Problem: There are n piles of pebbles on the table, the i-th pile contains ai pebbles. Your task is to paint each pebble using one of the k given colors so that for each color c and any two piles i and j the difference between the number of pebbles of color c in pile i and number of pebbles of color c in pile j is at most one.

In other words, let's say that bi, c is the number of pebbles of color c in the i-th pile. Then for any 1 ≤ c ≤ k, 1 ≤ i, j ≤ n the following condition must be satisfied |bi, c - bj, c| ≤ 1. It isn't necessary to use all k colors: if color c hasn't been used in pile i, then bi, c is considered to be zero.

Input

The first line of the input contains positive integers n and k (1 ≤ n, k ≤ 100), separated by a space — the number of piles and the number of colors respectively.

The second line contains n positive integers a1, a2, ..., an (1 ≤ ai ≤ 100) denoting number of pebbles in each of the piles.

Output

If there is no way to paint the pebbles satisfying the given condition, output "NO" (without quotes) .

Otherwise in the first line output "YES" (without quotes). Then n lines should follow, the i-th of them should contain ai space-separated integers. j-th (1 ≤ j ≤ ai) of these integers should be equal to the color of the j-th pebble in the i-th pile. If there are several possible answers, you may output any of them.

Examples

Input

4 4
1 2 3 4


Output

YES
1
1 4
1 2 4
1 2 3 4


Input

5 2
3 2 4 1 3


Output

NO


Input

5 4
3 2 4 3 5


Output

YES
1 2 3
1 3
1 2 3 4
1 3 4
1 1 2 3 4

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.*;
public final class painting_pebbles
{
	static Scanner sc=new Scanner(System.in);
	static PrintWriter out=new PrintWriter(System.out);
	static final String s1="YES",s2="NO";
	
	public static void main(String args[]) throws Exception
	{
		int n=sc.nextInt(),k=sc.nextInt();
		int[] a=new int[n];
		int max=0;
		for(int i=0;i<n;i++)
		{
			a[i]=sc.nextInt();
			if(a[i]>max)
			{
				max=a[i];
			}
		}
		Integer[][] ans=new Integer[n][max];
		int[][] col=new int[n][k];
		for(int i=0;i<n;i++)
		{
			int c=0;
			for(int j=0;j<a[i];j++)
			{
				if(c>=k)
				{
					c=0;
				}
				ans[i][j]=c;
				col[i][c]++;
				c++;
			}
		}
		boolean e=true;
		for(int j=0;j<k;j++)
		{
			for(int i=0;i<n;i++)
			{
				for(int l=0;l<n;l++)
				{
					if(l==i)
					{
						continue;
					}
					if(Math.abs(col[i][j]-col[l][j])>1)
					{
						e=false;
						break;
					}
				}
			}
		}
		if(!e)
		{
			out.println(s2);
		}
		else
		{
			out.println(s1);
			for(int i=0;i<n;i++)
			{
				for(int j=0;j<a[i];j++)
				{
					out.print((ans[i][j]+1)+" ");
				}
				out.println("");
			}
		}
		out.close();
	}
}