Problem: Let's define logical OR as an operation on two logical values (i. e. values that belong to the set {0, 1}) that is equal to 1 if either or both of the logical values is set to 1, otherwise it is 0. We can define logical OR of three or more logical values in the same manner:

<image> where <image> is equal to 1 if some ai = 1, otherwise it is equal to 0.

Nam has a matrix A consisting of m rows and n columns. The rows are numbered from 1 to m, columns are numbered from 1 to n. Element at row i (1 ≤ i ≤ m) and column j (1 ≤ j ≤ n) is denoted as Aij. All elements of A are either 0 or 1. From matrix A, Nam creates another matrix B of the same size using formula:

<image>.

(Bij is OR of all elements in row i and column j of matrix A)

Nam gives you matrix B and challenges you to guess matrix A. Although Nam is smart, he could probably make a mistake while calculating matrix B, since size of A can be large.

Input

The first line contains two integer m and n (1 ≤ m, n ≤ 100), number of rows and number of columns of matrices respectively.

The next m lines each contain n integers separated by spaces describing rows of matrix B (each element of B is either 0 or 1).

Output

In the first line, print "NO" if Nam has made a mistake when calculating B, otherwise print "YES". If the first line is "YES", then also print m rows consisting of n integers representing matrix A that can produce given matrix B. If there are several solutions print any one.

Examples

Input

2 2
1 0
0 0


Output

NO


Input

2 3
1 1 1
1 1 1


Output

YES
1 1 1
1 1 1


Input

2 3
0 1 0
1 1 1


Output

YES
0 0 0
0 1 0

Solution (in PYTHON3):

Solution:
# a simple parser for python. use get_number() and get_word() to read
def main():
    def parser():
        while 1:
            data = list(input().split(' '))
            for number in data:
                if len(number) > 0:
                    yield(number)

    input_parser = parser()
    gets = lambda: next(input_parser)

    def getNum():
        data = gets()
        try:
            return int(data)
        except ValueError:
            return float(data)
    # ---------input---------
    n, m = getNum(), getNum()
    RANGN = range(n)
    RANGM = range(m)
    b = [[] for _ in RANGN]
    a = [[ 1 for _ in RANGM]for _ in RANGN]
    for y in RANGN:
        for x in RANGM:
            v = getNum()
            b[y].append(v)
            if ( v == 0 ):
                for i in RANGM: a[y][i] = 0
                for i in RANGN: a[i][x] = 0
                
    for y in RANGN:
        for x in RANGM:
            ror = any(a[y]) or any({a[i][x] for i in RANGN}) 
            if( ror != b[y][x] ):
                print('NO')
                return

    print('YES')
    for y in RANGN:
        for x in RANGM:    
            print(a[y][x],end=' \n'[x==m-1])

if __name__ == "__main__":
    main()