Problem: There are n railway stations in Berland. They are connected to each other by n-1 railway sections. The railway network is connected, i.e. can be represented as an undirected tree.

You have a map of that network, so for each railway section you know which stations it connects.

Each of the n-1 sections has some integer value of the scenery beauty. However, these values are not marked on the map and you don't know them. All these values are from 1 to 10^6 inclusive.

You asked m passengers some questions: the j-th one told you three values:

  * his departure station a_j; 
  * his arrival station b_j; 
  * minimum scenery beauty along the path from a_j to b_j (the train is moving along the shortest path from a_j to b_j). 



You are planning to update the map and set some value f_i on each railway section — the scenery beauty. The passengers' answers should be consistent with these values.

Print any valid set of values f_1, f_2, ..., f_{n-1}, which the passengers' answer is consistent with or report that it doesn't exist.

Input

The first line contains a single integer n (2 ≤ n ≤ 5000) — the number of railway stations in Berland.

The next n-1 lines contain descriptions of the railway sections: the i-th section description is two integers x_i and y_i (1 ≤ x_i, y_i ≤ n, x_i ≠ y_i), where x_i and y_i are the indices of the stations which are connected by the i-th railway section. All the railway sections are bidirected. Each station can be reached from any other station by the railway.

The next line contains a single integer m (1 ≤ m ≤ 5000) — the number of passengers which were asked questions. Then m lines follow, the j-th line contains three integers a_j, b_j and g_j (1 ≤ a_j, b_j ≤ n; a_j ≠ b_j; 1 ≤ g_j ≤ 10^6) — the departure station, the arrival station and the minimum scenery beauty along his path.

Output

If there is no answer then print a single integer -1.

Otherwise, print n-1 integers f_1, f_2, ..., f_{n-1} (1 ≤ f_i ≤ 10^6), where f_i is some valid scenery beauty along the i-th railway section.

If there are multiple answers, you can print any of them.

Examples

Input


4
1 2
3 2
3 4
2
1 2 5
1 3 3


Output


5 3 5


Input


6
1 2
1 6
3 1
1 5
4 1
4
6 1 3
3 4 1
6 5 2
1 2 5


Output


5 3 1 2 1 


Input


6
1 2
1 6
3 1
1 5
4 1
4
6 1 1
3 4 3
6 5 3
1 2 4


Output


-1

Solution (in JAVA):

Solution:
import java.io.OutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.PrintWriter;
import java.util.Arrays;
import java.util.InputMismatchException;
import java.io.IOException;
import java.util.ArrayList;
import java.io.InputStream;

/**
 * Built using CHelper plug-in
 * Actual solution is at the top
 *
 * @author KharYusuf
 */
public class Main {
    public static void main(String[] args) {
        InputStream inputStream = System.in;
        OutputStream outputStream = System.out;
        FastReader in = new FastReader(inputStream);
        PrintWriter out = new PrintWriter(outputStream);
        FBerlandBeauty solver = new FBerlandBeauty();
        solver.solve(1, in, out);
        out.close();
    }

    static class FBerlandBeauty {
        ArrayList<Integer> path;
        boolean[] vis;
        ArrayList<Integer>[] a;
        int[][] ind;

        public void solve(int testNumber, FastReader s, PrintWriter w) {
            int n = s.nextInt();
            a = new ArrayList[n];
            for (int i = 0; i < n; i++) a[i] = new ArrayList<>();
            ind = new int[n][n];
            for (int i = 1; i < n; i++) {
                int u = s.nextInt() - 1, v = s.nextInt() - 1;
                ind[u][v] = i - 1;
                ind[v][u] = i - 1;
                a[u].add(v);
                a[v].add(u);
            }
            int[] f = new int[n - 1];
            int m = s.nextInt();
            dist[] d = new dist[m];
            for (int i = 0; i < m; i++) d[i] = new dist(s.nextInt() - 1, s.nextInt() - 1, s.nextInt());
            Arrays.sort(d);
            for (int i = m - 1; i >= 0; i--) {
                path = new ArrayList<>();
                vis = new boolean[n];
                int u = d[i].x, v = d[i].y, g = d[i].z;
                dfs(u, v);
                int mn = Integer.MAX_VALUE;
                for (int j : path) {
                    if (f[j] == 0) f[j] = g;
                    mn = Math.min(mn, f[j]);
                }
                if (mn != g) {
                    w.println(-1);
                    return;
                }
            }
            for (int i = 0; i < n - 1; i++) if (f[i] == 0) f[i] = 1;
            for (int i : f) w.print(i + " ");
        }

        void dfs(int cur, int to) {
            vis[cur] = true;
            if (cur == to) return;
            for (int i : a[cur]) {
                if (!vis[i]) dfs(i, to);
                if (vis[to]) {
                    path.add(ind[cur][i]);
                    return;
                }
            }
        }

    }

    static class FastReader {
        private InputStream stream;
        private byte[] buf = new byte[1024];
        private int curChar;
        private int numChars;
        private FastReader.SpaceCharFilter filter;

        public FastReader(InputStream stream) {
            this.stream = stream;
        }

        public int read() {

            if (numChars == -1)
                throw new InputMismatchException();

            if (curChar >= numChars) {

                curChar = 0;

                try {
                    numChars = stream.read(buf);
                } catch (IOException e) {
                    throw new InputMismatchException();
                }

                if (numChars <= 0)
                    return -1;
            }

            return buf[curChar++];
        }

        public int nextInt() {

            int c = read();

            while (isSpaceChar(c))
                c = read();

            int sgn = 1;

            if (c == '-') {
                sgn = -1;
                c = read();
            }

            int res = 0;

            do {
                if (c < '0' || c > '9')
                    throw new InputMismatchException();

                res *= 10;
                res += c - '0';
                c = read();
            }
            while (!isSpaceChar(c));

            return res * sgn;
        }

        public boolean isSpaceChar(int c) {

            if (filter != null)
                return filter.isSpaceChar(c);

            return c == ' ' || c == '\n' || c == '\r' || c == '\t' || c == -1;
        }

        public interface SpaceCharFilter {
            public boolean isSpaceChar(int ch);

        }

    }

    static class dist implements Comparable<dist> {
        public int x;
        public int y;
        public int z;

        public dist(int xi, int yi, int zi) {
            x = xi;
            y = yi;
            z = zi;
        }

        public int compareTo(dist other) {
            if (this.z > other.z) {
                return 1;
            }
            if (this.z < other.z) {
                return -1;
            }
            return 0;
        }

    }
}