Problem: You are given two positive integers n (1 ≤ n ≤ 10^9) and k (1 ≤ k ≤ 100). Represent the number n as the sum of k positive integers of the same parity (have the same remainder when divided by 2).

In other words, find a_1, a_2, …, a_k such that all a_i>0, n = a_1 + a_2 + … + a_k and either all a_i are even or all a_i are odd at the same time.

If such a representation does not exist, then report it.

Input

The first line contains an integer t (1 ≤ t ≤ 1000) — the number of test cases in the input. Next, t test cases are given, one per line.

Each test case is two positive integers n (1 ≤ n ≤ 10^9) and k (1 ≤ k ≤ 100).

Output

For each test case print:

  * YES and the required values a_i, if the answer exists (if there are several answers, print any of them); 
  * NO if the answer does not exist. 



The letters in the words YES and NO can be printed in any case.

Example

Input


8
10 3
100 4
8 7
97 2
8 8
3 10
5 3
1000000000 9


Output


YES
4 2 4
YES
55 5 5 35
NO
NO
YES
1 1 1 1 1 1 1 1
NO
YES
3 1 1
YES
111111110 111111110 111111110 111111110 111111110 111111110 111111110 111111110 111111120

Solution (in PYTHON3):

Solution:
n = int(input())
nums = []
for i in range(n):
    in_num = input().split()
    nums.append([int(in_num[0]),int(in_num[1])])
for num in nums:
    test1 = num[0] - (num[1]-1)
    test2 = num[0] - 2*(num[1]-1)
    if test1 % 2 == 1 and test1 > 0:
        print("YES")
        print(test1, end=" ")
        while num[0] > test1:
            print(1,end=" ")
            num[0] -= 1
        print()
    elif test2 % 2 == 0 and test2 > 0:
        print("YES")
        print(test2, end=" ")
        while num[0] > test2:
            print(2,end=" ")
            num[0] -= 2
        print()
    else:
        print("NO")