Problem: One day Ms Swan bought an orange in a shop. The orange consisted of n·k segments, numbered with integers from 1 to n·k. 

There were k children waiting for Ms Swan at home. The children have recently learned about the orange and they decided to divide it between them. For that each child took a piece of paper and wrote the number of the segment that he would like to get: the i-th (1 ≤ i ≤ k) child wrote the number ai (1 ≤ ai ≤ n·k). All numbers ai accidentally turned out to be different.

Now the children wonder, how to divide the orange so as to meet these conditions:

  * each child gets exactly n orange segments; 
  * the i-th child gets the segment with number ai for sure; 
  * no segment goes to two children simultaneously. 



Help the children, divide the orange and fulfill the requirements, described above.

Input

The first line contains two integers n, k (1 ≤ n, k ≤ 30). The second line contains k space-separated integers a1, a2, ..., ak (1 ≤ ai ≤ n·k), where ai is the number of the orange segment that the i-th child would like to get.

It is guaranteed that all numbers ai are distinct.

Output

Print exactly n·k distinct integers. The first n integers represent the indexes of the segments the first child will get, the second n integers represent the indexes of the segments the second child will get, and so on. Separate the printed numbers with whitespaces.

You can print a child's segment indexes in any order. It is guaranteed that the answer always exists. If there are multiple correct answers, print any of them.

Examples

Input

2 2
4 1


Output

2 4 
1 3 


Input

3 1
2


Output

3 2 1 

Solution (in JAVA):

Solution:
//package C_150;

import java.util.Scanner;

public class Q1 {
	public static void main(String[] arsd){
		Scanner s=new Scanner(System.in);
		int n=s.nextInt();
		int k=s.nextInt();
		boolean[] req=new boolean[n*k+1];
		int[] a=new int[k+1];
		for(int i=1;i<=k;i++){
			a[i]=s.nextInt();
			req[a[i]]=true;
		}
		int p=1;
		int[][] ans=new int[k+1][n+1];
		for(int i=1;i<=k;i++){
			ans[i][1]=a[i];
			int j=2;
			while(j<=n){
				if(!req[p]){
					ans[i][j]=p;
					j++;
					req[p]=true;
				}
				p++;
			}
		}
		for(int i=1;i<=k;i++){
			for(int j=1;j<=n;j++){
				System.out.print(ans[i][j]+" ");
			}
			System.out.println();
		}
	}
}