Problem: We know that prime numbers are positive integers that have exactly two distinct positive divisors. Similarly, we'll call a positive integer t Т-prime, if t has exactly three distinct positive divisors.

You are given an array of n positive integers. For each of them determine whether it is Т-prime or not.

Input

The first line contains a single positive integer, n (1 ≤ n ≤ 105), showing how many numbers are in the array. The next line contains n space-separated integers xi (1 ≤ xi ≤ 1012).

Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is advised to use the cin, cout streams or the %I64d specifier.

Output

Print n lines: the i-th line should contain "YES" (without the quotes), if number xi is Т-prime, and "NO" (without the quotes), if it isn't.

Examples

Input

3
4 5 6


Output

YES
NO
NO

Note

The given test has three numbers. The first number 4 has exactly three divisors — 1, 2 and 4, thus the answer for this number is "YES". The second number 5 has two divisors (1 and 5), and the third number 6 has four divisors (1, 2, 3, 6), hence the answer for them is "NO".

Solution (in PYTHON3):

Solution:
import sys
is_prime = [True]*(10**6+1)
is_prime[0]=is_prime[1] = False
p = 2
while p*p <= 10**6:
    if is_prime[p]:
        for n in range(p*p,10**6+1,p):
            is_prime[n] = False
    p += 1

n = int(sys.stdin.readline())
arr = [int(x) for x in sys.stdin.readline().split()]
for x in arr:
    d = int(x**(1/2))
    if d*d == x:
        if is_prime[int(d)] is True:
            print("YES")
        else:
            print("NO")
    else:
        print("NO")