Problem: You are given one integer number n. Find three distinct integers a, b, c such that 2 ≤ a, b, c and a ⋅ b ⋅ c = n or say that it is impossible to do it.

If there are several answers, you can print any.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of test cases.

The next n lines describe test cases. The i-th test case is given on a new line as one integer n (2 ≤ n ≤ 10^9).

Output

For each test case, print the answer on it. Print "NO" if it is impossible to represent n as a ⋅ b ⋅ c for some distinct integers a, b, c such that 2 ≤ a, b, c.

Otherwise, print "YES" and any possible such representation.

Example

Input


5
64
32
97
2
12345


Output


YES
2 4 8 
NO
NO
NO
YES
3 5 823 

Solution (in CPP):

Solution:
#include <bits/stdc++.h>
using namespace std;
int main() {
  ios::sync_with_stdio(false);
  cin.tie(), cout.tie(NULL);
  int t;
  cin >> t;
  while (t--) {
    long long n, i, j, k, a = 1, b = 1, c = 1;
    cin >> n;
    bool ok = 1;
    for (i = 2; i * i <= n; i++) {
      if (n % i == 0) {
        a = i;
        break;
      }
    }
    j = n / a;
    for (i = 2; i * i <= j; i++) {
      if (j % i == 0) {
        if (i == a) continue;
        b = i;
        break;
      }
    }
    if (b == 1 || a == 1 || (j / b) == 1) ok = 0;
    c = n / (a * b);
    if (a == b || b == c || c == a) ok = 0;
    if (!ok) {
      cout << "NO" << endl;
    } else {
      cout << "YES" << endl;
      cout << a << ' ' << b << ' ' << c << endl;
    }
  }
  return 0;
}