Avg = [(x+2)^2 + (x-4)^2] / 2
Expanding and simplifying, (x^2 + 4x + 4 + x^2 - 8x + 16 ) / 2 = x^2 - 2x +10is the reasoning for what question and answer pair?
Q: Which of the following is equal to the average (arithmetic mean) of (x+2)^2 and (x-4)^2?
Options:
(A) x^2
(B) x^2+2
(C) x^2-2x+10
(D) x^2+2x+10
(E) x^2+4x+5
A: (C)