Problem: After you had helped George and Alex to move in the dorm, they went to help their friend Fedor play a new computer game «Call of Soldiers 3».

The game has (m + 1) players and n types of soldiers in total. Players «Call of Soldiers 3» are numbered form 1 to (m + 1). Types of soldiers are numbered from 0 to n - 1. Each player has an army. Army of the i-th player can be described by non-negative integer xi. Consider binary representation of xi: if the j-th bit of number xi equal to one, then the army of the i-th player has soldiers of the j-th type. 

Fedor is the (m + 1)-th player of the game. He assume that two players can become friends if their armies differ in at most k types of soldiers (in other words, binary representations of the corresponding numbers differ in at most k bits). Help Fedor and count how many players can become his friends.

Input

The first line contains three integers n, m, k (1 ≤ k ≤ n ≤ 20; 1 ≤ m ≤ 1000).

The i-th of the next (m + 1) lines contains a single integer xi (1 ≤ xi ≤ 2n - 1), that describes the i-th player's army. We remind you that Fedor is the (m + 1)-th player.

Output

Print a single integer — the number of Fedor's potential friends.

Examples

Input

7 3 1
8
5
111
17


Output

0


Input

3 3 3
1
2
3
4


Output

3

Solution (in PYTHON3):

Solution:
n,m,k=map(int,input().split())
a=[]
b=[]
h=0
c=0
for i in range(m+1):
   a.append(int(input()))
for i in a:
  z=bin(i)
  b.append(z[2:])
b=list(map(str,b))
b[-1]=(n-len(b[-1]))*'0'+b[-1]

for  i in range(len(b)):
  if len(b[i])<len(b [-1]) :
      b[i]=(len(b[-1])-len(b[i]))*'0'+b[i]
      
for i in b:
    
     for j in range(len(b[-1])):
        if i[j]!=b[-1][j]:
            c+=1
   
     if c<=k:
        h+=1          
     c=0               
          

print(h-1)