Problem: Let's define a string <x> as an opening tag, where x is any small letter of the Latin alphabet. Each opening tag matches a closing tag of the type </x>, where x is the same letter.

Tegs can be nested into each other: in this case one opening and closing tag pair is located inside another pair.

Let's define the notion of a XML-text: 

  * an empty string is a XML-text
  * if s is a XML-text, then s'=<a>+s+</a> also is a XML-text, where a is any small Latin letter 
  * if s1, s2 are XML-texts, then s1+s2 also is a XML-text



You are given a XML-text (it is guaranteed that the text is valid), your task is to print in the following form: 

  * each tag (opening and closing) is located on a single line 
  * print before the tag 2 * h spaces, where h is the level of the tag's nestedness. 

Input

The input data consists on the only non-empty string — the XML-text, its length does not exceed 1000 characters. It is guaranteed that the text is valid. The text contains no spaces.

Output

Print the given XML-text according to the above-given rules.

Examples

Input

&lt;a&gt;&lt;b&gt;&lt;c&gt;&lt;/c&gt;&lt;/b&gt;&lt;/a&gt;


Output

&lt;a&gt;
  &lt;b&gt;
    &lt;c&gt;
    &lt;/c&gt;
  &lt;/b&gt;
&lt;/a&gt;


Input

&lt;a&gt;&lt;b&gt;&lt;/b&gt;&lt;d&gt;&lt;c&gt;&lt;/c&gt;&lt;/d&gt;&lt;/a&gt;


Output

&lt;a&gt;
  &lt;b&gt;
  &lt;/b&gt;
  &lt;d&gt;
    &lt;c&gt;
    &lt;/c&gt;
  &lt;/d&gt;
&lt;/a&gt;

Solution (in PYTHON3):

Solution:
n=input()
ls=[]
i=0
while (i<len(n)):
    if(n[i]=='<'):
        p=''
        j=i
        while(n[j]!='>'):
            p+=n[j]
            j+=1
        p+='>'
        ls.append(p)
    i+=1
k=0
i=0
while i<len(ls):
    count=0
    anticount=0
    if (ls[i].replace(' ','')[1]=='/'):
        i+=1
        continue
    else:
        j=i+1
        while(j<len(ls) and count-anticount>=0):
            if((ls[j].replace(' ','')==ls[i].replace(' ',''))):
               count+=1
            elif(ls[j].replace(' ','').replace('<','')=='/'+ls[i].replace(' ','').replace('<','')):
                anticount+=1
            j+=1
        j=i+1
        while ((j<len(ls) and ls[j].replace(' ','').replace('<','')!='/'+ls[i].replace(' ','').replace('<','')) or count!=0):
            if(ls[j].replace(' ','').replace('<','')=='/'+ls[i].replace(' ','').replace('<','')):
                if(count>0):
                    count-=1
            ls[j]=' '*2 + ls[j]
            j+=1   
    i+=1
for i in ls:
    print(i)