Problem: You are given an array s consisting of n integers.

You have to find any array t of length k such that you can cut out maximum number of copies of array t from array s.

Cutting out the copy of t means that for each element t_i of array t you have to find t_i in s and remove it from s. If for some t_i you cannot find such element in s, then you cannot cut out one more copy of t. The both arrays can contain duplicate elements.

For example, if s = [1, 2, 3, 2, 4, 3, 1] and k = 3 then one of the possible answers is t = [1, 2, 3]. This array t can be cut out 2 times. 

  * To cut out the first copy of t you can use the elements [1, \underline{2}, 3, 2, 4, \underline{3}, \underline{1}] (use the highlighted elements). After cutting out the first copy of t the array s can look like [1, 3, 2, 4]. 
  * To cut out the second copy of t you can use the elements [\underline{1}, \underline{3}, \underline{2}, 4]. After cutting out the second copy of t the array s will be [4]. 



Your task is to find such array t that you can cut out the copy of t from s maximum number of times. If there are multiple answers, you may choose any of them.

Input

The first line of the input contains two integers n and k (1 ≤ k ≤ n ≤ 2 ⋅ 10^5) — the number of elements in s and the desired number of elements in t, respectively.

The second line of the input contains exactly n integers s_1, s_2, ..., s_n (1 ≤ s_i ≤ 2 ⋅ 10^5).

Output

Print k integers — the elements of array t such that you can cut out maximum possible number of copies of this array from s. If there are multiple answers, print any of them. The required array t can contain duplicate elements. All the elements of t (t_1, t_2, ..., t_k) should satisfy the following condition: 1 ≤ t_i ≤ 2 ⋅ 10^5.

Examples

Input


7 3
1 2 3 2 4 3 1


Output


1 2 3 


Input


10 4
1 3 1 3 10 3 7 7 12 3


Output


7 3 1 3


Input


15 2
1 2 1 1 1 2 1 1 2 1 2 1 1 1 1


Output


1 1 

Note

The first example is described in the problem statement.

In the second example the only answer is [7, 3, 1, 3] and any its permutations. It can be shown that you cannot choose any other array such that the maximum number of copies you can cut out would be equal to 2.

In the third example the array t can be cut out 5 times.

Solution (in JAVA):

Solution:
import java.io.*;
import java.math.*;
import java.util.*;

/*
   author : Multi-Thread
*/
public class D {
	// public class Main {

	// static int INF = 998244353;
	static int INF = (int) 1e9 + 7;
	static int MAX = Integer.MAX_VALUE;
	static int MIN = Integer.MIN_VALUE;

	public static void main(String[] args) {
		// int test = fs.nextInt();
		int test = 1;

		for (int cases = 0; cases < test; cases++) {

			solve();
			// System.out.print(solve() + "\n");

		}
	}

	static String solve() {
		int n = fs.nextInt(), k = fs.nextInt();
		HashMap<Integer, Integer> hm = new HashMap<Integer, Integer>();
		for (int i = 0; i < n; i++) {
			int x = fs.nextInt();
			hm.put(x, hm.getOrDefault(x, 0) + 1);
		}
		Pair ar[] = new Pair[hm.size()];
		int ii = 0;
		for (Integer z : hm.keySet()) {
			ar[ii] = new Pair(z, hm.get(z));
			++ii;
		}
		fn = new int[k];
		Arrays.sort(ar, (a, b) -> a.second - b.second);
		int start = 1, end = n;
		int curr = 0;
		while (start <= end) {
			int mid = (start + end) / 2;
			int gc = get(ar, mid, k);
			// System.out.println("For mid " + mid + " " + gc);
			if (gc > curr) {
				curr = gc;
				start = mid + 1;
			} else {
				end = mid - 1;
			}
		}
		// System.out.println(curr);
		for (int i = 0; i < k; i++)
			out.print(fn[i] + " ");
		out.flush();
		return "";
	}

	static int[] fn;

	static int get(Pair[] ar, int mid, int k) {
		int n = ar.length;
		Pair cp[] = new Pair[k];
		int z = k - 1;
		for (int i = n - 1; z >= 0; i--, z--) {
//			System.out.println(i + " " + z);
			if (i >= 0)
				cp[z] = new Pair(ar[i].first, ar[i].second);
			else
				cp[z] = new Pair(0, 0);
		}
		// System.out.println("For mid " + mid);
		// System.out.println(Arrays.toString(cp));
		int start = 0, end = cp.length - 1;
		while (start < end) {
			int curr = cp[start].second;
			if (curr >= mid) {
				++start;
			} else {
				int left = cp[end].second - mid;
				if (left >= mid) {
					cp[start] = new Pair(cp[end].first, mid);
					cp[end] = new Pair(cp[end].first, (left - mid) + mid);
					// System.out.println(Arrays.toString(cp));
					++start;
				} else {
					--end;
				}
			}
		}
		// System.out.println(Arrays.toString(cp));
		boolean rs = true;
		for (int i = 0; i < k; i++) {
			int zz = cp[i].second;
			if (zz < mid) {
				rs = false;
				break;
			}
		}
		if (rs) {
			for (int i = 0; i < k; i++) {
				fn[i] = cp[i].first;
			}
		}
		return rs ? mid : Integer.MIN_VALUE;
	}

	static int _min(int... ar) {
		intSort(ar, true);
		return ar[ar.length - 1];
	}

	static int _max(int... ar) {
		intSort(ar, true);
		return ar[ar.length - 1];
	}

	static void intSort(int[] a, boolean reverse) {
		ArrayList<Integer> al = new ArrayList<Integer>();
		for (int i : a)
			al.add(i);
		Collections.sort(al);
		if (reverse) {
			for (int i = 0; i < a.length; i++)
				a[i] = al.get(a.length - i - 1);
		} else {
			for (int i = 0; i < a.length; i++)
				a[i] = al.get(i);
		}
	}

	static void longSort(long[] a, boolean reverse) {
		ArrayList<Long> al = new ArrayList<>();
		for (long i : a)
			al.add(i);
		Collections.sort(al);
		if (reverse) {
			for (int i = 0; i < a.length; i++)
				a[i] = al.get(a.length - i - 1);
		} else {
			for (int i = 0; i < a.length; i++)
				a[i] = al.get(i);
		}
	}

	public static int[] radixSort(int[] f) {
		return radixSort(f, f.length);
	}

	public static int[] radixSort(int[] f, int n) {
		int[] to = new int[n];
		{
			int[] b = new int[65537];
			for (int i = 0; i < n; i++)
				b[1 + (f[i] & 0xffff)]++;
			for (int i = 1; i <= 65536; i++)
				b[i] += b[i - 1];
			for (int i = 0; i < n; i++)
				to[b[f[i] & 0xffff]++] = f[i];
			int[] d = f;
			f = to;
			to = d;
		}
		{
			int[] b = new int[65537];
			for (int i = 0; i < n; i++)
				b[1 + (f[i] >>> 16)]++;
			for (int i = 1; i <= 65536; i++)
				b[i] += b[i - 1];
			for (int i = 0; i < n; i++)
				to[b[f[i] >>> 16]++] = f[i];
			int[] d = f;
			f = to;
			to = d;
		}
		return f;
	}

	static class Pair {
		int first, second;

		public Pair(int first, int second) {
			this.first = first;
			this.second = second;
		}

		public String toString() {
			return "[" + first + "," + second + "]";
		}
	}

	static class LongPair {
		long first;
		long second;

		LongPair(long a, long b) {
			this.first = a;
			this.second = b;
		}

		public String toString() {
			return "[" + first + "," + second + "]";
		}
	}

	static class FastReader {
		BufferedReader br;
		StringTokenizer st;

		public FastReader() {
			br = new BufferedReader(new InputStreamReader(System.in));
		}

		String next() {
			while (st == null || !st.hasMoreElements()) {
				try {
					st = new StringTokenizer(br.readLine());
				} catch (IOException e) {
					e.printStackTrace();
				}
			}
			return st.nextToken();
		}

		int nextInt() {
			return Integer.parseInt(next());
		}

		long nextLong() {
			return Long.parseLong(next());
		}

		double nextDouble() {
			return Double.parseDouble(next());
		}

		String nextLine() {
			String str = "";
			try {
				str = br.readLine();
			} catch (IOException e) {
				e.printStackTrace();
			}
			return str;
		}
	}

	static class OutputWriter {
		private final PrintWriter writer;

		public OutputWriter(OutputStream outputStream) {
			writer = new PrintWriter(new BufferedWriter(new OutputStreamWriter(outputStream)));
		}

		public OutputWriter(Writer writer) {
			this.writer = new PrintWriter(writer);
		}

		public void print(Object... objects) {
			for (int i = 0; i < objects.length; i++) {
				if (i != 0)
					writer.print(' ');
				writer.print(objects[i]);
			}
		}

		public void println() {
			writer.print("\n");
		}

		public void printLine(Object... objects) {
			print(objects);
			writer.println();
		}

		public void close() {
			writer.close();
		}

		public void flush() {
			writer.flush();
		}

	}

	private static final FastReader fs = new FastReader();
	private static final OutputWriter out = new OutputWriter(System.out);
}