Problem: We know that prime numbers are positive integers that have exactly two distinct positive divisors. Similarly, we'll call a positive integer t Т-prime, if t has exactly three distinct positive divisors.

You are given an array of n positive integers. For each of them determine whether it is Т-prime or not.

Input

The first line contains a single positive integer, n (1 ≤ n ≤ 105), showing how many numbers are in the array. The next line contains n space-separated integers xi (1 ≤ xi ≤ 1012).

Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is advised to use the cin, cout streams or the %I64d specifier.

Output

Print n lines: the i-th line should contain "YES" (without the quotes), if number xi is Т-prime, and "NO" (without the quotes), if it isn't.

Examples

Input

3
4 5 6


Output

YES
NO
NO

Note

The given test has three numbers. The first number 4 has exactly three divisors — 1, 2 and 4, thus the answer for this number is "YES". The second number 5 has two divisors (1 and 5), and the third number 6 has four divisors (1, 2, 3, 6), hence the answer for them is "NO".

Solution (in PYTHON3):

Solution:
primo = [1]*1000001

def Raiz(x):
    raiz = int(x**0.5)-1
    
    if(raiz*raiz == x):
        return raiz
    raiz += 1
    if(raiz*raiz == x):
        return raiz
    raiz += 1
    if(raiz*raiz == x):
        return raiz
    return -1
        
primo[0] = 0
primo[1] = 0

for i in range(2,1001):
    if(primo[i] == 1):
        for j in range(i*i,1000001,i):
            primo[j] = 0

n = int(input())

entrada = input().split(' ')
numeros = [int(x) for x in entrada]

for i in numeros:
    raiz = Raiz(i)
    if(raiz != -1 and primo[raiz]):
        print('YES')
    else:
        print('NO')