Sweet Hope hosts a casino with 3 roulette tables labeled A, B, and C. At 6:00 pm, Table B had twice as much money on it as table C, which had $20 more than table A. If there was $40 on table A, how much money was there on all the tables?
Let's think: If table C had $20 more than table A, then table C had $20 + $40 = $60. Roulette tables A and C had $60 + $40 = $100. Table B had twice as much money on it as table C, meaning table B had $60 * 2 = $120. Together, the three roulette tables had $120 + $100 = $220.. The answer is: 220.

Armand is playing a guessing game with his dad where he has to guess a number his dad is thinking of. His dad tells him that the number, when multiplied by 3, is three less than twice 51. What is the number?
Let's think: 102 is twice 51 because 2 x 51 = 102. Three less than 102 is 99 because 102 - 3 = 99. The number is 33 because 99 / 3 = 33.. The answer is: 33.

Tim has some cans of soda. Jeff comes by, and takes 6 cans of soda from Tim. Tim then goes and buys another half the amount of soda cans he had left. If Tim has 24 cans of soda in the end, how many cans of soda did Tim have at first?
Let's think: Let x be the number of cans Tim has at first. After Jeff comes by, Tim has x - 6 cans left. Tim buys another (x - 6) / 2 cans. x - 6 + (x - 6) / 2 = 24. 2 * x - 12 + x - 6 = 48. 3 * x - 18 = 48. 3 * x = 66. x = 22.. The answer is: 22.

There are 10 students in a class. The average age of 9 of them is 8 years. By how many years will this average increase if the tenth student is (quite strangely) 28 years old?
Let's think:
9 students have an average age of 8 years so the sum of their ages is 9 * 8 = 72 years. A tenth student who is 28 years old will make the sum 72 + 28 = 100 years. The new average age will be 100 / 10 = 10 years. This is 10 - 8 = 2 years higher than the previous average.. The answer is: 2.