Problem: One day Ms Swan bought an orange in a shop. The orange consisted of n·k segments, numbered with integers from 1 to n·k. 

There were k children waiting for Ms Swan at home. The children have recently learned about the orange and they decided to divide it between them. For that each child took a piece of paper and wrote the number of the segment that he would like to get: the i-th (1 ≤ i ≤ k) child wrote the number ai (1 ≤ ai ≤ n·k). All numbers ai accidentally turned out to be different.

Now the children wonder, how to divide the orange so as to meet these conditions:

  * each child gets exactly n orange segments; 
  * the i-th child gets the segment with number ai for sure; 
  * no segment goes to two children simultaneously. 



Help the children, divide the orange and fulfill the requirements, described above.

Input

The first line contains two integers n, k (1 ≤ n, k ≤ 30). The second line contains k space-separated integers a1, a2, ..., ak (1 ≤ ai ≤ n·k), where ai is the number of the orange segment that the i-th child would like to get.

It is guaranteed that all numbers ai are distinct.

Output

Print exactly n·k distinct integers. The first n integers represent the indexes of the segments the first child will get, the second n integers represent the indexes of the segments the second child will get, and so on. Separate the printed numbers with whitespaces.

You can print a child's segment indexes in any order. It is guaranteed that the answer always exists. If there are multiple correct answers, print any of them.

Examples

Input

2 2
4 1


Output

2 4 
1 3 


Input

3 1
2


Output

3 2 1 

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.util.logging.Level;
import java.util.logging.Logger;

public class orange {

	public static void main(String[] args) {
		try {
			BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
			String linea;
			linea = br.readLine();
			String[] dat = linea.split(" ");
			int n = Integer.parseInt(dat[0]);
			int k = Integer.parseInt(dat[1]);
			linea = br.readLine();
			String[] seg = linea.split(" ");
			int[][] child = new int[k][n];
			for(int i = 0; i < k; i++) {
				child[i][0] = Integer.parseInt(seg[i]);
			}
			int col = 0, fil = 1;
			for(int i = 1; i <= n * k; i++) {
				boolean b = false;
				for(int j = 0; j < k; j++) {
					for(int l = 0; l < n; l++) {
						if(child[j][l] == i) {
							b = true;
						}
					}
				}
				if(b == false) {
					child[col][fil] = i;
					if(fil < n - 1) {
						fil++;
					}
					else {
						col++;
						fil = 1;
					}
				}
			}
			for(int i = 0; i < k; i++) {
				for(int j = 0; j < n; j++) {
					//if(j == n - 1) {
						//System.out.print(child[i][j]);
					//}
					//else {
						System.out.print(child[i][j] + " ");
					//}
				}
				System.out.println();
			}
			br.close();
		}
		catch (Exception e) {
			Logger.getLogger(orange.class.getName()).log(Level.SEVERE, null, e);
		}
	}
}