Problem: You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.*;

public class Solution {

    public static void main(String[] args) {
        InputStream inputStream = System.in;
        OutputStream outputStream = System.out;
        InputReader in = new InputReader(inputStream);
        PrintWriter out = new PrintWriter(outputStream);
        solve(in, out);
        out.close();
    }

    public static void solve(InputReader in, PrintWriter out) {
        int t = in.nextInt();
        while (t-- > 0) {
            int a = in.nextInt();
            int b = in.nextInt();
            int q = in.nextInt();
            long[] arr = new long[a*b];
            arr[0] = 0;
            for (int i = 1; i < a*b; ++i) {
                if ((i % a)%b != (i%b)%a) {
                    arr[i] = arr[i-1] + 1;
                } else {
                    arr[i] = arr[i-1];
                }
            }
            int ab = a*b;
            while (q-- > 0) {
                long l = in.nextLong();
                long r = in.nextLong();
                long res = 0;
                long lab = l / ab;
                long rab = r / ab;
                int leftIndex = Math.max(0, (int) (l % ab) - 1);
                int rightIndex = (int) (r % ab);
                if (lab == rab) {
                    res = arr[rightIndex] - arr[leftIndex];
                } else if (rab - lab == 1) {
                    res = arr[ab-1] - arr[leftIndex] + arr[rightIndex];
                } else {
                    res = arr[ab-1] - arr[leftIndex] + arr[rightIndex];
                    res += arr[ab-1] * (rab - lab - 1);
                }
                out.print(res);
                out.print(' ');
            }
            out.println();
        }
    }

    static class InputReader {
        public BufferedReader reader;
        public StringTokenizer tokenizer;

        public InputReader(InputStream stream) {
            reader = new BufferedReader(new InputStreamReader(stream), 32768);
            tokenizer = null;
        }

        public String next() {
            while (tokenizer == null || !tokenizer.hasMoreTokens()) {
                try {
                    tokenizer = new StringTokenizer(reader.readLine());
                } catch (IOException e) {
                    throw new RuntimeException(e);
                }
            }
            return tokenizer.nextToken();
        }

        public int nextInt() {
            return Integer.parseInt(next());
        }

        public void skip() {
            tokenizer = null;
        }

        public long nextLong() {
            return Long.parseLong(next());
        }
    }
}