Problem: While walking down the street Vanya saw a label "Hide&Seek". Because he is a programmer, he used & as a bitwise AND for these two words represented as a integers in base 64 and got new word. Now Vanya thinks of some string s and wants to know the number of pairs of words of length |s| (length of s), such that their bitwise AND is equal to s. As this number can be large, output it modulo 109 + 7.

To represent the string as a number in numeral system with base 64 Vanya uses the following rules:

  * digits from '0' to '9' correspond to integers from 0 to 9; 
  * letters from 'A' to 'Z' correspond to integers from 10 to 35; 
  * letters from 'a' to 'z' correspond to integers from 36 to 61; 
  * letter '-' correspond to integer 62; 
  * letter '_' correspond to integer 63. 

Input

The only line of the input contains a single word s (1 ≤ |s| ≤ 100 000), consisting of digits, lowercase and uppercase English letters, characters '-' and '_'.

Output

Print a single integer — the number of possible pairs of words, such that their bitwise AND is equal to string s modulo 109 + 7.

Examples

Input

z


Output

3


Input

V_V


Output

9


Input

Codeforces


Output

130653412

Note

For a detailed definition of bitwise AND we recommend to take a look in the corresponding article in Wikipedia.

In the first sample, there are 3 possible solutions: 

  1. z&_ = 61&63 = 61 = z
  2. _&z = 63&61 = 61 = z
  3. z&z = 61&61 = 61 = z

Solution (in JAVA):

Solution:
//package yr16.m6.codeForces.div355;

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

/**
 * Created by cscvenkatmadurai on 6/1/2016.
 */
public class VanyaAndLabel {
    public static int mapper(char c){

        if(c == '-'){
            return 62;
        }else if(c == '_'){
            return 63;
        }else if( '0'<=c && c<='9' ){

            return c-'0';
        }else if('a'<=c && c<='z'){

            return c-'a'+36;
        }else {

            return c-'A'+10;
        }
    }

    static int findNoOfZero(String x){
        int count = 0;
        for (int i = 0; i < x.length(); i++) {
            if(x.charAt(i)=='0'){
                count++;
            }
        }
        return count+(6-x.length());
    }

    public static void main(String[] args) throws IOException{
        BufferedReader kb = new BufferedReader(new InputStreamReader(System.in));
        String ip = kb.readLine();
        long ans = 1;
        for (int i = 0; i < ip.length(); i++) {
            ans *= Math.pow(3,findNoOfZero(Integer.toBinaryString(mapper(ip.charAt(i) ))));
            ans %=1000000007;
        }
        System.out.println(ans );


    }
}