Problem: You are given a string s of length n. Does a tree with n vertices that satisfies the following conditions exist?

* The vertices are numbered 1,2,..., n.
* The edges are numbered 1,2,..., n-1, and Edge i connects Vertex u_i and v_i.
* If the i-th character in s is `1`, we can have a connected component of size i by removing one edge from the tree.
* If the i-th character in s is `0`, we cannot have a connected component of size i by removing any one edge from the tree.



If such a tree exists, construct one such tree.

Constraints

* 2 \leq n \leq 10^5
* s is a string of length n consisting of `0` and `1`.

Input

Input is given from Standard Input in the following format:


s


Output

If a tree with n vertices that satisfies the conditions does not exist, print `-1`.

If a tree with n vertices that satisfies the conditions exist, print n-1 lines. The i-th line should contain u_i and v_i with a space in between. If there are multiple trees that satisfy the conditions, any such tree will be accepted.

Examples

Input

1111


Output

-1


Input

1110


Output

1 2
2 3
3 4


Input

1010


Output

1 2
1 3
1 4

Solution (in CPP):

Solution:
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#define reg register
using namespace std;
typedef long long ll;
const int MN=1e5+5;
int n,x[MN],y[MN];
char ch[MN];
int main(){
	scanf("%s",ch+1);n=strlen(ch+1);
	if((ch[n]^48)||!(ch[1]^48))return 0*puts("-1");
	for(reg int i=1;i<=(n>>1);i++)if(ch[i]^ch[n-i])return 0*puts("-1");
	reg int pre=1;
	for(reg int i=2;i<=n;i++)if(ch[i]^48)for(;pre<i;pre++)printf("%d %d\n",pre,i);
	printf("%d %d\n",n-1,n);
	return 0;
}
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