Problem: Petya started to attend programming lessons. On the first lesson his task was to write a simple program. The program was supposed to do the following: in the given string, consisting if uppercase and lowercase Latin letters, it: 

  * deletes all the vowels, 
  * inserts a character "." before each consonant, 
  * replaces all uppercase consonants with corresponding lowercase ones. 



Vowels are letters "A", "O", "Y", "E", "U", "I", and the rest are consonants. The program's input is exactly one string, it should return the output as a single string, resulting after the program's processing the initial string.

Help Petya cope with this easy task.

Input

The first line represents input string of Petya's program. This string only consists of uppercase and lowercase Latin letters and its length is from 1 to 100, inclusive.

Output

Print the resulting string. It is guaranteed that this string is not empty.

Examples

Input

tour


Output

.t.r


Input

Codeforces


Output

.c.d.f.r.c.s


Input

aBAcAba


Output

.b.c.b

Solution (in PYTHON3):

Solution:
string = input() #store the input's value in a string
string2 = string.lower()

#convert a string to a list
lists = [] #define an empty list
for value in range(0,len(string2)):
	lists.append(string2[value])# list of string's letters

for value in range(0,len(lists)):
	if(lists[value] == 'a' or lists[value] == 'e' or lists[value] == 'i' or lists[value] == 'o' or lists[value] == 'u' or lists[value] == 'y'):
		lists[value] =''
	
word = ''
for item in lists: #looping through each item
	word = word + item #form the original string without vowel
	
#we continue to convert a string to a list
lists = []
for value in range(0,len(word)):
	lists.append(word[value]) #create a list of word's letters
	
for value in range(0,len(lists)):
		lists[value] ='.'+lists[value] #now we have '.' before each consonant
		
word = ''
for item in lists: #looping through each item
	word = word + item 
	
print(word.lower())