Problem: Let's say string s has period k if s_i = s_{i + k} for all i from 1 to |s| - k (|s| means length of string s) and k is the minimum positive integer with this property.

Some examples of a period: for s="0101" the period is k=2, for s="0000" the period is k=1, for s="010" the period is k=2, for s="0011" the period is k=4.

You are given string t consisting only of 0's and 1's and you need to find such string s that:

  1. String s consists only of 0's and 1's; 
  2. The length of s doesn't exceed 2 ⋅ |t|; 
  3. String t is a subsequence of string s; 
  4. String s has smallest possible period among all strings that meet conditions 1—3. 



Let us recall that t is a subsequence of s if t can be derived from s by deleting zero or more elements (any) without changing the order of the remaining elements. For example, t="011" is a subsequence of s="10101".

Input

The first line contains single integer T (1 ≤ T ≤ 100) — the number of test cases.

Next T lines contain test cases — one per line. Each line contains string t (1 ≤ |t| ≤ 100) consisting only of 0's and 1's.

Output

Print one string for each test case — string s you needed to find. If there are multiple solutions print any one of them.

Example

Input


4
00
01
111
110


Output


00
01
11111
1010

Note

In the first and second test cases, s = t since it's already one of the optimal solutions. Answers have periods equal to 1 and 2, respectively.

In the third test case, there are shorter optimal solutions, but it's okay since we don't need to minimize the string s. String s has period equal to 1.

Solution (in JAVA):

Solution:
import java.util.*;
import java.io.*;

public class Main {
    // For fast input output
    static class FastReader {
        BufferedReader br;
        StringTokenizer st;

        public FastReader() {
            try {
                br = new BufferedReader(new FileReader("input.txt"));
                PrintStream out = new PrintStream(new FileOutputStream("output.txt"));
                System.setOut(out);
            } catch (Exception e) {
                br = new BufferedReader(new InputStreamReader(System.in));
            }
        }

        String next() {
            while (st == null || !st.hasMoreElements()) {
                try {
                    st = new StringTokenizer(br.readLine());
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
            return st.nextToken();
        }

        int nextInt() {
            return Integer.parseInt(next());
        }

        long nextLong() {
            return Long.parseLong(next());
        }

        double nextDouble() {
            return Double.parseDouble(next());
        }

        String nextLine() {
            String str = "";
            try {
                str = br.readLine();
            } catch (IOException e) {
                e.printStackTrace();
            }
            return str;
        }
    }

    // end of fast i/o code
    public static void main(String[] args) {
        FastReader reader = new FastReader();
        int t = reader.nextInt();
        while(t-->0)
        {
            String s = reader.nextLine();
            if(s.length()<3)
            {
                System.out.println(s);
                continue;
            }
            ArrayList<Integer> list = new ArrayList<Integer>();
            int a;
            boolean b = true;
            for(int i=0; i<s.length()-1; i++)
            {
                if(s.charAt(i)!=s.charAt(i+1))
                {
                    b = false;
                    break;
                }
            }
            if(b)
            {
                System.out.println(s);
                continue;
            }
            for(int i = 0; i < s.length(); i++)
            {
                a = Character.getNumericValue(s.charAt(i));
                list.add(a);
            }
            int val;
            if(list.get(0)==0)
                val = 1;
            else    
                val = 0;
            //System.out.println("till here");
            for(int i=1; i<list.size(); i++)
            {
                if(list.get(i)!=val)
                    list.add(i, val);
                if(val==0)
                    val = 1;
                else
                    val = 0;
            }
            //System.out.println("till here");
            for(int i: list)
                System.out.print(i);
            System.out.println();
        }
    }
}