Problem: Mashmokh's boss, Bimokh, didn't like Mashmokh. So he fired him. Mashmokh decided to go to university and participate in ACM instead of finding a new job. He wants to become a member of Bamokh's team. In order to join he was given some programming tasks and one week to solve them. Mashmokh is not a very experienced programmer. Actually he is not a programmer at all. So he wasn't able to solve them. That's why he asked you to help him with these tasks. One of these tasks is the following.

A sequence of l integers b1, b2, ..., bl (1 ≤ b1 ≤ b2 ≤ ... ≤ bl ≤ n) is called good if each number divides (without a remainder) by the next number in the sequence. More formally <image> for all i (1 ≤ i ≤ l - 1).

Given n and k find the number of good sequences of length k. As the answer can be rather large print it modulo 1000000007 (109 + 7).

Input

The first line of input contains two space-separated integers n, k (1 ≤ n, k ≤ 2000).

Output

Output a single integer — the number of good sequences of length k modulo 1000000007 (109 + 7).

Examples

Input

3 2


Output

5


Input

6 4


Output

39


Input

2 1


Output

2

Note

In the first sample the good sequences are: [1, 1], [2, 2], [3, 3], [1, 2], [1, 3].

Solution (in JAVA):

Solution:

import java.util.*;
import java.io.*;
public class B {
    public static long time = 0;
    public static void main(String[] args) throws Exception {
        time = System.currentTimeMillis();
        
        IN = System.in;
        OUT = System.out;
        in = new BufferedReader(new InputStreamReader(IN));
        out = new PrintWriter(OUT, FLUSH);
        solveOne();
        out.flush();
    }
    public static final long MOD = 1_000_000_007l;
    public static void solveOne() throws Exception {
        int n1 = ni();
        int k1 = ni();
        long[] dp1 = new long[n1 + 1];
        for (int i = 0; i < n1; i++){
            dp1[i + 1] = 1;
        }
        long[] dp2 = new long[n1 + 1];
        for (int i = 2;i <= k1; i++){
            for (int j = 1; j <= n1; j++){
                int cur = j;
                for (;cur <= n1;){
                    dp2[cur] += dp1[j];
                    dp2[cur] %= MOD;
                    cur += j;
                }
            }
            dp1 = dp2;
            dp2 = new long[n1 + 1];
        }
        long fin = 0;
        for (long e: dp1){
            fin += e;
            fin %= MOD;
        }
        pn(fin);;
    }
    
    public static void solveTwo() throws Exception {
        
    }
    
    public static void solveThree() throws Exception {
        
    }
    
    public static BufferedReader in;
    public static StringTokenizer st;
    public static InputStream IN;
    public static OutputStream OUT;
    public static String nx() throws Exception {
        for (;st == null || !st.hasMoreTokens();){
            String k1 = in.readLine();
            if (k1 == null) return null;
            st = new StringTokenizer(k1);
        }
        return st.nextToken();
    }
    public static int ni () throws Exception {
        return Integer.parseInt(nx());
    }
    public static long nl() throws Exception{
        return Long.parseLong(nx());
    }
    public static double nd() throws Exception{
        return Double.parseDouble(nx());
    }
    public static void px(Object ... l1){
        System.out.println(Arrays.deepToString(l1));
    }
    public static boolean FLUSH = false;
    public static PrintWriter out;
    public static void p(Object ... l1){
        for (int i = 0; i < l1.length; i++){
            if (i != 0) out.print(' ');
            out.print(l1[i].toString());
        }
    }
    public static void pn(Object ... l1){
        for (int i = 0; i < l1.length; i++){
            if (i != 0) out.print(' ');
            out.print(l1[i].toString());
        }
        out.println();
    }
    
    public static void pn(Collection l1){
        boolean first = true;
        for (Object e: l1){
            if (first) first = false;
            else out.print(' ');
            out.print(e.toString());
        }
        out.println();
    }

}