q: There are 3 teams each with 3 basket players. How many combinations are there if we were to pick 2 players from the 3 teams such that no team was picked twice?
Options:
(A) 50
(B) 23
(C) 27
(D) 28
(E) 45
a: OK... There are altogether three arrangements, which are we can select two members each from team A and B, each from team A and C, and each from team B and C. For each arrangement, there are altogether 9 possibilities (3*3) since each team has 3 players. So there are a total of 27 possibilities (9*3). I hope this method is easier for you to understand.
The answer is (C).

q: What is the difference between 62% of 150 nd 20% of 250.
Options:
(A) 16
(B) 17
(C) 43
(D) 19
(E) 20
a: OK... (62/100) * 150 (20/100) * 250
93 - 50 = 43
The answer is (C).

q: The average of 13 numbers is 60. Average of the first 7 of them is 57 and that of the last 7 is 61. Find the 8th number?
Options:
(A) 46
(B) 82
(C) 45
(D) 43
(E) 53
a:
OK... Sum of all the 13 numbers = 13 * 60 = 780
Sum of the first 7 of them = 7 * 57 = 399
Sum of the last 7 of them = 7 * 61 = 427
So, the 8th number = 427 + 399 - 780 = 46.
The answer is (A).