Problem: We know that prime numbers are positive integers that have exactly two distinct positive divisors. Similarly, we'll call a positive integer t Т-prime, if t has exactly three distinct positive divisors.

You are given an array of n positive integers. For each of them determine whether it is Т-prime or not.

Input

The first line contains a single positive integer, n (1 ≤ n ≤ 105), showing how many numbers are in the array. The next line contains n space-separated integers xi (1 ≤ xi ≤ 1012).

Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is advised to use the cin, cout streams or the %I64d specifier.

Output

Print n lines: the i-th line should contain "YES" (without the quotes), if number xi is Т-prime, and "NO" (without the quotes), if it isn't.

Examples

Input

3
4 5 6


Output

YES
NO
NO

Note

The given test has three numbers. The first number 4 has exactly three divisors — 1, 2 and 4, thus the answer for this number is "YES". The second number 5 has two divisors (1 and 5), and the third number 6 has four divisors (1, 2, 3, 6), hence the answer for them is "NO".

Solution (in PYTHON3):

Solution:
limit = 1000000
def calculate_prime_flag_for_each_number_upto_limit():
    prime_flag = [True] * limit
    prime_flag[0] = prime_flag[1] = False
    for i in range(2,limit):
        if prime_flag[i] == True:
            for j in range(i*i, limit, i):
                prime_flag[j] = False
    return prime_flag 
def ctp(q):
    g=q**0.5
    
    if(g-int(g)==0and (g%10%2!=0 or g==2)):
        if(pf[int(g)]==True):
            return 1
    return 0
n=int(input())
a=list(map(int,input().strip().split(' ')))
pf=calculate_prime_flag_for_each_number_upto_limit()
for i in a:
    if( ctp(i)==1):
        print("YES")
        
    else:
        print("NO")