Problem: We know that prime numbers are positive integers that have exactly two distinct positive divisors. Similarly, we'll call a positive integer t Т-prime, if t has exactly three distinct positive divisors.

You are given an array of n positive integers. For each of them determine whether it is Т-prime or not.

Input

The first line contains a single positive integer, n (1 ≤ n ≤ 105), showing how many numbers are in the array. The next line contains n space-separated integers xi (1 ≤ xi ≤ 1012).

Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is advised to use the cin, cout streams or the %I64d specifier.

Output

Print n lines: the i-th line should contain "YES" (without the quotes), if number xi is Т-prime, and "NO" (without the quotes), if it isn't.

Examples

Input

3
4 5 6


Output

YES
NO
NO

Note

The given test has three numbers. The first number 4 has exactly three divisors — 1, 2 and 4, thus the answer for this number is "YES". The second number 5 has two divisors (1 and 5), and the third number 6 has four divisors (1, 2, 3, 6), hence the answer for them is "NO".

Solution (in PYTHON3):

Solution:
from math import sqrt 
def isPrime(n): 
    if (n <= 1): 
        return False
    if (n <= 3): 
        return True
    if (n % 2 == 0 or n % 3 == 0): 
        return False
    k= int(sqrt(n))+1
    for i in range(5,k,6): 
        if (n % i == 0 or n % (i + 2) == 0): 
            return False
    return True
def isThreeDisctFactors(n): 
    sq = int(sqrt(n)) 
    if (1 * sq * sq != n): 
        return False
    if (isPrime(sq)): 
        return True
    else: 
        return False
if __name__ == '__main__': 
    n=int(input())
    l=list(map(int,input().split()))
    for i in range(n):
        num =l[i]
        if (isThreeDisctFactors(num)): 
            print("YES") 
        else: 
            print("NO")