Problem: You are given three positive (i.e. strictly greater than zero) integers x, y and z.

Your task is to find positive integers a, b and c such that x = max(a, b), y = max(a, c) and z = max(b, c), or determine that it is impossible to find such a, b and c.

You have to answer t independent test cases. Print required a, b and c in any (arbitrary) order.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers x, y, and z (1 ≤ x, y, z ≤ 10^9).

Output

For each test case, print the answer:

  * "NO" in the only line of the output if a solution doesn't exist; 
  * or "YES" in the first line and any valid triple of positive integers a, b and c (1 ≤ a, b, c ≤ 10^9) in the second line. You can print a, b and c in any order. 

Example

Input


5
3 2 3
100 100 100
50 49 49
10 30 20
1 1000000000 1000000000


Output


YES
3 2 1
YES
100 100 100
NO
NO
YES
1 1 1000000000

Solution (in PYTHON3):

Solution:
from sys import stdin,stdout
import math 
from collections import Counter,deque
L=lambda:list(map(int, stdin.readline().strip().split()))
M=lambda:map(int, stdin.readline().strip().split())
I=lambda:int(stdin.readline().strip())
IN=lambda:stdin.readline().strip()
C=lambda:stdin.readline().strip().split()
mod=1000000007
#Keymax = max(Tv, key=Tv.get)
def s(a):print(" ".join(list(map(str,a))))
#______________________-------------------------------_____________________#
#I_am_pavan
def solve():
    x,y,z=M()
    if max(y,z)<x or max(x,y)<z or max(x,z)<y:
        print("NO")
    else:
        print("YES")
        print(min(x,y),min(y,z),min(x,z))
for _ in range(I()):
    solve()