Problem: Polycarpus got hold of a family tree. The found tree describes the family relations of n people, numbered from 1 to n. Every person in this tree has at most one direct ancestor. Also, each person in the tree has a name, the names are not necessarily unique.

We call the man with a number a a 1-ancestor of the man with a number b, if the man with a number a is a direct ancestor of the man with a number b.

We call the man with a number a a k-ancestor (k > 1) of the man with a number b, if the man with a number b has a 1-ancestor, and the man with a number a is a (k - 1)-ancestor of the 1-ancestor of the man with a number b.

In the tree the family ties do not form cycles. In other words there isn't a person who is his own direct or indirect ancestor (that is, who is an x-ancestor of himself, for some x, x > 0).

We call a man with a number a the k-son of the man with a number b, if the man with a number b is a k-ancestor of the man with a number a.

Polycarpus is very much interested in how many sons and which sons each person has. He took a piece of paper and wrote m pairs of numbers vi, ki. Help him to learn for each pair vi, ki the number of distinct names among all names of the ki-sons of the man with number vi.

Input

The first line of the input contains a single integer n (1 ≤ n ≤ 105) — the number of people in the tree. Next n lines contain the description of people in the tree. The i-th line contains space-separated string si and integer ri (0 ≤ ri ≤ n), where si is the name of the man with a number i, and ri is either the number of the direct ancestor of the man with a number i or 0, if the man with a number i has no direct ancestor. 

The next line contains a single integer m (1 ≤ m ≤ 105) — the number of Polycarpus's records. Next m lines contain space-separated pairs of integers. The i-th line contains integers vi, ki (1 ≤ vi, ki ≤ n).

It is guaranteed that the family relationships do not form cycles. The names of all people are non-empty strings, consisting of no more than 20 lowercase English letters.

Output

Print m whitespace-separated integers — the answers to Polycarpus's records. Print the answers to the records in the order, in which the records occur in the input.

Examples

Input

6
pasha 0
gerald 1
gerald 1
valera 2
igor 3
olesya 1
5
1 1
1 2
1 3
3 1
6 1


Output

2
2
0
1
0


Input

6
valera 0
valera 1
valera 1
gerald 0
valera 4
kolya 4
7
1 1
1 2
2 1
2 2
4 1
5 1
6 1


Output

1
0
0
0
2
0
0

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.*;

public class Template implements Runnable {

    BufferedReader in;
    PrintWriter out;
    StringTokenizer tok = new StringTokenizer("");

    void init() throws FileNotFoundException {
        try {
            in = new BufferedReader(new FileReader("input.txt"));
            out = new PrintWriter("output.txt");
        } catch (Exception e) {
            in = new BufferedReader(new InputStreamReader(System.in));
            out = new PrintWriter(System.out);
        }
    }

    class GraphBuilder {
        int n, m;
        int[] x, y;
        int index;
        int[] size;


        GraphBuilder(int n, int m) {
            this.n = n;
            this.m = m;
            x = new int[m];
            y = new int[m];
            size = new int[n];
        }

        void add(int u, int v) {
            x[index] = u;
            y[index] = v;
            size[u]++;
            size[v]++;
            index++;
        }

        int[][] build() {
            int[][] graph = new int[n][];
            for (int i = 0; i < n; i++) {
                graph[i] = new int[size[i]];
            }
            for (int i = index - 1; i >= 0; i--) {
                int u = x[i];
                int v = y[i];
                graph[u][--size[u]] = v;
                graph[v][--size[v]] = u;
            }
            return graph;
        }
    }

    String readString() throws IOException {
        while (!tok.hasMoreTokens()) {
            try {
                tok = new StringTokenizer(in.readLine());
            } catch (Exception e) {
                return null;
            }
        }
        return tok.nextToken();
    }

    int readInt() throws IOException {
        return Integer.parseInt(readString());
    }

    int[] readIntArray(int size) throws IOException {
        int[] res = new int[size];
        for (int i = 0; i < size; i++) {
            res[i] = readInt();
        }
        return res;
    }

    long[] readLongArray(int size) throws IOException {
        long[] res = new long[size];
        for (int i = 0; i < size; i++) {
            res[i] = readLong();
        }
        return res;
    }

    long readLong() throws IOException {
        return Long.parseLong(readString());
    }

    double readDouble() throws IOException {
        return Double.parseDouble(readString());
    }

    <T> List<T>[] createGraphList(int size) {
        List<T>[] list = new List[size];
        for (int i = 0; i < size; i++) {
            list[i] = new ArrayList<>();
        }
        return list;
    }

    public static void main(String[] args) {
        new Template().run();
        // new Thread(null, new Template(), "", 1l * 200 * 1024 * 1024).start();
    }

    long timeBegin, timeEnd;

    void time() {
        timeEnd = System.currentTimeMillis();
        System.err.println("Time = " + (timeEnd - timeBegin));
    }

    long memoryTotal, memoryFree;

    void memory() {
        memoryFree = Runtime.getRuntime().freeMemory();
        System.err.println("Memory = " + ((memoryTotal - memoryFree) >> 10)
                + " KB");
    }

    public void run() {
        try {
            timeBegin = System.currentTimeMillis();
            memoryTotal = Runtime.getRuntime().freeMemory();
            init();
            solve();
            out.close();
            if (System.getProperty("ONLINE_JUDGE") == null) {
                time();
                memory();
            }
        } catch (Exception e) {
            e.printStackTrace();
            System.exit(-1);
        }
    }

    HashMap<String, Integer> map = new HashMap<>();


    int[] name;
    List<Integer>[] childs;

    int[] tin;
    int[] tout;
    int time;

    List<Integer>[] layers;
    int[] he;

    void dfs(int x, int h) {
        he[x] = h;
        layers[h].add(x);
        tin[x] = time++;
        for (int y : childs[x]) {
            dfs(y, h + 1);
        }
        tout[x] = time++;
    }

    class Query implements Comparable<Query> {
        int l,  r;
        int index;

        public Query(int l, int r, int index) {
            this.l = l;
            this.r = r;
            this.index = index;
        }

        @Override
        public int compareTo(Query o) {
            if (l != o.l) return l - o.l;
            return r - o.r;
        }
    }

    void solve() throws IOException {
        int n = readInt() + 1;
        childs = createGraphList(n);
        int root = 0;
        name = new int[n];
        tin = new int[n];
        tout = new int[n];
        he = new int[n];
        for (int i = 0; i < n - 1; i++) {
            String nm = readString();
            int p = readInt();
            if (!map.containsKey(nm)) {
                map.put(nm, map.size());
            }
            name[i + 1] = map.get(nm);
            childs[p].add(i + 1);
        }
        layers = createGraphList(n * 2);
        dfs(root, 0);

        int m = readInt();
        List<Query>[] queries = createGraphList(n * 2);
        int[] answer = new int[m];
        for (int i = 0; i < m; i++) {
            int v = readInt();
            int k = readInt();

            List<Integer> targetLayer = layers[he[v] + k];
            int li = findLeftChild(targetLayer, v);
            int ri = findRightChild(targetLayer, v);
            if (li > ri) continue;
            queries[he[v] + k].add(new Query(li, ri, i));
        }
        for (int l = 0; l < queries.length; l++) {
            solveForLayer(layers[l], queries[l], answer);
        }
        for (int x : answer) {
            out.println(x);
        }
    }

    void solveForLayer(List<Integer> layer, List<Query> queries, int[] ans) {
        HashMap<Integer, ArrayDeque<Integer>> map = new HashMap<>();
        for (int i = 0; i < layer.size(); i++) {
            int v = layer.get(i);
            if (!map.containsKey(name[v])) {
                map.put(name[v], new ArrayDeque<>());
            }
            map.get(name[v]).add(i);
        }
        BIT bit = new BIT(layer.size());
        for (Map.Entry<Integer, ArrayDeque<Integer>> entry : map.entrySet()) {
            bit.update(entry.getValue().peek(), 1);
        }
        Collections.sort(queries);
        ArrayDeque<Query> deq = new ArrayDeque<>();
        deq.addAll(queries);

        for (int i = 0; i < layer.size(); i++) {
            int v = layer.get(i);
            while (deq.size() > 0 && deq.peek().l == i) {
                Query query = deq.poll();
                ans[query.index] = bit.get(query.r);
            }
            ArrayDeque<Integer> d = map.get(name[v]);
            d.poll();
            bit.update(i, -1);
            if (d.size() > 0) {
                bit.update(d.peek(), 1);
            }
        }
    }

    int findLeftChild(List<Integer> list, int root) {
        int l = 0;
        int r = list.size() - 1;
        int answer = Integer.MAX_VALUE;
        while (l <= r) {
            int mid = (l + r) >> 1;
            int x = list.get(mid);

            if (tin[x] >= tin[root] && tout[x] <= tout[root]) {
                answer = mid;
                r = mid - 1;
            } else if (tout[x] < tin[root]) {
                l = mid + 1;
            } else {
                r = mid - 1;
            }
        }
        return answer;
    }

    int findRightChild(List<Integer> list, int root) {
        int l = 0;
        int r = list.size() - 1;
        int answer = Integer.MIN_VALUE;
        while (l <= r) {
            int mid = (l + r) >> 1;
            int x = list.get(mid);

            if (tin[x] >= tin[root] && tout[x] <= tout[root]) {
                answer = mid;
                l = mid + 1;
            } else if (tout[x] < tin[root]) {
                l = mid + 1;
            } else {
                r = mid - 1;
            }
        }
        return answer;
    }


    class BIT {
        int[] data;

        BIT(int n) {
            data = new int[n];
        }

        void update(int at, int diff) {
            while (at < data.length) {
                data[at] += diff;
                at = at | (at + 1);
            }
        }

        int get(int at) {
            int res = 0;
            while (at >= 0) {
                res += data[at];
                at = (at & (at + 1)) - 1;
            }
            return res;
        }
    }

}