Problem: Ashish has n elements arranged in a line. 

These elements are represented by two integers a_i — the value of the element and b_i — the type of the element (there are only two possible types: 0 and 1). He wants to sort the elements in non-decreasing values of a_i.

He can perform the following operation any number of times: 

  * Select any two elements i and j such that b_i ≠ b_j and swap them. That is, he can only swap two elements of different types in one move. 



Tell him if he can sort the elements in non-decreasing values of a_i after performing any number of operations.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. The description of the test cases follows.

The first line of each test case contains one integer n (1 ≤ n ≤ 500) — the size of the arrays.

The second line contains n integers a_i (1 ≤ a_i ≤ 10^5) — the value of the i-th element.

The third line containts n integers b_i (b_i ∈ \{0, 1\}) — the type of the i-th element.

Output

For each test case, print "Yes" or "No" (without quotes) depending on whether it is possible to sort elements in non-decreasing order of their value.

You may print each letter in any case (upper or lower).

Example

Input


5
4
10 20 20 30
0 1 0 1
3
3 1 2
0 1 1
4
2 2 4 8
1 1 1 1
3
5 15 4
0 0 0
4
20 10 100 50
1 0 0 1


Output


Yes
Yes
Yes
No
Yes

Note

For the first case: The elements are already in sorted order.

For the second case: Ashish may first swap elements at positions 1 and 2, then swap elements at positions 2 and 3.

For the third case: The elements are already in sorted order.

For the fourth case: No swap operations may be performed as there is no pair of elements i and j such that b_i ≠ b_j. The elements cannot be sorted.

For the fifth case: Ashish may swap elements at positions 3 and 4, then elements at positions 1 and 2.

Solution (in JAVA):

Solution:
import java.util.Scanner;

public class Solution {

    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int testCases = sc.nextInt();

        while(testCases-- > 0){
            int n = sc.nextInt();
            int[] values = new int[n];
            int[] type = new int[n];

            for(int i = 0; i < n; i++){
                values[i] = sc.nextInt();
            }

            for(int i = 0; i < n; i++){
                type[i] = sc.nextInt();
            }

            //check if elements are already sorted
            boolean sorted = true;

            for(int i = 1; i < n; i++){
                if(values[i] < values[i - 1]){
                    sorted = false;
                    break;
                }
            }

            if(sorted){
                System.out.println("Yes");
                continue;
            }

            // check if there are both types present
            boolean typeZero = false;
            boolean typeOne = false;

            for(int num : type){
                if(num == 0){
                    typeZero = true;
                    continue;
                }

                if(num == 1){
                    typeOne = true;
                    continue;
                }
            }

            if(typeOne && typeZero){
                System.out.println("Yes");
            } else {
                System.out.println("No");
            }

        }



    }
}