Problem: The Shuseki Islands are an archipelago of 30001 small islands in the Yutampo Sea. The islands are evenly spaced along a line, numbered from 0 to 30000 from the west to the east. These islands are known to contain many treasures. There are n gems in the Shuseki Islands in total, and the i-th gem is located on island pi.

Mr. Kitayuta has just arrived at island 0. With his great jumping ability, he will repeatedly perform jumps between islands to the east according to the following process: 

  * First, he will jump from island 0 to island d. 
  * After that, he will continue jumping according to the following rule. Let l be the length of the previous jump, that is, if his previous jump was from island prev to island cur, let l = cur - prev. He will perform a jump of length l - 1, l or l + 1 to the east. That is, he will jump to island (cur + l - 1), (cur + l) or (cur + l + 1) (if they exist). The length of a jump must be positive, that is, he cannot perform a jump of length 0 when l = 1. If there is no valid destination, he will stop jumping. 



Mr. Kitayuta will collect the gems on the islands visited during the process. Find the maximum number of gems that he can collect.

Input

The first line of the input contains two space-separated integers n and d (1 ≤ n, d ≤ 30000), denoting the number of the gems in the Shuseki Islands and the length of the Mr. Kitayuta's first jump, respectively.

The next n lines describe the location of the gems. The i-th of them (1 ≤ i ≤ n) contains a integer pi (d ≤ p1 ≤ p2 ≤ ... ≤ pn ≤ 30000), denoting the number of the island that contains the i-th gem.

Output

Print the maximum number of gems that Mr. Kitayuta can collect.

Examples

Input

4 10
10
21
27
27


Output

3


Input

8 8
9
19
28
36
45
55
66
78


Output

6


Input

13 7
8
8
9
16
17
17
18
21
23
24
24
26
30


Output

4

Note

In the first sample, the optimal route is 0  →  10 (+1 gem)  →  19  →  27 (+2 gems)  → ...

In the second sample, the optimal route is 0  →  8  →  15  →  21 →  28 (+1 gem)  →  36 (+1 gem)  →  45 (+1 gem)  →  55 (+1 gem)  →  66 (+1 gem)  →  78 (+1 gem)  → ...

In the third sample, the optimal route is 0  →  7  →  13  →  18 (+1 gem)  →  24 (+2 gems)  →  30 (+1 gem)  → ...

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.*;

public class _505C {

    static final int MIN = Integer.MIN_VALUE / 10;
    static final int MAX = 30000;
    static final int OFFSET = 280;
    static int n;
    static int d;
    static int[] cnt;
    static int[][] f = new int[MAX + 1][2 * OFFSET + 10];

    static int F(int i, int j) {
        if (i < d || j < -OFFSET || j > OFFSET || d + j <= 0) return MIN;
        if (i == d) {
            if (j == 0) return cnt[i];
            else return MIN;
        }
        if (f[i][j + OFFSET] != -1) return f[i][j + OFFSET];

        int ans = MIN;
        ans = Math.max(ans, F(i - (d + j), j - 1));
        ans = Math.max(ans, F(i - (d + j), j));
        ans = Math.max(ans, F(i - (d + j), j + 1));
        ans += cnt[i];

        f[i][j + OFFSET] = ans;
        return ans;
    }

    public static void main(String[] args) throws Exception {
        Reader.init(System.in);
        BufferedWriter cout = new BufferedWriter(new OutputStreamWriter(System.out));

        n = Reader.nextInt();
        d = Reader.nextInt();
        cnt = new int[MAX + 1];
        for (int i = 0; i < n; i++) cnt[Reader.nextInt()]++;

        for (int[] arr : f) Arrays.fill(arr, -1);
        int ans = 0;
        for (int i = d; i <= MAX; i++) {
            for (int j = -OFFSET; j <= OFFSET; j++)
                ans = Math.max(ans, F(i, j));
        }
        System.out.println(ans);

        cout.close();
    }

    static class Pair<U extends Comparable<U>, V extends Comparable<V>> implements Comparable<Pair<U, V>> {
        final U _1;
        final V _2;

        private Pair(U key, V val) {
            this._1 = key;
            this._2 = val;
        }

        public static <U extends Comparable<U>, V extends Comparable<V>> Pair<U, V> instanceOf(U _1, V _2) {
            return new Pair<U, V>(_1, _2);
        }

        @Override
        public String toString() {
            return _1 + " " + _2;
        }

        @Override
        public int hashCode() {
            int res = 17;
            res = res * 31 + _1.hashCode();
            res = res * 31 + _2.hashCode();
            return res;
        }

        @Override
        public int compareTo(Pair<U, V> that) {
            int res = this._1.compareTo(that._1);
            if (res < 0 || res > 0) return res;
            else return this._2.compareTo(that._2);
        }

        @Override
        public boolean equals(Object obj) {
            if (this == obj) return true;
            if (!(obj instanceof Pair)) return false;
            Pair<?, ?> that = (Pair<?, ?>) obj;
            return _1.equals(that._1) && _2.equals(that._2);
        }
    }

    /**
     * Class for buffered reading int and double values
     */
    static class Reader {
        static BufferedReader reader;
        static StringTokenizer tokenizer;

        /**
         * call this method to initialize reader for InputStream
         */
        static void init(InputStream input) {
            reader = new BufferedReader(new InputStreamReader(input));
            tokenizer = new StringTokenizer("");
        }

        /**
         * get next word
         */
        static String next() throws IOException {
            while (!tokenizer.hasMoreTokens()) {
                // TODO add check for eof if necessary
                tokenizer = new StringTokenizer(reader.readLine());
            }
            return tokenizer.nextToken();
        }

        static int nextInt() throws IOException {
            return Integer.parseInt(next());
        }

        static double nextDouble() throws IOException {
            return Double.parseDouble(next());
        }
    }

    static class ArrayUtil {
        static void swap(int[] a, int i, int j) {
            int tmp = a[i];
            a[i] = a[j];
            a[j] = tmp;
        }

        static void swap(long[] a, int i, int j) {
            long tmp = a[i];
            a[i] = a[j];
            a[j] = tmp;
        }

        static void swap(double[] a, int i, int j) {
            double tmp = a[i];
            a[i] = a[j];
            a[j] = tmp;
        }

        static void swap(char[] a, int i, int j) {
            char tmp = a[i];
            a[i] = a[j];
            a[j] = tmp;
        }

        static void swap(boolean[] a, int i, int j) {
            boolean tmp = a[i];
            a[i] = a[j];
            a[j] = tmp;
        }

        static void reverse(int[] a, int i, int j) {
            for (; i < j; i++, j--)
                swap(a, i, j);
        }

        static void reverse(long[] a, int i, int j) {
            for (; i < j; i++, j--)
                swap(a, i, j);
        }

        static void reverse(double[] a, int i, int j) {
            for (; i < j; i++, j--)
                swap(a, i, j);
        }

        static void reverse(char[] a, int i, int j) {
            for (; i < j; i++, j--)
                swap(a, i, j);
        }

        static void reverse(boolean[] a, int i, int j) {
            for (; i < j; i++, j--)
                swap(a, i, j);
        }

        static long sum(int[] a) {
            int sum = 0;
            for (int i : a)
                sum += i;
            return sum;
        }

        static long sum(long[] a) {
            long sum = 0;
            for (long i : a)
                sum += i;
            return sum;
        }

        static double sum(double[] a) {
            double sum = 0;
            for (double i : a)
                sum += i;
            return sum;
        }

        static int max(int[] a) {
            int max = Integer.MIN_VALUE;
            for (int i : a)
                if (i > max) max = i;
            return max;
        }

        static int min(int[] a) {
            int min = Integer.MAX_VALUE;
            for (int i : a)
                if (i < min) min = i;
            return min;
        }

        static long max(long[] a) {
            long max = Long.MIN_VALUE;
            for (long i : a)
                if (i > max) max = i;
            return max;
        }

        static long min(long[] a) {
            long min = Long.MAX_VALUE;
            for (long i : a)
                if (i < min) min = i;
            return min;
        }
    }
}