Problem: Olesya loves numbers consisting of n digits, and Rodion only likes numbers that are divisible by t. Find some number that satisfies both of them.

Your task is: given the n and t print an integer strictly larger than zero consisting of n digits that is divisible by t. If such number doesn't exist, print  - 1.

Input

The single line contains two numbers, n and t (1 ≤ n ≤ 100, 2 ≤ t ≤ 10) — the length of the number and the number it should be divisible by.

Output

Print one such positive number without leading zeroes, — the answer to the problem, or  - 1, if such number doesn't exist. If there are multiple possible answers, you are allowed to print any of them.

Examples

Input

3 2


Output

712

Solution (in JAVA):

Solution:
import java.util.Scanner;
 
public class AC{
    public static  void main(String args[]){
        Scanner in = new Scanner(System.in);
        int n = in.nextInt();
        int t = in.nextInt();
        
        if(t == 10){
            if(n == 1)
                System.out.println(-1);
            else{
                System.out.print(1);
               for(int i = 0; i < n-1 ; i++)
                    System.out.print(0);
            }
            
        }else
            for(int i = 0; i < n; i++)
                System.out.print(t);
    }
}