Problem: Asterix, Obelix and their temporary buddies Suffix and Prefix has finally found the Harmony temple. However, its doors were firmly locked and even Obelix had no luck opening them.

A little later they found a string s, carved on a rock below the temple's gates. Asterix supposed that that's the password that opens the temple and read the string aloud. However, nothing happened. Then Asterix supposed that a password is some substring t of the string s.

Prefix supposed that the substring t is the beginning of the string s; Suffix supposed that the substring t should be the end of the string s; and Obelix supposed that t should be located somewhere inside the string s, that is, t is neither its beginning, nor its end.

Asterix chose the substring t so as to please all his companions. Besides, from all acceptable variants Asterix chose the longest one (as Asterix loves long strings). When Asterix read the substring t aloud, the temple doors opened. 

You know the string s. Find the substring t or determine that such substring does not exist and all that's been written above is just a nice legend.

Input

You are given the string s whose length can vary from 1 to 106 (inclusive), consisting of small Latin letters.

Output

Print the string t. If a suitable t string does not exist, then print "Just a legend" without the quotes.

Examples

Input

fixprefixsuffix


Output

fix

Input

abcdabc


Output

Just a legend

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int main() {
  char *s = new char[1 << 20];
  int *t = new int[1 << 20];
  int n = 0;
  cin >> s;
  while (s[n]) n++;
  int k = -1;
  t[0] = -1;
  for (int i = 1; i < n; i++) {
    char si = s[i];
    while (k != -1 && s[k + 1] != si) k = t[k];
    if (s[k + 1] == si) k++;
    t[i] = k;
  }
  if (t[n - 1] == -1) {
    cout << "Just a legend" << endl;
    return 0;
  }
  k = 0;
  for (int i = 1; i < n - 1; i++)
    if (t[i] == t[n - 1]) k = 1;
  if (!k) t[n - 1] = t[t[n - 1]];
  if (t[n - 1] == -1) {
    cout << "Just a legend" << endl;
    return 0;
  }
  s[t[n - 1] + 1] = 0;
  cout << s << endl;
  delete[] t;
  delete[] s;
  return (0);
}