Problem: Range Count Query

Given the sequence a_1, a_2, .., a_N.

In the query, answer the number of terms whose value is l or more and r or less.

input


N Q
a_1 a_2 ... a_N
l_1 r_1
l_2 r_2
::
l_q r_q


output


ans_1
ans_2
::
ans_q


On line i, output the answer to the i-th query, that is, the number of j such as l_i \ leq a_j \ leq r_i.

Constraint

* 1 \ leq N, Q \ leq 10 ^ 5
* 1 \ leq a_i \ leq 10 ^ 9
* 1 \ leq l_i \ leq r_i \ leq 10 ^ 9



Input example


6 3
8 6 9 1 2 1
2 8
1 7
3 5


Output example


3
Four
0






Example

Input

6 3
8 6 9 1 2 1
2 8
1 7
3 5


Output

3
4
0

Solution (in CPP):

Solution:
//
//  main.cpp
//  test130
//
//  Created by  on 2019/06/16.
//  Copyright © 2 All rights reserved.
//
//
//  main.cpp
//  new
//
//  Created on 2019/06/09.
//  Copyright  All rights reserved.
//

// C++ includes used for precompiling -*- C++ -*-

// Copyright (C) 2003-2013 Free Software Foundation, Inc.
//
// This file is part of the GNU ISO C++ Library.  This library is free
// software; you can redistribute it and/or modify it under the
// terms of the GNU General Public License as published by the
// Free Software Foundation; either version 3, or (at your option)
// any later version.

// This library is distributed in the hope that it will be useful,
// but WITHOUT ANY WARRANTY; without even the implied warranty of
// MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
// GNU General Public License for more details.

// Under Section 7 of GPL version 3, you are granted additional
// permissions described in the GCC Runtime Library Exception, version
// 3.1, as published by the Free Software Foundation.

// You should have received a copy of the GNU General Public License and
// a copy of the GCC Runtime Library Exception along with this program;
// see the files COPYING3 and COPYING.RUNTIME respectively.  If not, see
// <http://www.gnu.org/licenses/>.

/** @file stdc++.h
 *  This is an implementation file for a precompiled header.
 */

// 17.4.1.2 Headers

// C
#ifndef _GLIBCXX_NO_ASSERT
#include <cassert>
#endif
#include <cctype>
#include <cerrno>
#include <cfloat>
#include <ciso646>
#include <climits>
#include <clocale>
#include <cmath>
#include <csetjmp>
#include <csignal>
#include <cstdarg>
#include <cstddef>
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <ctime>

#if __cplusplus >= 201103L
#include <ccomplex>
#include <cfenv>
#include <cinttypes>
#include <cstdbool>
#include <cstdint>
#include <ctgmath>
#include <cwchar>
#include <cwctype>
#endif

// C++
#include <algorithm>
#include <bitset>
#include <complex>
#include <deque>
#include <exception>
#include <fstream>
#include <functional>
#include <iomanip>
#include <ios>
#include <iosfwd>
#include <iostream>
#include <istream>
#include <iterator>
#include <limits>
#include <list>
#include <locale>
#include <map>
#include <memory>
#include <new>
#include <numeric>
#include <ostream>
#include <queue>
#include <set>
#include <sstream>
#include <stack>
#include <stdexcept>
#include <streambuf>
#include <string>
#include <typeinfo>
#include <utility>
#include <valarray>
#include <vector>

#if __cplusplus >= 201103L
#include <array>
#include <atomic>
#include <chrono>
#include <condition_variable>
#include <forward_list>
#include <future>
#include <initializer_list>
#include <mutex>
#include <random>
#include <ratio>
#include <regex>
#include <scoped_allocator>
#include <system_error>
#include <thread>
#include <tuple>
#include <typeindex>
#include <type_traits>
#include <unordered_map>
#include <unordered_set>
#endif


#define f(i,n) for(int i=0;i<(n);i++)


#define inf (int)(3e18)
#define int long long
#define mod (int)(1000000007)
using namespace std;


int modpow(int x, int y, int m = mod) {
    int res = 1;
    while (y) {
        if (y % 2) {
            res *= x;
            res %= m;
        }
        x = x * x % mod;
        y /= 2;
    }
    return res;
}
bool prime(int x){
    for (int i=2; i<=sqrt(x); i++) {
        if (!(x%i)) {
            return false;
        }
    }
    return true;
}
double kyori(pair<int, int> f, pair<int, int> s){
    double ans=0;
    double t = fabs(f.first-s.first);
    double y = fabs(f.second-s.second);
    ans=sqrt(t*t+y*y);
    return ans;
}
int gcd(int x,int y){
    if (y==0) {
        return x;
    }
    return gcd(y,x%y);
}

int n,ans,q,a[100004];
signed main(){
    cin>>n>>q;
    for (int i=0; i<n; i++) {
        cin>>a[i];
    }
    sort(a, a+n);
    for (int i=0; i<q; i++) {
        int l,r;
        cin>>l>>r;
        int hajime=lower_bound(a, a+n, l)-a;
        int owari=lower_bound(a, a+n, r)-a;
        for (int j=hajime; j>=0; j--) {
            if (a[j]==a[hajime]) {
                hajime=j;
            }else{
                break;
            }
        }
        if (a[owari]>r) {
            for (int j=owari; j>=0; j--) {
                if (a[j]<=r) {
                    owari=j;
                    break;
                }
            }
        }
        if (owari>=n) {
            owari=n-1;
        }
        cout<<owari-hajime+1<<endl;
    }
}