Problem: You are given three positive (i.e. strictly greater than zero) integers x, y and z.

Your task is to find positive integers a, b and c such that x = max(a, b), y = max(a, c) and z = max(b, c), or determine that it is impossible to find such a, b and c.

You have to answer t independent test cases. Print required a, b and c in any (arbitrary) order.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers x, y, and z (1 ≤ x, y, z ≤ 10^9).

Output

For each test case, print the answer:

  * "NO" in the only line of the output if a solution doesn't exist; 
  * or "YES" in the first line and any valid triple of positive integers a, b and c (1 ≤ a, b, c ≤ 10^9) in the second line. You can print a, b and c in any order. 

Example

Input


5
3 2 3
100 100 100
50 49 49
10 30 20
1 1000000000 1000000000


Output


YES
3 2 1
YES
100 100 100
NO
NO
YES
1 1 1000000000

Solution (in PYTHON3):

Solution:
t = int(input())
for i in range(t):
    a = input().split()
    x = int(a[0])
    y = int(a[1])
    z = int(a[2])
    if x != y and x != z and y != z:
        print ('NO')
        continue
    if x == y == z:
        print ('YES' + '\n' + str(x) + ' ' + str(y) + ' ' + str(z))
        continue
    if x == y and x > z:
        print ('YES' + '\n' + str(x) + ' '  + str(z) + ' '  + str(z))
        continue
    if x == z and x > y:
        print ('YES' + '\n' + str(x) + ' '  + str(y) + ' '  + str(y))
        continue
    if z == y and z > x:
        print ('YES' + '\n' + str(z) + ' '  + str(x) + ' '  + str(x))
        continue
    print ('NO')


# YES
# 3 2 1
# YES
# 100 100 100
# NO
# YES
# 1000000000 1 0