Problem: Phoenix has decided to become a scientist! He is currently investigating the growth of bacteria.

Initially, on day 1, there is one bacterium with mass 1.

Every day, some number of bacteria will split (possibly zero or all). When a bacterium of mass m splits, it becomes two bacteria of mass m/2 each. For example, a bacterium of mass 3 can split into two bacteria of mass 1.5.

Also, every night, the mass of every bacteria will increase by one.

Phoenix is wondering if it is possible for the total mass of all the bacteria to be exactly n. If it is possible, he is interested in the way to obtain that mass using the minimum possible number of nights. Help him become the best scientist!

Input

The input consists of multiple test cases. The first line contains an integer t (1 ≤ t ≤ 1000) — the number of test cases.

The first line of each test case contains an integer n (2 ≤ n ≤ 10^9) — the sum of bacteria masses that Phoenix is interested in. 

Output

For each test case, if there is no way for the bacteria to exactly achieve total mass n, print -1. Otherwise, print two lines.

The first line should contain an integer d — the minimum number of nights needed.

The next line should contain d integers, with the i-th integer representing the number of bacteria that should split on the i-th day.

If there are multiple solutions, print any.

Example

Input


3
9
11
2


Output


3
1 0 2 
3
1 1 2
1
0 

Note

In the first test case, the following process results in bacteria with total mass 9: 

  * Day 1: The bacterium with mass 1 splits. There are now two bacteria with mass 0.5 each. 
  * Night 1: All bacteria's mass increases by one. There are now two bacteria with mass 1.5. 
  * Day 2: None split. 
  * Night 2: There are now two bacteria with mass 2.5. 
  * Day 3: Both bacteria split. There are now four bacteria with mass 1.25. 
  * Night 3: There are now four bacteria with mass 2.25. 

The total mass is 2.25+2.25+2.25+2.25=9. It can be proved that 3 is the minimum number of nights needed. There are also other ways to obtain total mass 9 in 3 nights.

 

In the second test case, the following process results in bacteria with total mass 11: 

  * Day 1: The bacterium with mass 1 splits. There are now two bacteria with mass 0.5. 
  * Night 1: There are now two bacteria with mass 1.5. 
  * Day 2: One bacterium splits. There are now three bacteria with masses 0.75, 0.75, and 1.5. 
  * Night 2: There are now three bacteria with masses 1.75, 1.75, and 2.5. 
  * Day 3: The bacteria with mass 1.75 and the bacteria with mass 2.5 split. There are now five bacteria with masses 0.875, 0.875, 1.25, 1.25, and 1.75. 
  * Night 3: There are now five bacteria with masses 1.875, 1.875, 2.25, 2.25, and 2.75. 

The total mass is 1.875+1.875+2.25+2.25+2.75=11. It can be proved that 3 is the minimum number of nights needed. There are also other ways to obtain total mass 11 in 3 nights.

 

In the third test case, the bacterium does not split on day 1, and then grows to mass 2 during night 1.

Solution (in JAVA):

Solution:
//package codeforces.round638div2;

import java.io.*;
import java.util.*;

public class Science {
    public static void main(String[] args) {
//        try {
//            FastScanner in = new FastScanner(new FileInputStream("src/input.in"));
//            PrintWriter out = new PrintWriter(new FileOutputStream("src/output.out"));

        FastScanner in = new FastScanner(System.in);
        PrintWriter out = new PrintWriter(System.out);

            int t = in.nextInt();
            solve(t, in, out);
//        } catch (IOException e) {
//            e.printStackTrace();
//        }
    }

    private static void solve(int q, FastScanner in, PrintWriter out) {
        for (int qq = 0; qq < q; qq++) {
            long n = in.nextLong();
            long currTotal = 1;
            long nextMaxGain = 2;
            int cnt = 0;
            List<Long> ans = new ArrayList<>();
            while(currTotal + nextMaxGain < n && nextMaxGain <= n - currTotal - nextMaxGain) {
                currTotal += nextMaxGain;
                nextMaxGain = nextMaxGain << 1;
                cnt++;
            }

            long[] p = new long[64];
            for(int i = 0; i < cnt; i++) {
                p[i] = i > 0 ? p[i - 1] * 2 : 1;
                ans.add(p[i]);
            }

            long diff = n - currTotal;
            if(diff > 0) {
                if(diff > nextMaxGain) {
                    long prevMaxGain = nextMaxGain >> 1;
                    long i1 = prevMaxGain, i2 = diff - prevMaxGain;
                    if(i2 > nextMaxGain) {
                        i1 += (i2 - nextMaxGain);
                        i2 = nextMaxGain;
                    }
                    ans.add(i1 - prevMaxGain);
                    ans.add(i2 - i1);
                }
                else {
                    long preMaxGain = nextMaxGain >> 1;
                    ans.add(diff - preMaxGain);
                }
            }
            out.println(ans.size());
            for(int i = 0; i < ans.size(); i++) {
                out.print(ans.get(i) + " ");
            }
            out.println();
        }
        out.close();
    }

    private static class BinarySearch {
        // return the right most index i such that a[i] <= t
        private static int rightMostUpperBound(Integer[] a, int t) {
            int l = 0, r = a.length - 1;
            while (l < r - 1) {
                int mid = l + (r - l) / 2;
                if (a[mid] <= t) {
                    l = mid;
                } else {
                    r = mid - 1;
                }
            }
            if (a[r] <= t) {
                return r;
            } else if (a[l] <= t) {
                return l;
            }
            return -1;
        }

        // return the left most index i such that a[i] >= t
        private static int leftMostLowerBound(Integer[] a, int t) {
            int l = 0, r = a.length - 1;
            while (l < r - 1) {
                int mid = l + (r - l) / 2;
                if (a[mid] >= t) {
                    r = mid;
                } else {
                    l = mid + 1;
                }
            }
            if (a[l] >= t) {
                return l;
            } else if (a[r] >= t) {
                return r;
            }
            return -1;
        }

        // Find the start and end index of a given t in a sorted(ascending) array; return [-1, -1] is t is not found
        private static int[] searchRange(Integer[] a, int t) {
            int first = firstPos(a, t);
            int last = firstPos(a, t + 1) - 1;
            if (first <= last) {
                return new int[]{first, last};
            }
            return new int[]{-1, -1};
        }

        private static int firstPos(Integer[] a, int t) {
            int first = a.length;
            int l = 0, r = a.length - 1;
            while (l <= r) {
                int mid = l + (r - l) / 2;
                if (a[mid] >= t) {
                    first = mid;
                    r = mid - 1;
                } else {
                    l = mid + 1;
                }
            }
            return first;
        }
    }

    private static class NumberTheory {
        private static long modularAdd(long a, long b, int mod) {
            long sum = a + b;
            if (sum >= mod) {
                sum -= mod;
            }
            return sum;
        }

        private static long modularSubtract(long a, long b, int mod) {
            long diff = a - b;
            if (diff < 0) {
                diff += mod;
            }
            return diff;
        }

        private static long fastModPow(long x, int n, long mod) {
            if (n == 0) {
                return 1;
            }
            long coeff = 1, base = x;
            while (n > 1) {
                if (n % 2 != 0) {
                    coeff = (coeff * base % mod);
                }
                base = (base * base % mod);
                n = n / 2;
            }
            long res = coeff * base % mod;
            return res;
        }

        private static long gcd(long a, long b) {
            if (b == 0) {
                return a;
            }
            return gcd(b, a % b);
        }

        private static long[] factorial(int n, long mod) {
            long[] factor = new long[n + 1];
            factor[0] = 1;
            for (int i = 1; i <= n; i++) {
                factor[i] = factor[i - 1] * i % mod;
            }
            return factor;
        }

        private static long modInv_EEA(long a, long mod) {
            long[] res = solveGcdEquation(a, mod);
            if (res[2] != 1) {
                // a and m are not coprime, modular inverse of a by m does not exist.
                return -1;
            }
            return (res[0] % mod + mod) % mod;
        }

        private static long[] solveGcdEquation(long a, long b) {
            if (b == 0) {
                return new long[]{1, 0, a};
            }
            long[] res = solveGcdEquation(b, a % b);
            return new long[]{res[1], res[0] - (a / b) * res[1], res[2]};
        }

        private static long binomialCoefficient(long[] factorial, long n, long k, long mod) {
            return factorial[(int) n] * modInv_EEA(factorial[(int) k], mod) % mod
                    * modInv_EEA(factorial[(int) (n - k)], mod) % mod;
        }
    }

    private static class Graph {
        private static int UNVISITED = 0;
        private static int VISITING = -1;
        private static int VISITED = 1;

        private static Stack<Integer> topologicalSort(Set<Integer>[] g) {
            Stack<Integer> stack = new Stack<>();
            int[] state = new int[g.length];

            for (int node = 0; node < g.length; node++) {
                if (!topoSortHelper(g, stack, state, node)) {
                    return null;
                }
            }
            return stack;
        }

        private static boolean topoSortHelper(Set<Integer>[] g, Stack<Integer> stack, int[] state, int currNode) {
            if (state[currNode] == VISITED) {
                return true;
            } else if (state[currNode] == VISITING) {
                return false;
            }
            state[currNode] = VISITING;
            for (int neighbor : g[currNode]) {
                if (!topoSortHelper(g, stack, state, neighbor)) {
                    return false;
                }
            }
            state[currNode] = VISITED;
            stack.push(currNode);
            return true;
        }
    }

    private static class FastScanner {
        BufferedReader br;
        StringTokenizer st;

        FastScanner(InputStream stream) {
            try {
                br = new BufferedReader(new InputStreamReader(stream));
            } catch (Exception e) {
                e.printStackTrace();
            }
        }

        String next() {
            while (st == null || !st.hasMoreTokens()) {
                try {
                    st = new StringTokenizer(br.readLine());
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
            return st.nextToken();
        }

        int nextInt() {
            return Integer.parseInt(next());
        }

        long nextLong() {
            return Long.parseLong(next());
        }

        double nextDouble() {
            return Double.parseDouble(next());
        }

        String nextLine() {
            String str = "";
            try {
                str = br.readLine();
            } catch (IOException e) {
                e.printStackTrace();
            }
            return str;
        }

        Integer[] nextIntArray(int n) {
            Integer[] a = new Integer[n];
            for (int i = 0; i < n; i++) {
                a[i] = nextInt();
            }
            return a;
        }

        Long[] nextLongArray(int n) {
            Long[] a = new Long[n];
            for (int i = 0; i < n; i++) {
                a[i] = nextLong();
            }
            return a;
        }
    }
}