Problem: While walking down the street Vanya saw a label "Hide&Seek". Because he is a programmer, he used & as a bitwise AND for these two words represented as a integers in base 64 and got new word. Now Vanya thinks of some string s and wants to know the number of pairs of words of length |s| (length of s), such that their bitwise AND is equal to s. As this number can be large, output it modulo 109 + 7.

To represent the string as a number in numeral system with base 64 Vanya uses the following rules:

  * digits from '0' to '9' correspond to integers from 0 to 9; 
  * letters from 'A' to 'Z' correspond to integers from 10 to 35; 
  * letters from 'a' to 'z' correspond to integers from 36 to 61; 
  * letter '-' correspond to integer 62; 
  * letter '_' correspond to integer 63. 

Input

The only line of the input contains a single word s (1 ≤ |s| ≤ 100 000), consisting of digits, lowercase and uppercase English letters, characters '-' and '_'.

Output

Print a single integer — the number of possible pairs of words, such that their bitwise AND is equal to string s modulo 109 + 7.

Examples

Input

z


Output

3


Input

V_V


Output

9


Input

Codeforces


Output

130653412

Note

For a detailed definition of bitwise AND we recommend to take a look in the corresponding article in Wikipedia.

In the first sample, there are 3 possible solutions: 

  1. z&_ = 61&63 = 61 = z
  2. _&z = 63&61 = 61 = z
  3. z&z = 61&61 = 61 = z

Solution (in PYTHON3):

Solution:

def str_to_array(s):
    array = [None] * len(s)
    for i, c in enumerate(s):
        code = ord(c)
        if 48 <= code <= 57:
            array[i] = code - 48
        elif 65 <= code <= 90:
            array[i] = code - 55
        elif 97 <= code <= 122:
            array[i] = code - 61
        elif code == 45:
            array[i] = 62
        elif code == 95:
            array[i] = 63
    return array


def calculate_for_one_number(number):
    r = 1
    # print(number, bin(number))
    for _ in range(6):
        digit = number & 1
        # print(digit)
        if digit == 0:
            r *= 3
        number >>= 1
    return r


inp = str_to_array(input())
result = 1
for n in inp:
    # print(calculate_for_one_number(n), n)
    result *= calculate_for_one_number(n)
    result %= 1000000007

print(result)