Problem: Ilya got tired of sports programming, left university and got a job in the subway. He was given the task to determine the escalator load factor. 

Let's assume that n people stand in the queue for the escalator. At each second one of the two following possibilities takes place: either the first person in the queue enters the escalator with probability p, or the first person in the queue doesn't move with probability (1 - p), paralyzed by his fear of escalators and making the whole queue wait behind him.

Formally speaking, the i-th person in the queue cannot enter the escalator until people with indices from 1 to i - 1 inclusive enter it. In one second only one person can enter the escalator. The escalator is infinite, so if a person enters it, he never leaves it, that is he will be standing on the escalator at any following second. Ilya needs to count the expected value of the number of people standing on the escalator after t seconds. 

Your task is to help him solve this complicated task.

Input

The first line of the input contains three numbers n, p, t (1 ≤ n, t ≤ 2000, 0 ≤ p ≤ 1). Numbers n and t are integers, number p is real, given with exactly two digits after the decimal point.

Output

Print a single real number — the expected number of people who will be standing on the escalator after t seconds. The absolute or relative error mustn't exceed 10 - 6.

Examples

Input

1 0.50 1


Output

0.5


Input

1 0.50 4


Output

0.9375


Input

4 0.20 2


Output

0.4

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.*;
import java.math.BigInteger;

public class Main{
    final boolean isFileIO =  false;
    BufferedReader in;
    PrintWriter out;
    StringTokenizer st = new StringTokenizer("");
    String delim = " ";

    public static void main(String[] args) throws IOException {
        Main m = new Main();
        m.initIO();
        m.solve();
        m.in.close();
        m.out.close();
    }

    public void initIO() throws IOException {
        if(!isFileIO) {
            in = new BufferedReader(new InputStreamReader(System.in));
            out = new PrintWriter(System.out);
        } else {
            in = new BufferedReader(new FileReader("input.txt"));
            out = new PrintWriter("output.txt");
        }
    }

    String nt() throws IOException {
        if(!st.hasMoreTokens()) {
            st = new StringTokenizer(in.readLine());
        }
        return st.nextToken(delim);
    }

    String rl() throws IOException {
        return in.readLine();
    }

    int ni() throws IOException {
        return Integer.parseInt(nt());
    }

    long nl() throws IOException {
        return Long.parseLong(nt());
    }

    double nd() throws IOException {
        return Double.parseDouble(nt());
    }

    class Pair {
        public long x;
        public long y;

        public Pair(long x, long y) {
            this.x = x;
            this.y = y;
        }

        public String toString() {
            return String.format("{%d, %d}", x, y);
        }
    }

    public void solve() throws IOException {
        int n, t;
        double p;
        n = ni(); p = nd(); t = ni();

        double[][] dp = new double[n + 1][t + 1];

        dp[0][0] = 1;
        for(int i = 1; i <= t; i++) {
            dp[0][i] = dp[0][i - 1] * (1 - p);
        }
        for(int i = 1; i < n; i++) {
            for(int j = 1; j <= t; j++) {
                dp[i][j] = dp[i][j - 1] * (1 - p) + dp[i - 1][j - 1] * p;
            }
        }
        for(int i = 1; i <= t; i++) {
            dp[n][i] = dp[n][i - 1] + dp[n - 1][i - 1] * p;
        }
        double ans = 0;
        for(int i = 1; i <= n; i++) {
            ans += i * dp[i][t];
        }
        out.println(ans);

    }
}

class Utils {

    public static long binpow(long a, long exp, long mod) {
        if(exp == 0) {
            return 1;
        }
        if(exp % 2 == 0) {
            long temp = binpow(a, exp / 2, mod);
            return (temp * temp) % mod;
        } else {
            return (binpow(a, exp - 1, mod) * a) % mod;
        }
    }

    public static long inv(long a, long mod) {
        return binpow(a, mod - 2, mod);
    }

    public static long addmod(long a, long b, long mod) {
        return ((a + b) % mod + mod) % mod;
    }

    public static long gcd(long a, long b) {
        if(b == 0)
            return a;
        return gcd(b, a % b);
    }

    //mul must be < 10^18
    public static long mulmod(long a, long b, long mod) {
        return (a * b + (((a * b) / mod) + 1) * mod) % mod;
    }
}