Problem: There are n piles of pebbles on the table, the i-th pile contains ai pebbles. Your task is to paint each pebble using one of the k given colors so that for each color c and any two piles i and j the difference between the number of pebbles of color c in pile i and number of pebbles of color c in pile j is at most one.

In other words, let's say that bi, c is the number of pebbles of color c in the i-th pile. Then for any 1 ≤ c ≤ k, 1 ≤ i, j ≤ n the following condition must be satisfied |bi, c - bj, c| ≤ 1. It isn't necessary to use all k colors: if color c hasn't been used in pile i, then bi, c is considered to be zero.

Input

The first line of the input contains positive integers n and k (1 ≤ n, k ≤ 100), separated by a space — the number of piles and the number of colors respectively.

The second line contains n positive integers a1, a2, ..., an (1 ≤ ai ≤ 100) denoting number of pebbles in each of the piles.

Output

If there is no way to paint the pebbles satisfying the given condition, output "NO" (without quotes) .

Otherwise in the first line output "YES" (without quotes). Then n lines should follow, the i-th of them should contain ai space-separated integers. j-th (1 ≤ j ≤ ai) of these integers should be equal to the color of the j-th pebble in the i-th pile. If there are several possible answers, you may output any of them.

Examples

Input

4 4
1 2 3 4


Output

YES
1
1 4
1 2 4
1 2 3 4


Input

5 2
3 2 4 1 3


Output

NO


Input

5 4
3 2 4 3 5


Output

YES
1 2 3
1 3
1 2 3 4
1 3 4
1 1 2 3 4

Solution (in PYTHON):

Solution:
n,k=map(int,raw_input().split())
ar=map(int,raw_input().split())
l=[]
for i in xrange(n):
    l.append([])
c1=0
flg=True
while(ar!=[0]*n):
    if flg:
        mi=10**9
        for i in xrange(n):
            if ar[i]!=0:
                mi=min(ar[i],mi)
        c1+=1
        for i in xrange(n):
            if mi+1<=ar[i] and ar[i]!=0:
                ar[i]-=(mi+1)
                l[i]+=([c1]*(mi+1))
            elif ar[i]!=0:
                ar[i]-=(mi)
                l[i]+=([c1]*(mi))
        flg=False
        continue
    mi=10**9
    for i in xrange(n):
        if ar[i]!=0:
            mi=min(ar[i],mi)
    c1+=1
    for i in xrange(n):
        if mi+1<=ar[i] and ar[i]!=0:
            ar[i]-=(1)
            l[i]+=([c1])
        elif ar[i]!=0:
            ar[i]-=(1)
            l[i]+=([c1])
    #print l,ar
if c1>k:
    print "NO"
else:
    print "YES"
    for i in xrange(n):
        for j in l[i]:
            print j,
        print ""