Problem: Jafar has n cans of cola. Each can is described by two integers: remaining volume of cola ai and can's capacity bi (ai ≤  bi).

Jafar has decided to pour all remaining cola into just 2 cans, determine if he can do this or not!

Input

The first line of the input contains one integer n (2 ≤ n ≤ 100 000) — number of cola cans.

The second line contains n space-separated integers a1, a2, ..., an (0 ≤ ai ≤ 109) — volume of remaining cola in cans.

The third line contains n space-separated integers that b1, b2, ..., bn (ai ≤ bi ≤ 109) — capacities of the cans.

Output

Print "YES" (without quotes) if it is possible to pour all remaining cola in 2 cans. Otherwise print "NO" (without quotes).

You can print each letter in any case (upper or lower).

Examples

Input

2
3 5
3 6


Output

YES


Input

3
6 8 9
6 10 12


Output

NO


Input

5
0 0 5 0 0
1 1 8 10 5


Output

YES


Input

4
4 1 0 3
5 2 2 3


Output

YES

Note

In the first sample, there are already 2 cans, so the answer is "YES".

Solution (in JAVA):

Solution:
import java.util.*;

public class Main {
    public static void main(String[] args) {
	Scanner sc = new Scanner(System.in);
	int n = sc.nextInt();

	long s = 0, x;
	for(int i=0; i<n; i++) {
	    x = sc.nextLong();
	    s += x;
	}

	long V[] = new long[n];
	for(int i=0; i<n; i++) {
	    V[i] = sc.nextLong();
	    //System.out.println(">> " + V[i]);
	}

	Arrays.sort(V);

	//System.out.println("s = " + s);
	//System.out.println("V = " + (V[n-1] + V[n-2]));
	
	if(V[n-1] + V[n-2] >= s) {
	    System.out.println("YES");
	} else {
	    System.out.println("NO");
	}
    }
}