Problem: One very experienced problem writer decided to prepare a problem for April Fools Day contest. The task was very simple - given an arithmetic expression, return the result of evaluating this expression. However, looks like there is a bug in the reference solution...

Input

The only line of input data contains the arithmetic expression. The expression will contain between 2 and 10 operands, separated with arithmetic signs plus and/or minus. Each operand will be an integer between 0 and 255, inclusive.

Output

Reproduce the output of the reference solution, including the bug.

Examples

Input

8-7+6-5+4-3+2-1-0


Output

4


Input

2+2


Output

-46


Input

112-37


Output

375

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
int main() {
  char s[1024];
  scanf("%s", s);
  int n = 0, a = 0;
  char* t = s + 0;
  n = (int)t[0] - '0';
  ++t;
  while (*t != 0 && *t != '+' && *t != '-') n = n * 10 + *t++ - '0';
  for (int i = 0; s[i]; ++i) {
    if (s[i] == '+') {
      t = s + i;
      a = (int)*t - '0';
      ++t;
      while (*t != 0 && *t != '+' && *t != '-') a = a * 10 + *t++ - '0';
      n += a;
    } else if (s[i] == '-') {
      t = s + i;
      a = (int)*t - '0';
      ++t;
      while (*t != 0 && *t != '+' && *t != '-') a = a * 10 + *t++ - '0';
      n -= a;
    }
  }
  printf("%d\n", n);
  return 0;
}