Problem: You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 

Solution (in PYTHON3):

Solution:
def main_function():
    from sys import stdin
    from sys import stdout
    input = stdin.readline
    print = stdout.write

    def count_good(bound: int):
        return bound // pack * good_in_pack[-1] + good_in_pack[bound % pack]

    t = int(input())
    for _ in range(t):
        a, b, query = list(map(int, input().split()))
        a, b = min(a, b), max(a, b)
        pack = a * b
        ans = ['0'] * query
        good_in_pack = [0] * pack
        for x in range(1, pack):
            if x % a % b != x % b % a:
                good_in_pack[x] = good_in_pack[x - 1] + 1
            else:
                good_in_pack[x] = good_in_pack[x - 1]
        for q_ix in range(query):
            l, r = list(map(int, input().split()))
            ans[q_ix] = str(count_good(r) - count_good(l - 1))
        print(' '.join(ans) + '\n')


if __name__ == '__main__':
    main_function()