Problem: You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 

Solution (in PYTHON3):

Solution:
def gcd(a,b):
    if b==0:
        return a
    return gcd(b,a%b)
n = int(input())
for k in range(n):
    a,b, q = map(int, input().split())
    m = a*b//gcd(a,b)
    f = [0]*m
    for i in range(1,m):
        f[i] = f[i-1]
        if i%a%b != i%b%a:
            f[i] += 1
    res_list = []
    for _ in range(q):
        l,r = map(int, input().split())
        l -= 1

        res = (r//m)*f[m-1] + f[r%m]
        res -= (l//m)*f[m-1] + f[l%m]
        res_list.append(res)
    print(" ".join(map(str,res_list)))