Problem: You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 

Solution (in PYTHON3):

Solution:

def gcd(a, b): return a if b == 0 else gcd(b, a%b)

T = int(input())
for _ in range(T):
    a, b, q = map(int, input().split())
    g = gcd(a, b)
    lcm = a*b//g

    cc = []
    for u in range(lcm):
        cc.append(1 if u%a%b != u%b%a else 0)
        if len(cc) > 1: cc[-1] += cc[-2]
    def get_count(u):
        return cc[-1]*(u//lcm) + cc[u%lcm]

    res = []
    for _ in range(q):
        l, r = map(int, input().split())
        res.append(get_count(r)-get_count(l-1))
    print(' '.join(map(str, res)))