Problem: Let's call a positive integer composite if it has at least one divisor other than 1 and itself. For example:

  * the following numbers are composite: 1024, 4, 6, 9; 
  * the following numbers are not composite: 13, 1, 2, 3, 37. 



You are given a positive integer n. Find two composite integers a,b such that a-b=n.

It can be proven that solution always exists.

Input

The input contains one integer n (1 ≤ n ≤ 10^7): the given integer.

Output

Print two composite integers a,b (2 ≤ a, b ≤ 10^9, a-b=n).

It can be proven, that solution always exists.

If there are several possible solutions, you can print any. 

Examples

Input


1


Output


9 8


Input


512


Output


4608 4096

Solution (in PYTHON3):

Solution:
#!/usr/bin/env python3
import sys
import math
#lines = stdin.readlines()
def rint():
    return map(int, sys.stdin.readline().split())

def input():
    return sys.stdin.readline().rstrip('\n')

def oint():
    return int(input())

def check_prime(num):
    if all(num%i !=0 for i in range(2, int(math.sqrt(num))+1)):
        return 1
    else:
        return 0

n = oint()

if n %2 == 0:
    print(n+4, 4)
else:
    print(n+9, 9)