In one sentence, describe what the following article is about: This works well for tatting providing you test first that it slides well in the shuttle. It can be a boon for items that need to be durable, such as coasters, placemats, etc.
Summary: Consider using nylon ribbon.

In one sentence, describe what the following article is about: This can be especially fun if you are playing with a large group of people. However, you might want to make a rule that seekers can't wait around the jail or babysit the can. The number of seekers you add depends on your preference. Even with fewer than 20 players, 2 seekers can balance the game. This way, seekers can split between offense (seeking) and defense (protecting the can). If you choose to add seekers to the game, you might also want to increase the number of cans for each additional seeker. For example, a 2 seeker game might have 2 cans. This can add a thrilling pursuit aspect to this game. Instead of having seekers beat hiders to the can, have them tag hiders instead. Tagged players should go, as per usual, to jail. Playing in the dark can be dangerous, so you should make sure your parent or guardian knows and is OK with you doing this beforehand. This version of the game uses no can, as it would be difficult to locate a kicked can in the dark. Instead: Equip seekers with flashlights. Tag people out by shining the light on them and calling their name. Release people from jail by having hiders tag jailed players. Choose a jail in a well lit location, like a porch, so seekers can see potential jailbreaks. This variation requires you to split players into two teams. In the middle of a hardtop area, place your can. Draw a large circle around it with a piece of chalk. Have teams stand an equal distance from the can on opposite sides. Then: Flip a coin to determine which team goes first. Take turns rolling a soft ball at the can to knock it over. Each team should have a ball. The first team to knock over the can must run to it and set it up again with only their feet. Only one active player can be in the circle at a time. The opposing team can freeze players trying to set up the can by hitting them with their ball. The game continues until the can is set up or all the players on one team are frozen.
Summary: Add more seekers to your game. Have seekers tag players. Play in the dark with flashlights. Contest the can.

In one sentence, describe what the following article is about: Suppose, as a different problem, that you know two sides and need to solve an unknown angle. You are given that side A is 10 inches long, side B is 7 inches long, and angle {\displaystyle lpha } is 50 degrees. You can use this information to find the measurement of angle {\displaystyle eta }. Set up the problem as follows: Asin=Bsin{\displaystyle {
rac {A}{\sin lpha }}={
rac {B}{\sin eta }}} 10sin50=7sin{\displaystyle {
rac {10}{\sin 50}}={
rac {7}{\sin eta }}} sin=7sin5010{\displaystyle \sin eta ={
rac {7\sin 50}{10}}} sin=70.76610{\displaystyle \sin eta ={
rac {7*0.766}{10}}} sin=0.536{\displaystyle \sin eta =0.536} In the above example, the law of sines provides the sine of the selected angle as its solution. To find the measure of the angle itself, you must use the inverse sine function. This is also called the arcsine. On a calculator, this is generally marked as sin1{\displaystyle \sin ^{-1}}. Use this to find the measure of the angle. For the example above, the final step is as follows: sin=0.536{\displaystyle \sin eta =0.536} =arcsin0.536{\displaystyle eta =rcsin 0.536} =32.4{\displaystyle eta =32.4}. Suppose you are told that angle =30degrees{\displaystyle lpha =30{ ext{ degrees}}}, angle =50degrees{\displaystyle eta =50{ ext{ degrees}}}, and side C, which connects them, is 10 inches long. Find the measurement of all sides and angles for the triangle. First, you should recognize that you do not yet have enough information for the sine rule to apply. The sine rule requires that you have at least one pair with an angle that opposes a known side. However, you can calculate the third angle of this triangle using simple subtraction. All three angles add up to 180 degrees, so you can find angle {\displaystyle \gamma } by subtracting: =180=1803050=100{\displaystyle \gamma =180-lpha -eta =180-30-50=100} Now that you know all three angles, you can use the sine rule to find the two remaining sides. Solve them one at a time: Csin=Bsin{\displaystyle {
rac {C}{\sin \gamma }}={
rac {B}{\sin eta }}} 10sin100=Bsin50{\displaystyle {
rac {10}{\sin 100}}={
rac {B}{\sin 50}}} 10sin50sin100=B{\displaystyle {
rac {10\sin 50}{\sin 100}}=B} 100.7660.985=B{\displaystyle {
rac {10*0.766}{0.985}}=B} 7.78=B{\displaystyle 7.78=B} Thus, side B is 7.78 inches long. Now solve for the final remaining side. Csin=Asin{\displaystyle {
rac {C}{\sin \gamma }}={
rac {A}{\sin lpha }}} 10sin100=Asin30{\displaystyle {
rac {10}{\sin 100}}={
rac {A}{\sin 30}}} 10sin30sin100=A{\displaystyle {
rac {10\sin 30}{\sin 100}}=A} 100.50.985=A{\displaystyle {
rac {10*0.5}{0.985}}=A} 5.08=A{\displaystyle 5.08=A} Side A, therefore, is 5.08 inches long. You now have all three angles, 30, 50 and 100 degrees, and all three sides, 5.08, 7.78, and 10 inches.
Summary:
Solve for an unknown angle. Use the inverse function if needed to find the angle. Solve a problem with incomplete information.