Problem: As you very well know, this year's funkiest numbers are so called triangular numbers (that is, integers that are representable as <image>, where k is some positive integer), and the coolest numbers are those that are representable as a sum of two triangular numbers.

A well-known hipster Andrew adores everything funky and cool but unfortunately, he isn't good at maths. Given number n, help him define whether this number can be represented by a sum of two triangular numbers (not necessarily different)!

Input

The first input line contains an integer n (1 ≤ n ≤ 109).

Output

Print "YES" (without the quotes), if n can be represented as a sum of two triangular numbers, otherwise print "NO" (without the quotes).

Examples

Input

256


Output

YES


Input

512


Output

NO

Note

In the first sample number <image>.

In the second sample number 512 can not be represented as a sum of two triangular numbers.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int main() {
  int n;
  set<int> st;
  set<int>::iterator it;
  for (int i = 1; i <= 45000; ++i) {
    int ans = i * (i + 1) / 2;
    st.insert(ans);
  }
  while (~scanf("%d", &n)) {
    int flag = 0;
    for (it = st.begin(); it != st.end(); ++it) {
      if (st.find(n - *it) != st.end()) {
        flag = 1;
        break;
      }
    }
    if (flag)
      puts("YES");
    else
      puts("NO");
  }
  return 0;
}