Problem: You are given three positive (i.e. strictly greater than zero) integers x, y and z.

Your task is to find positive integers a, b and c such that x = max(a, b), y = max(a, c) and z = max(b, c), or determine that it is impossible to find such a, b and c.

You have to answer t independent test cases. Print required a, b and c in any (arbitrary) order.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers x, y, and z (1 ≤ x, y, z ≤ 10^9).

Output

For each test case, print the answer:

  * "NO" in the only line of the output if a solution doesn't exist; 
  * or "YES" in the first line and any valid triple of positive integers a, b and c (1 ≤ a, b, c ≤ 10^9) in the second line. You can print a, b and c in any order. 

Example

Input


5
3 2 3
100 100 100
50 49 49
10 30 20
1 1000000000 1000000000


Output


YES
3 2 1
YES
100 100 100
NO
NO
YES
1 1 1000000000

Solution (in PYTHON3):

Solution:
from math import *
from copy import *
from string import *				# alpha = ascii_lowercase
from random import *
from sys import stdin,stdout
from sys import maxsize
from operator import *				# d = sorted(d.items(), key=itemgetter(1))
from itertools import *
from collections import Counter		# d = dict(Counter(l))
import math
import math
import time
from queue import Queue
# PradeepGhosh_2017076

def seive(n):
	l=[True]
	l=l*(n+1)
	for i in range(2,int(sqrt(n))+1):
		if(l[i]==True):
			val=i*i
			while(val<len(l)):
				l[val]=False
				val+=i
	prime=[]
	for i in range(2,len(l)):
		if(l[i]==True):
			prime.append(i)
	return prime

def dp(l,i,n,val,ans):
	if(i>=n or val<0):
		return 1000000
	elif(val==0):
		return 0
	else:
		if(ans[i]==1000000):
			ans[i]=min(min(1+dp(l,i+1,n,val-l[i],ans),1+dp(l,i,n,val-l[i],ans)),dp(l,i+1,n,val,ans))
		return ans[i]
from queue import Queue
def factors(n):
	l=[]
	for i in range(1,int(sqrt(n))+1):
		if(n%i==0):
			if(n//i==i):
				l.append(i)
			else:
				l.append(i)
				l.append(n//i)
	return l
def check1(s,v,x):
	while(True):
		if(v not in s):
			return v
		else:
			v-=1
def check2(s,v,x):
	while(True):
		if(v not in s):
			return v
		else:
			v+=1

def up(n):
	j=n-1
	while(j>0):
		if(n%j==0):
			break
		j-=1
	return j		
def fac(n):
	c=1
	i=1
	while(i<=n):
		c*=i
		i+=1
	return c
def check_happy(n):
	ss=set()
	print(n)
	while(n!=1):
		val=n
		s=0
		print(val)
		while(val!=0):
			s+=(val%10)**2
			val=val//10
		print(val)
		print("hi")
		if(val in ss):
			return False
		else:
			n=val
			ss.add(n)
	return True
def update(a,b):
	c=1
	val=a
	while(a<b):
		print(c,a)
		c+=c
		a+=a
	print(1)
	while(a>b):
		print()
		a-=val
		c-=1
	return c
import random as rand
def gcd(a,b): 
    if a == 0: 
        return b 
    return gcd(b % a, a) 
# nakdna
from itertools import permutations
if __name__ == '__main__':
	t=int(input())
	for i in range(t):
		x,y,z=map(int,input().split(" "))
		if(x==y and y==z):
			print("YES")
			print(x,x,x)
		elif(x==y and y!=z):
			if(z>x):
				print("NO")
			else:
				print("YES")
				print(x,z,z)
		elif(x==z and y!=z):
			if(y>x):
				print("NO")
			else:
				print("YES")
				print(x,y,y)
		elif(z==y and y!=x):
			if(x>y):
				print("NO")
			else:
				print("YES")
				print(x,x,z)
		else:
			print("NO")