Hence: S − S 0 = k B ln ⁡ Ω = k B ln ⁡ 1 = 0 {\displaystyle S-S_{0}=k_{\text{B}}\ln \Omega =k_{\text{B}}\ln {1}=0} The difference is zero, hence the initial entropy S0 can be any selected value so long as all other such calculations include that as the initial entropy.
Maka: S − S 0 = k B ln ⁡ Ω = k B ln ⁡ 1 = 0 {\displaystyle S-S_{0}=k_{\text{B}}\ln \Omega =k_{\text{B}}\ln {1}=0} Perbedaannya adalah nol, maka entropi awal S0 dapat berupa nilai berapapun yang dipilih asalkan semua perhitungan lainnya dimasukkan sebagai entropi awal.