Problem: Given are an integer N and arrays S, T, U, and V, each of length N. Construct an N×N matrix a that satisfy the following conditions:

* a_{i,j} is an integer.
* 0 \leq a_{i,j} \lt 2^{64}.
* If S_{i} = 0, the bitwise AND of the elements in the i-th row is U_{i}.
* If S_{i} = 1, the bitwise OR of the elements in the i-th row is U_{i}.
* If T_{i} = 0, the bitwise AND of the elements in the i-th column is V_{i}.
* If T_{i} = 1, the bitwise OR of the elements in the i-th column is V_{i}.



However, there may be cases where no matrix satisfies the conditions.

Constraints

* All values in input are integers.
* 1 \leq N \leq 500
* 0 \leq S_{i} \leq 1
* 0 \leq T_{i} \leq 1
* 0 \leq U_{i} \lt 2^{64}
* 0 \leq V_{i} \lt 2^{64}

Input

Input is given from Standard Input in the following format:


N
S_{1} S_{2} ...  S_{N}
T_{1} T_{2} ...  T_{N}
U_{1} U_{2} ...  U_{N}
V_{1} V_{2} ...  V_{N}


Output

If there exists a matrix that satisfies the conditions, print one such matrix in the following format:


a_{1,1} ...  a_{1,N}
:
a_{N,1} ...  a_{N,N}


Note that any matrix satisfying the conditions is accepted.

If no matrix satisfies the conditions, print -1.

Examples

Input

2
0 1
1 0
1 1
1 0


Output

1 1
1 0


Input

2
1 1
1 0
15 15
15 11


Output

15 11
15 11

Solution (in PYTHON3):

Solution:
n,*s=map(int,open(0).read().split());s,t,f,g=[s[i*n:i*n+n]for i in range(4)];r=range(n);a=[n*[0]for _ in r];e=enumerate
for b in range(64):
 y=1<<b;u=[k&y for k in f];v=[k&y for k in g];l=[0]*n;m=l[:]
 for i,k in e(u):
  for j,h in e(v):
   if(k&h)|((s[i]^1)*k)|((t[j]^1)*h):a[i][j]|=y;l[i]+=1;m[j]+=1
 for i in r:
  if(l[i]==0)*s[i]*u[i]:
   for j in r:
    if(t[j]^1)*(n-m[j]>1):a[i][j]|=y;m[j]+=1;break
  if(m[i]==0)*t[i]*v[i]:
   for j in r:
    if(s[j]^1)*(n-l[j]>1):a[j][i]|=y;l[j]+=1;break
h=a[0][:];w=[i[0]for i in a]
for i,k in e(a):
 for j,l in e(k):w[i]=(l|w[i]if s[i]else w[i]&l);h[j]=(l|h[j]if t[j]else h[j]&l)
if g+f!=h+w:exit(print(-1))
for i in a:print(*i)