Problem: Write a program which reads a sequence of integers $A = \\{a_0, a_1, ..., a_{n-1}\\}$ and reverse specified elements by a list of the following operation:

* reverse($b, e$): reverse the order of $a_b, a_{b+1}, ..., a_{e-1}$

Constraints

* $1 \leq n \leq 1,000$
* $-1,000,000,000 \leq a_i \leq 1,000,000,000$
* $1 \leq q \leq 1,000$
* $0 \leq b < e \leq n$

Input

The input is given in the following format.


$n$
$a_0 \; a_1 \; ...,\; a_{n-1}$
$q$
$b_1 \; e_1$
$b_2 \; e_2$
:
$b_{q} \; b_{q}$


In the first line, $n$ (the number of elements in $A$) is given. In the second line, $a_i$ (each element in $A$) are given. In the third line, the number of queries $q$ is given and each query is given by two integers $b_i \; e_i$ in the following $q$ lines.

Output

Print all elements of $A$ in a line after performing the given operations. Put a single space character between adjacency elements and a newline at the end of the last element.

Example

Input

8
1 2 3 4 5 6 7 8
2
1 6
3 8


Output

1 6 5 8 7 2 3 4

Solution (in CPP):

Solution:
#include <algorithm>
#include <iostream>
#include <vector>

int main() {
    int n;
    std::cin >> n;

    std::vector<int> vec{};
    for (int i = 0; i < n; ++i) {
        int a;
        std::cin >> a;
        vec.push_back(a);
    }

    int q;
    std::cin >> q;

    for (int j = 0; j < q; ++j) {
        int b, e;
        std::cin >> b >> e;
        std::reverse(vec.begin() + b, vec.begin() + e);
    }

    for (auto iter = vec.begin(); iter != vec.end(); ++iter) {
        int member = *iter;
        std::cout << member;
        if (iter != vec.end() - 1) std::cout << ' ';
    }
    std::cout << std::endl;
}