Problem: Apart from having lots of holidays throughout the year, residents of Berland also have whole lucky years. Year is considered lucky if it has no more than 1 non-zero digit in its number. So years 100, 40000, 5 are lucky and 12, 3001 and 12345 are not.

You are given current year in Berland. Your task is to find how long will residents of Berland wait till the next lucky year.

Input

The first line contains integer number n (1 ≤ n ≤ 109) — current year in Berland.

Output

Output amount of years from the current year to the next lucky one.

Examples

Input

4


Output

1


Input

201


Output

99


Input

4000


Output

1000

Note

In the first example next lucky year is 5. In the second one — 300. In the third — 5000.

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.StringTokenizer;

public final class Solution implements Closeable, AutoCloseable
{
  void Solve() throws NumberFormatException, IOException
  {
    int n = input.nextInt();
    int k = n;
    int c = 0;
    while (n >= 10)
    {
      n /= 10;
      c++;
    }
    int m = n + 1;
    for (int i = 0; i < c; i++)
      m *= 10;
    output.print(m - k);
  }

  private final FastScanner input;
  private final PrintWriter output;

  Solution()
  {
    input = new FastScanner(System.in);
    output = new PrintWriter(System.out);
  }

  public static void main(String[] args) throws IOException
  {
    try (Solution solution = new Solution())
    {
      solution.Solve();
    }
  }

  @Override
  public void close()
  {
    output.flush();
    output.close();
  }

  @SuppressWarnings("unused")
  class FastScanner
  {
    private static final int bufferSize = 64 * 1024;
    private final BufferedReader reader;
    private StringTokenizer tokenizer;

    FastScanner(InputStream inputStream)
    {
      this.reader = new BufferedReader(new InputStreamReader(inputStream), bufferSize);
    }

    String nextToken() throws IOException
    {
      while (tokenizer == null || !tokenizer.hasMoreTokens())
      {
        String line = reader.readLine();
        if (line == null)
        {
          tokenizer = null;
          return null;
        }
        tokenizer = new StringTokenizer(line);
      }
      return tokenizer.nextToken();
    }

    int[] readIntArray(int n) throws IOException
    {
      int[] a = new int[n];
      for (int i = 0; i < n; i++)
      {
        a[i] = nextInt();
      }
      return a;
    }

    long[] readLongArray(int n) throws IOException
    {
      long[] a = new long[n];
      for (int i = 0; i < n; i++)
      {
        a[i] = nextLong();
      }
      return a;
    }

    int nextInt() throws NumberFormatException, IOException
    {
      return Integer.parseInt(nextToken());
    }

    long nextLong() throws NumberFormatException, IOException
    {
      return Long.parseLong(nextToken());
    }

    double nextDouble() throws NumberFormatException, IOException
    {
      return Double.parseDouble(nextToken());
    }

    String nextLine() throws IOException
    {
      tokenizer = null;
      return reader.readLine();
    }
  }
}