Problem: Every great chef knows that lucky numbers are positive integers whose decimal representations contain only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.  
Our chef has recently returned from the Lucky country. He observed that every restaurant in the Lucky country had a lucky number as its name.
He believes that having a lucky number as a restaurant name can indeed turn out to be very lucky.   
Our chef believes that it is possible to make a lucky number having N digits even luckier. Any number following the rules below is called Lucky lucky number -   
 1. The number contains only digits 4 and 7. 
 2. Count of digit 4 in the number should be divisible by 7. 
 3. Count of digit 7 in the number should be divisible by 4.  
Help our chef to compute the count of digit 4 in the smallest Lucky lucky number having N digits. 

Input

First line contains T, number of test cases. Each of the next T lines contains a number N, the number of digits in the Lucky lucky number to be formed.  
1<=T<=1000 
1<=N<=1000000000 (10^9) 

Output

If it is not possible to form a Lucky lucky number having N digits, output -1.
Otherwise, output the count of digit 4 in the smallest Lucky lucky number having N digits.

Example

Input:
5
7
4
11
1
15

Output:
7
0
7
-1
7

Explanation
For the last test case, N = 15, the smallest lucky lucky number is
444444477777777. The count of digit 4 is 7.

Solution (in PYTHON):

Solution:
# cook your code here
class Lucky():
    hashed={0:0, 1:8, 2:16 ,3:24 ,4:4, 5:12 ,6:20}
    test_cases=int(raw_input())
    arr=[]
    for j in range(test_cases):
        inp=int(raw_input())          
        n=(inp%7)
        if(inp<hashed[n]):
            arr.append(-1)
        else:    
            arr.append(inp-hashed[n])
    for k in arr:
        print k