Problem: problem

AOR Ika likes rooted trees with a fractal (self-similar) structure. Consider using the weighted rooted tree $ T $ consisting of $ N $ vertices to represent the rooted tree $ T'$ with the following fractal structure.

* $ T'$ is the addition of a tree rooted at $ x $ and having a tree structure similar to $ T $ (same cost) for each vertex $ x $ of $ T $.
* The root of $ T'$ is the same as that of $ T $.



The tree represented in this way is, for example, as shown in the figure below.

<image>

AOR Ika is trying to do a depth-first search for $ T'$, but finds that it takes a lot of time to trace all the vertices. Therefore, we decided to skip some node visits by performing a depth-first search with a policy of transitioning with a probability of $ p $ and not transitioning with a probability of $ 1-p $ at the time of transition during a depth-first search. Given $ T $ and the probability $ p $, find the expected value of the sum of the costs of all edges to follow when performing a depth-first search for $ T'$. The information of $ T $ is given by the number of vertices $ N $ and the information of the edges of $ N-1 $, and the vertex $ 1 $ is the root. Each vertex is labeled $ 1,2, \ dots, N $, and the $ i \ (1 \ le i \ le N-1) $ th edge costs the vertices $ x_i $ and $ y_i $ $ c_i $ It is tied with. The non-deterministic algorithm of the depth-first search that transitions to a child with a probability of $ p $, which is dealt with in this problem, is expressed as follows. The sum of the costs of the edges that the output $ \ mathrm {answer} $ follows.

1. Prepare an empty stack $ S $.
2. Set $ ​​\ mathrm {answer} = 0 $
3. Push the root vertex of $ T'$ to $ S $.
4. Extract the first element of $ S $ and make it $ x $.
5. For each child $ c $ of $ x $, do the following with probability $ p $ and do nothing with probability $ 1-p $.
* Add vertex $ c $ to $ S $. Then add the weight of the edge connecting $ x $ to $ c $ to $ \ mathrm {answer} $.
6. If S is not empty, transition to 3.
7. Output $ \ mathrm {answer} $.



output

Print the answer in one line. If the relative or absolute error is less than $ 10 ^ {-6} $, then AC. Also, output a line break at the end.

Example

Input

0.75
4
1 2 1
2 3 3
3 4 10


Output

24.8569335938

Solution (in CPP):

Solution:
#include "bits/stdc++.h"
using namespace std;
typedef long long ll;
const ll MOD = 1e9 + 7;
using PII = pair<ll, ll>;
#define FOR(i,a,n) for(ll i=(ll)a; i<(ll)n; ++i)
#define REP(i,n) FOR(i,0,n)

int main() {
	double p;
	ll n;
	cin >> p >> n;
	vector<vector<PII>> g(n);
	REP(i, n - 1) {
		ll a, b, c;
		cin >> a >> b >> c;
		a--, b--;
		g[a].push_back({ b, c });
		g[b].push_back({ a, c });
	}

	double all = 0;
	function<void(ll, ll, double)> pre = [&](ll v, ll par, double prob) {
		for (auto to : g[v]) {
			if (to.first == par) continue;
			all += prob * to.second;
			pre(to.first, v, prob * p);
		}
	};
	pre(0, -1, p);

	double ans = 0;
	function<void(ll, ll, double)> dfs = [&](ll v, ll par, double prob) {
		ans += prob * all;
		for (auto to : g[v]) {
			if (to.first == par) continue;
			ans += prob * p * to.second;
			dfs(to.first, v, prob*p);
		}
	};
	dfs(0, -1, 1);
	
	cout << fixed << setprecision(9) << ans << endl;
}