Problem: You are given two integers b and w. You have a chessboard of size 10^9 × 10^9 with the top left cell at (1; 1), the cell (1; 1) is painted white.

Your task is to find a connected component on this chessboard that contains exactly b black cells and exactly w white cells. Two cells are called connected if they share a side (i.e. for the cell (x, y) there are at most four connected cells: (x - 1, y), (x + 1, y), (x, y - 1), (x, y + 1)). A set of cells is called a connected component if for every pair of cells C_1 and C_2 from this set, there exists a sequence of cells c_1, c_2, ..., c_k such that c_1 = C_1, c_k = C_2, all c_i from 1 to k are belong to this set of cells and for every i ∈ [1, k - 1], cells c_i and c_{i + 1} are connected.

Obviously, it can be impossible to find such component. In this case print "NO". Otherwise, print "YES" and any suitable connected component.

You have to answer q independent queries.

Input

The first line of the input contains one integer q (1 ≤ q ≤ 10^5) — the number of queries. Then q queries follow.

The only line of the query contains two integers b and w (1 ≤ b, w ≤ 10^5) — the number of black cells required and the number of white cells required.

It is guaranteed that the sum of numbers of cells does not exceed 2 ⋅ 10^5 (∑ w + ∑ b ≤ 2 ⋅ 10^5).

Output

For each query, print the answer to it.

If it is impossible to find the required component, print "NO" on the first line.

Otherwise, print "YES" on the first line. In the next b + w lines print coordinates of cells of your component in any order. There should be exactly b black cells and w white cells in your answer. The printed component should be connected.

If there are several answers, you can print any. All coordinates in the answer should be in the range [1; 10^9].

Example

Input


3
1 1
1 4
2 5


Output


YES
2 2
1 2
YES
2 3
1 3
3 3
2 2
2 4
YES
2 3
2 4
2 5
1 3
1 5
3 3
3 5

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.HashSet;
import java.util.Random;
import java.util.StringTokenizer;
     
public class Solution{
    	
	static final int mod = 998244353;
    		
    	
    public static void main(String[] args) {
     
    	FastScanner fs = new FastScanner();
    	PrintWriter out = new PrintWriter(System.out);
    		
    		
    	int tt = fs.nextInt();
    	while(tt-->0) {
    		
    		int b = fs.nextInt();
    		int w = fs.nextInt();
    		
    		ArrayList<Pair> list = new ArrayList<Pair>();
    		
    		boolean bool = b<w;
    		if(bool) { int temp = b; b = w; w = temp; }
    		
    		int x = 2, y = 2;
    		while(w>0) {
    			if((x+y)%2==1) {
    				list.add(new Pair(x,y));
    				b--;
    			}
    			else {
    				list.add(new Pair(x, y));
    				w--;
    			}
    			y++;
    		}
    		
    		
    		int cx = 1, cy = 2;
    		while(b>0 && cy<y) {
    			list.add(new Pair(cx, cy));
    			cy += 2;
    			b--;
    		}
    		
    		cx = 3; cy = 2;
    		while(b>0 && cy<y) {
    			list.add(new Pair(cx, cy));
    			cy += 2;
    			b--;
    		}
    		
    		if(b>0) {
    			list.add(new Pair(2, 1));
    			b--;
    		}
    		if(b>0) {
    			list.add(new Pair(2,y));
    			b--;
    		}
    		
    		if(b>0) {
    			out.println("NO");
    			continue;
    		}
    		
    		int k = (bool)?1:0;
    		
    		out.println("YES");
    		
    		for(Pair p: list) out.println(p.first+" "+(p.second+k));
    		
    		
    		
    	}
    		
    	out.close();
    		
    }
    
    
    
  
    static class Pair{
    	int first;
    	int second;
    	Pair(int a, int b){
    		first = a;
    		second = b;
    	}
    }
    

    
    
    	
    	
    	
    	
    	
    static final Random random=new Random();
    	
    static void ruffleSort(int[] a) {
    	int n=a.length;//shuffle, then sort 
    	for (int i=0; i<n; i++) {
    		int oi=random.nextInt(n); int temp=a[oi];
    		a[oi]=a[i]; a[i]=temp;
    	}
    	Arrays.sort(a);
    }
    	
    	
    	
    static class FastScanner{
    	BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
    	StringTokenizer st = new StringTokenizer("");
     
    	public String next(){
    		while(!st.hasMoreElements()){
    			try{
    				st = new StringTokenizer(br.readLine());
    			} catch(IOException e){
    				e.printStackTrace();
    			}
    		}
    		return st.nextToken();
    	}
    		
    	public String nextLine() throws IOException {
    		return br.readLine();
    	}
    		
    	public int nextInt(){
    		return Integer.parseInt(next());
    	}
     
    	public int[] readArray(int n){
    		int[] a = new int[n];
    		for(int i=0;i<n;i++)
    			a[i] = nextInt();
    		return a;
    	}
    		
    	public long nextLong() {
    		return Long.parseLong(next());
    	}
    		
    	public char nextChar() {
    		return next().toCharArray()[0];
    	}
    }
   	
}