Problem: There is a grid of square cells with H horizontal rows and W vertical columns. The cell at the i-th row and the j-th column will be denoted as Cell (i, j).

In Cell (i, j), a_{ij} coins are placed.

You can perform the following operation any number of times:

Operation: Choose a cell that was not chosen before and contains one or more coins, then move one of those coins to a vertically or horizontally adjacent cell.

Maximize the number of cells containing an even number of coins.

Constraints

* All values in input are integers.
* 1 \leq H, W \leq 500
* 0 \leq a_{ij} \leq 9

Input

Input is given from Standard Input in the following format:


H W
a_{11} a_{12} ... a_{1W}
a_{21} a_{22} ... a_{2W}
:
a_{H1} a_{H2} ... a_{HW}


Output

Print a sequence of operations that maximizes the number of cells containing an even number of coins, in the following format:


N
y_1 x_1 y_1' x_1'
y_2 x_2 y_2' x_2'
:
y_N x_N y_N' x_N'


That is, in the first line, print an integer N between 0 and H \times W (inclusive), representing the number of operations.

In the (i+1)-th line (1 \leq i \leq N), print four integers y_i, x_i, y_i' and x_i' (1 \leq y_i, y_i' \leq H and 1 \leq x_i, x_i' \leq W), representing the i-th operation. These four integers represents the operation of moving one of the coins placed in Cell (y_i, x_i) to a vertically or horizontally adjacent cell, (y_i', x_i').

Note that if the specified operation violates the specification in the problem statement or the output format is invalid, it will result in Wrong Answer.

Examples

Input

2 3
1 2 3
0 1 1


Output

3
2 2 2 3
1 1 1 2
1 3 1 2


Input

3 2
1 0
2 1
1 0


Output

3
1 1 1 2
1 2 2 2
3 1 3 2


Input

1 5
9 9 9 9 9


Output

2
1 1 1 2
1 3 1 4

Solution (in JAVA):

Solution:
import java.util.ArrayList;
import java.util.PriorityQueue;
import java.util.Scanner;

class Main {
    public static void main(String args[]) {
        Scanner sc = new Scanner(System.in);
        int H = sc.nextInt();
        int W = sc.nextInt();
        int[][] board = new int[H][W];
        for (int i = 0; i < H; i++) {
            for (int j = 0; j < W; j++) {
                board[i][j] = sc.nextInt();
            }
        }
        ArrayList<String> ans = new ArrayList<String>();
        for (int i = 0; i < H; i++) {
            for (int j = 0; j < W - 1; j++) {
                right(i, j, board, ans);
            }
            if (++i < H) {
                down(i - 1, W - 1, board, ans);
                for (int j = W - 1; j > 0; --j) {
                    left(i, j, board, ans);
                }
                if (i + 1 < H) {
                    down(i, 0, board, ans);
                }
            }
        }
        System.out.println(ans.size());
        for (String str : ans) {
            System.out.println(str);
        }
    }

    static void right(int i, int j, int[][] board, ArrayList<String> ans) {
        if (board[i][j] % 2 != 0) {
            board[i][j + 1]++;
            ans.add((i + 1) + " " + (j + 1) + " " + (i + 1) + " " + (j + 2));
        }
    }

    static void left(int i, int j, int[][] board, ArrayList<String> ans) {
        if (board[i][j] % 2 != 0) {
            board[i][j - 1]++;
            ans.add((i + 1) + " " + (j + 1) + " " + (i + 1) + " " + (j));
        }
    }

    static void down(int i, int j, int[][] board, ArrayList<String> ans) {
        if (board[i][j] % 2 != 0) {
            board[i + 1][j]++;
            ans.add((i + 1) + " " + (j + 1) + " " + (i + 2) + " " + (j + 1));
        }
    }
}