Problem: Mike and Ann are sitting in the classroom. The lesson is boring, so they decided to play an interesting game. Fortunately, all they need to play this game is a string s and a number k (0 ≤ k < |s|).

At the beginning of the game, players are given a substring of s with left border l and right border r, both equal to k (i.e. initially l=r=k). Then players start to make moves one by one, according to the following rules:

  * A player chooses l^{\prime} and r^{\prime} so that l^{\prime} ≤ l, r^{\prime} ≥ r and s[l^{\prime}, r^{\prime}] is lexicographically less than s[l, r]. Then the player changes l and r in this way: l := l^{\prime}, r := r^{\prime}.
  * Ann moves first.
  * The player, that can't make a move loses.



Recall that a substring s[l, r] (l ≤ r) of a string s is a continuous segment of letters from s that starts at position l and ends at position r. For example, "ehn" is a substring (s[3, 5]) of "aaaehnsvz" and "ahz" is not.

Mike and Ann were playing so enthusiastically that they did not notice the teacher approached them. Surprisingly, the teacher didn't scold them, instead of that he said, that he can figure out the winner of the game before it starts, even if he knows only s and k.

Unfortunately, Mike and Ann are not so keen in the game theory, so they ask you to write a program, that takes s and determines the winner for all possible k.

Input

The first line of the input contains a single string s (1 ≤ |s| ≤ 5 ⋅ 10^5) consisting of lowercase English letters.

Output

Print |s| lines.

In the line i write the name of the winner (print Mike or Ann) in the game with string s and k = i, if both play optimally

Examples

Input


abba


Output


Mike
Ann
Ann
Mike


Input


cba


Output


Mike
Mike
Mike

Solution (in JAVA):

Solution:
import java.util.*;
import java.io.*;
  
public class A2 {   
 
    public static BufferedReader br;
    public static StringTokenizer st;
    public static String next() {
        while (st == null || !st.hasMoreTokens()) {
            try {
                st = new StringTokenizer(br.readLine());
            } catch (Exception e) {
                throw new RuntimeException(e);
            }
        }
        return st.nextToken();
    }
 
    public static Integer nextInt() {
        return Integer.parseInt(next());
    }
 
    public static Long nextLong() {
        return Long.parseLong(next());
    }
 
    public static Double nextDouble() {
        return Double.parseDouble(next());
    }
 
    static long fast_pow(long base,long n,long M)
    {
        if(n==0)
           return 1;
        if(n==1)
        return base;
        long halfn=fast_pow(base,n/2,M);
        if(n%2==0)
            return ( halfn * halfn ) % M;
        else
            return ( ( ( halfn * halfn ) % M ) * base ) % M;
    }
 
    static long finextDoubleMMI_fermat(long n,int M)
    {
        return fast_pow(n,M-2,M);
    }
 
    static long nCrModPFermat(int n, int r, int p) 
    { 
        if (r == 0) 
            return 1; 
        long[] fac = new long[n+1]; 
        fac[0] = 1;           
        for (int i = 1 ;i <= n; i++) 
            fac[i] = fac[i-1] * i % p;       
        return (fac[n]* finextDoubleMMI_fermat(fac[r], p)% p * finextDoubleMMI_fermat(fac[n-r], p) % p) % p; 
    } 
 
    static void merge(int arr[], int l, int m, int r) 
    { 
        int n1 = m - l + 1; 
        int n2 = r - m; 
  
        int L[] = new int [n1]; 
        int R[] = new int [n2]; 
  
        for (int i=0; i<n1; ++i) 
            L[i] = arr[l + i]; 
        for (int j=0; j<n2; ++j) 
            R[j] = arr[m + 1+ j]; 
        int i = 0, j = 0; 
        
        int k = l; 
        while (i < n1 && j < n2) 
        { 
            if (L[i] <= R[j]) 
            { 
                arr[k] = L[i]; 
                i++; 
            } 
            else
            { 
                arr[k] = R[j]; 
                j++; 
            } 
            k++; 
        } 
  
        while (i < n1) 
        { 
            arr[k] = L[i]; 
            i++; 
            k++; 
        } 
  
        while (j < n2) 
        { 
            arr[k] = R[j]; 
            j++; 
            k++; 
        } 
    } 
  
    static void sort(int arr[], int l, int r) 
    { 
        if (l < r) 
        { 
            int m = (l+r)/2; 
            sort(arr, l, m); 
            sort(arr , m+1, r); 
            merge(arr, l, m, r); 
        } 
    } 
 
    static void sort(int arr[]) 
    { 
        int l=0;
        int r=arr.length-1;
        if (l < r) 
        { 
            int m = (l+r)/2; 
            sort(arr, l, m); 
            sort(arr , m+1, r); 
            merge(arr, l, m, r); 
        } 
    } 

    static long gcd(long a, long b){
        if(a%b==0)
            return b;
        if(b%a==0)
            return a;
        if(a>b)
            return gcd(a%b,b);
        return gcd(a,b%a);
    }

    static class Item{
        int a;
        int b;
        Item(int a,int b){
            this.a=a;
            this.b=b;
        }
    }
 
    static PrintWriter pw = new PrintWriter(new BufferedWriter(new OutputStreamWriter(System.out)));
    
    static class sorting implements Comparator<Item>{  
        public int compare(Item o1,Item o2){  
            if(o1.b==o2.a)
                return 0;  
            else if(o1.b>o2.a)  
                return 1;  
            else  
                return -1;  
        }
    }  

    public static void main(String args[])throws IOException{
        int i,j;
        br = new BufferedReader(new InputStreamReader(System.in));
        String s=next();
        int n=s.length();
        int h[]=new int[n];
        for(i=0;i<n;i++){
            int c=s.charAt(i)-97;
            if(i==0)
                h[i]=c;
            else
                h[i]=Math.min(h[i-1],c);
        }
        for(i=0;i<n;i++){
            int c=s.charAt(i)-97;
            if(h[i]<c){
                pw.println("Ann");
                continue;
            }
            else{
                pw.println("Mike");
            }
        }
        pw.close();
    }
}