Problem: Little girl Susie accidentally found her elder brother's notebook. She has many things to do, more important than solving problems, but she found this problem too interesting, so she wanted to know its solution and decided to ask you about it. So, the problem statement is as follows.

Let's assume that we are given a connected weighted undirected graph G = (V, E) (here V is the set of vertices, E is the set of edges). The shortest-path tree from vertex u is such graph G1 = (V, E1) that is a tree with the set of edges E1 that is the subset of the set of edges of the initial graph E, and the lengths of the shortest paths from u to any vertex to G and to G1 are the same. 

You are given a connected weighted undirected graph G and vertex u. Your task is to find the shortest-path tree of the given graph from vertex u, the total weight of whose edges is minimum possible.

Input

The first line contains two numbers, n and m (1 ≤ n ≤ 3·105, 0 ≤ m ≤ 3·105) — the number of vertices and edges of the graph, respectively.

Next m lines contain three integers each, representing an edge — ui, vi, wi — the numbers of vertices connected by an edge and the weight of the edge (ui ≠ vi, 1 ≤ wi ≤ 109). It is guaranteed that graph is connected and that there is no more than one edge between any pair of vertices.

The last line of the input contains integer u (1 ≤ u ≤ n) — the number of the start vertex.

Output

In the first line print the minimum total weight of the edges of the tree.

In the next line print the indices of the edges that are included in the tree, separated by spaces. The edges are numbered starting from 1 in the order they follow in the input. You may print the numbers of the edges in any order.

If there are multiple answers, print any of them.

Examples

Input

3 3
1 2 1
2 3 1
1 3 2
3


Output

2
1 2 


Input

4 4
1 2 1
2 3 1
3 4 1
4 1 2
4


Output

4
2 3 4 

Note

In the first sample there are two possible shortest path trees:

  * with edges 1 – 3 and 2 – 3 (the total weight is 3); 
  * with edges 1 – 2 and 2 – 3 (the total weight is 2); 



And, for example, a tree with edges 1 – 2 and 1 – 3 won't be a shortest path tree for vertex 3, because the distance from vertex 3 to vertex 2 in this tree equals 3, and in the original graph it is 1.

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.*;

public class source {
    private static class Edge {
        int direction, id; long w;
        Edge(int _id, int _direction, long _w) {
            id=_id; direction=_direction; w=_w;
        }
    }

    private static class Node implements Comparable<Node> {
        long distance;
        Edge edge;

        public Node(long _dist, Edge _edge) {
            distance=_dist; edge=_edge;
        }

        public int compareTo(Node n) {
            if(this.distance != n.distance) return this.distance < n.distance ? -1 : 1;
            return this.edge.w < n.edge.w? -1 : 1;
        }
    }
    private static ArrayList<Edge>[] graph;
    private static long[] dijkstra;

    public static void main(String[] args) throws IOException {
        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
        StringTokenizer st = new StringTokenizer(br.readLine());
        int n = Integer.parseInt(st.nextToken());
        int m = Integer.parseInt(st.nextToken());

        graph = new ArrayList[n];
        dijkstra = new long[n];
        for(int i=0;i<n;i++) {
            graph[i] = new ArrayList<>();
        }
        for(int i=0; i<m; i++) {
            st = new StringTokenizer(br.readLine());
            int a = Integer.parseInt(st.nextToken())-1;
            int b = Integer.parseInt(st.nextToken())-1;
            int w = Integer.parseInt(st.nextToken());
            graph[a].add(new Edge(i, b, w));
            graph[b].add(new Edge(i, a, w));
        }
        st = new StringTokenizer(br.readLine());
        int root = Integer.parseInt(st.nextToken())-1;

        Arrays.fill(dijkstra, -1);
        long total=0;

        ArrayList<Integer> result = new ArrayList<>();
        PriorityQueue<Node> pq = new PriorityQueue<>();
        // root 를 방문하기 위한 dummy 노드
        pq.add(new Node(0, new Edge(-1, root, 0)));

        while(pq.size() > 0) {
            Node node = pq.poll();
            // 노드와 연결된 엣지가 가리키는 다른 노드 (destination)
            int destination = node.edge.direction;
            // 방문 안한 노드만
            if(dijkstra[destination] != -1) continue;
            // 다익스트라. node 의 distance 에는 이전 노드까지의 거리 + 엣지의 weight 가 적혀 있을 것
            dijkstra[destination] = node.distance;
            // weight 누적
            total += node.edge.w;
            // 선택된 edge 출력을 위해 마킹
            result.add(node.edge.id);
            // 방문지에 연결된 엣지들 전부 넣음
            for(Edge e : graph[destination]) {
                pq.add(new Node(node.distance + e.w, e));
            }
            // 근데 넣고나면 우선순위 큐라, Min distance 가 먼저 나오고
            // visit 처리가 되어서 다른건 안감 (노드와 연결된 것 중 가장 짧은걸 다음번에 간다는 뜻)
        }

        System.out.println(total);
        Collections.sort(result);
        for(int edgeId : result) {
            if (edgeId >= 0) {
                System.out.print((edgeId + 1) + " ");
            }
        }
        System.out.println();
    }
}