Problem: For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.

* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$.
* get($key$): Print the value with the specified $key$. Print 0 if there is no such element.
* delete($key$): Delete the element with the specified $key$.

Constraints

* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consits of lower case letters

Input

The input is given in the following format.


$q$
$query_1$
$query_2$
:
$query_q$


Each query $query_i$ is given by


0 $key$ $x$


or


1 $key$


or


2 $key$


where the first digits 0, 1 and 2 represent insert, get and delete operations respectively.

Output

For each get operation, print an integer in a line.

Example

Input

8
0 blue 4
0 red 1
0 white 5
1 red
1 blue
2 red
1 black
1 red


Output

1
4
0
0

Solution (in CPP):

Solution:
#include <iostream>
#include <stdio.h>
#include <map>
#include <string>
using namespace std;

int main()
{
    map<string, int> M;
    int query;
    scanf("%d", &query);

    int commend, value;
    string key;
    for (int i = 0; i < query; i++)
    {
        scanf("%d", &commend);
        if (0 == commend)
        {
            cin >> key >> value;
            M[key] = value;
        }
        else if (1 == commend)
        {
            cin >> key;
            if (M.count(key) != 0)
            {
                printf("%d\n", M[key]);
            }
            else
            {
                printf("%d\n", 0);
            }
        }
        else
        {
            cin >> key;
            //M<string, int>::iterator itr = M.find(key);
            M.erase(key);
        }
    }
    return 0;
}