Problem: We guessed a permutation p consisting of n integers. The permutation of length n is the array of length n where each element from 1 to n appears exactly once. This permutation is a secret for you.

For each position r from 2 to n we chose some other index l (l < r) and gave you the segment p_l, p_{l + 1}, ..., p_r in sorted order (i.e. we rearranged the elements of this segment in a way that the elements of this segment are sorted). Thus, you are given exactly n-1 segments of the initial permutation but elements inside each segment are sorted. The segments are given to you in random order.

For example, if the secret permutation is p=[3, 1, 4, 6, 2, 5] then the possible given set of segments can be:

  * [2, 5, 6] 
  * [4, 6] 
  * [1, 3, 4] 
  * [1, 3] 
  * [1, 2, 4, 6] 



Your task is to find any suitable permutation (i.e. any permutation corresponding to the given input data). It is guaranteed that the input data corresponds to some permutation (i.e. such permutation exists).

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then t test cases follow.

The first line of the test case contains one integer n (2 ≤ n ≤ 200) — the length of the permutation.

The next n-1 lines describe given segments.

The i-th line contains the description of the i-th segment. The line starts with the integer k_i (2 ≤ k_i ≤ n) — the length of the i-th segment. Then k_i integers follow. All integers in a line are distinct, sorted in ascending order, between 1 and n, inclusive.

It is guaranteed that the required p exists for each test case.

It is also guaranteed that the sum of n over all test cases does not exceed 200 (∑ n ≤ 200).

Output

For each test case, print the answer: n integers p_1, p_2, ..., p_n (1 ≤ p_i ≤ n, all p_i should be distinct) — any suitable permutation (i.e. any permutation corresponding to the test case input).

Example

Input


5
6
3 2 5 6
2 4 6
3 1 3 4
2 1 3
4 1 2 4 6
5
2 2 3
2 1 2
2 1 4
2 4 5
7
3 1 2 6
4 1 3 5 6
2 1 2
3 4 5 7
6 1 2 3 4 5 6
3 1 3 6
2
2 1 2
5
2 2 5
3 2 3 5
4 2 3 4 5
5 1 2 3 4 5


Output


3 1 4 6 2 5 
3 2 1 4 5 
2 1 6 3 5 4 7 
1 2 
2 5 3 4 1 

Solution (in JAVA):

Solution:


import java.io.*;
import java.util.*;

import static java.lang.Math.*;

public class Contest {
    public static class pair implements Comparable<pair> {
        int u;
        long val;

        public pair(int a, long value) {
            u = a;
            val = value;
        }

        @Override
        public int compareTo(pair p) {
            return Long.compare(val, p.val);
        }
    }

    static int n, m;
    static ArrayList<Integer>[] adj;
    static int dist[];
    static int parent[];
    static long inf = (long) 1e16;
    static int INF = (int) 1e9;

    public static int[] bfs(int s) {
        dist = new int[n];
        Arrays.fill(dist, -1);
        dist[s] = 0;
        Queue<Integer> q = new LinkedList<>();
        q.add(s);
        while (!q.isEmpty()) {
            int u = q.poll();
            for (int v : adj[u])
                if (dist[v] == -1) {
                    dist[v] = dist[u] + 1;
                    q.add(v);
                }
        }
        return dist;
    }

    public static long calc(long[] acc, int single, int Dbl) {
        if (single + Dbl > m) return inf;
        return acc[Dbl] + acc[single + Dbl];
    }

    public static boolean subset(TreeSet<Integer> small, TreeSet<Integer> big) {
        for (int x : small)
            if (!big.contains(x))
                return false;
        return true;
    }

    public static TreeSet<Integer> subset2(TreeSet<Integer> small, TreeSet<Integer> big) {
        TreeSet<Integer> ts = new TreeSet<>();
        for (int x : small)
            if (!big.contains(x))
                ts.add(x);
        return ts;
    }

    public static boolean CanBeStart(int x, TreeSet<Integer>[] Arr) {
        TreeSet<Integer> last = new TreeSet<>();
        for (int j = 0; j < n - 1; j++)
            if (Arr[j].contains(x)) {
                if (!subset(last, Arr[j]))
                    return false;
                last = Arr[j];
            }
        return true;
    }

    public static boolean check(TreeSet<Integer> sublist, ArrayList<Integer> arr) {
        int len = sublist.size(), n = arr.size();
        for (int i = 0; i < n - len + 1; i++) {
            boolean flag = true;
            for (int j = 0; j < len; j++)
                if (!sublist.contains(arr.get(i + j)))
                    flag = false;
            if (flag) return true;
        }
        return false;
    }

    public static boolean check(TreeSet<Integer>[] Arr, ArrayList<Integer> arr) {
        boolean ans = true;
        for (int i = 0; i < n - 1; i++)
            ans &= check(Arr[i], arr);
        return ans;
    }

    public static void main(String[] args) throws Exception {
        Scanner sc = new Scanner(System.in);
        PrintWriter pw = new PrintWriter(System.out);
        int t = sc.nextInt();
        while (t-- > 0) {
            n = sc.nextInt();
            TreeSet<Integer>[] Arr = new TreeSet[n - 1];

            for (int i = 0; i < n - 1; i++) {
                Arr[i] = new TreeSet<>();
                int k = sc.nextInt();
                while (k-- > 0) Arr[i].add(sc.nextInt());
            }
         //   System.out.println(Arrays.toString(Arr));
            ArrayList<Integer> ans = new ArrayList();

            out:
            for (int i = 1; i <= n; i++) {
                TreeSet<Integer>[] temp = new TreeSet[n-1];
                for(int l=0;l<n-1;l++)temp[l]= (TreeSet<Integer>) Arr[l].clone();
                ArrayList sofAns = new ArrayList();
                int start = i;
                sofAns.add(start);
                for (int k = 0; k < n - 1; k++) {
                    for (int j = 0; j < n - 1; j++)
                        temp[j].remove(start);
                    boolean cont = false;
                    for (int j = 0; j < n - 1; j++)
                        if (temp[j].size() == 1) {
                            cont = true;
                            int rem = temp[j].first();
                            sofAns.add(rem);
                            start = rem;
                            break;
                        }
                    if (!cont)
                        continue out;

                }
                if (check(Arr, sofAns   ))
                    ans = sofAns;
            }
            for(int y:ans)
            pw.print(y+" ");
            pw.println();
        }
        pw.close();

    }

    static class Scanner {
        StringTokenizer st;
        BufferedReader br;

        public Scanner(InputStream s) {
            br = new BufferedReader(new InputStreamReader(s));
        }

        public String next() throws IOException {
            while (st == null || !st.hasMoreTokens())
                st = new StringTokenizer(br.readLine());
            return st.nextToken();
        }

        public int nextInt() throws IOException {
            return Integer.parseInt(next());
        }

        public long nextLong() throws IOException {
            return Long.parseLong(next());
        }

        public String nextLine() throws IOException {
            return br.readLine();
        }

        public double nextDouble() throws IOException {
            String x = next();
            StringBuilder sb = new StringBuilder("0");
            double res = 0, f = 1;
            boolean dec = false, neg = false;
            int start = 0;
            if (x.charAt(0) == '-') {
                neg = true;
                start++;
            }
            for (int i = start; i < x.length(); i++)
                if (x.charAt(i) == '.') {
                    res = Long.parseLong(sb.toString());
                    sb = new StringBuilder("0");
                    dec = true;
                } else {
                    sb.append(x.charAt(i));
                    if (dec)
                        f *= 10;
                }
            res += Long.parseLong(sb.toString()) / f;
            return res * (neg ? -1 : 1);
        }

        public boolean ready() throws IOException, IOException {
            return br.ready();
        }

    }
}