Problem: Vasya collects coins: he has exactly one coin for every year from 1 to n. Naturally, Vasya keeps all the coins in his collection in the order in which they were released. Once Vasya's younger brother made a change — he took all the coins whose release year dated from l to r inclusively and put them in the reverse order. That is, he took a certain segment [l, r] and reversed it. At that the segment's endpoints did not coincide. For example, if n = 8, then initially Vasya's coins were kept in the order 1 2 3 4 5 6 7 8. If Vasya's younger brother chose the segment [2, 6], then after the reversal the coin order will change to 1 6 5 4 3 2 7 8. Vasya suspects that someone else could have spoilt the permutation after his brother. Help him to find that out. Check if the given permutation can be obtained from the permutation 1 2 ... n using exactly one segment reversal. If it is possible, find the segment itself.

Input

The first line contains an integer n (1 ≤ n ≤ 1000) which is the number of coins in Vasya's collection. The second line contains space-separated n integers which are the spoilt sequence of coins. It is guaranteed that the given sequence is a permutation, i.e. it contains only integers from 1 to n, and every number is used exactly 1 time.

Output

If it is impossible to obtain the given permutation from the original one in exactly one action, print 0 0. Otherwise, print two numbers l r (1 ≤ l < r ≤ n) which are the endpoints of the segment that needs to be reversed to obtain from permutation 1 2 ... n the given one.

Examples

Input

8
1 6 5 4 3 2 7 8


Output

2 6


Input

4
2 3 4 1


Output

0 0


Input

4
1 2 3 4


Output

0 0

Solution (in JAVA):

Solution:
import java.util.Scanner;


public class p56b {
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        int n = in.nextInt();
        int[] all  = new int[n];
        for (int i = 0; i < all.length; i++) {
            all[i] = in.nextInt();
        }
        
        int left = 0;
        int right = 0;
        for (int i = 0; i < all.length; i++) {
            if(all[i] != (i+1)) {
                left = i;
                right = all[i]-1;
                
                int[] temp = new int[right - left + 1];
                for (int j = 0; j < temp.length; j++) {
                    temp[j] = all[right - j];
                }
                for(int j = left ; j<=right ; j++) {
                    all[j] = temp[j-left];
                }
                
                for (int k = 0; k < all.length; k++) {
                    if(all[k] != (k+1)) {
                        System.out.println("0 0");
                        return;
                    }
                }
                System.out.println((left+1)+" "+(right+1));
                return;
            }
        }
        System.out.println("0 0");
    }
}