Problem: Find an n × n matrix with different numbers from 1 to n2, so the sum in each row, column and both main diagonals are odd.

Input

The only line contains odd integer n (1 ≤ n ≤ 49).

Output

Print n lines with n integers. All the integers should be different and from 1 to n2. The sum in each row, column and both main diagonals should be odd.

Examples

Input

1


Output

1


Input

3


Output

2 1 4
3 5 7
6 9 8

Solution (in PYTHON3):

Solution:
n = int(input())
a = [[0] * n for _ in range(n)]

odds = iter(range(1, n ** 2 + 1, 2))
evens = iter(range(2, n ** 2 + 1, 2))

for i in range((n + 1) // 2):
    for j in range(n):
        a[i][j] = next(odds) if i + j >= n // 2 >= j - i else next(evens)

for i in range((n + 1) // 2, n):
    for j in range(n):
        a[i][j] = next(odds) if i - j <= n // 2 and i + j <= (n - 1) + n // 2 else next(evens)

for i in range(n):
    print(*a[i])