Problem: There is a road with length l meters. The start of the road has coordinate 0, the end of the road has coordinate l.

There are two cars, the first standing at the start of the road and the second standing at the end of the road. They will start driving simultaneously. The first car will drive from the start to the end and the second car will drive from the end to the start.

Initially, they will drive with a speed of 1 meter per second. There are n flags at different coordinates a_1, a_2, …, a_n. Each time when any of two cars drives through a flag, the speed of that car increases by 1 meter per second.

Find how long will it take for cars to meet (to reach the same coordinate). 

Input

The first line contains one integer t (1 ≤ t ≤ 10^4): the number of test cases.

The first line of each test case contains two integers n, l (1 ≤ n ≤ 10^5, 1 ≤ l ≤ 10^9): the number of flags and the length of the road.

The second line contains n integers a_1, a_2, …, a_n in the increasing order (1 ≤ a_1 < a_2 < … < a_n < l).

It is guaranteed that the sum of n among all test cases does not exceed 10^5.

Output

For each test case print a single real number: the time required for cars to meet.

Your answer will be considered correct, if its absolute or relative error does not exceed 10^{-6}. More formally, if your answer is a and jury's answer is b, your answer will be considered correct if \frac{|a-b|}{max{(1, b)}} ≤ 10^{-6}.

Example

Input


5
2 10
1 9
1 10
1
5 7
1 2 3 4 6
2 1000000000
413470354 982876160
9 478
1 10 25 33 239 445 453 468 477


Output


3.000000000000000
3.666666666666667
2.047619047619048
329737645.750000000000000
53.700000000000000

Note

In the first test case cars will meet in the coordinate 5.

The first car will be in the coordinate 1 in 1 second and after that its speed will increase by 1 and will be equal to 2 meters per second. After 2 more seconds it will be in the coordinate 5. So, it will be in the coordinate 5 in 3 seconds.

The second car will be in the coordinate 9 in 1 second and after that its speed will increase by 1 and will be equal to 2 meters per second. After 2 more seconds it will be in the coordinate 5. So, it will be in the coordinate 5 in 3 seconds.

In the second test case after 1 second the first car will be in the coordinate 1 and will have the speed equal to 2 meters per second, the second car will be in the coordinate 9 and will have the speed equal to 1 meter per second. So, they will meet after (9-1)/(2+1) = 8/3 seconds. So, the answer is equal to 1 + 8/3 = 11/3.

Solution (in JAVA):

Solution:
import sun.security.krb5.internal.PAData;

import java.io.*;
import java.util.*;

public class Main {

    public static void main(String[] args) throws Exception {
        MyReader reader = new MyReader(System.in);
//        MyReader reader = new MyReader(new FileInputStream("input.txt"));
        MyWriter writer = new MyWriter(System.out);
        new Main().run(reader, writer);
        writer.close();
    }

    private void run(MyReader reader, MyWriter writer) throws Exception {
        int t = reader.nextInt();
        for (int i = 0; i < t; i++) {
            int n = reader.nextInt();
            double x1 = 0;
            double x2 = reader.nextInt();
            double v1 = 1;
            double v2 = 1;
            int st = 0;
            int en = n - 1;
            int[] a = reader.nextIntArray(n);
            double ans = 0;
            while (st <= en) {
                double t1 = (a[st] - x1) / v1;
                double t2 = (x2 - a[en]) / v2;
                if (t1 < t2) {
                    ans += t1;
                    x1 = a[st++];
                    v1++;
                    x2 -= t1 * v2;
                } else {
                    ans += t2;
                    x2 = a[en--];
                    v2++;
                    x1 += t2 * v1;
                }
            }
            ans += (x2 - x1) / (v1 + v2);
            writer.println(ans + "");
        }
    }

    class Pair<T> extends Pair2<T, T> {

        public Pair(T x, T y) {
            super(x, y);
        }
    }

    class Pair2<T, U> {

        T x;
        U y;

        public Pair2(T x, U y) {
            this.x = x;
            this.y = y;
        }
    }

    private static class MyReader {

        final BufferedInputStream in;
        final int bufSize = 1 << 16;
        final byte[] buf = new byte[bufSize];
        int i = bufSize;
        int k = bufSize;
        boolean end = false;
        final StringBuilder str = new StringBuilder();

        MyReader(InputStream in) {
            this.in = new BufferedInputStream(in, bufSize);
        }

        int nextInt() throws IOException {
            return (int) nextLong();
        }

        int[] nextIntArray(int n) throws IOException {
            int[] m = new int[n];
            for (int i = 0; i < n; i++) {
                m[i] = nextInt();
            }
            return m;
        }

        int[][] nextIntMatrix(int n, int m) throws IOException {
            int[][] a = new int[n][0];
            for (int j = 0; j < n; j++) {
                a[j] = nextIntArray(m);
            }
            return a;
        }

        long nextLong() throws IOException {
            int c;
            long x = 0;
            int sign = 1;
            while ((c = nextChar()) <= 32) ;
            if (c == '-') {
                sign = -1;
                c = nextChar();
            }
            if (c == '+') {
                c = nextChar();
            }
            while (c >= '0') {
                x = x * 10 + (c - '0');
                c = nextChar();
            }
            return sign * x;
        }

        long[] nextLongArray(int n) throws IOException {
            long[] m = new long[n];
            for (int i = 0; i < n; i++) {
                m[i] = nextLong();
            }
            return m;
        }

        int nextChar() throws IOException {
            if (i == k) {
                k = in.read(buf, 0, bufSize);
                i = 0;
            }
            return i >= k ? -1 : buf[i++];
        }

        String nextString() throws IOException {
            if (end) {
                return null;
            }
            str.setLength(0);
            int c;
            while ((c = nextChar()) <= 32 && c != -1) ;
            if (c == -1) {
                end = true;
                return null;
            }
            while (c > 32) {
                str.append((char) c);
                c = nextChar();
            }
            return str.toString();
        }

        String nextLine() throws IOException {
            if (end) {
                return null;
            }
            str.setLength(0);
            int c = nextChar();
            while (c != '\n' && c != '\r' && c != -1) {
                str.append((char) c);
                c = nextChar();
            }
            if (c == -1) {
                end = true;
                if (str.length() == 0) {
                    return null;
                }
            }
            if (c == '\r') {
                nextChar();
            }
            return str.toString();
        }

        char[] nextCharArray() throws IOException {
            return nextString().toCharArray();
        }

        char[][] nextCharMatrix(int n) throws IOException {
            char[][] a = new char[n][0];
            for (int i = 0; i < n; i++) {
                a[i] = nextCharArray();
            }
            return a;
        }
    }

    static class MyWriter {

        final BufferedOutputStream out;
        final int bufSize = 1 << 16;
        final byte buf[] = new byte[bufSize];
        int i = 0;
        final byte c[] = new byte[30];
        static final String newLine = System.getProperty("line.separator");

        MyWriter(OutputStream out) {
            this.out = new BufferedOutputStream(out, bufSize);
        }

        void print(long x) throws IOException {
            int j = 0;
            if (i + 30 >= bufSize) {
                flush();
            }
            if (x < 0) {
                buf[i++] = (byte) ('-');
                x = -x;
            }
            do {
                c[j++] = (byte) (x % 10 + '0');
                x /= 10;
            } while (x != 0);
            while (--j >= 0) {
                buf[i++] = c[j];
            }
        }

        void println(long x) throws IOException {
            print(x);
            println();
        }

        void print(int[] m) throws IOException {
            for (int a : m) {
                print(a);
                print(' ');
            }
        }

        void print(long[] m) throws IOException {
            for (long a : m) {
                print(a);
                print(' ');
            }
        }

        void print(String s) throws IOException {
            for (int i = 0; i < s.length(); i++) {
                print(s.charAt(i));
            }
        }

        void print(char x) throws IOException {
            if (i == bufSize) {
                flush();
            }
            buf[i++] = (byte) x;
        }

        void print(char[] m) throws IOException {
            for (char c : m) {
                print(c);
            }
        }

        void println(String s) throws IOException {
            print(s);
            println();
        }

        void println() throws IOException {
            print(newLine);
        }

        void flush() throws IOException {
            out.write(buf, 0, i);
            out.flush();
            i = 0;
        }

        void close() throws IOException {
            flush();
            out.close();
        }
    }
}