Problem: You are given two positive integers n (1 ≤ n ≤ 10^9) and k (1 ≤ k ≤ 100). Represent the number n as the sum of k positive integers of the same parity (have the same remainder when divided by 2).

In other words, find a_1, a_2, …, a_k such that all a_i>0, n = a_1 + a_2 + … + a_k and either all a_i are even or all a_i are odd at the same time.

If such a representation does not exist, then report it.

Input

The first line contains an integer t (1 ≤ t ≤ 1000) — the number of test cases in the input. Next, t test cases are given, one per line.

Each test case is two positive integers n (1 ≤ n ≤ 10^9) and k (1 ≤ k ≤ 100).

Output

For each test case print:

  * YES and the required values a_i, if the answer exists (if there are several answers, print any of them); 
  * NO if the answer does not exist. 



The letters in the words YES and NO can be printed in any case.

Example

Input


8
10 3
100 4
8 7
97 2
8 8
3 10
5 3
1000000000 9


Output


YES
4 2 4
YES
55 5 5 35
NO
NO
YES
1 1 1 1 1 1 1 1
NO
YES
3 1 1
YES
111111110 111111110 111111110 111111110 111111110 111111110 111111110 111111110 111111120

Solution (in PYTHON3):

Solution:
#DIV 4 part  B  to doo...
i = int(input())
for _ in range(i):
    li = []
    x,y = map(int, input().split())
    if x==y:
        li= [1]*y

    elif x%2 ==0:
        li = [2]*(y-1) + [x-2*y +2]
        if li[-1] <2 or li[-1]%2 !=0:
            li = [1]*(y-1) + [x-1*y +1]
            if li[-1] < 1 or li[-1]%2 ==0:
                print("NO")
                continue

    else:
        li = [1]*(y-1) + [x-y+1]
        if li[-1] < 1 or li[-1]%2 ==0:
            li = [2]*(y-1) + [x-2*y +2]
            if li[-1] <2 or li[-1]%2 !=0:
                print("NO")
                continue

    print('YES')
    for j in li[:-1]:
        print(j,end = ' ')
    print(li[-1])