Problem: Find an n × n matrix with different numbers from 1 to n2, so the sum in each row, column and both main diagonals are odd.

Input

The only line contains odd integer n (1 ≤ n ≤ 49).

Output

Print n lines with n integers. All the integers should be different and from 1 to n2. The sum in each row, column and both main diagonals should be odd.

Examples

Input

1


Output

1


Input

3


Output

2 1 4
3 5 7
6 9 8

Solution (in PYTHON3):

Solution:
a = int(input())
list = []
for i in range (a):
    list.append([0]*a)
it = [int(a / 2), 0]
list[it[0]][it[1]] = 1
for i in range(2, a ** 2 + 1):
    if list[(it[0] + 1) % a][(it[1] - 1) % a] == 0:
        list[(it[0] + 1) % a][(it[1] - 1) % a] = i
        it[0] = (it[0] + 1) % a
        it[1] = (it[1] - 1) % a
    else:
        list[it[0]][(it[1] + 1) % a] = i
        it[1] = (it[1] + 1) % a
for i in range(a):
    for j in range(a):
        print(list[i][j],end=" ")
    print("")