Problem: One day Ms Swan bought an orange in a shop. The orange consisted of n·k segments, numbered with integers from 1 to n·k. 

There were k children waiting for Ms Swan at home. The children have recently learned about the orange and they decided to divide it between them. For that each child took a piece of paper and wrote the number of the segment that he would like to get: the i-th (1 ≤ i ≤ k) child wrote the number ai (1 ≤ ai ≤ n·k). All numbers ai accidentally turned out to be different.

Now the children wonder, how to divide the orange so as to meet these conditions:

  * each child gets exactly n orange segments; 
  * the i-th child gets the segment with number ai for sure; 
  * no segment goes to two children simultaneously. 



Help the children, divide the orange and fulfill the requirements, described above.

Input

The first line contains two integers n, k (1 ≤ n, k ≤ 30). The second line contains k space-separated integers a1, a2, ..., ak (1 ≤ ai ≤ n·k), where ai is the number of the orange segment that the i-th child would like to get.

It is guaranteed that all numbers ai are distinct.

Output

Print exactly n·k distinct integers. The first n integers represent the indexes of the segments the first child will get, the second n integers represent the indexes of the segments the second child will get, and so on. Separate the printed numbers with whitespaces.

You can print a child's segment indexes in any order. It is guaranteed that the answer always exists. If there are multiple correct answers, print any of them.

Examples

Input

2 2
4 1


Output

2 4 
1 3 


Input

3 1
2


Output

3 2 1 

Solution (in JAVA):

Solution:

import java.util.*;
public class Contest{
    public static void main(String[] args) {
        
 Scanner s= new Scanner(System.in);
 int n= s.nextInt();
 int k= s.nextInt();
 int [] a= new int [k];
 String [] v= new String [k];
 boolean [] b= new boolean [n*k+1];
 
 for (int i=0; i<k; i++)
 {
     int x= s.nextInt();
     a[i]=x;
 }
 
 Arrays.fill(v, "");
 int y=n*k;
 for (int j= 0; j<k;j++)
 { v[j]+= a[j]+ " ";
   b[a[j]]= true;
     y--;
 }


 
 while (y>0)
 {
     for (int i=0; i<k; i++)
         for(int j=1; j<n*k+1; j++)
         {
             if(b[j]==false)
             {
                 b[j]= true;
                 v[i]+=j+ " ";
                 y--;
                 break;
             }
         }
 }
 
 for (int x=0; x<v.length;x++)
 {
     System.out.println(v[x]);
 }

    }
}