Problem: Let's say string s has period k if s_i = s_{i + k} for all i from 1 to |s| - k (|s| means length of string s) and k is the minimum positive integer with this property.

Some examples of a period: for s="0101" the period is k=2, for s="0000" the period is k=1, for s="010" the period is k=2, for s="0011" the period is k=4.

You are given string t consisting only of 0's and 1's and you need to find such string s that:

  1. String s consists only of 0's and 1's; 
  2. The length of s doesn't exceed 2 ⋅ |t|; 
  3. String t is a subsequence of string s; 
  4. String s has smallest possible period among all strings that meet conditions 1—3. 



Let us recall that t is a subsequence of s if t can be derived from s by deleting zero or more elements (any) without changing the order of the remaining elements. For example, t="011" is a subsequence of s="10101".

Input

The first line contains single integer T (1 ≤ T ≤ 100) — the number of test cases.

Next T lines contain test cases — one per line. Each line contains string t (1 ≤ |t| ≤ 100) consisting only of 0's and 1's.

Output

Print one string for each test case — string s you needed to find. If there are multiple solutions print any one of them.

Example

Input


4
00
01
111
110


Output


00
01
11111
1010

Note

In the first and second test cases, s = t since it's already one of the optimal solutions. Answers have periods equal to 1 and 2, respectively.

In the third test case, there are shorter optimal solutions, but it's okay since we don't need to minimize the string s. String s has period equal to 1.

Solution (in PYTHON3):

Solution:
t = int(input())
for _ in range(t):
    a = input()
    if len(a) < 3:
        print(a)
    else:
        flag = False
        for i in range(1, len(a)):
            if a[i] != a[0]:
                flag = True
        if (flag):
            ans = ''
            for i in range(len(a)-1):
                if a[i] == a[i+1]:
                    if a[i] == '0':
                        ans+='01'
                    else:
                        ans+='10'
                else:
                    ans+=a[i]
            if (len(ans)%2==0):
                if a[-1] == '0':
                        ans += '01'
                else:
                    ans+='10'
            else:
                ans+=a[-1]
            print(ans)
        else:
            print(a)