Problem: Chouti and his classmates are going to the university soon. To say goodbye to each other, the class has planned a big farewell party in which classmates, teachers and parents sang and danced.

Chouti remembered that n persons took part in that party. To make the party funnier, each person wore one hat among n kinds of weird hats numbered 1, 2, … n. It is possible that several persons wore hats of the same kind. Some kinds of hats can remain unclaimed by anyone.

After the party, the i-th person said that there were a_i persons wearing a hat differing from his own.

It has been some days, so Chouti forgot all about others' hats, but he is curious about that. Let b_i be the number of hat type the i-th person was wearing, Chouti wants you to find any possible b_1, b_2, …, b_n that doesn't contradict with any person's statement. Because some persons might have a poor memory, there could be no solution at all.

Input

The first line contains a single integer n (1 ≤ n ≤ 10^5), the number of persons in the party.

The second line contains n integers a_1, a_2, …, a_n (0 ≤ a_i ≤ n-1), the statements of people.

Output

If there is no solution, print a single line "Impossible".

Otherwise, print "Possible" and then n integers b_1, b_2, …, b_n (1 ≤ b_i ≤ n).

If there are multiple answers, print any of them.

Examples

Input

3
0 0 0


Output

Possible
1 1 1 

Input

5
3 3 2 2 2


Output

Possible
1 1 2 2 2 

Input

4
0 1 2 3


Output

Impossible

Note

In the answer to the first example, all hats are the same, so every person will say that there were no persons wearing a hat different from kind 1.

In the answer to the second example, the first and the second person wore the hat with type 1 and all other wore a hat of type 2.

So the first two persons will say there were three persons with hats differing from their own. Similarly, three last persons will say there were two persons wearing a hat different from their own.

In the third example, it can be shown that no solution exists.

In the first and the second example, other possible configurations are possible.

Solution (in JAVA):

Solution:
//    A Computer is Like a mischievous genie.
//    It will give you exactly what you ask for,
//    but not always what you want
//    A code by Rahul Verma


import java.io.BufferedOutputStream;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Collections;
import java.util.Comparator;
import java.util.HashMap;
import java.util.HashSet;
import java.util.LinkedList;
import java.util.PriorityQueue;
import java.util.Queue;
import java.util.Stack;
import java.util.StringTokenizer;
import java.util.TreeMap;


public class Main {


    static class Clock {

        protected long start, stop;

        public void start() {
            start = System.currentTimeMillis();
        }

        public void stop() {
            stop = System.currentTimeMillis();
        }

        public String getTime() {
            return ((stop - start) + " ms");
        }
    }


    public static PrintWriter out = new PrintWriter(new BufferedOutputStream(System.out));

    static class FastReader {

        BufferedReader br;
        StringTokenizer st;

        public FastReader() {
            br = new BufferedReader(new
                InputStreamReader(System.in));
        }

        String next() {
            while (st == null || !st.hasMoreElements()) {
                try {
                    st = new StringTokenizer(br.readLine());
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
            return st.nextToken();
        }

        int nextInt() {
            return Integer.parseInt(next());
        }

        long nextLong() {
            return Long.parseLong(next());
        }

        double nextDouble() {
            return Double.parseDouble(next());
        }

        String[] nextSArray() {
            String sr[] = null;
            try {
                sr = br.readLine().trim().split(" ");
            } catch (IOException e) {
                e.printStackTrace();
            }
            return sr;
        }

        String nextLine() {
            String str = "";
            try {
                str = br.readLine();
            } catch (IOException e) {
                e.printStackTrace();
            }

            return str;
        }
    }


    static long powmodulo(long a, long p) {
        if (p == 0) {
            return 1 % mod;
        }
        if (p == 1) {
            return a % mod;
        }
        long ans = 1;
        while (p > 0) {
            if ((p & 1) > 0) {
                ans = (ans * a) % mod;
            }
            a = (a * a) % mod;
            p = p >> 1;
        }
        return ans % mod;
    }


    static long mod = 1000000007;

    static long gcd(long a, long b) {
        if (a == 0) {
            return b;
        }
        return gcd(b % a, a);
    }

    static long fast_powerNumbers(long a, long n) {
        if (n == 1) {
            return a;
        }
        long ans = fast_powerNumbers(a, n / 2);
        if (n % 2 == 0) {
            return (ans * ans);
        } else {
            return ((ans * ans) * (a));
        }
    }


    static void dfs_helper(int[][] arr, int i, int j, int team, int n, int m) {
        arr[i][j] = team;
        if (i - 1 >= 0 && arr[i - 1][j] == 1) {
            dfs(arr, i - 1, j, team, n, m);
        }
        if (j - 1 >= 0 && arr[i][j - 1] == 1) {
            dfs(arr, i, j - 1, team, n, m);
        }
        if (i + 1 < n && arr[i + 1][j] == 1) {
            dfs(arr, i + 1, j, team, n, m);
        }
        if (j + 1 < m && arr[i][j + 1] == 1) {
            dfs(arr, i, j + 1, team, n, m);
        }

    }

    static void dfs(int[][] arr, int i, int j, int team, int n, int m) {
        dfs_helper(arr, i, j, team, n, m);

    }

    static int parent[];
    static int rank[];

    static int find(int i) {
        if (parent[i] == -1) {
            parent[i] = i;
            return i;
        }

        if (parent[i] == i) {
            return i;
        } else {
            parent[i] = find(parent[i]);
        }
        return parent[i];

    }

    static void unite(int s1, int s2) {

        if (rank[s1] > rank[s2]) {
            parent[s2] = s1;
            rank[s1] += rank[s2];
        } else {
            parent[s1] = s2;
            rank[s2] += rank[s1];
        }
    }


    public static long arr[];
    public static int arr1[];

//    static void seive(int n) {
//        arr = new int[n + 1];
//        arr[0] = arr[1] = 1;
//        for (int i = 4; i <= n; i = i + 2) {
//            arr[i] = 1;
//        }
//        for (int i = 3; i * i <= n; i = i + 2) {
//            if (arr[i] == 0) {
//                for (int j = i * i; j <= n; j = j + i) {
//                    arr[j] = 1;
//                }
//
//            }
//        }
//    }

    static  void seive(int n)
    {
        arr1=new int[n+1];
        arr1[0]=arr1[1]=1;
        for (int i = 4; i <=n ; i+=2) {
            arr1[i]=1;
        }
        for (int i = 3; i*i <=n ; i+=2) {
            if (arr1[i] == 0)
            {
                for (int j = i*i; j <=n ; j+=i) {
                    arr1[j]=1;
                }
            }
        }

    }

    public static void main(String[] args) throws Exception {
        FastReader sc = new FastReader();

        Clock clock = new Clock();
        clock.start();
        int n=sc.nextInt();
        int arr[]=new int[n];
        int brr[]=new int[n];
        HashMap<Integer,Integer>hm=new HashMap<>();
        HashMap<Integer,Integer>hm2=new HashMap<>();
        for (int i = 0; i < n; i++) {
            arr[i]=sc.nextInt();

        }
        int c=1;
        brr[0]=c;
        hm2.put(arr[0],c);
        hm.put(arr[0], n-arr[0]-1);
        if (n - arr[0] - 1 == 0) {
            hm.remove(arr[0]);
        }

        for (int i = 1; i < n; i++) {
//            System.out.println(hm);
//            System.out.println(hm2);
            if(hm2.containsKey(arr[i])&&hm.containsKey(arr[i]))
            {
                if(hm.get(arr[i])==0)
                    continue;
                brr[i]=hm2.get(arr[i]);
                if(hm.get(arr[i])>1)
                hm.put(arr[i],hm.get(arr[i])-1);
                else
                    hm.remove(arr[i]);
            }
            else
            {
                ++c;
                hm2.put(arr[i],c);
                hm.put(arr[i],n-1-arr[i]);
                if(n-1-arr[i]==0)
                    hm.remove(arr[i]);
                brr[i]=c;
            }
        }
        int sum=0;
        for(Integer k: hm.keySet())
            sum+=hm.get(k);
        if(sum==0)
        { out.println("Possible");
            for (int i = 0; i < n; i++) {
                out.print(brr[i]+" ");
            }
        }
        else
            out.println("Impossible");
        out.close();


    }


 }


class Pair{

    int a,b;
    Pair(int a,int b)
    {
        this.a=a;
        this.b=b;
    }
}
class DSU
{
    int parent[];
    int rank[];

    long sum[] ;
    DSU(int n)
    {
        this.parent=new int[n];
        this.rank=new int[n];
        sum=new long[n];
        Arrays.fill(parent,-1);
        Arrays.fill(rank,1);

    }

    int find(int s1)
    {
        if(parent[s1]==-1)
            return s1;
        return parent[s1]=find(parent[s1]);
    }

    void unite(int s1,int s2)
    {
        int p1=this.find(s1);
        int p2=this.find(s2);
        if(p1==p2)
            return;
        if(rank[p1]>rank[p2])
        {
            parent[p2]=p1;
            rank[p1]+=rank[p2];
            // System.out.println(arr[p2]);

            sum[p1]+=sum[p2];
            //sum[p2]+=sum[p1];

        }
        else
        {
            parent[p1]=p2;
            rank[p2]+=rank[p1];
            //System.out.println(arr[p1]);
            sum[p2]+=sum[p1];
            //sum[p1]+=sum[p2];
        }
    }


}

class Gaph {

    HashMap<Integer, ArrayList<Integer>> hm;

    Gaph() {
        hm = new HashMap<>();
    }

    Gaph(int n) {

        hm = new HashMap<>();
        for (int i = 0; i < n; i++) {
            hm.put(i, new ArrayList<Integer>());
        }
    }

    // function for adding an edge.................................................
    public void addEdge(int a, int b, boolean isDir) {
        if (isDir) {
            if (hm.containsKey(a)) {
                hm.get(a).add(b);
            } else {
                hm.put(a, new ArrayList<>(Arrays.asList(b)));
            }
        } else {
            if (hm.containsKey(a)) {
                hm.get(a).add(b);
            } else if (!hm.containsKey(a)) {
                hm.put(a, new ArrayList<>(Arrays.asList(b)));
            }

            if (hm.containsKey(b)) {
                hm.get(b).add(a);
            } else if (!hm.containsKey(b)) {
                hm.put(b, new ArrayList<>(Arrays.asList(a)));
            }
        }
    }


}

// out.println(al.toString().replaceAll("[\\[|\\]|,]",""));