Problem: We know that prime numbers are positive integers that have exactly two distinct positive divisors. Similarly, we'll call a positive integer t Т-prime, if t has exactly three distinct positive divisors.

You are given an array of n positive integers. For each of them determine whether it is Т-prime or not.

Input

The first line contains a single positive integer, n (1 ≤ n ≤ 105), showing how many numbers are in the array. The next line contains n space-separated integers xi (1 ≤ xi ≤ 1012).

Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is advised to use the cin, cout streams or the %I64d specifier.

Output

Print n lines: the i-th line should contain "YES" (without the quotes), if number xi is Т-prime, and "NO" (without the quotes), if it isn't.

Examples

Input

3
4 5 6


Output

YES
NO
NO

Note

The given test has three numbers. The first number 4 has exactly three divisors — 1, 2 and 4, thus the answer for this number is "YES". The second number 5 has two divisors (1 and 5), and the third number 6 has four divisors (1, 2, 3, 6), hence the answer for them is "NO".

Solution (in JAVA):

Solution:
import java.io.PrintWriter;
import java.util.Arrays;
import java.util.Scanner;
import java.util.TreeSet;

public class N230B {

    Scanner in;
    PrintWriter out;

    void solve() {
        int xmax = 1000000;
        boolean mass[] = new boolean[1 + xmax];

        Arrays.fill(mass, true);
        TreeSet<Long> set = new TreeSet<Long>();

        for (long i = 2; i <= xmax; i++) {
            if (mass[(int) i] == true) {
                for (int j = (int) (i + i); j <= xmax; j += i) {
                    if (mass[j] == true) {
                        mass[j] = false;
                    }
                }
            }
        }
        for (int i = xmax; i >= 2; i--) {
            if (mass[i] == true) {
                set.add((long) i * i);
            }
        }

        long n = in.nextInt();
        for (long i = 1; i <= n; i++) {
            long t = in.nextLong();
            if (set.contains(t)) {
                out.println("YES");
            } else {
                out.println("NO");
            }

        }
    }

    void run() {

        in = new Scanner(System.in);
        out = new PrintWriter(System.out);
        try {
            solve();
        } finally {
            out.close();
        }

    }

    public static void main(String[] args) {
        new N230B().run();

    }

}