Problem: You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 

Solution (in PYTHON3):

Solution:

from math import gcd
import sys
input = sys.stdin.readline
 
for _ in range(int(input())):
    a, b, q = map(int, input().split())
    if a > b:
        a, b = b, a
    lcm = a * b // gcd(a, b)
    ans = [0]*q
 
    for i in range(q):
        l, r = map(int, input().split())
        edge = r // lcm * lcm
        sub = (r // lcm) * b + min(b, r-edge+1)
        #print(sub)
        l -= 1
        edge_l = l // lcm * lcm
        sub -= (l // lcm) * b + min(b, l-edge_l+1)
        #print(sub)
        ans[i] = r - l - sub
 
    print(*ans)
'''for i in range(100,201):
    
    print(((i)%7)%10,((i)%10)%7,i)
    if ((i)%7)%10==((i)%10)%7:
        print("yes")'''