Problem: Ashish has n elements arranged in a line. 

These elements are represented by two integers a_i — the value of the element and b_i — the type of the element (there are only two possible types: 0 and 1). He wants to sort the elements in non-decreasing values of a_i.

He can perform the following operation any number of times: 

  * Select any two elements i and j such that b_i ≠ b_j and swap them. That is, he can only swap two elements of different types in one move. 



Tell him if he can sort the elements in non-decreasing values of a_i after performing any number of operations.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. The description of the test cases follows.

The first line of each test case contains one integer n (1 ≤ n ≤ 500) — the size of the arrays.

The second line contains n integers a_i (1 ≤ a_i ≤ 10^5) — the value of the i-th element.

The third line containts n integers b_i (b_i ∈ \{0, 1\}) — the type of the i-th element.

Output

For each test case, print "Yes" or "No" (without quotes) depending on whether it is possible to sort elements in non-decreasing order of their value.

You may print each letter in any case (upper or lower).

Example

Input


5
4
10 20 20 30
0 1 0 1
3
3 1 2
0 1 1
4
2 2 4 8
1 1 1 1
3
5 15 4
0 0 0
4
20 10 100 50
1 0 0 1


Output


Yes
Yes
Yes
No
Yes

Note

For the first case: The elements are already in sorted order.

For the second case: Ashish may first swap elements at positions 1 and 2, then swap elements at positions 2 and 3.

For the third case: The elements are already in sorted order.

For the fourth case: No swap operations may be performed as there is no pair of elements i and j such that b_i ≠ b_j. The elements cannot be sorted.

For the fifth case: Ashish may swap elements at positions 3 and 4, then elements at positions 1 and 2.

Solution (in JAVA):

Solution:
import java.util.*;
 
public class Main{
    public static void main(String[] args){
        Scanner s = new Scanner(System.in);
        int t = s.nextInt();
        
        while(t-->0){
            boolean one = false;
            
            boolean zero = false;
            int n = s.nextInt();
            int[] arr = new int[n];
            for(int i=0; i<n ;i++){
               arr[i]=s.nextInt();
            }
              
            for(int i=0; i<n ;i++){
                int x = s.nextInt();
                if(x==0)
                zero = true;
                else if(x==1)
                one = true;
                
            }
            boolean sorted = true;
            
            for(int i=0; i<arr.length-1; i++){
                if(arr[i+1]-arr[i]<0)
                sorted = false;
                
            }
            

          if(sorted)
          System.out.println("Yes");
          else{
            if(zero&&one)
            System.out.println("Yes");
            else
            System.out.println("No");
        }
        }
    }
}