sharkiefff/RBAC-Text2SQL-Benchmark huggingface dataset:
##Instruction:
Database: employee_hire_evaluation
Total Tables: 4
Total Columns: 17

Table Schemas:

employee_hire_evaluation contains tables such as employee, shop, hiring, evaluation.
Table employee has columns such as Employee_ID, Name, Age, City.
Employee_ID is the primary key.
Table shop has columns such as Shop_ID, Name, Location, District, Number_products, Manager_name.
Shop_ID is the primary key.
Table hiring has columns such as Shop_ID, Employee_ID, Start_from, Is_full_time.
Employee_ID is the primary key.
Table evaluation has columns such as Employee_ID, Year_awarded, Bonus.
Employee_ID is the primary key.
The Employee_ID of hiring is the foreign key of Employee_ID of employee.
The Shop_ID of hiring is the foreign key of Shop_ID of shop.
The Employee_ID of evaluation is the foreign key of Employee_ID of employee.

##Role Access Policy (Column-Level):
Role: ShopManager
Accessible Columns: shop: Shop_ID, Name, Location, District, Number_products, Manager_name; hiring: Shop_ID, Employee_ID, Start_from, Is_full_time; employee: Employee_ID, Name, Age, City; evaluation: Employee_ID, Year_awarded, Bonus

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: Which employee received the biggest bonus? Give me the employee name.
Answer: SELECT t1.name FROM employee AS t1 JOIN evaluation AS t2 ON t1.Employee_ID  =  t2.Employee_ID ORDER BY t2.bonus DESC LIMIT 1
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT t1.name FROM employee AS t1 JOIN evaluation AS t2 ON t1.Employee_ID  =  t2.Employee_ID ORDER BY t2.bonus DESC LIMIT 1
##Instruction:
Database: employee_hire_evaluation
Total Tables: 4
Total Columns: 17

Table Schemas:

employee_hire_evaluation contains tables such as employee, shop, hiring, evaluation.
Table employee has columns such as Employee_ID, Name, Age, City.
Employee_ID is the primary key.
Table shop has columns such as Shop_ID, Name, Location, District, Number_products, Manager_name.
Shop_ID is the primary key.
Table hiring has columns such as Shop_ID, Employee_ID, Start_from, Is_full_time.
Employee_ID is the primary key.
Table evaluation has columns such as Employee_ID, Year_awarded, Bonus.
Employee_ID is the primary key.
The Employee_ID of hiring is the foreign key of Employee_ID of employee.
The Shop_ID of hiring is the foreign key of Shop_ID of shop.
The Employee_ID of evaluation is the foreign key of Employee_ID of employee.

##Role Access Policy (Column-Level):
Role: ShopManager
Accessible Columns: shop: Shop_ID, Name, Location, District, Number_products, Manager_name; hiring: Shop_ID, Employee_ID, Start_from, Is_full_time; employee: Employee_ID, Name, Age, City; evaluation: Employee_ID, Year_awarded, Bonus

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: Find the names of employees who never won any award in the evaluation.
Answer: SELECT name FROM employee WHERE Employee_ID NOT IN (SELECT Employee_ID FROM evaluation)
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT name FROM employee WHERE Employee_ID NOT IN (SELECT Employee_ID FROM evaluation)
##Instruction:
Database: employee_hire_evaluation
Total Tables: 4
Total Columns: 17

Table Schemas:

employee_hire_evaluation contains tables such as employee, shop, hiring, evaluation.
Table employee has columns such as Employee_ID, Name, Age, City.
Employee_ID is the primary key.
Table shop has columns such as Shop_ID, Name, Location, District, Number_products, Manager_name.
Shop_ID is the primary key.
Table hiring has columns such as Shop_ID, Employee_ID, Start_from, Is_full_time.
Employee_ID is the primary key.
Table evaluation has columns such as Employee_ID, Year_awarded, Bonus.
Employee_ID is the primary key.
The Employee_ID of hiring is the foreign key of Employee_ID of employee.
The Shop_ID of hiring is the foreign key of Shop_ID of shop.
The Employee_ID of evaluation is the foreign key of Employee_ID of employee.

##Role Access Policy (Column-Level):
Role: ShopManager
Accessible Columns: shop: Shop_ID, Name, Location, District, Number_products, Manager_name; hiring: Shop_ID, Employee_ID, Start_from, Is_full_time; employee: Employee_ID, Name, Age, City; evaluation: Employee_ID, Year_awarded, Bonus

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: What are the names of the employees who never received any evaluation?
Answer: SELECT name FROM employee WHERE Employee_ID NOT IN (SELECT Employee_ID FROM evaluation)
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT name FROM employee WHERE Employee_ID NOT IN (SELECT Employee_ID FROM evaluation)
##Instruction:
Database: employee_hire_evaluation
Total Tables: 4
Total Columns: 17

Table Schemas:

employee_hire_evaluation contains tables such as employee, shop, hiring, evaluation.
Table employee has columns such as Employee_ID, Name, Age, City.
Employee_ID is the primary key.
Table shop has columns such as Shop_ID, Name, Location, District, Number_products, Manager_name.
Shop_ID is the primary key.
Table hiring has columns such as Shop_ID, Employee_ID, Start_from, Is_full_time.
Employee_ID is the primary key.
Table evaluation has columns such as Employee_ID, Year_awarded, Bonus.
Employee_ID is the primary key.
The Employee_ID of hiring is the foreign key of Employee_ID of employee.
The Shop_ID of hiring is the foreign key of Shop_ID of shop.
The Employee_ID of evaluation is the foreign key of Employee_ID of employee.

##Role Access Policy (Column-Level):
Role: ShopManager
Accessible Columns: shop: Shop_ID, Name, Location, District, Number_products, Manager_name; hiring: Shop_ID, Employee_ID, Start_from, Is_full_time; employee: Employee_ID, Name, Age, City; evaluation: Employee_ID, Year_awarded, Bonus

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: What is the name of the shop that is hiring the largest number of employees?
Answer: SELECT t2.name FROM hiring AS t1 JOIN shop AS t2 ON t1.shop_id  =  t2.shop_id GROUP BY t1.shop_id ORDER BY count(*) DESC LIMIT 1
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT t2.name FROM hiring AS t1 JOIN shop AS t2 ON t1.shop_id  =  t2.shop_id GROUP BY t1.shop_id ORDER BY count(*) DESC LIMIT 1
##Instruction:
Database: employee_hire_evaluation
Total Tables: 4
Total Columns: 17

Table Schemas:

employee_hire_evaluation contains tables such as employee, shop, hiring, evaluation.
Table employee has columns such as Employee_ID, Name, Age, City.
Employee_ID is the primary key.
Table shop has columns such as Shop_ID, Name, Location, District, Number_products, Manager_name.
Shop_ID is the primary key.
Table hiring has columns such as Shop_ID, Employee_ID, Start_from, Is_full_time.
Employee_ID is the primary key.
Table evaluation has columns such as Employee_ID, Year_awarded, Bonus.
Employee_ID is the primary key.
The Employee_ID of hiring is the foreign key of Employee_ID of employee.
The Shop_ID of hiring is the foreign key of Shop_ID of shop.
The Employee_ID of evaluation is the foreign key of Employee_ID of employee.

##Role Access Policy (Column-Level):
Role: ShopManager
Accessible Columns: shop: Shop_ID, Name, Location, District, Number_products, Manager_name; hiring: Shop_ID, Employee_ID, Start_from, Is_full_time; employee: Employee_ID, Name, Age, City; evaluation: Employee_ID, Year_awarded, Bonus

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: Which shop has the most employees? Give me the shop name.
Answer: SELECT t2.name FROM hiring AS t1 JOIN shop AS t2 ON t1.shop_id  =  t2.shop_id GROUP BY t1.shop_id ORDER BY count(*) DESC LIMIT 1
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT t2.name FROM hiring AS t1 JOIN shop AS t2 ON t1.shop_id  =  t2.shop_id GROUP BY t1.shop_id ORDER BY count(*) DESC LIMIT 1
##Instruction:
Database: employee_hire_evaluation
Total Tables: 4
Total Columns: 17

Table Schemas:

employee_hire_evaluation contains tables such as employee, shop, hiring, evaluation.
Table employee has columns such as Employee_ID, Name, Age, City.
Employee_ID is the primary key.
Table shop has columns such as Shop_ID, Name, Location, District, Number_products, Manager_name.
Shop_ID is the primary key.
Table hiring has columns such as Shop_ID, Employee_ID, Start_from, Is_full_time.
Employee_ID is the primary key.
Table evaluation has columns such as Employee_ID, Year_awarded, Bonus.
Employee_ID is the primary key.
The Employee_ID of hiring is the foreign key of Employee_ID of employee.
The Shop_ID of hiring is the foreign key of Shop_ID of shop.
The Employee_ID of evaluation is the foreign key of Employee_ID of employee.

##Role Access Policy (Column-Level):
Role: ShopManager
Accessible Columns: shop: Shop_ID, Name, Location, District, Number_products, Manager_name; hiring: Shop_ID, Employee_ID, Start_from, Is_full_time; employee: Employee_ID, Name, Age, City; evaluation: Employee_ID, Year_awarded, Bonus

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: Find the name of the shops that do not hire any employee.
Answer: SELECT name FROM shop WHERE shop_id NOT IN (SELECT shop_id FROM hiring)
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT name FROM shop WHERE shop_id NOT IN (SELECT shop_id FROM hiring)
##Instruction:
Database: employee_hire_evaluation
Total Tables: 4
Total Columns: 17

Table Schemas:

employee_hire_evaluation contains tables such as employee, shop, hiring, evaluation.
Table employee has columns such as Employee_ID, Name, Age, City.
Employee_ID is the primary key.
Table shop has columns such as Shop_ID, Name, Location, District, Number_products, Manager_name.
Shop_ID is the primary key.
Table hiring has columns such as Shop_ID, Employee_ID, Start_from, Is_full_time.
Employee_ID is the primary key.
Table evaluation has columns such as Employee_ID, Year_awarded, Bonus.
Employee_ID is the primary key.
The Employee_ID of hiring is the foreign key of Employee_ID of employee.
The Shop_ID of hiring is the foreign key of Shop_ID of shop.
The Employee_ID of evaluation is the foreign key of Employee_ID of employee.

##Role Access Policy (Column-Level):
Role: ShopManager
Accessible Columns: shop: Shop_ID, Name, Location, District, Number_products, Manager_name; hiring: Shop_ID, Employee_ID, Start_from, Is_full_time; employee: Employee_ID, Name, Age, City; evaluation: Employee_ID, Year_awarded, Bonus

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: Which shops run with no employees? Find the shop names
Answer: SELECT name FROM shop WHERE shop_id NOT IN (SELECT shop_id FROM hiring)
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT name FROM shop WHERE shop_id NOT IN (SELECT shop_id FROM hiring)
##Instruction:
Database: employee_hire_evaluation
Total Tables: 4
Total Columns: 17

Table Schemas:

employee_hire_evaluation contains tables such as employee, shop, hiring, evaluation.
Table employee has columns such as Employee_ID, Name, Age, City.
Employee_ID is the primary key.
Table shop has columns such as Shop_ID, Name, Location, District, Number_products, Manager_name.
Shop_ID is the primary key.
Table hiring has columns such as Shop_ID, Employee_ID, Start_from, Is_full_time.
Employee_ID is the primary key.
Table evaluation has columns such as Employee_ID, Year_awarded, Bonus.
Employee_ID is the primary key.
The Employee_ID of hiring is the foreign key of Employee_ID of employee.
The Shop_ID of hiring is the foreign key of Shop_ID of shop.
The Employee_ID of evaluation is the foreign key of Employee_ID of employee.

##Role Access Policy (Column-Level):
Role: ShopManager
Accessible Columns: shop: Shop_ID, Name, Location, District, Number_products, Manager_name; hiring: Shop_ID, Employee_ID, Start_from, Is_full_time; employee: Employee_ID, Name, Age, City; evaluation: Employee_ID, Year_awarded, Bonus

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: Find the number of employees hired in each shop; show the shop name as well.
Answer: SELECT count(*) ,  t2.name FROM hiring AS t1 JOIN shop AS t2 ON t1.shop_id  =  t2.shop_id GROUP BY t2.name
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT count(*) ,  t2.name FROM hiring AS t1 JOIN shop AS t2 ON t1.shop_id  =  t2.shop_id GROUP BY t2.name
##Instruction:
Database: employee_hire_evaluation
Total Tables: 4
Total Columns: 17

Table Schemas:

employee_hire_evaluation contains tables such as employee, shop, hiring, evaluation.
Table employee has columns such as Employee_ID, Name, Age, City.
Employee_ID is the primary key.
Table shop has columns such as Shop_ID, Name, Location, District, Number_products, Manager_name.
Shop_ID is the primary key.
Table hiring has columns such as Shop_ID, Employee_ID, Start_from, Is_full_time.
Employee_ID is the primary key.
Table evaluation has columns such as Employee_ID, Year_awarded, Bonus.
Employee_ID is the primary key.
The Employee_ID of hiring is the foreign key of Employee_ID of employee.
The Shop_ID of hiring is the foreign key of Shop_ID of shop.
The Employee_ID of evaluation is the foreign key of Employee_ID of employee.

##Role Access Policy (Column-Level):
Role: ShopManager
Accessible Columns: shop: Shop_ID, Name, Location, District, Number_products, Manager_name; hiring: Shop_ID, Employee_ID, Start_from, Is_full_time; employee: Employee_ID, Name, Age, City; evaluation: Employee_ID, Year_awarded, Bonus

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: For each shop, return the number of employees working there and the name of the shop.
Answer: SELECT count(*) ,  t2.name FROM hiring AS t1 JOIN shop AS t2 ON t1.shop_id  =  t2.shop_id GROUP BY t2.name
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT count(*) ,  t2.name FROM hiring AS t1 JOIN shop AS t2 ON t1.shop_id  =  t2.shop_id GROUP BY t2.name
##Instruction:
Database: employee_hire_evaluation
Total Tables: 4
Total Columns: 17

Table Schemas:

employee_hire_evaluation contains tables such as employee, shop, hiring, evaluation.
Table employee has columns such as Employee_ID, Name, Age, City.
Employee_ID is the primary key.
Table shop has columns such as Shop_ID, Name, Location, District, Number_products, Manager_name.
Shop_ID is the primary key.
Table hiring has columns such as Shop_ID, Employee_ID, Start_from, Is_full_time.
Employee_ID is the primary key.
Table evaluation has columns such as Employee_ID, Year_awarded, Bonus.
Employee_ID is the primary key.
The Employee_ID of hiring is the foreign key of Employee_ID of employee.
The Shop_ID of hiring is the foreign key of Shop_ID of shop.
The Employee_ID of evaluation is the foreign key of Employee_ID of employee.

##Role Access Policy (Column-Level):
Role: ShopManager
Accessible Columns: shop: Shop_ID, Name, Location, District, Number_products, Manager_name; hiring: Shop_ID, Employee_ID, Start_from, Is_full_time; employee: Employee_ID, Name, Age, City; evaluation: Employee_ID, Year_awarded, Bonus

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: What is total bonus given in all evaluations?
Answer: SELECT sum(bonus) FROM evaluation
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT sum(bonus) FROM evaluation
##Instruction:
Database: employee_hire_evaluation
Total Tables: 4
Total Columns: 17

Table Schemas:

employee_hire_evaluation contains tables such as employee, shop, hiring, evaluation.
Table employee has columns such as Employee_ID, Name, Age, City.
Employee_ID is the primary key.
Table shop has columns such as Shop_ID, Name, Location, District, Number_products, Manager_name.
Shop_ID is the primary key.
Table hiring has columns such as Shop_ID, Employee_ID, Start_from, Is_full_time.
Employee_ID is the primary key.
Table evaluation has columns such as Employee_ID, Year_awarded, Bonus.
Employee_ID is the primary key.
The Employee_ID of hiring is the foreign key of Employee_ID of employee.
The Shop_ID of hiring is the foreign key of Shop_ID of shop.
The Employee_ID of evaluation is the foreign key of Employee_ID of employee.

##Role Access Policy (Column-Level):
Role: ShopManager
Accessible Columns: shop: Shop_ID, Name, Location, District, Number_products, Manager_name; hiring: Shop_ID, Employee_ID, Start_from, Is_full_time; employee: Employee_ID, Name, Age, City; evaluation: Employee_ID, Year_awarded, Bonus

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: Find the total amount of bonus given in all the evaluations.
Answer: SELECT sum(bonus) FROM evaluation
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT sum(bonus) FROM evaluation
##Instruction:
Database: employee_hire_evaluation
Total Tables: 4
Total Columns: 17

Table Schemas:

employee_hire_evaluation contains tables such as employee, shop, hiring, evaluation.
Table employee has columns such as Employee_ID, Name, Age, City.
Employee_ID is the primary key.
Table shop has columns such as Shop_ID, Name, Location, District, Number_products, Manager_name.
Shop_ID is the primary key.
Table hiring has columns such as Shop_ID, Employee_ID, Start_from, Is_full_time.
Employee_ID is the primary key.
Table evaluation has columns such as Employee_ID, Year_awarded, Bonus.
Employee_ID is the primary key.
The Employee_ID of hiring is the foreign key of Employee_ID of employee.
The Shop_ID of hiring is the foreign key of Shop_ID of shop.
The Employee_ID of evaluation is the foreign key of Employee_ID of employee.

##Role Access Policy (Column-Level):
Role: ShopManager
Accessible Columns: shop: Shop_ID, Name, Location, District, Number_products, Manager_name; hiring: Shop_ID, Employee_ID, Start_from, Is_full_time; employee: Employee_ID, Name, Age, City; evaluation: Employee_ID, Year_awarded, Bonus

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: Give me all the information about hiring.
Answer: SELECT * FROM hiring
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT * FROM hiring
##Instruction:
Database: employee_hire_evaluation
Total Tables: 4
Total Columns: 17

Table Schemas:

employee_hire_evaluation contains tables such as employee, shop, hiring, evaluation.
Table employee has columns such as Employee_ID, Name, Age, City.
Employee_ID is the primary key.
Table shop has columns such as Shop_ID, Name, Location, District, Number_products, Manager_name.
Shop_ID is the primary key.
Table hiring has columns such as Shop_ID, Employee_ID, Start_from, Is_full_time.
Employee_ID is the primary key.
Table evaluation has columns such as Employee_ID, Year_awarded, Bonus.
Employee_ID is the primary key.
The Employee_ID of hiring is the foreign key of Employee_ID of employee.
The Shop_ID of hiring is the foreign key of Shop_ID of shop.
The Employee_ID of evaluation is the foreign key of Employee_ID of employee.

##Role Access Policy (Column-Level):
Role: ShopManager
Accessible Columns: shop: Shop_ID, Name, Location, District, Number_products, Manager_name; hiring: Shop_ID, Employee_ID, Start_from, Is_full_time; employee: Employee_ID, Name, Age, City; evaluation: Employee_ID, Year_awarded, Bonus

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: What is all the information about hiring?
Answer: SELECT * FROM hiring
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT * FROM hiring
##Instruction:
Database: employee_hire_evaluation
Total Tables: 4
Total Columns: 17

Table Schemas:

employee_hire_evaluation contains tables such as employee, shop, hiring, evaluation.
Table employee has columns such as Employee_ID, Name, Age, City.
Employee_ID is the primary key.
Table shop has columns such as Shop_ID, Name, Location, District, Number_products, Manager_name.
Shop_ID is the primary key.
Table hiring has columns such as Shop_ID, Employee_ID, Start_from, Is_full_time.
Employee_ID is the primary key.
Table evaluation has columns such as Employee_ID, Year_awarded, Bonus.
Employee_ID is the primary key.
The Employee_ID of hiring is the foreign key of Employee_ID of employee.
The Shop_ID of hiring is the foreign key of Shop_ID of shop.
The Employee_ID of evaluation is the foreign key of Employee_ID of employee.

##Role Access Policy (Column-Level):
Role: ShopManager
Accessible Columns: shop: Shop_ID, Name, Location, District, Number_products, Manager_name; hiring: Shop_ID, Employee_ID, Start_from, Is_full_time; employee: Employee_ID, Name, Age, City; evaluation: Employee_ID, Year_awarded, Bonus

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: Which district has both stores with less than 3000 products and stores with more than 10000 products?
Answer: SELECT district FROM shop WHERE Number_products  <  3000 INTERSECT SELECT district FROM shop WHERE Number_products  >  10000
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT district FROM shop WHERE Number_products  <  3000 INTERSECT SELECT district FROM shop WHERE Number_products  >  10000