Question: Is the official website of the rock band that has a subscription number of 625 under the Twitter username Official_Police http://www.thepolice.com/?
Choices:
yes
no
unknown
unknown
unknown
unknown
unknown
unknown
unknown
unknown
Program:
function: FindAll
function: FilterStr
dependencies: 0
inputs: Twitter username
Official_Police
function: QFilterNum
dependencies: 1
inputs: number of subscribers
625
=
function: FilterConcept
dependencies: 2
inputs: rock band
function: QueryAttr
dependencies: 3
inputs: official website
function: VerifyStr
dependencies: 4
inputs: http://www.thepolice.com/
SPARQL: ASK { ?e <pred:instance_of> ?c . ?c <pred:name> "rock band" . ?e <Twitter_username> ?pv_1 . ?pv_1 <pred:value> "Official_Police" . [ <pred:fact_h> ?e ; <pred:fact_r> <Twitter_username> ; <pred:fact_t> ?pv_1 ] <number_of_subscribers> ?qpv . ?qpv <pred:unit> "1" . ?qpv <pred:value> "625"^^xsd:double . ?e <official_website> ?pv . ?pv <pred:value> "http://www.thepolice.com/" .  }
Answer: yes