Problem: Today Pari and Arya are playing a game called Remainders.

Pari chooses two positive integer x and k, and tells Arya k but not x. Arya have to find the value <image>. There are n ancient numbers c1, c2, ..., cn and Pari has to tell Arya <image> if Arya wants. Given k and the ancient values, tell us if Arya has a winning strategy independent of value of x or not. Formally, is it true that Arya can understand the value <image> for any positive integer x?

Note, that <image> means the remainder of x after dividing it by y.

Input

The first line of the input contains two integers n and k (1 ≤ n, k ≤ 1 000 000) — the number of ancient integers and value k that is chosen by Pari.

The second line contains n integers c1, c2, ..., cn (1 ≤ ci ≤ 1 000 000).

Output

Print "Yes" (without quotes) if Arya has a winning strategy independent of value of x, or "No" (without quotes) otherwise.

Examples

Input

4 5
2 3 5 12


Output

Yes


Input

2 7
2 3


Output

No

Note

In the first sample, Arya can understand <image> because 5 is one of the ancient numbers.

In the second sample, Arya can't be sure what <image> is. For example 1 and 7 have the same remainders after dividing by 2 and 3, but they differ in remainders after dividing by 7.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int i, j, n, k, freq[1000005], x;
bool c[2005];
vector<int> primes, fact;
int main() {
  ios_base::sync_with_stdio(0);
  cin >> n >> k;
  for (i = 1; i <= n; ++i) cin >> x, freq[x] = 1;
  for (i = 2; i <= 2000; ++i)
    if (!c[i]) {
      primes.push_back(i);
      for (j = i + i; j <= 2000; j += i) c[j] = 1;
    }
  for (auto it : primes) {
    if (it * it > k) break;
    if (k % it) continue;
    int sum = 1;
    while (k % it == 0) k /= it, sum *= it;
    fact.push_back(sum);
  }
  if (k > 1) fact.push_back(k);
  for (auto it : fact) {
    bool ok = 0;
    for (i = it; i <= 1000000; i += it)
      if (freq[i]) ok = 1, i = 1e9;
    if (!ok) return cout << "No\n", 0;
  }
  cout << "Yes\n";
  return 0;
}