Problem: You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

* It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:


N


Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:


h n w

Examples

Input

2


Output

1 2 2


Input

3485


Output

872 1012974 1539173474040


Input

4664


Output

3498 3498 3498

Solution (in CPP):

Solution:
#include<bits/stdc++.h>
#define int long long
using namespace std;
signed main(){
  int N;
  cin>>N;
  for(int a=1;a<=3500;a++)
    for(int b=1;b<=3500;b++)
      if(4*a*b-a*N-b*N>0 && N*a*b%(4*a*b-a*N-b*N)==0){
        cout<<a<<' '<<b<<' '<<N*a*b/(4*a*b-a*N-b*N)<<endl;
        return 0;
      }
}