Problem: PolandBall lives in a forest with his family. There are some trees in the forest. Trees are undirected acyclic graphs with k vertices and k - 1 edges, where k is some integer. Note that one vertex is a valid tree.

There is exactly one relative living in each vertex of each tree, they have unique ids from 1 to n. For each Ball i we know the id of its most distant relative living on the same tree. If there are several such vertices, we only know the value of the one with smallest id among those.

How many trees are there in the forest?

Input

The first line contains single integer n (1 ≤ n ≤ 104) — the number of Balls living in the forest.

The second line contains a sequence p1, p2, ..., pn of length n, where (1 ≤ pi ≤ n) holds and pi denotes the most distant from Ball i relative living on the same tree. If there are several most distant relatives living on the same tree, pi is the id of one with the smallest id.

It's guaranteed that the sequence p corresponds to some valid forest.

Hacking: To hack someone, you should provide a correct forest as a test. The sequence p will be calculated according to the forest and given to the solution you try to hack as input. Use the following format:

In the first line, output the integer n (1 ≤ n ≤ 104) — the number of Balls and the integer m (0 ≤ m < n) — the total number of edges in the forest. Then m lines should follow. The i-th of them should contain two integers ai and bi and represent an edge between vertices in which relatives ai and bi live. For example, the first sample is written as follows:
    
    
      
    5 3  
    1 2  
    3 4  
    4 5  
    

Output

You should output the number of trees in the forest where PolandBall lives.

Interaction

From the technical side, this problem is interactive. However, it should not affect you (except hacking) since there is no interaction.

Examples

Input

5
2 1 5 3 3

Output

2

Input

1
1


Output

1

Note

In the first sample testcase, possible forest is: 1-2 3-4-5. 

There are 2 trees overall.

In the second sample testcase, the only possible graph is one vertex and no edges. Therefore, there is only one tree.

Solution (in JAVA):

Solution:


import java.util.*;
import java.util.function.Function;
import java.util.stream.Collectors;
import java.io.*;
import java.math.*;
import java.text.*;

public class PolandBallForest {

	static InputReader in = new InputReader(System.in);
	static OutputWriter out = new OutputWriter(System.out);
	
	static void dfs(boolean vis[],int src,ArrayList<ArrayList<Integer>> ara) {
		vis[src]=true;
		for(int j:ara.get(src)) {
			if(!vis[j]) {
				vis[j]=true;
				dfs(vis,j,ara);
			}
		}
	}

	public static void main(String[] args) throws NumberFormatException, IOException {
		// TODO Auto-generated method stub
		BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
		int t = 1;
		while (t > 0) {
			int n=i();
			int arr[]=new int[n];
			for(int i=0;i<n;i++)
				arr[i]=i();
			ArrayList<ArrayList<Integer>> ar = new ArrayList<ArrayList<Integer>>(n+1);
			for(int i=0;i<=n;i++) {
				ar.add(new ArrayList<Integer>());
			}
			for(int i=1;i<=n;i++) {
				ar.get(i).add(arr[i-1]);
				ar.get(arr[i-1]).add(i);
			}
			long count=0;
			boolean vis[]=new boolean[n+1];
			for(int i=1;i<=n;i++) {
				if(!vis[i]) {
					count++;
					dfs(vis,i,ar);
				}
			}
			System.out.println(count);
			

			t--;
		}

		//		long l=l();
		//		String s=s();     //	ONLY BEFORE SPACE IN STRING , ELSE USE BUFFER-READER

	}

	public static long pow(long a, long b) {
		long m = 1000000007;
		long result = 1;
		while (b > 0) {
			if (b % 2 != 0) {
				result = (result * a) % m;
				b--;
			}
			a = (a * a) % m;
			b /= 2;
		}
		return result % m;
	}

	public static long gcd(long a, long b) {
		if (a == 0) {
			return b;
		}
		return gcd(b % a, a);
	}

	public static long lcm(long a, long b) {
		return a * (b / gcd(a, b));
	}

	public static long l() {
		String s = in.String();
		return Long.parseLong(s);
	}

	public static void pln(String value) {
		System.out.println(value);
	}

	public static int i() {
		return in.Int();
	}

	public static String s() {
		return in.String();
	}

}

class pair {
	int x, y;

	pair(int x, int y) {
		this.x = x;
		this.y = y;
	}
}

class CompareValue {

	static void compare(pair arr[], int n) {
		Arrays.sort(arr, new Comparator<pair>() {
			public int compare(pair p1, pair p2) {
				return p1.y - p2.y;
			}
		});
	}
}

class CompareKey {
	static void compare(pair arr[], int n) {
		Arrays.sort(arr, new Comparator<pair>() {
			public int compare(pair p1, pair p2) {
				return p2.x - p1.x;
			}
		});
	}
}

class InputReader {
	private InputStream stream;
	private byte[] buf = new byte[1024];
	private int curChar;
	private int numChars;
	private SpaceCharFilter filter;

	public InputReader(InputStream stream) {
		this.stream = stream;
	}

	public int read() {
		if (numChars == -1)
			throw new InputMismatchException();
		if (curChar >= numChars) {
			curChar = 0;
			try {
				numChars = stream.read(buf);
			} catch (IOException e) {
				throw new InputMismatchException();
			}
			if (numChars <= 0)
				return -1;
		}
		return buf[curChar++];
	}

	public int Int() {
		int c = read();
		while (isSpaceChar(c))
			c = read();
		int sgn = 1;
		if (c == '-') {
			sgn = -1;
			c = read();
		}
		int res = 0;
		do {
			if (c < '0' || c > '9')
				throw new InputMismatchException();
			res *= 10;
			res += c - '0';
			c = read();
		} while (!isSpaceChar(c));
		return res * sgn;
	}

	public String String() {
		int c = read();
		while (isSpaceChar(c))
			c = read();
		StringBuilder res = new StringBuilder();
		do {
			res.appendCodePoint(c);
			c = read();
		} while (!isSpaceChar(c));
		return res.toString();
	}

	public boolean isSpaceChar(int c) {
		if (filter != null)
			return filter.isSpaceChar(c);
		return c == ' ' || c == '\n' || c == '\r' || c == '\t' || c == -1;
	}

	public String next() {
		return String();
	}

	public interface SpaceCharFilter {
		public boolean isSpaceChar(int ch);
	}

	public double readDouble() {
		int c = read();
		while (isSpaceChar(c)) {
			c = read();
		}
		int sgn = 1;
		if (c == '-') {
			sgn = -1;
			c = read();
		}
		double res = 0;
		while (!isSpaceChar(c) && c != '.') {
			if (c == 'e' || c == 'E') {
				return res * Math.pow(10, Int());
			}
			if (c < '0' || c > '9') {
				throw new InputMismatchException();
			}
			res *= 10;
			res += c - '0';
			c = read();
		}
		if (c == '.') {
			c = read();
			double m = 1;
			while (!isSpaceChar(c)) {
				if (c == 'e' || c == 'E') {
					return res * Math.pow(10, Int());
				}
				if (c < '0' || c > '9') {
					throw new InputMismatchException();
				}
				m /= 10;
				res += (c - '0') * m;
				c = read();
			}
		}
		return res * sgn;
	}
}

class OutputWriter {
	private final PrintWriter writer;

	public OutputWriter(OutputStream outputStream) {
		writer = new PrintWriter(new BufferedWriter(new OutputStreamWriter(outputStream)));
	}

	public OutputWriter(Writer writer) {
		this.writer = new PrintWriter(writer);
	}

	public void print(Object... objects) {
		for (int i = 0; i < objects.length; i++) {
			if (i != 0) {
				writer.print(' ');
			}
			writer.print(objects[i]);
		}
		writer.flush();
	}

	public void printLine(Object... objects) {
		print(objects);
		writer.println();
		writer.flush();
	}

	public void close() {
		writer.close();
	}

	public void flush() {
		writer.flush();
	}
}

class IOUtils {
	public static int[] readIntArray(InputReader in, int size) {
		int[] array = new int[size];
		for (int i = 0; i < size; i++)
			array[i] = in.Int();
		return array;
	}
}

/**
 * TO SORT VIA TWO KEYS , HERE IT IS ACCORDING TO ASCENDING ORDER OF FIRST AND
 * DESC ORDER OF SECOND
 * LIST name-list 
 * ARRAYLIST
 * COPY PASTE
 * 
 * Collections.sort(list, (first,second) ->{
		    	if(first.con >second.con)
		    		return -1;
		    	else if(first.con<second.con)
		    		return 1;
		    	else {
		    		if(first.index >second.index)
		    			return 1;
		    		else
		    			return -1;
		    	}
		    	
		    });
 * 
 */

/**
 * 
 

  DECIMAL FORMATTER
Double k = in.readDouble();

System.out.println(k);
DecimalFormat df = new DecimalFormat("#.##");
System.out.print(df.format(k));
out.printLine(k);
* 
* */