q: The measure of the side of a square is doubled. If x represents the perimeter of the original square, what is the value of the new perimeter?
Options:
(A) 2x
(B) 4x
(C) 9x
(D) 12x
(E) 27x
a: Stream of consciousness: Original perimeter = x
Hence original side = x/4
New side = 2x/4
New perimeter = 4*2x/4 = 2x The answer is (A).

question: A car finishes a journey in five hours at the speed of 100 km/hr. If the same distance is to be covered in two hours how much more speed does the car have to gain?
Options:
(A) 8 km/hr
(B) 10 km/hr
(C) 150 km/hr
(D) 16 km/hr
(E) None of these
answer: Stream of consciousness: Distance covered by the car = 100 5 = 500 km
\ Speed = 5002 = 250 km/hr
\ Speed gain = 250 100 = 150 km/hr The answer is (C).

q: Find the value of y from (12)^3 x 6^4 432 = y?
Options:
(A) 2567
(B) 3589
(C) 3789
(D) 4890
(E) 5184
a: Stream of consciousness: Given Exp. = (12)3 x 64 = (12)3 x 64 = (12)2 x 62 = (72)2 = 5184
432 12 x 62 The answer is (E).

question: If X is the sum of first 30 positive even integers and Y is the sum of first 30 positive odd integers, what is the value of x-y?
Please try to explain your answers
Options:
(A) 10
(B) 25
(C) 30
(D) 75
(E) 100
answer: Stream of consciousness: First even minus first odd = 2-1 = 1;
The sum of first 2 even integers minus the sum of first 2 odd integers = (2+4)-(1+3) = 2;
The sum of first 3 even integers minus the sum of first 3 odd integers = (2+4+6)-(1+3+5) = 3;
We can see the patterns here, so the sum of first 30 positive even integers minus the sum of first 30 positive odd integers will be 30. The answer is (C).

q: A and B can do a work in 12 days, B and C in 30 days and C and A in 36 days. In how many days will the work be completed, if all three of them work together?
Options:
(A) 189/13 days
(B) 188/13 days
(C) 180/13 days
(D) 180/17 days
(E) 280/13 days
a: Stream of consciousness: One day work of A and B = 1/12
One day work of B and C = 1/30
One day work of C and A = 1/36
2(A + B + C) = 1/12 + 1/30 + 1/36
2(A + B + C) = 13/90
(A + B + C) = 13/180
Number of days required = 180/13 days. The answer is (C).

q: In Cricket game, one player throws two fair, six-sided die at the same time. If the player receives at least a five or a one on either die, that player wins. What is the probability that a player wins after playing the game once?
Options:
(A) 1/3
(B) 4/9
(C) 5/9
(D) 2/3
(E) 3/4
a:
Stream of consciousness: In Cricket game Probably the easiest approach would be to find the probability of the opposite event and subtract it from 1:
P(win) = 1- P(not win) = 1 - 4/6*4/6 = 5/9. The answer is (C).