Problem: You are given three positive (i.e. strictly greater than zero) integers x, y and z.

Your task is to find positive integers a, b and c such that x = max(a, b), y = max(a, c) and z = max(b, c), or determine that it is impossible to find such a, b and c.

You have to answer t independent test cases. Print required a, b and c in any (arbitrary) order.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers x, y, and z (1 ≤ x, y, z ≤ 10^9).

Output

For each test case, print the answer:

  * "NO" in the only line of the output if a solution doesn't exist; 
  * or "YES" in the first line and any valid triple of positive integers a, b and c (1 ≤ a, b, c ≤ 10^9) in the second line. You can print a, b and c in any order. 

Example

Input


5
3 2 3
100 100 100
50 49 49
10 30 20
1 1000000000 1000000000


Output


YES
3 2 1
YES
100 100 100
NO
NO
YES
1 1 1000000000

Solution (in PYTHON3):

Solution:
# cook your dish here
from sys import stdin, stdout
import math
from itertools import permutations, combinations
from collections import defaultdict
from bisect import bisect_left 
from bisect import bisect_right
 
def L():
    return list(map(int, stdin.readline().split()))
 
def In():
    return map(int, stdin.readline().split())
 
def I():
    return int(stdin.readline())
 
P = 1000000007
def main():
    for t in range(I()):
        arr = L()
        if len(list(set(arr))) == 1:
            print("YES")
            print(*arr)
        elif len(list(set(arr))) == 2:
            if arr.count(max(arr)) == 2:
                print("YES")
                print(min(arr), min(arr), max(arr))
            else:
                print("NO")
        else:
            print("NO")
            
            
    
    
if __name__ == '__main__':
    main()