Problem: Today Pari and Arya are playing a game called Remainders.

Pari chooses two positive integer x and k, and tells Arya k but not x. Arya have to find the value <image>. There are n ancient numbers c1, c2, ..., cn and Pari has to tell Arya <image> if Arya wants. Given k and the ancient values, tell us if Arya has a winning strategy independent of value of x or not. Formally, is it true that Arya can understand the value <image> for any positive integer x?

Note, that <image> means the remainder of x after dividing it by y.

Input

The first line of the input contains two integers n and k (1 ≤ n, k ≤ 1 000 000) — the number of ancient integers and value k that is chosen by Pari.

The second line contains n integers c1, c2, ..., cn (1 ≤ ci ≤ 1 000 000).

Output

Print "Yes" (without quotes) if Arya has a winning strategy independent of value of x, or "No" (without quotes) otherwise.

Examples

Input

4 5
2 3 5 12


Output

Yes


Input

2 7
2 3


Output

No

Note

In the first sample, Arya can understand <image> because 5 is one of the ancient numbers.

In the second sample, Arya can't be sure what <image> is. For example 1 and 7 have the same remainders after dividing by 2 and 3, but they differ in remainders after dividing by 7.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
bool known[1000005] = {0};
int c[1000005];
int gcd(int a, int b) {
  if (!b) return a;
  return gcd(b, a % b);
}
void calc(int n, int k) {
  for (int i = 0; i < n; ++i) {
    if (known[c[i]] or gcd(c[i], k) == 1) continue;
    known[c[i]] = true;
    int sq = sqrt(c[i]);
    for (int j = 2; j <= sq; ++j) {
      if (c[i] % j == 0) {
        known[j] = true;
        known[c[i] / j] = true;
      }
    }
    if (known[k]) return;
  }
}
bool check(int k) {
  if (known[k]) return true;
  int sq = sqrt(k), temp = k;
  for (int i = 2; i <= sq; ++i) {
    if (temp % i == 0) {
      int x = 1;
      while (temp % i == 0) {
        temp /= i;
        x *= i;
      }
      if (!known[x]) return false;
    }
  }
  return known[temp];
}
int main() {
  ios_base::sync_with_stdio(false);
  int n, k;
  cin >> n >> k;
  known[1] = true;
  for (int i = 0; i < n; ++i) {
    cin >> c[i];
    if (c[i] % k == 0) known[k] = true;
  }
  if (known[k]) {
    cout << "Yes";
    return 0;
  }
  calc(n, k);
  if (check(k))
    cout << "Yes";
  else
    cout << "No";
}