INPUT ARTICLE: Article: Sometimes the way to give a shy guy a little push is to let him know how much you like him. Let him know regularly that you like him, laugh at his jokes, smile when he's around, make sure that he sees how much you genuinely enjoy him and his company. Shyness is directly related to a lack of confidence, so by instilling confidence in his position in your life by showing him that enjoy his company and that you value him in your life, he will be more likely to feel more confident with where he stands with you in the end. If your guy isn't good at picking up nonverbal cues, it might be necessary to actually say to him every once in a while that you like him. If he says something funny, laugh genuinely, and then end it by saying, "Wow, I really like you" with a smile. Send visual cues that you want to be kissed by taking special care of your lips. Full kissable lips can be very alluring to your boyfriend. Exfoliate your lips regularly by rubbing wet sugar against them in gentle circles. Keep them moisturized by applying a lip balm or gloss. Avoid wearing lipstick in moments you want to kiss your man. Lipstick can be a great way to show off your lips, but sometimes makes guys afraid to kiss you in public because the lipstick will be on their lips. If you insist on wearing lipstick, try a nude lip or something matte, since it's less likely to transfer during kissing. Eyes can be one of the most power indicators of attraction and desire. Look into his eyes to show how engaged you are in him and his conversation. He'll want what you want in no time at all. When the two of you make eye contact, briefly bite your lip to bring attention to that area on your face, look at his mouth, and then return to his gaze. A more subtle way to give the hint that you want to be kissed is just to smile flirtatiously while you maintain eye contact with him. While you're talking to him, send a subliminal message that you're thinking about kissing his lips by looking at his mouth as he talks to you. Make it a point to drop your stare from his eyes to his lips to exude longing. Smile with your eyes as you look from his eyes to his lips and then back repeatedly. Build anticipation between you two for the big moment by making sure that he notices how longingly you're looking at his mouth. Sometimes you can set the mood, give hints, and try to initiate things, but things still don't pay off with a kiss. Sometimes the best move is to be direct and initiate your kiss by being straightforward with your boyfriend about what you want. Express to him how much you have wanted to have a kiss from him. You can also ask him if he can kiss you if you prefer him to be the one who leads the kiss. Say something like, "I really like you and am ready to take things a step further by kissing you. I want to show you how you make me feel." If he doesn't seem interested in fulfilling your needs, even when you express them plainly, you might have to consider how long you're willing to be patient with his shyness. If you've reached your breaking point, break up with him and find someone who is dying to kiss you.

SUMMARY: Make sure he knows how much you like him. Perfect your pout. Give him direct eye contact. Stare at his lips. Ask him if you can kiss him.

INPUT ARTICLE: Article: The formula used for calculating vapor pressure given a change in the vapor pressure over time is known as the Clausius-Clapeyron equation (named for physicists Rudolf Clausius and Benoit Paul Emile Clapeyron). This is the formula you'll use to solve the most common sorts of vapor pressure problems you'll find in physics and chemistry classes. The formula looks like this: ln(P1/P2) = (Hvap/R)((1/T2) - (1/T1)). In this formula, the variables refer to: Hvap: The enthalpy of vaporization of the liquid. This can usually be found in a table at the back of chemistry textbooks. R: The real gas constant, or 8.314 J/(K Mol). T1: The temperature at which the vapor pressure is known (or the starting temperature.) T2: The temperature at which the vapor pressure is to be found (or the final temperature.) P1 and P2: The vapor pressures at the temperatures T1 and T2, respectively. The Clausius-Clapeyron equation looks tricky because it has so many different variables, but it's actually not very difficult when you have the right information. The most basic vapor pressure problems will give you two temperature values and a pressure value or two pressure values and a temperature value once you have these, solving is a piece of cake. For example, let's say that we're told that we have a container full of liquid at 295 K whose vapor pressure is 1 atmosphere (atm). Our question is: What is the vapor pressure at 393 K? We have two temperature values and a pressure, so we can solve for the other pressure value with the Clausius-Clapeyron equation. Plugging in our variables, we get ln(1/P2) = (Hvap/R)((1/393) - (1/295)). Note that, for Clausius-Clapeyron equations, you must always use Kelvin temperature values. You can use any pressure values as long as they are the same for both P1 and P2. The Clausius-Clapeyron equation contains two constants: R and Hvap. R is always equal to 8.314 J/(K Mol). Hvap (the enthalpy of vaporization), however, depends on the substance whose vapor pressure you are examining. As noted above, you can usually find the Hvap values for a huge variety of substances in the back of chemistry or physics textbooks, or else online (like, for instance, here.) In our example, let's say that our liquid is pure liquid water. If we look in a table of Hvap values, we can find that the Hvap is roughly 40.65 kJ/mol. Since our H value uses joules, rather than kilojoules, we can convert this to 40,650 J/mol. Plugging our constants in to our equation, we get ln(1/P2) = (40,650/8.314)((1/393) - (1/295)). Once you have all of your variables in the equation plugged in except for the one you are solving for, proceed to solve the equation according to the rules of ordinary algebra. The only difficult part of solving our equation (ln(1/P2) = (40,650/8.314)((1/393) - (1/295))) is dealing with the natural log (ln). To cancel out a natural log, simply use both sides of the equation as the exponent for the mathematical constant e. In other words, ln(x) = 2 eln(x) = e2 x = e2. Now, let's solve our equation: ln(1/P2) = (40,650/8.314)((1/393) - (1/295)) ln(1/P2) = (4,889.34)(-0.00084) (1/P2) = e(-4.107) 1/P2 = 0.0165 P2 = 0.0165-1 = 60.76 atm. This makes sense in a sealed container, increasing the temperature by almost 100 degrees (to almost 20 degrees over the boiling point of water) will create lots of vapor, increasing the pressure greatly

SUMMARY:
Write the Clausius-Clapeyron equation. Plug in the variables you know. Plug in your constants. Solve the equation.