Problem: One day Ms Swan bought an orange in a shop. The orange consisted of n·k segments, numbered with integers from 1 to n·k. 

There were k children waiting for Ms Swan at home. The children have recently learned about the orange and they decided to divide it between them. For that each child took a piece of paper and wrote the number of the segment that he would like to get: the i-th (1 ≤ i ≤ k) child wrote the number ai (1 ≤ ai ≤ n·k). All numbers ai accidentally turned out to be different.

Now the children wonder, how to divide the orange so as to meet these conditions:

  * each child gets exactly n orange segments; 
  * the i-th child gets the segment with number ai for sure; 
  * no segment goes to two children simultaneously. 



Help the children, divide the orange and fulfill the requirements, described above.

Input

The first line contains two integers n, k (1 ≤ n, k ≤ 30). The second line contains k space-separated integers a1, a2, ..., ak (1 ≤ ai ≤ n·k), where ai is the number of the orange segment that the i-th child would like to get.

It is guaranteed that all numbers ai are distinct.

Output

Print exactly n·k distinct integers. The first n integers represent the indexes of the segments the first child will get, the second n integers represent the indexes of the segments the second child will get, and so on. Separate the printed numbers with whitespaces.

You can print a child's segment indexes in any order. It is guaranteed that the answer always exists. If there are multiple correct answers, print any of them.

Examples

Input

2 2
4 1


Output

2 4 
1 3 


Input

3 1
2


Output

3 2 1 

Solution (in JAVA):

Solution:
import java.math.BigInteger;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Scanner;

public class Main {

	public static void main(String[] args){

		Scanner in=new Scanner(System.in);


		int n=in.nextInt();
		int k=in.nextInt();


		int[] ch=new int[k];



		int[][] a=new int[k][n];

		ArrayList<Integer> b=new ArrayList();

		for(int i=0;i<k;i++){
			b.add(in.nextInt());
			a[i][0]=b.get(i);
		}

		int nn=1;
		for(int i=0;i<k;i++){
			for(int j=1;j<n;j++){
				while(b.contains(nn))
					nn++;

				a[i][j]=nn;
				b.add(nn);
				//System.out.println(i+"  "+j);
			}


		}

		for(int i=0;i<k;i++){
			for(int j=0;j<n;j++)
				System.out.print(a[i][j]+" ");

			System.out.println();


		}

	}

}