Problem: You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

* It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:


N


Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:


h n w

Examples

Input

2


Output

1 2 2


Input

3485


Output

872 1012974 1539173474040


Input

4664


Output

3498 3498 3498

Solution (in CPP):

Solution:
#include<iostream>
#include<cstdio>
#define ll long long
using namespace std;
ll n;
int main()
{
	scanf("%lld",&n);
	for(int a1=1;a1<=3500;a1++)
		for(int a2=a1;a2<=3500;a2++)
		{
			ll fz=-n*a1-n*a2+4*a1*a2,fm=n*a1*a2;
			if(fz>0&&fm>0&&fm%fz==0) {printf("%d %d %lld",a1,a2,fm/fz); return 0;}
			
		}
	return 0;
}