Problem: Find an n × n matrix with different numbers from 1 to n2, so the sum in each row, column and both main diagonals are odd.

Input

The only line contains odd integer n (1 ≤ n ≤ 49).

Output

Print n lines with n integers. All the integers should be different and from 1 to n2. The sum in each row, column and both main diagonals should be odd.

Examples

Input

1


Output

1


Input

3


Output

2 1 4
3 5 7
6 9 8

Solution (in PYTHON3):

Solution:
#!/usr/bin/env python3

import math

n=int(input())
m=n//2
mx=m
my=m
a=[[0 for x in range(n)] for y in range(n)]

a[mx][my]=1
for dm in range(1, m+1):
    base=int(math.pow(2*(dm-1)+1, 2))+1
    for x in range(0,2*dm):
        a[my-dm][mx-dm+x+((dm+1)%2)]=base+x
        a[my-dm+x+((dm+1)%2)][mx+dm]=base+2*dm+x
        a[my+dm][mx+dm-x-((dm+1)%2)]=base+4*dm+x
        a[my+dm-x-((dm+1)%2)][mx-dm]=base+6*dm+x

for y in range(0, n):
    print(' '.join(map(str, a[y])))