Problem: You are given three positive (i.e. strictly greater than zero) integers x, y and z.

Your task is to find positive integers a, b and c such that x = max(a, b), y = max(a, c) and z = max(b, c), or determine that it is impossible to find such a, b and c.

You have to answer t independent test cases. Print required a, b and c in any (arbitrary) order.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers x, y, and z (1 ≤ x, y, z ≤ 10^9).

Output

For each test case, print the answer:

  * "NO" in the only line of the output if a solution doesn't exist; 
  * or "YES" in the first line and any valid triple of positive integers a, b and c (1 ≤ a, b, c ≤ 10^9) in the second line. You can print a, b and c in any order. 

Example

Input


5
3 2 3
100 100 100
50 49 49
10 30 20
1 1000000000 1000000000


Output


YES
3 2 1
YES
100 100 100
NO
NO
YES
1 1 1000000000

Solution (in JAVA):

Solution:

import java.util.Scanner;

public class maxofthree {
    public static void send(int a[],int n){
    int i=0,j=1,c=0,k=0;
    while(i<n&&j<n&&i!=j){
    if(a[i]>a[j]){
    c++;
    i++;
    }
    else{
   // j++;
    k++;
    }
    }
        System.out.println(c+" "+k);
    }
    public static void main(String[] args) {
    Scanner s=new Scanner(System.in);
        int t=s.nextInt();
        for (int i = 0; i < t; i++) {
            int a=s.nextInt();
            int b=s.nextInt();
            int c=s.nextInt();
            int max=0;
            if(a==b&&b==c){
                System.out.println("YES");
                System.out.println(a+" "+b+" "+c);
            }
            else{
                if(((a==b)&&(a>c))){
                    max=a;
                System.out.println("YES");
                System.out.println(max+" "+c+" "+c);
                }
                else if(((b==c)&&(b>a))){
                max=b;
                System.out.println("YES");
                System.out.println(max+" "+a+" "+a);
                
                }
                else if(((c==a)&&(c>b))){
                max=c;
                System.out.println("YES");
                System.out.println(max+" "+b+" "+b);
                }
                else{
                    System.out.println("NO");
                }
                }
        }
    }
}