Problem: You are given three positive (i.e. strictly greater than zero) integers x, y and z.

Your task is to find positive integers a, b and c such that x = max(a, b), y = max(a, c) and z = max(b, c), or determine that it is impossible to find such a, b and c.

You have to answer t independent test cases. Print required a, b and c in any (arbitrary) order.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers x, y, and z (1 ≤ x, y, z ≤ 10^9).

Output

For each test case, print the answer:

  * "NO" in the only line of the output if a solution doesn't exist; 
  * or "YES" in the first line and any valid triple of positive integers a, b and c (1 ≤ a, b, c ≤ 10^9) in the second line. You can print a, b and c in any order. 

Example

Input


5
3 2 3
100 100 100
50 49 49
10 30 20
1 1000000000 1000000000


Output


YES
3 2 1
YES
100 100 100
NO
NO
YES
1 1 1000000000

Solution (in JAVA):

Solution:
import java.util.*;

public class Solution {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        int test_case = scanner.nextInt();
        
        for(int i = 0; i < test_case; ++i)
        {
            int x = scanner.nextInt();
            int y = scanner.nextInt();
            int z = scanner.nextInt();
            
            if(x == y || x == z || y == z)
            {
                if(x == y)
                {
                    if(z > x) System.out.println("NO");
                    else {
                         System.out.println("YES");
                        System.out.println(x+ " " + z + " " + z);
                    }
                }
                else if(x == z)
                {
                    if(y > x) System.out.println("NO");
                    else {
                        System.out.println("YES");
                        System.out.println(x+ " " + y + " " + y);
                    }
                }
                else{
                      if(x > y) System.out.println("NO");
                    else {
                          System.out.println("YES");
                          System.out.println(y+ " " + x + " " + x);
                      }  
                }
            }
            else System.out.println("NO");
        }
    }
}