Problem: Write a program which reads a sequence of integers $A = \\{a_0, a_1, ..., a_{n-1}\\}$ and reverse specified elements by a list of the following operation:

* reverse($b, e$): reverse the order of $a_b, a_{b+1}, ..., a_{e-1}$

Constraints

* $1 \leq n \leq 1,000$
* $-1,000,000,000 \leq a_i \leq 1,000,000,000$
* $1 \leq q \leq 1,000$
* $0 \leq b < e \leq n$

Input

The input is given in the following format.


$n$
$a_0 \; a_1 \; ...,\; a_{n-1}$
$q$
$b_1 \; e_1$
$b_2 \; e_2$
:
$b_{q} \; b_{q}$


In the first line, $n$ (the number of elements in $A$) is given. In the second line, $a_i$ (each element in $A$) are given. In the third line, the number of queries $q$ is given and each query is given by two integers $b_i \; e_i$ in the following $q$ lines.

Output

Print all elements of $A$ in a line after performing the given operations. Put a single space character between adjacency elements and a newline at the end of the last element.

Example

Input

8
1 2 3 4 5 6 7 8
2
1 6
3 8


Output

1 6 5 8 7 2 3 4

Solution (in CPP):

Solution:
#include <cstdio>
#include <utility>
#include <vector>
#include <algorithm>
using namespace std;

#define gcu getchar_unlocked
#define pcu putchar_unlocked
#define _il inline
#define _in _il int in
#define _sc _il bool scan
_in(int c){int n=0;bool m=false;if(c=='-')m=true,c=gcu();
	do{n=10*n+(c-'0'),c=gcu();}while(c>='0');return m?-n:n;} //&&c<='9'
_in() {return in(gcu());}
_sc(int &n){int c=gcu();return c==EOF?false:(n=in(c),true);}
_sc(char &c){c=gcu();gcu();return c!=EOF;}
//_sc(string &s){int c;s="";
//	for(;;){c=gcu();if(c=='\n'||c==' ')return true;else if(c==EOF)return false;s+=c;}}
template <typename H,typename... T> _sc(H &h, T&&... t){return scan(h)&&scan(t...);}
#define _vo _il void out
#define _vl _il void outl
template <typename T>
_vo(T n){static char buf[20];char *p=buf;
	if(n<0)pcu('-'),n*=-1;if(!n)*p++='0';else while(n)*p++=n%10+'0',n/=10;
	while (p!=buf)pcu(*--p);}
_vo(const char *s){while(*s)pcu(*s++);}
_vo(char c){pcu(c);}
//_vo(string &s){for (char c: s) pcu(c);}
template <typename H,typename... T> _vo(H&& h, T&&... t){out(h);out(move(t)...);}
template <typename T> _vo(vector<T> &v){for(T &x:v)out(&x == &v[0]?"":" "),out(x);out('\n');}
_vl(){out('\n');}
template <typename... T> _vl(T&&... t){out(move(t)...);outl();}

int main() {
	vector<int> v(in());
	for (int &x: v)
		x = in();
	auto s = v.begin();
	for (int q = in(); q; q--) {
		int b = in();
		reverse(s + b, s + in());
	}
	out(v);
}