Problem: One day Ms Swan bought an orange in a shop. The orange consisted of n·k segments, numbered with integers from 1 to n·k. 

There were k children waiting for Ms Swan at home. The children have recently learned about the orange and they decided to divide it between them. For that each child took a piece of paper and wrote the number of the segment that he would like to get: the i-th (1 ≤ i ≤ k) child wrote the number ai (1 ≤ ai ≤ n·k). All numbers ai accidentally turned out to be different.

Now the children wonder, how to divide the orange so as to meet these conditions:

  * each child gets exactly n orange segments; 
  * the i-th child gets the segment with number ai for sure; 
  * no segment goes to two children simultaneously. 



Help the children, divide the orange and fulfill the requirements, described above.

Input

The first line contains two integers n, k (1 ≤ n, k ≤ 30). The second line contains k space-separated integers a1, a2, ..., ak (1 ≤ ai ≤ n·k), where ai is the number of the orange segment that the i-th child would like to get.

It is guaranteed that all numbers ai are distinct.

Output

Print exactly n·k distinct integers. The first n integers represent the indexes of the segments the first child will get, the second n integers represent the indexes of the segments the second child will get, and so on. Separate the printed numbers with whitespaces.

You can print a child's segment indexes in any order. It is guaranteed that the answer always exists. If there are multiple correct answers, print any of them.

Examples

Input

2 2
4 1


Output

2 4 
1 3 


Input

3 1
2


Output

3 2 1 

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.*;

public class Main {
    public static void main(String[] args) throws IOException {
        InputReader in = new InputReader();
        PrintWriter out = new PrintWriter(System.out);
        int test_cases = 1;
        Solver s = new Solver();
        for (int i = 1; i <= test_cases; i++) {
            s.solve(i, in, out);
        }
        out.close();
    }
}

class Solver {
    void solve(int test_number, InputReader in, PrintWriter out) throws IOException {
        int n = in.nextInt();
        int k = in.nextInt();
        boolean[] taken = new boolean[n * k + 1];
        @SuppressWarnings("unchecked")
        HashSet<Integer>[] s = new HashSet[k];
        for (int i = 0; i < k; i++) {
            s[i] = new HashSet<>();
        }
        for (int i = 0; i < k; i++) {
            int x = in.nextInt();
            taken[x] = true;
            s[i].add(x);
        }
        for (int i = 0; i < k; i++) {
            for (int j = 1; j <= n * k && s[i].size() < n; j++) {
                if (!s[i].contains(j) && !taken[j]) {
                    taken[j] = true;
                    s[i].add(j);
                }
            }
            for (Integer x : s[i]) out.print(x + " ");
            out.println();
        }
    }
}


class InputReader {
    BufferedReader br;
    StringTokenizer st;

    public InputReader()
    {
        br = new BufferedReader(new
                InputStreamReader(System.in));
    }

    String next()
    {
        while (st == null || !st.hasMoreElements())
        {
            try
            {
                st = new StringTokenizer(br.readLine());
            }
            catch (IOException  e)
            {
                e.printStackTrace();
            }
        }
        return st.nextToken();
    }

    int nextInt()
    {
        return Integer.parseInt(next());
    }

    long nextLong()
    {
        return Long.parseLong(next());
    }

    double nextDouble()
    {
        return Double.parseDouble(next());
    }

    String nextLine()
    {
        String str = "";
        try
        {
            str = br.readLine();
        }
        catch (IOException e)
        {
            e.printStackTrace();
        }
        return str;
    }
}