sharkiefff/RBAC-Text2SQL-Benchmark huggingface dataset:
##Instruction:
Database: music_2
Total Tables: 7
Total Columns: 22

Table Schemas:

music_2 contains tables such as Songs, Albums, Band, Instruments, Performance, Tracklists, Vocals.
Table Songs has columns such as SongId, Title.
SongId is the primary key.
Table Albums has columns such as AId, Title, Year, Label, Type.
AId is the primary key.
Table Band has columns such as Id, Firstname, Lastname.
Id is the primary key.
Table Instruments has columns such as SongId, BandmateId, Instrument.
SongId is the primary key.
Table Performance has columns such as SongId, Bandmate, StagePosition.
SongId is the primary key.
Table Tracklists has columns such as AlbumId, Position, SongId.
AlbumId is the primary key.
Table Vocals has columns such as SongId, Bandmate, Type.
SongId is the primary key.
The BandmateId of Instruments is the foreign key of Id of Band.
The SongId of Instruments is the foreign key of SongId of Songs.
The Bandmate of Performance is the foreign key of Id of Band.
The SongId of Performance is the foreign key of SongId of Songs.
The AlbumId of Tracklists is the foreign key of AId of Albums.
The SongId of Tracklists is the foreign key of SongId of Songs.
The Bandmate of Vocals is the foreign key of Id of Band.
The SongId of Vocals is the foreign key of SongId of Songs.

##Role Access Policy (Column-Level):
Role: VocalCoordinator
Accessible Columns: Songs: SongId, Title; Band: Id, Firstname, Lastname; Vocals: ALL COLUMNS

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: What is the last name of the artist who sang the most songs?
Answer: Sorry, I cannot answer.
Permission: denied (Missing column permissions: performance: SongId, bandmate)
Gold SQL: SELECT T2.lastname FROM Performance AS T1 JOIN Band AS T2 ON T1.bandmate  =  T2.id JOIN Songs AS T3 ON T3.SongId  =  T1.SongId GROUP BY lastname ORDER BY count(*) DESC LIMIT 1
##Instruction:
Database: music_2
Total Tables: 7
Total Columns: 22

Table Schemas:

music_2 contains tables such as Songs, Albums, Band, Instruments, Performance, Tracklists, Vocals.
Table Songs has columns such as SongId, Title.
SongId is the primary key.
Table Albums has columns such as AId, Title, Year, Label, Type.
AId is the primary key.
Table Band has columns such as Id, Firstname, Lastname.
Id is the primary key.
Table Instruments has columns such as SongId, BandmateId, Instrument.
SongId is the primary key.
Table Performance has columns such as SongId, Bandmate, StagePosition.
SongId is the primary key.
Table Tracklists has columns such as AlbumId, Position, SongId.
AlbumId is the primary key.
Table Vocals has columns such as SongId, Bandmate, Type.
SongId is the primary key.
The BandmateId of Instruments is the foreign key of Id of Band.
The SongId of Instruments is the foreign key of SongId of Songs.
The Bandmate of Performance is the foreign key of Id of Band.
The SongId of Performance is the foreign key of SongId of Songs.
The AlbumId of Tracklists is the foreign key of AId of Albums.
The SongId of Tracklists is the foreign key of SongId of Songs.
The Bandmate of Vocals is the foreign key of Id of Band.
The SongId of Vocals is the foreign key of SongId of Songs.

##Role Access Policy (Column-Level):
Role: VocalCoordinator
Accessible Columns: Songs: SongId, Title; Band: Id, Firstname, Lastname; Vocals: ALL COLUMNS

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: What instrument did the musician with last name "Heilo" use in the song "Badlands"?
Answer: Sorry, I cannot answer.
Permission: denied (Missing column permissions: instruments: bandmateid, instrument, songid; performance: SongId, bandmate)
Gold SQL: SELECT T4.instrument FROM Performance AS T1 JOIN Band AS T2 ON T1.bandmate  =  T2.id JOIN Songs AS T3 ON T3.SongId  =  T1.SongId JOIN Instruments AS T4 ON T4.songid  =  T3.songid AND T4.bandmateid  =  T2.id WHERE T2.lastname  =  "Heilo" AND T3.title  =  "Badlands"
##Instruction:
Database: music_2
Total Tables: 7
Total Columns: 22

Table Schemas:

music_2 contains tables such as Songs, Albums, Band, Instruments, Performance, Tracklists, Vocals.
Table Songs has columns such as SongId, Title.
SongId is the primary key.
Table Albums has columns such as AId, Title, Year, Label, Type.
AId is the primary key.
Table Band has columns such as Id, Firstname, Lastname.
Id is the primary key.
Table Instruments has columns such as SongId, BandmateId, Instrument.
SongId is the primary key.
Table Performance has columns such as SongId, Bandmate, StagePosition.
SongId is the primary key.
Table Tracklists has columns such as AlbumId, Position, SongId.
AlbumId is the primary key.
Table Vocals has columns such as SongId, Bandmate, Type.
SongId is the primary key.
The BandmateId of Instruments is the foreign key of Id of Band.
The SongId of Instruments is the foreign key of SongId of Songs.
The Bandmate of Performance is the foreign key of Id of Band.
The SongId of Performance is the foreign key of SongId of Songs.
The AlbumId of Tracklists is the foreign key of AId of Albums.
The SongId of Tracklists is the foreign key of SongId of Songs.
The Bandmate of Vocals is the foreign key of Id of Band.
The SongId of Vocals is the foreign key of SongId of Songs.

##Role Access Policy (Column-Level):
Role: VocalCoordinator
Accessible Columns: Songs: SongId, Title; Band: Id, Firstname, Lastname; Vocals: ALL COLUMNS

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: What instruments did the musician with the last name "Heilo" play in "Badlands"?
Answer: Sorry, I cannot answer.
Permission: denied (Missing column permissions: instruments: bandmateid, instrument, songid; performance: SongId, bandmate)
Gold SQL: SELECT T4.instrument FROM Performance AS T1 JOIN Band AS T2 ON T1.bandmate  =  T2.id JOIN Songs AS T3 ON T3.SongId  =  T1.SongId JOIN Instruments AS T4 ON T4.songid  =  T3.songid AND T4.bandmateid  =  T2.id WHERE T2.lastname  =  "Heilo" AND T3.title  =  "Badlands"
##Instruction:
Database: music_2
Total Tables: 7
Total Columns: 22

Table Schemas:

music_2 contains tables such as Songs, Albums, Band, Instruments, Performance, Tracklists, Vocals.
Table Songs has columns such as SongId, Title.
SongId is the primary key.
Table Albums has columns such as AId, Title, Year, Label, Type.
AId is the primary key.
Table Band has columns such as Id, Firstname, Lastname.
Id is the primary key.
Table Instruments has columns such as SongId, BandmateId, Instrument.
SongId is the primary key.
Table Performance has columns such as SongId, Bandmate, StagePosition.
SongId is the primary key.
Table Tracklists has columns such as AlbumId, Position, SongId.
AlbumId is the primary key.
Table Vocals has columns such as SongId, Bandmate, Type.
SongId is the primary key.
The BandmateId of Instruments is the foreign key of Id of Band.
The SongId of Instruments is the foreign key of SongId of Songs.
The Bandmate of Performance is the foreign key of Id of Band.
The SongId of Performance is the foreign key of SongId of Songs.
The AlbumId of Tracklists is the foreign key of AId of Albums.
The SongId of Tracklists is the foreign key of SongId of Songs.
The Bandmate of Vocals is the foreign key of Id of Band.
The SongId of Vocals is the foreign key of SongId of Songs.

##Role Access Policy (Column-Level):
Role: VocalCoordinator
Accessible Columns: Songs: SongId, Title; Band: Id, Firstname, Lastname; Vocals: ALL COLUMNS

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: How many instruments does the song "Badlands" use?
Answer: Sorry, I cannot answer.
Permission: denied (Missing column permissions: instruments: Instrument, songid)
Gold SQL: SELECT count(DISTINCT instrument) FROM instruments AS T1 JOIN songs AS T2 ON T1.songid  =  T2.songid WHERE title  =  "Badlands"
##Instruction:
Database: music_2
Total Tables: 7
Total Columns: 22

Table Schemas:

music_2 contains tables such as Songs, Albums, Band, Instruments, Performance, Tracklists, Vocals.
Table Songs has columns such as SongId, Title.
SongId is the primary key.
Table Albums has columns such as AId, Title, Year, Label, Type.
AId is the primary key.
Table Band has columns such as Id, Firstname, Lastname.
Id is the primary key.
Table Instruments has columns such as SongId, BandmateId, Instrument.
SongId is the primary key.
Table Performance has columns such as SongId, Bandmate, StagePosition.
SongId is the primary key.
Table Tracklists has columns such as AlbumId, Position, SongId.
AlbumId is the primary key.
Table Vocals has columns such as SongId, Bandmate, Type.
SongId is the primary key.
The BandmateId of Instruments is the foreign key of Id of Band.
The SongId of Instruments is the foreign key of SongId of Songs.
The Bandmate of Performance is the foreign key of Id of Band.
The SongId of Performance is the foreign key of SongId of Songs.
The AlbumId of Tracklists is the foreign key of AId of Albums.
The SongId of Tracklists is the foreign key of SongId of Songs.
The Bandmate of Vocals is the foreign key of Id of Band.
The SongId of Vocals is the foreign key of SongId of Songs.

##Role Access Policy (Column-Level):
Role: VocalCoordinator
Accessible Columns: Songs: SongId, Title; Band: Id, Firstname, Lastname; Vocals: ALL COLUMNS

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: How many different instruments are used in the song "Badlands"?
Answer: Sorry, I cannot answer.
Permission: denied (Missing column permissions: instruments: Instrument, songid)
Gold SQL: SELECT count(DISTINCT instrument) FROM instruments AS T1 JOIN songs AS T2 ON T1.songid  =  T2.songid WHERE title  =  "Badlands"
##Instruction:
Database: music_2
Total Tables: 7
Total Columns: 22

Table Schemas:

music_2 contains tables such as Songs, Albums, Band, Instruments, Performance, Tracklists, Vocals.
Table Songs has columns such as SongId, Title.
SongId is the primary key.
Table Albums has columns such as AId, Title, Year, Label, Type.
AId is the primary key.
Table Band has columns such as Id, Firstname, Lastname.
Id is the primary key.
Table Instruments has columns such as SongId, BandmateId, Instrument.
SongId is the primary key.
Table Performance has columns such as SongId, Bandmate, StagePosition.
SongId is the primary key.
Table Tracklists has columns such as AlbumId, Position, SongId.
AlbumId is the primary key.
Table Vocals has columns such as SongId, Bandmate, Type.
SongId is the primary key.
The BandmateId of Instruments is the foreign key of Id of Band.
The SongId of Instruments is the foreign key of SongId of Songs.
The Bandmate of Performance is the foreign key of Id of Band.
The SongId of Performance is the foreign key of SongId of Songs.
The AlbumId of Tracklists is the foreign key of AId of Albums.
The SongId of Tracklists is the foreign key of SongId of Songs.
The Bandmate of Vocals is the foreign key of Id of Band.
The SongId of Vocals is the foreign key of SongId of Songs.

##Role Access Policy (Column-Level):
Role: VocalCoordinator
Accessible Columns: Songs: SongId, Title; Band: Id, Firstname, Lastname; Vocals: ALL COLUMNS

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: What are the vocal types used in song "Badlands"?
Answer: SELECT TYPE FROM vocals AS T1 JOIN songs AS T2 ON T1.songid  =  T2.songid WHERE title  =  "Badlands"
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT TYPE FROM vocals AS T1 JOIN songs AS T2 ON T1.songid  =  T2.songid WHERE title  =  "Badlands"
##Instruction:
Database: music_2
Total Tables: 7
Total Columns: 22

Table Schemas:

music_2 contains tables such as Songs, Albums, Band, Instruments, Performance, Tracklists, Vocals.
Table Songs has columns such as SongId, Title.
SongId is the primary key.
Table Albums has columns such as AId, Title, Year, Label, Type.
AId is the primary key.
Table Band has columns such as Id, Firstname, Lastname.
Id is the primary key.
Table Instruments has columns such as SongId, BandmateId, Instrument.
SongId is the primary key.
Table Performance has columns such as SongId, Bandmate, StagePosition.
SongId is the primary key.
Table Tracklists has columns such as AlbumId, Position, SongId.
AlbumId is the primary key.
Table Vocals has columns such as SongId, Bandmate, Type.
SongId is the primary key.
The BandmateId of Instruments is the foreign key of Id of Band.
The SongId of Instruments is the foreign key of SongId of Songs.
The Bandmate of Performance is the foreign key of Id of Band.
The SongId of Performance is the foreign key of SongId of Songs.
The AlbumId of Tracklists is the foreign key of AId of Albums.
The SongId of Tracklists is the foreign key of SongId of Songs.
The Bandmate of Vocals is the foreign key of Id of Band.
The SongId of Vocals is the foreign key of SongId of Songs.

##Role Access Policy (Column-Level):
Role: VocalCoordinator
Accessible Columns: Songs: SongId, Title; Band: Id, Firstname, Lastname; Vocals: ALL COLUMNS

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: What types of vocals are used in the song "Badlands"?
Answer: SELECT TYPE FROM vocals AS T1 JOIN songs AS T2 ON T1.songid  =  T2.songid WHERE title  =  "Badlands"
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT TYPE FROM vocals AS T1 JOIN songs AS T2 ON T1.songid  =  T2.songid WHERE title  =  "Badlands"
##Instruction:
Database: music_2
Total Tables: 7
Total Columns: 22

Table Schemas:

music_2 contains tables such as Songs, Albums, Band, Instruments, Performance, Tracklists, Vocals.
Table Songs has columns such as SongId, Title.
SongId is the primary key.
Table Albums has columns such as AId, Title, Year, Label, Type.
AId is the primary key.
Table Band has columns such as Id, Firstname, Lastname.
Id is the primary key.
Table Instruments has columns such as SongId, BandmateId, Instrument.
SongId is the primary key.
Table Performance has columns such as SongId, Bandmate, StagePosition.
SongId is the primary key.
Table Tracklists has columns such as AlbumId, Position, SongId.
AlbumId is the primary key.
Table Vocals has columns such as SongId, Bandmate, Type.
SongId is the primary key.
The BandmateId of Instruments is the foreign key of Id of Band.
The SongId of Instruments is the foreign key of SongId of Songs.
The Bandmate of Performance is the foreign key of Id of Band.
The SongId of Performance is the foreign key of SongId of Songs.
The AlbumId of Tracklists is the foreign key of AId of Albums.
The SongId of Tracklists is the foreign key of SongId of Songs.
The Bandmate of Vocals is the foreign key of Id of Band.
The SongId of Vocals is the foreign key of SongId of Songs.

##Role Access Policy (Column-Level):
Role: VocalCoordinator
Accessible Columns: Songs: SongId, Title; Band: Id, Firstname, Lastname; Vocals: ALL COLUMNS

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: Find the number of vocal types used in song "Le Pop"
Answer: SELECT count(*) FROM vocals AS T1 JOIN songs AS T2 ON T1.songid  =  T2.songid WHERE title  =  "Le Pop"
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT count(*) FROM vocals AS T1 JOIN songs AS T2 ON T1.songid  =  T2.songid WHERE title  =  "Le Pop"
##Instruction:
Database: music_2
Total Tables: 7
Total Columns: 22

Table Schemas:

music_2 contains tables such as Songs, Albums, Band, Instruments, Performance, Tracklists, Vocals.
Table Songs has columns such as SongId, Title.
SongId is the primary key.
Table Albums has columns such as AId, Title, Year, Label, Type.
AId is the primary key.
Table Band has columns such as Id, Firstname, Lastname.
Id is the primary key.
Table Instruments has columns such as SongId, BandmateId, Instrument.
SongId is the primary key.
Table Performance has columns such as SongId, Bandmate, StagePosition.
SongId is the primary key.
Table Tracklists has columns such as AlbumId, Position, SongId.
AlbumId is the primary key.
Table Vocals has columns such as SongId, Bandmate, Type.
SongId is the primary key.
The BandmateId of Instruments is the foreign key of Id of Band.
The SongId of Instruments is the foreign key of SongId of Songs.
The Bandmate of Performance is the foreign key of Id of Band.
The SongId of Performance is the foreign key of SongId of Songs.
The AlbumId of Tracklists is the foreign key of AId of Albums.
The SongId of Tracklists is the foreign key of SongId of Songs.
The Bandmate of Vocals is the foreign key of Id of Band.
The SongId of Vocals is the foreign key of SongId of Songs.

##Role Access Policy (Column-Level):
Role: VocalCoordinator
Accessible Columns: Songs: SongId, Title; Band: Id, Firstname, Lastname; Vocals: ALL COLUMNS

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: How many vocal types are used in the song "Le Pop"?
Answer: SELECT count(*) FROM vocals AS T1 JOIN songs AS T2 ON T1.songid  =  T2.songid WHERE title  =  "Le Pop"
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT count(*) FROM vocals AS T1 JOIN songs AS T2 ON T1.songid  =  T2.songid WHERE title  =  "Le Pop"
##Instruction:
Database: music_2
Total Tables: 7
Total Columns: 22

Table Schemas:

music_2 contains tables such as Songs, Albums, Band, Instruments, Performance, Tracklists, Vocals.
Table Songs has columns such as SongId, Title.
SongId is the primary key.
Table Albums has columns such as AId, Title, Year, Label, Type.
AId is the primary key.
Table Band has columns such as Id, Firstname, Lastname.
Id is the primary key.
Table Instruments has columns such as SongId, BandmateId, Instrument.
SongId is the primary key.
Table Performance has columns such as SongId, Bandmate, StagePosition.
SongId is the primary key.
Table Tracklists has columns such as AlbumId, Position, SongId.
AlbumId is the primary key.
Table Vocals has columns such as SongId, Bandmate, Type.
SongId is the primary key.
The BandmateId of Instruments is the foreign key of Id of Band.
The SongId of Instruments is the foreign key of SongId of Songs.
The Bandmate of Performance is the foreign key of Id of Band.
The SongId of Performance is the foreign key of SongId of Songs.
The AlbumId of Tracklists is the foreign key of AId of Albums.
The SongId of Tracklists is the foreign key of SongId of Songs.
The Bandmate of Vocals is the foreign key of Id of Band.
The SongId of Vocals is the foreign key of SongId of Songs.

##Role Access Policy (Column-Level):
Role: VocalCoordinator
Accessible Columns: Songs: SongId, Title; Band: Id, Firstname, Lastname; Vocals: ALL COLUMNS

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: How many songs have a shared vocal?
Answer: SELECT count(DISTINCT title) FROM vocals AS T1 JOIN songs AS T2 ON T1.songid  =  T2.songid WHERE TYPE  =  "shared"
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT count(DISTINCT title) FROM vocals AS T1 JOIN songs AS T2 ON T1.songid  =  T2.songid WHERE TYPE  =  "shared"
##Instruction:
Database: music_2
Total Tables: 7
Total Columns: 22

Table Schemas:

music_2 contains tables such as Songs, Albums, Band, Instruments, Performance, Tracklists, Vocals.
Table Songs has columns such as SongId, Title.
SongId is the primary key.
Table Albums has columns such as AId, Title, Year, Label, Type.
AId is the primary key.
Table Band has columns such as Id, Firstname, Lastname.
Id is the primary key.
Table Instruments has columns such as SongId, BandmateId, Instrument.
SongId is the primary key.
Table Performance has columns such as SongId, Bandmate, StagePosition.
SongId is the primary key.
Table Tracklists has columns such as AlbumId, Position, SongId.
AlbumId is the primary key.
Table Vocals has columns such as SongId, Bandmate, Type.
SongId is the primary key.
The BandmateId of Instruments is the foreign key of Id of Band.
The SongId of Instruments is the foreign key of SongId of Songs.
The Bandmate of Performance is the foreign key of Id of Band.
The SongId of Performance is the foreign key of SongId of Songs.
The AlbumId of Tracklists is the foreign key of AId of Albums.
The SongId of Tracklists is the foreign key of SongId of Songs.
The Bandmate of Vocals is the foreign key of Id of Band.
The SongId of Vocals is the foreign key of SongId of Songs.

##Role Access Policy (Column-Level):
Role: VocalCoordinator
Accessible Columns: Songs: SongId, Title; Band: Id, Firstname, Lastname; Vocals: ALL COLUMNS

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: How many different songs have shared vocals?
Answer: SELECT count(DISTINCT title) FROM vocals AS T1 JOIN songs AS T2 ON T1.songid  =  T2.songid WHERE TYPE  =  "shared"
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT count(DISTINCT title) FROM vocals AS T1 JOIN songs AS T2 ON T1.songid  =  T2.songid WHERE TYPE  =  "shared"