Problem: The New Year holidays are over, but Resha doesn't want to throw away the New Year tree. He invited his best friends Kerim and Gural to help him to redecorate the New Year tree.

The New Year tree is an undirected tree with n vertices and root in the vertex 1.

You should process the queries of the two types:

  1. Change the colours of all vertices in the subtree of the vertex v to the colour c. 
  2. Find the number of different colours in the subtree of the vertex v. 

Input

The first line contains two integers n, m (1 ≤ n, m ≤ 4·105) — the number of vertices in the tree and the number of the queries.

The second line contains n integers ci (1 ≤ ci ≤ 60) — the colour of the i-th vertex.

Each of the next n - 1 lines contains two integers xj, yj (1 ≤ xj, yj ≤ n) — the vertices of the j-th edge. It is guaranteed that you are given correct undirected tree.

The last m lines contains the description of the queries. Each description starts with the integer tk (1 ≤ tk ≤ 2) — the type of the k-th query. For the queries of the first type then follows two integers vk, ck (1 ≤ vk ≤ n, 1 ≤ ck ≤ 60) — the number of the vertex whose subtree will be recoloured with the colour ck. For the queries of the second type then follows integer vk (1 ≤ vk ≤ n) — the number of the vertex for which subtree you should find the number of different colours.

Output

For each query of the second type print the integer a — the number of different colours in the subtree of the vertex given in the query.

Each of the numbers should be printed on a separate line in order of query appearing in the input.

Examples

Input

7 10
1 1 1 1 1 1 1
1 2
1 3
1 4
3 5
3 6
3 7
1 3 2
2 1
1 4 3
2 1
1 2 5
2 1
1 6 4
2 1
2 2
2 3


Output

2
3
4
5
1
2


Input

23 30
1 2 2 6 5 3 2 1 1 1 2 4 5 3 4 4 3 3 3 3 3 4 6
1 2
1 3
1 4
2 5
2 6
3 7
3 8
4 9
4 10
4 11
6 12
6 13
7 14
7 15
7 16
8 17
8 18
10 19
10 20
10 21
11 22
11 23
2 1
2 5
2 6
2 7
2 8
2 9
2 10
2 11
2 4
1 12 1
1 13 1
1 14 1
1 15 1
1 16 1
1 17 1
1 18 1
1 19 1
1 20 1
1 21 1
1 22 1
1 23 1
2 1
2 5
2 6
2 7
2 8
2 9
2 10
2 11
2 4


Output

6
1
3
3
2
1
2
3
5
5
1
2
2
1
1
1
2
3

Solution (in JAVA):

Solution:
import java.util.*;
import java.io.*;
import java.math.*;
 
public class Main {
    public static void main(String[] args) throws IOException {
        PrintWriter out = new PrintWriter(System.out);
        //Scanner sc = new Scanner();
        Reader in = new Reader();
        Main solver = new Main();
        solver.solve(out, in);
        out.flush();
        out.close();
 
    }
 
    static int INF = (int)1e5*4*4+5;
    static int maxn = (int)1e7+5;
    static int mod=(int)1e9+7 ;
    static int n,m,k,t,q,x;
    
    static ArrayList<Integer> adj[];
    static long[] tree,lazy;
    static int[] inv,outv;
    
    void solve(PrintWriter out, Reader in) throws IOException{   
        n = in.nextInt();
        m = in.nextInt();
        
        inv = new int[n+1];
        outv = new int[n+1];
        lazy = new long[maxn];
        tree = new long[maxn];
        int[] c = new int[n+1];
        for(int i=0;i<maxn;i++) lazy[i]=-1;
        for(int i=1;i<=n;i++) {
            c[i] = in.nextInt()-1;
        }
        
        adj = new ArrayList[n+1];
        for(int i=1;i<=n;i++) adj[i] = new ArrayList<Integer>();
        
        int u,v;
        for(int i=0;i<n-1;i++){
            u = in.nextInt();
            v = in.nextInt();
            adj[u].add(v);
            adj[v].add(u);
        }
        dfs(1,0);
        
        for(int i=1;i<=n;i++) {
            update(1,1,n,inv[i],inv[i],c[i]);
        }
        
        for(int i=0;i<m;i++){
            t = in.nextInt();
            
            if(t==1){
                u = in.nextInt();
                v = in.nextInt()-1;
                update(1,1,n,inv[u],outv[u],v);
            }else{
                u = in.nextInt();
                long tmp= query(1,1,n,inv[u],outv[u]);
                int cnt=0;
                
                for(int j=0;j<60;j++){
                    if((((1L<<j))&tmp)!=0) cnt++;
                }
                out.println(cnt);
                    
            }
        }
    }
    
    //<>
    
    static void relax(int idx,long val,boolean flag){
        tree[idx] = val;
        
        if(!flag){
            lazy[idx*2] = val;
            lazy[idx*2+1] = val;
        }
        lazy[idx]=-1;
        return;
    }
    
    static void update(int idx,int s,int e,int l,int r,int val){
        if(lazy[idx]!=-1){
            relax(idx,lazy[idx],s==e);
        }
        
        if(s>r || e<l) return;
        
        if(l<=s && e<=r) {
            relax(idx,1L<<val,s==e);
            return;
        }
        
        int mid = (s+e)/2;
        update(idx*2,s,mid,l,r,val);
        update(idx*2+1,mid+1,e,l,r,val);
        
        tree[idx] = tree[idx*2]|tree[idx*2+1];
        return;
    }
    
    static long query(int idx,int s,int e,int l,int r){
        if(lazy[idx]!=-1){
            relax(idx,lazy[idx],s==e);
        }
        
        
        if(s>r || e<l)    return 0;
        
        if(l<=s && e<=r) return tree[idx];
        
        int mid=(s+e)/2;
        
        long a = query(idx*2,s,mid,l,r);
        long b = query(idx*2+1,mid+1,e,l,r);
        return a|b;
        
        
    }
    
    static int time=1;
    static void dfs(int s,int p){
        inv[s] = time++;
        for(int e:adj[s]){
            if(e!=p){
                dfs(e,s);
            }
        }
        
        outv[s] = time-1;
    }
    
    static class Reader {

    private InputStream mIs;
    private byte[] buf = new byte[1024];
    private int curChar;
    private int numChars;

    public Reader() {
        this(System.in);
    }

    public Reader(InputStream is) {
        mIs = is;
    }

    public int read() {
        if (numChars == -1) {
            throw new InputMismatchException();

    }
        if (curChar >= numChars) {
            curChar = 0;
            try {
                numChars = mIs.read(buf);
            } catch (IOException e) {
                throw new InputMismatchException();
            }
            if (numChars <= 0) {
                return -1;
            }
        }
        return buf[curChar++];
    }

    public String nextLine() {
        int c = read();
        while (isSpaceChar(c)) {
            c = read();
        }
        StringBuilder res = new StringBuilder();
        do {
            res.appendCodePoint(c);
            c = read();
        } while (!isEndOfLine(c));
        return res.toString();
    }

    public String next() {
        int c = read();
        while (isSpaceChar(c)) {
            c = read();
        }
        StringBuilder res = new StringBuilder();
        do {
            res.appendCodePoint(c);
            c = read();
        } while (!isSpaceChar(c));
        return res.toString();
    }

    double nextDouble()
    {
        return Double.parseDouble(next());
    }

    public long nextLong() {
        int c = read();
        while (isSpaceChar(c)) {
            c = read();
        }
        int sgn = 1;
        if (c == '-') {
            sgn = -1;
            c = read();
        }
        long res = 0;
        do {
            if (c < '0' || c > '9') {
                throw new InputMismatchException();
            }
            res *= 10;
            res += c - '0';
            c = read();
        } while (!isSpaceChar(c));
        return res * sgn;
    }

    public int nextInt() {
        int c = read();
        while (isSpaceChar(c)) {
            c = read();
        }
        int sgn = 1;
        if (c == '-') {
            sgn = -1;
            c = read();
        }
        int res = 0;
        do {
            if (c < '0' || c > '9') {
                throw new InputMismatchException();
            }
            res *= 10;
            res += c - '0';
            c = read();
        } while (!isSpaceChar(c));
        return res * sgn;
    }

    public boolean isSpaceChar(int c) {
        return c == ' ' || c == '\n' || c == '\r' || c == '\t' || c == -1;
    }

    public boolean isEndOfLine(int c) {
        return c == '\n' || c == '\r' || c == -1;
    }

    }
}