Problem: You're given an integer n. For every integer i from 2 to n, assign a positive integer a_i such that the following conditions hold:

  * For any pair of integers (i,j), if i and j are coprime, a_i ≠ a_j. 
  * The maximal value of all a_i should be minimized (that is, as small as possible). 



A pair of integers is called [coprime](https://en.wikipedia.org/wiki/Coprime_integers) if their [greatest common divisor](https://en.wikipedia.org/wiki/Greatest_common_divisor) is 1.

Input

The only line contains the integer n (2 ≤ n ≤ 10^5).

Output

Print n-1 integers, a_2, a_3, …, a_n (1 ≤ a_i ≤ n). 

If there are multiple solutions, print any of them.

Examples

Input


4


Output


1 2 1 

Input


3


Output


2 1

Note

In the first example, notice that 3 and 4 are coprime, so a_3 ≠ a_4. Also, notice that a=[1,2,3] satisfies the first condition, but it's not a correct answer because its maximal value is 3.

Solution (in PYTHON3):

Solution:
N = int(input())

# Mまでの素数全列挙(エラトステネスの篩)
def primes(M):
    is_prime = [-1 for _ in range(M+1)]
    for m in range(2, M+1):
        if is_prime[m] == -1:
            is_prime[m] = 1
            l = 2
            while m*l <= M:
                is_prime[m*l] = 0
                l += 1
    primes = []
    for p in range(2, M+1):
        if is_prime[p] == 1:
            primes.append(p)
    return primes

P = primes(N)
ans = [None]*(N+1)

for i, p in enumerate(P):
    k = p
    while k <= N:
        if ans[k] is None:
            ans[k] = i+1
        k += p

for n in range(2, N+1):
    print(ans[n], end=' ')
print()