Problem: Find an n × n matrix with different numbers from 1 to n2, so the sum in each row, column and both main diagonals are odd.

Input

The only line contains odd integer n (1 ≤ n ≤ 49).

Output

Print n lines with n integers. All the integers should be different and from 1 to n2. The sum in each row, column and both main diagonals should be odd.

Examples

Input

1


Output

1


Input

3


Output

2 1 4
3 5 7
6 9 8

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int main() {
  int a, b = 1, c = 2, o = 1, j, k;
  cin >> a;
  int p = a / 2;
  for (k = 0; k < a; k++) {
    for (j = 0; j < p; j++) {
      cout << c << " ";
      c += 2;
    }
    for (j = 0; j < a - p * 2; j++) {
      cout << b << " ";
      b += 2;
    }
    for (int j = 0; j < p; j++) {
      cout << c << " ";
      c += 2;
    }
    cout << endl;
    if (p == 0) o = 0;
    if (o == 0)
      p++;
    else
      p--;
  }
  return 0;
}