Problem: Attention: we lost all the test cases for this problem, so instead of solving the problem, we need you to generate test cases. We're going to give you the answer, and you need to print a test case that produces the given answer. The original problem is in the following paragraph.

People don't use cash as often as they used to. Having a credit card solves some of the hassles of cash, such as having to receive change when you can't form the exact amount of money needed to purchase an item. Typically cashiers will give you as few coins as possible in change, but they don't have to. For example, if your change is 30 cents, a cashier could give you a 5 cent piece and a 25 cent piece, or they could give you three 10 cent pieces, or ten 1 cent pieces, two 5 cent pieces, and one 10 cent piece. Altogether there are 18 different ways to make 30 cents using only 1 cent pieces, 5 cent pieces, 10 cent pieces, and 25 cent pieces. Two ways are considered different if they contain a different number of at least one type of coin. Given the denominations of the coins and an amount of change to be made, how many different ways are there to make change?

As we mentioned before, we lost all the test cases for this problem, so we're actually going to give you the number of ways, and want you to produce a test case for which the number of ways is the given number. There could be many ways to achieve this (we guarantee there's always at least one), so you can print any, as long as it meets the constraints described below.

Input

Input will consist of a single integer A (1 ≤ A ≤ 105), the desired number of ways.

Output

In the first line print integers N and M (1 ≤ N ≤ 106, 1 ≤ M ≤ 10), the amount of change to be made, and the number of denominations, respectively.

Then print M integers D1, D2, ..., DM (1 ≤ Di ≤ 106), the denominations of the coins. All denominations must be distinct: for any i ≠ j we must have Di ≠ Dj.

If there are multiple tests, print any of them. You can print denominations in atbitrary order.

Examples

Input

18


Output

30 4
1 5 10 25


Input

3


Output

20 2
5 2


Input

314


Output

183 4
6 5 2 139

Solution (in JAVA):

Solution:
import java.util.*;
import java.io.*;
public class Main
{
 
	static ArrayList<Integer> adj[];
	static char color[];
	static boolean b[],visited[],possible;
	static int level[];
	static Map<Integer,HashSet<Integer>> s;
	static int totalnodes,colored;
	static int count[];
	static long sum[];
	static int nodes;
	static double ans=0;
	static long[] as=new long[10001];
	static long c1=0,c2=0;
	static int[] a,d,k;
	static int max=100000000;
	public static void main(String[] args) throws IOException
	{
		in=new InputReader(System.in);
		w=new PrintWriter(System.out);
	      int n=in.nextInt();
	      if(n==1)
	      {
	    	  w.println("1 1");
	          w.print(1);
	      }
	      else
	      {
	        w.println((2*(n-1))+" 2");
	        w.print("1 2");
	      }
       w.close();
    }
	public static int[] kthAncestors(int[] a,int[] c,int n,int k)
	{
		int[] ans=new int[n+1];
		ans[1]=-1;
		for(int i=2;i<=n;i++)
		{
			int temp=0;
			boolean r=false;
			int j=i;
			while(a[j]!=j)
			{
				if(c[j]==c[a[j]])
					temp++;
				if(temp==k)
					{
					ans[i]=a[j];
					r=true;
					break;
					}
				j=a[j];
			}
			if(r==false)
				ans[i]=-1;
		}
		
		return ans;
	}
	public static void printDivisors(int n)
    {
        for (int i=1; i<=Math.sqrt(n); i++)
        {
            if (n%i==0)
            {
                if (n/i == i)
                    k[i]++;
                else 
                {
                	k[i]++;
                	k[n/i]++;
                }
            }
        }
    }
   private static void nextIntArray() 
	{
	   int n=a.length;
		 for(int i=0;i<n;i++)
			 a[i]=in.nextInt();
		
	}
	
  public static void bfs()
  {
	 level[1]=1;
	 visited[1]=true;
	 Queue<Integer> q=new LinkedList<Integer>();
	 q.add(1);
	 while(!q.isEmpty())
	 {
		 int t=q.poll();
		 for(int i=0;i<adj[t].size();i++)
		 {
			 if(!visited[adj[t].get(i)])
			 {
				 level[adj[t].get(i)]=level[t]+1;
				 visited[adj[t].get(i)]=true;
				 q.add(adj[t].get(i));
			 }
		 }
	 }
  }
  
  public static void dfs(int i)
  {
	  visited[i]=true;
	  for(int j:adj[i])
	  {
		  if(!visited[j])
			  {
			  dfs(j);
			  nodes++;
			  }
	  }
	  
  }
  public static String rev(String s)
	{
		StringBuilder sb=new StringBuilder(s);
		sb.reverse();
		return sb.toString();
	}
	static long lcm(long a, long b)
	{
	    return a * (b / gcd(a, b));
	}
	static long gcd(long a, long b)
	{
	    while (b > 0)
	    {
	        long temp = b;
	        b = a % b; // % is remainder
	        a = temp;
	    }
	    return a;
	}
	static InputReader in;
	static PrintWriter w;
static class InputReader 
{
 
private final InputStream stream;
private final byte[] buf = new byte[8192];
private int curChar, snumChars;
private SpaceCharFilter filter;
 
public InputReader(InputStream stream)
{
  this.stream = stream;
}
 
public int snext()
{
  if (snumChars == -1)
    throw new InputMismatchException();
  if (curChar >= snumChars)
  {
    curChar = 0;
    try 
    {
      snumChars = stream.read(buf);
    }
    catch (IOException e)
    {
      throw new InputMismatchException();
    }
    if (snumChars <= 0)
      return -1;
  }
  return buf[curChar++];
}
 
public int nextInt() 
{
  int c = snext();
  while (isSpaceChar(c)) 
  {
    c = snext();
  }
  int sgn = 1;
  if (c == '-')
  {
    sgn = -1;
    c = snext();
  }
  int res = 0;
  do
  {
    if (c < '0' || c > '9')
      throw new InputMismatchException();
    res *= 10;
    res += c - '0';
    c = snext();
  }
  while (!isSpaceChar(c));
  return res * sgn;
}
 
public long nextLong() 
{
  int c = snext();
  while (isSpaceChar(c)) 
  {
    c = snext();
  }
  int sgn = 1;
  if (c == '-')
  {
    sgn = -1;
    c = snext();
  }
  long res = 0;
  do
  {
    if (c < '0' || c > '9')
      throw new InputMismatchException();
    res *= 10;
    res += c - '0';
    c = snext();
  }
  while (!isSpaceChar(c));
  return res * sgn;
}
 
public static void nextIntArray(int n) 
{
	 for(int i=0;i<n;i++)
		 a[i]=in.nextInt();
}
	    
public int[] nextIntArray(int n, int off)
{
	 int[] arr = new int[n + off];
	   for (int i = 0; i < n; i++)
	   {
	    arr[i + off] = nextInt();
	    }
	    return arr;
	    }
	    
public long[] nextLongArray(int n)
{
return nextLongArray(n, 0);
	    }
        
	public long[] nextLongArray(int n, int off)
	{
	 long[] arr = new long[n + off];
	 for (int i = 0; i < n; i++)
	 {
		  arr[i + off] = nextLong();
		 }
 return arr;
	}
 
 
public String readString() 
{
  int c = snext();
  while (isSpaceChar(c)) 
  {
    c = snext();
  }
  StringBuilder res = new StringBuilder();
  do
  {
    res.appendCodePoint(c);
    c = snext();
  }
  while (!isSpaceChar(c));
  return res.toString();
}
 
public String nextLine() 
{
  int c = snext();
  while (isSpaceChar(c))
    c = snext();
  StringBuilder res = new StringBuilder();
  do
  {
    res.appendCodePoint(c);
    c = snext();
  }
  while (!isEndOfLine(c));
  return res.toString();
}
 
public boolean isSpaceChar(int c)
{
  if (filter != null)
    return filter.isSpaceChar(c);
  return c == ' ' || c == '\n' || c == '\r' || c == '\t' || c == -1;
}
 
private boolean isEndOfLine(int c) 
{
  return c == '\n' || c == '\r' || c == -1;
}
 
public interface SpaceCharFilter
{
  public boolean isSpaceChar(int ch);
}
}
	
}