Problem: Olesya loves numbers consisting of n digits, and Rodion only likes numbers that are divisible by t. Find some number that satisfies both of them.

Your task is: given the n and t print an integer strictly larger than zero consisting of n digits that is divisible by t. If such number doesn't exist, print  - 1.

Input

The single line contains two numbers, n and t (1 ≤ n ≤ 100, 2 ≤ t ≤ 10) — the length of the number and the number it should be divisible by.

Output

Print one such positive number without leading zeroes, — the answer to the problem, or  - 1, if such number doesn't exist. If there are multiple possible answers, you are allowed to print any of them.

Examples

Input

3 2


Output

712

Solution (in JAVA):

Solution:
import java.util.Scanner;

public class OlesyaAndRodion
{
	public static void main(String[] args)
	{
		Scanner sc = new Scanner(System.in);
		int n = sc.nextInt();
		int t = sc.nextInt();
		if(t == 10)
		{
			if(n == 1)
			{
				System.out.println(-1);
				return;
			}
			else
			{
				System.out.print(10);
				for (int i = 0; i < n-2; i++)
				{
					System.out.print(0);
				}
			}
		}
		else
		{
			if(n == 1)
				System.out.print(t);
			else
			{
				System.out.print(t);
				for (int i = 0; i < n-2; i++)
					System.out.print(0);
				System.out.println(t);
				{
					
				}
			}
		}
		
		System.out.println();
	}
}