Problem: You are given three positive (i.e. strictly greater than zero) integers x, y and z.

Your task is to find positive integers a, b and c such that x = max(a, b), y = max(a, c) and z = max(b, c), or determine that it is impossible to find such a, b and c.

You have to answer t independent test cases. Print required a, b and c in any (arbitrary) order.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers x, y, and z (1 ≤ x, y, z ≤ 10^9).

Output

For each test case, print the answer:

  * "NO" in the only line of the output if a solution doesn't exist; 
  * or "YES" in the first line and any valid triple of positive integers a, b and c (1 ≤ a, b, c ≤ 10^9) in the second line. You can print a, b and c in any order. 

Example

Input


5
3 2 3
100 100 100
50 49 49
10 30 20
1 1000000000 1000000000


Output


YES
3 2 1
YES
100 100 100
NO
NO
YES
1 1 1000000000

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int x, y, z;
bool check(int first, int second, int third) {
  int a, b, c;
  if (first == 1) {
    if (x != y) return 0;
    a = x;
    if (second == 2) {
      b = z;
      c = z;
      if (a < b || a < c || b < c) return 0;
    } else {
      c = z;
      b = z;
      if (a < b || a < c || c < b) return 0;
    }
    cout << "YES\n" << a << ' ' << b << ' ' << c << '\n';
    return 1;
  } else if (first == 2) {
    if (x != z) return 0;
    b = x;
    c = y;
    a = y;
    if (b < a || b < c || a < c) return 0;
    cout << "YES\n" << a << ' ' << b << ' ' << c << '\n';
    return 1;
  } else {
    if (y != z) return 0;
    c = y;
    a = x;
    b = x;
    if (c < a || c < b) return 0;
    cout << "YES\n" << a << ' ' << b << ' ' << c << '\n';
    return 1;
  }
}
int main() {
  ios::sync_with_stdio(0);
  cin.tie(0), cout.tie(0);
  int t;
  cin >> t;
  while (t--) {
    cin >> x >> y >> z;
    if (check(1, 2, 3)) continue;
    if (check(1, 3, 2)) continue;
    if (check(2, 1, 3)) continue;
    if (check(2, 3, 1)) continue;
    if (check(3, 1, 2)) continue;
    if (check(3, 2, 1)) continue;
    cout << "NO\n";
  }
  return 0;
}