sharkiefff/RBAC-Text2SQL-Benchmark huggingface dataset:
##Instruction:
Database: college_3
Total Tables: 8
Total Columns: 39

Table Schemas:

college_3 contains tables such as Student, Faculty, Department, Member_of, Course, Minor_in, Enrolled_in, Gradeconversion.
Table Student has columns such as StuID, LName, Fname, Age, Sex, Major, Advisor, city_code.
StuID is the primary key.
Table Faculty has columns such as FacID, Lname, Fname, Rank, Sex, Phone, Room, Building.
FacID is the primary key.
Table Department has columns such as DNO, Division, DName, Room, Building, DPhone.
DNO is the primary key.
Table Member_of has columns such as FacID, DNO, Appt_Type.
Table Course has columns such as CID, CName, Credits, Instructor, Days, Hours, DNO.
CID is the primary key.
Table Minor_in has columns such as StuID, DNO.
Table Enrolled_in has columns such as StuID, CID, Grade.
Table Gradeconversion has columns such as lettergrade, gradepoint.
lettergrade is the primary key.
The DNO of Member_of is the foreign key of DNO of Department.
The FacID of Member_of is the foreign key of FacID of Faculty.
The DNO of Course is the foreign key of DNO of Department.
The Instructor of Course is the foreign key of FacID of Faculty.
The DNO of Minor_in is the foreign key of DNO of Department.
The StuID of Minor_in is the foreign key of StuID of Student.
The Grade of Enrolled_in is the foreign key of lettergrade of Gradeconversion.
The CID of Enrolled_in is the foreign key of CID of Course.
The StuID of Enrolled_in is the foreign key of StuID of Student.

##Role Access Policy (Column-Level):
Role: AcademicAdvisor
Accessible Columns: Student: StuID, LName, Fname, Age, Sex, Major, Advisor, city_code; Enrolled_in: StuID, CID, Grade; Minor_in: StuID, DNO; Course: CID, CName, Credits, Instructor, Days, Hours, DNO; Faculty: FacID, Lname, Fname, Rank, Room, Building; Gradeconversion: lettergrade, gradepoint

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: What are the department name and room for the course INTRODUCTION TO COMPUTER SCIENCE?
Answer: Sorry, I cannot answer.
Permission: denied (Missing column permissions: department: DNO, Dname, Room)
Gold SQL: SELECT T2.Dname ,  T2.Room FROM COURSE AS T1 JOIN DEPARTMENT AS T2 ON T1.DNO  =  T2.DNO WHERE T1.CName  =  "INTRODUCTION TO COMPUTER SCIENCE"
##Instruction:
Database: college_3
Total Tables: 8
Total Columns: 39

Table Schemas:

college_3 contains tables such as Student, Faculty, Department, Member_of, Course, Minor_in, Enrolled_in, Gradeconversion.
Table Student has columns such as StuID, LName, Fname, Age, Sex, Major, Advisor, city_code.
StuID is the primary key.
Table Faculty has columns such as FacID, Lname, Fname, Rank, Sex, Phone, Room, Building.
FacID is the primary key.
Table Department has columns such as DNO, Division, DName, Room, Building, DPhone.
DNO is the primary key.
Table Member_of has columns such as FacID, DNO, Appt_Type.
Table Course has columns such as CID, CName, Credits, Instructor, Days, Hours, DNO.
CID is the primary key.
Table Minor_in has columns such as StuID, DNO.
Table Enrolled_in has columns such as StuID, CID, Grade.
Table Gradeconversion has columns such as lettergrade, gradepoint.
lettergrade is the primary key.
The DNO of Member_of is the foreign key of DNO of Department.
The FacID of Member_of is the foreign key of FacID of Faculty.
The DNO of Course is the foreign key of DNO of Department.
The Instructor of Course is the foreign key of FacID of Faculty.
The DNO of Minor_in is the foreign key of DNO of Department.
The StuID of Minor_in is the foreign key of StuID of Student.
The Grade of Enrolled_in is the foreign key of lettergrade of Gradeconversion.
The CID of Enrolled_in is the foreign key of CID of Course.
The StuID of Enrolled_in is the foreign key of StuID of Student.

##Role Access Policy (Column-Level):
Role: AcademicAdvisor
Accessible Columns: Student: StuID, LName, Fname, Age, Sex, Major, Advisor, city_code; Enrolled_in: StuID, CID, Grade; Minor_in: StuID, DNO; Course: CID, CName, Credits, Instructor, Days, Hours, DNO; Faculty: FacID, Lname, Fname, Rank, Room, Building; Gradeconversion: lettergrade, gradepoint

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: Find the student first and last names and grade points of all enrollments.
Answer: SELECT T3.Fname ,  T3.LName ,  T2.gradepoint FROM ENROLLED_IN AS T1 JOIN GRADECONVERSION AS T2 JOIN STUDENT AS T3 ON T1.Grade  =  T2.lettergrade AND T1.StuID  =  T3.StuID
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT T3.Fname ,  T3.LName ,  T2.gradepoint FROM ENROLLED_IN AS T1 JOIN GRADECONVERSION AS T2 JOIN STUDENT AS T3 ON T1.Grade  =  T2.lettergrade AND T1.StuID  =  T3.StuID
##Instruction:
Database: college_3
Total Tables: 8
Total Columns: 39

Table Schemas:

college_3 contains tables such as Student, Faculty, Department, Member_of, Course, Minor_in, Enrolled_in, Gradeconversion.
Table Student has columns such as StuID, LName, Fname, Age, Sex, Major, Advisor, city_code.
StuID is the primary key.
Table Faculty has columns such as FacID, Lname, Fname, Rank, Sex, Phone, Room, Building.
FacID is the primary key.
Table Department has columns such as DNO, Division, DName, Room, Building, DPhone.
DNO is the primary key.
Table Member_of has columns such as FacID, DNO, Appt_Type.
Table Course has columns such as CID, CName, Credits, Instructor, Days, Hours, DNO.
CID is the primary key.
Table Minor_in has columns such as StuID, DNO.
Table Enrolled_in has columns such as StuID, CID, Grade.
Table Gradeconversion has columns such as lettergrade, gradepoint.
lettergrade is the primary key.
The DNO of Member_of is the foreign key of DNO of Department.
The FacID of Member_of is the foreign key of FacID of Faculty.
The DNO of Course is the foreign key of DNO of Department.
The Instructor of Course is the foreign key of FacID of Faculty.
The DNO of Minor_in is the foreign key of DNO of Department.
The StuID of Minor_in is the foreign key of StuID of Student.
The Grade of Enrolled_in is the foreign key of lettergrade of Gradeconversion.
The CID of Enrolled_in is the foreign key of CID of Course.
The StuID of Enrolled_in is the foreign key of StuID of Student.

##Role Access Policy (Column-Level):
Role: AcademicAdvisor
Accessible Columns: Student: StuID, LName, Fname, Age, Sex, Major, Advisor, city_code; Enrolled_in: StuID, CID, Grade; Minor_in: StuID, DNO; Course: CID, CName, Credits, Instructor, Days, Hours, DNO; Faculty: FacID, Lname, Fname, Rank, Room, Building; Gradeconversion: lettergrade, gradepoint

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: What are the full names and gradepoints for all enrollments?
Answer: SELECT T3.Fname ,  T3.LName ,  T2.gradepoint FROM ENROLLED_IN AS T1 JOIN GRADECONVERSION AS T2 JOIN STUDENT AS T3 ON T1.Grade  =  T2.lettergrade AND T1.StuID  =  T3.StuID
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT T3.Fname ,  T3.LName ,  T2.gradepoint FROM ENROLLED_IN AS T1 JOIN GRADECONVERSION AS T2 JOIN STUDENT AS T3 ON T1.Grade  =  T2.lettergrade AND T1.StuID  =  T3.StuID
##Instruction:
Database: college_3
Total Tables: 8
Total Columns: 39

Table Schemas:

college_3 contains tables such as Student, Faculty, Department, Member_of, Course, Minor_in, Enrolled_in, Gradeconversion.
Table Student has columns such as StuID, LName, Fname, Age, Sex, Major, Advisor, city_code.
StuID is the primary key.
Table Faculty has columns such as FacID, Lname, Fname, Rank, Sex, Phone, Room, Building.
FacID is the primary key.
Table Department has columns such as DNO, Division, DName, Room, Building, DPhone.
DNO is the primary key.
Table Member_of has columns such as FacID, DNO, Appt_Type.
Table Course has columns such as CID, CName, Credits, Instructor, Days, Hours, DNO.
CID is the primary key.
Table Minor_in has columns such as StuID, DNO.
Table Enrolled_in has columns such as StuID, CID, Grade.
Table Gradeconversion has columns such as lettergrade, gradepoint.
lettergrade is the primary key.
The DNO of Member_of is the foreign key of DNO of Department.
The FacID of Member_of is the foreign key of FacID of Faculty.
The DNO of Course is the foreign key of DNO of Department.
The Instructor of Course is the foreign key of FacID of Faculty.
The DNO of Minor_in is the foreign key of DNO of Department.
The StuID of Minor_in is the foreign key of StuID of Student.
The Grade of Enrolled_in is the foreign key of lettergrade of Gradeconversion.
The CID of Enrolled_in is the foreign key of CID of Course.
The StuID of Enrolled_in is the foreign key of StuID of Student.

##Role Access Policy (Column-Level):
Role: AcademicAdvisor
Accessible Columns: Student: StuID, LName, Fname, Age, Sex, Major, Advisor, city_code; Enrolled_in: StuID, CID, Grade; Minor_in: StuID, DNO; Course: CID, CName, Credits, Instructor, Days, Hours, DNO; Faculty: FacID, Lname, Fname, Rank, Room, Building; Gradeconversion: lettergrade, gradepoint

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: Find the distinct student first names of all students that have grade point at least 3.8 in one course.
Answer: SELECT DISTINCT T3.Fname FROM ENROLLED_IN AS T1 JOIN GRADECONVERSION AS T2 JOIN STUDENT AS T3 ON T1.Grade  =  T2.lettergrade AND T1.StuID  =  T3.StuID WHERE T2.gradepoint  >=  3.8
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT DISTINCT T3.Fname FROM ENROLLED_IN AS T1 JOIN GRADECONVERSION AS T2 JOIN STUDENT AS T3 ON T1.Grade  =  T2.lettergrade AND T1.StuID  =  T3.StuID WHERE T2.gradepoint  >=  3.8
##Instruction:
Database: college_3
Total Tables: 8
Total Columns: 39

Table Schemas:

college_3 contains tables such as Student, Faculty, Department, Member_of, Course, Minor_in, Enrolled_in, Gradeconversion.
Table Student has columns such as StuID, LName, Fname, Age, Sex, Major, Advisor, city_code.
StuID is the primary key.
Table Faculty has columns such as FacID, Lname, Fname, Rank, Sex, Phone, Room, Building.
FacID is the primary key.
Table Department has columns such as DNO, Division, DName, Room, Building, DPhone.
DNO is the primary key.
Table Member_of has columns such as FacID, DNO, Appt_Type.
Table Course has columns such as CID, CName, Credits, Instructor, Days, Hours, DNO.
CID is the primary key.
Table Minor_in has columns such as StuID, DNO.
Table Enrolled_in has columns such as StuID, CID, Grade.
Table Gradeconversion has columns such as lettergrade, gradepoint.
lettergrade is the primary key.
The DNO of Member_of is the foreign key of DNO of Department.
The FacID of Member_of is the foreign key of FacID of Faculty.
The DNO of Course is the foreign key of DNO of Department.
The Instructor of Course is the foreign key of FacID of Faculty.
The DNO of Minor_in is the foreign key of DNO of Department.
The StuID of Minor_in is the foreign key of StuID of Student.
The Grade of Enrolled_in is the foreign key of lettergrade of Gradeconversion.
The CID of Enrolled_in is the foreign key of CID of Course.
The StuID of Enrolled_in is the foreign key of StuID of Student.

##Role Access Policy (Column-Level):
Role: AcademicAdvisor
Accessible Columns: Student: StuID, LName, Fname, Age, Sex, Major, Advisor, city_code; Enrolled_in: StuID, CID, Grade; Minor_in: StuID, DNO; Course: CID, CName, Credits, Instructor, Days, Hours, DNO; Faculty: FacID, Lname, Fname, Rank, Room, Building; Gradeconversion: lettergrade, gradepoint

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: What are the distinct first names for students with a grade point of 3.8 or above in at least one course?
Answer: SELECT DISTINCT T3.Fname FROM ENROLLED_IN AS T1 JOIN GRADECONVERSION AS T2 JOIN STUDENT AS T3 ON T1.Grade  =  T2.lettergrade AND T1.StuID  =  T3.StuID WHERE T2.gradepoint  >=  3.8
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT DISTINCT T3.Fname FROM ENROLLED_IN AS T1 JOIN GRADECONVERSION AS T2 JOIN STUDENT AS T3 ON T1.Grade  =  T2.lettergrade AND T1.StuID  =  T3.StuID WHERE T2.gradepoint  >=  3.8
##Instruction:
Database: college_3
Total Tables: 8
Total Columns: 39

Table Schemas:

college_3 contains tables such as Student, Faculty, Department, Member_of, Course, Minor_in, Enrolled_in, Gradeconversion.
Table Student has columns such as StuID, LName, Fname, Age, Sex, Major, Advisor, city_code.
StuID is the primary key.
Table Faculty has columns such as FacID, Lname, Fname, Rank, Sex, Phone, Room, Building.
FacID is the primary key.
Table Department has columns such as DNO, Division, DName, Room, Building, DPhone.
DNO is the primary key.
Table Member_of has columns such as FacID, DNO, Appt_Type.
Table Course has columns such as CID, CName, Credits, Instructor, Days, Hours, DNO.
CID is the primary key.
Table Minor_in has columns such as StuID, DNO.
Table Enrolled_in has columns such as StuID, CID, Grade.
Table Gradeconversion has columns such as lettergrade, gradepoint.
lettergrade is the primary key.
The DNO of Member_of is the foreign key of DNO of Department.
The FacID of Member_of is the foreign key of FacID of Faculty.
The DNO of Course is the foreign key of DNO of Department.
The Instructor of Course is the foreign key of FacID of Faculty.
The DNO of Minor_in is the foreign key of DNO of Department.
The StuID of Minor_in is the foreign key of StuID of Student.
The Grade of Enrolled_in is the foreign key of lettergrade of Gradeconversion.
The CID of Enrolled_in is the foreign key of CID of Course.
The StuID of Enrolled_in is the foreign key of StuID of Student.

##Role Access Policy (Column-Level):
Role: AcademicAdvisor
Accessible Columns: Student: StuID, LName, Fname, Age, Sex, Major, Advisor, city_code; Enrolled_in: StuID, CID, Grade; Minor_in: StuID, DNO; Course: CID, CName, Credits, Instructor, Days, Hours, DNO; Faculty: FacID, Lname, Fname, Rank, Room, Building; Gradeconversion: lettergrade, gradepoint

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: Find the full names of faculties who are members of department with department number 520.
Answer: Sorry, I cannot answer.
Permission: denied (Missing column permissions: member_of: DNO, FacID)
Gold SQL: SELECT T1.Fname ,  T1.Lname FROM FACULTY AS T1 JOIN MEMBER_OF AS T2 ON T1.FacID  =  T2.FacID WHERE T2.DNO  =  520
##Instruction:
Database: college_3
Total Tables: 8
Total Columns: 39

Table Schemas:

college_3 contains tables such as Student, Faculty, Department, Member_of, Course, Minor_in, Enrolled_in, Gradeconversion.
Table Student has columns such as StuID, LName, Fname, Age, Sex, Major, Advisor, city_code.
StuID is the primary key.
Table Faculty has columns such as FacID, Lname, Fname, Rank, Sex, Phone, Room, Building.
FacID is the primary key.
Table Department has columns such as DNO, Division, DName, Room, Building, DPhone.
DNO is the primary key.
Table Member_of has columns such as FacID, DNO, Appt_Type.
Table Course has columns such as CID, CName, Credits, Instructor, Days, Hours, DNO.
CID is the primary key.
Table Minor_in has columns such as StuID, DNO.
Table Enrolled_in has columns such as StuID, CID, Grade.
Table Gradeconversion has columns such as lettergrade, gradepoint.
lettergrade is the primary key.
The DNO of Member_of is the foreign key of DNO of Department.
The FacID of Member_of is the foreign key of FacID of Faculty.
The DNO of Course is the foreign key of DNO of Department.
The Instructor of Course is the foreign key of FacID of Faculty.
The DNO of Minor_in is the foreign key of DNO of Department.
The StuID of Minor_in is the foreign key of StuID of Student.
The Grade of Enrolled_in is the foreign key of lettergrade of Gradeconversion.
The CID of Enrolled_in is the foreign key of CID of Course.
The StuID of Enrolled_in is the foreign key of StuID of Student.

##Role Access Policy (Column-Level):
Role: AcademicAdvisor
Accessible Columns: Student: StuID, LName, Fname, Age, Sex, Major, Advisor, city_code; Enrolled_in: StuID, CID, Grade; Minor_in: StuID, DNO; Course: CID, CName, Credits, Instructor, Days, Hours, DNO; Faculty: FacID, Lname, Fname, Rank, Room, Building; Gradeconversion: lettergrade, gradepoint

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: What are the full names of faculty members who are a part of department 520?
Answer: Sorry, I cannot answer.
Permission: denied (Missing column permissions: member_of: DNO, FacID)
Gold SQL: SELECT T1.Fname ,  T1.Lname FROM FACULTY AS T1 JOIN MEMBER_OF AS T2 ON T1.FacID  =  T2.FacID WHERE T2.DNO  =  520
##Instruction:
Database: college_3
Total Tables: 8
Total Columns: 39

Table Schemas:

college_3 contains tables such as Student, Faculty, Department, Member_of, Course, Minor_in, Enrolled_in, Gradeconversion.
Table Student has columns such as StuID, LName, Fname, Age, Sex, Major, Advisor, city_code.
StuID is the primary key.
Table Faculty has columns such as FacID, Lname, Fname, Rank, Sex, Phone, Room, Building.
FacID is the primary key.
Table Department has columns such as DNO, Division, DName, Room, Building, DPhone.
DNO is the primary key.
Table Member_of has columns such as FacID, DNO, Appt_Type.
Table Course has columns such as CID, CName, Credits, Instructor, Days, Hours, DNO.
CID is the primary key.
Table Minor_in has columns such as StuID, DNO.
Table Enrolled_in has columns such as StuID, CID, Grade.
Table Gradeconversion has columns such as lettergrade, gradepoint.
lettergrade is the primary key.
The DNO of Member_of is the foreign key of DNO of Department.
The FacID of Member_of is the foreign key of FacID of Faculty.
The DNO of Course is the foreign key of DNO of Department.
The Instructor of Course is the foreign key of FacID of Faculty.
The DNO of Minor_in is the foreign key of DNO of Department.
The StuID of Minor_in is the foreign key of StuID of Student.
The Grade of Enrolled_in is the foreign key of lettergrade of Gradeconversion.
The CID of Enrolled_in is the foreign key of CID of Course.
The StuID of Enrolled_in is the foreign key of StuID of Student.

##Role Access Policy (Column-Level):
Role: AcademicAdvisor
Accessible Columns: Student: StuID, LName, Fname, Age, Sex, Major, Advisor, city_code; Enrolled_in: StuID, CID, Grade; Minor_in: StuID, DNO; Course: CID, CName, Credits, Instructor, Days, Hours, DNO; Faculty: FacID, Lname, Fname, Rank, Room, Building; Gradeconversion: lettergrade, gradepoint

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: What are the first names and last names of the students that minor in the department with DNO 140.
Answer: SELECT T2.Fname ,  T2.Lname FROM MINOR_IN AS T1 JOIN STUDENT AS T2 ON T1.StuID  =  T2.StuID WHERE T1.DNO  =  140
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT T2.Fname ,  T2.Lname FROM MINOR_IN AS T1 JOIN STUDENT AS T2 ON T1.StuID  =  T2.StuID WHERE T1.DNO  =  140
##Instruction:
Database: college_3
Total Tables: 8
Total Columns: 39

Table Schemas:

college_3 contains tables such as Student, Faculty, Department, Member_of, Course, Minor_in, Enrolled_in, Gradeconversion.
Table Student has columns such as StuID, LName, Fname, Age, Sex, Major, Advisor, city_code.
StuID is the primary key.
Table Faculty has columns such as FacID, Lname, Fname, Rank, Sex, Phone, Room, Building.
FacID is the primary key.
Table Department has columns such as DNO, Division, DName, Room, Building, DPhone.
DNO is the primary key.
Table Member_of has columns such as FacID, DNO, Appt_Type.
Table Course has columns such as CID, CName, Credits, Instructor, Days, Hours, DNO.
CID is the primary key.
Table Minor_in has columns such as StuID, DNO.
Table Enrolled_in has columns such as StuID, CID, Grade.
Table Gradeconversion has columns such as lettergrade, gradepoint.
lettergrade is the primary key.
The DNO of Member_of is the foreign key of DNO of Department.
The FacID of Member_of is the foreign key of FacID of Faculty.
The DNO of Course is the foreign key of DNO of Department.
The Instructor of Course is the foreign key of FacID of Faculty.
The DNO of Minor_in is the foreign key of DNO of Department.
The StuID of Minor_in is the foreign key of StuID of Student.
The Grade of Enrolled_in is the foreign key of lettergrade of Gradeconversion.
The CID of Enrolled_in is the foreign key of CID of Course.
The StuID of Enrolled_in is the foreign key of StuID of Student.

##Role Access Policy (Column-Level):
Role: AcademicAdvisor
Accessible Columns: Student: StuID, LName, Fname, Age, Sex, Major, Advisor, city_code; Enrolled_in: StuID, CID, Grade; Minor_in: StuID, DNO; Course: CID, CName, Credits, Instructor, Days, Hours, DNO; Faculty: FacID, Lname, Fname, Rank, Room, Building; Gradeconversion: lettergrade, gradepoint

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: What are the full names of students minoring in department 140?
Answer: SELECT T2.Fname ,  T2.Lname FROM MINOR_IN AS T1 JOIN STUDENT AS T2 ON T1.StuID  =  T2.StuID WHERE T1.DNO  =  140
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT T2.Fname ,  T2.Lname FROM MINOR_IN AS T1 JOIN STUDENT AS T2 ON T1.StuID  =  T2.StuID WHERE T1.DNO  =  140