Problem: While walking down the street Vanya saw a label "Hide&Seek". Because he is a programmer, he used & as a bitwise AND for these two words represented as a integers in base 64 and got new word. Now Vanya thinks of some string s and wants to know the number of pairs of words of length |s| (length of s), such that their bitwise AND is equal to s. As this number can be large, output it modulo 109 + 7.

To represent the string as a number in numeral system with base 64 Vanya uses the following rules:

  * digits from '0' to '9' correspond to integers from 0 to 9; 
  * letters from 'A' to 'Z' correspond to integers from 10 to 35; 
  * letters from 'a' to 'z' correspond to integers from 36 to 61; 
  * letter '-' correspond to integer 62; 
  * letter '_' correspond to integer 63. 

Input

The only line of the input contains a single word s (1 ≤ |s| ≤ 100 000), consisting of digits, lowercase and uppercase English letters, characters '-' and '_'.

Output

Print a single integer — the number of possible pairs of words, such that their bitwise AND is equal to string s modulo 109 + 7.

Examples

Input

z


Output

3


Input

V_V


Output

9


Input

Codeforces


Output

130653412

Note

For a detailed definition of bitwise AND we recommend to take a look in the corresponding article in Wikipedia.

In the first sample, there are 3 possible solutions: 

  1. z&_ = 61&63 = 61 = z
  2. _&z = 63&61 = 61 = z
  3. z&z = 61&61 = 61 = z

Solution (in JAVA):

Solution:
import java.util.*;

public class Solution {

    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);

        String line = in.nextLine();
        char[] lines = line.toCharArray();

        long module = 1000000007;

        char[] dic = new char[64];
        for (int i = 0; i < 64; i++) {
            if (i >= 0 && i < 10) {
                dic[i] = Character.forDigit(i,10);
            } else if (i >= 10 && i < 36) {
                dic[i] = ((char) ('A' + (i - 10)));
            } else if (i >= 36 && i < 62) {
                dic[i] = ((char) ('a' + (i - 36)));
            } else if (i == 62) {
                dic[i] = '-';
            } else {
                dic[i] = '_';
            }
        }
        int[] chars = new int[lines.length];

        for (int i = 0; i < lines.length; i++) {
            for (int j = 0; j < 64; j++) {
                if (dic[j] == lines[i]) {
                    chars[i] = j;
                    break;
                }
            }
        }

        long total = 1;
        for (int i = 0; i < chars.length; i++) {
            int cur = chars[i];
            int count = 0;
            for (int j = 0; j < 6; j++) {
                count += (cur & 1) == 0 ? 1 : 0;
                cur = cur >> 1;
            }
            total *= Math.pow(3, count);
            total %= module;
        }

        System.out.println(total);
    }

}