There are 360 balls in the ball pit. If a quarter of the balls in the ball pit are red and a fifth of the remaining balls are blue. How many of the balls are neither red nor blue?
Thoughts? Step-by-step reasoning:
A quarter of the balls are red and therefore there are 360 x (1 / 4) = 90 red balls. When you remove the red balls from the ball pit there are 360 - 90 = 270 remaining balls. A fifth of the remaining balls are blue, and therefore there are 270 x (1 / 5) = 54 blue balls. The total of red and blue balls equals 90 + 54 = 144 balls. When you remove the red and blue balls from the total there are 360 - 144 = 216 balls that are neither red nor blue.
Thus, the answer is 216.