This task is to find the number of 'For' loops present in the given cpp program.

const int mov[4][2] = {{-1, 0}, {0, -1}, {1, 0}, {0, 1}};

int m, n, counter;

void dfs(int m, int i) {
//cout << m << ' ' << n << endl;
if (m == 1) {
++counter;
return;
}
for (;i <= m; ++i) {
if (m % i == 0) {
dfs(m/i, i);
}
}
}

int main() {
int t, m, n;
cin >> t;
while (t--) {
counter = 0;
cin >> m;
dfs(m, 2);
cout << counter << endl;
}
}
1

int num;
int fjys(int n,int m,int i,int d,int ji[20])
{
int a;
for(a=i;a<m;a++)
{
if(n%a==0)
{
ji[d]=a;
int chenji=1,k;
for(k=0;k<=d;k++)
chenji=chenji*ji[k];
if(chenji==m)
{
num++;
break;
}
else
fjys(n/a,m,a,d+1,ji);
}
}
return num;
}
int main()
{
int m,n,j,result=0,ji[20]={0};
cin>>m;
for(j=1;j<=m;j++)
{
num=0;
cin>>n;
result=fjys(n,n,2,0,ji);
cout<<result+1<<endl;
}
return 0;
}

3

int t;
int main()
{int n,i,a[100];
void fenjie(int x,int y);
scanf("%d",&n);
for(i=0;i<n;i++)
scanf("%d",&a[i]);
for(i=0;i<n;i++)
{t=0;
fenjie(2,a[i]);
printf("%d
",t);
}
return 0;
}

void fenjie(int x,int y)
{int j;
if(y==1){
t++;
return;}
for(j=x;j<=y;j++)
{if(y%j==0)
fenjie(j,y/j);
}

}
3