Problem: Let's define logical OR as an operation on two logical values (i. e. values that belong to the set {0, 1}) that is equal to 1 if either or both of the logical values is set to 1, otherwise it is 0. We can define logical OR of three or more logical values in the same manner:

<image> where <image> is equal to 1 if some ai = 1, otherwise it is equal to 0.

Nam has a matrix A consisting of m rows and n columns. The rows are numbered from 1 to m, columns are numbered from 1 to n. Element at row i (1 ≤ i ≤ m) and column j (1 ≤ j ≤ n) is denoted as Aij. All elements of A are either 0 or 1. From matrix A, Nam creates another matrix B of the same size using formula:

<image>.

(Bij is OR of all elements in row i and column j of matrix A)

Nam gives you matrix B and challenges you to guess matrix A. Although Nam is smart, he could probably make a mistake while calculating matrix B, since size of A can be large.

Input

The first line contains two integer m and n (1 ≤ m, n ≤ 100), number of rows and number of columns of matrices respectively.

The next m lines each contain n integers separated by spaces describing rows of matrix B (each element of B is either 0 or 1).

Output

In the first line, print "NO" if Nam has made a mistake when calculating B, otherwise print "YES". If the first line is "YES", then also print m rows consisting of n integers representing matrix A that can produce given matrix B. If there are several solutions print any one.

Examples

Input

2 2
1 0
0 0


Output

NO


Input

2 3
1 1 1
1 1 1


Output

YES
1 1 1
1 1 1


Input

2 3
0 1 0
1 1 1


Output

YES
0 0 0
0 1 0

Solution (in PYTHON3):

Solution:
import copy

m, n = map(int, input().split())
mat = [list(map(int, input().split())) for x in range(m)]
mat2 = copy.deepcopy(mat)
matResp = [[0 for x in range(n)] for x in range(m)]


def checkAllDirFull(i, j):
    global mat

    aux = j + 1
    while aux < n:
        if mat[i][aux] == 0:
            return False
        aux += 1

    aux = j - 1
    while aux >= 0:
        if mat[i][aux] == 0:
            return False
        aux -= 1

    aux = i + 1
    while aux < m:
        if mat[aux][j] == 0:
            return False
        aux += 1

    aux = i - 1
    while aux >= 0:
        if mat[aux][j] == 0:
            return False
        aux -= 1
    return True


def change(i, j):
    global mat, mat2, matResp

    matResp[i][j] = 1
    mat2[i][j] = 2

    aux = j+1
    while aux < n:
        mat2[i][aux] = 2
        aux += 1

    aux = j-1
    while aux >= 0:
        mat2[i][aux] = 2
        aux -= 1

    aux = i + 1
    while aux < m:
        mat2[aux][j] = 2
        aux += 1

    aux = i-1
    while aux >= 0:
        mat2[aux][j] = 2
        aux -= 1


def process():
    global mat

    for i in range(m):
        for j in range(n):
            if mat[i][j] == 1:
                if checkAllDirFull(i, j):
                    change(i, j)


def check():
    for i in range(m):
        for j in range(n):
            if mat2[i][j] == 1:
                return False

    return True


def printMat(matrix):
    if len(matrix[0]) == 1:
        for i in range(len(matrix)):
            for j in range(len(matrix[0])):
                print(matrix[i][j])

    else:
        for i in range(len(matrix)):
            for j in range(len(matrix[0])-1):
                print(matrix[i][j], end=' ')
            print(matrix[i][j+1], end='\n')


process()

if check():
    print("YES")
    printMat(matResp)
else:
    print("NO")