Problem: Let's define logical OR as an operation on two logical values (i. e. values that belong to the set {0, 1}) that is equal to 1 if either or both of the logical values is set to 1, otherwise it is 0. We can define logical OR of three or more logical values in the same manner:

<image> where <image> is equal to 1 if some ai = 1, otherwise it is equal to 0.

Nam has a matrix A consisting of m rows and n columns. The rows are numbered from 1 to m, columns are numbered from 1 to n. Element at row i (1 ≤ i ≤ m) and column j (1 ≤ j ≤ n) is denoted as Aij. All elements of A are either 0 or 1. From matrix A, Nam creates another matrix B of the same size using formula:

<image>.

(Bij is OR of all elements in row i and column j of matrix A)

Nam gives you matrix B and challenges you to guess matrix A. Although Nam is smart, he could probably make a mistake while calculating matrix B, since size of A can be large.

Input

The first line contains two integer m and n (1 ≤ m, n ≤ 100), number of rows and number of columns of matrices respectively.

The next m lines each contain n integers separated by spaces describing rows of matrix B (each element of B is either 0 or 1).

Output

In the first line, print "NO" if Nam has made a mistake when calculating B, otherwise print "YES". If the first line is "YES", then also print m rows consisting of n integers representing matrix A that can produce given matrix B. If there are several solutions print any one.

Examples

Input

2 2
1 0
0 0


Output

NO


Input

2 3
1 1 1
1 1 1


Output

YES
1 1 1
1 1 1


Input

2 3
0 1 0
1 1 1


Output

YES
0 0 0
0 1 0

Solution (in JAVA):

Solution:
import java.util.*;

public class OrInMatrix{

	public static void main(String[] args){
		Scanner myS = new Scanner(System.in);
		int rows = myS.nextInt();
		int cols = myS.nextInt();
		int[][] BMatrix = new int[rows][cols];
		for(int i=0; i<rows; i++){
			for(int j=0; j<cols; j++){
				BMatrix[i][j] = myS.nextInt();
			}
		}
		int[][] AMatrix = BtoA(BMatrix);
		//printMatrix(AMatrix);
		int[][] newB = AtoB(AMatrix);
		//printMatrix(newB);
		boolean same = checkSameMatrices(BMatrix, newB);
		if(same){
			System.out.println("YES");
			printMatrix(AMatrix);
		}		
		else{
			System.out.println("NO");
		}
	}

	public static int[][] BtoA(int[][] B){
		int rows = B.length;
		int cols = B[0].length;
		boolean[][] rowsCheck = new boolean[rows][cols];
		boolean[][] colsCheck = new boolean[rows][cols];

		for(int i=0; i<rows; i++){
			boolean allOnes = true;
			for(int j=0; j<cols; j++){
				if(B[i][j] == 0){
					allOnes = false;
				}
			}
			if(allOnes){
				for(int j=0;j<cols; j++){
					rowsCheck[i][j] = true;
				}
			}
		}

		for(int i=0; i<cols; i++){
			boolean allOnes = true;
			for(int j=0; j<rows; j++){
				if(B[j][i] == 0){
					allOnes = false;
				}
			}
			if(allOnes){
				for(int j=0;j<rows; j++){
					colsCheck[j][i] = true;
				}
			}
		}

		//printBMatrix(rowsCheck);
		//printBMatrix(colsCheck);
		int[][] A = new int[rows][cols];
		for(int i=0; i<rows; i++){
			for(int j=0; j<cols; j++){
				if(rowsCheck[i][j] && colsCheck[i][j]){
					A[i][j] = 1;
				}
			}
		}
		return A;		
	}// BtoA

	public static int[][] AtoB (int[][] A){
		int rows = A.length;
		int cols = A[0].length;
		int[][] B = new int[rows][cols];
		for(int i=0; i<rows; i++){
			for(int j=0; j<cols; j++){
				if(A[i][j]==1){
					for(int k=0; k<rows; k++){
						B[k][j] = 1;
					}
					for(int k=0; k<cols; k++){
						B[i][k] = 1;
					}
				}
			}
		}
		return B;
	}	

	public static boolean checkSameMatrices(int[][] A, int[][] B){
		int rows = A.length;
		int cols = A[0].length;
		boolean ugh = true;
		for(int i=0; i<rows; i++){
			for(int j=0; j<cols; j++){
				if(A[i][j] != B[i][j]){
					ugh = false;
				}
			}
		}
		return ugh;
	}

	public static void printMatrix(int[][] A){
		for(int i=0; i<A.length; i++){
			for(int j=0; j<A[0].length; j++){
				System.out.print(A[i][j] + " ");
			}
			System.out.println();
		}
	}

	public static void printBMatrix(boolean[][] A){
		for(int i=0; i<A.length; i++){
			for(int j=0; j<A[0].length; j++){
				System.out.print(A[i][j] + " ");
			}
			System.out.println();
		}
	}	
}