Problem: You are given a tree consisting of n nodes. You want to write some labels on the tree's edges such that the following conditions hold:

  * Every label is an integer between 0 and n-2 inclusive. 
  * All the written labels are distinct. 
  * The largest value among MEX(u,v) over all pairs of nodes (u,v) is as small as possible. 



Here, MEX(u,v) denotes the smallest non-negative integer that isn't written on any edge on the unique simple path from node u to node v.

Input

The first line contains the integer n (2 ≤ n ≤ 10^5) — the number of nodes in the tree.

Each of the next n-1 lines contains two space-separated integers u and v (1 ≤ u,v ≤ n) that mean there's an edge between nodes u and v. It's guaranteed that the given graph is a tree.

Output

Output n-1 integers. The i^{th} of them will be the number written on the i^{th} edge (in the input order).

Examples

Input


3
1 2
1 3


Output


0
1


Input


6
1 2
1 3
2 4
2 5
5 6


Output


0
3
2
4
1

Note

The tree from the second sample:

<image>

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int T;
int n;
vector<int> edg[100010];
int main() {
  int from, to;
  scanf("%d", &n);
  int ans = -1;
  for (int i = 1; i < n; i++) {
    scanf("%d %d", &from, &to);
    if (ans == -1) {
      edg[from].push_back(i);
      edg[to].push_back(i);
      if (edg[from].size() >= 3) ans = from;
      if (edg[to].size() >= 3) ans = to;
    }
  }
  int cnt1 = 0, cnt2 = (ans == -1 ? 0 : 3);
  for (int i = 1; i <= n - 1; i++)
    if (ans != -1 && (i == edg[ans][0] || i == edg[ans][1] || i == edg[ans][2]))
      printf("%d\n", cnt1++);
    else
      printf("%d\n", cnt2++);
  return 0;
}