Problem: Asterix, Obelix and their temporary buddies Suffix and Prefix has finally found the Harmony temple. However, its doors were firmly locked and even Obelix had no luck opening them.

A little later they found a string s, carved on a rock below the temple's gates. Asterix supposed that that's the password that opens the temple and read the string aloud. However, nothing happened. Then Asterix supposed that a password is some substring t of the string s.

Prefix supposed that the substring t is the beginning of the string s; Suffix supposed that the substring t should be the end of the string s; and Obelix supposed that t should be located somewhere inside the string s, that is, t is neither its beginning, nor its end.

Asterix chose the substring t so as to please all his companions. Besides, from all acceptable variants Asterix chose the longest one (as Asterix loves long strings). When Asterix read the substring t aloud, the temple doors opened. 

You know the string s. Find the substring t or determine that such substring does not exist and all that's been written above is just a nice legend.

Input

You are given the string s whose length can vary from 1 to 106 (inclusive), consisting of small Latin letters.

Output

Print the string t. If a suitable t string does not exist, then print "Just a legend" without the quotes.

Examples

Input

fixprefixsuffix


Output

fix

Input

abcdabc


Output

Just a legend

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
vector<int> pfun(string& s) {
  int j, n = (int)s.size();
  vector<int> p(n, 0);
  for (int i = 1; i <= n - 1; i++) {
    j = p[i - 1];
    while ((j > 0) && (s[i] != s[j])) j = p[j - 1];
    if (s[i] == s[j]) p[i] = j + 1;
  }
  return p;
}
bool used[1000005];
class Solution {
 public:
  void solve(std::istream& in, std::ostream& out) {
    string s;
    in >> s;
    vector<int> p = pfun(s);
    int n = (int)s.size();
    for (int i = 0; i <= n - 2; i++) {
      used[p[i]] = true;
    }
    int x = p[n - 1];
    while (x != 0) {
      if (used[x]) break;
      x = p[x - 1];
    }
    if (x == 0)
      out << "Just a legend" << '\n';
    else {
      out << s.substr(0, x) << '\n';
    }
  }
};
void solve(std::istream& in, std::ostream& out) {
  out << std::setprecision(12);
  Solution solution;
  solution.solve(in, out);
}
int main() {
  ios_base::sync_with_stdio(0);
  cin.tie(0);
  istream& in = cin;
  ostream& out = cout;
  solve(in, out);
  return 0;
}