Problem: The fact that any positive integer has a representation as the sum of at most four positive squares (i.e. squares of positive integers) is known as Lagrange’s Four-Square Theorem. The first published proof of the theorem was given by Joseph-Louis Lagrange in 1770. Your mission however is not to explain the original proof nor to discover a new proof but to show that the theorem holds for some specific numbers by counting how many such possible representations there are.

For a given positive integer n, you should report the number of all representations of n as the sum of at most four positive squares. The order of addition does not matter, e.g. you should consider 42 + 32 and 32 + 42 are the same representation.

For example, let’s check the case of 25. This integer has just three representations 12 +22 +22 +42 , 32 + 42 , and 52 . Thus you should report 3 in this case. Be careful not to count 42 + 32 and 32 + 42 separately.



Input

The input is composed of at most 255 lines, each containing a single positive integer less than 215 , followed by a line containing a single zero. The last line is not a part of the input data.

Output

The output should be composed of lines, each containing a single integer. No other characters should appear in the output.

The output integer corresponding to the input integer n is the number of all representations of n as the sum of at most four positive squares.

Example

Input

1
25
2003
211
20007
0


Output

1
3
48
7
738

Solution (in CPP):

Solution:
#include <bits/stdc++.h>

using namespace std;

int main()
{
	static int dp[2][5][1 + (1 << 15)];
	dp[0][0][0] = 1;
	for (int i = 1; i * i <= (1 << 15); i++){
		memset(dp[i & 1], 0, sizeof(dp[i & 1]));
		for (int j = 0; j <= 4; j++){
			for (int k = 4; k - j >= 0; k--){
				for (int l = (1 << 15); l - i * i * j >= 0; l--){
					dp[i & 1][k][l] += dp[1 - (i & 1)][k - j][l - i * i * j];
				}
			}
		}
	}
	
	for (int T; scanf("%d", &T) && T;){
		printf("%d\n", dp[1][1][T] + dp[1][2][T] + dp[1][3][T] + dp[1][4][T]);
	}
	
	return (0);
}