sharkiefff/RBAC-Text2SQL-Benchmark huggingface dataset:
##Instruction:
Database: music_2
Total Tables: 7
Total Columns: 22

Table Schemas:

music_2 contains tables such as Songs, Albums, Band, Instruments, Performance, Tracklists, Vocals.
Table Songs has columns such as SongId, Title.
SongId is the primary key.
Table Albums has columns such as AId, Title, Year, Label, Type.
AId is the primary key.
Table Band has columns such as Id, Firstname, Lastname.
Id is the primary key.
Table Instruments has columns such as SongId, BandmateId, Instrument.
SongId is the primary key.
Table Performance has columns such as SongId, Bandmate, StagePosition.
SongId is the primary key.
Table Tracklists has columns such as AlbumId, Position, SongId.
AlbumId is the primary key.
Table Vocals has columns such as SongId, Bandmate, Type.
SongId is the primary key.
The BandmateId of Instruments is the foreign key of Id of Band.
The SongId of Instruments is the foreign key of SongId of Songs.
The Bandmate of Performance is the foreign key of Id of Band.
The SongId of Performance is the foreign key of SongId of Songs.
The AlbumId of Tracklists is the foreign key of AId of Albums.
The SongId of Tracklists is the foreign key of SongId of Songs.
The Bandmate of Vocals is the foreign key of Id of Band.
The SongId of Vocals is the foreign key of SongId of Songs.

##Role Access Policy (Column-Level):
Role: MusicCatalogManager
Accessible Columns: Songs: SongId, Title; Albums: AId, Title, Year, Label, Type; Tracklists: ALL COLUMNS

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: What instrument did the musician with last name "Heilo" use in the song "Le Pop"?
Answer: Sorry, I cannot answer.
Permission: denied (Missing column permissions: band: id, lastname; instruments: bandmateid, instrument, songid; performance: SongId, bandmate)
Gold SQL: SELECT T4.instrument FROM Performance AS T1 JOIN Band AS T2 ON T1.bandmate  =  T2.id JOIN Songs AS T3 ON T3.SongId  =  T1.SongId JOIN Instruments AS T4 ON T4.songid  =  T3.songid AND T4.bandmateid  =  T2.id WHERE T2.lastname  =  "Heilo" AND T3.title  =  "Le Pop"
##Instruction:
Database: music_2
Total Tables: 7
Total Columns: 22

Table Schemas:

music_2 contains tables such as Songs, Albums, Band, Instruments, Performance, Tracklists, Vocals.
Table Songs has columns such as SongId, Title.
SongId is the primary key.
Table Albums has columns such as AId, Title, Year, Label, Type.
AId is the primary key.
Table Band has columns such as Id, Firstname, Lastname.
Id is the primary key.
Table Instruments has columns such as SongId, BandmateId, Instrument.
SongId is the primary key.
Table Performance has columns such as SongId, Bandmate, StagePosition.
SongId is the primary key.
Table Tracklists has columns such as AlbumId, Position, SongId.
AlbumId is the primary key.
Table Vocals has columns such as SongId, Bandmate, Type.
SongId is the primary key.
The BandmateId of Instruments is the foreign key of Id of Band.
The SongId of Instruments is the foreign key of SongId of Songs.
The Bandmate of Performance is the foreign key of Id of Band.
The SongId of Performance is the foreign key of SongId of Songs.
The AlbumId of Tracklists is the foreign key of AId of Albums.
The SongId of Tracklists is the foreign key of SongId of Songs.
The Bandmate of Vocals is the foreign key of Id of Band.
The SongId of Vocals is the foreign key of SongId of Songs.

##Role Access Policy (Column-Level):
Role: MusicCatalogManager
Accessible Columns: Songs: SongId, Title; Albums: AId, Title, Year, Label, Type; Tracklists: ALL COLUMNS

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: What instruments did the musician with the last name "Heilo" play in the song "Le Pop"?
Answer: Sorry, I cannot answer.
Permission: denied (Missing column permissions: band: id, lastname; instruments: bandmateid, instrument, songid; performance: SongId, bandmate)
Gold SQL: SELECT T4.instrument FROM Performance AS T1 JOIN Band AS T2 ON T1.bandmate  =  T2.id JOIN Songs AS T3 ON T3.SongId  =  T1.SongId JOIN Instruments AS T4 ON T4.songid  =  T3.songid AND T4.bandmateid  =  T2.id WHERE T2.lastname  =  "Heilo" AND T3.title  =  "Le Pop"
##Instruction:
Database: music_2
Total Tables: 7
Total Columns: 22

Table Schemas:

music_2 contains tables such as Songs, Albums, Band, Instruments, Performance, Tracklists, Vocals.
Table Songs has columns such as SongId, Title.
SongId is the primary key.
Table Albums has columns such as AId, Title, Year, Label, Type.
AId is the primary key.
Table Band has columns such as Id, Firstname, Lastname.
Id is the primary key.
Table Instruments has columns such as SongId, BandmateId, Instrument.
SongId is the primary key.
Table Performance has columns such as SongId, Bandmate, StagePosition.
SongId is the primary key.
Table Tracklists has columns such as AlbumId, Position, SongId.
AlbumId is the primary key.
Table Vocals has columns such as SongId, Bandmate, Type.
SongId is the primary key.
The BandmateId of Instruments is the foreign key of Id of Band.
The SongId of Instruments is the foreign key of SongId of Songs.
The Bandmate of Performance is the foreign key of Id of Band.
The SongId of Performance is the foreign key of SongId of Songs.
The AlbumId of Tracklists is the foreign key of AId of Albums.
The SongId of Tracklists is the foreign key of SongId of Songs.
The Bandmate of Vocals is the foreign key of Id of Band.
The SongId of Vocals is the foreign key of SongId of Songs.

##Role Access Policy (Column-Level):
Role: MusicCatalogManager
Accessible Columns: Songs: SongId, Title; Albums: AId, Title, Year, Label, Type; Tracklists: ALL COLUMNS

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: What is the most used instrument?
Answer: Sorry, I cannot answer.
Permission: denied (Missing column permissions: instruments: Instrument)
Gold SQL: SELECT instrument FROM instruments GROUP BY instrument ORDER BY count(*) DESC LIMIT 1
##Instruction:
Database: music_2
Total Tables: 7
Total Columns: 22

Table Schemas:

music_2 contains tables such as Songs, Albums, Band, Instruments, Performance, Tracklists, Vocals.
Table Songs has columns such as SongId, Title.
SongId is the primary key.
Table Albums has columns such as AId, Title, Year, Label, Type.
AId is the primary key.
Table Band has columns such as Id, Firstname, Lastname.
Id is the primary key.
Table Instruments has columns such as SongId, BandmateId, Instrument.
SongId is the primary key.
Table Performance has columns such as SongId, Bandmate, StagePosition.
SongId is the primary key.
Table Tracklists has columns such as AlbumId, Position, SongId.
AlbumId is the primary key.
Table Vocals has columns such as SongId, Bandmate, Type.
SongId is the primary key.
The BandmateId of Instruments is the foreign key of Id of Band.
The SongId of Instruments is the foreign key of SongId of Songs.
The Bandmate of Performance is the foreign key of Id of Band.
The SongId of Performance is the foreign key of SongId of Songs.
The AlbumId of Tracklists is the foreign key of AId of Albums.
The SongId of Tracklists is the foreign key of SongId of Songs.
The Bandmate of Vocals is the foreign key of Id of Band.
The SongId of Vocals is the foreign key of SongId of Songs.

##Role Access Policy (Column-Level):
Role: MusicCatalogManager
Accessible Columns: Songs: SongId, Title; Albums: AId, Title, Year, Label, Type; Tracklists: ALL COLUMNS

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: What instrument is used the most?
Answer: Sorry, I cannot answer.
Permission: denied (Missing column permissions: instruments: Instrument)
Gold SQL: SELECT instrument FROM instruments GROUP BY instrument ORDER BY count(*) DESC LIMIT 1
##Instruction:
Database: music_2
Total Tables: 7
Total Columns: 22

Table Schemas:

music_2 contains tables such as Songs, Albums, Band, Instruments, Performance, Tracklists, Vocals.
Table Songs has columns such as SongId, Title.
SongId is the primary key.
Table Albums has columns such as AId, Title, Year, Label, Type.
AId is the primary key.
Table Band has columns such as Id, Firstname, Lastname.
Id is the primary key.
Table Instruments has columns such as SongId, BandmateId, Instrument.
SongId is the primary key.
Table Performance has columns such as SongId, Bandmate, StagePosition.
SongId is the primary key.
Table Tracklists has columns such as AlbumId, Position, SongId.
AlbumId is the primary key.
Table Vocals has columns such as SongId, Bandmate, Type.
SongId is the primary key.
The BandmateId of Instruments is the foreign key of Id of Band.
The SongId of Instruments is the foreign key of SongId of Songs.
The Bandmate of Performance is the foreign key of Id of Band.
The SongId of Performance is the foreign key of SongId of Songs.
The AlbumId of Tracklists is the foreign key of AId of Albums.
The SongId of Tracklists is the foreign key of SongId of Songs.
The Bandmate of Vocals is the foreign key of Id of Band.
The SongId of Vocals is the foreign key of SongId of Songs.

##Role Access Policy (Column-Level):
Role: MusicCatalogManager
Accessible Columns: Songs: SongId, Title; Albums: AId, Title, Year, Label, Type; Tracklists: ALL COLUMNS

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: How many songs have used the instrument "drums"?
Answer: Sorry, I cannot answer.
Permission: denied (Missing column permissions: instruments: Instrument)
Gold SQL: SELECT count(*) FROM instruments WHERE instrument  =  "drums"
##Instruction:
Database: music_2
Total Tables: 7
Total Columns: 22

Table Schemas:

music_2 contains tables such as Songs, Albums, Band, Instruments, Performance, Tracklists, Vocals.
Table Songs has columns such as SongId, Title.
SongId is the primary key.
Table Albums has columns such as AId, Title, Year, Label, Type.
AId is the primary key.
Table Band has columns such as Id, Firstname, Lastname.
Id is the primary key.
Table Instruments has columns such as SongId, BandmateId, Instrument.
SongId is the primary key.
Table Performance has columns such as SongId, Bandmate, StagePosition.
SongId is the primary key.
Table Tracklists has columns such as AlbumId, Position, SongId.
AlbumId is the primary key.
Table Vocals has columns such as SongId, Bandmate, Type.
SongId is the primary key.
The BandmateId of Instruments is the foreign key of Id of Band.
The SongId of Instruments is the foreign key of SongId of Songs.
The Bandmate of Performance is the foreign key of Id of Band.
The SongId of Performance is the foreign key of SongId of Songs.
The AlbumId of Tracklists is the foreign key of AId of Albums.
The SongId of Tracklists is the foreign key of SongId of Songs.
The Bandmate of Vocals is the foreign key of Id of Band.
The SongId of Vocals is the foreign key of SongId of Songs.

##Role Access Policy (Column-Level):
Role: MusicCatalogManager
Accessible Columns: Songs: SongId, Title; Albums: AId, Title, Year, Label, Type; Tracklists: ALL COLUMNS

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: How many songs use drums as an instrument?
Answer: Sorry, I cannot answer.
Permission: denied (Missing column permissions: instruments: Instrument)
Gold SQL: SELECT count(*) FROM instruments WHERE instrument  =  "drums"
##Instruction:
Database: music_2
Total Tables: 7
Total Columns: 22

Table Schemas:

music_2 contains tables such as Songs, Albums, Band, Instruments, Performance, Tracklists, Vocals.
Table Songs has columns such as SongId, Title.
SongId is the primary key.
Table Albums has columns such as AId, Title, Year, Label, Type.
AId is the primary key.
Table Band has columns such as Id, Firstname, Lastname.
Id is the primary key.
Table Instruments has columns such as SongId, BandmateId, Instrument.
SongId is the primary key.
Table Performance has columns such as SongId, Bandmate, StagePosition.
SongId is the primary key.
Table Tracklists has columns such as AlbumId, Position, SongId.
AlbumId is the primary key.
Table Vocals has columns such as SongId, Bandmate, Type.
SongId is the primary key.
The BandmateId of Instruments is the foreign key of Id of Band.
The SongId of Instruments is the foreign key of SongId of Songs.
The Bandmate of Performance is the foreign key of Id of Band.
The SongId of Performance is the foreign key of SongId of Songs.
The AlbumId of Tracklists is the foreign key of AId of Albums.
The SongId of Tracklists is the foreign key of SongId of Songs.
The Bandmate of Vocals is the foreign key of Id of Band.
The SongId of Vocals is the foreign key of SongId of Songs.

##Role Access Policy (Column-Level):
Role: MusicCatalogManager
Accessible Columns: Songs: SongId, Title; Albums: AId, Title, Year, Label, Type; Tracklists: ALL COLUMNS

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: What instruments does the the song "Le Pop" use?
Answer: Sorry, I cannot answer.
Permission: denied (Missing column permissions: instruments: Instrument, songid)
Gold SQL: SELECT instrument FROM instruments AS T1 JOIN songs AS T2 ON T1.songid  =  T2.songid WHERE title  =  "Le Pop"
##Instruction:
Database: music_2
Total Tables: 7
Total Columns: 22

Table Schemas:

music_2 contains tables such as Songs, Albums, Band, Instruments, Performance, Tracklists, Vocals.
Table Songs has columns such as SongId, Title.
SongId is the primary key.
Table Albums has columns such as AId, Title, Year, Label, Type.
AId is the primary key.
Table Band has columns such as Id, Firstname, Lastname.
Id is the primary key.
Table Instruments has columns such as SongId, BandmateId, Instrument.
SongId is the primary key.
Table Performance has columns such as SongId, Bandmate, StagePosition.
SongId is the primary key.
Table Tracklists has columns such as AlbumId, Position, SongId.
AlbumId is the primary key.
Table Vocals has columns such as SongId, Bandmate, Type.
SongId is the primary key.
The BandmateId of Instruments is the foreign key of Id of Band.
The SongId of Instruments is the foreign key of SongId of Songs.
The Bandmate of Performance is the foreign key of Id of Band.
The SongId of Performance is the foreign key of SongId of Songs.
The AlbumId of Tracklists is the foreign key of AId of Albums.
The SongId of Tracklists is the foreign key of SongId of Songs.
The Bandmate of Vocals is the foreign key of Id of Band.
The SongId of Vocals is the foreign key of SongId of Songs.

##Role Access Policy (Column-Level):
Role: MusicCatalogManager
Accessible Columns: Songs: SongId, Title; Albums: AId, Title, Year, Label, Type; Tracklists: ALL COLUMNS

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: What are the instruments are used in the song "Le Pop"?
Answer: Sorry, I cannot answer.
Permission: denied (Missing column permissions: instruments: Instrument, songid)
Gold SQL: SELECT instrument FROM instruments AS T1 JOIN songs AS T2 ON T1.songid  =  T2.songid WHERE title  =  "Le Pop"
##Instruction:
Database: music_2
Total Tables: 7
Total Columns: 22

Table Schemas:

music_2 contains tables such as Songs, Albums, Band, Instruments, Performance, Tracklists, Vocals.
Table Songs has columns such as SongId, Title.
SongId is the primary key.
Table Albums has columns such as AId, Title, Year, Label, Type.
AId is the primary key.
Table Band has columns such as Id, Firstname, Lastname.
Id is the primary key.
Table Instruments has columns such as SongId, BandmateId, Instrument.
SongId is the primary key.
Table Performance has columns such as SongId, Bandmate, StagePosition.
SongId is the primary key.
Table Tracklists has columns such as AlbumId, Position, SongId.
AlbumId is the primary key.
Table Vocals has columns such as SongId, Bandmate, Type.
SongId is the primary key.
The BandmateId of Instruments is the foreign key of Id of Band.
The SongId of Instruments is the foreign key of SongId of Songs.
The Bandmate of Performance is the foreign key of Id of Band.
The SongId of Performance is the foreign key of SongId of Songs.
The AlbumId of Tracklists is the foreign key of AId of Albums.
The SongId of Tracklists is the foreign key of SongId of Songs.
The Bandmate of Vocals is the foreign key of Id of Band.
The SongId of Vocals is the foreign key of SongId of Songs.

##Role Access Policy (Column-Level):
Role: MusicCatalogManager
Accessible Columns: Songs: SongId, Title; Albums: AId, Title, Year, Label, Type; Tracklists: ALL COLUMNS

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: How many instruments does the song "Le Pop" use?
Answer: Sorry, I cannot answer.
Permission: denied (Missing column permissions: instruments: Instrument, songid)
Gold SQL: SELECT count(DISTINCT instrument) FROM instruments AS T1 JOIN songs AS T2 ON T1.songid  =  T2.songid WHERE title  =  "Le Pop"
##Instruction:
Database: music_2
Total Tables: 7
Total Columns: 22

Table Schemas:

music_2 contains tables such as Songs, Albums, Band, Instruments, Performance, Tracklists, Vocals.
Table Songs has columns such as SongId, Title.
SongId is the primary key.
Table Albums has columns such as AId, Title, Year, Label, Type.
AId is the primary key.
Table Band has columns such as Id, Firstname, Lastname.
Id is the primary key.
Table Instruments has columns such as SongId, BandmateId, Instrument.
SongId is the primary key.
Table Performance has columns such as SongId, Bandmate, StagePosition.
SongId is the primary key.
Table Tracklists has columns such as AlbumId, Position, SongId.
AlbumId is the primary key.
Table Vocals has columns such as SongId, Bandmate, Type.
SongId is the primary key.
The BandmateId of Instruments is the foreign key of Id of Band.
The SongId of Instruments is the foreign key of SongId of Songs.
The Bandmate of Performance is the foreign key of Id of Band.
The SongId of Performance is the foreign key of SongId of Songs.
The AlbumId of Tracklists is the foreign key of AId of Albums.
The SongId of Tracklists is the foreign key of SongId of Songs.
The Bandmate of Vocals is the foreign key of Id of Band.
The SongId of Vocals is the foreign key of SongId of Songs.

##Role Access Policy (Column-Level):
Role: MusicCatalogManager
Accessible Columns: Songs: SongId, Title; Albums: AId, Title, Year, Label, Type; Tracklists: ALL COLUMNS

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: How many different instruments are used in the song "Le Pop"?
Answer: Sorry, I cannot answer.
Permission: denied (Missing column permissions: instruments: Instrument, songid)
Gold SQL: SELECT count(DISTINCT instrument) FROM instruments AS T1 JOIN songs AS T2 ON T1.songid  =  T2.songid WHERE title  =  "Le Pop"
##Instruction:
Database: music_2
Total Tables: 7
Total Columns: 22

Table Schemas:

music_2 contains tables such as Songs, Albums, Band, Instruments, Performance, Tracklists, Vocals.
Table Songs has columns such as SongId, Title.
SongId is the primary key.
Table Albums has columns such as AId, Title, Year, Label, Type.
AId is the primary key.
Table Band has columns such as Id, Firstname, Lastname.
Id is the primary key.
Table Instruments has columns such as SongId, BandmateId, Instrument.
SongId is the primary key.
Table Performance has columns such as SongId, Bandmate, StagePosition.
SongId is the primary key.
Table Tracklists has columns such as AlbumId, Position, SongId.
AlbumId is the primary key.
Table Vocals has columns such as SongId, Bandmate, Type.
SongId is the primary key.
The BandmateId of Instruments is the foreign key of Id of Band.
The SongId of Instruments is the foreign key of SongId of Songs.
The Bandmate of Performance is the foreign key of Id of Band.
The SongId of Performance is the foreign key of SongId of Songs.
The AlbumId of Tracklists is the foreign key of AId of Albums.
The SongId of Tracklists is the foreign key of SongId of Songs.
The Bandmate of Vocals is the foreign key of Id of Band.
The SongId of Vocals is the foreign key of SongId of Songs.

##Role Access Policy (Column-Level):
Role: MusicCatalogManager
Accessible Columns: Songs: SongId, Title; Albums: AId, Title, Year, Label, Type; Tracklists: ALL COLUMNS

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: How many instrument does the musician with last name "Heilo" use?
Answer: Sorry, I cannot answer.
Permission: denied (Missing column permissions: band: id, lastname; instruments: Instrument, bandmateid)
Gold SQL: SELECT count(DISTINCT instrument) FROM instruments AS T1 JOIN Band AS T2 ON T1.bandmateid  =  T2.id WHERE T2.lastname  =  "Heilo"
##Instruction:
Database: music_2
Total Tables: 7
Total Columns: 22

Table Schemas:

music_2 contains tables such as Songs, Albums, Band, Instruments, Performance, Tracklists, Vocals.
Table Songs has columns such as SongId, Title.
SongId is the primary key.
Table Albums has columns such as AId, Title, Year, Label, Type.
AId is the primary key.
Table Band has columns such as Id, Firstname, Lastname.
Id is the primary key.
Table Instruments has columns such as SongId, BandmateId, Instrument.
SongId is the primary key.
Table Performance has columns such as SongId, Bandmate, StagePosition.
SongId is the primary key.
Table Tracklists has columns such as AlbumId, Position, SongId.
AlbumId is the primary key.
Table Vocals has columns such as SongId, Bandmate, Type.
SongId is the primary key.
The BandmateId of Instruments is the foreign key of Id of Band.
The SongId of Instruments is the foreign key of SongId of Songs.
The Bandmate of Performance is the foreign key of Id of Band.
The SongId of Performance is the foreign key of SongId of Songs.
The AlbumId of Tracklists is the foreign key of AId of Albums.
The SongId of Tracklists is the foreign key of SongId of Songs.
The Bandmate of Vocals is the foreign key of Id of Band.
The SongId of Vocals is the foreign key of SongId of Songs.

##Role Access Policy (Column-Level):
Role: MusicCatalogManager
Accessible Columns: Songs: SongId, Title; Albums: AId, Title, Year, Label, Type; Tracklists: ALL COLUMNS

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: How many different instruments does the musician with the last name "Heilo" use?
Answer: Sorry, I cannot answer.
Permission: denied (Missing column permissions: band: id, lastname; instruments: Instrument, bandmateid)
Gold SQL: SELECT count(DISTINCT instrument) FROM instruments AS T1 JOIN Band AS T2 ON T1.bandmateid  =  T2.id WHERE T2.lastname  =  "Heilo"