Problem: There is a tree with N vertices numbered 1 to N. The i-th edge in this tree connects Vertex a_i and Vertex b_i, and the color and length of that edge are c_i and d_i, respectively. Here the color of each edge is represented by an integer between 1 and N-1 (inclusive). The same integer corresponds to the same color, and different integers correspond to different colors.

Answer the following Q queries:

* Query j (1 \leq j \leq Q): assuming that the length of every edge whose color is x_j is changed to y_j, find the distance between Vertex u_j and Vertex v_j. (The changes of the lengths of edges do not affect the subsequent queries.)

Constraints

* 2 \leq N \leq 10^5
* 1 \leq Q \leq 10^5
* 1 \leq a_i, b_i \leq N
* 1 \leq c_i \leq N-1
* 1 \leq d_i \leq 10^4
* 1 \leq x_j \leq N-1
* 1 \leq y_j \leq 10^4
* 1 \leq u_j < v_j \leq N
* The given graph is a tree.
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N Q
a_1 b_1 c_1 d_1
:
a_{N-1} b_{N-1} c_{N-1} d_{N-1}
x_1 y_1 u_1 v_1
:
x_Q y_Q u_Q v_Q


Output

Print Q lines. The j-th line (1 \leq j \leq Q) should contain the answer to Query j.

Example

Input

5 3
1 2 1 10
1 3 2 20
2 4 4 30
5 2 1 40
1 100 1 4
1 100 1 5
3 1000 3 4


Output

130
200
60

Solution (in PYTHON3):

Solution:
import sys
from itertools import combinations, permutations, product, combinations_with_replacement, accumulate
from heapq import heapify, heappop, heappush, heappushpop
from bisect import bisect_left, bisect_right
from collections import Counter, defaultdict, deque
from math import sqrt, log, floor, ceil, factorial, cos, sin, pi#, gcd
from fractions import gcd
from operator import mul
from functools import reduce
sys.setrecursionlimit(10**8)
input = sys.stdin.readline
INF = float('inf')
LINF = 2**63-1
NIL = -LINF
MOD = 10**9+7
MGN = 4
def AST(exp: bool, msg: str = ""): assert exp, msg
def TAST(exp: bool, msg = ""):
    if exp is False: print("TAssertionError:", msg)
    while exp is False:
        pass
def EPR(msg): print(msg, file=sys.stderr)
def II(): return int(input())
def IF(): return float(input())
def IS(): return input().replace('\n', '')
def ILCI(n: int): return [II() for _ in range(n)]
def ILCF(n: int): return [IF() for _ in range(n)]
def ILI(): return list(map(int, input().split()))
def ILLI(n: int): return [[int(j) for j in input().split()] for i in range(n)]
def ILF(): return list(map(float, input().split()))
def ILLF(n: int): return [[float(j) for j in input().split()] for i in range(n)]
def LTOS(lst: list, sep: str = ' '): return sep.join(map(str, lst))
def DEC(lst: list): return list(map(lambda x: x-1, lst))
def INC(lst: list): return list(map(lambda x: x+1, lst))

class LCA:
    def __init__(self, N: int) -> None:
        self.N = N
        self.to = [[] for _ in range(N)]
        self.co = [[] for _ in range(N)]
        self.dep = [0] * N
        self.costs = [0] * N
        l = 0
        while (1 << l) < N:
            l += 1
        self.l = l
        self.par = [([0]*l) for _ in range(N+1)]
    def add_edge(self, a: int, b: int, c = 0) -> None:
        self.to[a].append(b)
        self.co[a].append(c)
        self.to[b].append(a)
        self.co[b].append(c)
    def _dfs(self, v: int, d: int = 0, c = 0, p: int = -1) -> None:
        if p != -1:
            self.par[v][0] = p
        self.dep[v] = d
        self.costs[v] = c
        for i in range(len(self.to[v])):
            u = self.to[v][i]
            if u == p:
                continue
            else:
                self._dfs(u, d+1, c+self.co[v][i], v)
    def init(self, root: int = 0) -> None:
        self.root = root
        self._dfs(root)
        for i in range(self.l - 1):
            for v in range(self.N):
                self.par[v][i+1] = self.par[self.par[v][i]][i]
    def lca(self, a: int, b: int) -> int:
        dep_s, dep_l = self.dep[a], self.dep[b]
        if dep_s > dep_l:
            a, b = b, a
            dep_s, dep_l = dep_l, dep_s
        gap = dep_l - dep_s
        L_1 = self.l-1
        par = self.par
        for i in range(L_1, -1, -1):
            leng = 1 << i
            if gap >= leng:
                gap -= leng
                b = par[b][i]
        if a == b:
            return a
        for i in range(L_1, -1, -1):
            na = par[a][i]
            nb = par[b][i]
            if na != nb:
                a, b = na, nb
        return par[a][0]
    def length(self, a: int, b: int) -> int:
        c = self.lca(a, b)
        dep = self.dep
        return dep[a] + dep[b] - dep[c] * 2
    def dist(self, a: int, b: int):
        c = self.lca(a, b)
        costs = self.costs
        return costs[a] + costs[b] - costs[c] * 2

def main():
    N,Q = ILI()
    gr = LCA(N)
    es = [[] for _ in range(N)]
    for i in range(N-1):
        a,b, col, dist = ILI()
        a -= 1; b -= 1
        es[a].append((b, dist, col))
        es[b].append((a, dist, col))
        gr.add_edge(a, b, dist)

    gr.init()
    ans = [0] * Q
    qs = [[] for _ in range(N)]
    for i in range(Q):
        cx,dy, a,b = ILI()
        a -= 1; b -= 1
        #ans[i] = gr.dist(a, b)
        c = gr.lca(a, b)
        ans[i] = gr.costs[a] + gr.costs[b] - gr.costs[c] * 2
        qs[a].append((cx, i, 1, dy))
        qs[b].append((cx, i, 1, dy))
        qs[c].append((cx, i, -2, dy))

    cnt = [0] * N
    sum_ = [0] * N

    def dfs(v: int, p: int = -1) -> None:
        for (col,qid,coeff,dist) in qs[v]:
            x = -sum_[col]
            x += dist * cnt[col]
            ans[qid] += x * coeff
        
        for (to, co, col) in es[v]:
            if to == p:
                continue
            cnt[col] += 1
            sum_[col] += co
            dfs(to, v)
            cnt[col] -= 1
            sum_[col] -= co

    dfs(0)

    for an in ans:
        print(an)


if __name__ == '__main__':
    main()