Problem: You are given three positive (i.e. strictly greater than zero) integers x, y and z.

Your task is to find positive integers a, b and c such that x = max(a, b), y = max(a, c) and z = max(b, c), or determine that it is impossible to find such a, b and c.

You have to answer t independent test cases. Print required a, b and c in any (arbitrary) order.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains three integers x, y, and z (1 ≤ x, y, z ≤ 10^9).

Output

For each test case, print the answer:

  * "NO" in the only line of the output if a solution doesn't exist; 
  * or "YES" in the first line and any valid triple of positive integers a, b and c (1 ≤ a, b, c ≤ 10^9) in the second line. You can print a, b and c in any order. 

Example

Input


5
3 2 3
100 100 100
50 49 49
10 30 20
1 1000000000 1000000000


Output


YES
3 2 1
YES
100 100 100
NO
NO
YES
1 1 1000000000

Solution (in JAVA):

Solution:
/******************************************************************************

                            Online Java Compiler.
                Code, Compile, Run and Debug java program online.
Write your code in this editor and press "Run" button to execute it.

*******************************************************************************/
import java.util.*;
import java.lang.*;
import java.io.*;

public class Main
{
	public static void main(String[] args) {
	Scanner in=new Scanner(System.in);
	int t=in.nextInt();
	
	while(t-->0)
	{
	   long x=in.nextLong();
	   long y=in.nextLong();
	   long z=in.nextLong();
	    
	    
	    if(x==y && x==z && y==z)
	    {
	        System.out.println("Yes");
	        System.out.println(x+" "+x+" "+x);
	    }
        
       else if(x!=y && x!=z && y!=z)
       {
           System.out.println("No");
       }
        
        else if(x==y && z<x)
        {
            System.out.println("Yes");
            System.out.println(x+" "+z+" "+z);
        }
        
        else if(z==y && z>x)
        {
            System.out.println("Yes");
            System.out.println(z+" "+x+" "+x);
        }
        
        else if(x==z && y<x)
        {
            System.out.println("Yes");
            System.out.println(x+" "+y+" "+y);
        }
        
        else{
            System.out.println("No");
        }
	}
	}
}