Problem: You are given three positive (i.e. strictly greater than zero) integers x, y and z.

Your task is to find positive integers a, b and c such that x = max(a, b), y = max(a, c) and z = max(b, c), or determine that it is impossible to find such a, b and c.

You have to answer t independent test cases. Print required a, b and c in any (arbitrary) order.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers x, y, and z (1 ≤ x, y, z ≤ 10^9).

Output

For each test case, print the answer:

  * "NO" in the only line of the output if a solution doesn't exist; 
  * or "YES" in the first line and any valid triple of positive integers a, b and c (1 ≤ a, b, c ≤ 10^9) in the second line. You can print a, b and c in any order. 

Example

Input


5
3 2 3
100 100 100
50 49 49
10 30 20
1 1000000000 1000000000


Output


YES
3 2 1
YES
100 100 100
NO
NO
YES
1 1 1000000000

Solution (in JAVA):

Solution:

import java.util.ArrayList;
import java.util.Collections;
import java.util.Scanner;



public class Main {

    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        int t = scanner.nextInt();
        while (t > 0) {
            ArrayList<Long> nums = new ArrayList<>();
            ArrayList<Long> dNums = new ArrayList<>();
            for (int i = 0; i < 3; i++) {
                long m = scanner.nextLong();
                nums.add(m);
                if (!dNums.contains(m))
                    dNums.add(m);
            }

            if (dNums.size() == 3)
                System.out.println("NO");
            else if (dNums.size() == 2) {
                Collections.sort(dNums);
                long max = dNums.get(1);
                int counter = 0;
                for (int i = 0; i < 3; i++) {
                    if (nums.get(i) == max)
                        counter++;
                }

                if (counter == 1)
                    System.out.println("NO");
                else {
                    System.out.println("YES");
                    System.out.print(max + " ");
                    System.out.print(dNums.get(0) + " ");
                    System.out.print(dNums.get(0));
                    System.out.println();
                }
            } else {
                System.out.println("YES");
                for (int i = 0; i < 3; i++) {
                    System.out.print(dNums.get(0) + " ");
                }
                System.out.println();
            }
            t--;
        }
    }
}