Problem: You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 

Solution (in PYTHON3):

Solution:
import math 
def func(a,b,l):
	start = max(a,b)
	if start>l:
		return 0 
	gc = (a*b)//math.gcd(a,b)

	time = l//gc 
	count = 0 
	if time > 0 and gc*time+max(a,b)-1 <= l:
		count = time+(max(a,b)-1)*time
	elif time > 0 :
		count = time+(max(a,b)-1)*(time-1)+(l%max(a,b))
	# print(gc,time,count)
	return l-(count+start-1) 	




for _ in range(int(input())):
	(a,b,q) = map(int,input().split())
	li = []
	for _ in range(q):
		(l,r) = map(int,input().split())
		li.append(func(a,b,r)-func(a,b,l-1))
	print(*li)


# a = 7
# b = 10

# count = 0 
# for i in range(1,100):
# 	if (i%a)%b != (i%b)%a:
# 		count+=1 
# 	else:
# 		print(i)
# print(25,count)
# count = 0
# for i in range(1,201):
# 	if (i%a)%b != (i%b)%a:
# 		count+=1 
# 	else:
# 		print(i)
# print(25,count)