Problem: You are given three positive (i.e. strictly greater than zero) integers x, y and z.

Your task is to find positive integers a, b and c such that x = max(a, b), y = max(a, c) and z = max(b, c), or determine that it is impossible to find such a, b and c.

You have to answer t independent test cases. Print required a, b and c in any (arbitrary) order.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers x, y, and z (1 ≤ x, y, z ≤ 10^9).

Output

For each test case, print the answer:

  * "NO" in the only line of the output if a solution doesn't exist; 
  * or "YES" in the first line and any valid triple of positive integers a, b and c (1 ≤ a, b, c ≤ 10^9) in the second line. You can print a, b and c in any order. 

Example

Input


5
3 2 3
100 100 100
50 49 49
10 30 20
1 1000000000 1000000000


Output


YES
3 2 1
YES
100 100 100
NO
NO
YES
1 1 1000000000

Solution (in JAVA):

Solution:
import java.io.*;
    import java.util.*;
    import java.math.*;
    import java.lang.*;
public class Example
{
    public static void main(String args[])
    {
        Scanner sc=new Scanner(System.in);
         int t=sc.nextInt();
            while(t--!=0)
            {
               int x=sc.nextInt();
               int y=sc.nextInt();
               int z=sc.nextInt();
               if(x==y && y==z && x==z)
               {

                System.out.println("YES");
                System.out.println(x+" "+y+" "+z);
               

               }
               else if(x!=y && y!=z && z!=x)
               {
                System.out.println("NO");
                
               }
               else
               {
               int min=Math.min(y,z);
               min=Math.min(x,min);
               int max=Math.min(y,z);
               max=Math.max(x,max);
               

               if((min==x && min==y) || (min==x && min==z) || (min==z && min==y))
               {
                System.out.println("NO");
                
               }
               else
               {

               System.out.println("YES");
               System.out.println(max+" "+min+" "+min);
               
                }
            }



         
                
              


            }
    }
}