Problem: Let s(x) be sum of digits in decimal representation of positive integer x. Given two integers n and m, find some positive integers a and b such that 

  * s(a) ≥ n, 
  * s(b) ≥ n, 
  * s(a + b) ≤ m. 

Input

The only line of input contain two integers n and m (1 ≤ n, m ≤ 1129).

Output

Print two lines, one for decimal representation of a and one for decimal representation of b. Both numbers must not contain leading zeros and must have length no more than 2230.

Examples

Input

6 5


Output

6 
7


Input

8 16


Output

35 
53

Note

In the first sample, we have n = 6 and m = 5. One valid solution is a = 6, b = 7. Indeed, we have s(a) = 6 ≥ n and s(b) = 7 ≥ n, and also s(a + b) = s(13) = 4 ≤ m.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
const long long M = 1e9 + 7;
const long long INF = 1e9;
inline long long pwr(long long base, long long n, long long m) {
  long long ans = 1;
  while (n > 0) {
    if (n % 2 == 1) ans = (ans * base) % m;
    base = (base * base) % m;
    n /= 2;
  }
  return ans;
}
int n, m;
int main() {
  ios_base::sync_with_stdio(false);
  cin.tie(NULL);
  cin >> n >> m;
  for (int i = 0; i < n; i++) cout << 5;
  cout << "\n";
  for (int j = 0; j < n; j++) {
    if (j == n - 1)
      cout << 5;
    else
      cout << 4;
  }
  return 0;
}