Problem: Let's call a positive integer composite if it has at least one divisor other than 1 and itself. For example:

  * the following numbers are composite: 1024, 4, 6, 9; 
  * the following numbers are not composite: 13, 1, 2, 3, 37. 



You are given a positive integer n. Find two composite integers a,b such that a-b=n.

It can be proven that solution always exists.

Input

The input contains one integer n (1 ≤ n ≤ 10^7): the given integer.

Output

Print two composite integers a,b (2 ≤ a, b ≤ 10^9, a-b=n).

It can be proven, that solution always exists.

If there are several possible solutions, you can print any. 

Examples

Input


1


Output


9 8


Input


512


Output


4608 4096

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.*;

public class A {
	
	public static void main(String[] args) {
		FastScanner sc=new FastScanner();
		int n=sc.nextInt();
		long a = (long)1e9;
		long b = 0;
		if(n%2==0) {
			a = 4;
			b = 4+n;
		}else {
			a = 9;
			b = 9+n;
		}
		System.out.println(b+" "+a);
	}
	
	static final Random random = new Random();
	
	static void sort(int[] a) {
		int n = a.length;
		for(int i =0; i<n; i++) {
			int val = random.nextInt(n);
			int cur = a[i];
			a[i] = a[val];
			a[val] = cur;
		}
		Arrays.sort(a);
	}
	
	static void sortl(long[] a) {
		int n = a.length;
		for(int i =0; i<n; i++) {
			int val = random.nextInt(n);
			long cur = a[i];
			a[i] = a[val];
			a[val] = cur;
		}
		Arrays.sort(a);
	}
	
	static class FastScanner {
		BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
		StringTokenizer st=new StringTokenizer("");
		String next() {
			while (st == null  || !st.hasMoreTokens()) {
				try {
					st=new StringTokenizer(br.readLine());
				} catch (IOException e) {
					e.printStackTrace();
				}
			}
			return st.nextToken();
		}
		String nextLine() { 
            String str = ""; 
            try
            { 
                str = br.readLine(); 
            } 
            catch (IOException e) 
            { 
                e.printStackTrace(); 
            } 
            return str; 
		} 
		int nextInt() {
			return Integer.parseInt(next());
		}
		int[] readArray(int n) {
			int[] a=new int[n];
			for (int i=0; i<n; i++) a[i]=nextInt();
			return a;
		}
		long nextLong() {
			return Long.parseLong(next());
		}
		double nextDouble() { 
            return Double.parseDouble(next()); 
        } 
	}

}