Problem: You are given n arrays a_1, a_2, ..., a_n; each array consists of exactly m integers. We denote the y-th element of the x-th array as a_{x, y}.

You have to choose two arrays a_i and a_j (1 ≤ i, j ≤ n, it is possible that i = j). After that, you will obtain a new array b consisting of m integers, such that for every k ∈ [1, m] b_k = max(a_{i, k}, a_{j, k}).

Your goal is to choose i and j so that the value of min _{k = 1}^{m} b_k is maximum possible.

Input

The first line contains two integers n and m (1 ≤ n ≤ 3 ⋅ 10^5, 1 ≤ m ≤ 8) — the number of arrays and the number of elements in each array, respectively.

Then n lines follow, the x-th line contains the array a_x represented by m integers a_{x, 1}, a_{x, 2}, ..., a_{x, m} (0 ≤ a_{x, y} ≤ 10^9).

Output

Print two integers i and j (1 ≤ i, j ≤ n, it is possible that i = j) — the indices of the two arrays you have to choose so that the value of min _{k = 1}^{m} b_k is maximum possible. If there are multiple answers, print any of them.

Example

Input


6 5
5 0 3 1 2
1 8 9 1 3
1 2 3 4 5
9 1 0 3 7
2 3 0 6 3
6 4 1 7 0


Output


1 5

Solution (in JAVA):

Solution:
import java.util.*;
import java.io.*;
public class Main
{
    public static int u,w;
	public static void main(String[] args) throws Exception {
		Scanner sc=new Scanner(System.in);
	    int n=sc.nextInt();
	    int m=sc.nextInt();
	    int[][] arr=new int[n][m];
	    for(int i=0;i<n;i++)
	     for(int j=0;j<m;j++)
	      arr[i][j]=sc.nextInt();
	    u=w=1;
	    int l=0,r=1000000000;
	    while(l<=r)
	    {
	        int mid=(l+r)/2;
	        if(f(mid,arr,n,m))
	        l=mid+1;
	        else
	        r=mid-1;
	    }
	    System.out.println(u+" "+w);
	    }
	public static boolean f(int x,int[][] a,int n,int m)
	{
	    int[] v=new int[300];
	    Arrays.fill(v,0);
	     for(int i=0;i<n;i++)
       {
        int q=0;
        for(int j=0;j<m;j++)if(a[i][j]>=x)q|=(1<<j);
        v[q]=i+1;
       }
    for(int i=1;i<300;i++)
        for(int j=i;j<300;j++)
    if((v[i]!=0)&&(v[j]!=0)&&((i|j)==(1<<m)-1)){u=v[i];w=v[j];return true;}
    return false;
	}
}