Problem: You are given a permutation p of the set {1, 2, ..., N}. Please construct two sequences of positive integers a_1, a_2, ..., a_N and b_1, b_2, ..., b_N satisfying the following conditions:

* 1 \leq a_i, b_i \leq 10^9 for all i
* a_1 < a_2 < ... < a_N
* b_1 > b_2 > ... > b_N
* a_{p_1}+b_{p_1} < a_{p_2}+b_{p_2} < ... < a_{p_N}+b_{p_N}

Constraints

* 2 \leq N \leq 20,000
* p is a permutation of the set {1, 2, ..., N}

Input

The input is given from Standard Input in the following format:


N
p_1 p_2 ... p_N


Output

The output consists of two lines. The first line contains a_1, a_2, ..., a_N seperated by a space. The second line contains b_1, b_2, ..., b_N seperated by a space.

It can be shown that there always exists a solution for any input satisfying the constraints.

Examples

Input

2
1 2


Output

1 4
5 4


Input

3
3 2 1


Output

1 2 3
5 3 1


Input

3
2 3 1


Output

5 10 100
100 10 1

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
const int N=20005;
int a[N],b[N],p[N];
int main (){
	int n;scanf ("%d",&n);
	for (int i=1;i<=n;i++) scanf ("%d",&p[i]);
	for (int i=1;i<=n;i++) a[i]=a[i-1]+20005;
	for (int i=n;i>=1;i--) b[i]=b[i+1]+20005;
	for (int i=1;i<=n;i++)
		a[p[i]]-=(n-i+1);
	for (int i=1;i<=n;i++) printf ("%d ",a[i]);
	puts("");
	for (int i=1;i<=n;i++) printf ("%d ",b[i]);
	return 0;
}