Problem: This is the easy version of the problem. The difference between the versions is the constraint on n and the required number of operations. You can make hacks only if all versions of the problem are solved.

There are two binary strings a and b of length n (a binary string is a string consisting of symbols 0 and 1). In an operation, you select a prefix of a, and simultaneously invert the bits in the prefix (0 changes to 1 and 1 changes to 0) and reverse the order of the bits in the prefix.

For example, if a=001011 and you select the prefix of length 3, it becomes 011011. Then if you select the entire string, it becomes 001001.

Your task is to transform the string a into b in at most 3n operations. It can be proved that it is always possible.

Input

The first line contains a single integer t (1≤ t≤ 1000) — the number of test cases. Next 3t lines contain descriptions of test cases.

The first line of each test case contains a single integer n (1≤ n≤ 1000) — the length of the binary strings.

The next two lines contain two binary strings a and b of length n.

It is guaranteed that the sum of n across all test cases does not exceed 1000.

Output

For each test case, output an integer k (0≤ k≤ 3n), followed by k integers p_1,…,p_k (1≤ p_i≤ n). Here k is the number of operations you use and p_i is the length of the prefix you flip in the i-th operation.

Example

Input


5
2
01
10
5
01011
11100
2
01
01
10
0110011011
1000110100
1
0
1


Output


3 1 2 1
6 5 2 5 3 1 2
0
9 4 1 2 10 4 1 2 1 5
1 1

Note

In the first test case, we have 01→ 11→ 00→ 10.

In the second test case, we have 01011→ 00101→ 11101→ 01000→ 10100→ 00100→ 11100.

In the third test case, the strings are already the same. Another solution is to flip the prefix of length 2, which will leave a unchanged.

Solution (in PYTHON3):

Solution:
import sys

t=int(input())
for _ in range(t):
	n=int(input())
	tempa=input()
	tempb=input()
	a=[]
	for i in tempa:
		a.append(int(i))
	b=[]
	for i in tempb:
		b.append(int(i))
	count=0
	anslist=[]
	start=1
	rev=0
	for i in range(n-1,-1,-1):
		if(rev==0):
			pos=start+i 
		else:
			pos=start-i
		curr=a[pos-1]
		if(rev==1):
			curr=curr^1
		if(curr!=b[i]):
			first=a[start-1]
			if(rev==1):
				first=first^1
			if(first!=b[i]):
				anslist.append(i+1)
				count+=1
			else:
				anslist.append(1)
				anslist.append(i+1)
				count+=2
			rev=rev^1
			start=pos
	print(count,end=" ")
	for i in anslist:
		sys.stdout.write(str(i)+" ")
	print()