Problem: You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

* It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:


N


Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:


h n w

Examples

Input

2


Output

1 2 2


Input

3485


Output

872 1012974 1539173474040


Input

4664


Output

3498 3498 3498

Solution (in CPP):

Solution:
#include<bits/stdc++.h>
using namespace std;

using ll = int64_t;

signed main(){

  ll n;
  cin>>n;

  for(ll a=1;a<=3500;++a)for(ll b=1;b<=3500;++b){
    if(4*a*b-n*a-n*b==0)continue;
    ll c = n*a*b/(4*a*b-n*a-n*b);
    if(c<0)continue;
    if(4*a*b*c==n*(a*b+a*c+b*c)){
      cout<<a<<" "<<b<<" "<<c<<endl;
      return 0;
    }
  }

}