Problem: Given a connected undirected graph with n vertices and an integer k, you have to either:

  * either find an independent set that has exactly ⌈k/2⌉ vertices.
  * or find a simple cycle of length at most k. 



An independent set is a set of vertices such that no two of them are connected by an edge. A simple cycle is a cycle that doesn't contain any vertex twice. 

I have a proof that for any input you can always solve at least one of these problems, but it's left as an exercise for the reader.

Input

The first line contains three integers n, m, and k (3 ≤ k ≤ n ≤ 10^5, n-1 ≤ m ≤ 2 ⋅ 10^5) — the number of vertices and edges in the graph, and the parameter k from the statement.

Each of the next m lines contains two integers u and v (1 ≤ u,v ≤ n) that mean there's an edge between vertices u and v. It's guaranteed that the graph is connected and doesn't contain any self-loops or multiple edges.

Output

If you choose to solve the first problem, then on the first line print 1, followed by a line containing ⌈k/2⌉ distinct integers not exceeding n, the vertices in the desired independent set.

If you, however, choose to solve the second problem, then on the first line print 2, followed by a line containing one integer, c, representing the length of the found cycle, followed by a line containing c distinct integers not exceeding n, the vertices in the desired cycle, in the order they appear in the cycle.

Examples

Input


4 4 3
1 2
2 3
3 4
4 1


Output


1
1 3 

Input


4 5 3
1 2
2 3
3 4
4 1
2 4


Output


2
3
2 3 4 

Input


4 6 3
1 2
2 3
3 4
4 1
1 3
2 4


Output


2
3
1 2 3 

Input


5 4 5
1 2
1 3
2 4
2 5


Output


1
1 4 5 

Note

In the first sample:

<image>

Notice that printing the independent set \{2,4\} is also OK, but printing the cycle 1-2-3-4 isn't, because its length must be at most 3.

In the second sample:

<image>

Notice that printing the independent set \{1,3\} or printing the cycle 2-1-4 is also OK.

In the third sample:

<image>

In the fourth sample:

<image>

Solution (in JAVA):

Solution:
import java.util.*;
import java.lang.*;
import java.io.*;

public class Solution {
    static int N = 100005;
    static Map<Integer, List<Integer>> map = new HashMap<>();
    static List<Integer> list = new ArrayList<>();
    static List<Integer> ans = new ArrayList<>();
    static int[] distance = new int[N];
    static boolean[] visited = new boolean[N];
    static int n, m, k;
    static boolean done = false;
    public static void main(String[] args) throws java.lang.Exception {
        out = new PrintWriter(new BufferedOutputStream(System.out));
        sc = new FastReader();
        int test = 1;
        for (int t = 0; t < test; t++) {
            solve();
        }
        out.close();
    }

    private static void solve() {
        n = sc.nextInt();
        m = sc.nextInt();
        k = sc.nextInt();
        for (int i = 0; i <= n; i++) {
            map.put(i, new ArrayList<>());
        }
        for (int i = 0; i < m; i++) {
            int u = sc.nextInt();
            int v = sc.nextInt();
            map.get(u).add(v);
            map.get(v).add(u);
        }
        dfs(1);
        if (done) {
            return;
        }
        out.println(1);
        for (int i = 0; i < k - k / 2; i++) {
            out.print(ans.get(i) + " ");
        }
        out.println();
    }

    private static void dfs(int node) {
        if (done) {
            return;
        }
        list.add(node);
        distance[node] = list.size();
        for (int adj : map.get(node)) {
            if (distance[adj] == 0) {
                dfs(adj);
            }else if (!done && distance[node] - distance[adj] + 1 <= k && distance[node] - distance[adj] + 1 > 2) {
                // found a cycle of length <= k
                out.println(2);
                out.println(distance[node] - distance[adj] + 1);
                for (int i = distance[adj]; i <= distance[node]; i++) {
                    out.print(list.get(i - 1)+ " ");
                }
                out.println();
                done = true;
                return;
            }
        }
        if (!visited[node]) {
            ans.add(node);
            visited[node] = true;
            // mark its adjacents visited, independent set [no two of them are connected by an edge]
            for (int adj : map.get(node)) {
                visited[adj] = true;
            }
        }
        list.remove(list.size() - 1);
    }

    public static FastReader sc;
    public static PrintWriter out;
    static class FastReader
    {
        BufferedReader br;
        StringTokenizer st;

        public FastReader()
        {
            br = new BufferedReader(new
                    InputStreamReader(System.in));
        }

        String next()
        {
            while (st == null || !st.hasMoreElements())
            {
                try
                {
                    st = new StringTokenizer(br.readLine());
                }
                catch (IOException  e)
                {
                    e.printStackTrace();
                }
            }
            return st.nextToken();
        }

        int nextInt()
        {
            return Integer.parseInt(next());
        }

        long nextLong()
        {
            return Long.parseLong(next());
        }

        double nextDouble()
        {
            return Double.parseDouble(next());
        }

        String nextLine()
        {
            String str = "";
            try
            {
                str = br.readLine();
            }
            catch (IOException e)
            {
                e.printStackTrace();
            }
            return str;
        }
    }
}