Problem: JATC loves Banh-mi (a Vietnamese food). His affection for Banh-mi is so much that he always has it for breakfast. This morning, as usual, he buys a Banh-mi and decides to enjoy it in a special way.

First, he splits the Banh-mi into n parts, places them on a row and numbers them from 1 through n. For each part i, he defines the deliciousness of the part as x_i ∈ \{0, 1\}. JATC's going to eat those parts one by one. At each step, he chooses arbitrary remaining part and eats it. Suppose that part is the i-th part then his enjoyment of the Banh-mi will increase by x_i and the deliciousness of all the remaining parts will also increase by x_i. The initial enjoyment of JATC is equal to 0.

For example, suppose the deliciousness of 3 parts are [0, 1, 0]. If JATC eats the second part then his enjoyment will become 1 and the deliciousness of remaining parts will become [1, \\_, 1]. Next, if he eats the first part then his enjoyment will become 2 and the remaining parts will become [\\_, \\_, 2]. After eating the last part, JATC's enjoyment will become 4.

However, JATC doesn't want to eat all the parts but to save some for later. He gives you q queries, each of them consisting of two integers l_i and r_i. For each query, you have to let him know what is the maximum enjoyment he can get if he eats all the parts with indices in the range [l_i, r_i] in some order.

All the queries are independent of each other. Since the answer to the query could be very large, print it modulo 10^9+7.

Input

The first line contains two integers n and q (1 ≤ n, q ≤ 100 000).

The second line contains a string of n characters, each character is either '0' or '1'. The i-th character defines the deliciousness of the i-th part.

Each of the following q lines contains two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ n) — the segment of the corresponding query.

Output

Print q lines, where i-th of them contains a single integer — the answer to the i-th query modulo 10^9 + 7.

Examples

Input

4 2
1011
1 4
3 4


Output

14
3


Input

3 2
111
1 2
3 3


Output

3
1

Note

In the first example: 

  * For query 1: One of the best ways for JATC to eats those parts is in this order: 1, 4, 3, 2. 
  * For query 2: Both 3, 4 and 4, 3 ordering give the same answer. 



In the second example, any order of eating parts leads to the same answer.

Solution (in PYTHON3):

Solution:
import sys, os, io
def rs(): return sys.stdin.readline().rstrip()
def ri(): return int(sys.stdin.readline())
def ria(): return list(map(int, sys.stdin.readline().split()))
def ws(s): sys.stdout.write(s + '\n')
def wi(n): sys.stdout.write(str(n) + '\n')
def wia(a): sys.stdout.write(' '.join([str(x) for x in a]) + '\n')
import math,datetime,functools,itertools,operator,bisect,fractions,statistics
from collections import deque,defaultdict,OrderedDict,Counter
from fractions import Fraction
from decimal import Decimal
from sys import stdout
from heapq import heappush, heappop, heapify ,_heapify_max,_heappop_max,nsmallest,nlargest




def main():
    mod=1000000007
    f=[1]
    t=[1]
    for i in range(1,100005):
        t.append((t[-1]*2)%mod)
        f.append((f[-1]+t[i])%mod)
    # InverseofNumber(mod)
    # InverseofFactorial(mod)
    # factorial(mod)
    starttime=datetime.datetime.now()
    if(os.path.exists('input.txt')):
        sys.stdin = open("input.txt","r")
        sys.stdout = open("output.txt","w")
    
    tc=1
    for _ in range(tc):
        n,q=ria()
        s=rs()
        cs1=[0]
        cs0=[0]
        ns1=0
        ns0=0
        for i in range(n):
            if s[i]=='1':
                ns1+=1
            else:
                ns0+=1
            cs1.append(ns1)
            cs0.append(ns0)
        
        for i in range(q):
            l,r=ria()
            n1q=cs1[r]-cs1[l-1]
            n0q=cs0[r]-cs0[l-1]
            ans=0
            if n1q>0:
                ans+=f[n1q-1]
            if n0q>0:    
                ans+=(t[n1q]-1)*f[n0q-1]
            wi(ans%mod)
                
                    
                
        
        
            
                
        

            
        

               
            
        
              
                
        
        
            
        
        
            
            
        
        
                
                
                
                
            
        
        
            
           
        
            
                    

                                 
                
                
        

                
        
        
        
            
        
        
                
            
        
        
                    
        
        
        
            
                    
            

                
            
            
                
            
                
            
            
            
            
                
            
        
        
        
        
        
        
        
                    
        
        
        
                
                
        
            
            
            
        

                    
        
                
        
        
                        
        
                            

        

                
            
        

                
            
                    
                
                
        
        
         
        

                        
                            
                
        
                            
                    

                
            
        
                
            
                
        
        
        
                             
        
            
        
        
            
                        
                        
                    
            
        
        
        
        
        
                        
       

        
                           
        
        
        
            
        
        
        
                      

      
                            
            
        
        
            
            
            
            
            
        
        
        
            
        
        
        
            
        
        
        
        
            
            
        
        
        
        
        
        
        
                
                
                    
        
        
            
            
        
                
            
            
        
        
        
        
                
        
            
        
                
        
        
            
        
       
            

                
        
        
        
   
            
        
        
        
        
            
        
                
        
        
        
            
            
        
        
            
        
        

        
        
            
        
        
            
        
                        

        
        
            
     
        
        
            
        
        
                
            
        
        
        
                
            
        

            
             
        
            
        
        
        
                
        
            
        
        
        
        
                
        
        
            
        
        
        
        
                
        
    #<--Solving Area Ends
    endtime=datetime.datetime.now()
    time=(endtime-starttime).total_seconds()*1000
    if(os.path.exists('input.txt')):
        print("Time:",time,"ms")  
    
                
class FastReader(io.IOBase):
    newlines = 0

    def __init__(self, fd, chunk_size=1024 * 8):
        self._fd = fd
        self._chunk_size = chunk_size
        self.buffer = io.BytesIO()

    def read(self):
        while True:
            b = os.read(self._fd, max(os.fstat(self._fd).st_size, self._chunk_size))
            if not b:
                break
            ptr = self.buffer.tell()
            self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
        self.newlines = 0
        return self.buffer.read()

    def readline(self, size=-1):
        while self.newlines == 0:
            b = os.read(self._fd, max(os.fstat(self._fd).st_size, self._chunk_size if size == -1 else size))
            self.newlines = b.count(b"\n") + (not b)
            ptr = self.buffer.tell()
            self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
        self.newlines -= 1
        return self.buffer.readline()


class FastWriter(io.IOBase):

    def __init__(self, fd):
        self._fd = fd
        self.buffer = io.BytesIO()
        self.write = self.buffer.write

    def flush(self):
        os.write(self._fd, self.buffer.getvalue())
        self.buffer.truncate(0), self.buffer.seek(0)


class FastStdin(io.IOBase):
    def __init__(self, fd=0):
        self.buffer = FastReader(fd)
        self.read = lambda: self.buffer.read().decode("ascii")
        self.readline = lambda: self.buffer.readline().decode("ascii")


class FastStdout(io.IOBase):
    def __init__(self, fd=1):
        self.buffer = FastWriter(fd)
        self.write = lambda s: self.buffer.write(s.encode("ascii"))
        self.flush = self.buffer.flush


if __name__ == '__main__':
    sys.stdin = FastStdin()
    sys.stdout = FastStdout()
    main()