Problem: You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 

Solution (in PYTHON3):

Solution:
from math import gcd

def max(x, y):
    if (x > y):
        return x
    return y
    

def calc(p, a, b):
    ans = (p - p % (a * b // gcd(a, b))) // (a * b // gcd(a, b)) * int(max(a, b))
    cur = (p - p % (a * b // gcd(a, b)))
    ans += int(max(a, b))
    if (cur + int(max(a, b)) - 1 > p):
        ans -= (cur + int(max(a, b)) - 1 - p)
    return ans
    
t = int(input())
while t > 0:
    t -= 1
    a, b, q = input().split()
    a = int(a)
    b = int(b)
    if (a > b):
        p = a
        a = b
        b = p
    q = int(q)
    while q > 0:
        q -= 1
        l, r = input().split()
        l = int(l)
        r = int(r)
        print((r - l + 1) - (int(calc(r, a, b)) - int(calc(l - 1, a, b))), end = ' ')
        
    print(end = '\n')