Problem: You're given an integer n. For every integer i from 2 to n, assign a positive integer a_i such that the following conditions hold:

  * For any pair of integers (i,j), if i and j are coprime, a_i ≠ a_j. 
  * The maximal value of all a_i should be minimized (that is, as small as possible). 



A pair of integers is called [coprime](https://en.wikipedia.org/wiki/Coprime_integers) if their [greatest common divisor](https://en.wikipedia.org/wiki/Greatest_common_divisor) is 1.

Input

The only line contains the integer n (2 ≤ n ≤ 10^5).

Output

Print n-1 integers, a_2, a_3, …, a_n (1 ≤ a_i ≤ n). 

If there are multiple solutions, print any of them.

Examples

Input


4


Output


1 2 1 

Input


3


Output


2 1

Note

In the first example, notice that 3 and 4 are coprime, so a_3 ≠ a_4. Also, notice that a=[1,2,3] satisfies the first condition, but it's not a correct answer because its maximal value is 3.

Solution (in PYTHON3):

Solution:
from sys import stdin,stdout
from itertools import combinations
from collections import defaultdict,OrderedDict
import math
import heapq

def listIn():
    return list((map(int,stdin.readline().strip().split())))

def stringListIn():
    return([x for x in stdin.readline().split()])
    
def intIn():
    return (int(stdin.readline()))

def stringIn():
    return (stdin.readline().strip())
    
def primes(n):
    """ Returns  a list of primes < n """
    sieve = [True] * n
    for i in range(3,int(n**0.5)+1,2):
        if sieve[i]:
            sieve[i*i::2*i]=[False]*((n-i*i-1)//(2*i)+1)
    return [2] + [i for i in range(3,n,2) if sieve[i]]


def isPrime(n) : 
    if (n <= 1) : 
        return False
    if (n <= 3) : 
        return True
    if (n % 2 == 0 or n % 3 == 0) : 
        return False
    i = 5
    while(i * i <= n) : 
        if (n % i == 0 or n % (i + 2) == 0) : 
            return False
        i = i + 6
    return True
    
def leastPrimeFactor(n) : 
    least_prime = [0] * (n + 1) 
    least_prime[1] = 1
    for i in range(2, n + 1) : 
        if (least_prime[i] == 0) : 
            least_prime[i] = i 
            for j in range(2 * i, n + 1, i) : 
                if (least_prime[j] == 0) : 
                    least_prime[j] = i 
    return least_prime



if __name__=="__main__":
    n=intIn()
    
    A=leastPrimeFactor(n)
    prime_n=sorted(set(A[2:]))
    #print(prime_n)
    di={}
    c=1
    for ele in prime_n:
        di[ele]=c
        c+=1
    
    #print(di)
    ans=[0]*(n+1)
    
    for i in range(2,n+1):
        ans[i]=di[A[i]]
    
    print(*ans[2:])