Problem: You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 

Solution (in PYTHON3):

Solution:
def calc(arr, p, n):
    return(arr[n - 1] * (p // n) + arr[p % n])


t = int(input())
for T in range(t):
    a, b, q = [int(x) for x in input().split()]
    if a > b:
        a, b = b, a
    ans = [0] * q
    arr = [0] * (b * a)
    for i in range(1, a * b):
        arr[i] = arr[i - 1]
        if(i % a % b != i % b % a):
            arr[i] += 1
    
    for Q in range(q):
        l, r = [int(x) for x in input().split()]
        ans[Q] = calc(arr, r, a * b) - calc(arr, l - 1, a * b)

    print(*ans)