Problem: Petya learned a new programming language CALPAS. A program in this language always takes one non-negative integer and returns one non-negative integer as well.

In the language, there are only three commands: apply a bitwise operation AND, OR or XOR with a given constant to the current integer. A program can contain an arbitrary sequence of these operations with arbitrary constants from 0 to 1023. When the program is run, all operations are applied (in the given order) to the argument and in the end the result integer is returned.

Petya wrote a program in this language, but it turned out to be too long. Write a program in CALPAS that does the same thing as the Petya's program, and consists of no more than 5 lines. Your program should return the same integer as Petya's program for all arguments from 0 to 1023.

Input

The first line contains an integer n (1 ≤ n ≤ 5·105) — the number of lines.

Next n lines contain commands. A command consists of a character that represents the operation ("&", "|" or "^" for AND, OR or XOR respectively), and the constant xi 0 ≤ xi ≤ 1023.

Output

Output an integer k (0 ≤ k ≤ 5) — the length of your program.

Next k lines must contain commands in the same format as in the input.

Examples

Input

3
| 3
^ 2
| 1


Output

2
| 3
^ 2


Input

3
&amp; 1
&amp; 3
&amp; 5


Output

1
&amp; 1


Input

3
^ 1
^ 2
^ 3


Output

0

Note

You can read about bitwise operations in <https://en.wikipedia.org/wiki/Bitwise_operation>.

Second sample:

Let x be an input of the Petya's program. It's output is ((x&1)&3)&5 = x&(1&3&5) = x&1. So these two programs always give the same outputs.

Solution (in PYTHON):

Solution:
def app(out1, i, v2, c):
    if c == '|':
        out1[i] |= v2
    elif c == '&':
        out1[i] &= v2
    else:
        out1[i] ^= v2


n = input()
out1 = [0] * 10
out2 = [1] * 10
f = 0
for a0 in xrange(1, n + 1):
    c, v = raw_input().split()
    v = int(v)
    for i in xrange(10):
        p = 1 << i
        app(out1, i, p & v != 0, c)
        app(out2, i, p & v != 0, c)
#print out1, out2
xorp = 0
orp = 0
for i in xrange(10):
    if out1[i] == 1 and out2[i] == 0:
        xorp += 1 << i
    elif out1[i] == 1 and out2[i] == 1:
        orp += 1 << i
    elif out1[i] == 0 and out2[i] == 0:
        xorp += 1 << i
        orp += 1 << i
ans = []
if orp != 0:
    ans.append(('|', orp))
if xorp != 0:
    ans.append(('^', xorp))

print len(ans)
for c in ans:
    print c[0], c[1]