Problem: Find an n × n matrix with different numbers from 1 to n2, so the sum in each row, column and both main diagonals are odd.

Input

The only line contains odd integer n (1 ≤ n ≤ 49).

Output

Print n lines with n integers. All the integers should be different and from 1 to n2. The sum in each row, column and both main diagonals should be odd.

Examples

Input

1


Output

1


Input

3


Output

2 1 4
3 5 7
6 9 8

Solution (in PYTHON3):

Solution:
a = int(input())

odd = 1
even = 2
c = a//2

l = [[] for x in range(a)]

for row in range(0, a):
    for col in range(0, a):
        if c <= col <= a - 1 - c:
            l[row].append(odd)
            odd += 2
        else:
            l[row].append(even)
            even += 2

    if row < a//2:
        c -= 1
    else:
        c += 1

for row in l:
    print(" ".join(list(map(str, row))))