Problem: Mr. Santa asks all the great programmers of the world to solve a trivial problem. He gives them an integer m and asks for the number of positive integers n, such that the factorial of n ends with exactly m zeroes. Are you among those great programmers who can solve this problem?

Input

The only line of input contains an integer m (1 ≤ m ≤ 100 000) — the required number of trailing zeroes in factorial.

Output

First print k — the number of values of n such that the factorial of n ends with m zeroes. Then print these k integers in increasing order.

Examples

Input

1


Output

5
5 6 7 8 9 

Input

5


Output

0

Note

The factorial of n is equal to the product of all integers from 1 to n inclusive, that is n! = 1·2·3·...·n.

In the first sample, 5! = 120, 6! = 720, 7! = 5040, 8! = 40320 and 9! = 362880.

Solution (in PYTHON):

Solution:
#!/usr/bin/env python
#-*- coding:utf-8 -*-

import sys, math, random, operator
from string import ascii_lowercase
from string import ascii_uppercase
from fractions import Fraction, gcd
from decimal import Decimal, getcontext
from itertools import product, permutations, combinations
from Queue import Queue, PriorityQueue
from collections import deque, defaultdict, Counter
getcontext().prec = 100

MOD = 10**9 + 7
INF = float("+inf")

if sys.subversion[0] != "CPython":  # PyPy?
    raw_input = lambda: sys.stdin.readline().rstrip()
pr = lambda *args: sys.stdout.write(" ".join(str(x) for x in args) + "\n")
epr = lambda *args: sys.stderr.write(" ".join(str(x) for x in args) + "\n")
die = lambda *args: pr(*args) ^ exit(0)

read_str = raw_input
read_strs = lambda: raw_input().split()
read_int = lambda: int(raw_input())
read_ints = lambda: map(int, raw_input().split())
read_float = lambda: float(raw_input())
read_floats = lambda: map(float, raw_input().split())

"---------------------------------------------------------------"

n = read_int()
k = 5
a = 0
while a < n:
    q = k
    #epr(k, a)
    while q and q % 5 == 0:
        a += 1
        q /= 5
    #epr(k, a, "<")
    if a < n:
        k += 5
epr(k, a, n)
if a > n:
    die("0")
print 5
for i in range(5):
    print k + i,
print