Problem: You are given two strings s and t consisting of small Latin letters, string s can also contain '?' characters. 

Suitability of string s is calculated by following metric:

Any two letters can be swapped positions, these operations can be performed arbitrary number of times over any pair of positions. Among all resulting strings s, you choose the one with the largest number of non-intersecting occurrences of string t. Suitability is this number of occurrences.

You should replace all '?' characters with small Latin letters in such a way that the suitability of string s is maximal.

Input

The first line contains string s (1 ≤ |s| ≤ 106).

The second line contains string t (1 ≤ |t| ≤ 106).

Output

Print string s with '?' replaced with small Latin letters in such a way that suitability of that string is maximal.

If there are multiple strings with maximal suitability then print any of them.

Examples

Input

?aa?
ab


Output

baab


Input

??b?
za


Output

azbz


Input

abcd
abacaba


Output

abcd

Note

In the first example string "baab" can be transformed to "abab" with swaps, this one has suitability of 2. That means that string "baab" also has suitability of 2.

In the second example maximal suitability you can achieve is 1 and there are several dozens of such strings, "azbz" is just one of them.

In the third example there are no '?' characters and the suitability of the string is 0.

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
ifstream fin("input.txt");
ofstream fout("output.txt");
bool isPrime(long long int x) {
  if (x <= 4 || x % 2 == 0 || x % 3 == 0) return x == 2 || x == 3;
  for (int i = 5; i * i <= x; i += 6)
    if (x % i == 0 || x % (i + 2) == 0) return 0;
  return 1;
}
void primeFactors(long long n, set<long long> &Fac) {
  while (n % 2 == 0) {
    Fac.insert(2);
    n = n / 2;
  }
  for (int i = 3; i <= sqrt(n); i = i + 2) {
    while (n % i == 0) {
      Fac.insert(i);
      n = n / i;
    }
  }
  if (n > 2) Fac.insert(n);
}
int NumDigits(int x) {
  return (
      x < 10
          ? 1
          : (x < 100
                 ? 2
                 : (x < 1000
                        ? 3
                        : (x < 10000
                               ? 4
                               : (x < 100000
                                      ? 5
                                      : (x < 1000000
                                             ? 6
                                             : (x < 10000000
                                                    ? 7
                                                    : (x < 100000000
                                                           ? 8
                                                           : (x < 1000000000
                                                                  ? 9
                                                                  : 10)))))))));
}
inline void boostIO() {
  ios_base::sync_with_stdio(0);
  cin.tie(0);
  cout.tie(0);
  cout.precision(10);
}
long long int Pow10[19] = {
    (long long int)0,    (long long int)1e1,  (long long int)1e2,
    (long long int)1e3,  (long long int)1e4,  (long long int)1e5,
    (long long int)1e6,  (long long int)1e7,  (long long int)1e8,
    (long long int)1e9,  (long long int)1e10, (long long int)1e11,
    (long long int)1e12, (long long int)1e13, (long long int)1e14,
    (long long int)1e15, (long long int)1e16, (long long int)1e17,
    (long long int)1e18};
long long int gcd(long long int a, long long int b) {
  return b ? gcd(b, a % b) : a;
}
long long int lcm(long long int a, long long int b) {
  return a * b / gcd(a, b);
}
long long MOD = 1e9 + 7;
template <class T>
struct Fenwick {
  vector<T> V;
  Fenwick(long long n) : V(n) {}
  void add(size_t i, T x) {
    for (; i < V.size(); i |= i + 1) V[i] += x;
  }
  T sum(long long i) {
    T r = T();
    for (--i; i >= 0; i = (i & (i + 1)) - 1) r += V[i];
    return r;
  }
  T sum(long long l, long long r) { return sum(r) - sum(l); }
};
long long f_Minimum(long long a, long long b) { return (min(a, b)); }
long long f_Maximum(long long a, long long b) { return (max(a, b)); }
long long f_Summarize(long long a, long long b) { return (a + b); }
class Parameter {
 public:
  long long InitialValue;
  long long (*Function)(long long a, long long b);
  Parameter(long long (*f)(long long a, long long b), long long value) {
    Function = f;
    InitialValue = value;
  }

 private:
};
Parameter Minimum(f_Minimum, LONG_LONG_MAX);
Parameter Maximum(f_Maximum, LONG_LONG_MIN);
Parameter Summarize(f_Summarize, 0);
class SegmentTree {
 public:
  SegmentTree(long long size, Parameter p) {
    Function = p.Function;
    InitialValue = p.InitialValue;
    n = size;
    data = vector<long long>(2 * n, 0);
  }
  SegmentTree(vector<long long> array, Parameter p) {
    Function = p.Function;
    InitialValue = p.InitialValue;
    n = array.size();
    ;
    data = vector<long long>(2 * n, 0);
    for (long long i = 0; i < (n); ++i) {
      data[n + i] = array[i];
    }
    for (long long i = n - 1; i >= 1; ++i) {
      data[i] = Function(data[i * 2], data[i * 2] + 1);
    }
  }
  void Update(long long idx, long long value) {
    idx += n;
    data[idx] = value;
    while (idx > 1) {
      idx /= 2;
      data[idx] = Function(data[idx * 2], data[idx * 2 + 1]);
    }
  }
  long long Find(long long left, long long right) {
    left += n;
    right += n;
    long long value = InitialValue;
    while (left < right) {
      if (left % 2 == 1) {
        value = Function(left, value);
        left++;
      }
      if (right % 2 == 1) {
        value = Function(right, value);
        right--;
      }
      left /= 2;
      right /= 2;
    }
    return value;
  }

 private:
  long long n;
  vector<long long> data;
  long long (*Function)(long long a, long long b);
  long long InitialValue;
};
int32_t main() {
  boostIO();
  string s;
  cin >> s;
  string t;
  cin >> t;
  map<char, long long> Map;
  long long z = 0;
  for (auto c : s) {
    Map[c]++;
    if (c == '?') z++;
  }
  map<char, long long> Map2;
  for (auto c : t) {
    Map2[c]++;
  }
  long long low = 0;
  long long high = 1e6 + 1;
  while (high - low > 1) {
    long long mid = (high + low) / 2;
    long long req = 0;
    for (long long c = 'a'; c <= 'z'; ++c) {
      req += max(0LL, mid * Map2[c] - Map[c]);
    }
    if (req > z) {
      high = mid;
    } else {
      low = mid;
    }
  }
  vector<char> B;
  for (char c = 'a'; c <= 'z'; ++c) {
    for (long long i = 0; i < (Map2[c] * low - Map[c]); ++i) {
      B.push_back(c);
    }
  }
  long long idx = 0;
  for (auto c : s) {
    if (c != '?') {
      cout << c;
    } else {
      if (idx >= B.size()) {
        cout << 'a';
      } else {
        cout << B[idx];
        idx++;
      }
    }
  }
  cerr << '\n' << "RUNTIME: " << 1.0 * clock() / CLOCKS_PER_SEC << " s" << '\n';
  return 0;
  ;
}