Problem: You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

* It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:


N


Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:


h n w

Examples

Input

2


Output

1 2 2


Input

3485


Output

872 1012974 1539173474040


Input

4664


Output

3498 3498 3498

Solution (in CPP):

Solution:
#include<cstdio>
using namespace std;
int main()
{
	long long n,a,b,c;
	scanf("%lld",&n);
	for(a=1ll;a<=3500ll;a++)
		for(b=1ll;b<=3500ll;b++){
			if(4ll*a*b-n*a-n*b!=0ll)
			if((n*a*b)%(4ll*a*b-n*a-n*b)==0ll&&(n*a*b)/(4ll*a*b-n*a-n*b)>0ll&&(n*a*b)/(4ll*a*b-n*a-n*b)<=3500){
				printf("%lld %lld %lld\n",a,b,(n*a*b)/(4ll*a*b-n*a-n*b));
				return 0;
			}
		}
	return 0;
}