Problem: There are N cells arranged in a row, numbered 1, 2, \ldots, N from left to right.

Tak lives in these cells and is currently on Cell 1. He is trying to reach Cell N by using the procedure described below.

You are given an integer K that is less than or equal to 10, and K non-intersecting segments [L_1, R_1], [L_2, R_2], \ldots, [L_K, R_K]. Let S be the union of these K segments. Here, the segment [l, r] denotes the set consisting of all integers i that satisfy l \leq i \leq r.

* When you are on Cell i, pick an integer d from S and move to Cell i + d. You cannot move out of the cells.



To help Tak, find the number of ways to go to Cell N, modulo 998244353.

Constraints

* 2 \leq N \leq 2 \times 10^5
* 1 \leq K \leq \min(N, 10)
* 1 \leq L_i \leq R_i \leq N
* [L_i, R_i] and [L_j, R_j] do not intersect (i \neq j)
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N K
L_1 R_1
L_2 R_2
:
L_K R_K


Output

Print the number of ways for Tak to go from Cell 1 to Cell N, modulo 998244353.

Examples

Input

5 2
1 1
3 4


Output

4


Input

5 2
3 3
5 5


Output

0


Input

5 1
1 2


Output

5


Input

60 3
5 8
1 3
10 15


Output

221823067

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;


#define int long long 

const int N = 4e5 + 7, mod = 998244353;

int dp[N], cum[N], L[N], R[N];

int32_t main() {
	ios_base :: sync_with_stdio(0); cin.tie(0); cout.tie(0);
	int n, k; cin >> n >> k;
	for(int i = 1; i <= k; ++i) cin >> L[i] >> R[i];

	dp[n] = 1;
	for(int i = n - 1; i >= 1; i--) {
		for(int j = 1; j <= k; j++) {
			int l = L[j], r = R[j];
			if(i + l <= n) {
				dp[i] += dp[i + l] + mod - dp[i + r + 1] % mod;
				dp[i] %= mod;
			}
		}
		dp[i] = (dp[i] + dp[i + 1]) % mod;
	}
	cout << (dp[1] + mod - dp[2]) % mod;
}