Problem: Let's define logical OR as an operation on two logical values (i. e. values that belong to the set {0, 1}) that is equal to 1 if either or both of the logical values is set to 1, otherwise it is 0. We can define logical OR of three or more logical values in the same manner:

<image> where <image> is equal to 1 if some ai = 1, otherwise it is equal to 0.

Nam has a matrix A consisting of m rows and n columns. The rows are numbered from 1 to m, columns are numbered from 1 to n. Element at row i (1 ≤ i ≤ m) and column j (1 ≤ j ≤ n) is denoted as Aij. All elements of A are either 0 or 1. From matrix A, Nam creates another matrix B of the same size using formula:

<image>.

(Bij is OR of all elements in row i and column j of matrix A)

Nam gives you matrix B and challenges you to guess matrix A. Although Nam is smart, he could probably make a mistake while calculating matrix B, since size of A can be large.

Input

The first line contains two integer m and n (1 ≤ m, n ≤ 100), number of rows and number of columns of matrices respectively.

The next m lines each contain n integers separated by spaces describing rows of matrix B (each element of B is either 0 or 1).

Output

In the first line, print "NO" if Nam has made a mistake when calculating B, otherwise print "YES". If the first line is "YES", then also print m rows consisting of n integers representing matrix A that can produce given matrix B. If there are several solutions print any one.

Examples

Input

2 2
1 0
0 0


Output

NO


Input

2 3
1 1 1
1 1 1


Output

YES
1 1 1
1 1 1


Input

2 3
0 1 0
1 1 1


Output

YES
0 0 0
0 1 0

Solution (in JAVA):

Solution:
import java.util.*;
import java.io.*;
public class OR_in_Matrix
{
	public static void main(String args[]) throws Exception
	{
		BufferedReader f=new BufferedReader(new InputStreamReader(System.in));
		StringTokenizer st=new StringTokenizer(f.readLine());
		int height=Integer.parseInt(st.nextToken());
		int width=Integer.parseInt(st.nextToken());
		int[][] arr=new int[height][width];
		for(int y=0;y<height;y++)
		{
			st=new StringTokenizer(f.readLine());
			for(int x=0;x<width;x++)
				arr[y][x]=Integer.parseInt(st.nextToken());
		}
		int[][] sources=new int[height][width];
		for(int y=0;y<height;y++)
			for(int x=0;x<width;x++)
				if(arr[y][x]==1)
				{
					boolean flag=true;
					for(int a=0;a<height;a++)
						if(arr[a][x]==0)
							flag=false;
					for(int b=0;b<width;b++)
						if(arr[y][b]==0)
							flag=false;
					if(flag)
						sources[y][x]=1;
				}
		int[][] res=new int[height][width];
		for(int y=0;y<height;y++)
			for(int x=0;x<width;x++)
				if(sources[y][x]==1)
				{
					for(int a=0;a<height;a++)
						res[a][x]=1;
					for(int b=0;b<width;b++)
						res[y][b]=1;
				}
		boolean flag=true;
		for(int y=0;y<height;y++)
			for(int x=0;x<width;x++)
				if(res[y][x]!=arr[y][x])
					flag=false;
		if(flag)
		{
			System.out.println("YES");
			for(int y=0;y<height;y++)
			{
				for(int x=0;x<width;x++)
					System.out.print(sources[y][x]+" ");
				System.out.println();
			}
		}
		else
			System.out.println("NO");
	}
}