Problem: We know that prime numbers are positive integers that have exactly two distinct positive divisors. Similarly, we'll call a positive integer t Т-prime, if t has exactly three distinct positive divisors.

You are given an array of n positive integers. For each of them determine whether it is Т-prime or not.

Input

The first line contains a single positive integer, n (1 ≤ n ≤ 105), showing how many numbers are in the array. The next line contains n space-separated integers xi (1 ≤ xi ≤ 1012).

Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is advised to use the cin, cout streams or the %I64d specifier.

Output

Print n lines: the i-th line should contain "YES" (without the quotes), if number xi is Т-prime, and "NO" (without the quotes), if it isn't.

Examples

Input

3
4 5 6


Output

YES
NO
NO

Note

The given test has three numbers. The first number 4 has exactly three divisors — 1, 2 and 4, thus the answer for this number is "YES". The second number 5 has two divisors (1 and 5), and the third number 6 has four divisors (1, 2, 3, 6), hence the answer for them is "NO".

Solution (in PYTHON3):

Solution:
def sieve(a):
    prime = [True for i in range(a+1)]
    p = 2
    while(p*p<=a):
        if(prime[p]):
            for i in range(p*p,a+1,p):
                prime[i]=False
        p+=1
    return prime


n = int(input())
A = list(map(int,input().split()))
a = int(1e6+2)
prime = sieve(a)
for i in A:
    c = i**0.5
    if(c-int(c)!=0 or c==1):
        print("NO")
        continue
    c = int(c)
    #print(prime[c],c)
    if(prime[c]):
        print("YES")
    else:
        print("NO")