Reasoning: D = 72 * 5/18 = 25 = 500 150 = 350
Ans: (C)
Question: A train 150 m long running at 72 kmph crosses a platform in 25 sec. What is the length of the platform?
Options:
(A) 33
(B) 87
(C) 350
(D) 88
(E) 277
Rationale: Suppose the amount in the beginning was Rs 'x'
Money spent on clothes = Rs 1x/3 Balance = Rs 2x/3
Money spent on food = 1/5 of 2x/3 = Rs 2x/15
Balance = 2x/3 - 2x/15 = Rs 8x/15
Money spent on travel = 1/4 of 8x/15 = Rs 2x/15 = 8x/15 - 2x/15 = 6x/15 = Rs2x/5
Therefore 2x/5 = 100 = 1500
The answer: (B)
Question: A person spends 1/3rd of the money with him on clothes, 1/5th of the remaining on food and 1/4th of the remaining on travel. Now, he is left with Rs 600. How much did he have with him in the beginning?
Options:
(A) s 200
(B) s 1500
(C) s 300
(D) s 450
(E) s 550
Reasoning: (555 + 445) * 2 * 110 + 25 = 220000 + 25 = 220025
Ans: (E)
Question: A no. when divided by the sum of 555 and 445 gives 2times their difference as quotient & 25 as remainder. Find the no. is?
Options:
(A) 145646
(B) 236578
(C) 645353
(D) 456546
(E) 220025
Rationale: Initial no of students + 3 * (1 + No of possible 3 minute intervals between 15:03 and 15:44) -
8 *(1 + No of possible 10 minute intervals between 15:10 and 15:44)
20 + 3*14 -8 * 4 = 27
The answer: (D)
Question: At 15:00 there were 21 students in the computer lab. At 15:03 and every three minutes after that, 3 students entered the lab. If at 15:10 and every ten minutes after that 8 students left the lab, how many students were in the computer lab at 15:44 ?
Options:
(A) 7
(B) 14
(C) 25
(D) 27
(E) 30
Reasoning: Initial no of students + 3 * (1 + No of possible 3 minute intervals between 15:03 and 15:44) -
8 *(1 + No of possible 10 minute intervals between 15:10 and 15:44)
20 + 3*14 -8 * 4 = 27
Ans: (D)
Question: At 15:00 there were 20 students in the computer lab. At 15:03 and every three minutes after that, 4 students entered the lab. If at 15:10 and every ten minutes after that 8 students left the lab, how many students were in the computer lab at 15:44 ?
Options:
(A) 7
(B) 14
(C) 25
(D) 27
(E) 30
Reasoning: P = (P*8*R)/100
R = 12 1/2%
Ans: (E)
Question: In what time a sum of money double itself at 8% per annum simple interest?
Options:
(A) 33 1/8%
(B) 33 1/3%
(C) 83 1/3%
(D) 33 4/3%
(E) 12 1/2%