Problem: Kana was just an ordinary high school girl before a talent scout discovered her. Then, she became an idol. But different from the stereotype, she is also a gameholic. 

One day Kana gets interested in a new adventure game called Dragon Quest. In this game, her quest is to beat a dragon.

<image>

The dragon has a hit point of x initially. When its hit point goes to 0 or under 0, it will be defeated. In order to defeat the dragon, Kana can cast the two following types of spells. 

  * Void Absorption

Assume that the dragon's current hit point is h, after casting this spell its hit point will become \left⌊ h/2 \right⌋ + 10. Here \left⌊ h/2 \right⌋ denotes h divided by two, rounded down.

  * Lightning Strike

This spell will decrease the dragon's hit point by 10. Assume that the dragon's current hit point is h, after casting this spell its hit point will be lowered to h-10.




Due to some reasons Kana can only cast no more than n Void Absorptions and m Lightning Strikes. She can cast the spells in any order and doesn't have to cast all the spells. Kana isn't good at math, so you are going to help her to find out whether it is possible to defeat the dragon.

Input

The first line contains a single integer t (1 ≤ t ≤ 1000) — the number of test cases.

The next t lines describe test cases. For each test case the only line contains three integers x, n, m (1≤ x ≤ 10^5, 0≤ n,m≤30) — the dragon's intitial hit point, the maximum number of Void Absorptions and Lightning Strikes Kana can cast respectively.

Output

If it is possible to defeat the dragon, print "YES" (without quotes). Otherwise, print "NO" (without quotes).

You can print each letter in any case (upper or lower).

Example

Input


7
100 3 4
189 3 4
64 2 3
63 2 3
30 27 7
10 9 1
69117 21 2


Output


YES
NO
NO
YES
YES
YES
YES

Note

One possible casting sequence of the first test case is shown below:

  * Void Absorption \left⌊ 100/2 \right⌋ + 10=60.
  * Lightning Strike 60-10=50.
  * Void Absorption \left⌊ 50/2 \right⌋ + 10=35.
  * Void Absorption \left⌊ 35/2 \right⌋ + 10=27.
  * Lightning Strike 27-10=17.
  * Lightning Strike 17-10=7.
  * Lightning Strike 7-10=-3.

Solution (in PYTHON3):

Solution:

def main():
    for _ in inputt():
        x, n, m = inputi()
        while x > 20 and n:
            x = x // 2 + 10
            n -= 1
        x -= 10 * m
        print("YES" if x <= 0 else "NO")

# region M


# region import
# 所有import部分

from math import *
from heapq import *
from itertools import *
from functools import reduce, lru_cache, partial
from collections import Counter, defaultdict
import re, copy, operator, cmath
import sys, io, os, builtins
sys.setrecursionlimit(1000)

# endregion

# region fastio
# 快速io，能提升大量时间

BUFSIZE = 8192
class FastIO(io.IOBase):
    newlines = 0
    def __init__(self, file):
        self._fd = file.fileno()
        self.buffer = io.BytesIO()
        self.writable = "x" in file.mode or "r" not in file.mode
        self.write = self.buffer.write if self.writable else None
    def read(self):
        while True:
            b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
            if not b:
                break
            ptr = self.buffer.tell()
            self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
        self.newlines = 0
        return self.buffer.read()
    def readline(self):
        while self.newlines == 0:
            b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
            self.newlines = b.count(b"\n") + (not b)
            ptr = self.buffer.tell()
            self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
        self.newlines -= 1
        return self.buffer.readline()
    def flush(self):
        if self.writable:
            os.write(self._fd, self.buffer.getvalue())
            self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(io.IOBase):
    def __init__(self, file):
        self.buffer = FastIO(file)
        self.flush = self.buffer.flush
        self.writable = self.buffer.writable
        self.write = lambda s: self.buffer.write(s.encode("ascii"))
        self.read = lambda: self.buffer.read().decode("ascii")
        self.readline = lambda: self.buffer.readline().decode("ascii")
def print(*args, **kwargs):
    sys.stdout.write(kwargs.pop("split", " ").join(map(str, args)))
    sys.stdout.write(kwargs.pop("end", "\n"))
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip()
inputt = lambda t = 0: range(t) if t else range(int(input()))
inputs = lambda: input().split()
inputi = lambda: map(int, inputs())
inputl = lambda t = 0, k = inputi: map(list, (k() for _ in range(t))) if t else list(k())

# endregion

# region bisect
# 二分搜索，标准库没有函数参数

def len(a):
    if isinstance(a, range):
        return -((a.start - a.stop) // a.step)
    return builtins.len(a)
def bisect_left(a, x, key = None, lo = 0, hi = None):
    if lo < 0: lo = 0
    if hi == None: hi = len(a)
    if key == None: key = do_nothing
    while lo < hi:
        mid = (lo + hi) // 2
        if key(a[mid]) < x: lo = mid + 1
        else: hi = mid
    return lo
def bisect_right(a, x, key = None, lo = 0, hi = None):
    if lo < 0: lo = 0
    if hi == None: hi = len(a)
    if key == None: key = do_nothing
    while lo < hi:
        mid = (lo + hi) // 2
        if x < key(a[mid]): hi = mid
        else: lo = mid + 1
    return lo
def insort_left(a, x, key = None, lo = 0, hi = None):
    lo = bisect_left(a, x, key, lo, hi)
    a.insert(lo, x)
def insort_right(a, x, key = None, lo = 0, hi = None):
    lo = bisect_right(a, x, key, lo, hi)
    a.insert(lo, x)
do_nothing = lambda x: x
bisect = bisect_right
insort = insort_right
def index(a, x, default = None, key = None, lo = 0, hi = None):
    if lo < 0: lo = 0
    if hi == None: hi = len(a)
    if key == None: key = do_nothing
    i = bisect_left(a, x, key, lo, hi)
    if lo <= i < hi and key(a[i]) == x: return a[i]
    if default != None: return default
    raise ValueError
def find_lt(a, x, default = None, key = None, lo = 0, hi = None):
    if lo < 0: lo = 0
    if hi == None: hi = len(a)
    i = bisect_left(a, x, key, lo, hi)
    if lo < i <= hi: return a[i - 1]
    if default != None: return default
    raise ValueError
def find_le(a, x, default = None, key = None, lo = 0, hi = None):
    if lo < 0: lo = 0
    if hi == None: hi = len(a)
    i = bisect_right(a, x, key, lo, hi)
    if lo < i <= hi: return a[i - 1]
    if default != None: return default
    raise ValueError
def find_gt(a, x, default = None, key = None, lo = 0, hi = None):
    if lo < 0: lo = 0
    if hi == None: hi = len(a)
    i = bisect_right(a, x, key, lo, hi)
    if lo <= i < hi: return a[i]
    if default != None: return default
    raise ValueError
def find_ge(a, x, default = None, key = None, lo = 0, hi = None):
    if lo < 0: lo = 0
    if hi == None: hi = len(a)
    i = bisect_left(a, x, key, lo, hi)
    if lo <= i < hi: return a[i]
    if default != None: return default
    raise ValueError

# endregion

# region main
# main 函数部分

if __name__ == "__main__":
    main()

# endregion


# endregion