Problem: Write a program which reads a sequence of integers $A = \\{a_0, a_1, ..., a_{n-1}\\}$ and reverse specified elements by a list of the following operation:

* reverse($b, e$): reverse the order of $a_b, a_{b+1}, ..., a_{e-1}$

Constraints

* $1 \leq n \leq 1,000$
* $-1,000,000,000 \leq a_i \leq 1,000,000,000$
* $1 \leq q \leq 1,000$
* $0 \leq b < e \leq n$

Input

The input is given in the following format.


$n$
$a_0 \; a_1 \; ...,\; a_{n-1}$
$q$
$b_1 \; e_1$
$b_2 \; e_2$
:
$b_{q} \; b_{q}$


In the first line, $n$ (the number of elements in $A$) is given. In the second line, $a_i$ (each element in $A$) are given. In the third line, the number of queries $q$ is given and each query is given by two integers $b_i \; e_i$ in the following $q$ lines.

Output

Print all elements of $A$ in a line after performing the given operations. Put a single space character between adjacency elements and a newline at the end of the last element.

Example

Input

8
1 2 3 4 5 6 7 8
2
1 6
3 8


Output

1 6 5 8 7 2 3 4

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
using i64 = int64_t;
using vi = vector<i64>;
using vvi = vector<vi>;

void printvec(vi& x, int size = 0) {
    if (x.size() == 0) {
        cout << endl;
        return;
    }
    cout << x.front();
    for (int i = 1; i < (size == 0 ? x.size() : size); i++) {
        cout << " " << x[i];
    }
    cout << endl;
}

int main() {
    int n;
    cin >> n;
    vi as(n);
    for (int i = 0; i < n; i++) {
        cin >> as[i];
    }
    int q;
    cin >> q;
    while (q--) {
        int b, e;
        cin >> b >> e;
        reverse(as.begin() + b, as.begin() + e);
    }

    printvec(as);
}