Problem: You are given three positive (i.e. strictly greater than zero) integers x, y and z.

Your task is to find positive integers a, b and c such that x = max(a, b), y = max(a, c) and z = max(b, c), or determine that it is impossible to find such a, b and c.

You have to answer t independent test cases. Print required a, b and c in any (arbitrary) order.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers x, y, and z (1 ≤ x, y, z ≤ 10^9).

Output

For each test case, print the answer:

  * "NO" in the only line of the output if a solution doesn't exist; 
  * or "YES" in the first line and any valid triple of positive integers a, b and c (1 ≤ a, b, c ≤ 10^9) in the second line. You can print a, b and c in any order. 

Example

Input


5
3 2 3
100 100 100
50 49 49
10 30 20
1 1000000000 1000000000


Output


YES
3 2 1
YES
100 100 100
NO
NO
YES
1 1 1000000000

Solution (in PYTHON):

Solution:
from __future__ import print_function, division
from sys import stdin, stdout
from fractions import gcd
from math import *
from collections import *
from operator import itemgetter, mul
from functools import reduce

rstr = lambda: stdin.readline().strip()
rstrs = lambda: [str(x) for x in stdin.readline().split()]
rint = lambda: int(stdin.readline())
rints = lambda: [int(x) for x in stdin.readline().split()]
arr_2d = lambda n: [rints() for i in range(n)]
out = []

for _ in range(int(input())):
    a = rints()
    if len(set(a)) == 3:
        print('NO')
    elif len(set(a)) == 1:
        print('YES')
        print(' '.join(map(str, a)))
    else:
        ma = max(a)
        if a.count(ma) == 1:
            print('NO')
        else:
            print('YES')
            print(' '.join(map(str, [min(a), ma, min(a)])))