Problem: You are given a tree consisting of n nodes. You want to write some labels on the tree's edges such that the following conditions hold:

  * Every label is an integer between 0 and n-2 inclusive. 
  * All the written labels are distinct. 
  * The largest value among MEX(u,v) over all pairs of nodes (u,v) is as small as possible. 



Here, MEX(u,v) denotes the smallest non-negative integer that isn't written on any edge on the unique simple path from node u to node v.

Input

The first line contains the integer n (2 ≤ n ≤ 10^5) — the number of nodes in the tree.

Each of the next n-1 lines contains two space-separated integers u and v (1 ≤ u,v ≤ n) that mean there's an edge between nodes u and v. It's guaranteed that the given graph is a tree.

Output

Output n-1 integers. The i^{th} of them will be the number written on the i^{th} edge (in the input order).

Examples

Input


3
1 2
1 3


Output


0
1


Input


6
1 2
1 3
2 4
2 5
5 6


Output


0
3
2
4
1

Note

The tree from the second sample:

<image>

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int main() {
  ios_base::sync_with_stdio(false);
  cin.tie(0);
  cout.tie(0);
  long long n;
  cin >> n;
  vector<long long> adj[n + 1];
  vector<pair<long long int, long long int> > edges;
  map<pair<long long int, long long int>, long long> m;
  for (int i = 0; i < n - 1; i++) {
    long long x, y;
    cin >> x >> y;
    adj[x].push_back(y);
    adj[y].push_back(x);
    edges.push_back(make_pair(x, y));
  }
  long long count = 0;
  for (int i = 0; i < n - 1; i++) {
    if (adj[edges[i].first].size() == 1 || adj[edges[i].second].size() == 1) {
      m[edges[i]] = count++;
    } else {
      m[edges[i]] = -1;
    }
  }
  for (int i = 0; i < n - 1; i++) {
    if (m[edges[i]] == -1) {
      m[edges[i]] = count++;
    }
  }
  for (int i = 0; i < n - 1; i++) {
    cout << m[edges[i]] << "\n";
  }
  return 0;
}