## Solution
Rate of flow of water in second hour = 12 gallons per hour
Rate of flow of water in first hour = 12/(3/2) = 8 gallons per hour
Rate of flow of water in third hour = (125/100)* 12 = (5/4) * 12 = 15 gallons per hour
Number of gallons of water that flowed through the pipe during the entire 3 hours = 12+8+15 = 35 gallons
## What the question and answer could be
The flow of water through a drainage pipe was monitored for a 3-hour period. In the second hour, the rate of flow was 12 gallons per hour, which was 50 percent faster than the rate of flow for the first hour. If 25 percent more water flowed through the pipe in the third hour than it did in the second, how many gallons of water flowed through the pipe during the entire three hours?
Options:
(A) 31.25
(B) 31.5
(C) 33.75
(D) 35.0
(E) 37.5
(D)

## Solution
6C2 * 5C2 * 3C1 = 15*10*3 = 450.
## What the question and answer could be
An analyst will recommend a combination of 2 industrial stocks, 2 transportation stocks, and 1 utility stocks. If the analyst can choose from 6 industrial stocks, 5 transportation stocks, and 3 utility stocks, how many different combinations of 5 stocks are possible?
Options:
(A) 12
(B) 460
(C) 60
(D) 450
(E) 720
(D)

## Solution
Number of gallons of fuel per mile = 300 /60 = 5 gallons per mile
Number of gallons of fuel for a 700 mile flight = 700/5 = 140
## What the question and answer could be
The pilot of a small aircraft uses 60 gallons of fuel to fly 300 miles. At this rate, how many gallons of fuel are needed for a 700 mile flight?
Options:
(A) 140
(B) 155
(C) 160
(D) 170
(E) 175
(A)

## Solution
Vowel: E O
Consonants: V R M N T
First letter can be filled in 2 Ways ( As the question states thatfirst letter has to be a vowel)
Fourth letter can be filled in 5 Ways ( As the question states thatthe last letter has to be a consonant)
Now since each letter can be used only once, and 2 letters out of 7 letters are already used in First and fourth letter
Second letter can be filled in 5 Ways
Third letter can be filled in 4 Ways
So, Total number of ways = 2 Ways x 5 Ways x 4 ways x 5 ways = 200
## What the question and answer could be
How many 4 letter combinations can be made from the letters of the word VERMONT if the first letter has to be a vowel and the last letter has to be a consonant, and each letter can be used only once?
Options:
(A) 21
(B) 42
(C) 120
(D) 600
(E) 200
(E)