Problem: You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 

Solution (in PYTHON3):

Solution:
from math import gcd

def solve(r, a, b, g):

	num = r//g

	maxg = num*g

	# print("AA", maxg, r)

	ret = 0
	ret += num*(max(a, b))

	if maxg+max(a, b) <= r:
		ret += max(a, b)
	else:
		ret += r-maxg+1 

	return ret


t = int(input())
for _ in range(t):
	a, b, q = map(int, input().split())
	g = a*b//gcd(a, b)
	for i in range(q):
		l, r = map(int, input().split())
		count = 0
		if a == b:
			print(0)
			continue

		# for j in range(l, r+1):
		# 	if (j%a)%b == (j%b)%a:
		# 		count += 1
		# 		print(j)

		# print('C', count)

		print(r-l+1 - (solve(r, a, b, g) - solve(l-1, a, b, g)), end=' ')

		# num = r//g
		# print(num)

		# maxg = num*g
		# print(maxg, r)
	print('')