Problem: You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

* It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:


N


Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:


h n w

Examples

Input

2


Output

1 2 2


Input

3485


Output

872 1012974 1539173474040


Input

4664


Output

3498 3498 3498

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;

int main() {
	long double N;
	cin >> N; 
	for (long double i = 1; i <= 3500; i += 1) {
		for (long double j = 1; j <= 3500; j += 1) {
			long double w = (N * i * j)/(4 * i * j - N * i - N * j);
			if (w > 0.0 && w < 3500.0 && floor(w) == w) {
				cout << fixed << setprecision(0) << i << " " << j << " " << w << " \n";
				return 0;
			}
		}
	}
}