Problem: You are given n strings s1, s2, ..., sn consisting of characters 0 and 1. m operations are performed, on each of them you concatenate two existing strings into a new one. On the i-th operation the concatenation saisbi is saved into a new string sn + i (the operations are numbered starting from 1). After each operation you need to find the maximum positive integer k such that all possible strings consisting of 0 and 1 of length k (there are 2k such strings) are substrings of the new string. If there is no such k, print 0.

Input

The first line contains single integer n (1 ≤ n ≤ 100) — the number of strings. The next n lines contain strings s1, s2, ..., sn (1 ≤ |si| ≤ 100), one per line. The total length of strings is not greater than 100.

The next line contains single integer m (1 ≤ m ≤ 100) — the number of operations. m lines follow, each of them contains two integers ai abd bi (1 ≤ ai, bi ≤ n + i - 1) — the number of strings that are concatenated to form sn + i.

Output

Print m lines, each should contain one integer — the answer to the question after the corresponding operation.

Example

Input

5
01
10
101
11111
0
3
1 2
6 5
4 4


Output

1
2
0

Note

On the first operation, a new string "0110" is created. For k = 1 the two possible binary strings of length k are "0" and "1", they are substrings of the new string. For k = 2 and greater there exist strings of length k that do not appear in this string (for k = 2 such string is "00"). So the answer is 1.

On the second operation the string "01100" is created. Now all strings of length k = 2 are present.

On the third operation the string "1111111111" is created. There is no zero, so the answer is 0.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
string substr(string str, int idx, int len) {
  return str.substr(idx >= 0 ? idx : max((int)(str).size() + idx, 0), len);
}
void collect(unordered_set<string>& set, string str, int len) {
  for (int j = 0; j + len - 1 < (int)(str).size(); ++j)
    set.insert(str.substr(j, len));
}
int main(int argc, char* argv[]) {
  const int km = 10;
  int n;
  cin >> n;
  vector<string> prefix(n), postfix(n);
  vector<vector<unordered_set<string>>> substrings(
      n, vector<unordered_set<string>>(km + 1));
  for (int i = 0; i < n; ++i) {
    string str;
    cin >> str;
    prefix[i] = substr(str, 0, km);
    postfix[i] = substr(str, -km, km);
    for (int l = 1; l <= km; ++l) collect(substrings[i][l], str, l);
  }
  int m;
  cin >> m;
  for (int i = 0; i < m; ++i) {
    int a, b;
    cin >> a >> b;
    a--, b--;
    prefix.push_back(substr(prefix[a] + prefix[b], 0, km));
    postfix.push_back(substr(postfix[a] + postfix[b], -km, km));
    string str = postfix[a] + prefix[b];
    vector<unordered_set<string>> absubstrings(km + 1);
    int res = 0;
    for (int idx : {a, b})
      for (int l = 0; l < km + 1; ++l)
        absubstrings[l].insert(substrings[idx][l].begin(),
                               substrings[idx][l].end());
    for (int l = 1; l <= km; ++l)
      collect(absubstrings[l], str, l),
          res = ((int)(absubstrings[l]).size() == (1 << l)) ? l : res;
    substrings.push_back(absubstrings);
    cout << res << endl;
  }
}