Problem: You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 

Solution (in PYTHON3):

Solution:
import sys
input = sys.stdin.buffer.readline
ans=[]
for _ in range(int(input())):
	a,b,q=map(int,input().split())
	m=a*b
	ret=[]
	c=[int(i%a%b!=i%b%a) for i in range(m)]
	s=sum(c)
	for i in range(m-1):
		c[i+1]+=c[i]
	for _ in range(q):
		l,r=map(int,input().split())
		rr=(r//m)*s+c[r%m]
		ll=((l-1)//m)*s+c[(l-1)%m]
		ret.append(rr-ll)
	ans.append(" ".join(map(str,ret)))
print("\n".join(ans))