Problem: As you very well know, this year's funkiest numbers are so called triangular numbers (that is, integers that are representable as <image>, where k is some positive integer), and the coolest numbers are those that are representable as a sum of two triangular numbers.

A well-known hipster Andrew adores everything funky and cool but unfortunately, he isn't good at maths. Given number n, help him define whether this number can be represented by a sum of two triangular numbers (not necessarily different)!

Input

The first input line contains an integer n (1 ≤ n ≤ 109).

Output

Print "YES" (without the quotes), if n can be represented as a sum of two triangular numbers, otherwise print "NO" (without the quotes).

Examples

Input

256


Output

YES


Input

512


Output

NO

Note

In the first sample number <image>.

In the second sample number 512 can not be represented as a sum of two triangular numbers.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
long long n;
map<int, bool> f;
long long get(int x) { return (x * (x + 1)) / 2; }
int main() {
  cin >> n;
  for (int i = 1; i <= n; i++) {
    if (get(i) >= n) {
      break;
    } else {
      f[get(i)] = 1;
    }
  }
  for (int i = 1; i <= n; i++) {
    if (get(i) >= n) {
      break;
    } else {
      if (f[n - get(i)]) {
        cout << "YES";
        return 0;
      }
    }
  }
  cout << "NO";
  return 0;
}