Problem: You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 

Solution (in PYTHON3):

Solution:
input = __import__("sys").stdin.buffer.readline

t = int(input())

for tc in range(t):
    a, b, q = map(int, input().split())
    
    c = [1]
    for x in range(1, a*b):
        c.append(c[-1])
        if (x % a) % b == (x % b) % a:
            c[-1] += 1
    
    def pre(x):
        full = x // (a*b)
        right = x % (a*b)
        
        return full * c[a*b-1] + c[right]
    
    output = []
    for _ in range(q):
        l, r = map(int, input().split())
        
        sol = pre(r) - pre(l-1)
        output.append(str(r-l+1-sol))
        
    print(" ".join(output))