Problem: You are given a correct solution of the sudoku puzzle. If you don't know what is the sudoku, you can read about it [here](http://tiny.cc/636xmz).

The picture showing the correct sudoku solution:

<image>

Blocks are bordered with bold black color.

Your task is to change at most 9 elements of this field (i.e. choose some 1 ≤ i, j ≤ 9 and change the number at the position (i, j) to any other number in range [1; 9]) to make it anti-sudoku. The anti-sudoku is the 9 × 9 field, in which:

  * Any number in this field is in range [1; 9]; 
  * each row contains at least two equal elements; 
  * each column contains at least two equal elements; 
  * each 3 × 3 block (you can read what is the block in the link above) contains at least two equal elements. 



It is guaranteed that the answer exists.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases. Then t test cases follow.

Each test case consists of 9 lines, each line consists of 9 characters from 1 to 9 without any whitespaces — the correct solution of the sudoku puzzle.

Output

For each test case, print the answer — the initial field with at most 9 changed elements so that the obtained field is anti-sudoku. If there are several solutions, you can print any. It is guaranteed that the answer exists.

Example

Input


1
154873296
386592714
729641835
863725149
975314628
412968357
631457982
598236471
247189563


Output


154873396
336592714
729645835
863725145
979314628
412958357
631457992
998236471
247789563

Solution (in PYTHON3):

Solution:
for _ in range(int(input())):
    arr=[None]*9
    ans=[None]*9
    for i in range(9):
        arr[i]=input()
        ans[i]=list(arr[i])
    ones=[None]*9
    s=set()
    for i in range(9):
        for j in range(9):
            if arr[i][j]=="1":
                # u=
                if (i//3)*3+((i+1)%3) not in s:
                    ans[(i//3)*3+((i+1)%3)][j]="1"
                    s.add((i//3)*3+((i+1)%3))
                elif (i//3)*3+((i+2)%3) not in s:
                    ans[(i//3)*3+((i+2)%3)][j]="1"
                    s.add((i//3)*3+((i+2)%3))
    for i in range(9):
        print("".join(ans[i]))