Problem: There is a grid of square cells with H horizontal rows and W vertical columns. The cell at the i-th row and the j-th column will be denoted as Cell (i, j).

In Cell (i, j), a_{ij} coins are placed.

You can perform the following operation any number of times:

Operation: Choose a cell that was not chosen before and contains one or more coins, then move one of those coins to a vertically or horizontally adjacent cell.

Maximize the number of cells containing an even number of coins.

Constraints

* All values in input are integers.
* 1 \leq H, W \leq 500
* 0 \leq a_{ij} \leq 9

Input

Input is given from Standard Input in the following format:


H W
a_{11} a_{12} ... a_{1W}
a_{21} a_{22} ... a_{2W}
:
a_{H1} a_{H2} ... a_{HW}


Output

Print a sequence of operations that maximizes the number of cells containing an even number of coins, in the following format:


N
y_1 x_1 y_1' x_1'
y_2 x_2 y_2' x_2'
:
y_N x_N y_N' x_N'


That is, in the first line, print an integer N between 0 and H \times W (inclusive), representing the number of operations.

In the (i+1)-th line (1 \leq i \leq N), print four integers y_i, x_i, y_i' and x_i' (1 \leq y_i, y_i' \leq H and 1 \leq x_i, x_i' \leq W), representing the i-th operation. These four integers represents the operation of moving one of the coins placed in Cell (y_i, x_i) to a vertically or horizontally adjacent cell, (y_i', x_i').

Note that if the specified operation violates the specification in the problem statement or the output format is invalid, it will result in Wrong Answer.

Examples

Input

2 3
1 2 3
0 1 1


Output

3
2 2 2 3
1 1 1 2
1 3 1 2


Input

3 2
1 0
2 1
1 0


Output

3
1 1 1 2
1 2 2 2
3 1 3 2


Input

1 5
9 9 9 9 9


Output

2
1 1 1 2
1 3 1 4

Solution (in PYTHON):

Solution:
import collections
h,w = map(int, raw_input().split())
mat = [map(int, raw_input().split(' ')) for _ in range(h)]
elems = [(i,j) for i in range(len(mat)) for j in range(len(mat[0]))]
elems.sort(key = lambda x: x[0] + x[1])
q = collections.deque(elems)
moves = []
while(q):
	i,j = q.popleft()
	if mat[i][j] % 2:
		if j + 1 < len(mat[0]):
			mat[i][j] -= 1
			mat[i][j+1] += 1
			moves.append([(i+1,j+1), (i+1, j + 2)])
			#q.append((i,j + 1))
		elif i + 1 < len(mat):
			mat[i][j] -=1
			mat[i+1][j] += 1
			moves.append([(i+1,j+1), (i+2, j+1)])
			#q.append((i + 1,j ))
print len(moves)
for u,v in moves: print u[0],u[1],v[0],v[1]