Problem: Recently Pashmak has been employed in a transportation company. The company has k buses and has a contract with a school which has n students. The school planned to take the students to d different places for d days (each day in one place). Each day the company provides all the buses for the trip. Pashmak has to arrange the students in the buses. He wants to arrange the students in a way that no two students become close friends. In his ridiculous idea, two students will become close friends if and only if they are in the same buses for all d days.

Please help Pashmak with his weird idea. Assume that each bus has an unlimited capacity.

Input

The first line of input contains three space-separated integers n, k, d (1 ≤ n, d ≤ 1000; 1 ≤ k ≤ 109).

Output

If there is no valid arrangement just print -1. Otherwise print d lines, in each of them print n integers. The j-th integer of the i-th line shows which bus the j-th student has to take on the i-th day. You can assume that the buses are numbered from 1 to k.

Examples

Input

3 2 2


Output

1 1 2 
1 2 1 


Input

3 2 1


Output

-1

Note

Note that two students become close friends only if they share a bus each day. But the bus they share can differ from day to day.

Solution (in PYTHON):

Solution:
from sys import stdin,stdout,setrecursionlimit,maxint,exit
setrecursionlimit(2*10**4)
def listInput():
 return map(long,stdin.readline().split())
def printBS(li):
 for i in xrange(len(li)-1):
  stdout.write("%d "%li[i])
 stdout.write("%d\n"%li[-1])
def sin():
 return stdin.readline().rstrip()
# n- no of students
# d- no of days(trips)
# k- no of buses
# for each day..a stduenr can be assigned a
# bus
# i.e. for for d days...k^d possible ordering 
# of buses for d days..
# i.e. atmax..k^d distinct orderings of buses possible that 
#can be assigned to students
# n>k^d not possible
# otherwise to find a order can use
# orderings of k upto nth ordering in increasing order
#for each student
def maxprod(k,d):
 t=float(1)
 for i in xrange(1,d+1):
  t*=k
  if t>1000:
   return t
 return t
n,k,d=listInput()
if n>maxprod(k,d):
 print -1
 exit(0)
orders=[]
os=0
def ways(i,d,no):
 global os
 if i==d+1:
  orders.append(list(no))
  os+=1
  return
 for j in xrange(1,k+1):
  if os>n:
   return
  no.append(j)
  ways(i+1,d,no)
  no.pop()
ways(1,d,[])
#print orders
for i in xrange(d):
  out=[str(orders[j][i]) for j in xrange(n)]
  stdout.write(" ".join(out)+"\n")