Problem: Today Oz is playing with his game-board. He has N coins of type-1 and M coins of type-2. Also the game-board has N squares of type-1 and M squares of type-2. In this game Oz must place one coin into each square. After placing all coins Oz will get a score based on his coin placement strategy . 

His score calculation is like this : If type-1 square contains a type-1 coin then he will get A points, if type-2 square contains a type-2 coin then he will get B points and in all other cases, he will get C points.
Oz's total game score will be sum of scores of all squares. Help Oz to earn maximum game points with his game-board.

Input :

The first line contains the number of test cases T . 

Each test case consists of five space separated integers - N, M, A, B and C. 

Output :

For each test case output maximum game points that Oz can earn.

Constraints :

1 ≤  T ≤ 100

1 ≤ N, M ≤ 10^9

-10^4  ≤ A, B, C ≤ 10^4

SAMPLE INPUT
2
3 4 500 800 600
1 5 10 -20 -30

SAMPLE OUTPUT
4700
-90

Explanation

For first sample :

With optimal strategy Oz will place 3 coins of type-1 into 3 squares of type-1 getting score =500+500+500 = 1500
and he will place 4 coins of type-2 into 4 squares of type-2 getting score = 800+800+800+800 = 3200
so total score will be 1500+3200 =4700
He cannot get better then this in any other coin placement strategy.

Solution (in PYTHON):

Solution:
t = input()
while t > 0:
	t -= 1
	n, m, nc, mc, oc = map(int, raw_input().split(" "))
	cost1 = (n*nc) + (m*mc)
	cost2 = -99999999999999
	cost3 = -99999999999999
	cost4 = -99999999999999
	if n > m:
		cost2 = (m*oc) + (n-m)*nc + (m*oc)
	elif n < m:
		cost3 = (n*oc) + (m-n)*mc + (n*oc)
	else:
		cost4 = (m+n)*oc
	print max(cost1, cost2, cost3, cost4)