l - 1; i++) cout << 4;
  cout << 5 << endl;
}