Problem: You're given an integer n. For every integer i from 2 to n, assign a positive integer a_i such that the following conditions hold:

  * For any pair of integers (i,j), if i and j are coprime, a_i ≠ a_j. 
  * The maximal value of all a_i should be minimized (that is, as small as possible). 



A pair of integers is called [coprime](https://en.wikipedia.org/wiki/Coprime_integers) if their [greatest common divisor](https://en.wikipedia.org/wiki/Greatest_common_divisor) is 1.

Input

The only line contains the integer n (2 ≤ n ≤ 10^5).

Output

Print n-1 integers, a_2, a_3, …, a_n (1 ≤ a_i ≤ n). 

If there are multiple solutions, print any of them.

Examples

Input


4


Output


1 2 1 

Input


3


Output


2 1

Note

In the first example, notice that 3 and 4 are coprime, so a_3 ≠ a_4. Also, notice that a=[1,2,3] satisfies the first condition, but it's not a correct answer because its maximal value is 3.

Solution (in PYTHON3):

Solution:
def SieveOfEratosthenes(n): 
    prime = [0 for i in range(n+1)] 
    p = 2
    count = 1
    while (p * p <= n): 
        if (prime[p] == 0): 
            prime[p] = count
            count += 1
            for i in range(p * p, n+1, p): 
                prime[i] = prime[p]
        p += 1
    for p in range(2, n): 
        if prime[p] == 0:
            prime[p] = count
            count += 1
        print(prime[p],end=' ')
    print()

n = int(input())
SieveOfEratosthenes(n+1)