Problem: You are given three positive (i.e. strictly greater than zero) integers x, y and z.

Your task is to find positive integers a, b and c such that x = max(a, b), y = max(a, c) and z = max(b, c), or determine that it is impossible to find such a, b and c.

You have to answer t independent test cases. Print required a, b and c in any (arbitrary) order.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers x, y, and z (1 ≤ x, y, z ≤ 10^9).

Output

For each test case, print the answer:

  * "NO" in the only line of the output if a solution doesn't exist; 
  * or "YES" in the first line and any valid triple of positive integers a, b and c (1 ≤ a, b, c ≤ 10^9) in the second line. You can print a, b and c in any order. 

Example

Input


5
3 2 3
100 100 100
50 49 49
10 30 20
1 1000000000 1000000000


Output


YES
3 2 1
YES
100 100 100
NO
NO
YES
1 1 1000000000

Solution (in PYTHON3):

Solution:
def f():
    t = int(input())
    arr = []
    for _ in range(t):
        x,y,z = list(map(int, input().split(' ')))
        arr.append((x,y,z))
    
    # O(n^2)?
    for x,y,z in arr:
        sx, sy, sz = sorted([x,y,z])

        # bad case: all different or only bottom 2 are same
        if (sx <= sy and sy < sz):
            print('NO')
            continue

        print('YES')
        # good cases: all same or top 2 are same
        if x == y == z:
            print(f'{x} {y} {z}')
        elif x == y or y == z:
            print(f'{x} 1 {z}')
        elif x == z:
            print(f'{x} {y} 1')


f()