sharkiefff/RBAC-Text2SQL-Benchmark huggingface dataset:
##Instruction:
Database: allergy_1
Total Tables: 3
Total Columns: 12

Table Schemas:

allergy_1 contains tables such as Allergy_Type, Has_Allergy, Student.
Table Allergy_Type has columns such as Allergy, AllergyType.
Allergy is the primary key.
Table Has_Allergy has columns such as StuID, Allergy.
Table Student has columns such as StuID, LName, Fname, Age, Sex, Major, Advisor, city_code.
StuID is the primary key.
The Allergy of Has_Allergy is the foreign key of Allergy of Allergy_Type.
The StuID of Has_Allergy is the foreign key of StuID of Student.

##Role Access Policy (Column-Level):
Role: HealthServicesCoordinator
Accessible Columns: Student: StuID, LName, Fname, Age, Sex; Has_Allergy: ALL COLUMNS; Allergy_Type: ALL COLUMNS

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: Which students are unaffected by allergies?
Answer: SELECT StuID FROM Student EXCEPT SELECT StuID FROM Has_allergy
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT StuID FROM Student EXCEPT SELECT StuID FROM Has_allergy
##Instruction:
Database: allergy_1
Total Tables: 3
Total Columns: 12

Table Schemas:

allergy_1 contains tables such as Allergy_Type, Has_Allergy, Student.
Table Allergy_Type has columns such as Allergy, AllergyType.
Allergy is the primary key.
Table Has_Allergy has columns such as StuID, Allergy.
Table Student has columns such as StuID, LName, Fname, Age, Sex, Major, Advisor, city_code.
StuID is the primary key.
The Allergy of Has_Allergy is the foreign key of Allergy of Allergy_Type.
The StuID of Has_Allergy is the foreign key of StuID of Student.

##Role Access Policy (Column-Level):
Role: HealthServicesCoordinator
Accessible Columns: Student: StuID, LName, Fname, Age, Sex; Has_Allergy: ALL COLUMNS; Allergy_Type: ALL COLUMNS

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: How many female students have milk or egg allergies?
Answer: SELECT count(*) FROM has_allergy AS T1 JOIN Student AS T2 ON T1.StuID  =  T2.StuID WHERE T2.sex  =  "F" AND T1.allergy  =  "Milk" OR T1.allergy  =  "Eggs"
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT count(*) FROM has_allergy AS T1 JOIN Student AS T2 ON T1.StuID  =  T2.StuID WHERE T2.sex  =  "F" AND T1.allergy  =  "Milk" OR T1.allergy  =  "Eggs"
##Instruction:
Database: allergy_1
Total Tables: 3
Total Columns: 12

Table Schemas:

allergy_1 contains tables such as Allergy_Type, Has_Allergy, Student.
Table Allergy_Type has columns such as Allergy, AllergyType.
Allergy is the primary key.
Table Has_Allergy has columns such as StuID, Allergy.
Table Student has columns such as StuID, LName, Fname, Age, Sex, Major, Advisor, city_code.
StuID is the primary key.
The Allergy of Has_Allergy is the foreign key of Allergy of Allergy_Type.
The StuID of Has_Allergy is the foreign key of StuID of Student.

##Role Access Policy (Column-Level):
Role: HealthServicesCoordinator
Accessible Columns: Student: StuID, LName, Fname, Age, Sex; Has_Allergy: ALL COLUMNS; Allergy_Type: ALL COLUMNS

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: How many students who are female are allergic to milk or eggs?
Answer: SELECT count(*) FROM has_allergy AS T1 JOIN Student AS T2 ON T1.StuID  =  T2.StuID WHERE T2.sex  =  "F" AND T1.allergy  =  "Milk" OR T1.allergy  =  "Eggs"
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT count(*) FROM has_allergy AS T1 JOIN Student AS T2 ON T1.StuID  =  T2.StuID WHERE T2.sex  =  "F" AND T1.allergy  =  "Milk" OR T1.allergy  =  "Eggs"
##Instruction:
Database: allergy_1
Total Tables: 3
Total Columns: 12

Table Schemas:

allergy_1 contains tables such as Allergy_Type, Has_Allergy, Student.
Table Allergy_Type has columns such as Allergy, AllergyType.
Allergy is the primary key.
Table Has_Allergy has columns such as StuID, Allergy.
Table Student has columns such as StuID, LName, Fname, Age, Sex, Major, Advisor, city_code.
StuID is the primary key.
The Allergy of Has_Allergy is the foreign key of Allergy of Allergy_Type.
The StuID of Has_Allergy is the foreign key of StuID of Student.

##Role Access Policy (Column-Level):
Role: HealthServicesCoordinator
Accessible Columns: Student: StuID, LName, Fname, Age, Sex; Has_Allergy: ALL COLUMNS; Allergy_Type: ALL COLUMNS

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: How many students have a food allergy?
Answer: SELECT count(*) FROM Has_allergy AS T1 JOIN Allergy_type AS T2 ON T1.allergy  =  T2.allergy WHERE T2.allergytype  =  "food"
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT count(*) FROM Has_allergy AS T1 JOIN Allergy_type AS T2 ON T1.allergy  =  T2.allergy WHERE T2.allergytype  =  "food"
##Instruction:
Database: allergy_1
Total Tables: 3
Total Columns: 12

Table Schemas:

allergy_1 contains tables such as Allergy_Type, Has_Allergy, Student.
Table Allergy_Type has columns such as Allergy, AllergyType.
Allergy is the primary key.
Table Has_Allergy has columns such as StuID, Allergy.
Table Student has columns such as StuID, LName, Fname, Age, Sex, Major, Advisor, city_code.
StuID is the primary key.
The Allergy of Has_Allergy is the foreign key of Allergy of Allergy_Type.
The StuID of Has_Allergy is the foreign key of StuID of Student.

##Role Access Policy (Column-Level):
Role: HealthServicesCoordinator
Accessible Columns: Student: StuID, LName, Fname, Age, Sex; Has_Allergy: ALL COLUMNS; Allergy_Type: ALL COLUMNS

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: How many students are affected by food related allergies?
Answer: SELECT count(*) FROM Has_allergy AS T1 JOIN Allergy_type AS T2 ON T1.allergy  =  T2.allergy WHERE T2.allergytype  =  "food"
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT count(*) FROM Has_allergy AS T1 JOIN Allergy_type AS T2 ON T1.allergy  =  T2.allergy WHERE T2.allergytype  =  "food"
##Instruction:
Database: allergy_1
Total Tables: 3
Total Columns: 12

Table Schemas:

allergy_1 contains tables such as Allergy_Type, Has_Allergy, Student.
Table Allergy_Type has columns such as Allergy, AllergyType.
Allergy is the primary key.
Table Has_Allergy has columns such as StuID, Allergy.
Table Student has columns such as StuID, LName, Fname, Age, Sex, Major, Advisor, city_code.
StuID is the primary key.
The Allergy of Has_Allergy is the foreign key of Allergy of Allergy_Type.
The StuID of Has_Allergy is the foreign key of StuID of Student.

##Role Access Policy (Column-Level):
Role: HealthServicesCoordinator
Accessible Columns: Student: StuID, LName, Fname, Age, Sex; Has_Allergy: ALL COLUMNS; Allergy_Type: ALL COLUMNS

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: Which allergy has most number of students affected?
Answer: SELECT Allergy FROM Has_allergy GROUP BY Allergy ORDER BY count(*) DESC LIMIT 1
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT Allergy FROM Has_allergy GROUP BY Allergy ORDER BY count(*) DESC LIMIT 1
##Instruction:
Database: allergy_1
Total Tables: 3
Total Columns: 12

Table Schemas:

allergy_1 contains tables such as Allergy_Type, Has_Allergy, Student.
Table Allergy_Type has columns such as Allergy, AllergyType.
Allergy is the primary key.
Table Has_Allergy has columns such as StuID, Allergy.
Table Student has columns such as StuID, LName, Fname, Age, Sex, Major, Advisor, city_code.
StuID is the primary key.
The Allergy of Has_Allergy is the foreign key of Allergy of Allergy_Type.
The StuID of Has_Allergy is the foreign key of StuID of Student.

##Role Access Policy (Column-Level):
Role: HealthServicesCoordinator
Accessible Columns: Student: StuID, LName, Fname, Age, Sex; Has_Allergy: ALL COLUMNS; Allergy_Type: ALL COLUMNS

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: Which allergy is the most common?
Answer: SELECT Allergy FROM Has_allergy GROUP BY Allergy ORDER BY count(*) DESC LIMIT 1
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT Allergy FROM Has_allergy GROUP BY Allergy ORDER BY count(*) DESC LIMIT 1
##Instruction:
Database: allergy_1
Total Tables: 3
Total Columns: 12

Table Schemas:

allergy_1 contains tables such as Allergy_Type, Has_Allergy, Student.
Table Allergy_Type has columns such as Allergy, AllergyType.
Allergy is the primary key.
Table Has_Allergy has columns such as StuID, Allergy.
Table Student has columns such as StuID, LName, Fname, Age, Sex, Major, Advisor, city_code.
StuID is the primary key.
The Allergy of Has_Allergy is the foreign key of Allergy of Allergy_Type.
The StuID of Has_Allergy is the foreign key of StuID of Student.

##Role Access Policy (Column-Level):
Role: HealthServicesCoordinator
Accessible Columns: Student: StuID, LName, Fname, Age, Sex; Has_Allergy: ALL COLUMNS; Allergy_Type: ALL COLUMNS

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: Show all allergies with number of students affected.
Answer: SELECT Allergy ,  count(*) FROM Has_allergy GROUP BY Allergy
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT Allergy ,  count(*) FROM Has_allergy GROUP BY Allergy
##Instruction:
Database: allergy_1
Total Tables: 3
Total Columns: 12

Table Schemas:

allergy_1 contains tables such as Allergy_Type, Has_Allergy, Student.
Table Allergy_Type has columns such as Allergy, AllergyType.
Allergy is the primary key.
Table Has_Allergy has columns such as StuID, Allergy.
Table Student has columns such as StuID, LName, Fname, Age, Sex, Major, Advisor, city_code.
StuID is the primary key.
The Allergy of Has_Allergy is the foreign key of Allergy of Allergy_Type.
The StuID of Has_Allergy is the foreign key of StuID of Student.

##Role Access Policy (Column-Level):
Role: HealthServicesCoordinator
Accessible Columns: Student: StuID, LName, Fname, Age, Sex; Has_Allergy: ALL COLUMNS; Allergy_Type: ALL COLUMNS

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: How many students have each different allergy?
Answer: SELECT Allergy ,  count(*) FROM Has_allergy GROUP BY Allergy
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT Allergy ,  count(*) FROM Has_allergy GROUP BY Allergy
##Instruction:
Database: allergy_1
Total Tables: 3
Total Columns: 12

Table Schemas:

allergy_1 contains tables such as Allergy_Type, Has_Allergy, Student.
Table Allergy_Type has columns such as Allergy, AllergyType.
Allergy is the primary key.
Table Has_Allergy has columns such as StuID, Allergy.
Table Student has columns such as StuID, LName, Fname, Age, Sex, Major, Advisor, city_code.
StuID is the primary key.
The Allergy of Has_Allergy is the foreign key of Allergy of Allergy_Type.
The StuID of Has_Allergy is the foreign key of StuID of Student.

##Role Access Policy (Column-Level):
Role: HealthServicesCoordinator
Accessible Columns: Student: StuID, LName, Fname, Age, Sex; Has_Allergy: ALL COLUMNS; Allergy_Type: ALL COLUMNS

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: Show all allergy type with number of students affected.
Answer: SELECT T2.allergytype ,  count(*) FROM Has_allergy AS T1 JOIN Allergy_type AS T2 ON T1.allergy  =  T2.allergy GROUP BY T2.allergytype
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT T2.allergytype ,  count(*) FROM Has_allergy AS T1 JOIN Allergy_type AS T2 ON T1.allergy  =  T2.allergy GROUP BY T2.allergytype
##Instruction:
Database: allergy_1
Total Tables: 3
Total Columns: 12

Table Schemas:

allergy_1 contains tables such as Allergy_Type, Has_Allergy, Student.
Table Allergy_Type has columns such as Allergy, AllergyType.
Allergy is the primary key.
Table Has_Allergy has columns such as StuID, Allergy.
Table Student has columns such as StuID, LName, Fname, Age, Sex, Major, Advisor, city_code.
StuID is the primary key.
The Allergy of Has_Allergy is the foreign key of Allergy of Allergy_Type.
The StuID of Has_Allergy is the foreign key of StuID of Student.

##Role Access Policy (Column-Level):
Role: HealthServicesCoordinator
Accessible Columns: Student: StuID, LName, Fname, Age, Sex; Has_Allergy: ALL COLUMNS; Allergy_Type: ALL COLUMNS

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: How many students are affected by each allergy type?
Answer: SELECT T2.allergytype ,  count(*) FROM Has_allergy AS T1 JOIN Allergy_type AS T2 ON T1.allergy  =  T2.allergy GROUP BY T2.allergytype
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT T2.allergytype ,  count(*) FROM Has_allergy AS T1 JOIN Allergy_type AS T2 ON T1.allergy  =  T2.allergy GROUP BY T2.allergytype
##Instruction:
Database: allergy_1
Total Tables: 3
Total Columns: 12

Table Schemas:

allergy_1 contains tables such as Allergy_Type, Has_Allergy, Student.
Table Allergy_Type has columns such as Allergy, AllergyType.
Allergy is the primary key.
Table Has_Allergy has columns such as StuID, Allergy.
Table Student has columns such as StuID, LName, Fname, Age, Sex, Major, Advisor, city_code.
StuID is the primary key.
The Allergy of Has_Allergy is the foreign key of Allergy of Allergy_Type.
The StuID of Has_Allergy is the foreign key of StuID of Student.

##Role Access Policy (Column-Level):
Role: HealthServicesCoordinator
Accessible Columns: Student: StuID, LName, Fname, Age, Sex; Has_Allergy: ALL COLUMNS; Allergy_Type: ALL COLUMNS

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: Find the last name and age of the student who has allergy to both milk and cat.
Answer: SELECT lname ,  age FROM Student WHERE StuID IN (SELECT StuID FROM Has_allergy WHERE Allergy  =  "Milk" INTERSECT SELECT StuID FROM Has_allergy WHERE Allergy  =  "Cat")
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT lname ,  age FROM Student WHERE StuID IN (SELECT StuID FROM Has_allergy WHERE Allergy  =  "Milk" INTERSECT SELECT StuID FROM Has_allergy WHERE Allergy  =  "Cat")
##Instruction:
Database: allergy_1
Total Tables: 3
Total Columns: 12

Table Schemas:

allergy_1 contains tables such as Allergy_Type, Has_Allergy, Student.
Table Allergy_Type has columns such as Allergy, AllergyType.
Allergy is the primary key.
Table Has_Allergy has columns such as StuID, Allergy.
Table Student has columns such as StuID, LName, Fname, Age, Sex, Major, Advisor, city_code.
StuID is the primary key.
The Allergy of Has_Allergy is the foreign key of Allergy of Allergy_Type.
The StuID of Has_Allergy is the foreign key of StuID of Student.

##Role Access Policy (Column-Level):
Role: HealthServicesCoordinator
Accessible Columns: Student: StuID, LName, Fname, Age, Sex; Has_Allergy: ALL COLUMNS; Allergy_Type: ALL COLUMNS

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: What are the last names and ages of the students who are allergic to milk and cat?
Answer: SELECT lname ,  age FROM Student WHERE StuID IN (SELECT StuID FROM Has_allergy WHERE Allergy  =  "Milk" INTERSECT SELECT StuID FROM Has_allergy WHERE Allergy  =  "Cat")
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT lname ,  age FROM Student WHERE StuID IN (SELECT StuID FROM Has_allergy WHERE Allergy  =  "Milk" INTERSECT SELECT StuID FROM Has_allergy WHERE Allergy  =  "Cat")
##Instruction:
Database: allergy_1
Total Tables: 3
Total Columns: 12

Table Schemas:

allergy_1 contains tables such as Allergy_Type, Has_Allergy, Student.
Table Allergy_Type has columns such as Allergy, AllergyType.
Allergy is the primary key.
Table Has_Allergy has columns such as StuID, Allergy.
Table Student has columns such as StuID, LName, Fname, Age, Sex, Major, Advisor, city_code.
StuID is the primary key.
The Allergy of Has_Allergy is the foreign key of Allergy of Allergy_Type.
The StuID of Has_Allergy is the foreign key of StuID of Student.

##Role Access Policy (Column-Level):
Role: HealthServicesCoordinator
Accessible Columns: Student: StuID, LName, Fname, Age, Sex; Has_Allergy: ALL COLUMNS; Allergy_Type: ALL COLUMNS

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: What are the allergies and their types that the student with first name Lisa has? And order the result by name of allergies.
Answer: SELECT T1.Allergy ,  T1.AllergyType FROM Allergy_type AS T1 JOIN Has_allergy AS T2 ON T1.Allergy  =  T2.Allergy JOIN Student AS T3 ON T3.StuID  =  T2.StuID WHERE T3.Fname  =  "Lisa" ORDER BY T1.Allergy
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT T1.Allergy ,  T1.AllergyType FROM Allergy_type AS T1 JOIN Has_allergy AS T2 ON T1.Allergy  =  T2.Allergy JOIN Student AS T3 ON T3.StuID  =  T2.StuID WHERE T3.Fname  =  "Lisa" ORDER BY T1.Allergy
##Instruction:
Database: allergy_1
Total Tables: 3
Total Columns: 12

Table Schemas:

allergy_1 contains tables such as Allergy_Type, Has_Allergy, Student.
Table Allergy_Type has columns such as Allergy, AllergyType.
Allergy is the primary key.
Table Has_Allergy has columns such as StuID, Allergy.
Table Student has columns such as StuID, LName, Fname, Age, Sex, Major, Advisor, city_code.
StuID is the primary key.
The Allergy of Has_Allergy is the foreign key of Allergy of Allergy_Type.
The StuID of Has_Allergy is the foreign key of StuID of Student.

##Role Access Policy (Column-Level):
Role: HealthServicesCoordinator
Accessible Columns: Student: StuID, LName, Fname, Age, Sex; Has_Allergy: ALL COLUMNS; Allergy_Type: ALL COLUMNS

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: What are the allergies the girl named Lisa has? And what are the types of them? Order the result by allergy names.
Answer: SELECT T1.Allergy ,  T1.AllergyType FROM Allergy_type AS T1 JOIN Has_allergy AS T2 ON T1.Allergy  =  T2.Allergy JOIN Student AS T3 ON T3.StuID  =  T2.StuID WHERE T3.Fname  =  "Lisa" ORDER BY T1.Allergy
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT T1.Allergy ,  T1.AllergyType FROM Allergy_type AS T1 JOIN Has_allergy AS T2 ON T1.Allergy  =  T2.Allergy JOIN Student AS T3 ON T3.StuID  =  T2.StuID WHERE T3.Fname  =  "Lisa" ORDER BY T1.Allergy
##Instruction:
Database: allergy_1
Total Tables: 3
Total Columns: 12

Table Schemas:

allergy_1 contains tables such as Allergy_Type, Has_Allergy, Student.
Table Allergy_Type has columns such as Allergy, AllergyType.
Allergy is the primary key.
Table Has_Allergy has columns such as StuID, Allergy.
Table Student has columns such as StuID, LName, Fname, Age, Sex, Major, Advisor, city_code.
StuID is the primary key.
The Allergy of Has_Allergy is the foreign key of Allergy of Allergy_Type.
The StuID of Has_Allergy is the foreign key of StuID of Student.

##Role Access Policy (Column-Level):
Role: HealthServicesCoordinator
Accessible Columns: Student: StuID, LName, Fname, Age, Sex; Has_Allergy: ALL COLUMNS; Allergy_Type: ALL COLUMNS

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: Find the first name and gender of the student who has allergy to milk but not cat.
Answer: SELECT fname ,  sex FROM Student WHERE StuID IN (SELECT StuID FROM Has_allergy WHERE Allergy  =  "Milk" EXCEPT SELECT StuID FROM Has_allergy WHERE Allergy  =  "Cat")
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT fname ,  sex FROM Student WHERE StuID IN (SELECT StuID FROM Has_allergy WHERE Allergy  =  "Milk" EXCEPT SELECT StuID FROM Has_allergy WHERE Allergy  =  "Cat")
##Instruction:
Database: allergy_1
Total Tables: 3
Total Columns: 12

Table Schemas:

allergy_1 contains tables such as Allergy_Type, Has_Allergy, Student.
Table Allergy_Type has columns such as Allergy, AllergyType.
Allergy is the primary key.
Table Has_Allergy has columns such as StuID, Allergy.
Table Student has columns such as StuID, LName, Fname, Age, Sex, Major, Advisor, city_code.
StuID is the primary key.
The Allergy of Has_Allergy is the foreign key of Allergy of Allergy_Type.
The StuID of Has_Allergy is the foreign key of StuID of Student.

##Role Access Policy (Column-Level):
Role: HealthServicesCoordinator
Accessible Columns: Student: StuID, LName, Fname, Age, Sex; Has_Allergy: ALL COLUMNS; Allergy_Type: ALL COLUMNS

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: What are the first name and gender of the students who have allergy to milk but can put up with cats?
Answer: SELECT fname ,  sex FROM Student WHERE StuID IN (SELECT StuID FROM Has_allergy WHERE Allergy  =  "Milk" EXCEPT SELECT StuID FROM Has_allergy WHERE Allergy  =  "Cat")
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT fname ,  sex FROM Student WHERE StuID IN (SELECT StuID FROM Has_allergy WHERE Allergy  =  "Milk" EXCEPT SELECT StuID FROM Has_allergy WHERE Allergy  =  "Cat")