Problem: In the NN country, there are n cities, numbered from 1 to n, and n - 1 roads, connecting them. There is a roads path between any two cities.

There are m bidirectional bus routes between cities. Buses drive between two cities taking the shortest path with stops in every city they drive through. Travelling by bus, you can travel from any stop on the route to any other. You can travel between cities only by bus.

You are interested in q questions: is it possible to get from one city to another and what is the minimum number of buses you need to use for it?

Input

The first line contains a single integer n (2 ≤ n ≤ 2 ⋅ 10^5) — the number of cities.

The second line contains n - 1 integers p_2, p_3, …, p_n (1 ≤ p_i < i), where p_i means that cities p_i and i are connected by road.

The third line contains a single integer m (1 ≤ m ≤ 2 ⋅ 10^5) — the number of bus routes.

Each of the next m lines contains 2 integers a and b (1 ≤ a, b ≤ n, a ≠ b), meaning that there is a bus route between cities a and b. It is possible that there is more than one route between two cities.

The next line contains a single integer q (1 ≤ q ≤ 2 ⋅ 10^5) — the number of questions you are interested in.

Each of the next q lines contains 2 integers v and u (1 ≤ v, u ≤ n, v ≠ u), meaning that you are interested if it is possible to get from city v to city u and what is the minimum number of buses you need to use for it.

Output

Print the answer for each question on a separate line. If there is no way to get from one city to another, print -1. Otherwise print the minimum number of buses you have to use.

Examples

Input

7
1 1 1 4 5 6
4
4 2
5 4
1 3
6 7
6
4 5
3 5
7 2
4 5
3 2
5 3


Output

1
3
-1
1
2
3


Input

7
1 1 2 3 4 1
4
4 7
3 5
7 6
7 6
6
4 6
3 1
3 2
2 7
6 3
5 3


Output

1
-1
-1
1
-1
1

Note

<image> Routes for first sample are marked on the picture. 

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
const int MOD = 1e9 + 7;
const long long LINF = 2e16;
const int INF = 2e9;
const int magic = 348;
const double eps = 1e-10;
const double pi = acos(-1);
inline int getint() {
  char ch;
  int res;
  bool f;
  while (!isdigit(ch = getchar()) && ch != '-') {
  }
  if (ch == '-')
    f = false, res = 0;
  else
    f = true, res = ch - '0';
  while (isdigit(ch = getchar())) res = res * 10 + ch - '0';
  return f ? res : -res;
}
int n, m, q;
vector<int> v[200048];
vector<int> vv[200048];
vector<pair<int, int> > qq[200048];
int bef[200048];
int ans[200048];
pair<int, int> a[200048];
int seq[200048], pos[200048], ind = 0;
int L[200048], R[200048], depth[200048];
int anc[200048][21];
pair<int, int> jump[200048][21];
inline void dfs(int cur, int father) {
  seq[++ind] = cur;
  pos[cur] = ind;
  L[cur] = ind;
  int i, j, second;
  for (i = 0; i < int(v[cur].size()); i++) {
    second = v[cur][i];
    if (second != father) {
      depth[second] = depth[cur] + 1;
      anc[second][0] = cur;
      for (j = 1; j <= 20; j++) anc[second][j] = anc[anc[second][j - 1]][j - 1];
      dfs(second, cur);
    }
  }
  R[cur] = ind;
}
inline int getlca(int u, int v) {
  if (depth[u] < depth[v]) swap(u, v);
  for (register int i = 20; i >= 0; i--)
    if (depth[anc[u][i]] >= depth[v]) u = anc[u][i];
  if (u == v) return u;
  for (register int i = 20; i >= 0; i--)
    if (anc[u][i] != anc[v][i]) u = anc[u][i], v = anc[v][i];
  return anc[u][0];
}
namespace SegmentTree {
struct node {
  int left, right;
  int minn, minind;
} tree[1000048];
inline void pushup(int cur) {
  if (tree[cur << 1].minn <= tree[cur << 1 | 1].minn) {
    tree[cur].minn = tree[cur << 1].minn;
    tree[cur].minind = tree[cur << 1].minind;
  } else {
    tree[cur].minn = tree[cur << 1 | 1].minn;
    tree[cur].minind = tree[cur << 1 | 1].minind;
  }
}
inline void build(int cur, int left, int right) {
  tree[cur].left = left;
  tree[cur].right = right;
  if (left != right) {
    int mid = (left + right) >> 1;
    build(cur << 1, left, mid);
    build(cur << 1 | 1, mid + 1, right);
    pushup(cur);
  } else {
    tree[cur].minn = depth[seq[left]];
    tree[cur].minind = seq[left];
  }
}
inline void update(int cur, int pos, int newval, int newind) {
  if (tree[cur].left == tree[cur].right) {
    if (newval < tree[cur].minn) {
      tree[cur].minn = newval;
      tree[cur].minind = newind;
    }
    return;
  }
  int mid = (tree[cur].left + tree[cur].right) >> 1;
  if (pos <= mid)
    update(cur << 1, pos, newval, newind);
  else
    update(cur << 1 | 1, pos, newval, newind);
  pushup(cur);
}
inline pair<int, int> query(int cur, int left, int right) {
  if (left <= tree[cur].left && tree[cur].right <= right)
    return make_pair(tree[cur].minn, tree[cur].minind);
  int mid = (tree[cur].left + tree[cur].right) >> 1;
  pair<int, int> res1 = make_pair(INF, INF), res2 = make_pair(INF, INF);
  if (left <= mid) res1 = query(cur << 1, left, right);
  if (mid + 1 <= right) res2 = query(cur << 1 | 1, left, right);
  return min(res1, res2);
}
}  // namespace SegmentTree
namespace BIT {
int c[400048];
inline void init() { memset(c, 0, sizeof(c)); }
inline void update(int first, int delta) {
  while (first <= n) c[first] += delta, first += first & (-first);
}
inline int query(int first) {
  int res = 0;
  while (first) res += c[first], first -= first & (-first);
  return res;
}
inline int calc(int left, int right) { return query(right) - query(left - 1); }
}  // namespace BIT
inline void Dfs(int cur, int father) {
  int i, second;
  for (i = 0; i < int(qq[cur].size()); i++)
    bef[qq[cur][i].second] =
        BIT::calc(L[qq[cur][i].first], R[qq[cur][i].first]);
  for (i = 0; i < int(vv[cur].size()); i++) BIT::update(pos[vv[cur][i]], 1);
  for (i = 0; i < int(v[cur].size()); i++) {
    second = v[cur][i];
    if (second != father) Dfs(second, cur);
  }
  for (i = 0; i < int(qq[cur].size()); i++)
    if (BIT::calc(L[qq[cur][i].first], R[qq[cur][i].first]) !=
            bef[qq[cur][i].second] ||
        (getlca(cur, qq[cur][i].first) == cur &&
         jump[qq[cur][i].first][0].first <= depth[cur]))
      ans[qq[cur][i].second]++;
    else
      ans[qq[cur][i].second] += 2;
}
int main() {
  int i, j, first, second, LCA;
  n = getint();
  for (i = 2; i <= n; i++) {
    first = getint();
    v[first].push_back(i);
    v[i].push_back(first);
  }
  depth[1] = 1;
  dfs(1, -1);
  SegmentTree::build(1, 1, n);
  m = getint();
  for (i = 1; i <= m; i++) {
    first = getint();
    second = getint();
    vv[first].push_back(second);
    vv[second].push_back(first);
    LCA = getlca(first, second);
    SegmentTree::update(1, pos[first], depth[LCA], LCA);
    SegmentTree::update(1, pos[second], depth[LCA], LCA);
  }
  for (i = 1; i <= n; i++) jump[i][0] = SegmentTree::query(1, L[i], R[i]);
  for (j = 1; j <= 20; j++)
    for (i = 1; i <= n; i++) jump[i][j] = jump[jump[i][j - 1].second][j - 1];
  q = getint();
  int cur, cnt1, cnt2, pt1, pt2;
  for (register int qnum = 1; qnum <= q; qnum++) {
    first = getint();
    second = getint();
    LCA = getlca(first, second);
    cnt1 = 0;
    cur = first;
    for (i = 20; i >= 0; i--)
      if (jump[cur][i].first > depth[LCA])
        cnt1 += (1 << i), cur = jump[cur][i].second;
    if (jump[cur][0].first > depth[LCA]) {
      ans[qnum] = -1;
      continue;
    }
    pt1 = cur;
    cnt2 = 0;
    cur = second;
    for (i = 20; i >= 0; i--)
      if (jump[cur][i].first > depth[LCA])
        cnt2 += (1 << i), cur = jump[cur][i].second;
    if (jump[cur][0].first > depth[LCA]) {
      ans[qnum] = -1;
      continue;
    }
    pt2 = cur;
    if (depth[pt1] > depth[pt2]) swap(pt1, pt2);
    ans[qnum] = cnt1 + cnt2;
    a[qnum] = make_pair(pt1, pt2);
    qq[pt1].push_back(make_pair(pt2, qnum));
  }
  BIT::init();
  Dfs(1, -1);
  for (i = 1; i <= q; i++) printf("%d\n", ans[i]);
  return 0;
}