Problem: You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 

Solution (in PYTHON3):

Solution:
for _ in range(int(input())):
    a,b,q=map(int,input().split())
    prefix=[0]*(a*b+2)
    v=[]
    for i in range(1,a*b):
        if ((i%a)%b)!=((i%b)%a):
            v.append(i)
            prefix[i]=prefix[i-1]+1
        else:
            prefix[i]=prefix[i-1]
            
    for _ in range(q):
        l,r=map(int,input().split())
        
        l_grp=l//(a*b)
        r_grp=r//(a*b)
        ans=(r_grp-l_grp+1)*prefix[a*b-1]
        ans-=prefix[a*b-1]-prefix[r%(a*b)]
        if l%(a*b)!=0:
            ans-=prefix[l%(a*b)-1]
        print(ans,end=" ")
    print()