Problem: Jafar has n cans of cola. Each can is described by two integers: remaining volume of cola ai and can's capacity bi (ai ≤  bi).

Jafar has decided to pour all remaining cola into just 2 cans, determine if he can do this or not!

Input

The first line of the input contains one integer n (2 ≤ n ≤ 100 000) — number of cola cans.

The second line contains n space-separated integers a1, a2, ..., an (0 ≤ ai ≤ 109) — volume of remaining cola in cans.

The third line contains n space-separated integers that b1, b2, ..., bn (ai ≤ bi ≤ 109) — capacities of the cans.

Output

Print "YES" (without quotes) if it is possible to pour all remaining cola in 2 cans. Otherwise print "NO" (without quotes).

You can print each letter in any case (upper or lower).

Examples

Input

2
3 5
3 6


Output

YES


Input

3
6 8 9
6 10 12


Output

NO


Input

5
0 0 5 0 0
1 1 8 10 5


Output

YES


Input

4
4 1 0 3
5 2 2 3


Output

YES

Note

In the first sample, there are already 2 cans, so the answer is "YES".

Solution (in JAVA):

Solution:
import java.util.*;
public class cfss {
	public static void main (String[] args) {
		Scanner c=new Scanner(System.in) ;
		int n=c.nextInt();
		int[] a=new int[n];
		int[] b=new int[n];
		long sum=0;
		for(int i=0 ; i<n ; i++) {
			a[i]=c.nextInt();	
			sum+=a[i];
		}
		//System.out.println(sum);
		for(int i=0 ; i<n ; i++) {
			b[i]=c.nextInt();
		}
		//System.out.println(Arrays.toString(b));
		Arrays.sort(b);
		//System.out.println(Arrays.toString(b));
		long capacity= b[n-1]+b[n-2];
		if(sum<=capacity) {
			System.out.println("YES");
		} else {
			System.out.println("NO");
		}
		
	}
}