Problem: Mr. Santa asks all the great programmers of the world to solve a trivial problem. He gives them an integer m and asks for the number of positive integers n, such that the factorial of n ends with exactly m zeroes. Are you among those great programmers who can solve this problem?

Input

The only line of input contains an integer m (1 ≤ m ≤ 100 000) — the required number of trailing zeroes in factorial.

Output

First print k — the number of values of n such that the factorial of n ends with m zeroes. Then print these k integers in increasing order.

Examples

Input

1


Output

5
5 6 7 8 9 

Input

5


Output

0

Note

The factorial of n is equal to the product of all integers from 1 to n inclusive, that is n! = 1·2·3·...·n.

In the first sample, 5! = 120, 6! = 720, 7! = 5040, 8! = 40320 and 9! = 362880.

Solution (in PYTHON):

Solution:
def go():
    a = [0]
    for i in range(1,100001):
        x = i/5
        a.append(i+a[x])
    return a

a = go()
m = int(raw_input())
if m in a:
    i = a.index(m)
    print "5"
    i = i*5
    print `i` +" "+ `i+1` +" "+ `i+2` +" "+ `i+3` +" "+ `i+4`
    
else:
    print "0"