Problem: You are given a string t consisting of n lowercase Latin letters and an integer number k.

Let's define a substring of some string s with indices from l to r as s[l ... r].

Your task is to construct such string s of minimum possible length that there are exactly k positions i such that s[i ... i + n - 1] = t. In other words, your task is to construct such string s of minimum possible length that there are exactly k substrings of s equal to t.

It is guaranteed that the answer is always unique.

Input

The first line of the input contains two integers n and k (1 ≤ n, k ≤ 50) — the length of the string t and the number of substrings.

The second line of the input contains the string t consisting of exactly n lowercase Latin letters.

Output

Print such string s of minimum possible length that there are exactly k substrings of s equal to t.

It is guaranteed that the answer is always unique.

Examples

Input

3 4
aba


Output

ababababa


Input

3 2
cat


Output

catcat

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
const int maxn = 1e6 + 7;
const int inf = INT_MAX;
const long long inff = 1e18;
const int mod = 1e9 + 7;
string s;
int32_t main() {
  ios::sync_with_stdio(0);
  cin.tie(0);
  cout.tie(0);
  int n, k;
  cin >> n >> k;
  cin >> s;
  int nn = 0;
  for (int j = 1; j < n; j++) {
    bool flag = 1;
    for (int i = 0; i < n - j; i++) {
      if (s[i] != s[i + j]) {
        flag = 0;
        break;
      }
    }
    if (flag) {
      nn = j;
      break;
    }
  }
  cout << s;
  if (nn == 0) nn = n;
  for (int i = 2; i <= k; i++) {
    for (int j = n - nn; j < n; j++) cout << s[j];
  }
  cout << endl;
}