Problem: Olesya loves numbers consisting of n digits, and Rodion only likes numbers that are divisible by t. Find some number that satisfies both of them.

Your task is: given the n and t print an integer strictly larger than zero consisting of n digits that is divisible by t. If such number doesn't exist, print  - 1.

Input

The single line contains two numbers, n and t (1 ≤ n ≤ 100, 2 ≤ t ≤ 10) — the length of the number and the number it should be divisible by.

Output

Print one such positive number without leading zeroes, — the answer to the problem, or  - 1, if such number doesn't exist. If there are multiple possible answers, you are allowed to print any of them.

Examples

Input

3 2


Output

712

Solution (in JAVA):

Solution:
import java.io.IOException;
import java.math.BigInteger;
import java.util.Scanner;

public class CF584A {
    public static void main(String[] args) throws IOException {
        Scanner scanner = new Scanner(System.in);
        int n = scanner.nextInt();
        int t = scanner.nextInt();
        String number = "1";
        for (int i = 0; i < n - 1; i++) {
            number += "0";
        }
        BigInteger bigNumber = new BigInteger(number);
        bigNumber = bigNumber.divide(BigInteger.valueOf(t)).add(BigInteger.valueOf(1)).multiply(BigInteger.valueOf(t));
        if (bigNumber.toString().length() != n) {
            System.out.println(-1);
        }
        else {
            System.out.println(bigNumber);
        }
    }
}