Problem: You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

* It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:


N


Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:


h n w

Examples

Input

2


Output

1 2 2


Input

3485


Output

872 1012974 1539173474040


Input

4664


Output

3498 3498 3498

Solution (in CPP):

Solution:
#include "bits/stdc++.h"
using namespace std;

#define FOR(i,a,b) for(int i=(a);i<(b);++i)
#define REP(i,n)   FOR(i,0,n)
#define LL long long


int main(){
  LL n;
  cin>>n;
  FOR(h,1,3501){
    FOR(w,1,3501){
      if(((4*h-n)*w-n*h)!=0&&(n*h*w)/((4*h-n)*w-n*h)>0&&(n*h*w)%((4*h-n)*w-n*h)==0){
	cout<<h<<" "<<w<<" "<<(n*h*w)/((4*h-n)*w-n*h)<<endl;
	return 0;
      }
    }
  }
  return 0;
}