Problem: It's time polar bears Menshykov and Uslada from the zoo of St. Petersburg and elephant Horace from the zoo of Kiev got down to business. In total, there are n tasks for the day and each animal should do each of these tasks. For each task, they have evaluated its difficulty. Also animals decided to do the tasks in order of their difficulty. Unfortunately, some tasks can have the same difficulty, so the order in which one can perform the tasks may vary.

Menshykov, Uslada and Horace ask you to deal with this nuisance and come up with individual plans for each of them. The plan is a sequence describing the order in which an animal should do all the n tasks. Besides, each of them wants to have its own unique plan. Therefore three plans must form three different sequences. You are to find the required plans, or otherwise deliver the sad news to them by stating that it is impossible to come up with three distinct plans for the given tasks.

Input

The first line contains integer n (1 ≤ n ≤ 2000) — the number of tasks. The second line contains n integers h1, h2, ..., hn (1 ≤ hi ≤ 2000), where hi is the difficulty of the i-th task. The larger number hi is, the more difficult the i-th task is.

Output

In the first line print "YES" (without the quotes), if it is possible to come up with three distinct plans of doing the tasks. Otherwise print in the first line "NO" (without the quotes). If three desired plans do exist, print in the second line n distinct integers that represent the numbers of the tasks in the order they are done according to the first plan. In the third and fourth line print two remaining plans in the same form.

If there are multiple possible answers, you can print any of them.

Examples

Input

4
1 3 3 1


Output

YES
1 4 2 3 
4 1 2 3 
4 1 3 2 


Input

5
2 4 1 4 8


Output

NO

Note

In the first sample the difficulty of the tasks sets one limit: tasks 1 and 4 must be done before tasks 2 and 3. That gives the total of four possible sequences of doing tasks : [1, 4, 2, 3], [4, 1, 2, 3], [1, 4, 3, 2], [4, 1, 3, 2]. You can print any three of them in the answer.

In the second sample there are only two sequences of tasks that meet the conditions — [3, 1, 2, 4, 5] and [3, 1, 4, 2, 5]. Consequently, it is impossible to make three distinct sequences of tasks.

Solution (in JAVA):

Solution:
/*
 * To change this license header, choose License Headers in Project Properties.
 * To change this template file, choose Tools | Templates
 * and open the template in the editor.
 */
/**
 *
 * @author Administrator
 */
import java.util.*;
import java.io.*;
import java.math.*;
import java.awt.geom.*;

import static java.lang.Math.*;

public class Rd269B implements Runnable {

    public void solve() throws Exception {
        int n = sc.nextInt();
        int[] ar = new int[n];
        for(int i = 0; i < n; i++)
            ar[i] = sc.nextInt();
        helper(ar);
        

    }
    public void helper(int[] ar){
        int len = ar.length;
        int n = 2000;
        int[] hp = new int[n];
        for(int i = 0; i < len; i++)
            hp[ar[i] - 1]++;
        int tot = 0;
        for(int i = 0; i < n; i++) {
            if(hp[i] != 0) {
                tot = tot + hp[i] * (hp[i] - 1);
            }
            if(tot > 3)
                break;
        }
        if(tot < 3) {
            System.out.println("NO");
            return;
        }
        int[] ind = new int[len];
        for(int i = 0; i < len; i++)
            ind[i] = i + 1;
        
        sorthp(ar, ind);
        System.out.println("YES");
        int cn = 0;
        for(int i = 0; i < len; i++)
            for(int j = i + 1; j < len; j++) {
                if(ar[i] == ar[j]) {
                    if(cn < 3) {
                        int temp = ind[i];
                        ind[i] = ind[j];
                        ind[j] = temp;
                        for(int k = 0; k < len; k++) {
                            System.out.print(ind[k] + " ");
                        }
                        System.out.println();
                        cn++;
                    }
                    else 
                        return;
                    if(cn < 3) {
                        int temp = ind[i];
                        ind[i] = ind[j];
                        ind[j] = temp;
                        for(int k = 0; k < len; k++) {
                            System.out.print(ind[k] + " ");
                        }
                        System.out.println();
                        cn++;
                        
                    }
                    else
                        return;
                    
                }
            }
    }
    public void sorthp(int[] ar, int[] ind){
        int len = ar.length;
        for(int i = 0; i < len; i++)
            for(int j = i + 1; j < len; j++)
                if(ar[i] > ar[j]) {
                    int tp = ar[i];
                    ar[i] = ar[j];
                    ar[j] = tp;
                    tp = ind[i];
                    ind[i] = ind[j];
                    ind[j] = tp;
                }
        
        
        
        
    }
    
    static Throwable uncaught;

    BufferedReader in;
    FastScanner sc;
    PrintWriter out;

    @Override
    public void run() {
        try {
            in = new BufferedReader(new InputStreamReader(System.in));
            out = new PrintWriter(System.out);
            sc = new FastScanner(in);
            solve();
        } catch (Throwable uncaught) {
            Rd269B.uncaught = uncaught;
        } finally {
            out.close();
        }
    }

    public static void main(String[] args) throws Throwable {
        Thread thread = new Thread(null, new Rd269B(), "", (1 << 26));
        thread.start();
        thread.join();
        if (Rd269B.uncaught != null) {
            throw Rd269B.uncaught;
        }
    }

}


class FastScanner {

    BufferedReader in;
    StringTokenizer st;

    public FastScanner(BufferedReader in) {
        this.in = in;
    }

    public String nextToken() throws Exception {
        while (st == null || !st.hasMoreTokens()) {
            st = new StringTokenizer(in.readLine());
        }
        return st.nextToken();
    }

    public int nextInt() throws Exception {
        return Integer.parseInt(nextToken());
    }

    public long nextLong() throws Exception {
        return Long.parseLong(nextToken());
    }

    public double nextDouble() throws Exception {
        return Double.parseDouble(nextToken());
    }

}