Problem: Find an n × n matrix with different numbers from 1 to n2, so the sum in each row, column and both main diagonals are odd.

Input

The only line contains odd integer n (1 ≤ n ≤ 49).

Output

Print n lines with n integers. All the integers should be different and from 1 to n2. The sum in each row, column and both main diagonals should be odd.

Examples

Input

1


Output

1


Input

3


Output

2 1 4
3 5 7
6 9 8

Solution (in PYTHON3):

Solution:
#Magic odd square
import sys
n=int(input())
odd=[i for i in range(1,n**2+1,2)]
even=[i for i in range(2,n**2,2)]
for i in range(1,n+1,2):
    for j in range((n-i)//2):
        sys.stdout.write("%-2d "%(even.pop()))
    for j in range(i):
        sys.stdout.write("%-2d "%(odd.pop()))
    for j in range((n-i)//2):
        sys.stdout.write("%-2d "%(even.pop()))
    sys.stdout.write("\n")
for i in reversed(range(1,n,2)):
    for j in range((n-i)//2):
        sys.stdout.write("%-2d "%(even.pop()))
    for j in range(i):
        sys.stdout.write("%-2d "%(odd.pop()))
    for j in range((n-i)//2):
        sys.stdout.write("%-2d "%(even.pop()))
    sys.stdout.write("\n")