Problem: There are n piles of pebbles on the table, the i-th pile contains ai pebbles. Your task is to paint each pebble using one of the k given colors so that for each color c and any two piles i and j the difference between the number of pebbles of color c in pile i and number of pebbles of color c in pile j is at most one.

In other words, let's say that bi, c is the number of pebbles of color c in the i-th pile. Then for any 1 ≤ c ≤ k, 1 ≤ i, j ≤ n the following condition must be satisfied |bi, c - bj, c| ≤ 1. It isn't necessary to use all k colors: if color c hasn't been used in pile i, then bi, c is considered to be zero.

Input

The first line of the input contains positive integers n and k (1 ≤ n, k ≤ 100), separated by a space — the number of piles and the number of colors respectively.

The second line contains n positive integers a1, a2, ..., an (1 ≤ ai ≤ 100) denoting number of pebbles in each of the piles.

Output

If there is no way to paint the pebbles satisfying the given condition, output "NO" (without quotes) .

Otherwise in the first line output "YES" (without quotes). Then n lines should follow, the i-th of them should contain ai space-separated integers. j-th (1 ≤ j ≤ ai) of these integers should be equal to the color of the j-th pebble in the i-th pile. If there are several possible answers, you may output any of them.

Examples

Input

4 4
1 2 3 4


Output

YES
1
1 4
1 2 4
1 2 3 4


Input

5 2
3 2 4 1 3


Output

NO


Input

5 4
3 2 4 3 5


Output

YES
1 2 3
1 3
1 2 3 4
1 3 4
1 1 2 3 4

Solution (in JAVA):

Solution:
import java.util.*;
import java.io.*;
import java.lang.*;
import java.math.*;

import static java.lang.Math.*;

public class Solution implements Runnable {
	
	void solve() throws Exception {
		int n = sc.nextInt();
		int k = sc.nextInt();
		int a[] = new int[n];
		int mn = 101;
		int mx = 0;
		for (int i = 0; i < n; i++) {
			a[i] = sc.nextInt();
			mn = min(mn, a[i]);
			mx = max(mx, a[i]);
		}
		if (mx - mn > k) {
			out.println("NO");
			return;
		}
		out.println("YES");
		for (int i = 0; i < n; i++) {
			for (int j = 0; j < mn; j++) {
				out.print("1 ");
			}
			for (int j = mn; j < a[i]; j++) {
				out.print((j - mn + 1) + " ");
			}
			out.println();
		}		
	}
	
	BufferedReader in;
	PrintWriter out;
	FastScanner sc;
	
	static Throwable throwable;
	
	public static void main(String[] args) throws Throwable {
		Thread thread = new Thread(null, new Solution(), "", (1 << 26));
		thread.start();
		thread.join();
		thread.run();
		if (throwable != null)
			throw throwable;
	}
	
	
	public void run() {
		try {
			//in = new BufferedReader(new FileReader(".in"));
			//out = new PrintWriter(new FileWriter(".out"));
			in = new BufferedReader(new InputStreamReader(System.in));
			out = new PrintWriter(System.out);
			sc = new FastScanner(in);
			solve();
		} catch (Exception e) {
			throwable = e;
		} finally {
			out.close();
		}
	}
}

class FastScanner {
	BufferedReader reader;
	StringTokenizer strTok;
	
	FastScanner(BufferedReader reader) {
		this.reader = reader;
	}
	
	public String nextToken() throws Exception {
		while (strTok == null || !strTok.hasMoreTokens())
			strTok = new StringTokenizer(reader.readLine());
		return strTok.nextToken();
	}
	
	public int nextInt() throws Exception {
		return Integer.parseInt(nextToken());
	}
	
	public long nextLong() throws Exception {
		return Long.parseLong(nextToken());
	}
	
	public double nextDouble() throws Exception {
		return Double.parseDouble(nextToken());
	}
}