[Question]: Two runners are competing in a 10-mile race. The first runs at an average pace of 8 minutes per mile, while the second runs at an average pace of 7 minutes per mile. After 56 minutes, the second runner stops for a drink of water. For how many minutes could the second runner remain stopped before the first runner catches up with him?
[Answer]: After 56 minutes, the second runner has traveled 56 / 7 = 8 miles. Similarly, the first runner has traveled 56 / 8 = 7 miles. Therefore, the two runners are 8 - 7 = 1 mile apart when the second runner stops. Thus, the second runner can stop for a maximum of 8 minutes, which is the amount of time it takes the first runner to travel 1 mile.
So the answer is 8.

[Question]: Abigail spent 60% of her money on food, and 25% of the remainder on her phone bill. After spending $20 on entertainment, she is left with $40. How much money did Abigail have initially?
[Answer]: Abigail had $20 + $40 = $60 left after paying her phone bill. The $60 is 100% - 25% = 75% of the remainder of her money after spending for food. Since 75% is $60, then 1% is $60 / 75 = $0.80. Thus, Abigail had $0.80 x 100 = $80 left after she spent money on food. The $80 is 100% - 60% = 40% of her original money. So 1% is $80 / 40 = $2. Therefore, Abigail initially had $2 x 100 = $200.
So the answer is 200.

[Question]: A store sells 20 packets of 100 grams of sugar every week. How many kilograms of sugar does it sell every week?
[Answer]:
A total of 20 x 100 = 2000 grams are sold every week. Since 1 kilogram is equal to 1000 grams, then 2000 / 1000 = 2 kilograms of sugar are sold every week.
So the answer is 2.