Problem: Dreamoon likes to play with sets, integers and <image>. <image> is defined as the largest positive integer that divides both a and b.

Let S be a set of exactly four distinct integers greater than 0. Define S to be of rank k if and only if for all pairs of distinct elements si, sj from S, <image>.

Given k and n, Dreamoon wants to make up n sets of rank k using integers from 1 to m such that no integer is used in two different sets (of course you can leave some integers without use). Calculate the minimum m that makes it possible and print one possible solution.

Input

The single line of the input contains two space separated integers n, k (1 ≤ n ≤ 10 000, 1 ≤ k ≤ 100).

Output

On the first line print a single integer — the minimal possible m. 

On each of the next n lines print four space separated integers representing the i-th set.

Neither the order of the sets nor the order of integers within a set is important. If there are multiple possible solutions with minimal m, print any one of them.

Examples

Input

1 1


Output

5
1 2 3 5


Input

2 2


Output

22
2 4 6 22
14 18 10 16

Note

For the first example it's easy to see that set {1, 2, 3, 4} isn't a valid set of rank 1 since <image>.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
const int maxn = 1e5 + 1000;
const int maxm = 1e4 + 10;
int main() {
  int ans[40000 + 100], cnt = 0, num = 0, pos = 1;
  while (1) {
    cnt++;
    num++;
    if (cnt != 4 && cnt != 6) ans[pos++] = num;
    if (cnt == 6) cnt = 0;
    if (pos >= 40010) break;
  }
  int n, k;
  cin >> n >> k;
  cout << ans[n * 4] * k << endl;
  for (unsigned int i = 1; i <= n * 4; i++) {
    printf("%d ", ans[i] * k);
    if (i % 4 == 0) printf("\n");
  }
  return 0;
}