Problem: You are given one integer n (n > 1).

Recall that a permutation of length n is an array consisting of n distinct integers from 1 to n in arbitrary order. For example, [2, 3, 1, 5, 4] is a permutation of length 5, but [1, 2, 2] is not a permutation (2 appears twice in the array) and [1, 3, 4] is also not a permutation (n = 3 but there is 4 in the array).

Your task is to find a permutation p of length n that there is no index i (1 ≤ i ≤ n) such that p_i = i (so, for all i from 1 to n the condition p_i ≠ i should be satisfied).

You have to answer t independent test cases.

If there are several answers, you can print any. It can be proven that the answer exists for each n > 1.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then t test cases follow.

The only line of the test case contains one integer n (2 ≤ n ≤ 100) — the length of the permutation you have to find.

Output

For each test case, print n distinct integers p_1, p_2, …, p_n — a permutation that there is no index i (1 ≤ i ≤ n) such that p_i = i (so, for all i from 1 to n the condition p_i ≠ i should be satisfied).

If there are several answers, you can print any. It can be proven that the answer exists for each n > 1.

Example

Input


2
2
5


Output


2 1
2 1 5 3 4

Solution (in CPP):

Solution:
#include<iostream>
#include<vector>

using namespace std;

int main()
{
    int t,n;
    cin>>t;
    while(t--)
    {
        cin>>n;
        vector<int> output(n,0);
        if(n%2==0)
        {
            for(int i=0;i<n;i++)
                if(i%2==0)
                    output[i] = i+2;
                else
                {
                    output[i] = i;
                }
        }
        else
        {
            for(int i=0;i<n/2;i++)
            {
                output[i] = n - i;
            }
            output[n/2 - 1] =  n/2 + 2;
            output[n/2] = n/2;
            output[n/2 + 1] = n/2 + 1;
            for(int i=n/2+2;i<n;i++)
                output[i] = n-i;
        }
        for(auto x:output)
            cout<<x<<" ";
        cout<<endl;
    }
    return 0;
}