Problem: A tree is an undirected connected graph without cycles.

Let's consider a rooted undirected tree with n vertices, numbered 1 through n. There are many ways to represent such a tree. One way is to create an array with n integers p1, p2, ..., pn, where pi denotes a parent of vertex i (here, for convenience a root is considered its own parent).

<image> For this rooted tree the array p is [2, 3, 3, 2].

Given a sequence p1, p2, ..., pn, one is able to restore a tree:

  1. There must be exactly one index r that pr = r. A vertex r is a root of the tree. 
  2. For all other n - 1 vertices i, there is an edge between vertex i and vertex pi. 



A sequence p1, p2, ..., pn is called valid if the described procedure generates some (any) rooted tree. For example, for n = 3 sequences (1,2,2), (2,3,1) and (2,1,3) are not valid.

You are given a sequence a1, a2, ..., an, not necessarily valid. Your task is to change the minimum number of elements, in order to get a valid sequence. Print the minimum number of changes and an example of a valid sequence after that number of changes. If there are many valid sequences achievable in the minimum number of changes, print any of them.

Input

The first line of the input contains an integer n (2 ≤ n ≤ 200 000) — the number of vertices in the tree.

The second line contains n integers a1, a2, ..., an (1 ≤ ai ≤ n).

Output

In the first line print the minimum number of elements to change, in order to get a valid sequence.

In the second line, print any valid sequence possible to get from (a1, a2, ..., an) in the minimum number of changes. If there are many such sequences, any of them will be accepted.

Examples

Input

4
2 3 3 4


Output

1
2 3 4 4 


Input

5
3 2 2 5 3


Output

0
3 2 2 5 3 


Input

8
2 3 5 4 1 6 6 7


Output

2
2 3 7 8 1 6 6 7

Note

In the first sample, it's enough to change one element. In the provided output, a sequence represents a tree rooted in a vertex 4 (because p4 = 4), which you can see on the left drawing below. One of other correct solutions would be a sequence 2 3 3 2, representing a tree rooted in vertex 3 (right drawing below). On both drawings, roots are painted red.

<image>

In the second sample, the given sequence is already valid.

Solution (in JAVA):

Solution:
import java.util.*;
import java.io.*;
public class Main {
    static class Scan {
        private byte[] buf=new byte[1024];
        private int index;
        private InputStream in;
        private int total;
        public Scan()
        {
            in=System.in;
        }
        public int scan()throws IOException
        {
            if(total<0)
            throw new InputMismatchException();
            if(index>=total)
            {
                index=0;
                total=in.read(buf);
                if(total<=0)
                return -1;
            }
            return buf[index++];
        }
        public int scanInt()throws IOException
        {
            int integer=0;
            int n=scan();
            while(isWhiteSpace(n))
            n=scan();
            int neg=1;
            if(n=='-')
            {
                neg=-1;
                n=scan();
            }
            while(!isWhiteSpace(n))
            {
                if(n>='0'&&n<='9')
                {
                    integer*=10;
                    integer+=n-'0';
                    n=scan();
                }
                else throw new InputMismatchException();
            }
            return neg*integer;
        }
        public double scanDouble()throws IOException
        {
            double doub=0;
            int n=scan();
            while(isWhiteSpace(n))
            n=scan();
            int neg=1;
            if(n=='-')
            {
                neg=-1;
                n=scan();
            }
            while(!isWhiteSpace(n)&&n!='.')
            {
                if(n>='0'&&n<='9')
                {
                    doub*=10;
                    doub+=n-'0';
                    n=scan();
                }
                else throw new InputMismatchException();
            }
            if(n=='.')
            {
                n=scan();
                double temp=1;
                while(!isWhiteSpace(n))
                {
                    if(n>='0'&&n<='9')
                    {
                        temp/=10;
                        doub+=(n-'0')*temp;
                        n=scan();
                    }
                    else throw new InputMismatchException();
                }
            }
            return doub*neg;
        }
        public String scanString()throws IOException
        {
            StringBuilder sb=new StringBuilder();
            int n=scan();
            while(isWhiteSpace(n))
            n=scan();
            while(!isWhiteSpace(n))
            {
                sb.append((char)n);
                n=scan();
            }
            return sb.toString();
        }
        private boolean isWhiteSpace(int n)
        {
            if(n==' '||n=='\n'||n=='\r'||n=='\t'||n==-1)
            return true;
            return false;
        }
    }
    static ArrayList<Integer> adj_lst[];
    static boolean vis[];
    static int fin_root=-1;
    static int color[];
    public static void main(String args[]) throws IOException {
        Scan input=new Scan();
        int n=input.scanInt();
        int arr[]=new int[n];
        for(int i=0;i<n;i++) {
            arr[i]=input.scanInt()-1;
        }
        //No of nodes
        adj_lst=new ArrayList[n];
        vis=new boolean[n];
        for(int i=0;i<n;i++) {
            adj_lst[i]=new ArrayList<Integer>();
        }
        //No of edges
        for(int i=0;i<n;i++) {
            // input u & v
            if(arr[i]==i) {
                continue;
            }
            adj_lst[arr[i]].add(i);
        }
        color=new int[n];
        boolean par[]=new boolean[n];
        for(int i=0;i<n;i++) {
            for(int j=0;j<adj_lst[i].size();j++) {
                par[adj_lst[i].get(j)]=true;
            }
        }
        int root=-1,clr=1;
        for(int i=0;i<n;i++) {
            if(!par[i]) {
                root=i;
                DFS(i,clr);
                clr++;
            }
        }
        for(int i=0;i<n;i++) {
            if(!vis[i]) {
                DFS(i,clr);
                clr++;
            }
        }
        
//        for(int i=0;i<adj_lst.length;i++) {
//            System.out.print((i+1)+"->");
//            for(int j=0;j<adj_lst[i].size();j++) {
//                System.out.print((adj_lst[i].get(j)+1)+" ");
//            }
//            System.out.println();
//        }
        par=new boolean[n];
        for(int i=0;i<n;i++) {
            for(int j=0;j<adj_lst[i].size();j++) {
                par[adj_lst[i].get(j)]=true;
            }
        }
        if(root==-1) {
            for(int i=0;i<n;i++) {
                if(!par[i]) {
                    root=i;
                    break;
                }
            }
        }
//        System.out.println(root);
        for(int i=0;i<n;i++) {
            if(!par[i] && i!=root) {
//                System.out.println(first+" "+i);
                adj_lst[root].add(i);
            }
        }
        
        int ans[]=new int[n];
        for(int i=0;i<n;i++) {
            for(int j=0;j<adj_lst[i].size();j++) {
                ans[adj_lst[i].get(j)]=i;
            }
        }
        ans[root]=root;
        int cnt=0;
        for(int i=0;i<n;i++) {
            if(arr[i]!=ans[i]) {
                cnt++;
            }
        }
        StringBuilder fin=new StringBuilder("");
        for(int i=0;i<n;i++) {
            ans[i]++;
            fin.append(ans[i]+" ");
        }
        System.out.println(cnt+"\n"+fin);
    }
    public static void DFS(int root,int clr) {
//        System.out.println(root);
        color[root]=clr;
        vis[root]=true;
        for(int i=0;i<adj_lst[root].size();i++) {
            if(!vis[adj_lst[root].get(i)]) {
                DFS(adj_lst[root].get(i),clr);
            }
            else if(color[adj_lst[root].get(i)]==clr){
                adj_lst[root].remove(i);
                i--;
            }
        }
    }
}