Problem: Fox Ciel is participating in a party in Prime Kingdom. There are n foxes there (include Fox Ciel). The i-th fox is ai years old.

They will have dinner around some round tables. You want to distribute foxes such that:

  1. Each fox is sitting at some table. 
  2. Each table has at least 3 foxes sitting around it. 
  3. The sum of ages of any two adjacent foxes around each table should be a prime number. 



If k foxes f1, f2, ..., fk are sitting around table in clockwise order, then for 1 ≤ i ≤ k - 1: fi and fi + 1 are adjacent, and f1 and fk are also adjacent.

If it is possible to distribute the foxes in the desired manner, find out a way to do that.

Input

The first line contains single integer n (3 ≤ n ≤ 200): the number of foxes in this party. 

The second line contains n integers ai (2 ≤ ai ≤ 104).

Output

If it is impossible to do this, output "Impossible".

Otherwise, in the first line output an integer m (<image>): the number of tables.

Then output m lines, each line should start with an integer k -=– the number of foxes around that table, and then k numbers — indices of fox sitting around that table in clockwise order.

If there are several possible arrangements, output any of them.

Examples

Input

4
3 4 8 9


Output

1
4 1 2 4 3


Input

5
2 2 2 2 2


Output

Impossible


Input

12
2 3 4 5 6 7 8 9 10 11 12 13


Output

1
12 1 2 3 6 5 12 9 8 7 10 11 4


Input

24
2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25


Output

3
6 1 2 3 6 5 4
10 7 8 9 12 15 14 13 16 11 10
8 17 18 23 22 19 20 21 24

Note

In example 1, they can sit around one table, their ages are: 3-8-9-4, adjacent sums are: 11, 17, 13 and 7, all those integers are primes.

In example 2, it is not possible: the sum of 2+2 = 4 is not a prime number.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
vector<bool> eratosthenes(int N) {
  vector<bool> is_prime(N + 1, true);
  is_prime[0] = is_prime[1] = false;
  const int LIM = static_cast<int>(sqrt(N));
  for (long long i = 2; i <= LIM; ++i) {
    if (is_prime[i]) {
      for (long long j = i * i; j <= N; j += i) {
        is_prime[j] = false;
      }
    }
  }
  return is_prime;
}
template <typename T, T INF, bool directed = true>
struct Dinic {
  struct Edge {
    int to;
    T cap, flow;
    Edge *back;
    Edge(int to, T cap, T flow, Edge *back)
        : to(to), cap(cap), flow(flow), back(back) {}
    bool remain() const { return flow < cap; }
    void add_flow(T f) {
      flow += f;
      back->flow -= f;
    }
  };
  vector<vector<Edge *>> g_;
  vector<int> memo_, level_;
  int src_, sink_;
  Dinic(int N, int src, int sink)
      : g_(N), memo_(N), level_(N), src_(src), sink_(sink) {}
  ~Dinic() {
    for (auto &row : g_) {
      for (auto e : row) {
        delete e;
      }
    }
  }
  T dinic_augment(int v, T cap) {
    if (v == sink_) return cap;
    const int N = g_[v].size();
    for (int i = memo_[v]; i < N; ++i) {
      const auto &e = g_[v][i];
      if (level_[e->to] != level_[v] + 1) continue;
      if (!e->remain()) continue;
      const T f = dinic_augment(e->to, min(cap, e->cap - e->flow));
      if (f > 0) {
        e->add_flow(f);
        memo_[v] = i + 1;
        return f;
      }
    }
    return 0;
  }
  void add_edge(int from, int to, T cap) {
    Edge *e = new Edge(to, cap, 0, nullptr);
    Edge *r = new Edge(from, directed ? 0 : cap, 0, e);
    e->back = r;
    g_[from].push_back(e);
    g_[to].push_back(r);
  }
  T calc() {
    T flow = 0;
    while (true) {
      fill(begin(level_), end(level_), -1);
      queue<int> q;
      q.push(src_);
      level_[src_] = 0;
      while (!q.empty()) {
        const int v = q.front();
        q.pop();
        for (const auto &e : g_[v]) {
          if (e->remain() && level_[e->to] == -1) {
            level_[e->to] = level_[v] + 1;
            q.push(e->to);
          }
        }
      }
      bool updated = false;
      fill(begin(memo_), end(memo_), 0);
      while (true) {
        T add = dinic_augment(src_, INF);
        if (add == 0) break;
        flow += add;
        updated = true;
      }
      if (!updated) break;
    }
    return flow;
  }
};
template <typename T>
ostream &operator<<(ostream &os, const vector<T> &v) {
  bool first = true;
  for (const T &t : v) {
    if (!first) cout << ' ';
    os << t;
    first = false;
  }
  return os;
}
vector<bool> is_prime = eratosthenes(20000);
bool solve(bool first) {
  int N;
  if (!(cin >> N)) return false;
  if (!N) return false;
  vector<int> nodes(N);
  for (int i = 0; i < N; ++i) {
    cin >> nodes[i];
  }
  Dinic<int, 10000> dinic(N + 2, N, N + 1);
  int flow = 0;
  for (int i = 0; i < N; ++i) {
    for (int j = 0; j < i; ++j) {
      if (is_prime[nodes[i] + nodes[j]]) {
        if (nodes[i] % 2 == 0)
          dinic.add_edge(i, j, 1);
        else
          dinic.add_edge(j, i, 1);
      }
    }
    if (nodes[i] % 2 == 0) {
      dinic.add_edge(N, i, 2);
      flow += 2;
    } else {
      dinic.add_edge(i, N + 1, 2);
    }
  }
  if (flow != N || dinic.calc() != flow) {
    cout << "Impossible" << endl;
  } else {
    const auto &graph = dinic.g_;
    vector<bool> used(N, false);
    vector<vector<int>> components;
    for (int i = 0; i < N; ++i) {
      if (used[i]) continue;
      int cur = i;
      used[i] = true;
      components.push_back(vector<int>());
      while (true) {
        components.back().push_back(cur + 1);
        for (auto e : graph[cur]) {
          if (e->flow != 0 && e->to < N && !used[e->to]) {
            used[e->to] = true;
            cur = e->to;
            break;
          }
        }
        if (cur + 1 == components.back().back()) break;
      }
    }
    cout << components.size() << endl;
    for (const auto &c : components) {
      cout << c.size() << ' ';
      cout << c << endl;
    }
  }
  return true;
}
int main() {
  bool first = true;
  while (solve(first)) {
    first = false;
  }
  return 0;
}