Problem: Masha has n types of tiles of size 2 × 2. Each cell of the tile contains one integer. Masha has an infinite number of tiles of each type.

Masha decides to construct the square of size m × m consisting of the given tiles. This square also has to be a symmetric with respect to the main diagonal matrix, and each cell of this square has to be covered with exactly one tile cell, and also sides of tiles should be parallel to the sides of the square. All placed tiles cannot intersect with each other. Also, each tile should lie inside the square. See the picture in Notes section for better understanding.

Symmetric with respect to the main diagonal matrix is such a square s that for each pair (i, j) the condition s[i][j] = s[j][i] holds. I.e. it is true that the element written in the i-row and j-th column equals to the element written in the j-th row and i-th column.

Your task is to determine if Masha can construct a square of size m × m which is a symmetric matrix and consists of tiles she has. Masha can use any number of tiles of each type she has to construct the square. Note that she can not rotate tiles, she can only place them in the orientation they have in the input.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then t test cases follow.

The first line of the test case contains two integers n and m (1 ≤ n ≤ 100, 1 ≤ m ≤ 100) — the number of types of tiles and the size of the square Masha wants to construct.

The next 2n lines of the test case contain descriptions of tiles types. Types of tiles are written one after another, each type is written on two lines. 

The first line of the description contains two positive (greater than zero) integers not exceeding 100 — the number written in the top left corner of the tile and the number written in the top right corner of the tile of the current type. The second line of the description contains two positive (greater than zero) integers not exceeding 100 — the number written in the bottom left corner of the tile and the number written in the bottom right corner of the tile of the current type.

It is forbidden to rotate tiles, it is only allowed to place them in the orientation they have in the input.

Output

For each test case print the answer: "YES" (without quotes) if Masha can construct the square of size m × m which is a symmetric matrix. Otherwise, print "NO" (withtout quotes).

Example

Input


6
3 4
1 2
5 6
5 7
7 4
8 9
9 8
2 5
1 1
1 1
2 2
2 2
1 100
10 10
10 10
1 2
4 5
8 4
2 2
1 1
1 1
1 2
3 4
1 2
1 1
1 1


Output


YES
NO
YES
NO
YES
YES

Note

The first test case of the input has three types of tiles, they are shown on the picture below.

<image>

Masha can construct, for example, the following square of size 4 × 4 which is a symmetric matrix:

<image>

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.*;
import java.math.BigDecimal;
import java.math.*;

public class Main{
	public static void main(String[] args) {
	    
	      TaskA solver = new TaskA();
	      
		     
	      int t = in.nextInt();
	      for (int i = 1; i <= t ; i++) {
	          solver.solve(i, in, out);
	      }
	     
	      
//	      solver.solve(1, in, out);
	      
	      
	      out.flush();
	    out.close();
	  }
	
	 static class TaskA {
	      public void solve(int testNumber, InputReader in, PrintWriter out) {
	    	  int n=in.nextInt();
	    	  int m=in.nextInt();
	    	  
	    	  boolean fs=false;
	    	  boolean sn=false;
	    	  for(int j=0;j<n;j++) {
		    		  int x=in.nextInt();
		    		  int y=in.nextInt();
		    		  int z=in.nextInt();
		    		  int w=in.nextInt();
		    		  if(x==w) {
		    			  fs=true;
		    		  }
		    		  if(y==z) {
		    			  sn=true;
		    		  }
		    	  
	    	  }
	    	  if(m%2==1) {out.println("NO");return;}
	    	  if(sn) {
	    		  out.println("YES");
	    	  }
	    	  
	    	  else {
	    		  out.println("NO");
	    	  }
	    	  
	      }
	  }
	 	 
	 
	 
	 static long power(long a,long b,long m ) {
		 long ans=1;
		 while(b>0) {
			 if(b%2==1) {
				 ans=((ans%m)*(a%m))%m; b--;
			 }
			 else {
				 a=(a*a)%m;b/=2;
			 }
			 
		 }
		 return ans%m;
	 }
	 
	 public static boolean repeatedSubString(String string) {
		    return ((string + string).indexOf(string, 1) != string.length());
		}
	 static int search(char[]c,int start,int end,char x) {
		 for(int i=start;i<end;i++) {
			 if(c[i]==x) {return i;}
		 }
		 return -2;
	 }
	 static int bs(int size,int[]arr) {
		 int x = -1;
    	 for (int b = size/2; b >= 1; b /= 2) {
        	 while (!ok(arr));
        	 }
    	 int k = x+1;
    	 return k;
	 }
	 
	 static boolean ok(int[]x) {
		 return false;
	 }
	 
	 static int gcd(int a, int b) {
	        while (b != 0) {
	            int t = b;
	            b = a % b;
	            a = t;
	        }
	        return a;
	    }
	
	 
	 static long fun(long[]a,int f,int b,int k) {
		 long max= Long.MIN_VALUE;
		 while(f<b) {
 	  		max= Math.max(max, (f)*(b)-k*(a[f]|a[b]));
 	  		max= Math.max(max, (f+1)*(b)-k*(a[f+1]|a[b]));
 	  		max=Math.max(max, (f)*(b)-k*(a[f]|a[b]));
 	  	}
 	  	return max;
	 }
	 
	 
	
	 
	 static long fac(long a)
	 {
	     if(a== 0L || a==1L)return 1L ;
	     
	     return a*fac(a-1L) ;
	 }
	 static int nD(long n) {
		 int count =0;
		 while(n>0) {
			 n/=10;
			 count++;
			 
		 }
		 return count;
	 }
	 
	 static ArrayList al() {
		 ArrayList<Integer>a =new ArrayList<>();
			return a;
		}
	 
	static HashSet h() {
			return new HashSet<Integer>();
		}
	static void debug(int[][]a) {
		int n= a.length;
		for(int i=1;i<=n;i++) {
	  		for(int j=1;j<=n;j++) {
	  			out.print(a[i][j]+" ");
	  		}
	  		out.print("\n");
	  	}
	}
	static void debug(int[]a) {
			out.println(Arrays.toString(a));
		}
	
	static void debug(ArrayList<Integer>a) {
				out.println(a.toString());
		}
	
	static boolean[]seive(int n){
		boolean[]b=new boolean[n+1];
		 for (int i = 2; i <= n; i++)
	            b[i] = true;
		 
		for(int i=2;i*i<=n;i++) {
			if(b[i]) {
				for(int j=i*i;j<=n;j+=i) {
					b[j]=false;
				}
			}
		}
		return b;
	}
	
	 static int longestIncreasingSubseq(int[]arr) {
		  int[]sizes=new int[arr.length];
		  Arrays.fill(sizes, 1);
		  int max=1;
		  for(int i=1;i<arr.length;i++) {
			  for(int j=0;j<i;j++) {
				  if(arr[j]<arr[i]) {
					  sizes[i]=Math.max(sizes[i],sizes[j]+1);
					  max=Math.max(max, sizes[i]);
				  }
			  }
		  }
		  return max;
	 }
	 
	 public static ArrayList primeFactors(long n)
	    {
		    ArrayList<Long>h= new ArrayList<>();
	        // Print the number of 2s that divide n
	        if(n%2 ==0) {h.add(2L);}
	 
	        // n must be odd at this point.  So we can
	        // skip one element (Note i = i +2)
	        for (long i = 3; i <= Math.sqrt(n); i+= 2)
	        {
	            if(n%i==0) {h.add(i);}
	        }
	        if (n > 2)
	            h.add(n);
	        return h;
	    }
	 
	 static boolean Divisors(long n){
		 if(n%2==1) {
			 return true;
		 }
	     for (long i=2; i<=Math.sqrt(n); i++){
	            if (n%i==0 && i%2==1){
	                   return true;
	            } 
	        }
	     return false;
	    }
	
	static InputStream inputStream = System.in;
    static OutputStream outputStream = System.out;
    static InputReader in = new InputReader(inputStream);
    static PrintWriter out = new PrintWriter(outputStream);
    
    public static void superSet(int[]a,ArrayList<String>al,int i,String s) {
    	if(i==a.length) {
    		al.add(s);
    		return;
    	}
    	superSet(a,al,i+1,s);
    	superSet(a,al,i+1,s+a[i]+" ");
    }
    
	public static long[] makeArr() {
		long size=in.nextInt();
		long []arr=new long[(int)size];
		for(int i=0;i<size;i++) {
			arr[i]=in.nextInt();
		}
		return arr;
	}
	
	public static long[] arr(int n) {
		long []arr=new long[n+1];
		for(int i=1;i<n+1;i++) {
			arr[i]=in.nextLong();
		}
		return arr;
	}
  
  public static void sort(long arr[], int l, int r)
  {
      if (l < r)
      {
          // Find the middle point
          int m = (l+r)/2;

          // Sort first and second halves
          sort(arr, l, m);
          sort(arr , m+1, r);

          // Merge the sorted halves
          merge(arr, l, m, r);
      }
  }

  static void print(int c) {
		 out.print(c);
	 }
	 static void println(int x) {
		 out.println(x);
	 }
	 static void print(String s) {
		 out.print(s);
	 }
	 static void println(String s) {
		 out.println(s);
	 }
public static void merge(long arr[], int l, int m, int r)
  {
      // Find sizes of two subarrays to be merged
      int n1 = m - l + 1;
      int n2 = r - m;

      /* Create temp arrays */
      long L[] = new long[n1];
      long R[] = new long[n2];

      //Copy data to temp arrays
      for (int i=0; i<n1; ++i)
          L[i] = arr[l + i];
      for (int j=0; j<n2; ++j)
          R[j] = arr[m + 1+ j];


      /* Merge the temp arrays */

      // Initial indexes of first and second subarrays
      int i = 0, j = 0;

      // Initial index of merged subarry array
      int k = l;
      while (i < n1 && j < n2)
      {
          if (L[i] <= R[j])
          {
              arr[k] = L[i];
              i++;
          }
          else
          {
              arr[k] = R[j];
              j++;
          }
          k++;
      }

      /* Copy remaining elements of L[] if any */
      while (i < n1)
      {
          arr[k] = L[i];
          i++;
          k++;
      }

      /* Copy remaining elements of R[] if any */
      while (j < n2)
      {
          arr[k] = R[j];
          j++;
          k++;
      }
  }

public static void reverse(int[] array)
{
    int n = array.length;
    for (int i = 0; i < n / 2; i++) {
        int temp = array[i];
        array[i] = array[n - i - 1];
        array[n - i - 1] = temp;
    }
}

  public static long nCr(int n,int k)
  {
      long ans=1L;
      k=k>n-k?n-k:k;
     
      for( int j=1;j<=k;j++,n--)
      {
          if(n%j==0)
          {
              ans*=n/j;
          }else
          if(ans%j==0)
          {
              ans=ans/j*n;
          }else
          {
              ans=(ans*n)/j;
          }
      }
      return ans;
  }
  static int searchMax(int index,long[]inp) {
	  while(index+1<inp.length &&inp[index+1]>inp[index]) {
		  index+=1;
	  }
	  return index;
  }
  static int searchMin(int index,long[]inp) {
	  while(index+1<inp.length &&inp[index+1]<inp[index]) {
		  index+=1;
	  }
	  return index;
  }

  static class InputReader {
      public BufferedReader reader;
      public StringTokenizer tokenizer;

      public InputReader(InputStream stream) {
          reader = new BufferedReader(new InputStreamReader(stream), 32768);
          tokenizer = null;
      }

      public String next() {
          while (tokenizer == null || !tokenizer.hasMoreTokens()) {
              try {
                  tokenizer = new StringTokenizer(reader.readLine());
              } catch (IOException e) {
                  throw new RuntimeException(e);
              }
          }
          return tokenizer.nextToken();
      }

      public int nextInt() {
          return Integer.parseInt(next());
      }
      public long nextLong() {
    	  return Long.parseLong(next());
      }
  }
}