Problem: You are given n pairs of integers (a_1, b_1), (a_2, b_2), …, (a_n, b_n). All of the integers in the pairs are distinct and are in the range from 1 to 2 ⋅ n inclusive.

Let's call a sequence of integers x_1, x_2, …, x_{2k} good if either 

  * x_1 < x_2 > x_3 < … < x_{2k-2} > x_{2k-1} < x_{2k}, or 
  * x_1 > x_2 < x_3 > … > x_{2k-2} < x_{2k-1} > x_{2k}. 



You need to choose a subset of distinct indices i_1, i_2, …, i_t and their order in a way that if you write down all numbers from the pairs in a single sequence (the sequence would be a_{i_1}, b_{i_1}, a_{i_2}, b_{i_2}, …, a_{i_t}, b_{i_t}), this sequence is good.

What is the largest subset of indices you can choose? You also need to construct the corresponding index sequence i_1, i_2, …, i_t.

Input

The first line contains single integer n (2 ≤ n ≤ 3 ⋅ 10^5) — the number of pairs.

Each of the next n lines contain two numbers — a_i and b_i (1 ≤ a_i, b_i ≤ 2 ⋅ n) — the elements of the pairs.

It is guaranteed that all integers in the pairs are distinct, that is, every integer from 1 to 2 ⋅ n is mentioned exactly once.

Output

In the first line print a single integer t — the number of pairs in the answer.

Then print t distinct integers i_1, i_2, …, i_t — the indexes of pairs in the corresponding order.

Examples

Input


5
1 7
6 4
2 10
9 8
3 5


Output


3
1 5 3


Input


3
5 4
3 2
6 1


Output


3
3 2 1

Note

The final sequence in the first example is 1 < 7 > 3 < 5 > 2 < 10.

The final sequence in the second example is 6 > 1 < 3 > 2 < 5 > 4.

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.*;
public class D{
    public static void main(String[] args) {
        InputStream inputStream = System.in;
        OutputStream outputStream = System.out;
        InputReader in = new InputReader(inputStream);
        PrintWriter out = new PrintWriter(outputStream);
        TaskE solver = new TaskE();
        solver.solve(1, in, out);
        out.flush();out.close();
    }
        static class TaskE {
            class pair{
                int F,S,T;
                pair(int a,int b,int c){F=a;S=b;T=c;}
            }
            ArrayList<pair> dec=new ArrayList<>(),inc=new ArrayList<>();
           public void solve(int testNumber, InputReader in, PrintWriter out) {
            int n=in.nextInt();
            for(int i=0;i<n;i++){
                int a=in.nextInt(),b=in.nextInt();
                if(a>b){
                    dec.add(new pair(a,b,i+1));
                }else if(a<b){
                    inc.add(new pair(a,b,i+1));
                }
            }
            int szd=dec.size(),szi=inc.size();
            Collections.sort(inc,(A,B)->B.F-A.F);
            Collections.sort(dec,(A,B)->A.F-B.F);
            out.println(Math.max(szi,szd));
            if(szd<szi){
                for(int i=0;i<szi;i++){
                    out.print(inc.get(i).T+" ");
                }
            }else{
                for(int i=0;i<szd;i++){
                    out.print(dec.get(i).T+" ");
                }
            }
          }
//         pair ja[][];long w[];int from[],to[],c[];
//             void make(int n,int m,InputReader in){
//              ja=new pair[n+1][];w=new long[m];from=new int[m];to=new int[m];c=new int[n+1];
//              for(int i=0;i<m;i++){
//               int u=in.nextInt(),v=in.nextInt();long wt=in.nextLong();
//               c[u]++;c[v]++;from[i]=u;to[i]=v;w[i]=wt;
//              }
//              for(int i=1;i<=n;i++){
//               ja[i]=new pair[c[i]];c[i]=0;
//              }
//              for(int i=0;i<m;i++){
//               ja[from[i]][c[from[i]]++]=new pair(to[i],w[i]);
//               ja[to[i]][c[to[i]]++]=new pair(from[i],w[i]);
//              }
//             }
//        int[] radixSort(int[] f){ return radixSort(f, f.length); }
//    int[] radixSort(int[] f, int n)
//    {
//        int[] to = new int[n];
//        {
//            int[] b = new int[65537];
//            for(int i = 0;i < n;i++)b[1+(f[i]&0xffff)]++;
//            for(int i = 1;i <= 65536;i++)b[i]+=b[i-1];
//            for(int i = 0;i < n;i++)to[b[f[i]&0xffff]++] = f[i];
//            int[] d = f; f = to;to = d;
//        }
//        {
//            int[] b = new int[65537];
//            for(int i = 0;i < n;i++)b[1+(f[i]>>>16)]++;
//            for(int i = 1;i <= 65536;i++)b[i]+=b[i-1];
//            for(int i = 0;i < n;i++)to[b[f[i]>>>16]++] = f[i];
//            int[] d = f; f = to;to = d;
//        }
//        return f;
//    }
    }
    static class InputReader {
        BufferedReader br;
        StringTokenizer st;
        public InputReader(InputStream stream) {
            br = new BufferedReader(new InputStreamReader(stream));
            st = null;
        }

        String next() {
            while (st == null || !st.hasMoreTokens()) {
                String s = null;
                try {
                    s = br.readLine();
                } catch (IOException e) {
                    e.printStackTrace();
                }
                if (s == null)
                    return null;
                st = new StringTokenizer(s);
            }
            return st.nextToken();
        }

        boolean hasMoreTokens() {
            while (st == null || !st.hasMoreTokens()) {
                String s = null;
                try {
                    s = br.readLine();
                } catch (IOException e) {
                    e.printStackTrace();
                }
                if (s == null)
                    return false;
                st = new StringTokenizer(s);
            }
            return true;
        }

        public int nextInt() {
            return Integer.parseInt(next());
        }
        public long nextLong() {
            return Long.parseLong(next());
        }
        public double nextDouble() {
            return Double.parseDouble(next());
        }
    }
}