Problem: Asterix, Obelix and their temporary buddies Suffix and Prefix has finally found the Harmony temple. However, its doors were firmly locked and even Obelix had no luck opening them.

A little later they found a string s, carved on a rock below the temple's gates. Asterix supposed that that's the password that opens the temple and read the string aloud. However, nothing happened. Then Asterix supposed that a password is some substring t of the string s.

Prefix supposed that the substring t is the beginning of the string s; Suffix supposed that the substring t should be the end of the string s; and Obelix supposed that t should be located somewhere inside the string s, that is, t is neither its beginning, nor its end.

Asterix chose the substring t so as to please all his companions. Besides, from all acceptable variants Asterix chose the longest one (as Asterix loves long strings). When Asterix read the substring t aloud, the temple doors opened. 

You know the string s. Find the substring t or determine that such substring does not exist and all that's been written above is just a nice legend.

Input

You are given the string s whose length can vary from 1 to 106 (inclusive), consisting of small Latin letters.

Output

Print the string t. If a suitable t string does not exist, then print "Just a legend" without the quotes.

Examples

Input

fixprefixsuffix


Output

fix

Input

abcdabc


Output

Just a legend

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int i, n, k, pref[1000005];
bool u;
string s;
int main() {
  ios_base::sync_with_stdio(0);
  cin.tie(0);
  getline(cin, s);
  n = s.length();
  for (i = 1; i < n; ++i) {
    while (k && s[i] != s[k]) k = pref[k - 1];
    if (s[i] == s[k]) ++k;
    pref[i] = k;
  }
  if (!pref[n - 1] || n < 3) return cout << "Just a legend\n", 0;
  for (i = 1; i < n - 1 && !u; ++i)
    if (pref[i] == pref[n - 1]) u = 1;
  if (!u) {
    if (!pref[pref[n - 1] - 1]) return cout << "Just a legend\n", 0;
    for (i = 0; i < pref[pref[n - 1] - 1]; ++i) cout << s[i];
    return 0;
  }
  for (i = 0; i < pref[n - 1]; ++i) cout << s[i];
  return 0;
}