Problem: You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 

Solution (in PYTHON3):

Solution:
import sys
import heapq
import math
import bisect

def input():
    return sys.stdin.readline().strip()
 
def iinput():
    return int(input())
 
def rinput():
    return map(int, input().split())

def rlinput():
    return list(map(i, input().split()))

def srlinput():
    return sorted(list(map(int, input().split())))

def main():
    def pro(x):
        return len(w) * (x//(a * b)) + bisect.bisect_right(w, x % (a * b))
    a, b, q = rinput()
    w = []
    for i in range(a*b):
        if (i % a) % b != (i % b) % a:
            w.append(i)
    for i in range(q):
        l,r=rinput()
        print(pro(r) - pro(l - 1), end=" ")
    print()
    
            
for i in range(iinput()):
    main()