Problem: You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 

Solution (in PYTHON3):

Solution:
"""
2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200
"""
def gcd(a,b):
    if b == 0:
        return a
    else:
        return gcd(b,a%b)

def ec(x,y):
    return x*y/gcd(x,y)

for _ in range(int(input())):
    a,b,q = map(int,input().split())
    for __ in range(q):
        l,r = map(int,input().split())
        tem = int(ec(a,b))
        if r >= b:
            l = max(l,b)
            res = r-l+1
            n = r//tem-(l-1)//tem
            res -= n*max(a,b)
            res += max(a,b)-r%tem-1 if r%tem < max(a,b) else 0
            res -= max(a,b)-l%tem if l%tem < max(a,b) and l % tem != 0 else 0
            print(res)
        else:
            print(0)