Problem: You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 

Solution (in PYTHON3):

Solution:
t=int(input())

def gcd(a,b):
    if not b:
        return a
    return gcd(b,a%b)

def LCM(a,b):
    return (a*b)//gcd(a,b)

for _ in range(t):
    a,b,q=map(int,input().split())
    lcm = LCM(a,b)
    temp = [0]
    for x in range(1,lcm+1):
        ab = (x%a)%b
        ba = (x%b)%a
        if ab!=ba:
            temp.append(1)
        else:
            temp.append(0)
    for x in range(1,lcm+1):
        temp[x]+=temp[x-1]
    while q:
        l,r=map(int,input().split())
        ansR = (r//lcm)*(temp[-1]) + temp[r%lcm]
        l-=1
        ansL = (l//lcm)*(temp[-1]) + temp[l%lcm]
        print(ansR-ansL,end=" ")
        q-=1
    print()