Problem: Let's call a string "s-palindrome" if it is symmetric about the middle of the string. For example, the string "oHo" is "s-palindrome", but the string "aa" is not. The string "aa" is not "s-palindrome", because the second half of it is not a mirror reflection of the first half.

<image> English alphabet

You are given a string s. Check if the string is "s-palindrome".

Input

The only line contains the string s (1 ≤ |s| ≤ 1000) which consists of only English letters.

Output

Print "TAK" if the string s is "s-palindrome" and "NIE" otherwise.

Examples

Input

oXoxoXo


Output

TAK


Input

bod


Output

TAK


Input

ER


Output

NIE

Solution (in PYTHON3):

Solution:
def check(string):
    first = string[:len(string)//2]
    second = string[len(string)//2:]
    second.reverse()


    for i in range(0, len(first)):
        if first[i] != second[i]:
            if first[i] == "b":
                if second[i] == "d":
                    pass
                else:
                    print("NIE")
                    return 1

            elif first[i] == "d":
                if second[i] == "b":
                    pass
                else:
                    print("NIE")
                    return 1
            elif first[i] == "p":
                if second[i] == "q":
                    pass
                else:
                    print("NIE")
                    return 1
            elif first[i] == "q":
                if second[i] == "p":
                    pass
                else:
                    print("NIE")
                    return 1
            else:
                print("NIE")
                return 1
        else:
            if first[i] in set:
                pass
            else:
                print("NIE")
                return 1

    print("TAK")
    return 0








data = input()
string = []
for letter in data:
    string.append(letter)
set = ["A", "H", "I", "M", "O",
         "o", "T", "U", "V", "v",
         "W", "w", "X", "x", "Y"]
if len(string) % 2 != 0:
    if(string[len(string)//2] in set):
        string.pop(len(string)//2)
        check(string)
    else:
        print("NIE")
else:
    check(string)