Problem: Mr. Santa asks all the great programmers of the world to solve a trivial problem. He gives them an integer m and asks for the number of positive integers n, such that the factorial of n ends with exactly m zeroes. Are you among those great programmers who can solve this problem?

Input

The only line of input contains an integer m (1 ≤ m ≤ 100 000) — the required number of trailing zeroes in factorial.

Output

First print k — the number of values of n such that the factorial of n ends with m zeroes. Then print these k integers in increasing order.

Examples

Input

1


Output

5
5 6 7 8 9 

Input

5


Output

0

Note

The factorial of n is equal to the product of all integers from 1 to n inclusive, that is n! = 1·2·3·...·n.

In the first sample, 5! = 120, 6! = 720, 7! = 5040, 8! = 40320 and 9! = 362880.

Solution (in JAVA):

Solution:
import java.io.BufferedOutputStream;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.util.StringTokenizer;


public class B {
	
	public static int findFive(int z){
		int c =0;
		int m =1;
		while(c<z){
			int x = m*5;
			while(x>0 && x%5==0){
				c++;
				x/=5;
			}
			m++;
		}
		//System.out.println(c + " "+ z);
		if(c>z)
			return -1;
		return m-1;
		
		
	}

	public static void main(String[] args){
		FastScanner in = new FastScanner();
		PrintWriter out = new PrintWriter(new BufferedOutputStream(System.out),true);
		
		int z = in.nextInt();
		
		int x = findFive(z);
		
		if(x==-1){
			out.println(0);
		}
		else{
			out.println(5);
			for(int i=0;i<5;i++){
				out.print(5L * x + i + " ");
			}
		}
		out.close();
	}
	
	public static class FastScanner{
		BufferedReader br;
		StringTokenizer st;
		
		
		public FastScanner(){
			br = new BufferedReader(new InputStreamReader(System.in));
		}
		
		public String nextLine(){
			
			String out = "";
			try{
				out = br.readLine();
			}
			catch(IOException e){
				
			}
			return out;
		}
		
		public String next(){
			while (st == null || !st.hasMoreElements()) {
                try {
                    st = new StringTokenizer(br.readLine());
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
            return st.nextToken();
		}
		
		public int nextInt(){
			return Integer.parseInt(next());
		}
		
		public long nextLong(){
			return Long.parseLong(next());
		}
		
		public double nextDouble(){
			return Double.parseDouble(next());
		}
		
	}
}