Problem: Find an n × n matrix with different numbers from 1 to n2, so the sum in each row, column and both main diagonals are odd.

Input

The only line contains odd integer n (1 ≤ n ≤ 49).

Output

Print n lines with n integers. All the integers should be different and from 1 to n2. The sum in each row, column and both main diagonals should be odd.

Examples

Input

1


Output

1


Input

3


Output

2 1 4
3 5 7
6 9 8

Solution (in PYTHON3):

Solution:
from math import ceil
n = int(input())
evens = [i for i in range(1,n**2+1) if i%2==0]
odds  = [i for i in range(1,n**2+1) if i%2==1]
#print(evens)
#print(odds)
x = ceil(n/2)
e = 0
o = 0
for i in range(1,n+1):
    for j in range(abs(x-i)):
        print(evens[e],end=" ")
        e+=1
    for j in range(abs(n-abs(x - i)*2)):
        print(odds[o],end=" ")
        o+=1
    for j in range(abs(x - i)):
        print(evens[e], end=" ")
        e += 1
    print("\t")