sharkiefff/RBAC-Text2SQL-Benchmark huggingface dataset:
##Instruction:
Database: car_1
Total Tables: 6
Total Columns: 23

Table Schemas:

car_1 contains tables such as continents, countries, car_makers, model_list, car_names, cars_data.
Table continents has columns such as ContId, Continent.
ContId is the primary key.
Table countries has columns such as CountryId, CountryName, Continent.
CountryId is the primary key.
Table car_makers has columns such as Id, Maker, FullName, Country.
Id is the primary key.
Table model_list has columns such as ModelId, Maker, Model.
ModelId is the primary key.
Table car_names has columns such as MakeId, Model, Make.
MakeId is the primary key.
Table cars_data has columns such as Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year.
Id is the primary key.
The Continent of countries is the foreign key of ContId of continents.
The Country of car_makers is the foreign key of CountryId of countries.
The Maker of model_list is the foreign key of Id of car_makers.
The Model of car_names is the foreign key of Model of model_list.
The Id of cars_data is the foreign key of MakeId of car_names.

##Role Access Policy (Column-Level):
Role: MarketAnalyst
Accessible Columns: continents: ContId, Continent; countries: CountryId, CountryName, Continent; car_makers: Id, Maker, FullName, Country; model_list: ModelId, Maker, Model; car_names: MakeId, Model, Make; cars_data: Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: How many car makers are there in each continents? List the continent name and the count.
Answer: SELECT T1.Continent ,  count(*) FROM CONTINENTS AS T1 JOIN COUNTRIES AS T2 ON T1.ContId  =  T2.continent JOIN car_makers AS T3 ON T2.CountryId  =  T3.Country GROUP BY T1.Continent;
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT T1.Continent ,  count(*) FROM CONTINENTS AS T1 JOIN COUNTRIES AS T2 ON T1.ContId  =  T2.continent JOIN car_makers AS T3 ON T2.CountryId  =  T3.Country GROUP BY T1.Continent;
##Instruction:
Database: car_1
Total Tables: 6
Total Columns: 23

Table Schemas:

car_1 contains tables such as continents, countries, car_makers, model_list, car_names, cars_data.
Table continents has columns such as ContId, Continent.
ContId is the primary key.
Table countries has columns such as CountryId, CountryName, Continent.
CountryId is the primary key.
Table car_makers has columns such as Id, Maker, FullName, Country.
Id is the primary key.
Table model_list has columns such as ModelId, Maker, Model.
ModelId is the primary key.
Table car_names has columns such as MakeId, Model, Make.
MakeId is the primary key.
Table cars_data has columns such as Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year.
Id is the primary key.
The Continent of countries is the foreign key of ContId of continents.
The Country of car_makers is the foreign key of CountryId of countries.
The Maker of model_list is the foreign key of Id of car_makers.
The Model of car_names is the foreign key of Model of model_list.
The Id of cars_data is the foreign key of MakeId of car_names.

##Role Access Policy (Column-Level):
Role: MarketAnalyst
Accessible Columns: continents: ContId, Continent; countries: CountryId, CountryName, Continent; car_makers: Id, Maker, FullName, Country; model_list: ModelId, Maker, Model; car_names: MakeId, Model, Make; cars_data: Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: What is the name of each continent and how many car makers are there in each one?
Answer: SELECT T1.Continent ,  count(*) FROM CONTINENTS AS T1 JOIN COUNTRIES AS T2 ON T1.ContId  =  T2.continent JOIN car_makers AS T3 ON T2.CountryId  =  T3.Country GROUP BY T1.Continent;
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT T1.Continent ,  count(*) FROM CONTINENTS AS T1 JOIN COUNTRIES AS T2 ON T1.ContId  =  T2.continent JOIN car_makers AS T3 ON T2.CountryId  =  T3.Country GROUP BY T1.Continent;
##Instruction:
Database: car_1
Total Tables: 6
Total Columns: 23

Table Schemas:

car_1 contains tables such as continents, countries, car_makers, model_list, car_names, cars_data.
Table continents has columns such as ContId, Continent.
ContId is the primary key.
Table countries has columns such as CountryId, CountryName, Continent.
CountryId is the primary key.
Table car_makers has columns such as Id, Maker, FullName, Country.
Id is the primary key.
Table model_list has columns such as ModelId, Maker, Model.
ModelId is the primary key.
Table car_names has columns such as MakeId, Model, Make.
MakeId is the primary key.
Table cars_data has columns such as Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year.
Id is the primary key.
The Continent of countries is the foreign key of ContId of continents.
The Country of car_makers is the foreign key of CountryId of countries.
The Maker of model_list is the foreign key of Id of car_makers.
The Model of car_names is the foreign key of Model of model_list.
The Id of cars_data is the foreign key of MakeId of car_names.

##Role Access Policy (Column-Level):
Role: MarketAnalyst
Accessible Columns: continents: ContId, Continent; countries: CountryId, CountryName, Continent; car_makers: Id, Maker, FullName, Country; model_list: ModelId, Maker, Model; car_names: MakeId, Model, Make; cars_data: Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: Which of the countries has the most car makers? List the country name.
Answer: SELECT T2.CountryName FROM CAR_MAKERS AS T1 JOIN COUNTRIES AS T2 ON T1.Country  =  T2.CountryId GROUP BY T1.Country ORDER BY Count(*) DESC LIMIT 1;
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT T2.CountryName FROM CAR_MAKERS AS T1 JOIN COUNTRIES AS T2 ON T1.Country  =  T2.CountryId GROUP BY T1.Country ORDER BY Count(*) DESC LIMIT 1;
##Instruction:
Database: car_1
Total Tables: 6
Total Columns: 23

Table Schemas:

car_1 contains tables such as continents, countries, car_makers, model_list, car_names, cars_data.
Table continents has columns such as ContId, Continent.
ContId is the primary key.
Table countries has columns such as CountryId, CountryName, Continent.
CountryId is the primary key.
Table car_makers has columns such as Id, Maker, FullName, Country.
Id is the primary key.
Table model_list has columns such as ModelId, Maker, Model.
ModelId is the primary key.
Table car_names has columns such as MakeId, Model, Make.
MakeId is the primary key.
Table cars_data has columns such as Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year.
Id is the primary key.
The Continent of countries is the foreign key of ContId of continents.
The Country of car_makers is the foreign key of CountryId of countries.
The Maker of model_list is the foreign key of Id of car_makers.
The Model of car_names is the foreign key of Model of model_list.
The Id of cars_data is the foreign key of MakeId of car_names.

##Role Access Policy (Column-Level):
Role: MarketAnalyst
Accessible Columns: continents: ContId, Continent; countries: CountryId, CountryName, Continent; car_makers: Id, Maker, FullName, Country; model_list: ModelId, Maker, Model; car_names: MakeId, Model, Make; cars_data: Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: What is the name of the country with the most car makers?
Answer: SELECT T2.CountryName FROM CAR_MAKERS AS T1 JOIN COUNTRIES AS T2 ON T1.Country  =  T2.CountryId GROUP BY T1.Country ORDER BY Count(*) DESC LIMIT 1;
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT T2.CountryName FROM CAR_MAKERS AS T1 JOIN COUNTRIES AS T2 ON T1.Country  =  T2.CountryId GROUP BY T1.Country ORDER BY Count(*) DESC LIMIT 1;
##Instruction:
Database: car_1
Total Tables: 6
Total Columns: 23

Table Schemas:

car_1 contains tables such as continents, countries, car_makers, model_list, car_names, cars_data.
Table continents has columns such as ContId, Continent.
ContId is the primary key.
Table countries has columns such as CountryId, CountryName, Continent.
CountryId is the primary key.
Table car_makers has columns such as Id, Maker, FullName, Country.
Id is the primary key.
Table model_list has columns such as ModelId, Maker, Model.
ModelId is the primary key.
Table car_names has columns such as MakeId, Model, Make.
MakeId is the primary key.
Table cars_data has columns such as Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year.
Id is the primary key.
The Continent of countries is the foreign key of ContId of continents.
The Country of car_makers is the foreign key of CountryId of countries.
The Maker of model_list is the foreign key of Id of car_makers.
The Model of car_names is the foreign key of Model of model_list.
The Id of cars_data is the foreign key of MakeId of car_names.

##Role Access Policy (Column-Level):
Role: MarketAnalyst
Accessible Columns: continents: ContId, Continent; countries: CountryId, CountryName, Continent; car_makers: Id, Maker, FullName, Country; model_list: ModelId, Maker, Model; car_names: MakeId, Model, Make; cars_data: Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: How many car models are produced by each maker ? Only list the count and the maker full name .
Answer: select count(*) ,  t2.fullname from model_list as t1 join car_makers as t2 on t1.maker  =  t2.id group by t2.id;
Permission: allowed (All required columns are permitted)
Gold SQL: select count(*) ,  t2.fullname from model_list as t1 join car_makers as t2 on t1.maker  =  t2.id group by t2.id;
##Instruction:
Database: car_1
Total Tables: 6
Total Columns: 23

Table Schemas:

car_1 contains tables such as continents, countries, car_makers, model_list, car_names, cars_data.
Table continents has columns such as ContId, Continent.
ContId is the primary key.
Table countries has columns such as CountryId, CountryName, Continent.
CountryId is the primary key.
Table car_makers has columns such as Id, Maker, FullName, Country.
Id is the primary key.
Table model_list has columns such as ModelId, Maker, Model.
ModelId is the primary key.
Table car_names has columns such as MakeId, Model, Make.
MakeId is the primary key.
Table cars_data has columns such as Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year.
Id is the primary key.
The Continent of countries is the foreign key of ContId of continents.
The Country of car_makers is the foreign key of CountryId of countries.
The Maker of model_list is the foreign key of Id of car_makers.
The Model of car_names is the foreign key of Model of model_list.
The Id of cars_data is the foreign key of MakeId of car_names.

##Role Access Policy (Column-Level):
Role: MarketAnalyst
Accessible Columns: continents: ContId, Continent; countries: CountryId, CountryName, Continent; car_makers: Id, Maker, FullName, Country; model_list: ModelId, Maker, Model; car_names: MakeId, Model, Make; cars_data: Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: What is the number of car models that are produced by each maker and what is the id and full name of each maker?
Answer: SELECT Count(*) ,  T2.FullName ,  T2.id FROM MODEL_LIST AS T1 JOIN CAR_MAKERS AS T2 ON T1.Maker  =  T2.Id GROUP BY T2.id;
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT Count(*) ,  T2.FullName ,  T2.id FROM MODEL_LIST AS T1 JOIN CAR_MAKERS AS T2 ON T1.Maker  =  T2.Id GROUP BY T2.id;
##Instruction:
Database: car_1
Total Tables: 6
Total Columns: 23

Table Schemas:

car_1 contains tables such as continents, countries, car_makers, model_list, car_names, cars_data.
Table continents has columns such as ContId, Continent.
ContId is the primary key.
Table countries has columns such as CountryId, CountryName, Continent.
CountryId is the primary key.
Table car_makers has columns such as Id, Maker, FullName, Country.
Id is the primary key.
Table model_list has columns such as ModelId, Maker, Model.
ModelId is the primary key.
Table car_names has columns such as MakeId, Model, Make.
MakeId is the primary key.
Table cars_data has columns such as Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year.
Id is the primary key.
The Continent of countries is the foreign key of ContId of continents.
The Country of car_makers is the foreign key of CountryId of countries.
The Maker of model_list is the foreign key of Id of car_makers.
The Model of car_names is the foreign key of Model of model_list.
The Id of cars_data is the foreign key of MakeId of car_names.

##Role Access Policy (Column-Level):
Role: MarketAnalyst
Accessible Columns: continents: ContId, Continent; countries: CountryId, CountryName, Continent; car_makers: Id, Maker, FullName, Country; model_list: ModelId, Maker, Model; car_names: MakeId, Model, Make; cars_data: Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: What is the accelerate of the car make amc hornet sportabout (sw)?
Answer: SELECT T1.Accelerate FROM CARS_DATA AS T1 JOIN CAR_NAMES AS T2 ON T1.Id  =  T2.MakeId WHERE T2.Make  =  'amc hornet sportabout (sw)';
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT T1.Accelerate FROM CARS_DATA AS T1 JOIN CAR_NAMES AS T2 ON T1.Id  =  T2.MakeId WHERE T2.Make  =  'amc hornet sportabout (sw)';
##Instruction:
Database: car_1
Total Tables: 6
Total Columns: 23

Table Schemas:

car_1 contains tables such as continents, countries, car_makers, model_list, car_names, cars_data.
Table continents has columns such as ContId, Continent.
ContId is the primary key.
Table countries has columns such as CountryId, CountryName, Continent.
CountryId is the primary key.
Table car_makers has columns such as Id, Maker, FullName, Country.
Id is the primary key.
Table model_list has columns such as ModelId, Maker, Model.
ModelId is the primary key.
Table car_names has columns such as MakeId, Model, Make.
MakeId is the primary key.
Table cars_data has columns such as Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year.
Id is the primary key.
The Continent of countries is the foreign key of ContId of continents.
The Country of car_makers is the foreign key of CountryId of countries.
The Maker of model_list is the foreign key of Id of car_makers.
The Model of car_names is the foreign key of Model of model_list.
The Id of cars_data is the foreign key of MakeId of car_names.

##Role Access Policy (Column-Level):
Role: MarketAnalyst
Accessible Columns: continents: ContId, Continent; countries: CountryId, CountryName, Continent; car_makers: Id, Maker, FullName, Country; model_list: ModelId, Maker, Model; car_names: MakeId, Model, Make; cars_data: Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: How much does the car accelerate that makes amc hornet sportabout (sw)?
Answer: SELECT T1.Accelerate FROM CARS_DATA AS T1 JOIN CAR_NAMES AS T2 ON T1.Id  =  T2.MakeId WHERE T2.Make  =  'amc hornet sportabout (sw)';
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT T1.Accelerate FROM CARS_DATA AS T1 JOIN CAR_NAMES AS T2 ON T1.Id  =  T2.MakeId WHERE T2.Make  =  'amc hornet sportabout (sw)';
##Instruction:
Database: car_1
Total Tables: 6
Total Columns: 23

Table Schemas:

car_1 contains tables such as continents, countries, car_makers, model_list, car_names, cars_data.
Table continents has columns such as ContId, Continent.
ContId is the primary key.
Table countries has columns such as CountryId, CountryName, Continent.
CountryId is the primary key.
Table car_makers has columns such as Id, Maker, FullName, Country.
Id is the primary key.
Table model_list has columns such as ModelId, Maker, Model.
ModelId is the primary key.
Table car_names has columns such as MakeId, Model, Make.
MakeId is the primary key.
Table cars_data has columns such as Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year.
Id is the primary key.
The Continent of countries is the foreign key of ContId of continents.
The Country of car_makers is the foreign key of CountryId of countries.
The Maker of model_list is the foreign key of Id of car_makers.
The Model of car_names is the foreign key of Model of model_list.
The Id of cars_data is the foreign key of MakeId of car_names.

##Role Access Policy (Column-Level):
Role: MarketAnalyst
Accessible Columns: continents: ContId, Continent; countries: CountryId, CountryName, Continent; car_makers: Id, Maker, FullName, Country; model_list: ModelId, Maker, Model; car_names: MakeId, Model, Make; cars_data: Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: How many car makers are there in france?
Answer: SELECT count(*) FROM CAR_MAKERS AS T1 JOIN COUNTRIES AS T2 ON T1.Country  =  T2.CountryId WHERE T2.CountryName  =  'france';
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT count(*) FROM CAR_MAKERS AS T1 JOIN COUNTRIES AS T2 ON T1.Country  =  T2.CountryId WHERE T2.CountryName  =  'france';
##Instruction:
Database: car_1
Total Tables: 6
Total Columns: 23

Table Schemas:

car_1 contains tables such as continents, countries, car_makers, model_list, car_names, cars_data.
Table continents has columns such as ContId, Continent.
ContId is the primary key.
Table countries has columns such as CountryId, CountryName, Continent.
CountryId is the primary key.
Table car_makers has columns such as Id, Maker, FullName, Country.
Id is the primary key.
Table model_list has columns such as ModelId, Maker, Model.
ModelId is the primary key.
Table car_names has columns such as MakeId, Model, Make.
MakeId is the primary key.
Table cars_data has columns such as Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year.
Id is the primary key.
The Continent of countries is the foreign key of ContId of continents.
The Country of car_makers is the foreign key of CountryId of countries.
The Maker of model_list is the foreign key of Id of car_makers.
The Model of car_names is the foreign key of Model of model_list.
The Id of cars_data is the foreign key of MakeId of car_names.

##Role Access Policy (Column-Level):
Role: MarketAnalyst
Accessible Columns: continents: ContId, Continent; countries: CountryId, CountryName, Continent; car_makers: Id, Maker, FullName, Country; model_list: ModelId, Maker, Model; car_names: MakeId, Model, Make; cars_data: Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: What is the number of makers of care in France?
Answer: SELECT count(*) FROM CAR_MAKERS AS T1 JOIN COUNTRIES AS T2 ON T1.Country  =  T2.CountryId WHERE T2.CountryName  =  'france';
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT count(*) FROM CAR_MAKERS AS T1 JOIN COUNTRIES AS T2 ON T1.Country  =  T2.CountryId WHERE T2.CountryName  =  'france';
##Instruction:
Database: car_1
Total Tables: 6
Total Columns: 23

Table Schemas:

car_1 contains tables such as continents, countries, car_makers, model_list, car_names, cars_data.
Table continents has columns such as ContId, Continent.
ContId is the primary key.
Table countries has columns such as CountryId, CountryName, Continent.
CountryId is the primary key.
Table car_makers has columns such as Id, Maker, FullName, Country.
Id is the primary key.
Table model_list has columns such as ModelId, Maker, Model.
ModelId is the primary key.
Table car_names has columns such as MakeId, Model, Make.
MakeId is the primary key.
Table cars_data has columns such as Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year.
Id is the primary key.
The Continent of countries is the foreign key of ContId of continents.
The Country of car_makers is the foreign key of CountryId of countries.
The Maker of model_list is the foreign key of Id of car_makers.
The Model of car_names is the foreign key of Model of model_list.
The Id of cars_data is the foreign key of MakeId of car_names.

##Role Access Policy (Column-Level):
Role: MarketAnalyst
Accessible Columns: continents: ContId, Continent; countries: CountryId, CountryName, Continent; car_makers: Id, Maker, FullName, Country; model_list: ModelId, Maker, Model; car_names: MakeId, Model, Make; cars_data: Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: How many car models are produced in the usa?
Answer: SELECT count(*) FROM MODEL_LIST AS T1 JOIN CAR_MAKERS AS T2 ON T1.Maker  =  T2.Id JOIN COUNTRIES AS T3 ON T2.Country  =  T3.CountryId WHERE T3.CountryName  =  'usa';
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT count(*) FROM MODEL_LIST AS T1 JOIN CAR_MAKERS AS T2 ON T1.Maker  =  T2.Id JOIN COUNTRIES AS T3 ON T2.Country  =  T3.CountryId WHERE T3.CountryName  =  'usa';