Problem: You are given three positive (i.e. strictly greater than zero) integers x, y and z.

Your task is to find positive integers a, b and c such that x = max(a, b), y = max(a, c) and z = max(b, c), or determine that it is impossible to find such a, b and c.

You have to answer t independent test cases. Print required a, b and c in any (arbitrary) order.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers x, y, and z (1 ≤ x, y, z ≤ 10^9).

Output

For each test case, print the answer:

  * "NO" in the only line of the output if a solution doesn't exist; 
  * or "YES" in the first line and any valid triple of positive integers a, b and c (1 ≤ a, b, c ≤ 10^9) in the second line. You can print a, b and c in any order. 

Example

Input


5
3 2 3
100 100 100
50 49 49
10 30 20
1 1000000000 1000000000


Output


YES
3 2 1
YES
100 100 100
NO
NO
YES
1 1 1000000000

Solution (in JAVA):

Solution:
import java.util.*;
public class mrje {
	public static void main(String args[]) {
		Scanner sc=new Scanner(System.in);
		int t=sc.nextInt();
		while(t-->0) {
			int a=sc.nextInt(),b=sc.nextInt(),c=sc.nextInt();
			if(a>b) {
				if(c==a) {
					System.out.println("YES");
					System.out.println(a+" "+b+" "+b);
				}else
					System.out.println("NO");
			}else if(a<b) {
				if(c==b) {
					System.out.println("YES");
					System.out.println(b+" "+a+" "+a);
				}else
					System.out.println("NO");
			}else {
				if(c>a)
					System.out.println("NO");
				else {
					System.out.println("YES");
					System.out.println(a+" "+c+" "+c);
				}
			}
		}
	}
}