Problem: Let's say string s has period k if s_i = s_{i + k} for all i from 1 to |s| - k (|s| means length of string s) and k is the minimum positive integer with this property.

Some examples of a period: for s="0101" the period is k=2, for s="0000" the period is k=1, for s="010" the period is k=2, for s="0011" the period is k=4.

You are given string t consisting only of 0's and 1's and you need to find such string s that:

  1. String s consists only of 0's and 1's; 
  2. The length of s doesn't exceed 2 ⋅ |t|; 
  3. String t is a subsequence of string s; 
  4. String s has smallest possible period among all strings that meet conditions 1—3. 



Let us recall that t is a subsequence of s if t can be derived from s by deleting zero or more elements (any) without changing the order of the remaining elements. For example, t="011" is a subsequence of s="10101".

Input

The first line contains single integer T (1 ≤ T ≤ 100) — the number of test cases.

Next T lines contain test cases — one per line. Each line contains string t (1 ≤ |t| ≤ 100) consisting only of 0's and 1's.

Output

Print one string for each test case — string s you needed to find. If there are multiple solutions print any one of them.

Example

Input


4
00
01
111
110


Output


00
01
11111
1010

Note

In the first and second test cases, s = t since it's already one of the optimal solutions. Answers have periods equal to 1 and 2, respectively.

In the third test case, there are shorter optimal solutions, but it's okay since we don't need to minimize the string s. String s has period equal to 1.

Solution (in PYTHON3):

Solution:
# # t=int(input())
# # for _ in range(t):
# #     a,b,c=map(int,input().split())
# #     ans=[]
# #     m=max(a,b)
# #     if a%2==0 and b%2==0:
    
# #     else:

# #     for i in range(c):

# x=0
# arr=[]
# for i in range(100,201):
#     if (i%7)%10==(i%10)%7:
#             arr.append(i)
#             x+=1
# print(arr,x)


# t=int(input())
# for _ in range(t):
#     a=input()
#     m=[]
#     for i in range(len(a)):
#         if a[i] in m:
#             continue
#         else:
#             m.append(i)
#     if len(m)==1:
#         print(a)
#     else:
#         x='01'*int(len(a))
#         print(x)


from collections import Counter
c=int(input())
t=[0,1]
for _ in range(c):
  n=input()
  
  d=Counter(list(n)).most_common()
  x=d[0][0]
  y=d[0][1]
  try:
    m3=d[1][0]
    m4=d[1][1]
  except:
    print(n)
    continue
  
  print('01'*len(n))

  # # t=int(input())
# # for _ in range(t):
# #     a,b,c=map(int,input().split())
# #     ans=[]
# #     m=max(a,b)
# #     if a%2==0 and b%2==0:
    
# #     else:

# #     for i in range(c):

# x=0
# arr=[]
# for i in range(100,201):
#     if (i%7)%10==(i%10)%7:
#             arr.append(i)
#             x+=1
# print(arr,x)


# t=int(input())
# for _ in range(t):
#     a=input()
#     m=[]
#     for i in range(len(a)):
#         if a[i] in m:
#             continue
#         else:
#             m.append(i)
#     if len(m)==1:
#         print(a)
#     else:
#         x='01'*int(len(a))
#         print(x)