Problem: Notes

Template in C

Constraints

* 1 ≤ n ≤ 100000
* 1 ≤ q ≤ 1000
* 1 ≤ timei ≤ 50000
* 1 ≤ length of namei ≤ 10
* 1 ≤ Sum of timei ≤ 1000000

Input

n q
name1 time1
name2 time2
...
namen timen


In the first line the number of processes n and the quantum q are given separated by a single space.

In the following n lines, names and times for the n processes are given. namei and timei are separated by a single space.

Output

For each process, prints its name and the time the process finished in order.

Example

Input

5 100
p1 150
p2 80
p3 200
p4 350
p5 20


Output

p2 180
p5 400
p1 450
p3 550
p4 800

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.*;
import java.lang.*;

class Main{
  public static void main(String[] args) throws IOException{
    Scanner scan=new Scanner(System.in);
    int n=Integer.parseInt(scan.next());
    int q=Integer.parseInt(scan.next());
    int sumTime=0;
    Queue<Process> queue=new ArrayDeque<Process>();

    for(int i=0;i<n;i++){
      String namae=scan.next();
      int Time=Integer.parseInt(scan.next());
      queue.add(new Process(namae,Time));
    }

    Queue<Process> ans=new ArrayDeque<>();
    while(!queue.isEmpty()){
      Process buf=queue.remove();
      if(buf.pTime-q<=0){
        int buf2=buf.pTime;
        buf.pTime+=sumTime;
        sumTime+=buf2;
        ans.add(buf);
      }else {
        buf.pTime-=q;
        queue.add(buf);
        sumTime+=q;
      }
    }
    for(Process p:ans){
      System.out.println(p.name+" "+p.pTime);
    }
  }
}
class Process{
  String name;
  int pTime;

  public Process(String name,int pTime){
    this.name=name;
    this.pTime=pTime;
  }
}