Problem: Our beloved detective, Sherlock is currently trying to catch a serial killer who kills a person each day. Using his powers of deduction, he came to know that the killer has a strategy for selecting his next victim.

The killer starts with two potential victims on his first day, selects one of these two, kills selected victim and replaces him with a new person. He repeats this procedure each day. This way, each day he has two potential victims to choose from. Sherlock knows the initial two potential victims. Also, he knows the murder that happened on a particular day and the new person who replaced this victim.

You need to help him get all the pairs of potential victims at each day so that Sherlock can observe some pattern.

Input

First line of input contains two names (length of each of them doesn't exceed 10), the two initials potential victims. Next line contains integer n (1 ≤ n ≤ 1000), the number of days.

Next n lines contains two names (length of each of them doesn't exceed 10), first being the person murdered on this day and the second being the one who replaced that person.

The input format is consistent, that is, a person murdered is guaranteed to be from the two potential victims at that time. Also, all the names are guaranteed to be distinct and consists of lowercase English letters.

Output

Output n + 1 lines, the i-th line should contain the two persons from which the killer selects for the i-th murder. The (n + 1)-th line should contain the two persons from which the next victim is selected. In each line, the two names can be printed in any order.

Examples

Input

ross rachel
4
ross joey
rachel phoebe
phoebe monica
monica chandler


Output

ross rachel
joey rachel
joey phoebe
joey monica
joey chandler


Input

icm codeforces
1
codeforces technex


Output

icm codeforces
icm technex

Note

In first example, the killer starts with ross and rachel. 

  * After day 1, ross is killed and joey appears. 
  * After day 2, rachel is killed and phoebe appears. 
  * After day 3, phoebe is killed and monica appears. 
  * After day 4, monica is killed and chandler appears. 

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
double maxd(double a, double b) {
  if (a >= b) {
    return a;
  }
  return b;
}
double mind(double a, double b) {
  if (a <= b) {
    return a;
  }
  return b;
}
long long gcd(long long a, long long b) {
  if (a < b) {
    swap(a, b);
  }
  while (b) {
    long long r = a % b;
    a = b;
    b = r;
  }
  return a;
}
long long lcm(long long a, long long b) { return (a * b) / gcd(a, b); }
int isPrim(int a) {
  if (a == 1) {
    return 0;
  }
  for (int i = 2; i <= (a + 1) / 2; i++) {
    if (a % i == 0) {
      return 0;
    }
  }
  return 1;
}
long long mod_pow(long long x, long long n, long long mod) {
  long long ret = 1;
  while (n > 0) {
    if (n % 2 == 1) {
      ret = (ret * x) % mod;
    }
    x = (x * x) % mod;
    n = n / 2;
  }
  return ret;
}
struct XX {
  int u;
  int v;
  int t;
};
class xxIntu {
 public:
  bool operator()(const XX& riLeft, const XX& riRight) const {
    if ((riLeft.t) == (riRight.t)) {
      return riLeft.u < riRight.u;
    }
    return (riLeft.t) < (riRight.t);
  }
};
int index(string in) {
  if (in == "A") {
    return 0;
  } else if (in == "B") {
    return 1;
  } else if (in == "C") {
    return 2;
  } else if (in == "D") {
    return 3;
  } else if (in == "E") {
    return 4;
  } else if (in == "F") {
    return 5;
  } else if (in == "G") {
    return 6;
  } else if (in == "H") {
    return 7;
  } else if (in == "I") {
    return 8;
  } else if (in == "J") {
    return 9;
  } else if (in == "K") {
    return 10;
  } else if (in == "L") {
    return 11;
  } else if (in == "M") {
    return 12;
  } else if (in == "N") {
    return 13;
  } else if (in == "O") {
    return 14;
  } else if (in == "P") {
    return 15;
  } else if (in == "Q") {
    return 16;
  } else if (in == "R") {
    return 17;
  } else if (in == "S") {
    return 18;
  } else if (in == "T") {
    return 19;
  } else if (in == "U") {
    return 20;
  } else if (in == "V") {
    return 21;
  } else if (in == "W") {
    return 22;
  } else if (in == "X") {
    return 23;
  } else if (in == "Y") {
    return 24;
  } else if (in == "Z") {
    return 25;
  }
  return -1;
}
string rindex(int in) {
  if (in == 65) {
    return "A";
  } else if (in == 66) {
    return "B";
  } else if (in == 67) {
    return "C";
  } else if (in == 68) {
    return "D";
  } else if (in == 69) {
    return "E";
  } else if (in == 70) {
    return "F";
  } else if (in == 71) {
    return "G";
  } else if (in == 72) {
    return "H";
  } else if (in == 73) {
    return "I";
  } else if (in == 74) {
    return "J";
  } else if (in == 75) {
    return "K";
  } else if (in == 76) {
    return "L";
  } else if (in == 77) {
    return "M";
  } else if (in == 78) {
    return "N";
  } else if (in == 79) {
    return "O";
  } else if (in == 80) {
    return "P";
  } else if (in == 81) {
    return "Q";
  } else if (in == 82) {
    return "R";
  } else if (in == 83) {
    return "S";
  } else if (in == 84) {
    return "T";
  } else if (in == 85) {
    return "U";
  } else if (in == 86) {
    return "V";
  } else if (in == 87) {
    return "W";
  } else if (in == 88) {
    return "X";
  } else if (in == 89) {
    return "Y";
  } else if (in == 90) {
    return "Z";
  }
  return "";
}
int ppar[200001];
int rrank[200001];
void init(int n) {
  for (int i = 1; i <= n; i++) {
    ppar[i] = i;
    rrank[i] = 0;
  }
}
int find(int x) {
  if (ppar[x] == x) {
    return x;
  } else {
    return ppar[x] = find(ppar[x]);
  }
}
void unite(int x, int y) {
  x = find(x);
  y = find(y);
  if (x == y) {
    return;
  }
  if (rrank[x] < rrank[y]) {
    ppar[x] = ppar[y];
  } else {
    ppar[y] = x;
    if (rrank[x] == rrank[y]) {
      rrank[x]++;
    }
  }
}
bool same(int x, int y) { return find(x) == find(y); }
struct edge {
  int u;
  int v;
  int cost;
};
bool comp(edge& e1, edge& e2) { return e1.cost < e2.cost; }
edge es[1000];
int V, E;
int ans = 0;
int kruskal() {
  sort(es, es + E, comp);
  init(V);
  int res = 0;
  for (int i = 0; i < E; i++) {
    edge e = es[i];
    if (!same(e.u, e.v)) {
      unite(e.u, e.v);
      res += e.cost;
      ans++;
    }
  }
  return res;
}
int main(int argc, const char* argv[]) {
  string s1, s2;
  int n;
  cin >> s1 >> s2 >> n;
  string kil[1000];
  string rep[1000];
  for (int i = 0; i < n; i++) {
    cin >> kil[i] >> rep[i];
  }
  cout << s1 << " " << s2 << endl;
  for (int i = 0; i < n; i++) {
    if (s1 == kil[i]) {
      s1 = rep[i];
    } else {
      s2 = rep[i];
    }
    cout << s1 << " " << s2 << endl;
  }
  return 0;
}