##Instruction:
Database: cre_Doc_Tracking_DB
Total Tables: 8
Total Columns: 33

Table Schemas:

cre_Doc_Tracking_DB contains tables such as Ref_Document_Types, Ref_Calendar, Ref_Locations, Roles, All_Documents, Employees, Document_Locations, Documents_to_be_Destroyed.
Table Ref_Document_Types has columns such as Document_Type_Code, Document_Type_Name, Document_Type_Description.
Document_Type_Code is the primary key.
Table Ref_Calendar has columns such as Calendar_Date, Day_Number.
Calendar_Date is the primary key.
Table Ref_Locations has columns such as Location_Code, Location_Name, Location_Description.
Location_Code is the primary key.
Table Roles has columns such as Role_Code, Role_Name, Role_Description.
Role_Code is the primary key.
Table All_Documents has columns such as Document_ID, Date_Stored, Document_Type_Code, Document_Name, Document_Description, Other_Details.
Document_ID is the primary key.
Table Employees has columns such as Employee_ID, Role_Code, Employee_Name, Gender_MFU, Date_of_Birth, Other_Details.
Employee_ID is the primary key.
Table Document_Locations has columns such as Document_ID, Location_Code, Date_in_Location_From, Date_in_Locaton_To.
Document_ID is the primary key.
Table Documents_to_be_Destroyed has columns such as Document_ID, Destruction_Authorised_by_Employee_ID, Destroyed_by_Employee_ID, Planned_Destruction_Date, Actual_Destruction_Date, Other_Details.
Document_ID is the primary key.
The Date_Stored of All_Documents is the foreign key of Calendar_Date of Ref_Calendar.
The Document_Type_Code of All_Documents is the foreign key of Document_Type_Code of Ref_Document_Types.
The Role_Code of Employees is the foreign key of Role_Code of Roles.
The Document_ID of Document_Locations is the foreign key of Document_ID of All_Documents.
The Date_in_Locaton_To of Document_Locations is the foreign key of Calendar_Date of Ref_Calendar.
The Date_in_Location_From of Document_Locations is the foreign key of Calendar_Date of Ref_Calendar.
The Location_Code of Document_Locations is the foreign key of Location_Code of Ref_Locations.
The Document_ID of Documents_to_be_Destroyed is the foreign key of Document_ID of All_Documents.
The Actual_Destruction_Date of Documents_to_be_Destroyed is the foreign key of Calendar_Date of Ref_Calendar.
The Planned_Destruction_Date of Documents_to_be_Destroyed is the foreign key of Calendar_Date of Ref_Calendar.
The Destruction_Authorised_by_Employee_ID of Documents_to_be_Destroyed is the foreign key of Employee_ID of Employees.
The Destroyed_by_Employee_ID of Documents_to_be_Destroyed is the foreign key of Employee_ID of Employees.

##Role Access Policy (Column-Level):
Role: Auditor
Accessible Columns: All_Documents: Document_ID, Date_Stored, Document_Type_Code, Document_Name, Document_Description, Other_Details; Document_Locations: ALL COLUMNS; Documents_to_be_Destroyed: Document_ID, Planned_Destruction_Date, Actual_Destruction_Date, Other_Details; Ref_Document_Types: Document_Type_Code, Document_Type_Name; Ref_Locations: Location_Code, Location_Name; Ref_Calendar: Calendar_Date; Employees: Employee_ID, Employee_Name

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: Show the location name and code with the least documents.
Answer: SELECT T2.location_name ,  T1.location_code FROM Document_locations AS T1 JOIN Ref_locations AS T2 ON T1.location_code  =  T2.location_code GROUP BY T1.location_code ORDER BY count(*) ASC LIMIT 1
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT T2.location_name ,  T1.location_code FROM Document_locations AS T1 JOIN Ref_locations AS T2 ON T1.location_code  =  T2.location_code GROUP BY T1.location_code ORDER BY count(*) ASC LIMIT 1