Problem: One day Vasya was solving arithmetical problems. He wrote down an expression a + b = c in his notebook. When the teacher checked Vasya's work it turned out that Vasya had solved the problem incorrectly. Now Vasya tries to find excuses. He says that he simply forgot to write down several digits in numbers a, b and c, but he can't remember what numbers they actually were. Help Vasya, find such numbers x, y and z, with which the following conditions are met: 

  * x + y = z, 
  * from the expression x + y = z several digits can be erased in such a way that the result will be a + b = c, 
  * the expression x + y = z should have the minimal length. 

Input

The first and only input line contains the expression a + b = c (1 ≤ a, b, c ≤ 106, a, b and c don't contain leading zeroes) which is the expression Vasya wrote down.

Output

Print the correct expression x + y = z (x, y and z are non-negative numbers without leading zeroes). The expression a + b = c must be met in x + y = z as a subsequence. The printed solution should have the minimal possible number of characters. If there are several such solutions, you can print any of them.

Examples

Input

2+4=5


Output

21+4=25


Input

1+1=3


Output

1+31=32


Input

1+1=2


Output

1+1=2

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
struct fastIO {
  inline fastIO operator>>(int& num) {
    num = 0;
    char c = getchar();
    while (c != '-' && (c < '0' || c > '9')) c = getchar();
    bool foo = 0;
    if (c == '-') {
      foo = 1;
      c = getchar();
    }
    while (c >= '0' && c <= '9') {
      num = (num << 3) + (num << 1) + c - '0';
      c = getchar();
    }
    if (foo) num = -num;
    return *this;
  }
  inline fastIO operator>>(long long& num) {
    num = 0;
    char c = getchar();
    while (c != '-' && (c < '0' || c > '9')) c = getchar();
    bool foo = 0;
    if (c == '-') {
      foo = 1;
      c = getchar();
    }
    while (c >= '0' && c <= '9') {
      num = (num << 3) + (num << 1) + c - '0';
      c = getchar();
    }
    if (foo) num = -num;
    return *this;
  }
  inline fastIO operator>>(float& num) {
    scanf("%f", &num);
    return *this;
  }
  inline fastIO operator>>(double& num) {
    scanf("%lf", &num);
    return *this;
  }
  inline fastIO operator>>(long double& num) {
    scanf("%Lf", &num);
    return *this;
  }
  inline fastIO operator>>(char& num) {
    num = getchar();
    while (num == ' ' || num == '\n') num = getchar();
    return *this;
  }
  inline fastIO operator>>(char* num) {
    int cnt = 0;
    char c = getchar();
    while (c == ' ' || c == '\n') c = getchar();
    while (c != ' ' && c != '\n') {
      num[cnt++] = c;
      c = getchar();
    }
    num[cnt] = 0;
    return *this;
  }
  inline fastIO operator>>(string& num) {
    cin >> num;
    return *this;
  }
  inline void printInt(const int& num) {
    if (num < 10) {
      putchar(num + '0');
      return;
    }
    printInt(num / 10);
    putchar((num % 10) + '0');
  }
  inline void printINT(const long long& num) {
    if (num < 10) {
      putchar(num + '0');
      return;
    }
    printINT(num / 10);
    putchar((num % 10) + '0');
  }
  inline fastIO operator<<(const int& num) {
    if (num < 0)
      putchar('-'), printInt(-num);
    else
      printInt(num);
    return *this;
  }
  inline fastIO operator<<(const long long& num) {
    if (num < 0)
      putchar('-'), printINT(-num);
    else
      printINT(num);
    return *this;
  }
  inline fastIO operator<<(const float& num) {
    printf("%.10f", num);
    return *this;
  }
  inline fastIO operator<<(const double& num) {
    printf("%.16lf", num);
    return *this;
  }
  inline fastIO operator<<(const long double& num) {
    printf("%.20Lf", num);
    return *this;
  }
  inline fastIO operator<<(const char& num) {
    putchar(num);
    return *this;
  }
  inline fastIO operator<<(const char* num) {
    for (int i = 0; num[i]; i++) putchar(num[i]);
    return *this;
  }
  inline fastIO operator<<(const string& num) {
    cout << num;
    return *this;
  }
} fio;
int x, y, z;
long long mina, minb;
long long minlen = 15;
long long mii10[20];
void dfs(long long a, long long b, long long c, long long A, long long B,
         long long jw, long long wht, long long len) {
  if (len >= minlen) {
    return;
  }
  if (!a && !b && !c && !jw) {
    minlen = len;
    mina = A;
    minb = B;
    return;
  }
  if (!c) {
    long long num = a + b + jw;
    int wei = 0;
    while (num) {
      num /= 10;
      wei++;
    }
    dfs(0, 0, 0, A + mii10[wht] * a, B + mii10[wht] * b, 0, wht, len + wei);
  } else if ((a + b + jw) % 10 == c % 10) {
    dfs(a / 10, b / 10, c / 10, A + mii10[wht] * (a % 10),
        B + mii10[wht] * (b % 10), (jw + a % 10 + b % 10) / 10, wht + 1, len);
  } else {
    dfs(a * 10 + (c - b % 10 - jw + 10) % 10, b, c, A, B, jw, wht, len + 1);
    dfs(a, b * 10 + (c - a % 10 - jw + 10) % 10, c, A, B, jw, wht, len + 1);
    dfs(a, b, c * 10 + (a + b + jw) % 10, A, B, jw, wht, len + 1);
  }
}
int main() {
  scanf("%d+%d=%d", &x, &y, &z);
  mii10[0] = 1;
  for (int i = 1; i < 19; i++) {
    mii10[i] = mii10[i - 1] * 10;
  }
  dfs(x, y, z, 0, 0, 0, 0, 0);
  printf("%I64d+%I64d=%I64d", mina, minb, mina + minb);
  return 0;
}