Problem: You are given three positive (i.e. strictly greater than zero) integers x, y and z.

Your task is to find positive integers a, b and c such that x = max(a, b), y = max(a, c) and z = max(b, c), or determine that it is impossible to find such a, b and c.

You have to answer t independent test cases. Print required a, b and c in any (arbitrary) order.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers x, y, and z (1 ≤ x, y, z ≤ 10^9).

Output

For each test case, print the answer:

  * "NO" in the only line of the output if a solution doesn't exist; 
  * or "YES" in the first line and any valid triple of positive integers a, b and c (1 ≤ a, b, c ≤ 10^9) in the second line. You can print a, b and c in any order. 

Example

Input


5
3 2 3
100 100 100
50 49 49
10 30 20
1 1000000000 1000000000


Output


YES
3 2 1
YES
100 100 100
NO
NO
YES
1 1 1000000000

Solution (in PYTHON3):

Solution:
def inp():
    return(int(input()))
def inlt():
    return(list(map(int,input().split())))
def insr():
    s = input()
    return(list(s[:len(s) ]))
def invr():
    return(map(int,input().split()))


n = inp()

for i in range(n):
    l = inlt()
    x = l[0]
    y = l[1]
    z = l[2]

    l.sort()

    if(l[2] == l[1]):
        print("YES")
        if(l[0] == x ):
            print(str(l[0]) + " " + str(l[0]) + " " + str(l[2]))
        elif(l[0] == y ):
            print(str(l[0]) + " " + str(l[2]) + " " + str(l[0]))
        else:
            print(str(l[2]) + " " + str(l[0]) + " " + str(l[0]))
    else:
        print("NO")