Problem: You are given one integer n (n > 1).

Recall that a permutation of length n is an array consisting of n distinct integers from 1 to n in arbitrary order. For example, [2, 3, 1, 5, 4] is a permutation of length 5, but [1, 2, 2] is not a permutation (2 appears twice in the array) and [1, 3, 4] is also not a permutation (n = 3 but there is 4 in the array).

Your task is to find a permutation p of length n that there is no index i (1 ≤ i ≤ n) such that p_i = i (so, for all i from 1 to n the condition p_i ≠ i should be satisfied).

You have to answer t independent test cases.

If there are several answers, you can print any. It can be proven that the answer exists for each n > 1.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then t test cases follow.

The only line of the test case contains one integer n (2 ≤ n ≤ 100) — the length of the permutation you have to find.

Output

For each test case, print n distinct integers p_1, p_2, …, p_n — a permutation that there is no index i (1 ≤ i ≤ n) such that p_i = i (so, for all i from 1 to n the condition p_i ≠ i should be satisfied).

If there are several answers, you can print any. It can be proven that the answer exists for each n > 1.

Example

Input


2
2
5


Output


2 1
2 1 5 3 4

Solution (in JAVA):

Solution:
import java.io.*;
import java.math.*;
import java.security.*;
import java.text.*;
import java.util.*;
import java.util.concurrent.*;
import java.util.function.*;
import java.util.regex.*;
import java.util.stream.*;
import static java.util.stream.Collectors.joining;
import static java.util.stream.Collectors.toList;
 
public class Main
{
    public static void main(String[] args)
    {
        Scanner in=new Scanner(System.in);
        int t=in.nextInt();
        while(t>0)
        {
            t--;
            int n=in.nextInt();
            if((n&1)==0)
            {
                for(int i=0;i<n;i+=2)
                {
                    System.out.print((i+2)+" ");
                    System.out.print((i+1)+" ");
                }
            }
            else
            {
                for(int i=0;i<n-3;i+=2)
                {
                    System.out.print((i+2)+" ");
                    System.out.print((i+1)+" ");
                }
                System.out.print(n+" ");
                System.out.print((n-2)+" ");
                System.out.print((n-1)+" ");
            }
            System.out.println();
        }
    }
}