Problem: While walking down the street Vanya saw a label "Hide&Seek". Because he is a programmer, he used & as a bitwise AND for these two words represented as a integers in base 64 and got new word. Now Vanya thinks of some string s and wants to know the number of pairs of words of length |s| (length of s), such that their bitwise AND is equal to s. As this number can be large, output it modulo 109 + 7.

To represent the string as a number in numeral system with base 64 Vanya uses the following rules:

  * digits from '0' to '9' correspond to integers from 0 to 9; 
  * letters from 'A' to 'Z' correspond to integers from 10 to 35; 
  * letters from 'a' to 'z' correspond to integers from 36 to 61; 
  * letter '-' correspond to integer 62; 
  * letter '_' correspond to integer 63. 

Input

The only line of the input contains a single word s (1 ≤ |s| ≤ 100 000), consisting of digits, lowercase and uppercase English letters, characters '-' and '_'.

Output

Print a single integer — the number of possible pairs of words, such that their bitwise AND is equal to string s modulo 109 + 7.

Examples

Input

z


Output

3


Input

V_V


Output

9


Input

Codeforces


Output

130653412

Note

For a detailed definition of bitwise AND we recommend to take a look in the corresponding article in Wikipedia.

In the first sample, there are 3 possible solutions: 

  1. z&_ = 61&63 = 61 = z
  2. _&z = 63&61 = 61 = z
  3. z&z = 61&61 = 61 = z

Solution (in PYTHON3):

Solution:
cyph = [str(x) for x in range(10)]+[chr(65+i) for i in range(26)]+[chr(97+i) for i in range(26)]+['-']+['_']
dct = {}
def decod(char):
    i = 0
    if char in dct:
        return dct[char]
    else:
        while cyph[i] != char:
            i += 1
        dct[char]=i
        return i
        
dct2 = {}
def zeros(i):
    if i in dct2:
        return dct2[i]
    else:
        cct = 0
        for j in range(6):
            cct += (i >> j) % 2
        dct2[i] = 6 - cct
        return dct2[i]
        
s = input()
cnt = 1
for char in s:
    tmp = decod(char)
    cnt *= (3 ** zeros(tmp))
    cnt %= 1000000007
    
print(cnt)