Problem: You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 

Solution (in PYTHON3):

Solution:
from sys import stdin, stdout
import heapq as hq
from collections import defaultdict

def lcm(x,y):
    m=max(x,y)
    while m%x>0 or m%y>0:
        m+=1
    return m

def truths(inp,m,higher):
    inp+=1
    resu=0
    resu+=(inp//m)*(m-higher)
    inp-=m*(inp//m)
    resu+=max(inp-higher,0)
    return resu

t = int(input())
for tc in range(t):
    a,b,q = list(map(int, stdin.readline().split()))

    m=lcm(a,b)
    higher=max(a,b)
    allEq=False
    if m==higher:
        allEq=True
    for qc in range(q):
        l,r = list(map(int, stdin.readline().split()))
        if allEq:
            res=r-l+1
            res=0 # !!!
        else:
            #print("\n#",truths(r,m,higher),truths(l-1,m,higher))
            res=truths(r,m,higher)-truths(l-1,m,higher)
        stdout.write(str(res) + " ")

    stdout.write("\n")