Problem: Let's say string s has period k if s_i = s_{i + k} for all i from 1 to |s| - k (|s| means length of string s) and k is the minimum positive integer with this property.

Some examples of a period: for s="0101" the period is k=2, for s="0000" the period is k=1, for s="010" the period is k=2, for s="0011" the period is k=4.

You are given string t consisting only of 0's and 1's and you need to find such string s that:

  1. String s consists only of 0's and 1's; 
  2. The length of s doesn't exceed 2 ⋅ |t|; 
  3. String t is a subsequence of string s; 
  4. String s has smallest possible period among all strings that meet conditions 1—3. 



Let us recall that t is a subsequence of s if t can be derived from s by deleting zero or more elements (any) without changing the order of the remaining elements. For example, t="011" is a subsequence of s="10101".

Input

The first line contains single integer T (1 ≤ T ≤ 100) — the number of test cases.

Next T lines contain test cases — one per line. Each line contains string t (1 ≤ |t| ≤ 100) consisting only of 0's and 1's.

Output

Print one string for each test case — string s you needed to find. If there are multiple solutions print any one of them.

Example

Input


4
00
01
111
110


Output


00
01
11111
1010

Note

In the first and second test cases, s = t since it's already one of the optimal solutions. Answers have periods equal to 1 and 2, respectively.

In the third test case, there are shorter optimal solutions, but it's okay since we don't need to minimize the string s. String s has period equal to 1.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
long long gcd(long long a, long long b) {
  while (b) {
    a %= b;
    swap(a, b);
  }
  return a;
}
long long lcm(long long a, long long b) { return a * b / gcd(a, b); }
int mod = 1000000007;
inline int add(int a, int b) {
  int ret = a + b;
  if (ret >= mod) ret -= mod;
  return ret;
}
int main() {
  char ok;
  int t, len;
  string str, res;
  scanf("%d", &t);
  while (t--) {
    cin >> str;
    len = str.length();
    res = "";
    ok = true;
    for (int i = 0; i < len; ++i) {
      if (str[i] == '0') {
        ok = false;
        break;
      }
    }
    if (ok)
      cout << str;
    else {
      ok = true;
      for (int i = 0; i < len; ++i) {
        if (str[i] == '1') {
          ok = false;
          break;
        }
      }
      if (ok)
        cout << str;
      else {
        for (int i = 0; i < len; ++i) {
          res += "01";
        }
        cout << res;
      }
    }
    cout << '\n';
  }
  return 0;
}