Problem: You are given three positive (i.e. strictly greater than zero) integers x, y and z.

Your task is to find positive integers a, b and c such that x = max(a, b), y = max(a, c) and z = max(b, c), or determine that it is impossible to find such a, b and c.

You have to answer t independent test cases. Print required a, b and c in any (arbitrary) order.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers x, y, and z (1 ≤ x, y, z ≤ 10^9).

Output

For each test case, print the answer:

  * "NO" in the only line of the output if a solution doesn't exist; 
  * or "YES" in the first line and any valid triple of positive integers a, b and c (1 ≤ a, b, c ≤ 10^9) in the second line. You can print a, b and c in any order. 

Example

Input


5
3 2 3
100 100 100
50 49 49
10 30 20
1 1000000000 1000000000


Output


YES
3 2 1
YES
100 100 100
NO
NO
YES
1 1 1000000000

Solution (in JAVA):

Solution:

import java.util.*;
import java.io.*;
public class Solution{

    static class Pair<A, B> {

        A parent;
        B rank;

        Pair(A parent, B rank) {
            this.rank = rank;
            this.parent = parent;
        }
    }

    static class Node {
        int i;
        int j;
        Node(int k,int l)
        {
            i=k;j=l;
        }
    }
    static int m=1000000007;
    public static void main(String[] args) throws IOException {
        FastReader s1 = new FastReader();
        StringBuilder sb = new StringBuilder();
        int t=s1.I();
        while(t--!=0)
        {
            int ar[] = new int[3];
            for(int i=0;i<3;i++)
                ar[i]=s1.I();
            Arrays.sort(ar);
            if(ar[2]!=ar[1])
            {
                sb.append("NO\n");
                continue;
            }
            if(ar[0]==ar[1] && ar[1]!=ar[2])
            {
                sb.append("NO\n");
                continue;
            }
            sb.append("YES\n");
            sb.append(ar[2]+" "+(ar[0])+" "+(ar[0])+"\n");
        }
        System.out.println(sb);
    }
    static void dfs(boolean flag[][],int i,int j,char ar[][])
    {
        flag[i][j]=true;
        if(i>0 && ar[i-1][j]!='#' && flag[i-1][j]==false)
        {
            dfs(flag,i-1,j,ar);
        }
        if(j>0 && ar[i][j-1]!='#' && flag[i][j-1]==false)
        {
            dfs(flag,i,j-1,ar);
        }
    }
    static class FastReader {

        BufferedReader br;
        StringTokenizer st;

        public FastReader() {
            br = new BufferedReader(new InputStreamReader(System.in));
        }

        String next() {
            while (st == null || !st.hasMoreElements()) {
                try {
                    st = new StringTokenizer(br.readLine());
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
            return st.nextToken();
        }

        int I() {
            return Integer.parseInt(next());
        }

        long L() {
            return Long.parseLong(next());
        }

        double D() {
            return Double.parseDouble(next());
        }

        String nextLine() {
            String str = "";
            try {
                str = br.readLine();
            } catch (IOException e) {
                e.printStackTrace();
            }
            return str;
        }
    }

    static long gcd(long a, long b) {
        if (a % b == 0) {
            return b;
        }
        return gcd(b, a % b);
    }

    static float power(float x, int y) {
        float temp;
        if (y == 0) {
            return 1;
        }
        temp = power(x, y / 2);

        if (y % 2 == 0) {
            return temp * temp;
        } else {
            if (y > 0) {
                return x * temp * temp;
            } else {
                return (temp * temp) / x;
            }
        }
    }
    static long pow(long x, long y) {
        long res = 1;
        x = x % m;
        if (x < 0) {
            x += m;
        }
        while (y > 0) {
            if ((y & 1) == 1) {
                res = (res * x) % m;
                if (res < 0) {
                    res += m;
                }
            }
            y = y >> 1;
            x = (x * x) % m;
            if (x < 0) {
                x = x + m;
            }
        }
        res = res % m;
        if (res < 0) {
            res += m;
        }
        return res;
    }

    static void sieveOfEratosthenes(int n) {
        ArrayList<Integer> prime = new ArrayList<Integer>();
        boolean Prime[] = new boolean[n + 1];
        for (int i = 2; i < n; i++) {
            Prime[i] = true;
        }

        for (int p = 2; p * p <= n; p++) {
            if (Prime[p] == true) {
                prime.add(p);
                for (int i = p * p; i <= n; i += p) {
                    Prime[i] = false;
                }
            }
        }
    }
}