Problem: Let's define logical OR as an operation on two logical values (i. e. values that belong to the set {0, 1}) that is equal to 1 if either or both of the logical values is set to 1, otherwise it is 0. We can define logical OR of three or more logical values in the same manner:

<image> where <image> is equal to 1 if some ai = 1, otherwise it is equal to 0.

Nam has a matrix A consisting of m rows and n columns. The rows are numbered from 1 to m, columns are numbered from 1 to n. Element at row i (1 ≤ i ≤ m) and column j (1 ≤ j ≤ n) is denoted as Aij. All elements of A are either 0 or 1. From matrix A, Nam creates another matrix B of the same size using formula:

<image>.

(Bij is OR of all elements in row i and column j of matrix A)

Nam gives you matrix B and challenges you to guess matrix A. Although Nam is smart, he could probably make a mistake while calculating matrix B, since size of A can be large.

Input

The first line contains two integer m and n (1 ≤ m, n ≤ 100), number of rows and number of columns of matrices respectively.

The next m lines each contain n integers separated by spaces describing rows of matrix B (each element of B is either 0 or 1).

Output

In the first line, print "NO" if Nam has made a mistake when calculating B, otherwise print "YES". If the first line is "YES", then also print m rows consisting of n integers representing matrix A that can produce given matrix B. If there are several solutions print any one.

Examples

Input

2 2
1 0
0 0


Output

NO


Input

2 3
1 1 1
1 1 1


Output

YES
1 1 1
1 1 1


Input

2 3
0 1 0
1 1 1


Output

YES
0 0 0
0 1 0

Solution (in PYTHON):

Solution:
from __future__ import print_function

[m,n] = [int(i) for i in raw_input().split()]
L = []
result = []
for i in range(m):
    l = [int(i) for i in raw_input().split()]
    L += [l[:]]
    result += [l] 

def help(L,x,y,v):
    for i in range(len(L)):
        for j in range(len(L[i])):
            if i == x or j == y:
                L[i][j] = v
    return L

rows_clear = []
cols_clear = []

for i in range(len(L)):
    for j in range(len(L[i])):
        if L[i][j] == 0:
            rows_clear += [i]
            cols_clear += [j]


rows_clear = set(rows_clear)
cols_clear = set(cols_clear)


for i in rows_clear:
    result = help(result, i, -1, 0)


for i in cols_clear:
    result = help(result, -1, i, 0)


checker = []
for i in range(len(result)):
    checker += [result[i][:]]
rows_clear = []
cols_clear = []

for i in range(len(L)):
    for j in range(len(L[i])):
        if result[i][j] == 1:
            rows_clear += [i]
            cols_clear += [j]


rows_clear = set(rows_clear)
cols_clear = set(cols_clear)


for i in rows_clear:
    checker = help(checker, i, -1, 1)


for i in cols_clear:
    checker = help(checker, -1, i, 1)


if checker != L:
    print ("NO")
else:
    print  ("YES")
    for i in range(len(L)):
        for j in range(len(L[i])):
            if j<len(L[i])-1:
                print(result[i][j], end=' ')
            else:
                print(result[i][j])