Problem: Omkar has received a message from Anton saying "Your story for problem A is confusing. Just make a formal statement." Because of this, Omkar gives you an array a = [a_1, a_2, …, a_n] of n distinct integers. An array b = [b_1, b_2, …, b_k] is called nice if for any two distinct elements b_i, b_j of b, |b_i-b_j| appears in b at least once. In addition, all elements in b must be distinct. Can you add several (maybe, 0) integers to a to create a nice array b of size at most 300? If a is already nice, you don't have to add any elements.

For example, array [3, 6, 9] is nice, as |6-3|=|9-6| = 3, which appears in the array, and |9-3| = 6, which appears in the array, while array [4, 2, 0, 6, 9] is not nice, as |9-4| = 5 is not present in the array.

For integers x and y, |x-y| = x-y if x > y and |x-y| = y-x otherwise.

Input

Each test contains multiple test cases. The first line contains t (1 ≤ t ≤ 50), the number of test cases. Description of the test cases follows.

The first line of each test case contains a single integer n (2 ≤ n ≤ 100) — the length of the array a.

The second line of each test case contains n distinct integers a_1, a_2, ⋅⋅⋅, a_n (-100 ≤ a_i ≤ 100) — the elements of the array a.

Output

For each test case, output one line containing YES if Omkar can create a nice array b by adding elements to a and NO otherwise. The case of each letter does not matter, so yEs and nO will also be accepted.

If the first line is YES, output a second line containing a single integer k (n ≤ k ≤ 300). 

Then output one line containing k distinct integers b_1, b_2, ⋅⋅⋅, b_k (-10^9 ≤ b_i ≤ 10^9), the elements of the nice array b. b_1, b_2, ⋅⋅⋅, b_k can be in any order. For each a_i in a, a_i must appear at least once in b.

It can be proved that if Omkar can create such an array b, then he can also do so in a way that satisfies the above constraints.

If multiple solutions exist, you can print any. 

Example

Input


4
3
3 0 9
2
3 4
5
-7 3 13 -2 8
4
4 8 12 6


Output


yes
4
6 0 3 9
yEs
5
5 3 1 2 4
NO
Yes
6
8 12 6 2 4 10

Note

For the first case, you can add integers to a to receive the array b = [6, 0, 3, 9]. Note that |6-3| = |9-6| = |3-0| = 3 and 3 is in b, |6-0| = |9-3| = 6 and 6 is in b, and |9-0| = 9 is in b, so b is nice.

For the second case, you can add integers to a to receive the array b = [5, 3, 1, 2, 4]. We have that |2-1| = |3-2| = |4-3| = |5-4| = 1 is in b, |3-1| = |4-2| = |5-3| = 2 is in b, |4-1| = |5-2| = 3 is in b, and |5-1| = 4 is in b, so b is nice.

For the fourth case, you can add integers to a to receive the array b = [8, 12, 6, 2, 4, 10]. We have that |4-2| = |6-4| = |8-6| = |10-8| = |12-10| = 2 is in b, |6-2| = |8-4| = |10-6| = |12-8| = 4 is in b, |8-2| = |10-4| = |12-6| = 6 is in b, |10-2| = |12-4| = 8 is in b, and |12-2| = 10 is in b, so b is nice.

It can be proven that for all other test cases it is impossible to create a nice array b.

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.*;
 public class Main {
	public static void main(String[] args) throws Exception {
		FastIO io = new FastIO();
		int test=io.nextInt();
		while(test>0)
		{
		    int n=io.nextInt();
		    int arr[]=new int[n];
		    int f=0;
		    int max=Integer.MIN_VALUE;
		    HashSet<Integer> set=new HashSet<Integer>();
		    for(int i=0;i<n;i++){
		        arr[i]=io.nextInt();
		        if(arr[i]<0)f=1;
		        if(arr[i]>max)max=arr[i];
		        set.add(arr[i]);
		    }
		    if(f==1){
		        io.println("NO");
		        test--;
		        continue;
		    }
		    int c=0;
		    StringBuilder sb=new StringBuilder();
		    for(int i=0;i<=max;i++)
		    {
		        c++;
		        sb.append(i+" ");
		    }
		    io.println("YES");
		    io.println(c);
		    io.println(sb.toString());
		    test--;
		}
		io.close();
	}
	static int gcd(int a, int b)
    {
        // Everything divides 0
        if (a == 0)
          return b;
        if (b == 0)
          return a;
      
        // base case
        if (a == b)
            return a;
      
        // a is greater
        if (a > b)
            return gcd(a-b, b);
        return gcd(a, b-a);
    }
}
 
 class FastIO extends PrintWriter {
	private InputStream stream;
	private byte[] buf = new byte[1<<16];
	private int curChar, numChars;
 
	// standard input
	public FastIO() { this(System.in,System.out); }
	public FastIO(InputStream i, OutputStream o) {
		super(o);
		stream = i;
	}
	// file input
	public FastIO(String i, String o) throws IOException {
		super(new FileWriter(o));
		stream = new FileInputStream(i);
	}
 
	// throws InputMismatchException() if previously detected end of file
	private int nextByte() {
		if (numChars == -1) throw new InputMismatchException();
		if (curChar >= numChars) {
			curChar = 0;
			try {
				numChars = stream.read(buf);
			} catch (IOException e) {
				throw new InputMismatchException();
			}
			if (numChars == -1) return -1; // end of file
		}
		return buf[curChar++];
	}
 
	public String nextLine() {
		int c; do { c = nextByte(); } while (c <= '\n');
		StringBuilder res = new StringBuilder();
		do { res.appendCodePoint(c); c = nextByte(); } while (c > '\n');
		return res.toString();
	}
 
	public String next() {
		int c; do { c = nextByte(); } while (c <= ' ');
		StringBuilder res = new StringBuilder();
		do { res.appendCodePoint(c); c = nextByte(); } while (c > ' ');
		return res.toString();
	}
 
	public int nextInt() { 
		int c; do { c = nextByte(); } while (c <= ' ');
		int sgn = 1; if (c == '-') { sgn = -1; c = nextByte(); }
		int res = 0;
		do {
			if (c < '0' || c > '9')
				throw new InputMismatchException();
			res = 10*res+c-'0';
			c = nextByte();
		} while (c > ' ');
		return res * sgn;
	}
 
  public long nextLong() { 
		int c; do { c = nextByte(); } while (c <= ' ');
		long sgn = 1; if (c == '-') { sgn = -1; c = nextByte(); }
		long res = 0;
		do {
			if (c < '0' || c > '9')
				throw new InputMismatchException();
			res = 10*res+c-'0';
			c = nextByte();
		} while (c > ' ');
		return res * sgn;
	}
 
	public double nextDouble() { return Double.parseDouble(next()); }
}