Problem: Find an n × n matrix with different numbers from 1 to n2, so the sum in each row, column and both main diagonals are odd.

Input

The only line contains odd integer n (1 ≤ n ≤ 49).

Output

Print n lines with n integers. All the integers should be different and from 1 to n2. The sum in each row, column and both main diagonals should be odd.

Examples

Input

1


Output

1


Input

3


Output

2 1 4
3 5 7
6 9 8

Solution (in PYTHON3):

Solution:
n=int(input())

def fun(n,s,nn):	
 mas=[[0]*(n) for i in range(n)]
 start=n//2
 i=0
 j=start

 for value in range(s,nn):
     if i<0 and j>n-1:
     	i=n-1
     	j=n-1
     	if mas[i][j]!=0:
     		i=1
     		j=n-1
     if i<0:
     	i=n-1
     if j>n-1:
     	j=0
     if mas[i][j]!=0:
         i=i+2
         j=j-1
     mas[i][j]=value
     i=i-1
     j=j+1
 return mas

if n%2!=0:
 mas=fun(n,1,n**2+1)    
 for i in range(n):
    t=[]
    for y in range(n):
        t.append(str(mas[i][y]))
    print(" ".join(t))