Problem: You are given a string t consisting of n lowercase Latin letters and an integer number k.

Let's define a substring of some string s with indices from l to r as s[l ... r].

Your task is to construct such string s of minimum possible length that there are exactly k positions i such that s[i ... i + n - 1] = t. In other words, your task is to construct such string s of minimum possible length that there are exactly k substrings of s equal to t.

It is guaranteed that the answer is always unique.

Input

The first line of the input contains two integers n and k (1 ≤ n, k ≤ 50) — the length of the string t and the number of substrings.

The second line of the input contains the string t consisting of exactly n lowercase Latin letters.

Output

Print such string s of minimum possible length that there are exactly k substrings of s equal to t.

It is guaranteed that the answer is always unique.

Examples

Input

3 4
aba


Output

ababababa


Input

3 2
cat


Output

catcat

Solution (in JAVA):

Solution:
import java.util.Scanner;

public class Main {
	public static void main(String[] args) {
		Scanner cin=new Scanner(System.in);
		int n=cin.nextInt(),k=cin.nextInt();
		String s=cin.next();
		int pos=0;
		for(int i=1;i<n;++i) {
			boolean flag=true;
			for(int j=0;j<n-i;++j) {
				if(s.charAt(i+j)!=s.charAt(j)) {
					flag=false;break;
				}
			}
			if(flag) {
				pos=n-i;break;
			}
		}
		System.out.print(s);
		for(int i=1;i<k;++i) {
			for(int j=pos;j<n;++j)System.out.print(s.charAt(j));
		}
		System.out.println();
	}
}