Problem: You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 

Solution (in PYTHON3):

Solution:
from math import gcd


def solve(rf):
    r1 = rf // b
    ans = (r1 - (r1 - 1) // a) * b
    if r1 % a:
        ans += rf - r1 * b
    return ans


def input_and_solve(_):
    li, r = map(int, input().split())
    return solve(r + 1) - solve(li)


for _ in range(int(input())):
    a, b, q = map(int, input().split())
    if a > b:
        a, b = b, a
    # x % a % b != x % b % a <=> x % a != x % b % a <=> (x - x % b) % a <=> x // b * b % a
    a //= gcd(a, b)
    # x // b % a
    print(*map(input_and_solve, range(q)))