Problem: There are n piles of pebbles on the table, the i-th pile contains ai pebbles. Your task is to paint each pebble using one of the k given colors so that for each color c and any two piles i and j the difference between the number of pebbles of color c in pile i and number of pebbles of color c in pile j is at most one.

In other words, let's say that bi, c is the number of pebbles of color c in the i-th pile. Then for any 1 ≤ c ≤ k, 1 ≤ i, j ≤ n the following condition must be satisfied |bi, c - bj, c| ≤ 1. It isn't necessary to use all k colors: if color c hasn't been used in pile i, then bi, c is considered to be zero.

Input

The first line of the input contains positive integers n and k (1 ≤ n, k ≤ 100), separated by a space — the number of piles and the number of colors respectively.

The second line contains n positive integers a1, a2, ..., an (1 ≤ ai ≤ 100) denoting number of pebbles in each of the piles.

Output

If there is no way to paint the pebbles satisfying the given condition, output "NO" (without quotes) .

Otherwise in the first line output "YES" (without quotes). Then n lines should follow, the i-th of them should contain ai space-separated integers. j-th (1 ≤ j ≤ ai) of these integers should be equal to the color of the j-th pebble in the i-th pile. If there are several possible answers, you may output any of them.

Examples

Input

4 4
1 2 3 4


Output

YES
1
1 4
1 2 4
1 2 3 4


Input

5 2
3 2 4 1 3


Output

NO


Input

5 4
3 2 4 3 5


Output

YES
1 2 3
1 3
1 2 3 4
1 3 4
1 1 2 3 4

Solution (in PYTHON3):

Solution:
n, k = map(int, input().split())
heaps = list(map(int, input().split()))
mas = [[] for i in range(n)]
color = 0
flag = 0
r = 0
while True:
    count = 0
    color += 1
    if color > k:
        color = 1    
    for i in range(n):
        if len(mas[i]) < heaps[i]:
            mas[i].append(color)
        else:
            count += 1
        if count == n:
            flag = 1
            break
    if flag == 1:
        break
flag = 0
for i in range(k):
    pr = []
    for j in range(n):
        ans = 0
        for g in mas[j]:
            if g == i + 1:
                ans += 1
        pr.append(ans)
    pr.sort()
    if pr[-1] - pr[0] > 1:
        flag = 1
        break
if flag == 0:
    print('YES')
    for i in mas:
        print(*i)
else:
    print('NO')