Problem: You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

* It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:


N


Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:


h n w

Examples

Input

2


Output

1 2 2


Input

3485


Output

872 1012974 1539173474040


Input

4664


Output

3498 3498 3498

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
#define ll long long
using namespace std;
int main (){
	ll i,j,n;
	scanf ("%lld",&n);
	for (i=1;i<=3500;i++)
	{for (j=1;j<=3500;j++)
	{ll f1=n*i*j,f2=4*i*j-(i+j)*n;
	if (f2==0) {continue;}
	if (f1%f2==0&&f1/f2>0)
	{printf ("%lld %lld %lld\n",i,j,f1/f2);
	return 0;
	}
	}
	}
}