Problem: <image>

William is a huge fan of planning ahead. That is why he starts his morning routine by creating a nested list of upcoming errands.

A valid nested list is any list which can be created from a list with one item "1" by applying some operations. Each operation inserts a new item into the list, on a new line, just after one of existing items a_1  .  a_2  .  a_3  .   ⋅⋅⋅   .\,a_k and can be one of two types: 

  1. Add an item a_1  .  a_2  .  a_3  .  ⋅⋅⋅  .  a_k  .  1 (starting a list of a deeper level), or 
  2. Add an item a_1  .  a_2  .  a_3  .  ⋅⋅⋅  .  (a_k + 1) (continuing the current level). 

Operation can only be applied if the list does not contain two identical items afterwards. And also, if we consider every item as a sequence of numbers, then the sequence of items should always remain increasing in lexicographical order. Examples of valid and invalid lists that are shown in the picture can found in the "Notes" section.

When William decided to save a Word document with the list of his errands he accidentally hit a completely different keyboard shortcut from the "Ctrl-S" he wanted to hit. It's not known exactly what shortcut he pressed but after triggering it all items in the list were replaced by a single number: the last number originally written in the item number.

William wants you to help him restore a fitting original nested list.

Input

Each test contains multiple test cases. The first line contains the number of test cases t (1 ≤ t ≤ 10). Description of the test cases follows.

The first line of each test case contains a single integer n (1 ≤ n ≤ 10^3), which is the number of lines in the list.

Each of the next n lines contains a single integer a_i (1 ≤ a_i ≤ n), which is what remains of William's nested list.

It is guaranteed that in each test case at least one fitting list exists.

It is guaranteed that the sum of values n across all test cases does not exceed 10^3.

Output

For each test case output n lines which represent a valid nested list, which could become the data provided to you by William.

If there are multiple answers, print any.

Example

Input


2
4
1
1
2
3
9
1
1
1
2
2
1
2
1
2


Output


1
1.1
1.2
1.3
1
1.1
1.1.1
1.1.2
1.2
1.2.1
2
2.1
2.2

Note

In the second example test case one example of a fitting list is:

1

1.1

1.1.1

1.1.2

1.2

1.2.1

2

2.1

2.2

This list can be produced by using the sequence of operations shown below: <image>

  1. Original list with a single item 1. 
  2. Insert item 2 by using the insertion operation of the second type after item 1. 
  3. Insert item 1.1 by using the insertion operation of the first type after item 1. 
  4. Insert item 1.2 by using the insertion operation of the second type after item 1.1. 
  5. Insert item 1.1.1 by using the insertion operation of the first type after item 1.1. 
  6. Insert item 1.1.2 by using the insertion operation of the second type after item 1.1.1. 
  7. Insert item 1.2.1 by using the insertion operation of the first type after item 1.2. 
  8. Insert item 2.1 by using the insertion operation of the first type after item 2. 
  9. Insert item 2.2 by using the insertion operation of the second type after item 2.1. 

Solution (in JAVA):

Solution:
//package com.company;


import javax.xml.transform.stax.StAXResult;
import java.awt.*;
import java.io.*;
import java.util.*;

public class Main implements Runnable {
    int size[];
    static int e9 = 1000000007;
    int max = Integer.MIN_VALUE;
    long max1 = Long.MIN_VALUE;
    long min1 = Long.MAX_VALUE;
    long fib[][];
    static class FastReader {
        BufferedReader br;
        StringTokenizer st;

        public FastReader() {
            br = new BufferedReader(new
                    InputStreamReader(System.in));
        }

        String next() {
            while (st == null || !st.hasMoreElements()) {
                try {
                    st = new StringTokenizer(br.readLine());
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
            return st.nextToken();
        }

        int nextInt() {
            return Integer.parseInt(next());
        }

        long nextLong() {
            return Long.parseLong(next());
        }

        double nextDouble() {
            return Double.parseDouble(next());
        }

        String nextLine() {
            String str = "";
            try {
                str = br.readLine();
            } catch (IOException e) {
                e.printStackTrace();
            }
            return str;
        }
    }
    int parent[];
    int rank[];
    ArrayList<ArrayList<Integer>> arrayLists;
    ArrayList<Integer> arr[];
    long fib1[][];
    long r[];
    int n;
    int m;
    long co=0;
    long size1[];
    long v[];
    public static void main(String[] args) throws IOException {
        new Thread(null,new Main(),"Main",1<<28).start();
    }

    public void run(){
        FastReader scanner = new FastReader();
//            Scanner scanner = new Scanner(System.in);
//            BufferedReader bufferedReader=new BufferedReader(new InputStreamReader(System.in));
//            String s;
        PrintWriter printWriter = new PrintWriter(System.out);
//        System.out.println(1<<6);
//        String arr1[]=("1.2.3").split("\\.");
//        System.out.println(arr1.length);
        long t=scanner.nextLong();
        high:while (t-->0) {
            int n=scanner.nextInt();
            Stack<Integer> stack=new Stack<>();
            for (int i = 0; i < n; i++) {
                int k=scanner.nextInt();
                if(k==1){
                    stack.add(k);
//                    System.out.println("k");
                }else{
//                    System.out.println(stack.size());
                        while (true) {
//                            System.out.println(stack.size());
                            int y=stack.pop();
                            if(y==k-1){
                                stack.add(k);
                                break ;
                            }
                        }
                }
                int k1=0;
                for(int r:stack){
                    k1++;
                    if(k1==stack.size()){
                        printWriter.print(r);
                    }else{
                        printWriter.print(r+".");
                    }
                }
                printWriter.println();
            }
        }
        printWriter.flush();
    }
    static long mod=1_000_000_007;
    public long lcm(long a,long b){
        return (a*b)/gcd(a,b);
    }
    public long mul(long a, long b) {
//        System.out.println(a+" "+b);
        return ((a)%mod*(b)%mod);
    }
    public long fact(int x) {
        long ans=1;
        for (int i=2; i<=x; i++) ans=mul(ans, i);
        return ans;
    }
    public long fastPow(long base, long exp) {
        if (exp==0) return 1;
        long half=fastPow(base, exp/2);
        if (exp%2==0) return mul(half, half);
        return mul(half, mul(half, base));
    }
    public long modInv(long x) {
        return fastPow(x, mod-2);
    }
    public long nCk(int n, int k) {
        return mul(fact(n), mul(modInv(fact(k)), modInv(fact(n-k))));
    }
    public void parent(int n){
        parent=new int[n+1];
        size=new int[n+1];
        rank=new int[n+1];
        for (int i = 0; i <=n; i++) {
            parent[i]=i;
            rank[i]=0;
//            size[i]=1;
        }
    }
    public void union(int i,int j){
        int root1=find(i);
        int root2=find(j);
//            if(root1 != root2) {
//                parent[root2] = root1;
////                sz[a] += sz[b];
//            }
        if(root1==root2){
            return;
        }
        if(rank[root1]>rank[root2]){
            parent[root2]=root1;
            size[root1]+=size[root2];
        }
        else if(rank[root1]<rank[root2]){
            parent[root1]=root2;
            size[root2]+=size[root1];
        }
        else{
            parent[root2]=root1;
            rank[root1]+=1;
            size[root1]+=size[root2];
        }
    }
    public int find(int p){
        if(parent[p]!=p){
            if(parent[p]==-1){
                return parent[p];
            }
            parent[p]=find(parent[p]);
        }
        return parent[p];
    }
    public double dist(double x1,double y1,double x2,double y2){
        double e=(x2-x1)*(x2-x1)+(y2-y1)*(y2-y1);
        double e1=Math.sqrt(e);
        return e1;
    }
    public void make(int p){
        parent[p]=p;
        rank[p]=1;
    }
    Random rand = new Random();
    public void sort(int[] a, int n) {
        for (int i = 0; i < n; i++) {
            int j = rand.nextInt(i + 1);
            int tmp = a[i];
            a[i] = a[j];
            a[j] = tmp;
        }
        Arrays.sort(a, 0, n);
    }
    public long gcd(long a,long b){
        if(b==0){
            return a;
        }
        return gcd(b,a%b);
    }
    //    public void dfs(ArrayList<Integer> arrayList){
//        for (int i = 0; i < arrayList.size(); i++) {
//            if(v1[arrayList.get(i)]==false){
//                v1[arrayList.get(i)]=true;
//                dfs(arrayLists.get(i));
//            }
//        }
//    }
    public double fact(double h){
        double sum=1;
        while(h>=1){
            sum=(sum%e9)*(h%e9);
            h--;
        }
        return sum%e9;
    }
    public long primef(double r){
        long c=0;
        long ans=1;
        while(r%2==0){
            c++;
            r=r/2;
        }
        if(c>0){
            ans*=2;
        }
        c=0;
//            System.out.println(ans+" "+r);
        for (int i = 3; i <=Math.sqrt(r) ;i+=2) {
            while(r%i==0){
//                    System.out.println(i);
                c++;
                r=r/i;
            }
            if(c>0){
                ans*=i;
            }
            c=0;
        }
        if(r>2){
            ans*=r;
        }
        return ans;
    }
    public long divisor(double r,long n,long k){
        long c=0;
//        if(n==3)
//            System.out.println(r+" "+n+" "+k+" "+"l");
        for (int i =2; i <=Math.sqrt(r)&&i<k&&i<n; i++) {
            if(r%i==0){
                if(r/i==i){
                    c++;
                }
                else{
                    if(r/i<n){
                        c+=2;
                    }else{
                        c++;
                    }
                }
            }
        }
        return c;
    }
}
class Pair {
    int x;
    int y;
    int z;
    public Pair(int x,int y) {
        this.x = x;
        this.y = y;
//        this.z=z;
    }

    // @Override
//    public int hashCode() {
//        int hash = 37;
//        return this.x * hash + this.y;
//    }
//
//    @Override
//    public boolean equals(Object o1) {
//        if (o1 == null || o1.getClass() != this.getClass()) {
//            return false;
//        }
//        Pair o = (Pair) o1;
//        if (o.x == this.x && o.y == this.y) {
//            return true;
//        }
//        return false;
//    }
}
class Sorting implements Comparator<Pair> {
    public int compare(Pair p1, Pair p2) {
//        if(p1.y==p2.y){
//            return Long.compare(p1.x,p2.x);
//        }else {
        return Long.compare(p1.x, p2.x);
        // }
    }
}
class Edge{
    int s=0;
    int d=0;
    int c=0;
    public Edge(int s,int d,int c){
        this.s=s;
        this.d=d;
        this.c=c;
    }
}