Problem: There is a polyline going through points (0, 0) – (x, x) – (2x, 0) – (3x, x) – (4x, 0) – ... - (2kx, 0) – (2kx + x, x) – .... 

We know that the polyline passes through the point (a, b). Find minimum positive value x such that it is true or determine that there is no such x.

Input

Only one line containing two positive integers a and b (1 ≤ a, b ≤ 109).

Output

Output the only line containing the answer. Your answer will be considered correct if its relative or absolute error doesn't exceed 10 - 9. If there is no such x then output  - 1 as the answer.

Examples

Input

3 1


Output

1.000000000000


Input

1 3


Output

-1


Input

4 1


Output

1.250000000000

Note

You can see following graphs for sample 1 and sample 3. 

<image> <image>

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int main() {
  long long int a, b;
  cin >> a >> b;
  long long int temp = b;
  double x, ans = 10000000001, d = 2;
  if (b > a) {
    cout << "-1" << endl;
    return 0;
  }
  d = (a + b) / b;
  d = (int)d;
  if ((int)d % 2 != 0) d = d - 1;
  x = (a + b) / (d);
  if (x >= temp && x > 0) {
    if (ans > x) ans = x;
  }
  d = (a - b) / b;
  d = (int)d;
  if ((int)d % 2 != 0) d = d - 1.0;
  x = (a - b) / d;
  if (x >= temp && x > 0) {
    if (ans > x) ans = x;
  }
  if (ans == 10000000001)
    cout << "-1" << endl;
  else {
    cout << fixed;
    cout << setprecision(12) << ans << endl;
  }
  return 0;
}