Problem: You have 4 bags A, B, C and D each of which includes N coins (there are totally 4N coins). Values of the coins in each bag are ai, bi, ci and di respectively.

Find the number of combinations that result when you choose one coin from each bag (totally 4 coins) in such a way that the total value of the coins is V. You should distinguish the coins in a bag.

Constraints

* 1 ≤ N ≤ 1000
* 1 ≤ ai, bi, ci, di ≤ 1016
* 1 ≤ V ≤ 1016
* All input values are given in integers

Input

The input is given in the following format.


N V
a1 a2 ... aN
b1 b2 ... bN
c1 c2 ... cN
d1 d2 ... dN


Output

Print the number of combinations in a line.

Examples

Input

3 14
3 1 2
4 8 2
1 2 3
7 3 2


Output

9


Input

5 4
1 1 1 1 1
1 1 1 1 1
1 1 1 1 1
1 1 1 1 1


Output

625

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;

#define d(x) cerr << #x ":" << x << endl;
#define dd(x, y) cerr << "(" #x "," #y "):(" << x << "," << y << ")" << endl
#define rep(i, n) for (int i = (int)(0); i < (int)(n); i++)
#define all(v) v.begin(), v.end()
#define dump(v)                  \
    cerr << #v ":[ ";            \
    for (auto macro_vi : v) {    \
        cerr << macro_vi << " "; \
    }                            \
    cerr << "]" << endl;
#define ddump(v)                           \
    cerr << #v ":" << endl;                \
    for (auto macro_row : v) {             \
        cerr << "[";                       \
        for (auto macro__vi : macro_row) { \
            cerr << macro__vi << " ";      \
        }                                  \
        cerr << "]" << endl;               \
    }
using lint       = long long;
const int INF    = 1e9;
const lint LINF  = 1e18;
const double EPS = 1e-10;

int main() {
    lint N, V;
    cin >> N >> V;
    vector<lint> A(N), B(N), C(N), D(N);
    rep(i, N) cin >> A[i];
    rep(i, N) cin >> B[i];
    rep(i, N) cin >> C[i];
    rep(i, N) cin >> D[i];

    vector<lint> E(0);
    for (int i = 0; i < N; i++) {
        for (int j = 0; j < N; j++) {
            E.push_back(A[i] + B[j]);
        }
    }

    map<lint, lint> mp;
    for (int i = 0; i < N; i++) {
        for (int j = 0; j < N; j++) {
            mp[C[i] + D[j]]++;
        }
    }

    // dump(E);

    lint ans = 0;
    for (int i = 0; i < E.size(); i++) {
        lint F = V - E[i];
        ans += mp[F];
    }
    cout << ans << endl;

    return 0;
}