Problem: For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.

* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$.
* get($key$): Print the value with the specified $key$. Print 0 if there is no such element.
* delete($key$): Delete the element with the specified $key$.

Constraints

* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consits of lower case letters

Input

The input is given in the following format.


$q$
$query_1$
$query_2$
:
$query_q$


Each query $query_i$ is given by


0 $key$ $x$


or


1 $key$


or


2 $key$


where the first digits 0, 1 and 2 represent insert, get and delete operations respectively.

Output

For each get operation, print an integer in a line.

Example

Input

8
0 blue 4
0 red 1
0 white 5
1 red
1 blue
2 red
1 black
1 red


Output

1
4
0
0

Solution (in CPP):

Solution:
#include<bits/stdc++.h>
using namespace std;
using lint = long long;
template<typename T = lint>inline T in() { T x; cin >> x; return x; }
#define INF           1e9
#define INFL          static_cast<lint>(INF)
#define REP(i,n)      for(lint i=0,i##_len=(n);i<i##_len;++i)
#define REP1(i,n)     for(lint i=1,i##_len=(n);i<=i##_len;++i)
#define REPR(i,n)     for(lint i=n-1;i>=0;--i)
#define REPR1(i,n)    for(lint i=n;i>0;--i)
#define REPI(i,ini,n) for(lint i=(ini),i##_len=(n);i<i##_len;++i)
#define REPC(i,obj)   for(auto i:obj)
#define R_UP(a,b)     (((a)+(b)-1)/(b))
#define ALL(obj)      (obj).begin(),(obj).end()
int main()
{
	map<string, int>m;
	int q = in();
	REP(i, q)
	{
		int n = in();
		string key;
		int x;
		switch (n)
		{
		case 0:
			key = in<string>();
			x = in();
			m[key] = x;
			break;
		case 1:
			key = in<string>();
			try
			{
				cout << m.at(key) << endl;
			}
			catch (out_of_range)
			{
				cout << 0 << endl;
			}
			break;
		case 2:
			key = in<string>();
			m.erase(key);
			break;
		}
	}
}