Problem: Mashmokh's boss, Bimokh, didn't like Mashmokh. So he fired him. Mashmokh decided to go to university and participate in ACM instead of finding a new job. He wants to become a member of Bamokh's team. In order to join he was given some programming tasks and one week to solve them. Mashmokh is not a very experienced programmer. Actually he is not a programmer at all. So he wasn't able to solve them. That's why he asked you to help him with these tasks. One of these tasks is the following.

A sequence of l integers b1, b2, ..., bl (1 ≤ b1 ≤ b2 ≤ ... ≤ bl ≤ n) is called good if each number divides (without a remainder) by the next number in the sequence. More formally <image> for all i (1 ≤ i ≤ l - 1).

Given n and k find the number of good sequences of length k. As the answer can be rather large print it modulo 1000000007 (109 + 7).

Input

The first line of input contains two space-separated integers n, k (1 ≤ n, k ≤ 2000).

Output

Output a single integer — the number of good sequences of length k modulo 1000000007 (109 + 7).

Examples

Input

3 2


Output

5


Input

6 4


Output

39


Input

2 1


Output

2

Note

In the first sample the good sequences are: [1, 1], [2, 2], [3, 3], [1, 2], [1, 3].

Solution (in PYTHON3):

Solution:
n, k = map(int, input().split())

if k == 1:
    print(n)
else:
    counts = [0]*n
    m = 1e9 + 7
    for i in range(1, n+1):
        t = 1
        while (t+1)*i <= n:
            t += 1
        counts[i-1] = t
    for i in range(k-2):
        temp = [0]*n
        for i in range(len(temp)):
            t = 0
            for j in range(1, 2001):
                if (i+1)*j <= n:
                    t += counts[(i+1)*j-1]
                else:
                    break
            temp[i] = t%m
        counts = temp
    
    print(int(sum(counts)%m))