Problem: One day Ms Swan bought an orange in a shop. The orange consisted of n·k segments, numbered with integers from 1 to n·k. 

There were k children waiting for Ms Swan at home. The children have recently learned about the orange and they decided to divide it between them. For that each child took a piece of paper and wrote the number of the segment that he would like to get: the i-th (1 ≤ i ≤ k) child wrote the number ai (1 ≤ ai ≤ n·k). All numbers ai accidentally turned out to be different.

Now the children wonder, how to divide the orange so as to meet these conditions:

  * each child gets exactly n orange segments; 
  * the i-th child gets the segment with number ai for sure; 
  * no segment goes to two children simultaneously. 



Help the children, divide the orange and fulfill the requirements, described above.

Input

The first line contains two integers n, k (1 ≤ n, k ≤ 30). The second line contains k space-separated integers a1, a2, ..., ak (1 ≤ ai ≤ n·k), where ai is the number of the orange segment that the i-th child would like to get.

It is guaranteed that all numbers ai are distinct.

Output

Print exactly n·k distinct integers. The first n integers represent the indexes of the segments the first child will get, the second n integers represent the indexes of the segments the second child will get, and so on. Separate the printed numbers with whitespaces.

You can print a child's segment indexes in any order. It is guaranteed that the answer always exists. If there are multiple correct answers, print any of them.

Examples

Input

2 2
4 1


Output

2 4 
1 3 


Input

3 1
2


Output

3 2 1 

Solution (in PYTHON):

Solution:
####################################################
# -*- coding: utf-8 -*-
import sys

w = sys.stdout.write
read = sys.stdin.readline
reads = sys.stdin.read

def r(f=None):
    if f:
        return map(f, read().split())
    else:
        return read().split()

def rs(t,f=None):
    result = []
    result_append = result.append
    for i in xrange(t):
        if f:
            result_append(map(f, read().split()))
        else:
            result_append(list(read().split()))
    return result


####################################################
import math
sqrt = math.sqrt
from collections import deque


n, k = r(int)
ax = r(int)

i = 1
j = 1
while i <= k:
    w("%s " % ax[i-1])
    h = 1
    while h < n:
        if j not in ax:
            w("%s " % j)
            h += 1
        j += 1
    w("\n")
    i += 1