Problem: JATC loves Banh-mi (a Vietnamese food). His affection for Banh-mi is so much that he always has it for breakfast. This morning, as usual, he buys a Banh-mi and decides to enjoy it in a special way.

First, he splits the Banh-mi into n parts, places them on a row and numbers them from 1 through n. For each part i, he defines the deliciousness of the part as x_i ∈ \{0, 1\}. JATC's going to eat those parts one by one. At each step, he chooses arbitrary remaining part and eats it. Suppose that part is the i-th part then his enjoyment of the Banh-mi will increase by x_i and the deliciousness of all the remaining parts will also increase by x_i. The initial enjoyment of JATC is equal to 0.

For example, suppose the deliciousness of 3 parts are [0, 1, 0]. If JATC eats the second part then his enjoyment will become 1 and the deliciousness of remaining parts will become [1, \\_, 1]. Next, if he eats the first part then his enjoyment will become 2 and the remaining parts will become [\\_, \\_, 2]. After eating the last part, JATC's enjoyment will become 4.

However, JATC doesn't want to eat all the parts but to save some for later. He gives you q queries, each of them consisting of two integers l_i and r_i. For each query, you have to let him know what is the maximum enjoyment he can get if he eats all the parts with indices in the range [l_i, r_i] in some order.

All the queries are independent of each other. Since the answer to the query could be very large, print it modulo 10^9+7.

Input

The first line contains two integers n and q (1 ≤ n, q ≤ 100 000).

The second line contains a string of n characters, each character is either '0' or '1'. The i-th character defines the deliciousness of the i-th part.

Each of the following q lines contains two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ n) — the segment of the corresponding query.

Output

Print q lines, where i-th of them contains a single integer — the answer to the i-th query modulo 10^9 + 7.

Examples

Input

4 2
1011
1 4
3 4


Output

14
3


Input

3 2
111
1 2
3 3


Output

3
1

Note

In the first example: 

  * For query 1: One of the best ways for JATC to eats those parts is in this order: 1, 4, 3, 2. 
  * For query 2: Both 3, 4 and 4, 3 ordering give the same answer. 



In the second example, any order of eating parts leads to the same answer.

Solution (in JAVA):

Solution:
import java.io.BufferedReader;
import java.io.DataInputStream;
import java.io.FileInputStream;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.io.StringWriter;
import java.util.Arrays;
import java.util.Comparator;
import java.util.StringTokenizer;
import java.io.InputStream ;
import java.util.InputMismatchException;
import java.util.ArrayList;


public class Main {
    public static void main(String[] args) throws IOException {
        PrintWriter out = new PrintWriter(System.out);
        //Scanner sc = new Scanner();
        Reader in = new Reader();
        Main solver = new Main();
        solver.solve(out, in);
        out.flush();
        out.close();

    }
    
    static int maxn = (int)1e5+1;
    static int mod = (int)1e9+7;
    
    void solve(PrintWriter out, Reader in) throws IOException{   
        int n = in.nextInt();
        int q = in.nextInt();
        
        long[] add =new long[n+1];
        long[] pow = new long[maxn];
        pow[1]=1;
        for(int i=2;i<=n;i++) pow[i] = (pow[i-1]*2)%mod;
        for(int i=1;i<=n;i++) add[i] = (pow[i] +add[i-1])%mod;
        
        String str = in.next();
        int[] arr = new int[n];
        for(int i=0 ;i<n;i++){
            arr[i] = str.charAt(i)-'0';
        }
        int[] pre = new int[n];
        pre[0]=arr[0];
        for(int i=1;i<n;i++) pre[i] = arr[i]+pre[i-1];
        
        long ad[] = new long[maxn];
        for(int i=1;i<maxn;i++){
                ad[i] = (ad[i-1]+pow[i])%mod;
        }
        
        
        int l,r,size;
        int cnt1,cnt2;
        long ans=0L;
        for(int i=0 ;i<q ;i++){
            l = in.nextInt()-1;
            r = in.nextInt()-1;
            ans=0L;
            
            if(l==0) size = pre[r];
            else size = pre[r]-pre[l-1];
            int d = size;
            
            ans+=ad[size];
            /*long temp=0;
            for(int j=size;j>=1;j--){
                ans = (ans+pow[size-j+1])%mod;
            }*/
            
            size = r-l+1-size;
            long init = add[d];
            //out.println(init*power(2,size));
            
            out.println((ans-((init*(1-power(2L,size)))%mod)+mod)%mod);
        }
        
        
        
        
            
    }
    
    static long power(long x,  int y) 
{ 
    long res = 1L;  
    if(y==-1) return 0L;
    while (y > 0) 
    { 
        // If y is odd, multiply x with result 
        if ((y & 1)==1) 
            res = (res*x)%mod; 
   
        
        y = y>>1; 
        x = (x*x)%mod;  
    } 
    return res; 
}
    
    
    static class Reader {
 
        private InputStream mIs;
        private byte[] buf = new byte[1024];
        private int curChar;
        private int numChars;
     
        public Reader() {
            this(System.in);
        }
     
        public Reader(InputStream is) {
            mIs = is;
        }
     
        public int read() {
            if (numChars == -1) {
                throw new InputMismatchException();
        
        }
            if (curChar >= numChars) {
                curChar = 0;
                try {
                    numChars = mIs.read(buf);
                } catch (IOException e) {
                    throw new InputMismatchException();
                }
                if (numChars <= 0) {
                    return -1;
                }
            }
            return buf[curChar++];
        }
     
        public String nextLine() {
            int c = read();
            while (isSpaceChar(c)) {
                c = read();
            }
            StringBuilder res = new StringBuilder();
            do {
                res.appendCodePoint(c);
                c = read();
            } while (!isEndOfLine(c));
            return res.toString();
        }
     
        public String next() {
            int c = read();
            while (isSpaceChar(c)) {
                c = read();
            }
            StringBuilder res = new StringBuilder();
            do {
                res.appendCodePoint(c);
                c = read();
            } while (!isSpaceChar(c));
            return res.toString();
        }
     
        public long nextLong() {
            int c = read();
            while (isSpaceChar(c)) {
                c = read();
            }
            int sgn = 1;
            if (c == '-') {
                sgn = -1;
                c = read();
            }
            long res = 0;
            do {
                if (c < '0' || c > '9') {
                    throw new InputMismatchException();
                }
                res *= 10;
                res += c - '0';
                c = read();
            } while (!isSpaceChar(c));
            return res * sgn;
        }
     
        public int nextInt() {
            int c = read();
            while (isSpaceChar(c)) {
                c = read();
            }
            int sgn = 1;
            if (c == '-') {
                sgn = -1;
                c = read();
            }
            int res = 0;
            do {
                if (c < '0' || c > '9') {
                    throw new InputMismatchException();
                }
                res *= 10;
                res += c - '0';
                c = read();
            } while (!isSpaceChar(c));
            return res * sgn;
        }
     
        public boolean isSpaceChar(int c) {
            return c == ' ' || c == '\n' || c == '\r' || c == '\t' || c == -1;
        }
     
        public boolean isEndOfLine(int c) {
            return c == '\n' || c == '\r' || c == -1;
        }
 
    }
}