Problem: You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 

Solution (in PYTHON3):

Solution:
import sys
import math

def lcm(a, b):
        return abs(a*b) // math.gcd(a, b)

def F(n, a, b):
    return (n // lcm(a, b))*a + min(a, n % lcm(a, b))

t = int(input())

for i in range(0, t):
    a, b, q = map(int, input().split())
    if(a < b):
        temp = a
        a = b
        b = temp
    for j in range(0, q):
        l, r = map(int, input().split())
        r += 1
        ans = (r-F(r, a, b)) - (l-F(l, a, b))
        print(ans, end = ' ')
    print()

#a, b = map(int, input().split())
#
#A = [0] * 10000
#A[0] = 0;
#
#for i in range(1, 10000):
#    A[i] = A[i-1]
#    if(i%a%b != i%b%a):
#        A[i] += 1
#    if(A[i] != i-F(i, a, b)):
#        print("wrong")
#        print(i)
#        print(i-F(i, a, b))
#        print(A[i])
#        break
#