Problem: We know that prime numbers are positive integers that have exactly two distinct positive divisors. Similarly, we'll call a positive integer t Т-prime, if t has exactly three distinct positive divisors.

You are given an array of n positive integers. For each of them determine whether it is Т-prime or not.

Input

The first line contains a single positive integer, n (1 ≤ n ≤ 105), showing how many numbers are in the array. The next line contains n space-separated integers xi (1 ≤ xi ≤ 1012).

Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is advised to use the cin, cout streams or the %I64d specifier.

Output

Print n lines: the i-th line should contain "YES" (without the quotes), if number xi is Т-prime, and "NO" (without the quotes), if it isn't.

Examples

Input

3
4 5 6


Output

YES
NO
NO

Note

The given test has three numbers. The first number 4 has exactly three divisors — 1, 2 and 4, thus the answer for this number is "YES". The second number 5 has two divisors (1 and 5), and the third number 6 has four divisors (1, 2, 3, 6), hence the answer for them is "NO".

Solution (in PYTHON3):

Solution:
l = 1000000
def is_prime():
    p_f = [True] * l
    p_f[0] = p_f[1] = False
    for i in range(2,l):
        if p_f[i] == True:
            for j in range(i*i, l, i):
                p_f[j] = False
    return p_f


def sq_is_prime(n):
    if n == 4:
        return True
    if n < 4 or n % 2 == 0:
        return False
    sqrt_n = n**0.5
    if sqrt_n == int(sqrt_n):
        if p_f[int(sqrt_n)] == True:
            return True
    return False

p_f = is_prime()
a = int(input())
in_a = list(map(int,input().split()))
for i in in_a:
    if sq_is_prime(i) == True:
        print("YES")
    else:
        print("NO")