Problem: You are given a correct solution of the sudoku puzzle. If you don't know what is the sudoku, you can read about it [here](http://tiny.cc/636xmz).

The picture showing the correct sudoku solution:

<image>

Blocks are bordered with bold black color.

Your task is to change at most 9 elements of this field (i.e. choose some 1 ≤ i, j ≤ 9 and change the number at the position (i, j) to any other number in range [1; 9]) to make it anti-sudoku. The anti-sudoku is the 9 × 9 field, in which:

  * Any number in this field is in range [1; 9]; 
  * each row contains at least two equal elements; 
  * each column contains at least two equal elements; 
  * each 3 × 3 block (you can read what is the block in the link above) contains at least two equal elements. 



It is guaranteed that the answer exists.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases. Then t test cases follow.

Each test case consists of 9 lines, each line consists of 9 characters from 1 to 9 without any whitespaces — the correct solution of the sudoku puzzle.

Output

For each test case, print the answer — the initial field with at most 9 changed elements so that the obtained field is anti-sudoku. If there are several solutions, you can print any. It is guaranteed that the answer exists.

Example

Input


1
154873296
386592714
729641835
863725149
975314628
412968357
631457982
598236471
247189563


Output


154873396
336592714
729645835
863725145
979314628
412958357
631457992
998236471
247789563

Solution (in JAVA):

Solution:


import java.util.ArrayList;
import java.util.Arrays;
import java.util.Scanner;

public class Demo09 {

	
	
	private static void findAns(String [] mat)
	{
		
		String [] ans = new String[9];
		char [] []	matArr = new char[9][9];	  
		
		for(int i =0;i<9;i++)
		{
			matArr[i] =mat[i].toCharArray();
			for(int j =0;j<9;j++)
			{
				if(mat[i].charAt(j)=='2') {
					
					matArr[i][j] ='1';
				}
				}
			ans[i] = new String(matArr[i]);
		}
		
		
		
		
		for(int i =0;i<9;i++)
		{
			System.out.println(ans[i]);
		}
		
		
	}
	
	
	
	
	public static void main(String [] args)
	{
		
		Scanner in =new Scanner(System.in);
		
		int t =in.nextInt();
		
		for(int j =0;j<t;j++)
		{
			
			String [] mat =new String [9];
			
			for(int k =0;k<9;k++)
			{
				
				mat[k] =in.next();
				
			}
			
			findAns(mat);
			//System.out.println();
			
			
		}
		
		
		
		
		
		
		
	}
	
	
	
	
	
	
	
	
	
}