Problem: You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

* It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:


N


Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:


h n w

Examples

Input

2


Output

1 2 2


Input

3485


Output

872 1012974 1539173474040


Input

4664


Output

3498 3498 3498

Solution (in PYTHON3):

Solution:
N=int(input())
 
for h in range(1,3501):
  for n in range(1,3501):
    #divが負数ならwは負数になる
    if (4*h*n)-(N*n)-(N*h)>0:
      w=N*h*n/((4*h*n)-(N*n)-(N*h))
      if w.is_integer():
        print(h,n,int(w))
        exit()