Problem: You are given a tree consisting of n nodes. You want to write some labels on the tree's edges such that the following conditions hold:

  * Every label is an integer between 0 and n-2 inclusive. 
  * All the written labels are distinct. 
  * The largest value among MEX(u,v) over all pairs of nodes (u,v) is as small as possible. 



Here, MEX(u,v) denotes the smallest non-negative integer that isn't written on any edge on the unique simple path from node u to node v.

Input

The first line contains the integer n (2 ≤ n ≤ 10^5) — the number of nodes in the tree.

Each of the next n-1 lines contains two space-separated integers u and v (1 ≤ u,v ≤ n) that mean there's an edge between nodes u and v. It's guaranteed that the given graph is a tree.

Output

Output n-1 integers. The i^{th} of them will be the number written on the i^{th} edge (in the input order).

Examples

Input


3
1 2
1 3


Output


0
1


Input


6
1 2
1 3
2 4
2 5
5 6


Output


0
3
2
4
1

Note

The tree from the second sample:

<image>

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
vector<int> ve[100005];
int ans[100005];
int n;
int main() {
  ios_base::sync_with_stdio(false);
  cin.tie(NULL);
  cout.tie(NULL);
  cin >> n;
  for (int i = 1; i < n; i++) {
    int u, v;
    cin >> u >> v;
    ve[u].push_back(i);
    ve[v].push_back(i);
    ans[i] = -1;
  }
  int cnt = 0;
  for (int i = 1; i <= n; i++) {
    if (ve[i].size() > 2) {
      for (int j = 0; j <= ve[i].size() - 1; j++) {
        int id = ve[i][j];
        if (ans[id] == -1) {
          ans[id] = cnt++;
        }
      }
    }
  }
  for (int i = 1; i < n; i++) {
    if (ans[i] == -1) {
      ans[i] = cnt++;
    }
  }
  for (int i = 1; i < n; i++) {
    cout << ans[i] << endl;
  }
  return 0;
}