Problem: Write a program which manipulates a sequence A = {a1, a2, . . . , an} with the following operations:

* add(s, t, x): add x to as, as+1, ..., at.
* get(i): output the value of ai.



Note that the initial values of ai (i = 1, 2, . . . , n) are 0.

Constraints

* 1 ≤ n ≤ 100000
* 1 ≤ q ≤ 100000
* 1 ≤ s ≤ t ≤ n
* 1 ≤ i ≤ n
* 0 ≤ x ≤ 1000

Input


n q
query1
query2
:
queryq


In the first line, n (the number of elements in A) and q (the number of queries) are given. Then, ith query queryi is given in the following format:


0 s t x


or


1 t


The first digit represents the type of the query. '0' denotes add(s, t, x) and '1' denotes get(i).

Output

For each get operation, print the value.

Examples

Input

3 5
0 1 2 1
0 2 3 2
0 3 3 3
1 2
1 3


Output

3
5


Input

4 3
1 2
0 1 4 1
1 2


Output

0
1

Solution (in CPP):

Solution:
#include <iostream>
#include <vector>

using namespace std;

template<typename T>
class RangeAddQuery {
public:
    explicit RangeAddQuery(int n) : N(calcN_(n)) {
        mVal.assign(2*N+1, 0);
    }
    void update(int l, int r, T value){
        updateImpl_(l, r, value, 0, 0, N);
    }
    T get(int idx){
        int i = N + idx - 1;
        auto res = mVal[i];
        while(i > 0){
            i = (i-1)/2;
            res += mVal[i];
        }
        return res;
    }
private:
    int calcN_(int n){
        int res = 1;
        while(res < n) res *= 2;
        return res;
    }
    void updateImpl_(int l, int r, T value, int idx, int rangeL, int rangeR){
        if(r <= rangeL || rangeR <= l) return;
        if(l <= rangeL && rangeR <= r){
            mVal[idx] += value;
        } else {
            int rangeM = (rangeL+rangeR)/2;
            updateImpl_(l, r, value, 2*idx+1, rangeL, rangeM);
            updateImpl_(l, r, value, 2*idx+2, rangeM, rangeR);
        }
    }
    const int N;
    vector<T> mVal; 
};

int main(){
    int n, q;
    while(cin >> n >> q){
        RangeAddQuery<int> raq(n);
        for(int i=0;i<q;i++){
            int c; cin >> c;
            if(c == 0){
                int s, t, x; cin >> s >> t >> x;
                raq.update(s-1, t, x);
            } else {
                int p; cin >> p;
                cout << raq.get(p-1) << endl;
            }
        }
    }
}