Problem: Let's say string s has period k if s_i = s_{i + k} for all i from 1 to |s| - k (|s| means length of string s) and k is the minimum positive integer with this property.

Some examples of a period: for s="0101" the period is k=2, for s="0000" the period is k=1, for s="010" the period is k=2, for s="0011" the period is k=4.

You are given string t consisting only of 0's and 1's and you need to find such string s that:

  1. String s consists only of 0's and 1's; 
  2. The length of s doesn't exceed 2 ⋅ |t|; 
  3. String t is a subsequence of string s; 
  4. String s has smallest possible period among all strings that meet conditions 1—3. 



Let us recall that t is a subsequence of s if t can be derived from s by deleting zero or more elements (any) without changing the order of the remaining elements. For example, t="011" is a subsequence of s="10101".

Input

The first line contains single integer T (1 ≤ T ≤ 100) — the number of test cases.

Next T lines contain test cases — one per line. Each line contains string t (1 ≤ |t| ≤ 100) consisting only of 0's and 1's.

Output

Print one string for each test case — string s you needed to find. If there are multiple solutions print any one of them.

Example

Input


4
00
01
111
110


Output


00
01
11111
1010

Note

In the first and second test cases, s = t since it's already one of the optimal solutions. Answers have periods equal to 1 and 2, respectively.

In the third test case, there are shorter optimal solutions, but it's okay since we don't need to minimize the string s. String s has period equal to 1.

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.*;
 
public class TestClass {
 
	static PrintWriter out = new PrintWriter(System.out);
	public static void main(String[] args) throws IOException{
 
		BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
		int t = Integer.parseInt(in.readLine());
		for(int ti=0;ti<t;ti++) {
			String s = in.readLine();
			int n = s.length();
			int f=0;
			for(int i=1;i<n;i++) {
				if(s.charAt(i)!=s.charAt(i-1)) {
					f=1;
					break;
				}
			}
			if(f==0) {
				out.println(s);
			}
			else {
				int a = Integer.parseInt(s.charAt(0)+"");
				for(int i=0;i<2*n;i++) {
					out.print(a);
					a = a^1;
				}
				out.println();
			}
		}	
        out.close();
	}	
}