Problem: As you very well know, this year's funkiest numbers are so called triangular numbers (that is, integers that are representable as <image>, where k is some positive integer), and the coolest numbers are those that are representable as a sum of two triangular numbers.

A well-known hipster Andrew adores everything funky and cool but unfortunately, he isn't good at maths. Given number n, help him define whether this number can be represented by a sum of two triangular numbers (not necessarily different)!

Input

The first input line contains an integer n (1 ≤ n ≤ 109).

Output

Print "YES" (without the quotes), if n can be represented as a sum of two triangular numbers, otherwise print "NO" (without the quotes).

Examples

Input

256


Output

YES


Input

512


Output

NO

Note

In the first sample number <image>.

In the second sample number 512 can not be represented as a sum of two triangular numbers.

Solution (in PYTHON3):

Solution:
# cook your dish here
from collections import defaultdict, OrderedDict, Counter
from sys import stdin, stdout
from bisect import bisect_left, bisect_right
# import numpy as np
from queue import Queue, PriorityQueue
from heapq import *
from statistics import *
from math import sqrt, log10, log2, log, gcd,ceil, floor
import fractions
import copy
from copy import deepcopy
import sys
import io

sys.setrecursionlimit(10000)
import math
import os
import bisect
import collections

mod = int(pow(10, 9)) + 7
import random
from random import *
from time import time;
import itertools
from itertools import  combinations,permutations,combinations_with_replacement,product


def ncr(n, r, p=mod):
    num = den = 1
    for i in range(r):
        num = (num * (n - i)) % p
        den = (den * (i + 1)) % p
    return (num * pow(den,
                      p - 2, p)) % p


def normalncr(n, r):
    r = min(r, n - r)
    count = 1;
    for i in range(n - r, n + 1):
        count *= i;

    for i in range(1, r + 1):
        count //= i;
    return count


inf = float("inf")
adj = defaultdict(set)
visited = defaultdict(int)


def addedge(a, b):
    adj[a].add(b)
    adj[b].add(a)


def bfs(v):
    q = Queue()
    q.put(v)
    visited[v] = 1
    while q.qsize() > 0:
        s = q.get_nowait()
        print(s)
        for i in adj[s]:
            if visited[i] == 0:
                q.put(i)
                visited[i] = 1


def dfs(v, visited):
    if visited[v] == 1:
        return;
    visited[v] = 1

    print(v)
    for i in adj[v]:
        dfs(i, visited)


# a9=pow(10,6)+10
# prime = [True for i in range(a9 + 1)]
# def SieveOfEratosthenes(n):
#     p = 2
#     while (p * p <= n):
#         if (prime[p] == True):
#             for i in range(p * p, n + 1, p):
#                 prime[i] = False
#         p += 1
# SieveOfEratosthenes(a9)
# prime_number=[]
# for i in range(2,a9):
#     if prime[i]:
#         prime_number.append(i)
def reverse_bisect_right(a, x, lo=0, hi=None):
    if lo < 0:
        raise ValueError('lo must be non-negative')
    if hi is None:
        hi = len(a)
    while lo < hi:
        mid = (lo + hi) // 2
        if x > a[mid]:
            hi = mid
        else:
            lo = mid + 1
    return lo


def reverse_bisect_left(a, x, lo=0, hi=None):
    if lo < 0:
        raise ValueError('lo must be non-negative')
    if hi is None:
        hi = len(a)
    while lo < hi:
        mid = (lo + hi) // 2
        if x >= a[mid]:
            hi = mid
        else:
            lo = mid + 1
    return lo


def get_list():
    return list(map(int, input().split()))

def make_list(m):
    m+=list(map(int, input().split()))

def get_str_list_in_int():
    return [int(i) for i in list(input())]


def get_str_list():
    return list(input())


def get_map():
    return map(int, input().split())


def input_int():
    return int(input())


def matrix(a, b):
    return [[0 for i in range(b)] for j in range(a)]


def swap(a, b):
    return b, a


def find_gcd(l):
    a = l[0]
    for i in range(len(l)):
        a = gcd(a, l[i])
    return a;


def is_prime(n):
    sqrta = int(sqrt(n))
    for i in range(2, sqrta + 1):
        if n % i == 0:
            return 0;
    return 1;


def prime_factors(n):
    while n % 2 == 0:
        return [2] + prime_factors(n // 2)
    sqrta = int(sqrt(n))

    for i in range(3, sqrta + 1, 2):
        if n % i == 0:
            return [i] + prime_factors(n // i)

    return [n]

def p(a):
    if type(a) == str:
        print(a + "\n")
    else:
        print(str(a) + "\n")


def ps(a):
    if type(a) == str:
        print(a)
    else:
        print(str(a))


def kth_no_not_div_by_n(n, k):
    return k + (k - 1) // (n - 1)


def forward_array(l):
    """
    returns the forward index where the elemetn is just greater than that element
    [100,200] gives [1,2]
    because element at index 1 is greater than 100 and nearest
    similarly if it is largest then it outputs n
    :param l:
    :return:
    """
    n = len(l)
    stack = []
    forward = [0] * n
    for i in range(len(l) - 1, -1, -1):
        while len(stack) and l[stack[-1]] < l[i]:
            stack.pop()
        if len(stack) == 0:
            forward[i] = len(l);
        else:
            forward[i] = stack[-1]
        stack.append(i)
    return forward;


def backward_array(l):
    n = len(l)
    stack = []
    backward = [0] * n
    for i in range(len(l)):
        while len(stack) and l[stack[-1]] < l[i]:
            stack.pop()
        if len(stack) == 0:
            backward[i] = -1;
        else:
            backward[i] = stack[-1]
        stack.append(i)
    return backward


def char(a):
    return chr(a + 97)


def get_length(a):
    return 1 + int(log10(a))


def issq(n):
    sqrta = int(n ** 0.5)
    return sqrta ** 2 == n;


def ceil(a,b):
    return int((a+b-1)/b)

def equal_sum_partition(arr,n):
    sum = 0
    for i in range(n):
        sum += arr[i]
    if sum % 2 != 0:
        return False

    part = [[True for i in range(n + 1)]
            for j in range(sum // 2 + 1)]

    for i in range(0, n + 1):
        part[0][i] = True

    for i in range(1, sum // 2 + 1):
        part[i][0] = False

    for i in range(1, sum // 2 + 1):

        for j in range(1, n + 1):
            part[i][j] = part[i][j - 1]

            if i >= arr[j - 1]:
                part[i][j] = (part[i][j] or
                              part[i - arr[j - 1]][j - 1])

    return part[sum // 2][n]

def bin_sum_array(arr,n):
    for i in range(n):
        if arr[i]%2==1:
            return i+1
    binarray=[list(reversed(bin(i)[2:])) for i in arr]
    new_array=[0 for i in range(32)]
    for i in binarray:
        for j in range(len(i)):
            if i[j]=='1':
                new_array[j]+=1
    return new_array

nc = "NO"
yc = "YES"
ns = "No"
ys = "Yes"
def yesno(a):
    print(yc if a else nc)
def reduce(dict,a):
    dict[a]-=1;
    if dict[a]==0:
        dict.pop(a)
# import math as mt
# MAXN=10**7
# spf = [0 for i in range(MAXN)]
# def sieve():
#     spf[1] = 1
#     for i in range(2, MAXN):
#         # marking smallest prime factor
#         # for every number to be itself.
#         spf[i] = i
#
#         # separately marking spf for
#     # every even number as 2
#     for i in range(4, MAXN, 2):
#         spf[i] = 2
#
#     for i in range(3, mt.ceil(mt.sqrt(MAXN))):
#
#         # checking if i is prime
#         if (spf[i] == i):
#
#             # marking SPF for all numbers
#             # divisible by i
#             for j in range(i * i, MAXN, i):
#
#                 # marking spf[j] if it is
#                 # not previously marked
#                 if (spf[j] == j):
#                     spf[j] = i
# def getFactorization(x):
#     ret = list()
#     while (x != 1):
#         ret.append(spf[x])
#         x = x // spf[x]
#
#     return ret
# sieve()


# if(os.path.exists('input.txt')):
#     sys.stdin = open("input.txt","r") ; sys.stdout = open("output.txt","w")


# input = io.BytesIO(os.read(0, os.fstat(0).st_size)).readline
# input=stdin.readline
# print=stdout.write

arr=[i*(i+1)//2 for i in range(1,100000) if i*(i+1)//2<10**9]

no=10**9


for i in range(1):
    n=int(input())
    for i in arr:
        index=bisect_left(arr,n-i)
        if index!=len(arr) and arr[index]==n-i:

            print(yc)
            break;
    else:
        print(nc)