Problem: There are n piles of pebbles on the table, the i-th pile contains ai pebbles. Your task is to paint each pebble using one of the k given colors so that for each color c and any two piles i and j the difference between the number of pebbles of color c in pile i and number of pebbles of color c in pile j is at most one.

In other words, let's say that bi, c is the number of pebbles of color c in the i-th pile. Then for any 1 ≤ c ≤ k, 1 ≤ i, j ≤ n the following condition must be satisfied |bi, c - bj, c| ≤ 1. It isn't necessary to use all k colors: if color c hasn't been used in pile i, then bi, c is considered to be zero.

Input

The first line of the input contains positive integers n and k (1 ≤ n, k ≤ 100), separated by a space — the number of piles and the number of colors respectively.

The second line contains n positive integers a1, a2, ..., an (1 ≤ ai ≤ 100) denoting number of pebbles in each of the piles.

Output

If there is no way to paint the pebbles satisfying the given condition, output "NO" (without quotes) .

Otherwise in the first line output "YES" (without quotes). Then n lines should follow, the i-th of them should contain ai space-separated integers. j-th (1 ≤ j ≤ ai) of these integers should be equal to the color of the j-th pebble in the i-th pile. If there are several possible answers, you may output any of them.

Examples

Input

4 4
1 2 3 4


Output

YES
1
1 4
1 2 4
1 2 3 4


Input

5 2
3 2 4 1 3


Output

NO


Input

5 4
3 2 4 3 5


Output

YES
1 2 3
1 3
1 2 3 4
1 3 4
1 1 2 3 4

Solution (in JAVA):

Solution:
import java.util.Scanner;


public class Main_Round289Div2_B {

	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);

		int n = sc.nextInt();
		int k = sc.nextInt();

		int[] a = new int[n];
		for (int i = 0; i < n; i++) {
			a[i] = sc.nextInt();
		}

		int[][] cnum = new int[n][k];
		for (int i = 0; i < n; i++) {
			for (int j = 0; j < k; j++) {
				cnum[i][j] = a[i] / k + (a[i] % k - j > 0 ? 1 : 0);
			}
		}

		boolean flag = true;
		for (int j = 0; j < k; j++) {
			int min = Integer.MAX_VALUE;
			int max = Integer.MIN_VALUE;
			for (int i = 0; i < n; i++) {
				min = Math.min(min, cnum[i][j]);
				max = Math.max(max, cnum[i][j]);
			}
			if (max - min > 1) {
				flag = false;
				break;
			}
		}

		if (flag) {
			System.out.println("YES");
			for (int i = 0; i < n; i++) {
				StringBuffer sb = new StringBuffer();
				for (int j = 0; j < k; j++) {
					for (int l = 0; l < cnum[i][j]; l++) {
						sb.append(j + 1);
						sb.append(" ");
					}
				}
				System.out.println(sb.substring(0, sb.length() - 1));
			}
		} else {
			System.out.println("NO");
		}

		sc.close();
	}
}