Problem: While walking down the street Vanya saw a label "Hide&Seek". Because he is a programmer, he used & as a bitwise AND for these two words represented as a integers in base 64 and got new word. Now Vanya thinks of some string s and wants to know the number of pairs of words of length |s| (length of s), such that their bitwise AND is equal to s. As this number can be large, output it modulo 109 + 7.

To represent the string as a number in numeral system with base 64 Vanya uses the following rules:

  * digits from '0' to '9' correspond to integers from 0 to 9; 
  * letters from 'A' to 'Z' correspond to integers from 10 to 35; 
  * letters from 'a' to 'z' correspond to integers from 36 to 61; 
  * letter '-' correspond to integer 62; 
  * letter '_' correspond to integer 63. 

Input

The only line of the input contains a single word s (1 ≤ |s| ≤ 100 000), consisting of digits, lowercase and uppercase English letters, characters '-' and '_'.

Output

Print a single integer — the number of possible pairs of words, such that their bitwise AND is equal to string s modulo 109 + 7.

Examples

Input

z


Output

3


Input

V_V


Output

9


Input

Codeforces


Output

130653412

Note

For a detailed definition of bitwise AND we recommend to take a look in the corresponding article in Wikipedia.

In the first sample, there are 3 possible solutions: 

  1. z&_ = 61&63 = 61 = z
  2. _&z = 63&61 = 61 = z
  3. z&z = 61&61 = 61 = z

Solution (in PYTHON3):

Solution:
def Binary(n):                    #Convierte a binario pero en reversa
    s=""
    while n!=0:
        s+=str(n%2)
        n= n//2
    return s
            
def Zeros(b):                     #Obtiene los ceros
    ones=0
    for i in range(b.__len__()):
        if("1"==b[i]):
            ones+=1
    return 6-ones

def Bitiwise(s):
    total=1
    alphabet= list(
        '0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz-')

    dic = {}
    num=0
    for i in alphabet:
         binary = Binary(alphabet.index(i))   #Convierte a binario
         dic[i]= Zeros(binary)          #Asigna a cada letra su cantidad de 0

    M=int(1e9+7)   
    for i in s:
         if(i=="_"): continue           #Si es _ no tiene ceros
         num = dic[i]
         VR= 3**num                      #VR = 3^k
         total= (total * VR )%M     # VR_total= (V_1 * V_2*...V_n) % (10^9+7)

    print(total)

Bitiwise(input())