Problem: You are given strings s and t. Find one longest string that is a subsequence of both s and t.

Constraints

* s and t are strings consisting of lowercase English letters.
* 1 \leq |s|, |t| \leq 3000

Input

Input is given from Standard Input in the following format:


s
t


Output

Print one longest string that is a subsequence of both s and t. If there are multiple such strings, any of them will be accepted.

Examples

Input

axyb
abyxb


Output

axb


Input

aa
xayaz


Output

aa


Input

a
z


Output




Input

abracadabra
avadakedavra


Output

aaadara

Solution (in PYTHON3):

Solution:
s = list(input())
t = list(input())
a = len(s)
b = len(t)
dp = [[0]*(b+1) for _ in range(a+1)]
ans = ""
#dp[i][j]はi文字目までのsとtのj文字目までの共通部分
for i in range(a):
  for j in range(b):
    if s[i] == t[j]:
      dp[i+1][j+1] = dp[i][j]+1
    else:
      dp[i+1][j+1] = max(dp[i][j+1],dp[i+1][j])
i = a
j = b
while(i>=0 and j>=0):
  if dp[i][j] == dp[i-1][j]:
    i -= 1
  elif dp[i][j] == dp[i][j-1]:
    j -= 1
  else:
    ans = t[j-1]+ans
    i -= 1
    j -= 1
print(ans)