Problem: After you had helped George and Alex to move in the dorm, they went to help their friend Fedor play a new computer game «Call of Soldiers 3».

The game has (m + 1) players and n types of soldiers in total. Players «Call of Soldiers 3» are numbered form 1 to (m + 1). Types of soldiers are numbered from 0 to n - 1. Each player has an army. Army of the i-th player can be described by non-negative integer xi. Consider binary representation of xi: if the j-th bit of number xi equal to one, then the army of the i-th player has soldiers of the j-th type. 

Fedor is the (m + 1)-th player of the game. He assume that two players can become friends if their armies differ in at most k types of soldiers (in other words, binary representations of the corresponding numbers differ in at most k bits). Help Fedor and count how many players can become his friends.

Input

The first line contains three integers n, m, k (1 ≤ k ≤ n ≤ 20; 1 ≤ m ≤ 1000).

The i-th of the next (m + 1) lines contains a single integer xi (1 ≤ xi ≤ 2n - 1), that describes the i-th player's army. We remind you that Fedor is the (m + 1)-th player.

Output

Print a single integer — the number of Fedor's potential friends.

Examples

Input

7 3 1
8
5
111
17


Output

0


Input

3 3 3
1
2
3
4


Output

3

Solution (in PYTHON3):

Solution:
s = input().split(' ')
n = int(s[0])
m = int(s[1])
k = int(s[2])
x = []
a = 0
for i in range(m):
	s = bin(int(input()))[2:]
	x.append(s)
player = bin(int(input()))[2:]
for i in x:
	if (len(i)) > len(player):
		player = '0'*(len(i)-len(player)) + player
	else:
		i = '0'*(len(player)-len(i)) + i
	lol = 0
	for j in range(len(i)):
		if (i[j] != player[j]):
			lol+=1
			if lol > k:
				break
	if lol <= k:
		a+=1
print(a)