Problem: You are given strings s and t. Find one longest string that is a subsequence of both s and t.

Constraints

* s and t are strings consisting of lowercase English letters.
* 1 \leq |s|, |t| \leq 3000

Input

Input is given from Standard Input in the following format:


s
t


Output

Print one longest string that is a subsequence of both s and t. If there are multiple such strings, any of them will be accepted.

Examples

Input

axyb
abyxb


Output

axb


Input

aa
xayaz


Output

aa


Input

a
z


Output




Input

abracadabra
avadakedavra


Output

aaadara

Solution (in PYTHON3):

Solution:
s=input()
t=input()
n=len(s)
m=len(t)
dp=[[0 for i in range(m+1)] for j in range(n+1)]
for i in range(n):
    for j in range(m):
        if s[i]==t[j]:
            dp[i+1][j+1]=dp[i][j]+1
        else:
            dp[i+1][j+1]=max(dp[i][j+1],dp[i+1][j])
ans = ''
while(dp[n][m]>0):
  if dp[n][m] == dp[n-1][m-1] +1 and dp[n][m] == dp[n-1][m] +1 and dp[n][m] == dp[n][m-1] +1:
    ans = ''.join([s[n-1],ans])
    n -= 1
    m -= 1
  elif dp[n-1][m] > dp[n][m-1]:
    n -= 1
  else:
    m -= 1
print(ans)