Problem: Given 2 integers u and v, find the shortest array such that [bitwise-xor](https://en.wikipedia.org/wiki/Bitwise_operation#XOR) of its elements is u, and the sum of its elements is v.

Input

The only line contains 2 integers u and v (0 ≤ u,v ≤ 10^{18}).

Output

If there's no array that satisfies the condition, print "-1". Otherwise:

The first line should contain one integer, n, representing the length of the desired array. The next line should contain n positive integers, the array itself. If there are multiple possible answers, print any.

Examples

Input


2 4


Output


2
3 1

Input


1 3


Output


3
1 1 1

Input


8 5


Output


-1

Input


0 0


Output


0

Note

In the first sample, 3⊕ 1 = 2 and 3 + 1 = 4. There is no valid array of smaller length.

Notice that in the fourth sample the array is empty.

Solution (in PYTHON3):

Solution:
u,v=map(int,input().split())
if v==0 and u==0:
    print(0)
elif v<u:
    print(-1)
else:
    if (v-u)%2==0:
        array=[u,int((v-u)//2),int((v-u)//2)]
        if v-u==0:
            print(1,u,sep="\n")
        elif int(u+((v-u)//2))^int((v-u)//2)==u:
            print(2)
            print(int(u+((v-u)//2)),int((v-u)//2))
        else:
            print(3)
            print(*array)
    else:print(-1)