Problem: Sherlock Holmes found a mysterious correspondence of two VIPs and made up his mind to read it. But there is a problem! The correspondence turned out to be encrypted. The detective tried really hard to decipher the correspondence, but he couldn't understand anything. 

At last, after some thought, he thought of something. Let's say there is a word s, consisting of |s| lowercase Latin letters. Then for one operation you can choose a certain position p (1 ≤ p < |s|) and perform one of the following actions: 

  * either replace letter sp with the one that alphabetically follows it and replace letter sp + 1 with the one that alphabetically precedes it; 
  * or replace letter sp with the one that alphabetically precedes it and replace letter sp + 1 with the one that alphabetically follows it. 



Let us note that letter "z" doesn't have a defined following letter and letter "a" doesn't have a defined preceding letter. That's why the corresponding changes are not acceptable. If the operation requires performing at least one unacceptable change, then such operation cannot be performed.

Two words coincide in their meaning iff one of them can be transformed into the other one as a result of zero or more operations.

Sherlock Holmes needs to learn to quickly determine the following for each word: how many words can exist that coincide in their meaning with the given word, but differs from the given word in at least one character? Count this number for him modulo 1000000007 (109 + 7).

Input

The input data contains several tests. The first line contains the only integer t (1 ≤ t ≤ 104) — the number of tests.

Next t lines contain the words, one per line. Each word consists of lowercase Latin letters and has length from 1 to 100, inclusive. Lengths of words can differ.

Output

For each word you should print the number of different other words that coincide with it in their meaning — not from the words listed in the input data, but from all possible words. As the sought number can be very large, print its value modulo 1000000007 (109 + 7).

Examples

Input

1
ab


Output

1


Input

1
aaaaaaaaaaa


Output

0


Input

2
ya
klmbfxzb


Output

24
320092793

Note

Some explanations about the operation:

  * Note that for each letter, we can clearly define the letter that follows it. Letter "b" alphabetically follows letter "a", letter "c" follows letter "b", ..., "z" follows letter "y". 
  * Preceding letters are defined in the similar manner: letter "y" precedes letter "z", ..., "a" precedes letter "b". 
  * Note that the operation never changes a word's length. 



In the first sample you can obtain the only other word "ba". In the second sample you cannot obtain any other word, so the correct answer is 0.

Consider the third sample. One operation can transform word "klmbfxzb" into word "klmcexzb": we should choose p = 4, and replace the fourth letter with the following one ("b"  →  "c"), and the fifth one — with the preceding one ("f"  →  "e"). Also, we can obtain many other words from this one. An operation can transform word "ya" only into one other word "xb". 

Word "ya" coincides in its meaning with words "xb", "wc", "vd", ..., "ay" (overall there are 24 other words). The word "klmbfxzb has many more variants — there are 3320092814 other words that coincide with in the meaning. So the answer for the first word equals 24 and for the second one equals 320092793 — the number 3320092814 modulo 109 + 7

Solution (in JAVA):

Solution:

import java.sql.Array;
import java.util.*;
import java.io.*;


 public class TestClass {

    static class Parser
    {
        final private int BUFFER_SIZE = 1 << 16;

        private DataInputStream din;
        private byte[] buffer;
        private int bufferPointer, bytesRead;

        public Parser(InputStream in)
        {
            din = new DataInputStream(in);
            buffer = new byte[BUFFER_SIZE];
            bufferPointer = bytesRead = 0;
        }

        public long nextLong() throws Exception
        {
            long ret = 0;
            byte c = read();
            while (c <= ' ') c = read();
            boolean neg = c == '-';
            if (neg) c = read();
            do
            {
                ret = ret * 10 + c - '0';
                c = read();
            } while (c > ' ');
            if (neg) return -ret;
            return ret;
        }

        //reads in the next string
        public String next() throws Exception
        {
            StringBuilder ret =  new StringBuilder();
            byte c = read();
            while (c <= ' ') c = read();
            do
            {
                ret = ret.append((char)c);
                c = read();
            } while (c > ' ');
            return ret.toString();
        }

        public int nextInt() throws Exception
        {
            int ret = 0;
            byte c = read();
            while (c <= ' ') c = read();
            boolean neg = c == '-';
            if (neg) c = read();
            do
            {
                ret = ret * 10 + c - '0';
                c = read();
            } while (c > ' ');
            if (neg) return -ret;
            return ret;
        }

        private void fillBuffer() throws Exception
        {
            bytesRead = din.read(buffer, bufferPointer = 0, BUFFER_SIZE);
            if (bytesRead == -1) buffer[0] = -1;
        }

        private byte read() throws Exception
        {
            if (bufferPointer == bytesRead) fillBuffer();
            return buffer[bufferPointer++];
        }
    }
    static class OutputWriter
    {
        private PrintWriter writer;

        public OutputWriter(OutputStream stream)
        {
            writer = new PrintWriter(new BufferedWriter(new OutputStreamWriter(
                    stream)));
        }

        public OutputWriter(Writer writer)
        {
            this.writer = new PrintWriter(writer);
        }

        public void println(int x)
        {
            writer.println(x);
        }

        public void print(int x)
        {
            writer.print(x);
        }

        public void println(char x)
        {
            writer.println(x);
        }

        public void print(char x)
        {
            writer.print(x);
        }

        public void println(int array[], int size)
        {
            for (int i = 0; i < size; i++)
                println(array[i]);
        }

        public void print(int array[], int size)
        {
            for (int i = 0; i < size; i++)
                print(array[i] + " ");
        }

        public void println(long x)
        {
            writer.println(x);
        }

        public void print(long x)
        {
            writer.print(x);
        }

        public void println(long array[], int size)
        {
            for (int i = 0; i < size; i++)
                println(array[i]);
        }

        public void print(long array[], int size)
        {
            for (int i = 0; i < size; i++)
                print(array[i]);
        }

        public void println(float num)
        {
            writer.println(num);
        }

        public void print(float num)
        {
            writer.print(num);
        }

        public void println(double num)
        {
            writer.println(num);
        }

        public void print(double num)
        {
            writer.print(num);
        }

        public void println(String s)
        {
            writer.println(s);
        }

        public void print(String s)
        {
            writer.print(s);
        }

        public void println()
        {
            writer.println();
        }

        public void printSpace()
        {
            writer.print(" ");
        }

        public void printf(String format, Object args)
        {
            writer.printf(format, args);
        }

        public void flush()
        {
            writer.flush();
        }

        public void close()
        {
            writer.close();
        }
    }
    public static void main(String args[]) throws Exception {
        Parser s = new Parser(System.in);
        OutputWriter out = new OutputWriter(System.out);
        long Mod=1000000007;
        long dp[][]=new long[101][2600];
        dp[0][0]=1;
        for (int i = 0; i <100 ; i++) {
            for (int j = 0; j <2600 ; j++) {
                long c=0l;
                for(int k=0;k<26&&k<=j;k++){
                    dp[i+1][j]=(dp[i+1][j]+dp[i][j-k])%Mod;
                }
            }
        }
        int t=s.nextInt();
        for (int i = 0; i <t ; i++) {
            char ch[]=s.next().toCharArray();
            int c=0;
            for (int j = 0; j <ch.length ; j++) {
                c+=(ch[j]-'a');
            }
            long ans=(dp[ch.length][c]-1+Mod)%Mod;
            out.println(ans);
        }out.close();
    }}