q: In a particular year, the month of january had exactly 4 thursdays, and 4 sundays. On which day of the week did january 1st occur in the year.
Options:
(A) 33
(B) Monday
(C) 299
(D) 299
(E) 277
a: Stream of consciousness: Ans: If a month has 31 days, and it starts with sunday, Then Sundays, Mondays, tuesdays are 5 for that month. If this month starts with monday, then mondays, tuesdays, and wednesdays are 5 and remaining days are 4 each. so this month start with Monday. The answer is (B).

question: Find the largest 4 digit number which isexactly divisible by 88?
Options:
(A) 8765
(B) 9543
(C) 9944
(D) 1012
(E) 2465
answer: Stream of consciousness: Largest 4 digit number is 9999
After doing 9999 88 we get remainder 55
Hence largest 4 digit number exactly divisible by 88 = 9999 - 55 = 9944 The answer is (C).

q: 5,9,18,31,52,__
Options:
(A) 79
(B) 80
(C) 86
(D) 82
(E) 83
a: Stream of consciousness: (9+5) +4 = 18
(16+9) +6 = 31
(28+16)+8 = 52
(48+28)+10 = 86 The answer is (C).

question: The average of 20 numbers is zero. Of them, at the most, how many may be greater than zero?
Options:
(A) 18
(B) 16
(C) 17
(D) 19
(E) 13
answer: Stream of consciousness: Average of 20 numbers = 0
Sum of 20 numbers = (0 * 20) = 0
It is quite possible that 19 of these numbers may be positive and if their sum is a, then 20th number is (-a). The answer is (D).

q: If P(A) = 2/15, P(B) = 4/15, and P(A B) = 6/15 Find P(B|A)
Options:
(A) 1/2
(B) 2/3
(C) 3
(D) 4/5
(E) 4/7
a: Stream of consciousness: P(B|A) = P(A B)/P(A)
P(B|A) = (6/15)/(2/15) = 3. The answer is (C).

q: A telephone company needs to create a set of 3-digit area codes. The company is entitled to use only digits 6, 4 and 3, which can be repeated. If the product of the digits in the area code must be even, how many different codes can be created?
Options:
(A) 20
(B) 22
(C) 26
(D) 24
(E) 30
a:
Stream of consciousness: Total # of codes possible is 3*3*3 = 27. Oit of those 27 codes only the product of 333 and will be odd, the remaining 26 will have either 2 or 4 in them, which ensures that their product will be even. Therefore the number of codes where the product of the digits is even = (total) - (restriction) = 27 - 1 = 26. The answer is (C).