Problem: Mikhail the Freelancer dreams of two things: to become a cool programmer and to buy a flat in Moscow. To become a cool programmer, he needs at least p experience points, and a desired flat in Moscow costs q dollars. Mikhail is determined to follow his dreams and registered at a freelance site.

He has suggestions to work on n distinct projects. Mikhail has already evaluated that the participation in the i-th project will increase his experience by ai per day and bring bi dollars per day. As freelance work implies flexible working hours, Mikhail is free to stop working on one project at any time and start working on another project. Doing so, he receives the respective share of experience and money. Mikhail is only trying to become a cool programmer, so he is able to work only on one project at any moment of time.

Find the real value, equal to the minimum number of days Mikhail needs to make his dream come true.

For example, suppose Mikhail is suggested to work on three projects and a1 = 6, b1 = 2, a2 = 1, b2 = 3, a3 = 2, b3 = 6. Also, p = 20 and q = 20. In order to achieve his aims Mikhail has to work for 2.5 days on both first and third projects. Indeed, a1·2.5 + a2·0 + a3·2.5 = 6·2.5 + 1·0 + 2·2.5 = 20 and b1·2.5 + b2·0 + b3·2.5 = 2·2.5 + 3·0 + 6·2.5 = 20.

Input

The first line of the input contains three integers n, p and q (1 ≤ n ≤ 100 000, 1 ≤ p, q ≤ 1 000 000) — the number of projects and the required number of experience and money.

Each of the next n lines contains two integers ai and bi (1 ≤ ai, bi ≤ 1 000 000) — the daily increase in experience and daily income for working on the i-th project.

Output

Print a real value — the minimum number of days Mikhail needs to get the required amount of experience and money. Your answer will be considered correct if its absolute or relative error does not exceed 10 - 6. 

Namely: let's assume that your answer is a, and the answer of the jury is b. The checker program will consider your answer correct, if <image>.

Examples

Input

3 20 20
6 2
1 3
2 6


Output

5.000000000000000


Input

4 1 1
2 3
3 2
2 3
3 2


Output

0.400000000000000

Note

First sample corresponds to the example in the problem statement.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
using db = double;
using ll = long long;
using ull = unsigned long long;
using pII = pair<int, int>;
using pLL = pair<ll, ll>;
constexpr int mod = 1e9 + 7;
template <class T1, class T2>
inline void chadd(T1 &x, T2 y, int Mod = mod) {
  x += y;
  while (x >= Mod) x -= Mod;
  while (x < 0) x += Mod;
}
template <class T1, class T2>
inline void chmax(T1 &x, T2 y) {
  if (x < y) x = y;
}
template <class T1, class T2>
inline void chmin(T1 &x, T2 y) {
  if (x > y) x = y;
}
inline int nextInt() {
  int x;
  cin >> x;
  return x;
}
void rd() {}
template <class T, class... Ts>
void rd(T &arg, Ts &...args) {
  cin >> arg;
  rd(args...);
}
void err() {
  cout << "\033[39;0m"
       << "\n";
}
template <class T, class... Ts>
void err(const T &arg, const Ts &...args) {
  cout << arg << ' ';
  err(args...);
}
template <template <typename...> class T, typename t, typename... A>
void err(const T<t> &arg, const A &...args) {
  for (auto &v : arg) cout << v << ' ';
  err(args...);
}
void ptt() { cout << "\n"; }
template <class T, class... Ts>
void ptt(const T &arg, const Ts &...args) {
  cout << ' ' << arg;
  ptt(args...);
}
template <class T, class... Ts>
void pt(const T &arg, const Ts &...args) {
  cout << arg;
  ptt(args...);
}
void pt() {}
template <template <typename...> class T, typename t, typename... A>
void pt(const T<t> &arg, const A &...args) {
  for (int i = 0, sze = arg.size(); i < sze; ++i)
    cout << arg[i] << " \n"[i == sze - 1];
  pt(args...);
}
inline ll qpow(ll base, ll n) {
  assert(n >= 0);
  ll res = 1;
  while (n) {
    if (n & 1) res = res * base % mod;
    base = base * base % mod;
    n >>= 1;
  }
  return res;
}
const db eps = 1e-8;
const db PI = acos(-1.0);
int sgn(db x) {
  if (fabs(x) < eps) return 0;
  return x < 0 ? -1 : 1;
}
constexpr int N = 1e5 + 10;
int n, p, q, a[N], b[N];
struct Point {
  db x, y;
  Point(db x = 0, db y = 0) : x(x), y(y) {}
  void scan() { rd(x, y); }
  void print() { printf("%.11f %.11f\n", x, y); }
  bool operator==(const Point &b) const {
    return sgn(x - b.x) == 0 && sgn(y - b.y) == 0;
  }
  bool operator<(const Point &b) const {
    return sgn(x - b.x) == 0 ? sgn(y - b.y) < 0 : x < b.x;
  }
  Point operator+(const Point &b) const { return Point(x + b.x, y + b.y); }
  Point operator-(const Point &b) const { return Point(x - b.x, y - b.y); }
  Point operator*(const db &b) const { return Point(x * b, y * b); }
  Point operator/(const db &b) const { return Point(x / b, y / b); }
  db operator^(const Point &b) const { return x * b.y - y * b.x; }
  db operator*(const Point &b) const { return x * b.x + y * b.y; }
  db len() { return norm(complex<db>(x, y)); }
  db len2() { return x * x + y * y; }
  db dis(Point b) { return norm(complex<db>(x - b.x, y - b.y)); }
  db dis2(Point b) { return (x - b.x) * (x - b.x) + (y - b.y) * (y - b.y); }
  int quad() {
    int _x = sgn(x), _y = sgn(y);
    if (_x > 0 && _y >= 0) return 1;
    if (_x <= 0 && _y > 0) return 2;
    if (_x < 0 && _y <= 0) return 3;
    if (_x >= 0 && _y < 0) return 4;
  }
  db getRad(Point a, Point b) {
    Point p = *this;
    return fabs(atan2(fabs((a - p) ^ (b - p)), (a - p) * (b - p)));
  }
  Point normal() { return Point(-y, x) / len(); }
  Point trunc(db r) {
    db l = len();
    if (!sgn(l)) return *this;
    r /= l;
    return Point(x * r, y * r);
  }
  Point rotleft() { return Point(-y, x); }
  Point rotright() { return Point(y, -x); }
  Point rotate(Point p, db rad) {
    Point v = (*this) - p;
    db c = cos(rad), s = sin(rad);
    return Point(p.x + v.x * c - v.y * s, p.y + v.x * s + v.y * c);
  }
};
struct Line {
  Point s, e;
  Line() {}
  Line(Point s, Point e) : s(s), e(e) {}
  void scan() {
    s.scan();
    e.scan();
  }
  void print() {
    s.print();
    e.print();
  }
  bool operator==(const Line &b) const { return s == b.s && e == b.e; }
  Line(Point p, db rad) {
    s = p;
    if (sgn(rad - PI / 2) == 0) {
      e = (s + Point(0, 1));
    } else {
      e = (s + Point(1, tan(rad)));
    }
  }
  Line(db a, db b, db c) {
    if (sgn(a) == 0) {
      s = Point(0, -c / b);
      e = Point(1, -c / b);
    } else if (sgn(b) == 0) {
      s = Point(-c / a, 0);
      e = Point(-c / a, 1);
    } else {
      s = Point(0, -c / b);
      e = Point(1, (-c - a) / b);
    }
  }
  void adjust() {
    if (e < s) swap(s, e);
  }
  db length() { return s.dis(e); }
  db getAngle() {
    db k = atan2(e.y - s.y, e.x - s.x);
    if (sgn(k) < 0) k += PI;
    if (sgn(k - PI) == 0) k -= PI;
    return k;
  }
  int relationPoint(Point p) {
    int c = sgn((p - s) ^ (e - s));
    if (c < 0) return 1;
    if (c > 0) return 2;
    return 3;
  }
  bool pointOnSeg(Point p) {
    return sgn((p - s) ^ (e - s)) == 0 && sgn((p - s) * (p - e)) <= 0;
  }
  bool parallel(Line b) { return sgn((e - s) ^ (b.e - b.s)) == 0; }
  int segCrossSeg(Line b) {
    int d1 = sgn((e - s) ^ (b.s - s));
    int d2 = sgn((e - s) ^ (b.e - s));
    int d3 = sgn((b.e - b.s) ^ (s - b.s));
    int d4 = sgn((b.e - b.s) ^ (e - b.s));
    if ((d1 ^ d2) == -2 && (d3 ^ d4) == -2) return 2;
    return ((d1 == 0 && sgn((b.s - s) * (b.s - e)) <= 0) ||
            (d2 == 0 && sgn((b.e - s) * (b.e - e)) <= 0) ||
            (d3 == 0 && sgn((s - b.s) * (s - b.e)) <= 0) ||
            (d4 == 0 && sgn((e - b.s) * (e - b.e)) <= 0));
  }
  int lineCrossSeg(Line b) {
    int d1 = sgn((e - s) ^ (b.s - s));
    int d2 = sgn((e - s) ^ (b.e - s));
    if ((d1 ^ d2) == -2) return 2;
    return (d1 == 0 || d2 == 0);
  }
  int lineCrossLine(Line b) {
    if ((*this).parallel(b)) return b.relationPoint(s) == 3;
    return 2;
  }
  Point crossPoint(Line b) {
    db a1 = (b.e - b.s) ^ (s - b.s);
    db a2 = (b.e - b.s) ^ (e - b.s);
    return Point((s.x * a2 - e.x * a1) / (a2 - a1),
                 (s.y * a2 - e.y * a1) / (a2 - a1));
  }
  db disPointToLine(Point p) { return fabs((p - s) ^ (e - s)) / length(); }
  db disPointToSeg(Point p) {
    if (sgn((p - s) * (e - s)) < 0 || sgn((p - e) * (s - e)) < 0)
      return min(p.dis(s), p.dis(e));
    return disPointToLine(p);
  }
  db disSegToSeg(Line b) {
    return min(min(disPointToSeg(b.s), disPointToSeg(b.e)),
               min(b.disPointToSeg(s), b.disPointToSeg(e)));
  }
  Point lineProg(Point p) {
    return s + (((e - s) * ((e - s) * (p - s))) / ((e - s).len2()));
  }
  Point symmetryPoint(Point p) {
    Point q = lineProg(p);
    return Point(q.x * 2 - p.x, q.y * 2 - p.y);
  }
};
struct Polygon {
  vector<Point> p;
  Polygon() { p.clear(); }
  Polygon(int n) {
    p.clear();
    p.resize(n);
  }
  int sze() { return p.size(); }
  Point &operator[](int x) { return p[(x + sze()) % sze()]; }
  void add(Point q) { p.push_back(q); }
  void scan(int n = -1) {
    if (n == -1) scanf("%d", &n);
    (*this) = Polygon(n);
    for (int i = 0; i < n; ++i) p[i].scan();
  }
  vector<Line> getline() {
    vector<Line> l(sze());
    for (int i = 0; i < sze(); ++i) {
      int j = (i + 1) % sze();
      l[i] = Line(p[i], p[j]);
    }
    return l;
  }
  void convexHull(int opt = 1) {
    sort(p.begin(), p.end());
    Polygon res;
    res.p.resize(sze() * 2);
    int top = -1;
    for (int i = 0; i < sze(); ++i) {
      while (top > 0 &&
             sgn((res[top] - res[top - 1]) ^ (p[i] - res[top - 1])) < opt)
        --top;
      res[++top] = p[i];
    }
    int pre = top;
    for (int i = sze() - 2; i >= 0; --i) {
      while (top > pre &&
             sgn((res[top] - res[top - 1]) ^ (p[i] - res[top - 1])) < opt)
        --top;
      res[++top] = p[i];
    }
    if (top > 0) res.p.resize(top);
    p = res.p;
  }
};
void run() {
  db ans = 1e18;
  for (int i = 1; i <= n; ++i) rd(a[i], b[i]);
  for (int i = 1; i <= n; ++i) {
    chmin(ans, max(p * 1.0 / a[i], q * 1.0 / b[i]));
  }
  Polygon po;
  for (int i = 1; i <= n; ++i) po.add(Point((db)a[i], (db)b[i]));
  po.convexHull();
  vector<Line> li(po.getline());
  Line base = Line(Point(0, 0), Point((db)p, (db)q));
  for (auto &it : li) {
    Point now = base.crossPoint(it);
    if (sgn(now.x) > 0 && sgn(now.y) > 0 && it.pointOnSeg(now)) {
      chmin(ans, p * 1.0 / (db)now.x);
    }
  }
  pt(ans);
}
int main() {
  ios::sync_with_stdio(false);
  cin.tie(nullptr);
  cout.tie(nullptr);
  cout << fixed << setprecision(20);
  while (cin >> n >> p >> q) run();
  return 0;
}