Problem: You are given a correct solution of the sudoku puzzle. If you don't know what is the sudoku, you can read about it [here](http://tiny.cc/636xmz).

The picture showing the correct sudoku solution:

<image>

Blocks are bordered with bold black color.

Your task is to change at most 9 elements of this field (i.e. choose some 1 ≤ i, j ≤ 9 and change the number at the position (i, j) to any other number in range [1; 9]) to make it anti-sudoku. The anti-sudoku is the 9 × 9 field, in which:

  * Any number in this field is in range [1; 9]; 
  * each row contains at least two equal elements; 
  * each column contains at least two equal elements; 
  * each 3 × 3 block (you can read what is the block in the link above) contains at least two equal elements. 



It is guaranteed that the answer exists.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases. Then t test cases follow.

Each test case consists of 9 lines, each line consists of 9 characters from 1 to 9 without any whitespaces — the correct solution of the sudoku puzzle.

Output

For each test case, print the answer — the initial field with at most 9 changed elements so that the obtained field is anti-sudoku. If there are several solutions, you can print any. It is guaranteed that the answer exists.

Example

Input


1
154873296
386592714
729641835
863725149
975314628
412968357
631457982
598236471
247189563


Output


154873396
336592714
729645835
863725145
979314628
412958357
631457992
998236471
247789563

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
using LL = long long;
template <class T>
int size(T &&x) {
  return int(x.size());
}
template <class A, class B>
ostream &operator<<(ostream &out, const pair<A, B> &p) {
  return out << '(' << p.first << ", " << p.second << ')';
}
template <class T>
auto operator<<(ostream &out, T &&x) -> decltype(x.begin(), out) {
  out << '{';
  for (auto it = x.begin(); it != x.end(); ++it)
    out << *it << (it == prev(x.end()) ? "" : ", ");
  return out << '}';
}
void dump() {}
template <class T, class... Args>
void dump(T &&x, Args... args) {
  cerr << x << ";  ";
  dump(args...);
}
mt19937_64 rng(0);
int rd(int l, int r) { return uniform_int_distribution<int>(l, r)(rng); }
int main() {
  ios_base::sync_with_stdio(0);
  cin.tie(0);
  int t;
  cin >> t;
  while (t-- > 0) {
    constexpr int n = 9;
    vector<string> in(n);
    for (int y = (0); y <= ((n)-1); ++y) cin >> in[y];
    vector<pair<int, int>> change = {{0, 0}, {1, 3}, {2, 6}, {3, 1}, {4, 4},
                                     {5, 7}, {6, 2}, {7, 5}, {8, 8}};
    for (auto [x, y] : change)
      if (in[x][y] == '1')
        in[x][y] = '2';
      else
        in[x][y] = '1';
    for (int y = (0); y <= ((n)-1); ++y) {
      for (char c : in[y]) cout << c;
      cout << '\n';
    }
  }
}