Problem: After you had helped George and Alex to move in the dorm, they went to help their friend Fedor play a new computer game «Call of Soldiers 3».

The game has (m + 1) players and n types of soldiers in total. Players «Call of Soldiers 3» are numbered form 1 to (m + 1). Types of soldiers are numbered from 0 to n - 1. Each player has an army. Army of the i-th player can be described by non-negative integer xi. Consider binary representation of xi: if the j-th bit of number xi equal to one, then the army of the i-th player has soldiers of the j-th type. 

Fedor is the (m + 1)-th player of the game. He assume that two players can become friends if their armies differ in at most k types of soldiers (in other words, binary representations of the corresponding numbers differ in at most k bits). Help Fedor and count how many players can become his friends.

Input

The first line contains three integers n, m, k (1 ≤ k ≤ n ≤ 20; 1 ≤ m ≤ 1000).

The i-th of the next (m + 1) lines contains a single integer xi (1 ≤ xi ≤ 2n - 1), that describes the i-th player's army. We remind you that Fedor is the (m + 1)-th player.

Output

Print a single integer — the number of Fedor's potential friends.

Examples

Input

7 3 1
8
5
111
17


Output

0


Input

3 3 3
1
2
3
4


Output

3

Solution (in JAVA):

Solution:
import java.util.Scanner;

public class apples {
    public static void main (String args []){
        Scanner s = new Scanner(System.in);
        int n = s.nextInt();
        int m = s.nextInt();
        int k = s.nextInt();
        String so[]= new String[m+1];
        for(int i = 0 ;i<=m;++i){
            int x =s.nextInt();
            so[i]=Integer.toBinaryString(x);
            for(int j = so[i].length() ; j<n;++j){
             so[i]='0'+so[i];
       }
            }
        int ans = 0;
        for(int i = 0 ;i<m;++i){
            int temp = 0 ;
            for(int j = 0 ;j<n;++j){
                if(so[m].charAt(j)!=so[i].charAt(j))++temp;
            }
            if(temp<=k)++ans;
        }
        System.out.println(ans);
    } 
  
    }