Problem: Ivan is going to sleep now and wants to set his alarm clock. There will be many necessary events tomorrow, the i-th of them will start during the x_i-th minute. Ivan doesn't want to skip any of the events, so he has to set his alarm clock in such a way that it rings during minutes x_1, x_2, ..., x_n, so he will be awake during each of these minutes (note that it does not matter if his alarm clock will ring during any other minute).

Ivan can choose two properties for the alarm clock — the first minute it will ring (let's denote it as y) and the interval between two consecutive signals (let's denote it by p). After the clock is set, it will ring during minutes y, y + p, y + 2p, y + 3p and so on.

Ivan can choose any minute as the first one, but he cannot choose any arbitrary value of p. He has to pick it among the given values p_1, p_2, ..., p_m (his phone does not support any other options for this setting).

So Ivan has to choose the first minute y when the alarm clock should start ringing and the interval between two consecutive signals p_j in such a way that it will ring during all given minutes x_1, x_2, ..., x_n (and it does not matter if his alarm clock will ring in any other minutes).

Your task is to tell the first minute y and the index j such that if Ivan sets his alarm clock with properties y and p_j it will ring during all given minutes x_1, x_2, ..., x_n or say that it is impossible to choose such values of the given properties. If there are multiple answers, you can print any.

Input

The first line of the input contains two integers n and m (2 ≤ n ≤ 3 ⋅ 10^5, 1 ≤ m ≤ 3 ⋅ 10^5) — the number of events and the number of possible settings for the interval between signals.

The second line of the input contains n integers x_1, x_2, ..., x_n (1 ≤ x_i ≤ 10^{18}), where x_i is the minute when i-th event starts. It is guaranteed that all x_i are given in increasing order (i. e. the condition x_1 < x_2 < ... < x_n holds).

The third line of the input contains m integers p_1, p_2, ..., p_m (1 ≤ p_j ≤ 10^{18}), where p_j is the j-th option for the interval between two consecutive signals.

Output

If it's impossible to choose such values y and j so all constraints are satisfied, print "NO" in the first line.

Otherwise print "YES" in the first line. Then print two integers y (1 ≤ y ≤ 10^{18}) and j (1 ≤ j ≤ m) in the second line, where y is the first minute Ivan's alarm clock should start ringing and j is the index of the option for the interval between two consecutive signals (options are numbered from 1 to m in the order they are given input). These values should be chosen in such a way that the alarm clock will ring during all given minutes x_1, x_2, ..., x_n. If there are multiple answers, you can print any.

Examples

Input


3 5
3 12 18
2 6 5 3 3


Output


YES
3 4


Input


4 2
1 5 17 19
4 5


Output


NO


Input


4 2
1 5 17 19
2 1


Output


YES
1 1

Solution (in JAVA):

Solution:



import java.io.*;
import java.lang.reflect.Array;
import java.math.*;
import java.util.*;

@SuppressWarnings("Duplicates")
// author @mdazmat9
public class codeforces{
    static long abs=1000000007;
    public static void main(String[] args) throws IOException {

        Scanner sc = new Scanner(System.in);
        PrintWriter out = new PrintWriter(System.out);
        int test = 1;
        for (int ind = 0; ind < test; ind++) {
            int n = sc.nextInt();
            int m=sc.nextInt();
            HashMap<Long,Long> map=new HashMap<>();
            ArrayList<Long> list=new ArrayList<>();
            long[] a=new long[n];
            for(int i=0;i<n;i++)
                a[i]=sc.nextLong();
            for(long i=0;i<m;i++){
                long number=sc.nextLong();
                map.put(number,i+1);
                list.add(number);
            }
            long gc=a[1]-a[0];
            for(int i=0;i<n-1;i++){
                long num=a[i+1]-a[i];
                gc=gcd(gc,num);
            }
            boolean bool=false;
            long loop=gc;
            long ans=0;
            for(int i=0;i<m;i++){
                if(gc%list.get(i)==0){
                    ans=i+1;
                    bool=true;
                    break;
                }
            }


            if(bool){
                out.println("YES");
                out.println(a[0]+" "+ans);
            }
            else out.println("NO");


        }

        out.flush();
    }






    public static double logb( double a, double b )
    {
        return Math.log(a) / Math.log(b);
    }

    static long fast_pow(long a, long b) {
        if(b == 0)
            return 1L;

        long val = fast_pow(a, b / 2);

        if(b % 2 == 0)
            return val * val % mod;
        else
            return val * val % mod * a % mod;
    }
    static long mod = (long)1e9 + 7;
    static   void shuffle(int[] a) {
        int n = a.length;
        for(int i = 0; i < n; i++) {
            int r = i + (int) (Math.random() * (n - i));
            int tmp = a[i];
            a[i] = a[r];
            a[r] = tmp;
        }
    }
    static long gcd(long a , long b)
    {
        if(b == 0)
            return a;
        return gcd(b , a % b);
    }

}
class Scanner {
    public BufferedReader reader;
    public StringTokenizer st;

    public Scanner(InputStream stream) {
        reader = new BufferedReader(new InputStreamReader(stream));
        st = null;
    }

    public String next() {
        while (st == null || !st.hasMoreTokens()) {
            try {
                String line = reader.readLine();
                if (line == null) return null;
                st = new StringTokenizer(line);
            } catch (Exception e) {
                throw (new RuntimeException());
            }
        }
        return st.nextToken();
    }

    public int nextInt() {
        return Integer.parseInt(next());
    }

    public long nextLong() {
        return Long.parseLong(next());
    }

    public double nextDouble() {
        return Double.parseDouble(next());
    }
}

class OutputWriter {
    BufferedWriter writer;

    public OutputWriter(OutputStream stream) {
        writer = new BufferedWriter(new OutputStreamWriter(stream));
    }

    public void print(int i) throws IOException {
        writer.write(i);
    }

    public void print(String s) throws IOException {
        writer.write(s);
    }

    public void print(char[] c) throws IOException {
        writer.write(c);
    }

    public void close() throws IOException {
        writer.close();
    }

}
class Pair {
    int x;
    int y;

    // Constructor
    public Pair(int x, int y)
    {
        this.x = x;
        this.y = y;
    }
}
class Compare {

    static void compare_x(Pair arr[], int n)
    {
        // Comparator to sort the pair according to second element
        Arrays.sort(arr, new Comparator<Pair>() {
            @Override public int compare(Pair p1, Pair p2)
            {
                return (p1.x - p2.x);
            }
        });
    }
    static void compare_y(Pair arr[], int n)
    {
        // Comparator to sort the pair according to second element
        Arrays.sort(arr, new Comparator<Pair>() {
            @Override public int compare(Pair p1, Pair p2)
            {
                return (p1.y - p2.y);
            }
        });
    }
}

class Graph {

    int V;
    ArrayList<Integer>[] adjListArray;

    // constructor
    Graph(int V) {
        this.V = V;

        adjListArray = new ArrayList[V];

        for (int i = 0; i < V; i++) {
            adjListArray[i] = new ArrayList<>();
        }
    }

    // Adds an edge to an undirected graph
    void addEdge(int src, int dest) {

        adjListArray[src].add(dest);
        adjListArray[dest].add(src);
    }


    ArrayList<Integer> DFSUtil(int u, boolean visited[], int parent,ArrayList<Integer> list)
    {
        // Mark the current node as visited
        visited[u] = true;

        for (int i = 0; i < adjListArray[u].size(); i++) {
            int n = adjListArray[u].get(i);
            list.add(n);

            if (!visited[i]) {
                DFSUtil(n, visited, u,list);
            }
        }
        return list;

    }


    // The function to do DFS traversal. It uses recursive DFSUtil()
    void DFS(int r,int c) {
        // Mark all the vertices as not visited(set as
        // false by default in java)
        boolean visited[] = new boolean[V];
        ArrayList<Integer> list=new ArrayList<>();
        // Call the recursive helper function to print DFS traversal
        boolean bool=true;

    }


}