Problem: For a given array $a_1, a_2, a_3, ... , a_N$ of $N$ elements and an integer $L$, find the minimum of each possible sub-arrays with size $L$ and print them from the beginning. For example, for an array $\\{1, 7, 7, 4, 8, 1, 6\\}$ and $L = 3$, the possible sub-arrays with size $L = 3$ includes $\\{1, 7, 7\\}$, $\\{7, 7, 4\\}$, $\\{7, 4, 8\\}$, $\\{4, 8, 1\\}$, $\\{8, 1, 6\\}$ and the minimum of each sub-array is 1, 4, 4, 1, 1 respectively.

Constraints

* $1 \leq N \leq 10^6$
* $1 \leq L \leq 10^6$
* $1 \leq a_i \leq 10^9$
* $L \leq N$

Input

The input is given in the following format.

$N$ $L$
$a_1$ $a_2$ ... $a_N$

Output

Print a sequence of the minimum in a line. Print a space character between adjacent elements.

Example

Input

7 3
1 7 7 4 8 1 6


Output

1 4 4 1 1

Solution (in PYTHON3):

Solution:
def ascend(a,b):
    mini = min(A[a:a+L])
    ans[a] = mini
    for i in range(a+1,b):
        if A[i+L-1] <= mini : mini = A[i+L-1]
        elif A[i-1] == mini : mini = min(A[i:i+L])
        ans[i] = mini

def descend(a,b):
    mini = min(A[b-1:b+L-1])
    ans[b-1] = mini
    for i in range(b-2,a-1,-1):
        if A[i] <= mini : mini = A[i]
        elif A[i+L] == mini: mini = min(A[i:i+L])
        ans[i] = mini
    
[N,L] = [int(x) for x in input().split()]
A = [int(x) for x in input().split()]
ans = [None]*(N-L+1)
count = 0;
if N > 10 ** 4:
    for i in range(100):
        if A[i+1] > A[i] : count += 1
    if count > 80 : descend(0, N-L+1)
    else : ascend(0,N-L+1)
else :
    ascend(0, N-L+1)
for i in ans[:-1] : print(i, end=" ")
print(ans[-1])