Problem: You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 

Solution (in PYTHON3):

Solution:
def swap(a, b):
    temp = a
    a = b
    b = temp


for _ in range(int(input())):
    a, b, q = [int(i) for i in input().split()]
    if a > b:
        swap(a, b)
    pre = [0 for i in range(a * b + 2)]

    for i in range(1, a * b ):
        if (i % a) % b != (i % b) % a:
            pre[i] = pre[i - 1] + 1
        else:
            pre[i] = pre[i - 1]
    # print(pre)
    # print([i for i in range(a*b+2)])
    for i in range(q):
        l, r = [int(i) for i in input().split()]

        l_gr = l // (a * b)
        r_gr = r // (a * b)
        ans = (r_gr - l_gr + 1) * pre[a * b - 1]
        ans = ans - pre[a*b - 1] + pre[r % (a * b)]
        if l % (a * b) != 0:
            ans = ans - pre[l % (a * b) - 1]
        print(ans)