Problem: Mashmokh's boss, Bimokh, didn't like Mashmokh. So he fired him. Mashmokh decided to go to university and participate in ACM instead of finding a new job. He wants to become a member of Bamokh's team. In order to join he was given some programming tasks and one week to solve them. Mashmokh is not a very experienced programmer. Actually he is not a programmer at all. So he wasn't able to solve them. That's why he asked you to help him with these tasks. One of these tasks is the following.

A sequence of l integers b1, b2, ..., bl (1 ≤ b1 ≤ b2 ≤ ... ≤ bl ≤ n) is called good if each number divides (without a remainder) by the next number in the sequence. More formally <image> for all i (1 ≤ i ≤ l - 1).

Given n and k find the number of good sequences of length k. As the answer can be rather large print it modulo 1000000007 (109 + 7).

Input

The first line of input contains two space-separated integers n, k (1 ≤ n, k ≤ 2000).

Output

Output a single integer — the number of good sequences of length k modulo 1000000007 (109 + 7).

Examples

Input

3 2


Output

5


Input

6 4


Output

39


Input

2 1


Output

2

Note

In the first sample the good sequences are: [1, 1], [2, 2], [3, 3], [1, 2], [1, 3].

Solution (in JAVA):

Solution:

import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.BufferedReader;
import java.io.OutputStream;
import java.io.PrintWriter;
import java.io.IOException;
import java.util.StringTokenizer;

public class B414 {

    public static BufferedReader in;
    public static PrintWriter out;
    public static StringTokenizer tokenizer;

    public static void main(String[] args) {
        InputStream inputStream = System.in;
        OutputStream outputStream = System.out;
        in = new BufferedReader(new InputStreamReader(inputStream), 32768);
        out = new PrintWriter(outputStream);
        solve();
        out.close();
    }

    public static final int MOD = 1000000007;

    public static void solve() {
        int n = nextInt();
        int k = nextInt();
        long[][] dp = new long[k + 1][n + 1];
        for (int i = 1; i <= k; i++) {
            for (int j = 1; j <= n; j++) {
                if (i == 1) {
                    dp[i][j] = 1;
                    continue;
                }
                dp[i][j] = 0;
                int x = 1;
                while (x * x <= j) {
                    if (j % x == 0) {
                        dp[i][j] += dp[i - 1][x];
                        if (j / x != x) {
                            dp[i][j] += dp[i - 1][j / x];
                        }
                        dp[i][j] %= MOD;
                    }
                    x++;
                }
            }
        }
        long res = 0L;
        for (int i = 1; i <= n; i++) {
            res = (res + dp[k][i]) % MOD;
        }
        out.println(res);
    }

    public static String next() {
        while (tokenizer == null || !tokenizer.hasMoreTokens()) {
            try {
                tokenizer = new StringTokenizer(in.readLine());
            } catch (IOException e) {
                throw new RuntimeException(e);
            }
        }
        return tokenizer.nextToken();
    }

    public static int nextInt() {
        return Integer.parseInt(next());
    }

    public static long nextLong() {
        return Long.parseLong(next());
    }

    public static double nextDouble() {
        return Double.parseDouble(next());
    }
}