Problem: You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

* It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:


N


Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:


h n w

Examples

Input

2


Output

1 2 2


Input

3485


Output

872 1012974 1539173474040


Input

4664


Output

3498 3498 3498

Solution (in CPP):

Solution:
#include<bits/stdc++.h>
using namespace std;
typedef long long ll;

int main(){
  ll N;
  cin>>N;
  for(ll h=1;h<=3501;h++){
    for(ll n=1;n<=3501;n++){
      ll B=4*n*h-N*n-N*h;
      ll A=n*h*N;
      
      if(B>0&&A%B==0){
        cout<<h<<' '<<n<<' '<<A/B<<endl;
        return 0;
      }

    }
  }
  return 0;
}