Problem: Asterix, Obelix and their temporary buddies Suffix and Prefix has finally found the Harmony temple. However, its doors were firmly locked and even Obelix had no luck opening them.

A little later they found a string s, carved on a rock below the temple's gates. Asterix supposed that that's the password that opens the temple and read the string aloud. However, nothing happened. Then Asterix supposed that a password is some substring t of the string s.

Prefix supposed that the substring t is the beginning of the string s; Suffix supposed that the substring t should be the end of the string s; and Obelix supposed that t should be located somewhere inside the string s, that is, t is neither its beginning, nor its end.

Asterix chose the substring t so as to please all his companions. Besides, from all acceptable variants Asterix chose the longest one (as Asterix loves long strings). When Asterix read the substring t aloud, the temple doors opened. 

You know the string s. Find the substring t or determine that such substring does not exist and all that's been written above is just a nice legend.

Input

You are given the string s whose length can vary from 1 to 106 (inclusive), consisting of small Latin letters.

Output

Print the string t. If a suitable t string does not exist, then print "Just a legend" without the quotes.

Examples

Input

fixprefixsuffix


Output

fix

Input

abcdabc


Output

Just a legend

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int h, n, i, l, m, w, z, f, k;
int d[1000010];
char a[1000010];
int main() {
  ios_base::sync_with_stdio(false);
  cin >> a, l = strlen(a);
  if (l <= 2) {
    cout << "Just a legend";
    return 0;
  }
  while (m < 2) {
    if (!m)
      k = 1;
    else
      k = l - h, h = 0;
    while (true) {
      if (k == l) break;
      if (a[h] == a[k])
        d[k] = ++h, k++;
      else
        !h ? k++ : h = d[h - 1];
    }
    if (!m) {
      for (h = 0, i = 1; i < l - 1; i++) h = max(h, d[i]);
      d[l - 1] = 0;
    }
    m++;
  }
  if (!d[l - 1])
    cout << "Just a legend";
  else {
    a[d[l - 1]] = '\0';
    cout << a;
  }
  return 0;
}