Problem: Today Oz is playing with his game-board. He has N coins of type-1 and M coins of type-2. Also the game-board has N squares of type-1 and M squares of type-2. In this game Oz must place one coin into each square. After placing all coins Oz will get a score based on his coin placement strategy . 

His score calculation is like this : If type-1 square contains a type-1 coin then he will get A points, if type-2 square contains a type-2 coin then he will get B points and in all other cases, he will get C points.
Oz's total game score will be sum of scores of all squares. Help Oz to earn maximum game points with his game-board.

Input :

The first line contains the number of test cases T . 

Each test case consists of five space separated integers - N, M, A, B and C. 

Output :

For each test case output maximum game points that Oz can earn.

Constraints :

1 ≤  T ≤ 100

1 ≤ N, M ≤ 10^9

-10^4  ≤ A, B, C ≤ 10^4

SAMPLE INPUT
2
3 4 500 800 600
1 5 10 -20 -30

SAMPLE OUTPUT
4700
-90

Explanation

For first sample :

With optimal strategy Oz will place 3 coins of type-1 into 3 squares of type-1 getting score =500+500+500 = 1500
and he will place 4 coins of type-2 into 4 squares of type-2 getting score = 800+800+800+800 = 3200
so total score will be 1500+3200 =4700
He cannot get better then this in any other coin placement strategy.

Solution (in PYTHON):

Solution:
'''
# Read input from stdin and provide input before running code'''

t = raw_input()
p=[]
#print 'Hi, %s.' % t
for i in range(int(t)):
	x = raw_input()
	p = x.split(" ");
	n = int(p[0]);
	m = int(p[1]);
	a = int(p[2]);
	b = int(p[3]);
	c = int(p[4]);
	sum1 = n*a+m*b;
	if(n>m):
		sum2 = 2*m*c+(n-m)*a;
	else:
		sum2 = 2*n*c+(m-n)*b;
	if(sum1>sum2):
		print sum1
	else:
		print sum2