This task is to find the number of 'For' loops present in the given cpp program.

Input: Consider Input: int sdw(int a,int b)
{
int i;
int m=1;
for(i=a;i<b/2;i++)
{
if(b%i==0)
{
if(i<=b/i)
m=sdw(i,b/i)+m;
}
}
return m;
}
int main()
{
int n,i,p,b;
int a[1000];
scanf("%d",&n);
for(i=0;i<n;i++)
{
scanf("%d",&a[i]);
}
for(i=0;i<n;i++)
{
b=a[i];
p=sdw(2,b);
printf("%d
",p);
}
return 0;
}

Output: 3

Input: Consider Input: int f(int a,int min)
{
if(a<min)
{
return 0;
}
int k=1,i;
for(i=min;i<a;i++)
{
if(a%i==0)
{
k=k+f(a/i,i);
}
}
return(k);
}

int main()
{
int f(int a,int min);
int j,n;
int a[100],b[100];
scanf("%d",&n);
for(j=0;j<n;j++)
scanf("%d",&a[j]);
for(j=0;j<n;j++)
{
b[j]=f(a[j],2);
printf("%d
",b[j]);
}
return 0;
}

Output: 3

Input: Consider Input: int fenjie(int k, int l);
int main()
{
int n, i;
cin >> n;
for(i = 1; i <= n; i++)
{
int a;
cin >> a;
cout << fenjie(a, 2) << endl;
}
return 0;
}

int fenjie(int k, int l)
{
int num = 1, d, e;
if(k < l)
{
return 0;
}
d = (int) (sqrt((double) k));
for(e = l; e <= d; e++)
{
if(k % e == 0)
{
num += fenjie(k / e, e);
}
}
return num;
}
Output: 2