Problem: There are r red and g green blocks for construction of the red-green tower. Red-green tower can be built following next rules:

  * Red-green tower is consisting of some number of levels;

  * Let the red-green tower consist of n levels, then the first level of this tower should consist of n blocks, second level — of n - 1 blocks, the third one — of n - 2 blocks, and so on — the last level of such tower should consist of the one block. In other words, each successive level should contain one block less than the previous one;

  * Each level of the red-green tower should contain blocks of the same color.

<image>

Let h be the maximum possible number of levels of red-green tower, that can be built out of r red and g green blocks meeting the rules above. The task is to determine how many different red-green towers having h levels can be built out of the available blocks.

Two red-green towers are considered different if there exists some level, that consists of red blocks in the one tower and consists of green blocks in the other tower.

You are to write a program that will find the number of different red-green towers of height h modulo 109 + 7.

Input

The only line of input contains two integers r and g, separated by a single space — the number of available red and green blocks respectively (0 ≤ r, g ≤ 2·105, r + g ≥ 1).

Output

Output the only integer — the number of different possible red-green towers of height h modulo 109 + 7.

Examples

Input

4 6


Output

2


Input

9 7


Output

6


Input

1 1


Output

2

Note

The image in the problem statement shows all possible red-green towers for the first sample.

Solution (in JAVA):

Solution:

/* 
Keep solving problems. 
*/
import java.util.*;
import java.io.*;

public class CF478D {

    BufferedReader br;
    PrintWriter out;
    StringTokenizer st;
    boolean eof;
    final long MOD = 1000L * 1000L * 1000L + 7;
    void solve() throws IOException {
        int r = nextInt();
        int g = nextInt();

        int n = 200000 + 1;
        int[] arr0 = new int[n];
        int[] arr1 = new int[n];
        arr0[0] = 1;
        long res = 1;
        for(int i = 0; i < 900; i++) {
            Arrays.fill(arr1, 0);
            int sum = (i + 1) * (i + 2) / 2;
            int limit = Math.min(n, sum + 10);
            for(int j = 0; j < limit; j++) {
                if(arr0[j] == 0) {
                    continue;
                }
                arr1[j] += arr0[j];
                if(arr1[j] >= MOD) {
                    arr1[j] -= MOD;
                }
                if(j + i + 1 < n) {
                    arr1[j + i + 1] = arr0[j];
                    if (arr1[j + i + 1] >= MOD) {
                        arr1[j + i + 1] -= MOD;
                    }
                }
            }

            long tmp = 0;
            int low = Math.max(0, sum - g);
            for(int j = low; j <= r; j++) {
                tmp += arr1[j];
                if(tmp >= MOD) {
                    tmp -= MOD;
                }
            }
            if(tmp != 0) {
                res = tmp;
            }
            for(int j = 0; j < n; j++) {
                arr0[j] = arr1[j];
            }
        }
        out(res);
    }
    void shuffle(int[] a) {
        int n = a.length;
        for(int i = 0; i < n; i++) {
            int r = i + (int) (Math.random() * (n - i));
            int tmp = a[i];
            a[i] = a[r];
            a[r] = tmp;
        }
    }
    private void outln(Object o) {
        out.println(o);
    }
    private void out(Object o) {
        out.print(o);
    }
    public CF478D() throws IOException {
        br = new BufferedReader(new InputStreamReader(System.in));
        out = new PrintWriter(System.out);
        solve();
        out.close();
    }
    public static void main(String[] args) throws IOException {
        new CF478D();
    }

    public long[] nextLongArr(int n) throws IOException{
        long[] res = new long[n];
        for(int i = 0; i < n; i++)
            res[i] = nextLong();
        return res;
    }
    public int[] nextIntArr(int n) throws IOException {
        int[] res = new int[n];
        for(int i = 0; i < n; i++)
            res[i] = nextInt();
        return res;
    }
    public String nextToken() {
        while (st == null || !st.hasMoreTokens()) {
            try {
                st = new StringTokenizer(br.readLine());
            } catch (Exception e) {
                eof = true;
                return null;
            }
        }
        return st.nextToken();
    }
    public String nextString() {
        try {
            return br.readLine();
        } catch (IOException e) {
            eof = true;
            return null;
        }
    }
    public int nextInt() throws IOException {
        return Integer.parseInt(nextToken());
    }
    public long nextLong() throws IOException {
        return Long.parseLong(nextToken());
    }
    public double nextDouble() throws IOException {
        return Double.parseDouble(nextToken());
    }
}