Problem: A word or a sentence in some language is called a pangram if all the characters of the alphabet of this language appear in it at least once. Pangrams are often used to demonstrate fonts in printing or test the output devices.

You are given a string consisting of lowercase and uppercase Latin letters. Check whether this string is a pangram. We say that the string contains a letter of the Latin alphabet if this letter occurs in the string in uppercase or lowercase.

Input

The first line contains a single integer n (1 ≤ n ≤ 100) — the number of characters in the string.

The second line contains the string. The string consists only of uppercase and lowercase Latin letters.

Output

Output "YES", if the string is a pangram and "NO" otherwise.

Examples

Input

12
toosmallword


Output

NO


Input

35
TheQuickBrownFoxJumpsOverTheLazyDog


Output

YES

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.Reader;
import java.util.StringTokenizer;

public class Pangram implements Runnable
{
	public static void main(String[] args)
	{
		new Thread(null, new Pangram(), "", 1 << 26).start();
	}

	@Override
	public void run()
	{
		FastScanner input = new FastScanner(System.in);
		
		int n = input.nextInt();
		String str = input.nextLine();
		
		if(n < 26)
		{
			System.out.println("NO");
		}
		else
		{	
			int[] arr = new int[str.length()];
			
			for(int i = 0; i < str.length(); i++)
			{
				char c = str.charAt(i);
				arr[charIndex(c)]++;
			}
			
			boolean flag = true;
			for(int i = 0; i < 26; i++)
			{
				if(arr[i] == 0)
				{
					flag = false;
				}
			}
			
			if(!flag)
			{
				System.out.println("NO");
			}
			else
			{
				System.out.println("YES");
			}
		}
	}

	private char[] charArr = { 'a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r',
			's', 't', 'u', 'v', 'w', 'x', 'y', 'z' };
	
	private int charIndex(char c)
	{
		int index = 0;
		for(int i = 0; i < charArr.length; i++)
		{
			if(charArr[i] == c || charArr[i] == Character.toLowerCase(c))
			{
				index = i;
			}
		}
		
		return index;
	}
	
	public class FastScanner
	{
		private BufferedReader br;
		private StringTokenizer st;

		public FastScanner(Reader in)
		{
			br = new BufferedReader(in);
		}

		public FastScanner(InputStream in)
		{
			this(new InputStreamReader(in));
		}

		public int nextInt()
		{
			return Integer.parseInt(next());
		}

		public String next()
		{
			while (st == null || !st.hasMoreElements())
			{
				try
				{
					st = new StringTokenizer(br.readLine());
				}
				catch (IOException e)
				{
					e.printStackTrace();
				}
			}

			return st.nextToken();
		}

		public String nextLine()
		{
			String str = "";

			try
			{
				str = br.readLine();
			}
			catch (IOException e)
			{
				e.printStackTrace();
			}

			return str;
		}
	}
}