Problem: Given a permutation p of length n, find its subsequence s_1, s_2, …, s_k of length at least 2 such that:

  * |s_1-s_2|+|s_2-s_3|+…+|s_{k-1}-s_k| is as big as possible over all subsequences of p with length at least 2. 
  * Among all such subsequences, choose the one whose length, k, is as small as possible. 



If multiple subsequences satisfy these conditions, you are allowed to find any of them.

A sequence a is a subsequence of an array b if a can be obtained from b by deleting some (possibly, zero or all) elements.

A permutation of length n is an array of length n in which every element from 1 to n occurs exactly once.

Input

The first line contains an integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. The description of the test cases follows.

The first line of each test case contains an integer n (2 ≤ n ≤ 10^5) — the length of the permutation p.

The second line of each test case contains n integers p_1, p_2, …, p_{n} (1 ≤ p_i ≤ n, p_i are distinct) — the elements of the permutation p.

The sum of n across the test cases doesn't exceed 10^5.

Output

For each test case, the first line should contain the length of the found subsequence, k. The second line should contain s_1, s_2, …, s_k — its elements.

If multiple subsequences satisfy these conditions, you are allowed to find any of them.

Example

Input


2
3
3 2 1
4
1 3 4 2


Output


2
3 1 
3
1 4 2 

Note

In the first test case, there are 4 subsequences of length at least 2:

  * [3,2] which gives us |3-2|=1. 
  * [3,1] which gives us |3-1|=2. 
  * [2,1] which gives us |2-1|=1. 
  * [3,2,1] which gives us |3-2|+|2-1|=2. 



So the answer is either [3,1] or [3,2,1]. Since we want the subsequence to be as short as possible, the answer is [3,1].

Solution (in JAVA):

Solution:
import java.util.*;

import java.io.*;
public class cf645 {

	public static void main(String[] args) throws NumberFormatException, IOException {
	   BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
	   int t=Integer.parseInt(br.readLine().trim());
	while(t-->0) {
	   String str[]=br.readLine().trim().split(" ");
		   int n=Integer.parseInt(str[0]);
		 //  int x=Integer.parseInt(str[1]);
		   str=br.readLine().trim().split(" ");
		  // HashMap<Integer,Integer>map1=new HashMap<>();
		   int a[]=new int[n];
		//   int b[]=new int[n];
		 //  boolean f=false;
		 //  int ind=0;
		   for(int i=0;i<n;i++) {
			   a[i]=Integer.parseInt(str[i]);
			   
		   }
		  ArrayList<Integer>l=new ArrayList<>();
		  l.add(a[0]);
		  int i=0;
		  while(i+1<n) {
			  if(i+1<n && a[i]<a[i+1]) {
				  while(i+1<n && a[i]<a[i+1]) {
					  i++;
				  }
				  l.add(a[i]);
			  }else {
				  while(i+1<n && a[i]>a[i+1]) {
					  i++;
				  }
				  l.add(a[i]);														 
		       }
		  }
		  System.out.println(l.size());
		  StringBuffer sb=new StringBuffer();
		  for(int j:l) {
			  sb.append(j+" ");
		  }
		  System.out.println(sb);
	   }
	}
}