Problem: A colored stripe is represented by a horizontal row of n square cells, each cell is pained one of k colors. Your task is to repaint the minimum number of cells so that no two neighbouring cells are of the same color. You can use any color from 1 to k to repaint the cells.

Input

The first input line contains two integers n and k (1 ≤ n ≤ 5·105; 2 ≤ k ≤ 26). The second line contains n uppercase English letters. Letter "A" stands for the first color, letter "B" stands for the second color and so on. The first k English letters may be used. Each letter represents the color of the corresponding cell of the stripe.

Output

Print a single integer — the required minimum number of repaintings. In the second line print any possible variant of the repainted stripe.

Examples

Input

6 3
ABBACC


Output

2
ABCACA


Input

3 2
BBB


Output

1
BAB

Solution (in PYTHON3):

Solution:
import os
import sys
from io import BytesIO, IOBase

BUFSIZE = 8192


class FastIO(IOBase):
    newlines = 0

    def __init__(self, file):
        self._fd = file.fileno()
        self.buffer = BytesIO()
        self.writable = "x" in file.mode or "r" not in file.mode
        self.write = self.buffer.write if self.writable else None

    def read(self):
        while True:
            b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
            if not b:
                break
            ptr = self.buffer.tell()
            self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
        self.newlines = 0
        return self.buffer.read()

    def readline(self):
        while self.newlines == 0:
            b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
            self.newlines = b.count(b"\n") + (not b)
            ptr = self.buffer.tell()
            self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
        self.newlines -= 1
        return self.buffer.readline()

    def flush(self):
        if self.writable:
            os.write(self._fd, self.buffer.getvalue())
            self.buffer.truncate(0), self.buffer.seek(0)


class IOWrapper(IOBase):
    def __init__(self, file):
        self.buffer = FastIO(file)
        self.flush = self.buffer.flush
        self.writable = self.buffer.writable
        self.write = lambda s: self.buffer.write(s.encode("ascii"))
        self.read = lambda: self.buffer.read().decode("ascii")
        self.readline = lambda: self.buffer.readline().decode("ascii")


sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
##########################################################
from collections import Counter
# c=sorted((i,int(val))for i,val in enumerate(input().split()))
import heapq
# c=sorted((i,int(val))for i,val in enumerate(input().split()))
# n = int(input())
# ls = list(map(int, input().split()))
# n, k = map(int, input().split())
# n =int(input())
#arr=[(i,x) for i,x in enum]
#arr.sort(key=lambda x:x[0])
#print(arr)
# e=list(map(int, input().split()))
from collections import Counter
#print("\n".join(ls))
#print(os.path.commonprefix(ls[0:2]))
#n=int(input())
from bisect import  bisect_right
#for _ in range(int(input())):
#n=int(input())
#arr = list(map(int, input().split()))
#for _ in range(int(input())):
n, k = map(int, input().split())
s=list(input())
ans=0
if k>2:
    for i,x in enumerate(s):
        if i==0:
            continue
        if s[i]==s[i-1]:
            for j in range(k):
                if chr(j+65)==s[i]:
                    continue
                if i+1<n and s[i+1]==chr(65+j):
                    continue
                s[i]=chr(65+j)
                ans+=1
                break


    print(ans)
    print("".join(s))
else:
    ans1=0
    ans2=0
    s1="AB"*((n+1)//2)
    s2="BA"*((n+1)//2)
    for ind,i in enumerate(s):
        if i!=s1[ind]:

            ans1+=1
    for ind, i in enumerate(s):
        if i != s2[ind]:
            ans2 += 1
    if ans1<=ans2:
        print(ans1)
        c="".join(s1)
        print(c[:n])
    else:
        print(ans2)
        c="".join(s2)
        print(c[:n])