Problem: Write a program which manipulates a sequence A = {a1, a2, . . . , an} with the following operations:

* add(s, t, x): add x to as, as+1, ..., at.
* get(i): output the value of ai.



Note that the initial values of ai (i = 1, 2, . . . , n) are 0.

Constraints

* 1 ≤ n ≤ 100000
* 1 ≤ q ≤ 100000
* 1 ≤ s ≤ t ≤ n
* 1 ≤ i ≤ n
* 0 ≤ x ≤ 1000

Input


n q
query1
query2
:
queryq


In the first line, n (the number of elements in A) and q (the number of queries) are given. Then, ith query queryi is given in the following format:


0 s t x


or


1 t


The first digit represents the type of the query. '0' denotes add(s, t, x) and '1' denotes get(i).

Output

For each get operation, print the value.

Examples

Input

3 5
0 1 2 1
0 2 3 2
0 3 3 3
1 2
1 3


Output

3
5


Input

4 3
1 2
0 1 4 1
1 2


Output

0
1

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;

const int MAX_N = 1 << 17;
const int INF = 1 << 30;

struct MinSegTree2 {
	int n, segMin[2 * MAX_N - 1], segAdd[2 * MAX_N - 1];
	void init(int n_) {
		n = 1;
		while(n < n_) n *= 2;
		for(int i = 0; i < 2 * n - 1; i++) segMin[i] = 0;
	}

	void add(int a, int b, int x) { add(a, b, x, 0, 0, n); }

	void add(int a, int b, int x, int k, int l, int r) {
		if(r <= a || b <= l) return;
		if(a <= l && r <= b) {
			segAdd[k] += x;
			return;
		}
		add(a, b, x, k * 2 + 1, l, (l + r) / 2);
		add(a, b, x, k * 2 + 2, (l + r) / 2, r);
		segMin[k] = min(segMin[k * 2 + 1] + segAdd[k * 2 + 1], segMin[k * 2 + 2] + segMin[k * 2 + 2]);
	}

	int query(int a, int b) { return query(a, b, 0, 0, n); }

	int query(int a, int b, int k, int l, int r) {
		if(r <= a || b <= l) return INF;
		if(a <= l && r <= b) return segMin[k] + segAdd[k];
		int vl = query(a, b, k * 2 + 1, l, (l + r) / 2);
		int vr = query(a, b, k * 2 + 2, (l + r) / 2, r);
		return min(vl, vr) + segAdd[k];
	}
};

MinSegTree2 st;

int main() {
	cin.tie(0);
	ios::sync_with_stdio(false);

	int n, q;
	cin >> n >> q;

	st.init(n);
	while(q--) {
		int a;
		cin >> a;
		if(a == 0) {
			int s, t, x;
			cin >> s >> t >> x;
			st.add(s - 1, t, x);
		}
		else {
			int i;
			cin >> i;
			cout << st.query(i - 1, i) << endl;
		}
	}
}