Problem: The employees of the R1 company often spend time together: they watch football, they go camping, they solve contests. So, it's no big deal that sometimes someone pays for someone else.

Today is the day of giving out money rewards. The R1 company CEO will invite employees into his office one by one, rewarding each one for the hard work this month. The CEO knows who owes money to whom. And he also understands that if he invites person x to his office for a reward, and then immediately invite person y, who has lent some money to person x, then they can meet. Of course, in such a situation, the joy of person x from his brand new money reward will be much less. Therefore, the R1 CEO decided to invite the staff in such an order that the described situation will not happen for any pair of employees invited one after another.

However, there are a lot of employees in the company, and the CEO doesn't have a lot of time. Therefore, the task has been assigned to you. Given the debt relationships between all the employees, determine in which order they should be invited to the office of the R1 company CEO, or determine that the described order does not exist.

Input

The first line contains space-separated integers n and m <image> — the number of employees in R1 and the number of debt relations. Each of the following m lines contains two space-separated integers ai, bi (1 ≤ ai, bi ≤ n; ai ≠ bi), these integers indicate that the person number ai owes money to a person a number bi. Assume that all the employees are numbered from 1 to n.

It is guaranteed that each pair of people p, q is mentioned in the input data at most once. In particular, the input data will not contain pairs p, q and q, p simultaneously.

Output

Print -1 if the described order does not exist. Otherwise, print the permutation of n distinct integers. The first number should denote the number of the person who goes to the CEO office first, the second number denote the person who goes second and so on.

If there are multiple correct orders, you are allowed to print any of them.

Examples

Input

2 1
1 2


Output

2 1 


Input

3 3
1 2
2 3
3 1


Output

2 1 3 

Solution (in JAVA):

Solution:
import java.io.OutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.PrintWriter;
import java.io.OutputStream;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.Stack;
import java.io.File;
import java.io.FileNotFoundException;
import java.util.ArrayList;
import java.util.Vector;
import java.util.StringTokenizer;
import java.io.Writer;
import java.io.BufferedReader;
import java.io.FileReader;
import java.io.InputStream;

/**
 * Built using CHelper plug-in
 * Actual solution is at the top
 * @author zodiacLeo
 */
public class Main
{
    public static void main(String[] args)
    {
        InputStream inputStream = System.in;
        OutputStream outputStream = System.out;
        FastScanner in = new FastScanner(inputStream);
        FastPrinter out = new FastPrinter(outputStream);
        CoderStrike2014Round1 solver = new CoderStrike2014Round1();
        solver.solve(1, in, out);
        out.close();
    }

    static class CoderStrike2014Round1
    {
        private int V;
        private int E;
        private boolean[] was;
        private IntegerGraph g;
        private Stack<Integer> stack;

        public void solve(int testNumber, FastScanner in, FastPrinter out)
        {
            V = in.nextInt();
            E = in.nextInt();
            g = new IntegerGraph(V, 0);
            for (int i = 0; i < E; i++)
            {
                int to = in.nextInt() - 1;
                int from = in.nextInt() - 1;
                g.addEdge(from, to, false);
            }
            was = new boolean[V];
            stack = new Stack<>();

            for (int i = 0; i < V; i++)
            {
                if (!was[i])
                {
                    dfs(i);
                }
            }

            StringBuilder sb = new StringBuilder("");
            while (!stack.isEmpty())
            {
                sb.append((stack.pop() + 1) + " ");
            }
            out.println(sb);
        }

        private void dfs(int u)
        {
            was[u] = true;
            ArrayList<Integer> next = g.internalGraph[u];
            for (int i = 0; i < next.size(); i++)
            {
                int v = next.get(i);
                if (!was[v])
                {
                    dfs(v);
                }
            }
            stack.push(u);
        }

    }

    static class FastScanner
    {
        public BufferedReader br;
        public StringTokenizer st;

        public FastScanner(InputStream is)
        {
            br = new BufferedReader(new InputStreamReader(is));
        }

        public FastScanner(File f)
        {
            try
            {
                br = new BufferedReader(new FileReader(f));
            } catch (FileNotFoundException e)
            {
                e.printStackTrace();
            }
        }

        public String next()
        {
            while (st == null || !st.hasMoreElements())
            {
                String s = null;
                try
                {
                    s = br.readLine();
                } catch (IOException e)
                {
                    e.printStackTrace();
                }
                if (s == null)
                    return null;
                st = new StringTokenizer(s);
            }
            return st.nextToken();
        }

        public int nextInt()
        {
            return Integer.parseInt(next());
        }

    }

    static class IntegerGraph
    {
        public int V;
        public int startVertex;
        public int endVertex;
        public boolean[] was;
        public ArrayList[] internalGraph;

        public IntegerGraph(int V, int offset)
        {
            this.V = V;
            this.startVertex = offset;
            this.endVertex = offset + V - 1;

            was = new boolean[V + offset];
            internalGraph = new ArrayList[V + offset];
            for (int i = offset; i < V + offset; i++)
            {
                internalGraph[i] = new ArrayList<Integer>();
            }
        }

        public boolean addEdge(int from, int to, boolean bidirectional)
        {
            if (bidirectional)
            {
                internalGraph[to].add(from);
            }
            return internalGraph[from].add(to);
        }

    }

    static class FastPrinter extends PrintWriter
    {
        public FastPrinter(OutputStream out)
        {
            super(out);
        }

        public FastPrinter(Writer out)
        {
            super(out);
        }

    }
}