Problem: You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 

Solution (in PYTHON3):

Solution:
T = int(input())
for t in range(T):
    a, b, Q = [int(i) for i in input().split()]
    prod = a*b
    precompute = [(i%a)%b != (i%b)%a for i in range(prod+1)]
    prefix = [0 for i in range(prod+1)]
    prefix[0] = 0
    for i in range(1, prod+1):
        prefix[i] = prefix[i-1] + (1 if precompute[i] else 0)
    def total_seg(x):
        ans = x // prod * prefix[-1]
        tmp = x % prod
        if tmp > 0:
            ans += prefix[tmp]
        return ans
    final = []
    for q in range(Q):
        l, r = [int(i) for i in input().split()]
        final.append(total_seg(r) - total_seg(l-1))
    print(*final)