Problem: You are given three positive (i.e. strictly greater than zero) integers x, y and z.

Your task is to find positive integers a, b and c such that x = max(a, b), y = max(a, c) and z = max(b, c), or determine that it is impossible to find such a, b and c.

You have to answer t independent test cases. Print required a, b and c in any (arbitrary) order.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers x, y, and z (1 ≤ x, y, z ≤ 10^9).

Output

For each test case, print the answer:

  * "NO" in the only line of the output if a solution doesn't exist; 
  * or "YES" in the first line and any valid triple of positive integers a, b and c (1 ≤ a, b, c ≤ 10^9) in the second line. You can print a, b and c in any order. 

Example

Input


5
3 2 3
100 100 100
50 49 49
10 30 20
1 1000000000 1000000000


Output


YES
3 2 1
YES
100 100 100
NO
NO
YES
1 1 1000000000

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.*;

public class Solution {

    public static void main(String[] args) {
        /* Enter your code here. Read input from STDIN. Print output to STDOUT. Your class should be named Solution. */
        Scanner sc = new Scanner(System.in);
        int t = sc.nextInt();
        for(int i=0; i<t; i++){
            long x = sc.nextLong();
            long y = sc.nextLong();
            long z = sc.nextLong();
            if(x != y && x != z && y != z){
                System.out.println("NO");
            } else {
                if((x == y) && (x == z) && (y==z)){
                    System.out.println("YES");
                    System.out.println(x+" "+x+" "+x);
                }else if((x == y && x<z) || (x==z && x<y) || (y==z && y<x)){
                    System.out.println("NO");
                } else {
                    long max = x>=y ? x>=z ? x : z : y>=z ? y : z;
                    long min = x<=y ? x<=z ? x : z : y<=z ? y : z;
                    if(min==1){
                        System.out.println("YES");
                        System.out.println(max+" "+min+" "+(min));
                    } else {
                        System.out.println("YES");
                        System.out.println(max+" "+min+" "+(min-1));
                    }
                }
            }
        }
    }
}