Problem: Toad Rash has a binary string s. A binary string consists only of zeros and ones.

Let n be the length of s.

Rash needs to find the number of such pairs of integers l, r that 1 ≤ l ≤ r ≤ n and there is at least one pair of integers x, k such that 1 ≤ x, k ≤ n, l ≤ x < x + 2k ≤ r, and s_x = s_{x+k} = s_{x+2k}.

Find this number of pairs for Rash.

Input

The first line contains the string s (1 ≤ |s| ≤ 300 000), consisting of zeros and ones.

Output

Output one integer: the number of such pairs of integers l, r that 1 ≤ l ≤ r ≤ n and there is at least one pair of integers x, k such that 1 ≤ x, k ≤ n, l ≤ x < x + 2k ≤ r, and s_x = s_{x+k} = s_{x+2k}.

Examples

Input


010101


Output


3


Input


11001100


Output


0

Note

In the first example, there are three l, r pairs we need to count: 1, 6; 2, 6; and 1, 5.

In the second example, there are no values x, k for the initial string, so the answer is 0.

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.*;

public class B {
	// ------------------------

	public static void main(String[] args) {
		MyScanner sc = new MyScanner();
		out = new PrintWriter(new BufferedOutputStream(System.out));
		// ------------------------
		char[]s=sc.nextLine().toCharArray();
		long ans=(long)s.length*(long)(s.length+1)/2L;
		for(int i=0;i<s.length;i++)
			ans-=bad(i,s);
		out.println(ans);
		// ------------------------
		out.close();
	}
	//------------------------
	public static long bad(int ind,char[]s){
		long ans=0;
		for(int i=ind;i<s.length;i++){
			if(works(s,ind,i))
				break;
			ans++;
		}
		return ans;
	}
	public static boolean works(char[]s,int st,int en){
		if(en-st<2)
			return false;
		for(int i=st+1;i<=en-1;i++)
			for(int j=1;j<=Math.min(i-st,en-i);j++)
				if(s[i]==s[i-j]&&s[i]==s[i+j])
					return true;
		return false;
	}
	public static PrintWriter out;
	public static class MyScanner {
		BufferedReader br;
		StringTokenizer st;
		public MyScanner() {
			br = new BufferedReader(new InputStreamReader(System.in));
		}
		String next() {
			while (st == null || !st.hasMoreElements()) {
				try {
					st = new StringTokenizer(br.readLine());
				} catch (IOException e) {
					e.printStackTrace();
				}
			}
			return st.nextToken();
		}
		int nextInt() {
			return Integer.parseInt(next());
		}
		long nextLong() {
			return Long.parseLong(next());
		}
		double nextDouble() {
			return Double.parseDouble(next());
		}
		String nextLine() {
			String str = "";
			try {
				str = br.readLine();
			} catch (IOException e) {
				e.printStackTrace();
			}
			return str;
		}
	}
}