Problem: Let's call a positive integer composite if it has at least one divisor other than 1 and itself. For example:

  * the following numbers are composite: 1024, 4, 6, 9; 
  * the following numbers are not composite: 13, 1, 2, 3, 37. 



You are given a positive integer n. Find two composite integers a,b such that a-b=n.

It can be proven that solution always exists.

Input

The input contains one integer n (1 ≤ n ≤ 10^7): the given integer.

Output

Print two composite integers a,b (2 ≤ a, b ≤ 10^9, a-b=n).

It can be proven, that solution always exists.

If there are several possible solutions, you can print any. 

Examples

Input


1


Output


9 8


Input


512


Output


4608 4096

Solution (in JAVA):

Solution:
import java.util.*;
import java.io.*;
public class Main {
    public static void main ( String args[] ) {
      FastReader sc = new FastReader();
      PrintWriter out = new PrintWriter(System.out);
      int a = sc.nextInt();  
    	  if (a == 1 ) {
    		  System.out.println(9+" "+ 8);}
    		  else {
    			  System.out.println(3*a + " " + 2*a); 
    	  }
    	  }
    static class FastReader 
	{ 
		BufferedReader br; 
		StringTokenizer st; 
		
		public FastReader() 
		{ 
			br = new BufferedReader(new
					InputStreamReader(System.in)); 
		} 
		
		String next() 
		{ 
			while (st == null || !st.hasMoreElements()) 
			{ 
				try
				{ 
					st = new StringTokenizer(br.readLine()); 
				} 
				catch (IOException  e) 
				{ 
					e.printStackTrace(); 
				} 
			} 
			return st.nextToken(); 
		} 
		
		int nextInt() 
		{ 
			return Integer.parseInt(next()); 
		} 
		
		long nextLong() 
		{ 
			return Long.parseLong(next()); 
		} 
		
		double nextDouble() 
		{ 
			return Double.parseDouble(next()); 
		} 
		
		String nextLine() 
		{ 
			String str = ""; 
			try
			{ 
				str = br.readLine(); 
			} 
			catch (IOException e) 
			{ 
				e.printStackTrace(); 
			} 
			return str; 
		}
}
}