Problem: Let's call a positive integer composite if it has at least one divisor other than 1 and itself. For example:

  * the following numbers are composite: 1024, 4, 6, 9; 
  * the following numbers are not composite: 13, 1, 2, 3, 37. 



You are given a positive integer n. Find two composite integers a,b such that a-b=n.

It can be proven that solution always exists.

Input

The input contains one integer n (1 ≤ n ≤ 10^7): the given integer.

Output

Print two composite integers a,b (2 ≤ a, b ≤ 10^9, a-b=n).

It can be proven, that solution always exists.

If there are several possible solutions, you can print any. 

Examples

Input


1


Output


9 8


Input


512


Output


4608 4096

Solution (in PYTHON3):

Solution:
import sys
import collections
import heapq
import math
import bisect

input = sys.stdin.readline

def rints(): return map(int, input().strip().split())
def rstr(): return input().strip()
def rint(): return int(input().strip())
def rintas(): return [int(i) for i in input().strip().split()]
    
def gcd(a, b):       
    if (b == 0): 
        return a 
    return gcd(b, a%b) 

from itertools import accumulate
 
t = int(input())
if t  == 1:
    print(9, 8)
else:
    a = 3*t
    b = 2*t
    print(a, b)