Problem: Find an n × n matrix with different numbers from 1 to n2, so the sum in each row, column and both main diagonals are odd.

Input

The only line contains odd integer n (1 ≤ n ≤ 49).

Output

Print n lines with n integers. All the integers should be different and from 1 to n2. The sum in each row, column and both main diagonals should be odd.

Examples

Input

1


Output

1


Input

3


Output

2 1 4
3 5 7
6 9 8

Solution (in PYTHON3):

Solution:
n=int(input())
magic=int((n-1)/2)
x = []
for t in range(magic, -1, -1):
    x.append(t*'*'+'D'*(n-2*t)+t*'*')
for u in range(1, magic+1):
    x.append(u*'*'+'D'*(n-2*u)+u*'*')

no = 1
ne = 2
for i in range(n):
    for j in range(n):
        if (x[i][j] == 'D'):
            print(no, end = ' ')
            no += 2
        else:
            print(ne, end = ' ')
            ne += 2
    print()