Problem: You are given three positive (i.e. strictly greater than zero) integers x, y and z.

Your task is to find positive integers a, b and c such that x = max(a, b), y = max(a, c) and z = max(b, c), or determine that it is impossible to find such a, b and c.

You have to answer t independent test cases. Print required a, b and c in any (arbitrary) order.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers x, y, and z (1 ≤ x, y, z ≤ 10^9).

Output

For each test case, print the answer:

  * "NO" in the only line of the output if a solution doesn't exist; 
  * or "YES" in the first line and any valid triple of positive integers a, b and c (1 ≤ a, b, c ≤ 10^9) in the second line. You can print a, b and c in any order. 

Example

Input


5
3 2 3
100 100 100
50 49 49
10 30 20
1 1000000000 1000000000


Output


YES
3 2 1
YES
100 100 100
NO
NO
YES
1 1 1000000000

Solution (in PYTHON3):

Solution:
#import math
#from functools import lru_cache
#import heapq
#from collections import defaultdict
from collections import Counter
#from collections import deque
#from sys import stdout
#from sys import setrecursionlimit
#setrecursionlimit(10**7)
from sys import stdin
input = stdin.readline

INF = 10**9 + 7
MAX = 10**7 + 7
MOD = 10**9 + 7

for Ti in range(int(input().strip())):
    l = [int(x) for x in input().strip().split()]
    l.sort()
    c=  Counter(l)
    if len(c) == 1:
        print('YES')
        print(*l)
    elif len(c) == 2:
        mini = min(l)
        maxa = max(l)
        if(c[mini] == 2):
            print('NO')
        else:
            print('YES')
            print(maxa, mini, mini)
    else:
        print('NO')