Problem: You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 

Solution (in PYTHON3):

Solution:
T = int(input())

for t in range(T):
    a, b, q = [int(i) for i in input().split()]
    queries = []
    for j in range(q):
        li, ri = [int(i) for i in input().split()]
        queries.append((li, ri))

    if a == b:
        print(' '.join(['0'] * len(queries)))
        continue

    a, b = min(a, b), max(a, b)

    count = 0
    V = [0]
    for x in range(1, a*b):
        if (x % a) % b != (x % b) % a:
            count += 1
        V.append(count)

    # print('a=', a, ' b=', b, ' V=', V)

    results = []
    for query in queries:
        l, r = query[0], query[1]

        ll = l - l % (a*b)
        lr = r - r % (a*b)
        # print('query (', l, ',', r, ') => (ll=', ll, ', lr=', lr)
        answer = ((lr-ll) // (a*b)) * count + V[r % (a*b)]
        if ll != l:
            answer -= V[(l-1) % (a*b)]
        results.append(answer)

    print(' '.join([str(r) for r in results]))