Problem: There is a polyline going through points (0, 0) – (x, x) – (2x, 0) – (3x, x) – (4x, 0) – ... - (2kx, 0) – (2kx + x, x) – .... 

We know that the polyline passes through the point (a, b). Find minimum positive value x such that it is true or determine that there is no such x.

Input

Only one line containing two positive integers a and b (1 ≤ a, b ≤ 109).

Output

Output the only line containing the answer. Your answer will be considered correct if its relative or absolute error doesn't exceed 10 - 9. If there is no such x then output  - 1 as the answer.

Examples

Input

3 1


Output

1.000000000000


Input

1 3


Output

-1


Input

4 1


Output

1.250000000000

Note

You can see following graphs for sample 1 and sample 3. 

<image> <image>

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
double solve(double V, double B) {
  if (V < 1e-7) return B;
  return V / (floor(V / B));
}
int main() {
  ios_base::sync_with_stdio(false);
  cin.tie(0), cout.tie(0), cout.precision(15);
  long long A, B;
  cin >> A >> B;
  if (A < B) {
    cout << -1 << "\n";
    return 0;
  }
  cout << min(solve((A + B) / 2.0, B), solve((A - B) / 2.0, B)) << "\n";
}