Problem: You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

* It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:


N


Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:


h n w

Examples

Input

2


Output

1 2 2


Input

3485


Output

872 1012974 1539173474040


Input

4664


Output

3498 3498 3498

Solution (in CPP):

Solution:
#include <iostream>
using namespace std;

int main(){
  double n;
  cin >> n;
  for(double i=1.0; i<=3500; i+=1.0){
    for(double j=1.0; j<=3500; j+=1.0){
  	  double w = (n*i*j)/(4*i*j-n*i-n*j);
      if(w == (int)w && w > 0){
        cout << (int)i << " " << (int)j << " " << (int)w;
        return 0;
      }
    }
  }
}