Problem: Mashmokh's boss, Bimokh, didn't like Mashmokh. So he fired him. Mashmokh decided to go to university and participate in ACM instead of finding a new job. He wants to become a member of Bamokh's team. In order to join he was given some programming tasks and one week to solve them. Mashmokh is not a very experienced programmer. Actually he is not a programmer at all. So he wasn't able to solve them. That's why he asked you to help him with these tasks. One of these tasks is the following.

A sequence of l integers b1, b2, ..., bl (1 ≤ b1 ≤ b2 ≤ ... ≤ bl ≤ n) is called good if each number divides (without a remainder) by the next number in the sequence. More formally <image> for all i (1 ≤ i ≤ l - 1).

Given n and k find the number of good sequences of length k. As the answer can be rather large print it modulo 1000000007 (109 + 7).

Input

The first line of input contains two space-separated integers n, k (1 ≤ n, k ≤ 2000).

Output

Output a single integer — the number of good sequences of length k modulo 1000000007 (109 + 7).

Examples

Input

3 2


Output

5


Input

6 4


Output

39


Input

2 1


Output

2

Note

In the first sample the good sequences are: [1, 1], [2, 2], [3, 3], [1, 2], [1, 3].

Solution (in PYTHON3):

Solution:
import math
from collections import defaultdict
MOD = 10**9 + 7
def printDivisors(n) : 
    
    i = 1
    Factors = []
    while i <= math.sqrt(n): 
          
        if (n % i == 0) : 
            if (n / i == i) : 
                Factors.append(i)
            else : 
                Factors.append(i)
                Factors.append(int(n/i))
        i = i + 1
    Factors.sort(reverse = True)
    return Factors
F = defaultdict(list)
n,k = map(int,input().split())
for i in range(1,n+1):
    F[i] =printDivisors(i)
dp = [1] * (n+1)
dp[0] = 0
for i in range(1,k):
    for j in range(1,n+1):
        for f in range(j+j,n+1,j):
            dp[j] += dp[f]
            dp[j] %= MOD
print(sum(dp)%MOD)