Problem: You are given three positive (i.e. strictly greater than zero) integers x, y and z.

Your task is to find positive integers a, b and c such that x = max(a, b), y = max(a, c) and z = max(b, c), or determine that it is impossible to find such a, b and c.

You have to answer t independent test cases. Print required a, b and c in any (arbitrary) order.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers x, y, and z (1 ≤ x, y, z ≤ 10^9).

Output

For each test case, print the answer:

  * "NO" in the only line of the output if a solution doesn't exist; 
  * or "YES" in the first line and any valid triple of positive integers a, b and c (1 ≤ a, b, c ≤ 10^9) in the second line. You can print a, b and c in any order. 

Example

Input


5
3 2 3
100 100 100
50 49 49
10 30 20
1 1000000000 1000000000


Output


YES
3 2 1
YES
100 100 100
NO
NO
YES
1 1 1000000000

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

public class ThreePairwiseMaximums {
    public static void main(String[] args) throws IOException {
        BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
        int tests = Integer.parseInt(reader.readLine());
        for(int test = 0; test < tests; test++) {
            String[] input = reader.readLine().split(" ");
            int x = Integer.parseInt(input[0]);
            int y = Integer.parseInt(input[1]);
            int z = Integer.parseInt(input[2]);
            if(x == y && x == z) {
                System.out.println("YES");
                System.out.println(x + " " + y + " " + z);
            } else if(x == y && x > z){
                System.out.println("YES");
                System.out.println(z + " " + z + " " + y);
            } else if(x == z && x > y) {
                System.out.println("YES");
                System.out.println(y + " " + y + " " + x);
            } else if(y == z && y > x) {
                System.out.println("YES");
                System.out.println(x + " " + x + " " + z);
            } else {
                System.out.println("NO");
            }
        }
    }
}