Problem: The statement of this problem is the same as the statement of problem C2. The only difference is that, in problem C1, n is always even, and in C2, n is always odd.

You are given a regular polygon with 2 ⋅ n vertices (it's convex and has equal sides and equal angles) and all its sides have length 1. Let's name it as 2n-gon.

Your task is to find the square of the minimum size such that you can embed 2n-gon in the square. Embedding 2n-gon in the square means that you need to place 2n-gon in the square in such way that each point which lies inside or on a border of 2n-gon should also lie inside or on a border of the square.

You can rotate 2n-gon and/or the square.

Input

The first line contains a single integer T (1 ≤ T ≤ 200) — the number of test cases.

Next T lines contain descriptions of test cases — one per line. Each line contains single even integer n (2 ≤ n ≤ 200). Don't forget you need to embed 2n-gon, not an n-gon.

Output

Print T real numbers — one per test case. For each test case, print the minimum length of a side of the square 2n-gon can be embedded in. Your answer will be considered correct if its absolute or relative error doesn't exceed 10^{-6}.

Example

Input


3
2
4
200


Output


1.000000000
2.414213562
127.321336469

Solution (in JAVA):

Solution:
import java.io.*;
import java.lang.reflect.Array;
import java.util.*;


public class Main {


    static Long max = (long) (2 * 10E5);
    private static BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
    private static BufferedWriter bw = new BufferedWriter(new OutputStreamWriter(System.out));

    static Long[] readLongArray() throws IOException {
        return Arrays.stream(br.readLine().split("\\s+")).map(Long::parseLong).toArray(Long[]::new);
    }

    static Integer[] readIntArray() throws IOException {
        return Arrays.stream(br.readLine().split("\\s+")).map(Integer::parseInt).toArray(Integer[]::new);
    }

    static int readInt() throws IOException {
        return Integer.parseInt(br.readLine());
    }

    static long readLong() throws IOException {
        return Long.parseLong(br.readLine());
    }

    static double findGiag(int n, int sidesToFind) {
        if (sidesToFind == 1) {
            return 1.0;
        }
        double angle = ((n - 2.0) / n) * 180;
        double alpha = angle;
        double beta = alpha / (n - 3 + 1);
        double gama = beta;
        double diag = Math.sqrt((1.0 + 1.0) - (2.0 * 1.0 * 1.0 * Math.cos(Math.toRadians(alpha))));

        if (sidesToFind == 2) {
            return diag;
        } else {
            for (int i = 3; i <= sidesToFind; i++) {
                alpha = angle - gama;
                gama = 180 - alpha - beta;
                diag = Math.sqrt((Math.pow(diag, 2) + Math.pow(1.0, 2)) - ((2 * diag * 1.0) * Math.cos(Math.toRadians(alpha))));
            }
        }
        return diag;
    }

    static double findTriangleSide(int n, int sidesToFind) {
        double diag = findGiag(n, sidesToFind);
        return diag / Math.sqrt(2);
    }


    public static void main(String[] args) throws IOException {
        Scanner scanner = new Scanner(System.in);
        int _t = scanner.nextInt();
        for (int t = 0; t < _t; t++) {
            int n = 2 * scanner.nextInt();
            double res = findTriangleSide(n, (int) Math.floor((n * 1.0) / 4)) +
                    findTriangleSide(n, (int) Math.ceil((n * 1.0) / 4));
            System.out.println(res);
        }
    }
}