Problem: Today Oz is playing with his game-board. He has N coins of type-1 and M coins of type-2. Also the game-board has N squares of type-1 and M squares of type-2. In this game Oz must place one coin into each square. After placing all coins Oz will get a score based on his coin placement strategy . 

His score calculation is like this : If type-1 square contains a type-1 coin then he will get A points, if type-2 square contains a type-2 coin then he will get B points and in all other cases, he will get C points.
Oz's total game score will be sum of scores of all squares. Help Oz to earn maximum game points with his game-board.

Input :

The first line contains the number of test cases T . 

Each test case consists of five space separated integers - N, M, A, B and C. 

Output :

For each test case output maximum game points that Oz can earn.

Constraints :

1 ≤  T ≤ 100

1 ≤ N, M ≤ 10^9

-10^4  ≤ A, B, C ≤ 10^4

SAMPLE INPUT
2
3 4 500 800 600
1 5 10 -20 -30

SAMPLE OUTPUT
4700
-90

Explanation

For first sample :

With optimal strategy Oz will place 3 coins of type-1 into 3 squares of type-1 getting score =500+500+500 = 1500
and he will place 4 coins of type-2 into 4 squares of type-2 getting score = 800+800+800+800 = 3200
so total score will be 1500+3200 =4700
He cannot get better then this in any other coin placement strategy.

Solution (in PYTHON):

Solution:
test_case = input()
for test in range(test_case):
    line = raw_input()
    value_list = line.split()
    N = int(value_list[0])
    M = int(value_list[1])
    A = int(value_list[2])
    B = int(value_list[3])
    C = int(value_list[4])

    sum_placed = N*A + M*B
    if N > M:
        sum_displaced = 2*M*C+ (N-M)*A
    elif M>N:
        sum_displaced = 2*N*C+ (M-N)*B
    else:
        sum_displaced = 2*M*C

    if sum_placed>sum_displaced:
        print str(sum_placed)
    else:
        print str(sum_displaced)