Problem: Ashish has n elements arranged in a line. 

These elements are represented by two integers a_i — the value of the element and b_i — the type of the element (there are only two possible types: 0 and 1). He wants to sort the elements in non-decreasing values of a_i.

He can perform the following operation any number of times: 

  * Select any two elements i and j such that b_i ≠ b_j and swap them. That is, he can only swap two elements of different types in one move. 



Tell him if he can sort the elements in non-decreasing values of a_i after performing any number of operations.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. The description of the test cases follows.

The first line of each test case contains one integer n (1 ≤ n ≤ 500) — the size of the arrays.

The second line contains n integers a_i (1 ≤ a_i ≤ 10^5) — the value of the i-th element.

The third line containts n integers b_i (b_i ∈ \{0, 1\}) — the type of the i-th element.

Output

For each test case, print "Yes" or "No" (without quotes) depending on whether it is possible to sort elements in non-decreasing order of their value.

You may print each letter in any case (upper or lower).

Example

Input


5
4
10 20 20 30
0 1 0 1
3
3 1 2
0 1 1
4
2 2 4 8
1 1 1 1
3
5 15 4
0 0 0
4
20 10 100 50
1 0 0 1


Output


Yes
Yes
Yes
No
Yes

Note

For the first case: The elements are already in sorted order.

For the second case: Ashish may first swap elements at positions 1 and 2, then swap elements at positions 2 and 3.

For the third case: The elements are already in sorted order.

For the fourth case: No swap operations may be performed as there is no pair of elements i and j such that b_i ≠ b_j. The elements cannot be sorted.

For the fifth case: Ashish may swap elements at positions 3 and 4, then elements at positions 1 and 2.

Solution (in PYTHON3):

Solution:
######################################################
############Created by Devesh Kumar###################
#############devesh1102@gmail.com####################
##########For CodeForces(Devesh1102)#################
#####################2020#############################
######################################################
import sys
input = sys.stdin.readline
 #qn given an arr of size n for every  i position find a min j such that j>i and arr[j]>arr[i]
#it prints the position of the nearest .
# import sys
import heapq 
import copy
import math
#heapq.heapify(li) 
#
#heapq.heappush(li,4) 
#
#heapq.heappop(li)
#
# &	Bitwise AND Operator	10 & 7 = 2
# |	Bitwise OR Operator	10 | 7 = 15
# ^	Bitwise XOR Operator	10 ^ 7 = 13

# <<	Bitwise Left Shift operator	10<<2 = 40
# >>	Bitwise Right Shift Operator
'''############ ---- Input Functions ---- #######Start#####'''
def inp():
	return(int(input()))
def inlt(): 
	return(list(map(int,input().split())))
def insr():
	s = input()
	return(list(s[:len(s) - 1]))
def invr():
	return(map(int,input().split()))
 ############ ---- Input Functions ---- #######End
 # #####   

class Node:
    def _init_(self,val):
        self.data = val
        self.left = None
        self.right = None
##to initialize wire : object_name= node(val)##to create a new node
## can also be used to create linked list


def pre_sum(arr):
	#"""returns the prefix sum inclusive ie ith position in ans  represent sum from 0 to ith position"""
	p = [0]
	for i in arr:
		p.append(p[-1] + i)
	p.pop(0)
	return p

def pre_back(arr):
	#"""returns the prefix sum inclusive ie ith position in ans  represent sum from 0 to ith position"""
	p = [0]
	for i in arr:
		p.append(p[-1] + i)
	p.pop(0)
	return p
def bin_search(arr,l,r,val):#strickly greater
	if arr[r] <= val:
		return r+1	
	if r-l < 2:
		if arr[l]>val:
			return l
		else:
			return r
	mid = int((l+r)/2)
	if arr[mid] <= val:
		return bin_search(arr,mid,r,val)
	else:
		return bin_search(arr,l,mid,val)
def search_leftmost(arr,val):
	def helper(arr,l,r,val):
		# print(arr)
		print(l,r)
		if arr[l] == val:
			return l
		if r -l <=1:
			if arr[r] == val:
				return r
			else:
				print("not found")
				return
		mid = int((r+l)/2)
		if arr[mid] >= val:
			return helper(arr,l,mid,val)
		else:
			return helper(arr,mid,r,val)
	return helper(arr,0,len(arr)-1,val)
def search_rightmost(arr,val):
	def helper(arr,l,r,val):
		# print(arr)
		print(l,r)
		if arr[r] == val:
			return r
		if r -l <=1:
			if arr[l] == val:
				return r
			else:
				print("not found")
				return
		mid = int((r+l)/2)
		if arr[mid] > val:
			return helper(arr,l,mid,val)
		else:
			return helper(arr,mid,r,val)
	return helper(arr,0,len(arr)-1,val)


def pr_list(a):
	print(*a, sep=" ")
def main():
	tests =  inp()
	# tests = 1
	mod = 1000000007

	limit = 10**18
	for test in range(tests):
		n = inp()
		a = inlt()
		b = inlt()
		if sum(b) != n and  sum(b) != 0:
			print("Yes")
		else:
			flag = 0
			for i in range(1,n):
				if a[i] < a[i-1]:
					flag = 1
					break
			if flag == 1:
				print("No")
			else:
				print("Yes")







		# print(x_values)
		
		# for i in range(x):
		# 	if int(x_values[i])!=1:
		# 		n_new = i+1 + (n-i-1)*int(x_values[i])
		# 		n = n_new%mod
		# print(n)
				
			
		




if __name__== "__main__":
  main()