Problem: A positive integer x is called a power of two if it can be represented as x = 2^y, where y is a non-negative integer. So, the powers of two are 1, 2, 4, 8, 16, ....

You are given two positive integers n and k. Your task is to represent n as the sum of exactly k powers of two.

Input

The only line of the input contains two integers n and k (1 ≤ n ≤ 10^9, 1 ≤ k ≤ 2 ⋅ 10^5).

Output

If it is impossible to represent n as the sum of k powers of two, print NO.

Otherwise, print YES, and then print k positive integers b_1, b_2, ..., b_k such that each of b_i is a power of two, and ∑ _{i = 1}^{k} b_i = n. If there are multiple answers, you may print any of them.

Examples

Input


9 4


Output


YES
1 2 2 4 


Input


8 1


Output


YES
8 


Input


5 1


Output


NO


Input


3 7


Output


NO

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
priority_queue<int> pq;
int main() {
  int n, k;
  cin >> n >> k;
  for (long long int i = 0; i < 31; i++) {
    if (n & (1LL << i)) pq.push(i);
  }
  int j = k - pq.size();
  if (j < 0) {
    cout << "NO";
    return 0;
  }
  int h;
  int flag = 0;
  while (j--) {
    h = pq.top();
    if (h == 0) {
      flag = 1;
      break;
    }
    pq.pop();
    pq.push(h - 1);
    pq.push(h - 1);
  }
  if (flag) {
    cout << "NO";
    return 0;
  }
  cout << "YES" << endl;
  while (pq.size() >= 1) {
    int X = pq.top();
    pq.pop();
    cout << (1 << X) << " ";
  }
  return 0;
}