Problem: Toad Rash has a binary string s. A binary string consists only of zeros and ones.

Let n be the length of s.

Rash needs to find the number of such pairs of integers l, r that 1 ≤ l ≤ r ≤ n and there is at least one pair of integers x, k such that 1 ≤ x, k ≤ n, l ≤ x < x + 2k ≤ r, and s_x = s_{x+k} = s_{x+2k}.

Find this number of pairs for Rash.

Input

The first line contains the string s (1 ≤ |s| ≤ 300 000), consisting of zeros and ones.

Output

Output one integer: the number of such pairs of integers l, r that 1 ≤ l ≤ r ≤ n and there is at least one pair of integers x, k such that 1 ≤ x, k ≤ n, l ≤ x < x + 2k ≤ r, and s_x = s_{x+k} = s_{x+2k}.

Examples

Input


010101


Output


3


Input


11001100


Output


0

Note

In the first example, there are three l, r pairs we need to count: 1, 6; 2, 6; and 1, 5.

In the second example, there are no values x, k for the initial string, so the answer is 0.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
const int MAX_N = 300005;
int n;
char s[MAX_N];
bool f(int l, int r) {
  for (int x = l; x <= r; x++)
    for (int k = 1; x + 2 * k <= r; k++)
      if (s[x] == s[x + k] && s[x] == s[x + 2 * k]) return true;
  return false;
}
int main() {
  scanf("%s", s + 1);
  n = strlen(s + 1);
  long long ans = 0;
  for (int l = 1; l <= n; l++) {
    ans += max(0, n - (l + 8) + 1);
    for (int r = l + 2; r <= n && r - l + 1 < 9; r++)
      if (f(l, r)) ans++;
  }
  printf("%lld\n", ans);
  return 0;
}