Problem: Today Pari and Arya are playing a game called Remainders.

Pari chooses two positive integer x and k, and tells Arya k but not x. Arya have to find the value <image>. There are n ancient numbers c1, c2, ..., cn and Pari has to tell Arya <image> if Arya wants. Given k and the ancient values, tell us if Arya has a winning strategy independent of value of x or not. Formally, is it true that Arya can understand the value <image> for any positive integer x?

Note, that <image> means the remainder of x after dividing it by y.

Input

The first line of the input contains two integers n and k (1 ≤ n, k ≤ 1 000 000) — the number of ancient integers and value k that is chosen by Pari.

The second line contains n integers c1, c2, ..., cn (1 ≤ ci ≤ 1 000 000).

Output

Print "Yes" (without quotes) if Arya has a winning strategy independent of value of x, or "No" (without quotes) otherwise.

Examples

Input

4 5
2 3 5 12


Output

Yes


Input

2 7
2 3


Output

No

Note

In the first sample, Arya can understand <image> because 5 is one of the ancient numbers.

In the second sample, Arya can't be sure what <image> is. For example 1 and 7 have the same remainders after dividing by 2 and 3, but they differ in remainders after dividing by 7.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
string a, b;
vector<int> vec[2000008];
int mark[2000008], x = 0;
int main() {
  for (int i = 2; i <= 1000000; i++)
    if (vec[i].size() == 0)
      for (int j = i; j <= 1000000; j += i) {
        vec[j].push_back(i);
      }
  int n, k, tmp, cp;
  scanf("%d %d", &n, &k);
  for (int i = 0; i < n; i++) {
    scanf("%d", &tmp);
    cp = tmp;
    for (int j = 0; j < vec[cp].size(); j++) {
      x = 0;
      while (tmp % vec[cp][j] == 0) {
        x++;
        tmp /= vec[cp][j];
      }
      mark[vec[cp][j]] = max(mark[vec[cp][j]], x);
    }
  }
  int ch = 0;
  cp = k;
  for (int i = 0; i < vec[cp].size(); i++) {
    x = 0;
    while (k % vec[cp][i] == 0) {
      x++;
      k /= vec[cp][i];
    }
    if (mark[vec[cp][i]] < x) ch = 1;
  }
  if (ch)
    printf("No\n");
  else
    printf("Yes\n");
}