Problem: Write a program which manipulates a sequence $A$ = {$a_0, a_1, ..., a_{n-1}$} with the following operations:

* $update(s, t, x)$: change $a_s, a_{s+1}, ..., a_t$ to $x$.
* $getSum(s, t)$: print the sum of $a_s, a_{s+1}, ..., a_t$.



Note that the initial values of $a_i ( i = 0, 1, ..., n-1 )$ are 0.

Constraints

* $1 ≤ n ≤ 100000$
* $1 ≤ q ≤ 100000$
* $0 ≤ s ≤ t < n$
* $-1000 ≤ x ≤ 1000$

Input


$n$ $q$
$query_1$
$query_2$
:
$query_q$


In the first line, $n$ (the number of elements in $A$) and $q$ (the number of queries) are given. Then, $i$-th query $query_i$ is given in the following format:


0 $s$ $t$ $x$


or


1 $s$ $t$


The first digit represents the type of the query. '0' denotes $update(s, t, x)$ and '1' denotes $find(s, t)$.

Output

For each $getSum$ query, print the sum in a line.

Example

Input

6 7
0 1 3 1
0 2 4 -2
1 0 5
1 0 1
0 3 5 3
1 3 4
1 0 5


Output

-5
1
6
8

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int e = 10000;
template <typename T>
struct range_update_range_sum{
	int N;
	vector<T> ST;
	vector<T> lazy;
	range_update_range_sum(int n){
		N = 1;
		while (N < n){
			N *= 2;
		}
		ST = vector<T>(N * 2 - 1, 0);
		lazy = vector<T>(N * 2 - 1, e);
	}
	range_update_range_sum(vector<T> &A){
		int n = A.size();
		N = 1;
		while (N < n){
			N *= 2;
		}
		ST = vector<T>(N * 2 - 1, 0);
		lazy = vector<T>(N * 2 - 1, e);
		for (int i = 0; i < n; i++){
			ST[N - 1 + i] = A[i];
		}
		for (int i = N - 2; i >= 0; i--){
			ST[i] = ST[i * 2 + 1] + ST[i * 2 + 2];
		}
	}
	void eval(int i, int l, int r){
		if (lazy[i] != e){
			if (i < N - 1){
				lazy[i * 2 + 1] = lazy[i];
				lazy[i * 2 + 2] = lazy[i];
			}
			ST[i] = lazy[i] * (r - l);
			lazy[i] = e;
		}
	}
	void range_update(int L, int R, T x, int i, int l, int r){
		eval(i, l, r);
		if (R <= l || r <= L){
			return;
		} else if (L <= l && r <= R){
			lazy[i] = x;
			eval(i, l, r);
		} else {
			int m = (l + r) / 2;
			range_update(L, R, x, i * 2 + 1, l, m);
			range_update(L, R, x, i * 2 + 2, m, r);
			ST[i] = ST[i * 2 + 1] + ST[i * 2 + 2];
		}
	}
	void range_update(int L, int R, T x){
		range_update(L, R, x, 0, 0, N);
	}
	T range_sum(int L, int R, int i, int l, int r){
		eval(i, l, r);
		if (R <= l || r <= L){
			return 0;
		} else if (L <= l && r <= R){
			return ST[i];
		} else {
			int m = (l + r) / 2;
			return range_sum(L, R, i * 2 + 1, l, m) + range_sum(L, R, i * 2 + 2, m, r);
		}
	}
	T range_sum(int L, int R){
		return range_sum(L, R, 0, 0, N);
	}
};
int main(){
  int n, q;
  cin >> n >> q;
  range_update_range_sum<long long> a(n);
  for (int i = 0; i < q; i++){
    int T;
    cin >> T;
    if (T == 0){
      int s, t, x;
      cin >> s >> t >> x;
      a.range_update(s, t + 1, x);
    }
    if (T == 1){
      int s, t;
      cin >> s >> t;
      cout << a.range_sum(s, t + 1) << endl;
    }
  }
}