Problem: There are n piles of pebbles on the table, the i-th pile contains ai pebbles. Your task is to paint each pebble using one of the k given colors so that for each color c and any two piles i and j the difference between the number of pebbles of color c in pile i and number of pebbles of color c in pile j is at most one.

In other words, let's say that bi, c is the number of pebbles of color c in the i-th pile. Then for any 1 ≤ c ≤ k, 1 ≤ i, j ≤ n the following condition must be satisfied |bi, c - bj, c| ≤ 1. It isn't necessary to use all k colors: if color c hasn't been used in pile i, then bi, c is considered to be zero.

Input

The first line of the input contains positive integers n and k (1 ≤ n, k ≤ 100), separated by a space — the number of piles and the number of colors respectively.

The second line contains n positive integers a1, a2, ..., an (1 ≤ ai ≤ 100) denoting number of pebbles in each of the piles.

Output

If there is no way to paint the pebbles satisfying the given condition, output "NO" (without quotes) .

Otherwise in the first line output "YES" (without quotes). Then n lines should follow, the i-th of them should contain ai space-separated integers. j-th (1 ≤ j ≤ ai) of these integers should be equal to the color of the j-th pebble in the i-th pile. If there are several possible answers, you may output any of them.

Examples

Input

4 4
1 2 3 4


Output

YES
1
1 4
1 2 4
1 2 3 4


Input

5 2
3 2 4 1 3


Output

NO


Input

5 4
3 2 4 3 5


Output

YES
1 2 3
1 3
1 2 3 4
1 3 4
1 1 2 3 4

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.*;

public class prueba{
    
    public static void main(String[] args) throws IOException{
        Scanner sc = new Scanner(System.in);/**/
        PrintWriter printer = new PrintWriter(System.out);/**/
        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
        BufferedWriter bw = new BufferedWriter(new OutputStreamWriter(System.out));
        int n = sc.nextInt() ;
        int k = sc.nextInt() ;
        int[] a= new int[n];
        //int max=-1;
        boolean flag=true;
        String rpta="";
        
        a[0]=sc.nextInt();
        int max=a[0],min=a[0];
        for(int j=0;j<a[0];j++){
            rpta+= String.valueOf(j%k+1);
            if(j!=a[0]-1)rpta+=' ';
            
        }
        rpta+='\n';
        for(int i=1;i<n;i++){
            a[i]=sc.nextInt() ;
            if(Math.abs(a[i]-a[i-1])>k){flag=false;break;}
            for(int j=0;j<a[i];j++){
                rpta+= String.valueOf(j%k+1);
                if(j!=a[i]-1)rpta+=' ';
            }
            rpta+='\n';
            if(max<a[i])max=a[i];
            if(min>a[i])min=a[i];
            if(Math.abs(max-min)>k){flag=false;break;}
        }
        
        if(flag)printer.println("YES\n"+rpta);
        else printer.println("NO");

        printer.close(); /**/
        bw.close();
    }
}