We know the following theorem from Galois theory:


  Let $F$ be a field of characteristic $0$ and $f(x) \in F[x]$. Then $f(x)$ is solvable by radicals if and only if the Galois group of $f(x)$ is solvable.


For fields of characteristic $p &gt; 0$ one direction of this theorem is not true. We could take $F = \mathbb{F}_p(t)$ and $f(x) = x^p - x - t \in F[x]$. Then the Galois group of $f(x)$ is $\mathbb{F}_p$ which is solvable, but $f(x)$ is not solvable by radicals.

What about the other direction? If $f(x) \in F[x]$ is solvable by radicals, is the Galois group of $f(x)$ solvable even when $F$ has characteristic $p &gt; 0$?


Question: SASS Index in nested list
Answer: @cimmanon answered this: http://stackoverflow.com/a/17004655/786123

@function find-value($list, $key) {
    @each $item in $list {
        @if ($key == nth($item, 1)) {
            @return nth($items, 2);
        }
    }
    @return false;
}