Problem: Snuke has an integer sequence, a, of length N. The i-th element of a (1-indexed) is a_{i}.

He can perform the following operation any number of times:

* Operation: Choose integers x and y between 1 and N (inclusive), and add a_x to a_y.



He would like to perform this operation between 0 and 2N times (inclusive) so that a satisfies the condition below. Show one such sequence of operations. It can be proved that such a sequence of operations always exists under the constraints in this problem.

* Condition: a_1 \leq a_2 \leq ... \leq a_{N}

Constraints

* 2 \leq N \leq 50
* -10^{6} \leq a_i \leq 10^{6}
* All input values are integers.

Input

Input is given from Standard Input in the following format:


N
a_1 a_2 ... a_{N}


Output

Let m be the number of operations in your solution. In the first line, print m. In the i-th of the subsequent m lines, print the numbers x and y chosen in the i-th operation, with a space in between. The output will be considered correct if m is between 0 and 2N (inclusive) and a satisfies the condition after the m operations.

Examples

Input

3
-2 5 -1


Output

2
2 3
3 3


Input

2
-1 -3


Output

1
2 1


Input

5
0 0 0 0 0


Output

0

Solution (in PYTHON3):

Solution:
n = int(input())
a = list(map(lambda x: int(x),input().split()))

count = 0
ans = ""

max_num = max(a)
max_idx = a.index(max_num)
min_num = min(a)
min_idx = a.index(min_num)

if abs(max_num) >= abs(min_num):
    for i in range(len(a)):
        a[i] += max_num
        ans += "{} {}\n".format(max_idx+1, i+1)
        count += 1
    for i in range(len(a)-1):
        a[i+1] += a[i]
        ans += "{} {}\n".format(i+1, i+1+1)
        count += 1
else:
    for i in range(len(a)):
        a[i] += min_num
        ans += "{} {}\n".format(min_idx+1, i+1)
        count += 1
    for i in range(len(a)-1):
        a[len(a)-(i+2)] += a[len(a)-(i+1)]
        ans += "{} {}\n".format(len(a)-(i+1)+1, len(a)-(i+2)+1)
        count += 1
print(count)
print(ans)