Problem: Asterix, Obelix and their temporary buddies Suffix and Prefix has finally found the Harmony temple. However, its doors were firmly locked and even Obelix had no luck opening them.

A little later they found a string s, carved on a rock below the temple's gates. Asterix supposed that that's the password that opens the temple and read the string aloud. However, nothing happened. Then Asterix supposed that a password is some substring t of the string s.

Prefix supposed that the substring t is the beginning of the string s; Suffix supposed that the substring t should be the end of the string s; and Obelix supposed that t should be located somewhere inside the string s, that is, t is neither its beginning, nor its end.

Asterix chose the substring t so as to please all his companions. Besides, from all acceptable variants Asterix chose the longest one (as Asterix loves long strings). When Asterix read the substring t aloud, the temple doors opened. 

You know the string s. Find the substring t or determine that such substring does not exist and all that's been written above is just a nice legend.

Input

You are given the string s whose length can vary from 1 to 106 (inclusive), consisting of small Latin letters.

Output

Print the string t. If a suitable t string does not exist, then print "Just a legend" without the quotes.

Examples

Input

fixprefixsuffix


Output

fix

Input

abcdabc


Output

Just a legend

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
const int MAXN = 1e6 + 10;
int b[MAXN];
int ada[MAXN];
string p;
string lol = "Just a legend\n";
void kmp() {
  int i = 0, j = -1, n = p.size();
  b[0] = -1;
  while (i < n) {
    while (j >= 0 && p[i] != p[j]) j = b[j];
    i++;
    j++;
    b[i] = j;
    ada[j]++;
  }
}
int main() {
  ios::sync_with_stdio(0);
  cin.tie(0);
  cin >> p;
  kmp();
  if (b[p.size()] == 0)
    cout << lol;
  else if (ada[b[p.size()]] > 1)
    cout << p.substr(0, b[p.size()]);
  else if (b[b[p.size()]] == 0)
    cout << lol;
  else
    cout << p.substr(0, b[b[p.size()]]);
}