Problem: You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 

Solution (in PYTHON3):

Solution:
import sys
import math

def ii():
    return sys.stdin.readline().strip()

def idata():
    return [int(x) for x in ii().split()]

def solve_of_problem():
    a, b, q = idata()
    a, b = min(a, b), max(a, b)
    ans = []
    for i in range(q):
        l, r = idata()
        qw = a * b // math.gcd(a, b)
        l1, r1 = l // qw, r // qw
        l1, r1 = l1 * (qw - b), r1 * (qw - b)
        l, r = max(0, l % qw - b), max(0, r % qw - b + 1)
        ans += [r1 + r - l1 - l]
    print(*ans)
    return

for ______ in range(int(ii())):
    solve_of_problem()