Problem: Consider All lowercase Alphabets of the English language. Here we consider each alphabet from a to z to have a certain weight. The weight of the alphabet a is considered to be 1, b to be 2, c to be 3 and so on until z has a weight of 26. In short, the weight of the alphabet a is 1, and the weight of all other alphabets is the weight of its previous alphabet + 1. 

Now, you have been given a String S consisting of lowercase English characters. You need to find the summation of weight of each character in this String.  

For example, Consider the String aba
Here, the first character a has a weight of 1, the second character b has 2 and the third character a again has a weight of 1. So the summation here is equal to :
 1  + 2 + 1 =  4    

Input Format:
The first and only line of input contains the String S. 

Output Format 
Print the required answer on a single line

Constraints
 1 ≤ |S| ≤ 1000    

SAMPLE INPUT
aba

SAMPLE OUTPUT
4

Explanation

Explanation for the Sample has been given in the Problem Statement.

Solution (in PYTHON):

Solution:
s=raw_input()
wt=0
wt=wt+s.count('a')*1
wt=wt+s.count('b')*2
wt=wt+s.count('c')*3
wt=wt+s.count('d')*4
wt=wt+s.count('e')*5
wt=wt+s.count('f')*6
wt=wt+s.count('g')*7
wt=wt+s.count('h')*8
wt=wt+s.count('i')*9
wt=wt+s.count('j')*10
wt=wt+s.count('k')*11
wt=wt+s.count('l')*12
wt=wt+s.count('m')*13
wt=wt+s.count('n')*14
wt=wt+s.count('o')*15
wt=wt+s.count('p')*16
wt=wt+s.count('q')*17
wt=wt+s.count('r')*18
wt=wt+s.count('s')*19
wt=wt+s.count('t')*20
wt=wt+s.count('u')*21
wt=wt+s.count('v')*22
wt=wt+s.count('w')*23
wt=wt+s.count('x')*24
wt=wt+s.count('y')*25
wt=wt+s.count('z')*26
print wt