Problem: You are given three positive (i.e. strictly greater than zero) integers x, y and z.

Your task is to find positive integers a, b and c such that x = max(a, b), y = max(a, c) and z = max(b, c), or determine that it is impossible to find such a, b and c.

You have to answer t independent test cases. Print required a, b and c in any (arbitrary) order.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers x, y, and z (1 ≤ x, y, z ≤ 10^9).

Output

For each test case, print the answer:

  * "NO" in the only line of the output if a solution doesn't exist; 
  * or "YES" in the first line and any valid triple of positive integers a, b and c (1 ≤ a, b, c ≤ 10^9) in the second line. You can print a, b and c in any order. 

Example

Input


5
3 2 3
100 100 100
50 49 49
10 30 20
1 1000000000 1000000000


Output


YES
3 2 1
YES
100 100 100
NO
NO
YES
1 1 1000000000

Solution (in PYTHON3):

Solution:
t=int(input())
d=[]
for i in range(t):
    x,y,z=input().split()
    x,y,z=int(x),int(y),int(z)
    if x==y and y==z:
        a=x 
        b=x 
        c=x 
        d.append("YES")
        d.append(str(a)+" "+str(b)+" "+str(c))
    elif x==y:
        if z<=x:
            a=x 
            b=z 
            c=z
            d.append("YES")
            d.append(str(a)+" "+str(b)+" "+str(c))
        else:
            d.append("NO")
    elif y==z:
        if x<=y:
            a=y  
            b=x 
            c=x 
            d.append("YES")
            d.append(str(a)+" "+str(b)+" "+str(c))
        else:
            d.append("NO")
        
    elif z==x:
        if y<=x:
            a=x 
            b=y   
            c=y
            d.append("YES")
            d.append(str(a)+" "+str(b)+" "+str(c))
        else:
            d.append("NO")
    else:
        d.append("NO")
for k in d:
    print(k)