Problem: Let's call a positive integer composite if it has at least one divisor other than 1 and itself. For example:

  * the following numbers are composite: 1024, 4, 6, 9; 
  * the following numbers are not composite: 13, 1, 2, 3, 37. 



You are given a positive integer n. Find two composite integers a,b such that a-b=n.

It can be proven that solution always exists.

Input

The input contains one integer n (1 ≤ n ≤ 10^7): the given integer.

Output

Print two composite integers a,b (2 ≤ a, b ≤ 10^9, a-b=n).

It can be proven, that solution always exists.

If there are several possible solutions, you can print any. 

Examples

Input


1


Output


9 8


Input


512


Output


4608 4096

Solution (in PYTHON3):

Solution:
n = int(input())
for a in range(n,10**9 +1):
    c1=0
    c2=0
    b = a-n
    for i in range(2,a):
        if(a%i ==0):
            c1=1
            break
    if(c1==1):
        for i in range(2,b):
            if(b%i ==0):
                c2=1
                break
    if(c1==1 and c2==1):
        print(a,b)
        break