Problem: We have a pyramid with N steps, built with blocks. The steps are numbered 1 through N from top to bottom. For each 1≤i≤N, step i consists of 2i-1 blocks aligned horizontally. The pyramid is built so that the blocks at the centers of the steps are aligned vertically.

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A pyramid with N=4 steps

Snuke wrote a permutation of (1, 2, ..., 2N-1) into the blocks of step N. Then, he wrote integers into all remaining blocks, under the following rule:

* The integer written into a block b must be equal to the median of the three integers written into the three blocks directly under b, or to the lower left or lower right of b.



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Writing integers into the blocks

Afterwards, he erased all integers written into the blocks. Now, he only remembers that the integer written into the block of step 1 was x.

Construct a permutation of (1, 2, ..., 2N-1) that could have been written into the blocks of step N, or declare that Snuke's memory is incorrect and such a permutation does not exist.

Constraints

* 2≤N≤10^5
* 1≤x≤2N-1

Input

The input is given from Standard Input in the following format:


N x


Output

If no permutation of (1, 2, ..., 2N-1) could have been written into the blocks of step N, print `No`.

Otherwise, print `Yes` in the first line, then print 2N-1 lines in addition.

The i-th of these 2N-1 lines should contain the i-th element of a possible permutation.

Examples

Input

4 4


Output

Yes
1
6
3
7
4
5
2


Input

2 1


Output

No

Solution (in PYTHON3):

Solution:
N, X = map(int, input().split())
if N == 2:
    if X != 2:
        print('No')
    else:
        print('Yes')
        print(1)
        print(2)
        print(3)
elif X == 1 or X == 2*N-1:
    print('No')
else:
    print('Yes')
    used = [False]*(2*N-1)
    if X >= N:
        p1 = 2*N-1
        s1 = 1
        s2 = 2
    else:
        p1 = 1
        s1 = 2*N-1
        s2 = 2*N-2
    a = 0
    for k in range(1, 2*N):
        if a == N-2:
            print(s1)
            print(X)
            print(p1)
            print(s2)
            a += 4
        if k in [X, p1, s1, s2]:
            continue
        print(k)
        a += 1