Problem: This is a harder version of the problem. The difference is only in constraints.

You are given a rectangular n × m matrix a. In one move you can choose any column and cyclically shift elements in this column. You can perform this operation as many times as you want (possibly zero). You can perform this operation to a column multiple times.

After you are done with cyclical shifts, you compute for every row the maximal value in it. Suppose that for i-th row it is equal r_i. What is the maximal possible value of r_1+r_2+…+r_n?

Input

The first line contains an integer t (1 ≤ t ≤ 40), the number of test cases in the input.

The first line of each test case contains integers n and m (1 ≤ n ≤ 12, 1 ≤ m ≤ 2000) — the number of rows and the number of columns in the given matrix a. 

Each of the following n lines contains m integers, the elements of a (1 ≤ a_{i, j} ≤ 10^5).

Output

Print t integers: answers for all test cases in the order they are given in the input.

Example

Input


3
2 3
2 5 7
4 2 4
3 6
4 1 5 2 10 4
8 6 6 4 9 10
5 4 9 5 8 7
3 3
9 9 9
1 1 1
1 1 1


Output


12
29
27

Note

In the first test case you can shift the third column down by one, this way there will be r_1 = 5 and r_2 = 7.

In the second case you can don't rotate anything at all, this way there will be r_1 = r_2 = 10 and r_3 = 9.

Solution (in JAVA):

Solution:
//package round584;
import java.io.ByteArrayInputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.PrintWriter;
import java.util.Arrays;
import java.util.InputMismatchException;

// imp:12m
public class E4 {
	InputStream is;
	PrintWriter out;
	String INPUT = "";

	
	void solve()
	{
		for(int T = ni(); T> 0;T--){
			int n = ni(), m = ni();
			int[][] a = new int[n][];
			for(int i = 0;i < n;i++)a[i] = na(m);
			
			long[] mx = new long[m];
			for(int i = 0;i < m;i++){
				int u = 0;
				for(int j = 0;j < n;j++){
					u = Math.max(u, a[j][i]);
				}
				mx[i] = 1000000000L-u<<32|i;
			}
			Arrays.sort(mx);
			int[] dp = new int[1<<n];
			for(int i = 0;i < n && i < m;i++){
				int c = (int)mx[i];
				int[] ls = new int[1<<n];
				for(int j = 1;j < 1<<n;j++){
					ls[j] = ls[j&j-1] + a[Integer.numberOfTrailingZeros(j)][c];
				}
				for(int j = 1;j < 1<<n;j++){
					int r = rot(j, n);
					ls[r] = Math.max(ls[r], ls[j]);
				}
				int[] ndp = new int[1<<n];
				for(int j = 0;j < 1<<n;j++){
					if(rot(j, n) == j){
						int cur = j;
						for(int sh = 0;sh < n;sh++){
							cur = cur>>1|(cur&1)<<n-1;
							int mask = (1<<n)-1^cur;
							for(int k = mask;k >= 0;k--){
								k &= mask;
								
								ndp[k|cur] = Math.max(
										ndp[k|cur], dp[k] + ls[j]);
							}
						}
					}
				}
				dp = ndp;
			}
			out.println(dp[(1<<n)-1]);
		}
	}
	
	int rot(int x, int n)
	{
		int ret = x;
		for(int i = 0;i < n;i++){
			x = x>>>1|(x&1)<<n-1;
				ret = Math.min(ret, x);
		}
		return ret;
	}
	
	void run() throws Exception
	{
//		int n = 12, m = 2000;
//		Random gen = new Random();
//		StringBuilder sb = new StringBuilder();
//		sb.append(40 + " ");
//		for(int rep = 0;rep < 40;rep++){
//			sb.append(n + " ");
//			sb.append(m + " ");
//			for (int i = 0; i < n*m; i++) {
//				sb.append(gen.nextInt(100000) + " ");
//			}
//		}
//		INPUT = sb.toString();

		
		is = oj ? System.in : new ByteArrayInputStream(INPUT.getBytes());
		out = new PrintWriter(System.out);
		
		long s = System.currentTimeMillis();
		solve();
		out.flush();
		tr(System.currentTimeMillis()-s+"ms");
	}
	
	public static void main(String[] args) throws Exception { new E4().run(); }
	
	private byte[] inbuf = new byte[1024];
	public int lenbuf = 0, ptrbuf = 0;
	
	private int readByte()
	{
		if(lenbuf == -1)throw new InputMismatchException();
		if(ptrbuf >= lenbuf){
			ptrbuf = 0;
			try { lenbuf = is.read(inbuf); } catch (IOException e) { throw new InputMismatchException(); }
			if(lenbuf <= 0)return -1;
		}
		return inbuf[ptrbuf++];
	}
	
	private boolean isSpaceChar(int c) { return !(c >= 33 && c <= 126); }
	private int skip() { int b; while((b = readByte()) != -1 && isSpaceChar(b)); return b; }
	
	private double nd() { return Double.parseDouble(ns()); }
	private char nc() { return (char)skip(); }
	
	private String ns()
	{
		int b = skip();
		StringBuilder sb = new StringBuilder();
		while(!(isSpaceChar(b))){ // when nextLine, (isSpaceChar(b) && b != ' ')
			sb.appendCodePoint(b);
			b = readByte();
		}
		return sb.toString();
	}
	
	private char[] ns(int n)
	{
		char[] buf = new char[n];
		int b = skip(), p = 0;
		while(p < n && !(isSpaceChar(b))){
			buf[p++] = (char)b;
			b = readByte();
		}
		return n == p ? buf : Arrays.copyOf(buf, p);
	}
	
	private char[][] nm(int n, int m)
	{
		char[][] map = new char[n][];
		for(int i = 0;i < n;i++)map[i] = ns(m);
		return map;
	}
	
	private int[] na(int n)
	{
		int[] a = new int[n];
		for(int i = 0;i < n;i++)a[i] = ni();
		return a;
	}
	
	private int ni()
	{
		int num = 0, b;
		boolean minus = false;
		while((b = readByte()) != -1 && !((b >= '0' && b <= '9') || b == '-'));
		if(b == '-'){
			minus = true;
			b = readByte();
		}
		
		while(true){
			if(b >= '0' && b <= '9'){
				num = num * 10 + (b - '0');
			}else{
				return minus ? -num : num;
			}
			b = readByte();
		}
	}
	
	private long nl()
	{
		long num = 0;
		int b;
		boolean minus = false;
		while((b = readByte()) != -1 && !((b >= '0' && b <= '9') || b == '-'));
		if(b == '-'){
			minus = true;
			b = readByte();
		}
		
		while(true){
			if(b >= '0' && b <= '9'){
				num = num * 10 + (b - '0');
			}else{
				return minus ? -num : num;
			}
			b = readByte();
		}
	}
	
	private boolean oj = System.getProperty("ONLINE_JUDGE") != null;
	private void tr(Object... o) { if(!oj)System.out.println(Arrays.deepToString(o)); }
}