Problem: Today Pari and Arya are playing a game called Remainders.

Pari chooses two positive integer x and k, and tells Arya k but not x. Arya have to find the value <image>. There are n ancient numbers c1, c2, ..., cn and Pari has to tell Arya <image> if Arya wants. Given k and the ancient values, tell us if Arya has a winning strategy independent of value of x or not. Formally, is it true that Arya can understand the value <image> for any positive integer x?

Note, that <image> means the remainder of x after dividing it by y.

Input

The first line of the input contains two integers n and k (1 ≤ n, k ≤ 1 000 000) — the number of ancient integers and value k that is chosen by Pari.

The second line contains n integers c1, c2, ..., cn (1 ≤ ci ≤ 1 000 000).

Output

Print "Yes" (without quotes) if Arya has a winning strategy independent of value of x, or "No" (without quotes) otherwise.

Examples

Input

4 5
2 3 5 12


Output

Yes


Input

2 7
2 3


Output

No

Note

In the first sample, Arya can understand <image> because 5 is one of the ancient numbers.

In the second sample, Arya can't be sure what <image> is. For example 1 and 7 have the same remainders after dividing by 2 and 3, but they differ in remainders after dividing by 7.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
const int unplaced = 0;
int cnt[1000006];
int main() {
  ios_base::sync_with_stdio(false);
  cin.tie(0);
  int n, k;
  cin >> n >> k;
  for (int i = 0; i < n; i++) {
    int x;
    cin >> x;
    cnt[x]++;
  }
  bool fnf = true;
  for (int i = 2; i <= sqrt(k); i++) {
    if (k % i == 0) {
      int c = 1;
      while (k % i == 0) {
        c *= i;
        k /= i;
      }
      bool cool = false;
      for (int j = 1; j * c <= 1000001; j++) {
        if (cnt[j * c] >= 1) {
          cool = true;
          break;
        }
      }
      if (!cool) {
        fnf = false;
        break;
      }
    }
  }
  if (k > 1) {
    bool cool = false;
    for (int j = 1; j * k <= 1000001; j++) {
      if (cnt[j * k] >= 1) {
        cool = true;
        break;
      }
    }
    if (!cool) {
      fnf = false;
    }
  }
  if (fnf) {
    cout << "Yes" << '\n';
    ;
  } else {
    cout << "No" << '\n';
    ;
  }
  return unplaced;
}