Problem: Chubby Yang is studying linear equations right now. He came up with a nice problem. In the problem you are given an n × n matrix W, consisting of integers, and you should find two n × n matrices A and B, all the following conditions must hold: 

  * Aij = Aji, for all i, j (1 ≤ i, j ≤ n); 
  * Bij = - Bji, for all i, j (1 ≤ i, j ≤ n); 
  * Wij = Aij + Bij, for all i, j (1 ≤ i, j ≤ n). 



Can you solve the problem?

Input

The first line contains an integer n (1 ≤ n ≤ 170). Each of the following n lines contains n integers. The j-th integer in the i-th line is Wij (0 ≤ |Wij| < 1717).

Output

The first n lines must contain matrix A. The next n lines must contain matrix B. Print the matrices in the format equal to format of matrix W in input. It is guaranteed that the answer exists. If there are multiple answers, you are allowed to print any of them.

The answer will be considered correct if the absolute or relative error doesn't exceed 10 - 4.

Examples

Input

2
1 4
3 2


Output

1.00000000 3.50000000
3.50000000 2.00000000
0.00000000 0.50000000
-0.50000000 0.00000000


Input

3
1 2 3
4 5 6
7 8 9


Output

1.00000000 3.00000000 5.00000000
3.00000000 5.00000000 7.00000000
5.00000000 7.00000000 9.00000000
0.00000000 -1.00000000 -2.00000000
1.00000000 0.00000000 -1.00000000
2.00000000 1.00000000 0.00000000

Solution (in JAVA):

Solution:
import javax.print.attribute.HashDocAttributeSet;
import java.awt.*;
import java.io.*;
import java.util.*;

public class Main{
    public static double getDistance( Point a, Point b){
        return Math.sqrt( Math.pow( ( a.x - b.x ), 2 ) + Math.pow( ( a.y - b.y ), 2 ) );
    }
    public static void main(String[] args) {
        MyScanner scanner = new MyScanner();
        int n = scanner.nextInt();
        double[][] W = new double[ n ][ n ], A = new double[ n ][ n ], B = new double[ n ][ n ];
        for( int i = 0 ; i < n ; i++ ) for( int j = 0 ; j < n ; j++ ){
            W[ i ][ j ] = scanner.nextDouble();
            if( i == j )
            {
                A[i][j] = W[ i ][ j ];
            }
        }
        for( int i = 0 ; i < n ; i++ )
        {
            for( int j = i + 1; j < n ; j++ )
            {
                double t = W[ i ][ j ];
                double b = W[ j ][ i ];
                if( t < b )
                {
                    double diff = b - t;
                    diff = diff / 2;
                    A[ j ][ i ] = b - diff;
                    A[ i ][ j ] = b - diff;
                    B[ j ][ i ] = diff;
                    B[ i ][ j ] = -1 * diff;
                }
                else{
                    double diff = t - b;
                    diff = diff / 2;
                    A[ j ][ i ] = t - diff;
                    A[ i ][ j ] = t - diff;
                    B[ j ][ i ] = -1 * diff;
                    B[ i ][ j ] = diff;
                }
            }
        }
        for( int i = 0; i < n ; i++ )
        {
            for( int j = 0 ; j < n ; j ++ )
            {
                System.out.print(A[i][j]+" ");
            }
            System.out.println();
        }
        for( int i = 0; i < n ; i++ )
        {
            for( int j = 0 ; j < n ; j ++ )
            {
                System.out.print(B[i][j]+" ");
            }
            System.out.println();
        }


    }
}

class MyScanner {
    BufferedReader br;
    StringTokenizer st;

    public MyScanner() {
        br = new BufferedReader(new InputStreamReader(System.in));
    }

    public int mod(long x) {
        // TODO Auto-generated method stub
        return (int) x % 1000000007;
    }

    public int mod(int x) {
        return x % 1000000007;
    }

    boolean hasNext() {
        if (st.hasMoreElements())
            return true;
        try {
            st = new StringTokenizer(br.readLine());
        } catch (IOException e) {
            e.printStackTrace();
        }
        return st.hasMoreTokens();
    }

    String next() {
        while (st == null || !st.hasMoreElements()) {
            try {
                st = new StringTokenizer(br.readLine());
            } catch (Exception e) {
                e.printStackTrace();
            }
        }
        return st.nextToken();
    }

    int nextInt() {
        return Integer.parseInt(next());
    }

    double nextDouble() {
        return Double.parseDouble(next());
    }

    String nextLine() {
        String str = "";
        try {
            str = br.readLine();
        } catch (IOException e) {
            e.printStackTrace();
        }
        return str;
    }
    public int[] readIntArray( int n )
    {
        int ar[] = new int[ n ];
        for( int i = 0;  i < n ; i++ )
            ar[ i ] = this.nextInt();
        return ar;
    }
    public long nextLong() {
        return Long.parseLong(next());
    }
}