Problem: You have 4 bags A, B, C and D each of which includes N coins (there are totally 4N coins). Values of the coins in each bag are ai, bi, ci and di respectively.

Find the number of combinations that result when you choose one coin from each bag (totally 4 coins) in such a way that the total value of the coins is V. You should distinguish the coins in a bag.

Constraints

* 1 ≤ N ≤ 1000
* 1 ≤ ai, bi, ci, di ≤ 1016
* 1 ≤ V ≤ 1016
* All input values are given in integers

Input

The input is given in the following format.


N V
a1 a2 ... aN
b1 b2 ... bN
c1 c2 ... cN
d1 d2 ... dN


Output

Print the number of combinations in a line.

Examples

Input

3 14
3 1 2
4 8 2
1 2 3
7 3 2


Output

9


Input

5 4
1 1 1 1 1
1 1 1 1 1
1 1 1 1 1
1 1 1 1 1


Output

625

Solution (in CPP):

Solution:
#include "bits/stdc++.h"
using namespace std;
#ifdef _DEBUG
#include "dump.hpp"
#else
#define dump(...)
#endif

#define int long long
#define rep(i,a,b) for(int i=(a);i<(b);i++)
#define rrep(i,a,b) for(int i=(b)-1;i>=(a);i--)
#define all(c) begin(c),end(c)
const int INF = sizeof(int) == sizeof(long long) ? 0x3f3f3f3f3f3f3f3fLL : 0x3f3f3f3f;
const int MOD = (int)(1e9) + 7;
template<class T> bool chmax(T &a, const T &b) { if (a < b) { a = b; return true; } return false; }
template<class T> bool chmin(T &a, const T &b) { if (b < a) { a = b; return true; } return false; }

//??§?¨???§???
//index()??¨??????????????????
template<typename T>
vector<T> compress(vector<T> v) {
	sort(v.begin(), v.end());
	v.erase(unique(v.begin(), v.end()), v.end());
	return v;
}

//??§????????????????????????????????????
//index(??§???????????????, ????´?)
template<typename T>
int index(const vector<T> &v, T i) { return lower_bound(v.begin(), v.end(), i) - v.begin(); }

signed main() {
	cin.tie(0);
	ios::sync_with_stdio(false);
	int N, V; cin >> N >> V;
	vector<int> a(N); rep(i, 0, N) { cin >> a[i]; }
	vector<int> b(N); rep(i, 0, N) { cin >> b[i]; }
	vector<int> c(N); rep(i, 0, N) { cin >> c[i]; }
	vector<int> d(N); rep(i, 0, N) { cin >> d[i]; }
	vector<int>	A, B;
	rep(i, 0, N)rep(j, 0, N) {
		A.emplace_back(a[i] + b[j]);
		B.emplace_back(c[i] + d[j]);
	}
	sort(all(A));
	sort(all(B));
	unordered_map<int, int> cntA, cntB;
	rep(i, 0, A.size()) {
		cntA[A[i]]++;
		cntB[B[i]]++;
	}
	A.erase(unique(A.begin(), A.end()), A.end());
	int ans = 0;
	rep(i, 0, A.size()) {
		ans += cntA[A[i]] * cntB[V - A[i]];
	}
	cout << ans << endl;
	return 0;
}