Reasoning: Suppose the amount in the beginning was Rs 'x'
Money spent on clothes = Rs 1x/3 Balance = Rs 2x/3
Money spent on food = 1/5 of 2x/3 = Rs 2x/15
Balance = 2x/3 - 2x/15 = Rs 8x/15
Money spent on travel = 1/4 of 8x/15 = Rs 2x/15 = 8x/15 - 2x/15 = 6x/15 = Rs2x/5
Therefore 2x/5 = 500 = 1250
Ans: (B)
Question: A person spends 1/3rd of the money with him on clothes, 1/5th of the remaining on food and 1/4th of the remaining on travel. Now, he is left with Rs 500. How much did he have with him in the beginning?
Options:
(A) s 200
(B) s 1250
(C) s 300
(D) s 450
(E) s 550
Rationale: 44 + 28 + 10 = 82%
100 82 = 18%
450 * 18/100 = 81
The answer: (D)
Question: In a school of 450 boys, 44% of Muslims, 28% Hindus, 10% Sikhs and the remaining of other communities. How many belonged to the other communities?
Options:
(A) 72
(B) 75
(C) 80
(D) 81
(E) 90
Reasoning: 1 man's 1 day work = 1/100
(10 men + 15 women)'s 1 day work = 1/7
15 women's 1 day work = (1/7 - 10/100) = 3/70
1 woman's 1 day work = 1/350
1 woman alone can complete the work in 350 days.
Ans: (E)
Question: 10 men and 15 women together can complete a work in 7 days. It takes 100 days for one man alone to complete the same work. How many days will be required for one woman alone to complete the same work?
Options:
(A) 127 days
(B) 667 days
(C) 177 days
(D) 187 days
(E) 350 days
Rationale: A's one day's work = 1/15
B's one day's work = 1/30
(A + B)'s one day's work = 1/15 + 1/30 = 1/10
The part of the work completed in 5 days = 5 (1/10) = 1/2.
The answer: (D)
Question: Two persons A and B can complete a piece of work in 15 days and 30 days respectively. If they work together, what part of the work will be completed in 5 days?
Options:
(A) 1/8
(B) 1/3
(C) 1/6
(D) 1/2
(E) 5/3
Reasoning: Speed downstream = d/t = 75/(2 1/2) = 28 kmph
Speed upstream = d/t = 45/(2 1/2) = 18 kmph
The speed of the stream = (28 - 18)/2 = 5 kmph
Ans: (C)
Question: A man rows his boat 70 km downstream and 45 km upstream, taking 2 1/2 hours each time. Find the speed of the stream?
Options:
(A) 1 kmph
(B) 6 kmph
(C) 5 kmph
(D) 8 kmph
(E) 7 kmph
Reasoning: The total possibilities are W@W@W@ (or) @W@W@W, where 2 blue and 1 red flowers occupy the space marked as @. Hence, the Total number of permutations is 2 x (3! / 2!) = 6.
Ans: (A)
Question: One red flower, three white flowers and two blue flowers are arranged in a line such that
I. No two adjacent flowers are of the same colour.
II. The flowers at the two ends of the line are of different colours.
In how many different ways can the flowers be arranged?
Options:
(A) 6
(B) 4
(C) 10
(D) 12
(E) 14