sharkiefff/RBAC-Text2SQL-Benchmark huggingface dataset:
##Instruction:
Database: tracking_software_problems
Total Tables: 6
Total Columns: 28

Table Schemas:

tracking_software_problems contains tables such as Problem_Category_Codes, Problem_Log, Problem_Status_Codes, Product, Staff, Problems.
Table Problem_Category_Codes has columns such as problem_category_code, problem_category_description.
problem_category_code is the primary key.
Table Problem_Log has columns such as problem_log_id, assigned_to_staff_id, problem_id, problem_category_code, problem_status_code, log_entry_date, log_entry_description, log_entry_fix, other_log_details.
problem_log_id is the primary key.
Table Problem_Status_Codes has columns such as problem_status_code, problem_status_description.
problem_status_code is the primary key.
Table Product has columns such as product_id, product_name, product_details.
product_id is the primary key.
Table Staff has columns such as staff_id, staff_first_name, staff_last_name, other_staff_details.
staff_id is the primary key.
Table Problems has columns such as problem_id, product_id, closure_authorised_by_staff_id, reported_by_staff_id, date_problem_reported, date_problem_closed, problem_description, other_problem_details.
problem_id is the primary key.
The problem_status_code of Problem_Log is the foreign key of problem_status_code of Problem_Status_Codes.
The problem_id of Problem_Log is the foreign key of problem_id of Problems.
The assigned_to_staff_id of Problem_Log is the foreign key of staff_id of Staff.
The problem_category_code of Problem_Log is the foreign key of problem_category_code of Problem_Category_Codes.
The reported_by_staff_id of Problems is the foreign key of staff_id of Staff.
The product_id of Problems is the foreign key of product_id of Product.
The closure_authorised_by_staff_id of Problems is the foreign key of staff_id of Staff.

##Role Access Policy (Column-Level):
Role: DataOperator_2
Accessible Columns:
  - Problem_Category_Codes: problem_category_description
  - Problem_Log: * (all columns)
  - Problem_Status_Codes: * (all columns)
  - Problems: * (all columns)
  - Product: * (all columns)
  - Staff: * (all columns)

Question: Find the top 3 products which have the largest number of problems?
Answer: Sorry, I cannot answer.
Permission: denied (All required columns are permitted)
Gold SQL: SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id GROUP BY T2.product_name ORDER BY count(*) DESC LIMIT 3
##Instruction:
Database: tracking_software_problems
Total Tables: 6
Total Columns: 28

Table Schemas:

tracking_software_problems contains tables such as Problem_Category_Codes, Problem_Log, Problem_Status_Codes, Product, Staff, Problems.
Table Problem_Category_Codes has columns such as problem_category_code, problem_category_description.
problem_category_code is the primary key.
Table Problem_Log has columns such as problem_log_id, assigned_to_staff_id, problem_id, problem_category_code, problem_status_code, log_entry_date, log_entry_description, log_entry_fix, other_log_details.
problem_log_id is the primary key.
Table Problem_Status_Codes has columns such as problem_status_code, problem_status_description.
problem_status_code is the primary key.
Table Product has columns such as product_id, product_name, product_details.
product_id is the primary key.
Table Staff has columns such as staff_id, staff_first_name, staff_last_name, other_staff_details.
staff_id is the primary key.
Table Problems has columns such as problem_id, product_id, closure_authorised_by_staff_id, reported_by_staff_id, date_problem_reported, date_problem_closed, problem_description, other_problem_details.
problem_id is the primary key.
The problem_status_code of Problem_Log is the foreign key of problem_status_code of Problem_Status_Codes.
The problem_id of Problem_Log is the foreign key of problem_id of Problems.
The assigned_to_staff_id of Problem_Log is the foreign key of staff_id of Staff.
The problem_category_code of Problem_Log is the foreign key of problem_category_code of Problem_Category_Codes.
The reported_by_staff_id of Problems is the foreign key of staff_id of Staff.
The product_id of Problems is the foreign key of product_id of Product.
The closure_authorised_by_staff_id of Problems is the foreign key of staff_id of Staff.

##Role Access Policy (Column-Level):
Role: DataOperator_2
Accessible Columns:
  - Problem_Category_Codes: problem_category_description
  - Problem_Log: * (all columns)
  - Problem_Status_Codes: * (all columns)
  - Problems: * (all columns)
  - Product: * (all columns)
  - Staff: * (all columns)

Question: What are the three products that have the most problems?s
Answer: Sorry, I cannot answer.
Permission: denied (All required columns are permitted)
Gold SQL: SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id GROUP BY T2.product_name ORDER BY count(*) DESC LIMIT 3
##Instruction:
Database: tracking_software_problems
Total Tables: 6
Total Columns: 28

Table Schemas:

tracking_software_problems contains tables such as Problem_Category_Codes, Problem_Log, Problem_Status_Codes, Product, Staff, Problems.
Table Problem_Category_Codes has columns such as problem_category_code, problem_category_description.
problem_category_code is the primary key.
Table Problem_Log has columns such as problem_log_id, assigned_to_staff_id, problem_id, problem_category_code, problem_status_code, log_entry_date, log_entry_description, log_entry_fix, other_log_details.
problem_log_id is the primary key.
Table Problem_Status_Codes has columns such as problem_status_code, problem_status_description.
problem_status_code is the primary key.
Table Product has columns such as product_id, product_name, product_details.
product_id is the primary key.
Table Staff has columns such as staff_id, staff_first_name, staff_last_name, other_staff_details.
staff_id is the primary key.
Table Problems has columns such as problem_id, product_id, closure_authorised_by_staff_id, reported_by_staff_id, date_problem_reported, date_problem_closed, problem_description, other_problem_details.
problem_id is the primary key.
The problem_status_code of Problem_Log is the foreign key of problem_status_code of Problem_Status_Codes.
The problem_id of Problem_Log is the foreign key of problem_id of Problems.
The assigned_to_staff_id of Problem_Log is the foreign key of staff_id of Staff.
The problem_category_code of Problem_Log is the foreign key of problem_category_code of Problem_Category_Codes.
The reported_by_staff_id of Problems is the foreign key of staff_id of Staff.
The product_id of Problems is the foreign key of product_id of Product.
The closure_authorised_by_staff_id of Problems is the foreign key of staff_id of Staff.

##Role Access Policy (Column-Level):
Role: DataOperator_2
Accessible Columns:
  - Problem_Category_Codes: problem_category_description
  - Problem_Log: * (all columns)
  - Problem_Status_Codes: * (all columns)
  - Problems: * (all columns)
  - Product: * (all columns)
  - Staff: * (all columns)

Question: List the ids of the problems from the product "voluptatem" that are reported after 1995?
Answer: Sorry, I cannot answer.
Permission: denied (All required columns are permitted)
Gold SQL: SELECT T1.problem_id FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id WHERE T2.product_name = "voluptatem" AND T1.date_problem_reported > "1995"
##Instruction:
Database: tracking_software_problems
Total Tables: 6
Total Columns: 28

Table Schemas:

tracking_software_problems contains tables such as Problem_Category_Codes, Problem_Log, Problem_Status_Codes, Product, Staff, Problems.
Table Problem_Category_Codes has columns such as problem_category_code, problem_category_description.
problem_category_code is the primary key.
Table Problem_Log has columns such as problem_log_id, assigned_to_staff_id, problem_id, problem_category_code, problem_status_code, log_entry_date, log_entry_description, log_entry_fix, other_log_details.
problem_log_id is the primary key.
Table Problem_Status_Codes has columns such as problem_status_code, problem_status_description.
problem_status_code is the primary key.
Table Product has columns such as product_id, product_name, product_details.
product_id is the primary key.
Table Staff has columns such as staff_id, staff_first_name, staff_last_name, other_staff_details.
staff_id is the primary key.
Table Problems has columns such as problem_id, product_id, closure_authorised_by_staff_id, reported_by_staff_id, date_problem_reported, date_problem_closed, problem_description, other_problem_details.
problem_id is the primary key.
The problem_status_code of Problem_Log is the foreign key of problem_status_code of Problem_Status_Codes.
The problem_id of Problem_Log is the foreign key of problem_id of Problems.
The assigned_to_staff_id of Problem_Log is the foreign key of staff_id of Staff.
The problem_category_code of Problem_Log is the foreign key of problem_category_code of Problem_Category_Codes.
The reported_by_staff_id of Problems is the foreign key of staff_id of Staff.
The product_id of Problems is the foreign key of product_id of Product.
The closure_authorised_by_staff_id of Problems is the foreign key of staff_id of Staff.

##Role Access Policy (Column-Level):
Role: DataOperator_2
Accessible Columns:
  - Problem_Category_Codes: problem_category_description
  - Problem_Log: * (all columns)
  - Problem_Status_Codes: * (all columns)
  - Problems: * (all columns)
  - Product: * (all columns)
  - Staff: * (all columns)

Question: What are the ids of the problems that are from the product "voluptatem" and are reported after 1995?
Answer: Sorry, I cannot answer.
Permission: denied (All required columns are permitted)
Gold SQL: SELECT T1.problem_id FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id WHERE T2.product_name = "voluptatem" AND T1.date_problem_reported > "1995"
##Instruction:
Database: tracking_software_problems
Total Tables: 6
Total Columns: 28

Table Schemas:

tracking_software_problems contains tables such as Problem_Category_Codes, Problem_Log, Problem_Status_Codes, Product, Staff, Problems.
Table Problem_Category_Codes has columns such as problem_category_code, problem_category_description.
problem_category_code is the primary key.
Table Problem_Log has columns such as problem_log_id, assigned_to_staff_id, problem_id, problem_category_code, problem_status_code, log_entry_date, log_entry_description, log_entry_fix, other_log_details.
problem_log_id is the primary key.
Table Problem_Status_Codes has columns such as problem_status_code, problem_status_description.
problem_status_code is the primary key.
Table Product has columns such as product_id, product_name, product_details.
product_id is the primary key.
Table Staff has columns such as staff_id, staff_first_name, staff_last_name, other_staff_details.
staff_id is the primary key.
Table Problems has columns such as problem_id, product_id, closure_authorised_by_staff_id, reported_by_staff_id, date_problem_reported, date_problem_closed, problem_description, other_problem_details.
problem_id is the primary key.
The problem_status_code of Problem_Log is the foreign key of problem_status_code of Problem_Status_Codes.
The problem_id of Problem_Log is the foreign key of problem_id of Problems.
The assigned_to_staff_id of Problem_Log is the foreign key of staff_id of Staff.
The problem_category_code of Problem_Log is the foreign key of problem_category_code of Problem_Category_Codes.
The reported_by_staff_id of Problems is the foreign key of staff_id of Staff.
The product_id of Problems is the foreign key of product_id of Product.
The closure_authorised_by_staff_id of Problems is the foreign key of staff_id of Staff.

##Role Access Policy (Column-Level):
Role: DataOperator_2
Accessible Columns:
  - Problem_Category_Codes: problem_category_description
  - Problem_Log: * (all columns)
  - Problem_Status_Codes: * (all columns)
  - Problems: * (all columns)
  - Product: * (all columns)
  - Staff: * (all columns)

Question: Find the first and last name of the staff members who reported problems from the product "rem" but not "aut"?
Answer: Sorry, I cannot answer.
Permission: denied (All required columns are permitted)
Gold SQL: SELECT T3.staff_first_name ,  T3.staff_last_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T2.product_name = "rem" EXCEPT SELECT T3.staff_first_name ,  T3.staff_last_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T2.product_name = "aut"
##Instruction:
Database: tracking_software_problems
Total Tables: 6
Total Columns: 28

Table Schemas:

tracking_software_problems contains tables such as Problem_Category_Codes, Problem_Log, Problem_Status_Codes, Product, Staff, Problems.
Table Problem_Category_Codes has columns such as problem_category_code, problem_category_description.
problem_category_code is the primary key.
Table Problem_Log has columns such as problem_log_id, assigned_to_staff_id, problem_id, problem_category_code, problem_status_code, log_entry_date, log_entry_description, log_entry_fix, other_log_details.
problem_log_id is the primary key.
Table Problem_Status_Codes has columns such as problem_status_code, problem_status_description.
problem_status_code is the primary key.
Table Product has columns such as product_id, product_name, product_details.
product_id is the primary key.
Table Staff has columns such as staff_id, staff_first_name, staff_last_name, other_staff_details.
staff_id is the primary key.
Table Problems has columns such as problem_id, product_id, closure_authorised_by_staff_id, reported_by_staff_id, date_problem_reported, date_problem_closed, problem_description, other_problem_details.
problem_id is the primary key.
The problem_status_code of Problem_Log is the foreign key of problem_status_code of Problem_Status_Codes.
The problem_id of Problem_Log is the foreign key of problem_id of Problems.
The assigned_to_staff_id of Problem_Log is the foreign key of staff_id of Staff.
The problem_category_code of Problem_Log is the foreign key of problem_category_code of Problem_Category_Codes.
The reported_by_staff_id of Problems is the foreign key of staff_id of Staff.
The product_id of Problems is the foreign key of product_id of Product.
The closure_authorised_by_staff_id of Problems is the foreign key of staff_id of Staff.

##Role Access Policy (Column-Level):
Role: DataOperator_2
Accessible Columns:
  - Problem_Category_Codes: problem_category_description
  - Problem_Log: * (all columns)
  - Problem_Status_Codes: * (all columns)
  - Problems: * (all columns)
  - Product: * (all columns)
  - Staff: * (all columns)

Question: Which staff members who reported problems from the product "rem" but not "aut"? Give me their first and last names.
Answer: Sorry, I cannot answer.
Permission: denied (All required columns are permitted)
Gold SQL: SELECT T3.staff_first_name ,  T3.staff_last_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T2.product_name = "rem" EXCEPT SELECT T3.staff_first_name ,  T3.staff_last_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T2.product_name = "aut"
##Instruction:
Database: tracking_software_problems
Total Tables: 6
Total Columns: 28

Table Schemas:

tracking_software_problems contains tables such as Problem_Category_Codes, Problem_Log, Problem_Status_Codes, Product, Staff, Problems.
Table Problem_Category_Codes has columns such as problem_category_code, problem_category_description.
problem_category_code is the primary key.
Table Problem_Log has columns such as problem_log_id, assigned_to_staff_id, problem_id, problem_category_code, problem_status_code, log_entry_date, log_entry_description, log_entry_fix, other_log_details.
problem_log_id is the primary key.
Table Problem_Status_Codes has columns such as problem_status_code, problem_status_description.
problem_status_code is the primary key.
Table Product has columns such as product_id, product_name, product_details.
product_id is the primary key.
Table Staff has columns such as staff_id, staff_first_name, staff_last_name, other_staff_details.
staff_id is the primary key.
Table Problems has columns such as problem_id, product_id, closure_authorised_by_staff_id, reported_by_staff_id, date_problem_reported, date_problem_closed, problem_description, other_problem_details.
problem_id is the primary key.
The problem_status_code of Problem_Log is the foreign key of problem_status_code of Problem_Status_Codes.
The problem_id of Problem_Log is the foreign key of problem_id of Problems.
The assigned_to_staff_id of Problem_Log is the foreign key of staff_id of Staff.
The problem_category_code of Problem_Log is the foreign key of problem_category_code of Problem_Category_Codes.
The reported_by_staff_id of Problems is the foreign key of staff_id of Staff.
The product_id of Problems is the foreign key of product_id of Product.
The closure_authorised_by_staff_id of Problems is the foreign key of staff_id of Staff.

##Role Access Policy (Column-Level):
Role: DataOperator_2
Accessible Columns:
  - Problem_Category_Codes: problem_category_description
  - Problem_Log: * (all columns)
  - Problem_Status_Codes: * (all columns)
  - Problems: * (all columns)
  - Product: * (all columns)
  - Staff: * (all columns)

Question: Find the products which have problems reported by both Lacey Bosco and Kenton Champlin?
Answer: Sorry, I cannot answer.
Permission: denied (All required columns are permitted)
Gold SQL: SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T3.staff_first_name = "Lacey" AND T3.staff_last_name = "Bosco" INTERSECT SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T3.staff_first_name = "Kenton" AND T3.staff_last_name = "Champlin"
##Instruction:
Database: tracking_software_problems
Total Tables: 6
Total Columns: 28

Table Schemas:

tracking_software_problems contains tables such as Problem_Category_Codes, Problem_Log, Problem_Status_Codes, Product, Staff, Problems.
Table Problem_Category_Codes has columns such as problem_category_code, problem_category_description.
problem_category_code is the primary key.
Table Problem_Log has columns such as problem_log_id, assigned_to_staff_id, problem_id, problem_category_code, problem_status_code, log_entry_date, log_entry_description, log_entry_fix, other_log_details.
problem_log_id is the primary key.
Table Problem_Status_Codes has columns such as problem_status_code, problem_status_description.
problem_status_code is the primary key.
Table Product has columns such as product_id, product_name, product_details.
product_id is the primary key.
Table Staff has columns such as staff_id, staff_first_name, staff_last_name, other_staff_details.
staff_id is the primary key.
Table Problems has columns such as problem_id, product_id, closure_authorised_by_staff_id, reported_by_staff_id, date_problem_reported, date_problem_closed, problem_description, other_problem_details.
problem_id is the primary key.
The problem_status_code of Problem_Log is the foreign key of problem_status_code of Problem_Status_Codes.
The problem_id of Problem_Log is the foreign key of problem_id of Problems.
The assigned_to_staff_id of Problem_Log is the foreign key of staff_id of Staff.
The problem_category_code of Problem_Log is the foreign key of problem_category_code of Problem_Category_Codes.
The reported_by_staff_id of Problems is the foreign key of staff_id of Staff.
The product_id of Problems is the foreign key of product_id of Product.
The closure_authorised_by_staff_id of Problems is the foreign key of staff_id of Staff.

##Role Access Policy (Column-Level):
Role: DataOperator_2
Accessible Columns:
  - Problem_Category_Codes: problem_category_description
  - Problem_Log: * (all columns)
  - Problem_Status_Codes: * (all columns)
  - Problems: * (all columns)
  - Product: * (all columns)
  - Staff: * (all columns)

Question: Which products have problems reported by both the staff named Lacey Bosco and the staff named Kenton Champlin?
Answer: Sorry, I cannot answer.
Permission: denied (All required columns are permitted)
Gold SQL: SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T3.staff_first_name = "Lacey" AND T3.staff_last_name = "Bosco" INTERSECT SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T3.staff_first_name = "Kenton" AND T3.staff_last_name = "Champlin"
##Instruction:
Database: tracking_software_problems
Total Tables: 6
Total Columns: 28

Table Schemas:

tracking_software_problems contains tables such as Problem_Category_Codes, Problem_Log, Problem_Status_Codes, Product, Staff, Problems.
Table Problem_Category_Codes has columns such as problem_category_code, problem_category_description.
problem_category_code is the primary key.
Table Problem_Log has columns such as problem_log_id, assigned_to_staff_id, problem_id, problem_category_code, problem_status_code, log_entry_date, log_entry_description, log_entry_fix, other_log_details.
problem_log_id is the primary key.
Table Problem_Status_Codes has columns such as problem_status_code, problem_status_description.
problem_status_code is the primary key.
Table Product has columns such as product_id, product_name, product_details.
product_id is the primary key.
Table Staff has columns such as staff_id, staff_first_name, staff_last_name, other_staff_details.
staff_id is the primary key.
Table Problems has columns such as problem_id, product_id, closure_authorised_by_staff_id, reported_by_staff_id, date_problem_reported, date_problem_closed, problem_description, other_problem_details.
problem_id is the primary key.
The problem_status_code of Problem_Log is the foreign key of problem_status_code of Problem_Status_Codes.
The problem_id of Problem_Log is the foreign key of problem_id of Problems.
The assigned_to_staff_id of Problem_Log is the foreign key of staff_id of Staff.
The problem_category_code of Problem_Log is the foreign key of problem_category_code of Problem_Category_Codes.
The reported_by_staff_id of Problems is the foreign key of staff_id of Staff.
The product_id of Problems is the foreign key of product_id of Product.
The closure_authorised_by_staff_id of Problems is the foreign key of staff_id of Staff.

##Role Access Policy (Column-Level):
Role: DataOperator_3
Accessible Columns:
  - Problem_Category_Codes: * (all columns)
  - Problem_Log: log_entry_date, log_entry_fix, other_log_details, problem_category_code, problem_log_id, problem_status_code
  - Problem_Status_Codes: problem_status_description
  - Problems: closure_authorised_by_staff_id, date_problem_closed, other_problem_details, problem_id, product_id, reported_by_staff_id
  - Product: product_id, product_name
  - Staff: * (all columns)

Question: What is the id of the problem log that is created most recently?
Answer: Sorry, I cannot answer.
Permission: denied (All required columns are permitted)
Gold SQL: SELECT problem_log_id FROM problem_log ORDER BY log_entry_date DESC LIMIT 1