Problem: Notes

Template in C

Constraints

* 1 ≤ n ≤ 100000
* 1 ≤ q ≤ 1000
* 1 ≤ timei ≤ 50000
* 1 ≤ length of namei ≤ 10
* 1 ≤ Sum of timei ≤ 1000000

Input

n q
name1 time1
name2 time2
...
namen timen


In the first line the number of processes n and the quantum q are given separated by a single space.

In the following n lines, names and times for the n processes are given. namei and timei are separated by a single space.

Output

For each process, prints its name and the time the process finished in order.

Example

Input

5 100
p1 150
p2 80
p3 200
p4 350
p5 20


Output

p2 180
p5 400
p1 450
p3 550
p4 800

Solution (in JAVA):

Solution:
import java.util.*;

public class Main {

	public static void main(String[] args) {
		
		Scanner in = new Scanner(System.in);
		int num = in.nextInt();
		int quantum = in.nextInt();
		
		Queue<String> names = new LinkedList<String>();
		Queue<Integer> times = new LinkedList<Integer>();
		
		for(int i = 0; i < num; i++) {
			names.add(in.next());
			times.add(in.nextInt());
		}
		
		int totTime = 0;
		Queue<String> resultNames = new LinkedList<String>();
		Queue<Integer> resultTimes = new LinkedList<Integer>();
		
		while(!names.isEmpty()) {
			
			int tempTime = times.remove();
			
			if(tempTime <= quantum) {
				
				totTime += tempTime;
				resultNames.add(names.remove());
				resultTimes.add(totTime);
				
			} else {
				
				totTime += quantum;
				names.add(names.remove());
				times.add(tempTime - quantum);
				
			}
		}
		
		for(int i = 0; i < num; i++) {
			
			System.out.println(resultNames.remove() + " " + resultTimes.remove());
			
		}
		
		in.close();
		
	}

}