In a group of dogs and peacocks, the number of legs are 18 less than four times the number of heads How many peacocks are there in that group?
Options:
(A) 9
(B) 8
(C) 7
(D) 6
(E) 5 Let's think first. Stream of consciousness:
Let the number of dogs be 'x' and the number of peacocks by 'y'. Then, number of legs in the group = 4x + 2y. Number of heads in the group = x+y So, 4x+2y = 4(x+y) 18 2y = 18 y = 9 Number of peacocks in that group = 9.
So, the answer is (A).