Problem: Nastya just made a huge mistake and dropped a whole package of rice on the floor. Mom will come soon. If she sees this, then Nastya will be punished.

In total, Nastya dropped n grains. Nastya read that each grain weighs some integer number of grams from a - b to a + b, inclusive (numbers a and b are known), and the whole package of n grains weighs from c - d to c + d grams, inclusive (numbers c and d are known). The weight of the package is the sum of the weights of all n grains in it.

Help Nastya understand if this information can be correct. In other words, check whether each grain can have such a mass that the i-th grain weighs some integer number x_i (a - b ≤ x_i ≤ a + b), and in total they weigh from c - d to c + d, inclusive (c - d ≤ ∑_{i=1}^{n}{x_i} ≤ c + d).

Input

The input consists of multiple test cases. The first line contains a single integer t (1 ≤ t ≤ 1000) — the number of test cases. 

The next t lines contain descriptions of the test cases, each line contains 5 integers: n (1 ≤ n ≤ 1000) — the number of grains that Nastya counted and a, b, c, d (0 ≤ b < a ≤ 1000, 0 ≤ d < c ≤ 1000) — numbers that determine the possible weight of one grain of rice (from a - b to a + b) and the possible total weight of the package (from c - d to c + d).

Output

For each test case given in the input print "Yes", if the information about the weights is not inconsistent, and print "No" if n grains with masses from a - b to a + b cannot make a package with a total mass from c - d to c + d.

Example

Input


5
7 20 3 101 18
11 11 10 234 2
8 9 7 250 122
19 41 21 321 10
3 10 8 6 1


Output


Yes
No
Yes
No
Yes

Note

In the first test case of the example, we can assume that each grain weighs 17 grams, and a pack 119 grams, then really Nastya could collect the whole pack.

In the third test case of the example, we can assume that each grain weighs 16 grams, and a pack 128 grams, then really Nastya could collect the whole pack.

In the fifth test case of the example, we can be assumed that 3 grains of rice weigh 2, 2, and 3 grams, and a pack is 7 grams, then really Nastya could collect the whole pack.

In the second and fourth test cases of the example, we can prove that it is impossible to determine the correct weight of all grains of rice and the weight of the pack so that the weight of the pack is equal to the total weight of all collected grains.

Solution (in JAVA):

Solution:
//package codeforces.round637div2;

import java.io.*;
import java.util.*;

public class NastyaAndRice {
    public static void main(String[] args) {
//        try {
//            FastScanner in = new FastScanner(new FileInputStream("src/input.in"));
//            PrintWriter out = new PrintWriter(new FileOutputStream("src/output.out"));

        FastScanner in = new FastScanner(System.in);
        PrintWriter out = new PrintWriter(System.out);

            int t = in.nextInt();
            solve(t, in, out);

//        } catch (IOException e) {
//            e.printStackTrace();
//        }
    }

    private static void solve(int q, FastScanner in, PrintWriter out) {
        for (int qq = 0; qq < q; qq++) {
            int n = in.nextInt(), a = in.nextInt(), b = in.nextInt(), c = in.nextInt(), d = in.nextInt();
            if((a - b) * n > c + d || (a + b) * n < c - d) {
                out.println("No");
            }
            else {
                out.println("Yes");
            }
        }
        out.close();
    }

    private static class BinarySearch {
        // return the right most index i such that a[i] <= t
        private static int rightMostUpperBound(Integer[] a, int t) {
            int l = 0, r = a.length - 1;
            while (l < r - 1) {
                int mid = l + (r - l) / 2;
                if (a[mid] <= t) {
                    l = mid;
                } else {
                    r = mid - 1;
                }
            }
            if (a[r] <= t) {
                return r;
            } else if (a[l] <= t) {
                return l;
            }
            return -1;
        }

        // return the left most index i such that a[i] >= t
        private static int leftMostLowerBound(Integer[] a, int t) {
            int l = 0, r = a.length - 1;
            while (l < r - 1) {
                int mid = l + (r - l) / 2;
                if (a[mid] >= t) {
                    r = mid;
                } else {
                    l = mid + 1;
                }
            }
            if (a[l] >= t) {
                return l;
            } else if (a[r] >= t) {
                return r;
            }
            return -1;
        }

        // Find the start and end index of a given t in a sorted(ascending) array; return [-1, -1] is t is not found
        private static int[] searchRange(Integer[] a, int t) {
            int first = firstPos(a, t);
            int last = firstPos(a, t + 1) - 1;
            if (first <= last) {
                return new int[]{first, last};
            }
            return new int[]{-1, -1};
        }

        private static int firstPos(Integer[] a, int t) {
            int first = a.length;
            int l = 0, r = a.length - 1;
            while (l <= r) {
                int mid = l + (r - l) / 2;
                if (a[mid] >= t) {
                    first = mid;
                    r = mid - 1;
                } else {
                    l = mid + 1;
                }
            }
            return first;
        }
    }

    private static class NumberTheory {
        private static long modularAdd(long a, long b, int mod) {
            long sum = a + b;
            if (sum >= mod) {
                sum -= mod;
            }
            return sum;
        }

        private static long modularSubtract(long a, long b, int mod) {
            long diff = a - b;
            if (diff < 0) {
                diff += mod;
            }
            return diff;
        }

        private static long fastModPow(long x, int n, long mod) {
            if (n == 0) {
                return 1;
            }
            long coeff = 1, base = x;
            while (n > 1) {
                if (n % 2 != 0) {
                    coeff = (coeff * base % mod);
                }
                base = (base * base % mod);
                n = n / 2;
            }
            long res = coeff * base % mod;
            return res;
        }

        private static long gcd(long a, long b) {
            if (b == 0) {
                return a;
            }
            return gcd(b, a % b);
        }

        private static long[] factorial(int n, long mod) {
            long[] factor = new long[n + 1];
            factor[0] = 1;
            for (int i = 1; i <= n; i++) {
                factor[i] = factor[i - 1] * i % mod;
            }
            return factor;
        }

        private static long modInv_EEA(long a, long mod) {
            long[] res = solveGcdEquation(a, mod);
            if (res[2] != 1) {
                // a and m are not coprime, modular inverse of a by m does not exist.
                return -1;
            }
            return (res[0] % mod + mod) % mod;
        }

        private static long[] solveGcdEquation(long a, long b) {
            if (b == 0) {
                return new long[]{1, 0, a};
            }
            long[] res = solveGcdEquation(b, a % b);
            return new long[]{res[1], res[0] - (a / b) * res[1], res[2]};
        }

        private static long binomialCoefficient(long[] factorial, long n, long k, long mod) {
            return factorial[(int) n] * modInv_EEA(factorial[(int) k], mod) % mod
                    * modInv_EEA(factorial[(int) (n - k)], mod) % mod;
        }
    }

    private static class Graph {
        private static int UNVISITED = 0;
        private static int VISITING = -1;
        private static int VISITED = 1;

        private static Stack<Integer> topologicalSort(Set<Integer>[] g) {
            Stack<Integer> stack = new Stack<>();
            int[] state = new int[g.length];

            for (int node = 0; node < g.length; node++) {
                if (!topoSortHelper(g, stack, state, node)) {
                    return null;
                }
            }
            return stack;
        }

        private static boolean topoSortHelper(Set<Integer>[] g, Stack<Integer> stack, int[] state, int currNode) {
            if (state[currNode] == VISITED) {
                return true;
            } else if (state[currNode] == VISITING) {
                return false;
            }
            state[currNode] = VISITING;
            for (int neighbor : g[currNode]) {
                if (!topoSortHelper(g, stack, state, neighbor)) {
                    return false;
                }
            }
            state[currNode] = VISITED;
            stack.push(currNode);
            return true;
        }
    }

    private static class FastScanner {
        BufferedReader br;
        StringTokenizer st;

        FastScanner(InputStream stream) {
            try {
                br = new BufferedReader(new InputStreamReader(stream));
            } catch (Exception e) {
                e.printStackTrace();
            }
        }

        String next() {
            while (st == null || !st.hasMoreTokens()) {
                try {
                    st = new StringTokenizer(br.readLine());
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
            return st.nextToken();
        }

        int nextInt() {
            return Integer.parseInt(next());
        }

        long nextLong() {
            return Long.parseLong(next());
        }

        double nextDouble() {
            return Double.parseDouble(next());
        }

        String nextLine() {
            String str = "";
            try {
                str = br.readLine();
            } catch (IOException e) {
                e.printStackTrace();
            }
            return str;
        }

        Integer[] nextIntArray(int n) {
            Integer[] a = new Integer[n];
            for (int i = 0; i < n; i++) {
                a[i] = nextInt();
            }
            return a;
        }

        Long[] nextLongArray(int n) {
            Long[] a = new Long[n];
            for (int i = 0; i < n; i++) {
                a[i] = nextLong();
            }
            return a;
        }
    }
}