Problem: Merge sort is a well-known sorting algorithm. The main function that sorts the elements of array a with indices from [l, r) can be implemented as follows:

  1. If the segment [l, r) is already sorted in non-descending order (that is, for any i such that l ≤ i < r - 1 a[i] ≤ a[i + 1]), then end the function call; 
  2. Let <image>; 
  3. Call mergesort(a, l, mid); 
  4. Call mergesort(a, mid, r); 
  5. Merge segments [l, mid) and [mid, r), making the segment [l, r) sorted in non-descending order. The merge algorithm doesn't call any other functions. 



The array in this problem is 0-indexed, so to sort the whole array, you need to call mergesort(a, 0, n).

The number of calls of function mergesort is very important, so Ivan has decided to calculate it while sorting the array. For example, if a = {1, 2, 3, 4}, then there will be 1 call of mergesort — mergesort(0, 4), which will check that the array is sorted and then end. If a = {2, 1, 3}, then the number of calls is 3: first of all, you call mergesort(0, 3), which then sets mid = 1 and calls mergesort(0, 1) and mergesort(1, 3), which do not perform any recursive calls because segments (0, 1) and (1, 3) are sorted.

Ivan has implemented the program that counts the number of mergesort calls, but now he needs to test it. To do this, he needs to find an array a such that a is a permutation of size n (that is, the number of elements in a is n, and every integer number from [1, n] can be found in this array), and the number of mergesort calls when sorting the array is exactly k.

Help Ivan to find an array he wants!

Input

The first line contains two numbers n and k (1 ≤ n ≤ 100000, 1 ≤ k ≤ 200000) — the size of a desired permutation and the number of mergesort calls required to sort it.

Output

If a permutation of size n such that there will be exactly k calls of mergesort while sorting it doesn't exist, output  - 1. Otherwise output n integer numbers a[0], a[1], ..., a[n - 1] — the elements of a permutation that would meet the required conditions. If there are multiple answers, print any of them.

Examples

Input

3 3


Output

2 1 3 

Input

4 1


Output

1 2 3 4 

Input

5 6


Output

-1

Solution (in JAVA):

Solution:
	import java.io.*;
	import java.util.*;
	import java.math.*;
	
	 
	 public class Main	{
	   static class Pair implements Comparable<Pair>{

		   int a;
		   long b;
		   public Pair(int x,long y){a=x;b=y;}
		   public int compareTo(Pair p){
				 return Long.compare(a, p.a);
		   }
//		@Override
//		public int hashCode() {
//			final int prime = 31;
//			int result = 1;
//			result = prime * result + a;
//			result = prime * result + b;
//		   
//			return result;
//		}
//		@Override
//		public boolean equals(Object obj) {
//			Pair cur = (Pair)obj;
//			if((a==cur.a && b==cur.b))return true;
//			return false;
//		}
	 }
	   static class ArrayUtils {
			public static Integer[] generateOrder(int size) {
				Integer[] order = new Integer[size];
				for (int i = 0; i < size; i++)
					order[i] = i;
				return order;
			}
		 
			public static Integer[] order(int size, Comparator<Integer> comparator) {
				Integer[] order = generateOrder(size);
				Arrays.sort(order, comparator);
				return order;
			}
		 
				}
	static class TrieNode{
		int cnt;
		TrieNode[]child;
		public TrieNode() {
			cnt = 0;
			child = new TrieNode[10];
		}
	}
	  public static long gcd(long a,long b)
	  {
	    if(a<b)
	      return gcd(b,a);
	    if(b==0)
	      return a;
	    return gcd(b,a%b);
	    
	  }
	  static int lcm(int a,int b) {
		  return  a*b / (int)gcd(a,b);
	  }
	  
	  static long mod = 998244353;//(long)(1e9+7); //
	   
	    public static void main(String[] args) throws Exception {
	       new Thread(null, null, "Anshum Gupta", 99999999) {
	            public void run() {
	                try {
	                    solve();
	                } catch(Exception e) {
	                    e.printStackTrace();
	                    System.exit(1);
	                }
	            }
	        }.start();
	    }
	
	static long pow(long x,long y){
	    if(y == 0)return 1;
	    if(y==1)return x;
	    long a = pow(x,y/2);
	    a = (a*a)%mod;
	    if(y%2==0){
	        return a;
	    }
	    return (a*x)%mod;
	}
	
	static long mxx;
	static int mxN = (int)(2e6+5);
	static int mxV = (int)(2e5);
	static long[]fact,inv_fact;
	static long my_inv(long a) {
		return pow(a,mod-2);
	}
	static long bin(int a,int b) {
		if(a < b || a<0 || b<0)return 0;
	    return ((fact[a]*inv_fact[a-b])%mod * inv_fact[b])%mod;
	}
		static ArrayList<ArrayList<Integer>>adj;
		static boolean[]vis;
	static void make_facts() {
	  fact=new long[mxN];
	  inv_fact = new long[mxN];
	  fact[0]=inv_fact[0]=1L;
	  for(int i=1;i<mxN;i++) {
		   fact[i] = (i*fact[i-1])%mod;
		   inv_fact[i] = my_inv(fact[i]);
	  }
	}
     static void merge(int i, int j) {
    	 if(i + 1 == j) {
    		 return;
    	 }
    	 if(cnt == k) {
    		 Arrays.parallelSort(ans, i, j);
    		 return;
    	 }
    	 cnt += 2;
    	 int mid = (i+j) >> 1;
	     merge(i, mid);
	     merge(mid, j);
     }
     static int[]ans;
     static int n, k, cnt;
	 public static void solve() throws Exception {
	   // solve the problem here
	   MyScanner s = new MyScanner();
	        out = new PrintWriter(new BufferedOutputStream(System.out), true);
	        int tc = 1;//s.nextInt();
	        mxx = (long)(1e18+5);
	//	        make_facts(); 
	//	        int mod = (int)1e9+7;
	        
	        while(tc-->0){
	        	n = s.nextInt();
	        	k = s.nextInt();
	        	ans = new int[n];
	        	int mx = 2 * n - 1;
	        	if(k > mx || k % 2 == 0) {
	        		out.println("-1");
	        		return;
	        	}
	        	cnt = 1;
	        	for(int i=0;i<n;i++)ans[i] = n - i - 1;
	        	merge(0, n);
	        	for(int i=0;i<n;i++) {
	        		out.print((ans[i]+1) + " ");
	        	}
	        	
	        	
	        }
	        	
	           
	        out.flush();
	}
	 
	     
	 
	 
	 
	    //-----------PrintWriter for faster output---------------------------------
	    public static PrintWriter out;
	 
	    //-----------MyScanner class for faster input----------
	    public static class MyScanner {
	        BufferedReader br;
	        StringTokenizer st;
	 
	        public MyScanner() {
	            br = new BufferedReader(new InputStreamReader(System.in));
	        }
	 
	        String next() {
	            while (st == null || !st.hasMoreElements()) {
	                try {
	                    st = new StringTokenizer(br.readLine());
	                } catch (IOException e) {
	                    e.printStackTrace();
	                }
	            }
	            return st.nextToken();
	        }
	 
	        int nextInt() { return Integer.parseInt(next()); }
	        long nextLong() { return Long.parseLong(next()); }
	        double nextDouble() { return Double.parseDouble(next()); }
	         
	        String nextLine(){
	            String str = "";
	            try {
	                str = br.readLine();
	            } catch (IOException e) {
	                e.printStackTrace();
	            }
	            return str;
	        }
	    }
	    //--------------------------------------------------------
	}