Problem: For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.

* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$.
* get($key$): Print the value with the specified $key$. Print 0 if there is no such element.
* delete($key$): Delete the element with the specified $key$.

Constraints

* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consits of lower case letters

Input

The input is given in the following format.


$q$
$query_1$
$query_2$
:
$query_q$


Each query $query_i$ is given by


0 $key$ $x$


or


1 $key$


or


2 $key$


where the first digits 0, 1 and 2 represent insert, get and delete operations respectively.

Output

For each get operation, print an integer in a line.

Example

Input

8
0 blue 4
0 red 1
0 white 5
1 red
1 blue
2 red
1 black
1 red


Output

1
4
0
0

Solution (in CPP):

Solution:
#include <iostream>
#include <cstdio>
#include <vector>
#include <algorithm>
#include <map>
#include <numeric>
#include <string>
#include <cmath>
#include <iomanip>
#include <queue>
#include <list>
#include <set>
#include <stack>
#include <cctype>
#include <cmath>

using namespace std;

/* typedef */
typedef long long ll;

/* constant */
const int INF = 1 << 30;
const int NIL = -1;
const int MAX = 10000;
const int mod = 1000000007;
const double pi = 3.141592653589;

/* global variables */

/* function */

/* main */
int main(){

    int q; cin >> q;
    int op, x;
    string key;
    map<string, int> M;

    for (int i = 0; i < q; i++) {
        cin >> op >> key;
        switch(op) {
            case 0:
                cin >> x;
                // insert(key, x) :
                // Insert an element formed by a pair of key and x to M
                M[key] = x;
                break;
            case 1:
                // get(key): Print the value with the specified key
                if (M.count(key))
                    cout << M[key] << '\n';
                else
                    cout << 0 << '\n';
                break;
            case 2:
                // delete(key)
                M.erase(key);
                break;
        }
    }

}