Problem: Snuke loves colorful balls. He has a total of N×K balls, K in each of his favorite N colors. The colors are numbered 1 through N.

He will arrange all of the balls in a row from left to right, in arbitrary order. Then, for each of the N colors, he will paint the leftmost ball of that color into color 0, a color different from any of the N original colors.

After painting, how many sequences of the colors of the balls are possible? Find this number modulo 10^9+7.

Constraints

* 1≤N,K≤2,000

Input

The input is given from Standard Input in the following format:


N K


Output

Print the number of the possible sequences of the colors of the balls after painting, modulo 10^9+7.

Examples

Input

2 2


Output

4


Input

3 1


Output

1


Input

2 3


Output

14


Input

2000 2000


Output

546381702

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.*;

public class Main {

	BufferedReader br;
	PrintWriter out;
	StringTokenizer st;
	boolean eof;

	static final int P = 1_000_000_007;

	void solve() throws IOException {
		int n = nextInt();
		int k = nextInt();

		if (k == 1) {
			out.println(1);
			return;
		}

		ModuloCombinatorics mc = new ModuloCombinatorics(n * k, P);

		int[][] dp = new int[n + 1][n + 1];
		dp[0][0] = 1;
		for (int i = 0; i <= n; i++) {
			for (int j = i; j <= n; j++) {

				if (i > 0) {
					dp[i][j] += dp[i - 1][j];
					if (dp[i][j] >= P) {
						dp[i][j] -= P;
					}
				}

				if (j > i) {
					int n1 = i + j * (k - 1) - 1;
					int k1 = k - 2;
					dp[i][j] += (int) ((long) dp[i][j - 1]
							* ((int) ((long) mc.fact[n1] * mc.invFact[k1]
									% mc.P * mc.invFact[n1 - k1] % mc.P)) % P);
					dp[i][j] %= P;
				}

			}
		}

		int ret = (int) ((long) dp[n][n] * mc.fact[n] % P);

		out.println(ret);
	}

	static class ModuloCombinatorics {
		/** maximal needed number, N itself is included **/
		final int N;

		/** prime modulo **/
		final int P;

		/** factorials **/
		final int[] fact;

		/** multiplicative inverses, take care to not touch inv[0] **/
		final int[] inv;

		/** inverse factorials **/
		final int[] invFact;

		public ModuloCombinatorics(int N, int P) {
			this.N = N;
			this.P = P;
			fact = new int[N + 1];
			fact[0] = 1;
			for (int i = 1; i <= N; i++) {
				fact[i] = (int) ((long) i * fact[i - 1] % P);
			}

			inv = new int[N + 1];
			inv[1] = 1;
			for (int i = 2; i <= N; i++) {
				inv[i] = P - (int) ((long) (P / i) * inv[P % i] % P);
			}

			invFact = new int[N + 1];
			invFact[0] = 1;
			for (int i = 1; i <= N; i++) {
				invFact[i] = (int) ((long) invFact[i - 1] * inv[i] % P);
			}
		}

		public int choose(int n, int k) {
			return (n < 0 || k < 0 || k > n) ? 0 : (int) ((long) fact[n]
					* invFact[k] % P * invFact[n - k] % P);
		}

		/** a^b modulo mod, mod is arbitrary **/
		static public int pow(int a, long b, int mod) {
			if (a < 0 || a >= mod || b < 0) {
				throw new IllegalArgumentException();
			}
			int ret = 1;
			for (; b > 0; b >>= 1) {
				if ((b & 1) == 1) {
					ret = (int) ((long) ret * a % mod);
				}
				a = (int) ((long) a * a % mod);
			}
			return ret;
		}

		/** a^b modulo P **/
		public int pow(int a, long b) {
			return pow(a, b, P);
		}
	}

	Main() throws IOException {
		br = new BufferedReader(new InputStreamReader(System.in));
		out = new PrintWriter(System.out);
		solve();
		out.close();
	}

	public static void main(String[] args) throws IOException {
		new Main();
	}

	String nextToken() {
		while (st == null || !st.hasMoreTokens()) {
			try {
				st = new StringTokenizer(br.readLine());
			} catch (Exception e) {
				eof = true;
				return null;
			}
		}
		return st.nextToken();
	}

	String nextString() {
		try {
			return br.readLine();
		} catch (IOException e) {
			eof = true;
			return null;
		}
	}

	int nextInt() throws IOException {
		return Integer.parseInt(nextToken());
	}

	long nextLong() throws IOException {
		return Long.parseLong(nextToken());
	}

	double nextDouble() throws IOException {
		return Double.parseDouble(nextToken());
	}
}