Problem: Jafar has n cans of cola. Each can is described by two integers: remaining volume of cola ai and can's capacity bi (ai ≤  bi).

Jafar has decided to pour all remaining cola into just 2 cans, determine if he can do this or not!

Input

The first line of the input contains one integer n (2 ≤ n ≤ 100 000) — number of cola cans.

The second line contains n space-separated integers a1, a2, ..., an (0 ≤ ai ≤ 109) — volume of remaining cola in cans.

The third line contains n space-separated integers that b1, b2, ..., bn (ai ≤ bi ≤ 109) — capacities of the cans.

Output

Print "YES" (without quotes) if it is possible to pour all remaining cola in 2 cans. Otherwise print "NO" (without quotes).

You can print each letter in any case (upper or lower).

Examples

Input

2
3 5
3 6


Output

YES


Input

3
6 8 9
6 10 12


Output

NO


Input

5
0 0 5 0 0
1 1 8 10 5


Output

YES


Input

4
4 1 0 3
5 2 2 3


Output

YES

Note

In the first sample, there are already 2 cans, so the answer is "YES".

Solution (in JAVA):

Solution:
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Collections;
import java.util.List;
import java.util.Scanner;

public class A892 {
    public static void main(String[] args) {
//        Scanner in = new Scanner(System.in);
//
//        Integer n = in.nextInt();
//        Integer remain = 0;
//        List<Integer> b = new ArrayList<>();
//        for (int i = 0; i < n; i++) {
//            remain += in.nextInt();
//        }
//        for (int i = 0; i < n; i++) {
//            b.add(in.nextInt());
//        }
//
//        Collections.sort(b);
////        System.out.println(b);
//        int maxSum = b.get(n - 1) + b.get(n - 2);
//        String res = maxSum >= remain ? "YES" : "NO";
//        System.out.println(res);
        Scanner scan=new Scanner(System.in);
        int n=scan.nextInt();
        long s=0;
        for(int i=0;i<n;i++) s+=scan.nextInt();
        int[] a=new int[n];
        for(int i=0;i<n;i++) a[i]=scan.nextInt();
        Arrays.sort(a);
        System.out.println(s<=a[n-2]+a[n-1]?"YES":"NO");

    }
}