Problem: You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

* It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:


N


Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:


h n w

Examples

Input

2


Output

1 2 2


Input

3485


Output

872 1012974 1539173474040


Input

4664


Output

3498 3498 3498

Solution (in CPP):

Solution:
#include<bits/stdc++.h>
using namespace std;
int main()
{
	long long n; scanf("%lld", &n);
	long long k;
	for (long long i = 1; i <= 3500; i++) {
		for (long long j = 1; j <= 3500; j++) {
			if (4 * i*j - n*j - n*i == 0)continue;
			k = (n*i*j)/(4 * i*j - n*j - n*i) ;
			if (n*i*j == (4 * i*j - n*j - n*i)*k&&k>0) {
				printf("%lld %lld %lld", i, j, k);
				return 0;
			}
		}
	}
}