Problem: You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 

Solution (in PYTHON3):

Solution:
# Whatever the mind of man can conceive and believe, it can achieve. Napoleon Hill
# by : Blue Edge - Create some chaos

def gcd(a,b):
    if b==0:
        return a
    return gcd(b,a%b)

def lcm(a,b):
    return (a*b)//gcd(a,b)

for _ in range(int(input())):
    a,b,q=map(int,input().split())
    m,n=max(a,b),min(a,b)
    lm=lcm(m,n)
    p=[]
    while q:
        q-=1
        l,r=map(int,input().split())
        l1=l//lm + int(l%lm!=0)
        l2=r//lm
        if l%lm==0:
            p1=0
        else:
            p1=lm-max(m,l%lm)

        p2=max(m-1,r%lm)-m+1
        mid=(l2-l1)*(lm-m)
        # print(p1,mid,p2,l1,l2)
        p.append(p1+p2+mid)

    print(*p)