Problem: Find an n × n matrix with different numbers from 1 to n2, so the sum in each row, column and both main diagonals are odd.

Input

The only line contains odd integer n (1 ≤ n ≤ 49).

Output

Print n lines with n integers. All the integers should be different and from 1 to n2. The sum in each row, column and both main diagonals should be odd.

Examples

Input

1


Output

1


Input

3


Output

2 1 4
3 5 7
6 9 8

Solution (in PYTHON3):

Solution:
n=int(input())
a=[i for i in range(1,n*n+1)]
even=[]
odd=[]
for x in a:
    if x%2==0:
        even.append(x)
    else:
        odd.append(x)

c=1

for i in range(n):
    si=(n-c)//2
    ei=si+c-1
    for j in range(n):
        if j>=si and j<=ei:
            print(odd[0],end=" ")
            odd.pop(0)
        else:
            print(even[0],end=" ")
            even.pop(0)
    print()

    if i>=n//2:
        c-=2
    else:
        c+=2


    
    


"""
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"""