Problem: You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 

Solution (in PYTHON3):

Solution:
for i in range(int(input())):
    a, b, q = map(int, input().split())
    check = [0 for _ in range(a * b)]
    for i in range(1, a * b):
        check[i] = check[i - 1]
        if (i % a) % b != (i % b) % a:
            check[i] += 1
    for _ in range(q):
        ans = 0
        l, r = map(int, input().split())
        ch = l % (a * b)
        if ch == 0:
            ch = b * a
        helpp = (l - 1) % (a * b)
        ch = a * b - ch
        if l + ch <= r:
            l += ch
            ans += check[a * b - 1] - check[helpp]
            ch = r - l
            ans += check[-1] * (ch // (a * b))
            ch = ch % (a * b)
            ans += check[ch]
        else:
            ans = check[r % (a * b)] - check[(l - 1) % (a * b)]
        print(ans, end=' ')
    print()