Problem: There are n piles of pebbles on the table, the i-th pile contains ai pebbles. Your task is to paint each pebble using one of the k given colors so that for each color c and any two piles i and j the difference between the number of pebbles of color c in pile i and number of pebbles of color c in pile j is at most one.

In other words, let's say that bi, c is the number of pebbles of color c in the i-th pile. Then for any 1 ≤ c ≤ k, 1 ≤ i, j ≤ n the following condition must be satisfied |bi, c - bj, c| ≤ 1. It isn't necessary to use all k colors: if color c hasn't been used in pile i, then bi, c is considered to be zero.

Input

The first line of the input contains positive integers n and k (1 ≤ n, k ≤ 100), separated by a space — the number of piles and the number of colors respectively.

The second line contains n positive integers a1, a2, ..., an (1 ≤ ai ≤ 100) denoting number of pebbles in each of the piles.

Output

If there is no way to paint the pebbles satisfying the given condition, output "NO" (without quotes) .

Otherwise in the first line output "YES" (without quotes). Then n lines should follow, the i-th of them should contain ai space-separated integers. j-th (1 ≤ j ≤ ai) of these integers should be equal to the color of the j-th pebble in the i-th pile. If there are several possible answers, you may output any of them.

Examples

Input

4 4
1 2 3 4


Output

YES
1
1 4
1 2 4
1 2 3 4


Input

5 2
3 2 4 1 3


Output

NO


Input

5 4
3 2 4 3 5


Output

YES
1 2 3
1 3
1 2 3 4
1 3 4
1 1 2 3 4

Solution (in JAVA):

Solution:

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.io.StreamTokenizer;

public class Main {

    static StreamTokenizer st;
    static int n, k, m[][], a[], painted[];

    public static void main(String[] args) throws IOException {
        st = new StreamTokenizer(new BufferedReader(new InputStreamReader(System.in)));
        PrintWriter out = new PrintWriter(System.out);
        n = ri();
        k = ri();
        a = new int[n];
        for (int i = 0; i < n; i++) {
            a[i] = ri();
        }
        painted = new int[n];
        m = new int[n][k + 1];
        boolean con;
        for (int i = 1; i <= k;) {
            con = true;
            if (check(m, i)) {
                for (int j = 0; j < n; ++j) {
                    if (painted[j] < a[j]) {
                        ++painted[j];
                        ++m[j][i];
                    } else {
                        con = false;
                    }
                }
            } else {
                ++i;
            }
            if (!con) {
                ++i;
            }
        }
        for (int i = 0; i < n; ++i) {
            if (painted[i] != a[i]) {
                out.println("NO");
                out.close();
                return;
            }
        }
        out.println("YES");
        for (int i = 0; i < n; i++) {
            for (int j = 1; j <= k; j++) {
                while (m[i][j]-- > 0) {
                    out.print(j);
                    out.print(' ');
                }
            }
            out.println();
        }
        out.close();
    }

    static boolean check(int[][] m, int c) {
        int v = m[0][c];
        for (int i = 1; i < n; i++) {
            if (m[i][c] != v) {
                return false;
            }
        }
        return true;
    }

    static int ri() throws IOException {
        st.nextToken();
        return (int) st.nval;
    }

}