Problem: We have a graph with N vertices and M edges, and there are two people on the graph: Takahashi and Aoki.

The i-th edge connects Vertex U_i and Vertex V_i. The time it takes to traverse this edge is D_i minutes, regardless of direction and who traverses the edge (Takahashi or Aoki).

Takahashi departs Vertex S and Aoki departs Vertex T at the same time. Takahashi travels to Vertex T and Aoki travels to Vertex S, both in the shortest time possible. Find the number of the pairs of ways for Takahashi and Aoki to choose their shortest paths such that they never meet (at a vertex or on an edge) during the travel, modulo 10^9 + 7.

Constraints

* 1 \leq N \leq 100 000
* 1 \leq M \leq 200 000
* 1 \leq S, T \leq N
* S \neq T
* 1 \leq U_i, V_i \leq N (1 \leq i \leq M)
* 1 \leq D_i \leq 10^9 (1 \leq i \leq M)
* If i \neq j, then (U_i, V_i) \neq (U_j, V_j) and (U_i, V_i) \neq (V_j, U_j).
* U_i \neq V_i (1 \leq i \leq M)
* D_i are integers.
* The given graph is connected.

Input

Input is given from Standard Input in the following format:


N M
S T
U_1 V_1 D_1
U_2 V_2 D_2
:
U_M V_M D_M


Output

Print the answer.

Examples

Input

4 4
1 3
1 2 1
2 3 1
3 4 1
4 1 1


Output

2


Input

3 3
1 3
1 2 1
2 3 1
3 1 2


Output

2


Input

8 13
4 2
7 3 9
6 2 3
1 6 4
7 6 9
3 8 9
1 2 2
2 8 12
8 6 9
2 5 5
4 2 18
5 3 7
5 1 515371567
4 8 6


Output

6

Solution (in PYTHON3):

Solution:
def examC():
    ans = 0
    print(ans)
    return

def examD():
    ans = 0
    print(ans)
    return

def examE():
    def dijkstra(edges, start=0):
        dist = [inf] * len(edges)
        dist[start] = 0
        Q = [(0, start)]  # (dist,vertex)
        while (Q):
            d, v = heapq.heappop(Q)
            if dist[v] < d: continue  # 候補として挙がったd,vだが、他に短いのがある
            for u, cost in edges[v]:
                if dist[u] > dist[v] + cost:
                    dist[u] = dist[v] + cost
                    heapq.heappush(Q, (dist[u], u))
        return dist
    N, M = LI()
    S, T = LI()
    S -= 1; T -= 1
    V = [set()for _ in range(N)]
    for _ in range(M):
        u, v, c = LI()
        u -= 1; v -= 1
        V[u].add((v,c))
        V[v].add((u,c))
    distS = dijkstra(V,S)
    distT = dijkstra(V,T)
    L = distS[T]
    numS = [i for i in range(N)]
    C = list(zip(distS,numS))
    C.sort()
    _, numS = zip(*C)
    numT = [i for i in range(N)]
    C = list(zip(distT,numT))
    C.sort()
    _, numT = zip(*C)
    #print(numS)

    dp1 = [0]*N
    dp2 = [0]*N
    dp1[S] = 1; dp2[T] = 1
    S_collision_points = set()
    S_collision_edges = set()
    for now in numS:
        if distS[now] + distT[now] == L and distS[now] == distT[now]:
            S_collision_points.add(now)
        #print(now,used,dp1)
        for v,c in V[now]:
            if distT[v]+distS[now]==L-c:
                #print(distS[v],distS[now],now)
                dp1[v] += dp1[now]
                dp1[v] %= mod
                if distS[now]*2<L and L<distS[v]*2:
                    S_collision_edges.add((now,v))
    for now in numT:
        for v,c in V[now]:
            if distS[v]+distT[now]==L-c:
                dp2[v] += dp2[now]
                dp2[v] %= mod
    collision_points = S_collision_points
    collision_edges = S_collision_edges
    #print(distS)
    #print(distT)
    #print(dp1)
    #print(dp2)
    #print(S_collision_edges)
    ans = 0
    ans += dp1[T]**2
    ans %= mod
    for p in collision_points:
        if distS[p]==distT[p]:
            ans -= (dp1[p]**2)*(dp2[p]**2)
            ans += supermod
            ans %= mod
            #print(ans,p)
    for u,v in collision_edges:
        ans -= (dp1[u]**2)*(dp2[v]**2)
        ans += supermod
        ans %= mod
        #print(ans,u,v)
    print(ans)
    return

def examF():
    ans = 0
    print(ans)
    return


from decimal import getcontext,Decimal as dec
import sys,bisect,itertools,heapq,math,random
from copy import deepcopy
from heapq import heappop,heappush,heapify
from collections import Counter,defaultdict,deque
read = sys.stdin.buffer.read
readline = sys.stdin.buffer.readline
readlines = sys.stdin.buffer.readlines
def I(): return int(input())
def LI(): return list(map(int,sys.stdin.readline().split()))
def DI(): return dec(input())
def LDI(): return list(map(dec,sys.stdin.readline().split()))
def LSI(): return list(map(str,sys.stdin.readline().split()))
def LS(): return sys.stdin.readline().split()
def SI(): return sys.stdin.readline().strip()
global mod,mod2,inf,alphabet,_ep
mod = 10**9 + 7
supermod = mod**4
mod2 = 998244353
inf = 10**18
_ep = dec("0.000000000001")
alphabet = [chr(ord('a') + i) for i in range(26)]
alphabet_convert = {chr(ord('a') + i): i for i in range(26)}

getcontext().prec = 28

sys.setrecursionlimit(10**7)

if __name__ == '__main__':
    examE()

"""
142
12 9 1445 0 1
asd dfg hj o o
aidn
"""