Problem: Write a program which reads a sequence of integers $A = \\{a_0, a_1, ..., a_{n-1}\\}$ and reverse specified elements by a list of the following operation:

* reverse($b, e$): reverse the order of $a_b, a_{b+1}, ..., a_{e-1}$

Constraints

* $1 \leq n \leq 1,000$
* $-1,000,000,000 \leq a_i \leq 1,000,000,000$
* $1 \leq q \leq 1,000$
* $0 \leq b < e \leq n$

Input

The input is given in the following format.


$n$
$a_0 \; a_1 \; ...,\; a_{n-1}$
$q$
$b_1 \; e_1$
$b_2 \; e_2$
:
$b_{q} \; b_{q}$


In the first line, $n$ (the number of elements in $A$) is given. In the second line, $a_i$ (each element in $A$) are given. In the third line, the number of queries $q$ is given and each query is given by two integers $b_i \; e_i$ in the following $q$ lines.

Output

Print all elements of $A$ in a line after performing the given operations. Put a single space character between adjacency elements and a newline at the end of the last element.

Example

Input

8
1 2 3 4 5 6 7 8
2
1 6
3 8


Output

1 6 5 8 7 2 3 4

Solution (in CPP):

Solution:
#include<bits/stdc++.h>
using namespace std;
using lint = long long;
template<typename T = lint>inline T in() { T x; cin >> x; return x; }
#define INF           1e9
#define INFL          static_cast<lint>(INF)
#define REP(i,n)      for(lint i=0,i##_len=(n);i<i##_len;++i)
#define REP1(i,n)     for(lint i=1,i##_len=(n);i<=i##_len;++i)
#define REPI(i,ini,n) for(lint i=(ini),i##_len=(n);i<i##_len;++i)
#define REPC(i,obj)   for(auto i:obj)
#define R_UP(a,b)     (((a)+(b)-1)/(b))
#define ALL(obj)      (obj).begin(),(obj).end()
int main()
{
	vector<int>a(in());
	REPC(&i, a)i = in();
	REP(i, in())
	{
		int b = in(), e = in();
		reverse(a.begin() + b, a.begin() + e);
	}
	REP(i, a.size())
	{
		if (i != 0)cout << ' ';
		cout << a[i];
	}
	cout << endl;
}