Problem: Mr. Santa asks all the great programmers of the world to solve a trivial problem. He gives them an integer m and asks for the number of positive integers n, such that the factorial of n ends with exactly m zeroes. Are you among those great programmers who can solve this problem?

Input

The only line of input contains an integer m (1 ≤ m ≤ 100 000) — the required number of trailing zeroes in factorial.

Output

First print k — the number of values of n such that the factorial of n ends with m zeroes. Then print these k integers in increasing order.

Examples

Input

1


Output

5
5 6 7 8 9 

Input

5


Output

0

Note

The factorial of n is equal to the product of all integers from 1 to n inclusive, that is n! = 1·2·3·...·n.

In the first sample, 5! = 120, 6! = 720, 7! = 5040, 8! = 40320 and 9! = 362880.

Solution (in JAVA):

Solution:
//package CodeForces.ManhatanCodeFest16;

import java.io.BufferedOutputStream;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.util.StringTokenizer;

/**
 * Created by ilya on 26.02.16.
 */

public class B633 {
    public static void main(String[] args) {
        sc sc = new sc();
        PrintWriter out = new PrintWriter(new BufferedOutputStream(System.out));
        int m = sc.nextInt();
        int i = 0;
        long a = 25, start = 0, tmp = 0;
            for (i = 0; i < m; i++) {
                start += 5;
                tmp = start/5;
                while(tmp%5 == 0){
                    i++;
                    tmp/=5;
                }
            }
            if (i == m) {
                out.println(5);
                for (long j= start; j < start + 5; j++) {
                    out.print(j + " ");
                }
            } else {
                out.println(0);
            }

        out.close();
    }

    public static class sc {
        BufferedReader br;
        StringTokenizer st;

        public sc() {
            br = new BufferedReader(new InputStreamReader(System.in));
        }

        String next() {
            while (st == null || !st.hasMoreElements()) {
                try {
                    st = new StringTokenizer(br.readLine());
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
            return st.nextToken();
        }

        Integer nextInt() {
            return Integer.parseInt(next());
        }

        long nextLong() {
            return Long.parseLong(next());
        }

        double nextDouble() {
            return Double.parseDouble(next());
        }

        String nextLine() {
            String str = "";
            try {
                str = br.readLine();
            } catch (IOException e) {
                e.printStackTrace();
            }
            return str;
        }
    }

}