Problem: You are given three positive (i.e. strictly greater than zero) integers x, y and z.

Your task is to find positive integers a, b and c such that x = max(a, b), y = max(a, c) and z = max(b, c), or determine that it is impossible to find such a, b and c.

You have to answer t independent test cases. Print required a, b and c in any (arbitrary) order.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers x, y, and z (1 ≤ x, y, z ≤ 10^9).

Output

For each test case, print the answer:

  * "NO" in the only line of the output if a solution doesn't exist; 
  * or "YES" in the first line and any valid triple of positive integers a, b and c (1 ≤ a, b, c ≤ 10^9) in the second line. You can print a, b and c in any order. 

Example

Input


5
3 2 3
100 100 100
50 49 49
10 30 20
1 1000000000 1000000000


Output


YES
3 2 1
YES
100 100 100
NO
NO
YES
1 1 1000000000

Solution (in PYTHON3):

Solution:
Test_case=int(input())
for i in range(Test_case):
    x,y,z=input().split()
    x=int(x)
    y=int(y)
    z=int(z)    
    if x==y and x==z:
        print('YES')
        print("{} {} {}".format(x,y,1))
    elif x==y and x!=z:
        if z>x:
            print('NO')
        else:
            print("YES")
            print("{} {} {}".format(x,1,z))
    elif x==z and x!=y:
        if y>x:
            print('NO')
        else:
            print("YES")
            print("{} {} {}".format(x,y,1))
    elif z==y and x!=z:
        if x>z:
            print('NO')
        else:
            print("YES")
            print("{} {} {}".format(x,1,z))
    elif x!=y and y!=z:
        print('NO')