Problem: There are N cells arranged in a row, numbered 1, 2, \ldots, N from left to right.

Tak lives in these cells and is currently on Cell 1. He is trying to reach Cell N by using the procedure described below.

You are given an integer K that is less than or equal to 10, and K non-intersecting segments [L_1, R_1], [L_2, R_2], \ldots, [L_K, R_K]. Let S be the union of these K segments. Here, the segment [l, r] denotes the set consisting of all integers i that satisfy l \leq i \leq r.

* When you are on Cell i, pick an integer d from S and move to Cell i + d. You cannot move out of the cells.



To help Tak, find the number of ways to go to Cell N, modulo 998244353.

Constraints

* 2 \leq N \leq 2 \times 10^5
* 1 \leq K \leq \min(N, 10)
* 1 \leq L_i \leq R_i \leq N
* [L_i, R_i] and [L_j, R_j] do not intersect (i \neq j)
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N K
L_1 R_1
L_2 R_2
:
L_K R_K


Output

Print the number of ways for Tak to go from Cell 1 to Cell N, modulo 998244353.

Examples

Input

5 2
1 1
3 4


Output

4


Input

5 2
3 3
5 5


Output

0


Input

5 1
1 2


Output

5


Input

60 3
5 8
1 3
10 15


Output

221823067

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const int MOD = 998244353;
int main(){
	int n,k;
	cin >> n >> k;

	vector<ll> dp(n+1,0);
	vector<ll> accum(n+1,0);

	vector<int> l(k);
	vector<int> r(k);

	for(int i = 0;i < k;i++){
		cin >> l[i] >> r[i];
	}

	dp[1] = 1;
	accum[1] = 1;
	for(int i = 2;i <= n;i++){
		for(int j = 0;j < k;j++){
			dp[i] += (accum[max(0,i-l[j])] - accum[max(0,i-r[j]-1)] + MOD) % MOD;
			dp[i] %= MOD;
		}
		accum[i] = (dp[i] + accum[i-1]) % MOD;
	}

	cout << dp[n] << endl;
}