Problem: Let's define logical OR as an operation on two logical values (i. e. values that belong to the set {0, 1}) that is equal to 1 if either or both of the logical values is set to 1, otherwise it is 0. We can define logical OR of three or more logical values in the same manner:

<image> where <image> is equal to 1 if some ai = 1, otherwise it is equal to 0.

Nam has a matrix A consisting of m rows and n columns. The rows are numbered from 1 to m, columns are numbered from 1 to n. Element at row i (1 ≤ i ≤ m) and column j (1 ≤ j ≤ n) is denoted as Aij. All elements of A are either 0 or 1. From matrix A, Nam creates another matrix B of the same size using formula:

<image>.

(Bij is OR of all elements in row i and column j of matrix A)

Nam gives you matrix B and challenges you to guess matrix A. Although Nam is smart, he could probably make a mistake while calculating matrix B, since size of A can be large.

Input

The first line contains two integer m and n (1 ≤ m, n ≤ 100), number of rows and number of columns of matrices respectively.

The next m lines each contain n integers separated by spaces describing rows of matrix B (each element of B is either 0 or 1).

Output

In the first line, print "NO" if Nam has made a mistake when calculating B, otherwise print "YES". If the first line is "YES", then also print m rows consisting of n integers representing matrix A that can produce given matrix B. If there are several solutions print any one.

Examples

Input

2 2
1 0
0 0


Output

NO


Input

2 3
1 1 1
1 1 1


Output

YES
1 1 1
1 1 1


Input

2 3
0 1 0
1 1 1


Output

YES
0 0 0
0 1 0

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.StringTokenizer;
import java.util.Arrays;
import java.util.Scanner;

public class ORinMatrix {
	
	public static String print(int a[][]){
		String f="";
		for(int i=0;i<a.length;i++){
			for(int j=0;j<a[i].length;j++){
				f+=a[i][j]+" ";
			}
			f+="\n";
		}
		return f;
	}
	
	public static String print(Object a[][]){
		String f="";
		for(int i=0;i<a.length;i++){
			for(int j=0;j<a[i].length;j++){
				f+=((Integer)a[i][j]).intValue()+" ";
			}
			f+="\n";
		}
		return f;
	}
	public static int[][] aTob(Object [][]a){
		int b[][]=new int [a.length][a[0].length];
		for(int i=0;i<a.length;i++){
			for(int j=0;j<a[i].length;j++){
				if (((Integer)(a[i][j])).intValue()==1){
					for(int l=0;l<a[i].length;l++){
						b[i][l]=1;
					}
					for(int k=0;k<a.length;k++){
						b[k][j]=1;
					}
				}
			}
		}
		return b;
	}
	
	public static boolean equal(int[][]a,int [][]b){
		for(int i=0;i<a.length;i++){
			for(int j=0;j<a[i].length;j++){
				if (a[i][j]!=b[i][j])
					return false;
			}
		}
		return true;
	}

    public static void main (String[] args) throws IOException {
        BufferedReader in=new BufferedReader(new InputStreamReader(System.in));
        StringTokenizer s =new StringTokenizer(in.readLine());
        int m=Integer.parseInt(s.nextToken());
        int n=Integer.parseInt(s.nextToken());
        Object[][] a=new Object[m][n];
        int [][]b=new int[m][n];
        for (int i=0;i<m;i++){
        	s =new StringTokenizer(in.readLine());
        	for(int j=0;j<n;j++){
        		int r=Integer.parseInt(s.nextToken());
        		if(r==0){
        			for (int l=0;l<n;l++){
        				a[i][l]=0;
        			}
        			for (int k=0;k<m;k++){
        				a[k][j]=0;
        			}
        		}
        		b[i][j]=r;
        	}
        }
        for(int i=0;i<m;i++){
        	for(int j=0;j<n;j++){
        		if (a[i][j]==null)
        			a[i][j]=1;
        	}
        }
        if (equal(aTob(a),b)){
        	System.out.println("YES");
        	System.out.println(print(a));
        }
        else
        	System.out.println("NO");
        
    }
    
    
}