Problem: You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 

Solution (in PYTHON3):

Solution:
import sys
reader = (s.rstrip() for s in sys.stdin)
input = reader.__next__
import math
def gift():
    for _ in range(t):
        a,b,q=map(int,input().split())
        lcm=a*b//math.gcd(a,b)
        maxdog=max(a,b)
        for i in range(q):
            
            s,e=map(int,input().split())
            ans=(e-s+1)

            startq,startm=s//lcm,s%lcm
            endq,endm=e//lcm,e%lcm
            if startq==endq:
                if startm<maxdog:
                    if endm<maxdog:
                        ans-=(endm-startm+1)
                    else:
                        ans-=(maxdog-startm)
            else:
                if startm<maxdog:
                    ans-=(maxdog-startm)
                #print(ans)
                ans-=((endq-startq-1)*maxdog)
                if endm<maxdog:
                    ans-=(endm+1)
                else:
                    ans-=maxdog
            yield ans

                
if __name__ == '__main__':
    t= int(input())
    ans = gift()
    print(*ans,sep='\n')