Problem: You are given three positive (i.e. strictly greater than zero) integers x, y and z.

Your task is to find positive integers a, b and c such that x = max(a, b), y = max(a, c) and z = max(b, c), or determine that it is impossible to find such a, b and c.

You have to answer t independent test cases. Print required a, b and c in any (arbitrary) order.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers x, y, and z (1 ≤ x, y, z ≤ 10^9).

Output

For each test case, print the answer:

  * "NO" in the only line of the output if a solution doesn't exist; 
  * or "YES" in the first line and any valid triple of positive integers a, b and c (1 ≤ a, b, c ≤ 10^9) in the second line. You can print a, b and c in any order. 

Example

Input


5
3 2 3
100 100 100
50 49 49
10 30 20
1 1000000000 1000000000


Output


YES
3 2 1
YES
100 100 100
NO
NO
YES
1 1 1000000000

Solution (in PYTHON3):

Solution:
for _ in range(int(input())):
    x, y, z = map(int, input().split())
    a, b, c = 0,0,0
    if(x == y):
        a = x
    if(x != y):
        b = x
        c = y
    if(x == z):
        b = x
    if(x != z):
        a = x
        c = z
    if(y == z):
        c = y
    if(y != z):
        a = y
        b = z
    f = 0
    if(max(a, b) == x and max(a, c) == y and max(b, c) == z):
        f = 1
    elif(max(a, c) == x and max(a, b) == y and max(b, c) == z):
        f = 1
    elif(max(b, a) == x and max(b, c) == y and max(a, c) == z):
        f = 1
    elif(max(b, c) == x and max(b, a) == y and max(a, c) == z):
        f = 1
    elif(max(c, a) == x and max(b, c) == y and max(a, b) == z):
        f = 1
    elif(max(c, b) == x and max(c, a) == y and max(a, b) == z):
        f = 1
    if(f):
        print("YES")
        print(a, b, c)
    else:
        print("NO")