Problem: You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 

Solution (in PYTHON3):

Solution:
import math

def solve(r, lcm, b):
    total = r
    div = int(r // lcm)
    prod = div * lcm
    if div != 0:
        total -= (div - 1) * b
        total -= min(b, r - prod + 1)
    total -= min(r, b - 1)
    return total

t = int(input())
while t:
    t = t - 1
    a, b, q = map(int, input().split())
    for w in range(q):
        l, r = map(int, input().split())
        a, b = min(a, b), max(a,b)
        lcm = int((a * b) // math.gcd(a, b))
        if r < b or lcm == b:
            print(0, end=' ')
            continue
        ans = solve(r, lcm, b)
        if l > 1:
            ans -= solve(l - 1, lcm, b)
        print(ans, end=' ')
    print()