Problem: Mr. Santa asks all the great programmers of the world to solve a trivial problem. He gives them an integer m and asks for the number of positive integers n, such that the factorial of n ends with exactly m zeroes. Are you among those great programmers who can solve this problem?

Input

The only line of input contains an integer m (1 ≤ m ≤ 100 000) — the required number of trailing zeroes in factorial.

Output

First print k — the number of values of n such that the factorial of n ends with m zeroes. Then print these k integers in increasing order.

Examples

Input

1


Output

5
5 6 7 8 9 

Input

5


Output

0

Note

The factorial of n is equal to the product of all integers from 1 to n inclusive, that is n! = 1·2·3·...·n.

In the first sample, 5! = 120, 6! = 720, 7! = 5040, 8! = 40320 and 9! = 362880.

Solution (in JAVA):

Solution:

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.*;

public class B_A_Trivial_Problem {

    public static void main(String[] args)throws Exception {
        FastReader in = new FastReader();
        List<Integer> list = new ArrayList<Integer>();
        int m = in.nextInt();
        int res = 0;
        for (int i = 1; res <= m; i++) {
            for (int j = i; j % 5 == 0; j /= 5) {
                res++;
            }
            if (res == m) {
                list.add(i);
            }
        }
        System.out.println(list.size());
        for (Integer i : list) {
            System.out.print(i+" ");
        }
        System.out.println();
    }


static class FastReader {

    BufferedReader br;
    StringTokenizer st;

    FastReader() { // To read from the standard input
        br = new BufferedReader(new InputStreamReader(System.in));
    }
    // You can add a constructor to read from a file
    /////

    String next() throws IOException {
        while (st == null || !st.hasMoreTokens()) {
            st = new StringTokenizer(br.readLine());
        }
        return st.nextToken();
    }

    String nextLine() throws IOException {
        return br.readLine();
    }

    int nextInt() throws IOException {
        return Integer.parseInt(next());
    }
    //You can add nextDouble() etc...   

    boolean hasNext() throws IOException { // if input is terminated by EOF
        String s = br.readLine();
        if (s == null) {
            return false;
        }
        st = new StringTokenizer(s);
        return true;
    }
} //end FastReader


}