Problem: Asterix, Obelix and their temporary buddies Suffix and Prefix has finally found the Harmony temple. However, its doors were firmly locked and even Obelix had no luck opening them.

A little later they found a string s, carved on a rock below the temple's gates. Asterix supposed that that's the password that opens the temple and read the string aloud. However, nothing happened. Then Asterix supposed that a password is some substring t of the string s.

Prefix supposed that the substring t is the beginning of the string s; Suffix supposed that the substring t should be the end of the string s; and Obelix supposed that t should be located somewhere inside the string s, that is, t is neither its beginning, nor its end.

Asterix chose the substring t so as to please all his companions. Besides, from all acceptable variants Asterix chose the longest one (as Asterix loves long strings). When Asterix read the substring t aloud, the temple doors opened. 

You know the string s. Find the substring t or determine that such substring does not exist and all that's been written above is just a nice legend.

Input

You are given the string s whose length can vary from 1 to 106 (inclusive), consisting of small Latin letters.

Output

Print the string t. If a suitable t string does not exist, then print "Just a legend" without the quotes.

Examples

Input

fixprefixsuffix


Output

fix

Input

abcdabc


Output

Just a legend

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace ::std;
const int maxn = 1e6 + 500;
int f[maxn];
int cnt[maxn];
int main() {
  ios_base::sync_with_stdio(0);
  cin.tie(0);
  cout.tie(0);
  string s;
  cin >> s;
  int n = s.size();
  int k = -1;
  f[0] = -1;
  for (int i = 1; i < n; i++) {
    while (s[k + 1] != s[i] && k >= 0) {
      k = f[k];
    }
    if (s[k + 1] == s[i]) k++;
    f[i] = k;
  }
  for (int i = 0; i < n; i++) {
    cnt[f[i]]++;
  }
  k = f[n - 1];
  if (k == -1) {
    cout << "Just a legend";
    return 0;
  }
  if (cnt[k] > 1) {
    cout << s.substr(0, 1 + k);
    return 0;
  }
  k = f[k];
  if (k == -1) {
    cout << "Just a legend";
    return 0;
  }
  cout << s.substr(0, 1 + k);
}