Problem: You are given three positive (i.e. strictly greater than zero) integers x, y and z.

Your task is to find positive integers a, b and c such that x = max(a, b), y = max(a, c) and z = max(b, c), or determine that it is impossible to find such a, b and c.

You have to answer t independent test cases. Print required a, b and c in any (arbitrary) order.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers x, y, and z (1 ≤ x, y, z ≤ 10^9).

Output

For each test case, print the answer:

  * "NO" in the only line of the output if a solution doesn't exist; 
  * or "YES" in the first line and any valid triple of positive integers a, b and c (1 ≤ a, b, c ≤ 10^9) in the second line. You can print a, b and c in any order. 

Example

Input


5
3 2 3
100 100 100
50 49 49
10 30 20
1 1000000000 1000000000


Output


YES
3 2 1
YES
100 100 100
NO
NO
YES
1 1 1000000000

Solution (in JAVA):

Solution:
/* package codechef; // don't place package name! */

import java.util.*;
import java.lang.*;
import java.io.*;

/* Name of the class has to be "Main" only if the class is public. */
public class Codechef
{
	public static void main (String[] args) throws java.lang.Exception
	{
		// your code goes here
		BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
		int t=Integer.parseInt(br.readLine());
		while(t-- >0){
		    //int n=Integer.parseInt(br.readLine());
		    String s[]=br.readLine().split(" ");
		    int x=Integer.parseInt(s[0]);
		    int y=Integer.parseInt(s[1]);
		    int z=Integer.parseInt(s[2]);
		    int aa=1;
		    if(x==y && x>=z){
		        System.out.println("YES");
		        System.out.println(aa+" "+x+" "+z);
		    }
		    else if(y==z && y>=x){
		        System.out.println("YES");
		        System.out.println(aa+" "+x+" "+z);
		    }
		    else if(x==z && x>=y){
		        System.out.println("YES");
		        System.out.println(aa+" "+x+" "+y);
		    }
		    else 
		    System.out.println("NO");
		}
	}
}