Problem: While walking down the street Vanya saw a label "Hide&Seek". Because he is a programmer, he used & as a bitwise AND for these two words represented as a integers in base 64 and got new word. Now Vanya thinks of some string s and wants to know the number of pairs of words of length |s| (length of s), such that their bitwise AND is equal to s. As this number can be large, output it modulo 109 + 7.

To represent the string as a number in numeral system with base 64 Vanya uses the following rules:

  * digits from '0' to '9' correspond to integers from 0 to 9; 
  * letters from 'A' to 'Z' correspond to integers from 10 to 35; 
  * letters from 'a' to 'z' correspond to integers from 36 to 61; 
  * letter '-' correspond to integer 62; 
  * letter '_' correspond to integer 63. 

Input

The only line of the input contains a single word s (1 ≤ |s| ≤ 100 000), consisting of digits, lowercase and uppercase English letters, characters '-' and '_'.

Output

Print a single integer — the number of possible pairs of words, such that their bitwise AND is equal to string s modulo 109 + 7.

Examples

Input

z


Output

3


Input

V_V


Output

9


Input

Codeforces


Output

130653412

Note

For a detailed definition of bitwise AND we recommend to take a look in the corresponding article in Wikipedia.

In the first sample, there are 3 possible solutions: 

  1. z&_ = 61&63 = 61 = z
  2. _&z = 63&61 = 61 = z
  3. z&z = 61&61 = 61 = z

Solution (in JAVA):

Solution:
import java.util.Scanner;

public class A {
	public static void main(String args[]){
		Scanner in = new Scanner(System.in);
		String a = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz-_";
		long mod = 1000000007;
	    long a1[] = new long[64];
	    long cnt = 1 , j = 0 ;
		int i = 0;
	    String r = in.next();
	    for(i=0;i<64;i++)
	    	for(j=0;j<64;j++)
	    		a1[(int) (i&j)]++;
	    for(i=0;i<r.length();)
	    	cnt = cnt * a1 [ cnt(r.charAt(i++)) ]%mod;
	    System.out.println(cnt);
	}
	static int cnt(char t){
		int s=(int)t;
		return s==95?63:s==45?62:s>96?s-61:s>64?s-55:s-48;
	}
	
}