Problem: Let's say string s has period k if s_i = s_{i + k} for all i from 1 to |s| - k (|s| means length of string s) and k is the minimum positive integer with this property.

Some examples of a period: for s="0101" the period is k=2, for s="0000" the period is k=1, for s="010" the period is k=2, for s="0011" the period is k=4.

You are given string t consisting only of 0's and 1's and you need to find such string s that:

  1. String s consists only of 0's and 1's; 
  2. The length of s doesn't exceed 2 ⋅ |t|; 
  3. String t is a subsequence of string s; 
  4. String s has smallest possible period among all strings that meet conditions 1—3. 



Let us recall that t is a subsequence of s if t can be derived from s by deleting zero or more elements (any) without changing the order of the remaining elements. For example, t="011" is a subsequence of s="10101".

Input

The first line contains single integer T (1 ≤ T ≤ 100) — the number of test cases.

Next T lines contain test cases — one per line. Each line contains string t (1 ≤ |t| ≤ 100) consisting only of 0's and 1's.

Output

Print one string for each test case — string s you needed to find. If there are multiple solutions print any one of them.

Example

Input


4
00
01
111
110


Output


00
01
11111
1010

Note

In the first and second test cases, s = t since it's already one of the optimal solutions. Answers have periods equal to 1 and 2, respectively.

In the third test case, there are shorter optimal solutions, but it's okay since we don't need to minimize the string s. String s has period equal to 1.

Solution (in JAVA):

Solution:
import java.util.*;


public class Main {

    public static void main (String [] args ) {

        Scanner scanner = new Scanner(System.in);

        int t = scanner.nextInt();
        for(int tt=0;tt<t;tt++) {

            String str = scanner.next();
            int n = str.length();
            char [] ts = str.toCharArray();
           
            boolean ok = false;
            for(int i=0;i<n-1;i++) {
                if(ts[i]!=ts[i+1]) {
                    ok = true;
                    break;
                }
            }
            if(ok) {
                String ans = "";
                for(int i=0;i<n;i++) {
                    ans+="01"; 
                }
                System.out.println(ans);
            }
            else {
                System.out.println(new String(ts));
            }
           
        }
    }
}