Problem: You are given strings s and t. Find one longest string that is a subsequence of both s and t.

Constraints

* s and t are strings consisting of lowercase English letters.
* 1 \leq |s|, |t| \leq 3000

Input

Input is given from Standard Input in the following format:


s
t


Output

Print one longest string that is a subsequence of both s and t. If there are multiple such strings, any of them will be accepted.

Examples

Input

axyb
abyxb


Output

axb


Input

aa
xayaz


Output

aa


Input

a
z


Output




Input

abracadabra
avadakedavra


Output

aaadara

Solution (in PYTHON):

Solution:
input = raw_input
s = input().strip()
t = input().strip()

NS = len(s)
NT = len(t)

dp = [[0] * (NT+2) for i in range(NS+2)]
dp2 = [[""] * (NT+2) for i in range(NS+2)]

for i in range(1,NS+1):
    for j in range(1,NT+1):
        if s[i-1] == t[j-1]:
            dp[i][j] = max(dp[i-1][j-1]+1, dp[i-1][j], dp[i][j-1])
            if dp[i-1][j-1]+1 > dp[i-1][j] and dp[i-1][j-1]+1 > dp[i][j-1]:
                dp2[i][j] = dp2[i-1][j-1] + s[i-1]
            elif dp[i-1][j] > dp[i][j-1]:
                dp2[i][j] = dp2[i-1][j]
            else:
                dp2[i][j] = dp2[i][j-1]
        else:
            dp[i][j] = max(dp[i-1][j], dp[i][j-1])
            if dp[i-1][j] > dp[i][j-1]:
                dp2[i][j] = dp2[i-1][j]
            else:
                dp2[i][j] = dp2[i][j-1]
print(dp2[NS][NT])