Problem: We know that prime numbers are positive integers that have exactly two distinct positive divisors. Similarly, we'll call a positive integer t Т-prime, if t has exactly three distinct positive divisors.

You are given an array of n positive integers. For each of them determine whether it is Т-prime or not.

Input

The first line contains a single positive integer, n (1 ≤ n ≤ 105), showing how many numbers are in the array. The next line contains n space-separated integers xi (1 ≤ xi ≤ 1012).

Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is advised to use the cin, cout streams or the %I64d specifier.

Output

Print n lines: the i-th line should contain "YES" (without the quotes), if number xi is Т-prime, and "NO" (without the quotes), if it isn't.

Examples

Input

3
4 5 6


Output

YES
NO
NO

Note

The given test has three numbers. The first number 4 has exactly three divisors — 1, 2 and 4, thus the answer for this number is "YES". The second number 5 has two divisors (1 and 5), and the third number 6 has four divisors (1, 2, 3, 6), hence the answer for them is "NO".

Solution (in PYTHON):

Solution:
import math
def criba_eratostenes2(n):
  A= n*[True]
  k=1
  for i in range(2, n+1):
    if (A[i-1]==True):
      k+=1
      for j in range(i*i, n+1, i):
        A[j-1]=False
  return A
ArregloPrimos=criba_eratostenes2(1000000)
N=int(input())
A=list(map(int,raw_input().split()))
for k in range (N):
    if(A[k]==1 or math.sqrt(A[k])!=int(math.sqrt(A[k]))):
        print "NO"
    else:
        if(ArregloPrimos[int(math.sqrt(A[k])-1)]==True):
           print "YES"
        else:
           print "NO"