Problem: One day Ms Swan bought an orange in a shop. The orange consisted of n·k segments, numbered with integers from 1 to n·k. 

There were k children waiting for Ms Swan at home. The children have recently learned about the orange and they decided to divide it between them. For that each child took a piece of paper and wrote the number of the segment that he would like to get: the i-th (1 ≤ i ≤ k) child wrote the number ai (1 ≤ ai ≤ n·k). All numbers ai accidentally turned out to be different.

Now the children wonder, how to divide the orange so as to meet these conditions:

  * each child gets exactly n orange segments; 
  * the i-th child gets the segment with number ai for sure; 
  * no segment goes to two children simultaneously. 



Help the children, divide the orange and fulfill the requirements, described above.

Input

The first line contains two integers n, k (1 ≤ n, k ≤ 30). The second line contains k space-separated integers a1, a2, ..., ak (1 ≤ ai ≤ n·k), where ai is the number of the orange segment that the i-th child would like to get.

It is guaranteed that all numbers ai are distinct.

Output

Print exactly n·k distinct integers. The first n integers represent the indexes of the segments the first child will get, the second n integers represent the indexes of the segments the second child will get, and so on. Separate the printed numbers with whitespaces.

You can print a child's segment indexes in any order. It is guaranteed that the answer always exists. If there are multiple correct answers, print any of them.

Examples

Input

2 2
4 1


Output

2 4 
1 3 


Input

3 1
2


Output

3 2 1 

Solution (in PYTHON):

Solution:
def diff(first, second):
    second = set(second)
    return [item for item in first if item not in second]

n, k = [int(i) for i in raw_input().split()]
segments_wanted = [int(i) for i in raw_input().split()]

# each child gets exactly n orange segments
all_segments = [i for i in xrange(1, n*k + 1)]

unwanted = diff(all_segments, segments_wanted)

for seg in segments_wanted:
    res = [seg]
    count = n - 1
    for idx, i in enumerate(unwanted):
        if count <= 0:
            break
        if i == -1:
            continue
        
        res += [i]
        unwanted[idx] = -1
        count -= 1
    
    print ' '.join(map(str,res))