Problem: Acacius is studying strings theory. Today he came with the following problem.

You are given a string s of length n consisting of lowercase English letters and question marks. It is possible to replace question marks with lowercase English letters in such a way that a string "abacaba" occurs as a substring in a resulting string exactly once?

Each question mark should be replaced with exactly one lowercase English letter. For example, string "a?b?c" can be transformed into strings "aabbc" and "azbzc", but can't be transformed into strings "aabc", "a?bbc" and "babbc".

Occurrence of a string t of length m in the string s of length n as a substring is a index i (1 ≤ i ≤ n - m + 1) such that string s[i..i+m-1] consisting of m consecutive symbols of s starting from i-th equals to string t. For example string "ababa" has two occurrences of a string "aba" as a substring with i = 1 and i = 3, but there are no occurrences of a string "aba" in the string "acba" as a substring.

Please help Acacius to check if it is possible to replace all question marks with lowercase English letters in such a way that a string "abacaba" occurs as a substring in a resulting string exactly once.

Input

First line of input contains an integer T (1 ≤ T ≤ 5000), number of test cases. T pairs of lines with test case descriptions follow.

The first line of a test case description contains a single integer n (7 ≤ n ≤ 50), length of a string s.

The second line of a test case description contains string s of length n consisting of lowercase English letters and question marks.

Output

For each test case output an answer for it.

In case if there is no way to replace question marks in string s with a lowercase English letters in such a way that there is exactly one occurrence of a string "abacaba" in the resulting string as a substring output "No".

Otherwise output "Yes" and in the next line output a resulting string consisting of n lowercase English letters. If there are multiple possible strings, output any.

You may print every letter in "Yes" and "No" in any case you want (so, for example, the strings yEs, yes, Yes, and YES will all be recognized as positive answer).

Example

Input


6
7
abacaba
7
???????
11
aba?abacaba
11
abacaba?aba
15
asdf???f???qwer
11
abacabacaba


Output


Yes
abacaba
Yes
abacaba
Yes
abadabacaba
Yes
abacabadaba
No
No

Note

In first example there is exactly one occurrence of a string "abacaba" in the string "abacaba" as a substring.

In second example seven question marks can be replaced with any seven lowercase English letters and with "abacaba" in particular.

In sixth example there are two occurrences of a string "abacaba" as a substring.

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.*;

import static java.lang.Math.*;
import static java.util.Arrays.fill;
import static java.util.Arrays.sort;
import static java.util.Comparator.comparingInt;
import static java.util.Comparator.comparingLong;

public class Main {
    FastScanner in;
    PrintWriter out;
    ArrayList<Integer>[] graph;
    ArrayList<GraphPair>[] weightedGraph;
    long mod = 998_244_353L; // (long) 1e9 + 7 || (long) 1e9 + 9
    boolean multitests = true;

    String t = "abacaba";

    private void solve() throws IOException {
        int n = in.nextInt();
        String s = in.next();

        int cnt = 0;
        for (int i = 0; i < n; i++)
            if (s.startsWith(t, i))
                cnt++;

        if (cnt > 0)
            out.println(cnt == 1 ? "Yes\n" + s.replace('?', 'z') : "No");

        else {
            for (int i = 0; i + t.length() <= n; i++) {
                char[] curC = s.toCharArray();
                for (int j = 0; j < t.length(); j++)
                    if (curC[i + j] == '?')
                        curC[i + j] = t.charAt(j);

                cnt = 0;
                String curS = new String(curC).replace('?', 'z');
                for (int j = 0; j < n; j++)
                    if (curS.startsWith(t, j))
                        cnt++;

                if (cnt == 1) {
                    out.println("Yes\n" + curS);
                    return;
                }
            }
            out.println("No");
        }
    }


    int binSearch(int[] a, int x) {
        int l = -1, mid, r = a.length;
        while (l + 1 < r) {
            mid = (l + r) / 2;
            if (a[mid] >= x)
                r = mid;
            else
                l = mid;
        }
        return r;
    }

    void shuffleInt(int[] a) {
        Random random = new Random();
        for (int i = a.length - 1; i > 0; i--) {
            int j = random.nextInt(i + 1);
            int swap = a[j];
            a[j] = a[i];
            a[i] = swap;
        }
    }

    void shuffleLong(long[] a) {
        Random random = new Random();
        for (int i = a.length - 1; i > 0; i--) {
            int j = random.nextInt(i + 1);
            long swap = a[j];
            a[j] = a[i];
            a[i] = swap;
        }
    }

    void reverseInt(int[] a) {
        for (int i = 0, j = a.length - 1; i < j; i++, j--) {
            int swap = a[i];
            a[i] = a[j];
            a[j] = swap;
        }
    }

    void reverseLong(long[] a) {
        for (int i = 0, j = a.length - 1; i < j; i++, j--) {
            long swap = a[i];
            a[i] = a[j];
            a[j] = swap;
        }
    }

    int maxInt(int[] a) {
        int max = a[0];
        for (int i = 1; i < a.length; i++)
            if (max < a[i])
                max = a[i];
        return max;
    }

    long maxLong(long[] a) {
        long max = a[0];
        for (int i = 1; i < a.length; i++)
            if (max < a[i])
                max = a[i];
        return max;
    }

    int minInt(int[] a) {
        int min = a[0];
        for (int i = 1; i < a.length; i++)
            if (min > a[i])
                min = a[i];
        return min;
    }

    long minLong(long[] a) {
        long min = a[0];
        for (int i = 1; i < a.length; i++)
            if (min > a[i])
                min = a[i];
        return min;
    }

    long sumInt(int[] a) {
        long s = 0;
        for (int i = 0; i < a.length; i++)
            s += a[i];
        return s;
    }

    long sumLong(long[] a) {
        long s = 0;
        for (int i = 0; i < a.length; i++)
            s += a[i];
        return s;
    }

    long gcd(long a, long b) {
        return b == 0 ? a : gcd(b, a % b);
    }

    long binpow(long a, long n) {
        long res = 1;
        while (n > 0) {
            if (n % 2 == 1)
                res = res * a;
            a *= a;
            n /= 2;
        }
        return res;
    }

    long binpowmod(long a, long n) {
        long res = 1;
        a %= mod;
        n %= mod - 1;
        while (n > 0) {
            if (n % 2 == 1)
                res = (res * a) % mod;
            a = (a * a) % mod;
            n /= 2;
        }
        return res;
    }

    class GraphPair implements Comparable<GraphPair> {
        int v;
        long w;

        GraphPair(int v, long w) {
            this.v = v;
            this.w = w;
        }

        public int compareTo(GraphPair o) {
            return w != o.w ? Long.compare(w, o.w) : Integer.compare(v, o.v);
        }
    }

    ArrayList<Integer>[] createGraph(int n) {
        ArrayList<Integer>[] graph = new ArrayList[n];
        for (int i = 0; i < n; i++)
            graph[i] = new ArrayList<>();
        return graph;
    }

    ArrayList<GraphPair>[] createWeightedGraph(int n) {
        ArrayList<GraphPair>[] graph = new ArrayList[n];
        for (int i = 0; i < n; i++)
            graph[i] = new ArrayList<>();
        return graph;
    }

    class FastScanner {
        StringTokenizer st;
        BufferedReader br;

        FastScanner(InputStream s) {
            br = new BufferedReader(new InputStreamReader(s), 32768);
        }

        String next() throws IOException {
            while (st == null || !st.hasMoreTokens())
                st = new StringTokenizer(br.readLine());
            return st.nextToken();
        }

        boolean hasNext() throws IOException {
            return br.ready() || (st != null && st.hasMoreTokens());
        }

        int nextInt() throws IOException {
            return Integer.parseInt(next());
        }

        int[] nextIntArray(int n) throws IOException {
            int[] a = new int[n];
            for (int i = 0; i < n; i++)
                a[i] = in.nextInt();
            return a;
        }

        int[][] nextIntTable(int n, int m) throws IOException {
            int[][] a = new int[n][m];
            for (int i = 0; i < n; i++)
                for (int j = 0; j < m; j++)
                    a[i][j] = in.nextInt();
            return a;
        }

        long nextLong() throws IOException {
            return Long.parseLong(next());
        }

        long[] nextLongArray(int n) throws IOException {
            long[] a = new long[n];
            for (int i = 0; i < n; i++)
                a[i] = in.nextLong();
            return a;
        }

        long[][] nextLongTable(int n, int m) throws IOException {
            long[][] a = new long[n][m];
            for (int i = 0; i < n; i++)
                for (int j = 0; j < m; j++)
                    a[i][j] = in.nextLong();
            return a;
        }

        ArrayList<Integer>[] nextGraph(int n, int m, boolean directed) throws IOException {
            ArrayList<Integer>[] graph = createGraph(n);
            for (int i = 0; i < m; i++) {
                int v = in.nextInt() - 1, u = in.nextInt() - 1;
                graph[v].add(u);
                if (!directed)
                    graph[u].add(v);
            }
            return graph;
        }

        ArrayList<GraphPair>[] nextWeightedGraph(int n, int m, boolean directed) throws IOException {
            ArrayList<GraphPair>[] graph = createWeightedGraph(n);
            for (int i = 0; i < m; i++) {
                int v = in.nextInt() - 1, u = in.nextInt() - 1;
                long w = in.nextLong();
                graph[v].add(new GraphPair(u, w));
                if (!directed)
                    graph[u].add(new GraphPair(v, w));
            }
            return graph;
        }

        double nextDouble() throws IOException {
            return Double.parseDouble(next());
        }

        String nextLine() throws IOException {
            return br.readLine();
        }

        boolean hasNextLine() throws IOException {
            return br.ready();
        }
    }

    private void run() throws IOException {
        in = new FastScanner(System.in); // new FastScanner(new FileInputStream(".in"));
        out = new PrintWriter(System.out); // new PrintWriter(new FileOutputStream(".out"));

        for (int t = multitests ? in.nextInt() : 1; t-- > 0; )
            solve();

        out.flush();
        out.close();
    }

    public static void main(String[] args) throws IOException {
        new Main().run();
    }
}