Problem: As you very well know, this year's funkiest numbers are so called triangular numbers (that is, integers that are representable as <image>, where k is some positive integer), and the coolest numbers are those that are representable as a sum of two triangular numbers.

A well-known hipster Andrew adores everything funky and cool but unfortunately, he isn't good at maths. Given number n, help him define whether this number can be represented by a sum of two triangular numbers (not necessarily different)!

Input

The first input line contains an integer n (1 ≤ n ≤ 109).

Output

Print "YES" (without the quotes), if n can be represented as a sum of two triangular numbers, otherwise print "NO" (without the quotes).

Examples

Input

256


Output

YES


Input

512


Output

NO

Note

In the first sample number <image>.

In the second sample number 512 can not be represented as a sum of two triangular numbers.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
long long n;
map<long long, int> v;
int main() {
  for (long long i = 1; i <= 100000; i++) {
    v[(i * (i + 1)) / (long long)2] = 1;
  }
  int n;
  scanf("%d", &n);
  bool si = 0;
  for (long long i = 1; i * (i + 1) / 2 < n && !si; i++) {
    if (v[n - i * (i + 1) / 2] == 1) {
      si = 1;
    }
  }
  if (si)
    printf("YES\n");
  else
    printf("NO\n");
  return 0;
}