Problem: As you very well know, this year's funkiest numbers are so called triangular numbers (that is, integers that are representable as <image>, where k is some positive integer), and the coolest numbers are those that are representable as a sum of two triangular numbers.

A well-known hipster Andrew adores everything funky and cool but unfortunately, he isn't good at maths. Given number n, help him define whether this number can be represented by a sum of two triangular numbers (not necessarily different)!

Input

The first input line contains an integer n (1 ≤ n ≤ 109).

Output

Print "YES" (without the quotes), if n can be represented as a sum of two triangular numbers, otherwise print "NO" (without the quotes).

Examples

Input

256


Output

YES


Input

512


Output

NO

Note

In the first sample number <image>.

In the second sample number 512 can not be represented as a sum of two triangular numbers.

Solution (in JAVA):

Solution:
import java.util.*;
import java.lang.*;
import java.io.*;

public class Main {
    
    static boolean bs(long[] a, long k) {
        int s = 1, e = a.length - 1, m;
        while (s <= e) {
            m = (s + e) / 2;
            if (a[m] == k) {
                return true;
            } else if (a[m] < k) {
                s = m + 1;
            } else {
                e = m - 1;
            }
        }
        return false;
    }

    public static void main(String[] args) throws Exception {
        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
        String line;
        String[] ar;
        StringBuilder sb = new StringBuilder();
        //-----------------------------------------------------------------------
        long n = Long.parseLong(br.readLine());
        long[] a = new long[50000];
        for (int i = 1; i < 50000; i++) {
            a[i] = i * (i + 1) / 2;
        }
        for (int i = 1; i < 50000; i++) {
            if (bs(a, n - a[i])) {
                System.out.println("YES");
                return;
            }
        }
        System.out.println("NO");
        //-----------------------------------------------------------------------
    }
}