Problem: There is a grid of square cells with H horizontal rows and W vertical columns. The cell at the i-th row and the j-th column will be denoted as Cell (i, j).

In Cell (i, j), a_{ij} coins are placed.

You can perform the following operation any number of times:

Operation: Choose a cell that was not chosen before and contains one or more coins, then move one of those coins to a vertically or horizontally adjacent cell.

Maximize the number of cells containing an even number of coins.

Constraints

* All values in input are integers.
* 1 \leq H, W \leq 500
* 0 \leq a_{ij} \leq 9

Input

Input is given from Standard Input in the following format:


H W
a_{11} a_{12} ... a_{1W}
a_{21} a_{22} ... a_{2W}
:
a_{H1} a_{H2} ... a_{HW}


Output

Print a sequence of operations that maximizes the number of cells containing an even number of coins, in the following format:


N
y_1 x_1 y_1' x_1'
y_2 x_2 y_2' x_2'
:
y_N x_N y_N' x_N'


That is, in the first line, print an integer N between 0 and H \times W (inclusive), representing the number of operations.

In the (i+1)-th line (1 \leq i \leq N), print four integers y_i, x_i, y_i' and x_i' (1 \leq y_i, y_i' \leq H and 1 \leq x_i, x_i' \leq W), representing the i-th operation. These four integers represents the operation of moving one of the coins placed in Cell (y_i, x_i) to a vertically or horizontally adjacent cell, (y_i', x_i').

Note that if the specified operation violates the specification in the problem statement or the output format is invalid, it will result in Wrong Answer.

Examples

Input

2 3
1 2 3
0 1 1


Output

3
2 2 2 3
1 1 1 2
1 3 1 2


Input

3 2
1 0
2 1
1 0


Output

3
1 1 1 2
1 2 2 2
3 1 3 2


Input

1 5
9 9 9 9 9


Output

2
1 1 1 2
1 3 1 4

Solution (in JAVA):

Solution:
import java.util.*;

class Main {
    public static void main(String... args) {
        int H = IN.nextInt();
		int W = IN.nextInt();
		int[][] G = new int[H][W + 1];
		for (int i = 0; i < H; i++) {
			for (int j = 0; j < W; j++) {
				G[i][j] = IN.nextInt() % 2;
			}
		}
	//	puts(Arrays.deepToString(G));
		List<int[]> log = new ArrayList<>();
        for (int i = 0; i < H - 1; i++) {
			for (int j = 0; j < W; j++) {
                if (G[i][j] == 1) {
					if (G[i][j + 1] == 1) {
						G[i][j + 1] = 0;
						log.add(createL(i, j, i, j + 1));
					} else {
						if (G[i + 1][j] == 1) {
						    G[i + 1][j] = 0;
					    } else {
						    G[i + 1][j] = 1;
						}
					    log.add(createL(i, j, i + 1, j));
					}
				}
			}
		}
		for (int j = 0; j < W - 1; j++) {
			if (G[H - 1][j] == 1) {
				if (G[H - 1][j + 1] == 1) {
					G[H - 1][j + 1] = 0;
				} else {
					G[H - 1][j + 1] = 1;
				}
				log.add(createL(H - 1, j, H - 1, j + 1));
			}
		}
        puts(log.size());
		for (int[] x: log) {
			puts(join(x, " "));
		}

	}
    static int[] createL(int a, int b, int c, int d) {
		int[] x = {a + 1, b + 1, c + 1, d + 1};
		return x;
	}


	static String join(int[] a, String s) {
		StringBuilder v = new StringBuilder();
		for (int i = 0; i < a.length - 1; i ++) {
			v.append(a[i]);
			v.append(s);
		}
		return v.append(a[a.length - 1]).toString();
	}
    static final Scanner IN = new Scanner(System.in);
    static <T> void puts(T arg) { System.out.println(arg); }
}