Problem: Find an n × n matrix with different numbers from 1 to n2, so the sum in each row, column and both main diagonals are odd.

Input

The only line contains odd integer n (1 ≤ n ≤ 49).

Output

Print n lines with n integers. All the integers should be different and from 1 to n2. The sum in each row, column and both main diagonals should be odd.

Examples

Input

1


Output

1


Input

3


Output

2 1 4
3 5 7
6 9 8

Solution (in JAVA):

Solution:
import java.util.*;

public class C {
	
	public static void main(String[] args){
		Scanner sc = new Scanner(System.in);
		int n = sc.nextInt();
		int odd = 0, even = 1;
		int arr[][] = new int[n][n];
		StringBuilder sb = new StringBuilder();
		
		for(int i=0;i<n;i++){
			for(int j=0;j<n;j++){
				if(arr[i][j]!=0)	continue;
				if(j<n/2 && even*2<=n*n){
					arr[i][j] = even++*2;
					arr[i][n-1-j] = even++*2;
					arr[n-1-i][j] = even++*2;
					arr[n-1-i][n-1-j] = even++*2;
				}
				else{
					arr[i][j] = odd++*2+1;
				}
			}
		}
			
		for(int i=0;i<n;i++){
			for(int j=0;j<n;j++){
				sb.append(arr[i][j]+" ");
			}
			sb.append("\n");
		}
		
		System.out.print(sb);
		
	}
}