Problem: Find an n × n matrix with different numbers from 1 to n2, so the sum in each row, column and both main diagonals are odd.

Input

The only line contains odd integer n (1 ≤ n ≤ 49).

Output

Print n lines with n integers. All the integers should be different and from 1 to n2. The sum in each row, column and both main diagonals should be odd.

Examples

Input

1


Output

1


Input

3


Output

2 1 4
3 5 7
6 9 8

Solution (in PYTHON):

Solution:
# your code goes here
n = int(raw_input())
ans = [[0 for __ in range(n)] for _ in range(n)]
mid = (n+1)/2
even = 2
odd = 1
for i in range(mid):
	odds = i*2+1
	evens = n-odds
	for j in range(evens/2):
		ans[i][j] = even
		even += 2
	for j in range(evens/2, evens/2+odds):
		ans[i][j] = odd
		odd += 2
	for j in range(evens/2+odds, n):
		ans[i][j] = even
		even += 2
for i in range(mid, n):
	odds = (n-1-i)*2+1
	evens = n-odds
	for j in range(evens/2):
		ans[i][j] = even
		even += 2
	for j in range(evens/2, evens/2+odds):
		ans[i][j] = odd
		odd += 2
	for j in range(evens/2+odds, n):
		ans[i][j] = even
		even += 2
print "\n".join([" ".join(map(str, ans[i])) for i in range(n)])