Problem: There is a directed graph G with N vertices and M edges. The vertices are numbered 1, 2, \ldots, N, and for each i (1 \leq i \leq M), the i-th directed edge goes from Vertex x_i to y_i. G does not contain directed cycles.

Find the length of the longest directed path in G. Here, the length of a directed path is the number of edges in it.

Constraints

* All values in input are integers.
* 2 \leq N \leq 10^5
* 1 \leq M \leq 10^5
* 1 \leq x_i, y_i \leq N
* All pairs (x_i, y_i) are distinct.
* G does not contain directed cycles.

Input

Input is given from Standard Input in the following format:


N M
x_1 y_1
x_2 y_2
:
x_M y_M


Output

Print the length of the longest directed path in G.

Examples

Input

4 5
1 2
1 3
3 2
2 4
3 4


Output

3


Input

6 3
2 3
4 5
5 6


Output

2


Input

5 8
5 3
2 3
2 4
5 2
5 1
1 4
4 3
1 3


Output

3

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
vector <int> graph[100005];
int visited[100005];
int path[100005];
int dfs(int u){
	if(visited[u]==1){
		return path[u];
	}
	visited[u]=1;
	int i,l=graph[u].size(),p=1;
	for(i=0;i<l;i++){
		p=max(p,dfs(graph[u][i])+1);
	}
	return path[u]=p;
}
int main(){
	int i,n,m,u,v,ans=0;
	cin>>n>>m;
	for(i=0;i<m;i++){
		cin>>u>>v;
		graph[u].push_back(v);
	}
	for(i=1;i<=n;i++){
		if(visited[i]==0){
			ans=max(ans,dfs(i)-1);
		}
	}
	cout<<ans<<endl;
}