Problem: Find an n × n matrix with different numbers from 1 to n2, so the sum in each row, column and both main diagonals are odd.

Input

The only line contains odd integer n (1 ≤ n ≤ 49).

Output

Print n lines with n integers. All the integers should be different and from 1 to n2. The sum in each row, column and both main diagonals should be odd.

Examples

Input

1


Output

1


Input

3


Output

2 1 4
3 5 7
6 9 8

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int n, a[2500][2500];
void solve(int n) {
  int i = n / 2, j = n - 1;
  for (int k = 0; k <= n * n;) {
    if (i == -1 && j == n) {
      j = n - 2;
      i = 0;
    } else {
      if (j == n) j = 0;
      if (i < 0) i = n - 1;
    }
    if (a[i][j]) {
      j -= 2;
      ++i;
      continue;
    } else
      a[i][j] = ++k;
    ++j;
    --i;
  }
}
int main() {
  cin >> n;
  solve(n);
  for (int i = 0; i < n; ++i) {
    for (int j = 0; j < n; ++j) {
      cout << a[i][j] << " ";
    }
    cout << "\n";
  }
}