Problem: You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 

Solution (in PYTHON3):

Solution:
from sys import stdin
input=stdin.readline
t=int(input())
for _ in range(t):
  a,b,q=map(int,input().split())
  c=a*b
  s=[0]*c
  for i in range(c):
    if (i%a)%b!=(i%b)%a:
      s[i]+=1
  for i in range(1,c):
    s[i]+=s[i-1]
  ans=[]
  for __ in range(q):
    l,r=map(int,input().split())
    l-=1
    rp=r//c
    rm=r%c
    lp=l//c
    lm=l%c
    rx=rp*s[-1]
    if rm>0:
      rx+=s[rm]
    lx=lp*s[-1]
    if lm>0:
      lx+=s[lm]
    ans.append(rx-lx)
  print(*ans)