Q: Consider a smaller store over a large chain as they may have a smaller stock. This may mean they spend more time with the hamsters, making sure that they are healthy and ready to be sold. Make sure they are clean and the hamsters have access to fresh food, bedding, water. They should also have access to exercise. If there are multiple hamsters in the habitat, they are probably young. Observe how they interact with each other. They should be inquisitive and active if awake. They should not be aggressive toward each other. The hamsters should look well fed and well taken care of. They should appear to have bright eyes and shiny coats. Another way to assess the store is by interacting with the store employees. Ask questions about the hamsters, such as age and breed. They should be knowledgeable and readily helpful. Ask for references from other customers. If you are unsure if the pet store is for you, ask if the store can provide references from other customers. You may be able to ask questions of these pet owners to inquire about the hamsters after they were purchased. If you are thinking about a breed that you plan on handling and interacting with, ask if you can hold your pick before you decide to pick it up. You will want to look for a few good attributes before purchasing. Tameness. You want to make sure the hamster is not stressed or anxious while being held. It should not nip, bite, or squirm. Interested rather than anxious. Your hamster should be interested in its surroundings rather than scared. If your hamster is looking around or sniffing for food, it is showing signs that it is relaxed. As hamsters have a life-span of about 2-3 years, you want to make sure you are taking home a healthy and happy friend. Observe these obvious traits before making a purchase. Clear eyes, nose, and mouth Dry, not runny, nose Shiny coat A steady gate No overgrown teeth A happy disposition No hair loss No lumps in body or fur The pet store or breeder may provide a small box to take home your hamster. Your hamster may feel trapped or anxious in the box, so it may crawl, chew, or dig. It is important to go straight home with your new friend. You do not want to stress it out even more or allow it to escape!
A: Pick a good pet store or breeder. Observe the hamster cages and habitat. Interact with the store employees. Ask to handle your hamster before purchase. Look for a healthy, young hamster. Take your hamster home.

Q: To use this method, you should see at least one binomial in your expression. It can be in the numerator, denominator, or both. A binomial is a polynomial with two terms. For example, the expression 4x16x22x{\displaystyle {
rac {4x}{16x^{2}-2x}}} has two terms in the denominator. Thus, the denominator contains a binomial. The factor must be common to all terms in the expression. Factor out this term and rewrite the expression. For example, the monomial 2x{\displaystyle 2x} is common to each term in the expression 4x16x22x{\displaystyle {
rac {4x}{16x^{2}-2x}}}. So after factoring this term out of the numerator and denominator, your expression will look like this: 2x(2)2x(8x1){\displaystyle {
rac {2x(2)}{2x(8x-1)}}}. The monomial term factored out of the numerator and denominator cancels to 1, since you are dividing that term by itself. For example:2x(2)2x(8x1){\displaystyle {
rac {2x(2)}{2x(8x-1)}}}2x(2)2x(8x1){\displaystyle {
rac {{\cancel {2x}}(2)}{{\cancel {2x}}(8x-1)}}} This will leave you with your simplified rational expression. If you factored correctly, there will be no more factors that are common to each term in the numerator and denominator. For example:2x(2)2x(8x1){\displaystyle {
rac {{\cancel {2x}}(2)}{{\cancel {2x}}(8x-1)}}}28x1{\displaystyle {
rac {2}{8x-1}}}
A: Assess the rational expression. Find a monomial factor common to the numerator and denominator. Cancel out the common factor. Rewrite the expression after cancelling out the monomial.

Q: Consider all consecutive integers. Determine the number of terms (n{\displaystyle n}) in the sequence. Since you are considering all consecutive integers to 500, n=500{\displaystyle n=500}. Determine the first (a1{\displaystyle a_{1}}) and last (an{\displaystyle a_{n}}) terms in the sequence. Since the sequence is 1 to 500, a1=1{\displaystyle a_{1}=1} and an=500{\displaystyle a_{n}=500}. Find the average of a1{\displaystyle a_{1}} and an{\displaystyle a_{n}}: 1+5002=250.5{\displaystyle {
rac {1+500}{2}}=250.5}. Multiply the average by n{\displaystyle n}: 250.5500=125,250{\displaystyle 250.5 imes 500=125,250}. The first term in the sequence is 3. The last term in the sequence is 24. The common difference is 7. Determine the number of terms (n{\displaystyle n}) in the sequence. Since you begin with 3, end with 24, and go up by 7 each time, the series is 3, 10, 17, 24. (The common difference is the difference between each term in the sequence.) This means that n=4{\displaystyle n=4} Determine the first (a1{\displaystyle a_{1}}) and last (an{\displaystyle a_{n}}) terms in the sequence. Since the sequence is 3 to 24, a1=3{\displaystyle a_{1}=3} and an=24{\displaystyle a_{n}=24}. Find the average of a1{\displaystyle a_{1}} and an{\displaystyle a_{n}}: 3+242=13.5{\displaystyle {
rac {3+24}{2}}=13.5}. Multiply the average by n{\displaystyle n}: 13.54=54{\displaystyle 13.5 imes 4=54}. Mara saves 5 dollars the first week of the year. For the rest of the year, she increases her weekly savings by 5 dollars every week. How much money does Mara save by the end of the year? Determine the number of terms (n{\displaystyle n}) in the sequence. Since Mara save for 52 weeks (1 year), n=52{\displaystyle n=52}. Determine the first (a1{\displaystyle a_{1}}) and last (an{\displaystyle a_{n}}) terms in the sequence. The first amount she saves is 5 dollars, so a1=5{\displaystyle a_{1}=5}. To find out the amount she saves the last week of the year, calculate 552=260{\displaystyle 5 imes 52=260}. So an=260{\displaystyle a_{n}=260}. Find the average of a1{\displaystyle a_{1}} and an{\displaystyle a_{n}}: 5+2602=132.5{\displaystyle {
rac {5+260}{2}}=132.5}. Multiply the average by n{\displaystyle n}: 132.552=6,890{\displaystyle 132.5 imes 52=6,890}. So she saves $6,890 by the end of the year.
A:
Find the sum of numbers between 1 and 500. Find the sum of the described arithmetic sequence. Solve the following problem.