Problem: You are given n arrays a_1, a_2, ..., a_n; each array consists of exactly m integers. We denote the y-th element of the x-th array as a_{x, y}.

You have to choose two arrays a_i and a_j (1 ≤ i, j ≤ n, it is possible that i = j). After that, you will obtain a new array b consisting of m integers, such that for every k ∈ [1, m] b_k = max(a_{i, k}, a_{j, k}).

Your goal is to choose i and j so that the value of min _{k = 1}^{m} b_k is maximum possible.

Input

The first line contains two integers n and m (1 ≤ n ≤ 3 ⋅ 10^5, 1 ≤ m ≤ 8) — the number of arrays and the number of elements in each array, respectively.

Then n lines follow, the x-th line contains the array a_x represented by m integers a_{x, 1}, a_{x, 2}, ..., a_{x, m} (0 ≤ a_{x, y} ≤ 10^9).

Output

Print two integers i and j (1 ≤ i, j ≤ n, it is possible that i = j) — the indices of the two arrays you have to choose so that the value of min _{k = 1}^{m} b_k is maximum possible. If there are multiple answers, print any of them.

Example

Input


6 5
5 0 3 1 2
1 8 9 1 3
1 2 3 4 5
9 1 0 3 7
2 3 0 6 3
6 4 1 7 0


Output


1 5

Solution (in PYTHON3):

Solution:
def get_ans(x, a, n, m):

    lim = 1<<m
    match = lim-1
    track = [-1 for i in range(lim)]

    for i in range(n):
        mask = 0
        for j in range(m):
            if(a[i][j] >= x):
                mask |= 1 << j
        track[mask] = i

    for i in range(lim):
        for j in range(lim):
            if(i|j == match and track[i] != -1 and track[j] != -1):
                return track[i], track[j]
    
    return -1, -1


n, m = map(int, input().split())
a = [list(map(int, input().split())) for i in range(n)]

lo = 0
hi = 1000000000
while(lo < hi-1):
    mid = (lo+hi)/2
    i, j = get_ans(mid,a,n,m)
    if(i == -1):
        hi = mid-1
    else:
        lo = mid

i,j = get_ans(hi,a,n,m)
if(i != -1):
    print("{} {}".format(i+1,j+1))
else:
    i,j = get_ans(lo,a,n,m)
    print("{} {}".format(i+1,j+1))