Problem: Asterix, Obelix and their temporary buddies Suffix and Prefix has finally found the Harmony temple. However, its doors were firmly locked and even Obelix had no luck opening them.

A little later they found a string s, carved on a rock below the temple's gates. Asterix supposed that that's the password that opens the temple and read the string aloud. However, nothing happened. Then Asterix supposed that a password is some substring t of the string s.

Prefix supposed that the substring t is the beginning of the string s; Suffix supposed that the substring t should be the end of the string s; and Obelix supposed that t should be located somewhere inside the string s, that is, t is neither its beginning, nor its end.

Asterix chose the substring t so as to please all his companions. Besides, from all acceptable variants Asterix chose the longest one (as Asterix loves long strings). When Asterix read the substring t aloud, the temple doors opened. 

You know the string s. Find the substring t or determine that such substring does not exist and all that's been written above is just a nice legend.

Input

You are given the string s whose length can vary from 1 to 106 (inclusive), consisting of small Latin letters.

Output

Print the string t. If a suitable t string does not exist, then print "Just a legend" without the quotes.

Examples

Input

fixprefixsuffix


Output

fix

Input

abcdabc


Output

Just a legend

Solution (in PYTHON3):

Solution:
def pf(txt,m,lps):
	l = 0
	lps[0] = 0
	i = 1
	while i<m:
		if txt[i]==txt[l]:
			l+=1
			lps[i] = l
			i += 1
		else:
			if l!=0:
				l = lps[l-1]
			else:
				lps[i] = 0
				i += 1

s = input()
_len = len(s)
if _len==1 or _len==2:
	print("Just a legend")
	exit(0)
lps = [0]*_len
pf(s,_len,lps)
val = lps[-1]
if val==0:
	print("Just a legend")
elif val in lps[:-1]:
	print(s[:val])
elif lps[val-1]==0:
	print("Just a legend")
elif lps[val-1]:
	print(s[:lps[val-1]])
else:
	print("Just a legend")