Problem: Omkar has received a message from Anton saying "Your story for problem A is confusing. Just make a formal statement." Because of this, Omkar gives you an array a = [a_1, a_2, …, a_n] of n distinct integers. An array b = [b_1, b_2, …, b_k] is called nice if for any two distinct elements b_i, b_j of b, |b_i-b_j| appears in b at least once. In addition, all elements in b must be distinct. Can you add several (maybe, 0) integers to a to create a nice array b of size at most 300? If a is already nice, you don't have to add any elements.

For example, array [3, 6, 9] is nice, as |6-3|=|9-6| = 3, which appears in the array, and |9-3| = 6, which appears in the array, while array [4, 2, 0, 6, 9] is not nice, as |9-4| = 5 is not present in the array.

For integers x and y, |x-y| = x-y if x > y and |x-y| = y-x otherwise.

Input

Each test contains multiple test cases. The first line contains t (1 ≤ t ≤ 50), the number of test cases. Description of the test cases follows.

The first line of each test case contains a single integer n (2 ≤ n ≤ 100) — the length of the array a.

The second line of each test case contains n distinct integers a_1, a_2, ⋅⋅⋅, a_n (-100 ≤ a_i ≤ 100) — the elements of the array a.

Output

For each test case, output one line containing YES if Omkar can create a nice array b by adding elements to a and NO otherwise. The case of each letter does not matter, so yEs and nO will also be accepted.

If the first line is YES, output a second line containing a single integer k (n ≤ k ≤ 300). 

Then output one line containing k distinct integers b_1, b_2, ⋅⋅⋅, b_k (-10^9 ≤ b_i ≤ 10^9), the elements of the nice array b. b_1, b_2, ⋅⋅⋅, b_k can be in any order. For each a_i in a, a_i must appear at least once in b.

It can be proved that if Omkar can create such an array b, then he can also do so in a way that satisfies the above constraints.

If multiple solutions exist, you can print any. 

Example

Input


4
3
3 0 9
2
3 4
5
-7 3 13 -2 8
4
4 8 12 6


Output


yes
4
6 0 3 9
yEs
5
5 3 1 2 4
NO
Yes
6
8 12 6 2 4 10

Note

For the first case, you can add integers to a to receive the array b = [6, 0, 3, 9]. Note that |6-3| = |9-6| = |3-0| = 3 and 3 is in b, |6-0| = |9-3| = 6 and 6 is in b, and |9-0| = 9 is in b, so b is nice.

For the second case, you can add integers to a to receive the array b = [5, 3, 1, 2, 4]. We have that |2-1| = |3-2| = |4-3| = |5-4| = 1 is in b, |3-1| = |4-2| = |5-3| = 2 is in b, |4-1| = |5-2| = 3 is in b, and |5-1| = 4 is in b, so b is nice.

For the fourth case, you can add integers to a to receive the array b = [8, 12, 6, 2, 4, 10]. We have that |4-2| = |6-4| = |8-6| = |10-8| = |12-10| = 2 is in b, |6-2| = |8-4| = |10-6| = |12-8| = 4 is in b, |8-2| = |10-4| = |12-6| = 6 is in b, |10-2| = |12-4| = 8 is in b, and |12-2| = 10 is in b, so b is nice.

It can be proven that for all other test cases it is impossible to create a nice array b.

Solution (in JAVA):

Solution:
import java.sql.SQLSyntaxErrorException;
import java.util.*;
import java.io.*;
import java.util.stream.StreamSupport;

public class Solution {
    static long mod = (long)Math.pow(10,9)+7l;
    public static void main(String str[]) throws IOException{
//        Reader sc = new Reader();
        BufferedWriter output = new BufferedWriter(
                new OutputStreamWriter(System.out));
        Scanner sc = new Scanner(System.in);
        int t = sc.nextInt();
        while(t-->0){
            int n = sc.nextInt();
            int[] arr = new int[n];
            boolean bb = true;
            for(int i=0;i<n;i++){
                arr[i] = sc.nextInt();
                if(arr[i]<0)    bb = false;
            }
            if(bb){
                    output.write("YES\n101\n");
                    for(int i=0;i<=100;i++){
                        output.write(i+" ");
                    }
                    output.write("\n");
            }
            else    output.write("NO\n");
        }

        output.flush();
    }

    static void arri(int arr[], int n, Reader sc) throws IOException{
        for(int i=0;i<n;i++){
            arr[i] = sc.nextInt();
        }
    }
    static void arrl(long arr[], int n, Reader sc) throws IOException{
        for(int i=0;i<n;i++){
            arr[i] = sc.nextLong();
        }
    }

    static long gcd(long a, long b)
    {
        if (b == 0)
            return a;
        return gcd(b, a % b);
    }
    static long power(long x, long y, long p)
    {
        long res = 1; // Initialize result

        x = x % p; // Update x if it is more than or
        // equal to p

        if (x == 0)
            return 0; // In case x is divisible by p;

        while (y > 0)
        {

            // If y is odd, multiply x with result
            if ((y & 1) != 0)
                res = (res * x) % p;

            // y must be even now
            y = y >> 1; // y = y/2
            x = (x * x) % p;
        }
        return res;
    }

//    static boolean dfs(Tree node, boolean[] visited, int parent, ArrayList<Tree> tt){
//        visited[node.a] = true;
//        boolean b = false;
//        for(int i: node.al){
//            if(tt.get(i).a!=parent){
//                if(visited[tt.get(i).a])    return true;
//                b|= dfs(tt.get(i), visited, node.a, tt);
//            }
//        }
//        return b;
//    }

    static class Pair{
        //        int ind;
        int a;
        int b;
        ArrayList<Integer> ii = new ArrayList<>();
        Pair( int a, int b){
//            this.ind = i;
            this.a = a;
            this.b = b;
        }

    }
    static class SortbyI implements Comparator<Pair> {
        // Used for sorting in ascending order of
        // roll number
        public int compare(Pair a, Pair b)
        {
            return a.a - b.a;
        }
    }
    static class SortbyD implements Comparator<Pair> {
        // Used for sorting in ascending order of
        // roll number
        public int compare(Pair a, Pair b)
        {
            return b.a - a.a;
        }
    }
    static int binarySearch(ArrayList<Pair> a, int x, int s, int e){
        if(s>=e){
            if(x<=a.get(s).b)  return s;
            else    return s+1;
        }
        int mid = (e+s)/2;
        if(a.get(mid).b<x){
            return binarySearch(a, x, mid+1, e);
        }
        else    return binarySearch(a,x,s, mid);
    }

    //    static class Edge{
//        int a;
//        int b;
//        int c;
//        int sec;
//        Edge(int a, int b, int c, int sec){
//            this.a = a;
//            this.b = b;
//            this.c = c;
//            this.sec = sec;
//        }
//
//    }
    static class Tree{
        int a;
        ArrayList<Integer> al = new ArrayList<>();
        Tree(int a){
            this.a = a;
        }

    }
    static class Reader {
        final private int BUFFER_SIZE = 1 << 16;
        private DataInputStream din;
        private byte[] buffer;
        private int bufferPointer, bytesRead;

        public Reader()
        {
            din = new DataInputStream(System.in);
            buffer = new byte[BUFFER_SIZE];
            bufferPointer = bytesRead = 0;
        }

        public Reader(String file_name) throws IOException
        {
            din = new DataInputStream(
                    new FileInputStream(file_name));
            buffer = new byte[BUFFER_SIZE];
            bufferPointer = bytesRead = 0;
        }

        public String readLine() throws IOException
        {
            byte[] buf = new byte[64]; // line length
            int cnt = 0, c;
            while ((c = read()) != -1) {
                if (c == '\n') {
                    if (cnt != 0) {
                        break;
                    }
                    else {
                        continue;
                    }
                }
                buf[cnt++] = (byte)c;
            }
            return new String(buf, 0, cnt);
        }

        public int nextInt() throws IOException
        {
            int ret = 0;
            byte c = read();
            while (c <= ' ') {
                c = read();
            }
            boolean neg = (c == '-');
            if (neg)
                c = read();
            do {
                ret = ret * 10 + c - '0';
            } while ((c = read()) >= '0' && c <= '9');

            if (neg)
                return -ret;
            return ret;
        }

        public long nextLong() throws IOException
        {
            long ret = 0;
            byte c = read();
            while (c <= ' ')
                c = read();
            boolean neg = (c == '-');
            if (neg)
                c = read();
            do {
                ret = ret * 10 + c - '0';
            } while ((c = read()) >= '0' && c <= '9');
            if (neg)
                return -ret;
            return ret;
        }

        public double nextDouble() throws IOException
        {
            double ret = 0, div = 1;
            byte c = read();
            while (c <= ' ')
                c = read();
            boolean neg = (c == '-');
            if (neg)
                c = read();

            do {
                ret = ret * 10 + c - '0';
            } while ((c = read()) >= '0' && c <= '9');

            if (c == '.') {
                while ((c = read()) >= '0' && c <= '9') {
                    ret += (c - '0') / (div *= 10);
                }
            }

            if (neg)
                return -ret;
            return ret;
        }

        private void fillBuffer() throws IOException
        {
            bytesRead = din.read(buffer, bufferPointer = 0,
                    BUFFER_SIZE);
            if (bytesRead == -1)
                buffer[0] = -1;
        }

        private byte read() throws IOException
        {
            if (bufferPointer == bytesRead)
                fillBuffer();
            return buffer[bufferPointer++];
        }

        public void close() throws IOException
        {
            if (din == null)
                return;
            din.close();
        }
    }


    static boolean isPrime(int n)
    {
        if (n <= 1)
            return false;
        if (n <= 3)
            return true;
        if (n % 2 == 0 ||
                n % 3 == 0)
            return false;

        for (int i = 5;
             i * i <= n; i = i + 6)
            if (n % i == 0 ||
                    n % (i + 2) == 0)
                return false;

        return true;
    }
    static ArrayList<Integer> sieveOfEratosthenes(int n)
    {
        ArrayList<Integer> al = new ArrayList<>();
        // Create a boolean array
        // "prime[0..n]" and
        // initialize all entries
        // it as true. A value in
        // prime[i] will finally be
        // false if i is Not a
        // prime, else true.
        boolean prime[] = new boolean[n + 1];
        for (int i = 0; i <= n; i++)
            prime[i] = true;

        for (int p = 2; p * p <= n; p++)
        {
            // If prime[p] is not changed, then it is a
            // prime
            if (prime[p] == true)
            {
                // Update all multiples of p
                for (int i = p * p; i <= n; i += p)
                    prime[i] = false;
            }
        }

        // Print all prime numbers
        for (int i = 2; i <= n; i++)
        {
            if (prime[i] == true)
                al.add(i);
        }
        return al;
    }

}