Problem: While walking down the street Vanya saw a label "Hide&Seek". Because he is a programmer, he used & as a bitwise AND for these two words represented as a integers in base 64 and got new word. Now Vanya thinks of some string s and wants to know the number of pairs of words of length |s| (length of s), such that their bitwise AND is equal to s. As this number can be large, output it modulo 109 + 7.

To represent the string as a number in numeral system with base 64 Vanya uses the following rules:

  * digits from '0' to '9' correspond to integers from 0 to 9; 
  * letters from 'A' to 'Z' correspond to integers from 10 to 35; 
  * letters from 'a' to 'z' correspond to integers from 36 to 61; 
  * letter '-' correspond to integer 62; 
  * letter '_' correspond to integer 63. 

Input

The only line of the input contains a single word s (1 ≤ |s| ≤ 100 000), consisting of digits, lowercase and uppercase English letters, characters '-' and '_'.

Output

Print a single integer — the number of possible pairs of words, such that their bitwise AND is equal to string s modulo 109 + 7.

Examples

Input

z


Output

3


Input

V_V


Output

9


Input

Codeforces


Output

130653412

Note

For a detailed definition of bitwise AND we recommend to take a look in the corresponding article in Wikipedia.

In the first sample, there are 3 possible solutions: 

  1. z&_ = 61&63 = 61 = z
  2. _&z = 63&61 = 61 = z
  3. z&z = 61&61 = 61 = z

Solution (in PYTHON):

Solution:
def f():
    M = 10**9+7
    s = raw_input().strip()
    n = len(s)
    ones = 0
    for c in s:
        if '0' <= c <= '9':
            x = ord(c)-ord('0')
        elif 'A' <= c <= 'Z':
            x = 10 + ord(c)-ord('A')
        elif 'a' <= c <= 'z':
            x = 36 + ord(c)-ord('a')
        elif c == '-':
            x = 62
        elif c == '_':
            x = 63
        while x:
            ones += 1
            x ^= x&-x
    z = n*6-ones
    res = 1
    for x in xrange(z):
        res = res * 3 % M

    print res
f()