Problem: Recently you have bought a snow walking robot and brought it home. Suppose your home is a cell (0, 0) on an infinite grid.

You also have the sequence of instructions of this robot. It is written as the string s consisting of characters 'L', 'R', 'U' and 'D'. If the robot is in the cell (x, y) right now, he can move to one of the adjacent cells (depending on the current instruction).

  * If the current instruction is 'L', then the robot can move to the left to (x - 1, y); 
  * if the current instruction is 'R', then the robot can move to the right to (x + 1, y); 
  * if the current instruction is 'U', then the robot can move to the top to (x, y + 1); 
  * if the current instruction is 'D', then the robot can move to the bottom to (x, y - 1). 



You've noticed the warning on the last page of the manual: if the robot visits some cell (except (0, 0)) twice then it breaks.

So the sequence of instructions is valid if the robot starts in the cell (0, 0), performs the given instructions, visits no cell other than (0, 0) two or more times and ends the path in the cell (0, 0). Also cell (0, 0) should be visited at most two times: at the beginning and at the end (if the path is empty then it is visited only once). For example, the following sequences of instructions are considered valid: "UD", "RL", "UUURULLDDDDLDDRRUU", and the following are considered invalid: "U" (the endpoint is not (0, 0)) and "UUDD" (the cell (0, 1) is visited twice).

The initial sequence of instructions, however, might be not valid. You don't want your robot to break so you decided to reprogram it in the following way: you will remove some (possibly, all or none) instructions from the initial sequence of instructions, then rearrange the remaining instructions as you wish and turn on your robot to move. 

Your task is to remove as few instructions from the initial sequence as possible and rearrange the remaining ones so that the sequence is valid. Report the valid sequence of the maximum length you can obtain.

Note that you can choose any order of remaining instructions (you don't need to minimize the number of swaps or any other similar metric).

You have to answer q independent test cases.

Input

The first line of the input contains one integer q (1 ≤ q ≤ 2 ⋅ 10^4) — the number of test cases.

The next q lines contain test cases. The i-th test case is given as the string s consisting of at least 1 and no more than 10^5 characters 'L', 'R', 'U' and 'D' — the initial sequence of instructions.

It is guaranteed that the sum of |s| (where |s| is the length of s) does not exceed 10^5 over all test cases (∑ |s| ≤ 10^5).

Output

For each test case print the answer on it. In the first line print the maximum number of remaining instructions. In the second line print the valid sequence of remaining instructions t the robot has to perform. The moves are performed from left to right in the order of the printed sequence. If there are several answers, you can print any. If the answer is 0, you are allowed to print an empty line (but you can don't print it).

Example

Input


6
LRU
DURLDRUDRULRDURDDL
LRUDDLRUDRUL
LLLLRRRR
URDUR
LLL


Output


2
LR
14
RUURDDDDLLLUUR
12
ULDDDRRRUULL
2
LR
2
UD
0

Note

There are only two possible answers in the first test case: "LR" and "RL".

The picture corresponding to the second test case:

<image> Note that the direction of traverse does not matter 

Another correct answer to the third test case: "URDDLLLUURDR".

Solution (in JAVA):

Solution:
import java.io.BufferedReader; 
import java.io.IOException; 
import java.io.InputStreamReader;
import java.util.StringTokenizer; 
import java.util.*;

public class Main{
	//Se utilizo FastReader al ser mas rapido que Scanner
	static class FastReader{ 
		BufferedReader br; 
		StringTokenizer st; 

		public FastReader(){ 
			br = new BufferedReader(new
					InputStreamReader(System.in)); 
		} 

		String next(){ 
			while (st == null || !st.hasMoreElements()){ 
				try{ 
					st = new StringTokenizer(br.readLine()); 
				} 
				catch (IOException e){ 
					e.printStackTrace(); 
				} 
			} 
			return st.nextToken(); 
		} 

		int nextInt(){ 
			return Integer.parseInt(next()); 
		} 

		long nextLong(){ 
			return Long.parseLong(next()); 
		} 

		double nextDouble(){ 
			return Double.parseDouble(next()); 
		} 

		String nextLine(){ 
			String str = ""; 
			try{ 
				str = br.readLine(); 
			} 
			catch (IOException e){ 
				e.printStackTrace(); 
			} 
			return str; 
		} 
	}

	public static void main(String[] args){
		FastReader s = new FastReader();
		int q = s.nextInt();
		for(int i = 0; i < q; i++){
			String m = s.next();
			Robot tinman = Handler.handle(m);
			String newPath = tinman.move(m);
			System.out.println(tinman.newlen(newPath)); //Si el robot camina, newlen sera igual al largo de newPath. Si el robot salta, newlen sera igual a la mitad del largo de newPath.
			System.out.println(newPath);
		}
	}
}

interface Robot{
	public String move(String path);
	public int newlen(String path);
}

class WalkBot implements Robot{
	@Override
	public String move(String path){
		String[] direction = path.split("(?<=\\G.)"); //Se utiliza esta regex para separar strings de a 1 caracter a la vez.
		int u = 0, d = 0, l = 0, r = 0;
		//Se cuenta la cantidad de letras de cierto tipo.
		for(String c : direction){
			if(c.equals("U")){
				u++;
			}
			else if(c.equals("D")){
				d++;
			}
			else if(c.equals("L")){
				l++;
			}
			else{
				r++;
			}
		}
		//Si el robot no puede caminar hacia la derecha o izquierda, no podra dar mas de un paso arriba y abajo, y vice versa.
		if(l == 0 || r == 0){
			u = Math.min(u, 1);
		}
		else if(u == 0 || d == 0){
			l = Math.min(l, 1);
		}
		u = d = Math.min(u, d);
		l = r = Math.min(l, r);
		StringBuilder np = new StringBuilder("");
		Handler.app(np, "U", "", u, 0);
		Handler.app(np, "L", "", l, 0);
		Handler.app(np, "D", "", d, 0);
		Handler.app(np, "R", "", r, 0);
		return np.toString();
	}

	@Override
	public int newlen(String path){
		return path.length();
	}
}

class JumpBot implements Robot{
	@Override
	public String move(String path){
		String[] direction = path.split("(?<=\\G..)"); //Se utiliza esta regex para separar strings de a 2 caracteres a la vez.
		int[] u = {0, 0, 0}, d = {0, 0, 0}, l = {0, 0, 0}, r = {0, 0, 0}; //Se utilizo un array para no tener que declarar demasiadas variables, ademas de poder utilizar la funcion cal mas abajo. t = {total, T1, T2}
		for(String c : direction){
			if(c.equals("U1")){
				u[1]++;
				u[0]++;
			}
			else if(c.equals("U2")){
				u[2]++;
				u[0] += 2;
			}
			else if(c.equals("D1")){
				d[1]++;
				d[0]++;
			}
			else if(c.equals("D2")){
				d[2]++;
				d[0] += 2;
			}
			else if(c.equals("L1")){
				l[1]++;
				l[0]++;
			}
			else if(c.equals("L2")){
				l[2]++;
				l[0] += 2;
			}
			else if(c.equals("R1")){
				r[1]++;
				r[0]++;
			}
			else{
				r[2]++;
				r[0] += 2;
			}
		}
		if(l[0] == 0 || r[0] == 0){
			u[0] = Math.min(u[0], 1);
		}
		else if(u[0] == 0 || d[0] == 0){
			l[0] = Math.min(l[0], 1);
		}
		u[0] = d[0] = Math.min(u[0], d[0]);
		if(u[1] > d[1]){
			Handler.cal(d, u);
			Handler.cal(u, d);
		}
		else{
			Handler.cal(u, d);
			Handler.cal(d, u);
		}
		l[0] = r[0] = Math.min(l[0], r[0]);
		if(r[1] > l[1]){
			Handler.cal(l, r);
			Handler.cal(r, l);
		}
		else{
			Handler.cal(r, l);
			Handler.cal(l, r);
		}
		StringBuilder np = new StringBuilder("");
		Handler.app(np, "U1", "U2", u[1], u[2]);
		Handler.app(np, "L1", "L2", l[1], l[2]);
		Handler.app(np, "D1", "D2", d[1], d[2]);
		Handler.app(np, "R1", "R2", r[1], r[2]);
		return np.toString();
	}

	@Override
	public int newlen(String path){
		return (path.length() / 2);
	}
}

class Handler{
	//Esto crea al robot
	public static Robot handle(String path){
		if(path.contains("1") || path.contains("2")){
			Robot tinman = new JumpBot();
			return tinman;
		}
		else{
			Robot tinman = new WalkBot();
			return tinman;
		}
	}

	//Esta funcion sirve para calcular el t[1] y t[2] necesarios para hacer los pasos requeridos.
	public static void cal(int[] t, int[] s){
		t[0] -= t[1];
		while(t[0] < 0 && t[1] > 0){
			t[2] = 0;
			t[1]--;
			t[0]++;
		}
		if(t[0] > 0){
			t[0] -= 2 * t[2];
			while(t[0] < 0 && t[2] > 0){
				t[2]--;
				t[0] += 2;
			}
		}
		else if(t[0] == 0){
			t[2] = 0;
		}
		while(t[0] > 0 && t[1] > 0){
			t[2]++;
			t[1]--;
			t[0]--;
		}
		s[0] -= t[0];
	}

	//Como se apendan muchas cosas, se hizo la funcion app para no hacer esto mismo 4 veces. Esta funcion funciona tanto para el robot que camina como para el que salta.
	public static void app(StringBuilder b, String q1, String q2, int c1, int c2){
		int x = c1;
		int y = c2;
		for(int j = 0; j < (c1 + (2 * c2)); j++){
			if(x > 0){
				b.append(q1);
				x--;
			}
			else if(y > 0){
				b.append(q2);
				y--;
				c1--;
			}
		}
	}
}