Problem: You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 

Solution (in PYTHON3):

Solution:
t = int(input())
for i in range(t):
    a, b, q = map(int, input().split())
    ans = [0 for j in range(a * b + 1)]
    for j in range(1, a * b + 1):
        if ((j % a) % b != (j % b) % a):
            ans[j] = 1
    for j in range(1, a * b + 1):
        ans[j] += ans[j - 1]
    for j in range(q):
        l, r = map(int, input().split())
        if (r // (a * b) == l // (a * b)):
            lll = l % (a * b)
            if (lll == 0):
                lll = 1
            print(ans[r % (a * b)] - ans[lll - 1], end = ' ')
            continue
        ll = (l + a * b - 1) // (a * b)
        rr = r // (a * b)
        answ = ans[-1] * (max(0, rr - ll))
        lll = l % (a * b)
        if (lll == 0):
            lll = a * b
        answ += ans[a * b - 1] - ans[lll - 1]
        answ += ans[(r % (a * b))]
        print(answ, end = ' ')
    print(' ')