Problem: The Little Girl loves problems on games very much. Here's one of them.

Two players have got a string s, consisting of lowercase English letters. They play a game that is described by the following rules:

  * The players move in turns; In one move the player can remove an arbitrary letter from string s. 
  * If the player before his turn can reorder the letters in string s so as to get a palindrome, this player wins. A palindrome is a string that reads the same both ways (from left to right, and vice versa). For example, string "abba" is a palindrome and string "abc" isn't. 



Determine which player will win, provided that both sides play optimally well — the one who moves first or the one who moves second.

Input

The input contains a single line, containing string s (1 ≤ |s| ≤ 103). String s consists of lowercase English letters.

Output

In a single line print word "First" if the first player wins (provided that both players play optimally well). Otherwise, print word "Second". Print the words without the quotes.

Examples

Input

aba


Output

First


Input

abca


Output

Second

Solution (in PYTHON3):

Solution:
#sys.setrecursionlimit(300000)
import sys
def main():
    pass
def binary(n):
    #decimal to binary
    return (bin(n).replace("0b", ""))
def decimal(s):
    #binary to decimal
    return (int(s, 2))
def pow2(n):
    #power of a number base 2
    p = 0
    while n > 1:
        n //= 2
        p += 1
    return (p)
def isPrime(n):
    # if  number is prime in √n time
    if (n == 1):
        return (False)
    else:
        root = int(n ** 0.5)
        root += 1
        for i in range(2, root):
            if (n % i == 0):
                return (False)
        return (True)
def lts(l):
    #list to string ,no spaces
    s=''.join(map(str,l))
    return s
def stl(s):
    #for each character in string to list with no spaces -->
    l=list(s)
    #for space in string  -->
    #l=list(s.split(" "))
    return l
#Returns list of numbers with a particular sum
def sq(a,target,arr=[]):
    s=sum(arr)
    if(s==target):
        return arr
    if(s>=target):
        return
    for i in range(len(a)):
        n=a[i]
        remaining=a[i+1:]
        ans=sq(remaining,target,arr+[n])
        if(ans):
            return ans

#1000000007
mod=int(1e9)+7
def sinp(): return sys.stdin.readline().strip()
def iinp(): return int(input())
def ninp(): return map(int, sys.stdin.readline().strip().split())
def llinp(): return list(map(int, sys.stdin.readline().strip().split()))
def p(xyz): print(xyz)
def p2(a,b):print(a,b)
import math as m
#for _ in range(iinp()):
s=sinp();
freq=[0]*26
for c in s:
    freq[ord(c)-97]+=1
x=0
for i in freq:
    if(i%2==1):
        x+=1
if(x==0 or x%2==1):
    print("First")
else:
    print("Second")