Problem: This is the hard version of the problem. The only difference between easy and hard versions is the constraint of m. You can make hacks only if both versions are solved.

Chiori loves dolls and now she is going to decorate her bedroom!

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As a doll collector, Chiori has got n dolls. The i-th doll has a non-negative integer value a_i (a_i < 2^m, m is given). Chiori wants to pick some (maybe zero) dolls for the decoration, so there are 2^n different picking ways.

Let x be the bitwise-xor-sum of values of dolls Chiori picks (in case Chiori picks no dolls x = 0). The value of this picking way is equal to the number of 1-bits in the binary representation of x. More formally, it is also equal to the number of indices 0 ≤ i < m, such that \left⌊ (x)/(2^i) \right⌋ is odd.

Tell her the number of picking ways with value i for each integer i from 0 to m. Due to the answers can be very huge, print them by modulo 998 244 353.

Input

The first line contains two integers n and m (1 ≤ n ≤ 2 ⋅ 10^5, 0 ≤ m ≤ 53) — the number of dolls and the maximum value of the picking way.

The second line contains n integers a_1, a_2, …, a_n (0 ≤ a_i < 2^m) — the values of dolls.

Output

Print m+1 integers p_0, p_1, …, p_m — p_i is equal to the number of picking ways with value i by modulo 998 244 353.

Examples

Input


4 4
3 5 8 14


Output


2 2 6 6 0 

Input


6 7
11 45 14 9 19 81


Output


1 2 11 20 15 10 5 0 

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
template <class t, class u>
void chmax(t& first, u second) {
  if (first < second) first = second;
}
template <class t, class u>
void chmin(t& first, u second) {
  if (second < first) first = second;
}
template <class t>
using vc = vector<t>;
template <class t>
using vvc = vc<vc<t>>;
using pi = pair<ll, ll>;
using vi = vc<ll>;
template <class t, class u>
ostream& operator<<(ostream& os, const pair<t, u>& p) {
  return os << "{" << p.first << "," << p.second << "}";
}
template <class t>
ostream& operator<<(ostream& os, const vc<t>& v) {
  os << "{";
  for (auto e : v) os << e << ",";
  return os << "}";
}
using uint = unsigned;
using ull = unsigned long long;
template <class t, size_t n>
ostream& operator<<(ostream& os, const array<t, n>& first) {
  return os << vc<t>(first.begin(), first.end());
}
template <ll i, class T>
void print_tuple(ostream&, const T&) {}
template <ll i, class T, class H, class... Args>
void print_tuple(ostream& os, const T& t) {
  if (i) os << ",";
  os << get<i>(t);
  print_tuple<i + 1, T, Args...>(os, t);
}
template <class... Args>
ostream& operator<<(ostream& os, const tuple<Args...>& t) {
  os << "{";
  print_tuple<0, tuple<Args...>, Args...>(os, t);
  return os << "}";
}
template <class t>
void print(t x, ll suc = 1) {
  cout << x;
  if (suc == 1) cout << "\n";
  if (suc == 2) cout << " ";
}
ll read() {
  ll i;
  cin >> i;
  return i;
}
vi readvi(ll n, ll off = 0) {
  vi v(n);
  for (ll i = ll(0); i < ll(n); i++) v[i] = read() + off;
  return v;
}
template <class T>
void print(const vector<T>& v, ll suc = 1) {
  for (ll i = ll(0); i < ll(v.size()); i++)
    print(v[i], i == ll(v.size()) - 1 ? suc : 2);
}
string readString() {
  string s;
  cin >> s;
  return s;
}
template <class T>
T sq(const T& t) {
  return t * t;
}
void yes(bool ex = true) {
  cout << "Yes"
       << "\n";
  if (ex) exit(0);
}
void no(bool ex = true) {
  cout << "No"
       << "\n";
  if (ex) exit(0);
}
void possible(bool ex = true) {
  cout << "Possible"
       << "\n";
  if (ex) exit(0);
}
void impossible(bool ex = true) {
  cout << "Impossible"
       << "\n";
  if (ex) exit(0);
}
constexpr ll ten(ll n) { return n == 0 ? 1 : ten(n - 1) * 10; }
const ll infLL = LLONG_MAX / 3;
const ll inf = infLL;
ll topbit(signed t) { return t == 0 ? -1 : 31 - __builtin_clz(t); }
ll topbit(ll t) { return t == 0 ? -1 : 63 - __builtin_clzll(t); }
ll botbit(signed first) { return first == 0 ? 32 : __builtin_ctz(first); }
ll botbit(ll first) { return first == 0 ? 64 : __builtin_ctzll(first); }
ll popcount(signed t) { return __builtin_popcount(t); }
ll popcount(ll t) { return __builtin_popcountll(t); }
bool ispow2(ll i) { return i && (i & -i) == i; }
ll mask(ll i) { return (ll(1) << i) - 1; }
bool inc(ll first, ll second, ll c) { return first <= second && second <= c; }
template <class t>
void mkuni(vc<t>& v) {
  sort(v.begin(), v.end());
  v.erase(unique(v.begin(), v.end()), v.end());
}
ll rand_int(ll l, ll r) {
  static mt19937_64 gen(chrono::steady_clock::now().time_since_epoch().count());
  return uniform_int_distribution<ll>(l, r)(gen);
}
template <class t>
void myshuffle(vc<t>& first) {
  for (ll i = ll(0); i < ll(ll(first.size())); i++)
    swap(first[i], first[rand_int(0, i)]);
}
template <class t>
ll lwb(const vc<t>& v, const t& first) {
  return lower_bound(v.begin(), v.end(), first) - v.begin();
}
struct modinfo {
  uint mod, root;
};
template <modinfo const& ref>
struct modular {
  static constexpr uint const& mod = ref.mod;
  static modular root() { return modular(ref.root); }
  uint v;
  modular(ll vv = 0) { s(vv % mod + mod); }
  modular& s(uint vv) {
    v = vv < mod ? vv : vv - mod;
    return *this;
  }
  modular operator-() const { return modular() - *this; }
  modular& operator+=(const modular& rhs) { return s(v + rhs.v); }
  modular& operator-=(const modular& rhs) { return s(v + mod - rhs.v); }
  modular& operator*=(const modular& rhs) {
    v = ull(v) * rhs.v % mod;
    return *this;
  }
  modular& operator/=(const modular& rhs) { return *this *= rhs.inv(); }
  modular operator+(const modular& rhs) const { return modular(*this) += rhs; }
  modular operator-(const modular& rhs) const { return modular(*this) -= rhs; }
  modular operator*(const modular& rhs) const { return modular(*this) *= rhs; }
  modular operator/(const modular& rhs) const { return modular(*this) /= rhs; }
  modular pow(ll n) const {
    modular res(1), x(*this);
    while (n) {
      if (n & 1) res *= x;
      x *= x;
      n >>= 1;
    }
    return res;
  }
  modular inv() const { return pow(mod - 2); }
  friend modular operator+(ll x, const modular& y) { return modular(x) + y; }
  friend modular operator-(ll x, const modular& y) { return modular(x) - y; }
  friend modular operator*(ll x, const modular& y) { return modular(x) * y; }
  friend modular operator/(ll x, const modular& y) { return modular(x) / y; }
  friend ostream& operator<<(ostream& os, const modular& m) {
    return os << m.v;
  }
  friend istream& operator>>(istream& is, modular& m) {
    ll x;
    is >> x;
    m = modular(x);
    return is;
  }
  bool operator<(const modular& r) const { return v < r.v; }
  bool operator==(const modular& r) const { return v == r.v; }
  bool operator!=(const modular& r) const { return v != r.v; }
  explicit operator bool() const { return v; }
};
template <class mint>
vi sweep(vvc<mint>& first, ll c = -1) {
  if (first.empty()) return {};
  if (c == -1) c = first[0].size();
  ll h = first.size(), w = first[0].size(), r = 0;
  vi res;
  for (ll i = ll(0); i < ll(c); i++) {
    if (r == h) break;
    for (ll j = ll(r); j < ll(h); j++)
      if (first[j][i].v) {
        swap(first[r], first[j]);
        break;
      }
    if (first[r][i].v == 0) continue;
    for (ll j = ll(0); j < ll(h); j++)
      if (j != r) {
        mint z = -first[j][i] / first[r][i];
        for (ll k = ll(i); k < ll(w); k++) first[j][k] += first[r][k] * z;
      }
    res.push_back(i);
    r++;
  }
  return res;
}
template <class mint>
vvc<mint> kernel(const vvc<mint>& first, ll w) {
  ll h = first.size();
  vvc<mint> second(w, vc<mint>(h + w));
  for (ll i = ll(0); i < ll(h); i++)
    for (ll j = ll(0); j < ll(w); j++) second[j][i] = first[i][j];
  for (ll i = ll(0); i < ll(w); i++) second[i][h + i] = 1;
  ll r = sweep(second, h).size();
  vvc<mint> res;
  for (ll i = ll(r); i < ll(w); i++)
    res.emplace_back(second[i].begin() + h, second[i].end());
  return res;
}
extern constexpr modinfo base{998244353, 3};
extern constexpr modinfo base2{2, 1};
using mint = modular<base>;
const ll vmax = (1 << 21) + 10;
mint fact[vmax], finv[vmax], invs[vmax];
void initfact() {
  fact[0] = 1;
  for (ll i = ll(1); i < ll(vmax); i++) {
    fact[i] = fact[i - 1] * i;
  }
  finv[vmax - 1] = fact[vmax - 1].inv();
  for (ll i = vmax - 2; i >= 0; i--) {
    finv[i] = finv[i + 1] * (i + 1);
  }
  for (ll i = vmax - 1; i >= 1; i--) {
    invs[i] = finv[i] * fact[i - 1];
  }
}
mint choose(ll n, ll k) { return fact[n] * finv[n - k] * finv[k]; }
mint binom(ll first, ll second) {
  return fact[first + second] * finv[first] * finv[second];
}
mint catalan(ll n) {
  return binom(n, n) - (n - 1 >= 0 ? binom(n - 1, n + 1) : 0);
}
vc<mint> getfreq(ll m, vi first) {
  ll n = ll(first.size());
  vc<mint> res(m + 1);
  ll cur = 0;
  for (ll bit = ll(0); bit < ll(1 << n); bit++) {
    for (ll j = ll(0); j < ll(n); j++)
      if ((bit ^ (bit - 1)) & 1 << j)
        cur ^= first[j];
      else
        break;
    res[popcount(cur)] += 1;
  }
  return res;
}
signed main() {
  cin.tie(0);
  ios::sync_with_stdio(0);
  cout << fixed << setprecision(20);
  ll n, m;
  cin >> n >> m;
  vi first;
  ll cnt = 0;
  for (ll _ = ll(0); _ < ll(n); _++) {
    ll x;
    cin >> x;
    for (auto v : first) chmin(x, x ^ v);
    if (x)
      first.push_back(x);
    else
      cnt++;
  }
  vc<mint> ans(m + 1);
  if (ll(first.size()) <= m / 2) {
    void(0);
    ans = getfreq(m, first);
  } else {
    void(0);
    initfact();
    using mint2 = modular<base2>;
    vvc<mint2> vs(ll(first.size()), vc<mint2>(m));
    for (ll i = ll(0); i < ll(ll(first.size())); i++)
      for (ll j = ll(0); j < ll(m); j++) vs[i][j] = (first[i] >> j) & 1;
    auto ker = kernel(vs, m);
    vi second(ll(ker.size()));
    for (ll i = ll(0); i < ll(ll(ker.size())); i++)
      for (ll j = ll(0); j < ll(m); j++) second[i] += ll(ker[i][j].v) << j;
    auto z = getfreq(m, second);
    for (ll i = ll(0); i < ll(m + 1); i++) {
      for (ll c = ll(0); c < ll(i + 1); c++)
        for (ll d = ll(0); d < ll(m - i + 1); d++) {
          mint w = z[i] * choose(i, c) * choose(m - i, d);
          if (c & 1) w = -w;
          ans[c + d] += w;
        }
    }
    for (auto& v : ans) v /= mint(2).pow(m - ll(first.size()));
  }
  for (auto& v : ans) v *= mint(2).pow(cnt);
  print(ans);
}