Problem: K: Relief (Angel Relief)

Tenma, an angel, decides to save a city.

The city has a rectangular shape divided into north-south $ H $ parcels x east-west $ W $ parcels, with houses in each parcel.

The $ X $ th section from the north and the $ Y $ th section from the west are represented by $ (X, Y) $.

The house in parcel $ (i, j) $ is inhabited by $ A_ {i, j} $ people.

Tenshin chooses a rectangular area whose sides are parallel or vertical to north-south or east-west, and rescues all the people living in it one by one.

Tenshin does this for every possible rectangle.

Find the total number of times Tenma-san rescues people.

input

The integers $ H, W $ are given on the first line, separated by blanks.

Of the following $ H $ lines, the integers $ A_ {i, 1}, A_ {i, 2}, A_ {i, 3}, \ dots, A_ {i, W} $ are blank on the $ i $ line. Given as a delimiter.

output

Output the total number of times Tenma-san rescues people.

Constraint

* $ H, W $ are integers between $ 1 $ and $ 500 $
* $ A_ {i, j} $ are all integers greater than or equal to $ 1 $ and less than or equal to $ 9 $.



Input example 1


twenty two
1 2
4 8


Output example 1


60


For example, if you choose a rectangular area with $ (1, 1) $ in the upper left and $ (2, 2) $ in the lower right, you will rescue $ 15 $ people there one by one, so a total of $ 15 $ times. Relief.

$ 1, 2, 3, 4, 5, 8, 10, 12, 15 $ relief for each of the $ 9 $ rectangular areas, for a total of $ 60 $.

Input example 2


twenty three
one two Three
4 5 6


Output example 2


140






Example

Input

2 2
1 2
4 8


Output

60

Solution (in CPP):

Solution:
#include<iostream>
#include<vector>
#include<algorithm>
#include<string>
#define REP(i,n) for(int i=0;i<(n);++i)
#define REPA(i,n) for(int i=1;i<(n);++i)
#define MOD ((int)1e9 + 7)
#define INF ((int)1e9)
#define ALL(x) (x).begin(),(x).end()
#define ctoi(x) (x - 'a') 
#define CTOI(x) (x - 'A')
using namespace std;
int main(){
    int H,W;
    cin>>H>>W;
    vector<vector<int> > map(H,vector<int>(W));
    REP(i,H){
        REP(j,W){
            cin >> map[i][j];
        }
    }
    long long ans = 0;
    REP(i,H){
        REP(j,W){
            ans += (long long)map[i][j] * (i+1) * (H-i) * (j+1) * (W-j);
        }
    }
    cout << ans << endl;
    return 0;
}