Problem: Masha has n types of tiles of size 2 × 2. Each cell of the tile contains one integer. Masha has an infinite number of tiles of each type.

Masha decides to construct the square of size m × m consisting of the given tiles. This square also has to be a symmetric with respect to the main diagonal matrix, and each cell of this square has to be covered with exactly one tile cell, and also sides of tiles should be parallel to the sides of the square. All placed tiles cannot intersect with each other. Also, each tile should lie inside the square. See the picture in Notes section for better understanding.

Symmetric with respect to the main diagonal matrix is such a square s that for each pair (i, j) the condition s[i][j] = s[j][i] holds. I.e. it is true that the element written in the i-row and j-th column equals to the element written in the j-th row and i-th column.

Your task is to determine if Masha can construct a square of size m × m which is a symmetric matrix and consists of tiles she has. Masha can use any number of tiles of each type she has to construct the square. Note that she can not rotate tiles, she can only place them in the orientation they have in the input.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then t test cases follow.

The first line of the test case contains two integers n and m (1 ≤ n ≤ 100, 1 ≤ m ≤ 100) — the number of types of tiles and the size of the square Masha wants to construct.

The next 2n lines of the test case contain descriptions of tiles types. Types of tiles are written one after another, each type is written on two lines. 

The first line of the description contains two positive (greater than zero) integers not exceeding 100 — the number written in the top left corner of the tile and the number written in the top right corner of the tile of the current type. The second line of the description contains two positive (greater than zero) integers not exceeding 100 — the number written in the bottom left corner of the tile and the number written in the bottom right corner of the tile of the current type.

It is forbidden to rotate tiles, it is only allowed to place them in the orientation they have in the input.

Output

For each test case print the answer: "YES" (without quotes) if Masha can construct the square of size m × m which is a symmetric matrix. Otherwise, print "NO" (withtout quotes).

Example

Input


6
3 4
1 2
5 6
5 7
7 4
8 9
9 8
2 5
1 1
1 1
2 2
2 2
1 100
10 10
10 10
1 2
4 5
8 4
2 2
1 1
1 1
1 2
3 4
1 2
1 1
1 1


Output


YES
NO
YES
NO
YES
YES

Note

The first test case of the input has three types of tiles, they are shown on the picture below.

<image>

Masha can construct, for example, the following square of size 4 × 4 which is a symmetric matrix:

<image>

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.*;
import static java.util.Collections.*;
import static java.util.Scanner.*;
import static java.lang.Math.*;
import static java.util.Arrays.*;
public class Main extends Object {
    public static final String ANSI_RED = "\u001B[31m";
    public static final String ANSI_RESET = "\u001B[0m";
    static long startTime;
    static long endTime;
    static boolean [] prime ;
    static int M=(int)1e9+7;
    static long MM=M*M;
    static int MAX=Integer.MAX_VALUE;
    static int MIN=Integer.MIN_VALUE;
    static int SIZE = (int)1e9*2;
    static class FastReader{
        BufferedReader br;
        StringTokenizer st;

        public FastReader()
        {
            br = new BufferedReader(new
                    InputStreamReader(System.in));
        }

        String next()
        {
            while (st == null || !st.hasMoreElements())
            {
                try
                {
                    st = new StringTokenizer(br.readLine());
                }
                catch (IOException  e)
                {
                    e.printStackTrace();
                }
            }
            return st.nextToken();
        }

        int nextInt()
        {
            return Integer.parseInt(next());
        }

        long nextLong()
        {
            return Long.parseLong(next());
        }

        double nextDouble()
        {
            return Double.parseDouble(next());
        }

        String nextLine()
        {
            String str = "";
            try
            {
                str = br.readLine();
            }
            catch (IOException e)
            {
                e.printStackTrace();
            }
            return str;
        }
    }
    public static void revArray(int [] arr){
        int n =arr.length;
        for (int i = 0; i < n/2; i++) {
            int temp=arr[i];
            arr[i]=arr[n-i-1];
            arr[n-i-1]=temp;
        }
    }
    public static void revArray(long [] arr){
        int n =arr.length;
        for (int i = 0; i < n/2; i++) {
            long temp=arr[i];
            arr[i]=arr[n-i-1];
            arr[n-i-1]=temp;
        }
    }
    public static void revArray(Long [] arr){
        int n =arr.length;
        for (int i = 0; i < n/2; i++) {
            Long temp=arr[i];
            arr[i]=arr[n-i-1];
            arr[n-i-1]=temp;
        }
    }
    public static void revArray(Integer [] arr){
        int n =arr.length;
        for (int i = 0; i < n/2; i++) {
            Integer temp=arr[i];
            arr[i]=arr[n-i-1];
            arr[n-i-1]=temp;
        }
    }
    static void printArray(int[] arr)
    {
        int n = arr.length;
        for (int i = 0; i < n; ++i)
            System.out.print(arr[i] + " ");
        System.out.println();
    }
    static void printArray(long[] arr)
    {
        int n = arr.length;
        for (int i = 0; i < n; ++i)
            System.out.print(arr[i] + " ");
        System.out.println();
    }
    static void printArray(Integer[] arr)
    {
        int n = arr.length;
        for (int i = 0; i < n; ++i)
            System.out.print(arr[i] + " ");
        System.out.println();
    }
    static void printArray(Long[] arr)
    {
        int n = arr.length;
        for (int i = 0; i < n; ++i)
            System.out.print(arr[i] + " ");
        System.out.println();
    }
    static void yes(){
        System.out.println("YES");
    }
    static void no(){System.out.println("NO");}
    public static int lowerBound
            (Integer[] array, int length, int value) {
        // Returns the index of the value or
        // if there is no value, returns the closest to the left.
        int low=-1; // arr[low]<=tar
        int hi=length;//arr[hi]>tar
        while (low+1<hi){ // while pointers are not neighboring(low+1!=hi)
            int mid=(low+hi)/2;
            if(array[mid]<=value){
                low=mid;
            }
            else {
                hi=mid;
            }
        }
        return low;// if no such element, returns -1.
    }
    public static int upperBound(Integer[] array, int length, int value){
        // returns the index of the value or
        // if the value does not exist, returns the closest to the right
        int low=-1; // arr[low]<tar
        int hi=length;// arr[hi]>=tar
        while (low+1<hi){// Eventually, pointers should be adjacent.
            int mid=(low+hi)>>1;
            if(array[mid]>=value){
                hi=mid;
            }
            else low=mid;
        }
        return hi;
    }
    public  static  int binarySearch(Integer [] arr, int length, int value){
        // returns the index of the targeted value or -1 if there is no value.
        int low=0;
        int hi=length-1;
        int ans=-1;
        while (low<=hi){
            int mid=(low+hi)>>1;
            if(arr[mid]>value){
                hi=mid-1;
            }
            else if(arr[mid]<value){
                low=mid+1;
            }
            else {
                ans=mid;
                break;
            }
        }
        return ans;
    }
    public static int gcd(int a, int b){
        if (b == 0)
            return a;
        else return gcd(b, a % b);
    }
    public static long lcm(int a , int b){
        return a/gcd(a,b)*b;
    }
    public  static  int countDivs(int n ){
        int cn=0;
        int sqr = (int)Math.sqrt(n);
        for (int i = 1; i<=sqr ; ++i) {
            if(n%i==0){
                ++cn;
            }
        }
        cn*=2;
        if(sqr*sqr==n) cn--;
        return cn;

    }
    static void prime(int  x) {
        //sieve algorithm. nlog(log(n)).
        prime=new boolean[ (x+1)];
        Arrays.fill(prime,true);
        prime[0] = prime[1] = false;
        for (int  i = 2; i * i <= x ; i++)
            if (prime[i])
                for (int  j = i * i; j <= x; j += i)
                    prime[j] = false;
    }
    static int[] sum;
    static void cumulitiveSum( int [] arr){
        sum = new int[arr.length];
        sum[0]=arr[0];
        for (int i = 1; i <arr.length; i++) {
            sum[i]=arr[i]+sum[i-1];
        }
    }
    static boolean isEven(long x ){
        return x % 2 == 0;
    }
    static boolean isPrime(long x ){
        boolean flag = true;
        int sqr = (int)Math.sqrt(x);
        if(x<2) return false;
        for (int i = 2; i <=sqr; i++) {
            if(x%i==0){
                flag=false;
                break;
            }
        }
        return flag;
    }
    static long factorial( long x) {
        long total = 1;
        for (int i = 2; i <= x; i++)
            total *= i;
        return total;
    }
    static long power(long x, long n) {
        if (n == 0) {
            return 1;
        }
        long pow = power(x, n / 2L);
        if ((n & 1) == 1) {
            return (x * (pow) * (pow));
        }

        return (pow * pow);
    }
    static void decimalToRadix(){
        int num=sc.nextInt(),radix=sc.nextInt();
        StringBuilder s = new StringBuilder();
        while (num>0){
            int x=num%radix;
            if(x>9){
                s.append((char)('A'+x-10));
            }
            else s.append(x);
            num/=radix;
        }
        System.out.println(s.reverse());
    }
    static void radixToDecimal(){
        String num=sc.next();
        int radix=sc.nextInt();
        int n =num.length();
        long ans=0;
        for (int i = 0; i < n; i++) {
            int number =num.charAt(i)-'0';
            if(!(number>=0 && number<=9)){
                number+='0'+10-'A';
            }
            ans+=number*power(radix,n-1-i);
        }
        System.out.println(ans);
    }
    static void remAndNumber(){
        int  number=sc.nextInt(),radix=sc.nextInt();
        while (number>0) {
            System.out.println("Remainder: " + number%radix +" Number: " + number  );
            number /= radix;
        }

    }
    static void dg (String ss){
        System.out.println(ANSI_RED + ss + ANSI_RESET);
    }
    public static void main(String [] args) {
        startTime = System.currentTimeMillis();
        int T = sc.nextInt();while (T--!=0)
        {
            solve();
        }
        endTime = System.currentTimeMillis();
        long duration= endTime-startTime;
        // System.out.println(duration);
    }

    // static Scanner sc = new Scanner(System.in);
    static FastReader sc = new FastReader();
    // dg(String.valueOf());
    public static int swap(int... args) {
        return args[0];
    }
    static int countSetBits(int n)
    {
        int count = 0;
        while (n > 0) {
            count ++;
            n >>= 1;
        }
        return count;
    }
    public static void solve()  {
//////////////////////////////////////////////////////////////////////
     int n =sc.nextInt(),x=sc.nextInt();
     int a1,a2,a3,a4;
     String ans ="NO";
    boolean is1=false,is2=false;
     while (n--!=0){
         a1=sc.nextInt();a2=sc.nextInt();a3=sc.nextInt();a4=sc.nextInt();
         if(a2==a3){
             is1=true;
             is2=true;
         }
     }
     if(is1&&is2){
         ans="YES";
     }
        if(x%2!=0){
            ans="NO";
        }
        System.out.println(ans);
///////////////////////////////////////////////////////////////////////
    }

}