Problem: Write a program which reads a sequence of integers $A = \\{a_0, a_1, ..., a_{n-1}\\}$ and reverse specified elements by a list of the following operation:

* reverse($b, e$): reverse the order of $a_b, a_{b+1}, ..., a_{e-1}$

Constraints

* $1 \leq n \leq 1,000$
* $-1,000,000,000 \leq a_i \leq 1,000,000,000$
* $1 \leq q \leq 1,000$
* $0 \leq b < e \leq n$

Input

The input is given in the following format.


$n$
$a_0 \; a_1 \; ...,\; a_{n-1}$
$q$
$b_1 \; e_1$
$b_2 \; e_2$
:
$b_{q} \; b_{q}$


In the first line, $n$ (the number of elements in $A$) is given. In the second line, $a_i$ (each element in $A$) are given. In the third line, the number of queries $q$ is given and each query is given by two integers $b_i \; e_i$ in the following $q$ lines.

Output

Print all elements of $A$ in a line after performing the given operations. Put a single space character between adjacency elements and a newline at the end of the last element.

Example

Input

8
1 2 3 4 5 6 7 8
2
1 6
3 8


Output

1 6 5 8 7 2 3 4

Solution (in CPP):

Solution:
#include <bits/stdc++.h>

using namespace std;
typedef long long ll;

int main(){
    vector <ll> v;
    ll n, q, b, e, t;
    scanf("%lld", &n);
    for(ll i = 0; i < n; i++){
        scanf("%lld", &t);
        v.push_back(t);
    }
    scanf("%lld", &q);
    for(ll i = 0; i < q; i++){
        scanf("%lld %lld", &b, &e);
        reverse(v.begin()+b, v.begin()+e);
    }
    for (auto i = v.begin(); i != v.end(); i++){
        if(i != v.begin()){
            printf(" ");
        }
        printf("%lld", *i);
    }
    printf("\n");
}