Question: Zain has 10 more of each coin than Emerie. If Emerie has six quarters, seven dimes, and five nickels, how many coins does Zain have? Think carefully first, then make a decision:
If Emerie has six quarters, Zain has 6 + 10 = 16 quarters. At the same time, Zain has 7 + 10 = 17 dimes, ten more than Emerie. The total number of quarters and dimes Zain has is 17 + 16 = 33 coins. Zain also has 10 more nickels than Emerie, a total of 10 + 5 = 15 nickels. In total, Zain has 33 + 15 = 48 coins. So the answer is 48.