Problem: You are given three positive (i.e. strictly greater than zero) integers x, y and z.

Your task is to find positive integers a, b and c such that x = max(a, b), y = max(a, c) and z = max(b, c), or determine that it is impossible to find such a, b and c.

You have to answer t independent test cases. Print required a, b and c in any (arbitrary) order.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers x, y, and z (1 ≤ x, y, z ≤ 10^9).

Output

For each test case, print the answer:

  * "NO" in the only line of the output if a solution doesn't exist; 
  * or "YES" in the first line and any valid triple of positive integers a, b and c (1 ≤ a, b, c ≤ 10^9) in the second line. You can print a, b and c in any order. 

Example

Input


5
3 2 3
100 100 100
50 49 49
10 30 20
1 1000000000 1000000000


Output


YES
3 2 1
YES
100 100 100
NO
NO
YES
1 1 1000000000

Solution (in JAVA):

Solution:
import java.util.*;

public class HelloWorld{

     public static void main(String []args){
        Scanner scn = new Scanner(System.in);
        int T = scn.nextInt();
        while(T-->0){
            int x = scn.nextInt();
            int y = scn.nextInt();
            int z = scn.nextInt();
           
           int a,b,c;
           if(x==y && x==z){
              a=b=c=x;
              System.out.println("YES");
                System.out.println(a+" "+b+" "+c);
           }else if(x==y && x>z){
               a=x;
               b=z;
               c=Math.min(a-b,b);
                System.out.println("YES");
                 System.out.println(a+" "+b+" "+c);
           }else if(x==z && x>y){
               b=x;
               a=y;
               c=Math.min(b-a,a);
                System.out.println("YES");
                System.out.println(a+" "+b+" "+c);
           }else if(y==z && y>x){
                c=y;
                a=x;
                b=Math.min(c-a,a);
                System.out.println("YES");
                System.out.println(a+" "+b+" "+c); 
               
           }else{
               System.out.println("NO");
           }
            
        }
     }
}