Problem: You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

* It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:


N


Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:


h n w

Examples

Input

2


Output

1 2 2


Input

3485


Output

872 1012974 1539173474040


Input

4664


Output

3498 3498 3498

Solution (in CPP):

Solution:
#include<bits/stdc++.h>
#define ll long long
using namespace std;
int n;
int main(){
	scanf("%d",&n);
	for(int i=1;i<=3500;i++)
		for(int j=1;j<=3500;j++){
			ll x=(ll)n*i*j;
			ll y=(ll)i*j*4-(ll)n*j-(ll)n*i;
			if(y<=0) continue;
			if(x%y==0){
				printf("%d %d %lld",i,j,x/y);
				return 0;
			}
		}
}