Problem: There are n piles of pebbles on the table, the i-th pile contains ai pebbles. Your task is to paint each pebble using one of the k given colors so that for each color c and any two piles i and j the difference between the number of pebbles of color c in pile i and number of pebbles of color c in pile j is at most one.

In other words, let's say that bi, c is the number of pebbles of color c in the i-th pile. Then for any 1 ≤ c ≤ k, 1 ≤ i, j ≤ n the following condition must be satisfied |bi, c - bj, c| ≤ 1. It isn't necessary to use all k colors: if color c hasn't been used in pile i, then bi, c is considered to be zero.

Input

The first line of the input contains positive integers n and k (1 ≤ n, k ≤ 100), separated by a space — the number of piles and the number of colors respectively.

The second line contains n positive integers a1, a2, ..., an (1 ≤ ai ≤ 100) denoting number of pebbles in each of the piles.

Output

If there is no way to paint the pebbles satisfying the given condition, output "NO" (without quotes) .

Otherwise in the first line output "YES" (without quotes). Then n lines should follow, the i-th of them should contain ai space-separated integers. j-th (1 ≤ j ≤ ai) of these integers should be equal to the color of the j-th pebble in the i-th pile. If there are several possible answers, you may output any of them.

Examples

Input

4 4
1 2 3 4


Output

YES
1
1 4
1 2 4
1 2 3 4


Input

5 2
3 2 4 1 3


Output

NO


Input

5 4
3 2 4 3 5


Output

YES
1 2 3
1 3
1 2 3 4
1 3 4
1 1 2 3 4

Solution (in PYTHON):

Solution:
import sys
data = sys.stdin.readline()
n,m = data.split(' ')
n = int(n)
m = int(m)
data = sys.stdin.readline()
a = [int(i) for i in data.split(' ')]
min_a = 200
for data in a:
    if data < min_a:
        min_a = data
res = []
for i in xrange(n):
    res.append([])

for j in xrange(n):
    for k in xrange(min_a):
        res[j].append(1)

for i in xrange(1,m+1):
    for j in xrange(n):
        if len(res[j]) < a[j]:
            res[j].append(i)
flag = 1
for i in xrange(n):
    if len(res[i]) < a[i]:
        flag = 0

if flag:
    print 'YES'
    for i in xrange(n):
        print ' '.join([str(d) for d in res[i]])
            
else:
    print 'NO'