Problem: One day Ms Swan bought an orange in a shop. The orange consisted of n·k segments, numbered with integers from 1 to n·k. 

There were k children waiting for Ms Swan at home. The children have recently learned about the orange and they decided to divide it between them. For that each child took a piece of paper and wrote the number of the segment that he would like to get: the i-th (1 ≤ i ≤ k) child wrote the number ai (1 ≤ ai ≤ n·k). All numbers ai accidentally turned out to be different.

Now the children wonder, how to divide the orange so as to meet these conditions:

  * each child gets exactly n orange segments; 
  * the i-th child gets the segment with number ai for sure; 
  * no segment goes to two children simultaneously. 



Help the children, divide the orange and fulfill the requirements, described above.

Input

The first line contains two integers n, k (1 ≤ n, k ≤ 30). The second line contains k space-separated integers a1, a2, ..., ak (1 ≤ ai ≤ n·k), where ai is the number of the orange segment that the i-th child would like to get.

It is guaranteed that all numbers ai are distinct.

Output

Print exactly n·k distinct integers. The first n integers represent the indexes of the segments the first child will get, the second n integers represent the indexes of the segments the second child will get, and so on. Separate the printed numbers with whitespaces.

You can print a child's segment indexes in any order. It is guaranteed that the answer always exists. If there are multiple correct answers, print any of them.

Examples

Input

2 2
4 1


Output

2 4 
1 3 


Input

3 1
2


Output

3 2 1 

Solution (in JAVA):

Solution:

import java.util.Arrays;
import java.util.Scanner;

public class A244 {

    public static void main(String[] args) {
        Scanner I = new Scanner(System.in);
        int n = I.nextInt();
        int k = I.nextInt();
        int a[] = new int[k];
        int t = n * k;
        boolean f[] = new boolean[t+1];
        String s[] = new String[k];
        Arrays.fill(s,"");
        
        for (int i = 0; i < k; i++) {
            a[i] = I.nextInt();
        }
        I.close();
        for (int i = 0; i < k; i++) {
            s[i] += a[i] + " ";
            f[a[i]] = true;
            t--;
        }
        while(t>0){
        for(int i=0;i<k;i++){
            for(int j=1;j<f.length;j++){
                if(f[j]==false){
                    f[j]=true;
                    s[i]+=j+" ";
                    t--;
                    break;
                }
            }           
        }}
        for(String ss:s){
            System.out.println(ss);
        }

    }

}