Problem: Ashish has n elements arranged in a line. 

These elements are represented by two integers a_i — the value of the element and b_i — the type of the element (there are only two possible types: 0 and 1). He wants to sort the elements in non-decreasing values of a_i.

He can perform the following operation any number of times: 

  * Select any two elements i and j such that b_i ≠ b_j and swap them. That is, he can only swap two elements of different types in one move. 



Tell him if he can sort the elements in non-decreasing values of a_i after performing any number of operations.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. The description of the test cases follows.

The first line of each test case contains one integer n (1 ≤ n ≤ 500) — the size of the arrays.

The second line contains n integers a_i (1 ≤ a_i ≤ 10^5) — the value of the i-th element.

The third line containts n integers b_i (b_i ∈ \{0, 1\}) — the type of the i-th element.

Output

For each test case, print "Yes" or "No" (without quotes) depending on whether it is possible to sort elements in non-decreasing order of their value.

You may print each letter in any case (upper or lower).

Example

Input


5
4
10 20 20 30
0 1 0 1
3
3 1 2
0 1 1
4
2 2 4 8
1 1 1 1
3
5 15 4
0 0 0
4
20 10 100 50
1 0 0 1


Output


Yes
Yes
Yes
No
Yes

Note

For the first case: The elements are already in sorted order.

For the second case: Ashish may first swap elements at positions 1 and 2, then swap elements at positions 2 and 3.

For the third case: The elements are already in sorted order.

For the fourth case: No swap operations may be performed as there is no pair of elements i and j such that b_i ≠ b_j. The elements cannot be sorted.

For the fifth case: Ashish may swap elements at positions 3 and 4, then elements at positions 1 and 2.

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.*;
import java.math.*;

public class B {

	public void realMain() throws Exception {

		BufferedReader fin = new BufferedReader(new InputStreamReader(System.in), 1000000);

		String in = fin.readLine();

		String[] ar = in.split(" ");

		int T = Integer.parseInt(ar[0]);
	for(int t = 0; t < T; t++) {
		int ret2 = 0;
		boolean dig2 = false;
		for (int ch = 0; (ch = fin.read()) != -1; ) {
        		if (ch >= '0' && ch <= '9') {
            			dig2 = true;
           			ret2 = ret2 * 10 + ch - '0';
        		} else if (dig2) break;
    		}

		int n = ret2;

		int[] a = new int[n];
		int[] b = new int[n];



		for(int i = 0; i < n; i++) {
			int ret = 0;
			boolean dig = false;
			for (int ch = 0; (ch = fin.read()) != -1; ) {
        			if (ch >= '0' && ch <= '9') {
            				dig = true;
           				ret = ret * 10 + ch - '0';
        			} else if (dig) break;
    			}

			a[i] = ret;
			
		}

		for(int i = 0; i < n; i++) {
			int ret = 0;
			boolean dig = false;
			for (int ch = 0; (ch = fin.read()) != -1; ) {
        			if (ch >= '0' && ch <= '9') {
            				dig = true;
           				ret = ret * 10 + ch - '0';
        			} else if (dig) break;
    			}

			b[i] = ret;
			
		}

		int numzero = 0;
		int numone = 0;

		boolean issorted = true;

		for(int i = 0; i < n; i++) {
			if(b[i] == 0) {
				numzero++;
			} else {
				numone++;
			}

		}

		for(int i = 1; i < n; i++) {
			if(a[i] < a[i - 1]) {
				issorted = false;
			}
		}

		if(numone > 0 && numzero > 0) {
			System.out.println("Yes");
		} else if(issorted) {
			System.out.println("Yes");
		} else {
			System.out.println("No");
		}




	}

	}


	public static void main(String[] args) throws Exception {
		B b = new B();
		b.realMain();
	}
}