Problem: Let's say string s has period k if s_i = s_{i + k} for all i from 1 to |s| - k (|s| means length of string s) and k is the minimum positive integer with this property.

Some examples of a period: for s="0101" the period is k=2, for s="0000" the period is k=1, for s="010" the period is k=2, for s="0011" the period is k=4.

You are given string t consisting only of 0's and 1's and you need to find such string s that:

  1. String s consists only of 0's and 1's; 
  2. The length of s doesn't exceed 2 ⋅ |t|; 
  3. String t is a subsequence of string s; 
  4. String s has smallest possible period among all strings that meet conditions 1—3. 



Let us recall that t is a subsequence of s if t can be derived from s by deleting zero or more elements (any) without changing the order of the remaining elements. For example, t="011" is a subsequence of s="10101".

Input

The first line contains single integer T (1 ≤ T ≤ 100) — the number of test cases.

Next T lines contain test cases — one per line. Each line contains string t (1 ≤ |t| ≤ 100) consisting only of 0's and 1's.

Output

Print one string for each test case — string s you needed to find. If there are multiple solutions print any one of them.

Example

Input


4
00
01
111
110


Output


00
01
11111
1010

Note

In the first and second test cases, s = t since it's already one of the optimal solutions. Answers have periods equal to 1 and 2, respectively.

In the third test case, there are shorter optimal solutions, but it's okay since we don't need to minimize the string s. String s has period equal to 1.

Solution (in JAVA):

Solution:
/*
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 * To change this template file, choose Tools | Templates
 * and open the template in the editor.
 */



import java.util.Scanner;

/**
 *
 * @author Pieter
 */
public class B {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        StringBuilder sb = new StringBuilder("");

        int tests = sc.nextInt();

        for(int t = 0; t < tests; t++) {

            String s = sc.next();
            
            int zeros = 0;
            int ones = 0;
            
            char[] arr = s.toCharArray();
            for(int i = 0; i < arr.length; i++) {
                if(arr[i] == '0') zeros++;
                if(arr[i] == '1') ones++;
            }
            
            if(zeros == 0) {
                for(int i = 0; i < s.length(); i++) {
                    sb.append("1");
                }
                sb.append("\n");
            } else if(ones == 0) {
                for(int i = 0; i < s.length(); i++) {
                    sb.append("0");
                }
                sb.append("\n");
            } else {
                for(int i = 0; i < arr.length; i++) {
                    sb.append("10");
                }
                sb.append("\n");
            }
            
        }

        System.out.println(sb);
    }
}