Problem: Today Pari and Arya are playing a game called Remainders.

Pari chooses two positive integer x and k, and tells Arya k but not x. Arya have to find the value <image>. There are n ancient numbers c1, c2, ..., cn and Pari has to tell Arya <image> if Arya wants. Given k and the ancient values, tell us if Arya has a winning strategy independent of value of x or not. Formally, is it true that Arya can understand the value <image> for any positive integer x?

Note, that <image> means the remainder of x after dividing it by y.

Input

The first line of the input contains two integers n and k (1 ≤ n, k ≤ 1 000 000) — the number of ancient integers and value k that is chosen by Pari.

The second line contains n integers c1, c2, ..., cn (1 ≤ ci ≤ 1 000 000).

Output

Print "Yes" (without quotes) if Arya has a winning strategy independent of value of x, or "No" (without quotes) otherwise.

Examples

Input

4 5
2 3 5 12


Output

Yes


Input

2 7
2 3


Output

No

Note

In the first sample, Arya can understand <image> because 5 is one of the ancient numbers.

In the second sample, Arya can't be sure what <image> is. For example 1 and 7 have the same remainders after dividing by 2 and 3, but they differ in remainders after dividing by 7.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
const int maxn = 1e6 + 10;
int a[maxn], b[maxn];
int prime(int n) {
  if (n == 1) return -1;
  for (int i = 2; i * i <= n; i++)
    if (n % i == 0) return i;
  return n;
}
int main() {
  int n, k;
  cin >> n >> k;
  vector<int> v;
  int cur = k;
  while (cur != 1) {
    int p = prime(cur);
    v.push_back(p);
    cur /= p;
  }
  vector<int> z;
  for (int i = 0; i < v.size(); i++) {
    int res = 1;
    if (i == 0 || v[i] != v[i - 1])
      for (int j = 0; j < v.size(); j++)
        if (v[j] == v[i]) res *= v[i];
    z.push_back(res);
  }
  for (int i = 0; i < n; i++) scanf("%d", a + i);
  for (int i = 0; i < z.size(); i++) {
    bool can = 0;
    for (int j = 0; j < n; j++)
      if (a[j] % z[i] == 0) can = 1;
    if (can == 0) {
      cout << "No" << endl;
      return 0;
    }
  }
  cout << "Yes" << endl;
}