Problem: Today Pari and Arya are playing a game called Remainders.

Pari chooses two positive integer x and k, and tells Arya k but not x. Arya have to find the value <image>. There are n ancient numbers c1, c2, ..., cn and Pari has to tell Arya <image> if Arya wants. Given k and the ancient values, tell us if Arya has a winning strategy independent of value of x or not. Formally, is it true that Arya can understand the value <image> for any positive integer x?

Note, that <image> means the remainder of x after dividing it by y.

Input

The first line of the input contains two integers n and k (1 ≤ n, k ≤ 1 000 000) — the number of ancient integers and value k that is chosen by Pari.

The second line contains n integers c1, c2, ..., cn (1 ≤ ci ≤ 1 000 000).

Output

Print "Yes" (without quotes) if Arya has a winning strategy independent of value of x, or "No" (without quotes) otherwise.

Examples

Input

4 5
2 3 5 12


Output

Yes


Input

2 7
2 3


Output

No

Note

In the first sample, Arya can understand <image> because 5 is one of the ancient numbers.

In the second sample, Arya can't be sure what <image> is. For example 1 and 7 have the same remainders after dividing by 2 and 3, but they differ in remainders after dividing by 7.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int n, k, c[1000010], prime[1000010], a[30], len, tot;
bool check[1000010];
int main() {
  scanf("%d%d", &n, &k);
  for (int i = 1; i <= n; i++) scanf("%d", &c[i]);
  for (int i = 2; i <= k; i++) {
    if (!check[i]) prime[++tot] = i;
    for (int j = 1; j <= tot; j++) {
      if ((long long)prime[j] * i > k) break;
      check[prime[j] * i] = 1;
      if (!(i % prime[j])) break;
    }
  }
  for (int i = 1; i <= tot; i++) {
    int mul = 1;
    for (; !(k % prime[i]);) {
      mul *= prime[i];
      k /= prime[i];
    }
    a[++len] = mul;
  }
  for (int i = 1; i <= len; i++) {
    bool bo = 0;
    for (int j = 1; j <= n; j++)
      if (!(c[j] % a[i])) {
        bo = 1;
        break;
      }
    if (!bo) {
      printf("No");
      return 0;
    }
  }
  printf("Yes");
  return 0;
}