Problem: Asterix, Obelix and their temporary buddies Suffix and Prefix has finally found the Harmony temple. However, its doors were firmly locked and even Obelix had no luck opening them.

A little later they found a string s, carved on a rock below the temple's gates. Asterix supposed that that's the password that opens the temple and read the string aloud. However, nothing happened. Then Asterix supposed that a password is some substring t of the string s.

Prefix supposed that the substring t is the beginning of the string s; Suffix supposed that the substring t should be the end of the string s; and Obelix supposed that t should be located somewhere inside the string s, that is, t is neither its beginning, nor its end.

Asterix chose the substring t so as to please all his companions. Besides, from all acceptable variants Asterix chose the longest one (as Asterix loves long strings). When Asterix read the substring t aloud, the temple doors opened. 

You know the string s. Find the substring t or determine that such substring does not exist and all that's been written above is just a nice legend.

Input

You are given the string s whose length can vary from 1 to 106 (inclusive), consisting of small Latin letters.

Output

Print the string t. If a suitable t string does not exist, then print "Just a legend" without the quotes.

Examples

Input

fixprefixsuffix


Output

fix

Input

abcdabc


Output

Just a legend

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
string s;
int z[1000001];
void zAlgo() {
  int L = 0, R = 0;
  for (int i = 1; i < s.length(); i++) {
    if (i > R) {
      L = R = i;
      while (R < s.length() && s[R - L] == s[R]) R++;
      z[i] = R - L;
      R--;
    } else {
      int k = i - L;
      if (z[k] < R - i + 1)
        z[i] = z[k];
      else {
        L = i;
        while (R < s.length() && s[R - L] == s[R]) R++;
        z[i] = R - L;
        R--;
      }
    }
  }
}
void solution() {
  cin >> s;
  zAlgo();
  int maxz = 0, res = 0;
  for (int i = 1; i < s.length(); i++) {
    int n = s.length();
    if (z[i] == s.length() - i && maxz >= s.length() - i) {
      res = s.length() - i;
      break;
    }
    maxz = max(maxz, z[i]);
  }
  res ? cout << s.substr(0, res) : cout << "Just a legend";
}
int main() {
  double beg = clock();
  ios::sync_with_stdio(false);
  solution();
  return 0;
}