Problem: Today Pari and Arya are playing a game called Remainders.

Pari chooses two positive integer x and k, and tells Arya k but not x. Arya have to find the value <image>. There are n ancient numbers c1, c2, ..., cn and Pari has to tell Arya <image> if Arya wants. Given k and the ancient values, tell us if Arya has a winning strategy independent of value of x or not. Formally, is it true that Arya can understand the value <image> for any positive integer x?

Note, that <image> means the remainder of x after dividing it by y.

Input

The first line of the input contains two integers n and k (1 ≤ n, k ≤ 1 000 000) — the number of ancient integers and value k that is chosen by Pari.

The second line contains n integers c1, c2, ..., cn (1 ≤ ci ≤ 1 000 000).

Output

Print "Yes" (without quotes) if Arya has a winning strategy independent of value of x, or "No" (without quotes) otherwise.

Examples

Input

4 5
2 3 5 12


Output

Yes


Input

2 7
2 3


Output

No

Note

In the first sample, Arya can understand <image> because 5 is one of the ancient numbers.

In the second sample, Arya can't be sure what <image> is. For example 1 and 7 have the same remainders after dividing by 2 and 3, but they differ in remainders after dividing by 7.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int n, k, c;
bool prime[1000010 + 5];
vector<int> p;
vector<pair<int, bool>> v;
void criba() {
  p.push_back(2);
  for (int i = 3; i < 1000010; i += 2)
    if (!prime[i]) {
      for (int j = i + i; j < 1000010; j += i) prime[j] = true;
      p.push_back(i);
    }
}
int main() {
  criba();
  scanf("%d %d", &n, &k);
  for (int i = 0; i < p.size(); i++) {
    if (k % p[i] == 0) {
      int tmp = 1;
      while (k % p[i] == 0) tmp *= p[i], k /= p[i];
      v.push_back(make_pair(tmp, false));
    }
  }
  for (int i = 0; i < n; i++) {
    scanf("%d", &c);
    for (int j = 0; j < v.size(); j++)
      if (c % v[j].first == 0) v[j].second = true;
  }
  bool ok = true;
  for (int i = 0; i < v.size(); i++)
    if (v[i].second == false) ok = false;
  printf(ok ? "Yes\n" : "No\n");
  return (0);
}