Problem: After you had helped George and Alex to move in the dorm, they went to help their friend Fedor play a new computer game «Call of Soldiers 3».

The game has (m + 1) players and n types of soldiers in total. Players «Call of Soldiers 3» are numbered form 1 to (m + 1). Types of soldiers are numbered from 0 to n - 1. Each player has an army. Army of the i-th player can be described by non-negative integer xi. Consider binary representation of xi: if the j-th bit of number xi equal to one, then the army of the i-th player has soldiers of the j-th type. 

Fedor is the (m + 1)-th player of the game. He assume that two players can become friends if their armies differ in at most k types of soldiers (in other words, binary representations of the corresponding numbers differ in at most k bits). Help Fedor and count how many players can become his friends.

Input

The first line contains three integers n, m, k (1 ≤ k ≤ n ≤ 20; 1 ≤ m ≤ 1000).

The i-th of the next (m + 1) lines contains a single integer xi (1 ≤ xi ≤ 2n - 1), that describes the i-th player's army. We remind you that Fedor is the (m + 1)-th player.

Output

Print a single integer — the number of Fedor's potential friends.

Examples

Input

7 3 1
8
5
111
17


Output

0


Input

3 3 3
1
2
3
4


Output

3

Solution (in PYTHON3):

Solution:
#"from dust i have come, dust i will be"

import sys

def toBinary(n,size):
    s=[]
    while 1:
        r=n%2
        n=n//2
        s.append(r)

        if n==0:
            break


    while len(s)<size:
        s.append(0)

    s.reverse()
    return s


n,m,k=map(int,input().split())
a=[0]*(m+1)

for i in range(m+1):
    a[i]=int(input())

fedor=[0]*n
fedor=toBinary(a[m],n)

cnt=0
for i in range(m):
    x=toBinary(a[i],n)

    sum=0
    for j in range(n):
        if fedor[j]!=x[j]:
            sum+=1

    if sum<=k:
        cnt+=1

print(cnt)