Problem: Notes

Template in C

Constraints

* 1 ≤ n ≤ 100000
* 1 ≤ q ≤ 1000
* 1 ≤ timei ≤ 50000
* 1 ≤ length of namei ≤ 10
* 1 ≤ Sum of timei ≤ 1000000

Input

n q
name1 time1
name2 time2
...
namen timen


In the first line the number of processes n and the quantum q are given separated by a single space.

In the following n lines, names and times for the n processes are given. namei and timei are separated by a single space.

Output

For each process, prints its name and the time the process finished in order.

Example

Input

5 100
p1 150
p2 80
p3 200
p4 350
p5 20


Output

p2 180
p5 400
p1 450
p3 550
p4 800

Solution (in PYTHON):

Solution:
import sys

def isEmpty(S):
  if len(S) == 0:
    return True

def isFull(S):
  if len(S) >= 100000:
    return True

def enqueue(x):
  if isFull(x_list_list):
    print 'Error'
  x_list_list.append(x)

def dequeue(x_list_list):
  if isEmpty(x_list_list):
    print 'Error'
  del_list = x_list_list[0]
  x_list_list.pop(0)
  return(del_list)

y = sys.stdin.readline()
a, b = y.split(" ")
a = int(a)
b = int(b)

S = []
x_list_list = []
run_time = 0

for i in range(a):
  text = raw_input()
  x_list = text.split()
  x_list[1] = int(x_list[1])
  x_list.append(0)
  x_list_list.append(x_list)

flag = a
while flag != 0:
  if x_list_list[0][1] > b:
    x_list_list[0][1] -= int(b)
    run_time += b
    del_list = dequeue(x_list_list)
    enqueue(del_list)
  else:
    run_time += x_list_list[0][1]
    x_list_list[0][2] = run_time
    x_list_list[0][1] = 0
    flag -= 1
    print x_list_list[0][0],x_list_list[0][2]
    dequeue(x_list_list)