Problem: Mary Thomas has a number of sheets of squared paper. Some of squares are painted either in black or some colorful color (such as red and blue) on the front side. Cutting off the unpainted part, she will have eight opened-up unit cubes. A unit cube here refers to a cube of which each face consists of one square.

She is going to build those eight unit cubes with the front side exposed and then a bicube with them. A bicube is a cube of the size 2 × 2 × 2, consisting of eight unit cubes, that satisfies the following conditions:

* faces of the unit cubes that comes to the inside of the bicube are all black;
* each face of the bicube has a uniform colorful color; and
* the faces of the bicube have colors all different.



Your task is to write a program that reads the specification of a sheet of squared paper and decides whether a bicube can be built with the eight unit cubes resulting from it.



Input

The input contains the specification of a sheet. The first line contains two integers H and W, which denote the height and width of the sheet (3 ≤ H, W ≤ 50). Then H lines follow, each consisting of W characters. These lines show the squares on the front side of the sheet. A character represents the color of a grid: alphabets and digits ('A' to 'Z', 'a' to 'z', '0' to '9') for colorful squares, a hash ('#') for a black square, and a dot ('.') for an unpainted square. Each alphabet or digit denotes a unique color: squares have the same color if and only if they are represented by the same character.

Each component of connected squares forms one opened-up cube. Squares are regarded as connected when they have a common edge; those just with a common vertex are not.

Output

Print "Yes" if a bicube can be built with the given sheet; "No" otherwise.

Examples

Input

3 40
.a....a....a....a....f....f....f....f...
#bc#.#cd#.#de#.#eb#.#cb#.#dc#.#ed#.#be#.
.#....#....#....#....#....#....#....#...


Output

Yes


Input

3 40
.a....a....a....a....f....f....f....f...
bc#.#cd#.#de#.#eb#.#cb#.#dc#.#ed#.#be#.
.#....#....#....#....#....#....#....#...


Output

Yes


Input

5 35
.a....a....a....a....f....f....f...
bc#.#cd#.#de#.#eb#.#cb#.#dc#.#ed#.
.#..f.#....#....#....#....#....#...
..e##..............................
.b#................................


Output

Yes


Input

3 40
.a....a....a....a....f....f....f....f...
bc#.#cd#.#de#.#eb#.#cb#.#dc#.#ed#.#eb#.
.#....#....#....#....#....#....#....#...


Output

No

Solution (in JAVA):

Solution:
import java.util.*;

class Main{

    int h,w;
    char[][] sheet;
    ArrayList<Dice> list;
    ArrayList<Character> color;
    int[] colors;

    int[] dx = {0, 1, 0, -1};
    int[] dy = {-1, 0, 1, 0};

    int[][] nei = {{1, 3, 2, 4},
                   {5, 3, 0, 4},
                   {0, 3, 5, 4},
                   {1, 5, 2, 0},
                   {1, 0, 2, 5},
                   {1, 4, 2, 3}};

    class Dice{
        char[] dice = new char[6]; 
        Dice(char f, char t, char b, char r, char l, char u){
            dice[0] = f;
            dice[1] = t;
            dice[2] = b;
            dice[3] = r;
            dice[4] = l;
            dice[5] = u;
        }
    }

    Dice rotateRight(Dice d){
        return new Dice(d.dice[0], d.dice[4], d.dice[3], d.dice[1], d.dice[2], d.dice[5]);
    }

    Dice rotateLeft(Dice d){
        return new Dice(d.dice[0], d.dice[3], d.dice[4], d.dice[2], d.dice[1], d.dice[5]);
    }

    Dice rotateDown(Dice d){
        return new Dice(d.dice[1], d.dice[5], d.dice[0], d.dice[3], d.dice[4], d.dice[2]);
    }

    Dice rotateUp(Dice d){
        return new Dice(d.dice[2], d.dice[0], d.dice[5], d.dice[3], d.dice[4], d.dice[1]);
    }
    
    boolean check(Dice d){
        if(d.dice[1]!='#' && d.dice[3]!='#') return true;
        if(d.dice[3]!='#' && d.dice[2]!='#') return true;
        if(d.dice[2]!='#' && d.dice[4]!='#') return true;
        if(d.dice[4]!='#' && d.dice[1]!='#') return true;
        return false;
    }

    Dice rotate(int k, Dice d){
        if(k==0) return d;
        if(k==1) return rotateDown(d);
        if(k==2) return rotateUp(d);
        if(k==3) return rotateDown(rotateLeft(d));
        if(k==4) return rotateDown(rotateRight(d));
        if(k==5) return rotateDown(rotateDown(d));
        return d;
    }

    void solve(){
        Scanner sc = new Scanner(System.in);

        h = sc.nextInt();
        w = sc.nextInt();
        sheet = new char[h][w];
        color = new ArrayList<Character>();
        for(int i=0; i<h; i++){
            String s = sc.next();
            for(int j=0; j<w; j++){
                sheet[i][j] = s.charAt(j);
                if(sheet[i][j]!='#' && sheet[i][j]!='.' && !color.contains(sheet[i][j])) 
                    color.add(sheet[i][j]);
            }
        }

        list = new ArrayList<Dice>();
        colors = new int[color.size()];

        for(int i=0; i<h; i++){
            for(int j=0; j<w; j++){
                if(sheet[i][j]!='.'){
                    bfs(i, j);
                }
            }
        }

        ArrayList<Dice> list2 = new ArrayList<Dice>();

        for(int i=0; i<colors.length; i++){
            if(colors[i]<4) continue;
            ArrayList<Dice> same = new ArrayList<Dice>();
            for(int j=0; j<list.size(); j++){
                Dice dd  = list.get(j);
                for(int k=0; k<6; k++){
                    if(dd.dice[k]==color.get(i)){
                        Dice newDice = rotate(k, dd); //kを前面に
                        same.add(newDice);
                        break;
                    }
                }
            }
            if(same.size()<4) continue;

            for(int j=0; j<same.size(); j++){
                Dice d1 = same.get(j);
                if(!check(d1)) continue;
                while(d1.dice[1]=='#' || d1.dice[4]=='#') d1 = rotateRight(d1);
                for(int k=0; k<same.size(); k++){
                    Dice d2 = same.get(k);
                    if(!check(d2)) continue;
                    while(d2.dice[1]=='#' || d2.dice[3]=='#') d2 = rotateRight(d2); 
                    for(int l=0; l<same.size(); l++){
                        Dice d3 = same.get(l);
                        if(!check(d3)) continue;
                        while(d3.dice[4]=='#' || d3.dice[2]=='#') d3 = rotateRight(d3);
                        for(int m=0; m<same.size(); m++){
                            Dice d4 = same.get(m);
                            if(!check(d4)) continue;
                            while(d4.dice[3]=='#' || d4.dice[2]=='#') d4 = rotateRight(d4);

                            if(d1.dice[1]==d2.dice[1] && d2.dice[3]==d4.dice[3] &&
                               d3.dice[2]==d4.dice[2] && d1.dice[4]==d3.dice[4] && 
                               d1.dice[1]!=d3.dice[2] && d1.dice[4]!=d2.dice[3]){
                                list2.add(new Dice((char)color.get(i), d1.dice[1], d3.dice[2], d2.dice[3], d1.dice[4], '.'));
                            }
                        }
                    }
                }
            }
        }

        String ans = "No";
        for(int i=0; i<list2.size(); i++){
            Dice d1 = list2.get(i);
            for(int j=i+1; j<list2.size(); j++){
                Dice d2 = list2.get(j);
                for(int k=0; k<4; k++){
                    d2 = rotateRight(d2);
                    if(d1.dice[0]!=d2.dice[0] && d1.dice[1]==d2.dice[1] && 
                       d1.dice[2]==d2.dice[2] && d1.dice[3]==d2.dice[4] && d1.dice[4]==d2.dice[3]){
                        ans = "Yes";
                    }
                }
            }
        }

        System.out.println(ans);
    }

    int[][] abs = {{2,1,0,3},{3,2,1,0},{0,3,2,1},{1,0,3,2}};

    void bfs(int y, int x){
        //y, x, pos, prior
        Queue<int[]> q = new LinkedList<int[]>();
        q.add(new int[]{y, x, 0, 0});
        boolean[][] v = new boolean[h][w];
        v[y][x] = true;

        char[] c = new char[6];
        HashSet<Character> set = new HashSet<Character>();

        int black = 0;
        int cnt = 0;
        while(q.size()>0){
            int[] yx = q.poll();
            int yy = yx[0], xx = yx[1], pos = yx[2], prior = yx[3];
          
            c[pos] = sheet[yy][xx];
            set.add(c[pos]);
            if(sheet[yy][xx]=='#') black++;
            cnt++;
            sheet[yy][xx] = '.';  

            for(int i=0; i<4; i++){
                int ny = yy + dy[(i+prior)%4], nx = xx + dx[(i+prior)%4];
                if(ny<0 || ny>=h || nx<0 || nx>=w || v[ny][nx] || sheet[ny][nx]=='.') continue;
                for(int j=0; j<4; j++){
                    if(nei[nei[pos][i]][j]==pos){
                        v[ny][nx] = true;
                        q.add(new int[]{ny, nx, nei[pos][i], (abs[i][j]+prior)%4});
                    }
                }
            }
        }



        if(cnt==6 && black==3 && set.size()==4){
            list.add(new Dice(c[0], c[1], c[2], c[3], c[4], c[5]));
            //System.out.println(c[0]+" "+c[1]+" "+c[2]+" "+c[3]+" "+c[4]+" "+c[5]);
            for(int i=0; i<6; i++){
                if(c[i]=='#') continue;
                colors[color.indexOf(c[i])]++;
            }
        }
    }

    public static void main(String[] args){
        new Main().solve();
    }
}