Problem: You are given three positive (i.e. strictly greater than zero) integers x, y and z.

Your task is to find positive integers a, b and c such that x = max(a, b), y = max(a, c) and z = max(b, c), or determine that it is impossible to find such a, b and c.

You have to answer t independent test cases. Print required a, b and c in any (arbitrary) order.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers x, y, and z (1 ≤ x, y, z ≤ 10^9).

Output

For each test case, print the answer:

  * "NO" in the only line of the output if a solution doesn't exist; 
  * or "YES" in the first line and any valid triple of positive integers a, b and c (1 ≤ a, b, c ≤ 10^9) in the second line. You can print a, b and c in any order. 

Example

Input


5
3 2 3
100 100 100
50 49 49
10 30 20
1 1000000000 1000000000


Output


YES
3 2 1
YES
100 100 100
NO
NO
YES
1 1 1000000000

Solution (in JAVA):

Solution:
import java.util.*;

public class Test41
{
    public static void main(String[] args)
    {int t,x,y,z;
    Scanner sc=new Scanner(System.in);
    t=sc.nextInt();
    while(t>0)
    {  
        x=sc.nextInt();
        y=sc.nextInt();
        z=sc.nextInt();
        if(x==y && x>=z)
        {if(x>z)
            {
            System.out.println("YES");
            System.out.println(x+" "+z+" "+"1");}
            else
            { System.out.println("YES");
            System.out.println(x+" "+y+" "+z);}
        }
        else if(x==z && x>=y)
        {
            if(x>y)
            {
                System.out.println("YES");
                System.out.println(y+" "+x+" "+"1");
            }
            else
            {
                System.out.println("YES");
                System.out.println(y+" "+x+" "+z);
            }
        }
        else if(y==z && y>=x)
        {
            if(y>x)
            {
                System.out.println("YES");
                System.out.println(x+" "+"1"+" "+y);
            }
            else
            {
                System.out.println("YES");
                System.out.println(x+" "+y+" "+z);
            }
        }
        else
        {
            System.out.println("NO");
        }
        t--;
}
    }
}