Problem: You are given a string t consisting of n lowercase Latin letters and an integer number k.

Let's define a substring of some string s with indices from l to r as s[l ... r].

Your task is to construct such string s of minimum possible length that there are exactly k positions i such that s[i ... i + n - 1] = t. In other words, your task is to construct such string s of minimum possible length that there are exactly k substrings of s equal to t.

It is guaranteed that the answer is always unique.

Input

The first line of the input contains two integers n and k (1 ≤ n, k ≤ 50) — the length of the string t and the number of substrings.

The second line of the input contains the string t consisting of exactly n lowercase Latin letters.

Output

Print such string s of minimum possible length that there are exactly k substrings of s equal to t.

It is guaranteed that the answer is always unique.

Examples

Input

3 4
aba


Output

ababababa


Input

3 2
cat


Output

catcat

Solution (in PYTHON):

Solution:
# inp.readline()
# int(inp.readline())
# out.write()
# raw_input()
# map(int,raw_input().split())
# map(int,inp.readline().split())
def main():
    an = ""
    n,k=map(int,inp.readline().split())
    s=inp.readline().strip()
    l=0
    for i in xrange(1,n):
        if s[i:]==s[:n-i]:
            l=n-i
            break
    print (s+s[l:]*(k-1)).strip()
if __name__ == "__main__":
    from sys import stdin as inp, stdout as out
    main()