Problem: We have a secret array. You don't know this array and you have to restore it. However, you know some facts about this array:

  * The array consists of n distinct positive (greater than 0) integers. 
  * The array contains two elements x and y (these elements are known for you) such that x < y. 
  * If you sort the array in increasing order (such that a_1 < a_2 < … < a_n), differences between all adjacent (consecutive) elements are equal (i.e. a_2 - a_1 = a_3 - a_2 = … = a_n - a_{n-1}). 



It can be proven that such an array always exists under the constraints given below.

Among all possible arrays that satisfy the given conditions, we ask you to restore one which has the minimum possible maximum element. In other words, you have to minimize max(a_1, a_2, ..., a_n).

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers n, x and y (2 ≤ n ≤ 50; 1 ≤ x < y ≤ 50) — the length of the array and two elements that are present in the array, respectively.

Output

For each test case, print the answer: n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9), where a_i is the i-th element of the required array. If there are several answers, you can print any (it also means that the order of elements doesn't matter).

It can be proven that such an array always exists under the given constraints.

Example

Input


5
2 1 49
5 20 50
6 20 50
5 3 8
9 13 22


Output


1 49 
20 40 30 50 10
26 32 20 38 44 50 
8 23 18 13 3 
1 10 13 4 19 22 25 16 7 

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.lang.reflect.Array;
import java.math.BigInteger;
import java.text.DateFormat;
import java.text.Format;
import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.time.LocalDateTime;
import java.util.*;
import java.io.*;
import java.math.*;
import java.security.*;
import java.text.*;
import java.util.*;
import java.util.concurrent.*;
import java.util.function.*;
import java.util.regex.*;
import java.util.stream.*;
import static java.util.stream.Collectors.joining;
import static java.util.stream.Collectors.toList;

public class file {



    private static final Scanner sc = new Scanner(System.in);
    private static String s;
    private static int[] arr;
    private static HashSet<Long> set;
    private static HashMap<Character, Integer> cmap;
    private static Map<Long, Long> Lmap;
    private static Map<Integer, Integer> map;
    private static Stack<Integer> stk;
    private static ArrayList<Integer>[] graph;
    private static boolean[] visited;
    private static ArrayList<Integer> list;
    private static ArrayList<Long> Llist;

    private static final int MOD = 1000000007;

    //find max of array
    private static int findMax(int[] arr) {
        int max = Integer.MIN_VALUE;
        for (int x : arr) {
            max = Math.max(x, max);
        }
        return max;
    }

    // print an array
    private static void printArray(int[] arr) {
        for (int x : arr) {
            System.out.print(x + " ");
        }
        System.out.println();
    }

    //DFS
    private static int dfs(int curr, int prev) {
        int count = 1;
        for (int next : graph[curr]) {
            if (next==prev) continue;
            long new_count = dfs(next, curr);
            Llist.add(new_count* (graph.length - new_count));
            count += new_count;
        }
        return count;
    }

    private static int min_index(int first, int last) {
        int ind = 0, min = Integer.MAX_VALUE;
        for (int i = first; i <= last; i++) {
            if (arr[i] < min) {
                min = arr[i];
                ind = i;
            }
        }
        return ind;
    }

    private static long recurse(int first, int last) {
        int ind = min_index(first, last);
        int min = arr[ind];
        if (first > last) {
            return 0;
        } else {
            return Math.min(last-first + 1, recurse(first, ind - 1) + recurse(ind + 1, last) + min - Math.max(arr[first - 1], arr[last + 1]));
        }
    }

    private static boolean contains(int[] arr, int x, int y) {
        boolean a = false, b = false;
        for (int i = 0; i < arr.length; i++) {
            if (arr[i] == x) a = true;
            if (arr[i] == y) b = true;
        }
        return (a && b);
    }

    private static void foo(int testCase) {
        int n = sc.nextInt();
        int x = sc.nextInt();
        int y = sc.nextInt();
        int[] arr = new int[n];
        for (int i = 1; i < 51; i++) {
            for (int j = 1; j < 51; j++) {
                for (int k = 0; k < n; k++) {
                    arr[k] = j + k*i;
                }
                if (contains(arr, x, y)) {
                    printArray(arr);
                    return;
                }
            }
        }

    }



    public static void main(String[] args) throws IOException {
        //foo(0);
        ///*
        int t = sc.nextInt();
        for (int i = 0; i < t; i++) {
            foo(i);
        }
        //*/

    }
}