Problem: You are given three positive (i.e. strictly greater than zero) integers x, y and z.

Your task is to find positive integers a, b and c such that x = max(a, b), y = max(a, c) and z = max(b, c), or determine that it is impossible to find such a, b and c.

You have to answer t independent test cases. Print required a, b and c in any (arbitrary) order.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers x, y, and z (1 ≤ x, y, z ≤ 10^9).

Output

For each test case, print the answer:

  * "NO" in the only line of the output if a solution doesn't exist; 
  * or "YES" in the first line and any valid triple of positive integers a, b and c (1 ≤ a, b, c ≤ 10^9) in the second line. You can print a, b and c in any order. 

Example

Input


5
3 2 3
100 100 100
50 49 49
10 30 20
1 1000000000 1000000000


Output


YES
3 2 1
YES
100 100 100
NO
NO
YES
1 1 1000000000

Solution (in JAVA):

Solution:
import java.util.*;
 
import java.io.*;
 
 
public class Main{
          public static void main(String args[])
          {
                    Scanner sc = new  Scanner(System.in);
		
		
		int test = sc.nextInt();
	
		while(test-->0)
		{
			int x = sc.nextInt();
			int y = sc.nextInt();
			int z = sc.nextInt();
			
			
			if(x!=y && y!=z && z!=x)
				System.out.println("NO");
			else if((x==y && x<z) || (x==z && x<y) || (y==z && y<x))
			{
				System.out.println("NO");
			}else if(x ==y && y== z) {
				System.out.println("YES");
				System.out.println(x + " "+ y +" "+ z);
			}else 
			{
				if(x==y && z < x) {
					System.out.println("YES");
					int a = x;
					int b = 1; 
					int c = z;
					System.out.println(a+" "+b+" "+c);
				}else if(x == z && y<z)
				{
					System.out.println("YES");
					int a = x;
					int b = y;
					int c = 1;
					System.out.println(a+" "+b+" "+c);
				}
				else {
					System.out.println("YES");
					int a = x;
					int b = 1;
					int c = z;
					System.out.println(a+" "+b+" "+c);
			}
				
			
			
			
		}
 
	}
                    
          }
}