Problem: Mr. Santa asks all the great programmers of the world to solve a trivial problem. He gives them an integer m and asks for the number of positive integers n, such that the factorial of n ends with exactly m zeroes. Are you among those great programmers who can solve this problem?

Input

The only line of input contains an integer m (1 ≤ m ≤ 100 000) — the required number of trailing zeroes in factorial.

Output

First print k — the number of values of n such that the factorial of n ends with m zeroes. Then print these k integers in increasing order.

Examples

Input

1


Output

5
5 6 7 8 9 

Input

5


Output

0

Note

The factorial of n is equal to the product of all integers from 1 to n inclusive, that is n! = 1·2·3·...·n.

In the first sample, 5! = 120, 6! = 720, 7! = 5040, 8! = 40320 and 9! = 362880.

Solution (in PYTHON3):

Solution:
#!/usr/bin/env python3

import sys
from math import log

m = int(input())

number_of_zeroes = 0
for i in range(5, 100000 * 5, 5):
    k = i
    while k % 5 == 0:
        number_of_zeroes += 1
        k //= 5
    if number_of_zeroes == m:
        print(5)
        for j in range(0, 5):
            print(i + j, end=' ')
        sys.exit(0)
    elif m < number_of_zeroes:
        break
print(0)