Problem: You are given a convex polygon P with n distinct vertices p1, p2, ..., pn. Vertex pi has coordinates (xi, yi) in the 2D plane. These vertices are listed in clockwise order.

You can choose a real number D and move each vertex of the polygon a distance of at most D from their original positions.

Find the maximum value of D such that no matter how you move the vertices, the polygon does not intersect itself and stays convex.

Input

The first line has one integer n (4 ≤ n ≤ 1 000) — the number of vertices.

The next n lines contain the coordinates of the vertices. Line i contains two integers xi and yi ( - 109 ≤ xi, yi ≤ 109) — the coordinates of the i-th vertex. These points are guaranteed to be given in clockwise order, and will form a strictly convex polygon (in particular, no three consecutive points lie on the same straight line).

Output

Print one real number D, which is the maximum real number such that no matter how you move the vertices, the polygon stays convex.

Your answer will be considered correct if its absolute or relative error does not exceed 10 - 6.

Namely, let's assume that your answer is a and the answer of the jury is b. The checker program will consider your answer correct if <image>.

Examples

Input

4
0 0
0 1
1 1
1 0


Output

0.3535533906


Input

6
5 0
10 0
12 -4
10 -8
5 -8
3 -4


Output

1.0000000000

Note

Here is a picture of the first sample

<image>

Here is an example of making the polygon non-convex.

<image>

This is not an optimal solution, since the maximum distance we moved one point is  ≈ 0.4242640687, whereas we can make it non-convex by only moving each point a distance of at most  ≈ 0.3535533906.

Solution (in JAVA):

Solution:
/**
 * Created by Aminul on 4/16/2017.
 */

import java.io.*;
import java.util.*;
import java.awt.*;
import java.awt.geom.*;

public class CF7801D {
    public static int index;
    public static void main(String[] args)throws Exception {
        InputReader in = new InputReader(System.in);
        PrintWriter pw = new PrintWriter(new OutputStreamWriter(System.out));
        int n = in.nextInt();

        //Point2D.Double p[] = new Point2D.Double[n];
        double xx [] = new double[n];
        double yy [] = new double[n];

        for(int i = 0; i <= n-1; i++){
            double x = in.nextDouble(), y =  in.nextDouble();
           // p[i] = new Point2D.Double(x, y);
            xx[i] = x;
            yy[i] = y;
        }

        double min = 1e18;

        for(int i = 0; i < n; i++){
           // Line2D.Double l = new Line2D.Double(p[i], p[(i+2)%n]);
          //  double dist = l.ptLineDist(p[(i+1)%n]);

            double dist = LineToPointDistance2D(new double[]{xx[i], yy[i]}, new double[]{xx[(i+2)%n], yy[(i+2)%n]},
                    new double[]{xx[(i+1)%n], yy[(i+1)%n]}, true);

            min = Math.min(min, dist/2.0);
        }



        pw.println(min);

        pw.close();
    }

    //Compute the dot product AB . AC
    static double DotProduct(double[] pointA, double[] pointB, double[] pointC)
    {
        double[] AB = new double[2];
        double[] BC = new double[2];
        AB[0] = pointB[0] - pointA[0];
        AB[1] = pointB[1] - pointA[1];
        BC[0] = pointC[0] - pointB[0];
        BC[1] = pointC[1] - pointB[1];
        double dot = AB[0] * BC[0] + AB[1] * BC[1];

        return dot;
    }

    //Compute the cross product AB x AC
    static double CrossProduct(double[] pointA, double[] pointB, double[] pointC)
    {
        double[] AB = new double[2];
        double[] AC = new double[2];
        AB[0] = pointB[0] - pointA[0];
        AB[1] = pointB[1] - pointA[1];
        AC[0] = pointC[0] - pointA[0];
        AC[1] = pointC[1] - pointA[1];
        double cross = AB[0] * AC[1] - AB[1] * AC[0];

        return cross;
    }

    //Compute the distance from A to B
    static double Distance(double[] pointA, double[] pointB)
    {
        double d1 = pointA[0] - pointB[0];
        double d2 = pointA[1] - pointB[1];

        return Math.sqrt(d1 * d1 + d2 * d2);
    }

    //Compute the distance from AB to C
//if isSegment is true, AB is a segment, not a line.
    static double LineToPointDistance2D(double[] pointA, double[] pointB, double[] pointC,
                                 boolean isSegment)
    {
        double dist = CrossProduct(pointA, pointB, pointC) / Distance(pointA, pointB);
        if (isSegment)
        {
            double dot1 = DotProduct(pointA, pointB, pointC);
            if (dot1 > 0)
                return Distance(pointB, pointC);

            double dot2 = DotProduct(pointB, pointA, pointC);
            if (dot2 > 0)
                return Distance(pointA, pointC);
        }
        return Math.abs(dist);
    }
    static class InputReader {
        public BufferedReader reader;
        public StringTokenizer tokenizer;

        public InputReader(InputStream stream) {
            reader = new BufferedReader(new InputStreamReader(stream));
            tokenizer = null;
        }

        public String next()throws Exception {
            while (tokenizer == null || !tokenizer.hasMoreTokens())
                tokenizer = new StringTokenizer(reader.readLine());
            return tokenizer.nextToken();
        }

        public String nextLine()throws Exception {
            String line = null;
            tokenizer = null;
            line =  reader.readLine();
            return line;
        }

        public int nextInt()throws Exception {
            return Integer.parseInt(next());
        }

        public double nextDouble() throws Exception{
            return Double.parseDouble(next());
        }

        public long nextLong()throws Exception {
            return Long.parseLong(next());
        }

    }
}