Question: There are 66 goats at a farm and twice as many chickens. If the number of ducks is half of the total of the goats and chickens, and the number of pigs is a third of the number of ducks, how many more goats are there than pigs?
Answer: There are 66 x 2 = 132 chickens. There are 66 + 132 = 198 goats and chickens. There are are 198 / 2 = 99 ducks. There are 99 / 3 = 33 pigs. There are 66 - 33 = 33 more goats than pigs. The answer is 33.
[Question]A shop sells laptops at $600 each and a smartphone at $400. Celine buys two laptops and four smartphones for her children. How much change does she get back if she has $3000?
[Answer]The cost of the two laptops is 2 x $600 = $1200. The cost of the four smartphones is 4 x $400 = $1600. Thus, the total cost of all the items is $1200 + $1600 = $2800. Therefore, Celine gets a change of $3000 - $2800 = $200. The answer is 200.
Q: Eric has a chicken farm with 4 chickens. His chickens lay 3 eggs each day. If Eric collects all the eggs after 3 days, then how many eggs will Eric have collected?
A: Each chicken lays 3 eggs per day and there are 4 chickens 3 * 4 = 12. He will collect all the eggs after 3 days 12 * 3 = 36. The answer is 36.
Question: The ratio representing the age of Halima, Beckham, and Michelle is 4:3:7, respectively. If the total age for the three siblings is 126, calculate the age difference between Halima and Beckham.
Answer: The total ratio representing the age of the three siblings is 4 + 3 + 7 = 14. Halima's age is represented by the fraction 4 / 14, which means she is 4 / 14 * 126 = 36 years old. Beckhams age, from the total age of the three, is 3 / 14 * 126 = 27. The difference in age between Halima and Beckham is 36 - 27 = 9. The answer is 9.
[Question]There's a Bobbit worm hiding in the bottom of James' aquarium. Every day it eats 2 fish. After two weeks, James adds 8 more fish to the aquarium. A week later, he discovers the Bobbit worm. If the aquarium had 60 fish to start with, how many does it have when James discovers the Bobbit worm?
[Answer]First find the total number of weeks the Bobbit worm preys on the fish: 2 weeks + 1 week = 3 weeks. Then multiply that number by the number of days per week: 3 weeks * 7 days / week = 21 days. Then multiply that number by the number of fish the worm eats per day to find how many fish it eats total: 21 days * 2 fish / day = 42 fish. Then add the number of fish James adds to the starting number of fish to find the ending number of fish: 60 fish + 8 fish = 68 fish. Then subtract the number of eaten fish to find the number of surviving fish: 68 fish - 42 fish = 26 fish. The answer is 26.
[Question]In a single day, it rained for many hours. From 2pm to 4pm, it rained at a rate of 4 inches per hour. From 4pm to 7pm, it rained at a rate of 3 inches per hour. And from 7pm to 9pm, it rained at a rate of 0.5 inches per hour. If the rain gauge started out the day already containing 2 inches of rainwater, how many inches of water will the gauge contain at 9pm?
[Answer]
From 2pm to 4pm is 4 - 2 = 2 hours. Thus, from 2 - 4pm, raining at 4 inches per hour, it added 8 inches to the rain gauge. From 4pm to 7pm is 7 - 4 = 3 hours. Thus, from 4 - 7pm, raining at a rate of 3 inches per hour, it added 3 * 3 = 9 inches to the rain gauge. From 7pm to 9pm is 9 - 7 = 2 hours. Thus, from 7 - 9pm, raining at a rate of 0.5 inches per hour, it added 2 * 0.5 = 1 inch to the gauge. If the gauge originally contained 2 inches of water, by 9pm the gauge contained 2 + 8 + 9 + 1 = 20 inches of water. The answer is 20.