sharkiefff/RBAC-Text2SQL-Benchmark huggingface dataset:
##Instruction:
Database: college_3
Total Tables: 8
Total Columns: 39

Table Schemas:

college_3 contains tables such as Student, Faculty, Department, Member_of, Course, Minor_in, Enrolled_in, Gradeconversion.
Table Student has columns such as StuID, LName, Fname, Age, Sex, Major, Advisor, city_code.
StuID is the primary key.
Table Faculty has columns such as FacID, Lname, Fname, Rank, Sex, Phone, Room, Building.
FacID is the primary key.
Table Department has columns such as DNO, Division, DName, Room, Building, DPhone.
DNO is the primary key.
Table Member_of has columns such as FacID, DNO, Appt_Type.
Table Course has columns such as CID, CName, Credits, Instructor, Days, Hours, DNO.
CID is the primary key.
Table Minor_in has columns such as StuID, DNO.
Table Enrolled_in has columns such as StuID, CID, Grade.
Table Gradeconversion has columns such as lettergrade, gradepoint.
lettergrade is the primary key.
The DNO of Member_of is the foreign key of DNO of Department.
The FacID of Member_of is the foreign key of FacID of Faculty.
The DNO of Course is the foreign key of DNO of Department.
The Instructor of Course is the foreign key of FacID of Faculty.
The DNO of Minor_in is the foreign key of DNO of Department.
The StuID of Minor_in is the foreign key of StuID of Student.
The Grade of Enrolled_in is the foreign key of lettergrade of Gradeconversion.
The CID of Enrolled_in is the foreign key of CID of Course.
The StuID of Enrolled_in is the foreign key of StuID of Student.

##Role Access Policy (Column-Level):
Role: AcademicAdvisor
Accessible Columns: Student: StuID, LName, Fname, Age, Sex, Major, Advisor, city_code; Enrolled_in: StuID, CID, Grade; Minor_in: StuID, DNO; Course: CID, CName, Credits, Instructor, Days, Hours, DNO; Faculty: FacID, Lname, Fname, Rank, Room, Building; Gradeconversion: lettergrade, gradepoint

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: What are the first and last names of the instructors who teach the top 3 number of courses?
Answer: SELECT T2.Fname ,  T2.Lname FROM COURSE AS T1 JOIN FACULTY AS T2 ON T1.Instructor  =  T2.FacID GROUP BY T1.Instructor ORDER BY count(*) DESC LIMIT 3
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT T2.Fname ,  T2.Lname FROM COURSE AS T1 JOIN FACULTY AS T2 ON T1.Instructor  =  T2.FacID GROUP BY T1.Instructor ORDER BY count(*) DESC LIMIT 3
##Instruction:
Database: college_3
Total Tables: 8
Total Columns: 39

Table Schemas:

college_3 contains tables such as Student, Faculty, Department, Member_of, Course, Minor_in, Enrolled_in, Gradeconversion.
Table Student has columns such as StuID, LName, Fname, Age, Sex, Major, Advisor, city_code.
StuID is the primary key.
Table Faculty has columns such as FacID, Lname, Fname, Rank, Sex, Phone, Room, Building.
FacID is the primary key.
Table Department has columns such as DNO, Division, DName, Room, Building, DPhone.
DNO is the primary key.
Table Member_of has columns such as FacID, DNO, Appt_Type.
Table Course has columns such as CID, CName, Credits, Instructor, Days, Hours, DNO.
CID is the primary key.
Table Minor_in has columns such as StuID, DNO.
Table Enrolled_in has columns such as StuID, CID, Grade.
Table Gradeconversion has columns such as lettergrade, gradepoint.
lettergrade is the primary key.
The DNO of Member_of is the foreign key of DNO of Department.
The FacID of Member_of is the foreign key of FacID of Faculty.
The DNO of Course is the foreign key of DNO of Department.
The Instructor of Course is the foreign key of FacID of Faculty.
The DNO of Minor_in is the foreign key of DNO of Department.
The StuID of Minor_in is the foreign key of StuID of Student.
The Grade of Enrolled_in is the foreign key of lettergrade of Gradeconversion.
The CID of Enrolled_in is the foreign key of CID of Course.
The StuID of Enrolled_in is the foreign key of StuID of Student.

##Role Access Policy (Column-Level):
Role: AcademicAdvisor
Accessible Columns: Student: StuID, LName, Fname, Age, Sex, Major, Advisor, city_code; Enrolled_in: StuID, CID, Grade; Minor_in: StuID, DNO; Course: CID, CName, Credits, Instructor, Days, Hours, DNO; Faculty: FacID, Lname, Fname, Rank, Room, Building; Gradeconversion: lettergrade, gradepoint

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: What are the full names of the 3 instructors who teach the most courses?
Answer: SELECT T2.Fname ,  T2.Lname FROM COURSE AS T1 JOIN FACULTY AS T2 ON T1.Instructor  =  T2.FacID GROUP BY T1.Instructor ORDER BY count(*) DESC LIMIT 3
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT T2.Fname ,  T2.Lname FROM COURSE AS T1 JOIN FACULTY AS T2 ON T1.Instructor  =  T2.FacID GROUP BY T1.Instructor ORDER BY count(*) DESC LIMIT 3
##Instruction:
Database: college_3
Total Tables: 8
Total Columns: 39

Table Schemas:

college_3 contains tables such as Student, Faculty, Department, Member_of, Course, Minor_in, Enrolled_in, Gradeconversion.
Table Student has columns such as StuID, LName, Fname, Age, Sex, Major, Advisor, city_code.
StuID is the primary key.
Table Faculty has columns such as FacID, Lname, Fname, Rank, Sex, Phone, Room, Building.
FacID is the primary key.
Table Department has columns such as DNO, Division, DName, Room, Building, DPhone.
DNO is the primary key.
Table Member_of has columns such as FacID, DNO, Appt_Type.
Table Course has columns such as CID, CName, Credits, Instructor, Days, Hours, DNO.
CID is the primary key.
Table Minor_in has columns such as StuID, DNO.
Table Enrolled_in has columns such as StuID, CID, Grade.
Table Gradeconversion has columns such as lettergrade, gradepoint.
lettergrade is the primary key.
The DNO of Member_of is the foreign key of DNO of Department.
The FacID of Member_of is the foreign key of FacID of Faculty.
The DNO of Course is the foreign key of DNO of Department.
The Instructor of Course is the foreign key of FacID of Faculty.
The DNO of Minor_in is the foreign key of DNO of Department.
The StuID of Minor_in is the foreign key of StuID of Student.
The Grade of Enrolled_in is the foreign key of lettergrade of Gradeconversion.
The CID of Enrolled_in is the foreign key of CID of Course.
The StuID of Enrolled_in is the foreign key of StuID of Student.

##Role Access Policy (Column-Level):
Role: AcademicAdvisor
Accessible Columns: Student: StuID, LName, Fname, Age, Sex, Major, Advisor, city_code; Enrolled_in: StuID, CID, Grade; Minor_in: StuID, DNO; Course: CID, CName, Credits, Instructor, Days, Hours, DNO; Faculty: FacID, Lname, Fname, Rank, Room, Building; Gradeconversion: lettergrade, gradepoint

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: Which building does the instructor who teaches the most number of courses live in?
Answer: SELECT T2.Building FROM COURSE AS T1 JOIN FACULTY AS T2 ON T1.Instructor  =  T2.FacID GROUP BY T1.Instructor ORDER BY count(*) DESC LIMIT 1
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT T2.Building FROM COURSE AS T1 JOIN FACULTY AS T2 ON T1.Instructor  =  T2.FacID GROUP BY T1.Instructor ORDER BY count(*) DESC LIMIT 1
##Instruction:
Database: college_3
Total Tables: 8
Total Columns: 39

Table Schemas:

college_3 contains tables such as Student, Faculty, Department, Member_of, Course, Minor_in, Enrolled_in, Gradeconversion.
Table Student has columns such as StuID, LName, Fname, Age, Sex, Major, Advisor, city_code.
StuID is the primary key.
Table Faculty has columns such as FacID, Lname, Fname, Rank, Sex, Phone, Room, Building.
FacID is the primary key.
Table Department has columns such as DNO, Division, DName, Room, Building, DPhone.
DNO is the primary key.
Table Member_of has columns such as FacID, DNO, Appt_Type.
Table Course has columns such as CID, CName, Credits, Instructor, Days, Hours, DNO.
CID is the primary key.
Table Minor_in has columns such as StuID, DNO.
Table Enrolled_in has columns such as StuID, CID, Grade.
Table Gradeconversion has columns such as lettergrade, gradepoint.
lettergrade is the primary key.
The DNO of Member_of is the foreign key of DNO of Department.
The FacID of Member_of is the foreign key of FacID of Faculty.
The DNO of Course is the foreign key of DNO of Department.
The Instructor of Course is the foreign key of FacID of Faculty.
The DNO of Minor_in is the foreign key of DNO of Department.
The StuID of Minor_in is the foreign key of StuID of Student.
The Grade of Enrolled_in is the foreign key of lettergrade of Gradeconversion.
The CID of Enrolled_in is the foreign key of CID of Course.
The StuID of Enrolled_in is the foreign key of StuID of Student.

##Role Access Policy (Column-Level):
Role: AcademicAdvisor
Accessible Columns: Student: StuID, LName, Fname, Age, Sex, Major, Advisor, city_code; Enrolled_in: StuID, CID, Grade; Minor_in: StuID, DNO; Course: CID, CName, Credits, Instructor, Days, Hours, DNO; Faculty: FacID, Lname, Fname, Rank, Room, Building; Gradeconversion: lettergrade, gradepoint

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: Give the building that the instructor who teaches the greatest number of courses lives in.
Answer: SELECT T2.Building FROM COURSE AS T1 JOIN FACULTY AS T2 ON T1.Instructor  =  T2.FacID GROUP BY T1.Instructor ORDER BY count(*) DESC LIMIT 1
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT T2.Building FROM COURSE AS T1 JOIN FACULTY AS T2 ON T1.Instructor  =  T2.FacID GROUP BY T1.Instructor ORDER BY count(*) DESC LIMIT 1
##Instruction:
Database: college_3
Total Tables: 8
Total Columns: 39

Table Schemas:

college_3 contains tables such as Student, Faculty, Department, Member_of, Course, Minor_in, Enrolled_in, Gradeconversion.
Table Student has columns such as StuID, LName, Fname, Age, Sex, Major, Advisor, city_code.
StuID is the primary key.
Table Faculty has columns such as FacID, Lname, Fname, Rank, Sex, Phone, Room, Building.
FacID is the primary key.
Table Department has columns such as DNO, Division, DName, Room, Building, DPhone.
DNO is the primary key.
Table Member_of has columns such as FacID, DNO, Appt_Type.
Table Course has columns such as CID, CName, Credits, Instructor, Days, Hours, DNO.
CID is the primary key.
Table Minor_in has columns such as StuID, DNO.
Table Enrolled_in has columns such as StuID, CID, Grade.
Table Gradeconversion has columns such as lettergrade, gradepoint.
lettergrade is the primary key.
The DNO of Member_of is the foreign key of DNO of Department.
The FacID of Member_of is the foreign key of FacID of Faculty.
The DNO of Course is the foreign key of DNO of Department.
The Instructor of Course is the foreign key of FacID of Faculty.
The DNO of Minor_in is the foreign key of DNO of Department.
The StuID of Minor_in is the foreign key of StuID of Student.
The Grade of Enrolled_in is the foreign key of lettergrade of Gradeconversion.
The CID of Enrolled_in is the foreign key of CID of Course.
The StuID of Enrolled_in is the foreign key of StuID of Student.

##Role Access Policy (Column-Level):
Role: AcademicAdvisor
Accessible Columns: Student: StuID, LName, Fname, Age, Sex, Major, Advisor, city_code; Enrolled_in: StuID, CID, Grade; Minor_in: StuID, DNO; Course: CID, CName, Credits, Instructor, Days, Hours, DNO; Faculty: FacID, Lname, Fname, Rank, Room, Building; Gradeconversion: lettergrade, gradepoint

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: What are the name of courses that have at least five enrollments?
Answer: SELECT T1.CName FROM COURSE AS T1 JOIN ENROLLED_IN AS T2 ON T1.CID  =  T2.CID GROUP BY T2.CID HAVING COUNT(*)  >=  5
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT T1.CName FROM COURSE AS T1 JOIN ENROLLED_IN AS T2 ON T1.CID  =  T2.CID GROUP BY T2.CID HAVING COUNT(*)  >=  5
##Instruction:
Database: college_3
Total Tables: 8
Total Columns: 39

Table Schemas:

college_3 contains tables such as Student, Faculty, Department, Member_of, Course, Minor_in, Enrolled_in, Gradeconversion.
Table Student has columns such as StuID, LName, Fname, Age, Sex, Major, Advisor, city_code.
StuID is the primary key.
Table Faculty has columns such as FacID, Lname, Fname, Rank, Sex, Phone, Room, Building.
FacID is the primary key.
Table Department has columns such as DNO, Division, DName, Room, Building, DPhone.
DNO is the primary key.
Table Member_of has columns such as FacID, DNO, Appt_Type.
Table Course has columns such as CID, CName, Credits, Instructor, Days, Hours, DNO.
CID is the primary key.
Table Minor_in has columns such as StuID, DNO.
Table Enrolled_in has columns such as StuID, CID, Grade.
Table Gradeconversion has columns such as lettergrade, gradepoint.
lettergrade is the primary key.
The DNO of Member_of is the foreign key of DNO of Department.
The FacID of Member_of is the foreign key of FacID of Faculty.
The DNO of Course is the foreign key of DNO of Department.
The Instructor of Course is the foreign key of FacID of Faculty.
The DNO of Minor_in is the foreign key of DNO of Department.
The StuID of Minor_in is the foreign key of StuID of Student.
The Grade of Enrolled_in is the foreign key of lettergrade of Gradeconversion.
The CID of Enrolled_in is the foreign key of CID of Course.
The StuID of Enrolled_in is the foreign key of StuID of Student.

##Role Access Policy (Column-Level):
Role: AcademicAdvisor
Accessible Columns: Student: StuID, LName, Fname, Age, Sex, Major, Advisor, city_code; Enrolled_in: StuID, CID, Grade; Minor_in: StuID, DNO; Course: CID, CName, Credits, Instructor, Days, Hours, DNO; Faculty: FacID, Lname, Fname, Rank, Room, Building; Gradeconversion: lettergrade, gradepoint

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: Give the names of the courses with at least five enrollments.
Answer: SELECT T1.CName FROM COURSE AS T1 JOIN ENROLLED_IN AS T2 ON T1.CID  =  T2.CID GROUP BY T2.CID HAVING COUNT(*)  >=  5
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT T1.CName FROM COURSE AS T1 JOIN ENROLLED_IN AS T2 ON T1.CID  =  T2.CID GROUP BY T2.CID HAVING COUNT(*)  >=  5
##Instruction:
Database: college_3
Total Tables: 8
Total Columns: 39

Table Schemas:

college_3 contains tables such as Student, Faculty, Department, Member_of, Course, Minor_in, Enrolled_in, Gradeconversion.
Table Student has columns such as StuID, LName, Fname, Age, Sex, Major, Advisor, city_code.
StuID is the primary key.
Table Faculty has columns such as FacID, Lname, Fname, Rank, Sex, Phone, Room, Building.
FacID is the primary key.
Table Department has columns such as DNO, Division, DName, Room, Building, DPhone.
DNO is the primary key.
Table Member_of has columns such as FacID, DNO, Appt_Type.
Table Course has columns such as CID, CName, Credits, Instructor, Days, Hours, DNO.
CID is the primary key.
Table Minor_in has columns such as StuID, DNO.
Table Enrolled_in has columns such as StuID, CID, Grade.
Table Gradeconversion has columns such as lettergrade, gradepoint.
lettergrade is the primary key.
The DNO of Member_of is the foreign key of DNO of Department.
The FacID of Member_of is the foreign key of FacID of Faculty.
The DNO of Course is the foreign key of DNO of Department.
The Instructor of Course is the foreign key of FacID of Faculty.
The DNO of Minor_in is the foreign key of DNO of Department.
The StuID of Minor_in is the foreign key of StuID of Student.
The Grade of Enrolled_in is the foreign key of lettergrade of Gradeconversion.
The CID of Enrolled_in is the foreign key of CID of Course.
The StuID of Enrolled_in is the foreign key of StuID of Student.

##Role Access Policy (Column-Level):
Role: AcademicAdvisor
Accessible Columns: Student: StuID, LName, Fname, Age, Sex, Major, Advisor, city_code; Enrolled_in: StuID, CID, Grade; Minor_in: StuID, DNO; Course: CID, CName, Credits, Instructor, Days, Hours, DNO; Faculty: FacID, Lname, Fname, Rank, Room, Building; Gradeconversion: lettergrade, gradepoint

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: Find the first name and last name of the instructor of course that has course name
Answer: SELECT T2.Fname ,  T2.Lname FROM COURSE AS T1 JOIN FACULTY AS T2 ON T1.Instructor  =  T2.FacID WHERE T1.CName  =  "COMPUTER LITERACY"
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT T2.Fname ,  T2.Lname FROM COURSE AS T1 JOIN FACULTY AS T2 ON T1.Instructor  =  T2.FacID WHERE T1.CName  =  "COMPUTER LITERACY"
##Instruction:
Database: college_3
Total Tables: 8
Total Columns: 39

Table Schemas:

college_3 contains tables such as Student, Faculty, Department, Member_of, Course, Minor_in, Enrolled_in, Gradeconversion.
Table Student has columns such as StuID, LName, Fname, Age, Sex, Major, Advisor, city_code.
StuID is the primary key.
Table Faculty has columns such as FacID, Lname, Fname, Rank, Sex, Phone, Room, Building.
FacID is the primary key.
Table Department has columns such as DNO, Division, DName, Room, Building, DPhone.
DNO is the primary key.
Table Member_of has columns such as FacID, DNO, Appt_Type.
Table Course has columns such as CID, CName, Credits, Instructor, Days, Hours, DNO.
CID is the primary key.
Table Minor_in has columns such as StuID, DNO.
Table Enrolled_in has columns such as StuID, CID, Grade.
Table Gradeconversion has columns such as lettergrade, gradepoint.
lettergrade is the primary key.
The DNO of Member_of is the foreign key of DNO of Department.
The FacID of Member_of is the foreign key of FacID of Faculty.
The DNO of Course is the foreign key of DNO of Department.
The Instructor of Course is the foreign key of FacID of Faculty.
The DNO of Minor_in is the foreign key of DNO of Department.
The StuID of Minor_in is the foreign key of StuID of Student.
The Grade of Enrolled_in is the foreign key of lettergrade of Gradeconversion.
The CID of Enrolled_in is the foreign key of CID of Course.
The StuID of Enrolled_in is the foreign key of StuID of Student.

##Role Access Policy (Column-Level):
Role: AcademicAdvisor
Accessible Columns: Student: StuID, LName, Fname, Age, Sex, Major, Advisor, city_code; Enrolled_in: StuID, CID, Grade; Minor_in: StuID, DNO; Course: CID, CName, Credits, Instructor, Days, Hours, DNO; Faculty: FacID, Lname, Fname, Rank, Room, Building; Gradeconversion: lettergrade, gradepoint

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: What is the full name of the instructor who has a course named COMPUTER LITERACY?
Answer: SELECT T2.Fname ,  T2.Lname FROM COURSE AS T1 JOIN FACULTY AS T2 ON T1.Instructor  =  T2.FacID WHERE T1.CName  =  "COMPUTER LITERACY"
Permission: allowed (All required columns are permitted)
Gold SQL: SELECT T2.Fname ,  T2.Lname FROM COURSE AS T1 JOIN FACULTY AS T2 ON T1.Instructor  =  T2.FacID WHERE T1.CName  =  "COMPUTER LITERACY"
##Instruction:
Database: college_3
Total Tables: 8
Total Columns: 39

Table Schemas:

college_3 contains tables such as Student, Faculty, Department, Member_of, Course, Minor_in, Enrolled_in, Gradeconversion.
Table Student has columns such as StuID, LName, Fname, Age, Sex, Major, Advisor, city_code.
StuID is the primary key.
Table Faculty has columns such as FacID, Lname, Fname, Rank, Sex, Phone, Room, Building.
FacID is the primary key.
Table Department has columns such as DNO, Division, DName, Room, Building, DPhone.
DNO is the primary key.
Table Member_of has columns such as FacID, DNO, Appt_Type.
Table Course has columns such as CID, CName, Credits, Instructor, Days, Hours, DNO.
CID is the primary key.
Table Minor_in has columns such as StuID, DNO.
Table Enrolled_in has columns such as StuID, CID, Grade.
Table Gradeconversion has columns such as lettergrade, gradepoint.
lettergrade is the primary key.
The DNO of Member_of is the foreign key of DNO of Department.
The FacID of Member_of is the foreign key of FacID of Faculty.
The DNO of Course is the foreign key of DNO of Department.
The Instructor of Course is the foreign key of FacID of Faculty.
The DNO of Minor_in is the foreign key of DNO of Department.
The StuID of Minor_in is the foreign key of StuID of Student.
The Grade of Enrolled_in is the foreign key of lettergrade of Gradeconversion.
The CID of Enrolled_in is the foreign key of CID of Course.
The StuID of Enrolled_in is the foreign key of StuID of Student.

##Role Access Policy (Column-Level):
Role: AcademicAdvisor
Accessible Columns: Student: StuID, LName, Fname, Age, Sex, Major, Advisor, city_code; Enrolled_in: StuID, CID, Grade; Minor_in: StuID, DNO; Course: CID, CName, Credits, Instructor, Days, Hours, DNO; Faculty: FacID, Lname, Fname, Rank, Room, Building; Gradeconversion: lettergrade, gradepoint

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: Find the department name and room of the course INTRODUCTION TO COMPUTER SCIENCE.
Answer: Sorry, I cannot answer.
Permission: denied (Missing column permissions: department: DNO, Dname, Room)
Gold SQL: SELECT T2.Dname ,  T2.Room FROM COURSE AS T1 JOIN DEPARTMENT AS T2 ON T1.DNO  =  T2.DNO WHERE T1.CName  =  "INTRODUCTION TO COMPUTER SCIENCE"