Problem: A championship is held in Berland, in which n players participate. The player with the number i has a_i (a_i ≥ 1) tokens.

The championship consists of n-1 games, which are played according to the following rules:

  * in each game, two random players with non-zero tokens are selected; 
  * the player with more tokens is considered the winner of the game (in case of a tie, the winner is chosen randomly); 
  * the winning player takes all of the loser's tokens; 



The last player with non-zero tokens is the winner of the championship.

All random decisions that are made during the championship are made equally probable and independently.

For example, if n=4, a = [1, 2, 4, 3], then one of the options for the game (there could be other options) is: 

  * during the first game, the first and fourth players were selected. The fourth player has more tokens, so he takes the first player's tokens. Now a = [0, 2, 4, 4]; 
  * during the second game, the fourth and third players were selected. They have the same number of tokens, but in a random way, the third player is the winner. Now a = [0, 2, 8, 0]; 
  * during the third game, the second and third players were selected. The third player has more tokens, so he takes the second player's tokens. Now a = [0, 0, 10, 0]; 
  * the third player is declared the winner of the championship. 



Championship winners will receive personalized prizes. Therefore, the judges want to know in advance which players have a chance of winning, i.e have a non-zero probability of winning the championship. You have been asked to find all such players. 

Input

The first line contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases. Then t test cases follow.

The first line of each test case consists of one positive integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the number of players in the championship.

The second line of each test case contains n positive integers a_1, a_2, …, a_n (1 ≤ a_i ≤ 10^9) — the number of tokens the players have.

It is guaranteed that the sum of n over all test cases does not exceed 2 ⋅ 10^5. 

Output

For each test case, print the number of players who have a nonzero probability of winning the championship. On the next line print the numbers of these players in increasing order. Players are numbered starting from one in the order in which they appear in the input. 

Example

Input


2
4
1 2 4 3
5
1 1 1 1 1


Output


3
2 3 4 
5
1 2 3 4 5 

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.*;
public class Main {
    InputReader in;
    Helper_class h;
    final long mod=1000000007;
    public static void main(String[] args) throws java.lang.Exception {
        new Main().run();
    }
    void run() throws Exception {
        in=new InputReader(System.in);
        StringBuilder sb = new  StringBuilder(); 
        h = new Helper_class();       
        int t=h.i();
        for(int i=1;i<=t;i++)
            solve(sb);
        System.out.print(sb);
    }
    void solve(StringBuilder sb) {
        int i, j;
        int n=h.i();
        long a[]=new long[n];
        int b[]=new int[n];
        ArrayList<Pair> ar = new ArrayList<>();
        for(i=0;i<n;i++) {
            a[i]=h.l();
            b[i]=(int)a[i];
            ar.add(new Pair(b[i], i+1));
        }
        /*for(Pair p : ar)
            System.out.print(p.x+" "+p.y+"   ");
        System.out.println();*/
        h.sorter(a);
        h.sorter(b);
        for(i=1;i<n;i++)
            a[i]+=a[i-1];
        HashMap<Integer, Integer> map = new HashMap<>();
        for(i=n-2;i>=0;i--) {
            if(a[i]>=b[i+1])
                map.put(b[i], 1);
            else
                break;
        }
        map.put(b[n-1], 1);
        //System.out.println(map);
        ArrayList<Integer> list = new ArrayList<>();
        for(i=0;i<n;i++) {
            if(map.containsKey(ar.get(i).x))
                list.add(ar.get(i).y);
        }
        sb.append(list.size()+"\n");
        for(i=0;i<list.size();i++)
            sb.append(list.get(i)+" ");
        sb.append("\n");
    }
    class Helper_class{
        long gcd(long a, long b){return (b==0)?a:gcd(b,a%b);}
        int gcd(int a, int b){return (b==0)?a:gcd(b,a%b);}
        String s(){return in.next();}
        int i(){return Integer.parseInt(in.next());}
        long l(){return Long.parseLong(in.next());}
        double d(){return Double.parseDouble(in.next());}
        long square(int x) {return ((long)x * (long)x);}
        long mul(long x, long y) {long ans = x*y;return (ans>=mod ? ans%mod : ans);}
        long power(long x, long y, long p) {  
            long res = 1;       
            x = x % p;  
            if (x == 0) return 0;   
            while (y > 0) {
                if((y & 1)==1) 
                    res = (res * x) % p;  
                y = y >> 1;  
                x = (x * x) % p;  
            } 
            return res%p; 
        } 
        void sorter(int a[]) {
            ArrayList<Integer> ar=new ArrayList<>();
            for(int i=0;i<a.length;i++)
                ar.add(a[i]);
            Collections.sort(ar);
            for(int i=0;i<ar.size();i++)
                a[i]=ar.get(i);
        }
        void sorter(long a[]) {
            ArrayList<Long> ar=new ArrayList<>();
            for(int i=0;i<a.length;i++)
                ar.add(a[i]);
            Collections.sort(ar);
            for(int i=0;i<ar.size();i++)
                a[i]=ar.get(i);
        }
        int lower(int a[], int k) {
            int l=0, r=a.length-1, ans=-1;
            while(l<=r) {
                int mid = (r+l)/2;
                if(a[mid]>k)
                    r=mid-1;
                else {
                    ans=mid;
                    l=mid+1;
                }
            }
            if(ans!=-1)
                ans=a[ans];
            return ans;
        }
        int upper(int a[], int k) {
            int l=0, r=a.length-1, ans=-1;
            while(l<=r) {
                int mid = (r+l)/2;
                if(a[mid]<k)
                    l=mid+1;
                else {
                    ans=mid;
                    r=mid-1;
                }
            }
            if(ans!=-1)
                ans=a[ans];
            return ans;
        }
        void reverse(int a[]) {
            for(int i=0;i<a.length/2;i++) {
                int x=a[i];
                a[i]=a[a.length-1-i];
                a[a.length-1-i]=x;
            }
        }
        //String.format("%.kf",x)
    }
    class Pair { 
        int x; 
        int y; 
        public Pair(int x, int y) 
        {
            this.x = x; 
            this.y = y; 
        } 
    }
    class InputReader {
        private InputStream stream;
        private byte[] buf = new byte[1024];
        private int curChar;
        private int numChars;
        public InputReader(InputStream stream) {
            this.stream = stream;
        }
        public int read() {
            if (numChars == -1)
                throw new UnknownError();
            if (curChar >= numChars) {
                curChar = 0;
                try {
                    numChars = stream.read(buf);
                } catch (IOException e) {
                    throw new UnknownError();
                }
                if (numChars <= 0)
                    return -1;
            }
            return buf[curChar++];
        }
        public int peek() {
            if (numChars == -1)
                return -1;
            if (curChar >= numChars) {
                curChar = 0;
                try {
                    numChars = stream.read(buf);
                } catch (IOException e) {
                    return -1;
                }
                if (numChars <= 0)
                    return -1;
            }
            return buf[curChar];
        }
        public void skip(int x) {
            while (x-->0)
                read();
        }
        public int nextInt() {
            return Integer.parseInt(next());
        }
        public long nextLong() {
            return Long.parseLong(next());
        }
        public String nextString() {
            return next();
        }
        public String next() {
            int c = read();
            while (isSpaceChar(c))
                c = read();
            StringBuffer res = new StringBuffer();
            do {
                res.appendCodePoint(c);
                c = read();
            } while (!isSpaceChar(c));
 
            return res.toString();
        }
        public String nextLine() {
            StringBuffer buf = new StringBuffer();
            int c = read();
            while (c != '\n' && c != -1) {
                if (c != '\r')
                    buf.appendCodePoint(c);
                c = read();
            }
            return buf.toString();
        }
        public double nextDouble() {
            int c = read();
            while (isSpaceChar(c))
                c = read();
            int sgn = 1;
            if (c == '-') {
                sgn = -1;
                c = read();
            }
            double res = 0;
            while (!isSpaceChar(c) && c != '.') {
                if (c == 'e' || c == 'E')
                    return res * Math.pow(10, nextInt());
                if (c < '0' || c > '9')
                    throw new InputMismatchException();
                res *= 10;
                res += c - '0';
                c = read();
            }
            if (c == '.') {
                c = read();
                double m = 1;
                while (!isSpaceChar(c)) {
                    if (c == 'e' || c == 'E')
                        return res * Math.pow(10, nextInt());
                    if (c < '0' || c > '9')
                        throw new InputMismatchException();
                    m /= 10;
                    res += (c - '0') * m;
                    c = read();
                }
            }
            return res * sgn;
        }
        public boolean hasNext() {
            int value;
            while (isSpaceChar(value = peek()) && value != -1)
                read();
            return value != -1;
        }
        private boolean isSpaceChar(int c) {
            return c == ' ' || c == '\n' || c == '\r' || c == '\t' || c == -1;
        }
    }
}