Problem: One day Ms Swan bought an orange in a shop. The orange consisted of n·k segments, numbered with integers from 1 to n·k. 

There were k children waiting for Ms Swan at home. The children have recently learned about the orange and they decided to divide it between them. For that each child took a piece of paper and wrote the number of the segment that he would like to get: the i-th (1 ≤ i ≤ k) child wrote the number ai (1 ≤ ai ≤ n·k). All numbers ai accidentally turned out to be different.

Now the children wonder, how to divide the orange so as to meet these conditions:

  * each child gets exactly n orange segments; 
  * the i-th child gets the segment with number ai for sure; 
  * no segment goes to two children simultaneously. 



Help the children, divide the orange and fulfill the requirements, described above.

Input

The first line contains two integers n, k (1 ≤ n, k ≤ 30). The second line contains k space-separated integers a1, a2, ..., ak (1 ≤ ai ≤ n·k), where ai is the number of the orange segment that the i-th child would like to get.

It is guaranteed that all numbers ai are distinct.

Output

Print exactly n·k distinct integers. The first n integers represent the indexes of the segments the first child will get, the second n integers represent the indexes of the segments the second child will get, and so on. Separate the printed numbers with whitespaces.

You can print a child's segment indexes in any order. It is guaranteed that the answer always exists. If there are multiple correct answers, print any of them.

Examples

Input

2 2
4 1


Output

2 4 
1 3 


Input

3 1
2


Output

3 2 1 

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.PrintWriter;

import java.io.InputStreamReader;

import java.io.IOException;

import java.util.StringTokenizer;

import java.util.LinkedList;

public class Main {
    
    static Scanner in = new Scanner();
    static PrintWriter out = new PrintWriter(System.out);
    
    public static void main(String[] args) throws IOException {
        LinkedList<Integer> list = new LinkedList<Integer>();
        int n = in.nextInt(), k = in.nextInt(), m = n * k + 1, l[] = new int[k];
        boolean[] b = new boolean[m];
        for(int i = 0; i < k; i++)
            b[(l[i] = in.nextInt())] = true;
        for(int i = 1; i < m; i++)
            if(!b[i])
                list.add(i);
        for(int i = 0; i < k; i++) {
            for(int j = 1; j < n; j++)
                out.print(list.remove() + " ");
            out.println(l[i]);
        }
        out.close();
    }
    
    static class Scanner {
        BufferedReader br;
        StringTokenizer st;
        
        public Scanner() {
            br = new BufferedReader(new InputStreamReader(System.in));
            st = new StringTokenizer("");
        }
        
        public String next() throws IOException {
            if(!st.hasMoreTokens())
                st = new StringTokenizer(br.readLine());
            return st.nextToken();
        }
        
        public String nextLine() throws IOException {
            if(!st.hasMoreTokens())
                st = new StringTokenizer(br.readLine());
            String r = st.nextToken("\n");
            st = new StringTokenizer(br.readLine(), " ");
            return r;
        }
        
        public int nextInt() throws IOException {
            return Integer.parseInt(next());
        }
        
        public long nextLong() throws IOException {
            return Long.parseLong(next());
        }
    }
}