I have a new situation: There are two rocks that scientists are looking at. Rock A is located near the lava stored in an active volcano, and rock B is outside this volcano near the base of it. The scientists are currently trying to find a way to safely transport both rocks back to a lab so they can get these rocks under a microscope to look at them. However, they are currently struggling to figure out an effective way to lift rock A out of the volcano. But I can use this background: Emission is the opposite of absorption, it is when an object emits radiation. Objects tend to emit amounts and wavelengths of radiation depending on their "black body" emission curves, therefore hotter objects tend to emit more radiation, with shorter wavelengths. Colder objects emit less radiation, with longer wavelengths. For example, the Sun is approximately 6,000 K (5,730 C; 10,340 F), its radiation peaks near 500 nm, and is visible to the human eye. Earth is approximately 290 K (17 C; 62 F), so its radiation peaks near 10,000 nm, and is much too long to be visible to humans. The light that is observed on photographs of earth from space and with the naked eye is only reflected visible light. What is an answer for this question: Are rock A's wavelengths shorter or longer than rock B's?
shorter