Problem: You are given a correct solution of the sudoku puzzle. If you don't know what is the sudoku, you can read about it [here](http://tiny.cc/636xmz).

The picture showing the correct sudoku solution:

<image>

Blocks are bordered with bold black color.

Your task is to change at most 9 elements of this field (i.e. choose some 1 ≤ i, j ≤ 9 and change the number at the position (i, j) to any other number in range [1; 9]) to make it anti-sudoku. The anti-sudoku is the 9 × 9 field, in which:

  * Any number in this field is in range [1; 9]; 
  * each row contains at least two equal elements; 
  * each column contains at least two equal elements; 
  * each 3 × 3 block (you can read what is the block in the link above) contains at least two equal elements. 



It is guaranteed that the answer exists.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases. Then t test cases follow.

Each test case consists of 9 lines, each line consists of 9 characters from 1 to 9 without any whitespaces — the correct solution of the sudoku puzzle.

Output

For each test case, print the answer — the initial field with at most 9 changed elements so that the obtained field is anti-sudoku. If there are several solutions, you can print any. It is guaranteed that the answer exists.

Example

Input


1
154873296
386592714
729641835
863725149
975314628
412968357
631457982
598236471
247189563


Output


154873396
336592714
729645835
863725145
979314628
412958357
631457992
998236471
247789563

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int a[200005];
int max(int a, int b) {
  if (a > b)
    return a;
  else
    return b;
}
int min(int a, int b) {
  if (a < b)
    return a;
  else
    return b;
}
vector<string> sd;
int main() {
  int t;
  cin >> t;
  while (t--) {
    sd.clear();
    for (int i = 0; i < 9; i++) {
      string tmp;
      cin >> tmp;
      sd.push_back(tmp);
    }
    for (int i = 0; i < 9; i++) {
      sd[0][0] = sd[0][1];
      sd[1][3] = sd[1][4];
      sd[2][6] = sd[2][7];
      sd[3][1] = sd[3][2];
      sd[4][4] = sd[4][5];
      sd[5][7] = sd[5][8];
      sd[6][2] = sd[6][1];
      sd[7][5] = sd[7][4];
      sd[8][8] = sd[8][7];
    }
    for (int i = 0; i < sd.size(); i++) {
      cout << sd[i] << "\n";
    }
  }
  return 0;
}