Problem: You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 

Solution (in PYTHON3):

Solution:
t = int(input())

def gcd(a,b): 
    if(b==0): 
        return a 
    else: 
        return gcd(b,a%b)

for xx in range(t):
	a,b,q = map(int,input().split())
	cf = (a*b)//gcd(a,b)
	ans = []
	for i in range(q):
		l,r = map(int,input().split())
		if l%cf <= max(a,b):
			l = ((l//cf)*cf)+max(a,b)
		if r%cf < max(a,b):
			r = ((r//cf)*cf)-1
		if l > r or a%b == 0 or b%a == 0:
				ans.append(0)
				continue
		l1 = (l-1)//cf
		r1 = r//cf
		an = max(r1-l1,0)
		giv = r-l+1
		giv -= an*max(a,b)
#		print(l,r,l1,r1)
		ans.append(giv)
	lel = " ".join([str(i) for i in ans])
	print(lel)