Problem: As you very well know, this year's funkiest numbers are so called triangular numbers (that is, integers that are representable as <image>, where k is some positive integer), and the coolest numbers are those that are representable as a sum of two triangular numbers.

A well-known hipster Andrew adores everything funky and cool but unfortunately, he isn't good at maths. Given number n, help him define whether this number can be represented by a sum of two triangular numbers (not necessarily different)!

Input

The first input line contains an integer n (1 ≤ n ≤ 109).

Output

Print "YES" (without the quotes), if n can be represented as a sum of two triangular numbers, otherwise print "NO" (without the quotes).

Examples

Input

256


Output

YES


Input

512


Output

NO

Note

In the first sample number <image>.

In the second sample number 512 can not be represented as a sum of two triangular numbers.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int main() {
  int n;
  cin >> n;
  int sum = 1;
  int i = 2;
  vector<int> v;
  while (true) {
    if (sum > n) break;
    v.push_back(sum);
    sum += i;
    i++;
  }
  bool haysol = false;
  for (int i = 0; i < v.size(); i++) {
    for (int j = i; j < v.size(); j++) {
      int num = v[i] + v[j];
      if (num == n) {
        haysol = true;
        break;
      }
    }
    if (haysol) break;
  }
  if (haysol) {
    cout << "YES" << endl;
  } else {
    cout << "NO" << endl;
  }
}