Problem: Asterix, Obelix and their temporary buddies Suffix and Prefix has finally found the Harmony temple. However, its doors were firmly locked and even Obelix had no luck opening them.

A little later they found a string s, carved on a rock below the temple's gates. Asterix supposed that that's the password that opens the temple and read the string aloud. However, nothing happened. Then Asterix supposed that a password is some substring t of the string s.

Prefix supposed that the substring t is the beginning of the string s; Suffix supposed that the substring t should be the end of the string s; and Obelix supposed that t should be located somewhere inside the string s, that is, t is neither its beginning, nor its end.

Asterix chose the substring t so as to please all his companions. Besides, from all acceptable variants Asterix chose the longest one (as Asterix loves long strings). When Asterix read the substring t aloud, the temple doors opened. 

You know the string s. Find the substring t or determine that such substring does not exist and all that's been written above is just a nice legend.

Input

You are given the string s whose length can vary from 1 to 106 (inclusive), consisting of small Latin letters.

Output

Print the string t. If a suitable t string does not exist, then print "Just a legend" without the quotes.

Examples

Input

fixprefixsuffix


Output

fix

Input

abcdabc


Output

Just a legend

Solution (in PYTHON3):

Solution:
s = input()
n = len(s)
m = [0]*(n+1)
z = [0]*(n+1)
l = 0
r = 0
flag = 0

for i  in range(1,n):
    if(i<=r):
        z[i] = min(r-i+1,z[i-l]);
    while(i+z[i] < n  and s[z[i]]==s[i+z[i]]):
        z[i] += 1
    if(i+z[i]-1>r):
        l = i
        r = i+z[i]-1
    m[z[i]]+=1

for i in range(n-1,-1,-1):
    m[i] += m[i+1]
    
for i in range(1,n):
    if(i+z[i]==n and m[z[i]]>1):
        print(s[0:z[i]])
        flag = 1
        break

if(flag==0):
    print("Just a legend")