Problem: For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.

* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$.
* get($key$): Print the value with the specified $key$. Print 0 if there is no such element.
* delete($key$): Delete the element with the specified $key$.

Constraints

* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consits of lower case letters

Input

The input is given in the following format.


$q$
$query_1$
$query_2$
:
$query_q$


Each query $query_i$ is given by


0 $key$ $x$


or


1 $key$


or


2 $key$


where the first digits 0, 1 and 2 represent insert, get and delete operations respectively.

Output

For each get operation, print an integer in a line.

Example

Input

8
0 blue 4
0 red 1
0 white 5
1 red
1 blue
2 red
1 black
1 red


Output

1
4
0
0

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int main(void) {
    map<string,int> map;
    int n,a,c;
    string b;
    cin >> n;
    for (int i=0;i<n;i++) {
        cin >> a;
        if ( a==0 ) {
            cin >> b >> c;
            if ( map.find(b)!=map.end() ) {
                map.erase(b);
                map.emplace(b,c);
            } else {
                map.emplace(b,c);
            }
        } else if ( a==1 ) {
            cin >> b;
            if ( map.find(b)!=map.end() ) {
                cout << map.at(b) << endl;
            } else {
                cout << "0" << endl;
            }
        } else if ( a==2 ) {
            cin >> b;
            map.erase(b);
        }
    }
}