Problem: «Next please», — the princess called and cast an estimating glance at the next groom.

The princess intends to choose the most worthy groom, this is, the richest one. Whenever she sees a groom who is more rich than each of the previous ones, she says a measured «Oh...». Whenever the groom is richer than all previous ones added together, she exclaims «Wow!» (no «Oh...» in this case). At the sight of the first groom the princess stays calm and says nothing.

The fortune of each groom is described with an integer between 1 and 50000. You know that during the day the princess saw n grooms, said «Oh...» exactly a times and exclaimed «Wow!» exactly b times. Your task is to output a sequence of n integers t1, t2, ..., tn, where ti describes the fortune of i-th groom. If several sequences are possible, output any of them. If no sequence exists that would satisfy all the requirements, output a single number -1.

Input

The only line of input data contains three integer numbers n, a and b (1 ≤ n ≤ 100, 0 ≤ a, b ≤ 15, n > a + b), separated with single spaces.

Output

Output any sequence of integers t1, t2, ..., tn, where ti (1 ≤ ti ≤ 50000) is the fortune of i-th groom, that satisfies the given constraints. If no sequence exists that would satisfy all the requirements, output a single number -1.

Examples

Input

10 2 3


Output

5 1 3 6 16 35 46 4 200 99

Input

5 0 0


Output

10 10 6 6 5

Note

Let's have a closer look at the answer for the first sample test. 

  * The princess said «Oh...» (highlighted in bold): 5 1 3 6 16 35 46 4 200 99. 
  * The princess exclaimed «Wow!» (highlighted in bold): 5 1 3 6 16 35 46 4 200 99. 

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.util.Arrays;
import java.util.StringTokenizer;

public class Main {
	
	public static void main(String[] args) throws Throwable {
		Scanner sc = new Scanner(System.in);
		int n = sc.nextInt() , a=sc.nextInt(),b=sc.nextInt();
		int[] arr = new int[n];
		if(a+b==0)
			Arrays.fill(arr, 1);
		else if(b==0)
		{
			if(n<a+2)
			{
				System.out.println(-1);return;
			}
			arr[0] = arr[1] = 2;
			int max = 2;
			for(int i = 2;i<n;i++)
			{
				if(a-->0)
					arr[i] = ++max;
				else
					arr[i] = 1;
			}
		}
		else
		{
			arr[0] = 1;
			int sum = 1 , max = 1;
			for (int i = 1; i < n; i++) {
				if(b-->0)
				{
					arr[i] = sum+1;
					sum += (max = arr[i]);
				}
				else if(a-->0)
				{
					arr[i] = ++max;
					sum += arr[i];
				}
				else
					arr[i] = 1;
				if(arr[i]>50000)
				{
					System.out.println(-1);return;
				}
			}
		}
		
		for(int i : arr)System.out.print(i+" ");
		System.out.println();
	}
	
	static class Scanner 
	{
		StringTokenizer st;
		BufferedReader br;
		public Scanner(InputStream s){	br = new BufferedReader(new InputStreamReader(s));}
		public Scanner(String file) throws FileNotFoundException { br = new BufferedReader(new FileReader(file));}
		public String next() throws IOException 
		{
			while (st == null || !st.hasMoreTokens())st = new StringTokenizer(br.readLine());
			return st.nextToken();
		}
		public int nextInt() throws IOException {return Integer.parseInt(next());}
		public long nextLong() throws IOException {return Long.parseLong(next());}
		public String nextLine() throws IOException {return br.readLine();}
		public double nextDouble() throws IOException
		{
			String x = next();
			StringBuilder sb = new StringBuilder("0");
			double res = 0, f = 1;
			boolean dec = false, neg = false;
			int start = 0;
			if(x.charAt(0) == '-'){neg = true;start++;}
			for(int i = start; i < x.length(); i++)
				if(x.charAt(i) == '.')
				{
					res = Long.parseLong(sb.toString());
					sb = new StringBuilder("0");
					dec = true;
				}
				else{sb.append(x.charAt(i));if(dec)f *= 10;}
			res += Long.parseLong(sb.toString()) / f;
			return res * (neg?-1:1);
		}
		public int[] nexIntArray() throws Throwable
		{
			st = new StringTokenizer(br.readLine());
			int[] a = new int[st.countTokens()];
			for(int i = 0; i < a.length;i++)a[i]=nextInt();
			return a;
		}
		public boolean ready() throws IOException {return br.ready();}
	}

}