Problem: The Olympic Games in Bercouver are in full swing now. Here everyone has their own objectives: sportsmen compete for medals, and sport commentators compete for more convenient positions to give a running commentary. Today the main sport events take place at three round stadiums, and the commentator's objective is to choose the best point of observation, that is to say the point from where all the three stadiums can be observed. As all the sport competitions are of the same importance, the stadiums should be observed at the same angle. If the number of points meeting the conditions is more than one, the point with the maximum angle of observation is prefered. 

Would you, please, help the famous Berland commentator G. Berniev to find the best point of observation. It should be noted, that the stadiums do not hide each other, the commentator can easily see one stadium through the other.

Input

The input data consists of three lines, each of them describes the position of one stadium. The lines have the format x, y, r, where (x, y) are the coordinates of the stadium's center ( - 103 ≤ x, y ≤ 103), and r (1 ≤ r ≤ 103) is its radius. All the numbers in the input data are integer, stadiums do not have common points, and their centers are not on the same line. 

Output

Print the coordinates of the required point with five digits after the decimal point. If there is no answer meeting the conditions, the program shouldn't print anything. The output data should be left blank.

Examples

Input

0 0 10
60 0 10
30 30 10


Output

30.00000 0.00000

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
typedef struct {
  double x, y;
} point_t;
typedef struct {
  double x, y, r;
} circle_t;
typedef struct {
  double A, B, C;
} Line;
Line zhong_chui_xian(circle_t circle1, circle_t circle2) {
  Line L1;
  point_t p;
  double k;
  p.x = (circle1.x + circle2.x) / 2;
  p.y = (circle1.y + circle2.y) / 2;
  if (fabs(circle1.y - circle2.y) < 1E-8) {
    L1.A = 1;
    L1.B = 0;
    L1.C = -p.x;
  } else if (fabs(circle1.x - circle2.x) < 1E-8) {
    L1.A = 0;
    L1.B = 1;
    L1.C = -p.y;
  } else {
    k = -1 / ((circle1.y - circle2.y) / (circle1.x - circle2.x));
    L1.A = k;
    L1.B = -1;
    L1.C = p.y - k * p.x;
  }
  return L1;
}
int line_intersect(Line L1, Line L2, point_t& p) {
  double d, d1, d2, d3;
  d = L1.A * L2.B - L2.A * L1.B;
  if (fabs(d) < 1E-8) {
    d1 = L1.A / L2.A;
    d2 = L1.B / L2.B;
    d3 = L1.C / L2.C;
    if (fabs(d1 - d2) < 1E-8 && fabs(d2 - d3) < 1E-8)
      return 2;
    else
      return 0;
  }
  p.x = (L2.C * L1.B - L1.C * L2.B) / d;
  p.y = (L2.A * L1.C - L1.A * L2.C) / d;
  return 1;
}
circle_t yuan_guiji(circle_t circle1, circle_t circle2) {
  circle_t circle3;
  double keep1, keep2, keep3;
  keep1 =
      (circle2.r * circle2.r * circle1.x - circle1.r * circle1.r * circle2.x) /
      (circle1.r * circle1.r - circle2.r * circle2.r);
  keep2 =
      (circle2.r * circle2.r * circle1.y - circle1.r * circle1.r * circle2.y) /
      (circle1.r * circle1.r - circle2.r * circle2.r);
  keep3 = (circle2.r * circle2.r * circle1.x * circle1.x -
           circle1.r * circle1.r * circle2.x * circle2.x -
           circle1.r * circle1.r * circle2.y * circle2.y +
           circle2.r * circle2.r * circle1.y * circle1.y) /
          (circle1.r * circle1.r - circle2.r * circle2.r);
  circle3.x = -keep1;
  circle3.y = -keep2;
  circle3.r = sqrt(keep3 + keep1 * keep1 + keep2 * keep2);
  return circle3;
}
int equa(double A, double B, double C, double& x1, double& x2) {
  double f = B * B - 4 * A * C;
  if (f < 0) return -1;
  x1 = (-B + sqrt(f)) / (2 * A);
  x2 = (-B - sqrt(f)) / (2 * A);
  return 1;
}
double point_line_dis(point_t a, Line ln) {
  return (fabs(ln.A * a.x + ln.B * a.y + ln.C) /
          sqrt(ln.A * ln.A + ln.B * ln.B));
}
int line_circle_intersect(Line ln, circle_t Y, point_t& p1, point_t& p2) {
  double t1, t2, len;
  point_t p3;
  p3.x = Y.x;
  p3.y = Y.y;
  len = point_line_dis(p3, ln);
  if (len > Y.r) return 0;
  int zz = -1;
  if (fabs(ln.B) < 1e-8) {
    p1.x = p2.x = -1.0 * ln.C / ln.A;
    zz = equa(1.0, -2.0 * Y.y,
              Y.y * Y.y + (p1.x - Y.x) * (p1.x - Y.x) - Y.r * Y.r, t1, t2);
    p1.y = t1;
    p2.y = t2;
  } else if (fabs(ln.A) < 1e-8) {
    p1.y = p2.y = -1.0 * ln.C / ln.B;
    zz = equa(1.0, -2.0 * Y.x,
              Y.x * Y.x + (p1.y - Y.y) * (p1.y - Y.y) - Y.r * Y.r, t1, t2);
    p1.x = t1;
    p2.x = t2;
  } else {
    zz = equa(
        ln.A * ln.A + ln.B * ln.B,
        2.0 * ln.A * ln.C + 2.0 * ln.A * ln.B * Y.y - 2.0 * ln.B * ln.B * Y.x,
        ln.B * ln.B * Y.x * Y.x + ln.C * ln.C + 2 * ln.B * ln.C * Y.y +
            ln.B * ln.B * Y.y * Y.y - ln.B * ln.B * Y.r * Y.r,
        t1, t2);
    p1.x = t1, p1.y = -1 * (ln.A / ln.B * t1 + ln.C / ln.B);
    p2.x = t2, p2.y = -1 * (ln.A / ln.B * t2 + ln.C / ln.B);
  }
  if (p1.x - p2.x < 1E-8 && p1.y - p2.y < 1E-8)
    return 1;
  else
    return 2;
}
double dist(double xa, double ya, double xb, double yb) {
  return sqrt((xa - xb) * (xa - xb) + (ya - yb) * (ya - yb));
}
double max(double a, double b) { return a > b ? a : b; }
double min(double a, double b) { return a < b ? a : b; }
int circle_intersect(circle_t A, circle_t B, point_t& ia, point_t& ib) {
  if (A.x == B.x && A.y == B.y) return 5;
  double dd = dist(A.x, A.y, B.x, B.y);
  if (A.r + B.r + 1E-8 < dd) return 1;
  double k, a, b, d, aa, bb, cc, c, drt;
  k = A.r;
  a = B.x - A.x;
  b = B.y - A.y;
  c = B.r;
  d = (c * c) - (k * k) - (a * a) - (b * b);
  aa = 4 * (a * a) + 4 * (b * b);
  bb = 4 * b * d;
  cc = (d * d) - 4 * (a * a) * (k * k);
  drt = (bb * bb) - 4 * aa * cc;
  if (drt < 0) return 5;
  drt = sqrt(drt);
  ia.y = (-bb + drt) / 2 / aa;
  ib.y = (-bb - drt) / 2 / aa;
  if (fabs(a) < 1E-8) {
    ia.x = sqrt((k * k) - (ia.y * ia.y));
    ib.x = -ia.x;
  } else {
    ia.x = (2 * b * ia.y + d) / -2 / a;
    ib.x = (2 * b * ib.y + d) / -2 / a;
  }
  ia.x += A.x;
  ia.y += A.y;
  ib.x += A.x;
  ib.y += A.y;
  if (fabs(ia.y - ib.y) < 1E-8) {
    if (fabs(A.r + B.r - dd) < 1E-8) return 2;
    if (fabs(dd - (max(A.r, B.r) - min(A.r, B.r))) < 1E-8) return 3;
  }
  return 4;
}
int main() {
  circle_t circle[3];
  int i, count;
  Line L1, L2;
  point_t p, p1, p2;
  circle_t circle1, circle2;
  for (i = 0; i < 3; i++)
    scanf("%lf%lf%lf", &circle[i].x, &circle[i].y, &circle[i].r);
  if (fabs(circle[0].r - circle[1].r) < 1E-8) {
    L1 = zhong_chui_xian(circle[0], circle[1]);
    if (fabs(circle[1].r - circle[2].r) < 1E-8) {
      L2 = zhong_chui_xian(circle[1], circle[2]);
      line_intersect(L1, L2, p);
      printf("%0.5lf %0.5lf\n", p.x, p.y);
    } else {
      circle2 = yuan_guiji(circle[1], circle[2]);
      count = line_circle_intersect(L1, circle2, p1, p2);
      if (count == 1) {
        printf("%0.5lf %0.5lf\n", p1.x, p1.y);
      } else if (count == 2) {
        if ((circle[0].r / dist(circle[0].x, circle[0].y, p1.x, p1.y)) >
            (circle[0].r / dist(circle[0].x, circle[0].y, p2.x, p2.y)))
          printf("%0.5lf %0.5lf\n", p1.x, p1.y);
        else
          printf("%0.5lf %0.5lf\n", p2.x, p2.y);
      }
    }
  } else {
    circle1 = yuan_guiji(circle[0], circle[1]);
    if (fabs(circle[1].r - circle[2].r) < 1E-8) {
      L2 = zhong_chui_xian(circle[1], circle[2]);
      count = line_circle_intersect(L2, circle1, p1, p2);
      if (count == 1) {
        printf("%0.5lf %0.5lf\n", p1.x, p1.y);
      } else if (count == 2) {
        if ((circle[0].r / dist(circle[0].x, circle[0].y, p1.x, p1.y)) >
            (circle[0].r / dist(circle[0].x, circle[0].y, p2.x, p2.y)))
          printf("%0.5lf %0.5lf\n", p1.x, p1.y);
        else
          printf("%0.5lf %0.5lf\n", p2.x, p2.y);
      }
    } else {
      circle2 = yuan_guiji(circle[1], circle[2]);
      count = circle_intersect(circle1, circle2, p1, p2);
      if (count == 2 || count == 3) {
        printf("%0.5lf %0.5lf\n", p1.x, p1.y);
      } else if (count == 4) {
        if ((circle[0].r / dist(circle[0].x, circle[0].y, p1.x, p1.y)) >
            (circle[0].r / dist(circle[0].x, circle[0].y, p2.x, p2.y)))
          printf("%0.5lf %0.5lf\n", p1.x, p1.y);
        else
          printf("%0.5lf %0.5lf\n", p2.x, p2.y);
      }
    }
  }
  return 0;
}