Problem: Find an n × n matrix with different numbers from 1 to n2, so the sum in each row, column and both main diagonals are odd.

Input

The only line contains odd integer n (1 ≤ n ≤ 49).

Output

Print n lines with n integers. All the integers should be different and from 1 to n2. The sum in each row, column and both main diagonals should be odd.

Examples

Input

1


Output

1


Input

3


Output

2 1 4
3 5 7
6 9 8

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int a[55][55];
int main() {
  int n;
  scanf("%d", &n);
  memset(a, 0, sizeof(a));
  int p = 1, q = 2, nn = n / 2 + 1;
  for (int i = 1; i <= n; ++i) {
    a[nn][i] = p;
    p += 2;
  }
  for (int i = 1; i <= n; ++i) {
    if (i != nn) {
      a[i][nn] = p;
      p += 2;
    }
  }
  int maxn = n * n;
  for (int i = 1; i < nn; ++i) {
    for (int j = 1; j < nn; ++j) {
      if (p <= maxn) {
        a[i][j] = p;
        a[n + 1 - i][j] = p + 2;
        a[n + 1 - i][n + 1 - j] = p + 4;
        a[i][n + 1 - j] = p + 6;
        p += 8;
      } else {
        a[i][j] = q;
        a[n + 1 - i][j] = q + 2;
        a[n + 1 - i][n + 1 - j] = q + 4;
        a[i][n + 1 - j] = q + 6;
        q += 8;
      }
    }
  }
  for (int i = 1; i <= n; ++i) {
    for (int j = 1; j <= n; ++j) printf("%d ", a[i][j]);
    printf("\n");
  }
  return 0;
}