In a bucket there are 3 green balls and 2 yellow balls. What is the probability of drawing at least one green ball when drawing two consecutive balls randomly?
Options:
(A) 16/20
(B) 9/10
(C) 2/5
(D) 3/5
(E) Now, let's think a bit. Some random thoughts:
P(at least one green) = 1 - P(no green, so 2 yellow) = 1- 2/5*1/4 = 9/10.
The final answer: (B).