Problem: You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 

Solution (in PYTHON3):

Solution:
import math
for nt in range(int(input())):
	a,b,q=map(int,input().split())
	lcm = (a*b)//math.gcd(a,b)
	for i in range(q):
		l,r=map(int,input().split())
		if b%a==0 or a%b==0:
			print (0,end=" ")
			continue
		ans=r-l+1
		m=max(a,b)
		x=l//lcm+1
		y=r//lcm
		ans-=max(0,y-x+1)*m
		i=l
		# print (ans,y,x)
		while ((i%a)%b)==((i%b)%a) and i<=r:
			ans-=1
			i+=1
		j=r+1
		if x<=y and j%lcm!=0:
			while ((j%a)%b)==((j%b)%a):
				ans+=1
				j+=1
		print (ans,end=" ")
	print ()