Problem: Write a program which manipulates a sequence A = {a1, a2, . . . , an} with the following operations:

* add(s, t, x): add x to as, as+1, ..., at.
* get(i): output the value of ai.



Note that the initial values of ai (i = 1, 2, . . . , n) are 0.

Constraints

* 1 ≤ n ≤ 100000
* 1 ≤ q ≤ 100000
* 1 ≤ s ≤ t ≤ n
* 1 ≤ i ≤ n
* 0 ≤ x ≤ 1000

Input


n q
query1
query2
:
queryq


In the first line, n (the number of elements in A) and q (the number of queries) are given. Then, ith query queryi is given in the following format:


0 s t x


or


1 t


The first digit represents the type of the query. '0' denotes add(s, t, x) and '1' denotes get(i).

Output

For each get operation, print the value.

Examples

Input

3 5
0 1 2 1
0 2 3 2
0 3 3 3
1 2
1 3


Output

3
5


Input

4 3
1 2
0 1 4 1
1 2


Output

0
1

Solution (in CPP):

Solution:
#include<bits/stdc++.h>
#define int long long
using namespace std;
template<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }
template<class T>bool chmin(T &a, const T &b) { if (a>b) { a=b; return 1; } return 0; }

class SegmentTree
{
 private:
    int sz;
    vector<int> data;
 public:
    SegmentTree(int n){
        sz=1;
        while(sz<n) sz*=2;
        data.resize(2*sz,0LL);
    }
    void add(int l,int r,int x){
        l+=sz; r+=sz;
        for(;l<r;l>>=1,r>>=1){
            if(l&1) data[l++]+=x;
            if(r&1) data[--r]+=x;
        }
    }
    int get(int k){
        int res=0;
        for(k+=sz;k>0;k>>=1){
            res+=data[k];
        }
        return res;
    }
};

signed main()
{
    cin.tie(0);
    ios::sync_with_stdio(false);

    int N,Q; cin>>N>>Q;
    SegmentTree seg(N);
    while(Q--){
        int q; cin>>q;
        if(q==0){
            int s,t,x; cin>>s>>t>>x;
            s--;
            seg.add(s,t,x);
        }else{
            int i; cin>>i;
            i--;
            cout<<seg.get(i)<<endl;
        }
    }
    return 0;
}