Problem: There are n piles of pebbles on the table, the i-th pile contains ai pebbles. Your task is to paint each pebble using one of the k given colors so that for each color c and any two piles i and j the difference between the number of pebbles of color c in pile i and number of pebbles of color c in pile j is at most one.

In other words, let's say that bi, c is the number of pebbles of color c in the i-th pile. Then for any 1 ≤ c ≤ k, 1 ≤ i, j ≤ n the following condition must be satisfied |bi, c - bj, c| ≤ 1. It isn't necessary to use all k colors: if color c hasn't been used in pile i, then bi, c is considered to be zero.

Input

The first line of the input contains positive integers n and k (1 ≤ n, k ≤ 100), separated by a space — the number of piles and the number of colors respectively.

The second line contains n positive integers a1, a2, ..., an (1 ≤ ai ≤ 100) denoting number of pebbles in each of the piles.

Output

If there is no way to paint the pebbles satisfying the given condition, output "NO" (without quotes) .

Otherwise in the first line output "YES" (without quotes). Then n lines should follow, the i-th of them should contain ai space-separated integers. j-th (1 ≤ j ≤ ai) of these integers should be equal to the color of the j-th pebble in the i-th pile. If there are several possible answers, you may output any of them.

Examples

Input

4 4
1 2 3 4


Output

YES
1
1 4
1 2 4
1 2 3 4


Input

5 2
3 2 4 1 3


Output

NO


Input

5 4
3 2 4 3 5


Output

YES
1 2 3
1 3
1 2 3 4
1 3 4
1 1 2 3 4

Solution (in PYTHON3):

Solution:
import sys
import math
 
n, k = [int(x) for x in (sys.stdin.readline()).split()]
an = [int(x) for x in (sys.stdin.readline()).split()]

valarr = []

vmax = 0
vmin = 101

for i in range(n):
    v = [int(an[i] / k)] * k
    for j in range(an[i] % k):
        v[j] += 1

    valarr.append(v)
    if(an[i] > vmax):
        vmax = an[i]
    
    if(an[i] < vmin):
        vmin = an[i]

if(vmax - vmin > k):
    print("NO")
    exit()

print("YES")
for i in range(n):
    t = []
    for j in range(k):
        t.extend([str(j + 1)] * valarr[i][j])

    print(" ".join(t))