Problem: You are given two circles. Find the area of their intersection.

Input

The first line contains three integers x1, y1, r1 ( - 109 ≤ x1, y1 ≤ 109, 1 ≤ r1 ≤ 109) — the position of the center and the radius of the first circle.

The second line contains three integers x2, y2, r2 ( - 109 ≤ x2, y2 ≤ 109, 1 ≤ r2 ≤ 109) — the position of the center and the radius of the second circle.

Output

Print the area of the intersection of the circles. The answer will be considered correct if the absolute or relative error doesn't exceed 10 - 6.

Examples

Input

0 0 4
6 0 4


Output

7.25298806364175601379


Input

0 0 5
11 0 5


Output

0.00000000000000000000

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
long double min(long double a, long double b) { return a < b ? a : b; }
long double tri(long double a, long double b, long double c) {
  long double s = (a + b + c) / 2;
  return sqrt(s * (s - a) * (s - b) * (s - c));
}
long double dist(long double x1, long double y1, long double x2,
                 long double y2) {
  long double dx = x2 - x1;
  long double dy = y2 - y1;
  return sqrt(dx * dx + dy * dy);
}
long double area(long double x1, long double y1, long double r1, long double x2,
                 long double y2, long double r2) {
  long double d = dist(x1, y1, x2, y2);
  if (d >= (r1 + r2)) return 0;
  if (d <= abs(r1 - r2)) return 3.14159265358979323846 * min(r1 * r1, r2 * r2);
  long double t1 = 2 * acos((r2 * r2 + d * d - r1 * r1) / (2 * r2 * d));
  long double t2 = 2 * acos((r1 * r1 + d * d - r2 * r2) / (2 * r1 * d));
  long double a1 = .5 * t1 * r2 * r2 - .5 * r2 * r2 * sin(t1);
  long double a2 = .5 * t2 * r1 * r1 - .5 * r1 * r1 * sin(t2);
  return a1 + a2;
}
int main() {
  long double x1, y1, r1;
  long double x2, y2, r2;
  cin >> x1 >> y1 >> r1 >> x2 >> y2 >> r2;
  cout << setprecision(32) << area(x1, y1, r1, x2, y2, r2);
  return 0;
}