Problem: Igor the analyst has adopted n little bunnies. As we all know, bunnies love carrots. Thus, Igor has bought a carrot to be shared between his bunnies. Igor wants to treat all the bunnies equally, and thus he wants to cut the carrot into n pieces of equal area. 

Formally, the carrot can be viewed as an isosceles triangle with base length equal to 1 and height equal to h. Igor wants to make n - 1 cuts parallel to the base to cut the carrot into n pieces. He wants to make sure that all n pieces have the same area. Can you help Igor determine where to cut the carrot so that each piece have equal area?

<image> Illustration to the first example.

Input

The first and only line of input contains two space-separated integers, n and h (2 ≤ n ≤ 1000, 1 ≤ h ≤ 105).

Output

The output should contain n - 1 real numbers x1, x2, ..., xn - 1. The number xi denotes that the i-th cut must be made xi units away from the apex of the carrot. In addition, 0 < x1 < x2 < ... < xn - 1 < h must hold. 

Your output will be considered correct if absolute or relative error of every number in your output doesn't exceed 10 - 6.

Formally, let your answer be a, and the jury's answer be b. Your answer is considered correct if <image>.

Examples

Input

3 2


Output

1.154700538379 1.632993161855


Input

2 100000


Output

70710.678118654752

Note

Definition of isosceles triangle: <https://en.wikipedia.org/wiki/Isosceles_triangle>.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using std::cin;
using std::cout;
using std::endl;
long long Factorial(long long i) { return i > 1 ? i * Factorial(i - 1) : 1; }
long long Combination(long long n, long long r) {
  if (n - r < r) r = n - r;
  long long ansn = 1, ansr = 1;
  for (long long i = n - r + 1; i <= n; ++i) ansn *= i;
  for (long long j = 1; j <= r; ++j) ansr *= j;
  return ansn / ansr;
}
long long gcd(long long a, long long b) { return b ? gcd(b, a % b) : a; }
long long lcm(long long a, long long b) { return a / gcd(a, b) * b; }
std::vector<int> Eratosthenes(const int len, int *vis) {
  memset(vis, 0, sizeof(int) * len);
  std::vector<int> prime;
  int m = (int)sqrt(len + 0.5);
  for (int i = (2); i <= (m); ++i)
    if (!vis[i])
      for (int j = i * i; j < len; j += i) vis[j] = 1;
  for (int i = (2); i < (len); ++i)
    if (!vis[i]) prime.push_back(i);
  return prime;
}
void phi_table(int n, int *phi) {
  for (int i = (2); i <= (n); ++i) phi[i] = 0;
  phi[1] = 1;
  for (int i = (2); i <= (n); ++i)
    if (!phi[i])
      for (int j = i; j <= n; j += i) {
        if (!phi[j]) phi[j] = j;
        phi[j] = phi[j] / i * (i - 1);
      }
}
double n, h;
bool check(double m, double s) {
  double x = h / m;
  double base = (double)1 / x;
  double S = m * base / 2;
  return S <= s;
}
int main() {
  cin >> n >> h;
  double S = h / 2;
  double s = S / n;
  for (int i = (1); i < (n); ++i) {
    double l = 0, r = h;
    for (int j = (0); j < (100); ++j) {
      double m = l + (r - l) / 2;
      if (check(m, s * i))
        l = m;
      else
        r = m;
    }
    printf("%.12f%c", l, i != n - 1 ? ' ' : '\n');
  }
  return 0;
}