Problem: You are given a tree consisting of n nodes. You want to write some labels on the tree's edges such that the following conditions hold:

  * Every label is an integer between 0 and n-2 inclusive. 
  * All the written labels are distinct. 
  * The largest value among MEX(u,v) over all pairs of nodes (u,v) is as small as possible. 



Here, MEX(u,v) denotes the smallest non-negative integer that isn't written on any edge on the unique simple path from node u to node v.

Input

The first line contains the integer n (2 ≤ n ≤ 10^5) — the number of nodes in the tree.

Each of the next n-1 lines contains two space-separated integers u and v (1 ≤ u,v ≤ n) that mean there's an edge between nodes u and v. It's guaranteed that the given graph is a tree.

Output

Output n-1 integers. The i^{th} of them will be the number written on the i^{th} edge (in the input order).

Examples

Input


3
1 2
1 3


Output


0
1


Input


6
1 2
1 3
2 4
2 5
5 6


Output


0
3
2
4
1

Note

The tree from the second sample:

<image>

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int main() {
  ios_base::sync_with_stdio(0);
  cin.tie(0);
  cout.tie(0);
  ;
  int n;
  cin >> n;
  vector<vector<int> > g(n + 1);
  vector<pair<int, int> > a(n - 1);
  for (int i = 0; i < n - 1; i++) {
    cin >> a[i].first >> a[i].second;
    g[a[i].first].push_back(a[i].second);
    g[a[i].second].push_back(a[i].first);
  }
  int vert = -1, nxt2 = 0, nxt1 = 0;
  for (int i = 1; i <= n; i++) {
    if (g[i].size() >= 3) {
      vert = i;
      nxt2 = g[i].size();
      break;
    }
  }
  for (int i = 0; i < n - 1; i++) {
    if (a[i].first == vert || a[i].second == vert) {
      cout << nxt1 << "\n";
      nxt1++;
    } else {
      cout << nxt2 << "\n";
      nxt2++;
    }
  }
}