Problem: You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

* It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:


N


Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:


h n w

Examples

Input

2


Output

1 2 2


Input

3485


Output

872 1012974 1539173474040


Input

4664


Output

3498 3498 3498

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
#define rep1(i,n) for(int i=1;i<=int(n);++i)
typedef long long ll;

int main(void){
    ll N;
    cin>>N;
    rep1(a,3500)rep1(b,a){
        if(4*a*b-N*a-N*b <= 0) continue;
        if((N*a*b)%(4*a*b-N*a-N*b)==0){
            cout<<a<<" "<<b<<" "<<(N*a*b)/(4*a*b-N*a-N*b)<<endl;
            return 0;
        }
    }
}