Problem: Takahashi loves sorting.

He has a permutation (p_1,p_2,...,p_N) of the integers from 1 through N. Now, he will repeat the following operation until the permutation becomes (1,2,...,N):

* First, we will define high and low elements in the permutation, as follows. The i-th element in the permutation is high if the maximum element between the 1-st and i-th elements, inclusive, is the i-th element itself, and otherwise the i-th element is low.
* Then, let a_1,a_2,...,a_k be the values of the high elements, and b_1,b_2,...,b_{N-k} be the values of the low elements in the current permutation, in the order they appear in it.
* Lastly, rearrange the permutation into (b_1,b_2,...,b_{N-k},a_1,a_2,...,a_k).



How many operations are necessary until the permutation is sorted?

Constraints

* 1 ≤ N ≤ 2×10^5
* (p_1,p_2,...,p_N) is a permutation of the integers from 1 through N.

Input

Input is given from Standard Input in the following format:


N
p_1 p_2 ... p_N


Output

Print the number of operations that are necessary until the permutation is sorted.

Examples

Input

5
3 5 1 2 4


Output

3


Input

5
5 4 3 2 1


Output

4


Input

10
2 10 5 7 3 6 4 9 8 1


Output

6

Solution (in CPP):

Solution:
#include <cstdio>
int idx[200005];
int main()
{
	// freopen("AGC014-F.in", "r", stdin);
	int n, ans = 0, lst;
	scanf("%d", &n);
	for (int i = 0; i < n; i++)
	{
		int x;
		scanf("%d", &x);
		idx[x - 1] = i;
	}
	for (int i = n - 2; i >= 0; i--)
	{
		if (!ans)
		{
			if (idx[i] > idx[i + 1])
			{
				ans++;
				lst = i + 1;
			}
			continue;
		}
		if ((idx[lst] < idx[i + 1]) + (idx[i + 1] < idx[i]) + (idx[i] < idx[lst]) == 2)
		{
			ans++;
			lst = i + 1;
		}
	}
	printf("%d\n", ans);
	return 0;
}