Problem: You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

* It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:


N


Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:


h n w

Examples

Input

2


Output

1 2 2


Input

3485


Output

872 1012974 1539173474040


Input

4664


Output

3498 3498 3498

Solution (in CPP):

Solution:
#include<cstdio>
using namespace std;
int main(){
    double n;
    int w;
    scanf("%lf",&n);
    for(double i=1;i<=3500;i++){
        for(double j=1;j<=3500;j++){
            w=(n*i*j)/(4*i*j-n*i-n*j);
            if((double)w==(n*i*j)/(4*i*j-n*i-n*j)&&w>0){
                printf("%.0f %.0f %d\n",i,j,w);
                return 0;
            }
        }
    }
}