qyliang/CodeNanoFix huggingface dataset:
You have a chocolate bar divided into H horizontal rows and W vertical columns of squares. Each square is dark if S_{i,j} is 0, and white if S_{i,j} is 1. The task is to determine the minimum number of cuts needed to ensure that each resulting block has K or fewer white squares. Constraints: 1 ≤ H ≤ 10, 1 ≤ W ≤ 1000, 1 ≤ K ≤ H × W, and S_{i,j} is 0 or 1. The input is given in the format H W K followed by the arrangement of dark and white squares. Output the minimum number of cuts required.

# Buggy version:
x,*s=open(0)
h,w,k,*m=map(int,x.split())
for b in range(512):
  r=t=j=0;d[0]*h
  while w-j:
    i=c=0
    while(h-i):
      d[c]+=s[i][j]>'0'; x=d[c]>k
      if(t<j)&x:r+=1;t=j;d=[0]*h;break
      r+=h*w*x;c+=b>>i&1;i+=1
      else:j+=1
  m+=r+bin(b).count('1'),
print(min(m))

# Fixed version:
x,*s=open(0)
h,w,k,*m=map(int,x.split())
for b in range(512):
 r=t=j=0;d=[0]*h
 while j<w:
  i=c=0
  while h-i:
   d[c]+=s[i][j]>'0';x=d[c]>k
   if(t<j)&x:r+=1;t=j;d=[0]*h;break
   r+=x*h*w;c+=b>>i&1;i+=1
  else:j+=1
 while b:r+=b&1;b>>=1
 m+=r,
print(min(m))
Takahashi plans to visit N stores, each with a specific waiting time. He starts at his house at time 0 and can travel between stores in one unit of time. Each store closes at time T + 0.5. Takahashi can shop at a store after waiting in a queue for a specific duration. He cannot shop more than once at the same store. The task is to find the maximum number of times he can shop before time T + 0.5. The input consists of N, T, a_i, and b_i, and the output is the maximum number of times he can shop.

# Buggy version:
import sys
read = sys.stdin.buffer.read
readline = sys.stdin.buffer.readline
readlines = sys.stdin.buffer.readlines

from functools import cmp_to_key
import itertools

N, T = map(int, readline().split())
m = map(int, read().split())
AB0 = []
AB1 = []
for a,b in zip(m,m):
    if a == 0:
        AB0.append(b)
    else:
        AB1.append((a,b))

if N == 1:
    raise

def sort_func(ab0, ab1):
    a0, b0 = ab0
    a1, b1 = ab1
    return a1*b0 - a0*b1

AB0.sort()
AB1.sort(key=cmp_to_key(sort_func))
AB0, AB1

def compute_0():
    INF = T + 1
    dp = [INF] * 40
    dp[0] = 0
    for a,b in AB1:
        for n in range(39, -1, -1):
            if dp[n] > T:
                continue
            x = (dp[n] + 1) * (a + 1) + b
            if x < dp[n+1]:
                dp[n+1] = x
    return dp

def compute_1():
    return [0] + list(itertools.accumulate(x + 1 for x in AB0))

dp0 = compute_0()
dp1 = compute_1()

R = len(dp1) - 1
answer = 0
for i,x in enumerate(dp0):
    if x > T:
        break
    while x + dp1[R] > T:
        R -= 1
    value = i + R
    if answer < value:
        answer = value

print(answer)

# Fixed version:
import sys
read = sys.stdin.buffer.read
readline = sys.stdin.buffer.readline
readlines = sys.stdin.buffer.readlines

from functools import cmp_to_key
import itertools

N, T = map(int, readline().split())
m = map(int, read().split())
AB0 = []
AB1 = []
for a,b in zip(m,m):
    if a == 0:
        AB0.append(b)
    else:
        AB1.append((a,b))

def sort_func(ab0, ab1):
    a0, b0 = ab0
    a1, b1 = ab1
    return a1*(1+b0) - a0*(1+b1)

AB0.sort()
AB1.sort(key=cmp_to_key(sort_func))
AB0, AB1

def compute_0():
    INF = T + 1
    dp = [INF] * 40
    dp[0] = 0
    for a,b in AB1:
        for n in range(39, -1, -1):
            if dp[n] > T:
                continue
            x = (dp[n] + 1) * (a + 1) + b
            if x < dp[n+1]:
                dp[n+1] = x
    return dp

def compute_1():
    return [0] + list(itertools.accumulate(x + 1 for x in AB0))

dp0 = compute_0()
dp1 = compute_1()

R = len(dp1) - 1
answer = 0
for i,x in enumerate(dp0):
    if x > T:
        break
    while x + dp1[R] > T:
        R -= 1
    value = i + R
    if answer < value:
        answer = value

print(answer)
You are given N robots placed on a number line. Each robot moves a specific distance when activated. Takahashi can activate robots, and if a moving robot touches another, that robot also activates. Find the number of possible sets of remaining robots after Takahashi's operations, modulo 998244353. The input format is N followed by N lines of X and D values for each robot. Output the count of possible sets.

# Buggy version:

import numpy as np

M = 998244353

n = int(input())
xs = [0] * n
ds = [0] * n
for i in range(n):
    x, d = (int(c) for c in input().split())
    ds[i] = d
    xs[i] = x
xs = np.array(xs)
ds = np.array(ds)

import sys
sys.setrecursionlimit(n)

index = xs.argsort()
xs = xs[index]
ds = ds[index]

def _sub(i):
    # 深さ優先探索しながらi番目以下の組み合わせと、次に調べるべき番号を返す
    if i==n-1:
        return 2, n
    res = 1
    ind = i+1
    while True:
        if (xs[i]+ds[i] <= xs[ind]):
            break
        o, ind = _sub(ind)
        res *= o
        res %= M
        if ind>=n:
            break
    return res+1, ind
out = []
done = 0
while True:
    o, done = _sub(done)
    out.append(o)
    if done>=n:
        break
result = 1
for o in out:
    result *= o
    result %= M
print(result)

# Fixed version:

M = 998244353

n = int(input())
xs = [0] * n
ds = [0] * n
for i in range(n):
    x, d = (int(c) for c in input().split())
    ds[i] = d
    xs[i] = (x,i)

import sys
sys.setrecursionlimit(max(1000,n))

xs.sort()
index = [x[1] for x in xs]
xs = [x[0] for x in xs]
ds = [ds[ind] for ind in index]

def _sub(i):
    # 深さ優先探索しながらi番目以下の組み合わせと、次に調べるべき番号を返す
    if i==n-1:
        return 2, n
    res = 1
    ind = i+1
    while True:
        if (xs[i]+ds[i] <= xs[ind]):
            break
        o, ind = _sub(ind)
        res *= o
        res %= M
        if ind>=n:
            break
    return res+1, ind
out = []
done = 0
while True:
    o, done = _sub(done)
    out.append(o)
    if done>=n:
        break
result = 1
for o in out:
    result *= o
    result %= M
print(result)

# Buggy version:
import heapq

mod = 998244353

n = int(input())
robot = [tuple(map(int, input().split())) for _ in range(n)]
robot.sort(reverse=True)
parent = list(range(n))

root = []
for i in range(n):
  x, d = robot[i]
  while root:
    r = heapq.heappop(root)
    if r[0] < x + d:
      parent[r[1]] = i
    else:
      heapq.heappush(root, r)
      break
  heapq.heappush(root, (x, i))
  
count = 1
dp = [1] * n
for i in range(n):
  p = parent[i]
  if p == i:
    count = count * dp[i] % mod
  else:
    dp[p] = dp[p] * (dp[i] + 1) % mod
print(count)

# Fixed version:
import heapq

mod = 998244353

n = int(input())
robot = [tuple(map(int, input().split())) for _ in range(n)]
robot.sort(reverse=True)
parent = list(range(n))

root = []
for i in range(n):
  x, d = robot[i]
  while root:
    r = heapq.heappop(root)
    if r[0] < x + d:
      parent[r[1]] = i
    else:
      heapq.heappush(root, r)
      break
  heapq.heappush(root, (x, i))
  
count = 1
dp = [1] * n
for i in range(n):
  p = parent[i]
  if p == i:
    count = count * (dp[i] + 1) % mod
  else:
    dp[p] = dp[p] * (dp[i] + 1) % mod
print(count)
Title: Milk Shop

Suzuki has opened a new mobile milk vending shop in the Aizu region. Customers have already lined up with bottles to purchase fresh milk, and each customer will only place one order. As there is only one tap on the tank, milk must be sold to customers one by one. Suzuki wants to minimize the total waiting time for the customers in line.

You are given the number of customers and the time each customer takes to pour milk. Your task is to create a program that determines the optimal order of orders to minimize the total waiting time and output the total waiting time for that order. Each customer takes at most 60 minutes, and there are at most 10,000 customers.

Input:
Multiple datasets are provided. Each dataset is in the following format:
n
t1
t2
...
tn

The first line contains the number of customers, n (n ≤ 10,000). The following n lines each contain an integer ti (0 ≤ ti ≤ 60) representing the time the ith customer takes to pour milk.

The input ends with a line containing a single 0. There are at most 50 datasets.

Output:
For each dataset, output the total waiting time (an integer) on a single line.

Sample Input:
5
2
6
4
3
9
0

Output for the Sample Input:
31

# Buggy version:
n = int(input())
t = []
s = []
temp = 0
sum = 0
for i in range(n+1):
    t.append(i)
    t[i] = int(input())
    if t[i] == 0:
        break
    else:
        t.sort()
print(t)
for m in range(n):
    sum = sum + t[m]*(n-m-1)

print(sum)



# Fixed version:
while True:
    n = int(input())
    t = []
    s = 0
    sum = 0

    if n == 0:
        break

    else:
        for i in range(n):
            t.append(i)
            t[i] = int(input())
            t.sort()

        for m in range(n):
            sum = sum + t[m]*(n-m-1)

        print(sum)
Title: Rectangle Exploration

Description:
Given a grid of dimensions H rows and W columns, with a total of W * H cells, some cells have marks. Create a program to read the state of marks in each cell and output the area of the largest rectangle consisting only of cells without marks.

Input:
Multiple datasets are provided. Each dataset begins with a line containing H and W separated by a space, followed by a rectangle of size H * W. H and W are both less than or equal to 500. The input ends with a line containing two zeros. The number of datasets does not exceed 20.

Output:
For each dataset, output the area of the largest rectangle on a single line.

Sample Input:
10 10
...*....**
..........
**....**..
........*.
..*.......
**........
.*........
..........
....*..***
.*....*...
10 10
..*....*..
.*.*...*..
*****..*..
*...*..*..
*...*..*..
..........
****.*...*
..*..*...*
.*...*...*
****..***.
2 3
...
...
0 0

Output for the Sample Input:
28
12
6

# Buggy version:
# ref: http://judge.u-aizu.ac.jp/onlinejudge/review.jsp?rid=924554#1
from itertools import product
while(True):
    H,W = map(int,input().split())
    if not H: break
    ma = [list(map(int,input().replace(".","1").replace("*","0")))+[0] for _ in range(H)]
    for i,j in product(range(1,H),range(W)):
        if ma[i][j]: ma[i][j] += ma[i-1][j]
    ans = 0
    for i in range(H):
        stk = []
        for j in range(W+1):
            cur = ma[i][j]
            if (not stk) or stk[-1][1] < cur:
                stk.append([j,cur])
            elif stk[-1][1] > cur:
                idx = j
                while stk and stk[-1][1] >= cur:
                    ans = max(ans,stk[-1][1]*(j-stk[-1][0]))
                    stk.pop()
    print(ans)


# Fixed version:
# ref: http://judge.u-aizu.ac.jp/onlinejudge/review.jsp?rid=924554#1
from itertools import product
while(True):
    H,W = map(int,input().split())
    if not H: break
    ma = [list(map(int,input().replace(".","1").replace("*","0")))+[0] for _ in range(H)]
    for i,j in product(range(1,H),range(W)):
        if ma[i][j]: ma[i][j] += ma[i-1][j]
    ans = 0
    for i in range(H):
        stk = []
        for j in range(W+1):
            cur = ma[i][j]
            if (not stk) or stk[-1][1] < cur:
                stk.append([j,cur])
            elif stk[-1][1] > cur:
                idx = j
                while stk and stk[-1][1] >= cur:
                    idx = stk[-1][0]
                    ans = max(ans,stk[-1][1]*(j-stk[-1][0]))
                    stk.pop()
                stk.append([idx,cur])
    print(ans)
Title: League Score Sheet

In sports tournaments, there are league and tournament matches. In soccer league matches, points are awarded for wins, losses, and draws, and teams compete for rankings based on these points. The points are as follows: win (3 points), loss (0 points), draw (1 point).

Create a program that takes the number of teams and their league match results as input, sorts them in descending order of performance (based on points earned), and outputs the team names along with their points. In case of a tie in points, output the teams in the order they were input.

Input:
Multiple datasets are provided. Each dataset is in the following format:
n
name1 w1 l1 d1
name2 w2 l2 d2
...
namen wn ln dn

The first line contains the number of teams, n (n ≤ 10). The following n lines contain the name of team i (up to 20 alphabetic characters), the number of wins wi, losses li, and draws di (0 ≤ wi, li, di ≤ 9), separated by spaces.

When the number of teams is 0, it indicates the end of input. The number of datasets does not exceed 50.

Output:
For each dataset, output the sorted list of teams. On the ith line, output the name of the ith team and their points separated by a comma.

Insert a single empty line between datasets.

Sample Input:
4
Japan 1 0 2
Egypt 1 2 0
Canada 0 2 1
Spain 2 0 1
3
India 0 2 0
Poland 1 0 1
Italy 1 0 1
0

Output for the Sample Input:
Spain,7
Japan,5
Egypt,3
Canada,1

Poland,4
Italy,4
India,0

# Buggy version:
b=False
while True:
    n = int(input())
    if n==0:break
    d=dict()
    if b:print()
    b=True
    for _ in range(n):
        line = input().split()
        tmp = int(line[1])*3+int(line[3]*1)
        if tmp in d:
            d[tmp].append(line[0])
        else:
            d[tmp] = []
            d[tmp].append(line[0])
    for k, vs in sorted(d.items(), key=lambda x: x[0])[::-1]:
        for v in vs:
            print('{0},{1}'.format(k, v))

# Fixed version:
b=False
while True:
    n = int(input())
    if n==0:break
    d=dict()
    if b:print()
    b=True
    for _ in range(n):
        line = input().split()
        tmp = int(line[1])*3+int(line[3]*1)
        if tmp in d:
            d[tmp].append(line[0])
        else:
            d[tmp] = []
            d[tmp].append(line[0])
    for k, vs in sorted(d.items(), key=lambda x: x[0])[::-1]:
        for v in vs:
            print('{0},{1}'.format(v, k))

# Buggy version:
while True:
    n = int(input())
    if n == 0:
        break
    dataset = []
    for _ in range(n):
        name, w, l, d = input().split()
        dataset.append((name, 3*int(w) + int(d), n-len(dataset)))
    for name, score, _ in sorted(dataset, key=lambda x: (x[1], x[2]))[::-1]:
        print(name + "," + str(score))

# Fixed version:
b = False
while True:
    n = int(input())
    if n == 0:
        break
    dataset = []
    if b:
        print()
    b = True
    for _ in range(n):
        name, w, l, d = input().split()
        dataset.append((name, 3*int(w) + int(d), n-len(dataset)))
    for name, score, _ in sorted(dataset, key=lambda x: (x[1], x[2]))[::-1]:
        print(name + "," + str(score))
Title: Pocket Pager Input

One day, Tarou received a strange message containing the number "519345213244". It was from his cousin, who is 10 years older. When he called her, she mentioned that she sent it in a hurry using "pocket pager input" and abruptly ended the call. Tarou, familiar with his cousin's assertive nature, researched and found that "pocket pager input" is a method popular about 10 years ago.

In "pocket pager input," characters are entered using two numbers based on a conversion table. For example, the string "naruto" is input as "519345". Thus, each character can be input using two numbers.

During the time when mobile phones were not widely used, high school students used this method to send messages from public phones to their friends' pagers. There were even high school girls who could input messages at an incredible speed. Recently, due to her busy work schedule, Tarou's cousin unconsciously started typing emails using the pocket pager input method.

To help Tarou, who struggles to decipher these messages, create a program that converts messages input using pocket pager into strings. Use the conversion table in Figure 2 and consider only lowercase English letters, ".", "?", "!", and spaces for conversion. For messages containing unconvertible characters, output "NA".

Input:
Multiple messages are provided. Each line contains one message (up to 200 characters). The total number of messages does not exceed 50.

Output:
For each message, output the converted message or "NA" on a single line.

Sample Input:
(Provided in the original problem)

Sample Output:
(Provided in the original problem)

# Buggy version:
# Aizu Problem 00127: Pocket Pager Input
#
import sys, math, os, copy

# read input:
PYDEV = os.environ.get('PYDEV')
if PYDEV=="True":
    sys.stdin = open("sample-input.txt", "rt")


code = {1: "afkpuz", 2: "ablqv.", 3: "chmrw?", 4: "dinsx!", 5: "ejoty "}

def pocket_pager(string):
    if len(string) % 2 == 1:
        return "NA"
    res = ""
    for k in range(len(string) // 2):
        i = int(string[2*k])
        j = int(string[2*k+1])
        if not 1 <= i <= 6 or not 1 <= j <= 5:
            return "NA"
        res += code[j][i-1]
    return res


for line in sys.stdin:
    print(pocket_pager(line.strip()))

# Fixed version:
# Aizu Problem 00127: Pocket Pager Input
#
import sys, math, os, copy

# read input:
PYDEV = os.environ.get('PYDEV')
if PYDEV=="True":
    sys.stdin = open("sample-input.txt", "rt")


code = {1: "afkpuz", 2: "bglqv.", 3: "chmrw?", 4: "dinsx!", 5: "ejoty "}

def pocket_pager(string):
    if len(string) % 2 == 1:
        return "NA"
    res = ""
    for k in range(len(string) // 2):
        i = int(string[2*k])
        j = int(string[2*k+1])
        if not 1 <= i <= 6 or not 1 <= j <= 5:
            return "NA"
        res += code[j][i-1]
    return res


for line in sys.stdin:
    print(pocket_pager(line.strip()))
Title: Square Middle Method

The task is to create a program for the classical random number generation method called the Square Middle Method. This method, proposed by von Neumann in the mid-1940s, involves squaring an initial value 's', considering the result as a 2n-digit number, and taking the middle n digits as the first random number. This process is repeated to generate subsequent random numbers. For example, with an initial value of 123, the first few random numbers are generated as shown in the example.

The program should take as input the initial value 's' (a positive integer less than 10000) and generate 10 random numbers for the case when n=4.

Input:
Multiple datasets are provided. The first line contains the number of datasets, 'd' (d ≤ 10). Each dataset consists of one line with the initial value 's' (an integer, 1 ≤ s < 10000).

Output:
For each dataset, output the generated random numbers in the format:
Case x:
1st generated random number (integer)
2nd generated random number (integer)
...
10th generated random number (integer)

Sample Input:
2
123
567

Output for the Sample Input:
Case 1:
151
228
519
2693
2522
3604
9888
7725
6756
6435
Case 2:
3214
3297
8702
7248
5335
4622
3628
1623
6341
2082

# Buggy version:
n = int(input())
for i in range(n):
    s = int(input())
    print("Case {}:".format(i+1))
    for _ in range(10):
        s = int("{:08d}".format(s ** 2)[2:7])
        print(s)

# Fixed version:
n = int(input())
for i in range(n):
    s = int(input())
    print("Case {}:".format(i+1))
    for _ in range(10):
        s = int("{:08d}".format(s ** 2)[2:6])
        print(s)

# Buggy version:
import os
import sys

def main():
    n = int(input())
    for i in range(1,n+1):
        x = int(input())
        print("Case {}:".format(i))
        for j in range(10):
            x = x**2
            out = '{0:08d}'.format(x)
            print(out[2:6])
            x = int(out[2:6])

main()

# Fixed version:
import os
import sys

def main():
    n = int(input())
    for i in range(1,n+1):
        x = int(input())
        print("Case {}:".format(i))
        for j in range(10):
            x = x**2
            out = '{0:08d}'.format(x)
            print(int(out[2:6]))
            x = int(out[2:6])

main()
Title: Packet Transmission

In the internet, data is divided into packets and transferred to the destination through intermediary devices called routers. Each router determines the next router to transfer the packet based on the destination specified in the packet. Additionally, to prevent infinite packet transfers between routers, a value called TTL (Time To Live) is added to each packet. The router decrements the TTL of the received packet by 1, discarding the packet if the result is 0, or forwarding it to the next router otherwise.

To assist in network design, a program needs to be created. Given the network connection information and packet transmission details as input, the program should display the minimum number of routers through which each packet reaches its destination.

The network consists of multiple routers connected by cables, with each connection being unidirectional. The network's connection information is provided as an array of router numbers. If there are multiple routes from the source to the destination, the program should output the minimum number of routers. If a packet does not reach its destination, the program should output "NA".

The input is provided in the following format:
- The total number of routers, followed by each router's connection information.
- The number of packets, followed by each packet's information, including the source router, destination router, and TTL value.

For each packet, the program should output the number of routers it passes through or "NA".

Sample Input:
7
1 4 2 5 4 3
2 1 5
3 1 6
4 1 7
5 2 7 6
6 1 1
7 0
6
1 2 2
1 5 3
1 2 1
5 1 3
6 3 3
1 7 4

Output for the Sample Input:
2
2
NA
3
3
3

# Buggy version:
from collections import deque
n = int(input())
rlst = [None] * (n + 1)
#print(rlst)
for _ in range(n):
  lst = list(map(int, input().split()))
  r = lst[0]
  print(r)
  lst = lst[2:]
  rlst[r] = lst

p = int(input())

for _ in range(p):
  s, d, v = map(int, input().split())
  visited = [False] * (n + 1)
  visited[s] = True
  que = deque()
  que.append((s, 1))
  while que:
    node, dist = que.pop()
    if node == d:
      print(dist)
      break
    if dist < v:
      for to in rlst[node]:
        if not visited[to]:
          que.append((to, dist + 1))
  else:
    print("NA")


# Fixed version:
from collections import deque

n = int(input())
rlst = [None] * (n + 1)
for _ in range(n):
  lst = list(map(int, input().split()))
  r = lst[0]
  lst = lst[2:]
  rlst[r] = lst

p = int(input())

for _ in range(p):
  s, d, v = map(int, input().split())
  visited = [False] * (n + 1)
  visited[s] = True
  que = deque()
  que.append((s, 0))
  while que:
    node, dist = que.popleft()
    if node == d:
      if dist < v:
        print(dist + 1)
      else:
        print("NA")
      break
    for to in rlst[node]:
      if not visited[to]:
        que.append((to, dist + 1))
        visited[to] = True
  else:
    print("NA")
Title: Candy and Class Flag

In class 3C, it was decided to use the "class flag" used in the sports festival on November 10, Heisei 19, for future class reunions. To determine the student who will store the "class flag," a game using a large amount of candy provided by the teacher was devised.

- Each student takes one candy in order of their student number.
- If candy remains after one round, students continue taking candy in order from the first student number.
- The student who takes the last candy will store the "class flag."

The class consists of 39 students, numbered from 3C01 to 3C39. For example, if there are 50 candies, after each student takes their first candy, 11 candies will remain. Following the student number order, the last candy will be taken by student 3C11, who will then store the "class flag."

Create a program that takes the number of candies as input and outputs the student number who will store the "class flag."

Input:
- Multiple test cases are provided.
- Each test case consists of an integer a (1 ≤ a ≤ 10000) representing the number of candies.

Output:
- For each test case, output the student number who will store the "class flag" on a single line.

Sample Input:
50
5576
5577
5578

Output for the Sample Input:
3C11
3C38
3C39
3C01

# Buggy version:
while True:
    try:
        a = int(input())
    except:
        break
    tmp = a - (a // 39) * 39
    print("3C{:02d}".format(39 if tmp == 39 else tmp))

# Fixed version:
while True:
    try:
        a = int(input())
    except:
        break
    tmp = a - (a // 39) * 39
    print("3C{:02d}".format(tmp if tmp % 39 else 39))