Problem: You are given two strings s and t consisting of small Latin letters, string s can also contain '?' characters. 

Suitability of string s is calculated by following metric:

Any two letters can be swapped positions, these operations can be performed arbitrary number of times over any pair of positions. Among all resulting strings s, you choose the one with the largest number of non-intersecting occurrences of string t. Suitability is this number of occurrences.

You should replace all '?' characters with small Latin letters in such a way that the suitability of string s is maximal.

Input

The first line contains string s (1 ≤ |s| ≤ 106).

The second line contains string t (1 ≤ |t| ≤ 106).

Output

Print string s with '?' replaced with small Latin letters in such a way that suitability of that string is maximal.

If there are multiple strings with maximal suitability then print any of them.

Examples

Input

?aa?
ab


Output

baab


Input

??b?
za


Output

azbz


Input

abcd
abacaba


Output

abcd

Note

In the first example string "baab" can be transformed to "abab" with swaps, this one has suitability of 2. That means that string "baab" also has suitability of 2.

In the second example maximal suitability you can achieve is 1 and there are several dozens of such strings, "azbz" is just one of them.

In the third example there are no '?' characters and the suitability of the string is 0.

Solution (in PYTHON3):

Solution:
#!/usr/bin/env python3

def solve():
    s = list(get(str))
    t = get(str)

    smap = collections.Counter(s)
    tmap = collections.Counter(t)

    alphabet = set(tmap)

    suit = min(smap[a] // tmap[a] for a in alphabet if tmap[a] > 0)

    for a in alphabet:
        smap[a] -= suit * tmap[a]

    def getchar():
        while True:
            for a in alphabet:
                while tmap[a] > smap[a]:
                    yield a
                    smap[a] += 1
                smap[a] -= tmap[a]
            

    gen = getchar()
    for i, a in enumerate(s):
        if a == '?':
            s[i] = gen.__next__()
    return ''.join(s)










_testcases = """
?aa?
ab

baab

??b?
za

azbz

abcd
abacaba

abcd


""".strip()

# ======================= B O I L E R P L A T E ======================= #
# Practicality beats purity

import re
import sys
import math
import heapq
from heapq import heapify, heappop, heappush
import bisect
import string
from bisect import bisect_left, bisect_right
import operator
from operator import itemgetter, attrgetter
import itertools
import collections

inf = float('inf')
sys.setrecursionlimit(10000)


def tree():
    return collections.defaultdict(tree)


def cache(func):  # Decorator for memoizing a function
    cache_dict = {}

    def _cached_func(*args, _get_cache=False):
        if _get_cache:
            return cache_dict
        if args in cache_dict:
            return cache_dict[args]
        cache_dict[args] = func(*args)
        return cache_dict[args]
    return _cached_func


def equal(x, y, epsilon=1e-6):
    # https://code.google.com/codejam/kickstart/resources/faq#real-number-behavior
    if -epsilon <= x - y <= epsilon:
        return True
    if -epsilon <= x <= epsilon or -epsilon <= y <= epsilon:
        return False
    return (-epsilon <= (x - y) / x <= epsilon or -epsilon <= (x - y) / y <= epsilon)


def get(_type):  # For easy input
    if type(_type) == list:
        if len(_type) == 1:
            _type = _type[0]
            return list(map(_type, input().strip().split()))
        else:
            return [_type[i](inp) for i, inp in enumerate(input().strip().split())]
    else:
        return _type(input().strip())

if __name__ == '__main__':
    print(solve())