Problem: You are given three positive (i.e. strictly greater than zero) integers x, y and z.

Your task is to find positive integers a, b and c such that x = max(a, b), y = max(a, c) and z = max(b, c), or determine that it is impossible to find such a, b and c.

You have to answer t independent test cases. Print required a, b and c in any (arbitrary) order.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers x, y, and z (1 ≤ x, y, z ≤ 10^9).

Output

For each test case, print the answer:

  * "NO" in the only line of the output if a solution doesn't exist; 
  * or "YES" in the first line and any valid triple of positive integers a, b and c (1 ≤ a, b, c ≤ 10^9) in the second line. You can print a, b and c in any order. 

Example

Input


5
3 2 3
100 100 100
50 49 49
10 30 20
1 1000000000 1000000000


Output


YES
3 2 1
YES
100 100 100
NO
NO
YES
1 1 1000000000

Solution (in JAVA):

Solution:
import java.util.HashMap;
import java.util.Scanner;
import java.util.Set;

public class Main {
	public static void main(String[] args) {

		Scanner scn = new Scanner(System.in);
		int t = scn.nextInt();
		while (t > 0) {
			HashMap<Integer, Integer> hp = new HashMap<>();
			int item = 0;
			for (int i = 1; i <= 3; i++) {
				item = scn.nextInt();
				if (hp.containsKey(item))
					hp.put(item, hp.get(item) + 1);
				else
					hp.put(item, 1);
			}
			if (hp.size() == 3)
				System.out.println("NO");
			else if (hp.size() == 1) {
				System.out.println("YES");
				System.out.println(item + " " + item + " " + item);
			} else {
				Set<Integer> keys = hp.keySet();
				int i = 1, x = 0, y = 0;
				for (int val : keys) {
					if (i == 1)
						x = val;
					else
						y = val;
					i++;
				}
				if (hp.get(x) > hp.get(y) && x >= y) {
					System.out.println("YES");
					System.out.println(x + " " + y + " " + 1);
				} else if (hp.get(x) < hp.get(y) && y >= x) {
					System.out.println("YES");
					System.out.println(x + " " + y + " " + 1);
				} else {
					System.out.println("NO");
				}
			}
			t--;
		}
	}
}