Problem: You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 

Solution (in PYTHON3):

Solution:
from math import gcd as g
t = int(input())
while t:
    t += -1
    a, b, q = map(int, input().split())
    if a > b: a, b = b, a
    a = a
    b = b
    lcm = (a * b) // g(a, b)
    while q:
        q += -1
        l, r = map(int, input().split())
        if b % a == 0: 
            print(0, end = " ")
        else:
            k = r // (lcm)
            ans = 0
            if k != 0: ans += min(r, lcm * k + b - 1) - lcm * k + 1
            if k >= 1:
                ans += b * (k - 1) + b - 1
            else: 
                ans += min(b - 1, r)
            l = l - 1
            k = l // (lcm)
            ans1 = 0
            if k != 0: ans1 = min(l, lcm * k + b - 1) - lcm * k + 1
            if k >= 1:
                ans1 += b * (k - 1) + b - 1
            else: ans1 += min(b - 1, l)
            l = l + 1
            tt = r - l + 1 - (ans - ans1)
            print(tt, end = " ")
    print()