Problem: You are given an array s consisting of n integers.

You have to find any array t of length k such that you can cut out maximum number of copies of array t from array s.

Cutting out the copy of t means that for each element t_i of array t you have to find t_i in s and remove it from s. If for some t_i you cannot find such element in s, then you cannot cut out one more copy of t. The both arrays can contain duplicate elements.

For example, if s = [1, 2, 3, 2, 4, 3, 1] and k = 3 then one of the possible answers is t = [1, 2, 3]. This array t can be cut out 2 times. 

  * To cut out the first copy of t you can use the elements [1, \underline{2}, 3, 2, 4, \underline{3}, \underline{1}] (use the highlighted elements). After cutting out the first copy of t the array s can look like [1, 3, 2, 4]. 
  * To cut out the second copy of t you can use the elements [\underline{1}, \underline{3}, \underline{2}, 4]. After cutting out the second copy of t the array s will be [4]. 



Your task is to find such array t that you can cut out the copy of t from s maximum number of times. If there are multiple answers, you may choose any of them.

Input

The first line of the input contains two integers n and k (1 ≤ k ≤ n ≤ 2 ⋅ 10^5) — the number of elements in s and the desired number of elements in t, respectively.

The second line of the input contains exactly n integers s_1, s_2, ..., s_n (1 ≤ s_i ≤ 2 ⋅ 10^5).

Output

Print k integers — the elements of array t such that you can cut out maximum possible number of copies of this array from s. If there are multiple answers, print any of them. The required array t can contain duplicate elements. All the elements of t (t_1, t_2, ..., t_k) should satisfy the following condition: 1 ≤ t_i ≤ 2 ⋅ 10^5.

Examples

Input


7 3
1 2 3 2 4 3 1


Output


1 2 3 


Input


10 4
1 3 1 3 10 3 7 7 12 3


Output


7 3 1 3


Input


15 2
1 2 1 1 1 2 1 1 2 1 2 1 1 1 1


Output


1 1 

Note

The first example is described in the problem statement.

In the second example the only answer is [7, 3, 1, 3] and any its permutations. It can be shown that you cannot choose any other array such that the maximum number of copies you can cut out would be equal to 2.

In the third example the array t can be cut out 5 times.

Solution (in JAVA):

Solution:
//package code;
import java.io.*;
import java.util.*;
import java.util.Map.Entry;
import java.text.*;
import java.math.*;
import java.util.regex.*;
import java.awt.Point;
/**
 *
 * @author prabhat // use stringbuilder,TreeSet, priorityQueue, x+y=(x&y + x|y);
 */
public  class  a
   {
   public static int n,max1=2000005,k,m,q,a[],a1[],mat[][],id,depth[],parent[][],len=22,tin[],tout[],count=0,size[];
   public static Point[] p1,p2,p;
   public static long mod=(long)1e9+7,nCr[][],suf[][],ans=Long.MAX_VALUE,dp[][][][],max=Long.MIN_VALUE;
   public static boolean isPrime[],visit[];
   public static HashSet<Integer> hash;
   public static  ArrayList<Integer> divisor[],prime,adj[],last,lpf;
   public static ArrayList<Character> list[];
   public static  TreeSet<Integer> ts;
   public static char[]s;
   public  static BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
   static PrintWriter pw;
   static int[] x={0,1},y={1,0};

   public static void main(String[] args) {
	new Thread(null,null,"Prabhat Kumar",99999999)
	{
	   public void run() 
	   {
		   try
		   {
			   solve();
		   }
		   catch(Exception e)
		   {   
			   e.printStackTrace();
			   System.exit(1);
		   }
	   }
	}.start();
}
static void solve() throws IOException
 {
	InputReader in = new InputReader(System.in);
	pw=new PrintWriter(System.out);
	n=in.ii();
	k=in.ii();
	a=in.iia(n);
	int[] freq=new int[2000005];
	for(int i:a)freq[i]++;
	int ans=1;
	int low=1;
	int high=n;
	while(low<=high)
	{
		int mid=(low+high)/2;
		if(isValid(mid,freq))
		{
			ans=mid;
			low=mid+1;
		}
		else 
		    high=mid-1;
	}
	int cnt=0;
   for(int i=1;i<2000005;i++)
   {
	   if(freq[i]>=ans)
	   {
		   int x=freq[i]/ans;
		   while(cnt<k&&x-->0)
		   {
			   pw.print(i+" ");
			   cnt++;
		   }
	   }
   }
	pw.close();
 }

 static boolean isValid(int mid,int[] freq)
 {
	 int x=0;
	 for(int i=1;i<2000005;i++)
	 {
		 if(freq[i]>=mid)
		 {
			 x+=freq[i]/mid;
		 }
	 }
	 return  x>=k;
 }
 static int dfs(int u, int p) {

	//discover[count1++]=arr[u];  //  it storing color or arr of vertex u
	//discover[count1++]=u;
	//tin[u] = count++;
   int d1=1000000;
   int d2=1000000;
   int cnt=0;
	//parent[u][0] = p==-1?0:p;
	//size[u]++;
	//for (int i = 1; i < len; i++)
	//	parent[u][i] = parent[parent[u][i-1]][i-1];
	for (int v :adj[u])
		if (v != p)
		{
			cnt++;
			depth[v] = depth[u] + 1;
			int y=dfs( v, u);
			if(y<d1)
			{
				d2=d1;
				d1=y;
			}
			else if(y<d2)
			{
				d2=y;
			}
	//		size[u] += size[v];
		}
	if(cnt==0)return 1;
	ans=Math.min(d1+d2,ans);
	return 1+Math.min(d1,d2);
//	if(adj[u].size()==1&&parent[u][0]!=0)last.add(u);
//	tout[u] = count-1;
}


static boolean isParent(int parent, int child) {
	return tin[parent] <= tin[child] && tout[child] <= tout[parent];
}

static int lca(int a, int b) {
	if (isParent(a, b))
		return a;
	if (isParent(b, a))
		return b;
	for (int i = len - 1; i >= 0; i--)
		if (!isParent(parent[a][i], b))
			a = parent[a][i];
	return parent[a][0];
}
static boolean valid(int i,int j)
{
	return i>=1&&i<=n&&j>=1&&j<=m;
}
 
static int gcd(int a,int b)
{
	while(a!=0)
	{
		int temp=a;
		a=b%a;
		b=temp;
	}
	return b;
}
static void Seive()
{
	a1=new int[max1];
	isPrime=new boolean[max1];
	Arrays.fill(isPrime,true);
//	prime=new ArrayList<>();
//	divisor=new ArrayList[max1];
//	for(int i=1;i<max1;i++)divisor[i]=new ArrayList<Integer>();
    isPrime[0]=isPrime[1]=false;
	for(int i=2;i<(max1);i++)
	{
         if(isPrime[i]){
		//	 divisor[i].add(i);
		//	 prime.add(i);
			 a1[i]=1;
			for(int j=2*i;j<max1;j+=i)
			{
				a1[j]++;
				isPrime[j]=false;
				//divisor[j].add(i);
			}
		}
	}
}
public static long pow(long n,long p)
{
	 long  result = 1;
	  if(p==0)
	    return 1;

	while(p!=0)
	{
	    if(p%2==1)
	        result *= n;
	    
	    p >>=1;
	    n*=n;
	}
	return result;
}


static  class InputReader
{
   private InputStream stream;
   private byte[] buf = new byte[1024];

   private SpaceCharFilter filter;
    byte inbuffer[] = new byte[1024];
   int lenbuffer = 0, ptrbuffer = 0;
    final int M = (int) 1e9 + 7;
   int md=(int)(1e7+1);
    int[] SMP=new int[md];
   final double eps = 1e-6;
   final double pi = Math.PI;

	PrintWriter out;
   String check = "";
 InputStream   obj = check.isEmpty() ? System.in : new ByteArrayInputStream(check.getBytes());
   public InputReader(InputStream stream)
   {
       this.stream = stream;
   }

    int readByte() {
	        if (lenbuffer == -1) throw new InputMismatchException();
	        if (ptrbuffer >= lenbuffer) {
	            ptrbuffer = 0;
	            try {
	                lenbuffer = obj.read(inbuffer);
	            } catch (IOException e) {
	                throw new InputMismatchException();
	            }
	        }
	        if (lenbuffer <= 0) return -1;
	        return inbuffer[ptrbuffer++];
   }

   public  int read()
   {
       int c = read();
       while (isSpaceChar(c))
           c = read();
       int sgn = 1;
       if (c == '-')
       {
           sgn = -1;
           c = read();
       }
       int res = 0;
       do
       {
           if (c < '0' || c > '9')
               throw new InputMismatchException();
           res *= 10;
           res += c - '0';
           c = read();
       } while (!isSpaceChar(c));
       return res * sgn;
   }

   String is() {
	        int b = skip();
	        StringBuilder sb = new StringBuilder();
	        while (!(isSpaceChar(b))) // when nextLine, (isSpaceChar(b) && b!=' ')
	        {
	            sb.appendCodePoint(b);
	            b = readByte();
	        }
	        return sb.toString();
   }
   public   int ii() {
	        int num = 0, b;
	        boolean minus = false;
	        while ((b = readByte()) != -1 && !((b >= '0' && b <= '9') || b == '-')) ;
	        if (b == '-') {
	            minus = true;
	            b = readByte();
	        }
	        while (true) {
	            if (b >= '0' && b <= '9') {
	                num = num * 10 + (b - '0');
	            } else {
	                return minus ? -num : num;
	            }
	            b = readByte();
	        }
   }
 public   long il() {
	        long num = 0;
	        int b;
	        boolean minus = false;
	        while ((b = readByte()) != -1 && !((b >= '0' && b <= '9') || b == '-')) ;
	        if (b == '-') {
	            minus = true;
	            b = readByte();
	        }
	        while (true) {
	            if (b >= '0' && b <= '9') {
	                num = num * 10 + (b - '0');
	            } else {
	                return minus ? -num : num;
	            }
	            b = readByte();
	        }
   }

	    boolean isSpaceChar(int c) {
	        return (!(c >= 33 && c <= 126));
	       }

	      int skip()
	        {
	        int b;
	        while ((b = readByte()) != -1 && isSpaceChar(b)) ;
	        return b;
	        }

	    float nf() {
	        return Float.parseFloat(is());
	    }

	    double id() {
	        return Double.parseDouble(is());
	    }

	    char ic() {
	        return (char) skip();
	    }

	    int[] iia(int n) {
	        int a[] = new int[n];
	        for (int i = 0; i<n; i++) a[i] = ii();
	        return a;
	    }

	    long[] ila(int n) {
	        long a[] = new long[n];
	        for (int i = 0; i <n; i++) a[i] = il();
	        return a;
	    }

	    String[] isa(int n) {
	        String a[] = new String[n];
	        for (int i = 0; i < n; i++) a[i] = is();
	        return a;
	    }


		 long mul(long a, long b) { return a * b % M; }

		/*	long div(long a, long b)
				 {
					return mul(a, pow(b, M - 2,M));

		           }
*/


	    double[][] idm(int n, int m) {
	        double a[][] = new double[n][m];
	        for (int i = 0; i < n; i++) for (int j = 0; j < m; j++) a[i][j] = id();
	        return a;
	        }

	    int[][] iim(int n, int m) {
	        int a[][] = new int[n][m];
	        for (int i = 0; i < n; i++) for (int j = 0; j <m; j++) a[i][j] = ii();
	        return a;
          }


   public String readLine() {
       int c = read();
       while (isSpaceChar(c))
           c = read();
       StringBuilder res = new StringBuilder();
       do {
           res.appendCodePoint(c);
           c = read();
       } while (!isEndOfLine(c));
       return res.toString();
   }

   public interface SpaceCharFilter
   {
       public boolean isSpaceChar(int ch);
   }
   public boolean isEndOfLine(int c) {
       return c == '\n' || c == '\r' || c == -1;
   }
}

}