Problem: You are given a string t consisting of n lowercase Latin letters and an integer number k.

Let's define a substring of some string s with indices from l to r as s[l ... r].

Your task is to construct such string s of minimum possible length that there are exactly k positions i such that s[i ... i + n - 1] = t. In other words, your task is to construct such string s of minimum possible length that there are exactly k substrings of s equal to t.

It is guaranteed that the answer is always unique.

Input

The first line of the input contains two integers n and k (1 ≤ n, k ≤ 50) — the length of the string t and the number of substrings.

The second line of the input contains the string t consisting of exactly n lowercase Latin letters.

Output

Print such string s of minimum possible length that there are exactly k substrings of s equal to t.

It is guaranteed that the answer is always unique.

Examples

Input

3 4
aba


Output

ababababa


Input

3 2
cat


Output

catcat

Solution (in JAVA):

Solution:

import java.io.*;
import java.util.StringTokenizer;

public class Main {
    private static final fast sc = new fast();
    private static final int OO = (int) 1e9 + 1;
    private static final BufferedWriter output = new BufferedWriter(new OutputStreamWriter(System.out));
    private static final double PI = (double) 22 / 7;
    private static final int[] dx4 = {0, 1, 0, -1}, dx = {0, 0, 1, -1, 1, -1, 1, -1};
    private static final int[] dy4 = {1, 0, -1, 0}, dy = {1, -1, 0, 0, 1, -1, -1, 1};
    //static void print6P{ System.out.printf("%8.6f\n"); }

    public static void main(String[] args) throws IOException {
        int n = sc.nextInt(), k = sc.nextInt();
        String s = sc.next();
        String ss = get(s);
        String r = s + "" + ss.repeat(Math.max(0, k - 1));
        output.write(r );
        output.close();
    }

    static String get(String s) throws IOException {
        String rr = s;
        for (int i = 1; i < s.length(); i++) {
            String r = s.substring(0, s.length() - i), ss = s.substring(i);
            ///output.write(r + " " + ss);
            if (ss.equals(r)) {
                rr = s.substring(s.length() - i);
                break;
            }
        }
        return rr;
    }

    static class fast {
        BufferedReader br;
        StringTokenizer st;

        public fast() {
            br = new BufferedReader(new InputStreamReader(System.in));
        }

        String next() {
            while (st == null || !st.hasMoreElements()) {
                try {
                    st = new StringTokenizer(br.readLine());
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
            return st.nextToken();
        }


        int nextInt() {
            return Integer.parseInt(next());
        }

        long nextLong() {
            return Long.parseLong(next());
        }

        double nextDouble() {
            return Double.parseDouble(next());
        }

        double nextFloat() {
            return Float.parseFloat(next());
        }

        String nextLine() {
            String str = "";
            try {
                str = br.readLine();
            } catch (IOException e) {
                e.printStackTrace();
            }
            return str;
        }
    }

    static class Pair implements Comparable<Pair> {
        int first;
        int second;

        Pair(int first, int second) {
            this.first = first;
            this.second = second;
        }

        @Override
        public int compareTo(Pair o) {
            return Double.compare(o.first, first);
        }
    }
}