Problem: You are given one integer n (n > 1).

Recall that a permutation of length n is an array consisting of n distinct integers from 1 to n in arbitrary order. For example, [2, 3, 1, 5, 4] is a permutation of length 5, but [1, 2, 2] is not a permutation (2 appears twice in the array) and [1, 3, 4] is also not a permutation (n = 3 but there is 4 in the array).

Your task is to find a permutation p of length n that there is no index i (1 ≤ i ≤ n) such that p_i = i (so, for all i from 1 to n the condition p_i ≠ i should be satisfied).

You have to answer t independent test cases.

If there are several answers, you can print any. It can be proven that the answer exists for each n > 1.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then t test cases follow.

The only line of the test case contains one integer n (2 ≤ n ≤ 100) — the length of the permutation you have to find.

Output

For each test case, print n distinct integers p_1, p_2, …, p_n — a permutation that there is no index i (1 ≤ i ≤ n) such that p_i = i (so, for all i from 1 to n the condition p_i ≠ i should be satisfied).

If there are several answers, you can print any. It can be proven that the answer exists for each n > 1.

Example

Input


2
2
5


Output


2 1
2 1 5 3 4

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.*;
public class spcl
{
    public static void main(String args[])throws IOException
    {
        Scanner sc = new Scanner(System.in);
        
        int t=sc.nextInt();
        
        while(t-->0)
        {
            int n=sc.nextInt();int d=n;
            int a[]=new int[n];
            for(int i=0;i<n;i++)
            {
                a[i] =d;
                d--;
            }
            for(int i=0;i<n-1;i++)
            {
                if(a[i]==(i+1))
                {
                    int t1=a[i+1];
                    a[i+1]=a[i];
                    a[i]=t1;
                }
            }
            for(int i=0;i<n;i++)
            System.out.print(a[i]+" ");
            System.out.println();
            
        }
    }
}