Problem: You are given a string t consisting of n lowercase Latin letters and an integer number k.

Let's define a substring of some string s with indices from l to r as s[l ... r].

Your task is to construct such string s of minimum possible length that there are exactly k positions i such that s[i ... i + n - 1] = t. In other words, your task is to construct such string s of minimum possible length that there are exactly k substrings of s equal to t.

It is guaranteed that the answer is always unique.

Input

The first line of the input contains two integers n and k (1 ≤ n, k ≤ 50) — the length of the string t and the number of substrings.

The second line of the input contains the string t consisting of exactly n lowercase Latin letters.

Output

Print such string s of minimum possible length that there are exactly k substrings of s equal to t.

It is guaranteed that the answer is always unique.

Examples

Input

3 4
aba


Output

ababababa


Input

3 2
cat


Output

catcat

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
string s;
int f() {
  int len = s.size();
  for (int i = 1; i < len; ++i) {
    if (s.substr(i) == s.substr(0, len - i)) return len - i;
  }
  return 0;
}
int main() {
  int n, k;
  scanf("%d %d", &n, &k);
  cin >> s;
  int len = f();
  cout << s;
  for (int i = 1; i < k; ++i) cout << s.substr(len);
  cout << "\n";
  return 0;
}