Problem: Phoenix has collected n pieces of gold, and he wants to weigh them together so he can feel rich. The i-th piece of gold has weight w_i. All weights are distinct. He will put his n pieces of gold on a weight scale, one piece at a time. 

The scale has an unusual defect: if the total weight on it is exactly x, it will explode. Can he put all n gold pieces onto the scale in some order, without the scale exploding during the process? If so, help him find some possible order. 

Formally, rearrange the array w so that for each i (1 ≤ i ≤ n), ∑_{j = 1}^{i}w_j ≠ x.

Input

The input consists of multiple test cases. The first line contains an integer t (1 ≤ t ≤ 1000) — the number of test cases.

The first line of each test case contains two integers n and x (1 ≤ n ≤ 100; 1 ≤ x ≤ 10^4) — the number of gold pieces that Phoenix has and the weight to avoid, respectively. 

The second line of each test case contains n space-separated integers (1 ≤ w_i ≤ 100) — the weights of the gold pieces. It is guaranteed that the weights are pairwise distinct.

Output

For each test case, if Phoenix cannot place all n pieces without the scale exploding, print NO. Otherwise, print YES followed by the rearranged array w. If there are multiple solutions, print any.

Example

Input


3
3 2
3 2 1
5 3
1 2 3 4 8
1 5
5


Output


YES
3 2 1
YES
8 1 2 3 4
NO

Note

In the first test case, Phoenix puts the gold piece with weight 3 on the scale first, then the piece with weight 2, and finally the piece with weight 1. The total weight on the scale is 3, then 5, then 6. The scale does not explode because the total weight on the scale is never 2.

In the second test case, the total weight on the scale is 8, 9, 11, 14, then 18. It is never 3.

In the third test case, Phoenix must put the gold piece with weight 5 on the scale, and the scale will always explode.

Solution (in JAVA):

Solution:
//package com.company;

import java.awt.image.AreaAveragingScaleFilter;
import java.io.*;
import java.math.BigInteger;
import java.text.DecimalFormat;
import java.util.*;

public class Main
{
    public static void main(String[] args) throws IOException {
        OutputStream outputStream = System.out;
        FastReader in = new FastReader();
        PrintWriter out = new PrintWriter(outputStream);
        PROBLEM solver = new PROBLEM();
        int t=1;
        t = in.nextInt();
        for(int i=0;i<t;i++){
            solver.solve(in, out);
        }
        out.close();
    }

    static class PROBLEM
    {
        public void solve(FastReader in,PrintWriter out) {

            int n = in.nextInt(), x = in.nextInt();
            int[] w = new int[n];
            int sum = 0, flag = 0;
            for (int i = 0; i < n; i++) {
                w[i] = in.nextInt();
                sum += w[i];
                if(w[i] > x) flag = 1;
            }

            if(sum == x) out.println("NO");
            else{
                w = mergeSort(w);
                if(flag == 1){
                    out.println("YES");
                    for (int i = n-1; i >= 0; i--) {
                        out.print(w[i] + " ");
                    }
                    out.println();
                }else{
                    int chk = 0;
                    for (int i = n-1; i >= 0 ; i--) {
                        chk += w[i];
                        if(chk == x){
                            int temp = w[i];
                            w[i] = w[i-1];
                            w[i-1] = temp;
                            break;
                        }
                    }

                    out.println("YES");
                    for (int i = n-1; i >= 0; i--) {
                        out.print(w[i] + " ");
                    }
                    out.println();
                }
            }



        }
    }

    static int power(int x, long y, int p)
    {
        int res = 1; // Initialize result

        x = x % p; // Update x if it is more than or
        // equal to p

        if (x == 0)
            return 0; // In case x is divisible by p;

        while (y > 0)
        {

            // If y is odd, multiply x with result
            if ((y & 1) != 0)
                res = (res * x) % p;

            // y must be even now
            y = y >> 1; // y = y/2
            x = (x * x) % p;
        }
        return res;
    }

    public static class Pair<U extends Comparable<U>, V extends Comparable<V>> implements Comparable<Pair<U, V>> {
        public U x;
        public V y;

        public Pair(U x, V y) {
            this.x = x;
            this.y = y;
        }

        public int hashCode() {
            return (x == null ? 0 : x.hashCode() * 31) + (y == null ? 0 : y.hashCode());
        }

        public boolean equals(Object o) {
            if (this == o)
                return true;
            if (o == null || getClass() != o.getClass())
                return false;
            Pair<U, V> p = (Pair<U, V>) o;
            return (x == null ? p.x == null : x.equals(p.x)) && (y == null ? p.y == null : y.equals(p.y));
        }

        public int compareTo(Pair<U, V> b) {
            int cmpU = x.compareTo(b.x);
            return cmpU != 0 ? cmpU : y.compareTo(b.y);
        }

        public String toString() {
            return String.format("(%s, %s)", x.toString(), y.toString());
        }

    }

    static class FastReader {
        BufferedReader br;
        StringTokenizer st;

        public FastReader() {
            br = new BufferedReader(new InputStreamReader(System.in));
        }

        String next() {
            while (st == null || !st.hasMoreElements()) {
                try {
                    st = new StringTokenizer(br.readLine());
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
            return st.nextToken();
        }

        int nextInt() {
            return Integer.parseInt(next());
        }

        long nextLong() {
            return Long.parseLong(next());
        }

        double nextDouble() {
            return Double.parseDouble(next());
        }

        char nextChar() {
            return next().charAt(0);
        }

        boolean nextBoolean() {
            return !(nextInt() == 0);
        }
        // boolean nextBoolean(){return Boolean.parseBoolean(next());}

        String nextLine() {
            String str = "";
            try {
                str = br.readLine();
            } catch (IOException e) {
                e.printStackTrace();
            }
            return str;
        }

    }

    //private static long binaryExpo(long )

    private static int[] mergeSort(int[] array){

        if(array.length <= 1){
            return array;
        }

        int midpoint = array.length / 2;

        int[] left = new int[midpoint];
        int[] right;

        if(array.length % 2 == 0){
            right = new int[midpoint];
        }else{
            right = new int[midpoint + 1];
        }

        for (int i = 0; i < left.length; i++) {
            left[i] = array[i];
        }

        for (int i = 0; i < right.length; i++) {
            right[i] = array[i + midpoint];
        }

        int[] result = new int[array.length];

        left = mergeSort(left);
        right = mergeSort(right);

        result = merge(left, right);

        return result;
    }

    private static int[] merge(int[] left, int[] right){

        int[] result = new int[left.length + right.length];
        int leftPointer = 0, rightPointer = 0, resultPointer = 0;

        while(leftPointer < left.length || rightPointer < right.length){

            if(leftPointer < left.length && rightPointer < right.length){

                if(left[leftPointer] < right[rightPointer]){
                    result[resultPointer++] = left[leftPointer++];
                }else{
                    result[resultPointer++] = right[rightPointer++];
                }
            }else if(leftPointer < left.length){
                result[resultPointer++] = left[leftPointer++];
            }else{
                result[resultPointer++] = right[rightPointer++];
            }
        }
        return result;
    }
}