Problem: You are given three positive (i.e. strictly greater than zero) integers x, y and z.

Your task is to find positive integers a, b and c such that x = max(a, b), y = max(a, c) and z = max(b, c), or determine that it is impossible to find such a, b and c.

You have to answer t independent test cases. Print required a, b and c in any (arbitrary) order.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers x, y, and z (1 ≤ x, y, z ≤ 10^9).

Output

For each test case, print the answer:

  * "NO" in the only line of the output if a solution doesn't exist; 
  * or "YES" in the first line and any valid triple of positive integers a, b and c (1 ≤ a, b, c ≤ 10^9) in the second line. You can print a, b and c in any order. 

Example

Input


5
3 2 3
100 100 100
50 49 49
10 30 20
1 1000000000 1000000000


Output


YES
3 2 1
YES
100 100 100
NO
NO
YES
1 1 1000000000

Solution (in JAVA):

Solution:
import java.util.*;
import java.io.*;

public class test{
    public static void main (String[] args) 
	{
	    Scanner s =new Scanner(System.in);
	    int t=s.nextInt();
	    while(t>0){
	            long a=s.nextLong();
	            long b=s.nextLong();
	            long c=s.nextLong();
	            if(a==b){
                    if (b>=c){
                        long z=c-1;
                        if(z==0){
                            System.out.println("YES");
                            System.out.println(b+" "+c+" "+c);
                        }
                        else {
                            System.out.println("YES");
                            System.out.println(b+" "+c+" "+z);
                        }
                       
                    }else{
                        System.out.println("NO");
                    }
                }
                else if (a==c){
                    if (a>=b){
                        long z=b-1;
                        if(z==0){
                            System.out.println("YES");
                            System.out.println(a+" "+b+" "+b);
                        }
                        else {
                            System.out.println("YES");
                            System.out.println(a+" "+b+" "+z);
                        }
                       
                    }else{
                        System.out.println("NO");
                    }

                }
                else if(b==c){
                     if (b>=a){
                        long z=a-1;
                        if(z==0){
                            System.out.println("YES");
                            System.out.println(b+" "+a+" "+a);
                        }
                        else {
                            System.out.println("YES");
                            System.out.println(b+" "+a+" "+z);
                        }
                       
                    }else{
                        System.out.println("NO");
                    }

                }
                else System.out.println("NO");
	        
	        t--;
        }
        s.close();
	}
}