Problem: We will call a string x good if it satisfies the following condition:

* Condition: x can be represented as a concatenation of two copies of another string y of length at least 1.



For example, `aa` and `bubobubo` are good; an empty string, `a`, `abcabcabc` and `abba` are not good.

Eagle and Owl created a puzzle on good strings. Find one string s that satisfies the following conditions. It can be proved that such a string always exists under the constraints in this problem.

* 1 ≤ |s| ≤ 200
* Each character of s is one of the 100 characters represented by the integers 1 through 100.
* Among the 2^{|s|} subsequences of s, exactly N are good strings.

Constraints

* 1 ≤ N ≤ 10^{12}

Input

Input is given from Standard Input in the following format:


N


Output

In the first line, print |s|, the length of s. In the second line, print the elements in s in order, with spaces in between. Any string that satisfies the above conditions will be accepted.

Examples

Input

7


Output

4
1 1 1 1


Input

299


Output

23
32 11 11 73 45 8 11 83 83 8 45 32 32 10 100 73 32 83 45 73 32 11 10

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;

typedef long long  LL;
LL n;
int m;
deque <int> a,b;

void solve(LL n)
{
	if (n==0)  return;
	if (n&1)  solve(n/2),m++,a.push_back(m),b.push_back(m);
	else  solve(n-1),m++,a.push_back(m),b.push_front(m);
}

void work()
{
	scanf("%lld",&n);
	solve(n);
	printf("%d\n",a.size()+b.size());
	for (int i=0; i<a.size(); i++)  printf("%d ",a[i]);
	for (int i=0; i<b.size(); i++)  printf("%d ",b[i]);
}

int main()
{
	work();
	return 0;
}