| 1 | A | B | C | D | E |
| --- | --- | --- | --- | --- | --- |
| 2 | 1860 United States presidential election in Iowa - Results |  |  |  |  |
| 3 | Party | Party | Candidate | Votes | % |
| 4 | - | Republican | Abraham Lincoln | 70,302 | 54.61% |
| 5 | - | Democratic | Stephen A. Douglas | 55,639 | 43.22% |
| 6 | - | Constitutional Union | John Bell | 1,763 | 1.37% |
| 7 | - | Southern Democratic | John C. Breckinridge | 1,035 | 0.80% |
| 8 | Total votes | Total votes | Total votes | 128,739 | 100% |

Question: I hat was the vote breakdown of the 1860 United States presidential election in Iowa?
Answer: Iowa was won by Abraham Lincoln (R), with 54.61% of the popular vote against Senator Stephen A. Douglas (D), with 43.22% of the popular vote.