Problem: You are given three positive (i.e. strictly greater than zero) integers x, y and z.

Your task is to find positive integers a, b and c such that x = max(a, b), y = max(a, c) and z = max(b, c), or determine that it is impossible to find such a, b and c.

You have to answer t independent test cases. Print required a, b and c in any (arbitrary) order.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers x, y, and z (1 ≤ x, y, z ≤ 10^9).

Output

For each test case, print the answer:

  * "NO" in the only line of the output if a solution doesn't exist; 
  * or "YES" in the first line and any valid triple of positive integers a, b and c (1 ≤ a, b, c ≤ 10^9) in the second line. You can print a, b and c in any order. 

Example

Input


5
3 2 3
100 100 100
50 49 49
10 30 20
1 1000000000 1000000000


Output


YES
3 2 1
YES
100 100 100
NO
NO
YES
1 1 1000000000

Solution (in PYTHON3):

Solution:
from sys import stdin, stdout


def input(): return stdin.readline().strip()
x, y, z = 0, 0, 0
us, us1, us2, us3 = True, True, True, True

def solve():
    x, y, z = map(int, input().split())
    us = x == y and y == z 
    if us: 
        print("YES")
        print(f"{x} {x} {x}")
        return 0
    us1 = x < y and y == z
    us2 = y < x and x == z
    us3 = z < x and x == y
    if us1 or us2 or us3:
        print("YES")
        # 1 2 2
        if x < y:
            print(f"{x} {x} {y}")
        # 2 1 2
        elif y < x:
            print(f"{y} {x} {y}")
        # 2 2 1
        else:
            print(f"{x} {z} {z}")
    else:
        print("NO")







if __name__ == '__main__':
    t = int(input())
    for _ in range(t):
       solve()