Problem: Find an n × n matrix with different numbers from 1 to n2, so the sum in each row, column and both main diagonals are odd.

Input

The only line contains odd integer n (1 ≤ n ≤ 49).

Output

Print n lines with n integers. All the integers should be different and from 1 to n2. The sum in each row, column and both main diagonals should be odd.

Examples

Input

1


Output

1


Input

3


Output

2 1 4
3 5 7
6 9 8

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
const int maxn = 57;
int dp[2037][2037];
const int mod = 1e9 + 7;
int main() {
  ios_base::sync_with_stdio(false);
  cin.tie(NULL);
  int n;
  cin >> n;
  vector<vector<int>> v(n, vector<int>(n, 1));
  int neparne = 1;
  int parne = 2;
  int a = (n * n + 1) / 2;
  int b = n * n - a;
  for (int i = 0; i < n / 2; i++) {
    for (int j = 0; j < n / 2; j++) {
      if (b > 0) {
        b -= 4;
        v[n - 1 - i][j] = 0;
        v[n - 1 - i][n - 1 - j] = 0;
        v[i][n - 1 - j] = 0;
        v[i][j] = 0;
      }
    }
  }
  for (int i = 0; i < n; i++) {
    for (int j = 0; j < n; j++) {
      if (v[i][j] == 0) {
        v[i][j] = parne;
        parne += 2;
      } else {
        v[i][j] = neparne;
        neparne += 2;
      }
    }
  }
  for (int i = 0; i < n; i++) {
    for (int j = 0; j < n; j++) {
      cout << v[i][j];
      cout << ' ';
    }
    cout << endl;
  }
  return 0;
}