Problem: Acacius is studying strings theory. Today he came with the following problem.

You are given a string s of length n consisting of lowercase English letters and question marks. It is possible to replace question marks with lowercase English letters in such a way that a string "abacaba" occurs as a substring in a resulting string exactly once?

Each question mark should be replaced with exactly one lowercase English letter. For example, string "a?b?c" can be transformed into strings "aabbc" and "azbzc", but can't be transformed into strings "aabc", "a?bbc" and "babbc".

Occurrence of a string t of length m in the string s of length n as a substring is a index i (1 ≤ i ≤ n - m + 1) such that string s[i..i+m-1] consisting of m consecutive symbols of s starting from i-th equals to string t. For example string "ababa" has two occurrences of a string "aba" as a substring with i = 1 and i = 3, but there are no occurrences of a string "aba" in the string "acba" as a substring.

Please help Acacius to check if it is possible to replace all question marks with lowercase English letters in such a way that a string "abacaba" occurs as a substring in a resulting string exactly once.

Input

First line of input contains an integer T (1 ≤ T ≤ 5000), number of test cases. T pairs of lines with test case descriptions follow.

The first line of a test case description contains a single integer n (7 ≤ n ≤ 50), length of a string s.

The second line of a test case description contains string s of length n consisting of lowercase English letters and question marks.

Output

For each test case output an answer for it.

In case if there is no way to replace question marks in string s with a lowercase English letters in such a way that there is exactly one occurrence of a string "abacaba" in the resulting string as a substring output "No".

Otherwise output "Yes" and in the next line output a resulting string consisting of n lowercase English letters. If there are multiple possible strings, output any.

You may print every letter in "Yes" and "No" in any case you want (so, for example, the strings yEs, yes, Yes, and YES will all be recognized as positive answer).

Example

Input


6
7
abacaba
7
???????
11
aba?abacaba
11
abacaba?aba
15
asdf???f???qwer
11
abacabacaba


Output


Yes
abacaba
Yes
abacaba
Yes
abadabacaba
Yes
abacabadaba
No
No

Note

In first example there is exactly one occurrence of a string "abacaba" in the string "abacaba" as a substring.

In second example seven question marks can be replaced with any seven lowercase English letters and with "abacaba" in particular.

In sixth example there are two occurrences of a string "abacaba" as a substring.

Solution (in PYTHON):

Solution:
#!/usr/bin/env python
from __future__ import division, print_function

import os
import sys
from io import BytesIO, IOBase

if sys.version_info[0] < 3:
    from __builtin__ import xrange as range
    from future_builtins import ascii, filter, hex, map, oct, zip

import random
import collections
import math
import itertools
import bisect

token = 'abacaba'
tl = len(token)

def match(s):
    for i in range(tl):
        if s[i] != '?' and s[i] != token[i]:
            return False
    return True

def check(s, i):
    return s[i + tl:i + tl + 4] != 'caba' \
           and s[i + tl:i + tl + 6] != 'bacaba' \
           and s[max(0, i-4):i] != 'abac' \
           and s[max(0, i-6):i] != 'abacab'

def real_main():
    t = read_int()
    for _ in range(t):
        n = read_int()
        s = read()
        count = sum(s[i:i+tl] == token for i in range(n-tl+1))
        if count > 1:
            print("No")
        elif count == 1:
            print("Yes")
            print(s.replace('?', 'd'))
        else:
            for i in range(n-tl+1):
                if match(s[i:i+tl]) and check(s, i):
                    print("Yes")
                    print(s[:i].replace('?', 'd') + token + s[i+tl:].replace('?', 'd'))
                    break
            else:
                print("No")


def solve():
    pass


def main():
    if False and 'PYCHARM_HOSTED' in os.environ:
        main_pycharm()
    else:
        real_main()


from copy import deepcopy
def main_pycharm():
    solution = solve

    test_inputs = None
    test_outputs = None
    judge = None
    slow_solution = None
    if solution is not None:
        if test_outputs is not None:
            test_with_answers(solution, test_inputs, test_outputs)
        if judge is not None:
            test_with_judge(solution, test_inputs, judge)
        if slow_solution is not None:
            test_with_slow_solution(solution, test_inputs, slow_solution)


def test_with_answers(solution, inputs, answers):
    total, wrong = 0, 0
    for args, test_ans in zip(inputs, answers):
        ans = solution(*deepcopy(args))
        if ans != test_ans:
            print('WRONG! ans=%s, test_ans=%s, args=%s' % (ans, test_ans, args))
            wrong += 1
        else:
            print('GOOD')
        total += 1
    print('ALL %d TESTS PASSED' % total if not wrong else '%d out of %d tests are WRONG' % (wrong, total))


def test_with_judge(solution, inputs_gen, judge):
    total, wrong = 0, 0
    for args in inputs_gen:
        ans = solution(*deepcopy(args))
        if not judge(deepcopy(ans), *deepcopy(args)):
            print('WRONG! ans=%s, args=%s' % (ans, args))
            wrong += 1
        total += 1
    print('ALL %d TESTS PASSED' % total if not wrong else '%d out of %d tests are WRONG' % (wrong, total))


def test_with_slow_solution(solution, inputs_gen, solution_slow):
    total, wrong = 0, 0
    for args in inputs_gen:
        ans = solution(*deepcopy(args))
        slow = solution_slow(*deepcopy(args))
        if ans != slow:
            print('WRONG! ans=%s, slow=%s, args=%s' % (ans, slow, args))
            wrong += 1
        total += 1
    print('ALL %d TESTS PASSED' % total if not wrong else '%d out of %d tests are WRONG' % (wrong, total))

def generate_nums(n, min, max, check_if_good=None):
    while True:
        nums = [random.randint(min, max) for _ in range(n)]
        if check_if_good is None or check_if_good(nums):
            return nums

# This mergesort can be like 7 times faster than build in sort
# (for stupid reasons)
def mergesort(A, key=lambda x: x, reverse=False):
    C = A
    A = list(range(len(A)))
    B = list(A)

    n = len(A)
    for i in range(0, n - 1, 2):
        if key(C[A[i]]) > key(C[A[i ^ 1]]):
            A[i], A[i ^ 1] = A[i ^ 1], A[i]

    width = 2
    while width < n:
        for i in range(0, n, 2 * width):
            R1, R2 = min(i + width, n), min(i + 2 * width, n)
            j, k = R1, i
            while i < R1 and j < R2:
                if key(C[A[i]]) > key(C[A[j]]):
                    B[k] = A[j]
                    j += 1
                else:
                    B[k] = A[i]
                    i += 1
                k += 1
            while i < R1:
                B[k] = A[i]
                k += 1
                i += 1
            while k < R2:
                B[k] = A[k]
                k += 1
        A, B = B, A
        width *= 2

    if reverse:
        A.reverse()
    return A

def mergesort_simple(A, reverse=False):
    C = A
    A = list(range(len(A)))
    B = list(A)

    n = len(A)
    for i in range(0, n - 1, 2):
        if C[A[i]] > C[A[i ^ 1]]:
            A[i], A[i ^ 1] = A[i ^ 1], A[i]

    width = 2
    while width < n:
        for i in range(0, n, 2 * width):
            R1, R2 = min(i + width, n), min(i + 2 * width, n)
            j, k = R1, i
            while i < R1 and j < R2:
                if C[A[i]] > C[A[j]]:
                    B[k] = A[j]
                    j += 1
                else:
                    B[k] = A[i]
                    i += 1
                k += 1
            while i < R1:
                B[k] = A[i]
                k += 1
                i += 1
            while k < R2:
                B[k] = A[k]
                k += 1
        A, B = B, A
        width *= 2

    if reverse:
        A.reverse()
    return A


# region fastio

BUFSIZE = 8192


class FastIO(IOBase):
    newlines = 0

    def __init__(self, file):
        self._fd = file.fileno()
        self.buffer = BytesIO()
        self.writable = "x" in file.mode or "r" not in file.mode
        self.write = self.buffer.write if self.writable else None

    def read(self):
        while True:
            b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
            if not b:
                break
            ptr = self.buffer.tell()
            self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
        self.newlines = 0
        return self.buffer.read()

    def readline(self):
        while self.newlines == 0:
            b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
            self.newlines = b.count(b"\n") + (not b)
            ptr = self.buffer.tell()
            self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
        self.newlines -= 1
        return self.buffer.readline()

    def flush(self):
        if self.writable:
            os.write(self._fd, self.buffer.getvalue())
            self.buffer.truncate(0), self.buffer.seek(0)


class IOWrapper(IOBase):
    def __init__(self, file):
        self.buffer = FastIO(file)
        self.flush = self.buffer.flush
        self.writable = self.buffer.writable
        self.write = lambda s: self.buffer.write(s.encode("ascii"))
        self.read = lambda: self.buffer.read().decode("ascii")
        self.readline = lambda: self.buffer.readline().decode("ascii")


def print(*args, **kwargs):
    """Prints the values to a stream, or to sys.stdout by default."""
    sep, file = kwargs.pop("sep", " "), kwargs.pop("file", sys.stdout)
    at_start = True
    for x in args:
        if not at_start:
            file.write(sep)
        file.write(str(x))
        at_start = False
    file.write(kwargs.pop("end", "\n"))
    if kwargs.pop("flush", False):
        file.flush()


if sys.version_info[0] < 3:
    sys.stdin, sys.stdout = FastIO(sys.stdin), FastIO(sys.stdout)
else:
    sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)

input = lambda: sys.stdin.readline().rstrip("\r\n")

def read():
    return input()

def read_int():
    return int(input())

def read_array(sep=None, maxsplit=-1):
    return input().split(sep, maxsplit)

def read_int_array():
    return [int(a) for a in read_array()]

# endregion

if __name__ == "__main__":
    main()