Problem: Snuke is introducing a robot arm with the following properties to his factory:

* The robot arm consists of m sections and m+1 joints. The sections are numbered 1, 2, ..., m, and the joints are numbered 0, 1, ..., m. Section i connects Joint i-1 and Joint i. The length of Section i is d_i.
* For each section, its mode can be specified individually. There are four modes: `L`, `R`, `D` and `U`. The mode of a section decides the direction of that section. If we consider the factory as a coordinate plane, the position of Joint i will be determined as follows (we denote its coordinates as (x_i, y_i)):
* (x_0, y_0) = (0, 0).
* If the mode of Section i is `L`, (x_{i}, y_{i}) = (x_{i-1} - d_{i}, y_{i-1}).
* If the mode of Section i is `R`, (x_{i}, y_{i}) = (x_{i-1} + d_{i}, y_{i-1}).
* If the mode of Section i is `D`, (x_{i}, y_{i}) = (x_{i-1}, y_{i-1} - d_{i}).
* If the mode of Section i is `U`, (x_{i}, y_{i}) = (x_{i-1}, y_{i-1} + d_{i}).



Snuke would like to introduce a robot arm so that the position of Joint m can be matched with all of the N points (X_1, Y_1), (X_2, Y_2), ..., (X_N, Y_N) by properly specifying the modes of the sections. Is this possible? If so, find such a robot arm and how to bring Joint m to each point (X_j, Y_j).

Constraints

* All values in input are integers.
* 1 \leq N \leq 1000
* -10^9 \leq X_i \leq 10^9
* -10^9 \leq Y_i \leq 10^9

Input

Input is given from Standard Input in the following format:


N
X_1 Y_1
X_2 Y_2
:
X_N Y_N


Output

If the condition can be satisfied, follow the following format. If the condition cannot be satisfied, print `-1`.


m
d_1 d_2 ... d_m
w_1
w_2
:
w_N


m and d_i are the configurations of the robot arm. Refer to the problem statement for what each of them means. Here, 1 \leq m \leq 40 and 1 \leq d_i \leq 10^{12} must hold. Also, m and d_i must all be integers.

w_j is a string of length m that represents the way to bring Joint m of the robot arm to point (X_j, Y_j). The i-th character of w_j should be one of the letters `L`, `R`, `D` and `U`, representing the mode of Section i.

Examples

Input

3
-1 0
0 3
2 -1


Output

2
1 2
RL
UU
DR


Input

5
0 0
1 0
2 0
3 0
4 0


Output

-1


Input

2
1 1
1 1


Output

2
1 1
RU
UR


Input

3
-7 -3
7 3
-3 -7


Output

5
3 1 4 1 5
LRDUL
RDULR
DULRD

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;

int main() {
  int N;
  cin >> N;

  int tmp;
  vector< vector<int> > XY(N);
  for (int i = 0; i < N; i++) {
    cin >> tmp; XY[i].push_back(tmp);
    cin >> tmp; XY[i].push_back(tmp);
  }

  int prevmod, mod;
  prevmod = (XY[0][0] + XY[0][1]) % 2 != 0;
  for (int i = 1; i < N; i++) {
    mod = (XY[i][0] + XY[i][1]) % 2 != 0;
    if (mod != prevmod) {
      cout << -1 << endl;
      return 0;
    }
    prevmod = mod;
  }

  vector<long> D;
  if (mod == 0) {
    D.push_back(1);
  }
  for (int i = 0; i < 32; i++) {
    D.push_back(pow(2, i));
  }
  reverse(D.begin(), D.end());

  int m = D.size();
  cout << m << endl;
  for (int i = 0; i < m - 1; i++) {
    cout << D[i] << ' ';
  }
  cout << D[m - 1] << endl;

  for (int i = 0; i < N; i++) {
    long x = XY[i][0];
    long y = XY[i][1];
    for (int j = 0; j < m; j++) {
      if (0 < x + y && 0 < x - y) {
        cout << 'R';
        x -= D[j];
      } else if (0 < x + y && x - y <= 0) {
        cout << 'U';
        y -= D[j];
      } else if (x + y <= 0 && x - y <= 0) {
        cout << 'L';
        x += D[j];
      } else {
        cout << 'D';
        y += D[j];
      }
    }
    cout << endl;
  }
}