Problem: We know that prime numbers are positive integers that have exactly two distinct positive divisors. Similarly, we'll call a positive integer t Т-prime, if t has exactly three distinct positive divisors.

You are given an array of n positive integers. For each of them determine whether it is Т-prime or not.

Input

The first line contains a single positive integer, n (1 ≤ n ≤ 105), showing how many numbers are in the array. The next line contains n space-separated integers xi (1 ≤ xi ≤ 1012).

Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is advised to use the cin, cout streams or the %I64d specifier.

Output

Print n lines: the i-th line should contain "YES" (without the quotes), if number xi is Т-prime, and "NO" (without the quotes), if it isn't.

Examples

Input

3
4 5 6


Output

YES
NO
NO

Note

The given test has three numbers. The first number 4 has exactly three divisors — 1, 2 and 4, thus the answer for this number is "YES". The second number 5 has two divisors (1 and 5), and the third number 6 has four divisors (1, 2, 3, 6), hence the answer for them is "NO".

Solution (in PYTHON3):

Solution:
import math

def isPrime(n):
        for i in range(3,int( math.sqrt(n))+1,2):
                if n % i == 0:
                        return False
        return True

if __name__ == "__main__":
        a=int(input())
        b= list(map(int,input().split()))
        for k in b:
                if k == 4:
                        print("YES")
                elif k%2 == 0:
                        print("NO")
                elif k<4:
                        print ("NO")
                else:
                        g= math.sqrt(k)
                        if g!=int(g):
                                print("NO")
                        else:
                                if isPrime(int(g)):
                                        print("YES")
                                else:
                                        print("NO")