Problem: You are given a correct solution of the sudoku puzzle. If you don't know what is the sudoku, you can read about it [here](http://tiny.cc/636xmz).

The picture showing the correct sudoku solution:

<image>

Blocks are bordered with bold black color.

Your task is to change at most 9 elements of this field (i.e. choose some 1 ≤ i, j ≤ 9 and change the number at the position (i, j) to any other number in range [1; 9]) to make it anti-sudoku. The anti-sudoku is the 9 × 9 field, in which:

  * Any number in this field is in range [1; 9]; 
  * each row contains at least two equal elements; 
  * each column contains at least two equal elements; 
  * each 3 × 3 block (you can read what is the block in the link above) contains at least two equal elements. 



It is guaranteed that the answer exists.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases. Then t test cases follow.

Each test case consists of 9 lines, each line consists of 9 characters from 1 to 9 without any whitespaces — the correct solution of the sudoku puzzle.

Output

For each test case, print the answer — the initial field with at most 9 changed elements so that the obtained field is anti-sudoku. If there are several solutions, you can print any. It is guaranteed that the answer exists.

Example

Input


1
154873296
386592714
729641835
863725149
975314628
412968357
631457982
598236471
247189563


Output


154873396
336592714
729645835
863725145
979314628
412958357
631457992
998236471
247789563

Solution (in PYTHON3):

Solution:

def main():
    for _ in inputt():
        for _ in range(9):
            s = input()
            print(s.replace("1", "2"))



# region M


# region import
# 所有import部分

from math import *
from heapq import *
from itertools import *
from functools import reduce, lru_cache, partial
from collections import Counter, defaultdict, deque
import re, copy, operator, cmath
import calendar
import sys, io, os, builtins
sys.setrecursionlimit(1000)

# endregion

# region fastio
# 快速io，能提升大量时间

BUFSIZE = 8192
class FastIO(io.IOBase):
    newlines = 0
    def __init__(self, file):
        self._fd = file.fileno()
        self.buffer = io.BytesIO()
        self.writable = "x" in file.mode or "r" not in file.mode
        self.write = self.buffer.write if self.writable else None
    def read(self):
        while True:
            b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
            if not b:
                break
            ptr = self.buffer.tell()
            self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
        self.newlines = 0
        return self.buffer.read()
    def readline(self):
        while self.newlines == 0:
            b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
            self.newlines = b.count(b"\n") + (not b)
            ptr = self.buffer.tell()
            self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
        self.newlines -= 1
        return self.buffer.readline()
    def flush(self):
        if self.writable:
            os.write(self._fd, self.buffer.getvalue())
            self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(io.IOBase):
    def __init__(self, file):
        self.buffer = FastIO(file)
        self.flush = self.buffer.flush
        self.writable = self.buffer.writable
        self.write = lambda s: self.buffer.write(s.encode("ascii"))
        self.read = lambda: self.buffer.read().decode("ascii")
        self.readline = lambda: self.buffer.readline().decode("ascii")
def print(*args, **kwargs):
    sys.stdout.write(kwargs.pop("split", " ").join(map(str, args)))
    sys.stdout.write(kwargs.pop("end", "\n"))
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip()
inputt = lambda t = 0: range(t) if t else range(int(input()))
inputs = lambda: input().split()
inputi = lambda k = int: map(k, inputs())
inputf = lambda: inputi(float)
inputl = lambda t = 0, k = inputi: map(list, (k() for _ in range(t))) if t else list(k())

# endregion

# region bisect
# 二分搜索，标准库没有函数参数

def len(a):
    if isinstance(a, range):
        return -((a.start - a.stop) // a.step)
    return builtins.len(a)
def bisect_left(a, x, key = None, lo = 0, hi = None):
    if lo < 0: lo = 0
    if hi == None: hi = len(a)
    if key == None: key = do_nothing
    while lo < hi:
        mid = (lo + hi) // 2
        if key(a[mid]) < x: lo = mid + 1
        else: hi = mid
    return lo
def bisect_right(a, x, key = None, lo = 0, hi = None):
    if lo < 0: lo = 0
    if hi == None: hi = len(a)
    if key == None: key = do_nothing
    while lo < hi:
        mid = (lo + hi) // 2
        if x < key(a[mid]): hi = mid
        else: lo = mid + 1
    return lo
def insort_left(a, x, key = None, lo = 0, hi = None):
    lo = bisect_left(a, x, key, lo, hi)
    a.insert(lo, x)
def insort_right(a, x, key = None, lo = 0, hi = None):
    lo = bisect_right(a, x, key, lo, hi)
    a.insert(lo, x)
do_nothing = lambda x: x
bisect = bisect_right
insort = insort_right
def index(a, x, default = None, key = None, lo = 0, hi = None):
    if lo < 0: lo = 0
    if hi == None: hi = len(a)
    if key == None: key = do_nothing
    i = bisect_left(a, x, key, lo, hi)
    if lo <= i < hi and key(a[i]) == x: return a[i]
    if default != None: return default
    raise ValueError
def find_lt(a, x, default = None, key = None, lo = 0, hi = None):
    if lo < 0: lo = 0
    if hi == None: hi = len(a)
    i = bisect_left(a, x, key, lo, hi)
    if lo < i <= hi: return a[i - 1]
    if default != None: return default
    raise ValueError
def find_le(a, x, default = None, key = None, lo = 0, hi = None):
    if lo < 0: lo = 0
    if hi == None: hi = len(a)
    i = bisect_right(a, x, key, lo, hi)
    if lo < i <= hi: return a[i - 1]
    if default != None: return default
    raise ValueError
def find_gt(a, x, default = None, key = None, lo = 0, hi = None):
    if lo < 0: lo = 0
    if hi == None: hi = len(a)
    i = bisect_right(a, x, key, lo, hi)
    if lo <= i < hi: return a[i]
    if default != None: return default
    raise ValueError
def find_ge(a, x, default = None, key = None, lo = 0, hi = None):
    if lo < 0: lo = 0
    if hi == None: hi = len(a)
    i = bisect_left(a, x, key, lo, hi)
    if lo <= i < hi: return a[i]
    if default != None: return default
    raise ValueError

# endregion

# region main
# main函数部分

if __name__ == "__main__":
    main()

# endregion


# endregion