Problem: There are n piles of pebbles on the table, the i-th pile contains ai pebbles. Your task is to paint each pebble using one of the k given colors so that for each color c and any two piles i and j the difference between the number of pebbles of color c in pile i and number of pebbles of color c in pile j is at most one.

In other words, let's say that bi, c is the number of pebbles of color c in the i-th pile. Then for any 1 ≤ c ≤ k, 1 ≤ i, j ≤ n the following condition must be satisfied |bi, c - bj, c| ≤ 1. It isn't necessary to use all k colors: if color c hasn't been used in pile i, then bi, c is considered to be zero.

Input

The first line of the input contains positive integers n and k (1 ≤ n, k ≤ 100), separated by a space — the number of piles and the number of colors respectively.

The second line contains n positive integers a1, a2, ..., an (1 ≤ ai ≤ 100) denoting number of pebbles in each of the piles.

Output

If there is no way to paint the pebbles satisfying the given condition, output "NO" (without quotes) .

Otherwise in the first line output "YES" (without quotes). Then n lines should follow, the i-th of them should contain ai space-separated integers. j-th (1 ≤ j ≤ ai) of these integers should be equal to the color of the j-th pebble in the i-th pile. If there are several possible answers, you may output any of them.

Examples

Input

4 4
1 2 3 4


Output

YES
1
1 4
1 2 4
1 2 3 4


Input

5 2
3 2 4 1 3


Output

NO


Input

5 4
3 2 4 3 5


Output

YES
1 2 3
1 3
1 2 3 4
1 3 4
1 1 2 3 4

Solution (in PYTHON):

Solution:
n, k = map(int, raw_input().split())

ans = [list() for _ in range(n)]
a = []
min_a = 102
min_i = None
for i, x in enumerate(raw_input().split()):
	a.append((int(x), i))
	if min_a > a[i][0]:
		min_a = a[i][0]
		min_i = i
		
color = 1
for x, index in a:
	for _ in range(min(min_a+1, x)):
		ans[index].append(color)

color += 1
a.sort()

i = 1
while color <= k:
	add_i = False
	for j in range(i, n):
		if len(ans[a[j][1]]) < a[j][0]:
			ans[a[j][1]].append(color)
		else:
			add_i = True
			
	if add_i: i += 1
	color += 1
	
a.sort(key=lambda x: x[1])
for i in range(n):
	if len(ans[i]) != a[i][0]:
		print 'NO'
		exit()
		
print 'YES'
for i in range(n): print ' '.join(map(str, ans[i]))