Problem: As you very well know, this year's funkiest numbers are so called triangular numbers (that is, integers that are representable as <image>, where k is some positive integer), and the coolest numbers are those that are representable as a sum of two triangular numbers.

A well-known hipster Andrew adores everything funky and cool but unfortunately, he isn't good at maths. Given number n, help him define whether this number can be represented by a sum of two triangular numbers (not necessarily different)!

Input

The first input line contains an integer n (1 ≤ n ≤ 109).

Output

Print "YES" (without the quotes), if n can be represented as a sum of two triangular numbers, otherwise print "NO" (without the quotes).

Examples

Input

256


Output

YES


Input

512


Output

NO

Note

In the first sample number <image>.

In the second sample number 512 can not be represented as a sum of two triangular numbers.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
long long a[50005];
long long n;
int main() {
  scanf("%lld", &n);
  for (register long long i = 1; i <= 50003; ++i) a[i] = (i * (i + 1)) / 2;
  for (register long long i = 1; a[i] < n; ++i) {
    long long num = n - a[i];
    int h = lower_bound(a + 1, a + 50001, num) - a;
    if (a[h] == num) {
      printf("Yes");
      return 0;
    }
  }
  printf("No");
}