Problem: Snuke is introducing a robot arm with the following properties to his factory:

* The robot arm consists of m sections and m+1 joints. The sections are numbered 1, 2, ..., m, and the joints are numbered 0, 1, ..., m. Section i connects Joint i-1 and Joint i. The length of Section i is d_i.
* For each section, its mode can be specified individually. There are four modes: `L`, `R`, `D` and `U`. The mode of a section decides the direction of that section. If we consider the factory as a coordinate plane, the position of Joint i will be determined as follows (we denote its coordinates as (x_i, y_i)):
* (x_0, y_0) = (0, 0).
* If the mode of Section i is `L`, (x_{i}, y_{i}) = (x_{i-1} - d_{i}, y_{i-1}).
* If the mode of Section i is `R`, (x_{i}, y_{i}) = (x_{i-1} + d_{i}, y_{i-1}).
* If the mode of Section i is `D`, (x_{i}, y_{i}) = (x_{i-1}, y_{i-1} - d_{i}).
* If the mode of Section i is `U`, (x_{i}, y_{i}) = (x_{i-1}, y_{i-1} + d_{i}).



Snuke would like to introduce a robot arm so that the position of Joint m can be matched with all of the N points (X_1, Y_1), (X_2, Y_2), ..., (X_N, Y_N) by properly specifying the modes of the sections. Is this possible? If so, find such a robot arm and how to bring Joint m to each point (X_j, Y_j).

Constraints

* All values in input are integers.
* 1 \leq N \leq 1000
* -10^9 \leq X_i \leq 10^9
* -10^9 \leq Y_i \leq 10^9

Input

Input is given from Standard Input in the following format:


N
X_1 Y_1
X_2 Y_2
:
X_N Y_N


Output

If the condition can be satisfied, follow the following format. If the condition cannot be satisfied, print `-1`.


m
d_1 d_2 ... d_m
w_1
w_2
:
w_N


m and d_i are the configurations of the robot arm. Refer to the problem statement for what each of them means. Here, 1 \leq m \leq 40 and 1 \leq d_i \leq 10^{12} must hold. Also, m and d_i must all be integers.

w_j is a string of length m that represents the way to bring Joint m of the robot arm to point (X_j, Y_j). The i-th character of w_j should be one of the letters `L`, `R`, `D` and `U`, representing the mode of Section i.

Examples

Input

3
-1 0
0 3
2 -1


Output

2
1 2
RL
UU
DR


Input

5
0 0
1 0
2 0
3 0
4 0


Output

-1


Input

2
1 1
1 1


Output

2
1 1
RU
UR


Input

3
-7 -3
7 3
-3 -7


Output

5
3 1 4 1 5
LRDUL
RDULR
DULRD

Solution (in CPP):

Solution:
#include <iostream>
#include <vector>
using namespace std;

int main() {
    ios::sync_with_stdio(false); cin.tie(0);
    int n; cin >> n;
    long x[1010], y[1010];
    for(int i=0; i < n; ++i) cin >> x[i] >> y[i];

    // parity check
    bool parity = (abs(x[0]) + abs(y[0])) & 1;
    for(int i = 1; i < n; ++i) {
        bool tmp = (abs(x[i]) + abs(y[i])) & 1;
        if(parity != tmp) {
            cout << -1 << endl;
            return 0;
        }
    }

    vector<long> d;
    // length
    for(int i = 30; i >= 0; --i) d.push_back(1L<<i);
    if(!parity) d.push_back(1);

    cout << d.size() << '\n';
    for(int i = 0; i < d.size(); ++i) cout << d[i] << (i == d.size()-1 ? '\n' : ' ');

    for(int i = 0; i < n; ++i) {
        for(int j = 0; j < d.size(); ++j) {
            if(abs(x[i]) >= abs(y[i])) {
                if(x[i] < 0) {
                    cout << 'L';
                    x[i] += d[j];
                } else {
                    cout << 'R';
                    x[i] -= d[j];
                }
            } else {
                if(y[i] < 0) {
                    cout << 'D';
                    y[i] += d[j];
                } else {
                    cout << 'U';
                    y[i] -= d[j];
                }
            }
        }
        cout << '\n';
    }
    return 0;
}