Problem: Mashmokh's boss, Bimokh, didn't like Mashmokh. So he fired him. Mashmokh decided to go to university and participate in ACM instead of finding a new job. He wants to become a member of Bamokh's team. In order to join he was given some programming tasks and one week to solve them. Mashmokh is not a very experienced programmer. Actually he is not a programmer at all. So he wasn't able to solve them. That's why he asked you to help him with these tasks. One of these tasks is the following.

A sequence of l integers b1, b2, ..., bl (1 ≤ b1 ≤ b2 ≤ ... ≤ bl ≤ n) is called good if each number divides (without a remainder) by the next number in the sequence. More formally <image> for all i (1 ≤ i ≤ l - 1).

Given n and k find the number of good sequences of length k. As the answer can be rather large print it modulo 1000000007 (109 + 7).

Input

The first line of input contains two space-separated integers n, k (1 ≤ n, k ≤ 2000).

Output

Output a single integer — the number of good sequences of length k modulo 1000000007 (109 + 7).

Examples

Input

3 2


Output

5


Input

6 4


Output

39


Input

2 1


Output

2

Note

In the first sample the good sequences are: [1, 1], [2, 2], [3, 3], [1, 2], [1, 3].

Solution (in JAVA):

Solution:


import java.util.*;
import java.lang.*;
import java.io.*;
import java.math.*;

public class Main
{
    static class FastReader 
    { 
        BufferedReader br; 
        StringTokenizer st; 
  
        public FastReader() 
        { 
            br = new BufferedReader(new
                     InputStreamReader(System.in)); 
        } 
  
        String next() 
        { 
            while (st == null || !st.hasMoreElements()) 
            { 
                try
                { 
                    st = new StringTokenizer(br.readLine()); 
                } 
                catch (IOException  e) 
                { 
                    e.printStackTrace(); 
                } 
            } 
            return st.nextToken(); 
        } 
  
        int nextInt() 
        { 
            return Integer.parseInt(next()); 
        } 
  
        long nextLong() 
        { 
            return Long.parseLong(next()); 
        } 
  
        double nextDouble() 
        { 
            return Double.parseDouble(next()); 
        } 
  
        String nextLine() 
        { 
            String str = ""; 
            try
            { 
                str = br.readLine(); 
            } 
            catch (IOException e) 
            { 
                e.printStackTrace(); 
            } 
            return str; 
        } 
    }

     public static long[] randomize(long arr[])
    {
        Random rand = new Random();
for (int i = 0; i < arr.length; ++i) {
   int index = rand.nextInt(arr.length - i);
   long tmp = arr[arr.length - 1 - i];
   arr[arr.length - 1 - i] = arr[index];
   arr[index] = tmp;
}

return arr;
    } 
    static int mod = 1000000007;

  
    public static void main (String[] args) throws java.lang.Exception
    {
        FastReader sc = new FastReader();
        
        int n = sc.nextInt();
        int k = sc.nextInt();
        
        dp = new int[n+1][k+1];

        for(int i=0;i<=n;i++)
        {
            for(int j=0;j<=k;j++)
            {
                dp[i][j]=-1;
            }
        }

        int ans = 0;

        for(int i=1;i<=n;i++)
        {
            ans = ( ans % mod + solve(i, n, k) % mod )%mod;
        }

        System.out.println(ans);
       
    }
    
    static int dp[][];

    public static int solve(int number, int n, int k)
    {
        if(k==1)
        {
            return 1;
        }

        if(dp[number][k]!=-1)
            return dp[number][k];


        int ans =0;

        for(int i=number;i<=n;i=i+number)
        {
           
            ans = (ans%mod + solve(i, n,k-1)%mod)%mod;

        }

        return dp[number][k]=ans%mod;
    }
    
    
    
}