Problem: Find an n × n matrix with different numbers from 1 to n2, so the sum in each row, column and both main diagonals are odd.

Input

The only line contains odd integer n (1 ≤ n ≤ 49).

Output

Print n lines with n integers. All the integers should be different and from 1 to n2. The sum in each row, column and both main diagonals should be odd.

Examples

Input

1


Output

1


Input

3


Output

2 1 4
3 5 7
6 9 8

Solution (in PYTHON3):

Solution:
n = int(input())
used = set()
odd = 1
even = 2
data = [[0]*n for i in range(n)]
rombs = n//2
rombe = n//2

for x in range(n):
  for y in range(n):
    if rombs <= y <= rombe:
      data[y][x] = str(odd)
      odd += 2
    else:
      data[y][x] = str(even)
      even += 2
  
  if x < n//2:
    rombs -= 1
    rombe += 1
  else:
    rombs += 1
    rombe -= 1

for i in data:
  print(' '.join(i))