Problem: K Average Ranges

Given the sequence a_1, a_2, .., a_N.

How many intervals in this sequence have an average value of K or more and a length of 1 or more?

input


N K
a_1 a_2 ... a_N


output

Output the answer.

Constraint

* 1 \ leq N \ leq 10 ^ 5
* 1 \ leq K \ leq 10 ^ 9
* 1 \ leq a_i \ leq 10 ^ 9



Input example


6 6
8 6 9 1 2 1


Output example


7






Example

Input

6 6
8 6 9 1 2 1


Output

7

Solution (in CPP):

Solution:
#include <iostream>
#include <algorithm>
#include <string>
#include <vector>
#include <cmath>
#include <map>
#include <queue>
#include <iomanip>
#include <set>
#include <tuple>
#define mkp make_pair
#define mkt make_tuple
#define rep(i,n) for(int i = 0; i < (n); ++i)
using namespace std;
typedef long long ll;
const ll MOD=1e9+7;

#include <functional>
#include <climits>

//SegmentTree<int> seg(N,[](int a,int b){return min(a,b);},INT_MAX);
template< typename T>
class SegmentTree{
public:

  using F = function<T(T,T)>;

  int n;
  vector<T> tree;
  const F operation;
  const T def;

  SegmentTree(int size,F _operation,T _def):operation(_operation),def(_def){
    n=1;
    while(n<size) n*=2;
    tree.resize(2*n-1,def);
  }

  void initialize(vector<T> v){
    int vSize=v.size();
    n=1;
    while(n<vSize) n*=2;
    tree.resize(2*n-1,def);

    for(int i=0;i<vSize;i++) tree[i+n-1]=v[i];
    for(int i=n-2;i>=0;i--) tree[i]=operation(tree[2*i+1],tree[2*i+2]);
  }

  void update(int index,T value){
    index+=n-1;

    tree[index]=value;
    while(index>0){
      index=(index-1)/2;
      tree[index]=operation(tree[2*index+1],tree[2*index+2]);
    }
  }

  T query(int a,int b,int k=0,int l=0,int r=-1){//[a,b),getMin(a,b,0,0,-1)
    if(r<0) r=n;

    if(r<=a||b<=l) return def;
    else if(a<=l&&r<=b) return tree[k];
    else{
      T lval=query(a,b,2*k+1,l,(l+r)/2);
      T rval=query(a,b,2*k+2,(l+r)/2,r);
      return operation(lval,rval);
    }
  }

  int find(int x,int k=0,int l=0,int r=-1){// a[0]+...+a[i]>=x (i:minimal)
    if(r<0) r=n;
    if(r-l==1) return k-(n-1);
    if(tree[2*k+1]>=x) return find(x,2*k+1,l,(l+r)/2);
    else return find(x-tree[2*k+1],2*k+2,(l+r)/2,r);
  }
};


int main(){
  int N;
  ll K;
  cin>>N>>K;
  vector<ll> A(N);
  rep(i,N) cin>>A[i];

  rep(i,N) A[i]-=K;

  map<ll,int> mp;
  int cnt=0;
  vector<ll> sum(N+1,0);
  rep(i,N) sum[i+1]=sum[i]+A[i];

  vector<ll> v;
  for(int i=0;i<=N;i++){
    v.push_back(sum[i]);
    v.push_back(-sum[i]);
  }
  sort(v.begin(),v.end());
  v.erase(unique(v.begin(),v.end()),v.end());

  for(int i=0;i<v.size();i++){
    if(mp.count(v[i])) continue;
    mp[v[i]]=cnt++;
  }

  SegmentTree<int> seg(cnt+1,[](int a,int b){return a+b;},0);
  seg.update(mp[0],1);
  ll ans=0;
  for(int i=1;i<=N;i++){
    int q=seg.query(0,mp[sum[i]]+1);
    ans+=q;
    int val=seg.query(mp[sum[i]],mp[sum[i]]+1);
    seg.update(mp[sum[i]],val+1);
  }

  cout<<ans<<endl;



  return 0;
}