Problem: As you very well know, this year's funkiest numbers are so called triangular numbers (that is, integers that are representable as <image>, where k is some positive integer), and the coolest numbers are those that are representable as a sum of two triangular numbers.

A well-known hipster Andrew adores everything funky and cool but unfortunately, he isn't good at maths. Given number n, help him define whether this number can be represented by a sum of two triangular numbers (not necessarily different)!

Input

The first input line contains an integer n (1 ≤ n ≤ 109).

Output

Print "YES" (without the quotes), if n can be represented as a sum of two triangular numbers, otherwise print "NO" (without the quotes).

Examples

Input

256


Output

YES


Input

512


Output

NO

Note

In the first sample number <image>.

In the second sample number 512 can not be represented as a sum of two triangular numbers.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
template <class c>
struct rge {
  c b, e;
};
template <class c>
rge<c> range(c i, c j) {
  return rge<c>{i, j};
}
template <class c>
auto dud(c* x) -> decltype(cerr << *x, 0);
template <class c>
char dud(...);
struct debug {
  template <class c>
  debug& operator<<(const c&) {
    return *this;
  }
};
int mxn = 1e5;
void solve() {
  long long n;
  cin >> n;
  vector<long long> sums(mxn);
  for (int i = 0; i < mxn; i++) {
    sums[i] = (long long)i * (i + 1) / 2;
  }
  for (int i = 1; i < mxn; i++) {
    if (n - sums[i] < 0) break;
    long long rem = n - sums[i];
    int l = 1, r = mxn - 1;
    while (l < r) {
      int m = (l + r) / 2;
      if (sums[m] == rem) {
        l = r = m;
      } else if (sums[m] < rem) {
        l = m + 1;
      } else {
        r = m - 1;
      }
    }
    if (sums[l] == rem) {
      cout << "YES\n";
      return;
    }
  }
  cout << "NO\n";
}
int main() {
  ios_base::sync_with_stdio(false);
  cin.tie(NULL);
  cout.tie(NULL);
  int t = 1;
  for (int z = 1; z <= t; z++) {
    solve();
  }
  return 0;
}