Problem: Petya loves lucky numbers. Everybody knows that positive integers are lucky if their decimal representation doesn't contain digits other than 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.

Lucky number is super lucky if it's decimal representation contains equal amount of digits 4 and 7. For example, numbers 47, 7744, 474477 are super lucky and 4, 744, 467 are not.

One day Petya came across a positive integer n. Help him to find the least super lucky number which is not less than n.

Input

The only line contains a positive integer n (1 ≤ n ≤ 10100000). This number doesn't have leading zeroes.

Output

Output the least super lucky number that is more than or equal to n.

Examples

Input

4500


Output

4747


Input

47


Output

47

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

public class C2 {
    static String inp;
    static char [] result;
    public static StringBuffer call1(int len) {
        StringBuffer res = new StringBuffer("");
        for (int i = 0; i < len; i++) {
            if (i < len / 2)
                res = res.append('4');
            else
                res = res.append('7');
        }
        return res;
    }

    public static boolean call2(int i, int num, boolean flag) {
        if (i == inp.length() && num == 0)
            return true;
        if(i == inp.length())
            return false;
        if(flag){
            if(num==0){
                result[i] = '7';
                return call2(i+1,num,flag);
            }else{
                result[i] = '4';
                return call2(i+1,num-1,flag);
            }
        }else{
            int curr = inp.charAt(i)-'0';
            if(curr>7)
                return false;
            else if(curr == 7){
                result[i] = '7';
                return call2(i+1,num,false);
            }else if(curr>4){
                result[i] = '7';
                return call2(i+1,num,true);
            }else if(curr==4){
                if(call2(i+1,num-1,false)){
                    result[i] = '4';
                    return true;
                }else{
                    result[i] = '7';
                    return call2(i+1,num,true);
                }
            }else{
                result[i]= '4';
                return call2(i+1,num-1,true);
            }
        }
    }

    public static void main(String[] args) throws IOException {
        BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
        inp = in.readLine();
        result = new char[inp.length()];
        if (inp.length() % 2 == 1)
            System.out.println(call1(inp.length() + 1));
        else {
            if (call2(0, inp.length() / 2, false))
                System.out.println(new String(result));
            else
                System.out.println(call1(inp.length()+2));
        }
    }
}