Problem: Mr. Santa asks all the great programmers of the world to solve a trivial problem. He gives them an integer m and asks for the number of positive integers n, such that the factorial of n ends with exactly m zeroes. Are you among those great programmers who can solve this problem?

Input

The only line of input contains an integer m (1 ≤ m ≤ 100 000) — the required number of trailing zeroes in factorial.

Output

First print k — the number of values of n such that the factorial of n ends with m zeroes. Then print these k integers in increasing order.

Examples

Input

1


Output

5
5 6 7 8 9 

Input

5


Output

0

Note

The factorial of n is equal to the product of all integers from 1 to n inclusive, that is n! = 1·2·3·...·n.

In the first sample, 5! = 120, 6! = 720, 7! = 5040, 8! = 40320 and 9! = 362880.

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.FileReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.util.StringTokenizer;

public class ManthanB {

	public static void main(String[] args) throws NumberFormatException, IOException {
		Scanner sc = new Scanner(System.in);
		int m = sc.nextInt();
		int cur = 0;
		int zeros = 0;
		boolean found = false;
		for(int i=0; i<=m; i++){
			
			cur += 5;
			int count = 0;
			int tmp = cur;
			while(tmp>0){
				if(tmp%5 == 0)
					zeros++;
				else
					break;
				tmp /= 5;
			}
			if(zeros == m){
				found = true;
				break;
			}
			else if(zeros>m){
				
				break;
			}
			
		}
		System.out.println(found?5:0);
		if(found){
			for(int i=0; i<5; i++)
				System.out.print(cur+i+" ");
		}
		
	}
	
	static class Scanner {
		BufferedReader br;
		StringTokenizer st;

		Scanner(FileReader f) {
			br = new BufferedReader(f);
		}

		public boolean ready() throws IOException {
			return br.ready();
		}

		Scanner(InputStream s) {
			br = new BufferedReader(new InputStreamReader(s));
		}

		String next() throws IOException {
			while (st == null || !st.hasMoreTokens())
				st = new StringTokenizer(br.readLine());
			return st.nextToken();
		}

		String nextLine() throws IOException {
			return br.readLine();
		}

		int nextInt() throws NumberFormatException, IOException {
			return Integer.parseInt(next());
		}

		long nextLong() throws NumberFormatException, IOException {
			return Long.parseLong(next());
		}
	}

}