Problem: You are given a correct solution of the sudoku puzzle. If you don't know what is the sudoku, you can read about it [here](http://tiny.cc/636xmz).

The picture showing the correct sudoku solution:

<image>

Blocks are bordered with bold black color.

Your task is to change at most 9 elements of this field (i.e. choose some 1 ≤ i, j ≤ 9 and change the number at the position (i, j) to any other number in range [1; 9]) to make it anti-sudoku. The anti-sudoku is the 9 × 9 field, in which:

  * Any number in this field is in range [1; 9]; 
  * each row contains at least two equal elements; 
  * each column contains at least two equal elements; 
  * each 3 × 3 block (you can read what is the block in the link above) contains at least two equal elements. 



It is guaranteed that the answer exists.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases. Then t test cases follow.

Each test case consists of 9 lines, each line consists of 9 characters from 1 to 9 without any whitespaces — the correct solution of the sudoku puzzle.

Output

For each test case, print the answer — the initial field with at most 9 changed elements so that the obtained field is anti-sudoku. If there are several solutions, you can print any. It is guaranteed that the answer exists.

Example

Input


1
154873296
386592714
729641835
863725149
975314628
412968357
631457982
598236471
247189563


Output


154873396
336592714
729645835
863725145
979314628
412958357
631457992
998236471
247789563

Solution (in JAVA):

Solution:

// Codeforces Round #634 (Div. 3) // 2020-04-13 //
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.StringTokenizer;


//  Time limit exceeded on test 2  // during contest

// but after much modification // more efficient code below was accepted ! //

// improvements:
    //   1. row_to_col arr , to map the changes needed, reduced need for
    //      another unnecessary iteration to change values
    //  2.  using StringBuilder to "collect" output as we go along the input
    //      and change it ... this reduces the need for another nested-for loops to print
    //         the matrix again ... >> also much lest out.println calls !! much much faster!!


public class D {
    public static void main(String[] args) {
        FastReader s = new FastReader();

        int t = s.nextInt();

        byte[] row_to_col = {0,3,6,1,4,7,2,5,8};

        for (int i = 0; i < t; i++) {

            byte[][] sudoku = new byte[9][9];
            String tmp = "";
            StringBuilder res = new StringBuilder(81);
            for (byte j = 0; j < 9; j++) {
                tmp = s.next();
                for (byte k = 0; k < 9; k++) {
                    sudoku[j][k] = (byte)(tmp.charAt(k)-48);
                }
                sudoku[j][row_to_col[j]]++;
                if(sudoku[j][row_to_col[j]]==10) sudoku[j][row_to_col[j]]=1;
                for (byte k=0; k<9; k++) {
                    res.append(sudoku[j][k]);
                }
                res.append("\n");
            }

            System.out.println(res);
        }
    }


    static class FastReader
    {
        BufferedReader br;
        StringTokenizer st;

        public FastReader() {
            br = new BufferedReader(new
                    InputStreamReader(System.in));
        }

        String next() {
            while (st == null || !st.hasMoreElements())
            {
                try
                {
                    st = new StringTokenizer(br.readLine());
                }
                catch (IOException e)
                {
                    e.printStackTrace();
                }
            }
            return st.nextToken();
        }

        int nextInt() {
            return Integer.parseInt(next());
        }

        long nextLong() {
            return Long.parseLong(next());
        }

        double nextDouble()
        {
            return Double.parseDouble(next());
        }

        String nextLine() {
            String str = "";
            try
            {
                str = br.readLine();
            }
            catch (IOException e)
            {
                e.printStackTrace();
            }
            return str;
        }
    }
}