Problem: Let's call a positive integer composite if it has at least one divisor other than 1 and itself. For example:

  * the following numbers are composite: 1024, 4, 6, 9; 
  * the following numbers are not composite: 13, 1, 2, 3, 37. 



You are given a positive integer n. Find two composite integers a,b such that a-b=n.

It can be proven that solution always exists.

Input

The input contains one integer n (1 ≤ n ≤ 10^7): the given integer.

Output

Print two composite integers a,b (2 ≤ a, b ≤ 10^9, a-b=n).

It can be proven, that solution always exists.

If there are several possible solutions, you can print any. 

Examples

Input


1


Output


9 8


Input


512


Output


4608 4096

Solution (in PYTHON3):

Solution:
import sys
from random import choice,randint
 
# sys.setrecursionlimit(10**7)
# inf = 10**20
# eps = 1.0 / 10**10
# mod = 10**9+7
# dd = [(-1,0),(0,1),(1,0),(0,-1)]
# ddn = [(-1,0),(-1,1),(0,1),(1,1),(1,0),(1,-1),(0,-1),(-1,-1)]
 
def MI(): return map(int, sys.stdin.readline().strip().split())
def LI(): return list(map(int, sys.stdin.readline().strip().split()))
def LLI(): return [list(map(int, l.split())) for l in sys.stdin.readlines().strip()]
def LI_(): return [int(x)-1 for x in sys.stdin.readline().strip().split()]
def LF(): return [float(x) for x in sys.stdin.readline().strip().split()]
def LS(): return sys.stdin.readline().strip().split()
def I(): return int(sys.stdin.readline().strip())
def F(): return float(sys.stdin.readline().strip())
def S(): return sys.stdin.readline().strip()
def pf(s): return print(s, flush=True)
def pe(s): return print(str(s), file=sys.stderr)
def JA(a, sep): return sep.join(map(str, a))
def JAA(a, s, t): return s.join(t.join(map(str, b)) for b in a)

inp=sys.stdin.readline
out=sys.stdout.write

def main():
    n = I()
    print(n*9,n*8)

if __name__ == "__main__":
    main()