Problem: Write a program which reads a sequence of integers $A = \\{a_0, a_1, ..., a_{n-1}\\}$ and reverse specified elements by a list of the following operation:

* reverse($b, e$): reverse the order of $a_b, a_{b+1}, ..., a_{e-1}$

Constraints

* $1 \leq n \leq 1,000$
* $-1,000,000,000 \leq a_i \leq 1,000,000,000$
* $1 \leq q \leq 1,000$
* $0 \leq b < e \leq n$

Input

The input is given in the following format.


$n$
$a_0 \; a_1 \; ...,\; a_{n-1}$
$q$
$b_1 \; e_1$
$b_2 \; e_2$
:
$b_{q} \; b_{q}$


In the first line, $n$ (the number of elements in $A$) is given. In the second line, $a_i$ (each element in $A$) are given. In the third line, the number of queries $q$ is given and each query is given by two integers $b_i \; e_i$ in the following $q$ lines.

Output

Print all elements of $A$ in a line after performing the given operations. Put a single space character between adjacency elements and a newline at the end of the last element.

Example

Input

8
1 2 3 4 5 6 7 8
2
1 6
3 8


Output

1 6 5 8 7 2 3 4

Solution (in JAVA):

Solution:
import java.util.Scanner;
public class Main{
    public static void reverse(long a[], int b, int e){
        long A[] = new long[e-b];
        for(int i = 0 ; i < e-b ; i++)
            A[i] = a[e-1-i];
        for(int i = 0 ; i < e-b ; i++)
            a[b+i] = A[i];
    }
    public static void main(String[] args){
        Scanner sc = new Scanner(System.in);
        int n = sc.nextInt();
        long a[] = new long[n];
        for(int i = 0 ; i < n ; i++)
            a[i] = sc.nextLong();
        int q = sc.nextInt();
        for(int i = 0 ; i < q ; i++){
            int b = sc.nextInt();
            int e = sc.nextInt();
            reverse(a,b,e);
        }
        for(int i = 0 ; i < n-1 ; i++)
            System.out.print(a[i] + " ");
        System.out.println(a[n-1]);
    }
}