Problem: Olesya loves numbers consisting of n digits, and Rodion only likes numbers that are divisible by t. Find some number that satisfies both of them.

Your task is: given the n and t print an integer strictly larger than zero consisting of n digits that is divisible by t. If such number doesn't exist, print  - 1.

Input

The single line contains two numbers, n and t (1 ≤ n ≤ 100, 2 ≤ t ≤ 10) — the length of the number and the number it should be divisible by.

Output

Print one such positive number without leading zeroes, — the answer to the problem, or  - 1, if such number doesn't exist. If there are multiple possible answers, you are allowed to print any of them.

Examples

Input

3 2


Output

712

Solution (in JAVA):

Solution:
import java.math.BigInteger;
import java.util.Scanner;

public class CF584AOdesyaAndRodion {

	public static void main(String[] args) {
		Scanner s = new Scanner(System.in);
		int n = s.nextInt();
		int t = s.nextInt();
		String st = "";
		if(t==10) {
			if(n<2) {
				st="-1";
			}else if(n==2){
				st="10";
			}else {
				st="10";
				for (int i = 2; i < n; i++) {
					st=st+'0';
				}
			}
		}else {
			for (int i = 0; i < n; i++) {
				st=st+t;
			}
		}
		
		System.out.println(st);
	}

}