Problem: Asterix, Obelix and their temporary buddies Suffix and Prefix has finally found the Harmony temple. However, its doors were firmly locked and even Obelix had no luck opening them.

A little later they found a string s, carved on a rock below the temple's gates. Asterix supposed that that's the password that opens the temple and read the string aloud. However, nothing happened. Then Asterix supposed that a password is some substring t of the string s.

Prefix supposed that the substring t is the beginning of the string s; Suffix supposed that the substring t should be the end of the string s; and Obelix supposed that t should be located somewhere inside the string s, that is, t is neither its beginning, nor its end.

Asterix chose the substring t so as to please all his companions. Besides, from all acceptable variants Asterix chose the longest one (as Asterix loves long strings). When Asterix read the substring t aloud, the temple doors opened. 

You know the string s. Find the substring t or determine that such substring does not exist and all that's been written above is just a nice legend.

Input

You are given the string s whose length can vary from 1 to 106 (inclusive), consisting of small Latin letters.

Output

Print the string t. If a suitable t string does not exist, then print "Just a legend" without the quotes.

Examples

Input

fixprefixsuffix


Output

fix

Input

abcdabc


Output

Just a legend

Solution (in JAVA):

Solution:
import java.util.ArrayList;
import java.util.Scanner;
 
public class JavaApplication46 {

    static ArrayList<Integer> longestPrefix;
 
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
 
        String s = in.next();
        longestPrefix = new ArrayList();
        computePrefix(s);
 
        boolean found = false;
        int len;
 
        len = longestPrefix.get(s.length() - 1);
 
        if(len!=0){
       for(int j=0;j<2;j++) {
            for (int i = 1; i < s.length() - 1; i++) {
                if (len == longestPrefix.get(i)) {
                    found = true;
                    break;
                }
 
            }
            if(!found){
           len=longestPrefix.get(len-1);
            if(len==0)
                break;
            }
            else
                break;
        }
 
        }
        if (!found || len == 0) {
            System.out.println("Just a legend");
        } else {
            System.out.println(s.substring(0, len));
        }
 
    }
 
    public static void computePrefix(String str) {
        longestPrefix.add(0);
        int m = str.length();
        for (int i = 1, k = 0; i < m; i++) {
            while (k > 0 && str.charAt(k) != str.charAt(i)) {
                k = longestPrefix.get(k - 1);
            }
 
            if (str.charAt(k) == str.charAt(i)) {
                longestPrefix.add(i, ++k);
            } else {
                longestPrefix.add(i, k);
            }
        }
    }
 
}