Problem: Let's define logical OR as an operation on two logical values (i. e. values that belong to the set {0, 1}) that is equal to 1 if either or both of the logical values is set to 1, otherwise it is 0. We can define logical OR of three or more logical values in the same manner:

<image> where <image> is equal to 1 if some ai = 1, otherwise it is equal to 0.

Nam has a matrix A consisting of m rows and n columns. The rows are numbered from 1 to m, columns are numbered from 1 to n. Element at row i (1 ≤ i ≤ m) and column j (1 ≤ j ≤ n) is denoted as Aij. All elements of A are either 0 or 1. From matrix A, Nam creates another matrix B of the same size using formula:

<image>.

(Bij is OR of all elements in row i and column j of matrix A)

Nam gives you matrix B and challenges you to guess matrix A. Although Nam is smart, he could probably make a mistake while calculating matrix B, since size of A can be large.

Input

The first line contains two integer m and n (1 ≤ m, n ≤ 100), number of rows and number of columns of matrices respectively.

The next m lines each contain n integers separated by spaces describing rows of matrix B (each element of B is either 0 or 1).

Output

In the first line, print "NO" if Nam has made a mistake when calculating B, otherwise print "YES". If the first line is "YES", then also print m rows consisting of n integers representing matrix A that can produce given matrix B. If there are several solutions print any one.

Examples

Input

2 2
1 0
0 0


Output

NO


Input

2 3
1 1 1
1 1 1


Output

YES
1 1 1
1 1 1


Input

2 3
0 1 0
1 1 1


Output

YES
0 0 0
0 1 0

Solution (in JAVA):

Solution:

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

public class ORinMatrix {

	public static void main(String[] args) throws IOException {
		BufferedReader br = new BufferedReader(new InputStreamReader(System.in));

		String s = br.readLine();
		String[] sa = s.split(" ");
		int n =Integer.parseInt(sa[0]);
		int m =Integer.parseInt(sa[1]);
		int[][] arr = new int [n][m];
		for(int i=0;i<n;i++)
		{
			s= br.readLine();
			sa= s.split(" ");
			for(int j=0;j<m;j++)
			{
				arr[i][j] =Integer.parseInt(sa[j]);
			}
		}
		if(n==1 && m==1)
			System.out.println("YES\n"+arr[0][0]);
		else
		{
			int[][] ans = new int[n][m];
			boolean ok = true;
			int rows =0,columns= 0;
			for(int i=0;ok && i<n;i++)
				for(int j=0;ok && j<m;j++)
					if(arr[i][j]==1)
					{
						boolean col =true;
						boolean row = true;
						for(int k=0;k<n;k++)
							if(k!=i)
								if(arr[k][j] == 0)
									row = false;
						for(int k=0;k<m;k++)
							if(k!=j)
								if(arr[i][k] == 0)
									col = false;
						if(!row && !col)
							ok = false;
						if(row && col)
							ans[i][j] = 1;
						if(row)
							rows++;
						if(col)
							columns++;
					}
			
			if((rows == 0 && columns > 0 ) || (rows > 0 && columns == 0 ) )
				ok = false;
			if(ok)
			{
				System.out.println("YES");
				for(int i=0;i<n;i++)
				{
					for(int j=0;j<m;j++)
						System.out.print(ans[i][j]  + " ");
					System.out.println();
				}
			}
			else
				System.out.println("NO");
		}
	}

}