Problem: You are given matrix with n rows and n columns filled with zeroes. You should put k ones in it in such a way that the resulting matrix is symmetrical with respect to the main diagonal (the diagonal that goes from the top left to the bottom right corner) and is lexicographically maximal.

One matrix is lexicographically greater than the other if the first different number in the first different row from the top in the first matrix is greater than the corresponding number in the second one.

If there exists no such matrix then output -1.

Input

The first line consists of two numbers n and k (1 ≤ n ≤ 100, 0 ≤ k ≤ 106).

Output

If the answer exists then output resulting matrix. Otherwise output -1.

Examples

Input

2 1


Output

1 0 
0 0 


Input

3 2


Output

1 0 0 
0 1 0 
0 0 0 


Input

2 5


Output

-1

Solution (in PYTHON):

Solution:
if 1:
    from sys import *
    from functools import *
    from collections import *
    from itertools import *
    from functools import *
    from heapq import *
    xr = xrange

    def print_args(*args, **kwargs):
        return ','.join(value for value in [','.join(map(repr, args)),','.join("%s=%s" % (k, repr(v)) for k, v in kwargs.items())] if value)

    def print_result(before=False, after=True):
        def fc(func):
            @wraps(func)
            def f(*args, **kwargs):
                if before:
                    print "%s(%s)"      % (func.__name__, print_args(*args, **kwargs))
                r = func(*args, **kwargs)
                if after:
                    print "%s(%s) = %s" % (func.__name__, print_args(*args, **kwargs), r)
                return r
            return f
        return fc

    def memoize(function):
        memo = {}
        @wraps(function)
        def f(*args):
            key = args
            if key not in memo:
                memo[key] = function(*args)
                if not (len(memo) & 32767):
                    print >>stderr, "memo", function.__name__, len(memo)
            return memo[key]
        f.memo = memo
        return f

    def line():
        return raw_input().strip()

    def parts(f=int):
        return map(f, line().split())

    def qparts(f=int):
        data = line().split()
        return data[0], map(f, data[1:])

def printm(m):
    for a in m:
        print ' '.join(map(lambda x: chr(x+ord('0')),a))

def solve():
    n, k = parts()
    m = [ [0]*n for _ in range(n) ]
    if k == 0:
        printm(m)
        return
    if k > n*n:
        print '-1'
        return

    m[0][0] = 1
    k -= 1
    i, j = 0, 1
    while k > 1:
        if i == j:
            m[i][j] = 1
            k -= 1
            j += 1
        else:
            m[i][j] = m[j][i] = 1
            k -= 2
            j += 1
            if j == n:
                i += 1
                j = i
    if k != 0:
        if i != j:
            i += 1
            j = i
        m[i][j] = 1

    printm(m)

solve()