Problem: You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 

Solution (in PYTHON3):

Solution:
import math

def lcm(a, b):
    return abs(a * b) // math.gcd(a, b)

def func(n, a, b):
    mx = max(a, b)
    lc = lcm(a, b)
    c = n // lc
    g = n % lc
    if(g >= mx):
        res = (n - (c + 1) *  mx) + 1
    else:
        res = c * lc - c * mx
    return(res)

t = int(input())
res = []

for _ in range(t):
    a, b, q = map(int, input().split())
    temp = []
    for _ in range(q):
        l, r = map(int, input().split())
        if(lcm(a, b) == max(a, b)):
            temp.append(str(0))
        else:
            temp.append(str(func(r, a, b) - func(l - 1, a, b)))
    res.append(' '.join(temp))

for r in res:
    print(r)