Problem: We know that prime numbers are positive integers that have exactly two distinct positive divisors. Similarly, we'll call a positive integer t Т-prime, if t has exactly three distinct positive divisors.

You are given an array of n positive integers. For each of them determine whether it is Т-prime or not.

Input

The first line contains a single positive integer, n (1 ≤ n ≤ 105), showing how many numbers are in the array. The next line contains n space-separated integers xi (1 ≤ xi ≤ 1012).

Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is advised to use the cin, cout streams or the %I64d specifier.

Output

Print n lines: the i-th line should contain "YES" (without the quotes), if number xi is Т-prime, and "NO" (without the quotes), if it isn't.

Examples

Input

3
4 5 6


Output

YES
NO
NO

Note

The given test has three numbers. The first number 4 has exactly three divisors — 1, 2 and 4, thus the answer for this number is "YES". The second number 5 has two divisors (1 and 5), and the third number 6 has four divisors (1, 2, 3, 6), hence the answer for them is "NO".

Solution (in PYTHON3):

Solution:
import math

m = int(math.sqrt(10 ** 12))

isPrime = [False for i in range(m + 1)]
isPrime[0], isPrime[1] = True, True

for i in range(4, m + 1, 2):
    isPrime[i] = True

for i in range(3, int(math.sqrt(m + 1)), 2):
    if isPrime[i] == False:
        for j in range(i * i, m + 1, 2 * i):
            isPrime[j] = True

n = int(input())
tp = list(map(int, input().split(' ')))

for i in tp:
    sq = int(math.sqrt(i))
    if sq * sq == i and isPrime[sq] == False:
        print('YES')
    else:
        print('NO')