Question: what is the wave length of x rays
[{'answer': 'from 0.01 to 10 nanometers', 'provenance': [{'wikipedia_id': '34197', 'title': 'X-ray', 'start_paragraph_id': 1, 'start_character': 115, 'end_paragraph_id': 1, 'end_character': 141, 'bleu_score': 1.0, 'section': 'Section::::Abstract.'}]}, {'answer': 'from 0.01 to 10 nanometers , corresponding to frequencies in the range 30 petahertz to 30 exahertz ( 3 × 10 Hz to 3 × 10 Hz ) and energies in the range 100 eV to 100 keV'}, {'answer': 'ranging from 0.01 to 10 nanometers'}, {'provenance': [{'wikipedia_id': '34197', 'title': 'X-ray', 'start_paragraph_id': 1, 'start_character': 0, 'end_paragraph_id': 1, 'end_character': 693, 'bleu_score': 0.592118916550143, 'meta': {'yes_no_answer': 'NONE', 'annotation_id': 1062040028614041232}, 'section': 'Section::::Abstract.'}]}, {'provenance': [{'wikipedia_id': '34197', 'title': 'X-ray', 'section': 'Section::::Abstract.', 'start_paragraph_id': 1, 'end_paragraph_id': 1, 'meta': {'evidence_span': ['X-rays make up X-radiation, a form of high-energy electromagnetic radiation. Most X-rays have a wavelength ranging from 0.01 to 10 nanometers, corresponding to frequencies in the range 30 petahertz to 30 exahertz (3×10 Hz to 3×10 Hz) and energies in the range 100 eV to 100 keV. X-ray wavelengths are shorter than those of UV rays and typically longer than those of gamma rays. In many languages, X-radiation is referred to as Röntgen radiation, after the German scientist Wilhelm Röntgen who discovered it on November 8, 1895. He named it "X-radiation" to signify an unknown type of radiation. Spelling of "X-ray(s)" in the English language includes the variants "x-ray(s)", "xray(s)", and "X ray(s)".', 'X-rays make up X-radiation, a form of high-energy electromagnetic radiation. Most X-rays have a wavelength ranging from 0.01 to 10 nanometers, corresponding to frequencies in the range 30 petahertz to 30 exahertz (3×10 Hz to 3×10 Hz) and energies in the range 100 eV to 100 keV. X-ray wavelengths are shorter than those of UV rays and typically longer than those of gamma rays. In many languages, X-radiation is referred to as Röntgen radiation, after the German scientist Wilhelm Röntgen who discovered it on November 8, 1895. He named it "X-radiation" to signify an unknown type of radiation. Spelling of "X-ray(s)" in the English language includes the variants "x-ray(s)", "xray(s)", and "X ray(s)".\rhighlight sentence(s) containing evidence, not only the answer', 'Most X-rays have a wavelength ranging from 0.01 to 10 nanometers, corresponding to frequencies in the range 30 petahertz to 30 exahertz (3×10 Hz to 3×10 Hz) and energies in the range 100 eV to 100 keV. X-ray wavelengths are shorter than those of UV rays and typically longer than those of gamma rays.']}}]}, {'provenance': [{'wikipedia_id': '26828712', 'title': 'Quantization of the electromagnetic field', 'section': 'Section::::Photon energy.:Example photon density.\n', 'start_paragraph_id': 59, 'end_paragraph_id': 59, 'meta': {'evidence_span': ['waves. In that case quantum fluctuations are negligible and cannot be heard. Suppose the radio station broadcasts at "ν" = 100\xa0MHz, then it is sending out photons with an energy content of "νh" = 1\xa0×\xa010 × 6.6\xa0×\xa010 = 6.6\xa0×\xa010\xa0J, where "h" is Planck\'s constant. The wavelength of the station is "λ" = "c"/"ν" = 3\xa0m, so that "λ"/(2"π") = 48\xa0cm and the volume is 0.109\xa0m. The energy content of this volume element is 2.1\xa0×\xa010 × 0.109 = 2.3\xa0×\xa010\xa0J, which amounts to 3.4\xa0×\xa010 photons per formula_62 Obviously, 3.4\xa0×\xa010 1 and hence quantum effects do not play a role; the waves emitted by this station are well-described by the classical limit and quantum mechanics is not needed.', 'waves. In that case quantum fluctuations are negligible and cannot be heard. Suppose the radio station broadcasts at "ν" = 100\xa0MHz, then it is sending out photons with an energy content of "νh" = 1\xa0×\xa010 × 6.6\xa0×\xa010 = 6.6\xa0×\xa010\xa0J, where "h" is Planck\'s constant. The wavelength of the station is "λ" = "c"/"ν" = 3\xa0m, so that "λ"/(2"π") = 48\xa0cm and the volume is 0.109\xa0m. The energy content of this volume element is 2.1\xa0×\xa010 × 0.109 = 2.3\xa0×\xa010\xa0J, which amounts to 3.4\xa0×\xa010 photons per formula_62 Obviously, 3.4\xa0×\xa010 1 and hence quantum effects do not play a role; the waves emitted by this station are well-described by the classical limit and quantum mechanics is not needed.\rhighlight sentence(s) containing evidence, not only the answer']}}]}]