Problem: Olesya loves numbers consisting of n digits, and Rodion only likes numbers that are divisible by t. Find some number that satisfies both of them.

Your task is: given the n and t print an integer strictly larger than zero consisting of n digits that is divisible by t. If such number doesn't exist, print  - 1.

Input

The single line contains two numbers, n and t (1 ≤ n ≤ 100, 2 ≤ t ≤ 10) — the length of the number and the number it should be divisible by.

Output

Print one such positive number without leading zeroes, — the answer to the problem, or  - 1, if such number doesn't exist. If there are multiple possible answers, you are allowed to print any of them.

Examples

Input

3 2


Output

712

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
void solve() {
  long long digits;
  string n;
  cin >> digits >> n;
  if (digits - n.size() < 0) {
    cout << -1;
  } else {
    cout << n;
    for (long long i = 1; i <= digits - n.size(); ++i) {
      cout << 0;
    }
  }
}
int32_t main() {
  ios::sync_with_stdio(false);
  cin.tie(0);
  solve();
}