Problem: Imagine that you are in a building that has exactly n floors. You can move between the floors in a lift. Let's number the floors from bottom to top with integers from 1 to n. Now you're on the floor number a. You are very bored, so you want to take the lift. Floor number b has a secret lab, the entry is forbidden. However, you already are in the mood and decide to make k consecutive trips in the lift.

Let us suppose that at the moment you are on the floor number x (initially, you were on floor a). For another trip between floors you choose some floor with number y (y ≠ x) and the lift travels to this floor. As you cannot visit floor b with the secret lab, you decided that the distance from the current floor x to the chosen y must be strictly less than the distance from the current floor x to floor b with the secret lab. Formally, it means that the following inequation must fulfill: |x - y| < |x - b|. After the lift successfully transports you to floor y, you write down number y in your notepad.

Your task is to find the number of distinct number sequences that you could have written in the notebook as the result of k trips in the lift. As the sought number of trips can be rather large, find the remainder after dividing the number by 1000000007 (109 + 7).

Input

The first line of the input contains four space-separated integers n, a, b, k (2 ≤ n ≤ 5000, 1 ≤ k ≤ 5000, 1 ≤ a, b ≤ n, a ≠ b).

Output

Print a single integer — the remainder after dividing the sought number of sequences by 1000000007 (109 + 7).

Examples

Input

5 2 4 1


Output

2


Input

5 2 4 2


Output

2


Input

5 3 4 1


Output

0

Note

Two sequences p1, p2, ..., pk and q1, q2, ..., qk are distinct, if there is such integer j (1 ≤ j ≤ k), that pj ≠ qj.

Notes to the samples:

  1. In the first sample after the first trip you are either on floor 1, or on floor 3, because |1 - 2| < |2 - 4| and |3 - 2| < |2 - 4|. 
  2. In the second sample there are two possible sequences: (1, 2); (1, 3). You cannot choose floor 3 for the first trip because in this case no floor can be the floor for the second trip. 
  3. In the third sample there are no sought sequences, because you cannot choose the floor for the first trip. 

Solution (in PYTHON):

Solution:
from sys import stdin, stdout
from collections import Counter, defaultdict
from itertools import permutations, combinations
raw_input = stdin.readline
pr = stdout.write


def in_num():
    return int(raw_input())


def in_arr():
    return map(int,raw_input().split())


def pr_num(n):
    stdout.write(str(n)+'\n')


def pr_arr(arr):
    pr(' '.join(map(str,arr))+'\n')

# fast read function for total integer input

def inp():
    # this function returns whole input of
    # space/line seperated integers
    # Use Ctrl+D to flush stdin.
    return map(int,stdin.read().split())

range = xrange # not for python 3.0+
mod=10**9+7
n,a,b,k=in_arr()
dp=[[0 for i in range(n+1)] for j in range(k+1)]
dp[0][a-1]=1
dp[0][a]=(-1)%mod
b-=1
for i in range(k):
    temp=0
    for j in range(n+1):
        temp=(temp+dp[i][j])%mod
        
        if i and int(abs(b-j))>1:
            temp-=dp[i-1][j]
            temp%=mod
        dp[i][j]=temp
        if j<n:
            x=int(abs(b-j))
            x-=1
            if x<=0:
                continue
            dp[i+1][max(0,j-x)]=(dp[i+1][max(0,j-x)]+temp)%mod
            dp[i+1][min(n,j+x+1)]=(dp[i+1][min(n,j+x+1)]-temp)%mod
            #dp[i+1][j]=(dp[i+1][j]-1)%mod
            #dp[i+1][j+1]=(dp[i+1][j+1]+1)%mod
        if i and int(abs(b-j))>1:
            temp+=dp[i-1][j]
            temp%=mod

ans=0
temp=0
for i in range(n):
    temp+=dp[k][i]
    temp%=mod
    if int(abs(i-b))>1:
        temp-=dp[k-1][i]
        temp%=mod
    ans+=temp
    ans%=mod
    
    if int(abs(i-b))>1:
        temp+=dp[k-1][i]
        temp%=mod
pr_num(ans)