Problem: Let's define logical OR as an operation on two logical values (i. e. values that belong to the set {0, 1}) that is equal to 1 if either or both of the logical values is set to 1, otherwise it is 0. We can define logical OR of three or more logical values in the same manner:

<image> where <image> is equal to 1 if some ai = 1, otherwise it is equal to 0.

Nam has a matrix A consisting of m rows and n columns. The rows are numbered from 1 to m, columns are numbered from 1 to n. Element at row i (1 ≤ i ≤ m) and column j (1 ≤ j ≤ n) is denoted as Aij. All elements of A are either 0 or 1. From matrix A, Nam creates another matrix B of the same size using formula:

<image>.

(Bij is OR of all elements in row i and column j of matrix A)

Nam gives you matrix B and challenges you to guess matrix A. Although Nam is smart, he could probably make a mistake while calculating matrix B, since size of A can be large.

Input

The first line contains two integer m and n (1 ≤ m, n ≤ 100), number of rows and number of columns of matrices respectively.

The next m lines each contain n integers separated by spaces describing rows of matrix B (each element of B is either 0 or 1).

Output

In the first line, print "NO" if Nam has made a mistake when calculating B, otherwise print "YES". If the first line is "YES", then also print m rows consisting of n integers representing matrix A that can produce given matrix B. If there are several solutions print any one.

Examples

Input

2 2
1 0
0 0


Output

NO


Input

2 3
1 1 1
1 1 1


Output

YES
1 1 1
1 1 1


Input

2 3
0 1 0
1 1 1


Output

YES
0 0 0
0 1 0

Solution (in JAVA):

Solution:
import java.util.*;
import java.io.*;
public class codeforces
{
    public static void main(String args[])throws IOException
    {
       Scanner sc=new Scanner(System.in);
       
       int n=sc.nextInt();
       int m=sc.nextInt();
       int arr[][]=new int[n][m];
       int ans[][]=new int[n][m];
       int check[][]=new int[n][m];
       for(int i = 0 ;i<n;i++)
       Arrays.fill(ans[i],1);
       
       for(int i = 0 ;i<n;i++)
       {
           for(int j=0;j<m;j++)
           arr[i][j]=sc.nextInt();
        }
       for(int i = 0 ;i<n;i++)
       {
           for(int j=0;j<m;j++)
           {
               if(arr[i][j]==0)
               {
                   for(int k=0;k<n;k++)
                   ans[k][j]=0;
                   for(int k=0;k<m;k++)
                   ans[i][k]=0;
               }
           }
       }
       for(int i = 0 ;i<n;i++)
       {
           for(int j=0;j<m;j++)
           {
               if(ans[i][j]==1)
               {
                   for(int k=0;k<n;k++)
                   check[k][j]=1;
                   for(int k=0;k<m;k++)
                   check[i][k]=1;
               }
           }
       }
       for(int i = 0 ;i<n;i++)
       {
           for(int j=0;j<m;j++)
           {
               if(arr[i][j]!=check[i][j])
               {
                   System.out.println("NO");
                   System.exit(0);
               }
           }
       }
       System.out.println("YES");
       for(int i = 0 ;i<n;i++)
       {
           for(int j=0;j<m;j++)
           {
               System.out.print(ans[i][j]+" ");
           }
           System.out.println();
       }
    }
}