Problem: Alice, the president of club FCB, wants to build a team for the new volleyball tournament. The team should consist of p players playing in p different positions. She also recognizes the importance of audience support, so she wants to select k people as part of the audience.

There are n people in Byteland. Alice needs to select exactly p players, one for each position, and exactly k members of the audience from this pool of n people. Her ultimate goal is to maximize the total strength of the club.

The i-th of the n persons has an integer a_{i} associated with him — the strength he adds to the club if he is selected as a member of the audience.

For each person i and for each position j, Alice knows s_{i, j} — the strength added by the i-th person to the club if he is selected to play in the j-th position.

Each person can be selected at most once as a player or a member of the audience. You have to choose exactly one player for each position.

Since Alice is busy, she needs you to help her find the maximum possible strength of the club that can be achieved by an optimal choice of players and the audience.

Input

The first line contains 3 integers n,p,k (2 ≤ n ≤ 10^{5}, 1 ≤ p ≤ 7, 1 ≤ k, p+k ≤ n).

The second line contains n integers a_{1},a_{2},…,a_{n}. (1 ≤ a_{i} ≤ 10^{9}).

The i-th of the next n lines contains p integers s_{i, 1}, s_{i, 2}, ..., s_{i, p}. (1 ≤ s_{i,j} ≤ 10^{9})

Output

Print a single integer {res} — the maximum possible strength of the club.

Examples

Input


4 1 2
1 16 10 3
18
19
13
15


Output


44


Input


6 2 3
78 93 9 17 13 78
80 97
30 52
26 17
56 68
60 36
84 55


Output


377


Input


3 2 1
500 498 564
100002 3
422332 2
232323 1


Output


422899

Note

In the first sample, we can select person 1 to play in the 1-st position and persons 2 and 3 as audience members. Then the total strength of the club will be equal to a_{2}+a_{3}+s_{1,1}.

Solution (in JAVA):

Solution:
import java.io.*; 
import java.util.*; 
//import javafx.util.*; 
import java.math.*;
//import java.lang.*;
public class Main 
{ 
    
    // static int n;
    // static int n;
    // static int parent[];
    // static int size[];
    // static long ans[];
    // static int arr[];
    static HashSet<Integer> adj[];
    static boolean vis[];
    static long mod=1000000007;
    static final long oo=(long)1e18;
    static long w[];
    static int v[];
  //  static Long dp[][];
    static int n;
    public static void main(String[] args) throws IOException { 
        PrintWriter pw = new PrintWriter(new BufferedWriter(new OutputStreamWriter(System.out)));
        br = new BufferedReader(new InputStreamReader(System.in));
        //int test=nextInt();
        int test=1;
        outer:while(test-->0){
            int n=nextInt();
            int p=nextInt();
            int k=nextInt();
            Pair arr[]=new Pair[n];
            for(int i=0;i<n;i++){
                int a=nextInt();
                arr[i]=new Pair(i,a);
            }
            Arrays.sort(arr);
            int s[][]=new int[n][p];
            for(int i=0;i<n;i++){
                for(int j=0;j<p;j++){
                    s[i][j]=nextInt();
                }
            }
            long dp[][]=new long[n+1][1<<p];
            for(int i=0;i<n;i++){
                Arrays.fill(dp[i],Long.MIN_VALUE);
            }
            dp[0][0]=0;
            for(int i=1;i<=n;i++){
                int pos=arr[i-1].x;
                for(int mask=0;mask<(1<<p);mask++){
                    int count=0;
                    for(int j=0;j<p;j++){
                        if((mask&(1<<j))==0){
                            dp[i][mask|(1<<j)]=Math.max(dp[i][mask|(1<<j)],dp[i-1][mask]+s[pos][j]);
                        }
                        else{
                            count++;
                        }
                    }
                    int a=i-1-count;
                    if(a>=k){
                        dp[i][mask]=Math.max(dp[i][mask],dp[i-1][mask]);
                    }
                    else{
                        dp[i][mask]=Math.max(dp[i][mask],(dp[i-1][mask]+arr[i-1].y));
                    }   

                }
            }
            pw.println(dp[n][(1<<p)-1]);
        }
        pw.close();
    }
    static class Pair implements Comparable<Pair>{
        int x;int y;
        Pair(int x,int y){
            this.x=x;
    
            this.y=y;
        }   
        public int compareTo(Pair p){
            return -1*(y-p.y);
        }
    }
    static long ncr(long n,long r){
        if(r==0)
            return 1;
        long val=ncr(n-1,r-1);
        val=(n*val)%mod;
        val=(val*modInverse(r,mod))%mod;
        return val;
    }
    public static BufferedReader br;
    public static StringTokenizer st;
    public static String next() {
        while (st == null || !st.hasMoreTokens()) {
           try{
                st = new StringTokenizer(br.readLine());
            }
            catch (Exception e){
                throw new RuntimeException(e);
            }
        }
        return st.nextToken();
    }
    public static Integer nextInt() {
        return Integer.parseInt(next());
    }
    public static Long nextLong() {
        return Long.parseLong(next());
    }
 
    public static Double nextDouble() {
        return Double.parseDouble(next());
    }
    public static int[] na(int n)throws IOException{
        int[] a = new int[n];
        for(int i = 0;i < n;i++)a[i] = nextInt();
        return a;
    }
    static class query implements Comparable<query>{
        int l,r,idx,block;
        static int len;
        query(int l,int r,int i){
            this.l=l;
            this.r=r;
            this.idx=i;
            this.block=l/len;
        }   
        public int compareTo(query a){
            return block==a.block?r-a.r:block-a.block;
        }
    }
    static boolean isPrime(int n) { 
        if (n <= 1) 
            return false; 
        if (n <= 3) 
            return true; 
        if (n % 2 == 0 ||  
            n % 3 == 0) 
            return false; 
      
        for (int i = 5; 
                 i * i <= n; i = i + 6) 
            if (n % i == 0 || 
                n % (i + 2) == 0) 
                return false; 
      
        return true; 
    } 
    static long gcd(long a, long b) { 
      if (b == 0) 
        return a; 
      return gcd(b, a % b);  
    }  
    static long power(long x, long y, long m){ 
        if (y == 0) 
            return 1;      
        long p = power(x, y / 2, m) % m; 
        p = (p * p) % m; 
      
        if (y % 2 == 0) 
            return p; 
        else
            return (x * p) % m; 
    }
    static long fast_pow(long base,long n,long M){
        if(n==0)
           return 1;
        if(n==1)
        return base;
        long halfn=fast_pow(base,n/2,M);
        if(n%2==0)
            return ( halfn * halfn ) % M;
        else
            return ( ( ( halfn * halfn ) % M ) * base ) % M;
    }
    static long modInverse(long n,long M){
        return fast_pow(n,M-2,M);
    }
}