Problem: Igor the analyst has adopted n little bunnies. As we all know, bunnies love carrots. Thus, Igor has bought a carrot to be shared between his bunnies. Igor wants to treat all the bunnies equally, and thus he wants to cut the carrot into n pieces of equal area. 

Formally, the carrot can be viewed as an isosceles triangle with base length equal to 1 and height equal to h. Igor wants to make n - 1 cuts parallel to the base to cut the carrot into n pieces. He wants to make sure that all n pieces have the same area. Can you help Igor determine where to cut the carrot so that each piece have equal area?

<image> Illustration to the first example.

Input

The first and only line of input contains two space-separated integers, n and h (2 ≤ n ≤ 1000, 1 ≤ h ≤ 105).

Output

The output should contain n - 1 real numbers x1, x2, ..., xn - 1. The number xi denotes that the i-th cut must be made xi units away from the apex of the carrot. In addition, 0 < x1 < x2 < ... < xn - 1 < h must hold. 

Your output will be considered correct if absolute or relative error of every number in your output doesn't exceed 10 - 6.

Formally, let your answer be a, and the jury's answer be b. Your answer is considered correct if <image>.

Examples

Input

3 2


Output

1.154700538379 1.632993161855


Input

2 100000


Output

70710.678118654752

Note

Definition of isosceles triangle: <https://en.wikipedia.org/wiki/Isosceles_triangle>.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
double a[10000000];
int main() {
  double h;
  long long n;
  while (cin >> n >> h) {
    long long temp = 0;
    double Sa = h / 2;
    double s = Sa / n, S;
    long long c = 0;
    double v = Sa;
    n = n - 1;
    while (n--) {
      Sa = Sa - s;
      S = Sa;
      a[c++] = sqrt(S * h * h / v);
    }
    reverse(a, a + c);
    for (long long i = 0; i < c; i++) {
      if (temp == 0)
        printf("%.10lf", a[0]);
      else
        printf(" %.10lf", a[i]);
      temp = 1;
    }
    cout << endl;
  }
}