Problem: Bachgold problem is very easy to formulate. Given a positive integer n represent it as a sum of maximum possible number of prime numbers. One can prove that such representation exists for any integer greater than 1.

Recall that integer k is called prime if it is greater than 1 and has exactly two positive integer divisors — 1 and k. 

Input

The only line of the input contains a single integer n (2 ≤ n ≤ 100 000).

Output

The first line of the output contains a single integer k — maximum possible number of primes in representation.

The second line should contain k primes with their sum equal to n. You can print them in any order. If there are several optimal solution, print any of them.

Examples

Input

5


Output

2
2 3


Input

6


Output

3
2 2 2

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.OutputStream;
import java.io.PrintWriter;
import java.util.Random;
import java.util.StringTokenizer;

public class Main {

	static class Pair implements Comparable<Pair> {

		int x;
		int y;

		Pair(int x, int y) {
			this.x = x;
			this.y = y;
		}

		@Override
		public int compareTo(Pair o) {
			int comp1 = Integer.compare(x, o.x);
			if (comp1 != 0) {
				return comp1;
			}
			return Integer.compare(y, o.y);
		}

	}

	static int MOD = 1000 * 1000 * 1000 + 7;

	public static void shuffleArray(int[] arr) {
		int n = arr.length;
		Random rnd = new Random();
		for (int i = 0; i < n; ++i) {
			int tmp = arr[i];
			int randomPos = i + rnd.nextInt(n - i);
			arr[i] = arr[randomPos];
			arr[randomPos] = tmp;
		}
	}

	public static void main(String[] args) {
		InputStream inputStream = System.in;
		OutputStream outputStream = System.out;
		InputReader in = new InputReader(inputStream);
		PrintWriter out = new PrintWriter(outputStream);
		solve(in, out);
		out.close();
		System.exit(0);
	}

	private static void solve(InputReader in, PrintWriter out) {
		int n = in.nextInt();
		int cntThree = 0;
		if(n % 2 == 1) {
			cntThree++;
			n -= 3;
		}
		int cntTwo = n / 2;
		out.println(cntThree + cntTwo);
		for(int i = 0; i < cntTwo; i++) {
			out.print(2 + " ");
		}
		for(int i = 0; i < cntThree; i++) {
			out.print(3);
		}
	}

	/*
	* 
	*/
	// --------------------------------------------------------

	static int gcd(int n, int m) {
		if (m == 0) {
			return n;
		}

		return gcd(m, n % m);
	}

	static class InputReader {
		public BufferedReader reader;
		public StringTokenizer tokenizer;

		public InputReader(InputStream stream) {
			reader = new BufferedReader(new InputStreamReader(stream), 32768);
			tokenizer = null;
		}

		public String next() {
			while (tokenizer == null || !tokenizer.hasMoreTokens()) {
				try {
					tokenizer = new StringTokenizer(reader.readLine());
				} catch (IOException e) {
					throw new RuntimeException(e);
				}
			}
			return tokenizer.nextToken();
		}

		public int nextInt() {
			return Integer.parseInt(next());
		}

		public long nextLong() {
			return Long.parseLong(next());
		}

		public double nextDouble() {
			return Double.parseDouble(next());
		}

		public String nextLine() {
			String str = "";
			try {
				str = reader.readLine();
			} catch (IOException e) {
				e.printStackTrace();
			}

			return str;
		}
	}

}