Problem: There are n digital panels placed in a straight line. Each panel can show any digit from 0 to 9. Initially, all panels show 0.

Every second, the digit shown by each panel increases by 1. In other words, at the end of every second, a panel that showed 9 would now show 0, a panel that showed 0 would now show 1, a panel that showed 1 would now show 2, and so on.

When a panel is paused, the digit displayed on the panel does not change in the subsequent seconds.

You must pause exactly one of these panels, at any second you wish. Then, the panels adjacent to it get paused one second later, the panels adjacent to those get paused 2 seconds later, and so on. In other words, if you pause panel x, panel y (for all valid y) would be paused exactly |x−y| seconds later.

For example, suppose there are 4 panels, and the 3-rd panel is paused when the digit 9 is on it.

  * The panel 1 pauses 2 seconds later, so it has the digit 1; 
  * the panel 2 pauses 1 second later, so it has the digit 0; 
  * the panel 4 pauses 1 second later, so it has the digit 0. 



The resulting 4-digit number is 1090. Note that this example is not optimal for n = 4.

Once all panels have been paused, you write the digits displayed on them from left to right, to form an n digit number (it can consist of leading zeros). What is the largest possible number you can get? Initially, all panels show 0.

Input

The first line of the input contains a single integer t (1 ≤ t ≤ 100) — the number of test cases. Each test case consists of a single line containing a single integer n (1 ≤ n ≤ 2⋅10^5).

It is guaranteed that the sum of n over all test cases does not exceed 2⋅10^5.

Output

For each test case, print the largest number you can achieve, if you pause one panel optimally.

Example

Input


2
1
2


Output


9
98

Note

In the first test case, it is optimal to pause the first panel when the number 9 is displayed on it.

In the second test case, it is optimal to pause the second panel when the number 8 is displayed on it.

Solution (in JAVA):

Solution:
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.util.StringTokenizer;
import java.io.BufferedReader;
import java.util.*;
 
public class wizardOfOrz {
	private static final FastReader fs = new FastReader();
	private static final PrintWriter out = new PrintWriter(System.out);
 
	private static void solve() {
		int n = fs.nextInt();
		if(n == 1) {
			out.println(9);
		}
		else {
			out.print(98);
			int num = 8;
			for(int i = 3; i<=n; i++) {
				num = (num + 1)%10;
				out.print(num);
			}
			out.println();
		}
	}
 
	public static void main(String[] args) {
		Thread t = new Thread(null, null, "", 1 << 28) {
			public void run() {
				int test_case = 1;
				test_case = fs.nextInt();
				for (int cs = 1; cs <= test_case; cs++) {
					solve();
				}
				out.close();
			}
		};
		t.start();
		try {
			t.join();
		} catch (InterruptedException e) {
			e.printStackTrace();
		}
	}
 
	private static class FastReader {
		BufferedReader br;
		StringTokenizer st;
 
		public FastReader() {
			br = new BufferedReader(new InputStreamReader(System.in));
		}
 
		String next() {
			while (st == null || !st.hasMoreElements()) {
				try {
					st = new StringTokenizer(br.readLine());
				} catch (IOException e) {
					e.printStackTrace();
				}
			}
			return st.nextToken();
		}
 
		int nextInt() {
			return Integer.parseInt(next());
		}
 
		long nextLong() {
			return Long.parseLong(next());
		}
 
		double nextDouble() {
			return Double.parseDouble(next());
		}
 
		String nextLine() {
			String str = "";
			try {
				str = br.readLine();
			} catch (IOException e) {
				e.printStackTrace();
			}
			return str;
		}
 
		int[] readintarray(int n) {
			int res[] = new int[n];
			for (int i = 0; i < n; i++)
				res[i] = nextInt();
			return res;
		}
 
		long[] readlongarray(int n) {
			long res[] = new long[n];
			for (int i = 0; i < n; i++)
				res[i] = nextLong();
			return res;
		}
	}
 
	public static class pair<T1 extends Comparable<T1>, T2 extends Comparable<T2>> implements Comparable<pair<T1, T2>> {
		T1 ff;
		T2 ss;
 
		public pair(T1 ff, T2 ss) {
			this.ff = ff;
			this.ss = ss;
		}
 
		public int compareTo(pair<T1, T2> o) {
			if (ff == o.ff)
				return ss.compareTo(o.ss);
			return ff.compareTo(o.ff);
		}
	}
 
	private static class cf {
		public static long power(long base, long exponent) {
			long res = 1;
			while (exponent > 0) {
				if (exponent % 2 == 1)
					res *= base;
				exponent >>= 1;
				base *= base;
			}
			return res;
		}
 
		public static long mul(long a, long b, long mod) {
			return (a % mod * b % mod) % mod;
		}
 
		public static long add(long a, long b, long mod) {
			return (a % mod + b % mod) % mod;
		}
 
		public static long sub(long a, long b, long mod) {
			return ((a % mod - b % mod) % mod + mod) % mod;
		}
 
		public static long power(long base, long exponent, long mod) {
			long res = 1;
			base %= mod;
			while (exponent > 0) {
				if (exponent % 2 == 1)
					res = mul(res, base, mod);
				exponent >>= 1;
				base = mul(base, base, mod);
			}
			return res;
		}
 
		public static void sortIntArray(int[] a) {
			ArrayList<Integer> tmp = new ArrayList<>();
			for (int x : a)
				tmp.add(x);
			Collections.sort(tmp);
			for (int i = 0; i < tmp.size(); i++)
				a[i] = tmp.get(i);
		}
 
		public static void sortLongArray(long[] a) {
			ArrayList<Long> tmp = new ArrayList<>();
			for (long x : a)
				tmp.add(x);
			Collections.sort(tmp);
			for (int i = 0; i < tmp.size(); i++)
				a[i] = tmp.get(i);
		}
 
		public static <T extends Comparable<T>> void sort(T[] a) {
			ArrayList<T> tmp = new ArrayList<>();
			for (T x : a)
				tmp.add(x);
			Collections.sort(tmp);
			for (int i = 0; i < tmp.size(); i++)
				a[i] = tmp.get(i);
		}
 
		public static int __gcd(int a, int b) {
			return b == 0 ? a : __gcd(b, a % b);
		}
 
		public static long __gcd(long a, long b) {
			return b == 0 ? a : __gcd(b, a % b);
		}
 
		public static int max(int[] a) {
			int mx = a[0];
			for (int ele : a) {
				mx = Math.max(mx, ele);
			}
			return mx;
		}
 
		public static long max(long[] a) {
			long mx = a[0];
			for (long ele : a) {
				mx = Math.max(mx, ele);
			}
			return mx;
		}
 
		public static int min(int[] a) {
			int mn = a[0];
			for (int ele : a) {
				mn = Math.min(mn, ele);
			}
			return mn;
		}
 
		public static long min(long[] a) {
			long mn = a[0];
			for (long ele : a) {
				mn = Math.min(mn, ele);
			}
			return mn;
		}
	}
}