Problem: You are given a string t consisting of n lowercase Latin letters and an integer number k.

Let's define a substring of some string s with indices from l to r as s[l ... r].

Your task is to construct such string s of minimum possible length that there are exactly k positions i such that s[i ... i + n - 1] = t. In other words, your task is to construct such string s of minimum possible length that there are exactly k substrings of s equal to t.

It is guaranteed that the answer is always unique.

Input

The first line of the input contains two integers n and k (1 ≤ n, k ≤ 50) — the length of the string t and the number of substrings.

The second line of the input contains the string t consisting of exactly n lowercase Latin letters.

Output

Print such string s of minimum possible length that there are exactly k substrings of s equal to t.

It is guaranteed that the answer is always unique.

Examples

Input

3 4
aba


Output

ababababa


Input

3 2
cat


Output

catcat

Solution (in JAVA):

Solution:
/*
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import java.util.*;
public class substr {
    public static void main(String[] args) {
	Scanner s = new Scanner(System.in);
	int n = s.nextInt();
	int k = s.nextInt();
	
	String t = s.next();
	int over = 0;
	
	for (int i = 0; i < n; i++)
	{
            if (t.endsWith(t.substring(0, i)))
                over = i;
	}
	for (int i = 0; i < k-1; i++)
            System.out.print(t.substring(0, n-over));
	System.out.println(t);
    }
}