Rationale: S = 400/16 * 18/5 = 90 kmph
The answer: (E)
Question: A train 400 m in length crosses a telegraph post in 16 seconds. The speed of the train is?
Options:
(A) 22 kmph
(B) 77 kmph
(C) 54 kmph
(D) 71 kmph
(E) 90 kmph
Reasoning: S = 250/12 * 18/5 = 75kmph
Ans: (D)
Question: A 250 meter long train crosses a man standing on the platform in 12 sec. What is the speed of the train?
Options:
(A) 228
(B) 108
(C) 1266
(D) 75
(E) 211
Rationale: S = 600/40 = 15 mps
S = 3600/15 = 240 sec = 4 min
The answer: (A)
Question: A 600 meter long train crosses a signal post in 40 seconds. How long will it take to cross a 3 kilometer long bridge, at the same speed?
Options:
(A) 4 min
(B) 2 min
(C) 8 min
(D) 9 min
(E) 5 min
Reasoning: In 12s the train crosses the pole and in 27 sec the train crosses one more stationary train
In 15 sec the train travels a distance of 300 mtrs
Speed = 300/15 = 20 m/s = 20 (3600/1000) = 20 * 18/5 = 72 kmph
Ans: (E)
Question: A Train requires 12 seconds to pass a pole while it requires 27 seconds to cross a stationary train which is 300 mtrs long. Find the speed of the train.
Options:
(A) 60 kmph
(B) 75 kmph
(C) 80 kmph
(D) 85 kmph
(E) 72 kmph
Rationale: Area of an equilateral triangle = 3/4 S2
If S = 24, Area of triangle = 3/4 * 24 * 24 = 1443 cm2;
The answer: (E)
Question: What is the are of an equilateral triangle of side 24 cm?
Options:
(A) 663 cm2
(B) 743 cm2
(C) 643 cm2
(D) 645 cm2
(E) 1443 cm2
Rationale: Speed = 60*(5/18) m/sec = 50/3 m/sec
Length of Train (Distance) = Speed * Time
(50/3) * 6 = 100 meter
The answer: (C)
Question: A train running at the speed of 60 km/hr crosses a pole in 6 seconds. Find the length of the train.
Options:
(A) 150 m
(B) 145 m
(C) 100 m
(D) 135 m
(E) 155 m