Problem: There are literally dozens of snooker competitions held each year, and team Jinotega tries to attend them all (for some reason they prefer name "snookah")! When a competition takes place somewhere far from their hometown, Ivan, Artsem and Konstantin take a flight to the contest and back.

Jinotega's best friends, team Base have found a list of their itinerary receipts with information about departure and arrival airports. Now they wonder, where is Jinotega now: at home or at some competition far away? They know that: 

  * this list contains all Jinotega's flights in this year (in arbitrary order), 
  * Jinotega has only flown from his hometown to a snooker contest and back, 
  * after each competition Jinotega flies back home (though they may attend a competition in one place several times), 
  * and finally, at the beginning of the year Jinotega was at home. 



Please help them to determine Jinotega's location!

Input

In the first line of input there is a single integer n: the number of Jinotega's flights (1 ≤ n ≤ 100). In the second line there is a string of 3 capital Latin letters: the name of Jinotega's home airport. In the next n lines there is flight information, one flight per line, in form "XXX->YYY", where "XXX" is the name of departure airport "YYY" is the name of arrival airport. Exactly one of these airports is Jinotega's home airport.

It is guaranteed that flights information is consistent with the knowledge of Jinotega's friends, which is described in the main part of the statement.

Output

If Jinotega is now at home, print "home" (without quotes), otherwise print "contest".

Examples

Input

4
SVO
SVO-&gt;CDG
LHR-&gt;SVO
SVO-&gt;LHR
CDG-&gt;SVO


Output

home


Input

3
SVO
SVO-&gt;HKT
HKT-&gt;SVO
SVO-&gt;RAP


Output

contest

Note

In the first sample Jinotega might first fly from SVO to CDG and back, and then from SVO to LHR and back, so now they should be at home. In the second sample Jinotega must now be at RAP because a flight from RAP back to SVO is not on the list.

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.*;

public class Main {
	static final boolean ONLINE_JUDGE = System.getProperty("ONLINE_JUDGE") != null;

	boolean checkIndex(int index, int size) {
		return (0 <= index && index < size);
	}

	// ======================================================
	void solve() throws IOException {
		out.println(rI()%2==0?"home":"contest");	}

	// ===========================================================================
	long summ(int[] a) {
		long ans = 0;
		for (int i = 0; i < a.length; i++) {
			ans += a[i];
		}
		return ans;
	}

	long summToIndex(int[] a, int index) {
		long ans = 0;
		for (int i = 0; i < index; i++) {
			ans += a[i];
		}
		return ans;
	}

	int minInt(int... values) {
		int min = Integer.MAX_VALUE;
		for (int value : values) {
			min = Math.min(min, value);
		}
		return min;
	}

	int maxInt(int... values) {
		int max = Integer.MIN_VALUE;
		for (int value : values) {
			max = Math.max(max, value);
		}
		return max;
	}

	long minLong(long... values) {
		long min = Long.MAX_VALUE;
		for (long value : values) {
			min = Math.min(min, value);
		}
		return min;
	}

	long maxLong(long... values) {
		long min = Long.MIN_VALUE;
		for (long value : values) {
			min = Math.max(min, value);
		}
		return min;
	}

	// ==============================================================================

	public static void main(String[] args) {
		new Main().run();
	}

	BufferedReader in;
	PrintWriter out;
	StringTokenizer tok;

	long maxA(int[] each) {
		long max = Integer.MIN_VALUE;
		for (int i = 0; i < each.length; i++) {
			if (each[i] > max) {
				max = each[i];

			}
		}
		return max;
	}

	long minA(long[] a) {
		long min = Long.MAX_VALUE;
		for (int i = 0; i < a.length; i++) {
			if (a[i] < min) {
				min = a[i];
			}
		}
		return min;
	}

	void init() throws FileNotFoundException {

		if (ONLINE_JUDGE) {
			in = new BufferedReader(new InputStreamReader(System.in));
			out = new PrintWriter(System.out);
		} else {
			in = new BufferedReader(new FileReader("input.txt"));
			out = new PrintWriter("output.txt");
		}

		tok = new StringTokenizer("");
	}

	void run() {
		try {
			long timeStart = System.currentTimeMillis();

			init();
			solve();

			out.close();

			long timeEnd = System.currentTimeMillis();
			System.err.println("Time = " + (timeEnd - timeStart) + " COMPILED");
		} catch (Exception e) {
			e.printStackTrace();
			System.exit(-1);
		}
	}

	long memoryTotal, memoryFree;

	void memory() {
		memoryFree = Runtime.getRuntime().freeMemory();
		System.err.println("Memory = " + ((-memoryTotal + memoryFree) >> 10) + " KB");
	}

	String readLine() throws IOException {
		return in.readLine();
	}

	String delimiter = " ";

	String rS() throws IOException {
		while (!tok.hasMoreTokens()) {
			String nextLine = readLine();
			if (null == nextLine)
				return null;

			tok = new StringTokenizer(nextLine);
		}

		return tok.nextToken(delimiter);
	}

	int[] rA(int b) {
		int a[] = new int[b];
		for (int i = 0; i < b; i++) {
			try {
				a[i] = rI();
			} catch (IOException e) {
				e.printStackTrace();
			}
		}
		return a;
	}

	int rI() throws IOException {
		return Integer.parseInt(rS());
	}

	long rL() throws IOException {
		return Long.parseLong(rS());
	}

	void sort(int[] a) {
		Integer arr[] = new Integer[a.length];
		for (int i = 0; i < a.length; i++) {
			arr[i] = a[i];
		}
		Arrays.sort(arr);
		for (int i = 0; i < a.length; i++) {
			a[i] = arr[i];
		}
	}

}