Problem: There is a polyline going through points (0, 0) – (x, x) – (2x, 0) – (3x, x) – (4x, 0) – ... - (2kx, 0) – (2kx + x, x) – .... 

We know that the polyline passes through the point (a, b). Find minimum positive value x such that it is true or determine that there is no such x.

Input

Only one line containing two positive integers a and b (1 ≤ a, b ≤ 109).

Output

Output the only line containing the answer. Your answer will be considered correct if its relative or absolute error doesn't exceed 10 - 9. If there is no such x then output  - 1 as the answer.

Examples

Input

3 1


Output

1.000000000000


Input

1 3


Output

-1


Input

4 1


Output

1.250000000000

Note

You can see following graphs for sample 1 and sample 3. 

<image> <image>

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
long long a, b;
double Get(double L, double m) {
  int k = L / (2 * m);
  if (k == 0) return -1;
  return L / (2 * k);
}
int main() {
  cin >> a >> b;
  if (b > a) {
    cout << -1 << endl;
    return 0;
  }
  double u = Get(a - b, b), v = Get(a + b, b);
  if (u == -1 && v == -1)
    cout << -1 << endl;
  else if (u == -1)
    cout << setprecision(9) << fixed << v << endl;
  else if (v == -1)
    cout << setprecision(9) << fixed << u << endl;
  else
    cout << setprecision(9) << fixed << min(u, v) << endl;
  return 0;
}