Problem: Let's call a string "s-palindrome" if it is symmetric about the middle of the string. For example, the string "oHo" is "s-palindrome", but the string "aa" is not. The string "aa" is not "s-palindrome", because the second half of it is not a mirror reflection of the first half.

<image> English alphabet

You are given a string s. Check if the string is "s-palindrome".

Input

The only line contains the string s (1 ≤ |s| ≤ 1000) which consists of only English letters.

Output

Print "TAK" if the string s is "s-palindrome" and "NIE" otherwise.

Examples

Input

oXoxoXo


Output

TAK


Input

bod


Output

TAK


Input

ER


Output

NIE

Solution (in PYTHON3):

Solution:
#!/usr/bin/env python3

import sys


def main():
    s = stdin_get_string_from_first_line()

    mirrors = ['A', 'H', 'I', 'M', 'O', 'o', 'T', 'U', 'V', 'v', 'W', 'w', 'X', 'x', 'Y']

    l = len(s)

    if l % 2 != 0 and s[int(l/2)] not in mirrors:
        n()

    for i in range(0, int(l/2)):
        j = l - i - 1

        if s[i] == s[j] and s[i] in mirrors:
            continue

        if s[i] == 'b' and s[j] == 'd':
            continue

        if s[i] == 'd' and s[j] == 'b':
            continue

        if s[i] == 'p' and s[j] == 'q':
            continue

        if s[i] == 'q' and s[j] == 'p':
            continue

        n()

    y()


def stdin_get_string_from_first_line():
    return sys.stdin.readline().strip()


def y():
    print('TAK')
    exit()


def n():
    print('NIE')
    exit()


if __name__ == '__main__':
    main()