Problem: There is a cave consisting of N rooms and M one-directional passages. The rooms are numbered 1 through N.

Takahashi is now in Room 1, and Room N has the exit. The i-th passage connects Room s_i and Room t_i (s_i < t_i) and can only be traversed in the direction from Room s_i to Room t_i. It is known that, for each room except Room N, there is at least one passage going from that room.

Takahashi will escape from the cave. Each time he reaches a room (assume that he has reached Room 1 at the beginning), he will choose a passage uniformly at random from the ones going from that room and take that passage.

Aoki, a friend of Takahashi's, can block one of the passages (or do nothing) before Takahashi leaves Room 1. However, it is not allowed to block a passage so that Takahashi is potentially unable to reach Room N.

Let E be the expected number of passages Takahashi takes before he reaches Room N. Find the value of E when Aoki makes a choice that minimizes E.

Constraints

* 2 \leq N \leq 600
* N-1 \leq M \leq \frac{N(N-1)}{2}
* s_i < t_i
* If i != j, (s_i, t_i) \neq (s_j, t_j). (Added 21:23 JST)
* For every v = 1, 2, ..., N-1, there exists i such that v = s_i.

Input

Input is given from Standard Input in the following format:


N M
s_1 t_1
:
s_M t_M


Output

Print the value of E when Aoki makes a choice that minimizes E. Your output will be judged as correct when the absolute or relative error from the judge's output is at most 10^{-6}.

Examples

Input

4 6
1 4
2 3
1 3
1 2
3 4
2 4


Output

1.5000000000


Input

3 2
1 2
2 3


Output

2.0000000000


Input

10 33
3 7
5 10
8 9
1 10
4 6
2 5
1 7
6 10
1 4
1 3
8 10
1 5
2 6
6 9
5 6
5 8
3 6
4 8
2 7
2 9
6 7
1 2
5 9
6 8
9 10
3 9
7 8
4 5
2 10
5 7
3 5
4 7
4 9


Output

3.0133333333

Solution (in PYTHON3):

Solution:
import sys
input = sys.stdin.readline
sys.setrecursionlimit(10**9)

def main():
    n, m = map(int, input().split())
    g = [[] for i in range(n)]
    deg2 = [0]*n
    atode = []
    for i in range(m):
        s, t = map(int, input().split())
        g[s-1].append(t-1)
        deg2[s-1] += 1
        atode.append((s-1,t-1))

    ee = [-1]*n
    def rec2(cur, s,t):
        if ee[cur] != -1:
            return ee[cur]
        res = 0
        cnt = 0
        for to in g[cur]:
            if cur==s and to ==t:
                continue
            res += rec2(to,s,t)+1
            cnt += 1
        if cnt:
            res /= cnt
        ee[cur] = res
        return ee[cur]

    rec2(0,-1,-1)
    ret = ee[0]

    use = [[-1, -1] for i in range(n)]
    for s,t in atode:
        if deg2[s] < 2:
            continue
        if use[s][1] < ee[t]:
            use[s][0] = t
            use[s][1] = ee[t]

    for s, (t,cost) in enumerate(use):
        if s == -1:
            continue
        ee = [-1]*n
        rec2(0,s,t)
        ret = min(ret, ee[0])
    print(ret)

if __name__ == "__main__":
    main()