Problem: You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 

Solution (in PYTHON3):

Solution:
from collections import deque, defaultdict, Counter
from bisect import bisect_left, bisect #bisect(list, num, beg, end)
import math
def test_case():
    # n = int(input())
    info = list(map(int, input().split()))
    a, b, q = info
    # a = list(map(int, input().split()))
    ans = []
    u = [0]*(a*b)
    for i in range(1, a*b):
        u[i] = u[i-1] + int(i % a %b != i % b % a)
    for _ in range(q):
        l, r = map(int, input().split())
        count = 0
        count += r//(a*b) * u[-1] + u[r%(a*b)]
        count -= (l-1)//(a*b) * u[-1] + u[(l-1)%(a*b)]
        ans.append(count)
    print(*ans)
for _ in range(int(input())):

    ret = test_case()
    if ret != None:
        print(ret)