Problem: You are given a correct solution of the sudoku puzzle. If you don't know what is the sudoku, you can read about it [here](http://tiny.cc/636xmz).

The picture showing the correct sudoku solution:

<image>

Blocks are bordered with bold black color.

Your task is to change at most 9 elements of this field (i.e. choose some 1 ≤ i, j ≤ 9 and change the number at the position (i, j) to any other number in range [1; 9]) to make it anti-sudoku. The anti-sudoku is the 9 × 9 field, in which:

  * Any number in this field is in range [1; 9]; 
  * each row contains at least two equal elements; 
  * each column contains at least two equal elements; 
  * each 3 × 3 block (you can read what is the block in the link above) contains at least two equal elements. 



It is guaranteed that the answer exists.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases. Then t test cases follow.

Each test case consists of 9 lines, each line consists of 9 characters from 1 to 9 without any whitespaces — the correct solution of the sudoku puzzle.

Output

For each test case, print the answer — the initial field with at most 9 changed elements so that the obtained field is anti-sudoku. If there are several solutions, you can print any. It is guaranteed that the answer exists.

Example

Input


1
154873296
386592714
729641835
863725149
975314628
412968357
631457982
598236471
247189563


Output


154873396
336592714
729645835
863725145
979314628
412958357
631457992
998236471
247789563

Solution (in PYTHON):

Solution:
t = input()


for _ in xrange(t):
	rows = []
	for _ in xrange(9):
		rows.append(
			map(int, list(raw_input().strip()))
		)

	for i in xrange(9):
		for j in xrange(9):
			if rows[i][j] == 2:
				rows[i][j] = 3
	# rows_used = set()
	# cols_used = set()
	# blocks_used = set()
	# nums_used = set()
	# # print rows
	# num_to_use = 1
	# for i in xrange(9):
	# 	for j in xrange(9):
	# 		block_id = (i / 3, j / 3)
	# 		if i not in rows_used and j not in cols_used and block_id not in blocks_used and rows[i][j] != num_to_use:
	# 			rows_used.add(i)
	# 			cols_used.add(j)
	# 			blocks_used.add(block_id)
	# 			rows[i][j] = num_to_use
	# 			num_to_use += 1
	# 			# print i, j

	for row in rows:
		print "".join(map(str, row))