Problem: The statement of this problem is the same as the statement of problem C2. The only difference is that, in problem C1, n is always even, and in C2, n is always odd.

You are given a regular polygon with 2 ⋅ n vertices (it's convex and has equal sides and equal angles) and all its sides have length 1. Let's name it as 2n-gon.

Your task is to find the square of the minimum size such that you can embed 2n-gon in the square. Embedding 2n-gon in the square means that you need to place 2n-gon in the square in such way that each point which lies inside or on a border of 2n-gon should also lie inside or on a border of the square.

You can rotate 2n-gon and/or the square.

Input

The first line contains a single integer T (1 ≤ T ≤ 200) — the number of test cases.

Next T lines contain descriptions of test cases — one per line. Each line contains single even integer n (2 ≤ n ≤ 200). Don't forget you need to embed 2n-gon, not an n-gon.

Output

Print T real numbers — one per test case. For each test case, print the minimum length of a side of the square 2n-gon can be embedded in. Your answer will be considered correct if its absolute or relative error doesn't exceed 10^{-6}.

Example

Input


3
2
4
200


Output


1.000000000
2.414213562
127.321336469

Solution (in PYTHON3):

Solution:
import math
import sys
import collections

def set_debug(debug_mode=False):
    if debug_mode:
        fin = open('input.txt', 'r')
        sys.stdin = fin


if __name__ == '__main__':
    # set_debug(True)

    t = int(input())

    for ti in range(1, t + 1):
        n = int(input())

        n = 2 * n

        res = 1

        inner = (math.pi - (n-2) * math.pi / n)

        cur = 0.5

        for i in range((n-2)//4):
            cur += 1 * math.cos((i+1) * inner)

        the = math.pi / 2 - (n-2) * math.pi / n / 2

        res = 2 * cur * math.cos(the / 2)

        print(res)