Problem: You are given three positive (i.e. strictly greater than zero) integers x, y and z.

Your task is to find positive integers a, b and c such that x = max(a, b), y = max(a, c) and z = max(b, c), or determine that it is impossible to find such a, b and c.

You have to answer t independent test cases. Print required a, b and c in any (arbitrary) order.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers x, y, and z (1 ≤ x, y, z ≤ 10^9).

Output

For each test case, print the answer:

  * "NO" in the only line of the output if a solution doesn't exist; 
  * or "YES" in the first line and any valid triple of positive integers a, b and c (1 ≤ a, b, c ≤ 10^9) in the second line. You can print a, b and c in any order. 

Example

Input


5
3 2 3
100 100 100
50 49 49
10 30 20
1 1000000000 1000000000


Output


YES
3 2 1
YES
100 100 100
NO
NO
YES
1 1 1000000000

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.*;

public class Main {

    public static void main(String[] args) throws IOException {
        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
        int tst = Integer.parseInt(br.readLine());
        while(tst-->0){
            String[] str = br.readLine().split(" ");
            int x = Integer.parseInt(str[0]), y = Integer.parseInt(str[1]), z = Integer.parseInt(str[2]);
            if(x!=y && x!=z && y!=z) System.out.println("NO");
            else{
                if(x == y && y == z){
                    System.out.println("YES");
                    System.out.println(x+" "+y+" "+z);
                }
                else if(x == y && z<y){
                    System.out.println("YES");
                    System.out.println(1+" "+x+" "+z);
                }
                else if(x == z && y<x){
                    System.out.println("YES");
                    System.out.println(x+" "+y+" "+1);
                }
                else if(y == z && x<y){
                    System.out.println("YES");
                    System.out.println(x+" "+1+" "+z);
                }
                else System.out.println("NO");
            }
        }
    }
}