Problem: One day Ms Swan bought an orange in a shop. The orange consisted of n·k segments, numbered with integers from 1 to n·k. 

There were k children waiting for Ms Swan at home. The children have recently learned about the orange and they decided to divide it between them. For that each child took a piece of paper and wrote the number of the segment that he would like to get: the i-th (1 ≤ i ≤ k) child wrote the number ai (1 ≤ ai ≤ n·k). All numbers ai accidentally turned out to be different.

Now the children wonder, how to divide the orange so as to meet these conditions:

  * each child gets exactly n orange segments; 
  * the i-th child gets the segment with number ai for sure; 
  * no segment goes to two children simultaneously. 



Help the children, divide the orange and fulfill the requirements, described above.

Input

The first line contains two integers n, k (1 ≤ n, k ≤ 30). The second line contains k space-separated integers a1, a2, ..., ak (1 ≤ ai ≤ n·k), where ai is the number of the orange segment that the i-th child would like to get.

It is guaranteed that all numbers ai are distinct.

Output

Print exactly n·k distinct integers. The first n integers represent the indexes of the segments the first child will get, the second n integers represent the indexes of the segments the second child will get, and so on. Separate the printed numbers with whitespaces.

You can print a child's segment indexes in any order. It is guaranteed that the answer always exists. If there are multiple correct answers, print any of them.

Examples

Input

2 2
4 1


Output

2 4 
1 3 


Input

3 1
2


Output

3 2 1 

Solution (in PYTHON):

Solution:
n,k = map(int,raw_input().split())

s = map(int,raw_input().split())
ls = []
for i in range(1,(n*k)+1):
    ls.append(i)
ps = [0]*((n*k)+1)

for i in range(k):
    ps[s[i]] = i+1

t = ((n*k)-k)/k
p = 1
count = 0
for i in range(1,(n*k)+1):
    if ps[i]==0:
        if count==t:
            p+=1
            ps[i]=p
            count=0
            count+=1
        else:
            ps[i]=p
            count+=1

for i in range(1,k+1):
    for j in range(1,(n*k)+1):
        if ps[j]==i:
            print(j),
    print('')