Problem: PolandBall lives in a forest with his family. There are some trees in the forest. Trees are undirected acyclic graphs with k vertices and k - 1 edges, where k is some integer. Note that one vertex is a valid tree.

There is exactly one relative living in each vertex of each tree, they have unique ids from 1 to n. For each Ball i we know the id of its most distant relative living on the same tree. If there are several such vertices, we only know the value of the one with smallest id among those.

How many trees are there in the forest?

Input

The first line contains single integer n (1 ≤ n ≤ 104) — the number of Balls living in the forest.

The second line contains a sequence p1, p2, ..., pn of length n, where (1 ≤ pi ≤ n) holds and pi denotes the most distant from Ball i relative living on the same tree. If there are several most distant relatives living on the same tree, pi is the id of one with the smallest id.

It's guaranteed that the sequence p corresponds to some valid forest.

Hacking: To hack someone, you should provide a correct forest as a test. The sequence p will be calculated according to the forest and given to the solution you try to hack as input. Use the following format:

In the first line, output the integer n (1 ≤ n ≤ 104) — the number of Balls and the integer m (0 ≤ m < n) — the total number of edges in the forest. Then m lines should follow. The i-th of them should contain two integers ai and bi and represent an edge between vertices in which relatives ai and bi live. For example, the first sample is written as follows:
    
    
      
    5 3  
    1 2  
    3 4  
    4 5  
    

Output

You should output the number of trees in the forest where PolandBall lives.

Interaction

From the technical side, this problem is interactive. However, it should not affect you (except hacking) since there is no interaction.

Examples

Input

5
2 1 5 3 3

Output

2

Input

1
1


Output

1

Note

In the first sample testcase, possible forest is: 1-2 3-4-5. 

There are 2 trees overall.

In the second sample testcase, the only possible graph is one vertex and no edges. Therefore, there is only one tree.

Solution (in JAVA):

Solution:

import java.io.IOException;
import java.io.InputStream;
import java.io.OutputStream;
import java.io.PrintWriter;
import java.math.BigInteger;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.InputMismatchException;

/**
 * @author Mubtasim Shahriar
 */

public class PollFor {


	public static void main(String[] args) {

		InputStream inputStream = System.in;
		OutputStream outputStream = System.out;
		InputReader sc = new InputReader(inputStream);
		PrintWriter out = new PrintWriter(outputStream);
		Solver solver = new Solver();
//		int t = sc.nextInt();
		int t = 1;
		while(t--!=0) {
			solver.solve(sc, out);
		}		
		out.close();

	}
	
	static int ans = 0;

	static class Solver {
		public void solve(InputReader sc, PrintWriter out) {
			int n = sc.nextInt();
			ArrayList<Integer>[] gp = new ArrayList[n];
			for(int i = 0; i < n; i++) gp[i] = new ArrayList();
			for(int i = 0; i < n; i++) {
				int src = i;
				int to = sc.nextInt()-1;
				gp[src].add(to);
				gp[to].add(src);
			}
			boolean[] visited = new boolean[n];
			for(int i = 0; i < n; i++) {
				if(!visited[i]) {
					ans++;
					dfs(gp,visited,i);
				}
			}
			out.println(ans);
		}

		private void dfs(ArrayList<Integer>[] gp, boolean[] visited, int now) {
			if(visited[now]) return;
			visited[now] = true;
			for(int i : gp[now]) {
				if(!visited[i]) dfs(gp,visited,i);
			}
		}
	}

	static class InputReader { 
		private boolean finished = false;

		private InputStream stream;
		private byte[] buf = new byte[1024];
		private int curChar;
		private int numChars;
		private SpaceCharFilter filter;

		public InputReader(InputStream stream) {
			this.stream = stream;
		}

		public int read() {
			if (numChars == -1) {
				throw new InputMismatchException();
			}
			if (curChar >= numChars) {
				curChar = 0;
				try {
					numChars = stream.read(buf);
				} catch (IOException e) {
					throw new InputMismatchException();
				}
				if (numChars <= 0) {
					return -1;
				}
			}
			return buf[curChar++];
		}

		public int peek() {
			if (numChars == -1) {
				return -1;
			}
			if (curChar >= numChars) {
				curChar = 0;
				try {
					numChars = stream.read(buf);
				} catch (IOException e) {
					return -1;
				}
				if (numChars <= 0) {
					return -1;
				}
			}
			return buf[curChar];
		}

		public int nextInt() {
			int c = read();
			while (isSpaceChar(c)) {
				c = read();
			}
			int sgn = 1;
			if (c == '-') {
				sgn = -1;
				c = read();
			}
			int res = 0;
			do {
				if (c < '0' || c > '9') {
					throw new InputMismatchException();
				}
				res *= 10;
				res += c - '0';
				c = read();
			} while (!isSpaceChar(c));
			return res * sgn;
		}

		public long nextLong() {
			int c = read();
			while (isSpaceChar(c)) {
				c = read();
			}
			int sgn = 1;
			if (c == '-') {
				sgn = -1;
				c = read();
			}
			long res = 0;
			do {
				if (c < '0' || c > '9') {
					throw new InputMismatchException();
				}
				res *= 10;
				res += c - '0';
				c = read();
			} while (!isSpaceChar(c));
			return res * sgn;
		}

		public String nextString() {
			int c = read();
			while (isSpaceChar(c)) {
				c = read();
			}
			StringBuilder res = new StringBuilder();
			do {
				if (Character.isValidCodePoint(c)) {
					res.appendCodePoint(c);
				}
				c = read();
			} while (!isSpaceChar(c));
			return res.toString();
		}

		public boolean isSpaceChar(int c) {
			if (filter != null) {
				return filter.isSpaceChar(c);
			}
			return isWhitespace(c);
		}

		public static boolean isWhitespace(int c) {
			return c == ' ' || c == '\n' || c == '\r' || c == '\t' || c == -1;
		}

		private String readLine0() {
			StringBuilder buf = new StringBuilder();
			int c = read();
			while (c != '\n' && c != -1) {
				if (c != '\r') {
					buf.appendCodePoint(c);
				}
				c = read();
			}
			return buf.toString();
		}

		public String readLine() {
			String s = readLine0();
			while (s.trim().length() == 0) {
				s = readLine0();
			}
			return s;
		}

		public String readLine(boolean ignoreEmptyLines) {
			if (ignoreEmptyLines) {
				return readLine();
			} else {
				return readLine0();
			}
		}

		public BigInteger readBigInteger() {
			try {
				return new BigInteger(nextString());
			} catch (NumberFormatException e) {
				throw new InputMismatchException();
			}
		}

		public char nextCharacter() {
			int c = read();
			while (isSpaceChar(c)) {
				c = read();
			}
			return (char) c;
		}

		public double nextDouble() {
			int c = read();
			while (isSpaceChar(c)) {
				c = read();
			}
			int sgn = 1;
			if (c == '-') {
				sgn = -1;
				c = read();
			}
			double res = 0;
			while (!isSpaceChar(c) && c != '.') {
				if (c == 'e' || c == 'E') {
					return res * Math.pow(10, nextInt());
				}
				if (c < '0' || c > '9') {
					throw new InputMismatchException();
				}
				res *= 10;
				res += c - '0';
				c = read();
			}
			if (c == '.') {
				c = read();
				double m = 1;
				while (!isSpaceChar(c)) {
					if (c == 'e' || c == 'E') {
						return res * Math.pow(10, nextInt());
					}
					if (c < '0' || c > '9') {
						throw new InputMismatchException();
					}
					m /= 10;
					res += (c - '0') * m;
					c = read();
				}
			}
			return res * sgn;
		}

		public boolean isExhausted() {
			int value;
			while (isSpaceChar(value = peek()) && value != -1) {
				read();
			}
			return value == -1;
		}

		public String next() {
			return nextString();
		}

		public SpaceCharFilter getFilter() {
			return filter;
		}

		public void setFilter(SpaceCharFilter filter) {
			this.filter = filter;
		}

		public interface SpaceCharFilter {
			public boolean isSpaceChar(int ch);
		}
		public int[] nextIntArray(int n){
			int[] array=new int[n];
			for(int i=0;i<n;++i)array[i]=nextInt();
			return array;
		}
		public int[] nextSortedIntArray(int n){
			int array[]=nextIntArray(n);
			Arrays.sort(array);
			return array;
		}
		public int[] nextSumIntArray(int n){
			int[] array=new int[n];
			array[0]=nextInt();
			for(int i=1;i<n;++i)array[i]=array[i-1]+nextInt();
			return array;
		}
		public long[] nextLongArray(int n){
			long[] array=new long[n];
			for(int i=0;i<n;++i)array[i]=nextLong();
			return array;
		}
		public long[] nextSumLongArray(int n){
			long[] array=new long[n];
			array[0]=nextInt();
			for(int i=1;i<n;++i)array[i]=array[i-1]+nextInt();
			return array;
		}
		public long[] nextSortedLongArray(int n){
			long array[]=nextLongArray(n);
			Arrays.sort(array);
			return array;
		}
	}


}