Problem: You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

* It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:


N


Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:


h n w

Examples

Input

2


Output

1 2 2


Input

3485


Output

872 1012974 1539173474040


Input

4664


Output

3498 3498 3498

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
#define ll long long

int main(void){
	cin.tie(0);
	ios::sync_with_stdio(false);
	ll N;
	ll a,b,c;
	cin >> N;
	for(a=1;a<=3500;a++){
		for(b=1;b<=3500;b++){
			ll x = (4*a*b - N*a - N*b);
			if(x>0 && N*a*b%x==0){
				c = (N*a*b)/x;
				cout << a <<" "<< b <<" "<< c << endl;
				return 0;
			}
			
		}
	}
}