Problem: You are given two positive integers n (1 ≤ n ≤ 10^9) and k (1 ≤ k ≤ 100). Represent the number n as the sum of k positive integers of the same parity (have the same remainder when divided by 2).

In other words, find a_1, a_2, …, a_k such that all a_i>0, n = a_1 + a_2 + … + a_k and either all a_i are even or all a_i are odd at the same time.

If such a representation does not exist, then report it.

Input

The first line contains an integer t (1 ≤ t ≤ 1000) — the number of test cases in the input. Next, t test cases are given, one per line.

Each test case is two positive integers n (1 ≤ n ≤ 10^9) and k (1 ≤ k ≤ 100).

Output

For each test case print:

  * YES and the required values a_i, if the answer exists (if there are several answers, print any of them); 
  * NO if the answer does not exist. 



The letters in the words YES and NO can be printed in any case.

Example

Input


8
10 3
100 4
8 7
97 2
8 8
3 10
5 3
1000000000 9


Output


YES
4 2 4
YES
55 5 5 35
NO
NO
YES
1 1 1 1 1 1 1 1
NO
YES
3 1 1
YES
111111110 111111110 111111110 111111110 111111110 111111110 111111110 111111110 111111120

Solution (in JAVA):

Solution:

//package CodeForce;

import java.util.Scanner;


public class SameParity {
    public static void main(String[] args) {
        Scanner input = new Scanner(System.in);
        int t = input.nextInt();
        while(t-->0){
            int n = input.nextInt();
            int k = input.nextInt();
            int p = n-k+1;
            if(p>0 && p%2==1)
            {
                System.out.println("YES");
                for (int i = 0; i < k-1; i++) {
                    System.out.print(1+" ");
                }
                System.out.println(p);
                continue;
            }
            int m=n-2*(k-1);
            if(m>0 && m%2==0){
                System.out.println("YES");
                for (int i = 0; i < k-1; i++) {
                    System.out.print(2+" ");
                }
                System.out.println(m);
                continue;
            }
            else
                System.out.println("NO");
        }
    }
}