Problem: You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

* It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:


N


Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:


h n w

Examples

Input

2


Output

1 2 2


Input

3485


Output

872 1012974 1539173474040


Input

4664


Output

3498 3498 3498

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

public class Main {

	public static void main(String[] args) throws IOException {
		BufferedReader br = new BufferedReader(new InputStreamReader(System.in));

		long N = Long.parseLong(br.readLine());

		for (int h = 1; h <= 3500; h++) {
			for (int n = 1; n <= 3500; n++) {
				long up = N * h * n;
				long down = 4 * h * n - N * n - N * h;

				if (down == 0)
					continue;

				if (up % down != 0)
					continue;

				long w = up / down;

				if (0 < w && w <= 3500) {
					System.out.println(h + " " + n + " " + w);
					return;
				}
			}
		}
	}

	static boolean isInt(double d) {
		return d == (int) d;
	}
}