Problem: For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.

* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$.
* get($key$): Print the value with the specified $key$. Print 0 if there is no such element.
* delete($key$): Delete the element with the specified $key$.

Constraints

* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consits of lower case letters

Input

The input is given in the following format.


$q$
$query_1$
$query_2$
:
$query_q$


Each query $query_i$ is given by


0 $key$ $x$


or


1 $key$


or


2 $key$


where the first digits 0, 1 and 2 represent insert, get and delete operations respectively.

Output

For each get operation, print an integer in a line.

Example

Input

8
0 blue 4
0 red 1
0 white 5
1 red
1 blue
2 red
1 black
1 red


Output

1
4
0
0

Solution (in CPP):

Solution:
#include <bits/stdc++.h>

using namespace std;


int main(){
    int num_query;
    int command,val;
    char key[20];

    scanf("%d",&num_query);
    map<string,int> map_array;

    for(int i = 0;i < num_query;i++){
        scanf("%d %s",&command,key);
        if(command == 0){
            scanf("%d",&val);
            map_array[key] = val;
        }else if(command == 1){
            if(map_array.find(key) != map_array.end()) printf("%d\n",map_array[key]);
            else printf("0\n");
        }else if(command == 2){
            if(map_array.find(key) != map_array.end()) map_array.erase(key);
        }
    }

    return 0;   
}