Problem: One day Ms Swan bought an orange in a shop. The orange consisted of n·k segments, numbered with integers from 1 to n·k. 

There were k children waiting for Ms Swan at home. The children have recently learned about the orange and they decided to divide it between them. For that each child took a piece of paper and wrote the number of the segment that he would like to get: the i-th (1 ≤ i ≤ k) child wrote the number ai (1 ≤ ai ≤ n·k). All numbers ai accidentally turned out to be different.

Now the children wonder, how to divide the orange so as to meet these conditions:

  * each child gets exactly n orange segments; 
  * the i-th child gets the segment with number ai for sure; 
  * no segment goes to two children simultaneously. 



Help the children, divide the orange and fulfill the requirements, described above.

Input

The first line contains two integers n, k (1 ≤ n, k ≤ 30). The second line contains k space-separated integers a1, a2, ..., ak (1 ≤ ai ≤ n·k), where ai is the number of the orange segment that the i-th child would like to get.

It is guaranteed that all numbers ai are distinct.

Output

Print exactly n·k distinct integers. The first n integers represent the indexes of the segments the first child will get, the second n integers represent the indexes of the segments the second child will get, and so on. Separate the printed numbers with whitespaces.

You can print a child's segment indexes in any order. It is guaranteed that the answer always exists. If there are multiple correct answers, print any of them.

Examples

Input

2 2
4 1


Output

2 4 
1 3 


Input

3 1
2


Output

3 2 1 

Solution (in JAVA):

Solution:
import java.util.Scanner;

public class A244 {
	public static void main (String args[]){
		Scanner in = new Scanner(System.in);
		int n = in.nextInt();
		int k = in.nextInt();
		int a[] = new int[k];
		boolean b[] = new boolean [n*k];
		for(int i = 0 ; i < k ; i++){
			a[i]=in.nextInt();
			b[a[i]-1]=true;
		}
		
		int index = 0;
		for(int i = 0 ; i < k ;i++){
			int c = 0;
			if(n > 0)
				System.out.print(a[i]+" ");
			else
				System.out.print(a[i]);
			c++;
			for(int j = index ; j < n*k ; j++){
				if(!b[j] && c < n){
					c++;
					b[j]=true;
					if(c < n)
						System.out.print((j+1)+" ");
					else
						System.out.print(j+1);
				}
				index = j;
				if(c >= n)
					break;
			}
			System.out.println();
		}
	}
}