Problem: Snuke has an integer sequence, a, of length N. The i-th element of a (1-indexed) is a_{i}.

He can perform the following operation any number of times:

* Operation: Choose integers x and y between 1 and N (inclusive), and add a_x to a_y.



He would like to perform this operation between 0 and 2N times (inclusive) so that a satisfies the condition below. Show one such sequence of operations. It can be proved that such a sequence of operations always exists under the constraints in this problem.

* Condition: a_1 \leq a_2 \leq ... \leq a_{N}

Constraints

* 2 \leq N \leq 50
* -10^{6} \leq a_i \leq 10^{6}
* All input values are integers.

Input

Input is given from Standard Input in the following format:


N
a_1 a_2 ... a_{N}


Output

Let m be the number of operations in your solution. In the first line, print m. In the i-th of the subsequent m lines, print the numbers x and y chosen in the i-th operation, with a space in between. The output will be considered correct if m is between 0 and 2N (inclusive) and a satisfies the condition after the m operations.

Examples

Input

3
-2 5 -1


Output

2
2 3
3 3


Input

2
-1 -3


Output

1
2 1


Input

5
0 0 0 0 0


Output

0

Solution (in CPP):

Solution:
#include <iostream>
#include <vector>
#include <algorithm>
#include <string>

using namespace std;

int main(void){
	int n;

	cin >> n;

	vector<int> a(n+1);

	for (int i = 1; i < n + 1; i++){
		cin >> a[i];
	}

	cout << 2*n-1 << endl;

	int absmax = 0, id = 1;
	for (int i = 1; i < n + 1; i++){
		if (abs(absmax) < abs(a[i])){
			absmax = a[i];
			id = i;
		}
	}

	for (int j = 1 ; j < n + 1; j++){
		cout << id << " " << j << endl;
	}

	if (a[id] < 0){
		for (int i = n; i > 1; i--){
			cout << i << " " << i - 1 << endl;
		}
	}
	else{
		for (int i = 1; i < n; i++){
			cout << i << " " << i + 1 << endl;
		}
	}
	return 0;
}