Problem: After you had helped George and Alex to move in the dorm, they went to help their friend Fedor play a new computer game «Call of Soldiers 3».

The game has (m + 1) players and n types of soldiers in total. Players «Call of Soldiers 3» are numbered form 1 to (m + 1). Types of soldiers are numbered from 0 to n - 1. Each player has an army. Army of the i-th player can be described by non-negative integer xi. Consider binary representation of xi: if the j-th bit of number xi equal to one, then the army of the i-th player has soldiers of the j-th type. 

Fedor is the (m + 1)-th player of the game. He assume that two players can become friends if their armies differ in at most k types of soldiers (in other words, binary representations of the corresponding numbers differ in at most k bits). Help Fedor and count how many players can become his friends.

Input

The first line contains three integers n, m, k (1 ≤ k ≤ n ≤ 20; 1 ≤ m ≤ 1000).

The i-th of the next (m + 1) lines contains a single integer xi (1 ≤ xi ≤ 2n - 1), that describes the i-th player's army. We remind you that Fedor is the (m + 1)-th player.

Output

Print a single integer — the number of Fedor's potential friends.

Examples

Input

7 3 1
8
5
111
17


Output

0


Input

3 3 3
1
2
3
4


Output

3

Solution (in PYTHON):

Solution:
def binary_convert(num,n):
    result = []
    if num <= 1:
        result.append(num)
    else:
        while True:
            consult = num/2
            reminder = num%2
            if consult != 1:
                result.append(reminder)
            else:
                result.append(reminder)
                result.append(1)
                break
            num = consult

    if len(result) < n:
        add_zero = n - len(result)
        for i in range(add_zero):
            result.append(0)
    result = result[::-1]
    return result



def xiangdananpy(temp,fedor,k):
    result = 0
    for i in range(len(temp)):
        if temp[i] != fedor[i]:
            result += 1
    if result <= k:
        return True
    else:
        return False


n,m,k = map(int,raw_input().split())
result = []
for i in range(m):
    temp = binary_convert(int(raw_input()),n)
    result.append(temp)
fedor = binary_convert(int(raw_input()),n)

friend = 0
for item in result:
    if xiangdananpy(item,fedor,k) == True:
        friend += 1

print friend