Problem: You are given string s of length n consisting of 0-s and 1-s. You build an infinite string t as a concatenation of an infinite number of strings s, or t = ssss ... For example, if s = 10010, then t = 100101001010010...

Calculate the number of prefixes of t with balance equal to x. The balance of some string q is equal to cnt_{0, q} - cnt_{1, q}, where cnt_{0, q} is the number of occurrences of 0 in q, and cnt_{1, q} is the number of occurrences of 1 in q. The number of such prefixes can be infinite; if it is so, you must say that.

A prefix is a string consisting of several first letters of a given string, without any reorders. An empty prefix is also a valid prefix. For example, the string "abcd" has 5 prefixes: empty string, "a", "ab", "abc" and "abcd".

Input

The first line contains the single integer T (1 ≤ T ≤ 100) — the number of test cases.

Next 2T lines contain descriptions of test cases — two lines per test case. The first line contains two integers n and x (1 ≤ n ≤ 10^5, -10^9 ≤ x ≤ 10^9) — the length of string s and the desired balance, respectively.

The second line contains the binary string s (|s| = n, s_i ∈ \{0, 1\}).

It's guaranteed that the total sum of n doesn't exceed 10^5.

Output

Print T integers — one per test case. For each test case print the number of prefixes or -1 if there is an infinite number of such prefixes.

Example

Input


4
6 10
010010
5 3
10101
1 0
0
2 0
01


Output


3
0
1
-1

Note

In the first test case, there are 3 good prefixes of t: with length 28, 30 and 32.

Solution (in PYTHON):

Solution:
''' Problem 1 :     10:15-10:39
t=int(input())

for i in range(0,t):
    ans=''
    n=int(input())
    if n%2==0:
        p=int(n/2)
        ans=ans+'1'*p
        
    else:
        p=int((n-3)/2)
        ans=(ans+'7')+'1'*p
    print(ans)'''

        
'''Problem2'''
for _ in range(input()):
	balance = [0]
	n, x = map(int, raw_input().split())
	s = raw_input()
 
	for i in s:
		if i == '0':
			balance.append(balance[-1] + 1)
		else:
			balance.append(balance[-1] - 1)
	if balance[-1] == 0:
		if x in balance:
			print -1
		else:
			print 0
	elif balance[-1] > 0:
		ans = 0
		if x == 0:
			ans = 1
		for i in balance[1:]:
			if i <= x and (x-i)%balance[-1] == 0:
				ans += 1
		print ans
	else:
		ans = 0
		if x == 0:
			ans = 1
		for i in balance[1:]:
			if x <= i and (i - x)%(abs(balance[-1])) == 0:
				ans += 1
		print ans