Problem: You are given two positive integers n (1 ≤ n ≤ 10^9) and k (1 ≤ k ≤ 100). Represent the number n as the sum of k positive integers of the same parity (have the same remainder when divided by 2).

In other words, find a_1, a_2, …, a_k such that all a_i>0, n = a_1 + a_2 + … + a_k and either all a_i are even or all a_i are odd at the same time.

If such a representation does not exist, then report it.

Input

The first line contains an integer t (1 ≤ t ≤ 1000) — the number of test cases in the input. Next, t test cases are given, one per line.

Each test case is two positive integers n (1 ≤ n ≤ 10^9) and k (1 ≤ k ≤ 100).

Output

For each test case print:

  * YES and the required values a_i, if the answer exists (if there are several answers, print any of them); 
  * NO if the answer does not exist. 



The letters in the words YES and NO can be printed in any case.

Example

Input


8
10 3
100 4
8 7
97 2
8 8
3 10
5 3
1000000000 9


Output


YES
4 2 4
YES
55 5 5 35
NO
NO
YES
1 1 1 1 1 1 1 1
NO
YES
3 1 1
YES
111111110 111111110 111111110 111111110 111111110 111111110 111111110 111111110 111111120

Solution (in PYTHON3):

Solution:
for _ in range(int(input())):
    n,k=map(int, input().split())
    if k>n:
        print('NO')
    elif n%2!=0 and k%2==0:
        print('NO')
    else:
        lst=[2]*(k-1)
        val=n-((k-1)*2)
        if val>1 and val%2==0:
            lst.append(val)
            print('YES')
            print(*lst)
        else:
            lst=[1]*(k-1)
            val=n-(k-1)
            if val>0 and val%2!=0:
                lst.append(val)
                rem=lst[0]%2
                f=0
                for i in lst:
                    if i%2!=rem:
                        f=1
                        break
                if f==1:
                    print('NO')
                else:
                    print('YES')
                    print(*lst)
            else:
                print('NO')