Problem: 

Interaction

This is an interactive problem. You need to read participants' queries from standard input and print your responses to standard output. You don't know the number of queries upfront, so you'll need to process them as you get them; you'll know you're done once you reach the end of the file.

In each query, you will be asked the question, written in one line. You have to answer it correctly, patiently and without any display of emotions. Your response is case-insensitive.

Please make sure to use the stream flushing operation after each response in order not to leave part of your output in some buffer.

Example

Input


Is it rated?
Is it rated?
Is it rated?


Output


NO
NO
NO

Solution (in CPP):

Solution:
#include<bits/stdc++.h>
using namespace std;

#define fastio ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL);
#define fr(i,k) for(i=0;i<k;i++)
#define deb(x) cerr<<#x<<"  = "<<x<<endl;
#define deb2(x,y) cerr<<#x<<" = "<<x<<"  "<<#y<<" = "<<y<<endl;
#define print(x) for (auto k:x) cout<<k<<" ";cout<<endl;
#define SZ(x) (x).size();
#define ll long long
#define mod 1000000007
#define ff first
#define ss second
#define pb push_back
#define em emplace_back
#define ulli unsigned long long int
#define inf 1e18
//#define endl "\n"
typedef vector<vector<ll>> vvll;
typedef vector<ll> vll;
typedef vector<pair<ll, ll>> vpll;
typedef pair<ll, ll> pll;
typedef vector<bool> vb;
ll mul(ll a, ll b) {return (1LL * a * b) % mod;}
ll add(ll a, ll b) {ll s = (a + b); if (s >= mod) s -= mod; return s;}
ll sub(ll a, ll b) {ll s = (a + mod - b); if (s >= mod) s -= mod; return s;}
void solve();
void pre();


int main() {
	fastio;
#ifndef ONLINE_JUDGE
	freopen("input.txt", "r", stdin);
	freopen("output.txt", "w", stdout);
#endif

	ll t;
	t = 1;

	//cin >> t;
	for (ll test = 1; test <= t; test++)
	{
		//cout << "Case #" << test << ": ";
		solve();
	}
	return 0;
}

inline void solve()
{
	string s;
	while (cin >> s)
	{
		cout << "NO" << endl;
	}
}