Problem: You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

* It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:


N


Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:


h n w

Examples

Input

2


Output

1 2 2


Input

3485


Output

872 1012974 1539173474040


Input

4664


Output

3498 3498 3498

Solution (in JAVA):

Solution:
import java.util.*;
import java.io.*;

public class Main {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        long N = sc.nextLong();
        if(N%2==0){
        	long h = N;
        	long n = N;
        	long w = N/2;
        	System.out.println(h+" "+n+" "+w);
        }else{
        	//4hnw = nwN + hwN + nhN
        	//h(4nw-wN-nN)=nwN
        	//3500^2 search...?
        	for(long n=1;n<=3500;n++){
        		for(long w=1;w<=3500;w++){
        			if(4*n*w-w*N-n*N>0 && (n*w*N)%(4*n*w-w*N-n*N)==0){
        				long h = (n*w*N)/(4*n*w-w*N-n*N);
        				System.out.println(h+" "+n+" "+w);
        				System.exit(0);
        			}
        		}
        	}
        }
    }
}