Problem: You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 

Solution (in PYTHON3):

Solution:
def compute_gcd(x, y):
    while (y):
        x, y = y, x % y
    return x


# This function computes LCM
def compute_lcm(x, y):
    lcm = (x * y) // compute_gcd(x, y)
    return lcm


for t in range(int(input())):
    a, b, q = map(int, input().split())
    mx = max(a, b)
    lcm = compute_lcm(a, b)
    a=[]
    for i in range(q):
        x, y = map(int, input().split())
        wran = y - x + 1
        st = x // lcm
        fn = y // lcm
        ans=0
        #first in:
        if st*lcm<=x<=y<st*lcm+mx or lcm==mx:
            a.append("0")
            continue
        if st*lcm<=x<=st*lcm+mx:
            ans+=st*lcm+mx-x
        st+=1
        if fn*lcm<=y<fn*lcm+mx:
            ans+=y-(fn*lcm)+1
            fn-=1
        ans+=(fn-st+1)*mx
        a.append(str(wran-ans))
    print(" ".join(a))