Problem: You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 

Solution (in PYTHON3):

Solution:
def gcd(a,b):
    if a % b == 0: return b
    return gcd(b, a%b)

def calc_lcm(a,b):
    g = gcd(a,b)
    return g * (a // g) * (b // g)

def same(l,r,a,b,lcm):
    left = a * (l // lcm) + min(a, l % lcm)
    right = a * ((r+1) // lcm) + min(a, (r+1) % lcm)
    # print(left,right)
    return right - left 


test_cases = int(input())
for test_case in range(test_cases):
    a,b,q = [int(x) for x in input().split()]
    a,b = max(a,b), min(a,b)
    lcm = calc_lcm(a,b)
    ans = []
    for qr in range(q):
        l,r = [int(inp) for inp in input().split()]
        ans.append(r - l + 1 - same(l,r,a,b,lcm))
    print(*ans)