Problem: This is the easy version of the problem. The difference is the constraint on the sum of lengths of strings and the number of test cases. You can make hacks only if you solve all versions of this task.

You are given a string s, consisting of lowercase English letters. Find the longest string, t, which satisfies the following conditions: 

  * The length of t does not exceed the length of s. 
  * t is a palindrome. 
  * There exists two strings a and b (possibly empty), such that t = a + b ( "+" represents concatenation), and a is prefix of s while b is suffix of s. 

Input

The input consists of multiple test cases. The first line contains a single integer t (1 ≤ t ≤ 1000), the number of test cases. The next t lines each describe a test case.

Each test case is a non-empty string s, consisting of lowercase English letters.

It is guaranteed that the sum of lengths of strings over all test cases does not exceed 5000.

Output

For each test case, print the longest string which satisfies the conditions described above. If there exists multiple possible solutions, print any of them.

Example

Input


5
a
abcdfdcecba
abbaxyzyx
codeforces
acbba


Output


a
abcdfdcba
xyzyx
c
abba

Note

In the first test, the string s = "a" satisfies all conditions.

In the second test, the string "abcdfdcba" satisfies all conditions, because:

  * Its length is 9, which does not exceed the length of the string s, which equals 11. 
  * It is a palindrome. 
  * "abcdfdcba" = "abcdfdc" + "ba", and "abcdfdc" is a prefix of s while "ba" is a suffix of s. 



It can be proven that there does not exist a longer string which satisfies the conditions.

In the fourth test, the string "c" is correct, because "c" = "c" + "" and a or b can be empty. The other possible solution for this test is "s".

Solution (in JAVA):

Solution:
// package june2020;

import java.util.*;
import java.lang.*;
import java.math.*;
import java.io.*;

public class cf_subs {
	static FastReader scn = new FastReader();
	static OutputStream out = new BufferedOutputStream(System.out);
	public static void main(String[] args) throws IOException {
		// TODO Auto-generated method stub
		int t = scn.nextInt();
		while(t-->0) {
			char[] s = scn.next().toCharArray();
			int n= s.length;
			//check if palindrome
			int lo=0,ji=n-1;
			boolean o=true;
			while(ji>=lo) {
				if(s[lo]!=s[ji]) {
					o=false;
					break;
				}
				lo++;
				ji--;
			}
			if(o) {
				System.out.println(s);
				continue;
			}
			int l=0,r=n-1;
			while(r>=l) {
				if(s[l]==s[r]) {
					l++;r--;
				}else {
					break;
				}
			}
			l--;
			r++;
			int max=0;
			int lf = -1,rg=-1;
			for(int i=l+1;i<r&&i<n;i++) {
				int ll=l+1;
				int rr=i;
				boolean ok= true;
				while(rr>=ll) {
					if(s[ll]!=s[rr]) {
						ok = false;
						break;
					}
					ll++;
					rr--;
				}
				if(ok) {
					if(max<(i-l)) {
						max =i-l;
						lf = l+1;
						rg=i;
					}
				}
			}
			for(int i=r-1;i>=0&&i>l;i--) {
				int ll=i;
				int rr = r-1;
				boolean ok =true;
				while(rr>=ll) {
					if(s[ll]!=s[rr]) {
						ok = false;
						break;
					}
					ll++;
					rr--;
				}
				
				if(ok) {
					if(max<(r-i)) {
						max=r-i;
						lf=i;
						rg=r-1;
					}
				}
			}
			for(int i=0;i<=l;i++) {
				out.write((s[i]+"").getBytes());
			}
			for(int i=lf;i<=rg;i++) {
				out.write((s[i]+"").getBytes());
			}
			for(int i=r;i<n;i++) {
				out.write((s[i]+"").getBytes());
			}
			out.write("\n".getBytes());
			out.flush();
		}
		out.close();
	}
	public static int[] merge(int[] one,int[] two){
		int[] res = new int[one.length+two.length];
		int i = 0;
		int j = 0;
		int k = 0;
		
		while(i<one.length&&j<two.length){
			if(one[i]<two[j]){
				res[k] = one[i];
				i++;
				k++;
			}
			else{
				res[k] = two[j];
				j++;
				k++;
			}
		}
		
		if(i==one.length){
			while(j<two.length){
				res[k] = two[j];
				j++;
				k++;
			}
		}
		else{
			while(i<one.length){
				res[k] = one[i];
				k++;
				i++;
			}
		}
		return res;
	}
	public static int[] mergesort(int[] arr, int l, int r){
		if(l==r){
			int[] br = new int[1];
			br[0] = arr[l];
			return br;
		}
		int mid = (l+r)/2;
		int[] fh = mergesort(arr,l,mid);
		int[] sh = mergesort(arr,mid+1,r);
		
		return merge(fh,sh);
	}
//	static int dfs(int idx) {
//		
//	}
	static <T> int upperBound(List<T> ls, T x) throws RuntimeException {
		if (ls.size() == 0)
			return -1;
		if (ls.get(0) instanceof Integer) {
			return ~Collections.binarySearch(ls, x, (t1, t2) -> ((Integer) t1).compareTo((Integer) t2) > 0 ? 1 : -1);
		} else if (ls.get(0) instanceof Long) {
			return ~Collections.binarySearch(ls, x, (t1, t2) -> ((Long) t1).compareTo((Long) t2) > 0 ? 1 : -1);
		} else if (ls.get(0) instanceof Double) {
			return ~Collections.binarySearch(ls, x, (t1, t2) -> ((Double) t1).compareTo((Double) t2) > 0 ? 1 : -1);
		} else {
			System.err.println(
					String.format("%s:Arey Maa chudi padi hai", Thread.currentThread().getStackTrace()[1].getMethodName()));
			throw new RuntimeException();
		}
	}
	static class FastReader 
    { 
        BufferedReader br; 
        StringTokenizer st; 
  
        public FastReader() 
        { 
            br = new BufferedReader(new
                     InputStreamReader(System.in)); 
        } 
  
        String next() 
        { 
            while (st == null || !st.hasMoreElements()) 
            { 
                try
                { 
                    st = new StringTokenizer(br.readLine()); 
                } 
                catch (IOException  e) 
                { 
                    e.printStackTrace(); 
                } 
            } 
            return st.nextToken(); 
        } 
  
        int nextInt() 
        { 
            return Integer.parseInt(next()); 
        } 
  
        long nextLong() 
        { 
            return Long.parseLong(next()); 
        } 
  
        double nextDouble() 
        { 
            return Double.parseDouble(next()); 
        } 
  
        String nextLine() 
        { 
            String str = ""; 
            try
            { 
                str = br.readLine(); 
            } 
            catch (IOException e) 
            { 
                e.printStackTrace(); 
            } 
            return str; 
        } 
    }

}