Problem: You're given an integer n. For every integer i from 2 to n, assign a positive integer a_i such that the following conditions hold:

  * For any pair of integers (i,j), if i and j are coprime, a_i ≠ a_j. 
  * The maximal value of all a_i should be minimized (that is, as small as possible). 



A pair of integers is called [coprime](https://en.wikipedia.org/wiki/Coprime_integers) if their [greatest common divisor](https://en.wikipedia.org/wiki/Greatest_common_divisor) is 1.

Input

The only line contains the integer n (2 ≤ n ≤ 10^5).

Output

Print n-1 integers, a_2, a_3, …, a_n (1 ≤ a_i ≤ n). 

If there are multiple solutions, print any of them.

Examples

Input


4


Output


1 2 1 

Input


3


Output


2 1

Note

In the first example, notice that 3 and 4 are coprime, so a_3 ≠ a_4. Also, notice that a=[1,2,3] satisfies the first condition, but it's not a correct answer because its maximal value is 3.

Solution (in PYTHON3):

Solution:
from sys import stdin
# stdin=open('input.txt')

def input():
	return stdin.readline().strip()


# from sys import stdout
# stdout=open('input.txt',mode='w+')

# def print1(x, end='\n'):
# 	stdout.write(str(x) +end)


# a, b = map(int, input().split())

# l = list(map(int, input().split()))


# CODE BEGINS HERE.................


n = int(input())
l = [-1]*(n + 1)
is_prime = [True]*(n + 1)
count = 0
for i in range(2, n + 1):
	if is_prime[i]:
		count += 1
		for j in range(i, n + 1, i):
			l[j] = count
			is_prime[j] = False

print(*l[2:])


# CODE ENDS HERE....................
# stdout.close()