Problem: You are given an unweighted tree with n vertices. Recall that a tree is a connected undirected graph without cycles.

Your task is to choose three distinct vertices a, b, c on this tree such that the number of edges which belong to at least one of the simple paths between a and b, b and c, or a and c is the maximum possible. See the notes section for a better understanding.

The simple path is the path that visits each vertex at most once.

Input

The first line contains one integer number n (3 ≤ n ≤ 2 ⋅ 10^5) — the number of vertices in the tree. 

Next n - 1 lines describe the edges of the tree in form a_i, b_i (1 ≤ a_i, b_i ≤ n, a_i ≠ b_i). It is guaranteed that given graph is a tree.

Output

In the first line print one integer res — the maximum number of edges which belong to at least one of the simple paths between a and b, b and c, or a and c.

In the second line print three integers a, b, c such that 1 ≤ a, b, c ≤ n and a ≠, b ≠ c, a ≠ c.

If there are several answers, you can print any.

Example

Input


8
1 2
2 3
3 4
4 5
4 6
3 7
3 8


Output


5
1 8 6

Note

The picture corresponding to the first example (and another one correct answer):

<image>

If you choose vertices 1, 5, 6 then the path between 1 and 5 consists of edges (1, 2), (2, 3), (3, 4), (4, 5), the path between 1 and 6 consists of edges (1, 2), (2, 3), (3, 4), (4, 6) and the path between 5 and 6 consists of edges (4, 5), (4, 6). The union of these paths is (1, 2), (2, 3), (3, 4), (4, 5), (4, 6) so the answer is 5. It can be shown that there is no better answer.

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.StringTokenizer;

public class Fdiv3 {
	static ArrayList<Integer>[] adj;
	static boolean[] visited;
	static ArrayList<Integer> path;

	public static void main(String[] args) throws NumberFormatException, IOException {
		// TODO Auto-generated method stub
		BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
		PrintWriter pw = new PrintWriter(System.out);
		int n = Integer.parseInt(br.readLine());

		adj = new ArrayList[n];
		visited = new boolean[n];
		path = new ArrayList<>();
		for (int i = 0; i < adj.length; i++) {
			adj[i] = new ArrayList<>();
		}
		for (int i = 0; i < n - 1; i++) {
			StringTokenizer st = new StringTokenizer(br.readLine());
			int u = Integer.parseInt(st.nextToken()) - 1;
			int v = Integer.parseInt(st.nextToken()) - 1;
			adj[u].add(v);
			adj[v].add(u);
		}

		diameter(n);
		pw.println(fc);
		pw.println((x + 1) + " " + (y + 1) + " " + (z + 1));
//		pw.println(path);
		pw.flush();
	}

	static int x;
	static int y;
	static int z = -1;
	static int fc;
	static int maxCount;

	// Sets maxCount as maximum distance
	// from node
	static void dfsUtil(int node, int count) {
		visited[node] = true;
		for (Integer i : adj[node]) {
			if (!visited[i]) {
				if (count + 1 >= maxCount) {
					maxCount = count + 1;
					x = i;
				}
				dfsUtil(i, count + 1);
			}
		}
	}

	static void dfs(int node, int count) {
		visited[node] = true;
		for (Integer i : adj[node]) {
			if (!visited[i]) {
				if (count + 1 >= maxCount) {
					maxCount = count + 1;
					y = i;
				}
				dfs(i, count + 1);
			}
		}
	}

	static boolean dfs1(int a, int b, int p) {
		visited[p] = true;
		if (p == b)
			return true;
		for (int v : adj[p]) {
			if (!visited[v]) {
				if (v == b)
					return true;
				if (dfs1(a, b, v)) {
					path.add(v);
					return true;
				}
			}
		}
		return false;
	}

	static void dfs3(int node, int count) {
		visited[node] = true;
		for (Integer i : adj[node]) {
			if (!visited[i]) {
				if (count + 1 >= maxCount) {
					maxCount = count + 1;
					z = i;
				}
				dfs3(i, count + 1);
			}
		}
	}

	static void diameter(int n) {
		maxCount = Integer.MIN_VALUE;
		dfsUtil(1, 1);
		Arrays.fill(visited, false);
		dfs(x, 1);
		fc += maxCount - 1;
		Arrays.fill(visited, false);
		dfs1(x, y, x);
		Arrays.fill(visited, false);
		visited[x] = true;
		visited[y] = true;
		maxCount = Integer.MIN_VALUE;
		for (int i : path)
			visited[i] = true;
		for (int i : path)
			dfs3(i, 1);
		if (z == -1)
			z = path.get(0);
		else
			fc += maxCount - 1;
	}

}