Problem: You are given one integer n (n > 1).

Recall that a permutation of length n is an array consisting of n distinct integers from 1 to n in arbitrary order. For example, [2, 3, 1, 5, 4] is a permutation of length 5, but [1, 2, 2] is not a permutation (2 appears twice in the array) and [1, 3, 4] is also not a permutation (n = 3 but there is 4 in the array).

Your task is to find a permutation p of length n that there is no index i (1 ≤ i ≤ n) such that p_i = i (so, for all i from 1 to n the condition p_i ≠ i should be satisfied).

You have to answer t independent test cases.

If there are several answers, you can print any. It can be proven that the answer exists for each n > 1.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then t test cases follow.

The only line of the test case contains one integer n (2 ≤ n ≤ 100) — the length of the permutation you have to find.

Output

For each test case, print n distinct integers p_1, p_2, …, p_n — a permutation that there is no index i (1 ≤ i ≤ n) such that p_i = i (so, for all i from 1 to n the condition p_i ≠ i should be satisfied).

If there are several answers, you can print any. It can be proven that the answer exists for each n > 1.

Example

Input


2
2
5


Output


2 1
2 1 5 3 4

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
#define int long long
using namespace std;

#define mod 1000000007
#define pi 2 * acos(0.0)

void fun()
{
    ios_base::sync_with_stdio(false), cin.tie(NULL), cout.tie(NULL);
#ifndef ONLINE_JUDGE
    freopen("input.txt", "r", stdin);
    freopen("output.txt", "w", stdout);
#endif
}

/* DON'T LIMIT YOUR CHALLENGES, CHALLENGE YOUR LIMITS */
void solve()
{
    int n;
    cin >> n;

    vector<int> v(n);
    iota(v.begin(), v.end(), 1);

    if (n & 1)
        swap(v[0], v[n / 2]);
    for (int i = v.size() - 1; i >= 0; i--)
        cout << v[i] << " ";
    cout << "\n";
}

signed main()
{
    fun();
    int t = 1;
    cin >> t;
    while (t--)
    {
        solve();
    }

    return 0;
}