Problem: We know that prime numbers are positive integers that have exactly two distinct positive divisors. Similarly, we'll call a positive integer t Т-prime, if t has exactly three distinct positive divisors.

You are given an array of n positive integers. For each of them determine whether it is Т-prime or not.

Input

The first line contains a single positive integer, n (1 ≤ n ≤ 105), showing how many numbers are in the array. The next line contains n space-separated integers xi (1 ≤ xi ≤ 1012).

Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is advised to use the cin, cout streams or the %I64d specifier.

Output

Print n lines: the i-th line should contain "YES" (without the quotes), if number xi is Т-prime, and "NO" (without the quotes), if it isn't.

Examples

Input

3
4 5 6


Output

YES
NO
NO

Note

The given test has three numbers. The first number 4 has exactly three divisors — 1, 2 and 4, thus the answer for this number is "YES". The second number 5 has two divisors (1 and 5), and the third number 6 has four divisors (1, 2, 3, 6), hence the answer for them is "NO".

Solution (in PYTHON3):

Solution:
#!/usr/bin/env python3
# -*- coding: utf-8 -*-
"""
Created on Tue Oct 27 12:50:52 2020

@author: apple
"""


M=[0]*1000001
bool(M)
m=[]
for i in range(0,1000001):
    M[i]= True
M[0]=M[1]=False
for j in range(2,1000):
    if M[j]:
        for l in range(2*j,1000001,j):
            M[l]=False
n=int(input())
a=list(map(int,input().split(' ')))
for k in range(n):
    b=a[k]**0.5
    if b==a[k]//b and M[int(b)]:
        print('YES')
    else:
        print('NO')