Problem: You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

* It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:


N


Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:


h n w

Examples

Input

2


Output

1 2 2


Input

3485


Output

872 1012974 1539173474040


Input

4664


Output

3498 3498 3498

Solution (in CPP):

Solution:
#include<bits/stdc++.h>
using namespace std;
int main(){
	long long x,y,N,h,n,w;
	scanf("%lld",&N);
	for(h=1;h<=3500;++h)
		for(n=1;n<=3500;++n){
			x=(4*h*n-(h+n)*N),y=N*h*n;
			if(x>0&&y%x==0)
				return printf("%lld %lld %lld\n",h,n,y/x),0;
		}
}