Problem: A schoolboy Petya studies square equations. The equations that are included in the school curriculum, usually look simple: 

x2 + 2bx + c = 0 where b, c are natural numbers.

Petya noticed that some equations have two real roots, some of them have only one root and some equations don't have real roots at all. Moreover it turned out that several different square equations can have a common root.

Petya is interested in how many different real roots have all the equations of the type described above for all the possible pairs of numbers b and c such that 1 ≤ b ≤ n, 1 ≤ c ≤ m. Help Petya find that number.

Input

The single line contains two integers n and m. (1 ≤ n, m ≤ 5000000).

Output

Print a single number which is the number of real roots of the described set of equations.

Examples

Input

3 3


Output

12


Input

1 2


Output

1

Note

In the second test from the statement the following equations are analysed:

b = 1, c = 1: x2 + 2x + 1 = 0; The root is x = - 1

b = 1, c = 2: x2 + 2x + 2 = 0; No roots

Overall there's one root

In the second test the following equations are analysed:

b = 1, c = 1: x2 + 2x + 1 = 0; The root is x = - 1

b = 1, c = 2: x2 + 2x + 2 = 0; No roots

b = 1, c = 3: x2 + 2x + 3 = 0; No roots

b = 2, c = 1: x2 + 4x + 1 = 0; The roots are <image>

b = 2, c = 2: x2 + 4x + 2 = 0; The roots are <image>

b = 2, c = 3: x2 + 4x + 3 = 0; The roots are x1 = - 3, x2 = - 1

b = 3, c = 1: x2 + 6x + 1 = 0; The roots are <image>

b = 3, c = 2: x2 + 6x + 2 = 0; The roots are <image>

b = 3, c = 3: x2 + 6x + 3 = 0; The roots are <image> Overall there are 13 roots and as the root  - 1 is repeated twice, that means there are 12 different roots.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
inline long long sqr(long long first) { return first * first; }
bool covered[50000000];
inline long long query(int pos, long long left, long long right,
                       long long first, long long second) {
  if (left == right) return covered[pos];
  if (covered[pos]) return second - first + 1;
  long long mid = (left + right) / 2;
  if (second <= mid)
    return query(pos * 2 + 1, left, mid, first, second);
  else if (first > mid)
    return query(pos * 2 + 2, mid + 1, right, first, second);
  else
    return query(pos * 2 + 1, left, mid, first, mid) +
           query(pos * 2 + 2, mid + 1, right, mid + 1, second);
}
inline void update(int pos, long long left, long long right, long long first,
                   long long second) {
  if (covered[pos]) return;
  if (second < first) return;
  if (left == first && right == second) {
    covered[pos] = 1;
    return;
  }
  long long mid = (left + right) / 2;
  if (second <= mid)
    update(pos * 2 + 1, left, mid, first, second);
  else if (first > mid)
    update(pos * 2 + 2, mid + 1, right, first, second);
  else
    update(pos * 2 + 1, left, mid, first, mid),
        update(pos * 2 + 2, mid + 1, right, mid + 1, second);
  covered[pos] |= covered[pos * 2 + 1] & covered[pos * 2 + 2];
}
int main(int argc, char **argv) {
  long long N, M;
  cin >> N >> M;
  long long res = 0;
  for (long long b = (1); b < (N + 1); ++b) {
    long long h = min(M, b * b);
    long long first = (long long)(ceil(sqrt(b * b - h) - 1e-9)),
              second = (long long)(floor(sqrt(b * b - 1.) + 1e-9));
    int num = max(0LL, second - first + 1), num2 = 0;
    if (!num) {
      res += 2 * h;
      continue;
    }
    res += 2 * (h - num);
    long long Q = query(0, 0, 2 * N, 2 * N - b + first, 2 * N - b + second);
    update(0, 0, 2 * N, 2 * N - b + first, 2 * N - b + second);
    res += max(0LL, (second - first + 1) - Q);
    Q = query(0, 0, 2 * N, 2 * N - b - second, 2 * N - b - first);
    res += max(0LL, (second - first + 1) - Q);
    update(0, 0, 2 * N, 2 * N - b - second, 2 * N - b - first);
  }
  cout << res << endl;
  return 0;
}