Q: A spaceship is traveling to another planet. The spaceship travels at a consistent speed its entire journey unless it is stopped for the crew's break. After launch, the spaceship traveled for 10 hours then stopped for 3 hours. It then traveled for another 10 hours then stopped for 1 hour. After this, the spaceship would take an hour's break after every 11 hours of traveling and maintained this routine until the end of its journey. If the entire journey took 3 days then how long, in hours, was the spaceship not moving?
A: 8
Explain how we arrive at this answer:
Explanation: On the first day, the spaceship spent a total of 10 hours + 10 hours = 20 hours traveling. On the first day, the spaceship spent a total of 3 hours + 1 hour = 4 hours not moving. This is a total of 20 hours traveling + 4 hours not moving = 24 hours or 1 day. So the rest of the journey took place over 3 days journey 1 first day = 2 days. This is the same as 2 days * 24 hours = 48 hours. In these 2 days, the spaceship's time is split into 11 hours traveling + 1 hour break = 12 hour blocks. So in the last 2 days, the spaceship wasn't moving for a total of 48 hours / 12 hour blocks = 4 hours. Adding this to breaks from the first day shows that the spaceship was not moving for a total of 4 + 4 = 8 hours.