Problem: Mashmokh's boss, Bimokh, didn't like Mashmokh. So he fired him. Mashmokh decided to go to university and participate in ACM instead of finding a new job. He wants to become a member of Bamokh's team. In order to join he was given some programming tasks and one week to solve them. Mashmokh is not a very experienced programmer. Actually he is not a programmer at all. So he wasn't able to solve them. That's why he asked you to help him with these tasks. One of these tasks is the following.

A sequence of l integers b1, b2, ..., bl (1 ≤ b1 ≤ b2 ≤ ... ≤ bl ≤ n) is called good if each number divides (without a remainder) by the next number in the sequence. More formally <image> for all i (1 ≤ i ≤ l - 1).

Given n and k find the number of good sequences of length k. As the answer can be rather large print it modulo 1000000007 (109 + 7).

Input

The first line of input contains two space-separated integers n, k (1 ≤ n, k ≤ 2000).

Output

Output a single integer — the number of good sequences of length k modulo 1000000007 (109 + 7).

Examples

Input

3 2


Output

5


Input

6 4


Output

39


Input

2 1


Output

2

Note

In the first sample the good sequences are: [1, 1], [2, 2], [3, 3], [1, 2], [1, 3].

Solution (in PYTHON3):

Solution:
def C(n , k) :
    w = 1
    for i in range(n - k + 1 , n + 1) :
        w *= i
    for i in range(1 , k + 1) :
        w //= i
    return w
n , k = input().split()
n = int(n)
k = int(k)
ans = 0
for i in range(1 , n + 1) :
    pp = 1
    i1 = i
    for j in range(2 , i + 1) :
        sch = 0
        while(i1 % j == 0) :
            sch += 1
            i1 //= j
        if(sch) :
            pp *= C(sch + k - 1 , sch)
    ans += pp
    ans %= 1000000007
print(ans)