Problem: Mike has a string s consisting of only lowercase English letters. He wants to change exactly one character from the string so that the resulting one is a palindrome. 

A palindrome is a string that reads the same backward as forward, for example strings "z", "aaa", "aba", "abccba" are palindromes, but strings "codeforces", "reality", "ab" are not.

Input

The first and single line contains string s (1 ≤ |s| ≤ 15).

Output

Print "YES" (without quotes) if Mike can change exactly one character so that the resulting string is palindrome or "NO" (without quotes) otherwise. 

Examples

Input

abccaa


Output

YES


Input

abbcca


Output

NO


Input

abcda


Output

YES

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.StringTokenizer;

public class CF410AEasyPalin {
    public static PrintWriter out;
    public static FastScanner in;

    private void solve() {
        String s = in.nextLine();

        int lo = 0;
        int hi = s.length()-1;

        int count = 0;
        while(lo<hi){
            if(s.charAt(lo)!=s.charAt(hi)) count++;
            lo++;
            hi--;
        }

        if(count == 1) {
            out.print("YES");
            return;
        }
        if(count == 0 && s.length()%2 == 1){
            out.print("YES");
            return;
        }
        out.print("NO");
    }

    private void runIO() {
        in = new FastScanner();
        out = new PrintWriter(new BufferedOutputStream(System.out));
        solve();
        out.close();
    }

    private static class FastScanner {
        BufferedReader bufferedReader;
        StringTokenizer stringTokenizer;

        private FastScanner() {
            bufferedReader = new BufferedReader(new InputStreamReader(System.in));
        }

        private String next() {
            if (stringTokenizer == null || !stringTokenizer.hasMoreElements()) {
                try {
                    stringTokenizer = new StringTokenizer(bufferedReader.readLine());
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
            return stringTokenizer.nextToken();
        }

        private int nextInt() {
            return Integer.parseInt(next());
        }

        private long nextLong() {
            return Long.parseLong(next());
        }

        private String nextLine() {
            String ret = "";
            try {
                ret = bufferedReader.readLine();
            } catch (IOException e) {
                e.printStackTrace();
            }
            return ret;
        }
    }

    public static void main(String[] args) {
        new CF410AEasyPalin().runIO();
    }
}