Reconstruct a question, answer pair from this explanation: 888 = 8*111 = 3*8*37
Hence 888 is a multiple of 37 and we need at least one 37 in N!
Therefore least value of N! is 37!, which will contain all of 3, 8, and 37.
Q:What is the least value of integer N such that N! is divisible by 888 ?
Options:
(A) 13
(B) 88
(C) 31
(D) 37
(E) D) 888
A:(D)