Problem: One day Ms Swan bought an orange in a shop. The orange consisted of n·k segments, numbered with integers from 1 to n·k. 

There were k children waiting for Ms Swan at home. The children have recently learned about the orange and they decided to divide it between them. For that each child took a piece of paper and wrote the number of the segment that he would like to get: the i-th (1 ≤ i ≤ k) child wrote the number ai (1 ≤ ai ≤ n·k). All numbers ai accidentally turned out to be different.

Now the children wonder, how to divide the orange so as to meet these conditions:

  * each child gets exactly n orange segments; 
  * the i-th child gets the segment with number ai for sure; 
  * no segment goes to two children simultaneously. 



Help the children, divide the orange and fulfill the requirements, described above.

Input

The first line contains two integers n, k (1 ≤ n, k ≤ 30). The second line contains k space-separated integers a1, a2, ..., ak (1 ≤ ai ≤ n·k), where ai is the number of the orange segment that the i-th child would like to get.

It is guaranteed that all numbers ai are distinct.

Output

Print exactly n·k distinct integers. The first n integers represent the indexes of the segments the first child will get, the second n integers represent the indexes of the segments the second child will get, and so on. Separate the printed numbers with whitespaces.

You can print a child's segment indexes in any order. It is guaranteed that the answer always exists. If there are multiple correct answers, print any of them.

Examples

Input

2 2
4 1


Output

2 4 
1 3 


Input

3 1
2


Output

3 2 1 

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.*;

import static java.lang.Math.max;
import static java.lang.Math.min;

public class Code implements Runnable {
    public static void main(String[] args) throws IOException {
        new Thread(new Code()).start();
    }

    private void solve() throws IOException {
        int n = nextInt(), k = nextInt();
        int q = n * k;

        int[] peoples = new int[k];
        Set<Integer> numbers = new HashSet<Integer>(q);

        for(int i = 0; i < k; ++i) {
            int want = nextInt();
            numbers.add(want);
            peoples[i] = want;
        }

        List<Integer> remain = new LinkedList<Integer>();
        for(int i = 1; i <= q; ++i) {
            if(!numbers.contains(i))
                remain.add(i);
        }

        int more = n - 1;
        ListIterator<Integer> iterator = remain.listIterator();

        for(int i = 0; i < k; ++i) {
            writer.print(peoples[i]);
            for(int j = 0; j < more; ++j)
                writer.print(" " + iterator.next());

            writer.println();
        }
    }

    private class Pair {
        public int first, second;
        public Pair(int first, int second) {
            this.first = first;
            this.second = second;
        }

        @Override
        public boolean equals(Object obj) {
            Pair other = (Pair)obj;
            return first == other.first && second == other.second;
        }
    }

    public void run() {
        try {
            if(in.equals(""))   reader = new BufferedReader(new InputStreamReader(System.in));
            else    reader = new BufferedReader(new FileReader(in));

            if(out.equals(""))  writer = new PrintWriter(new OutputStreamWriter(System.out));
            else    writer = new PrintWriter(new FileWriter(out));
            solve();
        } catch(IOException e) {
            e.printStackTrace();
        } finally {
            try {
                reader.close();
                writer.close();
            } catch(IOException e) {
                e.printStackTrace();
            }
        }
    }

    private int nextInt() throws IOException {
        return Integer.parseInt(nextToken());
    }

    private long nextLong() throws IOException {
        return Long.parseLong(nextToken());
    }

    private double nextDouble() throws IOException {
        return Double.parseDouble(nextToken());
    }

    private String nextToken() throws IOException {
        while(st == null || !st.hasMoreTokens())    st = new StringTokenizer(reader.readLine());
        return st.nextToken();
    }

    private String in = "", out = "";
    private BufferedReader reader;
    private PrintWriter writer;
    private StringTokenizer st;
}