Problem: One day Ms Swan bought an orange in a shop. The orange consisted of n·k segments, numbered with integers from 1 to n·k. 

There were k children waiting for Ms Swan at home. The children have recently learned about the orange and they decided to divide it between them. For that each child took a piece of paper and wrote the number of the segment that he would like to get: the i-th (1 ≤ i ≤ k) child wrote the number ai (1 ≤ ai ≤ n·k). All numbers ai accidentally turned out to be different.

Now the children wonder, how to divide the orange so as to meet these conditions:

  * each child gets exactly n orange segments; 
  * the i-th child gets the segment with number ai for sure; 
  * no segment goes to two children simultaneously. 



Help the children, divide the orange and fulfill the requirements, described above.

Input

The first line contains two integers n, k (1 ≤ n, k ≤ 30). The second line contains k space-separated integers a1, a2, ..., ak (1 ≤ ai ≤ n·k), where ai is the number of the orange segment that the i-th child would like to get.

It is guaranteed that all numbers ai are distinct.

Output

Print exactly n·k distinct integers. The first n integers represent the indexes of the segments the first child will get, the second n integers represent the indexes of the segments the second child will get, and so on. Separate the printed numbers with whitespaces.

You can print a child's segment indexes in any order. It is guaranteed that the answer always exists. If there are multiple correct answers, print any of them.

Examples

Input

2 2
4 1


Output

2 4 
1 3 


Input

3 1
2


Output

3 2 1 

Solution (in JAVA):

Solution:
import java.util.*;
public class acm {
	public static void main(String[] args) {
		Scanner in = new Scanner (System.in);
		int n = in.nextInt();
		int m = in.nextInt();
		int num[] = new int [35];
		for( int i = 0 ; i < m ; i++ ){
			num[i] = in.nextInt();
		}
		int cnt = 1;
		int sum = 0;
		int flag = 1;
		for( int i = 0 ; i < m ; i++ ){
			System.out.print(num[i]);
			sum = 1;
			while ( sum < n ){
				flag = 1;
				for( int k = 0 ; k < m ; k++){ if(cnt == num[k] ){
						flag = 0;
						break;
					}
				}
				if(flag == 1){
					System.out.print(" ");
					System.out.print(cnt);
					sum++;
				}
				cnt++;
			}
			System.out.print("\n");
		}
    }
}