Problem: Let's define logical OR as an operation on two logical values (i. e. values that belong to the set {0, 1}) that is equal to 1 if either or both of the logical values is set to 1, otherwise it is 0. We can define logical OR of three or more logical values in the same manner:

<image> where <image> is equal to 1 if some ai = 1, otherwise it is equal to 0.

Nam has a matrix A consisting of m rows and n columns. The rows are numbered from 1 to m, columns are numbered from 1 to n. Element at row i (1 ≤ i ≤ m) and column j (1 ≤ j ≤ n) is denoted as Aij. All elements of A are either 0 or 1. From matrix A, Nam creates another matrix B of the same size using formula:

<image>.

(Bij is OR of all elements in row i and column j of matrix A)

Nam gives you matrix B and challenges you to guess matrix A. Although Nam is smart, he could probably make a mistake while calculating matrix B, since size of A can be large.

Input

The first line contains two integer m and n (1 ≤ m, n ≤ 100), number of rows and number of columns of matrices respectively.

The next m lines each contain n integers separated by spaces describing rows of matrix B (each element of B is either 0 or 1).

Output

In the first line, print "NO" if Nam has made a mistake when calculating B, otherwise print "YES". If the first line is "YES", then also print m rows consisting of n integers representing matrix A that can produce given matrix B. If there are several solutions print any one.

Examples

Input

2 2
1 0
0 0


Output

NO


Input

2 3
1 1 1
1 1 1


Output

YES
1 1 1
1 1 1


Input

2 3
0 1 0
1 1 1


Output

YES
0 0 0
0 1 0

Solution (in JAVA):

Solution:
import java.util.Arrays;
import java.util.Scanner;


public class ORinMatrix {

    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int m = sc.nextInt();
        int n = sc.nextInt();
        
        int [][] a = new int [m][n];
        int [] rows = new int [m];
        int [] cols = new int [n];
        boolean One = false;
        boolean imp = false;
        Arrays.fill(rows, -1);
        Arrays.fill(cols, -1);
        for (int i = 0; i < a.length; i++) {
            for (int j = 0; j < a[i].length; j++) {
             a[i][j] = sc.nextInt();
             if(a[i][j] == 1)
                 One = true;
             if(a[i][j] == 0){
                 rows[i] = 0;
                 cols[j] = 0;
             }else{
                 if(rows[i]==0 && cols[j]==0) imp = true;
                 if(rows[i]!=0) rows[i] = 1;
                 if(cols[j]!=0)cols [j] = 1;
             }
            }
        }
        boolean zeros = true;
        int [][] b = new int[m][n];
        for (int i = 0; i < a.length; i++) {
            for (int j = 0; j < a[i].length; j++) {
                if(rows[i] ==0 || cols[j] ==0)
                    b[i][j] = 0;
                else{
                    b[i][j] = 1;
                    zeros = false;
                }
            }
        }
        
        
            
            
            int r [] = new int [m];
            int c [] = new int [n];
            for (int i = 0; i < b.length; i++) {
                for (int j = 0; j < b[i].length; j++) {
                    r[i] |= b[i][j];
                }
            }
            for (int i = 0; i < n; i++) {
                for (int j = 0; j < m; j++) {
                    c[i] |= b[j][i];
                }
            }
//          System.out.println(Arrays.toString(r));
//          System.out.println(Arrays.toString(c));
            for (int i = 0; i < a.length; i++) {
                for (int j = 0; j < a[i].length; j++) {
                    if(a[i][j] != (r[i] | c[j])){
                        imp = true;
                        break;
                }
                }
            
        }
            if(imp)
            System.out.println("NO");
            else
            {
                System.out.println("YES");
                
                for (int i = 0; i < b.length; i++) {
                    for (int j = 0; j < b[i].length; j++) {
                        System.out.print(b[i][j]+" ");
                    }
                    System.out.println();
                }
                
    }
}
}