I looked at the C# ones - the code is not great and neither are the explanations, both show a lack of experience in C# and .NET.

How to reverse the characters in a string

String.Join("",("1234Simple").Select(c=>c).Reverse());

- String.Join("", - concatenate one or more characters in a single list or array, by using empty "" string literal separator
- .Select(c=>c) - select each and every other character in a string into an array of characters
- .Reverse() - reverse each and every one elements in an array or list*

Calling Select(c => c) does nothing and can be omitted. The use of String.Join() feels wrong, it is just used to concatenate the characters and not to join them with some separator in between. Using the String(Char[]) constructor seems more appropriate.

new String("1234Simple".Reverse().ToArray())

But that is still bad code, it will rip apart and reverse grapheme clusters, a proper implementation should use System.Globalization.StringInfo. Not sure if it would still fit into one line.

Also the explanation are not very accurate and show a lack of understanding of the .NET collection type architecture and how array, list and enumeration types fit together.

How to reverse the words in a phrase

("This tests that").Split(' ').Aggregate((a,b) => b + " " + a);

- .Split(' ') - splits a string by using a space ' ' separator
- .Aggregate - gather every one other element a, in an element list to a target element b
- (a,b) => b + " " + a - arrow function taking input arguments (a,b) used to concatenate b gathered character argument in the list in reverse with " " space separator to the targeted character argument a

Here I would say IEnumerable<T>.Reverse() paired with String.Join() is the better solution as it is much easier to unterstand than using IEnumerable<T>.Aggregate().

String.Join(" ", "This tests that".Split(' ').Reverse())

Now nobody has to figure out that (a, b) are the accumulated result and the current list element in this order which is even with the explanation not to obvious - better variable names could really help here.

How to retrieve numeric fibonacci list up to 10

List<long> Fib = new List<long>(); Enumerable.Range(0,10).ToList().ForEach(n => (Fib).Add(n <= 1 ? 1 : Fib[n-2] + Fib[n-1]));

- new List(); - create an empty list of large integers
- Enumerable.Range(0,10) - get an enumerable list populated with integers from 0 to 10
- .ToList() - convert the enumerable list to a standard list
- .ForEach - apply a specific arrow function for each and every one item in the list
- n => (Fib).Add - arrow function used to add an item n to enumerable list Fib based on a condition for every one item in the list
- n <= 1 ? 1 : Fib[n-2] + Fib[n-1] - check if n less or equal to 1 then return 1, if n is larger then return addition of elements [n-2] and [n-1] in Fib list for every n

This is really abusing LINQ to express a for loop - create an IEnumerbale<T>, materialize it as a List<T> only to be able to use List<T>.ForEach() which is - for better or worse - not available for IEnumerable<T> and then manipulate a different list created with a second statement in the same line. If you desperately want a one line solution for Fibonacci numbers, maybe consider using a closed-form expression, the recursive definition just doesn't work well in C# and a single line. This will however run into precision issues for big enough numbers while working with integers will work fine until Int64 overflows.

Enumerable.Range(0, 10).Select(n => (Int64)(0.5 + Math.Pow((1 + Math.Sqrt(5)) / 2, n) / Math.Sqrt(5)))

Or with using static System.Math even shorter and more readable.

Enumerable.Range(0, 10).Select(n => (Int64)(0.5 + Pow((1 + Sqrt(5)) / 2, n) / Sqrt(5)))

The explanation has again issues with the collection types, Enumerable.Range(0, 10) generates 10 values starting from 0, i.e. 0 to 9, but maybe they wanted to say from 0 (inclusive) to 10 (exclusive). Also arrow functions are called lambda functions or lambda expressions in C#.