Problem: Jafar has n cans of cola. Each can is described by two integers: remaining volume of cola ai and can's capacity bi (ai ≤  bi).

Jafar has decided to pour all remaining cola into just 2 cans, determine if he can do this or not!

Input

The first line of the input contains one integer n (2 ≤ n ≤ 100 000) — number of cola cans.

The second line contains n space-separated integers a1, a2, ..., an (0 ≤ ai ≤ 109) — volume of remaining cola in cans.

The third line contains n space-separated integers that b1, b2, ..., bn (ai ≤ bi ≤ 109) — capacities of the cans.

Output

Print "YES" (without quotes) if it is possible to pour all remaining cola in 2 cans. Otherwise print "NO" (without quotes).

You can print each letter in any case (upper or lower).

Examples

Input

2
3 5
3 6


Output

YES


Input

3
6 8 9
6 10 12


Output

NO


Input

5
0 0 5 0 0
1 1 8 10 5


Output

YES


Input

4
4 1 0 3
5 2 2 3


Output

YES

Note

In the first sample, there are already 2 cans, so the answer is "YES".

Solution (in JAVA):

Solution:
import java.util.Scanner;

public class Greed {
    public static void main(String args[]){
        Scanner sc=new Scanner(System.in);
        int n=sc.nextInt(),i;
        long sum_remain=0;
        long tab_cap[]=new long[n];
        for(i=0; i<n; i++){
            sum_remain+=sc.nextInt();
        }
        for(i=0; i<n; i++){
            tab_cap[i]=sc.nextInt();
        }
        long max1=tab_cap[0];
        long max2=tab_cap[1];
        for(i=2; i<n; i++){
            if(tab_cap[i]>max1){
                max2=max1;
                max1=tab_cap[i];

            }else if(tab_cap[i]>max2){
                max2=tab_cap[i];
            }
        }

        if(sum_remain<=(max1+max2)){
            System.out.println("YES");
        }else{
            System.out.println("NO");
        }


    }
}