Problem: Jafar has n cans of cola. Each can is described by two integers: remaining volume of cola ai and can's capacity bi (ai ≤  bi).

Jafar has decided to pour all remaining cola into just 2 cans, determine if he can do this or not!

Input

The first line of the input contains one integer n (2 ≤ n ≤ 100 000) — number of cola cans.

The second line contains n space-separated integers a1, a2, ..., an (0 ≤ ai ≤ 109) — volume of remaining cola in cans.

The third line contains n space-separated integers that b1, b2, ..., bn (ai ≤ bi ≤ 109) — capacities of the cans.

Output

Print "YES" (without quotes) if it is possible to pour all remaining cola in 2 cans. Otherwise print "NO" (without quotes).

You can print each letter in any case (upper or lower).

Examples

Input

2
3 5
3 6


Output

YES


Input

3
6 8 9
6 10 12


Output

NO


Input

5
0 0 5 0 0
1 1 8 10 5


Output

YES


Input

4
4 1 0 3
5 2 2 3


Output

YES

Note

In the first sample, there are already 2 cans, so the answer is "YES".

Solution (in JAVA):

Solution:
import java.util.Arrays;
import java.util.Scanner;

public class Greed {

	public static void main(String[] args) {
		Scanner scan = new Scanner(System.in);
		int ColaCans = scan.nextInt();
		long[] arr1 = new long[ColaCans];
		long[] arr2 = new long[ColaCans];
		long one = 0;
		long two = 0;
		for(int i = 0;i<ColaCans;i++){
			arr1[i] = scan.nextLong();
			one+=arr1[i];
		}
		for(int i = 0;i<ColaCans;i++){
			arr2[i] = scan.nextLong();
		}
		Arrays.sort(arr2);
		two+=arr2[arr2.length-2]+arr2[arr2.length-1];
		if(one<=two){
			System.out.println("YES");
		}else{
			System.out.println("NO");
		}
	}
}