Problem: There is a tree with N vertices numbered 1 to N. The i-th edge in this tree connects Vertex a_i and Vertex b_i, and the color and length of that edge are c_i and d_i, respectively. Here the color of each edge is represented by an integer between 1 and N-1 (inclusive). The same integer corresponds to the same color, and different integers correspond to different colors.

Answer the following Q queries:

* Query j (1 \leq j \leq Q): assuming that the length of every edge whose color is x_j is changed to y_j, find the distance between Vertex u_j and Vertex v_j. (The changes of the lengths of edges do not affect the subsequent queries.)

Constraints

* 2 \leq N \leq 10^5
* 1 \leq Q \leq 10^5
* 1 \leq a_i, b_i \leq N
* 1 \leq c_i \leq N-1
* 1 \leq d_i \leq 10^4
* 1 \leq x_j \leq N-1
* 1 \leq y_j \leq 10^4
* 1 \leq u_j < v_j \leq N
* The given graph is a tree.
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N Q
a_1 b_1 c_1 d_1
:
a_{N-1} b_{N-1} c_{N-1} d_{N-1}
x_1 y_1 u_1 v_1
:
x_Q y_Q u_Q v_Q


Output

Print Q lines. The j-th line (1 \leq j \leq Q) should contain the answer to Query j.

Example

Input

5 3
1 2 1 10
1 3 2 20
2 4 4 30
5 2 1 40
1 100 1 4
1 100 1 5
3 1000 3 4


Output

130
200
60

Solution (in PYTHON3):

Solution:
import sys
input = sys.stdin.readline

N,Q=map(int,input().split())
EDGE=[list(map(int,input().split())) for i in range(N-1)]
Query=[list(map(int,input().split())) for i in range(Q)]
mod=10**9+7

EDGELIST=[dict() for i in range(N+1)]
for x,y,c,l in EDGE:
    EDGELIST[x][y]=(c,l)
    EDGELIST[y][x]=(c,l)
    
# LCA(オイラーツアー＋Segment tree)

DEPTH=[-1]*(N+1)
DEPTH[1]=0

from collections import deque
QUE = deque([1])
QUE2 = deque()
EULER=[]#(i,j)で,(1からツアーで辿った点の深さ,そのindex)

USED=[0]*(N+1)
while QUE:
    x=QUE.pop()
    EULER.append((DEPTH[x],x))
    if USED[x]==1:
        continue
    for to in EDGELIST[x]:
        
        if USED[to]==0:
            DEPTH[to]=DEPTH[x]+1
            QUE2.append(to)
        else:
            QUE.append(to)
    QUE.extend(QUE2)
    QUE2=deque()
 
    USED[x]=1

MINP=[1<<30]*(N+1)
MAXP=[-1]*(N+1)

for ind,(depth,p) in enumerate(EULER):
    MINP[p]=min(MINP[p],ind)
    MAXP[p]=max(MAXP[p],ind)

LEN=len(EULER)

seg_el=1<<(LEN.bit_length())#Segment treeの台の要素数
SEG=[(1<<30,0)]*(2*seg_el)#1-indexedなので、要素数2*seg_el.Segment treeの初期値で初期化

for i in range(LEN):#Dを対応する箇所へupdate
    SEG[i+seg_el]=EULER[i]

for i in range(seg_el-1,0,-1):#親の部分もupdate
    SEG[i]=min(SEG[i*2],SEG[i*2+1])

def update(n,x,seg_el):#A[n]をxへ更新（反映）
    i=n+seg_el
    SEG[i]=x
    i>>=1#子ノードへ
    
    while i!=0:
        SEG[i]=min(SEG[i*2],SEG[i*2+1])
        i>>=1
        
def getvalues(l,r):#区間[l,r)に関するminを調べる
    L=l+seg_el
    R=r+seg_el
    ANS=(1<<30,0)

    while L<R:
        if L & 1:
            ANS=min(ANS , SEG[L])
            L+=1

        if R & 1:
            R-=1
            ANS=min(ANS , SEG[R])
        L>>=1
        R>>=1

    return ANS

def LCA(l,r):
    return getvalues(min(MINP[l],MINP[r]),max(MAXP[l],MAXP[r])+1)

N_q=[[] for i in range(N+1)]
for ind,(c,pl,x,y) in enumerate(Query):
    N_q[x].append([ind,c,pl,1])
    N_q[y].append([ind,c,pl,1])
    N_q[LCA(x,y)[1]].append([ind,c,pl,0])

ANS=[0]*Q

LENG=0
C_LENGTH=[0]*N
C_SUM=[0]*N

for i in range(1,len(EULER)):
    ind=EULER[i][1]
    c,l=EDGELIST[EULER[i-1][1]][ind]
    if EULER[i][0]>EULER[i-1][0]:
        LENG+=l
        C_LENGTH[c]+=l
        C_SUM[c]+=1

        for que,c,pl,boo in N_q[ind]:
            if boo==1:
                ANS[que]+=LENG+C_SUM[c]*pl-C_LENGTH[c]

            else:
                ANS[que]-=(LENG+C_SUM[c]*pl-C_LENGTH[c])*2
            
    else:
        LENG-=l
        C_LENGTH[c]-=l
        C_SUM[c]-=1

for ans in ANS:
    print(ans)