Problem: Jafar has n cans of cola. Each can is described by two integers: remaining volume of cola ai and can's capacity bi (ai ≤  bi).

Jafar has decided to pour all remaining cola into just 2 cans, determine if he can do this or not!

Input

The first line of the input contains one integer n (2 ≤ n ≤ 100 000) — number of cola cans.

The second line contains n space-separated integers a1, a2, ..., an (0 ≤ ai ≤ 109) — volume of remaining cola in cans.

The third line contains n space-separated integers that b1, b2, ..., bn (ai ≤ bi ≤ 109) — capacities of the cans.

Output

Print "YES" (without quotes) if it is possible to pour all remaining cola in 2 cans. Otherwise print "NO" (without quotes).

You can print each letter in any case (upper or lower).

Examples

Input

2
3 5
3 6


Output

YES


Input

3
6 8 9
6 10 12


Output

NO


Input

5
0 0 5 0 0
1 1 8 10 5


Output

YES


Input

4
4 1 0 3
5 2 2 3


Output

YES

Note

In the first sample, there are already 2 cans, so the answer is "YES".

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.Arrays;

public class C {

	public static void main(String[] args) throws IOException{
		// TODO Auto-generated method stub
		BufferedReader rdr = new BufferedReader(new InputStreamReader(System.in));
		int n = new Integer(rdr.readLine());
		String[]prtsa = rdr.readLine().split(" ");
		String[]prtsb = rdr.readLine().split(" ");
		long[]as = new long[n];
		long[]bs = new long[n];
		long sum = 0;
		for(int i = 0; i < n; i++) {
			as[i] = new Long(prtsa[i]);
			bs[i] = new Long(prtsb[i]);
			sum += as[i];
		}
		Arrays.sort(bs);
		if((bs[n-1] + bs[n-2]) >= sum) {
			System.out.println("YES");
		} else {
			System.out.println("NO");
		}
	}
}