Problem: We know that prime numbers are positive integers that have exactly two distinct positive divisors. Similarly, we'll call a positive integer t Т-prime, if t has exactly three distinct positive divisors.

You are given an array of n positive integers. For each of them determine whether it is Т-prime or not.

Input

The first line contains a single positive integer, n (1 ≤ n ≤ 105), showing how many numbers are in the array. The next line contains n space-separated integers xi (1 ≤ xi ≤ 1012).

Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is advised to use the cin, cout streams or the %I64d specifier.

Output

Print n lines: the i-th line should contain "YES" (without the quotes), if number xi is Т-prime, and "NO" (without the quotes), if it isn't.

Examples

Input

3
4 5 6


Output

YES
NO
NO

Note

The given test has three numbers. The first number 4 has exactly three divisors — 1, 2 and 4, thus the answer for this number is "YES". The second number 5 has two divisors (1 and 5), and the third number 6 has four divisors (1, 2, 3, 6), hence the answer for them is "NO".

Solution (in PYTHON):

Solution:
import math
primos = [True] * (int(math.sqrt(10**12))+1)
primos[0] = False
primos[1] = False
tam =  int(math.sqrt(10**12)) + 1


for i in xrange(2,tam):
	if(primos[i]):
		for j in xrange(i+i,tam,i):
			
			primos[j] = False


n = int(raw_input())
a = map(int,raw_input().split())

for i in a:
	
	raiz = math.sqrt(i)

	if i == 1:
		
		print "NO"
	
	elif raiz == int(raiz):
		
		if primos[int(raiz)]:
			
			print "YES"
		
		else:
			
			print "NO"
	
	else:
		
		print "NO"