Problem: Write a program which manipulates a sequence A = {a1, a2, . . . , an} with the following operations:

* add(s, t, x): add x to as, as+1, ..., at.
* get(i): output the value of ai.



Note that the initial values of ai (i = 1, 2, . . . , n) are 0.

Constraints

* 1 ≤ n ≤ 100000
* 1 ≤ q ≤ 100000
* 1 ≤ s ≤ t ≤ n
* 1 ≤ i ≤ n
* 0 ≤ x ≤ 1000

Input


n q
query1
query2
:
queryq


In the first line, n (the number of elements in A) and q (the number of queries) are given. Then, ith query queryi is given in the following format:


0 s t x


or


1 t


The first digit represents the type of the query. '0' denotes add(s, t, x) and '1' denotes get(i).

Output

For each get operation, print the value.

Examples

Input

3 5
0 1 2 1
0 2 3 2
0 3 3 3
1 2
1 3


Output

3
5


Input

4 3
1 2
0 1 4 1
1 2


Output

0
1

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
#define all(vec) vec.begin(), vec.end()
using namespace std;
using ll = long long;
using P = pair<int, int>;
constexpr ll INF = (1LL << 30) - 1LL;
constexpr ll LINF = (1LL << 60) - 1LL;
constexpr ll MOD = 1e9 + 7;
template <typename T> void chmin(T &a, T b) { a = min(a, b); }
template <typename T> void chmax(T &a, T b) { a = max(a, b); }
template <typename T> struct Segtree {
    inline T merge(T a, T b) { return a + b; }
    inline void act(T &a, T b) { a += b; }
    vector<T> dat;
    int n;
    T e;
    Segtree(int n_, T e) : e(e) {
        n = 1;
        while (n < n_) {
            n <<= 1;
        }
        dat.resize(2 * n, e);
    }
    void set(const int &a, const int &b, const T &x, int k, int l, int r) {
        if (b <= l || r <= a) {
            return;
        }
        if (a <= l && r <= b) {
            act(dat[k], x);
            return;
        }
        set(a, b, x, k << 1, l, (l + r) >> 1);
        set(a, b, x, k << 1 | 1, (l + r) >> 1, r);
    }
    inline void set(const int &a, const int &b, const T &x) {
        if (a >= b) {
            return;
        }
        set(a, b, x, 1, 0, n);
    }
    T get(int k) {
        k += n;
        T res = dat[k];
        k >>= 1;
        while (k > 0) {
            res = merge(res, dat[k]);
            k >>= 1;
        }
        return res;
    }
};

int main() {
    cin.tie(0);
    ios::sync_with_stdio(false);
    int n, q;
    cin >> n >> q;
    Segtree<int> seg(n, 0);
    while (q--) {
        int t;
        cin >> t;
        if (t == 0) {
            int l, r, x;
            cin >> l >> r >> x;
            --l;
            seg.set(l, r, x);
        } else {
            int i;
            cin >> i;
            --i;
            cout << seg.get(i) << "\n";
        }
    }
}