Problem: Today Pari and Arya are playing a game called Remainders.

Pari chooses two positive integer x and k, and tells Arya k but not x. Arya have to find the value <image>. There are n ancient numbers c1, c2, ..., cn and Pari has to tell Arya <image> if Arya wants. Given k and the ancient values, tell us if Arya has a winning strategy independent of value of x or not. Formally, is it true that Arya can understand the value <image> for any positive integer x?

Note, that <image> means the remainder of x after dividing it by y.

Input

The first line of the input contains two integers n and k (1 ≤ n, k ≤ 1 000 000) — the number of ancient integers and value k that is chosen by Pari.

The second line contains n integers c1, c2, ..., cn (1 ≤ ci ≤ 1 000 000).

Output

Print "Yes" (without quotes) if Arya has a winning strategy independent of value of x, or "No" (without quotes) otherwise.

Examples

Input

4 5
2 3 5 12


Output

Yes


Input

2 7
2 3


Output

No

Note

In the first sample, Arya can understand <image> because 5 is one of the ancient numbers.

In the second sample, Arya can't be sure what <image> is. For example 1 and 7 have the same remainders after dividing by 2 and 3, but they differ in remainders after dividing by 7.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
long long gcd(long long a, long long b) {
  if (a < b) swap(a, b);
  return (b == 0 ? a : gcd(b, a % b));
}
long long c[1000002];
bool parzchi[1000002], mark[102];
vector<long long> v;
int main() {
  for (long long i = 2; i <= 1000000; i++)
    if (!parzchi[i])
      for (long long j = 2 * i; j <= 1000000; j += i) parzchi[j] = true;
  long long n, k;
  scanf("%lld%lld", &n, &k);
  for (long long i = 2; i <= k; i++) {
    if (parzchi[i] == false && k % i == 0) {
      long long qan = i;
      long long l = k;
      while (l % qan == 0) {
        qan *= i;
      }
      v.push_back(qan / i);
    }
  }
  for (long long i = 0; i < n; i++) {
    scanf("%lld", c + i);
    for (long long j = 0; j < v.size(); j++)
      if (c[i] % v[j] == 0) mark[j] = true;
  }
  for (long long i = 0; i < v.size(); i++)
    if (!mark[i]) {
      cout << "No" << endl;
      return 0;
    }
  cout << "Yes" << endl;
  return 0;
}