Problem: K Average Ranges

Given the sequence a_1, a_2, .., a_N.

How many intervals in this sequence have an average value of K or more and a length of 1 or more?

input


N K
a_1 a_2 ... a_N


output

Output the answer.

Constraint

* 1 \ leq N \ leq 10 ^ 5
* 1 \ leq K \ leq 10 ^ 9
* 1 \ leq a_i \ leq 10 ^ 9



Input example


6 6
8 6 9 1 2 1


Output example


7






Example

Input

6 6
8 6 9 1 2 1


Output

7

Solution (in CPP):

Solution:
#include <iostream>
#include <vector>
using namespace std;

typedef long long ll;
ll N,K;

ll merge_count(vector<ll> &a){
	int n = a.size();
	if(n<=1) return 0;
	ll cnt = 0;
	vector<ll> b(a.begin(),a.begin() + n/2);
	vector<ll> c(a.begin() + n/2, a.end());
	cnt += merge_count(b);
	cnt += merge_count(c);
	int ai = 0,bi = 0,ci = 0;
	while(ai<n){
		if(bi<b.size() && (ci == c.size() || b[bi] <= c[ci])){
			a[ai++] = b[bi++];
		}else{
			cnt += n/2 - bi;
			a[ai++] = c[ci++];
		}
	}
	return cnt;
}

int main(){
	cin >> N >> K;
	vector<ll> A(N+1);
	A[0] = 0;
	for(int i=1;i<=N;i++){
		cin >> A[i];
		A[i] -= K;
		A[i] += A[i-1];
	}
	cout << N*(N+1)/2 - merge_count(A) << endl;
}