Problem: As you very well know, this year's funkiest numbers are so called triangular numbers (that is, integers that are representable as <image>, where k is some positive integer), and the coolest numbers are those that are representable as a sum of two triangular numbers.

A well-known hipster Andrew adores everything funky and cool but unfortunately, he isn't good at maths. Given number n, help him define whether this number can be represented by a sum of two triangular numbers (not necessarily different)!

Input

The first input line contains an integer n (1 ≤ n ≤ 109).

Output

Print "YES" (without the quotes), if n can be represented as a sum of two triangular numbers, otherwise print "NO" (without the quotes).

Examples

Input

256


Output

YES


Input

512


Output

NO

Note

In the first sample number <image>.

In the second sample number 512 can not be represented as a sum of two triangular numbers.

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.ArrayList;
import java.util.Collections;
import java.util.List;

public class OtroPorblema {

    public static void main(String[] args) throws IOException {

        BufferedReader input = new BufferedReader(new InputStreamReader(
                System.in));
        int number = Integer.parseInt(input.readLine());
        List<Integer> numeros = new ArrayList<>();
        int cuad = 0;
        for (int i = 1;; i++) {
            cuad = i * (i + 1) / 2;
            if (cuad > 1000000000)
                break;
            else
                numeros.add(cuad);
        }
        int tam = numeros.size();
        boolean encon = false;
        for (int i = 1; i <= tam; i++) {
            int cu = i * (i + 1) / 2;
            int index = Collections.binarySearch(numeros, number - cu);
            if (index >= 0) {
                System.out.println("YES");
                encon = true;
                break;
            }
        }
        if (!encon)
            System.out.println("NO");

    }
}