Problem: Asterix, Obelix and their temporary buddies Suffix and Prefix has finally found the Harmony temple. However, its doors were firmly locked and even Obelix had no luck opening them.

A little later they found a string s, carved on a rock below the temple's gates. Asterix supposed that that's the password that opens the temple and read the string aloud. However, nothing happened. Then Asterix supposed that a password is some substring t of the string s.

Prefix supposed that the substring t is the beginning of the string s; Suffix supposed that the substring t should be the end of the string s; and Obelix supposed that t should be located somewhere inside the string s, that is, t is neither its beginning, nor its end.

Asterix chose the substring t so as to please all his companions. Besides, from all acceptable variants Asterix chose the longest one (as Asterix loves long strings). When Asterix read the substring t aloud, the temple doors opened. 

You know the string s. Find the substring t or determine that such substring does not exist and all that's been written above is just a nice legend.

Input

You are given the string s whose length can vary from 1 to 106 (inclusive), consisting of small Latin letters.

Output

Print the string t. If a suitable t string does not exist, then print "Just a legend" without the quotes.

Examples

Input

fixprefixsuffix


Output

fix

Input

abcdabc


Output

Just a legend

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
const int maxn = 1e6 + 10;
int n, f[maxn], k;
string s;
void imp() {
  cout << "Just a legend\n";
  exit(0);
}
int main() {
  ios_base::sync_with_stdio(0), cin.tie(0), cout.tie(0);
  cin >> s;
  n = s.size();
  f[0] = -1;
  for (int i = 2; i <= n; i++) {
    while (k > -1 && s[k] != s[i - 1]) k = f[k];
    f[i] = ++k;
  }
  if (!k) imp();
  int num = k;
  k = 0;
  for (int i = 2; i < n; i++) {
    while (k > -1 && s[k] != s[i - 1]) k = f[k];
    f[i] = ++k;
    if (f[i] == num) {
      cout << s.substr(0, num) << "\n";
      return 0;
    }
  }
  if (!f[f[n]]) imp();
  cout << s.substr(0, f[f[n]]) << "\n";
  return 0;
}