Problem: You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 

Solution (in PYTHON3):

Solution:
t = int(input())
def gcd(l,r):
	if l == 0:
		return r
	return gcd(r%l, l)

def fun(x,lcm,b):
	quo = x//lcm
	sub = quo*b
	sub += min(b,x - lcm*quo)
	#print("sub :",sub)
	return x - sub

for _ in range(t):
	a,b,q = list(map(int, input().strip().split()))
	if a>b:
		a,b = b,a
	ans = []
	for i in range(q):
		res = 0
		l,r = list(map(int, input().strip().split()))
		lcm = (a*b)//gcd(a,b)
		
		res = fun(r+1,lcm,b) - fun(l,lcm,b)
		ans.append(max(0,res))
	for i in ans:
		print(i, end = ' ')
	print()