Problem: One day Ms Swan bought an orange in a shop. The orange consisted of n·k segments, numbered with integers from 1 to n·k. 

There were k children waiting for Ms Swan at home. The children have recently learned about the orange and they decided to divide it between them. For that each child took a piece of paper and wrote the number of the segment that he would like to get: the i-th (1 ≤ i ≤ k) child wrote the number ai (1 ≤ ai ≤ n·k). All numbers ai accidentally turned out to be different.

Now the children wonder, how to divide the orange so as to meet these conditions:

  * each child gets exactly n orange segments; 
  * the i-th child gets the segment with number ai for sure; 
  * no segment goes to two children simultaneously. 



Help the children, divide the orange and fulfill the requirements, described above.

Input

The first line contains two integers n, k (1 ≤ n, k ≤ 30). The second line contains k space-separated integers a1, a2, ..., ak (1 ≤ ai ≤ n·k), where ai is the number of the orange segment that the i-th child would like to get.

It is guaranteed that all numbers ai are distinct.

Output

Print exactly n·k distinct integers. The first n integers represent the indexes of the segments the first child will get, the second n integers represent the indexes of the segments the second child will get, and so on. Separate the printed numbers with whitespaces.

You can print a child's segment indexes in any order. It is guaranteed that the answer always exists. If there are multiple correct answers, print any of them.

Examples

Input

2 2
4 1


Output

2 4 
1 3 


Input

3 1
2


Output

3 2 1 

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.*;

public class A {
    public static void main(String[] args) throws Exception {
        new A().solve();
    }

    void solve() throws IOException {
        // BufferedReader in = new BufferedReader(new
        // InputStreamReader(System.in));
        Scanner sc = new Scanner(System.in);
        int n = sc.nextInt();
        int k = sc.nextInt();
        LinkedList<Integer> list = new LinkedList<Integer>();
        for (int i = 0; i < n * k; i++) {
            list.add(i);
        }
        int[] a = new int[k];
        for (int i = 0; i < k; i++) {
            a[i] = sc.nextInt() - 1;
            list.remove(Integer.valueOf(a[i]));
        }

        for (int i = 0; i < k; i++) {
            for (int jj = 0; jj < n - 1; jj++) {
                System.out.print((list.poll() + 1) + " ");
            }
            System.out.println(a[i] + 1);
        }
    }
}

// ?????