Problem: You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 

Solution (in PYTHON3):

Solution:
t=int(input())
for i in range(t):
    a,b,q=map(int,input().strip().split(" "))
    def gcd(a,b): 
        if a == 0: 
            return b 
        return gcd(b % a, a) 
  
# Function to return LCM of two numbers 
    def lcm(a,b): 
        return (a*b) // gcd(a,b) 
    lcm_=lcm(a,b)
    for j in range(q):
        l,r=map(int,input().strip().split(" "))
        def calculate(l,lcm_,a,b):
            k=l//lcm_
            count=k*max(a,b)
            if(lcm_*k+max(a,b)-1<=l):
                count+=max(a,b)
            else:
                count+=(l-lcm_*k+1)
            return count
        res=calculate(r,lcm_,a,b)-calculate(l-1,lcm_,a,b)
        print(r-l+1-res,end=" ")
    print()