Problem: You are given a correct solution of the sudoku puzzle. If you don't know what is the sudoku, you can read about it [here](http://tiny.cc/636xmz).

The picture showing the correct sudoku solution:

<image>

Blocks are bordered with bold black color.

Your task is to change at most 9 elements of this field (i.e. choose some 1 ≤ i, j ≤ 9 and change the number at the position (i, j) to any other number in range [1; 9]) to make it anti-sudoku. The anti-sudoku is the 9 × 9 field, in which:

  * Any number in this field is in range [1; 9]; 
  * each row contains at least two equal elements; 
  * each column contains at least two equal elements; 
  * each 3 × 3 block (you can read what is the block in the link above) contains at least two equal elements. 



It is guaranteed that the answer exists.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases. Then t test cases follow.

Each test case consists of 9 lines, each line consists of 9 characters from 1 to 9 without any whitespaces — the correct solution of the sudoku puzzle.

Output

For each test case, print the answer — the initial field with at most 9 changed elements so that the obtained field is anti-sudoku. If there are several solutions, you can print any. It is guaranteed that the answer exists.

Example

Input


1
154873296
386592714
729641835
863725149
975314628
412968357
631457982
598236471
247189563


Output


154873396
336592714
729645835
863725145
979314628
412958357
631457992
998236471
247789563

Solution (in PYTHON3):

Solution:
s1=[]
for i in range(1,10):
    s1.append(str(i))
t=int(input())
for i in range(t):
    s=[]
    for j in range(9):
        y=input().rstrip()
        y=[ i for i in y]
        s.append(y)
    for i in s1:
        if s[0][0]!=i:
            s[0][0]=i
            break
    for i in s1:
        if s[1][3]!=i:
            s[1][3]=i
            break
    for i in s1:
        if s[2][6]!=i:
            s[2][6]=i
            break
    for i in s1:
        if s[3][1]!=i:
            s[3][1]=i
            break
    for i in s1:
        if s[4][4]!=i:
            s[4][4]=i
            break
    for i in s1:
        if s[5][7]!=i:
            s[5][7]=i
            break
    for i in s1:
        if s[6][2]!=i:
            s[6][2]=i
            break
    for i in s1:
        if s[7][5]!=i:
            s[7][5]=i
            break
    for i in s1:
        if s[8][8]!=i:
            s[8][8]=i
            break
    for i in s:
        print(''.join(i))