Problem: There is a polyline going through points (0, 0) – (x, x) – (2x, 0) – (3x, x) – (4x, 0) – ... - (2kx, 0) – (2kx + x, x) – .... 

We know that the polyline passes through the point (a, b). Find minimum positive value x such that it is true or determine that there is no such x.

Input

Only one line containing two positive integers a and b (1 ≤ a, b ≤ 109).

Output

Output the only line containing the answer. Your answer will be considered correct if its relative or absolute error doesn't exceed 10 - 9. If there is no such x then output  - 1 as the answer.

Examples

Input

3 1


Output

1.000000000000


Input

1 3


Output

-1


Input

4 1


Output

1.250000000000

Note

You can see following graphs for sample 1 and sample 3. 

<image> <image>

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
template <typename T>
class IntegerIterator
    : public std::iterator<std::input_iterator_tag, T, std::ptrdiff_t, T*, T> {
 public:
  explicit IntegerIterator(int value) : value(value) {}
  IntegerIterator& operator++() {
    ++value;
    return *this;
  }
  IntegerIterator operator++(int) {
    IntegerIterator copy = *this;
    ++value;
    return copy;
  }
  IntegerIterator& operator--() {
    --value;
    return *this;
  }
  IntegerIterator operator--(int) {
    IntegerIterator copy = *this;
    --value;
    return copy;
  }
  T operator*() const { return value; }
  bool operator==(IntegerIterator rhs) { return value == rhs.value; }
  bool operator!=(IntegerIterator rhs) { return !(*this == rhs); }

 private:
  T value;
};
template <typename T>
class IntegerRange {
 public:
  IntegerRange(T begin, T end) : begin_(begin), end_(end) {}
  IntegerIterator<T> begin() const { return IntegerIterator<T>(begin_); }
  IntegerIterator<T> end() const { return IntegerIterator<T>(end_); }

 private:
  T begin_;
  T end_;
};
template <typename T>
class ReversedIntegerRange {
 public:
  ReversedIntegerRange(T begin, T end) : begin_(begin), end_(end) {}
  std::reverse_iterator<IntegerIterator<T>> begin() const {
    return std::reverse_iterator<IntegerIterator<T>>(
        IntegerIterator<T>(begin_));
  }
  std::reverse_iterator<IntegerIterator<T>> end() const {
    return std::reverse_iterator<IntegerIterator<T>>(IntegerIterator<T>(end_));
  }

 private:
  T begin_;
  T end_;
};
template <typename T>
IntegerRange<T> range(T to) {
  ;
  return IntegerRange<T>(0, to);
}
template <typename T>
IntegerRange<T> range(T from, T to) {
  ;
  return IntegerRange<T>(from, to);
}
template <typename T>
IntegerRange<T> inclusiveRange(T to) {
  ;
  return IntegerRange<T>(0, to + 1);
}
template <typename T>
IntegerRange<T> inclusiveRange(T from, T to) {
  ;
  return IntegerRange<T>(from, to + 1);
}
template <typename T>
ReversedIntegerRange<T> downrange(T from) {
  ;
  return ReversedIntegerRange<T>(from, 0);
}
template <typename T>
ReversedIntegerRange<T> downrange(T from, T to) {
  ;
  return ReversedIntegerRange<T>(from, to);
}
template <typename T>
ReversedIntegerRange<T> inclusiveDownrange(T from) {
  ;
  return ReversedIntegerRange<T>(from + 1, 0);
}
template <typename T>
ReversedIntegerRange<T> inclusiveDownrange(T from, T to) {
  ;
  return ReversedIntegerRange<T>(from + 1, to);
}
template <typename R>
void sort(R& range) {
  std::sort(range.begin(), range.end());
}
template <typename R, typename Comp>
void sort(R& range, Comp comp) {
  std::sort(range.begin(), range.end(), comp);
}
template <typename R>
void reverse(R& range) {
  std::reverse(range.begin(), range.end());
}
template <typename R, typename T>
auto lower_bound(const R& range, const T& value) -> decltype(range.begin()) {
  return std::lower_bound(range.begin(), range.end(), value);
}
template <typename R, typename T, typename Comp>
auto lower_bound(const R& range, const T& value, Comp comp)
    -> decltype(range.begin()) {
  return std::lower_bound(range.begin(), range.end(), value, comp);
}
template <typename R, typename T>
auto upper_bound(const R& range, const T& value) -> decltype(range.begin()) {
  return std::upper_bound(range.begin(), range.end(), value);
}
template <typename R, typename T, typename Comp>
auto upper_bound(const R& range, const T& value, Comp comp)
    -> decltype(range.begin()) {
  return std::upper_bound(range.begin(), range.end(), value, comp);
}
template <typename R>
auto min_element(const R& range) -> decltype(range.begin()) {
  return std::min_element(range.begin(), range.end());
}
template <typename R>
auto max_element(const R& range) -> decltype(range.begin()) {
  return std::max_element(range.begin(), range.end());
}
template <typename R>
bool next_permutation(R& range) {
  return std::next_permutation(range.begin(), range.end());
}
template <typename T>
void unique(std::vector<T>& range) {
  range.erase(std::unique(range.begin(), range.end()), range.end());
}
template <typename R>
R sorted(R range) {
  sort(range);
  return range;
}
template <typename R, typename Comp>
R sorted(R range, Comp comp) {
  sort(range, comp);
  return range;
}
template <typename R>
R reversed(R range) {
  reverse(range);
  return range;
}
template <typename T>
std::vector<T> unsortedDivisors(const T& n) {
  std::vector<T> result;
  for (int i = 1; i * i <= n; ++i) {
    if (n % i == 0) {
      result.push_back(i);
      if (i * i != n) {
        result.push_back(n / i);
      }
    }
  }
  return result;
}
template <typename T>
std::vector<T> sortedDivisors(const T& n) {
  return sorted(unsortedDivisors(n));
}
using namespace std;
class TaskA {
 public:
  void solve(std::istream& in, std::ostream& out) {
    int a, b;
    in >> a >> b;
    if (b > a) {
      out << -1;
      return;
    }
    int k1 = (a + b) / 2 / b;
    out << (a + b) / 2.0 / k1;
  }
};
int main() {
  std::ios_base::sync_with_stdio(false);
  TaskA solver;
  std::istream& in(std::cin);
  std::ostream& out(std::cout);
  in.tie(0);
  out << std::fixed;
  out.precision(20);
  solver.solve(in, out);
  return 0;
}