Problem: Given two non-negative decimal integers $a$ and $b$, calculate their AND (logical conjunction), OR (logical disjunction) and XOR (exclusive disjunction) and print them in binary representation of 32 bits.

Constraints

* $0 \leq a, b \leq 2^{32} - 1$

Input

The input is given in the following format.


$a \; b$


Output

Print results of AND, OR and XOR in a line respectively.

Example

Input

8 10


Output

00000000000000000000000000001000
00000000000000000000000000001010
00000000000000000000000000000010

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
#define rep_i(i, n) for (int i = 0; i < (n); ++i)
#define rep_ll(i, n) for (long long i = 0; i < (n); ++i)
#define r_rep_i(i, start, end) for (int i = (start); i < (end); ++i)
#define r_rep_ll(i, start, end) for (long long i = (start); i < (end); ++i)
#define debug_vi(v) copy((v).begin(), (v).end(), ostream_iterator<int>(cout, " "));
#define debug_vll(v) copy((v).begin(), (v).end(), ostream_iterator<long long>(cout, " "));
#define debug_vd(v) copy((v).begin(), (v).end(), ostream_iterator<double>(cout, " "));
#define sort_v(v) sort((v).begin(), (v).end()); //昇順
#define d_sort_vi(v) sort((v).begin(), (v).end(), greater<int>()); //降
#define d_sort_vd(v) sort((v).begin(), (v).end(), greater<double>()); //昇順
#define say(t) cout << (t) << endl;
#define sum_vi(v) accumulate((v).begin(), (v).end(), 0);
#define sum_vll(v)accumulate((v).begin(), (v).end(), 0LL);

int main(){
  long long a, b; cin >> a >> b;
  cout << (bitset<32>(a&b)) << endl;
  cout << (bitset<32>(a|b)) << endl;
  cout << (bitset<32>(a^b)) << endl;
}