Problem: You are given an image A composed of N rows and N columns of pixels, and a template image B composed of M rows and M columns of pixels.
A pixel is the smallest element of an image, and in this problem it is a square of size 1×1.
Also, the given images are binary images, and the color of each pixel is either white or black.

In the input, every pixel is represented by a character: `.` corresponds to a white pixel, and `#` corresponds to a black pixel.
The image A is given as N strings A_1,...,A_N.
The j-th character in the string A_i corresponds to the pixel at the i-th row and j-th column of the image A (1≦i,j≦N).
Similarly, the template image B is given as M strings B_1,...,B_M.
The j-th character in the string B_i corresponds to the pixel at the i-th row and j-th column of the template image B (1≦i,j≦M).

Determine whether the template image B is contained in the image A when only parallel shifts can be applied to the images.

Constraints

* 1≦M≦N≦50
* A_i is a string of length N consisting of `#` and `.`.
* B_i is a string of length M consisting of `#` and `.`.

Input

The input is given from Standard Input in the following format:


N M
A_1
A_2
:
A_N
B_1
B_2
:
B_M


Output

Print `Yes` if the template image B is contained in the image A. Print `No` otherwise.

Examples

Input

3 2
#.#
.#.
#.#
#.
.#


Output

Yes


Input

3 2
.#
.#.
.#
.
.#


Output

Yes


Input

4 1
....
....
....
....


Output

No

Solution (in JAVA):

Solution:


import java.util.Scanner;

public class Main {

	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);

		int n = sc.nextInt();
		int m = sc.nextInt();

		String image[] = new String[n];
		for(int i = 0; i < n; i++){
			image[i] = sc.next();
		}

		String template[] = new String[m];
		for(int i = 0; i < m; i++){
			template[i] = sc.next();
		}

//		int count = 0;
		for(int i = 0; i < n - m + 1 ; i++){
			for(int j = 0; j < n - m + 1; j++){
//				System.out.println("i = "+i+" j = "+j);
				boolean same = true;
				for(int k = 0; k < m; k++){
//					System.out.println(template[k] + " " +image[i + k].substring(j, j + m));
					if(!template[k].equals(image[i + k].substring(j, j + m))){
						same = false;
						break;
					}
				}

				if(same){
//					count++;
					System.out.println("Yes");
					return;
				}
			}
		}

		System.out.println("No");

//		System.out.println(count);
    }
}