Problem: Walking along a riverside, Mino silently takes a note of something.

"Time," Mino thinks aloud.

"What?"

"Time and tide wait for no man," explains Mino. "My name, taken from the river, always reminds me of this."

"And what are you recording?"

"You see it, tide. Everything has its own period, and I think I've figured out this one," says Mino with confidence.

Doubtfully, Kanno peeks at Mino's records. 

The records are expressed as a string s of characters '0', '1' and '.', where '0' denotes a low tide, '1' denotes a high tide, and '.' denotes an unknown one (either high or low).

You are to help Mino determine whether it's possible that after replacing each '.' independently with '0' or '1', a given integer p is not a period of the resulting string. In case the answer is yes, please also show such a replacement to Mino.

In this problem, a positive integer p is considered a period of string s, if for all 1 ≤ i ≤ \lvert s \rvert - p, the i-th and (i + p)-th characters of s are the same. Here \lvert s \rvert is the length of s.

Input

The first line contains two space-separated integers n and p (1 ≤ p ≤ n ≤ 2000) — the length of the given string and the supposed period, respectively.

The second line contains a string s of n characters — Mino's records. s only contains characters '0', '1' and '.', and contains at least one '.' character.

Output

Output one line — if it's possible that p is not a period of the resulting string, output any one of such strings; otherwise output "No" (without quotes, you can print letters in any case (upper or lower)).

Examples

Input

10 7
1.0.1.0.1.


Output

1000100010


Input

10 6
1.0.1.1000


Output

1001101000


Input

10 9
1........1


Output

No

Note

In the first example, 7 is not a period of the resulting string because the 1-st and 8-th characters of it are different.

In the second example, 6 is not a period of the resulting string because the 4-th and 10-th characters of it are different.

In the third example, 9 is always a period because the only constraint that the first and last characters are the same is already satisfied.

Note that there are multiple acceptable answers for the first two examples, you can print any of them.

Solution (in JAVA):

Solution:
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 */

import java.io.*;
import java.util.*;

public class Main {

    boolean check(char[] a, int p) {
        char[] str = new char[p];
        for (int i = 0; i < p; i++) str[i] = '.';
        for (int i = 0; i < a.length; i++) {
            if (str[i % p] != '.' && a[i] != '.' && str[i % p] != a[i]) return false;
            if (a[i] != '.') str[i % p] = a[i];
        }
        return true;
    }

    void solve() throws IOException {
        int n = readInt();
        int p = readInt();
        char[] a = readString().toCharArray();
        char[] str = new char[p];
        for (int s = 0; s < n; s++) {

            char[] a_ = a.clone();
            for (int i = 0; i < n; i++) {
                if (a[i] == '.') a_[i] = '0';
                else a_[i] = a[i];
            }
            for (int j = 0; j < p; j++) {
                if (a[(s + j) % n] == '.') {
                    a_[(s + j) % n] = '1';
                }
            }
            if (!check(a_, p)) {
                for (int i = 0; i < n; i++) {
                    out.print(a_[i]);
                }
                return;
            }

        }

        out.println("No");
    }
    class Fenwik {
        long[] t;
        int length;

        Fenwik(int[] a) {
            length = 3000 * 1000;
            t = new long[length];

            for (int i = 0; i < a.length; ++i) {
                inc(i, a[i]);
            }
        }

        void inc(int ind, int delta) {
            for (; ind < length; ind = ind | (ind + 1)) {
                t[ind] += delta;
            }
        }

        long getSum(int r) {
            long sum = 0;
            for (; r >= 0; r = (r & (r + 1)) - 1) {
                sum += t[r];
            }
            return sum;
        }
    }

    public static void main(String[] args) throws IOException {
        new Main().run();
    }


    BufferedReader in;
    PrintWriter out;
    StringTokenizer tok;

    Main() throws FileNotFoundException {
        try {
            in = new BufferedReader(new FileReader("input.txt"));
            out = new PrintWriter("output.txt");
        } catch (Exception e) {
            in = new BufferedReader(new InputStreamReader(System.in));
            out = new PrintWriter(System.out);
        }
        tok = new StringTokenizer("");
    }

    void run() throws IOException {
        solve();
        out.close();
    }


    String delimiter = " ";

    String readLine() throws IOException {
        return in.readLine();
    }

    String readString() throws IOException {
        while (!tok.hasMoreTokens()) {
            String nextLine = readLine();
            if (null == nextLine) return null;
            tok = new StringTokenizer(nextLine);
        }
        return tok.nextToken(delimiter);
    }

    int readInt() throws IOException {
        return Integer.parseInt(readString());
    }

    long readLong() throws IOException {
        return Long.parseLong(readString());
    }

    double readDouble() throws IOException {
        return Double.parseDouble(readString());
    }

    int[] readIntArray(int b) {
        int a[] = new int[b];
        for (int i = 0; i < b; i++)
            try {
                a[i] = readInt();
            } catch (IOException e) {
                e.printStackTrace();
            }
        return a;
    }

    int[] readSortedIntArray(int size) throws IOException {
        Integer[] array = new Integer[size];
        for (int index = 0; index < size; ++index) array[index] = readInt();
        Arrays.sort(array);
        int[] sortedArray = new int[size];
        for (int index = 0; index < size; ++index) sortedArray[index] = array[index];
        return sortedArray;
    }

    int[] sortedIntArray(int size, int[] array) throws IOException {
        for (int index = 0; index < size; ++index) array[index] = readInt();
        Arrays.sort(array);
        int[] sortedArray = new int[size];
        for (int index = 0; index < size; ++index) sortedArray[index] = array[index];
        return sortedArray;
    }

    int minInt(int... values) {
        int min = Integer.MAX_VALUE;
        for (int value : values) min = Math.min(min, value);
        return min;
    }

    int maxInt(int... values) {
        int max = Integer.MIN_VALUE;
        for (int value : values) max = Math.max(max, value);
        return max;
    }

    long minLong(long... values) {
        long min = Long.MAX_VALUE;
        for (long value : values) min = Math.min(min, value);
        return min;
    }

    long maxLong(long... values) {
        long max = Long.MIN_VALUE;
        for (long value : values) max = Math.max(max, value);
        return max;
    }

    boolean checkIndex(int index, int size) {
        return (0 <= index && index < size);
    }

    int abs(int a) {
        if (a < 0) return -a;
        return a;
    }
}