Problem: There is a grid of square cells with H horizontal rows and W vertical columns. The cell at the i-th row and the j-th column will be denoted as Cell (i, j).

In Cell (i, j), a_{ij} coins are placed.

You can perform the following operation any number of times:

Operation: Choose a cell that was not chosen before and contains one or more coins, then move one of those coins to a vertically or horizontally adjacent cell.

Maximize the number of cells containing an even number of coins.

Constraints

* All values in input are integers.
* 1 \leq H, W \leq 500
* 0 \leq a_{ij} \leq 9

Input

Input is given from Standard Input in the following format:


H W
a_{11} a_{12} ... a_{1W}
a_{21} a_{22} ... a_{2W}
:
a_{H1} a_{H2} ... a_{HW}


Output

Print a sequence of operations that maximizes the number of cells containing an even number of coins, in the following format:


N
y_1 x_1 y_1' x_1'
y_2 x_2 y_2' x_2'
:
y_N x_N y_N' x_N'


That is, in the first line, print an integer N between 0 and H \times W (inclusive), representing the number of operations.

In the (i+1)-th line (1 \leq i \leq N), print four integers y_i, x_i, y_i' and x_i' (1 \leq y_i, y_i' \leq H and 1 \leq x_i, x_i' \leq W), representing the i-th operation. These four integers represents the operation of moving one of the coins placed in Cell (y_i, x_i) to a vertically or horizontally adjacent cell, (y_i', x_i').

Note that if the specified operation violates the specification in the problem statement or the output format is invalid, it will result in Wrong Answer.

Examples

Input

2 3
1 2 3
0 1 1


Output

3
2 2 2 3
1 1 1 2
1 3 1 2


Input

3 2
1 0
2 1
1 0


Output

3
1 1 1 2
1 2 2 2
3 1 3 2


Input

1 5
9 9 9 9 9


Output

2
1 1 1 2
1 3 1 4

Solution (in JAVA):

Solution:

import java.util.*;

public class Main {
	public static void main(String[] args) {
		Main main = new Main();
		main.run();
	}

	public void run() {
		Scanner sc = new Scanner(System.in);
		int h = sc.nextInt();
		int w = sc.nextInt();
		int a[][] = new int[h][w];
		for(int i=0; i<h; i++) {
			for(int j=0; j<w; j++) {
				a[i][j]=sc.nextInt();
			}
		}

		int s[][] = new int[500*500][4];
		int cnt = 0;
		for(int i=0; i<h-1; i++) {
			for(int j=0; j<w; j++) {
				if(a[i][j] % 2 != 0) {
					a[i][j]--;
					a[i+1][j]++;
					s[cnt][0] = i+1;
					s[cnt][1] = j+1;
					s[cnt][2] = i+2;
					s[cnt][3] = j+1;
					cnt++;
				}
			}
		}
		for(int j=0; j<w-1; j++) {
			if(a[h-1][j] % 2 != 0) {
				a[h-1][j]--;
				a[h-1][j+1]++;
				s[cnt][0] = h;
				s[cnt][1] = j+1;
				s[cnt][2] = h;
				s[cnt][3] = j+2;
				cnt++;
			}
		}

		System.out.println(cnt);
		for(int i=0; i<cnt; i++) {
			System.out.println(s[i][0] + " " + s[i][1] + " " + s[i][2] + " " + s[i][3]);
		}
		sc.close();
	}


}