Problem: You are given a string t consisting of n lowercase Latin letters and an integer number k.

Let's define a substring of some string s with indices from l to r as s[l ... r].

Your task is to construct such string s of minimum possible length that there are exactly k positions i such that s[i ... i + n - 1] = t. In other words, your task is to construct such string s of minimum possible length that there are exactly k substrings of s equal to t.

It is guaranteed that the answer is always unique.

Input

The first line of the input contains two integers n and k (1 ≤ n, k ≤ 50) — the length of the string t and the number of substrings.

The second line of the input contains the string t consisting of exactly n lowercase Latin letters.

Output

Print such string s of minimum possible length that there are exactly k substrings of s equal to t.

It is guaranteed that the answer is always unique.

Examples

Input

3 4
aba


Output

ababababa


Input

3 2
cat


Output

catcat

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int k;
string s;
void read() {
  int dummy;
  cin >> dummy >> k >> s;
}
void work() {
  for (int len = s.size() - 1; len >= 1; --len) {
    if (s.substr(0, len) == s.substr(s.size() - len)) {
      cout << s;
      for (int i = 0; i < k - 1; ++i) {
        cout << s.substr(len);
      }
      cout << endl;
      return;
    }
  }
  for (int i = 0; i < k; ++i) {
    cout << s;
  }
  cout << endl;
}
int main() {
  read();
  work();
  return 0;
}