Problem: Let's say string s has period k if s_i = s_{i + k} for all i from 1 to |s| - k (|s| means length of string s) and k is the minimum positive integer with this property.

Some examples of a period: for s="0101" the period is k=2, for s="0000" the period is k=1, for s="010" the period is k=2, for s="0011" the period is k=4.

You are given string t consisting only of 0's and 1's and you need to find such string s that:

  1. String s consists only of 0's and 1's; 
  2. The length of s doesn't exceed 2 ⋅ |t|; 
  3. String t is a subsequence of string s; 
  4. String s has smallest possible period among all strings that meet conditions 1—3. 



Let us recall that t is a subsequence of s if t can be derived from s by deleting zero or more elements (any) without changing the order of the remaining elements. For example, t="011" is a subsequence of s="10101".

Input

The first line contains single integer T (1 ≤ T ≤ 100) — the number of test cases.

Next T lines contain test cases — one per line. Each line contains string t (1 ≤ |t| ≤ 100) consisting only of 0's and 1's.

Output

Print one string for each test case — string s you needed to find. If there are multiple solutions print any one of them.

Example

Input


4
00
01
111
110


Output


00
01
11111
1010

Note

In the first and second test cases, s = t since it's already one of the optimal solutions. Answers have periods equal to 1 and 2, respectively.

In the third test case, there are shorter optimal solutions, but it's okay since we don't need to minimize the string s. String s has period equal to 1.

Solution (in PYTHON3):

Solution:
import sys
# from math import sqrt, floor, ceil
# from bisect import bisect
from collections import deque, Counter
inp = sys.stdin.readline
read = lambda: list(map(int, inp().split()))

def a():
	ans = ""
	for _ in range(int(inp())):
		x, y = sorted(read()); a, b = read()
		# print(x, y, a, b)
		d = min((y-x)*a + b*(x), (y+x)*a)
		ans += str(d)+"\n"
	print(ans)
def b():
	ans = ""
	for _ in range(int(inp())):
		t = inp().strip()
		if t.count("0") == 0 or t.count("1") == 0:ans+=t+"\n"
		else:
			tem = t[0]
			for i in range(1, len(t)):
				if t[i-1] == t[i]:tem+=("01" if t[i]=="1" else "10")
				else:tem += t[i]
			ans += tem +"\n"
	print(ans)



if __name__ == "__main__":
	# a()
	b()
	# c()
	# d()