Problem: One day Ms Swan bought an orange in a shop. The orange consisted of n·k segments, numbered with integers from 1 to n·k. 

There were k children waiting for Ms Swan at home. The children have recently learned about the orange and they decided to divide it between them. For that each child took a piece of paper and wrote the number of the segment that he would like to get: the i-th (1 ≤ i ≤ k) child wrote the number ai (1 ≤ ai ≤ n·k). All numbers ai accidentally turned out to be different.

Now the children wonder, how to divide the orange so as to meet these conditions:

  * each child gets exactly n orange segments; 
  * the i-th child gets the segment with number ai for sure; 
  * no segment goes to two children simultaneously. 



Help the children, divide the orange and fulfill the requirements, described above.

Input

The first line contains two integers n, k (1 ≤ n, k ≤ 30). The second line contains k space-separated integers a1, a2, ..., ak (1 ≤ ai ≤ n·k), where ai is the number of the orange segment that the i-th child would like to get.

It is guaranteed that all numbers ai are distinct.

Output

Print exactly n·k distinct integers. The first n integers represent the indexes of the segments the first child will get, the second n integers represent the indexes of the segments the second child will get, and so on. Separate the printed numbers with whitespaces.

You can print a child's segment indexes in any order. It is guaranteed that the answer always exists. If there are multiple correct answers, print any of them.

Examples

Input

2 2
4 1


Output

2 4 
1 3 


Input

3 1
2


Output

3 2 1 

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.OutputStreamWriter;
import java.io.PrintWriter;
import java.util.Locale;
import java.util.StringTokenizer;

public class CFA {

    BufferedReader in;
    StringTokenizer st;
    PrintWriter out;

    public static void main(String[] args) {
        CFA t = new CFA();
        t.init();
    }

    void run() throws Exception {
        int n = Int();
        int k = Int();
        int[] c = IntArray(k);
        boolean[] array = new boolean[n * k];

        for (int i = 0; i < c.length; i++) {
            array[c[i] - 1] = true;
        }

        int s = 0;
        for (int i = 0; i < c.length; i++) {
            StringBuilder sb = new StringBuilder();
            sb.append(c[i]);
            int x = n - 1;
            while (x > 0) {
                if (!array[s]) {
                    sb.append(" " + (s + 1));
                    x--;
                }
                s++;
            }
            PrintLn(sb);
        }
    }

    void init() {
        try {
            Locale.setDefault(Locale.US);
            in = new BufferedReader(new InputStreamReader(System.in));
            out = new PrintWriter(new OutputStreamWriter(System.out));
            run();
            out.close();
        } catch (Exception e) {
            e.printStackTrace();
            System.exit(1);
        }
    }

    String next() throws IOException {
        while (st == null || !st.hasMoreTokens()) {
            st = new StringTokenizer(in.readLine());
        }
        return st.nextToken();
    }

    String String() throws Exception {
        return next();
    }

    int Int() throws Exception {
        return Integer.parseInt(next());
    }

    int[] IntArray(int n) throws Exception {
        int[] array = new int[n];
        for (int i = 0; i < array.length; i++) {
            array[i] = Int();
        }
        return array;
    }

    void PrintLn(Object line) {
        out.println(line);
    }
}