Problem: One very experienced problem writer decided to prepare a problem for April Fools Day contest. The task was very simple - given an arithmetic expression, return the result of evaluating this expression. However, looks like there is a bug in the reference solution...

Input

The only line of input data contains the arithmetic expression. The expression will contain between 2 and 10 operands, separated with arithmetic signs plus and/or minus. Each operand will be an integer between 0 and 255, inclusive.

Output

Reproduce the output of the reference solution, including the bug.

Examples

Input

8-7+6-5+4-3+2-1-0


Output

4


Input

2+2


Output

-46


Input

112-37


Output

375

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
string s;
int k, sum, ans;
int main() {
  cin >> s;
  for (int i = 0; i < s.length(); i++) {
    if (s[i] >= '0' && s[i] <= '9') {
      sum *= 10;
      sum += s[i] - '0';
      k = i;
    } else {
      break;
    }
  }
  ans = sum;
  sum = 0;
  for (int i = k + 1; i < s.length(); i++) {
    if (s[i] >= '0' && s[i] <= '9') {
      if (s[i - 1] == '-') {
        sum = '-' - '0';
        for (int j = i; j < s.length(); j++) {
          if (s[j] >= '0' && s[j] <= '9') {
            sum *= 10;
            sum += s[j] - '0';
            i = j;
          } else {
            break;
          }
        }
        ans -= sum;
        sum = 0;
      }
      if (s[i - 1] == '+') {
        sum = '+' - '0';
        for (int j = i; j < s.length(); j++) {
          if (s[j] >= '0' && s[j] <= '9') {
            sum *= 10;
            sum += s[j] - '0';
            i = j;
          } else {
            break;
          }
        }
        ans += sum;
        sum = 0;
      }
    }
  }
  cout << ans << endl;
  return 0;
}