Problem: Little girl Susie accidentally found her elder brother's notebook. She has many things to do, more important than solving problems, but she found this problem too interesting, so she wanted to know its solution and decided to ask you about it. So, the problem statement is as follows.

Let's assume that we are given a connected weighted undirected graph G = (V, E) (here V is the set of vertices, E is the set of edges). The shortest-path tree from vertex u is such graph G1 = (V, E1) that is a tree with the set of edges E1 that is the subset of the set of edges of the initial graph E, and the lengths of the shortest paths from u to any vertex to G and to G1 are the same. 

You are given a connected weighted undirected graph G and vertex u. Your task is to find the shortest-path tree of the given graph from vertex u, the total weight of whose edges is minimum possible.

Input

The first line contains two numbers, n and m (1 ≤ n ≤ 3·105, 0 ≤ m ≤ 3·105) — the number of vertices and edges of the graph, respectively.

Next m lines contain three integers each, representing an edge — ui, vi, wi — the numbers of vertices connected by an edge and the weight of the edge (ui ≠ vi, 1 ≤ wi ≤ 109). It is guaranteed that graph is connected and that there is no more than one edge between any pair of vertices.

The last line of the input contains integer u (1 ≤ u ≤ n) — the number of the start vertex.

Output

In the first line print the minimum total weight of the edges of the tree.

In the next line print the indices of the edges that are included in the tree, separated by spaces. The edges are numbered starting from 1 in the order they follow in the input. You may print the numbers of the edges in any order.

If there are multiple answers, print any of them.

Examples

Input

3 3
1 2 1
2 3 1
1 3 2
3


Output

2
1 2 


Input

4 4
1 2 1
2 3 1
3 4 1
4 1 2
4


Output

4
2 3 4 

Note

In the first sample there are two possible shortest path trees:

  * with edges 1 – 3 and 2 – 3 (the total weight is 3); 
  * with edges 1 – 2 and 2 – 3 (the total weight is 2); 



And, for example, a tree with edges 1 – 2 and 1 – 3 won't be a shortest path tree for vertex 3, because the distance from vertex 3 to vertex 2 in this tree equals 3, and in the original graph it is 1.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
namespace minmax {
template <class T>
T max(T&& A) {
  return A;
}
template <class T>
T min(T&& A) {
  return A;
}
template <class T>
T max(T&& A, T&& B) {
  return A > B ? A : B;
}
template <class T>
T min(T&& A, T&& B) {
  return A < B ? A : B;
}
template <class T, class... Ts>
T max(T&& A, Ts&&... ts) {
  T B = max(ts...);
  return A > B ? A : B;
}
template <class T, class... Ts>
T min(T&& A, Ts&&... ts) {
  T B = min(ts...);
  return A < B ? A : B;
}
template <class T, class... Ts>
T chmax(T&& A, Ts&&... ts) {
  A = max(A, ts...);
  return A;
}
template <class T, class... Ts>
T chmin(T&& A, Ts&&... ts) {
  A = min(A, ts...);
  return A;
}
}  // namespace minmax
namespace input {
template <class T>
void re(T&& Xx) {
  cin >> Xx;
}
template <class T1, class T2>
void re(pair<T1, T2>& Pp) {
  re(Pp.first);
  re(Pp.second);
}
template <class T>
void re(vector<T>& Aa) {
  for (int i = 0; i < (int)(Aa).size(); i++) re(Aa[i]);
}
template <class T1, class T2>
void rea(T1&& Aa, T2 t) {
  for (int i = 0; i < t; i++) re(Aa[i]);
}
template <class T1, class T2, class... Ts>
void rea(T1&& Aa, T2 t, Ts&&... ts) {
  rea(Aa, t);
  rea(ts...);
}
template <class T1, class T2>
void rea1(T1&& Aa, T2 t) {
  for (int i = 1; i <= t; i++) re(Aa[i]);
}
template <class T1, class T2, class... Ts>
void rea1(T1&& Aa, T2 t, Ts&... ts) {
  rea1(Aa, t);
  rea1(ts...);
}
template <class T, class... Ts>
void re(T&& t, Ts&... ts) {
  re(t);
  re(ts...);
}
}  // namespace input
namespace output {
void pr(int Xx) { cout << Xx; }
void pr(bool Xx) { cout << Xx; }
void pr(long long Xx) { cout << Xx; }
void pr(long long unsigned Xx) { cout << Xx; }
void pr(double Xx) { cout << Xx; }
void pr(char Xx) { cout << Xx; }
void pr(const string& Xx) { cout << Xx; }
void pr(const char* Xx) { cout << Xx; }
void pr(const char* Xx, size_t len) { cout << string(Xx, len); }
void ps() { cout << "\n"; }
void pn() {}
void pw() { pr(" "); }
void pc() {
  pr("]");
  ps();
}
template <class T1, class T2>
void pr(const pair<T1, T2>& Xx) {
  pr(Xx.first);
  pw();
  pr(Xx.second);
}
template <class T>
void pr(const T&);
bool parse(const char* t) {
  if (t == "\n") return true;
  return false;
}
template <class T>
bool parse(T&& t) {
  return false;
}
template <class T1, class T2>
bool parsepair(const pair<T1, T2>& Xx) {
  return true;
}
template <class T>
bool parsepair(T&& t) {
  return false;
}
template <class T1, class T2>
void psa(T1&& Aa, T2 t) {
  for (int i = 0; i < t; i++) pr(Aa[i]), pw();
  ps();
}
template <class T1, class T2>
void pna(T1&& Aa, T2 t) {
  for (int i = 0; i < t; i++) pr(Aa[i]), ps();
}
template <class T1, class T2>
void psa2(T1&& Aa, T2 t1, T2 t2) {
  for (int i = 0; i < t1; i++) {
    for (int j = 0; j < t2; j++) pr(Aa[i][j]), pw();
    ps();
  }
}
template <class T>
void pr(const T& Xx) {
  if (!(int)(Xx).size()) return;
  bool fst = 1;
  bool op = 0;
  if (parsepair(*Xx.begin())) op = 1;
  for (const auto& Aa : Xx) {
    if (!fst) pw();
    if (op) pr("{");
    pr(Aa), fst = 0;
    if (op) pr("}");
  }
}
template <class T, class... Ts>
void pr(const T& t, const Ts&... ts) {
  pr(t);
  pr(ts...);
}
template <class T, class... Ts>
void ps(const T& t, const Ts&... ts) {
  pr(t);
  if (sizeof...(ts)) {
    if (!parse(t)) pw();
  }
  ps(ts...);
}
template <class T>
void pn(const T& t) {
  for (const auto& Aa : t) ps(Aa);
}
template <class T, class... Ts>
void pw(const T& t, const Ts&... ts) {
  pr(t);
  if (sizeof...(ts)) pw();
  pw(ts...);
}
template <class T, class... Ts>
void pc(const T& t, const Ts&... ts) {
  bool op = 0;
  if (parsepair(t)) op = 1;
  if (op) pr("{");
  pr(t);
  if (op) pr("}");
  if (sizeof...(ts)) pr(", ");
  pc(ts...);
}
namespace trace {
template <class T1, class T2>
void __f(const char* name, const T1& Xx, const T2& y) {
  pr("[", y, "] = ");
  ps(Xx);
}
template <class T1, class T2, class... Ts>
void __f(const char* name, const T1& Xx, const T2& y, const Ts&... rest) {
  const char* open = strchr(name, '[');
  pr("[", y, "]");
  __f(open + 1, Xx, rest...);
}
template <class T1, class T2, class... Ts>
void __f0(const char* name, const T1& Xx, const T2& y, const Ts&... rest) {
  const char* open = strchr(name, '[');
  pr(name, size_t(open - name));
  __f(name, Xx, y, rest...);
}
template <class T>
void __fn(int n, const char* name, const T& Xx) {
  for (int i = 0; i < n; i++) pr(name), __f(name, Xx[i], i);
}
}  // namespace trace
}  // namespace output
using namespace minmax;
using namespace input;
using namespace output;
using namespace output::trace;
using pii = pair<long long, long long>;
const long long N = 3e5 + 5;
long long n, m, wt, d[N], p[N];
set<pair<long long, pii>> g[N];
vector<long long> ans;
void makeG() {
  for (long long i = 0; i < m; i++) {
    long long u, v, w;
    re(u, v, w);
    u--, v--;
    g[u].insert(make_pair(v, make_pair(w, i + 1)));
    g[v].insert(make_pair(u, make_pair(w, i + 1)));
  }
}
void dijkstra(long long root) {
  long long i;
  set<pii> q;
  memset(p, -1, sizeof(p));
  for (i = 0; i < n; i++) d[i] = 1000000000000000000;
  d[root] = 0;
  q.insert({0, root});
  while (!q.empty()) {
    auto v = *q.begin();
    q.erase(q.begin());
    for (auto& x : g[v.second]) {
      bool equal = (d[x.first] == (d[v.second] + x.second.first)) and
                   (d[v.second] < d[x.first]);
      if (equal or (d[x.first] > d[v.second] + x.second.first)) {
        q.erase({d[x.first], x.first});
        d[x.first] = d[v.second] + x.second.first;
        q.insert({d[x.first], x.first});
        p[x.first] = v.second;
      }
    }
  }
  for (i = 0; i < n; i++) assert(d[i] < 1000000000000000000);
}
int32_t main() {
  ios::sync_with_stdio(0);
  cin.tie(0);
  cout.tie(0);
  ;
  long long i, root;
  re(n, m);
  makeG();
  re(root);
  dijkstra(--root);
  for (i = 0; i < n; i++) {
    if (~p[i]) {
      auto it = g[i].lower_bound(make_pair(p[i], make_pair(-1, -1)));
      ans.emplace_back(it->second.second);
      wt += it->second.first;
      p[i] = -1;
    }
  }
  ps(wt, "\n", ans);
  return 0;
}