q: In Hockey game, one player throws two fair, six-sided die at the same time. If the player receives at least a five or a one on either die, that player wins. What is the probability that a player wins after playing the game once?
Options:
(A) 1/3
(B) 4/9
(C) 5/9
(D) 2/3
(E) 3/4
a: Stream of consciousness: In Hockey game, Probably the easiest approach would be to find the probability of the opposite event and subtract it from 1:
P(win) = 1- P(not win) = 1 - 4/6*4/6 = 5/9. The answer is (C).
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q: If the given two numbers are respectively 7% and 28% of a third number, then what percentage is the first of the second ?
Options:
(A) 20%
(B) 25%
(C) 18%
(D) 30%
(E) none of these
a: Stream of consciousness: Here, l = 7 and m = 28
Therefore, first number = l/m x 100% of second number = 7/28 x 100% of second number = 25% of second number The answer is (B).
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q: Which of the following is equal to (y+1)!/y!?
Options:
(A) y-1
(B) 1+(1/y)
(C) 1
(D) y+1
(E) y
a:
Stream of consciousness: (y + 1)! = (y + 1) * x!
(y + 1)!/y! = y + 1 The answer is (D).
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