Problem: After you had helped George and Alex to move in the dorm, they went to help their friend Fedor play a new computer game «Call of Soldiers 3».

The game has (m + 1) players and n types of soldiers in total. Players «Call of Soldiers 3» are numbered form 1 to (m + 1). Types of soldiers are numbered from 0 to n - 1. Each player has an army. Army of the i-th player can be described by non-negative integer xi. Consider binary representation of xi: if the j-th bit of number xi equal to one, then the army of the i-th player has soldiers of the j-th type. 

Fedor is the (m + 1)-th player of the game. He assume that two players can become friends if their armies differ in at most k types of soldiers (in other words, binary representations of the corresponding numbers differ in at most k bits). Help Fedor and count how many players can become his friends.

Input

The first line contains three integers n, m, k (1 ≤ k ≤ n ≤ 20; 1 ≤ m ≤ 1000).

The i-th of the next (m + 1) lines contains a single integer xi (1 ≤ xi ≤ 2n - 1), that describes the i-th player's army. We remind you that Fedor is the (m + 1)-th player.

Output

Print a single integer — the number of Fedor's potential friends.

Examples

Input

7 3 1
8
5
111
17


Output

0


Input

3 3 3
1
2
3
4


Output

3

Solution (in PYTHON3):

Solution:
n, m, k = [int(i) for i in input().split()]
arms = []
max_len = 0
ans = 0
for i in range(m+1):
    x = bin(int(input()))
    x = x[2:len(x)]
    if len(x) > max_len:
        max_len = len(x)
    arms.append(x)
for i in range(len(arms)):
    if len(arms[i]) < max_len:
        arms[i] = '0' * (max_len - len(arms[i])) + arms[i]
for i in range(len(arms) - 1):
    curr_k = 0
    for j in range(max_len):
        if arms[i][j] != arms[-1][j]:
            curr_k += 1
    if curr_k <= k:
        ans += 1
print(ans)