Problem: We know that prime numbers are positive integers that have exactly two distinct positive divisors. Similarly, we'll call a positive integer t Т-prime, if t has exactly three distinct positive divisors.

You are given an array of n positive integers. For each of them determine whether it is Т-prime or not.

Input

The first line contains a single positive integer, n (1 ≤ n ≤ 105), showing how many numbers are in the array. The next line contains n space-separated integers xi (1 ≤ xi ≤ 1012).

Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is advised to use the cin, cout streams or the %I64d specifier.

Output

Print n lines: the i-th line should contain "YES" (without the quotes), if number xi is Т-prime, and "NO" (without the quotes), if it isn't.

Examples

Input

3
4 5 6


Output

YES
NO
NO

Note

The given test has three numbers. The first number 4 has exactly three divisors — 1, 2 and 4, thus the answer for this number is "YES". The second number 5 has two divisors (1 and 5), and the third number 6 has four divisors (1, 2, 3, 6), hence the answer for them is "NO".

Solution (in PYTHON3):

Solution:
def sieve(n):
    is_prime = [True for i in range(n)]
    is_prime[0] = is_prime[1] = False
    primes = []
    for i in range(2, n):
        if not is_prime[i]:
            continue
        primes.append(i)
        j = i ** 2
        while j < n:
            is_prime[j] = False
            j += i
    
    return primes

primes = sieve(10 ** 6)
e_nums = {i**2 for i in primes}

n = int(input())
tests = input().split()
for i in range(len(tests)):
    tests[i] = int(tests[i])

for test in tests:
    if test in e_nums:
        print("YES")
    else:
        print("NO")