Problem: Alice has a computer that operates on w-bit integers. The computer has n registers for values. The current content of the registers is given as an array a_1, a_2, …, a_n. 

The computer uses so-called "number gates" to manipulate this data. Each "number gate" takes two registers as inputs and calculates a function of the two values stored in those registers. Note that you can use the same register as both inputs.

Each "number gate" is assembled from bit gates. There are six types of bit gates: AND, OR, XOR, NOT AND, NOT OR, and NOT XOR, denoted "A", "O", "X", "a", "o", "x", respectively. Each bit gate takes two bits as input. Its output given the input bits b_1, b_2 is given below:

\begin{matrix} b_1 & b_2 & A & O & X & a & o & x \\\ 0 & 0 & 0 & 0 & 0 & 1 & 1 & 1 \\\ 0 & 1 & 0 & 1 & 1 & 1 & 0 & 0 \\\ 1 & 0 & 0 & 1 & 1 & 1 & 0 & 0 \\\ 1 & 1 & 1 & 1 & 0 & 0 & 0 & 1 \\\ \end{matrix} 

To build a "number gate", one takes w bit gates and assembles them into an array. A "number gate" takes two w-bit integers x_1 and x_2 as input. The "number gate" splits the integers into w bits and feeds the i-th bit of each input to the i-th bit gate. After that, it assembles the resulting bits again to form an output word. 

For instance, for 4-bit computer we might have a "number gate" "AXoA" (AND, XOR, NOT OR, AND). For two inputs, 13 = 1101_2 and 10 = 1010_2, this returns 12 = 1100_2, as 1 and 1 is 1, 1 xor 0 is 1, not (0 or 1) is 0, and finally 1 and 0 is 0. 

You are given a description of m "number gates". For each gate, your goal is to report the number of register pairs for which the "number gate" outputs the number 0. In other words, find the number of ordered pairs (i,j) where 1 ≤ i,j ≤ n, such that w_k(a_i, a_j) = 0, where w_k is the function computed by the k-th "number gate".

Input

The first line contains three integers: w, n, and m~(1 ≤ w ≤ 12, 1 ≤ n ≤ 3⋅ 10^4, 1 ≤ m ≤ 5⋅ 10^4) — the word size, the number of variables, and the number of gates.

The second line contains n integers a_1, a_2, …, a_n (0 ≤ a_i < 2^w) — the value of variables stored in the registers.

Each of the next m lines contains a string g_j~(|g_j| = w) with a description of a single gate. Each character of g_j is one of "A", "O", "X", "a", "o", "x".

Output

Print m lines. The i-th line should contain the number of ordered pairs of variables for which the i-th gate returns zero.

Examples

Input

4 3 1
13 10 6
AXoA


Output

3


Input

1 7 6
0 1 1 0 1 0 0
A
O
X
a
o
x


Output

40
16
25
9
33
24


Input

6 2 4
47 12
AOXaox
AAaaAA
xxxxxx
XXXXXX


Output

2
3
0
2


Input

2 2 2
2 0
xO
Ox


Output

2
0

Note

In the first test case, the inputs in binary are 1101, 1010, 0110. The pairs that return 0 are (13, 6), (6, 13), and (6, 6). As it was already mentioned in the problem statement, 13 ⊕ 10 = 10 ⊕ 13 = 12. The other pairs are 13 ⊕ 13 = 11, 10 ⊕ 10 = 8 and 10 ⊕ 6 = 6 ⊕ 10 = 4. 

Solution (in JAVA):

Solution:
import java.io.*;
import java.math.BigDecimal;
import java.math.BigInteger;
import java.math.RoundingMode;
import java.util.*;
import java.util.Map.Entry;

public class Main
{
	private InputStream stream;
	private byte[] buf = new byte[1024];
	private int curChar;
	private int numChars;
	private SpaceCharFilter filter;
	private PrintWriter pw;
	private long mod = 1000000000 + 7;

	private StringBuilder ans_sb;

	private void soln()
	{
		int w = nextInt();
		int n = nextInt();
		int m = nextInt();
		int p1 = (int) Math.pow(3, w);
		int p2 = (1 << w);
		long[] sum = new long[p1];
		long[] fre = new long[p2];
		int[] conv = new int[p2];
		for (int i = 0; i < n; i++) {
			int x = nextInt();
			// debug(Integer.toBinaryString(x));
			fre[x]++;
		}
		for (int i = 0; i < p2; i++) {
			int i1 = i;
			int ns = 0;
			int pow = 1;
			while (i1 != 0) {
				ns = ns + pow * (i1 & 1);
				i1 >>= 1;
				pow *= 3;
			}
			conv[i] = ns;
			// debug(Integer.toBinaryString(i) + " "+Integer.toString(ns, 3));
		}
		int[] pows = new int[w];
		pows[0] = 1;
		for (int i = 1; i < w; i++)
			pows[i] = pows[i - 1] * 3;
		for (int i = 0; i < p2; i++) {
			for (int j = 0; j < p2; j++) {
				sum[conv[i] + conv[j]] += fre[i] * fre[j];
			}
			// sum[2*conv[i]] = (fre[i] * (fre[i] - 1));
		}
		// for(int i=0;i<p1; i++) {
		// if(sum[i] > 0)
		// debug(Integer.toString(i, 3) +" "+sum[i]);
		// }
		while (m-- > 0) {
			String gate = new StringBuilder(nextLine()).reverse().toString();
			boolean[][] poss = find(gate, w);
			// debug(poss);
			pw.println(ans(poss, sum, 0, w, 0, pows));
		}
	}

	private long ans(boolean[][] pos, long[] sum, int i, int w, int cs, int[] pows)
	{
		long ans = 0;
		if (i == w) {
			// debug(Integer.toString(cs, 3));
			return sum[cs];
		}
		if (pos[i][0])
			ans += ans(pos, sum, i + 1, w, cs, pows);
		if (pos[i][1])
			ans += ans(pos, sum, i + 1, w, cs + pows[i], pows);
		if (pos[i][2])
			ans += ans(pos, sum, i + 1, w, cs + 2 * pows[i], pows);
		return ans;
	}

	private boolean[][] find(String gate, int w)
	{
		boolean[][] arr = new boolean[w][3];
		for (int i = 0; i < w; i++) {
			char c = gate.charAt(i);
			if (c == 'A') {
				arr[i][0] = true;
				arr[i][1] = true;
			} else if (c == 'O') {
				arr[i][0] = true;
			} else if (c == 'X') {
				arr[i][0] = true;
				arr[i][2] = true;
			} else if (c == 'a') {
				arr[i][2] = true;
			} else if (c == 'o') {
				arr[i][1] = true;
				arr[i][2] = true;
			} else {
				arr[i][1] = true;
			}
		}
		return arr;
	}

	private String solveEqn(long a, long b)
	{
		long x = 0, y = 1, lastx = 1, lasty = 0, temp;
		while (b != 0) {
			long q = a / b;
			long r = a % b;
			a = b;
			b = r;
			temp = x;
			x = lastx - q * x;
			lastx = temp;
			temp = y;
			y = lasty - q * y;
			lasty = temp;
		}
		return lastx + " " + lasty;
	}

	private static void debug(Object... o)
	{
		System.out.println(Arrays.deepToString(o));
	}

	private long pow(long a, long b, long c)
	{
		if (b == 0)
			return 1;
		long p = pow(a, b / 2, c);
		p = (p * p) % c;
		return (b % 2 == 0) ? p : (a * p) % c;
	}

	private long gcd(long n, long l)
	{
		if (l == 0)
			return n;
		return gcd(l, n % l);
	}

	public static void main(String[] args) throws Exception
	{
		new Thread(null, new Runnable()
		{
			@Override
			public void run()
			{
				new Main().solve();
			}
		}, "1", 1 << 26).start();
		// new Main().solve();
	}

	public StringBuilder solve()
	{
		InputReader(System.in);
		/*
		 * try { InputReader(new FileInputStream("C:\\Users\\hardik\\Desktop\\in.txt"));
		 * } catch(FileNotFoundException e) {}
		 */
		pw = new PrintWriter(System.out);
		// ans_sb = new StringBuilder();
		soln();

		pw.close();
		// System.out.println(ans_sb);
		return ans_sb;
	}

	public void InputReader(InputStream stream1)
	{
		stream = stream1;
	}

	private boolean isWhitespace(int c)
	{
		return c == ' ' || c == '\n' || c == '\r' || c == '\t' || c == -1;
	}

	private boolean isEndOfLine(int c)
	{
		return c == '\n' || c == '\r' || c == -1;
	}

	private int read()
	{
		if (numChars == -1)
			throw new InputMismatchException();
		if (curChar >= numChars) {
			curChar = 0;
			try {
				numChars = stream.read(buf);
			} catch (IOException e) {
				throw new InputMismatchException();
			}
			if (numChars <= 0)
				return -1;
		}
		return buf[curChar++];
	}

	private int nextInt()
	{
		int c = read();
		while (isSpaceChar(c))
			c = read();
		int sgn = 1;
		if (c == '-') {
			sgn = -1;
			c = read();
		}
		int res = 0;
		do {
			if (c < '0' || c > '9')
				throw new InputMismatchException();
			res *= 10;
			res += c - '0';
			c = read();
		} while (!isSpaceChar(c));
		return res * sgn;
	}

	private long nextLong()
	{
		int c = read();
		while (isSpaceChar(c))
			c = read();
		int sgn = 1;
		if (c == '-') {
			sgn = -1;
			c = read();
		}
		long res = 0;
		do {
			if (c < '0' || c > '9')
				throw new InputMismatchException();
			res *= 10;
			res += c - '0';
			c = read();
		} while (!isSpaceChar(c));
		return res * sgn;
	}

	private String nextToken()
	{
		int c = read();
		while (isSpaceChar(c))
			c = read();
		StringBuilder res = new StringBuilder();
		do {
			res.appendCodePoint(c);
			c = read();
		} while (!isSpaceChar(c));
		return res.toString();
	}

	private String nextLine()
	{
		int c = read();
		while (isSpaceChar(c))
			c = read();
		StringBuilder res = new StringBuilder();
		do {
			res.appendCodePoint(c);
			c = read();
		} while (!isEndOfLine(c));
		return res.toString();
	}

	private int[] nextIntArray(int n)
	{
		int[] arr = new int[n];
		for (int i = 0; i < n; i++) {
			arr[i] = nextInt();
		}
		return arr;
	}

	private long[] nextLongArray(int n)
	{
		long[] arr = new long[n];
		for (int i = 0; i < n; i++) {
			arr[i] = nextLong();
		}
		return arr;
	}

	private void pArray(int[] arr)
	{
		for (int i = 0; i < arr.length; i++) {
			System.out.print(arr[i] + " ");
		}
		System.out.println();
		return;
	}

	private void pArray(long[] arr)
	{
		for (int i = 0; i < arr.length; i++) {
			System.out.print(arr[i] + " ");
		}
		System.out.println();
		return;
	}

	private boolean isSpaceChar(int c)
	{
		if (filter != null)
			return filter.isSpaceChar(c);
		return isWhitespace(c);
	}

	private char nextChar()
	{
		int c = read();
		while (isSpaceChar(c))
			c = read();
		char c1 = (char) c;
		while (!isSpaceChar(c))
			c = read();
		return c1;
	}

	private interface SpaceCharFilter
	{
		public boolean isSpaceChar(int ch);
	}
}