Problem: You are given three positive (i.e. strictly greater than zero) integers x, y and z.

Your task is to find positive integers a, b and c such that x = max(a, b), y = max(a, c) and z = max(b, c), or determine that it is impossible to find such a, b and c.

You have to answer t independent test cases. Print required a, b and c in any (arbitrary) order.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers x, y, and z (1 ≤ x, y, z ≤ 10^9).

Output

For each test case, print the answer:

  * "NO" in the only line of the output if a solution doesn't exist; 
  * or "YES" in the first line and any valid triple of positive integers a, b and c (1 ≤ a, b, c ≤ 10^9) in the second line. You can print a, b and c in any order. 

Example

Input


5
3 2 3
100 100 100
50 49 49
10 30 20
1 1000000000 1000000000


Output


YES
3 2 1
YES
100 100 100
NO
NO
YES
1 1 1000000000

Solution (in JAVA):

Solution:
import java.util.*;
public class Solution{
    public static void main(String [] args){
        Scanner sc = new Scanner(System.in);
        int t = sc.nextInt();
        for(int z=0;z<t;z++){
            int dist=1,v1=0,v2=0;
            ArrayList<Integer> a = new ArrayList<Integer>();
            ArrayList<Integer> d = new ArrayList<Integer>();
            a.add(sc.nextInt());
            d.add(a.get(0));
            for(int i=0;i<2;i++){
                int v = sc.nextInt();
                if(!d.contains(v)){
                    dist++;
                    d.add(v);
                }
                a.add(v);
            }
            if(dist == 1){
                System.out.println("YES");
                System.out.println(a.get(0)+" "+a.get(0)+" "+a.get(0));
            }
            else if(dist == 2){
                int max = Collections.max(d);
                int min = Collections.min(d);
                if(Collections.frequency(a,max)>Collections.frequency(a,min)){
                    System.out.println("YES");
                    System.out.println(d.get(0)+" "+d.get(1)+" 1");
                }
                else
                    System.out.println("NO");
            }
            else
                System.out.println("NO");
        }
    }
}