Problem: You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 

Solution (in PYTHON3):

Solution:
from bisect import bisect_left

def GCD(x, y): 
    while(y): 
        x, y = y, x % y 
    return x
# ------------------- fast io --------------------
import os
import sys
from io import BytesIO, IOBase
 
BUFSIZE = 8192
 
class FastIO(IOBase):
    newlines = 0
    def __init__(self, file):
        self._fd = file.fileno()
        self.buffer = BytesIO()
        self.writable = "x" in file.mode or "r" not in file.mode
        self.write = self.buffer.write if self.writable else None
 
    def read(self):
        while True:
            b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
            if not b:
                break
            ptr = self.buffer.tell()
            self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
        self.newlines = 0
        return self.buffer.read()
 
    def readline(self):
        while self.newlines == 0:
            b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
            self.newlines = b.count(b"\n") + (not b)
            ptr = self.buffer.tell()
            self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
        self.newlines -= 1
        return self.buffer.readline()
 
    def flush(self):
        if self.writable:
            os.write(self._fd, self.buffer.getvalue())
            self.buffer.truncate(0), self.buffer.seek(0)
 
 
class IOWrapper(IOBase):
    def __init__(self, file):
        self.buffer = FastIO(file)
        self.flush = self.buffer.flush
        self.writable = self.buffer.writable
        self.write = lambda s: self.buffer.write(s.encode("ascii"))
        self.read = lambda: self.buffer.read().decode("ascii")
        self.readline = lambda: self.buffer.readline().decode("ascii")
 
 
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
 
# ------------------- fast io --------------------

testcases=int(input())

for j in range(testcases):
    vals=list(map(int,input().split()))
    a=vals[0]
    b=vals[1]
    q=vals[2]
    output=[]
    values=[]
    lcm=a*b//GCD(a,b)
    for k in range(a*b//GCD(a,b)):
        if (k%a)%b!=(k%b)%a:
            values.append(k)
    #
    for s in range(q):
        qs=list(map(int,input().split()))
        l=qs[0]-1
        r=qs[1]
        count=0
        val1=0
        val2=0
        if len(values)==0:
            output.append(str(0))
        #
        else:
            if r>=lcm:
                val1=(r//lcm)*len(values)
            r1=(r%lcm)
            rem1=bisect_left(values,r1)
            if rem1>len(values)-1:
                rem1-=1
            if values[rem1]==r1:
                rem1+=1
            #
            if l>=lcm:
                val2=(l//lcm)*len(values)
            r2=(l%lcm)
            rem2=bisect_left(values,r2)
            if rem2>len(values)-1:
                rem2-=1
            if values[rem2]==r2:
                rem2+=1
            #
            count+=(val1+rem1)-(val2+rem2)
            output.append(str(count))
    #
    print(" ".join(output))