Problem: Carl is a beginner magician. He has a blue, b violet and c orange magic spheres. In one move he can transform two spheres of the same color into one sphere of any other color. To make a spell that has never been seen before, he needs at least x blue, y violet and z orange spheres. Can he get them (possible, in multiple actions)?

Input

The first line of the input contains three integers a, b and c (0 ≤ a, b, c ≤ 1 000 000) — the number of blue, violet and orange spheres that are in the magician's disposal.

The second line of the input contains three integers, x, y and z (0 ≤ x, y, z ≤ 1 000 000) — the number of blue, violet and orange spheres that he needs to get.

Output

If the wizard is able to obtain the required numbers of spheres, print "Yes". Otherwise, print "No".

Examples

Input

4 4 0
2 1 2


Output

Yes


Input

5 6 1
2 7 2


Output

No


Input

3 3 3
2 2 2


Output

Yes

Note

In the first sample the wizard has 4 blue and 4 violet spheres. In his first action he can turn two blue spheres into one violet one. After that he will have 2 blue and 5 violet spheres. Then he turns 4 violet spheres into 2 orange spheres and he ends up with 2 blue, 1 violet and 2 orange spheres, which is exactly what he needs.

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.math.BigInteger;
import java.util.Arrays;
import java.util.Collections;
import java.util.HashMap;
import java.util.HashSet;
import java.util.StringTokenizer;


public class Main {
static class FastScanner {

BufferedReader reader;
StringTokenizer tokenizer;

public FastScanner(InputStream stream) {
this.reader = new BufferedReader(new InputStreamReader(stream));
}

public int nextInt() throws IOException {
return Integer.parseInt(next());
}

public int[] nextIntegerArray(int n) throws IOException {
int[] a = new int[n];
for (int i = 0; i < a.length; i++) {
a[i] = nextInt();
}
return a;
}

public long[] nextLongArray(int n) throws IOException {
long[] a = new long[n];
for (int i = 0; i < a.length; i++) {
a[i] = nextLong();
}
return a;
}

public int nextInt(int radix) throws IOException {
return Integer.parseInt(next(), radix);
}

public long nextLong() throws IOException {
return Long.parseLong(next());
}

public long nextLong(int radix) throws IOException {
return Long.parseLong(next(), radix);
}

public double nextDouble() throws IOException {
return Double.parseDouble(next());
}

public BigInteger nextBigInteger() throws IOException {
return new BigInteger(next());
}

public BigInteger nextBigInteger(int radix) throws IOException {
return new BigInteger(next(), radix);
}

public String next() throws IOException {
if (tokenizer == null || !tokenizer.hasMoreTokens()) {
tokenizer = new StringTokenizer(reader.readLine());
return this.next();
}
return tokenizer.nextToken();
}

public void close() throws IOException {
this.reader.close();
}
}

                   //SOLUTION //


	FastScanner in = new FastScanner(System.in);
	PrintWriter out = new PrintWriter(System.out);

	public static void main(String[] args) throws IOException{
    new Main().solve();
    }//void main
	
	void solve() throws IOException{
		 int oa = in.nextInt(), ob = in.nextInt(), oc = in.nextInt();
	     int ta = in.nextInt(), tb = in.nextInt(), tc = in.nextInt();
	     int count=0,rel=0;
	     if(oa > ta)count+=(oa-ta)/2;
	     else rel+=ta-oa;
	     if(ob > tb)count+=(ob-tb)/2;
	     else rel+=tb-ob;
	     if(oc > tc)count+=(oc-tc)/2;
	     else rel+=tc-oc;
		 if(rel<=count)out.println("Yes");
		 else out.println("No");
		 in.close();
	     out.flush();
		 out.close();
	}
}