Problem: This is an interactive problem. Remember to flush your output while communicating with the testing program. You may use fflush(stdout) in C++, system.out.flush() in Java, stdout.flush() in Python or flush(output) in Pascal to flush the output. If you use some other programming language, consult its documentation. You may also refer to the guide on interactive problems: <https://codeforces.com/blog/entry/45307>.

The jury guessed some array a consisting of 6 integers. There are 6 special numbers — 4, 8, 15, 16, 23, 42 — and each of these numbers occurs in a exactly once (so, a is some permutation of these numbers).

You don't know anything about their order, but you are allowed to ask up to 4 queries. In each query, you may choose two indices i and j (1 ≤ i, j ≤ 6, i and j are not necessarily distinct), and you will get the value of a_i ⋅ a_j in return.

Can you guess the array a?

The array a is fixed beforehand in each test, the interaction program doesn't try to adapt to your queries.

Interaction

Before submitting the answer, you may ask up to 4 queries. To ask a query, print one line in the following format: ? i j, where i and j should be two integers such that 1 ≤ i, j ≤ 6. The line should be ended with a line break character. After submitting a query, flush the output and read the answer to your query — one line containing one integer a_i ⋅ a_j. If you submit an incorrect query (or ask more than 4 queries), the answer to it will be one string 0. After receiving such an answer, your program should terminate immediately — otherwise you may receive verdict "Runtime error", "Time limit exceeded" or some other verdict instead of "Wrong answer".

To give the answer, your program should print one line ! a_1 a_2 a_3 a_4 a_5 a_6 with a line break in the end. After that, it should flush the output and terminate gracefully.

Example

Input


16
64
345
672

Output


? 1 1
? 2 2
? 3 5
? 4 6
! 4 8 15 16 23 42

Note

If you want to submit a hack for this problem, your test should contain exactly six space-separated integers a_1, a_2, ..., a_6. Each of 6 special numbers should occur exactly once in the test. The test should be ended with a line break character.

Solution (in JAVA):

Solution:
import java.util.*;
import java.io.*;

public class Main {
 
	public static void main(String[] args) throws IOException,InterruptedException{
		Scanner sc=new Scanner(System.in);
		int[] arr=new int[6];
		int[] key= {4,8,15,16,23,42};
		boolean[] freq=new boolean[43];
		HashSet<Double> hs=new HashSet<>();
		for (int i = 0; i < key.length; i++) {
			hs.add((double)key[i]);
		}
		pw.println("? 1 1");
		pw.flush();
		arr[0]=(int)Math.sqrt(sc.nextInt());
		hs.remove(arr[0]);
		pw.println("? 2 2");
		pw.flush();
		arr[1]=(int)Math.sqrt(sc.nextInt());
		hs.remove(arr[1]);
		pw.println("? 3 4");
		pw.flush();
		int a=0,b=0,c=0,d=0;
		int x=sc.nextInt();
//		pw.println(hs);
		for (double i : hs) {
//			pw.println(i+" "+(int)(x/(double)i));
			if(hs.contains((x/i))) {
				a=(int)i;
				b=(int)(x/i);
			}
		}
		pw.println("? 3 5");
		pw.flush();
		int y=sc.nextInt();
		for (double i : hs) {
//			pw.println(i+" "+(int)(y/(double)i));
			if(hs.contains((y/i))) {
				c=(int)i;
				d=(int)(y/i);
			}
		}
//		pw.println(a+" "+b+" "+c+" "+d);
		if (a==c) {
			arr[2]=a;
			arr[3]=b;
			arr[4]=d;
		}else if (a==d) {
			arr[2]=a;
			arr[3]=b;
			arr[4]=c;
		}else if (b==c) {
			arr[2]=b;
			arr[3]=a;
			arr[4]=d;
		}else {
			arr[2]=b;
			arr[3]=a;
			arr[4]=c;
		}
		for (int i = 0; i < arr.length; i++) {
			freq[arr[i]]=true;
		}
		for(int i = 0; i < freq.length; i++) {
			if(!freq[i]&&(i==42||i==23||i==15||i==16||i==8||i==4)) {
				arr[5]=i;
				break;
			}
		}
		
		pw.print("! ");
		for (int i = 0; i < 6; i++) {
			pw.print(arr[i]+" ");
		}
		pw.flush();
    }

	static PrintWriter pw=new PrintWriter(System.out);
	static long pow(int a,int b) {
		long r=1l;
		for (int i = 0; i < b; i++) {
			r*=a;
		}
		return r;
	}
	static int[]lp;
	static void sieveLinear(int N){
		ArrayList<Integer> primes = new ArrayList<Integer>();
		lp = new int[N + 1];								//lp[i] = least prime divisor of i
		for(int i = 2; i <= N; ++i){
			if(lp[i] == 0){
				primes.add(i);
				lp[i] = i;
			}
			int curLP = lp[i];
			for(int p: primes)//all primes smaller than or equal my lowest prime divisor
				if(p > curLP || p * 1l * i > N)
					break;
				else
					lp[p * i] = p;
		}
	}
	static long gcd(int x,int y) {
		while (x!=y) {
			if(Math.max(x,y)/Math.min(x,y)==(double)(Math.max(x,y))/Math.min(x,y)) return Math.min(x,y);
			if(lp.length!=0) {
				if(lp[x]==x) {
					if(y/x==y/(double)x) return x;
					else return 1;
				}else if (lp[y]==y) {
					if(x/y==x/(double)y) return y;
					else return 1;
				}	
			}
			if(x>y) x-=y;
			else y-=x;
		}
		return x;
	}
	static class pair implements Comparable<pair> {
		int x;
		int y;
 
		public pair(int x, int y) {
			this.x = x;
			this.y = y;
		}
 
		public String toString() {
			return x + " " + y;
		}
		public boolean equals(Object o) {
            if (o instanceof pair) {
                pair p = (pair)o;
                return p.x == x && p.y == y;
            }
            return false;
        }
        public int hashCode() {
            return new Double(x).hashCode() * 31 + new Double(y).hashCode();
        }
        public int compareTo(pair other) {
        	if(this.x==other.x) {
        		return Long.compare(this.y, other.y);
        	}
			return Long.compare(this.x, other.x);
		}
	}
	static class tuble implements Comparable<tuble> {
		int x;
		int y;
		int z;
 
		public tuble(int x, int y, int z) {
			this.x = x;
			this.y = y;
			this.z = z;
		}
 
		public String toString() {
			return x + " " + y + " " + z;
		}
 
		public int compareTo(tuble other) {
			if (this.x == other.x) {
				if(this.y==other.y) return this.z - other.z;
				else return this.y - other.y;
			} else {
				return this.x - other.x;
			}
		}
	}
 	static class Scanner {
		StringTokenizer st;
		BufferedReader br;
 
		public Scanner(InputStream s) {
			br = new BufferedReader(new InputStreamReader(s));
		}
 
		public boolean hasNext() {
			// TODO Auto-generated method stub
			return false;
		}
 
		public String next() throws IOException {
			while (st == null || !st.hasMoreTokens())
				st = new StringTokenizer(br.readLine());
			return st.nextToken();
		}
 
		public int nextInt() throws IOException {
			return Integer.parseInt(next());
		}
 
		public long nextLong() throws IOException {
			return Long.parseLong(next());
		}
 
		public String nextLine() throws IOException {
			return br.readLine();
		}
 
		public double nextDouble() throws IOException {
			String x = next();
			StringBuilder sb = new StringBuilder("0");
			double res = 0, f = 1;
			boolean dec = false, neg = false;
			int start = 0;
			if (x.charAt(0) == '-') {
				neg = true;
				start++;
			}
			for (int i = start; i < x.length(); i++)
				if (x.charAt(i) == '.') {
					res = Long.parseLong(sb.toString());
					sb = new StringBuilder("0");
					dec = true;
				} else {
					sb.append(x.charAt(i));
					if (dec)
						f *= 10;
				}
			res += Long.parseLong(sb.toString()) / f;
			return res * (neg ? -1 : 1);
		}
 
		public boolean ready() throws IOException {
			return br.ready();
		}
 
	}
 
}