Problem: While walking down the street Vanya saw a label "Hide&Seek". Because he is a programmer, he used & as a bitwise AND for these two words represented as a integers in base 64 and got new word. Now Vanya thinks of some string s and wants to know the number of pairs of words of length |s| (length of s), such that their bitwise AND is equal to s. As this number can be large, output it modulo 109 + 7.

To represent the string as a number in numeral system with base 64 Vanya uses the following rules:

  * digits from '0' to '9' correspond to integers from 0 to 9; 
  * letters from 'A' to 'Z' correspond to integers from 10 to 35; 
  * letters from 'a' to 'z' correspond to integers from 36 to 61; 
  * letter '-' correspond to integer 62; 
  * letter '_' correspond to integer 63. 

Input

The only line of the input contains a single word s (1 ≤ |s| ≤ 100 000), consisting of digits, lowercase and uppercase English letters, characters '-' and '_'.

Output

Print a single integer — the number of possible pairs of words, such that their bitwise AND is equal to string s modulo 109 + 7.

Examples

Input

z


Output

3


Input

V_V


Output

9


Input

Codeforces


Output

130653412

Note

For a detailed definition of bitwise AND we recommend to take a look in the corresponding article in Wikipedia.

In the first sample, there are 3 possible solutions: 

  1. z&_ = 61&63 = 61 = z
  2. _&z = 63&61 = 61 = z
  3. z&z = 61&61 = 61 = z

Solution (in JAVA):

Solution:
import java.util.*;
import java.io.*;
public class Main{
public static void main(String [] args)throws Exception{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
//StringTokenizer st = new StringTokenizer(br.readLine());
String str = br.readLine();
int ans = 0;
//System.out.println((12 >> 3));
for(int i = 0;i < str.length();i++){
   int val = -1;
   if(str.charAt(i) >= '0' && str.charAt(i) <= '9')
   val = str.charAt(i) - '0';
  else if(str.charAt(i) >= 'a' && str.charAt(i) <= 'z')
   val = str.charAt(i) - 'a' + 36;
  else if(str.charAt(i) >= 'A' && str.charAt(i) <= 'Z')
   val = str.charAt(i) - 'A'+ 10;
  else if(str.charAt(i) == '-')
   val = 62;
  else val = 63;
  for(int j = 0;j < 6;j++)
  if(((val >> j) & 1) == 0) ++ans;
  //System.out.println(val + " " + ans);
}
 long temp = 1;
//System.out.println(ans); 
 for(int i = 1;i <= ans;i++){
 temp *= 3;
 while(temp > 1000_000_000 + 7)
 temp -= 1000_000_000 + 7;
}
System.out.print(temp);
}
}