Problem: You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

* It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:


N


Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:


h n w

Examples

Input

2


Output

1 2 2


Input

3485


Output

872 1012974 1539173474040


Input

4664


Output

3498 3498 3498

Solution (in JAVA):

Solution:
import java.util.Scanner;

public class Main {

	public static final long MAX = 3500;

	public static void main(String args[]) {

		Scanner sc = new Scanner(System.in);
		long N = sc.nextLong();

		for(long h=1;h<=MAX;h++) {
			for(long n=1;n<=MAX;n++) {
				long child = N*h*n;
				long mother = 4*h*n - N*n - N*h;

				if(mother != 0 && child%mother == 0 && child/mother > 0) {
					System.out.println(h + " " + n + " " + (child/mother));
					return;
				}

			}
		}
	}
}