Problem: Jafar has n cans of cola. Each can is described by two integers: remaining volume of cola ai and can's capacity bi (ai ≤  bi).

Jafar has decided to pour all remaining cola into just 2 cans, determine if he can do this or not!

Input

The first line of the input contains one integer n (2 ≤ n ≤ 100 000) — number of cola cans.

The second line contains n space-separated integers a1, a2, ..., an (0 ≤ ai ≤ 109) — volume of remaining cola in cans.

The third line contains n space-separated integers that b1, b2, ..., bn (ai ≤ bi ≤ 109) — capacities of the cans.

Output

Print "YES" (without quotes) if it is possible to pour all remaining cola in 2 cans. Otherwise print "NO" (without quotes).

You can print each letter in any case (upper or lower).

Examples

Input

2
3 5
3 6


Output

YES


Input

3
6 8 9
6 10 12


Output

NO


Input

5
0 0 5 0 0
1 1 8 10 5


Output

YES


Input

4
4 1 0 3
5 2 2 3


Output

YES

Note

In the first sample, there are already 2 cans, so the answer is "YES".

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.*;


public class TestClass {
 public static void main(String[] args) {
        // TODO code application logic here
        Scanner sc=new Scanner(System.in);
        int n=sc.nextInt();
        int a[]=new int[n];
        int b[]=new int[n];
        long sum=0;
        for(int i=0;i<n;i++){
            a[i]=sc.nextInt();
            sum+=a[i];
        }
        long max=-1;
        for(int i=0;i<n;i++){
            b[i]=sc.nextInt();
            max=Math.max(b[i],max);
        }
        long flag=0,nextmax=-1;
        for(int i=0;i<n;i++){
            if(flag==0 && max==b[i]){
                flag=1;
                continue;
            }
            nextmax=Math.max(nextmax,b[i]);
        }
        if(nextmax+max>=sum)System.out.println("YES");
        else System.out.println("NO");
        
    }
    
}