##Instruction:
Database: financial
Total Tables: 8
Total Columns: 55

Table Schemas:

Database: financial
Total Tables: 8
Total Columns: 55

Table Schemas:

Table: account (4 columns)
--------------------------
• account_id (integer): the id of the account
• district_id (integer): location of branch
• frequency (text): frequency of the acount
• date (date): the creation date of the account
  Values: in the form YYMMDD

Table: card (4 columns)
-----------------------
• card_id (integer): id number of credit card
• disp_id (integer): disposition id
• type (text): type of credit card
  Values: "junior": junior class of credit card; 
"classic": standard class of credit card; 
"gold": high-leve...
• issued (date): the date when the credit card issued
  Values: in the form YYMMDD

Table: client (4 columns)
-------------------------
• client_id (integer): the unique number
• gender (text)
  Values: F：female 
M：male
• birth_date (date): birth date
• district_id (integer): location of branch

Table: disp (4 columns)
-----------------------
• disp_id (integer): unique number of identifying this row of record
• client_id (integer): id number of client
• account_id (integer): id number of account
• type (text): type of disposition
  Values: "OWNER" : "USER" : "DISPONENT"
commonsense evidence:
the account can only have the right to issue pe...

Table: district (16 columns)
----------------------------
• district_id (integer): location of branch
• A2 (text): district_name
• A3 (text): region
• A4 (text)
• A5 (text): municipality < district < region
• A6 (text): municipality < district < region
• A7 (text): municipality < district < region
• A8 (integer): municipality < district < region
• A9 (integer)
  Values: not useful
• A10 (real): ratio of urban inhabitants
• A11 (integer): average salary
• A12 (real): unemployment rate 1995
• A13 (real): unemployment rate 1996
• A14 (integer): no. of entrepreneurs per 1000 inhabitants
• A15 (integer): no. of committed crimes 1995
• A16 (integer): no. of committed crimes 1996

Table: loan (7 columns)
-----------------------
• loan_id (integer): the id number identifying the loan data
• account_id (integer): the id number identifying the account
• date (date): the date when the loan is approved
• amount (integer): approved amount
  Values: unit：US dollar
• duration (integer): loan duration
  Values: unit：month
• payments (real): monthly payments
  Values: unit：month
• status (text): repayment status
  Values: 'A' stands for contract finished, no problems;
'B' stands for contract finished, loan not paid;
'C' ...

Table: order (6 columns)
------------------------
• order_id (integer): identifying the unique order
• account_id (integer): id number of account
• bank_to (text): bank of the recipient
• account_to (integer): account of the recipient
  Values: each bank has unique two-letter code
• amount (real): debited amount
• k_symbol (text): purpose of the payment
  Values: "POJISTNE" stands for insurance payment
"SIPO" stands for household payment
"LEASING" stands for lea...

Table: trans (10 columns)
-------------------------
• trans_id (integer): transaction id
• account_id (integer)
• date (date): date of transaction
• type (text): +/- transaction
  Values: "PRIJEM" stands for credit
"VYDAJ" stands for withdrawal
• operation (text): mode of transaction
  Values: "VYBER KARTOU": credit card withdrawal
"VKLAD": credit in cash
"PREVOD Z UCTU" :collection from anot...
• amount (integer): amount of money
  Values: Unit：USD
• balance (integer): balance after transaction
  Values: Unit：USD
• k_symbol (text)
  Values: "POJISTNE": stands for insurrance payment
"SLUZBY": stands for payment for statement
"UROK": stands ...
• bank (text)
  Values: each bank has unique two-letter code
• account (integer)

##Evidence:
Loan paid with no issue refers to status = 'A'; Interest paid = (monthly payments * duration) - loan amount; Percentage = (amount with status 'A' / total amount) * 100%

##Role Access Policy (Column-Level):
Role: LoanOfficer
Accessible Columns: account: account_id, district_id, frequency, date; client: client_id, district_id; disp: disp_id, client_id, account_id, type; loan: ALL COLUMNS; trans: account_id, date, type, amount, balance

Based on the above schema and your role's column-level access policy, generate a SQL query to answer the question. If your role does not have access to the required columns, respond with: "Sorry, I cannot answer."


Question: For each region, what percentage of the total loan amount has been fully paid without issues, and what percentage of loans were successfully completed? Also include the average interest paid on successful loans compared to all loans.
Evidence: Loan paid with no issue refers to status = 'A'; Interest paid = (monthly payments * duration) - loan amount; Percentage = (amount with status 'A' / total amount) * 100%
Answer: Sorry, I cannot answer.
Permission: denied (Missing column permissions: client: gender; district: A2, A3, district_id)
Gold SQL: WITH LoansByDistrict AS (
    SELECT 
        d.A2 AS district_name,
        d.A3 AS region,
        l.status,
        l.amount,
        l.duration,
        l.payments,
        a.frequency,
        strftime('%Y', l.date) AS loan_year,
        CASE 
            WHEN c.gender = 'M' THEN 'Male'
            WHEN c.gender = 'F' THEN 'Female'
            ELSE 'Unknown'
        END AS gender,
        ROUND((l.payments * l.duration) - l.amount, 2) AS interest_paid
    FROM 
        loan l
    JOIN 
        account a ON l.account_id = a.account_id
    JOIN 
        district d ON a.district_id = d.district_id
    JOIN 
        disp di ON a.account_id = di.account_id AND di.type = 'OWNER'
    JOIN 
        client c ON di.client_id = c.client_id
),
RegionSummary AS (
    SELECT
        region,
        SUM(CASE WHEN status = 'A' THEN amount ELSE 0 END) AS paid_amount,
        SUM(amount) AS total_amount,
        COUNT(CASE WHEN status = 'A' THEN 1 END) AS successful_loans,
        COUNT(*) AS total_loans,
        ROUND(AVG(CASE WHEN status = 'A' THEN interest_paid END), 2) AS avg_interest_paid_successful,
        ROUND(AVG(interest_paid), 2) AS avg_interest_paid_all
    FROM 
        LoansByDistrict
    GROUP BY 
        region
)
SELECT 
    region,
    ROUND((CAST(paid_amount AS REAL) * 100) / total_amount, 2) AS paid_amount_percentage,
    ROUND((CAST(successful_loans AS REAL) * 100) / total_loans, 2) AS successful_loans_percentage,
    successful_loans,
    total_loans,
    paid_amount,
    total_amount,
    avg_interest_paid_successful,
    avg_interest_paid_all,
    (SELECT ROUND((CAST(SUM(CASE WHEN status = 'A' THEN amount ELSE 0 END) AS REAL) * 100) / SUM(amount), 2) FROM loan) AS overall_percentage
FROM 
    RegionSummary
ORDER BY 
    paid_amount_percentage DESC;