Problem: Find an n × n matrix with different numbers from 1 to n2, so the sum in each row, column and both main diagonals are odd.

Input

The only line contains odd integer n (1 ≤ n ≤ 49).

Output

Print n lines with n integers. All the integers should be different and from 1 to n2. The sum in each row, column and both main diagonals should be odd.

Examples

Input

1


Output

1


Input

3


Output

2 1 4
3 5 7
6 9 8

Solution (in JAVA):

Solution:
import java.util.Scanner;
public class Main {
	static Scanner sc = new Scanner (System.in);
	static int [][]arr = new int [55][55];
	public static void main(String[]args)
	{
		int n = sc.nextInt(); 
		int sq = n * n ;
		int beginn = n / 2 + 1, tmp = beginn; //表示开始的下标是多少
		int len = 1; //表示长度应该要是多少
		int now = 1;
		for(int i = 1; i <= n ; i ++)
		{
			beginn = tmp;
			for(int j = beginn; j < beginn + len ; j ++)
			{
				arr[i][j] = now;
				now += 2; 
			}
			if(i > n / 2 + 1)
			{
				len -= 2;
				tmp ++;
			}else if(i == n / 2  + 1)
			{
				len -= 2;
				tmp = 2;
			}
			else 
			{
				len += 2;
				tmp --;
			}
		}
		now = 2;
		for(int i = 1; i <= n ; i ++)
		{
			for(int j = 1 ; j <= n ; j ++)
			{
				if(arr[i][j] == 0)
				{
					arr[i][j] = now;
					now += 2;
				}
				if(j != n)
					System.out.print(arr[i][j] + " ");
				else 
					System.out.println(arr[i][j]);
			}
		}
	}
}