Problem: Jafar has n cans of cola. Each can is described by two integers: remaining volume of cola ai and can's capacity bi (ai ≤  bi).

Jafar has decided to pour all remaining cola into just 2 cans, determine if he can do this or not!

Input

The first line of the input contains one integer n (2 ≤ n ≤ 100 000) — number of cola cans.

The second line contains n space-separated integers a1, a2, ..., an (0 ≤ ai ≤ 109) — volume of remaining cola in cans.

The third line contains n space-separated integers that b1, b2, ..., bn (ai ≤ bi ≤ 109) — capacities of the cans.

Output

Print "YES" (without quotes) if it is possible to pour all remaining cola in 2 cans. Otherwise print "NO" (without quotes).

You can print each letter in any case (upper or lower).

Examples

Input

2
3 5
3 6


Output

YES


Input

3
6 8 9
6 10 12


Output

NO


Input

5
0 0 5 0 0
1 1 8 10 5


Output

YES


Input

4
4 1 0 3
5 2 2 3


Output

YES

Note

In the first sample, there are already 2 cans, so the answer is "YES".

Solution (in JAVA):

Solution:
/*package whatever //do not write package name here */

import java.io.*;
import java.util.*;
import java.util.Locale;

public class GFG {
	public static void main (String[] args) {
	    Scanner sc = new Scanner(System.in);
	    
	   int n = sc.nextInt();
	   
	   int[] a = new int[n];
	   int[] b = new int[n];
	   long remain = 0;
	   
	   for(int i =0;i<n;i++){
	       a[i] = sc.nextInt();
	       remain += a[i];
	   }
	   
	   for(int i=0;i<n;i++){
	       b[i] = sc.nextInt();
	   }
	   
	   Arrays.sort(b);
	   
	   long sum = b[n-2] + b[n-1];
	   
	   if(remain <= sum){
	       System.out.println("YES");
	   }else{
	       System.out.println("NO");
	   }
	   
	  
	  
		
		
		
	}
}