Problem: You are given strings s and t. Find one longest string that is a subsequence of both s and t.

Constraints

* s and t are strings consisting of lowercase English letters.
* 1 \leq |s|, |t| \leq 3000

Input

Input is given from Standard Input in the following format:


s
t


Output

Print one longest string that is a subsequence of both s and t. If there are multiple such strings, any of them will be accepted.

Examples

Input

axyb
abyxb


Output

axb


Input

aa
xayaz


Output

aa


Input

a
z


Output




Input

abracadabra
avadakedavra


Output

aaadara

Solution (in PYTHON3):

Solution:
s = tuple(input())
t = tuple(input())
n = len(s)
m = len(t)

dp = [[0]*(m+1) for i in range(n+1)]

for i in range(1,n+1):
    for j in range(1,m+1):
        if s[i-1] == t[j-1]:
            dp[i][j] = dp[i-1][j-1]  + 1
        else:
            dp[i][j] = max(dp[i-1][j],dp[i][j-1])

res = []
while n != 0 and m != 0:
    if dp[n][m] == dp[n-1][m]:
        n -= 1
    elif dp[n][m] == dp[n][m-1]:
        m -= 1
    else:
        n -= 1
        m -= 1
        res.append(s[n])
print(''.join(res[::-1]))