Problem: For a set $S$ of integers, perform a sequence of the following operations. Note that multiple elements can have equivalent values in $S$.

* insert($x$): Insert $x$ to $S$ and report the number of elements in $S$ after the operation.
* find($x$): Report the number of $x$ in $S$.
* delete($x$): Delete all $x$ from $S$.
* dump($L$, $R$): Print elements $x$ in $S$ such that $L \leq x \leq R$.

Constraints

* $1 \leq q \leq 200,000$
* $0 \leq x \leq 1,000,000,000$
* The total number of elements printed by dump operations does not exceed $1,000,000$
* The sum of numbers printed by find operations does not exceed $2,000,000$

Input

The input is given in the following format.


$q$
$query_1$
$query_2$
:
$query_q$


Each query $query_i$ is given by


0 $x$


or


1 $x$


or


2 $x$


or


3 $L$ $R$


where the first digits 0, 1, 2 and 3 represent insert, find, delete and dump operations respectively.

Output

For each insert operation, print the number of elements in $S$.
For each find operation, print the number of specified elements in $S$.
For each dump operation, print the corresponding elements in ascending order. Print an element in a line.

Example

Input

10
0 1
0 1
0 2
0 3
2 2
1 1
1 2
1 3
0 4
3 1 4


Output

1
2
3
4
2
0
1
4
1
1
3
4

Solution (in CPP):

Solution:
#include <iostream>
#include<list>
#include<vector>
#include<stack>
#include<queue>
#include<algorithm>
#include<set>
#include<map>
using namespace std;
int main()
{
    multiset<int > s;
    int q;
    cin>>q;
    int b,tp1;
    while(q--){
        cin>>tp1;
        if(tp1==1){
                cin>>b;
                cout<<s.count(b)<<"\n";
        }
        else if(tp1==0){
            cin>>b;
            s.insert(b);
            cout<<s.size()<<"\n";
        }
        else if(tp1==2){
            cin>>b;
            s.erase(b);
        }
        else{
            int r,l;
            cin>>l>>r;
            set<int>::iterator it=s.lower_bound(l);
            while(*it<=r&&it!=s.end()){
                cout<<*it<<"\n";
                it++;
            }
        }
    }

}