Problem: You're given an integer n. For every integer i from 2 to n, assign a positive integer a_i such that the following conditions hold:

  * For any pair of integers (i,j), if i and j are coprime, a_i ≠ a_j. 
  * The maximal value of all a_i should be minimized (that is, as small as possible). 



A pair of integers is called [coprime](https://en.wikipedia.org/wiki/Coprime_integers) if their [greatest common divisor](https://en.wikipedia.org/wiki/Greatest_common_divisor) is 1.

Input

The only line contains the integer n (2 ≤ n ≤ 10^5).

Output

Print n-1 integers, a_2, a_3, …, a_n (1 ≤ a_i ≤ n). 

If there are multiple solutions, print any of them.

Examples

Input


4


Output


1 2 1 

Input


3


Output


2 1

Note

In the first example, notice that 3 and 4 are coprime, so a_3 ≠ a_4. Also, notice that a=[1,2,3] satisfies the first condition, but it's not a correct answer because its maximal value is 3.

Solution (in JAVA):

Solution:
import java.io.OutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.PrintWriter;
import java.util.Scanner;

/**
 * Built using CHelper plug-in
 * Actual solution is at the top
 *
 * @author test
 */
public class Main {
    public static void main(String[] args) {
        InputStream inputStream = System.in;
        OutputStream outputStream = System.out;
        Scanner in = new Scanner(inputStream);
        PrintWriter out = new PrintWriter(outputStream);
        CEhabAndASpecialColoringProblem solver = new CEhabAndASpecialColoringProblem();
        solver.solve(1, in, out);
        out.close();
    }

    static class CEhabAndASpecialColoringProblem {
        public void solve(int testNumber, Scanner in, PrintWriter out) {

            int n = in.nextInt();

            int[] res = new int[n + 1];

            int cnt = 1;
            for (int i = 2; i <= n; i++) {

                boolean found = false;
                for (int j = 2; j <= Math.floor(Math.sqrt(i)); j++) {
                    if (i % j == 0) {
                        res[i] = res[j];
                        found = true;
                        break;
                    }
                }

                if (!found) {
                    res[i] = cnt;
                    cnt++;
                }
            }

            for (int i = 2; i <= n; i++) {
                out.print(res[i] + " ");
            }

        }

    }
}