Problem: Mr. Santa asks all the great programmers of the world to solve a trivial problem. He gives them an integer m and asks for the number of positive integers n, such that the factorial of n ends with exactly m zeroes. Are you among those great programmers who can solve this problem?

Input

The only line of input contains an integer m (1 ≤ m ≤ 100 000) — the required number of trailing zeroes in factorial.

Output

First print k — the number of values of n such that the factorial of n ends with m zeroes. Then print these k integers in increasing order.

Examples

Input

1


Output

5
5 6 7 8 9 

Input

5


Output

0

Note

The factorial of n is equal to the product of all integers from 1 to n inclusive, that is n! = 1·2·3·...·n.

In the first sample, 5! = 120, 6! = 720, 7! = 5040, 8! = 40320 and 9! = 362880.

Solution (in PYTHON3):

Solution:
import collections
import math

#a, b, c = map(int, input().split())
n = int(input())
i, ans = 0, 0
while i < n:
    ans += 5
    x = ans
    while x % 5 == 0:
        i += 1
        x //= 5
    
    if i > n:
        print(0)
        exit(0)
print(5)
print(ans, ans + 1, ans + 2, ans + 3, ans + 4, sep=' ')