Problem: You are given three positive (i.e. strictly greater than zero) integers x, y and z.

Your task is to find positive integers a, b and c such that x = max(a, b), y = max(a, c) and z = max(b, c), or determine that it is impossible to find such a, b and c.

You have to answer t independent test cases. Print required a, b and c in any (arbitrary) order.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers x, y, and z (1 ≤ x, y, z ≤ 10^9).

Output

For each test case, print the answer:

  * "NO" in the only line of the output if a solution doesn't exist; 
  * or "YES" in the first line and any valid triple of positive integers a, b and c (1 ≤ a, b, c ≤ 10^9) in the second line. You can print a, b and c in any order. 

Example

Input


5
3 2 3
100 100 100
50 49 49
10 30 20
1 1000000000 1000000000


Output


YES
3 2 1
YES
100 100 100
NO
NO
YES
1 1 1000000000

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.util.*;


public class Cf656 {

    public static void main(String args[] ) throws Exception {
        
        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
        int test = Integer.parseInt(br.readLine());

        for(int idx = 1; idx <= test; idx++) {

            String[] vals = br.readLine().trim().split(" ");

            long x = Long.parseLong(vals[0]);
            long y = Long.parseLong(vals[1]);
            long z = Long.parseLong(vals[2]);

            boolean res = true;
            long a = 0, b = 0, c = 0;

            if(x > y) {
                if(x != z) {
                    res = false;
                }
                else {
                    a = y;
                    b = x;
                    c = y;
                }
            }
            else if(x == y) {
                if(z > y) {
                    res = false;
                }
                else {
                    a = x;
                    b = z;
                    c = z;
                }
            }
            else {
                if(z != y) {
                    res = false;
                }
                else {
                    a = x; b = x; c = y;
                }
            }

            if(res) {
                System.out.println("YES");
                System.out.println(a + " " + b + " " + c);
            }
            else {
                System.out.println("NO");
            }
        }
    }
}