Problem: You are given a permutation p of the set {1, 2, ..., N}. Please construct two sequences of positive integers a_1, a_2, ..., a_N and b_1, b_2, ..., b_N satisfying the following conditions:

* 1 \leq a_i, b_i \leq 10^9 for all i
* a_1 < a_2 < ... < a_N
* b_1 > b_2 > ... > b_N
* a_{p_1}+b_{p_1} < a_{p_2}+b_{p_2} < ... < a_{p_N}+b_{p_N}

Constraints

* 2 \leq N \leq 20,000
* p is a permutation of the set {1, 2, ..., N}

Input

The input is given from Standard Input in the following format:


N
p_1 p_2 ... p_N


Output

The output consists of two lines. The first line contains a_1, a_2, ..., a_N seperated by a space. The second line contains b_1, b_2, ..., b_N seperated by a space.

It can be shown that there always exists a solution for any input satisfying the constraints.

Examples

Input

2
1 2


Output

1 4
5 4


Input

3
3 2 1


Output

1 2 3
5 3 1


Input

3
2 3 1


Output

5 10 100
100 10 1

Solution (in CPP):

Solution:
#include <bits/stdc++.h>

using namespace std;
const int N = 22222;

int n;
int p[N];
int a[N], b[N];

int main()
{
	cin >> n;
	for (int i = 1; i <= n; i++)
	{
		scanf("%d", &p[i]);
	}
	for (int i = 1; i <= n; i++)
	{
		a[i] = i * n;
		b[i] = n * (n - i + 1);
	}
	for (int i = 1; i <= n; i++) a[p[i]] += i;
	for (int i = 1; i <= n; i++) printf("%d%c", a[i], " \n"[i == n]);
	for (int i = 1; i <= n; i++) printf("%d%c", b[i], " \n"[i == n]);
	return 0;
}