Problem: Soumika has a string S and its starting index is 1. The string S consists of characters from 1-9. As she is very intelligent, she wants to test his brother Vinay Tendulkar. She asked her brother Vinay Tendulkar to count the number of even numbered characters ( i.e  2,4,6,8 ) for every index i   (1 ≤  i  ≤ | S|). For an index i, the result should be calculated from i to the end of the string. As Vinay doesn't know  about programming, he wants you to help him find the solution.   

Input:
First line contains a string  S. 

Output:
Print |S| space-separated integers,the result of every index.

Constraints:
1 ≤ |S| ≤ 10^4

SAMPLE INPUT
574674546476

SAMPLE OUTPUT
7 7 7 6 5 5 4 4 3 2 1 1

Explanation

Given string S is 574674546476.
for index 1
Number of even numbers from 5 to end of the  string is 7 so the result of  index 1 is 7.
for index 2
Number of even numbers from 7 to end of the  string is 7  so the result of  index 2 is 7.
for index 3
Number of even numbers from 4 to end of the  string is 7 so the result of  index 3 is  7.
for index 3
Number of even numbers from 6 to end of the  string is  6 so the result of  index 4 is  6.....
...

Solution (in PYTHON):

Solution:
'''
# Read input from stdin and provide input before running code

name = raw_input('What is your name?\n')
print 'Hi, %s.' % name
'''
string=raw_input()
count=0
a=[]
for i in range(len(string)):
    if(int(string[i])%2==0):
        count=count+1
a.append(count)
for i in range(1,len(string)):

    if(int(string[i])%2==0 and int(string[i-1])%2==0):
        count=count-1
        a.append(count)
    elif(int(string[i])%2==0 and int(string[i-1])%2!=0):
        
        a.append(count)
    elif(int(string[i])%2!=0 and int(string[i-1])%2==0):
        count=count-1
        a.append(count)
    else:
        a.append(count)
        
    
final=" ".join(str(i) for i in a)
print final