Problem: Bachgold problem is very easy to formulate. Given a positive integer n represent it as a sum of maximum possible number of prime numbers. One can prove that such representation exists for any integer greater than 1.

Recall that integer k is called prime if it is greater than 1 and has exactly two positive integer divisors — 1 and k. 

Input

The only line of the input contains a single integer n (2 ≤ n ≤ 100 000).

Output

The first line of the output contains a single integer k — maximum possible number of primes in representation.

The second line should contain k primes with their sum equal to n. You can print them in any order. If there are several optimal solution, print any of them.

Examples

Input

5


Output

2
2 3


Input

6


Output

3
2 2 2

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
int main(void) {
  int n, count = 1, i;
  scanf("%d", &n);
  while (n != 2 && n != 3) {
    n = n - 2;
    count = count + 1;
  }
  printf("%d\n", count);
  for (i = count - 1; i > 0; i--) {
    printf("2 ");
  }
  printf("%d", n);
  return 0;
}