Problem: Find an n × n matrix with different numbers from 1 to n2, so the sum in each row, column and both main diagonals are odd.

Input

The only line contains odd integer n (1 ≤ n ≤ 49).

Output

Print n lines with n integers. All the integers should be different and from 1 to n2. The sum in each row, column and both main diagonals should be odd.

Examples

Input

1


Output

1


Input

3


Output

2 1 4
3 5 7
6 9 8

Solution (in PYTHON3):

Solution:
from collections import defaultdict
import sys

if __name__ == "__main__":
    #n, m = list(map(int, input().split()))
    n = int(input())
    table = [[0] * 100 for _ in range(100)]
    i, j = 0, n // 2
    for num in range(1, n * n + 1):
        table[i][j] = num
        if table[(i - 1 + n) % n][(j + 1 + n) % n] == 0:
            i = (i - 1 + n) % n
            j = (j + 1 + n) % n
        else:
            i = (i + 1 + n) % n       
    for i in range(n):
        print(' '.join([str(j) for j in table[i][:n]]))