Problem: Mashmokh's boss, Bimokh, didn't like Mashmokh. So he fired him. Mashmokh decided to go to university and participate in ACM instead of finding a new job. He wants to become a member of Bamokh's team. In order to join he was given some programming tasks and one week to solve them. Mashmokh is not a very experienced programmer. Actually he is not a programmer at all. So he wasn't able to solve them. That's why he asked you to help him with these tasks. One of these tasks is the following.

A sequence of l integers b1, b2, ..., bl (1 ≤ b1 ≤ b2 ≤ ... ≤ bl ≤ n) is called good if each number divides (without a remainder) by the next number in the sequence. More formally <image> for all i (1 ≤ i ≤ l - 1).

Given n and k find the number of good sequences of length k. As the answer can be rather large print it modulo 1000000007 (109 + 7).

Input

The first line of input contains two space-separated integers n, k (1 ≤ n, k ≤ 2000).

Output

Output a single integer — the number of good sequences of length k modulo 1000000007 (109 + 7).

Examples

Input

3 2


Output

5


Input

6 4


Output

39


Input

2 1


Output

2

Note

In the first sample the good sequences are: [1, 1], [2, 2], [3, 3], [1, 2], [1, 3].

Solution (in PYTHON3):

Solution:
n, k = map(int, input().split())
ost = 1000000007

a_num = []

for i in range(1, 2001):
    x = []
    for j in range(1, i + 1):
        if i % j == 0:
            x.append(j)
    a_num.append(x)

dp = []

for i in range(0, k + 1):
    x = []
    for j in range(0, n + 1):
        x.append(0)
    dp.append(x)

for i in range(1, n + 1):
    dp[1][i] = 1

for i in range(1, k + 1):
    for j in range(1, n + 1):
        for u in a_num[j - 1]:
            dp[i][j] += dp[i - 1][u]
            if dp[i][j] >= ost:
                dp[i][j] -= ost

ans = 0

for i in range(1, n + 1):
    ans += dp[k][i]
    if ans >= ost:
        ans -= ost

print(ans)