Problem: Let's call a positive integer composite if it has at least one divisor other than 1 and itself. For example:

  * the following numbers are composite: 1024, 4, 6, 9; 
  * the following numbers are not composite: 13, 1, 2, 3, 37. 



You are given a positive integer n. Find two composite integers a,b such that a-b=n.

It can be proven that solution always exists.

Input

The input contains one integer n (1 ≤ n ≤ 10^7): the given integer.

Output

Print two composite integers a,b (2 ≤ a, b ≤ 10^9, a-b=n).

It can be proven, that solution always exists.

If there are several possible solutions, you can print any. 

Examples

Input


1


Output


9 8


Input


512


Output


4608 4096

Solution (in PYTHON3):

Solution:
#import pysnooper
#import numpy
#import os,re,sys,operator
#from collections import Counter,deque
#from operator import itemgetter,mul
#from itertools import accumulate#,combinations,groupby,combinations_with_replacement,permutations
from sys import stdin,setrecursionlimit
#from bisect import bisect_left,bisect_right
#from copy import deepcopy
#import heapq
#import math
#import string
#from time import time
#from functools import lru_cache,reduce
#from math import factorial
#import sys

setrecursionlimit(10**6)
input=stdin.readline

n=int(input().rstrip())
if n%2==0:
    print(n+4,4)
else:
    print(n+9,9)