Problem: You are given three positive (i.e. strictly greater than zero) integers x, y and z.

Your task is to find positive integers a, b and c such that x = max(a, b), y = max(a, c) and z = max(b, c), or determine that it is impossible to find such a, b and c.

You have to answer t independent test cases. Print required a, b and c in any (arbitrary) order.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers x, y, and z (1 ≤ x, y, z ≤ 10^9).

Output

For each test case, print the answer:

  * "NO" in the only line of the output if a solution doesn't exist; 
  * or "YES" in the first line and any valid triple of positive integers a, b and c (1 ≤ a, b, c ≤ 10^9) in the second line. You can print a, b and c in any order. 

Example

Input


5
3 2 3
100 100 100
50 49 49
10 30 20
1 1000000000 1000000000


Output


YES
3 2 1
YES
100 100 100
NO
NO
YES
1 1 1000000000

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.*;

public class Codeforces
{
    public static void main(String args[])throws Exception
    {
        BufferedReader bu=new BufferedReader(new InputStreamReader(System.in));
        StringBuilder sb=new StringBuilder();
        int t=Integer.parseInt(bu.readLine());
        while(t-->0)
        {
            String s[]=bu.readLine().split(" ");
            int x=Integer.parseInt(s[0]),y=Integer.parseInt(s[1]),z=Integer.parseInt(s[2]);
            Set<Integer> se=new HashSet<>();
            se.add(x); se.add(y); se.add(z);
            if(se.size()>2) {sb.append("NO\n"); continue;}
            if(se.size()==1)
            {
                sb.append("YES\n");
                sb.append(x+" "+x+" "+x+"\n");
                continue;
            }

            int a=x,b=x,c=x;
            boolean ans=true;
            if(x==y)
            {
                a=x;
                b=z; c=z;
                if(z>x) ans=false;
            }
            if(y==z)
            {
                c=y;
                a=x;
                b=x;
                if(x>y) ans=false;
            }
            if(x==z)
            {
                b=x;
                a=y;
                c=y;
                if(y>x) ans=false;
            }

            if(!ans) sb.append("NO\n");
            else
            {
                sb.append("YES\n");
                sb.append(a+" "+b+" "+c+"\n");
            }
        }
        System.out.print(sb);
    }
}