Problem: Given 2 integers u and v, find the shortest array such that [bitwise-xor](https://en.wikipedia.org/wiki/Bitwise_operation#XOR) of its elements is u, and the sum of its elements is v.

Input

The only line contains 2 integers u and v (0 ≤ u,v ≤ 10^{18}).

Output

If there's no array that satisfies the condition, print "-1". Otherwise:

The first line should contain one integer, n, representing the length of the desired array. The next line should contain n positive integers, the array itself. If there are multiple possible answers, print any.

Examples

Input


2 4


Output


2
3 1

Input


1 3


Output


3
1 1 1

Input


8 5


Output


-1

Input


0 0


Output


0

Note

In the first sample, 3⊕ 1 = 2 and 3 + 1 = 4. There is no valid array of smaller length.

Notice that in the fourth sample the array is empty.

Solution (in JAVA):

Solution:
	import java.io.*;
	import java.util.*;
	import java.math.*;
	
	 
	 public class Main	{
	   static class Pair implements Comparable<Pair>{
//	   int a;
//	   int b;
//	   public Pair(){}
//	   public Pair(int x,int y){a=x;b=y;}
	   public int compareTo(Pair p){
		 return Double.compare(a, p.a);
	   }
//		   long a,b;
//		   public Pair(long x,long y){a=x;b=y;}
//		   public int compareTo(Pair p){
//				 return Long.compare(a, p.a);
//		   }
//		  
	   double a, b;
	   public Pair(double x, double y) {a=x;b=y;}
//		@Override
//		public int hashCode() {
//			final int prime = 31;
//			int result = 1;
//			result = prime * result + a;
//			result = prime * result + b;
//		   
//			return result;
//		}
		@Override
		public boolean equals(Object obj) {
			Pair cur = (Pair)obj;
			if((a==cur.a && b==cur.b))return true;
			return false;
		}
	 }
	static class TrieNode{
		int cnt;
		TrieNode[]child;
		public TrieNode() {
			cnt = 0;
			child = new TrieNode[10];
		}
	}
	  public static long gcd(long a,long b)
	  {
	    if(a<b)
	      return gcd(b,a);
	    if(b==0)
	      return a;
	    return gcd(b,a%b);
	    
	  }
	  static int lcm(int a,int b) {
		  return  a*b / (int)gcd(a,b);
	  }
	  
	  static long mod = 998244353;//(long)(1e9+7); //
	   
	    public static void main(String[] args) throws Exception {
	       new Thread(null, null, "Anshum Gupta", 99999999) {
	            public void run() {
	                try {
	                    solve();
	                } catch(Exception e) {
	                    e.printStackTrace();
	                    System.exit(1);
	                }
	            }
	        }.start();
	    }
	
	static long pow(long x,long y){
	    if(y == 0)return 1;
	    if(y==1)return x;
	    long a = pow(x,y/2);
	    a = (a*a)%mod;
	    if(y%2==0){
	        return a;
	    }
	    return (a*x)%mod;
	}
	
	static long mxx;
	static int mxN = (int)(2e6+5);
	static int mxV = (int)(2e5);
	static long[]fact,inv_fact;
	static long my_inv(long a) {
		return pow(a,mod-2);
	}
	static long bin(int a,int b) {
		if(a < b || a<0 || b<0)return 0;
	    return ((fact[a]*inv_fact[a-b])%mod * inv_fact[b])%mod;
	}
		static ArrayList<ArrayList<Integer>>adj;
		static boolean[]vis;
	static void make_facts() {
	  fact=new long[mxN];
	  inv_fact = new long[mxN];
	  fact[0]=inv_fact[0]=1L;
	  for(int i=1;i<mxN;i++) {
		   fact[i] = (i*fact[i-1])%mod;
		   inv_fact[i] = my_inv(fact[i]);
	  }
	}
	
	 public static void solve() throws Exception {
	   // solve the problem here
	   MyScanner s = new MyScanner();
	        out = new PrintWriter(new BufferedOutputStream(System.out), true);
	        int tc = 1;//s.nextInt();
	        mxx = (long)(1e18+5);
	//	        make_facts(); 
	//	        int mod = (int)1e9+7;
	        
	        while(tc-->0){
	        	long u = s.nextLong();
	        	long v = s.nextLong();
	        	if(u == 0 && v==0 ) {
	        		out.println("0");
	        		return;
	        	}
	        	else if(u > v || (u+v) % 2 != 0) {
	        		out.println("-1");
	        	}
	        	else if(u == v) {
	        		out.println("1");
	        		out.println(u);
	        	}
	        	else {
	        		long _and = (v - u)/2;
	        		if( (_and ^ ((u+v)/2)) == u ) {
	        			out.println("2");
	        			out.println((v-u)/2 + " " + (v+u)/2);
	        		}
	        		else {
	        			out.println("3");
	        			out.println((v-u)/2 + " " + (v-u)/2 +" "+ u);
	        		}
	        	}
	        }
	        	
	           
	        out.flush();
	}
	 
	     
	 
	 
	 
	    //-----------PrintWriter for faster output---------------------------------
	    public static PrintWriter out;
	 
	    //-----------MyScanner class for faster input----------
	    public static class MyScanner {
	        BufferedReader br;
	        StringTokenizer st;
	 
	        public MyScanner() {
	            br = new BufferedReader(new InputStreamReader(System.in));
	        }
	 
	        String next() {
	            while (st == null || !st.hasMoreElements()) {
	                try {
	                    st = new StringTokenizer(br.readLine());
	                } catch (IOException e) {
	                    e.printStackTrace();
	                }
	            }
	            return st.nextToken();
	        }
	 
	        int nextInt() { return Integer.parseInt(next()); }
	        long nextLong() { return Long.parseLong(next()); }
	        double nextDouble() { return Double.parseDouble(next()); }
	         
	        String nextLine(){
	            String str = "";
	            try {
	                str = br.readLine();
	            } catch (IOException e) {
	                e.printStackTrace();
	            }
	            return str;
	        }
	    }
	    //--------------------------------------------------------
	}