Problem: You are given strings s and t. Find one longest string that is a subsequence of both s and t.

Constraints

* s and t are strings consisting of lowercase English letters.
* 1 \leq |s|, |t| \leq 3000

Input

Input is given from Standard Input in the following format:


s
t


Output

Print one longest string that is a subsequence of both s and t. If there are multiple such strings, any of them will be accepted.

Examples

Input

axyb
abyxb


Output

axb


Input

aa
xayaz


Output

aa


Input

a
z


Output




Input

abracadabra
avadakedavra


Output

aaadara

Solution (in PYTHON3):

Solution:
s = input()
t = input()
dp = []
for i in range(len(s)+1):
  L = [0]*(len(t)+1)
  dp.append(L)
for i in range(len(s)):
  for j in range(len(t)):
    if s[i] == t[j]:
      dp[i+1][j+1] = dp[i][j]+1
    else:
      dp[i+1][j+1] = max(dp[i+1][j],dp[i][j+1])
n = len(s)
m = len(t)
ans = ''
while n > 0 and m > 0:
  if dp[n][m] == dp[n-1][m]:
    n -= 1
  elif dp[n][m] == dp[n][m-1]:
    m -= 1
  else:
    n -= 1
    m -= 1
    ans = s[n]+ans
print(ans)