Problem: Let s(x) be sum of digits in decimal representation of positive integer x. Given two integers n and m, find some positive integers a and b such that 

  * s(a) ≥ n, 
  * s(b) ≥ n, 
  * s(a + b) ≤ m. 

Input

The only line of input contain two integers n and m (1 ≤ n, m ≤ 1129).

Output

Print two lines, one for decimal representation of a and one for decimal representation of b. Both numbers must not contain leading zeros and must have length no more than 2230.

Examples

Input

6 5


Output

6 
7


Input

8 16


Output

35 
53

Note

In the first sample, we have n = 6 and m = 5. One valid solution is a = 6, b = 7. Indeed, we have s(a) = 6 ≥ n and s(b) = 7 ≥ n, and also s(a + b) = s(13) = 4 ≤ m.

Solution (in JAVA):

Solution:
import java.util.Scanner;

public class Main {
	static int MAX_Length=2230;
	public static void main(String[] args) {
		// TODO 自动生成的方法存根
		Scanner in=new Scanner(System.in);
		int n,m;
		for(int i=1;i<=MAX_Length;i++)
			System.out.print("5");
		System.out.println();
		for(int i=1;i<=MAX_Length-1;i++)
			System.out.print("4");
		System.out.println("5");
	}

}