Problem: You are given two positive integers n (1 ≤ n ≤ 10^9) and k (1 ≤ k ≤ 100). Represent the number n as the sum of k positive integers of the same parity (have the same remainder when divided by 2).

In other words, find a_1, a_2, …, a_k such that all a_i>0, n = a_1 + a_2 + … + a_k and either all a_i are even or all a_i are odd at the same time.

If such a representation does not exist, then report it.

Input

The first line contains an integer t (1 ≤ t ≤ 1000) — the number of test cases in the input. Next, t test cases are given, one per line.

Each test case is two positive integers n (1 ≤ n ≤ 10^9) and k (1 ≤ k ≤ 100).

Output

For each test case print:

  * YES and the required values a_i, if the answer exists (if there are several answers, print any of them); 
  * NO if the answer does not exist. 



The letters in the words YES and NO can be printed in any case.

Example

Input


8
10 3
100 4
8 7
97 2
8 8
3 10
5 3
1000000000 9


Output


YES
4 2 4
YES
55 5 5 35
NO
NO
YES
1 1 1 1 1 1 1 1
NO
YES
3 1 1
YES
111111110 111111110 111111110 111111110 111111110 111111110 111111110 111111110 111111120

Solution (in PYTHON3):

Solution:
for _ in range(int(input())):
    n,k=map(int,input().split())
    if k>n:
        print("NO")
    else:
        if n%2==1 and k%2==0:
            print("NO")
        else:
            if n%2==1:
                a=n//k
                if a%2==0:
                    a-=1
                lis=[a]*(k-1)
                b=n-(a*(k-1))
                if b!=0:
                    lis.append(b)
                print("YES")
                print(*lis)
            else:
                if k%2==0:
                    a=n//k
                    lis=[a]*(k-1)
                    b=n-(a*(k-1))
                    if b!=0:
                        lis.append(b)
                    print("YES")
                    print(*lis)
                else:
                    a=n//k
                    if a<2:
                        print("NO")
                    else:
                        if a%2==1:
                            a-=1
                        lis=[a]*(k-1)
                        b=n-(a*(k-1))
                        if b!=0:
                            lis.append(b)
                        print("YES")
                        print(*lis)