Q: Calculate the largest 3 digit number which is exactly divisible by 89?
Options:
(A) 911
(B) 969
(C) 979
(D) 977
(E) 971
A: OK... Stream of consciousness: Largest 4 digit number is 999
After doing 999 89 we get remainder 20
Hence largest 3 digit number exactly divisible by 89 = 999 - 20 = 979
The answer is (C).

Q: Joey is planning to throw a small party and for that he needs to do the following tasks:
I. Decide guest list
II. Send invites
III. Arrange catering
IV. Decide the venue
V. Rent a music system
The tasks can be done in any order as long as the invites are sent after the guest list is decided. In how many ways can Joey do the five tasks listed above?
Options:
(A) 24
(B) 48
(C) 60
(D) 120
(E) 240
A: OK... Stream of consciousness: These 5 tasks can be arranged in 5! = 120 ways. In half of them invites are sentafterthe guest list is decided and in half of them before. So, there are total of 120/2 = 60 ways to arrange the task so that the invites are sent after the guest list is decided.
The answer is (C).

Q: Four of the five parts numbered (a), (b), (c), (d) and (e) in the following equation are exactly equal. Which part is not equal to the other four ? The number of that part is the answer.
Options:
(A) (x + 2y) (3x + 2y)
(B) (x + 2y) 2 + 2x(x + 2y)
(C) (3x + 2y) 2 2x(3x + 2y)
(D) 3x(x + 2y) + 2y(x + 2y)
(E) x(3x + 2y) 2y(3x 2y)
A: OK... Stream of consciousness: Others are equal to 3x2 + 8xy + 4y2
The answer is (E).

Q: The average mark obtained by 22 candidates in an examination is 49. The average of the first ten is 55 while the last eleven is 40 .The marks obtained by the 11th candidate is ?
Options:
(A) 22
(B) 0
(C) 99
(D) 88
(E) 66
A:
OK... Stream of consciousness: It is clear that 22 x 49 = 10 x 55 + K + 11 x 40 K = 88
The answer is (D).