Problem: Find an n × n matrix with different numbers from 1 to n2, so the sum in each row, column and both main diagonals are odd.

Input

The only line contains odd integer n (1 ≤ n ≤ 49).

Output

Print n lines with n integers. All the integers should be different and from 1 to n2. The sum in each row, column and both main diagonals should be odd.

Examples

Input

1


Output

1


Input

3


Output

2 1 4
3 5 7
6 9 8

Solution (in PYTHON3):

Solution:
n = int(input())
a = [[0] * n for _ in range(n)]

def od(i, j):
    k = min(i + 1, n - i)
    return abs(j - n // 2) < k

u, v = 0, 0
for i in range(n):
    for j in range(n):
        if od(i, j):
            u += 1
            a[i][j] = u * 2 - 1
        else:
            v += 1
            a[i][j] = v * 2

print('\n'.join(map(lambda x: ' '.join(map(str, x)), a)))