Problem: You are given three positive (i.e. strictly greater than zero) integers x, y and z.

Your task is to find positive integers a, b and c such that x = max(a, b), y = max(a, c) and z = max(b, c), or determine that it is impossible to find such a, b and c.

You have to answer t independent test cases. Print required a, b and c in any (arbitrary) order.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers x, y, and z (1 ≤ x, y, z ≤ 10^9).

Output

For each test case, print the answer:

  * "NO" in the only line of the output if a solution doesn't exist; 
  * or "YES" in the first line and any valid triple of positive integers a, b and c (1 ≤ a, b, c ≤ 10^9) in the second line. You can print a, b and c in any order. 

Example

Input


5
3 2 3
100 100 100
50 49 49
10 30 20
1 1000000000 1000000000


Output


YES
3 2 1
YES
100 100 100
NO
NO
YES
1 1 1000000000

Solution (in JAVA):

Solution:

import java.util.*;
import java.lang.*;
import java.io.*;

public class Main {
    public static void main(String[] args) {

        Scanner scan = new Scanner(System.in);
        int n = scan.nextInt();
        for (int i=0;i<n;i++){
            int x = scan.nextInt();
            int y = scan.nextInt();
            int z = scan.nextInt();
            int a,b,c;
            if(x == y && y==z){
                System.out.println("YES");
                System.out.println(x+" "+y+" "+z);
            }
            else if(x == y){
                a = x;
                if(z>a){
                    System.out.println("NO");
                }
                else{
                    System.out.println("YES");
                    c=1;
                    System.out.println(a+" "+z+" "+c);
                }
            }
            else if(y == z){
                if(x > y){
                    System.out.println("NO");
                }
                else{
                    System.out.println("YES");
                    a=1;
                    System.out.println(x+" "+a+" "+y);
                }
            }
            else if(x == z){
                if(y > z){
                    System.out.println("NO");
                }
                else{
                    b=1;
                    System.out.println("YES");
                    System.out.println(y+" "+x+" "+b);
                }
            }
            else{
                System.out.println("NO");
            }

        }
    }






}