Problem: We know that prime numbers are positive integers that have exactly two distinct positive divisors. Similarly, we'll call a positive integer t Т-prime, if t has exactly three distinct positive divisors.

You are given an array of n positive integers. For each of them determine whether it is Т-prime or not.

Input

The first line contains a single positive integer, n (1 ≤ n ≤ 105), showing how many numbers are in the array. The next line contains n space-separated integers xi (1 ≤ xi ≤ 1012).

Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is advised to use the cin, cout streams or the %I64d specifier.

Output

Print n lines: the i-th line should contain "YES" (without the quotes), if number xi is Т-prime, and "NO" (without the quotes), if it isn't.

Examples

Input

3
4 5 6


Output

YES
NO
NO

Note

The given test has three numbers. The first number 4 has exactly three divisors — 1, 2 and 4, thus the answer for this number is "YES". The second number 5 has two divisors (1 and 5), and the third number 6 has four divisors (1, 2, 3, 6), hence the answer for them is "NO".

Solution (in PYTHON):

Solution:
from sys import stdin,stdout
read,write = stdin.readline,stdout.write
prime = [1]*1000001
n = int(raw_input())
 
def sq_root(x):
	root = int(x**0.5)-1
	if root*root == x:
		return root
	root += 1
	if root*root == x:
		return root
	root += 1
	if root*root == x:
		return root
	return -1
 
#crivo
prime[0] = prime[1] = 0
for i in xrange(2,1001):
	if prime[i] == 1:
		for j in xrange(i*i, 1000001, i):
			prime[j] = 0
 
numbers = map(int, read().split())
for i in numbers:
	root = sq_root(i)
	if root != -1 and prime[root]:
		write("YES\n")
	else:
		write("NO\n")