Problem: You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 

Solution (in PYTHON3):

Solution:
import math
def call(x,lcm,b):
    return (lcm-b)*(x//lcm)
t=int(input())
for _ in range(t):
    a,b,q=map(int,input().split())
    a,b=min(a,b),max(a,b)
    lcm=(a*b)//(math.gcd(a,b))
    dp=[0]*(lcm)
    for i in range(b,lcm):
        dp[i]+=dp[i-1]+1
    ans=[]
    for _ in range(q):
        l,r=map(int,input().split())
        ans.append(call(r,lcm,b)+dp[r%lcm]-call(l-1,lcm,b)-dp[(l-1)%lcm])
    print(*ans)