Problem: We know that prime numbers are positive integers that have exactly two distinct positive divisors. Similarly, we'll call a positive integer t Т-prime, if t has exactly three distinct positive divisors.

You are given an array of n positive integers. For each of them determine whether it is Т-prime or not.

Input

The first line contains a single positive integer, n (1 ≤ n ≤ 105), showing how many numbers are in the array. The next line contains n space-separated integers xi (1 ≤ xi ≤ 1012).

Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is advised to use the cin, cout streams or the %I64d specifier.

Output

Print n lines: the i-th line should contain "YES" (without the quotes), if number xi is Т-prime, and "NO" (without the quotes), if it isn't.

Examples

Input

3
4 5 6


Output

YES
NO
NO

Note

The given test has three numbers. The first number 4 has exactly three divisors — 1, 2 and 4, thus the answer for this number is "YES". The second number 5 has two divisors (1 and 5), and the third number 6 has four divisors (1, 2, 3, 6), hence the answer for them is "NO".

Solution (in PYTHON3):

Solution:
import math
def SieveOfEratosthenes(n):
    s = set()
    prime = [ True for i in range(n+1)]
    p = 2
    while(p * p <= n):
        if (prime[p] == True):
            for i in range(p * p, n+1, p):
                prime[i] =False
        p+=1
    for p in range(2, n):
        if (prime[p]):
            s.add(p)
    return s

nu = int(input())
l = list(map(int,input().split()))
S = SieveOfEratosthenes(10**6+1)
for n in l:
    x= int(math.sqrt(n))
    if(n==1):
        print("NO")
    elif(x*x !=n ):
        print("NO")
    elif(x in S):
        print("YES")
    else:
        print("NO")