Problem: Dima's spent much time thinking what present to give to Inna and gave her an empty sequence w. Now they want to fill sequence w with numbers zero and one. For that, they decided to play an amusing game. 

Before the game begins, Dima chooses m integers a1, a2, ..., am (1 ≤ a1 < a2 < ... < am). Then Inna and Dima start playing, that is, adding numbers to sequence w. Each new number they choose is added to the end of the sequence. At some moments of time Dima feels that the game is going to end too soon (and he wants to play with Inna as long as possible), so he hits a table hard with his fist. At that the a1-th, a2-th, a3-th, ..., ak-th numbers from the beginning simultaneously fall out of the sequence (the sequence gets k numbers less). Here k is such maximum number that value ak doesn't exceed the current length of the sequence. If number a1 is larger than the current length of w, then nothing falls out of the sequence.

You are given the chronological sequence of events in the game. Each event is either adding a number to the end of sequence w or Dima's hit on the table. Calculate the sequence w after all these events happen.

Input

The first line of the input contains two integers n and m (1 ≤ n, m ≤ 106) showing how many events took place and how many numbers Dima chose.

The next line contains m distinct integers ai (1 ≤ ai ≤ 106) sorted in the increasing order. 

Next n lines describe the events in the chronological order. Each line contains a single integer: -1, 0 or 1. Number -1 means that Dima hits the table. Number 0 means that Inna and Dima add number 0 to the end of the sequence. Number 1 means that Inna and Dima add number 1 to the end of the sequence.

Output

In a single line print a sequence of numbers 0 and 1 — the elements of the sequence after all events happen. Print the elements of the sequence in the order from the beginning to the end of the sequence.

If after all events the sequence ends up empty, print "Poor stack!".

Examples

Input

10 3
1 3 6
-1
1
1
0
0
-1
0
1
-1
1


Output

011


Input

2 1
1
1
-1


Output

Poor stack!

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.util.StringTokenizer;

import static java.lang.Integer.MAX_VALUE;
import static java.lang.Math.random;

/**
 * @author Don Li
 */
public class InnaSequence {
    
    int N = (int) 1e6;
    
    void solve() {
        int n = in.nextInt(), m = in.nextInt();
        int[] a = new int[m];
        for (int i = 0; i < m; i++) a[i] = in.nextInt();
        
        Node root = null;
        Treap treap = new Treap();
        boolean[] bad = new boolean[N];
        int[] seq = new int[N];
        int sz = 0, len = 0;
        for (int i = 0; i < n; i++) {
            int x = in.nextInt();
            if (x >= 0) {
                seq[sz] = x;
                root = treap.insert(root, new Node(sz));
                sz++;
                len++;
            } else {
                int p = upperBound(a, len);
                for (int j = p - 1; j >= 0; j--) {
                    int v = treap.findKth(root, a[j]);
                    bad[v] = true;
                    root = treap.erase(root, v);
                    len--;
                }
            }
        }
        
        if (len == 0) {
            out.println("Poor stack!");
            return;
        }
        for (int i = 0; i < sz; i++) {
            if (!bad[i]) out.print(seq[i]);
        }
    }
    
    int upperBound(int[] a, int k) {
        int lb = -1, ub = a.length;
        while (ub - lb > 1) {
            int m = (lb + ub) / 2;
            if (a[m] > k) ub = m;
            else lb = m;
        }
        return ub;
    }
    
    static class Treap {
        // insert a new node to the Treap
        public Node insert(Node root, Node node) {
            if (root == null) return node;
            if (node.prior > root.prior) {
                Node[] splitted = split(root, node.key);
                node.setLeft(splitted[0]);
                node.setRight(splitted[1]);
                return node;
            }
            if (node.key < root.key) {
                root.setLeft(insert(root.left, node));
            } else {
                root.setRight(insert(root.right, node));
            }
            return root;
        }
        
        // split the Treap root into 2 Treaps L and R, where L[i].key<x and R[i].key>x
        Node[] split(Node root, int x) {
            if (root == null) return new Node[2];
            if (root.key < x) {
                // split the right subtree
                Node[] splitted = split(root.right, x);
                root.setRight(splitted[0]);
                return new Node[]{root, splitted[1]};
            } else {
                // split the left subtree
                Node[] splitted = split(root.left, x);
                root.setLeft(splitted[1]);
                return new Node[]{splitted[0], root};
            }
        }
        
        // erase the key x from the Treap if exist
        public Node erase(Node root, int x) {
            if (root == null) return null;
            if (root.key == x) {
                return merge(root.left, root.right);
            }
            if (root.key > x) {
                root.setLeft(erase(root.left, x));
            } else {
                root.setRight(erase(root.right, x));
            }
            return root;
        }
        
        // merge Treap a and b when max(a)<min(b)
        Node merge(Node a, Node b) {
            if (a == null) return b;
            if (b == null) return a;
            if (a.prior < b.prior) {
                b.setLeft(merge(a, b.left));
                return b;
            } else {
                a.setRight(merge(a.right, b));
                return a;
            }
        }
        
        // find the k-th largest element in the Treap (1-based)
        public int findKth(Node root, int k) {
            int leftSize = getSize(root.left);
            if (leftSize == k - 1) return root.key;
            if (leftSize > k - 1) return findKth(root.left, k);
            return findKth(root.right, k - leftSize - 1);
        }
        
        int getSize(Node node) {
            return node == null ? 0 : node.size;
        }
    }
    
    static class Node {
        int key, prior, size; // the BST key, priority and subtree size
        Node left, right;     // left and right subtree
        
        Node(int x) {
            key = x;
            prior = rand();
            size = 1;
        }
        
        void setLeft(Node node) {
            left = node;
            updateSize();
        }
        
        void setRight(Node node) {
            right = node;
            updateSize();
        }
        
        void updateSize() {
            size = 1;
            if (left != null) size += left.size;
            if (right != null) size += right.size;
        }
        
        int rand() {
            return (int) (random() * MAX_VALUE);
        }
    }
    
    public static void main(String[] args) {
        in = new FastScanner(new BufferedReader(new InputStreamReader(System.in)));
        out = new PrintWriter(System.out);
        new InnaSequence().solve();
        out.close();
    }
    
    static FastScanner in;
    static PrintWriter out;
    
    static class FastScanner {
        BufferedReader in;
        StringTokenizer st;
        
        public FastScanner(BufferedReader in) {
            this.in = in;
        }
        
        public String nextToken() {
            while (st == null || !st.hasMoreTokens()) {
                try {
                    st = new StringTokenizer(in.readLine());
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
            return st.nextToken();
        }
        
        public int nextInt() {
            return Integer.parseInt(nextToken());
        }
        
        public long nextLong() {
            return Long.parseLong(nextToken());
        }
        
        public double nextDouble() {
            return Double.parseDouble(nextToken());
        }
    }
}