Problem: A word or a sentence in some language is called a pangram if all the characters of the alphabet of this language appear in it at least once. Pangrams are often used to demonstrate fonts in printing or test the output devices.

You are given a string consisting of lowercase and uppercase Latin letters. Check whether this string is a pangram. We say that the string contains a letter of the Latin alphabet if this letter occurs in the string in uppercase or lowercase.

Input

The first line contains a single integer n (1 ≤ n ≤ 100) — the number of characters in the string.

The second line contains the string. The string consists only of uppercase and lowercase Latin letters.

Output

Output "YES", if the string is a pangram and "NO" otherwise.

Examples

Input

12
toosmallword


Output

NO


Input

35
TheQuickBrownFoxJumpsOverTheLazyDog


Output

YES

Solution (in PYTHON3):

Solution:
# echo hey | python3 pangram.py
# echo 'The quick brown fox jumps over the lazy dog' | python3 pangram.py
# echo '35\n The quick brown fox jumps over the lazy dog\n' | python3 pangram.py
# echo '12\n toosmallword\n' | python3 pangram.py
# echo '48\n thereisasyetinsufficientdataforameaningfulanswer\n' | python3 pangram.py

import sys
import re

lines_entered = 0
is_panagram = None
for line in sys.stdin:
  lines_entered += 1
  # pangram is at least 26 characters long
  if lines_entered == 1:
    num = int(line)
    if num < 26:
      print('NO')
      sys.exit(0)
  # every character of abcs appears at least onece
  elif lines_entered == 2:      
    lowerCase = line.lower()
    uniq = ''.join(set(lowerCase))
    matches = re.findall('[A-z]', uniq)
    if len(matches) == 26:
       print('YES')
    else:
      print('NO')