Problem: You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

* It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:


N


Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:


h n w

Examples

Input

2


Output

1 2 2


Input

3485


Output

872 1012974 1539173474040


Input

4664


Output

3498 3498 3498

Solution (in CPP):

Solution:
#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
int main(){
 ll N; cin >> N;
  for(ll x = 1; x<= 3500; x++){
    for(ll y = 1; y <= 3500; y++){
      ll a= N*x*y; ll b = 4*x*y - N*(x+y);
      if( b>0 && a%b == 0){ cout << x << " " << y << " " << a/b << endl;return 0;}
    }
  }
  
  return 0;}