Problem: One day Ms Swan bought an orange in a shop. The orange consisted of n·k segments, numbered with integers from 1 to n·k. 

There were k children waiting for Ms Swan at home. The children have recently learned about the orange and they decided to divide it between them. For that each child took a piece of paper and wrote the number of the segment that he would like to get: the i-th (1 ≤ i ≤ k) child wrote the number ai (1 ≤ ai ≤ n·k). All numbers ai accidentally turned out to be different.

Now the children wonder, how to divide the orange so as to meet these conditions:

  * each child gets exactly n orange segments; 
  * the i-th child gets the segment with number ai for sure; 
  * no segment goes to two children simultaneously. 



Help the children, divide the orange and fulfill the requirements, described above.

Input

The first line contains two integers n, k (1 ≤ n, k ≤ 30). The second line contains k space-separated integers a1, a2, ..., ak (1 ≤ ai ≤ n·k), where ai is the number of the orange segment that the i-th child would like to get.

It is guaranteed that all numbers ai are distinct.

Output

Print exactly n·k distinct integers. The first n integers represent the indexes of the segments the first child will get, the second n integers represent the indexes of the segments the second child will get, and so on. Separate the printed numbers with whitespaces.

You can print a child's segment indexes in any order. It is guaranteed that the answer always exists. If there are multiple correct answers, print any of them.

Examples

Input

2 2
4 1


Output

2 4 
1 3 


Input

3 1
2


Output

3 2 1 

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.*;

public class CodeForces {
    static boolean ONLINE_JUDGE = System.getProperty("ONLINE_JUDGE") != null;


    void runCase(int caseNum) throws IOException {
        int n = nextInt();
        int k = nextInt();

        int[] a = new int[k];
        boolean[] taken = new boolean[n * k];
        for (int i = 0; i < k; ++i) {
            int t = nextInt();
            a[i] = t;
            taken[t - 1] = true;
        }

        int p = 0;
        for (int i = 0; i < k; ++i) {
            for (int j = 0; j < n - 1; ++j) {
                while (taken[p]) ++p;
                out.print(p + 1);
                out.print(" ");
                ++p;
            }
            out.print(a[i]);
            out.print(" ");
        }
        out.println();
    }


    public static void main(String[] args) throws IOException {
        if (ONLINE_JUDGE){
            System.out.println();
            in = new BufferedReader(new InputStreamReader(System.in));
            out = new PrintWriter(System.out);
        }else{
            in = new BufferedReader(new FileReader("input.txt"));
            out = new PrintWriter("output.txt");
        }
        new CodeForces().runIt();
        out.flush();
        out.close();
        return;
    }

    static BufferedReader in;
    private StringTokenizer st;
    static PrintWriter out;

    String next() throws IOException {
        while (!st.hasMoreTokens()) {
            String line = in.readLine();
            if (line == null) {
                return null;
            }
            st = new StringTokenizer(line);
        }
        return st.nextToken();
    }

    int nextInt() throws IOException {
        return Integer.parseInt(next());
    }

    double nextDouble() throws IOException {
        return Double.parseDouble(next());
    }

    long nextLong() throws IOException {
        return Long.parseLong(next());
    }


    void runIt() throws IOException {
        st = new StringTokenizer("");

//        int N = nextInt();
//        for (int i = 0; i < N; i++) {
//            runCase(i + 1);
//        }
        runCase(0);
        out.flush();
    }

}