Problem: You are a rebel leader and you are planning to start a revolution in your country. But the evil Government found out about your plans and set your punishment in the form of correctional labor.

You must paint a fence which consists of 10^{100} planks in two colors in the following way (suppose planks are numbered from left to right from 0): 

  * if the index of the plank is divisible by r (such planks have indices 0, r, 2r and so on) then you must paint it red; 
  * if the index of the plank is divisible by b (such planks have indices 0, b, 2b and so on) then you must paint it blue; 
  * if the index is divisible both by r and b you can choose the color to paint the plank; 
  * otherwise, you don't need to paint the plank at all (and it is forbidden to spent paint on it). 



Furthermore, the Government added one additional restriction to make your punishment worse. Let's list all painted planks of the fence in ascending order: if there are k consecutive planks with the same color in this list, then the Government will state that you failed the labor and execute you immediately. If you don't paint the fence according to the four aforementioned conditions, you will also be executed.

The question is: will you be able to accomplish the labor (the time is not important) or the execution is unavoidable and you need to escape at all costs.

Input

The first line contains single integer T (1 ≤ T ≤ 1000) — the number of test cases.

The next T lines contain descriptions of test cases — one per line. Each test case contains three integers r, b, k (1 ≤ r, b ≤ 10^9, 2 ≤ k ≤ 10^9) — the corresponding coefficients.

Output

Print T words — one per line. For each test case print REBEL (case insensitive) if the execution is unavoidable or OBEY (case insensitive) otherwise.

Example

Input


4
1 1 2
2 10 4
5 2 3
3 2 2


Output


OBEY
REBEL
OBEY
OBEY

Solution (in JAVA):

Solution:
//package main;

import java.io.*;
import java.util.*;
import java.math.*;

public final class Main {
    BufferedReader br;
    StringTokenizer stk;
    
    public static void main(String[] args) throws Exception {
        new Main().run();
    }
    
    {
        stk = null;
        br = new BufferedReader(new InputStreamReader(System.in));
    }
    
    boolean tests = true;
    
    long mod = 1000_000_000 + 7;
    StringBuilder res = new StringBuilder(1000005);
    
    void run() throws Exception {
        int t = tests ? ni() : 1;
        for(int i = 1; i <= t; i++) {
            go(i);
        }
        System.out.print(res.length() == 0 ? "" : res);
    }
    
    void go(int T) throws Exception {
        long r = nl();
        long b = nl();
        long k = nl();
        
        if(r > b) {
            long temp = r;
            r = b;
            b = temp;
        }
        
        long g = gcd(r, b);
        r /= g;
        b /= g;
        
        if((long)Math.ceil((double)(b - 1)/ (double)r) >= k) {
            res.append("REBEL\n");
        } else {
            res.append("OBEY\n");
        }
    }
    
    long gcd(long a, long b) {
        return BigInteger.valueOf(a).gcd(BigInteger.valueOf(b)).longValue();
    }
    
    //Reader & Writer
    String nt() throws Exception {
        if (stk == null || !stk.hasMoreTokens())
            stk = new StringTokenizer(br.readLine(), " ");
        return stk.nextToken();
    }

    char[] nc() throws Exception {
        return nt().toCharArray();
    }

    int ni() throws Exception {
        return Integer.parseInt(nt());
    }

    long nl() throws Exception {
        return Long.parseLong(nt());
    }
    
    double nd() throws Exception {
        return Double.parseDouble(nt());
    }
    
    //Some Misc methods
    long get(int l, int r, long[] a) {
        return l == 0 ? a[r] : a[r] - a[l - 1];
    }
    
    void shuffle(long[] a) {
        Random r = new Random();
        for(int i = 0; i < a.length; i++) {
            int idx = r.nextInt(a.length);
            long temp = a[i];
            a[i] = a[idx];
            a[idx] = temp;
        }
    }
    
    void reverse(long[] a) {
        for(int i = 0, j = a.length - 1; i < j; i++, j--) {
            long temp = a[i];
            a[i] = a[j];
            a[j] = temp;
        }
    }
    
    void print(int[] a) {
        System.out.println(Arrays.toString(a));
    }
    
    void print(long[] a) {
        System.out.println(Arrays.toString(a));
    }
}