Problem: Takahashi has a water bottle with the shape of a rectangular prism whose base is a square of side a~\mathrm{cm} and whose height is b~\mathrm{cm}. (The thickness of the bottle can be ignored.)

We will pour x~\mathrm{cm}^3 of water into the bottle, and gradually tilt the bottle around one of the sides of the base.

When will the water be spilled? More formally, find the maximum angle in which we can tilt the bottle without spilling any water.

Constraints

* All values in input are integers.
* 1 \leq a \leq 100
* 1 \leq b \leq 100
* 1 \leq x \leq a^2b

Input

Input is given from Standard Input in the following format:


a b x


Output

Print the maximum angle in which we can tilt the bottle without spilling any water, in degrees. Your output will be judged as correct when the absolute or relative error from the judge's output is at most 10^{-6}.

Examples

Input

2 2 4


Output

45.0000000000


Input

12 21 10


Output

89.7834636934


Input

3 1 8


Output

4.2363947991

Solution (in JAVA):

Solution:
import java.io.PrintStream;
import java.util.Scanner;

public class Main {
	public static void main(String[] args) throws Exception{
		new Main(new Scanner(System.in), System.out, System.err).exec();
	}
	public final Scanner sc;
	public final PrintStream out, err;
	public Main(final Scanner sc, final PrintStream out, final PrintStream err) {
		this.sc = sc;this.out = out;this.err = err;
	}
	static private final long pair(int a, int b) {return (((long)a) << 32) + b;}
	static private final int upper(long v) {return (int)(v >> 32);}
	static private final int lower(long v) {return (int)(v & 0xFFFFFFFF);}

	//-----------------------------------------

	static private final long load(int end, int length) {
		return pair(end, length);
	}
	static private final int end(long load) {
		return upper(load);
	}
	static private final int length(long load) {
		return lower(load);
	}
	static private final long score(int count, int last) {
		return pair(count, last);
	}
	static private final int count(long score) {
		return upper(score);
	}
	static private final int last(long score) {
		return lower(score);
	}

	//------------------------------------------

	public void exec() throws Exception{
		final long a = sc.nextLong();
		final long b = sc.nextLong();
		final long x = sc.nextLong();

		double bl = 0;
		double al = 0;

		if(b*a*a < 2*x) {
			//半分より多いケース
			err.println("H");
			al = a;
			bl=2.0*(1.0*b -(1.0*x)/(1.0*a*a));
		}else {
			//半分より少ないケース
			err.println("L");
			bl = b;
			al = (2.0*x)/(1.0*a*b);
		}
		err.println(al+"/"+bl);
		out.println(Math.toDegrees(Math.atan(bl/al)));

	}
}