Problem: We know that prime numbers are positive integers that have exactly two distinct positive divisors. Similarly, we'll call a positive integer t Т-prime, if t has exactly three distinct positive divisors.

You are given an array of n positive integers. For each of them determine whether it is Т-prime or not.

Input

The first line contains a single positive integer, n (1 ≤ n ≤ 105), showing how many numbers are in the array. The next line contains n space-separated integers xi (1 ≤ xi ≤ 1012).

Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is advised to use the cin, cout streams or the %I64d specifier.

Output

Print n lines: the i-th line should contain "YES" (without the quotes), if number xi is Т-prime, and "NO" (without the quotes), if it isn't.

Examples

Input

3
4 5 6


Output

YES
NO
NO

Note

The given test has three numbers. The first number 4 has exactly three divisors — 1, 2 and 4, thus the answer for this number is "YES". The second number 5 has two divisors (1 and 5), and the third number 6 has four divisors (1, 2, 3, 6), hence the answer for them is "NO".

Solution (in PYTHON3):

Solution:
from math import sqrt,ceil

n = int(input())
l = [int(x) for x in input().split()]

def calcula_primos(n):
	primos = [0] * (n+1)
	for i in range(2,ceil(sqrt(n))+1):
		if primos[i] == 0:
			step = 2*i
			while step <= n:
				primos[step] = 1
				step = step + (i)
	
	return primos

resp = set()
primos = calcula_primos(1000000)
for i in range(len(primos)):
	if primos[i] == 0:
		resp.add(i**2)


for i in l:
	if i == 1:
		print('NO')
		continue
	if i in resp:
		print('YES')
	else:
		print('NO')