Problem: Levko loves tables that consist of n rows and n columns very much. He especially loves beautiful tables. A table is beautiful to Levko if the sum of elements in each row and column of the table equals k.

Unfortunately, he doesn't know any such table. Your task is to help him to find at least one of them. 

Input

The single line contains two integers, n and k (1 ≤ n ≤ 100, 1 ≤ k ≤ 1000).

Output

Print any beautiful table. Levko doesn't like too big numbers, so all elements of the table mustn't exceed 1000 in their absolute value.

If there are multiple suitable tables, you are allowed to print any of them.

Examples

Input

2 4


Output

1 3
3 1


Input

4 7


Output

2 1 0 4
4 0 2 1
1 3 3 0
0 3 2 2

Note

In the first sample the sum in the first row is 1 + 3 = 4, in the second row — 3 + 1 = 4, in the first column — 1 + 3 = 4 and in the second column — 3 + 1 = 4. There are other beautiful tables for this sample.

In the second sample the sum of elements in each row and each column equals 7. Besides, there are other tables that meet the statement requirements.

Solution (in JAVA):

Solution:
import java.io.IOException;
import java.io.InputStream;


public class Main {
    public static void main(String[] args) throws IOException {
        FastScanner s = new FastScanner(System.in);
        int n = s.nextInt();
        int k = s.nextInt();
        int ar[] = new int[n];

        int t = k / n;
        if (t * n == k) {
            for (int i = 0; i < n; i++) {
                for (int j = 0; j < n; j++) {
                    System.out.print(t + " ");
                }
                System.out.println();
            }
        } else if (t >= 1) {
            for (int i = 0; i < n - 1; i++) {
                ar[i] = t;
            }
            ar[n - 1] = k - (t * (n - 1));

            for (int i = 0; i < n; i++) {
                for (int j = 0; j < n; j++) {
                    System.out.print(ar[(i + j) % n] + " ");
                }
                System.out.println();
            }
        } else {
            int i = 0;
            while (k > 0 && i < n) {
                ar[i] = 1;
                i++;
                k--;
            }
            for (int p = 0; p < n; p++) {
                for (int j = 0; j < n; j++) {
                    System.out.print(ar[(p + j) % n] + " ");
                }
                System.out.println();
            }
        }

    }
}

class FastScanner {

    InputStream is;
    byte buff[] = new byte[1024];
    int currentChar = -1;
    int buffChars = 0;

    public FastScanner(InputStream inputStream) {
        is = inputStream;
    }

    public boolean hasNext() throws IOException {
        return buffChars >= 0;
    }

    public int nextChar() throws IOException {
        //if we already have that next char read, just return else input
        if (currentChar == -1 || currentChar >= buffChars) {
            currentChar = 0;
            buffChars = is.read(buff);
        }

        if (buffChars <= 0) {
            return -1;
        }

        return (char) buff[currentChar++];
    }

    public String nextString() throws IOException {
        StringBuilder bldr = new StringBuilder();
        int ch;
        while (isSpace(ch = nextChar())) ;

        do {
            bldr.append((char) ch);
        } while (!isSpace(ch = nextChar()));

        return bldr.toString();
    }

    public int nextInt() throws IOException {
        //considering ASCII files--> 8 bit chars,     unicode files has 16 bit chars (byte1 then byte2)
        int result = 0;
        int sign = 1;
        int ch;
        while (isSpace(ch = nextChar())) ;

        if (ch == '-') {
            sign = -1;
            ch = nextChar();
        }

        do {
            if (ch < '0' || ch > '9') {
                throw new NumberFormatException("Found '" + ch + "' while parsing for int.");
            }

            result *= 10;
            result += ch - '0';
        } while (!isSpace(ch = nextChar()));

        return sign * result;
    }

    public long nextLong() throws IOException {
        //considering ASCII files--> 8 bit chars,     unicode files has 16 bit chars (byte1 then byte2)
        long result = 0;
        int sign = 1;
        int ch;
        while (isSpace(ch = nextChar())) ;

        if (ch == '-') {
            sign = -1;
            ch = nextChar();
        }

        do {
            if (ch < '0' || ch > '9') {
                throw new NumberFormatException("Found '" + ch + "' while parsing for int.");
            }

            result *= 10;
            result += ch - '0';
        } while (!isSpace(ch = nextChar()));

        return sign * result;
    }

    private boolean isSpace(int ch) {
        return ch == '\n' || ch == ' ' || ch == '\t' || ch == '\r' || ch == -1;
    }

    public void close() throws IOException {
        is.close();
    }
}