##Instruction:
Database: department_store
Total Tables: 14
Total Columns: 56

Table Schemas:

department_store contains tables such as Addresses, Staff, Suppliers, Department_Store_Chain, Customers, Products, Supplier_Addresses, Customer_Addresses, Customer_Orders, Department_Stores, Departments, Order_Items, Product_Suppliers, Staff_Department_Assignments.
Table Addresses has columns such as address_id, address_details.
address_id is the primary key.
Table Staff has columns such as staff_id, staff_gender, staff_name.
staff_id is the primary key.
Table Suppliers has columns such as supplier_id, supplier_name, supplier_phone.
supplier_id is the primary key.
Table Department_Store_Chain has columns such as dept_store_chain_id, dept_store_chain_name.
dept_store_chain_id is the primary key.
Table Customers has columns such as customer_id, payment_method_code, customer_code, customer_name, customer_address, customer_phone, customer_email.
customer_id is the primary key.
Table Products has columns such as product_id, product_type_code, product_name, product_price.
product_id is the primary key.
Table Supplier_Addresses has columns such as supplier_id, address_id, date_from, date_to.
supplier_id is the primary key.
Table Customer_Addresses has columns such as customer_id, address_id, date_from, date_to.
customer_id is the primary key.
Table Customer_Orders has columns such as order_id, customer_id, order_status_code, order_date.
order_id is the primary key.
Table Department_Stores has columns such as dept_store_id, dept_store_chain_id, store_name, store_address, store_phone, store_email.
dept_store_id is the primary key.
Table Departments has columns such as department_id, dept_store_id, department_name.
department_id is the primary key.
Table Order_Items has columns such as order_item_id, order_id, product_id.
order_item_id is the primary key.
Table Product_Suppliers has columns such as product_id, supplier_id, date_supplied_from, date_supplied_to, total_amount_purchased, total_value_purchased.
product_id is the primary key.
Table Staff_Department_Assignments has columns such as staff_id, department_id, date_assigned_from, job_title_code, date_assigned_to.
staff_id is the primary key.
The supplier_id of Supplier_Addresses is the foreign key of supplier_id of Suppliers.
The address_id of Supplier_Addresses is the foreign key of address_id of Addresses.
The customer_id of Customer_Addresses is the foreign key of customer_id of Customers.
The address_id of Customer_Addresses is the foreign key of address_id of Addresses.
The customer_id of Customer_Orders is the foreign key of customer_id of Customers.
The dept_store_chain_id of Department_Stores is the foreign key of dept_store_chain_id of Department_Store_Chain.
The dept_store_id of Departments is the foreign key of dept_store_id of Department_Stores.
The product_id of Order_Items is the foreign key of product_id of Products.
The order_id of Order_Items is the foreign key of order_id of Customer_Orders.
The product_id of Product_Suppliers is the foreign key of product_id of Products.
The supplier_id of Product_Suppliers is the foreign key of supplier_id of Suppliers.
The staff_id of Staff_Department_Assignments is the foreign key of staff_id of Staff.
The department_id of Staff_Department_Assignments is the foreign key of department_id of Departments.

##Role Access Policy (Column-Level):
Role: HRCoordinator
Accessible Columns: Staff: staff_id, staff_gender, staff_name; Staff_Department_Assignments: staff_id, department_id, date_assigned_from, job_title_code, date_assigned_to; Departments: department_id, department_name

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: List the name of staff who has been assigned multiple jobs.
Answer: SELECT T1.staff_name FROM staff AS T1 JOIN staff_department_assignments AS T2 ON T1.staff_id  =  T2.staff_id GROUP BY T2.staff_id HAVING COUNT (*)  >  1
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT T1.staff_name FROM staff AS T1 JOIN staff_department_assignments AS T2 ON T1.staff_id  =  T2.staff_id GROUP BY T2.staff_id HAVING COUNT (*)  >  1