Problem: Let's define logical OR as an operation on two logical values (i. e. values that belong to the set {0, 1}) that is equal to 1 if either or both of the logical values is set to 1, otherwise it is 0. We can define logical OR of three or more logical values in the same manner:

<image> where <image> is equal to 1 if some ai = 1, otherwise it is equal to 0.

Nam has a matrix A consisting of m rows and n columns. The rows are numbered from 1 to m, columns are numbered from 1 to n. Element at row i (1 ≤ i ≤ m) and column j (1 ≤ j ≤ n) is denoted as Aij. All elements of A are either 0 or 1. From matrix A, Nam creates another matrix B of the same size using formula:

<image>.

(Bij is OR of all elements in row i and column j of matrix A)

Nam gives you matrix B and challenges you to guess matrix A. Although Nam is smart, he could probably make a mistake while calculating matrix B, since size of A can be large.

Input

The first line contains two integer m and n (1 ≤ m, n ≤ 100), number of rows and number of columns of matrices respectively.

The next m lines each contain n integers separated by spaces describing rows of matrix B (each element of B is either 0 or 1).

Output

In the first line, print "NO" if Nam has made a mistake when calculating B, otherwise print "YES". If the first line is "YES", then also print m rows consisting of n integers representing matrix A that can produce given matrix B. If there are several solutions print any one.

Examples

Input

2 2
1 0
0 0


Output

NO


Input

2 3
1 1 1
1 1 1


Output

YES
1 1 1
1 1 1


Input

2 3
0 1 0
1 1 1


Output

YES
0 0 0
0 1 0

Solution (in JAVA):

Solution:

import java.math.*;
import java.util.*;

public class BruteForce {

    public static Scanner in = new Scanner(System.in);

    public static int[][] OR(int[][] mn) {
        int[][] ans = new int[mn.length][mn[0].length];
        for (int i = 0; i < ans.length; i++) {
            for (int j = 0; j < ans[0].length; j++) {
                int ones = 0;
                for (int x = 0; x < ans[0].length; x++) {
                    if (mn[i][x] == 1) {
                        ones++;
                    }
                }
                for (int x = 0; x < ans.length; x++) {
                    if (mn[x][j] == 1) {
                        ones++;
                    }
                }
                if (ones > 0) {
                    ans[i][j] = 1;
                }
            }
        }
        return ans;
    }

    public static boolean isEqual(int[][] gen, int[][] z) {
        boolean ans = true;
        for (int i = 0; i < z.length; i++) {
            for (int j = 0; j < z[0].length; j++) {
                if (gen[i][j] != z[i][j]) {
                    ans = false;
                    break;
                }
            }
        }
        return ans;
    }

    public static void main(String[] args) {
        int n = in.nextInt();
        int m = in.nextInt();

        //Reading the given matrix
        int[][] z = new int[n][m];
        for (int i = 0; i < n; i++) {
            for (int j = 0; j < m; j++) {
                z[i][j] = in.nextInt();
            }
        }
        //Finding the main matrix 
        int[][] mn = new int[n][m];
        for (int i = 0; i < n; i++) {
            for (int j = 0; j < m; j++) {
                mn[i][j] = -1;
            }
        }
        for (int i = 0; i < n; i++) {
            for (int j = 0; j < m; j++) {
                if (z[i][j] == 0) {
                    for (int x = 0; x < m; x++) {
                        mn[i][x] = 0;
                    }
                    for (int x = 0; x < n; x++) {
                        mn[x][j] = 0;
                    }
                }
            }
        }
        for (int i = 0; i < n; i++) {
            for (int j = 0; j < m; j++) {
                if (mn[i][j] == -1) {
                    mn[i][j] = 1;
                }
            }
        }
        //getting the generated matrix 
        int[][] gen = OR(mn);
        //check if generated matrix equal to the given matrix
        if (isEqual(gen, z)) {
            System.out.println("YES");
            for (int i = 0; i < n; i++) {
                for (int j = 0; j < m; j++) {
                    System.out.print(mn[i][j] + " ");
                }
                System.out.println("");
            }
        } else {
            System.out.println("NO");
        }
    }
}