Problem: You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 

Solution (in PYTHON3):

Solution:
from math import gcd


def lcm(p, q):
    return p*q//gcd(p, q)


def solve(mod, cmax, l, r):
    lmod, ldiv = l % mod, l // mod
    rmod, rdiv = (r + 1) % mod, (r + 1) // mod
    return  r - l - ((rdiv - ldiv) * cmax - min(cmax, lmod) + min(cmax, rmod)) + 1

t = int(input())
for _ in range(t):
    a, b, q = [int(i) for i in input().split()]
    ans = []
    for _ in range(q):
        m, c = lcm(a, b), max(a, b)
        left, right = [int(i) for i in input().split()]
        ans.append(solve(m, c, left, right))
    print(' '.join([str(i) for i in ans]))