Problem: A permutation of length n is a sequence of integers from 1 to n of length n containing each number exactly once. For example, [1], [4, 3, 5, 1, 2], [3, 2, 1] are permutations, and [1, 1], [0, 1], [2, 2, 1, 4] are not.

There was a permutation p[1 ... n]. It was merged with itself. In other words, let's take two instances of p and insert elements of the second p into the first maintaining relative order of elements. The result is a sequence of the length 2n.

For example, if p=[3, 1, 2] some possible results are: [3, 1, 2, 3, 1, 2], [3, 3, 1, 1, 2, 2], [3, 1, 3, 1, 2, 2]. The following sequences are not possible results of a merging: [1, 3, 2, 1, 2, 3], [3, 1, 2, 3, 2, 1], [3, 3, 1, 2, 2, 1].

For example, if p=[2, 1] the possible results are: [2, 2, 1, 1], [2, 1, 2, 1]. The following sequences are not possible results of a merging: [1, 1, 2, 2], [2, 1, 1, 2], [1, 2, 2, 1].

Your task is to restore the permutation p by the given resulting sequence a. It is guaranteed that the answer exists and is unique.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 400) — the number of test cases. Then t test cases follow.

The first line of the test case contains one integer n (1 ≤ n ≤ 50) — the length of permutation. The second line of the test case contains 2n integers a_1, a_2, ..., a_{2n} (1 ≤ a_i ≤ n), where a_i is the i-th element of a. It is guaranteed that the array a represents the result of merging of some permutation p with the same permutation p.

Output

For each test case, print the answer: n integers p_1, p_2, ..., p_n (1 ≤ p_i ≤ n), representing the initial permutation. It is guaranteed that the answer exists and is unique.

Example

Input


5
2
1 1 2 2
4
1 3 1 4 3 4 2 2
5
1 2 1 2 3 4 3 5 4 5
3
1 2 3 1 2 3
4
2 3 2 4 1 3 4 1


Output


1 2 
1 3 4 2 
1 2 3 4 5 
1 2 3 
2 3 4 1 

Solution (in PYTHON3):

Solution:
import sys,math,collections
from collections import defaultdict

#from itertools import permutations,combinations
	
def file():
	sys.stdin = open('input.py', 'r')
	sys.stdout = open('output.py', 'w') 
def get_array():
	l=list(map(int, input().split()))
	return l
def get_2_ints():	
	a,b=map(int, input().split())
	return a,b
def get_3_ints():	
	a,b,c=map(int, input().split())
	return a,b,c	
def sod(n):
	n,c=str(n),0
	for i in n:	
		c+=int(i)
	return c	

def getFloor(A, x):

	(left, right) = (0, len(A) - 1)

	floor = -1
	while left <= right:
		mid = (left + right) // 2
		if A[mid] == x:
			return A[mid]
		elif x < A[mid]:
			right = mid - 1
		else:
			floor = A[mid]
			left = mid + 1
			
	return floor
#file()	
def main():
	for tt in range(int(input())):
		n=int(input())
		l=get_array()
		c=collections.Counter(l)
		ans=[]
		for i in l:
			if(c[i]):
				ans.append(i)
				c[i]=c[i]-2
		print(*ans)		


















				

			







            
			
































		








if __name__ == '__main__':
    main()