Problem: For a set $S$ of integers, perform a sequence of the following operations. Note that multiple elements can have equivalent values in $S$.

* insert($x$): Insert $x$ to $S$ and report the number of elements in $S$ after the operation.
* find($x$): Report the number of $x$ in $S$.
* delete($x$): Delete all $x$ from $S$.
* dump($L$, $R$): Print elements $x$ in $S$ such that $L \leq x \leq R$.

Constraints

* $1 \leq q \leq 200,000$
* $0 \leq x \leq 1,000,000,000$
* The total number of elements printed by dump operations does not exceed $1,000,000$
* The sum of numbers printed by find operations does not exceed $2,000,000$

Input

The input is given in the following format.


$q$
$query_1$
$query_2$
:
$query_q$


Each query $query_i$ is given by


0 $x$


or


1 $x$


or


2 $x$


or


3 $L$ $R$


where the first digits 0, 1, 2 and 3 represent insert, find, delete and dump operations respectively.

Output

For each insert operation, print the number of elements in $S$.
For each find operation, print the number of specified elements in $S$.
For each dump operation, print the corresponding elements in ascending order. Print an element in a line.

Example

Input

10
0 1
0 1
0 2
0 3
2 2
1 1
1 2
1 3
0 4
3 1 4


Output

1
2
3
4
2
0
1
4
1
1
3
4

Solution (in CPP):

Solution:
# include <iostream>
# include <set>
using namespace std;

int main() {
    int num_query; scanf("%d", &num_query);
    int command, x, left, right;
    multiset<int> S;
    
    for (int i = 0; i < num_query; ++i) {
        scanf("%d", &command);
        
        switch (command) {
            case 0:
                scanf("%d", &x);
                S.insert(x);
                printf("%d\n", (int) S.size());
                break;
            case 1:
                scanf("%d", &x);
                printf("%d\n", S.count(x));
                break;
            case 2:
                scanf("%d", &x);
                S.erase(x);
                break;
            case 3:
                scanf("%d%d", &left, &right);
                auto lower_itr = S.lower_bound(left);
                auto upper_itr = S.upper_bound(right);
                
                for (auto itr = lower_itr; itr != upper_itr; ++itr) printf("%d\n", *itr);
                break;
        }
    }
    return 0;
}