Problem: Given is a string S consisting of `0` and `1`. Find the number of strings, modulo 998244353, that can result from applying the following operation on S between 0 and K times (inclusive):

* Choose a pair of integers i, j (1\leq i < j\leq |S|) such that the i-th and j-th characters of S are `0` and `1`, respectively. Remove the j-th character from S and insert it to the immediate left of the i-th character.

Constraints

* 1 \leq |S| \leq 300
* 0 \leq K \leq 10^9
* S consists of `0` and `1`.

Input

Input is given from Standard Input in the following format:


S K


Output

Find the number of strings, modulo 998244353, that can result from applying the operation on S between 0 and K times (inclusive).

Examples

Input

0101 1


Output

4


Input

01100110 2


Output

14


Input

1101010010101101110111100011011111011000111101110101010010101010101 20


Output

113434815

Solution (in PYTHON3):

Solution:
def main():
    mod = 998244353
    s, k = input().split()
    k, n, one, cnt, z, zero_list = int(k), len(s), s.count("1")+1, 0, 0, []
    for i in range(n):
        if s[i] == "0":
            zero_list.append(cnt)
            cnt = 0
        else:
            cnt += 1
    mm = min(one-1, k)

    dp = [[0]*(mm+1) for _ in [0]*one]
    dp[0][0] = 1

    for i in zero_list:
        dp2 = [[0]*(mm+1) for _ in [0]*one]
        for jl in range(z+i, one):
            for x in range(i, min(one, jl+1, mm+i+1)):
                dp2[jl][x-i] = (dp2[jl][x-i]+sum([dp[jl-x+p][p]
                                                  for p in range(min(one, x-i+1))])) % mod
            for p in range(min(one, mm+1)):
                dp2[jl][p] = (dp2[jl][p]+sum([dp[jl-l][p]
                                              for l in range(min(one, i, jl-p+1))])) % mod
        z += i
        dp = dp2
    print(sum([sum(i) for i in dp]) % mod)


main()