Problem: There is a grid of square cells with H horizontal rows and W vertical columns. The cell at the i-th row and the j-th column will be denoted as Cell (i, j).

In Cell (i, j), a_{ij} coins are placed.

You can perform the following operation any number of times:

Operation: Choose a cell that was not chosen before and contains one or more coins, then move one of those coins to a vertically or horizontally adjacent cell.

Maximize the number of cells containing an even number of coins.

Constraints

* All values in input are integers.
* 1 \leq H, W \leq 500
* 0 \leq a_{ij} \leq 9

Input

Input is given from Standard Input in the following format:


H W
a_{11} a_{12} ... a_{1W}
a_{21} a_{22} ... a_{2W}
:
a_{H1} a_{H2} ... a_{HW}


Output

Print a sequence of operations that maximizes the number of cells containing an even number of coins, in the following format:


N
y_1 x_1 y_1' x_1'
y_2 x_2 y_2' x_2'
:
y_N x_N y_N' x_N'


That is, in the first line, print an integer N between 0 and H \times W (inclusive), representing the number of operations.

In the (i+1)-th line (1 \leq i \leq N), print four integers y_i, x_i, y_i' and x_i' (1 \leq y_i, y_i' \leq H and 1 \leq x_i, x_i' \leq W), representing the i-th operation. These four integers represents the operation of moving one of the coins placed in Cell (y_i, x_i) to a vertically or horizontally adjacent cell, (y_i', x_i').

Note that if the specified operation violates the specification in the problem statement or the output format is invalid, it will result in Wrong Answer.

Examples

Input

2 3
1 2 3
0 1 1


Output

3
2 2 2 3
1 1 1 2
1 3 1 2


Input

3 2
1 0
2 1
1 0


Output

3
1 1 1 2
1 2 2 2
3 1 3 2


Input

1 5
9 9 9 9 9


Output

2
1 1 1 2
1 3 1 4

Solution (in JAVA):

Solution:
import java.util.ArrayList;
import java.util.List;
import java.util.Scanner;

public class Main {

	public static void main(String[] args) {
		Scanner scanner = new Scanner(System.in);
		int h = scanner.nextInt();
		int w = scanner.nextInt();
		int[][] matrix = new int[h][w];
		int odd = 0;
		for (int j = 0; j < h; j++) {
			for (int i = 0; i < w; i++) {
				int c = scanner.nextInt();
				matrix[j][i] = c;
				if (c % 2 == 1) {
					odd++;
				}
			}
		}
		int i = 0;
		int j = 0;
		int previ = 0;
		int prevj = 0;
		List<String> opeList = new ArrayList<String>();
		boolean isOpe = false;
		while (1 < odd) {
			int curVal = matrix[j][i];
			boolean isOdd = curVal % 2 == 1;

			// OPERATION
			if (isOpe && isOdd) {
				opeList.add((prevj+1) + " " + (previ+1) + " " + (j+1) + " " + (i+1));
				isOpe = false;
				odd -= 2;
			} else if (isOpe && !isOdd) {
				opeList.add((prevj+1) + " " + (previ+1) + " " + (j+1) + " " + (i+1));
			} else if (!isOpe && isOdd) {
				isOpe = true;
			}

			// MOVE
			previ = i;
			prevj = j;
			boolean moveRight = j % 2 == 0;
			if (moveRight) {
				if (i == w - 1) {
					j++;
				} else {
					i++;
				}
			} else {
				if (i == 0) {
					j++;
				} else {
					i--;
				}
			}
		}

		System.out.println(opeList.size());
		for (String ope : opeList) {
			System.out.println(ope);
		}
	}
}