##Instruction:
Database: sakila_1
Total Tables: 16
Total Columns: 89

Table Schemas:

sakila_1 contains tables such as actor, address, category, city, country, customer, film, film_actor, film_category, film_text, inventory, language, payment, rental, staff, store.
Table actor has columns such as actor_id, first_name, last_name, last_update.
actor_id is the primary key.
Table address has columns such as address_id, address, address2, district, city_id, postal_code, phone, last_update.
address_id is the primary key.
Table category has columns such as category_id, name, last_update.
category_id is the primary key.
Table city has columns such as city_id, city, country_id, last_update.
city_id is the primary key.
Table country has columns such as country_id, country, last_update.
country_id is the primary key.
Table customer has columns such as customer_id, store_id, first_name, last_name, email, address_id, active, create_date, last_update.
customer_id is the primary key.
Table film has columns such as film_id, title, description, release_year, language_id, original_language_id, rental_duration, rental_rate, length, replacement_cost, rating, special_features, last_update.
film_id is the primary key.
Table film_actor has columns such as actor_id, film_id, last_update.
actor_id is the primary key.
Table film_category has columns such as film_id, category_id, last_update.
film_id is the primary key.
Table film_text has columns such as film_id, title, description.
film_id is the primary key.
Table inventory has columns such as inventory_id, film_id, store_id, last_update.
inventory_id is the primary key.
Table language has columns such as language_id, name, last_update.
language_id is the primary key.
Table payment has columns such as payment_id, customer_id, staff_id, rental_id, amount, payment_date, last_update.
payment_id is the primary key.
Table rental has columns such as rental_id, rental_date, inventory_id, customer_id, return_date, staff_id, last_update.
rental_id is the primary key.
Table staff has columns such as staff_id, first_name, last_name, address_id, picture, email, store_id, active, username, password, last_update.
staff_id is the primary key.
Table store has columns such as store_id, manager_staff_id, address_id, last_update.
store_id is the primary key.
The city_id of address is the foreign key of city_id of city.
The country_id of city is the foreign key of country_id of country.
The store_id of customer is the foreign key of store_id of store.
The address_id of customer is the foreign key of address_id of address.
The original_language_id of film is the foreign key of language_id of language.
The language_id of film is the foreign key of language_id of language.
The film_id of film_actor is the foreign key of film_id of film.
The actor_id of film_actor is the foreign key of actor_id of actor.
The category_id of film_category is the foreign key of category_id of category.
The film_id of film_category is the foreign key of film_id of film.
The film_id of inventory is the foreign key of film_id of film.
The store_id of inventory is the foreign key of store_id of store.
The staff_id of payment is the foreign key of staff_id of staff.
The customer_id of payment is the foreign key of customer_id of customer.
The rental_id of payment is the foreign key of rental_id of rental.
The customer_id of rental is the foreign key of customer_id of customer.
The inventory_id of rental is the foreign key of inventory_id of inventory.
The staff_id of rental is the foreign key of staff_id of staff.
The address_id of staff is the foreign key of address_id of address.
The address_id of store is the foreign key of address_id of address.
The manager_staff_id of store is the foreign key of staff_id of staff.

##Role Access Policy (Column-Level):
Role: ContentManager
Accessible Columns: actor: ALL COLUMNS; category: ALL COLUMNS; film: ALL COLUMNS; film_actor: ALL COLUMNS; film_category: ALL COLUMNS; film_text: ALL COLUMNS; language: ALL COLUMNS

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: What are the names and ids of the different categories, and how many films are in each?
Answer: SELECT T2.name ,  T1.category_id ,  count(*) FROM film_category AS T1 JOIN category AS T2 ON T1.category_id  =  T2.category_id GROUP BY T1.category_id
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT T2.name ,  T1.category_id ,  count(*) FROM film_category AS T1 JOIN category AS T2 ON T1.category_id  =  T2.category_id GROUP BY T1.category_id