Problem: There are N cells arranged in a row, numbered 1, 2, \ldots, N from left to right.

Tak lives in these cells and is currently on Cell 1. He is trying to reach Cell N by using the procedure described below.

You are given an integer K that is less than or equal to 10, and K non-intersecting segments [L_1, R_1], [L_2, R_2], \ldots, [L_K, R_K]. Let S be the union of these K segments. Here, the segment [l, r] denotes the set consisting of all integers i that satisfy l \leq i \leq r.

* When you are on Cell i, pick an integer d from S and move to Cell i + d. You cannot move out of the cells.



To help Tak, find the number of ways to go to Cell N, modulo 998244353.

Constraints

* 2 \leq N \leq 2 \times 10^5
* 1 \leq K \leq \min(N, 10)
* 1 \leq L_i \leq R_i \leq N
* [L_i, R_i] and [L_j, R_j] do not intersect (i \neq j)
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N K
L_1 R_1
L_2 R_2
:
L_K R_K


Output

Print the number of ways for Tak to go from Cell 1 to Cell N, modulo 998244353.

Examples

Input

5 2
1 1
3 4


Output

4


Input

5 2
3 3
5 5


Output

0


Input

5 1
1 2


Output

5


Input

60 3
5 8
1 3
10 15


Output

221823067

Solution (in CPP):

Solution:
#include<bits/stdc++.h>
using namespace std;
typedef long long LL;
const int Mod=998244353,N=2e5+5;
const int INF=0x3f3f3f3f;
LL f[N],a[20],b[20],c[20];
int main() {
#ifndef ONLINE_JUDGE
	freopen("in.txt","r",stdin);
#endif
	ios::sync_with_stdio(false);
	cin.tie(0);
	int n,m;
	cin>>n>>m;
	for(int i=0;i<m;++i){
		cin>>a[i]>>b[i]; 
	}
	f[1]=1;
	for(int i=2;i<=n;++i){
		for(int j=0;j<m;++j){
			c[j]+=(i-a[j]>=1 ? f[i-a[j]] : 0) - (i-b[j]-1>=1 ? f[i-b[j]-1] : 0);
			f[i]=(f[i]+c[j])%Mod;
		}
	}
	cout<<f[n]<<endl;
	return 0;
}