Problem: The only difference between easy and hard versions is a number of elements in the array.

You are given an array a consisting of n integers. The value of the i-th element of the array is a_i.

You are also given a set of m segments. The j-th segment is [l_j; r_j], where 1 ≤ l_j ≤ r_j ≤ n.

You can choose some subset of the given set of segments and decrease values on each of the chosen segments by one (independently). For example, if the initial array a = [0, 0, 0, 0, 0] and the given segments are [1; 3] and [2; 4] then you can choose both of them and the array will become b = [-1, -2, -2, -1, 0].

You have to choose some subset of the given segments (each segment can be chosen at most once) in such a way that if you apply this subset of segments to the array a and obtain the array b then the value max_{i=1}^{n}b_i - min_{i=1}^{n}b_i will be maximum possible.

Note that you can choose the empty set.

If there are multiple answers, you can print any.

If you are Python programmer, consider using PyPy instead of Python when you submit your code.

Input

The first line of the input contains two integers n and m (1 ≤ n ≤ 300, 0 ≤ m ≤ 300) — the length of the array a and the number of segments, respectively.

The second line of the input contains n integers a_1, a_2, ..., a_n (-10^6 ≤ a_i ≤ 10^6), where a_i is the value of the i-th element of the array a.

The next m lines are contain two integers each. The j-th of them contains two integers l_j and r_j (1 ≤ l_j ≤ r_j ≤ n), where l_j and r_j are the ends of the j-th segment.

Output

In the first line of the output print one integer d — the maximum possible value max_{i=1}^{n}b_i - min_{i=1}^{n}b_i if b is the array obtained by applying some subset of the given segments to the array a.

In the second line of the output print one integer q (0 ≤ q ≤ m) — the number of segments you apply.

In the third line print q distinct integers c_1, c_2, ..., c_q in any order (1 ≤ c_k ≤ m) — indices of segments you apply to the array a in such a way that the value max_{i=1}^{n}b_i - min_{i=1}^{n}b_i of the obtained array b is maximum possible.

If there are multiple answers, you can print any.

Examples

Input


5 4
2 -2 3 1 2
1 3
4 5
2 5
1 3


Output


6
2
1 4 


Input


5 4
2 -2 3 1 4
3 5
3 4
2 4
2 5


Output


7
2
3 2 


Input


1 0
1000000


Output


0
0

Note

In the first example the obtained array b will be [0, -4, 1, 1, 2] so the answer is 6.

In the second example the obtained array b will be [2, -3, 1, -1, 4] so the answer is 7.

In the third example you cannot do anything so the answer is 0.

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.*;
public class d {
    public static void main(String[] args) throws IOException {
        //      Scanner s = new Scanner(System.in);
        BufferedReader s = new BufferedReader(new InputStreamReader(System.in));
        //       String[] st=s.readLine().trim().split("\\s+");
        //      a[i]=Integer.parseInt(st[i]);
        //      Integer.parseInt(s.readLine().trim().split("\\s+");
        StringBuilder sb = new StringBuilder();
        StringBuilder sbf = new StringBuilder();
        //  int n=Integer.parseInt(s.readLine().trim().split("\\s+")[0]);
     /*   String[] st=s.readLine().trim().split("\\s+");
        int n=Integer.parseInt(st[0]);*/
        String[] st=s.readLine().trim().split("\\s+");int v=0;
       int n=Integer.parseInt(st[0]);
       int m=Integer.parseInt(st[1]);
       String[] st1=s.readLine().trim().split("\\s+");
       long[] a=new long[n];long min=Long.MAX_VALUE;
       for(int i=0;i<n;i++){
           a[i]=Long.parseLong(st1[i]);min=Math.min(min,a[i]);
       }
       int[] l=new int[m];int[] r=new int[m];
       for(int i=0;i<m;i++){
           String[] ss=s.readLine().trim().split("\\s+");
           l[i]=Integer.parseInt(ss[0]);r[i]=Integer.parseInt(ss[1]);
       }long ans=0;
       for(int i=0;i<n;i++){
           long max=a[i];long diff=max-min;
           long[] b=a.clone();
           StringBuilder sb1=new StringBuilder();
           int val=0;
           for(int j=0;j<m;j++){
               if(!(l[j]-1<=i&&r[j]-1>=i)){
               for(int k=l[j]-1;k<=r[j]-1;k++){
                   b[k]-=1;
               }
               long min1=Long.MAX_VALUE;
               for(int k=0;k<n;k++){
                   min1=Math.min(min1,b[k]);
               }
               if(max-min1<diff){
                   for(int k=l[j]-1;k<=r[j]-1;k++){
                       b[k]+=1;
                   }
               }else {diff=max-min1;sb1.append((j+1)+" ");val++;}
           }}if(diff>ans){sb=sb1;v=val;
           ans=Math.max(ans,diff);}
       }
        System.out.println(ans);
        System.out.println(v);
        if(v!=0) System.out.println(sb.toString());

    }
    static String lexographicallysmallest(String s) {
        if (s.length() % 2 == 1) return s;
        String s1 =lexographicallysmallest(s.substring(0, s.length()/2));
        String s2 = lexographicallysmallest(s.substring(s.length()/2, s.length()));
        if (s1.compareTo(s2)<0) return s1 + s2;
        else return s2 + s1;
    }
    public static int countSetBits(int n)
    {
        return (BitsSetTable256[n & 0xff]
                + BitsSetTable256[(n >> 8) & 0xff]
                + BitsSetTable256[(n >> 16) & 0xff]
                + BitsSetTable256[n >> 24]);
    }
    static int[] BitsSetTable256 ;
    public static void initialize(int n)
    {
        BitsSetTable256[0] = 0;
        for (int i = 0; i <=Math.pow(2,n); i++) {
            BitsSetTable256[i] = (i & 1) + BitsSetTable256[i / 2];
        }
    }
    static void dfs(int i,int val,ArrayList<Integer>[] adj){
    }

    static  void computeLPSArray(String pat, int M, int lps[]) {
        int len = 0;
        int i = 1;
        lps[0] = 0;
        while (i < M) {
            if (pat.charAt(i) == pat.charAt(len)) {
                len++;
                lps[i] = len;
                i++;
            }
            else
            {
                if (len != 0) {
                    len = lps[len - 1];
                }
                else
                {
                    lps[i] = len;
                    i++;
                }
            }
        }
    }
    static boolean isPrime(int n) {
        if (n <= 1) return false;
        if (n <= 3) return true;

        if (n % 2 == 0 || n % 3 == 0) return false;

        for (int i = 5; i * i <= n; i = i + 6)
            if (n % i == 0 || n % (i + 2) == 0)
                return false;

        return true;
    }
    static long powerwithmod(long  x, long y, long p) {
        long  res = 1;
        x = x % p;
        while (y > 0) {
            if ((y & 1) == 1)
                res = (res * x) % p;
            y = y >> 1;
            x = (x * x) % p;
        }
        return res;
    }
    static long  powerwithoutmod(long x, int y) {
        long  temp;
        if( y == 0)
            return 1;
        temp = powerwithoutmod(x, y/2);
        if (y%2 == 0)
            return temp*temp;
        else
        {
            if(y > 0)
                return x * temp * temp;
            else
                return (temp * temp) / x;
        }
    }
    static void fracion(double x) {
        String a = "" + x;
        String spilts[] = a.split("\\."); // split using decimal
        int b = spilts[1].length(); // find the decimal length
        int denominator = (int) Math.pow(10, b); // calculate the denominator
        int numerator = (int) (x * denominator); // calculate the nerumrator Ex
        // 1.2*10 = 12
        int gcd = (int) gcd((long) numerator, denominator); // Find the greatest common
        // divisor bw them
        String fraction = "" + numerator / gcd + "/" + denominator / gcd;
        // System.out.println((denominator/gcd));
        long x1 = modInverse(denominator / gcd, 998244353);
        //  System.out.println(x1);
        System.out.println((((numerator / gcd) % 998244353 * (x1 % 998244353)) % 998244353));
    }
    static int bfs(int i1, ArrayList<Integer>[] h, int[] vis, int n,int val1) {
        Queue<Integer> q = new LinkedList<Integer>();
        q.add(i1);Queue<Integer> aq=new LinkedList<Integer>();
        aq.add(0);
        while(!q.isEmpty()){
            int i=q.poll();
            int val=aq.poll();
            if(i==n){
                return val;
            }
            if(h[i]!=null){
                for(Integer j:h[i]){
                    if(vis[j]==0){
                        q.add(j);vis[j]=1;
                        aq.add(val+1);}
                }
            }
        }return -1;
    }
    static long gcd(long a, long b) {
        if (b == 0)
            return a;
        return gcd(b, a % b);
    }
    static long modInverse(long a, long m)
    {
        return (powerwithmod(a, m - 2, m));
    }
    static int MAXN;
    static int[] spf;
    static void sieve() {
        spf[1] = 1;
        for (int i=2; i<MAXN; i++)
            spf[i] = i;
        for (int i=4; i<MAXN; i+=2)
            spf[i] = 2;
        for (int i=3; i*i<MAXN; i++)
        {
            if (spf[i] == i)
            {
                for (int j=i*i; j<MAXN; j+=i)

                    if (spf[j]==j)
                        spf[j] = i;
            }
        }
    }
    static ArrayList<Integer> getFactorizationUsingSeive(int x) {
        ArrayList<Integer> ret = new ArrayList<Integer>();
        while (x != 1)
        {
            ret.add(spf[x]);
            if(spf[x]!=0)   x = x / spf[x];
            else break;       }
        return ret;
    }
    static long[] fac ;
    static void calculatefac(long mod){
        fac[0]=1;
        for (int i = 1 ;i <= MAXN; i++)
            fac[i] = fac[i-1] * i % mod;
    }
    static long nCrModPFermat(int n, int r, long mod) {
        if (r == 0)
            return 1;
        fac[0] = 1;
        return (fac[n]*
                modInverse(fac[r], mod)
                % mod * modInverse(fac[n-r], mod)
                % mod) % mod;
    } }
class Student {
    long  l;long r;long x;
    public Student(long l, long r,long x) {
        this.l = l;
        this.r = r;this.x=x;
    }

    public String toString()
    {
        return this.l+" ";
    }
}
class Sortbyroll implements Comparator<Student>
{

    public int compare(Student a, Student b){
        if(a.x<b.x) return -1;
        else if(a.x==b.x){
            if(a.r==b.r){
                return 0;
            }
            if(a.r<b.r) return -1;
            return 1;}
        return 1;  }
}
class Sortbyroll2 implements Comparator<Student>
{

    public int compare(Student a, Student b){
        try{
            if(a.l*b.r<b.l*a.r) return 1;
            return -1;}
        catch (IllegalArgumentException e){
            System.out.println("HI");
        }
        return 9;}
}