Problem: Write a program which manipulates a sequence $A = \\{a_0, a_1, ..., a_{n-1}\\}$ by the following operations:

* min($b, e$): report the minimum element in $a_b, a_{b+1}, ..., a_{e-1}$
* max($b, e$): report the maximum element in $a_b, a_{b+1}, ..., a_{e-1}$

Constraints

* $1 \leq n \leq 1,000$
* $-1,000,000,000 \leq a_i \leq 1,000,000,000$
* $1 \leq q \leq 1,000$
* $0 \leq b < e \leq n$

Input

The input is given in the following format.


$n$
$a_0 \; a_1, ..., \; a_{n-1}$
$q$
$com_1 \; b_1 \; e_1$
$com_2 \; b_2 \; e_2$
:
$com_{q} \; b_{q} \; e_{q}$


In the first line, $n$ (the number of elements in $A$) is given. In the second line, $a_i$ (each element in $A$) are given. In the third line, the number of queries $q$ is given and each query is given in the following $q$ lines. $com_i$ denotes a type of query. 0 and 1 represents min($b, e$) and max($b, e$) respectively.

Output

For each query, print the minimum element or the maximum element in a line.

Example

Input

7
8 3 7 1 9 1 4
3
0 0 3
0 1 5
1 0 7


Output

3
1
9

Solution (in CPP):

Solution:
#include <iostream>
#include <cstdio>
#include <algorithm>
#include <cmath>
#include <vector>
#include <list>
#include <set>
#include <map>
#include <queue>
#include <stack>
#include <cctype>
#include <cassert>
#include <climits>
#include <string>
#include <bitset>
#include <cfloat>
#include <random>
#include <unordered_set>
#pragma GCC optimize("Ofast")
using namespace std;
typedef long double ld;
typedef long long int ll;
typedef unsigned long long int ull;
typedef vector<int> vi;
typedef vector<char> vc;
typedef vector<bool> vb;
typedef vector<double> vd;
typedef vector<string> vs;
typedef vector<ll> vll;
typedef vector<pair<int,int> > vpii;
typedef vector<vector<int> > vvi;
typedef vector<vector<char> > vvc;
typedef vector<vector<string> > vvs;
typedef vector<vector<ll> > vvll;
typedef map<int, int> mii;
typedef set<int> si;
#define rep(i,n) for(int i = 0; i < (n); ++i)
#define rrep(i,n) for(int i = 1; i <= (n); ++i)
#define irep(it, stl) for(auto it = stl.begin(); it != stl.end(); it++)
#define drep(i,n) for(int i = (n) - 1; i >= 0; --i)
#define fin(ans) cout << (ans) << '\n'
#define STLL(s) strtoll(s.c_str(), NULL, 10)
#define mp(p,q) make_pair(p, q)
#define pb(n) push_back(n)
#define all(a) a.begin(), a.end()
#define rall(a) a.rbegin(), a.rend()
#define Sort(a) sort(a.begin(), a.end())
#define Rort(a) sort(a.rbegin(), a.rend())
#define MATHPI acos(-1)
#define itn int
#define endl '\n';
#define fi first
#define se second
#define NONVOID [[nodiscard]]
const int dx[8] = {1, 0, -1, 0, 1, -1, -1, 1};
const int dy[8] = {0, 1, 0, -1, 1, 1, -1, -1};
template <class T> inline bool chmax(T& a,T b){if(a<b){a=b;return 1;} return 0;}
template <class T> inline bool chmin(T& a,T b){if(a>b){a=b;return 1;} return 0;}
inline string getline(){string s; getline(cin,s); return s;}
inline void yn(const bool b){b?fin("yes"):fin("no");}
inline void Yn(const bool b){b?fin("Yes"):fin("No");}
inline void YN(const bool b){b?fin("YES"):fin("NO");}
struct io{io(){ios::sync_with_stdio(false);cin.tie(0);}};
const int INF = INT_MAX;
const ll LLINF = 1LL<<60;
const ll MOD = 1000000007;
const double EPS = 1e-9;

template <typename T>
class Max {
public:
    // 単位元
    T unit;
    
    Max(void) {
        // 単位元
        unit = -INF;
    }

    // 演算関数
    T calc(T a, T b) {
        return max(a , b); 
    }
};

template <typename T>
struct Min {
public:
    // 単位元
    T unit;
    
    Min(void) {
        // 単位元
        unit = INF;
    }

    // 演算関数
    T calc(T a, T b) {
        return min(a, b); 
    }
};

template <typename T, class MONOID>
class SegmentTree {
public:
    // セグメント木の葉の要素数
    int n;

    // セグメント木
    vector<T> tree;

    // モノイド
    MONOID mono;

    SegmentTree(vector<T> v) : n(1 << (int)ceil(log2(v.size()))), tree(vector<T>(n << 1)) {
        for(int i = 0; i < v.size(); ++i) {
            update(i, v[i]);
        }
        for(int i = v.size(); i < n; ++i) {
            update(i, mono.unit);
        }
    }

    // k番目の値(0-indexed)をxに変更
    void update(int k, T x) {
        k += n;
        tree[k] = x;
        for(k = k >> 1; k > 0; k >>= 1){
            tree[k] = mono.calc(tree[k << 1 | 0], tree[k << 1 | 1]);
        }
    }

    // [l, r)の最小値(0-indexed)を求める．
    T query(int l, int r) {
        T res = mono.unit;
        l += n;
        r += n;
        while(l < r) {
            if(l & 1) {
                res = mono.calc(res, tree[l++]);
            }
            if(r & 1) {
                res = mono.calc(res, tree[--r]);
            }
            l >>= 1;
            r >>= 1;
        }
        return res;
    }

    T operator[](int k) {
        // st[i]で添字iの要素の値を返す
        if(k - n >= 0 || k < 0) {
            return -INF;
        }
        return tree[tree.size() - n + k];
    }

    void show(void) {
        int ret = 2;
        for(int i = 1; i < 2*n; ++i) {
            if(tree[i] == mono.unit) cout << "UNIT ";
            else cout << tree[i] << " ";
            if(i == ret - 1) {
                cout << endl;
                ret <<= 1;
            }
        }
        cout << endl;
    }
};

int main() {
    
    int n;
    cin>>n;
    vll v(n);
    rep(i,n)cin>>v[i];
    SegmentTree<ll,Min<ll>> st(v);
    SegmentTree<ll,Max<ll>> st2(v);
    int _;
    cin>>_;
    while(_--){
        int q,l,r;
        cin>>q>>l>>r;
        if(q==0){
            cout<<st.query(l,r)<<endl;
        } else {
            cout<<st2.query(l,r)<<endl;
        }
    }
}