Problem: For a set $S$ of integers, perform a sequence of the following operations. Note that multiple elements can have equivalent values in $S$.

* insert($x$): Insert $x$ to $S$ and report the number of elements in $S$ after the operation.
* find($x$): Report the number of $x$ in $S$.
* delete($x$): Delete all $x$ from $S$.
* dump($L$, $R$): Print elements $x$ in $S$ such that $L \leq x \leq R$.

Constraints

* $1 \leq q \leq 200,000$
* $0 \leq x \leq 1,000,000,000$
* The total number of elements printed by dump operations does not exceed $1,000,000$
* The sum of numbers printed by find operations does not exceed $2,000,000$

Input

The input is given in the following format.


$q$
$query_1$
$query_2$
:
$query_q$


Each query $query_i$ is given by


0 $x$


or


1 $x$


or


2 $x$


or


3 $L$ $R$


where the first digits 0, 1, 2 and 3 represent insert, find, delete and dump operations respectively.

Output

For each insert operation, print the number of elements in $S$.
For each find operation, print the number of specified elements in $S$.
For each dump operation, print the corresponding elements in ascending order. Print an element in a line.

Example

Input

10
0 1
0 1
0 2
0 3
2 2
1 1
1 2
1 3
0 4
3 1 4


Output

1
2
3
4
2
0
1
4
1
1
3
4

Solution (in JAVA):

Solution:
import java.util.Scanner;
import java.util.TreeMap;

public class Main {

	public static void main(String[] args) {
		// TODO 自動生成されたメソッド・スタブ
		Scanner sc = new Scanner(System.in);
		int q = sc.nextInt();
		TreeMap<Integer, Integer> map = new TreeMap<Integer, Integer>();  //キーに対応する値にはキーの要素数を入れる
		int mapSize = 0;

		for(int i = 0; i < q; i++) {
			int query = sc.nextInt();

			switch(query) {
			case 0:
				int x = sc.nextInt();
				if(map.get(x) == null) {
					map.put(x, 1);
				}
				else map.replace(x, map.get(x) + 1);
				mapSize++;
				System.out.println(mapSize);
				break;

			case 1:
				x = sc.nextInt();
				if(map.get(x) == null) 	System.out.println(0);
				else System.out.println(map.get(x));
				break;

			case 2:
				x = sc.nextInt();
				if(map.get(x) != null) {
					mapSize -= map.get(x);
					map.remove(x);
				}
				break;

			case 3:
				int l = sc.nextInt();
				int r = sc.nextInt();

				for(int n : map.subMap(l, true, r, true).keySet()) {
					for(int j = 0; j < map.get(n); j++) {
						System.out.println(n);
					}
				}
				break;
			}
		}
	}

}