Problem: Find an n × n matrix with different numbers from 1 to n2, so the sum in each row, column and both main diagonals are odd.

Input

The only line contains odd integer n (1 ≤ n ≤ 49).

Output

Print n lines with n integers. All the integers should be different and from 1 to n2. The sum in each row, column and both main diagonals should be odd.

Examples

Input

1


Output

1


Input

3


Output

2 1 4
3 5 7
6 9 8

Solution (in PYTHON3):

Solution:
from math import *

n = int(input())
nn = 1
nc = 2
a = []
for i in range(n):
    a.append([0] * n)
    for q in range(n):
        #print(i, q, (n - 1) // 2 - i + (n - 1) // 2 - q)
        if abs((n - 1) // 2 - i) + abs((n - 1) // 2 - q) <= (n - 1) // 2:
            a[i][q] = nn
            nn += 2
        else:
            a[i][q] = nc
            nc += 2
for i in range(n):
    print(*a[i])