Problem: We have a pyramid with N steps, built with blocks. The steps are numbered 1 through N from top to bottom. For each 1≤i≤N, step i consists of 2i-1 blocks aligned horizontally. The pyramid is built so that the blocks at the centers of the steps are aligned vertically.

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A pyramid with N=4 steps

Snuke wrote a permutation of (1, 2, ..., 2N-1) into the blocks of step N. Then, he wrote integers into all remaining blocks, under the following rule:

* The integer written into a block b must be equal to the median of the three integers written into the three blocks directly under b, or to the lower left or lower right of b.



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Writing integers into the blocks

Afterwards, he erased all integers written into the blocks. Now, he only remembers that the integer written into the block of step 1 was x.

Construct a permutation of (1, 2, ..., 2N-1) that could have been written into the blocks of step N, or declare that Snuke's memory is incorrect and such a permutation does not exist.

Constraints

* 2≤N≤10^5
* 1≤x≤2N-1

Input

The input is given from Standard Input in the following format:


N x


Output

If no permutation of (1, 2, ..., 2N-1) could have been written into the blocks of step N, print `No`.

Otherwise, print `Yes` in the first line, then print 2N-1 lines in addition.

The i-th of these 2N-1 lines should contain the i-th element of a possible permutation.

Examples

Input

4 4


Output

Yes
1
6
3
7
4
5
2


Input

2 1


Output

No

Solution (in PYTHON):

Solution:
def getPermutation(n, x):
    if x==1 or x==n*2-1:
        return None
    if n==2:
        return [1, 2, 3]
    if x==2:
        bar = [x+1, x-1, x, x+2]
    else:
        bar = [x-1, x+1, x, x-2]
    rem = [i for i in xrange(1, n*2) if i not in bar]
    return rem[:n-2]+bar+rem[n-2:]

def main():
    n, x = [int(i) for i in raw_input().strip().split()]
    res = getPermutation(n, x)
    if res is None:
        print 'No'
    else:
        print 'Yes'
        for i in res:
            print i

if __name__ == '__main__':
    main()