Problem: You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible.

Input

Each test contains one or more test cases. The first line contains the number of test cases t (1 ≤ t ≤ 100).

The first line of each test case consists of one integer n — the number of elements in the sequence b (1 ≤ n ≤ 100).

The second line of each test case consists of n different integers b_1, …, b_n — elements of the sequence b (1 ≤ b_i ≤ 2n).

It is guaranteed that the sum of n by all test cases doesn't exceed 100.

Output

For each test case, if there is no appropriate permutation, print one number -1.

Otherwise, print 2n integers a_1, …, a_{2n} — required lexicographically minimal permutation of numbers from 1 to 2n.

Example

Input


5
1
1
2
4 1
3
4 1 3
4
2 3 4 5
5
1 5 7 2 8


Output


1 2 
-1
4 5 1 2 3 6 
-1
1 3 5 6 7 9 2 4 8 10 

Solution (in PYTHON3):

Solution:
import bisect
import sys
input=sys.stdin.readline
from collections import defaultdict as dd
t=int(input())
while t:
    n=int(input())
    l=list(map(int,input().split()))
    rem=[]
    for i in range(1,2*n+1):
        if i not in l:
            rem.append(i)
    ans=[]
    lol=0
    for i in l:
        ans.append(i)
        ind=bisect.bisect_left(rem,i)
        if(ind==len(rem)):
            lol=1
            break
        else:
            
            ans.append(rem[ind])
            rem.pop(ind)
    if(lol):
        print(-1)
    else:
        print(*ans)
    t-=1