Problem: Find an n × n matrix with different numbers from 1 to n2, so the sum in each row, column and both main diagonals are odd.

Input

The only line contains odd integer n (1 ≤ n ≤ 49).

Output

Print n lines with n integers. All the integers should be different and from 1 to n2. The sum in each row, column and both main diagonals should be odd.

Examples

Input

1


Output

1


Input

3


Output

2 1 4
3 5 7
6 9 8

Solution (in PYTHON3):

Solution:
n = int(input())
odd = []
even = []
for i in range(1, n ** 2 + 1):
    if i % 2: odd.append(i)
    else: even.append(i)
a = [[0] * n for i in range(n)]
L = R = n // 2
flag = False
for i in range(n):
    for j in range(L, R + 1):
        a[i][j] = odd.pop()
    if flag or L == 0:
        flag = True
        L += 1
        R -= 1
    else:
        L -= 1
        R += 1
for i in range(n):
    for j in range(n):
        if not a[i][j]:
            a[i][j] = even.pop()
[print(*i) for i in a]