Problem: One day Ms Swan bought an orange in a shop. The orange consisted of n·k segments, numbered with integers from 1 to n·k. 

There were k children waiting for Ms Swan at home. The children have recently learned about the orange and they decided to divide it between them. For that each child took a piece of paper and wrote the number of the segment that he would like to get: the i-th (1 ≤ i ≤ k) child wrote the number ai (1 ≤ ai ≤ n·k). All numbers ai accidentally turned out to be different.

Now the children wonder, how to divide the orange so as to meet these conditions:

  * each child gets exactly n orange segments; 
  * the i-th child gets the segment with number ai for sure; 
  * no segment goes to two children simultaneously. 



Help the children, divide the orange and fulfill the requirements, described above.

Input

The first line contains two integers n, k (1 ≤ n, k ≤ 30). The second line contains k space-separated integers a1, a2, ..., ak (1 ≤ ai ≤ n·k), where ai is the number of the orange segment that the i-th child would like to get.

It is guaranteed that all numbers ai are distinct.

Output

Print exactly n·k distinct integers. The first n integers represent the indexes of the segments the first child will get, the second n integers represent the indexes of the segments the second child will get, and so on. Separate the printed numbers with whitespaces.

You can print a child's segment indexes in any order. It is guaranteed that the answer always exists. If there are multiple correct answers, print any of them.

Examples

Input

2 2
4 1


Output

2 4 
1 3 


Input

3 1
2


Output

3 2 1 

Solution (in JAVA):

Solution:

import java.util.*;

public class Main
{
    

    public static void main(String[] args)
    {
        Scanner input = new Scanner(System.in);
        int n = input.nextInt();
        int k = input.nextInt();
        int a[] = new int[n*k];
        for (int i = 0; i <n*k; i++) {
            a[i] = i+1;
        }
        String ans[] = new String[k];
//        System.out.println(Arrays.toString(a));
        int student[]= new int[k];
        for (int i = 0; i < k; i++) {
            student[i] = input.nextInt()-1;
            ans[i]=(student[i]+1)+"";
            a[student[i]]=-1;
        }
        for (int i = 0; i < k; i++) {
            int count= n-1;
            int j=0;
            while(j<n*k&&count>0)
            {
                
                
                if(a[j]!=-1)
                {
                    ans[i]+=" "+a[j];
                    a[j]=-1;
                    count--;
                }
                j++;
                
            }
        }
//        System.out.println(Arrays.toString(a));
//        System.out.println(Arrays.toString(ans));
for (String an : ans) {
            System.out.println(an);
        }
    }

}