Problem: Olesya loves numbers consisting of n digits, and Rodion only likes numbers that are divisible by t. Find some number that satisfies both of them.

Your task is: given the n and t print an integer strictly larger than zero consisting of n digits that is divisible by t. If such number doesn't exist, print  - 1.

Input

The single line contains two numbers, n and t (1 ≤ n ≤ 100, 2 ≤ t ≤ 10) — the length of the number and the number it should be divisible by.

Output

Print one such positive number without leading zeroes, — the answer to the problem, or  - 1, if such number doesn't exist. If there are multiple possible answers, you are allowed to print any of them.

Examples

Input

3 2


Output

712

Solution (in JAVA):

Solution:
import java.util.Scanner;

public final class Codeforces {
  public static void main(String args[]) {
    Scanner scan = new Scanner(System.in);
    int n = scan.nextInt();
    int t = scan.nextInt();
    if (n == 1 && t == 10) {
      System.out.print("-1");
      return;
    }
    System.out.print(t == 10 ? 1 : t);
    for (int i = 0; i < n - 1; ++i) {
      System.out.print('0');
    }
  }
}