Problem: You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible.

Input

Each test contains one or more test cases. The first line contains the number of test cases t (1 ≤ t ≤ 100).

The first line of each test case consists of one integer n — the number of elements in the sequence b (1 ≤ n ≤ 100).

The second line of each test case consists of n different integers b_1, …, b_n — elements of the sequence b (1 ≤ b_i ≤ 2n).

It is guaranteed that the sum of n by all test cases doesn't exceed 100.

Output

For each test case, if there is no appropriate permutation, print one number -1.

Otherwise, print 2n integers a_1, …, a_{2n} — required lexicographically minimal permutation of numbers from 1 to 2n.

Example

Input


5
1
1
2
4 1
3
4 1 3
4
2 3 4 5
5
1 5 7 2 8


Output


1 2 
-1
4 5 1 2 3 6 
-1
1 3 5 6 7 9 2 4 8 10 

Solution (in PYTHON3):

Solution:
t=int(input())
while(t):
    t-=1
    n=int(input())
    li=list(map(int,input().split()))
    b_li=[0]*(2*n)
    for i in range(0,n):
        b_li[i*2]=li[i]
    have=[]
    for i in range(1,2*n+1):
        if i not in li:
            have.append(i)
    for i in range(1,2*n+1,2):
        pre=b_li[i-1]
        flag=0
        for j in range(len(have)):
            if have[j]>pre:
                flag=1
                break
        if flag==1:
            b_li[i]=have[j]
            del(have[j])
        else:
            print(-1)
            break
    if (flag==1):
        for i in b_li:
            print(i,end=" ")
        print()