Answer: (B)
Question: A does a work in 10 days and B does the same work in 15 days. In how many days they together will do the same work?
Options:
(A) 1
(B) 6
(C) 7
(D) 5
(E) 43
[CoT]: [A's 1 day work = 1/10; B's 1 day work = 1/15
(A + B)'s 1 day work = (1/10 + 1/15) = 1/6
So, both together will finish the work in 6 days.]

Answer: (C)
Question: A train running at the speed of 60 km/hr crosses a pole in 15 seconds. Find the length of the train?
Options:
(A) 150
(B) 872
(C) 250
(D) 288
(E) 212
[CoT]: [Speed = 60*(5/18) m/sec = 50/3 m/sec
Length of Train (Distance) = Speed * Time
(50/3) * 15 = 250 meter]

Answer: (B)
Question: A and B can do a work in 5 days and 10 days respectively. A starts the work and B joins him after 2 days. In how many days can they complete the remaining work?
Options:
(A) 6
(B) 2
(C) 3
(D) 4
(E) 98
[CoT]: [Work done by A in 2 days = 2/5
Remaining work = 3/5
Work done by both A and B in one day = 1/5 + 1/10 = 3/10
Remaining work = 3/5 * 10/3 = 2 day]

Answer: (D)
Question:
Which of the options is a two-digit number, which has a unit's digit that exceeds its ten's digit by 4 and the product of the given number and the sum of its digits is equal to 208.
Options:
(A) 15
(B) 37
(C) 55
(D) 26
(E) 73
[CoT]: [Using the elimination method the option that fits this description is 26
6-2 = 4 (unit's digit that exceeds its ten's digit by 3)
26*8 = 208 (the product of the given number and the sum of its digits is equal to 175)]