Problem: Find an n × n matrix with different numbers from 1 to n2, so the sum in each row, column and both main diagonals are odd.

Input

The only line contains odd integer n (1 ≤ n ≤ 49).

Output

Print n lines with n integers. All the integers should be different and from 1 to n2. The sum in each row, column and both main diagonals should be odd.

Examples

Input

1


Output

1


Input

3


Output

2 1 4
3 5 7
6 9 8

Solution (in PYTHON):

Solution:
n = int(raw_input())

sq = []
for i in range(0,n) :
    sq.append([0]*n)

oldRow = 0
row = 0
oldCol = int(n/2)
col = int(n/2)

for i in range(1,n*n + 1) :
    if sq[row][col] != 0 :
        sq[(oldRow + 1)%n][oldCol] = i
        row = (oldRow + 1)%n
        col = oldCol
    else :
        sq[row][col] = i

    oldRow = row
    oldCol = col
    row = (row-1 + n) % n
    col = (col+1) % n

for i in sq :
    for j in i :
        print j,
    print ''