Problem: Mashmokh's boss, Bimokh, didn't like Mashmokh. So he fired him. Mashmokh decided to go to university and participate in ACM instead of finding a new job. He wants to become a member of Bamokh's team. In order to join he was given some programming tasks and one week to solve them. Mashmokh is not a very experienced programmer. Actually he is not a programmer at all. So he wasn't able to solve them. That's why he asked you to help him with these tasks. One of these tasks is the following.

A sequence of l integers b1, b2, ..., bl (1 ≤ b1 ≤ b2 ≤ ... ≤ bl ≤ n) is called good if each number divides (without a remainder) by the next number in the sequence. More formally <image> for all i (1 ≤ i ≤ l - 1).

Given n and k find the number of good sequences of length k. As the answer can be rather large print it modulo 1000000007 (109 + 7).

Input

The first line of input contains two space-separated integers n, k (1 ≤ n, k ≤ 2000).

Output

Output a single integer — the number of good sequences of length k modulo 1000000007 (109 + 7).

Examples

Input

3 2


Output

5


Input

6 4


Output

39


Input

2 1


Output

2

Note

In the first sample the good sequences are: [1, 1], [2, 2], [3, 3], [1, 2], [1, 3].

Solution (in PYTHON3):

Solution:
#	!/bin/env python3
#	encoding: UTF-8


#	✪ H4WK3yE乡
#	Mohd. Farhan Tahir
#	Indian Institute Of Information Technology and Management,Gwalior

#	Question Link
#	https://codeforces.com/problemset/problem/414/B
#

# ///==========Libraries, Constants and Functions=============///


import sys

inf = float("inf")
mod = 1000000007


def get_array(): return list(map(int, sys.stdin.readline().split()))


def get_ints(): return map(int, sys.stdin.readline().split())


def input(): return sys.stdin.readline()

# ///==========MAIN=============///


def main():
    n, k = get_ints()
    dp = [[0]*(n+1) for _ in range(k+1)]
    # dp[i][j] no of sequences of length i that end with j
    for i in range(1, n+1):
        dp[1][i] = 1
    for i in range(1, k):
        for j in range(1, n+1):
            for l in range(j, n+1, j):  # factors of j
                dp[i+1][l] = (dp[i+1][l]+dp[i][j]) % mod

    ans = 0
    for i in range(1, n+1):
        ans = (ans+dp[k][i]) % mod
    print(ans)


if __name__ == "__main__":
    main()