Problem: You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 

Solution (in PYTHON3):

Solution:
import sys

read = sys.stdin.buffer.read
input = sys.stdin.buffer.readline
readlines = sys.stdin.buffer.readlines
t = int(input())
for case in range(t):
    a, b, q = map(int, input().split())
    # 事前計算
    mod_dif = [0] * (a * b)
    for i in range(a * b):
        if (i % a) % b != (i % b) % a:
            mod_dif[i] = mod_dif[i - 1] + 1
        else:
            mod_dif[i] = mod_dif[i - 1]
    ans = [0] * q
    for query in range(q):
        x, y = map(int, input().split())
        x_d, x_m = divmod(x - 1, a * b)
        y_d, y_m = divmod(y, a * b)
        ans[query] = (y_d - x_d) * mod_dif[-1] + mod_dif[y_m] - mod_dif[x_m]
    print(*ans)