Problem: You are given an integer N.

Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.

If there are multiple solutions, any of them will be accepted.

Constraints

* It is guaranteed that, for the given integer N, there exists a solution such that h,n,w \leq 3500.

Inputs

Input is given from Standard Input in the following format:


N


Outputs

Print a triple of positive integers h, n and w that satisfies the condition, in the following format:


h n w

Examples

Input

2


Output

1 2 2


Input

3485


Output

872 1012974 1539173474040


Input

4664


Output

3498 3498 3498

Solution (in CPP):

Solution:
#include <bits/stdc++.h>

using namespace std;
#define ll long long
#define int ll
#define m_p make_pair


int32_t main() 
{
	int n;
	cin >> n;
	
	for (int a=1;a<=3500;a++)
	{
		//cout << a << endl;
		for (int b=1;b<=3500;b++)
			if (4*a*b-n*a-n*b > 0)
				if ((n*a*b)%(4*a*b-n*a-n*b) == 0)
				{
					return cout << a << " "<< b << " "<<n*a*b/(4*a*b-n*a-n*b),0;
				}
			
	}

    return 0;
}