Problem: You are given three positive (i.e. strictly greater than zero) integers x, y and z.

Your task is to find positive integers a, b and c such that x = max(a, b), y = max(a, c) and z = max(b, c), or determine that it is impossible to find such a, b and c.

You have to answer t independent test cases. Print required a, b and c in any (arbitrary) order.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers x, y, and z (1 ≤ x, y, z ≤ 10^9).

Output

For each test case, print the answer:

  * "NO" in the only line of the output if a solution doesn't exist; 
  * or "YES" in the first line and any valid triple of positive integers a, b and c (1 ≤ a, b, c ≤ 10^9) in the second line. You can print a, b and c in any order. 

Example

Input


5
3 2 3
100 100 100
50 49 49
10 30 20
1 1000000000 1000000000


Output


YES
3 2 1
YES
100 100 100
NO
NO
YES
1 1 1000000000

Solution (in JAVA):

Solution:
import java.util.*;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.BufferedReader;

public class CF_A_1385
{
    public static void main(String[] args) throws IOException
    {
        long t = readLong();
        for (int __ = 0; __ < t; __++)
        {
            long x = readLong();
            long y = readLong();
            long z = readLong();

            if (x != y && x != z && y != z)
            {
                System.out.println("NO");
            }
            else if (x == y && y == z)
            {
                System.out.println("YES");
                System.out.println((x + " ").repeat(3));
            }
            else
            {
                if (x == y && z > x)
                {
                    System.out.println("NO");
                }
                else if (x == z && y > x)
                {
                    System.out.println("NO");
                }
                else if (y == z && x > y)
                {
                    System.out.println("NO");
                }
                else
                {
                    System.out.println("YES");
                    if (x == z)
                    {
                        System.out.println(x + " " + y + " 1");
                    }
                    else
                    {
                        System.out.println(x + " " + z + " 1");
                    }
                }
            }
        }
    }

    static BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
    static StringTokenizer st;

    static long readLong() throws IOException
    {
        while (st == null || !st.hasMoreTokens())
        {
            st = new StringTokenizer(br.readLine());
        }
        return Long.parseLong(st.nextToken());
    }
}