Problem: Snuke and Ciel went to a strange stationery store. Each of them got a transparent graph paper with H rows and W columns.

Snuke painted some of the cells red in his paper. Here, the cells painted red were 4-connected, that is, it was possible to traverse from any red cell to any other red cell, by moving to vertically or horizontally adjacent red cells only.

Ciel painted some of the cells blue in her paper. Here, the cells painted blue were 4-connected.

Afterwards, they precisely overlaid the two sheets in the same direction. Then, the intersection of the red cells and the blue cells appeared purple.

You are given a matrix of letters a_{ij} (1≤i≤H, 1≤j≤W) that describes the positions of the purple cells. If the cell at the i-th row and j-th column is purple, then a_{ij} is `#`, otherwise a_{ij} is `.`. Here, it is guaranteed that no outermost cell is purple. That is, if i=1, H or j = 1, W, then a_{ij} is `.`.

Find a pair of the set of the positions of the red cells and the blue cells that is consistent with the situation described. It can be shown that a solution always exists.

Constraints

* 3≤H,W≤500
* a_{ij} is `#` or `.`.
* If i=1,H or j=1,W, then a_{ij} is `.`.
* At least one of a_{ij} is `#`.

Input

The input is given from Standard Input in the following format:


H W
a_{11}...a_{1W}
:
a_{H1}...a_{HW}


Output

Print a pair of the set of the positions of the red cells and the blue cells that is consistent with the situation, as follows:

* The first H lines should describe the positions of the red cells.
* The following 1 line should be empty.
* The following H lines should describe the positions of the blue cells.



The description of the positions of the red or blue cells should follow the format of the description of the positions of the purple cells.

Examples

Input

5 5
.....
.#.#.
.....
.#.#.
.....


Output

.....
#####
#....
#####
.....

.###.
.#.#.
.#.#.
.#.#.
.....


Input

7 13
.............
.###.###.###.
.#.#.#...#...
.###.#...#...
.#.#.#.#.#...
.#.#.###.###.
.............


Output

.............
.###########.
.###.###.###.
.###.###.###.
.###.###.###.
.###.###.###.
.............

.............
.###.###.###.
.#.#.#...#...
.###.#...#...
.#.#.#.#.#...
.#.#########.
.............

Solution (in JAVA):

Solution:
import java.io.IOException;
import java.io.InputStream;
import java.util.NoSuchElementException;
 
public class Main {
	public static void main(String[] args) {
		FastScanner sc = new FastScanner();
		int H = sc.nextInt();
		int W = sc.nextInt();
 
		char[][] map = new char[H][W];
		for (int i = 0; i < H; i++) {
			map[i] = sc.next().toCharArray();
		}
 
		char[][] ans1 = new char[H][W];
		char[][] ans2 = new char[H][W];

		for (int i = 0; i < H; i++) {		
			for (int j = 0; j < W; j ++) {
				ans1[i][j] = map[i][j] == '#' || j == 0 || j < W - 1 && i % 2 == 0 ? '#' : '.';
				ans2[i][j] = map[i][j] == '#' || j == W - 1 || j > 0 && i % 2 == 1 ? '#' : '.';
			}		
		}
 
		for (int i = 0; i < H; i++) {
			System.out.println(ans1[i]);
		}
		System.out.println();
		for (int i = 0; i < H; i++) {
			System.out.println(ans2[i]);
		}
	}
 
}
 
class FastScanner {
	public static String debug = null;
 
	private final InputStream in = System.in;
	private int ptr = 0;
	private int buflen = 0;
	private byte[] buffer = new byte[1024];
	private boolean eos = false;
 
	private boolean hasNextByte() {
		if (ptr < buflen) {
			return true;
		} else {
			ptr = 0;
			try {
				if (debug != null) {
					buflen = debug.length();
					buffer = debug.getBytes();
					debug = "";
					eos = true;
				} else {
					buflen = in.read(buffer);
				}
			} catch (IOException e) {
				e.printStackTrace();
			}
			if (buflen < 0) {
				eos = true;
				return false;
			} else if (buflen == 0) {
				return false;
			}
		}
		return true;
	}
 
	private int readByte() {
		if (hasNextByte())
			return buffer[ptr++];
		else
			return -1;
	}
 
	private static boolean isPrintableChar(int c) {
		return 33 <= c && c <= 126;
	}
 
	private void skipUnprintable() {
		while (hasNextByte() && !isPrintableChar(buffer[ptr]))
			ptr++;
	}
 
	public boolean isEOS() {
		return this.eos;
	}
 
	public boolean hasNext() {
		skipUnprintable();
		return hasNextByte();
	}
 
	public String next() {
		if (!hasNext())
			throw new NoSuchElementException();
		StringBuilder sb = new StringBuilder();
		int b = readByte();
		while (isPrintableChar(b)) {
			sb.appendCodePoint(b);
			b = readByte();
		}
		return sb.toString();
	}
 
	public long nextLong() {
		if (!hasNext())
			throw new NoSuchElementException();
		long n = 0;
		boolean minus = false;
		int b = readByte();
		if (b == '-') {
			minus = true;
			b = readByte();
		}
		if (b < '0' || '9' < b) {
			throw new NumberFormatException();
		}
		while (true) {
			if ('0' <= b && b <= '9') {
				n *= 10;
				n += b - '0';
			} else if (b == -1 || !isPrintableChar(b)) {
				return minus ? -n : n;
			} else {
				throw new NumberFormatException();
			}
			b = readByte();
		}
	}
 
	public int nextInt() {
		return (int) nextLong();
	}
 
	public long[] nextLongList(int n) {
		return nextLongTable(1, n)[0];
	}
 
	public int[] nextIntList(int n) {
		return nextIntTable(1, n)[0];
	}
 
	public long[][] nextLongTable(int n, int m) {
		long[][] ret = new long[n][m];
		for (int i = 0; i < n; i++) {
			for (int j = 0; j < m; j++) {
				ret[i][j] = nextLong();
			}
		}
		return ret;
	}
 
	public int[][] nextIntTable(int n, int m) {
		int[][] ret = new int[n][m];
		for (int i = 0; i < n; i++) {
			for (int j = 0; j < m; j++) {
				ret[i][j] = nextInt();
			}
		}
		return ret;
	}
}