Problem: A robot is standing at the origin of the infinite two-dimensional plane. Each second the robot moves exactly 1 meter in one of the four cardinal directions: north, south, west, and east. For the first step the robot can choose any of the four directions, but then at the end of every second it has to turn 90 degrees left or right with respect to the direction it just moved in. For example, if the robot has just moved north or south, the next step it takes has to be either west or east, and vice versa.

The robot makes exactly n steps from its starting position according to the rules above. How many different points can the robot arrive to at the end? The final orientation of the robot can be ignored.

Input

The only line contains a single integer n (1 ≤ n ≤ 1000) — the number of steps the robot makes.

Output

Print a single integer — the number of different possible locations after exactly n steps.

Examples

Input


1


Output


4


Input


2


Output


4


Input


3


Output


12

Note

In the first sample case, the robot will end up 1 meter north, south, west, or east depending on its initial direction.

In the second sample case, the robot will always end up √{2} meters north-west, north-east, south-west, or south-east.

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.*;

public class Codeforces {

    static Scanner sc = new Scanner(System.in);
    static BufferedReader br = new BufferedReader(new InputStreamReader(System.in));

    public static long GCD(long a,long b){
        if (b == 0)
            return a;
        return GCD(b,a%b);
    }

    static int highestPowerof2(int n) {
        int p = (int)(Math.log(n) /
                Math.log(2));
        return (int)Math.pow(2, p);
    }

    public static int binsearch(long[] a,long x){
        int l = 0;
        int r = a.length - 1;
        while (l <= r){
            int mid = l + (r-l)/2;
            if (a[mid]==x)
                return 1;
            else if (a[mid] < x)
                l = mid+1;
            else
                r = mid-1;
        }
        return -1;
    }

    public static int upperbound(long[] arr,long key){
        int start=0;int end=arr.length-1;
        int idx=-1;
        int mid;
        while(start<=end){
            int i=(start+end)/2;
            if(arr[i]<key){
                start=i+1;
            }
            else if(arr[i]>key){
                end=i-1;
            }
            else{
                idx=i;
                start=i+1;
            }
        }

        return idx;    }

    public static int lowerbound(long[] arr,long key){
        int start=0;int end=arr.length-1;
        int idx=-1;
        int mid;
        while(start<=end){
            int i=(start+end)/2;
            if(arr[i]<key){
                start=i+1;
            }
            else if(arr[i]>key){
                end=i-1;
            }
            else{
                idx=i;
                end=i-1;
            }
        }
        return idx;
    }

    public static int searchInsert(long[] nums, long target) {
        int s=0,e=nums.length-1;
        int mid;
        if(target<nums[0]){
            return 0;
        }
        while(s<=e){
            mid=(s+e)/2;
            if(nums[mid]>target){
                e=mid-1;
            }
            else if(nums[mid]==target){
                return mid;
            }
            else{
                s=mid+1;
            }
        }
        return s;
    }

    public static class Pair<T1,T2>{
        T1 first;
        T2 second;
        Pair(T1 a,T2 b){
            this.first = a;
            this.second = b;
        }

        @Override
        public String toString() {
            return "[" + first + ", " + second + "]";
        }
    }

    static boolean isPrime(long n) {
        if (n <= 1)
            return false;
        if (n <= 3)
            return true;

        if (n % 2 == 0 || n % 3 == 0)
            return false;

        for (long i = 5; i <= Math.sqrt(n); i = i + 6)
            if (n % i == 0 || n % (i + 2) == 0)
                return false;

        return true;
    }

    public static long fastExpo(long a,int n,int mod){
        if (n == 0)
            return 1;
        else{
            if ((n&1) == 1){
                long x = fastExpo(a,n/2,mod);
                return (((a*x)%mod)*x)%mod;
            }
            else{
                long x = fastExpo(a,n/2,mod);
                return (((x%mod)*(x%mod))%mod)%mod;
            }
        }
    }

    public static long modInverse(long n,int p){
        return fastExpo(n,p-2,p);
    }

    public static long nCr(int n,int r,long[] fact,int mod){
        long val =  (((fact[n] * modInverse(fact[r],mod))%mod)*modInverse(fact[n-r],mod))%mod;
        return val;
    }

    public static void factorial(long[] fact,int n,int mod){
        for (int i=1;i<=n;i++){
            fact[i] = (fact[i-1] * i)%mod;
        }
    }

    public static int log2(long val){
        return (int) Math.floor(Math.log(val)/Math.log(2));
    }

    public static void solve() throws IOException {
        int n = sc.nextInt();
        if ((n&1) == 0){
            int k = n/2;
            int ans = (k+1)*(k+1);
            System.out.println(ans);
        }
        else{
            int k = n/2;
            int ans = 2*(k+1)*(k+2);
            System.out.println(ans);
        }
    }
    public static void main(String[] args) throws IOException{
        int t;
        t = 1;//sc.nextInt();
        while (t-- > 0){
            solve();
        }
    }
}