Problem: After you had helped George and Alex to move in the dorm, they went to help their friend Fedor play a new computer game «Call of Soldiers 3».

The game has (m + 1) players and n types of soldiers in total. Players «Call of Soldiers 3» are numbered form 1 to (m + 1). Types of soldiers are numbered from 0 to n - 1. Each player has an army. Army of the i-th player can be described by non-negative integer xi. Consider binary representation of xi: if the j-th bit of number xi equal to one, then the army of the i-th player has soldiers of the j-th type. 

Fedor is the (m + 1)-th player of the game. He assume that two players can become friends if their armies differ in at most k types of soldiers (in other words, binary representations of the corresponding numbers differ in at most k bits). Help Fedor and count how many players can become his friends.

Input

The first line contains three integers n, m, k (1 ≤ k ≤ n ≤ 20; 1 ≤ m ≤ 1000).

The i-th of the next (m + 1) lines contains a single integer xi (1 ≤ xi ≤ 2n - 1), that describes the i-th player's army. We remind you that Fedor is the (m + 1)-th player.

Output

Print a single integer — the number of Fedor's potential friends.

Examples

Input

7 3 1
8
5
111
17


Output

0


Input

3 3 3
1
2
3
4


Output

3

Solution (in PYTHON3):

Solution:
n,m,k=map(int,input().split())
solider=[]
for a in range(m+1):
    b=int(input( ))
    solider.append(b)
fedor=''
for c in range(n-1,-1,-1):
    if 2**c<=solider[m]:
        solider[m]-=2**c
        fedor+='1'
    else:
        fedor+='0'
friend=0
for i in range(m):
    count=0
    for j in range(n-1,-1,-1):
        if 2**j <= solider[i]:
            solider[i]-=2**(j)
            if fedor[n-1-j]!='1':
                count+=1
        else:
            solider[i]=solider[i]
            if fedor[n-1-j]!='0':
                count+=1

    if count<=k:
        friend+=1
print(friend)