Problem: This is an interactive problem.

Vasya and Vitya play a game. Vasya thought of two integers a and b from 1 to n and Vitya tries to guess them. Each round he tells Vasya two numbers x and y from 1 to n. If both x=a and y=b then Vitya wins. Else Vasya must say one of the three phrases: 

  1. x is less than a; 
  2. y is less than b; 
  3. x is greater than a or y is greater than b. 



Vasya can't lie, but if multiple phrases are true, he may choose any of them. For example, if Vasya thought of numbers 2 and 4, then he answers with the phrase 3 to a query (3, 4), and he can answer with the phrase 1 or phrase 3 to a query (1, 5).

Help Vitya win in no more than 600 rounds. 

Input

The first line contains a single integer n (1 ≤ n ≤ 10^{18}) — the upper limit of the numbers.

Interaction

First, you need to read the number n, after that you can make queries.

To make a query, print two integers: x and y (1 ≤ x, y ≤ n), then flush the output.

After each query, read a single integer ans (0 ≤ ans ≤ 3).

If ans > 0, then it is the number of the phrase said by Vasya.

If ans = 0, it means that you win and your program should terminate.

If you make more than 600 queries or make an incorrect query, you will get Wrong Answer.

Your solution will get Idleness Limit Exceeded, if you don't print anything or forget to flush the output.

To flush you need to do the following right after printing a query and a line end: 

  * fflush(stdout) in C++; 
  * System.out.flush() in Java; 
  * stdout.flush() in Python; 
  * flush(output) in Pascal; 
  * For other languages see documentation. 



Hacks format

For hacks, use the following format:

In the first line, print a single integer n (1 ≤ n ≤ 10^{18}) — the upper limit of the numbers.

In the second line, print two integers a and b (1 ≤ a, b ≤ n) — the numbers which Vasya thought of.

In the third line, print a single integer m (1 ≤ m ≤ 10^5) — the number of instructions for the interactor.

In each of the next m lines, print five integers: x_i, y_i, r^{12}_i, r^{13}_i, and r^{23}_i (1 ≤ x_i, y_i ≤ n), where r^{ST}_i equals to either number S or number T.

While answering the query x   y, the interactor finds a number i from 1 to n with the minimal value |x-x_i| + |y-y_i|. If multiple numbers can be chosen, the least i is preferred. Then the interactor answers to the query, but if there are two phrases S and T that can be given, then r^{ST}_i is chosen.

For example, the sample test data file contains the following: 
    
    
      
    5  
    2 4  
    2  
    2 5 1 1 2  
    4 1 2 3 3  
    

Example

Input

5
3
3
2
1
0

Output

4 3
3 4
3 3
1 5
2 4

Note

Let's analyze the sample test. The chosen numbers are 2 and 4. The interactor was given two instructions.

For the query (4, 3), it can return 2 or 3. Out of the two instructions the second one is chosen, so the interactor returns a^{23}_2=3.

For the query (3, 4), it can return only 3.

For the query (3, 3), it can return 2 or 3. Out of the two instructions the first one is chosen (since in case of equal values, the least number is preferred), so the interactor returns a^{23}_1=2.

For the query (1, 5), it can return 1 or 3. Out of the two instructions the first one is chosen, so the interactor returns a^{13}_1=1.

In the fifth query (2, 4), the numbers are guessed correctly, the player wins.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
inline int in() {
  int x;
  scanf("%d", &x);
  return x;
}
template <typename T>
inline istream& operator>>(istream& i, vector<T>& v) {
  for (int j = 0; j < ((int)(v).size()); ++j) i >> v[j];
  return i;
}
template <typename T>
string join(const vector<T>& v) {
  stringstream s;
  for (int i = 0; i < ((int)(v).size()); ++i) s << ' ' << v[i];
  return s.str().substr(1);
}
template <typename T>
inline ostream& operator<<(ostream& o, const vector<T>& v) {
  if ((int)(v).size()) o << join(v);
  return o;
}
template <typename T1, typename T2>
inline istream& operator>>(istream& i, pair<T1, T2>& v) {
  return i >> v.first >> v.second;
}
template <typename T1, typename T2>
inline ostream& operator<<(ostream& o, const pair<T1, T2>& v) {
  return o << v.first << "," << v.second;
}
template <typename T>
inline long long int suma(const vector<T>& a) {
  long long int res(0);
  for (auto&& x : a) res += x;
  return res;
}
const double eps = 1e-10;
const long long int LINF = 1001002003004005006ll;
const int INF = 1001001001;
const int MX = 200005;
const int B = 9;
inline long long int ten(int n) { return n ? ten(n - 1) * 10 : 1; }
const int BS = ten(B);
struct bint;
istream& operator>>(istream& i, bint& a);
ostream& operator<<(ostream& o, const bint& a);
struct bint {
  vector<int> d;
  bool sg;
  bint(long long int n = 0) {
    sg = n < 0;
    if (sg) n = -n;
    while (n) {
      d.push_back(n % BS);
      n /= BS;
    }
  }
  bint(const string& s) {
    sg = s[0] == '-';
    int si = sg;
    for (int i = (int)(s).size(); i > si; i -= B) {
      d.push_back(0);
      for (int j = max(si, i - B); j < i; ++j)
        d.back() = d.back() * 10 + (s[j] - '0');
    }
    cut();
  }
  bint(const vector<int>& d, bool sg = false) : d(d), sg(sg) {}
  inline bint& cut() {
    while ((int)(d).size() && !d.back()) d.pop_back();
    sg &= !iszero();
    return *this;
  }
  inline int size() const { return (int)(d).size(); }
  inline int& operator[](int i) { return d[i]; }
  inline const int& operator[](int i) const { return d[i]; }
  inline int len() const {
    if (!(int)(d).size()) return 0;
    int l = ((int)(d).size() - 1) * B;
    int b = d.back();
    while (b) ++l, b /= 10;
    return l;
  }
  bint abs() const {
    bint a(*this);
    a.sg = false;
    return a;
  }
  inline bool iszero() const { return !(int)(d).size(); }
  long long int toLL() const {
    if (bint(INF) < abs()) return sg ? -INF : INF;
    long long int x = 0;
    for (int i = ((int)(d).size()) - 1; i >= 0; --i) x = x * BS + d[i];
    if (sg) x = -x;
    return x;
  }
  bint& _add(const bint& a) {
    if ((int)(d).size() <= (int)(a).size())
      d.resize((int)(a).size() + 1);
    else
      d.push_back(0);
    int i = 0;
    while (i < (int)(a).size()) {
      d[i] += a[i];
      if (d[i] >= BS)
        d[i] -= BS, ++d[++i];
      else
        ++i;
    }
    while (d[i] == BS) d[i] = 0, ++d[++i];
    if (!d.back()) d.pop_back();
    return *this;
  }
  bint& _asub(const bint& a) {
    int i = 0;
    while (i < (int)(a).size()) {
      d[i] -= a[i];
      if (d[i] < 0)
        d[i] += BS, --d[++i];
      else
        ++i;
    }
    if (i < (int)(d).size())
      while (d[i] == -1) d[i] = BS - 1, --d[++i];
    return cut();
  }
  bint& _sub(const bint& a) {
    if (_cmp(a)) {
      bint b(a);
      swap(*this, b);
      return _asub(b);
    }
    return _asub(a);
  }
  bint& operator+=(const bint& a) {
    if (sg == a.sg) return _add(a);
    return _sub(a);
  }
  bint& operator-=(const bint& a) {
    if (sg != a.sg) return _add(a);
    sg ^= 1;
    _sub(a);
    if (!iszero()) sg ^= 1;
    return *this;
  }
  bint& operator*=(long long int a) {
    if (!a) return *this = 0;
    if (a < 0) sg ^= 1, a = -a;
    if (LINF / BS < a) return (*this) *= bint(a);
    long long int x = 0;
    for (int i = 0; i < ((int)(d).size()); ++i) {
      x += a * d[i];
      d[i] = x % BS;
      x /= BS;
    }
    while (x) d.push_back(x % BS), x /= BS;
    return *this;
  }
  bint mult(const bint& a) const {
    if ((int)(a).size() == 1) return bint(*this) *= a[0];
    if (a.iszero()) return 0;
    bint b = (*this) * a.d.back();
    b.sg ^= a.sg;
    for (int i = ((int)(a).size() - 1) - 1; i >= 0; --i) {
      b.d.insert(b.d.begin(), 0);
      b += (*this) * a[i];
    }
    return b;
  }
  long long int operator%(long long int a) const {
    assert(a > 0);
    long long int r = 0;
    for (int i = ((int)(d).size()) - 1; i >= 0; --i) r = (r * BS + d[i]) % a;
    if (sg) r = (a - r) % a;
    return r;
  }
  bint& operator/=(long long int a) {
    assert(a);
    if (a < 0) sg ^= 1, a = -a;
    assert(LINF / BS >= a);
    long long int x = 0;
    for (int i = ((int)(d).size()) - 1; i >= 0; --i) {
      x = x * BS + d[i];
      d[i] = x / a;
      x %= a;
    }
    return cut();
  }
  bint operator+(const bint& a) const { return bint(*this) += a; }
  bint operator-(const bint& a) const { return bint(*this) -= a; }
  bint operator*(long long int a) const { return bint(*this) *= a; }
  bint operator*(const bint& a) const;
  bint& operator*=(const bint& a) { return *this = (*this) * a; }
  bint operator/(long long int a) const { return bint(*this) /= a; }
  bint operator/(const bint& a) const {
    assert(false);
    return bint();
  }
  bint operator%(const bint& a) const {
    assert(false);
    return bint();
  }
  bint square() const;
  bint ex(long long int t) const {
    if (!t) return 1;
    bint a = ex(t >> 1).square();
    if (t & 1) return a * (*this);
    return a;
  }
  bool _cmp(const bint& a) const {
    if ((int)(d).size() != (int)(a).size())
      return (int)(d).size() < (int)(a).size();
    for (int i = ((int)(d).size()) - 1; i >= 0; --i)
      if (d[i] != a[i]) return d[i] < a[i];
    return false;
  }
  bool operator<(const bint& a) const {
    if (sg != a.sg) return sg;
    return sg ? a._cmp(*this) : _cmp(a);
  }
  bool operator<=(const bint& a) const { return !(a < (*this)); }
  bool operator==(const bint& a) const { return sg == a.sg && d == a.d; }
  string str() const {
    if (!(int)(d).size()) return "0";
    ostringstream os;
    if (sg) os << '-';
    os << d.back();
    for (int i = ((int)(d).size() - 1) - 1; i >= 0; --i)
      os << setw(B) << setfill('0') << d[i];
    return os.str();
  }
};
long long int extgcd(long long int a, long long int b, long long int& x,
                     long long int& y) {
  for (long long int u = y = 1, v = x = 0; a;) {
    long long int q = b / a;
    swap(x -= q * u, u);
    swap(y -= q * v, v);
    swap(b -= q * a, a);
  }
  return b;
}
long long int mod_inv(long long int a, long long int m) {
  long long int x, y;
  extgcd(a, m, x, y);
  return (m + x % m) % m;
}
long long int mod_pow(long long int a, long long int n, long long int mod) {
  long long int ret = 1;
  long long int p = a % mod;
  while (n) {
    if (n & 1) ret = ret * p % mod;
    p = p * p % mod;
    n >>= 1;
  }
  return ret;
}
template <int mod, int primitive_root>
struct NTT {
  int get_mod() const { return mod; }
  void _ntt(vector<int>& a, int sign) {
    const int n = (int)(a).size();
    int h = mod_pow(primitive_root, (mod - 1) / n, mod);
    if (sign == -1) h = mod_inv(h, mod);
    int i = 0;
    for (int j = 1; j < n - 1; ++j) {
      for (int k = n >> 1; k > (i ^= k); k >>= 1)
        ;
      if (j < i) swap(a[i], a[j]);
    }
    for (int m = 1; m < n; m *= 2) {
      const int m2 = m * 2;
      const long long int base = mod_pow(h, n / m2, mod);
      vector<long long int> w(m);
      w[0] = 1;
      for (int j = 1; j < m; ++j) w[j] = w[j - 1] * base % mod;
      for (int s = 0; s < n; s += m2) {
        for (int x = 0; x < (m); ++x) {
          int j = s + x;
          int d = a[j + m] * w[x] % mod;
          a[j + m] = a[j] - d;
          if (a[j + m] < 0) a[j + m] += mod;
          a[j] -= mod - d;
          if (a[j] < 0) a[j] += mod;
        }
      }
    }
  }
  void ntt(vector<int>& input) { _ntt(input, 1); }
  void intt(vector<int>& input) {
    _ntt(input, -1);
    const int n_inv = mod_inv((int)(input).size(), mod);
    for (auto& x : input) x = (long long int)x * n_inv % mod;
  }
  vector<int> convolution(const vector<int>& a, const vector<int>& b) {
    int ntt_size = 1;
    while (ntt_size < (int)(a).size() + (int)(b).size()) ntt_size *= 2;
    vector<int> _a = a, _b = b;
    _a.resize(ntt_size);
    _b.resize(ntt_size);
    ntt(_a);
    ntt(_b);
    for (int i = 0; i < (ntt_size); ++i)
      _a[i] = (long long int)_a[i] * _b[i] % mod;
    intt(_a);
    _a.resize((int)(a).size() + (int)(b).size());
    return _a;
  }
  vector<int> square(const vector<int>& a) {
    int ntt_size = 1;
    while (ntt_size < (int)(a).size() * 2) ntt_size *= 2;
    vector<int> _a = a;
    _a.resize(ntt_size);
    ntt(_a);
    for (int i = 0; i < (ntt_size); ++i)
      _a[i] = (long long int)_a[i] * _a[i] % mod;
    intt(_a);
    _a.resize((int)(a).size() * 2);
    return _a;
  }
};
const int P1 = 1811939329;
const int P2 = 2013265921;
const int P3 = 2113929217;
const long long int P12 = (long long int)P1 * P2;
const int IP1_2 = mod_inv(P1, P2);
const int IP12_3 = mod_inv(P12, P3);
const long long int P12_R = P12 % BS;
const long long int P12_Q = P12 / BS;
vector<int> _garner(vector<int>& x, vector<int>& y, vector<int>& z) {
  long long int c = 0;
  for (int i = 0; i < ((int)(x).size()); ++i) {
    y[i] = ((long long int)y[i] - x[i] + P2) * IP1_2 % P2;
    long long int s = x[i] + (long long int)y[i] * P1;
    z[i] = (z[i] - s % P3 + P3) * IP12_3 % P3;
    s += c + P12_R * z[i];
    c = P12_Q * z[i] + s / BS;
    x[i] = s % BS;
  }
  return x;
}
bint bint::operator*(const bint& a) const {
  if ((int)(a).size() <= 10) return mult(a);
  NTT<P1, 13> ntt1;
  NTT<P2, 31> ntt2;
  NTT<P3, 5> ntt3;
  vector<int> x = ntt1.convolution(d, a.d);
  vector<int> y = ntt2.convolution(d, a.d);
  vector<int> z = ntt3.convolution(d, a.d);
  return bint(_garner(x, y, z), sg ^ a.sg).cut();
}
bint bint::square() const {
  NTT<P1, 13> ntt1;
  NTT<P2, 31> ntt2;
  NTT<P3, 5> ntt3;
  vector<int> x = ntt1.square(d);
  vector<int> y = ntt2.square(d);
  vector<int> z = ntt3.square(d);
  return bint(_garner(x, y, z), false).cut();
}
istream& operator>>(istream& i, bint& a) {
  string s;
  i >> s;
  a = bint(s);
  return i;
}
ostream& operator<<(ostream& o, const bint& a) { return o << a.str(); }
long long int n;
int cnt;
int f(long long int i, long long int j) {
  i = n - i;
  j = n - j;
  cout << i << " " << j << endl;
  int res;
  cin >> res;
  ++cnt;
  return res;
}
bint area(pair<long long int, long long int> s,
          pair<long long int, long long int> t) {
  return bint(t.first - s.first) * (t.second - s.second);
}
int main() {
  cin >> n;
  pair<long long int, long long int> s(0, 0);
  pair<long long int, long long int> t(n, n);
  pair<long long int, long long int> x(0, 0);
  while (1) {
    bint a = (area(s, t) - area(s, x)) / 3 + 1;
    long long int i, j;
    {
      long long int l = x.first, r = t.first;
      while (l + 1 < r) {
        long long int c = (l + r) >> 1;
        if (area(pair<long long int, long long int>(c, s.second), t) < a)
          r = c;
        else
          l = c;
      }
      i = l;
    }
    {
      long long int l = x.second, r = t.second;
      while (l + 1 < r) {
        long long int c = (l + r) >> 1;
        if (area(pair<long long int, long long int>(s.first, c), t) < a)
          r = c;
        else
          l = c;
      }
      j = l;
    }
    int res = f(i, j);
    if (!res) break;
    if (res == 1) {
      t.first = i;
    } else if (res == 2) {
      t.second = j;
    } else {
      x = pair<long long int, long long int>(i + 1, j + 1);
    }
    if (x.first >= t.first) s.second = x.second, x = s;
    if (x.second >= t.second) s.first = x.first, x = s;
  }
  cerr << cnt << endl;
  return 0;
}