One red flower, three white flowers and two blue flowers are arranged in a line such that
I. No two adjacent flowers are of the same colour.
II. The flowers at the two ends of the line are of different colours.
In how many different ways can the flowers be arranged?
Options:
(A) 6
(B) 4
(C) 10
(D) 12
(E) 14 Hmmm, my stream of consciousness:
The total possibilities are W@W@W@ (or) @W@W@W, where 2 blue and 1 red flowers occupy the space marked as @. Hence, the Total number of permutations is 2 x (3! / 2!) = 6. So, the answer is (A).