satoshi-2000/llms-suitable huggingface dataset:
Question: What a vertical bar means in a PropertyGroup .csproj file

I have a PropertyGroup like this:
<PropertyGroup Condition="'$(Configuration)|$(Platform)'=='Debug|x86'">
  <DefineConstants>$(DefineConstants)TRACE;X86</DefineConstants>
</PropertyGroup>

I want to know what the vertical bar (|) means when it is placed between parameters in the Condition attribute.


Answer:
It doesn't mean anything - it's just a way of separating the configuration and platform.
Note that these aren't really parameters in a condition attribute - they're just property values which are replaced with the MSBuild property. | is unlikely to be part of a configuration or platform name, so it's a good choice as a separator.
You could have a condition of "'$(Configuration)/$(Platform)'=='Debug/x86'" just as easily, for example. | is just more conventional.
Question: How do I move UIView to the back?

I have a prototype cell with some labels and image views, all added thru Storyboard. I am trying to add a color background view behind these elements (sort of like a bubble view behind the text that is commonly used in messengers). Trying to add this bubble view through Storyboard became a nightmare because of constraints' conflicts. So I decided to add it programmatically right in the prototypeCell class:
let backgroundBubble = UIView()

override func awakeFromNib() {
    super.awakeFromNib()
    backgroundBubble.backgroundColor = .yellow
    backgroundBubble.translatesAutoresizingMaskIntoConstraints = false
    addSubview(backgroundBubble)
    let constraints = [
        backgroundBubble.topAnchor.constraint(equalTo: Label.topAnchor, constant: 0),
        backgroundBubble.leadingAnchor.constraint(equalTo: Label.leadingAnchor, constant: 0),
        backgroundBubble.bottomAnchor.constraint(equalTo: Label.bottomAnchor, constant: 0),
        backgroundBubble.trailingAnchor.constraint(equalTo: Label.trailingAnchor, constant: 0)
    ]
    NSLayoutConstraint.activate(constraints)
}

The problem is that now the bubble view is sitting in front of the content:

I tried to move it back with:
sendSubviewToBack(backgroundBubble)

but then the yellow bubbleView disappears altogether.
How do I move the bubbleView behind the content of the prototype cell?


Answer:
The content of a cell should basically always be added to its contentView. In this case, you may use contentView.insertSubview(backgroundBubble, at: 0) to add it as the first view in the hierarchy stack
Question: Efficient algorithm to calculate the most right non-zero digit of a number's factorial in Python

Calculate the most right non-zero digit of n factorial efficiently
I want to calculate the right most digit of a given number's factorial and print it. What I've done so far is:
import math
n = int(input())
fact = math.factorial(n)
print(str(fact).rstrip('0')[-1])

but I still get time limits and I look for faster solutions.
It's worth noting that I must use python to solve this problem.
Also, I shall point out that n is from 1 to 65536, the time limit is 0.5 seconds and I have 256 megabytes of memory.


Answer:
There is a neat recursive formula you can use: let D(n) be the last non-zero digit in n!

If n<10, use a lookup table
If the second last digit of n is odd, D(n) = 4 * D(n//5) * D(unit digit of n)
If the second last digit of n is even, D(n) = 6 * D(n//5) * D(Unit digit of n)

See this math stackexchange post for a proof.
Translating it into code:
def last_nonzero_factorial_digit(n):
    lookup = [1, 1, 2, 6, 4, 2, 2, 4, 2, 8]
    if n < 10:
        return lookup[n]

    if ((n // 10) % 10) % 2 == 0:
        return (6 * last_nonzero_factorial_digit(n // 5) * lookup[n % 10]) % 10
    else:
        return (4 * last_nonzero_factorial_digit(n // 5) * lookup[n % 10]) % 10

On my laptop, this version runs ~14,000 times faster on a 5-digit number.
Question: Python Cerberus - Validating Schema with this Example

I am using Cerberus to validate dataframes schema. Using this sample data and code below, the  if-else statement should "data structure is valid", however it returns that the "data structure is not valid". Any insight would be appreciated.
import pandas as pd
from cerberus import Validator

df = pd.DataFrame({
    'name': ['Alice', 'Bob', 'Charlie'],
    'age': [25, 30, 35],
    'city': ['New York', 'Paris', 'London']
})

data = df.to_dict()

schema = {
    'name': {'type': 'string'},
    'age': {'type': 'integer', 'min': 18},
    'city': {'type': 'string'}
}

validator = Validator(schema)
is_valid = validator.validate(data)

if is_valid:
    print("Data structure is valid!")
else:
    print("Data structure is not valid.")
    print(validator.errors)

Which results:
>>> Data structure is not valid.
>>> {'age': ['must be of integer type'], 'city': ['must be of string type'], 'name': ['must be of string type']}



Answer:
It is failing because df.to_dict() returns dictionary with values ad dictionaries
data = df.to_dict()
print(data)
>>> {'name': {0: 'Alice', 1: 'Bob', 2: 'Charlie'}, 'age': {0: 25, 1: 30, 2: 35}, 'city': {0: 'New York', 1: 'Paris', 2: 'London'}}

If you want your schema to validate this data you need to change it to:
schema = {
    "name": {"type": "dict", "valuesrules": {"type": "string"}},
    "age": {"type": "dict", "valuesrules": {"type": "integer", "min": 18}},
    "city": {"type": "dict", "valuesrules": {"type": "string"}},
}
Question: WebScraping - Parsel: XPath in python

I am trying to scrape medium.com
I am using the following code:
from parsel import Selector
def get_trending(html):
    selector = Selector(text=html)

    text = selector.xpath("//*[@id='root']/div/div[4]/div[1]/div/div/div/div[2]/div/div[1]/div/div/div[2]/div[2]/a/div/h2")
    # h2 = text.xpath("//h2/text()")
    print(text)

response = requests.get("https://medium.com")
opponents = get_trending(response.text)
opponents

For some reason, it is giving an empty list as a result. I tried it with another h2 and I got the result I wanted. What might be the problem?
Here is the screenshot when I try the xpath in the inspect tool it is working as shown in the image below.



Answer:
Here is a way to get those elements you're looking for using BeautifulSoup instead of Parsel -- you can adapt the code to Parsel if you are so inclined, and you can edit the class content as well to suit your usecase:
from bs4 import BeautifulSoup as bs
import requests

headers= {
    'User-Agent':'Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/113.0.0.0 Safari/537.36'
}

r = requests.get("https://medium.com/", headers=headers)
soup = bs(r.text, 'html.parser')
elements = soup.select('h2[class^="by j"]')
for x in elements:
    print(x.text)

Result in terminal:
No One Really Tells You The Hardest Part Of Getting Older
A good day with Jeff
4 Secrets of Emotionally Stable People
Thought experiment in the National Library of Thailand
Unnatural Keys
Business Model Generation & Playing to Win
On the nature of elegance
It’s Time to Re-Design How We Think
Report from a Relationship
The Secret to Good Photography
A good day with Jeff
How I Turned My Company’s Docs into a Searchable Database with OpenAI
Thought experiment in the National Library of Thailand
What We’re Reading: Always Take a Peek at the Comments
A Contrarian Bet Against Generative AI: The Value of Being Uniquely Human
Why an Engineering Manager Should Not Review Code

BeautifulSoup documentation can be found here.
Question: How to enable authenticator MFA for cognitio user pool created using AWS Node js API?

I am trying to create a AWS Cogntio user pool using AWS Node js SDK in a lambda function. Our use case requires multi factor authentication and enabling authenticator apps for MFA. Looks like the cognito console UI provides an option to specify this but the API does not provide a way to enable authenticator apps for MFA.
Screenshot of Cognito user pool console UI showing option to enable Authenticator apps for MFA
Tried adding
"SoftwareTokenMfaConfiguration": {
    "Enabled": true
  }


field in the params to cognitoIdentityServiceProvider.createUserPool
API but the response indicates "Error creating User Pool:
UnexpectedParameter: Unexpected key 'SoftwareTokenMfaConfiguration'
found in params"

So my code snippet looks like below:
async function createCognitoUserPool(poolName) {
  const cognitoIdentityServiceProvider =
    new AWS.CognitoIdentityServiceProvider();

  // Define the parameters for creating the user pool
  const params = {
    PoolName: poolName,
    Policies: {
      PasswordPolicy: {
        MinimumLength: 8,
        RequireUppercase: true,
        RequireLowercase: true,
        RequireNumbers: true,
        RequireSymbols: true,
      },
    },
    MfaConfiguration: "ON",
    SoftwareTokenMfaConfiguration: {
      Enabled: true,
    },
    AutoVerifiedAttributes: ["phone_number"],
    SmsConfiguration: JSON.parse(
      process.env.COGNITO_USER_POOL_SMS_CONFIGURATION
    ),
  };

  try {
    // Call the CreateUserPool method
    const response = await cognitoIdentityServiceProvider
      .createUserPool(params)
      .promise();

    console.log("User Pool created successfully:", response.UserPool.Id);
    return response.UserPool.Id;
  } catch (error) {
    console.error("Error creating User Pool:", error);
    throw error;
  }
}

Looking forward to find a solution for this. Thanks!


Answer:
You can use SetUserPoolMfaConfig method after creating the user pool.
From TOTP software token MFA page.

You can activate TOTP MFA for your user pool in the Amazon Cognito console, or you can use Amazon Cognito API operations. At the user pool level, you can call SetUserPoolMfaConfig to configure MFA and enable TOTP MFA.

Here are the links of API references from AWS documentation.

SetUserPoolMfaConfig
setUserPoolMfaConfig(params = {}, callback) ⇒ AWS.Request
Question: Count 2 different date fields in a single query

I have 2 different date fields, 1 when the case was created and the other when the case completed. I am trying to count total cases and total completions in say 2023.
Whenever I run my query and set the where field, both columns return the same figure.
SELECT COUNT(*) AS cases,
       COUNT(IF(YEAR(tbl_lead.CompDate) = '2023', 1, NULL)) AS Completed,
       tbl_lead.LeadSource
FROM tbl_lead
WHERE YEAR(tbl_lead.CompDate) = '2023'
GROUP BY tbl_lead.LeadSource

I guess what I'm trying to do is count all records for 2023 as cases, then count how many of those have completed in 2023. Is it impossible?
It should output as:




Cases
Completed
LeadSource




1000
500
Google


2000
700
Facebook




Whereas it currently outputs:




Cases
Completed
LeadSource




500
500
Google


700
700
Facebook




Thank you


Answer:
Your current query only refers to CompDate but in your question you refer to two different date columns. Is this what you are looking for:
SELECT SUM(CreateDate >= '2023-01-01' AND CreateDate < '2024-01-01') AS cases,
       SUM(CompDate >= '2023-01-01' AND CompDate < '2024-01-01') AS Completed,
       LeadSource
FROM tbl_lead
WHERE (CreateDate >= '2023-01-01' AND CreateDate < '2024-01-01')
   OR (CompDate >= '2023-01-01' AND CompDate < '2024-01-01')
GROUP BY LeadSource
Question: R: Append matrix rows if condition is met

I loop through a matrix and I would like to append a matrix row to another empty matrix if a specific condition is met. How do I do this without getting problems with the different indexes?
I had this code, but my dataset is very large, so I get problems in the implementation
for (i in 1:length(matrix1)) {
    if ((substr(matrix1[i,1],6,7) == '02') == TRUE) {
        for (j in 1:nrow(matrix2)) {
            matrix2[j,] <- matrix1[i,]
        }
    }
}

Is there a more efficient solution?
dput(matrix1[1]) is c("271", "269", "274", "278", "293", "270", "274", "274", "275",  "271", "2018-01-03_0445")
nrow(matrix1) is 400000


Answer:
You can simply extract the rows satisfying your condition:
matrix2 <- matrix1[substr(matrix1[, 1], 6, 7) == '02', ]
Question: Error finding a string in another string in Python

I'm trying to return links that have the word "attach" in a list using Python on a web page. But every method I use to find that word in the link gives almost the same error.
This is my code and the error is received from line 16:
from bs4 import BeautifulSoup

# pip install requests
import requests

def list_image_links(url):
    # Send a GET request to the URL
    response = requests.get(url)

    soup = BeautifulSoup(response.content, "html.parser")
    image_links = []
    for image_links in soup.find_all('a'):
        href = image_links.get('href')
#if attach is in href
        word = 'attach'
        if word in href:
            image_links.append(href)
    
    print(image_links)
    return image_links

list_image_links('https://forum.ubuntu.ir/index.php?topic=211.0')


Error:
Traceback (most recent call last):
  File "d:\...\main.py", line 22, in <module>
    list_image_links('https://forum.ubuntu.ir/index.php?topic=211.0')
  File "d:\...\main.py", line 16, in list_image_links
    if word in href:
       ^^^^^^^^^^^^
TypeError: argument of type 'NoneType' is not iterable



Answer:
In my perspective, the error you're encountering is due to the fact that some of the href values returned by link.get('href') may be None, and you cannot iterate over a None value. To avoid this error, you can add a condition to check if href is not None before checking if the word is in it. Here's the modified code:
from bs4 import BeautifulSoup
import requests

def list_image_links(url):
    response = requests.get(url)

    soup = BeautifulSoup(response.content, "html.parser")
    image_links = []
    for image_links in soup.find_all('a'):
        href = image_links.get('href')
        word = 'attach'
        
        if href and word in href:
            image_links.append(href)
    
# rest of the code...

The only change I made was adding an additional condition to the if clause, specifically if href and word in href:. I think this modification will resolve the issues.
Question: Vue - show loader while computed property being computed

EDIT - Found that sorting is quick, real issue is performance of rendering huge list, so already answered
pls explain to me, why this does nothing:
I have array of thousands of items, there is a button for sorting them by some prop (changes "sortBy" prop. Sorting items takes almost 2 seconds, at least that how long after the click does the list change. During computing (until new list displayed) i want to display some "Loading" element. Im not aware, byt maybe Vue has some app-wide state to tell something is being recomputed?
<div v-if="loading">Wait pliz</div>
<div @click="sortBy='ctg'">SortByCtg</div>
<div v-for="item in sortedRows">{{item.ctg}} , {{item.name}} .... </div>

and the computed prop fn:
data: function(){ 
   return { 
    'sortby': 'name', 
    'sortbyDir': 1, 
    'loading': false,
    'rows': [ {'name':'abc','ctg':'def'}, ...] 
  }
},
computed: {
    sortedRows: function(){
     this.loading = true; //  <<< should show element
     var sortby = this.sortby;
     var sortbyDir = this.sortbyDir;
     var sorted = this.rows;
     sorted = this.rows.sort(function(a, b) { 
      return sortbyDir * a[sortby].localeCompare(b[sortby]); 
     });
    this.loading = false; //  <<< hide element
    return sorted;
  }
},
...

but the "loading" element never shows. May it be sort is quick, and what is taking the time is the nodes generation itself? Then can i anyhow show the loader? Maybe somehow use next tick? I tried but with no result.


Answer:
Sorting is quick (few miliseconds),
what really takes time is rendering the long list
Question: How to subtract values between months for each group and each year separately in R

i have such data example
mydata=structure(list(month_id = c(201206L, 201206L, 201207L, 201207L, 
201306L, 201306L, 201307L, 201307L, 201406L, 201406L, 201407L, 
201407L, 201506L, 201506L, 201507L, 201507L, 201606L, 201606L, 
201607L, 201607L, 201706L, 201706L, 201707L, 201707L), MDM_Key = c(1L, 
2L, 1L, 2L, 1L, 2L, 1L, 2L, 1L, 2L, 1L, 2L, 1L, 2L, 1L, 2L, 1L, 
2L, 1L, 2L, 1L, 2L, 1L, 2L), sale_count = c(6978517L, 13957034L, 
6148636L, 12297272L, 6147466L, 12294932L, 6050044L, 12100088L, 
8127548L, 16255096L, 3341936L, 6683872L, 8995701L, 17991402L, 
6803563L, 13607126L, 7098546L, 14197092L, 7855146L, 15710292L, 
5575453L, 11150906L, 7543770L, 15087540L)), class = "data.frame", row.names = c(NA, 
-24L))

I need for each group (mdm_key) to get the difference between the months (07-06) by sale_count Variable. The data contains histories by year. e.g. 06(june) and 07(jule) monthes for 2012,
06 and 07 for 2013 and so on...
For each year and each mdm_key I need to subtract the sale_count from month 7 to month 6.
So that the desired result for each year and each group mdm_key looks something like this
   year MDM_Key sale_count
1  2012       1    -829881
2  2013       1     -97422
3  2014       1   -4785612
4  2015       1   -2192138
5  2016       1     756600
6  2017       1    1968317
7  2012       2   -1659762
8  2013       2    -194844
9  2014       2   -9571224
10 2015       2   -4384276
11 2016       2    1513200
12 2017       2    3936634

What is the easiest way to do such a subtraction?
Thanks for your any help.


Answer:
Does this work?
library(tidyverse)
mydata %>%
  # Filter on months 6 and 7
  filter(str_sub(month_id, -2) %in% c("07", "06")) %>%
  # Sort by Key + yearmonth
  arrange(MDM_Key, month_id) %>%
  # Group by Key
  group_by(MDM_Key) %>%
  # Calculate difference between sales
  mutate(sale_diff = sale_count - lag(sale_count)) %>%
  # Return unique values for each Key + year
  filter(str_sub(month_id, -2) == "07") %>%
  mutate(year = as.integer(str_sub(month_id, 1, 4))) %>%
  select(year, MDM_Key, sale_count = sale_diff)
# A tibble: 12 x 3
# Groups:   MDM_Key [2]
    year MDM_Key sale_count
   <int>   <int>      <int>
 1  2012       1    -829881
 2  2013       1     -97422
 3  2014       1   -4785612
 4  2015       1   -2192138
 5  2016       1     756600
 6  2017       1    1968317
 7  2012       2   -1659762
 8  2013       2    -194844
 9  2014       2   -9571224
10  2015       2   -4384276
11  2016       2    1513200
12  2017       2    3936634
Question: How can I split a column in pandas

I have a data frame with a column that contains string and digit,
Prod_nbr| prod_name
5   Natural chip companyseasalt175g
66  cC Nacho cheese 172g
61  Smiths Crinkle cut chips chicken135g

My desired output is
Prod_nbr|pack|prod_name
5          175g  Natural chip....
66         172g  cC Nacho cheese..
61         135g   Smiths Crinkle...

I tried the code below but I didn't get my desired output, I got

df['pack'] = df['prod_name'].str.extract(r'\d+\s*(\w{,5})\b').fillna('')[0]



Answer:
I would make a custom function to solve the parsing of the field, then apply it by row to the whole DataFrame. I prefer this way because most of the time you will find some unexpected string in the data, and using a function helps you with tweaking the output when needed.
Here is a quick example.
def parse(row):
    s = row.prod_name
    matches = re.findall('\d+g', s)
    if matches:
        if len(matches) == 1:
            return matches[0] #if you have a single match
        else:
            return 'parsing error' #if you have multiple unexpected matches
    return np.nan #no matches


df['pack'] = df.apply(parse, axis=1)
Question: Why does my 2 pointers approach to solve the 3 sum problem on LeetCode throw an index out of bounds error?

class Solution {
    public List<List<Integer>> threeSum(int[] nums) {
        Arrays.sort(nums);
        List<List<Integer>> ans = new ArrayList<>();     
        for(int i=0;i<=nums.length-3;i++){
            if(i==0 || nums[i]!=nums[i-1]){
                int L=i+1;
                int R = nums.length-1;
                int target = 0-(nums[i]);
                while(L<R){ 
                    if(nums[L]+nums[R]==target){
                        List<Integer> temp = new ArrayList<>();
                        temp.add(nums[i]);
                        temp.add(nums[L]);
                        temp.add(nums[R]);
                        ans.add(temp);
                        while(L<nums.length-1 && nums[L]==nums[L+1]) L++;
                        while(R>0 && nums[R]==nums[R-1]) R--;
                        L++;
                        R--;
                    }else if(nums[L]+nums[R]<target){
                        L+=1;
                    }else{
                        R+=1;
                    }
                }    
            }
        }
    return ans;    
    }
# }


trying to solve the 3 sum problem of leetcode with 2 pointers approach . I am getting java.lang.ArrayIndexOutOfBoundsException: Index 6 out of bounds for length 6 at
if(nums[L]+nums[R]==target){


Answer:
A error in the condition for increasing the R pointer is probably what is generating the ArrayIndexOutOfBoundsException in your code. R-=1 should be used instead of R+=1 to move the pointer to the left.
The updated code is as follows:
class Solution {
    public List<List<Integer>> threeSum(int[] nums) {
        Arrays.sort(nums);
        List<List<Integer>> ans = new ArrayList<>();
        for (int i = 0; i <= nums.length - 3; i++) {
            if (i == 0 || nums[i] != nums[i - 1]) {
                int L = i + 1;
                int R = nums.length - 1;
                int target = 0 - nums[i];
                while (L < R) {
                    if (nums[L] + nums[R] == target) {
                        List<Integer> temp = new ArrayList<>();
                        temp.add(nums[i]);
                        temp.add(nums[L]);
                        temp.add(nums[R]);
                        ans.add(temp);
                        while (L < nums.length - 1 && nums[L] == nums[L + 1]) L++;
                        while (R > 0 && nums[R] == nums[R - 1]) R--;
                        L++;
                        R--;
                    } else if (nums[L] + nums[R] < target) {
                        L += 1;
                    } else {
                        R -= 1;  // Fix the typo here
                    }
                }
            }
        }
        return ans;
    }
}