Problem: Jafar has n cans of cola. Each can is described by two integers: remaining volume of cola ai and can's capacity bi (ai ≤  bi).

Jafar has decided to pour all remaining cola into just 2 cans, determine if he can do this or not!

Input

The first line of the input contains one integer n (2 ≤ n ≤ 100 000) — number of cola cans.

The second line contains n space-separated integers a1, a2, ..., an (0 ≤ ai ≤ 109) — volume of remaining cola in cans.

The third line contains n space-separated integers that b1, b2, ..., bn (ai ≤ bi ≤ 109) — capacities of the cans.

Output

Print "YES" (without quotes) if it is possible to pour all remaining cola in 2 cans. Otherwise print "NO" (without quotes).

You can print each letter in any case (upper or lower).

Examples

Input

2
3 5
3 6


Output

YES


Input

3
6 8 9
6 10 12


Output

NO


Input

5
0 0 5 0 0
1 1 8 10 5


Output

YES


Input

4
4 1 0 3
5 2 2 3


Output

YES

Note

In the first sample, there are already 2 cans, so the answer is "YES".

Solution (in JAVA):

Solution:
import java.util.Scanner;

public class main {
  public static void main(String args[]){
  Scanner input = new Scanner(System.in);

  int n = input.nextInt();

  long arr[] = new long[n];
  long brr[] = new long[n];
  long max = Long.MIN_VALUE;
  long second_max = Long.MIN_VALUE;

  long sum = 0;

  for(int i=0;i<n;i++){
    sum += input.nextLong();
  }

  for(int i=0;i<n;i++){
    long z = input.nextLong();
    if(z > max){
      second_max = max;
      max = z;
    } else if(z >= second_max){
        second_max = z;
    }
  }

  // System.out.println(max+" "+second_max+" "+sum);

  if(max + second_max >= sum){
    System.out.println("YES");
  } else {
    System.out.println("NO");
  }
}
}