Problem: You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 

Solution (in PYTHON3):

Solution:
t = int(input())
for u in range(t):
	a,b,q = list(map(int,input().split()))
	c = int(a)
	d = int(b)
	cnt = 19
	while a*b != 0:
		if a < b:
			a,b = b,a
		a = a%b
	nok = (c*d)//max(a,b)
	act = [0]*nok
	for i in range(1,nok+1):
		if ((i%c)%d == (i%d)%c):
			act[i-1] = 0
		else:
			act[i-1] = 1
	dp = [0]*(len(act)+1)
	dp[0] = 0
	dp[1] = act[0]
	for i in range(1,len(act)):
		dp[i+1] = dp[i] + act[i]
	res = ''
	for i in range(q):
		l,r = list(map(int,input().split()))
		if r < (nok):
			res += str(dp[r]-dp[l-1]) + " "
		else:
			if l%nok == 0:
				dpl = (dp[-1]*(l//(nok)))
			else:
				dpl = (dp[-1]*(l//(nok)) + dp[l%(nok)-1])
			res += str(dp[-1]*(r//(nok)) + dp[r%(nok)] - dpl) + " "
	print(res)