Problem: Let's call a positive integer composite if it has at least one divisor other than 1 and itself. For example:

  * the following numbers are composite: 1024, 4, 6, 9; 
  * the following numbers are not composite: 13, 1, 2, 3, 37. 



You are given a positive integer n. Find two composite integers a,b such that a-b=n.

It can be proven that solution always exists.

Input

The input contains one integer n (1 ≤ n ≤ 10^7): the given integer.

Output

Print two composite integers a,b (2 ≤ a, b ≤ 10^9, a-b=n).

It can be proven, that solution always exists.

If there are several possible solutions, you can print any. 

Examples

Input


1


Output


9 8


Input


512


Output


4608 4096

Solution (in PYTHON3):

Solution:
def is_comp(n):
    c = 0

    for i in range(1, int(n ** 0.5) + 1):
        if n % i == 0:
            c += 1

            if n // i != i:
                c += 1

    return c

n = int(input())

i = n+1

while True:
    if 2 < is_comp(i) and 2 < is_comp(i-n):
        print(i, i-n)
        break

    i += 1