Problem: Now you get Baby Ehab's first words: "Given an integer n, find the longest subsequence of [1,2, …, n-1] whose product is 1 modulo n." Please solve the problem.

A sequence b is a subsequence of an array a if b can be obtained from a by deleting some (possibly all) elements. The product of an empty subsequence is equal to 1.

Input

The only line contains the integer n (2 ≤ n ≤ 10^5).

Output

The first line should contain a single integer, the length of the longest subsequence.

The second line should contain the elements of the subsequence, in increasing order.

If there are multiple solutions, you can print any.

Examples

Input


5


Output


3
1 2 3 

Input


8


Output


4
1 3 5 7 

Note

In the first example, the product of the elements is 6 which is congruent to 1 modulo 5. The only longer subsequence is [1,2,3,4]. Its product is 24 which is congruent to 4 modulo 5. Hence, the answer is [1,2,3].

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.util.*;

public class Main {
    public static void main(String[] args) {
        Reader in = new Reader(System.in);
        int t = 1;
        NumberTheory numberTheory = new NumberTheory();
        StringBuilder stringBuilder = new StringBuilder();
        while (t-- > 0) {
            int n = in.nextInt();
            int[] inv = new int[n];
            Arrays.fill(inv, -1);
            for (int i = 1; i < n; i++) {
                if (numberTheory.gcd(i, n) == 1L) {
                    inv[i] = (int)(numberTheory.extendedEuclid(i, n).x + n) % n;
                }
            }
            inv[1] = 1;
            int count = 0;
            for (int i = 1; i < n; i++) {
                if (inv[i] == i) {
                    count ++;
                }
            }
            TreeSet<Integer> all = new TreeSet<>();
            if (count > 2) {
                for (int i = 0; i < n; i++) {
                    if (inv[i] == i) {
                        all.add(i);
                    }
                }
            }
            all.add(1);
            for (int i = 0; i < n; i++) {
                if (inv[i] != -1 && inv[i] != i) {
                    all.add(i);
                    all.add(inv[i]);
                }
            }
            stringBuilder.append(all.size()).append("\n");
            for (int x : all) {
                stringBuilder.append(x).append(" ");
            }
        }
        System.out.println(stringBuilder);
    }
}
class Reader {
    public BufferedReader reader;
    public StringTokenizer tokenizer;

    public Reader(InputStream stream) {
        reader = new BufferedReader(new InputStreamReader(stream), 32768);
        tokenizer = null;
    }

    public String next() {
        while (tokenizer == null || !tokenizer.hasMoreTokens()) {
            try {
                tokenizer = new StringTokenizer(reader.readLine());
            } catch (IOException e) {
                throw new RuntimeException(e);
            }
        }
        return tokenizer.nextToken();
    }

    public int nextInt() {
        return Integer.parseInt(next());
    }

    public long nextLong() {
        return Long.parseLong(next());
    }

}
class NumberTheory
{
    public boolean isPrime(long n)
    {
        if(n < 2)
            return false;
        for(long x = 2;x * x <= n;x++)
        {
            if(n % x == 0)
                return false;
        }
        return true;
    }
    public ArrayList<Long> primeFactorisation(long n)
    {
        ArrayList<Long> f = new ArrayList<>();
        for(long x=2;x * x <= n;x++)
        {
            while(n % x == 0)
            {
                f.add(x);
                n /= x;
            }
        }
        if(n > 1)
            f.add(n);
        return f;
    }
    public int[] sieveOfEratosthenes(int n)
    {
        int[] sieve = new int[n + 1];
        for(int x=2;x<=n;x++)
        {
            if(sieve[x] != 0)
                continue;
            sieve[x] = x;
            for(int u=2*x;u<=n;u+=x)
                if(sieve[u] == 0)
                    sieve[u] = x;
        }
        return sieve;
    }
    public long gcd(long a, long b)
    {
        if(b == 0)
            return a;
        return gcd(b, a % b);
    }
    public long phi(long n)
    {
        double result = n;

        for(long p=2;p*p<=n;p++)
        {
            if(n % p == 0)
            {
                while (n % p == 0)
                    n /= p;
                result *= (1.0 - (1.0 / (double)p));
            }
        }
        if(n > 1)
            result *= (1.0 - (1.0 / (double)n));
        return (long)result;
    }
    public Name extendedEuclid(long a, long b)
    {
        if(b == 0)
            return new Name(a, 1, 0);
        Name n1 = extendedEuclid(b, a % b);
        Name n2 = new Name(n1.d, n1.y, n1.x - (long)Math.floor((double)a / b) * n1.y);
        return n2;
    }
    public long modularExponentiation(long a, long b, long n)
    {
        long d = 1L;
        String bString = Long.toBinaryString(b);
        for(int i=0;i<bString.length();i++)
        {
            d = (d * d) % n;
            if(bString.charAt(i) == '1')
                d = (d * a) % n;
        }
        return d;
    }
}
class Name
{
    long d;
    long x;
    long y;

    public Name(long d, long x, long y)
    {
        this.d = d;
        this.x = x;
        this.y = y;
    }
}