Problem: A permutation is a sequence of integers from 1 to n of length n containing each number exactly once. For example, [1], [4, 3, 5, 1, 2], [3, 2, 1] — are permutations, and [1, 1], [4, 3, 1], [2, 3, 4] — no.

Permutation a is lexicographically smaller than permutation b (they have the same length n), if in the first index i in which they differ, a[i] < b[i]. For example, the permutation [1, 3, 2, 4] is lexicographically smaller than the permutation [1, 3, 4, 2], because the first two elements are equal, and the third element in the first permutation is smaller than in the second.

The next permutation for a permutation a of length n — is the lexicographically smallest permutation b of length n that lexicographically larger than a. For example: 

  * for permutation [2, 1, 4, 3] the next permutation is [2, 3, 1, 4]; 
  * for permutation [1, 2, 3] the next permutation is [1, 3, 2]; 
  * for permutation [2, 1] next permutation does not exist. 



You are given the number n — the length of the initial permutation. The initial permutation has the form a = [1, 2, …, n]. In other words, a[i] = i (1 ≤ i ≤ n).

You need to process q queries of two types: 

  * 1 l r: query for the sum of all elements on the segment [l, r]. More formally, you need to find a[l] + a[l + 1] + … + a[r]. 
  * 2 x: x times replace the current permutation with the next permutation. For example, if x=2 and the current permutation has the form [1, 3, 4, 2], then we should perform such a chain of replacements [1, 3, 4, 2] → [1, 4, 2, 3] → [1, 4, 3, 2]. 



For each query of the 1-st type output the required sum.

Input

The first line contains two integers n (2 ≤ n ≤ 2 ⋅ 10^5) and q (1 ≤ q ≤ 2 ⋅ 10^5), where n — the length of the initial permutation, and q — the number of queries.

The next q lines contain a single query of the 1-st or 2-nd type. The 1-st type query consists of three integers 1, l and r (1 ≤ l ≤ r ≤ n), the 2-nd type query consists of two integers 2 and x (1 ≤ x ≤ 10^5).

It is guaranteed that all requests of the 2-nd type are possible to process.

Output

For each query of the 1-st type, output on a separate line one integer — the required sum.

Example

Input


4 4
1 2 4
2 3
1 1 2
1 3 4


Output


9
4
6

Note

Initially, the permutation has the form [1, 2, 3, 4]. Queries processing is as follows: 

  1. 2 + 3 + 4 = 9; 
  2. [1, 2, 3, 4] → [1, 2, 4, 3] → [1, 3, 2, 4] → [1, 3, 4, 2]; 
  3. 1 + 3 = 4; 
  4. 4 + 2 = 6 

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
inline int read() {
  register int res = 0;
  register char c = getchar(), f = 1;
  while (c < 48 || c > 57) {
    if (c == '-') f = 0;
    c = getchar();
  }
  while (c >= 48 && c <= 57)
    res = (res << 3) + (res << 1) + (c & 15), c = getchar();
  return f ? res : -res;
}
inline void write(long long x) {
  register char c[21], len = 0;
  if (!x) return putchar('0'), void();
  if (x < 0) x = -x, putchar('-');
  while (x) c[++len] = x % 10, x /= 10;
  while (len) putchar(c[len--] + 48);
}
const int N = 2e5 + 10;
int n, m, a[N], k, op, l, r;
long long x, s[N], fac[15];
bool vis[15];
void getp(long long x) {
  memset(vis, 0, sizeof(vis));
  for (int i = 1; i <= k; ++i) {
    int t = x / fac[k - i] + 1;
    x %= fac[k - i];
    for (int j = 1; j <= k; ++j)
      if (!vis[j])
        if (!--t) {
          a[i] = j, vis[j] = 1;
          break;
        }
  }
}
int main() {
  n = read(), m = read();
  for (int i = 1; i <= n; ++i) s[i] = s[i - 1] + i;
  k = min(n, 14);
  fac[0] = 1;
  for (int i = 1; i <= k; ++i) fac[i] = fac[i - 1] * i;
  while (m--) {
    op = read();
    if (op == 1) {
      l = read(), r = read();
      write(s[r] - s[l - 1]), putchar('\n');
    } else {
      x += read();
      getp(x);
      for (int i = n - k + 1; i <= n; ++i)
        s[i] = s[i - 1] + a[i + k - n] + (n - k);
    }
  }
}