Problem: Asterix, Obelix and their temporary buddies Suffix and Prefix has finally found the Harmony temple. However, its doors were firmly locked and even Obelix had no luck opening them.

A little later they found a string s, carved on a rock below the temple's gates. Asterix supposed that that's the password that opens the temple and read the string aloud. However, nothing happened. Then Asterix supposed that a password is some substring t of the string s.

Prefix supposed that the substring t is the beginning of the string s; Suffix supposed that the substring t should be the end of the string s; and Obelix supposed that t should be located somewhere inside the string s, that is, t is neither its beginning, nor its end.

Asterix chose the substring t so as to please all his companions. Besides, from all acceptable variants Asterix chose the longest one (as Asterix loves long strings). When Asterix read the substring t aloud, the temple doors opened. 

You know the string s. Find the substring t or determine that such substring does not exist and all that's been written above is just a nice legend.

Input

You are given the string s whose length can vary from 1 to 106 (inclusive), consisting of small Latin letters.

Output

Print the string t. If a suitable t string does not exist, then print "Just a legend" without the quotes.

Examples

Input

fixprefixsuffix


Output

fix

Input

abcdabc


Output

Just a legend

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int main() {
  {
    ios::sync_with_stdio(false);
    cin.tie(NULL);
    cout.tie(NULL);
  };
  string s;
  cin >> s;
  int n = s.size();
  vector<int> p(n);
  p[0] = 0;
  for (int i = 1; i < n; i++) {
    int a = p[i - 1];
    while (a > 0 && s[i] != s[a]) {
      a = p[a - 1];
    }
    if (s[a] == s[i]) a++;
    p[i] = a;
  }
  if (p[n - 1] == 0)
    cout << "Just a legend" << endl;
  else {
    int boo = 0;
    for (int i = 0; i < n - 1; i++) {
      if (p[i] == p[n - 1]) boo = 1;
    }
    if (boo)
      cout << s.substr(0, p[n - 1]) << endl;
    else {
      if (p[p[n - 1] - 1] == 0)
        cout << "Just a legend" << endl;
      else {
        cout << s.substr(0, p[p[n - 1] - 1]) << endl;
      }
    }
  }
  return 0;
}