Problem: You are given three positive (i.e. strictly greater than zero) integers x, y and z.

Your task is to find positive integers a, b and c such that x = max(a, b), y = max(a, c) and z = max(b, c), or determine that it is impossible to find such a, b and c.

You have to answer t independent test cases. Print required a, b and c in any (arbitrary) order.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers x, y, and z (1 ≤ x, y, z ≤ 10^9).

Output

For each test case, print the answer:

  * "NO" in the only line of the output if a solution doesn't exist; 
  * or "YES" in the first line and any valid triple of positive integers a, b and c (1 ≤ a, b, c ≤ 10^9) in the second line. You can print a, b and c in any order. 

Example

Input


5
3 2 3
100 100 100
50 49 49
10 30 20
1 1000000000 1000000000


Output


YES
3 2 1
YES
100 100 100
NO
NO
YES
1 1 1000000000

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;
 
public class ThreePairwiseMaximums{
 
    public static void main(String[] args)throws IOException {
        /* Enter your code here. Read input from STDIN. Print output to STDOUT. Your class should be named Solution. */
        BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
        int t=Integer.parseInt(br.readLine());
        for(int j=0;j<t;j++){
         //   int n=Integer.parseInt(br.readLine());
            String[]inp=br.readLine().split(" ");
            int x=Integer.parseInt(inp[0]);
            int y=Integer.parseInt(inp[1]);
            int z=Integer.parseInt(inp[2]);
            if(x!=y&&y!=z&&z!=x||x>y&&y==z)
                System.out.println("No");
            else if(x==y&&x==z){
                System.out.println("Yes");
                System.out.println(x+" "+x+" "+x);
            }
            else if(x<y&&y==z){
                System.out.println("Yes");
                System.out.println(x+" "+x+" "+y);
            }
            else if(x==z&&x>y){
                System.out.println("Yes");
                System.out.println(y+" "+y+" "+z);
            }
            else if(x==y&&x>z){
                System.out.println("Yes");
                int r=z-1;
                System.out.println(z+" "+z+" "+x);
            }
            else
                System.out.println("No");
        }
    }
}