Problem: Olesya loves numbers consisting of n digits, and Rodion only likes numbers that are divisible by t. Find some number that satisfies both of them.

Your task is: given the n and t print an integer strictly larger than zero consisting of n digits that is divisible by t. If such number doesn't exist, print  - 1.

Input

The single line contains two numbers, n and t (1 ≤ n ≤ 100, 2 ≤ t ≤ 10) — the length of the number and the number it should be divisible by.

Output

Print one such positive number without leading zeroes, — the answer to the problem, or  - 1, if such number doesn't exist. If there are multiple possible answers, you are allowed to print any of them.

Examples

Input

3 2


Output

712

Solution (in JAVA):

Solution:
import java.util.Scanner;

public class OlesyaRodion {

	public static void main(String[] args) {
		// TODO Auto-generated method stub
		Scanner s = new Scanner(System.in);
		long n = s.nextLong(); //1 to 100
		long t = s.nextLong(); //
		if (t==10) {
			if (n==1) System.out.println(-1);
			else {
				System.out.print(10);
				for (int i = 0; i < n-2; i++) {
					System.out.print(0);
				}
				System.out.println();
			}
		}
		else {
			System.out.print(t);
			for (int i = 0; i < n-1; i++) {
				System.out.print(0);
			}
			System.out.println();
		}
	}

}