Problem: One day Ms Swan bought an orange in a shop. The orange consisted of n·k segments, numbered with integers from 1 to n·k. 

There were k children waiting for Ms Swan at home. The children have recently learned about the orange and they decided to divide it between them. For that each child took a piece of paper and wrote the number of the segment that he would like to get: the i-th (1 ≤ i ≤ k) child wrote the number ai (1 ≤ ai ≤ n·k). All numbers ai accidentally turned out to be different.

Now the children wonder, how to divide the orange so as to meet these conditions:

  * each child gets exactly n orange segments; 
  * the i-th child gets the segment with number ai for sure; 
  * no segment goes to two children simultaneously. 



Help the children, divide the orange and fulfill the requirements, described above.

Input

The first line contains two integers n, k (1 ≤ n, k ≤ 30). The second line contains k space-separated integers a1, a2, ..., ak (1 ≤ ai ≤ n·k), where ai is the number of the orange segment that the i-th child would like to get.

It is guaranteed that all numbers ai are distinct.

Output

Print exactly n·k distinct integers. The first n integers represent the indexes of the segments the first child will get, the second n integers represent the indexes of the segments the second child will get, and so on. Separate the printed numbers with whitespaces.

You can print a child's segment indexes in any order. It is guaranteed that the answer always exists. If there are multiple correct answers, print any of them.

Examples

Input

2 2
4 1


Output

2 4 
1 3 


Input

3 1
2


Output

3 2 1 

Solution (in JAVA):

Solution:
import java.lang.*;
import java.io.*;
import java.util.*;


public class code
{
	public static void main(String argsp[])
	{
		Scanner scn  = new Scanner(System.in);	
		
		int n = scn.nextInt();
		int k = scn.nextInt();
		
		int list[] = new int[1 + n*k];

		for(int i =0; i < k; i++)
		{
			list[scn.nextInt()] = i + 1;
		}

		int index = 1;
		int count = 1;
		for(int i = 1; i <= n*k; i++)
		{
			if(list[i]!=0)
				continue;

			list[i] = index;
			count++;
			
			if(count == n)
			{
				index++;
				count = 1;
			}
		}

		for(int i=1; i<=k; i++)
		{
			for(int j=1; j<=n*k; j++)
			{
				if(list[j]==i)
					System.out.print(j+" ");
			}
			System.out.println();
		}

	}
}