Problem: In Pavlopolis University where Noora studies it was decided to hold beauty contest "Miss Pavlopolis University". Let's describe the process of choosing the most beautiful girl in the university in more detail.

The contest is held in several stages. Suppose that exactly n girls participate in the competition initially. All the participants are divided into equal groups, x participants in each group. Furthermore the number x is chosen arbitrarily, i. e. on every stage number x can be different. Within each group the jury of the contest compares beauty of the girls in the format "each with each". In this way, if group consists of x girls, then <image> comparisons occur. Then, from each group, the most beautiful participant is selected. Selected girls enter the next stage of the competition. Thus if n girls were divided into groups, x participants in each group, then exactly <image> participants will enter the next stage. The contest continues until there is exactly one girl left who will be "Miss Pavlopolis University"

But for the jury this contest is a very tedious task. They would like to divide the girls into groups in each stage so that the total number of pairwise comparisons of the girls is as few as possible. Let f(n) be the minimal total number of comparisons that should be made to select the most beautiful participant, if we admit n girls to the first stage.

The organizers of the competition are insane. They give Noora three integers t, l and r and ask the poor girl to calculate the value of the following expression: t0·f(l) + t1·f(l + 1) + ... + tr - l·f(r). However, since the value of this expression can be quite large the organizers ask her to calculate it modulo 109 + 7. If Noora can calculate the value of this expression the organizers promise her to help during the beauty contest. But the poor girl is not strong in mathematics, so she turned for help to Leha and he turned to you.

Input

The first and single line contains three integers t, l and r (1 ≤ t < 109 + 7, 2 ≤ l ≤ r ≤ 5·106).

Output

In the first line print single integer — the value of the expression modulo 109 + 7.

Example

Input

2 2 4


Output

19

Note

Consider the sample.

It is necessary to find the value of <image>.

f(2) = 1. From two girls you can form only one group of two people, in which there will be one comparison.

f(3) = 3. From three girls you can form only one group of three people, in which there will be three comparisons.

f(4) = 3. From four girls you can form two groups of two girls each. Then at the first stage there will be two comparisons, one in each of the two groups. In the second stage there will be two girls and there will be one comparison between them. Total 2 + 1 = 3 comparisons. You can also leave all girls in same group in the first stage. Then <image> comparisons will occur. Obviously, it's better to split girls into groups in the first way.

Then the value of the expression is <image>.

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.OutputStream;
import java.io.PrintWriter;
import java.lang.reflect.Array;
import java.util.*;

public class Main {

    public static void main(String[] args) {
        InputStream inputStream = System.in;
        OutputStream outputStream = System.out;
        Scanner in = new Scanner(inputStream);
        PrintWriter out = new PrintWriter(outputStream);
        Task solver = new Task();
        solver.solve(in, out);
        out.close();
    }
}

class Task {

    //    static int MAX = 1000001;
//    List<List<Integer>> g = new ArrayList<>();
//    int n;
//    char[] s;

    public void solve(Scanner in, PrintWriter out) {
        int t = in.nextInt();
        int l = in.nextInt();
        int r = in.nextInt();

        long[] a = new long[r + 1];
        boolean[] prime = new boolean[r + 1];
        Arrays.fill(prime, true);
        prime[0] = prime[1] = false;
        for (int i = 2; i <= r; i++) {
            if (prime[i]) {
                if ((long)i * i <= (long)r) {
                    for (long j = (long)i*i; j <= r; j+=i) {
                        prime[(int)j] = false;
                    }
                }
            }
        }


        List<Integer> pr = new ArrayList<>();
        for (int i = 2; i <= r; i++) {
            if (prime[i]) {
                pr.add(i);
                a[i] = (long) i * (i - 1) / 2;
            } else {
                for (Integer p : pr) {
                    if (i % p == 0) {
                        int p1 = i / p;
                        int max = Math.max(p, p1);
                        int min = Math.min(p, p1);
                        a[i] = a[min] * max + a[max];
                        break;
                    }
                }
            }
        }

        long tt[] = new long[r];
        tt[0] = 1;
        long temp = 1;
        for (int i = 1; i <= r - l; i++) {
            temp *= (long)t;
            temp %= 1000000007;
            tt[i] = temp;
        }

        long res = 0;
        for (int i = 0; i <= r - l; i++) {
            res += (tt[i] * (a[i + l] % 1000000007)) % 1000000007;
            res %= 1000000007;
        }

        System.out.println(res);
    }


}

class Utils {

    public static int binarySearch(int[] a, int key) {
        int s = 0;
        int f = a.length;
        while (f > s) {
            int mid = (s + f) / 2;
            if (a[mid] > key) {
                f = mid - 1;
            } else if (a[mid] <= key) {
                s = mid + 1;
            }
        }
        return -1;
    }

    public static long gcd(long a, long b) {
        return b != 0 ? gcd(b, a % b) : a;
    }

    public static long lcm(long a, long b) {
        return a / gcd(a, b) * b;
    }

    static List<Integer> prime(int number) {
        List<Integer> a = new ArrayList<>();
        for (int i = 2; i * i <= number; i++) {
            if (number % i == 0) {
                a.add(i);
                number /= i;
                i = 1;
            }
        }
        a.add(number);
        return a;
    }
}

class Pair<T, U> {
    public T a;
    public U b;

    public Pair(T a, U b) {
        this.a = a;
        this.b = b;
    }

    @Override
    public boolean equals(Object o) {
        if (this == o) return true;
        if (o == null || getClass() != o.getClass()) return false;

        Pair<?, ?> pair = (Pair<?, ?>) o;

        if (a != null ? !a.equals(pair.a) : pair.a != null) return false;
        return b != null ? b.equals(pair.b) : pair.b == null;
    }

    @Override
    public int hashCode() {
        int result = a != null ? a.hashCode() : 0;
        result = 31 * result + (b != null ? b.hashCode() : 0);
        return result;
    }
}


class Vect {
    public int a;
    public int b;

    public Vect(int a, int b) {
        this.a = a;
        this.b = b;
    }

    @Override
    public boolean equals(Object o) {
        if (this == o) return true;
        if (o == null || getClass() != o.getClass()) return false;

        Vect vect = (Vect) o;

        if (a != vect.a) return false;
        return b == vect.b;
    }

    @Override
    public int hashCode() {
        int result = a;
        result = 31 * result + b;
        return result;
    }
}

class Tri {
    public int a;
    public int b;
    public int c;

    public Tri(int a, int b, int c) {
        this.a = a;
        this.b = b;
        this.c = c;
    }

    @Override
    public boolean equals(Object o) {
        if (this == o) return true;
        if (o == null || getClass() != o.getClass()) return false;

        Tri tri = (Tri) o;

        if (a != tri.a) return false;
        return b == tri.b;
    }

    @Override
    public int hashCode() {
        int result = a;
        result = 31 * result + b;
        return result;
    }
}

class Triple<T, U, P> {
    public T a;
    public U b;
    public P c;

    public Triple(T a, U b, P c) {
        this.a = a;
        this.b = b;
        this.c = c;
    }

    @Override
    public boolean equals(Object o) {
        if (this == o) return true;
        if (o == null || getClass() != o.getClass()) return false;

        Triple<?, ?, ?> triple = (Triple<?, ?, ?>) o;

        if (a != null ? !a.equals(triple.a) : triple.a != null) return false;
        return b != null ? b.equals(triple.b) : triple.b == null;
    }

    @Override
    public int hashCode() {
        int result = a != null ? a.hashCode() : 0;
        result = 31 * result + (b != null ? b.hashCode() : 0);
        return result;
    }
}


class Scanner {
    BufferedReader in;
    StringTokenizer tok;

    public Scanner(InputStream in) {
        this.in = new BufferedReader(new InputStreamReader(in));
        tok = new StringTokenizer("");
    }

    private String tryReadNextLine() {
        try {
            return in.readLine();
        } catch (Exception e) {
            throw new InputMismatchException();
        }
    }

    public String nextToken() {
        while (!tok.hasMoreTokens()) {
            tok = new StringTokenizer(next());
        }
        return tok.nextToken();
    }

    public String next() {
        String newLine = tryReadNextLine();
        if (newLine == null)
            throw new InputMismatchException();
        return newLine;
    }

    public int nextInt() {
        return Integer.parseInt(nextToken());
    }

    public long nextLong() {
        return Long.parseLong(nextToken());
    }
}