Problem: Heidi is a statistician to the core, and she likes to study the evolution of marmot populations in each of V (1 ≤ V ≤ 100) villages! So it comes that every spring, when Heidi sees the first snowdrops sprout in the meadows around her barn, she impatiently dons her snowshoes and sets out to the Alps, to welcome her friends the marmots to a new season of thrilling adventures.

Arriving in a village, Heidi asks each and every marmot she comes across for the number of inhabitants of that village. This year, the marmots decide to play an April Fools' joke on Heidi. Instead of consistently providing the exact number of inhabitants P (10 ≤ P ≤ 1000) of the village, they respond with a random non-negative integer k, drawn from one of two types of probability distributions:

  * Poisson (d'avril) distribution: the probability of getting an answer k is <image> for k = 0, 1, 2, 3, ..., 
  * Uniform distribution: the probability of getting an answer k is <image> for k = 0, 1, 2, ..., 2P. 



Heidi collects exactly 250 answers per village. Every village follows either the Poisson or the uniform distribution. Heidi cannot tell marmots apart, so she may query some marmots several times, and each time the marmot will answer with a new number drawn from the village's distribution.

Can you help Heidi to find out whether a village follows a Poisson or a uniform distribution?

Input

The first line of input will contain the number of villages V (1 ≤ V ≤ 100). The following V lines each describe one village. The description of each village consists of 250 space-separated integers k, drawn from one of the above distributions.

Output

Output one line per village, in the same order as provided in the input. The village's line shall state poisson if the village's distribution is of the Poisson type, and uniform if the answer came from a uniform distribution.

Example

Input

2
92 100 99 109 93 105 103 106 101 99 ... (input is truncated)
28 180 147 53 84 80 180 85 8 16 ... (input is truncated)

Output

poisson
uniform

Note

The full example input is visually represented below, along with the probability distribution function it was drawn from (the y-axis is labeled by its values multiplied by 250).

<image>

Solution (in JAVA):

Solution:


import java.util.*;
import static java.lang.System.out;

import java.io.DataInputStream; 
import java.io.FileInputStream; 
import java.io.IOException; 
import java.io.InputStreamReader; 

public class Main 
{ 

	static int mod = 1000000007;
	static final long M = (int)1e9+7;
	 
	
	static class Reader 
	{ 
		final private int BUFFER_SIZE = 1 << 16; 
		private DataInputStream din; 
		private byte[] buffer; 
		private int bufferPointer, bytesRead; 

		public Reader() 
		{ 
			din = new DataInputStream(System.in); 
			buffer = new byte[BUFFER_SIZE]; 
			bufferPointer = bytesRead = 0; 
		} 

		public Reader(String file_name) throws IOException 
		{ 
			din = new DataInputStream(new FileInputStream(file_name)); 
			buffer = new byte[BUFFER_SIZE]; 
			bufferPointer = bytesRead = 0; 
		} 

		public String next() throws IOException 
		{ 
			byte[] buf = new byte[64]; // line length 
			int cnt = 0, c; 
			while ((c = read()) != -1) 
			{ 
				if (c == '\n') 
					break; 
				buf[cnt++] = (byte) c; 
			} 
			return new String(buf, 0, cnt); 
		} 
		
		public int nextInt() throws IOException 
		{ 
			int ret = 0; 
			byte c = read(); 
			while (c <= ' ') 
				c = read(); 
			boolean neg = (c == '-'); 
			if (neg) 
				c = read(); 
			do
			{ 
				ret = ret * 10 + c - '0'; 
			} while ((c = read()) >= '0' && c <= '9'); 

			if (neg) 
				return -ret; 
			return ret; 
		}
		int[] readArray(int n) throws IOException {
			int[] a=new int[n];
			for (int i=0; i<n; i++) a[i]=nextInt();
			return a;
		}

		public long nextLong() throws IOException 
		{ 
			long ret = 0; 
			byte c = read(); 
			while (c <= ' ') 
				c = read(); 
			boolean neg = (c == '-'); 
			if (neg) 
				c = read(); 
			do { 
				ret = ret * 10 + c - '0'; 
			} 
			while ((c = read()) >= '0' && c <= '9'); 
			if (neg) 
				return -ret; 
			return ret; 
		} 

		public double nextDouble() throws IOException 
		{ 
			double ret = 0, div = 1; 
			byte c = read(); 
			while (c <= ' ') 
				c = read(); 
			boolean neg = (c == '-'); 
			if (neg) 
				c = read(); 

			do { 
				ret = ret * 10 + c - '0'; 
			} 
			while ((c = read()) >= '0' && c <= '9'); 

			if (c == '.') 
			{ 
				while ((c = read()) >= '0' && c <= '9') 
				{ 
					ret += (c - '0') / (div *= 10); 
				} 
			} 

			if (neg) 
				return -ret; 
			return ret; 
		} 

		private void fillBuffer() throws IOException 
		{ 
			bytesRead = din.read(buffer, bufferPointer = 0, BUFFER_SIZE); 
			if (bytesRead == -1) 
				buffer[0] = -1; 
		} 

		private byte read() throws IOException 
		{ 
			if (bufferPointer == bytesRead) 
				fillBuffer(); 
			return buffer[bufferPointer++]; 
		} 

		public void close() throws IOException 
		{ 
			if (din == null) 
				return; 
			din.close(); 
		}

	}

	
	public static boolean isPrime(int n) {
		if(n == 1)
		{
			return false;
		}
		for(int i = 2;i*i<=n;i++)
		{
			if(n%i == 0)
			{
				return false;
			}
		}
		return true;
	}
	
	public static int gcd(int a, int b)
	{
		if(b == 0)
		 return a;
		
		else
		return gcd(b,a%b);
	}
	
	
	public static int[] computePrefix(int arr[], int n)
	{
		int[] prefix = new int[n];
		prefix[0] = arr[0];
		for(int i = 1;i<n;i++)
		{
			prefix[i] = prefix[i-1]+arr[i];
		}
		
		return prefix;
	}
	
	public static int lcm(int a, int b)
	{
		return (a*b)/gcd(a,b);
	}
	
	public static int phi(int n)  //euler totient function
    { 
        int result = 1; 
        for (int i = 2; i < n; i++) 
            if (gcd(i, n) == 1) 
                result++; 
        return result; 
    }
	
	public static int check(int n)
	{
		int cl = 0;
		while(n > 0)
		{
			if(n%10 == 8)
			{
				cl++;
				n/=10;
			}
		}
		
		return cl;
	}
	
	public static boolean digCheck(int n)
	{
		int cond = 8;
		while(n > 0)
		{
			if(n%10 == cond)
			{
				return true;
			}
			n/=10;
		}
		return false;
	}
	
	public static int[] Sort(int arr[])
	{
		
		//Heap Sort!!!
		PriorityQueue<Integer> pq = new PriorityQueue<>();
		for(int i : arr)
		{
			pq.add(i);
		}
		
		for(int i = 0;i < arr.length;i++)
		{
			arr[i] = pq.poll();
		}
		
		return arr;
	}
	
	
	
	public static void main(String[] args) throws IOException 
	{ 
		Reader sc=new Reader();
		
		int t = sc.nextInt();
		while(t-- > 0)
		{
			int n = 250;
			List<Integer> list = new ArrayList<>();
			int average = 0;
			for(int i = 0;i<n;i++)
			{
				int add = sc.nextInt();
				list.add(add);
				average += add;
			}
			average /= n;
			int cnt = 0;
			for(int i : list)
			{
				if(i < average / 2 || i > average * 2)
				{
					cnt++;
				}
			}
			if(cnt >= 15)
			{
				System.out.println("uniform");
			}
			else {
				System.out.println("poisson");
			}
		}
	}
}