Problem: Find an n × n matrix with different numbers from 1 to n2, so the sum in each row, column and both main diagonals are odd.

Input

The only line contains odd integer n (1 ≤ n ≤ 49).

Output

Print n lines with n integers. All the integers should be different and from 1 to n2. The sum in each row, column and both main diagonals should be odd.

Examples

Input

1


Output

1


Input

3


Output

2 1 4
3 5 7
6 9 8

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int matrix[50][50];
void magic(int n) {
  int mid = n / 2;
  int even = 2;
  int odd = 1;
  for (int i = 0; i < n; i++) {
    int bound = min(i, n - i - 1);
    for (int j = 0; j < n; j++) {
      if (i != mid && j != mid && j >= bound && j < max(bound, n - bound)) {
        matrix[i][j] = even;
        even += 2;
      } else {
        matrix[i][j] = odd;
        odd += 2;
      }
    }
  }
}
int main() {
  int n = 0;
  cin >> n;
  magic(n);
  for (int i = 0; i < n; i++) {
    for (int j = 0; j < n; j++) {
      cout << matrix[i][j] << " ";
    }
    cout << endl;
  }
  return 0;
}