Problem: Ford Prefect got a job as a web developer for a small company that makes towels. His current work task is to create a search engine for the website of the company. During the development process, he needs to write a subroutine for comparing strings S and T of equal length to be "similar". After a brief search on the Internet, he learned about the Hamming distance between two strings S and T of the same length, which is defined as the number of positions in which S and T have different characters. For example, the Hamming distance between words "permanent" and "pergament" is two, as these words differ in the fourth and sixth letters.

Moreover, as he was searching for information, he also noticed that modern search engines have powerful mechanisms to correct errors in the request to improve the quality of search. Ford doesn't know much about human beings, so he assumed that the most common mistake in a request is swapping two arbitrary letters of the string (not necessarily adjacent). Now he wants to write a function that determines which two letters should be swapped in string S, so that the Hamming distance between a new string S and string T would be as small as possible, or otherwise, determine that such a replacement cannot reduce the distance between the strings.

Help him do this!

Input

The first line contains integer n (1 ≤ n ≤ 200 000) — the length of strings S and T.

The second line contains string S.

The third line contains string T.

Each of the lines only contains lowercase Latin letters.

Output

In the first line, print number x — the minimum possible Hamming distance between strings S and T if you swap at most one pair of letters in S.

In the second line, either print the indexes i and j (1 ≤ i, j ≤ n, i ≠ j), if reaching the minimum possible distance is possible by swapping letters on positions i and j, or print "-1 -1", if it is not necessary to swap characters.

If there are multiple possible answers, print any of them.

Examples

Input

9
pergament
permanent


Output

1
4 6


Input

6
wookie
cookie


Output

1
-1 -1


Input

4
petr
egor


Output

2
1 2


Input

6
double
bundle


Output

2
4 1

Note

In the second test it is acceptable to print i = 2, j = 3.

Solution (in JAVA):

Solution:
import java.io.*;
import java.math.BigInteger;
import java.util.*;
 
 
 
 public class Main {
	public static InputReader in;
    public static PrintWriter pw;
 
 
 
	public static void main(String args[]) {
		new Thread(null, new Runnable() {
            public void run() {
                try{
                    solve();
                }
                catch(Exception e){
                    e.printStackTrace();
                }
            }
        }, "1", 1 << 26).start();
    }
	//static HashSet<Integer> set;
	static ArrayList<Integer> g[];
	static ArrayList<Integer> h[];
	//static boolean visited[];
	static long edje=0;
    static boolean vis[];
	static int col[];
	static boolean[] visited;
	static int Parent[];
	static int Ans=0;
	static int min=Integer.MAX_VALUE;
	static boolean vis1[];
	static int degree[];
	static int f[];
	static  int size[];
	static int n;
	static int edjes=0;
	static int start=-1;
	static int end=-1;
	static boolean bool=false;
	static int Total=0;
	static int nums[];
	//static int a[];
	static int fr[];
	static int min1=Integer.MAX_VALUE;
	static TreeSet<String> set;
	static int a[];
	static int time1[];
	static int time2[];
	static int glob=0;
	static  HashSet<Integer>[] s;
	static StringBuilder tmp=new StringBuilder();
	static HashMap<String,String> hm=new HashMap<String,String>();
	
	public static void solve(){
	
		 in = new InputReader(System.in);
		 pw = new PrintWriter(System.out);
	     int n=in.nextInt();
	     String s1=in.readString();
	     String s2=in.readString();
	     HashSet<Character> two=new HashSet<Character>();
	     if(s1.equals(s2))
	     {
	    	 System.out.println(0);
	    	 System.out.println(-1+" "+-1);
	    	 System.exit(0);
	     }
	  //   int ind[]=new int[26];
	    int c=0;
	    int fuck[]=new int[26];
	    HashSet<String> set=new HashSet<String>();
	    HashMap<String,Integer> hm=new HashMap<String,Integer>();
	    StringBuilder sb=new StringBuilder();
	    boolean bool=false;
	    HashSet<Character> ind=new HashSet<Character>();
	     for(int i=0;i<s1.length();i++)
	     {
	    	 if(s1.charAt(i)!=s2.charAt(i))
	    	 {
	    		// ind[s2.charAt(i)-'a']=i;
	 	    	ind.add(s2.charAt(i));
	    		 c++;
	    		 fuck[s2.charAt(i)-'a']=i+1;
	    		 String one="";
	    		
	    			 one=s1.charAt(i)+""+s2.charAt(i);
	    			 if(!hm.containsKey(one))
	    				 hm.put(one, i+1);
	    			 String rev=new StringBuilder(one).reverse().toString();
	    		    if(set.contains(rev))
	    		    {
	    		    	//bool=true;
	    		    	if(!bool)
	    		   sb.append(hm.get(rev)+" "+(i+1));
	    		   bool=true;
	    		    }
	    		    set.add(one);
	    	 }
	    	 
	     }
	     if(bool)
	     {
	    	 System.out.println(c-2);
	    	 System.out.println(sb);
	    	 System.exit(0);
	     }
	     
	     for(int i=0;i<s1.length();i++)
	     {
	    	 if(s1.charAt(i)!=s2.charAt(i))
	    	 {
	    		if(ind.contains(s1.charAt(i)))
	    		{
	    		System.out.println(c-1);
	    		System.out.println((i+1)+" "+(fuck[s1.charAt(i)-'a']));
	    		System.exit(0);
	    		}
	    	 }
	     }
	     System.out.println(c);
	     System.out.println(-1+" "+-1);
	    
	  
	}
	
	/*
	 SubTree Checker DFS (TO CHECK IF X IS IN A SUBTREE OF Y)
	public static void dfs(int curr)
	{
		visited[curr]=true;
		time1[curr]=glob++;
		for(int x:g[curr])
		{
		if(!visited[x])
			dfs(x);
		}
		time2[curr]=glob++;
	}
    
	
	
 
    /*NO OF EDJES IN WHOLE CONNECTED COMPONENTS
  
	public static void dfs1(int curr)
	{
		visited[curr]=true;
		for(int next:g[curr])
		{
			edje++;
			if(!visited[next])
				dfs1(next);
		}
	}
	/*SUM OF ALL SUBTREE NODE'S VLAUES DFS
	public static void dfs(int curr,int prev)
		{
		val[curr]=1;
			for(int x:g[curr])
			{
				if(x!=prev)
				{
		            dfs(x,curr);
		            val[curr]+=val[x];
					
			    }
			}
		}*/
	
		public static long power(long a,long b)
		{
			long result=1;
			while(b>0)
			{
				if(b%2==1)
					result*=a;
				a=a*a;
				b/=2;
			}
			return result;
		}
				public static long pow(long n,long p,long m)
	{
		 long  result = 1;
		  if(p==0)
		    return 1;
		if (p==1)
		    return n;
		while(p!=0)
		{
		    if(p%2==1)
		        result *= n;
		    if(result>=m)
		    result%=m;
		    p >>=1;
		    n*=n;
		    if(n>=m)
		    n%=m;
		}
		return result;
	}
	static class Pair implements Comparable<Pair>{
	int y;
		int x;
		Pair(int mr,int i){
	     	y=mr;
			x=i;
			
		}
		@Override
		public int compareTo(Pair o) {
		      //  if(o.dis<this.dis)
		        	return 1;
		       // else
		        //	return -1;
			
			}
		
	}
	public static long gcd(long a, long b) {
		  if (b == 0) return a;
		  return gcd(b, a%b);
		}
	static class InputReader {
 
		private InputStream stream;
		private byte[] buf = new byte[8192];
		private int curChar, snumChars;
		private SpaceCharFilter filter;
 
		public InputReader(InputStream stream) {
			this.stream = stream;
		}
 
		public int snext() {
			if (snumChars == -1)
				throw new InputMismatchException();
			if (curChar >= snumChars) {
				curChar = 0;
				try {
					snumChars = stream.read(buf);
				} catch (IOException e) {
					throw new InputMismatchException();
				}
				if (snumChars <= 0)
					return -1;
			}
			return buf[curChar++];
		}
 
		public   int nextInt() {
			int c = snext();
			while (isSpaceChar(c))
				c = snext();
			int sgn = 1;
			if (c == '-') {
				sgn = -1;
				c = snext();
			}
			int res = 0;
			do {
				if (c < '0' || c > '9')
					throw new InputMismatchException();
				res *= 10;
				res += c - '0';
				c = snext();
			} while (!isSpaceChar(c));
			return res * sgn;
		}
 
		public long nextLong() {
			int c = snext();
			while (isSpaceChar(c))
				c = snext();
			int sgn = 1;
			if (c == '-') {
				sgn = -1;
				c = snext();
			}
			long res = 0;
			do {
				if (c < '0' || c > '9')
					throw new InputMismatchException();
				res *= 10;
				res += c - '0';
				c = snext();
			} while (!isSpaceChar(c));
			return res * sgn;
		}
 
		public int[] nextIntArray(int n) {
			int a[] = new int[n];
			for (int i = 0; i < n; i++)
				a[i] = nextInt();
			return a;
		}
 
		public String readString() {
			int c = snext();
			while (isSpaceChar(c))
				c = snext();
			StringBuilder res = new StringBuilder();
			do {
				res.appendCodePoint(c);
				c = snext();
			} while (!isSpaceChar(c));
			return res.toString();
		}
 
		public boolean isSpaceChar(int c) {
			if (filter != null)
				return filter.isSpaceChar(c);
			return c == ' ' || c == '\n' || c == '\r' || c == '\t' || c == -1;
		}
 
		public interface SpaceCharFilter {
			public boolean isSpaceChar(int ch);
		}
	}
}