Problem: We have a tree with N vertices. The vertices are numbered 1 to N, and the i-th edge connects Vertex a_i and Vertex b_i.

Takahashi loves the number 3. He is seeking a permutation p_1, p_2, \ldots , p_N of integers from 1 to N satisfying the following condition:

* For every pair of vertices (i, j), if the distance between Vertex i and Vertex j is 3, the sum or product of p_i and p_j is a multiple of 3.



Here the distance between Vertex i and Vertex j is the number of edges contained in the shortest path from Vertex i to Vertex j.

Help Takahashi by finding a permutation that satisfies the condition.

Constraints

* 2\leq N\leq 2\times 10^5
* 1\leq a_i, b_i \leq N
* The given graph is a tree.

Input

Input is given from Standard Input in the following format:


N
a_1 b_1
a_2 b_2
\vdots
a_{N-1} b_{N-1}


Output

If no permutation satisfies the condition, print `-1`.

Otherwise, print a permutation satisfying the condition, with space in between. If there are multiple solutions, you can print any of them.

Example

Input

5
1 2
1 3
3 4
3 5


Output

1 2 5 4 3

Solution (in PYTHON3):

Solution:
import sys
from collections import defaultdict as dd
input = sys.stdin.readline
sys.setrecursionlimit(10 ** 6)
N = int(input())
e = dd(list)
for _ in range(N - 1):
  u, v = map(int, input().split())
  e[u].append(v)
  e[v].append(u)

cl = [0] * (N + 1)
vis = set()
def dfs(x):
  global cl
  global vis
  vis.add(x)
  for y in e[x]:
    if y in vis: continue
    cl[y] = (cl[x] + 1) % 2
    dfs(y)

dfs(1)
bl = cl.count(1)
wh = N - bl
res = [0] * (N + 1)
nm = [[] for _ in range(3)]
for i in range(1, N + 1): nm[i % 3].append(i)
#print(cl)
if bl <= N // 3:
  for i in range(1, N + 1):
    if cl[i]:
      res[i] = nm[0].pop()
    else:
      if len(nm[1]): res[i] = nm[1].pop()
      elif len(nm[2]): res[i] = nm[2].pop()
      else: res[i] = nm[0].pop()
  print(*res[1: ])
  exit(0)
if wh <= N // 3:
  for i in range(1, N + 1):
    if cl[i] == 0:
      res[i] = nm[0].pop()
    else:
      if len(nm[1]): res[i] = nm[1].pop()
      elif len(nm[2]): res[i] = nm[2].pop()
      else: res[i] = nm[0].pop()
  print(*res[1: ])
  exit(0)
#print(nm)
#print(cl, nm)
f = 0
for i in range(1, N + 1):
  if cl[i]:
    if len(nm[1]):
      res[i] = nm[1].pop()
    else:
      res[i] = nm[0].pop()
  else:
    if len(nm[2]):
      res[i] = nm[2].pop()
    else:
      res[i] = nm[0].pop()

print(*res[1: ])