Problem: You are given three positive (i.e. strictly greater than zero) integers x, y and z.

Your task is to find positive integers a, b and c such that x = max(a, b), y = max(a, c) and z = max(b, c), or determine that it is impossible to find such a, b and c.

You have to answer t independent test cases. Print required a, b and c in any (arbitrary) order.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers x, y, and z (1 ≤ x, y, z ≤ 10^9).

Output

For each test case, print the answer:

  * "NO" in the only line of the output if a solution doesn't exist; 
  * or "YES" in the first line and any valid triple of positive integers a, b and c (1 ≤ a, b, c ≤ 10^9) in the second line. You can print a, b and c in any order. 

Example

Input


5
3 2 3
100 100 100
50 49 49
10 30 20
1 1000000000 1000000000


Output


YES
3 2 1
YES
100 100 100
NO
NO
YES
1 1 1000000000

Solution (in JAVA):

Solution:
import java.util.Scanner;

public class three_pairwise_maximums {
    public static void main(String args[]){
        int t,a=0,b=0,c=0,x,y,z;
        Scanner sc=new Scanner(System.in);
        t=sc.nextInt();
        for(int i=1;i<=t;i++){
            x=sc.nextInt();
            y=sc.nextInt();
            z=sc.nextInt();

            if(x==y){
                if(x>z&&x>0){
                    a=x;
                    b=z;
                    c=b;
                    System.out.println("YES");
                    System.out.println(a+" "+b+" "+c);
                }
                else if(x==z){
                    a=x;
                    b=x;
                    c=b;
                    System.out.println("YES");
                    System.out.println(a+" "+b+" "+c);
                }
                else{
                    System.out.println("NO");
                }
            }
            else if(y==z){
                if(y>x&&y>0){
                    a=y;
                    b=x;
                    c=b;
                    System.out.println("YES");
                    System.out.println(a+" "+b+" "+c);
                }
                else if(y==x){
                    a=y;
                    b=y;
                    c=b;
                    System.out.println("YES");
                    System.out.println(a+" "+b+" "+c);
                }
                else{
                    System.out.println("NO");
                }
            }
            else if(x==z){
                if(x>y&&x>0){
                    a=x;
                    b=y;
                    c=b;
                    System.out.println("YES");
                    System.out.println(a+" "+b+" "+c);
                }
                else if(x==y){
                    a=x;
                    b=x;
                    c=b;
                    System.out.println("YES");
                    System.out.println(a+" "+b+" "+c);
                }
                else{
                    System.out.println("NO");
                }
            }
            else
                System.out.println("NO");
        }
    }
}