Problem: We have a grid with A horizontal rows and B vertical columns, with the squares painted white. On this grid, we will repeatedly apply the following operation:

* Assume that the grid currently has a horizontal rows and b vertical columns. Choose "vertical" or "horizontal".
* If we choose "vertical", insert one row at the top of the grid, resulting in an (a+1) \times b grid.
* If we choose "horizontal", insert one column at the right end of the grid, resulting in an a \times (b+1) grid.
* Then, paint one of the added squares black, and the other squares white.



Assume the grid eventually has C horizontal rows and D vertical columns. Find the number of ways in which the squares can be painted in the end, modulo 998244353.

Constraints

* 1 \leq A \leq C \leq 3000
* 1 \leq B \leq D \leq 3000
* A, B, C, and D are integers.

Input

Input is given from Standard Input in the following format:


A B C D


Output

Print the number of ways in which the squares can be painted in the end, modulo 998244353.

Examples

Input

1 1 2 2


Output

3


Input

2 1 3 4


Output

65


Input

31 41 59 265


Output

387222020

Solution (in PYTHON3):

Solution:
A, B, C, D = map(int, input().split())
mod = 998244353

dp = [[0] * (D+1) for _ in range(C+1)]

x, y = A, B
dp[x][y] = 1

for i in range(x, C+1):
    for j in range(y, D+1):
        if i == x and j == y:
            continue

        if i > x:
            dp[i][j] += dp[i-1][j] * j
        if j > y:
            dp[i][j] += dp[i][j-1] * i

        if i > x and j > y:
            dp[i][j] -= (i-1) * (j-1) * dp[i-1][j-1]

        dp[i][j] %= mod

print(dp[C][D])