Problem: You are given three positive (i.e. strictly greater than zero) integers x, y and z.

Your task is to find positive integers a, b and c such that x = max(a, b), y = max(a, c) and z = max(b, c), or determine that it is impossible to find such a, b and c.

You have to answer t independent test cases. Print required a, b and c in any (arbitrary) order.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers x, y, and z (1 ≤ x, y, z ≤ 10^9).

Output

For each test case, print the answer:

  * "NO" in the only line of the output if a solution doesn't exist; 
  * or "YES" in the first line and any valid triple of positive integers a, b and c (1 ≤ a, b, c ≤ 10^9) in the second line. You can print a, b and c in any order. 

Example

Input


5
3 2 3
100 100 100
50 49 49
10 30 20
1 1000000000 1000000000


Output


YES
3 2 1
YES
100 100 100
NO
NO
YES
1 1 1000000000

Solution (in PYTHON3):

Solution:

def f(x, y, z):
    x_y_z = [x, y, z]
    x_y_z.sort()
    # print(x_y_z)
    if x_y_z[0] == x_y_z[1] == x_y_z[2]:
        result = x_y_z
    elif x_y_z[0] != x_y_z[1] == x_y_z[2]:
        result = [x_y_z[0], x_y_z[0], x_y_z[1]]
    elif x_y_z[0] == x_y_z[1] != x_y_z[2]:
        result = None
    elif x_y_z[0] != x_y_z[1] != x_y_z[2]:
        result = None

    return "NO" if result is None else f"YES\n{result[0]} {result[1]} {result[2]}"


if __name__ == "__main__":
    for _ in range(int(input())):
        print(f(*tuple(map(int, input().split()))))