Problem: You are given three positive (i.e. strictly greater than zero) integers x, y and z.

Your task is to find positive integers a, b and c such that x = max(a, b), y = max(a, c) and z = max(b, c), or determine that it is impossible to find such a, b and c.

You have to answer t independent test cases. Print required a, b and c in any (arbitrary) order.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers x, y, and z (1 ≤ x, y, z ≤ 10^9).

Output

For each test case, print the answer:

  * "NO" in the only line of the output if a solution doesn't exist; 
  * or "YES" in the first line and any valid triple of positive integers a, b and c (1 ≤ a, b, c ≤ 10^9) in the second line. You can print a, b and c in any order. 

Example

Input


5
3 2 3
100 100 100
50 49 49
10 30 20
1 1000000000 1000000000


Output


YES
3 2 1
YES
100 100 100
NO
NO
YES
1 1 1000000000

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.*;
public class Coin{
    public static void main(String[] args) throws IOException {
        BufferedReader br=new BufferedReader(new InputStreamReader(System.in));

        int t=Integer.parseInt(br.readLine());
 while(t-->0) {
String[] str= br.readLine().split(" ");
	 	long x=Long.parseLong(str[0]);
	  long y=Long.parseLong(str[1]);
	  long z=Long.parseLong(str[2]);
	  
 long max=Integer.MIN_VALUE;
	  
	  max=Math.max(x, y);
	  max=Math.max(max, z);
	  
	  if(x==y && y==z) {
		  
		  System.out.println("YES");
		  System.out.println(x+" "+y+" "+z);
		  
	  }
	  else if(x==y && z<y) {   // a is max
		  System.out.println("YES");
		 
		  System.out.println(max+" "+z+" "+z);

		  
	  }
	  else if(y==z && x<y) {
		  
		  System.out.println("YES");
			 
		  System.out.println(max+" "+x+" "+x);

		  
	  }
	  else if(x==z && y<x) {
		  
		  System.out.println("YES");
			 
		  System.out.println(max+" "+y+" "+y);

		  
		  
	  }
	  else {
		  
		  System.out.println("NO");
	  }
  }

        
        
        
    }
}