A can do a piece of work in 24 days. B in 15 days and C in 12 days. In how many days can A finish the work if he is assisted by B on one day and C on the next, alternately?
Options:
(A) 8 2/5days
(B) 10 2/5days
(C) 6 2/5days
(D) 18 2/5days
(E) 17 2/5days Now, let's think a bit. Some random thoughts:
A + B = 1/24 + 1/15 = 13/120
A + C = 1/24 + 1/12 = 1/8
13/120 + 1/8 = 28/120
4 1/5 days * 2 = 8 2/5days
The final answer: (A).