| 1 | A | B | C | D | E |
| --- | --- | --- | --- | --- | --- |
| 2 | 1956 United States presidential election in Iowa - Results |  |  |  |  |
| 3 | Party | Party | Candidate | Votes | % |
| 4 | - | Republican | Dwight D. Eisenhower (inc.) | 729,187 | 59.06% |
| 5 | - | Democratic | Adlai Stevenson | 501,858 | 40.65% |
| 6 | - | A.C.P. of Iowa | T. Coleman Andrews | 3,202 | 0.26% |
| 7 | - | Write-in | - | 317 | 0.03% |
| 8 | Total votes | Total votes | Total votes | 1,234,564 | 100% |

Question: Who were the top two finishers in the 1956 United States presidential election in Iowa, and what percentage of vote did each get?
Answer: Iowa was won by Dwight D. Eisenhower, with 59.06% of the popular vote, against Adlai Stevenson, with 40.65% of the popular vote.