Problem: A permutation is a sequence of n integers from 1 to n, in which all numbers occur exactly once. For example, [1], [3, 5, 2, 1, 4], [1, 3, 2] are permutations, and [2, 3, 2], [4, 3, 1], [0] are not.

Polycarp was presented with a permutation p of numbers from 1 to n. However, when Polycarp came home, he noticed that in his pocket, the permutation p had turned into an array q according to the following rule: 

  * q_i = max(p_1, p_2, …, p_i). 



Now Polycarp wondered what lexicographically minimal and lexicographically maximal permutations could be presented to him.

An array a of length n is lexicographically smaller than an array b of length n if there is an index i (1 ≤ i ≤ n) such that the first i-1 elements of arrays a and b are the same, and the i-th element of the array a is less than the i-th element of the array b. For example, the array a=[1, 3, 2, 3] is lexicographically smaller than the array b=[1, 3, 4, 2].

For example, if n=7 and p=[3, 2, 4, 1, 7, 5, 6], then q=[3, 3, 4, 4, 7, 7, 7] and the following permutations could have been as p initially: 

  * [3, 1, 4, 2, 7, 5, 6] (lexicographically minimal permutation); 
  * [3, 1, 4, 2, 7, 6, 5]; 
  * [3, 2, 4, 1, 7, 5, 6]; 
  * [3, 2, 4, 1, 7, 6, 5] (lexicographically maximum permutation). 



For a given array q, find the lexicographically minimal and lexicographically maximal permutations that could have been originally presented to Polycarp.

Input

The first line contains one integer t (1 ≤ t ≤ 10^4). Then t test cases follow.

The first line of each test case contains one integer n (1 ≤ n ≤ 2 ⋅ 10^5).

The second line of each test case contains n integers q_1, q_2, …, q_n (1 ≤ q_i ≤ n).

It is guaranteed that the array q was obtained by applying the rule from the statement to some permutation p.

It is guaranteed that the sum of n over all test cases does not exceed 2 ⋅ 10^5.

Output

For each test case, output two lines: 

  * on the first line output n integers — lexicographically minimal permutation that could have been originally presented to Polycarp; 
  * on the second line print n integers — lexicographically maximal permutation that could have been originally presented to Polycarp; 

Example

Input


4
7
3 3 4 4 7 7 7
4
1 2 3 4
7
3 4 5 5 5 7 7
1
1


Output


3 1 4 2 7 5 6 
3 2 4 1 7 6 5 
1 2 3 4 
1 2 3 4 
3 4 5 1 2 7 6 
3 4 5 2 1 7 6 
1 
1 

Solution (in CPP):

Solution:
#include<bits/stdc++.h>
using namespace std;

int main()
{
	int t;
	cin>>t;
	while(t--){
		long long n;
		cin>>n;
		long long a[n];
		map<long long,long long>m;
		vector<long long> vi,vx;
		set<long long>v;
		for(int i=0;i<n;i++)
		{
			cin>>a[i];
			m[a[i]]++;
		}
		for(long long i=1;i<=n;i++)
		{
			if(m[i]==0)
				v.insert(i);

		}
		set<long long > v2;
		v2=v;
		
		for(int i=0;i<n;i++)
		{
			int p;
			if(i==0){
			vi.push_back(a[i]);
			vx.push_back(a[i]);
			p=a[i];
			}
			if(a[i]!=a[i-1])
			{
				vi.push_back(a[i]);
				vx.push_back(a[i]);
				p=a[i];
			}
			if(a[i]==a[i-1])
			{
				p=a[i];
				set<long long>::iterator lower, upper,it;
				it=v.begin();
				vi.push_back(*it);
				v.erase(it);
				//set<long long>::iterator lower, upper;
				lower = v2.lower_bound(p);
				lower--;
				vx.push_back(*lower);
				v2.erase(lower);
				//cout<<*it<<" "<<*lower<<endl;

			}

		}

		 for (auto it = vi.begin()+1; it != vi.end(); it++)
        cout << *it << " ";
		cout<<endl;
	 for (auto it = vx.begin()+1; it != vx.end(); it++)
        cout << *it << " ";
		cout<<endl;

	}
return 0;
}