Problem: You are given a tree consisting of n nodes. You want to write some labels on the tree's edges such that the following conditions hold:

  * Every label is an integer between 0 and n-2 inclusive. 
  * All the written labels are distinct. 
  * The largest value among MEX(u,v) over all pairs of nodes (u,v) is as small as possible. 



Here, MEX(u,v) denotes the smallest non-negative integer that isn't written on any edge on the unique simple path from node u to node v.

Input

The first line contains the integer n (2 ≤ n ≤ 10^5) — the number of nodes in the tree.

Each of the next n-1 lines contains two space-separated integers u and v (1 ≤ u,v ≤ n) that mean there's an edge between nodes u and v. It's guaranteed that the given graph is a tree.

Output

Output n-1 integers. The i^{th} of them will be the number written on the i^{th} edge (in the input order).

Examples

Input


3
1 2
1 3


Output


0
1


Input


6
1 2
1 3
2 4
2 5
5 6


Output


0
3
2
4
1

Note

The tree from the second sample:

<image>

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
vector<vector<pair<int, int>>> v;
int main() {
  ios_base::sync_with_stdio(false);
  cin.tie(nullptr);
  int n;
  cin >> n;
  v.resize(n + 1);
  for (int i = 0; i < n - 1; ++i) {
    int a, b;
    cin >> a >> b;
    v[a].push_back({b, i}), v[b].push_back({a, i});
  }
  if (n == 2) {
    cout << "0";
  } else if (n == 3) {
    cout << "0 1";
  } else {
    vector<int> ans(n - 1, -1);
    int st = 0;
    for (int i = 1; i <= n; ++i) {
      if (v[i].size() == 1) {
        ans[v[i][0].second] = st++;
      }
    }
    for (int i = 0; i < n - 1; ++i) {
      if (ans[i] == -1) ans[i] = st++;
    }
    for (int i : ans) cout << i << '\n';
  }
  return 0;
}