Problem: The statement of this problem is the same as the statement of problem C2. The only difference is that, in problem C1, n is always even, and in C2, n is always odd.

You are given a regular polygon with 2 ⋅ n vertices (it's convex and has equal sides and equal angles) and all its sides have length 1. Let's name it as 2n-gon.

Your task is to find the square of the minimum size such that you can embed 2n-gon in the square. Embedding 2n-gon in the square means that you need to place 2n-gon in the square in such way that each point which lies inside or on a border of 2n-gon should also lie inside or on a border of the square.

You can rotate 2n-gon and/or the square.

Input

The first line contains a single integer T (1 ≤ T ≤ 200) — the number of test cases.

Next T lines contain descriptions of test cases — one per line. Each line contains single even integer n (2 ≤ n ≤ 200). Don't forget you need to embed 2n-gon, not an n-gon.

Output

Print T real numbers — one per test case. For each test case, print the minimum length of a side of the square 2n-gon can be embedded in. Your answer will be considered correct if its absolute or relative error doesn't exceed 10^{-6}.

Example

Input


3
2
4
200


Output


1.000000000
2.414213562
127.321336469

Solution (in JAVA):

Solution:
import java.io.*;
import java.util.StringTokenizer;

public class C {
    public static void main(String[] args) throws IOException {
        PrintWriter out = new PrintWriter(new OutputStreamWriter(System.out));
        InputReader in=new InputReader(System.in);
        int t=in.nextInt();
        while (t-->0){
            int n=in.nextInt();
            if(n==2){
                out.println(1);
                continue;
            }
            double jiao=Math.PI/2/(n/2);
            double res=0;
            double cur=jiao;
            for(int i=0,j=1;i<(n/2-1);i++,j++){
                res+=Math.sin(cur);
                cur+=jiao;
            }
            out.println(res*2+1);
        }
        out.flush();
    }
    static class InputReader{
        private BufferedReader in;
        private StringTokenizer tokenizer;
        public InputReader(InputStream stream){
            in = new BufferedReader(new InputStreamReader(stream),32768);
            tokenizer = null;
        }
        public String next() throws IOException{
            while(tokenizer==null || !tokenizer.hasMoreTokens()){
                tokenizer = new StringTokenizer(in.readLine());
            }
            return tokenizer.nextToken();
        }
        public Long nextLong() throws IOException {
            String next = next();
            return Long.valueOf(next);
        }
        public int nextInt() throws IOException{
            return Integer.valueOf(next());
        }
    }
}