Problem: Student Dima from Kremland has a matrix a of size n × m filled with non-negative integers.

He wants to select exactly one integer from each row of the matrix so that the bitwise exclusive OR of the selected integers is strictly greater than zero. Help him!

Formally, he wants to choose an integers sequence c_1, c_2, …, c_n (1 ≤ c_j ≤ m) so that the inequality a_{1, c_1} ⊕ a_{2, c_2} ⊕ … ⊕ a_{n, c_n} > 0 holds, where a_{i, j} is the matrix element from the i-th row and the j-th column.

Here x ⊕ y denotes the [bitwise XOR operation](https://en.wikipedia.org/wiki/Bitwise_operation#XOR) of integers x and y.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 500) — the number of rows and the number of columns in the matrix a.

Each of the next n lines contains m integers: the j-th integer in the i-th line is the j-th element of the i-th row of the matrix a, i.e. a_{i, j} (0 ≤ a_{i, j} ≤ 1023). 

Output

If there is no way to choose one integer from each row so that their bitwise exclusive OR is strictly greater than zero, print "NIE".

Otherwise print "TAK" in the first line, in the next line print n integers c_1, c_2, … c_n (1 ≤ c_j ≤ m), so that the inequality a_{1, c_1} ⊕ a_{2, c_2} ⊕ … ⊕ a_{n, c_n} > 0 holds. 

If there is more than one possible answer, you may output any.

Examples

Input


3 2
0 0
0 0
0 0


Output


NIE


Input


2 3
7 7 7
7 7 10


Output


TAK
1 3 

Note

In the first example, all the numbers in the matrix are 0, so it is impossible to select one number in each row of the table so that their bitwise exclusive OR is strictly greater than zero.

In the second example, the selected numbers are 7 (the first number in the first line) and 10 (the third number in the second line), 7 ⊕ 10 = 13, 13 is more than 0, so the answer is found.

Solution (in PYTHON3):

Solution:
import sys
from math import gcd
import bisect
import heapq
from collections import deque

# from types import GeneratorType
# def bootstrap(func, stack=[]):
#     def wrapped_function(*args, **kwargs):
#         if stack:
#             return func(*args, **kwargs)
#         else:
#             call = func(*args, **kwargs)
#             while True:
#                 if type(call) is GeneratorType:
#                     stack.append(call)
#                     call = next(call)
#                 else:
#                     stack.pop()
#                     if not stack:
#                         break
#                     call = stack[-1].send(call)
#             return call
#     return wrapped_function

Ri = lambda : [int(x) for x in sys.stdin.readline().split()]
ri = lambda : sys.stdin.readline().strip()
 
def input(): return sys.stdin.readline().strip()
def list2d(a, b, c): return [[c] * b for i in range(a)]
def list3d(a, b, c, d): return [[[d] * c for j in range(b)] for i in range(a)]
def list4d(a, b, c, d, e): return [[[[e] * d for j in range(c)] for j in range(b)] for i in range(a)]
def ceil(x, y=1): return int(-(-x // y))
def INT(): return int(input())
def MAP(): return map(int, input().split())
def LIST(N=None): return list(MAP()) if N is None else [INT() for i in range(N)]
def Yes(): print('Yes')
def No(): print('No')
def YES(): print('YES')
def NO(): print('NO')
INF = 10 ** 18
MOD = 998244353

flag = False
n,m  = Ri()
arr=  []
for i in range(n):
    temp = Ri()
    arr.append(temp)

ts = set()
ind = -1
for i in range(n):
    s = set()
    for j in range(m):
        s.add(arr[i][j])
    if len(s) > 1:
        ind = i
        ts = s
        flag = True
        break


xor  = 0
val=  -1
for i in range(n):
    if i == ind:
        val = arr[i][0]
    xor = xor ^ arr[i][0]
if xor == 0:
    if not flag : 
        print("NIE")
    else:
        print('TAK')
        for  i in range(n):
            if ind == i:
                for j in range(m):
                    if arr[i][j] != arr[i][0]:
                        print(j+1,end=" ")
                        break
            else:
                print(1,end=" ")
else:
    print('TAK')
    print(*[1]*n)