Problem: Find an n × n matrix with different numbers from 1 to n2, so the sum in each row, column and both main diagonals are odd.

Input

The only line contains odd integer n (1 ≤ n ≤ 49).

Output

Print n lines with n integers. All the integers should be different and from 1 to n2. The sum in each row, column and both main diagonals should be odd.

Examples

Input

1


Output

1


Input

3


Output

2 1 4
3 5 7
6 9 8

Solution (in PYTHON3):

Solution:
n = int(input())

arr = []
kC = 2
for i in range(n):
    arr.append([])
    for j in range(n):
        arr[i].append(0)
kN = 1
kS = 1
for i in range(n//2 + 1):
    k = 0
    for j in range(n // 2, n):
        
        if  k == 0:
            arr[i][j] = kN
            kN += 2
            k += 1
        elif k + 2 <= kS:
            arr[i][j] = kN
            kN += 2
            arr[i][n // 2 - (k - 1) // 2 - 1] = kN
            kN += 2
            k += 2
        else:
            break
    kS += 2
kS = n - 2
for i in range(n//2 + 1, n):
    k = 0
    for j in range(n // 2, n):
        
        if  k == 0:
            arr[i][j] = kN
            kN += 2
            k += 1
        elif k + 2 <= kS:
            arr[i][j] = kN
            kN += 2
            arr[i][n // 2 - (k - 1) // 2 - 1] = kN
            kN += 2
            k += 2
        else:
            break
    kS -= 2
kC = 2
for i in range(n):
    for j in range(n):
        if arr[i][j] == 0:
            arr[i][j] = kC
            kC += 2
    print(*arr[i])