Problem: As you very well know, this year's funkiest numbers are so called triangular numbers (that is, integers that are representable as <image>, where k is some positive integer), and the coolest numbers are those that are representable as a sum of two triangular numbers.

A well-known hipster Andrew adores everything funky and cool but unfortunately, he isn't good at maths. Given number n, help him define whether this number can be represented by a sum of two triangular numbers (not necessarily different)!

Input

The first input line contains an integer n (1 ≤ n ≤ 109).

Output

Print "YES" (without the quotes), if n can be represented as a sum of two triangular numbers, otherwise print "NO" (without the quotes).

Examples

Input

256


Output

YES


Input

512


Output

NO

Note

In the first sample number <image>.

In the second sample number 512 can not be represented as a sum of two triangular numbers.

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.Arrays;


public class A_Div2_121 {
    public static void main(String[]arg) throws IOException
    {
        new A_Div2_121().solve();
    }
    public void solve()throws IOException
    {
        BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
        long n,a,b;
        int c;
        //tn = triangular numbers
        long[]tn = new long[44720];
        c = 0;
        for(a = 1, b = 2; a < 1000000001; a += b, b++)
            tn[c++] = a;
        boolean end = false;
        c = 0;
        n = Integer.parseInt(in.readLine());    
        while(!end && c != -1 && c < 44720)
        {
            a = tn[c++];
            if(n - a < 0)
                c = -1;
            else
            {
                b = n - a;
                if(Arrays.binarySearch(tn, b) > -1)
                    end = true;
            }
        }       
        //System.out.println(a + "##" + b);
        if(end)
            System.out.println("YES");
        else
            System.out.println("NO");
    }
}