Problem: The only difference between easy and hard versions is constraints.

Polycarp loves to listen to music, so he never leaves the player, even on the way home from the university. Polycarp overcomes the distance from the university to the house in exactly T minutes.

In the player, Polycarp stores n songs, each of which is characterized by two parameters: t_i and g_i, where t_i is the length of the song in minutes (1 ≤ t_i ≤ 15), g_i is its genre (1 ≤ g_i ≤ 3).

Polycarp wants to create such a playlist so that he can listen to music all the time on the way from the university to his home, and at the time of his arrival home, the playlist is over. Polycarp never interrupts songs and always listens to them from beginning to end. Thus, if he started listening to the i-th song, he would spend exactly t_i minutes on its listening. Polycarp also does not like when two songs of the same genre play in a row (i.e. successively/adjacently) or when the songs in his playlist are repeated.

Help Polycarpus count the number of different sequences of songs (their order matters), the total duration is exactly T, such that there are no two consecutive songs of the same genre in them and all the songs in the playlist are different.

Input

The first line of the input contains two integers n and T (1 ≤ n ≤ 15, 1 ≤ T ≤ 225) — the number of songs in the player and the required total duration, respectively.

Next, the n lines contain descriptions of songs: the i-th line contains two integers t_i and g_i (1 ≤ t_i ≤ 15, 1 ≤ g_i ≤ 3) — the duration of the i-th song and its genre, respectively.

Output

Output one integer — the number of different sequences of songs, the total length of exactly T, such that there are no two consecutive songs of the same genre in them and all the songs in the playlist are different. Since the answer may be huge, output it modulo 10^9 + 7 (that is, the remainder when dividing the quantity by 10^9 + 7).

Examples

Input


3 3
1 1
1 2
1 3


Output


6


Input


3 3
1 1
1 1
1 3


Output


2


Input


4 10
5 3
2 1
3 2
5 1


Output


10

Note

In the first example, Polycarp can make any of the 6 possible playlist by rearranging the available songs: [1, 2, 3], [1, 3, 2], [2, 1, 3], [2, 3, 1], [3, 1, 2] and [3, 2, 1] (indices of the songs are given).

In the second example, the first and second songs cannot go in succession (since they have the same genre). Thus, Polycarp can create a playlist in one of 2 possible ways: [1, 3, 2] and [2, 3, 1] (indices of the songs are given).

In the third example, Polycarp can make the following playlists: [1, 2, 3], [1, 3, 2], [2, 1, 3], [2, 3, 1], [3, 1, 2], [3, 2, 1], [1, 4], [4, 1], [2, 3, 4] and [4, 3, 2] (indices of the songs are given).

Solution (in PYTHON):

Solution:
#!/usr/bin/env python
from __future__ import division, print_function

import os
import sys
from io import BytesIO, IOBase

if sys.version_info[0] < 3:
    from __builtin__ import xrange as range
    from future_builtins import ascii, filter, hex, map, oct, zip

import random
import collections
import math
import itertools
import bisect

def main():
    MOD = 10**9 + 7
    n, T = read_int_array()
    maxbit = (1 << n)
    total_time = [0]*maxbit
    times = []
    genres = []
    for _ in range(n):
        t, g = read_int_array()
        g -= 1
        times.append(t)
        genres.append(g)

    for i in range(maxbit):
        total_time[i] = sum(times[b] for b in range(n) if (i & (1 << b)))

    dp = [[0]*3 for _ in range(maxbit)]
    for b in range(n):
        dp[1 << b][genres[b]] = 1 if times[b] <= T else 0
    for i in range(1, maxbit):
        if (i & (i-1)) == 0:
            continue
        for b in range(n):
            if (i & (1 << b)) != 0:
                g = genres[b]
                dp[i][g] += (sum(dp[i ^ (1 << b)]) - dp[i ^ (1 << b)][g]) % MOD


    ans = 0
    for i in range(maxbit):
        if total_time[i] == T:
            ans = (ans + sum(dp[i])) % MOD
    print(ans)



def solve():
    pass


def main2():
    if False and 'PYCHARM_HOSTED' in os.environ:
        main_pycharm()
    else:
        real_main()


from copy import deepcopy
def main_pycharm():
    solution = solve

    test_inputs = None
    test_outputs = None
    judge = None
    slow_solution = None
    if solution is not None:
        if test_outputs is not None:
            test_with_answers(solution, test_inputs, test_outputs)
        if judge is not None:
            test_with_judge(solution, test_inputs, judge)
        if slow_solution is not None:
            test_with_slow_solution(solution, test_inputs, slow_solution)


def test_with_answers(solution, inputs, answers):
    total, wrong = 0, 0
    for args, test_ans in zip(inputs, answers):
        ans = solution(*deepcopy(args))
        if ans != test_ans:
            print('WRONG! ans=%s, test_ans=%s, args=%s' % (ans, test_ans, args))
            wrong += 1
        else:
            print('GOOD')
        total += 1
    print('ALL %d TESTS PASSED' % total if not wrong else '%d out of %d tests are WRONG' % (wrong, total))


def test_with_judge(solution, inputs_gen, judge):
    total, wrong = 0, 0
    for args in inputs_gen:
        ans = solution(*deepcopy(args))
        if not judge(deepcopy(ans), *deepcopy(args)):
            print('WRONG! ans=%s, args=%s' % (ans, args))
            wrong += 1
        total += 1
    print('ALL %d TESTS PASSED' % total if not wrong else '%d out of %d tests are WRONG' % (wrong, total))


def test_with_slow_solution(solution, inputs_gen, solution_slow):
    total, wrong = 0, 0
    for args in inputs_gen:
        ans = solution(*deepcopy(args))
        slow = solution_slow(*deepcopy(args))
        if ans != slow:
            print('WRONG! ans=%s, slow=%s, args=%s' % (ans, slow, args))
            wrong += 1
        total += 1
    print('ALL %d TESTS PASSED' % total if not wrong else '%d out of %d tests are WRONG' % (wrong, total))


# This mergesort can be like 7 times faster than build in sort
# (for stupid reasons)
def mergesort(A, key=lambda x: x, reverse=False):
    C = A
    A = list(range(len(A)))
    B = list(A)

    n = len(A)
    for i in range(0, n - 1, 2):
        if key(C[A[i]]) > key(C[A[i ^ 1]]):
            A[i], A[i ^ 1] = A[i ^ 1], A[i]

    width = 2
    while width < n:
        for i in range(0, n, 2 * width):
            R1, R2 = min(i + width, n), min(i + 2 * width, n)
            j, k = R1, i
            while i < R1 and j < R2:
                if key(C[A[i]]) > key(C[A[j]]):
                    B[k] = A[j]
                    j += 1
                else:
                    B[k] = A[i]
                    i += 1
                k += 1
            while i < R1:
                B[k] = A[i]
                k += 1
                i += 1
            while k < R2:
                B[k] = A[k]
                k += 1
        A, B = B, A
        width *= 2

    if reverse:
        A.reverse()
    return A


# region fastio

BUFSIZE = 8192


class FastIO(IOBase):
    newlines = 0

    def __init__(self, file):
        self._fd = file.fileno()
        self.buffer = BytesIO()
        self.writable = "x" in file.mode or "r" not in file.mode
        self.write = self.buffer.write if self.writable else None

    def read(self):
        while True:
            b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
            if not b:
                break
            ptr = self.buffer.tell()
            self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
        self.newlines = 0
        return self.buffer.read()

    def readline(self):
        while self.newlines == 0:
            b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
            self.newlines = b.count(b"\n") + (not b)
            ptr = self.buffer.tell()
            self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
        self.newlines -= 1
        return self.buffer.readline()

    def flush(self):
        if self.writable:
            os.write(self._fd, self.buffer.getvalue())
            self.buffer.truncate(0), self.buffer.seek(0)


class IOWrapper(IOBase):
    def __init__(self, file):
        self.buffer = FastIO(file)
        self.flush = self.buffer.flush
        self.writable = self.buffer.writable
        self.write = lambda s: self.buffer.write(s.encode("ascii"))
        self.read = lambda: self.buffer.read().decode("ascii")
        self.readline = lambda: self.buffer.readline().decode("ascii")


def print(*args, **kwargs):
    """Prints the values to a stream, or to sys.stdout by default."""
    sep, file = kwargs.pop("sep", " "), kwargs.pop("file", sys.stdout)
    at_start = True
    for x in args:
        if not at_start:
            file.write(sep)
        file.write(str(x))
        at_start = False
    file.write(kwargs.pop("end", "\n"))
    if kwargs.pop("flush", False):
        file.flush()


if sys.version_info[0] < 3:
    sys.stdin, sys.stdout = FastIO(sys.stdin), FastIO(sys.stdout)
else:
    sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)

input = lambda: sys.stdin.readline().rstrip("\r\n")

def read():
    return input()

def read_int():
    return int(input())

def read_array(sep=None, maxsplit=-1):
    return input().split(sep, maxsplit)

def read_int_array():
    return [int(a) for a in read_array()]

# endregion

if __name__ == "__main__":
    main()