Problem: You are given three positive (i.e. strictly greater than zero) integers x, y and z.

Your task is to find positive integers a, b and c such that x = max(a, b), y = max(a, c) and z = max(b, c), or determine that it is impossible to find such a, b and c.

You have to answer t independent test cases. Print required a, b and c in any (arbitrary) order.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers x, y, and z (1 ≤ x, y, z ≤ 10^9).

Output

For each test case, print the answer:

  * "NO" in the only line of the output if a solution doesn't exist; 
  * or "YES" in the first line and any valid triple of positive integers a, b and c (1 ≤ a, b, c ≤ 10^9) in the second line. You can print a, b and c in any order. 

Example

Input


5
3 2 3
100 100 100
50 49 49
10 30 20
1 1000000000 1000000000


Output


YES
3 2 1
YES
100 100 100
NO
NO
YES
1 1 1000000000

Solution (in PYTHON3):

Solution:
t = int(input())
l=[]
for i in range(t):
    s = list(map(int, input().split()))
    if s[0] == s[1] :
        if s[0]==s[2]:
            l.append("YES")
            l.append(f"{s[0]} {s[1]} {s[2]}")
        elif s[0]>s[2]:
            l.append("YES")
            l.append(f"{s[0]} 1 {s[2]}")
        else:
            l.append("NO")

    elif s[0]==s[2]:
        if s[0]==s[1]:
            l.append("YES")
            l.append(f"{s[0]} {s[1]} {s[2]}")
        elif s[0]>s[1]:
            l.append("YES")
            l.append(f"{s[0]} {s[1]} 1")
        else:
            l.append("NO")

    elif s[1]==s[2]:
        if s[0]==s[1]:
            l.append("YES")
            l.append(f"{s[0]} {s[1]} {s[2]}")
        elif s[1]>s[0]:
            l.append("YES")
            l.append(f"{s[0]} 1 {s[1]}")
        else:
            l.append("NO")
    else:
        l.append("NO")
for i in l:
    print(i)