Problem: One day Ms Swan bought an orange in a shop. The orange consisted of n·k segments, numbered with integers from 1 to n·k. 

There were k children waiting for Ms Swan at home. The children have recently learned about the orange and they decided to divide it between them. For that each child took a piece of paper and wrote the number of the segment that he would like to get: the i-th (1 ≤ i ≤ k) child wrote the number ai (1 ≤ ai ≤ n·k). All numbers ai accidentally turned out to be different.

Now the children wonder, how to divide the orange so as to meet these conditions:

  * each child gets exactly n orange segments; 
  * the i-th child gets the segment with number ai for sure; 
  * no segment goes to two children simultaneously. 



Help the children, divide the orange and fulfill the requirements, described above.

Input

The first line contains two integers n, k (1 ≤ n, k ≤ 30). The second line contains k space-separated integers a1, a2, ..., ak (1 ≤ ai ≤ n·k), where ai is the number of the orange segment that the i-th child would like to get.

It is guaranteed that all numbers ai are distinct.

Output

Print exactly n·k distinct integers. The first n integers represent the indexes of the segments the first child will get, the second n integers represent the indexes of the segments the second child will get, and so on. Separate the printed numbers with whitespaces.

You can print a child's segment indexes in any order. It is guaranteed that the answer always exists. If there are multiple correct answers, print any of them.

Examples

Input

2 2
4 1


Output

2 4 
1 3 


Input

3 1
2


Output

3 2 1 

Solution (in JAVA):

Solution:
import java.util.*;
import java.io.*;
/*

 */
public class b
{
	public static void main(String[] arg) throws Exception
	{
		new b();
	}
	public b() throws Exception
	{
		FastScanner in = new FastScanner(System.in);
		PrintWriter out = new PrintWriter(System.out);
		int n = in.nextInt();
		int k = in.nextInt();
		TreeSet<Integer> ts = new TreeSet<Integer>();
		for(int i = 1; i <= n*k; i++) ts.add(i);
		int[] vs = new int[k];
		for(int i = 0; i < k; i++)
		{
			vs[i] = in.nextInt();
			ts.remove(vs[i]);
		}
		for(int i = 0; i < k; i++)
		{
			out.print(vs[i]);
			for(int j = 0; j < n-1; j++)
			{
				out.print(' ');
				out.print(ts.first());
				ts.remove(ts.first());
			}
			out.println();
		}
		in.close(); out.close();
	}

	class FastScanner
	{
		BufferedReader br;
		StringTokenizer st;
		public FastScanner(InputStream in)
		{
			br = new BufferedReader(new InputStreamReader(in));
			st = new StringTokenizer("");
		}
		public String next() throws IOException
		{
			while(!st.hasMoreTokens()) st = new StringTokenizer(br.readLine());
			return st.nextToken();
		}
		public int nextInt() throws IOException
		{
			return Integer.parseInt(next());
		}
		public void close() throws IOException
		{
			br.close();
		}
		public long nextLong() throws IOException
		{
			return Long.parseLong(next());
		}
		public double nextDouble() throws IOException
		{
			return Double.parseDouble(next());
		}
	}
}