Problem: Find an n × n matrix with different numbers from 1 to n2, so the sum in each row, column and both main diagonals are odd.

Input

The only line contains odd integer n (1 ≤ n ≤ 49).

Output

Print n lines with n integers. All the integers should be different and from 1 to n2. The sum in each row, column and both main diagonals should be odd.

Examples

Input

1


Output

1


Input

3


Output

2 1 4
3 5 7
6 9 8

Solution (in PYTHON3):

Solution:
sz = int(input())

odd_no = 1
even_no = 2

for z in range(sz):
	odds_to_print = sz - 2*int(abs(sz//2-z))
	evens_to_print = (sz - odds_to_print)//2
	while evens_to_print > 0:
		print(even_no, end= ' ')
		even_no+=2
		evens_to_print -= 1
	while odds_to_print > 0:
		print(odd_no, end = ' ')
		odd_no+=2
		odds_to_print -= 1
	odds_to_print = sz - 2*abs(sz//2-z)
	evens_to_print = (sz - odds_to_print)//2
	while evens_to_print > 0:
		print(even_no, end= ' ')
		even_no+=2
		evens_to_print -= 1
	print("")