Problem: You are given k sequences of integers. The length of the i-th sequence equals to n_i.

You have to choose exactly two sequences i and j (i ≠ j) such that you can remove exactly one element in each of them in such a way that the sum of the changed sequence i (its length will be equal to n_i - 1) equals to the sum of the changed sequence j (its length will be equal to n_j - 1).

Note that it's required to remove exactly one element in each of the two chosen sequences.

Assume that the sum of the empty (of the length equals 0) sequence is 0.

Input

The first line contains an integer k (2 ≤ k ≤ 2 ⋅ 10^5) — the number of sequences.

Then k pairs of lines follow, each pair containing a sequence.

The first line in the i-th pair contains one integer n_i (1 ≤ n_i < 2 ⋅ 10^5) — the length of the i-th sequence. The second line of the i-th pair contains a sequence of n_i integers a_{i, 1}, a_{i, 2}, ..., a_{i, n_i}.

The elements of sequences are integer numbers from -10^4 to 10^4.

The sum of lengths of all given sequences don't exceed 2 ⋅ 10^5, i.e. n_1 + n_2 + ... + n_k ≤ 2 ⋅ 10^5.

Output

If it is impossible to choose two sequences such that they satisfy given conditions, print "NO" (without quotes). Otherwise in the first line print "YES" (without quotes), in the second line — two integers i, x (1 ≤ i ≤ k, 1 ≤ x ≤ n_i), in the third line — two integers j, y (1 ≤ j ≤ k, 1 ≤ y ≤ n_j). It means that the sum of the elements of the i-th sequence without the element with index x equals to the sum of the elements of the j-th sequence without the element with index y.

Two chosen sequences must be distinct, i.e. i ≠ j. You can print them in any order.

If there are multiple possible answers, print any of them.

Examples

Input

2
5
2 3 1 3 2
6
1 1 2 2 2 1


Output

YES
2 6
1 2


Input

3
1
5
5
1 1 1 1 1
2
2 3


Output

NO


Input

4
6
2 2 2 2 2 2
5
2 2 2 2 2
3
2 2 2
5
2 2 2 2 2


Output

YES
2 2
4 1

Note

In the first example there are two sequences [2, 3, 1, 3, 2] and [1, 1, 2, 2, 2, 1]. You can remove the second element from the first sequence to get [2, 1, 3, 2] and you can remove the sixth element from the second sequence to get [1, 1, 2, 2, 2]. The sums of the both resulting sequences equal to 8, i.e. the sums are equal.

Solution (in JAVA):

Solution:
/*
 * Remember a 6.72 student can know more than a 10.0 student.
 * Grades don't determine intelligence, they test obedience. 
 * I Never Give Up.
 * I will become Candidate Master.
 * I will defeat Saurabh Anand.
 * Skills are Cheap,Passion is Priceless.
 * Obsession is necessary.
 * Author : Sameer Raj
 */
import java.util.*;
import java.util.Map.Entry;
import java.io.*;
import java.lang.Math.*;

import static java.lang.System.out;
import static java.util.Arrays.fill;
import static java.lang.Math.log;
import static java.lang.Math.abs;
 
public class ContestMain implements Runnable{
	private static Reader in=new Reader();
	private static StringBuilder ans=new StringBuilder();
	private static long MOD=(long)1e9+7;
	private static final int N=(int) (1e5+7); // 1e5+7
    private static ArrayList<Integer> v[]=new ArrayList[N];
	private static boolean mark[]=new boolean[N];
//    private static BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
	/*Not try to hack the sort function*/
	public static void sort(long arr[]){
		for(int i=arr.length-1;i>=2;i--){
			int x=new Random().nextInt(i-1);
			long temp=arr[x];
			arr[x]=arr[i];
			arr[i]=temp;
		}
		Arrays.sort(arr);
	}
	public static void sort(int arr[]){
		for(int i=arr.length-1;i>=2;i--){
			int x=new Random().nextInt(i-1);
			int temp=arr[x];
			arr[x]=arr[i];
			arr[i]=temp;
		}
		Arrays.sort(arr);
	}
    private static long gcd(long a, long b){
        if(b==0)return a;
        return gcd(b,a%b);
    }
    /*Code lies here*/
    @Override
	public void run(){
    	int k=in.nextInt();
    	ArrayList<Integer> ar[]=new ArrayList[k];
    	for(int i=0;i<k;i++)
    		ar[i]=new ArrayList();
    	HashMap<Long,Integer> map=new HashMap();
    	int size;
    	long sum,fsum=0;
    	int ind1=-1,ind2=-1;
    	for(int i=0;i<k;i++){
    		size=in.nextInt();
    		sum=0;
    		for(int j=0;j<size;j++){
    			ar[i].add(in.nextInt());
    			sum+=ar[i].get(ar[i].size()-1);
    		}
    		if(ind1==-1){
    			for(int j=0;j<ar[i].size();j++){
        			if(map.containsKey(sum-ar[i].get(j))&&map.get(sum-ar[i].get(j))!=i){
        				ind1=i;
        				ind2=map.get(sum-ar[i].get(j));
        				fsum=sum-ar[i].get(j);
        			}
        			else map.put(sum-ar[i].get(j),i);
        		}
    		}
    	}
    	if(ind1==-1)pn("NO");
    	else{
    		appn("YES");
    		sum=0;
    		for(int i=0;i<ar[ind1].size();i++)
    			sum+=ar[ind1].get(i);
    		for(int i=0;i<ar[ind1].size();i++){
    			if(sum-ar[ind1].get(i)==fsum){
    				appn((ind1+1)+" "+(i+1));
    				break;
    			}
    		}
    		sum=0;
    		for(int i=0;i<ar[ind2].size();i++)
    			sum+=ar[ind2].get(i);
    		for(int i=0;i<ar[ind2].size();i++){
    			if(sum-ar[ind2].get(i)==fsum){
    				appn((ind2+1)+" "+(i+1));
    				break;
    			}
    		}
    		pn(ans);
    	}
	}
	public static void main(String[] args) throws IOException{
		new Thread(null,new ContestMain(),"Accepted",1<<26).start();
		/* 0_0 I am watching you 0_0 */
	}
	static class Pair<T> implements Comparable<Pair>{
		int l;
		int r;
		Pair(){
			l=0;
			r=0;
		}
		Pair(int k,int v){
			l=k;
			r=v;
		}
		@Override
		public int compareTo(Pair o){
			if(l!=o.l)return (int)(l-o.l);
			return (int)(r-o.r);
		}
		// Fenwick tree question comparator
//        @Override
//        public int compareTo(Pair o) {
//            if(o.r!=r)return (int) (r-o.r);
//            else return (int)(l-o.l);
//        }
	}
	/* BINARY SEARCH FUNCTIONS */
	public static int ceilSearch(int l,int r,int val,int ar[]){
		int mid;
		while(l+1!=r&&l<r){
			mid=(l+r)/2;
			if(ar[mid]<val)l=mid;
			else r=mid;
		}
		if(ar[l]>=val)return l;
		else if(ar[r]>=val)return r;
		else return -1;
	}
	public static int ceilSearch(int l,int r,long val,long ar[]){
		int mid;
		while(l+1!=r&&l<r){
			mid=(l+r)/2;
			if(ar[mid]<val)l=mid;
			else r=mid;
		}
		if(ar[l]>=val)return l;
		else if(ar[r]>=val)return r;
		else return -1;
	}
	public static int floorSearch(int l,int r,int val,int ar[]){
		int mid;
		while(l+1!=r&&l<r){
			mid=(l+r)/2;
			if(ar[mid]>val)r=mid;
			else l=mid;
		}
		if(ar[r]<=val)return r;
		else if(ar[l]<=val)return l;
		else return -1;
	}
	public static int floorSearch(int l,int r,long val,long ar[]){
		int mid;
		while(l+1!=r&&l<r){
			mid=(l+r)/2;
			if(ar[mid]>val)r=mid;
			else l=mid;
		}
		if(ar[r]<=val)return r;
		else if(ar[l]<=val)return l;
		else return -1;
	}
	/* MODULAR OPERATIONS */
	private static long mod(long a,long b){ //a%b
	    	return (b+a%b)%b;
	}
	private static long modInv(long a){
	    	return powmod(a,MOD-2);
	}
	private static long powmod(long x,long n){
		if(n==0||x==0)return 1;
		else if(n%2==0)return(powmod((x*x)%MOD,n/2));
		else return (x*(powmod((x*x)%MOD,(n-1)/2)))%MOD;
	}
	public static long mult(long a,long b){
		return mod(mod(a,MOD)*mod(b,MOD),MOD);
	}
	public static long add(long a,long b){
		return mod(mod(a,MOD)+mod(b,MOD),MOD);
	}
	public static long sub(long a,long b){
		return mod(mod(a,MOD)-mod(b,MOD),MOD);
	}
	/* MAX-MIN FUNCTIONS */
	public static long min(long a,long b){
		return Math.min(a, b);
	}
	public static int min(int a,int b){
		return Math.min(a, b);
	}
	public static long max(long a,long b){
		return Math.max(a, b);
	}
	public static int max(int a,int b){
		return Math.max(a, b);
	}
	public static long min(long ar[]){
		return Arrays.stream(ar).min().getAsLong();
	}
	public static int min(int ar[]){
		return Arrays.stream(ar).min().getAsInt();
	}
	public static long max(long ar[]){
		return Arrays.stream(ar).max().getAsLong();
	}
	public static int max(int ar[]){
		return Arrays.stream(ar).max().getAsInt();
	}
	//Reader Class
	static class Reader{
		BufferedReader br;
		StringTokenizer st;
		public Reader(){br=new BufferedReader(new InputStreamReader(System.in));}
		String next(){
			while(st==null||!st.hasMoreElements()){
				try{st=new StringTokenizer(br.readLine());
				}catch(IOException e){e.printStackTrace();}
			}
			return st.nextToken();
		}
		int nextInt(){return Integer.parseInt(next());}
		long nextLong(){return Long.parseLong(next());}
		double nextDouble(){return Double.parseDouble(next());}
		String nextLine(){
			String str="";
			try{
				str=br.readLine();
			}catch(IOException e){
				e.printStackTrace();
			}
			return str;
		}
	}
	//Looping methods
	static void rep(int ar[],int start,int end){
		for(int i=start;i<end;i++)
			ar[i]=in.nextInt();
	}
	static void rep(long ar[],int start,int end){
		for(int i=start;i<end;i++)
			ar[i]=in.nextLong();
	}
	static void rep(String ar[],int start,int end){
		for(int i=start;i<end;i++)
			ar[i]=in.next();
	}
	//Printer Methods
	static void pn(Object o){out.print(o);}
	static void pln(Object o){out.println(o);}
	static void pln(){out.println();}
	static void pf(String format,Object o){out.printf(format,o);}
	//Appenders
	static void app(Object o){ans.append(o);}
	static void appn(Object o){ans.append(o+"\n");}
}