Problem: You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 

Solution (in PYTHON3):

Solution:
from math import gcd
import sys
from copy import copy, deepcopy
input = sys.stdin.readline
'''
n, m = map(int, input().split())
n = int(input())
A = list(map(int, input().split()))
S = input().strip()
for CASES in range(int(input())):
'''
inf = 100000000000000000  # 1e17
mod = 998244353

'''
# example input


'''


for CASES in range(int(input())):
    a, b, q = map(int, input().split())
    lcm = b // gcd(a, b) * a
    A = [0] * (lcm + 3)
    for i in range(lcm):
        A[i + 1] = A[i]
        if i % a % b != i % b % a:
            A[i + 1] += 1
    ANS = []
    for QUERY in range(q):
        l, r = map(int, input().split())
        divl, resl = divmod(l, lcm)
        divr, resr = divmod(r, lcm)
        ANS.append((divr - divl) * A[lcm] - A[resl] + A[resr + 1])

    print(*ANS)