Problem: Mashmokh's boss, Bimokh, didn't like Mashmokh. So he fired him. Mashmokh decided to go to university and participate in ACM instead of finding a new job. He wants to become a member of Bamokh's team. In order to join he was given some programming tasks and one week to solve them. Mashmokh is not a very experienced programmer. Actually he is not a programmer at all. So he wasn't able to solve them. That's why he asked you to help him with these tasks. One of these tasks is the following.

A sequence of l integers b1, b2, ..., bl (1 ≤ b1 ≤ b2 ≤ ... ≤ bl ≤ n) is called good if each number divides (without a remainder) by the next number in the sequence. More formally <image> for all i (1 ≤ i ≤ l - 1).

Given n and k find the number of good sequences of length k. As the answer can be rather large print it modulo 1000000007 (109 + 7).

Input

The first line of input contains two space-separated integers n, k (1 ≤ n, k ≤ 2000).

Output

Output a single integer — the number of good sequences of length k modulo 1000000007 (109 + 7).

Examples

Input

3 2


Output

5


Input

6 4


Output

39


Input

2 1


Output

2

Note

In the first sample the good sequences are: [1, 1], [2, 2], [3, 3], [1, 2], [1, 3].

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.*;
  
public class Main implements Runnable {
  final boolean isFileIO = false; 
  BufferedReader in;
  PrintWriter out;
  StringTokenizer st = new StringTokenizer("");
  String delim = " ";

  public static void main(String[] args) {
    new Thread(null, new Main(), "", 268435456).start(); 
  }

  public void run() {
    try {
      initIO();
      solve();
      out.close();
    } catch(Exception e) {
      e.printStackTrace(System.err);
      System.exit(-1);
    }
  }

  public void initIO() throws IOException {
    if(!isFileIO) {
      in = new BufferedReader(new InputStreamReader(System.in));
      out = new PrintWriter(System.out);
    } else {
      in = new BufferedReader(new FileReader("input.txt"));
      out = new PrintWriter("output.txt"); 
    }
  }
  
  String nextToken() throws IOException {
    if(!st.hasMoreTokens()) {
      st = new StringTokenizer(in.readLine());
    }
    return st.nextToken(delim);
  }
 
  String readLine() throws IOException {
    return in.readLine();
  }

  int nextInt() throws IOException {
   return Integer.parseInt(nextToken());
  }

  long nextLong() throws IOException {
    return Long.parseLong(nextToken());
  }

  double nextDouble() throws IOException {
    return Double.parseDouble(nextToken());
  }

  void solve() throws IOException {
    int n, k;
    n = nextInt(); k = nextInt();
    long mod = 1000_000_007;
    long[][] dp = new long[k][n + 1];
    for(int i = 1; i <= n; i++)
      dp[0][i] = 1;
    ArrayList<ArrayList<Integer>> div = new ArrayList<ArrayList<Integer>>();
    div.add(new ArrayList<Integer>());
    for(int i = 1; i <= n; i++) {
      div.add(new ArrayList<Integer>());
      for(int j = i; j >= 1; j--) {
        if(i % j == 0) div.get(i).add(j);
      }
    }
    for(int i = 1; i < k; i++) {
      for(int j = 1; j <= n; j++) {
        for(int z = 0; z < div.get(j).size(); z++) {
          dp[i][j] = (dp[i][j] + dp[i - 1][div.get(j).get(z)]) % mod;
        }
      }
    }
    long ans = 0;
    for(int i = 1; i <= n; i++)
      ans = (ans + dp[k - 1][i]) % mod;
    out.println(ans);
  }
}