In a bag there are 3 Snicker's bars and 2 Milky Way bars. What is the probability of choosing at least one Snickers when choosing two consecutive candy bars randomly?
Options:
(A) 9/10
(B) 16/20
(C) 2/5
(D) 3/5
(E) Think first, then make a decision. Some random thoughts:
P(at least one Snicker's Bar) = 1 - P(no Snicker's Bar, so 2 Milky Way Bars) = 1- 2/5*1/4 = 9/10. So the answer is (A).