Problem: You have an integer sequence of length N: a_1, a_2, ..., a_N.

You repeatedly perform the following operation until the length of the sequence becomes 1:

* First, choose an element of the sequence.
* If that element is at either end of the sequence, delete the element.
* If that element is not at either end of the sequence, replace the element with the sum of the two elements that are adjacent to it. Then, delete those two elements.



You would like to maximize the final element that remains in the sequence.

Find the maximum possible value of the final element, and the way to achieve it.

Constraints

* All input values are integers.
* 2 \leq N \leq 1000
* |a_i| \leq 10^9

Input

Input is given from Standard Input in the following format:


N
a_1 a_2 ... a_N


Output

* In the first line, print the maximum possible value of the final element in the sequence.
* In the second line, print the number of operations that you perform.
* In the (2+i)-th line, if the element chosen in the i-th operation is the x-th element from the left in the sequence at that moment, print x.
* If there are multiple ways to achieve the maximum value of the final element, any of them may be printed.

Examples

Input

5
1 4 3 7 5


Output

11
3
1
4
2


Input

4
100 100 -1 100


Output

200
2
3
1


Input

6
-1 -2 -3 1 2 3


Output

4
3
2
1
2


Input

9
1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000


Output

5000000000
4
2
2
2
2

Solution (in JAVA):

Solution:
import java.util.ArrayList;
import java.util.LinkedList;
import java.util.List;
 
public class Main {
  private static void solve() {
    int n = ni();
    int[] a = na(n);
    
    int[] p = new int[n / 2 + (n % 2 == 1 ? 1 : 0)];
    int[] q = new int[n / 2];
    
    for (int i = 0; i < n; i ++) {
      if (i % 2 == 0) {
        p[i / 2] = a[i];
      } else {
        q[i / 2] = a[i];
      }
    }
 
    long max1 = Long.MIN_VALUE;
    long max2 = Long.MIN_VALUE;
    for (int v : p) {
      if (v > 0) max1 += v;
    }
    for (int v : q) {
      if (v > 0) max2 += v;
    }
    
    List<Integer> list = new ArrayList<>();
    LinkedList<Long> l = new LinkedList<>();
    for (int v : a) {
      l.add((long)v);
    }

    if (max1 == Long.MIN_VALUE && max2 == Long.MIN_VALUE) {
      int max = Integer.MIN_VALUE;
      int maxIdx = 0;
      for (int i = 0; i < n; i ++) {
        if (max < a[i]) {
          max = a[i];
          maxIdx = i;
        }
      }
      for (int i = 0; i < maxIdx; i ++) {
        list.add(1);
        l.removeFirst();
      }
      while(l.size() > 1) {
        list.add(l.size());
        l.remove(l.size() - 1);
      }
    } else {
      if (max1 < max2) {
        list.add(1);
        l.removeFirst();
      }
      if (l.size() % 2 == 0) {
        list.add(l.size());
        l.removeLast();
      }
      
      int ptr = 0;
      while (l.size() > 1 && ptr < l.size()) {
        if (l.get(ptr) < 0) {
          if (ptr == 0) {
            list.add(1);
            list.add(1);
            l.removeFirst();
            l.removeFirst();
          } else if (ptr == l.size() - 1) {
            list.add(l.size());
            list.add(l.size() - 1);
            l.removeLast();
            l.removeLast();
          } else {
            long right = l.remove(ptr + 1);
            long left = l.remove(ptr - 1);
            l.set(ptr - 1, right + left);
            list.add(ptr + 1);
          }
        } else {
          ptr += 2;
        }
      }
      
      while (l.size() > 1) {
        long left = l.remove(0);
        long right = l.remove(1);
        l.set(0, left + right);
        list.add(2);
      }
    }

    System.out.println(l.getFirst());
    System.out.println(list.size());
    for (int v : list) {
      System.out.println(v);
    }
  }
  
 
 
  public static void main(String[] args) {
    new Thread(null, new Runnable() {
      @Override
      public void run() {
        long start = System.currentTimeMillis();
        String debug = args.length > 0 ? args[0] : null;
        if (debug != null) {
          try {
            is = java.nio.file.Files.newInputStream(java.nio.file.Paths.get(debug));
          } catch (Exception e) {
            throw new RuntimeException(e);
          }
        }
        reader = new java.io.BufferedReader(new java.io.InputStreamReader(is), 32768);
        solve();
        out.flush();
        tr((System.currentTimeMillis() - start) + "ms");
      }
    }, "", 64000000).start();
  }
 
  private static java.io.InputStream is = System.in;
  private static java.io.PrintWriter out = new java.io.PrintWriter(System.out);
  private static java.util.StringTokenizer tokenizer = null;
  private static java.io.BufferedReader reader;
 
  public static String next() {
    while (tokenizer == null || !tokenizer.hasMoreTokens()) {
      try {
        tokenizer = new java.util.StringTokenizer(reader.readLine());
      } catch (Exception e) {
        throw new RuntimeException(e);
      }
    }
    return tokenizer.nextToken();
  }
 
  private static double nd() {
    return Double.parseDouble(next());
  }
 
  private static long nl() {
    return Long.parseLong(next());
  }
 
  private static int[] na(int n) {
    int[] a = new int[n];
    for (int i = 0; i < n; i++)
      a[i] = ni();
    return a;
  }
 
  private static char[] ns() {
    return next().toCharArray();
  }
 
  private static long[] nal(int n) {
    long[] a = new long[n];
    for (int i = 0; i < n; i++)
      a[i] = nl();
    return a;
  }
 
  private static int[][] ntable(int n, int m) {
    int[][] table = new int[n][m];
    for (int i = 0; i < n; i++) {
      for (int j = 0; j < m; j++) {
        table[i][j] = ni();
      }
    }
    return table;
  }
 
  private static int[][] nlist(int n, int m) {
    int[][] table = new int[m][n];
    for (int i = 0; i < n; i++) {
      for (int j = 0; j < m; j++) {
        table[j][i] = ni();
      }
    }
    return table;
  }
 
  private static int ni() {
    return Integer.parseInt(next());
  }
 
  private static void tr(Object... o) {
    if (is != System.in)
      System.out.println(java.util.Arrays.deepToString(o));
  }
}