Problem: One day Ms Swan bought an orange in a shop. The orange consisted of n·k segments, numbered with integers from 1 to n·k. 

There were k children waiting for Ms Swan at home. The children have recently learned about the orange and they decided to divide it between them. For that each child took a piece of paper and wrote the number of the segment that he would like to get: the i-th (1 ≤ i ≤ k) child wrote the number ai (1 ≤ ai ≤ n·k). All numbers ai accidentally turned out to be different.

Now the children wonder, how to divide the orange so as to meet these conditions:

  * each child gets exactly n orange segments; 
  * the i-th child gets the segment with number ai for sure; 
  * no segment goes to two children simultaneously. 



Help the children, divide the orange and fulfill the requirements, described above.

Input

The first line contains two integers n, k (1 ≤ n, k ≤ 30). The second line contains k space-separated integers a1, a2, ..., ak (1 ≤ ai ≤ n·k), where ai is the number of the orange segment that the i-th child would like to get.

It is guaranteed that all numbers ai are distinct.

Output

Print exactly n·k distinct integers. The first n integers represent the indexes of the segments the first child will get, the second n integers represent the indexes of the segments the second child will get, and so on. Separate the printed numbers with whitespaces.

You can print a child's segment indexes in any order. It is guaranteed that the answer always exists. If there are multiple correct answers, print any of them.

Examples

Input

2 2
4 1


Output

2 4 
1 3 


Input

3 1
2


Output

3 2 1 

Solution (in JAVA):

Solution:
import java.util.*;

public class Main
{
    public static void main(String args[])
    {
        Scanner sc=new Scanner(System.in);
        int n=sc.nextInt();
        int k=sc.nextInt();
        ArrayList<Integer> indexes=new ArrayList<Integer>();
        ArrayList<String> gets=new ArrayList<String>();
        ArrayList<Integer> count=new ArrayList<Integer>();
        for(int i=1;i<=n*k;i++)
            indexes.add(new Integer(i));
        for(int i=0;i<k;i++)
        {
            int pos=sc.nextInt();
            if(indexes.contains(new Integer(pos)))
            {
                indexes.remove(new Integer(pos));
                String str=pos+"";
                gets.add(str);
                count.add(1);
            }
        }
        int pos=0;
        while(!indexes.isEmpty())
        {
            String s=gets.get(pos);
            s=s+" "+indexes.remove(0);
            int c=count.get(pos);
            if((c+1)<=n)
            {
                gets.set(pos, s);
                count.set(pos, c+1);
            }
            pos=(pos+1)%k;
        }
        for(int i=0;i<gets.size();i++)
            System.out.println(gets.get(i).trim());
    }
}