Problem: Igor the analyst has adopted n little bunnies. As we all know, bunnies love carrots. Thus, Igor has bought a carrot to be shared between his bunnies. Igor wants to treat all the bunnies equally, and thus he wants to cut the carrot into n pieces of equal area. 

Formally, the carrot can be viewed as an isosceles triangle with base length equal to 1 and height equal to h. Igor wants to make n - 1 cuts parallel to the base to cut the carrot into n pieces. He wants to make sure that all n pieces have the same area. Can you help Igor determine where to cut the carrot so that each piece have equal area?

<image> Illustration to the first example.

Input

The first and only line of input contains two space-separated integers, n and h (2 ≤ n ≤ 1000, 1 ≤ h ≤ 105).

Output

The output should contain n - 1 real numbers x1, x2, ..., xn - 1. The number xi denotes that the i-th cut must be made xi units away from the apex of the carrot. In addition, 0 < x1 < x2 < ... < xn - 1 < h must hold. 

Your output will be considered correct if absolute or relative error of every number in your output doesn't exceed 10 - 6.

Formally, let your answer be a, and the jury's answer be b. Your answer is considered correct if <image>.

Examples

Input

3 2


Output

1.154700538379 1.632993161855


Input

2 100000


Output

70710.678118654752

Note

Definition of isosceles triangle: <https://en.wikipedia.org/wiki/Isosceles_triangle>.

Solution (in JAVA):

Solution:

import java.util.Scanner;

/**
 * Created by imahmoud on 5/13/17.
 */
public class B {

    public void solve(){
        Scanner in =  new Scanner(System.in);
        double N = in.nextInt();
        double H = in.nextInt();
        double B = 1;

        double C = Math.sqrt(Math.pow(H,2) + Math.pow(B/2,2));
        double angleC = Math.asin(H/C);
        double angleA = (Math.PI - angleC*2);







        double triangleArea = H * B /2;
        double partArea = triangleArea/ N;

        for (int i = 0; i < N - 1; i++) {
            double area = partArea * (i +1);
            double a = Math.sqrt(area*2/Math.sin(angleA));

            double h = area /(Math.sin(angleA/2) * a);
            System.out.print(h+" ");
        }


    }
    public static void main(String[] args) {
        new B().solve();
    }
}