Problem: Asterix, Obelix and their temporary buddies Suffix and Prefix has finally found the Harmony temple. However, its doors were firmly locked and even Obelix had no luck opening them.

A little later they found a string s, carved on a rock below the temple's gates. Asterix supposed that that's the password that opens the temple and read the string aloud. However, nothing happened. Then Asterix supposed that a password is some substring t of the string s.

Prefix supposed that the substring t is the beginning of the string s; Suffix supposed that the substring t should be the end of the string s; and Obelix supposed that t should be located somewhere inside the string s, that is, t is neither its beginning, nor its end.

Asterix chose the substring t so as to please all his companions. Besides, from all acceptable variants Asterix chose the longest one (as Asterix loves long strings). When Asterix read the substring t aloud, the temple doors opened. 

You know the string s. Find the substring t or determine that such substring does not exist and all that's been written above is just a nice legend.

Input

You are given the string s whose length can vary from 1 to 106 (inclusive), consisting of small Latin letters.

Output

Print the string t. If a suitable t string does not exist, then print "Just a legend" without the quotes.

Examples

Input

fixprefixsuffix


Output

fix

Input

abcdabc


Output

Just a legend

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int main() {
  ios_base::sync_with_stdio(0), cin.tie(0), cout.precision(10), cout << fixed;
  string s;
  cin >> s;
  int n = s.length();
  vector<int> P(n, 0);
  int j = 0;
  for (int i = 1; i < n; ++i) {
    j = P[i - 1];
    while (j > 0 && s[i] != s[j]) j = P[j - 1];
    if (s[i] == s[j]) ++j;
    P[i] = j;
  }
  if (P[n - 1] == 0) {
    cout << "Just a legend\n";
    return 0;
  }
  for (int i = 1; i < n - 1; ++i) {
    if (P[i] == P[n - 1]) {
      for (int i = 0; i < P[n - 1]; ++i) cout << s[i];
      return 0;
    }
  }
  if (P[P[n - 1] - 1]) {
    for (int i = 0; i < P[P[n - 1] - 1]; ++i) cout << s[i];
  } else
    cout << "Just a legend\n";
  return 0;
}