Problem: You are given a correct solution of the sudoku puzzle. If you don't know what is the sudoku, you can read about it [here](http://tiny.cc/636xmz).

The picture showing the correct sudoku solution:

<image>

Blocks are bordered with bold black color.

Your task is to change at most 9 elements of this field (i.e. choose some 1 ≤ i, j ≤ 9 and change the number at the position (i, j) to any other number in range [1; 9]) to make it anti-sudoku. The anti-sudoku is the 9 × 9 field, in which:

  * Any number in this field is in range [1; 9]; 
  * each row contains at least two equal elements; 
  * each column contains at least two equal elements; 
  * each 3 × 3 block (you can read what is the block in the link above) contains at least two equal elements. 



It is guaranteed that the answer exists.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases. Then t test cases follow.

Each test case consists of 9 lines, each line consists of 9 characters from 1 to 9 without any whitespaces — the correct solution of the sudoku puzzle.

Output

For each test case, print the answer — the initial field with at most 9 changed elements so that the obtained field is anti-sudoku. If there are several solutions, you can print any. It is guaranteed that the answer exists.

Example

Input


1
154873296
386592714
729641835
863725149
975314628
412968357
631457982
598236471
247189563


Output


154873396
336592714
729645835
863725145
979314628
412958357
631457992
998236471
247789563

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
const long long int LL_INF = 0x3f3f3f3f3f3f;
const long long int MOD = 1073741824;
using namespace std;
int T;
int n, m;
int inp, inc;
string arr[10];
set<int> st;
int ans[5][5];
int curr[5][5];
vector<pair<int, int> > v;
int main() {
  scanf("%d", &T);
  while (T--) {
    inc = 1;
    for (int i = 1; i <= 3; ++i) {
      for (int j = 1; j <= 3; ++j) ans[i][j] = inc++;
    }
    for (int i = 0; i < 9; ++i) cin >> arr[i];
    arr[0][0] = arr[0][0] + 1 > '9' ? '1' : 1 + arr[0][0];
    arr[1][3] = arr[1][3] + 1 > '9' ? '1' : 1 + arr[1][3];
    arr[2][6] = arr[2][6] + 1 > '9' ? '1' : 1 + arr[2][6];
    arr[3][1] = arr[3][1] + 1 > '9' ? '1' : 1 + arr[3][1];
    arr[4][4] = arr[4][4] + 1 > '9' ? '1' : 1 + arr[4][4];
    arr[5][7] = arr[5][7] + 1 > '9' ? '1' : 1 + arr[5][7];
    arr[6][2] = arr[6][2] + 1 > '9' ? '1' : 1 + arr[6][2];
    arr[7][5] = arr[7][5] + 1 > '9' ? '1' : 1 + arr[7][5];
    arr[8][8] = arr[8][8] + 1 > '9' ? '1' : 1 + arr[8][8];
    for (int i = 0; i < 9; ++i) cout << arr[i] << endl;
  }
  return 0;
}