Problem: Mashmokh's boss, Bimokh, didn't like Mashmokh. So he fired him. Mashmokh decided to go to university and participate in ACM instead of finding a new job. He wants to become a member of Bamokh's team. In order to join he was given some programming tasks and one week to solve them. Mashmokh is not a very experienced programmer. Actually he is not a programmer at all. So he wasn't able to solve them. That's why he asked you to help him with these tasks. One of these tasks is the following.

A sequence of l integers b1, b2, ..., bl (1 ≤ b1 ≤ b2 ≤ ... ≤ bl ≤ n) is called good if each number divides (without a remainder) by the next number in the sequence. More formally <image> for all i (1 ≤ i ≤ l - 1).

Given n and k find the number of good sequences of length k. As the answer can be rather large print it modulo 1000000007 (109 + 7).

Input

The first line of input contains two space-separated integers n, k (1 ≤ n, k ≤ 2000).

Output

Output a single integer — the number of good sequences of length k modulo 1000000007 (109 + 7).

Examples

Input

3 2


Output

5


Input

6 4


Output

39


Input

2 1


Output

2

Note

In the first sample the good sequences are: [1, 1], [2, 2], [3, 3], [1, 2], [1, 3].

Solution (in PYTHON3):

Solution:
import sys
reader = (line.rstrip() for line in sys.stdin)
input = reader.__next__

divs = {}
n, k = map(int, input().split())
for i in range(1, n + 1) :
	for j in range(1, i + 1) :
		if(i % j == 0) :
			if i not in divs :
				divs[i] = [j]
			else :
				divs[i].append(j)
ans = 0
dp = []
MOD = 10**9 + 7
for _ in range(k + 1) :
	dp.append([0] * (n + 1))

dp[0][1] = 1
for i in range(1, k + 1) :
	for j in range(1, n + 1) :
		for el in divs[j] :
			dp[i][j] += dp[i - 1][el]
			dp[i][j] %= MOD
		if i == k :
			ans += dp[i][j]
			ans %= MOD

print(ans % MOD)