Problem: You are given one integer number n. Find three distinct integers a, b, c such that 2 ≤ a, b, c and a ⋅ b ⋅ c = n or say that it is impossible to do it.

If there are several answers, you can print any.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of test cases.

The next n lines describe test cases. The i-th test case is given on a new line as one integer n (2 ≤ n ≤ 10^9).

Output

For each test case, print the answer on it. Print "NO" if it is impossible to represent n as a ⋅ b ⋅ c for some distinct integers a, b, c such that 2 ≤ a, b, c.

Otherwise, print "YES" and any possible such representation.

Example

Input


5
64
32
97
2
12345


Output


YES
2 4 8 
NO
NO
NO
YES
3 5 823 

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
void helper(long long int n) {
  set<int> nums;
  for (int i = 2; i * i <= n; i++) {
    if (n % i == 0 && !nums.count(i)) {
      nums.insert(i);
      n /= i;
      break;
    }
  }
  for (int i = 2; i * i <= n; i++) {
    if (n % i == 0 && !nums.count(i)) {
      nums.insert(i);
      n /= i;
      break;
    }
  }
  if (nums.size() < 2 || nums.count(n) || n <= 1) {
    cout << "NO" << endl;
  } else {
    cout << "YES" << endl;
    nums.insert(n);
    for (auto i : nums) {
      cout << i << " ";
    }
    cout << endl;
  }
}
int main() {
  int t;
  cin >> t;
  while (t--) {
    int n;
    cin >> n;
    helper(n);
  }
  return 0;
}