Problem: You are given a string t consisting of n lowercase Latin letters and an integer number k.

Let's define a substring of some string s with indices from l to r as s[l ... r].

Your task is to construct such string s of minimum possible length that there are exactly k positions i such that s[i ... i + n - 1] = t. In other words, your task is to construct such string s of minimum possible length that there are exactly k substrings of s equal to t.

It is guaranteed that the answer is always unique.

Input

The first line of the input contains two integers n and k (1 ≤ n, k ≤ 50) — the length of the string t and the number of substrings.

The second line of the input contains the string t consisting of exactly n lowercase Latin letters.

Output

Print such string s of minimum possible length that there are exactly k substrings of s equal to t.

It is guaranteed that the answer is always unique.

Examples

Input

3 4
aba


Output

ababababa


Input

3 2
cat


Output

catcat

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
int main() {
  ios_base::sync_with_stdio(false);
  cin.tie(0);
  int n, k;
  string s;
  cin >> n >> k >> s;
  int mxlen = 0;
  for (int i = 1; i < n; ++i) {
    string c = s.substr(0, n - i);
    int m = int(c.size());
    bool ok = true;
    for (int j = 0; j < m; ++j) {
      ok &= (c[j] == s[i + j]);
    }
    if (ok) {
      mxlen = n - i;
      break;
    }
  }
  string ans = "";
  string cp = s.substr(0, n - mxlen);
  for (int i = 0; i < k - 1; ++i) {
    ans += cp;
  }
  ans += s;
  cout << ans << '\n';
  return 0;
}