Problem: There is a grid of square cells with H horizontal rows and W vertical columns. The cell at the i-th row and the j-th column will be denoted as Cell (i, j).

In Cell (i, j), a_{ij} coins are placed.

You can perform the following operation any number of times:

Operation: Choose a cell that was not chosen before and contains one or more coins, then move one of those coins to a vertically or horizontally adjacent cell.

Maximize the number of cells containing an even number of coins.

Constraints

* All values in input are integers.
* 1 \leq H, W \leq 500
* 0 \leq a_{ij} \leq 9

Input

Input is given from Standard Input in the following format:


H W
a_{11} a_{12} ... a_{1W}
a_{21} a_{22} ... a_{2W}
:
a_{H1} a_{H2} ... a_{HW}


Output

Print a sequence of operations that maximizes the number of cells containing an even number of coins, in the following format:


N
y_1 x_1 y_1' x_1'
y_2 x_2 y_2' x_2'
:
y_N x_N y_N' x_N'


That is, in the first line, print an integer N between 0 and H \times W (inclusive), representing the number of operations.

In the (i+1)-th line (1 \leq i \leq N), print four integers y_i, x_i, y_i' and x_i' (1 \leq y_i, y_i' \leq H and 1 \leq x_i, x_i' \leq W), representing the i-th operation. These four integers represents the operation of moving one of the coins placed in Cell (y_i, x_i) to a vertically or horizontally adjacent cell, (y_i', x_i').

Note that if the specified operation violates the specification in the problem statement or the output format is invalid, it will result in Wrong Answer.

Examples

Input

2 3
1 2 3
0 1 1


Output

3
2 2 2 3
1 1 1 2
1 3 1 2


Input

3 2
1 0
2 1
1 0


Output

3
1 1 1 2
1 2 2 2
3 1 3 2


Input

1 5
9 9 9 9 9


Output

2
1 1 1 2
1 3 1 4

Solution (in JAVA):

Solution:
import java.io.OutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.PrintWriter;
import java.util.Scanner;

/**
 * Built using CHelper plug-in
 * Actual solution is at the top
*/public class Main {
	public static void main(String[] args) {
		InputStream inputStream = System.in;
		OutputStream outputStream = System.out;
		Scanner in = new Scanner(inputStream);
		PrintWriter out = new PrintWriter(outputStream);
		TaskD solver = new TaskD();
		solver.solve(1, in, out);
		out.close();
	}
static class TaskD   {
public void solve(int testNumber, Scanner in, PrintWriter out) {
        int H = in.nextInt();
        int W = in.nextInt();
        int a[][] = new int[H][W];
        for(int ih=0; ih<H; ih++){
            for(int iw=0; iw<W; iw++){
                a[ih][iw] = in.nextInt();
            }
        }
        int n = 0;
        String ans[] = new String[H*W];
        for(int ih=0; ih<H; ih++){
            for(int iw=0; iw<W-1; iw++){
                if(a[ih][iw]%2 != 0){
                    ans[n] = (ih+1)+" "+(iw+1)+" "+(ih+1)+" "+(iw+2);
                    n++;
                    a[ih][iw+1]++;
                }
            }
        }
        for(int ih=0; ih<H-1; ih++){
            if(a[ih][W-1]%2 != 0){
                ans[n] = (ih+1)+" "+W+" "+(ih+2)+" "+W;
                n++;
                a[ih+1][W-1]++;
            }
        }
        out.println(n);
        for(int i=0; i<n; i++) out.println(ans[i]);
    }

}
}