Problem: Let's say string s has period k if s_i = s_{i + k} for all i from 1 to |s| - k (|s| means length of string s) and k is the minimum positive integer with this property.

Some examples of a period: for s="0101" the period is k=2, for s="0000" the period is k=1, for s="010" the period is k=2, for s="0011" the period is k=4.

You are given string t consisting only of 0's and 1's and you need to find such string s that:

  1. String s consists only of 0's and 1's; 
  2. The length of s doesn't exceed 2 ⋅ |t|; 
  3. String t is a subsequence of string s; 
  4. String s has smallest possible period among all strings that meet conditions 1—3. 



Let us recall that t is a subsequence of s if t can be derived from s by deleting zero or more elements (any) without changing the order of the remaining elements. For example, t="011" is a subsequence of s="10101".

Input

The first line contains single integer T (1 ≤ T ≤ 100) — the number of test cases.

Next T lines contain test cases — one per line. Each line contains string t (1 ≤ |t| ≤ 100) consisting only of 0's and 1's.

Output

Print one string for each test case — string s you needed to find. If there are multiple solutions print any one of them.

Example

Input


4
00
01
111
110


Output


00
01
11111
1010

Note

In the first and second test cases, s = t since it's already one of the optimal solutions. Answers have periods equal to 1 and 2, respectively.

In the third test case, there are shorter optimal solutions, but it's okay since we don't need to minimize the string s. String s has period equal to 1.

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.*;

public class Binary {
    public static void main(String args[]) throws IOException{
        Scanner sc = new Scanner(System.in);
        PrintWriter pw = new PrintWriter(System.out);
        int t = sc.nextInt();
        while(t--!=0){
            String s = sc.next();
            int one=0;
            int zero=0;
            for(int i=0;i<s.length();i++){
                if(s.charAt(i)=='1')
                    one++;
                else
                    zero++;
            }
            if(one == 0 || zero == 0){
                pw.println(s);
            }else{
                StringBuilder sb = new StringBuilder("");
                if(s.charAt(0)=='1'){
                    String ans ="10";
                    for(int i=0;i<s.length();i++){
                        sb.append(ans);
                    }
                }else{
                    String ans ="01";
                    for(int i=0;i<s.length();i++){
                        sb.append(ans);
                    }
                }
                pw.println(sb);
            }
        }
        pw.close();
    }
    public static int gcd(int a,int b){
        int ans=1;
        for(int i = 1; i <= a && i <= a; i++)
        {
            if(a%i==0 && b%i==0)
                ans = i;
        }
        return ans;
    }
    static class Scanner {
	StringTokenizer st;
	BufferedReader br;
        
	public Scanner(InputStream s) {
		br = new BufferedReader(new InputStreamReader(s));
	}
        
	public Scanner(String file) throws FileNotFoundException {
		br = new BufferedReader(new FileReader(file));
        }
	public String next() throws IOException {
		while (st == null || !st.hasMoreTokens())
			st = new StringTokenizer(br.readLine());
		return st.nextToken();
	}
	public int nextInt() throws IOException {
		return Integer.parseInt(next());
	}

	public long nextLong() throws IOException {
		return Long.parseLong(next());
	}

	public String nextLine() throws IOException {
		return br.readLine();
	}

	public double nextDouble() throws IOException {
		return Double.parseDouble(next());
	}

	public boolean ready() throws IOException {
		return br.ready();
	}

    }
}