Problem: A permutation is a sequence of n integers from 1 to n, in which all numbers occur exactly once. For example, [1], [3, 5, 2, 1, 4], [1, 3, 2] are permutations, and [2, 3, 2], [4, 3, 1], [0] are not.

Polycarp was presented with a permutation p of numbers from 1 to n. However, when Polycarp came home, he noticed that in his pocket, the permutation p had turned into an array q according to the following rule: 

  * q_i = max(p_1, p_2, …, p_i). 



Now Polycarp wondered what lexicographically minimal and lexicographically maximal permutations could be presented to him.

An array a of length n is lexicographically smaller than an array b of length n if there is an index i (1 ≤ i ≤ n) such that the first i-1 elements of arrays a and b are the same, and the i-th element of the array a is less than the i-th element of the array b. For example, the array a=[1, 3, 2, 3] is lexicographically smaller than the array b=[1, 3, 4, 2].

For example, if n=7 and p=[3, 2, 4, 1, 7, 5, 6], then q=[3, 3, 4, 4, 7, 7, 7] and the following permutations could have been as p initially: 

  * [3, 1, 4, 2, 7, 5, 6] (lexicographically minimal permutation); 
  * [3, 1, 4, 2, 7, 6, 5]; 
  * [3, 2, 4, 1, 7, 5, 6]; 
  * [3, 2, 4, 1, 7, 6, 5] (lexicographically maximum permutation). 



For a given array q, find the lexicographically minimal and lexicographically maximal permutations that could have been originally presented to Polycarp.

Input

The first line contains one integer t (1 ≤ t ≤ 10^4). Then t test cases follow.

The first line of each test case contains one integer n (1 ≤ n ≤ 2 ⋅ 10^5).

The second line of each test case contains n integers q_1, q_2, …, q_n (1 ≤ q_i ≤ n).

It is guaranteed that the array q was obtained by applying the rule from the statement to some permutation p.

It is guaranteed that the sum of n over all test cases does not exceed 2 ⋅ 10^5.

Output

For each test case, output two lines: 

  * on the first line output n integers — lexicographically minimal permutation that could have been originally presented to Polycarp; 
  * on the second line print n integers — lexicographically maximal permutation that could have been originally presented to Polycarp; 

Example

Input


4
7
3 3 4 4 7 7 7
4
1 2 3 4
7
3 4 5 5 5 7 7
1
1


Output


3 1 4 2 7 5 6 
3 2 4 1 7 6 5 
1 2 3 4 
1 2 3 4 
3 4 5 1 2 7 6 
3 4 5 2 1 7 6 
1 
1 

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.*;

import static java.lang.Math.*;
import static java.util.Arrays.*;

public class CF1506E {
    public static void main(String[] args) throws IOException {
        int t = ri();
        while (t --> 0) {
            int n = ri(), q[] = ria(n), ans1[] = new int[n], ans2[] = new int[n];
            ans1[0] = ans2[0] = q[0];
            boolean[] used = new boolean[n + 1];
            used[q[0]] = true;
            int j = 1;
            for (int i = 1; i < n; ++i) {
                if (q[i] != q[i - 1]) {
                    ans1[i] = q[i];
                    used[q[i]] = true;
                } else {
                    while (used[j]) ++j;
                    ans1[i] = j;
                    used[j] = true;
                }
            }

            TreeSet<Integer> set = new TreeSet<>();
            for (int i = 1; i <= n; ++i) {
                set.add(i);
            }
            for (int i = 0; i < n; ++i) {
                ans2[i] = set.floor(q[i]);
                set.remove(ans2[i]);
            }
            prln(ans1);
            prln(ans2);
        }
        close();
    }

    static BufferedReader __i = new BufferedReader(new InputStreamReader(System.in));
    static PrintWriter __o = new PrintWriter(new OutputStreamWriter(System.out));
    static StringTokenizer input;
    static Random __r = new Random();

    // references
    // IBIG = 1e9 + 7
    // IMAX ~= 2e9
    // LMAX ~= 9e18

    // constants
    static final int IBIG = 1000000007;
    static final int IMAX = 2147483647;
    static final int IMIN = -2147483648;
    static final long LMAX = 9223372036854775807L;
    static final long LMIN = -9223372036854775808L;

    // math util
    static int minof(int a, int b, int c) {
        return min(a, min(b, c));
    }

    static int minof(int... x) {
        if (x.length == 1) return x[0];
        if (x.length == 2) return min(x[0], x[1]);
        if (x.length == 3) return min(x[0], min(x[1], x[2]));
        int min = x[0];
        for (int i = 1; i < x.length; ++i) if (x[i] < min) min = x[i];
        return min;
    }

    static long minof(long a, long b, long c) {
        return min(a, min(b, c));
    }

    static long minof(long... x) {
        if (x.length == 1) return x[0];
        if (x.length == 2) return min(x[0], x[1]);
        if (x.length == 3) return min(x[0], min(x[1], x[2]));
        long min = x[0];
        for (int i = 1; i < x.length; ++i) if (x[i] < min) min = x[i];
        return min;
    }

    static int maxof(int a, int b, int c) {
        return max(a, max(b, c));
    }

    static int maxof(int... x) {
        if (x.length == 1) return x[0];
        if (x.length == 2) return max(x[0], x[1]);
        if (x.length == 3) return max(x[0], max(x[1], x[2]));
        int max = x[0];
        for (int i = 1; i < x.length; ++i) if (x[i] > max) max = x[i];
        return max;
    }

    static long maxof(long a, long b, long c) {
        return max(a, max(b, c));
    }

    static long maxof(long... x) {
        if (x.length == 1) return x[0];
        if (x.length == 2) return max(x[0], x[1]);
        if (x.length == 3) return max(x[0], max(x[1], x[2]));
        long max = x[0];
        for (int i = 1; i < x.length; ++i) if (x[i] > max) max = x[i];
        return max;
    }

    static int powi(int a, int b) {
        if (a == 0) return 0;
        int ans = 1;
        while (b > 0) {
            if ((b & 1) > 0) ans *= a;
            a *= a;
            b >>= 1;
        }
        return ans;
    }

    static long powl(long a, int b) {
        if (a == 0) return 0;
        long ans = 1;
        while (b > 0) {
            if ((b & 1) > 0) ans *= a;
            a *= a;
            b >>= 1;
        }
        return ans;
    }

    static int fli(double d) {
        return (int) d;
    }

    static int cei(double d) {
        return (int) ceil(d);
    }

    static long fll(double d) {
        return (long) d;
    }

    static long cel(double d) {
        return (long) ceil(d);
    }

    static int gcf(int a, int b) {
        return b == 0 ? a : gcf(b, a % b);
    }

    static long gcf(long a, long b) {
        return b == 0 ? a : gcf(b, a % b);
    }

    static int[] exgcd(int a, int b) {
        if (b == 0) return new int[]{1, 0};
        int[] y = exgcd(b, a % b);
        return new int[]{y[1], y[0] - y[1] * (a / b)};
    }

    static long[] exgcd(long a, long b) {
        if (b == 0) return new long[]{1, 0};
        long[] y = exgcd(b, a % b);
        return new long[]{y[1], y[0] - y[1] * (a / b)};
    }

    static int randInt(int min, int max) {
        return __r.nextInt(max - min + 1) + min;
    }

    static long mix(long x) {
        x += 0x9e3779b97f4a7c15L;
        x = (x ^ (x >> 30)) * 0xbf58476d1ce4e5b9L;
        x = (x ^ (x >> 27)) * 0x94d049bb133111ebL;
        return x ^ (x >> 31);
    }

    // array util
    static void reverse(int[] a) {
        for (int i = 0, n = a.length, half = n / 2; i < half; ++i) {
            int swap = a[i];
            a[i] = a[n - i - 1];
            a[n - i - 1] = swap;
        }
    }

    static void reverse(long[] a) {
        for (int i = 0, n = a.length, half = n / 2; i < half; ++i) {
            long swap = a[i];
            a[i] = a[n - i - 1];
            a[n - i - 1] = swap;
        }
    }

    static void reverse(double[] a) {
        for (int i = 0, n = a.length, half = n / 2; i < half; ++i) {
            double swap = a[i];
            a[i] = a[n - i - 1];
            a[n - i - 1] = swap;
        }
    }

    static void reverse(char[] a) {
        for (int i = 0, n = a.length, half = n / 2; i < half; ++i) {
            char swap = a[i];
            a[i] = a[n - i - 1];
            a[n - i - 1] = swap;
        }
    }

    static void shuffle(int[] a) {
        int n = a.length - 1;
        for (int i = 0; i < n; ++i) {
            int ind = randInt(i, n);
            int swap = a[i];
            a[i] = a[ind];
            a[ind] = swap;
        }
    }

    static void shuffle(long[] a) {
        int n = a.length - 1;
        for (int i = 0; i < n; ++i) {
            int ind = randInt(i, n);
            long swap = a[i];
            a[i] = a[ind];
            a[ind] = swap;
        }
    }

    static void shuffle(double[] a) {
        int n = a.length - 1;
        for (int i = 0; i < n; ++i) {
            int ind = randInt(i, n);
            double swap = a[i];
            a[i] = a[ind];
            a[ind] = swap;
        }
    }

    static void rsort(int[] a) {
        shuffle(a);
        sort(a);
    }

    static void rsort(long[] a) {
        shuffle(a);
        sort(a);
    }

    static void rsort(double[] a) {
        shuffle(a);
        sort(a);
    }

    static int[] copy(int[] a) {
        int[] ans = new int[a.length];
        for (int i = 0; i < a.length; ++i) ans[i] = a[i];
        return ans;
    }

    static long[] copy(long[] a) {
        long[] ans = new long[a.length];
        for (int i = 0; i < a.length; ++i) ans[i] = a[i];
        return ans;
    }

    static double[] copy(double[] a) {
        double[] ans = new double[a.length];
        for (int i = 0; i < a.length; ++i) ans[i] = a[i];
        return ans;
    }

    static char[] copy(char[] a) {
        char[] ans = new char[a.length];
        for (int i = 0; i < a.length; ++i) ans[i] = a[i];
        return ans;
    }

    // input
    static void r() throws IOException {
        input = new StringTokenizer(rline());
    }

    static int ri() throws IOException {
        return Integer.parseInt(rline());
    }

    static long rl() throws IOException {
        return Long.parseLong(rline());
    }

    static double rd() throws IOException {
        return Double.parseDouble(rline());
    }

    static int[] ria(int n) throws IOException {
        int[] a = new int[n];
        r();
        for (int i = 0; i < n; ++i) a[i] = ni();
        return a;
    }

    static int[] riam1(int n) throws IOException {
        int[] a = new int[n];
        r();
        for (int i = 0; i < n; ++i) a[i] = ni() - 1;
        return a;
    }

    static long[] rla(int n) throws IOException {
        long[] a = new long[n];
        r();
        for (int i = 0; i < n; ++i) a[i] = nl();
        return a;
    }

    static double[] rda(int n) throws IOException {
        double[] a = new double[n];
        r();
        for (int i = 0; i < n; ++i) a[i] = nd();
        return a;
    }

    static char[] rcha() throws IOException {
        return rline().toCharArray();
    }

    static String rline() throws IOException {
        return __i.readLine();
    }

    static String n() {
        return input.nextToken();
    }

    static int rni() throws IOException {
        r();
        return ni();
    }

    static int ni() {
        return Integer.parseInt(n());
    }

    static long rnl() throws IOException {
        r();
        return nl();
    }

    static long nl() {
        return Long.parseLong(n());
    }

    static double rnd() throws IOException {
        r();
        return nd();
    }

    static double nd() {
        return Double.parseDouble(n());
    }

    // output
    static void pr(int i) {
        __o.print(i);
    }

    static void prln(int i) {
        __o.println(i);
    }

    static void pr(long l) {
        __o.print(l);
    }

    static void prln(long l) {
        __o.println(l);
    }

    static void pr(double d) {
        __o.print(d);
    }

    static void prln(double d) {
        __o.println(d);
    }

    static void pr(char c) {
        __o.print(c);
    }

    static void prln(char c) {
        __o.println(c);
    }

    static void pr(char[] s) {
        __o.print(new String(s));
    }

    static void prln(char[] s) {
        __o.println(new String(s));
    }

    static void pr(String s) {
        __o.print(s);
    }

    static void prln(String s) {
        __o.println(s);
    }

    static void pr(Object o) {
        __o.print(o);
    }

    static void prln(Object o) {
        __o.println(o);
    }

    static void prln() {
        __o.println();
    }

    static void pryes() {
        prln("yes");
    }

    static void pry() {
        prln("Yes");
    }

    static void prY() {
        prln("YES");
    }

    static void prno() {
        prln("no");
    }

    static void prn() {
        prln("No");
    }

    static void prN() {
        prln("NO");
    }

    static boolean pryesno(boolean b) {
        prln(b ? "yes" : "no");
        return b;
    }

    ;

    static boolean pryn(boolean b) {
        prln(b ? "Yes" : "No");
        return b;
    }

    static boolean prYN(boolean b) {
        prln(b ? "YES" : "NO");
        return b;
    }

    static void prln(int... a) {
        for (int i = 0, len = a.length - 1; i < len; pr(a[i]), pr(' '), ++i) ;
        if (a.length > 0) prln(a[a.length - 1]);
        else prln();
    }

    static void prln(long... a) {
        for (int i = 0, len = a.length - 1; i < len; pr(a[i]), pr(' '), ++i) ;
        if (a.length > 0) prln(a[a.length - 1]);
        else prln();
    }

    static void prln(double... a) {
        for (int i = 0, len = a.length - 1; i < len; pr(a[i]), pr(' '), ++i) ;
        if (a.length > 0) prln(a[a.length - 1]);
        else prln();
    }

    static <T> void prln(Collection<T> c) {
        int n = c.size() - 1;
        Iterator<T> iter = c.iterator();
        for (int i = 0; i < n; pr(iter.next()), pr(' '), ++i) ;
        if (n >= 0) prln(iter.next());
        else prln();
    }

    static void h() {
        prln("hlfd");
        flush();
    }

    static void flush() {
        __o.flush();
    }

    static void close() {
        __o.close();
    }
}