Problem: Find an n × n matrix with different numbers from 1 to n2, so the sum in each row, column and both main diagonals are odd.

Input

The only line contains odd integer n (1 ≤ n ≤ 49).

Output

Print n lines with n integers. All the integers should be different and from 1 to n2. The sum in each row, column and both main diagonals should be odd.

Examples

Input

1


Output

1


Input

3


Output

2 1 4
3 5 7
6 9 8

Solution (in PYTHON):

Solution:
def square(n):
	m=[[0 for i in range(n)]for j in range(n)]
	a=1
	i=n/2
	j=n-1
	while a<=n**2:
		if i==-1 and j==n:
			j=n-2
			i=0
		else:
			if j==n:
				j=0
			if i<0:
				i=n-1
		if(m[i][j]):
			j-=2
			i+=1
			continue
		else:
			m[i][j]=a
			a+=1
		j+=1
		i-=1
	return m
n=int(raw_input())
m=square(n)
for i in range(n):
	for j in range(n):
		if j==n-1:
			print m[i][j]
		else:
			print m[i][j],