Problem: One day Ms Swan bought an orange in a shop. The orange consisted of n·k segments, numbered with integers from 1 to n·k. 

There were k children waiting for Ms Swan at home. The children have recently learned about the orange and they decided to divide it between them. For that each child took a piece of paper and wrote the number of the segment that he would like to get: the i-th (1 ≤ i ≤ k) child wrote the number ai (1 ≤ ai ≤ n·k). All numbers ai accidentally turned out to be different.

Now the children wonder, how to divide the orange so as to meet these conditions:

  * each child gets exactly n orange segments; 
  * the i-th child gets the segment with number ai for sure; 
  * no segment goes to two children simultaneously. 



Help the children, divide the orange and fulfill the requirements, described above.

Input

The first line contains two integers n, k (1 ≤ n, k ≤ 30). The second line contains k space-separated integers a1, a2, ..., ak (1 ≤ ai ≤ n·k), where ai is the number of the orange segment that the i-th child would like to get.

It is guaranteed that all numbers ai are distinct.

Output

Print exactly n·k distinct integers. The first n integers represent the indexes of the segments the first child will get, the second n integers represent the indexes of the segments the second child will get, and so on. Separate the printed numbers with whitespaces.

You can print a child's segment indexes in any order. It is guaranteed that the answer always exists. If there are multiple correct answers, print any of them.

Examples

Input

2 2
4 1


Output

2 4 
1 3 


Input

3 1
2


Output

3 2 1 

Solution (in JAVA):

Solution:
import java.util.Arrays;
import java.util.LinkedList;
import java.util.Queue;
import java.util.Scanner;

public class divideOrange {
	static class pair {
		int id, slice;
		public pair(int id, int slice){
			this.id=id;
			this.slice=slice;
		}
	}
public static void main(String[] args) {
	Scanner sc=new Scanner(System.in); 	
	int n=sc.nextInt();
	int k=sc.nextInt();
	int [] orange=new int[n*k];
	Arrays.fill(orange, -1);
	int [] slices=new int[k];
	Queue<Integer> q=new LinkedList<Integer>();
	for (int i = 0; i < k; i++) {
		int wish=sc.nextInt();
		orange[wish-1]=i;
		slices[i]=wish;
	}
	for (int i = 0; i < orange.length; i++) {
		if(orange[i]!=-1)
			continue;
		q.add(i+1);
	}
	int kk=0;//System.out.println(q.size());
//	System.out.println(q.toString());
	if(n==1)
	{
		while(kk<k)
		System.out.println(slices[kk++]);
	}else
	while(!q.isEmpty()){
		int count=1;
		System.out.print(slices[kk++]+" ");
		while(count++<n){
			System.out.print(q.remove()+" ");
		}
//	
System.out.println();		
	}
}
}