Problem: A permutation of length n is a sequence of integers from 1 to n of length n containing each number exactly once. For example, [1], [4, 3, 5, 1, 2], [3, 2, 1] are permutations, and [1, 1], [0, 1], [2, 2, 1, 4] are not.

There was a permutation p[1 ... n]. It was merged with itself. In other words, let's take two instances of p and insert elements of the second p into the first maintaining relative order of elements. The result is a sequence of the length 2n.

For example, if p=[3, 1, 2] some possible results are: [3, 1, 2, 3, 1, 2], [3, 3, 1, 1, 2, 2], [3, 1, 3, 1, 2, 2]. The following sequences are not possible results of a merging: [1, 3, 2, 1, 2, 3], [3, 1, 2, 3, 2, 1], [3, 3, 1, 2, 2, 1].

For example, if p=[2, 1] the possible results are: [2, 2, 1, 1], [2, 1, 2, 1]. The following sequences are not possible results of a merging: [1, 1, 2, 2], [2, 1, 1, 2], [1, 2, 2, 1].

Your task is to restore the permutation p by the given resulting sequence a. It is guaranteed that the answer exists and is unique.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 400) — the number of test cases. Then t test cases follow.

The first line of the test case contains one integer n (1 ≤ n ≤ 50) — the length of permutation. The second line of the test case contains 2n integers a_1, a_2, ..., a_{2n} (1 ≤ a_i ≤ n), where a_i is the i-th element of a. It is guaranteed that the array a represents the result of merging of some permutation p with the same permutation p.

Output

For each test case, print the answer: n integers p_1, p_2, ..., p_n (1 ≤ p_i ≤ n), representing the initial permutation. It is guaranteed that the answer exists and is unique.

Example

Input


5
2
1 1 2 2
4
1 3 1 4 3 4 2 2
5
1 2 1 2 3 4 3 5 4 5
3
1 2 3 1 2 3
4
2 3 2 4 1 3 4 1


Output


1 2 
1 3 4 2 
1 2 3 4 5 
1 2 3 
2 3 4 1 

Solution (in JAVA):

Solution:
import java.util.*;
import java.io.*;
public class Main {
///////----------------input----------------//////
	static BufferedReader br= new BufferedReader(new
            InputStreamReader(System.in)); 
	static BufferedWriter bw = new BufferedWriter(new OutputStreamWriter(System.out));
	static StringTokenizer st; 
	static byte[] buffer =new byte[10*1024];
	static int index;
    static InputStream input_stream= System.in;
    static int total;
	
	static String ns() throws IOException
    { 
		 StringBuilder sb = new StringBuilder();
         int n = read();
         while (isWhiteSpace(n))
             n = read();
         while (!isWhiteSpace(n)) {
             sb.append((char)n);
             n = read();
         }
         return sb.toString();
    } 
	
	static int read() throws IOException
	{
		if(total<0)
            throw new InputMismatchException();
        if(index>=total) {
            index=0;
            total= input_stream.read(buffer);
            if(total<=0)
                return -1;
        }
        return buffer[index++];
	}
	static int ni() throws IOException
    { 
		int integer=0;
        int n= read();
        while(isWhiteSpace(n))
            n= read();
        int neg=1;
        if(n=='-') {
            neg=-1;
            n= read();
        }
        while(!isWhiteSpace(n)) {
            if(n>='0'&&n<='9') {
                integer*=10;
                integer+=n-'0';
                n= read();
            }
            else throw new InputMismatchException();
        }
        return neg*integer;
    } 

	static long nl() throws IOException
    { 
		long number=0;
        int n= read();
        while(isWhiteSpace(n))
            n= read();
        long neg=1l;
        if(n=='-') {
            neg=-1l;
            n= read();
        }
        while(!isWhiteSpace(n)) {
            if(n>='0'&&n<='9') {
                number*=10l;
                number+=(long)(n-'0');
                n= read();
            }
            else throw new InputMismatchException();
        }
        return neg*number;
    } 

	static double nd() throws IOException
    { 
		double doub=0;
        int n= read();
        while(isWhiteSpace(n))
            n= read();
        int neg=1;
        if(n=='-') {
            neg=-1;
            n= read();
        }
        while(!isWhiteSpace(n)&&n!='.') {
            if(n>='0'&&n<='9') {
                doub*=10;
                doub+=n-'0';
                n= read();
            }
            else throw new InputMismatchException();
        }

        if(n=='.') {
            n= read();
            double temp=1;
            while(!isWhiteSpace(n)) {
                if(n>='0'&&n<='9') {
                    temp/=10;
                    doub+=(n-'0')*temp;
                    n= read();
                }
                else throw new InputMismatchException();
            }
        }
        return doub*neg;
    } 

	static String nsl() throws IOException
    { 
        String str = ""; 
        try
        { 
            str = br.readLine(); 
        } 
        catch (IOException e) 
        { 
            e.printStackTrace(); 
        } 
        return str; 
    }
	static boolean isWhiteSpace(int n) {
        if(n==' '|| n=='\n'|| n=='\r'|| n=='\t'|| n==-1)
            return true;
        return false;
    }
	
	///////-------------output-----------------//////
	static public void p(String str) throws IOException {
        bw.append(str);
    }
	static public void pn(String str) throws IOException {
        p(str);
        bw.append("\n");
    }
	static public void close()throws IOException {
        bw.close();
    }
	static public void flush()throws IOException {
        bw.flush();
    }
	
	///////----------THE FAST I/O METHODS ENDS HERE -----------/////////////
	static class Node{
		int h;
		int w;
		Node(int h,int w)
		{
			this.h=h;
			this.w=w;
		}
	}
	static int bit_score(int n)  {
		  int a, b, c, largest, smallest;
		  int score;

		  a = n%10;  n/=10;
		  
		  b = n%10;  n/=10;
		  c = n%10;  n/=10;

		  largest = (a>b)?a:b;
		  largest = (c>largest)?c:largest;
		  smallest = (a<b)?a:b;
		  smallest = (c<smallest)?c:smallest;

		  score = largest*11 + smallest*7;

		  score = score % 100;
		  return score;
		}
	static int findPairs (int score_array[], int N)  {
		  int sig_dig[]=new int[100];
		  int i, pairs = 0, msb;

		  for(i=0; i<10; i++)  {
		    sig_dig[i] = 0;
		  }

		  for(i=0; i<N; i=i+2)  {
		    msb = score_array[i] / 10;
		        for(int j =i+2; j<N; j=j+2){
		            if(msb == score_array[j]/10){
		                if(sig_dig[msb] < 2)  {
		              sig_dig[msb]++;
		            }
		            }
		        }
		    
		  }
		    
		    for(i=1; i<N; i=i+2)  {
		    msb = score_array[i] / 10;
		    for(int j =i+2; j<N; j=j+2){
		            if(msb == score_array[j]/10){
		                if(sig_dig[msb] < 2)  {
		              sig_dig[msb]++;
		            }
		            }
		        }
		  }

		  for(i=0; i<10; i++)  {
		    pairs = pairs + sig_dig[i];
		  }

		  return pairs;
		}

	public static void main(String[] args)throws IOException {
  
		int t=ni();
		while(t-->0)
		{
			int N = ni();
            int[] seen = new int[100];
            List<Integer> res = new ArrayList<>();
            for (int i=0;i<2*N;i++) {
                int val = ni();
                if (seen[val]==0) {
                    res.add(val);
                    seen[val] = 1;
                }
            }
            for (int i=0;i<res.size();i++) {
                p(res.get(i)+" ");
               
            }
            p("\n");
		}
		flush();
    }

}