Problem: We know that prime numbers are positive integers that have exactly two distinct positive divisors. Similarly, we'll call a positive integer t Т-prime, if t has exactly three distinct positive divisors.

You are given an array of n positive integers. For each of them determine whether it is Т-prime or not.

Input

The first line contains a single positive integer, n (1 ≤ n ≤ 105), showing how many numbers are in the array. The next line contains n space-separated integers xi (1 ≤ xi ≤ 1012).

Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is advised to use the cin, cout streams or the %I64d specifier.

Output

Print n lines: the i-th line should contain "YES" (without the quotes), if number xi is Т-prime, and "NO" (without the quotes), if it isn't.

Examples

Input

3
4 5 6


Output

YES
NO
NO

Note

The given test has three numbers. The first number 4 has exactly three divisors — 1, 2 and 4, thus the answer for this number is "YES". The second number 5 has two divisors (1 and 5), and the third number 6 has four divisors (1, 2, 3, 6), hence the answer for them is "NO".

Solution (in PYTHON3):

Solution:

def cal_primeflag():
    primeflag=[0]*1000000
    primeflag[0]=primeflag[1]=1;
    for i in range(1000000):
        if (primeflag[i]==0):
            for j in range(i*i,1000000,i):
                primeflag[j]=1
    return primeflag
	
n=int(input())
l=input().split()
primeflag=cal_primeflag()
for i in range(n):
    l[i]=int(l[i])
    if l[i]==4:
        print("YES")
    elif l[i]%2==0:
        print("NO")
            
    elif pow(l[i],0.5)==int(pow(l[i],0.5)):
        if primeflag[int(pow(l[i],0.5))]==0:
            print("YES")
        else:
            print("NO")
    else:
        print("NO")