Problem: You are given strings s and t. Find one longest string that is a subsequence of both s and t.

Constraints

* s and t are strings consisting of lowercase English letters.
* 1 \leq |s|, |t| \leq 3000

Input

Input is given from Standard Input in the following format:


s
t


Output

Print one longest string that is a subsequence of both s and t. If there are multiple such strings, any of them will be accepted.

Examples

Input

axyb
abyxb


Output

axb


Input

aa
xayaz


Output

aa


Input

a
z


Output




Input

abracadabra
avadakedavra


Output

aaadara

Solution (in PYTHON3):

Solution:
s1 = list(input())
s2 = list(input())
n = len(s1)
m = len(s2)
dp = [[0]*(m+1) for _ in range(n+1)]
for i in range(1,n+1):
    for j in range(1, m+1):
        if s1[i-1] == s2[j-1]:
            dp[i][j] = 1 + dp[i-1][j-1]
        else:
            dp[i][j] = max(dp[i-1][j], dp[i][j-1])
res = []
i, j = n, m
while i > 0 and j > 0:
    if dp[i][j] == dp[i][j-1]:
        j -= 1
    elif dp[i][j] == dp[i-1][j]:
        i -= 1
    else:
        res.append(s1[i-1])
        i -= 1
        j -= 1
print(''.join(res[::-1]))