Problem: This is the easy version of the problem. The difference is the constraint on the sum of lengths of strings and the number of test cases. You can make hacks only if you solve all versions of this task.

You are given a string s, consisting of lowercase English letters. Find the longest string, t, which satisfies the following conditions: 

  * The length of t does not exceed the length of s. 
  * t is a palindrome. 
  * There exists two strings a and b (possibly empty), such that t = a + b ( "+" represents concatenation), and a is prefix of s while b is suffix of s. 

Input

The input consists of multiple test cases. The first line contains a single integer t (1 ≤ t ≤ 1000), the number of test cases. The next t lines each describe a test case.

Each test case is a non-empty string s, consisting of lowercase English letters.

It is guaranteed that the sum of lengths of strings over all test cases does not exceed 5000.

Output

For each test case, print the longest string which satisfies the conditions described above. If there exists multiple possible solutions, print any of them.

Example

Input


5
a
abcdfdcecba
abbaxyzyx
codeforces
acbba


Output


a
abcdfdcba
xyzyx
c
abba

Note

In the first test, the string s = "a" satisfies all conditions.

In the second test, the string "abcdfdcba" satisfies all conditions, because:

  * Its length is 9, which does not exceed the length of the string s, which equals 11. 
  * It is a palindrome. 
  * "abcdfdcba" = "abcdfdc" + "ba", and "abcdfdc" is a prefix of s while "ba" is a suffix of s. 



It can be proven that there does not exist a longer string which satisfies the conditions.

In the fourth test, the string "c" is correct, because "c" = "c" + "" and a or b can be empty. The other possible solution for this test is "s".

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.*;

public class Main {
    FasterScanner sc = new FasterScanner();
    PrintWriter pw = new PrintWriter(System.out);
    static int MOD = 1000000007;

    public static void main(String[] args) {
        Main m = new Main();
        m.solve();
        m.done();
    }

    public void solve() {
        int t = sc.nextInt();
        for (int tt = 0; tt < t; tt++) {
            String s = sc.nextLine();
            char[] C = s.toCharArray();
            if (check(C, 0, C.length - 1)) {
                pw.println(s);
                continue;
            }
            int L = 0;
            int R = C.length - 1;
            while (L < R) { // find where they differ
                if (C[L] != C[R]) break;
                L++;
                R--;
            }
            if (L == 0) { // only prefix or suffix
                int prefixLen = 1;
                int suffixLen = 1;
                for (int i = 1; i < C.length; i++) if (check(C, 0, i)) prefixLen = i+1;
                for (int i = C.length - 2; i >= 0; i--) if (check(C, i, C.length-1)) suffixLen = C.length-i;
                if (prefixLen >= suffixLen) pw.println(s.substring(0, prefixLen));
                else pw.println(s.substring(C.length-suffixLen));
            } else { // concatenation of prefix and suffix
                int prefixLen = 1;
                int suffixLen = 1;
                for (int i = L+1; i <= R; i++) if (check(C, L, i)) prefixLen = i+1-L; // prefix
                for (int i = R-1; i >= L; i--) if (check(C, i, R)) suffixLen = R-i+1; // suffix
                if (prefixLen >= suffixLen) pw.println(s.substring(0, L+prefixLen) + s.substring(R+1));
                else pw.println(s.substring(0, L) + s.substring(R-suffixLen+1));
            }
        }
    }

    public boolean check(char[] C, int L, int R) {
        while (L < R) if (C[L++] != C[R--]) return false;
        return true;
    }

    public void done() {
        pw.flush();
        pw.close();
    }
}

class FasterScanner {
    private byte[] buf = new byte[1024];
    private int curChar;
    private int numChars;

    public int read() {
        if (numChars == -1)
            throw new InputMismatchException();
        if (curChar >= numChars) {
            curChar = 0;
            try {
                numChars = System.in.read(buf);
            } catch (IOException e) {
                throw new InputMismatchException();
            }
            if (numChars <= 0)
                return -1;
        }
        return buf[curChar++];
    }

    public String nextLine() {
        int c = read();
        while (isSpaceChar(c))
            c = read();
        StringBuilder res = new StringBuilder();
        do {
            res.appendCodePoint(c);
            c = read();
        } while (!isEndOfLine(c));
        return res.toString();
    }

    public String nextString() {
        int c = read();
        while (isSpaceChar(c))
            c = read();
        StringBuilder res = new StringBuilder();
        do {
            res.appendCodePoint(c);
            c = read();
        } while (!isSpaceChar(c));
        return res.toString();
    }

    public long nextLong() {
        int c = read();
        while (isSpaceChar(c))
            c = read();
        int sgn = 1;
        if (c == '-') {
            sgn = -1;
            c = read();
        }
        long res = 0;
        do {
            if (c < '0' || c > '9')
                throw new InputMismatchException();
            res *= 10;
            res += c - '0';
            c = read();
        } while (!isSpaceChar(c));
        return res * sgn;
    }

    public int nextInt() {
        int c = read();
        while (isSpaceChar(c))
            c = read();
        int sgn = 1;
        if (c == '-') {
            sgn = -1;
            c = read();
        }
        int res = 0;
        do {
            if (c < '0' || c > '9')
                throw new InputMismatchException();
            res *= 10;
            res += c - '0';
            c = read();
        } while (!isSpaceChar(c));
        return res * sgn;
    }
        
    public int[] nextIntArray(int n) {
        int[] arr = new int[n];
        for (int i = 0; i < n; i++) {
            arr[i] = nextInt();
        }
        return arr;
    }
    
    public long[] nextLongArray(int n) {
        long[] arr = new long[n];
        for (int i = 0; i < n; i++) {
            arr[i] = nextLong();
        }
        return arr;
    }

    private boolean isSpaceChar(int c) {
        return c == ' ' || c == '\n' || c == '\r' || c == '\t' || c == -1;
    }

    private boolean isEndOfLine(int c) {
        return c == '\n' || c == '\r' || c == -1;
    }
}