Problem: There are n piles of pebbles on the table, the i-th pile contains ai pebbles. Your task is to paint each pebble using one of the k given colors so that for each color c and any two piles i and j the difference between the number of pebbles of color c in pile i and number of pebbles of color c in pile j is at most one.

In other words, let's say that bi, c is the number of pebbles of color c in the i-th pile. Then for any 1 ≤ c ≤ k, 1 ≤ i, j ≤ n the following condition must be satisfied |bi, c - bj, c| ≤ 1. It isn't necessary to use all k colors: if color c hasn't been used in pile i, then bi, c is considered to be zero.

Input

The first line of the input contains positive integers n and k (1 ≤ n, k ≤ 100), separated by a space — the number of piles and the number of colors respectively.

The second line contains n positive integers a1, a2, ..., an (1 ≤ ai ≤ 100) denoting number of pebbles in each of the piles.

Output

If there is no way to paint the pebbles satisfying the given condition, output "NO" (without quotes) .

Otherwise in the first line output "YES" (without quotes). Then n lines should follow, the i-th of them should contain ai space-separated integers. j-th (1 ≤ j ≤ ai) of these integers should be equal to the color of the j-th pebble in the i-th pile. If there are several possible answers, you may output any of them.

Examples

Input

4 4
1 2 3 4


Output

YES
1
1 4
1 2 4
1 2 3 4


Input

5 2
3 2 4 1 3


Output

NO


Input

5 4
3 2 4 3 5


Output

YES
1 2 3
1 3
1 2 3 4
1 3 4
1 1 2 3 4

Solution (in JAVA):

Solution:


import java.util.*;
import java.io.*;
 
public class codeforces {
	/*public static void sol(char [][] arr, int n, int m) {

	}*/
		
	
	public static void main(String args []) {
		InputReader obj = new InputReader(System.in);
		
		int n=obj.nextInt();
		int k=obj.nextInt();
		int arr [] = new int[n];
		for(int i=0;i<n;i++) {
			arr[i]=obj.nextInt();
		}
		int max=0;
		for(int i=0;i<n;i++) {
			if(arr[i]>max) {
				max=arr[i];
			}
		}
		int min=max+1;
		for(int i=0;i<n;i++) {
			if(arr[i]<min) {
				min=arr[i];
			}
		}
		if(max-min>k) {
			System.out.println("NO");
			return;
		}
		System.out.println("YES");
		int p=1;
		for(int i=0;i<n;i++) {
			p=1;
			for(int j=0;j<arr[i];j++) {
				System.out.print(p+" ");
				p++;
				if(p>k) {
					p=1;
				}
			}
			System.out.println();
		}
	}
	public static class InputReader {
	    public BufferedReader reader;
	    public StringTokenizer tokenizer;
 
	    public InputReader(InputStream stream) {
	        reader = new BufferedReader(new InputStreamReader(stream), 32768);
	        tokenizer = null;
	    }
 
	    public String next() {
	        while (tokenizer == null || !tokenizer.hasMoreTokens()) {
	            try {
	                tokenizer = new StringTokenizer(reader.readLine());
	            } catch (IOException e) {
	                throw new RuntimeException(e);
	            }
	        }
	        return tokenizer.nextToken();
	    }
 
	    public int nextInt() {
	        return Integer.parseInt(next());
	    }
 
	    public long nextLong() {
	        return Long.parseLong(next());
	    }
 
	}
}