Problem: Let's call a positive integer composite if it has at least one divisor other than 1 and itself. For example:

  * the following numbers are composite: 1024, 4, 6, 9; 
  * the following numbers are not composite: 13, 1, 2, 3, 37. 



You are given a positive integer n. Find two composite integers a,b such that a-b=n.

It can be proven that solution always exists.

Input

The input contains one integer n (1 ≤ n ≤ 10^7): the given integer.

Output

Print two composite integers a,b (2 ≤ a, b ≤ 10^9, a-b=n).

It can be proven, that solution always exists.

If there are several possible solutions, you can print any. 

Examples

Input


1


Output


9 8


Input


512


Output


4608 4096

Solution (in PYTHON3):

Solution:
def iscomposite(n):
  ans = 0
  for i in range(2, n):
    if (n%i==0):
      ans = 1
      break
    else:
      ans =0
  if (ans):
    return 1
  else:
    return 0

n = int(input())
i=4
while(i):
  if (iscomposite(i+n) and iscomposite(i)):
    print("%d %d" %(i+n, i))
    break
  i+=1