Reasoning: (90/100) * 40 (80/100) * 30
36 - 24 = 12
Ans: (A)
Question: How much 90% of 40 is greater than 80% of 30?
Options:
(A) 12
(B) 14
(C) 16
(D) 17
(E) 18

Reasoning: 17m - n = p
Add n to both sides:
17m = n + p
Add m to both sides:
18m = n + p + m
Now, divide both sides by 3
6m = (n + p + m)/3 = the average of n, p, and m
Ans: (C)
Question: If 17m n = p, then which of the following represents the average (arithmetic mean) of m, n, and p, in terms of m?
Options:
(A) 2m 1
(B) 4m
(C) 6m
(D) m/5
(E) 6m/5

Reasoning: Speed = 60*(5/18) m/sec = 50/3 m/sec
Length of Train (Distance) = Speed * Time
(50/3) * 15 = 250 meter
Ans: (C)
Question: A train running at the speed of 60 km/hr crosses a pole in 15 seconds. Find the length of the train?
Options:
(A) 150
(B) 872
(C) 250
(D) 288
(E) 212

Reasoning: The probability that she hits the bullseye at least once = 1 - (the probability that she misses the bullseye every shot)
The probability that she misses all shots = (prob that she misses from 30 yards)*(prob that she misses from 40 yards)*(prob that she misses from 50 yards)
Prob that she misses from 30 yards = 1 - 5/6 = 1/6; Prob that she misses from 40 yards = 1 - 4/5 = 1/5; Prob that she misses from 50 yards = 1 - 3/4 = 1/4
Thus the probability that she misses all shots = (1/6)*(1/5)*(1/4) = 1/120
Thus the probability that she makes at least one shot = 1 - (1/120) = 119/120
Ans: (B)
Question: An archer is shooting arrows from various distances. She shoots at a target from 30 yards, 40 yards, and 50 yards. The probability that she hits within the bullseye from 30 yards is 5/6, the probability that she hits within the bullseye from 40 yards is 4/5, and the probability that she hits within the bullseye from 50 yards is 3/4. What is the probability that she hits the bullseye at least once in three shots, one from each distance listed.
Options:
(A) 104/105
(B) 119/120
(C) 139/140
(D) 9/10
(E) 14/15