Problem: You are given three positive (i.e. strictly greater than zero) integers x, y and z.

Your task is to find positive integers a, b and c such that x = max(a, b), y = max(a, c) and z = max(b, c), or determine that it is impossible to find such a, b and c.

You have to answer t independent test cases. Print required a, b and c in any (arbitrary) order.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers x, y, and z (1 ≤ x, y, z ≤ 10^9).

Output

For each test case, print the answer:

  * "NO" in the only line of the output if a solution doesn't exist; 
  * or "YES" in the first line and any valid triple of positive integers a, b and c (1 ≤ a, b, c ≤ 10^9) in the second line. You can print a, b and c in any order. 

Example

Input


5
3 2 3
100 100 100
50 49 49
10 30 20
1 1000000000 1000000000


Output


YES
3 2 1
YES
100 100 100
NO
NO
YES
1 1 1000000000

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.*;
 
public class test
{
      public static void main(String[] args)
      {
        Scanner sc = new Scanner(System.in);
           
        int n = sc.nextInt();

        for (int i = 0; i<=n; i++) {
            String[] data = sc.nextLine().split(" ");
                if(i>0)
                solution(data);
        }
    }

    public static void solution(String[] data){
        int x=Integer.parseInt(data[0]), y = Integer.parseInt(data[1]), z = Integer.parseInt(data[2]);
        if(x==y && y==z){
            System.out.println("YES");
            System.out.println(x+" "+y+" "+z);
        }else if(x!=y && y!=z && x!=z){
            System.out.println("NO");
        }else if((x==y && y<z )||(y==z && z<x)||(x==z && x<y)){
            System.out.println("NO");
        }
        else{
            if(x>y && x==z){
                System.out.println("YES");
                System.out.println(x+" "+y+" "+1);
            }else if(y>z & y==x){
                System.out.println("YES");
                System.out.println(y+" "+z+" "+1);
            }else if(y==z&& y>x){
                System.out.println("YES");
                System.out.println(y+" "+x+" "+1);
            }
        }       
    }
 }