Problem: Find the symmetric difference of two sets $A = \\{a_0, a_1, ..., a_{n-1}\\}$ and $B = \\{b_0, b_1, ..., b_{m-1}\\}$.

Constraints

* $1 \leq n, m \leq 200,000$
* $0 \leq a_0 < a_1 < ... < a_{n-1} \leq 10^9$
* $0 \leq b_0 < b_1 < ... < b_{m-1} \leq 10^9$

Input

The input is given in the following format.


$n$
$a_0 \; a_1 \; ... \; a_{n-1}$
$m$
$b_0 \; b_1 \; ... \; b_{m-1}$


Elements in $A$ and $B$ are given in ascending order. There are no duplicate elements in each set.

Output

Print elements in the symmetric difference in ascending order. Print an element in a line.

Example

Input

7
1 2 3 4 5 6 7
4
2 4 6 8


Output

1
3
5
7
8

Solution (in CPP):

Solution:
#include <iostream>
#include <string>
#include <vector>
#include <queue>
#include <set>
#include <map>
#include <utility>
#include <stack>
#include <numeric>
#include <algorithm>
#include <tuple>
#include <stdio.h>
#include <bitset>
#include <limits.h>
#include <complex>
#include <deque>
#include <iomanip>
#include <list>
using namespace std;
#define pi pair<int32,int32>
#define pl pair<int64,int64>
#define chmax(a,b) (a<b ? a=b:0)
#define chmin(a,b) (a>b ? a=b:0)
#define en cout << endl //セミコロンつけろ
//#define MM 1000000000
//#define MOD MM+7
const int MM = 1e9;
const int MOD = MM+7;
const long double PI = acos(-1);
const long long INF = 1e15;
int dx[8] = {-1,0,1,0,-1,-1,1,1};
int dy[8] = {0,-1,0,1,-1,1,1,-1};
// 'A' = 65, 'Z' = 90, 'a' = 97, 'z' = 122
template<typename T>
T GCD(T u,T v){
    return v ? GCD(v,u%v) : u;
}
template<typename T>
T LCM(T x,T y){
    T gc = GCD(x,y);
    return x*y/gc;
}

int main(){
    int n,m; cin >> n;
    map<int,int> mp;
    int a[n];
    vector<int> v;
    for(int i = 0; i < n; i++){
        cin >> a[i];
        mp[a[i]]++;
    }
    cin >> m;
    int b[m];
    for(int i = 0; i < m; i++){
        cin >> b[i];
        mp[b[i]]++;
    }
    for(int i = 0; i < n; i++){
        if (mp[a[i]] == 1){
            v.push_back(a[i]);
        }
    }

    for(int i = 0; i < m; i++){
        if (mp[b[i]] == 1){
            v.push_back(b[i]);
        }
    }
    sort(v.begin(),v.end());
    for(int i = 0; i < v.size(); i++){
        cout << v[i] << endl;
    }
}