Problem: Mr. Santa asks all the great programmers of the world to solve a trivial problem. He gives them an integer m and asks for the number of positive integers n, such that the factorial of n ends with exactly m zeroes. Are you among those great programmers who can solve this problem?

Input

The only line of input contains an integer m (1 ≤ m ≤ 100 000) — the required number of trailing zeroes in factorial.

Output

First print k — the number of values of n such that the factorial of n ends with m zeroes. Then print these k integers in increasing order.

Examples

Input

1


Output

5
5 6 7 8 9 

Input

5


Output

0

Note

The factorial of n is equal to the product of all integers from 1 to n inclusive, that is n! = 1·2·3·...·n.

In the first sample, 5! = 120, 6! = 720, 7! = 5040, 8! = 40320 and 9! = 362880.

Solution (in JAVA):

Solution:
import java.io.*;
import java.lang.reflect.Array;
import java.util.*;

public class Codeforces {

    public int check(int n){
        return n < 5?0:n/5+check(n/5);
    }

    public  void solve() {
        FastScanner fs = new FastScanner();
        PrintWriter out = new PrintWriter(System.out);
        int m = fs.nextInt();
        int n = 1;
        while (check(n) < m ){
            n++;
        }
        int k = 0;
        ArrayList<Integer>ans = new ArrayList<>();
        while (check(n) == m){
            ans.add(n);
            n++;
            k++;
        }
        out.println(k);
        for(int i:ans)
            out.print(i+" ");
        out.flush();


    }
    public static void main(String[]args){
        try{
            new Codeforces().solve();
        }catch (Exception e){
            e.printStackTrace();
        }

    }
    class FastScanner {
        BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
        StringTokenizer st=new StringTokenizer("");
        String next() {
            while (!st.hasMoreTokens())
                try {
                    st=new StringTokenizer(br.readLine());
                } catch (IOException e) {
                    e.printStackTrace();
                }
            return st.nextToken();
        }
        String nextLine()
        {
            String str = "";
            try
            {
                str = br.readLine();
            }
            catch (IOException e)
            {
                e.printStackTrace();
            }
            return str;
        }

        int nextInt() {
            return Integer.parseInt(next());
        }
        long nextLong() {
            return Long.parseLong(next());
        }
    }
}