Problem: As you very well know, this year's funkiest numbers are so called triangular numbers (that is, integers that are representable as <image>, where k is some positive integer), and the coolest numbers are those that are representable as a sum of two triangular numbers.

A well-known hipster Andrew adores everything funky and cool but unfortunately, he isn't good at maths. Given number n, help him define whether this number can be represented by a sum of two triangular numbers (not necessarily different)!

Input

The first input line contains an integer n (1 ≤ n ≤ 109).

Output

Print "YES" (without the quotes), if n can be represented as a sum of two triangular numbers, otherwise print "NO" (without the quotes).

Examples

Input

256


Output

YES


Input

512


Output

NO

Note

In the first sample number <image>.

In the second sample number 512 can not be represented as a sum of two triangular numbers.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
using pii = pair<int, int>;
using vi = vector<int>;
int main() {
  ios::sync_with_stdio(false);
  cin.tie(NULL);
  ll n;
  cin >> n;
  vector<ll> funky;
  for (ll i = 1;; i++) {
    ll f = (i * (i + 1)) / 2;
    if (f > n) break;
    funky.push_back(f);
  }
  for (int i = 0; i < funky.size(); i++) {
    int b = binary_search(funky.begin(), funky.end(), n - funky[i]);
    if (b) {
      cout << "YES" << '\n';
      return 0;
    }
  }
  cout << "NO" << '\n';
}