Problem: You are given strings s and t. Find one longest string that is a subsequence of both s and t.

Constraints

* s and t are strings consisting of lowercase English letters.
* 1 \leq |s|, |t| \leq 3000

Input

Input is given from Standard Input in the following format:


s
t


Output

Print one longest string that is a subsequence of both s and t. If there are multiple such strings, any of them will be accepted.

Examples

Input

axyb
abyxb


Output

axb


Input

aa
xayaz


Output

aa


Input

a
z


Output




Input

abracadabra
avadakedavra


Output

aaadara

Solution (in PYTHON3):

Solution:
s = input()
t = input()

len_s=len(s)
len_t=len(t)

# dp[len(s)][len(t)]
# dp表をつくる
dp = [[0]*(len(t)+1) for _ in range(len(s)+1)]

for i in range(1,len_s+1):
  for j in range(1,len_t+1):
    if s[i-1]==t[j-1]:
      dp[i][j]=dp[i-1][j-1]+1
    else:
      dp[i][j]=max(dp[i][j-1],dp[i-1][j])
#print(dp)

#復元する
rev = ""
i = len_s
j = len_t
while (i>=1 and j>=1):
  if dp[i][j] == dp[i][j-1]:
    j -=1
  elif dp[i][j] == dp[i-1][j]:
    i -=1
  else:
    rev = t[j-1] + rev
    i -=1
    j -=1

print(rev)