Problem: You are given a directed graph of n vertices and m edges. Vertices are numbered from 1 to n. There is a token in vertex 1.

The following actions are allowed: 

  * Token movement. To move the token from vertex u to vertex v if there is an edge u → v in the graph. This action takes 1 second. 
  * Graph transposition. To transpose all the edges in the graph: replace each edge u → v by an edge v → u. This action takes increasingly more time: k-th transposition takes 2^{k-1} seconds, i.e. the first transposition takes 1 second, the second one takes 2 seconds, the third one takes 4 seconds, and so on. 



The goal is to move the token from vertex 1 to vertex n in the shortest possible time. Print this time modulo 998 244 353.

Input

The first line of input contains two integers n, m (1 ≤ n, m ≤ 200 000).

The next m lines contain two integers each: u, v (1 ≤ u, v ≤ n; u ≠ v), which represent the edges of the graph. It is guaranteed that all ordered pairs (u, v) are distinct.

It is guaranteed that it is possible to move the token from vertex 1 to vertex n using the actions above.

Output

Print one integer: the minimum required time modulo 998 244 353.

Examples

Input


4 4
1 2
2 3
3 4
4 1


Output


2


Input


4 3
2 1
2 3
4 3


Output


10

Note

The first example can be solved by transposing the graph and moving the token to vertex 4, taking 2 seconds.

The best way to solve the second example is the following: transpose the graph, move the token to vertex 2, transpose the graph again, move the token to vertex 3, transpose the graph once more and move the token to vertex 4.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
long long gcd(long long a, long long b) { return b ? gcd(b, a % b) : a; }
template <class T1, class T2>
struct cmpf {
  bool rev;
  inline bool operator()(const pair<T1, T2>& a, const pair<T1, T2>& b) const {
    return (a.first < b.first) ^ rev;
  }
  cmpf(bool b = false) { rev = b; }
};
template <class T1, class T2>
struct cmps {
  bool rev;
  inline bool operator()(const pair<T1, T2>& a, const pair<T1, T2>& b) const {
    return (a.second < b.second) ^ rev;
  }
  cmps(bool b = false) { rev = b; }
};
long long binpow(long long x, long long p, const long long& mod) {
  assert(mod > 0);
  long long ret = 1;
  for (; p > 0; p >>= 1, x = x * x % mod)
    if (p & 1) ret = ret * x % mod;
  return ret;
}
template <class T>
bool chmn(T& a, const T& b) {
  return (greater<T>()(a, b) ? (a = b, true) : false);
}
template <class T>
bool chmx(T& a, const T& b) {
  return (less<T>()(a, b) ? (a = b, true) : false);
}
void setIO(const string& filename = "") {
  if (filename.size() > 0) {
    freopen((filename + ".in").c_str(), "r", stdin);
    freopen((filename + ".out").c_str(), "w", stdout);
  }
  cin.tie(0)->sync_with_stdio(0);
}
int chr[8] = {-1, 0, 1, 0, -1, -1, 1, 1};
int chc[8] = {0, 1, 0, -1, -1, 1, -1, 1};
const long long MOD = 998244353;
const int INIT = 1001001001;
const int MN = 201001;
const int LG = 20;
const long long INF = 2e18 + 1;
long long N, M, K, Q;
long long A[MN];
set<long long> adj[MN], radj[MN];
struct Item {
  long long node;
  long long dst, revs;
  Item(const long long _node, const long long _dst, const long long _revs) {
    node = _node;
    dst = _dst;
    revs = _revs;
  }
  inline const bool operator<(const Item& o) const {
    if (revs == o.revs) {
      if (dst == o.dst) return node > o.node;
      return dst > o.dst;
    }
    return revs > o.revs;
  }
  void print() const {
    cerr << "Item node,revs,dst: " << node << ' ' << revs << ' ' << dst << endl;
  }
};
long long dist[LG + 1][MN];
long long p2[MN];
pair<long long, long long> V[2][MN];
void solve(int testcase) {
  cin >> N >> M;
  for (int i = 0; i < M; ++i) {
    long long u, v;
    cin >> u >> v;
    --u;
    --v;
    adj[u].insert(v);
    radj[v].insert(u);
  }
  p2[0] = 1;
  for (int i = 1; i < MN; ++i) {
    p2[i] = p2[i - 1] << 1;
    if (i >= 56) {
      p2[i] %= MOD;
    }
  }
  priority_queue<pair<long long, long long>, vector<pair<long long, long long>>,
                 greater<pair<long long, long long>>>
      pq[LG + 1];
  pq[0].emplace(0, 0);
  for (int i = 0; i <= LG; ++i) fill(dist[i], dist[i] + N, INF);
  dist[0][0] = 0;
  long long ans = INF;
  for (int i = 0; i < LG; ++i) {
    while (pq[i].size() > 0) {
      const pair<long long, long long> cur = pq[i].top();
      pq[i].pop();
      (i, cur);
      if (cur.second == N - 1) {
        chmn(ans, cur.first);
        continue;
      }
      if (i & 1) {
        for (const long long v : radj[cur.second]) {
          if (chmn(dist[i][v], cur.first + 1)) {
            pq[i].emplace(dist[i][v], v);
          }
        }
      } else {
        for (const long long v : adj[cur.second]) {
          if (chmn(dist[i][v], cur.first + 1)) {
            pq[i].emplace(dist[i][v], v);
          }
        }
      }
      if (chmn(dist[i + 1][cur.second], cur.first + p2[i])) {
        pq[i + 1].emplace(dist[i + 1][cur.second], cur.second);
      }
    }
  }
  if (ans != INF) {
    cout << ans % MOD << endl;
    return;
  }
  fill(V[0], V[0] + N, pair<long long, long long>(INF, INF));
  fill(V[1], V[1] + N, pair<long long, long long>(INF, INF));
  priority_queue<Item> pq2;
  while (pq[LG].size() > 0) {
    const pair<long long, long long> cur = pq[LG].top();
    pq[LG].pop();
    if (V[LG & 1][cur.second].first == LG) continue;
    const long long D = cur.first - (p2[LG] - 1);
    if (chmn(V[LG & 1][cur.second], pair<long long, long long>(LG, D))) {
      (D, cur.second);
      assert(0 <= D);
      assert(D < M);
      pq2.emplace(cur.second, D, LG);
    }
  }
  while (pq2.size() > 0) {
    const Item cur = pq2.top();
    pq2.pop();
    if (cur.node == N - 1) {
      cout << (cur.dst + p2[cur.revs] - 1) % MOD << endl;
      return;
    }
    for (const long long v : adj[cur.node]) {
      const bool flip = cur.revs & 1;
      const long long new_revs = cur.revs + flip;
      if (chmn(V[new_revs & 1][v],
               pair<long long, long long>(new_revs, cur.dst + 1))) {
        pq2.emplace(v, cur.dst + 1, new_revs);
      }
    }
    for (const long long v : radj[cur.node]) {
      const bool flip = !(cur.revs & 1);
      const long long new_revs = cur.revs + flip;
      if (chmn(V[new_revs & 1][v],
               pair<long long, long long>(new_revs, cur.dst + 1))) {
        pq2.emplace(v, cur.dst + 1, new_revs);
      }
    }
  }
  assert(false);
}
int main() {
  setIO();
  long long T = 1;
  for (int t = 1; t <= T; ++t) {
    solve(t);
  }
  return 0;
}