Problem: Given a connected undirected graph with n vertices and an integer k, you have to either:

  * either find an independent set that has exactly ⌈k/2⌉ vertices.
  * or find a simple cycle of length at most k. 



An independent set is a set of vertices such that no two of them are connected by an edge. A simple cycle is a cycle that doesn't contain any vertex twice. 

I have a proof that for any input you can always solve at least one of these problems, but it's left as an exercise for the reader.

Input

The first line contains three integers n, m, and k (3 ≤ k ≤ n ≤ 10^5, n-1 ≤ m ≤ 2 ⋅ 10^5) — the number of vertices and edges in the graph, and the parameter k from the statement.

Each of the next m lines contains two integers u and v (1 ≤ u,v ≤ n) that mean there's an edge between vertices u and v. It's guaranteed that the graph is connected and doesn't contain any self-loops or multiple edges.

Output

If you choose to solve the first problem, then on the first line print 1, followed by a line containing ⌈k/2⌉ distinct integers not exceeding n, the vertices in the desired independent set.

If you, however, choose to solve the second problem, then on the first line print 2, followed by a line containing one integer, c, representing the length of the found cycle, followed by a line containing c distinct integers not exceeding n, the vertices in the desired cycle, in the order they appear in the cycle.

Examples

Input


4 4 3
1 2
2 3
3 4
4 1


Output


1
1 3 

Input


4 5 3
1 2
2 3
3 4
4 1
2 4


Output


2
3
2 3 4 

Input


4 6 3
1 2
2 3
3 4
4 1
1 3
2 4


Output


2
3
1 2 3 

Input


5 4 5
1 2
1 3
2 4
2 5


Output


1
1 4 5 

Note

In the first sample:

<image>

Notice that printing the independent set \{2,4\} is also OK, but printing the cycle 1-2-3-4 isn't, because its length must be at most 3.

In the second sample:

<image>

Notice that printing the independent set \{1,3\} or printing the cycle 2-1-4 is also OK.

In the third sample:

<image>

In the fourth sample:

<image>

Solution (in JAVA):

Solution:
// Main Code at the Bottom
import java.util.*;
import java.lang.*;
import java.io.*;
import java.math.BigInteger; 
public class Main {
	//Fast IO class
    static class FastReader {
        BufferedReader br; 
        StringTokenizer st; 
        public FastReader() {
        	boolean env=System.getProperty("ONLINE_JUDGE") != null;
        	if(!env) {
        		try {
					br=new BufferedReader(new FileReader("src\\input.txt"));
				} catch (FileNotFoundException e) {
					e.printStackTrace();
				}
        	}
        	else br = new BufferedReader(new InputStreamReader(System.in)); 
        } 
        String next() {
            while (st == null || !st.hasMoreElements()) {
                try {
                    st = new StringTokenizer(br.readLine()); 
                } 
                catch (IOException  e) {
                    e.printStackTrace(); 
                } 
            } 
            return st.nextToken(); 
        } 
        int nextInt() {
            return Integer.parseInt(next()); 
        } 
        long nextLong() {
            return Long.parseLong(next()); 
        } 
        double nextDouble() {
            return Double.parseDouble(next()); 
        } 
        String nextLine() {
            String str = ""; 
            try {
                str = br.readLine(); 
            } 
            catch (IOException e) {
                e.printStackTrace(); 
            } 
            return str; 
        } 
    }     
    static long MOD=1000000000+7;
    //Euclidean Algorithm
    static long gcd(long A,long B){
    	return (B==0)?A:gcd(B,A%B);
    }
    //Modular Exponentiation
    static long fastExpo(long x,long n){
        if(n==0) return 1;
        if((n&1)==0) return fastExpo((x*x)%MOD,n/2)%MOD;
        return ((x%MOD)*fastExpo((x*x)%MOD,(n-1)/2))%MOD;
    }
    //Modular Inverse
    static long inverse(long x) {
    	return fastExpo(x,MOD-2);
    }
    //Prime Number Algorithm
    static boolean isPrime(long n){
        if(n<=1) return false;
        if(n<=3) return true;
        if(n%2==0 || n%3==0) return false;
        for(int i=5;i*i<=n;i+=6) if(n%i==0 || n%(i+2)==0) return false;
        return true;
    }
    //Print array
    static void print1d(int arr[]) {
    	out.println(Arrays.toString(arr));
    }
    static void print2d(int arr[][]) {
    	for(int a[]: arr) out.println(Arrays.toString(a));
    }
    // Pair
    static class pair{
    	long x,y;
    	pair(long a,long b){
    		this.x=a;
    		this.y=b;
    	}
    	public boolean equals(Object obj) {
    		if(obj == null || obj.getClass()!= this.getClass()) return false;
            pair p = (pair) obj;
            return (this.x==p.x && this.y==p.y);
        }
    	public int hashCode() {
            return Objects.hash(x,y);
        }
    }
    static FastReader sc=new FastReader();
    static PrintWriter out=new PrintWriter(System.out);  
    //Main function(The main code starts from here)
    static int V,visited[],color[];
    static ArrayList<Integer> graph[];
    static void init(int n){
        V=n;
        visited=new int[n];
        color=new int[n];
        Arrays.fill(color, -1);
        graph=new ArrayList[V];
        for(int i=0;i<V;i++) graph[i]=new ArrayList<>();
    }
    static void addEdge(int src,int dest){
        graph[src].add(dest);
        graph[dest].add(src);
    }
    static void dfs(int s,int c) {
    	color[s]=c;
    	visited[s]=1;
    	for(Integer x: graph[s]) {
    		if(visited[x]==1) {
    			if(color[x]==color[s]) color[s]=-1;
    			continue;
    		}
    		dfs(x,1-c);
    	}
    	//out.println((s+1)+" "+c);
    }
    static void dfs2(int s,int req) {
    	if(req>0) out.print((s+1)+" ");
    	visited[s]=1;
    	for(Integer x: graph[s]) {
    		if(visited[x]==1) continue;
    		dfs2(x,req-1);
    	}
    }
    public static void main (String[] args) throws java.lang.Exception {
    	int test=1;
    	//test=sc.nextInt();
    	while(test-->0){
    		//Think before code, it won't hurt
    		int n=sc.nextInt(),m=sc.nextInt(),k=sc.nextInt();
    		init(n);
    		while(m-->0) addEdge(sc.nextInt()-1,sc.nextInt()-1);
    		dfs(0,0);
    		int req=(k+1)/2,z=0,o=0;
			for(int i=0;i<n;i++) {
				if(color[i]==0) z++;
				else if(color[i]==1) o++;
			}
			if(req<=o) {
				out.println(1);
				for(int i=0;i<n;i++) {
					if(color[i]==1 && req>0) {
						out.print((i+1)+" ");
						req--;
					}
				}
			}
			else if(req<=z) {
				out.println(1);
				for(int i=0;i<n;i++) {
					if(color[i]==0 && req>0) {
						out.print((i+1)+" ");
						req--;
					}
				}
			}
			else {
				out.println(2);
				out.println(k);
				Arrays.fill(visited, 0);
				dfs2(0,k);
			}
    		
    	}
        out.flush();
        out.close();
    }
}