Problem: Let's call a positive integer composite if it has at least one divisor other than 1 and itself. For example:

  * the following numbers are composite: 1024, 4, 6, 9; 
  * the following numbers are not composite: 13, 1, 2, 3, 37. 



You are given a positive integer n. Find two composite integers a,b such that a-b=n.

It can be proven that solution always exists.

Input

The input contains one integer n (1 ≤ n ≤ 10^7): the given integer.

Output

Print two composite integers a,b (2 ≤ a, b ≤ 10^9, a-b=n).

It can be proven, that solution always exists.

If there are several possible solutions, you can print any. 

Examples

Input


1


Output


9 8


Input


512


Output


4608 4096

Solution (in PYTHON3):

Solution:
import sys     
import math as mt
import bisect
#input=sys.stdin.readline
#t=int(input())
t=1  


            
for _ in range(t):
    n=int(input())
    #n,x=map(int,input().split())
    #x,y,k=map(int,input().split())
    #n,h=(map(int,input().split()))
    #l=list(map(int,input().split()))
    print(9*n,8*n)