If 80 percent of the test takers taking an old paper and pencil GMAT exam answered the first question on a given math section correctly, and 75 percent of the test takers answered the second question correctly, and 5 percent of the test takers answered neither question correctly, what percent answered both correctly?
Options:
(A) 60 %
(B) 65 %
(C) 70%
(D) 75%
(E) 80%
Answer and stream of consciousness: (A)
Stream of consciousness: {Total} = {First correctly} + {Second correctly} - {Both correctly} + {Neither correctly}
100 = 80 + 75 - {Both correctly} + 5
{Both correctly} = 60.

The year next to 1991 having the same calendar as that of 1990 is
Options:
(A) 1998
(B) 2001
(C) 2002
(D) 2003
(E) None of these
Answer and stream of consciousness: (C)
Stream of consciousness: We go on counting the odd days from 1991 onward still the sum is divisible by 7. The number of such days are 14 upto the year 2001. So, the calender for 1991 will be repeated in the year 2002.

Twenty percent of Country Y's yearly exports come from fruit exports. One-sixth of all fruit exports from Country Y are orange exports. If country Y generates $5 million from its orange exports, how much money does it generate from its yearly total of exports?
Options:
(A) $21.25m
(B) $25.5m
(C) $106.25m
(D) $127.5m
(E) $150m
Answer and stream of consciousness: (E)
Stream of consciousness: 2/10*1/6*(total) = 5
1/30*(total) = 5
(total) = 5*30 = 150

he population of a city is 140,000. If it increases at the rate of 6% per annum, then what will be its population 2 years hence?
Options:
(A) 1797787
(B) 1597723
(C) 159776
(D) 159728
(E) 157304
Answer and stream of consciousness:
(E)
Stream of consciousness: Population after n years = P [1 + (R/100)]2
Population after 2 years = 140000 * [1 + 6/100]2 = (160000 x 53/50 x 53/50) = 157304