Problem: A word or a sentence in some language is called a pangram if all the characters of the alphabet of this language appear in it at least once. Pangrams are often used to demonstrate fonts in printing or test the output devices.

You are given a string consisting of lowercase and uppercase Latin letters. Check whether this string is a pangram. We say that the string contains a letter of the Latin alphabet if this letter occurs in the string in uppercase or lowercase.

Input

The first line contains a single integer n (1 ≤ n ≤ 100) — the number of characters in the string.

The second line contains the string. The string consists only of uppercase and lowercase Latin letters.

Output

Output "YES", if the string is a pangram and "NO" otherwise.

Examples

Input

12
toosmallword


Output

NO


Input

35
TheQuickBrownFoxJumpsOverTheLazyDog


Output

YES

Solution (in JAVA):

Solution:
import java.io.*;
import java.math.*;
import java.util.*;
import java.lang.*;


 
 
// Warning: Printing unwanted or ill-formatted data to output will cause the test cases to fail
 
public class TestClass {
    public static void main(String args[] ) throws Exception {
        /* Sample code to perform I/O:
         * Use either of these methods for input
 
        //BufferedReader
        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
        String name = br.readLine();                // Reading input from STDIN
        System.out.println("Hi, " + name + ".");    // Writing output to STDOUT
 
        //Scanner
        Scanner s = new Scanner(System.in);
        String name = s.nextLine();                 // Reading input from STDIN
        System.out.println("Hi, " + name + ".");    // Writing output to STDOUT
 
        */
 
        // Write your code here
        PrintWriter pw=new PrintWriter(System.out);
        Scanner scn=new Scanner(System.in);
        int n = scn.nextInt();
        scn.nextLine();
        char[] c = scn.nextLine().toCharArray();
        Set<Integer> s = new HashSet<Integer>();
        
        for(int i=0;i<n;i++){
            if(c[i]>='a'&&c[i]<='z')
                s.add(((int)(c[i]-'a')));
            else if(c[i]>='A'&&c[i]<='Z')
                s.add(((int)(c[i]-'A')));
        }
        if(s.size()==26)
            pw.println("YES");
        else
            pw.println("NO");
        pw.close();
        
        
        
        
        
        
        
        
        
        
        
        
        
        
        
        
        
        
        
        
        
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
    }
   
    
}