Problem: You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

* It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:


N


Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:


h n w

Examples

Input

2


Output

1 2 2


Input

3485


Output

872 1012974 1539173474040


Input

4664


Output

3498 3498 3498

Solution (in CPP):

Solution:
#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
int main(){
	ll n; cin>>n;
	for(ll a=1;a<=3500;a++){
		for(ll b=1;b<=3500;b++){
			ll x=a+b;
			ll y=a*b;
			ll p=y*n;
			ll q=(4*y)-(x*n);
			if(q<=0) continue;
			if(p%q) continue;
			ll c=p/q;
			if(c>3500) continue;
			cout<<a<<" "<< b<<" "<<c<<endl;
			return 0;
		}
	}	
	return 0;
}