Problem: Little Vova studies programming in an elite school. Vova and his classmates are supposed to write n progress tests, for each test they will get a mark from 1 to p. Vova is very smart and he can write every test for any mark, but he doesn't want to stand out from the crowd too much. If the sum of his marks for all tests exceeds value x, then his classmates notice how smart he is and start distracting him asking to let them copy his homework. And if the median of his marks will be lower than y points (the definition of a median is given in the notes), then his mom will decide that he gets too many bad marks and forbid him to play computer games.

Vova has already wrote k tests and got marks a1, ..., ak. He doesn't want to get into the first or the second situation described above and now he needs to determine which marks he needs to get for the remaining tests. Help him do that.

Input

The first line contains 5 space-separated integers: n, k, p, x and y (1 ≤ n ≤ 999, n is odd, 0 ≤ k < n, 1 ≤ p ≤ 1000, n ≤ x ≤ n·p, 1 ≤ y ≤ p). Here n is the number of tests that Vova is planned to write, k is the number of tests he has already written, p is the maximum possible mark for a test, x is the maximum total number of points so that the classmates don't yet disturb Vova, y is the minimum median point so that mom still lets him play computer games.

The second line contains k space-separated integers: a1, ..., ak (1 ≤ ai ≤ p) — the marks that Vova got for the tests he has already written.

Output

If Vova cannot achieve the desired result, print "-1".

Otherwise, print n - k space-separated integers — the marks that Vova should get for the remaining tests. If there are multiple possible solutions, print any of them.

Examples

Input

5 3 5 18 4
3 5 4


Output

4 1


Input

5 3 5 16 4
5 5 5


Output

-1

Note

The median of sequence a1, ..., an where n is odd (in this problem n is always odd) is the element staying on (n + 1) / 2 position in the sorted list of ai.

In the first sample the sum of marks equals 3 + 5 + 4 + 4 + 1 = 17, what doesn't exceed 18, that means that Vova won't be disturbed by his classmates. And the median point of the sequence {1, 3, 4, 4, 5} equals to 4, that isn't less than 4, so his mom lets him play computer games.

Please note that you do not have to maximize the sum of marks or the median mark. Any of the answers: "4 2", "2 4", "5 1", "1 5", "4 1", "1 4" for the first test is correct.

In the second sample Vova got three '5' marks, so even if he gets two '1' marks, the sum of marks will be 17, that is more than the required value of 16. So, the answer to this test is "-1".

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.*;

public class Main {
    private final static InputReader ir = new InputReader(System.in);
    private final static PrintWriter ow = new PrintWriter(System.out);

    public static void main(String[] args) throws IOException {
        int n = ir.ni(), k = ir.ni(), p = ir.ni(), x = ir.ni(), y = ir.ni();
        int[] a = new int[k];
        int cntl = 0;
        int cntm = 0;
        int sum = 0;
        for (int i = 0; i < k; ++i) {
            a[i] = ir.ni();
            if (a[i] >= y) ++cntm;
            else ++cntl;
            sum += a[i];
        }
        int l1 = (n - 1) / 2 - cntl;
        int l2 = (n - 1) / 2 - cntm + 1;
        if (l2 < 0) {
            l1 += l2;
            l2 = 0;
        }
        if (l1 < 0) {
            l2 += l1;
            l1 = 0;
        }
        if (cntl > (n - 1) / 2) {
            print(-1);
        } else if (sum + l1 + l2 * y > x){
            print(-1);
        } else {
            for (int i = 0; i < l1; ++i) {
                print(1 + " ");
            }
            for (int i = 0; i < l2; ++i) {
                print(y + " ");
            }
        }
        ow.close();
    }

    static void print(Object obj) {
        ow.print(obj);
    }

    static void println() {
        ow.print("\n");
    }

    static void println(Object obj) {
        print(obj);
        println();
    }
}

class InputReader implements AutoCloseable {
    private final InputStream in;
    private int capacity;
    private byte[] buffer;
    private int len = 0;
    private int cur = 0;

    InputReader(InputStream stream) {
        this(stream, 100_000);
    }

    InputReader(InputStream stream, int capacity) {
        this.in = stream;
        this.capacity = capacity;
        buffer = new byte[capacity];
    }

    private boolean update() {
        if (cur >= len) {
            try {
                cur = 0;
                len = in.read(buffer, 0, capacity);
                if (len <= 0)
                    return false;
            } catch (IOException e) {
                throw new InputMismatchException();
            }
        }
        return true;
    }

    private int read() {
        if (update())
            return buffer[cur++];
        else return -1;
    }

    public boolean isEmpty() {
        return !update();
    }

    private boolean isSpace(int c) {
        return c == '\n' || c == '\t' || c == '\r' || c == ' ';
    }

    private boolean isEscape(int c) {
        return c == '\n' || c == '\t' || c == '\r' || c == -1;
    }

    private int readSkipSpace() {
        int c;
        do {
            c = read();
        } while (isSpace(c));
        return c;
    }

    int ni() {
        int c = readSkipSpace();
        if (c < 0)
            throw new InputMismatchException();
        int sgn = 1;
        if (c == '-') {
            sgn = -1;
            c = read();
        }
        int res = 0;
        do {
            if (c == -1) break;
            if (c < '0' || c > '9')
                throw new InputMismatchException();
            res = res * 10 + c - '0';
            if (res < 0)
                throw new InputMismatchException();
            c = read();
        } while (!isSpace(c));
        res *= sgn;
        return res;
    }

    int nc() {
        int c = readSkipSpace();
        if (c < 0)
            throw new InputMismatchException();
        return c;
    }

    String ns(int initialCapacity) {
        StringBuilder res = new StringBuilder(initialCapacity);
        int c = readSkipSpace();
        do {
            res.append((char) (c));
            c = read();
        } while (!isEscape(c));
        return res.toString();
    }

    @Override
    public void close() throws IOException {
        in.close();
    }
}