Problem: You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 

Solution (in PYTHON3):

Solution:

def kgv(a,b):
    k = a
    while(1):
        if k % b == 0:
            return k
        k += a


t = int(input())

res = []
for ite in range(t):
    a, b, q = map(int, input().split())

    k = kgv(a,b)
    j = max(a,b)
    delta = k - j


    re = []
    for it in range(q):
        l, r = map(int, input().split())

        x = l//k
        l -= x*k
        r -= x*k

        dl = 0
        dr = r + (k-r%k)

        upper = (dr//k) * delta

        if l - j > 0:
            upper-= (l-j)

        if ( (dr-r) - delta) > 0:
            upper -= delta
        else:
            upper -= (dr-r-1)


        re.append(upper)
    res.append(re)

for el in res:
    print(*el)