Problem: Boy Dima gave Julian a birthday present — set B consisting of positive integers. However, he didn't know, that Julian hates sets, but enjoys bipartite graphs more than anything else!

Julian was almost upset, but her friend Alex said, that he can build an undirected graph using this set in such a way: let all integer numbers be vertices, then connect any two i and j with an edge if |i - j| belongs to B.

Unfortunately, Julian doesn't like the graph, that was built using B. Alex decided to rectify the situation, so he wants to erase some numbers from B, so that graph built using the new set is bipartite. The difficulty of this task is that the graph, Alex has to work with, has an infinite number of vertices and edges! It is impossible to solve this task alone, so Alex asks you for help. Write a program that erases a subset of minimum size from B so that graph constructed on the new set is bipartite.

Recall, that graph is bipartite if all its vertices can be divided into two disjoint sets such that every edge connects a vertex from different sets.

Input

First line contains an integer n ~ (1 ⩽ n ⩽ 200 000) — size of B

Second line contains n integers b_1, b_2, …, b_n ~ (1 ⩽ b_i ⩽ 10^{18}) — numbers of B, all b_i are unique

Output

In the first line print single integer k – the number of erased elements. In the second line print k integers — values of erased elements.

If there are multiple answers, print any of them.

Examples

Input


3
1 2 3


Output


1
2 

Input


2
2 6


Output


0

Solution (in JAVA):

Solution:
import java.io.*; 
import java.math.*;
import java.util.*;
 
public class Main {
	//static final long MOD = 998244353;
	static final long MOD = 1000000007;
	static boolean[] visited;
    public static void main(String[] args) throws IOException {
        FastScanner sc = new FastScanner();
        int N = sc.nextInt();
        int[] powerOf2 = new int[64];
        long[] nums = new long[N];
        for (int i = 0; i < N; i++) {
        	nums[i] = sc.nextLong();
        }
        int[] power = new int[N];
        for (int i = 0; i < N; i++) {
        	long pow = 2;
        	int ans = 0;
        	while (nums[i] % pow == 0) {
        		ans++;
        		pow *= 2;
        	}
        	power[i] = ans;
        	powerOf2[ans] += 1;
        }
        
        int bestPower = -1;
        int count = 0;
        for (int i = 0; i < 64; i++) {
        	if (powerOf2[i] > count) {
        		bestPower = i;
        		count = powerOf2[i];
        	}
        }
        System.out.println(N-count);
        StringBuilder ans = new StringBuilder();
        for (int i = 0; i < N; i++) {
        	if (power[i] != bestPower)
        		ans.append(nums[i] + " ");
        }
        System.out.println(ans);
    }
    
    public static int[] base26(int N, int num) {
    	int[] ans = new int[N];
    	for (int i = N-1; i >= 0; i--) {
    		int pow = (int)Math.pow(26,i);
    		ans[i] = num/pow;
    		num -= ans[i]*pow;
    	}
    	return ans;
    }
    
    public static int[][] sort(int[][] array) {
    	//Sort an array (immune to quicksort TLE)
		Random rgen = new Random();
		for (int i = 0; i< array.length; i++) {
		    int randomPosition = rgen.nextInt(array.length);
		    int[] temp = array[i];
		    array[i] = array[randomPosition];
		    array[randomPosition] = temp;
		}
		Arrays.sort(array, new Comparator<int[]>() {
			  @Override
			  public int compare(int[] arr1, int[] arr2) {
				  //Descending order
				  return arr2[0]-arr1[0];
			  }
		});
		return array;
	}
    
    static class FastScanner { 
        BufferedReader br; 
        StringTokenizer st; 
  
        public FastScanner() { 
            br = new BufferedReader(new InputStreamReader(System.in)); 
        } 
  
        String next() { 
            while (st == null || !st.hasMoreElements()) { 
                try { 
                    st = new StringTokenizer(br.readLine());
                } catch (IOException  e) { 
                    e.printStackTrace(); 
                } 
            } 
            return st.nextToken(); 
        } 
  
        int nextInt() { 
            return Integer.parseInt(next()); 
        } 
  
        long nextLong() { 
            return Long.parseLong(next()); 
        } 
  
        double nextDouble() { 
            return Double.parseDouble(next()); 
        } 
  
        String nextLine() { 
            String str = ""; 
            try { 
                str = br.readLine(); 
            } catch (IOException e) {
                e.printStackTrace(); 
            } 
            return str; 
        }
    }
}

class Node {
	public HashSet<Node> children;
	public int n;
	
	public Node(int n) {
		this.n = n;
		children = new HashSet<Node>();
	}
	
	public void addChild(Node node) {
		children.add(node);
	}
	
	public void removeChild(Node node) {
		children.remove(node);
	}

	/* (non-Javadoc)
	 * @see java.lang.Object#hashCode()
	 */
	@Override
	public int hashCode() {
		return n;
	}

	@Override
	public boolean equals(Object obj) {
		if (! (obj instanceof Node)) {
			return false;
		} else {
			Node node = (Node) obj;
			return (n == node.n);
		}
	}
	
	public String toString() {
		return (this.n+1)+"";
	}
}