Problem: There are n piles of pebbles on the table, the i-th pile contains ai pebbles. Your task is to paint each pebble using one of the k given colors so that for each color c and any two piles i and j the difference between the number of pebbles of color c in pile i and number of pebbles of color c in pile j is at most one.

In other words, let's say that bi, c is the number of pebbles of color c in the i-th pile. Then for any 1 ≤ c ≤ k, 1 ≤ i, j ≤ n the following condition must be satisfied |bi, c - bj, c| ≤ 1. It isn't necessary to use all k colors: if color c hasn't been used in pile i, then bi, c is considered to be zero.

Input

The first line of the input contains positive integers n and k (1 ≤ n, k ≤ 100), separated by a space — the number of piles and the number of colors respectively.

The second line contains n positive integers a1, a2, ..., an (1 ≤ ai ≤ 100) denoting number of pebbles in each of the piles.

Output

If there is no way to paint the pebbles satisfying the given condition, output "NO" (without quotes) .

Otherwise in the first line output "YES" (without quotes). Then n lines should follow, the i-th of them should contain ai space-separated integers. j-th (1 ≤ j ≤ ai) of these integers should be equal to the color of the j-th pebble in the i-th pile. If there are several possible answers, you may output any of them.

Examples

Input

4 4
1 2 3 4


Output

YES
1
1 4
1 2 4
1 2 3 4


Input

5 2
3 2 4 1 3


Output

NO


Input

5 4
3 2 4 3 5


Output

YES
1 2 3
1 3
1 2 3 4
1 3 4
1 1 2 3 4

Solution (in PYTHON3):

Solution:
n, k = list(map(int, input().split()))
piles = list(map(int, input().split()))
min_pebbles = min(piles)
pebble_colors = [[1 for j in range(min_pebbles)] for i in range(n)]
# print(f"initial pebble_colors = {pebble_colors}")

for i in range(1, k+1):
    # print(f"color = {i}")
    for j in range(n):
        pebbles_left = piles[j] - len(pebble_colors[j])
        if pebbles_left > 0:
            pebble_colors[j].append(i)
    # print("after using the given color")
    # print(pebble_colors)

b = True
# print(f"final pebble_colors = {pebble_colors}")
# print(f"piles = {piles}")
for j in range(n):
    if piles[j] != len(pebble_colors[j]):
        b = False
        print("NO")
        break


if b:
    print("YES")
    for colors in pebble_colors:
        for j in colors:
            print(j, end=" ")
        print()