Problem: The Little Girl loves problems on games very much. Here's one of them.

Two players have got a string s, consisting of lowercase English letters. They play a game that is described by the following rules:

  * The players move in turns; In one move the player can remove an arbitrary letter from string s. 
  * If the player before his turn can reorder the letters in string s so as to get a palindrome, this player wins. A palindrome is a string that reads the same both ways (from left to right, and vice versa). For example, string "abba" is a palindrome and string "abc" isn't. 



Determine which player will win, provided that both sides play optimally well — the one who moves first or the one who moves second.

Input

The input contains a single line, containing string s (1 ≤ |s| ≤ 103). String s consists of lowercase English letters.

Output

In a single line print word "First" if the first player wins (provided that both players play optimally well). Otherwise, print word "Second". Print the words without the quotes.

Examples

Input

aba


Output

First


Input

abca


Output

Second

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
bool isPrime(long long int n) {
  if (n <= 1) return false;
  if (n <= 3) return true;
  if (n % 2 == 0 || n % 3 == 0) return false;
  for (long long int i = 5; i * i <= n; i = i + 6)
    if (n % i == 0 || n % (i + 2) == 0) return false;
  return true;
}
unsigned int countBits(unsigned int n) {
  unsigned int count = 0;
  while (n) {
    count++;
    n >>= 1;
  }
  return count;
}
bool isPerfectSquare(long double x) {
  long double sr = sqrt(x);
  return ((sr - floor(sr)) == 0);
}
int subArraySum(int arr[], int n) {
  int curr_sum = arr[0], start = 0, i, count = 0, len;
  len = 0;
  for (i = 1; i <= n; i++) {
    len++;
    while (curr_sum > len && start < i - 1) {
      curr_sum = curr_sum - arr[start];
      start++;
      len++;
    }
    if (curr_sum == len) {
      count++;
    }
    if (i < n && i > 0) {
      curr_sum = curr_sum + arr[i];
    }
  }
  return count;
}
void printDigit(int N, vector<long long int>& arr) {
  int i = 0;
  int j, r;
  while (N != 0) {
    r = N % 10;
    arr.push_back(r);
    i++;
    N = N / 10;
  }
}
void solver(vector<long long int> arr, long long int start,
            long long int& count, long long int a1) {
  long long int sum = 0;
  for (long long int i = start + 1; i < arr.size() - 1; i++) {
    sum += arr[i];
    if (sum == a1) count++;
  }
}
bool checkDivisibility(long long int n, int digit) {
  if (digit == 0) return true;
  return (digit != 0 && n % digit == 0);
}
bool allDigitsDivide(long long int n) {
  long long int temp = n;
  while (temp > 0) {
    int digit = temp % 10;
    if (!(checkDivisibility(n, digit))) return false;
    temp /= 10;
  }
  return true;
}
bool isPrime(int n) {
  if (n <= 1) return false;
  if (n <= 3) return true;
  if (n % 2 == 0 || n % 3 == 0) return false;
  for (int i = 5; i * i <= n; i = i + 6)
    if (n % i == 0 || n % (i + 2) == 0) return false;
  return true;
}
bool isPowerOfTwo(unsigned long long x) { return x && (!(x & (x - 1))); }
int nextPrime(int N) {
  if (N <= 1) return 2;
  int prime = N;
  bool found = false;
  while (!found) {
    prime++;
    if (isPrime(prime)) found = true;
  }
  return prime;
}
bool sortcol(const vector<long long int>& v1, const vector<long long int>& v2) {
  return v1[0] < v2[0];
}
int main() {
  ios_base::sync_with_stdio(false);
  cin.tie(0);
  long long int b = 0, q, c, x, y, start = 0, end = 0, count = 0, neg = 0,
                pos = 0, count1 = 0, a1 = 0, b1 = 0, c1 = 0, x1, y1, n1, m,
                ans = 0, sum = 0, k;
  long long int n;
  string s1, s2(""), s3("");
  bool check2 = false, check3 = false;
  long long int x3, x2, y3, y2;
  int curr1 = 0, curr = 0;
  vector<int> arr(130, 0);
  vector<int> arr1;
  stack<char> s;
  long long int vb;
  bool check1 = false, check4 = false;
  vector<double> arrv;
  unordered_map<long long int, long long int> map1;
  unordered_map<long long int, long long int> map2;
  long long int a, l = 0, d = 0, u = 0, v, g, sub;
  cin >> s1;
  n = s1.length();
  for (int i = 0; i < n; i++) {
    arr[s1[i]]++;
  }
  for (int i = 0; i < arr.size(); i++) {
    if (arr[i] % 2 != 0) count++;
  }
  if (count == 0 || count == 1)
    cout << "First";
  else if (count % 2 != 0)
    cout << "First";
  else
    cout << "Second";
  return 0;
}