Problem: We know that prime numbers are positive integers that have exactly two distinct positive divisors. Similarly, we'll call a positive integer t Т-prime, if t has exactly three distinct positive divisors.

You are given an array of n positive integers. For each of them determine whether it is Т-prime or not.

Input

The first line contains a single positive integer, n (1 ≤ n ≤ 105), showing how many numbers are in the array. The next line contains n space-separated integers xi (1 ≤ xi ≤ 1012).

Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is advised to use the cin, cout streams or the %I64d specifier.

Output

Print n lines: the i-th line should contain "YES" (without the quotes), if number xi is Т-prime, and "NO" (without the quotes), if it isn't.

Examples

Input

3
4 5 6


Output

YES
NO
NO

Note

The given test has three numbers. The first number 4 has exactly three divisors — 1, 2 and 4, thus the answer for this number is "YES". The second number 5 has two divisors (1 and 5), and the third number 6 has four divisors (1, 2, 3, 6), hence the answer for them is "NO".

Solution (in PYTHON3):

Solution:
import sys
import math
import bisect
from sys import stdin, stdout
from math import gcd, floor, sqrt, log
from collections import defaultdict as dd
from bisect import bisect_left as bl, bisect_right as br
from collections import Counter

#sys.setrecursionlimit(100000000)

inp = lambda: int(input())
strng = lambda: input().strip()
jn = lambda x, l: x.join(map(str, l))
strl = lambda: list(input().strip())
mul = lambda: map(int, input().strip().split())
mulf = lambda: map(float, input().strip().split())
seq = lambda: list(map(int, input().strip().split()))

ceil = lambda x: int(x) if (x == int(x)) else int(x) + 1
ceildiv = lambda x, d: x // d if (x % d == 0) else x // d + 1

flush = lambda: stdout.flush()
stdstr = lambda: stdin.readline()
stdint = lambda: int(stdin.readline())
stdpr = lambda x: stdout.write(str(x))
stdarr = lambda: map(int, stdstr().split())

mod = 1000000007

p = [False]*(10**6+2)

for i in range(2, 10**6+1):
    if(p[i] == True):
        continue

    for j in range(i+i, 10**6+1, i):
        p[j] = True



n = stdint()
arr = list(stdarr())

for i in arr:
    if(i == 1):
        print("NO")
        continue
    sq = sqrt(i)

    if(sq%1 == 0 and p[int(sq)] == False):
        print("YES")
    else:
        print("NO")