Problem: You are given three positive (i.e. strictly greater than zero) integers x, y and z.

Your task is to find positive integers a, b and c such that x = max(a, b), y = max(a, c) and z = max(b, c), or determine that it is impossible to find such a, b and c.

You have to answer t independent test cases. Print required a, b and c in any (arbitrary) order.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers x, y, and z (1 ≤ x, y, z ≤ 10^9).

Output

For each test case, print the answer:

  * "NO" in the only line of the output if a solution doesn't exist; 
  * or "YES" in the first line and any valid triple of positive integers a, b and c (1 ≤ a, b, c ≤ 10^9) in the second line. You can print a, b and c in any order. 

Example

Input


5
3 2 3
100 100 100
50 49 49
10 30 20
1 1000000000 1000000000


Output


YES
3 2 1
YES
100 100 100
NO
NO
YES
1 1 1000000000

Solution (in PYTHON3):

Solution:
for _ in range(int(input())):
	x,y,z = list(map(int, input().split()))
	if x==y:
		a=x
		b=z
		c=b
		if c>0 and a>=b and b>=c:
			print('YES')
			print(a,b,c)
			continue
		c=z
		b=c
		if b>0 and a>=c and c>=b:
			print('YES')
			print(a,b,c)
			continue
		print('NO')
	elif x==z:
		a=y
		b=x
		c=a
		if c>0 and b>=a and a>=c:
			print('YES')
			print(a,b,c)
			continue
		c=y
		a=c
		if a>0 and b>=c and c>=a:
			print('YES')
			print(a,b,c)
			continue
		print('NO')
	elif y==z:
		a=x
		c=y
		b=a
		if b>=0 and c>=a and a>=b:
			print('YES')
			print(a,b,c)
			continue
		b=x
		a=b
		if a>0 and c>=b and b>=a:
			print('YES')
			print(a,b,c)
			continue
		print('NO')
	else:
		print('NO')