Problem: Kyoya Ootori is selling photobooks of the Ouran High School Host Club. He has 26 photos, labeled "a" to "z", and he has compiled them into a photo booklet with some photos in some order (possibly with some photos being duplicated). A photo booklet can be described as a string of lowercase letters, consisting of the photos in the booklet in order. He now wants to sell some "special edition" photobooks, each with one extra photo inserted anywhere in the book. He wants to make as many distinct photobooks as possible, so he can make more money. He asks Haruhi, how many distinct photobooks can he make by inserting one extra photo into the photobook he already has?

Please help Haruhi solve this problem.

Input

The first line of input will be a single string s (1 ≤ |s| ≤ 20). String s consists only of lowercase English letters. 

Output

Output a single integer equal to the number of distinct photobooks Kyoya Ootori can make.

Examples

Input

a


Output

51


Input

hi


Output

76

Note

In the first case, we can make 'ab','ac',...,'az','ba','ca',...,'za', and 'aa', producing a total of 51 distinct photo booklets. 

Solution (in PYTHON):

Solution:
from __future__ import division
from collections import Counter as ctr
from math import ceil, log, factorial
# reads a line of input and converts into a list of ints
# 1 1 3 => [1, 1, 3]
def rl():
    return [int(i) for i in raw_input().split()]

# reads n lines of input (if n defined) and returns a list of strings
# where each element is a line in the input
# abc
# abcdef
# => ['abc', 'abcdef']
# if n not defined, read first line to get number of lines
# 2
# abc
# abcdef
# => ['abc', 'abcdef']
def rm(n=None):
    if n is None:
        n = input()
    return [raw_input() for i in range(n)]

# same as rm, except converts each line to a list of ints like rl
def rlm(n=None):
    if n is None:
        n = input()
    return [rl() for i in range(n)]

def yn(b):
    if b:
        print "YES"
    else:
        print "NO"

s = raw_input()
p = set()
for i in range(0, len(s)+1):
	for l in 'abcdefghijklmnopqrstuvwxyz':
		p.add(s[0:i]+l+s[i:])
print len(p)