Problem: Mr. Santa asks all the great programmers of the world to solve a trivial problem. He gives them an integer m and asks for the number of positive integers n, such that the factorial of n ends with exactly m zeroes. Are you among those great programmers who can solve this problem?

Input

The only line of input contains an integer m (1 ≤ m ≤ 100 000) — the required number of trailing zeroes in factorial.

Output

First print k — the number of values of n such that the factorial of n ends with m zeroes. Then print these k integers in increasing order.

Examples

Input

1


Output

5
5 6 7 8 9 

Input

5


Output

0

Note

The factorial of n is equal to the product of all integers from 1 to n inclusive, that is n! = 1·2·3·...·n.

In the first sample, 5! = 120, 6! = 720, 7! = 5040, 8! = 40320 and 9! = 362880.

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.*;
import java.math.*;

public class B633 {

	public static BufferedReader read = null;
	public static PrintWriter out = null;
	public static StringTokenizer token = null;
	
	
	public static void solve()
	{
		int m = nint();
		String ans = "";
		int ct = 0;
		int f = 0;
		int i = 1;
		while(f < m+1)
		{
			int k = i;
			while(k%5 == 0)
			{
				f++;
				k/=5;
			}
				
			if(f == m)
			{
				ct++;
				ans+=i+" ";
			}
			i++;
		}
		
		out.println(ct);
		if(ct >=1) out.println(ans);
	}
	
	public static void main(String[] args)
	{
		read = new BufferedReader(new InputStreamReader(System.in));
		out = new PrintWriter(System.out);
		solve();
		out.flush();
		out.close();
		
	}
	
	// i/o functions
	public static String next() // returns the next string
	{
		while(token == null || !token.hasMoreTokens())
		{
			try {
				token = new StringTokenizer(read.readLine());
			} catch (IOException e) {
				// TODO Auto-generated catch block
				e.printStackTrace();
			}
		}
		return token.nextToken();
	}
	
	public static int nint()
	{
		return Integer.parseInt(next());
	}
	public static long nlong()
	{
		return Long.parseLong(next());
	}
	public static double ndouble()
	{
		return Double.parseDouble(next());
	}
	public static int[] narr(int n)
	{
		int[] a = new int[n];
		for(int i=0; i<n; i++) a[i] = nint();
		return a;
	}
	
	public static long[] nal(int n)
	{
		long[] a = new long[n];
		for(int i=0; i<n; i++) a[i] = nlong();
		return a;
	}
	
	
}