Problem: We know that prime numbers are positive integers that have exactly two distinct positive divisors. Similarly, we'll call a positive integer t Т-prime, if t has exactly three distinct positive divisors.

You are given an array of n positive integers. For each of them determine whether it is Т-prime or not.

Input

The first line contains a single positive integer, n (1 ≤ n ≤ 105), showing how many numbers are in the array. The next line contains n space-separated integers xi (1 ≤ xi ≤ 1012).

Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is advised to use the cin, cout streams or the %I64d specifier.

Output

Print n lines: the i-th line should contain "YES" (without the quotes), if number xi is Т-prime, and "NO" (without the quotes), if it isn't.

Examples

Input

3
4 5 6


Output

YES
NO
NO

Note

The given test has three numbers. The first number 4 has exactly three divisors — 1, 2 and 4, thus the answer for this number is "YES". The second number 5 has two divisors (1 and 5), and the third number 6 has four divisors (1, 2, 3, 6), hence the answer for them is "NO".

Solution (in PYTHON):

Solution:
import sys

def readints() :
    l = sys.stdin.readline()
    return map(int, l.split(' '))

def readstring() :
    l = sys.stdin.readline()[:-1]
    return l

def readint() :
    l = sys.stdin.readline()
    return int(l)

def clearchars(s, chars) :
    for c in chars :
        s = s.replace(c, '')
    return s

def gcd(a, b) :
    if (a < b ) :
        a, b = b, a
    if b == 0 :
        return a
    return gcd(b, a % b)

def hist(a) :
    h = {}
    for x in a :
        try : 
            h[x] += 1
        except KeyError :
            h[x] = 1
    return h

def lucky(n) :
    s = set(str(n))
    return all(map(lambda x: x in '47', s))    

def yslice(a, j) :
    return map(lambda x: x[j], a)

def dist2(a, b) :
    return ((a[0] - b[0]) ** 2 + (a[1] - b[1]) ** 2) ** 0.5

def chain_len(a) :
    l = .0
    for d, e in zip(a, a[1:]) :
        l += dist2(d, e)
    return l

def is_prime(x) :
    if x == 1 :
        return False
    if x == 2 :
        return True
    sq = int(x ** 0.5)
    for i in xrange(3, sq + 1, 2) :
        if x % i == 0 :
            return False
    return True

digits = '0123456789'

def noe() :
    print "NO"
    exit(0)

def yese() :
    print "YES"
    exit(0)


n = readint()
a = readints()
h = {}

er = [True] * 1000001
er[1] = False
for i in range(2, 500000) :
    if er[i] == True :
        for j in range(2 * i, 1000001, i) :
            er[j] = False

for x in a :
    try :
        if h[x] :
            print "YES"
        else :
            print "NO"
        continue
    except KeyError :
        pass
    s = int(round(x ** 0.5))
    if s * s == x and er[s] :
        h[x] = True
        print "YES"
    else :
        h[x] = False
        print "NO"