Problem: Today Pari and Arya are playing a game called Remainders.

Pari chooses two positive integer x and k, and tells Arya k but not x. Arya have to find the value <image>. There are n ancient numbers c1, c2, ..., cn and Pari has to tell Arya <image> if Arya wants. Given k and the ancient values, tell us if Arya has a winning strategy independent of value of x or not. Formally, is it true that Arya can understand the value <image> for any positive integer x?

Note, that <image> means the remainder of x after dividing it by y.

Input

The first line of the input contains two integers n and k (1 ≤ n, k ≤ 1 000 000) — the number of ancient integers and value k that is chosen by Pari.

The second line contains n integers c1, c2, ..., cn (1 ≤ ci ≤ 1 000 000).

Output

Print "Yes" (without quotes) if Arya has a winning strategy independent of value of x, or "No" (without quotes) otherwise.

Examples

Input

4 5
2 3 5 12


Output

Yes


Input

2 7
2 3


Output

No

Note

In the first sample, Arya can understand <image> because 5 is one of the ancient numbers.

In the second sample, Arya can't be sure what <image> is. For example 1 and 7 have the same remainders after dividing by 2 and 3, but they differ in remainders after dividing by 7.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
const double PI = acos(-1);
const long long INF = (1LL << 60);
int a[1000005], was[1000005];
int main() {
  int n, k;
  scanf("%d%d", &n, &k);
  bool win = false;
  for (int i = 1; i <= n; i++) {
    scanf("%d", &a[i]);
    if (a[i] % k == 0) win = true;
    was[a[i]]++;
  }
  if (win) {
    puts("Yes");
    return 0;
  }
  for (long long i = 2; i * i <= k; i++) {
    long long cur = 1;
    while (k % i == 0) k /= i, cur *= i;
    bool flag = false;
    if (cur == 1) continue;
    for (long long j = 1; j * cur <= 1000000; j++) {
      if (was[j * cur]) {
        flag = true;
        break;
      }
    }
    if (!flag) {
      puts("No");
      return 0;
    }
  }
  if (k > 1) {
    bool flag = false;
    for (long long j = 1; j * k <= 1000000; j++) {
      if (was[j * k]) {
        flag = true;
        break;
      }
    }
    if (!flag) {
      puts("No");
      return 0;
    }
  }
  puts("Yes");
  return 0;
}