Problem: You are given a binary string s consisting of n zeros and ones.

Your task is to divide the given string into the minimum number of subsequences in such a way that each character of the string belongs to exactly one subsequence and each subsequence looks like "010101 ..." or "101010 ..." (i.e. the subsequence should not contain two adjacent zeros or ones).

Recall that a subsequence is a sequence that can be derived from the given sequence by deleting zero or more elements without changing the order of the remaining elements. For example, subsequences of "1011101" are "0", "1", "11111", "0111", "101", "1001", but not "000", "101010" and "11100".

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The first line of the test case contains one integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the length of s. The second line of the test case contains n characters '0' and '1' — the string s.

It is guaranteed that the sum of n does not exceed 2 ⋅ 10^5 (∑ n ≤ 2 ⋅ 10^5).

Output

For each test case, print the answer: in the first line print one integer k (1 ≤ k ≤ n) — the minimum number of subsequences you can divide the string s to. In the second line print n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ k), where a_i is the number of subsequence the i-th character of s belongs to.

If there are several answers, you can print any.

Example

Input


4
4
0011
6
111111
5
10101
8
01010000


Output


2
1 2 2 1 
6
1 2 3 4 5 6 
1
1 1 1 1 1 
4
1 1 1 1 1 2 3 4 

Solution (in JAVA):

Solution:
/*
    Author: Anthony Ngene
    Created: 10/08/2020 - 11:28
*/

import java.io.*;
import java.util.*;

public class D {
// Courage doesn't always roar. Sometimes courage is the little voice at the end of the day that says ‘I'll try again tomorrow. - Mary Anne Radmacher
    public static void main(String[] args) throws IOException {
        in = new FastScanner();

        int cases = in.intNext();
        for (int t = 1; t <= cases; t++) {
            int n = in.intNext();
            String seq = in.next();
            int groups = 0;
            Stack<Integer> ones = new Stack<>();
            Stack<Integer> zeros = new Stack<>();
            int[] ans = new int[n];
            for (int i = 0; i < n; i++) {
                if (seq.charAt(i) == '0') {
                    if (ones.empty()) {
                        groups++;
                        ones.add(groups);
                    }
                    ans[i] = ones.peek();
                    zeros.add(ones.pop());
                } else {
                    if (zeros.empty()) {
                        groups++;
                        zeros.add(groups);
                    }
                    ans[i] = zeros.peek();
                    ones.add(zeros.pop());
                }
            }
            out.println(groups);
            for (int v: ans) out.p(v).p(" ");
            out.println("");
        }

        out.close();
    }


// Generated Code Below:
private static final FastWriter out = new FastWriter();
private static FastScanner in;
static ArrayList<Integer>[] adj;
private static long e97 = (long)1e9 + 7;
static class FastWriter {
    private static final int IO_BUFFERS = 128 * 1024;
    private final StringBuilder out;
    public FastWriter() { out = new StringBuilder(IO_BUFFERS); }
    public FastWriter p(Object object) { out.append(object); return this; }
    public FastWriter p(String format, Object... args) { out.append(String.format(format, args)); return this; }
    public FastWriter pp(Object... args) { for (Object ob : args) { out.append(ob).append(" ");  } out.append("\n"); return this; }
    public void println(long[] arr) { out.append(Arrays.toString(arr)).append("\n"); }
    public void println(int[] arr) { out.append(Arrays.toString(arr)).append("\n"); }
    public void println(char[] arr) { out.append(Arrays.toString(arr)).append("\n"); }
    public void println(float[] arr) { out.append(Arrays.toString(arr)).append("\n"); }
    public void println(boolean[] arr) { out.append(Arrays.toString(arr)).append("\n"); }
    public <T>void println(T[] arr) { out.append(Arrays.toString(arr)).append("\n"); }
    public void println(long[][] arr) {  for (long[] row: arr) out.append(Arrays.toString(row)).append(" "); out.append("\n");  }
    public void println(int[][] arr) {  for (int[] row: arr) out.append(Arrays.toString(row)).append(" "); out.append("\n");  }
    public void println(char[][] arr) {  for (char[] row: arr) out.append(Arrays.toString(row)).append(" "); out.append("\n");  }
    public void println(float[][] arr) {  for (float[] row: arr) out.append(Arrays.toString(row)).append(" "); out.append("\n");  }
    public <T>void println(T[][] arr) {  for (T[] row: arr) out.append(Arrays.toString(row)).append(" "); out.append("\n");  }
    public FastWriter println(Object object) { out.append(object).append("\n"); return this; }
    public void toFile(String fileName) throws IOException {
        BufferedWriter writer = new BufferedWriter(new FileWriter(fileName));
        writer.write(out.toString());
        writer.close();
    }
    public void close() throws IOException { System.out.print(out); }
}
static class FastScanner {
    private InputStream sin = System.in;
    private final byte[] buffer = new byte[1024];
    private int ptr = 0;
    private int buflen = 0;
    public FastScanner(){}
    public FastScanner(String filename) throws FileNotFoundException {
        File file = new File(filename);
        sin = new FileInputStream(file);
    }
    private boolean hasNextByte() {
        if (ptr < buflen) {
            return true;
        }else{
            ptr = 0;
            try {
                buflen = sin.read(buffer);
            } catch (IOException e) {
                e.printStackTrace();
            }
            if (buflen <= 0) {
                return false;
            }
        }
        return true;
    }
    private int readByte() { if (hasNextByte()) return buffer[ptr++]; else return -1;}
    private static boolean isPrintableChar(int c) { return 33 <= c && c <= 126;}
    public boolean hasNext() { while(hasNextByte() && !isPrintableChar(buffer[ptr])) ptr++; return hasNextByte();}
    public String next() {
        if (!hasNext()) throw new NoSuchElementException();
        StringBuilder sb = new StringBuilder();
        int b = readByte();
        while(isPrintableChar(b)) {
            sb.appendCodePoint(b);
            b = readByte();
        }
        return sb.toString();
    }
    public long longNext() {
        if (!hasNext()) throw new NoSuchElementException();
        long n = 0;
        boolean minus = false;
        int b = readByte();
        if (b == '-') {
            minus = true;
            b = readByte();
        }
        if (b < '0' || '9' < b) {
            throw new NumberFormatException();
        }
        while(true){
            if ('0' <= b && b <= '9') {
                n *= 10;
                n += b - '0';
            }else if(b == -1 || !isPrintableChar(b) || b == ':'){
                return minus ? -n : n;
            }else{
                throw new NumberFormatException();
            }
            b = readByte();
        }
    }
    public int intNext() {
        long nl = longNext();
        if (nl < Integer.MIN_VALUE || nl > Integer.MAX_VALUE) throw new NumberFormatException();
        return (int) nl;
    }
    public double doubleNext() { return Double.parseDouble(next());}
    public long[] nextLongArray(final int n){
        final long[] a = new long[n];
        for (int i = 0; i < n; i++)
            a[i] = longNext();
        return a;
    }
    public int[] nextIntArray(final int n){
        final int[] a = new int[n];
        for (int i = 0; i < n; i++)
            a[i] = intNext();
        return a;
    }
    public ArrayList<Integer>[] getAdj(int n) {
        ArrayList<Integer>[] adj = new ArrayList[n + 1];
        for (int i = 1; i <= n; i++) adj[i] = new ArrayList<>();
        return adj;
    }
    public ArrayList<Integer>[] adjacencyList(int n, int m) throws IOException {
        adj = getAdj(n);
        for (int i = 0; i < m; i++) {
            int a = intNext(), b = intNext();
            adj[a].add(b);
            adj[b].add(a);
        }
        return adj;
    }
}
}