Problem: Write a program which manipulates a sequence A = {a0, a1, . . . , an−1} with the following operations:

* update(s, t, x): change as, as+1, ..., at to x.
* find(s, t): report the minimum element in as, as+1, ..., at.



Note that the initial values of ai (i = 0, 1, . . . , n−1) are 231-1.

Constraints

* 1 ≤ n ≤ 100000
* 1 ≤ q ≤ 100000
* 0 ≤ s ≤ t < n
* 0 ≤ x < 231−1

Input


n q
query1
query2
:
queryq


In the first line, n (the number of elements in A) and q (the number of queries) are given. Then, ith query queryi is given in the following format:


0 s t x


or


1 s t


The first digit represents the type of the query. '0' denotes update(s, t, x) and '1' denotes find(s, t).

Output

For each find operation, print the minimum value.

Examples

Input

3 5
0 0 1 1
0 1 2 3
0 2 2 2
1 0 2
1 1 2


Output

1
2


Input

1 3
1 0 0
0 0 0 5
1 0 0


Output

2147483647
5

Solution (in CPP):

Solution:
#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
 
struct query{
  int type;//0=empty, 1=set
  ll value;
  query(int a=0,ll b=0):type(a),value(b) {}
};
 
query s[(1<<18)];
ll t[(1<<18)];
 
void compute(int k,int l,int r){
  query q=s[k];
  s[k].type=0;
  if(q.type==0||r-l==1)return;
  s[k*2+1]=s[k*2+2]=q;  
  t[k*2+1]=t[k*2+2]=q.value;
}
 
void Set(int a,int b,ll x,int k=0,int l=0,int r=(1<<17)){
  if(b<=l || r<=a)return;
  compute(k,l,r);
  if(a<=l && r<=b){
    s[k]=query(1,x);
    t[k]=x;
  }else{
    int m=(l+r)/2;
    Set(a,b,x,k*2+1,l,m);
    Set(a,b,x,k*2+2,m,r);
    t[k]=min(t[k*2+1],t[k*2+2]);
  }
}
 
ll Get(int a,int b,int k=0,int l=0,int r=(1<<17)){
  if(b<=l || r<=a)return (1LL<<60);
  compute(k,l,r);
  if(a<=l && r<=b){
    return t[k];
  }else{
    int m=(l+r)/2;
    ll lv=Get(a,b,k*2+1,l,m);
    ll rv=Get(a,b,k*2+2,m,r);
    return min(lv,rv);
  }
}
 
 
 
int main(){
  int n,q,type,a,b,x;
  Set(0,(1<<17),2147483647);
  scanf("%d %d",&n,&q);
  while(q--){
    scanf("%d",&type);
    if(type==0){
      scanf("%d %d %d",&a,&b,&x);
assert( x < INT_MAX ) ;
      b++;
      Set(a,b,x);
    }else{
      scanf("%d %d",&a,&b);
      b++;
      printf("%lld\n",Get(a,b));
    }
  }
  return 0;
}