Problem: You are given two positive integers n (1 ≤ n ≤ 10^9) and k (1 ≤ k ≤ 100). Represent the number n as the sum of k positive integers of the same parity (have the same remainder when divided by 2).

In other words, find a_1, a_2, …, a_k such that all a_i>0, n = a_1 + a_2 + … + a_k and either all a_i are even or all a_i are odd at the same time.

If such a representation does not exist, then report it.

Input

The first line contains an integer t (1 ≤ t ≤ 1000) — the number of test cases in the input. Next, t test cases are given, one per line.

Each test case is two positive integers n (1 ≤ n ≤ 10^9) and k (1 ≤ k ≤ 100).

Output

For each test case print:

  * YES and the required values a_i, if the answer exists (if there are several answers, print any of them); 
  * NO if the answer does not exist. 



The letters in the words YES and NO can be printed in any case.

Example

Input


8
10 3
100 4
8 7
97 2
8 8
3 10
5 3
1000000000 9


Output


YES
4 2 4
YES
55 5 5 35
NO
NO
YES
1 1 1 1 1 1 1 1
NO
YES
3 1 1
YES
111111110 111111110 111111110 111111110 111111110 111111110 111111110 111111110 111111120

Solution (in PYTHON3):

Solution:
"""
    Author : thekushalghosh
    Team   : CodeDiggers
    
    I prefer Python language over the C++ language :p :D
    
    Visit my website : thekushalghosh.github.io
"""
import sys,math,cmath,time
start_time = time.time()
tt = 0
################# ---- USER DEFINED INPUT FUNCTIONS ---- #################
def inp():
    return(int(input()))
def inlt():
    return(list(map(int,input().split())))
def insr():
    return(input().strip())
def invr():
    return(map(int,input().split()))
##########################################################################
################# ---- THE ACTUAL CODE STARTS BELOW ---- #################
 
def solve():
    n,k = invr()
    if n % 2 == 1 and k % 2 == 0:
        print("NO")
    elif n % 2 == 0 and k % 2 == 0:
        if n < k:
            print("NO")
        else:
            qw = ([1] * (k - 1)) + [n - (k - 1)]
            print("YES")
            print(*qw)
    elif n % 2 == 0 and k % 2 == 1:
        if 2 * k > n:
            print("NO")
        else:
            qw = ([2] * (k - 1)) + [n - (2 * (k - 1))]
            print("YES")
            print(*qw)
    else:
        if n < k:
            print("NO")
        else:
            print("YES")
            qw = ([1] * (k - 1)) + [n - (k - 1)]
            print(*qw)
    
################## ---- THE ACTUAL CODE ENDS ABOVE ---- ##################
##########################################################################
def main():
    if not ONLINE_JUDGE:
        sys.stdin = open("input.txt","r")
        sys.stdout = open("output.txt","w")
    t = 1
    t = inp()
    for tt in range(t):
        solve()
    if not ONLINE_JUDGE:
        print("Time Elapsed :",time.time() - start_time,"seconds")
    sys.stdout.close()
############## ---- USER DEFINED PROGRAMMING FUNCTIONS ---- ##############
def counter(a):
    q = [0] * max(a)
    for i in range(len(a)):
        q[a[i] - 1] = q[a[i] - 1] + 1
    return(q)
 
def string_counter(a):
    q = [0] * 26
    for i in range(len(a)):
        q[ord(a[i]) - 97] = q[ord(a[i]) - 97] + 1
    return(q)
ONLINE_JUDGE = __debug__
if ONLINE_JUDGE:
    input = sys.stdin.readline
main()