Problem: Write a program which reads a sequence of integers $A = \\{a_0, a_1, ..., a_{n-1}\\}$ and reverse specified elements by a list of the following operation:

* reverse($b, e$): reverse the order of $a_b, a_{b+1}, ..., a_{e-1}$

Constraints

* $1 \leq n \leq 1,000$
* $-1,000,000,000 \leq a_i \leq 1,000,000,000$
* $1 \leq q \leq 1,000$
* $0 \leq b < e \leq n$

Input

The input is given in the following format.


$n$
$a_0 \; a_1 \; ...,\; a_{n-1}$
$q$
$b_1 \; e_1$
$b_2 \; e_2$
:
$b_{q} \; b_{q}$


In the first line, $n$ (the number of elements in $A$) is given. In the second line, $a_i$ (each element in $A$) are given. In the third line, the number of queries $q$ is given and each query is given by two integers $b_i \; e_i$ in the following $q$ lines.

Output

Print all elements of $A$ in a line after performing the given operations. Put a single space character between adjacency elements and a newline at the end of the last element.

Example

Input

8
1 2 3 4 5 6 7 8
2
1 6
3 8


Output

1 6 5 8 7 2 3 4

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
#define ull unsigned long long
#define ll long long
#define il inline
#define db double
#define ls rt << 1
#define rs rt << 1 | 1
#define pb push_back
#define mp make_pair
#define pii pair<int, int>
#define pll pair<ll, ll>
#define X first
#define Y second
#define pcc pair<char, char>
#define vi vector<int>
#define vl vector<ll>
#define rep(i, x, y) for(int i = x; i <= y; i ++)
#define rrep(i, x, y) for(int i = x; i >= y; i --)
#define rep0(i, n) for(int i = 0; i < (n); i ++)
#define per0(i, n) for(int i = (n) - 1; i >= 0; i --)
#define ept 1e-9
#define INF 0x3f3f3f3f
#define sz(x) (x).size()
#define All(x) (x).begin(), (x).end()
#define lowbit(x) ((x) & -(x))
using namespace std;
inline int read()
{
	int x = 0, f = 1; char ch = getchar();
	while (ch < '0' || ch > '9') { if (ch == '-') f = -1; ch = getchar(); }
	while (ch >= '0' && ch <= '9') { x = x * 10 + ch - '0'; ch = getchar(); }
	return x * f;
}
inline ll read1()
{
	ll x = 0, f = 1; char ch = getchar();
	while (ch < '0' || ch > '9') { if (ch == '-') f = -1; ch = getchar(); }
	while (ch >= '0' && ch <= '9') { x = x * 10 + ch - '0'; ch = getchar(); }
	return x * f;
}
const ll mod = 1e9 + 7;
const int N = 4e6 + 10;
const db pi = acos(-1);
//int a[N];
int main()
{
	int n = read();
	vi a(n);
	rep0(i, n) a[i] = read();
	int q = read();
	while(q --)
	{
		int x = read();
		int y = read();
		reverse(a.begin() + x, a.begin() + y);
	} 
	rep0(i, n)
	{
		if(i) cout << " ";
		cout << a[i];
	}
	puts("");
	return 0;
}