Problem: You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 

Solution (in PYTHON3):

Solution:
num = int(input())
list_ = [0] * 201 * 201

def getSolve(list, n, target):
	return list[n-1]*(target//n) + list[target % n]

for _ in range(num):
	a, b, q = [int(i) for i in input().split()]
	res = []
	for i in range(1, a * b+1):
		list_[i] = list_[i - 1]
		if i % a % b != i % b % a:
			list_[i] += 1

	for _ in range(q):
		l, r = [int(i) for i in input().split()]
		res.append(str(getSolve(list_, a*b, r) - getSolve(list_, a*b, l-1)))
	print(" ".join(res))