Problem: You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 

Solution (in PYTHON3):

Solution:
def gcd(a, b):  
    if a == 0 : 
        return b  
        
    return gcd(b%a, a) 
def lcm(a,b):
    g=gcd(a,b)
    return a*b//g

for _ in range(int(input())):
    a,b,q=map(int,input().split())
    an=[];c=lcm(a,b)
    #print(a,b,c)
    mi=max(a,b)
    for i in range(q):
        l,r=map(int,input().split())
        l=max(l,a,b)
        if(l>r):
            an.append(0)
            continue
        x=l//c;y=r//c
        ans=(y-x)*mi+max(0,mi-l%c)-max(0,mi-r%c-1)
        #print(ans)
        temp=max(r-l-ans+1,0)
        an.append(temp)
        #print(temp)
    print(*an)