Problem: The main land of Japan called Honshu is an island surrounded by the sea. In such an island, it is natural to ask a question: "Where is the most distant point from the sea?" The answer to this question for Honshu was found in 1996. The most distant point is located in former Usuda Town, Nagano Prefecture, whose distance from the sea is 114.86 km.

In this problem, you are asked to write a program which, given a map of an island, finds the most distant point from the sea in the island, and reports its distance from the sea. In order to simplify the problem, we only consider maps representable by convex polygons.



Input

The input consists of multiple datasets. Each dataset represents a map of an island, which is a convex polygon. The format of a dataset is as follows.


n
x1    y1
.
.
.
xn    yn


Every input item in a dataset is a non-negative integer. Two input items in a line are separated by a space.

n in the first line is the number of vertices of the polygon, satisfying 3 ≤ n ≤ 100. Subsequent n lines are the x- and y-coordinates of the n vertices. Line segments (xi, yi) - (xi+1, yi+1) (1 ≤ i ≤ n - 1) and the line segment (xn, yn) - (x1, y1) form the border of the polygon in counterclockwise order. That is, these line segments see the inside of the polygon in the left of their directions. All coordinate values are between 0 and 10000, inclusive.

You can assume that the polygon is simple, that is, its border never crosses or touches itself. As stated above, the given polygon is always a convex one.

The last dataset is followed by a line containing a single zero.

Output

For each dataset in the input, one line containing the distance of the most distant point from the sea should be output. An output line should not contain extra characters such as spaces.

The answer should not have an error greater than 0.00001 (10-5 ). You may output any number of digits after the decimal point, provided that the above accuracy condition is satisfied.

Example

Input

4
0 0
10000 0
10000 10000
0 10000
3
0 0
10000 0
7000 1000
6
0 40
100 20
250 40
250 70
100 90
0 70
3
0 0
10000 10000
5000 5001
0


Output

5000.000000
494.233641
34.542948
0.353553

Solution (in CPP):

Solution:
#include <iostream>
#include <string>
#include <vector>
#include <deque>
#include <queue>
#include <algorithm>
#include <iomanip>
#include <set>
#include <map>
#include <bitset>
#include <cmath>
#include <complex>
#include <array>
#include <functional>

using namespace std;

#define REP(i,n) for(ll (i) = (0);(i) < (n);++i)
#define REV(i,n) for(ll (i) = (n) - 1;(i) >= 0;--i)
#define PB push_back
#define EB emplace_back
#define MP make_pair
#define FI first
#define SE second
#define SHOW1d(v,n) {REP(WW,n)cerr << v[WW] << ' ';cerr << endl << endl;}
#define SHOW2d(v,WW,HH) {REP(W_,WW){REP(H_,HH)cerr << v[W_][H_] << ' ';cerr << endl;}cerr << endl;}
#define ALL(v) v.begin(),v.end()
#define Decimal fixed<<setprecision(20)
#define INF 1000000000
#define LLINF 1000000000000000000LL
#define MOD 998244353

typedef long long ll;
typedef pair<ll,ll> P;
//--------geometry original ------------------
#define curr(PP, i) PP[i]
#define next(PP, i) PP[(i+1)%PP.size()]
#define diff(PP, i) (next(PP, i) - curr(PP, i))
#define eq(n,m) (abs((n)-(m)) < EPS)

typedef long long ll;
typedef pair<ll, ll> P;

const double EPS = 1e-8;
const double EPS_GIG = 1e-3;
const double PI = acos(-1.0);
typedef complex<double> point;
namespace std {
	bool operator < (const point& a, const point& b) {
		return real(a) != real(b) ? real(a) < real(b) : imag(a) < imag(b);
	}

	bool operator == (const point& a,const point& b) {
		return (abs(a.real() - b.real()) < EPS && abs(a.imag() - b.imag()) < EPS);
	}
}
struct circle {
	point p; double r;
	circle(){}
	circle(const point &p, double r) : p(p), r(r) { }
};

// 扇型、中心と半径、二つの端点
// 現在中心角が180未満の前提
struct sector {
	point o;
	point a, b;
	double r;
	sector(){}
	sector(point O, point A, point B, double _r) :o(O), a(A), b(B), r(_r) {}
};

struct segment : public array<point, 2> {
	segment(const point &a, const point &b) {
		at(0) = a;
		at(1) = b;
	}
};

double cross(const point& a, const point& b) {
	return imag(conj(a)*b);
}

double dot(const point& a, const point& b) {
	return real(conj(a)*b);
}

//角度足し算
double add_rad(double a,double b){
	double ret = a + b;
	if(ret > 2 * PI)ret -= 2 * PI;
	return ret;
}

//なす角(vector)
double angle(const point &a,const point &b) {
	auto tmp = abs(arg(a) - arg(b));
	return min(tmp, 2 * PI - tmp);
}

double angle(const segment &s1,const segment &s2) {
	return angle(s1[1] - s1[0], s2[1] - s2[0]);
}

//点の回転
point rotate(const point &p, double rad) {
	double x = p.real() * cos(rad) - p.imag() * sin(rad);
	double y = p.imag() * cos(rad) + p.real() * sin(rad);
	return point(x, y);
}

//並行
bool isParallel(const point &a, const point &b){
    return abs(cross(a,b)) < EPS;
}
bool isParallel(const segment &a, const segment &b){
    return isParallel(a[1]-a[0], b[1]-b[0]);
}
//直行
bool isOrthogonal(const point &a,const point &b){
	return abs(angle(a,b) - PI / 2) < EPS;
}
bool isOrthogonal(const segment &a,const segment &b){
	return isOrthogonal(a[1]-a[0],b[1]-b[0]);
}

/*
a → b で時計方向に折れて b → c
a → b で半時計方向に折れて b → c
a → b で逆を向いて a を通り越して b → c
a → b でそのまま b → c
a → b で逆を向いて b → c ( または b == c )
*/

int ccw(point a, point b, point c) {
	b -= a; c -= a;
	if (cross(b, c) > EPS)   return +1;       // counter clockwise
	if (cross(b, c) + EPS < 0)   return -1;       // clockwise
	if (dot(b, c) < 0)     return +2;       // c--a--b on line
	if (norm(b) < norm(c)) return -2;       // a--b--c on line
	return 0;
}

bool intersectLL(const segment &l, const segment &m) {
	return abs(cross(l[1] - l[0], m[1] - m[0])) > EPS || // non-parallel
		abs(cross(l[1] - l[0], m[0] - l[0])) < EPS;   // same line
}
bool intersectLS(const segment &l, const segment &s) {
	return cross(l[1] - l[0], s[0] - l[0])*       // s[0] is left of l
		cross(l[1] - l[0], s[1] - l[0]) < EPS; // s[1] is right of l
}
bool intersectLP(const segment &l, const point &p) {
	return abs(cross(l[1] - p, l[0] - p)) < EPS;
}
bool intersectSP(const segment &s, const point &p) {
	auto a = s[0] - p;
	auto b = s[1] - p;
	return (abs(cross(a, b)) < EPS && dot(a, b) <= EPS); // triangle inequality
}
//端点の交差も考える
bool intersectSS(const segment &s, const segment &t) {
	return ccw(s[0], s[1], t[0]) * ccw(s[0], s[1], t[1]) <= 0 &&
		ccw(t[0], t[1], s[0]) * ccw(t[0], t[1], s[1]) <= 0;
}
//端点の交差hは考えない
bool strictIntersectSS(const segment &s, const segment &t) {
	return ccw(s[0], s[1], t[0]) * ccw(s[0], s[1], t[1]) == -1 &&
		ccw(t[0], t[1], s[0]) * ccw(t[0], t[1], s[1]) == -1;
}

point projection(const segment &l, const point &p) {
	double t = dot(p - l[0], l[0] - l[1]) / norm(l[0] - l[1]);
	return l[0] + t*(l[0] - l[1]);
}
point reflection(const segment &l, const point &p) {
	return p + 2. * (projection(l, p) - p);
}
double distanceLP(const segment &l, const point &p) {
	return abs(p - projection(l, p));
}
double distanceLL(const segment &l, const segment &m) {
	return intersectLL(l, m) ? 0 : distanceLP(l, m[0]);
}
double distanceLS(const segment &l, const segment &s) {
	if (intersectLS(l, s)) return 0;
	return min(distanceLP(l, s[0]), distanceLP(l, s[1]));
}
double distanceSP(const segment &s, const point &p) {
	const point r = projection(s, p);
	if (intersectSP(s, r)) return abs(r - p);
	return min(abs(s[0] - p), abs(s[1] - p));
}
double distanceSS(const segment &s, const segment &t) {
	if (intersectSS(s, t)) return 0;
	return min(min(distanceSP(s, t[0]), distanceSP(s, t[1])),
		min(distanceSP(t, s[0]), distanceSP(t, s[1])));
}
double distancePP(const point &a,const point &b){
	return abs(a-b);
}

/*多角形内包判定
half-line crossing method
OUT:0
ON:1
IN:2
*/
int contains(const vector<point>& Poly, const point& p) {
	bool in = false;
	for (int i = 0; i < Poly.size(); ++i) {
		point a = curr(Poly, i) - p, b = next(Poly, i) - p;
		if (imag(a) > imag(b)) swap(a, b);
		if (imag(a) + EPS <= 0 && EPS < imag(b))
			if (cross(a, b) < 0) in = !in;
		if (abs(cross(a, b)) < EPS && dot(a, b) <= EPS) return 1;
	}
	return in ? 2 : 0;
}

/*
OUT:0
ON:1
IN:2
*/
int contain_sector(const sector &sec, point &p){
	if(eq(abs(p - sec.o), sec.r))return 1;
	if(intersectSP(segment(sec.o, sec.a), p))return 1;
	if(intersectSP(segment(sec.o, sec.b), p))return 1;
	if(abs(p - sec.o) + EPS > sec.r)return 0;
	point vec = p - sec.o;
	point vecA = sec.a - sec.o;
	point vecB = sec.b - sec.o;
	if(angle(vec, vecA) + EPS < angle(vecA, vecB) && angle(vec, vecB) + EPS < angle(vecA, vecB))return 2;
	return 0;
}

//交点
point crosspointSS(const segment &l, const segment &m) {
	double A = cross(l[1] - l[0], m[1] - m[0]);
	double B = cross(l[1] - l[0], l[1] - m[0]);
	if (abs(A) < EPS && abs(B) < EPS) return m[0]; // same line
	if (abs(A) < EPS) return point(INF,INF); // !!!PRECONDITION NOT SATISFIED!!!
	return m[0] + B / A * (m[1] - m[0]);
}

vector<point> crosspointCL(const circle &c, const segment &l) {
	auto ret = vector<point>(2, point(INF, INF));
	auto pro_p = projection(l, c.p);
	auto dist = distanceLP(l, c.p);
	if(abs(dist - c.r) < EPS){
		ret[0] = pro_p;
		return ret;
	}
	if(c.r < dist){
		return ret;
	}
	point vec = (l[1] - l[0]) * sqrt(c.r * c.r - dist * dist) / abs(l[1] - l[0]);
	ret[0] = pro_p + vec;
	ret[1] = pro_p - vec;
	return ret;
}

vector<point> crosspointCC(const circle c1, const circle c2) {
	auto ret = vector<point>(2, point(INF, INF));
	auto dist = abs(c2.p - c1.p);
	if(eq(dist, c1.r + c2.r) || eq(dist, abs(c2.r - c1.r))){
		auto tmp = c2.p - c1.p;
		ret[0] = c1.p + tmp * (c1.r / dist);
		return ret;
	}
	if(c1.r + c2.r < dist || dist < abs(c1.r - c2.r)){
		return ret;
	}
	auto alpha = acos((c1.r * c1.r + dist * dist - c2.r * c2.r) / (2 * c1.r * dist));
	auto theta = atan2(c2.p.imag() - c1.p.imag(), c2.p.real() - c1.p.real());
	ret[0] = c1.p + point(cos(theta + alpha) * c1.r, sin(theta + alpha) * c1.r);
	ret[1] = c1.p + point(cos(theta - alpha) * c1.r, sin(theta - alpha) * c1.r);
	return ret;
}

bool isOnSector(const sector sec, const point p) {
	point vec = p - sec.o;
	point vecA = sec.a - sec.o;
	point vecB = sec.b - sec.o;
	if(eq(angle(vec, vecA) + angle(vec, vecB), angle(vecA, vecB)))return true;
	return false;
}

vector<point> crosspointSecS(const sector sec, const segment s) {
	circle c = circle(sec.o, sec.r);
	auto ret = crosspointCL(c, s);
	point inf = point(INF, INF);
	REP(i, 2){
		if(eq(ret[i], inf))continue;
		if(!isOnSector(sec, ret[i])){
			ret[i] = inf;
			continue;
		}
		if(!intersectSP(s, ret[i])){
			ret[i] = inf;
		}
	}
	return ret;
}
vector<point> crosspointSecSec(const sector sec1, const sector sec2) {
	circle c1 = circle(sec1.o, sec1.r);
	circle c2 = circle(sec2.o, sec2.r);
	auto ret = crosspointCC(c1, c2);
	point inf = point(INF, INF);
	REP(i, 2){
		if(!isOnSector(sec1, ret[i])){
			ret[i] = inf;
			continue;
		}
		if(!isOnSector(sec2, ret[i])){
			ret[i] = inf;
		}
	}
	return ret;
}


//凸包
vector<point> convex_hull(vector<point> ps) {
	int n = ps.size(), k = 0;
	sort(ps.begin(), ps.end());
	vector<point> ch(2*n);
	for (int i = 0; i < n; ch[k++] = ps[i++]) // lower-hull
		while (k >= 2 && ccw(ch[k-2], ch[k-1], ps[i]) == -1) --k;
	for (int i = n-2, t = k+1;i >= 0; ch[k++] = ps[i--]) // upper-hull
		while (k >= t && ccw(ch[k-2], ch[k-1], ps[i]) == -1) --k;
	ch.resize(k - 1);
	return ch;
}

//見えるか(可視グラフ用)
bool block_off(const point &a, const point &b, const vector<point> &obj) {
  point m = (a + b) * 0.5;
  bool on = false, in = false;
  for (int j = 0; j < obj.size(); ++j) {
    point c = curr(obj,j), d = next(obj,j);
    if (imag(d) < imag(c)) swap(c, d);
    if (cross(a-c,b-c) * cross(a-d,b-d) < 0 &&    // strictly intersect.
        cross(c-a,d-a) * cross(c-b,d-b) < 0) return true;
    if (cross(a-c,b-c) == 0 && dot(a-c,b-c) < 0) return true;
    if (imag(c) <= imag(m) && imag(m) < imag(d))  // strictly contain.
      if (cross(c-m,d-m) < 0) in = !in;
    if (cross(c-m,d-m) == 0 && dot(c-m,d-m) <= EPS) on = true;
  }
  return !on && in;
}

//面積
double area(const vector<point>& p) {
	double A = 0;
	for (int i = 0; i < p.size(); ++i)
		A += cross(curr(p, i), next(p, i));
	return A / 2.;
}

//凸包判定
bool isConvex(vector<point> poly){
	int sz = poly.size();
	REP(i,sz){
		if(ccw(poly[i],poly[(i+1)%sz],poly[(i+2)%sz]) == -1)return false;
	}
	return true;
}

double convex_diameter(const vector<point> &pt) {
  const int n = pt.size();
  int is = 0, js = 0;
  for (int i = 1; i < n; ++i) {
    if (imag(pt[i]) > imag(pt[is])) is = i;
    if (imag(pt[i]) < imag(pt[js])) js = i;
  }
  double maxd = norm(pt[is]-pt[js]);

  int i, maxi, j, maxj;
  i = maxi = is;
  j = maxj = js;
  do {
    if (cross(diff(pt,i), diff(pt,j)) >= 0) j = (j+1) % n;
    else i = (i+1) % n;
    if (norm(pt[i]-pt[j]) > maxd) {
      maxd = norm(pt[i]-pt[j]);
      maxi = i; maxj = j;
    }
  } while (i != is || j != js);
  return sqrt(maxd); /* farthest pair is (maxi, maxj). */
}

vector<point> convex_cut(const vector<point> P, const segment& l) {
  vector<point> Q;
  for (int i = 0; i < P.size(); ++i) {
    point A = curr(P, i), B = next(P, i);
    if (ccw(l[0], l[1], A) != -1) Q.push_back(A);
    if (ccw(l[0], l[1], A)*ccw(l[0], l[1], B) < 0)
      Q.push_back(crosspointSS(segment(A, B), l));
  }
  return Q;
}

bool isOK(point p,
					vector<point> &v,
					double mid) {
	ll n = v.size();
	if(contains(v, p) == 0)return false;
	REP(i, n){
		auto seg = segment(v[i], v[(i+1)%n]);
		if(distanceLP(seg, p) < mid - EPS)return false;
	}
	return true;
}

bool check(double mid, vector<point> &v){
	ll n = v.size();
	vector<segment> segs;
	REP(i, n){
		auto a = v[i];
		auto b = v[(i+1)%n];
		auto vec = b - a;
		vec /= abs(vec);
		vec *= mid;
		vec = rotate(vec, PI/2);
		segs.EB(a + vec, b + vec);
	}

	REP(i, n){
		REP(j, i){
			auto p = crosspointSS(segs[i], segs[j]);
			if(isOK(p, v, mid)){
				return true;
			}
		}
	}

	return false;
}

void solve(ll n) {
	vector<point> v;
	REP(i, n){
		ll x, y;cin >> x >> y;
		v.EB(x, y);
	}

	double l = 0;
	double r = convex_diameter(v);
	REP(_, 100){
		if(abs(l - r) < EPS)break;
		double mid = (l + r) / 2;
		if(check(mid, v))l = mid;
		else r = mid;
	}

	cout << Decimal << l << endl;
	return;
}

int main(){
	cin.tie(0);cout.tie(0);ios::sync_with_stdio(false);

	while (true) {
		ll n;cin >> n;
		if(n == 0)break;
		solve(n);
	}

	return 0;
}