Problem: You are given a directed graph with n vertices and m directed edges without self-loops or multiple edges.

Let's denote the k-coloring of a digraph as following: you color each edge in one of k colors. The k-coloring is good if and only if there no cycle formed by edges of same color.

Find a good k-coloring of given digraph with minimum possible k.

Input

The first line contains two integers n and m (2 ≤ n ≤ 5000, 1 ≤ m ≤ 5000) — the number of vertices and edges in the digraph, respectively.

Next m lines contain description of edges — one per line. Each edge is a pair of integers u and v (1 ≤ u, v ≤ n, u ≠ v) — there is directed edge from u to v in the graph.

It is guaranteed that each ordered pair (u, v) appears in the list of edges at most once.

Output

In the first line print single integer k — the number of used colors in a good k-coloring of given graph.

In the second line print m integers c_1, c_2, ..., c_m (1 ≤ c_i ≤ k), where c_i is a color of the i-th edge (in order as they are given in the input).

If there are multiple answers print any of them (you still have to minimize k).

Examples

Input


4 5
1 2
1 3
3 4
2 4
1 4


Output


1
1 1 1 1 1 


Input


3 3
1 2
2 3
3 1


Output


2
1 1 2 

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
vector<int> d[10000];
int mark[10000];
int c = 0;
void dfs(int x) {
  if (mark[x] == 2) return;
  if (mark[x] == 1) {
    c = 1;
    return;
  }
  mark[x] = 1;
  for (int i = 0; i < d[x].size(); i++) {
    dfs(d[x][i]);
  }
  mark[x] = 2;
}
int32_t main() {
  ios_base::sync_with_stdio(false);
  cout << setprecision(10);
  int n, m;
  cin >> n >> m;
  int a[m];
  int b[m];
  for (int i = 0; i < m; i++) {
    cin >> a[i] >> b[i];
    a[i]--;
    b[i]--;
    d[a[i]].push_back(b[i]);
  }
  for (int i = 0; i < n; i++) {
    if (mark[i] == 0) dfs(i);
  }
  if (c == 0) {
    cout << 1 << endl;
    for (int i = 0; i < m; i++) cout << 1 << " ";
  } else {
    cout << 2 << endl;
    for (int i = 0; i < m; i++) {
      if (a[i] < b[i])
        cout << 1 << " ";
      else
        cout << 2 << " ";
    }
  }
}