Problem: We have a tree with N vertices. The vertices are numbered 1 to N, and the i-th edge connects Vertex a_i and Vertex b_i.

Takahashi loves the number 3. He is seeking a permutation p_1, p_2, \ldots , p_N of integers from 1 to N satisfying the following condition:

* For every pair of vertices (i, j), if the distance between Vertex i and Vertex j is 3, the sum or product of p_i and p_j is a multiple of 3.



Here the distance between Vertex i and Vertex j is the number of edges contained in the shortest path from Vertex i to Vertex j.

Help Takahashi by finding a permutation that satisfies the condition.

Constraints

* 2\leq N\leq 2\times 10^5
* 1\leq a_i, b_i \leq N
* The given graph is a tree.

Input

Input is given from Standard Input in the following format:


N
a_1 b_1
a_2 b_2
\vdots
a_{N-1} b_{N-1}


Output

If no permutation satisfies the condition, print `-1`.

Otherwise, print a permutation satisfying the condition, with space in between. If there are multiple solutions, you can print any of them.

Example

Input

5
1 2
1 3
3 4
3 5


Output

1 2 5 4 3

Solution (in PYTHON3):

Solution:
from sys import setrecursionlimit

setrecursionlimit(10**6)

def dfs(i, depth):
    visited[i] = True
    oe = depth%2
    ans[i-1] = oe
    count[oe] += 1
    nodes = tree[i]
    for node in nodes:
        if visited[node]:
            continue
        dfs(node, depth+1)
    


N = int(input())
ans = [-1]*N
tree = [[] for i in range(N+1)]
visited = [False]*(N+1)
count = [0, 0]
base = [1, 2, 3]
for i in range(N-1):
    a, b = map(int, input().split())
    tree[a] += [b]
    tree[b] += [a]
dfs(1, 0)
even_len = count[0]
odd_len = count[1]
if even_len > N//3 and odd_len > N//3:
    for i, oe in enumerate(ans):
        if base[oe] > N:
            ans[i] = str(base[2])
            base[2] += 3
        else:
            ans[i] = str(base[oe])
            base[oe] += 3
elif even_len <= N//3:
    for i, oe in enumerate(ans):
        if oe == 0:
            ans[i] = str(base[2])
            base[2] += 3
        elif base[0] <= N:
            ans[i] = str(base[0])
            base[0] += 3
        elif base[1] <= N:
            ans[i] = str(base[1])
            base[1] += 3
        else:
            ans[i] = str(base[2])
            base[2] += 3
elif odd_len <= N//3:
    for i, oe in enumerate(ans):
        if oe == 1:
            ans[i] = str(base[2])
            base[2] += 3
        elif base[0] <= N:
            ans[i] = str(base[0])
            base[0] += 3
        elif base[1] <= N:
            ans[i] = str(base[1])
            base[1] += 3
        else:
            ans[i] = str(base[2])
            base[2] += 3
print(' '.join(ans))