Problem: Recently you have bought a snow walking robot and brought it home. Suppose your home is a cell (0, 0) on an infinite grid.

You also have the sequence of instructions of this robot. It is written as the string s consisting of characters 'L', 'R', 'U' and 'D'. If the robot is in the cell (x, y) right now, he can move to one of the adjacent cells (depending on the current instruction).

  * If the current instruction is 'L', then the robot can move to the left to (x - 1, y); 
  * if the current instruction is 'R', then the robot can move to the right to (x + 1, y); 
  * if the current instruction is 'U', then the robot can move to the top to (x, y + 1); 
  * if the current instruction is 'D', then the robot can move to the bottom to (x, y - 1). 



You've noticed the warning on the last page of the manual: if the robot visits some cell (except (0, 0)) twice then it breaks.

So the sequence of instructions is valid if the robot starts in the cell (0, 0), performs the given instructions, visits no cell other than (0, 0) two or more times and ends the path in the cell (0, 0). Also cell (0, 0) should be visited at most two times: at the beginning and at the end (if the path is empty then it is visited only once). For example, the following sequences of instructions are considered valid: "UD", "RL", "UUURULLDDDDLDDRRUU", and the following are considered invalid: "U" (the endpoint is not (0, 0)) and "UUDD" (the cell (0, 1) is visited twice).

The initial sequence of instructions, however, might be not valid. You don't want your robot to break so you decided to reprogram it in the following way: you will remove some (possibly, all or none) instructions from the initial sequence of instructions, then rearrange the remaining instructions as you wish and turn on your robot to move. 

Your task is to remove as few instructions from the initial sequence as possible and rearrange the remaining ones so that the sequence is valid. Report the valid sequence of the maximum length you can obtain.

Note that you can choose any order of remaining instructions (you don't need to minimize the number of swaps or any other similar metric).

You have to answer q independent test cases.

Input

The first line of the input contains one integer q (1 ≤ q ≤ 2 ⋅ 10^4) — the number of test cases.

The next q lines contain test cases. The i-th test case is given as the string s consisting of at least 1 and no more than 10^5 characters 'L', 'R', 'U' and 'D' — the initial sequence of instructions.

It is guaranteed that the sum of |s| (where |s| is the length of s) does not exceed 10^5 over all test cases (∑ |s| ≤ 10^5).

Output

For each test case print the answer on it. In the first line print the maximum number of remaining instructions. In the second line print the valid sequence of remaining instructions t the robot has to perform. The moves are performed from left to right in the order of the printed sequence. If there are several answers, you can print any. If the answer is 0, you are allowed to print an empty line (but you can don't print it).

Example

Input


6
LRU
DURLDRUDRULRDURDDL
LRUDDLRUDRUL
LLLLRRRR
URDUR
LLL


Output


2
LR
14
RUURDDDDLLLUUR
12
ULDDDRRRUULL
2
LR
2
UD
0

Note

There are only two possible answers in the first test case: "LR" and "RL".

The picture corresponding to the second test case:

<image> Note that the direction of traverse does not matter 

Another correct answer to the third test case: "URDDLLLUURDR".

Solution (in JAVA):

Solution:
/*
                       _oo0oo_
                      o8888888o
                      88" . "88
                      (| -_- |)
                      0\  =  /0
                    ___/`---'\___
                  .' \\|     |// '.
                 / \\|||  :  |||// \
                / _||||| -:- |||||- \
               |   | \\\  -  /// |   |
               | \_|  ''\---/''  |_/ |
               \  .-\__  '-'  ___/-. /
             ___'. .'  /--.--\  `. .'___
          ."" '<  `.___\_<|>_/___.' >' "".
         | | :  `- \`.;`\ _ /`;.`/ - ` : | |
         \  \ `_.   \_ __\ /__ _/   .-` /  /
     =====`-.____`.___ \_____/___.-`___.-'=====
                       `=---='
 
*/
import java.util.function.Consumer;
import java.util.*;
import java.math.BigDecimal;
import java.math.BigInteger;
import java.math.RoundingMode;
import java.text.DecimalFormat;
import java.io.*;
import java.lang.Math.*;
 public class KickStart2020{
	static class FastReader {
        BufferedReader br;
        StringTokenizer st;
        public FastReader(){br = new BufferedReader(
           new InputStreamReader(System.in));}
        String next(){
            while (st == null || !st.hasMoreElements()) {
                try { st = new StringTokenizer(br.readLine()); }
                catch (IOException e) {e.printStackTrace();}}
            return st.nextToken();}
        int nextInt() { return Integer.parseInt(next()); }
        long nextLong() { return Long.parseLong(next()); }
        double nextDouble() { return Double.parseDouble(next());}
        float nextFloat() {return Float.parseFloat(next());}
        String nextLine() {
            String str = "";
            try {str = br.readLine();}
            catch (IOException e) { e.printStackTrace();}
            return str; }}
	static boolean isBracketSequence(String s, int a, int b) {
		Stack<Character> ss = new Stack<>();
		boolean hachu = true;
		for(int i = a; i <= b; i++) {
			if(s.charAt(i) == ')' && ss.isEmpty()) {hachu = false; break;}
			if(s.charAt(i) == '(') ss.add('(');
			else ss.pop();
		}
		return ss.empty() && hachu;
	}
	static String reverseOfString(String a) {
		StringBuilder ssd = new StringBuilder();
		for(int i = a.length() - 1; i >= 0; i--) {
			ssd.append(a.charAt(i));
		}
		return ssd.toString();
	}
	static char[] reverseOfChar(char a[]) {
		char b[] = new char[a.length];
		int j = 0;
		for(int i = a.length - 1; i >= 0; i--) {
			b[i] = a[j];
			j++;
		}
		return b;
	}
	static boolean isPalindrome(char a[]) {
		boolean hachu = true;
		for(int i = 0; i <= a.length / 2; i++) {
			if(a[i] != a[a.length - 1 - i]) {
				hachu = false;
				break;
			}
		}
		return hachu;
	} 
	static long gcd(long a, long b)
	{
	    if (b == 0)
	        return a;
	    return gcd(b, a % b);
	     
	}
	static long power(long x, long y, long mod){
	    long ans = 1;
	    x = x % mod; 
	    if (x == 0)
	      return 0; 
	    int i = 1;
	    while (y > 0){
	      if ((y & 1) != 0)
	        ans = (ans * x) % mod;
	      y = y >> 1; 
	      x = (x * x) % mod;
	    }
	    return ans;
	  }
	static boolean check(String a) {
		boolean hachu = true;
		for(int i = 0; i < a.length(); i++) {
			if(a.charAt(0) != a.charAt(i)) {hachu = false; break;}
		}
		return hachu;
	}
	 public static class Pair implements Comparable<Pair> {
	        public final int index;
	        public final int value;
	 
	        public Pair(int index, int value) {
	            this.index = index;
	            this.value = value;
	        }
	        @Override
	        public int compareTo(Pair other) {
	            //multiplied to -1 as the author need descending sort order
	            return  -1 * Integer.valueOf(this.value).compareTo(other.value);
	        }
	 }
	 static boolean equalString(int i, int j, int arr[], String b) {
		 int brr[] = new int[26];
		 for(int k = i; k <= j; k++) brr[b.charAt(k) - 'a']++;
		 for(int k = 0; k < 26; k++) {
			 if(arr[k] != brr[k]) return false;
		 }
		 return true;
	 }
	 static boolean cequalArray(String a, String b) {
		  int count[] = new int[26];
		  int count1[] = new int[26];
		  for(int i = 0; i < a.length(); i++) count[a.charAt(i) - 'a']++;
		  for(int i = 0; i < a.length(); i++) count1[b.charAt(i) - 'a']++;
		  for(int i = 0; i < 26; i++) if(count[i] != count1[i]) return false;
		  return true;
	 }
	 
		public static void main(String[] args) throws Exception{
			FastReader sc = new FastReader();
			PrintWriter out = new PrintWriter(System.out);
            int t = sc.nextInt();
            outerloop:
            while(t-- > 0) {
            	String a = sc.next();
            	int l = 0, r = 0, u = 0, d = 0;
            	for(int i = 0; i < a.length(); i++) {
            		if(a.charAt(i) == 'L') l++;
            		else if(a.charAt(i) == 'R') r++;
            		else if(a.charAt(i) == 'U') u++;
            		else d++;
            	}
            	if((u == 0 || d == 0) && (r != 0 && l != 0)) {
            		out.println(2);
            		out.println("LR");
            		continue outerloop;
            	}
            	else if((u != 0 && d != 0) && (l == 0 || r == 0)) {
            		out.println(2);
            		out.println("UD");
            		continue outerloop;
            	}
            	else if((u == 0 || d == 0) && (l == 0 || r == 0)) {
            		out.println(0);
            		out.println();
            	}
            	else {
            		int z = Math.min(r, l);
            		int y = Math.min(u, d);
            		out.println(z + y + z + y);
            		for(int i = 0; i < z; i++) out.print('R');
            		for(int i = 0; i < y; i++) out.print('U');
            		for(int i = 0; i < z; i++) out.print('L');
            		for(int i = 0; i < y; i++) out.print('D');
            		out.println();
            	}
            }
            
         out.close();
			}
		}