Problem: Let s(x) be sum of digits in decimal representation of positive integer x. Given two integers n and m, find some positive integers a and b such that 

  * s(a) ≥ n, 
  * s(b) ≥ n, 
  * s(a + b) ≤ m. 

Input

The only line of input contain two integers n and m (1 ≤ n, m ≤ 1129).

Output

Print two lines, one for decimal representation of a and one for decimal representation of b. Both numbers must not contain leading zeros and must have length no more than 2230.

Examples

Input

6 5


Output

6 
7


Input

8 16


Output

35 
53

Note

In the first sample, we have n = 6 and m = 5. One valid solution is a = 6, b = 7. Indeed, we have s(a) = 6 ≥ n and s(b) = 7 ≥ n, and also s(a + b) = s(13) = 4 ≤ m.

Solution (in JAVA):

Solution:


import java.util.Scanner;

public class sum {

	public static void main(String[] args) {
		Scanner sc =new Scanner(System.in);
		
		int n=sc.nextInt();
		int m=sc.nextInt();
		StringBuilder ss =new StringBuilder("");
		for(int i=0;i<200;i++) {
			ss.append("9");
		
		}
		for(int i=1;i<200;i++) {
			ss.append("0");
		
		}
		ss.append("1");
		
		StringBuilder t =new StringBuilder("");
		
		for(int i=0;i<200;i++)
		t.append("9");
		
		System.out.println(ss.toString());
		System.out.printf(t.toString());
	}

}