Problem: Olesya loves numbers consisting of n digits, and Rodion only likes numbers that are divisible by t. Find some number that satisfies both of them.

Your task is: given the n and t print an integer strictly larger than zero consisting of n digits that is divisible by t. If such number doesn't exist, print  - 1.

Input

The single line contains two numbers, n and t (1 ≤ n ≤ 100, 2 ≤ t ≤ 10) — the length of the number and the number it should be divisible by.

Output

Print one such positive number without leading zeroes, — the answer to the problem, or  - 1, if such number doesn't exist. If there are multiple possible answers, you are allowed to print any of them.

Examples

Input

3 2


Output

712

Solution (in JAVA):

Solution:
import java.util.*;
import java.io.*;

public class OlesyaRodion {
    public static void main(String[] args) throws Exception {
        Scanner in = new Scanner(new BufferedReader(new InputStreamReader(System.in)));
        int n = in.nextInt();
        int t = in.nextInt();
        in.close();
        if (n == 1 && t == 10) {
            int minusOne = -1;
            System.out.println(minusOne);
        } else {
            System.out.print(t);
            if (t == 10) {
                for (int i = 0; i < n - 2; i++) {
                    
                    if (i == n - 3) {
                        System.out.println(0);
                    } else {
                        System.out.print(0);
                    }
                }   
                
            } else {
                for (int i = 0; i < n - 1; i++) {
                    if (i == n - 2) {
                        System.out.println(0);
                    } else {
                        System.out.print(0);
                    }
                }
            }
        }  
    }
}