Problem: You are given n pairs of integers (a_1, b_1), (a_2, b_2), …, (a_n, b_n). All of the integers in the pairs are distinct and are in the range from 1 to 2 ⋅ n inclusive.

Let's call a sequence of integers x_1, x_2, …, x_{2k} good if either 

  * x_1 < x_2 > x_3 < … < x_{2k-2} > x_{2k-1} < x_{2k}, or 
  * x_1 > x_2 < x_3 > … > x_{2k-2} < x_{2k-1} > x_{2k}. 



You need to choose a subset of distinct indices i_1, i_2, …, i_t and their order in a way that if you write down all numbers from the pairs in a single sequence (the sequence would be a_{i_1}, b_{i_1}, a_{i_2}, b_{i_2}, …, a_{i_t}, b_{i_t}), this sequence is good.

What is the largest subset of indices you can choose? You also need to construct the corresponding index sequence i_1, i_2, …, i_t.

Input

The first line contains single integer n (2 ≤ n ≤ 3 ⋅ 10^5) — the number of pairs.

Each of the next n lines contain two numbers — a_i and b_i (1 ≤ a_i, b_i ≤ 2 ⋅ n) — the elements of the pairs.

It is guaranteed that all integers in the pairs are distinct, that is, every integer from 1 to 2 ⋅ n is mentioned exactly once.

Output

In the first line print a single integer t — the number of pairs in the answer.

Then print t distinct integers i_1, i_2, …, i_t — the indexes of pairs in the corresponding order.

Examples

Input


5
1 7
6 4
2 10
9 8
3 5


Output


3
1 5 3


Input


3
5 4
3 2
6 1


Output


3
3 2 1

Note

The final sequence in the first example is 1 < 7 > 3 < 5 > 2 < 10.

The final sequence in the second example is 6 > 1 < 3 > 2 < 5 > 4.

Solution (in JAVA):

Solution:

import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.util.ArrayList;
import java.util.Collections;
import java.util.Comparator;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
import java.util.Scanner;

public class TaskD {
	public static void main(String[] args) {
		Scanner in = new Scanner(new BufferedReader(new InputStreamReader(System.in)));
		int n = in.nextInt();
		int[][] a = getIntArr(in, n, 2);
		int[] r = solve(n, a);
		System.out.println(r.length);
		System.out.println(str(r));
		in.close();
	}

	private static int[] solve(int n, int[][] a) {
		List<int[]> up = new ArrayList<>();
		List<int[]> down = new ArrayList<>();
		for (int i = 0; i < a.length; i++) {
			if (a[i][0] < a[i][1]) {
				up.add(new int[] { a[i][0], a[i][1], i + 1 });
			} else {
				down.add(new int[] { a[i][0], a[i][1], i + 1 });
			}
		}
		List<int[]> win = null;
		if (up.size() > down.size()) {
			Collections.sort(up, new Comparator<int[]>() {
				@Override
				public int compare(int[] o1, int[] o2) {
					return -Integer.compare(o1[1], o2[1]);
				}
			});
			win = up;
		} else {
			Collections.sort(down, new Comparator<int[]>() {
				@Override
				public int compare(int[] o1, int[] o2) {
					return Integer.compare(o1[0], o2[0]);
				}
			});
			win = down;
		}

		return win.stream().mapToInt(e -> e[2]).toArray();
	}

	static long mod = 1000000007;

	static long add(long a, long b) {
		long r = a + b;
		if (r < 0) {
			r += mod;
		}
		return r % mod;
	}

	static long mul(long a, long b) {
		return (a * b) % mod;
	}

	static int gcd(int a, int b) {
		if (b == 0) {
			return a;
		} else {
			return gcd(b, a % b);
		}
	}

	static String str(int[] a) {
		String[] str = new String[a.length];
		for (int i = 0; i < a.length; i++) {
			str[i] = a[i] + "";
		}
		return String.join(" ", str);
	}

	static int[] getIntArr(Scanner in, int size) {
		int[] arr = new int[size];
		for (int i = 0; i < size; i++) {
			arr[i] = in.nextInt();
		}
		return arr;
	}

	static int[][] getIntArr(Scanner in, int row, int col) {
		int[][] arr = new int[row][];
		for (int i = 0; i < row; i++) {
			arr[i] = getIntArr(in, col);
		}
		return arr;
	}

	static char[] getCharArr(Scanner in, int size) {
		char[] arr = in.next().toCharArray();
		return arr;
	}

	static String[] getStringArr(Scanner in, int size) {
		String[] arr = new String[size];
		for (int i = 0; i < size; i++) {
			arr[i] = in.next();
		}
		return arr;
	}

	static Map<Integer, List<Integer>> getEdges(Scanner in, int size, boolean directed) {
		Map<Integer, List<Integer>> edges = new HashMap<>();
		for (int i = 0; i < size; i++) {
			int from = in.nextInt();
			int to = in.nextInt();
			if (!edges.containsKey(from)) {
				edges.put(from, new ArrayList<Integer>());
			}
			edges.get(from).add(to);
			if (!directed) {
				if (!edges.containsKey(to)) {
					edges.put(to, new ArrayList<Integer>());
				}
				edges.get(to).add(from);
			}

		}
		return edges;
	}
}