Problem: Write a program which manipulates a sequence A = {a0, a1, . . . , an−1} with the following operations:

* update(s, t, x): change as, as+1, ..., at to x.
* find(s, t): report the minimum element in as, as+1, ..., at.



Note that the initial values of ai (i = 0, 1, . . . , n−1) are 231-1.

Constraints

* 1 ≤ n ≤ 100000
* 1 ≤ q ≤ 100000
* 0 ≤ s ≤ t < n
* 0 ≤ x < 231−1

Input


n q
query1
query2
:
queryq


In the first line, n (the number of elements in A) and q (the number of queries) are given. Then, ith query queryi is given in the following format:


0 s t x


or


1 s t


The first digit represents the type of the query. '0' denotes update(s, t, x) and '1' denotes find(s, t).

Output

For each find operation, print the minimum value.

Examples

Input

3 5
0 0 1 1
0 1 2 3
0 2 2 2
1 0 2
1 1 2


Output

1
2


Input

1 3
1 0 0
0 0 0 5
1 0 0


Output

2147483647
5

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
/*
  RMQ and RUQ
  区間の最小値を得る(RMQ)
  区間の値を変更する(RUQ)
 */

class RMQ{
public : 
  typedef long long ll;
  ll INF = 1LL<<55;
  struct data{
    bool type; //0 - empty   , 1 - update
    ll value;
  };
  ll n,n_;
  vector<ll> dat;
  vector<data> td;
  int toMax; //0 -> RangeMin 1->RangeMax;
  
  RMQ(){n=-1;}
  RMQ(int n_,int toMax = 0):n_(n_),toMax(toMax){
    n=1;
    while(n<n_)n*=2;
    td.resize(2*n-1,(data){0,0});
    dat.resize(2*n-1,INF);
  }
  
  //[a,b)の値をxに変更　update(a,b,x)
  ll update(int a,int b,ll x,bool flg=true,int k=0,int l=0,int r=-1){
    if(r == -1) {
      r = n;
      assert(a <= b), assert(a <= n_ && b <= n_), assert(a >= 0 && b >= 0);
      if(toMax) x *= -1;
    }
    
    if(r<=a||b<=l)return flg? dat[k]:INF;
    if(a<=l&&r<=b){
      if(flg==true){
        td[k]=(data){1,x};
        dat[k]=x;
      }
      return dat[k];
    }
    
    if(td[k].type){
      td[k].type=0;
      dat[k*2+1] = dat[k*2+2] = td[k].value;
      td[k*2+1] = td[k*2+2] = (data){1,td[k].value};
    }
    
    ll vl=update(a,b,x,flg,k*2+1,l,(l+r)/2);
    ll vr=update(a,b,x,flg,k*2+2,(l+r)/2,r);
    if(flg==true)dat[k]=min(vl,vr);
    return min(vl,vr);
  }
  
  //[a,b)の最小値を得る　find(a,b);
  ll find(int a,int b){return (toMax? -1:1) * update(a,b,0,false);};
};


int main(){
  int q,n;
  cin>>n>>q;
  RMQ T(n);

  for(int i=0;i<n;i++) T.update(0,n,(1LL<<31)-1);
  while(q--){
    int cmd,s,t,x;
    scanf("%d%d%d",&cmd,&s,&t);
    if(cmd==0)cin>>x,T.update(s,t+1,x);
    else cout <<T.find(s,t+1)<<endl;
  }
  return 0;
}