Problem: One day Ms Swan bought an orange in a shop. The orange consisted of n·k segments, numbered with integers from 1 to n·k. 

There were k children waiting for Ms Swan at home. The children have recently learned about the orange and they decided to divide it between them. For that each child took a piece of paper and wrote the number of the segment that he would like to get: the i-th (1 ≤ i ≤ k) child wrote the number ai (1 ≤ ai ≤ n·k). All numbers ai accidentally turned out to be different.

Now the children wonder, how to divide the orange so as to meet these conditions:

  * each child gets exactly n orange segments; 
  * the i-th child gets the segment with number ai for sure; 
  * no segment goes to two children simultaneously. 



Help the children, divide the orange and fulfill the requirements, described above.

Input

The first line contains two integers n, k (1 ≤ n, k ≤ 30). The second line contains k space-separated integers a1, a2, ..., ak (1 ≤ ai ≤ n·k), where ai is the number of the orange segment that the i-th child would like to get.

It is guaranteed that all numbers ai are distinct.

Output

Print exactly n·k distinct integers. The first n integers represent the indexes of the segments the first child will get, the second n integers represent the indexes of the segments the second child will get, and so on. Separate the printed numbers with whitespaces.

You can print a child's segment indexes in any order. It is guaranteed that the answer always exists. If there are multiple correct answers, print any of them.

Examples

Input

2 2
4 1


Output

2 4 
1 3 


Input

3 1
2


Output

3 2 1 

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.util.Arrays;

public class A244 {

	public static void main(String[] args) throws Exception {
		BufferedReader br = new BufferedReader(new InputStreamReader(System.in));

		String[] aux = br.readLine().split(" ");

		int n = Integer.parseInt(aux[0]);
		int k = Integer.parseInt(aux[1]);

		aux = br.readLine().split(" ");

		int segs[] = new int[k + 1];
		int used[] = new int[(n + 1) * (k + 1)];

		for (int i = 0; i < k; i++) {
			segs[i] = Integer.parseInt(aux[i]);
			used[segs[i]] = 1;
		}

		int pos = 1;
		for (int i = 0; i < k; i++) {
			StringBuilder sb = new StringBuilder();
			int got = 0;
			sb.append(segs[i] + " ");
			while (got < n - 1 && pos < used.length) {
				if (used[pos] == 0) {
					used[pos] = 1;
					got++;
					sb.append(pos+ " ");
				}
				pos++;
			}
			System.out.println(sb.toString().trim());
		}

		br.close();
	}

}