Problem: One day Ms Swan bought an orange in a shop. The orange consisted of n·k segments, numbered with integers from 1 to n·k. 

There were k children waiting for Ms Swan at home. The children have recently learned about the orange and they decided to divide it between them. For that each child took a piece of paper and wrote the number of the segment that he would like to get: the i-th (1 ≤ i ≤ k) child wrote the number ai (1 ≤ ai ≤ n·k). All numbers ai accidentally turned out to be different.

Now the children wonder, how to divide the orange so as to meet these conditions:

  * each child gets exactly n orange segments; 
  * the i-th child gets the segment with number ai for sure; 
  * no segment goes to two children simultaneously. 



Help the children, divide the orange and fulfill the requirements, described above.

Input

The first line contains two integers n, k (1 ≤ n, k ≤ 30). The second line contains k space-separated integers a1, a2, ..., ak (1 ≤ ai ≤ n·k), where ai is the number of the orange segment that the i-th child would like to get.

It is guaranteed that all numbers ai are distinct.

Output

Print exactly n·k distinct integers. The first n integers represent the indexes of the segments the first child will get, the second n integers represent the indexes of the segments the second child will get, and so on. Separate the printed numbers with whitespaces.

You can print a child's segment indexes in any order. It is guaranteed that the answer always exists. If there are multiple correct answers, print any of them.

Examples

Input

2 2
4 1


Output

2 4 
1 3 


Input

3 1
2


Output

3 2 1 

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.util.StringTokenizer;

public class DividingOrange {

	public static void main(String[] args) {
		try {						
			BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
			StringTokenizer st = new StringTokenizer(br.readLine());
			int n = Integer.parseInt(st.nextToken());
			int k = Integer.parseInt(st.nextToken());
			String res[] = new String[k];
			int partes[] = new int[n*k];
			st = new StringTokenizer(br.readLine());			
			for(int i=0; i<k; i++) {								
				int p = Integer.parseInt(st.nextToken());
				res[i] = p + " ";
				partes[p-1] = 1;
			}
			for(int i=0; i<k; i++) {
				int q=0;
				int j=0;
				while(j<n-1) {
					if(partes[q]==0) {
						partes[q] = 1;
						res[i] += (q+1) + " ";
						j++;
					}
					q++;
				}
			}
			for(int i=0; i<k; i++) {
				System.out.println(res[i]);
			}
			br.close();
		} catch (Exception e) {
			e.printStackTrace();
		}
	}
	
}