Problem: Today Oz is playing with his game-board. He has N coins of type-1 and M coins of type-2. Also the game-board has N squares of type-1 and M squares of type-2. In this game Oz must place one coin into each square. After placing all coins Oz will get a score based on his coin placement strategy . 

His score calculation is like this : If type-1 square contains a type-1 coin then he will get A points, if type-2 square contains a type-2 coin then he will get B points and in all other cases, he will get C points.
Oz's total game score will be sum of scores of all squares. Help Oz to earn maximum game points with his game-board.

Input :

The first line contains the number of test cases T . 

Each test case consists of five space separated integers - N, M, A, B and C. 

Output :

For each test case output maximum game points that Oz can earn.

Constraints :

1 ≤  T ≤ 100

1 ≤ N, M ≤ 10^9

-10^4  ≤ A, B, C ≤ 10^4

SAMPLE INPUT
2
3 4 500 800 600
1 5 10 -20 -30

SAMPLE OUTPUT
4700
-90

Explanation

For first sample :

With optimal strategy Oz will place 3 coins of type-1 into 3 squares of type-1 getting score =500+500+500 = 1500
and he will place 4 coins of type-2 into 4 squares of type-2 getting score = 800+800+800+800 = 3200
so total score will be 1500+3200 =4700
He cannot get better then this in any other coin placement strategy.

Solution (in PYTHON):

Solution:
'''
# Read input from stdin and provide input before running code

name = raw_input('What is your name?\n')
print 'Hi, %s.' % name
'''
T = int(input())
for t in range(0, T):
    integers = map(int, raw_input().split())
    N = integers[0]
    M = integers[1]
    A = integers[2]
    B = integers[3]
    C = integers[4]

    if N < M:
        k = N
    else:
        k = M

    if 2*C < A+B:
        k = 0

    cost = N*A + M*B + k*(2*C-A-B)

    print cost