Of the families in City X in 1991, 60 percent owned a personal computer. The number of families in City X owning a computer in 1993 was 20 percent greater than it was in 1991, and the total number of families in City X was 9 percent greater in 1993 than it was in 1991. what percent of the families in City X owned a personal computer in 1993?
Options:
(A) 59%
(B) 55%
(C) 63%
(D) 66%
(E) 68% Stream of consciousness:
Say a 100 families existed in 1991 then the number of families owning a computer in 1991 - 60
Number of families owning computer in 1993 = 60 * 120/100 = 72
Number of families in 1993 = 109
The percentage = 72/109 * 100 = 66%.
Thus, the answer is (D).