Problem: Dreamoon likes to play with sets, integers and <image>. <image> is defined as the largest positive integer that divides both a and b.

Let S be a set of exactly four distinct integers greater than 0. Define S to be of rank k if and only if for all pairs of distinct elements si, sj from S, <image>.

Given k and n, Dreamoon wants to make up n sets of rank k using integers from 1 to m such that no integer is used in two different sets (of course you can leave some integers without use). Calculate the minimum m that makes it possible and print one possible solution.

Input

The single line of the input contains two space separated integers n, k (1 ≤ n ≤ 10 000, 1 ≤ k ≤ 100).

Output

On the first line print a single integer — the minimal possible m. 

On each of the next n lines print four space separated integers representing the i-th set.

Neither the order of the sets nor the order of integers within a set is important. If there are multiple possible solutions with minimal m, print any one of them.

Examples

Input

1 1


Output

5
1 2 3 5


Input

2 2


Output

22
2 4 6 22
14 18 10 16

Note

For the first example it's easy to see that set {1, 2, 3, 4} isn't a valid set of rank 1 since <image>.

Solution (in JAVA):

Solution:
import java.io.*;
import java.lang.*;
import java.util.*;
import java.text.*;


public class Main {
	

	public static void main(String[] args) throws IOException {

		//BufferedReader cin = new BufferedReader(new FileReader("te.txt"));
		 BufferedReader cin = new BufferedReader(new InputStreamReader(System.in));
	
		
		String line;
		StringTokenizer st;
		
		line = cin.readLine();
		st = new StringTokenizer(line);
		int n=Integer.parseInt(st.nextToken());
		int k=Integer.parseInt(st.nextToken());
		  
		int ans=(n*6-1)*k;
		System.out.println(ans);
		
		StringBuilder sb=new StringBuilder();
		int t;
		for(int i=0;i<n;i++){
			if(i>0)sb.append('\n');
			t=i*6;
			sb.append((t+1)*k);
			sb.append(' ');
			sb.append((t+2)*k);
			sb.append(' ');
			sb.append((t+3)*k);
			sb.append(' ');
			sb.append((t+5)*k);
		}
		System.out.println(sb);
		
		cin.close();
	}

}