Problem: Acacius is studying strings theory. Today he came with the following problem.

You are given a string s of length n consisting of lowercase English letters and question marks. It is possible to replace question marks with lowercase English letters in such a way that a string "abacaba" occurs as a substring in a resulting string exactly once?

Each question mark should be replaced with exactly one lowercase English letter. For example, string "a?b?c" can be transformed into strings "aabbc" and "azbzc", but can't be transformed into strings "aabc", "a?bbc" and "babbc".

Occurrence of a string t of length m in the string s of length n as a substring is a index i (1 ≤ i ≤ n - m + 1) such that string s[i..i+m-1] consisting of m consecutive symbols of s starting from i-th equals to string t. For example string "ababa" has two occurrences of a string "aba" as a substring with i = 1 and i = 3, but there are no occurrences of a string "aba" in the string "acba" as a substring.

Please help Acacius to check if it is possible to replace all question marks with lowercase English letters in such a way that a string "abacaba" occurs as a substring in a resulting string exactly once.

Input

First line of input contains an integer T (1 ≤ T ≤ 5000), number of test cases. T pairs of lines with test case descriptions follow.

The first line of a test case description contains a single integer n (7 ≤ n ≤ 50), length of a string s.

The second line of a test case description contains string s of length n consisting of lowercase English letters and question marks.

Output

For each test case output an answer for it.

In case if there is no way to replace question marks in string s with a lowercase English letters in such a way that there is exactly one occurrence of a string "abacaba" in the resulting string as a substring output "No".

Otherwise output "Yes" and in the next line output a resulting string consisting of n lowercase English letters. If there are multiple possible strings, output any.

You may print every letter in "Yes" and "No" in any case you want (so, for example, the strings yEs, yes, Yes, and YES will all be recognized as positive answer).

Example

Input


6
7
abacaba
7
???????
11
aba?abacaba
11
abacaba?aba
15
asdf???f???qwer
11
abacabacaba


Output


Yes
abacaba
Yes
abacaba
Yes
abadabacaba
Yes
abacabadaba
No
No

Note

In first example there is exactly one occurrence of a string "abacaba" in the string "abacaba" as a substring.

In second example seven question marks can be replaced with any seven lowercase English letters and with "abacaba" in particular.

In sixth example there are two occurrences of a string "abacaba" as a substring.

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.BufferedWriter;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.OutputStreamWriter;
import java.util.ArrayList;
import java.util.Random;
import java.util.StringTokenizer;

public class AcaciusAndString {
	
	static final int MAXN = 1000_006;
	
	static final long MOD = (long) 1e9 + 7;
	
	public static void main(String[] args) throws IOException {
		MyScanner s = new MyScanner();
		Print p = new Print();
		int t = s.nextInt();
		while (t-- > 0) {
			int n = s.nextInt();
			String str = s.nextLine();
			String pat = "abacaba";
			char[] arr = str.toCharArray();
			char[] patarr = pat.toCharArray();
			int cou = 0;
			int m = patarr.length;
			
			cou = chk(arr, patarr, n, m);
			if (cou == 1) {
				p.println("Yes");
				str = str.replace('?', 'z');
				p.println(str);
			} else if (cou > 1) {
				p.println("No");
			} else {
				for (int i = 0; i < n; i++) {
					int ind = i;
					int k = 0;
					while (k < m && ind < n && (arr[ind] == patarr[k] || arr[ind] == '?')) {
						k++;
						ind++;
					}
					if (k == m) {
						char[] tmp = arr.clone();
						for (int j = i; j < i + m; j++) {
							tmp[j] = patarr[j - i];
						}
						cou = chk(tmp, patarr, n, m);
						if (cou == 1) {
							for (int j = 0; j < n; j++)
								if (tmp[j] == '?')
									tmp[j] = 'z';
							arr = tmp;
							break;
						} else {
							cou = 0;
						}
					}
				}
				if (cou > 0) {
					p.println("Yes");
					p.println(String.valueOf(arr));
				}
				else
					p.println("No");
			}
		}
		p.close();
	}
	
	public static int chk(char[] arr, char[] patarr, int n, int m) {
		int cou = 0;
		for (int i = 0; i < n; i++) {
			int ind = i;
			int k = 0;
			while (k < m && ind < n && arr[ind] == patarr[k]) {
				k++;
				ind++;
			}
			if (k == m)
				cou++;
		}
		return cou;
	}
	public static class Pair implements Comparable<Pair> {
		
		int first;
		
		int second;
		
		public Pair(int a, int b) {
			this.first = a;
			this.second = b;
		}
		
		@Override
		public int hashCode() {
			final int prime = 31;
			int result = 1;
			result = prime * result + first;
			result = prime * result + second;
			return result;
		}
		
		@Override
		public boolean equals(Object obj) {
			if (this == obj)
				return true;
			if (obj == null)
				return false;
			if (getClass() != obj.getClass())
				return false;
			Pair other = (Pair) obj;
			if (first != other.first)
				return false;
			if (second != other.second)
				return false;
			return true;
		}
		
		@Override
		public int compareTo(Pair o) {
			// TODO Auto-generated method stub
			return o.first - first;
		}
		
	}
	
	public static class Helper {
		
		long MOD = (long) 1e9 + 7;
		
		int MAXN = 1000_006;;
		
		Random rnd;
		
		public Helper(long mod, int maxn) {
			MOD = mod;
			MAXN = maxn;
			rnd = new Random();
		}
		
		public Helper() {
			
		}
		
		public static int[] sieve;
		
		public static ArrayList<Integer> primes;
		
		public void setSieve() {
			primes = new ArrayList<>();
			sieve = new int[MAXN];
			int i, j;
			for (i = 2; i < MAXN; ++i)
				if (sieve[i] == 0) {
					primes.add(i);
					for (j = i; j < MAXN; j += i) {
						sieve[j] = i;
					}
				}
		}
		
		public static long[] factorial;
		
		public void setFactorial() {
			factorial = new long[MAXN];
			factorial[0] = 1;
			for (int i = 1; i < MAXN; ++i)
				factorial[i] = factorial[i - 1] * i % MOD;
		}
		
		public long getFactorial(int n) {
			if (factorial == null)
				setFactorial();
			return factorial[n];
		}
		
		public long ncr(int n, int r) {
			if (r > n)
				return 0;
			if (factorial == null)
				setFactorial();
			long numerator = factorial[n];
			long denominator = factorial[r] * factorial[n - r] % MOD;
			return numerator * pow(denominator, MOD - 2, MOD) % MOD;
		}
		
		public long[] getLongArray(int size, MyScanner s) throws Exception {
			long[] ar = new long[size];
			for (int i = 0; i < size; ++i)
				ar[i] = s.nextLong();
			return ar;
		}
		
		public int[] getIntArray(int size, MyScanner s) throws Exception {
			int[] ar = new int[size];
			for (int i = 0; i < size; ++i)
				ar[i] = s.nextInt();
			return ar;
		}
		
		public int[] getIntArray(String s) throws Exception {
			s = s.trim().replaceAll("\\s+", " ");
			String[] strs = s.split(" ");
			int[] arr = new int[strs.length];
			for (int i = 0; i < strs.length; i++) {
				arr[i] = Integer.parseInt(strs[i]);
			}
			return arr;
		}
		
		public long gcd(long a, long b) {
			return b == 0 ? a : gcd(b, a % b);
		}
		
		public int gcd(int a, int b) {
			return b == 0 ? a : gcd(b, a % b);
		}
		
		public long max(long[] ar) {
			long ret = ar[0];
			for (long itr : ar)
				ret = Math.max(ret, itr);
			return ret;
		}
		
		public int max(int[] ar) {
			int ret = ar[0];
			for (int itr : ar)
				ret = Math.max(ret, itr);
			return ret;
		}
		
		public long min(long[] ar) {
			long ret = ar[0];
			for (long itr : ar)
				ret = Math.min(ret, itr);
			return ret;
		}
		
		public int min(int[] ar) {
			int ret = ar[0];
			for (int itr : ar)
				ret = Math.min(ret, itr);
			return ret;
		}
		
		public long sum(long[] ar) {
			long sum = 0;
			for (long itr : ar)
				sum += itr;
			return sum;
		}
		
		public long sum(int[] ar) {
			long sum = 0;
			for (int itr : ar)
				sum += itr;
			return sum;
		}
		
		public long pow(long base, long exp, long MOD) {
			base %= MOD;
			long ret = 1;
			while (exp > 0) {
				if ((exp & 1) == 1)
					ret = ret * base % MOD;
				base = base * base % MOD;
				exp >>= 1;
			}
			return ret;
		}
		
	}
	
	static class Print {
		
		private BufferedWriter bw;
		
		public Print() {
			this.bw = new BufferedWriter(new OutputStreamWriter(System.out));
		}
		
		public void print(Object object) throws IOException {
			bw.append("" + object);
		}
		
		public void println(Object object) throws IOException {
			print(object);
			bw.append("\n");
		}
		
		public void close() throws IOException {
			bw.close();
		}
	}
	
	public static class MyScanner {
		
		BufferedReader br;
		
		StringTokenizer st;
		
		public MyScanner() {
			br = new BufferedReader(new InputStreamReader(System.in));
		}
		
		String next() {
			while (st == null || !st.hasMoreElements()) {
				try {
					st = new StringTokenizer(br.readLine());
				}
				catch (IOException e) {
					e.printStackTrace();
				}
			}
			return st.nextToken();
		}
		
		int nextInt() {
			return Integer.parseInt(next());
		}
		
		long nextLong() {
			return Long.parseLong(next());
		}
		
		double nextDouble() {
			return Double.parseDouble(next());
		}
		
		String nextLine() {
			String str = "";
			try {
				str = br.readLine();
			}
			catch (IOException e) {
				e.printStackTrace();
			}
			return str;
		}
	}
	
}