Problem: You are given three positive (i.e. strictly greater than zero) integers x, y and z.

Your task is to find positive integers a, b and c such that x = max(a, b), y = max(a, c) and z = max(b, c), or determine that it is impossible to find such a, b and c.

You have to answer t independent test cases. Print required a, b and c in any (arbitrary) order.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers x, y, and z (1 ≤ x, y, z ≤ 10^9).

Output

For each test case, print the answer:

  * "NO" in the only line of the output if a solution doesn't exist; 
  * or "YES" in the first line and any valid triple of positive integers a, b and c (1 ≤ a, b, c ≤ 10^9) in the second line. You can print a, b and c in any order. 

Example

Input


5
3 2 3
100 100 100
50 49 49
10 30 20
1 1000000000 1000000000


Output


YES
3 2 1
YES
100 100 100
NO
NO
YES
1 1 1000000000

Solution (in PYTHON3):

Solution:
from sys import stdin,stdout
# from collections import deque,Counter,defaultdict
# from itertools import permutations,combinations,combinations_with_replacement
# from operator import itemgetter
# import heapq
# from functools import reduce
def ii():return int(stdin.readline())
def mi():return map(int,stdin.readline().split())
def li():return list(mi())
def si():return stdin.readline()

for _ in range(ii()):
    x,y,z = mi()
    max1 = max(max(x,y),z)
    if x==y and max1 == x:
        print('YES')
        print(x,z,z)
    elif y == z and max1 == y:
        print("YES")
        print(y,x,x)
    elif x == z and max1 == x:
        print("YES")
        print(x,y,y)
    else:
        print("NO")