Problem: Let s(x) be sum of digits in decimal representation of positive integer x. Given two integers n and m, find some positive integers a and b such that 

  * s(a) ≥ n, 
  * s(b) ≥ n, 
  * s(a + b) ≤ m. 

Input

The only line of input contain two integers n and m (1 ≤ n, m ≤ 1129).

Output

Print two lines, one for decimal representation of a and one for decimal representation of b. Both numbers must not contain leading zeros and must have length no more than 2230.

Examples

Input

6 5


Output

6 
7


Input

8 16


Output

35 
53

Note

In the first sample, we have n = 6 and m = 5. One valid solution is a = 6, b = 7. Indeed, we have s(a) = 6 ≥ n and s(b) = 7 ≥ n, and also s(a + b) = s(13) = 4 ≤ m.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
int main() {
  int n, m;
  scanf("%d%d", &n, &m);
  int t = (n - 1) / 9 + 1;
  for (int i = 0; i < t; i++) {
    putchar('9');
  }
  for (int i = 0; i < t - 1; i++) {
    putchar('0');
  }
  printf("1\n");
  for (int i = 0; i < t; i++) {
    putchar('9');
  }
  putchar('\n');
  return 0;
}