Problem: Jafar has n cans of cola. Each can is described by two integers: remaining volume of cola ai and can's capacity bi (ai ≤  bi).

Jafar has decided to pour all remaining cola into just 2 cans, determine if he can do this or not!

Input

The first line of the input contains one integer n (2 ≤ n ≤ 100 000) — number of cola cans.

The second line contains n space-separated integers a1, a2, ..., an (0 ≤ ai ≤ 109) — volume of remaining cola in cans.

The third line contains n space-separated integers that b1, b2, ..., bn (ai ≤ bi ≤ 109) — capacities of the cans.

Output

Print "YES" (without quotes) if it is possible to pour all remaining cola in 2 cans. Otherwise print "NO" (without quotes).

You can print each letter in any case (upper or lower).

Examples

Input

2
3 5
3 6


Output

YES


Input

3
6 8 9
6 10 12


Output

NO


Input

5
0 0 5 0 0
1 1 8 10 5


Output

YES


Input

4
4 1 0 3
5 2 2 3


Output

YES

Note

In the first sample, there are already 2 cans, so the answer is "YES".

Solution (in JAVA):

Solution:
import java.util.Scanner;

public class Code {

    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int n = sc.nextInt();
        long s=0;
        final int maxValue =(int) Math.pow(10, 9)*2;
        int[] a = new int[n];
        int[] b = new int[n];
        int[] max = new int[2];
        for (int i = 0; i < n; i++) {
            a[i] = sc.nextInt();
            if(s<=maxValue) s+=a[i];
        }     
        if(s<=maxValue) 
            for (int i = 0; i < n; i++) {
            b[i] = sc.nextInt();
            if(b[i]>=max[0]){ max[1]=max[0]; max[0]=b[i]; }
            else if(b[i]>max[1]){ max[1]=b[i]; }
        }
        if(s<=max[0]+max[1]) System.out.println("YES");
        else System.out.println("NO");
    }
}