Problem: Carl is a beginner magician. He has a blue, b violet and c orange magic spheres. In one move he can transform two spheres of the same color into one sphere of any other color. To make a spell that has never been seen before, he needs at least x blue, y violet and z orange spheres. Can he get them (possible, in multiple actions)?

Input

The first line of the input contains three integers a, b and c (0 ≤ a, b, c ≤ 1 000 000) — the number of blue, violet and orange spheres that are in the magician's disposal.

The second line of the input contains three integers, x, y and z (0 ≤ x, y, z ≤ 1 000 000) — the number of blue, violet and orange spheres that he needs to get.

Output

If the wizard is able to obtain the required numbers of spheres, print "Yes". Otherwise, print "No".

Examples

Input

4 4 0
2 1 2


Output

Yes


Input

5 6 1
2 7 2


Output

No


Input

3 3 3
2 2 2


Output

Yes

Note

In the first sample the wizard has 4 blue and 4 violet spheres. In his first action he can turn two blue spheres into one violet one. After that he will have 2 blue and 5 violet spheres. Then he turns 4 violet spheres into 2 orange spheres and he ends up with 2 blue, 1 violet and 2 orange spheres, which is exactly what he needs.

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.StringTokenizer;


public class ProblemA {
    public static void main(String[] args) {
        int testMode = 0;
        String testInput = "1000000 500000 500000\n" +
                "0 750000 750000\n";
        /*-------------------------------------------------------------------------------------------------------*/
        FastReader in = new FastReader(testMode == 0 ? System.in : new ByteArrayInputStream(testInput.getBytes()));
        PrintWriter out = new PrintWriter(System.out);
        new ProblemSolver().solve(in, out);
        out.close();
    }
}

class ProblemSolver {

    void solve(FastReader in, PrintWriter out) {
        int[] a = {in.nextInt(), in.nextInt(), in.nextInt()};
        int[] b = {in.nextInt(), in.nextInt(), in.nextInt()};
        for (int i = 0; i < 3; i++) {
            int m = Math.min(a[i], b[i]);
            a[i] -= m;
            b[i] -= m;
        }
        for (int i = 0; i < 3; i++) {
            for (int j = 0; j < 3; j++) {
                if (i == j) continue;
                int d = Math.min(a[i] / 2, b[j]);
                a[i] -= 2 * d;
                b[j] -= d;
            }
        }
        boolean ans = true;
        for (int i = 0; i < 3; i++)
            ans &= (b[i] == 0);
        out.println(ans ? "Yes" : "No");
    }
}

class Pair implements Comparable<Pair> {
    public int a;
    public int b;

    public Pair(int a, int b) {
        this.a = a;
        this.b = b;
    }

    public int compareTo(Pair o) {
        if (this.a < o.a) return -1;
        if (this.a > o.a) return 1;
        if (this.b == o.b) return 0;
        return (int) ((this.b - o.b) / Math.abs(this.b - o.b));
    }
}


class FastReader extends BufferedReader {
    private StringTokenizer st;

    public FastReader(InputStream is) {
        super(new InputStreamReader(is));
    }

    public String nextToken() {
        try {
            while (st == null || !st.hasMoreElements()) {
                st = new StringTokenizer(readLine());
            }
            return st.nextToken();
        } catch (IOException e) {
            return null;
        }
    }

    public int nextInt() {
        return Integer.parseInt(nextToken());
    }

    public long nextLong() {
        return Long.parseLong(nextToken());
    }

    public int[] nextArrayInt(int size) {
        int[] ret = new int[size];
        for (int i = 0; i < size; i++) {
            ret[i] = nextInt();
        }
        return ret;
    }
}