Problem: You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

* It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:


N


Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:


h n w

Examples

Input

2


Output

1 2 2


Input

3485


Output

872 1012974 1539173474040


Input

4664


Output

3498 3498 3498

Solution (in CPP):

Solution:
#include <cstdio>
using namespace std;
typedef long long int ll;

int main(){
	int N;
	scanf("%d",&N);
	for(int i=1;i<=3500;i++){
		for(int j=1;j<=3500;j++){
			ll A=4LL*(ll) i*(ll) j-(ll) N*(ll) (i+j);
			ll B=(ll) N*(ll) i*(ll) j;
			if(A>0&&B%A==0){
				printf("%d %d %lld\n",i,j,B/A);
				return 0;
			}
		}
	}
 	return 0;
}