Problem: After you had helped George and Alex to move in the dorm, they went to help their friend Fedor play a new computer game «Call of Soldiers 3».

The game has (m + 1) players and n types of soldiers in total. Players «Call of Soldiers 3» are numbered form 1 to (m + 1). Types of soldiers are numbered from 0 to n - 1. Each player has an army. Army of the i-th player can be described by non-negative integer xi. Consider binary representation of xi: if the j-th bit of number xi equal to one, then the army of the i-th player has soldiers of the j-th type. 

Fedor is the (m + 1)-th player of the game. He assume that two players can become friends if their armies differ in at most k types of soldiers (in other words, binary representations of the corresponding numbers differ in at most k bits). Help Fedor and count how many players can become his friends.

Input

The first line contains three integers n, m, k (1 ≤ k ≤ n ≤ 20; 1 ≤ m ≤ 1000).

The i-th of the next (m + 1) lines contains a single integer xi (1 ≤ xi ≤ 2n - 1), that describes the i-th player's army. We remind you that Fedor is the (m + 1)-th player.

Output

Print a single integer — the number of Fedor's potential friends.

Examples

Input

7 3 1
8
5
111
17


Output

0


Input

3 3 3
1
2
3
4


Output

3

Solution (in PYTHON3):

Solution:
def is_friend(a, b, n, k):
    pre_a = '0' * (n - len(a))
    pre_b = '0' * (n - len(b))
    a = pre_a + a
    b = pre_b + b
    dif = 0
    for d in range(n):
        if a[d] != b[d]:
            dif += 1
    if dif > k:
        return False
    return True


n, m, k = map(int, input().split())
arr = []
for _ in range(m):
    arr.append(bin(int(input()))[2:])
f = bin(int(input()))[2:]
ans = 0
for m in arr:
    ans += is_friend(f, m, n, k)
print(ans)