Problem: Find an n × n matrix with different numbers from 1 to n2, so the sum in each row, column and both main diagonals are odd.

Input

The only line contains odd integer n (1 ≤ n ≤ 49).

Output

Print n lines with n integers. All the integers should be different and from 1 to n2. The sum in each row, column and both main diagonals should be odd.

Examples

Input

1


Output

1


Input

3


Output

2 1 4
3 5 7
6 9 8

Solution (in PYTHON3):

Solution:
n = int(input())
a = [[0] * n for i in range(n)]
cur = 1
sum = 0
x = n // 2
for i in range(n):
    a[x][i] = cur
    cur +=2
while(x != 0):
    x-=1
    sum+=1
    for i in range(sum, n - sum):
        a[x][i] = cur
        cur +=2
x = n // 2
sum = 0
while(x!=n-1):
    x+=1
    sum +=1
    for i in range(sum, n - sum):
        a[x][i] = cur
        cur +=2
cur = 2
for i in range(n):
    for j in range(n):
        if a[i][j] == 0:
            a[i][j] = cur
            cur += 2
    print(' '.join(map(str, a[i])))