Problem: We have N boxes, numbered 1 through N. At first, box 1 contains one red ball, and each of the other boxes contains one white ball.

Snuke will perform the following M operations, one by one. In the i-th operation, he randomly picks one ball from box x_i, then he puts it into box y_i.

Find the number of boxes that may contain the red ball after all operations are performed.

Constraints

* 2≤N≤10^5
* 1≤M≤10^5
* 1≤x_i,y_i≤N
* x_i≠y_i
* Just before the i-th operation is performed, box x_i contains at least 1 ball.

Input

The input is given from Standard Input in the following format:


N M
x_1 y_1
:
x_M y_M


Output

Print the number of boxes that may contain the red ball after all operations are performed.

Examples

Input

3 2
1 2
2 3


Output

2


Input

3 3
1 2
2 3
2 3


Output

1


Input

4 4
1 2
2 3
4 1
3 4


Output

3

Solution (in JAVA):

Solution:
import java.util.Arrays;
import java.util.Scanner;

public class Main {

	public static String Y = "Yes";
	public static String N = "No";
	public static long MOD = (long) (Math.pow(10, 9) + 7);
	public static Scanner sc = new Scanner(System.in);

	public static void main(String[] args) {
		int n = ni();
		int m = ni();

		boolean[] inred = new boolean[n];
		int[] innum = new int[n];
		inred[0] = true;
		for (int i = 0; i < n; i++) {
			innum[i] = 1;
		}

		for (int i = 0; i < m; i++) {
			int x = ni();
			int y = ni();

			if (inred[x - 1] && innum[x - 1] >= 2) {
				inred[y - 1] = true;
				innum[x - 1]--;
				innum[y - 1]++;
			} else if (inred[x - 1] && innum[x - 1] == 1) {
				inred[x - 1] = false;
				inred[y - 1] = true;
				innum[x - 1]--;
				innum[y - 1]++;
			}

			else if (!inred[x - 1]) {
				innum[x - 1]--;
				innum[y - 1]++;
			}

		}

		int ans = 0;

		for (boolean red : inred) {
			if (red) {
				ans++;
			}
		}

		out(ans);

	}

	/*
	 * 以下メソッド集
	 */
	static int[] sort(int[] n) {
		Arrays.sort(n);
		return n;
	}

	static long[] sort(long[] n) {
		Arrays.sort(n);
		return n;
	}

	static int ketasuu(int n) {
		String str = "" + n;
		return str.length();
	}

	static int abcount(String str) {
		int count = 0;
		int len = str.length();
		for (int i = 0; i < len - 1; i++) {
			if ("AB".equals(str.substring(i, i + "AB".length()))) {
				count++;
			}
		}
		return count;
	}

	static int ni() {
		return sc.nextInt();
	}

	static long nl() {
		return sc.nextLong();
	}

	static double nd() {
		return sc.nextDouble();
	}

	static String n() {
		return sc.next();
	}

	static char[] nc() {
		return sc.next().toCharArray();
	}

	static int kaijo(int n) {
		if (n == 0 || n == 1) {
			return 1;
		} else {
			return n * kaijo(n - 1);
		}
	}

	static int fib(int n) {
		return (n == 1 || n == 0) ? n : fib(n - 2) + fib(n - 1);
	}

	static long lcm(long m, long n) {

		return m * n / gcd(m, n);
	}

	static int lcm(int m, int n) {

		return m * n / gcd(m, n);
	}

	static long gcd(long a, long b) {
		return (b == 0) ? a : gcd(b, a % b);
	}

	static int gcd(int a, int b) {
		return (b == 0) ? a : gcd(b, a % b);
	}

	static void out(String info) {
		System.out.println(info);
	}

	static void out(int info) {
		System.out.println(info);
	}

	static void out(double info) {
		System.out.println(info);
	}

	static void out(long info) {
		System.out.println(info);
	}

	static void out(char info) {
		System.out.println(info);
	}

	static void out(Object obj) {
		System.out.println(obj.toString());
	}

	static void outn(String info) {
		System.out.print(info);
	}

	static void outn(int info) {
		System.out.print(info);
	}

	static void outn(double info) {
		System.out.print(info);
	}

	static void outn(long info) {
		System.out.print(info);
	}

	static void outn(char info) {
		System.out.print(info);
	}

	static double max(double d, double e) {
		return Math.max(d, e);
	}

	static long max(long a, long b) {
		return Math.max(a, b);
	}

	static double min(double d, double e) {
		return Math.min(d, e);
	}

	static int min(int a, int b) {
		return (int) Math.min(a, b);
	}
}

class XY {
	int h;
	int c;

	XY(int h, int c) {
		this.h = h;
		this.c = c;
	}
}