Problem: There are N cells arranged in a row, numbered 1, 2, \ldots, N from left to right.

Tak lives in these cells and is currently on Cell 1. He is trying to reach Cell N by using the procedure described below.

You are given an integer K that is less than or equal to 10, and K non-intersecting segments [L_1, R_1], [L_2, R_2], \ldots, [L_K, R_K]. Let S be the union of these K segments. Here, the segment [l, r] denotes the set consisting of all integers i that satisfy l \leq i \leq r.

* When you are on Cell i, pick an integer d from S and move to Cell i + d. You cannot move out of the cells.



To help Tak, find the number of ways to go to Cell N, modulo 998244353.

Constraints

* 2 \leq N \leq 2 \times 10^5
* 1 \leq K \leq \min(N, 10)
* 1 \leq L_i \leq R_i \leq N
* [L_i, R_i] and [L_j, R_j] do not intersect (i \neq j)
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N K
L_1 R_1
L_2 R_2
:
L_K R_K


Output

Print the number of ways for Tak to go from Cell 1 to Cell N, modulo 998244353.

Examples

Input

5 2
1 1
3 4


Output

4


Input

5 2
3 3
5 5


Output

0


Input

5 1
1 2


Output

5


Input

60 3
5 8
1 3
10 15


Output

221823067

Solution (in CPP):

Solution:
#include<bits/stdc++.h>
using namespace std;
#define rep(i,n) for(int i=0;i<(int)(n);i++)
using ll=long long;
const int MOD=998244353;
int main(){
    int n,k;
    cin>>n>>k;
    vector<int> l(k),r(k),dp(n+5),sum(n+5);
    rep(i,k){
      cin>>l[i]>>r[i];
    }
  
    dp[1]++;sum[1]++;
    for(int i=2;i<=n;i++){
        rep(j,k){
            int a=i-r[j];
            int b=i-l[j];
            a=max(a,1);
            if(b<0) continue;
            dp[i]+=sum[b]-sum[a-1];
            dp[i]=(dp[i]%MOD+MOD)%MOD;
        }
        sum[i]=dp[i]+sum[i-1];
        sum[i]=(sum[i]%MOD+MOD)%MOD;
    }
    cout<<(dp[n]+MOD)%MOD<<endl;
    return 0;
}