Problem: For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.

* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$.
* get($key$): Print the value with the specified $key$. Print 0 if there is no such element.
* delete($key$): Delete the element with the specified $key$.

Constraints

* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consits of lower case letters

Input

The input is given in the following format.


$q$
$query_1$
$query_2$
:
$query_q$


Each query $query_i$ is given by


0 $key$ $x$


or


1 $key$


or


2 $key$


where the first digits 0, 1 and 2 represent insert, get and delete operations respectively.

Output

For each get operation, print an integer in a line.

Example

Input

8
0 blue 4
0 red 1
0 white 5
1 red
1 blue
2 red
1 black
1 red


Output

1
4
0
0

Solution (in JAVA):

Solution:


import java.util.HashMap;
import java.util.Scanner;

public class Main {

	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		HashMap<String, Integer> M = new HashMap<>();

		int q = sc.nextInt();

		for (int i = 0; i < q; i++) {
			int p = sc.nextInt();
			if (p == 0) {
				String key = sc.next();
				int x = sc.nextInt();
				M.put(key, x);
			} else if (p == 1) {
				String key = sc.next();
				if (M.get(key) == null) {
					System.out.println("0");
				} else {
					System.out.println(M.get(key));
				}
			} else if (p == 2) {
				String key = sc.next();
				M.remove(key);
			}
		}

		sc.close();

	}

}