Problem: There are n piles of pebbles on the table, the i-th pile contains ai pebbles. Your task is to paint each pebble using one of the k given colors so that for each color c and any two piles i and j the difference between the number of pebbles of color c in pile i and number of pebbles of color c in pile j is at most one.

In other words, let's say that bi, c is the number of pebbles of color c in the i-th pile. Then for any 1 ≤ c ≤ k, 1 ≤ i, j ≤ n the following condition must be satisfied |bi, c - bj, c| ≤ 1. It isn't necessary to use all k colors: if color c hasn't been used in pile i, then bi, c is considered to be zero.

Input

The first line of the input contains positive integers n and k (1 ≤ n, k ≤ 100), separated by a space — the number of piles and the number of colors respectively.

The second line contains n positive integers a1, a2, ..., an (1 ≤ ai ≤ 100) denoting number of pebbles in each of the piles.

Output

If there is no way to paint the pebbles satisfying the given condition, output "NO" (without quotes) .

Otherwise in the first line output "YES" (without quotes). Then n lines should follow, the i-th of them should contain ai space-separated integers. j-th (1 ≤ j ≤ ai) of these integers should be equal to the color of the j-th pebble in the i-th pile. If there are several possible answers, you may output any of them.

Examples

Input

4 4
1 2 3 4


Output

YES
1
1 4
1 2 4
1 2 3 4


Input

5 2
3 2 4 1 3


Output

NO


Input

5 4
3 2 4 3 5


Output

YES
1 2 3
1 3
1 2 3 4
1 3 4
1 1 2 3 4

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.util.Arrays;
import java.util.StringTokenizer;


public class PaintingPebbles {

	public static void main(String args[] ) throws Exception {
		BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
	    PrintWriter w = new PrintWriter(System.out);
	        
	    StringTokenizer st1 = new StringTokenizer(br.readLine());
	    int n = ip(st1.nextToken());
	    int k = ip(st1.nextToken());
	          
	    StringTokenizer st2 = new StringTokenizer(br.readLine());
	    int a[] = new int[n];
	    for(int i=0;i<n;i++)
	    	a[i] = ip(st2.nextToken());
	         
	    int used[][] = new int[n][k];
	    for(int i=0;i<n;i++){
	    	int all = a[i] / k;
	    	Arrays.fill(used[i], all);
	    	for(int j=0;j<a[i]%k;j++)
	    		used[i][j]++;
	    }
	    
	    for(int i=0;i<n;i++){
	    	for(int j=i+1;j<n;j++){
	    		for(int l=0;l<k;l++){
	    			if(Math.abs(used[i][l] - used[j][l]) > 1){
	    				System.out.println("NO");
	    				return;
	    			}
	    		}
	    	}
	    }
	    
	    w.println("YES");
	    for(int i=0;i<n;i++){
	    	for(int j=0;j<k;j++){
	    		for(int t = 0;t<used[i][j];t++)
	    			w.printf("%d ",j+1);
	    	}
	    	w.println();
	    }
	    w.close(); 
	}
	
	public static int ip(String s){
		return Integer.parseInt(s);
	}

}