Problem: For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.

* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$.
* get($key$): Print the value with the specified $key$. Print 0 if there is no such element.
* delete($key$): Delete the element with the specified $key$.

Constraints

* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consits of lower case letters

Input

The input is given in the following format.


$q$
$query_1$
$query_2$
:
$query_q$


Each query $query_i$ is given by


0 $key$ $x$


or


1 $key$


or


2 $key$


where the first digits 0, 1 and 2 represent insert, get and delete operations respectively.

Output

For each get operation, print an integer in a line.

Example

Input

8
0 blue 4
0 red 1
0 white 5
1 red
1 blue
2 red
1 black
1 red


Output

1
4
0
0

Solution (in PYTHON3):

Solution:
import bisect

keys=[]

q=int(input())
d={}

def find(x):
    index=bisect.bisect_left(keys,x)
    if index==len(keys):
        return -1
    if keys[index]==x:
        return index
    else:
        return -1


for _ in range(q):
    query=input().split(" ")
    if query[0]=="0":
        if find(query[1])!=-1:
            pass
        else:
            bisect.insort_left(keys, query[1])
        d[query[1]]=query[2]
    elif query[0]=="1":
        if find(query[1])!=-1:
            print(d[query[1]])
        else:
            print(0)
    elif query[0]=="2":
        while find(query[1])>=0:
            keys.pop(find(query[1]))