Problem: Mr. Santa asks all the great programmers of the world to solve a trivial problem. He gives them an integer m and asks for the number of positive integers n, such that the factorial of n ends with exactly m zeroes. Are you among those great programmers who can solve this problem?

Input

The only line of input contains an integer m (1 ≤ m ≤ 100 000) — the required number of trailing zeroes in factorial.

Output

First print k — the number of values of n such that the factorial of n ends with m zeroes. Then print these k integers in increasing order.

Examples

Input

1


Output

5
5 6 7 8 9 

Input

5


Output

0

Note

The factorial of n is equal to the product of all integers from 1 to n inclusive, that is n! = 1·2·3·...·n.

In the first sample, 5! = 120, 6! = 720, 7! = 5040, 8! = 40320 and 9! = 362880.

Solution (in PYTHON):

Solution:
zeroes = int(input())
fives = 0

dp = []
def countfives(n):
 n = int(n)
 if n % 5 != 0:
  return 0

 if len(dp) >= n / 5:
  return dp[n // 5 - 1]
 
 ret = 1 + countfives(n / 5)
 #dp[int(n / 5)] = ret
 dp.append(ret);
 return ret

i = 1
ret = []

while fives <= zeroes:
 f = countfives(i)
 fives = fives + f
 
 if fives == zeroes:
  ret.append(i)
 
 i = i + 1

print(len(ret))
print(" ".join(str(s) for s in ret))