##Instruction:
Database: products_for_hire
Total Tables: 7
Total Columns: 45

Table Schemas:

products_for_hire contains tables such as Discount_Coupons, Customers, Bookings, Products_for_Hire, Payments, Products_Booked, View_Product_Availability.
Table Discount_Coupons has columns such as coupon_id, date_issued, coupon_amount.
coupon_id is the primary key.
Table Customers has columns such as customer_id, coupon_id, good_or_bad_customer, first_name, last_name, gender_mf, date_became_customer, date_last_hire.
customer_id is the primary key.
Table Bookings has columns such as booking_id, customer_id, booking_status_code, returned_damaged_yn, booking_start_date, booking_end_date, count_hired, amount_payable, amount_of_discount, amount_outstanding, amount_of_refund.
booking_id is the primary key.
Table Products_for_Hire has columns such as product_id, product_type_code, daily_hire_cost, product_name, product_description.
product_id is the primary key.
Table Payments has columns such as payment_id, booking_id, customer_id, payment_type_code, amount_paid_in_full_yn, payment_date, amount_due, amount_paid.
payment_id is the primary key.
Table Products_Booked has columns such as booking_id, product_id, returned_yn, returned_late_yn, booked_count, booked_amount.
booking_id is the primary key.
Table View_Product_Availability has columns such as product_id, booking_id, status_date, available_yn.
status_date is the primary key.
The coupon_id of Customers is the foreign key of coupon_id of Discount_Coupons.
The customer_id of Bookings is the foreign key of customer_id of Customers.
The customer_id of Payments is the foreign key of customer_id of Customers.
The booking_id of Payments is the foreign key of booking_id of Bookings.
The product_id of Products_Booked is the foreign key of product_id of Products_for_Hire.
The booking_id of Products_Booked is the foreign key of booking_id of Bookings.
The product_id of View_Product_Availability is the foreign key of product_id of Products_for_Hire.
The booking_id of View_Product_Availability is the foreign key of booking_id of Bookings.

##Role Access Policy (Column-Level):
Role: CustomerServiceAgent
Accessible Columns: Customers: customer_id, first_name, last_name, date_became_customer, date_last_hire; Bookings: booking_id, customer_id, booking_status_code, booking_start_date, booking_end_date, count_hired, amount_payable, amount_of_discount, amount_outstanding; Products_for_Hire: product_id, product_name, daily_hire_cost, product_description; Products_Booked: booking_id, product_id, returned_yn, returned_late_yn, booked_count; Payments: payment_id, booking_id, customer_id, payment_type_code, payment_date, amount_due, amount_paid; Discount_Coupons: coupon_id, date_issued, coupon_amount; View_Product_Availability: product_id, booking_id, status_date, available_yn

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: How many bookings did each customer make? List the customer id, first name, and the count.
Answer: SELECT T1.customer_id ,  T1.first_name ,  count(*) FROM Customers AS T1 JOIN bookings AS T2 ON T1.customer_id  =  T2.customer_id GROUP BY T1.customer_id
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT T1.customer_id ,  T1.first_name ,  count(*) FROM Customers AS T1 JOIN bookings AS T2 ON T1.customer_id  =  T2.customer_id GROUP BY T1.customer_id