Problem: We will call a string x good if it satisfies the following condition:

* Condition: x can be represented as a concatenation of two copies of another string y of length at least 1.



For example, `aa` and `bubobubo` are good; an empty string, `a`, `abcabcabc` and `abba` are not good.

Eagle and Owl created a puzzle on good strings. Find one string s that satisfies the following conditions. It can be proved that such a string always exists under the constraints in this problem.

* 1 ≤ |s| ≤ 200
* Each character of s is one of the 100 characters represented by the integers 1 through 100.
* Among the 2^{|s|} subsequences of s, exactly N are good strings.

Constraints

* 1 ≤ N ≤ 10^{12}

Input

Input is given from Standard Input in the following format:


N


Output

In the first line, print |s|, the length of s. In the second line, print the elements in s in order, with spaces in between. Any string that satisfies the above conditions will be accepted.

Examples

Input

7


Output

4
1 1 1 1


Input

299


Output

23
32 11 11 73 45 8 11 83 83 8 45 32 32 10 100 73 32 83 45 73 32 11 10

Solution (in CPP):

Solution:
#include<bits/stdc++.h>
using namespace std;
long long n, v;
list<int>a, b;
void solve()
{
	if (!n)return;
	if (n % 2 == 1)
		n >>= 1, solve(), v++, a.insert(a.begin(), v), b.insert(b.begin(), v);
	else n--, solve(), v++, a.insert(a.begin(), v), b.insert(b.end(), v);
}
int main()
{
	cin >> n;
	solve();
	cout << a.size() + b.size() << endl;
	for (list<int>::iterator i = a.begin(); i != a.end(); i++)
		cout << *i << ' ';
	for (list<int>::iterator i = b.begin(); i != b.end(); i++)
		cout << *i << ' ';
	cout << endl;
	return 0;
}