Problem: You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 

Solution (in PYTHON3):

Solution:
from math import *
def main():
	for _ in range(int(input())):
		a,b,q=map(int,input().split())
		if a>b:
			a,b=b,a
		ma=max(a,b)
		_gcd=int(gcd(a,b))
		_lcm=int((a*b)/_gcd)
		for qq in range(q):
			l,r=map(int,input().split())
			
			l1=(l-1)//_lcm-1
			left=(l-1)//_lcm*_lcm
			r1=r//_lcm-1
			right=r//_lcm*_lcm
			ans=r-l+1
			ans-=(r1-l1)*ma
			ans-=min(ma,r-right+1)
			ans+=min(ma,l-left)
			print(ans,end=' ')
		print()
				
main()