Problem: Olesya loves numbers consisting of n digits, and Rodion only likes numbers that are divisible by t. Find some number that satisfies both of them.

Your task is: given the n and t print an integer strictly larger than zero consisting of n digits that is divisible by t. If such number doesn't exist, print  - 1.

Input

The single line contains two numbers, n and t (1 ≤ n ≤ 100, 2 ≤ t ≤ 10) — the length of the number and the number it should be divisible by.

Output

Print one such positive number without leading zeroes, — the answer to the problem, or  - 1, if such number doesn't exist. If there are multiple possible answers, you are allowed to print any of them.

Examples

Input

3 2


Output

712

Solution (in JAVA):

Solution:
import java.util.Scanner;

public class Solution584A {

    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);

        int n = scanner.nextInt();
        int t = scanner.nextInt();


        if (t == 10) {
            if (n == 1) {
                System.out.println(-1);
            } else {
                System.out.printf("%d", 1);
                for (int i = 0; i < n - 1; ++i)
                {
                    System.out.printf("%d", 0);
                }
                System.out.println();
            }
        } else {
            for (int i = 0; i < n; ++i)
            {
                System.out.printf("%d", t);
            }
            System.out.println();
        }
    }

}