sharkiefff/RBAC-Text2SQL-Benchmark huggingface dataset:
##Instruction:
Database: train_station
Total Tables: 3
Total Columns: 14

Table Schemas:

train_station contains tables such as station, train, train_station.
Table station has columns such as Station_ID, Name, Annual_entry_exit, Annual_interchanges, Total_Passengers, Location, Main_Services, Number_of_Platforms.
Station_ID is the primary key.
Table train has columns such as Train_ID, Name, Time, Service.
Train_ID is the primary key.
Table train_station has columns such as Train_ID, Station_ID.
Train_ID is the primary key.
The Station_ID of train_station is the foreign key of Station_ID of station.
The Train_ID of train_station is the foreign key of Train_ID of train.

##Role Access Policy (Column-Level):
Role: StationManager
Accessible Columns: station: Station_ID, Name, Annual_entry_exit, Annual_interchanges, Total_Passengers, Location, Number_of_Platforms; train_station: Station_ID, Train_ID; train: Train_ID, Name, Time, Service

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: Show all locations which don't have a train station with at least 15 platforms.
Answer: SELECT LOCATION FROM station EXCEPT SELECT LOCATION FROM station WHERE number_of_platforms  >=  15
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT LOCATION FROM station EXCEPT SELECT LOCATION FROM station WHERE number_of_platforms  >=  15
##Instruction:
Database: train_station
Total Tables: 3
Total Columns: 14

Table Schemas:

train_station contains tables such as station, train, train_station.
Table station has columns such as Station_ID, Name, Annual_entry_exit, Annual_interchanges, Total_Passengers, Location, Main_Services, Number_of_Platforms.
Station_ID is the primary key.
Table train has columns such as Train_ID, Name, Time, Service.
Train_ID is the primary key.
Table train_station has columns such as Train_ID, Station_ID.
Train_ID is the primary key.
The Station_ID of train_station is the foreign key of Station_ID of station.
The Train_ID of train_station is the foreign key of Train_ID of train.

##Role Access Policy (Column-Level):
Role: StationManager
Accessible Columns: station: Station_ID, Name, Annual_entry_exit, Annual_interchanges, Total_Passengers, Location, Number_of_Platforms; train_station: Station_ID, Train_ID; train: Train_ID, Name, Time, Service

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: Show the location with most number of train stations.
Answer: SELECT LOCATION FROM station GROUP BY LOCATION ORDER BY count(*) DESC LIMIT 1
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT LOCATION FROM station GROUP BY LOCATION ORDER BY count(*) DESC LIMIT 1
##Instruction:
Database: train_station
Total Tables: 3
Total Columns: 14

Table Schemas:

train_station contains tables such as station, train, train_station.
Table station has columns such as Station_ID, Name, Annual_entry_exit, Annual_interchanges, Total_Passengers, Location, Main_Services, Number_of_Platforms.
Station_ID is the primary key.
Table train has columns such as Train_ID, Name, Time, Service.
Train_ID is the primary key.
Table train_station has columns such as Train_ID, Station_ID.
Train_ID is the primary key.
The Station_ID of train_station is the foreign key of Station_ID of station.
The Train_ID of train_station is the foreign key of Train_ID of train.

##Role Access Policy (Column-Level):
Role: StationManager
Accessible Columns: station: Station_ID, Name, Annual_entry_exit, Annual_interchanges, Total_Passengers, Location, Number_of_Platforms; train_station: Station_ID, Train_ID; train: Train_ID, Name, Time, Service

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: Show the name, time, and service for all trains.
Answer: SELECT name ,  TIME ,  service FROM train
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT name ,  TIME ,  service FROM train
##Instruction:
Database: train_station
Total Tables: 3
Total Columns: 14

Table Schemas:

train_station contains tables such as station, train, train_station.
Table station has columns such as Station_ID, Name, Annual_entry_exit, Annual_interchanges, Total_Passengers, Location, Main_Services, Number_of_Platforms.
Station_ID is the primary key.
Table train has columns such as Train_ID, Name, Time, Service.
Train_ID is the primary key.
Table train_station has columns such as Train_ID, Station_ID.
Train_ID is the primary key.
The Station_ID of train_station is the foreign key of Station_ID of station.
The Train_ID of train_station is the foreign key of Train_ID of train.

##Role Access Policy (Column-Level):
Role: StationManager
Accessible Columns: station: Station_ID, Name, Annual_entry_exit, Annual_interchanges, Total_Passengers, Location, Number_of_Platforms; train_station: Station_ID, Train_ID; train: Train_ID, Name, Time, Service

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: Show the number of trains
Answer: SELECT count(*) FROM train
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT count(*) FROM train
##Instruction:
Database: train_station
Total Tables: 3
Total Columns: 14

Table Schemas:

train_station contains tables such as station, train, train_station.
Table station has columns such as Station_ID, Name, Annual_entry_exit, Annual_interchanges, Total_Passengers, Location, Main_Services, Number_of_Platforms.
Station_ID is the primary key.
Table train has columns such as Train_ID, Name, Time, Service.
Train_ID is the primary key.
Table train_station has columns such as Train_ID, Station_ID.
Train_ID is the primary key.
The Station_ID of train_station is the foreign key of Station_ID of station.
The Train_ID of train_station is the foreign key of Train_ID of train.

##Role Access Policy (Column-Level):
Role: StationManager
Accessible Columns: station: Station_ID, Name, Annual_entry_exit, Annual_interchanges, Total_Passengers, Location, Number_of_Platforms; train_station: Station_ID, Train_ID; train: Train_ID, Name, Time, Service

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: Show the name and service for all trains in order by time.
Answer: SELECT name ,  service FROM train ORDER BY TIME
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT name ,  service FROM train ORDER BY TIME
##Instruction:
Database: train_station
Total Tables: 3
Total Columns: 14

Table Schemas:

train_station contains tables such as station, train, train_station.
Table station has columns such as Station_ID, Name, Annual_entry_exit, Annual_interchanges, Total_Passengers, Location, Main_Services, Number_of_Platforms.
Station_ID is the primary key.
Table train has columns such as Train_ID, Name, Time, Service.
Train_ID is the primary key.
Table train_station has columns such as Train_ID, Station_ID.
Train_ID is the primary key.
The Station_ID of train_station is the foreign key of Station_ID of station.
The Train_ID of train_station is the foreign key of Train_ID of train.

##Role Access Policy (Column-Level):
Role: StationManager
Accessible Columns: station: Station_ID, Name, Annual_entry_exit, Annual_interchanges, Total_Passengers, Location, Number_of_Platforms; train_station: Station_ID, Train_ID; train: Train_ID, Name, Time, Service

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: Show the station name and number of trains in each station.
Answer: SELECT T2.name ,  count(*) FROM train_station AS T1 JOIN station AS T2 ON T1.station_id  =  T2.station_id GROUP BY T1.station_id
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT T2.name ,  count(*) FROM train_station AS T1 JOIN station AS T2 ON T1.station_id  =  T2.station_id GROUP BY T1.station_id
##Instruction:
Database: train_station
Total Tables: 3
Total Columns: 14

Table Schemas:

train_station contains tables such as station, train, train_station.
Table station has columns such as Station_ID, Name, Annual_entry_exit, Annual_interchanges, Total_Passengers, Location, Main_Services, Number_of_Platforms.
Station_ID is the primary key.
Table train has columns such as Train_ID, Name, Time, Service.
Train_ID is the primary key.
Table train_station has columns such as Train_ID, Station_ID.
Train_ID is the primary key.
The Station_ID of train_station is the foreign key of Station_ID of station.
The Train_ID of train_station is the foreign key of Train_ID of train.

##Role Access Policy (Column-Level):
Role: StationManager
Accessible Columns: station: Station_ID, Name, Annual_entry_exit, Annual_interchanges, Total_Passengers, Location, Number_of_Platforms; train_station: Station_ID, Train_ID; train: Train_ID, Name, Time, Service

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: show the train name and station name for each train.
Answer: SELECT T2.name ,  T3.name FROM train_station AS T1 JOIN station AS T2 ON T1.station_id  =  T2.station_id JOIN train AS T3 ON T3.train_id  =  T1.train_id
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT T2.name ,  T3.name FROM train_station AS T1 JOIN station AS T2 ON T1.station_id  =  T2.station_id JOIN train AS T3 ON T3.train_id  =  T1.train_id
##Instruction:
Database: train_station
Total Tables: 3
Total Columns: 14

Table Schemas:

train_station contains tables such as station, train, train_station.
Table station has columns such as Station_ID, Name, Annual_entry_exit, Annual_interchanges, Total_Passengers, Location, Main_Services, Number_of_Platforms.
Station_ID is the primary key.
Table train has columns such as Train_ID, Name, Time, Service.
Train_ID is the primary key.
Table train_station has columns such as Train_ID, Station_ID.
Train_ID is the primary key.
The Station_ID of train_station is the foreign key of Station_ID of station.
The Train_ID of train_station is the foreign key of Train_ID of train.

##Role Access Policy (Column-Level):
Role: StationManager
Accessible Columns: station: Station_ID, Name, Annual_entry_exit, Annual_interchanges, Total_Passengers, Location, Number_of_Platforms; train_station: Station_ID, Train_ID; train: Train_ID, Name, Time, Service

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: Show all train names and times in stations in London in descending order by train time.
Answer: SELECT T3.name ,  T3.time FROM train_station AS T1 JOIN station AS T2 ON T1.station_id  =  T2.station_id JOIN train AS T3 ON T3.train_id  =  T1.train_id WHERE T2.location  =  'London' ORDER BY T3.time DESC
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT T3.name ,  T3.time FROM train_station AS T1 JOIN station AS T2 ON T1.station_id  =  T2.station_id JOIN train AS T3 ON T3.train_id  =  T1.train_id WHERE T2.location  =  'London' ORDER BY T3.time DESC
##Instruction:
Database: train_station
Total Tables: 3
Total Columns: 14

Table Schemas:

train_station contains tables such as station, train, train_station.
Table station has columns such as Station_ID, Name, Annual_entry_exit, Annual_interchanges, Total_Passengers, Location, Main_Services, Number_of_Platforms.
Station_ID is the primary key.
Table train has columns such as Train_ID, Name, Time, Service.
Train_ID is the primary key.
Table train_station has columns such as Train_ID, Station_ID.
Train_ID is the primary key.
The Station_ID of train_station is the foreign key of Station_ID of station.
The Train_ID of train_station is the foreign key of Train_ID of train.

##Role Access Policy (Column-Level):
Role: StationManager
Accessible Columns: station: Station_ID, Name, Annual_entry_exit, Annual_interchanges, Total_Passengers, Location, Number_of_Platforms; train_station: Station_ID, Train_ID; train: Train_ID, Name, Time, Service

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: Show the station name with greatest number of trains.
Answer: SELECT T2.name FROM train_station AS T1 JOIN station AS T2 ON T1.station_id  =  T2.station_id GROUP BY T1.station_id ORDER BY count(*) DESC LIMIT 1
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT T2.name FROM train_station AS T1 JOIN station AS T2 ON T1.station_id  =  T2.station_id GROUP BY T1.station_id ORDER BY count(*) DESC LIMIT 1
##Instruction:
Database: train_station
Total Tables: 3
Total Columns: 14

Table Schemas:

train_station contains tables such as station, train, train_station.
Table station has columns such as Station_ID, Name, Annual_entry_exit, Annual_interchanges, Total_Passengers, Location, Main_Services, Number_of_Platforms.
Station_ID is the primary key.
Table train has columns such as Train_ID, Name, Time, Service.
Train_ID is the primary key.
Table train_station has columns such as Train_ID, Station_ID.
Train_ID is the primary key.
The Station_ID of train_station is the foreign key of Station_ID of station.
The Train_ID of train_station is the foreign key of Train_ID of train.

##Role Access Policy (Column-Level):
Role: StationManager
Accessible Columns: station: Station_ID, Name, Annual_entry_exit, Annual_interchanges, Total_Passengers, Location, Number_of_Platforms; train_station: Station_ID, Train_ID; train: Train_ID, Name, Time, Service

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: Show the station name with at least two trains.
Answer: SELECT T2.name FROM train_station AS T1 JOIN station AS T2 ON T1.station_id  =  T2.station_id GROUP BY T1.station_id HAVING count(*)  >=  2
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT T2.name FROM train_station AS T1 JOIN station AS T2 ON T1.station_id  =  T2.station_id GROUP BY T1.station_id HAVING count(*)  >=  2
##Instruction:
Database: train_station
Total Tables: 3
Total Columns: 14

Table Schemas:

train_station contains tables such as station, train, train_station.
Table station has columns such as Station_ID, Name, Annual_entry_exit, Annual_interchanges, Total_Passengers, Location, Main_Services, Number_of_Platforms.
Station_ID is the primary key.
Table train has columns such as Train_ID, Name, Time, Service.
Train_ID is the primary key.
Table train_station has columns such as Train_ID, Station_ID.
Train_ID is the primary key.
The Station_ID of train_station is the foreign key of Station_ID of station.
The Train_ID of train_station is the foreign key of Train_ID of train.

##Role Access Policy (Column-Level):
Role: StationManager
Accessible Columns: station: Station_ID, Name, Annual_entry_exit, Annual_interchanges, Total_Passengers, Location, Number_of_Platforms; train_station: Station_ID, Train_ID; train: Train_ID, Name, Time, Service

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: Show all locations with only 1 station.
Answer: SELECT LOCATION FROM station GROUP BY LOCATION HAVING count(*)  =  1
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT LOCATION FROM station GROUP BY LOCATION HAVING count(*)  =  1
##Instruction:
Database: train_station
Total Tables: 3
Total Columns: 14

Table Schemas:

train_station contains tables such as station, train, train_station.
Table station has columns such as Station_ID, Name, Annual_entry_exit, Annual_interchanges, Total_Passengers, Location, Main_Services, Number_of_Platforms.
Station_ID is the primary key.
Table train has columns such as Train_ID, Name, Time, Service.
Train_ID is the primary key.
Table train_station has columns such as Train_ID, Station_ID.
Train_ID is the primary key.
The Station_ID of train_station is the foreign key of Station_ID of station.
The Train_ID of train_station is the foreign key of Train_ID of train.

##Role Access Policy (Column-Level):
Role: StationManager
Accessible Columns: station: Station_ID, Name, Annual_entry_exit, Annual_interchanges, Total_Passengers, Location, Number_of_Platforms; train_station: Station_ID, Train_ID; train: Train_ID, Name, Time, Service

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: Show station names without any trains.
Answer: SELECT name FROM station WHERE station_id NOT IN (SELECT station_id FROM train_station)
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT name FROM station WHERE station_id NOT IN (SELECT station_id FROM train_station)
##Instruction:
Database: train_station
Total Tables: 3
Total Columns: 14

Table Schemas:

train_station contains tables such as station, train, train_station.
Table station has columns such as Station_ID, Name, Annual_entry_exit, Annual_interchanges, Total_Passengers, Location, Main_Services, Number_of_Platforms.
Station_ID is the primary key.
Table train has columns such as Train_ID, Name, Time, Service.
Train_ID is the primary key.
Table train_station has columns such as Train_ID, Station_ID.
Train_ID is the primary key.
The Station_ID of train_station is the foreign key of Station_ID of station.
The Train_ID of train_station is the foreign key of Train_ID of train.

##Role Access Policy (Column-Level):
Role: StationManager
Accessible Columns: station: Station_ID, Name, Annual_entry_exit, Annual_interchanges, Total_Passengers, Location, Number_of_Platforms; train_station: Station_ID, Train_ID; train: Train_ID, Name, Time, Service

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: What are the names of the stations which serve both "Ananthapuri Express" and "Guruvayur Express" trains?
Answer: SELECT T2.name FROM train_station AS T1 JOIN station AS T2 ON T1.station_id  =  T2.station_id JOIN train AS T3 ON T3.train_id  =  T1.train_id WHERE T3.Name  =  "Ananthapuri Express" INTERSECT SELECT T2.name FROM train_station AS T1 JOIN station AS T2 ON T1.station_id  =  T2.station_id JOIN train AS T3 ON T3.train_id  =  T1.train_id WHERE T3.Name  =  "Guruvayur Express"
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT T2.name FROM train_station AS T1 JOIN station AS T2 ON T1.station_id  =  T2.station_id JOIN train AS T3 ON T3.train_id  =  T1.train_id WHERE T3.Name  =  "Ananthapuri Express" INTERSECT SELECT T2.name FROM train_station AS T1 JOIN station AS T2 ON T1.station_id  =  T2.station_id JOIN train AS T3 ON T3.train_id  =  T1.train_id WHERE T3.Name  =  "Guruvayur Express"
##Instruction:
Database: train_station
Total Tables: 3
Total Columns: 14

Table Schemas:

train_station contains tables such as station, train, train_station.
Table station has columns such as Station_ID, Name, Annual_entry_exit, Annual_interchanges, Total_Passengers, Location, Main_Services, Number_of_Platforms.
Station_ID is the primary key.
Table train has columns such as Train_ID, Name, Time, Service.
Train_ID is the primary key.
Table train_station has columns such as Train_ID, Station_ID.
Train_ID is the primary key.
The Station_ID of train_station is the foreign key of Station_ID of station.
The Train_ID of train_station is the foreign key of Train_ID of train.

##Role Access Policy (Column-Level):
Role: StationManager
Accessible Columns: station: Station_ID, Name, Annual_entry_exit, Annual_interchanges, Total_Passengers, Location, Number_of_Platforms; train_station: Station_ID, Train_ID; train: Train_ID, Name, Time, Service

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: Find the names of the trains that do not pass any station located in London.
Answer: SELECT T2.name FROM train_station AS T1 JOIN train AS T2 ON T1.train_id  =  T2.train_id WHERE T1.station_id NOT IN (SELECT T4.station_id FROM train_station AS T3 JOIN station AS T4 ON T3.station_id  =  T4.station_id WHERE t4.location  =  "London")
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT T2.name FROM train_station AS T1 JOIN train AS T2 ON T1.train_id  =  T2.train_id WHERE T1.station_id NOT IN (SELECT T4.station_id FROM train_station AS T3 JOIN station AS T4 ON T3.station_id  =  T4.station_id WHERE t4.location  =  "London")
##Instruction:
Database: train_station
Total Tables: 3
Total Columns: 14

Table Schemas:

train_station contains tables such as station, train, train_station.
Table station has columns such as Station_ID, Name, Annual_entry_exit, Annual_interchanges, Total_Passengers, Location, Main_Services, Number_of_Platforms.
Station_ID is the primary key.
Table train has columns such as Train_ID, Name, Time, Service.
Train_ID is the primary key.
Table train_station has columns such as Train_ID, Station_ID.
Train_ID is the primary key.
The Station_ID of train_station is the foreign key of Station_ID of station.
The Train_ID of train_station is the foreign key of Train_ID of train.

##Role Access Policy (Column-Level):
Role: StationManager
Accessible Columns: station: Station_ID, Name, Annual_entry_exit, Annual_interchanges, Total_Passengers, Location, Number_of_Platforms; train_station: Station_ID, Train_ID; train: Train_ID, Name, Time, Service

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: List the names and locations of all stations ordered by their yearly entry exit and interchange amounts.
Answer: SELECT name ,  LOCATION FROM station ORDER BY Annual_entry_exit ,  Annual_interchanges
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT name ,  LOCATION FROM station ORDER BY Annual_entry_exit ,  Annual_interchanges