Problem: We know that prime numbers are positive integers that have exactly two distinct positive divisors. Similarly, we'll call a positive integer t Т-prime, if t has exactly three distinct positive divisors.

You are given an array of n positive integers. For each of them determine whether it is Т-prime or not.

Input

The first line contains a single positive integer, n (1 ≤ n ≤ 105), showing how many numbers are in the array. The next line contains n space-separated integers xi (1 ≤ xi ≤ 1012).

Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is advised to use the cin, cout streams or the %I64d specifier.

Output

Print n lines: the i-th line should contain "YES" (without the quotes), if number xi is Т-prime, and "NO" (without the quotes), if it isn't.

Examples

Input

3
4 5 6


Output

YES
NO
NO

Note

The given test has three numbers. The first number 4 has exactly three divisors — 1, 2 and 4, thus the answer for this number is "YES". The second number 5 has two divisors (1 and 5), and the third number 6 has four divisors (1, 2, 3, 6), hence the answer for them is "NO".

Solution (in PYTHON):

Solution:
import math
x = input()
nums = map(int, raw_input().split())

def isPrime(n):
    primes = [True] * n

    primes[0] = False
    primes[1] = False

    for i in range(2, int(math.sqrt(n)) + 1):
        if primes[i] == 1:
            for j in range(i*i, n, i):
                primes[j] = False

    return primes

res = isPrime(int(math.sqrt(max(nums)))+1)
for n in nums:
    nsqrt = math.sqrt(n)
    if not nsqrt - int(nsqrt) and res[int(nsqrt)]:
        print 'YES'
    else:
        print 'NO'