Problem: Danil decided to earn some money, so he had found a part-time job. The interview have went well, so now he is a light switcher.

Danil works in a rooted tree (undirected connected acyclic graph) with n vertices, vertex 1 is the root of the tree. There is a room in each vertex, light can be switched on or off in each room. Danil's duties include switching light in all rooms of the subtree of the vertex. It means that if light is switched on in some room of the subtree, he should switch it off. Otherwise, he should switch it on.

Unfortunately (or fortunately), Danil is very lazy. He knows that his boss is not going to personally check the work. Instead, he will send Danil tasks using Workforces personal messages.

There are two types of tasks: 

  1. pow v describes a task to switch lights in the subtree of vertex v.
  2. get v describes a task to count the number of rooms in the subtree of v, in which the light is turned on. Danil should send the answer to his boss using Workforces messages.



A subtree of vertex v is a set of vertices for which the shortest path from them to the root passes through v. In particular, the vertex v is in the subtree of v.

Danil is not going to perform his duties. He asks you to write a program, which answers the boss instead of him.

Input

The first line contains a single integer n (1 ≤ n ≤ 200 000) — the number of vertices in the tree.

The second line contains n - 1 space-separated integers p2, p3, ..., pn (1 ≤ pi < i), where pi is the ancestor of vertex i.

The third line contains n space-separated integers t1, t2, ..., tn (0 ≤ ti ≤ 1), where ti is 1, if the light is turned on in vertex i and 0 otherwise.

The fourth line contains a single integer q (1 ≤ q ≤ 200 000) — the number of tasks.

The next q lines are get v or pow v (1 ≤ v ≤ n) — the tasks described above.

Output

For each task get v print the number of rooms in the subtree of v, in which the light is turned on.

Example

Input

4
1 1 1
1 0 0 1
9
get 1
get 2
get 3
get 4
pow 1
get 1
get 2
get 3
get 4


Output

2
0
0
1
2
1
1
0

Note

<image> The tree before the task pow 1.

<image> The tree after the task pow 1.

Solution (in JAVA):

Solution:
import java.util.*;
import java.text.*;
import java.io.*;
import java.math.*;
public class code5 {
	InputStream is;
	PrintWriter out;
	static long mod=pow(10,9)+7;
	static int dx[]={0,0,1,-1},dy[]={1,-1,0,0};
	int arr[];
 	void solve() throws Exception
	{
 		int n=ni();
 		al=new ArrayList[n];
 		for(int i=0;i<n;i++)
 			al[i]=new ArrayList<Integer>();
 		for(int i=0;i<n-1;i++)
 		{
 			int p=ni();
 			al[p-1].add(i+1);
 			al[i+1].add(p-1);
 		}
 		start=new int[n];
 		end=new int[n];
 		val=new int[n];
 		arr=na(n);
 		dfs(0,0);
 		//debug(start);
 		//debug(end);
 		segtree st=new segtree(val);
 		int q=ni();
 		while(q--!=0)
 		{
 			String s=ns();
 			if(s.compareTo("get")==0)
 			{
 				int x=ni()-1;
 				out.println(st.query(0,0,n-1,start[x],end[x]));
 				
 			}else {
 				int x=ni()-1;
 				st.update(0,0,n-1,start[x],end[x]);
 			}
 		}
 	}
 	static class segtree{
 		int st[],arr[],lazy[];
 		segtree(int arr[])
 		{
 			int size=arr.length;
 			st=new int[4*(size+1)+1];
 			lazy=new int[4*(size+1)+1];
 			this.arr=arr.clone();
 			build(0,0,size-1);
 		}
 		void build(int n,int l,int r)
 		{
 			if(l==r)
 			{
 				st[n]=arr[l];
 				return;
 			}
 			int mid=(l+r)/2;
 			build(2*n+1,l,mid);
 			build(2*n+2,mid+1,r);
 			st[n]=st[2*n+1]+st[2*n+2];
 		}
 		void update(int n,int l,int r,int ql,int qr)
 		{
 			if(lazy[n]!=0)
 			{
 				st[n]=(r-l+1)-st[n];
 				if(l!=r)
 				{
 					lazy[2*n+1]^=1;
 					lazy[2*n+2]^=1;
 				}
 				lazy[n]=0;
 			}
 			if(ql>r||qr<l)
 				return;
 			if(ql<=l&&qr>=r)
 			{
 				st[n]=(r-l+1)-st[n];
 				if(l!=r)
 				{
 					lazy[2*n+1]^=1;
 					lazy[2*n+2]^=1;
 				}
 				return;
 			}
 			int mid=(l+r)/2;
 			update(2*n+1,l,mid,ql,qr);
 			update(2*n+2,mid+1,r,ql,qr);
 			st[n]=st[2*n+1]+st[2*n+2];
 		}
 		int query(int n,int l,int r,int ql,int qr)
 		{
 			if(lazy[n]!=0)
 			{
 				st[n]=(r-l+1)-st[n];
 				if(l!=r)
 				{
 					lazy[2*n+1]^=1;
 					lazy[2*n+2]^=1;
 				}
 				lazy[n]=0;
 			}
 			if(ql>r||qr<l)
 				return 0;
 			if(ql<=l&&qr>=r)
 				return st[n];
 			int mid=(l+r)/2;
 			return query(2*n+1,l,mid,ql,qr)+query(2*n+2,mid+1,r,ql,qr);
 		
 		}
 	}
 	int start[],end[],time=-1,val[];
 	void dfs(int x,int p)
 	{
 		start[x]=++time;
 		val[time]=arr[x];
 		for(int i=0;i<al[x].size();i++)
 		{
 			if(al[x].get(i)!=p)
 				dfs(al[x].get(i),x);
 		}
 		end[x]=time;
 	}
 	ArrayList<Integer> al[];
 	void take(int n,int m)
 	{
 		al=new ArrayList[n];
 		for(int i=0;i<n;i++)
 			al[i]=new ArrayList<Integer>();
 		for(int i=0;i<m;i++)
 		{
 			int x=ni()-1;
 			int y=ni()-1;
 			al[x].add(y);
 			al[y].add(x);
 		}
 	}
 	int check(long n)
 	{
 		int count=0;
 		while(n!=0)
 		{
 			if(n%10!=0)
 				break;
 			n/=10;
 			count++;
 		}
 		return count;
 	}
	public static int count(int x)
	{
		int num=0;
		while(x!=0)
		{
			x=x&(x-1);
			num++;
		}
		return num;
	}
	static long d, x, y;
	void extendedEuclid(long A, long B) {
	    if(B == 0) {
	        d = A;
	        x = 1;
	        y = 0;
	    }
	    else {
	        extendedEuclid(B, A%B);
	        long temp = x;
	        x = y;
	        y = temp - (A/B)*y;
	    }
	}
	long modInverse(long A,long M) //A and M are coprime
	{
	    extendedEuclid(A,M);
	    return (x%M+M)%M;    //x may be negative
	}
	public static void mergeSort(int[] arr, int l ,int r){
		if((r-l)>=1){
			int mid = (l+r)/2;
			mergeSort(arr,l,mid);
			mergeSort(arr,mid+1,r);
			merge(arr,l,r,mid);
		}
	}
	public static void merge(int arr[], int l, int r, int mid){
		int n1 = (mid-l+1), n2 = (r-mid);
		int left[] = new int[n1];
		int right[] = new int[n2];
		for(int i =0 ;i<n1;i++) left[i] = arr[l+i];
		for(int i =0 ;i<n2;i++) right[i] = arr[mid+1+i];
		int i =0, j =0, k = l;
		while(i<n1 && j<n2){
			if(left[i]>right[j]){
				arr[k++] = right[j++];
			}
			else{
				arr[k++] = left[i++];
			}
		}
		while(i<n1) arr[k++] = left[i++];
		while(j<n2) arr[k++] = right[j++];
	}
	public static void mergeSort(long[] arr, int l ,int r){
		if((r-l)>=1){
			int mid = (l+r)/2;
			mergeSort(arr,l,mid);
			mergeSort(arr,mid+1,r);
			merge(arr,l,r,mid);
		}
	}
	public static void merge(long arr[], int l, int r, int mid){
		int n1 = (mid-l+1), n2 = (r-mid);
		long left[] = new long[n1];
		long right[] = new long[n2];
		for(int i =0 ;i<n1;i++) left[i] = arr[l+i];
		for(int i =0 ;i<n2;i++) right[i] = arr[mid+1+i];
		int i =0, j =0, k = l;
		while(i<n1 && j<n2){
			if(left[i]>right[j]){
				arr[k++] = right[j++];
			}
			else{
				arr[k++] = left[i++];
			}
		}
		while(i<n1) arr[k++] = left[i++];
		while(j<n2) arr[k++] = right[j++];
	}
	 static class Pair implements Comparable<Pair>{
		 
	       int x,y,k;
	       int i,dir;
		Pair (int xx,int yy){
			this.x=xx;
			this.y=yy;
			this.k=k;
		}   
		public int compareTo(Pair o) {
			if(this.x<=o.x)
				return this.x-o.x;
			return o.y-this.x;
		}
	 
		public String toString(){
			return x+" "+y+" "+k+" "+i;}
		public boolean equals(Object o) {
			if (o instanceof Pair) {
				Pair p = (Pair)o;
				return p.x == x && p.y == y;
			}
			return false;
		}
		public int hashCode() {
			return new Long(x).hashCode()*31 + new Long(y).hashCode() ;
		}
	} 
	    
	    public static boolean isPal(String s){
	        for(int i=0, j=s.length()-1;i<=j;i++,j--){
	                if(s.charAt(i)!=s.charAt(j)) return false;
	        }
	        return true;
	    }
	    public static String rev(String s){
			StringBuilder sb=new StringBuilder(s);
			sb.reverse();
			return sb.toString();
	    }
	    
	    public static long gcd(long x,long y){
		if(y==0)
			return x;
		else
			return gcd(y,x%y);
	    }
	    
	    public static int gcd(int x,int y){
	    	if(y==0) 
	    		return x; 
	    	return gcd(y,x%y);
	    }
	    
	    public static long gcdExtended(long a,long b,long[] x){
	        
	        if(a==0){
	            x[0]=0;
	            x[1]=1;
	            return b;
	        }
	        long[] y=new long[2];
	        long gcd=gcdExtended(b%a, a, y);
	        
	        x[0]=y[1]-(b/a)*y[0];
	        x[1]=y[0];
	        
	        return gcd;
	    }
	    
	    public static int abs(int a,int b){
		return (int)Math.abs(a-b);
	    }
	 
	    public static long abs(long a,long b){
		return (long)Math.abs(a-b);
	    }
	    
	    public static int max(int a,int b){
		if(a>b)
			return a;
		else
			return b;
	    }
	 
	    public static int min(int a,int b){
		if(a>b)
			return b;
		else 
			return a;
	    }
	    
	    public static long max(long a,long b){
		if(a>b)
			return a;
		else
			return b;
	    }
	 
	    public static long min(long a,long b){
		if(a>b)
			return b;
		else 
			return a;
	    }
	 
	    public static long pow(long n,long p,long m){
		 long  result = 1;
		  if(p==0)
		    return 1;
		if (p==1)
		    return n;
		while(p!=0)
		{
		    if(p%2==1)
		        result *= n;
		    if(result>=m)
		    result%=m;
		    p >>=1;
		    n*=n;
		    if(n>=m)
		    n%=m;
		}
		return result;
	    }
	    
	    public static long pow(long n,long p){
		long  result = 1;
		  if(p==0)
		    return 1;
		if (p==1)
		    return n;
		while(p!=0)
		{
		    if(p%2==1)
		        result *= n;	    
		    p >>=1;
		    n*=n;	    
		}
		return result;
	    }
	    public static void debug(Object... o) {
			System.out.println(Arrays.deepToString(o));
		}
	    void run() throws Exception {
			is = System.in;
			out = new PrintWriter(System.out);
			solve();
			out.flush();
		}
	   
	    public static void main(String[] args) throws Exception {
			new Thread(null, new Runnable() {
				public void run() {
					try {
						new code5().run();
					} catch (Exception e) {
						e.printStackTrace();
					}
				}
			}, "1", 1 << 26).start();
			
	    	//new code5().run();
		}
	    private byte[] inbuf = new byte[1024];
		public int lenbuf = 0, ptrbuf = 0;
	 
		private int readByte() {
			if (lenbuf == -1)
				throw new InputMismatchException();
			if (ptrbuf >= lenbuf) {
				ptrbuf = 0;
				try {
					lenbuf = is.read(inbuf);
				} catch (IOException e) {
					throw new InputMismatchException();
				}
				if (lenbuf <= 0)
					return -1;
			}
			return inbuf[ptrbuf++];
		}
	 
		private boolean isSpaceChar(int c) {
			return !(c >= 33 && c <= 126);
		}
	 
		private int skip() {
			int b;
			while ((b = readByte()) != -1 && isSpaceChar(b));
			return b;
		}
	 
		private double nd() {
			return Double.parseDouble(ns());
		}
	 
		private char nc() {
			return (char) skip();
		}
	 
		private String ns() {
			int b = skip();
			StringBuilder sb = new StringBuilder();
			while (!(isSpaceChar(b))) { // when nextLine, (isSpaceChar(b) && b != ' ')
				sb.appendCodePoint(b);
				b = readByte();
			}
			return sb.toString();
		}
	 
		private char[] ns(int n) {
			char[] buf = new char[n];
			int b = skip(), p = 0;
			while (p < n && !(isSpaceChar(b))) {
				buf[p++] = (char) b;
				b = readByte();
			}
			return n == p ? buf : Arrays.copyOf(buf, p);
		}
	 
		private char[][] nm(int n, int m) {
			char[][] map = new char[n][];
			for (int i = 0; i < n; i++)
				map[i] = ns(m);
			return map;
		}
	 
		private int[] na(int n) {
			int[] a = new int[n];
			for (int i = 0; i < n; i++)
				a[i] = ni();
			return a;
		}
		private long[] nl(int n) {
			long[] a = new long[n];
			for (int i = 0; i < n; i++)
				a[i] = nl();
			return a;
		}
	 
		private int ni() {
			int num = 0, b;
			boolean minus = false;
			while ((b = readByte()) != -1 && !((b >= '0' && b <= '9') || b == '-'))
				;
			if (b == '-') {
				minus = true;
				b = readByte();
			}
	 
			while (true) {
				if (b >= '0' && b <= '9') {
					num = num * 10 + (b - '0');
				} else {
					return minus ? -num : num;
				}
				b = readByte();
			}
		}
	 
		private long nl() {
			long num = 0;
			int b;
			boolean minus = false;
			while ((b = readByte()) != -1 && !((b >= '0' && b <= '9') || b == '-'))
				;
			if (b == '-') {
				minus = true;
				b = readByte();
			}
	 
			while (true) {
				if (b >= '0' && b <= '9') {
					num = num * 10 + (b - '0');
				} else {
					return minus ? -num : num;
				}
				b = readByte();
			}
		}
	 
}