Problem: Today Pari and Arya are playing a game called Remainders.

Pari chooses two positive integer x and k, and tells Arya k but not x. Arya have to find the value <image>. There are n ancient numbers c1, c2, ..., cn and Pari has to tell Arya <image> if Arya wants. Given k and the ancient values, tell us if Arya has a winning strategy independent of value of x or not. Formally, is it true that Arya can understand the value <image> for any positive integer x?

Note, that <image> means the remainder of x after dividing it by y.

Input

The first line of the input contains two integers n and k (1 ≤ n, k ≤ 1 000 000) — the number of ancient integers and value k that is chosen by Pari.

The second line contains n integers c1, c2, ..., cn (1 ≤ ci ≤ 1 000 000).

Output

Print "Yes" (without quotes) if Arya has a winning strategy independent of value of x, or "No" (without quotes) otherwise.

Examples

Input

4 5
2 3 5 12


Output

Yes


Input

2 7
2 3


Output

No

Note

In the first sample, Arya can understand <image> because 5 is one of the ancient numbers.

In the second sample, Arya can't be sure what <image> is. For example 1 and 7 have the same remainders after dividing by 2 and 3, but they differ in remainders after dividing by 7.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
const int maxn = 1000005;
const int logn = 18;
const int inf = (int)1e9 + 5;
const long long mod = (long long)1e9 + 7;
const long long base = 2204234849;
const long long l_inf = (long long)4e18;
const long double pi = acos(-1.0);
const long double eps = 1e-12;
int n, k;
int c[maxn];
vector<int> divs;
int main() {
  ios_base::sync_with_stdio(false);
  cout.precision(20);
  cout << fixed;
  srand(566);
  scanf("%d%d", &n, &k);
  for (int i = 0; i < n; i++) scanf("%d", &c[i]);
  for (int i = 2; i * i <= k; i++) {
    if (k % i == 0) {
      divs.push_back(1);
      while (k % i == 0) {
        k /= i;
        divs.back() *= i;
      }
    }
  }
  if (k != 1) divs.push_back(k);
  for (int d : divs) {
    bool found = false;
    for (int i = 0; i < n && !found; i++) found |= c[i] % d == 0;
    if (!found) {
      printf("No\n");
      exit(0);
    }
  }
  printf("Yes\n");
  return 0;
}