Problem: You are given three positive (i.e. strictly greater than zero) integers x, y and z.

Your task is to find positive integers a, b and c such that x = max(a, b), y = max(a, c) and z = max(b, c), or determine that it is impossible to find such a, b and c.

You have to answer t independent test cases. Print required a, b and c in any (arbitrary) order.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers x, y, and z (1 ≤ x, y, z ≤ 10^9).

Output

For each test case, print the answer:

  * "NO" in the only line of the output if a solution doesn't exist; 
  * or "YES" in the first line and any valid triple of positive integers a, b and c (1 ≤ a, b, c ≤ 10^9) in the second line. You can print a, b and c in any order. 

Example

Input


5
3 2 3
100 100 100
50 49 49
10 30 20
1 1000000000 1000000000


Output


YES
3 2 1
YES
100 100 100
NO
NO
YES
1 1 1000000000

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
long long findbits(long long n) {
  int i;
  for (i = 0;; i++) {
    if (pow(2, i) > n) return i - 1;
  }
}
long long b2d(string s) {
  long long deci = 0;
  string n = s;
  long long len = n.length();
  for (long long i = len - 1; i >= 0; i--) {
    if (n[i] == '1') {
      deci = deci + pow(2, (len - 1 - i));
    }
  }
  return deci;
}
bool isprime(long long n) {
  for (long long i = 2; i * i <= n; i++) {
    if (n % i == 0) return false;
  }
  return true;
}
float pi = 3.1415926535;
int main() {
  ios_base::sync_with_stdio(false);
  cin.tie(NULL);
  cout.tie(NULL);
  long long t = 1;
  cin >> t;
  while (t--) {
    long long maxi, x, y, z;
    cin >> x >> y >> z;
    maxi = max(x, max(z, y));
    if ((maxi == z && maxi == y) || (maxi == z && maxi == x) ||
        (maxi == x && maxi == y)) {
      cout << "YES" << endl;
      if (x == y)
        cout << maxi << " " << z << " " << z << endl;
      else if (x > y)
        cout << maxi << " " << y << " " << y << " " << endl;
      else if (y > x)
        cout << maxi << " " << x << " " << x << endl;
    } else
      cout << "NO" << endl;
  }
  return 0;
}