Problem: You are given three positive (i.e. strictly greater than zero) integers x, y and z.

Your task is to find positive integers a, b and c such that x = max(a, b), y = max(a, c) and z = max(b, c), or determine that it is impossible to find such a, b and c.

You have to answer t independent test cases. Print required a, b and c in any (arbitrary) order.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers x, y, and z (1 ≤ x, y, z ≤ 10^9).

Output

For each test case, print the answer:

  * "NO" in the only line of the output if a solution doesn't exist; 
  * or "YES" in the first line and any valid triple of positive integers a, b and c (1 ≤ a, b, c ≤ 10^9) in the second line. You can print a, b and c in any order. 

Example

Input


5
3 2 3
100 100 100
50 49 49
10 30 20
1 1000000000 1000000000


Output


YES
3 2 1
YES
100 100 100
NO
NO
YES
1 1 1000000000

Solution (in PYTHON3):

Solution:
import sys


for t in range(int(sys.stdin.readline())):
	x,y,z = map(int, sys.stdin.readline().split())

	if len(set((x, y, z))) == 3:
		sys.stdout.write("NO\n")
		continue
	
	a = sorted((x, y, z))
	if a[1] != a[2]:
		sys.stdout.write("NO\n")
		continue
		
	sys.stdout.write("YES\n")
	
	if len(set((x, y, z))) == 1:
		sys.stdout.write(f"{x} {x} {x}\n")
	else:
		if x == a[0]:
			sys.stdout.write(f"{x} {x} {z}\n")
		elif y == a[0]:
			sys.stdout.write(f"{x} {y} {1}\n")
		else:
			sys.stdout.write(f"{x} {z} {z}\n")