Problem: This is the easy version of the problem. The difference is the constraint on the sum of lengths of strings and the number of test cases. You can make hacks only if you solve all versions of this task.

You are given a string s, consisting of lowercase English letters. Find the longest string, t, which satisfies the following conditions: 

  * The length of t does not exceed the length of s. 
  * t is a palindrome. 
  * There exists two strings a and b (possibly empty), such that t = a + b ( "+" represents concatenation), and a is prefix of s while b is suffix of s. 

Input

The input consists of multiple test cases. The first line contains a single integer t (1 ≤ t ≤ 1000), the number of test cases. The next t lines each describe a test case.

Each test case is a non-empty string s, consisting of lowercase English letters.

It is guaranteed that the sum of lengths of strings over all test cases does not exceed 5000.

Output

For each test case, print the longest string which satisfies the conditions described above. If there exists multiple possible solutions, print any of them.

Example

Input


5
a
abcdfdcecba
abbaxyzyx
codeforces
acbba


Output


a
abcdfdcba
xyzyx
c
abba

Note

In the first test, the string s = "a" satisfies all conditions.

In the second test, the string "abcdfdcba" satisfies all conditions, because:

  * Its length is 9, which does not exceed the length of the string s, which equals 11. 
  * It is a palindrome. 
  * "abcdfdcba" = "abcdfdc" + "ba", and "abcdfdc" is a prefix of s while "ba" is a suffix of s. 



It can be proven that there does not exist a longer string which satisfies the conditions.

In the fourth test, the string "c" is correct, because "c" = "c" + "" and a or b can be empty. The other possible solution for this test is "s".

Solution (in JAVA):

Solution:
import java.io.OutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.PrintWriter;
import java.util.StringTokenizer;
import java.io.IOException;
import java.io.BufferedReader;
import java.io.FileReader;
import java.io.InputStreamReader;
import java.io.InputStream;

/**
 * Built using CHelper plug-in
 * Actual solution is at the top
 */
public class Main {
    public static void main(String[] args) {
        InputStream inputStream = System.in;
        OutputStream outputStream = System.out;
        Scanner in = new Scanner(inputStream);
        PrintWriter out = new PrintWriter(outputStream);
        D2PrefixSuffixPalindromeHardVersion solver = new D2PrefixSuffixPalindromeHardVersion();
        solver.solve(1, in, out);
        out.close();
    }

    static class D2PrefixSuffixPalindromeHardVersion {
        public void solve(int testNumber, Scanner sc, PrintWriter pw) {
            int t = sc.nextInt();
            while (t-- > 0) {
                String s = sc.nextLine();
                char[] arr = s.toCharArray();
                int n = arr.length;
                int ii = 0;
                int j = n - 1;
                StringBuilder ans = new StringBuilder();
                StringBuilder ans1 = new StringBuilder();
                while (ii < j && arr[ii] == arr[j]) {
                    ans1.append(arr[ii]);
                    ans.append(arr[ii]);
                    ii++;
                    j--;
                }
                String tmp = s.substring(ii, j + 1);
                int k = tmp.length();
                StringBuilder tt = new StringBuilder(tmp);
                tt.reverse();
                String tmp1 = tmp + "#" + tt.toString();
                String tmp2 = tt.toString() + "#" + tmp;
                int[] fail = compfail(tmp1);
                int max = fail[fail.length - 1];

                int[] fail1 = compfail(tmp2);
                int max1 = fail1[fail1.length - 1];

//            pw.println(Arrays.toString(z1));
//            pw.println(max +" "+ max1);
                if (max >= max1)
                    for (int i = 0; i < max; i++) {
                        ans.append(tmp.charAt(i));
                    }
                else
                    for (int i = k - 1, c = 0; c < max1; c++) {
                        ans.append(tmp.charAt(i));
                        i--;
                    }
                ans.append(ans1.reverse().toString());
                pw.println(ans.toString());

            }

        }

        int[] compfail(String s) {
            int m = s.length();
            int[] tmp = new int[m];
            int k = 0;
            for (int i = 1; i < m; i++) {
                while (k > 0 && s.charAt(i) != s.charAt(k)) {
                    k = tmp[k - 1];
                }
                if (s.charAt(i) == s.charAt(k)) tmp[i] = ++k;
                else tmp[i] = k;
            }
            return tmp;
        }

    }

    static class Scanner {
        StringTokenizer st;
        BufferedReader br;

        public Scanner(FileReader r) {
            br = new BufferedReader(r);
        }

        public Scanner(InputStream s) {
            br = new BufferedReader(new InputStreamReader(s));
        }

        public String next() {
            while (st == null || !st.hasMoreTokens()) {
                try {
                    st = new StringTokenizer(br.readLine());
                } catch (IOException e) {
                    throw new RuntimeException(e);
                }
            }
            return st.nextToken();
        }

        public int nextInt() {
            return Integer.parseInt(next());
        }

        public String nextLine() {
            try {
                return br.readLine();
            } catch (Exception e) {
                throw new RuntimeException(e);
            }
        }

    }
}