Problem: A permutation of length n is a sequence of integers from 1 to n of length n containing each number exactly once. For example, [1], [4, 3, 5, 1, 2], [3, 2, 1] are permutations, and [1, 1], [0, 1], [2, 2, 1, 4] are not.

There was a permutation p[1 ... n]. It was merged with itself. In other words, let's take two instances of p and insert elements of the second p into the first maintaining relative order of elements. The result is a sequence of the length 2n.

For example, if p=[3, 1, 2] some possible results are: [3, 1, 2, 3, 1, 2], [3, 3, 1, 1, 2, 2], [3, 1, 3, 1, 2, 2]. The following sequences are not possible results of a merging: [1, 3, 2, 1, 2, 3], [3, 1, 2, 3, 2, 1], [3, 3, 1, 2, 2, 1].

For example, if p=[2, 1] the possible results are: [2, 2, 1, 1], [2, 1, 2, 1]. The following sequences are not possible results of a merging: [1, 1, 2, 2], [2, 1, 1, 2], [1, 2, 2, 1].

Your task is to restore the permutation p by the given resulting sequence a. It is guaranteed that the answer exists and is unique.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 400) — the number of test cases. Then t test cases follow.

The first line of the test case contains one integer n (1 ≤ n ≤ 50) — the length of permutation. The second line of the test case contains 2n integers a_1, a_2, ..., a_{2n} (1 ≤ a_i ≤ n), where a_i is the i-th element of a. It is guaranteed that the array a represents the result of merging of some permutation p with the same permutation p.

Output

For each test case, print the answer: n integers p_1, p_2, ..., p_n (1 ≤ p_i ≤ n), representing the initial permutation. It is guaranteed that the answer exists and is unique.

Example

Input


5
2
1 1 2 2
4
1 3 1 4 3 4 2 2
5
1 2 1 2 3 4 3 5 4 5
3
1 2 3 1 2 3
4
2 3 2 4 1 3 4 1


Output


1 2 
1 3 4 2 
1 2 3 4 5 
1 2 3 
2 3 4 1 

Solution (in JAVA):

Solution:
import java.util.*;
import java.io.*;
public class Codeforces {
	
	public static void main(String[]args) throws IOException
	{
		    BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
		    int tc=Integer.parseInt(br.readLine());
		    for(int t=0;t<tc;t++) {
		    	 
		    	 int n=Integer.parseInt(br.readLine());
		    	 
		    	 int[]A=new int[2*n];
		    	 
		    	 String[]B=br.readLine().split(" ");
		    	 
		    	 for(int i=0;i<B.length;i++)
		    	 {
		    		 A[i]=Integer.parseInt(B[i]);
		    	 }
		    	 
		    	 int j=0;
		    	 int k=1;
		    	 
		    	 boolean[]visited=new boolean[2*n];
		    	 
		    	 while(j<visited.length)
		    	 {
		    		 if(!visited[j])
		    		 {
		    			 System.out.print(A[j]+" ");
		    			 visited[j]=true;
		    			 j++;
		    			 
		    			 if(j-1>=k)
		    			 {
		    				 k=j;
		    			 }
		    			 while(A[k]!=A[j-1])
		    			 {
		    				 k++;
		    			 }
		    			 visited[k]=true;
		    			 k++;
		    		 }
		    		 else
		    		 {
		    			 j++;
		    		 }
		    	 }
		    
		    		 System.out.println();
		    	}
		    	
		    
		    }
	}