Problem: You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible.

Input

Each test contains one or more test cases. The first line contains the number of test cases t (1 ≤ t ≤ 100).

The first line of each test case consists of one integer n — the number of elements in the sequence b (1 ≤ n ≤ 100).

The second line of each test case consists of n different integers b_1, …, b_n — elements of the sequence b (1 ≤ b_i ≤ 2n).

It is guaranteed that the sum of n by all test cases doesn't exceed 100.

Output

For each test case, if there is no appropriate permutation, print one number -1.

Otherwise, print 2n integers a_1, …, a_{2n} — required lexicographically minimal permutation of numbers from 1 to 2n.

Example

Input


5
1
1
2
4 1
3
4 1 3
4
2 3 4 5
5
1 5 7 2 8


Output


1 2 
-1
4 5 1 2 3 6 
-1
1 3 5 6 7 9 2 4 8 10 

Solution (in PYTHON3):

Solution:
import sys
import math
get_string = lambda: sys.stdin.readline().strip()
get_list = lambda: list( map(int,sys.stdin.readline().strip().split()) )
get_int = lambda: int(sys.stdin.readline())

#----------------------------------------------------------------------#

for _ in range(get_int()):
    n=get_int()
    b=get_list()
    l=2*n+1
    done=[0]*l
    for i in b:
        done[i]=1
    ans=[]
    for i in b:
        ans.append(i)
        for j in range(i+1,l):
            if(done[j])==0:
                done[j]=1
                ans.append(j)
                break
        else:
            print(-1)
            break
    else:
        print(*ans)