Problem: We know that prime numbers are positive integers that have exactly two distinct positive divisors. Similarly, we'll call a positive integer t Т-prime, if t has exactly three distinct positive divisors.

You are given an array of n positive integers. For each of them determine whether it is Т-prime or not.

Input

The first line contains a single positive integer, n (1 ≤ n ≤ 105), showing how many numbers are in the array. The next line contains n space-separated integers xi (1 ≤ xi ≤ 1012).

Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is advised to use the cin, cout streams or the %I64d specifier.

Output

Print n lines: the i-th line should contain "YES" (without the quotes), if number xi is Т-prime, and "NO" (without the quotes), if it isn't.

Examples

Input

3
4 5 6


Output

YES
NO
NO

Note

The given test has three numbers. The first number 4 has exactly three divisors — 1, 2 and 4, thus the answer for this number is "YES". The second number 5 has two divisors (1 and 5), and the third number 6 has four divisors (1, 2, 3, 6), hence the answer for them is "NO".

Solution (in PYTHON3):

Solution:
from math import sqrt
 
def prime(x):
    if x <= 1: 
        return 0
    if x <= 3: 
        return 1
    if x % 2 == 0 or x % 3 == 0: 
        return 0
    i = 5
    while i*i <= x: 
        if x % i == 0 or x % (i + 2) == 0: 
            return 0
        i += 6
    return 1
 
N = int(input())
A = list(map(int, input().split()))
for i in A:
    k = sqrt(i)
    m = int(k)
    if m != sqrt(i):
        print('NO')
    elif k in [2,3]:
        print('YES')
    elif k%2 == 0 or k%3 == 0:
        print('NO')
    elif prime(m) == 1:
        print('YES')
    else:
        print('NO')