Problem: You are given three positive (i.e. strictly greater than zero) integers x, y and z.

Your task is to find positive integers a, b and c such that x = max(a, b), y = max(a, c) and z = max(b, c), or determine that it is impossible to find such a, b and c.

You have to answer t independent test cases. Print required a, b and c in any (arbitrary) order.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers x, y, and z (1 ≤ x, y, z ≤ 10^9).

Output

For each test case, print the answer:

  * "NO" in the only line of the output if a solution doesn't exist; 
  * or "YES" in the first line and any valid triple of positive integers a, b and c (1 ≤ a, b, c ≤ 10^9) in the second line. You can print a, b and c in any order. 

Example

Input


5
3 2 3
100 100 100
50 49 49
10 30 20
1 1000000000 1000000000


Output


YES
3 2 1
YES
100 100 100
NO
NO
YES
1 1 1000000000

Solution (in PYTHON3):

Solution:
import sys,math
# from heapq import *
# from collections import defaultdict as dd
# from collections import Counter as cc
# sys.setrecursionlimit(10**6)
mod = 10**9+7; md = 998244353
input = lambda: sys.stdin.readline().strip()
inp = lambda: list(map(int,input().split()))
#______________________________________________________
for _ in range(int(input())):
	a,b,c = inp()
	t = max(a,b,c)
	d = [a,b,c]
	if d.count(t)>1:
		print("YES")
		ind = d.index(min(d))
		ans = [t,t,t]
		ans[ind] = min(d)
		ans[(ind+1)%3]=1 if d.count(t)==2 else t
		print(*ans)
	else:
		print("NO")