Problem: Mishka is decorating the Christmas tree. He has got three garlands, and all of them will be put on the tree. After that Mishka will switch these garlands on.

When a garland is switched on, it periodically changes its state — sometimes it is lit, sometimes not. Formally, if i-th garland is switched on during x-th second, then it is lit only during seconds x, x + ki, x + 2ki, x + 3ki and so on.

Mishka wants to switch on the garlands in such a way that during each second after switching the garlands on there would be at least one lit garland. Formally, Mishka wants to choose three integers x1, x2 and x3 (not necessarily distinct) so that he will switch on the first garland during x1-th second, the second one — during x2-th second, and the third one — during x3-th second, respectively, and during each second starting from max(x1, x2, x3) at least one garland will be lit.

Help Mishka by telling him if it is possible to do this!

Input

The first line contains three integers k1, k2 and k3 (1 ≤ ki ≤ 1500) — time intervals of the garlands.

Output

If Mishka can choose moments of time to switch on the garlands in such a way that each second after switching the garlands on at least one garland will be lit, print YES.

Otherwise, print NO.

Examples

Input

2 2 3


Output

YES


Input

4 2 3


Output

NO

Note

In the first example Mishka can choose x1 = 1, x2 = 2, x3 = 1. The first garland will be lit during seconds 1, 3, 5, 7, ..., the second — 2, 4, 6, 8, ..., which already cover all the seconds after the 2-nd one. It doesn't even matter what x3 is chosen. Our choice will lead third to be lit during seconds 1, 4, 7, 10, ..., though.

In the second example there is no way to choose such moments of time, there always be some seconds when no garland is lit.

Solution (in JAVA):

Solution:


import java.util.*;
import java.io.*;

public class C {
        String INPUT = "2 2 3";

        void solve()
        {
                /**
                 * for given k1,k2,k3 find whether it is possible
                 * to generate S1US2US3={m,m+1,m+2,...} where m = Max(m1,m2,m3)
                 * and S1 = x1,x1+k1,x1+2k1,....
                 * S2 = x2,x2+k2,x2+2k2,....
                 * and so on
                 *
                 * Solution:
                 * There are a few cases to consider for YES
                 * THose are
                 * 1. one of k =1
                 * 2. exactly two of them=2
                 * 3. all of them =3
                 * 4.{2,4,4}
                 */
                int[] a = ia(3);
                Arrays.sort(a);
                if(a[0] == 1)
                {
                        out.println("YES");
                }
                else if ((a[1]==2 &&a[2]==2 )||(a[0]==2 &&a[1]==2))
                {
                        out.println("YES");
                }
                else if(a[0]==3 && a[1]==3 &&a[2]==3)
                {
                        out.println("YES");
                }
                else if(a[0]==2 && a[1] ==4 && a[2]==4)
                {
                        out.println("YES");
                }
                else
                {
                        out.println("NO");
                }
        }
        ///////////////////////////////////////
        void run() throws Exception{
                is = oj ? System.in: new ByteArrayInputStream(INPUT.getBytes());
                //is = System.in;
                out = new PrintWriter(System.out);
                int t = 1;
                while(t-->0)	solve();
                out.flush();
        }
        public static void main(String[] args)throws Exception {
                new C().run();
        }
        InputStream is;
        PrintWriter out;
        private byte[] inbuf = new byte[1024];
        public int lenbuf = 0, ptrbuf = 0;

        private int readByte()
        {
                if(lenbuf == -1)throw new InputMismatchException();
                if(ptrbuf >= lenbuf){
                        ptrbuf = 0;
                        try { lenbuf = is.read(inbuf); } catch (IOException e) { throw new InputMismatchException(); }
                        if(lenbuf <= 0)return -1;
                }
                return inbuf[ptrbuf++];
        }

        private boolean isSpaceChar(int c) { return !(c >= 33 && c <= 126); }
        private int skip() { int b; while((b = readByte()) != -1 && isSpaceChar(b)); return b; }

        private double d() { return Double.parseDouble(s()); }
        private char c() { return (char)skip(); }

        private String s()
        {
                int b = skip();
                StringBuilder sb = new StringBuilder();
                while(!(isSpaceChar(b))){ // when nextLine, (isSpaceChar(b) && b != ' ')
                        sb.appendCodePoint(b);
                        b = readByte();
                }
                return sb.toString();
        }

        private char[] sa(int n)
        {
                char[] buf = new char[n];
                int b = skip(), p = 0;
                while(p < n && !(isSpaceChar(b))){
                        buf[p++] = (char)b;
                        b = readByte();
                }
                return n == p ? buf : Arrays.copyOf(buf, p);
        }

        private char[][] nm(int n, int m)
        {
                char[][] map = new char[n][];
                for(int i = 0;i < n;i++)map[i] = sa(m);
                return map;
        }

        private int[] ia(int n)
        {
                int[] a = new int[n];
                for(int i = 0;i < n;i++)a[i] = i();
                return a;
        }

        private int i()
        {
                int num = 0, b;
                boolean minus = false;
                while((b = readByte()) != -1 && !((b >= '0' && b <= '9') || b == '-'));
                if(b == '-'){
                        minus = true;
                        b = readByte();
                }

                while(true){
                        if(b >= '0' && b <= '9'){
                                num = num * 10 + (b - '0');
                        }else{
                                return minus ? -num : num;
                        }
                        b = readByte();
                }
        }

        private long l()
        {
                long num = 0;
                int b;
                boolean minus = false;
                while((b = readByte()) != -1 && !((b >= '0' && b <= '9') || b == '-'));
                if(b == '-'){
                        minus = true;
                        b = readByte();
                }

                while(true){
                        if(b >= '0' && b <= '9'){
                                num = num * 10 + (b - '0');
                        }else{
                                return minus ? -num : num;
                        }
                        b = readByte();
                }
        }

        private boolean oj = System.getProperty("ONLINE_JUDGE") != null;
        private void tr(Object... o) { if(!oj)System.out.println(Arrays.deepToString(o)); }
}