Problem: Ashish has n elements arranged in a line. 

These elements are represented by two integers a_i — the value of the element and b_i — the type of the element (there are only two possible types: 0 and 1). He wants to sort the elements in non-decreasing values of a_i.

He can perform the following operation any number of times: 

  * Select any two elements i and j such that b_i ≠ b_j and swap them. That is, he can only swap two elements of different types in one move. 



Tell him if he can sort the elements in non-decreasing values of a_i after performing any number of operations.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. The description of the test cases follows.

The first line of each test case contains one integer n (1 ≤ n ≤ 500) — the size of the arrays.

The second line contains n integers a_i (1 ≤ a_i ≤ 10^5) — the value of the i-th element.

The third line containts n integers b_i (b_i ∈ \{0, 1\}) — the type of the i-th element.

Output

For each test case, print "Yes" or "No" (without quotes) depending on whether it is possible to sort elements in non-decreasing order of their value.

You may print each letter in any case (upper or lower).

Example

Input


5
4
10 20 20 30
0 1 0 1
3
3 1 2
0 1 1
4
2 2 4 8
1 1 1 1
3
5 15 4
0 0 0
4
20 10 100 50
1 0 0 1


Output


Yes
Yes
Yes
No
Yes

Note

For the first case: The elements are already in sorted order.

For the second case: Ashish may first swap elements at positions 1 and 2, then swap elements at positions 2 and 3.

For the third case: The elements are already in sorted order.

For the fourth case: No swap operations may be performed as there is no pair of elements i and j such that b_i ≠ b_j. The elements cannot be sorted.

For the fifth case: Ashish may swap elements at positions 3 and 4, then elements at positions 1 and 2.

Solution (in JAVA):

Solution:
import java.util.*;
public class Solution
{
    public static void main(String args[])
    {
        Scanner s= new Scanner(System.in);
        int t=s.nextInt();
        int q=1;
        while(q<=t)
        {
            int n=s.nextInt();
            int[] a=new int[n];
            int[] b=new int[n];
            int prev=-1;
            int sorted=1;
            for(int i=0;i<n;i++)
            {
                a[i]=s.nextInt();
                if(a[i]<prev)
                    sorted=0;
                prev=a[i];
            }
            prev=s.nextInt();
            b[0]=prev;
            int flag=1;
            for(int i=1;i<n;i++)
            {
                b[i]=s.nextInt();
                if(b[i]!=prev)
                    flag=0;
            }

            if(sorted==1)
                System.out.println("Yes");
            else if(flag==0)
                System.out.println("Yes");
            else
                System.out.println("No");

            q++;
        }
    }
 }