Problem: Today Pari and Arya are playing a game called Remainders.

Pari chooses two positive integer x and k, and tells Arya k but not x. Arya have to find the value <image>. There are n ancient numbers c1, c2, ..., cn and Pari has to tell Arya <image> if Arya wants. Given k and the ancient values, tell us if Arya has a winning strategy independent of value of x or not. Formally, is it true that Arya can understand the value <image> for any positive integer x?

Note, that <image> means the remainder of x after dividing it by y.

Input

The first line of the input contains two integers n and k (1 ≤ n, k ≤ 1 000 000) — the number of ancient integers and value k that is chosen by Pari.

The second line contains n integers c1, c2, ..., cn (1 ≤ ci ≤ 1 000 000).

Output

Print "Yes" (without quotes) if Arya has a winning strategy independent of value of x, or "No" (without quotes) otherwise.

Examples

Input

4 5
2 3 5 12


Output

Yes


Input

2 7
2 3


Output

No

Note

In the first sample, Arya can understand <image> because 5 is one of the ancient numbers.

In the second sample, Arya can't be sure what <image> is. For example 1 and 7 have the same remainders after dividing by 2 and 3, but they differ in remainders after dividing by 7.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
const int MOD = 1000000007;
void sync_stdio() {
  cin.tie(NULL);
  ios_base::sync_with_stdio(false);
}
struct Sync_stdio {
  Sync_stdio() {
    cin.tie(NULL);
    ios_base::sync_with_stdio(false);
  }
} _sync_stdio;
struct FAIL {
  FAIL() {
    cout << "CHANGE!!!"
         << "\n";
  }
};
int main() {
  int n, x;
  scanf("%d%d", &n, &x);
  vector<int> a(n);
  for (int i = (0); i < (n); ++i) {
    scanf("%d", &a[i]);
  }
  vector<pair<int, int> > v;
  for (int i = (2); i < (x + 1); ++i) {
    int val = 1;
    while (x % i == 0) {
      val *= i;
      x /= i;
    }
    if (val != 1) {
      v.push_back({val, 0});
    }
  }
  for (int i = (0); i < (n); ++i) {
    for (int j = (0); j < (v.size()); ++j) {
      if (a[i] % v[j].first == 0) {
        v[j].second = 1;
      }
    }
  }
  for (int i = (0); i < (v.size()); ++i) {
    if (v[i].second == 0) {
      cout << "No";
      return 0;
    }
  }
  cout << "Yes";
}