Problem: Asterix, Obelix and their temporary buddies Suffix and Prefix has finally found the Harmony temple. However, its doors were firmly locked and even Obelix had no luck opening them.

A little later they found a string s, carved on a rock below the temple's gates. Asterix supposed that that's the password that opens the temple and read the string aloud. However, nothing happened. Then Asterix supposed that a password is some substring t of the string s.

Prefix supposed that the substring t is the beginning of the string s; Suffix supposed that the substring t should be the end of the string s; and Obelix supposed that t should be located somewhere inside the string s, that is, t is neither its beginning, nor its end.

Asterix chose the substring t so as to please all his companions. Besides, from all acceptable variants Asterix chose the longest one (as Asterix loves long strings). When Asterix read the substring t aloud, the temple doors opened. 

You know the string s. Find the substring t or determine that such substring does not exist and all that's been written above is just a nice legend.

Input

You are given the string s whose length can vary from 1 to 106 (inclusive), consisting of small Latin letters.

Output

Print the string t. If a suitable t string does not exist, then print "Just a legend" without the quotes.

Examples

Input

fixprefixsuffix


Output

fix

Input

abcdabc


Output

Just a legend

Solution (in PYTHON3):

Solution:
def kmpTable(s, n):
    res = [0]*n
    check_idx = 0
    for i in range(1, n):
        while check_idx > 0 and s[check_idx] != s[i]:
            check_idx = res[check_idx-1]
        if s[check_idx] == s[i]:
            check_idx += 1
        res[i] = check_idx
    return res

s = input()
n = len(s)
kmp_table = kmpTable(s, n)
psize = kmp_table[n-1]
if psize > 0 and psize in kmp_table[:-1]:
    print(s[:psize])
else:
	psize = kmp_table[psize-1]
	if psize > 0 and psize in kmp_table[:-1]:
		print(s[:psize])
	else:
		print("Just a legend")