Problem: Let's call a positive integer composite if it has at least one divisor other than 1 and itself. For example:

  * the following numbers are composite: 1024, 4, 6, 9; 
  * the following numbers are not composite: 13, 1, 2, 3, 37. 



You are given a positive integer n. Find two composite integers a,b such that a-b=n.

It can be proven that solution always exists.

Input

The input contains one integer n (1 ≤ n ≤ 10^7): the given integer.

Output

Print two composite integers a,b (2 ≤ a, b ≤ 10^9, a-b=n).

It can be proven, that solution always exists.

If there are several possible solutions, you can print any. 

Examples

Input


1


Output


9 8


Input


512


Output


4608 4096

Solution (in PYTHON3):

Solution:
from sys import stdin, stdout

def scal(typ=int):
  return typ(stdin.readline())

def vec(typ=int):
  if isinstance(typ, list):
    inp = stdin.readline().split()
    return [typ[i](inp[i]) for i in range(len(inp))]
  else:
    return list(map(typ, stdin.readline().split()))

n = scal()
if n % 2:
  print(n + 9, 9)
else:
  print(n + 4, 4)