Problem: Today Pari and Arya are playing a game called Remainders.

Pari chooses two positive integer x and k, and tells Arya k but not x. Arya have to find the value <image>. There are n ancient numbers c1, c2, ..., cn and Pari has to tell Arya <image> if Arya wants. Given k and the ancient values, tell us if Arya has a winning strategy independent of value of x or not. Formally, is it true that Arya can understand the value <image> for any positive integer x?

Note, that <image> means the remainder of x after dividing it by y.

Input

The first line of the input contains two integers n and k (1 ≤ n, k ≤ 1 000 000) — the number of ancient integers and value k that is chosen by Pari.

The second line contains n integers c1, c2, ..., cn (1 ≤ ci ≤ 1 000 000).

Output

Print "Yes" (without quotes) if Arya has a winning strategy independent of value of x, or "No" (without quotes) otherwise.

Examples

Input

4 5
2 3 5 12


Output

Yes


Input

2 7
2 3


Output

No

Note

In the first sample, Arya can understand <image> because 5 is one of the ancient numbers.

In the second sample, Arya can't be sure what <image> is. For example 1 and 7 have the same remainders after dividing by 2 and 3, but they differ in remainders after dividing by 7.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
const int maxn = 0x3f3f3f3f;
const double EI =
    2.71828182845904523536028747135266249775724709369995957496696762772407663035354594571382178525166427;
const double PI = 3.141592653589793238462643383279;
using namespace std;
inline long long Gcd(long long n, long long m) {
  long long r;
  if (n < m) {
    r = n;
    n = m;
    m = r;
  }
  while (n % m != 0) {
    r = n % m;
    n = m;
    m = r;
  }
  return m;
}
inline long long Lcm(long long n, long long m) { return n / Gcd(n, m) * m; }
int main(void) {
  int n, i;
  long long k, tmp, ans;
  while (~scanf("%d %lld", &n, &k)) {
    ans = 1;
    for (i = 0; i < n; i++) {
      scanf("%lld", &tmp);
      if (ans == 0) {
        continue;
      }
      ans = Lcm(ans, tmp);
      ans %= k;
    }
    if (ans == 0) {
      printf("Yes\n");
    } else {
      printf("No\n");
    }
  }
  return 0;
}