Problem: Let's define logical OR as an operation on two logical values (i. e. values that belong to the set {0, 1}) that is equal to 1 if either or both of the logical values is set to 1, otherwise it is 0. We can define logical OR of three or more logical values in the same manner:

<image> where <image> is equal to 1 if some ai = 1, otherwise it is equal to 0.

Nam has a matrix A consisting of m rows and n columns. The rows are numbered from 1 to m, columns are numbered from 1 to n. Element at row i (1 ≤ i ≤ m) and column j (1 ≤ j ≤ n) is denoted as Aij. All elements of A are either 0 or 1. From matrix A, Nam creates another matrix B of the same size using formula:

<image>.

(Bij is OR of all elements in row i and column j of matrix A)

Nam gives you matrix B and challenges you to guess matrix A. Although Nam is smart, he could probably make a mistake while calculating matrix B, since size of A can be large.

Input

The first line contains two integer m and n (1 ≤ m, n ≤ 100), number of rows and number of columns of matrices respectively.

The next m lines each contain n integers separated by spaces describing rows of matrix B (each element of B is either 0 or 1).

Output

In the first line, print "NO" if Nam has made a mistake when calculating B, otherwise print "YES". If the first line is "YES", then also print m rows consisting of n integers representing matrix A that can produce given matrix B. If there are several solutions print any one.

Examples

Input

2 2
1 0
0 0


Output

NO


Input

2 3
1 1 1
1 1 1


Output

YES
1 1 1
1 1 1


Input

2 3
0 1 0
1 1 1


Output

YES
0 0 0
0 1 0

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.*;
public class CF0486B
{
 static BufferedReader sIn = new BufferedReader(new InputStreamReader(System.in));
 static PrintWriter sOut = new PrintWriter(System.out);
 public static void main(String[] dieOder) throws IOException
 {
  StringTokenizer sT = new StringTokenizer(sIn.readLine());
  int n = Integer.parseInt(sT.nextToken());
  int m = Integer.parseInt(sT.nextToken());
  String[] allS = new String[n];
  boolean[] rzero = new boolean[n];
  boolean[] rset = new boolean[n];
  boolean[] czero = new boolean[m];
  boolean[] cset = new boolean[m];
  for (int i = 0; i < n; i ++)
  {
   allS[i] = sIn.readLine();
   for (int j = 0; j < m; j ++)
    if (allS[i].charAt(2 * j) == '0')
    {
     rzero[i] = true;
     czero[j] = true;
    }
  }
  int[][] all = new int[n][m];
  for (int i = 0; i < n; i ++)
   for (int j = 0; j < m; j ++)
    if (!rzero[i] && !czero[j])
    {
     all[i][j] = 1;
     rset[i] = true;
     cset[j] = true;
    }
  boolean yes = true;
  for (int i = 0; yes & i < n; i ++)
  {
   for (int j = 0; yes & j < m; j ++)
    if (allS[i].charAt(2 * j) == '1' && !rset[i] && !cset[j])
     yes = false;
  }
  if (yes)
  {
   sOut.println("YES");
   for (int i = 0; i < n; i ++)
   {
    StringJoiner sJ = new StringJoiner(" ");
    for (int j = 0; j < m; j ++)
     sJ.add(Integer.toString(all[i][j]));
    sOut.println(sJ);
   }
  }
   else
    sOut.println("NO");
  sOut.close();
 }
}