Problem: Asterix, Obelix and their temporary buddies Suffix and Prefix has finally found the Harmony temple. However, its doors were firmly locked and even Obelix had no luck opening them.

A little later they found a string s, carved on a rock below the temple's gates. Asterix supposed that that's the password that opens the temple and read the string aloud. However, nothing happened. Then Asterix supposed that a password is some substring t of the string s.

Prefix supposed that the substring t is the beginning of the string s; Suffix supposed that the substring t should be the end of the string s; and Obelix supposed that t should be located somewhere inside the string s, that is, t is neither its beginning, nor its end.

Asterix chose the substring t so as to please all his companions. Besides, from all acceptable variants Asterix chose the longest one (as Asterix loves long strings). When Asterix read the substring t aloud, the temple doors opened. 

You know the string s. Find the substring t or determine that such substring does not exist and all that's been written above is just a nice legend.

Input

You are given the string s whose length can vary from 1 to 106 (inclusive), consisting of small Latin letters.

Output

Print the string t. If a suitable t string does not exist, then print "Just a legend" without the quotes.

Examples

Input

fixprefixsuffix


Output

fix

Input

abcdabc


Output

Just a legend

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
vector<int> prefixFunction(const string& P) {
  int n = P.size(), k = 0;
  vector<int> v(n + 1);
  v[1] = 0;
  for (int i = 2; i < n; ++i) {
    while (k > 0 && P[k + 1] != P[i]) k = v[k];
    if (P[k + 1] == P[i]) ++k;
    v[i] = k;
  }
  return v;
}
int KMP(const string& P, int lim, const vector<int>& v) {
  int n = P.size();
  for (int i = 0; i < n - 1; ++i)
    if (v[i] == lim) return lim;
  return v[lim];
}
int main() {
  string s;
  int lim;
  while (cin >> s) {
    s = '`' + s;
    vector<int> v = prefixFunction(s);
    lim = v[s.size() - 1];
    if (lim == 0) {
      cout << "Just a legend\n";
      continue;
    }
    lim = KMP(s, lim, v);
    if (lim == 0)
      cout << "Just a legend\n";
    else {
      string ans = s.substr(1, lim);
      cout << ans << '\n';
    }
  }
  return 0;
}