Problem: Olesya loves numbers consisting of n digits, and Rodion only likes numbers that are divisible by t. Find some number that satisfies both of them.

Your task is: given the n and t print an integer strictly larger than zero consisting of n digits that is divisible by t. If such number doesn't exist, print  - 1.

Input

The single line contains two numbers, n and t (1 ≤ n ≤ 100, 2 ≤ t ≤ 10) — the length of the number and the number it should be divisible by.

Output

Print one such positive number without leading zeroes, — the answer to the problem, or  - 1, if such number doesn't exist. If there are multiple possible answers, you are allowed to print any of them.

Examples

Input

3 2


Output

712

Solution (in JAVA):

Solution:

import static java.lang.System.out;

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.math.BigInteger;
import java.util.*;

public class Main {
    static int n, k;


    public static void main(String[] args) {
        Input(new FastReader());
        Solve();

    }

    public static void Solve() {
        if (n == 1 && k == 10) out.println(-1);
        else {
            out.print(k);
            if (k == 10)
                for (int i = 0; i < n - 2; i++) out.print(0);
            else for (int i = 0; i < n - 1; i++) out.print(0);

        }
    }

    public static void Input(FastReader input) {
        n = input.nextInt();
        k = input.nextInt();
    }


    public static class FastReader {

        BufferedReader br;
        StringTokenizer st;

        public FastReader() {
            br = new BufferedReader(new InputStreamReader(System.in));
        }

        String next() {
            while (st == null || !st.hasMoreElements()) {
                try {
                    st = new StringTokenizer(br.readLine());
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
            return st.nextToken();
        }

        int nextInt() {
            return Integer.parseInt(next());
        }

        long nextLong() {
            return Long.parseLong(next());
        }

        double nextDouble() {
            return Double.parseDouble(next());
        }

        String nextLine() {
            String string = "";
            try {
                string = br.readLine();
            } catch (IOException e) {
                e.printStackTrace();
            }
            return string;
        }

        char nextChar() {
            return next().charAt(0);
        }

        String[] nextStringArray() {
            String[] str = null;
            try {
                str = this.br.readLine().trim().split(" ");
            } catch (IOException e) {
                e.printStackTrace();
            }
            return str;
        }

        int[] nextIntArray() {
            String[] data = nextStringArray();
            int[] a = new int[data.length];

            for (int i = 0; i < a.length; i++) {
                a[i] = Integer.parseInt(data[i]);
            }

            return a;
        }

        Integer[] nextIntegerArray() {
            String[] data = nextStringArray();
            Integer[] a = new Integer[data.length];

            for (int i = 0; i < a.length; i++) {
                a[i] = Integer.parseInt(data[i]);
            }

            return a;
        }

        long[] nextLongArray() {
            String[] data = nextStringArray();
            long[] a = new long[data.length];

            for (int i = 0; i < a.length; i++) {
                a[i] = Long.parseLong(data[i]);
            }

            return a;
        }

    }


}