Problem: Snuke has an integer sequence, a, of length N. The i-th element of a (1-indexed) is a_{i}.

He can perform the following operation any number of times:

* Operation: Choose integers x and y between 1 and N (inclusive), and add a_x to a_y.



He would like to perform this operation between 0 and 2N times (inclusive) so that a satisfies the condition below. Show one such sequence of operations. It can be proved that such a sequence of operations always exists under the constraints in this problem.

* Condition: a_1 \leq a_2 \leq ... \leq a_{N}

Constraints

* 2 \leq N \leq 50
* -10^{6} \leq a_i \leq 10^{6}
* All input values are integers.

Input

Input is given from Standard Input in the following format:


N
a_1 a_2 ... a_{N}


Output

Let m be the number of operations in your solution. In the first line, print m. In the i-th of the subsequent m lines, print the numbers x and y chosen in the i-th operation, with a space in between. The output will be considered correct if m is between 0 and 2N (inclusive) and a satisfies the condition after the m operations.

Examples

Input

3
-2 5 -1


Output

2
2 3
3 3


Input

2
-1 -3


Output

1
2 1


Input

5
0 0 0 0 0


Output

0

Solution (in CPP):

Solution:
#include <iostream>
#include <vector>
#include<algorithm>
using namespace std;
int main(){
int i,n,x,y,c,d;
x = -100010;
y = 100010;
cin >> n;
int a[n];
for(i=0;i<n;i++){
	cin >> a[i];
	if(x<a[i]){
		c = i+1;
	}
	x = max(x,a[i]);
	if(y>a[i]){
		d = i+1;
	}
	y = min(y,a[i]);
	}
cout << 2*n-1 << endl;
	if(x>-y){
		for(i=1;i<=n;i++){
			cout << c <<" "<< i << endl;
		}
		for(i=1;i<n;i++){
			cout << i <<" "<< i+1 << endl;
		}
	}else{
		for(i=1;i<=n;i++){
			cout << d <<" "<< i << endl;
		}
		for(i=n;i>1;i--){
			cout << i <<" "<< i-1 << endl;
		}
	}
}