Problem: Asterix, Obelix and their temporary buddies Suffix and Prefix has finally found the Harmony temple. However, its doors were firmly locked and even Obelix had no luck opening them.

A little later they found a string s, carved on a rock below the temple's gates. Asterix supposed that that's the password that opens the temple and read the string aloud. However, nothing happened. Then Asterix supposed that a password is some substring t of the string s.

Prefix supposed that the substring t is the beginning of the string s; Suffix supposed that the substring t should be the end of the string s; and Obelix supposed that t should be located somewhere inside the string s, that is, t is neither its beginning, nor its end.

Asterix chose the substring t so as to please all his companions. Besides, from all acceptable variants Asterix chose the longest one (as Asterix loves long strings). When Asterix read the substring t aloud, the temple doors opened. 

You know the string s. Find the substring t or determine that such substring does not exist and all that's been written above is just a nice legend.

Input

You are given the string s whose length can vary from 1 to 106 (inclusive), consisting of small Latin letters.

Output

Print the string t. If a suitable t string does not exist, then print "Just a legend" without the quotes.

Examples

Input

fixprefixsuffix


Output

fix

Input

abcdabc


Output

Just a legend

Solution (in PYTHON3):

Solution:
def getLPS(s1,l):
  lps=[0]*l
  i=1
  j=0
  while i<l:
    if s1[i]==s1[j]:
       lps[i]=j+1 
       j+=1
       i+=1
       
    else:
      if j!=0:
        j=lps[j-1]
      else:
         lps[i]=0
         i+=1
  return lps
s=input()
n=len(s)
arr=getLPS(s,n)
arr=[-1]+arr
lenth=arr[-1]
#print(arr)
if arr.count(lenth)<2:
  lenth=arr[lenth]
 # print(lenth)
if lenth>0:
  print(s[:lenth])
else:print('Just a legend')