Problem: Vasya has a multiset s consisting of n integer numbers. Vasya calls some number x nice if it appears in the multiset exactly once. For example, multiset \{1, 1, 2, 3, 3, 3, 4\} contains nice numbers 2 and 4.

Vasya wants to split multiset s into two multisets a and b (one of which may be empty) in such a way that the quantity of nice numbers in multiset a would be the same as the quantity of nice numbers in multiset b (the quantity of numbers to appear exactly once in multiset a and the quantity of numbers to appear exactly once in multiset b).

Input

The first line contains a single integer n~(2 ≤ n ≤ 100).

The second line contains n integers s_1, s_2, ... s_n~(1 ≤ s_i ≤ 100) — the multiset s.

Output

If there exists no split of s to satisfy the given requirements, then print "NO" in the first line.

Otherwise print "YES" in the first line.

The second line should contain a string, consisting of n characters. i-th character should be equal to 'A' if the i-th element of multiset s goes to multiset a and 'B' if if the i-th element of multiset s goes to multiset b. Elements are numbered from 1 to n in the order they are given in the input.

If there exist multiple solutions, then print any of them.

Examples

Input

4
3 5 7 1


Output

YES
BABA


Input

3
3 5 1


Output

NO

Solution (in PYTHON3):

Solution:
n = int(input())
a = [int(i) for i in input().split()]
freq = {}
for i in a:
    freq[i] = freq.get(i, 0) + 1
    
if sum(1 for i in freq if freq[i] == 1) % 2 == 0:
    print("YES")
    counter = 0
    for i in a:
        if freq[i] == 1:
            print("A" if counter % 2 else "B", end="", flush=False)
            counter += 1
        else:
            print("B", end="", flush=False)
    print()
elif any(freq[i] > 2 for i in freq):
    print("YES")
    counter = 0
    single = 0
    for i in a:
        if freq[i] == 1:
            print("A" if counter % 2 else "B", end="", flush=False)
            counter += 1
        else:
            if freq[i] > 2 and not single:
                print("A", end="", flush=False)
                single = True
            else:
                print("B", end="", flush=False)
    print()
else:
    print("NO")