Problem: PolandBall is standing in a row with Many Other Balls. More precisely, there are exactly n Balls. Balls are proud of their home land — and they want to prove that it's strong.

The Balls decided to start with selecting exactly m groups of Balls, each consisting either of single Ball or two neighboring Balls. Each Ball can join no more than one group.

The Balls really want to impress their Enemies. They kindly asked you to calculate number of such divisions for all m where 1 ≤ m ≤ k. Output all these values modulo 998244353, the Enemies will be impressed anyway.

Input

There are exactly two numbers n and k (1 ≤ n ≤ 109, 1 ≤ k < 215), denoting the number of Balls and the maximim number of groups, respectively.

Output

You should output a sequence of k values. The i-th of them should represent the sought number of divisions into exactly i groups, according to PolandBall's rules.

Examples

Input

3 3


Output

5 5 1 

Input

1 1


Output

1 

Input

5 10


Output

9 25 25 9 1 0 0 0 0 0 

Note

In the first sample case we can divide Balls into groups as follows: 

{1}, {2}, {3}, {12}, {23}.

{12}{3}, {1}{23}, {1}{2}, {1}{3}, {2}{3}.

{1}{2}{3}.

Therefore, output is: 5 5 1.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
const int p = 998244353;
const int inv2 = 499122177;
const int MAXN = 140000;
inline long long read() {
  long long x = 0, f = 1;
  char ch = getchar();
  while (ch > '9' || ch < '0') {
    if (ch == '-') f = -1;
    ch = getchar();
  }
  do x = (x * 10 + ch - 48) % p, ch = getchar();
  while (ch >= '0' && ch <= '9');
  return (x * f % p + p) % p;
}
int n, k, r[MAXN];
long long c[MAXN] = {1, 6, 1};
long long s[MAXN], f[MAXN], g[MAXN];
long long fastpow(long long a, int b) {
  long long res = 1;
  a %= p;
  while (b) {
    if (b & 1) res = res * a % p;
    a = a * a % p;
    b >>= 1;
  }
  return res;
}
void NTT(long long *a, int N) {
  for (int i = 0; i < N; i++)
    if (i < r[i]) std::swap(a[i], a[r[i]]);
  for (int n = 2, m = 1; n <= N; m = n, n <<= 1) {
    long long g1 = fastpow(3, (p - 1) / n);
    for (int l = 0; l < N; l += n) {
      long long g = 1, t1, t2;
      for (int i = l; i < l + m; i++) {
        t1 = a[i], t2 = g * a[i + m] % p;
        a[i] = (t1 + t2) % p;
        a[i + m] = (t1 - t2 + p) % p;
        g = g * g1 % p;
      }
    }
  }
  return;
}
void INTT(long long *a, int N) {
  NTT(a, N);
  std::reverse(a + 1, a + N);
  int invN = fastpow(N, p - 2);
  for (int i = 0; i < N; i++) a[i] = a[i] * invN % p;
}
long long a1[MAXN], b1[MAXN];
void Inv(long long *a, long long *b, int n) {
  if (n == 1) return void(b[0] = fastpow(a[0], p - 2));
  Inv(a, b, (n + 1) >> 1);
  int N = 1, l = -1;
  while (N <= n << 1) N <<= 1, l++;
  for (int i = 1; i < N; i++) r[i] = (r[i >> 1] >> 1) | ((i & 1) << l);
  for (int i = 0; i < n; i++) a1[i] = a[i];
  for (int i = n; i < N; i++) a1[i] = 0;
  NTT(a1, N);
  NTT(b, N);
  for (int i = 0; i < N; i++)
    b[i] = ((b[i] << 1) % p + p - a1[i] * b[i] % p * b[i] % p) % p;
  INTT(b, N);
  for (int i = n; i < N; i++) b[i] = 0;
  return;
}
void Dervt(long long *a, long long *b, int n) {
  for (int i = 1; i < n; i++) b[i - 1] = a[i] * i % p;
  b[n - 1] = 0;
}
void Integ(long long *a, long long *b, int n) {
  for (int i = 1; i < n; i++) b[i] = a[i - 1] * fastpow(i, p - 2) % p;
  b[0] = 0;
}
long long f1[MAXN], f2[MAXN];
void Ln(long long *f, long long *g, int n) {
  memset(f1, 0, sizeof(f1));
  memset(f2, 0, sizeof(f2));
  Dervt(f, f1, n);
  Inv(f, f2, n);
  int N = 1, l = -1;
  while (N <= n << 1) N <<= 1, l++;
  for (int i = 1; i < N; i++) r[i] = (r[i >> 1] >> 1) | ((i & 1) << l);
  NTT(f1, N);
  NTT(f2, N);
  for (int i = 0; i < N; i++) f1[i] = f1[i] * f2[i] % p;
  INTT(f1, N);
  Integ(f1, g, n);
  return;
}
long long g1[MAXN];
void Exp(long long *f, long long *g, int n) {
  if (n == 1) return void(g[0] = 1);
  Exp(f, g, (n + 1) >> 1);
  Ln(g, g1, n);
  int N = 1, l = -1;
  while (N <= n << 1) N <<= 1, l++;
  for (int i = 1; i < N; i++) r[i] = (r[i >> 1] >> 1) | ((i & 1) << l);
  for (int i = 0; i < n; i++) f1[i] = f[i];
  for (int i = n; i < N; i++) g1[i] = f1[i] = 0;
  for (int i = 0; i < N; i++) f1[i] = ((f1[i] - g1[i]) % p + p) % p;
  f1[0] = (f1[0] + 1) % p;
  NTT(f1, N);
  NTT(g, N);
  for (int i = 0; i < N; i++) g[i] = f1[i] * g[i] % p;
  INTT(g, N);
  for (int i = n; i < N; i++) g[i] = 0;
  return;
}
long long lnf[MAXN];
void Pow(long long *f, long long *g, int n, int k) {
  Ln(f, lnf, n);
  for (int i = 0; i < n; i++) lnf[i] = lnf[i] * k % p;
  memset(g, 0, sizeof(g1));
  Exp(lnf, g, n);
  return;
}
int main() {
  n = read();
  int t = read();
  k = std::min(n, t);
  int N = 1, l = -1;
  while (N <= (k + 1) << 1) N <<= 1, l++;
  for (int i = 1; i < N; i++) r[i] = (r[i >> 1] >> 1) | ((i & 1) << l);
  Pow(c, s, k + 1, inv2 - 1);
  Pow(c, f, k + 1, inv2);
  f[0]++, f[1]++;
  for (int i = 0; i <= k; i++) f[i] = f[i] * inv2 % p;
  Pow(f, g, k + 1, n + 1);
  NTT(s, N);
  NTT(g, N);
  for (int i = 0; i < N; i++) s[i] = s[i] * g[i] % p;
  INTT(s, N);
  for (int i = 1; i <= k; i++) std::printf("%lld ", s[i]);
  for (int i = k + 1; i <= t; i++) std::printf("0 ");
  std::putchar('\n');
  return 0;
}