Problem: For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.

* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$.
* get($key$): Print the value with the specified $key$. Print 0 if there is no such element.
* delete($key$): Delete the element with the specified $key$.

Constraints

* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consits of lower case letters

Input

The input is given in the following format.


$q$
$query_1$
$query_2$
:
$query_q$


Each query $query_i$ is given by


0 $key$ $x$


or


1 $key$


or


2 $key$


where the first digits 0, 1 and 2 represent insert, get and delete operations respectively.

Output

For each get operation, print an integer in a line.

Example

Input

8
0 blue 4
0 red 1
0 white 5
1 red
1 blue
2 red
1 black
1 red


Output

1
4
0
0

Solution (in CPP):

Solution:
#include <iostream>
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <algorithm>
#include <string>
#include <sstream>
#include <complex>
#include <vector>
#include <list>
#include <queue>
#include <deque>
#include <stack>
#include <map>
#include <set>
#include <iomanip>
#define rep(i, n) for (int i = 0; i < (int)(n); i++
using namespace std;

int main() {
	int q,a,c;
	string b;
	map<string,int> s;
	cin >> q;
	for (int i = 0; i < q; i++) {
		cin>>a>>b;
		if (a == 0) {
			cin >> c;
			if (s.count(b)) {
				s[b] = c;
			}
			else {
				s.insert(make_pair(b, c));
			}
		}
		else if (a == 1) {
			if (s.count(b)) {
				cout << s[b] << endl;
			}
			else {
				cout << 0 << endl;
			}
		}
		else {
			s.erase(b);
		}
	}
}