Problem: Snuke is introducing a robot arm with the following properties to his factory:

* The robot arm consists of m sections and m+1 joints. The sections are numbered 1, 2, ..., m, and the joints are numbered 0, 1, ..., m. Section i connects Joint i-1 and Joint i. The length of Section i is d_i.
* For each section, its mode can be specified individually. There are four modes: `L`, `R`, `D` and `U`. The mode of a section decides the direction of that section. If we consider the factory as a coordinate plane, the position of Joint i will be determined as follows (we denote its coordinates as (x_i, y_i)):
* (x_0, y_0) = (0, 0).
* If the mode of Section i is `L`, (x_{i}, y_{i}) = (x_{i-1} - d_{i}, y_{i-1}).
* If the mode of Section i is `R`, (x_{i}, y_{i}) = (x_{i-1} + d_{i}, y_{i-1}).
* If the mode of Section i is `D`, (x_{i}, y_{i}) = (x_{i-1}, y_{i-1} - d_{i}).
* If the mode of Section i is `U`, (x_{i}, y_{i}) = (x_{i-1}, y_{i-1} + d_{i}).



Snuke would like to introduce a robot arm so that the position of Joint m can be matched with all of the N points (X_1, Y_1), (X_2, Y_2), ..., (X_N, Y_N) by properly specifying the modes of the sections. Is this possible? If so, find such a robot arm and how to bring Joint m to each point (X_j, Y_j).

Constraints

* All values in input are integers.
* 1 \leq N \leq 1000
* -10^9 \leq X_i \leq 10^9
* -10^9 \leq Y_i \leq 10^9

Input

Input is given from Standard Input in the following format:


N
X_1 Y_1
X_2 Y_2
:
X_N Y_N


Output

If the condition can be satisfied, follow the following format. If the condition cannot be satisfied, print `-1`.


m
d_1 d_2 ... d_m
w_1
w_2
:
w_N


m and d_i are the configurations of the robot arm. Refer to the problem statement for what each of them means. Here, 1 \leq m \leq 40 and 1 \leq d_i \leq 10^{12} must hold. Also, m and d_i must all be integers.

w_j is a string of length m that represents the way to bring Joint m of the robot arm to point (X_j, Y_j). The i-th character of w_j should be one of the letters `L`, `R`, `D` and `U`, representing the mode of Section i.

Examples

Input

3
-1 0
0 3
2 -1


Output

2
1 2
RL
UU
DR


Input

5
0 0
1 0
2 0
3 0
4 0


Output

-1


Input

2
1 1
1 1


Output

2
1 1
RU
UR


Input

3
-7 -3
7 3
-3 -7


Output

5
3 1 4 1 5
LRDUL
RDULR
DULRD

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
#define rep(i,n) for (int (i)=(0);(i)<(long long)(n);++(i))
using ll = long long;
using P = pair<int, int>;
using namespace std;

int main() {
    int N;
    cin >> N;
    vector<pair<ll, ll>> pos(N);
    rep(i, N) cin >> pos[i].first >> pos[i].second;

    int par = (abs(pos[0].first) + abs(pos[0].second)) % 2;
    bool no = false;
    rep(i, N) {
        int par2 = (abs(pos[i].first) + abs(pos[i].second)) % 2;
        pos[i] = {pos[i].first + pos[i].second, pos[i].first - pos[i].second};
        if (par2 != par) {
            no = true;
        }
    }

    if (no) {
        cout << -1 << endl;
        return 0;
    }

    vector<ll> d;
    for (int i=30; i>=0; --i) d.push_back(1LL<<i);
    if (par%2 == 0) d.push_back(1);
    cout << d.size() << endl;
    rep(i, d.size()) cout << d[i] << " ";
    cout << endl;

    rep(i, N) {
        int xdir, ydir;
        ll xsum = 0, ysum = 0;
        rep(j, d.size()) {
            if (xsum <= pos[i].first) xdir = 1, xsum += d[j];
            else xdir = -1, xsum -= d[j];
            if (ysum <= pos[i].second) ydir = 1, ysum += d[j];
            else ydir = -1, ysum -= d[j];

            if (xdir == 1 and ydir == 1) cout << "R";
            else if (xdir == 1 and ydir == -1) cout << "U";
            else if (xdir == -1 and ydir == -1) cout << "L";
            else cout << "D";
        }
        cout << endl;
    }

    return 0;
}