Problem: Functional graph is a directed graph in which all vertices have outdegree equal to 1. Loops are allowed.

Some vertices of a functional graph lay on a cycle. From the others we can come to a cycle by making a finite number of steps along the edges (we consider only finite functional graphs in this problem).

Let's compute two values for each vertex. precyclei is the amount of edges we should pass to get to a vertex which is a part of some cycle (zero, if i itself lies on a cycle), cyclei is the length of the cycle we get to.

You are given the information about these values for some functional graph. For each vertex you know the values precyclei and cyclei, however, instead of some values there can be the question mark. It means that these values are unknown.

Build any functional graph that suits the description or determine that there is no such graph.

Input

The first line contains single integer n (1 ≤ n ≤ 300) — the number of vertices in the graph.

Each of the next n lines contain two integers — precyclei (0 ≤ precyclei ≤ n - 1) and cyclei (1 ≤ cyclei ≤ n). There could be question marks instead of some of these values.

Output

In case there is no solution, print -1.

Otherwise, print n integers. i-th of them is the number of vertex to which the edge form the i-th vertex go.

The vertices should be in the same order as they go in input data.

If there are multiple solutions, print any of them.

Examples

Input

3
0 3
0 3
? ?


Output

2 3 1 


Input

5
3 2
? ?
? ?
? ?
? ?


Output

5 3 2 2 4 


Input

8
? 3
? ?
0 2
0 2
0 3
0 3
0 3
3 3


Output

5 1 4 3 6 7 5 2 


Input

1
? ?


Output

1 


Input

6
0 3
0 3
0 3
0 3
0 3
0 3


Output

2 3 1 5 6 4 


Input

2
1 1
1 1


Output

-1

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
struct _ {
  _() {
    ios_base::sync_with_stdio(false);
    cin.tie(0);
  }
} _;
typedef pair<int, int> pii;
typedef vector<int> vi;
typedef vector<vi> vvi;
template <class T, class second>
void smax(T& a, const second& b) {
  if (b > a) a = b;
}
template <class T, class second>
void smin(T& a, const second& b) {
  if (b < a) a = b;
}
template <class T, class second>
T pop_begin(second& a) {
  auto it = a.begin();
  T ret = *it;
  a.erase(it);
  return ret;
}
void gotodie() {
  cout << "-1" << endl;
  exit(0);
}
struct MinCostMaxFlow {
  int n, qs;
  vector<vector<long long>> cap, cost, fnet;
  vector<vector<int>> adj;
  vector<long long> d, pi;
  vector<int> deg, par, q, inq;
  MinCostMaxFlow(int n)
      : n(n),
        qs(0),
        deg(n + 1),
        par(n + 1),
        d(n + 1),
        q(n + 1),
        inq(n + 1),
        pi(n + 1),
        cap(n + 1, vector<long long>(n + 1)),
        cost(cap),
        fnet(cap),
        adj(n + 1, vector<int>(n + 1)) {}
  void AddEdge(int from, int to, long long cap_, long long cost_) {
    cap[from][to] = cap_;
    cost[from][to] = cost_;
  }
  bool dijkstra(int s, int t) {
    fill(d.begin(), d.end(), 0x3f3f3f3f3f3f3f3fLL);
    fill(par.begin(), par.end(), -1);
    fill(inq.begin(), inq.end(), -1);
    d[s] = qs = 0;
    inq[q[qs++] = s] = 0;
    par[s] = n;
    while (qs) {
      int u = q[0];
      inq[u] = -1;
      q[0] = q[--qs];
      if (qs) inq[q[0]] = 0;
      for (int i = 0, j = 2 * i + 1, t; j < qs; i = j, j = 2 * i + 1) {
        if (j + 1 < qs && d[q[j + 1]] < d[q[j]]) j++;
        if (d[q[j]] >= d[q[i]]) break;
        {
          t = q[i];
          q[i] = q[j];
          q[j] = t;
          t = inq[q[i]];
          inq[q[i]] = inq[q[j]];
          inq[q[j]] = t;
        };
      }
      for (int k = 0, v = adj[u][k]; k < deg[u]; v = adj[u][++k]) {
        if (fnet[v][u] && d[v] > (d[u] + pi[u] - pi[v]) - cost[v][u])
          d[v] = (d[u] + pi[u] - pi[v]) - cost[v][par[v] = u];
        if (fnet[u][v] < cap[u][v] &&
            d[v] > (d[u] + pi[u] - pi[v]) + cost[u][v])
          d[v] = (d[u] + pi[u] - pi[v]) + cost[par[v] = u][v];
        if (par[v] == u) {
          if (inq[v] < 0) {
            inq[q[qs] = v] = qs;
            qs++;
          }
          for (int i = inq[v], j = (i - 1) / 2, t; d[q[i]] < d[q[j]];
               i = j, j = (i - 1) / 2) {
            t = q[i];
            q[i] = q[j];
            q[j] = t;
            t = inq[q[i]];
            inq[q[i]] = inq[q[j]];
            inq[q[j]] = t;
          };
        }
      }
    }
    for (int i = 0; i < n; i++)
      if (pi[i] < (LLONG_MAX / 2)) pi[i] += d[i];
    return par[t] >= 0;
  }
  pair<long long, long long> mcmf4(int s, int t) {
    for (int i = 0; i < n; i++)
      for (int j = 0; j < n; j++)
        if (cap[i][j] || cap[j][i]) adj[i][deg[i]++] = j;
    long long flow = 0;
    long long fcost = 0;
    while (dijkstra(s, t)) {
      long long bot = LLONG_MAX;
      for (int v = t, u = par[v]; v != s; u = par[v = u])
        bot = min(bot, fnet[v][u] ? fnet[v][u] : (cap[u][v] - fnet[u][v]));
      for (int v = t, u = par[v]; v != s; u = par[v = u])
        if (fnet[v][u]) {
          fnet[v][u] -= bot;
          fcost -= bot * cost[v][u];
        } else {
          fnet[u][v] += bot;
          fcost += bot * cost[u][v];
        }
      flow += bot;
    }
    return make_pair(flow, fcost);
  }
};
bool take(vi& give, vi& from) {
  if (from.empty()) return false;
  give.push_back(from.back());
  from.pop_back();
  return true;
}
void sett(int cyclen, int dist, vector<vi>& lcyc, vi& ans, vi& take) {
  assert((int)(take).size());
  int nod = take.back();
  take.pop_back();
  if (lcyc[cyclen][dist - 1] == -1) gotodie();
  ans[nod] = lcyc[cyclen][dist - 1];
  lcyc[cyclen][dist] = nod;
}
string tmp;
signed main() {
  int N;
  cin >> N;
  vector<vector<vi>> k2(N + 1, vector<vi>(N + 1));
  vector<vi> kcyc(N + 1);
  vector<vi> kpre(N + 1);
  vi nk;
  bool seencyc = false;
  for (int i = 0; i < (N); ++i) {
    string pres, cycs;
    cin >> pres >> cycs;
    int pre, cyc;
    if (pres == "?")
      pre = -1;
    else
      pre = atoi(pres.c_str());
    if (cycs == "?")
      cyc = -1;
    else
      cyc = atoi(cycs.c_str());
    if (pre >= 0 && cyc >= 0) {
      k2[cyc][pre].push_back(i);
      seencyc = true;
    } else if (pre >= 0)
      kpre[pre].push_back(i);
    else if (cyc >= 0) {
      kcyc[cyc].push_back(i);
      seencyc = true;
    } else
      nk.push_back(i);
  }
  if (!seencyc) {
    if (!kpre[0].empty()) {
      take(kcyc[1], kpre[0]);
    } else if (!nk.empty()) {
      take(kcyc[1], nk);
    } else
      gotodie();
  }
  vi ans(N, -1);
  vector<vi> lcyc(N + 1, vi(N + 2, -1));
  vector<int> cycval(N + 1, 1);
  for (int i = 1; i < (N + 1); ++i) {
    for (int j = 1; j < (N); ++j)
      if (!k2[i][j].empty()) cycval[j]++;
    cycval[i] += (int)(kcyc[i]).size();
  }
  MinCostMaxFlow G(0 + 1 + 1 + 2 * N + 1 + 2 * N + 1 + 1 + 2 * N + 1);
  for (int cyc = 1; cyc < (N + 1); ++cyc)
    G.AddEdge(0, 0 + 1 + 1 + 2 * N + 1 + cyc, (int)(kcyc[cyc]).size(),
              301 * cycval[cyc]);
  for (int pre = 0; pre < (N); ++pre)
    G.AddEdge(0, 0 + 1 + 1 + pre, (int)(kpre[pre]).size(), 1);
  G.AddEdge(0, 0 + 1 + 1 + 2 * N + 1 + 2 * N + 1, (int)(nk).size(),
            301 * 301 * 301);
  map<pair<int, int>, int> nodes;
  for (int cyc = 1; cyc < (N + 1); ++cyc) {
    int cycneed = ((int)(k2[cyc][0]).size() + cyc - 1) / cyc;
    if ((int)(kcyc[cyc]).size()) smax(cycneed, 1);
    for (auto& it : k2[cyc])
      if ((int)(it).size()) smax(cycneed, 1);
    if (!cycneed) continue;
    for (int i = 0; i < (cycneed * cyc - (int)(k2[cyc][0]).size()); ++i) {
      nodes[make_pair(cyc, 0)]++;
    }
  }
  for (int cyc = 1; cyc < (N + 1); ++cyc) {
    int mxhas = 0;
    for (int i = 1; i < (N); ++i)
      if (!k2[cyc][i].empty()) mxhas = i;
    for (int i = 1; i < (mxhas + 1); ++i)
      if (k2[cyc][i].empty()) {
        nodes[make_pair(cyc, i)]++;
      }
  }
  int flo = 0;
  int nod = 0;
  for (auto& it : nodes) {
    int cyc = it.first.first;
    int i = it.first.second;
    int cap = it.second;
    flo += cap;
    G.AddEdge(0 + 1 + 1 + 2 * N + 1 + 2 * N + 1 + 1 + nod, 0 + 1, cap, 0);
    G.AddEdge(0 + 1 + 1 + 2 * N + 1 + 2 * N + 1,
              0 + 1 + 1 + 2 * N + 1 + 2 * N + 1 + 1 + nod, cap, 0);
    G.AddEdge(0 + 1 + 1 + 2 * N + 1 + cyc,
              0 + 1 + 1 + 2 * N + 1 + 2 * N + 1 + 1 + nod, cap, 0);
    G.AddEdge(0 + 1 + 1 + i, 0 + 1 + 1 + 2 * N + 1 + 2 * N + 1 + 1 + nod, cap,
              0);
    ++nod;
  }
  pair<long long, long long> mx = G.mcmf4(0, 0 + 1);
  if (mx.first != flo) gotodie();
  nod = 0;
  for (auto& it : nodes) {
    int cyc = it.first.first;
    int dist = it.first.second;
    for (int i = 0; i < (it.second); ++i) {
      if (G.fnet[0 + 1 + 1 + 2 * N + 1 + 2 * N + 1]
                [0 + 1 + 1 + 2 * N + 1 + 2 * N + 1 + 1 + nod]-- > 0)
        take(k2[cyc][dist], nk);
      else if (G.fnet[0 + 1 + 1 + 2 * N + 1 + cyc]
                     [0 + 1 + 1 + 2 * N + 1 + 2 * N + 1 + 1 + nod]-- > 0)
        take(k2[cyc][dist], kcyc[cyc]);
      else if (G.fnet[0 + 1 + 1 + dist]
                     [0 + 1 + 1 + 2 * N + 1 + 2 * N + 1 + 1 + nod]-- > 0)
        take(k2[cyc][dist], kpre[dist]);
      else {
        cout << 0 + 1 + 1 + 2 * N + 1 + 2 * N + 1 + 1 + nod << endl;
        assert(G.fnet[0 + 1 + 1 + 2 * N + 1 + 2 * N + 1 + 1 + nod][0 + 1]);
        assert(false);
      }
    }
    ++nod;
  }
  int bestcyc = -1;
  int bestval = -1;
  for (int i = 1; i < (N + 1); ++i) {
    if (k2[i][0].empty()) continue;
    int togo = (int)(kcyc[i]).size() + (int)(nk).size();
    for (int j = 1;; ++j) {
      if ((int)(kpre[j]).size() || (int)(k2[i][j]).size())
        continue;
      else if (togo)
        --togo;
      else {
        if (j > bestval) {
          bestval = j;
          bestcyc = i;
        }
        break;
      }
    }
  }
  assert(bestcyc != -1);
  while (!nk.empty()) take(kcyc[bestcyc], nk);
  for (int i = 1; i < (bestval); ++i) {
    while (!kpre[i].empty()) take(k2[bestcyc][i], kpre[i]);
  }
  while (!kpre[0].empty()) take(k2[1][0], kpre[0]);
  for (int i = 1; i < (N + 1); ++i) {
    assert((int)(k2[i][0]).size() % i == 0);
    while ((int)(k2[i][0]).size()) {
      int f = k2[i][0].back();
      for (int j = 0; j < (i - 1); ++j) {
        int nnod = k2[i][0].back();
        k2[i][0].pop_back();
        ans[nnod] = k2[i][0].back();
      }
      lcyc[i][0] = f;
      ans[k2[i][0].back()] = f;
      k2[i][0].pop_back();
    }
    for (int j = 1; j < bestval; j++) {
      if (k2[i][j].empty() && (int)(kcyc[i]).size()) {
        sett(i, j, lcyc, ans, kcyc[i]);
      }
      while ((int)(k2[i][j]).size()) sett(i, j, lcyc, ans, k2[i][j]);
    }
  }
  for (auto& it : kpre)
    if (!it.empty()) gotodie();
  for (int i = 0; i < (N); ++i) cout << ans[i] + 1 << " ";
  cout << endl;
  return 0;
}