Problem: Find the difference of two sets $A = \\{a_0, a_1, ..., a_{n-1}\\}$ and $B = \\{b_0, b_1, ..., b_{m-1}\\}$, $A - B$.

Constraints

* $1 \leq n, m \leq 200,000$
* $0 \leq a_0 < a_1 < ... < a_{n-1} \leq 10^9$
* $0 \leq b_0 < b_1 < ... < b_{m-1} \leq 10^9$

Input

The input is given in the following format.


$n$
$a_0 \; a_1 \; ... \; a_{n-1}$
$m$
$b_0 \; b_1 \; ... \; b_{m-1}$


Elements in $A$ and $B$ are given in ascending order. There are no duplicate elements in each set.

Output

Print elements in the difference in ascending order. Print an element in a line.

Example

Input

5
1 2 3 5 8
2
2 5


Output

1
3
8

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
using i64 = int64_t;
using vi = vector<i64>;
using vvi = vector<vi>;

int main() {
    ios::sync_with_stdio(false);
    cin.tie(nullptr);
    cout.tie(nullptr);
    cout.setf(ios::fixed);
    cout.precision(10);
    int n;
    cin >> n;
    set<int> as, bs, isec;
    for (int i = 0; i < n; i++) {
        int a;
        cin >> a;
        as.insert(a);
    }
    cin >> n;
    for (int i = 0; i < n; i++) {
        int a;
        cin >> a;
        bs.insert(a);
    }

    set_difference(as.begin(), as.end(), bs.begin(), bs.end(), inserter(isec, isec.end()));
    vi vs;
    for (int i: isec) {
        vs.push_back(i);
    }
    sort(vs.begin(), vs.end());
    for (int v: vs) {
        cout << v << endl;
    }
}