Problem: <image>

Input

The input contains two integers a1, a2 (0 ≤ ai ≤ 32), separated by a single space.

Output

Output a single integer.

Examples

Input

1 1


Output

0


Input

3 7


Output

0


Input

13 10


Output

1

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int main() {
  string ans = "";
  ans = "111111101010101111100101001111111";
  ans.append("100000100000000001010110001000001");
  ans.append("101110100110110000011010001011101");
  ans.append("101110101011001001111101001011101");
  ans.append("101110101100011000111100101011101");
  ans.append("100000101010101011010000101000001");
  ans.append("111111101010101010101010101111111");
  ans.append("000000001111101111100111100000000");
  ans.append("100010111100100001011110111111001");
  ans.append("110111001111111100100001000101100");
  ans.append("011100111010000101000111010001010");
  ans.append("011110000110001111110101100000011");
  ans.append("111111111111111000111001001011000");
  ans.append("111000010111010011010011010100100");
  ans.append("101010100010110010110101010000010");
  ans.append("101100000101010001111101000000000");
  ans.append("000010100011001101000111101011010");
  ans.append("101001001111101111000101010001110");
  ans.append("101101111111000100100001110001000");
  ans.append("000010011000100110000011010000010");
  ans.append("001101101001101110010010011011000");
  ans.append("011101011010001000111101010100110");
  ans.append("111010100110011101001101000001110");
  ans.append("110001010010101111000101111111000");
  ans.append("001000111011100001010110111110000");
  ans.append("000000001110010110100010100010110");
  ans.append("111111101000101111000110101011010");
  ans.append("100000100111010101111100100011011");
  ans.append("101110101001010000101000111111000");
  ans.append("101110100011010010010111111011010");
  ans.append("101110100100011011110110101110000");
  ans.append("100000100110011001111100111100000");
  ans.append("111111101101000101001101110010001");
  int a, b;
  cin >> a >> b;
  cout << ans[a * 33 + b] << endl;
}