Problem: You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 

Solution (in PYTHON):

Solution:
from sys import stdin,stdout
from fractions import gcd
read,write = stdin.readline,stdout.write
iread = lambda: int(read())
sread = lambda: read().strip()
spread = lambda func=int: map(func,read().split())
lcm = lambda x,y: x*y/gcd(x,y)

def calculate(r,nax,LCM):
    int_div = r/LCM
    return r - ((int_div-1)*(nax) + min(nax,r-int_div*LCM+1) + min(r,nax-1)) if int_div else r - min(r,nax-1)

t = iread()
for _ in xrange(t):
    a,b,q = spread()
    nax = max(a,b)
    LCM = lcm(a,b)
    res = []
    for _ in xrange(q):
        l,r = spread()
        res.append(calculate(r,nax,LCM) - calculate(l-1,nax,LCM))
    print ' '.join(map(str,res))