Problem: After you had helped George and Alex to move in the dorm, they went to help their friend Fedor play a new computer game «Call of Soldiers 3».

The game has (m + 1) players and n types of soldiers in total. Players «Call of Soldiers 3» are numbered form 1 to (m + 1). Types of soldiers are numbered from 0 to n - 1. Each player has an army. Army of the i-th player can be described by non-negative integer xi. Consider binary representation of xi: if the j-th bit of number xi equal to one, then the army of the i-th player has soldiers of the j-th type. 

Fedor is the (m + 1)-th player of the game. He assume that two players can become friends if their armies differ in at most k types of soldiers (in other words, binary representations of the corresponding numbers differ in at most k bits). Help Fedor and count how many players can become his friends.

Input

The first line contains three integers n, m, k (1 ≤ k ≤ n ≤ 20; 1 ≤ m ≤ 1000).

The i-th of the next (m + 1) lines contains a single integer xi (1 ≤ xi ≤ 2n - 1), that describes the i-th player's army. We remind you that Fedor is the (m + 1)-th player.

Output

Print a single integer — the number of Fedor's potential friends.

Examples

Input

7 3 1
8
5
111
17


Output

0


Input

3 3 3
1
2
3
4


Output

3

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int main() {
  long long n, m, k, s, q = 0, b = 0, ans = 0;
  cin >> n >> m >> k;
  long long ar[m + 1][50];
  memset(ar, 0, sizeof(ar[0][0]) * (m + 1) * (50));
  for (int a = 0; a < m + 1; a++) {
    b = 0;
    cin >> s;
    while (s > 0) {
      if (s % 2 == 1) ar[a][b] = 1;
      s /= 2;
      b++;
    }
  }
  for (int a = 0; a < m; a++) {
    q = 0;
    for (int b = 0; b < n; b++) {
      if (ar[m][b] != ar[a][b]) q++;
    }
    if (q <= k) ans++;
  }
  cout << ans;
  return 0;
}