Problem: Now you get Baby Ehab's first words: "Given an integer n, find the longest subsequence of [1,2, …, n-1] whose product is 1 modulo n." Please solve the problem.

A sequence b is a subsequence of an array a if b can be obtained from a by deleting some (possibly all) elements. The product of an empty subsequence is equal to 1.

Input

The only line contains the integer n (2 ≤ n ≤ 10^5).

Output

The first line should contain a single integer, the length of the longest subsequence.

The second line should contain the elements of the subsequence, in increasing order.

If there are multiple solutions, you can print any.

Examples

Input


5


Output


3
1 2 3 

Input


8


Output


4
1 3 5 7 

Note

In the first example, the product of the elements is 6 which is congruent to 1 modulo 5. The only longer subsequence is [1,2,3,4]. Its product is 24 which is congruent to 4 modulo 5. Hence, the answer is [1,2,3].

Solution (in JAVA):

Solution:
import java.util.*;
import java.lang.*;
import java.io.*;

public class C
{
	public static void main(String[] args) {
		new Runner().run();
	}
	
	static class Runner {
		FastReader in;
		
		public void run() {
			in = new FastReader();
			//int T = in.nextInt();
			StringBuffer sb = new StringBuffer();

			//while(T-- > 0) {
				int n = in.nextInt();
				
				boolean[] done = new boolean[n];
				Arrays.fill(done, true);
				
				for(int i=1; i<n; i++) {
					if(gcd(i, n) == 1) done[i] = false;
				}
				
				int cnt = 0;
				List<Integer> v = new ArrayList<Integer>();
				v.add(1);
				List<Integer> v2 = new ArrayList<Integer>();
				for(int i=2; i<n; i++) {
					if(done[i]) continue;
					done[i] = true;
					int inv = modInverse(i, n);
					//System.out.println(i + " " + inv);
					done[inv] = true;
					
					if(i == inv) {
						v2.add(i);
						continue;
					}
					v.add(i);
					v.add(inv);
				}
				
				long d = 1L;
				for(Integer i: v2) {
					d = (i * d) %n;
				}
				
				if(d == 1) {
					for(Integer i: v2) {
						v.add(i);
					}
				}
				
				sb.append(v.size() + "\n");
				Collections.sort(v);
				for(Integer i: v) {
					sb.append(i + " ");
				}
				sb.append("\n");
			//}
			System.out.println(sb.toString());
		}
		
		int modInverse(int a, int m) {
			int m0 = m;
			int y = 0, x = 1;
			
			if (m == 1) return 0;

			while (a > 1) {
				int q = a / m;
            	int t = m;

	            m = a % m;
	            a = t;
	            t = y;
 
	            y = x - q * y;
    	        x = t;
			}
 
        	if (x < 0)
            	x += m0;
 
        	return x;
    	}
    	
    	int gcd(int a, int b) {
    		if(b==0) return a;
    		return gcd(b, a%b);
    	}
	}
	
	static class FastReader {
		BufferedReader br;
		StringTokenizer st;
	 
		public FastReader()
		{
		    br = new BufferedReader(
		        new InputStreamReader(System.in));
		}
	 
		String next()
		{
		    while (st == null || !st.hasMoreElements()) {
		        try {
		            st = new StringTokenizer(br.readLine());
		        }
		        catch (IOException e) {
		            e.printStackTrace();
		        }
		    }
		    return st.nextToken();
		}
	 
		int nextInt() { return Integer.parseInt(next()); }
	 
		long nextLong() { return Long.parseLong(next()); }
	 
		double nextDouble()
		{
		    return Double.parseDouble(next());
		}
	 
		String nextLine()
		{
		    String str = "";
		    try {
		        str = br.readLine();
		    }
		    catch (IOException e) {
		        e.printStackTrace();
		    }
		    return str;
		}
    	}
}