Question: What is the official website of the person whose Twitter username is AlbertBrooks (the subscription number of this statement is 1800582)?
Choices:
http://www.bournemouth.gov.uk/
http://www.norfolkadmirals.com/
http://www.emmawatsonofficial.com
http://www.bbc.co.uk/drama/stateofplay/
https://www.apple.com/
http://smironne.free.fr/NICO
http://www.alicecooper.com/
http://www.albertbrooks.com/
http://www.alastairreynolds.com/
http://www.jeffbeck.com
Program:
function: FindAll
function: FilterStr
dependencies: 0
inputs: Twitter username
AlbertBrooks
function: QFilterNum
dependencies: 1
inputs: number of subscribers
1800582
=
function: FilterConcept
dependencies: 2
inputs: human
function: QueryAttr
dependencies: 3
inputs: official website
SPARQL: SELECT DISTINCT ?pv WHERE { ?e <pred:instance_of> ?c . ?c <pred:name> "human" . ?e <Twitter_username> ?pv_1 . ?pv_1 <pred:value> "AlbertBrooks" . [ <pred:fact_h> ?e ; <pred:fact_r> <Twitter_username> ; <pred:fact_t> ?pv_1 ] <number_of_subscribers> ?qpv . ?qpv <pred:unit> "1" . ?qpv <pred:value> "1800582"^^xsd:double . ?e <official_website> ?pv .  }
Answer: http://www.albertbrooks.com/