Problem: You are given three positive (i.e. strictly greater than zero) integers x, y and z.

Your task is to find positive integers a, b and c such that x = max(a, b), y = max(a, c) and z = max(b, c), or determine that it is impossible to find such a, b and c.

You have to answer t independent test cases. Print required a, b and c in any (arbitrary) order.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers x, y, and z (1 ≤ x, y, z ≤ 10^9).

Output

For each test case, print the answer:

  * "NO" in the only line of the output if a solution doesn't exist; 
  * or "YES" in the first line and any valid triple of positive integers a, b and c (1 ≤ a, b, c ≤ 10^9) in the second line. You can print a, b and c in any order. 

Example

Input


5
3 2 3
100 100 100
50 49 49
10 30 20
1 1000000000 1000000000


Output


YES
3 2 1
YES
100 100 100
NO
NO
YES
1 1 1000000000

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

/**
 *
 * @author Varun
 */
public class div3a {

    /**
     * @param args the command line arguments
     */
    public static void main(String[] args) throws IOException {
        // TODO code application logic here
         BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
       int t = Integer.parseInt(br.readLine());
       
       while(t-->0){
           String s[] = br.readLine().trim().split(" ");
           long x  = Long.parseLong(s[0]);
             long y  = Long.parseLong(s[1]);
               long z  = Long.parseLong(s[2]);
               long res = Math.max(Math.max(x, y), z);
               int c = 0;
               if(x==res)
                   c++;
               if(y==res)
                   c++;
               if(z==res)
                   c++;
             //  System.out.println(res + " " + c);
               if(x==y && y==z)
               {
                   System.out.println("YES");
                   System.out.println(x + " " + y + " " + z);
               }
              else if(c==2){
                  long k=0;
                  if(res!=x)
                     k=x;
                  else if(res!=y)
                      k=y;
                  else
                      k=z;
                  System.out.println("YES");
                  System.out.print(res + " " + 1 + " " + k );
                  System.out.println();
                   
               }
               else{
                   System.out.println("NO");
               }
                   
       }
    }
    
}