Problem: We have a pyramid with N steps, built with blocks. The steps are numbered 1 through N from top to bottom. For each 1≤i≤N, step i consists of 2i-1 blocks aligned horizontally. The pyramid is built so that the blocks at the centers of the steps are aligned vertically.

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A pyramid with N=4 steps

Snuke wrote a permutation of (1, 2, ..., 2N-1) into the blocks of step N. Then, he wrote integers into all remaining blocks, under the following rule:

* The integer written into a block b must be equal to the median of the three integers written into the three blocks directly under b, or to the lower left or lower right of b.



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Writing integers into the blocks

Afterwards, he erased all integers written into the blocks. Now, he only remembers that the integer written into the block of step 1 was x.

Construct a permutation of (1, 2, ..., 2N-1) that could have been written into the blocks of step N, or declare that Snuke's memory is incorrect and such a permutation does not exist.

Constraints

* 2≤N≤10^5
* 1≤x≤2N-1

Input

The input is given from Standard Input in the following format:


N x


Output

If no permutation of (1, 2, ..., 2N-1) could have been written into the blocks of step N, print `No`.

Otherwise, print `Yes` in the first line, then print 2N-1 lines in addition.

The i-th of these 2N-1 lines should contain the i-th element of a possible permutation.

Examples

Input

4 4


Output

Yes
1
6
3
7
4
5
2


Input

2 1


Output

No

Solution (in PYTHON3):

Solution:
from collections import deque
N, x = map(int, input().split())
if x == 1 or x == 2*N-1: print("No")
else:
    A = deque([int(i) for i in range(1, 2*N)])
    Ans = [0 for i in range(2*N-1)]
    if x == 2:
        Ans[N-2], Ans[N-1], Ans[N] = 3, 2, 1
        A.remove(1)
        A.remove(2)
        A.remove(3)
        for i in range(2*N-1):
            if i < N-2 or i > N: Ans[i] = A.popleft()
    else:
        Ans[N-2], Ans[N-1], Ans[N], Ans[N+1] = x-1, x, x+1, x-2
        A.remove(x-1)
        A.remove(x)
        A.remove(x+1)
        A.remove(x-2)
        for i in range(2*N-1):
            if i < N-2 or i > N+1: Ans[i] = A.popleft()
    print("Yes")
    for a in Ans:print(a)