Problem: Apart from having lots of holidays throughout the year, residents of Berland also have whole lucky years. Year is considered lucky if it has no more than 1 non-zero digit in its number. So years 100, 40000, 5 are lucky and 12, 3001 and 12345 are not.

You are given current year in Berland. Your task is to find how long will residents of Berland wait till the next lucky year.

Input

The first line contains integer number n (1 ≤ n ≤ 109) — current year in Berland.

Output

Output amount of years from the current year to the next lucky one.

Examples

Input

4


Output

1


Input

201


Output

99


Input

4000


Output

1000

Note

In the first example next lucky year is 5. In the second one — 300. In the third — 5000.

Solution (in JAVA):

Solution:

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.util.StringTokenizer;
public class CF808A {
    
    public static void main(String args[]){
		InputReader in = new InputReader(System.in);
		//OutputStream outputStream = System.out;
		PrintWriter out = new PrintWriter(System.out);
                int n=in.nextInt();
                String s=n+"";
                int c=0;
                int l=s.length();
                for(int i =1;i<l;i++){
                    if(s.charAt(i)=='0')
                        c++;
                    else break;
                }
                double ans=0;
                if(c==l-1)
                {
                    ans=Math.pow(10, l-1);
                }
                else
                {
                    ans=((s.charAt(0)-'0')+1)*Math.pow(10, l-1)-n;
                }
                out.println((int)ans);
		out.close();
		
    }
    static class InputReader {
	public BufferedReader reader;
	public StringTokenizer tokenizer;

	public InputReader(InputStream inputstream) {
		reader = new BufferedReader(new InputStreamReader(inputstream));
		tokenizer = null;
	}

	public String nextLine(){
		String fullLine=null;
		while (tokenizer == null || !tokenizer.hasMoreTokens()) {
			try {
				fullLine=reader.readLine();
			} catch (IOException e) {
				throw new RuntimeException(e);
			}
			return fullLine;
		}
		return fullLine;
	}
	public String next() {
		while (tokenizer == null || !tokenizer.hasMoreTokens()) {
			try {
				tokenizer = new StringTokenizer(reader.readLine());
			} catch (IOException e) {
				throw new RuntimeException(e);
			}
		}
		return tokenizer.nextToken();
	}
	public long nextLong() {
		return Long.parseLong(next());
	}
	public int nextInt() {
		return Integer.parseInt(next());
	}
    }
}