Problem: Throughout Igor K.'s life he has had many situations worthy of attention. We remember the story with the virus, the story of his mathematical career and of course, his famous programming achievements. However, one does not always adopt new hobbies, one can quit something as well.

This time Igor K. got disappointed in one of his hobbies: editing and voicing videos. Moreover, he got disappointed in it so much, that he decided to destroy his secret archive for good. 

Igor K. use Pindows XR operation system which represents files and folders by small icons. At that, m icons can fit in a horizontal row in any window.

Igor K.'s computer contains n folders in the D: disk's root catalog. The folders are numbered from 1 to n in the order from the left to the right and from top to bottom (see the images). At that the folders with secret videos have numbers from a to b inclusive. Igor K. wants to delete them forever, at that making as few frame selections as possible, and then pressing Shift+Delete exactly once. What is the minimum number of times Igor K. will have to select the folder in order to select folders from a to b and only them? Let us note that if some selected folder is selected repeatedly, then it is deselected. Each selection possesses the shape of some rectangle with sides parallel to the screen's borders.

Input

The only line contains four integers n, m, a, b (1 ≤ n, m ≤ 109, 1 ≤ a ≤ b ≤ n). They are the number of folders in Igor K.'s computer, the width of a window and the numbers of the first and the last folders that need to be deleted.

Output

Print a single number: the least possible number of times Igor K. will have to select the folders using frames to select only the folders with numbers from a to b.

Examples

Input

11 4 3 9


Output

3


Input

20 5 2 20


Output

2

Note

The images below illustrate statement tests.

The first test:

<image>

In this test we can select folders 3 and 4 with out first selection, folders 5, 6, 7, 8 with our second selection and folder 9 with our third, last selection.

The second test:

<image>

In this test we can first select all folders in the first row (2, 3, 4, 5), then — all other ones.

Solution (in JAVA):

Solution:
import java.util.*;
import java.io.*;
		
		public class codeforces
		{	
			public static void main(String[] args)
			{
				InputReader in = new InputReader(System.in);
				PrintWriter pw = new PrintWriter(System.out);
				
				int n = in.nextInt();
				int m = in.nextInt();
				int a = in.nextInt();
				int b = in.nextInt();
				int ans = 0, line = 0;
				
				line = (int)(Math.ceil((double)b/m) - Math.ceil((double)a/m));
				
				if(line == 0 || m == 1)
					ans = 1;
				else if(line == 1 || m == 2)
				{
					ans = 2;
					
					if((a%m == 1 || a == 1) && (b%m == 0 || b == n))
						ans--;
				}
				else
				{
					ans = 3;
					
					if(a%m == 1 || a == 1)
						ans--;
					
					if(b%m == 0 || a%m - 1 == b%m || b == n || (a%m == 0 && b%m == m - 1))
						ans--;
				}
				
				pw.print(ans);
				
				pw.flush();
				pw.close();
			}
			
			public static long GCD(long a,long b)
			{
				if(b==0)
					return a;
				else
					return GCD(b,a%b);
			}
			
			static class pair implements Comparable<pair>
			{
				Long x, y;
				pair(long x,long y)
				{
					this.x=x;
					this.y=y;
				}
				
				public int compareTo(pair o) {
					int result = x.compareTo(o.x);
					if(result==0)
						result = y.compareTo(o.y);
					
					return result;
				}  
				
				public String toString()
				{
					return x+" "+y;
				}
				
				public boolean equals(Object o)
				{
					if (o instanceof pair)
				    {
						pair p = (pair)o;
						return p.x - x == 0 && p.y - y == 0 ;
					}
					return false;
				}
				
				public int hashCode()
				{
					return new Long(x).hashCode()*31 + new Long(y).hashCode();
				}
			}
			
			static class InputReader 
			{
				 
				private final InputStream stream;
				private final byte[] buf = new byte[8192];
				private int curChar, snumChars;
				private SpaceCharFilter filter;
		 
				public InputReader(InputStream stream) 
				{
					this.stream = stream;
				}
		 
				public int snext() 
				{
					if (snumChars == -1)
						throw new InputMismatchException();
					if (curChar >= snumChars) 
					{
						curChar = 0;
						try 
						{
							snumChars = stream.read(buf);
						} 
						catch (IOException e) 
						{
							throw new InputMismatchException();
						}
						if (snumChars <= 0)
							return -1;
					}
					return buf[curChar++];
				}
		 
				public int nextInt() 
			    {
					int c = snext();
					while (isSpaceChar(c)) 
					{
						c = snext();
					}
					int sgn = 1;
					if (c == '-')
				    {
						sgn = -1;
						c = snext();
					}
					int res = 0;
					do 
					{
						if (c < '0' || c > '9')
							throw new InputMismatchException();
						res *= 10;
						res += c - '0';
						c = snext();
					} while (!isSpaceChar(c));
					return res * sgn;
				}
		 
				public long nextLong()
			    {
					int c = snext();
					while (isSpaceChar(c)) 
					{
						c = snext();
					}
					int sgn = 1;
					if (c == '-') 
					{
						sgn = -1;
						c = snext();
					}
					long res = 0;
					do 
					{
						if (c < '0' || c > '9')
							throw new InputMismatchException();
						res *= 10;
						res += c - '0';
						c = snext();
					} while (!isSpaceChar(c));
					return res * sgn;
				}
		 
				public int[] nextIntArray(int n) 
				{
					int a[] = new int[n];
					for (int i = 0; i < n; i++) 
					{
						a[i] = nextInt();
					}
					return a;
				}
		 
				public String readString()
			    {
					int c = snext();
					while (isSpaceChar(c)) 
					{
						c = snext();
					}
					StringBuilder res = new StringBuilder();
					do 
					{
						res.appendCodePoint(c);
						c = snext();
					} while (!isSpaceChar(c));
					return res.toString();
				}
		 
				public String nextLine() 
				{
					int c = snext();
					while (isSpaceChar(c))
						c = snext();
					StringBuilder res = new StringBuilder();
					do 
					{
						res.appendCodePoint(c);
						c = snext();
					} while (!isEndOfLine(c));
					return res.toString();
				}
		 
				public boolean isSpaceChar(int c) 
				{
					if (filter != null)
						return filter.isSpaceChar(c);
					return c == ' ' || c == '\n' || c == '\r' || c == '\t' || c == -1;
				}
		 
				private boolean isEndOfLine(int c) 
				{
					return c == '\n' || c == '\r' || c == -1;
				}
		 
				public interface SpaceCharFilter
			    {
					public boolean isSpaceChar(int ch);
				}
			}
			
			static class CodeX {
	        public static void sort(long arr[]) {
	            merge_sort(arr, 0, arr.length - 1);
	        }
	
	        private static void merge_sort(long A[], long start, long end) {
	            if (start < end) {
	                long mid = (start + end) / 2;
	                merge_sort(A, start, mid);
	                merge_sort(A, mid + 1, end);
	                merge(A, start, mid, end);
	            }
	
	        }
	
	        private static void merge(long A[], long start,long mid, long end) {
	            long p = start, q = mid + 1;
	            long Arr[] = new long[(int)(end - start + 1)];
	            long k = 0;
	
	            for (int i = (int)start; i <= end; i++) {
	                if (p > mid)
	                    Arr[(int)k++] = A[(int)q++];
	
	                else if (q > end)
	                    Arr[(int)k++] = A[(int)p++];
	
	                else if (A[(int)p] < A[(int)q])
	                    Arr[(int)k++] = A[(int)p++];
	
	                else
	                    Arr[(int)k++] = A[(int)q++];
	            }
	            for (int i = 0; i < k; i++) {
	                A[(int)start++] = Arr[i];
	            }
	
	        }
	
	    }
		}