Problem: You are given three positive (i.e. strictly greater than zero) integers x, y and z.

Your task is to find positive integers a, b and c such that x = max(a, b), y = max(a, c) and z = max(b, c), or determine that it is impossible to find such a, b and c.

You have to answer t independent test cases. Print required a, b and c in any (arbitrary) order.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers x, y, and z (1 ≤ x, y, z ≤ 10^9).

Output

For each test case, print the answer:

  * "NO" in the only line of the output if a solution doesn't exist; 
  * or "YES" in the first line and any valid triple of positive integers a, b and c (1 ≤ a, b, c ≤ 10^9) in the second line. You can print a, b and c in any order. 

Example

Input


5
3 2 3
100 100 100
50 49 49
10 30 20
1 1000000000 1000000000


Output


YES
3 2 1
YES
100 100 100
NO
NO
YES
1 1 1000000000

Solution (in PYTHON3):

Solution:
def cons_check(a,b,c,lis):
    flag = 0
    if lis[0] == max(a,b):
        flag += 1
    if lis[1] == max(a,c):
        flag += 1
    if lis[2] == max(b,c):
        flag +=1
    return flag           



for test in range(int(input())):
    lis = list(map(int,input().split()))
    """
    val = [0,1,2]
    ini = [0,1,2]
    while True:
        a,b,c = lis[ini[0]],lis[ini[1]],lis[ini[2]]
        if cons_check(a,b,c,lis) == 3:
            print("YES")
            print(a,b,c)
            break
        for i in range(3):    
            if ini[i] < 2:
                ini[i] +=1
            else:
                ini[i] = 0
        if ini == val :
            print("NO")   
            break        """
    c = 0        
    for i in lis:
        for j in lis:
            for k in lis:
                if cons_check(i,j,k,lis) == 3:
                    print("YES")
                    print(i,j,k)
                    c = 1
                    break
            if c == 1:
                break
        if c == 1:
            break
    if c == 0:
        print("NO")