People usually love to talk about themselves, and feel flattered when another person takes an interest in them. It's also a great way to learn about a person and see if there's any chemistry between you. Ask her questions and get to know her. Great opening questions include: "Which school did you go to before you came here?" "I didn't see you on the bus; does somebody drive you to school?" "Have you taken Algebra with Ms. Smith?" If she doesn't know you or doesn't seem interested in sharing, back off. You don't want to come off as creepy. If a girl likes you, she'll want to talk to you. Say something like, "Is this seat taken?" or "Do you know what the cafeteria is serving for lunch today?" If she replies with more than a short, 1-word answer, that's a good sign! Continue the conversation that you just started. Remember that girls can be shy, too! It may take a few short conversations over a period of a few weeks for her to start opening up to you. Don't take it as a bad sign if she doesn't launch into a full-blown conversation with you right away. For both guys and girls, it's common to compliment someone if you're interested or find them attractive. Pay attention even to subtle compliments, which could be as innocuous as, "Wow, you did a great job on the math homework," or "Your hair looks cool today, are you styling it any differently?" It's always nice to return compliments, too. This can let a girl know you're interested. If she compliments your jacket, for example, say "thank you," and then tell her you like her earrings, for example. If a girl likes you, she may attempt to talk to you and start conversations. If she has a question, take note if she goes out of her way to ask you instead of anyone else. This shows that she has an interest in you as a person, and wants to get to know you better. As with nearly all of these signs, starting conversations could indicate that a girl has either a platonic or romantic interest in you. There's no real way to know for sure without taking a direct approach, like asking her out. If a girl likes you or is interested in spending more time together, she may casually bring up events or places where the two of you could hang out. She may not be asking for a date at this point, but the hang-out can still be a fun, low-key to spend time together and see if there's a mutual attraction. For example, if she says "I really want to see that new Marvel movie this weekend!" say something like "I've been wanting to see it too! Any chance you're free to see it on Saturday evening?" Get it out of the way! Body language and verbal clues can be helpful, but until you ask a girl out, you won't actually know how she feels about you. If you're nervous, you don't have to ask her out on an official date. Instead, ask her if she'd like to get a coffee or have some other low-pressure interaction. Say something like, "I've enjoyed talking with you over the past few days. Any chance you'd be interested in grabbing a soda together after school?"
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One-sentence summary -- Ask her about herself. Ask her a simple question. Notice if she compliments you. Pay attention if she frequently initiates conversations with you. Listen to her ideas and let her know you're interested in hanging out. Ask her out and see what she says.

After you have eliminated all the radicals from the problem, move all the terms to one side of the equation and combine like terms. Returning to the working sample problem, this looks as follows: x1=x214x+49{\displaystyle x-1=x^{2}-14x+49} 0=x215x+50{\displaystyle 0=x^{2}-15x+50} In most cases, this step will create a quadratic polynomial. This is an equation that contains an x2{\displaystyle x^{2}} term as its highest variable. If the original radical was something other than a square root (such as a cube root or fourth root, for example), then you may have a more difficult problem. We will focus on the quadratic for this article. You may be able to solve the quadratic equation by factoring, or you can go directly to the quadratic formula. In this case, the sample problem, 0=x215x+50{\displaystyle 0=x^{2}-15x+50}, can be factored into the two binomial factors of (x5){\displaystyle (x-5)} and (x10){\displaystyle (x-10)}. Factoring the quadratic equation in this case suggests two possible solutions. Because the quadratic equation is equal to 0, you find the solutions by setting each factor equal to 0 and then solve. In the working problem, the two factors are (x5){\displaystyle (x-5)} and (x10){\displaystyle (x-10)}. Set each of these equal to 0 to get the solutions x=5{\displaystyle x=5} and x=10{\displaystyle x=10}. With another problem, you may not be able to factor and would then have to use the quadratic formula to find the solution.
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One-sentence summary --
Consolidate and combine like terms. Solve the equation. Determine your solutions.