Problem: You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 

Solution (in PYTHON3):

Solution:
def gcd(a, b):
    if a == 0:
        return b
    return gcd(b % a, a)


def lcm(a, b):
    return (a * b) / gcd(a, b)


t = int(input())

for test in range(t):
    a, b, q = list(map(int, input().split()))

    if a == b:
        for query in range(q):
            l, r = list(map(int, input().split()))
            print(int(0), end=" ")
        print()

    else:
        greater = max(a, b)
        smaller = min(a, b)
        lc = int(lcm(greater, smaller))
        count = 0
        valid_list = [0] * lc
        valid_count = [0] * lc

        for i in range(0, lc):
            if ((i % smaller) % greater) != ((i % greater) % smaller):
                count += 1
                valid_list[i] = 1
            valid_count[i] = count

        for query in range(q):
            l, r = list(map(int, input().split()))

            #total_range = r - l + 1
            #num_to_check = total_range % lc
            ans = 0

            cycles_l = (l-1) // lc
            rem_l = (l-1) % lc
            ans_l = (cycles_l * count) + valid_count[rem_l]
            

            cycles_r = r // lc
            rem_r = r % lc
            ans_r = (cycles_r * count) + valid_count[rem_r]

            ans = ans_r - ans_l


            print(int(ans), end=" ")
        print()