Problem: We have a tree with N vertices. The vertices are numbered 1, 2, ..., N. The i-th (1 ≦ i ≦ N - 1) edge connects the two vertices A_i and B_i.

Takahashi wrote integers into K of the vertices. Specifically, for each 1 ≦ j ≦ K, he wrote the integer P_j into vertex V_j. The remaining vertices are left empty. After that, he got tired and fell asleep.

Then, Aoki appeared. He is trying to surprise Takahashi by writing integers into all empty vertices so that the following condition is satisfied:

* Condition: For any two vertices directly connected by an edge, the integers written into these vertices differ by exactly 1.



Determine if it is possible to write integers into all empty vertices so that the condition is satisfied. If the answer is positive, find one specific way to satisfy the condition.

Constraints

* 1 ≦ N ≦ 10^5
* 1 ≦ K ≦ N
* 1 ≦ A_i, B_i ≦ N (1 ≦ i ≦ N - 1)
* 1 ≦ V_j ≦ N (1 ≦ j ≦ K) (21:18, a mistake in this constraint was corrected)
* 0 ≦ P_j ≦ 10^5 (1 ≦ j ≦ K)
* The given graph is a tree.
* All v_j are distinct.

Input

The input is given from Standard Input in the following format:


N
A_1 B_1
A_2 B_2
:
A_{N-1} B_{N-1}
K
V_1 P_1
V_2 P_2
:
V_K P_K


Output

If it is possible to write integers into all empty vertices so that the condition is satisfied, print `Yes`. Otherwise, print `No`.

If it is possible to satisfy the condition, print N lines in addition. The v-th (1 ≦ v ≦ N) of these N lines should contain the integer that should be written into vertex v. If there are multiple ways to satisfy the condition, any of those is accepted.

Examples

Input

5
1 2
3 1
4 3
3 5
2
2 6
5 7


Output

Yes
5
6
6
5
7


Input

5
1 2
3 1
4 3
3 5
3
2 6
4 3
5 7


Output

No


Input

4
1 2
2 3
3 4
1
1 0


Output

Yes
0
-1
-2
-3

Solution (in JAVA):

Solution:
import java.io.*;
import java.lang.*;
import java.util.*;

public class Main {

	static boolean debug = false;

	public static void main(String[] args) throws IOException {
		BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
		int N = Integer.parseInt(reader.readLine());
		Tree tree = new Tree(N);
		for (int j = 0; j < N - 1; j++) {
			String[] xy = reader.readLine().split("\\s");
			int x = Integer.parseInt(xy[0]) - 1, y = Integer.parseInt(xy[1]) - 1;
			tree.insert(x, y);
			tree.insert(y, x);
		}
		int K = Integer.parseInt(reader.readLine()), start = 0;
		Color[] color = new Color[N];
		for (int j = 0; j < K; j++) {
			String[] vp = reader.readLine().split("\\s");
			int v = Integer.parseInt(vp[0]) - 1;
			color[v] = new Color(Integer.parseInt(vp[1]), 1);
			start = v;
		}
		PrintWriter pw = new PrintWriter(System.out);
		if (solve(tree, color, -1, start)) {
			pw.println("Yes");
			paint(tree, color, -1, start);
			for (int j = 0; j < N; j++)
				pw.println(color[j].start);
		}
		else
			pw.println("No");
		pw.close();
	}

	private static void paint(Tree tree, Color[] color, int parent, int node) {
		Node child = tree.first(node);
		if (color[node].count > 1) {
			if (color[node].start < color[parent].start)
				color[node].start = color[parent].start - 1;
			else
				color[node].start = color[parent].start + 1;
		}
		while (child != null) {
			if (child.node != parent)
				paint(tree, color, node, child.node);
			child = tree.next(child);
		}
	}

	private static boolean solve(Tree tree, Color[] color, int parent, int node) {
		if (debug) System.out.println(String.format("solve(tree, color, %d, %d)", parent, node));
		if (color[node] == null)
			color[node] = color[parent].expand();
		Node child = tree.first(node);
		while (child != null) {
			if (child.node != parent) {
				if (!solve(tree, color, node, child.node))
					return false;
				color[node] = merge(color[node], color[child.node]);
				if (color[node] == null)
					return false;
			}
			child = tree.next(child);
		}
		return true;
	}

	private static Color merge(Color current, Color child) {
		if (debug) System.out.println(String.format("merge(current: [%d, %d] with child: [%d, %d])",
			current.start, current.count, child.start, child.count));
		Color merge;
		if (current.start % 2 == child.start % 2)
			merge = null;
		Color expand = child.expand();
		long start = Math.max(expand.start, current.start);
		long end = Math.min(current.start + 2 * (current.count - 1), expand.start + 2 * (expand.count - 1));
		merge = new Color(start, (int) (end - start + 2) / 2);
		if (merge.count <= 0)
			merge = null;
		if (debug) System.out.println(merge != null ? String.format("merge result: [%d, %d]", merge.start, merge.count) : "merge result: [null]");
		return merge;
	}

	static class Color {
		long start;
		int count;

		public Color(long start, int count) {
			this.start = start;
			this.count = count;
		}

		public Color expand() {
			 return new Color(start - 1, count + 1);
		}
	}

	static class Tree {
		
		private Node[] tree;
		private int[] last;
		private int current;

		public Tree(int N) {
			tree = new Node[2 * N + 1];
			last = new int[N];
			current = 1;
		}

		public Node next(Node node) {
			return node.next > 0
				? tree[node.next]
				: null;
		}
		public Node first(int node) {
			return tree[last[node]];
		}

		public void insert(int x, int y) {
			tree[current] = new Node(x, last[y]);
			last[y] = current++;
		}

	}
	static class Node {
		int node, next;

		public Node(int node, int next) {
			this.node = node;
			this.next = next;
		}
	}

}