Problem: You are given a non-negative integer n, its decimal representation consists of at most 100 digits and doesn't contain leading zeroes.

Your task is to determine if it is possible in this case to remove some of the digits (possibly not remove any digit at all) so that the result contains at least one digit, forms a non-negative integer, doesn't have leading zeroes and is divisible by 8. After the removing, it is forbidden to rearrange the digits.

If a solution exists, you should print it.

Input

The single line of the input contains a non-negative integer n. The representation of number n doesn't contain any leading zeroes and its length doesn't exceed 100 digits. 

Output

Print "NO" (without quotes), if there is no such way to remove some digits from number n. 

Otherwise, print "YES" in the first line and the resulting number after removing digits from number n in the second line. The printed number must be divisible by 8.

If there are multiple possible answers, you may print any of them.

Examples

Input

3454


Output

YES
344


Input

10


Output

YES
0


Input

111111


Output

NO

Solution (in JAVA):

Solution:

import java.io.BufferedOutputStream;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.util.StringTokenizer;


public class Div550C {

	public static void main(String[] args) {
	      MyScanner sc = new MyScanner();
	      out = new PrintWriter(new BufferedOutputStream(System.out));

	      /*
	       * All possible inputs
	      int n      = sc.nextInt();        // read input as integer
	      long k     = sc.nextLong();       // read input as long
	      double d   = sc.nextDouble();     // read input as double
	      String str = sc.next();           // read input as String
	      String s   = sc.nextLine();       // read whole line as String
		  */
	      String inputStr = sc.nextLine();
	      //String inputStr = input + "";
	   // Use property of div by 8 means last 3 digits div by 8
	      // need only 3 digits then!
	      //So with 3 loops, we can check all possible combos of 1, 2, and 3 digit numbers in the given number
	      String ret = "NO";
	      int retNum = -1;
	      String iStr = "";
	      String jStr = "";
	      //String kStr = "";
	      //Checks 100s (hundreds)place
	      //Loop up to string length since we'll make i and j start negative a special case
	      // (so that we can check 1 and 2 digit numbers)
	      outerloop:
	      for(int i = -2; i < inputStr.length(); i++)
	      {
	    	  if(i < 0)
	    		  iStr = "";
	    	  else
	    		  iStr = inputStr.charAt(i) +"";
	    	  //Checks 10s (tens) place
	    	  for(int j = i+1; j < inputStr.length(); j++)
		      {
	    		  if(j < 0)
		    		  jStr = "";
		    	  else
		    		  jStr = inputStr.charAt(j) +"";
	    		  //Checks 1s place
	    		  for(int k =  j+1; k < inputStr.length(); k++)
	    	      {
	    	    	if(Integer.parseInt(iStr + jStr + inputStr.charAt(k)) % 8 == 0)
	    	    	{
	    	    		retNum = Integer.parseInt(iStr + jStr + inputStr.charAt(k));
	    	    		ret = "YES";
	    	    		break outerloop;
	    	    	}
	    	    	
	    	      }
	    		 
		      } 
	      }
	      out.println(ret);
	      if(retNum != -1)
	    	  out.println(retNum);
	     
	      out.close();
	   }

	     

	   public static PrintWriter out;
	      
	   public static class MyScanner {
	      BufferedReader br;
	      StringTokenizer st;
	 
	      public MyScanner() {
	         br = new BufferedReader(new InputStreamReader(System.in));
	      }
	 
	      String next() {
	          while (st == null || !st.hasMoreElements()) {
	              try {
	                  st = new StringTokenizer(br.readLine());
	              } catch (IOException e) {
	                  e.printStackTrace();
	              }
	          }
	          return st.nextToken();
	      }
	 
	      int nextInt() {
	          return Integer.parseInt(next());
	      }
	 
	      long nextLong() {
	          return Long.parseLong(next());
	      }
	 
	      double nextDouble() {
	          return Double.parseDouble(next());
	      }
	 
	      String nextLine(){
	          String str = "";
		  try {
		     str = br.readLine();
		  } catch (IOException e) {
		     e.printStackTrace();
		  }
		  return str;
	      }

	   }
}