Problem: You are given three positive (i.e. strictly greater than zero) integers x, y and z.

Your task is to find positive integers a, b and c such that x = max(a, b), y = max(a, c) and z = max(b, c), or determine that it is impossible to find such a, b and c.

You have to answer t independent test cases. Print required a, b and c in any (arbitrary) order.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers x, y, and z (1 ≤ x, y, z ≤ 10^9).

Output

For each test case, print the answer:

  * "NO" in the only line of the output if a solution doesn't exist; 
  * or "YES" in the first line and any valid triple of positive integers a, b and c (1 ≤ a, b, c ≤ 10^9) in the second line. You can print a, b and c in any order. 

Example

Input


5
3 2 3
100 100 100
50 49 49
10 30 20
1 1000000000 1000000000


Output


YES
3 2 1
YES
100 100 100
NO
NO
YES
1 1 1000000000

Solution (in JAVA):

Solution:
import java.util.Scanner;

public class Mins {

    private static Scanner scanner = new Scanner(System.in);

    public static void main(String[] args) {

        int cases = scanner.nextInt();

        for (int c = 1; c <= cases; c++) {
            solve();
        }

    }

    private static void solve() {

        int x = scanner.nextInt();
        int y = scanner.nextInt();
        int z = scanner.nextInt();

        int max = Math.max(x, Math.max(y, z));
        int min = Math.min(x, Math.min(y, z));

        int c = 0;
        if (x == max) {
            c++;
        }

        if (y == max)
            c++;
        if (z == max)
            c++;

        if (c == 1)
            System.out.println("NO");
        else if (c == 3) {
            System.out.println("YES");
            System.out.println(max + " " + max + " " + max);
        } else {
            System.out.println("YES");
            System.out.println(min + " " + min + " " + max);
        }


    }
}