Problem: Given is an integer S. Find a combination of six integers X_1,Y_1,X_2,Y_2,X_3, and Y_3 that satisfies all of the following conditions:

* 0 \leq X_1,Y_1,X_2,Y_2,X_3,Y_3 \leq 10^9
* The area of the triangle in a two-dimensional plane whose vertices are (X_1,Y_1),(X_2,Y_2), and (X_3,Y_3) is S/2.



We can prove that there always exist six integers that satisfy the conditions under the constraints of this problem.

Constraints

* 1 \leq S \leq 10^{18}
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


S


Output

Print six integers X_1,Y_1,X_2,Y_2,X_3, and Y_3 that satisfy the conditions, in this order, with spaces in between. If multiple solutions exist, any of them will be accepted.

Examples

Input

3


Output

1 0 2 2 0 1


Input

100


Output

0 0 10 0 0 10


Input

311114770564041497


Output

314159265 358979323 846264338 327950288 419716939 937510582

Solution (in JAVA):

Solution:
import java.io.IOException;
import java.io.InputStream;
import java.io.PrintWriter;
import java.util.NoSuchElementException;

public class Main {

	

	public static void main(String[] args) {

		FastScanner sc = new FastScanner();
		PrintWriter out=new PrintWriter(System.out);
		long S = sc.nextLong();
		long X1=0;
		long Y1=0;
		long X2=0;
		long Y2=0;
		long X3=0;
		long Y3=0;
		
		if(S<=1000*1000*1000) {
			Y2=S;
			X3=1;
			out.print(X1+" "+Y1+" "+X2+" "+Y2+" "+X3+" "+Y3);
			out.flush();
			return;
		}
		
		
		long N=(long) Math.sqrt(S)+1;
		
		if(S==(N-1)*(N-1)) {
			N=N-1;
		}
		
		if(S-N*N<S-(N-1)*N) {
			long M=N*N-S;
			X2=N;
			Y3=N;
			X3=1;
			Y2=M;
		}else {
			long M=N*(N-1)-S;
			X2=N;
			Y3=N-1;
			X3=1;
			Y2=M;
		}
		out.print(X1+" "+Y1+" "+X2+" "+Y2+" "+X3+" "+Y3);
	
		out.flush();
	}
	
}

class FastScanner {
	private final InputStream in = System.in;
	private final byte[] buffer = new byte[1024];
	private int ptr = 0;
	private int buflen = 0;

	private boolean hasNextByte() {
		if (ptr < buflen) {
			return true;
		} else {
			ptr = 0;
			try {
				buflen = in.read(buffer);
			} catch (IOException e) {
				e.printStackTrace();
			}
			if (buflen <= 0) {
				return false;
			}
		}
		return true;
	}

	private int readByte() {
		if (hasNextByte())
			return buffer[ptr++];
		else
			return -1;
	}

	private static boolean isPrintableChar(int c) {
		return 33 <= c && c <= 126;
	}

	public boolean hasNext() {
		while (hasNextByte() && !isPrintableChar(buffer[ptr]))
			ptr++;
		return hasNextByte();
	}

	public String next() {
		if (!hasNext())
			throw new NoSuchElementException();
		StringBuilder sb = new StringBuilder();
		int b = readByte();
		while (isPrintableChar(b)) {
			sb.appendCodePoint(b);
			b = readByte();
		}
		return sb.toString();
	}

	public long nextLong() {
		if (!hasNext())
			throw new NoSuchElementException();
		long n = 0;
		boolean minus = false;
		int b = readByte();
		if (b == '-') {
			minus = true;
			b = readByte();
		}
		if (b < '0' || '9' < b) {
			throw new NumberFormatException();
		}
		while (true) {
			if ('0' <= b && b <= '9') {
				n *= 10;
				n += b - '0';
			} else if (b == -1 || !isPrintableChar(b)) {
				return minus ? -n : n;
			} else {
				throw new NumberFormatException();
			}
			b = readByte();
		}
	}

	public int nextInt() {
		long nl = nextLong();
		if (nl < Integer.MIN_VALUE || nl > Integer.MAX_VALUE)
			throw new NumberFormatException();
		return (int) nl;
	}

	public double nextDouble() {
		return Double.parseDouble(next());
	}

	public char[][] nextCharsHW(int H, int W) {
		char[][] chars = new char[H][W];
		for (int i = 0; i < H; i++) {
			String str = next();
			for (int j = 0; j < W; j++) {
				chars[i][j] = str.charAt(j);
			}
		}
		return chars;
	}

	public int[][] nextIntsNM(int N, int M) {
		int[][] ints = new int[N][M];
		for (int i = 0; i < N; i++) {
			for (int j = 0; j < M; j++) {
				ints[i][j] = nextInt();
			}
		}
		return ints;
	}
}