sharkiefff/RBAC-Text2SQL-Benchmark huggingface dataset:
##Instruction:
Database: e_learning
Total Tables: 6
Total Columns: 32

Table Schemas:

e_learning contains tables such as Course_Authors_and_Tutors, Students, Subjects, Courses, Student_Course_Enrolment, Student_Tests_Taken.
Table Course_Authors_and_Tutors has columns such as author_id, author_tutor_ATB, login_name, password, personal_name, middle_name, family_name, gender_mf, address_line_1.
author_id is the primary key.
Table Students has columns such as student_id, date_of_registration, date_of_latest_logon, login_name, password, personal_name, middle_name, family_name.
student_id is the primary key.
Table Subjects has columns such as subject_id, subject_name.
subject_id is the primary key.
Table Courses has columns such as course_id, author_id, subject_id, course_name, course_description.
course_id is the primary key.
Table Student_Course_Enrolment has columns such as registration_id, student_id, course_id, date_of_enrolment, date_of_completion.
registration_id is the primary key.
Table Student_Tests_Taken has columns such as registration_id, date_test_taken, test_result.
The subject_id of Courses is the foreign key of subject_id of Subjects.
The author_id of Courses is the foreign key of author_id of Course_Authors_and_Tutors.
The student_id of Student_Course_Enrolment is the foreign key of student_id of Students.
The course_id of Student_Course_Enrolment is the foreign key of course_id of Courses.
The registration_id of Student_Tests_Taken is the foreign key of registration_id of Student_Course_Enrolment.

##Role Access Policy (Column-Level):
Role: CourseAuthor
Accessible Columns: Course_Authors_and_Tutors: author_id, author_tutor_ATB, login_name, personal_name, middle_name, family_name, gender_mf; Subjects: subject_id, subject_name; Courses: course_id, author_id, subject_id, course_name, course_description

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: Find the login name of the course author that teaches the course with name "advanced database".
Answer: SELECT T1.login_name FROM Course_Authors_and_Tutors AS T1 JOIN Courses AS T2 ON T1.author_id  =  T2.author_id WHERE T2.course_name  =  "advanced database"
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT T1.login_name FROM Course_Authors_and_Tutors AS T1 JOIN Courses AS T2 ON T1.author_id  =  T2.author_id WHERE T2.course_name  =  "advanced database"
##Instruction:
Database: e_learning
Total Tables: 6
Total Columns: 32

Table Schemas:

e_learning contains tables such as Course_Authors_and_Tutors, Students, Subjects, Courses, Student_Course_Enrolment, Student_Tests_Taken.
Table Course_Authors_and_Tutors has columns such as author_id, author_tutor_ATB, login_name, password, personal_name, middle_name, family_name, gender_mf, address_line_1.
author_id is the primary key.
Table Students has columns such as student_id, date_of_registration, date_of_latest_logon, login_name, password, personal_name, middle_name, family_name.
student_id is the primary key.
Table Subjects has columns such as subject_id, subject_name.
subject_id is the primary key.
Table Courses has columns such as course_id, author_id, subject_id, course_name, course_description.
course_id is the primary key.
Table Student_Course_Enrolment has columns such as registration_id, student_id, course_id, date_of_enrolment, date_of_completion.
registration_id is the primary key.
Table Student_Tests_Taken has columns such as registration_id, date_test_taken, test_result.
The subject_id of Courses is the foreign key of subject_id of Subjects.
The author_id of Courses is the foreign key of author_id of Course_Authors_and_Tutors.
The student_id of Student_Course_Enrolment is the foreign key of student_id of Students.
The course_id of Student_Course_Enrolment is the foreign key of course_id of Courses.
The registration_id of Student_Tests_Taken is the foreign key of registration_id of Student_Course_Enrolment.

##Role Access Policy (Column-Level):
Role: CourseAuthor
Accessible Columns: Course_Authors_and_Tutors: author_id, author_tutor_ATB, login_name, personal_name, middle_name, family_name, gender_mf; Subjects: subject_id, subject_name; Courses: course_id, author_id, subject_id, course_name, course_description

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: Which course author teaches the "advanced database" course? Give me his or her login name.
Answer: SELECT T1.login_name FROM Course_Authors_and_Tutors AS T1 JOIN Courses AS T2 ON T1.author_id  =  T2.author_id WHERE T2.course_name  =  "advanced database"
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT T1.login_name FROM Course_Authors_and_Tutors AS T1 JOIN Courses AS T2 ON T1.author_id  =  T2.author_id WHERE T2.course_name  =  "advanced database"
##Instruction:
Database: e_learning
Total Tables: 6
Total Columns: 32

Table Schemas:

e_learning contains tables such as Course_Authors_and_Tutors, Students, Subjects, Courses, Student_Course_Enrolment, Student_Tests_Taken.
Table Course_Authors_and_Tutors has columns such as author_id, author_tutor_ATB, login_name, password, personal_name, middle_name, family_name, gender_mf, address_line_1.
author_id is the primary key.
Table Students has columns such as student_id, date_of_registration, date_of_latest_logon, login_name, password, personal_name, middle_name, family_name.
student_id is the primary key.
Table Subjects has columns such as subject_id, subject_name.
subject_id is the primary key.
Table Courses has columns such as course_id, author_id, subject_id, course_name, course_description.
course_id is the primary key.
Table Student_Course_Enrolment has columns such as registration_id, student_id, course_id, date_of_enrolment, date_of_completion.
registration_id is the primary key.
Table Student_Tests_Taken has columns such as registration_id, date_test_taken, test_result.
The subject_id of Courses is the foreign key of subject_id of Subjects.
The author_id of Courses is the foreign key of author_id of Course_Authors_and_Tutors.
The student_id of Student_Course_Enrolment is the foreign key of student_id of Students.
The course_id of Student_Course_Enrolment is the foreign key of course_id of Courses.
The registration_id of Student_Tests_Taken is the foreign key of registration_id of Student_Course_Enrolment.

##Role Access Policy (Column-Level):
Role: CourseAuthor
Accessible Columns: Course_Authors_and_Tutors: author_id, author_tutor_ATB, login_name, personal_name, middle_name, family_name, gender_mf; Subjects: subject_id, subject_name; Courses: course_id, author_id, subject_id, course_name, course_description

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: Find the addresses of the course authors who teach the course with name "operating system" or "data structure".
Answer: Sorry, I cannot answer.
Permission: denied (Missing column permissions: course_authors_and_tutors: address_line_1)
Gold SQL: SELECT T1.address_line_1 FROM Course_Authors_and_Tutors AS T1 JOIN Courses AS T2 ON T1.author_id  =  T2.author_id WHERE T2.course_name  =  "operating system" OR T2.course_name  =  "data structure"
##Instruction:
Database: e_learning
Total Tables: 6
Total Columns: 32

Table Schemas:

e_learning contains tables such as Course_Authors_and_Tutors, Students, Subjects, Courses, Student_Course_Enrolment, Student_Tests_Taken.
Table Course_Authors_and_Tutors has columns such as author_id, author_tutor_ATB, login_name, password, personal_name, middle_name, family_name, gender_mf, address_line_1.
author_id is the primary key.
Table Students has columns such as student_id, date_of_registration, date_of_latest_logon, login_name, password, personal_name, middle_name, family_name.
student_id is the primary key.
Table Subjects has columns such as subject_id, subject_name.
subject_id is the primary key.
Table Courses has columns such as course_id, author_id, subject_id, course_name, course_description.
course_id is the primary key.
Table Student_Course_Enrolment has columns such as registration_id, student_id, course_id, date_of_enrolment, date_of_completion.
registration_id is the primary key.
Table Student_Tests_Taken has columns such as registration_id, date_test_taken, test_result.
The subject_id of Courses is the foreign key of subject_id of Subjects.
The author_id of Courses is the foreign key of author_id of Course_Authors_and_Tutors.
The student_id of Student_Course_Enrolment is the foreign key of student_id of Students.
The course_id of Student_Course_Enrolment is the foreign key of course_id of Courses.
The registration_id of Student_Tests_Taken is the foreign key of registration_id of Student_Course_Enrolment.

##Role Access Policy (Column-Level):
Role: CourseAuthor
Accessible Columns: Course_Authors_and_Tutors: author_id, author_tutor_ATB, login_name, personal_name, middle_name, family_name, gender_mf; Subjects: subject_id, subject_name; Courses: course_id, author_id, subject_id, course_name, course_description

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: What are the addresses of the course authors who teach either "operating system" or "data structure" course.
Answer: Sorry, I cannot answer.
Permission: denied (Missing column permissions: course_authors_and_tutors: address_line_1)
Gold SQL: SELECT T1.address_line_1 FROM Course_Authors_and_Tutors AS T1 JOIN Courses AS T2 ON T1.author_id  =  T2.author_id WHERE T2.course_name  =  "operating system" OR T2.course_name  =  "data structure"
##Instruction:
Database: e_learning
Total Tables: 6
Total Columns: 32

Table Schemas:

e_learning contains tables such as Course_Authors_and_Tutors, Students, Subjects, Courses, Student_Course_Enrolment, Student_Tests_Taken.
Table Course_Authors_and_Tutors has columns such as author_id, author_tutor_ATB, login_name, password, personal_name, middle_name, family_name, gender_mf, address_line_1.
author_id is the primary key.
Table Students has columns such as student_id, date_of_registration, date_of_latest_logon, login_name, password, personal_name, middle_name, family_name.
student_id is the primary key.
Table Subjects has columns such as subject_id, subject_name.
subject_id is the primary key.
Table Courses has columns such as course_id, author_id, subject_id, course_name, course_description.
course_id is the primary key.
Table Student_Course_Enrolment has columns such as registration_id, student_id, course_id, date_of_enrolment, date_of_completion.
registration_id is the primary key.
Table Student_Tests_Taken has columns such as registration_id, date_test_taken, test_result.
The subject_id of Courses is the foreign key of subject_id of Subjects.
The author_id of Courses is the foreign key of author_id of Course_Authors_and_Tutors.
The student_id of Student_Course_Enrolment is the foreign key of student_id of Students.
The course_id of Student_Course_Enrolment is the foreign key of course_id of Courses.
The registration_id of Student_Tests_Taken is the foreign key of registration_id of Student_Course_Enrolment.

##Role Access Policy (Column-Level):
Role: CourseAuthor
Accessible Columns: Course_Authors_and_Tutors: author_id, author_tutor_ATB, login_name, personal_name, middle_name, family_name, gender_mf; Subjects: subject_id, subject_name; Courses: course_id, author_id, subject_id, course_name, course_description

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: Find the personal name, family name, and author ID of the course author that teaches the most courses.
Answer: SELECT T1.personal_name ,  T1.family_name ,  T2.author_id FROM Course_Authors_and_Tutors AS T1 JOIN Courses AS T2 ON T1.author_id  =  T2.author_id GROUP BY T2.author_id ORDER BY COUNT(*) DESC LIMIT 1
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT T1.personal_name ,  T1.family_name ,  T2.author_id FROM Course_Authors_and_Tutors AS T1 JOIN Courses AS T2 ON T1.author_id  =  T2.author_id GROUP BY T2.author_id ORDER BY COUNT(*) DESC LIMIT 1
##Instruction:
Database: e_learning
Total Tables: 6
Total Columns: 32

Table Schemas:

e_learning contains tables such as Course_Authors_and_Tutors, Students, Subjects, Courses, Student_Course_Enrolment, Student_Tests_Taken.
Table Course_Authors_and_Tutors has columns such as author_id, author_tutor_ATB, login_name, password, personal_name, middle_name, family_name, gender_mf, address_line_1.
author_id is the primary key.
Table Students has columns such as student_id, date_of_registration, date_of_latest_logon, login_name, password, personal_name, middle_name, family_name.
student_id is the primary key.
Table Subjects has columns such as subject_id, subject_name.
subject_id is the primary key.
Table Courses has columns such as course_id, author_id, subject_id, course_name, course_description.
course_id is the primary key.
Table Student_Course_Enrolment has columns such as registration_id, student_id, course_id, date_of_enrolment, date_of_completion.
registration_id is the primary key.
Table Student_Tests_Taken has columns such as registration_id, date_test_taken, test_result.
The subject_id of Courses is the foreign key of subject_id of Subjects.
The author_id of Courses is the foreign key of author_id of Course_Authors_and_Tutors.
The student_id of Student_Course_Enrolment is the foreign key of student_id of Students.
The course_id of Student_Course_Enrolment is the foreign key of course_id of Courses.
The registration_id of Student_Tests_Taken is the foreign key of registration_id of Student_Course_Enrolment.

##Role Access Policy (Column-Level):
Role: CourseAuthor
Accessible Columns: Course_Authors_and_Tutors: author_id, author_tutor_ATB, login_name, personal_name, middle_name, family_name, gender_mf; Subjects: subject_id, subject_name; Courses: course_id, author_id, subject_id, course_name, course_description

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: What are the personal name, family name, and author ID of the course author who teaches the most courses?
Answer: SELECT T1.personal_name ,  T1.family_name ,  T2.author_id FROM Course_Authors_and_Tutors AS T1 JOIN Courses AS T2 ON T1.author_id  =  T2.author_id GROUP BY T2.author_id ORDER BY COUNT(*) DESC LIMIT 1
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT T1.personal_name ,  T1.family_name ,  T2.author_id FROM Course_Authors_and_Tutors AS T1 JOIN Courses AS T2 ON T1.author_id  =  T2.author_id GROUP BY T2.author_id ORDER BY COUNT(*) DESC LIMIT 1
##Instruction:
Database: e_learning
Total Tables: 6
Total Columns: 32

Table Schemas:

e_learning contains tables such as Course_Authors_and_Tutors, Students, Subjects, Courses, Student_Course_Enrolment, Student_Tests_Taken.
Table Course_Authors_and_Tutors has columns such as author_id, author_tutor_ATB, login_name, password, personal_name, middle_name, family_name, gender_mf, address_line_1.
author_id is the primary key.
Table Students has columns such as student_id, date_of_registration, date_of_latest_logon, login_name, password, personal_name, middle_name, family_name.
student_id is the primary key.
Table Subjects has columns such as subject_id, subject_name.
subject_id is the primary key.
Table Courses has columns such as course_id, author_id, subject_id, course_name, course_description.
course_id is the primary key.
Table Student_Course_Enrolment has columns such as registration_id, student_id, course_id, date_of_enrolment, date_of_completion.
registration_id is the primary key.
Table Student_Tests_Taken has columns such as registration_id, date_test_taken, test_result.
The subject_id of Courses is the foreign key of subject_id of Subjects.
The author_id of Courses is the foreign key of author_id of Course_Authors_and_Tutors.
The student_id of Student_Course_Enrolment is the foreign key of student_id of Students.
The course_id of Student_Course_Enrolment is the foreign key of course_id of Courses.
The registration_id of Student_Tests_Taken is the foreign key of registration_id of Student_Course_Enrolment.

##Role Access Policy (Column-Level):
Role: CourseAuthor
Accessible Columns: Course_Authors_and_Tutors: author_id, author_tutor_ATB, login_name, personal_name, middle_name, family_name, gender_mf; Subjects: subject_id, subject_name; Courses: course_id, author_id, subject_id, course_name, course_description

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: Find the addresses and author IDs of the course authors that teach at least two courses.
Answer: Sorry, I cannot answer.
Permission: denied (Missing column permissions: course_authors_and_tutors: address_line_1)
Gold SQL: SELECT T1.address_line_1 ,  T2.author_id FROM Course_Authors_and_Tutors AS T1 JOIN Courses AS T2 ON T1.author_id  =  T2.author_id GROUP BY T2.author_id HAVING Count(*)  >=  2
##Instruction:
Database: e_learning
Total Tables: 6
Total Columns: 32

Table Schemas:

e_learning contains tables such as Course_Authors_and_Tutors, Students, Subjects, Courses, Student_Course_Enrolment, Student_Tests_Taken.
Table Course_Authors_and_Tutors has columns such as author_id, author_tutor_ATB, login_name, password, personal_name, middle_name, family_name, gender_mf, address_line_1.
author_id is the primary key.
Table Students has columns such as student_id, date_of_registration, date_of_latest_logon, login_name, password, personal_name, middle_name, family_name.
student_id is the primary key.
Table Subjects has columns such as subject_id, subject_name.
subject_id is the primary key.
Table Courses has columns such as course_id, author_id, subject_id, course_name, course_description.
course_id is the primary key.
Table Student_Course_Enrolment has columns such as registration_id, student_id, course_id, date_of_enrolment, date_of_completion.
registration_id is the primary key.
Table Student_Tests_Taken has columns such as registration_id, date_test_taken, test_result.
The subject_id of Courses is the foreign key of subject_id of Subjects.
The author_id of Courses is the foreign key of author_id of Course_Authors_and_Tutors.
The student_id of Student_Course_Enrolment is the foreign key of student_id of Students.
The course_id of Student_Course_Enrolment is the foreign key of course_id of Courses.
The registration_id of Student_Tests_Taken is the foreign key of registration_id of Student_Course_Enrolment.

##Role Access Policy (Column-Level):
Role: CourseAuthor
Accessible Columns: Course_Authors_and_Tutors: author_id, author_tutor_ATB, login_name, personal_name, middle_name, family_name, gender_mf; Subjects: subject_id, subject_name; Courses: course_id, author_id, subject_id, course_name, course_description

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: Which course authors teach two or more courses? Give me their addresses and author IDs.
Answer: Sorry, I cannot answer.
Permission: denied (Missing column permissions: course_authors_and_tutors: address_line_1)
Gold SQL: SELECT T1.address_line_1 ,  T2.author_id FROM Course_Authors_and_Tutors AS T1 JOIN Courses AS T2 ON T1.author_id  =  T2.author_id GROUP BY T2.author_id HAVING Count(*)  >=  2
##Instruction:
Database: e_learning
Total Tables: 6
Total Columns: 32

Table Schemas:

e_learning contains tables such as Course_Authors_and_Tutors, Students, Subjects, Courses, Student_Course_Enrolment, Student_Tests_Taken.
Table Course_Authors_and_Tutors has columns such as author_id, author_tutor_ATB, login_name, password, personal_name, middle_name, family_name, gender_mf, address_line_1.
author_id is the primary key.
Table Students has columns such as student_id, date_of_registration, date_of_latest_logon, login_name, password, personal_name, middle_name, family_name.
student_id is the primary key.
Table Subjects has columns such as subject_id, subject_name.
subject_id is the primary key.
Table Courses has columns such as course_id, author_id, subject_id, course_name, course_description.
course_id is the primary key.
Table Student_Course_Enrolment has columns such as registration_id, student_id, course_id, date_of_enrolment, date_of_completion.
registration_id is the primary key.
Table Student_Tests_Taken has columns such as registration_id, date_test_taken, test_result.
The subject_id of Courses is the foreign key of subject_id of Subjects.
The author_id of Courses is the foreign key of author_id of Course_Authors_and_Tutors.
The student_id of Student_Course_Enrolment is the foreign key of student_id of Students.
The course_id of Student_Course_Enrolment is the foreign key of course_id of Courses.
The registration_id of Student_Tests_Taken is the foreign key of registration_id of Student_Course_Enrolment.

##Role Access Policy (Column-Level):
Role: CourseAuthor
Accessible Columns: Course_Authors_and_Tutors: author_id, author_tutor_ATB, login_name, personal_name, middle_name, family_name, gender_mf; Subjects: subject_id, subject_name; Courses: course_id, author_id, subject_id, course_name, course_description

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: Find the names of courses taught by the tutor who has personal name "Julio".
Answer: SELECT T2.course_name FROM Course_Authors_and_Tutors AS T1 JOIN Courses AS T2 ON T1.author_id  =  T2.author_id WHERE T1.personal_name  =  "Julio"
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT T2.course_name FROM Course_Authors_and_Tutors AS T1 JOIN Courses AS T2 ON T1.author_id  =  T2.author_id WHERE T1.personal_name  =  "Julio"