Problem: Olesya loves numbers consisting of n digits, and Rodion only likes numbers that are divisible by t. Find some number that satisfies both of them.

Your task is: given the n and t print an integer strictly larger than zero consisting of n digits that is divisible by t. If such number doesn't exist, print  - 1.

Input

The single line contains two numbers, n and t (1 ≤ n ≤ 100, 2 ≤ t ≤ 10) — the length of the number and the number it should be divisible by.

Output

Print one such positive number without leading zeroes, — the answer to the problem, or  - 1, if such number doesn't exist. If there are multiple possible answers, you are allowed to print any of them.

Examples

Input

3 2


Output

712

Solution (in JAVA):

Solution:
import java.util.*;

public class Rodidon {
	public static void main(String[] args) {
		Scanner f = new Scanner(System.in);
		int n = f.nextInt(), t = f.nextInt();
		f.close();
		if (t == 10) {
			if (n == 1) System.out.println(-1);
			else {
				System.out.print(1);
				for (int i = 1; i < n; i++) System.out.print(0);
			}
			return;
		}
		for (int i = 0; i < n; i++) System.out.print(t);
	}
}