Problem: Write a program which manipulates a sequence A = {a1, a2, . . . , an} with the following operations:

* add(s, t, x): add x to as, as+1, ..., at.
* get(i): output the value of ai.



Note that the initial values of ai (i = 1, 2, . . . , n) are 0.

Constraints

* 1 ≤ n ≤ 100000
* 1 ≤ q ≤ 100000
* 1 ≤ s ≤ t ≤ n
* 1 ≤ i ≤ n
* 0 ≤ x ≤ 1000

Input


n q
query1
query2
:
queryq


In the first line, n (the number of elements in A) and q (the number of queries) are given. Then, ith query queryi is given in the following format:


0 s t x


or


1 t


The first digit represents the type of the query. '0' denotes add(s, t, x) and '1' denotes get(i).

Output

For each get operation, print the value.

Examples

Input

3 5
0 1 2 1
0 2 3 2
0 3 3 3
1 2
1 3


Output

3
5


Input

4 3
1 2
0 1 4 1
1 2


Output

0
1

Solution (in CPP):

Solution:
#include<iostream>
using namespace std;
#include<vector>
#include<functional>
template<typename T>
struct dualsegtree{
	function<T(T,T)>lazycalcfn,updatefn;
	int n;
	T lazydefvalue;
	vector<T>dat,lazy;
	vector<bool>lazyflag;
	dualsegtree(int n_=0,T defvalue=0,
		function<T(T,T)>lazycalcfn_=[](T a,T b){return a+b;},
		function<T(T,T)>updatefn_=[](T a,T b){return a+b;},
		T lazydefvalue_=0
	):lazydefvalue(lazydefvalue_),
		lazycalcfn(lazycalcfn_),updatefn(updatefn_)
	{
		n=1;
		while(n<n_)n<<=1;
		dat.assign(n,defvalue);
		lazy.assign(n-1,lazydefvalue);
		lazyflag.assign(n-1,false);
	}
	void copy(const vector<T>&v)
	{
		for(int i=0;i<v.size();i++)dat[i]=v[i];
		lazy.assign(n-1,lazydefvalue);
		lazyflag.assign(n-1,false);
	}
	void update(int a,int b,T x,int k=0,int l=0,int r=-1)//[a,b)
	{
		if(r<0)r=n;
		if(b<=l||r<=a)return;
		else if(a<=l&&r<=b)
		{
			if(k<n-1)
			{
				lazy[k]=lazycalcfn(lazy[k],x);
				lazyflag[k]=true;
			}
			else dat[k-n+1]=updatefn(dat[k-n+1],x);
		}
		else
		{
			if(lazyflag[k])
			{
				update(0,n,lazy[k],k*2+1,l,(l+r)/2);
				update(0,n,lazy[k],k*2+2,(l+r)/2,r);
				lazy[k]=lazydefvalue;
				lazyflag[k]=false;
			}
			update(a,b,x,k*2+1,l,(l+r)/2);
			update(a,b,x,k*2+2,(l+r)/2,r);
		}
	}
	T query(int i)
	{
		T ret=dat[i];
		i+=n-1;
		while(i>0)
		{
			i=(i-1)/2;
			if(lazyflag[i])ret=updatefn(ret,lazy[i]);
		}
		return ret;
	}
};
int main()
{
	int N,Q;
	cin>>N>>Q;
	dualsegtree<int>P(N,0,
		[](int a,int b){return a+b;},[](int a,int b){return a+b;});
	for(;Q--;)
	{
		int q;cin>>q;
		if(q==0)
		{
			int s,t,x;cin>>s>>t>>x;
			P.update(s-1,t,x);
		}
		else
		{
			int i;cin>>i;cout<<P.query(i-1)<<endl;
		}
	}
}