Problem: You are given n arrays a_1, a_2, ..., a_n; each array consists of exactly m integers. We denote the y-th element of the x-th array as a_{x, y}.

You have to choose two arrays a_i and a_j (1 ≤ i, j ≤ n, it is possible that i = j). After that, you will obtain a new array b consisting of m integers, such that for every k ∈ [1, m] b_k = max(a_{i, k}, a_{j, k}).

Your goal is to choose i and j so that the value of min _{k = 1}^{m} b_k is maximum possible.

Input

The first line contains two integers n and m (1 ≤ n ≤ 3 ⋅ 10^5, 1 ≤ m ≤ 8) — the number of arrays and the number of elements in each array, respectively.

Then n lines follow, the x-th line contains the array a_x represented by m integers a_{x, 1}, a_{x, 2}, ..., a_{x, m} (0 ≤ a_{x, y} ≤ 10^9).

Output

Print two integers i and j (1 ≤ i, j ≤ n, it is possible that i = j) — the indices of the two arrays you have to choose so that the value of min _{k = 1}^{m} b_k is maximum possible. If there are multiple answers, print any of them.

Example

Input


6 5
5 0 3 1 2
1 8 9 1 3
1 2 3 4 5
9 1 0 3 7
2 3 0 6 3
6 4 1 7 0


Output


1 5

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int n, m;
vector<vector<int> > a(3e5, vector<int>(8));
int in1, in2;
bool check(int x) {
  map<int, int> s;
  for (int i = 0; i < n; i++) {
    int mask = 0;
    for (int j = 0; j < m; j++) mask |= ((a[i][j] >= x) << j);
    s[mask] = i;
  }
  for (auto i : s) {
    for (auto j : s)
      if ((i.first | j.first) == (1 << m) - 1) {
        in1 = i.second, in2 = j.second;
        return true;
      }
  }
  return false;
}
int main(int argc, char* argv[]) {
  ios_base::sync_with_stdio(false);
  cin.tie(NULL);
  cout.tie(NULL);
  cin >> n >> m;
  for (int i = 0; i < n; i++)
    for (int j = 0; j < m; j++) cin >> a[i][j];
  int low = 0, high = (int)10e9;
  while (low <= high) {
    int mid = (low + high) / 2;
    if (check(mid)) {
      if (!check(mid + 1)) break;
      low = mid + 1;
    } else
      high = mid - 1;
  }
  cout << in1 + 1 << " " << in2 + 1 << "\n";
  return 0;
}