Problem: You are given three positive (i.e. strictly greater than zero) integers x, y and z.

Your task is to find positive integers a, b and c such that x = max(a, b), y = max(a, c) and z = max(b, c), or determine that it is impossible to find such a, b and c.

You have to answer t independent test cases. Print required a, b and c in any (arbitrary) order.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers x, y, and z (1 ≤ x, y, z ≤ 10^9).

Output

For each test case, print the answer:

  * "NO" in the only line of the output if a solution doesn't exist; 
  * or "YES" in the first line and any valid triple of positive integers a, b and c (1 ≤ a, b, c ≤ 10^9) in the second line. You can print a, b and c in any order. 

Example

Input


5
3 2 3
100 100 100
50 49 49
10 30 20
1 1000000000 1000000000


Output


YES
3 2 1
YES
100 100 100
NO
NO
YES
1 1 1000000000

Solution (in PYTHON3):

Solution:
import sys
from math import floor as fl
from math import ceil as ce
from math import sqrt
cont = sys.stdin.readlines()
cont = [i.strip('\n').split() for i in cont]
num = int(cont.pop(0)[0])

for i in cont:
    x,y,z = [int(j) for j in i]

    #first do the NO cases
    #the max has to occur twice
    if len(set([x,y,z])) == 3 or [x,y,z].count(max(x,y,z)) == 1:
        print("NO")
    else:
        maxx = max(x,y,z)
        minn = min(x,y,z)
        print(f"YES\n{maxx} {minn} {minn}")