Problem: You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

* It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:


N


Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:


h n w

Examples

Input

2


Output

1 2 2


Input

3485


Output

872 1012974 1539173474040


Input

4664


Output

3498 3498 3498

Solution (in CPP):

Solution:
#include <iostream>
#define int long long
using namespace std;
signed main(){
  int N;
  cin >> N;
  for(int i = 1; i < 3500; ++i){
    for(int j = 1; j < 3500; ++j){
      if(4*i*j-N*(i+j) && (N*i*j)%(4*i*j-N*(i+j)) == 0 && (N*i*j)/(4*i*j-N*(i+j)) > 0){
	cout << i << " " << j << " " << (N*i*j)/(4*i*j-N*(i+j)) << endl;
	return 0;
      } 
    }    
  }
  return 0;
}