Problem: You're given an integer n. For every integer i from 2 to n, assign a positive integer a_i such that the following conditions hold:

  * For any pair of integers (i,j), if i and j are coprime, a_i ≠ a_j. 
  * The maximal value of all a_i should be minimized (that is, as small as possible). 



A pair of integers is called [coprime](https://en.wikipedia.org/wiki/Coprime_integers) if their [greatest common divisor](https://en.wikipedia.org/wiki/Greatest_common_divisor) is 1.

Input

The only line contains the integer n (2 ≤ n ≤ 10^5).

Output

Print n-1 integers, a_2, a_3, …, a_n (1 ≤ a_i ≤ n). 

If there are multiple solutions, print any of them.

Examples

Input


4


Output


1 2 1 

Input


3


Output


2 1

Note

In the first example, notice that 3 and 4 are coprime, so a_3 ≠ a_4. Also, notice that a=[1,2,3] satisfies the first condition, but it's not a correct answer because its maximal value is 3.

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.*;

/******************************\
 * The solution is at the top *
 *                            *
 *   Created by : azhar556    *
\******************************/

public class A {
    static void solve() {
		int n = ni();
		int[] val = new int[n + 1];
		int MaxNow = 0;
		for (int i = 2; i <= n; i++) {
			int res = -1;
			for (int j = 2; j * j <= i; j++) {
				if (i % j == 0) {
					res = val[j];
					break;
				}
			}
			if (res == -1) {
				res = MaxNow + 1;
				MaxNow++;
			}
			val[i] = res;
			out.print(res + " ");
		}
    }    

    public static void main(String[] args) {
        long time = System.currentTimeMillis();
        int t;// = ni();
        t = 1;
        while (t-- > 0) solve(); 
        err.println("Time elapsed : " + (System.currentTimeMillis() - time) / 1000F + " s.");
        err.close(); out.close();
    }

    static PrintWriter out = new PrintWriter(new BufferedWriter(new OutputStreamWriter(System.out)));
    static PrintWriter err = new PrintWriter(new BufferedWriter(new OutputStreamWriter(System.err)));
    static BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
    static StringTokenizer token;
        
    static String ns() {
        while (token == null || !token.hasMoreTokens()) {
            try {
                token = new StringTokenizer(br.readLine());
            }
            catch (IOException e) {
                throw new RuntimeException(e);
            }
        }
        return token.nextToken();
    }
    static char nc() {
        return Character.valueOf(ns().charAt(0));
    }
    static int ni() {
        return Integer.parseInt(ns());
    }
    static double nd() {
        return Double.parseDouble(ns());
    }
    static long nl() {
        return Long.parseLong(ns());
    }
}
// Collections Arrays Math
// Vector HashSet TreeSet HashMap TreeMap ArrayDeque