Problem: You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 

Solution (in PYTHON3):

Solution:
import math
t=int(input())
for i in range(t):
    a,b,q=map(int,input().split())
    lcm=a*b//math.gcd(a,b)
    arr=[]
    for i in range(q):
        ans=0
        l,r=map(int,input().split())
        total=r-l+1
        last=(r//lcm)
        first=((l//lcm)+1)
        pq=math.inf
        if r%lcm<max(a,b):
            pq=(r%lcm)+1
        
        ans+=min((last-first)*max(a,b)+pq,((last-first)+1)*max(a,b))
        ans=max(0,ans)
        
        #print(ans,total,lcm,last,first,((last-first)+1)*max(a,b))
        #l-=1
        if l%lcm<max(a,b):
            ans+=((max(a,b)-1)-(l%lcm)+1)
            #print('1',ans,total)
        
        #print('2',ans,total)
        f_ans=max(0,total-ans)
        arr.append(f_ans)
    print(*arr)

'''for i in range(39799,100000000,39800):
    print(i)'''