Problem: Ivan is going to sleep now and wants to set his alarm clock. There will be many necessary events tomorrow, the i-th of them will start during the x_i-th minute. Ivan doesn't want to skip any of the events, so he has to set his alarm clock in such a way that it rings during minutes x_1, x_2, ..., x_n, so he will be awake during each of these minutes (note that it does not matter if his alarm clock will ring during any other minute).

Ivan can choose two properties for the alarm clock — the first minute it will ring (let's denote it as y) and the interval between two consecutive signals (let's denote it by p). After the clock is set, it will ring during minutes y, y + p, y + 2p, y + 3p and so on.

Ivan can choose any minute as the first one, but he cannot choose any arbitrary value of p. He has to pick it among the given values p_1, p_2, ..., p_m (his phone does not support any other options for this setting).

So Ivan has to choose the first minute y when the alarm clock should start ringing and the interval between two consecutive signals p_j in such a way that it will ring during all given minutes x_1, x_2, ..., x_n (and it does not matter if his alarm clock will ring in any other minutes).

Your task is to tell the first minute y and the index j such that if Ivan sets his alarm clock with properties y and p_j it will ring during all given minutes x_1, x_2, ..., x_n or say that it is impossible to choose such values of the given properties. If there are multiple answers, you can print any.

Input

The first line of the input contains two integers n and m (2 ≤ n ≤ 3 ⋅ 10^5, 1 ≤ m ≤ 3 ⋅ 10^5) — the number of events and the number of possible settings for the interval between signals.

The second line of the input contains n integers x_1, x_2, ..., x_n (1 ≤ x_i ≤ 10^{18}), where x_i is the minute when i-th event starts. It is guaranteed that all x_i are given in increasing order (i. e. the condition x_1 < x_2 < ... < x_n holds).

The third line of the input contains m integers p_1, p_2, ..., p_m (1 ≤ p_j ≤ 10^{18}), where p_j is the j-th option for the interval between two consecutive signals.

Output

If it's impossible to choose such values y and j so all constraints are satisfied, print "NO" in the first line.

Otherwise print "YES" in the first line. Then print two integers y (1 ≤ y ≤ 10^{18}) and j (1 ≤ j ≤ m) in the second line, where y is the first minute Ivan's alarm clock should start ringing and j is the index of the option for the interval between two consecutive signals (options are numbered from 1 to m in the order they are given input). These values should be chosen in such a way that the alarm clock will ring during all given minutes x_1, x_2, ..., x_n. If there are multiple answers, you can print any.

Examples

Input


3 5
3 12 18
2 6 5 3 3


Output


YES
3 4


Input


4 2
1 5 17 19
4 5


Output


NO


Input


4 2
1 5 17 19
2 1


Output


YES
1 1

Solution (in JAVA):

Solution:
import java.io.BufferedOutputStream;
import java.io.DataInputStream;
import java.io.FileInputStream;
import java.io.IOException;
import java.io.OutputStream;
import java.math.BigInteger;
import java.io.*;
import java.util.*;
public class Main {
	private static Reader fr;
	private static OutputStream out;
	private static final int delta = (int) 1e9 + 7;

	private static class Reader {
		final private int BUFFER_SIZE = 1 << 16;
		private DataInputStream din;
		private byte[] buffer;
		private int bufferPointer, bytesRead;

		public Reader() {
			din = new DataInputStream(System.in);
			buffer = new byte[BUFFER_SIZE];
			bufferPointer = bytesRead = 0;
		}

		public Reader(String file_name) throws IOException {
			din = new DataInputStream(new FileInputStream(file_name));
			buffer = new byte[BUFFER_SIZE];
			bufferPointer = bytesRead = 0;
		}

		public String readLine() throws IOException {
			byte[] buf = new byte[1024];
			int cnt = 0, c;
			while ((c = read()) != -1) {
				if (c == '\n')
					break;
				buf[cnt++] = (byte) c;
			}
			return new String(buf, 0, cnt);
		}

		public int nextInt() throws IOException {
			int ret = 0;
			byte c = read();
			while (c <= ' ')
				c = read();
			boolean neg = (c == '-');
			if (neg)
				c = read();
			do {
				ret = ret * 10 + c - '0';
			} while ((c = read()) >= '0' && c <= '9');

			if (neg)
				return -ret;
			return ret;
		}

		public long nextLong() throws IOException {
			long ret = 0;
			byte c = read();
			while (c <= ' ')
				c = read();
			boolean neg = (c == '-');
			if (neg)
				c = read();
			do {
				ret = ret * 10 + c - '0';
			} while ((c = read()) >= '0' && c <= '9');
			if (neg)
				return -ret;
			return ret;
		}

		public double nextDouble() throws IOException {
			double ret = 0, div = 1;
			byte c = read();
			while (c <= ' ')
				c = read();
			boolean neg = (c == '-');
			if (neg)
				c = read();

			do {
				ret = ret * 10 + c - '0';
			} while ((c = read()) >= '0' && c <= '9');

			if (c == '.') {
				while ((c = read()) >= '0' && c <= '9') {
					ret += (c - '0') / (div *= 10);
				}
			}

			if (neg)
				return -ret;
			return ret;
		}

		private void fillBuffer() throws IOException {
			bytesRead = din.read(buffer, bufferPointer = 0, BUFFER_SIZE);
			if (bytesRead == -1)
				buffer[0] = -1;
		}

		private byte read() throws IOException {
			if (bufferPointer == bytesRead)
				fillBuffer();
			return buffer[bufferPointer++];
		}

		public void close() throws IOException {
			if (din == null)
				return;
			din.close();
		}

		public int[] nextArray(int n) throws IOException {
			int arr[] = new int[n];
			for (int i = 0; i < n; i++) {
				arr[i] = nextInt();
			}
			return arr;
		}
	}

	private static void print(Object str) {
		try {
			out.write(str.toString().getBytes());
		} catch (IOException e) {
			e.printStackTrace();
		}
	}

	private static void println(Object str) {
		try {
			out.write((str.toString() + "\n").getBytes());
		} catch (IOException e) {
			e.printStackTrace();
		}
	}

	private static void printArray(int arr[]) {
		for (int val : arr) {
			print(val + " ");
		}
		println("");
	}

	private static long add(long a, long b) {
		return add(a, b, delta);
	}

	private static long add(long a, long b, long mod) {
		return ((a % mod) + (b % mod)) % mod;
	}

	private static long multiply(long a, long b) {
		return ((a % delta) * (b % delta)) % delta;
	}

	public static double multiply(double a, double b) {
		return ((a % delta) * (b % delta)) % delta;
	}

	private static long pow(int base, int pow) {
		if (pow == 0)
			return 1;
		if (pow == 1)
			return base;
		long halfPow = pow(base, pow / 2);
		if ((pow & 1) == 0)
			return multiply(halfPow, halfPow);
		return multiply(halfPow, multiply(base, halfPow));
	}

	private static long gcd(long a, long b) {
		if (a == 0 || b == 0)
			return a == 0 ? b : a;
		return gcd(b, a % b);
	}

	private static long kadane(int[] arr) {
		int size = arr.length;
		long max_so_far = Integer.MIN_VALUE, max_ending_here = 0;

		for (int anArr : arr) {
			max_ending_here = max_ending_here + anArr;
			if (max_so_far < max_ending_here)
				max_so_far = max_ending_here;
			if (max_ending_here < 0)
				max_ending_here = 0;
		}
		return max_so_far;
	}

	public static void main(String args[]) throws IOException {
		run();
	}

	private static void run() throws IOException {
		fr = new Reader();
		out = new BufferedOutputStream(System.out);
		solve();
		out.flush();
		out.close();
	}
	static int mod=1000000007;
	private static void solve() throws IOException 
	{
	        int n = fr.nextInt();
	        int m = fr.nextInt();
	        
	        long x0 = fr.nextLong();
	        long xl = fr.nextLong();
	        long cgcd = xl - x0;
	        
	        for (int i = 2; i < n; i++) {
	            long l = fr.nextLong();
	            cgcd = gcd(cgcd, l - xl);
	            xl = l;
	        }
	        
	        for (int i = 0; i < m; i++) {
	            if (cgcd % fr.nextLong() == 0) {
	                System.out.println("YES\n" + x0 + " " + (i + 1));
	                return;
	            }
	        }
	        
	        System.out.println("NO");
		}
}