Problem: For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.

* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$.
* get($key$): Print the value with the specified $key$. Print 0 if there is no such element.
* delete($key$): Delete the element with the specified $key$.

Constraints

* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consits of lower case letters

Input

The input is given in the following format.


$q$
$query_1$
$query_2$
:
$query_q$


Each query $query_i$ is given by


0 $key$ $x$


or


1 $key$


or


2 $key$


where the first digits 0, 1 and 2 represent insert, get and delete operations respectively.

Output

For each get operation, print an integer in a line.

Example

Input

8
0 blue 4
0 red 1
0 white 5
1 red
1 blue
2 red
1 black
1 red


Output

1
4
0
0

Solution (in CPP):

Solution:
#include "bits/stdc++.h"
using namespace std;
#define long int64_t

struct Solver {
	Solver() {
		ios::sync_with_stdio( false );
		cout << fixed << setprecision( 10 );
	}

	void solve() {
		map<string, int> m;
		int q;
		cin >> q;
		while( q-- ) {
			int cmd, x;
			string key;
			cin >> cmd;

			if( cmd == 0 ) {
				cin >> key >> x;
				m[key] = x;
			}
			else if( cmd == 1 ) {
				cin >> key;
				cout << m[key] << '\n';
			}
			else {
				cin >> key;
				m.erase( key );
			}
		}
	}
};

int main() {
	Solver().solve();
	return 0;
}