Problem: A string is called diverse if it contains consecutive (adjacent) letters of the Latin alphabet and each letter occurs exactly once. For example, the following strings are diverse: "fced", "xyz", "r" and "dabcef". The following string are not diverse: "az", "aa", "bad" and "babc". Note that the letters 'a' and 'z' are not adjacent.

Formally, consider positions of all letters in the string in the alphabet. These positions should form contiguous segment, i.e. they should come one by one without any gaps. And all letters in the string should be distinct (duplicates are not allowed).

You are given a sequence of strings. For each string, if it is diverse, print "Yes". Otherwise, print "No".

Input

The first line contains integer n (1 ≤ n ≤ 100), denoting the number of strings to process. The following n lines contains strings, one string per line. Each string contains only lowercase Latin letters, its length is between 1 and 100, inclusive.

Output

Print n lines, one line per a string in the input. The line should contain "Yes" if the corresponding string is diverse and "No" if the corresponding string is not diverse. You can print each letter in any case (upper or lower). For example, "YeS", "no" and "yES" are all acceptable.

Example

Input


8
fced
xyz
r
dabcef
az
aa
bad
babc


Output


Yes
Yes
Yes
Yes
No
No
No
No

Solution (in PYTHON):

Solution:
"""
Author    : raj1307
Institute : Jalpaiguri Government Engineering College
Date      : 15.04.19
"""
from __future__ import division, print_function
import itertools,os,sys
#from collections import deque, Counter, OrderedDict
#from heapq import nsmallest, nlargest, heapify, #heappop ,heappush, heapreplace
#from math import ceil,floor,log,sqrt,factorial,pow,pi
#from bisect import bisect_left,bisect_right
#from decimal import *
from atexit import register
from io import BytesIO, StringIO

if sys.version_info[0]<3:
    range = xrange
    filter = itertools.ifilter
    map = itertools.imap
    zip = itertools.izip
    sys.stdin = BytesIO(os.read(0, os.fstat(0).st_size))
    sys.stdout = BytesIO()
    register(lambda: os.write(1, sys.stdout.getvalue()))
else:
    sys.stdin = StringIO(os.read(0, os.fstat(0).st_size).decode())
    sys.stdout = StringIO()
    register(lambda: os.write(1, sys.stdout.getvalue().encode()))

input = lambda: sys.stdin.readline().rstrip('\r\n')

def ii(): return int(input())
def si(): return str(input())
def mi():return map(int,input().strip().split(" "))
def li():return list(mi())

abc='abcdefghijklmnopqrstuvwxyz'
abd={'a': 0, 'b': 1, 'c': 2, 'd': 3, 'e': 4, 'f': 5, 'g': 6, 'h': 7, 'i': 8, 'j': 9, 'k': 10, 'l': 11, 'm': 12, 'n': 13, 'o': 14, 'p': 15, 'q': 16, 'r': 17, 's': 18, 't': 19, 'u': 20, 'v': 21, 'w': 22, 'x': 23, 'y': 24, 'z': 25}
def getKey(item): return item[0] 
def sort2(l):return sorted(l, key=getKey)
def d2(n,m,num):return [[num for x in range(m)] for y in range(n)]
def ntl(n):return [int(i) for i in str(n)]
def powerMod(x,y,p):
    res = 1
    x %= p
    while y > 0:
        if y&1:
            res = (res*x)%p
        y = y>>1
        x = (x*x)%p1
    return res
def gcd(x, y):
    while y:
        x, y = y, x % y
    return x

# For getting input from input.txt file 
#sys.stdin = open('input.txt', 'r')  
  
# Printing the Output to output.txt file 
#sys.stdout = open('output.txt', 'w') 

def main():
   
    n=ii()
    for _ in range(n):
        f=[0]*27
        s=si()
        for i in range(len(s)):
            f[abd[s[i]]]+=1
        cnt,flag=0,0
        if max(f)==1:
            for i in range(27):
                if f[i]==1:
                    cnt+=1
                    flag=1
                elif flag==1:
                    if cnt==len(s):
                        print('Yes')
                    else:
                        print('No')
                    break
        else:
            print('No')























if __name__ == "__main__":
    main()