Problem: You are given three positive (i.e. strictly greater than zero) integers x, y and z.

Your task is to find positive integers a, b and c such that x = max(a, b), y = max(a, c) and z = max(b, c), or determine that it is impossible to find such a, b and c.

You have to answer t independent test cases. Print required a, b and c in any (arbitrary) order.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers x, y, and z (1 ≤ x, y, z ≤ 10^9).

Output

For each test case, print the answer:

  * "NO" in the only line of the output if a solution doesn't exist; 
  * or "YES" in the first line and any valid triple of positive integers a, b and c (1 ≤ a, b, c ≤ 10^9) in the second line. You can print a, b and c in any order. 

Example

Input


5
3 2 3
100 100 100
50 49 49
10 30 20
1 1000000000 1000000000


Output


YES
3 2 1
YES
100 100 100
NO
NO
YES
1 1 1000000000

Solution (in PYTHON3):

Solution:
import sys
import math
import bisect
from sys import stdin, stdout
from math import gcd, floor, sqrt, log
from collections import defaultdict
from bisect import bisect_left as bl, bisect_right as br
from collections import Counter

ip = lambda : int(stdin.readline())
inp = lambda: map(int,stdin.readline().split())

t = ip()
for _ in range(t):
    x,y,z = inp()
    if len(set([x,y,z])) == 3:
        print("NO")
    else:
        ch = max(x,y,z)
        arr = [x,y,z]
        ct = 0
        for i in arr:
            if i == ch:
                ct += 1
        if ct == 1:
            print("NO")
        else:
            print("YES")
            print(min(arr),min(arr),ch)