Problem: You are given a correct solution of the sudoku puzzle. If you don't know what is the sudoku, you can read about it [here](http://tiny.cc/636xmz).

The picture showing the correct sudoku solution:

<image>

Blocks are bordered with bold black color.

Your task is to change at most 9 elements of this field (i.e. choose some 1 ≤ i, j ≤ 9 and change the number at the position (i, j) to any other number in range [1; 9]) to make it anti-sudoku. The anti-sudoku is the 9 × 9 field, in which:

  * Any number in this field is in range [1; 9]; 
  * each row contains at least two equal elements; 
  * each column contains at least two equal elements; 
  * each 3 × 3 block (you can read what is the block in the link above) contains at least two equal elements. 



It is guaranteed that the answer exists.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases. Then t test cases follow.

Each test case consists of 9 lines, each line consists of 9 characters from 1 to 9 without any whitespaces — the correct solution of the sudoku puzzle.

Output

For each test case, print the answer — the initial field with at most 9 changed elements so that the obtained field is anti-sudoku. If there are several solutions, you can print any. It is guaranteed that the answer exists.

Example

Input


1
154873296
386592714
729641835
863725149
975314628
412968357
631457982
598236471
247189563


Output


154873396
336592714
729645835
863725145
979314628
412958357
631457992
998236471
247789563

Solution (in PYTHON3):

Solution:
def center(n):
    x = 1 + ((n // 3) * 3)
    y = 1 + ((n % 3) * 3)
    return (x, y)


N = int(input())
for _ in range(N):
    field = [[int(i) for i in input()] for j in range(9)]
    for i in range(9):
        if i == 0:
            field[0][0] = field[0][1]
        elif i == 1:
            field[1][3] = field[1][4]
        elif i == 2:
            field[2][6] = field[2][7]
        elif i == 3:
            field[3][1] = field[3][2]
        elif i == 4:
            field[4][4] = field[4][5]
        elif i == 5:
            field[5][7] = field[5][8]
        elif i == 6:
            field[6][2] = field[6][0]
        elif i == 7:
            field[7][5] = field[7][3]
        elif i == 8:
            field[8][8] = field[8][6]

    for i in field:
        print(''.join(list(map(str, i))))