Problem: Given two non-negative decimal integers $a$ and $b$, calculate their AND (logical conjunction), OR (logical disjunction) and XOR (exclusive disjunction) and print them in binary representation of 32 bits.

Constraints

* $0 \leq a, b \leq 2^{32} - 1$

Input

The input is given in the following format.


$a \; b$


Output

Print results of AND, OR and XOR in a line respectively.

Example

Input

8 10


Output

00000000000000000000000000001000
00000000000000000000000000001010
00000000000000000000000000000010

Solution (in CPP):

Solution:
#include "bits/stdc++.h"
using namespace std;
using ll = long long;
using P = pair<int, int>;
#define PI acos(-1)
#define Mod (int)1000000007
#define INFTY (int)INT_MAX
#define Rep(i, n) for (int i = 0; i < (int)(n); i++)
#define BitRep(i, n) for (int i = 0; i < (int)(1 << n); i++)
#define All(vec) vec.begin(), vec.end()
#define Part(vec, b, e) vec.begin() + b, vec.begin() + e
#define Sum(vec) accumulate(vec.begin(), vec.end(), 0)
#define Sort(vec) sort(vec.begin(), vec.end())
#define Reverse(vec) reverse(vec.begin(), vec.end())
#define Count(vec, x) count(vec.begin(), vec.end(), x)
#define Next_permutation(vec) next_permutation(vec.begin(), vec.end())
#define Find(vec, s) vec.find(s) != vec.end()
#define Set_union(A, B, res) set_union(A.begin(), A.end(), B.begin(), B.end(), inserter(res, res.end()));
#define Set_intersection(A, B, res) set_intersection(A.begin(), A.end(), B.begin(), B.end(), inserter(res, res.end()));
#define Set_difference(A, B, res) set_difference(A.begin(), A.end(), B.begin(), B.end(), inserter(res, res.end()));
#define Set_symmetric_difference(A, B, res) set_symmetric_difference(A.begin(), A.end(), B.begin(), B.end(), inserter(res, res.end()));

int main() {
	unsigned int a, b;
	cin >> a >> b;
	cout << bitset<32>(a & b) << endl;
	cout << bitset<32>(a | b) << endl;
	cout << bitset<32>(a ^ b) << endl;
	return 0;
}