Problem: You are given three positive (i.e. strictly greater than zero) integers x, y and z.

Your task is to find positive integers a, b and c such that x = max(a, b), y = max(a, c) and z = max(b, c), or determine that it is impossible to find such a, b and c.

You have to answer t independent test cases. Print required a, b and c in any (arbitrary) order.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers x, y, and z (1 ≤ x, y, z ≤ 10^9).

Output

For each test case, print the answer:

  * "NO" in the only line of the output if a solution doesn't exist; 
  * or "YES" in the first line and any valid triple of positive integers a, b and c (1 ≤ a, b, c ≤ 10^9) in the second line. You can print a, b and c in any order. 

Example

Input


5
3 2 3
100 100 100
50 49 49
10 30 20
1 1000000000 1000000000


Output


YES
3 2 1
YES
100 100 100
NO
NO
YES
1 1 1000000000

Solution (in JAVA):

Solution:
/* package codechef; // don't place package name! */

import java.util.*;
import java.lang.*;
import java.io.*;

/* Name of the class has to be "Main" only if the class is public. */
public class Codeforces1
{
    public static void main (String[] args) throws java.lang.Exception
    {
        Scanner sc=new Scanner(System.in);
        int k=sc.nextInt();
        while(k-->0)
        {
            int x=sc.nextInt();
            int y=sc.nextInt();
            int z=sc.nextInt();
            
            if((x!=y)&&(x!=z)&&(y!=z))
            {
                System.out.println("NO");
            }
            else
            {
                int a=0,b=0,c=0;
                if(x==y)
                {
                    if(x<z)
                    {
                        System.out.println("NO");
                        continue;
                    }
                    a=x;
                    b=c=z;
                }
                else if(y==z)
                {
                    if(y<x)
                    {
                        System.out.println("NO");
                        continue;
                    }
                    c=y;
                    a=b=x;
                }
                else if(x==z)
                {
                    if(x<y)
                    {
                        System.out.println("NO");
                        continue;
                    }
                    b=z;
                    a=c=y;
                }
                if(a<1||b<1||c<1)
                    System.out.println("NO");
                else
                {
                                        System.out.println("YES");

                    System.out.println(a+" "+b+" "+c);
                }
            }
        }
    }
}