Problem: Polycarp is a head of a circus troupe. There are n — an even number — artists in the troupe. It is known whether the i-th artist can perform as a clown (if yes, then c_i = 1, otherwise c_i = 0), and whether they can perform as an acrobat (if yes, then a_i = 1, otherwise a_i = 0).

Split the artists into two performances in such a way that: 

  * each artist plays in exactly one performance, 
  * the number of artists in the two performances is equal (i.e. equal to n/2), 
  * the number of artists that can perform as clowns in the first performance is the same as the number of artists that can perform as acrobats in the second performance. 

Input

The first line contains a single integer n (2 ≤ n ≤ 5 000, n is even) — the number of artists in the troupe.

The second line contains n digits c_1 c_2 … c_n, the i-th of which is equal to 1 if the i-th artist can perform as a clown, and 0 otherwise.

The third line contains n digits a_1 a_2 … a_n, the i-th of which is equal to 1, if the i-th artist can perform as an acrobat, and 0 otherwise.

Output

Print n/2 distinct integers — the indices of the artists that should play in the first performance.

If there are multiple answers, print any.

If there is no solution, print a single integer -1.

Examples

Input


4
0011
0101


Output


1 4


Input


6
000000
111111


Output


-1


Input


4
0011
1100


Output


4 3


Input


8
00100101
01111100


Output


1 2 3 6

Note

In the first example, one of the possible divisions into two performances is as follows: in the first performance artists 1 and 4 should take part. Then the number of artists in the first performance who can perform as clowns is equal to 1. And the number of artists in the second performance who can perform as acrobats is 1 as well.

In the second example, the division is not possible.

In the third example, one of the possible divisions is as follows: in the first performance artists 3 and 4 should take part. Then in the first performance there are 2 artists who can perform as clowns. And the number of artists in the second performance who can perform as acrobats is 2 as well.

Solution (in JAVA):

Solution:
//package sept;

import java.io.*;
import java.util.*;


public class TimePass implements Runnable {
    InputStream is;
    PrintWriter out;
    String INPUT = "";
    //boolean debug=false;
    boolean debug=true;
    static long mod=998244353;
    static long mod2=1000000007;
    
    void solve() throws IOException
	{
	    int n=ni();
	    char[] c=ns(n);
	    char[] a=ns(n);
	    int[] cnt=new int[4];
	    ArrayList<Integer>[] list=new ArrayList[4];
	    for(int i=0;i<4;i++)list[i]=new ArrayList<>();
	    for(int i=0;i<n;i++)
	    {
	        int curr=Integer.parseInt(""+c[i]+a[i],2);
	        cnt[curr]++;
	        list[curr].add(i+1);
	    }
	    for(int i=0;i<=cnt[2];i++)
	    {
	        int[] tmp=new int[4];
	        int p1=0,p2=0,p3=0,p4=0;
	        for(int j=0;j<=cnt[3];j++)
	        {
	            Arrays.fill(tmp,0);
	            //tmp[2]=Math.min(j,cnt[2]);
	            tmp[3]=j;
	            tmp[2]=i;
	            //if(tmp[2]+tmp[3]!=i)continue;
	            
	            tmp[1]=Math.min(cnt[1],cnt[1]-(tmp[3]+tmp[2]-(cnt[3]-tmp[3])));
	            tmp[0]=Math.min(n/2-tmp[3]-tmp[1]-tmp[2],cnt[0]);
	            p1=tmp[0];
	            p2=tmp[1];
	            p3=tmp[2];
	            p4=tmp[3];
	            if(p1<0 || p2<0 || p3<0 || p4<0)continue;
	            if(tmp[0]+tmp[1]+tmp[2]+tmp[3]!=n/2)continue;
	            for(int k=0;k<4;k++)tmp[k]=cnt[k]-tmp[k];
	            if(tmp[1]+tmp[3]!=p3+p4)continue;
	            if(tmp[0]+tmp[1]+tmp[2]+tmp[3]!=n/2)continue;
	            if(tmp[0]<0 || tmp[1]<0 || tmp[2]<0 || tmp[3]<0)continue;
	            //out.println(p1+" "+p2+" "+p3+" "+p4);
	            for(int k=0;k<p1;k++)out.print(list[0].get(k)+" ");
	            for(int k=0;k<p2;k++)out.print(list[1].get(k)+" ");
	            for(int k=0;k<p3;k++)out.print(list[2].get(k)+" ");
	            for(int k=0;k<p4;k++)out.print(list[3].get(k)+" ");
	            out.println();
	            return;
	        }
	    }
	    out.println(-1);
	}
	
	static long fnc(int a,int b)
	{
	    return a+(long)1000000007*b;
	}
	
	static Pair[][] packU(int n,int[] from,Pair[] to)
	{
		Pair[][] g=new Pair[n][];
		int[] p=new int[n];
		for(int f:from)
		{
			p[f]++;
		}
		int m=from.length;
		for(int i=0;i<n;i++)
		{
			g[i]=new Pair[p[i]];
		}
		for(int i=0;i<m;i++)
		{
			g[from[i]][--p[from[i]]]=to[i];
		}
		return g;
	}

	static int[][] packD(int n,int[] from,int[] to)
	{
		int[][] g=new int[n][];
		int[] p=new int[n];
		for(int f:from)
		{
			p[f]++;
		}
		int m=from.length;
		for(int i=0;i<n;i++)
		{
			g[i]=new int[p[i]];
		}
		for(int i=0;i<m;i++)
		{
			g[from[i]][--p[from[i]]]=to[i];
		}
		return g;
	}
	    
    static class Pair
    {
        int a,b,c;
        public Pair(int a,int b
        //,int c
        )
        {
            this.a=a;
            this.b=b;
            //this.c=c;
        }
    }
    
    static long lcm(int a,int b)
    {
        long val=a;
        val*=b;
        return (val/gcd(a,b));
    }
    
    static long gcd(long a,long b)
    {
        if(a==0)return b;
        return gcd(b%a,a);
    }
    
    static int pow(int a, int b, int p)
    {
        long ans = 1, base = a;
        while (b!=0)
        {
            if ((b & 1)!=0)
            {
                ans *= base;
                ans%= p;
            }
            base *= base;
            base%= p;
            b >>= 1;
        }
        return (int)ans;
    }

    static int inv(int x, int p)
    {
        return pow(x, p - 2, p);
    }
    
    public static long[] radixSort(long[] f){ return radixSort(f, f.length); }
	public static long[] radixSort(long[] f, int n)
	{
		long[] to = new long[n];
		{
			int[] b = new int[65537];
			for(int i = 0;i < n;i++)b[1+(int)(f[i]&0xffff)]++;
			for(int i = 1;i <= 65536;i++)b[i]+=b[i-1];
			for(int i = 0;i < n;i++)to[b[(int)(f[i]&0xffff)]++] = f[i];
			long[] d = f; f = to;to = d;
		}
		{
			int[] b = new int[65537];
			for(int i = 0;i < n;i++)b[1+(int)(f[i]>>>16&0xffff)]++;
			for(int i = 1;i <= 65536;i++)b[i]+=b[i-1];
			for(int i = 0;i < n;i++)to[b[(int)(f[i]>>>16&0xffff)]++] = f[i];
			long[] d = f; f = to;to = d;
		}
		{
			int[] b = new int[65537];
			for(int i = 0;i < n;i++)b[1+(int)(f[i]>>>32&0xffff)]++;
			for(int i = 1;i <= 65536;i++)b[i]+=b[i-1];
			for(int i = 0;i < n;i++)to[b[(int)(f[i]>>>32&0xffff)]++] = f[i];
			long[] d = f; f = to;to = d;
		}
		{
			int[] b = new int[65537];
			for(int i = 0;i < n;i++)b[1+(int)(f[i]>>>48&0xffff)]++;
			for(int i = 1;i <= 65536;i++)b[i]+=b[i-1];
			for(int i = 0;i < n;i++)to[b[(int)(f[i]>>>48&0xffff)]++] = f[i];
			long[] d = f; f = to;to = d;
		}
		return f;
	}

    
    public void run()
    {
        if(debug)oj=true;
        is = oj ? System.in : new ByteArrayInputStream(INPUT.getBytes());
        out = new PrintWriter(System.out);
        
        long s = System.currentTimeMillis();
        try {
			solve();
		} catch (IOException e) {
			// TODO Auto-generated catch block
			e.printStackTrace();
		}
        out.flush();
        tr(System.currentTimeMillis()-s+"ms");
    }
    
    public static void main(String[] args) throws Exception {new Thread(null,new TimePass(),"Main",1<<26).start();}
    
    private byte[] inbuf = new byte[1024];
    public int lenbuf = 0, ptrbuf = 0;
    
    private int readByte()
    {
        if(lenbuf == -1)throw new InputMismatchException();
        if(ptrbuf >= lenbuf){
            ptrbuf = 0;
            try { lenbuf = is.read(inbuf); } catch (IOException e) { throw new InputMismatchException(); }
            if(lenbuf <= 0)return -1;
        }
        return inbuf[ptrbuf++];
    }
    
    private boolean isSpaceChar(int c) { return !(c >= 33 && c <= 126); }
    private int skip() { int b; while((b = readByte()) != -1 && isSpaceChar(b)); return b; }
    
    private double nd() { return Double.parseDouble(ns()); }
    private char nc() { return (char)skip(); }
    
    private String ns()
    {
        int b = skip();
        StringBuilder sb = new StringBuilder();
        while(!(isSpaceChar(b))){ // when nextLine, (isSpaceChar(b) && b != ' ')
            sb.appendCodePoint(b);
            b = readByte();
        }
        return sb.toString();
    }
    
    private char[] ns(int n)
    {
        char[] buf = new char[n];
        int b = skip(), p = 0;
        while(p < n && !(isSpaceChar(b))){
            buf[p++] = (char)b;
            b = readByte();
        }
        return n == p ? buf : Arrays.copyOf(buf, p);
    }
    
    private char[][] nm(int n, int m)
    {
        char[][] map = new char[n][];
        for(int i = 0;i < n;i++)map[i] = ns(m);
        return map;
    }
    
    private int[] na(int n)
    {
        int[] a = new int[n];
        for(int i = 0;i < n;i++)a[i] = ni();
        return a;
    }
    
    private int ni()
    {
        int num = 0, b;
        boolean minus = false;
        while((b = readByte()) != -1 && !((b >= '0' && b <= '9') || b == '-'));
        if(b == '-'){
            minus = true;
            b = readByte();
        }
        
        while(true){
            if(b >= '0' && b <= '9'){
                num = num * 10 + (b - '0');
            }else{
                return minus ? -num : num;
            }
            b = readByte();
        }
    }
    
    private long nl()
    {
        long num = 0;
        int b;
        boolean minus = false;
        while((b = readByte()) != -1 && !((b >= '0' && b <= '9') || b == '-'));
        if(b == '-'){
            minus = true;
            b = readByte();
        }
        
        while(true){
            if(b >= '0' && b <= '9'){
                num = num * 10 + (b - '0');
            }else{
                return minus ? -num : num;
            }
            b = readByte();
        }
    }
    
    private boolean oj = System.getProperty("ONLINE_JUDGE") != null;
    private void tr(Object... o) { if(!oj)System.out.println(Arrays.deepToString(o)); }
}