Consider the question. Jason has six fish in his aquarium. He realizes that every day the number of fish doubles. On the third day he takes out one-third of the fish. On the fifth day he takes out one-fourth of the fish. On the seventh day he adds 15 more fish. How many fish in total does he have?
What is the step-by-step reasoning process to arrive at the answer: 207?
Start by finding how many fish were in the aquarium on the third day 6 * 2 * 2 = 24. On day three, Jason took out one - third of the fish 24 / 3 = 8. So at the end of day three, he has 24 - 8 = 16 fish. On day five he has 16 * 2 * 2 = 64 fish, but he takes out one - fourth. So he took out 64 / 4 = 16 fishes. So at the end of day five, he has 64 - 16 = 48 fish. On day seven he has 48 * 2 * 2 = 192 fish. He adds in 15 more, so he has 192 + 15 = 207 fish in total.