Problem: Write a program which reads a sequence of integers $A = \\{a_0, a_1, ..., a_{n-1}\\}$ and reverse specified elements by a list of the following operation:

* reverse($b, e$): reverse the order of $a_b, a_{b+1}, ..., a_{e-1}$

Constraints

* $1 \leq n \leq 1,000$
* $-1,000,000,000 \leq a_i \leq 1,000,000,000$
* $1 \leq q \leq 1,000$
* $0 \leq b < e \leq n$

Input

The input is given in the following format.


$n$
$a_0 \; a_1 \; ...,\; a_{n-1}$
$q$
$b_1 \; e_1$
$b_2 \; e_2$
:
$b_{q} \; b_{q}$


In the first line, $n$ (the number of elements in $A$) is given. In the second line, $a_i$ (each element in $A$) are given. In the third line, the number of queries $q$ is given and each query is given by two integers $b_i \; e_i$ in the following $q$ lines.

Output

Print all elements of $A$ in a line after performing the given operations. Put a single space character between adjacency elements and a newline at the end of the last element.

Example

Input

8
1 2 3 4 5 6 7 8
2
1 6
3 8


Output

1 6 5 8 7 2 3 4

Solution (in JAVA):

Solution:
import java.util.Scanner;

public class Main {
	public static void main(String[] args) {
		Scanner src = new Scanner(System.in);

		//配列array
		int n = src.nextInt();
		int[] array = new int[n];
		for (int i=0; i<n; i++)
			array[i] = src.nextInt();

		int q = src.nextInt();
		for(int i=0; i<n; i++) {
//			System.out.print(array[i] + "debug");
		}

		for(int i=0; i<q; i++) {

			int b = src.nextInt();
			int e = src.nextInt() - 1;

			for(int j=0; j<(e+1 - b) / 2; j++) {
				int tmp = array[b+j];
				array[b+j] = array[e-j];
				array[e-j] = tmp;

			}
		}
		for(int i=0; i<n-1; i++) {
			System.out.print(array[i] + " ");
		}
		System.out.println(array[n-1]);
	}
}