Problem: You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

* It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:


N


Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:


h n w

Examples

Input

2


Output

1 2 2


Input

3485


Output

872 1012974 1539173474040


Input

4664


Output

3498 3498 3498

Solution (in JAVA):

Solution:
import java.util.*;

public class Main {
    static Scanner scanner = new Scanner(System.in);

    public static void main(String[]$) {
        int n = scanner.nextInt();
        for (double i = 1; i <= 3500; i++) {
            for (double j = 1; j <= 3500; j++) {
                double k = n * i * j / (4 * i * j - n * i - n * j);
                if (k > 0 && k % 1 == 0) {
                    System.out.println((long)i + " " + (long)j + " " + (long)k);
                    return;
                }
            }
        }
    }
}