Problem: You are given strings s and t. Find one longest string that is a subsequence of both s and t.

Constraints

* s and t are strings consisting of lowercase English letters.
* 1 \leq |s|, |t| \leq 3000

Input

Input is given from Standard Input in the following format:


s
t


Output

Print one longest string that is a subsequence of both s and t. If there are multiple such strings, any of them will be accepted.

Examples

Input

axyb
abyxb


Output

axb


Input

aa
xayaz


Output

aa


Input

a
z


Output




Input

abracadabra
avadakedavra


Output

aaadara

Solution (in PYTHON3):

Solution:
s1 = list(input())
s2 = list(input())
n = len(s1)
m = len(s2)
dp = [[0]*(m+1) for _ in range(n+1)]
dp=[[0]*(m+1) for i in range(n+1)]

for i in range(1,n+1):
    for j in range(1,m+1):
        if s1[i-1]==s2[j-1]:
            dp[i][j]=dp[i-1][j-1]+1
        else:
            dp[i][j]=max(dp[i-1][j],dp[i][j-1])
res=[]
i,j=n,m
while i> 0 and j>0:
    if dp[i][j]==dp[i-1][j]:
        i-=1
    elif dp[i][j]==dp[i][j-1]:
        j-=1
    else:
        res.append(s1[i-1])
        i-=1
        j-=1
print("".join(res[::-1]))