sharkiefff/RBAC-Text2SQL-Benchmark huggingface dataset:
##Instruction:
Database: music_2
Total Tables: 7
Total Columns: 22

Table Schemas:

music_2 contains tables such as Songs, Albums, Band, Instruments, Performance, Tracklists, Vocals.
Table Songs has columns such as SongId, Title.
SongId is the primary key.
Table Albums has columns such as AId, Title, Year, Label, Type.
AId is the primary key.
Table Band has columns such as Id, Firstname, Lastname.
Id is the primary key.
Table Instruments has columns such as SongId, BandmateId, Instrument.
SongId is the primary key.
Table Performance has columns such as SongId, Bandmate, StagePosition.
SongId is the primary key.
Table Tracklists has columns such as AlbumId, Position, SongId.
AlbumId is the primary key.
Table Vocals has columns such as SongId, Bandmate, Type.
SongId is the primary key.
The BandmateId of Instruments is the foreign key of Id of Band.
The SongId of Instruments is the foreign key of SongId of Songs.
The Bandmate of Performance is the foreign key of Id of Band.
The SongId of Performance is the foreign key of SongId of Songs.
The AlbumId of Tracklists is the foreign key of AId of Albums.
The SongId of Tracklists is the foreign key of SongId of Songs.
The Bandmate of Vocals is the foreign key of Id of Band.
The SongId of Vocals is the foreign key of SongId of Songs.

##Role Access Policy (Column-Level):
Role: MusicAnalyst
Accessible Columns: Songs: SongId, Title; Albums: AId, Title, Year, Label, Type; Tracklists: AlbumId, Position, SongId; Performance: SongId, Bandmate, StagePosition; Instruments: SongId, BandmateId, Instrument; Vocals: SongId, Bandmate, Type

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: Who is performing in the back stage position for the song "Der Kapitan"? Show the first name and last name.
Answer: Sorry, I cannot answer.
Permission: denied (Missing column permissions: band: firstname, id, lastname)
Gold SQL: SELECT T2.firstname ,  T2.lastname FROM Performance AS T1 JOIN Band AS T2 ON T1.bandmate  =  T2.id JOIN Songs AS T3 ON T3.SongId  =  T1.SongId WHERE T3.Title  =  "Der Kapitan" AND T1.StagePosition  =  "back"
##Instruction:
Database: music_2
Total Tables: 7
Total Columns: 22

Table Schemas:

music_2 contains tables such as Songs, Albums, Band, Instruments, Performance, Tracklists, Vocals.
Table Songs has columns such as SongId, Title.
SongId is the primary key.
Table Albums has columns such as AId, Title, Year, Label, Type.
AId is the primary key.
Table Band has columns such as Id, Firstname, Lastname.
Id is the primary key.
Table Instruments has columns such as SongId, BandmateId, Instrument.
SongId is the primary key.
Table Performance has columns such as SongId, Bandmate, StagePosition.
SongId is the primary key.
Table Tracklists has columns such as AlbumId, Position, SongId.
AlbumId is the primary key.
Table Vocals has columns such as SongId, Bandmate, Type.
SongId is the primary key.
The BandmateId of Instruments is the foreign key of Id of Band.
The SongId of Instruments is the foreign key of SongId of Songs.
The Bandmate of Performance is the foreign key of Id of Band.
The SongId of Performance is the foreign key of SongId of Songs.
The AlbumId of Tracklists is the foreign key of AId of Albums.
The SongId of Tracklists is the foreign key of SongId of Songs.
The Bandmate of Vocals is the foreign key of Id of Band.
The SongId of Vocals is the foreign key of SongId of Songs.

##Role Access Policy (Column-Level):
Role: MusicAnalyst
Accessible Columns: Songs: SongId, Title; Albums: AId, Title, Year, Label, Type; Tracklists: AlbumId, Position, SongId; Performance: SongId, Bandmate, StagePosition; Instruments: SongId, BandmateId, Instrument; Vocals: SongId, Bandmate, Type

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: What is the first and last name of the artist who performed back stage for the song "Der Kapitan"?
Answer: Sorry, I cannot answer.
Permission: denied (Missing column permissions: band: firstname, id, lastname)
Gold SQL: SELECT T2.firstname ,  T2.lastname FROM Performance AS T1 JOIN Band AS T2 ON T1.bandmate  =  T2.id JOIN Songs AS T3 ON T3.SongId  =  T1.SongId WHERE T3.Title  =  "Der Kapitan" AND T1.StagePosition  =  "back"
##Instruction:
Database: music_2
Total Tables: 7
Total Columns: 22

Table Schemas:

music_2 contains tables such as Songs, Albums, Band, Instruments, Performance, Tracklists, Vocals.
Table Songs has columns such as SongId, Title.
SongId is the primary key.
Table Albums has columns such as AId, Title, Year, Label, Type.
AId is the primary key.
Table Band has columns such as Id, Firstname, Lastname.
Id is the primary key.
Table Instruments has columns such as SongId, BandmateId, Instrument.
SongId is the primary key.
Table Performance has columns such as SongId, Bandmate, StagePosition.
SongId is the primary key.
Table Tracklists has columns such as AlbumId, Position, SongId.
AlbumId is the primary key.
Table Vocals has columns such as SongId, Bandmate, Type.
SongId is the primary key.
The BandmateId of Instruments is the foreign key of Id of Band.
The SongId of Instruments is the foreign key of SongId of Songs.
The Bandmate of Performance is the foreign key of Id of Band.
The SongId of Performance is the foreign key of SongId of Songs.
The AlbumId of Tracklists is the foreign key of AId of Albums.
The SongId of Tracklists is the foreign key of SongId of Songs.
The Bandmate of Vocals is the foreign key of Id of Band.
The SongId of Vocals is the foreign key of SongId of Songs.

##Role Access Policy (Column-Level):
Role: MusicAnalyst
Accessible Columns: Songs: SongId, Title; Albums: AId, Title, Year, Label, Type; Tracklists: AlbumId, Position, SongId; Performance: SongId, Bandmate, StagePosition; Instruments: SongId, BandmateId, Instrument; Vocals: SongId, Bandmate, Type

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: Find the name of songs that does not have a back vocal.
Answer: SELECT DISTINCT title FROM vocals AS t1 JOIN songs AS t2 ON t1.songid  =  t2.songid EXCEPT SELECT t2.title FROM vocals AS t1 JOIN songs AS t2 ON t1.songid  =  t2.songid WHERE TYPE  =  "back"
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT DISTINCT title FROM vocals AS t1 JOIN songs AS t2 ON t1.songid  =  t2.songid EXCEPT SELECT t2.title FROM vocals AS t1 JOIN songs AS t2 ON t1.songid  =  t2.songid WHERE TYPE  =  "back"
##Instruction:
Database: music_2
Total Tables: 7
Total Columns: 22

Table Schemas:

music_2 contains tables such as Songs, Albums, Band, Instruments, Performance, Tracklists, Vocals.
Table Songs has columns such as SongId, Title.
SongId is the primary key.
Table Albums has columns such as AId, Title, Year, Label, Type.
AId is the primary key.
Table Band has columns such as Id, Firstname, Lastname.
Id is the primary key.
Table Instruments has columns such as SongId, BandmateId, Instrument.
SongId is the primary key.
Table Performance has columns such as SongId, Bandmate, StagePosition.
SongId is the primary key.
Table Tracklists has columns such as AlbumId, Position, SongId.
AlbumId is the primary key.
Table Vocals has columns such as SongId, Bandmate, Type.
SongId is the primary key.
The BandmateId of Instruments is the foreign key of Id of Band.
The SongId of Instruments is the foreign key of SongId of Songs.
The Bandmate of Performance is the foreign key of Id of Band.
The SongId of Performance is the foreign key of SongId of Songs.
The AlbumId of Tracklists is the foreign key of AId of Albums.
The SongId of Tracklists is the foreign key of SongId of Songs.
The Bandmate of Vocals is the foreign key of Id of Band.
The SongId of Vocals is the foreign key of SongId of Songs.

##Role Access Policy (Column-Level):
Role: MusicAnalyst
Accessible Columns: Songs: SongId, Title; Albums: AId, Title, Year, Label, Type; Tracklists: AlbumId, Position, SongId; Performance: SongId, Bandmate, StagePosition; Instruments: SongId, BandmateId, Instrument; Vocals: SongId, Bandmate, Type

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: What are the names of the songs that do not have back vocals?
Answer: SELECT DISTINCT title FROM vocals AS t1 JOIN songs AS t2 ON t1.songid  =  t2.songid EXCEPT SELECT t2.title FROM vocals AS t1 JOIN songs AS t2 ON t1.songid  =  t2.songid WHERE TYPE  =  "back"
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT DISTINCT title FROM vocals AS t1 JOIN songs AS t2 ON t1.songid  =  t2.songid EXCEPT SELECT t2.title FROM vocals AS t1 JOIN songs AS t2 ON t1.songid  =  t2.songid WHERE TYPE  =  "back"
##Instruction:
Database: music_2
Total Tables: 7
Total Columns: 22

Table Schemas:

music_2 contains tables such as Songs, Albums, Band, Instruments, Performance, Tracklists, Vocals.
Table Songs has columns such as SongId, Title.
SongId is the primary key.
Table Albums has columns such as AId, Title, Year, Label, Type.
AId is the primary key.
Table Band has columns such as Id, Firstname, Lastname.
Id is the primary key.
Table Instruments has columns such as SongId, BandmateId, Instrument.
SongId is the primary key.
Table Performance has columns such as SongId, Bandmate, StagePosition.
SongId is the primary key.
Table Tracklists has columns such as AlbumId, Position, SongId.
AlbumId is the primary key.
Table Vocals has columns such as SongId, Bandmate, Type.
SongId is the primary key.
The BandmateId of Instruments is the foreign key of Id of Band.
The SongId of Instruments is the foreign key of SongId of Songs.
The Bandmate of Performance is the foreign key of Id of Band.
The SongId of Performance is the foreign key of SongId of Songs.
The AlbumId of Tracklists is the foreign key of AId of Albums.
The SongId of Tracklists is the foreign key of SongId of Songs.
The Bandmate of Vocals is the foreign key of Id of Band.
The SongId of Vocals is the foreign key of SongId of Songs.

##Role Access Policy (Column-Level):
Role: MusicAnalyst
Accessible Columns: Songs: SongId, Title; Albums: AId, Title, Year, Label, Type; Tracklists: AlbumId, Position, SongId; Performance: SongId, Bandmate, StagePosition; Instruments: SongId, BandmateId, Instrument; Vocals: SongId, Bandmate, Type

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: What are the songs in album "A Kiss Before You Go: Live in Hamburg"?
Answer: SELECT T3.title FROM albums AS T1 JOIN tracklists AS T2 ON T1.aid  =  T2.albumid JOIN songs AS T3 ON T2.songid  =  T3.songid WHERE T1.title  =  "A Kiss Before You Go: Live in Hamburg"
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT T3.title FROM albums AS T1 JOIN tracklists AS T2 ON T1.aid  =  T2.albumid JOIN songs AS T3 ON T2.songid  =  T3.songid WHERE T1.title  =  "A Kiss Before You Go: Live in Hamburg"
##Instruction:
Database: music_2
Total Tables: 7
Total Columns: 22

Table Schemas:

music_2 contains tables such as Songs, Albums, Band, Instruments, Performance, Tracklists, Vocals.
Table Songs has columns such as SongId, Title.
SongId is the primary key.
Table Albums has columns such as AId, Title, Year, Label, Type.
AId is the primary key.
Table Band has columns such as Id, Firstname, Lastname.
Id is the primary key.
Table Instruments has columns such as SongId, BandmateId, Instrument.
SongId is the primary key.
Table Performance has columns such as SongId, Bandmate, StagePosition.
SongId is the primary key.
Table Tracklists has columns such as AlbumId, Position, SongId.
AlbumId is the primary key.
Table Vocals has columns such as SongId, Bandmate, Type.
SongId is the primary key.
The BandmateId of Instruments is the foreign key of Id of Band.
The SongId of Instruments is the foreign key of SongId of Songs.
The Bandmate of Performance is the foreign key of Id of Band.
The SongId of Performance is the foreign key of SongId of Songs.
The AlbumId of Tracklists is the foreign key of AId of Albums.
The SongId of Tracklists is the foreign key of SongId of Songs.
The Bandmate of Vocals is the foreign key of Id of Band.
The SongId of Vocals is the foreign key of SongId of Songs.

##Role Access Policy (Column-Level):
Role: MusicAnalyst
Accessible Columns: Songs: SongId, Title; Albums: AId, Title, Year, Label, Type; Tracklists: AlbumId, Position, SongId; Performance: SongId, Bandmate, StagePosition; Instruments: SongId, BandmateId, Instrument; Vocals: SongId, Bandmate, Type

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: What are the song titles on the album "A Kiss Before You Go: Live in Hamburg"?
Answer: SELECT T3.title FROM albums AS T1 JOIN tracklists AS T2 ON T1.aid  =  T2.albumid JOIN songs AS T3 ON T2.songid  =  T3.songid WHERE T1.title  =  "A Kiss Before You Go: Live in Hamburg"
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT T3.title FROM albums AS T1 JOIN tracklists AS T2 ON T1.aid  =  T2.albumid JOIN songs AS T3 ON T2.songid  =  T3.songid WHERE T1.title  =  "A Kiss Before You Go: Live in Hamburg"
##Instruction:
Database: music_2
Total Tables: 7
Total Columns: 22

Table Schemas:

music_2 contains tables such as Songs, Albums, Band, Instruments, Performance, Tracklists, Vocals.
Table Songs has columns such as SongId, Title.
SongId is the primary key.
Table Albums has columns such as AId, Title, Year, Label, Type.
AId is the primary key.
Table Band has columns such as Id, Firstname, Lastname.
Id is the primary key.
Table Instruments has columns such as SongId, BandmateId, Instrument.
SongId is the primary key.
Table Performance has columns such as SongId, Bandmate, StagePosition.
SongId is the primary key.
Table Tracklists has columns such as AlbumId, Position, SongId.
AlbumId is the primary key.
Table Vocals has columns such as SongId, Bandmate, Type.
SongId is the primary key.
The BandmateId of Instruments is the foreign key of Id of Band.
The SongId of Instruments is the foreign key of SongId of Songs.
The Bandmate of Performance is the foreign key of Id of Band.
The SongId of Performance is the foreign key of SongId of Songs.
The AlbumId of Tracklists is the foreign key of AId of Albums.
The SongId of Tracklists is the foreign key of SongId of Songs.
The Bandmate of Vocals is the foreign key of Id of Band.
The SongId of Vocals is the foreign key of SongId of Songs.

##Role Access Policy (Column-Level):
Role: MusicAnalyst
Accessible Columns: Songs: SongId, Title; Albums: AId, Title, Year, Label, Type; Tracklists: AlbumId, Position, SongId; Performance: SongId, Bandmate, StagePosition; Instruments: SongId, BandmateId, Instrument; Vocals: SongId, Bandmate, Type

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: What are all the songs in albums under label "Universal Music Group"?
Answer: SELECT T3.title FROM albums AS T1 JOIN tracklists AS T2 ON T1.aid  =  T2.albumid JOIN songs AS T3 ON T2.songid  =  T3.songid WHERE t1.label  =  "Universal Music Group"
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT T3.title FROM albums AS T1 JOIN tracklists AS T2 ON T1.aid  =  T2.albumid JOIN songs AS T3 ON T2.songid  =  T3.songid WHERE t1.label  =  "Universal Music Group"
##Instruction:
Database: music_2
Total Tables: 7
Total Columns: 22

Table Schemas:

music_2 contains tables such as Songs, Albums, Band, Instruments, Performance, Tracklists, Vocals.
Table Songs has columns such as SongId, Title.
SongId is the primary key.
Table Albums has columns such as AId, Title, Year, Label, Type.
AId is the primary key.
Table Band has columns such as Id, Firstname, Lastname.
Id is the primary key.
Table Instruments has columns such as SongId, BandmateId, Instrument.
SongId is the primary key.
Table Performance has columns such as SongId, Bandmate, StagePosition.
SongId is the primary key.
Table Tracklists has columns such as AlbumId, Position, SongId.
AlbumId is the primary key.
Table Vocals has columns such as SongId, Bandmate, Type.
SongId is the primary key.
The BandmateId of Instruments is the foreign key of Id of Band.
The SongId of Instruments is the foreign key of SongId of Songs.
The Bandmate of Performance is the foreign key of Id of Band.
The SongId of Performance is the foreign key of SongId of Songs.
The AlbumId of Tracklists is the foreign key of AId of Albums.
The SongId of Tracklists is the foreign key of SongId of Songs.
The Bandmate of Vocals is the foreign key of Id of Band.
The SongId of Vocals is the foreign key of SongId of Songs.

##Role Access Policy (Column-Level):
Role: MusicAnalyst
Accessible Columns: Songs: SongId, Title; Albums: AId, Title, Year, Label, Type; Tracklists: AlbumId, Position, SongId; Performance: SongId, Bandmate, StagePosition; Instruments: SongId, BandmateId, Instrument; Vocals: SongId, Bandmate, Type

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: What are the names of all the songs whose album is under the label of "Universal Music Group"?
Answer: SELECT T3.title FROM albums AS T1 JOIN tracklists AS T2 ON T1.aid  =  T2.albumid JOIN songs AS T3 ON T2.songid  =  T3.songid WHERE t1.label  =  "Universal Music Group"
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT T3.title FROM albums AS T1 JOIN tracklists AS T2 ON T1.aid  =  T2.albumid JOIN songs AS T3 ON T2.songid  =  T3.songid WHERE t1.label  =  "Universal Music Group"
##Instruction:
Database: music_2
Total Tables: 7
Total Columns: 22

Table Schemas:

music_2 contains tables such as Songs, Albums, Band, Instruments, Performance, Tracklists, Vocals.
Table Songs has columns such as SongId, Title.
SongId is the primary key.
Table Albums has columns such as AId, Title, Year, Label, Type.
AId is the primary key.
Table Band has columns such as Id, Firstname, Lastname.
Id is the primary key.
Table Instruments has columns such as SongId, BandmateId, Instrument.
SongId is the primary key.
Table Performance has columns such as SongId, Bandmate, StagePosition.
SongId is the primary key.
Table Tracklists has columns such as AlbumId, Position, SongId.
AlbumId is the primary key.
Table Vocals has columns such as SongId, Bandmate, Type.
SongId is the primary key.
The BandmateId of Instruments is the foreign key of Id of Band.
The SongId of Instruments is the foreign key of SongId of Songs.
The Bandmate of Performance is the foreign key of Id of Band.
The SongId of Performance is the foreign key of SongId of Songs.
The AlbumId of Tracklists is the foreign key of AId of Albums.
The SongId of Tracklists is the foreign key of SongId of Songs.
The Bandmate of Vocals is the foreign key of Id of Band.
The SongId of Vocals is the foreign key of SongId of Songs.

##Role Access Policy (Column-Level):
Role: MusicAnalyst
Accessible Columns: Songs: SongId, Title; Albums: AId, Title, Year, Label, Type; Tracklists: AlbumId, Position, SongId; Performance: SongId, Bandmate, StagePosition; Instruments: SongId, BandmateId, Instrument; Vocals: SongId, Bandmate, Type

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: Find the number of songs in all the studio albums.
Answer: SELECT count(DISTINCT T3.title) FROM albums AS T1 JOIN tracklists AS T2 ON T1.aid  =  T2.albumid JOIN songs AS T3 ON T2.songid  =  T3.songid WHERE t1.type  =  "Studio"
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT count(DISTINCT T3.title) FROM albums AS T1 JOIN tracklists AS T2 ON T1.aid  =  T2.albumid JOIN songs AS T3 ON T2.songid  =  T3.songid WHERE t1.type  =  "Studio"
##Instruction:
Database: music_2
Total Tables: 7
Total Columns: 22

Table Schemas:

music_2 contains tables such as Songs, Albums, Band, Instruments, Performance, Tracklists, Vocals.
Table Songs has columns such as SongId, Title.
SongId is the primary key.
Table Albums has columns such as AId, Title, Year, Label, Type.
AId is the primary key.
Table Band has columns such as Id, Firstname, Lastname.
Id is the primary key.
Table Instruments has columns such as SongId, BandmateId, Instrument.
SongId is the primary key.
Table Performance has columns such as SongId, Bandmate, StagePosition.
SongId is the primary key.
Table Tracklists has columns such as AlbumId, Position, SongId.
AlbumId is the primary key.
Table Vocals has columns such as SongId, Bandmate, Type.
SongId is the primary key.
The BandmateId of Instruments is the foreign key of Id of Band.
The SongId of Instruments is the foreign key of SongId of Songs.
The Bandmate of Performance is the foreign key of Id of Band.
The SongId of Performance is the foreign key of SongId of Songs.
The AlbumId of Tracklists is the foreign key of AId of Albums.
The SongId of Tracklists is the foreign key of SongId of Songs.
The Bandmate of Vocals is the foreign key of Id of Band.
The SongId of Vocals is the foreign key of SongId of Songs.

##Role Access Policy (Column-Level):
Role: MusicAnalyst
Accessible Columns: Songs: SongId, Title; Albums: AId, Title, Year, Label, Type; Tracklists: AlbumId, Position, SongId; Performance: SongId, Bandmate, StagePosition; Instruments: SongId, BandmateId, Instrument; Vocals: SongId, Bandmate, Type

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: How many songs appear in studio albums?
Answer: SELECT count(DISTINCT T3.title) FROM albums AS T1 JOIN tracklists AS T2 ON T1.aid  =  T2.albumid JOIN songs AS T3 ON T2.songid  =  T3.songid WHERE t1.type  =  "Studio"
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT count(DISTINCT T3.title) FROM albums AS T1 JOIN tracklists AS T2 ON T1.aid  =  T2.albumid JOIN songs AS T3 ON T2.songid  =  T3.songid WHERE t1.type  =  "Studio"