Problem: Toad Rash has a binary string s. A binary string consists only of zeros and ones.

Let n be the length of s.

Rash needs to find the number of such pairs of integers l, r that 1 ≤ l ≤ r ≤ n and there is at least one pair of integers x, k such that 1 ≤ x, k ≤ n, l ≤ x < x + 2k ≤ r, and s_x = s_{x+k} = s_{x+2k}.

Find this number of pairs for Rash.

Input

The first line contains the string s (1 ≤ |s| ≤ 300 000), consisting of zeros and ones.

Output

Output one integer: the number of such pairs of integers l, r that 1 ≤ l ≤ r ≤ n and there is at least one pair of integers x, k such that 1 ≤ x, k ≤ n, l ≤ x < x + 2k ≤ r, and s_x = s_{x+k} = s_{x+2k}.

Examples

Input


010101


Output


3


Input


11001100


Output


0

Note

In the first example, there are three l, r pairs we need to count: 1, 6; 2, 6; and 1, 5.

In the second example, there are no values x, k for the initial string, so the answer is 0.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
const int maxn = 300010;
const int inf = 0x3f3f3f3f;
int n, x, m;
char ch[maxn];
int main() {
  scanf("%s", ch);
  n = strlen(ch);
  long long ans = 0;
  for (int i = 0; i < n; ++i) {
    int flag = 0;
    for (int j = i + 2; j < n; ++j) {
      for (int d = i; d <= j; ++d) {
        for (int k = 1; d + 2 * k <= j; ++k) {
          if (ch[d] == ch[d + k] && ch[d + k] == ch[d + 2 * k]) {
            ans += n - j;
            flag = 1;
            break;
          }
        }
        if (flag) break;
      }
      if (flag) break;
    }
  }
  printf("%lld\n", ans);
}