Problem: Find the sum of weights of edges of the Minimum Spanning Tree for a given weighted undirected graph G = (V, E).

Constraints

* 1 ≤ |V| ≤ 10,000
* 0 ≤ |E| ≤ 100,000
* 0 ≤ wi ≤ 10,000
* The graph is connected
* There are no parallel edges
* There are no self-loops

Input


|V| |E|
s0 t0 w0
s1 t1 w1
:
s|E|-1 t|E|-1 w|E|-1


, where |V| is the number of vertices and |E| is the number of edges in the graph. The graph vertices are named with the numbers 0, 1,..., |V|-1 respectively.

si and ti represent source and target verticess of i-th edge (undirected) and wi represents the weight of the i-th edge.

Output

Print the sum of the weights of the Minimum Spanning Tree.

Examples

Input

4 6
0 1 2
1 2 1
2 3 1
3 0 1
0 2 3
1 3 5


Output

3


Input

6 9
0 1 1
0 2 3
1 2 1
1 3 7
2 4 1
1 4 3
3 4 1
3 5 1
4 5 6


Output

5

Solution (in CPP):

Solution:
#include "bits/stdc++.h"

using namespace std;

class UnionFind
{
    vector<int> par;

public:
    UnionFind(int n) : par(n, -1) {}

    int root(int x)
    {
        if (par[x] < 0)
            return x;
        else
            return par[x] = root(par[x]);
    }

    bool merge(int x, int y)
    {
        x = root(x);
        y = root(y);
        if (x == y)
            return false;
        if (par[x] > par[y])
            swap(x, y);
        par[x] += par[y];
        par[y] = x;
        return true;
    }

    int size(int x) { return -par[root(x)]; }
};

void solve()
{
    int n, m;
    cin >> n >> m;
    UnionFind uf(n);
    priority_queue<pair<long, pair<int, int>>> es;
    while (m--)
    {
        int s, t;
        long w;
        cin >> s >> t >> w;
        es.push(make_pair(-w, make_pair(s, t)));
    }
    long ans = 0;
    while (!es.empty())
    {
        auto p = es.top();
        es.pop();
        if (uf.merge(p.second.first, p.second.second))
        {
            ans -= p.first;
        }
    }
    cout << ans << endl;
}

int main()
{
    solve();
    return 0;
}