Problem: Let's call a positive integer composite if it has at least one divisor other than 1 and itself. For example:

  * the following numbers are composite: 1024, 4, 6, 9; 
  * the following numbers are not composite: 13, 1, 2, 3, 37. 



You are given a positive integer n. Find two composite integers a,b such that a-b=n.

It can be proven that solution always exists.

Input

The input contains one integer n (1 ≤ n ≤ 10^7): the given integer.

Output

Print two composite integers a,b (2 ≤ a, b ≤ 10^9, a-b=n).

It can be proven, that solution always exists.

If there are several possible solutions, you can print any. 

Examples

Input


1


Output


9 8


Input


512


Output


4608 4096

Solution (in JAVA):

Solution:
import java.util.Scanner;

public class Equation {
    public static  void equation(long n) {
    	if(n==1)
    	{
    		System.out.println(9+" "+8);
    	}
    	else {
    		System.out.println(3*n+" "+2*n);
    	}
    }
	public static void main(String[] args) {
	Scanner sc=new Scanner(System.in);
	long n=sc.nextLong();
//	equation solove=new equation();
	equation (n);
	sc.close();

	}

}