Problem: For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.

* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$.
* get($key$): Print the value with the specified $key$. Print 0 if there is no such element.
* delete($key$): Delete the element with the specified $key$.

Constraints

* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consits of lower case letters

Input

The input is given in the following format.


$q$
$query_1$
$query_2$
:
$query_q$


Each query $query_i$ is given by


0 $key$ $x$


or


1 $key$


or


2 $key$


where the first digits 0, 1 and 2 represent insert, get and delete operations respectively.

Output

For each get operation, print an integer in a line.

Example

Input

8
0 blue 4
0 red 1
0 white 5
1 red
1 blue
2 red
1 black
1 red


Output

1
4
0
0

Solution (in CPP):

Solution:
#include <iostream>
#include <iterator>
#include <map>
#include <bits/stdc++.h>

using namespace std;

int main()
{
    map<string, int> mp;

    vector<int> v;
    int num, num1, num2, vec;
    string str;
    scanf("%d", &num);

    for(int i = 0; i < num; i++){
        scanf("%d", &num1);
        if(num1 == 0){
            cin >> str >> num2;
            mp[str] = num2;
        }
        else if(num1 == 1){
            cin >> str;
            if(mp.find(str) == mp.end()){
                v.push_back(0);
            }
            else{
                vec = mp[str];
                v.push_back(vec);
            }

        }
        else if(num1 == 2){
            cin >> str;
            mp.erase(str);
        }
    }

    for (auto val : v){
            if(!v.empty()){
                cout << val<< "\n";
            }

    }

    return 0;
}