Problem: We know that prime numbers are positive integers that have exactly two distinct positive divisors. Similarly, we'll call a positive integer t Т-prime, if t has exactly three distinct positive divisors.

You are given an array of n positive integers. For each of them determine whether it is Т-prime or not.

Input

The first line contains a single positive integer, n (1 ≤ n ≤ 105), showing how many numbers are in the array. The next line contains n space-separated integers xi (1 ≤ xi ≤ 1012).

Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is advised to use the cin, cout streams or the %I64d specifier.

Output

Print n lines: the i-th line should contain "YES" (without the quotes), if number xi is Т-prime, and "NO" (without the quotes), if it isn't.

Examples

Input

3
4 5 6


Output

YES
NO
NO

Note

The given test has three numbers. The first number 4 has exactly three divisors — 1, 2 and 4, thus the answer for this number is "YES". The second number 5 has two divisors (1 and 5), and the third number 6 has four divisors (1, 2, 3, 6), hence the answer for them is "NO".

Solution (in PYTHON3):

Solution:
import math


def sieve(n):
    isPrime = [True]*(n+1)

    # isPrime[0] = False
    isPrime[1] = False
    i = 2
    while(i*i <= n):
        if isPrime[i] == True:
            for j in range(i*i, n + 1, i):
                isPrime[j] = False
        i += 1
    return isPrime

# pri = prime(1000000)

def main():
    n = int(input())
    l = list(map(int, input().split()))
    arr = sieve(1000000)
    for i in range(n):
        number = math.sqrt(l[i])
        if number.is_integer():
            if arr[int(number)]:
                print("YES")
            else:
                print("NO")
        else:
            print("NO")

main()