Problem: You are given three positive (i.e. strictly greater than zero) integers x, y and z.

Your task is to find positive integers a, b and c such that x = max(a, b), y = max(a, c) and z = max(b, c), or determine that it is impossible to find such a, b and c.

You have to answer t independent test cases. Print required a, b and c in any (arbitrary) order.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers x, y, and z (1 ≤ x, y, z ≤ 10^9).

Output

For each test case, print the answer:

  * "NO" in the only line of the output if a solution doesn't exist; 
  * or "YES" in the first line and any valid triple of positive integers a, b and c (1 ≤ a, b, c ≤ 10^9) in the second line. You can print a, b and c in any order. 

Example

Input


5
3 2 3
100 100 100
50 49 49
10 30 20
1 1000000000 1000000000


Output


YES
3 2 1
YES
100 100 100
NO
NO
YES
1 1 1000000000

Solution (in JAVA):

Solution:
import java.util.*;
import java.io.*;

public class A {
	public static void main(String[] args) throws IOException {
		BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
		PrintWriter out = new PrintWriter(new BufferedWriter(new OutputStreamWriter(System.out)));

		int numCases = Integer.parseInt(in.readLine());
		for (int c = 0; c < numCases; c++) {
			StringTokenizer st = new StringTokenizer(in.readLine());
			int x = Integer.parseInt(st.nextToken());
			int y = Integer.parseInt(st.nextToken());
			int z = Integer.parseInt(st.nextToken());

			int[] res = process(x, y, z);
			if (res != null) {
				out.println("YES");
				out.println(String.format("%d %d %d", res[0], res[1], res[2]));
			} else {
				out.println("NO");
			}
		}

		out.flush();
		in.close();
		out.close();
	}

	private static int[] process(int x, int y, int z) {
		if (x == y && y == z) {
			return new int[] {x, x, x};
		}

		if (x == y && y > z) {
			return new int[] {x, z, z};
		} else if (y == z && y > x) {
			return new int[] {x, x, y};
		} else if (x == z && x > y) {
			return new int[] {y, x, y};
		} else {
			return null;
		}
	}
}