Problem: Olesya loves numbers consisting of n digits, and Rodion only likes numbers that are divisible by t. Find some number that satisfies both of them.

Your task is: given the n and t print an integer strictly larger than zero consisting of n digits that is divisible by t. If such number doesn't exist, print  - 1.

Input

The single line contains two numbers, n and t (1 ≤ n ≤ 100, 2 ≤ t ≤ 10) — the length of the number and the number it should be divisible by.

Output

Print one such positive number without leading zeroes, — the answer to the problem, or  - 1, if such number doesn't exist. If there are multiple possible answers, you are allowed to print any of them.

Examples

Input

3 2


Output

712

Solution (in JAVA):

Solution:
import java.util.Scanner;

/**
 *
 * @author Zhasan
 */
public class A584 {

    public static void main(String args[]) {
        Scanner in = new Scanner(System.in);

        int n = in.nextInt();
        int t = in.nextInt();

        String num = "";
        if (t < 10) {
            num = t + "";
        } else {
            num = 1 + "";
        }

        for (int i = 1; i < n; i++) {
            num += "0";
        }

        if (n == 1 && t == 10) {
            System.out.println(-1);
        } else {
            System.out.println(num);
        }
    }

}