Problem: You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 

Solution (in PYTHON3):

Solution:
from math import inf

def gcd(a, b):
    if not b:
        return a
    return gcd(b, a % b)

t = int(input())


for qq in range(t):
    a, b, q = [int(i) for i in input().split()]
    if a < b:
        a, b = b, a
    g = gcd(a, b)
    e = b // g
    #print(e)
    for h in range(q):
        l, r = [int(i) for i in input().split()]
        if a % b:
            s = r - l + 1
            k = l // a 
            j = r // a
            #print(j, k)
            if not k % e:
                s -= min((k + 1) * a - l, s)
                k += 1
            if not j % e:
                s -= min(r - (j * a) + 1, s)
                j -= 1
            if j == k - 2:
                print(0, end = ' ')
                continue
            j -= j % e
            k += (e - k % e)
            #print(j, k)
            s -= ((j - k) // e + 1) * a
            print(s, end = ' ')
        else:
            print(0, end = ' ')
    print('')