Problem: Omkar has received a message from Anton saying "Your story for problem A is confusing. Just make a formal statement." Because of this, Omkar gives you an array a = [a_1, a_2, …, a_n] of n distinct integers. An array b = [b_1, b_2, …, b_k] is called nice if for any two distinct elements b_i, b_j of b, |b_i-b_j| appears in b at least once. In addition, all elements in b must be distinct. Can you add several (maybe, 0) integers to a to create a nice array b of size at most 300? If a is already nice, you don't have to add any elements.

For example, array [3, 6, 9] is nice, as |6-3|=|9-6| = 3, which appears in the array, and |9-3| = 6, which appears in the array, while array [4, 2, 0, 6, 9] is not nice, as |9-4| = 5 is not present in the array.

For integers x and y, |x-y| = x-y if x > y and |x-y| = y-x otherwise.

Input

Each test contains multiple test cases. The first line contains t (1 ≤ t ≤ 50), the number of test cases. Description of the test cases follows.

The first line of each test case contains a single integer n (2 ≤ n ≤ 100) — the length of the array a.

The second line of each test case contains n distinct integers a_1, a_2, ⋅⋅⋅, a_n (-100 ≤ a_i ≤ 100) — the elements of the array a.

Output

For each test case, output one line containing YES if Omkar can create a nice array b by adding elements to a and NO otherwise. The case of each letter does not matter, so yEs and nO will also be accepted.

If the first line is YES, output a second line containing a single integer k (n ≤ k ≤ 300). 

Then output one line containing k distinct integers b_1, b_2, ⋅⋅⋅, b_k (-10^9 ≤ b_i ≤ 10^9), the elements of the nice array b. b_1, b_2, ⋅⋅⋅, b_k can be in any order. For each a_i in a, a_i must appear at least once in b.

It can be proved that if Omkar can create such an array b, then he can also do so in a way that satisfies the above constraints.

If multiple solutions exist, you can print any. 

Example

Input


4
3
3 0 9
2
3 4
5
-7 3 13 -2 8
4
4 8 12 6


Output


yes
4
6 0 3 9
yEs
5
5 3 1 2 4
NO
Yes
6
8 12 6 2 4 10

Note

For the first case, you can add integers to a to receive the array b = [6, 0, 3, 9]. Note that |6-3| = |9-6| = |3-0| = 3 and 3 is in b, |6-0| = |9-3| = 6 and 6 is in b, and |9-0| = 9 is in b, so b is nice.

For the second case, you can add integers to a to receive the array b = [5, 3, 1, 2, 4]. We have that |2-1| = |3-2| = |4-3| = |5-4| = 1 is in b, |3-1| = |4-2| = |5-3| = 2 is in b, |4-1| = |5-2| = 3 is in b, and |5-1| = 4 is in b, so b is nice.

For the fourth case, you can add integers to a to receive the array b = [8, 12, 6, 2, 4, 10]. We have that |4-2| = |6-4| = |8-6| = |10-8| = |12-10| = 2 is in b, |6-2| = |8-4| = |10-6| = |12-8| = 4 is in b, |8-2| = |10-4| = |12-6| = 6 is in b, |10-2| = |12-4| = 8 is in b, and |12-2| = 10 is in b, so b is nice.

It can be proven that for all other test cases it is impossible to create a nice array b.

Solution (in JAVA):

Solution:
// Author : RegalBeast

import java.io.*;
import java.util.*;
import java.util.concurrent.*;

public class Main implements Runnable {
  static Input in = new Input();
  static PrintWriter out = Output();
  
  public static void main(String[] args) {
    new Thread(null, new Main(), String.join(
                                  "All that is gold does not glitter,",
                                  "Not all those who wander are lost;",
                                  "The old that is strong does not wither,",
                                  "Deep roots are not reached by the frost.",
                                  
                                  "From the ashes a fire shall be woken,",
                                  "A light from the shadows shall spring;",
                                  "Renewed shall be blade that was broken,",
                                  "The crownless again shall be king."
                                ), 1<<25).start();
  }

  public void run() {
    int tests = in.nextInt();
    for (int t = 0; t < tests; t++) {
      int n = in.nextInt();

      int[] arr = new int[n];
      for (int i = 0; i < n; i++) {
        arr[i] = in.nextInt();
      }

      List<Integer> goodList = getGoodListFast(arr);
      if (goodList == null) {
        out.println("No");
      } else {
        out.println("Yes");
        out.println(goodList.size());

        for (var num : goodList) {
          out.print(num + " ");
        }
        out.println();
      }
    }
    in.close();
    out.close();
  }

  static List<Integer> getGoodListFast(int[] arr) {
    for (var num : arr) {
      if (num < 0) {
        return null;
      }
    }
    
    List<Integer> goodList = new ArrayList<Integer>(101);
    for (int i = 0; i <= 100; i++) {
      goodList.add(i);
    }

    return goodList;
  }

  static List<Integer> getAltGoodList(int[] arr) {
    elements = new HashSet<Integer>();
    List<Integer> list = new ArrayList<Integer>();
    for (var num : arr) {
      if (num < 0) {
        return null;
      }

      list.add(num);
      elements.add(num);
    }

    int max = arr[0];
    int min = arr[0];
    int g = arr[0];
    for (var num : arr) {
      g = gcd(g, num);
      min = Math.min(min, num);
      max = Math.max(max, num);
    }

    for (int val = g; val < max; val += g) {
      if (!elements.contains(val)) {
        list.add(val);
      }
    }
    return list;
  }

  static int gcd(int num1, int num2) {
    if (num1 == 0) {
      return num2;
    }
    return gcd(num2 % num1, num1);
  }


  static Set<Integer> elements;
  static List<Integer> getGoodList(int[] arr) {
    elements = new HashSet<Integer>();
    List<Integer> list = new ArrayList<Integer>();
    for (var num : arr) {
      list.add(num);
      elements.add(num);
    }

    return getGoodList(0, list);
  }

  static List<Integer> getGoodList(int pos, List<Integer> list) {
    if (pos > 300) {
      return null;
    }
    if (pos == list.size()) {
      return list;
    }

    for (int i = 0; i < pos; i++) {
      int diff = Math.abs(list.get(pos) - list.get(i));
      if (!elements.contains(diff)) {
        elements.add(diff);
        list.add(diff);
      }
    }

    return getGoodList(pos+1, list);
  }

  static PrintWriter Output() {
    return new PrintWriter(new BufferedWriter(new OutputStreamWriter(System.out)));
  }
  
  static PrintWriter Output(String fileName) {
    PrintWriter pw = null;
    try {
      pw = new PrintWriter(new BufferedWriter(new FileWriter(fileName)));
    } catch (IOException ex) {
      ex.printStackTrace();
    }
    return pw;
  }
}

class Input {
  BufferedReader br;
  StringTokenizer st;
  public Input() {
    br = new BufferedReader(new InputStreamReader(System.in));
  }

  public Input(String fileName) {
    try {
      br = new BufferedReader(new FileReader(fileName));
    } catch (IOException ex) {
      ex.printStackTrace();
    }
  }

  public String next() {
    while (st == null || !st.hasMoreElements()) {
      try {
        st = new StringTokenizer(br.readLine());
      } catch (IOException ex) {
        ex.printStackTrace();
      }
    }
    return st.nextToken();
  }

  public int nextInt() {
    return Integer.parseInt(next());
  }

  public long nextLong() {
    return Long.parseLong(next());
  }

  public Float nextFloat() {
    return Float.parseFloat(next());
  }

  public Double nextDouble() {
    return Double.parseDouble(next());
  }

  public String nextLine() {
    if (st.hasMoreElements()) {
      StringBuilder sb = new StringBuilder();
      while (st.hasMoreElements()) {
        sb.append(next());
      }
      return sb.toString();
    }

    String str = null;
    try {
      str = br.readLine();
    } catch (IOException ex) {
      ex.printStackTrace();
    }
    return str;
  }

  public void close() {
    try {
      br.close();
    } catch (IOException ex) {
      ex.printStackTrace();
    }
  }
}