Reasoning: {Total} = {finance} + {marketing} - {both} + {neither}
100 = 25 + 51 - {both} + 40
{both} = 16%.
Ans: (D)
Question: Walking across campus, a student interviewed a group of students. 25% of the students took a finance class last semester, 51% took a marketing class last semester, and 40% took neither a finance nor a marketing class last semester. What percent of the students in the group took both a finance and a marketing class?
Options:
(A) 60%
(B) 50%
(C) 25%
(D) 16%
(E) 10%
Rationale: 2nd day he earns = 2(2 1)
3rd day he earns = 2(3 1)
On 10th day he earns 2(10 -1) = 18 rupees
The answer: (A)
Question: A owner of a mart earns an income of Re 1 on the first day of his business. On every subsequent day, he earns an income which is just double of that made on the previous day. On the 10th day of business, he earns an income of:
Options:
(A) 18
(B) 21
(C) 22
(D) 20
(E) 30
Reasoning: ? = 5798 + 4632 7385 = 3045
Ans: (D)
Question: In the following equation what value would come in place of question mark (?)?
5798 ? = 7385 4632
Options:
(A) 3225
(B) 2595
(C) 2775
(D) 3045
(E) None of these above
Rationale: Required time = (5 1/4)/2 + (5 1/4)/7 = 3 5/2 hours.
The answer: (C)
Question: A man walks at a speed of 2 km/hr and runs at a speed of 7 km/hr. How much time will the man require to cover a distance of 10 1/2 km, if he completes half of the distance, i.e., (5 1/4) km on foot and the other half by running?
Options:
(A) 4 5/2 hours.
(B) 2 5/2 hours.
(C) 3 5/2 hours.
(D) 5 5/2 hours.
(E) 8 5/2 hours.
Reasoning: 3 is the only prime number or odd number in the series.
Ans: (E)
Question: Find the wrong number below mentioned series
3,20,50,60,80
Options:
(A) 80
(B) 60
(C) 50
(D) 20
(E) 3
Reasoning: Since today's is Daniel's birthday, his age must be an integer. As per the question, let A = 12, B = 2, and C = 6. Plugging these into the answer choices, only C does not yield an integer.
Ans: (C)
Question: Amy, Bob, Cindy, and Daniel all have the same birthday, but they are all different ages. Today is their birthday. Cindy's age is divisible by Bob's age, and Amy's age is divisible by Cindy's age. If A is Amy's age in years, B is Bob's age, and C is Cindy's age, which of the following CANNOT be Daniel's age?
Options:
(A) AC/B
(B) (A+C) /B
(C) (A+B) /C
(D) AB/C
(E) (A-C) /B