Problem: A sequence of brackets is called balanced if one can turn it into a valid math expression by adding characters '+' and '1'. For example, sequences '(())()', '()', and '(()(()))' are balanced, while ')(', '(()', and '(()))(' are not.

You are given a binary string s of length n. Construct two balanced bracket sequences a and b of length n such that for all 1≤ i≤ n: 

  * if s_i=1, then a_i=b_i 
  * if s_i=0, then a_i≠ b_i 



If it is impossible, you should report about it.

Input

The first line contains a single integer t (1≤ t≤ 10^4) — the number of test cases.

The first line of each test case contains a single integer n (2≤ n≤ 2⋅ 10^5, n is even).

The next line contains a string s of length n, consisting of characters 0 and 1.

The sum of n across all test cases does not exceed 2⋅ 10^5.

Output

If such two balanced bracked sequences exist, output "YES" on the first line, otherwise output "NO". You can print each letter in any case (upper or lower).

If the answer is "YES", output the balanced bracket sequences a and b satisfying the conditions on the next two lines.

If there are multiple solutions, you may print any.

Example

Input


3
6
101101
10
1001101101
4
1100


Output


YES
()()()
((()))
YES
()()((()))
(())()()()
NO

Note

In the first test case, a="()()()" and b="((()))". The characters are equal in positions 1, 3, 4, and 6, which are the exact same positions where s_i=1.

In the second test case, a="()()((()))" and b="(())()()()". The characters are equal in positions 1, 4, 5, 7, 8, 10, which are the exact same positions where s_i=1.

In the third test case, there is no solution.

Solution (in JAVA):

Solution:

import java.util.*;
import java.io.*;
import java.math.BigInteger;
public class Main {
	//  Solution 
    public static void main(String [] args) throws IOException {
    	//Dir by MohammedElkady
    	int tt=in.nextInt();
    	while(tt-->0) {
    		StringBuilder sl=new StringBuilder(),sd=new StringBuilder();
    		int n=in.nextInt();
    		String s=in.s();
    		if(s.charAt(0)==s.charAt(n-1)&&s.charAt(0)=='1'&&n%2==0) {
    			int x=0,z=0;
    			for(int i=0;i<n-1;i++) {
    				if(x>0&&z>0&&s.charAt(i)=='1'&&!(x==z&&x==1&&s.charAt(i+1)=='0')) {
    					x--;z--;
    					sd.append(")");
    					sl.append(")");
    				}
    				else if(x>1&&z>1&&s.charAt(i)=='1') {
    					x--;z--;
    					sd.append(")");
    					sl.append(")");
    				}
    				else if(s.charAt(i)=='1') {
    					z++;x++;
    					sd.append("(");
    					sl.append("(");
    				}
    				else if(z>=x) {
    					x++;z--;
    					sd.append("(");
    					sl.append(")");
    				}
    				else{
    					z++;x--;
    					sd.append(")");
    					sl.append("(");
    				}
    					
    			}
    			if(z==1&&x==1) {
    				out.append("YES\n");
    				out.append(sd+")"+"\n");
    				out.append(sl+")"+"\n");
    			}
    			else 

    				out.append("NO"+"\n");
    		}
    		else{
    			out.append("NO\n");
    		}
    	}
    	out.close();
    }
    static long mod=1000000007L;
    static long gcd(long a,long b) {
    	if(a==0)
    		return b;
    	return gcd(b%a,a);
    }
    static long dp[][][];
    static long vor(int i, int u,int t) {
    	if(t>1)
    		return -1;
    	if(dp[i][u][t]!=0) 
    		return dp[i][u][t];
    	long a=vor(i-1,u-1,t),b=vor(i-1,u-1,t);
    	
    	return 0;
    }
    static Reader in=new Reader();
    public static PrintWriter out = new PrintWriter(new BufferedOutputStream(System.out));
    static class Reader 
    { 
        private InputStream mIs;private byte[] buf = new byte[1024];private int curChar,numChars;public Reader() { this(System.in); }public Reader(InputStream is) { mIs = is;} 
        public int read() {if (numChars == -1) throw new InputMismatchException();if (curChar >= numChars) {curChar = 0;try { numChars = mIs.read(buf);} catch (IOException e) { throw new InputMismatchException();}if (numChars <= 0) return -1; }return buf[curChar++];} 
        public String nextLine(){int c = read();while (isSpaceChar(c)) c = read();StringBuilder res = new StringBuilder();do {res.appendCodePoint(c);c = read();}while (!isEndOfLine(c));return res.toString() ;} 
        public String s(){int c = read();while (isSpaceChar(c)) c = read();StringBuilder res = new StringBuilder();do {res.appendCodePoint(c);c = read();}while (!isSpaceChar(c));return res.toString();} 
        public long l(){int c = read();while (isSpaceChar(c)) c = read();int sgn = 1;if (c == '-') { sgn = -1 ; c = read() ; }long res = 0; do{ if (c < '0' || c > '9') throw new InputMismatchException();res *= 10 ; res += c - '0' ; c = read();}while(!isSpaceChar(c));return res * sgn;} 
        public int nextInt(){int c = read() ;while (isSpaceChar(c)) c = read();int sgn = 1;if (c == '-') { sgn = -1 ; c = read() ; }int res = 0;do{if (c < '0' || c > '9') throw new InputMismatchException();res *= 10 ; res += c - '0' ; c = read() ;}while(!isSpaceChar(c));return res * sgn;} 
        public double d() throws IOException {return Double.parseDouble(s()) ;}
        public boolean isSpaceChar(int c) { return c == ' ' || c == '\n' || c == '\r' || c == '\t' || c == -1; } 
        public boolean isEndOfLine(int c) { return c == '\n' || c == '\r' || c == -1; } 
        public int[] arr(int n){int[] ret = new int[n];for (int i = 0; i < n; i++) {ret[i] = nextInt();}return ret;}
    }
}
class node implements Comparable<node> {
int val,pos;
node(int val,int pos){
	this.pos=pos;this.val=val;
}
@Override
public int compareTo(node o) {
	
	return val-o.val;
}
 
 
}
class xtree{
	public xtree(int n,int a[]) {
		this.a=a;
		seg=new int[n*4];
		//lazy=new int[n*4];
		build(1,0,n-1);
	}
	int seg[], a[],lazy[];
	    void check(int p,int s,int e) {
	        if(lazy[p]!=0) {
	            seg[p] += lazy[p];
	            if(s!=e) {
	                lazy[2*p] += lazy[p];
	                lazy[2*p+1] += lazy[p];
	            }
	            lazy[p] = 0;
	        }
	    }
	    
	     void build(int p,int s,int e) {
	        //check(p,s,e);
	        
	        if(s==e) {
	            seg[p] = a[s];
	            return;
	        }
	        
	        build(2*p,s,(s+e)/2);
	        build(2*p+1,(s+e)/2+1,e);
	        
	        seg[p] = seg[2*p]+ seg[2*p+1];
	    }
	    
	   void update(int p,int s,int e,int i,int v) {
	       // check(p,s,e);
	        
	        if(s==e) {
	            seg[p] = v;
	            return;
	        }
	        
	        if(i<=(s+e)/2) update(2*p,s,(s+e)/2,i,v);
	        else update(2*p+1,(s+e)/2+1,e,i,v);
	        
	        seg[p] = seg[2*p]+seg[2*p+1];
	    }
	    
	     void update(int p,int s,int e,int a,int b,int v) {
	        //check(p,s,e);
	        
	        if(s>=a && e<=b) {
	            seg[p] += v;
	            
	            if(s!=e) {
	                lazy[2*p] += v;
	                lazy[2*p+1] += v;
	            }
	            
	            return;
	        }
	        
	        if(s>b || e<a)
	            return;
	        
	        update(2*p,s,(s+e)/2,a,b,v);
	        update(2*p+1,(s+e)/2+1,e,a,b,v);
	        
	        seg[p] = seg[2*p]+seg[2*p+1];
	    }
    
 
    
    int get(int p,int s,int e,int a,int b) {
        if(s>=a && e<=b)
            return seg[p];
        
        if(s>b || e<a)
            return 0; 
        
        return get(2*p,s,(s+e)/2,a,b)+ get(2*p+1,(s+e)/2+1,e,a,b);
    }
}
 
class FastReader
    {
        BufferedReader br;
        StringTokenizer st;
 
        public FastReader()
        {
            br = new BufferedReader(new
                     InputStreamReader(System.in));
        }
 
        String next()
        {
            while (st == null || !st.hasMoreElements())
            {
                try
                {
                    st = new StringTokenizer(br.readLine());
                }
                catch (IOException  e)
                {
                    e.printStackTrace();
                }
            }
            return st.nextToken();
        }
 
        int nextInt()
        {
            return Integer.parseInt(next());
        }
 
        long nextLong()
        {
            return Long.parseLong(next());
        }
 
        double nextDouble()
        {
            return Double.parseDouble(next());
        }
 
        String nextLine()
        {
            String str = "";
            try
            {
                str = br.readLine();
            }
            catch (IOException e)
            {
                e.printStackTrace();
            }
            return str;
        }
}
 
class Sorting{
 
 public static int[] bucketSort(int[] array, int bucketCount) {
 
 if (bucketCount <= 0) throw new IllegalArgumentException("Invalid bucket count");
 
 if (array.length <= 1) return array; //trivially sorted
 
 
 
 long high = array[0];
 
 long low = array[0];
 
 for (int i = 1; i < array.length; i++) { //find the range of input elements
 
 if (array[i] > high) high = array[i];
 
 if (array[i] < low) low = array[i];
 
 }
 
 double interval = ((double)(high - low + 1))/bucketCount; //range of one bucket
 
 
 ArrayList<Integer> buckets[] = new ArrayList[bucketCount];
 
 for (int i = 0; i < bucketCount; i++) { //initialize buckets
 
 buckets[i] = new ArrayList();
 
 }
 
 
 
 for (int i = 0; i < array.length; i++) { //partition the input array
 
 buckets[(int)((array[i] - low)/interval)].add(array[i]);
 
 }
 
 
 int pointer = 0;
 
 for (int i = 0; i < buckets.length; i++) {
 
 Collections.sort(buckets[i]); //mergeSort
 
 for (int j = 0; j < buckets[i].size(); j++) { //merge the buckets
 
 array[pointer] = buckets[i].get(j);
 
 pointer++;
 
 }
 
}
 
return array;
 
}
}
 class LongestCommonSubsequence 
{ 
  
  /* Returns length of LCS for X[0..m-1], Y[0..n-1] */
	 int lcs( char[] X, char[] Y, int m, int n ,int K) 
	  { 
		 int L[][] = new int[m+1][n+1]; 
		 int ans[][]=new int[m+1][n+1];
		 int min[][] = new int[m+1][n+1]; 
		 for(int i=0;i<=n;i++) 
			 for(int j=0;j<=m;j++) 
				 min[j][i]='z'+1;
	    /* Following steps build L[m+1][n+1] in bottom up fashion. Note 
	         that L[i][j] contains length of LCS of X[0..i-1] and Y[0..j-1] */
	    for (int i=0; i<=m; i++) 
	    { 
	      for (int j=0; j<=n; j++)
	      { 
	        if (i == 0 || j == 0) 
	            L[i][j] = 0; 
	        else if (X[i-1] == Y[j-1]) { 
	            L[i][j] = L[i-1][j-1] + 1; 
	            ans[i][j]=ans[i-1][j-1]+X[i-1];
	         
	        }
	        else {
	            L[i][j] = max(L[i-1][j], L[i][j-1]); }
	      } 
	    } 
	  return L[m][n]; 
	  } 
	  
	  /* Utility function to get max of 2 integers */
	  int max(int a, int b) 
	  { 
	    return (a > b)? a : b; 
	  } 
 
     // Returns length of LCS for X[0..m-1], Y[0..n-1] 
     static String lcs(String X, String Y, int m, int n) 
     { 
         int[][] L = new int[m+1][n+1]; 
    
         // Following steps build L[m+1][n+1] in bottom up fashion. Note 
         // that L[i][j] contains length of LCS of X[0..i-1] and Y[0..j-1]  
         for (int i=0; i<=m; i++) 
         { 
             for (int j=0; j<=n; j++) 
             { 
                 if (i == 0 || j == 0) 
                     L[i][j] = 0; 
                 else if (X.charAt(i-1) == Y.charAt(j-1)) 
                     L[i][j] = L[i-1][j-1] + 1; 
                 else
                     L[i][j] = Math.max(L[i-1][j], L[i][j-1]); 
             } 
         } 
    
         // Following code is used to print LCS 
         int index = L[m][n]; 
         int temp = index; 
    
         // Create a character array to store the lcs string 
         char[] lcs = new char[index+1]; 
         lcs[index] = '\u0000'; // Set the terminating character 
    
         // Start from the right-most-bottom-most corner and 
         // one by one store characters in lcs[] 
         int i = m; 
         int j = n; 
         while (i > 0 && j > 0) 
         { 
             // If current character in X[] and Y are same, then 
             // current character is part of LCS 
             if (X.charAt(i-1) == Y.charAt(j-1)) 
             { 
                 // Put current character in result 
                 lcs[index-1] = X.charAt(i-1);  
                   
                 // reduce values of i, j and index 
                 i--;  
                 j--;  
                 index--;      
             } 
    
             // If not same, then find the larger of two and 
             // go in the direction of larger value 
             else if (L[i-1][j] > L[i][j-1]) 
                 i--; 
             else
                 j--; 
         } 
    
         // Print the lcs 
         StringBuilder Sd=new StringBuilder();
         for(int k=0;k<=temp;k++) 
             Sd.append(lcs[k]); 
      return Sd.toString();   
     }
 }