Problem: Find an n × n matrix with different numbers from 1 to n2, so the sum in each row, column and both main diagonals are odd.

Input

The only line contains odd integer n (1 ≤ n ≤ 49).

Output

Print n lines with n integers. All the integers should be different and from 1 to n2. The sum in each row, column and both main diagonals should be odd.

Examples

Input

1


Output

1


Input

3


Output

2 1 4
3 5 7
6 9 8

Solution (in PYTHON3):

Solution:
n = int(input()) #always odd
#takes the shape of an expanding cross
evenNums = list(range(2, n**2+1, 2))
oddNums = list(range(1, n**2+1, 2))
for i in range(n):
    outList = []
    if i > n//2:
        oddNumIndeces = (list(range(n//2+i-n+1,n//2-(i-n))))
    else:
        oddNumIndeces = list(range(n//2-i,n//2+i+1))   
    for j in range(n):
        
        
            
        if j not in oddNumIndeces:
            outList.append(str(evenNums[0]))
            evenNums.pop(0)
        else:
            outList.append(str(oddNums[0]))
            oddNums.pop(0)
        
    print(" ".join(outList))