Problem: Find an n × n matrix with different numbers from 1 to n2, so the sum in each row, column and both main diagonals are odd.

Input

The only line contains odd integer n (1 ≤ n ≤ 49).

Output

Print n lines with n integers. All the integers should be different and from 1 to n2. The sum in each row, column and both main diagonals should be odd.

Examples

Input

1


Output

1


Input

3


Output

2 1 4
3 5 7
6 9 8

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int a[49][49];
int main() {
  int i = 1;
  int n;
  cin >> n;
  int x = n / 2;
  int y = 0;
  while (i <= n * n) {
    if (a[y][x] == 0) {
      a[y][x] = i;
      i++;
    } else {
      y += 2;
      y = y % n;
      x++;
      x = x % n;
      a[y][x] = i;
      i++;
    }
    y--;
    if (y < 0) y = n + y;
    x--;
    if (x < 0) x = n + x;
  }
  for (int i = 0; i < n; i++) {
    for (int j = 0; j < n; j++) cout << a[i][j] << ' ';
    cout << endl;
  }
}