Problem: For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.

* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$.
* get($key$): Print the value with the specified $key$. Print 0 if there is no such element.
* delete($key$): Delete the element with the specified $key$.

Constraints

* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consits of lower case letters

Input

The input is given in the following format.


$q$
$query_1$
$query_2$
:
$query_q$


Each query $query_i$ is given by


0 $key$ $x$


or


1 $key$


or


2 $key$


where the first digits 0, 1 and 2 represent insert, get and delete operations respectively.

Output

For each get operation, print an integer in a line.

Example

Input

8
0 blue 4
0 red 1
0 white 5
1 red
1 blue
2 red
1 black
1 red


Output

1
4
0
0

Solution (in JAVA):

Solution:
//import java.lang.Math;
import java.util.*;
//import java.util.ListIterator;
//import java.util.Iterator;
//import java.util.LinkedList;
 
public class Main{
	
	
	
	@SuppressWarnings({ "rawtypes", "unchecked", "resource" })
	public static void main(String[] arg) {
		
		
		Map map=new HashMap();
		 Scanner sc = new Scanner(System.in);
	        int cnt = sc.nextInt();
	        for (int i = 0; i < cnt; i++) {
	        
	        int cmt=sc.nextInt();
	        
	        switch(cmt){
	        
	        
	        case 0:
	        	  String str=sc.next();
	              int num=sc.nextInt();
	        
	               map.put(str,num);
	            break;
	        case 1:
	        	str=sc.next();
	        	if(map.containsKey(str))System.out.println(map.get(str));
	        	else System.out.println(0);
	        	break;
	        case 2:
	        	str=sc.next();
	        	map.remove(str);
	      
	        }
	        
	        
	        }
		
		
		
		
}
	
	
}