Problem: You are given a string t consisting of n lowercase Latin letters and an integer number k.

Let's define a substring of some string s with indices from l to r as s[l ... r].

Your task is to construct such string s of minimum possible length that there are exactly k positions i such that s[i ... i + n - 1] = t. In other words, your task is to construct such string s of minimum possible length that there are exactly k substrings of s equal to t.

It is guaranteed that the answer is always unique.

Input

The first line of the input contains two integers n and k (1 ≤ n, k ≤ 50) — the length of the string t and the number of substrings.

The second line of the input contains the string t consisting of exactly n lowercase Latin letters.

Output

Print such string s of minimum possible length that there are exactly k substrings of s equal to t.

It is guaranteed that the answer is always unique.

Examples

Input

3 4
aba


Output

ababababa


Input

3 2
cat


Output

catcat

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int nxt[1000005];
void build(string s) {
  int k = 0;
  nxt[0] = 0;
  for (int i = 1; i < s.size(); i++) {
    while (k && s[k] != s[i]) k = nxt[k - 1];
    if (s[k] == s[i]) k++;
    nxt[i] = k;
  }
}
int main() {
  int n, k;
  string s;
  cin >> n >> k >> s;
  build(s);
  int r = n - nxt[n - 1];
  for (int i = 0; i < k; i++) {
    for (int j = 0; j < r; j++) cout << s[j];
  }
  for (int i = r; i < n; i++) cout << s[i];
  cout << endl;
  return 0;
}