Problem: You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 

Solution (in PYTHON3):

Solution:
import math
t=int(input())

def findcount(r,lcm,b):
    div = r//lcm
    prod = div*lcm
    tot=r
    if(div!=0):
        tot-=min(b,r-prod+1)
        tot -= (div-1)*b
    return (tot-min(r,(b-1)))

while(t>0):
    a, b, q = map(int, input().split())
    if(a>b):
        a,b = b,a
    
    lc=(a*b)//(math.gcd(a,b))
    
    for i in range(q):
        l, r = map(int, input().split())
       
        if(lc==b or (r<b)):
            print(0," ")
            continue
        cnt = findcount(r,lc,b)
        if(l>1):
            cnt-=findcount(l-1,lc,b)
        print(cnt," ")
    print() 
    t=t-1