Problem: Write a program which manipulates a sequence A = {a0, a1, . . . , an−1} with the following operations:

* update(s, t, x): change as, as+1, ..., at to x.
* find(s, t): report the minimum element in as, as+1, ..., at.



Note that the initial values of ai (i = 0, 1, . . . , n−1) are 231-1.

Constraints

* 1 ≤ n ≤ 100000
* 1 ≤ q ≤ 100000
* 0 ≤ s ≤ t < n
* 0 ≤ x < 231−1

Input


n q
query1
query2
:
queryq


In the first line, n (the number of elements in A) and q (the number of queries) are given. Then, ith query queryi is given in the following format:


0 s t x


or


1 s t


The first digit represents the type of the query. '0' denotes update(s, t, x) and '1' denotes find(s, t).

Output

For each find operation, print the minimum value.

Examples

Input

3 5
0 0 1 1
0 1 2 3
0 2 2 2
1 0 2
1 1 2


Output

1
2


Input

1 3
1 0 0
0 0 0 5
1 0 0


Output

2147483647
5

Solution (in CPP):

Solution:
#include <cstdio>
#include <cstring>
#include <iostream>
#include <string>
#include <cmath>
#include <bitset>
#include <vector>
#include <map>
#include <set>
#include <queue>
#include <deque>
#include <algorithm>
#include <complex>
#include <unordered_map>
#include <unordered_set>
#include <random>
#include <cassert>
#include <fstream>
#include <utility>
#include <functional>
#define popcount __builtin_popcount
using namespace std;
typedef long long int ll;
typedef pair<int, int> P;

template<typename Monoid, typename OperatorMonoid=Monoid>
struct LazySegmentTree{
	using F=function<Monoid(Monoid, Monoid)>;
	using G=function<Monoid(Monoid, OperatorMonoid, int)>;
	using H=function<OperatorMonoid(OperatorMonoid, OperatorMonoid)>;
	int sz;
	vector<Monoid> data;
	vector<OperatorMonoid> lazy;
	const F f;
	const G g;
	const H h;
	const Monoid e1;
	const OperatorMonoid e0;

	LazySegmentTree(int n, const F f, const G g, const H h, const Monoid &e1, const OperatorMonoid &e0): f(f), g(g), h(h), e1(e1), e0(e0){
		sz=1;
		while(sz<n) sz<<=1;
		data.resize(2*sz-1, e1);
		lazy.resize(2*sz-1, e0);
	}

	void eval(int k, int l, int r){
		if(lazy[k]!=e0){
			data[k]=g(data[k], lazy[k], r-l);
			if(k<sz-1){
				lazy[2*k+1]=h(lazy[2*k+1], lazy[k]);
				lazy[2*k+2]=h(lazy[2*k+2], lazy[k]);
			}
		}
		lazy[k]=e0;
	}

	void update(int a, int b, const OperatorMonoid &x, int k, int l, int r){
		eval(k, l, r);
		if(r<=a || b<=l) return;
		if(a<=l && r<=b){
			lazy[k]=h(lazy[k], x);
			eval(k, l, r);
		}else{
			update(a, b, x, 2*k+1, l, (l+r)/2);
			update(a, b, x, 2*k+2, (l+r)/2, r);
			data[k]=f(data[2*k+1], data[2*k+2]);
		}
	}
	void update(int a, int b, const OperatorMonoid &x){
		return update(a, b, x, 0, 0, sz);
	}

	Monoid find(int a, int b, int k, int l, int r){
		eval(k, l, r);
		if(b<=l || r<=a) return e1;
		if(a<=l && r<=b) return data[k];
		else return f(find(a, b, 2*k+1, l, (l+r)/2), find(a, b, 2*k+2, (l+r)/2, r));
	}
	Monoid find(int a, int b){
		return find(a, b, 0, 0, sz);
	}
};
const int INF=2147483647;
int main()
{
	int n, q;
	scanf("%d %d", &n, &q);
	auto f=[](int a, int b){ return min(a, b);};
	auto g=[](int a, int x, int len){ return x;};
	auto h=[](int x, int y){ return y;};
	LazySegmentTree<int> seg(n, f, g, h, INF, INF);
	for(int z=0; z<q; z++){
		int p; scanf("%d", &p);
		if(p==0){
			int s, t, x;
			scanf("%d %d %d", &s, &t, &x);
			seg.update(s, t+1, x);
		}else{
			int s, t;
			scanf("%d %d", &s, &t);
			printf("%d\n", seg.find(s, t+1));
		}
	}
	return 0;
}