Problem: Given is an integer S. Find a combination of six integers X_1,Y_1,X_2,Y_2,X_3, and Y_3 that satisfies all of the following conditions:

* 0 \leq X_1,Y_1,X_2,Y_2,X_3,Y_3 \leq 10^9
* The area of the triangle in a two-dimensional plane whose vertices are (X_1,Y_1),(X_2,Y_2), and (X_3,Y_3) is S/2.



We can prove that there always exist six integers that satisfy the conditions under the constraints of this problem.

Constraints

* 1 \leq S \leq 10^{18}
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


S


Output

Print six integers X_1,Y_1,X_2,Y_2,X_3, and Y_3 that satisfy the conditions, in this order, with spaces in between. If multiple solutions exist, any of them will be accepted.

Examples

Input

3


Output

1 0 2 2 0 1


Input

100


Output

0 0 10 0 0 10


Input

311114770564041497


Output

314159265 358979323 846264338 327950288 419716939 937510582

Solution (in JAVA):

Solution:
import java.io.IOException;
import java.io.InputStream;
import java.io.PrintWriter;
import java.util.*;
import java.math.BigInteger;

public class Main implements Runnable {
	
	static int mod = 1000000007;
	
    public static void main(String[] args) {
    	new Thread(null, new Main(), "", 1024 * 1024 * 1024).start();
    }
    
    public void run() {
        PrintWriter out = new PrintWriter(System.out);
        FastScanner sc = new FastScanner();
        
        long s = sc.nextLong();
        
        long x3 = 0;
        long y3 = 0;
        
        if(s == 1000000000000000000L){
        	long x1 = 1000000000;
        	long y2 = x1;
        	long x2 = 0;
        	long y1 = 0;
            System.out.println(x1 + " " + y1 + " " + x2 + " " + y2 + " " + x3 + " " + y3);
            return;
        }
        
        long r = (long)Math.sqrt(s) + 1;
        
        long x1 = r;
        long y2 = r;
        
        long x2 = r*r - s;
        long y1 = 1;
        
        out.println(x1 + " " + y1 + " " + x2 + " " + y2 + " " + x3 + " " + y3);
        
        out.flush();
    }

	static ArrayList<Long> divisors(long n) {
		ArrayList<Long> l = new ArrayList<>();
		double sqrt = Math.sqrt(n);
		for (long i = (int)sqrt; i >= 1; i++) {	//自身と1を除きたければ2からスタート
			if (n % i == 0) {
				l.add(i);
				if (i != sqrt) {
					l.add(n/i);
				}
			}
		}
		return l;
	}
}

class FastScanner {
	private final InputStream in = System.in;
	private final byte[] buffer = new byte[1024];
	private int ptr = 0;
	private int buflen = 0;
	private boolean hasNextByte() {
		if (ptr < buflen) {
			return true;
		} else {
			ptr = 0;
			try {
				buflen = in.read(buffer);
			} catch (IOException e) {
				e.printStackTrace();
			}
			if (buflen <= 0) {
				return false;
			}
		}
		return true;
	}
	private int readByte() {
		if (hasNextByte())
			return buffer[ptr++];
		else
			return -1;
	}
	private static boolean isPrintableChar(int c) {
		return 33 <= c && c <= 126;
	}
	public boolean hasNext() {
		while (hasNextByte() && !isPrintableChar(buffer[ptr]))
			ptr++;
		return hasNextByte();
	}
	public String next() {
		if (!hasNext())
			throw new NoSuchElementException();
		StringBuilder sb = new StringBuilder();
		int b = readByte();
		while (isPrintableChar(b)) {
			sb.appendCodePoint(b);
			b = readByte();
		}
		return sb.toString();
	}
	public long nextLong() {
		if (!hasNext())
			throw new NoSuchElementException();
		long n = 0;
		boolean minus = false;
		int b = readByte();
		if (b == '-') {
			minus = true;
			b = readByte();
		}
		if (b < '0' || '9' < b) {
			throw new NumberFormatException();
		}
		while (true) {
			if ('0' <= b && b <= '9') {
				n *= 10;
				n += b - '0';
			} else if (b == -1 || !isPrintableChar(b)) {
				return minus ? -n : n;
			} else {
				throw new NumberFormatException();
			}
			b = readByte();
		}
	}
	public int nextInt() {
		long nl = nextLong();
		if (nl < Integer.MIN_VALUE || nl > Integer.MAX_VALUE)
			throw new NumberFormatException();
		return (int) nl;
	}
	public int[] nextintArray(int n){
		int[] a = new int[n];
		for(int i=0;i<n;i++){
			a[i] = nextInt();
		}
		return a;
	}
	public long[] nextlongArray(int n){
		long[] a = new long[n];
		for(int i=0;i<n;i++){
			a[i] = nextLong();
		}
		return a;
	}
	public Integer[] nextIntegerArray(int n){
		Integer[] a = new Integer[n];
		for(int i=0;i<n;i++){
			a[i] = nextInt();
		}
		return a;
	}
	public int[][] nextintMatrix(int h, int w){
		int[][] mat = new int[h][w];
		for(int i=0;i<h;i++){
			for(int j=0;j<w;j++){
				mat[i][j] = nextInt();
			}
		}
		return mat;
	}
	public double nextDouble() {
		return Double.parseDouble(next());
	}
}