Problem: Given a connected undirected graph with n vertices and an integer k, you have to either:

  * either find an independent set that has exactly ⌈k/2⌉ vertices.
  * or find a simple cycle of length at most k. 



An independent set is a set of vertices such that no two of them are connected by an edge. A simple cycle is a cycle that doesn't contain any vertex twice. 

I have a proof that for any input you can always solve at least one of these problems, but it's left as an exercise for the reader.

Input

The first line contains three integers n, m, and k (3 ≤ k ≤ n ≤ 10^5, n-1 ≤ m ≤ 2 ⋅ 10^5) — the number of vertices and edges in the graph, and the parameter k from the statement.

Each of the next m lines contains two integers u and v (1 ≤ u,v ≤ n) that mean there's an edge between vertices u and v. It's guaranteed that the graph is connected and doesn't contain any self-loops or multiple edges.

Output

If you choose to solve the first problem, then on the first line print 1, followed by a line containing ⌈k/2⌉ distinct integers not exceeding n, the vertices in the desired independent set.

If you, however, choose to solve the second problem, then on the first line print 2, followed by a line containing one integer, c, representing the length of the found cycle, followed by a line containing c distinct integers not exceeding n, the vertices in the desired cycle, in the order they appear in the cycle.

Examples

Input


4 4 3
1 2
2 3
3 4
4 1


Output


1
1 3 

Input


4 5 3
1 2
2 3
3 4
4 1
2 4


Output


2
3
2 3 4 

Input


4 6 3
1 2
2 3
3 4
4 1
1 3
2 4


Output


2
3
1 2 3 

Input


5 4 5
1 2
1 3
2 4
2 5


Output


1
1 4 5 

Note

In the first sample:

<image>

Notice that printing the independent set \{2,4\} is also OK, but printing the cycle 1-2-3-4 isn't, because its length must be at most 3.

In the second sample:

<image>

Notice that printing the independent set \{1,3\} or printing the cycle 2-1-4 is also OK.

In the third sample:

<image>

In the fourth sample:

<image>

Solution (in JAVA):

Solution:
/*
If you want to aim high, aim high
Don't let that studying and grades consume you
Just live life young
******************************
What do you think? What do you think?
1st on Billboard, what do you think of it
Next is a Grammy, what do you think of it
However you think, I’m sorry, but shit, I have no fcking interest
*******************************
I'm standing on top of my Monopoly board
That means I'm on top of my game and it don't stop
til my hip don't hop anymore
https://www.a2oj.com/Ladder16.html
*******************************
300IQ as writer = Sad!
*/
import java.util.*;
import java.io.*;
import java.math.*;

   public class x1325F
   {
      public static void main(String hi[]) throws Exception
      {
         BufferedReader infile = new BufferedReader(new InputStreamReader(System.in));  
         StringTokenizer st = new StringTokenizer(infile.readLine());
         int N = Integer.parseInt(st.nextToken());
         int M = Integer.parseInt(st.nextToken());
         ArrayDeque<Integer>[] edges = new ArrayDeque[N+1];
         for(int i=1; i <= N; i++)
            edges[i] = new ArrayDeque<Integer>();
         for(int i=0; i < M; i++)
         {
            st = new StringTokenizer(infile.readLine());
            int a = Integer.parseInt(st.nextToken());
            int b = Integer.parseInt(st.nextToken());
            edges[a].add(b);  edges[b].add(a);
         }
         int K = (int)(Math.sqrt(N));
         if(K*K != N)   K++;
         StringBuilder sb = new StringBuilder();
         //dfs tree
         marked = new boolean[N+1];
         indset = new ArrayList<Integer>();
         depth = new int[N+1];
         Arrays.fill(depth, -1);
         par = new int[N+1];
         depth[1] = 0;
         dfstree(1, edges);
         if(indset.size() >= K)
         {
            sb = new StringBuilder("1\n");
            for(int i=0; i < K; i++)
               sb.append(indset.get(i)+" ");
            System.out.println(sb);
            return;
         }
         ArrayDeque<Integer> q = new ArrayDeque<Integer>();
         q.add(1);
         while(q.size() > 0)
         {
            int curr = q.poll();
            for(int next: edges[curr])
            {
               if(depth[next] < depth[curr] && depth[curr]-depth[next]+1 >= K)
               {
                  System.out.println(2);
                  sb.append(depth[curr]-depth[next]+1).append("\n");
                  int cyc = curr;
                  while(cyc != next)
                  {
                     sb.append(cyc+" ");
                     cyc = par[cyc];
                  }  
                  sb.append(cyc);
                  System.out.println(sb);
                  return;
               }
               else if(depth[next] > depth[curr])
                  q.add(next);
            }
         }
         System.out.println("oops");
      }
      static ArrayList<Integer> indset;
      static boolean[] marked;
      static int[] par;
      static int[] depth;
      public static void dfstree(int curr, ArrayDeque<Integer>[] edges)
      {
         for(int next: edges[curr])
            if(depth[next] == -1)
            {
               depth[next] = depth[curr]+1;
               par[next] = curr;
               dfstree(next, edges);
            }
         if(!marked[curr])
         {
            indset.add(curr);
            for(int next: edges[curr])
               marked[next] = true;
         }
      }
   }