Problem: Snuke loves colorful balls. He has a total of N×K balls, K in each of his favorite N colors. The colors are numbered 1 through N.

He will arrange all of the balls in a row from left to right, in arbitrary order. Then, for each of the N colors, he will paint the leftmost ball of that color into color 0, a color different from any of the N original colors.

After painting, how many sequences of the colors of the balls are possible? Find this number modulo 10^9+7.

Constraints

* 1≤N,K≤2,000

Input

The input is given from Standard Input in the following format:


N K


Output

Print the number of the possible sequences of the colors of the balls after painting, modulo 10^9+7.

Examples

Input

2 2


Output

4


Input

3 1


Output

1


Input

2 3


Output

14


Input

2000 2000


Output

546381702

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
const int N=2005,mod=1e9+7;
int n,k;
int Fac[N*N],Inv[N*N],dp[N][N];
int Pow(int x,int y){
	int ans=1;
	for (;y;y>>=1,x=1LL*x*x%mod)
		if (y&1)
			ans=1LL*ans*x%mod;
	return ans;
}
int C(int n,int m){
	if (m<0||m>n)
		return 0;
	return 1LL*Fac[n]*Inv[m]%mod*Inv[n-m]%mod;
}
int main(){
	scanf("%d%d",&n,&k);
	if (k==1){
		puts("1");
		return 0;
	}
	for (int i=Fac[0]=Inv[0]=1;i<=n*k;i++){
		Fac[i]=1LL*Fac[i-1]*i%mod;
		Inv[i]=1LL*Inv[i-1]*Pow(i,mod-2)%mod;
	}
	dp[0][0]=1;
	for (int i=0;i<=n;i++)
		for (int j=i;j<=n;j++){
			dp[i][j+1]=(dp[i][j+1]+dp[i][j])%mod;
			dp[i+1][j]=(1LL*dp[i][j]*C(k*(n-i)-(j-i)-1,k-2)+dp[i+1][j])%mod;
		}
	printf("%lld",1LL*dp[n][n]*Fac[n]%mod);
	return 0;
}