Problem: We know that prime numbers are positive integers that have exactly two distinct positive divisors. Similarly, we'll call a positive integer t Т-prime, if t has exactly three distinct positive divisors.

You are given an array of n positive integers. For each of them determine whether it is Т-prime or not.

Input

The first line contains a single positive integer, n (1 ≤ n ≤ 105), showing how many numbers are in the array. The next line contains n space-separated integers xi (1 ≤ xi ≤ 1012).

Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is advised to use the cin, cout streams or the %I64d specifier.

Output

Print n lines: the i-th line should contain "YES" (without the quotes), if number xi is Т-prime, and "NO" (without the quotes), if it isn't.

Examples

Input

3
4 5 6


Output

YES
NO
NO

Note

The given test has three numbers. The first number 4 has exactly three divisors — 1, 2 and 4, thus the answer for this number is "YES". The second number 5 has two divisors (1 and 5), and the third number 6 has four divisors (1, 2, 3, 6), hence the answer for them is "NO".

Solution (in PYTHON3):

Solution:
n = int(input())
arr = list(map(int, input().split()))

max_value = max(arr)
limit = int(pow(max_value, 1/2) + 1)
aux = limit * [True]


def sieve():
    p = 2
    while p * p < limit:
        if aux[p]:
            for i in range(p * p, limit, p):
                aux[i] = False
        p += 1


def is_tprime(num):
    if num < limit and aux[num]:
        return False

    sqrt = pow(num, 1/2)
    if sqrt != int(sqrt):
        return False
    return aux[int(sqrt)]


sieve()
for num in arr:
    if is_tprime(num):
        print('YES')
    else:
        print('NO')