Problem: For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.

* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$.
* get($key$): Print the value with the specified $key$. Print 0 if there is no such element.
* delete($key$): Delete the element with the specified $key$.

Constraints

* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consits of lower case letters

Input

The input is given in the following format.


$q$
$query_1$
$query_2$
:
$query_q$


Each query $query_i$ is given by


0 $key$ $x$


or


1 $key$


or


2 $key$


where the first digits 0, 1 and 2 represent insert, get and delete operations respectively.

Output

For each get operation, print an integer in a line.

Example

Input

8
0 blue 4
0 red 1
0 white 5
1 red
1 blue
2 red
1 black
1 red


Output

1
4
0
0

Solution (in PYTHON3):

Solution:
import bisect

D=[]
N=[]
count=0

def insert(D,N,count,key,x):
    y=bisect.bisect_left(D,key)
    if y<count and D[y]==key:
        N[y]=x
    else:
        D.insert(y,key)
        N.insert(y,x)
        count+=1
    return D,N,count

def get(D,N,count,key):
    y=bisect.bisect_left(D,key)
    if y<count and D[y]==key:
        print(N[y])
    else:
        print(0)

def erase(D,N,count,key):
    y=bisect.bisect_left(D,key)
    if y<count and D[y]==key:
        D.pop(y)
        N.pop(y)
        count-=1
    return D,N,count

q=int(input())
for i in range(q):
    query=list(map(str,input().split()))
    query[0]=int(query[0])
    if query[0]==0:
        D,N,count=insert(D,N,count,query[1],int(query[2]))
    elif query[0]==1:
        get(D,N,count,query[1])
    else:
        D,N,count=erase(D,N,count,query[1])