Problem: You are given n arrays a_1, a_2, ..., a_n; each array consists of exactly m integers. We denote the y-th element of the x-th array as a_{x, y}.

You have to choose two arrays a_i and a_j (1 ≤ i, j ≤ n, it is possible that i = j). After that, you will obtain a new array b consisting of m integers, such that for every k ∈ [1, m] b_k = max(a_{i, k}, a_{j, k}).

Your goal is to choose i and j so that the value of min _{k = 1}^{m} b_k is maximum possible.

Input

The first line contains two integers n and m (1 ≤ n ≤ 3 ⋅ 10^5, 1 ≤ m ≤ 8) — the number of arrays and the number of elements in each array, respectively.

Then n lines follow, the x-th line contains the array a_x represented by m integers a_{x, 1}, a_{x, 2}, ..., a_{x, m} (0 ≤ a_{x, y} ≤ 10^9).

Output

Print two integers i and j (1 ≤ i, j ≤ n, it is possible that i = j) — the indices of the two arrays you have to choose so that the value of min _{k = 1}^{m} b_k is maximum possible. If there are multiple answers, print any of them.

Example

Input


6 5
5 0 3 1 2
1 8 9 1 3
1 2 3 4 5
9 1 0 3 7
2 3 0 6 3
6 4 1 7 0


Output


1 5

Solution (in PYTHON3):

Solution:
n, m = map(int, input().split())
a = [list(map(int, input().split())) for i in range(n)]
ans = []


def check(mid: int) -> bool:
    global ans
    dic = {}
    for i in range(n):
        bit = 0
        for j in range(m):
            if a[i][j] >= mid:
                bit += 1
            bit <<= 1
        dic[bit >> 1] = i
    for x, idx in dic.items():
        for y, idy in dic.items():
            if x | y == 2**m-1:
                ans = idx + 1, idy + 1
                return True
    return False


le = 0
ri = int(1e9)
while le <= ri:
    mid = (le + ri) >> 1
    if check(mid):
        le = mid + 1
    else:
        ri = mid - 1
print(ans[0], ans[1])