Problem: Ashish has n elements arranged in a line. 

These elements are represented by two integers a_i — the value of the element and b_i — the type of the element (there are only two possible types: 0 and 1). He wants to sort the elements in non-decreasing values of a_i.

He can perform the following operation any number of times: 

  * Select any two elements i and j such that b_i ≠ b_j and swap them. That is, he can only swap two elements of different types in one move. 



Tell him if he can sort the elements in non-decreasing values of a_i after performing any number of operations.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. The description of the test cases follows.

The first line of each test case contains one integer n (1 ≤ n ≤ 500) — the size of the arrays.

The second line contains n integers a_i (1 ≤ a_i ≤ 10^5) — the value of the i-th element.

The third line containts n integers b_i (b_i ∈ \{0, 1\}) — the type of the i-th element.

Output

For each test case, print "Yes" or "No" (without quotes) depending on whether it is possible to sort elements in non-decreasing order of their value.

You may print each letter in any case (upper or lower).

Example

Input


5
4
10 20 20 30
0 1 0 1
3
3 1 2
0 1 1
4
2 2 4 8
1 1 1 1
3
5 15 4
0 0 0
4
20 10 100 50
1 0 0 1


Output


Yes
Yes
Yes
No
Yes

Note

For the first case: The elements are already in sorted order.

For the second case: Ashish may first swap elements at positions 1 and 2, then swap elements at positions 2 and 3.

For the third case: The elements are already in sorted order.

For the fourth case: No swap operations may be performed as there is no pair of elements i and j such that b_i ≠ b_j. The elements cannot be sorted.

For the fifth case: Ashish may swap elements at positions 3 and 4, then elements at positions 1 and 2.

Solution (in JAVA):

Solution:
//package r648;

import java.util.ArrayList;
import java.util.Collections;
import java.util.Scanner;

public class second {

	public static void main(String[] args) {
		// TODO Auto-generated method stub
		Scanner sc = new Scanner(System.in);
		int t = sc.nextInt();
		while(t-->0)
		{
			int n = sc.nextInt();
			int num[] = new int[n];
			ArrayList<Integer> sorted = new ArrayList<Integer>();
			for(int i =0;i<n;i++)
			{
				num[i] = sc.nextInt();
				sorted.add(num[i]);
				
				
			}
			Collections.sort(sorted);
			int type[] = new int[n];
			for(int i =0;i<n;i++)
			{
				type[i] = sc.nextInt();
			}
			boolean one = false;
			boolean zero = false;
			boolean ans = true;
			boolean sort = true;
			for(int i =0;i<n;i++)
			{
				if(type[i] == 1)
					one = true;
				else
					zero = true;
				if(num[i]==sorted.get(i) && sort)
				{
					continue;
				}
				else
				{	sort = false;
					
					if(zero && one)
					{
						ans = true;
						break;
					}
					else
					{
						ans= false;
						
					}
					
				}
				
			}
			if(ans)
			{
				System.out.println("Yes");
			}
			else
			{
				System.out.println("No");
			}
			
			
			
			
			
		}

	}

}