Problem: On the way to school, Karen became fixated on the puzzle game on her phone!

<image>

The game is played as follows. In each level, you have a grid with n rows and m columns. Each cell originally contains the number 0.

One move consists of choosing one row or column, and adding 1 to all of the cells in that row or column.

To win the level, after all the moves, the number in the cell at the i-th row and j-th column should be equal to gi, j.

Karen is stuck on one level, and wants to know a way to beat this level using the minimum number of moves. Please, help her with this task!

Input

The first line of input contains two integers, n and m (1 ≤ n, m ≤ 100), the number of rows and the number of columns in the grid, respectively.

The next n lines each contain m integers. In particular, the j-th integer in the i-th of these rows contains gi, j (0 ≤ gi, j ≤ 500).

Output

If there is an error and it is actually not possible to beat the level, output a single integer -1.

Otherwise, on the first line, output a single integer k, the minimum number of moves necessary to beat the level.

The next k lines should each contain one of the following, describing the moves in the order they must be done:

  * row x, (1 ≤ x ≤ n) describing a move of the form "choose the x-th row". 
  * col x, (1 ≤ x ≤ m) describing a move of the form "choose the x-th column". 



If there are multiple optimal solutions, output any one of them.

Examples

Input

3 5
2 2 2 3 2
0 0 0 1 0
1 1 1 2 1


Output

4
row 1
row 1
col 4
row 3


Input

3 3
0 0 0
0 1 0
0 0 0


Output

-1


Input

3 3
1 1 1
1 1 1
1 1 1


Output

3
row 1
row 2
row 3

Note

In the first test case, Karen has a grid with 3 rows and 5 columns. She can perform the following 4 moves to beat the level:

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In the second test case, Karen has a grid with 3 rows and 3 columns. It is clear that it is impossible to beat the level; performing any move will create three 1s on the grid, but it is required to only have one 1 in the center.

In the third test case, Karen has a grid with 3 rows and 3 columns. She can perform the following 3 moves to beat the level:

<image>

Note that this is not the only solution; another solution, among others, is col 1, col 2, col 3.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int a[105][105], ll[105], rr[105], l[105], r[105];
int main() {
  int n, m, i, j, k, s, t, a1, b1, ans, p, ii;
  scanf("%d%d", &n, &m);
  for (i = 1; i <= n; i++)
    for (j = 1; j <= m; j++) scanf("%d", &a[i][j]);
  ans = 999999;
  p = 1;
  for (i = 2; i <= n; i++)
    for (j = 2; j <= m; j++)
      if (a[i][j] - a[i - 1][j] != a[i][1] - a[i - 1][1]) p = 0;
  for (i = 2; i <= m; i++)
    for (j = 2; j <= n; j++)
      if (a[j][i] - a[j][i - 1] != a[1][i] - a[1][i - 1]) p = 0;
  if (p == 0)
    printf("-1\n");
  else {
    for (ii = 0; ii <= a[1][1]; ii++) {
      p = 1;
      l[1] = ii;
      r[1] = a[1][1] - ii;
      s = a[1][1];
      for (i = 2; i <= n; i++) {
        l[i] = l[i - 1] + a[i][1] - a[i - 1][1];
        s += l[i];
        if (l[i] < 0) {
          p = 0;
          break;
        }
      }
      for (i = 2; i <= m; i++) {
        r[i] = r[i - 1] + a[1][i] - a[1][i - 1];
        s += r[i];
        if (r[i] < 0) {
          p = 0;
          break;
        }
      }
      if (p == 1) {
        if (s < ans) {
          ans = s;
          for (i = 1; i <= n; i++) ll[i] = l[i];
          for (i = 1; i <= m; i++) rr[i] = r[i];
        }
      }
    }
    printf("%d\n", ans);
    for (i = 1; i <= n; i++)
      for (j = 1; j <= ll[i]; j++) printf("row %d\n", i);
    for (i = 1; i <= m; i++)
      for (j = 1; j <= rr[i]; j++) printf("col %d\n", i);
  }
  return 0;
}