Problem: You are given a correct solution of the sudoku puzzle. If you don't know what is the sudoku, you can read about it [here](http://tiny.cc/636xmz).

The picture showing the correct sudoku solution:

<image>

Blocks are bordered with bold black color.

Your task is to change at most 9 elements of this field (i.e. choose some 1 ≤ i, j ≤ 9 and change the number at the position (i, j) to any other number in range [1; 9]) to make it anti-sudoku. The anti-sudoku is the 9 × 9 field, in which:

  * Any number in this field is in range [1; 9]; 
  * each row contains at least two equal elements; 
  * each column contains at least two equal elements; 
  * each 3 × 3 block (you can read what is the block in the link above) contains at least two equal elements. 



It is guaranteed that the answer exists.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases. Then t test cases follow.

Each test case consists of 9 lines, each line consists of 9 characters from 1 to 9 without any whitespaces — the correct solution of the sudoku puzzle.

Output

For each test case, print the answer — the initial field with at most 9 changed elements so that the obtained field is anti-sudoku. If there are several solutions, you can print any. It is guaranteed that the answer exists.

Example

Input


1
154873296
386592714
729641835
863725149
975314628
412968357
631457982
598236471
247189563


Output


154873396
336592714
729645835
863725145
979314628
412958357
631457992
998236471
247789563

Solution (in PYTHON3):

Solution:
q = int(input())
for _ in range(q):
    b = []
    for k in range(9):
        b.append([int(x) for x in input()])
    u = set()
    b[0][0] = b[0][1]
    u.add(b[0][1])
    for k in range(1,10):
        if k not in u and b[1][3] != k:
            b[1][3] = k
            u.add(k)
            break
    for k in range(1,10):
        if k not in u and b[2][6] != k:
            b[2][6] = k
            u.add(k)
            break
    for k in range(1,10):
        if k not in u and b[3][1] != k:
            b[3][1] = k
            u.add(k)
            break
    for k in range(1,10):
        if k not in u and b[4][4] != k:
            b[4][4] = k
            u.add(k)
            break
    for k in range(1,10):
        if k not in u and b[5][7] != k:
            b[5][7] = k
            u.add(k)
            break
    for k in range(1,10):
        if k not in u and b[6][2] != k:
            b[6][2] = k
            u.add(k)
            break
    for k in range(1,10):
        if k not in u and b[7][5] != k:
            b[7][5] = k
            u.add(k)
            break
    f = 1
    for k in range(1,10):
        if k not in u and b[8][8] != k:
            f = 0
            b[8][8] = k
            u.add(k)
            break
    if f == 1:
        b[8][8] = b[8][7]
    for e in b:
        print("".join(map(str,e)))