Problem: You are given three positive (i.e. strictly greater than zero) integers x, y and z.

Your task is to find positive integers a, b and c such that x = max(a, b), y = max(a, c) and z = max(b, c), or determine that it is impossible to find such a, b and c.

You have to answer t independent test cases. Print required a, b and c in any (arbitrary) order.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers x, y, and z (1 ≤ x, y, z ≤ 10^9).

Output

For each test case, print the answer:

  * "NO" in the only line of the output if a solution doesn't exist; 
  * or "YES" in the first line and any valid triple of positive integers a, b and c (1 ≤ a, b, c ≤ 10^9) in the second line. You can print a, b and c in any order. 

Example

Input


5
3 2 3
100 100 100
50 49 49
10 30 20
1 1000000000 1000000000


Output


YES
3 2 1
YES
100 100 100
NO
NO
YES
1 1 1000000000

Solution (in JAVA):

Solution:
import java.util.*;
import java.lang.*;
import java.math.*;
import java.io.*;

public class HelloWorld{

     public static void main(String []args){
        
        Scanner sc=new Scanner(System.in);
        PrintWriter op=new PrintWriter(System.out);
        
        int t=sc.nextInt();
        while(t!=0)
        {
            
            int a=sc.nextInt();
            
            int b=sc.nextInt();
            
            int c=sc.nextInt();
            
            if((a==b && c<=a)|| (a==c && b<=a) || (b==c && a<=b))
            {
                op.println("YES");
                
                if(a==b && c<=a)
                op.println(a+" "+c+" "+c);
                else if(a==c && b<=a)
                op.println(a+" "+b+" "+b);
                else if(b==c && a<=b)
                op.println(a+" "+a+" "+c);
            }
            else
            op.println("NO");
            
            
            
            
            t--;
        }
        
        
        op.flush();
        op.close();
     }
}