Problem: For given two segments s1 and s2, print the distance between them.

s1 is formed by end points p0 and p1, and s2 is formed by end points p2 and p3.

Constraints

* 1 ≤ q ≤ 1000
* -10000 ≤ xpi, ypi ≤ 10000
* p0 ≠ p1 and p2 ≠ p3.

Input

The entire input looks like:


q (the number of queries)
1st query
2nd query
...
qth query


Each query consists of integer coordinates of end points of s1 and s2 in the following format:


xp0 yp0 xp1 yp1 xp2 yp2 xp3 yp3


Output

For each query, print the distance. The output values should be in a decimal fraction with an error less than 0.00000001.

Example

Input

3
0 0 1 0 0 1 1 1
0 0 1 0 2 1 1 2
-1 0 1 0 0 1 0 -1


Output

1.0000000000
1.4142135624
0.0000000000

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
template<class T> using vec = vector<T>;
template<class T> using vvec = vector<vec<T>>;
using R = double;
using P = complex<R>;
#define x real()
#define y imag()
const R eps = 1e-9,PI = acos(-1);

bool equal(R a,R b){return abs(b-a)<eps;}
bool equal0(R a){return equal(a,0.0);}

P operator*(const P& p,const R& d){
    return P(p.x*d,p.y*d);
}

istream &operator>>(istream& is,P& p){
    R a,b;
    is >> a >> b;
    p = P(a,b);
    return is;
}

ostream &operator<<(ostream& os,P& p){
    os << fixed << setprecision(10) << p.real() << " " << p.imag();
}
//内積
double dot(P a,P b) {return (conj(a)*b).real();}
//外積
double cross(P a,P b) {return (conj(a)*b).imag();}

struct L{
    P a,b;
    L(P a,P b):a(a),b(b){}
    L(R A,R B,R C){
        if(equal(A,0)) a = P(0,C/B),b = P(1,C/B);
        else if(equal(B,0)) b = P(C/A,0),b = P(C/A,1);
        else a = P(0,C/B),b = P(C/A,0);
    }
};

//pをbに射影
P projection(P p,P b) {return b*dot(p,b)/norm(b);}

//pとp1 to p2 に射影
P projection(L l,P p){
    p -= l.a; l.b -= l.a;
    P proj = projection(p,l.b);
    return l.a+proj;
}

struct S:L{
    S(P a,P b):L(a,b){}
};

//点の回転方向を判定
int ccw(P p0,P p1,P p2){
    p1 -= p0,p2 -= p0;
    if(cross(p1,p2)>eps) return 1; //"COUNTER_CLOCKWISE"
    if(cross(p1,p2)<-eps) return -1; //"CLOCKWISE"
    if(dot(p1,p2)<0) return 2; //"ONLINE_BACK"
    if(norm(p1)<norm(p2)) return -2; //"ONLINE_FRONT"
    return 0; //"ON_SEGMENT"
}

bool is_parallel(L l1,L l2){
    return equal0(cross(l1.b-l1.a,l2.b-l2.a));
}

bool is_orthogonal(L l1,L l2){
    return equal0(dot(l1.b-l1.a,l2.b-l2.a));
}

//pをlに関して対称移動
P reflection(L l,P p){
    P pj = projection(l,p);
    return 2.0*pj-p;
}

//pがl上にあるか
bool is_online(L l,P p){
    return abs(ccw(l.a,l.b,p))!=1;
}

bool is_onsegment(S s,P p){
    return ccw(s.a,s.b,p)==0;
}

//線分の交差判定
bool intersect(S s,S t){
    return ccw(s.a,s.b,t.a)*ccw(s.a,s.b,t.b)<=0 && ccw(t.a,t.b,s.a)*ccw(t.a,t.b,s.b)<=0;
}

//2直線の交点
P crosspoint(L l1,L l2){
    R a = cross(l1.b-l1.a,l2.b-l2.a);
    R b = cross(l1.b-l1.a,l1.b-l2.a);
    if(equal0(abs(a)) && equal0(abs(b))) return l2.a;
    return l2.a+(l2.b-l2.a)*b/a;
}

P crosspoint(S s1, S s2){
    return crosspoint(L(s1),L(s2));
}

R dist(P a,P b){
    return abs(a-b);
}

R dist(L l,P p){
    return abs(p-projection(l,p));
}

R dist(L l1,L l2){
    return is_parallel(l1,l2)? 0:dist(l1,l2.a);
}

R dist(S s,P p){
    P r = projection(s,p);
    if(is_onsegment(s,r)) return abs(r-p);
    return min(dist(s.a,p),dist(s.b,p));
}

R dist (S s1,S s2){
    if(intersect(s1,s2)) return 0;
    return min({dist(s1,s2.a),dist(s1,s2.b),
    dist(s2,s1.a),dist(s2,s1.b)});
}

int main(){
    int Q;
    cin >> Q;
    for(int i=0;i<Q;i++){
        P p1,p2,p3,p4;
        cin >> p1 >> p2 >> p3 >> p4;
        R d = dist(S(p1,p2),S(p3,p4));
        cout << fixed << setprecision(10) << d << endl;
    }
}