Problem: You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 

Solution (in PYTHON3):

Solution:
import sys

input = sys.stdin.readline

import math


def solve(n, lc, a, b):
    x = n // lc
    ans = 0
    if x > 0:
        ans += ((n // lc) - 1) * max(a, b)
        ans += min(n % lc + 1, max(a, b))
    ans += min(max(a, b) - 1, n)
    return ans


def main():
    t = int(input())
    for _ in range(t):
        A, B, Q = [int(x) for x in input().split()]
        LR = [[int(x) for x in input().split()] for _ in range(Q)]

        ans = []
        lc = (A * B) // math.gcd(A, B)
        for l, r in LR:
            rn = solve(r, lc, A, B)
            ln = solve(l - 1, lc, A, B)

            ans.append((r - l + 1) - (rn - ln))

        print(*ans)


if __name__ == '__main__':
    main()
    # print(solve(140, 70, 7, 10))