Problem: You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

* It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:


N


Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:


h n w

Examples

Input

2


Output

1 2 2


Input

3485


Output

872 1012974 1539173474040


Input

4664


Output

3498 3498 3498

Solution (in JAVA):

Solution:
import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        long n = sc.nextInt();
        OUT:for (long i = 1; i <= 3500; i++) {
            for (long j = 1; j <= 3500; j++) {
                long k = Math.round((double)(n*i*j)/(double)(4*i*j-n*i-n*j));
                if(k>0&&4*i*j*k==n*(i*j+j*k+k*i)){
                    System.out.printf("%d %d %d",i,j,k);
                    break OUT;
                }
            }
        }
        sc.close();
    }
}