Problem: In this problem you will write a simple code generator for a 2D programming language derived from [Brainfuck](https://en.wikipedia.org/wiki/Brainfuck).

The code in this language is a rectangular grid of characters '.' and 'X'. The code is converted to a Brainfuck program as follows: the characters are read in the usual order (top to bottom, left to right), and each 'X' character is converted a Brainfuck instruction to be executed. The instruction is defined by the left, top and right neighbors of the 'X' character using the following conversion table:

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You are given a string. Output a program in the described language which prints this string.

You can download the language interpreter used for judging here: <https://assets.codeforces.com/rounds/952/puzzling-interpreter.cpp> (use C++11 to compile the code). Note several implementation details:

  * The first step of the language interpretation is conversion to a Brainfuck program, which is then executed.
  * The code must be rectangular, with all lines of the same length. It can have at most 10,000 lines and 10,000 columns, and can have at most 500,000 'X' characters.
  * The code has toroidal topology, i.e. the 'X' on the first line will have top neighbor in the last line.
  * Brainfuck interpreter has 30000 memory cells which store integers from 0 to 255 with increment/decrement done modulo 256.
  * Console input (, command) is allowed in Brainfuck code but has no effect when executed.

Input

The input consists of a single string of characters with ASCII codes between 33 ('!') and 122 ('z'), inclusive. The length of the string is between 1 and 10 characters, inclusive.

Output

Output a program in the described language which, when executed, will print the given message.

Example

Input

$$$

Output

.......X.......
......XXX......
.....XXXXX.....
....XXXXXXX....
...XXXXXXXXX...
..XXXXXXXXXXX..
.XXXXXXXXXXXXX.
...............
X.............X
X..............
X..............
X..............

Note

The example corresponds to the following Brainfuck program:
    
    
           -  
          >+<  
         >+++<  
        >+++++<  
       >+++++++<  
      >+++++++++<  
     >+++++++++++<  
      
    <             >  
    .  
    .  
    .  
    

The triangular block decrements the first memory cell and sets the value of the second memory cell to 36 - the ASCII code of '$' character. The next line after the triangular block moves the memory pointer to the second memory cell, and the next three lines print the '$' character three times.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int main() {
  ios_base::sync_with_stdio(false);
  cin.tie(0);
  string s;
  cin >> s;
  int tmp = 0, width = 16;
  for (int i = 0; i < s.length(); i++) {
    for (int i = 0; i < width; i++) cout << '.';
    cout << endl;
    char c = s[i];
    for (int j = 0; j < width; j++) cout << 'X';
    cout << endl;
    while (tmp < c || tmp - c > width) {
      for (int j = 0; j < width; j++) cout << 'X';
      cout << endl;
      tmp += width;
      tmp %= 256;
    }
    for (int j = 0; j < width; j++) cout << '.';
    cout << endl;
    int diff = 256 + tmp - c - 1;
    bool odd = true;
    diff %= 256;
    while (diff > 0) {
      for (int j = 0; j < width / 2; j++) {
        if (diff > 0) {
          cout << (odd ? "X." : ".X");
          diff--;
          tmp--;
        } else
          cout << "..";
      }
      odd = !odd;
      cout << endl;
    }
    tmp--;
    cout << (odd ? "X." : ".X");
    for (int j = 0; j < width - 2; j++) cout << '.';
    cout << endl;
    cout << (odd ? "X." : ".X");
    for (int j = 0; j < width - 2; j++) cout << '.';
    cout << endl;
  }
  return 0;
}