Problem: Jafar has n cans of cola. Each can is described by two integers: remaining volume of cola ai and can's capacity bi (ai ≤  bi).

Jafar has decided to pour all remaining cola into just 2 cans, determine if he can do this or not!

Input

The first line of the input contains one integer n (2 ≤ n ≤ 100 000) — number of cola cans.

The second line contains n space-separated integers a1, a2, ..., an (0 ≤ ai ≤ 109) — volume of remaining cola in cans.

The third line contains n space-separated integers that b1, b2, ..., bn (ai ≤ bi ≤ 109) — capacities of the cans.

Output

Print "YES" (without quotes) if it is possible to pour all remaining cola in 2 cans. Otherwise print "NO" (without quotes).

You can print each letter in any case (upper or lower).

Examples

Input

2
3 5
3 6


Output

YES


Input

3
6 8 9
6 10 12


Output

NO


Input

5
0 0 5 0 0
1 1 8 10 5


Output

YES


Input

4
4 1 0 3
5 2 2 3


Output

YES

Note

In the first sample, there are already 2 cans, so the answer is "YES".

Solution (in JAVA):

Solution:
import java.lang.invoke.ConstantCallSite;
import java.lang.reflect.Array;
import java.util.Arrays;
import java.util.Random;
import java.util.Scanner;

public class test {
    public static void main(String ... args) {
        Scanner cin = new Scanner(System.in);
        int n;
        long sum = 0;
        int []a = new int[100010];
        int []b = new int[100010];
        n = cin.nextInt();
        for(int i = 0; i < n; i++)
        {
        	a[i] = cin.nextInt();
        	sum += a[i];
        }
        for(int i = 0; i < n; i++)
        	b[i] = cin.nextInt();
        cin.close();
        Arrays.sort(b, 0, n);
        if(sum > b[n - 1] + b[n - 2])
        	System.out.println("NO");
        else 
        	System.out.println("YES");
    }
}