Problem: You are given three positive (i.e. strictly greater than zero) integers x, y and z.

Your task is to find positive integers a, b and c such that x = max(a, b), y = max(a, c) and z = max(b, c), or determine that it is impossible to find such a, b and c.

You have to answer t independent test cases. Print required a, b and c in any (arbitrary) order.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers x, y, and z (1 ≤ x, y, z ≤ 10^9).

Output

For each test case, print the answer:

  * "NO" in the only line of the output if a solution doesn't exist; 
  * or "YES" in the first line and any valid triple of positive integers a, b and c (1 ≤ a, b, c ≤ 10^9) in the second line. You can print a, b and c in any order. 

Example

Input


5
3 2 3
100 100 100
50 49 49
10 30 20
1 1000000000 1000000000


Output


YES
3 2 1
YES
100 100 100
NO
NO
YES
1 1 1000000000

Solution (in JAVA):

Solution:
import java.util.*; 
import java.io.*; 
import java.lang.Math; 
public class Main
{ 
  
    public static void main(String[] args)
{ 
     Scanner in=new Scanner(System.in); 
    int i,n,x,t,y,z,j,a,b,s1,c;
    t=in.nextInt();
    for(j=0;j<t;j++)
    {
        x=in.nextInt();
        y=in.nextInt();
        z=in.nextInt();
        if(x==y&&y==z)
        {
            System.out.println("YES"); 
              System.out.println(x+" "+y+" "+z); 
        }
        else if(y==z&&y>x)
        {
             System.out.println("YES"); 
              System.out.println(x+" "+x+" "+y); 
        }
        else if(x==z&&x>y)
        {
            
             System.out.println("YES"); 
              System.out.println(y+" "+y+" "+x); 
        }
         else if(x==y&&x>z)
        {
            
             System.out.println("YES"); 
              System.out.println(z+" "+z+" "+x); 
        }
    else
    {
        System.out.println("NO"); 
    }
      
    }
    
   
    
       
        
}
}