Problem: Let's define logical OR as an operation on two logical values (i. e. values that belong to the set {0, 1}) that is equal to 1 if either or both of the logical values is set to 1, otherwise it is 0. We can define logical OR of three or more logical values in the same manner:

<image> where <image> is equal to 1 if some ai = 1, otherwise it is equal to 0.

Nam has a matrix A consisting of m rows and n columns. The rows are numbered from 1 to m, columns are numbered from 1 to n. Element at row i (1 ≤ i ≤ m) and column j (1 ≤ j ≤ n) is denoted as Aij. All elements of A are either 0 or 1. From matrix A, Nam creates another matrix B of the same size using formula:

<image>.

(Bij is OR of all elements in row i and column j of matrix A)

Nam gives you matrix B and challenges you to guess matrix A. Although Nam is smart, he could probably make a mistake while calculating matrix B, since size of A can be large.

Input

The first line contains two integer m and n (1 ≤ m, n ≤ 100), number of rows and number of columns of matrices respectively.

The next m lines each contain n integers separated by spaces describing rows of matrix B (each element of B is either 0 or 1).

Output

In the first line, print "NO" if Nam has made a mistake when calculating B, otherwise print "YES". If the first line is "YES", then also print m rows consisting of n integers representing matrix A that can produce given matrix B. If there are several solutions print any one.

Examples

Input

2 2
1 0
0 0


Output

NO


Input

2 3
1 1 1
1 1 1


Output

YES
1 1 1
1 1 1


Input

2 3
0 1 0
1 1 1


Output

YES
0 0 0
0 1 0

Solution (in PYTHON3):

Solution:
flag=0
flg_one=0
zeros=[]
ones=[]
import sys
n,m=map(int,input().split())
lst=[[]]*n

for i in range(n):
    x=list(map(int,input().split()))
    if 0 in x:
        lst[i]=[0]*m
        for u in range(m):
                if x[u] ==1:
                    flag=1
                    ones.append(u)
                else:
                   zeros.append(u) 
                   
    else:
        lst[i]=[1]*m   
        flg_one=1
       # ones=list(range(m))
        
ones = list(set(ones))          
zeros = list(set(zeros))       
#print('zeros=',zeros)
if (flag==1 and flg_one==0) or (flg_one==1 and len(zeros)==m):
    print("NO")
else:

   
    for q in range(n):
        if lst[q][0]==1:
            for p in range(len(zeros)):
                lst[q][zeros[p]]=0
   
    for i in range(len(ones)):
                 co=0
                 for h in range(n):
                             if lst[h][ones[i]]!=1:
                                     co+=1
                 if co==n:
                     print("NO")
                     sys.exit(0)  

    print("YES") 
    for i in range(n):                
            print(*lst[i])