Problem: There are n cats in a line, labeled from 1 to n, with the i-th cat at position i. They are bored of gyrating in the same spot all day, so they want to reorder themselves such that no cat is in the same place as before. They are also lazy, so they want to minimize the total distance they move. Help them decide what cat should be at each location after the reordering.

For example, if there are 3 cats, this is a valid reordering: [3, 1, 2]. No cat is in its original position. The total distance the cats move is 1 + 1 + 2 = 4 as cat 1 moves one place to the right, cat 2 moves one place to the right, and cat 3 moves two places to the left.

Input

The first line contains a single integer t (1 ≤ t ≤ 100) — the number of test cases. Then t test cases follow.

The first and only line of each test case contains one integer n (2 ≤ n ≤ 100) — the number of cats.

It can be proven that under the constraints of the problem, an answer always exist. 

Output

Output t answers, one for each test case. Each answer consists of n integers — a permutation with the minimum total distance. If there are multiple answers, print any.

Example

Input


2
2
3


Output


2 1 
3 1 2 

Note

For the first test case, there is only one possible permutation that satisfies the conditions: [2, 1].

The second test case was described in the statement. Another possible answer is [2, 3, 1].

Solution (in CPP):

Solution:
#include<bits/stdc++.h>
using namespace std;

// #pragma comment(linker, "/stack:200000000")
// #pragma GCC optimize("Ofast")
// #pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native")

// - - - - - - Data Types - - - - - - //

typedef long int LI;
typedef long long LL;

// - - - - - - Vectors - - - - - - //
typedef vector<int> VI;
typedef vector<LL> VLL;
typedef vector<string> VS;
typedef vector<double> VD;
typedef vector<VI> VVI;

#define scanVI(v, n)        for(int i=0; i<n; i++){ int x; cin >> x; v.PB(x); }
#define scanVLLI(v, n)      for(int i=0; i<n; i++){ LLI x; cin >> x; v.PB(x); }
#define scanVS(v, n)        for(int i=0; i<n; i++){ string x; cin >> x; v.PB(x); }
#define scanVD(v, n)        for(int i=0; i<n; i++){ double x; cin >> x; v.PB(x); }

// - - - - - - Maps - - - - - - //
typedef map<int, int> MII;
typedef map<int, string> MIS;
typedef map<int, char> MIC;
typedef map<string, int> MSI;
typedef map<char, int> MCI;
typedef map<int, VI> MIVI;

// - - - - - - Pairs - - - - - - //
typedef pair<int, int> PII;
typedef pair<string, string> PSS;
typedef pair<char, char> PCC;
typedef pair<int, string> PIS;
typedef pair<int, char> PIC;
typedef pair<string, char> PSC;

// - - - - - - Sets - - - - - - //
typedef set<int> SI;
typedef set<LL> SLL;
typedef set<string> SS;
typedef set<char> SC;
// - - - - - - - - - - - - - - - - - - //

#define PF                  printf
#define SF                  scanf
#define PB                  push_back
#define POP                 pop_back()
#define PP                  prev_permutation
#define NP                  next_permutation
#define MP                  make_pair
#define CLRN(a, b)          memset(a, b, sizeof(a))
#define CLR(a)              memset(a, 0, sizeof(a))
#define ALL(a)              a.begin(), a.end()
#define ALLN(a, n)          (a, a+n)
#define BSRCN(a, n, x)      binary_search(ALLN(a, n), x)
#define BSRC                binary_search
#define MAX                 10000007
#define MIN                 -10000007
#define inf                 int(1e6+9)
#define PI                  acos(-1)
#define BR                  PF("\n")
#define FastIO              ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0);
#define READ()              freopen("input.txt", "r", stdin)
#define WRITE()             freopen("output.txt", "w", stdout)
#define len(a)              a.length()
#define rsort(a)            sort(a.rbegin(), a.rend())
#define pvec(v)             for(auto x: v) cout<<x<<" "

// - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - //
/*----------------------Graph Moves----------------*/
int ROW[]={+1,-1,+0,+0};
int COL[]={+0,+0,+1,-1};

int X[]={+0,+0,+1,-1,-1,+1,-1,+1};   // Kings Move
int Y[]={-1,+1,+0,+0,+1,+1,-1,-1};  // Kings Move

int KX[]={-2, -2, -1, -1,  1,  1,  2,  2};  // Knights Move
int KY[]={-1,  1, -2,  2, -2,  2, -1,  1}; // Knights Move
/*------------------------------------------------*/

// ---------------------DEBUG---------------------//

#ifdef WOLF
     #define debug(...) __f(#__VA_ARGS__, __VA_ARGS__)
    template < typename Arg1 >
    void __f(const char* name, Arg1&& arg1){
        cout << name << " = " << arg1 << std::endl;
    }
    template < typename Arg1, typename... Args>
    void __f(const char* names, Arg1&& arg1, Args&&... args){
        const char* comma = strchr(names, ',');
        cout.write(names, comma - names) << " = " << arg1 <<" | ";
        __f(comma+1, args...);
    }
#else
    #define debug(...)
#endif

//------------------------------------------------//

void fastscan(int &number) 
{ 
    bool negative = false; 
    int c; 
  
    number = 0; 
    c = getchar(); 
    if (c=='-') 
    { 
        negative = true; 
        c = getchar(); 
    } 
    for (; (c>47 && c<58); c=getchar()) 
        number = number *10 + c - 48; 
    if (negative) 
        number *= -1; 
} 

LL GCD(LL a, LL b) { return b == 0 ? a : GCD(b , a % b); }
int LCM(int a, int b) { return a * (b/GCD(a, b)); }
bool CMP(int a, int b) { return a>b; }

// - - - - - - - - - - - - - - - - - - - - - - - - - - - END - - - - - - - - - - - - - - - - - - - - - - - - - //


int main()
{
    // FastIO;
    #ifdef WOLF
     clock_t Start=clock();
     freopen("in.txt", "r", stdin);
     freopen("out.txt", "w", stdout);
    #endif
    
  	int t, ca = 1;
  	cin>>t;
  	while (t--) {
  	
  		int n;
  		cin>>n;

  		if (n & 1) {
  			cout<<"3 1 2";

  			for (int i=4; i<=n; i++) {
  				cout<<" "<<i+1<<" "<<i;
  				i++;
  			}

  			cout<<endl;
  		}

  		else {
  			cout<<"2 1";

  			for (int i=3; i<=n; i++) {
  				cout<<" "<<i+1<<" "<<i;
  				i++;
  			}

	  		cout<<endl;
  		}

  	}

    END:
    #ifdef WOLF
     fprintf(stderr, "\n>>Runtime: %.10fs\n", (double) (clock() - Start) / CLOCKS_PER_SEC);
    #endif
    return 0;
}