q: The H.C.F of two numbers is 23 and the other two factors of their L.C.M are 13 and 14. The larger of the two numbers is:
Options:
(A) 276
(B) 299
(C) 322
(D) 345
(E) 355
a: Stream of consciousness: Clearly, the numbers are (23 * 13) and (23 * 14). Larger number = (23 * 14) = 322. The answer is (C).

question: Given a two-digit number, the unit's digit exceeds its ten's digit by 4 and the product of the given number and the sum of its digits is equal to 90, which of the options is the number?
Options:
(A) 26
(B) 15
(C) 37
(D) 62
(E) 73
answer: Stream of consciousness: Using the elimination method the option that fits this description is 15
5-1 = 4 (unit's digit that exceeds its ten's digit by 4)
15*6 = 90 (the product of the given number and the sum of its digits is equal to 175) The answer is (B).

q: A train of 24 carriages, each of 60 meters length, when an engine also of 60 meters length is running at a speed of 60 kmph. In what time will the train cross a bridge 4.5 km long?
Options:
(A) 4
(B) 3
(C) 5
(D) 6
(E) 9
a: Stream of consciousness: D = 25 * 60 + 4500 = 6000 m
T = 6000/60 * 18/5 = 360 sec = 6 mins The answer is (D).

question: The simple interest on a sum of money is 4/9 of the principal and the number of years is equal to the rate percent. Find the rate and the time?
Options:
(A) 6 2/3%
(B) 6 2/7%
(C) 6 2/2%
(D) 6 3/3%
(E) 6 5/3%
answer: Stream of consciousness: 4/9 P = (P*R*R)/100
R = 20/3 = 6 2/3% The answer is (A).

q: In a race of 600 metres, A can beat B by 60 metres and in a race of 500 metres, B can beat C by 50 metres. By how many metres will A beat C in a race of 400 metres?
Options:
(A) 76 metres
(B) 80 metres
(C) 70 metres
(D) 84 metres
(E) None
a: Stream of consciousness: A runs B runs C runs
600 metres race 600m 540 m
500 metres race 500 m 450m
Combing ratio A runs B runs C runs
300metres - 2700meters - 2430metres
Unitary A runs B runs C runs
Method 400mtres - 360 metres - 324 metres
? A beats C by 400-324 = 76 metres. The answer is (A).

q: Working alone, Printers X, Y, and Z can do a certain printing job, consisting of a large number of pages, in 12, 25, and 30 hours, respectively. What is the ratio of the time it takes Printer X to do the job, working alone at its rate, to the time it takes Printers Y and Z to do the job, working together at their individual rates?
Options:
(A) 4/11
(B) 1/2
(C) 15/22
(D) 150/11
(E) 11/4
a:
Stream of consciousness: P1 takes 12 hrs
Rate for P2P3 together = 1/25 + 1/30 = 11/150
Therefore they take 150/11
Ratio = 150/11 = The answer is (D).