Problem: We know that prime numbers are positive integers that have exactly two distinct positive divisors. Similarly, we'll call a positive integer t Т-prime, if t has exactly three distinct positive divisors.

You are given an array of n positive integers. For each of them determine whether it is Т-prime or not.

Input

The first line contains a single positive integer, n (1 ≤ n ≤ 105), showing how many numbers are in the array. The next line contains n space-separated integers xi (1 ≤ xi ≤ 1012).

Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is advised to use the cin, cout streams or the %I64d specifier.

Output

Print n lines: the i-th line should contain "YES" (without the quotes), if number xi is Т-prime, and "NO" (without the quotes), if it isn't.

Examples

Input

3
4 5 6


Output

YES
NO
NO

Note

The given test has three numbers. The first number 4 has exactly three divisors — 1, 2 and 4, thus the answer for this number is "YES". The second number 5 has two divisors (1 and 5), and the third number 6 has four divisors (1, 2, 3, 6), hence the answer for them is "NO".

Solution (in PYTHON3):

Solution:
# -*- coding: utf-8 -*-
"""
Created on Thu Oct 29 21:07:28 2020

@author: Morris
"""

def xxs(n):
    isprimes=[True]*(n+1)
    isprimes[1]=0
    primes=[]
    for i in range(2,n):
        if isprimes[i]==1:
            primes.append(i)
        for j in primes:
            if j*i>n :
                break
            isprimes[i*j]=0
            if i%j==0:
                break
    return isprimes
n=int(input())
l=[int(x) for x in input().split()]
ln=xxs(1000000)

 
for i in l:
    sq=i**0.5
    if int(sq)*int(sq)!=i:
        print("NO")
    elif ln[int(i**0.5)]==1:
        print("YES")
    else:
        print("NO")