Problem: You are given a string t consisting of n lowercase Latin letters and an integer number k.

Let's define a substring of some string s with indices from l to r as s[l ... r].

Your task is to construct such string s of minimum possible length that there are exactly k positions i such that s[i ... i + n - 1] = t. In other words, your task is to construct such string s of minimum possible length that there are exactly k substrings of s equal to t.

It is guaranteed that the answer is always unique.

Input

The first line of the input contains two integers n and k (1 ≤ n, k ≤ 50) — the length of the string t and the number of substrings.

The second line of the input contains the string t consisting of exactly n lowercase Latin letters.

Output

Print such string s of minimum possible length that there are exactly k substrings of s equal to t.

It is guaranteed that the answer is always unique.

Examples

Input

3 4
aba


Output

ababababa


Input

3 2
cat


Output

catcat

Solution (in JAVA):

Solution:
import java.util.*;

public class second
{	
	static Scanner sc=new Scanner(System.in);
	public static void main(String[] args)
	{	int n=sc.nextInt();
		int k=sc.nextInt();
		String s=sc.next();
		int res=-1;
		for(int i=0;i<s.length();i++) {
			if(s.substring(0,i).equals(s.substring(s.length()-i))) res=i;
		}
		System.out.print(s);
		for(int i=0;i<k-1;i++) System.out.print(s.substring(res));
	}
}