Problem: As you very well know, this year's funkiest numbers are so called triangular numbers (that is, integers that are representable as <image>, where k is some positive integer), and the coolest numbers are those that are representable as a sum of two triangular numbers.

A well-known hipster Andrew adores everything funky and cool but unfortunately, he isn't good at maths. Given number n, help him define whether this number can be represented by a sum of two triangular numbers (not necessarily different)!

Input

The first input line contains an integer n (1 ≤ n ≤ 109).

Output

Print "YES" (without the quotes), if n can be represented as a sum of two triangular numbers, otherwise print "NO" (without the quotes).

Examples

Input

256


Output

YES


Input

512


Output

NO

Note

In the first sample number <image>.

In the second sample number 512 can not be represented as a sum of two triangular numbers.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
vector<long long> treugol;
long long N;
int main() {
  cin >> N;
  for (long long i = 1; i * (i + 1) / 2 <= 1000000000; i++)
    treugol.push_back(i * (i + 1) / 2);
  for (int i = 0; i < treugol.size() && treugol[i] < N; i++) {
    int j = (lower_bound(treugol.begin(), treugol.end(), N - treugol[i]) -
             treugol.begin());
    if (j >= 0 && j < treugol.size() && treugol[j] + treugol[i] == N) {
      cout << "YES" << endl;
      return 0;
    }
  }
  cout << "NO" << endl;
  return 0;
}